Problem:
Score : 400 points

Problem Statement

There are N islands lining up from west to east, connected by N-1 bridges.

The i-th bridge connects the i-th island from the west and the (i+1)-th island from the west.

One day, disputes took place between some islands, and there were M requests from the inhabitants of the islands:

Request i: A dispute took place between the a_i-th island from the west and the b_i-th island from the west. Please make traveling between these islands with bridges impossible.

You decided to remove some bridges to meet all these M requests.

Find the minimum number of bridges that must be removed.

Constraints

All values in input are integers.

2 \leq N \leq 10^5

1 \leq M \leq 10^5

1 \leq a_i < b_i \leq N

All pairs (a_i, b_i) are distinct.

Input

Input is given from Standard Input in the following format:

N M
a_1 b_1
a_2 b_2
:
a_M b_M

Output

Print the minimum number of bridges that must be removed.

Sample Input 1

5 2
1 4
2 5

Sample Output 1

1

The requests can be met by removing the bridge connecting the second and third islands from the west.

Sample Input 2

9 5
1 8
2 7
3 5
4 6
7 9

Sample Output 2

2

Sample Input 3

5 10
1 2
1 3
1 4
1 5
2 3
2 4
2 5
3 4
3 5
4 5

Sample Output 3

4

Solution in Java (OpenJDK 1.8.0) (judge verdict: Wrong Answer)


import java.util.Arrays;
import java.util.Scanner;

public class Main {
	public static void main(String[] args) {
		Scanner in = new Scanner(System.in);
			int n = in.nextInt(), m = in.nextInt();
			int nums = 1;
			Node[] a = new Node[m];
			for (int i = 0; i < m; i++) {
				a[i] = new Node(in.nextInt(), in.nextInt());
			}
			Arrays.sort(a);
			for (int i = 1; i < m; i++) {
				if (a[i].qian >= a[i - 1].hou)
					nums++;
			}
			System.out.println(nums);
		}
}

class Node implements Comparable<Node> {
	int qian, hou;

	public Node(int qian, int hou) {
		this.hou = hou;
		this.qian = qian;
	}

	public int compareTo(Node o) {
		if (this.qian == o.qian)
			return o.hou - this.hou;
		else
			return this.qian - o.qian;
	}
}