Problem:
Simultaneous Equation

Write a program which solve a simultaneous equation:

ax + by = c

dx + ey = f

The program should print x and y for given a, b, c, d, e and f (-1,000 ≤ a, b, c, d, e, f ≤ 1,000). You can suppose that given equation has a unique solution.

Input

The input consists of several data sets, 1 line for each data set. In a data set, there will be a, b, c, d, e, f separated by a single space. The input terminates with EOF.

Output

For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.

Sample Input 1

1 2 3 4 5 6
2 -1 -2 -1 -1 -5

Output for the Sample Input 1

-1.000 2.000
1.000 4.000

Sample Input 2

2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27

Output for the Sample Input 2

0.000 3.000
0.000 3.000

Solution in JAVA (judge verdict: Wrong Answer)

import java.util.Scanner;

public class Main {
	public static void main(String[] args)
	{
		Scanner sc = new Scanner(System.in);
		while(sc.hasNext()){
			double a = sc.nextDouble();
			double b = sc.nextDouble();
			double c = sc.nextDouble();
			double d = sc.nextDouble();
			double e = sc.nextDouble();
			double f = sc.nextDouble();
					   b = b*d;
					   c = c*d;
					   e = e*a;
					   f = f*a;

					double y = (c-f)/(b-e);
					double x = (c-(b*y))/(a*d);
					if(x>0)x = (double)((int)((x * 1000)+0.5))/1000;
					if(x<0)x = (double)((int)((x * 1000)-0.5))/1000;
					if(y>0)y = (double)((int)((y * 1000)+0.5))/1000;
					if(y<0)y = (double)((int)((y * 1000)-0.5))/1000;
					if(x==-0.0)x=0.0;
					if(y==-0.0)y=0.0;
			System.out.println(x +" "+ y);
		}
	}
}