Problem:
Score : 200 points

Problem Statement

Takahashi went to an all-you-can-eat buffet with N kinds of dishes and ate all of them (Dish 1, Dish 2, \ldots, Dish N) once.

The i-th dish (1 \leq i \leq N) he ate was Dish A_i.

When he eats Dish i (1 \leq i \leq N), he gains B_i satisfaction points.

Additionally, when he eats Dish i+1 just after eating Dish i (1 \leq i \leq N - 1), he gains C_i more satisfaction points.

Find the sum of the satisfaction points he gained.

Constraints

All values in input are integers.

2 \leq N \leq 20

1 \leq A_i \leq N

A_1, A_2, ..., A_N are all different.

1 \leq B_i \leq 50

1 \leq C_i \leq 50

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N
B_1 B_2 ... B_N
C_1 C_2 ... C_{N-1}

Output

Print the sum of the satisfaction points Takahashi gained, as an integer.

Sample Input 1

3
3 1 2
2 5 4
3 6

Sample Output 1

14

Takahashi gained 14 satisfaction points in total, as follows:

First, he ate Dish 3 and gained 4 satisfaction points.

Next, he ate Dish 1 and gained 2 satisfaction points.

Lastly, he ate Dish 2 and gained 5 + 3 = 8 satisfaction points.

Sample Input 2

4
2 3 4 1
13 5 8 24
45 9 15

Sample Output 2

74

Sample Input 3

2
1 2
50 50
50

Sample Output 3

150

Solution in Go (1.6) (judge verdict: Accepted)

package main

import (
	"fmt"
)

// main is...
func main() {
	// IO start
	var n int
	fmt.Scan(&n)

	var listA = make([]int, n)
	var listB = make([]int, n)
	var listC = make([]int, n-1)
	for i := 0; i < n; i++ {
		fmt.Scan(&listA[i])
	}
	for i := 0; i < n; i++ {
		fmt.Scan(&listB[i])
	}
	for i := 0; i < n-1; i++ {
		fmt.Scan(&listC[i])
	}

	ret := 0
	// process start
	ret += listB[listA[0]-1]
	for i := 1; i < n; i++ {
		value := listA[i] - 1
		ret += listB[value]
		if previous := listA[i-1]; previous == value {
			ret += listC[value-1]
		}
	}
	fmt.Print(ret)
}