Problem:
Score : 300 points

Problem Statement

There are N slimes lining up from left to right. The colors of these slimes will be given as a string S of length N consisting of lowercase English letters. The i-th slime from the left has the color that corresponds to the i-th character of S.

Adjacent slimes with the same color will fuse into one larger slime without changing the color. If there were a slime adjacent to this group of slimes before fusion, that slime is now adjacent to the new larger slime.

Ultimately, how many slimes will be there?

Constraints

1 \leq N \leq 10^5

|S| = N

S consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

N
S

Output

Print the final number of slimes.

Sample Input 1

10
aabbbbaaca

Sample Output 1

5

Ultimately, these slimes will fuse into abaca.

Sample Input 2

5
aaaaa

Sample Output 2

1

All the slimes will fuse into one.

Sample Input 3

20
xxzaffeeeeddfkkkkllq

Sample Output 3

10

Solution in Java7 (OpenJDK 1.7.0) (judge verdict: Accepted)

import java.util.*;

public class Main {
    public static void main(String[] args) throws Exception {
        // Your code here!
        Scanner sc = new Scanner(System.in);
        int N = Integer.parseInt(sc.nextLine());
        String Stmp = sc.nextLine();
        String S[] = new String[N];
        for(int i=0; i<N; i++){
            S[i] = Stmp.substring(i,i+1);
        }

        int counter=1;
        for(int i=0; i<N-1; i++){
            //System.out.println("i="+i+" compare "+S[i]+" and "+S[i+1]);
            if(S[i].equals(S[i+1])){
                //System.out.println("------"+S[i]+" and "+S[i+1]+" are same so merge & counter:"+counter);
            }else{
                counter++;
                //System.out.println("------Different so increment: "+counter);
            }
        }
        System.out.println(counter);
    }
}
// ・for：N体のスライムを順番に見ていく
// 　・i番目の色をtempに記録
// 　if：(i+1)番目の色と比較して同色なら
// 　　→counterが増えない
// 　　　→次のループに移る
// 　else：(i+1)番目の色と比較して別色なら
// 　　→counterをインクリメント
// 　　　→次のループに移る