Problem:
Score : 500 points

Problem Statement

There is an infinitely long street that runs west to east, which we consider as a number line.

There are N roadworks scheduled on this street.
The i-th roadwork blocks the point at coordinate X_i from time S_i - 0.5 to time T_i - 0.5.

Q people are standing at coordinate 0. The i-th person will start the coordinate 0 at time D_i, continue to walk with speed 1 in the positive direction and stop walking when reaching a blocked point.

Find the distance each of the Q people will walk.

Constraints

All values in input are integers.

1 \leq N, Q \leq 2 \times 10^5

0 \leq S_i < T_i \leq 10^9

1 \leq X_i \leq 10^9

0 \leq D_1 < D_2 < ... < D_Q \leq 10^9

If i \neq j and X_i = X_j, the intervals [S_i, T_i) and [S_j, T_j) do not overlap.

Input

Input is given from Standard Input in the following format:

N Q
S_1 T_1 X_1
:
S_N T_N X_N
D_1
:
D_Q

Output

Print Q lines. The i-th line should contain the distance the i-th person will walk or -1 if that person walks forever.

Sample Input 1

4 6
1 3 2
7 13 10
18 20 13
3 4 2
0
1
2
3
5
8

Sample Output 1

2
2
10
-1
13
-1

The first person starts coordinate 0 at time 0 and stops walking at coordinate 2 when reaching a point blocked by the first roadwork at time 2.

The second person starts coordinate 0 at time 1 and reaches coordinate 2 at time 3. The first roadwork has ended, but the fourth roadwork has begun, so this person also stops walking at coordinate 2.

The fourth and sixth persons encounter no roadworks while walking, so they walk forever. The output for these cases is -1.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.Scanner;
import java.util.TreeSet;

/**
 * Built using CHelper plug-in
 * Actual solution is at the top
 *
 * @author Eric
 */
public class Main {
    public static void main(String[] args) {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        Scanner in = new Scanner(inputStream);
        PrintWriter out = new PrintWriter(outputStream);
        ERoadwork solver = new ERoadwork();
        solver.solve(1, in, out);
        out.close();
    }

    static class ERoadwork {
        public void solve(int testNumber, Scanner in, PrintWriter out) {
            int n = in.nextInt();
            int q = in.nextInt();

            TreeSet<ERoadwork.Event> events = new TreeSet<>();
            for (int i = 0; i < n; i++) {
                int s = in.nextInt();
                int t = in.nextInt();
                int x = in.nextInt();

                events.add(new ERoadwork.Event(s - x, x, 2));
                events.add(new ERoadwork.Event(t - x, x, 1));
            }
            for (int i = 0; i < q; i++) {
                events.add(new ERoadwork.Event(in.nextInt(), i, 3));
            }

            TreeSet<Integer> currents = new TreeSet<>();
            int[] res = new int[q];
            for (ERoadwork.Event event : events)
                if (event.type == 2)
                    currents.add(event.x);
                else if (event.type == 1)
                    currents.remove(event.x);
                else {
                    res[event.x] = currents.isEmpty() ? -1 : currents.first();
                }

            for (int i = 0; i < q; i++) {
                out.println(res[i]);
            }

        }

        public static class Event implements Comparable<ERoadwork.Event> {
            int t;
            int x;
            int type;

            public Event(int t, int x, int type) {
                this.t = t;
                this.x = x;
                this.type = type;
            }

            public int compareTo(ERoadwork.Event o) {
                return t != o.t ? t - o.t : (type != o.type ? type - o.type : x - o.x);
            }

        }

    }
}