Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Java (OpenJDK 11.0.6) (judge verdict: Wrong Answer)

import java.util.*;
public class Main {
  public static void main(String[] args){
    Scanner sc = new Scanner(System.in);
    int n = sc.nextInt();
    
    if(n%2==0||n<104){
      System.out.println(0);
      return;
    }
	int ans = 0;
    int count = 0;
    for(int j = 105 ; j <= n ; ++j){ 
   	 for(int i = 1 ; i <= j ; ++i){ 
      if(j%i==0){
        count++;
      } 
     }
     if(count == 8){
          ans++;
     }
     count = 0;
    }
    
    System.out.println(ans);
    
  }
}