Problem:
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Maximum Heap

A binary heap which satisfies max-heap property is called max-heap. In a max-heap, for every node $i$ other than the root, $A[i] \leq A[parent(i)]$, that is, the value of a node is at most the value of its parent. The largest element in a max-heap is stored at the root, and the subtree rooted at a node contains values no larger than that contained at the node itself.

Here is an example of a max-heap.

Write a program which reads an array and constructs a max-heap from the array based on the following pseudo code.

$maxHeapify(A, i)$ move the value of $A[i]$ down to leaves to make a sub-tree of node $i$ a max-heap. Here, $H$ is the size of the heap.

1 maxHeapify(A, i)
2 l = left(i)
3 r = right(i)
4 // select the node which has the maximum value
5 if l ≤ H and A[l] > A[i]
6 largest = l
7 else
8 largest = i
9 if r ≤ H and A[r] > A[largest]
10 largest = r
11
12 if largest ≠ i　// value of children is larger than that of i
13 swap A[i] and A[largest]
14 maxHeapify(A, largest) // call recursively

The following procedure buildMaxHeap(A) makes $A$ a max-heap by performing maxHeapify in a bottom-up manner.

1 buildMaxHeap(A)
2 for i = H/2 downto 1
3 maxHeapify(A, i)

Input

In the first line, an integer $H$ is given. In the second line, $H$ integers which represent elements in the binary heap are given in order of node id (from $1$ to $H$).

Output

Print values of nodes in the max-heap in order of their id (from $1$ to $H$). Print a single space character before each value.

Constraint

$1 \leq H \leq 500,000$

$-2,000,000,000 \leq$ value of a node $\leq 2,000,000,000$

Sample Input 1

10
4 1 3 2 16 9 10 14 8 7

Sample Output 1

16 14 10 8 7 9 3 2 4 1

Reference

Introduction to Algorithms, Thomas H. Cormen, Charles E. Leiserson, Ronald L. Rivest, and Clifford Stein. The MIT Press.

Solution in Go (judge verdict: Accepted)

package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

var stdin = bufio.NewScanner(os.Stdin)
var H int

func nextInt() int {
	stdin.Scan()
	i, _ := strconv.Atoi(stdin.Text())
	return i
}

func maxHeapify(A []int, i int) {
	left := 2 * i
	right := 2*i + 1
	if left > H {
		return
	}
	var largest int
	if left <= H && A[left] > A[i] {
		largest = left
	} else {
		largest = i
	}
	if right <= H && A[right] > A[largest] {
		largest = right
	}

	if largest != i {
		A[i], A[largest] = A[largest], A[i]
		maxHeapify(A, largest)
	}
}

func buildMaxHeap(A []int) {
	for i := H / 2; i > 0; i-- {
		maxHeapify(A, i)
	}
}

func main() {
	stdin.Split(bufio.ScanWords)
	H = nextInt()
	heap := make([]int, H+1)

	for i := 1; i <= H; i++ {
		heap[i] = nextInt()
	}

	buildMaxHeap(heap)
	for i := 1; i <= H; i++ {
		fmt.Printf(" %d", heap[i])
	}
	fmt.Println()
}