Problem:
Score : 200 points

Problem Statement

Given is an integer N. Find the number of digits that N has in base K.

Notes

For information on base-K representation, see Positional notation - Wikipedia.

Constraints

All values in input are integers.

1 \leq N \leq 10^9

2 \leq K \leq 10

Input

Input is given from Standard Input in the following format:

N K

Output

Print the number of digits that N has in base K.

Sample Input 1

11 2

Sample Output 1

4

In binary, 11 is represented as 1011.

Sample Input 2

1010101 10

Sample Output 2

7

Sample Input 3

314159265 3

Sample Output 3

18

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;

public class Main {
    public static void main(String[] a) {
        Scanner scan = new Scanner(System.in);
        String[] t = scan.nextLine().split("\\s");
        int n = Integer.valueOf(t[0]);
        int r = Integer.valueOf(t[1]);
        int c = n / r;
      	int p = 1;
        while (c != 0) {
          	c = c / r;
          	p++;
        }
        System.out.print(p);
    }
}