Problem:
Score : 400 points

Problem Statement

You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

In the i-th operation, you replace every element whose value is B_{i} with C_{i}.

For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

All values in input are integers.

1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}

B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:

N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}

Output

Print Q integers S_{i} to Standard Output in the following format:

S_{1}
S_{2}
\vdots
S_{Q}

Note that S_{i} may not fit into a 32-bit integer.

Sample Input 1

4
1 2 3 4
3
1 2
3 4
2 4

Sample Output 1

11
12
16

Initially, the sequence A is 1,2,3,4.

After each operation, it becomes the following:

2, 2, 3, 4

2, 2, 4, 4

4, 4, 4, 4

Sample Input 2

4
1 1 1 1
3
1 2
2 1
3 5

Sample Output 2

8
4
4

Note that the sequence A may not contain an element whose value is B_{i}.

Sample Input 3

2
1 2
3
1 100
2 100
100 1000

Sample Output 3

102
200
2000

Solution in JavaScript (Node.js 12.16.1) (judge verdict: Runtime Error)

"use strict";

function main(arg) {
    lines = arg.split("\n")
    const N = Number(lines[0])
    let A = lines[1].split(" ").map(x=>Number(x))
    const Q = Number(lines[2])
    /*
    lines.shift()
    lines.shift()
    lines.shift()
    const B = lines.map(x=>Number(x.split(" ")[0]))
    const C = lines.map(x=>Number(x.split(" ")[1]))
    
    let sum = []
    sum[0] = A.reduce((a,b)=>a+b)//initial summation
    A.sort()
    for(let i=0; i<Q; i++) {
        let dif = 0
        for(let j=0; j<N; j++) {
            if(A[j]===B[i]) {
                A[j] = C[i]
                dif = dif + (C[i] - B[i])
            }
        }
        sum[i+1] = sum[i] + dif
    }
    sum.shift()
    console.log(sum.join("\n"))
    */
}

main(require("fs").readFileSync("/dev/stdin", "utf8"));