Problem:
Score : 200 points

Problem Statement

You are given string S and T consisting of lowercase English letters.

Determine if S equals T after rotation.

That is, determine if S equals T after the following operation is performed some number of times:

Operation: Let S = S_1 S_2 ... S_{|S|}. Change S to S_{|S|} S_1 S_2 ... S_{|S|-1}.

Here, |X| denotes the length of the string X.

Constraints

2 \leq |S| \leq 100

|S| = |T|

S and T consist of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S equals T after rotation, print Yes; if it does not, print No.

Sample Input 1

kyoto
tokyo

Sample Output 1

Yes

In the first operation, kyoto becomes okyot.

In the second operation, okyot becomes tokyo.

Sample Input 2

abc
arc

Sample Output 2

No

abc does not equal arc after any number of operations.

Sample Input 3

aaaaaaaaaaaaaaab
aaaaaaaaaaaaaaab

Sample Output 3

Yes

Solution in Java7 (OpenJDK 1.7.0) (judge verdict: Accepted)

import java.util.*;

public class Main {
    public static void main(String[] args) {
        Scanner sc=new Scanner(System.in);
        String s1=sc.next();
        String s2=sc.next();
        int a=0;
        for(int l=0;l<s1.length();l++){
            char[] c1=s1.toCharArray();
            if(!s1.equals(s2)){
                //System.out.println("A");
                char ch=c1[s1.length()-1];
                for(int i=s1.length()-1;i>0;i--){
                    c1[i]=c1[i-1];
                }
                c1[0]=ch;
                s1=String.valueOf(c1);
            }
            else{
                a=1;
                break;
            }
        }
        if(a==1){
            System.out.println("Yes");
        }    
        else{
            System.out.println("No");
        }
    }
}