Problem:
Simultaneous Equation

Write a program which solve a simultaneous equation:

ax + by = c

dx + ey = f

The program should print x and y for given a, b, c, d, e and f (-1,000 ≤ a, b, c, d, e, f ≤ 1,000). You can suppose that given equation has a unique solution.

Input

The input consists of several data sets, 1 line for each data set. In a data set, there will be a, b, c, d, e, f separated by a single space. The input terminates with EOF.

Output

For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.

Sample Input 1

1 2 3 4 5 6
2 -1 -2 -1 -1 -5

Output for the Sample Input 1

-1.000 2.000
1.000 4.000

Sample Input 2

2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27

Output for the Sample Input 2

0.000 3.000
0.000 3.000

Solution in JAVA (judge verdict: Wrong Answer)

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
 
public class Main {

  public static void main(String[] args) throws IOException {
    try ( BufferedReader br = new BufferedReader(new InputStreamReader(System.in)) ) {

      String line = null;
      String[] lines;
      double a,b,c,d,e,f;
      double x,y;

      for(int i = 0; i < 5; i++) {

        line = br.readLine();
        // if ( line == null ) break;

        lines = line.split(" ");
        a = Integer.parseInt(lines[0]);
        b = Integer.parseInt(lines[1]);
        c = Integer.parseInt(lines[2]);
        d = Integer.parseInt(lines[3]);
        e = Integer.parseInt(lines[4]);
        f = Integer.parseInt(lines[5]);

        y = (f-(d*c/a)) / (e-(d*b/a));
        x = (f-(e*c/b)) / (d-(a*e/b));

        System.out.printf("%.3f %.3f\n", x,y);

      }
    }
  }
}