Problem:
Score : 200 points

Problem Statement

You are given a string S. Each character of S is uppercase or lowercase English letter.
Determine if S satisfies all of the following conditions:

The initial character of S is an uppercase A.

There is exactly one occurrence of C between the third character from the beginning and the second to last character (inclusive).

All letters except the A and C mentioned above are lowercase.

Constraints

4 ≤ |S| ≤ 10 (|S| is the length of the string S.)

Each character of S is uppercase or lowercase English letter.

Input

Input is given from Standard Input in the following format:

S

Output

If S satisfies all of the conditions in the problem statement, print AC; otherwise, print WA.

Sample Input 1

AtCoder

Sample Output 1

AC

The first letter is A, the third letter is C and the remaining letters are all lowercase, so all the conditions are satisfied.

Sample Input 2

ACoder

Sample Output 2

WA

The second letter should not be C.

Sample Input 3

AcycliC

Sample Output 3

WA

The last letter should not be C, either.

Sample Input 4

AtCoCo

Sample Output 4

WA

There should not be two or more occurrences of C.

Sample Input 5

Atcoder

Sample Output 5

WA

The number of C should not be zero, either.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.*;
import java.math.*;
class Main {
  public static void main(String[] args) {
    Scanner sc = new Scanner(System.in);
    String s = sc.next();
    boolean cond1 = true;
    int cond2 =0;
    int count = 0;
    boolean flag= true;
    // to check condition 1 ( A at the begining)
    if(s.charAt(0) != 'A') cond1 = false;

    // to check condition 2 
    for(int i=2;i<=s.length()-1;i++) {
      if(s.charAt(i) == 'C') count++;
    }

    //to check condition 3
    for(int j=1;j<s.length()-1;j++) {
      if(Character.isUpperCase(j)) cond2++;
    }

    // to print result
    if(cond1 == true && count == 1 && cond2 == 1) {
      System.out.println("AC");
    } else {
      System.out.println("NO");
    }

    
      }


  }