Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in Fortran (gfortran v4.8.4) (judge verdict: Accepted)

program example
	implicit none
    
    integer N,A(3,3),i,j,k,count
    integer,allocatable :: b(:)
    
    do i=1,3
    	read(*,*) A(i,1:3)
    end do
    
    read(*,*) N
    
    allocate (b(N))
    
    do i=1,N
    	read(*,*) b(i)
    end do
    
    do i=1,3
    	count=0
    	do j=1,3
        	do k=1,N
            	if(A(i,j)==b(k)) then
                	count=count+1
                end if
            end do
        end do
        if (count==3) then
        	write(*,*) "Yes"
         	goto 1
    	end if       
    end do

    do i=1,3
    	count=0
    	do j=1,3
        	do k=1,N
            	if(A(j,i)==b(k)) then
                	count=count+1
                end if
            end do
        end do
        if (count==3) then
        	write(*,*) "Yes"
         	goto 1
    	end if       
    end do
    
    count=0
    
    do i=1,3
    	do j=1,N
    		if(A(i,i)==b(j)) then
            	count=count+1
            end if
        end do
    end do
    
    if (count==3) then
    	write(*,*) "Yes"
        goto 1
    end if
    
    count=0
    
    do i=1,N
    	if(A(1,3)==b(i)) then
        	count=count+1
        end if

    	if(A(2,2)==b(i)) then
        	count=count+1
        end if

    	if(A(3,1)==b(i)) then
        	count=count+1
        end if
    end do
    
    if (count==3) then
    	write(*,*) "Yes"
        goto 1
    end if
    
    write(*,*) "No"
    
    
1 end program example