Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Accepted)

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.IOException;
public class Main{
    public static void main(String[] args) throws IOException{
        try{
            BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
            StringBuilder sb = new StringBuilder();
            int[] counter = new int[26];
            String line; 
            //line = br.readLine();
            char ch = 'a';
            //char[] c = line.toCharArray();
            while((line = br.readLine())!=null){
                char[] c = line.toCharArray();
                for(int i = 0; i < c.length; i++){
                    if( c[i] >= 'A' && c[i] <= 'z' ){
                        if( Character.isUpperCase(c[i]) ){
                            c[i] = Character.toLowerCase(c[i]);
                        }
                        int num = c[i] - 'a';
                        counter[num]++;
                    }
                }
            }
             
            for(int i = 0; i < counter.length; i++){
                System.out.println( ch++ + " : " + counter[i]);
            }
        }catch(IOException e){
            System.out.println(e);
        }
    }
}