Problem:
Score: 100 points

Problem Statement

In this problem, a date is written as Y-M-D. For example, 2019-11-30 means November 30, 2019.

Integers M_1, D_1, M_2, and D_2 will be given as input.

It is known that the date 2019-M_2-D_2 follows 2019-M_1-D_1.

Determine whether the date 2019-M_1-D_1 is the last day of a month.

Constraints

Both 2019-M_1-D_1 and 2019-M_2-D_2 are valid dates in the Gregorian calendar.

The date 2019-M_2-D_2 follows 2019-M_1-D_1.

Input

Input is given from Standard Input in the following format:

M_1 D_1
M_2 D_2

Output

If the date 2019-M_1-D_1 is the last day of a month, print 1; otherwise, print 0.

Sample Input 1

11 16
11 17

Sample Output 1

0

November 16 is not the last day of a month.

Sample Input 2

11 30
12 1

Sample Output 2

1

November 30 is the last day of November.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Scanner;
public class Main {

	public static void main(String[] args) {
		Scanner stdIn = new Scanner(System.in);
		int m1 = stdIn.nextInt();
		int d1 = stdIn.nextInt();
		
		int m2 = stdIn.nextInt();
		int d2 = stdIn.nextInt();
		
		if(m1 ==1 || m1 == 3 || m1 == 5 || m1 == 7 || m1 ==8 || m1 == 10 || m1 ==12) {
			if(d1 == 31) {
				System.out.println(1);
			}else {
				System.out.println(0);
			}
		}
		
		if( m1 == 4 || m1 == 6 || m1 == 9 || m1 ==11) {
			if(d1 == 30) {
				System.out.println(1);
			}else {
				System.out.println(0);
			}
		}
		
		if(m1 == 2) {
			if(d1 == 28) {
				System.out.println(1);
			}else {
				System.out.println(0);
			}
		}
		
	}

}