Problem:
Score : 200 points

Problem Statement

The postal code in Atcoder Kingdom is A+B+1 characters long, its (A+1)-th character is a hyphen -, and the other characters are digits from 0 through 9.

You are given a string S. Determine whether it follows the postal code format in Atcoder Kingdom.

Constraints

1≤A,B≤5

|S|=A+B+1

S consists of - and digits from 0 through 9.

Input

Input is given from Standard Input in the following format:

A B
S

Output

Print Yes if S follows the postal code format in AtCoder Kingdom; print No otherwise.

Sample Input 1

3 4
269-6650

Sample Output 1

Yes

The (A+1)-th character of S is -, and the other characters are digits from 0 through 9, so it follows the format.

Sample Input 2

1 1
---

Sample Output 2

No

S contains unnecessary -s other than the (A+1)-th character, so it does not follow the format.

Sample Input 3

1 2
7444

Sample Output 3

No

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Runtime Error)

import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		int A = sc.nextInt();
		int B = sc.nextInt();
		String S = sc.next();
		boolean b = true;

		String[] SA = S.split("-");
		//
		System.out.println(A + " " + B + " " + SA[0].length() + " " + SA[1].length() + " " + SA.length);
		
		if(!(SA.length == 2)) b = false;
		if ((S.charAt(A) == '-') && (A == SA[0].length()) && (B == SA[1].length())) {
			for (int i = 0; i < A; i++) {
				if ((S.charAt(i) < 0) && (S.charAt(i) > 10)) {
                    b = false;
				}
				//
				System.out.println(S.charAt(i));
			}
			for (int j = A + 1; j < A + B + 1; j++) {
				if ((S.charAt(j) < 0) && (S.charAt(j) > 10)) {
					b = false;
				}
				//
				System.out.println(S.charAt(j));
			}
		} else {
			b = false;
		}



		if(b == true) {
			System.out.println("Yes");
		} else if(b == false){
			System.out.println("No");
		}

	}

}