Problem:
Problem A: Strange String Manipulation

A linear congruential generator produces a series R(⋅) of pseudo-random numbers by the following for-
mulas:

where S, A, C, and M are all parameters. In this problem, 0 ≤ S, A, C ≤ 15 and M = 256.

Now suppose we have some input string I(⋅), where each character in the string is an integer between 0
and (M - 1). Then, using the pseudo-random number series R(⋅), we obtain another string O(⋅) as the
output by the following formula:

Your task is to write a program that shows the parameters S, A, and C such that the information entropy of the output string O(⋅) is minimized. Here, the information entropy H is given by the following formula:

where N is the length of the string and #(x) is the number of occurences of the alphabet x.

Input

The input consists of multiple datasets. Each dataset has the following format:

N

I(1) I(2) ... I(N)

N does not exceed 256.

The last dataset is followed by a line containing one zero. This line is not a part of any dataset and should not be processed.

Output

For each dataset, print in a line the values of the three parameters S, A, and C separated by a single space. If more than one solution gives the same minimum entropy, choose the solution with the smallest S, A, and then C.

Sample Input

5
5 4 3 2 1
5
7 7 7 7 7
10
186 8 42 24 154 40 10 56 122 72
0

Output for the Sample Input

0 1 1
0 0 0
8 7 14

Solution in JAVA (judge verdict: Accepted)


import java.util.*;
import java.io.*;

public class Main{
    static final Reader sc = new Reader();
    static final PrintWriter out = new PrintWriter(System.out,false);

    public static void main(String[] args) throws Exception {
    	
    	while(true){
    		int n = sc.nextInt();
    		if(n==0){
    			break;
    		}
    		double ex = 0.0000000001;
    		int s = 0;
    		int a = 0;
    		int c = 0;
    		double ans = 1000000.0;
    		int m = 256;
    		int[] l = new int[n];
    		for(int i=0;i<n;i++){
    			l[i] = sc.nextInt();
    		}
    		for(int i=0;i<=15;i++){
    			for(int j=0;j<=15;j++){
    				for(int k=0;k<=15;k++){
    					int[] count = new int[256];
    					int r = i;
    					for(int d=0;d<n;d++){
    						r = (j*r+k)%m;
    						int o = (l[d]+r)%m;
    						count[o]++;
    					}
    					double h = 0.0;
    					for(int d=0;d<256;d++){
    						if(count[d]!=0){
    							h -= (double)count[d]/(double)n*Math.log((double)count[d]/(double)n);
    						}
    					}
    					if(h+ex<ans){
    						ans = h;
    						s = i;
    						a = j;
    						c = k;
    					}
    				}
    			}
    		}
    		out.println(s+" "+a+" "+c);
    		out.flush();
    	}

        sc.close();
        out.close();
    }

    static void trace(Object... o) { System.out.println(Arrays.deepToString(o));}
}

class Reader {

    private final InputStream in;
    private final byte[] buf = new byte[1024];
    private int ptr = 0;
    private int buflen = 0;

    public Reader() { this(System.in);}
    public Reader(InputStream source) { this.in = source;}

    private boolean hasNextByte() {
        if (ptr < buflen) return true;
        ptr = 0;
        try{
            buflen = in.read(buf);
        }catch (IOException e) {e.printStackTrace();}
        if (buflen <= 0) return false;
        return true;
    }

    private int readByte() { if (hasNextByte()) return buf[ptr++]; else return -1;}

    private boolean isPrintableChar(int c) { return 33 <= c && c <= 126;}

    private void skip() { while(hasNextByte() && !isPrintableChar(buf[ptr])) ptr++;}

    public boolean hasNext() {skip(); return hasNextByte();}

    public String next() {
        if (!hasNext()) throw new NoSuchElementException();
        StringBuilder sb = new StringBuilder();
        int b = readByte();
        while (isPrintableChar(b)) {
            sb.appendCodePoint(b);
            b = readByte();
        }
        return sb.toString();
    }

    public long nextLong() {
        if (!hasNext()) throw new NoSuchElementException();
        boolean minus = false;
        long num = readByte();

        if(num == '-'){
            num = 0;
            minus = true;
        }else if (num < '0' || '9' < num){
            throw new NumberFormatException();
        }else{
            num -= '0';
        }

        while(true){
            int b = readByte();
            if('0' <= b && b <= '9')
                num = num * 10 + (b - '0');
            else if(b == -1 || !isPrintableChar(b))
                return minus ? -num : num;
            else
                throw new NoSuchElementException();
        }
    }

    public int nextInt() {
        long num = nextLong();
        if (num < Integer.MIN_VALUE || Integer.MAX_VALUE < num)
            throw new NumberFormatException();
        return (int)num;
    }

    public double nextDouble() {
        return Double.parseDouble(next());
    }

    public char nextChar() {
        if (!hasNext()) throw new NoSuchElementException();
        return (char)readByte();
    }

    public String nextLine() {
        while (hasNextByte() && (buf[ptr] == '\n' || buf[ptr] == '\r')) ptr++;
        if (!hasNextByte()) throw new NoSuchElementException();

        StringBuilder sb = new StringBuilder();
        int b = readByte();
        while (b != '\n' && b != '\r') {
            sb.appendCodePoint(b);
            b = readByte();
        }

        return sb.toString();
    }

    public int[] nextIntArray(int n) {
        int[] res = new int[n];
        for (int i=0; i<n; i++) res[i] = nextInt();
        return res;
    }

    public char[] nextCharArray(int n) {
        char[] res = new char[n];
        for (int i=0; i<n; i++) res[i] = nextChar();
        return res;
    }

    public void close() {try{ in.close();}catch(IOException e){ e.printStackTrace();}};
}