Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Scanner;

public class Main{
    public static void main(String[] args){
	Scanner sc = new Scanner(System.in);
	int N = sc.nextInt();
	int count = 0;
	if(N < 105){
	    count = 0;
	}else if(N ==105){
	    count = 1;
	}else if(N > 105){
	    count = 1;
	    for(int j=107;j<=N;j+=2){
		int cc = 0;
		for(int i=1;i<=j;i+=2){
		    if(j%i==0) cc++;
		}
		if(cc==8) count++;
	    }
	}
	System.out.print(count);
    }
}