Problem:
Score : 300 points

Problem Statement

1000000000000001 dogs suddenly appeared under the roof of Roger's house, all of which he decided to keep. The dogs had been numbered 1 through 1000000000000001, but he gave them new names, as follows:

the dogs numbered 1,2,\cdots,26 were respectively given the names a, b, ..., z;

the dogs numbered 27,28,29,\cdots,701,702 were respectively given the names aa, ab, ac, ..., zy, zz;

the dogs numbered 703,704,705,\cdots,18277,18278 were respectively given the names aaa, aab, aac, ..., zzy, zzz;

the dogs numbered 18279,18280,18281,\cdots,475253,475254 were respectively given the names aaaa, aaab, aaac, ..., zzzy, zzzz;

the dogs numbered 475255,475256,\cdots were respectively given the names aaaaa, aaaab, ...;

and so on.

To sum it up, the dogs numbered 1, 2, \cdots were respectively given the following names:

a, b, ..., z, aa, ab, ..., az, ba, bb, ..., bz, ..., za, zb, ..., zz, aaa, aab, ..., aaz, aba, abb, ..., abz, ..., zzz, aaaa, ...

Now, Roger asks you:

"What is the name for the dog numbered N?"

Constraints

N is an integer.

1 \leq N \leq 1000000000000001

Input

Input is given from Standard Input in the following format:

N

Output

Print the answer to Roger's question as a string consisting of lowercase English letters.

Sample Input 1

2

Sample Output 1

b

Sample Input 2

27

Sample Output 2

aa

Sample Input 3

123456789

Sample Output 3

jjddja

Solution in Java (OpenJDK 11.0.6) (judge verdict: Wrong Answer)

import java.util.*;

public class Main {
  public static void main(String args[]) {
    Scanner sc = new Scanner(System.in);
    long N = sc.nextLong();
    int A[] = new int[11];
    String name ="";
    int firstIndexAlpha = (int)'a'; // アルファベットの最初の文字
    int sizeAlpha = 26;
    A[0] = (int)(N / Long.valueOf("141167095653376"));
    N = (long)(N % Long.valueOf("141167095653376"));
    A[1] = (int)(N / Long.valueOf("5429503678976"));
    N = (long)(N % Long.valueOf("5429503678976"));//2147483648
    A[2] = (int)(N / Long.valueOf("208827064576"));
    N = (long)(N % Long.valueOf("208827064576"));
    A[3] = (int)(N / Long.valueOf("8031810176"));
    N = (long)(N % Long.valueOf("8031810176"));
    A[4] = (int)(N /308915776);
    N = N %308915776;
    A[5] = (int)N / 11881376;
    N = N % 11881376;
    A[6] = (int)N /456976;
    N = N %456976;
    A[7] = (int)N /17576;
    N = N %17576;
    A[8] = (int)N /676;
    N = N %676;
    A[9] = (int)N /26;
    A[10] = (int)N %26;
    
    for(int a:A) {
      if(a!=0) {
      	name += String.valueOf((char)(firstIndexAlpha + a - 1));
      }
    }
    System.out.println(name);
  }
}