Problem:
Score : 300 points

Problem Statement

Takahashi loves the number 7 and multiples of K.

Where is the first occurrence of a multiple of K in the sequence 7,77,777,\ldots? (Also see Output and Sample Input/Output below.)

If the sequence contains no multiples of K, print -1 instead.

Constraints

1 \leq K \leq 10^6

K is an integer.

Input

Input is given from Standard Input in the following format:

K

Output

Print an integer representing the position of the first occurrence of a multiple of K. (For example, if the first occurrence is the fourth element of the sequence, print 4.)

Sample Input 1

101

Sample Output 1

4

None of 7, 77, and 777 is a multiple of 101, but 7777 is.

Sample Input 2

2

Sample Output 2

-1

All elements in the sequence are odd numbers; there are no multiples of 2.

Sample Input 3

999983

Sample Output 3

999982

Solution in Kotlin (1.3.71) (judge verdict: Time Limit Exceeded)

import java.util.*

fun main(args: Array<String>) {
  val sc = Scanner(System.`in`)
  val k = sc.nextInt()

  var l: Int
  if (k % 7 == 0) {
    l = 9 * k / 7
  } else {
    l = 9 * k
  }


  if (l % 2 == 0 || l % 5 == 0) {
    println(-1)
    return
  }

  var i = 1
  while (true) {
    val tmp = Math.pow(10.0, i.toDouble()).toInt()
    if (tmp % l == 1) {
      println(i)
      return
    }

    i++
  }

}