Problem:
Score : 100 points

Problem Statement

You are given four digits N_1, N_2, N_3 and N_4. Determine if these can be arranged into the sequence of digits "1974".

Constraints

0 \leq N_1, N_2, N_3, N_4 \leq 9

N_1, N_2, N_3 and N_4 are integers.

Input

Input is given from Standard Input in the following format:

N_1 N_2 N_3 N_4

Output

If N_1, N_2, N_3 and N_4 can be arranged into the sequence of digits "1974", print YES; if they cannot, print NO.

Sample Input 1

1 7 9 4

Sample Output 1

YES

We can get 1974 by swapping N_2 and N_3.

Sample Input 2

1 9 7 4

Sample Output 2

YES

We already have 1974 before doing anything.

Sample Input 3

1 2 9 1

Sample Output 3

NO

Sample Input 4

4 9 0 8

Sample Output 4

NO

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Runtime Error)

import java.util.*;
public class Main {
 public static void main (String[] args){

	 	Scanner sc = new Scanner(System.in);
	 	
	 	// 整数の入力
	 	String str = sc.next();

	 	String out = "NO";
	 	for (int i =0; i< 8; i++){
	 		String strTry = str.substring(0,i)+str.substring(i+str.length()-7);
	 		if (strTry.equals("keyence")){
	 			out = "YES";
	 			break;
	 		}
	 	}



	 	// 出力
	 	
	 	System.out.println(out);

	 
	 
 }
	
}