Problem:
Score : 300 points

Problem Statement

You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

1 \leq |S| \leq 2 \times 10^5

|S| = |T|

S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S and T can be made equal, print Yes; otherwise, print No.

Sample Input 1

azzel
apple

Sample Output 1

Yes

azzel can be changed to apple, as follows:

Choose e as c_1 and l as c_2. azzel becomes azzle.

Choose z as c_1 and p as c_2. azzle becomes apple.

Sample Input 2

chokudai
redcoder

Sample Output 2

No

No sequences of operation can change chokudai to redcoder.

Sample Input 3

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu

Sample Output 3

Yes

Solution in Kotlin (1.0.0) (judge verdict: Accepted)

fun main(args: Array<String>) {
    val s = readLine()!!
    val t = readLine()!!
    val sameMapS = mutableMapOf<Char, MutableList<Int>>()
    val sameMapT = mutableMapOf<Char, MutableList<Int>>()
    for (i in 0 until s.length) {
        if (sameMapS[s[i]] == null) sameMapS[s[i]] = mutableListOf(i) else sameMapS[s[i]]!!.add(i)
        if (sameMapT[t[i]] == null) sameMapT[t[i]] = mutableListOf(i) else sameMapT[t[i]]!!.add(i)
    }
    for (key in sameMapT.keys) {
        if (sameMapT[key]!!.size <= 1) continue
        var c = ""
        for (i in sameMapT[key]!!) {
            if (c != "" && s[i].toString() != c) {
                println("No")
                return
            }
            c = s[i].toString()
        }
    }
    for (key in sameMapS.keys) {
        if (sameMapS[key]!!.size <= 1) continue
        var c = ""
        for (i in sameMapS[key]!!) {
            if (c != "" && t[i].toString() != c) {
                println("No")
                return
            }
            c = t[i].toString()
        }
    }
    println("Yes")
}