Problem:
Score : 400 points

Problem Statement

Given are integers A, B, and N.

Find the maximum possible value of floor(Ax/B) - A × floor(x/B) for a non-negative integer x not greater than N.

Here floor(t) denotes the greatest integer not greater than the real number t.

Constraints

1 ≤ A ≤ 10^{6}

1 ≤ B ≤ 10^{12}

1 ≤ N ≤ 10^{12}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B N

Output

Print the maximum possible value of floor(Ax/B) - A × floor(x/B) for a non-negative integer x not greater than N, as an integer.

Sample Input 1

5 7 4

Sample Output 1

2

When x=3, floor(Ax/B)-A×floor(x/B) = floor(15/7) - 5×floor(3/7) = 2. This is the maximum value possible.

Sample Input 2

11 10 9

Sample Output 2

9

Solution in Lua (Lua 5.3.5) (judge verdict: Time Limit Exceeded)

A,B,N = string.match(io.read(), "(%d+) (%d+) (%d+)")
A,B,N = tonumber(A), tonumber(B), tonumber(N)

max = 0
for x = 0, N, 1 do
	tmp = math.floor((A*x)/B) - A * math.floor(x/B)
	if tmp > max then
		max = tmp
	end
end

print(max)