Problem:
Simultaneous Equation

Write a program which solve a simultaneous equation:

ax + by = c

dx + ey = f

The program should print x and y for given a, b, c, d, e and f (-1,000 ≤ a, b, c, d, e, f ≤ 1,000). You can suppose that given equation has a unique solution.

Input

The input consists of several data sets, 1 line for each data set. In a data set, there will be a, b, c, d, e, f separated by a single space. The input terminates with EOF.

Output

For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.

Sample Input 1

1 2 3 4 5 6
2 -1 -2 -1 -1 -5

Output for the Sample Input 1

-1.000 2.000
1.000 4.000

Sample Input 2

2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27

Output for the Sample Input 2

0.000 3.000
0.000 3.000

Solution in JAVA (judge verdict: Accepted)

import java.io.*;
class Main{

    public static void main(String[] args)throws IOException{
	BufferedReader br =
	    new BufferedReader(new  InputStreamReader(System.in));
	String buf;
	double[][] data=new double[2][3];
	double x,y;
	while(true){
	    buf=br.readLine();
	    if(buf==null) break;
	    if(buf.length()==0)break;
	    String[] buf2=buf.split(" ");
	    for(int i=0;i<data.length;i++){
		for(int j=0;j<data[i].length;j++){
		    data[i][j]=Double.parseDouble(buf2[i*3+j]);
		}
	    }
	    double a,b,c,d;
	    a=(data[0][2] * data[1][1] - data[0][1] * data[1][2]);
	    b=(data[0][0] * data[1][1] - data[1][0] * data[0][1]);
	    c=(data[0][2] * data[1][0] - data[1][2] * data[0][0]);
	    d=(data[0][1] * data[1][0] - data[0][0] * data[1][1]);
	    x = a / b;
	    y = c / d;
	    if(x==-0)x=0;if(y==-0)y=0;
	    System.out.print(String.format("%.3f",x));
	    System.out.print(" ");
	    System.out.println(String.format("%.3f",y));
	}
    }
}