Problem:
Score: 100 points

Problem Statement

In AtCoder Kingdom, Gregorian calendar is used, and dates are written in the "year-month-day" order, or the "month-day" order without the year.

For example, May 3, 2018 is written as 2018-5-3, or 5-3 without the year.

In this country, a date is called Takahashi when the month and the day are equal as numbers. For example, 5-5 is Takahashi.

How many days from 2018-1-1 through 2018-a-b are Takahashi?

Constraints

a is an integer between 1 and 12 (inclusive).

b is an integer between 1 and 31 (inclusive).

2018-a-b is a valid date in Gregorian calendar.

Input

Input is given from Standard Input in the following format:

a b

Output

Print the number of days from 2018-1-1 through 2018-a-b that are Takahashi.

Sample Input 1

5 5

Sample Output 1

5

There are five days that are Takahashi: 1-1, 2-2, 3-3, 4-4 and 5-5.

Sample Input 2

2 1

Sample Output 2

1

There is only one day that is Takahashi: 1-1.

Sample Input 3

11 30

Sample Output 3

11

There are eleven days that are Takahashi: 1-1, 2-2, 3-3, 4-4, 5-5, 6-6, 7-7, 8-8, 9-9, 10-10 and 11-11.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.Collections;
import java.util.List;

public class Main {

	private static Scanner sc;

	public static void main(String[] args) {
		Main instance = new Main();
		sc = instance.new Scanner();
		instance.solve();
	}

	private void solve() {
		try {
			int a = sc.nextInt();
			int b = sc.nextInt();

			if (a < b) {
				System.out.println(a-1);
			} else {
				System.out.println(a);
			}
		} catch (Exception e) {
			e.printStackTrace();
		}
	}

	private class Scanner {
		String[] s;
		int i;
		BufferedReader br;
		String regex = " ";

		public Scanner() {
			s = new String[0];
			i = 0;
			br = new BufferedReader(new InputStreamReader(System.in));
		}

		@Override
		protected void finalize() throws Throwable {
			try {
				super.finalize();
			} finally {
				destruction();
			}
		}

		private void destruction() throws IOException {
			if (br != null)
				br.close();
		}

		public String next() throws IOException {
			if (i < s.length)
				return s[i++];
			String st = br.readLine();
			while (st == "")
				st = br.readLine();
			s = st.split(regex, 0);
			i = 0;
			return s[i++];
		}

		public int nextInt() throws NumberFormatException, IOException {
			return Integer.parseInt(next());
		}

		public Long nextLong() throws NumberFormatException, IOException {
			return Long.parseLong(next());
		}

		public Double nextDouble() throws NumberFormatException, IOException {
			return Double.parseDouble(next());
		}
	}
}