Problem:
Score : 100 points

Problem Statement

Given is an integer N.

Takahashi chooses an integer a from the positive integers not greater than N with equal probability.

Find the probability that a is odd.

Constraints

1 \leq N \leq 100

Input

Input is given from Standard Input in the following format:

N

Output

Print the probability that a is odd.
Your output will be considered correct when its absolute or relative error from the judge's output is at most 10^{-6}.

Sample Input 1

4

Sample Output 1

0.5000000000

There are four positive integers not greater than 4: 1, 2, 3, and 4. Among them, we have two odd numbers: 1 and 3. Thus, the answer is \frac{2}{4} = 0.5.

Sample Input 2

5

Sample Output 2

0.6000000000

Sample Input 3

1

Sample Output 3

1.0000000000

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Runtime Error)

import java.math.BigDecimal;
import java.util.Scanner;

public class Main { 
    public static void main(String[] args) {
    	Scanner sc = new Scanner(System.in);
    	int count = Integer.parseInt(sc.nextLine());
    	int oddCount = 0;
    	for(int i = 1;i<=count;i++) {
    		if(i%2 == 1) {
    			oddCount++;
    		}
    	}
    	
    	BigDecimal totalCount = new BigDecimal(count);
    	BigDecimal bigOddCount = new BigDecimal(oddCount);
    	BigDecimal answer = bigOddCount.divide(totalCount);
    	System.out.println(answer.setScale(10));
    	
    	
    }
}