Problem:
Score : 400 points

Problem Statement

Takahashi has a string S consisting of lowercase English letters.

Starting with this string, he will produce a new one in the procedure given as follows.

The procedure consists of Q operations. In Operation i (1 \leq i \leq Q), an integer T_i is provided, which means the following:

If T_i = 1: reverse the string S.

If T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.

If F_i = 1 : Add C_i to the beginning of the string S.

If F_i = 2 : Add C_i to the end of the string S.

Help Takahashi by finding the final string that results from the procedure.

Constraints

1 \leq |S| \leq 10^5

S consists of lowercase English letters.

1 \leq Q \leq 2 \times 10^5

T_i = 1 or 2.

F_i = 1 or 2, if provided.

C_i is a lowercase English letter, if provided.

Input

Input is given from Standard Input in the following format:

S
Q
Query_1
:
Query_Q

In the 3-rd through the (Q+2)-th lines, Query_i is one of the following:

1

which means T_i = 1, and:

2 F_i C_i

which means T_i = 2.

Output

Print the resulting string.

Sample Input 1

a
4
2 1 p
1
2 2 c
1

Sample Output 1

cpa

There will be Q = 4 operations. Initially, S is a.

Operation 1: Add p at the beginning of S. S becomes pa.

Operation 2: Reverse S. S becomes ap.

Operation 3: Add c at the end of S. S becomes apc.

Operation 4: Reverse S. S becomes cpa.

Thus, the resulting string is cpa.

Sample Input 2

a
6
2 2 a
2 1 b
1
2 2 c
1
1

Sample Output 2

aabc

There will be Q = 6 operations. Initially, S is a.

Operation 1: S becomes aa.

Operation 2: S becomes baa.

Operation 3: S becomes aab.

Operation 4: S becomes aabc.

Operation 5: S becomes cbaa.

Operation 6: S becomes aabc.

Thus, the resulting string is aabc.

Sample Input 3

y
1
2 1 x

Sample Output 3

xy

Solution in Go (1.14.1) (judge verdict: Time Limit Exceeded)

package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

func solve(sc *scanner, wr *bufio.Writer) {
	s := sc.getString()
	q := sc.getInt()

	rolling := false
	ans := s
	for i := 0; i < q; i++ {
		switch t := sc.getInt(); t {
		case 1:
			rolling = !rolling
		case 2:
			f := sc.getInt()
			c := sc.getString()
			if rolling {
				if f == 1 {
					ans = ans + c
				} else {
					ans = c + ans
				}
			} else {
				if f == 1 {
					ans = c + ans
				} else {
					ans = ans + c
				}
			}
		}
	}

	if rolling {
		tmp := ans
		ans = ""
		for _, c := range tmp {
			ans = string(c) + ans
		}
	}
	fmt.Fprintln(wr, ans)
}

func main() {
	sc := newScanner()
	wr := bufio.NewWriter(os.Stdout)
	maxBufSize := int(1e8)
	sc.Buffer(make([]byte, 4096), maxBufSize)
	sc.Split(bufio.ScanWords)

	solve(sc, wr)
	wr.Flush()
}

// input ------------------------
type scanner struct {
	*bufio.Scanner
}

func newScanner() *scanner {
	sc := bufio.NewScanner(os.Stdin)
	return &scanner{sc}
}
func (sc *scanner) getInt() int {
	sc.Scan()
	ret, err := strconv.Atoi(sc.Text())
	if err != nil {
		panic(err)
	}
	return ret
}
func (sc *scanner) getInt2() (int, int) {
	return sc.getInt(), sc.getInt()
}
func (sc *scanner) getInt3() (int, int, int) {
	return sc.getInt(), sc.getInt(), sc.getInt()
}
func (sc *scanner) getInt4() (int, int, int, int) {
	return sc.getInt(), sc.getInt(), sc.getInt(), sc.getInt()
}
func (sc *scanner) getInts(n int) []int {
	ret := make([]int, n)
	for i := range ret {
		ret[i] = sc.getInt()
	}
	return ret
}
func (sc *scanner) getString() string {
	sc.Scan()
	return sc.Text()
}
func (sc *scanner) getRunes() []rune {
	return []rune(sc.getString())
}
func (sc *scanner) getFloat() float64 {
	sc.Scan()
	ret, err := strconv.ParseFloat(sc.Text(), 64)
	if err != nil {
		panic(err)
	}
	return ret
}
func (sc *scanner) getFloats(n int) []float64 {
	ret := make([]float64, n)
	for i := range ret {
		ret[i] = sc.getFloat()
	}
	return ret
}

// math ----------------------------
func sum(ns ...int) int {
	var sum int
	for _, n := range ns {
		sum += n
	}
	return sum
}

func max(ns ...int) int {
	max := ns[0]
	for i := 1; i < len(ns); i++ {
		if max < ns[i] {
			max = ns[i]
		}
	}
	return max
}

func min(ns ...int) int {
	min := ns[0]
	for i := 1; i < len(ns); i++ {
		if min > ns[i] {
			min = ns[i]
		}
	}
	return min
}

func pow(a, b int) int {
	ret := 1
	for b > 0 {
		if b&1 > 0 {
			ret = ret * a
		}
		a = a * a
		b >>= 1
	}
	return ret
}