Problem:
Score : 200 points

Problem Statement

There are N positive integers written on a blackboard: A_1, ..., A_N.

Snuke can perform the following operation when all integers on the blackboard are even:

Replace each integer X on the blackboard by X divided by 2.

Find the maximum possible number of operations that Snuke can perform.

Constraints

1 \leq N \leq 200

1 \leq A_i \leq 10^9

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

Print the maximum possible number of operations that Snuke can perform.

Sample Input 1

3
8 12 40

Sample Output 1

2

Initially, [8, 12, 40] are written on the blackboard.
Since all those integers are even, Snuke can perform the operation.

After the operation is performed once, [4, 6, 20] are written on the blackboard.
Since all those integers are again even, he can perform the operation.

After the operation is performed twice, [2, 3, 10] are written on the blackboard.
Now, there is an odd number 3 on the blackboard, so he cannot perform the operation any more.

Thus, Snuke can perform the operation at most twice.

Sample Input 2

4
5 6 8 10

Sample Output 2

0

Since there is an odd number 5 on the blackboard already in the beginning, Snuke cannot perform the operation at all.

Sample Input 3

6
382253568 723152896 37802240 379425024 404894720 471526144

Sample Output 3

8

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Scanner;
public class Main{
  public static void main(String [] args){
    Scanner stdIn = new Scanner(System.in);
   /* int n = stdIn.nextInt();
    int [] Array = new int[n];
    
    for(int i = 0; i < Array.length; i++) {
    	Array[i] = stdIn.nextInt();
    }
    
    int sum = 0;
    int a = 0;
    Outer:
    do{
      a++;
    	for(int i = 0; i < Array.length; i++){
      		if(Array[i]%2!=0) break Outer;
      		else Array[i]/=2;
      		if(i==n-1){ 
              sum++;
              a --;
            }
    	}
    }while(a==0);
    
    System.out.println(sum);*/
    int n = stdIn.nextInt();
    int[]a = new int[n];
    for(int i = 0; i < n; i++) {
    	a[i] = stdIn.nextInt();
    }
    
    int cnt = 0;
    
    Outer:while(true) {
    	for(int i = 0; i < n; i++) {
    		if(a[i]%2!=0){
    			break Outer;
    		}
    		a[i]/=2;
    	}
    	cnt++;
    	
    	
    }
    
    System.out.println(cnt);
    
    
    
  }
}