Problem:
Standard Deviation

You have final scores of an examination for n students. Calculate standard deviation of the scores s1, s2 ... sn.

The variance α2 is defined by

α2 = (∑ni=1(si - m)2)/n

where m is an average of si.

The standard deviation of the scores is the square root of their variance.

Input

The input consists of multiple datasets. Each dataset is given in the following format:

n
s1 s2 ... sn

The input ends with single zero for n.

Output

For each dataset, print the standard deviation in a line. The output should not contain an absolute error greater than 10-4.

Constraints

n ≤ 1000

0 ≤ si ≤ 100

Sample Input

5
70 80 100 90 20
3
80 80 80
0

Sample Output

27.85677655
0.00000000

Solution in JAVA (judge verdict: Accepted)

import java.util.Scanner;

public class Main {
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		int[] tokuten;
		int kazu = 0;
		double average = 0;
		double hensa2 =0.0;
		double bunsan;
		while (true){
			kazu = sc.nextInt();
			if(0==kazu) break;
			tokuten = new int[kazu];
			for(int i=0;i<tokuten.length;i++){
				tokuten[i]=sc.nextInt();
				//System.out.println();
				//System.out.println(tokuten[i]);
				average += (double)tokuten[i]/tokuten.length;
			}
			//System.out.println("average = "+average);
			for(int i=0;i<tokuten.length;i++){
				hensa2 += (tokuten[i]-average)*(tokuten[i]-average);
				//System.out.println("hensa2[0~"+i+"] = "+hensa2);
			}
			bunsan=hensa2/tokuten.length;
			//System.out.println("bunsan = "+bunsan);
			System.out.println(Math.sqrt(bunsan));

			/* 初期化 */
			average = 0;
			hensa2 = 0;
			kazu =0;
		}
	}
}