Problem:
Score : 300 points

Problem Statement

1000000000000001 dogs suddenly appeared under the roof of Roger's house, all of which he decided to keep. The dogs had been numbered 1 through 1000000000000001, but he gave them new names, as follows:

the dogs numbered 1,2,\cdots,26 were respectively given the names a, b, ..., z;

the dogs numbered 27,28,29,\cdots,701,702 were respectively given the names aa, ab, ac, ..., zy, zz;

the dogs numbered 703,704,705,\cdots,18277,18278 were respectively given the names aaa, aab, aac, ..., zzy, zzz;

the dogs numbered 18279,18280,18281,\cdots,475253,475254 were respectively given the names aaaa, aaab, aaac, ..., zzzy, zzzz;

the dogs numbered 475255,475256,\cdots were respectively given the names aaaaa, aaaab, ...;

and so on.

To sum it up, the dogs numbered 1, 2, \cdots were respectively given the following names:

a, b, ..., z, aa, ab, ..., az, ba, bb, ..., bz, ..., za, zb, ..., zz, aaa, aab, ..., aaz, aba, abb, ..., abz, ..., zzz, aaaa, ...

Now, Roger asks you:

"What is the name for the dog numbered N?"

Constraints

N is an integer.

1 \leq N \leq 1000000000000001

Input

Input is given from Standard Input in the following format:

N

Output

Print the answer to Roger's question as a string consisting of lowercase English letters.

Sample Input 1

2

Sample Output 1

b

Sample Input 2

27

Sample Output 2

aa

Sample Input 3

123456789

Sample Output 3

jjddja

Solution in Java (OpenJDK 11.0.6) (judge verdict: Wrong Answer)

import java.util.*;
import java.math.RoundingMode;
import java.math.BigDecimal;
 
 
 
public class Main{
	 public static void main(String[] args){
		Scanner sc = new Scanner(System.in);
		long n = sc.nextLong();
		String base26 = Long.toString(n,26);
		String ans = "";
		for(int i = 0; i < base26.length(); i++) {
			if(base26.charAt(i)=='1') {
				if(i+1<base26.length())ans+='z';
				else ans+='a';
			}
			else if(base26.charAt(i)=='2')ans+='b';
			else if(base26.charAt(i)=='3')ans+='c';
			else if(base26.charAt(i)=='4')ans+='d';
			else if(base26.charAt(i)=='5')ans+='e';
			else if(base26.charAt(i)=='6')ans+='f';
			else if(base26.charAt(i)=='7')ans+='g';
			else if(base26.charAt(i)=='8')ans+='h';
			else if(base26.charAt(i)=='9')ans+='i';
			else if(base26.charAt(i)=='a')ans+='j';
			else if(base26.charAt(i)=='b')ans+='k';
			else if(base26.charAt(i)=='c')ans+='l';
			else if(base26.charAt(i)=='d')ans+='m';
			else if(base26.charAt(i)=='e')ans+='n';
			else if(base26.charAt(i)=='f')ans+='o';
			else if(base26.charAt(i)=='g')ans+='p';
			else if(base26.charAt(i)=='h')ans+='q';
			else if(base26.charAt(i)=='i')ans+='r';
			else if(base26.charAt(i)=='j')ans+='s';
			else if(base26.charAt(i)=='k')ans+='t';
			else if(base26.charAt(i)=='l')ans+='u';
			else if(base26.charAt(i)=='m')ans+='v';
			else if(base26.charAt(i)=='n')ans+='w';
			else if(base26.charAt(i)=='o')ans+='x';
			else if(base26.charAt(i)=='p')ans+='y';
		}
		System.out.println(ans);
	 }
}