Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in JavaScript (node.js v5.12) (judge verdict: Wrong Answer)

'use strict';
const p = s => console.log(s);
// let a,b,c,d;
// [a,b,c,d] = input[0].trim().split(" ").map(i => parseInt(i));

function main(input) {
  let S = input[0].trim().split("");

  let num = parseInt(S[0] + S[1]);
  let num2 = parseInt(S[2] + S[3]);

  if(num === 0 || num2 ===0) {
    p('NA');
    return;
  }

  if(num < 13 && num2 < 13) {
    p('AMBIGUOUS');
  } else if(num < 13 && num2 >= 13) {
    p('MMYY');
  } else if (num >= 13 && num2 < 13) {
    p('YYMM');
  } else {
    p('NA');
  }
}
main(require('fs').readFileSync('/dev/stdin', 'utf8').trim().split("\n"));