Problem:
Score : 400 points

Problem Statement

Takahashi has a string S consisting of lowercase English letters.

Starting with this string, he will produce a new one in the procedure given as follows.

The procedure consists of Q operations. In Operation i (1 \leq i \leq Q), an integer T_i is provided, which means the following:

If T_i = 1: reverse the string S.

If T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.

If F_i = 1 : Add C_i to the beginning of the string S.

If F_i = 2 : Add C_i to the end of the string S.

Help Takahashi by finding the final string that results from the procedure.

Constraints

1 \leq |S| \leq 10^5

S consists of lowercase English letters.

1 \leq Q \leq 2 \times 10^5

T_i = 1 or 2.

F_i = 1 or 2, if provided.

C_i is a lowercase English letter, if provided.

Input

Input is given from Standard Input in the following format:

S
Q
Query_1
:
Query_Q

In the 3-rd through the (Q+2)-th lines, Query_i is one of the following:

1

which means T_i = 1, and:

2 F_i C_i

which means T_i = 2.

Output

Print the resulting string.

Sample Input 1

a
4
2 1 p
1
2 2 c
1

Sample Output 1

cpa

There will be Q = 4 operations. Initially, S is a.

Operation 1: Add p at the beginning of S. S becomes pa.

Operation 2: Reverse S. S becomes ap.

Operation 3: Add c at the end of S. S becomes apc.

Operation 4: Reverse S. S becomes cpa.

Thus, the resulting string is cpa.

Sample Input 2

a
6
2 2 a
2 1 b
1
2 2 c
1
1

Sample Output 2

aabc

There will be Q = 6 operations. Initially, S is a.

Operation 1: S becomes aa.

Operation 2: S becomes baa.

Operation 3: S becomes aab.

Operation 4: S becomes aabc.

Operation 5: S becomes cbaa.

Operation 6: S becomes aabc.

Thus, the resulting string is aabc.

Sample Input 3

y
1
2 1 x

Sample Output 3

xy

Solution in JavaScript (Node.js 12.16.1) (judge verdict: Time Limit Exceeded)


function Main(input) {
  input = input.trim().split("\n").map(function(x) { return x.split(" ")});
  var S = input[0];
  var Q = parseInt(input[1], 10);
  //var arr_qu;
  var nReverse = 0;
  var addHead = [];
  var addTail = [];
  for (var i = 0; i < Q; i++){
    if (input[i + 2][0] === '1') {
      nReverse ++;
      continue;
    }
    if ((parseInt(input[i + 2][1], 10) + nReverse) % 2 ===0) {
      addTail.push(input[i + 2][2]);
      continue;
    }
    addHead.unshift(input[i + 2][2]);
  }
  var ans = addHead.concat(S[0].split(""), addTail);
  if (nReverse % 2 === 1) ans = ans.reverse();
  console.log(ans.join(""));
}   

Main(require("fs").readFileSync("/dev/stdin", "utf8"));