Problem:
Score : 300 points

Problem Statement

In Takahashi Kingdom, there is an archipelago of N islands, called Takahashi Islands.
For convenience, we will call them Island 1, Island 2, ..., Island N.

There are M kinds of regular boat services between these islands.
Each service connects two islands. The i-th service connects Island a_i and Island b_i.

Cat Snuke is on Island 1 now, and wants to go to Island N.
However, it turned out that there is no boat service from Island 1 to Island N, so he wants to know whether it is possible to go to Island N by using two boat services.

Help him.

Constraints

3 ≤ N ≤ 200 000

1 ≤ M ≤ 200 000

1 ≤ a_i < b_i ≤ N

(a_i, b_i) \neq (1, N)

If i \neq j, (a_i, b_i) \neq (a_j, b_j).

Input

Input is given from Standard Input in the following format:

N M
a_1 b_1
a_2 b_2
:
a_M b_M

Output

If it is possible to go to Island N by using two boat services, print POSSIBLE; otherwise, print IMPOSSIBLE.

Sample Input 1

3 2
1 2
2 3

Sample Output 1

POSSIBLE

Sample Input 2

4 3
1 2
2 3
3 4

Sample Output 2

IMPOSSIBLE

You have to use three boat services to get to Island 4.

Sample Input 3

100000 1
1 99999

Sample Output 3

IMPOSSIBLE

Sample Input 4

5 5
1 3
4 5
2 3
2 4
1 4

Sample Output 4

POSSIBLE

You can get to Island 5 by using two boat services: Island 1 -> Island 4 -> Island 5.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.*;
import static java.lang.Integer.*;
import static java.lang.Long.*;
import static java.lang.Math.*;
import static java.lang.System.*;

import java.io.PrintWriter;

public class Main {
	public static void main(String[] args) {
		int i=0,j=0,k=0;
		Scanner sc = new Scanner(in);
		int n = parseInt(sc.next());
		int m = parseInt(sc.next());
		int a = 0;
		int b = 0;
		HashSet<Integer> m1 = new HashSet<>();
		HashSet<Integer> m2 = new HashSet<>();
		for(i=0;i<m;i++) {
			a = parseInt(sc.next());
			b = parseInt(sc.next());
			if(a==1) m1.add(b);
			if(b==n) m2.add(a);
		}
		sc.close();
		boolean f=false;
		for (Integer ii:m1) {
			if(m2.contains(ii)) {
				f = true;
				break;
			}
		}
		out.println(f?"POSSIBLE":"IMPOSSIBLE");
	}
}