Problem:
Simultaneous Equation

Write a program which solve a simultaneous equation:

ax + by = c

dx + ey = f

The program should print x and y for given a, b, c, d, e and f (-1,000 ≤ a, b, c, d, e, f ≤ 1,000). You can suppose that given equation has a unique solution.

Input

The input consists of several data sets, 1 line for each data set. In a data set, there will be a, b, c, d, e, f separated by a single space. The input terminates with EOF.

Output

For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.

Sample Input 1

1 2 3 4 5 6
2 -1 -2 -1 -1 -5

Output for the Sample Input 1

-1.000 2.000
1.000 4.000

Sample Input 2

2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27

Output for the Sample Input 2

0.000 3.000
0.000 3.000

Solution in JAVA (judge verdict: Wrong Answer)

import java.io.*;
import java.util.*;
//連立方程式ax+b=c,dx+e=fの解を求める
class Main {
    public static void main(String[] a){
	String str;
	double[] coeff = new double[6];
	int i;
	try{
	    BufferedReader input = new BufferedReader(new InputStreamReader(System.in));
	    str = input.readLine();//入力された文字列
	    StringTokenizer strCoeff = new StringTokenizer(str," ");//空白文字で分割
	    i = 0;
	    while(i<6)
		{
		    coeff[i] = Double.parseDouble(strCoeff.nextToken());
		    i++;
		}
	    double x,y,p,q;//y=p/q, p=af-cd, q=ae-bd, x=(cq-bp)/(aq)
	    p = coeff[0]*coeff[5]-coeff[2]*coeff[3];
	    q = coeff[0]*coeff[4]-coeff[1]*coeff[3];
	    if(coeff[0] != 0 && q != 0)
	    	{ 
	    x = (coeff[2]*q-coeff[1]*p)/(coeff[0]*q);
	    y = p/q;
	    String str_x = String.format("%.3f",x);
	    String str_y = String.format("%.3f",y);
	    System.out.println(str_x + " " + str_y);
	    	}

	}
	catch(Exception e)
	    {
		System.out.println("Error");
	    }
    }
}