Problem:
Score : 100 points

Problem Statement

In AtCoder City, there are three stations numbered 1, 2, and 3.

Each of these stations is operated by one of the two railway companies, A and B. A string S of length 3 represents which company operates each station. If S_i is A, Company A operates Station i; if S_i is B, Company B operates Station i.

To improve the transportation condition, for each pair of a station operated by Company A and one operated by Company B, there will be a bus service connecting them.

Determine if there is a pair of stations that will be connected by a bus service.

Constraints

Each character of S is A or B.

|S| = 3

Input

Input is given from Standard Input in the following format:

S

Output

If there is a pair of stations that will be connected by a bus service, print Yes; otherwise, print No.

Sample Input 1

ABA

Sample Output 1

Yes

Company A operates Station 1 and 3, while Company B operates Station 2.

There will be a bus service between Station 1 and 2, and between Station 2 and 3, so print Yes.

Sample Input 2

BBA

Sample Output 2

Yes

Company B operates Station 1 and 2, while Company A operates Station 3.

There will be a bus service between Station 1 and 3, and between Station 2 and 3, so print Yes.

Sample Input 3

BBB

Sample Output 3

No

Company B operates all the stations. Thus, there will be no bus service, so print No.

Solution in JavaScript (node.js v5.12) (judge verdict: Wrong Answer)

function toPlainValue(rawVal) {
    var splitVal = rawVal.toString().split('e');

    if(splitVal.length === 1) return splitVal[0];

    var period = splitVal[0].indexOf('.');

    if (0 < period ) splitVal[1] -= period ;

    return new Number(rawVal).toFixed(Math.abs(splitVal[1]));   
}



var input = require('fs').readFileSync('/dev/stdin', 'utf8');
var input_arr = input.split(' ');
var n = parseInt(input_arr[0]);
var b = parseInt(input_arr[1]);
var r = parseInt(input_arr[2]);


var less = n % (b + r);

var sum = b * parseInt(n / (b + r), 10);
if (less <= b) {
sum += less;
} else {
sum += b;
}

console.log(toPlainValue(sum));