Problem:
Score : 200 points

Problem Statement

In the beginning, Takahashi has A cookies, and Aoki has B cookies.
They will perform the following operation alternately, starting from Takahashi:

If the number of cookies in his hand is odd, eat one of those cookies; if the number is even, do nothing. Then, give one-half of the cookies in his hand to the other person.

Find the numbers of cookies Takahashi and Aoki respectively have after performing K operations in total.

Constraints

1 \leq A,B \leq 10^9

1 \leq K \leq 100

A,B and K are integers.

Input

Input is given from Standard Input in the following format:

A B K

Output

Print the number of cookies Takahashi has, and the number of cookies Aoki has, in this order, after performing K operations in total.

Sample Input 1

5 4 2

Sample Output 1

5 3

The process will go as follows:

In the beginning, Takahashi and Aoki have 5 and 4 cookies, respectively.

Takahashi eats one cookie and gives two cookies to Aoki. They now have 2 and 6 cookies, respectively.

Aoki gives three cookies to Takahashi. They now have 5 and 3 cookies, respectively.

Sample Input 2

3 3 3

Sample Output 2

1 3

Sample Input 3

314159265 358979323 84

Sample Output 3

448759046 224379523

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.Scanner;

public class Main {
	public static void main(String[] args){
		Scanner sc = new Scanner(System.in);
		
		// 整数の入力 高橋
		int T= sc.nextInt();
		// 整数の入力　青木
		int A = sc.nextInt();
		// 整数の入力　ループ回数
		int K = sc.nextInt();
		
		boolean aoki = false;
		for(int i = 0 ; i < K; i++){
			//trueなら青木
			if(aoki){
				//偶数
				if(T % 2 == 0){
					T += A / 2;
					A -= A / 2;
				}
				//奇数
				else{
					A -= 1;
					T += A / 2;
					A -= A / 2;
				}
				aoki = false;
			}
			else{
				//偶数
				if(T % 2 == 0){
					A += T / 2;
					T -= T / 2;
				}
				//奇数
				else{
					T -= 1;
					A += T / 2;
					T -= T / 2;
				}
				aoki = true;
			}
		}
		System.out.print(T + " ");
		System.out.print(A);
	}
}