Problem:
Score : 200 points

Problem Statement

You are given string S and T consisting of lowercase English letters.

Determine if S equals T after rotation.

That is, determine if S equals T after the following operation is performed some number of times:

Operation: Let S = S_1 S_2 ... S_{|S|}. Change S to S_{|S|} S_1 S_2 ... S_{|S|-1}.

Here, |X| denotes the length of the string X.

Constraints

2 \leq |S| \leq 100

|S| = |T|

S and T consist of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S equals T after rotation, print Yes; if it does not, print No.

Sample Input 1

kyoto
tokyo

Sample Output 1

Yes

In the first operation, kyoto becomes okyot.

In the second operation, okyot becomes tokyo.

Sample Input 2

abc
arc

Sample Output 2

No

abc does not equal arc after any number of operations.

Sample Input 3

aaaaaaaaaaaaaaab
aaaaaaaaaaaaaaab

Sample Output 3

Yes

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;


public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        String T = sc.next();
        String R = sc.next();

        int flgsub = 0;
        int flag = 0;
        int Rlength = R.length();

        for (int i = 0; i < T.length(); i++) {
            for (int j = 0; j < R.length(); j++) {
                if(flgsub == 1){
                    continue;
                }
                if(T.charAt(i) == R.charAt(j)) {
                    flgsub = 1;
                    R = R.substring(0,j) + R.substring(j+1,R.length());
                }
            }
            if(flgsub == 0){
                flag =1;
            }
            flgsub=0;
        }

        if(flag == 1){
            System.out.println("No");
        }else{
            System.out.println("Yes");
        }

    }
}