Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.*;

class Main{
    public static void main(String[] args) {
        int[][] n = new int[3][3];
        int N = 0;
        boolean keisan = false;
        String kotae = "";
        Scanner sc = new Scanner(System.in);
        for (int i = 0; i < 3; i++) {
            for (int j = 0; j < 3; j++) {
                 n[i][j] = Integer.parseInt(sc.next());  
            }
        }
        N = Integer.parseInt(sc.next());
        int b[] = new int[N];
        for (int k = 0; k < N; k++) {
            b[k] = Integer.parseInt(sc.next());
            keisan = Main.search(b[k],n);
            if (keisan == true) {
                kotae = "Yes";
            } 
        }
        if (kotae == "Yes") {
            System.out.println("Yes");
        } else if (keisan == false) {
            System.out.println("No");
        }
    }

    public static boolean search(int s,int n[][]) {
        for (int i = 0; i < 3; i++) {
            for (int j = 0; j < 3; j++) {
                if (s == n[i][j]) {
                    return true;
                }
            }
        }
        return false;
    }
}