Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Java (OpenJDK 11.0.6) (judge verdict: Accepted)

import java.util.Scanner;
import java.util.LinkedHashSet;
import java.util.Set;
public class Main {
  public static void main(String[] args) {
    Scanner sc = new Scanner(System.in);
    int n = sc.nextInt();
    int count = 0;
    for(int i=105;i<=n;i++){
      if(i%2==1){
        if(check(i)){
          count++;
        }
      }
    }
    System.out.println(count);
  }   
  static boolean check(int n){
    int count=0;
      for(int i=1;i<=n;i++){
        if(n%i == 0){
          count++;
        }
      }
    if(count==8){
      return true;
    }else{
      return false;
    }
  }
}