Problem:
Score : 400 points

Problem Statement

You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

In the i-th operation, you replace every element whose value is B_{i} with C_{i}.

For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

All values in input are integers.

1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}

B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:

N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}

Output

Print Q integers S_{i} to Standard Output in the following format:

S_{1}
S_{2}
\vdots
S_{Q}

Note that S_{i} may not fit into a 32-bit integer.

Sample Input 1

4
1 2 3 4
3
1 2
3 4
2 4

Sample Output 1

11
12
16

Initially, the sequence A is 1,2,3,4.

After each operation, it becomes the following:

2, 2, 3, 4

2, 2, 4, 4

4, 4, 4, 4

Sample Input 2

4
1 1 1 1
3
1 2
2 1
3 5

Sample Output 2

8
4
4

Note that the sequence A may not contain an element whose value is B_{i}.

Sample Input 3

2
1 2
3
1 100
2 100
100 1000

Sample Output 3

102
200
2000

Solution in Java (OpenJDK 11.0.6) (judge verdict: Wrong Answer)

import java.util.*;


public class Main {
  public static void main(String[] args) {
    Scanner scanner = new Scanner(System.in);

    int N = scanner.nextInt();
    int[] p = new int[100001];
    int[] a = new int[N]; 
    for (int i=0; i<N; i++){
      a[i] = scanner.nextInt();
      p[a[i]] += 1;
    }
    int Q = scanner.nextInt();
    int[] b = new int[Q];
    int[] c = new int[Q];
    for(int i=0; i<Q; i++){
      b[i] = scanner.nextInt();
      c[i] = scanner.nextInt();
    }

    long sum = 0;
    for(int j=0; j<N; j++){
      sum += a[j];
    }    
    for(int i =0; i< Q; i++){
      sum = sum - b[i]*p[b[i]] + c[i]*p[b[i]];
      p[c[i]] += p[b[i]];
      p[b[i]] = 0;
      
      System.out.println(sum);
    }
    scanner.close();
    return;
  }
}