Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Scanner;

public class Main {
	public static void main(String args[]) {
		Scanner scan = new Scanner(System.in);
		int N = scan.nextInt();
		//int b = scan.nextInt();
		int cnt = 0;
		/*N以下の自然数
		奇数である
		約数が8個ちょうど存在する*/
		for( int i = 1; i <= N; i += 2 ) {
			int yakusuu = 0;
			for( int j = 1; j <= i; j++  ) {
				if( i % j == 0 ) {
					yakusuu++;
				}
			}
			if( yakusuu == 8 ) {
				cnt++;
			}
		}
		System.out.println(cnt);
	}
}