Problem:
Score : 200 points

Problem Statement

Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Constraints

1 \leq N \leq 10^4

1 \leq A \leq B \leq 36

All input values are integers.

Input

Input is given from Standard Input in the following format:

N A B

Output

Print the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Sample Input 1

20 2 5

Sample Output 1

84

Among the integers not greater than 20, the ones whose sums of digits are between 2 and 5, are: 2,3,4,5,11,12,13,14 and 20. We should print the sum of these, 84.

Sample Input 2

10 1 2

Sample Output 2

13

Sample Input 3

100 4 16

Sample Output 3

4554

Solution in Kotlin (1.3.71) (judge verdict: Wrong Answer)

fun main() {
    val (numMax, min, max) = readLine()!!.split(" ").map(String::toInt)
    var sum = 0

    for (i in 0..9) {
        for (j in 0..9) {
            var tmp = i + 10*j
            if(numMax >= 100){
                for(k in 1..9) {
                    tmp = i + 10*j + 100*k
                    if(numMax > 1000) {
                        for(l in 1..9) {
                            tmp = i + 10*j + 100*k + 1000*l
                            if((i+j+k+l) in min..max && tmp <= numMax) {
                                sum += tmp
                            }
                        }
                    }else if((i+j+k) in min..max && tmp <= numMax) {
                        sum += tmp
                    }
                }
            }else if(i + j in min..max && tmp <= numMax) {
                sum += tmp
            }
        }
    }
    println(sum)
}