Problem:
Score : 600 points

Problem Statement

Given are two sequences A and B, both of length N.
A and B are each sorted in the ascending order.
Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderings that achieve it.

Constraints

1\leq N \leq 2 \times 10^5

1\leq A_i,B_i \leq N

A and B are each sorted in the ascending order.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 \cdots A_N
B_1 B_2 \cdots B_N

Output

If there exist no reorderings that satisfy the condition, print No.

If there exists a reordering that satisfies the condition, print Yes on the first line.
After that, print a reordering of B on the second line, separating terms with a whitespace.

If there are multiple reorderings that satisfy the condition, you can print any of them.

Sample Input 1

6
1 1 1 2 2 3
1 1 1 2 2 3

Sample Output 1

Yes
2 2 3 1 1 1

Sample Input 2

3
1 1 2
1 1 3

Sample Output 2

No

Sample Input 3

4
1 1 2 3
1 2 3 3

Sample Output 3

Yes
3 3 1 2

Solution in Java (OpenJDK 11.0.6) (judge verdict: Runtime Error)

import java.util.*;

public class Main {

	public static void main(String[] args) {
		// TODO 自動生成されたメソッド・スタブ
		Scanner sc= new Scanner(System.in);
		
		int N= sc.nextInt();
		
		String space= sc.nextLine();
		
		String strA= sc.nextLine();
		String strB= sc.nextLine();
		
		sc.close();
		
		String[]a=strA.split(" ");
		String[]b=strB.split(" ");
		
		int[]A= new int[N];
		int[]B= new int[N];
		for(int i=0;i<N;i++){
			A[i]= Integer.parseInt(a[i]);
			B[i]= Integer.parseInt(b[i]);
		}
		
		
		int[]cntA= new int[N];
		int[]cntB= new int[N];
		
		for(int i=0;i<N;i++){
			cntA[A[i]]++;
			cntB[B[i]]++;
		}
		
		for(int i=0;i<N;i++){
			if(cntA[i] > N/2 && cntB[i] > N/2){
				System.out.println("No");
				break;
			}
			else{
				System.out.println("Yes");
				for(int j=N-1;i>=0;i++){
					System.out.print(B[j]);
					if(j==0)System.out.println();
					else System.out.print(" ");
				}
			}
			
		}
		
	}

}