Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Kotlin (1.3.71) (judge verdict: Accepted)

fun main() {
    val N = readLine()!!.toInt()
    var ans = 0
    for (n in 1..N) {
        if (n % 2 == 1) {
            var cnt = 0
            for (i in 1..n) {
                if (n % i == 0) {
                    cnt++
                }
            }
            if (cnt == 8) {
                ans++
            }
        }
    }
    println(ans)
}