Problem:
Score : 300 points

Problem Statement

Fennec is fighting with N monsters.

The health of the i-th monster is H_i.

Fennec can do the following two actions:

Attack: Fennec chooses one monster. That monster's health will decrease by 1.

Special Move: Fennec chooses one monster. That monster's health will become 0.

There is no way other than Attack and Special Move to decrease the monsters' health.

Fennec wins when all the monsters' healths become 0 or below.

Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.

Constraints

1 \leq N \leq 2 \times 10^5

0 \leq K \leq 2 \times 10^5

1 \leq H_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
H_1 ... H_N

Output

Print the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning.

Sample Input 1

3 1
4 1 5

Sample Output 1

5

By using Special Move on the third monster, and doing Attack four times on the first monster and once on the second monster, Fennec can win with five Attacks.

Sample Input 2

8 9
7 9 3 2 3 8 4 6

Sample Output 2

0

She can use Special Move on all the monsters.

Sample Input 3

3 0
1000000000 1000000000 1000000000

Sample Output 3

3000000000

Watch out for overflow.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.io.*;
import java.util.*;
import java.math.*;
public class Main{

    static long M=(long)1e9+7;
    
    public static void main(String[] args) {
        FastReader fs=new FastReader();
        int n=fs.nextInt();
        int k=fs.nextInt();
        long[] h=new long[n];
        for(int i=0;i<n;i++){
            h[i]=fs.nextLong();
        }
        long ans=0;
        if(k>=n){
            ans=0;
        }
        else{
            long whilk=0;
            Arrays.sort(h);
            for(int i=h.length-k-1;i>=0;i--){
                whilk+=h[i];
            }
            ans=whilk;
        }
        System.out.println(ans);
    }
    
    public static long min(long a, long mod){
        return pow(a, mod-2,mod);
    }
    public static long mul(long a,long b,long mod){
        long res=0;
        while(b!=0){
            if ((b & 1) == 1){ res = (res + a) % mod;}
            a = (a + a) % mod;
            b >>= 1;
        }
        return res;
    }
    
    public static long pow(long a, long n, long mod){
        long res=1;
        while(n != 0){
            if ((n & 1) == 1) res = mul(res, a, mod)%mod;
            a = mul(a , a, mod)%mod;
            n >>= 1;
        }
        return res;
    }
    
    public static long gcd(long a, long b){
        if(a == 0) return b;
        return b == 0 ? a: gcd(b, a % b);
    }

    static class FastReader 
    { 
        BufferedReader br; 
        StringTokenizer st; 
  
        public FastReader() 
        { 
            br = new BufferedReader(new
                     InputStreamReader(System.in)); 
        } 
  
        String next() 
        { 
            while (st == null || !st.hasMoreElements()) 
            { 
                try
                { 
                    st = new StringTokenizer(br.readLine()); 
                } 
                catch (IOException  e) 
                { 
                    e.printStackTrace(); 
                } 
            } 
            return st.nextToken(); 
        } 
  
        int nextInt() 
        { 
            return Integer.parseInt(next()); 
        } 
  
        long nextLong() 
        { 
            return Long.parseLong(next()); 
        } 
  
        double nextDouble() 
        { 
            return Double.parseDouble(next()); 
        } 
  
        String nextLine() 
        { 
            String str = ""; 
            try
            { 
                str = br.readLine(); 
            } 
            catch (IOException e) 
            { 
                e.printStackTrace(); 
            } 
            return str; 
        } 
    }
}