Problem:
Score : 300 points

Problem Statement

You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

1 \leq |S| \leq 2 \times 10^5

|S| = |T|

S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S and T can be made equal, print Yes; otherwise, print No.

Sample Input 1

azzel
apple

Sample Output 1

Yes

azzel can be changed to apple, as follows:

Choose e as c_1 and l as c_2. azzel becomes azzle.

Choose z as c_1 and p as c_2. azzle becomes apple.

Sample Input 2

chokudai
redcoder

Sample Output 2

No

No sequences of operation can change chokudai to redcoder.

Sample Input 3

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu

Sample Output 3

Yes

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Arrays;
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        String S = sc.nextLine();
        String T = sc.nextLine();

        int[] R1 = new int[26];
        int[] R2 = new int[26];

        Arrays.fill(R1, -1);
        Arrays.fill(R2, -1);

        int c1 = -1;
        int c2 = -1;
        for (int i = 0; i < S.length(); i++) {
            c1 = S.charAt(i) - 'a';
            c2 = T.charAt(i) - 'a';

            if (R1[c1] != -1 || R2[c2] != -1) {
                if (R1[c1] != c2 || R2[c2] != c1) {
                    System.out.println("No");
                    return;
                }
            } else {
                R1[c1] = c2;
                R2[c2] = c1;
            }
        }
        System.out.println("Yes");
    }
}