Problem:
Score : 100 points

Problem Statement

A biscuit making machine produces B biscuits at the following moments: A seconds, 2A seconds, 3A seconds and each subsequent multiple of A seconds after activation.

Find the total number of biscuits produced within T + 0.5 seconds after activation.

Constraints

All values in input are integers.

1 \leq A, B, T \leq 20

Input

Input is given from Standard Input in the following format:

A B T

Output

Print the total number of biscuits produced within T + 0.5 seconds after activation.

Sample Input 1

3 5 7

Sample Output 1

10

Five biscuits will be produced three seconds after activation.

Another five biscuits will be produced six seconds after activation.

Thus, a total of ten biscuits will be produced within 7.5 seconds after activation.

Sample Input 2

3 2 9

Sample Output 2

6

Sample Input 3

20 20 19

Sample Output 3

0

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Scanner;

class Main{

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);			//文字の入力

		int a = sc.nextInt();
		int b = sc.nextInt();
		int c = sc.nextInt();
		
		int ans = 0;
		for(int i = a;i <= c;i+=a){
			ans += b;
		}
		System.out.print(ans);
	}




static String deletestr(String base,String remove){
	boolean flag = true;
	for(int i = 0;i < remove.length();i++){
		if(i == base.length()){
			flag = false;
			break;
		}
		if(base.charAt(i) - remove.charAt(i) != 0 && base.charAt(i) - remove.charAt(i) != 32 &&remove.charAt(i) - base.charAt(i)  != 32){
			flag = false;
			break;
		}
	}

	if(flag){
		base = base.substring(remove.length());
	}

	return base;

}



}


class Pair implements Comparable{
	int from;
	int end;
	@Override
	public int compareTo(Object other) {
		Pair otherpair = (Pair)other;

		return from - otherpair.from;
	}
}