Problem:
Score : 500 points

Problem Statement

We have N logs of lengths A_1,A_2,\cdots A_N.

We can cut these logs at most K times in total. When a log of length L is cut at a point whose distance from an end of the log is t (0<t<L), it becomes two logs of lengths t and L-t.

Find the shortest possible length of the longest log after at most K cuts, and print it after rounding up to an integer.

Constraints

1 \leq N \leq 2 \times 10^5

0 \leq K \leq 10^9

1 \leq A_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
A_1 A_2 \cdots A_N

Output

Print an integer representing the answer.

Sample Input 1

2 3
7 9

Sample Output 1

4

First, we will cut the log of length 7 at a point whose distance from an end of the log is 3.5, resulting in two logs of length 3.5 each.

Next, we will cut the log of length 9 at a point whose distance from an end of the log is 3, resulting in two logs of length 3 and 6.

Lastly, we will cut the log of length 6 at a point whose distance from an end of the log is 3.3, resulting in two logs of length 3.3 and 2.7.

In this case, the longest length of a log will be 3.5, which is the shortest possible result. After rounding up to an integer, the output should be 4.

Sample Input 2

3 0
3 4 5

Sample Output 2

5

Sample Input 3

10 10
158260522 877914575 602436426 24979445 861648772 623690081 433933447 476190629 262703497 211047202

Sample Output 3

292638192

Solution in Go (1.14.1) (judge verdict: Runtime Error)

package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

var sc *bufio.Scanner
var out *bufio.Writer

func main() {
	sc = bufio.NewScanner(os.Stdin)
	out = bufio.NewWriter(os.Stdout)
	buf := make([]byte, 1<<20)
	sc.Buffer(buf, bufio.MaxScanTokenSize)
	sc.Split(bufio.ScanWords)
	defer out.Flush()

	n, k := nextInt(), nextInt()
	a := nextInts(n)

	low, high := 0, int(1e9+1)
	middle := low + (high-low)/2
	divNum := 0
	for high >= low {
		for i := 0; i < n; i++ {
			if a[i]%middle == 0 {
				divNum += a[i]/middle - 1
			} else {
				divNum += a[i] / middle
			}
		}
		if divNum > k {
			low = middle + 1
		} else {
			high = middle - 1
		}
		middle = low + (high-low)/2
		divNum = 0
	}

	fmt.Fprintln(out, middle)
}

func next() string {
	sc.Scan()
	return sc.Text()
}
func nextInt() int {
	a, _ := strconv.Atoi(next())
	return a
}
func nextInts(n int) []int {
	ret := make([]int, n)
	for i := 0; i < n; i++ {
		ret[i] = nextInt()
	}
	return ret
}