Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in Fortran (gfortran v4.8.4) (judge verdict: Accepted)

program main
  implicit none
  integer :: i, j, k, n, a(1:3,1:3)
  integer, allocatable :: b(:)
  logical :: judge = .false.
  do i = 1, 3
    read *, a(i, :)
  end do
  read *, n
  allocate (b(n))
  do i = 1, n
    read *, b(i)
  end do

  do i = 1, n
    do j = 1, 3
      do k = 1, 3
        if (a(j, k) == b(i)) then
          a(j, k) = 0
        end if
      end do
    end do
  end do
  do j = 1, 3
    if (a(j, 1) + a(j, 2) + a(j, 3) == 0) then
      judge = .true. 
    else if (a(1, j) + a(2, j) + a(3, j) == 0) then
      judge = .true.
    end if
    if (judge) exit
  end do
  if (.not. judge) then
    if (a(1,1) + a(2,2)+ a(3,3) == 0) then
      judge = .true.
    else if (a(1,3) + a(2,2) + a(3,1) == 0) then
      judge = .true.
    end if
  end if

  if (judge) then
    print '(a)', "Yes"
  else
    print '(a)', "No"
  end if

end program