Problem:
Score : 100 points

Problem Statement

X and A are integers between 0 and 9 (inclusive).

If X is less than A, print 0; if X is not less than A, print 10.

Constraints

0 \leq X, A \leq 9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X A

Output

If X is less than A, print 0; if X is not less than A, print 10.

Sample Input 1

3 5

Sample Output 1

0

3 is less than 5, so we should print 0.

Sample Input 2

7 5

Sample Output 2

10

7 is not less than 5, so we should print 10.

Sample Input 3

6 6

Sample Output 3

10

6 is not less than 6, so we should print 10.

Solution in Haskell (GHC 7.10.3) (judge verdict: Accepted)

{-# LANGUAGE BangPatterns #-}
import Control.Arrow
import Control.Monad.Fix
import Data.Char
import Data.Int
import Data.Foldable
import Data.List
import qualified Data.Vector as V
import qualified Data.Vector.Unboxed as VU
import qualified Data.ByteString.Char8 as B

solve :: Int -> Int -> Int
solve !x !a | x < a  = 0
            | x >= a = 10

main = do
  let readInt :: Integral a => B.ByteString -> Maybe (a, B.ByteString)
      readInt = fmap (first fromIntegral . second B.tail) . B.readInt

  (x, a) <-
    (\vec -> (vec VU.! 0, vec VU.! 1)) . VU.unfoldrN 2 readInt <$> B.getLine
  print $ solve x a