Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Wrong Answer)

import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;

public class Main {

    public static void main(String[] args) {
        new Main().solve();
    }

    Scanner sc = new Scanner(System.in);

    void solve() {
        String str = sc.nextLine();
        char[] strArr = str.toCharArray();
        Map<String, Integer> map = new HashMap<String, Integer>();
        for (char c = 'a'; c <= 'z'; c++) {
            map.put(String.valueOf(c), 0);
        }
        for (int i = 0; i < strArr.length; ++i) {
            if (map.containsKey(String.valueOf(Character.toLowerCase(strArr[i]))))
                map.put(String.valueOf(Character.toLowerCase(strArr[i])),
                        map.get(String.valueOf(Character.toLowerCase(strArr[i]))) + 1);
        }
        for (char c = 'a'; c <= 'z'; c++) {
            System.out.println(c + " : " +
                    map.get(String.valueOf(Character.toLowerCase(c))));
        }
    }
}