Problem:
Score : 200 points

Problem Statement

Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print -1 instead.

Constraints

2 \leq N \leq 10^5

0 \leq A_i \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the value A_1 \times ... \times A_N as an integer, or -1 if the value exceeds 10^{18}.

Sample Input 1

2
1000000000 1000000000

Sample Output 1

1000000000000000000

We have 1000000000 \times 1000000000 = 1000000000000000000.

Sample Input 2

3
101 9901 999999000001

Sample Output 2

-1

We have 101 \times 9901 \times 999999000001 = 1000000000000000001, which exceeds 10^{18}, so we should print -1 instead.

Sample Input 3

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0

Sample Output 3

0

Solution in Fortran (GNU Fortran 9.2.1) (judge verdict: Accepted)

program b
    use,intrinsic :: iso_fortran_env
    implicit none
    integer(int64):: n,ans,i
    integer(int64),allocatable:: a(:)

    read*, n
    allocate(a(n))
    read*, a(:)

    if (minval(a) == 0) then
        print'(i0)', 0
        stop
    end if

    ans=1

    do i=1,n
        if (log10(dble(ans))+log10(dble(a(i))) > 18) then
            print'(i0)', -1
            stop
        else
            if (ans*a(i) > 1000000000000000000_8) then
                print'(i0)', -1
                stop
            end if
            ans=ans*a(i)
        end if
    end do
    print'(i0)', ans
end program b