Problem:
Finding Missing Cards

Taro is going to play a card game. However, now he has only n cards, even though there should be 52 cards (he has no Jokers).

The 52 cards include 13 ranks of each of the four suits: spade, heart, club and diamond.

Input

In the first line, the number of cards n (n ≤ 52) is given.

In the following n lines, data of the n cards are given. Each card is given by a pair of a character and an integer which represent its suit and rank respectively. A suit is represented by 'S', 'H', 'C' and 'D' for spades, hearts, clubs and diamonds respectively. A rank is represented by an integer from 1 to 13.

Output

Print the missing cards. The same as the input format, each card should be printed with a character and an integer separated by a space character in a line.
Arrange the missing cards in the following priorities:

Print cards of spades, hearts, clubs and diamonds in this order.

If the suits are equal, print cards with lower ranks first.

Sample Input

47
S 10
S 11
S 12
S 13
H 1
H 2
S 6
S 7
S 8
S 9
H 6
H 8
H 9
H 10
H 11
H 4
H 5
S 2
S 3
S 4
S 5
H 12
H 13
C 1
C 2
D 1
D 2
D 3
D 4
D 5
D 6
D 7
C 3
C 4
C 5
C 6
C 7
C 8
C 9
C 10
C 11
C 13
D 9
D 10
D 11
D 12
D 13

Sample Output

S 1
H 3
H 7
C 12
D 8

Note

      解説

Solution in JAVA (judge verdict: Accepted)

import java.util.Scanner;


public class Main {

	public static void main(String[] args) {
		
		Scanner scan = new Scanner(System.in);
		int n = scan.nextInt();
		String design;
		int num;
		String[] mark = {"S", "H", "C", "D"};
		
		boolean[] tramp = new boolean[52];		// spade,heart,clover,diamond??????
		
		for (int i = 0; i < n; i++) {
			
			design = scan.next();
			num = scan.nextInt();
			if (design.equals("S")) {
				tramp[num - 1] = true;
			} else if (design.equals("H")) {
				tramp[num + 13 - 1] = true;
			} else if (design.equals("C")) {
				tramp[num + 26 - 1] = true;
			} else if (design.equals("D")) {
				tramp[num + 39 - 1] = true;
			}
			
		}
		
		for (int i = 0; i < 52; i++) {
			if (tramp[i] == false) {
				System.out.println(mark[i/13] + " " + (i % 13 + 1));
			}
		}
	}

}