Problem:
Score : 300 points

Problem Statement

"Pizza At", a fast food chain, offers three kinds of pizza: "A-pizza", "B-pizza" and "AB-pizza". A-pizza and B-pizza are completely different pizzas, and AB-pizza is one half of A-pizza and one half of B-pizza combined together. The prices of one A-pizza, B-pizza and AB-pizza are A yen, B yen and C yen (yen is the currency of Japan), respectively.

Nakahashi needs to prepare X A-pizzas and Y B-pizzas for a party tonight. He can only obtain these pizzas by directly buying A-pizzas and B-pizzas, or buying two AB-pizzas and then rearrange them into one A-pizza and one B-pizza. At least how much money does he need for this? It is fine to have more pizzas than necessary by rearranging pizzas.

Constraints

1 ≤ A, B, C ≤ 5000

1 ≤ X, Y ≤ 10^5

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B C X Y

Output

Print the minimum amount of money required to prepare X A-pizzas and Y B-pizzas.

Sample Input 1

1500 2000 1600 3 2

Sample Output 1

7900

It is optimal to buy four AB-pizzas and rearrange them into two A-pizzas and two B-pizzas, then buy additional one A-pizza.

Sample Input 2

1500 2000 1900 3 2

Sample Output 2

8500

It is optimal to directly buy three A-pizzas and two B-pizzas.

Sample Input 3

1500 2000 500 90000 100000

Sample Output 3

100000000

It is optimal to buy 200000 AB-pizzas and rearrange them into 100000 A-pizzas and 100000 B-pizzas. We will have 10000 more A-pizzas than necessary, but that is fine.

Solution in JavaScript (node.js v5.12) (judge verdict: Accepted)

function Main(s) {
  s = s.split(" ").map(a => +a);
  var ans = s[0] * s[3];
  ans += s[1] * s[4];
  if(s[0] + s[1] > s[2] * 2){
    var m = Math.min(s[3], s[4]);
    ans -= (s[0] + s[1] - s[2] * 2) * m;
    s[3] -= m;
    s[4] -= m;
  }
  if(s[3]>0 && s[0]>s[2]*2)ans -= (s[0] - s[2] * 2) * s[3];
  if(s[4]>0 && s[1]>s[2]*2)ans -= (s[1] - s[2] * 2) * s[4];
  console.log(ans);
}
Main(require("fs").readFileSync("/dev/stdin","utf8"));