Problem:
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Matrix Multiplication

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\[
c_{ij} = \sum_{k=1}^m a_{ik}b_{kj}
\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Constraints

$1 \leq n, m, l \leq 100$

$0 \leq a_{ij}, b_{ij} \leq 10000$

Sample Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2

Sample Output

1 8 5
0 9 6
4 23 14

Note

      解説

Solution in JAVA (judge verdict: Wrong Answer)

import java.util.Scanner;

public class Main {
  public static void main(String[] args) {
    Scanner sc = new Scanner(System.in);
    int n = sc.nextInt();
    int m = sc.nextInt();
    int l = sc.nextInt();
    int[][] A = new int[n][m];
    int[][] B = new int[m][l];
    int[][] ans = new int[n][l];

    for (int i = 0; i < n; i++)
      for (int j = 0; j < m; j++)
        A[i][j] = sc.nextInt();

    for (int i = 0; i < m; i++)
      for (int j = 0; j < l; j++)
        B[i][j] = sc.nextInt();

    for (int i = 0; i < n; i++) {
      for (int j = 0; j < l; j++) {
        for (int k = 0; k < m; k++) {
          ans[i][j] += A[i][k] * B[k][j];
        }
        System.out.print(ans[i][j]);
        if (j != l - 1)
          System.out.print(" ");
      }
      System.out.println();
    }
  }
}