Problem:
Score : 700 points

Problem Statement

We have a rooted binary tree with N vertices, where the vertices are numbered 1 to N.
Vertex 1 is the root, and the parent of Vertex i (i \geq 2) is Vertex \left[ \frac{i}{2} \right].

Each vertex has one item in it. The item in Vertex i has a value of V_i and a weight of W_i.
Now, process the following query Q times:

Given are a vertex v of the tree and a positive integer L.
Let us choose some (possibly none) of the items in v and the ancestors of v so that their total weight is at most L.
Find the maximum possible total value of the chosen items.

Here, Vertex u is said to be an ancestor of Vertex v when u is an indirect parent of v, that is, there exists a sequence of vertices w_1,w_2,\ldots,w_k (k\geq 2) where w_1=v, w_k=u, and w_{i+1} is the parent of w_i for each i.

Constraints

All values in input are integers.

1 \leq N < 2^{18}

1 \leq Q \leq 10^5

1 \leq V_i \leq 10^5

1 \leq W_i \leq 10^5

For the values v and L given in each query, 1 \leq v \leq N and 1 \leq L \leq 10^5.

Input

Let v_i and L_i be the values v and L given in the i-th query.
Then, Input is given from Standard Input in the following format:

N
V_1 W_1
:
V_N W_N
Q
v_1 L_1
:
v_Q L_Q

Output

For each integer i from 1 through Q,
the i-th line should contain the response to the i-th query.

Sample Input 1

3
1 2
2 3
3 4
3
1 1
2 5
3 5

Sample Output 1

0
3
3

In the first query, we are given only one choice: the item with (V, W)=(1,2). Since L = 1, we cannot actually choose it, so our response should be 0.

In the second query, we are given two choices: the items with (V, W)=(1,2) and (V, W)=(2,3). Since L = 5, we can choose both of them, so our response should be 3.

Sample Input 2

15
123 119
129 120
132 112
126 109
118 103
115 109
102 100
130 120
105 105
132 115
104 102
107 107
127 116
121 104
121 115
8
8 234
9 244
10 226
11 227
12 240
13 237
14 206
15 227

Sample Output 2

256
255
250
247
255
259
223
253

Solution in Go (1.14.1) (judge verdict: Wrong Answer)

package main
import (
  "bufio"
  "os"
  "strconv"
  "strings"
  "fmt"
)

func Solve() {
  var N, Q, v, w, cnt, ans, p, n, k, K int
  NextInt(&N)
  V := make([]int, N + 1)
  W := make([]int, N + 1)
  for i := range V[1:] {
    NextInt(&V[i + 1], &W[i + 1])
  }
  NextInt(&Q)
  S := make([]int, Q)
  L := make([]int, Q)
  for i := range S {
    NextInt(&S[i], &L[i])
  }
  h := 0
  for n = 1; n < N; n *= 2 { h++ }
  U := 1 << uint(Ceil(h, 2))
  DP := make([][]int, U)
  l := MaxInt(L...) + 1
  for i := range DP { DP[i] = make([]int, l) }
  for i := range DP[1:] {
    v = i + 1
    for j, dp := range DP[v/2] {
      DP[v][j] = MaxInt(dp, DP[v][j])
      if W[v] + j >= l { continue }
      DP[v][W[v] + j] = MaxInt(dp + V[v], DP[v][W[v] + j])
    }
  }
  return
  P := make([]int, h)
  for i, s := range S {
    k, v = 0, s
    for ; v >= U; v /= 2 {
      P[k] = v
      k++
    }
    K = 1 << uint(k)
    ans = DP[v][L[i]]
    for j := 1; j < K; j++ {
      w, cnt, p = 0, 0, 0
      for n = j; n > 0; n /= 2 {
        if n % 2 == 1 { w, cnt = w + W[P[p]], cnt + V[P[p]] }
        p++
      }
      if w > L[i] { continue }
      ans = MaxInt(cnt + DP[v][L[i] - w], ans)
    }
    Write(ans)
  }
}

func main() {
  Solve()
  Output()
}

var reader = bufio.NewReaderSize(os.Stdin, 1000000)
var writer = bufio.NewWriter(os.Stdout)
func NextLine() string {
  buffer := make([]byte, 0)
  for true {
    line, isPrefix, err := reader.ReadLine()
    if err != nil { panic(err) }
    buffer = append(buffer, line...)
    if !isPrefix { break }
  }
  return string(buffer)
}
func NextInt(A ...*int) {
  L := strings.Split(NextLine(), " ")
  for i, a := range A {
    *a, _ = strconv.Atoi(L[i])
  }
}
func NextIntVec(A *[]int) {
  L := strings.Split(NextLine(), " ")
  (*A) = make([]int, len(L))
  for i, l := range L {
    (*A)[i], _ = strconv.Atoi(l)
  }
}
func NextFloat(A ...*float64) {
  L := strings.Split(NextLine(), " ")
  for i, a := range A {
    *a, _ = strconv.ParseFloat(L[i], 64)
  }
}
func NextFloatVec(A *[]float64) {
  L := strings.Split(NextLine(), " ")
  (*A) = make([]float64, len(L))
  for i, l := range L {
    (*A)[i], _ = strconv.ParseFloat(l, 64)
  }
}
func Write(s interface{}) {
  fmt.Fprintln(writer, s)
}
func WriteIntVec(A []int) {
  S := make([]string, len(A))
  for i, a := range A {
    S[i] = strconv.Itoa(a)
  }
  Write(strings.Join(S, " "))
}
func Output() {
  _ = writer.Flush()
}
func MaxInt(A ...int) int {
  max := A[0]
  for _, a := range A {
    if max < a { max = a }
  }
  return max
}
func MinInt(A ...int) int {
  min := A[0]
  for _, a := range A {
    if a < min { min = a }
  }
  return min
}
func SumInt(A ...int) int {
  sum := 0
  for _, a := range A {
    sum += a
  }
  return sum
}
func AbsInt(x int) int {
  if x < 0 { x = -x }
  return x
}
func Ceil(x, y int) int {
  a := x / y
  if x % y > 0 { a++ }
  return a
}