Problem:
Score : 200 points

Problem Statement

You are given an integer sequence A of length N.
Find the maximum absolute difference of two elements (with different indices) in A.

Constraints

2 \leq N \leq 100

1 \leq A_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

Print the maximum absolute difference of two elements (with different indices) in A.

Sample Input 1

4
1 4 6 3

Sample Output 1

5

The maximum absolute difference of two elements is A_3-A_1=6-1=5.

Sample Input 2

2
1000000000 1

Sample Output 2

999999999

Sample Input 3

5
1 1 1 1 1

Sample Output 3

0

Solution in JavaScript (node.js v5.12) (judge verdict: Accepted)

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r=n["Control.Applicative"],e=n["Control.Bind"],a=n["Control.Category"],o=n["Data.Either"],i=n["Data.Foldable"],u=n["Data.Functor"],c=n["Data.Int"],f=n["Data.Maybe"],l=n["Data.Monoid"],s=n["Data.Ord"],d=n["Data.Ring"],p=(n["Data.Semigroup"],n["Data.Show"]),D=(n["Data.String"],n["Data.String.Common"]),m=(n["Data.String.Pattern"],n["Data.Traversable"]),h=n["Data.Tuple"],v=n["Data.Unit"],w=n.Effect,g=n["Effect.Aff"],C=n["Effect.Class"],y=n["Effect.Ref"],b=n["Node.Encoding"],E=n["Node.Process"],A=n["Node.Stream"],S=n["Partial.Unsafe"],F=(n.Prelude,function(n){return o.either(function(n){return S.unsafeCrashWith(n)})(a.identity(a.categoryFn))(e.bind(o.bindEither)(o.note("n as")((t=n,2===(u=D.split("\n")(D.trim(t))).length?e.bind(f.bindMaybe)(c.fromString(u[0]))(function(n){return e.bind(f.bindMaybe)(m.traverse(m.traversableArray)(f.applicativeMaybe)(c.fromString)((t=u[1],D.split(" ")(t))))(function(t){return r.pure(f.applicativeMaybe)(new h.Tuple(n,t))});var t}):f.Nothing.value)))(function(n){return r.pure(o.applicativeEither)(p.show(p.showInt)((n.value0,function(n){return f["fromMaybe'"](function(n){return S.unsafeCrashWith("")})(e.bind(f.bindMaybe)(i.minimum(s.ordInt)(i.foldableArray)(n))(function(t){return e.bind(f.bindMaybe)(i.maximum(s.ordInt)(i.foldableArray)(n))(function(n){return r.pure(f.applicativeMaybe)(s.abs(s.ordInt)(d.ringInt)(n-t|0))})}))})(n.value1))+"\n")}));var t,u}),_=g.makeAff(function(n){return function(){var t=y.new("")();return A.onDataString(E.stdin)(b.UTF8.value)(function(n){return function(){var r=y.read(t)();return y.write(r+n)(t)()}})(),A.onEnd(E.stdin)(function(){var e=y.read(t)();return n(r.pure(o.applicativeEither)(e))()})(),l.mempty(g.monoidCanceler)}}),M=g.launchAff_(e.bind(g.bindAff)(_)(function(n){return e.bind(g.bindAff)(r.pure(g.applicativeAff)(F(n)))(function(n){return 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