Problem:
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Transformation

Write a program which performs a sequence of commands to a given string $str$. The command is one of:

print a b: print from the a-th character to the b-th character of $str$

reverse a b: reverse from the a-th character to the b-th character of $str$

replace a b p: replace from the a-th character to the b-th character of $str$ with p

Note that the indices of $str$ start with 0.

Input

In the first line, a string $str$ is given. $str$ consists of lowercase letters. In the second line, the number of commands q is given. In the next q lines, each command is given in the above mentioned format.

Output

For each print command, print a string in a line.

Constraints

$1 \leq $ length of $str \leq 1000$

$1 \leq q \leq 100$

$0 \leq a \leq b < $ length of $str$

for replace command, $b - a + 1 = $ length of $p$

Sample Input 1

abcde
3
replace 1 3 xyz
reverse 0 2
print 1 4

Sample Output 1

xaze

Sample Input 2

xyz
3
print 0 2
replace 0 2 abc
print 0 2

Sample Output 2

xyz
abc

Solution in JAVA (judge verdict: Accepted)

import java.util.Scanner;
public class Main {

	

	public static void main(String[] args) {
		Scanner stdIn = new Scanner(System.in);
		String str = stdIn.next();
		int q = stdIn.nextInt();
		for(int i = 0; i < q; i++) {
			String stt = stdIn.next();
			if(stt.equals("print")) {
				int a = stdIn.nextInt();
				int b = stdIn.nextInt();
				String tmp = str.substring(a, b+1);
				System.out.println(tmp);
			}
			else if(stt.equals("reverse")) {
				int a = stdIn.nextInt();
				int b = stdIn.nextInt();
				String tmp = str.substring(a,b+1);
				String tmp2 = "";
				for(int j = tmp.length()-1; j >= 0; j--) {
					tmp2 += String.valueOf(tmp.charAt(j));
				}
				String ck1 = str.substring(0, a);
				String ck2 = str.substring(b+1,str.length());
				str = ck1 + tmp2 + ck2;
			}
			else if(stt.equals("replace")) {
				int a = stdIn.nextInt();
				int b = stdIn.nextInt();
				String p = stdIn.next();
				String ck1 = str.substring(0, a);
				String ck2 = str.substring(b+1,str.length());
				str = ck1 + p + ck2;
				
			}
		}
	}
}