Problem:
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Distance II

Your task is to calculate the distance between two $n$ dimensional vectors $x = \{x_1, x_2, ..., x_n\}$ and $y = \{y_1, y_2, ..., y_n\}$.

The Minkowski's distance defined below is a metric which is a generalization of both the Manhattan distance and the Euclidean distance.

\[
D_{xy} = (\sum_{i=1}^n |x_i - y_i|^p)^{\frac{1}{p}}
\]

It can be the Manhattan distance

\[
D_{xy} = |x_1 - y_1| + |x_2 - y_2| + ... + |x_n - y_n|
\]

where $p = 1 $.

It can be the Euclidean distance

\[
D_{xy} = \sqrt{(|x_1 - y_1|)^{2} + (|x_2 - y_2|)^{2} + ... + (|x_n - y_n|)^{2}}
\]

where $p = 2 $.

Also, it can be the Chebyshev distance

\[
D_{xy} = max_{i=1}^n (|x_i - y_i|)
\]

where $p = \infty$

Write a program which reads two $n$ dimensional vectors $x$ and $y$, and calculates Minkowski's distance where $p = 1, 2, 3, \infty$ respectively.

Input

In the first line, an integer $n$ is given. In the second and third line, $x = \{x_1, x_2, ... x_n\}$ and $y = \{y_1, y_2, ... y_n\}$ are given respectively. The elements in $x$ and $y$ are given in integers.

Output

Print the distance where $p = 1, 2, 3$ and $\infty$ in a line respectively.
The output should not contain an absolute error greater than 10-5.

Constraints

$1 \leq n \leq 100$

$0 \leq x_i, y_i \leq 1000$

Sample Input

3
1 2 3
2 0 4

Sample Output

4.000000
2.449490
2.154435
2.000000

Solution in JAVA (judge verdict: Accepted)

import java.io.IOException;
import java.io.PrintWriter;
import java.text.DecimalFormat;
import java.util.Scanner;

class Main{
    private static final Scanner sc = new Scanner(System.in);
    private static final DecimalFormat fmt = new DecimalFormat("0.########");
    private static final PrintWriter out = new PrintWriter(System.out);
    public static void main(String[] Args) throws IOException{
        final int n = Integer.parseInt(sc.next());
        final int x[] = new int[n];
        for(int i = 0; i<n; i++)
            x[i] = Integer.parseInt(sc.next());
        int d1 = 0, d2 = 0, di = 0;
        long d3 = 0;
        for(int i = 0; i<n; i++){
            final int y = Math.abs(Integer.parseInt(sc.next())-x[i]);
            d1 += y;
            d2 += y*y;
            d3 += y*y*y;
            di = Math.max(di, y);
        }
        out.println(d1);
        out.println(fmt.format(Math.sqrt(d2)));
        out.println(fmt.format(Math.pow(d3, 1.0/3.0)));
        out.println(di);
        out.flush();
    }
}