Problem:
Reverse

Write a program which reads a sequence of integers $A = \{a_0, a_1, ..., a_{n-1}\}$ and reverse specified elements by a list of the following operation:

reverse($b, e$): reverse the order of $a_b, a_{b+1}, ..., a_{e-1}$

Input

The input is given in the following format.

$n$
$a_0 \; a_1 \; ...,\; a_{n-1}$
$q$
$b_1 \; e_1$
$b_2 \; e_2$
:
$b_{q} \; b_{q}$

In the first line, $n$ (the number of elements in $A$) is given. In the second line, $a_i$ (each element in $A$) are given. In the third line, the number of queries $q$ is given and each query is given by two integers $b_i \; e_i$ in the following $q$ lines.

Output

Print all elements of $A$ in a line after performing the given operations. Put a single space character between adjacency elements and a newline at the end of the last element.

Constraints

$1 \leq n \leq 1,000$

$-1,000,000,000 \leq a_i \leq 1,000,000,000$

$1 \leq q \leq 1,000$

$0 \leq b < e \leq n$

Sample Input 1

8
1 2 3 4 5 6 7 8
2
1 6
3 8

Sample Output 1

1 6 5 8 7 2 3 4

Solution in JAVA (judge verdict: Accepted)

import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collections;
import java.util.HashSet;
import java.util.List;
import java.util.Scanner;
import java.util.TreeMap;
import java.util.stream.Collectors;
import java.util.stream.IntStream;

public class Main {
    public static void main(String[] args) {
        try(Scanner sc = new Scanner(System.in)) {
            List<Integer> a =  IntStream.range(0, sc.nextInt()).mapToObj(x->sc.nextInt()).collect(Collectors.toList());
            int q = sc.nextInt();
            for(int i = 0; i < q; i++) {
                int b = sc.nextInt();
                int e = sc.nextInt();            	
                List<Integer> sub = a.subList(b, e);
                Collections.reverse(sub);
                for(int j = b; j < e; j++) {
                	a.set(j, sub.get(j-b));
                }
            }
            System.out.println(String.join(" ", a.stream().map(String::valueOf).toArray(String[]::new)));
        }
    }
}