Problem:
Score : 300 points

Problem Statement

A programming competition site AtCode provides algorithmic problems.
Each problem is allocated a score based on its difficulty.
Currently, for each integer i between 1 and D (inclusive), there are p_i problems with a score of 100i points.
These p_1 + … + p_D problems are all of the problems available on AtCode.

A user of AtCode has a value called total score.
The total score of a user is the sum of the following two elements:

Base score: the sum of the scores of all problems solved by the user.

Perfect bonuses: when a user solves all problems with a score of 100i points, he/she earns the perfect bonus of c_i points, aside from the base score (1 ≤ i ≤ D).

Takahashi, who is the new user of AtCode, has not solved any problem.
His objective is to have a total score of G or more points.
At least how many problems does he need to solve for this objective?

Constraints

1 ≤ D ≤ 10

1 ≤ p_i ≤ 100

100 ≤ c_i ≤ 10^6

100 ≤ G

All values in input are integers.

c_i and G are all multiples of 100.

It is possible to have a total score of G or more points.

Input

Input is given from Standard Input in the following format:

D G
p_1 c_1
:
p_D c_D

Output

Print the minimum number of problems that needs to be solved in order to have a total score of G or more points. Note that this objective is always achievable (see Constraints).

Sample Input 1

2 700
3 500
5 800

Sample Output 1

3

In this case, there are three problems each with 100 points and five problems each with 200 points. The perfect bonus for solving all the 100-point problems is 500 points, and the perfect bonus for solving all the 200-point problems is 800 points. Takahashi's objective is to have a total score of 700 points or more.

One way to achieve this objective is to solve four 200-point problems and earn a base score of 800 points. However, if we solve three 100-point problems, we can earn the perfect bonus of 500 points in addition to the base score of 300 points, for a total score of 800 points, and we can achieve the objective with fewer problems.

Sample Input 2

2 2000
3 500
5 800

Sample Output 2

7

This case is similar to Sample Input 1, but the Takahashi's objective this time is 2000 points or more. In this case, we inevitably need to solve all five 200-point problems, and by solving two 100-point problems additionally we have the total score of 2000 points.

Sample Input 3

2 400
3 500
5 800

Sample Output 3

2

This case is again similar to Sample Input 1, but the Takahashi's objective this time is 400 points or more. In this case, we only need to solve two 200-point problems to achieve the objective.

Sample Input 4

5 25000
20 1000
40 1000
50 1000
30 1000
1 1000

Sample Output 4

66

There is only one 500-point problem, but the perfect bonus can be earned even in such a case.

Solution in Kotlin (1.0.0) (judge verdict: Accepted)

fun main(args: Array<String>) {
    val (D, G) = readLine()!!.split(" ").map(String::toInt)
    val PCD = Array(D) { readLine()!!.split(" ").map(String::toInt).let { it[0] to it[1] } }
    val P = PCD.map(Pair<Int, Int>::first)
    val C = PCD.map(Pair<Int, Int>::second)

    var res = Long.MAX_VALUE
    // コンプリートボーナスの組み合わせをBit全探索する
    for (bit in 0..(1 shl D)) {
        var sum = 0L
        var num = 0L
        for (i in 0 until D) {
            if (bit and (1 shl i) > 0) {
                val p = P[i]
                val c = C[i]
                sum += c + p * 100 * (i + 1)
                num += p
            }
        }

        // コンプリートボーナスの組み合わせで総合スコアをG点以上にできていれば、比較して次へ
        if (sum >= G) {
            res = Math.min(res, num)
        } else {
            // 高得点から順に
            for (i in D - 1 downTo 0) {
                // コンプリートボーナスの組み合わせだったらスキップ
                if (bit and (1 shl i) > 0) {
                    continue
                }
                // コンプリートボーナスはもらわない
                for (j in 0 until P[i]) {
                    if (sum >= G) {
                        break
                    }
                    sum += 100 * (i + 1)
                    ++num
                }
            }
        }
        res = Math.min(res, num)
    }
    println(res)
}