Problem:
Score: 600 points

Problem Statement

We have N non-negative integers: A_1, A_2, ..., A_N.

Consider painting at least one and at most N-1 integers among them in red, and painting the rest in blue.

Let the beauty of the painting be the \mbox{XOR} of the integers painted in red, plus the \mbox{XOR} of the integers painted in blue.

Find the maximum possible beauty of the painting.

What is \mbox{XOR}?

The bitwise \mbox{XOR} x_1 \oplus x_2 \oplus \ldots \oplus x_n of n non-negative integers x_1, x_2, \ldots, x_n is defined as follows:

When x_1 \oplus x_2 \oplus \ldots \oplus x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.

For example, 3 \oplus 5 = 6.

Constraints

All values in input are integers.

2 \leq N \leq 10^5

0 \leq A_i < 2^{60}\ (1 \leq i \leq N)

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

Print the maximum possible beauty of the painting.

Sample Input 1

3
3 6 5

Sample Output 1

12

If we paint 3, 6, 5 in blue, red, blue, respectively, the beauty will be (6) + (3 \oplus 5) = 12.

There is no way to paint the integers resulting in greater beauty than 12, so the answer is 12.

Sample Input 2

4
23 36 66 65

Sample Output 2

188

Sample Input 3

20
1008288677408720767 539403903321871999 1044301017184589821 215886900497862655 504277496111605629 972104334925272829 792625803473366909 972333547668684797 467386965442856573 755861732751878143 1151846447448561405 467257771752201853 683930041385277311 432010719984459389 319104378117934975 611451291444233983 647509226592964607 251832107792119421 827811265410084479 864032478037725181

Sample Output 3

2012721721873704572

A_i and the answer may not fit into a 32-bit integer type.

Solution in Common Lisp (SBCL 1.1.14) (judge verdict: Runtime Error)

;; -*- coding: utf-8 -*-
(eval-when (:compile-toplevel :load-toplevel :execute)
  (sb-int:defconstant-eqx OPT
    #+swank '(optimize (speed 3) (safety 2))
    #-swank '(optimize (speed 3) (safety 0) (debug 0))
    #'equal)
  #+swank (ql:quickload '(:cl-debug-print :fiveam) :silent t)
  #-swank (set-dispatch-macro-character
           #\# #\> (lambda (s c p) (declare (ignore c p)) (read s nil nil t))))
#+swank (cl-syntax:use-syntax cl-debug-print:debug-print-syntax)
#-swank (disable-debugger) ; for CS Academy

;; BEGIN_INSERTED_CONTENTS
(declaim (inline shuffle!))
(defun shuffle! (vector)
  "Destructively shuffles VECTOR by Fisher-Yates algorithm."
  (declare (vector vector))
  (loop for i from (- (length vector) 1) above 0
        for j = (random (+ i 1))
        do (rotatef (aref vector i) (aref vector j)))
  vector)

;;;
;;; 1-dimensional binary indexed tree on arbitrary commutative monoid
;;;

(defmacro define-int-types (&rest bits)
  `(progn
     ,@(mapcar (lambda (b) `(deftype ,(intern (format nil "UINT~A" b)) () '(unsigned-byte ,b))) bits)
     ,@(mapcar (lambda (b) `(deftype ,(intern (format nil "INT~A" b)) () '(signed-byte ,b))) bits)))
(define-int-types 2 4 7 8 15 16 31 32 62 63 64)

(declaim (ftype (function * (values fixnum &optional)) read-fixnum))
(defun read-fixnum (&optional (in *standard-input*))
  (declare #.OPT)
  (macrolet ((%read-byte ()
               `(the (unsigned-byte 8)
                     #+swank (char-code (read-char in nil #\Nul))
                     #-swank (sb-impl::ansi-stream-read-byte in nil #.(char-code #\Nul) nil))))
    (let* ((minus nil)
           (result (loop (let ((byte (%read-byte)))
                           (cond ((<= 48 byte 57)
                                  (return (- byte 48)))
                                 ((zerop byte) ; #\Nul
                                  (error "Read EOF or #\Nul."))
                                 ((= byte #.(char-code #\-))
                                  (setf minus t)))))))
      (declare ((integer 0 #.most-positive-fixnum) result))
      (loop
        (let* ((byte (%read-byte)))
          (if (<= 48 byte 57)
              (setq result (+ (- byte 48)
                              (* 10 (the (integer 0 #.(floor most-positive-fixnum 10)) result))))
              (return (if minus (- result) result))))))))

(defmacro dbg (&rest forms)
  #+swank
  (if (= (length forms) 1)
      `(format *error-output* "~A => ~A~%" ',(car forms) ,(car forms))
      `(format *error-output* "~A => ~A~%" ',forms `(,,@forms)))
  #-swank (declare (ignore forms)))

(declaim (inline println))
(defun println (obj &optional (stream *standard-output*))
  (let ((*read-default-float-format* 'double-float))
    (prog1 (princ obj stream) (terpri stream))))

(defconstant +mod+ 1000000007)

;;;
;;; Body
;;;

(defconstant +time-limit+ 1.82f0)

(defun main ()
  (declare #.OPT)
  (let* ((n (read))
         (as (make-array n :element-type 'uint62)))
    (declare (uint32 n))
    (dotimes (i n)
      (setf (aref as i) (read-fixnum)))
    (shuffle! as)
    (let ((rxor 0)
          (totalxor (reduce #'logxor as))
          (max-temp (float (sb-int:power-of-two-ceiling (reduce #'max as)) 1f0)))
      (declare (uint62 rxor totalxor)
               (single-float max-temp))
      (dotimes (i n)
        (when (evenp i)
          (setq rxor (logxor rxor (aref as i)))))
      (let ((res (+ rxor (logxor totalxor rxor))))
        (declare (uint62 res))
        (sb-int:with-progressive-timeout (get-remaining-time :seconds +time-limit+)
          (dotimes (_ most-positive-fixnum)
            (let ((remaining-time (get-remaining-time)))
              (when (eq 0 (get-remaining-time))
                (println res)
                (return-from main))
              (let* ((ratio (* (the single-float remaining-time) #.(/ +time-limit+)))
                     (temp (+ 1f0 (* max-temp ratio))))
                (declare (single-float temp))
                (dotimes (_ 5000)
                  (let* ((idx (random n))
                         (old-val (+ rxor (logxor totalxor rxor)))
                         (new-rxor (logxor rxor (aref as idx)))
                         (new-val (+ new-rxor (logxor totalxor new-rxor)))
                         (prob (exp (/ (- new-val old-val) temp))))
                    (declare (uint62 old-val new-val)
                             (single-float prob))
                    (when (< (random 1f0) prob)
                      (setq res (max res new-val)
                            rxor new-rxor))))))))))))

#-swank (main)