Problem:
Problem A: ICPC Score Totalizer Software

The International Clown and Pierrot Competition (ICPC), is one of the
most distinguished and also the most popular events on earth in the
show business.

One of the unique features of this contest is the great number of
judges that sometimes counts up to one hundred. The number of judges
may differ from one contestant to another, because judges with any
relationship whatsoever with a specific contestant are temporarily
excluded for scoring his/her performance.

Basically, scores given to a contestant's performance by the judges
are averaged to decide his/her score. To avoid letting judges with
eccentric viewpoints too much influence the score, the highest and the
lowest scores are set aside in this calculation. If the same highest
score is marked by two or more judges, only one of them is ignored.
The same is with the lowest score. The average, which may contain
fractions, are truncated down to obtain final score as an integer.

You are asked to write a program that computes the scores of
performances, given the scores of all the judges, to speed up the event
to be suited for a TV program.

Input

The input consists of a number of datasets, each corresponding to a
contestant's performance. There are no more than 20 datasets in the input.

A dataset begins with a line with an integer n, the number of
judges participated in scoring the performance (3 ≤ n ≤
100). Each of the n lines following it has an integral
score s (0 ≤ s ≤ 1000) marked by a judge. No
other characters except for digits to express these numbers are in the
input. Judges' names are kept secret.

The end of the input is indicated by a line with a single zero in it.

Output

For each dataset, a line containing a single decimal integer
indicating the score for the corresponding performance should be
output. No other characters should be on the output line.

Sample Input

3
1000
342
0
5
2
2
9
11
932
5
300
1000
0
200
400
8
353
242
402
274
283
132
402
523
0

Output for the Sample Input

342
7
300
326

Solution in JAVA (judge verdict: Accepted)

import java.util.*;

public class Main {
	static int mod = 1000000007;
  static int size = 200000;
	static long[] fac = new long[size];
	static long[] finv = new long[size];
	static long[] inv = new long[size];
  static int INF = Integer.MAX_VALUE;

 	public static void main(String[] args){
		Scanner scanner = new Scanner(System.in);
		while(true){
			int n = scanner.nextInt();
			if(n == 0) break;
			int sum = 0;
			int max = 0;
			int min = 1001;
			int[] a = new int[n];
			for(int i = 0; i < n; i++){
				a[i] = scanner.nextInt();
				max = Math.max(a[i],max);
				min = Math.min(a[i],min);
				sum += a[i];
			}
			sum -= (max+min);
			sum /= (n-2);
			System.out.println(sum);
		}
	}
  static class Pair implements Comparable<Pair>{
    int x, y;
    Pair(int a, int b){
        x = a;
        y = b;
    }
    @Override
    public boolean equals(Object o){
        if (this == o) return true;
        if (!(o instanceof Pair)) return false;
        Pair p = (Pair) o;
        return x == p.x && y == p.y;
    }
    @Override
    public int compareTo(Pair p){
        //return x == p.x ? y - p.y : x - p.x; //xで昇順にソート
        //return (x == p.x ? y - p.y : x - p.x) * -1; //xで降順にソート
        //return y == p.y ? x - p.x : y - p.y;//yで昇順にソート
        return (y == p.y ? x - p.x : y - p.y)*-1;//yで降順にソート
    }
  }
  //繰り返し二乗法
  public static long pow(long x, long n){
    long ans = 1;
    while(n > 0){
      if((n & 1) == 1){
        ans = ans * x;
        ans %= mod;
      }
      x = x * x % mod;
      n >>= 1;
    }
    return ans;
  }

  //fac, inv, finvテーブルの初期化、これ使う場合はinitComb()で初期化必要
	public static  void initComb(){
		fac[0] = finv[0] = inv[0] = fac[1] = finv[1] = inv[1] = 1;
		for (int i = 2; i < size; ++i) {
			fac[i] = fac[i - 1] * i % mod;
			inv[i] = mod - (mod / i) * inv[(int) (mod % i)] % mod;
			finv[i] = finv[i - 1] * inv[i] % mod;
		}
	}

	//nCk % mod
	public static long comb(int n, int k){
		return fac[n] * finv[k] % mod * finv[n - k] % mod;
	}

	//n! % mod
	public static long fact(int n){
		return fac[n];
	}

	//(n!)^-1 with % mod
	public static long finv(int n){
		return finv[n];
	}

  static class UnionFind {
    int[] parent;
    public UnionFind(int size) {
      parent = new int[size];
      Arrays.fill(parent, -1);
    }
    public boolean unite(int x, int y) {
      x = root(x);
      y = root(y);
      if (x != y) {
        if (parent[y] < parent[x]) {
          int tmp = y;
          y = x;
          x = tmp;
        }
        parent[x] += parent[y];
        parent[y] = x;
        return true;
      }
      return false;
    }
    public boolean same(int x, int y) {
      return root(x) == root(y);
    }
    public int root(int x) {
      return parent[x] < 0 ? x : (parent[x] = root(parent[x]));
    }
    public int size(int x) {
      return -parent[root(x)];
    }
  }
	public static int upperBound(long[] array, long value) {
			 int low = 0;
			 int high = array.length;
			 int mid;
			 while( low < high ) {
					 mid = ((high - low) >>> 1) + low; // (high + low) / 2
					 if( array[mid] <= value ) {
							 low = mid + 1;
					 } else {
							 high = mid;
					 }
			 }
			 return low;
	 }
  //n,mの最大公約数
  public static int gcd(int n, int m){
    if(m > n) return gcd(m,n);
    if(m == 0) return n;
    return gcd(m, n%m);
  }
}