Problem:
Search II

You are given a sequence of n integers S and a sequence of different q integers T. Write a program which outputs C, the number of integers in T which are also in the set S.

Input

In the first line n is given. In the second line, n integers are given. In the third line q is given. Then, in the fourth line, q integers are given.

Output

Print C in a line.

Constraints

Elements in S is sorted in ascending order

n ≤ 100000

q ≤ 50000

0 ≤ an element in S ≤ 109

0 ≤ an element in T ≤ 109

Sample Input 1

5
1 2 3 4 5
3
3 4 1

Sample Output 1

3

Sample Input 2

3
1 2 3
1
5

Sample Output 2

0

Sample Input 3

5
1 1 2 2 3
2
1 2

Sample Output 3

2

Notes

Solution in JAVA (judge verdict: Accepted)

import java.io.*;
import java.util.*;
import static java.lang.System.*;

public class Main {
	static FastScanner sc = new FastScanner(System.in);
	public static void main(String[] args) {
		int n = sc.nextInt();
		int[] ar = new int[n];
		for (int i=0; i<n; i++) {ar[i] = sc.nextInt();}
		Arrays.sort(ar);
		int m = sc.nextInt();
		int total = 0;
		for (int i=0; i<m; i++) {
			if (Arrays.binarySearch(ar,sc.nextInt()) >= 0) {total++;}
		}
		out.println(total);
	}
}



class FastScanner implements Closeable {
	private final InputStream in;
	private final byte[] buffer = new byte[1024];
	private int ptr = 0;
	private int buflen = 0;
	public FastScanner(InputStream in) {this.in = in;}
	private boolean hasNextByte() {
		if (ptr < buflen) {return true;}
		else{
			ptr = 0;
			try {buflen = in.read(buffer);}
			catch (IOException e) {e.printStackTrace();}
			if (buflen <= 0) {return false;}
		}
		return true;
	}
	private int readByte() { if (hasNextByte()) return buffer[ptr++]; else return -1;}
	private static boolean isPrintableChar(int c) { return 33 <= c && c <= 126;}
	public boolean hasNext() { while(hasNextByte() && !isPrintableChar(buffer[ptr])) ptr++; return hasNextByte();}
	public String next() {
		if (!hasNext()) throw new NoSuchElementException();
		StringBuilder sb = new StringBuilder();
		int b = readByte();
		while(isPrintableChar(b)) {
			sb.appendCodePoint(b);
			b = readByte();
		}
		return sb.toString();
	}
	public long nextLong() {
		if (!hasNext()) throw new NoSuchElementException();
		long n = 0;
		boolean minus = false;
		int b = readByte();
		if (b == '-') {
			minus = true;
			b = readByte();
		}
		if (b < '0' || '9' < b) {throw new NumberFormatException();}
		while(true){
			if ('0' <= b && b <= '9') {
				n *= 10;
				n += b - '0';
			}else if(b == -1 || !isPrintableChar(b)){return minus ? -n : n;}
			else{throw new NumberFormatException();}
			b = readByte();
		}
	}
	public int nextInt() {
		long nl = nextLong();
		if (nl < Integer.MIN_VALUE || nl > Integer.MAX_VALUE) throw new NumberFormatException();
		return (int) nl;
	}
	public double nextDouble() { return Double.parseDouble(next());}
	public void close() {
		try {in.close();}
		catch (IOException e) {}
	}
}