Problem:
Hit and Blow

Let's play Hit and Blow game. A imagines four numbers and B guesses the numbers. After B picks out four numbers, A answers:

The number of numbers which have the same place with numbers A imagined (Hit)

The number of numbers included (but different place) in the numbers A imagined (Blow)

For example, if A imagined numbers:

9 1 8 2

and B chose:

4 1 5 9

A should say 1 Hit and 1 Blow.

Write a program which reads four numbers A imagined and four numbers B chose and prints the number of Hit and Blow respectively. You may assume that the four numbers are all different and within from 0 to 9.

Input

The input consists of multiple datasets. Each dataset set consists of:

a1 a2 a3 a4
b1 b2 b3 b4

, where ai (0 ≤ ai ≤ 9) is i-th number A imagined and bi (0 ≤ bi ≤ 9) is i-th number B chose.

The input ends with EOF. The number of datasets is less than or equal to 50.

Output

For each dataset, print the number of Hit and Blow in a line. These two numbers should be separated by a space.

Sample Input

9 1 8 2
4 1 5 9
4 6 8 2
4 6 3 2

Output for the Sample Input

1 1
3 0

Solution in JAVA (judge verdict: Wrong Answer)

import java.util.ArrayList;
import java.util.Scanner;

public class Main {
	static ArrayList<Integer> tgt = new ArrayList<Integer>();
	static ArrayList<Integer> ans = new ArrayList<Integer>();
	static Scanner sc = new Scanner(System.in);
	public static void main(String[] args) {

		while(sc.hasNext()) {
			hit_and_blow();
		}
    }


	private static void hit_and_blow() {
		int h = 0;
		int b = 0;

		for (int i = 0; i < 4; i++) {
			tgt.add( sc.nextInt() );
		}

		for (int i = 0; i < 4; i++) {
			ans.add( sc.nextInt() );
		}

		for (int i = 0; i < 4; i++) {
			if ( ans.get(i) == tgt.get(i) ) {
				h++;
			} else if ( tgt.contains(ans.get(i)) ){
				b++;
			}
		}

		System.out.printf("%d %d", h, b);
	}

}