Problem:
Score : 100 points

Problem Statement

Snuke has a favorite restaurant.

The price of any meal served at the restaurant is 800 yen (the currency of Japan), and each time a customer orders 15 meals, the restaurant pays 200 yen back to the customer.

So far, Snuke has ordered N meals at the restaurant.
Let the amount of money Snuke has paid to the restaurant be x yen, and let the amount of money the restaurant has paid back to Snuke be y yen.
Find x-y.

Constraints

1 ≤ N ≤ 100

Input

The input is given from Standard Input in the following format:

N

Output

Print the answer.

Sample Input 1

20

Sample Output 1

15800

So far, Snuke has paid 16000 yen, and the restaurant has paid back 200 yen. Thus, the answer is 15800.

Sample Input 2

60

Sample Output 2

47200

Snuke has paid 48000 yen for 60 meals, and the restaurant has paid back 800 yen.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		long a = Long.parseLong(sc.next());
//		String t = sc.next();
//		String buff="";
		//long b = Long.parseLong(sc.next());
		//int c = Integer.parseInt(sc.next());
		//int n = Integer.parseInt(sc.next());
		//long res=n;
		//int l = Integer.parseInt(sc.next());
		//int sum=0;
		//String s = sc.next();
		//String t = sc.next();
		//String b = sc.next();
		//int a = Integer.parseInt(sc.next());
		//String t = sc.next();

		/*if(a==b) {//a、e、i、o、u
			System.out.println("Draw");
		}else if(a==1){
			System.out.println("Alice");
		}*/
		/*for(int i=0;i<t.length();i++) {
			if(t.substring(i,i+1).equals(",")) {
				buff+=" ";
			}else {
				buff+=t.substring(i, i+1);
			}
		}*/
		System.out.println(a*800-(a%15)*200);
	}
}