Problem:
Score : 300 points

Problem Statement

Takahashi has N balls. Initially, an integer A_i is written on the i-th ball.

He would like to rewrite the integer on some balls so that there are at most K different integers written on the N balls.

Find the minimum number of balls that Takahashi needs to rewrite the integers on them.

Constraints

1 \leq K \leq N \leq 200000

1 \leq A_i \leq N

All input values are integers.

Input

Input is given from Standard Input in the following format:

N K
A_1 A_2 ... A_N

Output

Print the minimum number of balls that Takahashi needs to rewrite the integers on them.

Sample Input 1

5 2
1 1 2 2 5

Sample Output 1

1

For example, if we rewrite the integer on the fifth ball to 2, there are two different integers written on the balls: 1 and 2.
On the other hand, it is not possible to rewrite the integers on zero balls so that there are at most two different integers written on the balls, so we should print 1.

Sample Input 2

4 4
1 1 2 2

Sample Output 2

0

Already in the beginning, there are two different integers written on the balls, so we do not need to rewrite anything.

Sample Input 3

10 3
5 1 3 2 4 1 1 2 3 4

Sample Output 3

3

Solution in Kotlin (1.0.0) (judge verdict: Time Limit Exceeded)

fun main(args: Array<String>) {

    var list = readLine()!!.split(" ").map { it.toInt() }
    val mokuhyo = list[1]

    var numList = readLine()!!.split(" ").map { it.toInt() }
    // group byの戻り値ってなんだろう？ペアリストかな？mutableListじゃないとgroup byできない？
    val groupMap = numList.groupBy { it }
    // LOOK mapのソートってどうなっている？keyソート、valueソート
    // key sort
    //    groupMap.toSortedMap()
    // value sort
    // LOOK ソート処理結果はmutableであっても変数入れ直し必要。3回目くらいなのでOK
    // Maoの値を変更する場合はtoMutableMapしておく toMap().toMutableMap()??
    // atCoderでtoMutableMapが使えないのだが・・・filterなど高級関数で無理やり対応する
    var sortedGroupMap = groupMap.toList().sortedByDescending { it.second.count() }.toMap()

    var result = 0

    while (mokuhyo < sortedGroupMap.count()) {
        // 種類が多いので、変換処理を実施
        // LOOK Mapの先頭、末尾のオブジェクトって取れる？
        val last = sortedGroupMap.toList().last()
//        val first = sortedGroupMap.toList().first()
        result += last.second.count()
        // LOOK Mapの要素を削除したい
//        sortedGroupMap.remove(last.first)
        sortedGroupMap = sortedGroupMap.filter { it.key != last.first }

    }
    println(result)
}