Problem:
Score : 100 points

Problem Statement

We have two integers: A and B.

Print the largest number among A + B, A - B, and A \times B.

Constraints

All values in input are integers.

-100 \leq A,\ B \leq 100

Input

Input is given from Standard Input in the following format:

A B

Output

Print the largest number among A + B, A - B, and A \times B.

Sample Input 1

-13 3

Sample Output 1

-10

The largest number among A + B = -10, A - B = -16, and A \times B = -39 is -10.

Sample Input 2

1 -33

Sample Output 2

34

The largest number among A + B = -32, A - B = 34, and A \times B = -33 is 34.

Sample Input 3

13 3

Sample Output 3

39

The largest number among A + B = 16, A - B = 10, and A \times B = 39 is 39.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Runtime Error)

import java.util.*;

public class Main {
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		int n = sc.nextInt();
		sc.nextLine();
		String[] arr = new String[n+1];
		for(int i = 0; i < n; i++) {
			arr[i] = sc.nextLine();
			char temparr[] = arr[i].toCharArray();
			Arrays.sort(temparr);
			arr[i] = new String(temparr);
		}
		arr[n] = "zzzzzzzzzzzzz";
		Arrays.sort(arr);
//		System.out.println(Arrays.toString(arr));
		long ans = 0;
		long freq = 1;
		for(int i = 0; i < n; i++) {
				if (arr[i].equals(arr[i + 1])) {
//					System.out.println("cnt");
					freq += 1;
				}
				else if (freq == 1) {
					continue;
				}
				else {
					ans += freq*(freq - 1)/2;
					freq = 1;
				}
		}
		System.out.println(ans);
	}
}