Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in Kotlin (1.3.71) (judge verdict: Wrong Answer)

import java.io.PrintWriter
import kotlin.math.min

fun main() {
    val pw = PrintWriter(System.out)

    var (n, a, b, c) = readInputLine().split(" ").map { it.toInt() }

    val query = Array(n) { readInputLine() }

    pw.println("Yes")

    for (i in 0 until n) {
        when(query[i]) {
            "AB" -> {
                if (a == 0 && b == 0) {
                    println("No")
                    return
                }
                if (a == 0) {
                    pw.println("A")
                    a++
                    b--
                } else if (b == 0) {
                    pw.println("B")
                    a--
                    b++
                } else if (a == 1 && b == 1 && query[min(i + 1, n - 1)] != "AB") {
                    if (query[min(i + 1, n - 1)] == "AC") {
                        pw.println("A")
                        a++
                        b--
                    } else {
                        pw.println("B")
                        a--
                        b++
                    }
                } else {
                    pw.println("A")
                    a++
                    b--
                }
            }
            "AC" -> {
                if (a == 0 && c == 0) {
                    println("No")
                    return
                }
                if (a == 0) {
                    pw.println("A")
                    a++
                    c--
                } else if (c == 0) {
                    pw.println("C")
                    a--
                    c++
                } else if (a == 1 && c == 1 && query[min(i + 1, n - 1)] != "AC") {
                    if (query[min(i + 1, n - 1)] == "AB") {
                        pw.println("A")
                        a++
                        c--
                    } else {
                        pw.println("C")
                        a--
                        c++
                    }
                } else {
                    pw.println("A")
                    a++
                    c--
                }
            }
            "BC" -> {
                if (b == 0 && c == 0) {
                    println("No")
                    return
                }
                if (b == 0) {
                    pw.println("B")
                    b++
                    c--
                } else if (c == 0) {
                    pw.println("C")
                    b--
                    c++
                } else if (b == 1 && c == 1 && query[min(i + 1, n - 1)] != "BC") {
                    if (query[min(i + 1, n - 1)] == "AB") {
                        pw.println("B")
                        b++
                        c--
                    } else {
                        pw.println("C")
                        b--
                        c++
                    }
                } else {
                    pw.println("B")
                    b++
                    c--
                }
            }
        }
    }

    pw.flush()
}

fun readInputLine(): String {
    return readLine()!!
}