Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Wrong Answer)

import java.util.Scanner;

//20180510
//04

public class Main {
    public static void main(String[] args){
		Scanner scanner = new Scanner(System.in);
		String[] list = {"a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","x","y","z"};
		int[] count = new int[list.length];

		String str = scanner.nextLine();
		char[] cha = str.toCharArray();

		for(int i = 0;i < cha.length;i++) {
			for(int j = 0;j < list.length;j++) {
				String up = String.valueOf(Character.toUpperCase(cha[i]));
				String lo = String.valueOf(Character.toLowerCase(cha[i]));
				if(list[j].equals(up) || list[j].equals(lo)) {
					count[j]++;
				}
			}
		}

		for(int j = 0;j < list.length;j++) {
			System.out.printf("%s : %d\n",list[j],count[j]);
		}
		scanner.close();
    }
}