Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Accepted)

import java.util.Scanner;
public class Main
{
    public static void main(String[] args)
    {
        Scanner sc = new Scanner(System.in);
        String text,Line;
        int count[] = new int[26];
        int z;
        StringBuilder sb = new StringBuilder();
        while(sc.hasNextLine())
        {
           sb.append(sc.nextLine().toLowerCase());  
        }
        int toAscii[] =new int [sb.length()];
        
       
        for(int i =0; i<sb.length();i++)
        {
            z=0;
            toAscii[i] =(int) sb.charAt(i);
            if(97<=toAscii[i] && toAscii[i]<=122)
            {
                z = toAscii[i] - 97;
                count[z] =count[z]+1;
            }
        }
        for(int i = 0; i<26;i++)
        {
            z = i+97;
            char a = (char) z;
            System.out.println(a+ " : "+count[i]);
        }
    }
}