Problem:
Score : 100 points

Problem Statement

Given is an integer N.

Takahashi chooses an integer a from the positive integers not greater than N with equal probability.

Find the probability that a is odd.

Constraints

1 \leq N \leq 100

Input

Input is given from Standard Input in the following format:

N

Output

Print the probability that a is odd.
Your output will be considered correct when its absolute or relative error from the judge's output is at most 10^{-6}.

Sample Input 1

4

Sample Output 1

0.5000000000

There are four positive integers not greater than 4: 1, 2, 3, and 4. Among them, we have two odd numbers: 1 and 3. Thus, the answer is \frac{2}{4} = 0.5.

Sample Input 2

5

Sample Output 2

0.6000000000

Sample Input 3

1

Sample Output 3

1.0000000000

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Runtime Error)

import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;

public class Main {

    public static void main(String[] args) {
    	
		Scanner sc = new Scanner(System.in);
		// 整数の入力
		int N = sc.nextInt();
		String ans = "";

		// Mapの宣言
        Map<Integer, Integer> map = new HashMap<>();
        
		for (int i = 1; i <= N;i ++ ){
			// 文字列の入力
			int str = sc.nextInt();

        	map.put( str,i);

		}

		for (int i = 1; i <= N;i ++ ){
//        	if(ans.isEmpty()) {
//            	ans = "" + map.get(i);
//            }else {
//            	ans = ans + " " + map.get(i);
//        	}
    		System.out.println(map.get(i) + " ");
		}


   		sc.close();
        return ;

    }
    
}