Problem:
Score : 400 points

Problem Statement

We have a sequence of length N, a = (a_1, a_2, ..., a_N).
Each a_i is a positive integer.

Snuke's objective is to permute the element in a so that the following condition is satisfied:

For each 1 ≤ i ≤ N - 1, the product of a_i and a_{i + 1} is a multiple of 4.

Determine whether Snuke can achieve his objective.

Constraints

2 ≤ N ≤ 10^5

a_i is an integer.

1 ≤ a_i ≤ 10^9

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 ... a_N

Output

If Snuke can achieve his objective, print Yes; otherwise, print No.

Sample Input 1

3
1 10 100

Sample Output 1

Yes

One solution is (1, 100, 10).

Sample Input 2

4
1 2 3 4

Sample Output 2

No

It is impossible to permute a so that the condition is satisfied.

Sample Input 3

3
1 4 1

Sample Output 3

Yes

The condition is already satisfied initially.

Sample Input 4

2
1 1

Sample Output 4

No

Sample Input 5

6
2 7 1 8 2 8

Sample Output 5

Yes

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Scanner;

public class Main {
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		int N = sc.nextInt();
		
		long[] a = new long[N];
		
		int x1 = 0;
		int x2 = 0;
		int x4 = 0;
		
		for(int i = 0; i < N; i++) {
			a[i] = sc.nextLong();
			if(a[i] % 2 != 0) {
				x1++;
			} else if(a[i] % 2 == 0 && a[i] % 4 != 0) {
				x2++;
			} else if(a[i] % 4 == 0) {
				x4++;
			}
		}
		
		if(x4 >= x1) {
			System.out.println("Yes");
		} else if(x4 + 1 == x1 && x4 + x1 == N) {
			System.out.println("Yes");
		} else {
			System.out.println("No");
		}
		
	}
}