Problem:
Score : 200 points

Problem Statement

You are given string S and T consisting of lowercase English letters.

Determine if S equals T after rotation.

That is, determine if S equals T after the following operation is performed some number of times:

Operation: Let S = S_1 S_2 ... S_{|S|}. Change S to S_{|S|} S_1 S_2 ... S_{|S|-1}.

Here, |X| denotes the length of the string X.

Constraints

2 \leq |S| \leq 100

|S| = |T|

S and T consist of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S equals T after rotation, print Yes; if it does not, print No.

Sample Input 1

kyoto
tokyo

Sample Output 1

Yes

In the first operation, kyoto becomes okyot.

In the second operation, okyot becomes tokyo.

Sample Input 2

abc
arc

Sample Output 2

No

abc does not equal arc after any number of operations.

Sample Input 3

aaaaaaaaaaaaaaab
aaaaaaaaaaaaaaab

Sample Output 3

Yes

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		Scanner in = new Scanner(System.in);
		char[] str1 = in.nextLine().toCharArray();
		char[] str2 = in.nextLine().toCharArray();
		if (check(str1, str2)) {
			System.out.println("Yes");
		} else {
			System.out.println("No");
		}
		in.close();
	}

	private static boolean check(char[] str1, char[] str2) {
		for (int i = 0; i < str1.length; ++i) {
			char[] rotateStr = rotate(str2, i);
			if (compare(str1, rotateStr) == true) {
				return true;
			}
		}
		return false;
	}

	private static boolean compare(char[] str1, char[] str2) {
		for (int i = 0; i < str1.length; ++i) {
			if (str1[i] != str2[i]) {
				return false;
			}
		}
		return true;
	}

	private static char[] rotate(char[] str, int startIndex) {
		char[] result = new char[str.length];
		int index = 0;
		for (int i = startIndex; i < str.length; ++i) {
			result[index] = str[i];
			++index;
		}
		for (int i = 0; i < startIndex; ++i) {
			result[index] = str[i];
			++index;
		}
		return result;
	}

}