Problem:
Score : 300 points

Problem Statement

Does \sqrt{a} + \sqrt{b} < \sqrt{c} hold?

Constraints

1 \leq a, b, c \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

a \ b \ c

Output

If \sqrt{a} + \sqrt{b} < \sqrt{c}, print Yes; otherwise, print No.

Sample Input 1

2 3 9

Sample Output 1

No

\sqrt{2} + \sqrt{3} < \sqrt{9} does not hold.

Sample Input 2

2 3 10

Sample Output 2

Yes

\sqrt{2} + \sqrt{3} < \sqrt{10} holds.

Solution in Kotlin (1.0.0) (judge verdict: Wrong Answer)

import java.math.BigDecimal

fun main(args: Array<String>) {
    val (a, b, c) = readLine()!!.split(" ").map(String::toDouble)
    val decA = BigDecimal.valueOf(Math.sqrt(a))
    val decB = BigDecimal.valueOf(Math.sqrt(b))
    val decC = BigDecimal.valueOf(Math.sqrt(c))
    val decSum = decA.add(decB)
    if (decSum < decC) {
        println("Yes")
    } else {
        println("No")
    }
}