Problem:
Score : 200 points

Problem Statement

Raccoon is fighting with a monster.

The health of the monster is H.

Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i.
There is no other way to decrease the monster's health.

Raccoon wins when the monster's health becomes 0 or below.

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Constraints

1 \leq H \leq 10^9

1 \leq N \leq 10^5

1 \leq A_i \leq 10^4

All values in input are integers.

Input

Input is given from Standard Input in the following format:

H N
A_1 A_2 ... A_N

Output

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Sample Input 1

10 3
4 5 6

Sample Output 1

Yes

The monster's health will become 0 or below after, for example, using the second and third moves.

Sample Input 2

20 3
4 5 6

Sample Output 2

No

Sample Input 3

210 5
31 41 59 26 53

Sample Output 3

Yes

Sample Input 4

211 5
31 41 59 26 53

Sample Output 4

No

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.*;
import java.util.ArrayList;
import java.util.List;
import java.util.Arrays;

public class Main {
    public static void main(String[] args) {
        // Your code here!
        Scanner sc = new Scanner(System.in);
        int h = sc.nextInt();
        int n = sc.nextInt();
        String ans = "Yes";
        int a[] = new int[n]; 
        for(int i = 0; i < n; i++){
            a[i] = sc.nextInt();
            System.out.println("a[i]"+a[i]);
        }
        double sum = 0;
        for(int i = 0; i < a.length; i++){
            sum += a[i];
            System.out.println("sum"+sum);
            
        }
        if(sum <= h){
                ans = "No";
        }
        System.out.println(ans);
    }
}