Problem:
Score : 400 points

Problem Statement

Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.

You are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.

Constraints

2 ≦ |s| ≦ 10^5

s consists of lowercase letters.

Partial Score

200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.

Input

The input is given from Standard Input in the following format:

s

Output

If there exists no unbalanced substring of s, print -1 -1.

If there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.

Sample Input 1

needed

Sample Output 1

2 5

The string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.

Sample Input 2

atcoder

Sample Output 2

-1 -1

The string atcoder contains no unbalanced substring.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)



import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);

        while (sc.hasNext()) {
            String s = sc.next();
            char[] t = s.toCharArray();
            int ansA = -1;
            int ansB = -1;

            for (int i = 0; i < t.length; i++) {
                if ( i < t.length - 1 ) {
                    if ( t[i] == t[i + 1] ) {
                        ansA = i + 1;
                        ansB = i + 2;
                    }
                }
                if ( i < t.length - 2 ) {
                    if ( t[i] == t[i + 1] || t[i] == t[i + 2] || t[i + 1] == t[i + 2] ) {
                        ansA = i + 1;
                        ansB = i + 3;
                    }
                }
            }
            System.out.println(ansA + " " + ansB);
        }
    }
}