Problem:
Score : 400 points

Problem Statement

We have N balls. The i-th ball has an integer A_i written on it.

For each k=1, 2, ..., N, solve the following problem and print the answer.

Find the number of ways to choose two distinct balls (disregarding order) from the N-1 balls other than the k-th ball so that the integers written on them are equal.

Constraints

3 \leq N \leq 2 \times 10^5

1 \leq A_i \leq N

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

For each k=1,2,...,N, print a line containing the answer.

Sample Input 1

5
1 1 2 1 2

Sample Output 1

2
2
3
2
3

Consider the case k=1 for example. The numbers written on the remaining balls are 1,2,1,2.

From these balls, there are two ways to choose two distinct balls so that the integers written on them are equal.

Thus, the answer for k=1 is 2.

Sample Input 2

4
1 2 3 4

Sample Output 2

0
0
0
0

No two balls have equal numbers written on them.

Sample Input 3

5
3 3 3 3 3

Sample Output 3

6
6
6
6
6

Any two balls have equal numbers written on them.

Sample Input 4

8
1 2 1 4 2 1 4 1

Sample Output 4

5
7
5
7
7
5
7
5

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.*;


public class Main {

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		int num = sc.nextInt();
		List<Integer> integerList = getStrings(sc, num);
		HashMap<Integer, CalResult> map = new HashMap<Integer, CalResult>();

		long countSize = integerList.stream().distinct().count();
		if (countSize == 1) {
			for (int i = 0; i < integerList.size(); i++) {
				System.out.println((integerList.size() - 1) * (integerList.size() - 2) / 2);
			}
			return;
		} else if (countSize == integerList.size()) {
			for (int i = 0; i < integerList.size(); i++) {
				System.out.println(0);
			}
			return;
		}

		for (int i = 0; i < integerList.size(); i++) {
			int a = integerList.get(i);
			if (!map.containsKey(a)) {
				CalResult c = new CalResult();
				c.setCount(1);
				map.put(a, c);
			} else {
				CalResult c = map.get(a);
				int b = c.getCount();
				c.setCount(b+1);
				map.put(a, c);
			}
		}

		for (Map.Entry<Integer, CalResult> entry : map.entrySet()) {
			CalResult c = entry.getValue();
			int count = c.getCount();
			c.setWithCount(count>1 ? (count*(count-1))/2 : 0);
			c.setWithoutCount(count>2 ? ((count-1)*(count-2))/2 : 0);
		}

		for (int i = 0; i < integerList.size(); i++) {
			int sum =0;
			for (Map.Entry<Integer, CalResult> entry : map.entrySet()) {
				if (entry.getKey().equals(integerList.get(i))) {
					sum += entry.getValue().getWithoutCount();
				} else {
					sum += entry.getValue().getWithCount();
				}
			}
			System.out.println(sum);
		}

	}

	static class CalResult {
		int count;
		long withCount;
		long withoutCount;

		public CalResult() {}

		public int getCount() {
			return count;
		}

		public void setCount(int count) {
			this.count = count;
		}

		public long getWithCount() {
			return withCount;
		}

		public void setWithCount(int withCount) {
			this.withCount = withCount;
		}

		public long getWithoutCount() {
			return withoutCount;
		}

		public void setWithoutCount(int withoutCount) {
			this.withoutCount = withoutCount;
		}
	}

	private static List<Integer> getStrings(Scanner sc, int num) {
		List<Integer> integerList = new ArrayList<>();
		while(num>0) {
			int i = sc.nextInt();
			integerList.add(i);
			num--;
		}
		return integerList;
	}

}