Problem:
Score : 200 points

Problem Statement

There is a square in the xy-plane. The coordinates of its four vertices are (x_1,y_1),(x_2,y_2),(x_3,y_3) and (x_4,y_4) in counter-clockwise order.
(Assume that the positive x-axis points right, and the positive y-axis points up.)

Takahashi remembers (x_1,y_1) and (x_2,y_2), but he has forgot (x_3,y_3) and (x_4,y_4).

Given x_1,x_2,y_1,y_2, restore x_3,y_3,x_4,y_4. It can be shown that x_3,y_3,x_4 and y_4 uniquely exist and have integer values.

Constraints

|x_1|,|y_1|,|x_2|,|y_2| \leq 100

(x_1,y_1) ≠ (x_2,y_2)

All values in input are integers.

Input

Input is given from Standard Input in the following format:

x_1 y_1 x_2 y_2

Output

Print x_3,y_3,x_4 and y_4 as integers, in this order.

Sample Input 1

0 0 0 1

Sample Output 1

-1 1 -1 0

(0,0),(0,1),(-1,1),(-1,0) is the four vertices of a square in counter-clockwise order.
Note that (x_3,y_3)=(1,1),(x_4,y_4)=(1,0) is not accepted, as the vertices are in clockwise order.

Sample Input 2

2 3 6 6

Sample Output 2

3 10 -1 7

Sample Input 3

31 -41 -59 26

Sample Output 3

-126 -64 -36 -131

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Scanner;


public class Main {

	public static void main(String[] args) {
		Scanner stdin = new Scanner(System.in);
		int x1, y1, x2, y2, x3, y3, x4, y4;
		x1 = stdin.nextInt();
		y1 = stdin.nextInt();
		x2 = stdin.nextInt();
		y2 = stdin.nextInt();
		
//		System.out.println(x1);
//		System.out.println(y1);
//		System.out.println(x2);
//		System.out.println(y2);
		
		x3 = x2 - (y2 - y1);
		y3 = y2 + (x2 - x1);
		x4 = x3 - (y3 - y2);
		y4 = y3 + (x3 - x2);
		
//		System.out.println(x3);
//		System.out.println(y3);
//		System.out.println(x4);
//		System.out.println(y4);
		
		System.out.println(x3 + " " + y3 + " " + x4 + " " + y4);

	}

}