Problem:
Score : 200 points

Problem Statement

Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print -1 instead.

Constraints

2 \leq N \leq 10^5

0 \leq A_i \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the value A_1 \times ... \times A_N as an integer, or -1 if the value exceeds 10^{18}.

Sample Input 1

2
1000000000 1000000000

Sample Output 1

1000000000000000000

We have 1000000000 \times 1000000000 = 1000000000000000000.

Sample Input 2

3
101 9901 999999000001

Sample Output 2

-1

We have 101 \times 9901 \times 999999000001 = 1000000000000000001, which exceeds 10^{18}, so we should print -1 instead.

Sample Input 3

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0

Sample Output 3

0

Solution in Java (OpenJDK 11.0.6) (judge verdict: Runtime Error)

import java.util.Map.Entry;
import java.util.*;
import java.math.*;
import org.w3c.dom.css.Counter;
  
public class Main{
    public static void main(final String[] args){
 
        final Scanner sc = new Scanner(System.in);
        final int N = sc.nextInt();
        long An = 1;
        long temp =1;
        int flag=0;
        //final long answer=1;
        final long max = 1000000000000000000l;


        for(long i = 0; i < N; i++) {
            temp = sc.nextInt();
            if(temp == 0){
                System.out.println(0);
               return;
            }else{
                An = An * temp;
            }
            if(An >max){
                flag = 1;
                An =1;
            }
        }

        if(flag != 0){
            System.out.println(-1);
        }else{
            System.out.println(An);
        }
    
    }
}