Problem:
Score : 300 points

Problem Statement

Given are an integer X and an integer sequence of length N: p_1, \ldots, p_N.

Among the integers not contained in the sequence p_1, \ldots, p_N (not necessarily positive), find the integer nearest to X, that is, find the integer whose absolute difference with X is the minimum. If there are multiple such integers, report the smallest such integer.

Constraints

1 \leq X \leq 100

0 \leq N \leq 100

1 \leq p_i \leq 100

p_1, \ldots, p_N are all distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X N
p_1 ... p_N

Output

Print the answer.

Sample Input 1

6 5
4 7 10 6 5

Sample Output 1

8

Among the integers not contained in the sequence 4, 7, 10, 6, 5, the one nearest to 6 is 8.

Sample Input 2

10 5
4 7 10 6 5

Sample Output 2

9

Among the integers not contained in the sequence 4, 7, 10, 6, 5, the ones nearest to 10 are 9 and 11. We should print the smaller one, 9.

Sample Input 3

100 0

Sample Output 3

100

When N = 0, the second line in the input will be empty. Also, as seen here, X itself can be the answer.

Solution in Java (OpenJDK 11.0.6) (judge verdict: Accepted)

import java.util.Scanner;

public class Main {


    public static void main(String[] args) {


        Scanner sc = new Scanner(System.in);
        int x= sc.nextInt();
        int n = sc.nextInt();
        int p[] = new int[n];
        for(int i = 0;i<n;i++){
            p[i] = sc.nextInt();
        }
        int ans = 0;


        for(int i = 0;i<105;i++){
            int tmp = x + i;
            int tmpp = x - i;
            boolean tmplus  = true;
            boolean tmpminus = true;
            int j = 0;
            while (tmplus||tmpminus){
                if(j == n){
                    break;
                }
                if(p[j]==tmp){
                    tmplus =false;
                }
                if(p[j]==tmpp){
                    tmpminus = false;

                }

                j++;
            }
            if(tmplus&&tmpminus){
                System.out.println(x-i);
                System.exit(0);
            }
            else if(tmplus&&!tmpminus){
                System.out.println(x+i);
                System.exit(0);
            }
            else if(!tmplus&&tmpminus){
                System.out.println(x-i);
                System.exit(0);
            }



        }

    }

}