Problem:
Score : 200 points

Problem Statement

There are N rabbits, numbered 1 through N.

The i-th (1≤i≤N) rabbit likes rabbit a_i.
Note that no rabbit can like itself, that is, a_i≠i.

For a pair of rabbits i and j (i＜j), we call the pair (i，j) a friendly pair if the following condition is met.

Rabbit i likes rabbit j and rabbit j likes rabbit i.

Calculate the number of the friendly pairs.

Constraints

2≤N≤10^5

1≤a_i≤N

a_i≠i

Input

The input is given from Standard Input in the following format:

N
a_1 a_2 ... a_N

Output

Print the number of the friendly pairs.

Sample Input 1

4
2 1 4 3

Sample Output 1

2

There are two friendly pairs: (1，2) and (3，4).

Sample Input 2

3
2 3 1

Sample Output 2

0

There are no friendly pairs.

Sample Input 3

5
5 5 5 5 1

Sample Output 3

1

There is one friendly pair: (1，5).

Solution in Kotlin (1.0.0) (judge verdict: Accepted)

import java.util.*
object MainKt {
  @JvmStatic fun main(args:Array<String>) {
    val sc = Scanner(System.`in`)
    val N=sc.nextInt()
    val a=Array(N) {sc.nextInt()}
    var num=0

    for (j in 1..N)
    {
      val i=a[j-1]
      if (i>=j) continue
      num+=if(a[i-1]==j&&a[j-1]==i) 1 else 0
    }

    println(num)
  }
}