Problem:
Score : 200 points

Problem Statement

Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print -1 instead.

Constraints

2 \leq N \leq 10^5

0 \leq A_i \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the value A_1 \times ... \times A_N as an integer, or -1 if the value exceeds 10^{18}.

Sample Input 1

2
1000000000 1000000000

Sample Output 1

1000000000000000000

We have 1000000000 \times 1000000000 = 1000000000000000000.

Sample Input 2

3
101 9901 999999000001

Sample Output 2

-1

We have 101 \times 9901 \times 999999000001 = 1000000000000000001, which exceeds 10^{18}, so we should print -1 instead.

Sample Input 3

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0

Sample Output 3

0

Solution in Common Lisp (SBCL 2.0.3) (judge verdict: Accepted)

(defun App (n)
    (let ((ans 1)
        (a Nil))

    (loop for i below n
        do (push (read) a)
    )

    (setf a (sort a #'<))

    (loop for i in a
        do (progn
            (if (and (= ans 0))
            (return)
            (progn (setf ans (* ans i))
                (if (> ans 1000000000000000000)
                (progn 
                    (setq ans -1)
                    (return)
                )
                )
            )
            )
        )
    )   
    ans)
)
(format t "~D~%" (App (read)))