Problem:
Score : 200 points

Problem Statement

Takahashi has many red balls and blue balls. Now, he will place them in a row.

Initially, there is no ball placed.

Takahashi, who is very patient, will do the following operation 10^{100} times:

Place A blue balls at the end of the row of balls already placed. Then, place B red balls at the end of the row.

How many blue balls will be there among the first N balls in the row of balls made this way?

Constraints

1 \leq N \leq 10^{18}

A, B \geq 0

0 < A + B \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N A B

Output

Print the number of blue balls that will be there among the first N balls in the row of balls.

Sample Input 1

8 3 4

Sample Output 1

4

Let b denote a blue ball, and r denote a red ball. The first eight balls in the row will be bbbrrrrb, among which there are four blue balls.

Sample Input 2

8 0 4

Sample Output 2

0

He placed only red balls from the beginning.

Sample Input 3

6 2 4

Sample Output 3

2

Among bbrrrr, there are two blue balls.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Runtime Error)

import java.util.Scanner;
/**
 *
 * https://atcoder.jp/contests/abc158/tasks/abc158_b
 * @author shouma
 *
 */

public class Main {
	public static void main(String args[]) {

		Scanner scan = new Scanner(System.in);
		String str = scan.nextLine();
		String[] stries = str.split(" ");
		int[] ballNum = new int[stries.length];
		for(int i = 0;i < stries.length;i++) {
			ballNum[i] = Integer.parseInt(stries[i]);
		}
		//全体のボールの個数
			if(ballNum[1] != 0) {
				//個数が求められたら、プリントアウト
				System.out.println(count(ballNum));
			}else{
				//0ならプリントアウト
				System.out.println(ballNum[1]);
			}
        scan.close();
	}

	public static int count(int[] ballNum) {
		int answer = 0;
		int allBall = ballNum[0];
		int blueBall = ballNum[1];
		int redBall = ballNum[2];

		if(allBall != blueBall + redBall) {
			int aaa = 0;
			aaa = allBall - (blueBall + redBall);
//			System.out.println(aaa);
			if(aaa == 0) {
				answer = blueBall;
//				System.out.println(answer);
			}else {
				answer = blueBall + aaa;
//				System.out.println(+ answer);
			}
		}else{
			answer = blueBall;
		}
		return answer;
	}
}