Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in Lua (LuaJIT 2.1.0) (judge verdict: Wrong Answer)

N=io.read"*n"
A=io.read"*n"
B=io.read"*n"
C=io.read"*n"
io.read()
s={}
for i=1,N do
	table.insert(s,io.read())
end

r={}
for i=1,N do
	if(s[i]=="AB")then
		if(A==0 and B==0)then
			print("No") return
		end
		if(A<B)then A=A+1 B=B-1 table.insert(r,"A")
		else A=A-1 B=B+1 table.insert(r,"B")end
	elseif(s[i]=="AC")then
		if(A==0 and C==0)then
			print("No") return
		end
		if(A<C)then A=A+1 C=C-1 table.insert(r,"A")
		else A=A-1 C=C+1 table.insert(r,"C")end
	else
		if(B==0 and C==0)then
			print("No") return
		end
		if(B<C)then B=B+1 C=C-1 table.insert(r,"B")
		else B=B-1 C=C+1 table.insert(r,"C")end
	end
end
print("Yes")
for _,v in ipairs(r)do
print(v)
end