Problem:
Score : 100 points

Problem Statement

You are given a binary array A=(A_1,A_2,\cdots,A_N) of length N.

Process Q queries of the following types. The i-th query is represented by three integers T_i,L_i,R_i.

T_i=1: Replace the value of A_j with 1-A_j for each L_i \leq j \leq R_i.

T_i=2: Calculate the inversion(*) of the array A_{L_i},A_{L_i+1},\cdots,A_{R_i}．

Note：The inversion of the array x_1,x_2,\cdots,x_k is the number of the pair of integers i,j with 1 \leq i < j \leq k, x_i > x_j.

Constraints

1 \leq N \leq 2 \times 10^5

0 \leq A_i \leq 1

1 \leq Q \leq 2 \times 10^5

1 \leq T_i \leq 2

1 \leq L_i \leq R_i \leq N

All values in Input are integer.

Input

Input is given from Standard Input in the following format:

N Q
A_1 A_2 \cdots A_N
T_1 L_1 R_1
T_2 L_2 R_2
\vdots
T_Q L_Q R_Q

Output

For each query with T_i=2, print the answer.

Sample Input 1

5 5
0 1 0 0 1
2 1 5
1 3 4
2 2 5
1 1 3
2 1 2

Sample Output 1

2
0
1

First query: Print 2, which is the inversion of (A_1,A_2,A_3,A_4,A_5)=(0,1,0,0,1).

Second query: Replace the value of A_3 and A_4 with 1 and 1, respectively.

Third query: Print 0, which is the inversion of (A_2,A_3,A_4,A_5)=(1,1,1,1).

Fourth query: Replace the value of A_1, A_2 and A_4 with 1, 0 and 0, respectively.

Fifth query: Print 1, which is the inversion of (A_1,A_2)=(1,0).

Solution in Go (1.14.1) (judge verdict: Accepted)

package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
	"strings"
)

var sc = bufio.NewScanner(os.Stdin)

func Scan() string {
	sc.Scan()
	return sc.Text()
}
func rScan() []rune {
	return []rune(Scan())
}
func iScan() int {
	n, _ := strconv.Atoi(Scan())
	return n
}
func fScan() float64 {
	n, _ := strconv.ParseFloat(Scan(), 64)
	return n
}
func stringToInt(s string) int {
	n, _ := strconv.Atoi(s)
	return n
}
func SScan(n int) []string {
	a := make([]string, n)
	for i := 0; i < n; i++ {
		a[i] = Scan()
	}
	return a
}
func iSScan(n int) []int {
	a := make([]int, n)
	for i := 0; i < n; i++ {
		a[i] = iScan()
	}
	return a
}
func abs(x int) int {
	if x < 0 {
		x = -x
	}
	return x
}
func mod(x, d int) int {
	x %= d
	if x < 0 {
		x += d
	}
	return x
}
func larger(a, b int) int {
	if a < b {
		return b
	} else {
		return a
	}
}
func smaller(a, b int) int {
	if a > b {
		return b
	} else {
		return a
	}
}
func max(a []int) int {
	x := a[0]
	for i := 0; i < len(a); i++ {
		if x < a[i] {
			x = a[i]
		}
	}
	return x
}
func min(a []int) int {
	x := a[0]
	for i := 0; i < len(a); i++ {
		if x > a[i] {
			x = a[i]
		}
	}
	return x
}
func sum(a []int) int {
	x := 0
	for _, v := range a {
		x += v
	}
	return x
}
func fSum(a []float64) float64 {
	x := 0.
	for _, v := range a {
		x += v
	}
	return x
}
func bPrint(f bool, x string, y string) {
	if f {
		fmt.Println(x)
	} else {
		fmt.Println(y)
	}
}
func iSSPrint(x []int) {
	fmt.Println(strings.Trim(fmt.Sprint(x), "[]"))
}

var lp1 int = 1000000007
var lp2 int = 998244353

func main() {
	buf := make([]byte, 0)
	sc.Buffer(buf, lp1)
	sc.Split(bufio.ScanWords)
	n, q := iScan(), iScan()
	a := make([]S, n)
	for i := 0; i < n; i++ {
		if iScan() == 0 {
			a[i] = S{1, 0, 0}
		} else {
			a[i] = S{0, 1, 0}
		}
	}
	e := func() S {
		return S{0, 0, 0}
	}
	mrg := func(l, r S) S {
		return S{l.zero + r.zero, l.one + r.one, l.inversion + r.inversion + l.one*r.zero}
	}
	mp := func(l F, r S) S {
		if !l.b {
			return r
		}
		return S{r.one, r.zero, r.one*r.zero - r.inversion}
	}
	comp := func(l, r F) F {
		return F{l.b && !r.b || !l.b && r.b}
	}
	id := func() F {
		return F{false}
	}
	lseg := newLazySegtree(a, e, mrg, mp, comp, id)
	for i := 0; i < q; i++ {
		t, l, r := iScan(), iScan(), iScan()
		l--
		if t == 1 {
			lseg.RangeApply(l, r, F{true})
		} else {
			fmt.Println(lseg.Prod(l, r).inversion)
		}
	}
}

type S struct {
	zero      int
	one       int
	inversion int
}
type F struct {
	b bool
}
type E func() S
type Merger func(a, b S) S
type Mapper func(f F, x S) S
type Comp func(f, g F) F
type Id func() F
type Compare func(v S) bool
type LazySegtree struct {
	n      int
	size   int
	log    int
	d      []S
	lz     []F
	e      E
	merger Merger
	mapper Mapper
	comp   Comp
	id     Id
}

func newLazySegtree(v []S, e E, merger Merger, mapper Mapper, comp Comp, id Id) *LazySegtree {
	lseg := new(LazySegtree)
	lseg.n = len(v)
	lseg.log = lseg.ceilPow2(lseg.n)
	lseg.size = 1 << uint(lseg.log)
	lseg.d = make([]S, 2*lseg.size)
	lseg.e = e
	lseg.lz = make([]F, lseg.size)
	lseg.merger = merger
	lseg.mapper = mapper
	lseg.comp = comp
	lseg.id = id
	for i, _ := range lseg.d {
		lseg.d[i] = lseg.e()
	}
	for i, _ := range lseg.lz {
		lseg.lz[i] = lseg.id()
	}
	for i := 0; i < lseg.n; i++ {
		lseg.d[lseg.size+i] = v[i]
	}
	for i := lseg.size - 1; i >= 1; i-- {
		lseg.Update(i)
	}
	return lseg
}
func (lseg *LazySegtree) Update(k int) {
	lseg.d[k] = lseg.merger(lseg.d[2*k], lseg.d[2*k+1])
}
func (lseg *LazySegtree) AllApply(k int, f F) {
	lseg.d[k] = lseg.mapper(f, lseg.d[k])
	if k < lseg.size {
		lseg.lz[k] = lseg.comp(f, lseg.lz[k])
	}
}
func (lseg *LazySegtree) Push(k int) {
	lseg.AllApply(2*k, lseg.lz[k])
	lseg.AllApply(2*k+1, lseg.lz[k])
	lseg.lz[k] = lseg.id()
}
func (lseg *LazySegtree) Set(p int, x S) {
	p += lseg.size
	for i := lseg.log; i <= 1; i-- {
		lseg.Push(p >> uint(i))
	}
	lseg.d[p] = x
	for i := 1; i <= lseg.log; i++ {
		lseg.Update(p >> uint(i))
	}
}
func (lseg *LazySegtree) Get(p int) S {
	p += lseg.size
	for i := lseg.log; i >= 1; i-- {
		lseg.Push(p >> uint(i))
	}
	return lseg.d[p]
}
func (lseg *LazySegtree) Prod(l, r int) S {
	if l == r {
		return lseg.e()
	}
	l += lseg.size
	r += lseg.size
	for i := lseg.log; i >= 1; i-- {
		if (l>>uint(i))<<uint(i) != l {
			lseg.Push(l >> uint(i))
		}
		if (r>>uint(i))<<uint(i) != r {
			lseg.Push(r >> uint(i))
		}
	}
	sml, smr := lseg.e(), lseg.e()
	for l < r {
		if (l & 1) == 1 {
			sml = lseg.merger(sml, lseg.d[l])
			l++
		}
		if (r & 1) == 1 {
			r--
			smr = lseg.merger(lseg.d[r], smr)
		}
		l >>= 1
		r >>= 1
	}
	return lseg.merger(sml, smr)
}
func (lseg *LazySegtree) AllProd() S {
	return lseg.d[1]
}
func (lseg *LazySegtree) Apply(p int, f F) {
	p += lseg.size
	for i := lseg.log; i >= 1; i-- {
		lseg.Push(p >> uint(i))
	}
	lseg.d[p] = lseg.mapper(f, lseg.d[p])
	for i := 1; i <= lseg.log; i++ {
		lseg.Update(p >> uint(i))
	}
}
func (lseg *LazySegtree) RangeApply(l int, r int, f F) {
	if l == r {
		return
	}
	l += lseg.size
	r += lseg.size
	for i := lseg.log; i >= 1; i-- {
		if (l>>uint(i))<<uint(i) != l {
			lseg.Push(l >> uint(i))
		}
		if (r>>uint(i))<<uint(i) != r {
			lseg.Push((r - 1) >> uint(i))
		}
	}
	l2, r2 := l, r
	for l < r {
		if l&1 == 1 {
			lseg.AllApply(l, f)
			l++
		}
		if r&1 == 1 {
			r--
			lseg.AllApply(r, f)
		}
		l >>= 1
		r >>= 1
	}
	l, r = l2, r2
	for i := 1; i <= lseg.log; i++ {
		if (l>>uint(i))<<uint(i) != l {
			lseg.Update(l >> uint(i))
		}
		if (r>>uint(i))<<uint(i) != r {
			lseg.Update((r - 1) >> uint(i))
		}
	}
}
func (lseg *LazySegtree) MaxRight(l int, cmp Compare) int {
	if l == lseg.n {
		return lseg.n
	}
	l += lseg.size
	for i := lseg.log; i >= 1; i-- {
		lseg.Push(l >> uint(i))
	}
	sm := lseg.e()
	for {
		for l%2 == 0 {
			l >>= 1
		}
		if !cmp(lseg.merger(sm, lseg.d[l])) {
			for l < lseg.size {
				lseg.Push(l)
				l = 2 * l
				if cmp(lseg.merger(sm, lseg.d[l])) {
					sm = lseg.merger(sm, lseg.d[l])
					l++
				}
			}
			return l - lseg.size
		}
		sm = lseg.merger(sm, lseg.d[l])
		l++
		if l&-l == l {
			break
		}
	}
	return lseg.n
}
func (lseg *LazySegtree) MinLeft(r int, cmp Compare) int {
	if r == 0 {
		return 0
	}
	r += lseg.size
	for i := lseg.log; i >= 1; i-- {
		lseg.Push(r - 1>>uint(i))
	}
	sm := lseg.e()
	for {
		r--
		for r > 1 && r%2 != 0 {
			r >>= 1
		}
		if !cmp(lseg.merger(lseg.d[r], sm)) {
			for r < lseg.size {
				lseg.Push(r)
				r = 2*r + 1
				if cmp(lseg.merger(lseg.d[r], sm)) {
					sm = lseg.merger(lseg.d[r], sm)
					r--
				}
			}
			return r + 1 - lseg.size
		}
		sm = lseg.merger(lseg.d[r], sm)
		if r&-r == r {
			break
		}
	}
	return 0
}
func (lseg *LazySegtree) ceilPow2(n int) int {
	x := 0
	for (1 << uint(x)) < n {
		x++
	}
	return x
}