Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Accepted)

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class Main {

    public static void main(String[] args) throws IOException {

        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        String input;

        int[] count = new int[26];

        while((input = br.readLine()) != null){
            if(input.equals("")){
                break;
            }
//          ??¨????°????????????????
            input = input.toLowerCase();

//          ????????????????????????????´?
            char[] ch = input.toCharArray();

            for(char alpha : ch ){
                if('a' <= alpha && alpha <= 'z'){
//                  a????????°??????alpha???????????????1?????????a??????????????°=?????????????????????alpha?????°
                    count[alpha - 'a']++;
                }
            }
        }
        for(int i = 0; i < count.length; i++){
            System.out.println((char)('a' + i) + " : " + count[i]);
        }
    }
}