Problem:
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Transformation

Write a program which performs a sequence of commands to a given string $str$. The command is one of:

print a b: print from the a-th character to the b-th character of $str$

reverse a b: reverse from the a-th character to the b-th character of $str$

replace a b p: replace from the a-th character to the b-th character of $str$ with p

Note that the indices of $str$ start with 0.

Input

In the first line, a string $str$ is given. $str$ consists of lowercase letters. In the second line, the number of commands q is given. In the next q lines, each command is given in the above mentioned format.

Output

For each print command, print a string in a line.

Constraints

$1 \leq $ length of $str \leq 1000$

$1 \leq q \leq 100$

$0 \leq a \leq b < $ length of $str$

for replace command, $b - a + 1 = $ length of $p$

Sample Input 1

abcde
3
replace 1 3 xyz
reverse 0 2
print 1 4

Sample Output 1

xaze

Sample Input 2

xyz
3
print 0 2
replace 0 2 abc
print 0 2

Sample Output 2

xyz
abc

Solution in JAVA (judge verdict: Wrong Answer)

import java.util.Scanner;

class Main{
       public static void main(String[] args){
    	Scanner scan = new Scanner(System.in);
    	
    	String str = scan.nextLine();
    	int num = scan.nextInt();
    	
    	String meirei;
    	String change = "";
    	String find;
    	int begin;
    	int end;
    	
    	for(int i = 0; i < num; i++){
	    	meirei = scan.next();
	        begin = scan.nextInt();
	        end = scan.nextInt();
	    	
	    	String replace = "";
	    	String output = "";
	    	
	    	if(meirei.equals("replace")){
	    		replace = scan.next();
	    	}
	    	
	    	if(meirei.equals("print")){
	    		System.out.println(str.substring(begin, end + 1));
	    	}else if(meirei.equals("reverse")){
	    		find = str.substring(begin, end + 1);
	    		for(int j = find.length() - 1; j >= 0; j--){
	    			change += find.charAt(j);
	    		}
	    		str = str.replaceAll(find, change);
	    	}else{
	    		find = str.substring(begin, end + 1);
	    		str = str.replaceAll(find, replace);
	    	}
    	}
    	
     }
}