Problem:
Simultaneous Equation

Write a program which solve a simultaneous equation:

ax + by = c

dx + ey = f

The program should print x and y for given a, b, c, d, e and f (-1,000 ≤ a, b, c, d, e, f ≤ 1,000). You can suppose that given equation has a unique solution.

Input

The input consists of several data sets, 1 line for each data set. In a data set, there will be a, b, c, d, e, f separated by a single space. The input terminates with EOF.

Output

For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.

Sample Input 1

1 2 3 4 5 6
2 -1 -2 -1 -1 -5

Output for the Sample Input 1

-1.000 2.000
1.000 4.000

Sample Input 2

2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27

Output for the Sample Input 2

0.000 3.000
0.000 3.000

Solution in JAVA (judge verdict: Wrong Answer)

import java.io.IOException;
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.Scanner;
import java.util.Arrays;
import java.util.Collections;
import java.text.DecimalFormat;

class Main {
    public static void main (String[] args) throws IOException {
        Scanner sc = new Scanner(System.in);
        StringBuilder sb = new StringBuilder("");

        int a, b, c, d, e, f;
        int denominator;
        double x, y;

        DecimalFormat df = new DecimalFormat("#.000");

        while (sc.hasNextInt()) {
            a = sc.nextInt();
            b = sc.nextInt();
            c = sc.nextInt();
            d = sc.nextInt();
            e = sc.nextInt();
            f = sc.nextInt();

            denominator = b * d - a * e;

            x = (b * f - c * e) / denominator;
            y = (c * d - a * f) / denominator;

            sb.append(df.format(x)).append(' ').append(df.format(y)).append('\n');
        }
        System.out.print(sb);

    }
}