Problem:
Score : 400 points

Problem Statement

You are given N items.

The value of the i-th item (1 \leq i \leq N) is v_i.

Your have to select at least A and at most B of these items.

Under this condition, find the maximum possible arithmetic mean of the values of selected items.

Additionally, find the number of ways to select items so that the mean of the values of selected items is maximized.

Constraints

1 \leq N \leq 50

1 \leq A,B \leq N

1 \leq v_i \leq 10^{15}

Each v_i is an integer.

Input

The input is given from Standard Input in the following format:

N A B
v_1
v_2
...
v_N

Output

Print two lines.

The first line should contain the maximum possible arithmetic mean of the values of selected items. The output should be considered correct if the absolute or relative error is at most 10^{-6}.

The second line should contain the number of ways to select items so that the mean of the values of selected items is maximized.

Sample Input 1

5 2 2
1 2 3 4 5

Sample Output 1

4.500000
1

The mean of the values of selected items will be maximized when selecting the fourth and fifth items. Hence, the first line of the output should contain 4.5.

There is no other way to select items so that the mean of the values will be 4.5, and thus the second line of the output should contain 1.

Sample Input 2

4 2 3
10 20 10 10

Sample Output 2

15.000000
3

There can be multiple ways to select items so that the mean of the values will be maximized.

Sample Input 3

5 1 5
1000000000000000 999999999999999 999999999999998 999999999999997 999999999999996

Sample Output 3

1000000000000000.000000
1

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.io.*;
import java.util.*;

public class Main {
		
	public static void main(String[] args) throws IOException {
		FastScanner sc = new FastScanner(System.in);
		
		int N = sc.nextInt();
		int A = sc.nextInt();
		int B = sc.nextInt();
		
		int MAX = N+1;
		long[][] C = new long[MAX][MAX];
		C[0][0] = 1;
		for (int i = 1; i < C.length; ++i) {
			C[i][0] = 1;
			for (int j = 1; j < C[i].length; ++j) {
				C[i][j] = C[i - 1][j] + C[i - 1][j - 1];
			}
		}
		
		long[] v = new long[N];
		boolean all = true;
		for(int i = 0; i < N; i++){
			v[i] = sc.nextLong();
			if(v[i] != v[0]) all = false; 
		}
		
		if(all){
			System.out.println(v[0]);
			long count = 0;
			for(int i = A; i <= B; i++)
				count += C[N][i];
			System.out.println(count);
			return;
		}
		
		Arrays.sort(v);
		long maxSum = 0;
		int maxLen = A;
		for(int i = 1; i <= maxLen; i++)
			maxSum += v[N-i];
		double maxAvg = 1.0 * maxSum / A;
		System.out.println(maxAvg);
		
		long last = v[v.length-maxLen];
		int numAll = 0;
		int numSelect = 0;
		for(int i = 1; i <= N; i++){
			if(v[N-i] == last) numAll++;
			if(v[N-i] == last && i <= A) numSelect++;
		}
		System.out.println(C[numAll][numSelect]);
		
	}//end main
	
	public static void comb(){
		int MAX = 51;
		long[][] C = new long[MAX][MAX];
		C[0][0] = 1;
		for (int i = 1; i < C.length; ++i) {
			C[i][0] = 1;
			for (int j = 1; j < C[i].length; ++j) {
				C[i][j] = C[i - 1][j] + C[i - 1][j - 1];
			}
		}
	}
	
}//end Main

class FastScanner {
    private InputStream in;
    private final byte[] buffer = new byte[1024];
    private int ptr = 0;
    private int buflen = 0;
    public FastScanner(InputStream in) {
		this.in = in;
	}
    private boolean hasNextByte() {
        if (ptr < buflen) {
            return true;
        }else{
            ptr = 0;
            try {
                buflen = in.read(buffer);
            } catch (IOException e) {
                e.printStackTrace();
            }
            if (buflen <= 0) {
                return false;
            }
        }
        return true;
    }
    private int readByte() {
    	if (hasNextByte()) return buffer[ptr++];
    	else return -1;
    }
    private static boolean isPrintableChar(int c){
    	return 33 <= c && c <= 126;
    }
    public boolean hasNext() {
    	while(hasNextByte() && !isPrintableChar(buffer[ptr]))
    		ptr++; return hasNextByte();
    }
    public String next() {
        if (!hasNext()) throw new NoSuchElementException();
        StringBuilder sb = new StringBuilder();
        int b = readByte();
        while(isPrintableChar(b)) {
            sb.appendCodePoint(b);
            b = readByte();
        }
        return sb.toString();
    }
    public long nextLong() {
        if (!hasNext()) throw new NoSuchElementException();
        long n = 0;
        boolean minus = false;
        int b = readByte();
        if (b == '-') {
            minus = true;
            b = readByte();
        }
        if (b < '0' || '9' < b) {
            throw new NumberFormatException();
        }
        while(true){
            if ('0' <= b && b <= '9') {
                n *= 10;
                n += b - '0';
            }else if(b == -1 || !isPrintableChar(b)){
                return minus ? -n : n;
            }else{
                throw new NumberFormatException();
            }
            b = readByte();
        }
    }
    public int nextInt() {
        long nl = nextLong();
        if (nl < Integer.MIN_VALUE || nl > Integer.MAX_VALUE) throw new NumberFormatException();
        return (int) nl;
    }
    public double nextDouble() {
    	return Double.parseDouble(next());
    }
}