Problem:
Score : 400 points

Problem Statement

Takahashi has a string S consisting of lowercase English letters.

Starting with this string, he will produce a new one in the procedure given as follows.

The procedure consists of Q operations. In Operation i (1 \leq i \leq Q), an integer T_i is provided, which means the following:

If T_i = 1: reverse the string S.

If T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.

If F_i = 1 : Add C_i to the beginning of the string S.

If F_i = 2 : Add C_i to the end of the string S.

Help Takahashi by finding the final string that results from the procedure.

Constraints

1 \leq |S| \leq 10^5

S consists of lowercase English letters.

1 \leq Q \leq 2 \times 10^5

T_i = 1 or 2.

F_i = 1 or 2, if provided.

C_i is a lowercase English letter, if provided.

Input

Input is given from Standard Input in the following format:

S
Q
Query_1
:
Query_Q

In the 3-rd through the (Q+2)-th lines, Query_i is one of the following:

1

which means T_i = 1, and:

2 F_i C_i

which means T_i = 2.

Output

Print the resulting string.

Sample Input 1

a
4
2 1 p
1
2 2 c
1

Sample Output 1

cpa

There will be Q = 4 operations. Initially, S is a.

Operation 1: Add p at the beginning of S. S becomes pa.

Operation 2: Reverse S. S becomes ap.

Operation 3: Add c at the end of S. S becomes apc.

Operation 4: Reverse S. S becomes cpa.

Thus, the resulting string is cpa.

Sample Input 2

a
6
2 2 a
2 1 b
1
2 2 c
1
1

Sample Output 2

aabc

There will be Q = 6 operations. Initially, S is a.

Operation 1: S becomes aa.

Operation 2: S becomes baa.

Operation 3: S becomes aab.

Operation 4: S becomes aabc.

Operation 5: S becomes cbaa.

Operation 6: S becomes aabc.

Thus, the resulting string is aabc.

Sample Input 3

y
1
2 1 x

Sample Output 3

xy

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;

public class Main {
	
	public static void main(String[] args) throws IOException {
		Main mainObj = new Main();
		mainObj.solve();
	}
	
	public void solve() throws IOException {
		FastScanner fs = new FastScanner();
		String firstStr = fs.nextLine();
		
		StringBuffer frontStr = new StringBuffer();
		StringBuffer tailStr = new StringBuffer();
		
		int inverceCnt=0;
		int q = fs.nextInt();
		
		for(int i = 0; i < q; i++) {
			int queryNum = fs.nextInt();
			if(queryNum == 1) {
				inverceCnt++;
			}else {
				int posNum = fs.nextInt();
				// 前付け
				if((inverceCnt % 2 == 0 && posNum == 1) || (inverceCnt % 2 == 1 && posNum == 2)) {
					frontStr.insert(0, fs.next());
				}else {
					tailStr.append(fs.next());
				}
			}
		}
		
		StringBuffer ans = new StringBuffer();
		ans.append(frontStr).append(firstStr).append(tailStr);
		String ansStr = ans.toString();
		if(inverceCnt % 2 == 0) {
			System.out.println(ansStr);
		}else {
			for(int i = 0; i < ansStr.length(); i++) {
				System.out.print(ansStr.charAt(ansStr.length() - i - 1));
			}
			System.out.print("\n");
		}
	}
	
	public class FastScanner {
		
		BufferedReader reader;
		private StringTokenizer st;
		
		public FastScanner() {
			st = null;
			reader = new BufferedReader(new InputStreamReader(System.in));
		}

		
		public String next() throws IOException {
			if(st == null || !st.hasMoreElements()) {
				st = new StringTokenizer(reader.readLine());
			}
			return st.nextToken();
		}
		
		public String nextLine() throws IOException {
			st = null;
			String readLine = null;
			readLine = reader.readLine();
			return readLine;
		}
		
		public int nextInt() throws NumberFormatException, IOException {
			return Integer.parseInt(next());
		}
		
		public long nextLong() throws NumberFormatException, IOException {
			return Long.parseLong(next());
		}
		
		public int[] nextIntArr(int n) throws NumberFormatException, IOException {
			int[] retArr = new int[n];
			for(int i = 0; i < n; i++) {
				retArr[i] = nextInt();
			}
			return retArr;
		}
		
		public long[] nextLongArr(int n) throws NumberFormatException, IOException {
			long[] retArr = new long[n];
			for(int i = 0; i < n; i++) {
				retArr[i] = nextLong();
			}
			return retArr;
		}
		
		public void close() throws IOException {
			reader.close();
		}
	}


}