Problem:
Score : 200 points

Problem Statement

There are N students and M checkpoints on the xy-plane.

The coordinates of the i-th student (1 \leq i \leq N) is (a_i,b_i), and the coordinates of the checkpoint numbered j (1 \leq j \leq M) is (c_j,d_j).

When the teacher gives a signal, each student has to go to the nearest checkpoint measured in Manhattan distance.

The Manhattan distance between two points (x_1,y_1) and (x_2,y_2) is |x_1-x_2|+|y_1-y_2|.

Here, |x| denotes the absolute value of x.

If there are multiple nearest checkpoints for a student, he/she will select the checkpoint with the smallest index.

Which checkpoint will each student go to?

Constraints

1 \leq N,M \leq 50

-10^8 \leq a_i,b_i,c_j,d_j \leq 10^8

All input values are integers.

Input

The input is given from Standard Input in the following format:

N M
a_1 b_1
:
a_N b_N
c_1 d_1
:
c_M d_M

Output

Print N lines.

The i-th line (1 \leq i \leq N) should contain the index of the checkpoint for the i-th student to go.

Sample Input 1

2 2
2 0
0 0
-1 0
1 0

Sample Output 1

2
1

The Manhattan distance between the first student and each checkpoint is:

For checkpoint 1: |2-(-1)|+|0-0|=3

For checkpoint 2: |2-1|+|0-0|=1

The nearest checkpoint is checkpoint 2. Thus, the first line in the output should contain 2.

The Manhattan distance between the second student and each checkpoint is:

For checkpoint 1: |0-(-1)|+|0-0|=1

For checkpoint 2: |0-1|+|0-0|=1

When there are multiple nearest checkpoints, the student will go to the checkpoint with the smallest index. Thus, the second line in the output should contain 1.

Sample Input 2

3 4
10 10
-10 -10
3 3
1 2
2 3
3 5
3 5

Sample Output 2

3
1
2

There can be multiple checkpoints at the same coordinates.

Sample Input 3

5 5
-100000000 -100000000
-100000000 100000000
100000000 -100000000
100000000 100000000
0 0
0 0
100000000 100000000
100000000 -100000000
-100000000 100000000
-100000000 -100000000

Sample Output 3

5
4
3
2
1

Solution in Go (1.6) (judge verdict: Accepted)

package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

var sc = bufio.NewScanner(os.Stdin)

func nextLine() string {
	sc.Scan()
	return sc.Text()
}

func nextInt() int {
	sc.Scan()
	i, _ := strconv.Atoi(sc.Text())
	return i
}

func nextIntSlice(size int) []int {
	re := make([]int, size)
	for i := 0; i < size; i++ {
		re[i] = nextInt()
	}
	return re
}

func max(a []int) int {
	max := a[0]
	for _, v := range a {
		if v > max {
			max = v
		}
	}
	return max
}

func min(a []int) int {
	min := a[0]
	for _, v := range a {
		if v < min {
			min = v
		}
	}
	return min
}

func abs(n int) int {
	if n < 0 {
		return -n
	}
	return n
}

func main() {
	sc.Split(bufio.ScanWords)
	n, m := nextInt(), nextInt()
	a := make([]int, n)
	b := make([]int, n)
	c := make([]int, m)
	d := make([]int, m)
	for i := 0; i < n; i++ {
		a[i], b[i] = nextInt(), nextInt()
	}
	for i := 0; i < m; i++ {
		c[i], d[i] = nextInt(), nextInt()
	}

	for i := 0; i < n; i++ {
		minj := 0
		mindist := abs(a[i]-c[0]) + abs(b[i]-d[0])
		for j := 1; j < m; j++ {
			tempdist := abs(a[i]-c[j]) + abs(b[i]-d[j])
			if tempdist < mindist {
				minj = j
				mindist = tempdist
			}
		}
		fmt.Println(minj + 1)
	}
}