Problem:
Score : 500 points

Problem Statement

We have N bulbs arranged on a number line, numbered 1 to N from left to right.
Bulb i is at coordinate i.

Each bulb has a non-negative integer parameter called intensity.
When there is a bulb of intensity d at coordinate x, the bulb illuminates the segment from coordinate x-d-0.5 to x+d+0.5.
Initially, the intensity of Bulb i is A_i. We will now do the following operation K times in a row:

For each integer i between 1 and N (inclusive), let B_i be the number of bulbs illuminating coordinate i. Then, change the intensity of each bulb i to B_i.

Find the intensity of each bulb after the K operations.

Constraints

1 \leq N \leq 2 \times 10^5

1 \leq K \leq 2 \times 10^5

0 \leq A_i \leq N

Input

Input is given from Standard Input in the following format:

N K
A_1 A_2 \ldots A_N

Output

Print the intensity A{'}_i of each bulb i after the K operations to Standard Output in the following format:

A{'}_1 A{'}_2 \ldots A{'}_N

Sample Input 1

5 1
1 0 0 1 0

Sample Output 1

1 2 2 1 2

Initially, only Bulb 1 illuminates coordinate 1, so the intensity of Bulb 1 becomes 1 after the operation.
Similarly, the bulbs initially illuminating coordinate 2 are Bulb 1 and 2, so the intensity of Bulb 2 becomes 2.

Sample Input 2

5 2
1 0 0 1 0

Sample Output 2

3 3 4 4 3

Solution in Java (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.io.PrintWriter;
import java.util.*;

public class Main {
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		PrintWriter pw = new PrintWriter(System.out);
		
		int N = sc.nextInt();
		int K = sc.nextInt();
		int[] A = new int[N];
		
		for(int i=0; i<N; i++)
			A[i] = sc.nextInt();

		int[] d = new int[N+1];
		
		for(int i=0; i<K; i++) {
			Arrays.fill(d, 0);
			for(int j=0; j<N; j++) {
				d[Math.max(j-A[j], 0)]++;
				d[Math.min(j+A[j]+1, N)]--;
			}
			int cur = 0;
			for(int j=0; j<N; j++) {
				cur += d[j];
				A[j] = cur;
			}
			if(d[0]==N && d[N]==-N)
				break;
		}
		
		for(int i=0; i<N; i++)
			pw.print(A[i] + (i==N-1 ? "\n" : " "));
		
		sc.close();
		pw.close();
	}
}