Problem:
Score : 100 points

Problem Statement

X and A are integers between 0 and 9 (inclusive).

If X is less than A, print 0; if X is not less than A, print 10.

Constraints

0 \leq X, A \leq 9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X A

Output

If X is less than A, print 0; if X is not less than A, print 10.

Sample Input 1

3 5

Sample Output 1

0

3 is less than 5, so we should print 0.

Sample Input 2

7 5

Sample Output 2

10

7 is not less than 5, so we should print 10.

Sample Input 3

6 6

Sample Output 3

10

6 is not less than 6, so we should print 10.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Runtime Error)

package j.hiro.practice;

import java.util.Scanner;

/**
 * Rounding
 */
public class Main {

    public static void main(String... args) {
        // 標準入力から読み取り
        Scanner sc = new Scanner(System.in);
        int x = sc.nextInt();
        int a = sc.nextInt();
        sc.close();

        /* xがa未満であれば0を、a以上の時に10を出力 */
        // System.out.println(x < a ? 0 : 10);
        if(x < a) System.out.println(0);
        else System.out.println(10);
    }
}