Problem:
MathJax.Hub.Config({ tex2jax: { inlineMath: [["$","$"], ["\\(","\\)"]], processEscapes: true }});

You are given $n$ packages of $w_i$ kg from a belt conveyor in order ($i = 0, 1, ... n-1$). You should load all packages onto $k$ trucks which have the common maximum load $P$. Each truck can load consecutive packages (more than or equals to zero) from the belt conveyor unless the total weights of the packages in the sequence does not exceed the maximum load $P$.

Write a program which reads $n$, $k$ and $w_i$, and reports the minimum value of the maximum load $P$ to load all packages from the belt conveyor.

Input

In the first line, two integers $n$ and $k$ are given separated by a space character. In the following $n$ lines, $w_i$ are given respectively.

Output

Print the minimum value of $P$ in a line.

Constraints

$1 \leq n \leq 100,000$

$1 \leq k \leq 100,000$

$1 \leq w_i \leq 10,000$

Sample Input 1

5 3
8
1
7
3
9

Sample Output 1

10

If the first truck loads two packages of $\{8, 1\}$, the second truck loads two packages of $\{7, 3\}$ and the third truck loads a package of $\{9\}$, then the minimum value of the maximum load $P$ shall be 10.

Sample Input 2

4 2
1
2
2
6

Sample Output 2

6

If the first truck loads three packages of $\{1, 2, 2\}$ and the second truck loads a package of $\{6\}$, then the minimum value of the maximum load $P$ shall be 6.

Solution in JavaScript (judge verdict: Accepted)

"use strict"

/**
 * @param {number[]} ws
 * @param {number} p
 * @param {number} k
 */
const check = (ws, p, k) => {
  let sum = 0
  let kCount = 1
  let sumMax = 0
  for (let i = 0; i < ws.length; i++) {
    if (ws[i] > p) {
      // p大きさが足りない
      return -1
    }

    if (sum + ws[i] > p) {
      if (kCount === k) {
        // p大きさが足りない
        return -1
      } else {
        // 次のトラック
        kCount++
        sum = 0
      }
    }
    sum = sum + ws[i]

    // 1つのトラックあたりの最大積載量を更新
    if (sum > sumMax) sumMax = sum
  }
  // 荷物全部つめた

  // pをもっと小さくできるかもしれない
  return 1
}

/**
 * @param {number[]} ws
 * @param {number} k
 * @param {number} left
 * @param {number} right
 */
const search = (ws, k, left, right) => {
  if (left === right) return left
  let p = Math.floor((right + left) / 2)
  // console.log(`p:${p} left:${left} right:${right} k:${k}`)
  const result = check(ws, p, k)
  if (result < 0) return search(ws, k, p+1, right) // pは右側
  else if (result > 0) return search(ws, k, left, p) // pは左側
  else return p
}

let rows = 0
let n = 0
let k = 0
const ws = []
let sumW = 0
const reader = require("readline").createInterface({
  input: process.stdin,
  output: process.stdout,
})
reader.on("line", (line) => {
  rows++
  if (rows === 1) {
    ;[n, k] = line
      .trim()
      .split(" ")
      .map((x) => Number(x))
  } else {
    const w = Number(line.trim())
    ws.push(w)
    sumW = sumW + w
    if (rows - 1 === n) {
      const result = search(ws, k, 1, sumW)
      console.log(result)
      process.exit(0)
    }
  }
})