Problem:
Score : 200 points

Problem Statement

You are given string S and T consisting of lowercase English letters.

Determine if S equals T after rotation.

That is, determine if S equals T after the following operation is performed some number of times:

Operation: Let S = S_1 S_2 ... S_{|S|}. Change S to S_{|S|} S_1 S_2 ... S_{|S|-1}.

Here, |X| denotes the length of the string X.

Constraints

2 \leq |S| \leq 100

|S| = |T|

S and T consist of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S equals T after rotation, print Yes; if it does not, print No.

Sample Input 1

kyoto
tokyo

Sample Output 1

Yes

In the first operation, kyoto becomes okyot.

In the second operation, okyot becomes tokyo.

Sample Input 2

abc
arc

Sample Output 2

No

abc does not equal arc after any number of operations.

Sample Input 3

aaaaaaaaaaaaaaab
aaaaaaaaaaaaaaab

Sample Output 3

Yes

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)



import java.util.Scanner;

public class Main {

    static Scanner sc = new Scanner(System.in);


    public static void main(String[] args) {
        String a = sc.next();
        String b = sc.next();
        if (a.equals(b)) {
            System.out.println("Yes");
            return;
        }
        char[] charA = a.toCharArray();
        for (int j = 0; j < charA.length; j++) {
            char temp = charA[0];
            for (int i = 0; i < charA.length - 1; i++) {
                charA[i] = charA[i + 1];
            }
            charA[charA.length - 1] = temp;
            if (b.equals(String.valueOf(charA))) {
                System.out.println("Yes");
                return;
            }
        }
        System.out.println("No");
    }
}