Problem:
Score : 300 points

Problem Statement

You are given a sequence of length N: A_1, A_2, ..., A_N.
For each integer i between 1 and N (inclusive), answer the following question:

Find the maximum value among the N-1 elements other than A_i in the sequence.

Constraints

2 \leq N \leq 200000

1 \leq A_i \leq 200000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1
:
A_N

Output

Print N lines. The i-th line (1 \leq i \leq N) should contain the maximum value among the N-1 elements other than A_i in the sequence.

Sample Input 1

3
1
4
3

Sample Output 1

4
3
4

The maximum value among the two elements other than A_1, that is, A_2 = 4 and A_3 = 3, is 4.

The maximum value among the two elements other than A_2, that is, A_1 = 1 and A_3 = 3, is 3.

The maximum value among the two elements other than A_3, that is, A_1 = 1 and A_2 = 4, is 4.

Sample Input 2

2
5
5

Sample Output 2

5
5

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)



import java.util.Scanner;

public class Main {

	public static void main(String args[])
	{
		Scanner scan=new Scanner(System.in);
		int n=scan.nextInt();
		int ar[]=new int[n];
		for(int i=0;i<n;i++)
		{
			ar[i]=scan.nextInt();
		}
		int left[]=new int[n];
		int right[]=new int[n];
		for(int i=0;i<n;i++)
		{
			if(i==0)left[i]=ar[i];else
				left[i]=Math.max(ar[i],left[i-1]);
		}
		for(int i=n-1;i>=0;i--)
		{
			if(i==n-1)
			{
				right[i]=ar[i];
			}else{
				right[i]=Math.max(ar[i],right[i+1]);
			}
		}
		for(int i=0;i<n;i++)
		{
			if(i==0)
			{
				System.out.println(right[i+1]);
			}else if(i==n-1)
			{
				System.out.println(left[n-2]);
			}else {
			System.out.println(Math.max(left[i-1],right[i+1]));
			}
			}
	}
}