Problem:
Score : 400 points

Problem Statement

We have a grid with H rows and W columns of squares.
Snuke is painting these squares in colors 1, 2, ..., N.
Here, the following conditions should be satisfied:

For each i (1 ≤ i ≤ N), there are exactly a_i squares painted in Color i. Here, a_1 + a_2 + ... + a_N = H W.

For each i (1 ≤ i ≤ N), the squares painted in Color i are 4-connected. That is, every square painted in Color i can be reached from every square painted in Color i by repeatedly traveling to a horizontally or vertically adjacent square painted in Color i.

Find a way to paint the squares so that the conditions are satisfied.
It can be shown that a solution always exists.

Constraints

1 ≤ H, W ≤ 100

1 ≤ N ≤ H W

a_i ≥ 1

a_1 + a_2 + ... + a_N = H W

Input

Input is given from Standard Input in the following format:

H W
N
a_1 a_2 ... a_N

Output

Print one way to paint the squares that satisfies the conditions.
Output in the following format:

c_{1 1} ... c_{1 W}
:
c_{H 1} ... c_{H W}

Here, c_{i j} is the color of the square at the i-th row from the top and j-th column from the left.

Sample Input 1

2 2
3
2 1 1

Sample Output 1

1 1
2 3

Below is an example of an invalid solution:

1 2
3 1

This is because the squares painted in Color 1 are not 4-connected.

Sample Input 2

3 5
5
1 2 3 4 5

Sample Output 2

1 4 4 4 3
2 5 4 5 3
2 5 5 5 3

Sample Input 3

1 1
1
1

Sample Output 3

1

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.*;

public class Main {
    public static void main(String[] args) throws Exception {
        Scanner sc = new Scanner(System.in);
        int h = sc.nextInt();
        int w = sc.nextInt();
        int n = sc.nextInt();
        String[][] ans = new String[h][w];
        int[] color = new int[n];
        for(int i = 0; i < n; i++){
            color[i] = sc.nextInt();
        }
        boolean isReverse = false;
        int nowx = 0;
        int nowy = 0;
        for(int i = 0; i < n; i++){
            while(color[i] > 0){
                ans[nowy][nowx] = String.valueOf((i+1));
                color[i]--;
                if(isReverse){
                    if(nowx == 0){
                        nowy++;
                        isReverse = false;
                    }else{
                        nowx--;
                    }
                }else{
                    if(nowx == w-1){
                        nowy++;
                        isReverse = true;
                    }else{
                        nowx++;
                    }
                }
            }
        }
        for(int i = 0; i < h; i++){
            for(int j = 0; j < w; j++){
                System.out.print(ans[i][j]+" ");
            }
            System.out.println();
        }
    }
}