Problem:
Score : 300 points

Problem Statement

Hearing that energy drinks increase rating in those sites, Takahashi decides to buy up M cans of energy drinks.

There are N stores that sell energy drinks. In the i-th store, he can buy at most B_i cans of energy drinks for A_i yen (the currency of Japan) each.

What is the minimum amount of money with which he can buy M cans of energy drinks?

It is guaranteed that, in the given inputs, a sufficient amount of money can always buy M cans of energy drinks.

Constraints

All values in input are integers.

1 \leq N, M \leq 10^5

1 \leq A_i \leq 10^9

1 \leq B_i \leq 10^5

B_1 + ... + B_N \geq M

Input

Input is given from Standard Input in the following format:

N M
A_1 B_1
A_2 B_2
\vdots
A_N B_N

Output

Print the minimum amount of money with which Takahashi can buy M cans of energy drinks.

Sample Input 1

2 5
4 9
2 4

Sample Output 1

12

With 12 yen, we can buy one drink at the first store and four drinks at the second store, for the total of five drinks. However, we cannot buy 5 drinks with 11 yen or less.

Sample Input 2

4 30
6 18
2 5
3 10
7 9

Sample Output 2

130

Sample Input 3

1 100000
1000000000 100000

Sample Output 3

100000000000000

The output may not fit into a 32-bit integer type.

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

using System;
class Program
{
    static void Main(string[] args)
    {
        string[] input1 = Console.ReadLine().Split(' ');
        int N = int.Parse(input1[0]);
        int M = int.Parse(input1[1]);
        long[] A = new long[N];
        int[] B = new int[N];
        for(int i = 0; i < N; i++)
        {
            string[] input = Console.ReadLine().Split(' ');
            A[i] = long.Parse(input[0]);
            B[i] = int.Parse(input[1]);
        }
        Array.Sort(A, B);
        long c = 0;
        long sum = 0;
        for(int i = 0; i < N; i++)
        {
            if(c + B[i] >= M)
            {
                sum += (M - c) * A[i];
                break;
            }
            else
            {
                sum += A[i] * B[i];
                c += B[i];
            }
        }
        Console.WriteLine(sum);
    }
}