Problem:
Score : 100 points

Problem Statement

You went shopping to buy cakes and donuts with X yen (the currency of Japan).

First, you bought one cake for A yen at a cake shop.
Then, you bought as many donuts as possible for B yen each, at a donut shop.

How much do you have left after shopping?

Constraints

1 \leq A, B \leq 1 000

A + B \leq X \leq 10 000

X, A and B are integers.

Input

Input is given from Standard Input in the following format:

X
A
B

Output

Print the amount you have left after shopping.

Sample Input 1

1234
150
100

Sample Output 1

84

You have 1234 - 150 = 1084 yen left after buying a cake.
With this amount, you can buy 10 donuts, after which you have 84 yen left.

Sample Input 2

1000
108
108

Sample Output 2

28

Sample Input 3

579
123
456

Sample Output 3

0

Sample Input 4

7477
549
593

Sample Output 4

405

Solution in Haskell (GHC 7.10.3) (judge verdict: Accepted)

{-# LANGUAGE BangPatterns #-}
module Main (main) where

import           Control.Monad
import qualified Data.ByteString.Char8     as C8
import           Data.Bool
import           Data.Maybe

main :: IO ()
main = do
  [[x],[a],[b]] <- replicateM 3 readInts
  print . showAnswer $ solve (x,a,b)

type Input  = (Int, Int, Int)
type Output = Int

solve :: Input -> Output
solve (x,a,b) = (x-a) `mod` b

showAnswer :: Output -> Answer
showAnswer = Number

-- utils
readInts :: IO [Int]
readInts = map (fst . fromJust . C8.readInt) . C8.words <$> C8.getLine

data Answer
  = YesNo Bool
  | YESNO Bool
  | AB Bool
  | Number Int
  | String String
  | Compare Ordering
  | Compare2 Ordering

instance Show Answer where
  show (YesNo b)    = bool "No" "Yes" b
  show (YESNO b)    = bool "NO" "YES" b
  show (AB b)       = bool "B"  "A" b
  show (Number i)   = show i
  show (String s)   = s
  show (Compare o)  = ordering "<" "=" ">" o
  show (Compare2 o) = ordering "Right" "Balanced" "Left" o

ordering :: a -> a -> a -> Ordering -> a
ordering lt eq gt o = case o of
  LT -> lt
  EQ -> eq
  GT -> gt