Problem:
Score : 200 points

Problem Statement

Takahashi loves gold coins. He gains 1000 happiness points for each 500-yen coin he has and gains 5 happiness points for each 5-yen coin he has. (Yen is the currency of Japan.)

Takahashi has X yen. If he exchanges his money so that he will gain the most happiness points, how many happiness points will he earn?

(We assume that there are six kinds of coins available: 500-yen, 100-yen, 50-yen, 10-yen, 5-yen, and 1-yen coins.)

Constraints

0 \leq X \leq 10^9

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print the maximum number of happiness points that can be earned.

Sample Input 1

1024

Sample Output 1

2020

By exchanging his money so that he gets two 500-yen coins and four 5-yen coins, he gains 2020 happiness points, which is the maximum number of happiness points that can be earned.

Sample Input 2

0

Sample Output 2

0

He is penniless - or yenless.

Sample Input 3

1000000000

Sample Output 3

2000000000

He is a billionaire - in yen.

Solution in JavaScript (node.js v5.12) (judge verdict: Wrong Answer)

var input = require('fs').readFileSync('/dev/stdin', 'utf8');

function Calc(input){
  if(input === 0){
    console.log('高橋君は一文無しです。');
    
  }else if(input >= 5 && input < 500){
    var calcOver5 = Math.floor(input / 5) ;
    console.log(calc5 * 5);
  
  }else if(input >= 500 && input < 1000000000){
    var a = Math.floor(input / 500);
    var a2 = (input % 500);
    var a3 = Math.floor(a2 / 5);

    console.log(a*1000 + a3 * 5);
    
  }else{
      console.log('高橋君は大富豪です。');
  }
}