Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in Go (1.6) (judge verdict: Wrong Answer)

package main

import (
	"fmt"
)

func main() {
  
	Bingo()

}

//Bingo 3*3
func Bingo() {
  
	bingo := make([][]int, 3)
	for x := range bingo {

		bingo[x] = make([]int, 3)
	}

	allkumi := make([][]int, 8)

	for x := range allkumi {
		allkumi[x] = make([]int, 3)
	}

	var N int

	for i := 0; i < 3; i++ {
		for j := 0; j < 3; j++ {
			fmt.Scan(&bingo[i][j])
		}
	}
	fmt.Scan(&N)

	numbers := make([]int, N)

	for n := 0; n < N; n++ {

		fmt.Scan(&numbers[n])
	}

	//横３つ
	for i := 0; i < 3; i++ {
		for j := 0; j < 3; j++ {

			allkumi[i][j] = bingo[i][j]
		}
	}

	//縦３つ
	for i := 0; i < 3; i++ {

		for j := 0; j < 3; j++ {

			allkumi[i+3][j] = bingo[j][i]

		}
	}

	//斜め二つ

	allkumi[6][0] = bingo[0][0]
	allkumi[6][1] = bingo[1][1]
	allkumi[6][2] = bingo[2][2]

	allkumi[7][0] = bingo[0][2]
	allkumi[7][1] = bingo[1][1]
	allkumi[7][2] = bingo[2][0]

	count := 0

	for i := 0; i < 8; i++ {
		for j := 0; j < 3; j++ {
			for n := 0; n < N; n++ {

				if allkumi[i][j] == numbers[n] {
			    	count++
				}
			}
		}

		if count == 3 {
			fmt.Println("Yes")
			return
		}
	}
	fmt.Println("No")
}