Problem:
Score : 300 points

Problem Statement

You are given a string s.
Among the different substrings of s, print the K-th lexicographically smallest one.

A substring of s is a string obtained by taking out a non-empty contiguous part in s.
For example, if s = ababc, a, bab and ababc are substrings of s, while ac, z and an empty string are not.
Also, we say that substrings are different when they are different as strings.

Let X = x_{1}x_{2}...x_{n} and Y = y_{1}y_{2}...y_{m} be two distinct strings. X is lexicographically larger than Y if and only if Y is a prefix of X or x_{j} > y_{j} where j is the smallest integer such that x_{j} \neq y_{j}.

Constraints

1 ≤ |s| ≤ 5000

s consists of lowercase English letters.

1 ≤ K ≤ 5

s has at least K different substrings.

Partial Score

200 points will be awarded as a partial score for passing the test set satisfying |s| ≤ 50.

Input

Input is given from Standard Input in the following format:

s
K

Output

Print the K-th lexicographically smallest substring of K.

Sample Input 1

aba
4

Sample Output 1

b

s has five substrings: a, b, ab, ba and aba.
Among them, we should print the fourth smallest one, b.
Note that we do not count a twice.

Sample Input 2

atcoderandatcodeer
5

Sample Output 2

andat

Sample Input 3

z
1

Sample Output 3

z

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.ArrayList;
import java.util.Scanner;

public class Main {

  public static void main(String[] args) {

    Scanner sc = new Scanner(System.in);

    String s = sc.next();
    int K = Integer.parseInt(sc.next());

    ArrayList<String> subs = new ArrayList<>();
    for (int i = 0; i < s.length(); i++) {
      for (int j = 0; j < 5; j++) {
        if (i + j >= s.length()) {
          break;
        }
        subs.add(s.substring(i, i + j + 1));
      }
    }
    subs.sort(null);
    String ans = subs.get(0);
    int count = 1;
    if (count == K) {
      System.out.println(ans);
      return;
    }
    for (int i = 1; i < subs.size(); i++) {
      if (ans.equals(subs.get(i))) {
        continue;
      } else {
        ans = subs.get(i);
        count++;
      }
      if (count == K) {
        System.out.println(ans);
        break;
      }
    }
  }
}