Problem:
Score : 200 points

Problem Statement

We have held a popularity poll for N items on sale. Item i received A_i votes.

From these N items, we will select M as popular items. However, we cannot select an item with less than \dfrac{1}{4M} of the total number of votes.

If M popular items can be selected, print Yes; otherwise, print No.

Constraints

1 \leq M \leq N \leq 100

1 \leq A_i \leq 1000

A_i are distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M
A_1 ... A_N

Output

If M popular items can be selected, print Yes; otherwise, print No.

Sample Input 1

4 1
5 4 2 1

Sample Output 1

Yes

There were 12 votes in total. The most popular item received 5 votes, and we can select it.

Sample Input 2

3 2
380 19 1

Sample Output 2

No

There were 400 votes in total. The second and third most popular items received less than \dfrac{1}{4\times 2} of the total number of votes, so we cannot select them. Thus, we cannot select two popular items.

Sample Input 3

12 3
4 56 78 901 2 345 67 890 123 45 6 789

Sample Output 3

Yes

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)


import java.util.Arrays;
import java.util.Scanner;

/*
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/**
 *
 * @author wnqmw
 */
public class Main {
    public static void main(String args[]){
        Scanner kb = new Scanner(System.in);
        int nums = kb.nextInt(), sel = kb.nextInt();
        
        int[] num = new int[nums];
        
        int total = 0, totalvotes = 0;
        for(int i = 0; i < nums; i++){
            num[i] = kb.nextInt();
            totalvotes += num[i];
            
            
        }
        Arrays.sort(num);
        for(int i = nums-1; i >= 0; i--){
            if(num[i] >= totalvotes/(4*sel)){
                total++;
                if(total == sel){
                    break;
                }
            }
        }
        if(total < sel){
            System.out.println("No");
        }else{
            System.out.println("Yes");
        }
    }
}