Problem:
Score : 300 points

Problem Statement

Takahashi is a teacher responsible for a class of N students.

The students are given distinct student numbers from 1 to N.

Today, all the students entered the classroom at different times.

According to Takahashi's record, there were A_i students in the classroom when student number i entered the classroom (including student number i).

From these records, reconstruct the order in which the students entered the classroom.

Constraints

1 \le N \le 10^5

1 \le A_i \le N

A_i \neq A_j (i \neq j)

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 \ldots A_N

Output

Print the student numbers of the students in the order the students entered the classroom.

Sample Input 1

3
2 3 1

Sample Output 1

3 1 2

First, student number 3 entered the classroom.

Then, student number 1 entered the classroom.

Finally, student number 2 entered the classroom.

Sample Input 2

5
1 2 3 4 5

Sample Output 2

1 2 3 4 5

Sample Input 3

8
8 2 7 3 4 5 6 1

Sample Output 3

8 2 4 5 6 7 3 1

Solution in Java7 (OpenJDK 1.7.0) (judge verdict: Time Limit Exceeded)



import java.util.Scanner;

public class Main {
	static int intN =0;
	static int sosuCnt =0;

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		String n = sc.nextLine();
		//String[] h1 = sc.nextLine().split(" ");

		//int intK = Integer.parseInt(h1[1]);


		int intN = Integer.parseInt(n);
		int[] ans = new int[intN];

		String[] a = sc.nextLine().split(" ");

		int sum=0;

		for (int i = 0;i < intN;i++) {
			ans[Integer.parseInt(a[i])-1]=i+1;
		}

		String answer = "";
		for (int i = 0;i < intN;i++) {
			if (i==0) {
				answer=String.valueOf(ans[i]);
			} else {
				answer=answer + " " + String.valueOf(ans[i]);
			}


		}
		System.out.println(answer);


		//int a = Integer.parseInt("");
		//for (int i = 0;i < intN;i++) {
		//sum=sum+i;
	//}

	}
}