Problem:
Score : 300 points

Problem Statement

You are given an integer N.

For two positive integers A and B, we will define F(A,B) as the larger of the following: the number of digits in the decimal notation of A, and the number of digits in the decimal notation of B.

For example, F(3,11) = 2 since 3 has one digit and 11 has two digits.

Find the minimum value of F(A,B) as (A,B) ranges over all pairs of positive integers such that N = A \times B.

Constraints

1 \leq N \leq 10^{10}

N is an integer.

Input

The input is given from Standard Input in the following format:

N

Output

Print the minimum value of F(A,B) as (A,B) ranges over all pairs of positive integers such that N = A \times B.

Sample Input 1

10000

Sample Output 1

3

F(A,B) has a minimum value of 3 at (A,B)=(100,100).

Sample Input 2

1000003

Sample Output 2

7

There are two pairs (A,B) that satisfy the condition: (1,1000003) and (1000003,1). For these pairs, F(1,1000003)=F(1000003,1)=7.

Sample Input 3

9876543210

Sample Output 3

6

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)


import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.StringTokenizer;

public class Main implements Runnable { // クラス名はMain1

	public static void main(String[] args) {
		Thread.setDefaultUncaughtExceptionHandler((t, e) -> System.exit(1));
		new Thread(null, new Main(), "", 1024 * 1024 * 1024).start(); // 16MBスタックを確保して実行
	}

	/**
	 * for (int i = 0; i < N; i++) {} System.out.println(); HashMap<Integer,
	 * Integer> hm = new HashMap<>(); int[] s = new int[M]; ArrayDeque<Integer> deq
	 * = new ArrayDeque<>();
	 *
	 * 文字列のSort String sorted = S.chars() .sorted() .collect(StringBuilder::new,
	 * StringBuilder::appendCodePoint, StringBuilder::append) .toString(); for (char
	 * i = 'a'; i <= 'z'; i++) {}
	 * System.out.println("i:" + i + " ,j:" + j);
	 *
	 * あいうえお → い
	 * S.substring(1,2)
	 */
	public void run() {
		FastScannerMain1 sc = new FastScannerMain1(System.in);

		try {
			long N = sc.nextLong();
			ArrayList<Long> arr = new ArrayList<Long>();
			ArrayList<Long> arr2 = new ArrayList<Long>();
			enum_divisors(N, arr, arr2);

			int ans = Integer.MAX_VALUE;
			for (int i = 0; i < arr.size(); i++) {

				int len = Math.max(String.valueOf(arr.get(i)).length(), String.valueOf(arr2.get(i)).length());
				if (len < ans) {
					ans = len;
				}
			}
			System.out.println(ans);

		} catch (ArithmeticException ae) {
			ae.printStackTrace();
		} catch (Exception e) {
			e.printStackTrace();
		}

	}

	/*
	 * 約数列挙(O(√N ))
	 */
	public void enum_divisors(long number, ArrayList<Long> arr, ArrayList<Long> arr2) {

		for (long i = 1; i * i <= number; i++) {
			if (number % i == 0) {
				arr.add(i);
				// i の相方である N/i も push
				arr2.add(number / i);
			}
		}
	}

	// 下記はオーバーフローでExceptionをキャッチするよう
	private long multiple(long a, long b) {
		long ans = 0;
		try {
			ans = Math.multiplyExact(a, b);
			return ans;
		} catch (ArithmeticException ae) {
			throw new ArithmeticException();
		}
	}

	private int multiple(int a, int b) {
		int ans = 0;
		try {
			ans = Math.multiplyExact(a, b);
			return ans;
		} catch (ArithmeticException ae) {
			throw new ArithmeticException();
		}
	}

	private long add(long a, long b) {
		long ans = 0;
		try {
			ans = Math.addExact(a, b);
			return ans;
		} catch (ArithmeticException ae) {
			throw new ArithmeticException();
		}
	}

	private int add(int a, int b) {
		int ans = 0;
		try {
			ans = Math.addExact(a, b);
			return ans;
		} catch (ArithmeticException ae) {
			throw new ArithmeticException();
		}
	}
}

// 高速なScanner
class FastScannerMain1 {
	private BufferedReader reader = null;
	private StringTokenizer tokenizer = null;

	public FastScannerMain1(InputStream in) {
		reader = new BufferedReader(new InputStreamReader(in));
		tokenizer = null;
	}

	public String next() {
		if (tokenizer == null || !tokenizer.hasMoreTokens()) {
			try {
				tokenizer = new StringTokenizer(reader.readLine());
			} catch (IOException e) {
				throw new RuntimeException(e);
			}
		}
		return tokenizer.nextToken();
	}

	public String nextLine() {
		if (tokenizer == null || !tokenizer.hasMoreTokens()) {
			try {
				return reader.readLine();
			} catch (IOException e) {
				throw new RuntimeException(e);
			}
		}
		return tokenizer.nextToken("\n");
	}

	public long nextLong() {
		return Long.parseLong(next());
	}

	public int nextInt() {
		return Integer.parseInt(next());
	}

	public double nextDouble() {
		return Double.parseDouble(next());
	}

	public int[] nextIntArray(int n) {
		int[] a = new int[n];
		for (int i = 0; i < n; i++)
			a[i] = nextInt();
		return a;
	}

	public long[] nextLongArray(int n) {
		long[] a = new long[n];
		for (int i = 0; i < n; i++)
			a[i] = nextLong();
		return a;
	}
}