Problem:
Score : 200 points

Problem Statement

An integer N is a multiple of 9 if and only if the sum of the digits in the decimal representation of N is a multiple of 9.

Determine whether N is a multiple of 9.

Constraints

0 \leq N < 10^{200000}

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a multiple of 9, print Yes; otherwise, print No.

Sample Input 1

123456789

Sample Output 1

Yes

The sum of these digits is 1+2+3+4+5+6+7+8+9=45, which is a multiple of 9, so 123456789 is a multiple of 9.

Sample Input 2

0

Sample Output 2

Yes

Sample Input 3

31415926535897932384626433832795028841971693993751058209749445923078164062862089986280

Sample Output 3

No

Solution in Java (OpenJDK 11.0.6) (judge verdict: Accepted)

import java.util.Scanner;

/**
 * B - Multiple of 9
 * 整数 N が 9 の倍数であることと、N を十進法で表したときの各桁の数の和が 9 の倍数であることは同値です。
 * N が 9 の倍数であるか判定してください。
 */
public class Main {

    public static void main( String[] args ) {

        Scanner sc = new Scanner( System.in );
        // 入力値
        String n = sc.next(); // 整数

        int sum = 0;
        for( int i = 0; i < n.length(); i++ ) {
            sum += Integer.parseInt( n.substring( i, i + 1 ) );
        }

        System.out.println( ( sum % 9 == 0 ) ? "Yes" : "No"  );

        sc.close();
    }
}