Problem:
Score : 200 points

Problem Statement

You are given a positive integer X.
Find the largest perfect power that is at most X.
Here, a perfect power is an integer that can be represented as b^p, where b is an integer not less than 1 and p is an integer not less than 2.

Constraints

1 ≤ X ≤ 1000

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print the largest perfect power that is at most X.

Sample Input 1

10

Sample Output 1

9

There are four perfect powers that are at most 10: 1, 4, 8 and 9.
We should print the largest among them, 9.

Sample Input 2

1

Sample Output 2

1

Sample Input 3

999

Sample Output 3

961

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.*;

class Main{
    public static void main(String[] args){
        Scanner sc = new Scanner(System.in);
       
        int X = Integer.parseInt(sc.next());
        
        int ans = 1;
        for(int i=2; i<=X; i++){
            for(int j=2; j<=X; j++){
                int a = (int)Math.pow(i, j);
                if(a < X){
                    if(ans < a){
                        ans = a;
                    }
                }else{
                    break;
                }
            }
        }
        
        System.out.println(ans);
    }
}