Problem:
Score : 200 points

Problem Statement

Takahashi went to an all-you-can-eat buffet with N kinds of dishes and ate all of them (Dish 1, Dish 2, \ldots, Dish N) once.

The i-th dish (1 \leq i \leq N) he ate was Dish A_i.

When he eats Dish i (1 \leq i \leq N), he gains B_i satisfaction points.

Additionally, when he eats Dish i+1 just after eating Dish i (1 \leq i \leq N - 1), he gains C_i more satisfaction points.

Find the sum of the satisfaction points he gained.

Constraints

All values in input are integers.

2 \leq N \leq 20

1 \leq A_i \leq N

A_1, A_2, ..., A_N are all different.

1 \leq B_i \leq 50

1 \leq C_i \leq 50

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N
B_1 B_2 ... B_N
C_1 C_2 ... C_{N-1}

Output

Print the sum of the satisfaction points Takahashi gained, as an integer.

Sample Input 1

3
3 1 2
2 5 4
3 6

Sample Output 1

14

Takahashi gained 14 satisfaction points in total, as follows:

First, he ate Dish 3 and gained 4 satisfaction points.

Next, he ate Dish 1 and gained 2 satisfaction points.

Lastly, he ate Dish 2 and gained 5 + 3 = 8 satisfaction points.

Sample Input 2

4
2 3 4 1
13 5 8 24
45 9 15

Sample Output 2

74

Sample Input 3

2
1 2
50 50
50

Sample Output 3

150

Solution in JavaScript (node.js v5.12) (judge verdict: Accepted)

function Main(input){
  var N = input.split("\n")[0];
  var A = input.split("\n")[1].split(" ");
  var B = input.split("\n")[2].split(" ");
  var C = input.split("\n")[3].split(" ");
  N = parseInt(N,10);

  for(i=0;i<=(N-1);i++){
    A[i] = parseInt(A[i],10);
    B[i] = parseInt(B[i],10);
  }
  for(i=0;i<=(N-2);i++){
    C[i] = parseInt(C[i],10);
  }

  var sati = 0;
  var jud;
  for(i=0;i<=(N-1);i++){
    jud = A[i] + 1 === A[i+1];
    if(jud===false){
      sati += B[(A[i]-1)];
    }else{
      if(i===(N-1)){
        sati += B[(A[i]-1)];
      }else{
      sati += (B[(A[i]-1)] + C[(A[i]-1)]);
      }
    }
  }
  console.log(sati);
}  

Main(require("fs").readFileSync("/dev/stdin", "utf8"));