Problem:
Score : 500 points

Problem Statement

There are N cards placed face down in a row. On each card, an integer 1 or 2 is written.

Let A_i be the integer written on the i-th card.

Your objective is to guess A_1, A_2, ..., A_N correctly.

You know the following facts:

For each i = 1, 2, ..., M, the value A_{X_i} + A_{Y_i} + Z_i is an even number.

You are a magician and can use the following magic any number of times:

Magic: Choose one card and know the integer A_i written on it. The cost of using this magic is 1.

What is the minimum cost required to determine all of A_1, A_2, ..., A_N?

It is guaranteed that there is no contradiction in given input.

Constraints

All values in input are integers.

2 \leq N \leq 10^5

1 \leq M \leq 10^5

1 \leq X_i < Y_i \leq N

1 \leq Z_i \leq 100

The pairs (X_i, Y_i) are distinct.

There is no contradiction in input. (That is, there exist integers A_1, A_2, ..., A_N that satisfy the conditions.)

Input

Input is given from Standard Input in the following format:

N M
X_1 Y_1 Z_1
X_2 Y_2 Z_2
\vdots
X_M Y_M Z_M

Output

Print the minimum total cost required to determine all of A_1, A_2, ..., A_N.

Sample Input 1

3 1
1 2 1

Sample Output 1

2

You can determine all of A_1, A_2, A_3 by using the magic for the first and third cards.

Sample Input 2

6 5
1 2 1
2 3 2
1 3 3
4 5 4
5 6 5

Sample Output 2

2

Sample Input 3

100000 1
1 100000 100

Sample Output 3

99999

Solution in Kotlin (1.0.0) (judge verdict: Time Limit Exceeded)

import java.io.*
import java.util.*

fun solve(N: Int, M: Int, X: IntArray, Y: IntArray, Z: IntArray){
    val uf = UnionFind(N + 1)
    repeat(M){
        uf.unite(X[it], Y[it])
    }
    var nodes = (1..N).toList()
    var ans = 0
    for(node in X){
        if (node in nodes){
            nodes =  nodes.filter{ !uf.isSame(it, node) }
            ans++
        }
    }
    println(ans + nodes.size)
    return
}
class UnionFind(n: Int) {
    data class Node(var parent: Int, var size: Int)
    val nodes = Array<Node>(n) { Node(parent = it, size = 1) }
    fun findRoot(x: Int): Int {
        if (x == this.nodes[x].parent) return x
        nodes[x].parent = findRoot(nodes[x].parent)
        return nodes[x].parent
    }
    fun unite(x: Int, y: Int) {
        var xRoot = findRoot(x)
        var yRoot = findRoot(y)
        if (xRoot == yRoot) return
        if (getSize(xRoot) < getSize(yRoot)) {
            nodes[xRoot].parent = yRoot
            nodes[yRoot].size += nodes[xRoot].size
        } else {
            nodes[yRoot].parent = xRoot
            nodes[xRoot].size += nodes[yRoot].size
        }
    }
    fun getSize(x: Int) = nodes[findRoot(x)].size
    fun isSame(x: Int, y: Int) = findRoot(x) == findRoot(y)
}

fun main(args: Array<String>) {
    fun StringArray(size: Int, init: (Int) -> String = { "\u0000" }): Array<String> {
        return Array<String>(size, init)
    }
    class Scanner(stream: InputStream) {
        private val reader = BufferedInputStream(stream).bufferedReader()
        private var st: StringTokenizer? = null
        fun next(): String {
            while (!(st?.hasMoreTokens() ?: false)) st = StringTokenizer(reader.readLine())
            return st!!.nextToken()
        }
    }
    val sc = Scanner(System.`in`)
    val N = sc.next().toInt()
    val M = sc.next().toInt()
    val X = IntArray(M)
    val Y = IntArray(M)
    val Z = IntArray(M)
    for (i in 0 until M.toInt()) {
        X[i] = sc.next().toInt()
        Y[i] = sc.next().toInt()
        Z[i] = sc.next().toInt()
    }
    solve(N, M, X, Y, Z)
}