Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Wrong Answer)

import java.util.Scanner;

public class Main{
	public static void main(String[] args){
		//データ入力の準備
		Scanner sc = new Scanner(System.in);
		
		//データ数の配列
		int result[] = new int[26];
		for (int i = 0; i < 26; i++){
			result[i] = 0;
		}
		
		while (sc.hasNext() == true){
			//データを小文字に変換して入力
			String temp = sc.nextLine().toLowerCase();
			
			for (int i = 0; i < temp.length(); i++){
				//入力された文字のascllコード
				int ac = temp.charAt(i) - 97;
				if (ac < 0 || 26 <= ac){
					continue;
				}
				result[ac]++;
			}
			
			if (sc.hasNext() == true){
				System.out.println("hello");
			}else{
				System.out.println("good");
			}
		}
		
		//結果の出力
		char[] value = {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};
		
		for (int i = 0; i < 26; i++){
			System.out.println(value[i] + " : " + result[i]);
		}
	}
}