Problem:
Score : 400 points

Problem Statement

You are given an integer N. Among the divisors of N! (= 1 \times 2 \times ... \times N), how many Shichi-Go numbers (literally "Seven-Five numbers") are there?

Here, a Shichi-Go number is a positive integer that has exactly 75 divisors.

Note

When a positive integer A divides a positive integer B, A is said to a divisor of B.
For example, 6 has four divisors: 1, 2, 3 and 6.

Constraints

1 \leq N \leq 100

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

Print the number of the Shichi-Go numbers that are divisors of N!.

Sample Input 1

9

Sample Output 1

0

There are no Shichi-Go numbers among the divisors of 9! = 1 \times 2 \times ... \times 9 = 362880.

Sample Input 2

10

Sample Output 2

1

There is one Shichi-Go number among the divisors of 10! = 3628800: 32400.

Sample Input 3

100

Sample Output 3

543

Solution in Julia (0.5.0) (judge verdict: Accepted)

N=parse(Int,readline())
A=zeros(Int,100)
for i=1:N
	for j=2:i
		while i%j==0
			A[j]+=1
			i=div(i,j)
		end
	end
end
B=zeros(Int,100)
for a=A
	for i=1:a+1
		B[i]+=1
	end
end
println(B[75]+B[25]*(B[3]-1)+B[15]*(B[5]-1)+div(B[5]*(B[5]-1)*(B[3]-2),2))