Problem:
Score : 300 points

Problem Statement

You are given an integer N. Among the integers between 1 and N (inclusive), how many Shichi-Go-San numbers (literally "Seven-Five-Three numbers") are there?

Here, a Shichi-Go-San number is a positive integer that satisfies the following condition:

When the number is written in base ten, each of the digits 7, 5 and 3 appears at least once, and the other digits never appear.

Constraints

1 \leq N < 10^9

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

Print the number of the Shichi-Go-San numbers between 1 and N (inclusive).

Sample Input 1

575

Sample Output 1

4

There are four Shichi-Go-San numbers not greater than 575: 357, 375, 537 and 573.

Sample Input 2

3600

Sample Output 2

13

There are 13 Shichi-Go-San numbers not greater than 3600: the above four numbers, 735, 753, 3357, 3375, 3537, 3557, 3573, 3575 and 3577.

Sample Input 3

999999999

Sample Output 3

26484

Solution in JavaScript (node.js v5.12) (judge verdict: Wrong Answer)

function main(input) {
    const args = input.split(" ");

    var No = parseInt(args[0], 10);
    var Earlier_No = parseInt(args[0].slice(1), 10);

    var ans = 0;

    if(Earlier_No.length !== 0) {
        ans = 1;
    }

    // Max桁 -1まで
    for (var i = 0; i < parseInt(Earlier_No.toString().length) - 1; i++) {
        if (i == parseInt(Earlier_No.toString().length) - 2) {
            ans = ans * 2;
        }
        else if (i == parseInt(Earlier_No.toString().length) -1) {
            break;
        }
        else {
            ans = ans* 3;
        }
    }

    var puls_ans = 0;
    var is753 = /^[753][753]*[753]$/;

    var flag_7 = false;
    var flag_5 = false;
    var flag_3 = false;

    var start_no = parseInt(args[0].slice(0, 1), 10) * Math.pow(10, (args[0].length - 1));

    for(; start_no < No; start_no++){
        if(is753.test(start_no.toString())) {
            start_no = start_no.toString();
            flag_7 = start_no.indexOf('7') !== -1;
            flag_5 = start_no.indexOf('5') !== -1;
            flag_3 = start_no.indexOf('3') !== -1;
            if (flag_7 && flag_5 && flag_3) {
                puls_ans++;
            }
        }
    }

    console.log(puls_ans + ans);
}

main(require('fs').readFileSync('/dev/stdin', 'utf8'));