Problem:
Score : 300 points

Problem Statement

You are given three integers A, B and C. Find the minimum number of operations required to make A, B and C all equal by repeatedly performing the following two kinds of operations in any order:

Choose two among A, B and C, then increase both by 1.

Choose one among A, B and C, then increase it by 2.

It can be proved that we can always make A, B and C all equal by repeatedly performing these operations.

Constraints

0 \leq A,B,C \leq 50

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B C

Output

Print the minimum number of operations required to make A, B and C all equal.

Sample Input 1

2 5 4

Sample Output 1

2

We can make A, B and C all equal by the following operations:

Increase A and C by 1. Now, A, B, C are 3, 5, 5, respectively.

Increase A by 2. Now, A, B, C are 5, 5, 5, respectively.

Sample Input 2

2 6 3

Sample Output 2

5

Sample Input 3

31 41 5

Sample Output 3

23

Solution in Go (1.14.1) (judge verdict: Accepted)

// なんでこれがダメなの？？？？？？？？？？？？？？？？？？？？？？？？？？？？？？？？？？？？？ 
// 3 4 5
package main
import (
	"fmt"
	"sort"
)
func main(){
	A := make([]int, 3)
	for i:=0; i<3; i++{
		fmt.Scan(&A[i])
	}
	sort.Ints(A)
	minimum,maximum := A[0], A[2]
	if minimum == maximum{
		fmt.Println(0)
		return
	}
	ans := 0
	if (maximum-minimum)%2 == 0{
		ans += (maximum - minimum)/2
	}else{
		A[1]++
		ans += (maximum - minimum)/2 + 1
	}
	A[0] = A[2]
	sort.Ints(A)
	if (A[2]-A[0])%2==0{
		ans += (A[2]-A[0])/2
	}else{
		if A[0] == A[1]{
			ans += (A[2]-A[1])/2+1
		}else if A[1] == A[2]{
			ans += (A[2]-A[0])/2+2
		}else{
			panic("あわわわわ")
		}
	}
	fmt.Println(ans)
}