Problem:
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Matrix Multiplication

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\[
c_{ij} = \sum_{k=1}^m a_{ik}b_{kj}
\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Constraints

$1 \leq n, m, l \leq 100$

$0 \leq a_{ij}, b_{ij} \leq 10000$

Sample Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2

Sample Output

1 8 5
0 9 6
4 23 14

Note

      解説

Solution in JAVA (judge verdict: Accepted)


import java.util.Scanner;

public class Main {
	public static void main(String[] args) {
		Scanner scanner = new Scanner(System.in);
		int a = scanner.nextInt();
		int b = scanner.nextInt();
		int c = scanner.nextInt();

		int[][] list1 = new int[a][b];
		for (int i = 0; i < a; i++) {
			for (int j = 0; j < b; j++) {
				list1[i][j] = scanner.nextInt();
			}
		}
		int[][] list2 = new int[b][c];
		for (int i = 0; i < b; i++)
			for (int j = 0; j < c; j++)
				list2[i][j] = scanner.nextInt();

		for (int i = 0; i < a; i++) {
			for (int j = 0; j < c; j++) {
				long sum = 0;
				for (int k = 0; k < b; k++) {
					sum += list1[i][k] * list2[k][j];
				}
				if (j == 0)
					System.out.print(sum);
				else
					System.out.print(" " + sum);
			}
			System.out.println();
		}

	}
}