Problem:
Score : 200 points

Problem Statement

There are N gems. The value of the i-th gem is V_i.

You will choose some of these gems, possibly all or none, and get them.

However, you need to pay a cost of C_i to get the i-th gem.

Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid.

Find the maximum possible value of X-Y.

Constraints

All values in input are integers.

1 \leq N \leq 20

1 \leq C_i, V_i \leq 50

Input

Input is given from Standard Input in the following format:

N
V_1 V_2 ... V_N
C_1 C_2 ... C_N

Output

Print the maximum possible value of X-Y.

Sample Input 1

3
10 2 5
6 3 4

Sample Output 1

5

If we choose the first and third gems, X = 10 + 5 = 15 and Y = 6 + 4 = 10.
We have X-Y = 5 here, which is the maximum possible value.

Sample Input 2

4
13 21 6 19
11 30 6 15

Sample Output 2

6

Sample Input 3

1
1
50

Sample Output 3

0

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.Scanner;

public class Main {
		public static void main(String[] args) {
			String strV, strC;
			int N, result = 0;
			int[] V = new int[20];
			int[] C = new int[20];

			Scanner scN = new Scanner(System.in);
			N = Integer.parseInt(scN.nextLine());
			strV = scN.nextLine();
			strC = scN.nextLine();

			System.out.println(strC);

			for (int i = 0; i < N; i++) {
				V[i] = Integer.parseInt(strV.split(" ")[i]);
				C[i] = Integer.parseInt(strC.split(" ")[i]);
			}

			for (int i = 0; i < N; i++) {
				if (V[i] - C[i] > 0) {
					result += V[i] - C[i];
				}
			}

			System.out.print(result);

			scN.close();
		}
}