Problem:
Score : 100 points

Problem Statement

You are given four digits N_1, N_2, N_3 and N_4. Determine if these can be arranged into the sequence of digits "1974".

Constraints

0 \leq N_1, N_2, N_3, N_4 \leq 9

N_1, N_2, N_3 and N_4 are integers.

Input

Input is given from Standard Input in the following format:

N_1 N_2 N_3 N_4

Output

If N_1, N_2, N_3 and N_4 can be arranged into the sequence of digits "1974", print YES; if they cannot, print NO.

Sample Input 1

1 7 9 4

Sample Output 1

YES

We can get 1974 by swapping N_2 and N_3.

Sample Input 2

1 9 7 4

Sample Output 2

YES

We already have 1974 before doing anything.

Sample Input 3

1 2 9 1

Sample Output 3

NO

Sample Input 4

4 9 0 8

Sample Output 4

NO

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.io.*;
import java.util.*;
import java.math.*;
// import java.awt.Point;

public class Main {
    public Main(){
        Scanner sc=new Scanner(System.in);
        int N[]=new int[4];
        for(int i=0;i<4;i++){
            N[i]=sc.nextInt();
        }
        int[] ans=new int[]{1,7,9,4};
        boolean[] frag=new boolean[]{false,false,false,false};
        loop1:
        for(int i=0;i<4;i++){
            for(int j=0;j<4;j++){
                if(ans[i]==N[j]){
                    continue loop1;
                }
            }
            System.out.println("NO");
            return;
        }
        System.out.println("YES");
    }
    public static void main(String[] args){
        Main main=new Main();
    }

}