Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Kotlin (1.0.0) (judge verdict: Accepted)

import java.util.*

fun main(args: Array<String>) {
    val sc = Scanner(System.`in`)
    val n = sc.nextInt()
    println(problem106b(n))
}

fun problem106b(n: Int): Int {
    fun countDivisor(n: Long): Long {
        var count = 0L
        for (i in 1..n) {
            if (n % i == 0L) count++
        }
        return count
    }
    var count = 0
    for (i in 1..n) {
        if (i % 2 != 0 && countDivisor(i.toLong()) == 8L) count++
    }
    return count
}