Problem:
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Circles Intersection

You are given circle $A$ with radius $r_a$ and with central coordinate $(x_a, y_a)$ and circle $B$ with radius $r_b$ and with central coordinate $(x_b, y_b)$.

Write a program which prints:

"2" if $B$ is in $A$,

"-2" if $A$ is in $B$,

"1" if circumference of $A$ and $B$ intersect, and

"0" if $A$ and $B$ do not overlap.

You may assume that $A$ and $B$ are not identical.

Input

The input consists of multiple datasets. The first line consists of an integer $N$ ($N \leq 50$), the number of datasets. There will be $N$ lines where each line represents each dataset. Each data set consists of real numbers:

$x_a$ $y_a$ $r_a$ $x_b$ $y_b$ $r_b$

Output

For each dataset, print 2, -2, 1, or 0 in a line.

Sample Input

2
0.0 0.0 5.0 0.0 0.0 4.0
0.0 0.0 2.0 4.1 0.0 2.0

Output for the Sample Input

2
0

Solution in JAVA (judge verdict: Wrong Answer)

import java.util.*;
import java.lang.*;
import java.math.*;

public class Main {
	Scanner sc = new Scanner(System.in);
	class Cir{
		Double x;
		Double y;
		Double r;
		Cir(Double x, Double y , Double r){
			this.x = x;
			this.y = y;
			this.r = r;
		}
		Cir(){}
		Double dist2(Cir c){
			Double ret = (this.x -c.x)* (this.x -c.x) + (this.y -c.y) * (this.y -c.y);
			return ret;
		}
		
	}
	void run(){
		int n = sc.nextInt();
		for(int i = 0; i < n ; i ++){
			Cir a = new Cir(sc.nextDouble(),sc.nextDouble(),sc.nextDouble());
			Cir b = new Cir(sc.nextDouble(),sc.nextDouble(),sc.nextDouble());
			Double dist  = Math.sqrt(a.dist2(b));
			if(dist+b.r < a.r ){
				System.out.println("2");
				continue;
			}
			if(dist+a.r < b.r ){
				System.out.println("-2");
				continue;
			}
			if(dist >= b.r + a.r ){
				System.out.println("0");
				continue;
			}
			System.out.println("1");			
		}
	}
	public static void main(String[] args){
		Main m = new Main();
		m.run();
		
	}
}