Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Wrong Answer)

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class Main {
	public static void main(String[] args) {
		BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
    
		int[] count = new int[26];
		String x = "";
		
		for (int i = 0; i < count.length; i++) {
			count[i] = 0;
		}
		
		try {
			x = in.readLine();
			
			for (int i = 0; i < x.length(); i++) {
				char c = x.charAt(i);
				if ((c < 'A') || (c > 'z')) continue;
				
				if (c < 'a') {
					count[c - 'A']++;
				} else {
					count[c - 'a']++;
				}
			}
		} catch (NumberFormatException e) {
			// TODO Auto-generated catch block
			e.printStackTrace();
		} catch (IOException e) {
			// TODO Auto-generated catch block
			e.printStackTrace();
		}
		
		for (int i = 0; i < count.length; i++) {
			char c = (char)(i + 'a');
			System.out.println(c + " : " + count[i]);
		}
	}
}