Problem:
Score : 300 points

Problem Statement

You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

1 \leq |S| \leq 2 \times 10^5

|S| = |T|

S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S and T can be made equal, print Yes; otherwise, print No.

Sample Input 1

azzel
apple

Sample Output 1

Yes

azzel can be changed to apple, as follows:

Choose e as c_1 and l as c_2. azzel becomes azzle.

Choose z as c_1 and p as c_2. azzle becomes apple.

Sample Input 2

chokudai
redcoder

Sample Output 2

No

No sequences of operation can change chokudai to redcoder.

Sample Input 3

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu

Sample Output 3

Yes

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.IOException;
public class Main {
    public static void main(String[] args) {
	String s = "";
	String t = "";
	try(BufferedReader br = new BufferedReader(new InputStreamReader(System.in))) {
	    s = br.readLine();
	    t = br.readLine();
	} catch(IOException e) {
	    e.printStackTrace();
	}
	String alphabet = "abcdefghijklmnopqrstuvwxyz";
	int len = s.length();
	for (int i=0;i<26;i++) {
	    String ab = alphabet.substring(i,i+1);
	    int idx = -1;
	    idx = s.indexOf(ab,idx+1);
	    if (idx >= 0) {
		String t1 = t.substring(idx,idx+1);
		while (idx < len) {
		    idx = s.indexOf(ab,idx+1);
		    if (idx < 0) break;
		    String t2 = t.substring(idx,idx+1);
		    if (!t1.equals(t2)) {
			System.out.println("No");
			System.exit(0);
		    }
		}
	    }
	    idx = -1;
	    idx = t.indexOf(ab,idx+1);
	    if (idx >= 0) {
		String s1 = s.substring(idx,idx+1);
		while (idx < len) {
		    idx = t.indexOf(ab,idx+1);
		    if (idx < 0) break;
		    String s2 = s.substring(idx,idx+1);
		    if (!s1.equals(s2)) {
			System.out.println("No");
			System.exit(0);
		    }
		}
	    }
	}
	System.out.println("Yes");
    }
}