Problem:
Sale Result

There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.

Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:

n (the number of data in the list)
i p q
i p q
:
:
i p q

Output

For each dataset, print a list of employee IDs or a text "NA"

Sample Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0

Output for the Sample Input

1001
1003
NA
2013

Solution in JAVA (judge verdict: Wrong Answer)

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.*;
import java.io.IOException;

public class Main {
    public static void main(String[] args) throws Exception {
        List<Map<String, Long>> dataset = new ArrayList<>();
        
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        while (true){
            final int times = Integer.parseInt(br.readLine());
            if (times == 0) { dataset.add(new TreeMap<>()); break; }
            
            Map<String, Long> data = new TreeMap<>();
            for (int i=1; i <= times; i++) {
                String[] col = br.readLine().split(" ");
                data.merge(col[0], Long.parseLong(col[1]) * Long.parseLong(col[2]), Long::sum);
            }
            dataset.add(data);
        }

         dataset.forEach(data -> {
            long count = data.entrySet().stream()
                .filter(e -> e.getValue() >= 1_000_000)
                .peek(e -> System.out.println(e.getKey()))
                .count();
            if (count == 0) { System.out.println("NA"); }
        });
   }
}