Problem:
Selection Sort

Write a program of the Selection Sort algorithm which sorts a sequence A in ascending order. The algorithm should be based on the following pseudocode:

SelectionSort(A)
1 for i = 0 to A.length-1
2 mini = i
3 for j = i to A.length-1
4 if A[j] < A[mini]
5 mini = j
6 swap A[i] and A[mini]

Note that, indices for array elements are based on 0-origin.

Your program should also print the number of swap operations defined in line 6 of the pseudocode in the case where i ≠ mini.

Input

The first line of the input includes an integer N, the number of elements in the sequence.

In the second line, N elements of the sequence are given separated by space characters.

Output

The output consists of 2 lines.

In the first line, please print the sorted sequence. Two contiguous elements of the sequence should be separated by a space character.

In the second line, please print the number of swap operations.

Constraints

1 ≤ N ≤ 100

Sample Input 1

6
5 6 4 2 1 3

Sample Output 1

1 2 3 4 5 6
4

Sample Input 2

6
5 2 4 6 1 3

Sample Output 2

1 2 3 4 5 6
3

Solution in JAVA (judge verdict: Accepted)

import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		Scanner sc=new Scanner(System.in);
		int n=Integer.valueOf(sc.next());
		int[] arr= new int[n];
		for(int i=0;i<n;i++){
			arr[i]=Integer.valueOf(sc.next());
		}
		sc.close();
		
		int count=0;
		for(int i=0;i<n-1;i++){
			int min=Integer.MAX_VALUE;
			int k=0;
			for(int j=i;j<n;j++){
				if(min>arr[j]){
					min=arr[j];
					k=j;
				}
			}
			if(i!=k){
				arr[k]=arr[i];
				arr[i]=min;
				count++;
			}
		}
		System.out.print(arr[0]);
		for(int i=1;i<n;i++){
			System.out.print(" "+arr[i]);
		}
		System.out.println();
		System.out.println(count);
	}

}