Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Accepted)

import java.util.Scanner;

public class Main {
    public static void main(String... args) {
        Scanner sc = new Scanner(System.in);
        String str = "";

        while(sc.hasNext()) {
        	str += sc.nextLine();
        }
        str = str.toLowerCase();

        char[] alphabet = new char[] {'a','b','c','d','e','f','g','h','i','j','k',
        							  'l','m','n','o','p','q','r','s','t','u','v',
        							  'w','x','y','z'};

        int[] ans = new int[alphabet.length];

        for(int i = 0; i < str.length(); ++i) {
        	for(int j = 0; j < alphabet.length; j++) {
        		if(str.charAt(i) == alphabet[j]) {
        			ans[j]++;
        		}
        	}
        }

        for(int i = 0; i < alphabet.length; i++) {
        	System.out.println(String.format("%s : %d", alphabet[i], ans[i]));
        }

    }
}