Problem:
Simultaneous Equation

Write a program which solve a simultaneous equation:

ax + by = c

dx + ey = f

The program should print x and y for given a, b, c, d, e and f (-1,000 ≤ a, b, c, d, e, f ≤ 1,000). You can suppose that given equation has a unique solution.

Input

The input consists of several data sets, 1 line for each data set. In a data set, there will be a, b, c, d, e, f separated by a single space. The input terminates with EOF.

Output

For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.

Sample Input 1

1 2 3 4 5 6
2 -1 -2 -1 -1 -5

Output for the Sample Input 1

-1.000 2.000
1.000 4.000

Sample Input 2

2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27

Output for the Sample Input 2

0.000 3.000
0.000 3.000

Solution in JAVA (judge verdict: Wrong Answer)

import java.io.*;
import java.util.*;
public class Main{
 public static void main(String args[]){
  BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
  try{
   String str=br.readLine();
   StringTokenizer st=new StringTokenizer(str);
   Double a=Double.parseDouble(st.nextToken());
   Double b=Double.parseDouble(st.nextToken());
   Double c=Double.parseDouble(st.nextToken());
   Double d=Double.parseDouble(st.nextToken());
   Double e=Double.parseDouble(st.nextToken());
   Double f=Double.parseDouble(st.nextToken());
   Double x;
   Double y;
   x=((c*e)-(b*f))/((a*e)-(b*d));
   y=((c*d)-(a*f))/((b*d)-(a*e));
   if(x==0){
    x=Math.abs(x);
   }
   if(y==0){
    y=Math.abs(y);
   }
   System.out.printf("%.3f %.3f",x,y);
  }catch(Exception e){
  }
 }
}