Problem:
Score : 300 points

Problem Statement

Takahashi participated in a contest on AtCoder.

The contest had N problems.

Takahashi made M submissions during the contest.

The i-th submission was made for the p_i-th problem and received the verdict S_i (AC or WA).

The number of Takahashi's correct answers is the number of problems on which he received an AC once or more.

The number of Takahashi's penalties is the sum of the following count for the problems on which he received an AC once or more: the number of WAs received before receiving an AC for the first time on that problem.

Find the numbers of Takahashi's correct answers and penalties.

Constraints

N, M, and p_i are integers.

1 \leq N \leq 10^5

0 \leq M \leq 10^5

1 \leq p_i \leq N

S_i is AC or WA.

Input

Input is given from Standard Input in the following format:

N M
p_1 S_1
:
p_M S_M

Output

Print the number of Takahashi's correct answers and the number of Takahashi's penalties.

Sample Input 1

2 5
1 WA
1 AC
2 WA
2 AC
2 WA

Sample Output 1

2 2

In his second submission, he received an AC on the first problem for the first time. Before this, he received one WA on this problem.

In his fourth submission, he received an AC on the second problem for the first time. Before this, he received one WA on this problem.

Thus, he has two correct answers and two penalties.

Sample Input 2

100000 3
7777 AC
7777 AC
7777 AC

Sample Output 2

1 0

Note that it is pointless to get an AC more than once on the same problem.

Sample Input 3

6 0

Sample Output 3

0 0

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.*;
 

public class Main{
	
	
	
	
	public static long answer = 0;
	public static long MOD=1000000007;
	
	
	

	

 
	
	//最大公約数・最小公倍数（セットで使う）
	public static long gcm(long a, long b) {
		long result = a;
		long k = 0;
		long n = b;
		do {
			k = result % n;
			result = n;
			n = k;
		} while(k != 0);
		return result;
	}
	
	public static long lcm(long a, long b) {
		long g;
		g = gcm(a, b);
		return a/g*b;
	}
	
	static long gcd(long a, long b) {
		if (b == 0) {
			return a;			
		}
		return gcd(b, a % b);
	}
	
	//等差数列
	static long tousasum(int n) {
		return (long)n*((long)n+1)/2;
	}
 
 
 
	//素数判定
	static boolean isPrime (int n) {
		if (n==2) return true;
		if (n<2 || n%2==0) return false;
		double d = Math.sqrt(n);
		for (int i=3; i<=d; i+=2) if(n%i==0){return false;}
		return true;
	}
 
 
	//倍数判定（10進数以外のときに有用）
	static boolean isMultiple (String s, int base, int m) {
		int temp = 0;
		for (int i=0; i<s.length(); i++) {
			temp = (temp*base+Character.getNumericValue(s.charAt(i)))%m;
		}
		if (temp==0) {return true;}
		return false;
	}
 
 
	//階乗
	static long factorial (int k) {
		long sum = 1;
		for(int i=1;i<=k;i++) {
			sum = (sum*i)%MOD;
		}
		return sum;
		
	}
 
 
	//進数変換
	static String toNbase (String sm, int m, int n) {
		return Long.toString(Long.parseLong(sm,m),n);
	}
	
	public static final long gcd_n(long[] param) {
	    final int len = param.length;
	    long g = gcd(param[0], param[1]);    //gcd(a, b) は以前作ったもの
	    for (int i = 1; i < len - 1; i++) {
	        g = gcd(g, param[i + 1]);       //gcd(a, b) は以前作ったもの
	    }
	    return g;
	}
	
	public static long lcm_n(long[] numbers) {
		long l;
		l = numbers[0];
		for (int i = 1; i < numbers.length; i++) {
			l = lcm(l, numbers[i]);
		}
		return l;
	}
	
	
	private static String convertToOiginal(String unicode)
	{
	    String[] codeStrs = unicode.split("\\\\u");
	    int[] codePoints = new int[codeStrs.length - 1]; // 最初が空文字なのでそれを抜かす
	    for (int i = 0; i < codePoints.length; i++) {
	        codePoints[i] = Integer.parseInt(codeStrs[i + 1], 16);
	    }
	    String encodedText = new String(codePoints, 0, codePoints.length);
	    return encodedText;
	}
	
	
 public static void main(String[] args) {
	 
	Scanner sc=new Scanner(System.in);
	int N=sc.nextInt(),M=sc.nextInt();
	int p[] = new int[M];
	String S[] =new String[M];
	long temp;
	long WA = 0;
	long index = 0;
	Map<Integer,Integer> AC= new TreeMap<Integer,Integer>();
	for(int i=0;i<M;i++) {
		p[i]=sc.nextInt();
		S[i]=sc.next();
		if(S[i].equals("AC")) {
			if(!AC.containsKey(p[i])) {
				AC.put(p[i],i);
				index = i;
			}
			
		}else {
			if(AC.containsKey(p[i])) {
				S[i] = "";
			}
			
		}
		
	}
	
	for(int i=0;i<index;i++) {
		if(S[i].equals("WA")) {
			WA++;
		}
	}
	
	System.out.println(AC.size());
	System.out.println(WA);
	
	
	
	 

	 
	 
	
}
 
 
}