Problem:
Simultaneous Equation

Write a program which solve a simultaneous equation:

ax + by = c

dx + ey = f

The program should print x and y for given a, b, c, d, e and f (-1,000 ≤ a, b, c, d, e, f ≤ 1,000). You can suppose that given equation has a unique solution.

Input

The input consists of several data sets, 1 line for each data set. In a data set, there will be a, b, c, d, e, f separated by a single space. The input terminates with EOF.

Output

For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.

Sample Input 1

1 2 3 4 5 6
2 -1 -2 -1 -1 -5

Output for the Sample Input 1

-1.000 2.000
1.000 4.000

Sample Input 2

2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27

Output for the Sample Input 2

0.000 3.000
0.000 3.000

Solution in JAVA (judge verdict: Wrong Answer)

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.text.DecimalFormat;

public class Main {
	public static void main(String[] args) throws IOException {
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
		DecimalFormat df = new DecimalFormat("0.000");
		String str = br.readLine();
		while (str != null) {
			String[] datasetstr = str.split(" ", 6);
			int a = Integer.parseInt(datasetstr[0]);
			int b = Integer.parseInt(datasetstr[1]);
			int c = Integer.parseInt(datasetstr[2]);
			int d = Integer.parseInt(datasetstr[3]);
			int e = Integer.parseInt(datasetstr[4]);
			int f = Integer.parseInt(datasetstr[5]);
			double x = (double) (e * c - b * f) / (a * e - b * d);
			double y = (double) (a * f - c * d) / (a * e - b * d);
			System.out.println(df.format(x) + " " + df.format(y));
			str = br.readLine();
		}
	}
}