Problem:
Score : 100 points

Problem Statement

Takahashi is a user of a site that hosts programming contests.

When a user competes in a contest, the rating of the user (not necessarily an integer) changes according to the performance of the user, as follows:

Let the current rating of the user be a.

Suppose that the performance of the user in the contest is b.

Then, the new rating of the user will be the avarage of a and b.

For example, if a user with rating 1 competes in a contest and gives performance 1000, his/her new rating will be 500.5, the average of 1 and 1000.

Takahashi's current rating is R, and he wants his rating to be exactly G after the next contest.

Find the performance required to achieve it.

Constraints

0 \leq R, G \leq 4500

All input values are integers.

Input

Input is given from Standard Input in the following format:

R
G

Output

Print the performance required to achieve the objective.

Sample Input 1

2002
2017

Sample Output 1

2032

Takahashi's current rating is 2002.

If his performance in the contest is 2032, his rating will be the average of 2002 and 2032, which is equal to the desired rating, 2017.

Sample Input 2

4500
0

Sample Output 2

-4500

Although the current and desired ratings are between 0 and 4500, the performance of a user can be below 0.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Map;
import java.util.Scanner;

public class Main {

    /**
     * 本処理を実行します。
     */
    public static void execute() {
        Scanner sc = new Scanner(System.in);

        int r = nextInt(sc);
        int g = nextInt(sc);

        int s = g - r;

        out(g + s);
    }

    /**
     * 次の標準入力をintで受け取ります。
     * @return 標準入力値(int)
     */
    public static int nextInt(Scanner sc) {
        return sc.nextInt();
    }

    /**
     * 次の標準入力をStringで受け取ります。
     * @return 標準入力値(String)
     */
    public static String nextString(Scanner sc) {
        return sc.next();
    }

    /**
     * 次の標準入力を指定回数分intで受け取ります。
     * @param n 取得回数
     * @return 取得した標準入力値の配列(int)
     */
    public static int[] nextInts(Scanner sc, int n) {
        int[] arr = new int[n];

        for (int i = 0; i < n; i++) {
            arr[i] = nextInt(sc);
        }

        return arr;
    }

    /**
     * 標準出力にオブジェクトを出力します。
     * @param o 出力対象
     */
    public static void out(Object o) {
        System.out.println(o);
    }

    public static void main(String[] args) {
        execute();
    }

    public static void putCountMap(Map<Integer, Integer> map, int value) {
        if (map.containsKey(value)) {
            map.put(value, map.get(value) + 1);
        } else {
            map.put(value, 1);
        }
    }
}