Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Java8 (OpenJDK 1.8.0) (judge verdict: Accepted)

import java.util.*;
 
class Main {
	public static void main (String[] args) {
		Scanner scanner = new Scanner(System.in);
		int N = scanner.nextInt();
		int count = 0;
		
		//Nまでの奇数をとる
		for (int i = 1; i <= N; i+=2) {
			//divを初期化
			int div = 0;
			//約数の計算
			for (int j = 1; j <= i; j++) {
				if(i%j == 0) {
					div++;
				}
			}
			//System.out.println(i + "の約数 : " + div + "個");
			
			//div==8のときのみ、countに追加
			if (div == 8) {
				count++;
			}
		}
		System.out.println(count);
	}
}