Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Scanner;
public class Main {

    static int countDivisors(int n)
    {
    	int count=0;
        for (int i=1; i<=Math.sqrt(n); i++)
        {
            if (n%i==0)
            {
                if (n/i == i) {
                	if(i%2!=0)
                		count++;
                }
                    
      
                else {
                	if (i%2!=0) count++;
                	if ((n/i)%2!=0) count++;
                } 
                    
            }
        }
        return count;
    }
    	
	public static void main(String[] args) {
		// TODO Auto-generated method stub
		Scanner sc = new Scanner(System.in);
		int A = sc.nextInt();
		int count=0;
		if (A==105) System.out.println(1);
		else if(A>105) {
			while(A>105) {
				if(countDivisors(A)==8) {
					count++;
				}
				A--;
			}
			System.out.println(count+1);
		}
		else System.out.println(0);
		
	}

}