Problem:
Score : 300 points

Problem Statement

You are given an integer sequence of length n, a_1, ..., a_n.
Let us consider performing the following n operations on an empty sequence b.

The i-th operation is as follows:

Append a_i to the end of b.

Reverse the order of the elements in b.

Find the sequence b obtained after these n operations.

Constraints

1 \leq n \leq 2\times 10^5

0 \leq a_i \leq 10^9

n and a_i are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print n integers in a line with spaces in between.
The i-th integer should be b_i.

Sample Input 1

4
1 2 3 4

Sample Output 1

4 2 1 3

After step 1 of the first operation, b becomes: 1.

After step 2 of the first operation, b becomes: 1.

After step 1 of the second operation, b becomes: 1, 2.

After step 2 of the second operation, b becomes: 2, 1.

After step 1 of the third operation, b becomes: 2, 1, 3.

After step 2 of the third operation, b becomes: 3, 1, 2.

After step 1 of the fourth operation, b becomes: 3, 1, 2, 4.

After step 2 of the fourth operation, b becomes: 4, 2, 1, 3.

Thus, the answer is 4 2 1 3.

Sample Input 2

3
1 2 3

Sample Output 2

3 1 2

As shown above in Sample Output 1, b becomes 3, 1, 2 after step 2 of the third operation. Thus, the answer is 3 1 2.

Sample Input 3

1
1000000000

Sample Output 3

1000000000

Sample Input 4

6
0 6 7 6 7 0

Sample Output 4

0 6 6 0 7 7

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Arrays;
import java.util.Scanner;
import java.util.stream.Collectors;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);

        int n = sc.nextInt();
        int[] a = new int[n];
        for (int i = 0; i < a.length; ++i) {
            a[i] = sc.nextInt();
        }

        System.out.println(solve(a));

        sc.close();
    }

    static String solve(int[] a) {
        int[] result = new int[a.length];
        int leftIndex;
        int rightIndex;
        boolean leftOrRight;
        if (a.length % 2 == 0) {
            leftIndex = a.length / 2 - 1;
            rightIndex = a.length / 2;
            leftOrRight = false;
        } else {
            leftIndex = a.length / 2;
            rightIndex = a.length / 2 + 1;
            leftOrRight = true;
        }

        for (int i = 0; i < a.length; ++i) {
            if (leftOrRight) {
                result[leftIndex] = a[i];
                --leftIndex;
            } else {
                result[rightIndex] = a[i];
                ++rightIndex;
            }

            leftOrRight = !leftOrRight;
        }

        return Arrays.stream(result).mapToObj(String::valueOf).collect(Collectors.joining(" "));
    }
}