Problem:
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Circle in a Rectangle

Write a program which reads a rectangle and a circle, and determines whether the circle is arranged inside the rectangle. As shown in the following figures, the upper right coordinate $(W, H)$ of the rectangle and the central coordinate $(x, y)$ and radius $r$ of the circle are given.

Input

Five integers $W$, $H$, $x$, $y$ and $r$ separated by a single space are given in a line.

Output

Print "Yes" if the circle is placed inside the rectangle, otherwise "No" in a line.

Constraints

$ -100 \leq x, y \leq 100$

$ 0 < W, H, r \leq 100$

Sample Input 1

5 4 2 2 1

Sample Output 1

Yes

Sample Input 2

5 4 2 4 1

Sample Output 2

No

Solution in JAVA (judge verdict: Time Limit Exceeded)

import java.io.*;
import java.util.*;
class Main {
    public static void main(String[] args) throws IOException {
        BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
        StringTokenizer st=new StringTokenizer(br.readLine());
        int x=Integer.parseInt(st.nextToken());
        int y=Integer.parseInt(st.nextToken());
        int w=Integer.parseInt(st.nextToken());
        int h=Integer.parseInt(st.nextToken());
        int r2=(int)Math.pow(Integer.parseInt(st.nextToken()),2);
        for(int i=0;i<=w;i++){
            if((Math.pow(x-i,2))+Math.pow(y-0,2)<r2){
                System.out.println("No");
                System.exit(0);
            }
        }for(int i=0;i<=h;i++){
            if((Math.pow(x-w,2))+Math.pow(y-i,2)<r2){
                System.out.println("No");
                System.exit(0);
            }
        }for(int i=w;i>=0;i++){
            if((Math.pow(x-i,2))+Math.pow(y-h,2)<r2){
                System.out.println("No");
                System.exit(0);
            }
        }for(int i=h;i>=0;i++){
            if((Math.pow(x-0,2))+Math.pow(y-h,2)<r2){
                System.out.println("No");
                System.exit(0);
            }
        }System.out.println("Yes");
    }
}