Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in Java7 (OpenJDK 1.7.0) (judge verdict: Wrong Answer)

import java.util.*;
class Main{
	public static void main(String[] args){
		Scanner in = new Scanner(System.in);
		double N = Double.parseDouble(in.next());
		boolean breakFlag = false;
		double h,n,w;
		h=1;
		n=1;
		w=1;
//		for (h = 1; h <= 3500; h++){
			for (n = 1; n <= 3500; n++){
				for (w = 1; w <= 3500; w++){
					if(4*n*w>N*(n+w))h=N*n*w/(4*n*w-N*(n+w));
					if(4/N==1/h+1/n+1/w){
						breakFlag = true;
					}
					if(breakFlag)break;
				}if(breakFlag)break;
			}/*if(breakFlag)break;
		}*/
		System.out.println((int)h+" "+(int)n+" "+(int)w);
	}
}