Problem:
Score : 100 points

Problem Statement

There are two buttons, one of size A and one of size B.

When you press a button of size X, you get X coins and the size of that button decreases by 1.

You will press a button twice. Here, you can press the same button twice, or press both buttons once.

At most how many coins can you get?

Constraints

All values in input are integers.

3 \leq A, B \leq 20

Input

Input is given from Standard Input in the following format:

A B

Output

Print the maximum number of coins you can get.

Sample Input 1

5 3

Sample Output 1

9

You can get 5 + 4 = 9 coins by pressing the button of size 5 twice, and this is the maximum result.

Sample Input 2

3 4

Sample Output 2

7

Sample Input 3

6 6

Sample Output 3

12

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Runtime Error)

import java.util.*;

public class Main {
        public static void main(String[] args){
            Scanner sc =new Scanner(System.in);
            int n = sc.nextInt();
            int[] h = new int[n];
            for(int i=0;i<n;i++){
                h[i] = sc.nextInt();
            }
            int max = h[0];
            int sum = 1;
            for(int j=1;j<n;j++){
                if(h[j]>=max){
                    sum++;
                    max=h[j];
                }
            }
            System.out.println(sum);
            for(int k = 0;k<1000000;k++){
                sum=sum*1/1^1;
            }
        }

        }