Problem:
Score : 300 points

Problem Statement

You are given an integer sequence of length n, a_1, ..., a_n.
Let us consider performing the following n operations on an empty sequence b.

The i-th operation is as follows:

Append a_i to the end of b.

Reverse the order of the elements in b.

Find the sequence b obtained after these n operations.

Constraints

1 \leq n \leq 2\times 10^5

0 \leq a_i \leq 10^9

n and a_i are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print n integers in a line with spaces in between.
The i-th integer should be b_i.

Sample Input 1

4
1 2 3 4

Sample Output 1

4 2 1 3

After step 1 of the first operation, b becomes: 1.

After step 2 of the first operation, b becomes: 1.

After step 1 of the second operation, b becomes: 1, 2.

After step 2 of the second operation, b becomes: 2, 1.

After step 1 of the third operation, b becomes: 2, 1, 3.

After step 2 of the third operation, b becomes: 3, 1, 2.

After step 1 of the fourth operation, b becomes: 3, 1, 2, 4.

After step 2 of the fourth operation, b becomes: 4, 2, 1, 3.

Thus, the answer is 4 2 1 3.

Sample Input 2

3
1 2 3

Sample Output 2

3 1 2

As shown above in Sample Output 1, b becomes 3, 1, 2 after step 2 of the third operation. Thus, the answer is 3 1 2.

Sample Input 3

1
1000000000

Sample Output 3

1000000000

Sample Input 4

6
0 6 7 6 7 0

Sample Output 4

0 6 6 0 7 7

Solution in Go (1.6) (judge verdict: Wrong Answer)

package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
	"strings"
)

func main() {
	sc := bufio.NewScanner(os.Stdin)
	sc.Scan()
	ns := sc.Text()
	sc.Scan()
	line := strings.Split(sc.Text(), " ")
	n, _ := strconv.Atoi(ns)
	ad := n % 2
	l, r := make([]string, n / 2), make([]string, (n / 2) + ad)
	for i, v := range line {
		if i % 2 == 0 {
			r[i / 2] = v
		} else {
			l[i / 2] = v
		}
	}
	if n % 2 == 0 {
		for i := len(l) - 1; i >= 0; i-- {
			fmt.Print(l[i])
			if i != 0 {
				fmt.Print(" ")
			}
		}
		for i := 0; i < len(r); i++ {
			fmt.Print(" ")
			fmt.Print(r[i])
		}
	} else {
		for i := len(r) - 1; i >= 0; i-- {
			fmt.Print(r[i])
			if i != 0 {
				fmt.Print(" ")
			}
		}
		for i := 0; i < len(l); i++ {
			fmt.Print(" ")
			fmt.Print(l[i])
		}
	}
	fmt.Println()
}