Problem:
Score : 200 points

Problem Statement

Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print -1 instead.

Constraints

2 \leq N \leq 10^5

0 \leq A_i \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the value A_1 \times ... \times A_N as an integer, or -1 if the value exceeds 10^{18}.

Sample Input 1

2
1000000000 1000000000

Sample Output 1

1000000000000000000

We have 1000000000 \times 1000000000 = 1000000000000000000.

Sample Input 2

3
101 9901 999999000001

Sample Output 2

-1

We have 101 \times 9901 \times 999999000001 = 1000000000000000001, which exceeds 10^{18}, so we should print -1 instead.

Sample Input 3

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0

Sample Output 3

0

Solution in Go (1.14.1) (judge verdict: Wrong Answer)

package main

import (
	"bufio"
	"fmt"
	// "math"
	"os"
	"strconv"
)

var sc = bufio.NewScanner(os.Stdin)

// 1行読み込み
func nextLine() string {
	sc.Scan()
	return sc.Text()
}

// 読み込みをint型へキャスト
func nextInt() int {
	sc.Scan()
	num, err := strconv.Atoi(sc.Text())
	if err != nil {
		panic(err)
	}
	return num
}

func nextFloat() float64 {
	sc.Scan()
	num, err := strconv.ParseFloat(sc.Text(), 64)
	if err != nil {
		panic(err)
	}
	return num
}

const max = 1000000000000000000
func main() {
	// scannerの挙動を改行区切り → 空白区切りに変更
	sc.Split(bufio.ScanWords)
	n := nextInt()
	num := 1
	for i := 0; i < n; i++ {
		num *= nextInt()
		if num > max {
			break
		}
	}
	if num <= max {
		fmt.Println(num)
	} else {
		fmt.Println(-1)
	}
}