Problem:
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Circles Intersection

You are given circle $A$ with radius $r_a$ and with central coordinate $(x_a, y_a)$ and circle $B$ with radius $r_b$ and with central coordinate $(x_b, y_b)$.

Write a program which prints:

"2" if $B$ is in $A$,

"-2" if $A$ is in $B$,

"1" if circumference of $A$ and $B$ intersect, and

"0" if $A$ and $B$ do not overlap.

You may assume that $A$ and $B$ are not identical.

Input

The input consists of multiple datasets. The first line consists of an integer $N$ ($N \leq 50$), the number of datasets. There will be $N$ lines where each line represents each dataset. Each data set consists of real numbers:

$x_a$ $y_a$ $r_a$ $x_b$ $y_b$ $r_b$

Output

For each dataset, print 2, -2, 1, or 0 in a line.

Sample Input

2
0.0 0.0 5.0 0.0 0.0 4.0
0.0 0.0 2.0 4.1 0.0 2.0

Output for the Sample Input

2
0

Solution in JAVA (judge verdict: Accepted)

import java.lang.*;
import java.util.*;
import java.io.*;

public class Main
{
	public static void main (String[] arg)throws IOException
	{
		BufferedReader input =new BufferedReader (new InputStreamReader (System.in));
		String line;
		line=input.readLine();
		int a = Integer.parseInt(line);
		StringTokenizer tokenizer;
		double[] r1= new double[3];
		double[] r2= new double[3];
			
		for(int i=0;i < a; i++){
			tokenizer = new StringTokenizer(input.readLine());
			for(int j=0;j < 3; j++ ){
				r1[j]=Double.parseDouble(tokenizer.nextToken());
			}
			for(int j=0;j < 3; j++ ){
				r2[j]=Double.parseDouble(tokenizer.nextToken());
			}
			double dis=0;
			dis=Math.sqrt(Math.pow((r1[0]-r2[0]),2)+ Math.pow((r1[1]-r2[1]),2));
			if(dis>r2[2]+r1[2])
			{
				System.out.println("0");
			}else{
				if(dis+r2[2]<r1[2])	{
					System.out.println("2");
				}else{
					if(dis+r1[2]<r2[2]) {
						System.out.println("-2");
					}else{
						System.out.println("1");
					}
				}
			}
		}	
	}
}