Problem:
Score : 200 points

Problem Statement

Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Constraints

1 \leq N \leq 10^5

Input

Input is given from Standard Input in the following format:

N

Output

Print the number of positive integers less than or equal to N that have an odd number of digits.

Sample Input 1

11

Sample Output 1

9

Among the positive integers less than or equal to 11, nine integers have an odd number of digits: 1, 2, \ldots, 9.

Sample Input 2

136

Sample Output 2

46

In addition to 1, 2, \ldots, 9, another 37 integers also have an odd number of digits: 100, 101, \ldots, 136.

Sample Input 3

100000

Sample Output 3

90909

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.*;
public class Main{

 public static void main(String[] args)
 {
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        int len = String.valueOf( n ).length(); 
        int sum = 0;
        for(int i =1;i<len;i++){
          if(i%2==1){
            sum = sum + ( (int)Math.pow(10, i)  - 1);
          }
        }
        if(len%2 == 1){
            int tmp = len - 1;
            sum = sum + n - ((int)Math.pow(10, tmp) - 1);
        }
        System.out.println(sum);
      
    }

}