Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Accepted)


import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.lang.Character;
import java.util.Scanner;


public class Main {


	/**
	 * main
	 * @param args
	 * @throws IOException
	 */
	public static void main(String[] args) throws IOException {
		//BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
		Scanner scan = new Scanner(System.in);
		int[] cnt = new int[26];//??¢??????????????????26??????????????????
		int num = 0;		//???????????¨????????°
		String line = "";
		
		while(scan.hasNext()){
			line = scan.nextLine();
		    String st = line.toLowerCase();
		    for(int i = 0 ; i < st.length() ; i++){
			char c = st.charAt(i);
			if('a' <= c && c <= 'z') cnt[c - 'a']++;
			else continue;
			}
		}
		
		//??¨???
		for (int i = 0; i < cnt.length; i++) {
			System.out.println((char)('a'+i) + " : " + cnt[i]);
		}
	}
	
}