Problem:
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Circles Intersection

You are given circle $A$ with radius $r_a$ and with central coordinate $(x_a, y_a)$ and circle $B$ with radius $r_b$ and with central coordinate $(x_b, y_b)$.

Write a program which prints:

"2" if $B$ is in $A$,

"-2" if $A$ is in $B$,

"1" if circumference of $A$ and $B$ intersect, and

"0" if $A$ and $B$ do not overlap.

You may assume that $A$ and $B$ are not identical.

Input

The input consists of multiple datasets. The first line consists of an integer $N$ ($N \leq 50$), the number of datasets. There will be $N$ lines where each line represents each dataset. Each data set consists of real numbers:

$x_a$ $y_a$ $r_a$ $x_b$ $y_b$ $r_b$

Output

For each dataset, print 2, -2, 1, or 0 in a line.

Sample Input

2
0.0 0.0 5.0 0.0 0.0 4.0
0.0 0.0 2.0 4.1 0.0 2.0

Output for the Sample Input

2
0

Solution in JAVA (judge verdict: Wrong Answer)

import java.io.*;

public class Main{
	public static void main(String args[]) throws IOException{
		BufferedReader br = new BufferedReader(
				new InputStreamReader(System.in));
		int N = Integer.parseInt(br.readLine());
		Double data[] = new Double[6];
		String str;
		int result[] = new int[N];
		for(int i = 0; i < N; i++){
			str = br.readLine();
			String predata[] = str.split(" ",0);
			for(int j = 0; j < predata.length; j++){
				data[j] = Double.parseDouble(predata[j]);
			}
			double d = Math.sqrt(((data[0]-data[3])*(data[0]-data[3]))+((data[1]-data[4])*(data[1]-data[4])));
			if(d > data[2]+data[5]){
				result[i] = 0;
			} else {
				if(data[2] < data[5]){
					if(d + data[2] < data[5]){
						result[i] = -2;
					} else {
						result[i] = 1;
					}
				}
				if(data[2] > data[5]){
					if(d + data[5] < data[2]){
						result[i] = 2;
					} else {
						result[i] = 1;	
					}
				}
			}
		}
		for(int i = 0; i < N; i++){
			System.out.println(result[i]);
		}
	}
}