Problem:
Score : 200 points

Problem Statement

La Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each.
Determine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.

Constraints

N is an integer between 1 and 100, inclusive.

Input

Input is given from Standard Input in the following format:

N

Output

If there is a way to buy some cakes and some doughnuts for exactly N dollars, print Yes; otherwise, print No.

Sample Input 1

11

Sample Output 1

Yes

If you buy one cake and one doughnut, the total will be 4 + 7 = 11 dollars.

Sample Input 2

40

Sample Output 2

Yes

If you buy ten cakes, the total will be 4 \times 10 = 40 dollars.

Sample Input 3

3

Sample Output 3

No

The prices of cakes (4 dollars) and doughnuts (7 dollars) are both higher than 3 dollars, so there is no such way.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.ArrayList;
import java.util.Scanner;


public class Main {

	public static void main(String[] args) {

		Scanner scanner = new Scanner(System.in);

		int toi = Integer.parseInt(scanner.nextLine());
		int atemp = toi;
		int btemp = toi;

		if(toi > 3) {
			if(toi % 4 == 0  || toi % 7 == 0) {
				System.out.println("Yes");
			}else{
				for(int i = 0; i < toi / 7; i ++) {
					atemp -= 4;
					btemp -= 4;
					if(atemp % 7 == 0) {
						System.out.println("Yes");
						break;
					}
					if(btemp % 4 == 0) {
						System.out.println("Yes");
						break;
					}
				}
			}
		}else{
			System.out.println("No");
		}
	}
}