Problem:
Score : 300 points

Problem Statement

As a token of his gratitude, Takahashi has decided to give his mother an integer sequence.
The sequence A needs to satisfy the conditions below:

A consists of integers between X and Y (inclusive).

For each 1\leq i \leq |A|-1, A_{i+1} is a multiple of A_i and strictly greater than A_i.

Find the maximum possible length of the sequence.

Constraints

1 \leq X \leq Y \leq 10^{18}

All input values are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

Print the maximum possible length of the sequence.

Sample Input 1

3 20

Sample Output 1

3

The sequence 3,6,18 satisfies the conditions.

Sample Input 2

25 100

Sample Output 2

3

Sample Input 3

314159265 358979323846264338

Sample Output 3

31

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Optional;
import java.util.Scanner;

public class Main {
	public static void main(String[] args) {
		Main main = new Main();
		main.solveC();
	}

	private void solveA() {
		Scanner sc = new Scanner(System.in);
		int N = sc.nextInt();
		System.out.println(N);
	}

	private void solveB() {
		Scanner sc = new Scanner(System.in);
		int N = sc.nextInt();
		System.out.println(N);
	}

	private void solveC() {
		Scanner sc = new Scanner(System.in);
		long X = sc.nextLong();
		long Y = sc.nextLong();
		int ans = 0;
		while (X <= Y) {
			X *= 2;
			ans++;
		}
		System.out.println(ans);
	}

	private void solveD() {
		Scanner sc = new Scanner(System.in);
		int N = sc.nextInt();
		System.out.println(N);
	}

	private void solveE() {
		Scanner sc = new Scanner(System.in);
		int N = sc.nextInt();
		System.out.println(N);
	}

	private void solveF() {
		Scanner sc = new Scanner(System.in);
		int N = sc.nextInt();
		System.out.println(N);
	}

	interface Graph {
		void link(int from, int to, int cost);
		Optional<Integer> getCost(int from, int to);
		int getVertexNum();
	}

	interface FlowResolver {
		int maxFlow(int from, int to);
	}

	/**
	 * グラフの行列による実装
	 * 接点数の大きいグラフで使うとMLEで死にそう
	 */
	class ArrayGraph implements Graph {
		private Integer[][] costArray;
		private int vertexNum;

		public ArrayGraph(int n) {
			costArray = new Integer[n][];
			for (int i = 0; i < n; i++) {
				costArray[i] = new Integer[n];
			}
			vertexNum = n;
		}

		@Override
		public void link(int from, int to, int cost) {
			costArray[from][to] = new Integer(cost);
		}

		@Override
		public Optional<Integer> getCost(int from, int to) {
			return Optional.ofNullable(costArray[from][to]);
		}

		@Override
		public int getVertexNum() {
			return vertexNum;
		}
	}

	/**
	 * DFS(深さ優先探索)による実装
	 * 計算量はO(E*MaxFlow)のはず (E:辺の数, MaxFlow:最大フロー)
	 */
	class DfsFlowResolver implements FlowResolver {
		private Graph graph;
		public DfsFlowResolver(Graph graph) {
			this.graph = graph;
		}

		/**
		 * 最大フロー(最小カット)を求める
		 * @param from 始点(source)のID
		 * @param to 終点(target)のID
		 * @return 最大フロー(最小カット)
		 */
		public int maxFlow(int from, int to) {
			int sum = 0;
			int currentFlow;
			do {
				currentFlow = flow(from, to,Integer.MAX_VALUE / 3, new boolean[graph.getVertexNum()]);
				sum += currentFlow;
			} while (currentFlow > 0);
			return sum;
		}

		/**
		 * フローの実行 グラフの更新も行う
		 * @param from 現在いる節点のID
		 * @param to 終点(target)のID
		 * @param current_flow ここまでの流量
		 * @param passed 既に通った節点か否かを格納した配列
		 * @return 終点(target)に流した流量/戻りのグラフの流量
		 */
		private int flow(int from, int to, int current_flow, boolean[] passed) {
			passed[from] = true;
			if (from == to) {
				return current_flow;
			}
			for (int id = 0; id < graph.getVertexNum(); id++) {
				if (passed[id]) {
					continue;
				}
				Optional<Integer> cost = graph.getCost(from, id);
				if (cost.orElse(0) > 0) {
					int nextFlow = current_flow < cost.get() ? current_flow : cost.get();
					int returnFlow = flow(id, to, nextFlow, passed);
					if (returnFlow > 0) {
						graph.link(from, id, cost.get() - returnFlow);
						graph.link(id, from, graph.getCost(id, from).orElse(0) + returnFlow);
						return returnFlow;
					}
				}
			}
			return 0;
		}
	}
}