Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Accepted)

import java.util.Scanner;

public class Main {

	public static void main(String[] args) {

		Scanner sc = new Scanner(System.in);

		int[] count = new int[26];

		while(sc.hasNext()) {
			String input = sc.nextLine();
			String tmp = input.toLowerCase().replace(" ", "");

			for(char c : tmp.toCharArray()) {
				if('a' <= c && c <= 'z') {
					count[(int)c - (int)'a']++;
				}
			}
		}
		sc.close();

		for (int i = 0; i < 26; i++) {
			char now = (char)( (int)'a' + i );

			System.out.println(now + " : " + count[i]);
		}
	}
}