Problem:
Score : 100 points

Problem Statement

You are given a 4-character string S consisting of uppercase English letters.
Determine if S consists of exactly two kinds of characters which both appear twice in S.

Constraints

The length of S is 4.

S consists of uppercase English letters.

Input

Input is given from Standard Input in the following format:

S

Output

If S consists of exactly two kinds of characters which both appear twice in S, print Yes; otherwise, print No.

Sample Input 1

ASSA

Sample Output 1

Yes

S consists of A and S which both appear twice in S.

Sample Input 2

STOP

Sample Output 2

No

Sample Input 3

FFEE

Sample Output 3

Yes

Sample Input 4

FREE

Sample Output 4

No

Solution in Go (1.6) (judge verdict: Wrong Answer)

package main

import (
	"bufio"
	"fmt"
	"os"
	"reflect"
	"strconv"
)

var sc = bufio.NewScanner(os.Stdin)
var out = bufio.NewWriter(os.Stdout)

const yes = "Yes"
const no = "No"

func solve(s string) bool {
	if s[0]  == s[1] && s[2] == s[3] {
		return true
	}
	if s[0]  == s[2] && s[1] == s[3] {
		return true
	}
	if s[0]  == s[3] && s[1] == s[2] {
		return true
	}
	return false
}

func main() {
	sc.Split(bufio.ScanWords)
	defer out.Flush()

	s := next()
	if solve(s) {
		fmt.Fprintln(out, yes)
	} else {
		fmt.Fprintln(out, no)
	}
}

func next() string {
	sc.Scan()
	return sc.Text()
}

func nextInt() int64 {
	a, _ := strconv.ParseInt(next(), 10, 64)
	return a
}

func nextFloat() float64 {
	a, _ := strconv.ParseFloat(next(), 64)
	return a
}

func nextInts(n int64) []int64 {
	ret := make([]int64, n)
	for i := int64(0); i < n; i++ {
		ret[i] = nextInt()
	}
	return ret
}
func nextFloats(n int64) []float64 {
	ret := make([]float64, n)
	for i := int64(0); i < n; i++ {
		ret[i] = nextFloat()
	}
	return ret
}
func nextStrings(n int64) []string {
	ret := make([]string, n)
	for i := int64(0); i < n; i++ {
		ret[i] = next()
	}
	return ret
}

func containStr(arr []string, target string) bool {
	for _, v := range arr {
		if v == target {
			return true
		}
	}
	return false
}

func PrintOut(src interface{}, joinner string) {
	switch reflect.TypeOf(src).Kind() {
	case reflect.Slice:
		s := reflect.ValueOf(src)
		for idx := 0; idx < s.Len(); idx++ {
			fmt.Fprintf(out, "%v", s.Index(idx))
			if idx < s.Len()-1 {
				fmt.Fprintf(out, "%s", joinner)
			} else {
				fmt.Fprintln(out)
			}
		}
	default:
		fmt.Fprintln(out, "orz")
	}
}

// mapからkeysとvaluesを返す
func splitKeyValue(m map[interface{}]interface{}) (keys, values []interface{}) {
	switch reflect.TypeOf(m).Kind() {
	case reflect.Map:
		s := reflect.ValueOf(m)
		for _, v := range s.MapKeys() {
			keys = append(keys, v)
			values = append(values, s.MapIndex(v))
		}
	default:
		fmt.Fprintln(out, "orz")
	}
	return
}