Problem:
Score : 300 points

Problem Statement

You are given two integer sequences of length N: a_1,a_2,..,a_N and b_1,b_2,..,b_N.
Determine if we can repeat the following operation zero or more times so that the sequences a and b become equal.

Operation: Choose two integers i and j (possibly the same) between 1 and N (inclusive), then perform the following two actions simultaneously:

Add 2 to a_i.

Add 1 to b_j.

Constraints

1 ≤ N ≤ 10 000

0 ≤ a_i,b_i ≤ 10^9 (1 ≤ i ≤ N)

All input values are integers.

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 .. a_N
b_1 b_2 .. b_N

Output

If we can repeat the operation zero or more times so that the sequences a and b become equal, print Yes; otherwise, print No.

Sample Input 1

3
1 2 3
5 2 2

Sample Output 1

Yes

For example, we can perform three operations as follows to do our job:

First operation: i=1 and j=2. Now we have a = \{3,2,3\}, b = \{5,3,2\}.

Second operation: i=1 and j=2. Now we have a = \{5,2,3\}, b = \{5,4,2\}.

Third operation: i=2 and j=3. Now we have a = \{5,4,3\}, b = \{5,4,3\}.

Sample Input 2

5
3 1 4 1 5
2 7 1 8 2

Sample Output 2

No

Sample Input 3

5
2 7 1 8 2
3 1 4 1 5

Sample Output 3

No

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.*;

class Main {
   public static void main(String[] args)
   {
      Scanner scan = new Scanner(System.in);
      int     num = scan.nextInt();
      int     value = 0, count = 0;

      int[] A = new int[num];
      int[] B = new int[num];

      for(int i = 0; i < num; i++){
          A[i] = scan.nextInt();
          }
      for(int j = 0; j < num; j++){
          B[j] = scan.nextInt();
          }

      //Arrays.sort(A);
      //Arrays.sort(B);
      for(int i = 0; i < num; i++){
          if(A[i] < B[i]){
             do {
                A[i] += 2;
                value++;
                } while(A[i] < B[i]);
             //System.out.println("value" + value);
             if(A[i] > B[i]){
                count += A[i] - B[i];
                //System.out.println(count);
                }
             }
          else{
              count += A[i] - B[i];
              }
          }
      System.out.println("cou" + count);
      if((value - count) >= 0 && (value - count) <= 1){
         System.out.println("Yes");
         return;
         }
      else{
          System.out.println("No");
          return;
          }
   }
}