Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Wrong Answer)



import java.util.Scanner;

public class Main {
	public static void main(String []args){
		//????????£?????????????????????
		Scanner sc = new Scanner(System.in);
		//??£?¨?
		String line ="";
		char temp;
		//26???????????¨?????????
		int [] array = new int[26];
		while(sc.hasNext()){
			//??±????????????
			line += sc.nextLine();
			//??¨???????????????????°??????????????????????
			String lower = line.toLowerCase();
			//System.out.println(lower);
			//?????????char ??????
			for(int i = 0; i<lower.length(); i++){
				temp = lower.charAt(i);
				//System.out.println(temp);
				//??\?????????????????¨a?????¢???????????????????????°?????§??????
				//if(Character.isLetter('a')){
				if('a' <= temp && temp<= 'z'){
					array[temp - 'a']++;
					}
				}
			for(int i =0; i<array.length;i++){
				System.out.println((char)('a'+i) + " : " + array[i]);
			}
		}
	}
}