Problem:
Score : 200 points

Problem Statement

In the beginning, Takahashi has A cookies, and Aoki has B cookies.
They will perform the following operation alternately, starting from Takahashi:

If the number of cookies in his hand is odd, eat one of those cookies; if the number is even, do nothing. Then, give one-half of the cookies in his hand to the other person.

Find the numbers of cookies Takahashi and Aoki respectively have after performing K operations in total.

Constraints

1 \leq A,B \leq 10^9

1 \leq K \leq 100

A,B and K are integers.

Input

Input is given from Standard Input in the following format:

A B K

Output

Print the number of cookies Takahashi has, and the number of cookies Aoki has, in this order, after performing K operations in total.

Sample Input 1

5 4 2

Sample Output 1

5 3

The process will go as follows:

In the beginning, Takahashi and Aoki have 5 and 4 cookies, respectively.

Takahashi eats one cookie and gives two cookies to Aoki. They now have 2 and 6 cookies, respectively.

Aoki gives three cookies to Takahashi. They now have 5 and 3 cookies, respectively.

Sample Input 2

3 3 3

Sample Output 2

1 3

Sample Input 3

314159265 358979323 84

Sample Output 3

448759046 224379523

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.*;

public class Main {

	public static void main(String[] args) {
		// TODO Auto-generated method stub
        Scanner sc = new Scanner(System.in);
        
		int a = sc.nextInt();
		int b = sc.nextInt();
		int k = sc.nextInt();
		for(int i = 0; i < k; i++) {
			if(a % 2 == 1) {
				a = a - 1;
			}
			
			b = (a/2) + b;
			a = a/2;
			i++;
			if(i >= k) {
				break;
			}
			
			if(b % 2 == 1) {
				b = b - 1;
			}
			
			a = (b/2) + a;
			b = b/2;
		}
		System.out.println(a + " " + b);
	}

}