Problem:
Score : 200 points

Problem Statement

Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print -1 instead.

Constraints

2 \leq N \leq 10^5

0 \leq A_i \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the value A_1 \times ... \times A_N as an integer, or -1 if the value exceeds 10^{18}.

Sample Input 1

2
1000000000 1000000000

Sample Output 1

1000000000000000000

We have 1000000000 \times 1000000000 = 1000000000000000000.

Sample Input 2

3
101 9901 999999000001

Sample Output 2

-1

We have 101 \times 9901 \times 999999000001 = 1000000000000000001, which exceeds 10^{18}, so we should print -1 instead.

Sample Input 3

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0

Sample Output 3

0

Solution in Go (1.14.1) (judge verdict: Wrong Answer)

package main

import (
	"fmt"
	"math"
	"math/big"
	"strconv"
)

func main() {
	var n int
	fmt.Scan(&n)

	sum := big.NewInt(1)
	var fuck string
	for i:=0; i<n; i++ {
		var a int64
		fmt.Scan(&a)
		if a == 0 {
			fmt.Println(0)
			return
		}
		b := big.NewInt(a)
		sum = new(big.Int).Mul(sum, b)
		fuck=sum.String()
		q := new(big.Int).Sub(sum, big.NewInt(int64(math.Pow10(18)))).String()
		w, _ := strconv.Atoi(q)
		if w > 0 {
			fmt.Println(-1)
			return
		}
		t, _ := strconv.Atoi(fuck)
		sum = big.NewInt(int64(t))
	}
	c := new(big.Int).Sub(sum, big.NewInt(int64(math.Pow10(18)))).String()
	d, _ := strconv.Atoi(c)
	if d > 0 {
		fmt.Println(-1)
	} else {
		fmt.Println(fuck)
	}
}