Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Wrong Answer)

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int[] count = new int[26];
        for (int i = 0; i < 26; i++)
            count[i] = 0;


        String input = sc.nextLine();
        String lowed = input.toLowerCase();
        System.out.println(input + " " + lowed);
        for (int i = 0; i < lowed.length(); i++) {
            if (lowed.charAt(i) >= 'a' && lowed.charAt(i) <= 'z')
                count[(int)(lowed.charAt(i) - 'a')]++;
        }
        for (int i = 0; i < 26; i++)
            System.out.println((char) ('a' + i) + " : " + count[i]);
    }
}