Problem:
Score : 200 points

Problem Statement

Evi has N integers a_1,a_2,..,a_N. His objective is to have N equal integers by transforming some of them.

He may transform each integer at most once. Transforming an integer x into another integer y costs him (x-y)^2 dollars. Even if a_i=a_j (i≠j), he has to pay the cost separately for transforming each of them (See Sample 2).

Find the minimum total cost to achieve his objective.

Constraints

1≦N≦100

-100≦a_i≦100

Input

The input is given from Standard Input in the following format:

N
a_1 a_2 ... a_N

Output

Print the minimum total cost to achieve Evi's objective.

Sample Input 1

2
4 8

Sample Output 1

8

Transforming the both into 6s will cost (4-6)^2+(8-6)^2=8 dollars, which is the minimum.

Sample Input 2

3
1 1 3

Sample Output 2

3

Transforming the all into 2s will cost (1-2)^2+(1-2)^2+(3-2)^2=3 dollars. Note that Evi has to pay (1-2)^2 dollar separately for transforming each of the two 1s.

Sample Input 3

3
4 2 5

Sample Output 3

5

Leaving the 4 as it is and transforming the 2 and the 5 into 4s will achieve the total cost of (2-4)^2+(5-4)^2=5 dollars, which is the minimum.

Sample Input 4

4
-100 -100 -100 -100

Sample Output 4

0

Without transforming anything, Evi's objective is already achieved. Thus, the necessary cost is 0.

Solution in Go (1.6) (judge verdict: Accepted)

package main

import (
	"fmt"
)

func main() {
	var n int
	fmt.Scan(&n)
	var v = make([]int, n, n)
	for i := 0; i < n; i++ {
		fmt.Scan(&v[i])
	}
	max, min := maxAndMin(v)
	var lenOfCosts = max - min + 1
	var costs = make([]int, lenOfCosts, lenOfCosts)
	var costsIndex int = 0
	for i := min; i <= max; i++ {
		var sum int = 0
		for j := 0; j < n; j++ {
			diff := i - v[j]
			sum += (diff * diff)
		}
		costs[costsIndex] = sum
		costsIndex++
	}
	_, ans := maxAndMin(costs)
	fmt.Println(ans)
}

func maxAndMin(slice []int) (int, int) {
	var max int = 0
	var min int = slice[0]
	for _, v := range slice {
		if v > max {
			max = v
		}
		if min > v {
			min = v
		}
	}
	return max, min
}