Problem:
Score : 100 points

Problem Statement

Given is an integer N.

Takahashi chooses an integer a from the positive integers not greater than N with equal probability.

Find the probability that a is odd.

Constraints

1 \leq N \leq 100

Input

Input is given from Standard Input in the following format:

N

Output

Print the probability that a is odd.
Your output will be considered correct when its absolute or relative error from the judge's output is at most 10^{-6}.

Sample Input 1

4

Sample Output 1

0.5000000000

There are four positive integers not greater than 4: 1, 2, 3, and 4. Among them, we have two odd numbers: 1 and 3. Thus, the answer is \frac{2}{4} = 0.5.

Sample Input 2

5

Sample Output 2

0.6000000000

Sample Input 3

1

Sample Output 3

1.0000000000

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Scanner;

public class Main {

	public static void main(String[] args) {

//		long ans2 = 0;
		double ans = 0;

		Scanner sc = new Scanner(System.in);
		int  n = sc.nextInt();
//		int  k = sc.nextInt();

//		int  k = sc.nextInt();
//		long d = sc.nextLong();

//		String string = sc.next();
//		StringBuilder s = new StringBuilder(string);

//		boolean f = true;
//
//		int[] a = new int[m];
//		int[] b = new int[m];
//		for (int i = 0; i < n; i++) {
//			a[i] = sc.nextInt();
//		}
//		for (int i = 0; i < k; i++) {
//			b[i] = sc.nextInt();
//		}
//		for (int i = 1; i <n; i++) {
//			b[i] = sc.nextInt();
//		}
//		int[][] c = new int[h][w];
//		for (int i = 0; i < h; i++) {
//			for(int j = 0; j < w; j++) {
//				c[i][j] = 0;
//			}
//		}

//		int tmp_a = 0;
//		int tmp_b = 0;

		if(n%2 == 0) {
			ans = 0.5;
		} else {
			double tmp = n/2 +1;
			ans = tmp/n;
		}


		System.out.println(ans);

		sc.close();
	}
}