Problem:
Score : 300 points

Problem Statement

Iroha is very particular about numbers. There are K digits that she dislikes: D_1, D_2, ..., D_K.

She is shopping, and now paying at the cashier.
Her total is N yen (the currency of Japan), thus she has to hand at least N yen to the cashier (and possibly receive the change).

However, as mentioned before, she is very particular about numbers. When she hands money to the cashier, the decimal notation of the amount must not contain any digits that she dislikes. Under this condition, she will hand the minimum amount of money.

Find the amount of money that she will hand to the cashier.

Constraints

1 ≦ N < 10000

1 ≦ K < 10

0 ≦ D_1 < D_2 < … < D_K≦9

\{D_1,D_2,...,D_K\} ≠ \{1,2,3,4,5,6,7,8,9\}

Input

The input is given from Standard Input in the following format:

N K
D_1 D_2 … D_K

Output

Print the amount of money that Iroha will hand to the cashier.

Sample Input 1

1000 8
1 3 4 5 6 7 8 9

Sample Output 1

2000

She dislikes all digits except 0 and 2.

The smallest integer equal to or greater than N=1000 whose decimal notation contains only 0 and 2, is 2000.

Sample Input 2

9999 1
0

Sample Output 2

9999

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.ArrayList;
import java.util.Scanner;
import java.util.StringTokenizer;

public class Main {
	static int size;
	
	public static void main(String[] args) {
		Scanner scan = new  Scanner(System.in);
		StringTokenizer strToken = new StringTokenizer(scan.nextLine(), " ");
		StringTokenizer digitToken = new StringTokenizer(scan.nextLine(), " ");
		ArrayList<Integer> disLikes = new ArrayList<Integer>();
		
		StringBuffer N = new StringBuffer(strToken.nextToken());
		StringBuffer K = new StringBuffer(strToken.nextToken());
		
		while(digitToken.hasMoreTokens()){
			disLikes.add(Integer.parseInt(digitToken.nextToken()));
		}
		
		//돈을 자리수 대로 stack에 쌓는다
		ArrayList<Integer> nArr = new ArrayList<Integer>();
		N = N.reverse();
		for(int i=0; i<N.length(); i++){
			nArr.add(Integer.parseInt(Character.toString(N.toString().charAt(i))));			
		}
		
		size = nArr.size();
		
		for(int i=0; i<size; i++){
			while(true){
				if( disLikes.contains(nArr.get(i)) ){
					if(nArr.get(i) == 9){
						addArr(i, nArr);
					}else{
						nArr.set(i, nArr.get(i)+1);  							
					}
				}else{
					break;
				}	
			}
		}
		
		String print="";
		
		for(int i=nArr.size()-1; i >=0; i-- ){
			print += nArr.get(i);
		}
		
		System.out.println(print);
	}
	
	static void addArr(int i, ArrayList<Integer> nArr){
		//해당 수가 9이고 top일 경우 stack의 사이즈를 1증가시키고 값을 1로 초기화 시킨다.
		if(i == size-1){
			nArr.add(1);
			nArr.set(i, 0);
			size++;
		}else{
			//해당 수가 9인데 top이 아닐경우 해당수를 0으로 세팅한다.
			nArr.set(i, 0);
			
			//다음 수가 9일경우에는 addArr를 한번더 호출한다.
			if(nArr.get(i+1) == 9){
				addArr(i+1, nArr);
			}else{
				//다음 수가 9가 아닐 경우엔  다음수를 +1한 수로 초기화시켜준다.
				nArr.set(i+1, nArr.get(i+1)+1);
			}						
		}
	}
}