Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Wrong Answer)

import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		// TODO Auto-generated method stub
		Scanner sc = new Scanner(System.in);
		String[] sabc = {"a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"};
		int[] nabc = new int[sabc.length];
		String str = sc.nextLine();
		String[] strArray = str.split("");
		for(int i=0; i<nabc.length; i++)nabc[i]=0;
		for (int i = 0; i < strArray.length; i++) {
			strArray[i] = strArray[i].toLowerCase();
			for(int j = 0; j < sabc.length; j++){
				if(strArray[i].equals(sabc[j])){
		    	nabc[j]++;
				}
			}
		}
		for(int j=0; j<sabc.length; j++){
			System.out.println(sabc[j] + " : " + nabc[j]);
		}
	}
}