Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        new Main().run();
    }

    int N;
    int A;
    int B;
    int C;
    int D;
    byte[] S;

    private void run() {
        Scanner scanner = new Scanner(System.in);
        N = scanner.nextInt();
        A = scanner.nextInt() - 1;
        B = scanner.nextInt() - 1;
        C = scanner.nextInt() - 1;
        D = scanner.nextInt() - 1;
        S = scanner.next().getBytes();

        int time = 0;
        if (!check()) {
            System.out.println("No");
            return;
        }

        boolean ok = check2(time, A, B, C, D);
        if (ok) {
            System.out.println("Yes");
            return;
        } else {
            System.out.println("No");
            return;
        }
    }

    private boolean check() {
        for (int i = A; i < C - 1; i++) {
            if (S[i] == 35 && S[i + 1] == 35) {
                return false;
            }
        }
        for (int i = B; i < D - 1; i++) {
            if (S[i] == 35 && S[i + 1] == 35) {
                return false;
            }
        }
        return true;
    }

    private boolean check2(int time, int a, int b, int c, int d) {
        if (b >= N - 1 || b > d) {
            if (S[b - 1] != 35 && b - 1 != a) {
                return true;
            }
            return false;
        } else if (S[b] == 35) {
            return false;
        } else if (S[b - 1] != 35 && S[b + 1] != 35 && b - 1 != a) {
            return true;
        } else if (b == d && c > d) {
            if((S[b - 1] == 35 || S[b + 1] == 35)){
                return false;
            }else {
                return true;
            }
        }
        return check2(time, a, b + 1, c, d) ||
                check2(time, a, b + 2, c, d);
    }
}