Problem:
Reversing Numbers

Write a program which reads a sequence and prints it in the reverse order.

Input

The input is given in the following format:

n
a1 a2 . . . an

n is the size of the sequence and ai is the ith element of the sequence.

Output

Print the reversed sequence in a line. Print a single space character between adjacent elements (Note that your program should not put a space character after the last element).

Constraints

n ≤ 100

0 ≤ ai < 1000

Sample Input 1

5
1 2 3 4 5

Sample Output 1

5 4 3 2 1

Sample Input 2

8
3 3 4 4 5 8 7 9

Sample Output 2

9 7 8 5 4 4 3 3

Note

      解説

Solution in Kotlin (judge verdict: Accepted)

import java.util.*

fun main(arg: Array<String>) {
    val x = readLine()!!.toInt()
    val n = readLine()!!.split(" ")
                        .map(String::toInt)
                        .reversed()
    for (i in 0..(x-1)) {
        if (i == (x-1)) {
            println(n[i])
            break
        }
        print(Integer.toString(n[i]) + " ")
    }
}