Problem:
Score : 500 points

Problem Statement

You are given a string S of length N consisting of lowercase English letters.

Process Q queries of the following two types:

Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)

Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).

Constraints

N, Q, i_q, l_q, and r_q are integers.

S is a string consisting of lowercase English letters.

c_q is a lowercase English letter.

1 \leq N \leq 500000

1 \leq Q \leq 20000

|S| = N

1 \leq i_q \leq N

1 \leq l_q \leq r_q \leq N

There is at least one query of type 2 in each testcase.

Input

Input is given from Standard Input in the following format:

N
S
Q
Query_1
\vdots
Query_Q

Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:

1 i_q c_q

2 l_q r_q

Output

For each query of type 2, print a line containing the answer.

Sample Input 1

7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7

Sample Output 1

3
1
5

In the first query, cdbb contains three kinds of letters: b , c , and d, so we print 3.

In the second query, S is modified to abcdzbd.

In the third query, a contains one kind of letter: a, so we print 1.

In the fourth query, S is modified to abcazbd.

In the fifth query, S does not change and is still abcazbd.

In the sixth query, abcazbd contains five kinds of letters: a, b, c, d, and z, so we print 5.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.*;
import java.io.*;


public class Main{
    public static void main(String[] args) {
        FastScanner sc = new FastScanner();
        PrintWriter out = new PrintWriter(System.out);
        int N = sc.nextInt();
        String S = sc.next();
        int Q = sc.nextInt();
        int res = 0;
        String result = "";
        int[][] alphabet = new int[26][S.length()];
        for(int i=0;i<S.length();i++){
            alphabet[S.charAt(i)-'a'][i]++;
        }
        BinaryIndexedTree[] alphabetTree = new BinaryIndexedTree[26];
        for(int i=0;i<26;i++){
            alphabetTree[i] = new BinaryIndexedTree(alphabet[i]);
        }
        for(int i=0;i<Q;i++){
            if(sc.nextInt()==1){
                int iq = sc.nextInt();
                int c = sc.next().charAt(0)-'a';
                if(S.charAt(iq-1)-'a' == c) continue;
                alphabetTree[S.charAt(iq-1)-'a'].add(iq, -1);
                alphabetTree[c].add(iq, 1);
            }
            else{
                int l = sc.nextInt();
                int r = sc.nextInt();
                res = 0;
                for(int j=0;j<26;j++){
                    // out.println(Character.toChars(j+'a')[0] + ":" + alphabetTree[j].sum(l, r));
                    if(alphabetTree[j].sum(l, r)>0) {
                        res++;
                    }
                }
                // out.println(res);
                result += res + "\n";
            }
        }


        out.print(result);
        out.flush();
    }

}

class BinaryIndexedTree{
    int[] data;
    int[] tree;
    int n;

    public BinaryIndexedTree(int[] data){
        this.data = data;
        this.n = data.length;
        this.tree = new int[n+1];
        buildTree();
    }

    public void buildTree(){
        for(int i=0;i<n;i++){
            add(i+1, data[i]);
        }
    }

    public void add(int index, int value){
        for(int i=index; i<=n; i+=i & -i){
            tree[i] += value;
        }
    }

    public int sum(int from, int to){
        return sum(to) - sum(from-1);
    }

    public int sum(int index){
        int sum = 0;
        for(int i=index; i>0; i-=i & -i){
            sum += tree[i];
        }
        return sum;
    }
}

class nextPermutation{
    public static int[] swap(int data[], int left, int right)
    {

        // Swap the data
        int temp = data[left];
        data[left] = data[right];
        data[right] = temp;

        // Return the updated array
        return data;
    }

    // Function to reverse the sub-array
    // starting from left to the right
    // both inclusive
    public static int[] reverse(int data[], int left, int right)
    {

        // Reverse the sub-array
        while (left < right) {
            int temp = data[left];
            data[left++] = data[right];
            data[right--] = temp;
        }

        // Return the updated array
        return data;
    }

    // Function to find the next permutation
    // of the given integer array
    public static boolean findNextPermutation(int data[])
    {

        // If the given dataset is empty
        // or contains only one element
        // next_permutation is not possible
        if (data.length <= 1)
            return false;

        int last = data.length - 2;

        // find the longest non-increasing suffix
        // and find the pivot
        while (last >= 0) {
            if (data[last] < data[last + 1]) {
                break;
            }
            last--;
        }

        // If there is no increasing pair
        // there is no higher order permutation
        if (last < 0)
            return false;

        int nextGreater = data.length - 1;

        // Find the rightmost successor to the pivot
        for (int i = data.length - 1; i > last; i--) {
            if (data[i] > data[last]) {
                nextGreater = i;
                break;
            }
        }

        // Swap the successor and the pivot
        data = swap(data, nextGreater, last);

        // Reverse the suffix
        data = reverse(data, last + 1, data.length - 1);

        // Return true as the next_permutation is done
        return true;
    }
}

class graph{
    int[][] graph;
    public graph(int[][] graph){
        this.graph = graph;
    }

    public long dijkstra(int s, int t){
        Integer[] dist = new Integer[graph.length];
        int[] prev = new int[graph.length];
        Arrays.fill(prev, -1);
        PriorityQueue<Integer> manage = new PriorityQueue<>((x,y) -> dist[x]-dist[y]);
        HashSet<Integer> searched = new HashSet<>();
        Arrays.fill(dist,Integer.MAX_VALUE);
        dist[s] = 0;
        searched.add(s);
        for(int i=0;i<graph.length;i++){
            if(graph[s][i]!=Integer.MAX_VALUE){
                dist[i] = graph[s][i];
                prev[i] = s;
                manage.add(i);
            }
        }
        while(manage.size()>0){
            int now = manage.poll();
            searched.add(now);
            for(int i=0;i<graph.length;i++){
                if(graph[now][i]!=Integer.MAX_VALUE){
                    if(!searched.contains(i)){
                        if(dist[i]==Integer.MAX_VALUE){
                            dist[i] = dist[now] + graph[now][i];
                            prev[i] = now;
                            manage.add(i);
                        }
                        else{
                            dist[i] = Math.min(dist[i],dist[now]+graph[now][i]);
                            if(dist[i]==dist[now]+graph[now][i]) prev[i] = now;
                            manage.remove(i);
                            manage.add(i);
                        }
                    }
                }
            }
            if(searched.contains(t)) break;
        }

        return dist[t];
    }

    public boolean judgeBipartitegraph(){
        int[] color = new int[graph.length];
        PriorityQueue<Integer> queue = new PriorityQueue<>();
        HashSet<Integer> visited = new HashSet<>();
        queue.add(0);
        color[0] = 1;
        while(queue.size()>0){
            int now = queue.poll();
            visited.add(now);
            for(int j=0;j<graph[now].length;j++){
                if(visited.contains(j)) continue;
                if(graph[now][j]!=0){
                    if(color[j]==color[now]) return false;
                    queue.add(j);
                    if(color[j]==0) color[j] = -1*color[now];
                }
            }
        }
        return true;
    }

    public int[][] prim(){
        int[] mincost = new int[graph.length];
        boolean[] used = new boolean[graph.length];
        int[][] spanning = new int[graph.length][graph.length];
        for(int i=0;i<graph.length;i++){
            mincost[i] = Integer.MAX_VALUE;
            used[i] = false;
        }
        mincost[0] = 0;
        int totalCost = 0;
        while(true){
            int v = -1;
            for(int u=0;u<graph.length;u++){
                if(!used[u] && (v==-1||mincost[u]<mincost[v])){
                    v = u;
                }
            }
            if(v==-1) break;
            used[v] = true;
            totalCost += mincost[v];
            for(int u=0;u<graph.length;u++){
                if(graph[v][u]<mincost[u]){
                    mincost[u] = graph[v][u];
                }
            }
            for(int u=0;u<graph.length;u++){
                if(mincost[u]==graph[v][u]){
                    spanning[v][u] = 1;
                    spanning[u][v] = 1;
                    break;
                }
            }
        }
        return spanning;
        // return totalCost;
    }

    public int[][] wf(){
        int[][] dist = new int[graph.length][graph.length];
        dist = graph.clone();
        // for(int i=0;i<graph.length;i++){
        //     dist[i][i] = 0;
        // }
        for(int k=0;k<graph.length;k++){
            for(int i=0;i<graph.length;i++){
                for(int j=0;j<graph.length;j++){
                    if(dist[i][k]==Integer.MAX_VALUE || dist[k][j]==Integer.MAX_VALUE) continue;

                    dist[i][j] = Math.min(dist[i][j],dist[i][k]+dist[k][j]);

                }
            }
        }
        for(int i=0;i<graph.length;i++){
            if(dist[i][i]<0) return null;
        }
        return dist;
    }
}

class FastScanner {
    private final InputStream in = System.in;
    private final byte[] buffer = new byte[1024];
    private int ptr = 0;
    private int buflen = 0;
    private boolean hasNextByte() {
        if (ptr < buflen) {
            return true;
        }else{
            ptr = 0;
            try {
                buflen = in.read(buffer);
            } catch (IOException e) {
                e.printStackTrace();
            }
            if (buflen <= 0) {
                return false;
            }
        }
        return true;
    }
    private int readByte() { if (hasNextByte()) return buffer[ptr++]; else return -1;}
    private static boolean isPrintableChar(int c) { return 33 <= c && c <= 126;}
    public boolean hasNext() { while(hasNextByte() && !isPrintableChar(buffer[ptr])) ptr++; return hasNextByte();}
    public String next() {
        if (!hasNext()) throw new NoSuchElementException();
        StringBuilder sb = new StringBuilder();
        int b = readByte();
        while(isPrintableChar(b)) {
            sb.appendCodePoint(b);
            b = readByte();
        }
        return sb.toString();
    }
    public long nextLong() {
        if (!hasNext()) throw new NoSuchElementException();
        long n = 0;
        boolean minus = false;
        int b = readByte();
        if (b == '-') {
            minus = true;
            b = readByte();
        }
        if (b < '0' || '9' < b) {
            throw new NumberFormatException();
        }
        while(true){
            if ('0' <= b && b <= '9') {
                n *= 10;
                n += b - '0';
            }else if(b == -1 || !isPrintableChar(b)){
                return minus ? -n : n;
            }else{
                throw new NumberFormatException();
            }
            b = readByte();
        }
    }
    public int nextInt() {
        long nl = nextLong();
        if (nl < Integer.MIN_VALUE || nl > Integer.MAX_VALUE) throw new NumberFormatException();
        return (int) nl;
    }
    public double nextDouble() { return Double.parseDouble(next());}
}