Problem:
Score : 200 points

Problem Statement

Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print -1 instead.

Constraints

2 \leq N \leq 10^5

0 \leq A_i \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the value A_1 \times ... \times A_N as an integer, or -1 if the value exceeds 10^{18}.

Sample Input 1

2
1000000000 1000000000

Sample Output 1

1000000000000000000

We have 1000000000 \times 1000000000 = 1000000000000000000.

Sample Input 2

3
101 9901 999999000001

Sample Output 2

-1

We have 101 \times 9901 \times 999999000001 = 1000000000000000001, which exceeds 10^{18}, so we should print -1 instead.

Sample Input 3

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0

Sample Output 3

0

Solution in Kotlin (1.3.71) (judge verdict: Wrong Answer)

import java.io.PrintWriter
import kotlin.math.pow

// Helper
private val pw = PrintWriter(System.out)
private fun readLn() = readLine()!!
private fun readInt() = readLn().toInt()
private fun readStrings() = readLn().split(" ")
private fun readInts() = readStrings().map(String::toInt)
private fun readLongs() = readStrings().map(String::toLong)
private fun readDoubles() = readStrings().map(String::toDouble)
private fun readStrings2() = readLn().split("").filter { it.isNotEmpty() }
private fun readInts2() = readStrings2().map(String::toInt)
private fun initArray(n:Int, v:String) = Array(n) { v }
private fun initIntArray(n:Int, v:Int) = IntArray(n) { v }
private fun println(value : Any) = pw.println(value)

internal fun abc169b() {
    val N = readInt()
    val A = readDoubles()
    val sup = 10.0.pow(18.0)
    val ans = A.reduce { tmp, value ->
        tmp * value
    }
    if (ans > sup) {
        println(-1)
    } else {
        println(ans.toLong().toString())
    }
}

fun main(args: Array<String>) {
    abc169b()
    pw.flush()
}