Problem:
Score : 400 points

Problem Statement

You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

In the i-th operation, you replace every element whose value is B_{i} with C_{i}.

For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

All values in input are integers.

1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}

B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:

N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}

Output

Print Q integers S_{i} to Standard Output in the following format:

S_{1}
S_{2}
\vdots
S_{Q}

Note that S_{i} may not fit into a 32-bit integer.

Sample Input 1

4
1 2 3 4
3
1 2
3 4
2 4

Sample Output 1

11
12
16

Initially, the sequence A is 1,2,3,4.

After each operation, it becomes the following:

2, 2, 3, 4

2, 2, 4, 4

4, 4, 4, 4

Sample Input 2

4
1 1 1 1
3
1 2
2 1
3 5

Sample Output 2

8
4
4

Note that the sequence A may not contain an element whose value is B_{i}.

Sample Input 3

2
1 2
3
1 100
2 100
100 1000

Sample Output 3

102
200
2000

Solution in JavaScript (Node.js 12.16.1) (judge verdict: Wrong Answer)

function Main(input){
    /** 入力値の作成 */
    const arr = input.trim().split('\n');
    const N = Number(arr.shift());
    const Ai = arr.shift().split(' ').map(Number);
    const Q = Number(arr.shift());
    let BiCi = [];
    for(let i=0; i<arr.length; i++){
        BiCi.push(arr[i].trim().split(' ').map(Number));
    }
    /** ここから本処理 */
    let box = new Array(100000).fill(0);
    for(let i=0; i<Ai.length; i++){
        box[Ai[i]]++;
    }
    log(box);
    let sum = Ai.reduce((a,b) => a+b);
    for(let i=0; i<BiCi.length; i++){
        sum +=  (BiCi[i][1] - BiCi[i][0]) * box[BiCi[i][0]];
        box[BiCi[i][1]] += box[BiCi[i][0]];
        box[BiCi[i][0]] = 0;
        console.log(sum);
    }
}