Problem:
Score : 300 points

Problem Statement

You are given an integer sequence of length n, a_1, ..., a_n.
Let us consider performing the following n operations on an empty sequence b.

The i-th operation is as follows:

Append a_i to the end of b.

Reverse the order of the elements in b.

Find the sequence b obtained after these n operations.

Constraints

1 \leq n \leq 2\times 10^5

0 \leq a_i \leq 10^9

n and a_i are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print n integers in a line with spaces in between.
The i-th integer should be b_i.

Sample Input 1

4
1 2 3 4

Sample Output 1

4 2 1 3

After step 1 of the first operation, b becomes: 1.

After step 2 of the first operation, b becomes: 1.

After step 1 of the second operation, b becomes: 1, 2.

After step 2 of the second operation, b becomes: 2, 1.

After step 1 of the third operation, b becomes: 2, 1, 3.

After step 2 of the third operation, b becomes: 3, 1, 2.

After step 1 of the fourth operation, b becomes: 3, 1, 2, 4.

After step 2 of the fourth operation, b becomes: 4, 2, 1, 3.

Thus, the answer is 4 2 1 3.

Sample Input 2

3
1 2 3

Sample Output 2

3 1 2

As shown above in Sample Output 1, b becomes 3, 1, 2 after step 2 of the third operation. Thus, the answer is 3 1 2.

Sample Input 3

1
1000000000

Sample Output 3

1000000000

Sample Input 4

6
0 6 7 6 7 0

Sample Output 4

0 6 6 0 7 7

Solution in JavaScript (node.js v5.12) (judge verdict: Runtime Error)

process.stdin.setEncoding( 'utf8' );

process.stdin.on( 'readable', function() {
    var chunk = process.stdin.read();
    var inputLineArr;

    if ( chunk !== null ) {
        inputLineArr = chunk.split('\n');

        if( inputLineArr[inputLineArr.length-1] == '' )
            inputLineArr.pop();

        var n = inputLineArr[0]
        var ai = inputLineArr[1].split(' ').map( function( elem ) {
            return parseInt(elem);
        } )

        var s1 = [],
            s2 = []

        if ( n % 2 === 0 ) {
            for ( var i = 0; i < n; i++ ) {
                if ( i % 2 === 0 ) {
                    s1.push( ai[i] )
                } else {
                    s2.push( ai[n-i] )
                }
            }

            console.log( s2.join(' ') + ' ' + s1.join(' ')  )
        } else {
            for ( var i = 0; i < n; i++ ) {
                if ( i % 2 !== 0 ) {
                    s1.push( ai[i] )
                } else {
                    s2.push( ai[n-i-1] )
                }
            }

            console.log( s2.join(' ') + ' ' + s1.join(' ')  )
        }

    }
} );