Problem:
Score : 300 points

Problem Statement

You are given an integer sequence of length n, a_1, ..., a_n.
Let us consider performing the following n operations on an empty sequence b.

The i-th operation is as follows:

Append a_i to the end of b.

Reverse the order of the elements in b.

Find the sequence b obtained after these n operations.

Constraints

1 \leq n \leq 2\times 10^5

0 \leq a_i \leq 10^9

n and a_i are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print n integers in a line with spaces in between.
The i-th integer should be b_i.

Sample Input 1

4
1 2 3 4

Sample Output 1

4 2 1 3

After step 1 of the first operation, b becomes: 1.

After step 2 of the first operation, b becomes: 1.

After step 1 of the second operation, b becomes: 1, 2.

After step 2 of the second operation, b becomes: 2, 1.

After step 1 of the third operation, b becomes: 2, 1, 3.

After step 2 of the third operation, b becomes: 3, 1, 2.

After step 1 of the fourth operation, b becomes: 3, 1, 2, 4.

After step 2 of the fourth operation, b becomes: 4, 2, 1, 3.

Thus, the answer is 4 2 1 3.

Sample Input 2

3
1 2 3

Sample Output 2

3 1 2

As shown above in Sample Output 1, b becomes 3, 1, 2 after step 2 of the third operation. Thus, the answer is 3 1 2.

Sample Input 3

1
1000000000

Sample Output 3

1000000000

Sample Input 4

6
0 6 7 6 7 0

Sample Output 4

0 6 6 0 7 7

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Time Limit Exceeded)

import java.util.*;
import java.lang.*;

// class Pair implements Comparable<Pair>{
//   long a;
//   int cnt;
//   public Pair(long i, int j){
//     this.a = i;
//     this.cnt = j;
//   }
//   public int compareTo(Pair p){
//     if(this.cnt>=2 && p.cnt >=2 && this.a<p.a) return -1;
//     if(this.cnt<2 && p.cnt>=2) return -1;
//     return 1;
//   }
// }

class Main{
  public static void main(String[] args) {
      Scanner sc = new Scanner(System.in);
      int N = Integer.parseInt(sc.next());
      if(N==1){
        System.out.println(Long.parseLong(sc.next()));
        return;
      }
      LinkedList<Long> l = new LinkedList<>();
      for(int i = 0; i<N; i++){
        long a = Long.parseLong(sc.next());
        if(i%2==0) l.push(a);
        else l.add(a);
      }
      if(N%2==1){
        for(int i = 0; i<N-1; i++) System.out.print(l.get(i)+" ");
        System.out.println(l.get(N-1));
      }else{
        for(int i = 0; i<N-1; i++) System.out.print(l.get(N-1-i)+" ");
        System.out.println(l.get(0));
      }
  }
}