Problem:
Score : 100 points

Problem Statement

We have three boxes A, B, and C, each of which contains an integer.

Currently, the boxes A, B, and C contain the integers X, Y, and Z, respectively.

We will now do the operations below in order. Find the content of each box afterward.

Swap the contents of the boxes A and B

Swap the contents of the boxes A and C

Constraints

1 \leq X,Y,Z \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X Y Z

Output

Print the integers contained in the boxes A, B, and C, in this order, with space in between.

Sample Input 1

1 2 3

Sample Output 1

3 1 2

After the contents of the boxes A and B are swapped, A, B, and C contain 2, 1, and 3, respectively.

Then, after the contents of A and C are swapped, A, B, and C contain 3, 1, and 2, respectively.

Sample Input 2

100 100 100

Sample Output 2

100 100 100

Sample Input 3

41 59 31

Sample Output 3

31 41 59

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.StringTokenizer;

public class Main {
	public static void main(String[] args) {
		FastScanner sc = new FastScanner(System.in);
		int x = sc.nextInt(), y = sc.nextInt(), z = sc.nextInt();
		System.out.println(z + " " + x + " " + y);
	}
	
	static class FastScanner {
		private BufferedReader reader = null;
	    private StringTokenizer tokenizer = null;
	    public FastScanner(InputStream in) {
	        reader = new BufferedReader(new InputStreamReader(in));
	        tokenizer = null;
	    }

	    public String next() {
	        if (tokenizer == null || !tokenizer.hasMoreTokens()) {
	            try {
	                tokenizer = new StringTokenizer(reader.readLine());
	            } catch (IOException e) {
	                throw new RuntimeException(e);
	            }
	        }
	        return tokenizer.nextToken();
	    }

	    public String nextLine() {
	        if (tokenizer == null || !tokenizer.hasMoreTokens()) {
	            try {
	                return reader.readLine();
	            } catch (IOException e) {
	                throw new RuntimeException(e);
	            }
	        }

	        return tokenizer.nextToken("\n");
	    }

	    public long nextLong() {
	        return Long.parseLong(next());
	    }

	    public int nextInt() {
	        return Integer.parseInt(next());
	    }

	    public double nextDouble() {
	         return Double.parseDouble(next());
	     }

	    public int[] nextIntArray(int n) {
	        int[] a = new int[n];
	        for (int i = 0; i < n; i++)
	            a[i] = nextInt();
	        return a;
	    }

	    public long[] nextLongArray(int n) {
	        long[] a = new long[n];
	        for (int i = 0; i < n; i++)
	            a[i] = nextLong();
	        return a;
	    }
	}
}