Problem:
Score : 300 points

Problem Statement

There are N people living on a number line.

The i-th person lives at coordinate X_i.

You are going to hold a meeting that all N people have to attend.

The meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.

Find the minimum total points of stamina the N people have to spend.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq X_i \leq 100

Input

Input is given from Standard Input in the following format:

N
X_1 X_2 ... X_N

Output

Print the minimum total stamina the N people have to spend.

Sample Input 1

2
1 4

Sample Output 1

5

Assume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.

Note that you can hold the meeting only at an integer coordinate.

Sample Input 2

7
14 14 2 13 56 2 37

Sample Output 2

2354

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Scanner;
class Main
    {
        public static void main(String []args)
        {
            Scanner scan = new Scanner(System.in);
            int N = scan.nextInt();
            int arr[] = new int[N];
            for(int i = 0;i<N;i++)
            {
                arr[i] = scan.nextInt();
            }
            int sum = 0;
            for(int i =0;i<N;i++)
            {
                sum  += arr[i];
            }
            int a = sum/N;
            int b = a+1;
            int aa = 0;
            int bb = 0;
            for(int i =0;i<N;i++)
            {
                aa += (a-arr[i])*(a-arr[i]);
                bb += (b-arr[i])*(b-arr[i]);
            }
            int ans;
            if(aa<bb)
            {
                ans =  aa;
            }
            else
            {
                ans = bb;
            }
            System.out.println(ans);
        }
    }