Problem:
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Transformation

Write a program which performs a sequence of commands to a given string $str$. The command is one of:

print a b: print from the a-th character to the b-th character of $str$

reverse a b: reverse from the a-th character to the b-th character of $str$

replace a b p: replace from the a-th character to the b-th character of $str$ with p

Note that the indices of $str$ start with 0.

Input

In the first line, a string $str$ is given. $str$ consists of lowercase letters. In the second line, the number of commands q is given. In the next q lines, each command is given in the above mentioned format.

Output

For each print command, print a string in a line.

Constraints

$1 \leq $ length of $str \leq 1000$

$1 \leq q \leq 100$

$0 \leq a \leq b < $ length of $str$

for replace command, $b - a + 1 = $ length of $p$

Sample Input 1

abcde
3
replace 1 3 xyz
reverse 0 2
print 1 4

Sample Output 1

xaze

Sample Input 2

xyz
3
print 0 2
replace 0 2 abc
print 0 2

Sample Output 2

xyz
abc

Solution in JAVA (judge verdict: Runtime Error)

import java.util.*;
 
public class Main {
	
	public static final int A = 0;
	public static final int B = 1;
	
    public static void main( String args[] ) {
        Scanner scan = new Scanner( System.in );

		String str		= scan.next();
		int	strLength	= str.length();
		int orderNum	= scan.nextInt();
		
		
		for( int i = 0; i < orderNum; i++ ) {
			int[] option	= new int[2];
			String order	= scan.next();
			int A			= scan.nextInt();
			int B			= scan.nextInt();
	
			if ( order.equals( "print" ) ) {
				str = str.substring( A, B+1 );	
				System.out.println( str );
				
			} else if ( order.equals( "reverse" ) ) {
				StringBuffer strBuf = new StringBuffer( str.substring( A, B+1 ) );
				String temp			= strBuf.reverse().toString();
				str					= str.substring( 0, A ) + temp + str.substring( B+1, strLength );
				
			} else if ( order.equals( "replace" ) ) {
				String replaceStr	= scan.next();
				str					= str.substring( 0, A ) + replaceStr + str.substring( B+1, strLength );
				
			}
			
		}

	}
	
	
	
}