Problem:
Score : 100 points

Problem Statement

Given is an integer N.

Takahashi chooses an integer a from the positive integers not greater than N with equal probability.

Find the probability that a is odd.

Constraints

1 \leq N \leq 100

Input

Input is given from Standard Input in the following format:

N

Output

Print the probability that a is odd.
Your output will be considered correct when its absolute or relative error from the judge's output is at most 10^{-6}.

Sample Input 1

4

Sample Output 1

0.5000000000

There are four positive integers not greater than 4: 1, 2, 3, and 4. Among them, we have two odd numbers: 1 and 3. Thus, the answer is \frac{2}{4} = 0.5.

Sample Input 2

5

Sample Output 2

0.6000000000

Sample Input 3

1

Sample Output 3

1.0000000000

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.*;
public class Main{
	public static void main (String args[]){
		Scanner sc = new Scanner(System.in);
		int N = sc.nextInt();
        int count = oddCount(N);
        double result = (double)count/N;
      
      	System.out.println(result);
	}
  
  	public static int oddCount(int N){
      ArrayList<Integer> intList = new ArrayList<Integer>();
      for(int i = 1; i<=N; i++){
      	intList.add(i);
      }
      int count = 0;
      for(int aN : intList){
        if (aN%2==1){
          count++;
        }
      }
      System.out.println(count);
      return count;
      
    }
}