Problem:
Score : 200 points

Problem Statement

We have held a popularity poll for N items on sale. Item i received A_i votes.

From these N items, we will select M as popular items. However, we cannot select an item with less than \dfrac{1}{4M} of the total number of votes.

If M popular items can be selected, print Yes; otherwise, print No.

Constraints

1 \leq M \leq N \leq 100

1 \leq A_i \leq 1000

A_i are distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M
A_1 ... A_N

Output

If M popular items can be selected, print Yes; otherwise, print No.

Sample Input 1

4 1
5 4 2 1

Sample Output 1

Yes

There were 12 votes in total. The most popular item received 5 votes, and we can select it.

Sample Input 2

3 2
380 19 1

Sample Output 2

No

There were 400 votes in total. The second and third most popular items received less than \dfrac{1}{4\times 2} of the total number of votes, so we cannot select them. Thus, we cannot select two popular items.

Sample Input 3

12 3
4 56 78 901 2 345 67 890 123 45 6 789

Sample Output 3

Yes

Solution in Java (OpenJDK 11.0.6) (judge verdict: Wrong Answer)

import java.util.*;
 
	public class Main {
		public static void main(String[] args) {
      	Scanner sc = new Scanner(System.in);
      
      	int N  =sc.nextInt();
       	int M  =sc.nextInt();
          
          List<Integer> n = new ArrayList<>();
          
          for(int i=0; i<N; i++){
          n.add(sc.nextInt());
          }

          int sum = 0;
          for(int i=0; i<N; i++){
          sum += n.get(i);
          }
 
          double a = sum/(4*M);
           
          int count = 0;
          for(int i=0; i<N; i++){
            if(n.get(i)>=a){
            count++;
            }
           
          }
          if(M<=count){
          System.out.println("Yes");
          }
          else{
          System.out.println("No");
          }
        }
    }