Problem:
Score : 200 points

Problem Statement

A shop sells N kinds of fruits, Fruit 1, \ldots, N, at prices of p_1, \ldots, p_N yen per item, respectively. (Yen is the currency of Japan.)

Here, we will choose K kinds of fruits and buy one of each chosen kind. Find the minimum possible total price of those fruits.

Constraints

1 \leq K \leq N \leq 1000

1 \leq p_i \leq 1000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
p_1 p_2 \ldots p_N

Output

Print an integer representing the minimum possible total price of fruits.

Sample Input 1

5 3
50 100 80 120 80

Sample Output 1

210

This shop sells Fruit 1, 2, 3, 4, and 5 for 50 yen, 100 yen, 80 yen, 120 yen, and 80 yen, respectively.

The minimum total price for three kinds of fruits is 50 + 80 + 80 = 210 yen when choosing Fruit 1, 3, and 5.

Sample Input 2

1 1
1000

Sample Output 2

1000

Solution in JavaScript (Node.js 12.16.1) (judge verdict: Accepted)

function*stdinIter(){const t=require("fs").readFileSync("/dev/stdin","utf-8").trim().split(/\n|\s/);yield*t}function readMany(t,e){const i=e||this.iter||(this.iter=stdinIter()),n=[];for(let e=0;e<t;e+=1)n.push(i.next().value);return n};

(() => {
    const [ n, k ] = readMany(2).map(it => parseInt(it))
    const p = readMany(n).map(it => parseInt(it)).sort((a, b) => a - b)

    let answer = 0
    for (let i = 0; i < k; i += 1) {
        answer += p[i]
    }

    console.log(answer)
})()