Problem:
Score : 200 points

Problem Statement

There are N students and M checkpoints on the xy-plane.

The coordinates of the i-th student (1 \leq i \leq N) is (a_i,b_i), and the coordinates of the checkpoint numbered j (1 \leq j \leq M) is (c_j,d_j).

When the teacher gives a signal, each student has to go to the nearest checkpoint measured in Manhattan distance.

The Manhattan distance between two points (x_1,y_1) and (x_2,y_2) is |x_1-x_2|+|y_1-y_2|.

Here, |x| denotes the absolute value of x.

If there are multiple nearest checkpoints for a student, he/she will select the checkpoint with the smallest index.

Which checkpoint will each student go to?

Constraints

1 \leq N,M \leq 50

-10^8 \leq a_i,b_i,c_j,d_j \leq 10^8

All input values are integers.

Input

The input is given from Standard Input in the following format:

N M
a_1 b_1
:
a_N b_N
c_1 d_1
:
c_M d_M

Output

Print N lines.

The i-th line (1 \leq i \leq N) should contain the index of the checkpoint for the i-th student to go.

Sample Input 1

2 2
2 0
0 0
-1 0
1 0

Sample Output 1

2
1

The Manhattan distance between the first student and each checkpoint is:

For checkpoint 1: |2-(-1)|+|0-0|=3

For checkpoint 2: |2-1|+|0-0|=1

The nearest checkpoint is checkpoint 2. Thus, the first line in the output should contain 2.

The Manhattan distance between the second student and each checkpoint is:

For checkpoint 1: |0-(-1)|+|0-0|=1

For checkpoint 2: |0-1|+|0-0|=1

When there are multiple nearest checkpoints, the student will go to the checkpoint with the smallest index. Thus, the second line in the output should contain 1.

Sample Input 2

3 4
10 10
-10 -10
3 3
1 2
2 3
3 5
3 5

Sample Output 2

3
1
2

There can be multiple checkpoints at the same coordinates.

Sample Input 3

5 5
-100000000 -100000000
-100000000 100000000
100000000 -100000000
100000000 100000000
0 0
0 0
100000000 100000000
100000000 -100000000
-100000000 100000000
-100000000 -100000000

Sample Output 3

5
4
3
2
1

Solution in Go (1.6) (judge verdict: Accepted)

package main
 
import(
  "fmt"
	"bufio"
	"os"
	"strings"
	"math"
)
 
var sc = bufio.NewScanner(os.Stdin)
 
func Rr() []string {
  sc.Scan()
  slice := strings.Split(sc.Text(), " ")
  return slice
}
 
func abc057b(N int, M int){
	human_list := [][]int{}
	var a int
	var b int
	for i := 0; i < N; i++{
		fmt.Scan(&a)
		fmt.Scan(&b)
		ap := []int{a,b}
		human_list = append(human_list,ap)
	}
	point_list := [][]int{}
	for i := 0; i < M; i++{
		fmt.Scan(&a)
		fmt.Scan(&b)
		ap := []int{a,b}
		point_list = append(point_list,ap)
	}
	for j := 1; j <= N; j++{
		min := 1000000000.0
		ans := 1000000000.0
		for i := 1; i <= M; i++{
			x := math.Abs(float64(human_list[j-1][0]-point_list[i-1][0]))
			y := math.Abs(float64(human_list[j-1][1]-point_list[i-1][1]))
			current := x + y
			if current < min{
				ans = float64(i)
				min = current
			}
		}
		fmt.Println(ans)
	}
}
func main(){
	n,m := 0,0
	fmt.Scan(&n)
	fmt.Scan(&m)
	abc057b(n,m)
}