Problem:
Score : 500 points

Problem Statement

For an integer n not less than 0, let us define f(n) as follows:

f(n) = 1 (if n < 2)

f(n) = n f(n-2) (if n \geq 2)

Given is an integer N. Find the number of trailing zeros in the decimal notation of f(N).

Constraints

0 \leq N \leq 10^{18}

Input

Input is given from Standard Input in the following format:

N

Output

Print the number of trailing zeros in the decimal notation of f(N).

Sample Input 1

12

Sample Output 1

1

f(12) = 12 × 10 × 8 × 6 × 4 × 2 = 46080, which has one trailing zero.

Sample Input 2

5

Sample Output 2

0

f(5) = 5 × 3 × 1 = 15, which has no trailing zeros.

Sample Input 3

1000000000000000000

Sample Output 3

124999999999999995

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Runtime Error)

import java.util.Scanner;
public class Main {
	static long fn(long n) {
		if(n < 2) {
			return 1;
		}
		return n*fn(n-2);
	}




	public static void main(String[] args) {
		Scanner stdIn = new Scanner(System.in);
		long  n = stdIn.nextLong();
		if(n%2 != 0) {
			System.out.println(0);
			System.exit(0);
		}

		long a = fn(n);

		long cnt = 0;

		while(a%10 == 0) {
			cnt++;
			a /=10;
		}
		System.out.println(cnt);


	}

}