Problem:
Score : 400 points

Problem Statement

Given is an integer S.
Find a combination of six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfies all of the following conditions:

0 \leq X_1,Y_1,X_2,Y_2,X_3,Y_3 \leq 10^9

The area of the triangle in a two-dimensional plane whose vertices are (X_1,Y_1),(X_2,Y_2), and (X_3,Y_3) is S/2.

We can prove that there always exist six integers that satisfy the conditions under the constraints of this problem.

Constraints

1 \leq S \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

S

Output

Print six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfy the conditions, in this order, with spaces in between.
If multiple solutions exist, any of them will be accepted.

Sample Input 1

3

Sample Output 1

1 0 2 2 0 1

The area of the triangle in a two-dimensional plane whose vertices are (1,0),(2,2), and (0,1) is 3/2.
Printing 3 0 3 1 0 1 or 1 0 0 1 2 2 will also be accepted.

Sample Input 2

100

Sample Output 2

0 0 10 0 0 10

Sample Input 3

311114770564041497

Sample Output 3

314159265 358979323 846264338 327950288 419716939 937510582

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.*;
class Main{
  public static void main(String[] args){
    Scanner sc=new Scanner(System.in);
    long s=sc.nextLong();
    long a,b,c,d;
    if(Math.sqrt(s)%1==0){
        a=d=(int)Math.sqrt(s);
    }else{
        a=d=1+(int)Math.sqrt(s);
    }
    long tmp=a*a-s;
    if(tmp==1){
        System.out.println(0+" "+0+" "+a+" "+1+" "+1+" "+d);
        return;
    }else if(tmp==0){
        System.out.println(0+" "+0+" "+a+" "+0+" "+0+" "+d);
        return;
    }
    for(long i=2;i<=Math.sqrt(tmp);i++){
        if(tmp%i==0){
            b=i;
            c=tmp/i;
            System.out.println(0+" "+0+" "+a+" "+b+" "+c+" "+d);
            return;
        }
    }
    d-=1;
    tmp-=a;
    b=1;
    c=tmp;
    System.out.println(0+" "+0+" "+a+" "+b+" "+c+" "+d);
  }
}