Problem:
Score : 200 points

Problem Statement

There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is R, and a blue hat if s_i is B.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

1 \leq N \leq 100

|s| = N

s_i is R or B.

Input

Input is given from Standard Input in the following format:

N
s

Output

If there are more people wearing a red hat than there are people wearing a blue hat, print Yes; otherwise, print No.

Sample Input 1

4
RRBR

Sample Output 1

Yes

There are three people wearing a red hat, and one person wearing a blue hat.

Since there are more people wearing a red hat than people wearing a blue hat, the answer is Yes.

Sample Input 2

4
BRBR

Sample Output 2

No

There are two people wearing a red hat, and two people wearing a blue hat.

Since there are as many people wearing a red hat as people wearing a blue hat, the answer is No.

Solution in Go (1.6) (judge verdict: Accepted)

package main

import (
    "fmt"
)

func main() {
    n := scanInt()
    s := scanString()
    red_count := 0
    blue_count := 0
    for i := 0; i < n; i++ {
        if s[i] == 'R' {
            red_count++
        } else {
            blue_count++
        }
    }
    if red_count > blue_count {
        fmt.Println("Yes")
    } else {
        fmt.Println("No")
    }
}

func scanInt() (num int) {
    fmt.Scan(&num)
    return
}

func scanInts(len int) (nums []int) {
    var num int
    for i := 0; i < len; i++ {
        fmt.Scan(&num)
        nums = append(nums, num)
    }
    return
}

func scanString() (str string) {
    fmt.Scan(&str)
    return
}

func scanStrings(len int) (strs []string) {
    var str string
    for i := 0; i < len; i++ {
        fmt.Scan(&str)
        strs = append(strs, str)
    }
    return
}