Problem:
Score : 600 points

Problem Statement

Given are two sequences A and B, both of length N.
A and B are each sorted in the ascending order.
Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderings that achieve it.

Constraints

1\leq N \leq 2 \times 10^5

1\leq A_i,B_i \leq N

A and B are each sorted in the ascending order.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 \cdots A_N
B_1 B_2 \cdots B_N

Output

If there exist no reorderings that satisfy the condition, print No.

If there exists a reordering that satisfies the condition, print Yes on the first line.
After that, print a reordering of B on the second line, separating terms with a whitespace.

If there are multiple reorderings that satisfy the condition, you can print any of them.

Sample Input 1

6
1 1 1 2 2 3
1 1 1 2 2 3

Sample Output 1

Yes
2 2 3 1 1 1

Sample Input 2

3
1 1 2
1 1 3

Sample Output 2

No

Sample Input 3

4
1 1 2 3
1 2 3 3

Sample Output 3

Yes
3 3 1 2

Solution in Kotlin (1.3.71) (judge verdict: Wrong Answer)

fun list() = readLine()!!.split(" ").map { it.toInt() }

fun main() {
    val n = readLine()!!.toInt()

    val a = list().toIntArray()
    val b = list().toIntArray()

    var d = 0
    for (i in 0 until n * 2) {
        while (a[i % n] == b[(i + d) % n]) {
            ++d
            if (d >= n) {
                println("No")
                return
            }
        }
    }

    println("Yes")
    b.indices.map { b[(it + d) % n] }.joinToString(" ")
            .let { println(it) }
}