Problem:
Score : 300 points

Problem Statement

You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

1 \leq |S| \leq 2 \times 10^5

|S| = |T|

S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S and T can be made equal, print Yes; otherwise, print No.

Sample Input 1

azzel
apple

Sample Output 1

Yes

azzel can be changed to apple, as follows:

Choose e as c_1 and l as c_2. azzel becomes azzle.

Choose z as c_1 and p as c_2. azzle becomes apple.

Sample Input 2

chokudai
redcoder

Sample Output 2

No

No sequences of operation can change chokudai to redcoder.

Sample Input 3

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu

Sample Output 3

Yes

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Runtime Error)

import java .util.*;

public class Main {
	public static void main(String args[]) {
		Scanner sc = new Scanner(System.in);
		String S = sc.nextLine();
		String T = sc.nextLine();
		
		Map<String, String> map1 = new HashMap<String, String>();
		Map<String, String> map2 = new HashMap<String, String>();
		for(int i = 0; i < S.length(); i++) {
			String str1 = S.substring(i, i + 1);
			String str2 = T.substring(i, i + 1);
			if(!map1.containsKey(str1) && !map2.containsKey(str2)) {
				map1.put(str1, str2);
				map2.put(str2, str1);
			} else {
				if(!map1.get(str1).equals(str2) || !map2.get(str2).equals(str1)) {
					System.out.println("No");
					return;
				}
			}
		}
		
		System.out.println("Yes");
	}
}