Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Accepted)

   
import java.util.Scanner;

public class Main{
    public static void main(String[] args){
	final int ALPHA_NUM=26;
	Scanner in = new Scanner(System.in);
	int[] cnt = new int[ALPHA_NUM];
	
	for(int i=0;i<ALPHA_NUM;i++)cnt[i]=0;
	    
	while(in.hasNext()){
	    String str = in.next();
	    for(int i=0;i<str.length();i++){
		char ch= str.charAt(i);

		if(('a'<= ch && ch<='z')|| ('A'<= ch && ch<='Z')){
		    if(Character.isUpperCase(ch))cnt[ch-(int)'A']++;
		    else if(Character.isLowerCase(ch))cnt[ch-(int)'a']++;
		}
	    }
	}
	    for(int i=0;i<ALPHA_NUM;i++)System.out.println((char)((int)'a'+i)+" : "+cnt[i]);
	
    }
}