Problem:
Score : 400 points

Problem Statement

N people are arranged in a row from left to right.

You are given a string S of length N consisting of 0 and 1, and a positive integer K.

The i-th person from the left is standing on feet if the i-th character of S is 0, and standing on hands if that character is 1.

You will give the following direction at most K times (possibly zero):

Direction: Choose integers l and r satisfying 1 \leq l \leq r \leq N, and flip the l-th, (l+1)-th, ..., and r-th persons. That is, for each i = l, l+1, ..., r, the i-th person from the left now stands on hands if he/she was standing on feet, and stands on feet if he/she was standing on hands.

Find the maximum possible number of consecutive people standing on hands after at most K directions.

Constraints

N is an integer satisfying 1 \leq N \leq 10^5.

K is an integer satisfying 1 \leq K \leq 10^5.

The length of the string S is N.

Each character of the string S is 0 or 1.

Input

Input is given from Standard Input in the following format:

N K
S

Output

Print the maximum possible number of consecutive people standing on hands after at most K directions.

Sample Input 1

5 1
00010

Sample Output 1

4

We can have four consecutive people standing on hands, which is the maximum result, by giving the following direction:

Give the direction with l = 1, r = 3, which flips the first, second and third persons from the left.

Sample Input 2

14 2
11101010110011

Sample Output 2

8

Sample Input 3

1 1
1

Sample Output 3

1

No directions are necessary.

Solution in Kotlin (1.0.0) (judge verdict: Wrong Answer)

import com.sun.org.apache.xpath.internal.operations.Bool
import java.lang.Math.*

const val MOD = 1000000007L

fun main(args: Array<String>) {
    val (n, k) = readIntList()

    val s = readList().first()

    val m = mutableListOf<Int>()

    val connectM = mutableListOf<Int>()

    var prev = '-'
    var prevNum = 0
    var firstSakadatiIndex = -1
    s.forEachIndexed { index, c ->
        if (prev != c && prevNum > 0) {
            m.add(prevNum)
            prevNum = 1
        } else {
            prevNum++
        }
        prev = c

        if (firstSakadatiIndex == -1 && c == '1') {
            firstSakadatiIndex = m.size
        }
    }
    if (prevNum > 0) {
        m.add(prevNum)
    }


    m.size.rep {
        if (it % 2 != firstSakadatiIndex) {
            var sum = 0
            if (it > 0) {
                sum += m[it - 1]
            }
            if (it < m.size - 1) {
                sum += m[it + 1]
            }
            sum += m[it]
            connectM.add(sum)
        }
    }

    var ans = 0
    var sum = 0

    if (connectM.size == 0) {
        ans = n
    } else {
        k.rep {
            if (it < connectM.size) {
                ans += connectM[it]
            }
        }

        n.rep(start = k) { i ->
            if (i < connectM.size) {
                sum -= connectM[i - k]
                sum += connectM[i]
                ans = max(sum, ans)
            }
        }
    }



    println(ans)

}


fun readList() = readLine()!!.split(' ')
fun readInt() = readLine()!!.split(' ').map(String::toInt).first()
fun readIntList() = readList().map(String::toInt)
fun readLongList() = readList().map(String::toLong)
fun readDoubleList() = readList().map(String::toDouble)

fun readPair(): Pair<String, String> {
    val splite = readLine()!!.split(' ')
    return Pair(splite[0], splite[1])
}

fun <T> List<T>.copy() = this.map { it }

inline fun <reified T> dualArray(h: Int, w: Int, init: (Int, Int) -> T) {
    Array(h) { i ->
        return@Array Array(w) { j ->
            return@Array init(i, j)
        }
    }
}

// 速度のためforEachは避ける
inline fun Int.rep(start: Int = 0, shiftLast: Boolean = false, body: (Int) -> Unit) {
    for (i in start until if (shiftLast) this + start else this) {
        body(i)
    }
}

inline fun Long.rep(start: Long = 0, shiftLast: Boolean = false, body: (Long) -> Unit) {
    for (i in start until if (shiftLast) this + start else this) {
        body(i)
    }
}

// 約数のList
fun divisor(value: Long): List<Long> {
    val max = sqrt(value.toDouble()).toLong()
    val former = mutableListOf<Long>()
    val latter = mutableListOf<Long>()
    (1..max).filter { value % it == 0L }
        .forEach {
            former.add(it)
            latter.add(value / it)
        }
    former.addAll(latter.reversed())
    return former
}

// 範囲内の素数を取得
// fromだけ指定すると戻り値の個数で素数判定ができる
fun prime(from: Long, to: Long = from): List<Long> {
    return (from..to).filter { i ->
        val max = Math.sqrt(i.toDouble()).toLong()
        (2..max).all { j -> i % j != 0L }
    }
}

// 素因数分解
fun decom(value: Long): List<Long> {
    if (value == 1L) return listOf(1)
    val max = Math.sqrt(value.toDouble()).toLong()
    return prime(2, max).filter { value % it == 0L }
}

// 最大公約数
fun gcd(a: Long, b: Long): Long {
    return if (a % b == 0L) b else gcd(b, a % b)
}

// 文字列を入れ替え
fun swap(base: String, a: String, b: String): String {
    return base.map {
        when (it) {
            a.toCharArray()[0] -> b
            b.toCharArray()[0] -> a
            else -> it.toString()
        }
    }.joinToString()
}

// 二分探索
fun List<Long>.binarySearch(target: Long, _start: Int = 0, _end: Int = this.size): Int {
    var start = (_start - 1).toLong()
    var end = _end.toLong()
    while (end - start > 1) {
        val mid = (start + end) / 2
        if (this[mid.toInt()] < target) {
            start = mid
        } else {
            end = mid
        }
    }
    return end.toInt()
}

// bit全探索
inline fun Int.bitAllSearch(body: (Array<Int>) -> Unit) {
    for (bit in 0 until (1 shl this)) {
        val s = mutableListOf<Int>()
        for (i in 0 until this) {
            if ((bit and (1 shl i)) shr i == 1) { // i が bit に入るかどうか
                s.add(i)
            }
        }
        body(s.toTypedArray())
    }
}