Problem:
Score : 200 points

Problem Statement

A string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:

S is a palindrome.

Let N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.

The string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.

Determine whether S is a strong palindrome.

Constraints

S consists of lowercase English letters.

The length of S is an odd number between 3 and 99 (inclusive).

Input

Input is given from Standard Input in the following format:

S

Output

If S is a strong palindrome, print Yes;
otherwise, print No.

Sample Input 1

akasaka

Sample Output 1

Yes

S is akasaka.

The string formed by the 1-st through the 3-rd characters is aka.

The string formed by the 5-th through the 7-th characters is aka.
All of these are palindromes, so S is a strong palindrome.

Sample Input 2

level

Sample Output 2

No

Sample Input 3

atcoder

Sample Output 3

No

Solution in Kotlin (1.0.0) (judge verdict: Wrong Answer)

fun main(args: Array<String>) {
    var s= readLine()!!
    var l=s.length
    var lm=(l+1)/2
    var ll=(lm+1)/2
    var ls=Array(ll-1){' '}.toMutableList()
    var f=true
    for(i in 0 until ll-1){
        ls[i]=s[i]
        if(ls[i]!=s[l-1-i]){
            f=false
        }
        if(ls[i]!=s[lm-2-i]){
            f=false
        }
        if(ls[i]!=s[lm+i]){
            f=false
        }
    }
    if(f){
        println("Yes")
    }else{
        println("No")
    }

}