Problem:
Score : 200 points

Problem Statement

Given is an integer N. Find the number of digits that N has in base K.

Notes

For information on base-K representation, see Positional notation - Wikipedia.

Constraints

All values in input are integers.

1 \leq N \leq 10^9

2 \leq K \leq 10

Input

Input is given from Standard Input in the following format:

N K

Output

Print the number of digits that N has in base K.

Sample Input 1

11 2

Sample Output 1

4

In binary, 11 is represented as 1011.

Sample Input 2

1010101 10

Sample Output 2

7

Sample Input 3

314159265 3

Sample Output 3

18

Solution in Java (OpenJDK 11.0.6) (judge verdict: Accepted)

import java.util.LinkedList;
import java.util.List;
import java.util.Scanner;

public class Main{
	public static void main(String[] args) {

		Scanner scanner = new Scanner(System.in);

		String[] tmp = scanner.nextLine().split(" ");
		int n = Integer.parseInt(tmp[0]);
		int k = Integer.parseInt(tmp[1]);
		List<Character> list = new LinkedList<Character>();

		while(n > 0) {

			list.add((char) (n % k));
			n /= k;

		}



		System.out.println(list.size());

	}
}