Problem:
Score : 300 points

Problem Statement

In Takahashi Kingdom, there is an archipelago of N islands, called Takahashi Islands.
For convenience, we will call them Island 1, Island 2, ..., Island N.

There are M kinds of regular boat services between these islands.
Each service connects two islands. The i-th service connects Island a_i and Island b_i.

Cat Snuke is on Island 1 now, and wants to go to Island N.
However, it turned out that there is no boat service from Island 1 to Island N, so he wants to know whether it is possible to go to Island N by using two boat services.

Help him.

Constraints

3 ≤ N ≤ 200 000

1 ≤ M ≤ 200 000

1 ≤ a_i < b_i ≤ N

(a_i, b_i) \neq (1, N)

If i \neq j, (a_i, b_i) \neq (a_j, b_j).

Input

Input is given from Standard Input in the following format:

N M
a_1 b_1
a_2 b_2
:
a_M b_M

Output

If it is possible to go to Island N by using two boat services, print POSSIBLE; otherwise, print IMPOSSIBLE.

Sample Input 1

3 2
1 2
2 3

Sample Output 1

POSSIBLE

Sample Input 2

4 3
1 2
2 3
3 4

Sample Output 2

IMPOSSIBLE

You have to use three boat services to get to Island 4.

Sample Input 3

100000 1
1 99999

Sample Output 3

IMPOSSIBLE

Sample Input 4

5 5
1 3
4 5
2 3
2 4
1 4

Sample Output 4

POSSIBLE

You can get to Island 5 by using two boat services: Island 1 -> Island 4 -> Island 5.

Solution in Common Lisp (SBCL 1.1.14) (judge verdict: Time Limit Exceeded)

(declaim (optimize (speed 3) (debug 0) (safety 0)))
(let* ((n (read))
       (m (read))
       (e (loop for i below m
                collect (cons (read) (read))))
       (n1 (mapcan (lambda (x)
                     (cond ((= 1 (car x)) (list (cdr x)))
                           ((= 1 (cdr x)) (list (car x)))
                           (t nil)))
                   e))
       (nn (mapcan (lambda (x)
                     (cond ((= n (car x)) (list (cdr x)))
                           ((= n (cdr x)) (list (car x)))
                           (t nil)))
                   e)))
  (format t "~A~%" (if (find-if (lambda (x)
                                  (find-if (lambda (y)
                                             (= x y))
                                           nn))
                                n1)
                       'POSSIBLE
                       'IMPOSSIBLE)))