Problem:
Score : 300 points

Problem Statement

There are N people living on a number line.

The i-th person lives at coordinate X_i.

You are going to hold a meeting that all N people have to attend.

The meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.

Find the minimum total points of stamina the N people have to spend.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq X_i \leq 100

Input

Input is given from Standard Input in the following format:

N
X_1 X_2 ... X_N

Output

Print the minimum total stamina the N people have to spend.

Sample Input 1

2
1 4

Sample Output 1

5

Assume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.

Note that you can hold the meeting only at an integer coordinate.

Sample Input 2

7
14 14 2 13 56 2 37

Sample Output 2

2354

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Scanner;

public class Main {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int N = sc.nextInt();
        int[] X = new int[N];
        int minval = 100;
        int maxval = 0;
        for(int i=0; i<N; i++) {
            X[i] = sc.nextInt();
            if(X[i]<minval) minval=X[i];
            if(X[i]>maxval) maxval=X[i];
        }
        long result = Long.MAX_VALUE;
        for(int i=minval; i<=maxval; i++) {
            long tmpsum = 0;
            for(int t=0; t<N; t++) {
                tmpsum += (X[t]-i)*(X[t]-i);
            }
            if(tmpsum<result) result=tmpsum;
        }
        System.out.println(result);
    }
}