Problem:
Score : 300 points

Problem Statement

Given are an integer X and an integer sequence of length N: p_1, \ldots, p_N.

Among the integers not contained in the sequence p_1, \ldots, p_N (not necessarily positive), find the integer nearest to X, that is, find the integer whose absolute difference with X is the minimum. If there are multiple such integers, report the smallest such integer.

Constraints

1 \leq X \leq 100

0 \leq N \leq 100

1 \leq p_i \leq 100

p_1, \ldots, p_N are all distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X N
p_1 ... p_N

Output

Print the answer.

Sample Input 1

6 5
4 7 10 6 5

Sample Output 1

8

Among the integers not contained in the sequence 4, 7, 10, 6, 5, the one nearest to 6 is 8.

Sample Input 2

10 5
4 7 10 6 5

Sample Output 2

9

Among the integers not contained in the sequence 4, 7, 10, 6, 5, the ones nearest to 10 are 9 and 11. We should print the smaller one, 9.

Sample Input 3

100 0

Sample Output 3

100

When N = 0, the second line in the input will be empty. Also, as seen here, X itself can be the answer.

Solution in JavaScript (Node.js 12.16.1) (judge verdict: Accepted)

function*stdinIter(){const t=require("fs").readFileSync("/dev/stdin","utf-8").trim().split(/\n|\s/);yield*t}function readMany(t,e){const i=e||this.iter||(this.iter=stdinIter()),n=[];for(let e=0;e<t;e+=1)n.push(i.next().value);return n};

(() => {
    const [ x, n ] = readMany(2).map(it => parseInt(it))
    const p = readMany(n).map(it => parseInt(it)).sort()

    let candidate = -1
    let beforeCandidateAbs = Infinity
    for (let i = 0; i <= 101; i += 1) {
        if (p.includes(i)) continue

        const abs = Math.abs(i - x)
        if (abs < beforeCandidateAbs) {
            beforeCandidateAbs = abs
            candidate = i
        }
    }

    console.log(candidate)
})()