Problem:
Finding Missing Cards

Taro is going to play a card game. However, now he has only n cards, even though there should be 52 cards (he has no Jokers).

The 52 cards include 13 ranks of each of the four suits: spade, heart, club and diamond.

Input

In the first line, the number of cards n (n ≤ 52) is given.

In the following n lines, data of the n cards are given. Each card is given by a pair of a character and an integer which represent its suit and rank respectively. A suit is represented by 'S', 'H', 'C' and 'D' for spades, hearts, clubs and diamonds respectively. A rank is represented by an integer from 1 to 13.

Output

Print the missing cards. The same as the input format, each card should be printed with a character and an integer separated by a space character in a line.
Arrange the missing cards in the following priorities:

Print cards of spades, hearts, clubs and diamonds in this order.

If the suits are equal, print cards with lower ranks first.

Sample Input

47
S 10
S 11
S 12
S 13
H 1
H 2
S 6
S 7
S 8
S 9
H 6
H 8
H 9
H 10
H 11
H 4
H 5
S 2
S 3
S 4
S 5
H 12
H 13
C 1
C 2
D 1
D 2
D 3
D 4
D 5
D 6
D 7
C 3
C 4
C 5
C 6
C 7
C 8
C 9
C 10
C 11
C 13
D 9
D 10
D 11
D 12
D 13

Sample Output

S 1
H 3
H 7
C 12
D 8

Note

      解説

Solution in JAVA (judge verdict: Wrong Answer)

import java.util.Scanner;


public class Main {
	

	public static void main(String[] args) {
		Scanner stdIn = new Scanner(System.in);
		boolean[][] a = new boolean[4][13];
		int n = stdIn.nextInt();
		for(int i = 0; i < n; i++) {
			String p = stdIn.next();
			int v = stdIn.nextInt();
			
			if(p.equals("S")) {
				a[0][v-1] = true;
			}
			else if (p.equals("H")) {	
				a[1][v-1] = true;
			}
			else if (p.equals("C")) {	
				a[2][v-1] = true;
			}
			else {
				a[3][v-1] = true; break;
			}
		}
		
		for(int i = 0; i < 4; i++) {
			for(int j = 0; j < 13; j++) {
				if(!a[i][j]) {
					switch(i) {
					case 0 : System.out.println("S " + (j + 1)); break;
					case 1 : System.out.println("H " + (j + 1)); break;
					case 2 : System.out.println("C " + (j + 1)); break;
					case 3 : System.out.println("D " + (j + 1)); break;
					}
				}
			}
		}
	}

}