Problem:
Score : 300 points

Problem Statement

There are N candles placed on a number line.
The i-th candle from the left is placed on coordinate x_i.
Here, x_1 < x_2 < ... < x_N holds.

Initially, no candles are burning.
Snuke decides to light K of the N candles.

Now, he is at coordinate 0.
He can move left and right along the line with speed 1.
He can also light a candle when he is at the same position as the candle, in negligible time.

Find the minimum time required to light K candles.

Constraints

1 \leq N \leq 10^5

1 \leq K \leq N

x_i is an integer.

|x_i| \leq 10^8

x_1 < x_2 < ... < x_N

Input

Input is given from Standard Input in the following format:

N K
x_1 x_2 ... x_N

Output

Print the minimum time required to light K candles.

Sample Input 1

5 3
-30 -10 10 20 50

Sample Output 1

40

He should move and light candles as follows:

Move from coordinate 0 to -10.

Light the second candle from the left.

Move from coordinate -10 to 10.

Light the third candle from the left.

Move from coordinate 10 to 20.

Light the fourth candle from the left.

Sample Input 2

3 2
10 20 30

Sample Output 2

20

Sample Input 3

1 1
0

Sample Output 3

0

There may be a candle placed at coordinate 0.

Sample Input 4

8 5
-9 -7 -4 -3 1 2 3 4

Sample Output 4

10

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.*;

class Main{

    static final int DIV = 100000007;

    public static void main(String args[]){
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        int k = sc.nextInt();
        long[] ary = new long[n];
        long[] div = new long[n];
        ary[0] = sc.nextLong();
        div[0] = ary[0]>0?ary[0]:ary[0]*-1;
        for(int i = 1;i<n;i++){
            ary[i] = sc.nextLong();
            div[i] = ary[i] - ary[i-1];
        }
        long ans = DIV;
        for(int i = 0;i < n-k+1;i++){
            int sum = 0;
            for(int j = i;j<k+i-1;j++){
                sum += div[j];
            }
            if(ary[i]<0){
                sum-=ary[i];
            }else{
                sum+=ary[i];
            }
            if(sum < ans)ans = sum;
        }
        System.out.println(ans);
    }
}