Problem:
Score : 300 points

Problem Statement

You are given an integer sequence of length n, a_1, ..., a_n.
Let us consider performing the following n operations on an empty sequence b.

The i-th operation is as follows:

Append a_i to the end of b.

Reverse the order of the elements in b.

Find the sequence b obtained after these n operations.

Constraints

1 \leq n \leq 2\times 10^5

0 \leq a_i \leq 10^9

n and a_i are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print n integers in a line with spaces in between.
The i-th integer should be b_i.

Sample Input 1

4
1 2 3 4

Sample Output 1

4 2 1 3

After step 1 of the first operation, b becomes: 1.

After step 2 of the first operation, b becomes: 1.

After step 1 of the second operation, b becomes: 1, 2.

After step 2 of the second operation, b becomes: 2, 1.

After step 1 of the third operation, b becomes: 2, 1, 3.

After step 2 of the third operation, b becomes: 3, 1, 2.

After step 1 of the fourth operation, b becomes: 3, 1, 2, 4.

After step 2 of the fourth operation, b becomes: 4, 2, 1, 3.

Thus, the answer is 4 2 1 3.

Sample Input 2

3
1 2 3

Sample Output 2

3 1 2

As shown above in Sample Output 1, b becomes 3, 1, 2 after step 2 of the third operation. Thus, the answer is 3 1 2.

Sample Input 3

1
1000000000

Sample Output 3

1000000000

Sample Input 4

6
0 6 7 6 7 0

Sample Output 4

0 6 6 0 7 7

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Time Limit Exceeded)

import java.util.Collections;
import java.util.LinkedList;
import java.util.List;
import java.util.Scanner;


public class Main {
    public static void main(String[] args)
    {
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        int[] a = new int[n];
        for(int i = 0;i < n;i++)
            a[i] = sc.nextInt();
        List<Integer> odd = new LinkedList<>();
        List<Integer> even = new LinkedList<>();

        for(int i = 0;i < n;i += 2) {
            odd.add(a[i]);
            if(i+1 <= n - 1)
                even.add(a[i+1]);
        }
        if(n % 2 == 0)
        {
            Collections.reverse(even);
            even.addAll(odd);
            List<Integer> ls = even;
            StringBuilder sb = new StringBuilder();
            for(int i = 0;i < ls.size() - 1;i++)
                sb.append(ls.get(i) + " ");
            sb.append(ls.get(ls.size() - 1));
            System.out.println(sb.toString());
        }
        else
        {
            Collections.reverse(odd);
            odd.addAll(even);
            List<Integer> ls = odd;
            StringBuilder sb = new StringBuilder();
            for(int i = 0;i < ls.size() - 1;i++)
                sb.append(ls.get(i) + " ");
            sb.append(ls.get(ls.size() - 1));
            System.out.println(sb.toString());
        }

    }

}