Problem:
Score : 200 points

Problem Statement

There are N gems. The value of the i-th gem is V_i.

You will choose some of these gems, possibly all or none, and get them.

However, you need to pay a cost of C_i to get the i-th gem.

Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid.

Find the maximum possible value of X-Y.

Constraints

All values in input are integers.

1 \leq N \leq 20

1 \leq C_i, V_i \leq 50

Input

Input is given from Standard Input in the following format:

N
V_1 V_2 ... V_N
C_1 C_2 ... C_N

Output

Print the maximum possible value of X-Y.

Sample Input 1

3
10 2 5
6 3 4

Sample Output 1

5

If we choose the first and third gems, X = 10 + 5 = 15 and Y = 6 + 4 = 10.
We have X-Y = 5 here, which is the maximum possible value.

Sample Input 2

4
13 21 6 19
11 30 6 15

Sample Output 2

6

Sample Input 3

1
1
50

Sample Output 3

0

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Arrays;
import java.util.List;
import java.util.Scanner;

public class Main {
public static void main(String[] args) {
		
		Scanner keyboard = new Scanner(System.in); 

		int N = keyboard.nextInt();
		
		int[] X = new int[N];
			for(int i=0; i < N; i++) {
				X[i] = keyboard.nextInt();
			}
		int[] Y = new int[N];
			for(int j=0; j < N; j++) {
				Y[j] = keyboard.nextInt();
			}
			
		int[] sagaku = new int[N];
		for(int k=0; k < N; k++) {
			sagaku[k] = X[k] - Y[k];
		}
		
		int Max = 0;
		
		for(int l=0; l < N; l++) {	
			if(sagaku[l] + Max > Max) {
				Max += sagaku[l];
				}
		}

		System.out.print(Max);
		keyboard.close();	
	}
}