Problem:
Score : 300 points

Problem Statement

Takahashi, Aoki and Snuke love cookies. They have A, B and C cookies, respectively. Now, they will exchange those cookies by repeating the action below:

Each person simultaneously divides his cookies in half and gives one half to each of the other two persons.

This action will be repeated until there is a person with odd number of cookies in hand.

How many times will they repeat this action?
Note that the answer may not be finite.

Constraints

1 ≤ A,B,C ≤ 10^9

Input

Input is given from Standard Input in the following format:

A B C

Output

Print the number of times the action will be performed by the three people, if this number is finite.
If it is infinite, print -1 instead.

Sample Input 1

4 12 20

Sample Output 1

3

Initially, Takahashi, Aoki and Snuke have 4, 12 and 20 cookies. Then,

After the first action, they have 16, 12 and 8.

After the second action, they have 10, 12 and 14.

After the third action, they have 13, 12 and 11.

Now, Takahashi and Snuke have odd number of cookies, and therefore the answer is 3.

Sample Input 2

14 14 14

Sample Output 2

-1

Sample Input 3

454 414 444

Sample Output 3

1

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.io.*;
import java.lang.*;
import java.util.*;
import java.math.*;

class Solver extends Main{
	Solver(long a, long b, long c){
		long[] cur={a,b,c};
		long[] nex={0,0,0};
		long s=a+b+c;
		boolean con=true;
		boolean loop=false;
		int i=0;
		
		while(con==true){
			nex[0]=(s-cur[0])/2;
			nex[1]=(s-cur[1])/2;
			nex[2]=(s-cur[2])/2;
			
			//puts(nex[0],nex[1],nex[2],s);
			
			cur[0]=nex[0];cur[1]=nex[1];cur[2]=nex[2];
			nex[0]=0; nex[1]=0; nex[2]=0;
			if(cur[0]%2==1 || cur[2]%2==1 || cur[2]%2==1) con=false;
			if((s-cur[0])/2==cur[0] && (s-cur[1])/2==cur[1] &&(s-cur[2])/2==cur[2]){
				con=false;
				loop=true;
			}
			i+=1;
		}
		puts(-1);
	}
}

class Main{
	int imax=Integer.MAX_VALUE;
	long lmax=Long.MAX_VALUE;
	public static void main(String[] args) throws FileNotFoundException{

		Scanner sc=new Scanner(System.in);
		long[] data=readlL(sc," ");
		new Solver(data[0], data[1], data[2]);
	}	
	
	//utility
	static int[] readI(Scanner sc, String dl){
		return Arrays.stream(sc.nextLine().trim().split(dl)).mapToInt(Integer::parseInt).toArray();
	}
	static int[] readlI(Scanner sc, String dl){
		return Arrays.stream(sc.nextLine().trim().split(dl)).mapToInt(Integer::parseInt).toArray();
	}
	static long[] readlL(Scanner sc, String dl){
		return Arrays.stream(sc.nextLine().trim().split(dl)).mapToLong(Long::parseLong).toArray();
	}
	static int nextI(Scanner sc){
		return Integer.parseInt(sc.nextLine().trim());
	}
	static String[] readS(Scanner sc, String dl){
		return sc.nextLine().trim().split(dl);
	}
	static String nextS(Scanner sc){
		return sc.nextLine().trim();
	}
	@SuppressWarnings("unchecked")
	static <T> void puts(T... args){
		for(int i=0; i<args.length-1; i++){
			System.out.printf("%s ",args[i]);
		}
		System.out.println(args[args.length-1]);
	}
	static void puts(int[] ary){
		for(int i=0; i<ary.length-1; i++){
			System.out.printf("%d ",ary[i]);
		}
		System.out.println(ary[ary.length-1]);
	}
	static void puts(long[] ary){
		for(int i=0; i<ary.length-1; i++){
			System.out.printf("%d ",ary[i]);
		}
		System.out.println(ary[ary.length-1]);
	}
	static void tblSort(int[][] tbl){
		Arrays.sort(tbl, new Comparator<int[]>(){
			@Override
			public int compare(int[] a, int[] b){
				if(a[0]==b[0]){
					return b[1]-a[1];
				}else{
					return b[0]-a[0];
				}
			}
		});
	}
}