Problem:
Score : 100 points

Problem Statement

There are two buttons, one of size A and one of size B.

When you press a button of size X, you get X coins and the size of that button decreases by 1.

You will press a button twice. Here, you can press the same button twice, or press both buttons once.

At most how many coins can you get?

Constraints

All values in input are integers.

3 \leq A, B \leq 20

Input

Input is given from Standard Input in the following format:

A B

Output

Print the maximum number of coins you can get.

Sample Input 1

5 3

Sample Output 1

9

You can get 5 + 4 = 9 coins by pressing the button of size 5 twice, and this is the maximum result.

Sample Input 2

3 4

Sample Output 2

7

Sample Input 3

6 6

Sample Output 3

12

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Runtime Error)

import java.util.*;

public class Main {

	public static void main(String[] args){
		Scanner sc = new Scanner(System.in);
		int n = sc.nextInt();
		//Scanner sa = new Scanner(System.in);
		int building[] = new int[n-1]; 
		for(int i = 0;i < n ; i++){
			building[i] = sc.nextInt();
		}

		int ans =1;

		for(int j =1;j<n;j++){
			int counter=0;
			for(int k=0;k<j;k++){
				if(building[k] < building[j]){
					counter++;
				}
			}
			if(counter == j){
				ans++;
			}
		}

		System.out.println(ans);

	}
}