Problem:
Finding Missing Cards

Taro is going to play a card game. However, now he has only n cards, even though there should be 52 cards (he has no Jokers).

The 52 cards include 13 ranks of each of the four suits: spade, heart, club and diamond.

Input

In the first line, the number of cards n (n ≤ 52) is given.

In the following n lines, data of the n cards are given. Each card is given by a pair of a character and an integer which represent its suit and rank respectively. A suit is represented by 'S', 'H', 'C' and 'D' for spades, hearts, clubs and diamonds respectively. A rank is represented by an integer from 1 to 13.

Output

Print the missing cards. The same as the input format, each card should be printed with a character and an integer separated by a space character in a line.
Arrange the missing cards in the following priorities:

Print cards of spades, hearts, clubs and diamonds in this order.

If the suits are equal, print cards with lower ranks first.

Sample Input

47
S 10
S 11
S 12
S 13
H 1
H 2
S 6
S 7
S 8
S 9
H 6
H 8
H 9
H 10
H 11
H 4
H 5
S 2
S 3
S 4
S 5
H 12
H 13
C 1
C 2
D 1
D 2
D 3
D 4
D 5
D 6
D 7
C 3
C 4
C 5
C 6
C 7
C 8
C 9
C 10
C 11
C 13
D 9
D 10
D 11
D 12
D 13

Sample Output

S 1
H 3
H 7
C 12
D 8

Note

      解説

Solution in JavaScript (judge verdict: Accepted)

function shcdHash( key )
{
  var res = 0;
  if( 'S' == key ) {
    res = 0;
  } else if( 'H' == key ) {
    res = 1;
  } else if( 'C' == key ) {
    res = 2;
  } else if( 'D' == key ) {
    res = 3;
  }
  return res;
} 
var input = '';
var readable = process.stdin;
readable.resume();
readable.setEncoding( 'utf-8' );
readable.on( 'data', function( chunk ) {
  input += chunk;
});

readable.on( 'end', function() {
  var cards = { 'S':[] , 'H':[], 'C':[], 'D':[] };
  var shcd = [ 'S', 'H', 'C', 'D' ];
  for( var key in cards ) {
    for( var i=1; i<=13; i++ ) {
      cards[key].push( i );
    }
  }
  var data = input.split( '\n' );
 
  for( var i=1; i<data.length; i++ ) {
    var p = data[i].split( ' ' );
    var k = shcdHash( p[0] );
    var res = cards[ shcd[k] ].indexOf( Number( p[1] ) );
    if( -1 != res ) {
        cards[ shcd[k] ].splice( res, 1 );
    }
  }
  for( var i=0; i<4; i++ ) {
    for( var j = 0; j<cards[ shcd[i] ].length; j++ ) {
      console.log( shcd[i]+" "+cards[ shcd[i] ][j] );
    }
  }
});