Problem:
Score : 100 points

Problem Statement

Compute A \times B.

Constraints

1 \leq A \leq 100

1 \leq B \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the value A \times B as an integer.

Sample Input 1

2 5

Sample Output 1

10

We have 2 \times 5 = 10.

Sample Input 2

100 100

Sample Output 2

10000

Solution in Kotlin (1.3.71) (judge verdict: Accepted)

const val MOD = 1000000007
fun main(args: Array<String>) {
    val sc = MyScanner()
    val a = sc.nextInt()
    val b = sc.nextInt()

    println(a * b)
}

class MyScanner {
    operator fun next(): String {
        return sc.next()
    }

    fun nextLine(): String {
        return sc.nextLine()
    }

    fun nextInt(): Int {
        return sc.next().toInt()
    }

    fun nextDouble(): Double {
        return next().toDouble()
    }

    fun nextLong(): Long {
        return next().toLong()
    }

    fun nextIntArray(n: Int): IntArray {
        val array = IntArray(n)
        for (i in 0 until n) {
            array[i] = nextInt()
        }
        return array
    }

    fun nextDoubleArray(n: Int): DoubleArray {
        val array = DoubleArray(n)
        for (i in 0 until n) {
            array[i] = nextDouble()
        }
        return array
    }

    fun nextLongArray(n: Int): LongArray {
        val array = LongArray(n)
        for (i in 0 until n) {
            array[i] = nextLong()
        }
        return array
    }

    fun nextLineArray(n: Int): Array<String?> {
        val array = arrayOfNulls<String>(n)
        for (i in 0 until n) {
            array[i] = nextLine()
        }
        return array
    }

    fun nextIntMatrix(n: Int, m: Int): Array<IntArray> {
        val matrix = Array(n) { IntArray(m) }
        for (i in 0 until n) {
            for (j in 0 until m) {
                matrix[i][j] = nextInt()
            }
        }
        return matrix
    }

    fun nextDoubleMatrix(n: Int, m: Int): Array<DoubleArray> {
        val matrix = Array(n) { DoubleArray(m) }
        for (i in 0 until n) {
            for (j in 0 until m) {
                matrix[i][j] = nextDouble()
            }
        }
        return matrix
    }

    fun nextLongMatrix(n: Int, m: Int): Array<LongArray> {
        val matrix = Array(n) { LongArray(m) }
        for (i in 0 until n) {
            for (j in 0 until m) {
                matrix[i][j] = nextLong()
            }
        }
        return matrix
    }

    companion object {
        var sc: java.util.Scanner = java.util.Scanner(java.lang.System.`in`)
    }
}