Problem:
Score : 300 points

Problem Statement

A railroad running from west to east in Atcoder Kingdom is now complete.

There are N stations on the railroad, numbered 1 through N from west to east.

Tomorrow, the opening ceremony of the railroad will take place.

On this railroad, for each integer i such that 1≤i≤N-1, there will be trains that run from Station i to Station i+1 in C_i seconds. No other trains will be operated.

The first train from Station i to Station i+1 will depart Station i S_i seconds after the ceremony begins. Thereafter, there will be a train that departs Station i every F_i seconds.

Here, it is guaranteed that F_i divides S_i.

That is, for each Time t satisfying S_i≤t and t％F_i=0, there will be a train that departs Station i t seconds after the ceremony begins and arrives at Station i+1 t+C_i seconds after the ceremony begins, where A％B denotes A modulo B, and there will be no other trains.

For each i, find the earliest possible time we can reach Station N if we are at Station i when the ceremony begins, ignoring the time needed to change trains.

Constraints

1≤N≤500

1≤C_i≤100

1≤S_i≤10^5

1≤F_i≤10

S_i％F_i=0

All input values are integers.

Input

Input is given from Standard Input in the following format:

N
C_1 S_1 F_1
:
C_{N-1} S_{N-1} F_{N-1}

Output

Print N lines. Assuming that we are at Station i (1≤i≤N) when the ceremony begins, if the earliest possible time we can reach Station N is x seconds after the ceremony begins, the i-th line should contain x.

Sample Input 1

3
6 5 1
1 10 1

Sample Output 1

12
11
0

We will travel from Station 1 as follows:

5 seconds after the beginning: take the train to Station 2.

11 seconds: arrive at Station 2.

11 seconds: take the train to Station 3.

12 seconds: arrive at Station 3.

We will travel from Station 2 as follows:

10 seconds: take the train to Station 3.

11 seconds: arrive at Station 3.

Note that we should print 0 for Station 3.

Sample Input 2

4
12 24 6
52 16 4
99 2 2

Sample Output 2

187
167
101
0

Sample Input 3

4
12 13 1
44 17 17
66 4096 64

Sample Output 3

4162
4162
4162
0

Solution in Haskell (GHC 7.10.3) (judge verdict: Accepted)

import qualified Data.Array.IO as A
import Data.Array.IO
import Control.Monad
import Data.Maybe

type Array = IOArray Int

main :: IO ()
main = do
    n <- read <$> getLine :: IO Int
    ts <- A.newListArray (1,n-1) =<<
        replicateM (n-1) ((\[c,s,f]->(c,s,f)) . map read . words <$> getLine) :: IO (Array (Int, Int, Int))
    forM_ [1..n] $ \i -> do
        print =<< sim ts i 0 n

sim :: Array (Int, Int, Int) 
    -> Int -- current point
    -> Int -- time
    -> Int -- gool
    -> IO Int
sim arr pos time goal = do
    (c, s, f) <- fromMaybe (0, 0, 0) <$> (arr!?pos)
    case (pos==goal, s<=time, mod time f) of
        (True, _, _) -> return time
        (_, True, 0) -> sim arr (pos+1) (time+c) goal 
        (_, True, n) -> sim arr (pos+1) (time+(f-n)+c) goal 
        (_, False,_) -> sim arr (pos+1) (s+c) goal

(!) :: (A.Ix x) => A.IOArray x y -> x -> IO y
arr ! n = A.readArray arr n
{-# INLINE (!) #-}
 
(!?) :: (A.Ix x) => A.IOArray x y -> x -> IO (Maybe y)
arr !? n = do
    (start, last) <- A.getBounds arr
    if n >= start && last >= n 
        then Just <$> A.readArray arr n 
        else return Nothing
{-# INLINE (!?) #-}
 
(<<-) :: (A.Ix x) => (A.IOArray x y, x) -> y -> IO ()
(arr, i) <<- v = A.writeArray arr i v
{-# INLINE (<<-) #-}