Problem:
Score : 400 points

Problem Statement

You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

In the i-th operation, you replace every element whose value is B_{i} with C_{i}.

For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

All values in input are integers.

1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}

B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:

N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}

Output

Print Q integers S_{i} to Standard Output in the following format:

S_{1}
S_{2}
\vdots
S_{Q}

Note that S_{i} may not fit into a 32-bit integer.

Sample Input 1

4
1 2 3 4
3
1 2
3 4
2 4

Sample Output 1

11
12
16

Initially, the sequence A is 1,2,3,4.

After each operation, it becomes the following:

2, 2, 3, 4

2, 2, 4, 4

4, 4, 4, 4

Sample Input 2

4
1 1 1 1
3
1 2
2 1
3 5

Sample Output 2

8
4
4

Note that the sequence A may not contain an element whose value is B_{i}.

Sample Input 3

2
1 2
3
1 100
2 100
100 1000

Sample Output 3

102
200
2000

Solution in Java (OpenJDK 1.8.0) (judge verdict: Time Limit Exceeded)

import java.io.*;
import java.util.*;

public class Main
{
	//static Scanner scan = new Scanner(System.in);
	public static void main(String[] args) throws Exception
	{
		BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
		StringTokenizer tk = new StringTokenizer(in.readLine());
		int n = Integer.parseInt(tk.nextToken());
		int[] nums = new int[n];
		tk = new StringTokenizer(in.readLine());
		for(int i=0;i<n;i++)
		{
			nums[i]=Integer.parseInt(tk.nextToken());
		}
		tk = new StringTokenizer(in.readLine());
		int q = Integer.parseInt(tk.nextToken());
		while(q-->0)
		{
			tk = new StringTokenizer(in.readLine());
			int a = Integer.parseInt(tk.nextToken());
			int b = Integer.parseInt(tk.nextToken());
			long sum =0;
			for(int i=0;i<n;i++)
			{
				if(nums[i]==a)
					nums[i]=b;
				sum+=nums[i];
			}
			System.out.println(sum);
		}
	}
	/*
	public static void main(String[] args) throws Exception
	{
		if(scan.hasNext())
		{
			//int t= scan.nextInt();
			int t= 1;
			while(t-->0)
			{	
				solve();
			}
		}
	*/
}