Problem:
Score : 200 points

Problem Statement

We have a long seat of width X centimeters.
There are many people who wants to sit here. A person sitting on the seat will always occupy an interval of length Y centimeters.

We would like to seat as many people as possible, but they are all very shy, and there must be a gap of length at least Z centimeters between two people, and between the end of the seat and a person.

At most how many people can sit on the seat?

Constraints

All input values are integers.

1 \leq X, Y, Z \leq 10^5

Y+2Z \leq X

Input

Input is given from Standard Input in the following format:

X Y Z

Output

Print the answer.

Sample Input 1

13 3 1

Sample Output 1

3

There is just enough room for three, as shown below:

Figure

Sample Input 2

12 3 1

Sample Output 2

2

Sample Input 3

100000 1 1

Sample Output 3

49999

Sample Input 4

64146 123 456

Sample Output 4

110

Sample Input 5

64145 123 456

Sample Output 5

109

Solution in JavaScript (node.js v5.12) (judge verdict: Wrong Answer)

'use strict'

const main = input => {
	const args = input.split('\n')[0].split(' ')
	const x = parseInt(args[0], 10)
	const y = parseInt(args[1], 10)
	const z = parseInt(args[2], 10)

	if (y + z * 2 < x) {
		console.log(Math.floor((x - (y + z * 2)) / (y + z) + 1))
	} else {
		console.log(0)
	}
}

main(require('fs').readFileSync('/dev/stdin', 'utf8'))