Problem:
Search II

You are given a sequence of n integers S and a sequence of different q integers T. Write a program which outputs C, the number of integers in T which are also in the set S.

Input

In the first line n is given. In the second line, n integers are given. In the third line q is given. Then, in the fourth line, q integers are given.

Output

Print C in a line.

Constraints

Elements in S is sorted in ascending order

n ≤ 100000

q ≤ 50000

0 ≤ an element in S ≤ 109

0 ≤ an element in T ≤ 109

Sample Input 1

5
1 2 3 4 5
3
3 4 1

Sample Output 1

3

Sample Input 2

3
1 2 3
1
5

Sample Output 2

0

Sample Input 3

5
1 1 2 2 3
2
1 2

Sample Output 3

2

Notes

Solution in JAVA (judge verdict: Wrong Answer)

import java.util.*;

class Main {
	//?????¢??¢?´¢?????¬???
	public static boolean search(int[] A, int n, int key) {
		A[n] = key;
		int i = 0;
		while(A[i] != key)i++;
		return i != n;
	}
	
	public static boolean binarySearch(int[] A, int n, int key) {
		int left = 0;
		int right = n-1;
		int mid = 0;
		while(left < right) {
			 mid = (left + right) / 2;
			if ( key == A[mid] ) return true;
			if ( key > A[mid] ) left = mid + 1;
			if ( key < A[mid] ) right = mid;
		}
	return false;
	}

	public static void main(String args[]) {

		Scanner scan = new Scanner(System.in);
		int[] arrayS = new int[10001]; //??°???S
		int[] arrayT = new int[501];   //??°???T
		int count = 0;						 //?????°????¨???????????????°

		//????´??????°???????????????ArrayS?????°???S???????????????
		int sNum = scan.nextInt();
		for (int i = 0; i < sNum; i++)
			arrayS[i] = scan.nextInt();

		//????´??????°???????????????ArrayT?????°???T???????????????
		int tNum = scan.nextInt();
		for (int j = 0; j < tNum; j++)
			arrayT[j] = scan.nextInt();

		//??°???T???????´??????°???A????????????????????????????????????
		for (int j = 0; j < tNum; j++)
			if(binarySearch(arrayS, sNum, arrayT[j])) count++;

		System.out.println(count);
	}
}