Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.*;
import static java.lang.Integer.*;
//import static java.lang.Long.*;
//import static java.lang.Math.*;
import static java.lang.System.*;
import java.io.PrintWriter;

public class Main {
	public static void main(String[] args) {
		int i,j, k;
		Scanner sc = new Scanner(in);
		int n = parseInt(sc.next());
		sc.close();
		int[] so = {3*5*7, 3*5*11, 3*5*13, 3*3*3*5, 3*3*3*7};
		int cnt=0;
		for (i = 0; i < so.length; i++) {
			if(so[i] <= n)cnt++;
		}
		out.println(cnt);
	}
}