Problem:
Score : 300 points

Problem Statement

In AtCoder, a person who has participated in a contest receives a color, which corresponds to the person's rating as follows:

Rating 1-399 : gray

Rating 400-799 : brown

Rating 800-1199 : green

Rating 1200-1599 : cyan

Rating 1600-1999 : blue

Rating 2000-2399 : yellow

Rating 2400-2799 : orange

Rating 2800-3199 : red

Other than the above, a person whose rating is 3200 or higher can freely pick his/her color, which can be one of the eight colors above or not.

Currently, there are N users who have participated in a contest in AtCoder, and the i-th user has a rating of a_i.

Find the minimum and maximum possible numbers of different colors of the users.

Constraints

1 ≤ N ≤ 100

1 ≤ a_i ≤ 4800

a_i is an integer.

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 ... a_N

Output

Print the minimum possible number of different colors of the users, and the maximum possible number of different colors, with a space in between.

Sample Input 1

4
2100 2500 2700 2700

Sample Output 1

2 2

The user with rating 2100 is "yellow", and the others are "orange". There are two different colors.

Sample Input 2

5
1100 1900 2800 3200 3200

Sample Output 2

3 5

The user with rating 1100 is "green", the user with rating 1900 is blue and the user with rating 2800 is "red".

If the fourth user picks "red", and the fifth user picks "blue", there are three different colors. This is one possible scenario for the minimum number of colors.

If the fourth user picks "purple", and the fifth user picks "black", there are five different colors. This is one possible scenario for the maximum number of colors.

Sample Input 3

20
800 810 820 830 840 850 860 870 880 890 900 910 920 930 940 950 960 970 980 990

Sample Output 3

1 1

All the users are "green", and thus there is one color.

Solution in Haskell (GHC 7.10.3) (judge verdict: Accepted)

{-# LANGUAGE FlexibleInstances    #-}
{-# LANGUAGE TypeSynonymInstances #-}

import           Control.Applicative
import           Control.DeepSeq
import           Control.Monad
import           Control.Monad.ST
import qualified Data.Array                  as A
import qualified Data.Array.IArray           as IA
import qualified Data.Array.IO               as AI
import qualified Data.Array.MArray           as MA
import qualified Data.Array.ST               as STA
import qualified Data.Array.Unboxed          as AU
import           Data.Bits
import qualified Data.ByteString.Char8       as BS
import           Data.Char
import qualified Data.Graph                  as G
import           Data.Int
import qualified Data.IntMap                 as IM
import qualified Data.IntSet                 as IS
import           Data.List
import qualified Data.Map.Strict             as M
import           Data.Maybe
import           Data.Ord
import qualified Data.Sequence               as SQ
import qualified Data.Set                    as S
import           Data.Time
import qualified Data.Tree                   as T
import qualified Data.Vector                 as V
import qualified Data.Vector.Mutable         as VM
import qualified Data.Vector.Unboxed         as VU
import qualified Data.Vector.Unboxed.Mutable as VUM

class Printable a where
  format :: a -> String

instance Printable Int where
  format = show

instance Printable Integer where
  format = show

instance Printable Double where
  format = show

instance Printable Float where
  format = show

instance Printable Char where
  format = show

instance Printable String where
  format x = x

instance Printable Bool where
  format = show

put :: Printable a => a -> IO ()
put = putStr . format

putLn :: Printable a => a -> IO ()
putLn = putStrLn . format

putList :: Printable a => [a] -> IO ()
putList [a] = put a
putList (a:as) = do
  put a
  putStr " "
  putList as

readInt :: IO [Int]
readInt = map (fst . fromJust . BS.readInt) . BS.words <$> BS.getLine

readInts :: Int -> IO [[Int]]
readInts n = replicateM n readInt

readInteger :: IO [Integer]
readInteger = map (fst . fromJust . BS.readInteger) . BS.words <$> BS.getLine

readIntegers :: Int -> IO [[Integer]]
readIntegers n = replicateM n readInteger

readString :: IO [String]
readString = map BS.unpack . BS.words <$> BS.getLine

readStrings :: Int -> IO [[String]]
readStrings n = replicateM n <$> readString

toPair :: [a] -> (a, a)
toPair [x, y] = (x, y)

count :: Eq a => a -> [a] -> Int
count a as = length $ filter (== a) as

main = do
  readInt
  a <- readInt
  putList $ solve a

solve :: [Int] -> [Int]
solve a
  | sum [grey, brown, green, lightblue, blue, yellow, orange, red] == 0 && other >= 1 = [1, other ]
  | otherwise =
    [ sum [grey, brown, green, lightblue, blue, yellow, orange, red]
    , (sum [grey, brown, green, lightblue, blue, yellow, orange, red] + other) 
    ]
  where
    grey = f (any (\x -> 1 <= x && x <= 399) a)
    brown = f (any (\x -> 400 <= x && x <= 799) a)
    green = f (any (\x -> 800 <= x && x <= 1199) a)
    lightblue = f (any (\x -> 1200 <= x && x <= 1599) a)
    blue = f (any (\x -> 1600 <= x && x <= 1999) a)
    yellow = f (any (\x -> 2000 <= x && x <= 2399) a)
    orange = f (any (\x -> 2400 <= x && x <= 2799) a)
    red = f (any (\x -> 2800 <= x && x <= 3199) a)
    other = length $ filter (\x -> 3200 <= x) a
    o' = f $ not $ null $ filter (\x -> 3200 <= x) a

f b
  | b = 1
  | otherwise = 0