Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Wrong Answer)

import java.util.Scanner;

public class Main {


		public static void main(String[] args){
		Scanner scan = new Scanner(System.in);
		
		int ans[] = new int[26];
		
		while(scan.hasNext()){
		//??\??????????????±?????????????????¢???????????????????????°????¨??????????
		String moji = scan.nextLine();
		
		moji = moji.toLowerCase();
		
		int moji_len = moji.length();
		
		//??\????????????????????????????????????????????????????????§
		for(int cnt_len = 0; cnt_len < moji_len; cnt_len++){
			
			char moji_one = moji.charAt(cnt_len);
			
			//????????????????????????a~Z??????????????¨?????´????????????????????????
			int num = moji_one - 'a';  // ???????????????
			if(num >= 0 && num <= 26)
				ans[num]++; 
		}
		//???????????¨???
		for(int cnt_arp = 0; cnt_arp < 26; cnt_arp++){
			
			System.out.println((char)(cnt_arp + 'a') + " : " + ans[cnt_arp]);
		}
		}
		//????§????
		scan.close();
	}
}