Problem:
Score : 200 points

Problem Statement

Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.

The problem has N test cases.

For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is AC, WA, TLE, and RE, respectively.

See the Output section for the output format.

Constraints

1 \leq N \leq 10^5

S_i is AC, WA, TLE, or RE.

Input

Input is given from Standard Input in the following format:

N
S_1
\vdots
S_N

Output

Let C_0, C_1, C_2, and C_3 be the numbers of test cases for which the verdict is AC, WA, TLE, and RE, respectively. Print the following:

AC x C_0
WA x C_1
TLE x C_2
RE x C_3

Sample Input 1

6
AC
TLE
AC
AC
WA
TLE

Sample Output 1

AC x 3
WA x 1
TLE x 2
RE x 0

We have 3, 1, 2, and 0 test case(s) for which the verdict is AC, WA, TLE, and RE, respectively.

Sample Input 2

10
AC
AC
AC
AC
AC
AC
AC
AC
AC
AC

Sample Output 2

AC x 10
WA x 0
TLE x 0
RE x 0

Solution in Java (OpenJDK 11.0.6) (judge verdict: Wrong Answer)

import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;

public class Main {
    
    static final String keyAc = "AC";
    
    static final String keyWa = "WA";
    
    static final String keyTle = "TLE";
    
    static final String keyRe = "RE";
    
    static final String cntLiteral = "×";
    
    
    public static void main(String[] args) {
        
        //　入力された値を受け取る
        Scanner scanner = new Scanner(System.in);
        
        List<String> list = new ArrayList<>();
        
        int cntNum = Integer.parseInt(scanner.nextLine());
        
        for (int i = 0; i < cntNum ; i++) {
            String getData = scanner.nextLine();
            list.add(getData);
        }
        
        // 保持した値をイコールズメソッドで比較
        
        int cntAc = 0;
        
        int cntWa = 0;
        
        int cntTle = 0;
        
        int cntRe = 0;
        
        
        for(int cntupNum = 0; cntupNum< cntNum; cntupNum++){  
                
            switch(list.get(cntupNum)) {
                case keyAc:
                    cntAc++;
                    break;
                    
                case keyWa:
                    
                    cntWa++;
                    break;
                    
                case keyTle:
                    
                    cntTle++;
                    break;
                    
                case keyRe:
                    
                    cntRe++;
                    break;
                    
                
            }
            
            
        
        }

        System.out.println(keyAc+cntLiteral+cntAc);
        
        System.out.println(keyWa+cntLiteral+cntWa);
        
        System.out.println(keyTle+cntLiteral+cntTle);
        
        System.out.println(keyRe+cntLiteral+cntRe);
    }

}