Problem:
Score : 300 points

Problem Statement

You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

1 \leq |S| \leq 2 \times 10^5

|S| = |T|

S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S and T can be made equal, print Yes; otherwise, print No.

Sample Input 1

azzel
apple

Sample Output 1

Yes

azzel can be changed to apple, as follows:

Choose e as c_1 and l as c_2. azzel becomes azzle.

Choose z as c_1 and p as c_2. azzle becomes apple.

Sample Input 2

chokudai
redcoder

Sample Output 2

No

No sequences of operation can change chokudai to redcoder.

Sample Input 3

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu

Sample Output 3

Yes

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Time Limit Exceeded)

import java.util.*;
import java.lang.*;

public class Main{
    public static void main(String args[]){
        Scanner sc = new Scanner(System.in);
        String s = sc.next();
        String t = sc.next();
        int l = s.length();
        boolean ans = true;
        for(int i=0; i<l-1; i++){
            for(int j=i+1; j<l; j++){
                if(s.charAt(i)==s.charAt(j)){
                    if(t.charAt(i)!=t.charAt(j)){
                        ans = false;
                    }
                }
            }
        }
        for(int i=0; i<l-1; i++){
            for(int j=i+1; j<l; j++){
                if(t.charAt(i)==t.charAt(j)){
                    if(s.charAt(i)!=s.charAt(j)){
                        ans = false;
                    }
                }
            }
        }

        System.out.println(ans?"Yes":"No");
    }
}