Problem:
Score : 600 points

Problem Statement

Snuke has an integer sequence A of length N.

He will make three cuts in A and divide it into four (non-empty) contiguous subsequences B, C, D and E.
The positions of the cuts can be freely chosen.

Let P,Q,R,S be the sums of the elements in B,C,D,E, respectively.
Snuke is happier when the absolute difference of the maximum and the minimum among P,Q,R,S is smaller.
Find the minimum possible absolute difference of the maximum and the minimum among P,Q,R,S.

Constraints

4 \leq N \leq 2 \times 10^5

1 \leq A_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

Find the minimum possible absolute difference of the maximum and the minimum among P,Q,R,S.

Sample Input 1

5
3 2 4 1 2

Sample Output 1

2

If we divide A as B,C,D,E=(3),(2),(4),(1,2), then P=3,Q=2,R=4,S=1+2=3.
Here, the maximum and the minimum among P,Q,R,S are 4 and 2, with the absolute difference of 2.
We cannot make the absolute difference of the maximum and the minimum less than 2, so the answer is 2.

Sample Input 2

10
10 71 84 33 6 47 23 25 52 64

Sample Output 2

36

Sample Input 3

7
1 2 3 1000000000 4 5 6

Sample Output 3

999999994

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.Scanner;

/**
 * Built using CHelper plug-in
 * Actual solution is at the top
 *
 * @author mikit
 */
public class Main {
    public static void main(String[] args) {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        Scanner in = new Scanner(inputStream);
        PrintWriter out = new PrintWriter(outputStream);
        DEqualCut solver = new DEqualCut();
        solver.solve(1, in, out);
        out.close();
    }

    static class DEqualCut {
        public void solve(int testNumber, Scanner in, PrintWriter out) {
            int n = in.nextInt();
            int[] a = new int[n];
            long[] sum = new long[n];
            for (int i = 0; i < n; i++) {
                a[i] = in.nextInt();
                if (i == 0) {
                    sum[i] = a[i];
                } else {
                    sum[i] = sum[i - 1] + a[i];
                }
            }
            long d = Long.MAX_VALUE;
            for (int i = 1; i < n - 1; i++) {//i番目の後がQRの境
                long mdpr = Long.MAX_VALUE;
                long mdprm = 0, mdprx = 0;
                boolean br = false;
                for (int j = 0; j < i; j++) {//PQ
                    long p = sum[j];
                    long q = sum[i] - sum[j];
                    long dif = p - q;
                    if (dif > 0) {
                        if (br) {
                            break;
                        } else {
                            br = true;
                        }
                    } else {
                        dif = -dif;
                    }
                    if (dif < mdpr) {
                        mdpr = dif;
                        mdprm = p < q ? p : q;
                        mdprx = p < q ? q : p;
                    }
                }
                br = false;
                long mdrs = Long.MAX_VALUE;
                long mdrsm = 0, mdrsx = 0;
                for (int j = i + 1; j < n - 1; j++) {//rs
                    long r = sum[j] - sum[i];
                    long s = sum[n - 1] - sum[j];
                    long dif = r - s;
                    if (dif > 0) {
                        if (br) {
                            break;
                        } else {
                            br = true;
                        }
                    } else {
                        dif = -dif;
                    }
                    if (dif < mdrs) {
                        mdrs = dif;
                        mdrsm = r < s ? r : s;
                        mdrsx = r < s ? s : r;
                    }
                }
                d = Math.min(d, Math.max(mdprx, mdrsx) - Math.min(mdprm, mdrsm));
            }
            out.println(d);
        }

    }
}