Problem:
Score : 200 points

Problem Statement

Let us define the FizzBuzz sequence a_1,a_2,... as follows:

If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.

If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.

If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.

If none of the above holds, a_i=i.

Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Constraints

1 \leq N \leq 10^6

Input

Input is given from Standard Input in the following format:

N

Output

Print the sum of all numbers among the first N terms of the FizzBuzz sequence.

Sample Input 1

15

Sample Output 1

60

The first 15 terms of the FizzBuzz sequence are:

1,2,\mbox{Fizz},4,\mbox{Buzz},\mbox{Fizz},7,8,\mbox{Fizz},\mbox{Buzz},11,\mbox{Fizz},13,14,\mbox{FizzBuzz}

Among them, numbers are 1,2,4,7,8,11,13,14, and the sum of them is 60.

Sample Input 2

1000000

Sample Output 2

266666333332

Watch out for overflow.

Solution in Go (1.14.1) (judge verdict: Accepted)

package main

import (
	"bufio"
	"fmt"
	"math"
	"os"
	"strconv"
)

func scanInt() int {
	sc.Scan()
	i, _ := strconv.Atoi(sc.Text())
	return i
}

func scanInt64() int64 {
	sc.Scan()
	i, _ := strconv.ParseInt(sc.Text(), 10, 64)
	return i
}

func scanInts(n int) []int {
	res := make([]int, n)
	for i := 0; i < n; i++ {
		res[i] = scanInt()
	}
	return res
}

func scanInts64(n int) []int64 {
	res := make([]int64, n)
	for i := range res {
		res[i] = scanInt64()
	}
	return res
}

func scanText() string {
	sc.Buffer([]byte{}, math.MaxInt64)
	sc.Scan()
	return sc.Text()
}

var sc = bufio.NewScanner(os.Stdin)

func main() {
	sc.Split(bufio.ScanWords)
	n := scanInt()
	ans := 0
	for i := 1; i <= n; i++ {
		if i % 3==0 || i %5 ==0 {
			continue
		}
		ans += i
	}
	fmt.Println(ans)
}