Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Accepted)

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.IOException;
public class Main{
	public static void main(String[] args) throws IOException{
		try{
			BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
			StringBuilder sb = new StringBuilder();
			int[] counter = new int[26];
			String line; 
			//line = br.readLine();
			char ch = 'a';
			//char[] c = line.toCharArray();
			while((line = br.readLine())!=null){
				char[] c = line.toCharArray();
				for(int i = 0; i < c.length; i++){
					if( c[i] >= 'A' && c[i] <= 'z' ){
						if( Character.isUpperCase(c[i]) ){
							c[i] = Character.toLowerCase(c[i]);
						}
						int num = c[i] - 'a';
						counter[num]++;
					}
				}
			}
			
			for(int i = 0; i < counter.length; i++){
				System.out.println( ch++ + " : " + counter[i]);
			}
		}catch(IOException e){
			System.out.println(e);
		}
	}
}