Problem:
Score : 200 points

Problem Statement

When Mr. X is away from home, he has decided to use his smartwatch to search the best route to go back home, to participate in ABC.

You, the smartwatch, has found N routes to his home.

If Mr. X uses the i-th of these routes, he will get home in time t_i at cost c_i.

Find the smallest cost of a route that takes not longer than time T.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq T \leq 1000

1 \leq c_i \leq 1000

1 \leq t_i \leq 1000

The pairs (c_i, t_i) are distinct.

Input

Input is given from Standard Input in the following format:

N T
c_1 t_1
c_2 t_2
:
c_N t_N

Output

Print the smallest cost of a route that takes not longer than time T.

If there is no route that takes not longer than time T, print TLE instead.

Sample Input 1

3 70
7 60
1 80
4 50

Sample Output 1

4

The first route gets him home at cost 7.

The second route takes longer than time T = 70.

The third route gets him home at cost 4.

Thus, the cost 4 of the third route is the minimum.

Sample Input 2

4 3
1 1000
2 4
3 1000
4 500

Sample Output 2

TLE

There is no route that takes not longer than time T = 3.

Sample Input 3

5 9
25 8
5 9
4 10
1000 1000
6 1

Sample Output 3

5

Solution in Go (1.6) (judge verdict: Accepted)

package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

var sc *bufio.Scanner

func init() {
	sc = bufio.NewScanner(os.Stdin)
	buffsize := 1000000
	buff := make([]byte, buffsize)
	sc.Buffer(buff, buffsize)
	sc.Split(bufio.ScanWords)
}

func loadint() (result int) {
	sc.Scan()
	result, _ = strconv.Atoi(sc.Text())
	return
}

func main() {
	N := loadint()
	T := loadint()
	mincost := 9999
	for i := 0; i < N; i++ {
		c := loadint()
		t := loadint()
		if t <= T {
			if c < mincost {
				mincost = c
			}
		}
	}
	if mincost <= 1000 {
		fmt.Println(mincost)
	} else {
		fmt.Println("TLE")
	}
}