Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.Scanner;

public class Main {
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		int N, cnt = 0, sum = 0;
		N = sc.nextInt();
		for (int i = 1; i <= N; i++) {
			if (i % 2 != 0) {
				cnt = 0;
				for (int k = 1; k <= N; k++) {
					if (k % i == 0) {
						cnt++;
					}

				}
				if (cnt == 8) {
					sum++;
				}
			}
		}
		System.out.println(sum);
		sc.close();
	}

}