Problem:
Score : 300 points

Problem Statement

1000000000000001 dogs suddenly appeared under the roof of Roger's house, all of which he decided to keep. The dogs had been numbered 1 through 1000000000000001, but he gave them new names, as follows:

the dogs numbered 1,2,\cdots,26 were respectively given the names a, b, ..., z;

the dogs numbered 27,28,29,\cdots,701,702 were respectively given the names aa, ab, ac, ..., zy, zz;

the dogs numbered 703,704,705,\cdots,18277,18278 were respectively given the names aaa, aab, aac, ..., zzy, zzz;

the dogs numbered 18279,18280,18281,\cdots,475253,475254 were respectively given the names aaaa, aaab, aaac, ..., zzzy, zzzz;

the dogs numbered 475255,475256,\cdots were respectively given the names aaaaa, aaaab, ...;

and so on.

To sum it up, the dogs numbered 1, 2, \cdots were respectively given the following names:

a, b, ..., z, aa, ab, ..., az, ba, bb, ..., bz, ..., za, zb, ..., zz, aaa, aab, ..., aaz, aba, abb, ..., abz, ..., zzz, aaaa, ...

Now, Roger asks you:

"What is the name for the dog numbered N?"

Constraints

N is an integer.

1 \leq N \leq 1000000000000001

Input

Input is given from Standard Input in the following format:

N

Output

Print the answer to Roger's question as a string consisting of lowercase English letters.

Sample Input 1

2

Sample Output 1

b

Sample Input 2

27

Sample Output 2

aa

Sample Input 3

123456789

Sample Output 3

jjddja

Solution in Java (OpenJDK 11.0.6) (judge verdict: Accepted)

import java.util.Scanner;
public class Main {
     public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
       
        long n=sc.nextLong();
        printString(n);
       
      
          
        
        }
        
        
        
        private static void printString(long columnNumber) 
    { 
        // To store result (Excel column name) 
        StringBuilder columnName = new StringBuilder(); 
  
        while (columnNumber > 0) { 
            // Find remainder 
            long rem = columnNumber % 26; 
  
            // If remainder is 0, then a 
            // 'Z' must be there in output 
            if (rem == 0) { 
                columnName.append("z"); 
                columnNumber = (columnNumber / 26) - 1; 
            } 
            else // If remainder is non-zero 
            { 
                columnName.append((char)((rem - 1) + 'a')); 
                columnNumber = columnNumber / 26; 
            } 
        } 
  
        // Reverse the string and print result 
        System.out.println(columnName.reverse()); 
    } 
}