Problem:
Score : 300 points

Problem Statement

Given is a string S of length N-1.
Each character in S is < or >.

A sequence of N non-negative integers, a_1,a_2,\cdots,a_N, is said to be good when the following condition is satisfied for all i (1 \leq i \leq N-1):

If S_i= <: a_i<a_{i+1}

If S_i= >: a_i>a_{i+1}

Find the minimum possible sum of the elements of a good sequence of N non-negative integers.

Constraints

2 \leq N \leq 5 \times 10^5

S is a string of length N-1 consisting of < and >.

Input

Input is given from Standard Input in the following format:

S

Output

Find the minimum possible sum of the elements of a good sequence of N non-negative integers.

Sample Input 1

<>>

Sample Output 1

3

a=(0,2,1,0) is a good sequence whose sum is 3.
There is no good sequence whose sum is less than 3.

Sample Input 2

<>>><<><<<<<>>><

Sample Output 2

28

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.*;
import java.util.Scanner;

public class Main {
    public static void main(String[] args) throws Exception {
        Scanner sc = new Scanner(System.in);
        String S = sc.next();
        int r = 0;
        int l = 0;
        int res = 0;
        for(int i = 0;i < S.length();i++){
            if(S.charAt(i) == '<'){
                r++;
                if(l > 0){
                    if(r > l){
                        res = res + ((r * (r + 1)) + (l * (l - 1))) / 2;
                    }else{
                        res = res + ((r * (r - 1)) + (l * (l + 1))) / 2;
                    }
                    r = 0;
                    l = 0;
                }
            }else{
                l++;
            }
        }
        if(r > 0){
            if(l > 0){
                if(r > l){
                    res = res + ((r * (r + 1)) + (l * (l - 1))) / 2;
                }else{
                    res = res + ((r * (r - 1)) + (l * (l + 1))) / 2;
                }
            }else{
                res = res + (r * (r + 1)) / 2;
            }
        }
        
        System.out.println(res);
    }
}