Problem:
Score : 500 points

Problem Statement

You are given two integer sequences S and T of length N and M, respectively, both consisting of integers between 1 and 10^5 (inclusive).

In how many pairs of a subsequence of S and a subsequence of T do the two subsequences are the same in content?

Here the subsequence of A is a sequence obtained by removing zero or more elements from A and concatenating the remaining elements without changing the order.

For both S and T, we distinguish two subsequences if the sets of the indices of the removed elements are different, even if the subsequences are the same in content.

Since the answer can be tremendous, print the number modulo 10^9+7.

Constraints

1 \leq N, M \leq 2 \times 10^3

The length of S is N.

The length of T is M.

1 \leq S_i, T_i \leq 10^5

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M
S_1 S_2 ... S_{N-1} S_{N}
T_1 T_2 ... T_{M-1} T_{M}

Output

Print the number of pairs of a subsequence of S and a subsequence of T such that the subsequences are the same in content, modulo 10^9+7.

Sample Input 1

2 2
1 3
3 1

Sample Output 1

3

S has four subsequences: (), (1), (3), (1, 3).

T has four subsequences: (), (3), (1), (3, 1).

There are 1 \times 1 pair of subsequences in which the subsequences are both (), 1 \times 1 pair of subsequences in which the subsequences are both (1), and 1 \times 1 pair of subsequences in which the subsequences are both (3), for a total of three pairs.

Sample Input 2

2 2
1 1
1 1

Sample Output 2

6

S has four subsequences: (), (1), (1), (1, 1).

T has four subsequences: (), (1), (1), (1, 1).

There are 1 \times 1 pair of subsequences in which the subsequences are both (), 2 \times 2 pairs of subsequences in which the subsequences are both (1), and 1 \times 1 pair of subsequences in which the subsequences are both (1,1), for a total of six pairs.
Note again that we distinguish two subsequences if the sets of the indices of the removed elements are different, even if the subsequences are the same in content.

Sample Input 3

4 4
3 4 5 6
3 4 5 6

Sample Output 3

16

Sample Input 4

10 9
9 6 5 7 5 9 8 5 6 7
8 6 8 5 5 7 9 9 7

Sample Output 4

191

Sample Input 5

20 20
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1

Sample Output 5

846527861

Be sure to print the number modulo 10^9+7.

Solution in Haskell (GHC 7.10.3) (judge verdict: Accepted)

-- https://github.com/minoki/my-atcoder-solutions
{-# LANGUAGE BangPatterns #-}
{-# LANGUAGE MultiParamTypeClasses #-}
{-# LANGUAGE TypeFamilies #-}
import Data.Char (isSpace)
import Data.Int (Int64)
import Data.List (unfoldr)
import qualified Data.Vector.Unboxed as U
import qualified Data.ByteString.Char8 as BS
---
import Data.Coerce
import qualified Data.Vector.Unboxed.Mutable as UM
import qualified Data.Vector.Generic
import qualified Data.Vector.Generic.Mutable

main = do
  [n,m] <- unfoldr (BS.readInt . BS.dropWhile isSpace) <$> BS.getLine
  ss <- U.unfoldrN n (BS.readInt . BS.dropWhile isSpace) <$> BS.getLine
  ts <- U.unfoldrN m (BS.readInt . BS.dropWhile isSpace) <$> BS.getLine
  let v0 :: U.Vector N
      v0 = U.replicate (m + 1) 1
      step :: U.Vector N -> Int -> U.Vector N
      step v !s = U.scanl' (\c (t,a,b) -> if s == t then b + c else b + c - a) 1 $ U.zip3 ts v (U.tail v)
  print $ U.last $ U.foldl' step v0 ss

---

modulo :: Int64
modulo = 10^9+7
addMod, subMod, mulMod :: Int64 -> Int64 -> Int64
addMod !x !y = (x + y) `rem` modulo
subMod !x !y | x >= y = x - y
             | otherwise = x - y + modulo
mulMod !x !y = (x * y) `rem` modulo

newtype N = N { unwrapN :: Int64 } deriving (Eq)
instance Show N where
  show (N x) = show x
instance Num N where
  N x + N y = N ((x + y) `rem` modulo)
  N x - N y = N ((x - y) `mod` modulo)
  N x * N y = N ((x * y) `rem` modulo)
  fromInteger n = N (fromInteger (n `mod` fromIntegral modulo))
  abs = undefined; signum = undefined

---

newtype instance UM.MVector s N = MV_N (UM.MVector s Int64)
newtype instance U.Vector N = V_N (U.Vector Int64)

instance Data.Vector.Generic.Mutable.MVector UM.MVector N where -- needs MultiParamTypeClasses here
  basicLength (MV_N mv) = Data.Vector.Generic.Mutable.basicLength mv
  basicUnsafeSlice i l (MV_N mv) = MV_N (Data.Vector.Generic.Mutable.basicUnsafeSlice i l mv)
  basicOverlaps (MV_N mv) (MV_N mv') = Data.Vector.Generic.Mutable.basicOverlaps mv mv'
  basicUnsafeNew l = MV_N <$> Data.Vector.Generic.Mutable.basicUnsafeNew l
  basicInitialize (MV_N mv) = Data.Vector.Generic.Mutable.basicInitialize mv
  basicUnsafeReplicate i x = MV_N <$> Data.Vector.Generic.Mutable.basicUnsafeReplicate i (coerce x)
  basicUnsafeRead (MV_N mv) i = coerce <$> Data.Vector.Generic.Mutable.basicUnsafeRead mv i
  basicUnsafeWrite (MV_N mv) i x = Data.Vector.Generic.Mutable.basicUnsafeWrite mv i (coerce x)
  basicClear (MV_N mv) = Data.Vector.Generic.Mutable.basicClear mv
  basicSet (MV_N mv) x = Data.Vector.Generic.Mutable.basicSet mv (coerce x)
  basicUnsafeCopy (MV_N mv) (MV_N mv') = Data.Vector.Generic.Mutable.basicUnsafeCopy mv mv'
  basicUnsafeMove (MV_N mv) (MV_N mv') = Data.Vector.Generic.Mutable.basicUnsafeMove mv mv'
  basicUnsafeGrow (MV_N mv) n = MV_N <$> Data.Vector.Generic.Mutable.basicUnsafeGrow mv n

instance Data.Vector.Generic.Vector U.Vector N where -- needs MultiParamTypeClasses here
  basicUnsafeFreeze (MV_N mv) = V_N <$> Data.Vector.Generic.basicUnsafeFreeze mv
  basicUnsafeThaw (V_N v) = MV_N <$> Data.Vector.Generic.basicUnsafeThaw v
  basicLength (V_N v) = Data.Vector.Generic.basicLength v
  basicUnsafeSlice i l (V_N v) = V_N (Data.Vector.Generic.basicUnsafeSlice i l v)
  basicUnsafeIndexM (V_N v) i = coerce <$> Data.Vector.Generic.basicUnsafeIndexM v i
  basicUnsafeCopy (MV_N mv) (V_N v) = Data.Vector.Generic.basicUnsafeCopy mv v
  elemseq (V_N v) x y = Data.Vector.Generic.elemseq v (coerce x) y

instance U.Unbox N