Problem:
Simultaneous Equation

Write a program which solve a simultaneous equation:

ax + by = c

dx + ey = f

The program should print x and y for given a, b, c, d, e and f (-1,000 ≤ a, b, c, d, e, f ≤ 1,000). You can suppose that given equation has a unique solution.

Input

The input consists of several data sets, 1 line for each data set. In a data set, there will be a, b, c, d, e, f separated by a single space. The input terminates with EOF.

Output

For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.

Sample Input 1

1 2 3 4 5 6
2 -1 -2 -1 -1 -5

Output for the Sample Input 1

-1.000 2.000
1.000 4.000

Sample Input 2

2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27

Output for the Sample Input 2

0.000 3.000
0.000 3.000

Solution in JAVA (judge verdict: Wrong Answer)

import java.math.BigDecimal;
import java.util.Scanner;

public class Main {
	static Scanner sc =  new java.util.Scanner(System.in);

	public static void main(String[] args) {
		
		
		while ( sc.hasNext() ){
		
		int a = sc.nextInt();
		int b = sc.nextInt();
		int c = sc.nextInt();
		int d = sc.nextInt();
		int e = sc.nextInt();
		int f = sc.nextInt();
		
		double x = ( c*e - b*f ) / ( a*e - b*d );
		double y = ( a*f - c*d ) / ( a*e - b*d );
		
		BigDecimal bix = new BigDecimal (String.valueOf(x));
		BigDecimal biy = new BigDecimal (String.valueOf(y));
		x =bix.setScale(3, BigDecimal.ROUND_HALF_UP).doubleValue();
		y =biy.setScale(3, BigDecimal.ROUND_HALF_UP).doubleValue();
		String xx = String.format("%.3f",bix);
		String yy = String.format("%.3f",biy);
		
		System.out.println( xx +  " " + yy );
		
		}

	}

}