Problem:
Score: 400 points

Problem Statement

AtCoder Inc. has decided to lock the door of its office with a 3-digit PIN code.

The company has an N-digit lucky number, S. Takahashi, the president, will erase N-3 digits from S and concatenate the remaining 3 digits without changing the order to set the PIN code.

How many different PIN codes can he set this way?

Both the lucky number and the PIN code may begin with a 0.

Constraints

4 \leq N \leq 30000

S is a string of length N consisting of digits.

Input

Input is given from Standard Input in the following format:

N
S

Output

Print the number of different PIN codes Takahashi can set.

Sample Input 1

4
0224

Sample Output 1

3

Takahashi has the following options:

Erase the first digit of S and set 224.

Erase the second digit of S and set 024.

Erase the third digit of S and set 024.

Erase the fourth digit of S and set 022.

Thus, he can set three different PIN codes: 022, 024, and 224.

Sample Input 2

6
123123

Sample Output 2

17

Sample Input 3

19
3141592653589793238

Sample Output 3

329

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.Scanner;

/**
 * Built using CHelper plug-in
 * Actual solution is at the top
 *
 * @author Silviase
 */
public class Main {
    public static void main(String[] args) {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        Scanner in = new Scanner(inputStream);
        PrintWriter out = new PrintWriter(outputStream);
        DMitsui solver = new DMitsui();
        solver.solve(1, in, out);
        out.close();
    }

    static class DMitsui {
        public void solve(int testNumber, Scanner in, PrintWriter out) {
            int num = in.nextInt();
            String s = in.next();
            int res = 0;
            for (int i = 0; i < 1000; i++) {
                if (search(i, s)) {
                    res++;
                }
            }
            out.println(res);
        }

        public static boolean search(int num, String s) {
            String x1 = Integer.toString(num / 100);
            String x2 = Integer.toString((num / 10) % 10);
            String x3 = Integer.toString(num % 10);
            if (!s.contains(x1)) {
                return false;
            } else {
                s = s.substring(s.indexOf(x1) + 1);
                if (!s.contains(x2)) {
                    return false;
                } else {
                    s = s.substring(s.indexOf(x2) + 1);
                    if (!s.contains(x3)) {
                        return false;
                    } else {
                        return true;
                    }
                }
            }

        }

    }
}