Problem:
Score : 300 points

Problem Statement

1000000000000001 dogs suddenly appeared under the roof of Roger's house, all of which he decided to keep. The dogs had been numbered 1 through 1000000000000001, but he gave them new names, as follows:

the dogs numbered 1,2,\cdots,26 were respectively given the names a, b, ..., z;

the dogs numbered 27,28,29,\cdots,701,702 were respectively given the names aa, ab, ac, ..., zy, zz;

the dogs numbered 703,704,705,\cdots,18277,18278 were respectively given the names aaa, aab, aac, ..., zzy, zzz;

the dogs numbered 18279,18280,18281,\cdots,475253,475254 were respectively given the names aaaa, aaab, aaac, ..., zzzy, zzzz;

the dogs numbered 475255,475256,\cdots were respectively given the names aaaaa, aaaab, ...;

and so on.

To sum it up, the dogs numbered 1, 2, \cdots were respectively given the following names:

a, b, ..., z, aa, ab, ..., az, ba, bb, ..., bz, ..., za, zb, ..., zz, aaa, aab, ..., aaz, aba, abb, ..., abz, ..., zzz, aaaa, ...

Now, Roger asks you:

"What is the name for the dog numbered N?"

Constraints

N is an integer.

1 \leq N \leq 1000000000000001

Input

Input is given from Standard Input in the following format:

N

Output

Print the answer to Roger's question as a string consisting of lowercase English letters.

Sample Input 1

2

Sample Output 1

b

Sample Input 2

27

Sample Output 2

aa

Sample Input 3

123456789

Sample Output 3

jjddja

Solution in Kotlin (1.3.71) (judge verdict: Accepted)

import java.lang.StringBuilder
import java.util.StringTokenizer

fun main() {
    val reader = System.`in`.bufferedReader()
    var tokenizer: StringTokenizer = StringTokenizer("")

    fun next(): String {
        while (tokenizer.hasMoreTokens().not()) tokenizer = StringTokenizer(reader.readLine())
        return tokenizer.nextToken()
    }

    fun nextLine() = reader.readLine()

    fun solve() {
        var n = next().toLong()

        var ans = StringBuilder()

        while (n > 0){
            n--
            var rem = n%26
            rem += 97
            ans.append(rem.toChar())
            n/=26
        }

        ans.reverse()
        println(ans.toString())



    }

    solve()


}