Problem:
Score : 500 points

Problem Statement

We have N bulbs arranged on a number line, numbered 1 to N from left to right.
Bulb i is at coordinate i.

Each bulb has a non-negative integer parameter called intensity.
When there is a bulb of intensity d at coordinate x, the bulb illuminates the segment from coordinate x-d-0.5 to x+d+0.5.
Initially, the intensity of Bulb i is A_i. We will now do the following operation K times in a row:

For each integer i between 1 and N (inclusive), let B_i be the number of bulbs illuminating coordinate i. Then, change the intensity of each bulb i to B_i.

Find the intensity of each bulb after the K operations.

Constraints

1 \leq N \leq 2 \times 10^5

1 \leq K \leq 2 \times 10^5

0 \leq A_i \leq N

Input

Input is given from Standard Input in the following format:

N K
A_1 A_2 \ldots A_N

Output

Print the intensity A{'}_i of each bulb i after the K operations to Standard Output in the following format:

A{'}_1 A{'}_2 \ldots A{'}_N

Sample Input 1

5 1
1 0 0 1 0

Sample Output 1

1 2 2 1 2

Initially, only Bulb 1 illuminates coordinate 1, so the intensity of Bulb 1 becomes 1 after the operation.
Similarly, the bulbs initially illuminating coordinate 2 are Bulb 1 and 2, so the intensity of Bulb 2 becomes 2.

Sample Input 2

5 2
1 0 0 1 0

Sample Output 2

3 3 4 4 3

Solution in JavaScript (Node.js 12.16.1) (judge verdict: Wrong Answer)

"use strict";
var input = require("fs").readFileSync("/dev/stdin", "utf8");
var cin = input.split(/ |\n/),
    cid = 0;

function next() {
    return +cin[cid++];
} // number一個取得
function nextstr() {
    return cin[cid++];
} // 文字列一個取得
function nextbig() {
    return BigInt(cin[cid++]);
} // BigInteger一個取得
// 長さnの配列として取得。aは文字列フラグ
function nexts(n, a) {
    return a ? cin.slice(cid, cid += n) : cin.slice(cid, cid += n).map(a => +a);
}
// 長さnのBigInt配列として取得。
function nextsbig(n) {
    return cin.slice(cid, cid += n).map(a => BigInt(a));
}
// w個ずつを組にして長さhの配列。aは文字列フラグ。
function nextm(h, w, a) {
    var r = [],
        i = 0;
    if (a)
        for (; i < h; i++) r.push(cin.slice(cid, cid += w));
    else
        for (; i < h; i++) r.push(cin.slice(cid, cid += w).map(a => +a));
    return r;
}

function xArray(v) {
    var a = arguments,
        l = a.length,
        r = "Array(a[" + --l + "]).fill().map(x=>{return " + v + ";})";
    while (--l) r = "Array(a[" + l + "]).fill().map(x=>" + r + ")";
    return eval(r);
}


console.log(main().toString());

function main() {
    let N = next();
    let K = next();
    let AX = Array(K + 1);
    let A = nexts(N);
    for (let k = 0; k < K; k++) {
        let B = Array(N).fill(0);
        for (let i = 0; i < N; i++) {
            if (A[i] == 0) continue;
            // 各Aiの電球が各点zahyoを照らしているかどうかをチェックする。
            let min = Math.max(i + 1 - A[i], 1) - 1;
            let max = Math.min(i + 1 + A[i], N) - 1;
            console.log(i, min, max)
            for (let j = min; j <= max; j++) {
                B[j]++;
            }
        }
        A = B;
    }
    //    console.log(AX)
    return A.join(" ");
}