Problem:
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Matrix Multiplication

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\[
c_{ij} = \sum_{k=1}^m a_{ik}b_{kj}
\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Constraints

$1 \leq n, m, l \leq 100$

$0 \leq a_{ij}, b_{ij} \leq 10000$

Sample Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2

Sample Output

1 8 5
0 9 6
4 23 14

Note

      解説

Solution in JAVA (judge verdict: Wrong Answer)

import java.io.ByteArrayInputStream;
import java.io.PrintWriter;
import java.util.Scanner;

public class Main {

    String INPUT = "";

    public static void main(String[] args) throws Exception {
        new Main().run();
    }

    void run() {
        Scanner sc = INPUT.isEmpty() ? new Scanner(System.in) : new Scanner(new ByteArrayInputStream(INPUT.getBytes()));
        PrintWriter out = new PrintWriter(System.out);

        solve(sc, out);
        out.flush();
    }

    void solve(Scanner sc, PrintWriter out) {
        int n, m, l;
        
        n = sc.nextInt();
        m = sc.nextInt();
        l = sc.nextInt();
        int A[][] = new int[n][m];
        int B[][] = new int[m][l];
        int C[][] = new int[n][l];
        for (int i = 0; i < n; i++) {
        	for (int j = 0; j < m; j++) {
        	    A[i][j] = sc.nextInt();
            }
		}
        for (int i = 0; i < m; i++) {
            for (int j = 0; j < l; j++) {
                B[i][j] = sc.nextInt();
            }
        }
        for(int i = 0; i < n; i++){
            for(int j = 0; j < l; j++){
                for(int k = 0; k < m; k++){
                    C[i][j] += A[i][k]*B[k][j];
                }
            
                if(j != 0 ){
                    System.out.print(" ");
                }
                System.out.print(C[i][j]);
            }
            System.out.println();
        }
    }
}