Problem:
Score : 100 points

Problem Statement

You are given four digits N_1, N_2, N_3 and N_4. Determine if these can be arranged into the sequence of digits "1974".

Constraints

0 \leq N_1, N_2, N_3, N_4 \leq 9

N_1, N_2, N_3 and N_4 are integers.

Input

Input is given from Standard Input in the following format:

N_1 N_2 N_3 N_4

Output

If N_1, N_2, N_3 and N_4 can be arranged into the sequence of digits "1974", print YES; if they cannot, print NO.

Sample Input 1

1 7 9 4

Sample Output 1

YES

We can get 1974 by swapping N_2 and N_3.

Sample Input 2

1 9 7 4

Sample Output 2

YES

We already have 1974 before doing anything.

Sample Input 3

1 2 9 1

Sample Output 3

NO

Sample Input 4

4 9 0 8

Sample Output 4

NO

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Scanner;

public class Main{
public static void main(String[] args){
  Scanner sc = new Scanner(System.in);
  int N1 = sc.nextInt();  
  int N2 = sc.nextInt();
  int N3 = sc.nextInt();
  int N4 = sc.nextInt();
  
  int a1 = (N1-1)*(N2-1)*(N3-1)*(N4-1);
  int a4 = (N1-4)*(N2-4)*(N3-4)*(N4-4);
  int a7 = (N1-7)*(N2-7)*(N3-7)*(N4-7);
  int a9 = (N1-9)*(N2-9)*(N3-9)*(N4-9);
  
if(a1==0 && a4 == 0 && a7==0 && a9==0){
  System.out.println("YES");
}else{
  System.out.println("NO");
}

}
}