Problem:
Score : 300 points

Problem Statement

There are N slimes lining up from left to right. The colors of these slimes will be given as a string S of length N consisting of lowercase English letters. The i-th slime from the left has the color that corresponds to the i-th character of S.

Adjacent slimes with the same color will fuse into one larger slime without changing the color. If there were a slime adjacent to this group of slimes before fusion, that slime is now adjacent to the new larger slime.

Ultimately, how many slimes will be there?

Constraints

1 \leq N \leq 10^5

|S| = N

S consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

N
S

Output

Print the final number of slimes.

Sample Input 1

10
aabbbbaaca

Sample Output 1

5

Ultimately, these slimes will fuse into abaca.

Sample Input 2

5
aaaaa

Sample Output 2

1

All the slimes will fuse into one.

Sample Input 3

20
xxzaffeeeeddfkkkkllq

Sample Output 3

10

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Runtime Error)

import java.util.*;

public class Main {
    static Scanner sc;
    public static void main(String[] args) {
        sc=new Scanner(System.in);
        A();
        //B();
        //C();
        //D();
    }
    public static void A(){
        int n=sc.nextInt();
        int m=sc.nextInt();
        System.out.println((n-2*m>0)?n-2*m:0);
    }
    public static void B(){
        int n=sc.nextInt();
        int a[]=new int[n];
        for(int i=0;i<n;i++)a[i]=sc.nextInt();
        int sum=0;
        for(int i=0;i<n-1;i++)
            for(int j=i+1;j<n;j++)
                sum+=a[i]*a[j];
        System.out.println(sum);
    }
    public static void C(){
        int n=sc.nextInt();
        char []po=sc.next().toCharArray();
        char c=po[0];
        String a=""+c;
        for(int i=1;i<n;i++)
            if(c!=(c=po[i]))
                a+=c;
        System.out.println(a.length());
    }
    public static void D(){
        int n=sc.nextInt();
        int []a=new int[n];
        for(int i=0;i<n;i++)
            a[i]=sc.nextInt();
        Arrays.sort(a);
        long ans=0;
        for(int i=0;i<n-2;i++){
            int kk=i+1;
            for(int j=i+1;j<n-1;j++){
                for(int k=(Math.max(kk,j));k<n;k++)
                    if(!(a[i]+a[j]>a[k]))
                        break;
                    else kk=k;
                ans+=kk-j;
            }
        }
        System.out.println(ans);
    }
}