Problem:
Score : 200 points

Problem Statement

Given are two strings S and T.

Let us change some of the characters in S so that T will be a substring of S.

At least how many characters do we need to change?

Here, a substring is a consecutive subsequence. For example, xxx is a substring of yxxxy, but not a substring of xxyxx.

Constraints

The lengths of S and T are each at least 1 and at most 1000.

The length of T is at most that of S.

S and T consist of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

Print the minimum number of characters in S that need to be changed.

Sample Input 1

cabacc
abc

Sample Output 1

1

For example, changing the fourth character a in S to c will match the second through fourth characters in S to T.

Since S itself does not have T as its substring, this number of changes - one - is the minimum needed.

Sample Input 2

codeforces
atcoder

Sample Output 2

6

Solution in Java (OpenJDK 11.0.6) (judge verdict: Accepted)

import java.util.*; 
import java.io.*;

//the answer must be bountry * bountry
public class Main  {
    static StringTokenizer st;
    static BufferedReader br;  
    static PrintWriter out;
 
    public static void main(String[] args) throws IOException {
        br = new BufferedReader(new InputStreamReader(System.in));
 
        String S = next();
        String T = next();
        
        int ans = Integer.MAX_VALUE;

        for (int i=1; i<=S.length()-T.length()+1; i++) {
             String temp = S.substring(i-1, i-1+T.length());
             int count = 0;
             for (int j=1; j<=T.length(); j++) {
                if(!temp.substring(j-1,j).equals(T.substring(j-1,j))){
                    count ++;
                }
             };  
             
             ans = Math.min(ans, count);
        }

        System.out.println(ans);
 
    }
    
      
    public static int nextInt() throws IOException {
        return Integer.parseInt(next());
    }
    public static long nextLong() throws IOException {
        return Long.parseLong(next());
    }

    public static double nextDouble() throws IOException {
        return Double.parseDouble(next());
    }

    static String next() throws IOException {
        while (st == null || !st.hasMoreTokens())
            st = new StringTokenizer(br.readLine().trim());
        return st.nextToken();
    }
}