Problem:
Simultaneous Equation

Write a program which solve a simultaneous equation:

ax + by = c

dx + ey = f

The program should print x and y for given a, b, c, d, e and f (-1,000 ≤ a, b, c, d, e, f ≤ 1,000). You can suppose that given equation has a unique solution.

Input

The input consists of several data sets, 1 line for each data set. In a data set, there will be a, b, c, d, e, f separated by a single space. The input terminates with EOF.

Output

For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.

Sample Input 1

1 2 3 4 5 6
2 -1 -2 -1 -1 -5

Output for the Sample Input 1

-1.000 2.000
1.000 4.000

Sample Input 2

2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27

Output for the Sample Input 2

0.000 3.000
0.000 3.000

Solution in JAVA (judge verdict: Wrong Answer)

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.text.DecimalFormat;
import java.util.ArrayList;
import java.util.Scanner;


class Main {
	public static void main(String[] args) throws IOException {
		DecimalFormat df1 = new DecimalFormat("0.000");
		Scanner in = new Scanner(System.in);
		ArrayList<String> SL = new ArrayList<String>();
		
		
		while((in.hasNext())){
			String li = in.nextLine();
			SL.add(li);
			}
		System.out.println("ok");
		for(String s : SL){
			String[] ss = s.split(" ");
			double x1 = Double.parseDouble(ss[0]);
			double y1 = Double.parseDouble(ss[1]);
			double a1 = Double.parseDouble(ss[2]);
			double x2 = Double.parseDouble(ss[3]);
			double y2 = Double.parseDouble(ss[4]);
			double a2 = Double.parseDouble(ss[5]);
			double y3 = y1*x2 - y2*x1;
			double a3 = a1*x2 - a2*x1;
			double y = a3/y3;
			double x = (a1 - y1*y) / x1;
			System.out.println(df1.format(x) +" "+df1.format(y));
			
			
		}
		
		
	}

}