Problem:
Score : 400 points

Problem Statement

Takahashi has a string S consisting of lowercase English letters.

Starting with this string, he will produce a new one in the procedure given as follows.

The procedure consists of Q operations. In Operation i (1 \leq i \leq Q), an integer T_i is provided, which means the following:

If T_i = 1: reverse the string S.

If T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.

If F_i = 1 : Add C_i to the beginning of the string S.

If F_i = 2 : Add C_i to the end of the string S.

Help Takahashi by finding the final string that results from the procedure.

Constraints

1 \leq |S| \leq 10^5

S consists of lowercase English letters.

1 \leq Q \leq 2 \times 10^5

T_i = 1 or 2.

F_i = 1 or 2, if provided.

C_i is a lowercase English letter, if provided.

Input

Input is given from Standard Input in the following format:

S
Q
Query_1
:
Query_Q

In the 3-rd through the (Q+2)-th lines, Query_i is one of the following:

1

which means T_i = 1, and:

2 F_i C_i

which means T_i = 2.

Output

Print the resulting string.

Sample Input 1

a
4
2 1 p
1
2 2 c
1

Sample Output 1

cpa

There will be Q = 4 operations. Initially, S is a.

Operation 1: Add p at the beginning of S. S becomes pa.

Operation 2: Reverse S. S becomes ap.

Operation 3: Add c at the end of S. S becomes apc.

Operation 4: Reverse S. S becomes cpa.

Thus, the resulting string is cpa.

Sample Input 2

a
6
2 2 a
2 1 b
1
2 2 c
1
1

Sample Output 2

aabc

There will be Q = 6 operations. Initially, S is a.

Operation 1: S becomes aa.

Operation 2: S becomes baa.

Operation 3: S becomes aab.

Operation 4: S becomes aabc.

Operation 5: S becomes cbaa.

Operation 6: S becomes aabc.

Thus, the resulting string is aabc.

Sample Input 3

y
1
2 1 x

Sample Output 3

xy

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Time Limit Exceeded)

import java.util.*;

public class Main {
    void run() {
        Scanner sc = new Scanner(System.in);
        String s = sc.next();
        String mid = "";
        if (s.length() >= 2) {
            mid = s.substring(1, s.length() - 1);
//            debug(mid);
        }
        int q = sc.nextInt();
        StringBuffer sbHead = new StringBuffer(1000000);
        sbHead.append(s.charAt(0));
        StringBuffer sbLast = new StringBuffer(1000000);
        if (s.length() != 1) {
            sbLast.append(s.charAt(s.length() - 1));
        }
//        debug(sbHead, sbLast);
        boolean isHead = true;
        for (int i = 0; i < q; i++) {
            debug(sbHead, sbLast);
            int t = sc.nextInt();
            if (t == 1) {
                isHead = !isHead;
                continue;
            }
            int f = sc.nextInt();
            char c = sc.next().charAt(0);
            if ((f == 1 && isHead) || (f == 2 && !isHead)) {
                sbHead.append(c);
            } else {
                sbLast.append(c);
            }
        }


        StringBuffer ans = sbHead.reverse().append(mid).append(sbLast);
        if (isHead) {
            System.out.println(ans.toString());
        } else {
            System.out.println(ans.reverse().toString());
        }
    }

    void debug(Object... os) {
        System.err.println(Arrays.deepToString(os));
    }

    public static void main(String[] args) {
        new Main().run();
    }
}