Problem:
Score : 300 points

Problem Statement

We have N switches with "on" and "off" state, and M bulbs. The switches are numbered 1 to N, and the bulbs are numbered 1 to M.

Bulb i is connected to k_i switches: Switch s_{i1}, s_{i2}, ..., and s_{ik_i}. It is lighted when the number of switches that are "on" among these switches is congruent to p_i modulo 2.

How many combinations of "on" and "off" states of the switches light all the bulbs?

Constraints

1 \leq N, M \leq 10

1 \leq k_i \leq N

1 \leq s_{ij} \leq N

s_{ia} \neq s_{ib} (a \neq b)

p_i is 0 or 1.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M
k_1 s_{11} s_{12} ... s_{1k_1}
:
k_M s_{M1} s_{M2} ... s_{Mk_M}
p_1 p_2 ... p_M

Output

Print the number of combinations of "on" and "off" states of the switches that light all the bulbs.

Sample Input 1

2 2
2 1 2
1 2
0 1

Sample Output 1

1

Bulb 1 is lighted when there is an even number of switches that are "on" among the following: Switch 1 and 2.

Bulb 2 is lighted when there is an odd number of switches that are "on" among the following: Switch 2.

There are four possible combinations of states of (Switch 1, Switch 2): (on, on), (on, off), (off, on) and (off, off). Among them, only (on, on) lights all the bulbs, so we should print 1.

Sample Input 2

2 3
2 1 2
1 1
1 2
0 0 1

Sample Output 2

0

Bulb 1 is lighted when there is an even number of switches that are "on" among the following: Switch 1 and 2.

Bulb 2 is lighted when there is an even number of switches that are "on" among the following: Switch 1.

Bulb 3 is lighted when there is an odd number of switches that are "on" among the following: Switch 2.

Switch 1 has to be "off" to light Bulb 2 and Switch 2 has to be "on" to light Bulb 3, but then Bulb 1 will not be lighted. Thus, there are no combinations of states of the switches that light all the bulbs, so we should print 0.

Sample Input 3

5 2
3 1 2 5
2 2 3
1 0

Sample Output 3

8

Solution in Kotlin (1.0.0) (judge verdict: Accepted)

fun main(args: Array<String>) {
    val (n, m) = readLine()!!.split(" ").map { it.toInt() }


    val connectedLump = mutableListOf<MutableList<Int>>()
    for (i in 0 until n) {
        connectedLump.add(mutableListOf())
    }



    for (i in 0 until m){
        val inputs = readLine()!!.split(" ").map { it.toInt() }
        for (j in 1 until inputs.size) {
            connectedLump[inputs[j]-1].add(i)
        }
    }

    val condition = readLine()!!.split(" ").map { it.toInt() }

    var countAns = 0
    val lumpStatus = IntArray(m){0}.toMutableList()

    fun updateStatus(count: Int, mem: MutableList<Int>) {

        if (count == n){
            for(i in 0 until mem.size) {
                if (mem[i]%2 != condition[i]) {
                    return
                }
            }
            countAns += 1
            return
        }

        // スイッチを入れる場合
        val memTemp = mem.toMutableList()
        for (l in connectedLump[count]){
            memTemp[l] += 1
        }
        updateStatus(count+1, memTemp)

        // スイッチを入れない場合
        val memTempOff = mem.toMutableList()
        updateStatus(count+1, memTempOff)
    }

    updateStatus(0, lumpStatus)

    println(countAns)
}