Problem:
Score : 300 points

Problem Statement

A sequence a_1,a_2,... ,a_n is said to be /\/\/\/ when the following conditions are satisfied:

For each i = 1,2,..., n-2, a_i = a_{i+2}.

Exactly two different numbers appear in the sequence.

You are given a sequence v_1,v_2,...,v_n whose length is even.
We would like to make this sequence /\/\/\/ by replacing some of its elements.
Find the minimum number of elements that needs to be replaced.

Constraints

2 \leq n \leq 10^5

n is even.

1 \leq v_i \leq 10^5

v_i is an integer.

Input

Input is given from Standard Input in the following format:

n
v_1 v_2 ... v_n

Output

Print the minimum number of elements that needs to be replaced.

Sample Input 1

4
3 1 3 2

Sample Output 1

1

The sequence 3,1,3,2 is not /\/\/\/, but we can make it /\/\/\/ by replacing one of its elements: for example, replace the fourth element to make it 3,1,3,1.

Sample Input 2

6
105 119 105 119 105 119

Sample Output 2

0

The sequence 105,119,105,119,105,119 is /\/\/\/.

Sample Input 3

4
1 1 1 1

Sample Output 3

2

The elements of the sequence 1,1,1,1 are all the same, so it is not /\/\/\/.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.*;

class Main{
	public static void main(String args[]){
		Scanner sc = new Scanner(System.in);
		int n = sc.nextInt();
		int[] gcnt = new int[100001];
		int[] kcnt = new int[100001];
		int gmax = 0;
		int gmax2 = 0;
		int gid = 0;
		int kmax = 0;
		int kmax2 = 0;
		int kid = 0;
		for(int i = 0; i < n; i++){
			int tmp = sc.nextInt();
			if(i%2==0){
				gcnt[tmp]++;
				if(gmax <= gcnt[tmp]){
					if(tmp != gid)gmax2 = gmax;
					gmax = gcnt[tmp];
					gid = tmp;
				}
			}else{
				kcnt[tmp]++;
				if(kmax <= kcnt[tmp]){
					if(tmp != kid)kmax2 = kmax;
					kmax = kcnt[tmp];
					kid = tmp;
				}
			}
		}
		if(gid != kid){
			System.out.print(n-gmax-kmax);
		}else{
			if(gmax+kmax==n){
				System.out.print(n/2);
			}else if(gmax > kmax){
				System.out.print(n-gmax-kmax2);
			}else{
				System.out.print(n-gmax2-kmax);
			}
		}
	}
}