Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Accepted)

import java.util.*;

public class Main{
    public static void main(String[] args){
        Scanner sc = new Scanner(System.in);
        //String word = sc.next();
        String array = "";
        String alpha = "abcdefghijklmnopqrstuvwxyz";
        int count = 0;
        while(sc.hasNext()){
            array = array + sc.next();
        }
        for(int i=0;i<26;i++){
            for(int j=0;j<array.length();j++){
                if(array.toLowerCase().charAt(j) == alpha.charAt(i)){
                    count++;
                }
            }
            System.out.println(alpha.charAt(i) + " : " + count);
            count = 0;
        }
        sc.close();
    }
}