Problem:
Score : 300 points

Problem Statement

Given are an integer X and an integer sequence of length N: p_1, \ldots, p_N.

Among the integers not contained in the sequence p_1, \ldots, p_N (not necessarily positive), find the integer nearest to X, that is, find the integer whose absolute difference with X is the minimum. If there are multiple such integers, report the smallest such integer.

Constraints

1 \leq X \leq 100

0 \leq N \leq 100

1 \leq p_i \leq 100

p_1, \ldots, p_N are all distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X N
p_1 ... p_N

Output

Print the answer.

Sample Input 1

6 5
4 7 10 6 5

Sample Output 1

8

Among the integers not contained in the sequence 4, 7, 10, 6, 5, the one nearest to 6 is 8.

Sample Input 2

10 5
4 7 10 6 5

Sample Output 2

9

Among the integers not contained in the sequence 4, 7, 10, 6, 5, the ones nearest to 10 are 9 and 11. We should print the smaller one, 9.

Sample Input 3

100 0

Sample Output 3

100

When N = 0, the second line in the input will be empty. Also, as seen here, X itself can be the answer.

Solution in Java (OpenJDK 11.0.6) (judge verdict: Accepted)

import java.util.*;
public class Main{
	public static void main(String[] args)
	{
		 Scanner sc=new Scanner(System.in);
		 int i=sc.nextInt();
		 int j=sc.nextInt();
		 int min=9999;
		 int arr[]=new int[j];
		 List<Integer> li1=new ArrayList<Integer>();
		 int flag=0;
		 if(j==0)
		 {
			 System.out.println(i);
			 return;
		 }
		 for(int k=0;k<j;k++)
		 {
			 arr[k]=sc.nextInt();
			 li1.add(arr[k]);
		 }
		 if(!li1.contains(i))
		 {
			 System.out.println(i);
			 return;
		 }
		
		 for(int k=0;k<=j;k++)
		 {
			if((li1.contains(i+k))&&(li1.contains(i-k)))
			 { 
				 continue;
			 }
           
			 if(!li1.contains(i-k))
			 {
				 flag=1;
				
				 System.out.println(i-k);
                 break;
				 
			 }
			 if(!li1.contains(i+k))
			 {
				 flag=1;
				 System.out.println(i+k);
                 break;
				 
			 }
			 
			 
			 
			 
			 
		 }
		 
		 
	}

}