Problem:
Score : 100 points

Problem Statement

You are given three strings A, B and C. Check whether they form a word chain.

More formally, determine whether both of the following are true:

The last character in A and the initial character in B are the same.

The last character in B and the initial character in C are the same.

If both are true, print YES. Otherwise, print NO.

Constraints

A, B and C are all composed of lowercase English letters (a - z).

1 ≤ |A|, |B|, |C| ≤ 10, where |A|, |B| and |C| are the lengths of A, B and C, respectively.

Input

Input is given from Standard Input in the following format:

A B C

Output

Print YES or NO.

Sample Input 1

rng gorilla apple

Sample Output 1

YES

They form a word chain.

Sample Input 2

yakiniku unagi sushi

Sample Output 2

NO

A and B form a word chain, but B and C do not.

Sample Input 3

a a a

Sample Output 3

YES

Sample Input 4

aaaaaaaaab aaaaaaaaaa aaaaaaaaab

Sample Output 4

NO

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.io.*;
import java.util.*;
public class Main {
	public static void main(String[] args){
		Scanner sc = new Scanner(System.in);
 
     String[] nyu=sc.nextLine().split(" ");

String[] nyuA=nyu[0].split("");
String[] nyuB=nyu[1].split("");
String[] nyuC=nyu[2].split("");

//     String nyu=sc.nextLine();
//int A=Integer.parseInt(nyu[0]);
//int B=Integer.parseInt(nyu[1]);
//int C=Integer.parseInt(nyu[2]);
//int D=Integer.parseInt(nyu);



//StringBuffer sb = new StringBuffer(nyu);
//		String dst = sb.reverse().toString();

//     String nyu2=sc.nextLine();
//int E=Integer.parseInt(nyu2);



//double A=Double.parseDouble(nyu[0]);
//double B=Double.parseDouble(nyu[1]);
/*
switch(C){
case 7:
case 5:
case 3:
System.out.println("YES") ;
break;
default:
System.out.println("NO") ;

break;
}
*/

//int res=Math.min((A*B),C);

//for(String tem:nyu){
//if(tem.equals("1"))res++;
//}
//int res=0;
//for(int i=0;i<300;i++){
//if(num[i]==1)res=i;
//}

//char[] c = nyu.toCharArray();


//System.out.println(nyu+"-"+line_r_2+"-"+nyu2+"-"+line_r_1);



if(nyuA[nyuA.length-1].equals(nyuB[0]) && nyuB[nyuB.length-1].equals(nyuC[0])){
//double res=Math.ceil((AB)/2);

System.out.println("YES");
//}else if((C-B)<A){
//System.out.println("safe");

}else{
System.out.println("NO");

}




	}
}