Problem:
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Maximum Profit

You can obtain profits from foreign exchange margin transactions. For example, if you buy 1000 dollar at a rate of 100 yen per dollar, and sell them at a rate of 108 yen per dollar, you can obtain (108 - 100) × 1000 = 8000 yen.

Write a program which reads values of a currency $R_t$ at a certain time $t$ ($t = 0, 1, 2, ... n-1$), and reports the maximum value of $R_j - R_i$ where $j > i$ .

Input

The first line contains an integer $n$. In the following $n$ lines, $R_t$ ($t = 0, 1, 2, ... n-1$) are given in order.

Output

Print the maximum value in a line.

Constraints

$2 \leq n \leq 200,000$

$1 \leq R_t \leq 10^9$

Sample Input 1

6
5
3
1
3
4
3

Sample Output 1

3

Sample Input 2

3
4
3
2

Sample Output 2

-1

Solution in JAVA (judge verdict: WA: Presentation Error)

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
import java.util.Scanner;

/**
 * Created by martin-d28jp-love on 15/04/01.
 */
public class Main {

    public static void main(String[] args) {
        List<String> input = input();
//        List<String> input = mockuop();

        int inputLength = input.size();
        int maxSubtruction = 0;
        for (int i = 0; i < inputLength; i++) {
            for (int j = i; j < inputLength; j++) {
                int Ri = Integer.valueOf(input.get(i));
                int Rj = Integer.valueOf(input.get(j));
                if (Rj - Ri > maxSubtruction) {
                    maxSubtruction = Rj - Ri;
                }
            }
        }
        System.out.print(maxSubtruction);
    }

    public static List<String> mockuop() {
        List<String> input = Arrays.asList(
                "6",
                "5",
                "12",
                "11"
        );
        return input;
    }
    public static List<String> input() {
        Scanner in = new Scanner(System.in);
        List<String> input = new ArrayList<String>();
        while(in.hasNext()) {
            String buf = in.nextLine();
            input.add(buf);
        }
        in.close();
        return input;
    }
}