Problem:
Score : 200 points

Problem Statement

Rng is preparing a problem set for a qualification round of CODEFESTIVAL.

He has N candidates of problems. The difficulty of the i-th candidate is D_i.

There must be M problems in the problem set, and the difficulty of the i-th problem must be T_i. Here, one candidate of a problem cannot be used as multiple problems.

Determine whether Rng can complete the problem set without creating new candidates of problems.

Constraints

1 \leq N \leq 200,000

1 \leq D_i \leq 10^9

1 \leq M \leq 200,000

1 \leq T_i \leq 10^9

All numbers in the input are integers.

Partial Score

100 points will be awarded for passing the test set satisfying N \leq 100 and M \leq 100.

Input

Input is given from Standard Input in the following format:

N
D_1 D_2 ... D_N
M
T_1 T_2 ... T_M

Output

Print YES if Rng can complete the problem set without creating new candidates of problems; print NO if he cannot.

Sample Input 1

5
3 1 4 1 5
3
5 4 3

Sample Output 1

YES

Sample Input 2

7
100 200 500 700 1200 1600 2000
6
100 200 500 700 1600 1600

Sample Output 2

NO

Not enough 1600s.

Sample Input 3

1
800
5
100 100 100 100 100

Sample Output 3

NO

Sample Input 4

15
1 2 2 3 3 3 4 4 4 4 5 5 5 5 5
9
5 4 3 2 1 2 3 4 5

Sample Output 4

YES

Solution in Lua (5.3.2) (judge verdict: Accepted)

local n=io.read("*n","*l")
local d={}
for i=1,n do
    local x=io.read("*n")
    if not d[x] then
        d[x]=1
    else
        d[x]=d[x]+1
    end
end
local m=io.read("*n","*l")
local t={}
for i=1,m do
    local y=io.read("*n")
    if not t[y] then
        t[y]=1
    else
        t[y]=t[y]+1
    end
end

checker=true
for i,_ in pairs(t) do
    if d[i] then
        if t[i]>d[i] then
            checker=false
        end
    else
        checker=false
    end
end
print(checker and "YES" or "NO")