Problem:
Score : 300 points

Problem Statement

The commonly used bills in Japan are 10000-yen, 5000-yen and 1000-yen bills. Below, the word "bill" refers to only these.

According to Aohashi, he received an otoshidama (New Year money gift) envelope from his grandfather that contained N bills for a total of Y yen, but he may be lying. Determine whether such a situation is possible, and if it is, find a possible set of bills contained in the envelope. Assume that his grandfather is rich enough, and the envelope was large enough.

Constraints

1 ≤ N ≤ 2000

1000 ≤ Y ≤ 2 × 10^7

N is an integer.

Y is a multiple of 1000.

Input

Input is given from Standard Input in the following format:

N Y

Output

If the total value of N bills cannot be Y yen, print -1 -1 -1.

If the total value of N bills can be Y yen, let one such set of bills be "x 10000-yen bills, y 5000-yen bills and z 1000-yen bills", and print x, y, z with spaces in between. If there are multiple possibilities, any of them may be printed.

Sample Input 1

9 45000

Sample Output 1

4 0 5

If the envelope contained 4 10000-yen bills and 5 1000-yen bills, he had 9 bills and 45000 yen in total. It is also possible that the envelope contained 9 5000-yen bills, so the output 0 9 0 is also correct.

Sample Input 2

20 196000

Sample Output 2

-1 -1 -1

When the envelope contained 20 bills in total, the total value would be 200000 yen if all the bills were 10000-yen bills, and would be at most 195000 yen otherwise, so it would never be 196000 yen.

Sample Input 3

1000 1234000

Sample Output 3

14 27 959

There are also many other possibilities.

Sample Input 4

2000 20000000

Sample Output 4

2000 0 0

Solution in JavaScript (Node.js 12.16.1) (judge verdict: Accepted)

function main(input){
  var str = input.split(' ');
  var int = [];
  int.push(parseInt(str[0]));//入っているお札の枚数:N
  int.push(parseInt(str[1]));//合計金額:Y
  
  money:
  for(let i=0;i<=int[0];i++){
    for(let j=0;j<=int[0];j++){
      var com = 9*i+4*j;
      if(com === int[1]/1000-int[0]){
        var thou = int[0] - (i+j);
      	if(thou >=0){
          var fiveThou = j;
          var tenThou = i;
           break money;
        }else{
          continue;
        }
      }else{
        var thou = -1;
        var fiveThou = -1;
        var tenThou = -1;
      }
    }
  }
  console.log(tenThou+' '+fiveThou+' '+thou);
}
main(require('fs').readFileSync('/dev/stdin', 'utf8'));