Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Accepted)

import java.util.Scanner;

public class Main{
    public static void main(String args[]){
        Scanner input = new Scanner(System.in);
        String word = null;
        int[] cnt = new int[26];
        for (int i = 0; i < cnt.length; i++ )
            cnt[i] = 0;
        while(input.hasNext()){
            word = input.nextLine();
            char[] words = word.toCharArray();
            store(words, cnt);
        }
        for(int j = 0; j < cnt.length; j ++){
            System.out.println((char)('a' + j) + " : " + cnt[j]);
        }
    }
    
    public static void store(char[] w, int[] c){
        int temp = 0;
        for(int i = 0; i < w.length; i ++){
            if(w[i] <= 'z' && w[i] >= 'a'){
                temp = w[i] - 'a';
                c[temp] ++;
            }
            else if(w[i] <= 'Z' && w[i] >= 'A'){
                temp = w[i] - 'A';
                c[temp] ++;
            }
        }
    }
}