Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Accepted)

import java.util.Scanner;
public class Main {

	public static void main(String[] args) {
		String alphabet[] = new String[]{"a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"};
		int [] count = new int[26];
		Scanner sc = new Scanner(System.in);
		String inputValues = "";
		while (true) {
			String tmp = sc.nextLine();
			inputValues += tmp;
			if (!sc.hasNext()) {
				break;
			}
		}
		inputValues = inputValues.toLowerCase();
		String[] strAry = inputValues.split("");
		for (int i = 0; i < strAry.length; i++) {
			for (int j = 0; j < 26; j++) {
				if (strAry[i].equals(alphabet[j])) {
					count[j]++;
				}
			}
		}
		for (int i = 0; i < 26; i++) {
			System.out.println(String.format("%s : %d", alphabet[i], count[i]));
		}
	}
}