Problem:
Score : 200 points

Problem Statement

La Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each.
Determine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.

Constraints

N is an integer between 1 and 100, inclusive.

Input

Input is given from Standard Input in the following format:

N

Output

If there is a way to buy some cakes and some doughnuts for exactly N dollars, print Yes; otherwise, print No.

Sample Input 1

11

Sample Output 1

Yes

If you buy one cake and one doughnut, the total will be 4 + 7 = 11 dollars.

Sample Input 2

40

Sample Output 2

Yes

If you buy ten cakes, the total will be 4 \times 10 = 40 dollars.

Sample Input 3

3

Sample Output 3

No

The prices of cakes (4 dollars) and doughnuts (7 dollars) are both higher than 3 dollars, so there is no such way.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.*;
public class Main{
	public static void main(String[] args){
		Scanner sc = new Scanner(System.in);
		//数値を入力
		int N = sc.nextInt();
		//変数宣言
		int cake = 4;
		int donuts = 7;
		//計算
		int ans1 = N % cake;
		int ans2 = N % donuts;
		int ans3 = N % (cake + donuts);
		//判断
		if(cake > N){
			System.out.println("No");
		}
		else if(ans1 == 0 || ans1 == 3){
			System.out.println("Yes");
		}
		else if(ans2 == 0 || ans2 == 4){
			System.out.println("Yes");
		}
		else if(ans3 == 0 || ans3 == 4 || ans3 == 7){
			System.out.println("Yes");
		}
		else{
			System.out.println("No");
		}
	}
}