Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in Kotlin (1.3.71) (judge verdict: Accepted)

// https://atcoder.jp/contests/tenka1-2017/tasks/tenka1_2017_c

fun main() {
    tenka1_2017c()
}

fun tenka1_2017c() {
    val n = readLine()!!.toLong()
    var cm = 0L
    var i = 1L
    for (i in 1 .. 3500L) {
        for (j in 1..3500L) {
            val t = n * i * j
            val p = 4 * i * j - n * i - n * j
            if (p <= 0L) continue
            if (t % p == 0L) {
                println("$i $j ${t / p}")
                return
            }
        }
    }
}