Problem:
Score : 200 points

Problem Statement

We have a string S consisting of uppercase English letters. Additionally, an integer N will be given.

Shift each character of S by N in alphabetical order (see below), and print the resulting string.

We assume that A follows Z. For example, shifting A by 2 results in C (A \to B \to C), and shifting Y by 3 results in B (Y \to Z \to A \to B).

Constraints

0 \leq N \leq 26

1 \leq |S| \leq 10^4

S consists of uppercase English letters.

Input

Input is given from Standard Input in the following format:

N
S

Output

Print the string resulting from shifting each character of S by N in alphabetical order.

Sample Input 1

2
ABCXYZ

Sample Output 1

CDEZAB

Note that A follows Z.

Sample Input 2

0
ABCXYZ

Sample Output 2

ABCXYZ

Sample Input 3

13
ABCDEFGHIJKLMNOPQRSTUVWXYZ

Sample Output 3

NOPQRSTUVWXYZABCDEFGHIJKLM

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.*;
import java.math.*;
import java.io.*;

public class Main {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        PrintWriter out = new PrintWriter(System.out);

        final Map<String, Integer> cnt = new HashMap<>();
        {
            cnt.put("SUN", 7);
            cnt.put("MON", 6);
            cnt.put("TUE", 5);
            cnt.put("WED", 4);
            cnt.put("THU", 3);
            cnt.put("FRI", 2);
            cnt.put("SAT", 1);
        };


        int shift = in.nextInt();
        StringBuilder s = new StringBuilder(in.next());
        for (int i = 0; i < s.length(); ++i) {
            char newChar = (char)(s.charAt(i) + shift);
            if (newChar > 'Z') {
                newChar -= 'Z';
                newChar += ('A' - 1);
            }
            s.setCharAt(i, newChar);
        }
        out.println(s.toString());

        in.close();
        out.close();
    }
    static class Pair {
	  		public long first;
	  		public long second;

	  		public Pair() {
	  			this(0, 0);
	  		}

	  		public Pair(final long first, final long second) {
	  			this.first = first;
	  			this.second = second;
	  		}
	  	}
}