Problem:
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Circles Intersection

You are given circle $A$ with radius $r_a$ and with central coordinate $(x_a, y_a)$ and circle $B$ with radius $r_b$ and with central coordinate $(x_b, y_b)$.

Write a program which prints:

"2" if $B$ is in $A$,

"-2" if $A$ is in $B$,

"1" if circumference of $A$ and $B$ intersect, and

"0" if $A$ and $B$ do not overlap.

You may assume that $A$ and $B$ are not identical.

Input

The input consists of multiple datasets. The first line consists of an integer $N$ ($N \leq 50$), the number of datasets. There will be $N$ lines where each line represents each dataset. Each data set consists of real numbers:

$x_a$ $y_a$ $r_a$ $x_b$ $y_b$ $r_b$

Output

For each dataset, print 2, -2, 1, or 0 in a line.

Sample Input

2
0.0 0.0 5.0 0.0 0.0 4.0
0.0 0.0 2.0 4.1 0.0 2.0

Output for the Sample Input

2
0

Solution in JAVA (judge verdict: Wrong Answer)

import java.util.Scanner;


public class Main
{
	public static void main(String[] args)
	{
		Scanner scanner = new Scanner(System.in);
		
		int n = scanner.nextInt();
		for(int i=0; i<n; i++)
		{
			double[] x = new double[2];
			double[] y = new double[2];
			double[] r = new double[2];
			
			for(int j=0; j<2; j++)
			{
				x[j] = scanner.nextDouble();
				y[j] = scanner.nextDouble();
				r[j] = scanner.nextDouble();
			}
			
			int result = 0;
			double d = (x[1]-x[0])*(x[1]-x[0]) + (y[1]-y[0])*(y[1]-y[0]);

			if(d < r[0]-r[1])
			{
				result = 2;
			}
			else if(d < r[1]-r[0])
			{
				result = -2;
			}
			else if(d < r[0]+r[1])
			{
				result = 1;
			}
			
			System.out.println(result);
		}
	}
}