Problem:
Sale Result

There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.

Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:

n (the number of data in the list)
i p q
i p q
:
:
i p q

Output

For each dataset, print a list of employee IDs or a text "NA"

Sample Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0

Output for the Sample Input

1001
1003
NA
2013

Solution in JavaScript (judge verdict: Wrong Answer)

function main(input) {
	var lines = input.split("\n");
	var dataSetLength = parseInt(lines[0]);
	var currentLine = 1;
	var salesTotals = [];
	while (currentLine < lines.length && dataSetLength > 0) {
		var sale = lines[currentLine].split(" ").map(function(value) {return parseInt(value)});
		if (sale.length === 1) {
			var validSales = salesTotals.reduce(function(result, value) {
				if (value.salesTotal >= 1000000) {
					result.push(value.id);
				}
				return result;
			}, []);
			if (validSales.length <= 0) {
				console.log("NA");
			} else {
				for(var i = 0; i < validSales.length; i++) {
					if(!isNaN(validSales[i])) console.log(validSales[i]);
				}
			}
			salesTotals = [];
		} else if(!isNaN(sale[1]) && !isNaN(sale[2])) {
			var saleIndex = 0;
			for (; saleIndex < salesTotals.length; saleIndex++) {
				if (salesTotals[saleIndex].id === sale[0]) break;
			}
			var currentSalesTotal = (salesTotals[saleIndex] || {salesTotal: 0}).salesTotal;
			salesTotals[saleIndex] = {
				id: sale[0],
				salesTotal: currentSalesTotal + (sale[1] * sale[2])
			};
		}
		currentLine++;
	}
}
main(require('fs').readFileSync('/dev/stdin','utf8'));