Problem:
Score : 400 points

Problem Statement

Takahashi will play a game using a piece on an array of squares numbered 1, 2, \cdots, N. Square i has an integer C_i written on it. Also, he is given a permutation of 1, 2, \cdots, N: P_1, P_2, \cdots, P_N.

Now, he will choose one square and place the piece on that square. Then, he will make the following move some number of times between 1 and K (inclusive):

In one move, if the piece is now on Square i (1 \leq i \leq N), move it to Square P_i. Here, his score increases by C_{P_i}.

Help him by finding the maximum possible score at the end of the game. (The score is 0 at the beginning of the game.)

Constraints

2 \leq N \leq 5000

1 \leq K \leq 10^9

1 \leq P_i \leq N

P_i \neq i

P_1, P_2, \cdots, P_N are all different.

-10^9 \leq C_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
P_1 P_2 \cdots P_N
C_1 C_2 \cdots C_N

Output

Print the maximum possible score at the end of the game.

Sample Input 1

5 2
2 4 5 1 3
3 4 -10 -8 8

Sample Output 1

8

When we start at some square of our choice and make at most two moves, we have the following options:

If we start at Square 1, making one move sends the piece to Square 2, after which the score is 4. Making another move sends the piece to Square 4, after which the score is 4 + (-8) = -4.

If we start at Square 2, making one move sends the piece to Square 4, after which the score is -8. Making another move sends the piece to Square 1, after which the score is -8 + 3 = -5.

If we start at Square 3, making one move sends the piece to Square 5, after which the score is 8. Making another move sends the piece to Square 3, after which the score is 8 + (-10) = -2.

If we start at Square 4, making one move sends the piece to Square 1, after which the score is 3. Making another move sends the piece to Square 2, after which the score is 3 + 4 = 7.

If we start at Square 5, making one move sends the piece to Square 3, after which the score is -10. Making another move sends the piece to Square 5, after which the score is -10 + 8 = -2.

The maximum score achieved is 8.

Sample Input 2

2 3
2 1
10 -7

Sample Output 2

13

Sample Input 3

3 3
3 1 2
-1000 -2000 -3000

Sample Output 3

-1000

We have to make at least one move.

Sample Input 4

10 58
9 1 6 7 8 4 3 2 10 5
695279662 988782657 -119067776 382975538 -151885171 -177220596 -169777795 37619092 389386780 980092719

Sample Output 4

29507023469

The absolute value of the answer may be enormous.

Solution in Java (OpenJDK 11.0.6) (judge verdict: Wrong Answer)

import java.io.IOException;
import java.io.InputStream;
import java.util.Arrays;
import java.util.HashSet;
import java.util.NoSuchElementException;
import java.util.Objects;
import java.util.Random;
import java.util.Scanner;
import java.util.Set;
import java.util.TreeSet;
class BIT{
	long bit[]=new long[0];
	int N=0;
	BIT(int n){
		bit=new long[n+1];
		N=n;
	}
	void add(int a,long w) {
		for(int x=a;x<N;x+=(x&-x)) bit[x]+=w;
	}
	long sum(int a) {
		long ret=0;
		for(int x=a;x>0;x-=x&-x)ret+=bit[x];
		return ret;
	}
	long modsum(int a,int mod) {
		long ret=0;
		for(int x=a;x>0;x-=x&-x) {
			ret+=bit[x];
			ret%=mod;
		}
		return ret;
	}
}
class FastScanner {
	private final InputStream in = System.in;
	private final byte[] buffer = new byte[1024];
	private int ptr = 0;
	private int buflen = 0;
	private boolean hasNextByte() {
		if (ptr < buflen) {
			return true;
		} else {
			ptr = 0;
			try {
				buflen = in.read(buffer);
			} catch (IOException e) {
				e.printStackTrace();
			}
			if (buflen <= 0) {
				return false;
			}
		}
		return true;
	}
	private int readByte() {
		if (hasNextByte())
			return buffer[ptr++];
		else
			return -1;
	}
	private static boolean isPrintableChar(int c) {
		return 33 <= c && c <= 126;
	}
	public boolean hasNext() {
		while (hasNextByte() && !isPrintableChar(buffer[ptr]))
			ptr++;
		return hasNextByte();
	}
	public String next() {
		if (!hasNext())
			throw new NoSuchElementException();
		StringBuilder sb = new StringBuilder();
		int b = readByte();
		while (isPrintableChar(b)) {
			sb.appendCodePoint(b);
			b = readByte();
		}
		return sb.toString();
	}
	public long nextLong() {
		if (!hasNext())
			throw new NoSuchElementException();
		long n = 0;
		boolean minus = false;
		int b = readByte();
		if (b == '-') {
			minus = true;
			b = readByte();
		}
		if (b < '0' || '9' < b) {
			throw new NumberFormatException();
		}
		while (true) {
			if ('0' <= b && b <= '9') {
				n *= 10;
				n += b - '0';
			} else if (b == -1 || !isPrintableChar(b)) {
				return minus ? -n : n;
			} else {
				throw new NumberFormatException();
			}
			b = readByte();
		}
	}
	public int nextInt() {
		long nl = nextLong();
		if (nl < Integer.MIN_VALUE || nl > Integer.MAX_VALUE)
			throw new NumberFormatException();
		return (int) nl;
	}
	public double nextDouble() {
		return Double.parseDouble(next());
	}
	public char nextchar() {
		return next().charAt(0);
	}
}

class UnionFind {
	int Parent[];
	UnionFind(int n) {// Initialize by -1
		Parent = new int[n];
		Arrays.fill(Parent, -1);
	}
	int root(int A) {// In which tree is A?
		if (Parent[A] < 0)
			return A;
		return Parent[A] = root(Parent[A]);
	}
	int size(int A) {// size of tree which is include A
		return -Parent[root(A)];
	}
	boolean connect(int A, int B) {// Connect A and B
		A = root(A);
		B = root(B);
		if (A == B)
			return false;
		if (size(A) < size(B)) {
			int C = 0;
			C = B;
			B = A;
			A = C;
		} // SWAP
		Parent[A] += Parent[B];
		Parent[B] = A;
		return true;
	}
}

class Pair<T, E> {
	public T first;
	public E second;
	void set(T x, E y) {
		first = x;
		second = y;
	}
}

class Pint {
	@Override
	public boolean equals(Object obj) {
		if(obj instanceof Pint) {
			Pint other = (Pint) obj;
			return other.first==this.first&&other.second==this.second;
		}
		return false;
	}
	@Override
	public int hashCode() {
		return Objects.hash(this.first,this.second);
	}
	public int first;
	public int second;
	Pint(int x, int y) {
		first = x;
		second = y;
	}
	void set(int x, int y) {
		first = x;
		second = y;
	}
}

class Tpair {
	public int first;
	public int second;
	public long third;
	Tpair(int x, int y, long z) {
		first = x;
		second = y;
		third = z;
	}
	void set(int x, int y, long z) {
		first = x;
		second = y;
		third = z;
	}
}

public class Main {
	static FastScanner scan = new FastScanner();
	static Scanner scanner = new Scanner(System.in);
	static Random rand = new Random();
	static long mod = 1000000007;
	static double eps = 1.0E-14;
	static int big = Integer.MAX_VALUE;
	static double PI = 3.141592653589793;
	static long modlcm(long a, long b) {
		return a * b * modinv(GCD(a, b), mod);
	}
	static long GCD(long a, long b) {
		return b > 0 ? GCD(b, a % b) : a;
	}
	static long lcm(long a, long b) {
		return a * b / GCD(a, b);
	}
	static int min(int a, int b) {
		return a < b ? a : b;
	}
	static long factorial(int i) {
		return i == 1 ? 1 : i * factorial(i - 1);
	}
	static int max(int... i) {
		int x = i[0];
		for (int e : i)
			x = Math.max(x, e);
		return x;
	}
	static int min(int... i) {
		int x = i[0];
		for (int e : i)
			x = Math.min(x, e);
		return x;
	}
	static long gcd(long... i) {
		long x = i[0];
		for (long e : i)
			x = GCD(x, e);
		return x;
	}
	static long lmax(long... i) {
		long x = i[0];
		for (long e : i)
			x = Math.max(x, e);
		return x;
	}
	static long lmin(long... i) {
		long x = i[0];
		for (long e : i)
			x = Math.min(x, e);
		return x;
	}
	static long nCr(long n, long r, long m) {
		long ans = 1;
		for (long i = 0; i < r; i++) {
			ans *= (n - i);
			ans %= m;
		}
		for (long i = 0; i <= r; i++) {
			ans *= modinv(i, m);
			ans %= mod;
		}
		return ans;
	}
	static int lower_bound(int[] b, long cost) {
		int ok = b.length;
		int ng = -1;
		while (Math.abs(ok - ng) > 1) {
			int mid = (ok + ng) / 2;
			if (b[mid] >= cost)
				ok = mid;
			else
				ng = mid;
		}
		return ok;
	}
	static int upper_bound(int[] b, int cost) {
		int ok = b.length;
		int ng = -1;
		while (Math.abs(ok - ng) > 1) {
			int mid = (ok + ng) / 2;
			if (b[mid] > cost)
				ok = mid;
			else
				ng = mid;
		}
		return ok;
	}
	static boolean isPrime(long n) {
		if (n == 2)
			return true;
		if (n < 2 || n % 2 == 0)
			return false;
		double d = Math.sqrt(n);
		for (int i = 3; i <= d; i += 2)
			if (n % i == 0) {
				return false;
			}
		return true;
	}
	static int upper_division(int a, int b) {
		if (a % b == 0) {
			return a / b;
		} else {
			return a / b + 1;
		}
	}
	static long lupper_division(long a, long b) {
		if (a % b == 0) {
			return a / b;
		} else {
			return a / b + 1;
		}
	}
	static int[] setArray(int a) {
		int b[] = new int[a];
		for (int i = 0; i < a; i++) {
			b[i] = scan.nextInt();
		}
		return b;
	}
	static long[] lsetArray(int a) {
		long b[] = new long[a];
		for (int i = 0; i < a; i++) {
			b[i] = scan.nextLong();
		}
		return b;
	}
	static String reverse(String str) {
		char ch[] = new char[str.length()];
		char chch[] = str.toCharArray();
		int a = str.length();
		for (int i = 0; i < upper_division(a, 2); i++) {
			ch[i] = chch[ch.length - i - 1];
			ch[ch.length - 1 - i] = chch[i];
		}
		return String.valueOf(ch);
	}
	public static void printArray(int[] que) {
		for (int i = 0; i < que.length - 1; i++) {
			System.out.print(que[i] + " ");
		}
		System.out.println(que[que.length - 1]);
	}
	public static void lprintArray(long[] que) {
		for (int i = 0; i < que.length - 1; i++) {
			System.out.print(que[i] + " ");
		}
		System.out.println(que[que.length - 1]);
	}
	public static int[][] doublesort(int[][] a) {
		Arrays.sort(a, (x, y) -> Integer.compare(x[0], y[0]));
		return a;
	}
	public static long[][] ldoublesort(long[][] a) {
		Arrays.sort(a, (x, y) -> Long.compare(x[0], y[0]));
		return a;
	}
	static long modpow(long x, long n, long mo) {
		long sum = 1;
		while (n > 0) {
			if ((n & 1) == 1) {
				sum = sum * x % mo;
			}
			x = x * x % mo;
			n >>= 1;
		}
		return sum;
	}
	public static char[] revch(char ch[]) {
		char ret[] = new char[ch.length];
		for (int i = ch.length - 1, j = 0; i >= 0; i--, j++) {
			ret[j] = ch[i];
		}
		return ret;
	}
	public static int[] revint(int ch[]) {
		int ret[] = new int[ch.length];
		for (int i = ch.length - 1, j = 0; i >= 0; i--, j++) {
			ret[j] = ch[i];
		}
		return ret;
	}
	public static void warshall_floyd(long v[][]) {
		int n=v[0].length;
		for (int k = 0; k < n; k++)
			for (int i = 0; i < n; i++)
				for (int j = 0; j < n; j++)
					v[i][j] = lmin(v[i][j], v[i][k] + v[k][j]);
	}
	public static long modinv(long a, long m) {
		long b = m, u = 1, v = 0;
		while (b != 0) {
			long t = a / b;
			a -= t * b;
			long x = a;
			a = b;
			b = x;
			u -= t * v;
			x = u;
			u = v;
			v = x;
		}
		u %= m;
		if (u < 0)
			u += m;
		return u;
	}
	public static long lmod(long i, long j) {
	    return (i%j)<0?(i%j)+0+(j<0?-j:j):(i%j+0);
	}
	public static int next_combination(int sub) {
	    int x = sub & -sub, y = sub + x;
	    return (((sub & ~y) / x) >> 1) | y;
	}
	public static void main(String[] $) throws IOException{
		long n=scan.nextInt();
		long k=scan.nextInt();
		long p[]=new long[(int)n];
		long c[]=new long[(int)n];
		for(int i=0;i<n;i++) {
			long x=scan.nextInt()-1;
			p[i]=x;
		}
		for(int i=0;i<n;i++) {
			c[i]=scan.nextInt();
		}
		long d[][]=new long[(int)n][2];
		for(int i=0;i<n;i++) {
			long D=c[(int)p[i]];
			long now=p[i];
			d[i][1]=D;
			long cnt=1;
			while(now!=i) {
				D+=c[(int)p[(int)now]];
				now=p[(int)now];
				cnt++;
			}
			d[i][0]=D;
			d[i][1]=cnt;
		}
		long ans=0;
		if(d[0][0]<=0) {
			long now=0;
			long max=Long.MIN_VALUE;
			long C=0;
			for(int i=0;i<d[0][1];i++) {
				C+=c[(int)p[(int)now]];
				max=lmax(C,max);
				now=p[(int)now];
			}
			ans=max;
		}
		else{
			long can=k/d[0][1]-(k%d[0][1]==0?1:0);
			long cost=can*d[0][0];
			long nokori=k-can*d[0][1];
			long now=0;
			long max=0;
			long C=0;
			for(int i=0;i<nokori;i++) {
				C+=c[(int)p[(int)now]];
				max=lmax(C,max);
				now=p[(int)now];
			}
			cost+=max;
			ans=cost;
		}
		for(int i=1;i<n;i++) {
			long cost=0;
			if(d[i][0]<=0) {
				long now=i;
				long max=Long.MIN_VALUE;
				long C=0;
				for(int j=0;j<d[0][1];j++) {
					C+=c[(int)p[(int)now]];
					max=lmax(C,max);
					now=p[(int)now];
				}
				ans=lmax(ans,max);
			}
			else {
				long can=k/d[i][1]-(k%d[0][1]==0?1:0);
				cost=can*d[i][0];
				long nokori=k-can*d[i][1];
				long now=i;
				long max=0;
				long C=0;
				for(int j=0;j<nokori;j++) {
					C+=c[(int)p[(int)now]];
					max=lmax(C,max);
					now=p[(int)now];
				}
				cost+=max;
				ans=lmax(ans,cost);
			}
		}
		System.out.println(ans);
	}
}