Problem:
Score : 100 points

Problem Statement

You are given four digits N_1, N_2, N_3 and N_4. Determine if these can be arranged into the sequence of digits "1974".

Constraints

0 \leq N_1, N_2, N_3, N_4 \leq 9

N_1, N_2, N_3 and N_4 are integers.

Input

Input is given from Standard Input in the following format:

N_1 N_2 N_3 N_4

Output

If N_1, N_2, N_3 and N_4 can be arranged into the sequence of digits "1974", print YES; if they cannot, print NO.

Sample Input 1

1 7 9 4

Sample Output 1

YES

We can get 1974 by swapping N_2 and N_3.

Sample Input 2

1 9 7 4

Sample Output 2

YES

We already have 1974 before doing anything.

Sample Input 3

1 2 9 1

Sample Output 3

NO

Sample Input 4

4 9 0 8

Sample Output 4

NO

Solution in Fortran (GNU Fortran 9.2.1) (judge verdict: Accepted)

program sample
  implicit none

  integer(8) :: a,b,c,d,x(0:9)

  

  ! 整数を読み込む
  read(*,*) a,b,c,d
  x(:)=0
  x(a)=x(a)+1
  x(b)=x(b)+1
  x(c)=x(c)+1
  x(d)=x(d)+1
  if(x(1)==1 .and. x(4)==1 .and. x(7)==1 .and. x(9)==1)then
    write(*,*)'YES'
    else
    write(*,*)'NO'
    end if
  

  stop
end program sample