Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Java (OpenJDK 11.0.6) (judge verdict: Wrong Answer)

import java.util.*;
public class Main{
  	public static void main (String [] args){
     	Scanner sc = new Scanner (System.in);
      	int N = sc.nextInt();
      	int count = 0;
      	for (int i = 0; i < N; i++){
          	if (i%2 != 0){
          		int factorCount = 0;
              	for (int j = 1; j <= i; j++){
                  	if (i%j==0) factorCount++;
                }
              	if (factorCount == 8) count++;
            }
        }
      	System.out.println(count);
    }
}