Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in Kotlin (1.3.71) (judge verdict: Wrong Answer)

import kotlin.math.floor

fun main() {
    val n = readLine()?.toInt() ?: return
    1.until(3501).forEach { i ->
        1.until(3501).forEach { j ->
            val a = n / (4.0 * i) + n / (4.0 * j)
            if (a < 1.0) {
                val wv = 1.0 - a
                val w = n / (4.0 * wv)
                if (w == floor(w)) {
                    println("$i $j ${w.toInt()}")
                    return
                }
            }
        }
    }
}