Problem:
Score : 200 points

Problem Statement

There are N students and M checkpoints on the xy-plane.

The coordinates of the i-th student (1 \leq i \leq N) is (a_i,b_i), and the coordinates of the checkpoint numbered j (1 \leq j \leq M) is (c_j,d_j).

When the teacher gives a signal, each student has to go to the nearest checkpoint measured in Manhattan distance.

The Manhattan distance between two points (x_1,y_1) and (x_2,y_2) is |x_1-x_2|+|y_1-y_2|.

Here, |x| denotes the absolute value of x.

If there are multiple nearest checkpoints for a student, he/she will select the checkpoint with the smallest index.

Which checkpoint will each student go to?

Constraints

1 \leq N,M \leq 50

-10^8 \leq a_i,b_i,c_j,d_j \leq 10^8

All input values are integers.

Input

The input is given from Standard Input in the following format:

N M
a_1 b_1
:
a_N b_N
c_1 d_1
:
c_M d_M

Output

Print N lines.

The i-th line (1 \leq i \leq N) should contain the index of the checkpoint for the i-th student to go.

Sample Input 1

2 2
2 0
0 0
-1 0
1 0

Sample Output 1

2
1

The Manhattan distance between the first student and each checkpoint is:

For checkpoint 1: |2-(-1)|+|0-0|=3

For checkpoint 2: |2-1|+|0-0|=1

The nearest checkpoint is checkpoint 2. Thus, the first line in the output should contain 2.

The Manhattan distance between the second student and each checkpoint is:

For checkpoint 1: |0-(-1)|+|0-0|=1

For checkpoint 2: |0-1|+|0-0|=1

When there are multiple nearest checkpoints, the student will go to the checkpoint with the smallest index. Thus, the second line in the output should contain 1.

Sample Input 2

3 4
10 10
-10 -10
3 3
1 2
2 3
3 5
3 5

Sample Output 2

3
1
2

There can be multiple checkpoints at the same coordinates.

Sample Input 3

5 5
-100000000 -100000000
-100000000 100000000
100000000 -100000000
100000000 100000000
0 0
0 0
100000000 100000000
100000000 -100000000
-100000000 100000000
-100000000 -100000000

Sample Output 3

5
4
3
2
1

Solution in JavaScript (node.js v5.12) (judge verdict: Accepted)

process.stdin.resume();
process.stdin.setEncoding('ascii');

var input_stdin = "";
var input_stdin_array = "";
var input_currentline = 0;

process.stdin.on('data', function (data) {
    input_stdin += data;
});

process.on('SIGINT', function(){
    input_stdin_array = input_stdin.split("\n");
    main();
    process.exit();
});

process.stdin.on('end', function () {
    input_stdin_array = input_stdin.split("\n");
    main();    
});

function readLine() {
    return input_stdin_array[input_currentline++];
}

/////////////// ignore above this line ////////////////////

function abs(x){
	if (x < 0) return -x;
	return x;
}

function calc_min(x,y,c,d,M){
	var idx=1, dis=abs(x-c[1])+abs(y-d[1]);
	for (var i=2; i <= M; i++){
		if (dis > abs(x-c[i]) + abs(y-d[i])){
			dis = abs(x-c[i]) + abs(y-d[i]);
			idx = i;
		}
	}
	return idx;
}

function main() {
	var N, M, s;
	var a=[0], b=[0], c=[0], d=[0];
	s = readLine().split(" ");
	N = parseInt(s[0]); M = parseInt(s[1]);
	for (var i=1; i <= N; i++){
		s = readLine().split(" ");
		x = parseInt(s[0]); y = parseInt(s[1]);
		a.push(x);
		b.push(y);
	}
	for (var i=1; i <= M; i++){
		s = readLine().split(" ");
		x = parseInt(s[0]); y = parseInt(s[1]);
		c.push(x);
		d.push(y);
	}
	for (var i=1; i <= N; i++){
		console.log(calc_min(a[i],b[i],c,d,M).toString());
	}
}