Problem:
Score : 400 points

Problem Statement

Given is an integer S.
Find a combination of six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfies all of the following conditions:

0 \leq X_1,Y_1,X_2,Y_2,X_3,Y_3 \leq 10^9

The area of the triangle in a two-dimensional plane whose vertices are (X_1,Y_1),(X_2,Y_2), and (X_3,Y_3) is S/2.

We can prove that there always exist six integers that satisfy the conditions under the constraints of this problem.

Constraints

1 \leq S \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

S

Output

Print six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfy the conditions, in this order, with spaces in between.
If multiple solutions exist, any of them will be accepted.

Sample Input 1

3

Sample Output 1

1 0 2 2 0 1

The area of the triangle in a two-dimensional plane whose vertices are (1,0),(2,2), and (0,1) is 3/2.
Printing 3 0 3 1 0 1 or 1 0 0 1 2 2 will also be accepted.

Sample Input 2

100

Sample Output 2

0 0 10 0 0 10

Sample Input 3

311114770564041497

Sample Output 3

314159265 358979323 846264338 327950288 419716939 937510582

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.*;

public class Main {
    public static void main(String[] args) {
        Scanner sc=new Scanner(System.in);
        long n=Long.parseLong(sc.next());
        long n2=n;
        int ans=0;
        boolean c=(n%4==2);
        ArrayList<Integer>bunkai=new ArrayList<>();
        for(int i=2;i*i<=n;i++){
            while(n%i==0){
                n/=i;
                bunkai.add(i);
            }
        }
        if(n!=1)bunkai.add((int)n);
        Collections.sort(bunkai);
        int ans1=1;
        int ans2=1;
        for(int i=bunkai.size()-1;i>=0;i--){
            if(ans1>ans2){
                ans2*=bunkai.get(i);
            }
            else{
                ans1*=bunkai.get(i);
            }
        }
            if((ans1+ans2)%2==0){
                
            int x=(ans2+ans1)/2;
            int y=Math.abs((ans2-ans1))/2;
            System.out.println("0 0 "+x+" "+y+" "+y+" "+x);
            }
            else System.out.println("0 0 "+ans1+" 0 0 "+ans2);
   
    }
    
}