Problem:
Score : 300 points

Problem Statement

Takahashi is a teacher responsible for a class of N students.

The students are given distinct student numbers from 1 to N.

Today, all the students entered the classroom at different times.

According to Takahashi's record, there were A_i students in the classroom when student number i entered the classroom (including student number i).

From these records, reconstruct the order in which the students entered the classroom.

Constraints

1 \le N \le 10^5

1 \le A_i \le N

A_i \neq A_j (i \neq j)

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 \ldots A_N

Output

Print the student numbers of the students in the order the students entered the classroom.

Sample Input 1

3
2 3 1

Sample Output 1

3 1 2

First, student number 3 entered the classroom.

Then, student number 1 entered the classroom.

Finally, student number 2 entered the classroom.

Sample Input 2

5
1 2 3 4 5

Sample Output 2

1 2 3 4 5

Sample Input 3

8
8 2 7 3 4 5 6 1

Sample Output 3

8 2 4 5 6 7 3 1

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Time Limit Exceeded)

import java.util.Scanner;

public class Main {
	public static void main(String args[]) {
		Scanner sc = new Scanner(System.in);
		
		int n;
		n = sc.nextInt();
		
		int a[][] = new int[2][n];
		
		for (int i = 0; i < n; i++) {
			a[0][i] = sc.nextInt();
			a[1][i] = i + 1;
		}
		
		//ソートする([0]の値でソート)
		sort(a, n);
		
		
		for (int i = 0; i < n; i++) {
			System.out.print( a[1][i] + " " );
		}
		
		return;
	}
	
	public static void sort(int array[][], int n) {
	
		if (array == null) {
			return;
		}
		
		for (int i = 0; i < n; i++) {
			for (int j = n - 1; j > i; j--) {
				if (array[0][j] < array[0][j-1]) {
					int temp0 = array[0][j];
					int temp1 = array[1][j];
					
					array[0][j] = array[0][j-1];
					array[1][j] = array[1][j-1];
					
					array[0][j-1] = temp0;
					array[1][j-1] = temp1;
				}
			}
		}

		return;
	}
}