Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in Lua (Lua 5.3.5) (judge verdict: Wrong Answer)

local n = io.read("*n")
local a = io.read("*n")
local b = io.read("*n")
local c = io.read("*n")
local d = io.read("*n")
io.read("*l")
local s = io.read("*l")
local empty = string.byte(".", 1)
local rock = string.byte("#", 1)
if a > b then
	a, b = b, a
	c, d = d, c
end
local threeempty = false
for i = 1, math.max(c, d) do 
	if a < i and i < c and string.byte(s, i) == rock and string.byte(s, i + 1) == rock then
		print("No")
		return
	end
	if b < i and i < d and string.byte(s, i) == rock and string.byte(s, i + 1) == rock then
		print("No")
		return
	end
	if b <= i and i <= d and i + 2 <= n and string.byte(s, i) == empty and string.byte(s, i + 1) == empty and string.byte(s, i + 2) == empty then
		threeempty = true
	end
end

if d < c then
	if not threeempty then
		print('No')
		return
	end
end
print("Yes")