Problem:
Score : 300 points

Problem Statement

You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

1 \leq |S| \leq 2 \times 10^5

|S| = |T|

S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S and T can be made equal, print Yes; otherwise, print No.

Sample Input 1

azzel
apple

Sample Output 1

Yes

azzel can be changed to apple, as follows:

Choose e as c_1 and l as c_2. azzel becomes azzle.

Choose z as c_1 and p as c_2. azzle becomes apple.

Sample Input 2

chokudai
redcoder

Sample Output 2

No

No sequences of operation can change chokudai to redcoder.

Sample Input 3

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu

Sample Output 3

Yes

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)


import java.util.Scanner;

public class Main {
	public static void main(String[] args) {
		Scanner scan = new Scanner(System.in);
		String S = scan.next();
		String T = scan.next();
		int[] transArrayS = new int[26];
		for (int i = 0; i < transArrayS.length; i++) {
			transArrayS[i] = -1;
		}
		int[] transArrayT = new int[26];
		for (int i = 0; i < transArrayS.length; i++) {
			transArrayT[i] = -1;
		}
		for (int i = 0; i < S.length(); i++) {
			if (transArrayS[S.charAt(i) - 'a'] == -1) {
				transArrayS[S.charAt(i) - 'a'] = T.charAt(i) - 'a';
			} else if (transArrayS[S.charAt(i) - 'a'] != T.charAt(i) - 'a') {
				System.out.println("No");
				return;
			}
			if (transArrayT[T.charAt(i) - 'a'] == -1) {
				transArrayT[T.charAt(i) - 'a'] = S.charAt(i) - 'a';
			} else if (transArrayT[T.charAt(i) - 'a'] != S.charAt(i) - 'a') {
				System.out.println("No");
				return;
			}
		}
		System.out.println("Yes");
	}
}