Problem:
Score : 300 points

Problem Statement

The commonly used bills in Japan are 10000-yen, 5000-yen and 1000-yen bills. Below, the word "bill" refers to only these.

According to Aohashi, he received an otoshidama (New Year money gift) envelope from his grandfather that contained N bills for a total of Y yen, but he may be lying. Determine whether such a situation is possible, and if it is, find a possible set of bills contained in the envelope. Assume that his grandfather is rich enough, and the envelope was large enough.

Constraints

1 ≤ N ≤ 2000

1000 ≤ Y ≤ 2 × 10^7

N is an integer.

Y is a multiple of 1000.

Input

Input is given from Standard Input in the following format:

N Y

Output

If the total value of N bills cannot be Y yen, print -1 -1 -1.

If the total value of N bills can be Y yen, let one such set of bills be "x 10000-yen bills, y 5000-yen bills and z 1000-yen bills", and print x, y, z with spaces in between. If there are multiple possibilities, any of them may be printed.

Sample Input 1

9 45000

Sample Output 1

4 0 5

If the envelope contained 4 10000-yen bills and 5 1000-yen bills, he had 9 bills and 45000 yen in total. It is also possible that the envelope contained 9 5000-yen bills, so the output 0 9 0 is also correct.

Sample Input 2

20 196000

Sample Output 2

-1 -1 -1

When the envelope contained 20 bills in total, the total value would be 200000 yen if all the bills were 10000-yen bills, and would be at most 195000 yen otherwise, so it would never be 196000 yen.

Sample Input 3

1000 1234000

Sample Output 3

14 27 959

There are also many other possibilities.

Sample Input 4

2000 20000000

Sample Output 4

2000 0 0

Solution in Go (1.6) (judge verdict: Accepted)

package main

import (
	"bufio"
	"fmt"
	"io"
	"os"
	"strconv"
)

var sc *bufio.Scanner

func nextInt() int {
	sc.Scan()
	i, e := strconv.Atoi(sc.Text())
	if e != nil {
		panic(e)
	}
	return i
}
func answer(reader io.Reader, writer io.Writer) {
	sc = bufio.NewScanner(reader)
	sc.Split(bufio.ScanWords)
	a := nextInt()
	b := nextInt()
	x := -1
	y := -1
	z := -1
	c := b - a*1000
	for i := 0; i <= a && c-i*9000 >= 0; i++ {
		t := float64(c - i*9000)
		if (t/4000) == float64(int(t/4000)) && a-i-int(t/4000) >= 0 {
			x = i
			y = int(t / 4000)
			z = a - x - y
			break
		}
	}
	/*
		    x+y+z = a
			x*10000 + y*5000 + z*1000 = b
		    z = a - x - y
		    x*10000 + y*5000 + (a-x-y)*1000 = b
		    x*9000 + y*4000 = b - a*1000
		    y = (b-a*1000-x*9000)/4000
	*/

	fmt.Fprintf(writer, "%d %d %d", x, y, z)
}

func main() {
	answer(os.Stdin, os.Stdout)
}