Problem:
Score : 200 points

Problem Statement

Rng is preparing a problem set for a qualification round of CODEFESTIVAL.

He has N candidates of problems. The difficulty of the i-th candidate is D_i.

There must be M problems in the problem set, and the difficulty of the i-th problem must be T_i. Here, one candidate of a problem cannot be used as multiple problems.

Determine whether Rng can complete the problem set without creating new candidates of problems.

Constraints

1 \leq N \leq 200,000

1 \leq D_i \leq 10^9

1 \leq M \leq 200,000

1 \leq T_i \leq 10^9

All numbers in the input are integers.

Partial Score

100 points will be awarded for passing the test set satisfying N \leq 100 and M \leq 100.

Input

Input is given from Standard Input in the following format:

N
D_1 D_2 ... D_N
M
T_1 T_2 ... T_M

Output

Print YES if Rng can complete the problem set without creating new candidates of problems; print NO if he cannot.

Sample Input 1

5
3 1 4 1 5
3
5 4 3

Sample Output 1

YES

Sample Input 2

7
100 200 500 700 1200 1600 2000
6
100 200 500 700 1600 1600

Sample Output 2

NO

Not enough 1600s.

Sample Input 3

1
800
5
100 100 100 100 100

Sample Output 3

NO

Sample Input 4

15
1 2 2 3 3 3 4 4 4 4 5 5 5 5 5
9
5 4 3 2 1 2 3 4 5

Sample Output 4

YES

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Time Limit Exceeded)

import java.util.Scanner;
class Main{
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		int n=sc.nextInt();
		int p=(int)Math.pow(10, 8);
		int[] d=new int[p+1];
		int[] dd=new int[n];
		int ddite=0;//dd要素数
		for(int i=0;i<n;i++){
			int buf=sc.nextInt();
			if(buf<=p){
				d[buf]++;
			}
			else{
				dd[ddite]=buf;
				ddite++;
			}
		}
		int m=sc.nextInt();
		int[] t=new int[m];
		for(int i=0;i<m;i++){
			t[i]=sc.nextInt();
		}
		boolean is=true;
		if(n<m){
			is=false;
		}

		for(int i=0;is&&i<m;i++){
			if(t[i]<=p){
				if(d[t[i]]<=0){
					is=false;
					break;
				}
				d[t[i]]--;
			}
			else{
				for(int j=0;j<ddite;j++){
					if(dd[j]==t[i]){
						dd[j]=-1;
						break;
					}
					if(j==ddite){
						is=false;
					}
				}
			}

		}


		if(is){
			System.out.println("YES");
		}
		else{
			System.out.println("NO");
		}
	}
}