Problem:
Score : 400 points

Problem Statement

Takahashi has a string S consisting of lowercase English letters.

Starting with this string, he will produce a new one in the procedure given as follows.

The procedure consists of Q operations. In Operation i (1 \leq i \leq Q), an integer T_i is provided, which means the following:

If T_i = 1: reverse the string S.

If T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.

If F_i = 1 : Add C_i to the beginning of the string S.

If F_i = 2 : Add C_i to the end of the string S.

Help Takahashi by finding the final string that results from the procedure.

Constraints

1 \leq |S| \leq 10^5

S consists of lowercase English letters.

1 \leq Q \leq 2 \times 10^5

T_i = 1 or 2.

F_i = 1 or 2, if provided.

C_i is a lowercase English letter, if provided.

Input

Input is given from Standard Input in the following format:

S
Q
Query_1
:
Query_Q

In the 3-rd through the (Q+2)-th lines, Query_i is one of the following:

1

which means T_i = 1, and:

2 F_i C_i

which means T_i = 2.

Output

Print the resulting string.

Sample Input 1

a
4
2 1 p
1
2 2 c
1

Sample Output 1

cpa

There will be Q = 4 operations. Initially, S is a.

Operation 1: Add p at the beginning of S. S becomes pa.

Operation 2: Reverse S. S becomes ap.

Operation 3: Add c at the end of S. S becomes apc.

Operation 4: Reverse S. S becomes cpa.

Thus, the resulting string is cpa.

Sample Input 2

a
6
2 2 a
2 1 b
1
2 2 c
1
1

Sample Output 2

aabc

There will be Q = 6 operations. Initially, S is a.

Operation 1: S becomes aa.

Operation 2: S becomes baa.

Operation 3: S becomes aab.

Operation 4: S becomes aabc.

Operation 5: S becomes cbaa.

Operation 6: S becomes aabc.

Thus, the resulting string is aabc.

Sample Input 3

y
1
2 1 x

Sample Output 3

xy

Solution in JavaScript (node.js v5.12) (judge verdict: Time Limit Exceeded)

function Main(input){
	var temp = input.trim().split("\n");
  	var S = temp[0];
  	var Q = parseInt(temp[1],10);
	var q_start = 2
  	for(var i = 0;i<Q;i++){
      	var row = temp[q_start+i].split(" ");
      	switch(parseInt(row[0],10)){
          case 1:
            S = reversestr(S);
            //console.log("case 1:" + S);
            break;
          case 2:
            S = addstr(S,row[2],parseInt(row[1],10));
            //console.log(row[2],row[1] + "case 2 :" + S);
            break;
          default:
            break;
        }
    }//for
  	console.log(S);
}
function reversestr(str){
	str = str.split("").reverse().join("");
  	return str;
}
function addstr(str,addstr,p){
	if(p == 1){
    	str = addstr + str;
    }else if(p == 2){
    	str = str + addstr;
    }
  	return str;
}
Main(require("fs").readFileSync("/dev/stdin","utf8"));