Problem:
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Circles Intersection

You are given circle $A$ with radius $r_a$ and with central coordinate $(x_a, y_a)$ and circle $B$ with radius $r_b$ and with central coordinate $(x_b, y_b)$.

Write a program which prints:

"2" if $B$ is in $A$,

"-2" if $A$ is in $B$,

"1" if circumference of $A$ and $B$ intersect, and

"0" if $A$ and $B$ do not overlap.

You may assume that $A$ and $B$ are not identical.

Input

The input consists of multiple datasets. The first line consists of an integer $N$ ($N \leq 50$), the number of datasets. There will be $N$ lines where each line represents each dataset. Each data set consists of real numbers:

$x_a$ $y_a$ $r_a$ $x_b$ $y_b$ $r_b$

Output

For each dataset, print 2, -2, 1, or 0 in a line.

Sample Input

2
0.0 0.0 5.0 0.0 0.0 4.0
0.0 0.0 2.0 4.1 0.0 2.0

Output for the Sample Input

2
0

Solution in JAVA (judge verdict: Wrong Answer)

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;


class Main {

	public static void main(String[] args) throws NumberFormatException, IOException {
		BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
		double xa = 0;
		double ya = 0;
		double ra = 0;
		double xb = 0;
		double yb = 0;
		double rb = 0;
		int n = Integer.parseInt(in.readLine());
		for(int i= 0; i < n;i++){
			String ss[] =in.readLine().split(" ");
			xa = Double.parseDouble(ss[0]);
			ya = Double.parseDouble(ss[1]);
			ra = Double.parseDouble(ss[2]);
			xb = Double.parseDouble(ss[3]);
			yb = Double.parseDouble(ss[4]);
			rb = Double.parseDouble(ss[5]);
			double dist = Math.sqrt(Math.pow(xa-xb,2)+Math.pow(ya-yb,2));
			if(ra > rb + dist){
				//a?????\??£?????????
				System.out.println("2");
			}
			else if(rb > rb + dist){
				//b
				System.out.println("-2");
			}
			else if(dist < ra+rb){
				//????????£?????????
				System.out.println("1");
			}
			else{
				//???????????????
				System.out.println("0");
			}
		}
		

	}

}