Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.*;
import java.math.*;
import java.lang.*;
import java.io.*;
 
public class Main{
  public static void main(String args[]) throws IOException{
    Scanner s=new Scanner(System.in);
   
    
    
    String ss=s.next();
    int f=Integer.parseInt(ss.substring(0,2));
    int se=Integer.parseInt(ss.substring(2,4));
    //System.out.println(f+" "+se);
    String res="NA";
     if(f==0||se==0)
      res="NA";
      else{
    if(f>12&&se<=12)
      res="YYMM";
      else if(f>12&&se>12)
    res="NA";
    else if(f<=12&&se>12)
      res="MMYY";
    
    else if(f<=12&&se<=12)
    res="AMBIGUOUS";
      }
    System.out.println(res);
  }
}