Problem:
Score : 400 points

Problem Statement

Given is a positive integer N.

Find the number of pairs (A, B) of positive integers not greater than N that satisfy the following condition:

When A and B are written in base ten without leading zeros, the last digit of A is equal to the first digit of B, and the first digit of A is equal to the last digit of B.

Constraints

1 \leq N \leq 2 \times 10^5

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N

Output

Print the answer.

Sample Input 1

25

Sample Output 1

17

The following 17 pairs satisfy the condition: (1,1), (1,11), (2,2), (2,22), (3,3), (4,4), (5,5), (6,6), (7,7), (8,8), (9,9), (11,1), (11,11), (12,21), (21,12), (22,2), and (22,22).

Sample Input 2

1

Sample Output 2

1

Sample Input 3

100

Sample Output 3

108

Sample Input 4

2020

Sample Output 4

40812

Sample Input 5

200000

Sample Output 5

400000008

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Runtime Error)

import java.util.Scanner;

public class Main{
     void main(String[] args){
	Scanner sc = new Scanner(System.in);
	int N = sc.nextInt();
	int count = 0;
	for(int A=1;A<=N;A++){
	    for(int B=1;B<=N;B++){
		String a = Integer.toString(A);
		String b = Integer.toString(B);
		if(a.charAt(0) == b.charAt(b.length()-1) &&
		   a.charAt(a.length()-1) == b.charAt(0) ){
		    count++;
		}
	    }
	}
	System.out.print(count);
    }
}