Problem:
Score : 400 points

Problem Statement

Given is a string S consisting of digits from 1 through 9.

Find the number of pairs of integers (i,j) (1 ≤ i ≤ j ≤ |S|) that satisfy the following condition:

Condition: In base ten, the i-th through j-th characters of S form an integer that is a multiple of 2019.

Constraints

1 ≤ |S| ≤ 200000

S is a string consisting of digits from 1 through 9.

Input

Input is given from Standard Input in the following format:

S

Output

Print the number of pairs of integers (i,j) (1 ≤ i ≤ j ≤ |S|) that satisfy the condition.

Sample Input 1

1817181712114

Sample Output 1

3

Three pairs - (1,5), (5,9), and (9,13) - satisfy the condition.

Sample Input 2

14282668646

Sample Output 2

2

Sample Input 3

2119

Sample Output 3

0

No pairs satisfy the condition.

Solution in Julia (1.4.0) (judge verdict: Wrong Answer)

function MultipleOf2019(str)
    S = str
    n = length(S)
    T = zeros(Int, n+1)
    N = zeros(Int, 2019)
    N[1] += 1
    for i in n:-1:1
        T[i] = mod(T[i+1] + parse(Int, S[i])*10^(n-i), 2019)
        N[T[i]+1] += 1
    end
#     println(T)
    println(sum(div(m*(m-1), 2) for m in N))
end
MultipleOf2019(readline())