Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Accepted)

import java.util.Scanner;

public class Main {
	public static void main(String[] args) {
		char chLow = 'a';
		char chUpp = 'A';

		StringBuilder sb = new StringBuilder();
		Scanner sc = new Scanner(System.in);

		while (sc.hasNextLine()) {
			sb.append(sc.nextLine());
		}

		char[]car  = sb.toString().toCharArray();

		int count;
		for(int i = 0; i < 26;i++) {
			count=0;
			for(int j = 0;j<car.length;j++) {
				if(car[j]==chLow || car[j]==chUpp) {
					count++;
				}
			}
			System.out.println(chLow +" : "+count);
			chLow+=1;
			chUpp+=1;
		}

	}
}