Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Java (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		
		Scanner sc = new Scanner(System.in);
		
		int max = sc.nextInt() + 1;
		int[] facs = new int[max];

		for (int i = 2; i < max; ++i) {
		    for (int j = i; j < max; j += i) {
		        facs[j]++;
		    }
		}
		int count = 0;
		for (int i = 0; i < max; ++i)
		    if (facs[i] == 7 && i%2 == 1)//1 is a factor of all number so check for count 7
		        count++;
		System.out.println(count);

	}

}