Problem:
Score: 100 points

Problem Statement

M-kun is a competitor in AtCoder, whose highest rating is X.

In this site, a competitor is given a kyu (class) according to his/her highest rating. For ratings from 400 through 1999, the following kyus are given:

From 400 through 599: 8-kyu

From 600 through 799: 7-kyu

From 800 through 999: 6-kyu

From 1000 through 1199: 5-kyu

From 1200 through 1399: 4-kyu

From 1400 through 1599: 3-kyu

From 1600 through 1799: 2-kyu

From 1800 through 1999: 1-kyu

What kyu does M-kun have?

Constraints

400 \leq X \leq 1999

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print the kyu M-kun has, as an integer.
For example, if he has 8-kyu, print 8.

Sample Input 1

725

Sample Output 1

7

M-kun's highest rating is 725, which corresponds to 7-kyu.

Thus, 7 is the correct output.

Sample Input 2

1600

Sample Output 2

2

M-kun's highest rating is 1600, which corresponds to 2-kyu.

Thus, 2 is the correct output.

Solution in Go (1.14.1) (judge verdict: Accepted)

package main

import (
	"bufio"
	"os"
	"strconv"
	"fmt"
)

var sc = bufio.NewScanner(os.Stdin)

func init() {
	sc.Split(bufio.ScanWords)
	sc.Buffer(make([]byte, 1024*1024), bufio.MaxScanTokenSize)
}

//func nextString() string {
//	sc.Scan()
//	return sc.Text()
//}

func nextInt() int {
	sc.Scan()
	i, e := strconv.Atoi(sc.Text())
	if e != nil {
		panic(e)
	}
	return i
}

//func nextUint64() uint64 {
//	sc.Scan()
//	i, e := strconv.ParseUint(sc.Text(), 10, 64)
//	if e != nil {
//		panic(e)
//	}
//	return i
//}

func main() {
	x := nextInt()
	ans := 8

	if (x >= 400 && x <= 599) {
		ans = 8
	} else if (x >= 600 && x <= 799) {
		ans = 7
	} else if (x >= 800 && x <= 999) {
		ans = 6
	} else if (x >= 1000 && x <= 1199) {
		ans = 5
	} else if (x >= 1200 && x <= 1399) {
		ans = 4
	} else if (x >= 1400 && x <= 1599) {
		ans = 3
	} else if (x >= 1600 && x <= 1799) {
		ans = 2
	} else if (x >= 1800 && x <= 1999) {
		ans = 1
	} else {
		// do nothing
	}

	fmt.Println(ans)
}