Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Wrong Answer)

import java.util.Scanner;

public class Main {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);

        String str = sc.nextLine().toLowerCase();
        int ct[][] = new int[26][2];

        for (int i = 0; i < 26; i++) {
            ct[i][0] = 97 + i;
            ct[i][1] = 0;
        }

        for (int i = 0; i < str.length(); i++) {
            for (int j = 0; j < 26; j++) {
                if (str.charAt(i) == (char) ct[j][0]) {
                    ct[j][1]++;
                }

            }
        }

        for (int i = 0; i < 26; i++) {
            System.out.println((char) ct[i][0] + " : " + ct[i][1]);
        }
    }
}