Problem:
Score : 100 points

Problem Statement

We have A balls with the string S written on each of them and B balls with the string T written on each of them.

From these balls, Takahashi chooses one with the string U written on it and throws it away.

Find the number of balls with the string S and balls with the string T that we have now.

Constraints

S, T, and U are strings consisting of lowercase English letters.

The lengths of S and T are each between 1 and 10 (inclusive).

S \not= T

S=U or T=U.

1 \leq A,B \leq 10

A and B are integers.

Input

Input is given from Standard Input in the following format:

S T
A B
U

Output

Print the answer, with space in between.

Sample Input 1

red blue
3 4
red

Sample Output 1

2 4

Takahashi chose a ball with red written on it and threw it away.
Now we have two balls with the string S and four balls with the string T.

Sample Input 2

red blue
5 5
blue

Sample Output 2

5 4

Takahashi chose a ball with blue written on it and threw it away.
Now we have five balls with the string S and four balls with the string T.

Solution in Kotlin (1.0.0) (judge verdict: Accepted)

fun main(arg: Array<String>) {
    val (S, T) = listOfString()
    var (A, B) = listOfInt()
    val U = next()
    if (U == S) A -= 1 else B -= 1
    println("${A} ${B}")
}
fun next() = readLine()!!
fun nextInt() = Integer.parseInt(next())
fun nextInt(offset: Int = 0) = nextInt() + offset
fun nextLong() = java.lang.Long.parseLong(next())
fun nextLong(offset: Long = 0L) = nextLong() + offset
fun nextDouble() = next().toDouble()
fun listOfString() = next().split(" ")
fun listOfInt() = listOfString().map { Integer.parseInt(it) }
fun listOfInt(offset: Int = 0) = listOfString().map { Integer.parseInt(it) + offset }
fun listOfLong() = listOfString().map { java.lang.Long.parseLong(it) }
fun listOfLong(offset: Long = 0L) = listOfString().map { java.lang.Long.parseLong(it) + offset }
fun listOfDouble() = listOfString().map { it.toDouble() }