Problem:
Score : 200 points

Problem Statement

Raccoon is fighting with a monster.

The health of the monster is H.

Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i.
There is no other way to decrease the monster's health.

Raccoon wins when the monster's health becomes 0 or below.

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Constraints

1 \leq H \leq 10^9

1 \leq N \leq 10^5

1 \leq A_i \leq 10^4

All values in input are integers.

Input

Input is given from Standard Input in the following format:

H N
A_1 A_2 ... A_N

Output

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Sample Input 1

10 3
4 5 6

Sample Output 1

Yes

The monster's health will become 0 or below after, for example, using the second and third moves.

Sample Input 2

20 3
4 5 6

Sample Output 2

No

Sample Input 3

210 5
31 41 59 26 53

Sample Output 3

Yes

Sample Input 4

211 5
31 41 59 26 53

Sample Output 4

No

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

/*
    Those who cannot remember the past are condemned to repeat it.
                                            - Dynamic Programming
    
    I never lose, I either win or I learn.
                - Competitive Programming

*/

import javax.print.DocFlavor;
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.StringTokenizer;

public class Main {
    public static void main(String[] args) throws Exception {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        StringTokenizer st;
        PrintWriter pw = new PrintWriter(System.out);

        st = new StringTokenizer(br.readLine());
        int h = Integer.parseInt(st.nextToken());
        int n = Integer.parseInt(st.nextToken());
        long sum = 0;
        st = new StringTokenizer(br.readLine());
        for(int i=0 ; i<n ; i++) {
            sum += Integer.parseInt(st.nextToken());
        }

        if(h <= sum) {
            pw.println("Yes");
        }
        else {
            pw.println("No");
        }
        
        
        
        
        
        
        
        pw.flush();
        pw.close();
    }
}