Problem:
Score : 300 points

Problem Statement

You are given a sequence of length N: A_1, A_2, ..., A_N.
For each integer i between 1 and N (inclusive), answer the following question:

Find the maximum value among the N-1 elements other than A_i in the sequence.

Constraints

2 \leq N \leq 200000

1 \leq A_i \leq 200000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1
:
A_N

Output

Print N lines. The i-th line (1 \leq i \leq N) should contain the maximum value among the N-1 elements other than A_i in the sequence.

Sample Input 1

3
1
4
3

Sample Output 1

4
3
4

The maximum value among the two elements other than A_1, that is, A_2 = 4 and A_3 = 3, is 4.

The maximum value among the two elements other than A_2, that is, A_1 = 1 and A_3 = 3, is 3.

The maximum value among the two elements other than A_3, that is, A_1 = 1 and A_2 = 4, is 4.

Sample Input 2

2
5
5

Sample Output 2

5
5

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.Scanner;
import java.util.Collections;
import java.util.ArrayList;

/**
 * Built using CHelper plug-in
 * Actual solution is at the top
 *
 * @author Abhijeetkns
 */
public class Main {
    public static void main(String[] args) {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        Scanner in = new Scanner(inputStream);
        PrintWriter out = new PrintWriter(outputStream);
        CExceptionHandling solver = new CExceptionHandling();
        solver.solve(1, in, out);
        out.close();
    }

    static class CExceptionHandling {
        public void solve(int testNumber, Scanner in, PrintWriter out) {
            ArrayList<Integer> list = new ArrayList<>();
            int n = in.nextInt();
            for (int i = 0; i < n; i++) list.add(in.nextInt());
            ArrayList<Integer> list1 = new ArrayList<>(list);
            int max1 = Collections.max(list);
            Collections.sort(list);
            //out.println(list);
            int max2 = list.get(n - 2);

            for (int i = 0; i < n; i++) {
                int ele = list1.get(i);
                if (ele < max1) out.println(max1);
                else {
                    out.println(max2);
                }
            }
        }

    }
}