Problem:
Simultaneous Equation

Write a program which solve a simultaneous equation:

ax + by = c

dx + ey = f

The program should print x and y for given a, b, c, d, e and f (-1,000 ≤ a, b, c, d, e, f ≤ 1,000). You can suppose that given equation has a unique solution.

Input

The input consists of several data sets, 1 line for each data set. In a data set, there will be a, b, c, d, e, f separated by a single space. The input terminates with EOF.

Output

For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.

Sample Input 1

1 2 3 4 5 6
2 -1 -2 -1 -1 -5

Output for the Sample Input 1

-1.000 2.000
1.000 4.000

Sample Input 2

2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27

Output for the Sample Input 2

0.000 3.000
0.000 3.000

Solution in JAVA (judge verdict: Accepted)

import java.util.Scanner;
public class Main{
	public static void main(String[] args){
		Scanner sc=new Scanner(System.in);
		while(sc.hasNextInt()){
			int a,b,c,d,e,f;
			double x,y,det;
			a=sc.nextInt();
			b=sc.nextInt();
			c=sc.nextInt();
			d=sc.nextInt();
			e=sc.nextInt();
			f=sc.nextInt();
			det=a*e-b*d;
			x=(1/det)*(e*c-b*f);
			y=(1/det)*(-c*d+a*f);
			if((x*1000)%1>=2/1){
				x=((x*1000-(x*1000)%1)+1)/1000;
			}else if((x*1000)%1<2/1){
				x=(x*1000-(x*1000)%1)/1000;
			}
			if((y*1000)%1>=2/1){
				y=((y*1000-(y*1000)%1)+1)/1000;
			}else if((y*1000)%1<2/1){
				y=(y*1000-(y*1000)%1)/1000;
			}
			System.out.println(String.format("%.3f %.3f",x,y));
		}
		sc.close();
	}
}