Problem:
Score : 100 points

Problem Statement

You went shopping to buy cakes and donuts with X yen (the currency of Japan).

First, you bought one cake for A yen at a cake shop.
Then, you bought as many donuts as possible for B yen each, at a donut shop.

How much do you have left after shopping?

Constraints

1 \leq A, B \leq 1 000

A + B \leq X \leq 10 000

X, A and B are integers.

Input

Input is given from Standard Input in the following format:

X
A
B

Output

Print the amount you have left after shopping.

Sample Input 1

1234
150
100

Sample Output 1

84

You have 1234 - 150 = 1084 yen left after buying a cake.
With this amount, you can buy 10 donuts, after which you have 84 yen left.

Sample Input 2

1000
108
108

Sample Output 2

28

Sample Input 3

579
123
456

Sample Output 3

0

Sample Input 4

7477
549
593

Sample Output 4

405

Solution in Java (OpenJDK 11.0.6) (judge verdict: Runtime Error)

import java.util.*;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        byte A = Byte.parseByte(sc.next());
        byte B = Byte.parseByte(sc.next());
        byte C = Byte.parseByte(sc.next());
        short X = Short.parseShort(sc.next());

        int res = 0;
        for (int a = 0; a <= A; a++) {
            for (int b = 0; b <= B; b++) {
                int c = (X - a * 500 - b * 100) / 50;
                if (c >= 0 && c <= C)
                    res++;
            }
        }

        System.out.println(res);
    }
}