Problem:
Simultaneous Equation

Write a program which solve a simultaneous equation:

ax + by = c

dx + ey = f

The program should print x and y for given a, b, c, d, e and f (-1,000 ≤ a, b, c, d, e, f ≤ 1,000). You can suppose that given equation has a unique solution.

Input

The input consists of several data sets, 1 line for each data set. In a data set, there will be a, b, c, d, e, f separated by a single space. The input terminates with EOF.

Output

For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.

Sample Input 1

1 2 3 4 5 6
2 -1 -2 -1 -1 -5

Output for the Sample Input 1

-1.000 2.000
1.000 4.000

Sample Input 2

2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27

Output for the Sample Input 2

0.000 3.000
0.000 3.000

Solution in JAVA (judge verdict: Accepted)

import java.util.Scanner;

class Main{
    public static void main(String[] args){
    	Scanner scan = new Scanner(System.in);
    	
    	int[] coefX = new int[2];
    	int[] coefY = new int[2];
    	int[] num = new int[2];
    	double resultX = 0;
    	double resultY = 0;
    	while(scan.hasNextInt()){
    		for(int i = 0; i < 2; i++){
        		coefX[i] = scan.nextInt();
    			coefY[i] = scan.nextInt();
    			num[i] = scan.nextInt();
    		}
    		
    		resultX = (double) (num[0]*coefY[1] - coefY[0]*num[1]) / (coefX[0]*coefY[1] - coefY[0]*coefX[1]);
    		resultY = (double) (num[0]*coefX[1] - coefX[0]*num[1]) / (coefY[0]*coefX[1] - coefX[0]*coefY[1]);
    		if(resultX == -0.000){
    			resultX = 0.000;
    		}
    		if(resultY == -0.000){
    			resultY = 0.000;
    		}
    		System.out.printf("%.3f %.3f\n",resultX, resultY);
    	}
    }
}