Problem:
Score : 300 points

Problem Statement

You are given a sequence of length N: A_1, A_2, ..., A_N.
For each integer i between 1 and N (inclusive), answer the following question:

Find the maximum value among the N-1 elements other than A_i in the sequence.

Constraints

2 \leq N \leq 200000

1 \leq A_i \leq 200000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1
:
A_N

Output

Print N lines. The i-th line (1 \leq i \leq N) should contain the maximum value among the N-1 elements other than A_i in the sequence.

Sample Input 1

3
1
4
3

Sample Output 1

4
3
4

The maximum value among the two elements other than A_1, that is, A_2 = 4 and A_3 = 3, is 4.

The maximum value among the two elements other than A_2, that is, A_1 = 1 and A_3 = 3, is 3.

The maximum value among the two elements other than A_3, that is, A_1 = 1 and A_2 = 4, is 4.

Sample Input 2

2
5
5

Sample Output 2

5
5

Solution in Kotlin (1.0.0) (judge verdict: Accepted)

import java.io.PrintWriter
import kotlin.collections.*

val pw = PrintWriter(System.out)
fun main(args : Array<String>) {
    func()
    pw.flush()
}

    fun func() {
        val n = nextInt()
        val a = emptyList<Int>().toMutableList()
      	for(i in 0 until n){a.add(nextInt())}
        val a_s = a.map{e-> e}.sortedDescending()
      	for(i in 0 until n){
          if(a[i]==a_s[0]){println(a_s[1])}
          else println(a_s[0])
        }
    }

// 入力取得
fun next() = readLine()!!
fun nextInt() = next().toInt()
fun nextLong() = next().toLong()
fun nextDouble() = next().toDouble()
fun listOfString() = next().split(" ")
fun listOfInt() =listOfString().map { it.toInt() }
fun listOfLong() =listOfString().map { it.toLong() }
fun listOfDouble() =listOfString().map { it.toDouble() }

fun println(value : Any) {
    pw.println(value)
}