Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

public class Main {
    public static void main(String[] args) {
        int count = 0;
        for(int i = 0; 2 * i + 1 <= 200; i++)
            count += checkNum(2 * i + 1);
        System.out.println(count);
    }

    public static int checkNum(int n){
        int count = 0;
        for(int i = 1; i <= n; i++) {
            if (n % i == 0)
                count++;
            if(count > 8)
                return 0;
        }
        if(count == 8)
            return 1;
        else
            return 0;
    }
}