Problem:
Score: 300 points

Problem Statement

In Republic of Atcoder, there are N prefectures, and a total of M cities that belong to those prefectures.

City i is established in year Y_i and belongs to Prefecture P_i.

You can assume that there are no multiple cities that are established in the same year.

It is decided to allocate a 12-digit ID number to each city.

If City i is the x-th established city among the cities that belong to Prefecture i, the first six digits of the ID number of City i is P_i, and the last six digits of the ID number is x.

Here, if P_i or x (or both) has less than six digits, zeros are added to the left until it has six digits.

Find the ID numbers for all the cities.

Note that there can be a prefecture with no cities.

Constraints

1 \leq N \leq 10^5

1 \leq M \leq 10^5

1 \leq P_i \leq N

1 \leq Y_i \leq 10^9

Y_i are all different.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M
P_1 Y_1
:
P_M Y_M

Output

Print the ID numbers for all the cities, in ascending order of indices (City 1, City 2, ...).

Sample Input 1

2 3
1 32
2 63
1 12

Sample Output 1

000001000002
000002000001
000001000001

As City 1 is the second established city among the cities that belong to Prefecture 1, its ID number is 000001000002.

As City 2 is the first established city among the cities that belong to Prefecture 2, its ID number is 000002000001.

As City 3 is the first established city among the cities that belong to Prefecture 1, its ID number is 000001000001.

Sample Input 2

2 3
2 55
2 77
2 99

Sample Output 2

000002000001
000002000002
000002000003

Solution in Lua (5.3.2) (judge verdict: Wrong Answer)

function read()
    return io.read("*num")
end
n = read()
m = read()
a = {}
for i = 1, m do
    p = read()
    y = read()
    a[i] = {p = p, y = y, id = i}
end
table.sort(a, function(A, B)
                return A.y < B.y
            end)

a[1].c = 1
b = {}
for i = 2, m do
    if a[i].y > a[i - 1].y then
        a[i].c = a[i - 1].c + 1
    else
        a[i].c = a[i - 1].c
    end
end

for i = 1, m do
    b[a[i].id] = a[i]
end

for i = 1, m do
    str = string.format("%06d%06d", b[i].p, b[i].c)
    print(str)
end