Problem:
Score : 100 points

Problem Statement

We conducted a survey on newspaper subscriptions.
More specifically, we asked each of the N respondents the following two questions:

Question 1: Are you subscribing to Newspaper X?

Question 2: Are you subscribing to Newspaper Y?

As the result, A respondents answered "yes" to Question 1, and B respondents answered "yes" to Question 2.

What are the maximum possible number and the minimum possible number of respondents subscribing to both newspapers X and Y?

Write a program to answer this question.

Constraints

1 \leq N \leq 100

0 \leq A \leq N

0 \leq B \leq N

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N A B

Output

Print the maximum possible number and the minimum possible number of respondents subscribing to both newspapers, in this order, with a space in between.

Sample Input 1

10 3 5

Sample Output 1

3 0

In this sample, out of the 10 respondents, 3 answered they are subscribing to Newspaper X, and 5 answered they are subscribing to Newspaper Y.

Here, the number of respondents subscribing to both newspapers is at most 3 and at least 0.

Sample Input 2

10 7 5

Sample Output 2

5 2

In this sample, out of the 10 respondents, 7 answered they are subscribing to Newspaper X, and 5 answered they are subscribing to Newspaper Y.

Here, the number of respondents subscribing to both newspapers is at most 5 and at least 2.

Sample Input 3

100 100 100

Sample Output 3

100 100

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.Scanner;
import java.util.Arrays;
 
class Main{
    public static void main(String[]args){
        Scanner scanner = new Scanner(System.in);
        int N =scanner.nextInt();
        int A =scanner.nextInt();
        int B =scanner.nextInt();
        int min = 0;
        int max = 0;
 
 
        if(A+B>N && A+B != 2*N){
            min = max(A,B)-min(A,B);
            max = min(A,B);
        }
        else if(A+B==2*N){
            min = max =A;
        }
        else{
            min = 0;
            max = min(A,B); 
        }
 
        System.out.println(max + " " + min);
     
        scanner.close();
 
    }
    public static int POWER(int a,int b){
        int p = 1;
        for(int i = 1;i<=b;i++){
            p = a*p;
        }
        return p;
    }
    public static int min(int a,int b){
        if(a>=b) return b;
        else return a;
      }
    public static int max(int a,int b){
        if(a>=b) return a;
        else return b;
      }
    public static int abs(int a){
        if(a>=0) return a;
        else return -1*a;
      }
}