Problem:
Score : 200 points

Problem Statement

For a string S consisting of the uppercase English letters P and D, let the doctoral and postdoctoral quotient of S be the total number of occurrences of D and PD in S as contiguous substrings. For example, if S = PPDDP, it contains two occurrences of D and one occurrence of PD as contiguous substrings, so the doctoral and postdoctoral quotient of S is 3.

We have a string T consisting of P, D, and ?.

Among the strings that can be obtained by replacing each ? in T with P or D, find one with the maximum possible doctoral and postdoctoral quotient.

Constraints

1 \leq |T| \leq 2 \times 10^5

T consists of P, D, and ?.

Input

Input is given from Standard Input in the following format:

T

Output

Print one string with the maximum possible doctoral and postdoctoral quotient among the strings that can be obtained by replacing each ? in T with P or D.
If there are multiple such strings, you may print any of them.

Sample Input 1

PD?D??P

Sample Output 1

PDPDPDP

This string contains three occurrences of D and three occurrences of PD as contiguous substrings, so its doctoral and postdoctoral quotient is 6, which is the maximum doctoral and postdoctoral quotient of a string obtained by replacing each ? in T with P or D.

Sample Input 2

P?P?

Sample Output 2

PDPD

Solution in Java (OpenJDK 11.0.6) (judge verdict: Time Limit Exceeded)

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.*;

public class Main {
    private static final int MOD = (int) Math.pow(10, 9);
    private static final int[][] DIRS = {{0, 1}, {0, -1}, {1, 0}, {-1, 0}};

    public static void main(String[] args) {
        FastReader sc = new FastReader();
        String s = sc.next();
        String res = "";

        for (int i = 0; i < s.length(); i++) {
            char c = s.charAt(i);

            if (c == '?') {
                if (i == 0) {
                    res += "D";
                } else {
                    if (s.charAt(i - 1) == 'P') {
                        res += "D";
                    } else {
                        res += "D";
                    }
                }
            } else {
                res += c;
            }
        }


        print(""+res);
        System.exit(0);
    }

    static private void swap(int[] nums, int x, int y) {
        int tmp = nums[x];
        nums[x] = nums[y];
        nums[y] = tmp;
    }

    static  private void reverse(int[] nums, int left, int right) {
        while (left < right) {
            swap(nums, left, right);
            left++;
            right--;
        }
    }

    static private boolean findNextPermutation(int[] nums) {
        if (nums.length <= 1) {
            return false;
        }

        int last = nums.length - 2;

        while (last >= 0) {
            if (nums[last] < nums[last + 1]){
                break;
            }
            last--;
        }

        if (last < 0) { return false; }
        int nextGenerater = nums.length - 1;

        for (int i = nums.length - 1; i > last; i--) {
            if (nums[i] > nums[last]) {
                nextGenerater = i;
                break;
            }
        }

        swap(nums, nextGenerater, last);
        reverse(nums, last + 1, nums.length - 1);
        return true;
    }

    static private int[] generateNArray(int n) {
        int[] res = new int[n];

        for (int i = 0; i < n; i++) {
            res[i] = i + 1;
        }

        return res;
    }

    static  private void print(String s) {
        System.out.println(s);
    }

    static private void printArray(int[] e) {
        for (int s: e) {
            System.out.print(s + " ");
        }
        print("");
    }

    static private int log2(int x) {
        return (int)(Math.log(x) / Math.log(2));
    }

    static private long gcd(long m, long n) {
        if (m < n) { return gcd(n, m); }
        if (m % n == 0) { return n; }
        return gcd(n, m%n);
    }

    static class FastReader {
        BufferedReader br;
        StringTokenizer st;

        public FastReader() {
            br = new BufferedReader(new InputStreamReader(System.in));
        }

        String next() {
            while (st == null || !st.hasMoreElements()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException  e) {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }

        int nextInt() {
            return Integer.parseInt(next());
        }

        long nextLong() {
            return Long.parseLong(next());
        }

        double nextDouble() {
            return Double.parseDouble(next());
        }

        String nextLine() {
            String str = "";
            try{
                str = br.readLine();
            } catch (IOException e) {
                e.printStackTrace();
            }
            return str;
        }
    }
}