Problem:
Search II

You are given a sequence of n integers S and a sequence of different q integers T. Write a program which outputs C, the number of integers in T which are also in the set S.

Input

In the first line n is given. In the second line, n integers are given. In the third line q is given. Then, in the fourth line, q integers are given.

Output

Print C in a line.

Constraints

Elements in S is sorted in ascending order

n ≤ 100000

q ≤ 50000

0 ≤ an element in S ≤ 109

0 ≤ an element in T ≤ 109

Sample Input 1

5
1 2 3 4 5
3
3 4 1

Sample Output 1

3

Sample Input 2

3
1 2 3
1
5

Sample Output 2

0

Sample Input 3

5
1 1 2 2 3
2
1 2

Sample Output 3

2

Notes

Solution in JAVA (judge verdict: Time Limit Exceeded)

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.Arrays;
import java.util.regex.Pattern;

public class Main {
    public static void main(String[] args) throws IOException {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        int n = ip(br.readLine());
        int[] s = createListInt(br.readLine());
        int q = ip(br.readLine());
        int[] t = createListInt(br.readLine());
        int count = 0;
       // Arrays.sort(s);
        for (int i = 0; i < q; i++) {
            for (int j = 0; j < n + 1; j++) {
                if (binarySearch(s, t[i])) {
                    count++;
                    break;
                }
            }
        }
        System.out.println(count);
    }

    static boolean binarySearch(int[] a, int key) {
        int left = 0;
        int right = a.length;
        while (left < right) {
            int mid = (left + right) / 2;
            if (a[mid] == key) {
                return true;
            } else if (key < a[mid]) {
                right = mid;
            } else {
                left = mid + 1;
            }
        }
        return false;
    }

    static boolean isNumber(String num) {
        return Pattern.compile("^\\-?[0-9]*\\.?[0-9]+$").matcher(num).find();
    }

    static int[] createListInt(String line) {
        String[] lines = line.split(" ");
        int n = lines.length;
        int[] list = new int[n];
        while (n-- > 0) {
            list[n] = Integer.parseInt(lines[n]);
        }
        return list;
    }

    static long[] createListLong(String line) {
        String[] lines = line.split(" ");
        int n = lines.length;
        long[] list = new long[n];
        while (n-- > 0) {
            list[n] = Long.parseLong(lines[n]);
        }
        return list;
    }

    static int ip(String s) {
        return Integer.parseInt(s);
    }

    static long lp(String s) {
        return Long.parseLong(s);
    }
}