Problem:
Score : 400 points

Problem Statement

Given are positive integers A and B.

Let us choose some number of positive common divisors of A and B.

Here, any two of the chosen divisors must be coprime.

At most, how many divisors can we choose?

Definition of common divisor

An integer d is said to be a common divisor of integers x and y when d divides both x and y.

Definition of being coprime

Integers x and y are said to be coprime when x and y have no positive common divisors other than 1.

Definition of dividing

An integer x is said to divide another integer y when there exists an integer \alpha such that y = \alpha x.

Constraints

All values in input are integers.

1 \leq A, B \leq 10^{12}

Input

Input is given from Standard Input in the following format:

A B

Output

Print the maximum number of divisors that can be chosen to satisfy the condition.

Sample Input 1

12 18

Sample Output 1

3

12 and 18 have the following positive common divisors: 1, 2, 3, and 6.

1 and 2 are coprime, 2 and 3 are coprime, and 3 and 1 are coprime, so we can choose 1, 2, and 3, which achieve the maximum result.

Sample Input 2

420 660

Sample Output 2

4

Sample Input 3

1 2019

Sample Output 3

1

1 and 2019 have no positive common divisors other than 1.

Solution in Kotlin (1.0.0) (judge verdict: Runtime Error)

fun main(args: Array<String>) {
    val (a, b) = readLine()!!.split(" ").map(String::toLong)
    val dList = (1..Math.min(a,b)).filter { a % it == 0L && b % it == 0L }
//    val ddList = dList.map { (2..it).filter { x -> it % x == 0L } }
//    println(dList.joinToString(" "))
    if (dList.size == 1) {
        println(1)
    }
    if (dList.size == 2) {
        println(2)
    }
    val cList = mutableListOf(dList[1])
    for (i in 2 until dList.size) {
        if (cList.all { dList[i] % it != 0L }) {
//            println(cList.joinToString(" "))
            cList.add(dList[i])
//            println("di ${dList[i]}")
//            println(cList.joinToString(" "))
        }
//        println("di ${dList[i]}")
//        cList = cList.filter { it % dList[i] != 0L || it == dList[i] }
//        println(cList.joinToString(" "))
    }
    println(cList.size+1)
}