Problem:
Score : 200 points

Problem Statement

You are given an image A composed of N rows and N columns of pixels, and a template image B composed of M rows and M columns of pixels.

A pixel is the smallest element of an image, and in this problem it is a square of size 1×1.

Also, the given images are binary images, and the color of each pixel is either white or black.

In the input, every pixel is represented by a character: . corresponds to a white pixel, and # corresponds to a black pixel.

The image A is given as N strings A_1,...,A_N.

The j-th character in the string A_i corresponds to the pixel at the i-th row and j-th column of the image A (1≦i,j≦N).

Similarly, the template image B is given as M strings B_1,...,B_M.

The j-th character in the string B_i corresponds to the pixel at the i-th row and j-th column of the template image B (1≦i,j≦M).

Determine whether the template image B is contained in the image A when only parallel shifts can be applied to the images.

Constraints

1≦M≦N≦50

A_i is a string of length N consisting of # and ..

B_i is a string of length M consisting of # and ..

Input

The input is given from Standard Input in the following format:

N M
A_1
A_2
:
A_N
B_1
B_2
:
B_M

Output

Print Yes if the template image B is contained in the image A. Print No otherwise.

Sample Input 1

3 2
#.#
.#.
#.#
#.
.#

Sample Output 1

Yes

The template image B is identical to the upper-left 2 × 2 subimage and the lower-right 2 × 2 subimage of A. Thus, the output should be Yes.

Sample Input 2

4 1
....
....
....
....
#

Sample Output 2

No

The template image B, composed of a black pixel, is not contained in the image A composed of white pixels.

Solution in Java (OpenJDK 11.0.6) (judge verdict: Accepted)

import java.util.*;
public class Main {
  public static void main(String[] args) {
    Scanner sc = new Scanner(System.in);
    int N = sc.nextInt();
    int M = sc.nextInt();
    char[][] A = new char[N][N];
    char[][] B = new char[M][M];
    for(int i=0;i<N;i++){
      String n = sc.next();
      for(int j=0;j<N;j++){
        A[i][j]=n.charAt(j);
      }
    }
    for(int i=0;i<M;i++){
      String m = sc.next();
      for(int j=0;j<M;j++){
        B[i][j]=m.charAt(j);
      }
    }
    for(int i=0;i<N;i++){
      for(int j=0;j<N;j++){
        if(i+M>N || j+M>N){
          break;
        }
        boolean match = true;
        for(int k=0;k<M;k++){
          for(int l=0;l<M;l++){
            if(A[i+k][j+l]!=B[k][l]){
              match = false;
              break;
            }
          }
        }
        if(match){
          System.out.println("Yes");
          return;
        }
      }
    }
    System.out.println("No");
  }
}