Problem:
Score : 400 points

Problem Statement

Takahashi has a string S consisting of lowercase English letters.

Starting with this string, he will produce a new one in the procedure given as follows.

The procedure consists of Q operations. In Operation i (1 \leq i \leq Q), an integer T_i is provided, which means the following:

If T_i = 1: reverse the string S.

If T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.

If F_i = 1 : Add C_i to the beginning of the string S.

If F_i = 2 : Add C_i to the end of the string S.

Help Takahashi by finding the final string that results from the procedure.

Constraints

1 \leq |S| \leq 10^5

S consists of lowercase English letters.

1 \leq Q \leq 2 \times 10^5

T_i = 1 or 2.

F_i = 1 or 2, if provided.

C_i is a lowercase English letter, if provided.

Input

Input is given from Standard Input in the following format:

S
Q
Query_1
:
Query_Q

In the 3-rd through the (Q+2)-th lines, Query_i is one of the following:

1

which means T_i = 1, and:

2 F_i C_i

which means T_i = 2.

Output

Print the resulting string.

Sample Input 1

a
4
2 1 p
1
2 2 c
1

Sample Output 1

cpa

There will be Q = 4 operations. Initially, S is a.

Operation 1: Add p at the beginning of S. S becomes pa.

Operation 2: Reverse S. S becomes ap.

Operation 3: Add c at the end of S. S becomes apc.

Operation 4: Reverse S. S becomes cpa.

Thus, the resulting string is cpa.

Sample Input 2

a
6
2 2 a
2 1 b
1
2 2 c
1
1

Sample Output 2

aabc

There will be Q = 6 operations. Initially, S is a.

Operation 1: S becomes aa.

Operation 2: S becomes baa.

Operation 3: S becomes aab.

Operation 4: S becomes aabc.

Operation 5: S becomes cbaa.

Operation 6: S becomes aabc.

Thus, the resulting string is aabc.

Sample Input 3

y
1
2 1 x

Sample Output 3

xy

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Runtime Error)

import java.util.*;
import java.io.*;
public class Main{
/// functions
static long gcd(long a,long b){if(b==0){return a;}return gcd(b,a%b);}
static long Modpow(long a,long p,long m){long res=1;while(p>0){if((p&1)!=0){res=(res*a)%m;}p >>=1;a=(a*a)%m;}return res;}
static long Modmul(long a,long b,long m){return ((a%m)*(b%m))%m;}
static long ModInv(long a,long m){return Modpow(a,m-2,m);}
static long nck(int n,int r,long m){if(r>n){return 0l;}return Modmul(f[n],ModInv(Modmul(f[n-r],f[r],m),m),m);}
// end
static long[] f;
// taking inputs
static BufferedReader s;
static BufferedWriter out;
static String read() throws IOException{String line="";while(line.length()==0){line=s.readLine();continue;}return line;}
static int int_v (String s1){return Integer.parseInt(s1);}
static long long_v(String s1){return Long.parseLong(s1);}
static int[] int_arr() throws IOException{String[] a=read().split(" ");int[] b=new int[a.length];for(int i=0;i<a.length;i++){b[i]=int_v(a[i]);}return b;}
static long[] long_arr() throws IOException{String[] a=read().split(" ");long[] b=new long[a.length];for(int i=0;i<a.length;i++){b[i]=long_v(a[i]);}return b;}
static void assign(){s=new BufferedReader(new InputStreamReader(System.in));out=new BufferedWriter(new OutputStreamWriter(System.out));}
// ends
//......................................@uthor_Alx..............................................

public static void main(String[] args) throws  IOException{
       assign();
       String s1=read();
       char[] arr=new char[300000];
       int j1=100000,i1=100000-1;
       for(int i=0;i<s1.length();i++){
       	arr[j1]=s1.charAt(i);
       	j1++;
       }

        int q=int_v(read()); int flag=0;
        while(q--!=0){
        	String[] z=read().split(" ");
        	if(int_v(z[0])==1){
        		flag=(1^flag);
        		//sb=sb.reverse();
        	}
        	else{
        		if(flag==0){
        			if(int_v(z[1])==1){arr[i1]=z[2].charAt(0);i1--;}//sb.insert(0,z[2]);
        		else{arr[j1]=z[2].charAt(0);j1++;}//sb.append(z[2]);
        		}
        		else{
        			if(int_v(z[1])==1){arr[j1]=z[2].charAt(0);j1++;}
        		else{arr[i1]=z[2].charAt(0);i1--;}
        		}
        		
        	}
        }
    if(flag==0){
    	for(int i=i1+1;i<j1;i++){
    		out.write(arr[i]+"");
    	}
    	out.write("\n");
    }
     if(flag==1){
     	for(int i=j1-1;i>i1;i--){
    		out.write(arr[i]+"");
    	}
    	out.write("\n");
     }
             
        out.flush();
  }
}