Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Java (OpenJDK 11.0.6) (judge verdict: Accepted)

import java.util.Scanner;
public class Main {
	public static void main(String[] args){
		Scanner sc = new Scanner(System.in);
        int N = sc.nextInt();
        //char[] S = sc.next().toCharArray();
        int count=0;
        int yakusuu=0;
        int n;
        for(int i=0; 2*i<N; i++){
            n = 2*i+1;
            for(int k=1; k<n+1; k++){
                if(n%k==0){
                    yakusuu++;
                }
            }
            if(yakusuu==8){
                count++;
                
            }
            yakusuu=0;

        }

          System.out.println(count);
        }
    }