Problem:
Score : 200 points

Problem Statement

Determine if an N-sided polygon (not necessarily convex) with sides of length L_1, L_2, ..., L_N can be drawn in a two-dimensional plane.

You can use the following theorem:

Theorem: an N-sided polygon satisfying the condition can be drawn if and only if the longest side is strictly shorter than the sum of the lengths of the other N-1 sides.

Constraints

All values in input are integers.

3 \leq N \leq 10

1 \leq L_i \leq 100

Input

Input is given from Standard Input in the following format:

N
L_1 L_2 ... L_N

Output

If an N-sided polygon satisfying the condition can be drawn, print Yes; otherwise, print No.

Sample Input 1

4
3 8 5 1

Sample Output 1

Yes

Since 8 < 9 = 3 + 5 + 1, it follows from the theorem that such a polygon can be drawn on a plane.

Sample Input 2

4
3 8 4 1

Sample Output 2

No

Since 8 \geq 8 = 3 + 4 + 1, it follows from the theorem that such a polygon cannot be drawn on a plane.

Sample Input 3

10
1 8 10 5 8 12 34 100 11 3

Sample Output 3

No

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Runtime Error)

package com.example.demo;

import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;
public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int N = sc.nextInt();
        List<Integer> L = new ArrayList<>();
        for(int i = 0; i < N;i++) {
            int num = sc.nextInt();
            L.add(num);
        }
        int max = L.get(0);
        //		リスト内の最大値をとる
        for (int i = 1; i <L.size(); i++) {
            int v = L.get(i);
            if (v > max) {
                max = v;
            }
        }

        //		System.out.println(max);
        //		System.out.println(sum);
        int sum = 0;
        for(int i = 0; i < L.size();i++) {
            sum = sum + L.get(i);
        }
        sum = sum - max;
        if(sum > max) {
            System.out.println("Yes");
        }else {
            System.out.println("No");
        }
        //		System.out.println(sum);
        //		System.out.println(max);
        //		System.out.println(L);
        //		String A = sc.next();
        //1 8 10 5 8 12 34 100 11 3
        //		double answer = T/X;
        //
        //		 String str = BigDecimal.valueOf(answer).toPlainString();
        //
        //
        //		 System.out.println(answer);
    }
}