Problem:
Score : 200 points

Problem Statement

We have held a popularity poll for N items on sale. Item i received A_i votes.

From these N items, we will select M as popular items. However, we cannot select an item with less than \dfrac{1}{4M} of the total number of votes.

If M popular items can be selected, print Yes; otherwise, print No.

Constraints

1 \leq M \leq N \leq 100

1 \leq A_i \leq 1000

A_i are distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M
A_1 ... A_N

Output

If M popular items can be selected, print Yes; otherwise, print No.

Sample Input 1

4 1
5 4 2 1

Sample Output 1

Yes

There were 12 votes in total. The most popular item received 5 votes, and we can select it.

Sample Input 2

3 2
380 19 1

Sample Output 2

No

There were 400 votes in total. The second and third most popular items received less than \dfrac{1}{4\times 2} of the total number of votes, so we cannot select them. Thus, we cannot select two popular items.

Sample Input 3

12 3
4 56 78 901 2 345 67 890 123 45 6 789

Sample Output 3

Yes

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Main
{
	public static void main (String[] args) throws java.lang.Exception
	{
		// your code goes here
		try {
		    Scanner sc=new Scanner(System.in);
		    int n=sc.nextInt();
		    int m=sc.nextInt();
		    int sum=0;
		    int ar[]=new int[n];
		    for(int i=0;i<n;i++)
		    {
		        ar[i]=sc.nextInt();
		        sum+=ar[i];
		    }
		    sum=sum/(4*m);
		    int c=0;
		    for(int i=0;i<n;i++)
		    {
		        if(ar[i]>=sum)
		        c++;
		        if(c==m)
		        break;
		    }
		    if(c<m)
		    System.out.println("No");
		    else
		    System.out.println("Yes");
		    
		} catch(Exception e) {
		}
	}
}