Problem:
Score : 200 points

Problem Statement

In some other world, today is the day before Christmas Eve.

Mr. Takaha is buying N items at a department store. The regular price of the i-th item (1 \leq i \leq N) is p_i yen (the currency of Japan).

He has a discount coupon, and can buy one item with the highest price for half the regular price. The remaining N-1 items cost their regular prices. What is the total amount he will pay?

Constraints

2 \leq N \leq 10

100 \leq p_i \leq 10000

p_i is an even number.

Input

Input is given from Standard Input in the following format:

N
p_1
p_2
:
p_N

Output

Print the total amount Mr. Takaha will pay.

Sample Input 1

3
4980
7980
6980

Sample Output 1

15950

The 7980-yen item gets the discount and the total is 4980 + 7980 / 2 + 6980 = 15950 yen.

Note that outputs such as 15950.0 will be judged as Wrong Answer.

Sample Input 2

4
4320
4320
4320
4320

Sample Output 2

15120

Only one of the four items gets the discount and the total is 4320 / 2 + 4320 + 4320 + 4320 = 15120 yen.

Solution in Go (1.14.1) (judge verdict: Accepted)

package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

const (
	initialBufSize = 1e4
	maxBufSize     = 1e8
)

var sc = bufio.NewScanner(os.Stdin)

func init() {
	buf := make([]byte, initialBufSize)
	sc.Buffer(buf, maxBufSize)
	sc.Split(bufio.ScanWords)
}

func next() string {
	sc.Scan()
	return sc.Text()
}

func nextInt() int {
	a, _ := strconv.Atoi(next())
	return a
}

func sum(x []int) int {
	s := x[0]
	for i := 1; i < len(x); i++ {
		s += x[i]
	}
	return s
}

func max(x []int) int {
	m := x[0]
	for i := 1; i < len(x); i++ {
		if m < x[i] {
			m = x[i]
		}
	}
	return m
}

func main() {
	N := nextInt()
	p := make([]int, N)
	for i := 0; i < N; i++ {
		p[i] = nextInt()
	}
	fmt.Println(sum(p) - max(p)/2)
}