Problem:
Score : 300 points

Problem Statement

You've come to your favorite store Infinitesco to buy some ice tea.

The store sells ice tea in bottles of different volumes at different costs.
Specifically, a 0.25-liter bottle costs Q yen, a 0.5-liter bottle costs H yen, a 1-liter bottle costs S yen, and a 2-liter bottle costs D yen.
The store has an infinite supply of bottles of each type.

You want to buy exactly N liters of ice tea. How many yen do you have to spend?

Constraints

1 \leq Q, H, S, D \leq 10^8

1 \leq N \leq 10^9

All input values are integers.

Input

Input is given from Standard Input in the following format:

Q H S D
N

Output

Print the smallest number of yen you have to spend to buy exactly N liters of ice tea.

Sample Input 1

20 30 70 90
3

Sample Output 1

150

Buy one 2-liter bottle and two 0.5-liter bottles. You'll get 3 liters for 90 + 30 + 30 = 150 yen.

Sample Input 2

10000 1000 100 10
1

Sample Output 2

100

Even though a 2-liter bottle costs just 10 yen, you need only 1 liter.
Thus, you have to buy a 1-liter bottle for 100 yen.

Sample Input 3

10 100 1000 10000
1

Sample Output 3

40

Now it's better to buy four 0.25-liter bottles for 10 + 10 + 10 + 10 = 40 yen.

Sample Input 4

12345678 87654321 12345678 87654321
123456789

Sample Output 4

1524157763907942

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.Arrays;
import java.util.Comparator;


public class Main {

	/**
	 * @param args
	 */
	public static void main(String[] args) throws IOException{
		// TODO Auto-generated method stub
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
		String[] tmpArray = br.readLine().split(" ");
		int q = Integer.parseInt(tmpArray[0]);
		int h = Integer.parseInt(tmpArray[1]);
		int s = Integer.parseInt(tmpArray[2]);
		int d = Integer.parseInt(tmpArray[3]);
		
		Product[] products = new Product[4];
		
		products[0] = new Product(0.25,q);
		products[1] = new Product(0.5,h);
		products[2] = new Product(1,s);
		products[3] = new Product(2,d);
		
		Arrays.sort(products, new Comparator<Product>() {
			public int compare(Product a, Product b){
				if( a.pricePerLitter() > b.pricePerLitter()){
					return 1;
				}
				else if ( a.pricePerLitter() < b.pricePerLitter()){
					return -1;
				}
				else {
					return 0;
				}
			}
		});
		
		long result = 0;
		int require = Integer.parseInt(br.readLine());
		for(int i = 0; i < 4; i++){
			if(products[i].amount == 2){
				result += products[i].price*(require/2);
				require -= require/2*2;
			}
			else {
				result += products[i].pricePerLitter()*require;
				require = 0;
			}
			
			if(require == 0){
				break;
			}
		}
		System.out.println(result);
	}

}

class Product {
	double amount;
	int price;
	
	public Product(double amount, int price){
		this.amount = amount;
		this.price = price;
	}
	
	public long pricePerLitter(){
	//	return (long)(price/amount);
		if(amount == 0.25){
			return (long)price*4;
		}
		else if(amount == 0.5){
			return (long)price*2;
		}
		else if(amount == 1){
			return price;
		}
		else {
			return price/2;
		}
	}
}