Problem:
Score : 200 points

Problem Statement

Today is August 24, one of the five Product Days in a year.

A date m-d (m is the month, d is the date) is called a Product Day when d is a two-digit number, and all of the following conditions are satisfied (here d_{10} is the tens digit of the day and d_1 is the ones digit of the day):

d_1 \geq 2

d_{10} \geq 2

d_1 \times d_{10} = m

Takahashi wants more Product Days, and he made a new calendar called Takahashi Calendar where a year consists of M month from Month 1 to Month M, and each month consists of D days from Day 1 to Day D.

In Takahashi Calendar, how many Product Days does a year have?

Constraints

All values in input are integers.

1 \leq M \leq 100

1 \leq D \leq 99

Input

Input is given from Standard Input in the following format:

M D

Output

Print the number of Product Days in a year in Takahashi Calender.

Sample Input 1

15 40

Sample Output 1

10

There are 10 Product Days in a year, as follows (m-d denotes Month m, Day d):

4-22

6-23

6-32

8-24

9-33

10-25

12-26

12-34

14-27

15-35

Sample Input 2

12 31

Sample Output 2

5

Sample Input 3

1 1

Sample Output 3

0

Solution in JavaScript (node.js v5.12) (judge verdict: Accepted)

function Main(input) {
  var maxM = parseInt(input.split(" ")[0]);
  var maxD = parseInt(input.split(" ")[1]);
  var output = 0;
  if(maxD < 22){
     console.log(output);
    return;
     }
  for(var i = 1; i <= maxM; i++){
    for(var j = 22; j <= maxD; j++){
      var tmp10 = parseInt(j.toString().split("")[0]);
      var tmp1 = parseInt(j.toString().split("")[1]);
      if(tmp1 <= 1){
         continue;
         }
      if(i == tmp10 * tmp1){
         output++;
         }
    }
  }
  console.log(output);
}

Main(require("fs").readFileSync("/dev/stdin", "utf8"));