Problem:
Score : 200 points

Problem Statement

Let us define the FizzBuzz sequence a_1,a_2,... as follows:

If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.

If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.

If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.

If none of the above holds, a_i=i.

Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Constraints

1 \leq N \leq 10^6

Input

Input is given from Standard Input in the following format:

N

Output

Print the sum of all numbers among the first N terms of the FizzBuzz sequence.

Sample Input 1

15

Sample Output 1

60

The first 15 terms of the FizzBuzz sequence are:

1,2,\mbox{Fizz},4,\mbox{Buzz},\mbox{Fizz},7,8,\mbox{Fizz},\mbox{Buzz},11,\mbox{Fizz},13,14,\mbox{FizzBuzz}

Among them, numbers are 1,2,4,7,8,11,13,14, and the sum of them is 60.

Sample Input 2

1000000

Sample Output 2

266666333332

Watch out for overflow.

Solution in Java (OpenJDK 11.0.6) (judge verdict: Accepted)


import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class Main
{

  static boolean[][] z = new boolean[22][22];
  static boolean[][] zz = new boolean[22][22];
  public static void main(String[] args) throws IOException
  {
    BufferedReader r = new BufferedReader(new InputStreamReader(System.in), 1);
    String s;
    String sl[];

    s = r.readLine();
    sl = s.split(" ");

    int n = Integer.parseInt(sl[0]);
    long v = 0;

    for(int i = 0; i <= n; i++)
    {
      if(i % 3 != 0 && i % 5 != 0)
      {
        v += i;
      }
    }

    System.out.println(v);
  }

}

class RemRing
{
  long module;

  public RemRing(long module)
  {
    this.module = module;
  }

  public long sum(long a, long b)
  {
    return (a + b + module) % module;
  }

  public long sub(long a, long b)
  {
    return (a - b + module) % module;
  }

  public long prod(long a, long b)
  {
    return (a * b) % module;
  }

  public long div(long a, long b)
  {
    return (a * inv(b)) % module;
  }

  public long inv(long a)
  {
    long b = this.module;
    long u = 1;
    long v = 0;
    while (b > 0)
    {
      long t = a / b;
      a -= t * b;
      u -= t * v;
      long z = a;
      a = b;
      b = z;
      z = u;
      u = v;
      v = z;
    }
    u %= this.module;
    if (u < 0)
      u += this.module;
    return u;
  }
}