Problem:
Score : 200 points

Problem Statement

In some other world, today is the day before Christmas Eve.

Mr. Takaha is buying N items at a department store. The regular price of the i-th item (1 \leq i \leq N) is p_i yen (the currency of Japan).

He has a discount coupon, and can buy one item with the highest price for half the regular price. The remaining N-1 items cost their regular prices. What is the total amount he will pay?

Constraints

2 \leq N \leq 10

100 \leq p_i \leq 10000

p_i is an even number.

Input

Input is given from Standard Input in the following format:

N
p_1
p_2
:
p_N

Output

Print the total amount Mr. Takaha will pay.

Sample Input 1

3
4980
7980
6980

Sample Output 1

15950

The 7980-yen item gets the discount and the total is 4980 + 7980 / 2 + 6980 = 15950 yen.

Note that outputs such as 15950.0 will be judged as Wrong Answer.

Sample Input 2

4
4320
4320
4320
4320

Sample Output 2

15120

Only one of the four items gets the discount and the total is 4320 / 2 + 4320 + 4320 + 4320 = 15120 yen.

Solution in JavaScript (node.js v5.12) (judge verdict: Wrong Answer)

function Main(input){

  input = input.split('\n');
  for(var i=0;i<input.length;i++){
    input[i] = parseInt(input[i],10);
}
  var max;
  var sum;
  max = 0;
  sum = 0;
  
  for(var i=0;i<input.length;i++){
    if(input[i]>max){
      max = input[i];
    }
    sum = sum + input[i];
                      }
                      
                      
                      sum = sum - max/2;
                      console.log(sum);
                      }
                      
                      

  
 
Main(require("fs").readFileSync("/dev/stdin", "utf8"));