Problem:
Score : 100 points

Problem Statement

There are two buttons, one of size A and one of size B.

When you press a button of size X, you get X coins and the size of that button decreases by 1.

You will press a button twice. Here, you can press the same button twice, or press both buttons once.

At most how many coins can you get?

Constraints

All values in input are integers.

3 \leq A, B \leq 20

Input

Input is given from Standard Input in the following format:

A B

Output

Print the maximum number of coins you can get.

Sample Input 1

5 3

Sample Output 1

9

You can get 5 + 4 = 9 coins by pressing the button of size 5 twice, and this is the maximum result.

Sample Input 2

3 4

Sample Output 2

7

Sample Input 3

6 6

Sample Output 3

12

Solution in Java7 (OpenJDK 1.7.0) (judge verdict: Accepted)

import java.util.*;

public class Main {
    public static void main(String[] args) throws Exception {
        int A;
        int B;
        int total = 0;
        
        Scanner scanner = new Scanner(System.in);
        A = scanner.nextInt();
        B = scanner.nextInt();
        //System.out.println(A + "" + B);
        
        for(int i = 0; i < 2; i++){
            if(A >= B){
                total += A;
                A--;
            }else{
                total += B;
                B--;
            }
        }
        System.out.println(total);
        
    }
}