Problem:
Selection Sort

Write a program of the Selection Sort algorithm which sorts a sequence A in ascending order. The algorithm should be based on the following pseudocode:

SelectionSort(A)
1 for i = 0 to A.length-1
2 mini = i
3 for j = i to A.length-1
4 if A[j] < A[mini]
5 mini = j
6 swap A[i] and A[mini]

Note that, indices for array elements are based on 0-origin.

Your program should also print the number of swap operations defined in line 6 of the pseudocode in the case where i ≠ mini.

Input

The first line of the input includes an integer N, the number of elements in the sequence.

In the second line, N elements of the sequence are given separated by space characters.

Output

The output consists of 2 lines.

In the first line, please print the sorted sequence. Two contiguous elements of the sequence should be separated by a space character.

In the second line, please print the number of swap operations.

Constraints

1 ≤ N ≤ 100

Sample Input 1

6
5 6 4 2 1 3

Sample Output 1

1 2 3 4 5 6
4

Sample Input 2

6
5 2 4 6 1 3

Sample Output 2

1 2 3 4 5 6
3

Solution in JAVA (judge verdict: Accepted)


import java.util.Scanner;

/**
 * Created by sd on 2016/11/22.
 */
public class Main {
    public static void main(String[] args){
        Scanner sc = new Scanner(System.in);
        int N = sc.nextInt();
        int a[] = new int[N];
        for(int I=0;I<N;I++){
            a[I] = sc.nextInt();
        }

        int count = 0;
        for(int i=0; i<N; i++){
            int minj = i;
            for(int j=i; j<N; j++){
                if(a[j] < a[minj]){
                    minj = j;
                }
            }
            if(i != minj){
                count ++;
            }
            int t = a[i];
            a[i] = a[minj];
            a[minj] = t;
        }
        for(int ii=0; ii<N-1; ii++){
            System.out.print(a[ii]+" ");
        }
        System.out.println(a[N-1]);
        System.out.println(count);
    }
}