Problem:
Score : 200 points

Problem Statement

In some other world, today is the day before Christmas Eve.

Mr. Takaha is buying N items at a department store. The regular price of the i-th item (1 \leq i \leq N) is p_i yen (the currency of Japan).

He has a discount coupon, and can buy one item with the highest price for half the regular price. The remaining N-1 items cost their regular prices. What is the total amount he will pay?

Constraints

2 \leq N \leq 10

100 \leq p_i \leq 10000

p_i is an even number.

Input

Input is given from Standard Input in the following format:

N
p_1
p_2
:
p_N

Output

Print the total amount Mr. Takaha will pay.

Sample Input 1

3
4980
7980
6980

Sample Output 1

15950

The 7980-yen item gets the discount and the total is 4980 + 7980 / 2 + 6980 = 15950 yen.

Note that outputs such as 15950.0 will be judged as Wrong Answer.

Sample Input 2

4
4320
4320
4320
4320

Sample Output 2

15120

Only one of the four items gets the discount and the total is 4320 / 2 + 4320 + 4320 + 4320 = 15120 yen.

Solution in Haskell (GHC 7.10.3) (judge verdict: Accepted)

import Control.Monad
import Control.Applicative
import Data.List


-- [a] <- map read . words <$> getLine => [1] -> a == 1
-- 1
-- a <- readLn
-- 1 2 3
-- lst <- map read . words <$> getLine => [1, 2, 3]
-- 1 2 3
-- [l, m, n] <- map read . words <$. getLine :: IO [Int] => [1, 2, 3]
-- 'a'
-- c <- getChar => c == 'a'
--
-- slst <- replicateM h getLine

-- getBysplit = map read . words <$> getLine

main :: IO()
main = do
  n <- readLn :: IO Int
  plst <- replicateM n readLn :: IO [Int]
  let x:xs = (reverse . sort) plst
  let ans = x `div` 2 + sum xs
  print ans