Problem:
Score : 200 points

Problem Statement

Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print -1 instead.

Constraints

2 \leq N \leq 10^5

0 \leq A_i \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the value A_1 \times ... \times A_N as an integer, or -1 if the value exceeds 10^{18}.

Sample Input 1

2
1000000000 1000000000

Sample Output 1

1000000000000000000

We have 1000000000 \times 1000000000 = 1000000000000000000.

Sample Input 2

3
101 9901 999999000001

Sample Output 2

-1

We have 101 \times 9901 \times 999999000001 = 1000000000000000001, which exceeds 10^{18}, so we should print -1 instead.

Sample Input 3

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0

Sample Output 3

0

Solution in Kotlin (1.3.71) (judge verdict: Accepted)

fun main(args: Array<String>) {
    val line = readLine()!!.trim()
    val n: Long = line.toLong()
    val line2 = readLine()!!.trim()
    val nums: List<Long> = line2.split(" ").map {it.toLong()}.take(n.toInt())

    var prod: Long = 1L

    var maxNum: Long = 1L
    for (i in (0..17)) {
        maxNum *= 10L
    }

    if (nums.size == 0 || nums.contains(0L)) {
        prod = 0L
    } else {
        for (i in nums) {

            // val resultKeta: Int = result.toString().length
            // val iKeta: Int = i.toString().length

            if (i > maxNum / prod) {
                prod = -1
                break
            }

            prod *= i
        }

    }


    println(prod)
}