Problem:
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Matrix Multiplication

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\[
c_{ij} = \sum_{k=1}^m a_{ik}b_{kj}
\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Constraints

$1 \leq n, m, l \leq 100$

$0 \leq a_{ij}, b_{ij} \leq 10000$

Sample Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2

Sample Output

1 8 5
0 9 6
4 23 14

Note

      解説

Solution in JAVA (judge verdict: WA: Presentation Error)

import java.io.*;
import java.util.*;
import java.lang.*;

class Main{
  public static void main(String[] args) throws IOException{
    Scanner scan=new Scanner(System.in);
    int n=Integer.parseInt(scan.next());
    int m=Integer.parseInt(scan.next());
    int l=Integer.parseInt(scan.next());
    int[][] arrayA=new int[n][m];
    for(int i=0;i<arrayA.length;i++){
      for(int j=0;j<arrayA[i].length;j++){
        arrayA[i][j]=Integer.parseInt(scan.next());
      }
    }
    int[][] arrayB=new int[m][l];
    for(int i=0;i<arrayB.length;i++){
      for(int j=0;j<arrayB[i].length;j++){
        arrayB[i][j]=Integer.parseInt(scan.next());
      }
    }

    int[][] arrayC=new int[n][l];
    for(int i=0;i<n;i++){
      for(int j=0;j<l;j++){
        for(int k=0;k<m;k++){
          arrayC[i][j]+=arrayA[i][k]*arrayB[k][j];
        }
      }
    }

    for(int i=0;i<arrayC.length;i++){
      for(int j=0;j<arrayC[i].length;j++){
        System.out.print(arrayC[i][j]);
        if(j<arrayC[i].length-1){
          System.out.printf(" ");
        }
      }
      if(i<arrayC.length-1)System.out.println();
    }
  }
}