Problem:
Score : 300 points

Problem Statement

You are given an integer sequence of length N. The i-th term in the sequence is a_i.
In one operation, you can select a term and either increment or decrement it by one.

At least how many operations are necessary to satisfy the following conditions?

For every i (1≤i≤n), the sum of the terms from the 1-st through i-th term is not zero.

For every i (1≤i≤n-1), the sign of the sum of the terms from the 1-st through i-th term, is different from the sign of the sum of the terms from the 1-st through (i+1)-th term.

Constraints

2 ≤ n ≤ 10^5

|a_i| ≤ 10^9

Each a_i is an integer.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print the minimum necessary count of operations.

Sample Input 1

4
1 -3 1 0

Sample Output 1

4

For example, the given sequence can be transformed into 1, -2, 2, -2 by four operations. The sums of the first one, two, three and four terms are 1, -1, 1 and -1, respectively, which satisfy the conditions.

Sample Input 2

5
3 -6 4 -5 7

Sample Output 2

0

The given sequence already satisfies the conditions.

Sample Input 3

6
-1 4 3 2 -5 4

Sample Output 3

8

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

/*
* @Author Silviase(@silviasetitech)
* For ProCon
*/

import java.util.*;
import java.lang.*;
import java.math.*;

public class Main{

        static int MOD = (int)1e9+7;

        // for dfs
        static int n;
        static int ansi;
        static int[] w;
        static int[] ww;
        static boolean[] isvisited;
        //
    public static void main(String[] args){
        Scanner sc = new Scanner(System.in);

        int n = sc.nextInt();
        int[] nums = new int[n];
        int cntpm = 0;
        int cntmp = 0;
        for (int i = 0; i < n; i++) {
            nums[i] = sc.nextInt();
        }
        int ruisekipm = 0;
        int ruisekimp = 0;
        for (int i = 0; i < n; i++) {
            ruisekimp+=nums[i];
            ruisekipm+=nums[i];
            if (i % 2 == 0) { // mp -> m,pm -> p
                if (ruisekimp >= 0) {
                    cntmp += Math.abs(ruisekimp+1);
                    ruisekimp = -1;
                }
                if (ruisekipm <= 0) {
                    cntpm += Math.abs(ruisekipm-1);
                    ruisekipm = 1;
                }
            }else{
                if (ruisekipm >= 0) {
                    cntpm += Math.abs(ruisekipm+1);
                    ruisekipm = -1;
                }
                if (ruisekimp <= 0) {
                    cntmp += Math.abs(ruisekimp-1);
                    ruisekimp = 1;
                }
            }
        }
        System.out.println(Math.min(cntmp, cntpm));


        sc.close();
    }

    /*
    For Numeric Analysis
    */
    public static int ManhattanDist(int x, int y, int xx, int yy) {
        return(Math.abs(xx-x) + Math.abs(yy-y));
    }

    public static double FuncOfx(double x, int funcnum) {
        switch (funcnum) {
            case 1:
                return x*x;

            case 2:
                return Math.exp(-1*x)-x*x;
        
            default:
                throw new IllegalArgumentException("Such Func doesn't Exist.");
        }
            
    }

    public static void Nibutan(double target, int funcnum) {
        int callcounter = 0;
        double lowbound = Integer.MIN_VALUE;
        double highbound = Integer.MAX_VALUE;
        double pivot = (lowbound + highbound)/2;
        double tmp;
        double tmp4swap;
        if (funcnum == 1) {
            lowbound = 0;
            pivot = (lowbound+highbound)/2;
        }
        while (true) {
            callcounter++;
            if (FuncOfx(highbound, funcnum) < FuncOfx(lowbound, funcnum)) {
                tmp4swap = highbound;
                highbound = lowbound;
                lowbound = tmp4swap;
            }

            if (FuncOfx(pivot,funcnum) > target) {
                System.out.println(String.format("%2d", callcounter) + ": " 
                            + String.format("%.6f", pivot) + " f(" + String.format("%.6f", pivot) +") is " 
                            + String.format("%.6f",FuncOfx(pivot,funcnum))  + ", so too high :(");
                tmp = (lowbound + pivot)/2;
                if ( Math.abs(tmp-pivot) < 0.00005 ) {
                    System.out.println("Found!" +String.format("%.3f", tmp)+" is the answer.");
                    return;
                }
                highbound = pivot;
                pivot = tmp;
            }else if(FuncOfx(pivot,funcnum) < target){
                System.out.println(String.format("%2d", callcounter) + ": " 
                            + String.format("%.6f", pivot) + " f(" + String.format("%.6f", pivot) +") is " 
                            + String.format("%.6f",FuncOfx(pivot,funcnum))  + ", so too high :(");
                tmp = (highbound + pivot)/2;
                if ( Math.abs(tmp-pivot) < 0.00005 ) {
                    System.out.println("Found!" +String.format("%.3f", tmp)+" is the answer.");
                    return;
                }
                lowbound = pivot;
                pivot = tmp;
            }
        }
        
    }

    /*
    Numeric Analysis End
    */

    private static long[][] CombinationLong_nCk(long n, long k) {
        n++; k++;
        long[][] ans = new long[(int)n][(int)k];
        for (int i = 0; i < n; i++) {
            ans[i][0] = 1;
        }
        for (int i = 0; i < n-1; i++) {
            for (int j = 0; j < k-1; j++) {
                if (i < j) {
                    ans[i][j] = 0;
                }else{
                    ans[i+1][j+1] = ans[i][j] + ans[i][j+1];
                }
            }
        }
        return ans;
    }

        public static int gcd_int(int a, int b) {
        
            if (a < b) {
                int tmpp = a;
                a = b;
                b = tmpp;
            }
            if (b == 0) {
                return a;
            }else{
                return gcd_int(b, a%b);
            }
        } 

        public static long gcd_long(long a, long b) {
        
            if (a < b) {
                long tmpp = a;
                a = b;
                b = tmpp;
            }
            if (b == 0) {
                return a;
            }else{
                return gcd_long(b, a%b);
            }
        }

        public static int lcm_int(int a, int b) {
            int gcd = gcd_int(a,b);
            return a/gcd*b;
        }

        public static long lcm_long(long a, long b) {
            long gcd = gcd_long(a,b);
            return a/gcd*b;
        }

        public static void dfs(int placenow) {
            // if went all -> success! 
            // if not went all -> fail...
            
            /*
            dfs    
            Go All Place that there is way to and not having been yet. 

             if island 1 is start point, dfs(1);
            if there is way to island 2 and island 3,
            - island 2 changes non-visited -> visited, and dfs(2).
            - island 3 changes non-visited -> visited, and dfs(3).
    
            */

            isvisited[placenow] = true;
            boolean success = true;
            for (int i = 0; i < n; i++) {
                if (isvisited[i] == false) { // not go all place
                    success = false;
                    break;
                }
            }
            if (success) {
                ansi++;
                isvisited[placenow] = false;
                return;
            }

            for (int i = 0; i < n; i++) {
                if (w[i] == placenow && isvisited[ww[i]] == false ) {
                    dfs(ww[i]);
                }else if(ww[i] == placenow && isvisited[w[i]] == false){
                    dfs(w[i]);
                }else{
                    continue;
                }
            }
            isvisited[placenow] = false;
            return;
        }

}