Problem:
Score : 300 points

Problem Statement

There are N candles placed on a number line.
The i-th candle from the left is placed on coordinate x_i.
Here, x_1 < x_2 < ... < x_N holds.

Initially, no candles are burning.
Snuke decides to light K of the N candles.

Now, he is at coordinate 0.
He can move left and right along the line with speed 1.
He can also light a candle when he is at the same position as the candle, in negligible time.

Find the minimum time required to light K candles.

Constraints

1 \leq N \leq 10^5

1 \leq K \leq N

x_i is an integer.

|x_i| \leq 10^8

x_1 < x_2 < ... < x_N

Input

Input is given from Standard Input in the following format:

N K
x_1 x_2 ... x_N

Output

Print the minimum time required to light K candles.

Sample Input 1

5 3
-30 -10 10 20 50

Sample Output 1

40

He should move and light candles as follows:

Move from coordinate 0 to -10.

Light the second candle from the left.

Move from coordinate -10 to 10.

Light the third candle from the left.

Move from coordinate 10 to 20.

Light the fourth candle from the left.

Sample Input 2

3 2
10 20 30

Sample Output 2

20

Sample Input 3

1 1
0

Sample Output 3

0

There may be a candle placed at coordinate 0.

Sample Input 4

8 5
-9 -7 -4 -3 1 2 3 4

Sample Output 4

10

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.io.*;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
import java.util.StringTokenizer;


public class Main {


    private void solve(InputReader in, PrintWriter out) {
        int n = in.nextInt();
        int k = in.nextInt();
        int[] arr = new int[n];
        for (int i = 0; i < n; i++) {
            arr[i] = in.nextInt();
        }
        Arrays.sort(arr);
        long sum = 0;
        long min = Long.MAX_VALUE;
        for (int i = 0; i < n - (k - 1); i++) {
            if (arr[i] < 0 && arr[i + (k - 1)] < 0) {
                sum = Math.abs(arr[i]);
            } else if (arr[i] < 0 && arr[i + (k - 1)] > 0) {
                if (Math.abs(arr[i] * 2) <= arr[i + (k - 1)]) {
                    sum = Math.abs(arr[i] * 2) + arr[i + (k - 1)];
                } else {
                    sum = Math.abs(arr[i]) + arr[i + (k - 1)] * 2;
                }
            } else {
                sum = arr[i + (k - 1)];
            }
            min = Math.min(min, sum);

        }
        out.println(min);

    }

    public static void main(String[] args) {
        new Main().run();
    }

    private void run() {
        try (
                InputReader in = new InputReader(System.in);
                PrintWriter out = new PrintWriter(System.out)) {
            solve(in, out);
        }
    }


    static class InputReader implements AutoCloseable {
        private BufferedReader reader;
        private StringTokenizer tokenizer;

        public InputReader(InputStream stream) {
            reader = new BufferedReader(new InputStreamReader(stream), 32768);
            tokenizer = null;
        }

        public String next() {
            while (tokenizer == null || !tokenizer.hasMoreTokens()) {
                try {
                    tokenizer = new StringTokenizer(reader.readLine());
                } catch (IOException e) {
                    throw new RuntimeException(e);
                }
            }
            return tokenizer.nextToken();
        }


        public int nextInt() {
            return Integer.parseInt(next());
        }

        public long nextLong() {
            return Long.parseLong(next());
        }

        public double nextDouble() {
            return Double.parseDouble(next());
        }

        @Override
        public void close() {

        }
    }

}