Problem:
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Matrix Multiplication

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\[
c_{ij} = \sum_{k=1}^m a_{ik}b_{kj}
\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Constraints

$1 \leq n, m, l \leq 100$

$0 \leq a_{ij}, b_{ij} \leq 10000$

Sample Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2

Sample Output

1 8 5
0 9 6
4 23 14

Note

      解説

Solution in JAVA (judge verdict: Accepted)



import java.util.Scanner;
public class Main 
{ 
    public static void main(String[] args)
    {
       Scanner sc = new Scanner(System.in);  
       int n,m,l;
       n = sc.nextInt();
       m = sc.nextInt();
       l = sc.nextInt();
       long [] [] A = new long [n][m];
       long [] [] B = new long [m][l];
       for(int i=0; i<n; i++)  //input
       {
           for (int j = 0; j<m; j++)
           {
               A[i][j] = sc.nextLong();
           }
       }
        for(int i=0; i<m; i++)  //input
       {
           for (int j = 0; j<l; j++)
           {
               B[i][j] = sc.nextLong();
           }
       }
        
        for(int i=0; i<n; i++) //multiplying
        {
            for(int j = 0; j< l; j++)
            {
                long sum = 0;
                for(int k = 0; k< m;k++)
                {
                   sum = sum + A[i][k] * B[k][j];
                }
                if(j!=l-1)
                    {
                        System.out.print(sum + " ");
                    }
                else System.out.println(sum);
            
            }
        }
    }
}