Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Accepted)

import java.util.Scanner;

public class Main{
    public static void main(String[] aaa){
        Scanner s = new Scanner(System.in);
        int[] count = new int[27];
        String st;
        char m;
        int i,j;
        while(s.hasNext()){
            st = s.next();
            for(i=0;i<st.length();i++){
                j=st.charAt(i);
                if(j-'a'>=0&&j-'a'<26)count[st.charAt(i)-'a']++;
                else if(j-'A'<26&&j-'A'>=0)count[st.charAt(i)-'A']++;
            }
        }
        for(i=0;i<26;i++){
            m = (char)('a'+i);
            System.out.println(m+" : "+count[i]);
        }
    }
}