Problem:
Score : 200 points

Problem Statement

Tak performed the following action N times: rolling two dice.
The result of the i-th roll is D_{i,1} and D_{i,2}.

Check if doublets occurred at least three times in a row.
Specifically, check if there exists at lease one i such that D_{i,1}=D_{i,2}, D_{i+1,1}=D_{i+1,2} and D_{i+2,1}=D_{i+2,2} hold.

Constraints

3 \leq N \leq 100

1\leq D_{i,j} \leq 6

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
D_{1,1} D_{1,2}
\vdots
D_{N,1} D_{N,2}

Output

Print Yes if doublets occurred at least three times in a row. Print No otherwise.

Sample Input 1

5
1 2
6 6
4 4
3 3
3 2

Sample Output 1

Yes

From the second roll to the fourth roll, three doublets occurred in a row.

Sample Input 2

5
1 1
2 2
3 4
5 5
6 6

Sample Output 2

No

Sample Input 3

6
1 1
2 2
3 3
4 4
5 5
6 6

Sample Output 3

Yes

Solution in Kotlin (1.3.71) (judge verdict: Accepted)

import java.util.*
import kotlin.math.*

fun str() = readLine()!!
fun int() = str().toInt()
fun long() = str().toLong()

fun read(d: String = " ") = str().split(d)
fun <T> list(d: String = " ", f: String.() -> T) = read(d).map { f(it) }
fun list() = list { toInt() }

fun <T> MutableList<T>.removeLast() = this.removeAt(this.lastIndex)

const val mod = 1000000007L

fun main() {
    abc000X()
}

fun abc000X() {
    val n = int()
    val a = BooleanArray(n) {
        val (p, q) = list()
        p == q
    }

    (0..n - 3).any { a[it] && a[it + 1] && a[it + 2] }
            .let { println(if (it) "Yes" else "No") }
}