Problem:
Score : 100 points

Problem Statement

There are two buttons, one of size A and one of size B.

When you press a button of size X, you get X coins and the size of that button decreases by 1.

You will press a button twice. Here, you can press the same button twice, or press both buttons once.

At most how many coins can you get?

Constraints

All values in input are integers.

3 \leq A, B \leq 20

Input

Input is given from Standard Input in the following format:

A B

Output

Print the maximum number of coins you can get.

Sample Input 1

5 3

Sample Output 1

9

You can get 5 + 4 = 9 coins by pressing the button of size 5 twice, and this is the maximum result.

Sample Input 2

3 4

Sample Output 2

7

Sample Input 3

6 6

Sample Output 3

12

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Scanner;
public class Main{
	public static void main(String[] args) {
		Scanner scan = new Scanner(System.in);
		int A; int B; int X;
		A = scan.nextInt();
		B = scan.nextInt();
		X = 0;
		if(A>=B){
		X=X+A;
		A=A-1;
		}else if(A<=B){
			X=X+B;
			B=B-1;
		}
		if(A>=B){
		X=X+A;
		A=A-1;
		}else if(A<=B){
		X=X+B;
		B=B-1;
}
		System.out.println(X);
		scan.close();
	}
}