Problem:
Score : 300 points

Problem Statement

Let f(n) be the number of triples of integers (x,y,z) that satisfy both of the following conditions:

1 \leq x,y,z

x^2 + y^2 + z^2 + xy + yz + zx = n

Given an integer N, find each of f(1),f(2),f(3),\ldots,f(N).

Constraints

All values in input are integers.

1 \leq N \leq 10^4

Input

Input is given from Standard Input in the following format:

N

Output

Print N lines. The i-th line should contain the value f(i).

Sample Input 1

20

Sample Output 1

0
0
0
0
0
1
0
0
0
0
3
0
0
0
0
0
3
3
0
0

For n=6, only (1,1,1) satisfies both of the conditions. Thus, f(6) = 1.

For n=11, three triples, (1,1,2), (1,2,1), and (2,1,1), satisfy both of the conditions. Thus, f(6) = 3.

For n=17, three triples, (1,2,2), (2,1,2), and (2,2,1), satisfy both of the conditions. Thus, f(17) = 3.

For n=18, three triples, (1,1,3), (1,3,1), and (3,1,1), satisfy both of the conditions. Thus, f(18) = 3.

Solution in Java (OpenJDK 11.0.6) (judge verdict: Wrong Answer)

import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;

public class Main {
	public static void main(String[] args) {
		// TODO 自動生成されたメソッド・スタブ
		Scanner sc = new Scanner(System.in);
		int n = sc.nextInt();
		outer : for (int i = 1; i <= n; i++) {
			for (int x = 1; ; x++) {
				if (i < (x*x + 3 + 2*x)) {
					break;
				}
				for (int y = 1; ; y++) {
					if (i < (x*x + y*y + 1 +x*y + y + x)) {
						break;
					}
					for (int z = 1; ; z++) {
						int m = x*x + y*y + z*z +x*y + y*z + z*x;
						if (m < i) {
							continue;
						} else if (m == i) {
							if (x == y && y == z) {
								System.out.println(1);
								continue outer;
							} else {
								System.out.println(3);
								continue outer;
							}
						} else {
							// オーバー
							break;
						}
					}
				}
			}
			System.out.println(0);
		}
	}
}