Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Accepted)

import java.util.Scanner;
import java.io.*;

public class Main
{
	public static void main(String[] args)
	{
		Scanner sc = new Scanner(System.in);
		int kazu[] = new int[128];
		for (int i = 0; i < 128; i++)
		{
			kazu[i] = 0;
		}
		StringBuilder sb = new StringBuilder();
		while(sc.hasNext())
		{
			sb.append(sc.nextLine());
		}
		String line = sb.toString();
		line = line.toLowerCase();
		for (int i = 0; i < line.length(); i++)
		{
			kazu[line.charAt(i)]++;
		}
		for (int i = 'a'; i <= 'z'; i++)
		{
			System.out.println((char)(i) + " : " + kazu[i]);
		}
		sc.close();
	}
}