Problem:
Score : 600 points

Problem Statement

Snuke got an integer sequence of length N from his mother, as a birthday present. The i-th (1 ≦ i ≦ N) element of the sequence is a_i. The elements are pairwise distinct.
He is sorting this sequence in increasing order.
With supernatural power, he can perform the following two operations on the sequence in any order:

Operation 1: choose 2 consecutive elements, then reverse the order of those elements.

Operation 2: choose 3 consecutive elements, then reverse the order of those elements.

Snuke likes Operation 2, but not Operation 1. Find the minimum number of Operation 1 that he has to perform in order to sort the sequence in increasing order.

Constraints

1 ≦ N ≦ 10^5

0 ≦ A_i ≦ 10^9

If i ≠ j, then A_i ≠ A_j.

All input values are integers.

Input

The input is given from Standard Input in the following format:

N
A_1
:
A_N

Output

Print the minimum number of times Operation 1 that Snuke has to perform.

Sample Input 1

4
2
4
3
1

Sample Output 1

1

The given sequence can be sorted as follows:

First, reverse the order of the last three elements. The sequence is now: 2,1,3,4.

Then, reverse the order of the first two elements. The sequence is now: 1,2,3,4.

In this sequence of operations, Operation 1 is performed once. It is not possible to sort the sequence with less number of Operation 1, thus the answer is 1.

Sample Input 2

5
10
8
5
3
2

Sample Output 2

0

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.Arrays;
import java.io.StringReader;
import java.io.IOException;
import java.io.Reader;
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.InputStream;

/**
 * Built using CHelper plug-in
 * Actual solution is at the top
 *
 * @author Denis Nedelyaev
 */
public class Main {
    public static void main(String[] args) throws Exception {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        FastScanner in = new FastScanner(inputStream);
        PrintWriter out = new PrintWriter(outputStream);
        AtC solver = new AtC(in, out);
        solver.solve(1);
        out.close();
    }

    static class AtC {
        private final FastScanner in;
        private final PrintWriter out;

        public AtC(FastScanner in, PrintWriter out) {
            this.in = in;
            this.out = out;
        }

        public void solve(int testNumber) throws IOException {
            int n = in.nextInt();
            int[] a = in.nextInts(n);
            int[] b = new int[n];
            for (int i = 0; i < n; i++) {
                b[i] = a[i];
            }
            Arrays.sort(b);
            int count = 0;
            for (int i = 0; i < n; i++) {
                int j = Arrays.binarySearch(b, a[i]);
                int d = Math.abs(i - j);
                if (d % 2 != 0) {
                    count++;
                }
            }
            out.println(count / 2);
        }

    }

    static class FastScanner {
        private final BufferedReader br;
        private String line;
        private int pos;

        public FastScanner(String s) throws IOException {
            this(new StringReader(s));
        }

        public FastScanner(InputStream is) throws IOException {
            this(new InputStreamReader(is, "UTF-8"));
        }

        public FastScanner(Reader reader) throws IOException {
            this(new BufferedReader(reader));
        }

        public FastScanner(BufferedReader reader) throws IOException {
            br = reader;
            line = br.readLine();
            pos = 0;
        }

        public String next() throws IOException {
            if (!skipWhitespace()) {
                return null;
            }

            int start = pos;

            while (pos < line.length()) {
                char c = line.charAt(pos);

                if (c == ' ' || c == '\t') {
                    break;
                }

                pos++;
            }

            return line.substring(start, pos);
        }

        public int nextInt() throws IOException {
            return Integer.parseInt(next());
        }

        public int[] nextInts(int n) throws IOException {
            int[] res = new int[n];
            for (int i = 0; i < n; i++) {
                res[i] = nextInt();
            }
            return res;
        }

        private boolean skipWhitespace() throws IOException {
            while (line != null) {
                while (pos < line.length()) {
                    char c = line.charAt(pos);

                    if (c != ' ' && c != '\t') {
                        return true;
                    }

                    pos++;
                }

                line = br.readLine();
                pos = 0;
            }

            return false;
        }

    }
}