Problem:
Score : 400 points

Problem Statement

Given are integers A, B, and N.

Find the maximum possible value of floor(Ax/B) - A × floor(x/B) for a non-negative integer x not greater than N.

Here floor(t) denotes the greatest integer not greater than the real number t.

Constraints

1 ≤ A ≤ 10^{6}

1 ≤ B ≤ 10^{12}

1 ≤ N ≤ 10^{12}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B N

Output

Print the maximum possible value of floor(Ax/B) - A × floor(x/B) for a non-negative integer x not greater than N, as an integer.

Sample Input 1

5 7 4

Sample Output 1

2

When x=3, floor(Ax/B)-A×floor(x/B) = floor(15/7) - 5×floor(3/7) = 2. This is the maximum value possible.

Sample Input 2

11 10 9

Sample Output 2

9

Solution in Java (OpenJDK 11.0.6) (judge verdict: Wrong Answer)

import java.util.*; 
import java.lang.*; 


public class Main{
	public static void main(String[] args){
		Scanner scan = new Scanner(System.in);
                
                long A = scan.nextLong();
                long B = scan.nextLong();
                long N = scan.nextLong();
                
                long k=0;
                long l=0;
                
                long ans = -1;
                long preans = 0;
                
                long prean = 0;
                long xans = 0;
 
                for(long x=N/2; x<=N; x++ ){
                     k = (A*x)/B;
                     l = (x/B);
                     
                     preans = ans;
                     ans = k - A*l;
                     
                     if(preans>ans){
                         System.out.println(prean);
                     }
                }     
                 System.out.println(ans);
        }
}