Problem:
Score : 300 points

Problem Statement

The commonly used bills in Japan are 10000-yen, 5000-yen and 1000-yen bills. Below, the word "bill" refers to only these.

According to Aohashi, he received an otoshidama (New Year money gift) envelope from his grandfather that contained N bills for a total of Y yen, but he may be lying. Determine whether such a situation is possible, and if it is, find a possible set of bills contained in the envelope. Assume that his grandfather is rich enough, and the envelope was large enough.

Constraints

1 ≤ N ≤ 2000

1000 ≤ Y ≤ 2 × 10^7

N is an integer.

Y is a multiple of 1000.

Input

Input is given from Standard Input in the following format:

N Y

Output

If the total value of N bills cannot be Y yen, print -1 -1 -1.

If the total value of N bills can be Y yen, let one such set of bills be "x 10000-yen bills, y 5000-yen bills and z 1000-yen bills", and print x, y, z with spaces in between. If there are multiple possibilities, any of them may be printed.

Sample Input 1

9 45000

Sample Output 1

4 0 5

If the envelope contained 4 10000-yen bills and 5 1000-yen bills, he had 9 bills and 45000 yen in total. It is also possible that the envelope contained 9 5000-yen bills, so the output 0 9 0 is also correct.

Sample Input 2

20 196000

Sample Output 2

-1 -1 -1

When the envelope contained 20 bills in total, the total value would be 200000 yen if all the bills were 10000-yen bills, and would be at most 195000 yen otherwise, so it would never be 196000 yen.

Sample Input 3

1000 1234000

Sample Output 3

14 27 959

There are also many other possibilities.

Sample Input 4

2000 20000000

Sample Output 4

2000 0 0

Solution in JavaScript (node.js v5.12) (judge verdict: Time Limit Exceeded)

"use strict";

function Main(input) {
  input = input.split(" ");
  input[0] = parseInt(input[0]);
  input[1] = parseInt(input[1]);

  // const counter = [0, 0, 0];

  for (let counter1 = 0; counter1 <= input[0]; counter1++) {
    for (let counter2 = 0; counter2 <= input[0]; counter2++) {
      for (let counter3 = 0; counter3 <= input[0]; counter3++) {
        if (
          counter1 + counter2 + counter3 === input[0] &&
          counter1 * 10000 + counter2 * 5000 + counter3 * 1000 === input[1]
        ) {
          console.log(counter1, counter2, counter3);
          return;
        }
      }
    }
  }
  console.log(-1, -1, -1);
}

Main(require("fs").readFileSync("/dev/stdin", "utf-8"));