Problem:
Score : 500 points

Problem Statement

We have N bulbs arranged on a number line, numbered 1 to N from left to right.
Bulb i is at coordinate i.

Each bulb has a non-negative integer parameter called intensity.
When there is a bulb of intensity d at coordinate x, the bulb illuminates the segment from coordinate x-d-0.5 to x+d+0.5.
Initially, the intensity of Bulb i is A_i. We will now do the following operation K times in a row:

For each integer i between 1 and N (inclusive), let B_i be the number of bulbs illuminating coordinate i. Then, change the intensity of each bulb i to B_i.

Find the intensity of each bulb after the K operations.

Constraints

1 \leq N \leq 2 \times 10^5

1 \leq K \leq 2 \times 10^5

0 \leq A_i \leq N

Input

Input is given from Standard Input in the following format:

N K
A_1 A_2 \ldots A_N

Output

Print the intensity A{'}_i of each bulb i after the K operations to Standard Output in the following format:

A{'}_1 A{'}_2 \ldots A{'}_N

Sample Input 1

5 1
1 0 0 1 0

Sample Output 1

1 2 2 1 2

Initially, only Bulb 1 illuminates coordinate 1, so the intensity of Bulb 1 becomes 1 after the operation.
Similarly, the bulbs initially illuminating coordinate 2 are Bulb 1 and 2, so the intensity of Bulb 2 becomes 2.

Sample Input 2

5 2
1 0 0 1 0

Sample Output 2

3 3 4 4 3

Solution in Java (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.Scanner;

public class Main{
  public static void main(String[] args){
    Scanner sc = new Scanner(System.in);

    //input
    int numOfLamps = sc.nextInt();
    int numOfReps = sc.nextInt();
    int[] brightnessArray = new int[numOfLamps];
    for(int i = 0; i < brightnessArray.length; i++){
      brightnessArray[i] = sc.nextInt();
    }

    //output
    int realReps = numOfReps;
    if( numOfReps > (int)(Math.log(numOfLamps)/Math.log(2)) ){
      realReps = (int)(Math.log(numOfLamps)/Math.log(2));
    }
    
    for(int i = 0; i < realReps; i++){

      int[] cumulativeSumArray = new int[numOfLamps];
      for(int j = 0; j < brightnessArray.length; j++){

        int leftNum = j-brightnessArray[j];
        if( j-brightnessArray[j] < 0 ){
          leftNum = 0;
        }
        int rightNum = j+brightnessArray[j];
        if( j+brightnessArray[j] > numOfLamps ){ //if beyond the end, right side set to end
          rightNum = numOfLamps;
        }

        //upon taking the cumulative sum, code below would add 1 to all in range
        cumulativeSumArray[leftNum]++;
        if( rightNum+1 < numOfLamps ){ //if not beyond the end
          cumulativeSumArray[rightNum+1]--;
        }

      }
      //take cumulative sum
      for(int m = 1; m < cumulativeSumArray.length; m++){
        cumulativeSumArray[m] += cumulativeSumArray[m-1];
      }

      //if there is no difference, break
      if( cumulativeSumArray.equals(brightnessArray) ){
        break;
      }else{ //if there is a difference, continue
        brightnessArray = cumulativeSumArray;
      }

    }
    //print out numbers
    for(int i = 0; i < brightnessArray.length; i++){
      System.out.print(brightnessArray[i]+" ");
    }

  }
}