Problem:
Score : 200 points

Problem Statement

There are some animals in a garden. Each of them is a crane with two legs or a turtle with four legs.

Takahashi says: "there are X animals in total in the garden, and they have Y legs in total." Determine whether there is a combination of numbers of cranes and turtles in which this statement is correct.

Constraints

1 \leq X \leq 100

1 \leq Y \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

If there is a combination of numbers of cranes and turtles in which the statement is correct, print Yes; otherwise, print No.

Sample Input 1

3 8

Sample Output 1

Yes

The statement "there are 3 animals in total in the garden, and they have 8 legs in total" is correct if there are two cranes and one turtle. Thus, there is a combination of numbers of cranes and turtles in which the statement is correct.

Sample Input 2

2 100

Sample Output 2

No

There is no combination of numbers of cranes and turtles in which this statement is correct.

Sample Input 3

1 2

Sample Output 3

Yes

We also consider the case in which there are only cranes or only turtles.

Solution in Kotlin (1.3.71) (judge verdict: Accepted)

private fun readLn() = readLine()!!
private fun readInt() = readLn().toInt()
private fun readStrings() = readLn().split(" ")
private fun readInts() = readStrings().map(String::toInt)
private fun readStrings2() = readLn().split("").filter { it.isNotEmpty() }
private fun readInts2() = readStrings2().map(String::toInt)
private fun initArray(n:Int, v:String) = Array(n) { v }
private fun initIntArray(n:Int, v:Int) = IntArray(n) { v }

fun main(args: Array<String>) {
    // X: 動物の総数 Y: 足の総数
    // 2本の足を持つ鶴
    // 4本の足を持つ亀
    val (X, Y) = readInts()

    var flag = false
    for (i in 0 .. X) {
        // 鶴=i
        val j = X - i
        val tmp = 2 * i + 4 * j
        if (tmp == Y) {
            println("Yes")
            flag = true
            break
        }
    }
    if(!flag) {
        println("No")
    }
}