Problem:
Score : 600 points

Problem Statement

You are given an integer sequence of length N, a = {a_1, a_2, …, a_N}, and an integer K.

a has N(N+1)/2 non-empty contiguous subsequences, {a_l, a_{l+1}, …, a_r} (1 ≤ l ≤ r ≤ N). Among them, how many have an arithmetic mean that is greater than or equal to K?

Constraints

All input values are integers.

1 ≤ N ≤ 2 \times 10^5

1 ≤ K ≤ 10^9

1 ≤ a_i ≤ 10^9

Input

Input is given from Standard Input in the following format:

N K
a_1
a_2
:
a_N

Output

Print the number of the non-empty contiguous subsequences with an arithmetic mean that is greater than or equal to K.

Sample Input 1

3 6
7
5
7

Sample Output 1

5

All the non-empty contiguous subsequences of a are listed below:

{a_1} = {7}

{a_1, a_2} = {7, 5}

{a_1, a_2, a_3} = {7, 5, 7}

{a_2} = {5}

{a_2, a_3} = {5, 7}

{a_3} = {7}

Their means are 7, 6, 19/3, 5, 6 and 7, respectively, and five among them are 6 or greater. Note that {a_1} and {a_3} are indistinguishable by the values of their elements, but we count them individually.

Sample Input 2

1 2
1

Sample Output 2

0

Sample Input 3

7 26
10
20
30
40
30
20
10

Sample Output 3

13

Solution in LuaJIT (2.0.4) (judge verdict: Accepted)

local mfl, mce, mmi = math.floor, math.ceil, math.min
local SegTree = {}
SegTree.updateAll = function(self)
  for i = self.stagenum - 1, 1, -1 do
    for j = 1, self.cnt[i] do
      self.stage[i][j] = self.stage[i + 1][j * 2 - 1] + self.stage[i + 1][j * 2]
    end
  end
end
SegTree.create = function(self, n)
  self.emptyvalue = 0
  local stagenum, mul = 1, 1
  self.cnt, self.stage, self.size = {1}, {{}}, {}
  while mul < n do
    mul, stagenum = mul * 2, stagenum + 1
    self.cnt[stagenum], self.stage[stagenum] = mul, {}
  end
  for i = 1, stagenum do self.size[i] = self.cnt[stagenum + 1 - i] end
  self.stagenum = stagenum
  for i = 1, mul do self.stage[stagenum][i] = 0 end
  self:updateAll()
end
SegTree.getRange = function(self, left, right)
  if left == right then return self.stage[self.stagenum][left] end
  local start_stage, mul = 1, 1
  while right - left + 1 < self.size[start_stage] do
    start_stage = start_stage + 1
  end
  local ret = self.emptyvalue
  local tasks = {{start_stage, left, right}}
  local done = 0
  while done < #tasks do
    done = done + 1
    local task = tasks[done]
    local stage, l, r = task[1], task[2], task[3]
    local sz = self.size[stage]
    if (l - 1) % sz ~= 0 then
      local newr = mce((l - 1) / sz) * sz
      table.insert(tasks, {stage + 1, l, mmi(r, newr)})
      l = newr + 1
    end
    if sz <= r + 1 - l then
      local pos = mce(l / sz)
      ret = ret + self.stage[stage][pos]
      l = l + sz
    end
    if l <= r then
      table.insert(tasks, {stage + 1, l, r})
    end
  end
  return ret
end
SegTree.decValue = function(self, idx)
  self.stage[self.stagenum][idx] = self.stage[self.stagenum][idx] - 1
  for i = self.stagenum - 1, 1, -1 do
    local dst = mce(idx / 2)
    local rem = dst * 4 - 1 - idx
    self.stage[i][dst] = self.stage[i + 1][idx] + self.stage[i + 1][rem]
    idx = dst
  end
end
SegTree.inc = function(self, idx)
  self.stage[self.stagenum][idx] = 1 + self.stage[self.stagenum][idx]
end
SegTree.new = function(n)
  local obj = {}
  setmetatable(obj, {__index = SegTree})
  obj:create(n)
  return obj
end

local n, k = io.read("*n", "*n")
local sum, tmp, conv = {}, {}, {}
sum[1] = io.read("*n") - k
for i = 2, n do
  sum[i] = sum[i - 1] + io.read("*n") - k
end
sum[n + 1] = 0
for i = 1, n + 1 do tmp[i] = sum[i] end
table.sort(tmp)
local sumTypeCount = 1
local sumTypeList = {}
conv[tmp[1]] = 1
sumTypeList[1] = tmp[1]
for i = 2, n + 1 do
  if tmp[i] ~= sumTypeList[sumTypeCount] then
    sumTypeCount = sumTypeCount + 1
    conv[tmp[i]] = sumTypeCount
    sumTypeList[sumTypeCount] = tmp[i]
  end
end
local segtree = SegTree.new(sumTypeCount)
for i = 1, n do
  segtree:inc(conv[sum[i]])
end
segtree:updateAll()
local bias = 0
local cnt = 0
for i = 1, n do
  cnt = cnt + segtree:getRange(conv[bias], sumTypeCount)
  segtree:decValue(conv[sum[i]])
  bias = sum[i]
end
print(cnt)