Problem:
Score : 100 points

Problem Statement

Given is an integer N.

Takahashi chooses an integer a from the positive integers not greater than N with equal probability.

Find the probability that a is odd.

Constraints

1 \leq N \leq 100

Input

Input is given from Standard Input in the following format:

N

Output

Print the probability that a is odd.
Your output will be considered correct when its absolute or relative error from the judge's output is at most 10^{-6}.

Sample Input 1

4

Sample Output 1

0.5000000000

There are four positive integers not greater than 4: 1, 2, 3, and 4. Among them, we have two odd numbers: 1 and 3. Thus, the answer is \frac{2}{4} = 0.5.

Sample Input 2

5

Sample Output 2

0.6000000000

Sample Input 3

1

Sample Output 3

1.0000000000

Solution in Kotlin (1.0.0) (judge verdict: Wrong Answer)

import java.math.BigDecimal
import java.math.MathContext

fun main(args : Array<String>) {
    val result = Begginer20190928A.exec(readLine()!!.toInt())
    println(result)
}


object Begginer20190928A {
    fun exec(input : Int) : String {
        val isOdd = input % 2 == 1

        val oddCount = if (isOdd) {
            (input - 1) / 2 + 1
        } else {
            (input) / 2
        }

        println(oddCount)

        return BigDecimal(oddCount)
                .divide(BigDecimal(input), MathContext(10))
                .toString()
    }
}