Problem:
Score : 300 points

Problem Statement

Takahashi, who lives on the number line, is now at coordinate X. He will make exactly K moves of distance D in the positive or negative direction.

More specifically, in one move, he can go from coordinate x to x + D or x - D.

He wants to make K moves so that the absolute value of the coordinate of the destination will be the smallest possible.

Find the minimum possible absolute value of the coordinate of the destination.

Constraints

-10^{15} \leq X \leq 10^{15}

1 \leq K \leq 10^{15}

1 \leq D \leq 10^{15}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X K D

Output

Print the minimum possible absolute value of the coordinate of the destination.

Sample Input 1

6 2 4

Sample Output 1

2

Takahashi is now at coordinate 6. It is optimal to make the following moves:

Move from coordinate 6 to (6 - 4 =) 2.

Move from coordinate 2 to (2 - 4 =) -2.

Here, the absolute value of the coordinate of the destination is 2, and we cannot make it smaller.

Sample Input 2

7 4 3

Sample Output 2

1

Takahashi is now at coordinate 7. It is optimal to make, for example, the following moves:

Move from coordinate 7 to 4.

Move from coordinate 4 to 7.

Move from coordinate 7 to 4.

Move from coordinate 4 to 1.

Here, the absolute value of the coordinate of the destination is 1, and we cannot make it smaller.

Sample Input 3

10 1 2

Sample Output 3

8

Sample Input 4

1000000000000000 1000000000000000 1000000000000000

Sample Output 4

1000000000000000

The answer can be enormous.

Solution in Java (OpenJDK 11.0.6) (judge verdict: Wrong Answer)

import java.util.Scanner;

public class Main {
	public static void main(String[] args) {


		Scanner sc = new Scanner(System.in);

		long x = sc.nextLong();
		long k = sc.nextLong();
		long d = sc.nextLong();

		long a = Math.abs(x / d);

		if (a >= k) {
			if (x > 0){
				System.out.println(x - (k * d));
			} else {
				System.out.println(x + (k * d));
			}
		} else {
			long ans = 0;
			if (x > 0) {
				if (Math.abs(x - (a * d)) > Math.abs(x - (a+1) * d)){
					a++;
				}
				ans = x - (a * d);
				if ((k - a) % 2 == 1){
					if (ans > 0){
						ans -= d;
					} else {
						ans += d;
					}
				}
			} else {
				if (Math.abs(x - (a * d)) > Math.abs(x - (a+1) * d)){
					a++;
				}
				ans = x + (a * d);
				if ((k - a) % 2 == 1){
					if (ans > 0){
						ans -= d;
					} else {
						ans += d;
					}
				}
			}
			System.out.println(Math.abs(ans));
		}
	}


}