Problem:
Simultaneous Equation

Write a program which solve a simultaneous equation:

ax + by = c

dx + ey = f

The program should print x and y for given a, b, c, d, e and f (-1,000 ≤ a, b, c, d, e, f ≤ 1,000). You can suppose that given equation has a unique solution.

Input

The input consists of several data sets, 1 line for each data set. In a data set, there will be a, b, c, d, e, f separated by a single space. The input terminates with EOF.

Output

For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.

Sample Input 1

1 2 3 4 5 6
2 -1 -2 -1 -1 -5

Output for the Sample Input 1

-1.000 2.000
1.000 4.000

Sample Input 2

2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27

Output for the Sample Input 2

0.000 3.000
0.000 3.000

Solution in JAVA (judge verdict: Time Limit Exceeded)

import java.util.Scanner;
public class Main
{
	public static void main(String[] args){
		//??\???a,b,c,d,e,f
		Scanner scan = new Scanner(System.in);
		//??£???????¨????ax+by=c, dx+ey=f???x,y????±???????
		int a = scan.nextInt();
		int b = scan.nextInt();
		int c = scan.nextInt();
		int d = scan.nextInt();
		int e = scan.nextInt();
		int f = scan.nextInt();
		int a2 = scan.nextInt();
		int b2 = scan.nextInt();
		int c2 = scan.nextInt();
		int d2 = scan.nextInt();
		int e2 = scan.nextInt();
		int f2 = scan.nextInt();
		simultaneousEquation(a,b,c,d,e,f);
		simultaneousEquation(a2,b2,c2,d2,e2,f2);



	}

	//??£???????¨????????????????
	public static void simultaneousEquation(int a, int b, int c, int d, int e,int f){
		double x = 0;
		double y = 0;
		//a?????????????????°????????????
		int aCount = 1;
		//d?????????????????°????????????
		int dCount = 1;
		//b,e????¨?????????????????´???????
		int be;
		//b,y????¨?????????????????´???????
		double by;
		//c,f????¨?????????????????´???????
		int cf = 0;
		//ax????¨?????????????????´???????
		double ax;
		//a????????????????´???????
		int aFactorial = a;
		int dFactorial = d;

		while(true){
			//x????????????a,d?????????????¶?????????¨????????£???0???????????°break
			if(a - d == 0){
				break;
			}
			if(a + d == 0){
				break;
			}
			//??¶?????°??????a????°?????????¨???a???a????¶????????????????????????°?????????????????????
			if(Math.abs(a) < Math.abs(d)){
				a += aFactorial;
				aCount++;
			}
			//??¶?????°??????d????°?????????¨???d???d????¶????????????????????????°?????????????????????
			if(Math.abs(a) > Math.abs(d)){
				d += dFactorial;
				dCount++;
			}
		}
		//y????±???????
		//??????????????????
		if(a - d == 0){
			be = b * aCount - e * dCount;
			cf = c * aCount - f * dCount;
			y = cf / be;
		}
		//???????????????
		if(a + d == 0){
			be = b * aCount + e * dCount;
			cf = c * aCount + f * dCount;
			y = cf / be;
		}
		//x????±???????
		by = b * y;
		x = (c - by) / aFactorial;
		//????????????
		System.out.printf("%.3f %.3f\n",x,y);

	}
}