Problem:
Score : 300 points

Problem Statement

Snuke has an integer sequence A of length N.

He will freely choose an integer b.
Here, he will get sad if A_i and b+i are far from each other.
More specifically, the sadness of Snuke is calculated as follows:

abs(A_1 - (b+1)) + abs(A_2 - (b+2)) + ... + abs(A_N - (b+N))

Here, abs(x) is a function that returns the absolute value of x.

Find the minimum possible sadness of Snuke.

Constraints

1 \leq N \leq 2 \times 10^5

1 \leq A_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

Print the minimum possible sadness of Snuke.

Sample Input 1

5
2 2 3 5 5

Sample Output 1

2

If we choose b=0, the sadness of Snuke would be abs(2-(0+1))+abs(2-(0+2))+abs(3-(0+3))+abs(5-(0+4))+abs(5-(0+5))=2.
Any choice of b does not make the sadness of Snuke less than 2, so the answer is 2.

Sample Input 2

9
1 2 3 4 5 6 7 8 9

Sample Output 2

0

Sample Input 3

6
6 5 4 3 2 1

Sample Output 3

18

Sample Input 4

7
1 1 1 1 2 3 4

Sample Output 4

6

Solution in C# (Mono 4.6.2.0) (judge verdict: Wrong Answer)

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace test
{
    class Program
    {
        static void Main(string[] args)
        {
            var N = long.Parse(Console.ReadLine());
            var A = Console.ReadLine().Split(' ').Select(s => long.Parse(s)).ToArray();
            var Ai = new long[N];
            for (var i = 0; i < N; i++) Ai[i] = A[i] - i - 1;
            var zero = Ai.Select(i => Math.Abs(i)).Sum();

            var pos = Math.Pow(10, 19);
            var par = 1;

            while (true)
            {                
                var tmp = 0L;
                for(var i = 0; i < N; i++)
                {
                    tmp += Math.Abs(Ai[i] + par);
                }
                if (pos >= tmp) pos = tmp;
                else break;
                par++;
            }

            par = 1;
            var neg = Math.Pow(10, 19);
            while (true)
            {
                var tmp = 0L;
                for (var i = 0; i < N; i++)
                {
                    tmp += Math.Abs(Ai[i] - par);
                    par++;
                }
                if (neg >= tmp) neg = tmp;
                else break;
                par++;
            }

            Console.WriteLine(Math.Min(zero, Math.Min(pos, neg)));
        }
    }
}