Problem:
Score : 200 points

Problem Statement

We have a string S consisting of uppercase English letters. Additionally, an integer N will be given.

Shift each character of S by N in alphabetical order (see below), and print the resulting string.

We assume that A follows Z. For example, shifting A by 2 results in C (A \to B \to C), and shifting Y by 3 results in B (Y \to Z \to A \to B).

Constraints

0 \leq N \leq 26

1 \leq |S| \leq 10^4

S consists of uppercase English letters.

Input

Input is given from Standard Input in the following format:

N
S

Output

Print the string resulting from shifting each character of S by N in alphabetical order.

Sample Input 1

2
ABCXYZ

Sample Output 1

CDEZAB

Note that A follows Z.

Sample Input 2

0
ABCXYZ

Sample Output 2

ABCXYZ

Sample Input 3

13
ABCDEFGHIJKLMNOPQRSTUVWXYZ

Sample Output 3

NOPQRSTUVWXYZABCDEFGHIJKLM

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Scanner;

public class Main {
	public static void main(String[]args) {//A ~Z 65~90
		
		try(Scanner scan = new Scanner(System.in)){
			int N = scan.nextInt();
			String S = scan.next();
			char []s = new char[N];
			s = S.toCharArray();
			
			 
			StringBuffer sb = new StringBuffer();
			
			for(int i = 0;i<S.length();i++) {
				int k = (int)s[i]+N;
				if(k>90) {
					k = (k-90)+64;
				}
				
				s[i] = (char)k;
				sb.append(s[i]);
			}
			
			
			System.out.println(sb.toString());
			
			
			
			
		}
		
		
		
		
	}
	
}