Problem:
Score : 200 points

Problem Statement

A string is called a KEYENCE string when it can be changed to keyence by removing its contiguous substring (possibly empty) only once.

Given a string S consisting of lowercase English letters, determine if S is a KEYENCE string.

Constraints

The length of S is between 7 and 100 (inclusive).

S consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S

Output

If S is a KEYENCE string, print YES; otherwise, print NO.

Sample Input 1

keyofscience

Sample Output 1

YES

keyence is an abbreviation of key of science.

Sample Input 2

mpyszsbznf

Sample Output 2

NO

Sample Input 3

ashlfyha

Sample Output 3

NO

Sample Input 4

keyence

Sample Output 4

YES

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Runtime Error)

import java.util.*;
public class Main {
    public static void main(String[] args){
        Scanner sc = new Scanner(System.in);
        String S = sc.nextLine();
        String Sol = "keyence";
        ArrayList<Character> S_List = new ArrayList<>();
        ArrayList<Character> Solution = new ArrayList<>();
        for(int a=0;a<S.length();a++) S_List.add(S.charAt(a));
        for(int a=0;a<Sol.length();a++) Solution.add(Sol.charAt(a));
        int check=0;
        for(int a=0;a<Solution.size();a++) if(S_List.contains(Solution.get(a))==true) check++;
        if(check!=Solution.size()) System.out.println("NO");
        else{
            int num=0;
            ArrayList<Integer> List = new ArrayList<>();
            for(int a=0;a<S_List.size();a++){
             if(S_List.get(a)==Solution.get(num)){
                 List.add(num);
                if(num<=6) num++;
             }
             else List.add(8);
            }
            int check_num=0;
            for(int a=0;a<List.size()-1;a++){
                if(List.get(a)==8&&List.get(a+1)<7)check_num++;
                else if(List.get(a)<7&&List.get(a+1)==8)check_num++;
            }
            if(check_num<=2) System.out.println("YES");
            else System.out.println("NO");
        }
    }
}