Problem:
Score : 200 points

Problem Statement

There are N positive integers written on a blackboard: A_1, ..., A_N.

Snuke can perform the following operation when all integers on the blackboard are even:

Replace each integer X on the blackboard by X divided by 2.

Find the maximum possible number of operations that Snuke can perform.

Constraints

1 \leq N \leq 200

1 \leq A_i \leq 10^9

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

Print the maximum possible number of operations that Snuke can perform.

Sample Input 1

3
8 12 40

Sample Output 1

2

Initially, [8, 12, 40] are written on the blackboard.
Since all those integers are even, Snuke can perform the operation.

After the operation is performed once, [4, 6, 20] are written on the blackboard.
Since all those integers are again even, he can perform the operation.

After the operation is performed twice, [2, 3, 10] are written on the blackboard.
Now, there is an odd number 3 on the blackboard, so he cannot perform the operation any more.

Thus, Snuke can perform the operation at most twice.

Sample Input 2

4
5 6 8 10

Sample Output 2

0

Since there is an odd number 5 on the blackboard already in the beginning, Snuke cannot perform the operation at all.

Sample Input 3

6
382253568 723152896 37802240 379425024 404894720 471526144

Sample Output 3

8

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Arrays;
import java.util.Scanner;

/**
 * 【問題概要】 黒板に NN 個の正の整数 A1,…,ANA1,…,AN が書かれています。
 * すぬけ君は，黒板に書かれている整数がすべて偶数であるとき，次の操作を行うことができます。
 *
 * 黒板に書かれている整数すべてを，2 で割ったものに置き換える。 すぬけ君は最大で何回操作を行うことができるかを求めてください。
 *
 * @author tsuch
 *
 */
public class Main {

	private static Scanner sc = new Scanner(System.in);

	public static void main(String[] args) {
		Main instance = new Main();
		instance.solve();
	}

	private void solve() {
		try {
			int n = sc.nextInt();
			int[] a = new int[n];
			for (int i = 0; i < n; i++) {
				int j = 0;
				int temp = sc.nextInt();
				while (true) {
					if (temp / 2 == (temp + 1) / 2) {
						temp = temp / 2;
						j = j + 1;
					} else {
						a[i] = j;
						break;
					}
				}
			}
			int b = Arrays.stream(a).min().getAsInt();
			System.out.println(b);

		} catch (Exception e) {
			e.printStackTrace();
		}
	}
}