Problem:
Score : 200 points

Problem Statement

A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.

How many times will the ball make a bounce where the coordinate is at most X?

Constraints

1 \leq N \leq 100

1 \leq L_i \leq 100

1 \leq X \leq 10000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N X
L_1 L_2 ... L_{N-1} L_N

Output

Print the number of times the ball will make a bounce where the coordinate is at most X.

Sample Input 1

3 6
3 4 5

Sample Output 1

2

The ball will make a bounce at the coordinates 0, 3, 7 and 12, among which two are less than or equal to 6.

Sample Input 2

4 9
3 3 3 3

Sample Output 2

4

The ball will make a bounce at the coordinates 0, 3, 6, 9 and 12, among which four are less than or equal to 9.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.*;

public class Main {

    public static void main(String[] args) {
        //
        //Euclid e1=new Euclid();//ユークリッドの互除法
        //Compute c1=new Compute();//累積和，
        //変数
        int count = 0;
        boolean sw = false;
        int max = Integer.MIN_VALUE;
        int min = Integer.MAX_VALUE;
        double dMax = Double.MIN_VALUE;
        double dMin = Double.MAX_VALUE;
        int answer = 0;
        //String answer="Yes";
        //StringBuilder answer=new StringBuilder();
        //List<Integer> list = new ArrayList<>();
        //int array[] = new int[];

        //入力
        Scanner sc = new Scanner(System.in);
        int N = sc.nextInt();
        int X = sc.nextInt();
        int L[] =new int[N];
        for(int i=0;i<N;i++)
        {
            L[i]=sc.nextInt();
        }
        int D=0;
        count++;
        for (int i=0;i<N;i++)
        {
            //System.out.println(D);
            //System.out.println(L[i]);
            int a=D+L[i];
            if(a<=X)
            {
                count++;
            }
            D=a;
            //System.out.println(a);
            //System.out.println("-------------");
        }
        answer=count;
        //出力
        //BigDecimal bd = new BigDecimal(answer);
        //System.out.println(bd.setScale(12,BigDecimal.ROUND_DOWN));
        //System.out.println(String.format("%.0f",answer));
        System.out.println(answer);
    }
}