Problem:
Binary Search Tree III

Write a program which performs the following operations to a binary search tree $T$ by adding delete operation to B: Binary Search Tree II.

insert $k$: Insert a node containing $k$ as key into $T$.

find $k$: Report whether $T$ has a node containing $k$.

delete $k$: Delete a node containing $k$.

print: Print the keys of the binary search tree by inorder tree walk and preorder tree walk respectively.

The operation delete $k$ for deleting a given node $z$ containing key $k$ from $T$ can be implemented by an algorithm which considers the following cases:

If $z$ has no children, we modify its parent $z.p$ to replace $z$ with NIL as its child (delete $z$).

If $z$ has only a single child, we "splice out" $z$ by making a new link between its child and its parent.

If $z$ has two children, we splice out $z$'s successor $y$ and replace $z$'s key with $y$'s key.

Input

In the first line, the number of operations $m$ is given. In the following $m$ lines, operations represented by insert $k$, find $k$, delete $k$ or print are given.

Output

For each find $k$ operation, print "yes" if $T$ has a node containing $k$, "no" if not.

In addition, for each print operation, print a list of keys obtained by inorder tree walk and preorder tree walk in a line respectively. Put a space character before each key

Constraints

The number of operations $\leq 500,000$

The number of print operations $\leq 10$.

$-2,000,000,000 \leq key \leq 2,000,000,000$

The height of the binary tree does not exceed 100 if you employ the above pseudo code.

The keys in the binary search tree are all different.

Sample Input 1

18
insert 8
insert 2
insert 3
insert 7
insert 22
insert 1
find 1
find 2
find 3
find 4
find 5
find 6
find 7
find 8
print
delete 3
delete 7
print

Sample Output 1

yes
yes
yes
no
no
no
yes
yes
1 2 3 7 8 22
8 2 1 3 7 22
1 2 8 22
8 2 1 22

Reference

Introduction to Algorithms, Thomas H. Cormen, Charles E. Leiserson, Ronald L. Rivest, and Clifford Stein. The MIT Press.

Solution in JAVA (judge verdict: Wrong Answer)

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class Main {

  public static void main(String[] args) {
    
    new Main().run();
  }

  public void run() {

    try(BufferedReader br = new BufferedReader(new InputStreamReader(System.in))) {

      final int n = Integer.parseInt(br.readLine());
      String op;
      String[] words;
      Tree tree = new Tree();
      int t;

      for(int i=0,k=0; i<n; i++,k=0){
        words = br.readLine().split(" ");
        op  = words[k++];

        switch( op ) {
          case "insert" :
            tree.insert(Integer.parseInt(words[k]));
            break;
          case "find" :
            t = Integer.parseInt(words[k]);
            System.out.println( tree.find(t) ? "yes" : "no" );
            break;
          case "delete" :
            tree.delete(Integer.parseInt(words[k]));
            break;
          default :
            tree.dispRoundPath();
        }
      }

    }
    catch(IOException e) {
      System.out.println("IOException!");
    }
  }
}

class Tree {

  static final BTreeNode NIL = new BTreeNode(-1);
  BTreeNode root;
  StringBuilder buf;

  public Tree() {
    root = NIL;
    buf = new StringBuilder();
  }

  public void insert(int val) {
    BTreeNode y = NIL;
    BTreeNode x = root;
    BTreeNode z = new BTreeNode(val);

    while( !x.equals(NIL) ) {
      y = x;
      if( z.key < x.key )
        x = x.left;
      else
        x = x.right;
    }
    z.parent = y;

    if( y.equals(NIL) )
      root = z;
    else if( z.key < y.key )
      y.left = z;
    else
      y.right = z;
  }
  boolean find(int target) {
    BTreeNode x = root;

    while( !x.equals(NIL) ) {
      if( target == x.key )
        return true;
      else if( target < x.key )
        x = x.left;
      else
        x = x.right;
    }

    return false;
  }
  void delete(int target) {
    BTreeNode x = root;

    while( !x.equals(NIL) ) {
      if( target == x.key )
        break;
      else if( target < x.key )
        x = x.left;
      else
        x = x.right;
    }

    deleteNode(x);
  }
  void deleteNode(BTreeNode x) {

    if( x.left.equals(NIL) && x.right.equals(NIL) ) {
      int target = x.key;
      x = x.parent;
      if(x.left.key == target) x.left = NIL;
      else x.right = NIL;
    }
    else if( !x.left.equals(NIL) && !x.right.equals(NIL) ) {
      x.key = x.left.key;
      deleteNode(x.left);
    }
    else {
      int target = x.key;
      BTreeNode t;
      if( !x.left.equals(NIL)) t = x.left;
      else t = x.right;
      x = x.parent;

      if(x.left.key == target) x.left = t;
      else x.right = t;
    }
  }
  
  void preParse(BTreeNode u) {
    if( !u.equals(NIL) ) {
      buf.append(" ").append(u.key);
      preParse(u.left);
      preParse(u.right);
    }
  }
  void inParse(BTreeNode u) {
    if( !u.equals(NIL) ) {
      inParse(u.left);
      buf.append(" ").append(u.key);
      inParse(u.right);
    }
  }

  void dispRoundPath() {

    inParse(root);
    buf.append("\n");
    preParse(root);
    buf.append("\n");

    System.out.print(buf);
    buf.setLength(0);
  }
}

class BTreeNode {
  int key;
  BTreeNode parent,left,right;

  public BTreeNode(int key) {
    this.key = key;
    this.parent =
    this.left =
    this.right = Tree.NIL;
  }

  @Override
  public boolean equals(Object o) {
    if(o == this) return true;
    if(o == null) return false;
    if(!(o instanceof BTreeNode)) return false;

    BTreeNode node = (BTreeNode)o;
    if(!(this.key == node.key)) return false;

    return true;
  }
}