Problem:
Score : 200 points

Problem Statement

A string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:

S is a palindrome.

Let N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.

The string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.

Determine whether S is a strong palindrome.

Constraints

S consists of lowercase English letters.

The length of S is an odd number between 3 and 99 (inclusive).

Input

Input is given from Standard Input in the following format:

S

Output

If S is a strong palindrome, print Yes;
otherwise, print No.

Sample Input 1

akasaka

Sample Output 1

Yes

S is akasaka.

The string formed by the 1-st through the 3-rd characters is aka.

The string formed by the 5-th through the 7-th characters is aka.
All of these are palindromes, so S is a strong palindrome.

Sample Input 2

level

Sample Output 2

No

Sample Input 3

atcoder

Sample Output 3

No

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        // int n = Integer.parseInt(sc.next());
        // int m = Integer.parseInt(sc.next());
        String s = sc.next();
        int n = s.length();
        // int[] s = new int[n];

        // for (int i = 0; i < n; i++) {
        // s[i] = Integer.parseInt(sc.next());

        // }
        boolean flag = true;

        for (int i = 0; i < n; i++) {
            if (s.charAt(i) != s.charAt(n - 1 - i)) {
                flag = false;
                break;
            }
        }

        int m = (n - 1) / 2;
        for (int i = 0; i < m; i++) {
            if (s.charAt(i) != s.charAt(m - 1 - i)) {
                flag = false;
                break;
            }
        }

        if (flag) {
            System.out.println("Yes");
        } else {
            System.out.println("No");
        }
        sc.close();
    }
}