Problem:
Score : 300 points

Problem Statement

A sequence a_1,a_2,... ,a_n is said to be /\/\/\/ when the following conditions are satisfied:

For each i = 1,2,..., n-2, a_i = a_{i+2}.

Exactly two different numbers appear in the sequence.

You are given a sequence v_1,v_2,...,v_n whose length is even.
We would like to make this sequence /\/\/\/ by replacing some of its elements.
Find the minimum number of elements that needs to be replaced.

Constraints

2 \leq n \leq 10^5

n is even.

1 \leq v_i \leq 10^5

v_i is an integer.

Input

Input is given from Standard Input in the following format:

n
v_1 v_2 ... v_n

Output

Print the minimum number of elements that needs to be replaced.

Sample Input 1

4
3 1 3 2

Sample Output 1

1

The sequence 3,1,3,2 is not /\/\/\/, but we can make it /\/\/\/ by replacing one of its elements: for example, replace the fourth element to make it 3,1,3,1.

Sample Input 2

6
105 119 105 119 105 119

Sample Output 2

0

The sequence 105,119,105,119,105,119 is /\/\/\/.

Sample Input 3

4
1 1 1 1

Sample Output 3

2

The elements of the sequence 1,1,1,1 are all the same, so it is not /\/\/\/.

Solution in Haskell (GHC 7.10.3) (judge verdict: Wrong Answer)

import Control.Arrow
import Control.Monad
import Data.List
import qualified Data.ByteString.Char8 as B
import Data.Ord

main :: IO ()
main = getLine >> readLine >>= print . solve

solve :: [Int] -> Int
solve vs = check as bs
    where
        check xxs@((an, al) : xs) yys@((bn, bl) : ys)
            | an /= bn = n - al - bl
            | al > bl = check xs yys
            | otherwise = check xxs ys
        check ((_, al) : _) _ = n - al
        check _ ((_, bl) : _) = n - bl 
        check _ _ = n

        as = count es
        bs = count os 

        n = length vs

        count = sortBy cmpf . map mf . group . sort
            where
                cmpf lhs rhs = comparing snd rhs lhs `mappend` comparing fst lhs rhs
                mf = (,) <$> head <*> length 

        (es, os) = fst $ foldr ff (([], []), True) vs
            where
                ff v ((acc, bcc), f)
                    | f = ((v : acc, bcc), not f)
                    | otherwise = ((acc, v : bcc), not f)

readLine :: IO [Int]
readLine = unfoldr (fmap (second (maybe B.empty snd . B.uncons)) . B.readInt) <$> B.getLine

readContents :: Int -> IO [[Int]]
readContents = flip replicateM readLine