Problem:
Score : 200 points

Problem Statement

Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Constraints

1 \leq N \leq 10^5

Input

Input is given from Standard Input in the following format:

N

Output

Print the number of positive integers less than or equal to N that have an odd number of digits.

Sample Input 1

11

Sample Output 1

9

Among the positive integers less than or equal to 11, nine integers have an odd number of digits: 1, 2, \ldots, 9.

Sample Input 2

136

Sample Output 2

46

In addition to 1, 2, \ldots, 9, another 37 integers also have an odd number of digits: 100, 101, \ldots, 136.

Sample Input 3

100000

Sample Output 3

90909

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Scanner;

public class Main {
	public static void main(String[] args) {

		Scanner scan = new Scanner(System.in);

		int N = scan.nextInt();
		int answer = 0;
		
		if (N == 100000) {
			answer = 9 + 900 + 90000;
		} else if (N <= 99999 && N >= 10000) {
			answer = 9 + 900 + (N - 9999);
		} else if (N <= 9999 && N >= 1000) {
			answer = 9 + 900;
		} else if (N <= 999 && N >= 100) {
			answer = 9 + (N - 99);
		} else if (N <= 99 && N >= 10) {
			answer = 9;
		} else {
			answer = N;
		}

		System.out.println(answer);
	}
}