Problem:
Score : 200 points

Problem Statement

Given are integers a,b,c and d.
If x and y are integers and a \leq x \leq b and c\leq y \leq d hold, what is the maximum possible value of x \times y?

Constraints

-10^9 \leq a \leq b \leq 10^9

-10^9 \leq c \leq d \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

a b c d

Output

Print the answer.

Sample Input 1

1 2 1 1

Sample Output 1

2

If x = 1 and y = 1 then x \times y = 1.
If x = 2 and y = 1 then x \times y = 2.
Therefore, the answer is 2.

Sample Input 2

3 5 -4 -2

Sample Output 2

-6

The answer can be negative.

Sample Input 3

-1000000000 0 -1000000000 0

Sample Output 3

1000000000000000000

Solution in JavaScript (Node.js 12.16.1) (judge verdict: Wrong Answer)


 "use strict";

const main = arg => {
  const input = arg.trim().split("\n");
  const [ a , b , c , d ] =(input[0].split(" "));//分割代入
  console.log(a);
  let ary = [];
  ary.push(a*c);
  ary.push(a*d);
  ary.push(b*c);
  ary.push(b*d);
  let res = Math.max(...ary);
  console.log(res);
  
}

main(require('fs').readFileSync('/dev/stdin', 'utf8'));