Problem:
Score : 200 points

Problem Statement

You are given a string S. Each character of S is uppercase or lowercase English letter.
Determine if S satisfies all of the following conditions:

The initial character of S is an uppercase A.

There is exactly one occurrence of C between the third character from the beginning and the second to last character (inclusive).

All letters except the A and C mentioned above are lowercase.

Constraints

4 ≤ |S| ≤ 10 (|S| is the length of the string S.)

Each character of S is uppercase or lowercase English letter.

Input

Input is given from Standard Input in the following format:

S

Output

If S satisfies all of the conditions in the problem statement, print AC; otherwise, print WA.

Sample Input 1

AtCoder

Sample Output 1

AC

The first letter is A, the third letter is C and the remaining letters are all lowercase, so all the conditions are satisfied.

Sample Input 2

ACoder

Sample Output 2

WA

The second letter should not be C.

Sample Input 3

AcycliC

Sample Output 3

WA

The last letter should not be C, either.

Sample Input 4

AtCoCo

Sample Output 4

WA

There should not be two or more occurrences of C.

Sample Input 5

Atcoder

Sample Output 5

WA

The number of C should not be zero, either.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.*;
class Main{
	public static void main(String[] argv){
		//rated();
		accepted();
	}
	static void rated(){
		Scanner sc = new Scanner(System.in);
		int rate = sc.nextInt();
		if (rate<1200){
			System.out.println("ABC");
		}else{
			if(rate<2800){
				System.out.println("ARC");
			}else{
				System.out.println("AGC");
			}
		}
	}
	static void accepted(){
		Scanner sc = new Scanner(System.in);
		String s = sc.next();
		String ans = "AC";
		/*
		*先頭がA
		*先頭から三文字目から後ろから二文字目の間にCをちょうどひとつ含む．
		*A，C以外は小文字
		*/
		if(s.charAt(0)!='A'){
			ans = "WA";
		}
		if(Character.isUpperCase(s.charAt(1))){
			ans = "WA";
		}
		
		boolean hasC = false;
		for(int i=2;i<s.length()-1;i++){
			if(Character.isUpperCase(s.charAt(i))){
				if(hasC){
					ans = "WA";
				}
				if(s.charAt(i)=='C'){
					hasC = true;
				}
			}
		}
		if(Character.isUpperCase(s.charAt(s.length()-1))||hasC==false){
			ans = "WA";
		}
		System.out.println(ans);
	}
}