Problem:
Score : 200 points

Problem Statement

Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print -1 instead.

Constraints

2 \leq N \leq 10^5

0 \leq A_i \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the value A_1 \times ... \times A_N as an integer, or -1 if the value exceeds 10^{18}.

Sample Input 1

2
1000000000 1000000000

Sample Output 1

1000000000000000000

We have 1000000000 \times 1000000000 = 1000000000000000000.

Sample Input 2

3
101 9901 999999000001

Sample Output 2

-1

We have 101 \times 9901 \times 999999000001 = 1000000000000000001, which exceeds 10^{18}, so we should print -1 instead.

Sample Input 3

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0

Sample Output 3

0

Solution in Go (1.14.1) (judge verdict: Wrong Answer)

package main

import (
	"fmt"
)

func main() {
	var n int
	fmt.Scanf("%d", &n)

	nums := make([]int, n)
	for i := 0; i < n; i++ {
		fmt.Scanf("%d", &nums[i])
	}

	total := 1
	for i := 0; i < n; i++ {
		if nums[i] == 0 {
			total = 0
			break
		}
	}

	if total == 0 {
		fmt.Println(total)
	} else {
		for i := 0; i < n; i++ {
			total = total * nums[i]
			if nums[i] > 1000000000000000000/total {
				total = -1
				break
			}
		}

		fmt.Println(total)
	}
}