Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.*;
public class Main {
public static void main(String[] args){
  	Scanner sc = new Scanner(System.in);
  	int[][] a = new int[3][3];
  	for(int i=0;i<3;i++){
      for(int j=0;j<3;j++){
      	a[i][j] = sc.nextInt();
	  }
    }
	int N = sc.nextInt();	
  	int[] b = new int[N];
  	for(int k=0;k<N;k++){
      	b[k] = sc.nextInt();
	}
  	for(int t=0;t<N;t++){
      for(int i=0;i<3;i++){
        for(int j=0;j<3;j++){
          if(a[i][j] == b[t]){
            a[i][j] = 0;
          }
        }
      }
    }

    if((a[0][0]==0)&&(a[0][1]==0)&&(a[0][2]==0)){
      System.out.println("Yes");
    }else if((a[1][0]==0)&&(a[1][1]==0)&&(a[1][2]==0)){
      System.out.println("Yes");
    }else if((a[2][0]==0)&&(a[2][1]==0)&&(a[2][2]==0)){
      System.out.println("Yes");
    }else if((a[0][0]==0)&&(a[1][0]==0)&&(a[2][0]==0)){
      System.out.println("Yes");
    }else if((a[0][1]==0)&&(a[1][1]==0)&&(a[2][1]==0)){
      System.out.println("Yes");
    }else if((a[0][2]==0)&&(a[1][2]==0)&&(a[2][2]==0)){
      System.out.println("Yes");
    }else if((a[0][0]==0)&&(a[1][1]==0)&&(a[2][2]==0)){
      System.out.println("Yes");
    }else if((a[2][0]==0)&&(a[1][1]==0)&&(a[0][2]==0)){
      System.out.println("Yes");
    }else{
      System.out.println("No");
    }

	}
}