Problem:
Score : 400 points

Problem Statement

Takahashi has a string S consisting of lowercase English letters.

Starting with this string, he will produce a new one in the procedure given as follows.

The procedure consists of Q operations. In Operation i (1 \leq i \leq Q), an integer T_i is provided, which means the following:

If T_i = 1: reverse the string S.

If T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.

If F_i = 1 : Add C_i to the beginning of the string S.

If F_i = 2 : Add C_i to the end of the string S.

Help Takahashi by finding the final string that results from the procedure.

Constraints

1 \leq |S| \leq 10^5

S consists of lowercase English letters.

1 \leq Q \leq 2 \times 10^5

T_i = 1 or 2.

F_i = 1 or 2, if provided.

C_i is a lowercase English letter, if provided.

Input

Input is given from Standard Input in the following format:

S
Q
Query_1
:
Query_Q

In the 3-rd through the (Q+2)-th lines, Query_i is one of the following:

1

which means T_i = 1, and:

2 F_i C_i

which means T_i = 2.

Output

Print the resulting string.

Sample Input 1

a
4
2 1 p
1
2 2 c
1

Sample Output 1

cpa

There will be Q = 4 operations. Initially, S is a.

Operation 1: Add p at the beginning of S. S becomes pa.

Operation 2: Reverse S. S becomes ap.

Operation 3: Add c at the end of S. S becomes apc.

Operation 4: Reverse S. S becomes cpa.

Thus, the resulting string is cpa.

Sample Input 2

a
6
2 2 a
2 1 b
1
2 2 c
1
1

Sample Output 2

aabc

There will be Q = 6 operations. Initially, S is a.

Operation 1: S becomes aa.

Operation 2: S becomes baa.

Operation 3: S becomes aab.

Operation 4: S becomes aabc.

Operation 5: S becomes cbaa.

Operation 6: S becomes aabc.

Thus, the resulting string is aabc.

Sample Input 3

y
1
2 1 x

Sample Output 3

xy

Solution in Go (1.6) (judge verdict: Wrong Answer)

package main

import (
	"bufio"
	"fmt"
	"math"
	"os"
	"strconv"
)

var scanner = bufio.NewScanner(os.Stdin)

func scanInt() int {
	scanner.Scan()
	a, err := strconv.Atoi(scanner.Text())
	if err != nil {
		fmt.Println(err)
	}
	return a
}

func scanText() string {
	scanner.Scan()
	return scanner.Text()
}

func scanByte() byte {
	scanner.Scan()
	return []byte(scanner.Text())[0]
}

func main() {
	scanner.Split(bufio.ScanWords)

	s := scanText()

	space := make([]byte, 5*int(math.Pow(10, 5)))
	si := 2 * int(math.Pow(10, 5))
	ei := si + len(s)
	for i := si; i < ei; i++ {
		space[i] = s[i-si]
	}

	b := false

	q := scanInt()
	for i := 0; i < q; i++ {
		t := scanInt()
		if t == 1 {
			b = !b
		} else { // t == 2
			f := scanInt()
			c := scanByte()
			if f == 1 && !b || f == 2 && b { // 先頭
				si--
				space[si] = c
			} else {
				ei++
				space[ei-1] = c
			}
		}
	}

	if !b {
		fmt.Println(string(space[si:ei]))

	} else {
		sub := space[si:ei]
		for left, right := 0, len(sub)-1; left < right; left, right = left+1, right-1 {
			sub[left], sub[right] = sub[right], sub[left]
		}
		fmt.Println(string(sub))
	}
}