Problem:
Score : 300 points

Problem Statement

AtCoDeer the deer is going on a trip in a two-dimensional plane.
In his plan, he will depart from point (0, 0) at time 0, then for each i between 1 and N (inclusive), he will visit point (x_i,y_i) at time t_i.

If AtCoDeer is at point (x, y) at time t, he can be at one of the following points at time t+1: (x+1,y), (x-1,y), (x,y+1) and (x,y-1).
Note that he cannot stay at his place.
Determine whether he can carry out his plan.

Constraints

1 ≤ N ≤ 10^5

0 ≤ x_i ≤ 10^5

0 ≤ y_i ≤ 10^5

1 ≤ t_i ≤ 10^5

t_i < t_{i+1} (1 ≤ i ≤ N-1)

All input values are integers.

Input

Input is given from Standard Input in the following format:

N
t_1 x_1 y_1
t_2 x_2 y_2
:
t_N x_N y_N

Output

If AtCoDeer can carry out his plan, print Yes; if he cannot, print No.

Sample Input 1

2
3 1 2
6 1 1

Sample Output 1

Yes

For example, he can travel as follows: (0,0), (0,1), (1,1), (1,2), (1,1), (1,0), then (1,1).

Sample Input 2

1
2 100 100

Sample Output 2

No

It is impossible to be at (100,100) two seconds after being at (0,0).

Sample Input 3

2
5 1 1
100 1 1

Sample Output 3

No

Solution in Kotlin (1.0.0) (judge verdict: Accepted)

fun main(args: Array<String>) {
    val N = readLine()?.toInt() ?: 0
    var prevTern = listOf(0, 0, 0)
    var eachTern = arrayListOf(prevTern)
    for (n in 0..N-1) {
        eachTern.add(readLine()!!.split(" ").map(String::toInt))
    }
    var result = "Yes"
    for (e in eachTern) {
        val timeDiff = e[0] - prevTern[0]
        val xDiff = Math.abs(e[1] - prevTern[1])
        val yDiff = Math.abs(e[2] - prevTern[2])
        if (timeDiff < (xDiff + yDiff)) {
            result = "No"
            break
        }
        prevTern = e
        if (timeDiff % 2 == 0 && (xDiff + yDiff) % 2 == 0) {
            result = "Yes"
            continue
        }
        if (timeDiff % 2 != 0 && (xDiff + yDiff) % 2 != 0) {
            result = "Yes"
            continue
        }
        result = "No"
        break
    }
    print(result)
}