Problem:
Score : 200 points

Problem Statement

Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print -1 instead.

Constraints

2 \leq N \leq 10^5

0 \leq A_i \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the value A_1 \times ... \times A_N as an integer, or -1 if the value exceeds 10^{18}.

Sample Input 1

2
1000000000 1000000000

Sample Output 1

1000000000000000000

We have 1000000000 \times 1000000000 = 1000000000000000000.

Sample Input 2

3
101 9901 999999000001

Sample Output 2

-1

We have 101 \times 9901 \times 999999000001 = 1000000000000000001, which exceeds 10^{18}, so we should print -1 instead.

Sample Input 3

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0

Sample Output 3

0

Solution in Common Lisp (SBCL 2.0.3) (judge verdict: Wrong Answer)

(defun splitat (c line)
  (labels ((rec (line acc)
				(let ((pos (position-if (lambda(cc) (char= c cc)) line)))
				  (if pos
					  (rec (subseq line (1+ pos)) (cons (subseq line 0 pos) acc))
					(nreverse (cons line acc))))))
	(rec line nil)))

(defun f(lst n)
  (labels ((rec(lst acc n)
             (if (null lst)
               (if (<= acc (expt 10 18)) acc -1)
               (if (<= acc (expt 10 18))
                 (rec (cdr lst) (* (car lst) acc) (1- n))
                 -1))))
    (rec lst 1 n)))
(compile 'f)
(let ((line0 (parse-integer (read-line nil nil)))
      (line (mapcar #'parse-integer (splitat #\space (read-line nil nil)))))
      (format t "~A~%" (f line line0)))