Problem:
Score : 200 points

Problem Statement

A string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:

S is a palindrome.

Let N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.

The string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.

Determine whether S is a strong palindrome.

Constraints

S consists of lowercase English letters.

The length of S is an odd number between 3 and 99 (inclusive).

Input

Input is given from Standard Input in the following format:

S

Output

If S is a strong palindrome, print Yes;
otherwise, print No.

Sample Input 1

akasaka

Sample Output 1

Yes

S is akasaka.

The string formed by the 1-st through the 3-rd characters is aka.

The string formed by the 5-th through the 7-th characters is aka.
All of these are palindromes, so S is a strong palindrome.

Sample Input 2

level

Sample Output 2

No

Sample Input 3

atcoder

Sample Output 3

No

Solution in JavaScript (Node.js 12.16.1) (judge verdict: Accepted)

const { count } = require("console");

function main(lines) {
  const S = s();

  const N = S.length;
  const ans =  isPalindrome(S)
    && isPalindrome(S.slice(0, (N-1)/2))
    && isPalindrome(S.slice((N+1)/2))
    ? 'Yes' : 'No';
  
  return ans;
}

function isPalindrome(s) {
  return s == s.split('').reverse().join('');
}



const lines = require("fs").readFileSync("/dev/stdin", "utf8").trim().split("\n");

let lineCount = 0;
const s = () => lines[lineCount++];
const n = () => Number(s());
const b = () => BigInt(s());
const sa = () => s().split(' ');
const na = () => sa().map(Number);
const ba = () => sa().map(BigInt);

const ans = main(lines);
console.log( ans );