Problem:
Bubble Sort

Write a program of the Bubble Sort algorithm which sorts a sequence A in ascending order. The algorithm should be based on the following pseudocode:

BubbleSort(A)
1 for i = 0 to A.length-1
2 for j = A.length-1 downto i+1
3 if A[j] < A[j-1]
4 swap A[j] and A[j-1]

Note that, indices for array elements are based on 0-origin.

Your program should also print the number of swap operations defined in line 4 of the pseudocode.

Input

The first line of the input includes an integer N, the number of elements in the sequence.

In the second line, N elements of the sequence are given separated by spaces characters.

Output

The output consists of 2 lines.

In the first line, please print the sorted sequence. Two contiguous elements of the sequence should be separated by a space character.

In the second line, please print the number of swap operations.

Constraints

1 ≤ N ≤ 100

Sample Input 1

5
5 3 2 4 1

Sample Output 1

1 2 3 4 5
8

Sample Input 2

6
5 2 4 6 1 3

Sample Output 2

1 2 3 4 5 6
9

Solution in JAVA (judge verdict: Accepted)

import java.util.Scanner;

public class Main {
	public static Scanner sc;
	
	public static void main(String[] args) {
		//宣言
		int N=0;
		int A[]= new int[300];
		sc = new Scanner(System.in);
		int count=0;
		//入力
		N= sc.nextInt();
		for(int i=0;i<N;i++) {
			A[i]=sc.nextInt();
		}
		//出力
		for(int j=0;j<N;j++) {
			for(int i=N-1;i>=j+1;i--) {
				if(A[i]<A[i-1]) {
					int w = A[i];
					A[i]=A[i-1];
					A[i-1]=w;
					count++;
				}
			}	
		}
		for(int i=0;i<N;i++) {
			if(i>=0 &&i<N-1) {
				System.out.print(A[i]+" ");
			}else if(i==N-1) {
				System.out.println(A[i]);
			}
		}
		System.out.println(count);
	}
}