Problem:
Score : 400 points

Problem Statement

You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

In the i-th operation, you replace every element whose value is B_{i} with C_{i}.

For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

All values in input are integers.

1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}

B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:

N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}

Output

Print Q integers S_{i} to Standard Output in the following format:

S_{1}
S_{2}
\vdots
S_{Q}

Note that S_{i} may not fit into a 32-bit integer.

Sample Input 1

4
1 2 3 4
3
1 2
3 4
2 4

Sample Output 1

11
12
16

Initially, the sequence A is 1,2,3,4.

After each operation, it becomes the following:

2, 2, 3, 4

2, 2, 4, 4

4, 4, 4, 4

Sample Input 2

4
1 1 1 1
3
1 2
2 1
3 5

Sample Output 2

8
4
4

Note that the sequence A may not contain an element whose value is B_{i}.

Sample Input 3

2
1 2
3
1 100
2 100
100 1000

Sample Output 3

102
200
2000

Solution in Java (OpenJDK 11.0.6) (judge verdict: Accepted)

import java.util.ArrayList;
import java.util.Arrays;
import java.util.HashMap;
import java.util.HashSet;
import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		Scanner scanner = new Scanner(System.in);
		int length1 = Integer.parseInt(scanner.nextLine());

		String numbers = scanner.nextLine();

		SumSum sussm = new SumSum(numbers);

		int length2 = Integer.parseInt(scanner.nextLine());

		sussm.run(length2, scanner);

	}

}
 class SumSum {

//	public static void main(String[] args) {
//		Va.main(null);
//	}

	private String[] array;
	private int[] arrayNumbers = new int[100001];
	private long sum;
	StringBuilder sb = new StringBuilder();

	public SumSum(String numbers) {
		this.array = numbers.split(" ");
		createIntArray();
	}

	public void run(int length, Scanner scanner) {
		for (int i = 0; i < length; i++) {
			int oldNumber = scanner.nextInt();
			int newNumber = scanner.nextInt();

			int quantity = arrayNumbers[oldNumber];
			if (quantity == 0) {
				sb.append(sum).append("\n");
				continue;
			}

			int difference = newNumber - oldNumber;
			sum += (difference * quantity);
			sb.append(sum).append("\n");
			arrayNumbers[oldNumber] = 0;
			arrayNumbers[newNumber] += quantity;
		}

		System.out.println(sb.toString());
	}

	private void createIntArray() {
		for (String s : array) {
			int number = Integer.parseInt(s);
			arrayNumbers[number] += 1;
			sum += number;
		}
	}

}