Problem:
Score : 100 points

Problem Statement

There are a total of A + B cats and dogs.
Among them, A are known to be cats, but the remaining B are not known to be either cats or dogs.

Determine if it is possible that there are exactly X cats among these A + B animals.

Constraints

1 \leq A \leq 100

1 \leq B \leq 100

1 \leq X \leq 200

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B X

Output

If it is possible that there are exactly X cats, print YES; if it is impossible, print NO.

Sample Input 1

3 5 4

Sample Output 1

YES

If there are one cat and four dogs among the B = 5 animals, there are X = 4 cats in total.

Sample Input 2

2 2 6

Sample Output 2

NO

Even if all of the B = 2 animals are cats, there are less than X = 6 cats in total.

Sample Input 3

5 3 2

Sample Output 3

NO

Even if all of the B = 3 animals are dogs, there are more than X = 2 cats in total.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		// TODO 自動生成されたメソッド・スタブ

		Scanner sc = new Scanner(System.in);
		// A B C

		int one = sc.nextInt();
		int two = sc.nextInt();
		int three = sc.nextInt();

//		 int one = Integer.parseInt(args[0]);
//		 int two = Integer.parseInt(args[1]);
//		 int three = Integer.parseInt(args[2]);

		boolean flag = false;
		
		if (three - one > 0 && three - one <= two) {
			flag = true;
		}

//		if ((1 <= one && one < 100) && (1 <= two && two < 100)
//				&& (1 <= three && three < 100)) {
//
//			for (int i = 1; i <= two; i++) {
//				if (one + i == three) {
//					flag = true;
//					break;
//				}
//			}
//
//		}

		if (flag) {
			System.out.print("YES");
		} else {
			System.out.print("NO");
		}
 
	}
}