Problem:
Simultaneous Equation

Write a program which solve a simultaneous equation:

ax + by = c

dx + ey = f

The program should print x and y for given a, b, c, d, e and f (-1,000 ≤ a, b, c, d, e, f ≤ 1,000). You can suppose that given equation has a unique solution.

Input

The input consists of several data sets, 1 line for each data set. In a data set, there will be a, b, c, d, e, f separated by a single space. The input terminates with EOF.

Output

For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.

Sample Input 1

1 2 3 4 5 6
2 -1 -2 -1 -1 -5

Output for the Sample Input 1

-1.000 2.000
1.000 4.000

Sample Input 2

2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27

Output for the Sample Input 2

0.000 3.000
0.000 3.000

Solution in JAVA (judge verdict: Wrong Answer)

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.text.DecimalFormat;
import java.util.ArrayList;
import java.util.List;


public class Main {
	public static void main(String[] args)throws IOException {
		
		BufferedReader buf= new BufferedReader(new InputStreamReader(System.in));
		DecimalFormat df=new DecimalFormat("0.000");
		int a,b,c,d,e,f;
		float x,y;
		List<String> xlist=new ArrayList<String>();
		List<String> ylist=new ArrayList<String>();
		
		String line;
		while((line=buf.readLine())!=null){
			a=Integer.parseInt(line.split(" ")[0]);
			b=Integer.parseInt(line.split(" ")[1]);
			c=Integer.parseInt(line.split(" ")[2]);
			d=Integer.parseInt(line.split(" ")[3]);
			e=Integer.parseInt(line.split(" ")[4]);
			f=Integer.parseInt(line.split(" ")[5]);
			
			x=(e*c-b*f)/(e*a-b*d);
			y=(d*c-a*f)/(d*b-a*e);
			//Integer ix= Integer.valueOf((Intger)x);
			//Integer iy= Integer.valueOf(y);
			xlist.add(df.format(x));
			ylist.add(df.format(y));
		}
		
		for(int i=0;i<xlist.size();i++){
			System.out.println(xlist.get(i)+" "+ylist.get(i));
		}
		
	}
}