Problem:
Score : 600 points

Problem Statement

We have N colored balls arranged in a row from left to right; the color of the i-th ball from the left is c_i.

You are given Q queries. The i-th query is as follows: how many different colors do the l_i-th through r_i-th balls from the left have?

Constraints

1\leq N,Q \leq 5 \times 10^5

1\leq c_i \leq N

1\leq l_i \leq r_i \leq N

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N Q
c_1 c_2 \cdots c_N
l_1 r_1
l_2 r_2
:
l_Q r_Q

Output

Print Q lines. The i-th line should contain the response to the i-th query.

Sample Input 1

4 3
1 2 1 3
1 3
2 4
3 3

Sample Output 1

2
3
1

The 1-st, 2-nd, and 3-rd balls from the left have the colors 1, 2, and 1 - two different colors.

The 2-st, 3-rd, and 4-th balls from the left have the colors 2, 1, and 3 - three different colors.

The 3-rd ball from the left has the color 1 - just one color.

Sample Input 2

10 10
2 5 6 5 2 1 7 9 7 2
5 5
2 4
6 7
2 2
7 8
7 9
1 8
6 9
8 10
6 8

Sample Output 2

1
2
2
1
2
2
6
3
3
3

Solution in Java (OpenJDK 11.0.6) (judge verdict: Time Limit Exceeded)

// Java code to find number of distinct numbers  
// in a subarray  
import java.io.*; 
import java.util.*; 
  
public class Main  
{ 
    static int MAX = 1000001; 
  
    // structure to store queries 
    static class Query  
    { 
        int l, r, idx; 
    } 
  
    // updating the bit array 
    static void update(int idx, int val,  
                        int bit[], int n)  
    { 
        for (; idx <= n; idx += idx & -idx) 
            bit[idx] += val; 
    } 
  
    // querying the bit array 
    static int query(int idx, int bit[], int n)  
    { 
        int sum = 0; 
        for (; idx > 0; idx -= idx & -idx) 
            sum += bit[idx]; 
        return sum; 
    } 
  
    static void answeringQueries(int[] arr, int n,  
                                Query[] queries, int q) 
    { 
  
        // initialising bit array 
        int[] bit = new int[n + 1]; 
        Arrays.fill(bit, 0); 
  
        // holds the rightmost index of any number 
        // as numbers of a[i] are less than or equal to 10^6 
        int[] last_visit = new int[MAX]; 
        Arrays.fill(last_visit, -1); 
  
        // answer for each query 
        int[] ans = new int[q]; 
        int query_counter = 0; 
        for (int i = 0; i < n; i++)  
        { 
  
            // If last visit is not -1 update -1 at the 
            // idx equal to last_visit[arr[i]] 
            if (last_visit[arr[i]] != -1) 
                update(last_visit[arr[i]] + 1, -1, bit, n); 
  
            // Setting last_visit[arr[i]] as i and updating 
            // the bit array accordingly 
            last_visit[arr[i]] = i; 
            update(i + 1, 1, bit, n); 
  
            // If i is equal to r of any query store answer 
            // for that query in ans[] 
            while (query_counter < q && queries[query_counter].r == i)  
            { 
                ans[queries[query_counter].idx] =  
                        query(queries[query_counter].r + 1, bit, n) 
                        - query(queries[query_counter].l, bit, n); 
                query_counter++; 
            } 
        } 
  
        // print answer for each query 
        for (int i = 0; i < q; i++) 
            System.out.println(ans[i]); 
    } 
  
    // Driver Code 
    public static void main(String[] args)  
    { 
        Scanner in=new Scanner(System.in);
        int n=in.nextInt(), q=in.nextInt(),a[]=new int[n];
        for(int i=0;i<n;++i) a[i]=in.nextInt();
        Query[] queries = new Query[q]; 
        for (int i = 0; i < q; i++) 
            queries[i] = new Query(); 
        for(int i=0;i<q;++i){
        	queries[i].l=in.nextInt()-1;
            queries[i].r=in.nextInt()-1;
            queries[i].idx=i;
        }
        Arrays.sort(queries, new Comparator<Query>()  
        { 
            public int compare(Query x, Query y) 
            { 
                if (x.r < y.r) 
                    return -1; 
                else if (x.r == y.r) 
                    return 0; 
                else
                    return 1; 
            } 
        }); 
        answeringQueries(a, n, queries, q); 
    } 
}