Problem:
Finding Missing Cards

Taro is going to play a card game. However, now he has only n cards, even though there should be 52 cards (he has no Jokers).

The 52 cards include 13 ranks of each of the four suits: spade, heart, club and diamond.

Input

In the first line, the number of cards n (n ≤ 52) is given.

In the following n lines, data of the n cards are given. Each card is given by a pair of a character and an integer which represent its suit and rank respectively. A suit is represented by 'S', 'H', 'C' and 'D' for spades, hearts, clubs and diamonds respectively. A rank is represented by an integer from 1 to 13.

Output

Print the missing cards. The same as the input format, each card should be printed with a character and an integer separated by a space character in a line.
Arrange the missing cards in the following priorities:

Print cards of spades, hearts, clubs and diamonds in this order.

If the suits are equal, print cards with lower ranks first.

Sample Input

47
S 10
S 11
S 12
S 13
H 1
H 2
S 6
S 7
S 8
S 9
H 6
H 8
H 9
H 10
H 11
H 4
H 5
S 2
S 3
S 4
S 5
H 12
H 13
C 1
C 2
D 1
D 2
D 3
D 4
D 5
D 6
D 7
C 3
C 4
C 5
C 6
C 7
C 8
C 9
C 10
C 11
C 13
D 9
D 10
D 11
D 12
D 13

Sample Output

S 1
H 3
H 7
C 12
D 8

Note

      解説

Solution in JAVA (judge verdict: WA: Presentation Error)

import java.util.Scanner;

public class Main {
	public static void main(String [] args) {
		Scanner stdIn = new Scanner(System.in);
		int n, x , a = 13;
		String c;
		boolean data[] = new boolean[52];
		
		for(int i = 0; i < data.length; i++) {
			data[i] = false;
		}
		
		n = stdIn.nextInt();
		
		for( int i = 1; i <= n; i++) {
			c = stdIn.next();
			x = stdIn.nextInt();
			
			switch(c) {
			case "S":
				data[x - 1] = true;
				break;
			case "H":
				data[a + x - 1] = true;
				break;
			case "C":
				data[a * 2 + x - 1] = true;
				break;
			case "D":
				data[a * 3 + x - 1] = true;
				break;
			default:
				break;
			}
		}
		
		for(int i = 0; i < 4; i++) {
			for(int j = 1; j <= 13; j ++) {
				switch(i) {
				case 0:
					if(data[j - 1] == false) {
						System.out.println("S　" + j);
					}
					break;
				case 1:
					if(data[a + j - 1] == false) {
						System.out.println("H　" + j);
					}
					break;
				case 2:
					if(data[a * 2 + j - 1] == false) {
						System.out.println("C　" + j);
					}
					break;
				case 3:
					if(data[a * 3 + j - 1] == false) {
						System.out.println("D　" + j);
						
					}
					break;
				default:
					break;
				}
			}
			
		}
		
	}
}