Problem:
Score : 400 points

Problem Statement

Given is a string S consisting of digits from 1 through 9.

Find the number of pairs of integers (i,j) (1 ≤ i ≤ j ≤ |S|) that satisfy the following condition:

Condition: In base ten, the i-th through j-th characters of S form an integer that is a multiple of 2019.

Constraints

1 ≤ |S| ≤ 200000

S is a string consisting of digits from 1 through 9.

Input

Input is given from Standard Input in the following format:

S

Output

Print the number of pairs of integers (i,j) (1 ≤ i ≤ j ≤ |S|) that satisfy the condition.

Sample Input 1

1817181712114

Sample Output 1

3

Three pairs - (1,5), (5,9), and (9,13) - satisfy the condition.

Sample Input 2

14282668646

Sample Output 2

2

Sample Input 3

2119

Sample Output 3

0

No pairs satisfy the condition.

Solution in Lua (Lua 5.3.5) (judge verdict: Accepted)

local s=io.read()
local n=#s
local p=2019

local t={}
for i=1,p do
    t[i]=(i==1 and 1 or 0)
end

local combination=0
local digit=1
local smod=0
for i=n,1,-1 do
    local x=tonumber(s:sub(i,i))
    smod=(smod+x*digit)%p
    combination=combination+t[smod+1]
    t[smod+1]=t[smod+1]+1
    digit=(digit*10)%p
end
print(combination)