Problem:
Score : 300 points

Problem Statement

Iroha is very particular about numbers. There are K digits that she dislikes: D_1, D_2, ..., D_K.

She is shopping, and now paying at the cashier.
Her total is N yen (the currency of Japan), thus she has to hand at least N yen to the cashier (and possibly receive the change).

However, as mentioned before, she is very particular about numbers. When she hands money to the cashier, the decimal notation of the amount must not contain any digits that she dislikes. Under this condition, she will hand the minimum amount of money.

Find the amount of money that she will hand to the cashier.

Constraints

1 ≦ N < 10000

1 ≦ K < 10

0 ≦ D_1 < D_2 < … < D_K≦9

\{D_1,D_2,...,D_K\} ≠ \{1,2,3,4,5,6,7,8,9\}

Input

The input is given from Standard Input in the following format:

N K
D_1 D_2 … D_K

Output

Print the amount of money that Iroha will hand to the cashier.

Sample Input 1

1000 8
1 3 4 5 6 7 8 9

Sample Output 1

2000

She dislikes all digits except 0 and 2.

The smallest integer equal to or greater than N=1000 whose decimal notation contains only 0 and 2, is 2000.

Sample Input 2

9999 1
0

Sample Output 2

9999

Solution in Go (1.6) (judge verdict: Accepted)

package main

import (
	"fmt"
)

func main() {
	var n, k int
	var d int
	fmt.Scan(&n, &k)
	//嫌いな数字は最小0から最大9のためスライス宣言は10まで
	flag := make([]bool, 10)
	for i := 0; i < k; i++ {
		fmt.Scan(&d)
		//ここで無視された値は初期値のfalseのままとなる
		flag[d] = true
	}
	var price int
	//値が存在しているかどうか
	for {
		//払うお金を代入最低金額は商品金額(n)
		price = n
		flagMin := true
		for flagMin && price > 0 {
			//一桁目のスライスの値が嫌いな数字の場合
			if flag[price%10] {
				flagMin = false
			}
			//一桁目を切り詰める
			//priceはint型のため小数点を切り捨てられる
			//最後は0になる
			price /= 10
		}
		//全桁嫌いな数字出なかった場合
		if flagMin {
			fmt.Println(n)
			break
		}
		//誤まっていた場合の払う金額カウントアップ
		n++
	}
}