Problem:
Score : 200 points

Problem Statement

There is a square in the xy-plane. The coordinates of its four vertices are (x_1,y_1),(x_2,y_2),(x_3,y_3) and (x_4,y_4) in counter-clockwise order.
(Assume that the positive x-axis points right, and the positive y-axis points up.)

Takahashi remembers (x_1,y_1) and (x_2,y_2), but he has forgot (x_3,y_3) and (x_4,y_4).

Given x_1,x_2,y_1,y_2, restore x_3,y_3,x_4,y_4. It can be shown that x_3,y_3,x_4 and y_4 uniquely exist and have integer values.

Constraints

|x_1|,|y_1|,|x_2|,|y_2| \leq 100

(x_1,y_1) ≠ (x_2,y_2)

All values in input are integers.

Input

Input is given from Standard Input in the following format:

x_1 y_1 x_2 y_2

Output

Print x_3,y_3,x_4 and y_4 as integers, in this order.

Sample Input 1

0 0 0 1

Sample Output 1

-1 1 -1 0

(0,0),(0,1),(-1,1),(-1,0) is the four vertices of a square in counter-clockwise order.
Note that (x_3,y_3)=(1,1),(x_4,y_4)=(1,0) is not accepted, as the vertices are in clockwise order.

Sample Input 2

2 3 6 6

Sample Output 2

3 10 -1 7

Sample Input 3

31 -41 -59 26

Sample Output 3

-126 -64 -36 -131

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.*;

class Main {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        String[] xyxy = scanner.nextLine().split(" ", 4);
        int x1 = Integer.parseInt(xyxy[0]);
        int y1 = Integer.parseInt(xyxy[1]);
        int x2 = Integer.parseInt(xyxy[2]);
        int y2 = Integer.parseInt(xyxy[3]);

        int x3 = 0;
        int y3 = 0;
        int x4 = 0;
        int y4 = 0;
        if (x1 == x2) {
            if (y1 < y2) {
                x3 = x1 - (y2 - y1);
                y3 = y2;
                x4 = x1 - (y2 - y1);
                y4 = y1;
            } else {
                x3 = x1 + (y1 - y2);
                y3 = y2;
                x4 = x1 + (y1 - y2);
                y4 = y1;
            }
        } else {
            if (x1 < x2) {
                x3 = x2;
                y3 = y1 + x2 - x1;
                x4 = x1;
                y4 = y1 + x2 - x1;
            } else {
                x3 = x2;
                y3 = y1 - (x1 - x2);
                x4 = x1;
                y4 = y1 - (x1 - x2);
            }
        }
        System.out.printf("%d %d %d %d\n", x3, y3, x4, y4);
    }
}