Problem:
Score : 200 points

Problem Statement

You are given an image A composed of N rows and N columns of pixels, and a template image B composed of M rows and M columns of pixels.

A pixel is the smallest element of an image, and in this problem it is a square of size 1×1.

Also, the given images are binary images, and the color of each pixel is either white or black.

In the input, every pixel is represented by a character: . corresponds to a white pixel, and # corresponds to a black pixel.

The image A is given as N strings A_1,...,A_N.

The j-th character in the string A_i corresponds to the pixel at the i-th row and j-th column of the image A (1≦i,j≦N).

Similarly, the template image B is given as M strings B_1,...,B_M.

The j-th character in the string B_i corresponds to the pixel at the i-th row and j-th column of the template image B (1≦i,j≦M).

Determine whether the template image B is contained in the image A when only parallel shifts can be applied to the images.

Constraints

1≦M≦N≦50

A_i is a string of length N consisting of # and ..

B_i is a string of length M consisting of # and ..

Input

The input is given from Standard Input in the following format:

N M
A_1
A_2
:
A_N
B_1
B_2
:
B_M

Output

Print Yes if the template image B is contained in the image A. Print No otherwise.

Sample Input 1

3 2
#.#
.#.
#.#
#.
.#

Sample Output 1

Yes

The template image B is identical to the upper-left 2 × 2 subimage and the lower-right 2 × 2 subimage of A. Thus, the output should be Yes.

Sample Input 2

4 1
....
....
....
....
#

Sample Output 2

No

The template image B, composed of a black pixel, is not contained in the image A composed of white pixels.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Runtime Error)


import java.math.BigDecimal;
import java.math.BigInteger;
import java.util.Scanner;

public class Main {
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		int n = sc.nextInt();
		int m = sc.nextInt();
		
		String[] ns = new String[n];
		for (int i = 0; i < ns.length; i++) {
			ns[i] = sc.next();
		}
		
		String[] ms = new String[m];
		for (int i = 0; i < ms.length; i++) {
			ms[i] = sc.next();
		}
		
		
		String ans = "No";
		outside: for (int i = 0; i < n; i++) {
			String target = ns[i];
			for (int j = 0; j <= n - m; j++) {
				String target2 = target.substring(j, j + m);
				if (target2.equals(ms[0])) {
					
					if (m == 1) {
						ans = "Yes";
						break outside;
					}
					
					int cnt = 1;
					for (int k = 1; k < ms.length; k++) {
						String target3 = ns[i + k];
						String target4 = target3.substring(j, j + m);
						if (target4.equals(ms[k])) {
							cnt++;
						} else {
							break;
						}
						if (cnt == m) {
							ans = "Yes";
							break outside;
						}
					}
				}
			}
		}
		System.out.println(ans);
	}
}