Problem:
Score : 200 points

Problem Statement

Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print -1 instead.

Constraints

2 \leq N \leq 10^5

0 \leq A_i \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the value A_1 \times ... \times A_N as an integer, or -1 if the value exceeds 10^{18}.

Sample Input 1

2
1000000000 1000000000

Sample Output 1

1000000000000000000

We have 1000000000 \times 1000000000 = 1000000000000000000.

Sample Input 2

3
101 9901 999999000001

Sample Output 2

-1

We have 101 \times 9901 \times 999999000001 = 1000000000000000001, which exceeds 10^{18}, so we should print -1 instead.

Sample Input 3

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0

Sample Output 3

0

Solution in JavaScript (Node.js 12.16.1) (judge verdict: Runtime Error)

#include <bits/stdc++.h>
#define rep(i,n) for (int i = 0; i < (n); ++i)
using namespace std;
using ll = long long;
using P = pair<int,int>;
 
int main(){
	int n;
	cin >> n;
	unsigned long long ans = 1;
	int f = 0;
	rep(i, n){
		unsigned long long in;
		cin >> in;
		unsigned long long ans0 = ans;
		unsigned long long in0 = in;
		int ansk = 0;
		int ink = 0;
		ans *= in;
		while(ans0 >= 10){
			ans0 /= 10;
			ansk++;
		}
		while(in0 >= 10){
			in0 /= 10;
			ink++;
		}
		if(ink + ansk > 18){
			f = 1;
			ans = 1;
		}
		if(ink + ansk == 18 && ans0 * in0 > 1){
			f = 1;
			ans = 1;
		}
		//cout << ink << ' '  << ansk << endl;
		
		if(ans > 1000000000000000000){
			f = 1;
			ans = 1;
		}
	}
	if(ans == 0){
		cout << 0 << endl;
	}else if(f == 1){
		cout << -1 << endl;
	}else{
		cout << ans << endl;
	}
	return 0;
}