Problem:
Score : 300 points

Problem Statement

You are given a sequence of length N: A_1, A_2, ..., A_N.
For each integer i between 1 and N (inclusive), answer the following question:

Find the maximum value among the N-1 elements other than A_i in the sequence.

Constraints

2 \leq N \leq 200000

1 \leq A_i \leq 200000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1
:
A_N

Output

Print N lines. The i-th line (1 \leq i \leq N) should contain the maximum value among the N-1 elements other than A_i in the sequence.

Sample Input 1

3
1
4
3

Sample Output 1

4
3
4

The maximum value among the two elements other than A_1, that is, A_2 = 4 and A_3 = 3, is 4.

The maximum value among the two elements other than A_2, that is, A_1 = 1 and A_3 = 3, is 3.

The maximum value among the two elements other than A_3, that is, A_1 = 1 and A_2 = 4, is 4.

Sample Input 2

2
5
5

Sample Output 2

5
5

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.*;

public class Main{
	public static void main(String args[]){
    	Scanner scanner = new Scanner(System.in);
        int N = scanner.nextInt();
      
        int[] A = new int[N];
        for(int i = 0; i < N; i++){
            A[i] = scanner.nextInt();
        }
		
        int max_first = 0;
        int max_second = 0;
        int count_max_first = 0;
      
        for(int i = 0; i < N; i++){
            if(A[i] > max_first){
                max_first = A[i];
            }
        } 
      
        for(int i = 0; i < N; i++){
            if(A[i] > max_second && A[i] != max_first){
                max_second = A[i];
            } else if(A[i] == max_first) {
                count_max_first++;
            }
        } 
      
        if(count_max_first > 1){
            max_second = max_first;
        }
      
        for(int i = 0; i < N; i++){
            if(A[i] == max_first){
                System.out.println(max_second);
            } else {
                System.out.println(max_first);
            }
        } 
    }
}