Problem:
Score : 200 points

Problem Statement

Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print -1 instead.

Constraints

2 \leq N \leq 10^5

0 \leq A_i \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the value A_1 \times ... \times A_N as an integer, or -1 if the value exceeds 10^{18}.

Sample Input 1

2
1000000000 1000000000

Sample Output 1

1000000000000000000

We have 1000000000 \times 1000000000 = 1000000000000000000.

Sample Input 2

3
101 9901 999999000001

Sample Output 2

-1

We have 101 \times 9901 \times 999999000001 = 1000000000000000001, which exceeds 10^{18}, so we should print -1 instead.

Sample Input 3

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0

Sample Output 3

0

Solution in Julia (1.4.0) (judge verdict: Wrong Answer)

T=readline()
#println("Input: ",split(tmp))
N=parse(Int64,T)
T=readline()
A=parse.(Int128,split(T))
#println("Input: $N, $A")
#println("typeof each args... ",typeof(A))
if minimum(A) != 0
    let i = 1
        ans = 1
        while i <= N
            ans = ans * A[i]
    #        if ans == 0
    #            break
    #        end
            if ans > Int64(1e18)
                global answer = -1
                break
            end
            i += 1
        end
    #    if ans < 0
    #        ans = -1
    #    end
        global answer = ans
    end
    println(answer)
else
    println(0)
end