Problem:
Score : 200 points

Problem Statement

There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is R, and a blue hat if s_i is B.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

1 \leq N \leq 100

|s| = N

s_i is R or B.

Input

Input is given from Standard Input in the following format:

N
s

Output

If there are more people wearing a red hat than there are people wearing a blue hat, print Yes; otherwise, print No.

Sample Input 1

4
RRBR

Sample Output 1

Yes

There are three people wearing a red hat, and one person wearing a blue hat.

Since there are more people wearing a red hat than people wearing a blue hat, the answer is Yes.

Sample Input 2

4
BRBR

Sample Output 2

No

There are two people wearing a red hat, and two people wearing a blue hat.

Since there are as many people wearing a red hat as people wearing a blue hat, the answer is No.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.*;

public class Main {
  public static void main(String[] args ) throws Exception {
    Scanner sc = new Scanner(System.in);
    int Num = sc.nextInt();
    String BR=sc.next();
    int TotalBlue=0;
    int TotalRed=0;
    char B[]=new char[BR.length()];
    for(int i=0;i<BR.length();i++){
     B[i]=BR.charAt(i);
    }
    for(int i=0;i<BR.length();i++){
     if(B[i]=='R'){
      TotalRed++;
     }else{
      TotalBlue++;
     }
    }
    
    if(TotalRed>TotalBlue){
    System.out.println("Yes");
    }else{
    System.out.println("No");
    }
  }
}