Problem:
Score : 200 points

Problem Statement

Find the number of palindromic numbers among the integers between A and B (inclusive).
Here, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.

Constraints

10000 \leq A \leq B \leq 99999

All input values are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the number of palindromic numbers among the integers between A and B (inclusive).

Sample Input 1

11009 11332

Sample Output 1

4

There are four integers that satisfy the conditions: 11011, 11111, 11211 and 11311.

Sample Input 2

31415 92653

Sample Output 2

612

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.*;

public class Main {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int min = sc.nextInt();
        int max = sc.nextInt();

        int count = 0;
        for (int i = min; i <= max; i++) {
            if (isKaibun(i)) count++;
        }

        System.out.println(count);
    }

    private static boolean isKaibun(int n) {
        boolean isKaibun = true;
        String nString = Integer.toString(n);

        for (int i = 0; i < nString.length(); i++) {
            if (nString.charAt(i) == nString.charAt(nString.length()-1-i)) continue;

            // 文字が違うため回文ではない
            isKaibun = false;
            break;
        }

        return isKaibun;
    }
}