Problem:
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Matrix Multiplication

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\[
c_{ij} = \sum_{k=1}^m a_{ik}b_{kj}
\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Constraints

$1 \leq n, m, l \leq 100$

$0 \leq a_{ij}, b_{ij} \leq 10000$

Sample Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2

Sample Output

1 8 5
0 9 6
4 23 14

Note

      解説

Solution in JAVA (judge verdict: Wrong Answer)


import java.util.Scanner;

public class Main {

    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int n = scanner.nextInt();
        int m = scanner.nextInt();
        int l = scanner.nextInt();
        int[][] A = new int[(n)][(m)];
        int[][] B = new int[(m)][(l)];
        int[][] C = new int[(n)][(l)];

        for (int i = 0; n > i; i++) {
            for (int j = 0; m > j; j++) {
                int a = scanner.nextInt();
                A[i][j] = a;
            }
        }

        for (int i = 0; m > i; i++) {
            for (int j = 0; l > j; j++) {
                int a = scanner.nextInt();
                B[i][j] = a;
            }
        }

        for (int i = 0; n > i; i++) {
            for (int j = 0; m > j; j++) {
                for (int k = 0; l > k; k++) {
                    C[i][k] += A[i][j] * B[j][k];
                }
            }
        }

            for (int i = 0; n > i; i++) {
                for (int j = 0; l > j; j++) {
                    if (j != (l-1)) {
                        System.out.print(C[i][j]+" ");
                    } else {
                        System.out.println(C[i][j]);
                    }
                }
            }
        }
    }