Problem:
Score : 300 points

Problem Statement

Fennec is fighting with N monsters.

The health of the i-th monster is H_i.

Fennec can do the following two actions:

Attack: Fennec chooses one monster. That monster's health will decrease by 1.

Special Move: Fennec chooses one monster. That monster's health will become 0.

There is no way other than Attack and Special Move to decrease the monsters' health.

Fennec wins when all the monsters' healths become 0 or below.

Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.

Constraints

1 \leq N \leq 2 \times 10^5

0 \leq K \leq 2 \times 10^5

1 \leq H_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
H_1 ... H_N

Output

Print the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning.

Sample Input 1

3 1
4 1 5

Sample Output 1

5

By using Special Move on the third monster, and doing Attack four times on the first monster and once on the second monster, Fennec can win with five Attacks.

Sample Input 2

8 9
7 9 3 2 3 8 4 6

Sample Output 2

0

She can use Special Move on all the monsters.

Sample Input 3

3 0
1000000000 1000000000 1000000000

Sample Output 3

3000000000

Watch out for overflow.

Solution in Fortran (gfortran v4.8.4) (judge verdict: Wrong Answer)

program main
    implicit none
    integer(8), allocatable:: h(:)
    integer(8):: n, k, one
    one =1
    read*,n,k
    
    if (k >= n)then
        print*, 0
        stop
    end if
    
    allocate(h(n))
    read*, h(:)

    call marge_sort(h(:), one, n)

    print*, sum(h(k+1:))
contains
recursive subroutine marge_sort(arr,first,last)
    integer(8):: arr(:), tmp
    integer(8):: first, last, mean

    if (last - first <= 2) then
        if (arr(first) <= arr(last))then
            tmp = arr(first)
            arr(first) = arr(last)
            arr(last) = tmp
        end if
        return
    end if
    
    mean = (first + last) / 2
    call marge_sort(arr, first, mean)
    call marge_sort(arr, mean+1, last)
    call marge(arr, first, mean, last)

end subroutine


subroutine marge(arr, first, mean, last)
    integer(8):: arr(:)
    integer(8), allocatable:: tmp(:)
    integer(8):: first, mean, last
    integer(8):: i, i_left, i_right
    
    allocate(tmp(last-first+1))
    i_left = first
    i_right = mean + 1
    i = 0
    do while((i_left <= mean) .and. (i_right <= last))
        i = i + 1
        if (arr(i_left) >= arr(i_right))then
            tmp(i) = arr(i_left)
            i_left = i_left + 1
        else
            tmp(i) = arr(i_right)
            i_right = i_right + 1
        end if
    end do

    if (i_left > mean)then
        tmp(i+1:) = arr(i_right:last)
    else
        tmp(i+1:) = arr(i_left:mean)
    end if
    arr(first:last) = tmp(:)

end subroutine
end program main