Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Runtime Error)

import java.util.Scanner;

public class Main {
		public static void main(String args[]) {
			Scanner sc = new Scanner(System.in);
			char array[] = new char[1200], cnt = 0;
			int code[] = new int['z'-'a'+1];
			String str;
			
			get_out : for(;;) {
				str = sc.next();
				for(int j = 0; j < str.length(); j++) {
					if((int)str.charAt(j) == '.') {
						break get_out;
					}
					array[cnt] = str.charAt(j);
					cnt++;
				}
			}
			sc.close();
			
			for(int i = 0; i < cnt; i++) {
				if(array[i] <= 90 && array[i] >= 65) {
					array[i] += 'a' - 'A';
				}
				
				if(array[i] >= 97 && array[i] <= 122) {
					code[(int) array[i] - 97]++;
				}
			}
			
			for(int i = 0; i < 'z'-'a'+1; i++) {
				System.out.printf("%c : %d\n", 97+i, code[i]);
			}
		}
}