Problem:
Simultaneous Equation

Write a program which solve a simultaneous equation:

ax + by = c

dx + ey = f

The program should print x and y for given a, b, c, d, e and f (-1,000 ≤ a, b, c, d, e, f ≤ 1,000). You can suppose that given equation has a unique solution.

Input

The input consists of several data sets, 1 line for each data set. In a data set, there will be a, b, c, d, e, f separated by a single space. The input terminates with EOF.

Output

For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.

Sample Input 1

1 2 3 4 5 6
2 -1 -2 -1 -1 -5

Output for the Sample Input 1

-1.000 2.000
1.000 4.000

Sample Input 2

2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27

Output for the Sample Input 2

0.000 3.000
0.000 3.000

Solution in JAVA (judge verdict: Accepted)

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;


class Main{
	
	public static void main(String[] args) throws NumberFormatException, IOException {
	
		int a, b, c, d, e, f;
		String input;
		BufferedReader bf = new BufferedReader(new InputStreamReader(System.in));
		
		
		while ((input = bf.readLine()) != null) {
			String[] dataset = input.split(" ");
			int i = 0;
			a = Integer.parseInt(dataset[i++]);
			b = Integer.parseInt(dataset[i++]);
			c = Integer.parseInt(dataset[i++]);
			d = Integer.parseInt(dataset[i++]);
			e = Integer.parseInt(dataset[i++]);
			f = Integer.parseInt(dataset[i++]);
			
			float y = ((float)(d * c - a * f)) / ((float)(d * b - a * e));
			float x = (c - b * y) / a;
			
			System.out.printf("%.3f ", x);
			System.out.printf(String.format("%.3f\n", y));
		}
	}
}