Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Wrong Answer)

import java.util.Scanner;

class Main {
  public static void main(String[] args) {
    Scanner sc = new Scanner(System.in);
    int[] counter = new int[26];
    while (sc.hasNext()) {
      String str = sc.nextLine();
      for (int i = 0; i < str.length(); i++) {
        int num = 0;
        char ch = str.charAt(i);
        if (Character.isLowerCase(ch)) {
          num = str.charAt(i) - 'a';
        } else {
          num = str.charAt(i) - 'A';
        }
        if (num >= 0 && num <= 26) {
          counter[num]++;
        }
      }
    }
    for (int i = 0; i < counter.length; i++) {
      System.out.println(counter[i]);
    }
  }
}