Problem:
Bubble Sort

Write a program of the Bubble Sort algorithm which sorts a sequence A in ascending order. The algorithm should be based on the following pseudocode:

BubbleSort(A)
1 for i = 0 to A.length-1
2 for j = A.length-1 downto i+1
3 if A[j] < A[j-1]
4 swap A[j] and A[j-1]

Note that, indices for array elements are based on 0-origin.

Your program should also print the number of swap operations defined in line 4 of the pseudocode.

Input

The first line of the input includes an integer N, the number of elements in the sequence.

In the second line, N elements of the sequence are given separated by spaces characters.

Output

The output consists of 2 lines.

In the first line, please print the sorted sequence. Two contiguous elements of the sequence should be separated by a space character.

In the second line, please print the number of swap operations.

Constraints

1 ≤ N ≤ 100

Sample Input 1

5
5 3 2 4 1

Sample Output 1

1 2 3 4 5
8

Sample Input 2

6
5 2 4 6 1 3

Sample Output 2

1 2 3 4 5 6
9

Solution in JAVA (judge verdict: Accepted)

import java.util.Scanner;

class Main{
    public static void main(String[] args){
	int i;
	int j;
	int v;
	int flag = 1;
	int count = 0;
	
	Scanner scan = new Scanner(System.in);
	int n = scan.nextInt();
	int A[] = new int[n];

	//Initialize data
	for(i=0 ; i<A.length ; i++){
	    int num = scan.nextInt();
	    A[i] = num;
	}
	
	while( flag==1 ){
	    flag = 0;
	    for(j=n-1 ; j>0 ; j--){
		if(A[j] < A[j-1]){
		    v = A[j];
		    A[j] = A[j-1];
		    A[j-1] = v;
		    count++;
		    flag = 1;
		}
	    }
	}
	
	for(i=0 ; i<A.length-1 ; i++){
	    System.out.print(A[i]+" ");
	    }
	System.out.println(A[i]);
	System.out.println(count);
    }
    
}