Problem:
Score : 200 points

Problem Statement

A string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:

S is a palindrome.

Let N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.

The string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.

Determine whether S is a strong palindrome.

Constraints

S consists of lowercase English letters.

The length of S is an odd number between 3 and 99 (inclusive).

Input

Input is given from Standard Input in the following format:

S

Output

If S is a strong palindrome, print Yes;
otherwise, print No.

Sample Input 1

akasaka

Sample Output 1

Yes

S is akasaka.

The string formed by the 1-st through the 3-rd characters is aka.

The string formed by the 5-th through the 7-th characters is aka.
All of these are palindromes, so S is a strong palindrome.

Sample Input 2

level

Sample Output 2

No

Sample Input 3

atcoder

Sample Output 3

No

Solution in JavaScript (node.js v5.12) (judge verdict: Wrong Answer)

const main = (inputs) => {
  var array = inputs[0];
  var flag = true;
  if (array.length % 2 === 0) {
    console.log('No');
    return false;
  } else if (array.length <= 5) {
    for (var i = 0; i < array.length; i++) {
      if (array[i] === array[0]) {
        console.log('Yes');
        return false;
      } else {
        console.log('No');
        return false;
      }
    }
  }
  for (var i = 0; i < array.length / 2; i++) {
    var backWord = array[array.length - 1 - i];
    if (array[i] !== backWord) {
      flag = false;
      break;
    }
  }
  if (flag) {
    console.log('Yes');
  } else {
    console.log('No');
  }

}

main(require('fs').readFileSync('/dev/stdin', 'UTF-8').trim().split("\n"));