Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.*;
 
public class Main{
	public static void main(String[] args){
		Scanner sc = new Scanner(System.in);
		long N = sc.nextLong();
		if(N%4==0){
			System.out.println(N*3/4+" "+N*3/4+" "+N*3/4);
		}else if(N%2==0){
			System.out.println(N/2+" "+N+" "+N);
		}else{
			long h = (long)(Math.ceil((double)N/4.0));
			double amari = ((double)N*(double)h)/(4.0*(double)h-(double)N);
			long n = (long)(Math.ceil(amari));
			amari = ((double)N*(double)n*(double)h) / (4.0*(double)h*(double)n - ((double)h+(double)n)*(double)N);
			long w = (long)(Math.ceil(amari));
			System.out.println(h+" "+n+" "+w);			
		}
		return;
	}
}