Problem:
Score : 100 points

Problem Statement

In AtCoder City, there are three stations numbered 1, 2, and 3.

Each of these stations is operated by one of the two railway companies, A and B. A string S of length 3 represents which company operates each station. If S_i is A, Company A operates Station i; if S_i is B, Company B operates Station i.

To improve the transportation condition, for each pair of a station operated by Company A and one operated by Company B, there will be a bus service connecting them.

Determine if there is a pair of stations that will be connected by a bus service.

Constraints

Each character of S is A or B.

|S| = 3

Input

Input is given from Standard Input in the following format:

S

Output

If there is a pair of stations that will be connected by a bus service, print Yes; otherwise, print No.

Sample Input 1

ABA

Sample Output 1

Yes

Company A operates Station 1 and 3, while Company B operates Station 2.

There will be a bus service between Station 1 and 2, and between Station 2 and 3, so print Yes.

Sample Input 2

BBA

Sample Output 2

Yes

Company B operates Station 1 and 2, while Company A operates Station 3.

There will be a bus service between Station 1 and 3, and between Station 2 and 3, so print Yes.

Sample Input 3

BBB

Sample Output 3

No

Company B operates all the stations. Thus, there will be no bus service, so print No.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Runtime Error)

import java.io.*;
import java.util.*;
import java.lang.String;
import java.util.Arrays;

import static java.lang.Integer.min;
import static java.lang.Integer.parseInt;

public class Main extends PrintWriter {
    Main() { super(System.out, true); }
    Scanner sc = new Scanner(System.in);
    public static void main(String[] $) {
        Main o = new Main(); o.main(); o.flush();
    }

    void main(){

        char []A = new char[3];
        for(int i = 0; i < 3; i++){
            A[i] = sc.next().charAt(i);
        }
        if(A[0] == A[1] && A[1] == A[2]){
            print("Yes");
        }
        else
        {
            print("No");
        }


    }
}