Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Fortran (GNU Fortran 9.2.1) (judge verdict: Accepted)

program sample
  implicit none
  integer :: n,i,j,count8
  integer,allocatable :: count(:)

  read(*,*) n
  allocate(count(n))

  count=0
  count8=0
  count(1)=1
  do i=2,n
     do j=1,i
        if(mod(i,j)==0)then
           count(i)=count(i)+1
        endif
     enddo
     if(count(i)==8.and.mod(i,2)==1)then
        count8=count8+1
     endif     
  enddo

  write(*,*) count8

  stop
  
end program sample