Problem:
Score : 500 points

Problem Statement

You are given a string S of length N consisting of lowercase English letters.

Process Q queries of the following two types:

Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)

Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).

Constraints

N, Q, i_q, l_q, and r_q are integers.

S is a string consisting of lowercase English letters.

c_q is a lowercase English letter.

1 \leq N \leq 500000

1 \leq Q \leq 20000

|S| = N

1 \leq i_q \leq N

1 \leq l_q \leq r_q \leq N

There is at least one query of type 2 in each testcase.

Input

Input is given from Standard Input in the following format:

N
S
Q
Query_1
\vdots
Query_Q

Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:

1 i_q c_q

2 l_q r_q

Output

For each query of type 2, print a line containing the answer.

Sample Input 1

7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7

Sample Output 1

3
1
5

In the first query, cdbb contains three kinds of letters: b , c , and d, so we print 3.

In the second query, S is modified to abcdzbd.

In the third query, a contains one kind of letter: a, so we print 1.

In the fourth query, S is modified to abcazbd.

In the fifth query, S does not change and is still abcazbd.

In the sixth query, abcazbd contains five kinds of letters: a, b, c, d, and z, so we print 5.

Solution in LuaJIT (2.0.4) (judge verdict: Accepted)

local mfl, mce, mmi = math.floor, math.ceil, math.min
local bls, brs = bit.lshift, bit.rshift
local SegTree = {}
SegTree.updateAll = function(self)
  for i = self.stagenum - 1, 1, -1 do
    for j = 1, self.cnt[i] do
      self.stage[i][j] = false
    end
  end
end
SegTree.create = function(self, n)
  local stagenum, mul = 1, 1
  self.cnt, self.stage = {1}, {{}}
  while mul < n do
    mul, stagenum = mul * 2, stagenum + 1
    self.cnt[stagenum], self.stage[stagenum] = mul, {}
  end
  self.stagenum = stagenum
  for i = 1, mul do self.stage[stagenum][i] = false end
  self:updateAll()
end
SegTree.getRange = function(self, left, right)
  if left == right then return self.stage[self.stagenum][left] end
  local stagenum = self.stagenum
  local ret = false
  while true do
    local stage = 1
    local sz = bls(1, stagenum - stage)
    local len = right + 1 - left
    while (left - 1) % sz ~= 0 or len < sz do
      stage = stage + 1
      sz = brs(sz, 1)
    end
    ret = ret or self.stage[stage][1 + brs(left - 1, stagenum - stage)]
    left = left + sz
    if right < left then break end
  end
  return ret
end
SegTree.setValue = function(self, idx, value)
  self.stage[self.stagenum][idx] = value
  for i = self.stagenum - 1, 1, -1 do
    local dst = brs(idx + 1, 1)
    local rem = dst * 4 - 1 - idx
    self.stage[i][dst] = self.stage[i + 1][idx] or self.stage[i + 1][rem]
    idx = dst
  end
end
SegTree.new = function(n, func, emptyvalue)
  local obj = {}
  setmetatable(obj, {__index = SegTree})
  obj:create(n, func, emptyvalue)
  return obj
end

local n = io.read("*n", "*l")
local s = io.read()
local q = io.read("*n", "*l")
local sts = {}
local t = {}
for i = 1, 26 do
  sts[i] = SegTree.new(n, function(a, b) return a or b end, false)
end
for i = 1, n do
  t[i] = s:sub(i, i):byte() - 96
  sts[t[i]]:setValue(i, true)
end

for iq = 1, q do
  local iqstr = io.read()
  local ic = iqstr:sub(1, 1)
  if ic == "1" then
    local i, cs = iqstr:match("%d (%d+) (%w)")
    i = tonumber(i)
    local c = cs:byte() - 96
    if t[i] ~= c then
      sts[t[i]]:setValue(i, false)
      t[i] = c
      sts[c]:setValue(i, true)
    end
  else
    local l, r = iqstr:match("%d (%d+) (%d+)")
    l, r = tonumber(l), tonumber(r)
    local cnt = 0
    for i = 1, 26 do
      if sts[i]:getRange(l, r) then cnt = cnt + 1 end
    end
    print(cnt)
  end
end