Problem:
Score : 200 points

Problem Statement

You are given an image A composed of N rows and N columns of pixels, and a template image B composed of M rows and M columns of pixels.

A pixel is the smallest element of an image, and in this problem it is a square of size 1×1.

Also, the given images are binary images, and the color of each pixel is either white or black.

In the input, every pixel is represented by a character: . corresponds to a white pixel, and # corresponds to a black pixel.

The image A is given as N strings A_1,...,A_N.

The j-th character in the string A_i corresponds to the pixel at the i-th row and j-th column of the image A (1≦i,j≦N).

Similarly, the template image B is given as M strings B_1,...,B_M.

The j-th character in the string B_i corresponds to the pixel at the i-th row and j-th column of the template image B (1≦i,j≦M).

Determine whether the template image B is contained in the image A when only parallel shifts can be applied to the images.

Constraints

1≦M≦N≦50

A_i is a string of length N consisting of # and ..

B_i is a string of length M consisting of # and ..

Input

The input is given from Standard Input in the following format:

N M
A_1
A_2
:
A_N
B_1
B_2
:
B_M

Output

Print Yes if the template image B is contained in the image A. Print No otherwise.

Sample Input 1

3 2
#.#
.#.
#.#
#.
.#

Sample Output 1

Yes

The template image B is identical to the upper-left 2 × 2 subimage and the lower-right 2 × 2 subimage of A. Thus, the output should be Yes.

Sample Input 2

4 1
....
....
....
....
#

Sample Output 2

No

The template image B, composed of a black pixel, is not contained in the image A composed of white pixels.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;


public class Main {

	public static void main(String[] args) {
		// TODO 自動生成されたメソッド・スタブ
		Scanner scan = new Scanner(System.in);
		int n = scan.nextInt();
		int m = scan.nextInt();
		String[] a = new String[n];
		String[] b = new String[m];
		String x = "";
		String y = "";
		for (int i = 0; i < n; i++) {
			a[i] = scan.next();
			x = x + a[i];
		}
		for (int i = 0; i < m; i++) {
			b[i] = scan.next();
			y = y + b[i];
		}
		//System.out.println(x);
		List<Integer> index = new ArrayList<Integer>();
if(n>=m) {
		for (int i = 0; i < m; i++) {
			if(x.indexOf(b[i])>=0) {
				index.add(x.indexOf(b[i]));
			}
			}
}else {
	for (int i = 0; i < n; i++) {
		if(x.indexOf(b[i])>=0) {
			index.add(x.indexOf(b[i]));
		}
		}

}

		//System.out.println(index);
//indexの中身が連番になっていればOK
		boolean hyozi =false;
		for(int i=0, l=index.size()-1;i<index.size()-1;i++,l--) {
			if(index.get(i)+1==index.get(i+1)) {
				hyozi =true;

				//降順になってるとき
			}else if(index.get(l)+1==index.get(l-1)){
				hyozi = true;
			}else {
				hyozi = false;
			}
		}

		if(m==n) {
		int count=0;
		for (int i = 0; i < n; i++) {
			if(a[i].equals(b[i])) {
				count++;
			}
			}

		if(count == a.length) {
			hyozi = true;
		}else {
			hyozi=false;
		}
		}

		if (hyozi == true) {
			System.out.println("Yes");
		} else {
			System.out.println("No");
		}
	}
}