Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in Kotlin (1.3.71) (judge verdict: Wrong Answer)

fun main() {
    val N = readLine()?.toInt() ?: return
    1.until(3501).forEach { h ->
        1.until(3501).forEach { n ->
            val a = (N * h * n)
            val b = ((4 * h * n) - N * n - N * h)
            if (b > 0 && a % b == 0) {
                println("$h $n ${a / b}")
                return
            }
        }
    }
}