Problem:
Score : 200 points

Problem Statement

Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print -1 instead.

Constraints

2 \leq N \leq 10^5

0 \leq A_i \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the value A_1 \times ... \times A_N as an integer, or -1 if the value exceeds 10^{18}.

Sample Input 1

2
1000000000 1000000000

Sample Output 1

1000000000000000000

We have 1000000000 \times 1000000000 = 1000000000000000000.

Sample Input 2

3
101 9901 999999000001

Sample Output 2

-1

We have 101 \times 9901 \times 999999000001 = 1000000000000000001, which exceeds 10^{18}, so we should print -1 instead.

Sample Input 3

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0

Sample Output 3

0

Solution in Java (OpenJDK 11.0.6) (judge verdict: Wrong Answer)

import java.util.Scanner;
import java.util.ArrayList;

public class Main
{
    public static void main(String[] args)
    {
        String[] lines = getStdin();

        int n = Integer.parseInt(lines[0]);
        String[] inputs = lines[1].split(" ");

        Long[] val = new Long[n];
        for (int i = 0;i<n;i++){
            val[i] = Long.parseLong(inputs[i]);
            if(val[i]==0){
                System.out.println(0);
                return;
            }
        }

        long mul = 1L;
        for (int i = 0; i < n; i++) {
            mul *= val[i];
            if(mul > (long)Math.pow(10, 18)){
                System.out.println(-1);
                return;
            }
        }
        System.out.println((long)mul);
    }

    private static String[] getStdin()
    {
        Scanner scanner = new Scanner(System.in);
        ArrayList<String> lines = new ArrayList<>();
        while (scanner.hasNext()) {
            lines.add(scanner.nextLine());
        }
        return lines.toArray(new String[lines.size()]);
    }
}