Problem:
Score : 200 points

Problem Statement

Tak performed the following action N times: rolling two dice.
The result of the i-th roll is D_{i,1} and D_{i,2}.

Check if doublets occurred at least three times in a row.
Specifically, check if there exists at lease one i such that D_{i,1}=D_{i,2}, D_{i+1,1}=D_{i+1,2} and D_{i+2,1}=D_{i+2,2} hold.

Constraints

3 \leq N \leq 100

1\leq D_{i,j} \leq 6

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
D_{1,1} D_{1,2}
\vdots
D_{N,1} D_{N,2}

Output

Print Yes if doublets occurred at least three times in a row. Print No otherwise.

Sample Input 1

5
1 2
6 6
4 4
3 3
3 2

Sample Output 1

Yes

From the second roll to the fourth roll, three doublets occurred in a row.

Sample Input 2

5
1 1
2 2
3 4
5 5
6 6

Sample Output 2

No

Sample Input 3

6
1 1
2 2
3 3
4 4
5 5
6 6

Sample Output 3

Yes

Solution in Java (OpenJDK 11.0.6) (judge verdict: Wrong Answer)

import java.io.*;
import java.util.*;


public class Main{
	
	public static void main(String[] args){
	
	MyScanner sc = new MyScanner();
	out = new PrintWriter(new BufferedOutputStream(System.out));
	
	/**/
	
	int numberOfRolls = sc.nextInt();
	
	int[][] array = new int[numberOfRolls][2];
	
	for(int i = 0; i < numberOfRolls; i++){
		
		array[i][0] = sc.nextInt();
		array[i][1] = sc.nextInt();
		
	}
	
	for(int i = 0; i <= array.length - 3; i++){
		System.out.println(i);
		if(array[i][0] == array[i][1] && array[i+1][0] == array[i+1][1] && array[i+2][0] == array[i+2][1]){
			System.out.println("Yes");
			return;
		}
	
		
		
	}
	
	System.out.println("No");
	
	/**/
	 
	 out.close();	
	}
	
	public static PrintWriter out;
	
	public static class MyScanner{
		
		BufferedReader br;
		StringTokenizer st;
		
		public MyScanner(){
			br = new BufferedReader(new InputStreamReader(System.in));
		}
		
		String next() {
          while (st == null || !st.hasMoreElements()) {
              try {
                  st = new StringTokenizer(br.readLine());
              } catch (IOException e) {
                  e.printStackTrace();
              }
          }
          return st.nextToken();
      }
 
      int nextInt() {
          return Integer.parseInt(next());
      }
 
      long nextLong() {
          return Long.parseLong(next());
      }
 
      double nextDouble() {
          return Double.parseDouble(next());
      }
 
      String nextLine(){
          String str = "";
	  try {
	     str = br.readLine();
	  } catch (IOException e) {
	     e.printStackTrace();
	  }
	  return str;
      }

   }
	
}