Problem:
Score : 200 points

Problem Statement

La Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each.
Determine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.

Constraints

N is an integer between 1 and 100, inclusive.

Input

Input is given from Standard Input in the following format:

N

Output

If there is a way to buy some cakes and some doughnuts for exactly N dollars, print Yes; otherwise, print No.

Sample Input 1

11

Sample Output 1

Yes

If you buy one cake and one doughnut, the total will be 4 + 7 = 11 dollars.

Sample Input 2

40

Sample Output 2

Yes

If you buy ten cakes, the total will be 4 \times 10 = 40 dollars.

Sample Input 3

3

Sample Output 3

No

The prices of cakes (4 dollars) and doughnuts (7 dollars) are both higher than 3 dollars, so there is no such way.

Solution in Haskell (GHC 7.10.3) (judge verdict: Wrong Answer)

main = do
  line <- getLine
  let 
    n = read line :: Int
    ls = [0,4,7,8,11,12,14,15,16,18,19,21,22,25]
    contains x ls
      | ls == [] = False
      | (head ls) == x  = True
      | otherwise  = contains x (tail ls)
    in
      if contains (mod n 28) ls then putStrLn "Yes"
      else putStrLn "No"