Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Scanner;

public class Main {
	public static void main(String[] args){
		Scanner sc = new Scanner(System.in);
		int array[][] = new int [3][3];

		boolean ans[][] = new boolean [3][3];




		for(int i = 0;i<3;i++){
			for(int j = 0;j<3;j++){
				array[i][j] = sc.nextInt();
			}
		}
		int n = sc.nextInt();

		for(int i = 0;i<n;i++){
			int tmp = sc.nextInt();
			for(int j = 0;j<3;j++){
				for(int k = 0;k<3;k++){
					if(array[j][k] == tmp){
						ans[j][k] = true;
					}
				}
			}
		}

		boolean a = false;
		for(int i = 0;i<3;i++){
			if((ans[i][0] && ans[i][1] && ans[i][2]) || (ans[0][i] && ans[1][i] && ans[2][i])){
				a= true;
				break;
			}
		}

		if(!a){
			if((ans[0][0] && ans[1][1] && ans[2][2]) || (ans[0][2] && ans[1][1] && ans[2][0])){
				a= true;
			}
		}

		if(a){
			System.out.println("Yes");
		}else{
			System.out.println("No");
		}

	}

	}