Problem:
Score : 400 points

Problem Statement

You are given N integers; the i-th of them is A_i.
Find the maximum possible sum of the absolute differences between the adjacent elements after arranging these integers in a row in any order you like.

Constraints

2 \leq N \leq 10^5

1 \leq A_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1
:
A_N

Output

Print the maximum possible sum of the absolute differences between the adjacent elements after arranging the given integers in a row in any order you like.

Sample Input 1

5
6
8
1
2
3

Sample Output 1

21

When the integers are arranged as 3,8,1,6,2, the sum of the absolute differences between the adjacent elements is |3 - 8| + |8 - 1| + |1 - 6| + |6 - 2| = 21. This is the maximum possible sum.

Sample Input 2

6
3
1
4
1
5
9

Sample Output 2

25

Sample Input 3

3
5
5
1

Sample Output 3

8

Solution in Java (OpenJDK 11.0.6) (judge verdict: Wrong Answer)

import java.util.*;

class Main {
  public static void main(String[] args) {
    Scanner in = new Scanner(System.in);

    int N = in.nextInt();
    int[] nums = new int[N];

    for (int i = 0; i < N; i++) {
      nums[i] = in.nextInt();
    }

    Arrays.sort(nums);

    int[] arr = new int[N];
    int minIndex = 0;
    int maxIndex = N - 1;

    int index = N / 2;
    int maxIndex1 = index - 1;
    int maxIndex2 = index + 1;
    int minIndex1 = index - 2;
    int minIndex2 = index + 2;

    arr[index] = nums[minIndex];
    minIndex++;

    while (
      0 <= maxIndex1 ||
      0 <= minIndex1 ||
      maxIndex2 < N ||
      minIndex2 < N) {
        if (0 <= maxIndex1) {
          arr[maxIndex1] = nums[maxIndex];
          maxIndex--;
          maxIndex1 -= 2;
        }
        if (maxIndex2 < N) {
          arr[maxIndex2] = nums[maxIndex];
          maxIndex--;
          maxIndex2 += 2;
        }
        if (0 <= minIndex1) {
          arr[minIndex1] = nums[minIndex];
          minIndex++;
          minIndex1 -= 2;
        }
        if (minIndex2 < N) {
          arr[minIndex2] = nums[minIndex];
          minIndex++;
          minIndex2 += 2;
        }
      }

    long ans1 = 0;

    for (int i = 1; i < N; i++) {
      ans1 += Math.abs(arr[i] - arr[i - 1]);
    }

    minIndex = 0;
    maxIndex = N - 1;

    index = N / 2;
    maxIndex1 = index - 1;
    maxIndex2 = index + 1;
    minIndex1 = index - 2;
    minIndex2 = index + 2;

    arr[index] = nums[maxIndex];
    maxIndex--;

    while (
      0 <= maxIndex1 ||
      0 <= minIndex1 ||
      maxIndex2 < N ||
      minIndex2 < N) {
        if (0 <= maxIndex1) {
          arr[maxIndex1] = nums[maxIndex];
          maxIndex--;
          maxIndex1 -= 2;
        }
        if (maxIndex2 < N) {
          arr[maxIndex2] = nums[maxIndex];
          maxIndex--;
          maxIndex2 += 2;
        }
        if (0 <= minIndex1) {
          arr[minIndex1] = nums[minIndex];
          minIndex++;
          minIndex1 -= 2;
        }
        if (minIndex2 < N) {
          arr[minIndex2] = nums[minIndex];
          minIndex++;
          minIndex2 += 2;
        }
      }

    long ans2 = 0;

    for (int i = 1; i < N; i++) {
      ans2 += Math.abs(arr[i] - arr[i - 1]);
    }

    System.out.println(Math.max(ans1, ans2));
  }
}