Problem:
Score : 700 points

Problem Statement

N cells are arranged in a row.
Some of them may contain tokens.
You are given a string s that consists of 0s and 1s.
If the i-th character of s is 1, the i-th cell (from left) contains a token.
Otherwise, it doesn't contain a token.

Snuke wants to perform the following operation as many times as possible.
In each operation, he chooses three consecutive cells.
Let's call the cells X, Y, Z from left to right.
In order for the operation to be valid, both X and Z must contain tokens and Y must not contain a token.
Then, he removes these two tokens and puts a new token on Y.

How many operations can he perform if he performs operations in the optimal way?

Constraints

1 \leq N \leq 500,000

|s| = N

Each character in s is either 0 or 1.

Input

Input is given from Standard Input in the following format:

N
s

Output

Print the answer.

Sample Input 1

7
1010101

Sample Output 1

2

For example, he can perform two operations in the following way:

Perform an operation on the last three cells. Now the string that represents tokens becomes 1010010.

Perform an operation on the first three cells. Now the string that represents tokens becomes 0100010.

Note that the choice of operations matters.
For example, if he chooses three cells in the middle first, he can perform no more operations.

Sample Input 2

50
10101000010011011110001001111110000101010111100110

Sample Output 2

10

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.StringTokenizer;
import java.io.IOException;
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.InputStream;

/**
 * Built using CHelper plug-in
 * Actual solution is at the top
 */
public class Main {
    public static void main(String[] args) {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        InputReader in = new InputReader(inputStream);
        PrintWriter out = new PrintWriter(outputStream);
        TaskD solver = new TaskD();
        solver.solve(1, in, out);
        out.close();
    }

    static class TaskD {
        public void solve(int testNumber, InputReader in, PrintWriter out) {
            int N = in.nextInt();
            char[] str = in.next().toCharArray();

            int left = 0, right = N - 1;
            int ans = 0;
            while (left < right) {
                TaskD.Chunk leftChunk = findLeft(left, str);
                TaskD.Chunk rightChunk = findRight(right, str);

                if (leftChunk != null && rightChunk != null) {
                    if (leftChunk.len > rightChunk.len) {
                        ans += leftChunk.len - 2;
                        left = leftChunk.end + 2;
                    } else {
                        ans += rightChunk.len - 2;
                        right = rightChunk.start - 2;
                    }
                } else if (leftChunk != null) {
                    ans += leftChunk.len - 2;
                    left = leftChunk.end + 2;
                } else if (rightChunk != null) {
                    ans += rightChunk.len - 2;
                    right = rightChunk.start - 2;
                } else {
                    break;
                }
            }
            out.println(ans);
        }

        private TaskD.Chunk findRight(int right, char[] str) {
            int N = str.length;
            for (int i = right - 1; i > 0; i--) {
                if (str[i - 1] == '1' && str[i] == '0' && str[i + 1] == '1') {
                    int onesEnd = i + 1;
                    while (onesEnd + 1 <= right && str[onesEnd + 1] == '1') {
                        onesEnd++;
                    }
                    return new TaskD.Chunk(i - 1, onesEnd);
                }
            }
            return null;
        }

        private TaskD.Chunk findLeft(int left, char[] str) {
            int N = str.length;
            for (int i = left + 1; i < N - 1; i++) {
                if (str[i - 1] == '1' && str[i] == '0' && str[i + 1] == '1') {
                    int onesStart = i - 1;
                    while (onesStart - 1 >= left && str[onesStart - 1] == '1') {
                        onesStart--;
                    }
                    return new TaskD.Chunk(onesStart, i + 1);
                }
            }
            return null;
        }

        static class Chunk {
            int start;
            int end;
            int len;

            public Chunk(int start, int end) {
                this.start = start;
                this.end = end;
                this.len = end - start + 1;
            }

        }

    }

    static class InputReader {
        public BufferedReader reader;
        public StringTokenizer tokenizer;

        public InputReader(InputStream stream) {
            reader = new BufferedReader(new InputStreamReader(stream), 32768);
            tokenizer = null;
        }

        public String next() {
            while (tokenizer == null || !tokenizer.hasMoreTokens()) {
                try {
                    tokenizer = new StringTokenizer(reader.readLine());
                } catch (IOException e) {
                    throw new RuntimeException(e);
                }
            }
            return tokenizer.nextToken();
        }

        public int nextInt() {
            return Integer.parseInt(next());
        }

    }
}