Problem:
Score : 300 points

Problem Statement

You are given a sequence of length N: A_1, A_2, ..., A_N.
For each integer i between 1 and N (inclusive), answer the following question:

Find the maximum value among the N-1 elements other than A_i in the sequence.

Constraints

2 \leq N \leq 200000

1 \leq A_i \leq 200000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1
:
A_N

Output

Print N lines. The i-th line (1 \leq i \leq N) should contain the maximum value among the N-1 elements other than A_i in the sequence.

Sample Input 1

3
1
4
3

Sample Output 1

4
3
4

The maximum value among the two elements other than A_1, that is, A_2 = 4 and A_3 = 3, is 4.

The maximum value among the two elements other than A_2, that is, A_1 = 1 and A_3 = 3, is 3.

The maximum value among the two elements other than A_3, that is, A_1 = 1 and A_2 = 4, is 4.

Sample Input 2

2
5
5

Sample Output 2

5
5

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.*;

public class Main {
	// public static void printArray(int[] a) {
	// 	for (int i = 0; i < a.length; i++) {
	// 		System.out.print(a[i] + ", ");
	// 	}
	// 	System.out.println();
	// }

	// public static<T> void printArrayT(T[] a) {
	// 	for (int i = 0; i < a.length; i++) {
	// 		System.out.print(a[i] + ", ");
	// 	}
	// 	System.out.println();
	// }

	// public static class Triple implements Comparable<Triple> {
	// 	public int A, B, C;
	// 	Triple(int A, int B, int C) {
	// 		this.A = A;
	// 		this.B = B;
	// 		this.C = C;
	// 	}

	// 	@Override
	// 	public String toString() {
	// 		return String.format("(%d, %d, %d)", A, B, C);
	// 	}

	// 	@Override
	// 	public int compareTo(Triple o) {
	// 		int a = this.A - o.A;
	// 		if (a != 0) return a;
	// 		int b = this.B - o.B;
	// 		if (b != 0) return b;
	// 		return this.C - o.C;
	// 	}
	// }

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		int N = sc.nextInt();
		int[] A = new int[N];
		for (int i = 0; i < N; i++) {
			A[i] = sc.nextInt();
		}
		int[] L = new int[N];
		int[] R = new int[N];
		for (int i = 1; i < N; i++) {
			L[i] = Math.max(L[i-1], A[i-1]);
		}
		for (int i = N-2; i >= 0; i--) {
			R[i] = Math.max(R[i+1], A[i+1]);
		}
		StringBuilder buff = new StringBuilder();
		for (int i = 0; i < N; i++) {
			buff.append(Math.max(L[i], R[i]));
			buff.append('\n');
		}
		System.out.print(buff);
	}
}