Problem:
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Maximum Profit

You can obtain profits from foreign exchange margin transactions. For example, if you buy 1000 dollar at a rate of 100 yen per dollar, and sell them at a rate of 108 yen per dollar, you can obtain (108 - 100) × 1000 = 8000 yen.

Write a program which reads values of a currency $R_t$ at a certain time $t$ ($t = 0, 1, 2, ... n-1$), and reports the maximum value of $R_j - R_i$ where $j > i$ .

Input

The first line contains an integer $n$. In the following $n$ lines, $R_t$ ($t = 0, 1, 2, ... n-1$) are given in order.

Output

Print the maximum value in a line.

Constraints

$2 \leq n \leq 200,000$

$1 \leq R_t \leq 10^9$

Sample Input 1

6
5
3
1
3
4
3

Sample Output 1

3

Sample Input 2

3
4
3
2

Sample Output 2

-1

Solution in JAVA (judge verdict: Wrong Answer)

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
import java.util.Scanner;

/**
 * Created by martin-d28jp-love on 15/04/01.
 */
public class Main {

    public static void main(String[] args) {
//        int[] input = input();
        int[] input = mockuop();

        int inputLength = input.length;
        int minValue = Integer.MAX_VALUE;
        int maxValue = -Integer.MAX_VALUE;
        int minIndex = 0;
        int maxIndex = 0;
        for (int i=1; i < inputLength; i++) {
            int Ri = input[i];
            if (Ri < minValue) {
                minValue = Ri;
                minIndex = i;
            }
            if (Ri > maxValue) {
                maxValue = Ri;
                maxIndex = i;
            }
        }
        if (minIndex < maxIndex) {
            System.out.println(maxValue - minValue);
            return;
        }

        int maxSubtruction = -Integer.MAX_VALUE;
        int maxSubtructionIndex = 1;
        int beforeSubtructionRi = Integer.MAX_VALUE;
        for (int i = 1; i < inputLength - 1; i++) {
            int Ri = input[i];
            if (beforeSubtructionRi < Ri) {
                continue;
            }
            int start = maxSubtructionIndex > i + 1 ? maxSubtructionIndex : i + 1;
            for (int j = start; j < inputLength; j++) {
                int Rj = input[j];
                if (Rj - Ri > maxSubtruction) {
                    maxSubtruction = Rj - Ri;
                    maxSubtructionIndex = j;
                    beforeSubtructionRi = Ri;
                }
            }
        }
        System.out.println(maxSubtruction);
    }

    public static int[] mockuop() {
        int input[] = {20,100,99,95,86,85,76,75,71,70,61,52,48,47,43,42,38,37,33,32,28};
        return input;
    }

    public static int[] input() {
        Scanner in = new Scanner(System.in);
        int size = Integer.valueOf(in.nextLine());

        int[] input = new int[size];
        int i = 0;
        while(in.hasNext()) {
            input[i++] = Integer.valueOf(in.nextLine());
        }
        in.close();
        return input;
    }
}