Problem:
Score : 300 points

Problem Statement

There are N+1 towns. The i-th town is being attacked by A_i monsters.

We have N heroes. The i-th hero can defeat monsters attacking the i-th or (i+1)-th town, for a total of at most B_i monsters.

What is the maximum total number of monsters the heroes can cooperate to defeat?

Constraints

All values in input are integers.

1 \leq N \leq 10^5

1 \leq A_i \leq 10^9

1 \leq B_i \leq 10^9

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_{N+1}
B_1 B_2 ... B_N

Output

Print the maximum total number of monsters the heroes can defeat.

Sample Input 1

2
3 5 2
4 5

Sample Output 1

9

If the heroes choose the monsters to defeat as follows, they can defeat nine monsters in total, which is the maximum result.

The first hero defeats two monsters attacking the first town and two monsters attacking the second town.

The second hero defeats three monsters attacking the second town and two monsters attacking the third town.

Sample Input 2

3
5 6 3 8
5 100 8

Sample Output 2

22

Sample Input 3

2
100 1 1
1 100

Sample Output 3

3

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.io.*;
import java.util.*;

public class Main {
	static int mod = (int)1e9+7;
	static Comparator<Integer> lower_bound = (x, y) -> x.compareTo(y) >= 0 ? 1 : -1;
	static Comparator<Integer> upper_bound = (x, y) -> x.compareTo(y) > 0 ? 1 : -1;

	public static void main(String[] args){
		FastScanner sc = new FastScanner(System.in);
		PrintWriter out = new PrintWriter(System.out);

		solve(sc,out);

		out.flush();
	}

	public static void solve(FastScanner sc, PrintWriter out) {
		int n = sc.nextInt();
		int[] a = sc.nextIntArray(n+1);
		int[] b = sc.nextIntArray(n);
		
		long res = 0;
		
		for(int i = 0; i < n; i++) { //勇者i
			if(a[i] - b[i] >= 0) {
				res+=b[i];
				b[i]=0;
				a[i]-=b[i];
			}else{
				res+=a[i];
				b[i]-=a[i];
				a[i]=0;
			}
			
			if(b[i] != 0) {
				if(a[i+1] - b[i] >= 0) {
					res+=b[i];
					a[i+1]-=b[i];
				}else{
					res+=a[i+1];
					a[i+1]=0;
				}
			}
		}
		
		out.println(res);
	}

	public static long gcd(long a, long b) {
		if(a < b) return gcd(b, a);
		if(b == 0) return a;
		return gcd(b, a % b);
	}

	public static long lcm(long a, long b) {
		return a / gcd(a, b) * b;
	}

	public static long factorial(int n) {
		long a;

		if(n > 0) {
			a = n * factorial(n - 1);
		}else{
			a = 1;
		}
		return a;
	}
}

class Pair<K, V> extends AbstractMap.SimpleEntry<K, V> {

    public Pair(K key, V value) {
        super(key, value);
    }

    public Pair<V, K> swap() {
    	return new Pair<V, K>(getValue(), getKey());
    }
 }

class UnionFind {
	int[] par;

	public UnionFind(int n) {
		par = new int[n];

		Arrays.fill(par, -1);
	}

	int root(int x) {
		if(par[x] < 0) return x;
		return par[x] = root(par[x]);
	}

	boolean unite(int x,int y) {
		x = root(x);
		y = root(y);

		if(x == y) return false;

		if(size(x) < size(y)) {
			int tmp = x;
			x = y;
			y = tmp;
		}

		par[x] += par[y];
		par[y] = x;

		return true;
	}

	boolean same(int x,int y) {
		int rx = root(x);
		int ry = root(y);
		return rx == ry;
	}

	int size(int a) {
		return -par[root(a)];
	}
}

class FastScanner {
    private BufferedReader reader = null;
    private StringTokenizer tokenizer = null;

    public FastScanner(InputStream in) {
        reader = new BufferedReader(new InputStreamReader(in));
        tokenizer = null;
    }

    public String next() {
        if (tokenizer == null || !tokenizer.hasMoreTokens()) {
            try {
                tokenizer = new StringTokenizer(reader.readLine());
            } catch (IOException e) {
                throw new RuntimeException(e);
            }
        }
        return tokenizer.nextToken();
    }

    public String nextLine() {
        if (tokenizer == null || !tokenizer.hasMoreTokens()) {
            try {
                return reader.readLine();
            } catch (IOException e) {
                throw new RuntimeException(e);
            }
        }

        return tokenizer.nextToken("\n");
    }

    public long nextLong() {
        return Long.parseLong(next());
    }

    public int nextInt() {
        return Integer.parseInt(next());
    }

    public double nextDouble() {
         return Double.parseDouble(next());
     }

    public int[] nextIntArray(int n) {
        int[] a = new int[n];
        for (int i = 0; i < n; i++)
            a[i] = nextInt();
        return a;
    }

    public long[] nextLongArray(int n) {
        long[] a = new long[n];
        for (int i = 0; i < n; i++)
            a[i] = nextLong();
        return a;
    }
}