Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Runtime Error)

import java.util.*;

class Main {
  public static void main(String[] args) {
    Scanner sc = new Scanner(System.in);

    int s = sc.nextInt();
    String str = String.valueOf(s);
    boolean yymm = false;
    boolean mmyy = false;
    
    int mae = Integer.parseInt(str.substring(0,2).replaceFirst("0",""));
    int ato = Integer.parseInt(str.substring(2).replaceFirst("0",""));
    if(mae<13&&mae!=0&&ato!=0){
      mmyy = true;
    }
    if(ato<13&&ato!=0&&mae!=0){
        yymm = true;
    }
    if(mmyy&&yymm){System.out.println("AMBIGUOUS");}
    if(mmyy&&!yymm){System.out.println("MMYY");}
    if(!mmyy&&yymm){System.out.println("YYMM");}
    if(!mmyy&&!yymm){System.out.println("NA");}
  }
}