Problem:
Score : 200 points

Problem Statement

You are given an image A composed of N rows and N columns of pixels, and a template image B composed of M rows and M columns of pixels.

A pixel is the smallest element of an image, and in this problem it is a square of size 1×1.

Also, the given images are binary images, and the color of each pixel is either white or black.

In the input, every pixel is represented by a character: . corresponds to a white pixel, and # corresponds to a black pixel.

The image A is given as N strings A_1,...,A_N.

The j-th character in the string A_i corresponds to the pixel at the i-th row and j-th column of the image A (1≦i,j≦N).

Similarly, the template image B is given as M strings B_1,...,B_M.

The j-th character in the string B_i corresponds to the pixel at the i-th row and j-th column of the template image B (1≦i,j≦M).

Determine whether the template image B is contained in the image A when only parallel shifts can be applied to the images.

Constraints

1≦M≦N≦50

A_i is a string of length N consisting of # and ..

B_i is a string of length M consisting of # and ..

Input

The input is given from Standard Input in the following format:

N M
A_1
A_2
:
A_N
B_1
B_2
:
B_M

Output

Print Yes if the template image B is contained in the image A. Print No otherwise.

Sample Input 1

3 2
#.#
.#.
#.#
#.
.#

Sample Output 1

Yes

The template image B is identical to the upper-left 2 × 2 subimage and the lower-right 2 × 2 subimage of A. Thus, the output should be Yes.

Sample Input 2

4 1
....
....
....
....
#

Sample Output 2

No

The template image B, composed of a black pixel, is not contained in the image A composed of white pixels.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Wrong Answer)

import java.io.*;

public class Main {
    public static void main(String[] args) throws IOException {
      InputStreamReader is = new InputStreamReader(System.in);
      BufferedReader br = new BufferedReader(is);
        
        
        //キーボードから1列目を読み込み
        String str = br.readLine();
        //読み込みを分割
        String[] gazou = str.split(" ",0);
        int n = Integer.parseInt(gazou[0]);
        int m = Integer.parseInt(gazou[1]);
        //aとbの配列を作る
        String[][] a = new String[n][n];
        String[][] b = new String[m][m];
        //配列に代入(a)
        for(int i=0; i<n; i++){
        	String str1 = br.readLine();
        	String[] bunkai = str1.split("",0);
        	for(int j=0; j<n; j++){
        		a[i][j] = bunkai[j];
        	} 
        }
        //配列に代入(b)
        for(int i=0; i<m; i++){
        	String str2 = br.readLine();
        	String[] bunkai = str2.split("",0);
        	for(int j=0; j<m; j++){
        		b[i][j] = bunkai[j];
        	}
        }
        //比較
        for(int i=0; i<n-m; i++){
        	for(int j=0; j<n-m; j++){
        		//bの左上一致の場合
        		outside: if(b[0][0].equals(a[i][j])){
        			//停止して比較開始
        			for(int l=0; l<m; l++){
        				for(int k=0; k<m; k++){
        					//異なるものがあった場合
        					if(b[l][k].equals(a[i+l][j+k])){continue;}
        					else{break outside;}
        				}
        			}
        			//異なるものがなかった場合
        			System.out.println("Yes");
        			System.exit(0);
        		}
        		//そうでない場合
        		else{continue;}
        	}
        }
        //比較して完全になかった場合
        System.out.println("No");
    }
}