Problem:
Score : 300 points

Problem Statement

You are given an integer sequence of length N. The i-th term in the sequence is a_i.
In one operation, you can select a term and either increment or decrement it by one.

At least how many operations are necessary to satisfy the following conditions?

For every i (1≤i≤n), the sum of the terms from the 1-st through i-th term is not zero.

For every i (1≤i≤n-1), the sign of the sum of the terms from the 1-st through i-th term, is different from the sign of the sum of the terms from the 1-st through (i+1)-th term.

Constraints

2 ≤ n ≤ 10^5

|a_i| ≤ 10^9

Each a_i is an integer.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print the minimum necessary count of operations.

Sample Input 1

4
1 -3 1 0

Sample Output 1

4

For example, the given sequence can be transformed into 1, -2, 2, -2 by four operations. The sums of the first one, two, three and four terms are 1, -1, 1 and -1, respectively, which satisfy the conditions.

Sample Input 2

5
3 -6 4 -5 7

Sample Output 2

0

The given sequence already satisfies the conditions.

Sample Input 3

6
-1 4 3 2 -5 4

Sample Output 3

8

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.*;

public class Main{
  public static void main(String[]args){
    Scanner sc = new Scanner(System.in);
    int N = Integer.parseInt(sc.nextLine());
    long ans = 0;
    long now = sc.nextInt();
    for(int i = 1; i < N; i++){
      int A = sc.nextInt();
      if(now > 0){
        if(now + A >= 0){
          ans += now+A+1;
          now = -1;
        }else{
          now = now+A;
        }
      }else if(now < 0){
        if(now + A <= 0){
          ans += Math.abs(now+A)+1;
          now = 1;
        }else{
          now = now+A;
        }
      }else{
        if(A < 0){
          ans++;
          now++;
        }else if(A > 0){
          ans++;
          now--;
        }else{
          ans++;
        }
      }
    } 
    System.out.println(ans);
  }
}