Problem:
Score : 100 points

Problem Statement

Ringo is giving a present to Snuke.

Ringo has found out that Snuke loves yakiniku (a Japanese term meaning grilled meat. yaki: grilled, niku: meat). He supposes that Snuke likes grilled things starting with YAKI in Japanese, and does not like other things.

You are given a string S representing the Japanese name of Ringo's present to Snuke. Determine whether S starts with YAKI.

Constraints

1 \leq |S| \leq 10

S consists of uppercase English letters.

Input

Input is given from Standard Input in the following format:

S

Output

If S starts with YAKI, print Yes; otherwise, print No.

Sample Input 1

YAKINIKU

Sample Output 1

Yes

YAKINIKU starts with YAKI.

Sample Input 2

TAKOYAKI

Sample Output 2

No

TAKOYAKI (a Japanese snack. tako: octopus) does not start with YAKI.

Sample Input 3

YAK

Sample Output 3

No

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Runtime Error)

// 作者：杨成瑞先生
import java.io.*;
import java.util.*;

public class Main {

	static class FastScanner {
        BufferedReader br;
        StringTokenizer st;

        public FastScanner() {
            try {
                br = new BufferedReader(new InputStreamReader(System.in));
                st = new StringTokenizer(br.readLine());
            } catch (Exception e){e.printStackTrace();}
        }

        public String next() {
            if (st.hasMoreTokens()) return st.nextToken();
            try {st = new StringTokenizer(br.readLine());}
            catch (Exception e) {e.printStackTrace();}
            return st.nextToken();
        }

        public int nextInt() {return Integer.parseInt(next());}

        public long nextLong() {return Long.parseLong(next());}

        public double nextDouble() {return Double.parseDouble(next());}

        public String nextLine() {
            String line = "";
            if(st.hasMoreTokens()) line = st.nextToken();
            else try {return br.readLine();}catch(IOException e){e.printStackTrace();}
            while(st.hasMoreTokens()) line += " "+st.nextToken();
            return line;
        }
    }

	public static void main(String[] args) {
        FastScanner sc = new FastScanner();
        PrintWriter pw = new PrintWriter(System.out);

        pw.println(sc.nextLine().substring(0, 5).contains("YAKI") ? "YES" : "NO");
        
        pw.close();
	}

}