Problem:
Score : 100 points

Problem Statement

Taro's summer vacation starts tomorrow, and he has decided to make plans for it now.

The vacation consists of N days.
For each i (1 \leq i \leq N), Taro will choose one of the following activities and do it on the i-th day:

A: Swim in the sea. Gain a_i points of happiness.

B: Catch bugs in the mountains. Gain b_i points of happiness.

C: Do homework at home. Gain c_i points of happiness.

As Taro gets bored easily, he cannot do the same activities for two or more consecutive days.

Find the maximum possible total points of happiness that Taro gains.

Constraints

All values in input are integers.

1 \leq N \leq 10^5

1 \leq a_i, b_i, c_i \leq 10^4

Input

Input is given from Standard Input in the following format:

N
a_1 b_1 c_1
a_2 b_2 c_2
:
a_N b_N c_N

Output

Print the maximum possible total points of happiness that Taro gains.

Sample Input 1

3
10 40 70
20 50 80
30 60 90

Sample Output 1

210

If Taro does activities in the order C, B, C, he will gain 70 + 50 + 90 = 210 points of happiness.

Sample Input 2

1
100 10 1

Sample Output 2

100

Sample Input 3

7
6 7 8
8 8 3
2 5 2
7 8 6
4 6 8
2 3 4
7 5 1

Sample Output 3

46

Taro should do activities in the order C, A, B, A, C, B, A.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Scanner;

public class Main {
    static final Scanner sc  = new Scanner(System.in);
    static final int     MOD = (int) 1E9 + 7;
    static final int INF = Integer.MAX_VALUE;

    public static void main(String[] args) {
        int N = nint();
        final int A = 0, B = 1, C = 2;
        int[][] in = new int[3][N];
        for (int n = 0; n < N; n++) {
            for (int x = A; x <= C; x++) {
                in[x][n] = nint();
            }
        }
        
        int[][] dp = new int[3][N];
        for (int x = A; x <= C; x++) {
            dp[x][0] = in[x][0];
        }
        
        for (int i = 1; i < N; i++) {
            for (int x = A; x <= C; x++) {
                dp[x][i] = max(dp[(x+1) % 3][i-1], dp[(x+2) % 3][i-1]) + in[x][i];
            }
        }
        
        System.out.println(max(dp[A][N-1], dp[B][N-1], dp[C][N-1]));
    }
    static int max(int... ints) {
        int max = -INF;
        for (int i: ints) {
            max = Math.max(i, max);
        }
        return max;
    }

    private static long nlong() {
        return sc.nextLong();
    }

    private static int nint() {
        return sc.nextInt();
    }

    private static String nstr() {
        return sc.next();
    }

    private static char[] nchars() {
        return sc.next().toCharArray();
    }

    private static int[] nints(int n) {
        return nints(n, 0, 0);
    }

    private static int[] nints(int n, int padL, int padR) {
        int[] a = new int[padL + n + padR];
        for (int i = 0; i < n; i++)
            a[padL + i] = nint();
        return a;
    }

    private static char[][] nchars2(int h, int w) {
        return nchars2(h, w, 0);
    }

    private static char[][] nchars2(int h, int w, int pad) {
        char[][] a2 = new char[h + pad * 2][w + pad * 2];
        for (int i = 0; i < h; i++)
            System.arraycopy(nchars(), 0, a2[pad + i], pad, w);
        return a2;
    }
}