Problem:
Score : 200 points

Problem Statement

In some other world, today is the day before Christmas Eve.

Mr. Takaha is buying N items at a department store. The regular price of the i-th item (1 \leq i \leq N) is p_i yen (the currency of Japan).

He has a discount coupon, and can buy one item with the highest price for half the regular price. The remaining N-1 items cost their regular prices. What is the total amount he will pay?

Constraints

2 \leq N \leq 10

100 \leq p_i \leq 10000

p_i is an even number.

Input

Input is given from Standard Input in the following format:

N
p_1
p_2
:
p_N

Output

Print the total amount Mr. Takaha will pay.

Sample Input 1

3
4980
7980
6980

Sample Output 1

15950

The 7980-yen item gets the discount and the total is 4980 + 7980 / 2 + 6980 = 15950 yen.

Note that outputs such as 15950.0 will be judged as Wrong Answer.

Sample Input 2

4
4320
4320
4320
4320

Sample Output 2

15120

Only one of the four items gets the discount and the total is 4320 / 2 + 4320 + 4320 + 4320 = 15120 yen.

Solution in JavaScript (Node.js 12.16.1) (judge verdict: Wrong Answer)

function main(input) {
  const args = input.split('\n').map(n => parseInt(n, 10));
  const N = args[0];
  let ary = [];
  let sum = 0;
  
  for (let i = 1; i < args.length; i++) {
    ary.push(args[i]);
  }
  
  ary = ary.sort((a, b) => {
    return b - a;
  });
  
  for (let i = 0; i < ary.length; i++) {
    if (i === 0) {
      sum += (ary[i] / 2);
    } else {
      sum += ary[i];
    }
  }
  console.log(sum.toString());
}

main(require('fs').readFileSync('/dev/stdin', 'utf8'));