Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in Kotlin (1.0.0) (judge verdict: Wrong Answer)

fun main(arg: Array<String>){
    val (N, A, B, C, D) = readLine()!!.split(" ").map(String::toInt)
    val S = readLine()!!
    val A_last = S.substring(A - 1, listOf(C, D).max()!! - 1)
    val common_S = S.substring(listOf(A, B).max()!! - 2, listOf(C, D).min()!! - 1)

    if(A_last.contains("##")){
        System.err.println("double ##")
        println("No")
    }else{
        if(C < D){
            System.err.println("C < D")
            println("Yes")
        }else{
            System.err.println("S[D - 2]: ${S[D - 2]}, S[D} = ${S[D]}")
            val sideX = S[D - 2] == '#' || if(D < N) '#' == S[D] else false
            if(sideX && !common_S.contains("...")){
                System.err.println("cannot cross")
                println("No")
            }else{
                System.err.println("sideX: ${sideX}")
                println("Yes")
            }
        }
    }

}