Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.util.StringTokenizer;

public class Main {

	static int N, A, B, C, D;
	static char[] S;
	static boolean isCheck;

	public static void main(String[] args) throws Exception {
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
		BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(System.out));
		StringTokenizer st;

		st = new StringTokenizer(br.readLine());
		N = Integer.parseInt(st.nextToken());
		A = Integer.parseInt(st.nextToken()) - 1;
		B = Integer.parseInt(st.nextToken()) - 1;
		C = Integer.parseInt(st.nextToken()) - 1;
		D = Integer.parseInt(st.nextToken()) - 1;
		S = br.readLine().toCharArray();

		go(A, A + 1, B, B + 1);
		go(A, A + 1, B, B + 2);
		go(A, A + 2, B, B + 1);
		go(A, A + 2, B, B + 2);
		if (isCheck) {
			bw.write("Yes");
		} else {
			bw.write("No");
		}

		bw.flush();
		bw.close();
		br.close();
	}

	private static void go(int fromA, int toA, int fromB, int toB) {
		if (toA < N && toB < N && S[toA] == '.' && S[toB] == '.' && toA != toB) {
			if (toA == C && toB == D) {
				isCheck = true;
			}

			go(toA, toA + 1, toB, toB + 1);
			go(toA, toA + 1, toB, toB + 2);
			go(toA, toA + 2, toB, toB + 1);
			go(toA, toA + 2, toB, toB + 2);

		} else {
			return;
		}

	}

}