Problem:
Score : 200 points

Problem Statement

Let us define the FizzBuzz sequence a_1,a_2,... as follows:

If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.

If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.

If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.

If none of the above holds, a_i=i.

Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Constraints

1 \leq N \leq 10^6

Input

Input is given from Standard Input in the following format:

N

Output

Print the sum of all numbers among the first N terms of the FizzBuzz sequence.

Sample Input 1

15

Sample Output 1

60

The first 15 terms of the FizzBuzz sequence are:

1,2,\mbox{Fizz},4,\mbox{Buzz},\mbox{Fizz},7,8,\mbox{Fizz},\mbox{Buzz},11,\mbox{Fizz},13,14,\mbox{FizzBuzz}

Among them, numbers are 1,2,4,7,8,11,13,14, and the sum of them is 60.

Sample Input 2

1000000

Sample Output 2

266666333332

Watch out for overflow.

Solution in Haskell (GHC 8.8.3) (judge verdict: Accepted)

module Main where
import qualified Control.Monad as C
import qualified Data.Char as C
import qualified Data.List as L
import qualified Data.Map as M
import qualified Data.Array as A

int = read :: String -> Int
long = read :: String -> Integer
getWord :: IO String
getWord = do
  c <- getChar
  if C.isSpace c
  then
    return []
  else do
    ws <- getWord
    return (c:ws)
getInt = fmap int getWord
replace pred a = map (\x -> if pred x then a else x)

main = interact $ printer . solver . parser
parser = long . head . words
printer = unlines . (:[]) . show

solver x = sum $ filter (\x -> x`mod`3 /= 0 && x`mod`5 /= 0) $ [1..x]