Problem:
Score : 300 points

Problem Statement

You are given two integer sequences of length N: a_1,a_2,..,a_N and b_1,b_2,..,b_N.
Determine if we can repeat the following operation zero or more times so that the sequences a and b become equal.

Operation: Choose two integers i and j (possibly the same) between 1 and N (inclusive), then perform the following two actions simultaneously:

Add 2 to a_i.

Add 1 to b_j.

Constraints

1 ≤ N ≤ 10 000

0 ≤ a_i,b_i ≤ 10^9 (1 ≤ i ≤ N)

All input values are integers.

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 .. a_N
b_1 b_2 .. b_N

Output

If we can repeat the operation zero or more times so that the sequences a and b become equal, print Yes; otherwise, print No.

Sample Input 1

3
1 2 3
5 2 2

Sample Output 1

Yes

For example, we can perform three operations as follows to do our job:

First operation: i=1 and j=2. Now we have a = \{3,2,3\}, b = \{5,3,2\}.

Second operation: i=1 and j=2. Now we have a = \{5,2,3\}, b = \{5,4,2\}.

Third operation: i=2 and j=3. Now we have a = \{5,4,3\}, b = \{5,4,3\}.

Sample Input 2

5
3 1 4 1 5
2 7 1 8 2

Sample Output 2

No

Sample Input 3

5
2 7 1 8 2
3 1 4 1 5

Sample Output 3

No

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.Scanner;

/**
 * Built using CHelper plug-in
 * Actual solution is at the top
 */
public class Main {
    public static void main(String[] args) {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        Scanner in = new Scanner(inputStream);
        PrintWriter out = new PrintWriter(outputStream);
        APC001B solver = new APC001B();
        solver.solve(1, in, out);
        out.close();
    }

    static class APC001B {
        public void solve(int testNumber, Scanner in, PrintWriter out) {
            int n = in.nextInt();
            long aSum = 0;
            long bSum = 0;
            long bOver = 0;
            int[] a = new int[n];
            int[] b = new int[n];
            for (int i = 0; i < n; i++) {
                a[i] = in.nextInt();
                aSum += a[i];
            }
            for (int i = 0; i < n; i++) {
                b[i] = in.nextInt();
                bSum += b[i];
                if (b[i] < a[i]) bOver += a[i] - b[i];
            }

            if (aSum > bSum) {
                out.println("No");
                return;
            }

            long count = bSum - aSum;

            if (count % 2 == 0) out.println("No");
            else out.println("Yes");

        /*int filled = 0;
        long countA = count;

        while(countA > 0) {
            if(filled < n) {
                if (a[filled] < b[filled]) {
                    a[filled] += 2;
                    countA--;
                } else {
                    filled++;
                }
            }else{
                a[0] += 2;
                countA--;
            }
        }

        filled = 0;
        while(count > 0) {
            if(filled < n) {
                if (b[filled] < a[filled]) {
                    b[filled] += 1;
                    count--;
                } else {
                    filled++;
                }
            }else{
                b[0] += 1;
                count--;
            }
        }

        for(int i = 0; i < n; i++){
            if(a[i] != b[i]){
                out.println("No");
                return;
            }
        }
        out.println("Yes");*/
        }

    }
}