Problem:
Score : 500 points

Problem Statement

You are given a sequence with N integers: A = \{ A_1, A_2, \cdots, A_N \}.
For each of these N integers, we will choose a color and paint the integer with that color. Here the following condition must be satisfied:

If A_i and A_j (i < j) are painted with the same color, A_i < A_j.

Find the minimum number of colors required to satisfy the condition.

Constraints

1 \leq N \leq 10^5

0 \leq A_i \leq 10^9

Input

Input is given from Standard Input in the following format:

N
A_1
:
A_N

Output

Print the minimum number of colors required to satisfy the condition.

Sample Input 1

5
2
1
4
5
3

Sample Output 1

2

We can satisfy the condition with two colors by, for example, painting 2 and 3 red and painting 1, 4, and 5 blue.

Sample Input 2

4
0
0
0
0

Sample Output 2

4

We have to paint all the integers with distinct colors.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.Arrays;
import java.util.HashSet;
import java.util.Scanner;
import java.util.Set;



public class Main {

	public static void main(String[] args){
		Scanner sc = new Scanner(System.in);
		Set<String> set = new HashSet<String> ();
		int N = sc.nextInt();
		long a[] = new long[N];
		long b[] = new long[100];
		long temp[];
		int colorCount =1;
		for (int i=0;i<N;i++) {
			a[i] = sc.nextLong();
		}
		for (int i=0;i<100;i++) {
			b[i] =1000000001;
		}
		b[0] = a[0];
		long before =a[0];
		for (int i=1;i<N;i++) {
			if (before>=a[i]) {
				boolean isFind=false;
				for (int j=0;j<colorCount;j++) {
					if (b[j]<a[i]) {
						b[j] =a[i];
						isFind =true;
						Arrays.sort(b);
						break;
					}
				}
				if (isFind==false) {
					colorCount++;
					if (colorCount>b.length) {
						b=Arrays.copyOf(b, colorCount*2);
					}
					b[colorCount-1]=a[i];
				}
			}
			before=a[i];
		}
		System.out.println(colorCount);
  	}

}