Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Scanner;

public class Main {

  public static void main(String[] args) {
    Scanner scanner = new Scanner(System.in);
    int N = scanner.nextInt();
    int nfound = 0;

    for (int i = 1; i <= N; i++) {
      if (i % 2 == 0) {
        continue;
      }
      int n = 0;
      for (int j = 1; j <= i; j++) {
        if (j % 2 == 0) {
          continue;
        }
        if (i % j == 0) {
          n++;
        }
      }
      if (n == 8) {
        nfound++;
      }
    }
    System.out.println(nfound);
  }
}