Problem:
Simultaneous Equation

Write a program which solve a simultaneous equation:

ax + by = c

dx + ey = f

The program should print x and y for given a, b, c, d, e and f (-1,000 ≤ a, b, c, d, e, f ≤ 1,000). You can suppose that given equation has a unique solution.

Input

The input consists of several data sets, 1 line for each data set. In a data set, there will be a, b, c, d, e, f separated by a single space. The input terminates with EOF.

Output

For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.

Sample Input 1

1 2 3 4 5 6
2 -1 -2 -1 -1 -5

Output for the Sample Input 1

-1.000 2.000
1.000 4.000

Sample Input 2

2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27

Output for the Sample Input 2

0.000 3.000
0.000 3.000

Solution in JAVA (judge verdict: Accepted)

import java.util.*;class Main{public static void main(String[]g){Scanner S=new Scanner(System.in);int i;for(double x,y,a[]=new double[6];S.hasNext();System.out.printf("%.3f %.3f\n",x,y)){for(x=y=i=0;i<6;)a[i++]=S.nextInt();if(a[1]==0&&a[4]==0){x=a[0]==0?a[5]/a[3]:a[2]/a[0];}else{if(a[0]!=0&&a[3]!=0){x=a[0];for(i=0;i<6;a[i]*=i++>2?x:a[3]);for(i=0;i<3;)a[i]-=a[i+++3];}if(a[0]!=0){y=a[5]/a[4];x=(a[2]-y*a[1])/a[0];}if(a[3]!=0){y=a[2]/a[1];x=(a[5]-y*a[4])/a[3];}}x=x==-0?0:x;y=y==-0?0:y;}}}