Problem:
Score : 100 points

Problem Statement

You are given four digits N_1, N_2, N_3 and N_4. Determine if these can be arranged into the sequence of digits "1974".

Constraints

0 \leq N_1, N_2, N_3, N_4 \leq 9

N_1, N_2, N_3 and N_4 are integers.

Input

Input is given from Standard Input in the following format:

N_1 N_2 N_3 N_4

Output

If N_1, N_2, N_3 and N_4 can be arranged into the sequence of digits "1974", print YES; if they cannot, print NO.

Sample Input 1

1 7 9 4

Sample Output 1

YES

We can get 1974 by swapping N_2 and N_3.

Sample Input 2

1 9 7 4

Sample Output 2

YES

We already have 1974 before doing anything.

Sample Input 3

1 2 9 1

Sample Output 3

NO

Sample Input 4

4 9 0 8

Sample Output 4

NO

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Scanner;
import java.util.Arrays;
 
public class Main {
	public static void main(String[] args) {
		try(Scanner sc = new Scanner(System.in)){
			Integer bar[] = {1, 9, 7, 4};

			int in_bar[] = new int[4];

			for (int i=0; i<4; i++) {
				in_bar[i] = sc.nextInt();
			}
			
			int ok_count = 0;

			for (int i=0; i<4; i++) {
				for (int j=0; j<4; j++) {
					if (bar[i] == in_bar[j]) {
						ok_count++;
						break;
					}
				}
			}
			
			if (ok_count == 4) {
				System.out.println("YES");
			} else {
				System.out.println("NO");
			}

		}
	}
}