Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Accepted)

import java.util.Scanner;

class Main{
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        String str;
        int i,num;
        int[] count = new int[26];
        for(i=0;i<26;i++) count[i] = 0;
        while(sc.hasNext()){
            str = sc.nextLine().replace(" ","");
            str = str.replace(".","");
            str = str.replace("\n","");
            str = str.toLowerCase();
            for(i=0;i<str.length();i++){
                if(str.charAt(i)-97>=0&&str.charAt(i)-97<26) count[(int)str.charAt(i)-97]++;
            }
        }
        for(i=0;i<26;i++){
            System.out.println((char)('a'+i) + " : " + count[i]);
        }
    }
}