Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Java (OpenJDK 11.0.6) (judge verdict: Accepted)

import java.util.Scanner;
import java.util.stream.IntStream;

public class Main {

	public static void main(String[] args) {
		try (Scanner scanner = new Scanner(System.in)) {
			int n = scanner.nextInt();
			System.out.println(IntStream.rangeClosed(1, (n + 1) / 2).map(i -> 2 * i - 1)
					.filter(i -> 8 == getDivisorNumber(i)).count());
		}
	}

	/**
	 * nの約数の数を計算する
	 * 
	 * @param n
	 * @return nの約数の数
	 */
	private static int getDivisorNumber(int n) {
		int count = 0;
		for (int i = 1; i <= (int) Math.sqrt(n); i++) {
			if (0 == n % i) {
				count += (i == n / i) ? 1 : 2;
			}
		}
		return count;
	}
}