Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Accepted)

import java.util.Scanner;

public class Main {
	public static void main(String[] args) {
		int[] count=new int[26];
		try (Scanner scan=new Scanner(System.in)){
		while(scan.hasNextLine()) {
			String str=scan.nextLine();
			for(int i=0;i<str.length();i++) {
				if(0<=str.charAt(i)-'a' && str.charAt(i)-'a'<26)
				count[str.charAt(i)-'a']++;
				else if(0<=str.charAt(i)-'A' && str.charAt(i)-'A'<26)
				count[str.charAt(i)-'A']++;
			}
		}
		for(int i=0;i<26;i++) {
			System.out.printf("%c : %d\n",i+'a',count[i]);
		}
		}
}
}