Problem:
Score : 200 points

Problem Statement

Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Constraints

1 \leq N \leq 10^5

Input

Input is given from Standard Input in the following format:

N

Output

Print the number of positive integers less than or equal to N that have an odd number of digits.

Sample Input 1

11

Sample Output 1

9

Among the positive integers less than or equal to 11, nine integers have an odd number of digits: 1, 2, \ldots, 9.

Sample Input 2

136

Sample Output 2

46

In addition to 1, 2, \ldots, 9, another 37 integers also have an odd number of digits: 100, 101, \ldots, 136.

Sample Input 3

100000

Sample Output 3

90909

Solution in Go (1.6) (judge verdict: Wrong Answer)

package main

import (
	"fmt"
	"strconv"
)

func main() {
	var N int
	fmt.Scan(&N)

	s := strconv.Itoa(N)

	l := len(s)

	if l == 1 {
		println(N)
		return
	}

	if l == 2{
		println(9)
		return
	}

	if l == 3 {
		println(9 + N - 99)
		return
	}

	if l == 4 {
		println(9 + 900)
		return
	}

	if l == 5 {
		println(9 + 900 + N - 9999)
		return
	}

	if l == 6 {
		println(9 + 900 + 90000)
		return
	}

	if l == 7 {
		println(9 + 900 + 90000 + N - 999999)
		return
	}
}