Problem:
Finding Missing Cards

Taro is going to play a card game. However, now he has only n cards, even though there should be 52 cards (he has no Jokers).

The 52 cards include 13 ranks of each of the four suits: spade, heart, club and diamond.

Input

In the first line, the number of cards n (n ≤ 52) is given.

In the following n lines, data of the n cards are given. Each card is given by a pair of a character and an integer which represent its suit and rank respectively. A suit is represented by 'S', 'H', 'C' and 'D' for spades, hearts, clubs and diamonds respectively. A rank is represented by an integer from 1 to 13.

Output

Print the missing cards. The same as the input format, each card should be printed with a character and an integer separated by a space character in a line.
Arrange the missing cards in the following priorities:

Print cards of spades, hearts, clubs and diamonds in this order.

If the suits are equal, print cards with lower ranks first.

Sample Input

47
S 10
S 11
S 12
S 13
H 1
H 2
S 6
S 7
S 8
S 9
H 6
H 8
H 9
H 10
H 11
H 4
H 5
S 2
S 3
S 4
S 5
H 12
H 13
C 1
C 2
D 1
D 2
D 3
D 4
D 5
D 6
D 7
C 3
C 4
C 5
C 6
C 7
C 8
C 9
C 10
C 11
C 13
D 9
D 10
D 11
D 12
D 13

Sample Output

S 1
H 3
H 7
C 12
D 8

Note

      解説

Solution in JAVA (judge verdict: Accepted)

import java.util.*;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        // カードの枚数を受け取る
        int numberOfCards = sc.nextInt();
        
        // 4行13列の二次元配列(初期値はfalse)
        boolean[][] cardExistence = new boolean[4][13];
        
        for (int i=0; i<numberOfCards; i++) {
            String kigou = sc.next();
            int cardNum = sc.nextInt();
            
            // S:0, H:1, C:2, D:3
            if (kigou.equals("S")) 
                cardExistence[0][cardNum - 1] = true;
            else if (kigou.equals("H"))
                cardExistence[1][cardNum - 1] = true;
            else if (kigou.equals("C"))
                cardExistence[2][cardNum - 1] = true;
            else if (kigou.equals("D"))
                cardExistence[3][cardNum - 1] = true;
        }
        
        // S:0, H:1, C:2, D:3
        String[] marks = {"S", "H", "C", "D"};
        
        // 中身がfalse（ないカード）の場合、出力
        for (int i=0; i<4; i++) {
            for (int j=0; j<13; j++) {
                if (cardExistence[i][j] == false)
                    // ないカードの記号と数字を出力
                    System.out.println(marks[i] + " " + (j + 1));
            }
        }
    }
}