Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in Java (OpenJDK 11.0.6) (judge verdict: Accepted)

import java.util.Scanner;

// 7
public class Main {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int[][] a = new int[3][3];
        for(int i = 0; i < 3; i++)
            for(int j = 0; j < 3; j++)
                a[i][j] = sc.nextInt();
        int N = sc.nextInt();
        int[] b = new int[N];
        for(int i = 0; i < N; i++)
            b[i] = sc.nextInt();

        int count = 0;
        //if count >= 6 then break
        int i, j, k = 0;
        for(i = 0; i < 3; i++)
            for(j = 0; j < 3; j++) {
                for(k = 0; k < N; k++) {
                    if(b[k] == a[i][j]) {
                        a[i][j] = -1;
                        ++count;
                        if(count == 7) {
                            i = j = k = 10;
                            System.out.println("Yes");
                        }
                    }
                }
            }

        String ans = "No";
        if(count <= 6) {
            for(int ii = 0; ii < 3; ii++)
                if(a[ii][0] == -1 && a[ii][1] == -1 && a[ii][2] == -1) {
                    ans = "Yes";
                    break;
                }
            for(int jj = 0; jj < 3; jj++)
                if(a[0][jj] == -1 && a[1][jj] == -1 && a[2][jj] == -1) {
                    ans = "Yes";
                    break;
                }

            if(a[0][0] == -1 && a[1][1] == -1 && a[2][2] == -1) {
                ans = "Yes";
            }
            if(a[2][0] == -1 && a[1][1] == -1 && a[0][2] == -1) {
                ans = "Yes";
            }
            System.out.println(ans);
        }
    }

}