Problem:
Score : 300 points

Problem Statement

You are given a sequence of length N: A_1, A_2, ..., A_N.
For each integer i between 1 and N (inclusive), answer the following question:

Find the maximum value among the N-1 elements other than A_i in the sequence.

Constraints

2 \leq N \leq 200000

1 \leq A_i \leq 200000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1
:
A_N

Output

Print N lines. The i-th line (1 \leq i \leq N) should contain the maximum value among the N-1 elements other than A_i in the sequence.

Sample Input 1

3
1
4
3

Sample Output 1

4
3
4

The maximum value among the two elements other than A_1, that is, A_2 = 4 and A_3 = 3, is 4.

The maximum value among the two elements other than A_2, that is, A_1 = 1 and A_3 = 3, is 3.

The maximum value among the two elements other than A_3, that is, A_1 = 1 and A_2 = 4, is 4.

Sample Input 2

2
5
5

Sample Output 2

5
5

Solution in Kotlin (1.0.0) (judge verdict: Accepted)

fun main(args: Array<String>) {
    val N = nextInt()
    val A = Array(N) { nextInt() }
    val (first, second) = A.sortedDescending()
    val ans = IntArray(N)
    A.forEachIndexed { n, a ->
        ans[n] = if (a == first) second else first
    }
    println(ans.joinToString("\n"))
}
fun next() = readLine()!!
fun nextInt() = Integer.parseInt(next())
fun nextInt(offset: Int = 0) = nextInt() + offset
fun nextLong() = java.lang.Long.parseLong(next())
fun nextLong(offset: Long = 0L) = nextLong() + offset
fun nextDouble() = next().toDouble()
fun listOfString() = next().split(" ")
fun listOfInt() = listOfString().map { Integer.parseInt(it) }
fun listOfInt(offset: Int = 0) = listOfString().map { Integer.parseInt(it) + offset }
fun listOfLong() = listOfString().map { java.lang.Long.parseLong(it) }
fun listOfLong(offset: Long = 0L) = listOfString().map { java.lang.Long.parseLong(it) + offset }
fun listOfDouble() = listOfString().map { it.toDouble() }