Problem:
Score : 300 points

Problem Statement

Does \sqrt{a} + \sqrt{b} < \sqrt{c} hold?

Constraints

1 \leq a, b, c \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

a \ b \ c

Output

If \sqrt{a} + \sqrt{b} < \sqrt{c}, print Yes; otherwise, print No.

Sample Input 1

2 3 9

Sample Output 1

No

\sqrt{2} + \sqrt{3} < \sqrt{9} does not hold.

Sample Input 2

2 3 10

Sample Output 2

Yes

\sqrt{2} + \sqrt{3} < \sqrt{10} holds.

Solution in Kotlin (1.0.0) (judge verdict: Wrong Answer)

fun main(args: Array<String>) {
    val (a, b, c) = listOfDouble()
    val ans = (Math.sqrt(a) + Math.sqrt(b)) < Math.sqrt(c)
    println(if (ans) "Yes" else "No")
}
fun Long.isEven() = (this % 2L) == 0L
fun Long.isOdd() = !this.isEven()
fun next() = readLine()!!
fun nextInt() = Integer.parseInt(next())
fun nextInt(offset: Int = 0) = nextInt() + offset
fun nextLong() = java.lang.Long.parseLong(next())
fun nextLong(offset: Long = 0L) = nextLong() + offset
fun nextDouble() = next().toDouble()
fun listOfString() = next().split(" ")
fun listOfInt() = listOfString().map { Integer.parseInt(it) }
fun listOfInt(offset: Int = 0) = listOfString().map { Integer.parseInt(it) + offset }
fun listOfLong() = listOfString().map { java.lang.Long.parseLong(it) }
fun listOfLong(offset: Long = 0L) = listOfString().map { java.lang.Long.parseLong(it) + offset }
fun listOfDouble() = listOfString().map { it.toDouble() }