Problem:
Coin Changing Problem

Find the minimum number of coins to make change for n cents using coins of denominations d1, d2,.., dm. The coins can be used any number of times.

Input

n m
d1 d2 ... dm

Two integers n and m are given in the first line. The available denominations are given in the second line.

Output

Print the minimum number of coins in a line.

Constraints

1 ≤ n ≤ 50000

1 ≤ m ≤ 20

1 ≤ denomination ≤ 10000

The denominations are all different and contain 1.

Sample Input 1

55 4
1 5 10 50

Sample Output 1

2

Sample Input 2

15 6
1 2 7 8 12 50

Sample Output 2

2

Sample Input 3

65 6
1 2 7 8 12 50

Sample Output 3

3

Solution in JAVA (judge verdict: Wrong Answer)

import java.io.*;
import java.lang.*;
import java.util.Scanner;

public class Main {
	public static int typeList[];
	public static int types;
	public static int minCount;
	public static void main(String[] args){
		Scanner sc = new Scanner(System.in);
		int change, i;
		change = sc.nextInt();
		types = sc.nextInt();
		
		typeList = new int[types];
		for(i = 0; i < types; i++){
			typeList[i] = sc.nextInt();
		}
		minCount = change / typeList[types - 1] + change % typeList[types - 1];
		
		Main.check(change, 0, types - 1);
		System.out.println(minCount);
	}
	public static void check(int remChanges, int count, int typeIndex){
		if(typeIndex == 0){
			// type must be 1
			if(remChanges + count < minCount){
				minCount = remChanges + count;
				System.out.println(minCount);
			}
			return;
		}
		int tmp, uses;	
		//System.out.println(">" + typeList[typeIndex]);
		for(uses = remChanges / typeList[typeIndex]; uses >= 0; uses--){
			tmp = uses * typeList[typeIndex];
			if(tmp == remChanges){
				if(count + uses < minCount){
					minCount = count + uses;
					//System.out.println(minCount);
				}
				return;
			}
			Main.check(remChanges - tmp, count + uses, typeIndex - 1);
		}
		return;
	}
}