Problem:
Score : 200 points

Problem Statement

Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print -1 instead.

Constraints

2 \leq N \leq 10^5

0 \leq A_i \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the value A_1 \times ... \times A_N as an integer, or -1 if the value exceeds 10^{18}.

Sample Input 1

2
1000000000 1000000000

Sample Output 1

1000000000000000000

We have 1000000000 \times 1000000000 = 1000000000000000000.

Sample Input 2

3
101 9901 999999000001

Sample Output 2

-1

We have 101 \times 9901 \times 999999000001 = 1000000000000000001, which exceeds 10^{18}, so we should print -1 instead.

Sample Input 3

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0

Sample Output 3

0

Solution in Java (OpenJDK 11.0.6) (judge verdict: Time Limit Exceeded)

import java.util.*;
import java.io.*;
import java.lang.*;
import java.math.*;
class Main{
  public static void main(String[] args) throws IOException{
    BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
    StringTokenizer st;
        String str = br.readLine().trim();
    int n = Integer.parseInt(str);
     BigInteger b1 = new BigInteger("1");
      BigInteger b3 ;
      st = new StringTokenizer(br.readLine());
    while(n-->0){
        
        b3 = new BigInteger(st.nextToken());
        //System.out.println(b3);
        b1 = b1.multiply(b3);
    }
 //   BigInteger b2 = new BigInteger("1000000000000000000");
  //  System.out.println();
  //BigInteger n1 = b2.divide(b1);
  String s = String.valueOf(b1);
 // System.out.println(n1);
    if(b1.toString().length()>18 && s.charAt(s.length()-1)!='0')
        System.out.println("-1");
    else
        System.out.println(b1);
    
   
   
   
   
   
    
   
  }
}