Problem:
Score : 400 points

Problem Statement

Takahashi has a string S consisting of lowercase English letters.

Starting with this string, he will produce a new one in the procedure given as follows.

The procedure consists of Q operations. In Operation i (1 \leq i \leq Q), an integer T_i is provided, which means the following:

If T_i = 1: reverse the string S.

If T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.

If F_i = 1 : Add C_i to the beginning of the string S.

If F_i = 2 : Add C_i to the end of the string S.

Help Takahashi by finding the final string that results from the procedure.

Constraints

1 \leq |S| \leq 10^5

S consists of lowercase English letters.

1 \leq Q \leq 2 \times 10^5

T_i = 1 or 2.

F_i = 1 or 2, if provided.

C_i is a lowercase English letter, if provided.

Input

Input is given from Standard Input in the following format:

S
Q
Query_1
:
Query_Q

In the 3-rd through the (Q+2)-th lines, Query_i is one of the following:

1

which means T_i = 1, and:

2 F_i C_i

which means T_i = 2.

Output

Print the resulting string.

Sample Input 1

a
4
2 1 p
1
2 2 c
1

Sample Output 1

cpa

There will be Q = 4 operations. Initially, S is a.

Operation 1: Add p at the beginning of S. S becomes pa.

Operation 2: Reverse S. S becomes ap.

Operation 3: Add c at the end of S. S becomes apc.

Operation 4: Reverse S. S becomes cpa.

Thus, the resulting string is cpa.

Sample Input 2

a
6
2 2 a
2 1 b
1
2 2 c
1
1

Sample Output 2

aabc

There will be Q = 6 operations. Initially, S is a.

Operation 1: S becomes aa.

Operation 2: S becomes baa.

Operation 3: S becomes aab.

Operation 4: S becomes aabc.

Operation 5: S becomes cbaa.

Operation 6: S becomes aabc.

Thus, the resulting string is aabc.

Sample Input 3

y
1
2 1 x

Sample Output 3

xy

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.*;

public class Main {
    private static final int MOD = (int) Math.pow(10, 9);
    private static final long EIGHT = (long) 1e18;
    private static final int[][] DIRS = {{0, 1}, {0, -1}, {1, 0}, {-1, 0}};

    public static void main(String[] args) {
        FastReader sc = new FastReader();
        String s = sc.next();
        int q = sc.nextInt();
        Deque<Character> dq = new LinkedList<>();
        for (char c: s.toCharArray()) {
            dq.addLast(c);
        }

        boolean isLeftToRight = true;

        for (int i = 0; i < q; i++) {
            int cmd = sc.nextInt();
            if (cmd == 1) {
                isLeftToRight ^= true;
            } else {
                int f = sc.nextInt();
                char c = sc.next().charAt(0);

                if (f == 1) {
                    if (isLeftToRight) {
                        dq.addFirst(c);
                    } else {
                        dq.addLast(c);
                    }
                } else {
                    if (isLeftToRight) {
                        dq.addLast(c);
                    } else {
                        dq.addFirst(c);
                    }
                }
            }
        }

        StringBuilder res = new StringBuilder();

        for (char c: dq) {
            res.append(c);
        }

        if (!isLeftToRight) {
            res.reverse();
        }

        print(res.toString());
    }

    /*
     * Check if a * b is overflow or not
     */
    static Boolean isOverflowByMul(long a, long b) {
        if (a == 0 || b == 0) {
            return false;
        }

        long result = a * b;
        if (a == result / b) {
            return false;
        }
        return true;
    }

    static private void swap(int[] nums, int x, int y) {
        int tmp = nums[x];
        nums[x] = nums[y];
        nums[y] = tmp;
    }

    static  private void reverse(int[] nums, int left, int right) {
        while (left < right) {
            swap(nums, left, right);
            left++;
            right--;
        }
    }

    static private boolean findNextPermutation(int[] nums) {
        if (nums.length <= 1) {
            return false;
        }

        int last = nums.length - 2;

        while (last >= 0) {
            if (nums[last] < nums[last + 1]){
                break;
            }
            last--;
        }

        if (last < 0) { return false; }
        int nextGenerater = nums.length - 1;

        for (int i = nums.length - 1; i > last; i--) {
            if (nums[i] > nums[last]) {
                nextGenerater = i;
                break;
            }
        }

        swap(nums, nextGenerater, last);
        reverse(nums, last + 1, nums.length - 1);
        return true;
    }

    static private int[] generateNArray(int n) {
        int[] res = new int[n];

        for (int i = 0; i < n; i++) {
            res[i] = i + 1;
        }

        return res;
    }

    static  private void print(String s) {
        System.out.println(s);
    }

    static private void printArray(int[] e) {
        for (int s: e) {
            System.out.print(s + " ");
        }
        print("");
    }

    static private int log2(int x) {
        return (int)(Math.log(x) / Math.log(2));
    }

    static private long gcd(long m, long n) {
        if (m < n) { return gcd(n, m); }
        if (m % n == 0) { return n; }
        return gcd(n, m%n);
    }

    static class FastReader {
        BufferedReader br;
        StringTokenizer st;

        public FastReader() {
            br = new BufferedReader(new InputStreamReader(System.in));
        }

        String next() {
            while (st == null || !st.hasMoreElements()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException  e) {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }

        int nextInt() {
            return Integer.parseInt(next());
        }

        long nextLong() {
            return Long.parseLong(next());
        }

        double nextDouble() {
            return Double.parseDouble(next());
        }

        String nextLine() {
            String str = "";
            try{
                str = br.readLine();
            } catch (IOException e) {
                e.printStackTrace();
            }
            return str;
        }
    }
}