Problem:
Score : 400 points

Problem Statement

There is a directed graph with N vertices and M edges.
The i-th edge (1≤i≤M) points from vertex a_i to vertex b_i, and has a weight c_i.
We will play the following single-player game using this graph and a piece.

Initially, the piece is placed at vertex 1, and the score of the player is set to 0.
The player can move the piece as follows:

When the piece is placed at vertex a_i, move the piece along the i-th edge to vertex b_i. After this move, the score of the player is increased by c_i.

The player can end the game only when the piece is placed at vertex N.
The given graph guarantees that it is possible to traverse from vertex 1 to vertex N.

When the player acts optimally to maximize the score at the end of the game, what will the score be?
If it is possible to increase the score indefinitely, print inf.

Constraints

2≤N≤1000

1≤M≤min(N(N-1),2000)

1≤a_i,b_i≤N (1≤i≤M)

a_i≠b_i (1≤i≤M)

a_i≠a_j or b_i≠b_j (1≤i<j≤M)

-10^9≤c_i≤10^9 (1≤i≤M)

c_i is an integer.

In the given graph, there exists a path from vertex 1 to vertex N.

Input

Input is given from Standard Input in the following format:

N M
a_1 b_1 c_1
a_2 b_2 c_2
:
a_M b_M c_M

Output

Print the maximum possible score at the end of the game, if it is finite. If it is possible to increase the score indefinitely, print inf.

Sample Input 1

3 3
1 2 4
2 3 3
1 3 5

Sample Output 1

7

There are two ways to move the piece to vertex N=3:

vertex 1 → vertex 2 → vertex 3 : score 4+3=7

vertex 1 → vertex 3 : score 5

Thus, the maximum possible score at the end of the game is 7.

Sample Input 2

2 2
1 2 1
2 1 1

Sample Output 2

inf

It is possible to increase the score indefinitely by alternating between vertex 1 and 2.

Sample Input 3

6 5
1 2 -1000000000
2 3 -1000000000
3 4 -1000000000
4 5 -1000000000
5 6 -1000000000

Sample Output 3

-5000000000

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
import java.util.Scanner;

public class Main {
	//java11

	public static void main(String[] args) {

		Scanner sc = new Scanner(System.in);

		int N = sc.nextInt();
		int M = sc.nextInt();

		List<Edge> edges = new ArrayList<>();
		long INF = Long.MAX_VALUE / 2;
		for(int i=0; i<M; i++) {
			int a = sc.nextInt();
			int b = sc.nextInt();
			long c = sc.nextLong();

			edges.add(new Edge(a, b, -c));
		}

		BF bf = new BF(N, edges, INF);
		long[] weights = bf.getMinWeightArray(1);
		long ans = weights[N-1];

		boolean[] negative = new boolean[N];
		Arrays.fill(negative, false);
		for(int i=0; i<N; i++) {
			for(int j=0; j<edges.size(); j++) {
				Edge e = edges.get(j);

				if(weights[e.from-1] == INF)
					continue;

				//すでに最短の重みの和になっているにもかかわらず、更新する場合負の閉路
				if(weights[e.to-1] > weights[e.from-1] + e.weight) {
					weights[e.to-1] = weights[e.from-1] + e.weight;
					negative[e.to-1] = true;
				}

				//負の閉路を通ってたどり着ける
				if(negative[e.from-1]) {
					negative[e.to-1] = true;
				}
			}
		}

		if(negative[N-1]) {
			System.out.println("inf");
		}else {
			System.out.println(-ans);
		}

	}

	public static class BF{
		int V;
		List<Edge> edges;
		long[] weights;
		long INF;

		public BF(int V, List<Edge> e, long INF) {
			this.V = V;
			edges = e;
			weights = new long[V];
			this.INF = INF;
		}

		//負の辺ありの最短距離の重み(ベルマンフォード法)(O(VE))
		public long getMinWeight(int start, int goal) {
			Arrays.fill(weights, INF);
			weights[start-1] = 0;

			for(int i=0; i<V; i++) {
				for(int j=0; j<edges.size(); j++) {
					Edge e = edges.get(j);

					if(weights[e.from-1] == INF)
						continue;

					if(weights[e.to-1] > weights[e.from-1] + e.weight) {
						weights[e.to-1] = weights[e.from-1] + e.weight;

						//負の閉路判定(あるときINFを返す)
						if(i == V-1) {
							return INF;
						}
					}
				}
			}

			return weights[goal-1];
		}

		//負の辺ありの最短距離の重みの集合(ベルマンフォード法)(O(VE))
		public long[] getMinWeightArray(int start) {
			Arrays.fill(weights, INF);
			weights[start-1] = 0;

			for(int i=0; i<V-1; i++) {
				for(int j=0; j<edges.size(); j++) {
					Edge e = edges.get(j);

					if(weights[e.from-1] == INF)
						continue;

					if(weights[e.to-1] > weights[e.from-1] + e.weight) {
						weights[e.to-1] = weights[e.from-1] + e.weight;

//						//負の閉路判定(あるときは空の配列を返す)
//						if(i == V-1) {
//							return new long[0];
//						}
					}
				}
			}

			return weights;
		}
	}

	//エッジを表すクラス(一般的なグラフのエッジとは異なる)
	public static class Edge{
		int from;
		int to;
		long weight;

		public Edge(int f, int t, long w) {
			from = f;
			to = t;
			weight = w;
		}
	}

}