Problem:
Selection Sort

Write a program of the Selection Sort algorithm which sorts a sequence A in ascending order. The algorithm should be based on the following pseudocode:

SelectionSort(A)
1 for i = 0 to A.length-1
2 mini = i
3 for j = i to A.length-1
4 if A[j] < A[mini]
5 mini = j
6 swap A[i] and A[mini]

Note that, indices for array elements are based on 0-origin.

Your program should also print the number of swap operations defined in line 6 of the pseudocode in the case where i ≠ mini.

Input

The first line of the input includes an integer N, the number of elements in the sequence.

In the second line, N elements of the sequence are given separated by space characters.

Output

The output consists of 2 lines.

In the first line, please print the sorted sequence. Two contiguous elements of the sequence should be separated by a space character.

In the second line, please print the number of swap operations.

Constraints

1 ≤ N ≤ 100

Sample Input 1

6
5 6 4 2 1 3

Sample Output 1

1 2 3 4 5 6
4

Sample Input 2

6
5 2 4 6 1 3

Sample Output 2

1 2 3 4 5 6
3

Solution in JAVA (judge verdict: Accepted)

import java.util.Scanner;

public class Main {
	static int swap=0;
	public static void main(String[] args){
		Scanner sc=new Scanner(System.in);
		int N=sc.nextInt();
		int[] A =new int[N];
		for(int i=0;i<N;i++){
			A[i]=sc.nextInt();
		}
		SelectionSort(A);
		for(int i=0;i<N;i++){
			if(i==N-1){
				System.out.println(A[i]);
			}else{
				System.out.print(A[i]+" ");
			}
		}
		System.out.println(swap);
	}
	
	static void SelectionSort(int[] a){
		for(int i=0;i<a.length;i++){
			int mini=i;
			for(int j=i;j<a.length;j++){
				if(a[j]<a[mini]){
					mini=j;
				}
			}
			if(i!=mini){
				int t=a[i];
				a[i]=a[mini];
				a[mini]=t;
				swap++;	
			}
		}
	}
}