Problem:
Score : 100 points

Problem Statement

An uppercase or lowercase English letter \alpha will be given as input.
If \alpha is uppercase, print A; if it is lowercase, print a.

Constraints

\alpha is an uppercase (A - Z) or lowercase (a - z) English letter.

Input

Input is given from Standard Input in the following format:

α

Output

If \alpha is uppercase, print A; if it is lowercase, print a.

Sample Input 1

B

Sample Output 1

A

B is uppercase, so we should print A.

Sample Input 2

a

Sample Output 2

a

a is lowercase, so we should print a.

Solution in Kotlin (1.3.71) (judge verdict: Wrong Answer)

fun main(args: Array<String>) {
    val s = read().toCharArray()
    if (s[0].isUpperCase()) println("A") else println("B")



}

private fun read() = readLine()!!

private fun readInt() = read().toInt()

private fun readLong() = read().toLong()

private fun readDouble() = read().toDouble()

private fun readListString() = read().split(" ")

private fun readListInt() = readListString().map { it.toInt() }

private fun readListLong() = readListString().map { it.toLong() }

private fun readListDouble() = readListString().map { it.toDouble() }

private fun readMatrixString(n: Int): List<List<String>> {
    val matrix = mutableListOf<List<String>>()
    for (i in 0 until n) {
        val list = readListString()
        matrix.add(list)
    }
    return matrix
}

private fun readMatrixInt(n: Int): List<List<Int>> {
    val matrix = mutableListOf<List<Int>>()
    for (i in 0 until n) {
        val list = readListInt()
        matrix.add(list)
    }
    return matrix
}

private fun readMatrixDouble(n: Int): List<List<Double>> {
    val matrix = mutableListOf<List<Double>>()
    for (i in 0 until n) {
        val list = readListDouble()
        matrix.add(list)
    }
    return matrix
}

private fun readMatrixLong(n: Int): List<List<Long>> {
    val matrix = mutableListOf<List<Long>>()
    for (i in 0 until n) {
        val list = readListLong()
        matrix.add(list)
    }
    return matrix
}