Problem:
Score : 100 points

Problem Statement

You are given integers A and B, each between 1 and 3 (inclusive).

Determine if there is an integer C between 1 and 3 (inclusive) such that A \times B \times C is an odd number.

Constraints

All values in input are integers.

1 \leq A, B \leq 3

Input

Input is given from Standard Input in the following format:

A B

Output

If there is an integer C between 1 and 3 that satisfies the condition, print Yes; otherwise, print No.

Sample Input 1

3 1

Sample Output 1

Yes

Let C = 3. Then, A \times B \times C = 3 \times 1 \times 3 = 9, which is an odd number.

Sample Input 2

1 2

Sample Output 2

No

Sample Input 3

2 2

Sample Output 3

No

Solution in Haskell (GHC 7.10.3) (judge verdict: Accepted)

{-# LANGUAGE FlexibleContexts #-}
import Control.Monad
import Control.Monad.State
import Control.Monad.Reader
import Control.Arrow
-- import Control.Comonad
import Data.Maybe
import Data.List
import Data.Bool
import Data.Fixed
import Data.Tuple
import Data.Ratio
import qualified Data.Map.Strict as M
import qualified Data.Array.IO as IA
import qualified Data.Vector as V
 
getI = read <$> getLine :: IO Int
getIs = map read . words <$> getLine :: IO [Int]
getD = read <$> getLine :: IO Double
getDs = map read . words <$> getLine :: IO [Double]
getInt = read <$> getLine :: IO Integer
getInts = map read . words <$> getLine :: IO [Integer]
 
type Row = Integer
type Col = Integer
type PointI = (Integer, Integer)
type Point = (Int, Int)
 
mmm = 1000000007
fact n
    | n < 1 = 1
    | True = foldr1 (*) [1..n]
fi = fromInteger
fig = fromIntegral
rf = realToFrac
 
(.<.) f g -- combination
    | f < g = 0 
    | g < 1 || f < 1 = 1
    | True = foldr1 (*) (take g [f,f-1..]) `div` fact g
(.>.) f g --combination with repetition
    | g < 1 || f < 1 = 1
    | True = fact (f + g - 1) `div` (fact (f - 1) * fact g)
comb = (.<.)
combWp = (.>.)
 
unique a = unique_ (reverse . sort $ a) [] Nothing
    where
        unique_ [] arr _ = arr
        unique_ (x:xs) arr n
            | n == Just x = unique_ xs arr n
            | otherwise = unique_ xs (x:arr) $ Just x
 
zeroume keta num
    | (length . show $ num) > keta = show num
    | otherwise = do 
        let zeros = take keta $ repeat '0'
        reverse . take keta $ (reverse . show $ num) ++ zeros
 
i2b num
    | num < 2 = show num
    | otherwise = i2b_ num []
        where
            i2b_ num str
                | num == 0 = str
                | num == 1 = '1':str
                | otherwise = do
                    let next = num `div` 2
                    let this = if odd num then '1' else '0'
                    i2b_ next (this:str)
 
mapIncr = mapPlus 1
mapPlus n Nothing = Just n
mapPlus n a = (+) n <$> a
 
countIf f = length . filter f
 
-- 
--
--

main = do
  a <- getIs
  putStrLn $ bool "Yes" "No" (any (\x -> mod x 2 == 0) a)