Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Kotlin (1.3.71) (judge verdict: Accepted)

import kotlin.math.sqrt

fun main() {
    val nmk = nextInt()
    val ans = solve(nmk)
    println(ans)
}

fun solve(nmk: Int): Int {
    val a = (1..nmk).filter { it % 2 != 0 }.filter {
        (1..nmk).filter { i -> it % i == 0 }.size == 8
    }

    return a.size

}

fun nextInt(): Int {
    return readLine()!!.toInt()
}