Problem:
Score: 400 points

Problem Statement

In Takahashi Kingdom, there is a east-west railroad and N cities along it, numbered 1, 2, 3, ..., N from west to east.
A company called AtCoder Express possesses M trains, and the train i runs from City L_i to City R_i (it is possible that L_i = R_i).
Takahashi the king is interested in the following Q matters:

The number of the trains that runs strictly within the section from City p_i to City q_i, that is, the number of trains j such that p_i \leq L_j and R_j \leq q_i.

Although he is genius, this is too much data to process by himself. Find the answer for each of these Q queries to help him.

Constraints

N is an integer between 1 and 500 (inclusive).

M is an integer between 1 and 200 \ 000 (inclusive).

Q is an integer between 1 and 100 \ 000 (inclusive).

1 \leq L_i \leq R_i \leq N (1 \leq i \leq M)

1 \leq p_i \leq q_i \leq N (1 \leq i \leq Q)

Input

Input is given from Standard Input in the following format:

N M Q
L_1 R_1
L_2 R_2
:
L_M R_M
p_1 q_1
p_2 q_2
:
p_Q q_Q

Output

Print Q lines. The i-th line should contain the number of the trains that runs strictly within the section from City p_i to City q_i.

Sample Input 1

2 3 1
1 1
1 2
2 2
1 2

Sample Output 1

3

As all the trains runs within the section from City 1 to City 2, the answer to the only query is 3.

Sample Input 2

10 3 2
1 5
2 8
7 10
1 7
3 10

Sample Output 2

1
1

The first query is on the section from City 1 to 7. There is only one train that runs strictly within that section: Train 1.
The second query is on the section from City 3 to 10. There is only one train that runs strictly within that section: Train 3.

Sample Input 3

10 10 10
1 6
2 9
4 5
4 7
4 7
5 8
6 6
6 7
7 9
10 10
1 8
1 9
1 10
2 8
2 9
2 10
3 8
3 9
3 10
1 10

Sample Output 3

7
9
10
6
8
9
6
7
8
10

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Scanner;

public class Main {
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		int N = sc.nextInt();
		int M = sc.nextInt();
		int Q = sc.nextInt();
		int[] L = new int[M];
		int[] R = new int[M];
		int[] p = new int[Q];
		int[] q = new int[Q];

		int[][] LR = new int[N+1][N+1];

		for(int i=0;i<M;i++){
			L[i] = sc.nextInt();
			R[i] = sc.nextInt();
			LR[L[i]][R[i]] +=1;
		}
		for(int i=0;i<Q;i++){
			p[i] = sc.nextInt();
			q[i] = sc.nextInt();
//			pq[][]
		}
		sc.close();

		for(int x=1; x<=N; ++x){
			for(int y=1; y<=N; ++y){
				LR[x][y] += LR[x][y-1] +LR[x-1][y] -LR[x-1][y-1];
			}
		}

		for(int i=0;i<Q;i++){
			int sum = LR[q[i]][q[i]] - LR[p[i]-1][q[i]] - LR[q[i]][p[i]-1] + LR[q[i]-1][p[i]-1];
			System.out.println(sum);
		}

	}

}