Problem:
Score : 100 points

Problem Statement

You are given four digits N_1, N_2, N_3 and N_4. Determine if these can be arranged into the sequence of digits "1974".

Constraints

0 \leq N_1, N_2, N_3, N_4 \leq 9

N_1, N_2, N_3 and N_4 are integers.

Input

Input is given from Standard Input in the following format:

N_1 N_2 N_3 N_4

Output

If N_1, N_2, N_3 and N_4 can be arranged into the sequence of digits "1974", print YES; if they cannot, print NO.

Sample Input 1

1 7 9 4

Sample Output 1

YES

We can get 1974 by swapping N_2 and N_3.

Sample Input 2

1 9 7 4

Sample Output 2

YES

We already have 1974 before doing anything.

Sample Input 3

1 2 9 1

Sample Output 3

NO

Sample Input 4

4 9 0 8

Sample Output 4

NO

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.lang.reflect.Array;
import java.util.*;

/**
 * Created by Santa.
 */
public class Main {

  static int N;
  static int K;
  static long Q;
  static int A;
  static long B;
  static long C;
  static double min = 9999999;
  static long ans = 0;




  public static void main(String[] args) {
    Scanner scanner = new Scanner(System.in);
    int[] map = new int[10];
    int a = scanner.nextInt();
    map[a] = 1;

    int b = scanner.nextInt();
    map[b] = 1;

    a = scanner.nextInt();
    map[a] = 1;
    a = scanner.nextInt();
    map[a] = 1;


    if(map[1] == 1 && map[7] == 1 && map[9] == 1 && map[4] == 1){
      System.out.println("YES");
    }else{
      System.out.println("NO");
    }


  }

}