Problem:
Simultaneous Equation

Write a program which solve a simultaneous equation:

ax + by = c

dx + ey = f

The program should print x and y for given a, b, c, d, e and f (-1,000 ≤ a, b, c, d, e, f ≤ 1,000). You can suppose that given equation has a unique solution.

Input

The input consists of several data sets, 1 line for each data set. In a data set, there will be a, b, c, d, e, f separated by a single space. The input terminates with EOF.

Output

For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.

Sample Input 1

1 2 3 4 5 6
2 -1 -2 -1 -1 -5

Output for the Sample Input 1

-1.000 2.000
1.000 4.000

Sample Input 2

2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27

Output for the Sample Input 2

0.000 3.000
0.000 3.000

Solution in JAVA (judge verdict: Wrong Answer)

import java.text.DecimalFormat;
import java.util.Scanner;

class Main{
public static void main(String[] args){
	Scanner scan = new Scanner(System.in);
	double a = Double.parseDouble(scan.next());
	double b = Double.parseDouble(scan.next());
	double c = Double.parseDouble(scan.next());
	double d = Double.parseDouble(scan.next());
	double e = Double.parseDouble(scan.next());
	double f = Double.parseDouble(scan.next());
	DecimalFormat df = new DecimalFormat("0.000");
	double x =(c*e-b*f)/(a*e-b*d);
	double y = (a*f-c*d)/(a*e-b*d);
	x = Math.floor((x+0.5)*1000)/1000;
	x = Math.ceil((x-0.5)*1000)/1000;
	y = Math.floor((y+0.5)*1000)/1000;
	y = Math.ceil((y-0.5)*1000)/1000;

	System.out.println(df.format(x)+" "+df.format(y) );


}
}