Problem:
Score : 200 points

Problem Statement

Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print -1 instead.

Constraints

2 \leq N \leq 10^5

0 \leq A_i \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the value A_1 \times ... \times A_N as an integer, or -1 if the value exceeds 10^{18}.

Sample Input 1

2
1000000000 1000000000

Sample Output 1

1000000000000000000

We have 1000000000 \times 1000000000 = 1000000000000000000.

Sample Input 2

3
101 9901 999999000001

Sample Output 2

-1

We have 101 \times 9901 \times 999999000001 = 1000000000000000001, which exceeds 10^{18}, so we should print -1 instead.

Sample Input 3

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0

Sample Output 3

0

Solution in Kotlin (1.3.71) (judge verdict: Accepted)

fun main (args:Array<String>) {
    val n = readLine()!!.toInt()
    val list = readLine()!!.split(" ").map(String::toLong)
    var ans = 1L
    if(0 in list) {
        print(0)
        return
    }
    for (i in 0..n-1){
        if(list[i] <= 1000000000000000000/ans){
            ans *= list[i]
        }
        else{
            print("-1")
            return
        }
    }
//    list.forEach{
//        if(ans * it <= 1000000000000000000/1){
//            ans *= it
//        }
//        else{
//            print("-1")
//            return
//        }
//    }
    print(ans)
}