Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.*;
public class Main {
	public static void main(String[] args){
		Scanner sc = new Scanner(System.in);
		int N = sc.nextInt();
		if(N < 20){
        	System.out.println(0);
        	return;
        }
      	int Ncnt = 0;
      	for(int i = 1; i < N; i+=2){
          	Integer hN = (int) Math.floor(N/2);
          	int cnt = 0;
        	for(int j = 1; j < hN; j++){
              	if(i%j==0){
                	cnt++;
                }
            }
          	if(cnt==8){
              Ncnt++;
            }
        }
		System.out.println(Ncnt);
	}
}