Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.math.*;
import java.util.*;

public class Main {
    static boolean x(int a[][]) {
        boolean tmp = false;
        for (int i = 0; i < 3; i++) {
            if (a[i][0] == 0 && a[i][1] == 0 && a[i][2] == 0) {
                tmp = true;
                break;
            }
        }
        return tmp;
    }

    static boolean y(int a[][]) {
        boolean tmp = false;
        for (int i = 0; i < 3; i++) {
            if (a[0][i] == 0 && a[1][i] == 0 && a[2][i] == 0) {
                tmp = true;
                break;
            }
        }
        return tmp;
    }

    static boolean c(int a[][]) {
        boolean tmp = false;
        if (a[0][0] == 0 && a[1][1] == 0 && a[2][2] == 0)
            tmp = true;
        else if (a[0][2] == 0 && a[1][1] == 0 && a[2][0] == 0)
            tmp = true;
        return tmp;
    }

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int a[][] = new int[3][3];
        for (int i = 0; i < 3; i++) {
            for (int j = 0; j < 3; j++) {
                a[i][j] = sc.nextInt();
            }
        }
        int n = sc.nextInt();
        int tmp = 0;
        for (int i = 0; i < n; i++) {
            tmp = sc.nextInt();
            for (int k = 0; k < 3; k++) {
                for (int j = 0; j < 3; j++) {
                    if (a[k][j] == tmp)
                        a[k][j] = 0;
                }
            }
        }
        boolean xa = x(a);
        boolean ya = y(a);
        boolean ca = c(a);
        String ans = "No";
        if (xa || ya || ca)
            ans = "Yes";
        System.out.println(ans);
        sc.close();
    }
}