Problem:
Score : 200 points

Problem Statement

You are given a string S. Each character of S is uppercase or lowercase English letter.
Determine if S satisfies all of the following conditions:

The initial character of S is an uppercase A.

There is exactly one occurrence of C between the third character from the beginning and the second to last character (inclusive).

All letters except the A and C mentioned above are lowercase.

Constraints

4 ≤ |S| ≤ 10 (|S| is the length of the string S.)

Each character of S is uppercase or lowercase English letter.

Input

Input is given from Standard Input in the following format:

S

Output

If S satisfies all of the conditions in the problem statement, print AC; otherwise, print WA.

Sample Input 1

AtCoder

Sample Output 1

AC

The first letter is A, the third letter is C and the remaining letters are all lowercase, so all the conditions are satisfied.

Sample Input 2

ACoder

Sample Output 2

WA

The second letter should not be C.

Sample Input 3

AcycliC

Sample Output 3

WA

The last letter should not be C, either.

Sample Input 4

AtCoCo

Sample Output 4

WA

There should not be two or more occurrences of C.

Sample Input 5

Atcoder

Sample Output 5

WA

The number of C should not be zero, either.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)


import java.util.Scanner;

class Main{
	public static void main(String[] main) {
		Scanner sc=new Scanner(System.in);
		String a=sc.next();


		boolean isC=false;
		boolean caps=true;
		boolean isA=false;

		if(a.length()>4) {
			for(int i=0; i<a.length(); i++) {
				if(i==0) {
					if(a.charAt(i)=='A') {
						isA=true;
					}
					else {
						isA=false;
					}
				}
				
				if(a.charAt(i)=='C' && isC==false && i<a.length()-2) {
					isC=true;
				}
				
				else {
					if(((a.charAt(i)+"").toLowerCase().equals(a.charAt(i)+""))) {
						//
					}
					else {
						caps=false;
					}
				}
			}

			if(caps==true && isC==true && isA==true) {
				System.out.println("AC");
			}
			else {
				System.out.println("WA");
			}
		}
		else if(a.length()==4) {

			for(int i=0; i<a.length(); i++) {
				if(i==0) {
					if(a.charAt(i)=='A') {
						isA=true;
					}
					else {
						isA=false;
					}
				}
				else if(i==2) {
					if(a.charAt(i)=='C') {
						isC=true;
					}
				}

				else {
					if(((a.charAt(i)+"").toLowerCase().equals(a.charAt(i)+""))) {
						//
					}
					else {
						caps=false;
					}
				}
			}

			if(caps==true && isC==true && isA==true) {
				System.out.println("AC");
			}
			else {
				System.out.println("WA");
			}

		}
	}
}