Problem:
Score : 200 points

Problem Statement

A string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:

S is a palindrome.

Let N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.

The string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.

Determine whether S is a strong palindrome.

Constraints

S consists of lowercase English letters.

The length of S is an odd number between 3 and 99 (inclusive).

Input

Input is given from Standard Input in the following format:

S

Output

If S is a strong palindrome, print Yes;
otherwise, print No.

Sample Input 1

akasaka

Sample Output 1

Yes

S is akasaka.

The string formed by the 1-st through the 3-rd characters is aka.

The string formed by the 5-th through the 7-th characters is aka.
All of these are palindromes, so S is a strong palindrome.

Sample Input 2

level

Sample Output 2

No

Sample Input 3

atcoder

Sample Output 3

No

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.awt.Point;
import java.io.*;
import java.util.*;
import java.math.BigInteger;

public class Main {
    static class Solver {
        public void solve(MyReader in, PrintWriter out) {
            String s = in.next();
            int n = s.length();

            boolean res = isPali(s);
            String a = (s.substring(0,(n-1)/2));
//            out.println(a.toString());
            if (isPali(a))res = true;

            int pos = (n+3)/2 - 1;
            String b = (s.substring(pos));
//            out.println(b.toString());
            if (isPali(b))res = res;


            if (res)out.println("Yes");
            else out.println("No");


        }

        private boolean isPali(String a) {
            int l = 0,r = a.length()-1;
            while (l<r){
                if (a.charAt(l) != a.charAt(r))return false;
                l++;
                r--;
            }

            return true;
        }


    }

    public static void main(String[] args) {
        MyReader mr = new MyReader();
        PrintWriter out = new PrintWriter(new OutputStreamWriter(System.out));
        new Solver().solve(mr, out);
        out.close();
    }

    //    static int[][] dir = {{0,1}, {1,0},{-1,0}, {0,-1}};
//    static int[][] dir = {{0,1}, {1,0},{-1,0}, {0,-1}, {-1,-1},{-1,1}, {1,1}, {1,-1}};
    static class MyReader {
        BufferedReader br;
        StringTokenizer st;

        MyReader() {
            br = new BufferedReader(new InputStreamReader(System.in));
        }

        String next() {
            while (st == null || !st.hasMoreElements()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (Exception e) {
                    e.printStackTrace();
                }
            }

            return st.nextToken();
        }

        int nextInt() {
            return Integer.parseInt(next());
        }

        long nextLong() {
            return Long.parseLong(next());
        }

        double nextDouble() {
            return Double.parseDouble(next());
        }

        String nextLine() {
            String res = "";
            try {
                res = br.readLine();
            } catch (IOException e) {
                e.printStackTrace();
            }

            return res;
        }

        int[] nextIntArray(int n) {
            int[] arr = new int[n];
            for (int i = 0; i < n; i++) {
                arr[i] = nextInt();
            }

            return arr;
        }

        Integer[] nextIntegerArray(int n) {
            Integer[] arr = new Integer[n];
            for (int i = 0; i < n; i++) {
                arr[i] = nextInt();
            }

            return arr;
        }

        Long[] nextLongArray(int n) {
            Long[] arr = new Long[n];
            for (int i = 0; i < n; i++) {
                arr[i] = nextLong();
            }

            return arr;
        }

        String[] nextStringArray(int n) {
            String[] arr = new String[n];
            for (int i = 0; i < n; i++) {
                arr[i] = next();
            }
            return arr;
        }
    }

    static void swap(int[] arr, int i, int j) {
        int tmp = arr[i];
        arr[i] = arr[j];
        arr[j] = tmp;
    }

}