Problem:
Score : 600 points

Problem Statement

10^9 contestants, numbered 1 to 10^9, will compete in a competition.
There will be two contests in this competition.

The organizer prepared N problems, numbered 1 to N, to use in these contests.
When Problem i is presented in a contest, it will be solved by all contestants from Contestant L_i to Contestant R_i (inclusive), and will not be solved by any other contestants.

The organizer will use these N problems in the two contests.
Each problem must be used in exactly one of the contests, and each contest must have at least one problem.

The joyfulness of each contest is the number of contestants who will solve all the problems in the contest.
Find the maximum possible total joyfulness of the two contests.

Constraints

2 \leq N \leq 10^5

1 \leq L_i \leq R_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
L_1 R_1
L_2 R_2
\vdots
L_N R_N

Output

Print the maximum possible total joyfulness of the two contests.

Sample Input 1

4
4 7
1 4
5 8
2 5

Sample Output 1

6

The optimal choice is:

Use Problem 1 and 3 in the first contest. Contestant 5, 6, and 7 will solve both of them, so the joyfulness of this contest is 3.

Use Problem 2 and 4 in the second contest. Contestant 2, 3, and 4 will solve both of them, so the joyfulness of this contest is 3.

The total joyfulness of these two contests is 6. We cannot make the total joyfulness greater than 6.

Sample Input 2

4
1 20
2 19
3 18
4 17

Sample Output 2

34

Sample Input 3

10
457835016 996058008
456475528 529149798
455108441 512701454
455817105 523506955
457368248 814532746
455073228 459494089
456651538 774276744
457667152 974637457
457293701 800549465
456580262 636471526

Sample Output 3

540049931

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

/**
 * @author derrick20
 */
import java.io.*;
import java.util.*;

public class Main {
    public static void main(String args[]) throws Exception {
        FastScanner sc = new FastScanner();
        PrintWriter out = new PrintWriter(System.out);

        int N = sc.nextInt();
        Bag left = new Bag();
        Bag right = new Bag();
        Interval[] intervals = new Interval[N];
        for (int i = 0; i < N; i++) {
            long lo = sc.nextLong();
            long hi = sc.nextLong();
            intervals[i] = new Interval(lo, hi);
            right.loFreq.merge(lo, 1, Integer::sum);
            right.hiFreq.merge(hi, 1, Integer::sum);
        }
        Arrays.sort(intervals);
        long ans = intervals[N - 1].hi - intervals[N - 1].lo + 1; // We can at least get that best interval
        // Sweep through, transferring from right bag to left
        for (int i = 0; i < N; i++) {
            long lo = intervals[i].lo;
            long hi = intervals[i].hi;
            left.loFreq.merge(lo, 1, Integer::sum);
            left.hiFreq.merge(hi, 1, Integer::sum);

            right.loFreq.merge(lo, -1, Integer::sum);
            if (right.loFreq.get(lo) == 0) {
                right.loFreq.remove(lo);
            }
            right.hiFreq.merge(hi, -1, Integer::sum);
            if (right.hiFreq.get(hi) == 0) {
                right.hiFreq.remove(hi);
            }

            if (left.loFreq.size() > 0 && right.loFreq.size() > 0) {
                // Now compute answer! But both bags must be size >= 1
                // Choose the most limiting of each boundary, i.e.
                // highest min, lowest max
                long leftAns = Math.max(0, left.hiFreq.firstKey() - left.loFreq.lastKey() + 1);
                long rightAns = Math.max(0, right.hiFreq.firstKey() - right.loFreq.lastKey() + 1);
                ans = Math.max(ans, leftAns + rightAns);
            }
        }
        out.println(ans);

        out.close();
    }

    static class Bag {
        TreeMap<Long, Integer> loFreq, hiFreq;
        public Bag() {
            loFreq = new TreeMap<>();
            hiFreq = new TreeMap<>();
        }
    }

    static class Interval implements Comparable<Interval> {
        long lo, hi;
        public Interval(long l, long h) {
            lo = l; hi = h;
        }
        public int compareTo(Interval i2) {
            // We want the intervals to be close together
//            return (int) (hi - i2.hi);
            return lo - i2.lo != 0 ? (int) (lo - i2.lo) : (int) (hi - i2.hi);
        }
    }

    static class FastScanner {
        public int BS = 1<<16;
        public char NC = (char)0;
        byte[] buf = new byte[BS];
        int bId = 0, size = 0;
        char c = NC;
        double cnt = 1;
        BufferedInputStream in;

        public FastScanner() {
            in = new BufferedInputStream(System.in, BS);
        }

        public FastScanner(String s) {
            try {
                in = new BufferedInputStream(new FileInputStream(new File(s)), BS);
            }
            catch (Exception e) {
                in = new BufferedInputStream(System.in, BS);
            }
        }

        private char getChar(){
            while(bId==size) {
                try {
                    size = in.read(buf);
                }catch(Exception e) {
                    return NC;
                }
                if(size==-1)return NC;
                bId=0;
            }
            return (char)buf[bId++];
        }

        public int nextInt() {
            return (int)nextLong();
        }

        public long nextLong() {
            cnt=1;
            boolean neg = false;
            if(c==NC)c=getChar();
            for(;(c<'0' || c>'9'); c = getChar()) {
                if(c=='-')neg=true;
            }
            long res = 0;
            for(; c>='0' && c <='9'; c=getChar()) {
                res = (res<<3)+(res<<1)+c-'0';
                cnt*=10;
            }
            return neg?-res:res;
        }

        public double nextDouble() {
            double cur = nextLong();
            return c!='.' ? cur:cur+nextLong()/cnt;
        }

        public String next() {
            StringBuilder res = new StringBuilder();
            while(c<=32)c=getChar();
            while(c>32) {
                res.append(c);
                c=getChar();
            }
            return res.toString();
        }

        public String nextLine() {
            StringBuilder res = new StringBuilder();
            while(c<=32)c=getChar();
            while(c!='\n') {
                res.append(c);
                c=getChar();
            }
            return res.toString();
        }

        public boolean hasNext() {
            if(c>32)return true;
            while(true) {
                c=getChar();
                if(c==NC)return false;
                else if(c>32)return true;
            }
        }
    }
}