Problem:
Score : 200 points

Problem Statement

We have sticks numbered 1, \cdots, N. The length of Stick i (1 \leq i \leq N) is L_i.

In how many ways can we choose three of the sticks with different lengths that can form a triangle?

That is, find the number of triples of integers (i, j, k) (1 \leq i < j < k \leq N) that satisfy both of the following conditions:

L_i, L_j, and L_k are all different.

There exists a triangle whose sides have lengths L_i, L_j, and L_k.

Constraints

1 \leq N \leq 100

1 \leq L_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
L_1 L_2 \cdots L_N

Output

Print the number of ways to choose three of the sticks with different lengths that can form a triangle.

Sample Input 1

5
4 4 9 7 5

Sample Output 1

5

The following five triples (i, j, k) satisfy the conditions: (1, 3, 4), (1, 4, 5), (2, 3, 4), (2, 4, 5), and (3, 4, 5).

Sample Input 2

6
4 5 4 3 3 5

Sample Output 2

8

We have two sticks for each of the lengths 3, 4, and 5. To satisfy the first condition, we have to choose one from each length.

There is a triangle whose sides have lengths 3, 4, and 5, so we have 2 ^ 3 = 8 triples (i, j, k) that satisfy the conditions.

Sample Input 3

10
9 4 6 1 9 6 10 6 6 8

Sample Output 3

39

Sample Input 4

2
1 1

Sample Output 4

0

No triple (i, j, k) satisfies 1 \leq i < j < k \leq N, so we should print 0.

Solution in Kotlin (1.3.71) (judge verdict: Accepted)

private class B {
    fun solve() {
        val n = nextInt()
        val l = IntArray(n) { nextInt() }
        var ans = 0
        for (i in 0 until n) {
            for (j in i + 1 until n) {
                for (k in j + 1 until n) {
                    if (l[i] == l[j] || l[i] == l[k] || l[j] == l[k]) {
                        continue
                    }
                    if (l[i] + l[j] > l[k] && l[i] + l[k] > l[j] && l[j] + l[k] > l[i]) {
                        ans++
                    }
                }
            }
        }
        println(ans)
    }

    var tokenBuffer = listOf<String>()
    var bufferPosition = 0

    private fun checkBuffer() {
        if (bufferPosition == tokenBuffer.size) {
            tokenBuffer = nextLine().split(" ")
            bufferPosition = 0
        }
    }

    fun nextLine() = readLine()!!
    fun nextInt(): Int {
        checkBuffer()
        return tokenBuffer[bufferPosition++].toInt()
    }

    fun nextLong(): Long {
        checkBuffer()
        return tokenBuffer[bufferPosition++].toLong()
    }

    fun nextDouble(): Double {
        checkBuffer()
        return tokenBuffer[bufferPosition++].toDouble()
    }

    fun nextToken(): String {
        checkBuffer()
        return tokenBuffer[bufferPosition++]
    }
}

fun main() {
    val reader = B().solve()

}