Problem:
Score : 200 points

Problem Statement

We have held a popularity poll for N items on sale. Item i received A_i votes.

From these N items, we will select M as popular items. However, we cannot select an item with less than \dfrac{1}{4M} of the total number of votes.

If M popular items can be selected, print Yes; otherwise, print No.

Constraints

1 \leq M \leq N \leq 100

1 \leq A_i \leq 1000

A_i are distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M
A_1 ... A_N

Output

If M popular items can be selected, print Yes; otherwise, print No.

Sample Input 1

4 1
5 4 2 1

Sample Output 1

Yes

There were 12 votes in total. The most popular item received 5 votes, and we can select it.

Sample Input 2

3 2
380 19 1

Sample Output 2

No

There were 400 votes in total. The second and third most popular items received less than \dfrac{1}{4\times 2} of the total number of votes, so we cannot select them. Thus, we cannot select two popular items.

Sample Input 3

12 3
4 56 78 901 2 345 67 890 123 45 6 789

Sample Output 3

Yes

Solution in JavaScript (node.js v5.12) (judge verdict: Wrong Answer)

// ABC 161
"use strict"

//inputに入力データ全体が入る
function Main(input) {
  input = input.split("\n");
  const N = parseInt(input[0].split(" ")[0],10); //要素数
  const M = parseInt(input[0].split(" ")[1],10); //人気商品の数
  let A = input[1].split(" "); //各商品の数
  const sum = total(A); //総投票数
  let result = "Yes";

  // 降順
  A.sort(
    function(a,b){
      return (a < b ? 1 : -1);
    }
  );

  // 総得票数の1/4M未満ならNo
  for(let i=0;i<M;i++) {
    if(parseInt(A[i],10) < parseInt(sum * (1/(4*M))),10)result = "No";
  };
  console.log(result);
}

function total(arr) {
  let sum = 0;
  for(let i=0;i<arr.length;i++) {
    sum += parseInt(arr[i],10);
  }
  return sum;
}

Main(require("fs").readFileSync("/dev/stdin", "utf8"));