Problem:
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Matrix Multiplication

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\[
c_{ij} = \sum_{k=1}^m a_{ik}b_{kj}
\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Constraints

$1 \leq n, m, l \leq 100$

$0 \leq a_{ij}, b_{ij} \leq 10000$

Sample Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2

Sample Output

1 8 5
0 9 6
4 23 14

Note

      解説

Solution in JAVA (judge verdict: Wrong Answer)

import java.util.Scanner;


public class Main {
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);

			int i;
			int j;
			int k;

			int n = sc.nextInt();
			int m = sc.nextInt();
			int l = sc.nextInt();

			int A[][] = new int[n][m];
			int B[][] = new int[m][l];
			int C[][] = new int[n][l];

			for(i = 0; i < n; i++) {
				for(j = 0; j < m; j++) {
					int a_ij = sc.nextInt();
					A[i][j] = a_ij;
				}
			}

			for(i = 0; i < m; i++) {
				for(j = 0; j < l; j++) {
					int b_ij = sc.nextInt();
					B[i][j] = b_ij;
				}
			}

			for(i = 0; i < n; i++) {
				for(j = 0; j < l; j++) {
					for(k = 0; k < m; k++) {
						C[i][j] = C[i][j] + A[i][k] * B[k][j];
					}
					if(j == l - 1) {
						System.out.println(C[i][j]);
					} else {
						System.out.print(C[i][j] + " ");
					}
				}
			}

	}
}