Problem:
Score : 700 points

Problem Statement

Squid loves painting vertices in graphs.

There is a simple undirected graph consisting of N vertices numbered 1 through N, and M edges.
Initially, all the vertices are painted in color 0. The i-th edge bidirectionally connects two vertices a_i and b_i. The length of every edge is 1.

Squid performed Q operations on this graph. In the i-th operation, he repaints all the vertices within a distance of d_i from vertex v_i, in color c_i.

Find the color of each vertex after the Q operations.

Constraints

1 ≤ N,M,Q ≤ 10^5

1 ≤ a_i,b_i,v_i ≤ N

a_i ≠ b_i

0 ≤ d_i ≤ 10

1 ≤ c_i ≤10^5

d_i and c_i are all integers.

There are no self-loops or multiple edges in the given graph.

Partial Score

200 points will be awarded for passing the testset satisfying 1 ≤ N,M,Q ≤ 2{,}000.

Input

Input is given from Standard Input in the following format:

N M
a_1 b_1
:
a_{M} b_{M}
Q
v_1 d_1 c_1
:
v_{Q} d_{Q} c_{Q}

Output

Print the answer in N lines.
In the i-th line, print the color of vertex i after the Q operations.

Sample Input 1

7 7
1 2
1 3
1 4
4 5
5 6
5 7
2 3
2
6 1 1
1 2 2

Sample Output 1

2
2
2
2
2
1
0

Initially, each vertex is painted in color 0.
In the first operation, vertices 5 and 6 are repainted in color 1.
In the second operation, vertices 1, 2, 3, 4 and 5 are repainted in color 2.

Sample Input 2

14 10
1 4
5 7
7 11
4 10
14 7
14 3
6 14
8 11
5 13
8 3
8
8 6 2
9 7 85
6 9 3
6 7 5
10 3 1
12 9 4
9 6 6
8 2 3

Sample Output 2

1
0
3
1
5
5
3
3
6
1
3
4
5
3

The given graph may not be connected.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Time Limit Exceeded)

import java.util.Arrays;
import java.util.Scanner;
public class Main {
	public static void main(String[] args){
		Scanner as = new Scanner(System.in); 
		int n = as.nextInt();
		int m = as.nextInt();
		int[][] a;
		a = new int[n][n];
		for(int i=0;i<n;i++){
			for(int s=i;s<n;s++){
				if(i==s){
					a[i][s]=0;
				}else{
					a[i][s]=a[s][i]=-1;
				}
			}
		}
		int b,c;
		for(int i=0;i<m;i++){
			b = as.nextInt()-1;
			c = as.nextInt()-1;
			a[b][c]=a[c][b]=1;
		}
		int[] di = new int[n];
		int q = as.nextInt();
		int[]l;
		l = new int[n];
		Arrays.fill(l, 0);
		int av,ad,ac;
		for(int i=0;i<q;i++){
			av = as.nextInt()-1;
			ad = as.nextInt();
			ac = as.nextInt();
			dis(a,av,di);
			for(int s=0;s<n;s++){
				if(di[s]<=ad){
					l[s]=ac;
				}
			}
		}
		for(int i=0;i<n;i++){
			System.out.println(l[i]);
		}
	}
	public static void dis(int[][] map,int src,int[] distance) {
		int nTown = distance.length;
		boolean[] fixed = new boolean[nTown];
		for(int i=0; i<nTown; i++) {
			distance[i] = 100;
			fixed[i] = false;
		}
		distance[src] = 0;
		while (true) {
			int marked = minIndex(distance,fixed);
			if (marked < 0) return; 
			if (distance[marked]==100) return;
			fixed[marked] = true;
			for (int j=0; j<nTown; j++) { 
				if (map[marked][j]>0 && !fixed[j]) {
					int newDistance = distance[marked]+map[marked][j];
					if (newDistance < distance[j]) distance[j] = newDistance;
				}
			}
		}
	}
	static int minIndex(int[] distance,boolean[] fixed) {
		int idx=0;
		for (; idx<fixed.length; idx++)
			if (!fixed[idx]) break;
		if (idx == fixed.length) return -1;
		for (int i=idx+1; i<fixed.length; i++) 
			if (!fixed[i] && distance[i]<distance[idx]) idx=i;
		return idx;
	}
}