Problem:
Score : 300 points

Problem Statement

In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0.
You are given a sequence h=\{h_1,h_2,h_3,......\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:

Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.

Find the minimum number of watering operations required to satisfy the condition.

Constraints

1 \leq N \leq 100

0 \leq h_i \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
h_1 h_2 h_3 ...... h_N

Output

Print the minimum number of watering operations required to satisfy the condition.

Sample Input 1

4
1 2 2 1

Sample Output 1

2

The minimum number of watering operations required is 2.
One way to achieve it is:

Perform the operation with (l,r)=(1,3).

Perform the operation with (l,r)=(2,4).

Sample Input 2

5
3 1 2 3 1

Sample Output 2

5

Sample Input 3

8
4 23 75 0 23 96 50 100

Sample Output 3

221

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        int n = scan.nextInt();
        int[] h = new int[n];
        int sum = 0;
        for(int i= 0; i < n; i++) {
        	h[i] = scan.nextInt();
        	sum += h[i];
        }
        int ans = 0;
        while(true) {
        	int temp = ans;
        	boolean f = false;
        	for(int i = 0; i < n; i++) {
        		if(f == false && h[i] != 0) {
        			f = true;
        			ans ++;
        		}
        		if(f) {
        			if(h[i] > 0) {
        				h[i]--;
        				sum--;
        			}else {
        				break;
        			}
        		}
        	}
        	if(temp == ans) {
        		break;
        	}
        }
        System.out.println(ans);
    }
}