Problem:
Score : 300 points

Problem Statement

Given are an integer X and an integer sequence of length N: p_1, \ldots, p_N.

Among the integers not contained in the sequence p_1, \ldots, p_N (not necessarily positive), find the integer nearest to X, that is, find the integer whose absolute difference with X is the minimum. If there are multiple such integers, report the smallest such integer.

Constraints

1 \leq X \leq 100

0 \leq N \leq 100

1 \leq p_i \leq 100

p_1, \ldots, p_N are all distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X N
p_1 ... p_N

Output

Print the answer.

Sample Input 1

6 5
4 7 10 6 5

Sample Output 1

8

Among the integers not contained in the sequence 4, 7, 10, 6, 5, the one nearest to 6 is 8.

Sample Input 2

10 5
4 7 10 6 5

Sample Output 2

9

Among the integers not contained in the sequence 4, 7, 10, 6, 5, the ones nearest to 10 are 9 and 11. We should print the smaller one, 9.

Sample Input 3

100 0

Sample Output 3

100

When N = 0, the second line in the input will be empty. Also, as seen here, X itself can be the answer.

Solution in Java (OpenJDK 11.0.6) (judge verdict: Wrong Answer)

import java.util.Scanner;

public class Main {

  public static void main(String[] args) {
    Scanner sc = new Scanner(System.in);
    int x = sc.nextInt();
    int n = sc.nextInt();
    int[] array = new int[102];
    for(int i = 0; i < n; i++){
      array[sc.nextInt()]++;
    }
    int distance = 0;
    while((x + distance) <= 100){
      if(x - distance == 0){
        System.out.println(x - distance);
        return;
      }
      if(x + distance == 101){
        System.out.println(x + distance);
        return;
      }
      if(array[x - distance] == 0){
        System.out.println(x - distance);
        return;
      } else if(array[x + distance] == 0){
        System.out.println(x + distance);
        return;
      }
      distance++;
    }
    //System.out.println(Math.abs(x + 1) > Math.abs(101 - x) ? 101 : 0);
  }
}