Problem:
Score : 200 points

Problem Statement

Takahashi has many red balls and blue balls. Now, he will place them in a row.

Initially, there is no ball placed.

Takahashi, who is very patient, will do the following operation 10^{100} times:

Place A blue balls at the end of the row of balls already placed. Then, place B red balls at the end of the row.

How many blue balls will be there among the first N balls in the row of balls made this way?

Constraints

1 \leq N \leq 10^{18}

A, B \geq 0

0 < A + B \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N A B

Output

Print the number of blue balls that will be there among the first N balls in the row of balls.

Sample Input 1

8 3 4

Sample Output 1

4

Let b denote a blue ball, and r denote a red ball. The first eight balls in the row will be bbbrrrrb, among which there are four blue balls.

Sample Input 2

8 0 4

Sample Output 2

0

He placed only red balls from the beginning.

Sample Input 3

6 2 4

Sample Output 3

2

Among bbrrrr, there are two blue balls.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Runtime Error)

import java.util.*;
 public class Main
{ public static void main(String args[])
  { Scanner sc=new Scanner (System.in);
   int n=sc.nextInt();int s=0;int f=0;
   int b=sc.nextInt();int i=1;
   int r=sc.nextInt();
   while(n>s)
   {for(i=1;i<=b;i++)
       { if(n>s)
           s=s+1;
         else
         break;
        }if(b==0)
         f=0;
         else
        f=f+i-1;
        for(i=1;i<=r;i++)
        { if(n>s)
            s=s+1;
            else
            break;
        }
        
   }
   System.out.println(f);
}
}