Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Accepted)

/**
 * 与えられた文字列の小文字と大文字を入れ替えるプログラムを作成してください。
 */

//スキャナつかうため

import java.util.Scanner;

public class Main {
	// プログラムのエントリポイント
	public static void main(String[] args) {
		// 入力ストリームの生成
		Scanner sc = new Scanner(System.in);

		char[] iremono = { 'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j',
				'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v',
				'w', 'x', 'y', 'z' };
		int[] cou = new int[26];
		int j = 0;


		while (sc.hasNext()) {
			String stralf = sc.nextLine();

			for (int i = 0; i < stralf.length(); i++) {
				char chalf = stralf.charAt(i);
				chalf = Character.toLowerCase(chalf);
				for (j = 0; j < 26; j++) {
					if (iremono[j] == chalf) {
						cou[j]++;
					}
				}
			}
		}
		for (int k = 0; k < 26; k++) {
			System.out.print(iremono[k]);
			System.out.println(" : " + cou[k]);
		}
	}
}