Problem:
Score : 300 points

Problem Statement

You are given a string S of length N and another string T of length M.
These strings consist of lowercase English letters.

A string X is called a good string when the following conditions are all met:

Let L be the length of X. L is divisible by both N and M.

Concatenating the 1-st, (\frac{L}{N}+1)-th, (2 \times \frac{L}{N}+1)-th, ..., ((N-1)\times\frac{L}{N}+1)-th characters of X, without changing the order, results in S.

Concatenating the 1-st, (\frac{L}{M}+1)-th, (2 \times \frac{L}{M}+1)-th, ..., ((M-1)\times\frac{L}{M}+1)-th characters of X, without changing the order, results in T.

Determine if there exists a good string. If it exists, find the length of the shortest such string.

Constraints

1 \leq N,M \leq 10^5

S and T consist of lowercase English letters.

|S|=N

|T|=M

Input

Input is given from Standard Input in the following format:

N M
S
T

Output

If a good string does not exist, print -1; if it exists, print the length of the shortest such string.

Sample Input 1

3 2
acp
ae

Sample Output 1

6

For example, the string accept is a good string.
There is no good string shorter than this, so the answer is 6.

Sample Input 2

6 3
abcdef
abc

Sample Output 2

-1

Sample Input 3

15 9
dnsusrayukuaiia
dujrunuma

Sample Output 3

45

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Runtime Error)

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.io.PrintWriter;
import java.util.*;

class Main {
    public static void main(String[] args) {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        InputReader in = new InputReader(inputStream);
        PrintWriter out = new PrintWriter(outputStream);
        Task solver = new Task();
        solver.solve(in, out);
        out.close();
    }

    static class Task {
        int N, M;
        long LCM;
        String S, T;
        StringBuilder partialStrOfS = new StringBuilder();
        StringBuilder partialStrOfT = new StringBuilder();

        int gcd(int a, int b) {
            if (a < b) {
                int tmp = a;
                a = b;
                b = tmp;
            }
            if (b == 0) {
                return a;
            } else {
                return gcd(b, a % b);
            }
        }

        void solve(InputReader in, PrintWriter out) {
            N = in.nextInt();
            M = in.nextInt();
            S = in.next();
            T = in.next();
            LCM = N/gcd(N, M)*M;

            for (int i = 0; i < N; i += LCM/M) {
                partialStrOfS.append(S.charAt(i));
            }
            for (int i = 0; i < M; i += LCM/N) {
                partialStrOfT.append(T.charAt(i));
            }

            if (partialStrOfS.toString().equals(partialStrOfT.toString())) {
                out.println(LCM);
            } else {
                out.println(-1);
            }
        }
    }

    static class InputReader {
        BufferedReader reader;
        StringTokenizer tokenizer;

        InputReader(InputStream stream) {
            reader = new BufferedReader(new InputStreamReader(stream));
            tokenizer = null;
        }

        String next() {
            while (tokenizer == null || !tokenizer.hasMoreTokens()) {
                try {
                    tokenizer = new StringTokenizer(reader.readLine());
                } catch (IOException e) {
                    throw new RuntimeException(e);
                }
            }
            return tokenizer.nextToken();
        }

        int nextInt() { return Integer.parseInt(next()); }

        int[] nextIntArray(int n) {
        	int[] arr = new int[n];
        	for (int i = 0; i < n; ++i) {
        		arr[i] = nextInt();
        	}
        	return arr;
        }
    }
}