Problem:
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Transformation

Write a program which performs a sequence of commands to a given string $str$. The command is one of:

print a b: print from the a-th character to the b-th character of $str$

reverse a b: reverse from the a-th character to the b-th character of $str$

replace a b p: replace from the a-th character to the b-th character of $str$ with p

Note that the indices of $str$ start with 0.

Input

In the first line, a string $str$ is given. $str$ consists of lowercase letters. In the second line, the number of commands q is given. In the next q lines, each command is given in the above mentioned format.

Output

For each print command, print a string in a line.

Constraints

$1 \leq $ length of $str \leq 1000$

$1 \leq q \leq 100$

$0 \leq a \leq b < $ length of $str$

for replace command, $b - a + 1 = $ length of $p$

Sample Input 1

abcde
3
replace 1 3 xyz
reverse 0 2
print 1 4

Sample Output 1

xaze

Sample Input 2

xyz
3
print 0 2
replace 0 2 abc
print 0 2

Sample Output 2

xyz
abc

Solution in JavaScript (judge verdict: Accepted)

(function(input) {
    var a = input.split('\n');
    var s = a.shift();
    var n = Number(a.shift());
    var i = 0;
    while (i++ < n) {
        var c = a.shift().split(' ');
        s = command(s, c);
    }
})(require('fs').readFileSync('/dev/stdin', 'utf8'));

function command(s, c) {
    var com = c.shift();
    switch (com) {
        case 'print':
            var a = Number(c.shift());
            var b = Number(c.shift());
            console.log(s.slice(a, b + 1));
            break;
        case 'reverse':
            var a = Number(c.shift());
            var b = Number(c.shift());
            s = s.slice(0, a)
            + s.slice(a, b + 1).split('').reverse().join('')
            + s.slice(b + 1, s.length);
            break;
        case 'replace':
            var a = Number(c.shift());
            var b = Number(c.shift());
            var p = c.shift();
            s = s.slice(0, a)
            + p
            + s.slice(b + 1, s.length);
    }
    return s;
}