Problem:
Simultaneous Equation

Write a program which solve a simultaneous equation:

ax + by = c

dx + ey = f

The program should print x and y for given a, b, c, d, e and f (-1,000 ≤ a, b, c, d, e, f ≤ 1,000). You can suppose that given equation has a unique solution.

Input

The input consists of several data sets, 1 line for each data set. In a data set, there will be a, b, c, d, e, f separated by a single space. The input terminates with EOF.

Output

For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.

Sample Input 1

1 2 3 4 5 6
2 -1 -2 -1 -1 -5

Output for the Sample Input 1

-1.000 2.000
1.000 4.000

Sample Input 2

2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27

Output for the Sample Input 2

0.000 3.000
0.000 3.000

Solution in JAVA (judge verdict: Accepted)

import java.util.Scanner;
import java.math.BigDecimal;
 
class Main{
    public static void main(String[] args){
        Scanner scanline = new Scanner (System.in);
        while(scanline.hasNext()){
            String lines = scanline.nextLine();
            Scanner scan = new Scanner(lines);
            double a = scan.nextDouble();
            double b = scan.nextDouble();
            double c = scan.nextDouble();
            double d = scan.nextDouble();
            double e = scan.nextDouble();
            double f = scan.nextDouble();
            double ansx = (c*e-b*f)/(a*e-b*d);
            double ansy = (a*f-c*d)/(a*e-b*d);
            BigDecimal xx = new BigDecimal(String.valueOf(ansx));
            BigDecimal yy = new BigDecimal(String.valueOf(ansy));
            double x = xx.setScale(4,BigDecimal.ROUND_DOWN).doubleValue();
            double y = yy.setScale(4,BigDecimal.ROUND_DOWN).doubleValue();
            if (x == -0.000){
                x = 0.000;
            }
            if (y == -0.000){
                y = 0.000;
            }
            System.out.printf("%.3f %.3f\n",x,y);
        }
    }   
}