Problem:
Score : 100 points

Problem Statement

There are N items, numbered 1, 2, \ldots, N.
For each i (1 \leq i \leq N), Item i has a weight of w_i and a value of v_i.

Taro has decided to choose some of the N items and carry them home in a knapsack.
The capacity of the knapsack is W, which means that the sum of the weights of items taken must be at most W.

Find the maximum possible sum of the values of items that Taro takes home.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq W \leq 10^5

1 \leq w_i \leq W

1 \leq v_i \leq 10^9

Input

Input is given from Standard Input in the following format:

N W
w_1 v_1
w_2 v_2
:
w_N v_N

Output

Print the maximum possible sum of the values of items that Taro takes home.

Sample Input 1

3 8
3 30
4 50
5 60

Sample Output 1

90

Items 1 and 3 should be taken.
Then, the sum of the weights is 3 + 5 = 8, and the sum of the values is 30 + 60 = 90.

Sample Input 2

5 5
1 1000000000
1 1000000000
1 1000000000
1 1000000000
1 1000000000

Sample Output 2

5000000000

The answer may not fit into a 32-bit integer type.

Sample Input 3

6 15
6 5
5 6
6 4
6 6
3 5
7 2

Sample Output 3

17

Items 2, 4 and 5 should be taken.
Then, the sum of the weights is 5 + 6 + 3 = 14, and the sum of the values is 6 + 6 + 5 = 17.

Solution in Haskell (GHC 7.10.3) (judge verdict: Accepted)

{-# LANGUAGE BangPatterns #-}

import           Control.Monad
import           Data.Array.ST
import           Data.Array.Unboxed    (UArray)
import qualified Data.Array.Unboxed    as U
import qualified Data.ByteString.Char8 as BS
import           Data.Char
import           Data.List

getAsInt :: IO [Int]
getAsInt =  unfoldr (BS.readInt . BS.dropWhile isSpace) <$> BS.getLine

getAsIntLine :: Int -> IO [[Int]]
getAsIntLine n = replicateM n getAsInt

getAsIntArray2D :: Int -> Int -> IO (UArray (Int,Int) Int)
getAsIntArray2D n m = U.listArray ((1,1),(n,m)) . concat <$> getAsIntLine n


main :: IO ()
main = main2

main1 :: IO ()
main1 = do
  [n,w] <- getAsInt
  wvs <- getAsIntArray2D n 2
  let result = solve1 wvs n w
  print $ maximum $ map (\x -> result U.! (n,x)) [0..w]

main2 :: IO ()
main2 = do
  [n,w] <- getAsInt
  wvs <- map (\[x,y] -> (x, y)) <$> getAsIntLine n
  let solve = solve3
      result = solve w wvs
  print $ maximum $ map (\x -> result U.! x) [0..w]

solve1 :: UArray (Int,Int) Int -> Int -> Int -> UArray (Int,Int) Int
solve1 wvs n' w' = runSTUArray $ do
  dp <- newArray ((0,0),(n',w')) 0
  forM_ [(n_,w_) | n_ <- [1..n'], w_ <- [0..w']] $ \(n,w) -> do
    let wtmp = wvs U.! (n,1)
        vtmp = wvs U.! (n,2)
    if w - wtmp < 0
      then readArray dp (n-1,w) >>= writeArray dp (n,w)
      else do
        a <- readArray dp (n-1,w)
        b <- readArray dp (n-1,w-wtmp)
        writeArray dp (n,w) $ max a (b+vtmp)
  return dp

solve2 :: Int -> [(Int,Int)] -> UArray Int Int
solve2 w' [] = U.listArray (0,w') $ repeat 0
solve2 w' ((wtmp,vtmp):xs) = let a = solve2 w' xs
                                 f w = if w - wtmp >= 0
                                       then max (a U.! w) (a U.! (w - wtmp) + vtmp)
                                       else a U.! w
                             in U.array (0,w') [(w, f w) | w <- [0..w']]

solve3 :: Int -> [(Int,Int)] -> UArray Int Int
solve3 w' = foldr f (U.listArray (0,w') $ repeat 0)
  where f (wtmp,vtmp) a = let g w = if w - wtmp >= 0
                                    then max (a U.! w) (a U.! (w - wtmp) + vtmp)
                                    else a U.! w
                          in U.array (0,w') [(w, g w) | w <- [0..w']]

solve3' :: Int -> [(Int,Int)] -> UArray Int Int
solve3' !w' = foldr f (U.listArray (0,w') $ repeat 0)
  where f (!wtmp,!vtmp) !a = let g !w = if w - wtmp >= 0
                                        then max (a U.! w) (a U.! (w - wtmp) + vtmp)
                                        else a U.! w
                          in U.array (0,w') [(w, g w) | !w <- [0..w']]