Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.Scanner;

public class Main {
	public static void main(String[] args) {

		int[][] a = new int[3][3];
		int[] b = new int[10];
		boolean[][] match = new boolean[3][3];
		int n;
		boolean result = false;
		Scanner sc = new Scanner(System.in);

		for (int i = 0; i < 3; i++) {

			String arg1 = sc.nextLine();
			String[] column = arg1.split(" ");
			int[] ia = new int[column.length];

			for (int j = 0; j < column.length; j++) {
				ia[j] = Integer.parseInt(column[j]);
				a[i][j] = ia[j];
			}
		}

		n = sc.nextInt();

		for (int i = 0; i < n; i++) {
			b[i] = sc.nextInt();
		}

		for (int i = 0; i < a.length; i++) {
			for (int j = 0; j < a[i].length; j++) {

				match[i][j] = false;

				for (int k = 0; k < b.length; k++) {
					if (a[i][j] == b[k]) {
						match[i][j] = true;
					}
				}

			}
		}

		for (int i = 0; i < 3; i++) {
			if (match[i][0] && match[i][1] && match[i][2]) {
				result = true;
			}
		}

		for (int i = 0; i < 3; i++) {
			if (match[0][i] && match[1][i] && match[0][i]) {
				result = true;
			}
		}

		if (match[0][0] && match[1][1] && match[2][2]) {
			result = true;
		}
		if (match[0][2] && match[1][1] && match[2][0]) {
			result = true;
		}

		System.out.println(result ? "Yes" : "No");

		sc.close();

	}
}