Problem:
Score : 300 points

Problem Statement

2N players are running a competitive table tennis training on N tables numbered from 1 to N.

The training consists of rounds.
In each round, the players form N pairs, one pair per table.
In each pair, competitors play a match against each other.
As a result, one of them wins and the other one loses.

The winner of the match on table X plays on table X-1 in the next round,
except for the winner of the match on table 1 who stays at table 1.

Similarly, the loser of the match on table X plays on table X+1 in the next round,
except for the loser of the match on table N who stays at table N.

Two friends are playing their first round matches on distinct tables A and B.
Let's assume that the friends are strong enough to win or lose any match at will.
What is the smallest number of rounds after which the friends can get to play a match against each other?

Constraints

2 \leq N \leq 10^{18}

1 \leq A < B \leq N

All input values are integers.

Input

Input is given from Standard Input in the following format:

N A B

Output

Print the smallest number of rounds after which the friends can get to play a match against each other.

Sample Input 1

5 2 4

Sample Output 1

1

If the first friend loses their match and the second friend wins their match, they will both move to table 3 and play each other in the next round.

Sample Input 2

5 2 3

Sample Output 2

2

If both friends win two matches in a row, they will both move to table 1.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.io.*;
import java.util.*;
 
public class Main{
    
    public static void main(String[] args) throws IOException {
        Reader.init();
        long N=Reader.nextLong();
      	long A=Reader.nextLong();
      	long B=Reader.nextLong();
        
      	if((B-A)%2==0){
      	  	println((B-A)/2);
        }
      	else{
          	long res=0;
          	if((A-1)<(N-B)){
            	res+=A-1;
              	A=1;
              	B=B-res;
              	B--;
              	res++;
              	res+=(B-A)/2;
            }
          	else{
            	res+=N-B;
              	B=N;
              	A=A+res;
              	A++;
              	res++;
              	res+=(B-A)/2;
            }
          	println(res);
        }
    }
    
    static int mod=1000000007;
    public static void read(int arr[], int N) throws IOException{ for(int i=0;i<N;i++){ arr[i]=Reader.nextInt(); } }
    public static void read(long arr[], int N) throws IOException{ for(int i=0;i<N;i++){ arr[i]=Reader.nextLong(); } }
    public static void read(String arr[], int N) throws IOException{ for(int i=0;i<N;i++){ arr[i]=Reader.next(); } }
    public static void print(Object O){ System.out.print(O); }
    public static void println(Object O){ System.out.println(O); }
    public static void display(int arr[]){ System.out.println(Arrays.toString(arr)); }
    public static void display(int arr[][], int N){ for(int i=0;i<N;i++){ System.out.println(Arrays.toString(arr[i])); } }
}

class Reader {
    static BufferedReader reader;
    static StringTokenizer tokenizer;
 
    static void init() {
        reader=new BufferedReader(new InputStreamReader(System.in));
        tokenizer=new StringTokenizer("");
    }
 
    static String next() throws IOException {
        while (!tokenizer.hasMoreTokens() ) {
            tokenizer=new StringTokenizer(reader.readLine());
        }
        return tokenizer.nextToken();
    }
 
    static int nextInt() throws IOException { return Integer.parseInt(next()); }
    static double nextDouble() throws IOException { return Double.parseDouble(next()); }
    static long nextLong() throws IOException { return Long.parseLong(next()); }
    static String nextLine() throws IOException { return reader.readLine(); }
}