Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Accepted)

import java.util.ArrayList;
import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		// TODO 自動生成されたメソッド・スタブ
		char Character[] = {'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j',
				'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z'};

		ArrayList<String> strInput = new ArrayList<String>();
		Scanner scanner = new Scanner(System.in);

		int intLineNum = 0;
		while (scanner.hasNext()) {
			String strLine = scanner.nextLine();

			//if (strLine.length() == 0) {
			//	break;
			//}

			strInput.add(strLine);
			intLineNum++;
		}

			for (int intI = 0; intI < 26; intI++) {
				int intCounter = 0;
				for (int intJ = 0; intJ < intLineNum; intJ++) {
					for (int intK = 0; intK < strInput.get(intJ).length(); intK++) {
						char charLine = strInput.get(intJ).charAt(intK);
							String strMoji = String.valueOf(charLine);
							String strChar = String.valueOf(Character[intI]);
							if (strMoji.equalsIgnoreCase(strChar)) {
								intCounter++;
							}
					}
				}
				System.out.println(Character[intI] + " : " + intCounter);
			}
	}

}