Problem:
Score : 100 points

Problem Statement

There are N flowers arranged in a row.
For each i (1 \leq i \leq N), the height and the beauty of the i-th flower from the left is h_i and a_i, respectively.
Here, h_1, h_2, \ldots, h_N are all distinct.

Taro is pulling out some flowers so that the following condition is met:

The heights of the remaining flowers are monotonically increasing from left to right.

Find the maximum possible sum of the beauties of the remaining flowers.

Constraints

All values in input are integers.

1 \leq N \leq 2 × 10^5

1 \leq h_i \leq N

h_1, h_2, \ldots, h_N are all distinct.

1 \leq a_i \leq 10^9

Input

Input is given from Standard Input in the following format:

N
h_1 h_2 \ldots h_N
a_1 a_2 \ldots a_N

Output

Print the maximum possible sum of the beauties of the remaining flowers.

Sample Input 1

4
3 1 4 2
10 20 30 40

Sample Output 1

60

We should keep the second and fourth flowers from the left.
Then, the heights would be 1, 2 from left to right, which is monotonically increasing, and the sum of the beauties would be 20 + 40 = 60.

Sample Input 2

1
1
10

Sample Output 2

10

The condition is met already at the beginning.

Sample Input 3

5
1 2 3 4 5
1000000000 1000000000 1000000000 1000000000 1000000000

Sample Output 3

5000000000

The answer may not fit into a 32-bit integer type.

Sample Input 4

9
4 2 5 8 3 6 1 7 9
6 8 8 4 6 3 5 7 5

Sample Output 4

31

We should keep the second, third, sixth, eighth and ninth flowers from the left.

Solution in Java (OpenJDK 1.8.0) (judge verdict: Time Limit Exceeded)

import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.io.PrintWriter;
import java.util.StringTokenizer;

/**
 * Built using CHelper plug-in Actual solution is at the top
 */
public class Main {
	public static void main(String[] args) {
		InputReader in = new InputReader(System.in);
		PrintWriter out = new PrintWriter(new BufferedWriter(new OutputStreamWriter(System.out)), true);
		TaskB solver = new TaskB();
		solver.solve(1, in, out);
		out.flush();
		out.close();
	}
}

class Pair<A, B> {
	A first;
	B second;

	Pair(A first, B second) {
		this.first = first;
		this.second = second;
	}

}

class TaskB {
	long INF = (long) 1e18 + 5;
	long mod = (long) 1e9 + 7;

	public void solve(int testNumber, InputReader in, PrintWriter pw) {
		int n = in.nextInt();
		int arr[] = new int[n];
		long val[] = new long[n];
		for (int i = 0; i < arr.length; i++) {
			arr[i] = in.nextInt();
		}
		for (int i = 0; i < arr.length; i++) {
			val[i] = in.nextLong();
		}
		long dp[] = new long[n + 1];
		// maximum beauty ending with the height i
		for (int i = 0; i < n; i++) {
			for (int height = 0; height < arr[i]; height++) {
				dp[arr[i]] = Math.max(dp[arr[i]], val[i] + dp[height]);
			}
		}
//		pw.println(Arrays.toString(dp));
		long ans = -1;
		for (int i = 0; i <= n; i++) {
			ans = Math.max(ans, dp[i]);
		}
		pw.println(ans);
	}

	long fib(int N) {
		long fib[] = new long[N + 1];
		fib[0] = 1;
		fib[1] = 1;
		for (int i = 2; i <= N; i++) {
			fib[i] = (fib[i - 1] + fib[i - 2]) % mod;
		}
		return fib[N] % mod;
	}

	long sum(int i, int j, long arr[]) {
		long sum = 0;
		for (int k = i; k <= j; k++) {
			sum += arr[k];
		}
		return sum;
	}

	boolean FirstRow_Col(Pair<Integer, Integer> pair) {
		return pair.first == 0 || pair.second == 0;
	}

	int __gcd(int a, int b) {
		if (b == 0)
			return a;
		return __gcd(b, a % b);

	}

	public int getInt(int num) {
		int ret = -1;
		switch (num) {
		case 0:
			ret = 6;
			break;
		case 1:
			ret = 2;
			break;
		case 2:
			ret = 5;
			break;
		case 3:
			ret = 5;
			break;
		case 4:
			ret = 4;
			break;
		case 5:
			ret = 5;
			break;
		case 6:
			ret = 6;
			break;
		case 7:
			ret = 3;
			break;
		case 8:
			ret = 7;
			break;
		case 9:
			ret = 6;
			break;
		}
		return ret;
	}

	public int isPow(long num) {
		int count = 0;
		while (num > 0) {
			num /= 2;
			count++;
		}
		return count;
	}
}

class InputReader {
	BufferedReader br;
	StringTokenizer st;

	public InputReader(InputStream in) {
		br = new BufferedReader(new InputStreamReader(in));
		st = null;
	}

	public String next() {
		while (st == null || !st.hasMoreTokens()) {
			try {
				st = new StringTokenizer(br.readLine());
			} catch (IOException e) {
				throw new RuntimeException(e);
			}
		}
		return st.nextToken();
	}

	public int nextInt() {
		return Integer.parseInt(next());
	}

	public long nextLong() {
		return Long.parseLong(next());
	}

	public double nextDouble() {
		return Double.parseDouble(next());
	}
}