Problem:
Score : 200 points

Problem Statement

Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print -1 instead.

Constraints

2 \leq N \leq 10^5

0 \leq A_i \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the value A_1 \times ... \times A_N as an integer, or -1 if the value exceeds 10^{18}.

Sample Input 1

2
1000000000 1000000000

Sample Output 1

1000000000000000000

We have 1000000000 \times 1000000000 = 1000000000000000000.

Sample Input 2

3
101 9901 999999000001

Sample Output 2

-1

We have 101 \times 9901 \times 999999000001 = 1000000000000000001, which exceeds 10^{18}, so we should print -1 instead.

Sample Input 3

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0

Sample Output 3

0

Solution in Fortran (GNU Fortran 9.2.1) (judge verdict: Runtime Error)

program abc169b
  use iso_fortran_env
  implicit none

  integer :: n, i
  integer(int64) :: x, a(100000)
  integer(int64),parameter :: mx = 10_8**18

  read *, n
  read *, a(1:n)

  if (any(a(1:n) == 0)) then
     print *, 0
     stop
  end if

  x = 1

  do i = 1,n
     if((mx+x-1) / x * a(i) > mx .and. (mx+a(i)-1) / a(i) * x > mx) then
        print *, -1
        stop
     else
        x = x * a(i)
     end if
  end do

  print *, x
end program abc169b