Problem:
Score : 200 points

Problem Statement

Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Constraints

1 \leq N \leq 10^4

1 \leq A \leq B \leq 36

All input values are integers.

Input

Input is given from Standard Input in the following format:

N A B

Output

Print the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Sample Input 1

20 2 5

Sample Output 1

84

Among the integers not greater than 20, the ones whose sums of digits are between 2 and 5, are: 2,3,4,5,11,12,13,14 and 20. We should print the sum of these, 84.

Sample Input 2

10 1 2

Sample Output 2

13

Sample Input 3

100 4 16

Sample Output 3

4554

Solution in LuaJIT (2.0.4) (judge verdict: Wrong Answer)

local function sumDigits(num)
    local sum = 0
    while num > 0 do
        sum = sum + num % 10
        num = math.modf(num / 10)
    end
    return sum
end

local N, A, B = io.read("*n", "*n", "*n")
local total = 0
for i = 1, N do
    local sum = sumDigits(i)
    if sum >= A and sum <= B then
        total = total + 1
    end
end
print(total)