Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Fortran (gfortran v4.8.4) (judge verdict: Wrong Answer)

   program abc106b
      implicit none
      integer::n
      integer::i,j,count,ans
      
         read *, n
         
         ans=0
         do i=1,n,2
            count=0
            do j=1,n
               if (mod(n,j)==0) count=count+1
            end do
            if (count==8) ans=ans+1
         end do
         
         print *, ans
         
   end program abc106b