Problem:
Score : 100 points

Problem Statement

In programming, hexadecimal notation is often used.

In hexadecimal notation, besides the ten digits 0, 1, ..., 9, the six letters A, B, C, D, E and F are used to represent the values 10, 11, 12, 13, 14 and 15, respectively.

In this problem, you are given two letters X and Y. Each X and Y is A, B, C, D, E or F.

When X and Y are seen as hexadecimal numbers, which is larger?

Constraints

Each X and Y is A, B, C, D, E or F.

Input

Input is given from Standard Input in the following format:

X Y

Output

If X is smaller, print <; if Y is smaller, print >; if they are equal, print =.

Sample Input 1

A B

Sample Output 1

<

10 < 11.

Sample Input 2

E C

Sample Output 2

>

14 > 12.

Sample Input 3

F F

Sample Output 3

=

15 = 15.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)


import java.util.*;
public class Main {
	public static void main(String[] args){
		Scanner sc = new Scanner(System.in);
 
    // String[] nyu=sc.nextLine().split(" ");

     String nyu=sc.nextLine();
//int A=Integer.parseInt(nyu[0]);
//int B=Integer.parseInt(nyu[1]);
//int C=Integer.parseInt(nyu[2]);
//int D=Integer.parseInt(nyu[3]);


//double A=Double.parseDouble(nyu[0]);
//double B=Double.parseDouble(nyu[1]);
/*
switch(C){
case 7:
case 5:
case 3:
System.out.println("YES") ;
break;
default:
System.out.println("NO") ;

break;
}
*/

//int res=Math.min((A*B),C);

//for(String tem:nyu){
//if(tem.equals("1"))res++;
//}

char[] c = nyu.toCharArray();

if((int)c[0]<(int)c[2]){
//double res=Math.ceil((AB)/2);

System.out.println("<");
}else if((int)c[0]>(int)c[2]){
System.out.println(">");

}else{
System.out.println("=");

}




	}
}