Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in Kotlin (1.3.71) (judge verdict: Accepted)

import java.util.*

fun main(args: Array<String>) {
  val sc = Scanner(System.`in`)
  val n = sc.nextInt()
  val a = sc.nextInt()
  val b = sc.nextInt()
  val c = sc.nextInt()
  val d = sc.nextInt()
  val s = sc.next()

  val ss = "#" + s + "#"

  if (hasTwo(ss, a-1, c) || hasTwo(ss, b-1, d)) {
    println("No")
    return
  }

  if (c > d) {
    var ok = false
    for (i in b..d) {
      if (ss[i-1] == '.' && ss[i] == '.' && ss[i+1] == '.') {
        ok = true
      }
    }
    if (!ok) {
      println("No")
      return
    }
  }

  println("Yes")

}

private fun hasTwo(s: String, start: Int, end: Int): Boolean {
  for (i in start..end) {
    if (s[i] == '#' && s[i+1] == '#') return true
  }

  return false
}