Problem:
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Matrix Multiplication

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\[
c_{ij} = \sum_{k=1}^m a_{ik}b_{kj}
\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Constraints

$1 \leq n, m, l \leq 100$

$0 \leq a_{ij}, b_{ij} \leq 10000$

Sample Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2

Sample Output

1 8 5
0 9 6
4 23 14

Note

      解説

Solution in JAVA (judge verdict: Wrong Answer)

import java.util.Scanner;

public class Main {
	void run() {
		Scanner scan = new Scanner(System.in);
		int n = scan.nextInt();
		int m = scan.nextInt();
		int l = scan.nextInt();
		long[][] a = new long[n][];
		for (int i = 0; i < n; i++) {
			a[i] = new long[m];
			for (int j = 0; j < m; j++) {
				a[i][j] = scan.nextInt();
			}
		}
		long[][] b = new long[m][];
		for (int i = 0; i < m; i++) {
			b[i] = new long[l];
			for (int j = 0; j < l; j++) {
				b[i][j] = scan.nextInt();
			}
		}
		for (int i = 0; i < n; i++) {
			for (int j = 0; j < l; j++) {
				int c = 0;
				for (int k = 0; k < m; k++) {
					c += a[i][k] * b[k][j];
				}
				if (j == 0) {
					System.out.print(c);
				} else System.out.print(" " + c);
			}
			System.out.println();
		}
	}
	public static void main(String[] args) {
		new Main().run();
	}
}