Problem:
Score : 300 points

Problem Statement

There are N people living on a number line.

The i-th person lives at coordinate X_i.

You are going to hold a meeting that all N people have to attend.

The meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.

Find the minimum total points of stamina the N people have to spend.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq X_i \leq 100

Input

Input is given from Standard Input in the following format:

N
X_1 X_2 ... X_N

Output

Print the minimum total stamina the N people have to spend.

Sample Input 1

2
1 4

Sample Output 1

5

Assume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.

Note that you can hold the meeting only at an integer coordinate.

Sample Input 2

7
14 14 2 13 56 2 37

Sample Output 2

2354

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)


import java.io.DataInputStream;
import java.io.FileInputStream;
import java.io.IOException;
import java.util.Collections;
import java.util.Scanner;
import java.util.TreeSet;

public class Main{
       
	public static void main(String[] args) {
		Scanner sdf = new Scanner(System.in);
		
                int t=1;
                while(t-->0){
                    int n=sdf.nextInt();
                    int k=0;
                    int []a=new int[n];
                    for(int i=0;i<n;i++){
                        a[i]=sdf.nextInt();
                        k=k+a[i];
                    }
                    k=(int)Math.ceil((double)k/(double)n);
                    int sum=0;
                    for(int i=0;i<n;i++){
                        a[i]=(int)Math.pow(a[i]-k, 2);
                        sum=sum+a[i];
                    }
                    System.out.println(sum);
                    
                
                }                
        }
   


}