Problem:
Score : 200 points

Problem Statement

When Mr. X is away from home, he has decided to use his smartwatch to search the best route to go back home, to participate in ABC.

You, the smartwatch, has found N routes to his home.

If Mr. X uses the i-th of these routes, he will get home in time t_i at cost c_i.

Find the smallest cost of a route that takes not longer than time T.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq T \leq 1000

1 \leq c_i \leq 1000

1 \leq t_i \leq 1000

The pairs (c_i, t_i) are distinct.

Input

Input is given from Standard Input in the following format:

N T
c_1 t_1
c_2 t_2
:
c_N t_N

Output

Print the smallest cost of a route that takes not longer than time T.

If there is no route that takes not longer than time T, print TLE instead.

Sample Input 1

3 70
7 60
1 80
4 50

Sample Output 1

4

The first route gets him home at cost 7.

The second route takes longer than time T = 70.

The third route gets him home at cost 4.

Thus, the cost 4 of the third route is the minimum.

Sample Input 2

4 3
1 1000
2 4
3 1000
4 500

Sample Output 2

TLE

There is no route that takes not longer than time T = 3.

Sample Input 3

5 9
25 8
5 9
4 10
1000 1000
6 1

Sample Output 3

5

Solution in Go (1.6) (judge verdict: Accepted)

package main

import (
	"bufio"
	"fmt"
	"math"
	"os"
	_ "sort"
	"strconv"
	"strings"
)

var sc = bufio.NewScanner(os.Stdin)

func nextLine() string {
	sc.Scan()
	return sc.Text()
}

func convertToInt(s []string, len int) []int {
	ret := make([]int, len)
	for i := 0; i < len; i++ {
		ret[i], _ = strconv.Atoi(s[i])
	}
	return ret
}

var N int
var T int

func main() {
	cols := strings.Split(nextLine(), " ")
	N, _ = strconv.Atoi(cols[0])
	T, _ = strconv.Atoi(cols[1])
	min := math.MaxInt32

	for i := 0; i < N; i++ {
		cols := strings.Split(nextLine(), " ")
		c, _ := strconv.Atoi(cols[0])
		t, _ := strconv.Atoi(cols[1])
		if t > T {
			continue
		}
		if min > c {
			min = c
		}
	}

	if min == math.MaxInt32 {
		fmt.Println("TLE")
	} else {
		fmt.Println(min)
	}
}