Problem:
Sale Result

There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.

Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:

n (the number of data in the list)
i p q
i p q
:
:
i p q

Output

For each dataset, print a list of employee IDs or a text "NA"

Sample Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0

Output for the Sample Input

1001
1003
NA
2013

Solution in JAVA (judge verdict: Wrong Answer)

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;

import static java.lang.Integer.parseInt;

public class Main {

	static final int MAX_E = 4000;
	static final int MAX_S = 1000000;

	public static void main(String[] args) throws IOException {
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
		String line = "";

		while ((line = br.readLine()) != null) {
			int n = parseInt(line);
			if (n == 0) {
				break;
			}

			int[] emps = new int[MAX_E];
			int idx = 0;
			long[] sales = new long[MAX_E + 1];
			for (int i = 0; i < sales.length; i++) {
				sales[i] = -1;
			}
			for (int i = 0; i < n; i++) {
				StringTokenizer st = new StringTokenizer(br.readLine());
				int emp = parseInt(st.nextToken());
				if (sales[emp] < 0) {
					sales[emp] = 0;
					emps[idx] = emp;
					idx++;
				}
				sales[emp] += parseInt(st.nextToken()) * parseInt(st.nextToken());
			}
			int count = 0;
			for (int i = 0; i < idx; i++) {
				if (sales[emps[i]] >= MAX_S) {
					System.out.println(emps[i]);
					count++;
				}
			}
			if (count == 0) System.out.println("NA");
		}
	}
}