Problem:
Score : 200 points

Problem Statement

Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Constraints

1 \leq N \leq 10^5

Input

Input is given from Standard Input in the following format:

N

Output

Print the number of positive integers less than or equal to N that have an odd number of digits.

Sample Input 1

11

Sample Output 1

9

Among the positive integers less than or equal to 11, nine integers have an odd number of digits: 1, 2, \ldots, 9.

Sample Input 2

136

Sample Output 2

46

In addition to 1, 2, \ldots, 9, another 37 integers also have an odd number of digits: 100, 101, \ldots, 136.

Sample Input 3

100000

Sample Output 3

90909

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.*;
public class Main{
	public static void main(String sp[]){
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
String st = String.valueOf(n);
long total=0;
if(n<10){
	System.out.println(n);
}
else if(n<100){
	System.out.println(9);
}
else if(n<1000){
	System.out.println(9+(n-100+1));
}
else if(n<10000){
	System.out.println(9+(n-100+1));
}
else if(n<=100000)
	System.out.println(9+899+(n-10000+1));
}
}