Problem:
Score : 200 points

Problem Statement

We have sticks numbered 1, \cdots, N. The length of Stick i (1 \leq i \leq N) is L_i.

In how many ways can we choose three of the sticks with different lengths that can form a triangle?

That is, find the number of triples of integers (i, j, k) (1 \leq i < j < k \leq N) that satisfy both of the following conditions:

L_i, L_j, and L_k are all different.

There exists a triangle whose sides have lengths L_i, L_j, and L_k.

Constraints

1 \leq N \leq 100

1 \leq L_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
L_1 L_2 \cdots L_N

Output

Print the number of ways to choose three of the sticks with different lengths that can form a triangle.

Sample Input 1

5
4 4 9 7 5

Sample Output 1

5

The following five triples (i, j, k) satisfy the conditions: (1, 3, 4), (1, 4, 5), (2, 3, 4), (2, 4, 5), and (3, 4, 5).

Sample Input 2

6
4 5 4 3 3 5

Sample Output 2

8

We have two sticks for each of the lengths 3, 4, and 5. To satisfy the first condition, we have to choose one from each length.

There is a triangle whose sides have lengths 3, 4, and 5, so we have 2 ^ 3 = 8 triples (i, j, k) that satisfy the conditions.

Sample Input 3

10
9 4 6 1 9 6 10 6 6 8

Sample Output 3

39

Sample Input 4

2
1 1

Sample Output 4

0

No triple (i, j, k) satisfies 1 \leq i < j < k \leq N, so we should print 0.

Solution in Java (OpenJDK 11.0.6) (judge verdict: Wrong Answer)

import java.util.ArrayList;
import java.util.Collections;
import java.util.List;
import java.util.Scanner;

public class Main {

	public static void main(String[] args) {

		Scanner sc = new Scanner(System.in);

		Integer n = sc.nextInt();

		if (n < 3) {
			System.out.println(0);
			return;
		}

		List<Integer> l = new ArrayList<Integer>();

		for (Integer i = 0; i < n; i++) {
			Integer a = sc.nextInt();
			l.add(a);
		}

		Collections.sort(l);

		Integer count = 0;

		for (Integer i = 0; i < n - 2; i++) {
			for (Integer j = 0; j < n - 1; j++) {
				if (i >= j) {
					j = i + 1;
				}
				for (Integer k = 0; k < n; k++) {
					if (j >= k) {
						k = j + 1;
					}
					if (l.get(i) != l.get(j) && l.get(j) != l.get(k) && l.get(k) != l.get(i)) {
						if (l.get(k) < l.get(i) + l.get(j)) {
							count++;
						}
					}
				}
			}
		}
		System.out.println(count);
	}
}