Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in Kotlin (1.3.71) (judge verdict: Wrong Answer)

fun main(args: Array<String>) {
    
    val a = listOf(
            readLine()!!.split(" ").map { it.toInt() },
            readLine()!!.split(" ").map { it.toInt() },
            readLine()!!.split(" ").map { it.toInt() }
    )
    val n = readLine()!!.toInt()
    val b = (1..n).map { readLine()!!.toInt() }
    
/*
    val a = listOf(
            listOf(84, 97, 66),
            listOf(79, 89, 11),
            listOf(61, 59, 7)
    )
 
    val n = 7
 
    val b = listOf(
            89,
            7,
            87,
            79,
            24,
            84,
            30
    )
    */
 
    val card = listOf(
            mutableListOf(false, false, false),
            mutableListOf(false, false, false),
            mutableListOf(false, false, false)
    )
 
    b.forEach { value ->
        val pos = findPos(a, value)
        pos?.let { (x, y) ->
            card[y][x] = true
        }
    }
 
    if (isBingo(card)) {
        println("Yes")
    } else {
        println("No")
    }
}
 
fun findPos(list: List<List<Int>>, findValue: Int): Pair<Int, Int>? {
    list.forEachIndexed { y, xlist ->
        val x = xlist.indexOfFirst { it == findValue }
 
        if (x != -1) {
            return Pair(x, y)
        }
    }
 
    return null
}
 
fun isBingo(card: List<List<Boolean>>): Boolean {
    val length = card.size
 
    // 横のチェック
    card.forEach { xlist ->
        if (xlist.none { !it }) return true
    }
 
    // 縦のチェック
    (0 until length).forEach { y ->
        if ((0 until length).map { x -> card[y][x] }.none { !it }) return true
    }
 
    // 斜めのチェック
    if ((0 until length).map { card[it][it] }.none { !it }) return true
    if ((0 until length).map { card[it][length - 1 - it] }.none { !it }) return true
 
    return false
}