Problem:
Score : 200 points

Problem Statement

Evi has N integers a_1,a_2,..,a_N. His objective is to have N equal integers by transforming some of them.

He may transform each integer at most once. Transforming an integer x into another integer y costs him (x-y)^2 dollars. Even if a_i=a_j (i≠j), he has to pay the cost separately for transforming each of them (See Sample 2).

Find the minimum total cost to achieve his objective.

Constraints

1≦N≦100

-100≦a_i≦100

Input

The input is given from Standard Input in the following format:

N
a_1 a_2 ... a_N

Output

Print the minimum total cost to achieve Evi's objective.

Sample Input 1

2
4 8

Sample Output 1

8

Transforming the both into 6s will cost (4-6)^2+(8-6)^2=8 dollars, which is the minimum.

Sample Input 2

3
1 1 3

Sample Output 2

3

Transforming the all into 2s will cost (1-2)^2+(1-2)^2+(3-2)^2=3 dollars. Note that Evi has to pay (1-2)^2 dollar separately for transforming each of the two 1s.

Sample Input 3

3
4 2 5

Sample Output 3

5

Leaving the 4 as it is and transforming the 2 and the 5 into 4s will achieve the total cost of (2-4)^2+(5-4)^2=5 dollars, which is the minimum.

Sample Input 4

4
-100 -100 -100 -100

Sample Output 4

0

Without transforming anything, Evi's objective is already achieved. Thus, the necessary cost is 0.

Solution in Kotlin (1.0.0) (judge verdict: Accepted)

import java.util.*

val sc = Scanner(System.`in`)
val N = sc.nextInt()

fun main(args: Array<String>) {
    val a = Array(N) { sc.nextInt() }
    var ans = Int.MAX_VALUE
    for (k in a.min()!!..a.max()!!) {
        var cnt = 0
        for (ai in a) {
            cnt += pow((ai - k), 2)
        }
        ans = Math.min(ans, cnt)
    }
    println(ans)
}

fun pow(a: Int, b: Int): Int {
    var result = 1
    for (i in 0 until b) {
        result *= a
    }
    return result
}