Problem:
Score : 100 points

Problem Statement

There are two buttons, one of size A and one of size B.

When you press a button of size X, you get X coins and the size of that button decreases by 1.

You will press a button twice. Here, you can press the same button twice, or press both buttons once.

At most how many coins can you get?

Constraints

All values in input are integers.

3 \leq A, B \leq 20

Input

Input is given from Standard Input in the following format:

A B

Output

Print the maximum number of coins you can get.

Sample Input 1

5 3

Sample Output 1

9

You can get 5 + 4 = 9 coins by pressing the button of size 5 twice, and this is the maximum result.

Sample Input 2

3 4

Sample Output 2

7

Sample Input 3

6 6

Sample Output 3

12

Solution in Kotlin (1.0.0) (judge verdict: Accepted)

fun main(arg:Array<String>){
  var (a,b) = readLine()!!.split(" ").map(String::toInt)
  var num = 0
  for(i in 0..1){
    if(a > b){
      num += a
      a--
    }else{
      num += b
      b--
    }
  }
  println(num)
}