Problem:
Score : 300 points

Problem Statement

There are N people numbered 1 to N. Each of them is either an honest person whose testimonies are always correct or an unkind person whose testimonies may be correct or not.

Person i gives A_i testimonies. The j-th testimony by Person i is represented by two integers x_{ij} and y_{ij}. If y_{ij} = 1, the testimony says Person x_{ij} is honest; if y_{ij} = 0, it says Person x_{ij} is unkind.

How many honest persons can be among those N people at most?

Constraints

All values in input are integers.

1 \leq N \leq 15

0 \leq A_i \leq N - 1

1 \leq x_{ij} \leq N

x_{ij} \neq i

x_{ij_1} \neq x_{ij_2} (j_1 \neq j_2)

y_{ij} = 0, 1

Input

Input is given from Standard Input in the following format:

N
A_1
x_{11} y_{11}
x_{12} y_{12}
:
x_{1A_1} y_{1A_1}
A_2
x_{21} y_{21}
x_{22} y_{22}
:
x_{2A_2} y_{2A_2}
:
A_N
x_{N1} y_{N1}
x_{N2} y_{N2}
:
x_{NA_N} y_{NA_N}

Output

Print the maximum possible number of honest persons among the N people.

Sample Input 1

3
1
2 1
1
1 1
1
2 0

Sample Output 1

2

If Person 1 and Person 2 are honest and Person 3 is unkind, we have two honest persons without inconsistencies, which is the maximum possible number of honest persons.

Sample Input 2

3
2
2 1
3 0
2
3 1
1 0
2
1 1
2 0

Sample Output 2

0

Assuming that one or more of them are honest immediately leads to a contradiction.

Sample Input 3

2
1
2 0
1
1 0

Sample Output 3

1

Solution in Haskell (GHC 8.8.3) (judge verdict: Accepted)

import Control.Monad
import Data.List

solveSubSub [] xs = 1
solveSubSub (as:ass) xs
    | xs!!x' == y' = solveSubSub ass xs
    | otherwise = 0
        where
            x' = (as!!0) - 1
            y' = as!!1

solveSub [] xs = []
solveSub (ass:asss) xs
    | fst ass == 1 = (solveSubSub (snd ass) xs) : (solveSub asss xs)
    | otherwise = 0 : solveSub asss xs

solve [] [] = []
solve (asss:assss) (xs:xss)
    | ys == xs = (sum xs) : (solve assss xss)
    | otherwise = 0 : (solve assss xss)
    where
        ys = solveSub asss xs

main = do
    n <- readLn :: IO Int
    asss <- replicateM n $ do
        a <- readLn :: IO Int
        as <- replicateM a (map read . words <$> getLine) :: IO [[Int]]
        return $ as 
    let xss = replicateM n [0,1]
    print $ maximum $ solve (map (\x -> zip x asss) xss) xss