Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.Scanner;

public class Main {
	public static void main(String[] args) {
		Scanner scanner = new Scanner(System.in);
		int N = scanner.nextInt();
		
		if (N < 105) {
			System.out.println(0);
			return;
		}
		int count = 0;
		int sum = 1;
		
		for (int j = 106; j <= N; j++) {
			for (int i = 1; i <= j; i++) {
				if (j % i == 0) {
					count++;
				}
			}
			
//			System.out.println(count);
			if (count == 8) {
				sum++;
			}
			count = 0;
		}
		System.out.println(sum);
		scanner.close();
	}
}