Problem:
Score : 200 points

Problem Statement

Our world is one-dimensional, and ruled by two empires called Empire A and Empire B.

The capital of Empire A is located at coordinate X, and that of Empire B is located at coordinate Y.

One day, Empire A becomes inclined to put the cities at coordinates x_1, x_2, ..., x_N under its control, and Empire B becomes inclined to put the cities at coordinates y_1, y_2, ..., y_M under its control.

If there exists an integer Z that satisfies all of the following three conditions, they will come to an agreement, but otherwise war will break out.

X < Z \leq Y

x_1, x_2, ..., x_N < Z

y_1, y_2, ..., y_M \geq Z

Determine if war will break out.

Constraints

All values in input are integers.

1 \leq N, M \leq 100

-100 \leq X < Y \leq 100

-100 \leq x_i, y_i \leq 100

x_1, x_2, ..., x_N \neq X

x_i are all different.

y_1, y_2, ..., y_M \neq Y

y_i are all different.

Input

Input is given from Standard Input in the following format:

N M X Y
x_1 x_2 ... x_N
y_1 y_2 ... y_M

Output

If war will break out, print War; otherwise, print No War.

Sample Input 1

3 2 10 20
8 15 13
16 22

Sample Output 1

No War

The choice Z = 16 satisfies all of the three conditions as follows, thus they will come to an agreement.

X = 10 < 16 \leq 20 = Y

8, 15, 13 < 16

16, 22 \geq 16

Sample Input 2

4 2 -48 -1
-20 -35 -91 -23
-22 66

Sample Output 2

War

Sample Input 3

5 3 6 8
-10 3 1 5 -100
100 6 14

Sample Output 3

War

Solution in JavaScript (node.js v5.12) (judge verdict: Accepted)

function main(input) {
  input=input.trim();
  const N = parseInt(input.split(" ")[0], 10);
  const M = parseInt(input.split(" ")[1], 10);
  const X = parseInt(input.split(" ")[2], 10);
  const Y = parseInt(input.split(" ")[3], 10);
  const arrX = input.split('\n')[1].split(' ').map((n) => parseInt(n, 10));
  const arrY = input.split('\n')[2].split(' ').map((n) => parseInt(n, 10));
  var ans=0

  //Zで全探索
  for(var i=0; i<Y-X; i++){
    var judgeX=0;
    var judgeY=0;
    var Z=X+1+i;
    for(var j=0; j<N; j++){
      if(arrX[j]>=Z){
        judgeX++;
      }
    }
    for(var k=0; k<M; k++){
      if(arrY[k]<Z){
        judgeY++;
      }
    }
    //条件に反する場合ans処理しない
    if(judgeX>0||judgeY>0){
    }else{
      ans++
    }
  }

  if(ans>0){
    console.log("No War");
  }else{
    console.log("War");
  }

}
main(require('fs').readFileSync('/dev/stdin', 'utf8'));