Problem:
Score : 200 points

Problem Statement

There are N gems. The value of the i-th gem is V_i.

You will choose some of these gems, possibly all or none, and get them.

However, you need to pay a cost of C_i to get the i-th gem.

Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid.

Find the maximum possible value of X-Y.

Constraints

All values in input are integers.

1 \leq N \leq 20

1 \leq C_i, V_i \leq 50

Input

Input is given from Standard Input in the following format:

N
V_1 V_2 ... V_N
C_1 C_2 ... C_N

Output

Print the maximum possible value of X-Y.

Sample Input 1

3
10 2 5
6 3 4

Sample Output 1

5

If we choose the first and third gems, X = 10 + 5 = 15 and Y = 6 + 4 = 10.
We have X-Y = 5 here, which is the maximum possible value.

Sample Input 2

4
13 21 6 19
11 30 6 15

Sample Output 2

6

Sample Input 3

1
1
50

Sample Output 3

0

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.*;

class Main{
    public static void main(String[] args){

        Scanner sc = new Scanner(System.in);

        int N = sc.nextInt();
        int[] v;
        int[] c;

        v = new int[49];
        c = new int[49];
        for(int i=0;i<=N-1;i++){
            v[i] = sc.nextInt();
        }
        for(int j=0;j<=N-1;j++){
            c[j] = sc.nextInt();
        }
        if(N !=1){
            int x = v[0]+v[N];
            int y = c[0]+c[N];
            
            int xy = x-y;

            System.out.println(xy);

        }else if(N==1){
            int xy = v[0]-c[0];
            if(xy>0){
                System.out.println(xy);
            }else{
                System.out.println(0);
            }
        
        }else{
            System.out.println(0);
        }
    }
}