Problem:
Simultaneous Equation

Write a program which solve a simultaneous equation:

ax + by = c

dx + ey = f

The program should print x and y for given a, b, c, d, e and f (-1,000 ≤ a, b, c, d, e, f ≤ 1,000). You can suppose that given equation has a unique solution.

Input

The input consists of several data sets, 1 line for each data set. In a data set, there will be a, b, c, d, e, f separated by a single space. The input terminates with EOF.

Output

For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.

Sample Input 1

1 2 3 4 5 6
2 -1 -2 -1 -1 -5

Output for the Sample Input 1

-1.000 2.000
1.000 4.000

Sample Input 2

2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27

Output for the Sample Input 2

0.000 3.000
0.000 3.000

Solution in JAVA (judge verdict: Accepted)

import java.util.Scanner;


public class Main
{
	static double a, b, c, d, e, f;
	
	public static void main(String[] args)
	{
		Scanner scanner = new Scanner(System.in);
		
		for(; scanner.hasNext();)
		{
			a = scanner.nextDouble();
			b = scanner.nextDouble();
			c = scanner.nextDouble();
			
			d = scanner.nextDouble();
			e = scanner.nextDouble();
			f = scanner.nextDouble();	

			System.out.printf("%1$.3f %2$.3f\n", getX()+0.00049, getY()+0.00049);
		}
	}
	
	private static double getX()
	{
		if(b == 0)
		{
			return c/a;
		}
		else if(e == 0)
		{
			return f/d;
		}
		else {		
			double a0 = a/b;
			double c0 = c/b;
			
			double d0 = d/e;
			double f0 = f/e;
			
			if(a0-d0==0 || c0-f0==0)
				return 0;
			else
				return (c0-f0)/(a0-d0);
		}
	}
	
	private static double getY()
	{
		if(a == 0)
		{
			return c/b;
		}
		else if(d == 0)
		{
			return f/e;
		}
		else 
		{	
			double b0 = b/a;
			double c0 = c/a;
			
			double e0 = e/d;
			double f0 = f/d;
			
			if(b0-e0==0 || c0-f0==0)
				return 0;
			else
				return (c0-f0)/(b0-e0);
		}
	}
}