Problem:
Score : 300 points

Problem Statement

There are 3N participants in AtCoder Group Contest.
The strength of the i-th participant is represented by an integer a_i.
They will form N teams, each consisting of three participants.
No participant may belong to multiple teams.

The strength of a team is defined as the second largest strength among its members.
For example, a team of participants of strength 1, 5, 2 has a strength 2, and a team of three participants of strength 3, 2, 3 has a strength 3.

Find the maximum possible sum of the strengths of N teams.

Constraints

1 ≤ N ≤ 10^5

1 ≤ a_i ≤ 10^{9}

a_i are integers.

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 ... a_{3N}

Output

Print the answer.

Sample Input 1

2
5 2 8 5 1 5

Sample Output 1

10

The following is one formation of teams that maximizes the sum of the strengths of teams:

Team 1: consists of the first, fourth and fifth participants.

Team 2: consists of the second, third and sixth participants.

Sample Input 2

10
1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000

Sample Output 2

10000000000

The sum of the strengths can be quite large.

Solution in Haskell (GHC 7.10.3) (judge verdict: Wrong Answer)

import           Control.Applicative
import           Control.DeepSeq
import           Control.Monad
import           Control.Monad.ST
import qualified Data.Array                    as A
import qualified Data.Array.IArray             as IA
import qualified Data.Array.IO                 as AI
import qualified Data.Array.MArray             as MA
import qualified Data.Array.ST                 as STA
import qualified Data.Array.Unboxed            as AU
import           Data.Bits
import qualified Data.ByteString.Char8         as BS
import           Data.Char
import qualified Data.Graph                    as G
import           Data.Int
import qualified Data.IntMap                   as IM
import qualified Data.IntSet                   as IS
import           Data.List
import qualified Data.Map.Strict               as M
import           Data.Maybe
import           Data.Ord
import qualified Data.Sequence                 as SQ
import qualified Data.Set                      as S
import           Data.Time
import qualified Data.Tree                     as T
import qualified Data.Vector                   as V
import qualified Data.Vector.Mutable           as VM
import qualified Data.Vector.Unboxed           as VU
import qualified Data.Vector.Unboxed.Mutable   as VUM

readInt :: IO Int
readInt = fst . fromJust . BS.readInt <$> BS.getLine

readInts :: IO [Int]
readInts = map (fst . fromJust . BS.readInt) . BS.words <$> BS.getLine

readIntLists :: Int -> IO [[Int]]
readIntLists n = replicateM n readInts

readInteger :: IO Integer
readInteger = fst . fromJust . BS.readInteger <$> BS.getLine

readIntegers :: IO [Integer]
readIntegers = map (fst . fromJust . BS.readInteger) . BS.words <$> BS.getLine

readIntegerLists :: Int -> IO [[Integer]]
readIntegerLists n = replicateM n readIntegers

readStrings :: IO [String]
readStrings = map BS.unpack . BS.words <$> BS.getLine

readStringLists :: Int -> IO [[String]]
readStringLists n = replicateM n <$> readStrings

toPair :: [a] -> (a, a)
toPair [x, y] = (x, y)

count :: Eq a => a -> [a] -> Int
count a as = length $ filter (== a) as

put :: Show a => a -> IO ()
put = putStr . show

putList :: Show a => [a] -> IO ()
putList [n     ] = print n
putList (n : ns) = do
  put n
  putStr " "
  putList ns

putStrList :: [String] -> IO ()
putStrList [n     ] = putStrLn n
putStrList (n : ns) = do
  putStr n
  putStr " "
  putStrList ns

yesNoUpper b | b         = putStrLn "YES"
             | otherwise = putStrLn "NO"

yesNo b | b         = putStrLn "Yes"
        | otherwise = putStrLn "No"

divCeiling x n | b == 0    = a
               | otherwise = a + 1
  where (a, b) = x `divMod` n

main = do
  n  <- readInt
  as <- readInts
  print $ sum $ take n $ drop n $ sort as