Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)


import java.util.Scanner;
//
public class Main {
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
//━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━
		int n=sc.nextInt();
		int ans =0;
		for (int i=1;2*i-1<=n;i++) {
			if(divisorCount(2*i-1)==8) {
				ans++;
			}
		}
		System.out.println(ans);
//━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━
	}
	//----------------------------------------
	//置き場
	static int divisorCount(int n) {
		int res=0;
		for (int i=1;i<=n;i++) {
			if (n%i==0) {
				res++;
			}
		}
		return res;
	}
	//----------------------------------------
}