Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Wrong Answer)


import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class Main {

	public static void main(String[] args) {
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

		try {

			int[] alphaCnt = new int[26];
			String str;
			char[] cArr;

			while ((str = br.readLine()) != null) {
				cArr = str.toCharArray();
				for (char c : cArr) {
					if ('A' <= c && c <= 'Z') {
						alphaCnt[c - 'A']++;
					} else if ('a' <= c && c <= 'b') {
						alphaCnt[c - 'a']++;
					}
				}
			}

			StringBuilder sb = new StringBuilder();
			for (int i = 0; i < alphaCnt.length; i++) {
				System.out.println((char) (i + 65) + " : " + alphaCnt[i]);
			}

		} catch (IOException e) {
			e.printStackTrace();
		} finally {
			try {
				if (br != null) {
					br.close();
				}
			} catch (IOException ioe) {
			}

		}
	}
}