Problem:
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Min, Max and Sum

Write a program which reads a sequence of $n$ integers $a_i (i = 1, 2, ... n)$, and prints the minimum value, maximum value and sum of the sequence.

Input

In the first line, an integer $n$ is given. In the next line, $n$ integers $a_i$ are given in a line.

Output

Print the minimum value, maximum value and sum in a line. Put a single space between the values.

Constraints

$0 < n \leq 10000$

$-1000000 \leq a_i \leq 1000000$

Sample Input

5
10 1 5 4 17

Sample Output

1 17 37

Solution in JAVA (judge verdict: Wrong Answer)

import java.io.InputStreamReader;
import java.io.LineNumberReader;
import java.util.Arrays;

/**
 * http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=ITP1_4_D
 * 
 * @author eitatsuro
 * 
 */
public class Main {
    private final static String SPACE = " ";
    public static void main(String[] args) {
        try {
            LineNumberReader stdReader = new LineNumberReader(
                    new InputStreamReader(System.in));
            
            String sStr;
            int n = 0;
            int[] an = null;
            while ((sStr = stdReader.readLine()) != null) {
                if (stdReader.getLineNumber() == 1) {
                    String[] inputs = sStr.split(" ");
                    n = Integer.valueOf(inputs[0]);
                }
                
                if (stdReader.getLineNumber() == 2) {
                    String[] inputs = sStr.split(" ");
                    int i = 0;
                    an = new int[n];
                    for (String input : inputs) {
                        an[i] = Integer.parseInt(input);
                        i++;
                    }
                }
            }
            // sort by ascending order.
            Arrays.sort(an);
            System.out.print(an[0]);
            System.out.print(SPACE);
            System.out.print(an[n - 1]);
            System.out.print(SPACE);
            int sum = 0;
            for (int a : an) {
                sum += a;
            }
            System.out.println(sum);
            
            stdReader.close();
        } catch (Exception e) {
            System.exit(-1);
        }
    }
}