Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Wrong Answer)

import java.io.*;
import java.util.*;

class Alphabet{
	char ch;
	int count = 0;
	boolean with = false;
	static List<Alphabet> abc = new ArrayList<Alphabet>();

	Alphabet(char ch){
		this.ch = ch;
	}
}


public class Main{
	public static void main(String[] args) throws IOException{
		char a = 'a';
		for (int i = 0; i < 26; i++){
			Alphabet.abc.add(new Alphabet(a++));
		}

				
	BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
	String str;
	
		while((str = br.readLine()) != null){
			for(char c: str.toCharArray()){
				if(Character.isUpperCase(c)){
					c = Character.toLowerCase(c);
				}

				for (Alphabet x : Alphabet.abc){
					if(c == x.ch){
						x.with = true;
						x.count ++;
					}	
				}
			}

			for(Alphabet x : Alphabet.abc){
				System.out.println(x.ch + " : " + x.count);
			}
		}			
	}
}