Problem:
Score : 400 points

Problem Statement

There are N towns in the State of Atcoder, connected by M bidirectional roads.

The i-th road connects Town A_i and B_i and has a length of C_i.

Joisino is visiting R towns in the state, r_1,r_2,..,r_R (not necessarily in this order).

She will fly to the first town she visits, and fly back from the last town she visits, but for the rest of the trip she will have to travel by road.

If she visits the towns in the order that minimizes the distance traveled by road, what will that distance be?

Constraints

2≤N≤200

1≤M≤N×(N-1)/2

2≤R≤min(8,N) (min(8,N) is the smaller of 8 and N.)

r_i≠r_j (i≠j)

1≤A_i,B_i≤N, A_i≠B_i

(A_i,B_i)≠(A_j,B_j),(A_i,B_i)≠(B_j,A_j) (i≠j)

1≤C_i≤100000

Every town can be reached from every town by road.

All input values are integers.

Input

Input is given from Standard Input in the following format:

N M R
r_1 ... r_R
A_1 B_1 C_1
:
A_M B_M C_M

Output

Print the distance traveled by road if Joisino visits the towns in the order that minimizes it.

Sample Input 1

3 3 3
1 2 3
1 2 1
2 3 1
3 1 4

Sample Output 1

2

For example, if she visits the towns in the order of 1, 2, 3, the distance traveled will be 2, which is the minimum possible.

Sample Input 2

3 3 2
1 3
2 3 2
1 3 6
1 2 2

Sample Output 2

4

The shortest distance between Towns 1 and 3 is 4. Thus, whether she visits Town 1 or 3 first, the distance traveled will be 4.

Sample Input 3

4 6 3
2 3 4
1 2 4
2 3 3
4 3 1
1 4 1
4 2 2
3 1 6

Sample Output 3

3

Solution in Haskell (GHC 7.10.3) (judge verdict: Wrong Answer)

import qualified Data.Set as S
import qualified Data.ByteString.Char8 as B
import qualified Data.Array.IArray as A
import qualified Data.Map.Strict as M
import Data.List

main = do
  [n,m,r] <- map read . words <$> getLine
  rs <- map (pred . read) . words <$> getLine
  es <- readUndirectedEdge <$> B.getContents
  let g = buildG (0,n-1) es
  let memo = warshallFloyd n es
  let vs = [(v,w) | v<-rs, w<-rs, v<w]
  print $ sum $ (\xs -> if length xs <= 2 then xs else init xs) $ sort $ map (\e -> memo M.! e) vs

type Memo = M.Map (Vertex, Vertex) Weight

-- 0-indexed vertex
warshallFloyd :: Int -> [Edge] -> Memo
warshallFloyd n es = foldl shorten m0 kij
  where
    m0 = M.fromList es
    kij = [(k, i, j) | k <- [0 .. pred n], i <- [0 .. pred n], j <- [0 .. pred n]]

shorten :: Memo -> (Vertex, Vertex, Vertex) -> Memo
shorten m (k, i, j) = case connect m k i j of
  Nothing -> m
  Just w -> M.insertWith min (i, j) w m

connect :: Memo -> Vertex -> Vertex -> Vertex -> Maybe Weight
connect m k i j = do
  w1 <- M.lookup (i, k) m
  w2 <- M.lookup (k, j) m
  return (w1 + w2)

readInt :: B.ByteString -> Int
readInt = maybe undefined fst . B.readInt

type Bound = (Vertex, Vertex)
type Vertex = Int
type Weight = Int
type Edge = ((Vertex, Vertex), Weight)
type Path = [Vertex]
type Graph = A.Array Vertex (S.Set (Vertex, Weight))

buildG :: Bound -> [Edge] -> Graph
buildG b = A.accumArray (flip S.insert) S.empty b . map (\((s, t), w) -> (s, (t, w)))

target :: Graph -> Vertex -> S.Set (Vertex, Weight)
target = (A.!)

size :: Graph -> Int
size g = let (i,j) = A.bounds g in j - i + 1

readUndirectedEdge :: B.ByteString -> [Edge]
readUndirectedEdge = concatMap (constructTwoWay . map readInt . B.words) . B.lines

constructTwoWay :: [Int] -> [Edge]
constructTwoWay [s,t,w] = [((s-1, t-1), w), ((t-1, s-1), w)]
constructTwoWay _ = undefined