Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Java (OpenJDK 11.0.6) (judge verdict: Accepted)

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();

        int result = 0;
        for (int i = 1; i <= n; i = i+2) {
            int divisor = divisorCounter(i);
            if (divisor == 8) {
                result++;
            }
        }
        System.out.println(result);
    }

    private static int divisorCounter(int x) {
        int counter = 0;
        for (int i = 1; i <= x; i++) {
            if (x%i == 0) {
                counter++;
            }
        }
        return counter;
    }
}