Problem:
Score : 200 points

Problem Statement

Given is an integer N. Find the number of digits that N has in base K.

Notes

For information on base-K representation, see Positional notation - Wikipedia.

Constraints

All values in input are integers.

1 \leq N \leq 10^9

2 \leq K \leq 10

Input

Input is given from Standard Input in the following format:

N K

Output

Print the number of digits that N has in base K.

Sample Input 1

11 2

Sample Output 1

4

In binary, 11 is represented as 1011.

Sample Input 2

1010101 10

Sample Output 2

7

Sample Input 3

314159265 3

Sample Output 3

18

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.*;

public class Main {
    final static int MOD = 1000000007;
    
    public static void main(String[] args) {
        MyScanner in = new MyScanner();
        int n = in.nextInt();
        int k = in.nextInt();
        String str = Integer.toString(k,n);
        System.out.println(str);
        
        
    }
    
    static class MyScanner {
        static Scanner sc = new Scanner(System.in);
        
        String next() {
            return sc.next();
        }
        
        String nextLine() {
            return sc.nextLine();
        }
        
        int nextInt() {
            return Integer.parseInt(sc.next());
        }
        
        double nextDouble() {
            return Double.parseDouble(next());
        }
        
        long nextLong() {
            return Long.parseLong(next());
        }
        
        int[] nextIntArray(int n) {
            int[] array = new int[n];
            for (int i = 0; i < n; i++) {
                array[i] = nextInt();
            }
            return array;
        }
        
        double[] nextDoubleArray(int n) {
            double[] array = new double[n];
            for (int i = 0; i < n; i++) {
                array[i] = nextDouble();
            }
            return array;
        }
        
        long[] nextLongArray(int n) {
            long[] array = new long[n];
            for (int i = 0; i < n; i++) {
                array[i] = nextLong();
            }
            return array;
        }
        
        String[] nextLineArray(int n) {
            String[] array = new String[n];
            for (int i = 0; i < n; i++) {
                array[i] = nextLine();
            }
            return array;
        }
        
        int[][] nextIntMatrix(int n, int m) {
            int[][] matrix = new int[n][m];
            for (int i = 0; i < n; i++) {
                for (int j = 0; j < m; j++) {
                    matrix[i][j] = nextInt();
                }
            }
            return matrix;
        }
        
        double[][] nextDoubleMatrix(int n, int m) {
            double[][] matrix = new double[n][m];
            for (int i = 0; i < n; i++) {
                for (int j = 0; j < m; j++) {
                    matrix[i][j] = nextDouble();
                }
            }
            return matrix;
        }
        
        long[][] nextLongMatrix(int n, int m) {
            long[][] matrix = new long[n][m];
            for (int i = 0; i < n; i++) {
                for (int j = 0; j < m; j++) {
                    matrix[i][j] = nextLong();
                }
            }
            return matrix;
        }
    }
}