Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Wrong Answer)

import java.util.Scanner;

public class Main {
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);

		String line = sc.nextLine();
		String text = null;
		char[] c = new char[line.length()];

		for (int i = 0; i < line.length(); i++) {
			c[i] = line.charAt(i);
			if (c[i] != ' ') {
				text += c[i];
			}
		}

		char[] newc = new char[text.length()];
		if (text.length() > 1200) {
			System.exit(0);
		}
		for (int j = 'a'; j < 'z'; j++) {
			int count = 0;
			for (int i = 0; i < text.length(); i++) {
				newc[i] = text.charAt(i);
				if (newc[i] == (char) j || newc[i] == (char) (j + 36)) {
					count++;
				}

			}
			System.out.println((char) j + " : " + count);

			sc.close();
		}

	}

}