Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.*;
 
class Main {
static Scanner scan = new Scanner(System.in);
  
  public static void main(String[] args){
	int n = scan.nextInt();  
    int count = 0;
    int ans = 0;
    
    for(int kisuu = 105; kisuu <= n ;kisuu += 2)
    {
      for(int yakusuu = 1 ;yakusuu <= n ; yakusuu++)
      {
      if( kisuu % yakusuu == 0){count += 1; }
      }
      if (count == 8){ans += 1; }
    }
    System.out.println(ans);
  }
}