Problem:
Score : 300 points

Problem Statement

The commonly used bills in Japan are 10000-yen, 5000-yen and 1000-yen bills. Below, the word "bill" refers to only these.

According to Aohashi, he received an otoshidama (New Year money gift) envelope from his grandfather that contained N bills for a total of Y yen, but he may be lying. Determine whether such a situation is possible, and if it is, find a possible set of bills contained in the envelope. Assume that his grandfather is rich enough, and the envelope was large enough.

Constraints

1 ≤ N ≤ 2000

1000 ≤ Y ≤ 2 × 10^7

N is an integer.

Y is a multiple of 1000.

Input

Input is given from Standard Input in the following format:

N Y

Output

If the total value of N bills cannot be Y yen, print -1 -1 -1.

If the total value of N bills can be Y yen, let one such set of bills be "x 10000-yen bills, y 5000-yen bills and z 1000-yen bills", and print x, y, z with spaces in between. If there are multiple possibilities, any of them may be printed.

Sample Input 1

9 45000

Sample Output 1

4 0 5

If the envelope contained 4 10000-yen bills and 5 1000-yen bills, he had 9 bills and 45000 yen in total. It is also possible that the envelope contained 9 5000-yen bills, so the output 0 9 0 is also correct.

Sample Input 2

20 196000

Sample Output 2

-1 -1 -1

When the envelope contained 20 bills in total, the total value would be 200000 yen if all the bills were 10000-yen bills, and would be at most 195000 yen otherwise, so it would never be 196000 yen.

Sample Input 3

1000 1234000

Sample Output 3

14 27 959

There are also many other possibilities.

Sample Input 4

2000 20000000

Sample Output 4

2000 0 0

Solution in JavaScript (node.js v5.12) (judge verdict: Wrong Answer)

"use strict";
function Main(input) {
  input = input.split("\n");
  const totalNums = parseInt(input[0], 10);
  const otoshidamas = parseInt(input[1], 10);
  let result = "-1-1-1";
  
  for(let ichimanen = 0; ichimanen <= totalNums; ichimanen++){
      for(let gosenen = 0; gosenen <= totalNums; gosenen++){
          let senen = totalNums - (ichimanen + gosenen);
          let total = ichimanen + gosenen + senen;
          let otoshidamaSumTotal = (ichimanen*10000) + (gosenen*5000) + (senen*1000);
          if(total === totalNums && otoshidamaSumTotal === otoshidamas && senen >= 0){
              //result = "${ichimanen} ${gosenen} ${senen}"
              result = "(ichimanen)+(gosenen)+(senen)"
          }
      }
  }
  console.log(result);
}
 
Main(require("fs").readFileSync("/dev/stdin", "utf-8"));