Problem:
Score : 300 points

Problem Statement

You are given an integer sequence of length n, a_1, ..., a_n.
Let us consider performing the following n operations on an empty sequence b.

The i-th operation is as follows:

Append a_i to the end of b.

Reverse the order of the elements in b.

Find the sequence b obtained after these n operations.

Constraints

1 \leq n \leq 2\times 10^5

0 \leq a_i \leq 10^9

n and a_i are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print n integers in a line with spaces in between.
The i-th integer should be b_i.

Sample Input 1

4
1 2 3 4

Sample Output 1

4 2 1 3

After step 1 of the first operation, b becomes: 1.

After step 2 of the first operation, b becomes: 1.

After step 1 of the second operation, b becomes: 1, 2.

After step 2 of the second operation, b becomes: 2, 1.

After step 1 of the third operation, b becomes: 2, 1, 3.

After step 2 of the third operation, b becomes: 3, 1, 2.

After step 1 of the fourth operation, b becomes: 3, 1, 2, 4.

After step 2 of the fourth operation, b becomes: 4, 2, 1, 3.

Thus, the answer is 4 2 1 3.

Sample Input 2

3
1 2 3

Sample Output 2

3 1 2

As shown above in Sample Output 1, b becomes 3, 1, 2 after step 2 of the third operation. Thus, the answer is 3 1 2.

Sample Input 3

1
1000000000

Sample Output 3

1000000000

Sample Input 4

6
0 6 7 6 7 0

Sample Output 4

0 6 6 0 7 7

Solution in Kotlin (1.0.0) (judge verdict: Accepted)

fun main(args: Array<String>) {
    abc066c()
}

// nが奇数の場合は奇数indexが右、そうでない場合は逆
fun abc066c() {
    val n = readLine()!!.toInt()
    val aList = readLine()!!.split(" ").map { it.toLong() }.toLongArray()

    val (evenPairs, oddPairs) = aList.mapIndexed { index, l -> Pair(index, l) }.partition { it.first % 2 == 0 }

    val evens = evenPairs.map { it.second }.toLongArray()
    val odds = oddPairs.map { it.second }.toLongArray()

    val aListSizeIsEven = n % 2 == 0
    val left = if (aListSizeIsEven) odds.reversed().toLongArray() else evens.reversed().toLongArray()
    val right = if (aListSizeIsEven) evens else odds

    val answer = left + right

    println(answer.joinToString(separator = " "))
}