Problem:
Score : 200 points

Problem Statement

Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print -1 instead.

Constraints

2 \leq N \leq 10^5

0 \leq A_i \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the value A_1 \times ... \times A_N as an integer, or -1 if the value exceeds 10^{18}.

Sample Input 1

2
1000000000 1000000000

Sample Output 1

1000000000000000000

We have 1000000000 \times 1000000000 = 1000000000000000000.

Sample Input 2

3
101 9901 999999000001

Sample Output 2

-1

We have 101 \times 9901 \times 999999000001 = 1000000000000000001, which exceeds 10^{18}, so we should print -1 instead.

Sample Input 3

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0

Sample Output 3

0

Solution in Java (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.util.Scanner;

public class Main {
	private static final long MAX = 1000000000000000000L;
	public static void main(final String[] args) {
		Scanner sc = new Scanner(System.in);
		int N = sc.nextInt();
		boolean over = false;
		long answer = 1L;
		for(int i = 0; i < N; i++) {
			long A = sc.nextLong();
			if((answer * A) < 0 || (answer * A) > MAX) {
				over = true;
			} else {
				over = false;
			}
			if(!over) answer *= A;
		}
		sc.close();
		prtln(over ? -1 : answer);
	}

	public static <T> void prtln(T t) { System.out.println(t); }
}