Problem:
Score : 100 points

Problem Statement

We conducted a survey on newspaper subscriptions.
More specifically, we asked each of the N respondents the following two questions:

Question 1: Are you subscribing to Newspaper X?

Question 2: Are you subscribing to Newspaper Y?

As the result, A respondents answered "yes" to Question 1, and B respondents answered "yes" to Question 2.

What are the maximum possible number and the minimum possible number of respondents subscribing to both newspapers X and Y?

Write a program to answer this question.

Constraints

1 \leq N \leq 100

0 \leq A \leq N

0 \leq B \leq N

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N A B

Output

Print the maximum possible number and the minimum possible number of respondents subscribing to both newspapers, in this order, with a space in between.

Sample Input 1

10 3 5

Sample Output 1

3 0

In this sample, out of the 10 respondents, 3 answered they are subscribing to Newspaper X, and 5 answered they are subscribing to Newspaper Y.

Here, the number of respondents subscribing to both newspapers is at most 3 and at least 0.

Sample Input 2

10 7 5

Sample Output 2

5 2

In this sample, out of the 10 respondents, 7 answered they are subscribing to Newspaper X, and 5 answered they are subscribing to Newspaper Y.

Here, the number of respondents subscribing to both newspapers is at most 5 and at least 2.

Sample Input 3

100 100 100

Sample Output 3

100 100

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Runtime Error)

import java.util.ArrayList;
import java.util.Collections;
import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		Scanner in = new Scanner(System.in);
		int n = in.nextInt();
		ArrayList<U> aa = new ArrayList<>();
		for (int i = 0; i < n; i++) {
			long a = in.nextInt();
			long b = in.nextInt();

			U u = new U();
			u.d = a - b;
			u.t = a + b;
			u.a = a;
			u.b = b;

			aa.add(u);
		}
		Collections.sort(aa, (u1, u2) -> {
			if (u1.d > u2.d) {
				return 1;
			} else if (u1.d > u2.d) {
				return -1;
			} else {
				return 0;
			}
		});
		long r = 0;
		for (int i = 0; i < aa.size(); i = i + 2) {
			r += aa.get(i).a;
		}
		for (int i = 1; i < aa.size(); i = i + 2) {
			r -= aa.get(i).b;
		}

		in.close();
		System.out.println(r);
	}

}

class U {
	long d;
	long t;
	long a;
	long b;
}