Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Accepted)

import java.util.Scanner;

class Main {

    public static void main(String[] args) {
        int[] alphabets = new int[26];

        Scanner sc = new Scanner(System.in);

        try {
            while (true) {
                String line = sc.nextLine();

                char[] cs = line.toLowerCase().toCharArray();

                // aを0とする

                for (int i = 0; i < cs.length; i++) {
                    if (cs[i] >= 'a' && cs[i] <= 'z') {
                        alphabets[cs[i] - 'a']++;
                    }
                }
            }
        } catch (java.util.NoSuchElementException e) {
            for (int i = 0; i < 26; i++) {
                char a = (char) ('a' + i);
                System.out.println(a + " : " + alphabets[i]);
            }

        }

    }

}