Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.*;
public class Main {
	public static void main(String[] args){
		Scanner sc = new Scanner(System.in);
		
		int N = sc.nextInt();
		
		
		
		int count = 0;
		int num = 0;
		int numplus = 0;
		int divisor_count = 0;
		int Ncount = 0;
		
		
		
		for (Ncount = 1; Ncount <= N; Ncount = Ncount + 2){
			num = Ncount;
			for (numplus = 1; num >= numplus; numplus++){
				if (num % numplus == 0){
					count++;
				}
				
			}
			numplus = 0;
			
			if (count == 8){
				divisor_count++;
			}
			count = 0;
		}
		
		
		System.out.println(divisor_count);
		
	}
}