Problem:
Score : 400 points

Problem Statement

Given is a number sequence A of length N.

Find the number of integers i \left(1 \leq i \leq N\right) with the following property:

For every integer j \left(1 \leq j \leq N\right) such that i \neq j , A_j does not divide A_i.

Constraints

All values in input are integers.

1 \leq N \leq 2 \times 10^5

1 \leq A_i \leq 10^6

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 \cdots A_N

Output

Print the answer.

Sample Input 1

5
24 11 8 3 16

Sample Output 1

3

The integers with the property are 2, 3, and 4.

Sample Input 2

4
5 5 5 5

Sample Output 2

0

Note that there can be multiple equal numbers.

Sample Input 3

10
33 18 45 28 8 19 89 86 2 4

Sample Output 3

5

Solution in Kotlin (1.3.71) (judge verdict: Runtime Error)

private fun readLn() = readLine()!!
private fun readInt() = readLn().toInt()
private fun readStrings() = readLn().split(" ")
private fun readInts() = readStrings().map(String::toInt)
private fun readStrings2() = readLn().split("").filter { it.isNotEmpty() }
private fun readInts2() = readStrings2().map(String::toInt)
private fun initArray(n:Int, v:String) = Array(n) { v }
private fun initIntArray(n:Int, v:Int) = IntArray(n) { v }

fun main(args: Array<String>) {
    val N = readInt()
    val A = readInts().sorted().reversed()
    var count = 0

    for (i in 0 until N-1) {
        var flag = true
        for (j in i+1 until N) {
            val tmp = A[i]%A[j]
            if(tmp == 0) {
                flag = false
                break
            }
        }
        if (flag) {
            count += 1
        }
    }
    if(A[N-2] != A[N-1]) {
        count += 1
    }
    println(count)
}