Problem:
Score : 1200 points

Problem Statement

We have N boxes numbered 1 to N, and M balls numbered 1 to M.
Currently, Ball i is in Box A_i.

You can do the following operation:

Choose a box containing two or more balls, pick up one of the balls from that box, and put it into another box.

Since the balls are very easy to break, you cannot move Ball i more than C_i times in total.
Within this limit, you can do the operation any number of times.

Your objective is to have Ball i in Box B_i for every i (1 \leq i \leq M).
Determine whether this objective is achievable.
If it is, also find the minimum number of operations required to achieve it.

Constraints

1 \leq N \leq 10^5

1 \leq M \leq 10^5

1 \leq A_i,B_i \leq N

1 \leq C_i \leq 10^5

In the situation where the objective is achieved, every box contains one or more balls.
That is, for every i (1 \leq i \leq N), there exists j such that B_j=i.

Input

Input is given from Standard Input in the following format:

N M
A_1 B_1 C_1
A_2 B_2 C_2
\vdots
A_M B_M C_M

Output

If the objective is unachievable, print -1; if it is achievable, print the minimum number of operations required to achieve it.

Sample Input 1

3 3
1 2 1
2 1 1
1 3 2

Sample Output 1

3

We can achieve the objective in three operations, as follows:

Pick up Ball 1 from Box 1 and put it into Box 2.

Pick up Ball 2 from Box 2 and put it into Box 1.

Pick up Ball 3 from Box 1 and put it into Box 3.

Sample Input 2

2 2
1 2 1
2 1 1

Sample Output 2

-1

Sample Input 3

5 5
1 2 1
2 1 1
1 3 2
4 5 1
5 4 1

Sample Output 3

6

Sample Input 4

1 1
1 1 1

Sample Output 4

0

Solution in Java (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import static java.lang.Integer.parseInt;
import static java.lang.Long.parseLong;
import static java.lang.System.exit;

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.StringTokenizer;

public class Main {

	static void sort(int a[], int n) {
		if (n == 0) {
			return;
		}
		for (int i = 1; i < n; i++) {
			int j = i;
			int ca = a[i];
			do {
				int nj = (j - 1) >> 1;
				int na = a[nj];
				if (ca <= na) {
					break;
				}
				a[j] = na;
				j = nj;
			} while (j != 0);
			a[j] = ca;
		}
		int ca = a[0];
		for (int i = n - 1; i > 0; i--) {
			int j = 0;
			while ((j << 1) + 2 + Integer.MIN_VALUE < i + Integer.MIN_VALUE) {
				j <<= 1;
				j += (a[j + 2] > a[j + 1]) ? 2 : 1;
			}
			if ((j << 1) + 2 == i) {
				j = (j << 1) + 1;
			}
			int na = a[i];
			a[i] = ca;
			ca = na;
			while (j != 0 && a[j] < ca) {
				j = (j - 1) >> 1;
			}
			while (j != 0) {
				na = a[j];
				a[j] = ca;
				ca = na;
				j = (j - 1) >> 1;
			}
		}
		a[0] = ca;
	}

	static void solve() throws Exception {
		int n = scanInt(), m = scanInt();
		int a[] = new int[m], b[] = new int[m], c[] = new int[m];
		int nIn[] = new int[n], out[] = new int[n], nOut[] = new int[n];
		int ans = 0;
		for (int i = 0; i < m; i++) {
			a[i] = scanInt() - 1;
			b[i] = scanInt() - 1;
			c[i] = scanInt() - 1;
			out[a[i]] = i;
			++nOut[a[i]];
			++nIn[b[i]];
			if (a[i] != b[i]) {
				++ans;
			}
		}
		boolean seen[] = new boolean[n];
		boolean onLoop[] = new boolean[n];
		int nLoops = 0;
		for (int i = 0; i < n; i++) {
			if (nOut[i] == 1 && nIn[i] == 1 && b[out[i]] == i) {
				onLoop[i] = true;
				continue;
			}
			for (int j = i; !seen[j]; j = b[out[j]]) {
				seen[j] = true;
				if (nOut[j] != 1 || nIn[j] != 1) {
					break;
				}
				if (b[out[j]] == i) {
					for (j = i;; j = b[out[j]]) {
						onLoop[j] = true;
						if (b[out[j]] == i) {
							break;
						}
					}
					++nLoops;
					break;
				}
			}
		}
		if (nLoops == 0) {
			Main.out.print(ans);
			return;
		}
		long goodExcess = 0;
		int badExcess[] = new int[m], nBadExcess = 0;
		long loopExcess = 0;
		int badLoopExcess[] = new int[m], nBadLoopExcess = 0;
		for (int i = 0; i < m; i++) {
			if (onLoop[a[i]]) {
				if (a[i] == b[i]) {
					if (c[i] > 1) {
						badLoopExcess[nBadLoopExcess++] = c[i] - 1;
					}
				} else {
					loopExcess += c[i];
				}
			} else if (a[i] != b[i]) {
				goodExcess += c[i];
			} else {
				if (c[i] > 0) {
					badExcess[nBadExcess++] = c[i];
				}
			}
		}
		sort(badExcess, nBadExcess);
		ans += nLoops;
		if (goodExcess == 0) {
			if (nBadExcess == 0) {
				Main.out.print(-1);
				return;
			}
			goodExcess += badExcess[--nBadExcess];
			++ans;
		}
		goodExcess += loopExcess;
		sort(badLoopExcess, nBadLoopExcess);
		while (goodExcess < nLoops) {
			if (nBadExcess == 0 && nBadLoopExcess == 0) {
				Main.out.print(-1);
				return;
			}
			if (nBadExcess > 0 && (nBadExcess == 1 || goodExcess + badExcess[nBadExcess - 1] >= nLoops)) {
				goodExcess += badExcess[--nBadExcess];
				++ans;
			} else if (nBadExcess >= 2 && (nBadLoopExcess == 0 || badExcess[nBadExcess - 1] + badExcess[nBadExcess - 2] >= badLoopExcess[nBadLoopExcess - 1])) {
				goodExcess += badExcess[--nBadExcess];
				++ans;
			} else {
				goodExcess = badLoopExcess[--nBadLoopExcess];
				ans += 2;
			}
		}
		Main.out.print(ans);
	}

	static int scanInt() throws IOException {
		return parseInt(scanString());
	}

	static long scanLong() throws IOException {
		return parseLong(scanString());
	}

	static String scanString() throws IOException {
		while (tok == null || !tok.hasMoreTokens()) {
			tok = new StringTokenizer(in.readLine());
		}
		return tok.nextToken();
	}

	static BufferedReader in;
	static PrintWriter out;
	static StringTokenizer tok;

	public static void main(String[] args) {
		try {
			in = new BufferedReader(new InputStreamReader(System.in));
			out = new PrintWriter(System.out);
			solve();
			in.close();
			out.close();
		} catch (Throwable e) {
			e.printStackTrace();
			exit(1);
		}
	}
}