Problem:
Score : 300 points

Problem Statement

You are given two non-negative integers L and R.
We will choose two integers i and j such that L \leq i < j \leq R.
Find the minimum possible value of (i \times j) \mbox{ mod } 2019.

Constraints

All values in input are integers.

0 \leq L < R \leq 2 \times 10^9

Input

Input is given from Standard Input in the following format:

L R

Output

Print the minimum possible value of (i \times j) \mbox{ mod } 2019 when i and j are chosen under the given condition.

Sample Input 1

2020 2040

Sample Output 1

2

When (i, j) = (2020, 2021), (i \times j) \mbox{ mod } 2019 = 2.

Sample Input 2

4 5

Sample Output 2

20

We have only one choice: (i, j) = (4, 5).

Solution in Kotlin (1.0.0) (judge verdict: Accepted)

fun main(args: Array<String>){
    val (l, r) = readLine()!!.split(" ").map { it.toInt() }

    if(l / 2019 != r / 2019){
        println(0)
    }else{
        var min = Long.MAX_VALUE / 10
        for(i in l..r - 1){
            for(j in i + 1..r){
                min = Math.min(min, (i % 2019L) * (j % 2019L) % 2019L)
            }
        }
        println(min)
    }
}