Problem:
Range Sum Query

Write a program which manipulates a sequence A = {a1, a2, . . . , an} with the following operations:

add(i, x): add x to ai.

getSum(s, t): print the sum of as, as+1,...,at.

Note that the initial values of ai (i = 1, 2, . . . , n) are 0.

Input

n q
com1 x1 y1
com2 x2 y2
...
comq xq yq

In the first line, n (the number of elements in A) and q (the number of queries) are given. Then, q queries are given where com represents the type of queries. '0' denotes add(xi, yi) and '1' denotes getSum(xi, yi).

Output

For each getSum operation, print the sum in a line.

Constraints

1 ≤ n ≤ 100000

1 ≤ q ≤ 100000

If comi is 0, then 1 ≤ xi ≤ n, 0 ≤ yi ≤ 1000.

If comi is 1, then 1 ≤ xi ≤ n, 1 ≤ yi ≤ n.

Sample Input 1

3 5
0 1 1
0 2 2
0 3 3
1 1 2
1 2 2

Sample Output 1

3
2

Solution in JAVA (judge verdict: Accepted)

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.Arrays;

public class Main {

	public static void main(String[] args) throws IOException {
		// TODO ?????????????????????????????????????????????
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

		String[] tmpArray = br.readLine().split(" ");
		int n = Integer.parseInt(tmpArray[0]);
		int q = Integer.parseInt(tmpArray[1]);

		ArrayManager array = new ArrayManager(n);

		for(int i = 0; i < q; i++){
			tmpArray = br.readLine().split(" ");

			int x = Integer.parseInt(tmpArray[1]);
			int y = Integer.parseInt(tmpArray[2]);

			if(tmpArray[0].equals("0")){
				//array.update(x, y);
				array.add(x, y);
			}
			else {
//				int result = array.findMin(x, y);
//				System.out.println(result);
				long sum = array.getSum(x, y);
				System.out.println(sum);
			}
		}
	}

}

class ArrayManager {
	private int[] array;
	private int n;
	private final int INIT = 0;
	private int origin = 1;
	
	public ArrayManager(int n){
		this.n = n;
		array = new int[n + origin];
		
		

		Arrays.fill(array, INIT);
	}

	public void update(int index, int num){
		array[index] = num;
	}
	
	public void add(int index, int num){
		array[index] += num;
	}

	public int findMin(int s, int t){
		int min = Integer.MAX_VALUE;

		for(int i = s ; i <= t; i++){
			if(min > array[i]){
				min = array[i];
			}
		}

		return min;
	}
	
	public long getSum(int s, int t){
		long sum = 0;
		
		for(int i = s; i <= t ; i++){
			sum += array[i];
		}
		
		return sum;
	}
}