Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Accepted)

import java.util.Scanner;

public class Main {
	public static void main(String[] args) {
		try (Scanner sc = new Scanner(System.in);) {
			String s = "";
			while (sc.hasNextLine()) {
				s += sc.nextLine();
			}
			s = s.toLowerCase();
			int num[] = new int[26];
			for (int i = 0; i < s.length(); i++) {
				if (String.valueOf(s.charAt(i)).matches("[a-z]")) {
					num[(s.charAt(i) - 'a')]++;
				}
			}
			for (int j = 0; j < 26; j++) {
				System.out.println((char) (j + 'a') + " : " + num[j]);
			}
		}
	}
}