Problem:
Score : 200 points

Problem Statement

Given are integers a,b,c and d.
If x and y are integers and a \leq x \leq b and c\leq y \leq d hold, what is the maximum possible value of x \times y?

Constraints

-10^9 \leq a \leq b \leq 10^9

-10^9 \leq c \leq d \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

a b c d

Output

Print the answer.

Sample Input 1

1 2 1 1

Sample Output 1

2

If x = 1 and y = 1 then x \times y = 1.
If x = 2 and y = 1 then x \times y = 2.
Therefore, the answer is 2.

Sample Input 2

3 5 -4 -2

Sample Output 2

-6

The answer can be negative.

Sample Input 3

-1000000000 0 -1000000000 0

Sample Output 3

1000000000000000000

Solution in JavaScript (Node.js 12.16.1) (judge verdict: Wrong Answer)

function Main(input) {
  input = input.split(" ").map(n => parseInt(n, 10));
  const a = input[0];
  const b = input[1];
  const c = input[2];
  const d = input[3];

  if((a <= 0 && b >= 0) || (c <= 0 && d >= 0)){
    console.log(Math.max(a*c, a*d, b*c, b*d, 0))
  }else{
    console.log(Math.max(a*c, a*d, b*c, b*d))
  }
}
Main(require("fs").readFileSync("/dev/stdin", "utf8"));