Problem:
Score : 200 points

Problem Statement

In the beginning, Takahashi has A cookies, and Aoki has B cookies.
They will perform the following operation alternately, starting from Takahashi:

If the number of cookies in his hand is odd, eat one of those cookies; if the number is even, do nothing. Then, give one-half of the cookies in his hand to the other person.

Find the numbers of cookies Takahashi and Aoki respectively have after performing K operations in total.

Constraints

1 \leq A,B \leq 10^9

1 \leq K \leq 100

A,B and K are integers.

Input

Input is given from Standard Input in the following format:

A B K

Output

Print the number of cookies Takahashi has, and the number of cookies Aoki has, in this order, after performing K operations in total.

Sample Input 1

5 4 2

Sample Output 1

5 3

The process will go as follows:

In the beginning, Takahashi and Aoki have 5 and 4 cookies, respectively.

Takahashi eats one cookie and gives two cookies to Aoki. They now have 2 and 6 cookies, respectively.

Aoki gives three cookies to Takahashi. They now have 5 and 3 cookies, respectively.

Sample Input 2

3 3 3

Sample Output 2

1 3

Sample Input 3

314159265 358979323 84

Sample Output 3

448759046 224379523

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Scanner;

public class Main{
	
	public static void main(String[] args){
		
	Scanner sc =new Scanner(System.in);
	
	int a= sc.nextInt();
	int b= sc.nextInt();	
	int k= sc.nextInt();
	int c=0,d=0;
	
	for(int i=0;i<k;i++){
		
		if(i%2==0){
			if(a%2==1) a=a-1;
			//System.out.println(a);
			c=a;
			a=a-c/2;
			
			//System.out.println(a);
			b=b+c/2;
		}
		
		else if(i%2==1){
			if(b%2==1) b=b-1;
			
			d=b;
			a=a+d/2;
			b=b-d/2;
		}
	
			
	}
	
	System.out.print(a+" "+b);
	
	}

}