Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in JavaScript (node.js v5.12) (judge verdict: Accepted)

_dividers = function(n) {
  var arr = []
  for (var i = 1; i*i <= n; i++) {
     if (n % i === 0) {
       arr.push(i)
       if ( i != n / i) {
         arr.push(n / i)
       }
     }
  }
  return arr.sort((a, b) => a - b)
}

inp = require('fs').readFileSync('/dev/stdin', 'utf8').split('\n')
N = inp.shift() * 1
cnt = 0
for (i=1; i<=N; i+=2) {
    if (_dividers(i).length == 8) {
        cnt++
    }
}
console.log(cnt)