Problem:
Score : 100 points

Problem Statement

We have A balls with the string S written on each of them and B balls with the string T written on each of them.

From these balls, Takahashi chooses one with the string U written on it and throws it away.

Find the number of balls with the string S and balls with the string T that we have now.

Constraints

S, T, and U are strings consisting of lowercase English letters.

The lengths of S and T are each between 1 and 10 (inclusive).

S \not= T

S=U or T=U.

1 \leq A,B \leq 10

A and B are integers.

Input

Input is given from Standard Input in the following format:

S T
A B
U

Output

Print the answer, with space in between.

Sample Input 1

red blue
3 4
red

Sample Output 1

2 4

Takahashi chose a ball with red written on it and threw it away.
Now we have two balls with the string S and four balls with the string T.

Sample Input 2

red blue
5 5
blue

Sample Output 2

5 4

Takahashi chose a ball with blue written on it and threw it away.
Now we have five balls with the string S and four balls with the string T.

Solution in Kotlin (1.0.0) (judge verdict: Wrong Answer)

fun main(args:Array<String>){
    val a=readLine()!!.split( " ")
    val b=readLine()!!.split( " ").map{it.toInt()}
    val c=readLine()!!
   if (a[0]==c){
        when {
            b[0]-1>=1 && b[1]>=1 ->{ println("${b[0]} ${b[1]}")}
            b[0]-1>=1 && b[1]==0 ->{ println("${b[0]}")}
            b[0]-1==0 && b[1]>=1 ->{ println("${b[1]}")}
        }
    }else if (a[1]==c){
        when {
            b[0] >= 1 && b[1] - 1 >= 1 -> {
                println("${b[0]} ${b[1]}")
            }
            b[0] >= 1 && b[1] - 1 == 0 -> {
                println("${b[0]}")
            }
            b[0] == 0 && b[1] - 1 >= 1 -> {
                println("${b[1]}")
            }
        }
   }
}