Problem:
Score : 400 points

Problem Statement

We have N bricks arranged in a row from left to right.

The i-th brick from the left (1 \leq i \leq N) has an integer a_i written on it.

Among them, you can break at most N-1 bricks of your choice.

Let us say there are K bricks remaining. Snuke will be satisfied if, for each integer i (1 \leq i \leq K), the i-th of those brick from the left has the integer i written on it.

Find the minimum number of bricks you need to break to satisfy Snuke's desire. If his desire is unsatisfiable, print -1 instead.

Constraints

All values in input are integers.

1 \leq N \leq 200000

1 \leq a_i \leq N

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 ... a_N

Output

Print the minimum number of bricks that need to be broken to satisfy Snuke's desire, or print -1 if his desire is unsatisfiable.

Sample Input 1

3
2 1 2

Sample Output 1

1

If we break the leftmost brick, the remaining bricks have integers 1 and 2 written on them from left to right, in which case Snuke will be satisfied.

Sample Input 2

3
2 2 2

Sample Output 2

-1

In this case, there is no way to break some of the bricks to satisfy Snuke's desire.

Sample Input 3

10
3 1 4 1 5 9 2 6 5 3

Sample Output 3

7

Sample Input 4

1
1

Sample Output 4

0

There may be no need to break the bricks at all.

Solution in Go (1.6) (judge verdict: Accepted)

package main

import (
        "bufio"
        "fmt"
        "os"
        "strconv"
        "strings"
)

var sc = bufio.NewScanner(os.Stdin)

func readInt() int              { return readIntArray()[0] }
func readInt2() (int, int)      { a := readIntArray(); return a[0], a[1] }
func readInt3() (int, int, int) { a := readIntArray(); return a[0], a[1], a[2] }
func readIntArray() []int {
        a := make([]int, 0, 1000)
        sc.Scan()
        for _, v := range strings.Split(sc.Text(), " ") {
                vv, _ := strconv.Atoi(v)
                a = append(a, vv)
        }
        return a
}
func readString() string        { return readStringArray()[0] }
func readStringArray() []string { sc.Scan(); return strings.Split(sc.Text(), " ") }

func main() {
        var n int
        fmt.Scan(&n)
        cnt := 1
        for i := 0; i < n; i++ {
                var a int
                fmt.Scan(&a)
                if a == cnt {
                        cnt++
                }
        }
        if cnt == 1 {
                fmt.Println(-1)
        } else {
                fmt.Println(n - cnt + 1)
        }
}