Problem:
Score : 100 points

Problem Statement

A Hitachi string is a concatenation of one or more copies of the string hi.

For example, hi and hihi are Hitachi strings, while ha and hii are not.

Given a string S, determine whether S is a Hitachi string.

Constraints

The length of S is between 1 and 10 (inclusive).

S is a string consisting of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S

Output

If S is a Hitachi string, print Yes; otherwise, print No.

Sample Input 1

hihi

Sample Output 1

Yes

hihi is the concatenation of two copies of hi, so it is a Hitachi string.

Sample Input 2

hi

Sample Output 2

Yes

Sample Input 3

ha

Sample Output 3

No

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Runtime Error)

import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		int a = sc.nextInt();
		int b = sc.nextInt();
		int m = sc.nextInt();
		int[] A = new int[a];
		int mina=10000;
		int[] B = new int[b];
		int minb=10000;
		int min = 0;
		for(int i=0; i<a; i++) {
			A[i] = sc.nextInt();
			mina = A[0];
			if(mina>A[i]) {
				mina = A[i];
			}
		}
		for(int i=0; i<b; i++) {
			B[i] = sc.nextInt();
			minb = B[0];
			if(minb>B[i]) {
				minb = B[i];
			}
		}
		min = mina + minb;
		for(int i=0; i<m; i++) {
			int x = sc.nextInt();
			int y = sc.nextInt();
			int c = sc.nextInt();
			int coupon = A[x-1]+B[y-1]-c;
			if(min > coupon) {
				min = coupon;
			}
		}
		
		System.out.println(min);
	}

}