Problem:
Score : 400 points

Problem Statement

You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

In the i-th operation, you replace every element whose value is B_{i} with C_{i}.

For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

All values in input are integers.

1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}

B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:

N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}

Output

Print Q integers S_{i} to Standard Output in the following format:

S_{1}
S_{2}
\vdots
S_{Q}

Note that S_{i} may not fit into a 32-bit integer.

Sample Input 1

4
1 2 3 4
3
1 2
3 4
2 4

Sample Output 1

11
12
16

Initially, the sequence A is 1,2,3,4.

After each operation, it becomes the following:

2, 2, 3, 4

2, 2, 4, 4

4, 4, 4, 4

Sample Input 2

4
1 1 1 1
3
1 2
2 1
3 5

Sample Output 2

8
4
4

Note that the sequence A may not contain an element whose value is B_{i}.

Sample Input 3

2
1 2
3
1 100
2 100
100 1000

Sample Output 3

102
200
2000

Solution in JavaScript (Node.js 12.16.1) (judge verdict: Wrong Answer)

const main = (input) => {
  const ip = input.trim().split('\n')
  const arr = ip[1].split(' ').map(v => parseInt(v, 10))
  const n_q = parseInt(ip[2])
  const q = ip.slice(3)

  const nums = {}
  let currentSum = 0

  for (let v of arr) {
    currentSum += v
    nums[v] = ~~nums[v] + 1
  }

  for (let i = 0; i < n_q; i++) {
    const [pre, v] = q[i].split(' ').map(v => parseInt(v, 10))
    const dif = v - pre
    const count = ~~nums[pre]

    if (!count) continue

    nums[v] = ~~nums[v] + count

    currentSum += dif * count
    console.log(currentSum)
  }
}

process.env.MYTEST ? test() : main(require('fs').readFileSync('/dev/stdin', 'utf8'))