Problem:
Score : 400 points

Problem Statement

Takahashi has a string S consisting of lowercase English letters.

Starting with this string, he will produce a new one in the procedure given as follows.

The procedure consists of Q operations. In Operation i (1 \leq i \leq Q), an integer T_i is provided, which means the following:

If T_i = 1: reverse the string S.

If T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.

If F_i = 1 : Add C_i to the beginning of the string S.

If F_i = 2 : Add C_i to the end of the string S.

Help Takahashi by finding the final string that results from the procedure.

Constraints

1 \leq |S| \leq 10^5

S consists of lowercase English letters.

1 \leq Q \leq 2 \times 10^5

T_i = 1 or 2.

F_i = 1 or 2, if provided.

C_i is a lowercase English letter, if provided.

Input

Input is given from Standard Input in the following format:

S
Q
Query_1
:
Query_Q

In the 3-rd through the (Q+2)-th lines, Query_i is one of the following:

1

which means T_i = 1, and:

2 F_i C_i

which means T_i = 2.

Output

Print the resulting string.

Sample Input 1

a
4
2 1 p
1
2 2 c
1

Sample Output 1

cpa

There will be Q = 4 operations. Initially, S is a.

Operation 1: Add p at the beginning of S. S becomes pa.

Operation 2: Reverse S. S becomes ap.

Operation 3: Add c at the end of S. S becomes apc.

Operation 4: Reverse S. S becomes cpa.

Thus, the resulting string is cpa.

Sample Input 2

a
6
2 2 a
2 1 b
1
2 2 c
1
1

Sample Output 2

aabc

There will be Q = 6 operations. Initially, S is a.

Operation 1: S becomes aa.

Operation 2: S becomes baa.

Operation 3: S becomes aab.

Operation 4: S becomes aabc.

Operation 5: S becomes cbaa.

Operation 6: S becomes aabc.

Thus, the resulting string is aabc.

Sample Input 3

y
1
2 1 x

Sample Output 3

xy

Solution in Go (1.6) (judge verdict: Time Limit Exceeded)

package main

import (
	"fmt"
	"io"
	"os"
	"runtime"
)

type query struct {
	T int
	F int
	C byte
}

func calc(qq []query, bytes []byte) ([]byte, bool) {
	head := true
	for _, que := range qq {
		if que.T == 1 {
			head = !head
		} else {
			if (head && que.F == 1) || (!head && que.F == 2) {
				bytes = append([]byte{que.C}, bytes...)
			} else {
				bytes = append(bytes, que.C)
			}
		}
	}
	return bytes, head
}

func run(input io.Reader, output io.Writer) int {
	var s string
	fmt.Scanf("%s\n", &s)
	var q int
	fmt.Scanf("%d\n", &q)
	var qq []query
	for i := 0; i < q; i++ {
		var t int
		var f int
		var c byte
		fmt.Scanf("%d", &t)
		if t == 1 {
			if runtime.GOOS == "windows" {
				fmt.Scanf("\n")
			}
		} else {
			fmt.Scanf("%d %c\n", &f, &c)
		}
		qq = append(qq, query{T: t, F: f, C: c})
	}

	bytes := []byte(s)
	bytes, head := calc(qq, bytes)

	if head {
		fmt.Println(string(bytes))
	} else {
		for i := len(bytes) - 1; i >= 0; i-- {
			fmt.Printf("%c", bytes[i])
		}
		fmt.Println()
	}
	return 0
}

func main() {
	os.Exit(run(os.Stdin, os.Stdout))
}