Problem:
Score : 300 points

Problem Statement

Does \sqrt{a} + \sqrt{b} < \sqrt{c} hold?

Constraints

1 \leq a, b, c \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

a \ b \ c

Output

If \sqrt{a} + \sqrt{b} < \sqrt{c}, print Yes; otherwise, print No.

Sample Input 1

2 3 9

Sample Output 1

No

\sqrt{2} + \sqrt{3} < \sqrt{9} does not hold.

Sample Input 2

2 3 10

Sample Output 2

Yes

\sqrt{2} + \sqrt{3} < \sqrt{10} holds.

Solution in Julia (0.5.0) (judge verdict: Accepted)

A,B,C=map(x->parse(Int,x),split(readline()," "))

d=gcd(A,B,C)

A=div(A,d)
B=div(B,d)
C=div(C,d)

a = sqrt(big(A))
if (Int(ceil(a))^2==A )
  (a = Int(ceil(a)))
elseif (Int(floor(a))^2==A )
  (a  =Int(floor(a)))
end
b = sqrt(big(B))
if (Int(ceil(b))^2==B )
  (b = Int(ceil(b)))
elseif (Int(floor(b))^2==B )
  (b  =Int(floor(b)))
end
c = sqrt(big(C))
if (Int(ceil(c))^2==C )
  (c = Int(ceil(c)))
elseif (Int(floor(c))^2==C )
  (c  =Int(floor(c)))
end

an = (a+b < c ) ? "Yes" : "No"
print(an)