Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Runtime Error)

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class Main {
	static final int hashA = 97;
	static final int hashEnd = hashA + 26;
	static final int hashPeriod = 46;
	void run() throws IOException{
		InputStreamReader isr = new InputStreamReader(System.in);
		BufferedReader br = new BufferedReader(isr);
		String[] alphabet = "abcdefghijklmnopqrstuvwxyz".split("");
		int[] cntAlpha = new int[alphabet.length];
		out: while (true){
			String txt = br.readLine();
			txt = txt.toLowerCase();
			for (int i = 0;i < txt.length();i++){
				char ch = txt.charAt(i);
				int hash = String.valueOf(ch).hashCode();
				if(hash >= hashA && hash <= hashEnd){
					cntAlpha[hash - hashA]++;
				}else if(hash == hashPeriod){
					break out;
				}
			}
		}
		for(int i = 0;i < alphabet.length;i++){
			System.out.println(alphabet[i] + " : " + cntAlpha[i]);
		}
	}
	public static void main(String args[]){
		try{
			new Main().run();
		}catch (IOException e){
			System.out.println(e);
		}
	}
}