Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.*;

public class Main {
    static Scanner scanner = new Scanner(System.in);

    public static void main(String[]$) {
        int n = scanner.nextInt();
        int a = scanner.nextInt() - 1;
        int b = scanner.nextInt() - 1;
        int c = scanner.nextInt() - 1;
        int d = scanner.nextInt() - 1;
        String s = scanner.next();

        System.out.println(f(n, a, b, c, d, s) ? "Yes" : "No");
    }

    static boolean f(int n, int a, int b, int c, int d, String s) {
        boolean before = false;
        for (char ch : s.substring(a, c).toCharArray()) {
            if (before && ch == '#') {
                return false;
            }
            before = ch == '#';
        }
        before = false;
        for (char ch : s.substring(b, d).toCharArray()) {
            if (before && ch == '#') {
                return false;
            }
            before = ch == '#';
        }

        if (c > d) {
            String t = s.substring(a, c + 1);
            int count = 0;
            for (int i = 0; i < t.length(); i++) {
                if (t.charAt(i) == '.') {
                    count++;
                } else {
                    if (count >= 3) {
                        return true;
                    }
                    count = 0;
                }
            }
            return false;
        }
        return true;
    }
}