Problem:
Score : 300 points

Problem Statement

Takahashi is standing on a multiplication table with infinitely many rows and columns.

The square (i,j) contains the integer i \times j. Initially, Takahashi is standing at (1,1).

In one move, he can move from (i,j) to either (i+1,j) or (i,j+1).

Given an integer N, find the minimum number of moves needed to reach a square that contains N.

Constraints

2 \leq N \leq 10^{12}

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

Print the minimum number of moves needed to reach a square that contains the integer N.

Sample Input 1

10

Sample Output 1

5

(2,5) can be reached in five moves. We cannot reach a square that contains 10 in less than five moves.

Sample Input 2

50

Sample Output 2

13

(5, 10) can be reached in 13 moves.

Sample Input 3

10000000019

Sample Output 3

10000000018

Both input and output may be enormous.

Solution in Go (1.6) (judge verdict: Wrong Answer)

package main

import (
    "fmt"
    "os"
    "bufio"
    "sort"
    "math"
    "strconv"
)

var sc = bufio.NewScanner(os.Stdin)

func main() {

    sc.Split(bufio.ScanWords)
    n := nextInt()

    var min_val int = 10e12
    for i := 1; i*i < n; i++ {
        if n % i == 0 {
            j := n / i
            min_val = min(min_val, i+j-2)
        }
    }
    fmt.Println(min_val)

}



//==================================================
//
// Library
//
//==================================================

//===========================
//  round(12.54, 0) -> 13.0
//  round(12.54, -1) -> 12.5
//===========================

func round(num float64, digit uint) float64 {
    d := float64(digit)
    return float64(int(num * math.Pow(10, d) + 0.5)) / math.Pow(10, d)
}

func abs(n int) int {
    return int(math.Abs(float64(n)))
}

func max(a, b int) int {
    return int(math.Max(float64(a), float64(b)));
}

func min(a, b int) int {
    return int(math.Min(float64(a), float64(b)));
}

func gcd(x, y int) int {
    if y == 0 {
        return x
    }

    return gcd(y, x%y)
}

//===========================
//  var q Queue
//  q.Enqueue(n)
//  n := q.Dequeue()
//===========================
type Queue struct {
    data []int
}

func (q *Queue) Enqueue(n int) {
    q.data = append(q.data, n)
}

func (q *Queue) Dequeue() int {
    tmp := q.data[0]
    q.data = q.data[1:]
    return tmp
}

// 数値を桁区切りのスライスにする
func digit(n int, list []int) []int {
   if n > 0 {
       return digit(n/10, append(list, n%10))
   }
   return list
}

func sortIntsRev(list []int) {
    sort.Sort(sort.Reverse(sort.IntSlice(list)))
}

func strReverse(s string) string {
    runes := []rune(s)
    for i := 0; i < len(s)/2; i++ {
        runes[i], runes[len(s)-1-i] = runes[len(s)-1-i], runes[i]
    }
    return string(runes)
}

func nextInt() int {
    sc.Scan()
    i, _ := strconv.Atoi(sc.Text())
    return i
}

func nextStr() string {
    sc.Scan()
    return sc.Text()
}

func swap(a, b int) (int, int) {
    return b, a
}

func mySort(list []int, start int, end int) {
    var l []int
    for i := start; i < end; i++ {
        l = append(l, list[i])
    }
    sort.Ints(l)

    j := 0
    for i := start; i < end; i++ {
        list[i] = l[j]
        j++
    }
}

func mySortRev(list []int, start int, end int) {
    var l []int
    for i := start; i < end; i++ {
        l = append(l, list[i])
    }

    sortIntsRev(l)

    j := 0
    for i := start; i < end; i++ {
        list[i] = l[j]
        j++
    }
}

func nextPermutation(array []int) bool {
    n := len(array)

    for i:= n - 2; i >= 0; i-- {
        if array[i] < array[i+1] {
            j := n;
            for {
                j--;
                if (array[i] < array[j]) {
                    break
                }
            }
            array[i], array[j] = swap(array[i], array[j])
            mySort(array, i + 1, n)
            return true
        }
        if i == 0 {
            mySortRev(array, 0, n)
        }
    }
    return false
}