Problem:
Simultaneous Equation

Write a program which solve a simultaneous equation:

ax + by = c

dx + ey = f

The program should print x and y for given a, b, c, d, e and f (-1,000 ≤ a, b, c, d, e, f ≤ 1,000). You can suppose that given equation has a unique solution.

Input

The input consists of several data sets, 1 line for each data set. In a data set, there will be a, b, c, d, e, f separated by a single space. The input terminates with EOF.

Output

For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.

Sample Input 1

1 2 3 4 5 6
2 -1 -2 -1 -1 -5

Output for the Sample Input 1

-1.000 2.000
1.000 4.000

Sample Input 2

2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27

Output for the Sample Input 2

0.000 3.000
0.000 3.000

Solution in JAVA (judge verdict: Accepted)

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class Main{
	public static void main(String[] args) throws IOException{
		BufferedReader d=new BufferedReader(new InputStreamReader(System.in));
		String line;
		double x,y;
		while((line=d.readLine())!=null){
			String sp[] = line.split(" ");
			double[] var=new double[6];
			for(int i=0;i<sp.length;i++){
				var[i]=Double.valueOf(sp[i]);
			}
//[0]x + [1]y = [2]
//[3]x + [4]y = [5]
			var[1]/=var[0];// b/a
			var[2]/=var[0];// c/a
			var[0]=1;// a/a


			var[1]*=-1;

			//x=-by+c;
			//x=[1]y+[2];

			var[4]+=(var[3]*var[1]);
			var[5]-=(var[3]*var[2]);
			//[3]([1]y+[2])+[4]y=[5]
			//([4]+[3][1])y=[5]-[3][2]
			//[4]y=[5];

			y=var[5]/var[4];
			x=var[1]*y+var[2];
			System.out.println( String.format("%.3f", x)+" "+ String.format("%.3f", y));
		}
	}
}