Problem:
Score: 500 points

Problem Statement

Does there exist an undirected graph with N vertices satisfying the following conditions?

The graph is simple and connected.

The vertices are numbered 1, 2, ..., N.

Let M be the number of edges in the graph. The edges are numbered 1, 2, ..., M, the length of each edge is 1, and Edge i connects Vertex u_i and Vertex v_i.

There are exactly K pairs of vertices (i,\ j)\ (i < j) such that the shortest distance between them is 2.

If there exists such a graph, construct an example.

Constraints

All values in input are integers.

2 \leq N \leq 100

0 \leq K \leq \frac{N(N - 1)}{2}

Input

Input is given from Standard Input in the following format:

N K

Output

If there does not exist an undirected graph with N vertices satisfying the conditions, print -1.

If there exists such a graph, print an example in the following format (refer to Problem Statement for what the symbols stand for):

M
u_1 v_1
:
u_M v_M

If there exist multiple graphs satisfying the conditions, any of them will be accepted.

Sample Input 1

5 3

Sample Output 1

5
4 3
1 2
3 1
4 5
2 3

This graph has three pairs of vertices such that the shortest distance between them is 2: (1,\ 4), (2,\ 4), and (3,\ 5). Thus, the condition is satisfied.

Sample Input 2

5 8

Sample Output 2

-1

There is no graph satisfying the conditions.

Solution in Kotlin (1.0.0) (judge verdict: Wrong Answer)

import java.lang.Long.parseLong
import java.util.*

fun main(args:Array<String>) {
    val reader = System.`in`.bufferedReader()
    val (N, K) = reader.readLine()!!.split(" ").map(String::toInt)
//    val S = reader.readLine()!!.split(" ").map(String::toInt).toIntArray()
//    val T = reader.readLine()!!.split(" ").map(String::toInt).toIntArray()
//    val mod = 1000000007
//    var ans = 1L

    var C = (N-1)*(N-2)/2

    if (K > C) {
        println(-1)
        return
    }
    var ans = mutableListOf<String>()

    for (n in 2 .. N) {
        ans.add("1 $n")
    }
    var k = 0
    for (i in 2 until N) {
        for (j in i+1..N) {
            if (C - K == k) break
            k++
            ans.add("$i $j")
        }
    }
    println(ans.joinToString("\n"))
}