Problem:
Score : 500 points

Problem Statement

There are N towns on a plane. The i-th town is located at the coordinates (x_i,y_i). There may be more than one town at the same coordinates.

You can build a road between two towns at coordinates (a,b) and (c,d) for a cost of min(|a-c|,|b-d|) yen (the currency of Japan). It is not possible to build other types of roads.

Your objective is to build roads so that it will be possible to travel between every pair of towns by traversing roads. At least how much money is necessary to achieve this?

Constraints

2 ≤ N ≤ 10^5

0 ≤ x_i,y_i ≤ 10^9

All input values are integers.

Input

Input is given from Standard Input in the following format:

N
x_1 y_1
x_2 y_2
:
x_N y_N

Output

Print the minimum necessary amount of money in order to build roads so that it will be possible to travel between every pair of towns by traversing roads.

Sample Input 1

3
1 5
3 9
7 8

Sample Output 1

3

Build a road between Towns 1 and 2, and another between Towns 2 and 3. The total cost is 2+1=3 yen.

Sample Input 2

6
8 3
4 9
12 19
18 1
13 5
7 6

Sample Output 2

8

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Runtime Error)

import java.util.Arrays;
import java.util.Comparator;
import java.util.Scanner;

public class Main {
    static Scanner in = new Scanner(System.in);

    public static void main(String[] args) {
        int N = in.nextInt();
        City[] c = new City[N];
        UnionFind uf = new UnionFind(N);
        for (int i = 0; i < N; i++) {
            c[i] = new City(i, in.nextInt(), in.nextInt());
        }
        Road[] roads = new Road[(N - 1) * 2];
        Arrays.sort(c, new Comparator<City>() {
            public int compare(City p1, City p2){
                return p1.x > p2.x ? 1 : -1;
            }
        });
        for(int i = 0; i < N - 1; i++){
            roads[i] = new Road(c[i].p, c[i + 1].p, Math.abs(c[i].x - c[i + 1].x));
        }
        Arrays.sort(c, new Comparator<City>() {
            public int compare(City p1, City p2){
                return p1.y > p2.y ? 1 : -1;
            }
        });
        for(int i = 0; i < N - 1; i++){
            roads[(N - 1) + i] =  new Road(c[i].p, c[i + 1].p, Math.abs(c[i].y - c[i + 1].y));
        }
        Arrays.sort(roads, new Comparator<Road>() {
            public int compare(Road r1, Road r2){
                return r1.cost > r2.cost ? 1 : -1;
            }
        });
        long ans = 0;
        for(Road r: roads){
            if(!uf.same(r.from, r.to)){
                ans += r.cost;
                uf.union(r.from, r.to);
            }
        }
        System.out.println(ans);
    }
}

class City {
    int p, x, y;

    public City(int a, int b, int c) {
        p = a;
        x = b;
        y = c;
    }
}

class Road{
    int from, to, cost;
    public Road(int f, int t, int c){
        from = f;
        to= t;
        cost = c;
    }
}

class UnionFind {
    int[] par;
    int[] rank;

    public UnionFind(int n) {
        par = new int[n];
        rank = new int[n];

        for (int i = 0; i < n; i++) {
            par[i] = i;
            rank[i] = 0;
        }
    }

    public int find(int i) {
        if (par[i] == i) {
            return i;
        }
        return find(par[i]);
    }

    public void union(int x, int y) {
        x = find(x);
        y = find(y);

        if (rank[x] < rank[y]) {
            par[x] = y;
        } else {
            par[y] = x;
            if (rank[x] == rank[y]) {
                rank[x]++;
            }
        }
    }

    public boolean same(int x, int y) {
        return find(par[x]) == find(par[y]);
    }
}