Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Scanner;

public class Main {

	public static void main(String[] args) {

		Scanner sc = new Scanner(System.in);
		int a = sc.nextInt();
		int b=0;
		int c=0;
		
		for(int i=1;i<=a;i++){
			if (i%2==0){
				continue;
			}
//			System.out.println("i="+i);
			b=0;
			for(int j=1;j<=i;j++){
				if(i%j==0){
					b++;
				}
			}
//			System.out.println("	b="+b);
			if(b==8){
//				System.out.println("iiiii="+i);
				c++;
			}
		}
		
		
		
		
		
		System.out.println(c);
		
		
		
		
	}

}