Problem:
Score : 100 points

Problem Statement

We have A balls with the string S written on each of them and B balls with the string T written on each of them.

From these balls, Takahashi chooses one with the string U written on it and throws it away.

Find the number of balls with the string S and balls with the string T that we have now.

Constraints

S, T, and U are strings consisting of lowercase English letters.

The lengths of S and T are each between 1 and 10 (inclusive).

S \not= T

S=U or T=U.

1 \leq A,B \leq 10

A and B are integers.

Input

Input is given from Standard Input in the following format:

S T
A B
U

Output

Print the answer, with space in between.

Sample Input 1

red blue
3 4
red

Sample Output 1

2 4

Takahashi chose a ball with red written on it and threw it away.
Now we have two balls with the string S and four balls with the string T.

Sample Input 2

red blue
5 5
blue

Sample Output 2

5 4

Takahashi chose a ball with blue written on it and threw it away.
Now we have five balls with the string S and four balls with the string T.

Solution in Kotlin (1.0.0) (judge verdict: Accepted)

fun main (args : Array<String>) {
    val (s, t) = readLine()!!.split(" ")
    val (a, b) = readLine()!!.split(" ")
    val u= readLine()!!

    var A : Int = a.toInt()
    var B : Int = b.toInt()

    if (u.toString() == s.toString()) {
        A--
    } else if (u.toString() == t.toString()) {
        B--
    }

    println("${A} ${B}")

}