Problem:
Score : 100 points

Problem Statement

There are two buttons, one of size A and one of size B.

When you press a button of size X, you get X coins and the size of that button decreases by 1.

You will press a button twice. Here, you can press the same button twice, or press both buttons once.

At most how many coins can you get?

Constraints

All values in input are integers.

3 \leq A, B \leq 20

Input

Input is given from Standard Input in the following format:

A B

Output

Print the maximum number of coins you can get.

Sample Input 1

5 3

Sample Output 1

9

You can get 5 + 4 = 9 coins by pressing the button of size 5 twice, and this is the maximum result.

Sample Input 2

3 4

Sample Output 2

7

Sample Input 3

6 6

Sample Output 3

12

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Runtime Error)

package ABC124.ABC124A;

import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		Scanner scanner = new Scanner(System.in);
		String input1 = scanner.next();
		String input2 = scanner.next();
		scanner.close();

		int A = Integer.valueOf(input1);
		int B = Integer.valueOf(input2);

		// 対称性によりAが大きい方とする
		if(A < B) {
			int tmp = A;
			A = B;
			B = tmp;
		}
		// 2つめはどっちかなのでこれで決まる
		int result1 = A + A - 1;
		int result2 = A + B;
		if(result1 >= result2) {
			System.out.println(result1);
		} else {
			System.out.println(result2);
		}
	}

}