Problem:
Score : 300 points

Problem Statement

You are given an integer sequence of length N, a_1,a_2,...,a_N.

For each 1≤i≤N, you have three choices: add 1 to a_i, subtract 1 from a_i or do nothing.

After these operations, you select an integer X and count the number of i such that a_i=X.

Maximize this count by making optimal choices.

Constraints

1≤N≤10^5

0≤a_i<10^5 (1≤i≤N)

a_i is an integer.

Input

The input is given from Standard Input in the following format:

N
a_1 a_2 .. a_N

Output

Print the maximum possible number of i such that a_i=X.

Sample Input 1

7
3 1 4 1 5 9 2

Sample Output 1

4

For example, turn the sequence into 2,2,3,2,6,9,2 and select X=2 to obtain 4, the maximum possible count.

Sample Input 2

10
0 1 2 3 4 5 6 7 8 9

Sample Output 2

3

Sample Input 3

1
99999

Sample Output 3

1

Solution in Java (OpenJDK 11.0.6) (judge verdict: Time Limit Exceeded)

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.io.OutputStream;
import java.io.IOException;
import java.io.FileReader;
import java.io.FileWriter;

import java.util.*;
import java.util.stream.LongStream;

public class Main {
    // 標準入力
    static BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

    // 標準入力数値配列用 int
    static int[] inputval() throws Exception {
        String[] strarray = br.readLine().trim().split(" ");
        int[] intarray = new int[strarray.length];
        for (int i = 0; i < intarray.length; i++) {
            intarray[i] = Integer.parseInt(strarray[i]);
        }
        return intarray;
    }

    /* 標準入力数値配列用 long */
    static long[] inputLongArr() throws Exception {
        String[] strarray = br.readLine().trim().split(" ");
        long[] longarray = new long[strarray.length];
        for (int i = 0; i < longarray.length; i++) {
            longarray[i] = Long.parseLong(strarray[i]);
        }
        return longarray;
    }

    // 標準入力数値リスト用 int
    static List<Integer> inputIntList() throws Exception {
        List<String> strList = Arrays.asList(br.readLine().trim().split(" "));
        List<Integer> intList = new ArrayList<Integer>();
        for (String elem : strList){
            intList.add(Integer.parseInt(elem));
        }
        return intList;
    }

    // 標準入力数値配列用 integer 降順ソート用
    static Integer[] inputvalInteger() throws Exception {
        String[] strarray = br.readLine().trim().split(" ");
        Integer[] intarray = new Integer[strarray.length];
        for (int i = 0; i < intarray.length; i++) {
            intarray[i] = Integer.parseInt(strarray[i]);
        }
        return intarray;
    }

    /*標準入力long*/
    static long inputLong() throws Exception {
        return Long.parseLong(br.readLine());
    }

    /*標準入力long*/
    static int inputInt() throws Exception {
        return Integer.parseInt(br.readLine());
    }




    public static void main(String[] args) throws Exception {
        // write your code here
        int n = inputInt();
        long [] al = inputLongArr();
        long [] alPlus = new long [n];
        long [] alMinus = new long [n];
        HashSet<Long> am = new HashSet<Long>();
        long max = 0;
        for (int i=0; i<n; i++){
            am.add(al[i]);
            alPlus[i] = al[i] + 1;
            alMinus[i] = al[i] - 1;
        }
        LongStream tmp = LongStream.concat(Arrays.stream(al),Arrays.stream(alPlus));
        long all [] = LongStream.concat(tmp,Arrays.stream(alMinus)).toArray();
        for(long a : am){
            long cnt = Arrays.stream(all).filter(l -> l==a).count();
            max = Math.max(max, cnt);
        }

        System.out.println(max);

    }

}