Problem:
Score : 300 points

Problem Statement

Snuke has an integer sequence A of length N.

He will freely choose an integer b.
Here, he will get sad if A_i and b+i are far from each other.
More specifically, the sadness of Snuke is calculated as follows:

abs(A_1 - (b+1)) + abs(A_2 - (b+2)) + ... + abs(A_N - (b+N))

Here, abs(x) is a function that returns the absolute value of x.

Find the minimum possible sadness of Snuke.

Constraints

1 \leq N \leq 2 \times 10^5

1 \leq A_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

Print the minimum possible sadness of Snuke.

Sample Input 1

5
2 2 3 5 5

Sample Output 1

2

If we choose b=0, the sadness of Snuke would be abs(2-(0+1))+abs(2-(0+2))+abs(3-(0+3))+abs(5-(0+4))+abs(5-(0+5))=2.
Any choice of b does not make the sadness of Snuke less than 2, so the answer is 2.

Sample Input 2

9
1 2 3 4 5 6 7 8 9

Sample Output 2

0

Sample Input 3

6
6 5 4 3 2 1

Sample Output 3

18

Sample Input 4

7
1 1 1 1 2 3 4

Sample Output 4

6

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.Scanner;

public class Main{
	public static void main(String args[]) {
		Scanner scn = new Scanner(System.in);
		int N = scn.nextInt();
		long[] A = new long[N];
		long buf,ave = 0,up = 0,down = 0;
		for(int i = 1; i <= N ;i++) {
			buf = scn.nextLong() - i;
			A[i-1] = buf;
			ave += buf;
		}
		up =(long) Math.ceil((double)ave/(double)N);
		down = (long)Math.floor((double)ave/(double)N);
		long ans1 = 0,ans2 = 0;
		for(int i = 0; i < N;i++) {
			ans1 += Math.abs(A[i] - up);
			ans2 += Math.abs(A[i] - down);
		}
		System.out.println(Math.min(ans1, ans2));
		scn.close();
	}
}