Problem:
Score : 200 points

Problem Statement

You are given a positive integer X.
Find the largest perfect power that is at most X.
Here, a perfect power is an integer that can be represented as b^p, where b is an integer not less than 1 and p is an integer not less than 2.

Constraints

1 ≤ X ≤ 1000

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print the largest perfect power that is at most X.

Sample Input 1

10

Sample Output 1

9

There are four perfect powers that are at most 10: 1, 4, 8 and 9.
We should print the largest among them, 9.

Sample Input 2

1

Sample Output 2

1

Sample Input 3

999

Sample Output 3

961

Solution in Kotlin (1.3.71) (judge verdict: Accepted)

fun main(arr:Array<String>) {
    val n = readLine()!!.toInt()
    println(getAns(n))
}

fun getAns(num:Int):Int {
    var ret = 1
    for(i in (2..num)) {
        var tmp = i*i
        while (tmp <= num) {
            ret = Math.max(ret, tmp)
            tmp *= i
        }
    }
    return ret
}