Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Java (OpenJDK 11.0.6) (judge verdict: Accepted)

import java.util.*;
import java.lang.Math;

public class Main {
  public static void main(String[] args) {
    Scanner sc = new Scanner(System.in);
    
   	int n = sc.nextInt();
    int stack;
    int count = 0;
    int count2;
    int div = 1;
    
    if(n < 105) System.out.println(0);
    else{
    	for(int i = 105;i <= n;i+=2){
          stack = i;
          div = 1;
          for(int j = 3;j <= stack;j += 2){
            count2 = 1;
          	while(stack % j == 0){
              stack /= j;
              count2++;
            }
            div *= count2;
          }
          if(div == 8) count++;
        }
      System.out.println(count);
    }

  }
}