Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Java (OpenJDK 11.0.6) (judge verdict: Accepted)



import java.util.Scanner;

public class Main {

	public static void main(String[] args) {

		Scanner sc = new Scanner(System.in);

		int n = sc.nextInt();
		int count = 0; //約数の数
		int count2 = 0;

		for(int i=1 ; i<=n ; i++) {
			for(int j=1 ; j<=i ; j++) {
				if(i % 2 == 1 && i % j == 0) {
					count ++;
				}
			}
			if(count == 8) {
				count2++;
			}
			count = 0;
		}

		System.out.println(count2);


		sc.close();

	}

}