Problem:
Score : 200 points

Problem Statement

You are given strings s and t, consisting of lowercase English letters.
You will create a string s' by freely rearranging the characters in s.
You will also create a string t' by freely rearranging the characters in t.
Determine whether it is possible to satisfy s' < t' for the lexicographic order.

Notes

For a string a = a_1 a_2 ... a_N of length N and a string b = b_1 b_2 ... b_M of length M, we say a < b for the lexicographic order if either one of the following two conditions holds true:

N < M and a_1 = b_1, a_2 = b_2, ..., a_N = b_N.

There exists i (1 \leq i \leq N, M) such that a_1 = b_1, a_2 = b_2, ..., a_{i - 1} = b_{i - 1} and a_i < b_i. Here, letters are compared using alphabetical order.

For example, xy < xya and atcoder < atlas.

Constraints

The lengths of s and t are between 1 and 100 (inclusive).

s and t consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s
t

Output

If it is possible to satisfy s' < t', print Yes; if it is not, print No.

Sample Input 1

yx
axy

Sample Output 1

Yes

We can, for example, rearrange yx into xy and axy into yxa. Then, xy < yxa.

Sample Input 2

ratcode
atlas

Sample Output 2

Yes

We can, for example, rearrange ratcode into acdeort and atlas into tslaa. Then, acdeort < tslaa.

Sample Input 3

cd
abc

Sample Output 3

No

No matter how we rearrange cd and abc, we cannot achieve our objective.

Sample Input 4

w
ww

Sample Output 4

Yes

Sample Input 5

zzz
zzz

Sample Output 5

No

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.io.IOException;
import java.util.Arrays;
import java.util.Comparator;
import java.util.Scanner;

public class Main {


	public static void main(String[] args) throws IOException {

		Scanner sc = new Scanner(System.in);

		String s1 = sc.next();
		String s2 = sc.next();

		int loopCount = Math.min(s1.length(), s2.length());

		String[] os1 = stringSort(s1);
		String[] os2 = stringRevSort(s2);
		String res = "No";

		System.out.println(String.join("", os1));
		System.out.println(String.join("", os2));

		if (String.join("", os1).equals(String.join("", os2))) {
			res = "No";
		} else {
			for (int i = 0; i < loopCount; i++) {
				System.out.println("i:"+i);
				if (os1[i].compareTo(os2[i]) < 0) {
					res = "Yes";
					break;
				} else if (os1[i].compareTo(os2[i]) == 0) {
					if (i == loopCount-1) {
						res = "Yes";
					}
					continue;
				} else {
					continue;
				}
			}
		}

		System.out.println(res);
		sc.close();
	}

	public static String[] stringSort(String inString) {

		String[] inStrings = inString.split("");
		String[] outStrings;

		Arrays.sort(inStrings, new Comparator<String>() {

			public int compare(String obj1, String obj2) {
				return obj1.compareTo(obj2);
			}
		});
		outStrings = inStrings;

		return outStrings;
	}

	public static String[] stringRevSort(String inString) {

		String[] inStrings = inString.split("");
		String[] outStrings;

		Arrays.sort(inStrings, new Comparator<String>() {

			public int compare(String obj1, String obj2) {
				return obj2.compareTo(obj1);
			}
		});
		outStrings = inStrings;

		return outStrings;
	}
}