Problem:
Score : 200 points

Problem Statement

There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is R, and a blue hat if s_i is B.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

1 \leq N \leq 100

|s| = N

s_i is R or B.

Input

Input is given from Standard Input in the following format:

N
s

Output

If there are more people wearing a red hat than there are people wearing a blue hat, print Yes; otherwise, print No.

Sample Input 1

4
RRBR

Sample Output 1

Yes

There are three people wearing a red hat, and one person wearing a blue hat.

Since there are more people wearing a red hat than people wearing a blue hat, the answer is Yes.

Sample Input 2

4
BRBR

Sample Output 2

No

There are two people wearing a red hat, and two people wearing a blue hat.

Since there are as many people wearing a red hat as people wearing a blue hat, the answer is No.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Runtime Error)

import java.util.Scanner;
public class Main {
public static void main(String[]args) {
	Scanner t = new Scanner (System.in);
	int num,cont = 0, cont1=0;
	num =t.nextInt();
	String v[] = new String[num];
	for(int i = 0; i<v.length;i++) {
		v[i]= t.next();
	
	if(v[i].charAt(i)=='R'){
		cont++;
	}else if(v[i].charAt(i)=='B') {
		
		cont1++;
	}
		if(cont>cont1) {
			System.out.println("Yes");
		}else {
			System.out.println("No");
		}
	}
}
}