Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)


import java.util.Scanner;
//
public class Main {
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		//━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━
		int[][] bingo =new int[3][3];
		boolean[][] isHit=new boolean[3][3];
		for (int i=0;i<3;i++) {
			for (int j=0;j<3;j++) {
				bingo[i][j] =sc.nextInt();
				isHit[i][j]=false;
			}
		}
		int n=sc.nextInt();
		for (int k=0;k<n;k++) {
			int drawnCard =sc.nextInt();
			for (int i=0;i<3;i++) {
				for (int j=0;j<3;j++) {
					if (drawnCard==bingo[i][j]) {
						isHit[i][j]=true;
					}
				}
			}
		}
		boolean isBingo =false;
		for (int i=0;i<3;i++) {
			if(isHit[0][i]&&isHit[1][i]&&isHit[2][i]) {
				isBingo =true;
			}
		}
		for (int i=0;i<3;i++) {
			if(isHit[i][0]&&isHit[i][1]&&isHit[i][2]) {
				isBingo =true;
			}
		}
		if (isHit[0][0]&&isHit[1][1]&&isHit[2][2]) {
			isBingo=true;
		}
		if (isHit[0][2]&&isHit[1][1]&&isHit[2][0]) {
			isBingo=true;
		}
		if (isBingo) {
			System.out.println("Yes");
		} else {
			System.out.println("No");
		}
		
			//━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━
		}
		//----------------------------------------
		//置き場
		
		//----------------------------------------
	}