Problem:
Simultaneous Equation

Write a program which solve a simultaneous equation:

ax + by = c

dx + ey = f

The program should print x and y for given a, b, c, d, e and f (-1,000 ≤ a, b, c, d, e, f ≤ 1,000). You can suppose that given equation has a unique solution.

Input

The input consists of several data sets, 1 line for each data set. In a data set, there will be a, b, c, d, e, f separated by a single space. The input terminates with EOF.

Output

For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.

Sample Input 1

1 2 3 4 5 6
2 -1 -2 -1 -1 -5

Output for the Sample Input 1

-1.000 2.000
1.000 4.000

Sample Input 2

2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27

Output for the Sample Input 2

0.000 3.000
0.000 3.000

Solution in JAVA (judge verdict: Accepted)

import java.io.IOException;
import java.util.Scanner;

public class Main {
    public static void main(String[] args) throws IOException {
        Scanner sc = new Scanner(System.in);
        while (sc.hasNext()){
            int a = sc.nextInt();
            int b = sc.nextInt();
            int c = sc.nextInt();
            int d = sc.nextInt();
            int e = sc.nextInt();
            int f = sc.nextInt();
            
            float delta = a * e - b * d;
            
            if (Math.abs((e * c - b * f) / delta)< 1e-3){
                float x = 0;
                System.out.printf("%.3f ", x);
            }else{
                float x = (e * c - b * f) / delta;
                System.out.printf("%.3f ", x);
            }
            
            if (Math.abs((a * f - d * c) / delta) < 1e-3){
                float y = 0;
                System.out.printf("%.3f\n", y);
            }else{
                float y = (a * f - d * c) / delta;
                System.out.printf("%.3f\n", y);
            }
        }
    }
}