Problem:
Score : 200 points

Problem Statement

Given are integers a,b,c and d.
If x and y are integers and a \leq x \leq b and c\leq y \leq d hold, what is the maximum possible value of x \times y?

Constraints

-10^9 \leq a \leq b \leq 10^9

-10^9 \leq c \leq d \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

a b c d

Output

Print the answer.

Sample Input 1

1 2 1 1

Sample Output 1

2

If x = 1 and y = 1 then x \times y = 1.
If x = 2 and y = 1 then x \times y = 2.
Therefore, the answer is 2.

Sample Input 2

3 5 -4 -2

Sample Output 2

-6

The answer can be negative.

Sample Input 3

-1000000000 0 -1000000000 0

Sample Output 3

1000000000000000000

Solution in JavaScript (Node.js 12.16.1) (judge verdict: Wrong Answer)

const { SSL_OP_NO_SESSION_RESUMPTION_ON_RENEGOTIATION } = require("constants");
const readline = require("readline");
const rl = readline.createInterface({
  input: process.stdin,
  output: process.stdout
});

const solution = input => {
  [a,b,c,d] = input;
  let ans = b * d;
  ans = Math.max(ans, a * c);
  ans = Math.max(ans, a * d);
  ans = Math.max(ans, b * c);
  console.log(ans);
  
}

rl.on("line", function(line) {
  let input = line.split(' ');
  solution(input);
  rl.close();
}).on("close", function() {
  process.exit();
});