Problem:
Score : 200 points

Problem Statement

Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Constraints

1 \leq N \leq 10^4

1 \leq A \leq B \leq 36

All input values are integers.

Input

Input is given from Standard Input in the following format:

N A B

Output

Print the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Sample Input 1

20 2 5

Sample Output 1

84

Among the integers not greater than 20, the ones whose sums of digits are between 2 and 5, are: 2,3,4,5,11,12,13,14 and 20. We should print the sum of these, 84.

Sample Input 2

10 1 2

Sample Output 2

13

Sample Input 3

100 4 16

Sample Output 3

4554

Solution in Fortran (gfortran v4.8.4) (judge verdict: Wrong Answer)

      PROGRAM someSums
      IMPLICIT NONE
      INTEGER :: N,A,B, ans
      INTEGER :: num(4), digit, i, piyo, aa,bb,cc,dd , s
      
      READ*,N,A,B
      ans = 0
      
      num(:) = 0
      digit = 1000
      piyo = N
      DO i = 1,4
        DO while(.TRUE.)
          IF(piyo>=digit)THEN
            piyo = piyo - digit
            num(i) = num(i) + 1
          ELSE
            digit = digit / 10
            EXIT
          END IF
        END DO
      END DO
      
      DO aa = 0,9
        DO bb = 0,9
          DO cc = 0,9
            DO dd = 0,9
              s = aa + bb + cc + dd
              IF(A<=s.AND.B>=s)THEN
                ans = ans + aa*1000+bb*100+cc*10+dd
              END IF
              IF(dd==num(4).AND.cc==num(3).AND. &
              bb==num(2).AND.aa==num(1))THEN
                print'(I0)',ans
                STOP
              END IF
            END DO
          END DO
        END DO
      END DO
      
      
      
      
      
      END PROGRAM