Problem:
Score : 400 points

Problem Statement

We have N balls. The i-th ball has an integer A_i written on it.

For each k=1, 2, ..., N, solve the following problem and print the answer.

Find the number of ways to choose two distinct balls (disregarding order) from the N-1 balls other than the k-th ball so that the integers written on them are equal.

Constraints

3 \leq N \leq 2 \times 10^5

1 \leq A_i \leq N

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

For each k=1,2,...,N, print a line containing the answer.

Sample Input 1

5
1 1 2 1 2

Sample Output 1

2
2
3
2
3

Consider the case k=1 for example. The numbers written on the remaining balls are 1,2,1,2.

From these balls, there are two ways to choose two distinct balls so that the integers written on them are equal.

Thus, the answer for k=1 is 2.

Sample Input 2

4
1 2 3 4

Sample Output 2

0
0
0
0

No two balls have equal numbers written on them.

Sample Input 3

5
3 3 3 3 3

Sample Output 3

6
6
6
6
6

Any two balls have equal numbers written on them.

Sample Input 4

8
1 2 1 4 2 1 4 1

Sample Output 4

5
7
5
7
7
5
7
5

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)



import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.math.BigInteger;
import java.util.*;
import java.io.BufferedReader;
import java.io.InputStreamReader;

public class Main {
    public static void main(String[] args) {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        InputReader in = new InputReader(inputStream);
        PrintWriter out = new PrintWriter(outputStream);
        TaskD solver = new TaskD();
        solver.solve(1, in, out);
        out.close();
    }
    static class TaskD {
        static int log(long a  , long b){
            int ans = 0;
            while (a/b!=0){a/=b;ans++;}
            return ans;
        }
        static long pow(long a , long b){
            if (b==0)return 1;
            long v = pow(a , b/2);
            long ans = v*v;
            if (b%2!=0)ans*=a;
            return ans;
        }
        static  int[] count;
        static  boolean[] visited;
        static ArrayList<Integer>[] frinds;
        static int[] color ;
        public static void dfs(int v , int val){
            visited[v]=true;
            count[val]++;
            color[v]=val;
            if (frinds[v]!=null)for (int u: frinds[v]) {
                if (!visited[u]) dfs(u , val);
            }
        }
        public void solve(int testNumber, InputReader in, PrintWriter out) {
            int n = in.nextInt();
            int[] arr= new int[n];
            int[] count = new int[n+1];
            for (int i = 0; i <n ; i++) {
                arr[i]=in.nextInt();
                count[arr[i]]++;
            }
            long ans = 0;
            for (int i = 0; i <=n ; i++) {
                ans+=count[i]*(count[i]-1)/2;
            }
            for (int i = 0; i <n; i++) {
                System.out.println(ans-(count[arr[i]]-1));
            }







        }
    }
    static class InputReader {
        public BufferedReader reader;
        public StringTokenizer tokenizer;

        public InputReader(InputStream stream) {
            reader = new BufferedReader(new InputStreamReader(stream), 32768);
            tokenizer = null;
        }

        public String next() {
            while (tokenizer == null || !tokenizer.hasMoreTokens()) {
                try {
                    tokenizer = new StringTokenizer(reader.readLine());
                } catch (IOException e) {
                    throw new RuntimeException(e);
                }
            }
            return tokenizer.nextToken();
        }
        public int nextInt(){return  Integer.parseInt(next());}
        public long nextLong() {
            return Long.parseLong(next());
        }

    }
}