Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Java7 (OpenJDK 1.7.0) (judge verdict: Time Limit Exceeded)

import java.util.Scanner;

public class Main
{
	public static void main(String args[])
	{
		Scanner sc = new Scanner(System.in);
		int n;
		n=sc.nextInt();
		int res,count,temp;
		res=0;
		if(n<105)
			System.out.println(0);
		else if(n==105)
			System.out.println(1);
		else
		{
			for(int i=106;i<=n;i++)
			{
				count=0;
				temp=i;
				for(int j=2;j<=i/2;i++)
				{
					if(temp%j==0)
					{
						temp=temp/j;
						count++;
					}
					if(temp==1)
						break;
				}
				if(count==3)
					res++;
			}
			System.out.println(res);
		}		
	}
}