Problem:
Score : 200 points

Problem Statement

Let us define the FizzBuzz sequence a_1,a_2,... as follows:

If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.

If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.

If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.

If none of the above holds, a_i=i.

Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Constraints

1 \leq N \leq 10^6

Input

Input is given from Standard Input in the following format:

N

Output

Print the sum of all numbers among the first N terms of the FizzBuzz sequence.

Sample Input 1

15

Sample Output 1

60

The first 15 terms of the FizzBuzz sequence are:

1,2,\mbox{Fizz},4,\mbox{Buzz},\mbox{Fizz},7,8,\mbox{Fizz},\mbox{Buzz},11,\mbox{Fizz},13,14,\mbox{FizzBuzz}

Among them, numbers are 1,2,4,7,8,11,13,14, and the sum of them is 60.

Sample Input 2

1000000

Sample Output 2

266666333332

Watch out for overflow.

Solution in Java (OpenJDK 11.0.6) (judge verdict: Wrong Answer)

import java.util.Scanner;

public class Main {
	public static void main(String[] args) {
	 	Scanner scanner = new Scanner(System.in);
	 	long N = scanner.nextLong();
	 	long x = 0;
	 	long y = 0;
	 	long sum = 0;
	 	x = N / 15;
	 	y = N % 15;
	 	sum = (60 + 60 + 120 * (x - 1)) * x / 2;
	 	if (y == 1) {
	 		sum += 1 + 15 * x;
	 	} else if (y == 2 || y == 3) {
	 		sum += 3 + 15 * x * 2;
	 	} else if (y == 4 || y == 5 || y == 6) {
	 		sum += 7 + 15 * x * 3;
	 	} else if (y == 7) {
	 		sum += 14 + 15 * x * 4;
	 	} else if (y == 8 || y == 9 || y == 10) {
	 		sum += 22 + 15 * x * 5;
	 	} else if (y == 11 || y == 12) {
	 		sum += 33 + 15 * x * 6;
	 	} else if (y == 13) {
	 		sum += 26 + 15 * x * 7;
	 	} else if (y == 14) {
	 		sum += 40 + 15 * x * 8;
	 	}
	 	System.out.println(x);
	 	System.out.println(y);
	 	System.out.println(sum);
 	}
}