Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in Go (1.6) (judge verdict: Accepted)

package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

func out(x ...interface{}) {
	fmt.Println(x...)
}

var sc = bufio.NewScanner(os.Stdin)

func getInt() int {
	sc.Scan()
	i, e := strconv.Atoi(sc.Text())
	if e != nil {
		panic(e)
	}
	return i
}

func getString() string {
	sc.Scan()
	return sc.Text()
}

func main() {
	sc.Split(bufio.ScanWords)

	var a [3][3]int
	var c [3][3]int

	for i := 0; i < 3; i++ {
		for j := 0; j < 3; j++ {
			a[i][j] = getInt()
		}
	}

	N := getInt()
	for k := 0; k < N; k++ {
		b := getInt()
		for i := 0; i < 3; i++ {
			for j := 0; j < 3; j++ {
				if a[i][j] == b {
					c[i][j] = 1
				}
			}
		}
	}

	ans := "No"
	for i := 0; i < 3; i++ {
		if c[0][i]+c[1][i]+c[2][i] == 3 {
			ans = "Yes"
		}
	}
	for i := 0; i < 3; i++ {
		if c[i][0]+c[i][1]+c[i][2] == 3 {
			ans = "Yes"
		}
	}
	if c[0][0]+c[1][1]+c[2][2] == 3 {
		ans = "Yes"
	}
	if c[0][2]+c[1][1]+c[2][0] == 3 {
		ans = "Yes"
	}
	out(ans)
}