Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Accepted)

import java.io.*;
public class Main {
	public static void main(String[] args) throws IOException{
		BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
		String linesum = "";
		char[] alpha = {'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z'};
		int[] alphabet = new int[26];
		String line;
		while((line = reader.readLine()) != null){
			linesum = linesum + line;
		}
		char[] word = new char[linesum.length()];
		for(int i = 0; i < 26; i++){
			alphabet[i] = 0;
		}
		for(int i = 0; i < linesum.length(); i++){
			word[i] = linesum.toLowerCase().charAt(i);
			for(int j = 0; j < 26; j++){
				if(word[i] == alpha[j]){
					alphabet[j]++;
				}
			}
		}
		for(int i = 0; i < 26; i++){
			System.out.println(alpha[i] + " : " + alphabet[i]);
		}
	}
}