Problem:
Score : 200 points

Problem Statement

Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print -1 instead.

Constraints

2 \leq N \leq 10^5

0 \leq A_i \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the value A_1 \times ... \times A_N as an integer, or -1 if the value exceeds 10^{18}.

Sample Input 1

2
1000000000 1000000000

Sample Output 1

1000000000000000000

We have 1000000000 \times 1000000000 = 1000000000000000000.

Sample Input 2

3
101 9901 999999000001

Sample Output 2

-1

We have 101 \times 9901 \times 999999000001 = 1000000000000000001, which exceeds 10^{18}, so we should print -1 instead.

Sample Input 3

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0

Sample Output 3

0

Solution in Go (1.14.1) (judge verdict: Wrong Answer)

package main

import (
	"bufio"
	"fmt"
	"math"
	"os"
	"strconv"
	"strings"
)

func main() {
	var n int
	fmt.Scan(&n)
	stdin := bufio.NewScanner(os.Stdin)
	stdin.Scan()
	s := stdin.Text()

	is := strings.Split(s, " ")
	inputs := stringsToInts(is)

	for _, v := range inputs {
		if v == 0 {
			fmt.Println(0)
			return
		}
	}

	for _, v := range inputs {
		if v >= int64(math.Pow(10, 18)) {
			fmt.Println(-1)
			return
		}
	}

	var ans int64 = 1
	for _, v := range inputs {
		if ans*v >= int64(math.Pow(10, 18)) {
			fmt.Println(-1)
			return
		}
		ans *= v
	}
	fmt.Println(ans)
}

func stringsToInts(s []string) []int64 {
	arr := make([]int64, len(s))
	for i, v := range s {
		arr[i], _ = strconv.ParseInt(v, 10, 64)
	}
	return arr
}