Problem:
Score : 100 points

Problem Statement

A biscuit making machine produces B biscuits at the following moments: A seconds, 2A seconds, 3A seconds and each subsequent multiple of A seconds after activation.

Find the total number of biscuits produced within T + 0.5 seconds after activation.

Constraints

All values in input are integers.

1 \leq A, B, T \leq 20

Input

Input is given from Standard Input in the following format:

A B T

Output

Print the total number of biscuits produced within T + 0.5 seconds after activation.

Sample Input 1

3 5 7

Sample Output 1

10

Five biscuits will be produced three seconds after activation.

Another five biscuits will be produced six seconds after activation.

Thus, a total of ten biscuits will be produced within 7.5 seconds after activation.

Sample Input 2

3 2 9

Sample Output 2

6

Sample Input 3

20 20 19

Sample Output 3

0

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
import java.util.Scanner;
import java.util.function.Consumer;
import java.util.stream.Collectors;

public class Main {
    private static final Scanner scanner = new Scanner(System.in);
    private static final Consumer<List<String>> consumer = solve();

    public static void main(String[] args) {
        consumer.accept(readInput());
    }

    private static List<String> readInput() {
        final List<String> lineList = new ArrayList<>();
        while (scanner.hasNextLine()) {
            lineList.add(scanner.nextLine());
        }
        return lineList;
    }

    private static Consumer<List<String>> solve() {
        return args -> {
			final List<Integer> numList = Arrays.stream(args.get(0).split(" ")).map(Integer::valueOf).collect(Collectors.toList());
			System.out.println((numList.get(2) / numList.get(0)) * numList.get(1));
        };
    }

}