Problem:
Score : 200 points

Problem Statement

Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print -1 instead.

Constraints

2 \leq N \leq 10^5

0 \leq A_i \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the value A_1 \times ... \times A_N as an integer, or -1 if the value exceeds 10^{18}.

Sample Input 1

2
1000000000 1000000000

Sample Output 1

1000000000000000000

We have 1000000000 \times 1000000000 = 1000000000000000000.

Sample Input 2

3
101 9901 999999000001

Sample Output 2

-1

We have 101 \times 9901 \times 999999000001 = 1000000000000000001, which exceeds 10^{18}, so we should print -1 instead.

Sample Input 3

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0

Sample Output 3

0

Solution in Java (OpenJDK 11.0.6) (judge verdict: Wrong Answer)

import java.util.Scanner;

public class Main {
	public static void main(String[] args) {
		try (Scanner scn = new Scanner(System.in)) {
			int N = scn.nextInt();
			long[] a = new long[N];

			for(int i = 0; i < N; i++) {
				a[i] = scn.nextLong();
				if(a[i] == 0) {
					System.out.println(0);
					System.exit(0);
				}
			}

			long max = (long) Math.pow(10, 18);
			long chk = (long) Math.pow(10, 12);

			long tmp = a[0];
			for(int i = 1; i < N; i++){
				if(tmp > chk && a[i] > chk) {
					System.out.println(-1);
					System.exit(0);
				}

				try {
					tmp = Math.multiplyExact(tmp, a[i]);
		        } catch (ArithmeticException e) {
		        	System.out.println(-1);
					System.exit(0);
		        }
			}
			System.out.println(tmp);
		}
	}
}