Problem:
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A Point in a Triangle

There is a triangle formed by three points $(x_1, y_1)$, $(x_2, y_2)$, $(x_3, y_3)$ on a plain.

Write a program which prints "YES" if a point $P$ $(x_p, y_p)$ is in the triangle and "NO" if not.

Input

Input consists of several datasets. Each dataset consists of:

$x_1$ $y_1$ $x_2$ $y_2$ $x_3$ $y_3$ $x_p$ $y_p$

All the input are real numbers. Input ends with EOF. The number of datasets is less than or equal to 100.

Constraints

You can assume that:

$ -100 \leq x_1, y_1, x_2, y_2, x_3, y_3, x_p, y_p \leq 100$

1.0 $\leq$ Length of each side of a tringle

0.001 $\leq$ Distance between $P$ and each side of a triangle

Output

For each dataset, print "YES" or "NO" in a line.

Sample Input

0.0 0.0 2.0 0.0 2.0 2.0 1.5 0.5
0.0 0.0 1.0 4.0 5.0 3.0 -1.0 3.0

Output for the Sample Input

YES
NO

Solution in JAVA (judge verdict: Wrong Answer)

import java.io.*;

public class Main {
	public static void main(String[] args) throws Exception{
		BufferedReader bf =new BufferedReader(new InputStreamReader(System.in));
		double[][] p=new double[4][2];
		double[] s=new double[4];
		int a,b,c;
		String t = "";
		String[] d = new String[8];
		while((t=bf.readLine())!=null){
			if(t.length()<=0)break;
			d=t.split(" ");
			for(int i=0;i<4;i++)for(int j=0;j<2;j++)p[i][j]=Double.parseDouble(d[i*2+j]);
			if((p[0][0]-p[2][0])*(p[0][1]-p[3][1])==(p[0][0]-p[3][0])*(p[0][1]-p[2][1])){System.out.println("NO");continue;}
			for(int i=0;i<3;i++){
				a=i;
				b=(a+1)%3;
				c=(b+1)%3;
				s[0]=(p[a][0]-p[b][0])*(p[c][1]-p[a][1])+(p[a][1]-p[b][1])*(p[a][0]-p[c][0]);
				s[1]=(p[a][0]-p[b][0])*(p[3][1]-p[a][1])+(p[a][1]-p[b][1])*(p[a][0]-p[3][0]);
				s[2]=(p[c][0]-p[3][0])*(p[a][1]-p[c][1])+(p[c][1]-p[3][1])*(p[c][0]-p[a][0]);
				s[3]=(p[c][0]-p[3][0])*(p[b][1]-p[c][1])+(p[c][1]-p[3][1])*(p[c][0]-p[b][0]);
				if(s[0]*s[1]<0.0 && s[2]*s[3]<0.0){System.out.println("NO");break;}
				if(i==2)System.out.println("YES");
			}
		}
	}
}