Problem:
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Matrix Multiplication

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\[
c_{ij} = \sum_{k=1}^m a_{ik}b_{kj}
\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Constraints

$1 \leq n, m, l \leq 100$

$0 \leq a_{ij}, b_{ij} \leq 10000$

Sample Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2

Sample Output

1 8 5
0 9 6
4 23 14

Note

      解説

Solution in JAVA (judge verdict: Accepted)

import java.util.Scanner;

public class Main {
	public static void main(String[] args) {
		int n, m, l, i, j, k, a, b;
		try (Scanner sc = new Scanner(System.in)) {
			n = sc.nextInt();
			m = sc.nextInt();
			l = sc.nextInt();
			int n_m[][] = new int[n][m];
			int m_l[][] = new int[m][l];
			long output[][] = new long[n][l]; //表の配列
			for(i = 0; i < n; i++) {
				for(j = 0; j < m; j++) {
					n_m[i][j] = sc.nextInt();
				}
			}
			for(i = 0; i < m; i++) {
				for(j = 0; j < l; j++) {
					m_l[i][j] = sc.nextInt();
				}
			}
			for(i = 0; i < n; i++) {
				for(j = 0; j < m; j++) {
					for(k = 0; k < l; k++) {
						output[i][k] += n_m[i][j] * m_l[j][k];
						if(j == m - 1) {
							if(k < l - 1) {
								System.out.print(output[i][k] + " ");
							}else {
								System.out.println(output[i][k]);
							}
						}
					}
				}
			}
		}
	}
}