Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in Go (1.6) (judge verdict: Wrong Answer)

package main

import (
	"fmt"
)

func main() {
	var n int
	var a int
	var b int
	var c int
	var d int
	var s string
	fmt.Scan(&n)
	fmt.Scan(&a)
	fmt.Scan(&b)
	fmt.Scan(&c)
	fmt.Scan(&d)
	fmt.Scan(&s)

	ret := "No"
	if c < d {
		sharpTwoFlg := false
		sharpCount := 0
		for i := a - 1; i < c; i++ {
			if s[i] == '#' {
				sharpCount++
				if sharpCount >= 2 {
					sharpTwoFlg = true
					break
				}
			}
		}

		sharpCount = 0
		for i := b - 1; i < d; i++ {
			if s[i] == '#' {
				sharpCount++
				if sharpCount >= 2 {
					sharpTwoFlg = true
					break
				}
			}
		}

		if !sharpTwoFlg {
			ret = "Yes"
		}

	} else {

		dotThreeFlg := false
		sharpTwoFlg := false

		dotCount := 0
		sharpCount := 0
		for i := b - 2; i < c; i++ {
			if s[i] == '.' {
				dotCount++
				if dotCount == 3 {
					if i >= d && i-1 != b {
						dotThreeFlg = true
					}
				}
				sharpCount = 0
			} else {
				sharpCount++
				if sharpCount >= 2 {
					sharpTwoFlg = true
					break
				}
				dotCount = 0
			}
		}

		if !sharpTwoFlg && dotThreeFlg {
			ret = "Yes"
		}
	}

	fmt.Println(ret)
}