Problem:
Score : 200 points

Problem Statement

There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is R, and a blue hat if s_i is B.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

1 \leq N \leq 100

|s| = N

s_i is R or B.

Input

Input is given from Standard Input in the following format:

N
s

Output

If there are more people wearing a red hat than there are people wearing a blue hat, print Yes; otherwise, print No.

Sample Input 1

4
RRBR

Sample Output 1

Yes

There are three people wearing a red hat, and one person wearing a blue hat.

Since there are more people wearing a red hat than people wearing a blue hat, the answer is Yes.

Sample Input 2

4
BRBR

Sample Output 2

No

There are two people wearing a red hat, and two people wearing a blue hat.

Since there are as many people wearing a red hat as people wearing a blue hat, the answer is No.

Solution in Julia (0.5.0) (judge verdict: Wrong Answer)

function readline_STDIN()
    return Base.readline(Base.STDIN)
end

function exawizards2019_B()

    # STEP.01
    # read out the number of people
    num_people = Base.parse(Base.Int64, readline_STDIN())

    # STEP.02
    # read out the string which represents the colors of the people
    colors_people = readline_STDIN()

    # STEP.03
    # count up the number of hats
    num_hats_red  = Base.zero(num_people)
    num_hats_blue = num_hats_red

    for itr in Base.range(1, 1, num_people)
        if colors_people[itr] == "R"
            num_hats_red += 1
        else
            num_hats_blue += 1
        end
    end

    # STEP.04
    # output the result
    if num_hats_red > num_hats_blue
        Base.println(Base.STDOUT, "Yes")
    else
        Base.println(Base.STDOUT, "No")
    end

    # STEP.TRUE_END
    return Base.nothing

end

Main.exawizards2019_B()