Problem:
Sale Result

There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.

Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:

n (the number of data in the list)
i p q
i p q
:
:
i p q

Output

For each dataset, print a list of employee IDs or a text "NA"

Sample Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0

Output for the Sample Input

1001
1003
NA
2013

Solution in JAVA (judge verdict: Wrong Answer)

import java.util.ArrayList;
import java.util.HashMap;
import java.util.Scanner;

public class Main{
	
	static Main byakko = new Main();
	static Scanner sc = new Scanner(System.in);
	
	public static void main(String[] args){
		
		int n;
		boolean is;
		
		while(true){
			n = sc.nextInt();
			if(n == 0)break;
			HashMap<Integer, Integer> map = new HashMap<Integer, Integer>();
			ArrayList<Integer> list = new ArrayList<Integer>();
			is = true;
			
			for(int i = 0; i < n; i++){
				int x = sc.nextInt();
				if(map.containsKey(x)){
					map.put(x, map.get(x) + sc.nextInt() * sc.nextInt());
				}else{
					map.put(x, sc.nextInt() * sc.nextInt());
					list.add(x);
				}
			}
			for(int i = 0; i < list.size(); i++){
				if(map.get(list.get(i)) >= 1000000){
					System.out.println(list.get(i));
					is = false;
				}
			}
			if(is)
				System.out.println("NA");
		}
		sc.close();
	}
}