Problem:
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Matrix Multiplication

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\[
c_{ij} = \sum_{k=1}^m a_{ik}b_{kj}
\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Constraints

$1 \leq n, m, l \leq 100$

$0 \leq a_{ij}, b_{ij} \leq 10000$

Sample Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2

Sample Output

1 8 5
0 9 6
4 23 14

Note

      解説

Solution in JAVA (judge verdict: WA: Presentation Error)

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
public class Main {
	public static void main(String[] args)throws IOException {
		BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
		String[] str=br.readLine().split(" ");
		int n=Integer.parseInt(str[0]);
		int m=Integer.parseInt(str[1]);
		int l=Integer.parseInt(str[2]);
		int[][] a=new int [n][m];
		int[][] b=new int [m][l];
		int c;

		for(int i=0;i<n;i++){
    		str=br.readLine().split(" ");
            for(int j=0;j<m;j++){
                a[i][j]=Integer.parseInt(str[j]);
            }
        }//配列a[][]に格納
                 
        for(int i=0;i<m;i++){
            str=br.readLine().split(" ");
            for(int j=0;j<l;j++){
            	b[i][j]=Integer.parseInt(str[j]);
            }
        }//配列b[][]に格納
		
        StringBuilder outArray=new StringBuilder();
		for(int i=0;i<n;i++){
			for(int j=0;j<l;j++){
				c=0;
				for (int k=0;k<m;k++){
					c += a[i][k]*b[k][j];
				}
				outArray.append(c + " ");
			}
			outArray.deleteCharAt(outArray.length()-1);
			outArray.append("\n");
		}
		System.out.println(outArray);
	}

}