Problem:
Score : 200 points

Problem Statement

Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Constraints

1 \leq N \leq 10^5

Input

Input is given from Standard Input in the following format:

N

Output

Print the number of positive integers less than or equal to N that have an odd number of digits.

Sample Input 1

11

Sample Output 1

9

Among the positive integers less than or equal to 11, nine integers have an odd number of digits: 1, 2, \ldots, 9.

Sample Input 2

136

Sample Output 2

46

In addition to 1, 2, \ldots, 9, another 37 integers also have an odd number of digits: 100, 101, \ldots, 136.

Sample Input 3

100000

Sample Output 3

90909

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Scanner;

public class Main {

	
	public static void main(String[] args) {
		
		
		Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        	
				
		if(n<=9) {
			System.out.println(n);
		}else if(n<=99){
			System.out.println(9);
		}else if(n<=999) {
			System.out.println(n-90);
	    }else if(n<=9999) {
	    	System.out.println(909);
	    }else if(n<=99999) {
	    	System.out.println(n-9090);
	    }else{
	    	System.out.println(90909);
	    }
		
	}

}