Problem:
Score : 200 points

Problem Statement

There are N cities and M roads.
The i-th road (1≤i≤M) connects two cities a_i and b_i (1≤a_i,b_i≤N) bidirectionally.
There may be more than one road that connects the same pair of two cities.
For each city, how many roads are connected to the city?

Constraints

2≤N,M≤50

1≤a_i,b_i≤N

a_i ≠ b_i

All input values are integers.

Input

Input is given from Standard Input in the following format:

N M
a_1 b_1
:
a_M b_M

Output

Print the answer in N lines.
In the i-th line (1≤i≤N), print the number of roads connected to city i.

Sample Input 1

4 3
1 2
2 3
1 4

Sample Output 1

2
2
1
1

City 1 is connected to the 1-st and 3-rd roads.

City 2 is connected to the 1-st and 2-nd roads.

City 3 is connected to the 2-nd road.

City 4 is connected to the 3-rd road.

Sample Input 2

2 5
1 2
2 1
1 2
2 1
1 2

Sample Output 2

5
5

Sample Input 3

8 8
1 2
3 4
1 5
2 8
3 7
5 2
4 1
6 8

Sample Output 3

3
3
2
2
2
1
1
2

Solution in Java (OpenJDK 11.0.6) (judge verdict: Accepted)


import java.util.*;
import java.io.*;

public class Main {

	private static final int mod =(int)1e9+7;
	public static void main(String[] args) throws Exception  {
	      Scanner  sc=new Scanner(System.in);
	      PrintWriter out=new PrintWriter(System.out);
	     int n=sc.nextInt();
	     int m=sc.nextInt();
	     ArrayList<ArrayList<Integer>> aa=new ArrayList<>();
	     for(int i=0;i<n;i++) {
	       aa.add(new ArrayList<>());
	     }
	     for(int i=0;i<m;i++) {
	       int a=sc.nextInt();
	       int b=sc.nextInt();
	       aa.get(a-1).add(b-1);
	       aa.get(b-1).add(a-1);
	     }
	       for(ArrayList<Integer> i:aa) {
	         System.out.println(i.size());
	       }
	}


	static boolean vis[]=new boolean[10001];
	      static long gcd(long a, long b) 
	      { 
	          if (a == 0) 
	              return b; 
	          return gcd(b % a, a); 
	      } 

static long nCr(int n,int r) {
  int dp[][]=new int[2001][2001];
  for(int i=0;i<2001;i++) {
    dp[0][i]=0;
  }
  for(int i=0;i<2001;i++) {
    dp[i][0]=1;
  }
  for(int i=1;i<2001;i++) {
    for(int j=1;j<2001;j++) {
      if(i==j) {
        dp[i][j]=1;
      }else {
        dp[i][j]=dp[i-1][j-1]+dp[i][j-1];
      }
    }
  }
  return dp[n][r];
}


      
}
class pair{
  int wt,val;
  pair(int wt,int val){
    this.wt=wt;
    this.val=val;
  }
}