Problem:
Score : 600 points

Problem Statement

There is a function f(x), which is initially a constant function f(x) = 0.

We will ask you to process Q queries in order. There are two kinds of queries, update queries and evaluation queries, as follows:

An update query 1 a b: Given two integers a and b, let g(x) = f(x) + |x - a| + b and replace f(x) with g(x).

An evaluation query 2: Print x that minimizes f(x), and the minimum value of f(x). If there are multiple such values of x, choose the minimum such value.

We can show that the values to be output in an evaluation query are always integers, so we ask you to print those values as integers without decimal points.

Constraints

All values in input are integers.

1 \leq Q \leq 2 \times 10^5

-10^9 \leq a, b \leq 10^9

The first query is an update query.

Input

Input is given from Standard Input in the following format:

Q
Query_1
:
Query_Q

See Sample Input 1 for an example.

Output

For each evaluation query, print a line containing the response, in the order in which the queries are given.

The response to each evaluation query should be the minimum value of x that minimizes f(x), and the minimum value of f(x), in this order, with space in between.

Sample Input 1

4
1 4 2
2
1 1 -8
2

Sample Output 1

4 2
1 -3

In the first evaluation query, f(x) = |x - 4| + 2, which attains the minimum value of 2 at x = 4.

In the second evaluation query, f(x) = |x - 1| + |x - 4| - 6, which attains the minimum value of -3 when 1 \leq x \leq 4. Among the multiple values of x that minimize f(x), we ask you to print the minimum, that is, 1.

Sample Input 2

4
1 -1000000000 1000000000
1 -1000000000 1000000000
1 -1000000000 1000000000
2

Sample Output 2

-1000000000 3000000000

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

/*
* @Author Silviase(@silviasetitech)
* For ProCon
*/

import java.util.*;
import java.lang.*;
import java.math.*;
import java.awt.*;

public class Main{

    public static void main(String[] args){
        Scanner sc = new Scanner(System.in);

        int n = sc.nextInt();
        PriorityQueue<Long> pribig = new PriorityQueue<>(Comparator.naturalOrder());
        PriorityQueue<Long> prismall = new PriorityQueue<>(Comparator.reverseOrder());
        long big = 0;
        long small = 0;
        long b = 0;
        long ans;
        for (int i = 0; i < n; i++) {
            int tmp = sc.nextInt();
            if (tmp == 1) {
                // koushin
                long a = sc.nextLong();
                int bb = sc.nextInt();
                pribig.add(a);
                big += a;
                if (pribig.size() - prismall.size() >= 2){
                    long ods = pribig.poll();
                    big -= ods;
                    prismall.add(ods);
                    small += ods;
                }
                b += (long)bb;
            }else if(tmp == 2){
                // hanbetsu
                if (pribig.size() == prismall.size()){
                    ans = prismall.peek();
                    System.out.println(ans+" "+  (big - small + b) );
                }else{
                    ans = pribig.peek();
                    System.out.println(ans+" "+  (big - small - pribig.peek() + b) );
                }
                
            }
        }

        sc.close();
    }

    
static class Mathalgo{
    static int n;
    static long MOD = 1000000007;
    static int MAX = 510000;
    static long[] finv = new long[MAX];
    static long[] inv = new long[MAX];
    static long[] fac = new long[MAX];

    public static String make_bi_nari(int nbit, int num_to_binary) {
        String res = Integer.toBinaryString(num_to_binary);
        while(res.length() != nbit){
            res = "0" + res;
        }
        return res;
    }


    public static long fib(int x) {
        long[] fib = new long[x+1];
        fib[0] = 0; fib[1] = 1;
        for (int i = 2; i <= x; i++) {
            fib[i] = fib[i-1] + fib[i-2];
        }
        return fib[x];
    }

    public static int ManhattanDist(int x, int y, int xx, int yy) {
        return(Math.abs(xx-x) + Math.abs(yy-y));
    }

    static long modpow(long a, long n, long mod) {
        long res = 1;
        while (n > 0) {
            if (n % 2 == 1) res = res * a % mod;
            a = a * a % mod;
            n >>= 1;
        }
        return res;
    }
    
    
    static long modinv(long a, long mod) {
        return modpow(a, mod - 2, mod);
    }

    static void nCkmake() {
        fac[0] = fac[1] = 1;
        finv[0] = finv[1] = 1;
        inv[1] = 1;
        for (int i = 2; i < MAX; i++){
            fac[i] = fac[i - 1] * i % MOD;
            inv[i] = MOD - inv[(int)MOD%i] * (MOD / i) % MOD;
            finv[i] = finv[i - 1] * inv[i] % MOD;
        }
    }
    
    static long nCk(int n, int k){
        if (n < k) return 0;
        if (n < 0 || k < 0) return 0;
        return fac[n] * (finv[k] * finv[n - k] % MOD) % MOD;
    }

    public static long gcd_long(long a, long b) {
        if (a < b) {
            long x = a;
            a = b;
            b = x;
        }
        if (b == 0) {
            return a;
        }else{
            return gcd_long(b, a%b);
        }
    }

    public static long lcm_long(long a, long b) {
        long gcd = gcd_long(a,b);
        return a/gcd*b;
    }

    public static long GyakuGenMOD(long a) {
        return RepSquareMethod(a, MOD-2);
    }
    
    public static long factmod(int a) {
        long[] fact = new long[a+1];
        fact[0] = fact[1] = 1;
        for (int i = 2; i <= a; i++) {
            fact[i] = (fact[i-1]*i)%MOD;
        }
        return fact[a];
    }

    public static long RepSquareMethod(long a, long n) { // a^n
        long ans = 1;
        while (n > 0) {
            if ( n % 2 == 1) {
                ans = (ans * a) % MOD;
            }
            a = (a*a)%MOD;
            n/=2;
        }
        return ans;
    }
}
}