Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.Scanner;
public class Main{
	public static void main(String[] args) {
		Scanner sc=new Scanner(System.in);
		int N=sc.nextInt();
		int A=sc.nextInt();
		int B=sc.nextInt();
		int C=sc.nextInt();
		int D=sc.nextInt();
		String S=sc.next();
		Boolean can=true;Boolean nuku=false;
		char a1='#',a2='#',a3='.';
		int max=Math.max(C, D);
		int min=Math.min(C, D);

		for(int i=A-1;i<max;i++) {
			a1=a2;
			a2=a3;
			a3=S.charAt(i);
			if(a2=='#'&&a3=='#') {
				System.out.println("No");
				return;
			}
			if(a1=='.'&&a2=='.'&&a3=='.'&&i-1>=B) {
				nuku=true;
			}
		}
		if(C<D) {
			System.out.println("Yes");
			return;
		}
		if(nuku) {
			System.out.println("Yes");
		}else {
			System.out.print("No");
		}
	}

}