Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Accepted)

public class Main {
    public static void main(String[] args) {

        // ??????????????????????????????.
        java.util.Scanner sc = new java.util.Scanner(System.in);

        // ??¢??????????????????????????°????¨??????????????????????????????????????????????.
        int[] num = new int[26];
        for (int i = 0; i < 26; i ++) { num[i] = 0; }

        // ???????????????????????§????????????????????? 1 ?????\???????????????????????????.
        // ???????????? 1 ???????????????????????¢??????????????????????????°?????????????????????.
        while (sc.hasNext()) {
            String s = sc.nextLine();
            for (int i = 0; i < s.length(); i ++) {
                if (s.charAt(i) <= 'Z' && 'A' <= s.charAt(i)) { num[s.charAt(i) - 'A'] ++; }
                else if (s.charAt(i) <= 'z' && 'a' <= s.charAt(i)) { num[s.charAt(i) - 'a'] ++; }
            }
        }
        char c = 'a';
        for (int i = 0; i < 26; i ++) {
            System.out.println(c + " : " + num[i]);
            c ++;
        }
    }
}