Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: WA: Presentation Error)

import java.util.Scanner;

class Main{
       public static void main(String[] args){
    	Scanner scan = new Scanner(System.in);
    	String number = scan.nextLine();
    	String change = number.toLowerCase();
    	
    	char[] ca = change.toCharArray();
    	int[] count = new int[26];
    	int num;
    	char alphabet = 'a';
    	
    	for(int i = 0; i < ca.length; i++){
    		num = ca[i] - 'a';
    		if(num >= 0 && num < 26){
    			count[num]++;
    		}
    	}
    	
    	for(int i = 0; i < 26; i++){;
    		System.out.println(alphabet + ":" + count[i]);
    		alphabet += 1;
    	}
     }
}