Problem:
Score : 100 points

Problem Statement

In AtCoder City, there are three stations numbered 1, 2, and 3.

Each of these stations is operated by one of the two railway companies, A and B. A string S of length 3 represents which company operates each station. If S_i is A, Company A operates Station i; if S_i is B, Company B operates Station i.

To improve the transportation condition, for each pair of a station operated by Company A and one operated by Company B, there will be a bus service connecting them.

Determine if there is a pair of stations that will be connected by a bus service.

Constraints

Each character of S is A or B.

|S| = 3

Input

Input is given from Standard Input in the following format:

S

Output

If there is a pair of stations that will be connected by a bus service, print Yes; otherwise, print No.

Sample Input 1

ABA

Sample Output 1

Yes

Company A operates Station 1 and 3, while Company B operates Station 2.

There will be a bus service between Station 1 and 2, and between Station 2 and 3, so print Yes.

Sample Input 2

BBA

Sample Output 2

Yes

Company B operates Station 1 and 2, while Company A operates Station 3.

There will be a bus service between Station 1 and 3, and between Station 2 and 3, so print Yes.

Sample Input 3

BBB

Sample Output 3

No

Company B operates all the stations. Thus, there will be no bus service, so print No.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Runtime Error)

import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;
 
public class Main {
    
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int A = sc.nextInt();
        int B = sc.nextInt();
        int a = 100 * A / 8;
        if (!((100 * A)%8 == 0)) {
            a++;
        }
        int ap = 100 * (A+1) / 8;
        int b = 10 * B;
        int bp = 10 * (B+1);
        List<Integer> in = new ArrayList<>();
        List<Integer> out = new ArrayList<>();
        List<Integer> ans = new ArrayList<>();
        for (int i = a;i <= ap;i++) {
            in.add(i);
        }
        for (int i = b; i <= bp;i++) {
            out.add(i);
        }
        for (Integer i :in) {
            if (out.contains(i)) {
                ans.add(i);
            }
        }
        if (ans.isEmpty()) {
            System.out.println(-1);
        } else {
            System.out.println(ans.get(0));
        }
    }
}