Problem:
Score : 300 points

Problem Statement

A railroad running from west to east in Atcoder Kingdom is now complete.

There are N stations on the railroad, numbered 1 through N from west to east.

Tomorrow, the opening ceremony of the railroad will take place.

On this railroad, for each integer i such that 1≤i≤N-1, there will be trains that run from Station i to Station i+1 in C_i seconds. No other trains will be operated.

The first train from Station i to Station i+1 will depart Station i S_i seconds after the ceremony begins. Thereafter, there will be a train that departs Station i every F_i seconds.

Here, it is guaranteed that F_i divides S_i.

That is, for each Time t satisfying S_i≤t and t％F_i=0, there will be a train that departs Station i t seconds after the ceremony begins and arrives at Station i+1 t+C_i seconds after the ceremony begins, where A％B denotes A modulo B, and there will be no other trains.

For each i, find the earliest possible time we can reach Station N if we are at Station i when the ceremony begins, ignoring the time needed to change trains.

Constraints

1≤N≤500

1≤C_i≤100

1≤S_i≤10^5

1≤F_i≤10

S_i％F_i=0

All input values are integers.

Input

Input is given from Standard Input in the following format:

N
C_1 S_1 F_1
:
C_{N-1} S_{N-1} F_{N-1}

Output

Print N lines. Assuming that we are at Station i (1≤i≤N) when the ceremony begins, if the earliest possible time we can reach Station N is x seconds after the ceremony begins, the i-th line should contain x.

Sample Input 1

3
6 5 1
1 10 1

Sample Output 1

12
11
0

We will travel from Station 1 as follows:

5 seconds after the beginning: take the train to Station 2.

11 seconds: arrive at Station 2.

11 seconds: take the train to Station 3.

12 seconds: arrive at Station 3.

We will travel from Station 2 as follows:

10 seconds: take the train to Station 3.

11 seconds: arrive at Station 3.

Note that we should print 0 for Station 3.

Sample Input 2

4
12 24 6
52 16 4
99 2 2

Sample Output 2

187
167
101
0

Sample Input 3

4
12 13 1
44 17 17
66 4096 64

Sample Output 3

4162
4162
4162
0

Solution in Kotlin (1.0.0) (judge verdict: Accepted)

data class Data(val c:Int, val s:Int, val f:Int)
fun main(args:Array<String>) {
  val n = readLine()!!.toInt()
  
  val datasBase = (1..n-1).map { 
    val sp = readLine()!!.split(" ").map(String::toInt)
    val data = Data(sp[0], sp[1], sp[2])
    data
  }

  for( slicer in (0..datasBase.size-1) ) {
    val datas = datasBase.slice(slicer..datasBase.size-1)
    var time = 0
    for( loop in (0..100000) ) {
      if( datas.size-1 < loop ) break
      if( loop == 0 ) {
        time = datas[0].s
        time += datas[0].c
      } else { 
        if( time < datas[loop].s ) {
          // 未発射
          time += (datas[loop].s - time)
          time += datas[loop].c
        } else {
          // 発射済み
          if(  (time - datas[loop].s)%datas[loop].f  != 0 ){ 
            val wait = datas[loop].f - (time - datas[loop].s)%datas[loop].f 
            time += wait 
          }
          time += datas[loop].c
        }
      }
    }
    println(time)
  }
  println(0)
}