Problem:
Score : 100 points

Problem Statement

There are two buttons, one of size A and one of size B.

When you press a button of size X, you get X coins and the size of that button decreases by 1.

You will press a button twice. Here, you can press the same button twice, or press both buttons once.

At most how many coins can you get?

Constraints

All values in input are integers.

3 \leq A, B \leq 20

Input

Input is given from Standard Input in the following format:

A B

Output

Print the maximum number of coins you can get.

Sample Input 1

5 3

Sample Output 1

9

You can get 5 + 4 = 9 coins by pressing the button of size 5 twice, and this is the maximum result.

Sample Input 2

3 4

Sample Output 2

7

Sample Input 3

6 6

Sample Output 3

12

Solution in Java7 (OpenJDK 1.7.0) (judge verdict: Accepted)

import java.util.Scanner;

public class Main{
  public static void main(String[] args){
    Scanner scanner = new Scanner(System.in);
    int sum = 0;
    int inputA = scanner.nextInt();
    int inputB = scanner.nextInt();
    if(inputA >= 3 && inputB <= 20){
      if(inputB >= 3 && inputB <= 20){
        if(inputA > inputB + 1){
          sum = inputA + inputA - 1;
        }else if(inputB > inputA + 1){
          sum = inputB + inputB - 1;
        }else if(inputA == inputB + 1 || inputB == inputA + 1){
          sum = inputA + inputB;
        }else{
          sum = inputA + inputB;
        }
      }else{
        System.exit(1);
      }
    }else{
      System.exit(1);
    }
    System.out.println(sum);
    scanner.close();
  }
}