Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Wrong Answer)



import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class Main {

	public static void main(String[] args) throws IOException {

		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

		String str = br.readLine();
		// ??????????°????????????????
		String lower_case = str.toLowerCase();
		// ????????????1????????????????????????????????????????´?
		// char[] charArray = lower_case.toCharArray();

		int[] char_count = new int[26];

		for (int i = 0; i < lower_case.length(); i++) {

			if(lower_case.charAt(i) == 'a'){

				char_count[0]++;

			}else if(lower_case.charAt(i) == 'b'){

				char_count[1]++;

			}else if(lower_case.charAt(i) == 'c'){

				char_count[2]++;

			}else if(lower_case.charAt(i) == 'd'){

				char_count[3]++;

			}else if(lower_case.charAt(i) == 'e'){

				char_count[4]++;

			}else if(lower_case.charAt(i) == 'f'){

				char_count[5]++;

			}else if(lower_case.charAt(i) == 'g'){

				char_count[6]++;

			}else if(lower_case.charAt(i) == 'h'){

				char_count[7]++;

			}else if(lower_case.charAt(i) == 'i'){

				char_count[8]++;

			}else if(lower_case.charAt(i) == 'j'){

				char_count[9]++;

			}else if(lower_case.charAt(i) == 'k'){

				char_count[10]++;

			}else if(lower_case.charAt(i) == 'l'){

				char_count[11]++;

			}else if(lower_case.charAt(i) == 'm'){

				char_count[12]++;

			}else if(lower_case.charAt(i) == 'n'){

				char_count[13]++;

			}else if(lower_case.charAt(i) == 'o'){

				char_count[14]++;

			}else if(lower_case.charAt(i) == 'p'){

				char_count[15]++;

			}else if(lower_case.charAt(i) == 'q'){

				char_count[16]++;

			}else if(lower_case.charAt(i) == 'r'){

				char_count[17]++;

			}else if(lower_case.charAt(i) == 's'){

				char_count[18]++;

			}else if(lower_case.charAt(i) == 't'){

				char_count[19]++;

			}else if(lower_case.charAt(i) == 'u'){

				char_count[20]++;

			}else if(lower_case.charAt(i) == 'v'){

				char_count[21]++;

			}else if(lower_case.charAt(i) == 'w'){

				char_count[22]++;

			}else if(lower_case.charAt(i) == 'x'){

				char_count[23]++;

			}else if(lower_case.charAt(i) == 'y'){

				char_count[24]++;

			}else if(lower_case.charAt(i) == 'z'){

				char_count[25]++;

			}
		}

		// ??¢????????????????????????????????????????????¨?????°?????¨???
		char a = 'a';

		for(int i = 0; i < 26; i++){

			System.out.println(a++ + " : " + char_count[i]);

		}
	}
}