Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Wrong Answer)



import java.util.Scanner;

public class Main {
	public static void main(String [] args){
		//????????£?????????????????????
		Scanner sc =new Scanner(System.in);
		//??£?¨?
		char temp = ' '; //char????????????????????´???
		int [] table = new int[26]; //??¢?????????????????????26???????????¨?????????
		int count = 0; //????????????
		//??°?????????
		while(sc.hasNext()){
			//?????????(??±???)?????????
			String line = sc.nextLine();
			//??¨???????????????????°???????????????´
			String lower = line.toLowerCase();
			//?????????????????????
			for(int i =0; i < lower.length(); i++){
				//?°??????????char????????????
				temp = lower.charAt(i);
				//System.out.print(temp+ " ");
				//??¢??????????????????????°???????????????°????????????
				if('a' <= temp  && temp  <= 'z'){
					table[temp-'a']++;
				}
			}
			//
			for(int i = 0; i < table.length; i++){
				System.out.println( (char)('a' +i)+ " : "+ table[i]);
			}
		}
	}
}