Problem:
Score : 200 points

Problem Statement

When Mr. X is away from home, he has decided to use his smartwatch to search the best route to go back home, to participate in ABC.

You, the smartwatch, has found N routes to his home.

If Mr. X uses the i-th of these routes, he will get home in time t_i at cost c_i.

Find the smallest cost of a route that takes not longer than time T.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq T \leq 1000

1 \leq c_i \leq 1000

1 \leq t_i \leq 1000

The pairs (c_i, t_i) are distinct.

Input

Input is given from Standard Input in the following format:

N T
c_1 t_1
c_2 t_2
:
c_N t_N

Output

Print the smallest cost of a route that takes not longer than time T.

If there is no route that takes not longer than time T, print TLE instead.

Sample Input 1

3 70
7 60
1 80
4 50

Sample Output 1

4

The first route gets him home at cost 7.

The second route takes longer than time T = 70.

The third route gets him home at cost 4.

Thus, the cost 4 of the third route is the minimum.

Sample Input 2

4 3
1 1000
2 4
3 1000
4 500

Sample Output 2

TLE

There is no route that takes not longer than time T = 3.

Sample Input 3

5 9
25 8
5 9
4 10
1000 1000
6 1

Sample Output 3

5

Solution in Lua (5.3.2) (judge verdict: Accepted)

local n, t = string.match(io.read(), "(%d+) (%d+)")
local na, ta = string.match(io.read(), "(%d+) (%d+)")
n, t = tonumber(n), tonumber(t)
na, ta = tonumber(na), tonumber(ta)

local min = {
    n = na,
    t = ta,
}

for i = 2, n do
    na, ta = string.match(io.read(), "(%d+) (%d+)")
    na, ta = tonumber(na), tonumber(ta)

    if ta <= t and na < min.n then
        min.n = na
        min.t = ta
    end
end

if t < min.t then
    print("TLE")
else
    print(min.n)
end