Problem:
Score : 400 points

Problem Statement

On a two-dimensional plane, there are N red points and N blue points.
The coordinates of the i-th red point are (a_i, b_i), and the coordinates of the i-th blue point are (c_i, d_i).

A red point and a blue point can form a friendly pair when, the x-coordinate of the red point is smaller than that of the blue point, and the y-coordinate of the red point is also smaller than that of the blue point.

At most how many friendly pairs can you form? Note that a point cannot belong to multiple pairs.

Constraints

All input values are integers.

1 \leq N \leq 100

0 \leq a_i, b_i, c_i, d_i < 2N

a_1, a_2, ..., a_N, c_1, c_2, ..., c_N are all different.

b_1, b_2, ..., b_N, d_1, d_2, ..., d_N are all different.

Input

Input is given from Standard Input in the following format:

N
a_1 b_1
a_2 b_2
:
a_N b_N
c_1 d_1
c_2 d_2
:
c_N d_N

Output

Print the maximum number of friendly pairs.

Sample Input 1

3
2 0
3 1
1 3
4 2
0 4
5 5

Sample Output 1

2

For example, you can pair (2, 0) and (4, 2), then (3, 1) and (5, 5).

Sample Input 2

3
0 0
1 1
5 2
2 3
3 4
4 5

Sample Output 2

2

For example, you can pair (0, 0) and (2, 3), then (1, 1) and (3, 4).

Sample Input 3

2
2 2
3 3
0 0
1 1

Sample Output 3

0

It is possible that no pair can be formed.

Sample Input 4

5
0 0
7 3
2 2
4 8
1 6
8 5
6 9
5 4
9 1
3 7

Sample Output 4

5

Sample Input 5

5
0 0
1 1
5 5
6 6
7 7
2 2
3 3
4 4
8 8
9 9

Sample Output 5

4

Solution in Haskell (GHC 7.10.3) (judge verdict: Accepted)

import Control.Monad
import Control.Applicative
import Data.List
import qualified Data.Map as Map
import Data.Array
import qualified Data.ByteString.Char8 as BC
import Data.Maybe
import qualified Data.Set as Set
import qualified Data.Sequence as Sq
import qualified Data.IntMap as IMap
import qualified Data.Vector as V
import Data.Sequence (ViewL(..),ViewR(..),(><),(<|),(|>),Seq)

bsreadInt :: BC.ByteString -> Int
bsreadInt = fst . fromJust . BC.readInt

sqleft :: Seq a -> a
sqleft q = sqleft_(Sq.viewl q)
sqleft_ :: ViewL a -> a
sqleft_ (x :< xs) = x
sqright :: Seq a -> a
sqright q = sqright_(Sq.viewr q)
sqright_ :: ViewR a -> a
sqright_ (xs :> x) = x
--------------------------------------------------------------
tsort xs = reverse $ map reverse $ sort  $ map (reverse) xs
alt :: Int -> [Int] -> Bool
alt k an = if k <= (head an) then True else False
bgt k an = if (an !! 1) >= k then True else False
ans :: [[Int]] -> [[Int]] -> Int
ans xn [] = 0
ans [] yn = 0
ans (x:xn) (y:yn) = if a >= c
                    then ans xn (y:yn)
                    else if null mn == False
                         then 1 + ans xn (reverse (sort ( (y:yn) \\ [head mn]) ))
                         else ans xn (y:yn)
                           where a = x !! 0
                                 b = x !! 1
                                 c = y !! 0
                                 d = y !! 1
                                 mn = reverse $ tsort $ filter (bgt b) $ filter (alt a) (y:yn)

main = do
    n <- readLn :: IO Int
    ab <- map ((map bsreadInt . BC.words)) <$> replicateM n BC.getLine
    cd <- map ((map bsreadInt . BC.words)) <$> replicateM n BC.getLine
    
    print $ ans (reverse (sort ab)) (reverse (sort cd))