Problem:
Score : 400 points

Problem Statement

Given is an integer S.
Find a combination of six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfies all of the following conditions:

0 \leq X_1,Y_1,X_2,Y_2,X_3,Y_3 \leq 10^9

The area of the triangle in a two-dimensional plane whose vertices are (X_1,Y_1),(X_2,Y_2), and (X_3,Y_3) is S/2.

We can prove that there always exist six integers that satisfy the conditions under the constraints of this problem.

Constraints

1 \leq S \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

S

Output

Print six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfy the conditions, in this order, with spaces in between.
If multiple solutions exist, any of them will be accepted.

Sample Input 1

3

Sample Output 1

1 0 2 2 0 1

The area of the triangle in a two-dimensional plane whose vertices are (1,0),(2,2), and (0,1) is 3/2.
Printing 3 0 3 1 0 1 or 1 0 0 1 2 2 will also be accepted.

Sample Input 2

100

Sample Output 2

0 0 10 0 0 10

Sample Input 3

311114770564041497

Sample Output 3

314159265 358979323 846264338 327950288 419716939 937510582

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Runtime Error)

import java.util.*;

class Main{
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        String s = sc.next();
        long k = sc.nextLong();
        char[] div = s.toCharArray();
        long ans = 0;
        
        if(s.charAt(0) == s.charAt(s.length()-1)){
            ans = 1;
            div[s.length()-1] = '0';
        }
        for(int i = 1;i < s.length();i += 2){
            if((div[i-1] == div[i] && div[i] == div[i+1])||(div[i-1] == div[i+1])){
                div[i-1] = '1';
                div[i+1] = '2';
                ans +=2;
            }else if(div[i-1] == div[i]){
                div[i+1] = '3';
                ans++;
            }else if(div[i] == div[i+1]){
                div[i+1] = '4';
                ans++;
            }
        }
        if(s.length()%2 == 0){
            if(div[s.length()-1] == div[s.length()-2]){
                ans++;
            }
        }
      System.out.println("ansの値："+ans);
        ans *= k;
      

        System.out.println(ans);
    }
}