Problem:
Score : 200 points

Problem Statement

Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print -1 instead.

Constraints

2 \leq N \leq 10^5

0 \leq A_i \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the value A_1 \times ... \times A_N as an integer, or -1 if the value exceeds 10^{18}.

Sample Input 1

2
1000000000 1000000000

Sample Output 1

1000000000000000000

We have 1000000000 \times 1000000000 = 1000000000000000000.

Sample Input 2

3
101 9901 999999000001

Sample Output 2

-1

We have 101 \times 9901 \times 999999000001 = 1000000000000000001, which exceeds 10^{18}, so we should print -1 instead.

Sample Input 3

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0

Sample Output 3

0

Solution in Java (OpenJDK 1.8.0) (judge verdict: Runtime Error)

import java.util.*;
import java.lang.Math;
public class Main {
    public static void main (String [] args)
    {
        long max = (long)Math.pow(10,18);
        Scanner s = new Scanner(System.in);
        
        int len = s.nextInt();
        boolean isZero = false;
        boolean tooLong = false;
        int[] nums = new int[len];
        for(int i = 0; i < len; i++)
        {
            nums[i] = s.nextInt();
            if(nums[i] == 0)
            {
                isZero = true;
            }
        }
        int result = 1;
        
        for(int i = 0; i < len && !isZero; i++)
        {
            if(1000000000000000001L/result >= nums[i])
            {
                result *= nums[i];
            }
            else
            {
                tooLong = true;
                break;
            }
        }

        if(isZero)
        {
            System.out.println(0);
        }
        else if(tooLong)
        {
            System.out.println(-1);
        }
        else
        {
            System.out.println(result);
        }
    }
}