Problem:
Score : 400 points

Problem Statement

An altar enshrines N stones arranged in a row from left to right. The color of the i-th stone from the left (1 \leq i \leq N) is given to you as a character c_i; R stands for red and W stands for white.

You can do the following two kinds of operations any number of times in any order:

Choose two stones (not necessarily adjacent) and swap them.

Choose one stone and change its color (from red to white and vice versa).

According to a fortune-teller, a white stone placed to the immediate left of a red stone will bring a disaster. At least how many operations are needed to reach a situation without such a white stone?

Constraints

2 \leq N \leq 200000

c_i is R or W.

Input

Input is given from Standard Input in the following format:

N
c_{1}c_{2}...c_{N}

Output

Print an integer representing the minimum number of operations needed.

Sample Input 1

4
WWRR

Sample Output 1

2

For example, the two operations below will achieve the objective.

Swap the 1-st and 3-rd stones from the left, resulting in RWWR.

Change the color of the 4-th stone from the left, resulting in RWWW.

Sample Input 2

2
RR

Sample Output 2

0

It can be the case that no operation is needed.

Sample Input 3

8
WRWWRWRR

Sample Output 3

3

Solution in Java (OpenJDK 11.0.6) (judge verdict: Time Limit Exceeded)

import java.util.Scanner;

public class Main {
	public static void main(String[] args) {
		Scanner scan = new Scanner(System.in);
		int k = Integer.parseInt(scan.nextLine());
		String s = scan.nextLine();

		int w = s.indexOf('W');
		int r = s.lastIndexOf('R');
		int count = 0;

		if(k==s.length()) {
		}
		if(w < 0 || r < 0) {
			System.out.println(0);
		}else {
			while(w < r){
				StringBuilder sb = new StringBuilder(s);
				sb.setCharAt(w, 'R');
				sb.setCharAt(r, 'W');
				s = sb.toString();
				count++;
				w = s.indexOf('W');
				r = s.lastIndexOf('R');
			}
			System.out.println(count);
		}



		scan.close();
	}
}