Problem:
Priority Queue

Priority queue is a container of elements which the element with the highest priority should be extracted first.

For $n$ priority queues $Q_i$ ($i = 0, 1, ..., n-1$) of integers, perform a sequence of the following operations.

insert($t$, $x$): Insert $x$ to $Q_t$.

getMax($t$): Report the maximum value in $Q_t$. If $Q_t$ is empty, do nothing.

deleteMax($t$): Delete the maximum element from $Q_t$. If $Q_t$ is empty, do nothing.

In the initial state, all queues are empty.

Input

The input is given in the following format.

$n \; q$
$query_1$
$query_2$
:
$query_q$

Each query $query_i$ is given by

0 $t$ $x$

or

1 $t$

or

2 $t$

where the first digits 0, 1 and 2 represent insert, getMax and deleteMax operations respectively.

Output

For each getMax operation, print an integer in a line.

Constraints

$1 \leq n \leq 1,000$

$1 \leq q \leq 200,000$

$-1,000,000,000 \leq x \leq 1,000,000,000$

Sample Input 1

2 10
0 0 3
0 0 9
0 0 1
1 0
2 0
1 0
0 0 4
1 0
0 1 8
1 1

Sample Output 1

9
3
4
8

Solution in JAVA (judge verdict: Accepted)

import java.util.ArrayList;
import java.util.Comparator;
import java.util.List;
import java.util.PriorityQueue;
import java.util.Queue;

import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		// TODO 自動生成されたメソッド・スタブ
		Scanner sc = new Scanner(System.in);
		int n = sc.nextInt();
		int q = sc.nextInt();

		List<Queue<Integer>> queueList = new ArrayList<Queue<Integer>>();
		for(int i = 0; i < n; i++) {
			queueList.add(new PriorityQueue<Integer>(Comparator.reverseOrder()));
		}

		for(int i = 0; i < q; i++)	{
			int query = sc.nextInt();
			int t = sc.nextInt();

			switch(query){
			case 0:
				int x = sc.nextInt();
				queueList.get(t).add(x);
				break;

			case 1:  //getMax(t)
				if(!(queueList.get(t).isEmpty())) System.out.println(queueList.get(t).peek());
				break;

			case 2:  //deleteMax(t)
				if(!(queueList.get(t).isEmpty())) queueList.get(t).poll();
				break;
			}
		}
	}

}