Problem:
Score : 200 points

Problem Statement

An integer N is a multiple of 9 if and only if the sum of the digits in the decimal representation of N is a multiple of 9.

Determine whether N is a multiple of 9.

Constraints

0 \leq N < 10^{200000}

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a multiple of 9, print Yes; otherwise, print No.

Sample Input 1

123456789

Sample Output 1

Yes

The sum of these digits is 1+2+3+4+5+6+7+8+9=45, which is a multiple of 9, so 123456789 is a multiple of 9.

Sample Input 2

0

Sample Output 2

Yes

Sample Input 3

31415926535897932384626433832795028841971693993751058209749445923078164062862089986280

Sample Output 3

No

Solution in Java (OpenJDK 11.0.6) (judge verdict: Wrong Answer)

import java.util.Scanner;
 
public class Main {
 
    public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		String n = sc.next();// 入力
      	long sum=0;
      
      	for(int i=0;i<n.length();i++){
          if(n.charAt(i)=='0'){
          	sum+=0;
          }
          if(n.charAt(i)=='1'){
          	sum+=1;
          }
          if(n.charAt(i)=='2'){
          	sum+=2;
          }
          if(n.charAt(i)=='3'){
          	sum+=3;
          }
          if(n.charAt(i)=='4'){
          	sum+=4;
          }
          if(n.charAt(i)=='5'){
          	sum+=5;
          }
          if(n.charAt(i)=='6'){
          	sum+=6;
          }
          if(n.charAt(i)=='7'){
          	sum+=7;
          }
          if(n.charAt(i)=='8'){
          	sum+=8;
          }
          if(n.charAt(i)=='9'){
          	sum+=9;
          }
			System.out.println(sum);
        }
      
      
      	if(sum%9==0){
          System.out.println("yes");
        }else{
          System.out.println("No");
        }
      
    } 
}