Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in Go (1.6) (judge verdict: Time Limit Exceeded)

package main

import "fmt"

func main() {
	var n, a, b, c, d int
	var s string
	fmt.Scan(&n, &a, &b, &c, &d, &s)
	a--
	b--
	c--
	d--
	if c < d {
		for {
			if b+1 == d || b+2 == d {
				break
			}
			if s[b+1] == '.' {
				b++
				continue
			}
			if s[b+2] == '.' {
				b += 2
				continue
			}
			fmt.Println("No")
			return
		}
		for {
			if a+1 == c || a+2 == c {
				break
			}
			if s[a+1] == '.' {
				a++
				continue
			}
			if s[a+2] == '.' {
				a += 2
				continue
			}
			fmt.Println("No")
			return
		}
		fmt.Println("Yes")
		return
	}
	for {
		no := true
		for a != c {
			if s[a+1] == '.' && a+1 != b {
				a++
				no = false
				continue
			}
			if s[a+2] == '.' && a+2 != b {
				a += 2
				no = false
				continue
			}
			break
		}
		for {
			if b == d {
				if a == c {
					fmt.Println("Yes")
					return
				}
				break
			}
			if s[b+1] == '.' && b+1 != a {
				b++
				no = false
				break
			}
			if s[b+2] == '.' && b+2 != a {
				b += 2
				no = false
				break
			}
		}
		if a > c || b > d {
			fmt.Println("No")
			return
		}
		if no {
			fmt.Println("No")
			return
		}
	}
}