Problem:
Selection Sort

Write a program of the Selection Sort algorithm which sorts a sequence A in ascending order. The algorithm should be based on the following pseudocode:

SelectionSort(A)
1 for i = 0 to A.length-1
2 mini = i
3 for j = i to A.length-1
4 if A[j] < A[mini]
5 mini = j
6 swap A[i] and A[mini]

Note that, indices for array elements are based on 0-origin.

Your program should also print the number of swap operations defined in line 6 of the pseudocode in the case where i ≠ mini.

Input

The first line of the input includes an integer N, the number of elements in the sequence.

In the second line, N elements of the sequence are given separated by space characters.

Output

The output consists of 2 lines.

In the first line, please print the sorted sequence. Two contiguous elements of the sequence should be separated by a space character.

In the second line, please print the number of swap operations.

Constraints

1 ≤ N ≤ 100

Sample Input 1

6
5 6 4 2 1 3

Sample Output 1

1 2 3 4 5 6
4

Sample Input 2

6
5 2 4 6 1 3

Sample Output 2

1 2 3 4 5 6
3

Solution in JAVA (judge verdict: Accepted)

import java.util.Arrays;
import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
			Scanner scanner = new Scanner(System.in);
			int n = scanner.nextInt();
			int A[] = new int[n];
			for(int i = 0; i < n; i++) {
				A[i] = scanner.nextInt();
			}

			scanner.close();
			int changeCount = 0;

			//選択ソート
			for(int i = 0; i < A.length; i++) {
				int minIndex = i;
				for(int j = i; j < A.length; j++) {
					if(A[minIndex] > A[j]) {
						minIndex = j;
					}
				}
			//最小値が変わっていなければ値交換はしなくてよい
			if(minIndex == i) continue;
			//値交換
			int tmp = A[i];
			A[i] = A[minIndex];
			A[minIndex] = tmp;
			changeCount++;
			}
			System.out.println(Arrays.toString(A).replaceAll("[,\\[\\]]", ""));
			System.out.println(changeCount);
	 }
}