Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Wrong Answer)


import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class Main {

    public static void main(String[] args) {
        BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
        try {
//            char[] alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ".toCharArray();
            char[] alphabet = new char[26];
            char word = 'A';
            for (int x = 0; x <= ('z') - ('a'); x++) {
                alphabet[x] = word++; 
            }
            
            int[] sum = new int[26];
            String line = reader.readLine();
            char[] chaAryLine = line.toLowerCase().toCharArray();

            for (int i = 0; i < line.length(); i++) {
                for (int j = 0; j < 26; j++) {
                    if (alphabet[j] == chaAryLine[i]) {
                        sum[j]++;
                        break;
                    }
                }
            }
            for (int i = 0; i < 26; i++) {
                System.out.println(alphabet[i] + " : " + sum[i]);
            }
        } catch (IOException e) {
            System.out.println(e);
        }
    }
}