Problem:
Score : 200 points

Problem Statement

There are N positive integers written on a blackboard: A_1, ..., A_N.

Snuke can perform the following operation when all integers on the blackboard are even:

Replace each integer X on the blackboard by X divided by 2.

Find the maximum possible number of operations that Snuke can perform.

Constraints

1 \leq N \leq 200

1 \leq A_i \leq 10^9

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

Print the maximum possible number of operations that Snuke can perform.

Sample Input 1

3
8 12 40

Sample Output 1

2

Initially, [8, 12, 40] are written on the blackboard.
Since all those integers are even, Snuke can perform the operation.

After the operation is performed once, [4, 6, 20] are written on the blackboard.
Since all those integers are again even, he can perform the operation.

After the operation is performed twice, [2, 3, 10] are written on the blackboard.
Now, there is an odd number 3 on the blackboard, so he cannot perform the operation any more.

Thus, Snuke can perform the operation at most twice.

Sample Input 2

4
5 6 8 10

Sample Output 2

0

Since there is an odd number 5 on the blackboard already in the beginning, Snuke cannot perform the operation at all.

Sample Input 3

6
382253568 723152896 37802240 379425024 404894720 471526144

Sample Output 3

8

Solution in Go (1.6) (judge verdict: Accepted)

package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

func main() {
	var n int
	fmt.Scan(&n)
	scanner := bufio.NewScanner(os.Stdin)
	scanner.Split(bufio.ScanWords)
	a := make([]int, n)
	for i := 0; i < n; i++ {
		a[i], _ = scanInt(scanner)
	}

	count := 0
	for true {
		for i := 0; i < n; i++ {
			if a[i]%2 == 0 && a[i] != 0 {
				a[i] /= 2
			} else {
				fmt.Println(count)
				return
			}
		}
		count++
	}
}

func scanInt(s *bufio.Scanner) (int, error) {
	s.Scan()
	str := s.Text()
	return strconv.Atoi(str)
}