Problem:
Score: 100 points

Problem Statement

In AtCoder Kingdom, Gregorian calendar is used, and dates are written in the "year-month-day" order, or the "month-day" order without the year.

For example, May 3, 2018 is written as 2018-5-3, or 5-3 without the year.

In this country, a date is called Takahashi when the month and the day are equal as numbers. For example, 5-5 is Takahashi.

How many days from 2018-1-1 through 2018-a-b are Takahashi?

Constraints

a is an integer between 1 and 12 (inclusive).

b is an integer between 1 and 31 (inclusive).

2018-a-b is a valid date in Gregorian calendar.

Input

Input is given from Standard Input in the following format:

a b

Output

Print the number of days from 2018-1-1 through 2018-a-b that are Takahashi.

Sample Input 1

5 5

Sample Output 1

5

There are five days that are Takahashi: 1-1, 2-2, 3-3, 4-4 and 5-5.

Sample Input 2

2 1

Sample Output 2

1

There is only one day that is Takahashi: 1-1.

Sample Input 3

11 30

Sample Output 3

11

There are eleven days that are Takahashi: 1-1, 2-2, 3-3, 4-4, 5-5, 6-6, 7-7, 8-8, 9-9, 10-10 and 11-11.

Solution in Common Lisp (SBCL 1.1.14) (judge verdict: Accepted)

(defun split-string (str)                                                                     
  (let ((string-position (position #\Space str)))
    (cond
      ((null string-position) (list str))
      (t (cons (subseq str 0 string-position) (split-string (subseq str (1+ string-position)))))
      )))

(defun readline-to-list ()
  (let ((str (read-line *standard-input* nil)))
    (cond
      ((null str) nil)
      ((string= str "") nil)
      (t (cons str (readline-to-list))))))


(defun takahashi (a b)
  (let ((result (+ (parse-integer a) (if (>= (parse-integer b) (parse-integer a)) 0 -1))))
    (format t "~A~%" result)))

(apply #'takahashi (split-string (read-line)))