Problem:
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Transformation

Write a program which performs a sequence of commands to a given string $str$. The command is one of:

print a b: print from the a-th character to the b-th character of $str$

reverse a b: reverse from the a-th character to the b-th character of $str$

replace a b p: replace from the a-th character to the b-th character of $str$ with p

Note that the indices of $str$ start with 0.

Input

In the first line, a string $str$ is given. $str$ consists of lowercase letters. In the second line, the number of commands q is given. In the next q lines, each command is given in the above mentioned format.

Output

For each print command, print a string in a line.

Constraints

$1 \leq $ length of $str \leq 1000$

$1 \leq q \leq 100$

$0 \leq a \leq b < $ length of $str$

for replace command, $b - a + 1 = $ length of $p$

Sample Input 1

abcde
3
replace 1 3 xyz
reverse 0 2
print 1 4

Sample Output 1

xaze

Sample Input 2

xyz
3
print 0 2
replace 0 2 abc
print 0 2

Sample Output 2

xyz
abc

Solution in JAVA (judge verdict: Accepted)

import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		int i, q, a, b, r, len;
		String str, com, p, s1, s2, s3;
		str = sc.next();
		q = sc.nextInt();
		
		for (i = 0; i < q; i++) {
			com = sc.next();
			
			switch (com) {
			
			case ("print"):
				a = sc.nextInt();
				b = sc.nextInt();
				s1 = str.substring(a, b + 1);
				System.out.println(s1);
				break;
				
			case ("reverse"):
				a = sc.nextInt();
				b = sc.nextInt();
				s1 = str.substring(0, a);
				s2 = str.substring(a, b + 1);
				s3 = str.substring(b + 1);
				len = s2.length();
				
				for (r = len - 1; r >= 0; r--) {
					s1 += s2.substring(r, r + 1);
				}
				str = s1 + s3;
				break;
				
			case ("replace"):
				a = sc.nextInt();
				b = sc.nextInt();
				p = sc.next();
				s1 = str.substring(0, a);
				s2 = str.substring(a, b + 1);
				s3 = str.substring(b + 1);
				str = s1 + p + s3;
				break;
			default:
				break;
			}
		}
	}
}