Problem:
Score : 200 points

Problem Statement

A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.

How many times will the ball make a bounce where the coordinate is at most X?

Constraints

1 \leq N \leq 100

1 \leq L_i \leq 100

1 \leq X \leq 10000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N X
L_1 L_2 ... L_{N-1} L_N

Output

Print the number of times the ball will make a bounce where the coordinate is at most X.

Sample Input 1

3 6
3 4 5

Sample Output 1

2

The ball will make a bounce at the coordinates 0, 3, 7 and 12, among which two are less than or equal to 6.

Sample Input 2

4 9
3 3 3 3

Sample Output 2

4

The ball will make a bounce at the coordinates 0, 3, 6, 9 and 12, among which four are less than or equal to 9.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);

		int N = sc.nextInt();
		int X = sc.nextInt();
		int[] arrayL = new int[N];

		for (int i = 0; i < arrayL.length; i++) {
			arrayL[i] = sc.nextInt();
		}

		// 座標
		int coordinate = 0;
		// X内でバウンドした回数
		int counter = 0;

		for (int i = 0; i < arrayL.length; i++) {
			if (i == 0) {
				counter++;
				continue;
			}

			coordinate += arrayL[i];

			if (X < coordinate) {
				break;
			}

			counter++;
		}

		System.out.println(counter);
		sc.close();
	}

}