Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Accepted)

import java.util.Scanner;

public class Main {
	void run() {
		Scanner scan = new Scanner(System.in);
		char[] alphabet = {'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z'};
		int[] count = new int[27];

		while (scan.hasNext()) {
			String str = scan.next();
			char[] schar = str.toCharArray();
			for (char c : schar) {
				if (Character.isUpperCase(c))
					c = Character.toLowerCase(c);
				for (int i = 0; i < alphabet.length; i++)
					if (c == alphabet[i]) count[i] += 1;
			}
		}
		for (int i = 0; i < count.length - 1; i++)
			System.out.printf("%c : %d\n", alphabet[i], count[i]);
	}
	public static void main(String[] args) {
		new Main().run();
	}
}