Problem:
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Matrix Multiplication

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\[
c_{ij} = \sum_{k=1}^m a_{ik}b_{kj}
\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Constraints

$1 \leq n, m, l \leq 100$

$0 \leq a_{ij}, b_{ij} \leq 10000$

Sample Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2

Sample Output

1 8 5
0 9 6
4 23 14

Note

      解説

Solution in JAVA (judge verdict: Wrong Answer)

import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		int[][] a;
		int[][] b;
		int[][] c;
		int n = 0;
		int m = 0;
		int l = 0;

		Scanner sc= new Scanner( System.in );
		n = sc.nextInt();
		m = sc.nextInt();
		l = sc.nextInt();

		a = new int[n][m];
		b = new int[m][l];
		c = new int[n][l];


		for ( int i = 0 ; i < n ; i++ ) {
			for ( int j = 0 ; j < m ; j++ ) {
				a[i][j] = sc.nextInt();
			}
		}

		for ( int j = 0 ; j < m ; j++ ) {
			for ( int k = 0 ; k < l ; k++ ) {
				b[j][k] = sc.nextInt();
			}
		}

		for ( int i = 0 ; i < n ; i++ ) {
			for ( int k = 0 ; k < l ; k++ ) {
				for ( int j = 0 ; j < m ; j++ ) {
					if ( j == 0 ) {
						c[i][k] = 0;
					}
					c[i][k] += a[i][j] * b[j][k];
				}
				System.out.print( c[i][k] );
				if ( k != (l-1) ) {
					System.out.print( " " );
				}
			}
			System.out.print( "\n" );
		}
		sc.close();
	}
}