Problem:
Score : 300 points

Problem Statement

Does \sqrt{a} + \sqrt{b} < \sqrt{c} hold?

Constraints

1 \leq a, b, c \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

a \ b \ c

Output

If \sqrt{a} + \sqrt{b} < \sqrt{c}, print Yes; otherwise, print No.

Sample Input 1

2 3 9

Sample Output 1

No

\sqrt{2} + \sqrt{3} < \sqrt{9} does not hold.

Sample Input 2

2 3 10

Sample Output 2

Yes

\sqrt{2} + \sqrt{3} < \sqrt{10} holds.

Solution in JavaScript (node.js v5.12) (judge verdict: Wrong Answer)


function Main(input) {
  // 1行目がinput[0], 2行目がinput[1], …に入る
  input = input.split(" ");
  const a = Number(input[0]);
  const b = Number(input[1]);
  const c = Number(input[2]);
  if (Math.sqrt(c) > Math.sqrt(a) + Math.sqrt(b)) {

    console.log("Yes");
  } else if (Math.sqrt(c) <= Math.sqrt(a) + Math.sqrt(b)) {
    console.log("No");
  }
}
//*この行以降は編集しないでください（標準入出力から一度に読み込み、Mainを呼び出します）
Main(require("fs").readFileSync("/dev/stdin", "utf8"));