Problem:
Score : 500 points

Problem Statement

Given are N integers A_1,\ldots,A_N.

We will choose exactly K of these elements. Find the maximum possible product of the chosen elements.

Then, print the maximum product modulo (10^9+7), using an integer between 0 and 10^9+6 (inclusive).

Constraints

1 \leq K \leq N \leq 2\times 10^5

|A_i| \leq 10^9

Input

Input is given from Standard Input in the following format:

N K
A_1 \ldots A_N

Output

Print the maximum product modulo (10^9+7), using an integer between 0 and 10^9+6 (inclusive).

Sample Input 1

4 2
1 2 -3 -4

Sample Output 1

12

The possible products of the two chosen elements are 2, -3, -4, -6, -8, and 12, so the maximum product is 12.

Sample Input 2

4 3
-1 -2 -3 -4

Sample Output 2

1000000001

The possible products of the three chosen elements are -24, -12, -8, and -6, so the maximum product is -6.

We print this value modulo (10^9+7), that is, 1000000001.

Sample Input 3

2 1
-1 1000000000

Sample Output 3

1000000000

The possible products of the one chosen element are -1 and 1000000000, so the maximum product is 1000000000.

Sample Input 4

10 10
1000000000 100000000 10000000 1000000 100000 10000 1000 100 10 1

Sample Output 4

999983200

Be sure to print the product modulo (10^9+7).

Solution in Java (OpenJDK 11.0.6) (judge verdict: Wrong Answer)


import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.List;
import java.util.StringTokenizer;
import java.util.stream.Collectors;
import java.util.stream.IntStream;

public class Main {
    private static final long MOD = 1_000_000_007;

    public static void main(final String[] args) {
        final FastScanner scanner = new FastScanner(System.in);
        final int n = scanner.nextInt();
        int k = scanner.nextInt();

        final List<Long> list = IntStream.range(0, n)
            .mapToObj(i -> (long) scanner.nextInt())
            .sorted()
            .collect(Collectors.toList());

        if (k % 2 == 1 && list.get(n - k) <= 0) {
            final long answer = (MOD - list.stream()
                .map(Math::abs)
                .sorted()
                .limit(k)
                .reduce((a, b) -> a * b % MOD)
                .orElseThrow()) % MOD;
            System.out.println(answer);
            return;
        }

        long production = 1;
        int left = 0;
        int right = n - 1;
        for (int i = 0; i < k; i++) {
            if (i == k - 1) {
                production *= list.get(right--);
                production %= MOD;
                continue;
            }

            final long multi;
            if (list.get(left) * list.get(left + 1) >= list.get(right) * list.get(right - 1)) {
                multi = list.get(left) * list.get(left + 1) % MOD;
                left += 2;
                i++;
            } else {
                multi = list.get(right--);
            }
            production *= multi;
            production %= MOD;
        }
        System.out.println(production);
    }

    private static class FastScanner {
        private final BufferedReader reader;
        private StringTokenizer tokenizer;

        FastScanner(final InputStream in) {
            reader = new BufferedReader(new InputStreamReader(in));
        }

        String next() {
            if (tokenizer == null || !tokenizer.hasMoreTokens()) {
                try {
                    tokenizer = new StringTokenizer(reader.readLine());
                } catch (final IOException e) {
                    throw new RuntimeException(e);
                }
            }
            return tokenizer.nextToken();
        }

        int nextInt() {
            return Integer.parseInt(next());
        }
    }
}