Problem:
Score : 200 points

Problem Statement

La Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each.
Determine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.

Constraints

N is an integer between 1 and 100, inclusive.

Input

Input is given from Standard Input in the following format:

N

Output

If there is a way to buy some cakes and some doughnuts for exactly N dollars, print Yes; otherwise, print No.

Sample Input 1

11

Sample Output 1

Yes

If you buy one cake and one doughnut, the total will be 4 + 7 = 11 dollars.

Sample Input 2

40

Sample Output 2

Yes

If you buy ten cakes, the total will be 4 \times 10 = 40 dollars.

Sample Input 3

3

Sample Output 3

No

The prices of cakes (4 dollars) and doughnuts (7 dollars) are both higher than 3 dollars, so there is no such way.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.*;

public class Main {

  public static void main (String[] args) {

    Scanner sc = new Scanner(System.in);
    
    int N = sc.nextInt();

    sc.close();

    String result = "No";

    if (N % 4 == 0 || N % 11 == 0){
      result = "Yes";
    }
    
    if (result.equals("No")){

      for (int i = 1; i < N / 4; i++) {
        if((N - (4 * i)) % 11 == 0 ) {
          result = "Yes";
          break;
        }
      }

    }

    if (result.equals("No")){

      for (int i = 1; i < N / 11; i++) {
        if((N - (11 * i)) % 4 == 0 ) {
          result = "Yes";
          break;
        }
      }

    }

    System.out.println(result);

  }

}