Problem:
Score : 200 points

Problem Statement

There are N positive integers written on a blackboard: A_1, ..., A_N.

Snuke can perform the following operation when all integers on the blackboard are even:

Replace each integer X on the blackboard by X divided by 2.

Find the maximum possible number of operations that Snuke can perform.

Constraints

1 \leq N \leq 200

1 \leq A_i \leq 10^9

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

Print the maximum possible number of operations that Snuke can perform.

Sample Input 1

3
8 12 40

Sample Output 1

2

Initially, [8, 12, 40] are written on the blackboard.
Since all those integers are even, Snuke can perform the operation.

After the operation is performed once, [4, 6, 20] are written on the blackboard.
Since all those integers are again even, he can perform the operation.

After the operation is performed twice, [2, 3, 10] are written on the blackboard.
Now, there is an odd number 3 on the blackboard, so he cannot perform the operation any more.

Thus, Snuke can perform the operation at most twice.

Sample Input 2

4
5 6 8 10

Sample Output 2

0

Since there is an odd number 5 on the blackboard already in the beginning, Snuke cannot perform the operation at all.

Sample Input 3

6
382253568 723152896 37802240 379425024 404894720 471526144

Sample Output 3

8

Solution in Go (1.6) (judge verdict: Accepted)

package main

import "fmt"

func main(){
	var N int
	var count int
	fmt.Scan(&N)

	A := make([]int, N)
	for i := 0 ; i < N ; i++{
		fmt.Scan(&A[i])
	}
	//fmt.Println(A)
	flag := 0
	for {
		for i := 0 ; i < N ; i++{
			if i == 0 {	
				if A[0] % 2 == 0 {
					A[0] /= 2
				}else if A[0] % 2 == 1{
					flag = 1
					break
				}
			}else{
				if A[i] % 2 == 0{
					A[i] /= 2
				}else if A[i] % 2 == 1{
					flag = 1
					break
				}
			}
		}
		if flag == 1 {
			break
		}
		count++

	//	fmt.Println(A)
	}
	fmt.Println(count)

}