Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Accepted)

import java.util.Scanner;
 
class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int[] atoz = new int[26];
   
        do {
            String s = sc.nextLine();
            for (char c : s.toCharArray()){
                if ((c < 'A' || 'Z' < c) && (c < 'a' || 'z' < c)) continue;
                atoz[Character.toLowerCase(c)- 'a']++;
            }
        } while (sc.hasNext());
   
        for (char c = 'a'; c <= 'z'; c++){
            System.out.println(c + " : " + atoz[c - 'a']);
        }
    }
}