Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in JAVA (judge verdict: Wrong Answer)

import java.util.Scanner;

public class Main{
    public static void main(String[] args){
        Scanner sc = new Scanner(System.in);
        String str;
        String[] alfa = {"a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"};
        int[] count = new int[26];
        str = sc.nextLine();
        String[] s = new String[str.length()];
        for(int i=0;i<str.length();i++){
            s[i] = String.valueOf(str.charAt(i));
        }
        for(int i=0;i<str.length();i++){
            for(int j=0;j<26;j++){
                if(s[i].equalsIgnoreCase(alfa[j])) count[j]++;
            }
        }
        for(int i=0;i<26;i++){
            System.out.println(alfa[i] + " : " +count[i]);
        }
    }
}