Problem:
Score : 200 points

Problem Statement

Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Constraints

1 \leq N \leq 10^5

Input

Input is given from Standard Input in the following format:

N

Output

Print the number of positive integers less than or equal to N that have an odd number of digits.

Sample Input 1

11

Sample Output 1

9

Among the positive integers less than or equal to 11, nine integers have an odd number of digits: 1, 2, \ldots, 9.

Sample Input 2

136

Sample Output 2

46

In addition to 1, 2, \ldots, 9, another 37 integers also have an odd number of digits: 100, 101, \ldots, 136.

Sample Input 3

100000

Sample Output 3

90909

Solution in Java7 (OpenJDK 1.7.0) (judge verdict: Accepted)



import java.util.*;

public class Main {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int N = sc.nextInt();
        int digitNum = (int)Math.log10(N) + 1;

        int ans = 0;
        if(digitNum == 6){
            ans = 9 + 900 + 90000;
        }else if(digitNum == 5){
            ans = 9 + 900 + N - 10000 + 1;
        }else if(digitNum == 4){
            ans = 9 + 900;
        }else if(digitNum == 3){
            ans = 9 + N - 100 + 1;
        }else if(digitNum == 2){
            ans = 9;
        }else if(digitNum == 1){
            ans = N;
        }
        System.out.println("" + ans);
    }

}