Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Fortran (gfortran v4.8.4) (judge verdict: Accepted)

program main
  implicit none
  
  integer :: i,n,j,c,cc=0
  
  read(*,*)n
  
  do i = 1, n, 2
    c = 0
    do j = 1, n
      if (mod(i,j) == 0) then
        c = c + 1
      end if
    end do
    if (c == 8) then
      cc = cc + 1
    end if
  end do
  write(*,*)cc
end program main