Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Accepted)

import java.util.ArrayDeque;
import java.util.HashMap;
import java.util.Queue;
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);

        int[] cnt = new int[26];
        while (scanner.hasNext()) {
            String str = scanner.nextLine().toLowerCase();

            for (int i = 0; i < str.length(); ++i) {
                if (str.charAt(i) >= 'a' && str.charAt(i) <= 'z') {
                    ++cnt[str.charAt(i) - 'a'];
                }
            }
        }
        for (int i = 0; i < 26; ++i) {
            System.out.printf("%s : %d\n", (char) ('a' + i), cnt[i]);
        }
    }
}