Problem:
Score : 400 points

Problem Statement

You are given N integers; the i-th of them is A_i.
Find the maximum possible sum of the absolute differences between the adjacent elements after arranging these integers in a row in any order you like.

Constraints

2 \leq N \leq 10^5

1 \leq A_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1
:
A_N

Output

Print the maximum possible sum of the absolute differences between the adjacent elements after arranging the given integers in a row in any order you like.

Sample Input 1

5
6
8
1
2
3

Sample Output 1

21

When the integers are arranged as 3,8,1,6,2, the sum of the absolute differences between the adjacent elements is |3 - 8| + |8 - 1| + |1 - 6| + |6 - 2| = 21. This is the maximum possible sum.

Sample Input 2

6
3
1
4
1
5
9

Sample Output 2

25

Sample Input 3

3
5
5
1

Sample Output 3

8

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)


import java.util.Arrays;
import java.util.Scanner;

public class Main{

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        Integer[] a = new Integer[n];
        for (int i = 0; i < n; i++) {
            a[i] = sc.nextInt();
        }
        Arrays.sort(a);
        Integer[] c = new Integer[n];
        for (int i = 0; i < n; i++) {
            c[i] = a[n - 1 - i];
        }

        long ans = 0;
        int l = a[0];
        int r = a[n - 1];
        ans += r - l;
        int aa = 1;
        int cc = 1;
        for (int i = 1; i < n - 1; i++) {

            if (i % 2 == 1) {
                int b = a[aa];
                if (Math.abs(l - b) > Math.abs(r - b)) {
                    ans += Math.abs(l - b);
                    l = b;
                } else {
                    ans += Math.abs(r - b);
                    r = b;
                }
                aa++;
            } else {
                int b = c[cc];
                if (Math.abs(l - b) > Math.abs(r - b)) {
                    ans += Math.abs(l - b);
                    l = b;
                } else {
                    ans += Math.abs(r - b);
                    r = b;
                }
                cc++;
            }
        }
        System.out.println(ans);

    }

}