Problem:
Score : 200 points

Problem Statement

Given are integers a,b,c and d.
If x and y are integers and a \leq x \leq b and c\leq y \leq d hold, what is the maximum possible value of x \times y?

Constraints

-10^9 \leq a \leq b \leq 10^9

-10^9 \leq c \leq d \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

a b c d

Output

Print the answer.

Sample Input 1

1 2 1 1

Sample Output 1

2

If x = 1 and y = 1 then x \times y = 1.
If x = 2 and y = 1 then x \times y = 2.
Therefore, the answer is 2.

Sample Input 2

3 5 -4 -2

Sample Output 2

-6

The answer can be negative.

Sample Input 3

-1000000000 0 -1000000000 0

Sample Output 3

1000000000000000000

Solution in Java (OpenJDK 11.0.6) (judge verdict: Wrong Answer)

import java.util.*;
public class Main
{
	public static void main(String args[]){
        Scanner sc= new Scanner(System.in);
        long a=sc.nextLong();
        long b=sc.nextLong();
        long c=sc.nextLong();
        long d=sc.nextLong();
        
        long ans=1;
        
        if(a<=0 && b<=0){
            if(c<=0)
                ans=a*c;
            else if(c>=0)
                ans=b*c;
        }
        
        else if(a<=0 && b>=0){
            if(d<=0)
                ans=a*c;
            else if(d>=0)
                ans=b*d;
        }
        
        else if(a>=0 && b>=0){
            if(d<=0)
                ans=a*d;
            else if(d>=0)
                ans=b*d;
        }
       
        System.out.println(ans);
    }
}