Problem:
Score : 300 points

Problem Statement

There are N people living on a number line.

The i-th person lives at coordinate X_i.

You are going to hold a meeting that all N people have to attend.

The meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.

Find the minimum total points of stamina the N people have to spend.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq X_i \leq 100

Input

Input is given from Standard Input in the following format:

N
X_1 X_2 ... X_N

Output

Print the minimum total stamina the N people have to spend.

Sample Input 1

2
1 4

Sample Output 1

5

Assume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.

Note that you can hold the meeting only at an integer coordinate.

Sample Input 2

7
14 14 2 13 56 2 37

Sample Output 2

2354

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int numOfPerson = sc.nextInt();
        int sum = 0;
        int[] positions = new int[numOfPerson];
        for (int i = 0; i < numOfPerson; i++) {
            positions[i] = sc.nextInt();
            sum += positions[i];
        }
        sc.close();

        double juusin = sum / numOfPerson;
        int p = smallInt(juusin);
        if (juusin - p <= 0.5) {
            p += 1;
        }

        int e = 0;
        for (int i = 0; i< numOfPerson; i++) {
            e += Math.pow((positions[i] - p), 2);
        }
        System.out.println(e);
    }

    public static int smallInt(double x) {
        int p = (int) x;
        if (x >= 0) {
            return (x - p) <= 0.5 ? p : p + 1;
        } else {
            p = -p;
            return - smallInt(p);
        }
    }
}