Problem:
Reversing Numbers

Write a program which reads a sequence and prints it in the reverse order.

Input

The input is given in the following format:

n
a1 a2 . . . an

n is the size of the sequence and ai is the ith element of the sequence.

Output

Print the reversed sequence in a line. Print a single space character between adjacent elements (Note that your program should not put a space character after the last element).

Constraints

n ≤ 100

0 ≤ ai < 1000

Sample Input 1

5
1 2 3 4 5

Sample Output 1

5 4 3 2 1

Sample Input 2

8
3 3 4 4 5 8 7 9

Sample Output 2

9 7 8 5 4 4 3 3

Note

      解説

Solution in JAVA (judge verdict: Accepted)

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.StringTokenizer;

public class Main {
  static InputReader in;
  static PrintWriter out;

  static class Solution {
    void solve() throws IOException {
      int n = in.nextInt();
      int[] a = new int[n];
      for (int i = 0; i < n; i++) {
        a[i] = in.nextInt();
      }
      
      StringBuilder sb = new StringBuilder();
      for (int i = n-1; i >= 0; i--) {
        if (i != n-1) {
          sb.append(" ");
        }
        sb.append(a[i]);
      }
      
      out.println(sb);
//    End solve()
    }
//    End Solution
}

  public static void main(String[] args) throws IOException {
    in = new InputReader(System.in);
    out = new PrintWriter(System.out);
    Solution solver = new Solution();
    solver.solve();
    out.close();
}

  static class InputReader {
    public BufferedReader br;
    public StringTokenizer st;

    public InputReader(InputStream stream) {
      br = new BufferedReader(new InputStreamReader(stream));
    }

    public int nextInt() throws IOException {
      while (st == null || !st.hasMoreTokens()) {
        st = new StringTokenizer(br.readLine());
      }
      return Integer.parseInt(st.nextToken());
    }

    public long nextLong() throws IOException {
      while (st == null || !st.hasMoreTokens()) {
        st = new StringTokenizer(br.readLine());
      }
      return Long.parseLong(st.nextToken());
    }

    public String next() throws IOException {
      while (st == null || !st.hasMoreTokens()) {
        st = new StringTokenizer(br.readLine());
      }
      return st.nextToken();
    }

    public double nextDouble() throws IOException {
      while (st == null || !st.hasMoreTokens()) {
        st = new StringTokenizer(br.readLine());
      }
      return Double.parseDouble(st.nextToken());
    }

  }

}