Problem:
Score : 200 points

Problem Statement

There are N gems. The value of the i-th gem is V_i.

You will choose some of these gems, possibly all or none, and get them.

However, you need to pay a cost of C_i to get the i-th gem.

Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid.

Find the maximum possible value of X-Y.

Constraints

All values in input are integers.

1 \leq N \leq 20

1 \leq C_i, V_i \leq 50

Input

Input is given from Standard Input in the following format:

N
V_1 V_2 ... V_N
C_1 C_2 ... C_N

Output

Print the maximum possible value of X-Y.

Sample Input 1

3
10 2 5
6 3 4

Sample Output 1

5

If we choose the first and third gems, X = 10 + 5 = 15 and Y = 6 + 4 = 10.
We have X-Y = 5 here, which is the maximum possible value.

Sample Input 2

4
13 21 6 19
11 30 6 15

Sample Output 2

6

Sample Input 3

1
1
50

Sample Output 3

0

Solution in Fortran (gfortran v4.8.4) (judge verdict: Accepted)

PROGRAM ATCODER

implicit none
integer :: n,i,ans=0
integer,allocatable :: v(:), c(:)

read*, n
allocate(v(n),c(n))
read*, v(1:n), c(1:n)

do i = 1, n, 1
  if ( v(i)-c(i) > 0 ) then
    ans = ans + v(i) - c(i)
  end if
end do

print'(i0)', ans 

END PROGRAM ATCODER