Problem:
Score : 200 points

Problem Statement

We have held a popularity poll for N items on sale. Item i received A_i votes.

From these N items, we will select M as popular items. However, we cannot select an item with less than \dfrac{1}{4M} of the total number of votes.

If M popular items can be selected, print Yes; otherwise, print No.

Constraints

1 \leq M \leq N \leq 100

1 \leq A_i \leq 1000

A_i are distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M
A_1 ... A_N

Output

If M popular items can be selected, print Yes; otherwise, print No.

Sample Input 1

4 1
5 4 2 1

Sample Output 1

Yes

There were 12 votes in total. The most popular item received 5 votes, and we can select it.

Sample Input 2

3 2
380 19 1

Sample Output 2

No

There were 400 votes in total. The second and third most popular items received less than \dfrac{1}{4\times 2} of the total number of votes, so we cannot select them. Thus, we cannot select two popular items.

Sample Input 3

12 3
4 56 78 901 2 345 67 890 123 45 6 789

Sample Output 3

Yes

Solution in Java (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.Scanner;
public class Main {
	public static void main(String[] args) {

//	入力の読み込み
		Scanner sc = new Scanner(System.in);
		int shurui = sc.nextInt();  //商品の種類数
		double select = sc.nextInt();  //選びたい商品数
		double sum = 0;  //総投票数
		int shouhin[] = new int[shurui];  //商品配列

//	お菓子1つずつに得票数を記入
		for(int i=0 ; i<shurui ; i++) {
			int tokuhyou = sc.nextInt();
			shouhin[i] += tokuhyou;
			sum += tokuhyou;
		}

//	総投票数がわかったので基準値を求める
		double kijun = Math.ceil(sum/(4*select));

//	並列の中身を開けてみて、選べる商品をカウント
		int count = 0;
		for(int i : shouhin) {
			if(i >= kijun) {
				count ++;
			}
		}

//	選べる商品がM個以上あるかどうか
		System.out.println(count >= select ? "Yes" : "No");
	}
}