Problem:
Score : 200 points

Problem Statement

When Mr. X is away from home, he has decided to use his smartwatch to search the best route to go back home, to participate in ABC.

You, the smartwatch, has found N routes to his home.

If Mr. X uses the i-th of these routes, he will get home in time t_i at cost c_i.

Find the smallest cost of a route that takes not longer than time T.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq T \leq 1000

1 \leq c_i \leq 1000

1 \leq t_i \leq 1000

The pairs (c_i, t_i) are distinct.

Input

Input is given from Standard Input in the following format:

N T
c_1 t_1
c_2 t_2
:
c_N t_N

Output

Print the smallest cost of a route that takes not longer than time T.

If there is no route that takes not longer than time T, print TLE instead.

Sample Input 1

3 70
7 60
1 80
4 50

Sample Output 1

4

The first route gets him home at cost 7.

The second route takes longer than time T = 70.

The third route gets him home at cost 4.

Thus, the cost 4 of the third route is the minimum.

Sample Input 2

4 3
1 1000
2 4
3 1000
4 500

Sample Output 2

TLE

There is no route that takes not longer than time T = 3.

Sample Input 3

5 9
25 8
5 9
4 10
1000 1000
6 1

Sample Output 3

5

Solution in JavaScript (node.js v5.12) (judge verdict: Accepted)

// inputに入力データ全体が入る
function Main(input) {
    // 1行目がinput[0], 2行目がinput[1], …に入る
    input = input.split("\n");
    tmp0 = input[0].split(" ");
    N = Number(tmp0[0]);
    T = Number(tmp0[1]);
 // console.log(N,T);

    var ans=1001;
    for(i=1;i<=N;i++){
          tmp1 = input[i].split(" ");
          if(T>= Number(tmp1[1])){
                     c = Number(tmp1[0]);
                     ans= Math.min(ans,c);}
                        }
  
     if(ans==1001){console.log('TLE');} 
       else{console.log(ans);} 
     }        

    
  //*この行以降は編集しないでください（標準入出力から一度に読み込み、Mainを呼び出します）
  Main(require("fs").readFileSync("/dev/stdin", "utf8"));
//