Problem:
Score: 100 points

Problem Statement

In this problem, a date is written as Y-M-D. For example, 2019-11-30 means November 30, 2019.

Integers M_1, D_1, M_2, and D_2 will be given as input.

It is known that the date 2019-M_2-D_2 follows 2019-M_1-D_1.

Determine whether the date 2019-M_1-D_1 is the last day of a month.

Constraints

Both 2019-M_1-D_1 and 2019-M_2-D_2 are valid dates in the Gregorian calendar.

The date 2019-M_2-D_2 follows 2019-M_1-D_1.

Input

Input is given from Standard Input in the following format:

M_1 D_1
M_2 D_2

Output

If the date 2019-M_1-D_1 is the last day of a month, print 1; otherwise, print 0.

Sample Input 1

11 16
11 17

Sample Output 1

0

November 16 is not the last day of a month.

Sample Input 2

11 30
12 1

Sample Output 2

1

November 30 is the last day of November.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)





import java.util.Scanner;

/**
 * Created by pc on 2019/12/01.
 */
public class Main {
	public static void main(String[] args){
		Scanner sc = new Scanner(System.in);

		int[][] Days= {{0,0},{0,0}};

		for(int i = 0; i<2; i++){
			Days[i][0] = sc.nextInt();
			Days[i][1] = sc.nextInt();
		}

		boolean isLastday = false;
		if(Days[0][0]  != Days[1][0]){
			isLastday = true;
		}
		System.out.print(isLastday ? 1 :0);

	}
}