Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.Scanner;

public class Main {

    public static void main(String[] args) {
    Scanner cin = new Scanner(System.in);
    int N= 4/cin.nextInt();
    int h ,n ,w;
    h=0;
    n=0;
    w=0;
        for(h=1;h<=3500;h++){
            for (n=1;n<=3500;n++)
            {
                if((N-1/n-1/h)!=0)w=1/(N-1/n-1/h);
                if(w>0){System.out.println(w +" "+n+" "+h); return;}
            }
    }
    }

}