Problem:
Score : 200 points

Problem Statement

There are N rabbits, numbered 1 through N.

The i-th (1≤i≤N) rabbit likes rabbit a_i.
Note that no rabbit can like itself, that is, a_i≠i.

For a pair of rabbits i and j (i＜j), we call the pair (i，j) a friendly pair if the following condition is met.

Rabbit i likes rabbit j and rabbit j likes rabbit i.

Calculate the number of the friendly pairs.

Constraints

2≤N≤10^5

1≤a_i≤N

a_i≠i

Input

The input is given from Standard Input in the following format:

N
a_1 a_2 ... a_N

Output

Print the number of the friendly pairs.

Sample Input 1

4
2 1 4 3

Sample Output 1

2

There are two friendly pairs: (1，2) and (3，4).

Sample Input 2

3
2 3 1

Sample Output 2

0

There are no friendly pairs.

Sample Input 3

5
5 5 5 5 1

Sample Output 3

1

There is one friendly pair: (1，5).

Solution in JavaScript (Node.js 12.16.1) (judge verdict: Accepted)

// inputに入力データ全体が入る
function Main(input) {
	// 1行目がinput[0], 2行目がinput[1], …に入る
	const inputLines = input.split("\n");
	const line0 = inputLines[0];
	const line0vars = line0.split(" ");
	const line1 = inputLines[1];
	const line1vars = line1.split(" ");

	const n = parseInt(line0vars[0], 10);

	var a = [];
	line1vars.forEach(v => a.push(parseInt(v, 10)));

	var sum = 0;
	for (var i = 1; i <= a.length; i++) {
		var j = a[i-1];
		// console.log({
		// 	i: i,
		// 	aim1: a[i-1],
		// 	j: j,
		// 	ajm1: a[j-1]
		// });
		
		if (i === a[j-1] && j === a[i-1]) {
			sum += 1;
		}
	}
	console.log(sum/2);
	// tmp = input[1].split(" ");
	// //文字列から10進数に変換するときはparseIntを使います
	// var a = parseInt(input[0], 10);
	// var b = parseInt(tmp[0], 10);
	// var c = parseInt(tmp[1], 10);
	// var s = input[2];

	//出力
	// console.log('%d %s',a+b+c,s);
}
//*この行以降は編集しないでください（標準入出力から一度に読み込み、Mainを呼び出します）
Main(require("fs").readFileSync("/dev/stdin", "utf8"));

// node index.js
// 1
// 2 3
// test
// (Ctrl + D)