Problem:
Score : 500 points

Problem Statement

We have N logs of lengths A_1,A_2,\cdots A_N.

We can cut these logs at most K times in total. When a log of length L is cut at a point whose distance from an end of the log is t (0<t<L), it becomes two logs of lengths t and L-t.

Find the shortest possible length of the longest log after at most K cuts, and print it after rounding up to an integer.

Constraints

1 \leq N \leq 2 \times 10^5

0 \leq K \leq 10^9

1 \leq A_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
A_1 A_2 \cdots A_N

Output

Print an integer representing the answer.

Sample Input 1

2 3
7 9

Sample Output 1

4

First, we will cut the log of length 7 at a point whose distance from an end of the log is 3.5, resulting in two logs of length 3.5 each.

Next, we will cut the log of length 9 at a point whose distance from an end of the log is 3, resulting in two logs of length 3 and 6.

Lastly, we will cut the log of length 6 at a point whose distance from an end of the log is 3.3, resulting in two logs of length 3.3 and 2.7.

In this case, the longest length of a log will be 3.5, which is the shortest possible result. After rounding up to an integer, the output should be 4.

Sample Input 2

3 0
3 4 5

Sample Output 2

5

Sample Input 3

10 10
158260522 877914575 602436426 24979445 861648772 623690081 433933447 476190629 262703497 211047202

Sample Output 3

292638192

Solution in Java (OpenJDK 11.0.6) (judge verdict: Wrong Answer)

import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.function.*;
import java.util.regex.*;
import java.util.stream.*;
import static java.util.stream.Collectors.joining;
import static java.util.stream.Collectors.toList;

public class Main
{
    public static void main(String[] args)
    {
        Scanner in=new Scanner(System.in);
        int n=in.nextInt();
        long k=in.nextLong();
        long[] arr=new long[n];
        for(int i=0;i<n;i++)
            arr[i]=in.nextLong();
        long max=Integer.MIN_VALUE;
        for(int i=0;i<n;i++)
            max=Math.max(max,arr[i]);
        long low=1;
        long high=max;
        long curr=max;
        while(low<=high)
        {
            long mid=(low+high)/2;
            long sum=0;
            for(int i=0;i<n;i++)
            {
                if(((arr[i]-mid)%mid)==0)
                    sum+=(arr[i]-mid)/mid;
                else
                    sum+=1+(arr[i]-mid)/mid;
            }
            if(sum<=k)
            {
                high=mid-1;
                curr=mid;
            }
            else
                low=mid+1;
        }
        long sum=0;
        /*for(int i=0;i<n;i++)
        {
            if(((arr[i]-292638192)%292638192)==0)
                sum+=(arr[i]-292638192)/292638192;
            else
                sum+=(1+(arr[i]-292638192)/292638192);
        }*/
        System.out.println(curr);
    }
}