Problem:
Score : 400 points

Problem Statement

Takahashi has N sticks that are distinguishable from each other. The length of the i-th stick is L_i.

He is going to form a triangle using three of these sticks. Let a, b, and c be the lengths of the three sticks used. Here, all of the following conditions must be satisfied:

a < b + c

b < c + a

c < a + b

How many different triangles can be formed? Two triangles are considered different when there is a stick used in only one of them.

Constraints

All values in input are integers.

3 \leq N \leq 2 \times 10^3

1 \leq L_i \leq 10^3

Input

Input is given from Standard Input in the following format:

N
L_1 L_2 ... L_N

Constraints

Print the number of different triangles that can be formed.

Sample Input 1

4
3 4 2 1

Sample Output 1

1

Only one triangle can be formed: the triangle formed by the first, second, and third sticks.

Sample Input 2

3
1 1000 1

Sample Output 2

0

No triangles can be formed.

Sample Input 3

7
218 786 704 233 645 728 389

Sample Output 3

23

Solution in Lua (5.3.2) (judge verdict: Time Limit Exceeded)

local read = setmetatable({}, {__index = function(t, k) local a = {} for i=1,#k do table.insert(a, '*'..string.sub(k, i, i)) end local r = io.read local u = table.unpack or unpack return function() return r(u(a)) end end})
read.N = function(N) local t={} for i=1,N do t[i]=read.n() end return t end
string.totable = function(s) local t={} local u=string.sub for i=1,#s do t[i] = u(s, i, i) end return t end
string.split = function(s) local t={} for w in string.gmatch(s, "[^%s]+") do table.insert(t, w) end return (table.unpack or unpack)(t) end
--
-- 1 <= input to f <= n
local function find_min_true(n, f)
    local function loop(i, j)
        if i == j then
            assert(i >= 1 and i <= n + 1)
            return i
        end
        local h = (i + j) // 2
        assert(h >= 1 and h <= n)
        if f(h) then
            return loop(i, h)
        else
            return loop(h + 1, j)
        end
    end
    return loop(1, n + 1)
end
--
local N = read.n()
local L = read.N(N)
table.sort(L)
local ans = 0
for i=1,N-2 do
    local a = L[i]
    for j=i+1,N-1 do
        local b = L[j]
        local function count()
            local function f(x)
                x = x + j -- [1,N-j] --> [j+1,N]
                local c = L[x]
                return c >= a + b
            end
            return find_min_true(N-j, f) - 1
        end
        ans = ans + count()
    end
end
print(ans)