Problem:
Score : 600 points

Problem Statement

Ringo Mart, a convenience store, sells apple juice.

On the opening day of Ringo Mart, there were A cans of juice in stock in the morning.
Snuke buys B cans of juice here every day in the daytime.
Then, the manager checks the number of cans of juice remaining in stock every night.
If there are C or less cans, D new cans will be added to the stock by the next morning.

Determine if Snuke can buy juice indefinitely, that is, there is always B or more cans of juice in stock when he attempts to buy them.
Nobody besides Snuke buy juice at this store.

Note that each test case in this problem consists of T queries.

Constraints

1 \leq T \leq 300

1 \leq A, B, C, D \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

T
A_1 B_1 C_1 D_1
A_2 B_2 C_2 D_2
:
A_T B_T C_T D_T

In the i-th query, A = A_i, B = B_i, C = C_i, D = D_i.

Output

Print T lines. The i-th line should contain Yes if Snuke can buy apple juice indefinitely in the i-th query; No otherwise.

Sample Input 1

14
9 7 5 9
9 7 6 9
14 10 7 12
14 10 8 12
14 10 9 12
14 10 7 11
14 10 8 11
14 10 9 11
9 10 5 10
10 10 5 10
11 10 5 10
16 10 5 10
1000000000000000000 17 14 999999999999999985
1000000000000000000 17 15 999999999999999985

Sample Output 1

No
Yes
No
Yes
Yes
No
No
Yes
No
Yes
Yes
No
No
Yes

In the first query, the number of cans of juice in stock changes as follows: (D represents daytime and N represents night.)

9
→D 2
→N 11
→D 4
→N 13
→D 6
→N 6
→D x

In the second query, the number of cans of juice in stock changes as follows:

9
→D 2
→N 11
→D 4
→N 13
→D 6
→N 15
→D 8
→N 8
→D 1
→N 10
→D 3
→N 12
→D 5
→N 14
→D 7
→N 7
→D 0
→N 9
→D 2
→N 11
→D …

and so on, thus Snuke can buy juice indefinitely.

Sample Input 2

24
1 2 3 4
1 2 4 3
1 3 2 4
1 3 4 2
1 4 2 3
1 4 3 2
2 1 3 4
2 1 4 3
2 3 1 4
2 3 4 1
2 4 1 3
2 4 3 1
3 1 2 4
3 1 4 2
3 2 1 4
3 2 4 1
3 4 1 2
3 4 2 1
4 1 2 3
4 1 3 2
4 2 1 3
4 2 3 1
4 3 1 2
4 3 2 1

Sample Output 2

No
No
No
No
No
No
Yes
Yes
No
No
No
No
Yes
Yes
Yes
No
No
No
Yes
Yes
Yes
No
No
No

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Runtime Error)

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.nio.charset.StandardCharsets;
import java.util.*;

public class Main {

    int[] inputArray;
    Set<String> set = new HashSet<>();
    int K;

    public static void main(String[] args) throws IOException {
        new Main().run();
    }

    void run() {
        Scanner sc = new Scanner(System.in);
        int N = sc.nextInt();
        long sum = 0;

        for(int i=0; i<N; i++){
            long a = sc.nextLong();
            long b = sc.nextLong();
            long c = sc.nextLong();
            long d = sc.nextLong();

            long first = a % b;
            long constValue = d % b;
            long check = -1;
            long num = c;

            if(a < b){
                System.out.println("No");
            } else if(b > d){
                System.out.println("No");
            } else if(b <= c){
                System.out.println("Yes");
            } else if(constValue == 0){
                if(a % b > c){
                    System.out.println("No");
                } else {
                    System.out.println("Yes");
                }
            } else {
//                int count = 1;
                if(Math.max(first, constValue) % Math.min(first, constValue) == 0){
                    check = (c/constValue+1)*constValue;
                } else {
                    check = (c/constValue+1)*constValue + first;
                }
//                while(true){
//                    tmp++;
////                    tmp = constValue * count;
////                    if(tmp > c){
//                    if(tmp % constValue == 0){
//                        check = tmp;
//                        break;
//                    }
////                    count++;
//                }

                if(check < b){
                    System.out.println("No");
                } else {
                    System.out.println("Yes");
                }
            }
        }

    }

    void substring(String s, int num){
        for(int i=1; i<=num; i++){
            if(i > K){
                break;
            }
            for(int j=0; j<num; j++){
                if(j + i-1 < num){
//                    System.out.println(s.substring(j, j+i));
                    set.add(s.substring(j, j+i));
                } else {
                    break;
                }
            }
        }
    }

    void permutation(String s, String ans){
        if(s.length() <= 1){
            System.out.println(ans + s);
        } else {
            for(int i=0; i<s.length(); i++){
                permutation(s.substring(0, i) + s.substring(i + 1), ans + s.charAt(i));
            }
        }
    }
}