Problem:
Score : 200 points

Problem Statement

A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.

How many times will the ball make a bounce where the coordinate is at most X?

Constraints

1 \leq N \leq 100

1 \leq L_i \leq 100

1 \leq X \leq 10000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N X
L_1 L_2 ... L_{N-1} L_N

Output

Print the number of times the ball will make a bounce where the coordinate is at most X.

Sample Input 1

3 6
3 4 5

Sample Output 1

2

The ball will make a bounce at the coordinates 0, 3, 7 and 12, among which two are less than or equal to 6.

Sample Input 2

4 9
3 3 3 3

Sample Output 2

4

The ball will make a bounce at the coordinates 0, 3, 6, 9 and 12, among which four are less than or equal to 9.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);

		// 整数の入力
		int n = sc.nextInt();
		int x = sc.nextInt();
		int cnt = 0;
		long tmp = 0;

		Integer array[] = new Integer[n];
		long arySum[] = new long[n + 1];
		arySum[0] = 0;

		for (int i = 0; i < n; i++) {
			array[i] = sc.nextInt();
			//加算
			tmp = tmp + array[i];
			arySum[i + 1] = tmp;
		}

		for (int j = 0; j < n; j++) {
			if(arySum[j] <= x){
				cnt++;
			}else{
				break;
			}
		}

		System.out.println(cnt);

		sc.close();
	}
}