Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Accepted)

import java.util.Scanner;

public class Main {
    public static void main(String args[]) {
        Scanner scn = new Scanner(System.in);
        String al = "abcdefghijklmnopqrstuvwxyz";
        String[] alp = al.split("");
        int cou[] = new int[26];

        while(scn.hasNextLine()) {
            String s ="";
            s = scn.nextLine();
            String[] str = s.split("");

            for (int i = 0; i < al.length(); i++) {
                 cou[i] += count(str, alp[i]);
            }

        }


        for (int i = 0; i < al.length(); i++) {
            System.out.printf("%s : %d%n",alp[i],cou[i]);
        }

        scn.close();


    }

    static int count(String[] S, String M) {
        int c = 0;
        for (int i = 0; i < S.length; i++) {
            if (S[i].equalsIgnoreCase(M)) {
                c += 1;
            }
        }
        return c;
    }


}