Problem:
Score : 300 points

Problem Statement

Sitting in a station waiting room, Joisino is gazing at her train ticket.

The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).

In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.

The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Constraints

0≤A,B,C,D≤9

All input values are integers.

It is guaranteed that there is a solution.

Input

Input is given from Standard Input in the following format:

ABCD

Output

Print the formula you made, including the part =7.

Use the signs + and -.

Do not print a space between a digit and a sign.

Sample Input 1

1222

Sample Output 1

1+2+2+2=7

This is the only valid solution.

Sample Input 2

0290

Sample Output 2

0-2+9+0=7

0 - 2 + 9 - 0 = 7 is also a valid solution.

Sample Input 3

3242

Sample Output 3

3+2+4-2=7

Solution in Fortran (GNU Fortran 9.2.1) (judge verdict: Wrong Answer)

program sample
    implicit none
    character(1)::s(3)
    integer(8) :: i,j,m,n,p,x,t(4)
    integer(8),allocatable :: y(:)
  
    read(*,*) n
    t(1)=n/1000
    n=n-t(1)*1000
    t(2)=n/100
    n=n-t(2)*100
    t(3)=n/10
    t(4)=n-t(3)*10
    s(:)='+'
    
    do i=0,8
        x=t(1)
        if (mod(i,2)==0)then
            s(3)='-'
            x=x-t(4)
        else
            s(3)='+'
            m=i-1
            x=x+t(4)
        end if
        
        if (mod(i,4)==0)then
            s(2)='-'
            x=x-t(3)
        else
            s(2)='+'
            m=m-2
            x=x+t(3)
        end if
        if (mod(i,8)==0)then
            s(1)='-'
            x=x-t(2)
        else
            s(1)='+'
            x=x+t(2)
        end if
        if (x==7)then
            write(*,*)t(1),s(1),t(2),s(2),t(3),s(3),t(4),'=7'
            stop
        end if
    end do

    stop
end program sample