Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)


import java.util.*;

public class Main{
    public static void main(String[] args){
        Scanner sc =new Scanner(System.in);

        int n=sc.nextInt();
        int cnt_8;
        int cnt=0;

        for(int j=1;j<=n;j+=2){
            cnt_8=0;
            for(int k=1;k<=j;k++){
                if(j%k==0){
                    cnt_8++;
                }
            }
            if(cnt_8==8){
                //System.out.println("num="+j);
                cnt++;
            }
        }
    System.out.println(""+cnt);
    }
}