Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: WA: Presentation Error)

import java.util.Scanner;

public class Main {

	// a～zの文字数を記録する配列
	static int[] CharCount = new int[26];

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);

		// Ctrl+Zが押されるまで繰り返す
		while (sc.hasNext()) {
			// 入力と文字カウント
			CountingCharacters(sc.next());
		}
		// 表示
		Print();

	}

	// 文字列からa~zの文字をカウントする（大小文字区別なし）
	static void CountingCharacters(String str) {

		char[] c = str.toCharArray();
		for (int i = 0; i < c.length; i++) {
			for (int a = (int) 'A'; a < (int) 'Z'; a++) {
				if (Character.toUpperCase(c[i]) == (char) a) {
					CharCount[a - (int) 'A']++;
					break;
				}
			}
		}
	}

	// 表示処理
	static void Print() {
		for (int i = 0; i < CharCount.length; i++) {
			System.out.println((char) (i + (int) 'a') + ":" + CharCount[i]);
		}
	}

}