Problem:
Score : 100 points

Problem Statement

We conducted a survey on newspaper subscriptions.
More specifically, we asked each of the N respondents the following two questions:

Question 1: Are you subscribing to Newspaper X?

Question 2: Are you subscribing to Newspaper Y?

As the result, A respondents answered "yes" to Question 1, and B respondents answered "yes" to Question 2.

What are the maximum possible number and the minimum possible number of respondents subscribing to both newspapers X and Y?

Write a program to answer this question.

Constraints

1 \leq N \leq 100

0 \leq A \leq N

0 \leq B \leq N

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N A B

Output

Print the maximum possible number and the minimum possible number of respondents subscribing to both newspapers, in this order, with a space in between.

Sample Input 1

10 3 5

Sample Output 1

3 0

In this sample, out of the 10 respondents, 3 answered they are subscribing to Newspaper X, and 5 answered they are subscribing to Newspaper Y.

Here, the number of respondents subscribing to both newspapers is at most 3 and at least 0.

Sample Input 2

10 7 5

Sample Output 2

5 2

In this sample, out of the 10 respondents, 7 answered they are subscribing to Newspaper X, and 5 answered they are subscribing to Newspaper Y.

Here, the number of respondents subscribing to both newspapers is at most 5 and at least 2.

Sample Input 3

100 100 100

Sample Output 3

100 100

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.*;
public class Main {
	public static void main(String[] args){
		Scanner sc = new Scanner(System.in);
      int x=sc.nextInt();//対象者
      int a=sc.nextInt();//X新聞購読者
      int b=sc.nextInt();//Y新聞購読者
      int c=a+b;//X新聞とY新聞の購読者合計
      int d=0;
      int g=0;
      
      if(a>b){
      
        if(x>=c){
        g=0; 
          System.out.println(b+" "+g);
      }else{
          
          if(x==a){
          System.out.println(b+" "+b);
          }else{
             d=(x-b)-(x-a);
        System.out.println(b+" "+d);
          }
       
      }
        
      }else if(b>a){
        
        if(x>=c){
        g=0;
          System.out.println(a+" "+g);
      }else{
          
          if(x==b){
          System.out.println(a+" "+a);
          }else{
             d=(x-a)-(x-b);
          System.out.println(a+" "+d);
          }
        
      }
        
      }else{
        
        if(a==b && a==x && b==x){
          System.out.println(a+" "+b);
      	}else{
           g=0; 
          System.out.println(a+" "+g);
        }
        
      }
      
		
	}
}