Problem:
Score : 300 points

Problem Statement

Given is a permutation P_1, \ldots, P_N of 1, \ldots, N.
Find the number of integers i (1 \leq i \leq N) that satisfy the following condition:

For any integer j (1 \leq j \leq i), P_i \leq P_j.

Constraints

1 \leq N \leq 2 \times 10^5

P_1, \ldots, P_N is a permutation of 1, \ldots, N.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
P_1 ... P_N

Output

Print the number of integers i that satisfy the condition.

Sample Input 1

5
4 2 5 1 3

Sample Output 1

3

i=1, 2, and 4 satisfy the condition, but i=3 does not - for example, P_i > P_j holds for j = 1.

Similarly, i=5 does not satisfy the condition, either. Thus, there are three integers that satisfy the condition.

Sample Input 2

4
4 3 2 1

Sample Output 2

4

All integers i (1 \leq i \leq N) satisfy the condition.

Sample Input 3

6
1 2 3 4 5 6

Sample Output 3

1

Only i=1 satisfies the condition.

Sample Input 4

8
5 7 4 2 6 8 1 3

Sample Output 4

4

Sample Input 5

1
1

Sample Output 5

1

Solution in Java7 (OpenJDK 1.7.0) (judge verdict: Time Limit Exceeded)

import java.util.ArrayList;
import java.util.Scanner;

class Main {
    public static void main(String[] args) {
        Scanner s = new Scanner(System.in);
        int num = s.nextInt();
        ArrayList<Integer> list = new ArrayList<Integer>(num);
        for(int i=0;i<num;i++){
            list.add(s.nextInt());
        }
        int count=num;
        // for(int i=0;i<num;i++){
        //     System.out.print(list.get(i)+" ");
        // }
        for(int i=0;i<num;i++){
            for(int j=0;j<=i;j++){
                if(list.get(i)>list.get(j)){
                    // System.out.println(list.get(i)+">"+list.get(j));
                    // System.out.println("count :"+count);
                    count--;
                    break;
                }
            }
        }
        // if(count<0){
        //     count = 1;
        // }
        System.out.println(count);
        s.close();
    }
}