Problem:
Score : 200 points

Problem Statement

Takahashi has many red balls and blue balls. Now, he will place them in a row.

Initially, there is no ball placed.

Takahashi, who is very patient, will do the following operation 10^{100} times:

Place A blue balls at the end of the row of balls already placed. Then, place B red balls at the end of the row.

How many blue balls will be there among the first N balls in the row of balls made this way?

Constraints

1 \leq N \leq 10^{18}

A, B \geq 0

0 < A + B \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N A B

Output

Print the number of blue balls that will be there among the first N balls in the row of balls.

Sample Input 1

8 3 4

Sample Output 1

4

Let b denote a blue ball, and r denote a red ball. The first eight balls in the row will be bbbrrrrb, among which there are four blue balls.

Sample Input 2

8 0 4

Sample Output 2

0

He placed only red balls from the beginning.

Sample Input 3

6 2 4

Sample Output 3

2

Among bbrrrr, there are two blue balls.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Runtime Error)

import java.util.*;
public class Main {
 public static void main(String[] args){
  Scanner sc = new Scanner(System.in);
  // 整数の入力
  // int a = sc.nextInt();
  // スペース区切りの整数の入力
  int n = sc.nextInt();
  int a = sc.nextInt();
  int b = sc.nextInt();

  // 文字列の入力
 int amari =  n %  (a + b);
 int syo = n/(a+b);
 	
 	if(syo == 0){
 	
 		if(amari>a){
  	 System.out.println(a);

 		}else{
 			  	 System.out.println(n);
 		}
 	}else{
 		if(amari>a){
  	 System.out.println(a+syo*a);

 		}else{
 			  	 System.out.println(amari+syo*a);
 		}
 	
 	}
 // String s = sc.next();
// 	if(s.matches(".*A.*") & s.matches(".*B.*")){
 //	}else{
 //		 	 System.out.println("No");
 //	}
 }
}