Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Accepted)

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.HashMap;
import java.util.Map;

class Main {
	public static void main(String[] args) throws IOException {
 
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        StringBuffer sb = new StringBuffer();
 
        Map<Character, Integer> map = new HashMap<Character, Integer>();
        char[] mojiList = "abcdefghijklmnopqrstuvwxyz".toCharArray();
        
        for(char key : mojiList) {
           map.put(key, 0);
        }
        
        String input;
        
        while((input = br.readLine()) != null) {
            char[] strList = input.toLowerCase().toCharArray();
            for(char moji : strList) {
                if(map.containsKey(moji)) {
                    map.put(moji, map.get(moji) + 1);
                }
            }
        }
 
        for(char moji : mojiList) {
            System.out.println(moji + " : " + map.get(moji));
        }
    }
}