Problem:
Disjoint Set

Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.

same(x, y): determine whether x and y are in the same set.

Input

n q
com1 x1 y1
com2 x2 y2
...
comq xq yq

In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Constraints

1 ≤ n ≤ 10000

1 ≤ q ≤ 100000

x ≠ y

Sample Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0

Sample Output

0
0
1
1
1
0
1
1

Solution in JAVA (judge verdict: Accepted)

import java.util.ArrayList;
import java.util.Scanner;
import java.io.*;
import java.util.*;
/**
 * Created by takaesumizuki on 2018/06/22.
 */
public class Main {
    public static void main(String[] args) {
        new Main().run();
    }

    void run() {
        Scanner sc = new Scanner(System.in);
        Integer n = sc.nextInt();
        Integer q = sc.nextInt();
        UnionFind uni = new UnionFind(n);

        while (q-- > 0) {
            Integer com, x, y;
            com = sc.nextInt();
            x = sc.nextInt();
            y = sc.nextInt();

            if (com == 0) {
                uni.merge(x, y);
            } else {
                if (uni.same(x, y)) {
                    System.out.println(1);
                } else {
                    System.out.println(0);
                }
            }


        }

    }


    public class UnionFind {
//        ArrayList<Integer> unions;
        int[] unions;

        /**
         * 0 ~ size - 1までの集合を
         *
         * @param size 集合のサイズ
         */
        UnionFind(Integer size) {
//            this.unions = new ArrayList<>();
            this.unions = new int[size];
            for (Integer i = 0; i < size; i++) {
                this.unions[i] = i;
            }
        }

        int find(int v) {
            if (unions[v] == v) {
                return v;
            } else {
//                Integer ret = find(this.unions.get(v));
                int ret = find(this.unions[v]);
//                this.unions.set(v, ret);
                this.unions[v] = ret;
                return ret;
            }
        }

        /**
         * v1の集合 を v2の集合にする
         *
         * @param v1
         * @param v2
         */
        void merge(int v1, int v2) {
            int v1Root = find(v1);
            int v2Root = find(v2);

//            this.unions.set(v1Root, v2Root);
            this.unions[v1Root] = v2Root;
        }

        Boolean same(int v1, int v2) {
            return find(v1) == (find(v2));
        }
    }
}