Problem:
Score : 400 points

Problem Statement

Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.

You are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.

Constraints

2 ≦ |s| ≦ 10^5

s consists of lowercase letters.

Partial Score

200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.

Input

The input is given from Standard Input in the following format:

s

Output

If there exists no unbalanced substring of s, print -1 -1.

If there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.

Sample Input 1

needed

Sample Output 1

2 5

The string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.

Sample Input 2

atcoder

Sample Output 2

-1 -1

The string atcoder contains no unbalanced substring.

Solution in Kotlin (1.0.0) (judge verdict: Runtime Error)

fun main(args: Array<String>) {
    val s = readLine()!!

    fun containsDup(s: String) : Boolean {
        val map = hashMapOf<Char, Int>()
        s.forEach {
            map[it] = map.getOrElse(it, { 0 }) + 1
            if (map[it]!! > s.length / 2) {
                return true
            }
        }
        return false
    }

    var size = 2
    for (i in 0 until s.length - 1) {
        if (containsDup(
                        s.substring(i, i + size)
                )) {
            print(i + 1)
            print(' ')
            print(i + size)
            return
        }
    }

    size = 3
    for (i in 0 until s.length - 1) {
        if (containsDup(
                        s.substring(i, i + size)
                )) {
            print(i + 1)
            print(' ')
            print(i + size)
            return
        }
    }
    println("-1 -1")
}