Problem:
Score : 300 points

Problem Statement

You are given four integers A, B, C, and D. Find the number of integers between A and B (inclusive) that can be evenly divided by neither C nor D.

Constraints

1\leq A\leq B\leq 10^{18}

1\leq C,D\leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B C D

Output

Print the number of integers between A and B (inclusive) that can be evenly divided by neither C nor D.

Sample Input 1

4 9 2 3

Sample Output 1

2

5 and 7 satisfy the condition.

Sample Input 2

10 40 6 8

Sample Output 2

23

Sample Input 3

314159265358979323 846264338327950288 419716939 937510582

Sample Output 3

532105071133627368

Solution in JavaScript (node.js v5.12) (judge verdict: Runtime Error)

function Main(input){
  input = input.split("\n");
  inputStr = input[0].split(" ");
  var A = Number.parseInt(inputStr[0]);
  var B = Number.parseInt(inputStr[1]);
  var C = Number.parseInt(inputStr[2]);
  var D = Number.parseInt(inputStr[3]);
  //変数を定義
  var ARR = [];	//C/Dの倍数を溜めるカウンタ
  var cnt = 0;	//回答に使うカウンタ
  //CとDの倍数を配列ARRに溜め込む
  var i = 1;
  while ( C * i <= B || D * i <= B ){
    ARR.push(C*i);
    ARR.push(D*i);
    i++;
  }
  //AからBまでループして、配列ARRに含まれない場合はcntを足し込む
  //console.log(ARR);
  for( var j = A; j < B+1; j++){
    var flg = 0;
	for(var j2 = 0; j2 < ARR.length ; j2++){
      if( ARR[j2] === j ){
        flg = 1;
        break;
      }
    }
    if(flg === 0){
      cnt += 1;
    }
    flg = 0;
  }
  console.log(cnt);
}
Main(require("fs").readFileSync("/dev/stdin", "utf8"));