Problem:
Score : 200 points

Problem Statement

Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print -1 instead.

Constraints

2 \leq N \leq 10^5

0 \leq A_i \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the value A_1 \times ... \times A_N as an integer, or -1 if the value exceeds 10^{18}.

Sample Input 1

2
1000000000 1000000000

Sample Output 1

1000000000000000000

We have 1000000000 \times 1000000000 = 1000000000000000000.

Sample Input 2

3
101 9901 999999000001

Sample Output 2

-1

We have 101 \times 9901 \times 999999000001 = 1000000000000000001, which exceeds 10^{18}, so we should print -1 instead.

Sample Input 3

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0

Sample Output 3

0

Solution in Java (OpenJDK 11.0.6) (judge verdict: Wrong Answer)

import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.List;
import java.util.Scanner;
import java.util.ArrayList;

/**
 * Built using CHelper plug-in
 * Actual solution is at the top
 */
public class Main {
    public static void main(String[] args) {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        Scanner in = new Scanner(inputStream);
        PrintWriter out = new PrintWriter(outputStream);
        Multiplication2 solver = new Multiplication2();
        solver.solve(1, in, out);
        out.close();
    }

    static class Multiplication2 {
        public void solve(int testNumber, Scanner in, PrintWriter out) {
            int num = in.nextInt();
            long ans = 1;

            long border = pow(10, 18);
            List<Long> lists = new ArrayList<>();

            for (int i = 0; i < num; i++) {
                long a = in.nextLong();
                lists.add(a);
            }
            if (lists.contains(0L)) {
                out.append("0\n");
                return;
            }
            for (Long a : lists) {
                ans *= a;
                if (ans > border) {
                    out.append("-1\n");
                    return;
                }
            }
            out.append(String.valueOf(ans));
        }

        static long pow(long x, long n) {

            if (n == 0) {
                return 1;
            }
            long result = pow(x, n / 2);

            if (n % 2 == 0) {
                return (result * result);
            }
            return ((result * result)) * x;
        }

    }
}