Problem:
Simultaneous Equation

Write a program which solve a simultaneous equation:

ax + by = c

dx + ey = f

The program should print x and y for given a, b, c, d, e and f (-1,000 ≤ a, b, c, d, e, f ≤ 1,000). You can suppose that given equation has a unique solution.

Input

The input consists of several data sets, 1 line for each data set. In a data set, there will be a, b, c, d, e, f separated by a single space. The input terminates with EOF.

Output

For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.

Sample Input 1

1 2 3 4 5 6
2 -1 -2 -1 -1 -5

Output for the Sample Input 1

-1.000 2.000
1.000 4.000

Sample Input 2

2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27

Output for the Sample Input 2

0.000 3.000
0.000 3.000

Solution in JAVA (judge verdict: Wrong Answer)

import java.io.*;
import java.util.*;

public class Main {
	
	public static void main(String[] args) throws IOException {
		
		BufferedReader br = 
			new BufferedReader(new InputStreamReader(System.in));
		
		ArrayList<Double> x_list = new ArrayList<Double>();
		ArrayList<Double> y_list = new ArrayList<Double>();
		
		while (true) {
			
			String s = br.readLine();
			if(s == null) break;
			StringTokenizer st = new StringTokenizer(s," ");
			double a = Double.parseDouble(st.nextToken());
			double b = Double.parseDouble(st.nextToken());
			double c = Double.parseDouble(st.nextToken());
			double d = Double.parseDouble(st.nextToken());
			double e = Double.parseDouble(st.nextToken());
			double f = Double.parseDouble(st.nextToken());
			double x = (c * e - b * f) / (a * e - b * d);
			double y = (f * a - c * d) / (a * e - d * b);
			x_list.add(x);
			y_list.add(y);
		}
		for (int i = 0; i < x_list.size(); i++) {
			System.out.printf("%.4f %.4f", x_list.get(i), y_list.get(i));
			System.out.println();
		}
	}
	
}