Problem:
Sale Result

There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.

Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:

n (the number of data in the list)
i p q
i p q
:
:
i p q

Output

For each dataset, print a list of employee IDs or a text "NA"

Sample Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0

Output for the Sample Input

1001
1003
NA
2013

Solution in JAVA (judge verdict: Accepted)

import java.io.*;

public class Main{
	public static void main(String args[]) throws IOException{
		InputStreamReader is = new InputStreamReader(System.in); 
		BufferedReader br = new BufferedReader(is);

		String[][] eArray = new String[2][4000];
		int i;
		int j = 0;
		int k;
		boolean flg = false;

		for(i = 0; i < 4000; i++) eArray[1][i] = "0";

		int in = Integer.parseInt(br.readLine());

		while(in != 0){
			for(i = 0; i < in; i++){

				String str = br.readLine();

				int sp1 = str.indexOf(" ");
				int sp2 = str.lastIndexOf(" ");

				String e = str.substring(0, sp1);
				int p = Integer.parseInt(str.substring(sp1 + 1, sp2));
				int q = Integer.parseInt(str.substring(sp2 + 1, str.length()));

				for(k = 0; k < j; k++){
					if(eArray[0][k].equals(e)){
						eArray[1][k] = String.valueOf(Integer.parseInt(eArray[1][k]) + p * q);
					}
				}
				if(k == j){
					eArray[0][j] = e;
					eArray[1][j] = String.valueOf(p * q);
					j++;
				}
			}
			for(i = 0; i < j; i++){
				if(Integer.parseInt(eArray[1][i]) >= 1000000){
					System.out.println(eArray[0][i]);
					flg = true;
				}
				eArray[0][i] = "";
				eArray[1][i] = "0";
			}
			if(flg == false) System.out.println("NA");
			flg = false;
			in = Integer.parseInt(br.readLine());
		}
	}
}