Problem:
Score : 600 points

Problem Statement

Takahashi has N balls with positive integers written on them. The integer written on the i-th ball is A_i.
He would like to form some number of pairs such that the sum of the integers written on each pair of balls is a power of 2.
Note that a ball cannot belong to multiple pairs.
Find the maximum possible number of pairs that can be formed.

Here, a positive integer is said to be a power of 2 when it can be written as 2^t using some non-negative integer t.

Constraints

1 \leq N \leq 2\times 10^5

1 \leq A_i \leq 10^9

A_i is an integer.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

Print the maximum possible number of pairs such that the sum of the integers written on each pair of balls is a power of 2.

Sample Input 1

3
1 2 3

Sample Output 1

1

We can form one pair whose sum of the written numbers is 4 by pairing the first and third balls.
Note that we cannot pair the second ball with itself.

Sample Input 2

5
3 11 14 5 13

Sample Output 2

2

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Time Limit Exceeded)



import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.UncheckedIOException;
import java.util.ArrayList;
import java.util.Collections;
import java.util.StringTokenizer;

class Main{
	public static void main(String[] args) {
		SC sc=new SC(System.in);
		ArrayList<Integer> unko=new ArrayList<Integer>();
		int N=sc.nextInt();
		for(int i=0; i<N; i++) {
			unko.add(sc.nextInt());
		}
		Collections.sort(unko);
		int kosu=0;
		while(true){
			//System.out.println(unko.toString());
			int a=unko.get(unko.size()-1);
			unko.remove(unko.size()-1);
			int max=unko(a);
			int hosu=max-a;
			int ban=Collections.binarySearch(unko, hosu);
			if(ban>=0) {
					kosu++;
					unko.remove(ban);
			}
			if(unko.size()==0) {
				break;
			}
		}
		System.out.println(kosu);
	}
	static class SC {
		private BufferedReader reader = null;
		private StringTokenizer tokenizer = null;
		public SC(InputStream in) {
			reader = new BufferedReader(new InputStreamReader(in));
		}
		public String next() {
			if (tokenizer == null || !tokenizer.hasMoreTokens()) {
				try {
					tokenizer = new StringTokenizer(reader.readLine());
				} catch (IOException e) {
					throw new UncheckedIOException(e);
				}
			}
			return tokenizer.nextToken();
		}
		public int nextInt() {
			return Integer.parseInt(next());
		}
		public long nextLong() {
			return Long.parseLong(next());
		}
	}
	static int unko(int a) {
		int k=0;
		int b=a;
		while(b>0) {
			k++;
			b/=2;
		}
		int aaa=1;
		for(int i=0; i<k; i++) {
			aaa*=2;
		}
		return aaa;
	}
}