Problem:
Max Score: 250 Points

Problem Statement

Mr.X, who the handle name is T, looked at the list which written N handle names, S_1, S_2, ..., S_N.

But he couldn't see some parts of the list. Invisible part is denoted ?.

Please calculate all possible index of the handle name of Mr.X when you sort N+1 handle names (S_1, S_2, ..., S_N and T) in lexicographical order.

Note: If there are pair of people with same handle name, either one may come first.

Input

The input is given from standard input in the following format.

N
S_1
S_2
:
S_N
T

Output

Calculate the possible index and print in sorted order. The output should be separated with a space. Don't print a space after last number.

Put a line break in the end.

Constraints

1 ≤ N ≤ 10000

1 ≤ |S_i|, |T| ≤ 20 (|A| is the length of A.)

S_i consists from lower-case alphabet and ?.

T consists from lower-case alphabet.

Scoring

Subtask 1 [ 130 points ]

There are no ?'s.

Subtask 2 [ 120 points ]

There are no additional constraints.

Sample Input 1

2
tourist
petr
e

Sample Output 1

1

There are no invisible part, so there are only one possibility.
The sorted handle names are e, petr, tourist, so e comes first.

Sample Input 2

2
?o?r?s?
?et?
e

Solution in Kotlin (1.0.0) (judge verdict: Wrong Answer)

fun main(args: Array<String>) = IO().exec {
    val n = int()
    val s = Array(n){string()}
    val t = string()
    var p = 0
    var q = 0
    for (u in s) {
        if (u == t) q++
        else if (!u.startsWith(t)) {
            var zflag = false
            for (j in Math.min(u.length, t.length)) {
                if (u[j] == '?') {
                    if (t[j] == 'z') {
                        zflag = true
                    } else {
                        q++
                        break
                    }
                } else if (u[j] < t[j]) {
                    p++
                    break
                } else if (u[j] > t[j]) {
                    if (zflag) q++
                    break
                }
            }
        }
    }
    println((p..p+q).map { it+1 }.joinToString(" "))
}

// region template
operator fun Int.iterator() = 0.until(this).iterator()

class IO {
    val printable = 33..126
    val buffer = ByteArray(1024)
    var ptr = 0
    var buflen = 0
    val out = java.io.PrintWriter(System.out)
    fun hasNextByte(): Boolean = if (ptr < buflen) true else {
        ptr = 0
        buflen = System.`in`.read(buffer)
        buflen > 0
    }

    fun readByte(): Byte = if (hasNextByte()) buffer[ptr++] else -1
    fun hasNext(): Boolean {
        while (hasNextByte() && buffer[ptr] !in printable) ptr++
        return hasNextByte()
    }

    fun string(): String {
        if (!hasNext()) throw java.util.NoSuchElementException()
        val sb = StringBuilder()
        var b = readByte()
        while (b in printable) {
            sb.appendCodePoint(b.toInt())
            b = readByte()
        }
        return sb.toString()
    }

    fun long(): Long {
        if (!hasNext()) throw java.util.NoSuchElementException()
        var n = 0L
        var minus = false
        var b = readByte()
        if (b == '-'.toByte()) {
            minus = true
            b = readByte()
        }
        if (b !in '0'.toByte()..'9'.toByte()) {
            throw NumberFormatException()
        }
        while (true) {
            if (b in '0'.toByte()..'9'.toByte()) {
                n *= 10
                n += b - '0'.toByte()
            } else if (b == (-1).toByte() || b !in printable) {
                return if (minus) -n else n
            } else {
                throw NumberFormatException()
            }
            b = readByte()
        }
    }

    fun int(): Int {
        val nl = long()
        if (nl !in Integer.MIN_VALUE..Integer.MAX_VALUE) throw NumberFormatException()
        return nl.toInt()
    }

    fun double(): Double = string().toDouble()
    fun print(obj: Any) = out.print(obj)
    fun print(i: Int) = out.print(i)
    fun print(l: Long) = out.print(l)
    fun println(obj: Any) = out.println(obj)
    fun println(i: Int) = out.println(i)
    fun println(l: Long) = out.println(l)
    inline fun exec(block: IO.() -> Unit) {
        block()
        out.flush()
    }
}
// endregion