Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Go (1.6) (judge verdict: Accepted)

package main

import (
	"fmt"
)

func divs(n int) []int {
	r := make([]int, 0)
	for i := 1; i*i <= n; i++ {
		if n%i == 0 {
			r = append(r, i)
			if i*i != n {
				r = append(r, n/i)
			}
		}
	}
	return r
}

func main() {
	var N, ans int
	fmt.Scan(&N)
	for i := 1; i <= N; i += 2 {
		d := 0
		for j := 1; j <= N; j += 2 {
			if i%j == 0 {
				d++
			}
		}
		if d == 8 {
			ans++
		}
	}
	fmt.Println(ans)
}