Problem:
Score : 200 points

Problem Statement

Let us define the FizzBuzz sequence a_1,a_2,... as follows:

If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.

If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.

If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.

If none of the above holds, a_i=i.

Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Constraints

1 \leq N \leq 10^6

Input

Input is given from Standard Input in the following format:

N

Output

Print the sum of all numbers among the first N terms of the FizzBuzz sequence.

Sample Input 1

15

Sample Output 1

60

The first 15 terms of the FizzBuzz sequence are:

1,2,\mbox{Fizz},4,\mbox{Buzz},\mbox{Fizz},7,8,\mbox{Fizz},\mbox{Buzz},11,\mbox{Fizz},13,14,\mbox{FizzBuzz}

Among them, numbers are 1,2,4,7,8,11,13,14, and the sum of them is 60.

Sample Input 2

1000000

Sample Output 2

266666333332

Watch out for overflow.

Solution in Java (OpenJDK 11.0.6) (judge verdict: Runtime Error)

import java.util.Scanner;
//int[] date=new int[2];
public class Main {
int i,o,sum,h,s,e,u,ty,yu,ui,n,num,qw;
double m,t,r,j,k,f,d,g,w;
static double l;
String b,c,z,x,v,a,q;
Scanner scan =new Scanner(System.in);
//入力
	public void input() {	
	
	}
	//演算
	public void compute() {
	
		}
//出力
public void output() {
h=scan.nextInt();
int[] date=new int[h+1];
for(o=h;o>0;o--) {
	date[o]=o;
    if(date[h+1]%3!=0&&date[h+1]%5!=0){
    date[h+1]=0;
  }
 // System.out.println(date[o]);
	if(date[o]%3==0) {
date[o]=0;
	}else if(date[o]%5==0) {
date[o]=0;
	}

	e+=date[o];
}
System.out.println(e);
}
	public static void main(String [ ] args) {
		 Main p = new  Main ();
		p.input();
		p.compute();
		p.output();
		}
	}