Problem:
Score : 300 points

Problem Statement

You are given a sequence of length N: A_1, A_2, ..., A_N.
For each integer i between 1 and N (inclusive), answer the following question:

Find the maximum value among the N-1 elements other than A_i in the sequence.

Constraints

2 \leq N \leq 200000

1 \leq A_i \leq 200000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1
:
A_N

Output

Print N lines. The i-th line (1 \leq i \leq N) should contain the maximum value among the N-1 elements other than A_i in the sequence.

Sample Input 1

3
1
4
3

Sample Output 1

4
3
4

The maximum value among the two elements other than A_1, that is, A_2 = 4 and A_3 = 3, is 4.

The maximum value among the two elements other than A_2, that is, A_1 = 1 and A_3 = 3, is 3.

The maximum value among the two elements other than A_3, that is, A_1 = 1 and A_2 = 4, is 4.

Sample Input 2

2
5
5

Sample Output 2

5
5

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.ArrayList;
import java.util.Collections;
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        ArrayList<Integer> list = new ArrayList<>();
        for (int i = 0; i < n; i++){
            list.add(sc.nextInt());
        }

        int max = 0;
        int max2 = 0;
        int pos = -1;

        for (int i = 0; i < n; i++){
            int temp = list.get(i);
            if (max < temp){
                max = temp;
                pos = i;
            }
        }

        for (int i = 0; i < n; i++){
            if (i == pos){
                continue;
            }
            int temp = list.get(i);
            if (max2 < temp){
                max2 = temp;
//                pos = i;
            }
        }

        for (int i = 0; i < n; i++){
            if (i != pos) {
                System.out.println(max);
            }else {
                System.out.println(max2);
            }
        }
    }
}