Problem:
Simultaneous Equation

Write a program which solve a simultaneous equation:

ax + by = c

dx + ey = f

The program should print x and y for given a, b, c, d, e and f (-1,000 ≤ a, b, c, d, e, f ≤ 1,000). You can suppose that given equation has a unique solution.

Input

The input consists of several data sets, 1 line for each data set. In a data set, there will be a, b, c, d, e, f separated by a single space. The input terminates with EOF.

Output

For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.

Sample Input 1

1 2 3 4 5 6
2 -1 -2 -1 -1 -5

Output for the Sample Input 1

-1.000 2.000
1.000 4.000

Sample Input 2

2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27

Output for the Sample Input 2

0.000 3.000
0.000 3.000

Solution in JAVA (judge verdict: Wrong Answer)

import java.util.Scanner;
import java.math.BigDecimal;



public class Main{
       public static void main(String[] args){
       int i,j,a,b,c,d,e,f;
       double s,t;
    	double[] x = new double[1000];
    	double[] y = new double[1000];
    
        Scanner scan = new Scanner(System.in);
        

       
        i = 0;
        while(scan.hasNextInt()){
        	a = scan.nextInt();
        	b = scan.nextInt();
        	c = scan.nextInt();
        	d = scan.nextInt();
        	e = scan.nextInt();
        	f = scan.nextInt();
        	
        	x[i] = (double)(b*f-c*e)/(b*d-a*e);
        	y[i] = (double)(a*f-c*d)/(a*e-b*d);
        	
        	BigDecimal bx = new BigDecimal(String.valueOf(x[i]));
		BigDecimal by = new BigDecimal(String.valueOf(y[i]));
        	x[i] = bx.setScale(3, BigDecimal.ROUND_HALF_UP).doubleValue();
        	y[i] = by.setScale(3, BigDecimal.ROUND_HALF_UP).doubleValue();

        	
     		System.out.printf("%.3f",x[i]);
     		System.out.print(" ");
     		System.out.printf("%.3f",y[i]);
     		System.out.println();
        	i++;
        }
      
        
        j = 0;
        while(j < i){
        	System.out.println(x[j]+ " " + y[j]);
        	j++;
       		}
       		}
}