Problem:
Score : 200 points

Problem Statement

When Mr. X is away from home, he has decided to use his smartwatch to search the best route to go back home, to participate in ABC.

You, the smartwatch, has found N routes to his home.

If Mr. X uses the i-th of these routes, he will get home in time t_i at cost c_i.

Find the smallest cost of a route that takes not longer than time T.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq T \leq 1000

1 \leq c_i \leq 1000

1 \leq t_i \leq 1000

The pairs (c_i, t_i) are distinct.

Input

Input is given from Standard Input in the following format:

N T
c_1 t_1
c_2 t_2
:
c_N t_N

Output

Print the smallest cost of a route that takes not longer than time T.

If there is no route that takes not longer than time T, print TLE instead.

Sample Input 1

3 70
7 60
1 80
4 50

Sample Output 1

4

The first route gets him home at cost 7.

The second route takes longer than time T = 70.

The third route gets him home at cost 4.

Thus, the cost 4 of the third route is the minimum.

Sample Input 2

4 3
1 1000
2 4
3 1000
4 500

Sample Output 2

TLE

There is no route that takes not longer than time T = 3.

Sample Input 3

5 9
25 8
5 9
4 10
1000 1000
6 1

Sample Output 3

5

Solution in Java7 (OpenJDK 1.7.0) (judge verdict: Accepted)

import java.util.*;
import java.io.*;
 class Main{
public static void main(String[] args)throws IOException {
    FastReader in=new FastReader(System.in);
    int n=in.nextInt();
    int t=in.nextInt();
    int arr[][]=new int[n][2];
    int f=-1,i,max=1001;
    for(i=0;i<n;i++)
    {
        arr[i][0]=in.nextInt();
        arr[i][1]=in.nextInt();
        if(arr[i][1]<=t)
        {
            if(arr[i][0]<max)
            max=arr[i][0];
            f=1;
        }
    }
    if(f==-1)
    System.out.println("TLE");
    else
    System.out.println(max);
}
}
class FastReader {
 
    byte[] buf = new byte[2048];
    int index, total;
    InputStream in;
 
    FastReader(InputStream is) {
        in = is;
    }
 
    int scan() throws IOException {
        if (index >= total) {
            index = 0;
            total = in.read(buf);
            if (total <= 0) {
                return -1;
            }
        }
        return buf[index++];
    }
 
    String next() throws IOException {
        int c;
        for (c = scan(); c <= 32; c = scan());
        StringBuilder sb = new StringBuilder();
        for (; c > 32; c = scan()) {
            sb.append((char) c);
        }
        return sb.toString();
    }
    String nextLine() throws IOException {
        int c;
        for (c = scan(); c <= 32; c = scan());
        StringBuilder sb = new StringBuilder();
        for (; c !=10; c = scan()) {
            sb.append((char) c);
        }
        return sb.toString();
    }
    char nextChar() throws IOException{
        int c;
         for (c = scan(); c <= 32; c = scan());
         return (char)c;
        }
 
    int nextInt() throws IOException {
        int c, val = 0;
        for (c = scan(); c <= 32; c = scan());
        boolean neg = c == '-';
        if (c == '-' || c == '+') {
            c = scan();
        }
        for (; c >= '0' && c <= '9'; c = scan()) {
            val = (val << 3) + (val << 1) + (c & 15);
        }
        return neg ? -val : val;
    }
 
    long nextLong() throws IOException {
        int c;
        long val = 0;
        for (c = scan(); c <= 32; c = scan());
        boolean neg = c == '-';
        if (c == '-' || c == '+') {
            c = scan();
        }
        for (; c >= '0' && c <= '9'; c = scan()) {
            val = (val << 3) + (val << 1) + (c & 15);
        }
        return neg ? -val : val;
    }
}