Problem:
Score : 400 points

Problem Statement

Given is a tree G with N vertices.
The vertices are numbered 1 through N, and the i-th edge connects Vertex a_i and Vertex b_i.

Consider painting the edges in G with some number of colors.
We want to paint them so that, for each vertex, the colors of the edges incident to that vertex are all different.

Among the colorings satisfying the condition above, construct one that uses the minimum number of colors.

Constraints

2 \le N \le 10^5

1 \le a_i \lt b_i \le N

All values in input are integers.

The given graph is a tree.

Input

Input is given from Standard Input in the following format:

N
a_1 b_1
a_2 b_2
\vdots
a_{N-1} b_{N-1}

Output

Print N lines.

The first line should contain K, the number of colors used.

The (i+1)-th line (1 \le i \le N-1) should contain c_i, the integer representing the color of the i-th edge, where 1 \le c_i \le K must hold.

If there are multiple colorings with the minimum number of colors that satisfy the condition, printing any of them will be accepted.

Sample Input 1

3
1 2
2 3

Sample Output 1

2
1
2

Sample Input 2

8
1 2
2 3
2 4
2 5
4 7
5 6
6 8

Sample Output 2

4
1
2
3
4
1
1
2

Sample Input 3

6
1 2
1 3
1 4
1 5
1 6

Sample Output 3

5
1
2
3
4
5

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.awt.Point;
import java.util.*;
import java.io.*;
import java.util.function.*;

class Main {
    static Scanner scanner = new Scanner();
    static int mod = 1000000007;
    static int inf = 0x7ffffff;

    void solve() {
        int n = scanner.nextInt();
        List<Map<Integer, Integer>> edges = new ArrayList<>();
        for (int i = 0; i < n; i++) {
            edges.add(new HashMap<>());
        }
        int[][] edges1 = new int[n - 1][2];
        for (int i = 1; i < n; i++) {
            int a = scanner.nextInt() - 1;
            int b = scanner.nextInt() - 1;
            edges1[i - 1] = new int[] {a, b};
            edges.get(a).put(b, -1);
            edges.get(b).put(a, -1);
        }
        Deque<Point> deque = new ArrayDeque<>();
        deque.add(new Point(0, -1));
        int cc = 0;
        while (!deque.isEmpty()) {
            Point v = deque.poll();
            int pcolor = v.y == -1 ? -1 : edges.get(v.y).get(v.x);
            int color = 1;
            for (Map.Entry<Integer, Integer> u : edges.get(v.x).entrySet()) {
                if (v.y != u.getKey()) {
                    if (color == pcolor) {
                        color++;
                    }
                    cc = Math.max(cc, color);
                    u.setValue(color++);
                    deque.add(new Point(u.getKey(), v.x));
                }
            }
        }
        System.out.println(cc);
        for (int i = 0; i < n - 1; i++) {
            System.out.println(edges.get(edges1[i][0]).get(edges1[i][1]) == -1 ? edges.get(edges1[i][1]).get(edges1[i][0]) : edges.get(edges1[i][0]).get(edges1[i][1]));
        }
    }

    public static void main(String[]$) throws Exception {
        new Main().solve();
        System.out.flush();
    }
}

class System {
    static PrintWriter out = new PrintWriter(java.lang.System.out);

    static void exit() {
        java.lang.System.exit(0);
    }
}

class Scanner {
    private BufferedReader reader = new BufferedReader(new InputStreamReader(java.lang.System.in), 0x10000);
    private StringTokenizer tokenizer;

    String next() {
        try {
            while (tokenizer == null || !tokenizer.hasMoreTokens()) {
                tokenizer = new StringTokenizer(reader.readLine());
            }
        } catch (IOException ignored) {
        }
        return tokenizer.nextToken();
    }

    int nextInt() {
        return Integer.parseInt(next());
    }

    long nextLong() {
        return Long.parseLong(next());
    }

    char[][] nextCharArray(int n, int m) {
        char[][] a = new char[n][m];
        for (int i = 0; i < n; i++) {
            a[i] = next().toCharArray();
        }
        return a;
    }

    int[] nextIntArray(int n) {
        int[] a = new int[n];
        for (int i = 0; i < n; i++) {
            a[i] = nextInt();
        }
        return a;
    }

    int[] nextIntArray(int n, IntUnaryOperator op) {
        int[] a = new int[n];
        for (int i = 0; i < n; i++) {
            a[i] = op.applyAsInt(nextInt());
        }
        return a;
    }

    long[] nextLongArray(int n) {
        long[] a = new long[n];
        for (int i = 0; i < n; i++) {
            a[i] = nextLong();
        }
        return a;
    }

    long[] nextLongArray(int n, LongUnaryOperator op) {
        long[] a = new long[n];
        for (int i = 0; i < n; i++) {
            a[i] = op.applyAsLong(nextLong());
        }
        return a;
    }
}