Problem:
Score : 200 points

Problem Statement

A string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:

S is a palindrome.

Let N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.

The string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.

Determine whether S is a strong palindrome.

Constraints

S consists of lowercase English letters.

The length of S is an odd number between 3 and 99 (inclusive).

Input

Input is given from Standard Input in the following format:

S

Output

If S is a strong palindrome, print Yes;
otherwise, print No.

Sample Input 1

akasaka

Sample Output 1

Yes

S is akasaka.

The string formed by the 1-st through the 3-rd characters is aka.

The string formed by the 5-th through the 7-th characters is aka.
All of these are palindromes, so S is a strong palindrome.

Sample Input 2

level

Sample Output 2

No

Sample Input 3

atcoder

Sample Output 3

No

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.*;

public class Main {
  public static void main(String[] args) {
    Scanner sc = new Scanner(System.in);
    String s = sc.next();
    String ans = "Yes";
    for(int i = 0; i < s.length(); i++) {
      if(s.charAt(i) != s.charAt(s.length() - 1 - i)) {
        ans = "No";
        break;
      }
    }
    for(int i = 0; i < (s.length() - 1) / 2; i++) {
      if(s.charAt(i) != s.charAt((s.length() - 1) / 2 - 1 - i)) {
        ans = "No";
        break;
      }
    }
    for(int i = (s.length() + 1) / 2; i < s.length(); i++) {
      if(s.charAt(i) != s.charAt(s.length() - 1 - (i - (s.length() + 1) / 2))) {
        ans = "No";
        break;
      }
    }
    System.out.println(ans);
  }
}