Problem:
Score : 200 points

Problem Statement

You are given three strings A, B and C. Each of these is a string of length N consisting of lowercase English letters.

Our objective is to make all these three strings equal. For that, you can repeatedly perform the following operation:

Operation: Choose one of the strings A, B and C, and specify an integer i between 1 and N (inclusive). Change the i-th character from the beginning of the chosen string to some other lowercase English letter.

What is the minimum number of operations required to achieve the objective?

Constraints

1 \leq N \leq 100

Each of the strings A, B and C is a string of length N.

Each character in each of the strings A, B and C is a lowercase English letter.

Input

Input is given from Standard Input in the following format:

N
A
B
C

Output

Print the minimum number of operations required.

Sample Input 1

4
west
east
wait

Sample Output 1

3

In this sample, initially A = west、B = east、C = wait. We can achieve the objective in the minimum number of operations by performing three operations as follows:

Change the second character in A to a. A is now wast.

Change the first character in B to w. B is now wast.

Change the third character in C to s. C is now wast.

Sample Input 2

9
different
different
different

Sample Output 2

0

If A, B and C are already equal in the beginning, the number of operations required is 0.

Sample Input 3

7
zenkoku
touitsu
program

Sample Output 3

13

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Runtime Error)

import java.util.Scanner;

public class Main {

	public static void main(String[] args) {

		int length = Integer.parseInt(new Scanner(System.in).next());
		String a = new Scanner(System.in).next();
		String b = new Scanner(System.in).next();
		String c = new Scanner(System.in).next();

		int cnt = 0;
		for (int i = 0; i < length; i++) {
			String a1 = a.substring(i, i+1);
			String b1 = b.substring(i, i+1);
			String c1 = c.substring(i, i+1);

			if (!a1.equals(b1) && !b1.equals(c1) && !c1.equals(a1)) {
				cnt += 2;
			} else if (!a1.equals(b1) || !b1.equals(c1)) {
				cnt += 1;
			}
		}
		System.out.println(cnt);
	}

}