Problem:
Hit and Blow

Let's play Hit and Blow game. A imagines four numbers and B guesses the numbers. After B picks out four numbers, A answers:

The number of numbers which have the same place with numbers A imagined (Hit)

The number of numbers included (but different place) in the numbers A imagined (Blow)

For example, if A imagined numbers:

9 1 8 2

and B chose:

4 1 5 9

A should say 1 Hit and 1 Blow.

Write a program which reads four numbers A imagined and four numbers B chose and prints the number of Hit and Blow respectively. You may assume that the four numbers are all different and within from 0 to 9.

Input

The input consists of multiple datasets. Each dataset set consists of:

a1 a2 a3 a4
b1 b2 b3 b4

, where ai (0 ≤ ai ≤ 9) is i-th number A imagined and bi (0 ≤ bi ≤ 9) is i-th number B chose.

The input ends with EOF. The number of datasets is less than or equal to 50.

Output

For each dataset, print the number of Hit and Blow in a line. These two numbers should be separated by a space.

Sample Input

9 1 8 2
4 1 5 9
4 6 8 2
4 6 3 2

Output for the Sample Input

1 1
3 0

Solution in JAVA (judge verdict: Accepted)

import java.util.*;
import java.io.*;

class Main {

    public static void main(String[] args) {

	final Scanner stdin = new Scanner(System.in);

	while ( stdin.hasNextInt() ) {
	    int[] in = new int[4];
	    int[] think = new int[4];

	    for ( int j = 0; j < 4; j++ ) {
		in[j] = stdin.nextInt();
	    }
	    for ( int j = 0; j < 4; j++ ) {
		think[j] = stdin.nextInt();
	    }
	    
	    int hit = 0;
	    int brow = 0;
	    for ( int i = 0; i < 4; i++ ) {
		if ( in[i] == think[i] ) {
		    hit++;
		} else if ( contains( in[i], think ) ) {
		    brow++;
		}
	    }
	    System.out.printf( "%d %d\n", hit, brow );
	}	   
    }

    static boolean contains( int num, int[] array ) {
	for ( int i : array ) {
	    if ( num == i ) {
		return true;
	    }
	}
	return false;
    }
    
}