Problem:
Score : 200 points

Problem Statement

Tak performed the following action N times: rolling two dice.
The result of the i-th roll is D_{i,1} and D_{i,2}.

Check if doublets occurred at least three times in a row.
Specifically, check if there exists at lease one i such that D_{i,1}=D_{i,2}, D_{i+1,1}=D_{i+1,2} and D_{i+2,1}=D_{i+2,2} hold.

Constraints

3 \leq N \leq 100

1\leq D_{i,j} \leq 6

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
D_{1,1} D_{1,2}
\vdots
D_{N,1} D_{N,2}

Output

Print Yes if doublets occurred at least three times in a row. Print No otherwise.

Sample Input 1

5
1 2
6 6
4 4
3 3
3 2

Sample Output 1

Yes

From the second roll to the fourth roll, three doublets occurred in a row.

Sample Input 2

5
1 1
2 2
3 4
5 5
6 6

Sample Output 2

No

Sample Input 3

6
1 1
2 2
3 3
4 4
5 5
6 6

Sample Output 3

Yes

Solution in Java (OpenJDK 11.0.6) (judge verdict: Accepted)

import java.util.*;
// 繰り返し回数N
// 一行目数値1　数値2 
// 二行目数値1　数値2 で渡された場合で渡された場合
public class Main {
  public static void main(String[] args ) throws Exception {
    Scanner sc = new Scanner(System.in);
    int N = sc.nextInt();
    String ansFlg = "";
    String ans = "";
    int stack = 0;
    String stackFlg = "";
    for (int i = 0; i < N; i++) {
      String token1 = sc.next();
      String token2 = sc.next();
      // 文字列比較は == ではなく　StringA.equals(StringB)
      if(token1.equals(token2)){
          stack += 1;
          stackFlg = "X";
          if(stack == 3){
              ansFlg = "X";
              break;
          }else{
              //特になし
          }
      }
      // stackFlgがない場合にstackをリセットし、その後スタックフラグを切る
      if(stackFlg.equals("X")){
          //特になし
      }else{
          stack = 0;
      }
      stackFlg = "";
    }
    
    if(ansFlg == "X"){
        ans = "Yes";
    }else{
        ans = "No";
    }
    System.out.println(ans);
  }
}