Problem:
Score : 200 points

Problem Statement

There are N positive integers written on a blackboard: A_1, ..., A_N.

Snuke can perform the following operation when all integers on the blackboard are even:

Replace each integer X on the blackboard by X divided by 2.

Find the maximum possible number of operations that Snuke can perform.

Constraints

1 \leq N \leq 200

1 \leq A_i \leq 10^9

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

Print the maximum possible number of operations that Snuke can perform.

Sample Input 1

3
8 12 40

Sample Output 1

2

Initially, [8, 12, 40] are written on the blackboard.
Since all those integers are even, Snuke can perform the operation.

After the operation is performed once, [4, 6, 20] are written on the blackboard.
Since all those integers are again even, he can perform the operation.

After the operation is performed twice, [2, 3, 10] are written on the blackboard.
Now, there is an odd number 3 on the blackboard, so he cannot perform the operation any more.

Thus, Snuke can perform the operation at most twice.

Sample Input 2

4
5 6 8 10

Sample Output 2

0

Since there is an odd number 5 on the blackboard already in the beginning, Snuke cannot perform the operation at all.

Sample Input 3

6
382253568 723152896 37802240 379425024 404894720 471526144

Sample Output 3

8

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Scanner;

//-------------------------
// 
//-------------------------

public class Main {
    public static void main(String[] args) {
        boolean isTrue = true;
        int count = 0;

        Scanner scan = new Scanner(System.in);

        int N = Integer.parseInt(scan.next());

        int[] A = new int[N];
        for(int i=0; i<N; i++)
        {
            A[i] = Integer.parseInt(scan.next());
        }

        scan.close();
        
        while(true)
        {
            for(int i=0; i<N; i++)
            {
                if(A[i]%2 != 0) isTrue = false;
            }

            if(isTrue)
            {
                count++;
                for(int i=0; i<N; i++) A[i] = A[i]/2;
            }
            else
            {
                System.out.println(count);
                break;
            }
        }
    }
}