Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Go (1.6) (judge verdict: Wrong Answer)

package main

import (
	"fmt"
)

func main() {
	var n,counter int
	fmt.Scan(&n)
	for i := 0; i < n/2 + 1 ; i++ {
		ncounter := 0
		j := i*2 + 1

		if j % 3 == 0 {
			ncounter += 1
		}
		if j % 5 == 0 {
			ncounter += 1
		}
		if j % 7 == 0 {
			ncounter += 1
		}
		if j % 11 == 0 {
			ncounter += 1
		}
		if j % 13 == 0 {
			ncounter += 1
		}

		if ncounter == 3 {
			counter += 1
		}
	}
	println(counter)
}