Problem:
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Matrix Multiplication

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\[
c_{ij} = \sum_{k=1}^m a_{ik}b_{kj}
\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Constraints

$1 \leq n, m, l \leq 100$

$0 \leq a_{ij}, b_{ij} \leq 10000$

Sample Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2

Sample Output

1 8 5
0 9 6
4 23 14

Note

      解説

Solution in JAVA (judge verdict: Wrong Answer)

import java.util.Scanner;
class Main{
public static void main(String[] args){
Scanner scan=new Scanner(System.in);
int[][] A=new int[101][101];
int[][] B=new int[101][101];
int[][] sum=new int[101][101];
int a=scan.nextInt();
int b=scan.nextInt();
int c=scan.nextInt();
for(int i=0;i<a;i++){
for(int j=0;j<c;j++){
sum[i][j]=0;
}
}
for(int i=0;i<a;i++){
for(int j=0;j<b;j++){
A[i][j]=scan.nextInt();
}
}
for(int i=0;i<b;i++){
for(int j=0;j<c;j++){
B[i][j]=scan.nextInt();
}
}
for(int l=0;l<a;l++){
for(int m=0;m<c;m++){
for(int n=0;n<b;n++){
sum[l][m]+=A[l][n]*B[n][m];
}
}
}

for(int i=0;i<a;i++){
for(int j=0;j<c;j++){
System.out.print(sum[i][j]);
if(c-1!=j)
System.out.print(" ");
else
System.out.println();
}

}

}
}