Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Accepted)

import java.io.*;
import java.util.*;
public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
//        PrintWriter pw = new PrintWriter(System.out);
//        sc.useDelimiter("\n");
        int[] atozArray = new int[26];
        int ans;
        char atoz;
        while (sc.hasNext()) {
            String str = sc.nextLine().toLowerCase();
            for (int i = 97; i <= 122; i++) {
                atozArray[i-97] += strCount(str, i);
            }
        }
        for (int i = 97; i <= 122; i++) {
            atoz = (char) i;
            System.out.println(atoz + " : " + atozArray[i-97]);
        }
//        pw.flush();
    }
    
    public static int strCount(String str, int ch) {
        int count = 0;
        for (char c : str.toCharArray()) {
            if (c == ch) count++;
        }
        return count;
    }
}