Problem:
Score : 600 points

Problem Statement

There are 2N people numbered 1 through 2N.
The height of Person i is h_i.

How many ways are there to make N pairs of people such that the following conditions are satisfied?
Compute the answer modulo 998,244,353.

Each person is contained in exactly one pair.

For each pair, the heights of the two people in the pair are different.

Two ways are considered different if for some p and q, Person p and Person q are paired in one way and not in the other.

Constraints

1 \leq N \leq 50,000

1 \leq h_i \leq 100,000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
h_1
:
h_{2N}

Output

Print the answer.

Sample Input 1

2
1
1
2
3

Sample Output 1

2

There are two ways:

Form the pair (Person 1, Person 3) and the pair (Person 2, Person 4).

Form the pair (Person 1, Person 4) and the pair (Person 2, Person 3).

Sample Input 2

5
30
10
20
40
20
10
10
30
50
60

Sample Output 2

516

Solution in Java (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.io.*;
import java.math.*;
import java.util.*;
import java.util.stream.*;

public class Main {

	static final int P = 998_244_353;

	void submit() {
		int[] cnt = new int[100_000];
		int n = nextInt();
		for (int i = 0; i < 2 * n; i++) {
			cnt[nextInt() - 1]++;
		}

		long[] pair = new long[n + 1];
		pair[0] = 1;
		for (int i = 1; i < pair.length; i++) {
			pair[i] = pair[i - 1] * (2 * i - 1) % P;
		}

		long[] inv = new long[2 * n + 1];
		inv[1] = 1;

		for (int i = 2; i < inv.length; i++) {
			inv[i] = P - (long) (P / i) * inv[P % i] % P;
		}

		PriorityQueue<int[]> pq = new PriorityQueue<>((int[] a, int[] b) -> Integer.compare(a.length, b.length));
		pq.add(new int[] { 1 });
		for (int x : cnt) {
			if (x < 2) {
				continue;
			}
			int[] p = new int[x / 2 + 1];
			long cur = p[0] = 1;
			for (int i = 1; i < p.length; i++) {
				cur = cur * (x - 2 * i + 2) % P * (x - 2 * i + 1) % P * inv[2 * i - 1] % P * inv[2 * i] % P;
				p[i] = (int) (cur * pair[i] % P);
			}
			pq.add(p);
		}

		while (pq.size() > 1) {
			int[] a = pq.poll();
			int[] b = pq.poll();
			pq.add(mult(a, b));
		}

		int[] p = pq.poll();
		long ans = 0;
		for (int i = 0; i < p.length; i++) {
			ans += (1 - i % 2 * 2) * p[i] * pair[n - i];
			if (ans >= P2) {
				ans -= P2;
			}
			if (ans < 0) {
				ans += P2;
			}
		}
		out.println(ans % P);
	}

	static final int NAIVE_MULT_THRESHOLD = 192;
	static final long P2 = (long) P * P;

	int[] mult(int[] a, int[] b) {
		int[] ret = multSmall(a, b);
		return ret != null ? ret : multFFT(a, b);
	}

	static int[] getNonZeroesIdx(int[] p) {
		int n = 0;
		for (int i = 0; i < p.length; i++) {
			if (p[i] != 0) {
				n++;
			}
		}
		int[] ret = new int[n];
		for (int i = 0; i < p.length; i++) {
			if (p[i] != 0) {
				ret[--n] = i;
			}
		}
		return ret;
	}

	static int[] removeLeadingZeroes(int[] a) {
		int i = a.length - 1;
		while (i >= 0 && a[i] == 0) {
			i--;
		}
		return i == a.length - 1 ? a : Arrays.copyOf(a, i + 1);
	}

	int[] multSmall(int[] a, int[] b) {
		int[] nza = getNonZeroesIdx(a);
		int[] nzb = getNonZeroesIdx(b);
		if (nza.length == 0 || nzb.length == 0) {
			return new int[] { 0 };
		}
		if (Math.min(nza.length, nzb.length) <= NAIVE_MULT_THRESHOLD) {
			long[] c = new long[nza[0] + nzb[0] + 1];
			for (int i : nza) {
				for (int j : nzb) {
					c[i + j] += (long) a[i] * b[j];
					if (c[i + j] >= P2) {
						c[i + j] -= P2;
					}
				}
			}
			int[] ret = new int[c.length];
			for (int i = 0; i < c.length; i++) {
				ret[i] = (int) (c[i] % P);
			}
			return removeLeadingZeroes(ret);
		}
		return null;
	}

	static int nextPowerOf2(int x) {
		return x == 1 ? 1 : Integer.highestOneBit(x - 1) << 1;
	}

	static final int L = (int) Math.sqrt(P);
	static final int L2 = L * L;

	/**
	 * Decomposes intV into vectors a and b s.t. intV = a + b * L.
	 * 
	 * @param len - length to pad intV to. !!! MUST BE A POWER OF 2 !!!
	 * @return double[][]{FFT(a), FFT(b)}.
	 */
	static double[][] decomposeAndFFT(int[] intV, int len) {
		// pack into one complex vector
		double[] f = new double[len << 1];
		for (int i = 0; i < intV.length; i++) {
			f[i << 1] = intV[i] % L;
			f[i << 1 | 1] = intV[i] / L;
		}

		fft(f, false);

		// unpack
		double[] f1 = new double[len << 1];
		double[] f2 = new double[len << 1];
		int zzz = (len << 1) - 1;
		for (int i = 0; i < len << 1; i += 2) {
			int j = (-i) & zzz;
			f1[i] = .5 * (f[i] + f[j]);
			f1[i + 1] = .5 * (f[i + 1] - f[j + 1]);
			f2[i] = .5 * (f[i + 1] + f[j + 1]);
			f2[i + 1] = .5 * (f[j] - f[i]);
		}

		return new double[][] { f1, f2 };
	}

	public static int[] multFFT(int[] a, int[] b) {
		int len = nextPowerOf2(a.length + b.length - 1);
		int len2 = len << 1;

		double[][] fA = decomposeAndFFT(a, len);
		double[][] fB = decomposeAndFFT(b, len);

		// Multiply FFT-ed vectors and pack them in pairs for inverse FFT.
		// We need to calcualte smth like (a0 b0) + L(a0 b1 + a1 b0) + L^2 (a1 b1)
		// a0 b0 goes into invF[0] real part
		// (a0 b1 + a1 b0) invF[0] imag part
		// a1 b1 -> invF[1] real part
		double[][] invF = new double[2][len2];
		for (int ia = 0; ia < 2; ia++) {
			for (int ib = 0; ib < 2; ib++) {

				double[] r = invF[(ia + ib) >> 1];
				double[] p = fA[ia];
				double[] q = fB[ib];

				if (((ia + ib) & 1) == 0) {
					for (int i = 0; i < len2; i += 2) {
						r[i] += p[i] * q[i] - p[i + 1] * q[i + 1];
						r[i + 1] += p[i] * q[i + 1] + p[i + 1] * q[i];
					}

				} else {
					for (int i = 0; i < len2; i += 2) {
						r[i] -= p[i] * q[i + 1] + p[i + 1] * q[i];
						r[i + 1] += p[i] * q[i] - p[i + 1] * q[i + 1];
					}
				}

			}
		}

		fft(invF[0], true);
		fft(invF[1], true);

		int[] ret = new int[len];

		for (int i = 0; i < len2; i += 2) {
			long v0 = Math.round(invF[0][i]);
			long v1 = Math.round(invF[0][i + 1]) % P * L;
			long v2 = Math.round(invF[1][i]) % P * L2;
			ret[i >> 1] = (int) ((v0 + v1 + v2) % P);
		}

		return removeLeadingZeroes(ret);
	}

	public static void fft(double[] v, boolean invert) {
		int n2 = v.length;
		int n = n2 >> 1;
		int logN = Integer.numberOfTrailingZeros(n);
		prepareArrays(logN);
		int[] rev = rev2D[logN];

		for (int i = 0; i < n2; i += 2) {
			int j = rev[i >> 1] << 1;
			if (i < j) {
				double t = v[i];
				v[i] = v[j];
				v[j] = t;
				t = v[i + 1];
				v[i + 1] = v[j + 1];
				v[j + 1] = t;
			}
		}

		double conj = invert ? -1 : 1;

		for (int len = 2, row = 0; len <= n; len <<= 1, row++) {
			double[] pow = pow2D[row];
			for (int i = 0; i < n; i += len) {
				for (int j1 = i << 1, j2 = j1 + len, k = 0; k < len; j1 += 2, j2 += 2, k += 2) {
					double uA = v[j1];
					double uB = v[j1 + 1];

					double mRe = pow[k];
					double mIm = pow[k + 1] * conj;

					double vA = v[j2] * mRe - v[j2 + 1] * mIm;
					double vB = v[j2] * mIm + v[j2 + 1] * mRe;

					v[j1] = uA + vA;
					v[j1 + 1] = uB + vB;
					v[j2] = uA - vA;
					v[j2 + 1] = uB - vB;
				}
			}
		}
		if (invert) {
			for (int i = 0; i < n2; i++) {
				v[i] /= n;
			}
		}
	}

	static double[][] pow2D = { { 1, 0 } };
	static int[][] rev2D = {};

	static void prepareArrays(int n) {
		if (rev2D.length < n + 1) {
			rev2D = Arrays.copyOf(rev2D, n + 1);
		}

		if (rev2D[n] == null) {
			int[] tmp = rev2D[n] = new int[1 << n];
			for (int i = 0; i < (1 << n); i++) {
				tmp[i] = (tmp[i >> 1] >> 1) | ((i & 1) << (n - 1));
			}
		}

		int oldN = pow2D.length;

		if (oldN >= n) {
			return;
		}

		pow2D = Arrays.copyOf(pow2D, n);

		for (int i = oldN; i < n; i++) {
			double angle = Math.PI / (1 << i);

			double mRe = Math.cos(angle);
			double mIm = Math.sin(angle);

			double[] dst = pow2D[i] = new double[2 << i];
			double[] src = pow2D[i - 1];

			for (int j = 0; j < 1 << i; j += 2) {
				double re = src[j];
				double im = src[j + 1];

				dst[j << 1] = re;
				dst[j << 1 | 1] = im;
				dst[j << 1 | 2] = re * mRe - im * mIm;
				dst[j << 1 | 3] = re * mIm + im * mRe;
			}
		}
	}

	void test() {

	}

	void stress() {
		for (int tst = 0;; tst++) {
			if (false) {
				throw new AssertionError();
			}
			System.err.println(tst);
		}
	}

	Main() throws IOException {
		is = System.in;
		out = new PrintWriter(System.out);
		submit();
		// stress();
		// test();
		out.close();
	}

	static final Random rng = new Random();
	static final int C = 5;

	static int rand(int l, int r) {
		return l + rng.nextInt(r - l + 1);
	}

	public static void main(String[] args) throws IOException {
		new Main();
	}

	private InputStream is;
	PrintWriter out;

	private byte[] buf = new byte[1 << 14];
	private int bufSz = 0, bufPtr = 0;

	private int readByte() {
		if (bufSz == -1)
			throw new RuntimeException("Reading past EOF");
		if (bufPtr >= bufSz) {
			bufPtr = 0;
			try {
				bufSz = is.read(buf);
			} catch (IOException e) {
				throw new RuntimeException(e);
			}
			if (bufSz <= 0)
				return -1;
		}
		return buf[bufPtr++];
	}

	private boolean isTrash(int c) {
		return c < 33 || c > 126;
	}

	private int skip() {
		int b;
		while ((b = readByte()) != -1 && isTrash(b))
			;
		return b;
	}

	String nextToken() {
		int b = skip();
		StringBuilder sb = new StringBuilder();
		while (!isTrash(b)) {
			sb.appendCodePoint(b);
			b = readByte();
		}
		return sb.toString();
	}

	String nextString() {
		int b = readByte();
		StringBuilder sb = new StringBuilder();
		while (!isTrash(b) || b == ' ') {
			sb.appendCodePoint(b);
			b = readByte();
		}
		return sb.toString();
	}

	double nextDouble() {
		return Double.parseDouble(nextToken());
	}

	char nextChar() {
		return (char) skip();
	}

	int nextInt() {
		int ret = 0;
		int b = skip();
		if (b != '-' && (b < '0' || b > '9')) {
			throw new InputMismatchException();
		}
		boolean neg = false;
		if (b == '-') {
			neg = true;
			b = readByte();
		}
		while (true) {
			if (b >= '0' && b <= '9') {
				ret = ret * 10 + (b - '0');
			} else {
				if (b != -1 && !isTrash(b)) {
					throw new InputMismatchException();
				}
				return neg ? -ret : ret;
			}
			b = readByte();
		}
	}

	long nextLong() {
		long ret = 0;
		int b = skip();
		if (b != '-' && (b < '0' || b > '9')) {
			throw new InputMismatchException();
		}
		boolean neg = false;
		if (b == '-') {
			neg = true;
			b = readByte();
		}
		while (true) {
			if (b >= '0' && b <= '9') {
				ret = ret * 10 + (b - '0');
			} else {
				if (b != -1 && !isTrash(b)) {
					throw new InputMismatchException();
				}
				return neg ? -ret : ret;
			}
			b = readByte();
		}
	}
}