Problem:
Score : 200 points

Problem Statement

You are given a positive integer X.
Find the largest perfect power that is at most X.
Here, a perfect power is an integer that can be represented as b^p, where b is an integer not less than 1 and p is an integer not less than 2.

Constraints

1 ≤ X ≤ 1000

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print the largest perfect power that is at most X.

Sample Input 1

10

Sample Output 1

9

There are four perfect powers that are at most 10: 1, 4, 8 and 9.
We should print the largest among them, 9.

Sample Input 2

1

Sample Output 2

1

Sample Input 3

999

Sample Output 3

961

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		try(Scanner sn = new Scanner(System.in)) {
			int x = sn.nextInt();
			double max = 1;
			double tmp = 0;
			LAB:for (int i = 2; i < x; i++) {
				int j = 2;
				while (true) {
					tmp = Math.pow(i, j);
					if (tmp <= x) {
						if (max <= tmp) {
							max = tmp;
						}
						j++;
					} else {
						continue LAB;
					}
				}
			}
			System.out.println((int)max);
		}
	}

}