Problem:
Score : 200 points

Problem Statement

A string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:

S is a palindrome.

Let N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.

The string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.

Determine whether S is a strong palindrome.

Constraints

S consists of lowercase English letters.

The length of S is an odd number between 3 and 99 (inclusive).

Input

Input is given from Standard Input in the following format:

S

Output

If S is a strong palindrome, print Yes;
otherwise, print No.

Sample Input 1

akasaka

Sample Output 1

Yes

S is akasaka.

The string formed by the 1-st through the 3-rd characters is aka.

The string formed by the 5-th through the 7-th characters is aka.
All of these are palindromes, so S is a strong palindrome.

Sample Input 2

level

Sample Output 2

No

Sample Input 3

atcoder

Sample Output 3

No

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.Scanner;

class Main {
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		String S = sc.next();
		boolean isStrong = true;

		if(S.length() % 4 == 1) {
			int l = (S.length()-1 )/ 2;
			for(int i = 0; i < l/2 ; i++) {
				if(S.charAt(i) != S.charAt(l-i-1)) isStrong = false;
			}
			if(S.substring(0, l).equals( S.substring(l))) isStrong = false;
		}else {
			int l = (S.length()-1 )/ 2;
			for(int i = 0; i < (l-1)/2 ; i++) {
				if(S.charAt(i) != S.charAt(l-i-1)) isStrong = false;
			}
			if(S.substring(0, l).equals( S.substring(l))) isStrong = false;
			
		}

		if(isStrong) {
			System.out.println("Yes");
		}
		else {
			System.out.println("No");
		}




	}
}