Problem:
Score : 300 points

Problem Statement

In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0.
You are given a sequence h=\{h_1,h_2,h_3,......\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:

Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.

Find the minimum number of watering operations required to satisfy the condition.

Constraints

1 \leq N \leq 100

0 \leq h_i \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
h_1 h_2 h_3 ...... h_N

Output

Print the minimum number of watering operations required to satisfy the condition.

Sample Input 1

4
1 2 2 1

Sample Output 1

2

The minimum number of watering operations required is 2.
One way to achieve it is:

Perform the operation with (l,r)=(1,3).

Perform the operation with (l,r)=(2,4).

Sample Input 2

5
3 1 2 3 1

Sample Output 2

5

Sample Input 3

8
4 23 75 0 23 96 50 100

Sample Output 3

221

Solution in Go (1.6) (judge verdict: Accepted)

package main

import "fmt"

func main() {
	var n int
	_, _ = fmt.Scan(&n)
	arr := make([]int, n)
	for i := 0; i < n; i++ {
		var tmp int
		_, _ = fmt.Scan(&tmp)
		arr[i] = tmp
	}
	count := 0
	for {
		sum := 0
		flg := false
		for i := 0; i < n; i++ {
			if arr[i] > 0 {
				arr[i]--
				if !flg {
					count++
				}
				flg = true
			} else {
				flg = false
			}
			sum += arr[i]
		}
		if sum == 0 {
			break
		}
	}
	fmt.Println(count)
}