Problem:
Score : 200 points

Problem Statement

Given are integers a,b,c and d.
If x and y are integers and a \leq x \leq b and c\leq y \leq d hold, what is the maximum possible value of x \times y?

Constraints

-10^9 \leq a \leq b \leq 10^9

-10^9 \leq c \leq d \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

a b c d

Output

Print the answer.

Sample Input 1

1 2 1 1

Sample Output 1

2

If x = 1 and y = 1 then x \times y = 1.
If x = 2 and y = 1 then x \times y = 2.
Therefore, the answer is 2.

Sample Input 2

3 5 -4 -2

Sample Output 2

-6

The answer can be negative.

Sample Input 3

-1000000000 0 -1000000000 0

Sample Output 3

1000000000000000000

Solution in JavaScript (Node.js 12.16.1) (judge verdict: Wrong Answer)

process.stdin.resume();
process.stdin.setEncoding('utf8');
var lines = [];
var max;
var t = [];
var reader = require('readline').createInterface({
  input: process.stdin,
  output: process.stdout
});
reader.on('line', (line) => {
  lines.push(line);
});
reader.on('close', () => {
  var x = lines[0].split(' ');
  var a = parseInt(x[0]);
  var b= parseInt(x[1]);
  var c = parseInt(x[2]);
  var d = parseInt(x[3]);
  t.push(a*c);
  t.push(a*d);
  t.push(b*c);
  t.push(b*d);
  max = Math.max.apply(null,t);
  if(max == 0){
    max = Math.abs(max);
  }
  console.log(max);
});