Problem:
Score : 200 points

Problem Statement

A shop sells N kinds of fruits, Fruit 1, \ldots, N, at prices of p_1, \ldots, p_N yen per item, respectively. (Yen is the currency of Japan.)

Here, we will choose K kinds of fruits and buy one of each chosen kind. Find the minimum possible total price of those fruits.

Constraints

1 \leq K \leq N \leq 1000

1 \leq p_i \leq 1000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
p_1 p_2 \ldots p_N

Output

Print an integer representing the minimum possible total price of fruits.

Sample Input 1

5 3
50 100 80 120 80

Sample Output 1

210

This shop sells Fruit 1, 2, 3, 4, and 5 for 50 yen, 100 yen, 80 yen, 120 yen, and 80 yen, respectively.

The minimum total price for three kinds of fruits is 50 + 80 + 80 = 210 yen when choosing Fruit 1, 3, and 5.

Sample Input 2

1 1
1000

Sample Output 2

1000

Solution in Java (OpenJDK 11.0.6) (judge verdict: Accepted)

import java.io.*;
import java.util.Scanner;
import java.util.Arrays;
import java.util.ArrayList;
import java.math.BigDecimal;

public class Main{

    public static void main(String[] args){
        //START

        Scanner sc=new Scanner(System.in);

        //String N=sc.next();

        int N=sc.nextInt();
        int K=sc.nextInt();

        int[] p=new int[N];

        int i=0;

        for(i=0;i<N;i++){
            p[i]=sc.nextInt();
            //System.out.println(p[i]+" ");
        }

        Arrays.sort(p);

        int sum=0;

        for(i=0;i<K;i++){
            sum=sum+p[i];
            //System.out.println(p[i]);
        }

        System.out.print(sum);
        //END
    }
}