Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Accepted)


import java.util.Scanner;

public class Main {

	@SuppressWarnings("resource")
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		String scan="";
		while(sc.hasNext()) scan += sc.nextLine();
		scan = scan.toLowerCase();
		char abc[] = {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};
		int count[] = new int[abc.length];

		for(int i=0;i<scan.length();i++) {
			for(int j=0;j<abc.length;j++) {
				if(scan.charAt(i)==abc[j]) count[j]++;
			}
		}
		for(int i=0;i<abc.length;i++) {
			System.out.println(abc[i]+" : "+count[i]);
		}
	}

}