Problem:
Score : 300 points

Problem Statement

Given is a permutation P_1, \ldots, P_N of 1, \ldots, N.
Find the number of integers i (1 \leq i \leq N) that satisfy the following condition:

For any integer j (1 \leq j \leq i), P_i \leq P_j.

Constraints

1 \leq N \leq 2 \times 10^5

P_1, \ldots, P_N is a permutation of 1, \ldots, N.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
P_1 ... P_N

Output

Print the number of integers i that satisfy the condition.

Sample Input 1

5
4 2 5 1 3

Sample Output 1

3

i=1, 2, and 4 satisfy the condition, but i=3 does not - for example, P_i > P_j holds for j = 1.

Similarly, i=5 does not satisfy the condition, either. Thus, there are three integers that satisfy the condition.

Sample Input 2

4
4 3 2 1

Sample Output 2

4

All integers i (1 \leq i \leq N) satisfy the condition.

Sample Input 3

6
1 2 3 4 5 6

Sample Output 3

1

Only i=1 satisfies the condition.

Sample Input 4

8
5 7 4 2 6 8 1 3

Sample Output 4

4

Sample Input 5

1
1

Sample Output 5

1

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Time Limit Exceeded)

import java.util.Scanner;

public class Main	 {

	public static void main(String[] args) {
		// TODO 自動生成されたメソッド・スタブ
		Scanner scan = new Scanner(System.in);
		int N = scan.nextInt();
		int P[] = new int[N];
		int sum = 1;
		boolean flag = true;
		for(int i=0; i < N; i++) {
		P[i] = scan.nextInt();
		}
		int pre_min = P[0];


		for(int i=1; i<N; i++) {
			for(int j=1; j<i+1; j++) {
			flag = true;
			if(P[i] > pre_min) {
				flag = false;
				break;
			}
			/*
			if(P[i] > P[j-1]) {
				flag = false;
				break;
			}
			*/
			if(P[i] == 0) {
				flag = true;
				break;
			}
		}
			if(flag == true) {
				sum += 1;
				pre_min = P[i];
			}
		}
		System.out.print(sum);


	}

}