Problem:
Score : 100 points

Problem Statement

You are given four digits N_1, N_2, N_3 and N_4. Determine if these can be arranged into the sequence of digits "1974".

Constraints

0 \leq N_1, N_2, N_3, N_4 \leq 9

N_1, N_2, N_3 and N_4 are integers.

Input

Input is given from Standard Input in the following format:

N_1 N_2 N_3 N_4

Output

If N_1, N_2, N_3 and N_4 can be arranged into the sequence of digits "1974", print YES; if they cannot, print NO.

Sample Input 1

1 7 9 4

Sample Output 1

YES

We can get 1974 by swapping N_2 and N_3.

Sample Input 2

1 9 7 4

Sample Output 2

YES

We already have 1974 before doing anything.

Sample Input 3

1 2 9 1

Sample Output 3

NO

Sample Input 4

4 9 0 8

Sample Output 4

NO

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.Scanner;
public class Main{

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		String ans = "keyence";
		int i,j;
		Boolean f=false;
		int count =0;	
		String data=sc.next();

		for(i=0;i<data.length();i++) {
			count =0;	
			for(j=0;j<7;j++) {
					if(data.charAt(i+j)==ans.charAt(j))count++;
					else {
						int result = data.substring(i+j).indexOf(ans.substring(j));
						System.out.println(data.substring(i+j));
						System.out.println(ans.substring(j));
						System.out.println(data.substring(i+j).indexOf(ans.substring(j)));
						if (result != -1&&data.substring(i+j+result).length()==ans.substring(j).length()) {
						    f=true;
						    break;
						} else {
						    break;
						}
					}
				}
				if(f||count==7) {
					break;
				}
		}
		if(f||count==7) {
			System.out.println("YSE");
		}else {
			System.out.println("NO");
			
		}
	}
}