Problem:
Score : 200 points

Problem Statement

We have held a popularity poll for N items on sale. Item i received A_i votes.

From these N items, we will select M as popular items. However, we cannot select an item with less than \dfrac{1}{4M} of the total number of votes.

If M popular items can be selected, print Yes; otherwise, print No.

Constraints

1 \leq M \leq N \leq 100

1 \leq A_i \leq 1000

A_i are distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M
A_1 ... A_N

Output

If M popular items can be selected, print Yes; otherwise, print No.

Sample Input 1

4 1
5 4 2 1

Sample Output 1

Yes

There were 12 votes in total. The most popular item received 5 votes, and we can select it.

Sample Input 2

3 2
380 19 1

Sample Output 2

No

There were 400 votes in total. The second and third most popular items received less than \dfrac{1}{4\times 2} of the total number of votes, so we cannot select them. Thus, we cannot select two popular items.

Sample Input 3

12 3
4 56 78 901 2 345 67 890 123 45 6 789

Sample Output 3

Yes

Solution in Kotlin (1.3.71) (judge verdict: Accepted)


import java.lang.Math.ceil

fun main (args:Array<String>) {
    val (N, M) = readLine()!!.split(" ").map(String::toInt)
    val productList = readLine()!!.split(" ").map(String::toInt).sortedWith(reverseOrder())
    // prntln(productList)  // debug
    val minChooseablePoint = ceil(productList.sum() / (4.0 * M))
    // println(productList.sum().toString() + ", " + minChooseablePoint.toString())  // debug
    var chooseableCount = 0
    for (product in productList) {
        if (product < minChooseablePoint) break
        chooseableCount++
        if (chooseableCount == M) break
    }
    if (chooseableCount == M) print("Yes")
    else print("No")
}