Problem:
Score : 200 points

Problem Statement

Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Constraints

1 \leq N \leq 10^4

1 \leq A \leq B \leq 36

All input values are integers.

Input

Input is given from Standard Input in the following format:

N A B

Output

Print the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Sample Input 1

20 2 5

Sample Output 1

84

Among the integers not greater than 20, the ones whose sums of digits are between 2 and 5, are: 2,3,4,5,11,12,13,14 and 20. We should print the sum of these, 84.

Sample Input 2

10 1 2

Sample Output 2

13

Sample Input 3

100 4 16

Sample Output 3

4554

Solution in Kotlin (1.0.0) (judge verdict: Accepted)

fun main(args: Array<String>) {

    var (n, a, b) = readLine()!!.split(" ").map { it.toInt() }

    var cnt = 0
    for (i in 1..n) {
        val sum = digitSum(i)
        if (sum in a..b) cnt += i
    }
    print(cnt)
}

fun digitSum(num: Int): Int{
    var sum = 0
    sum += num%10
    sum += num/10%10
    sum += num/100%10
    sum += num/1000%10
    sum += num/10000%10


    return sum
}