Problem:
Score : 100 points

Problem Statement

You went shopping to buy cakes and donuts with X yen (the currency of Japan).

First, you bought one cake for A yen at a cake shop.
Then, you bought as many donuts as possible for B yen each, at a donut shop.

How much do you have left after shopping?

Constraints

1 \leq A, B \leq 1 000

A + B \leq X \leq 10 000

X, A and B are integers.

Input

Input is given from Standard Input in the following format:

X
A
B

Output

Print the amount you have left after shopping.

Sample Input 1

1234
150
100

Sample Output 1

84

You have 1234 - 150 = 1084 yen left after buying a cake.
With this amount, you can buy 10 donuts, after which you have 84 yen left.

Sample Input 2

1000
108
108

Sample Output 2

28

Sample Input 3

579
123
456

Sample Output 3

0

Sample Input 4

7477
549
593

Sample Output 4

405

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)


import java.util.*;
public class Main {
	public static void main(String[] args){
		Scanner sc = new Scanner(System.in);
 
   //  String[] nyu=sc.nextLine().split("");

     String nyu=sc.nextLine();
//int A=Integer.parseInt(nyu[0]);
//int B=Integer.parseInt(nyu[1]);
int C=Integer.parseInt(nyu);
     nyu=sc.nextLine();

int D=Integer.parseInt(nyu);
     nyu=sc.nextLine();

int E=Integer.parseInt(nyu);


//double A=Double.parseDouble(nyu[0]);
//double B=Double.parseDouble(nyu[1]);
/*
switch(C){
case 7:
case 5:
case 3:
System.out.println("YES") ;
break;
default:
System.out.println("NO") ;

break;
}
*/

int res=(C-D)%E;
//if(res<=D){

System.out.println(res);
//}else{
//System.out.println("No");

//}




	}
}