Problem:
Score : 300 points

Problem Statement

Takahashi is a teacher responsible for a class of N students.

The students are given distinct student numbers from 1 to N.

Today, all the students entered the classroom at different times.

According to Takahashi's record, there were A_i students in the classroom when student number i entered the classroom (including student number i).

From these records, reconstruct the order in which the students entered the classroom.

Constraints

1 \le N \le 10^5

1 \le A_i \le N

A_i \neq A_j (i \neq j)

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 \ldots A_N

Output

Print the student numbers of the students in the order the students entered the classroom.

Sample Input 1

3
2 3 1

Sample Output 1

3 1 2

First, student number 3 entered the classroom.

Then, student number 1 entered the classroom.

Finally, student number 2 entered the classroom.

Sample Input 2

5
1 2 3 4 5

Sample Output 2

1 2 3 4 5

Sample Input 3

8
8 2 7 3 4 5 6 1

Sample Output 3

8 2 4 5 6 7 3 1

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

using System;
using System.Collections.Generic;//list用
using System.Text;//StringBuilder用
using System.Collections;//ハッシュテーブル用
using System.Linq;

class Program
{
    //Hashtable ht = new Hashtable();
    static List<int> s = new List<int>();
    static List<int>[] sl;
    static decimal result;
    static int N,K;
    //StringBuilder strresult= new StringBuilder("");//Append(str ○○)関数で文字を追加していく



    static void Main()
    {
        //Modular mo = new Modular(0);//素数で割った余りを出せで使う。()内が初期値。★使い方：Modular型で宣言すると、その時点でのその素数で割った余りを保持する変数になる（powべき乗、Fac累乗、nCr組み合わせも関数として存在）
        //Node<> no = new Node<>();//UnionFind★Find関数で根っこの値を返す（根っこの値が一緒なら同グループ）、Unite関数で二つの木をくっつける
        //Permutation<> pe = new Permutation<>();//配列＆リストを並べ替えた場合の全ケースを出力★All関数でリスト形式で返す。
        //Treap<> tr = new Treap<>();//平衡二分木★Insert()関数で挿入、FindIndex()関数で該当する大きさの物が入るべき配列番号を返す。
        PriorityQueue<int,int> pr = new PriorityQueue<int,int>();//優先度付キュー★Add(key,value)で格納、Dequeue()で取りだし。keyが小さいものから取り出す。
Read1();
      Read2();
for(int i=0;i<N;i++){pr.Add(s[i],i);}
        
for(int i=0;i<N;i++){
  result=pr.Dequeue().Value;result++;
        Console.WriteLine(result.ToString());
}
    }


    static void Read1()//1項
    {
        string tmp = Console.ReadLine();
        N = int.Parse(tmp);
    }

    static void Read2()//複数項（項目数Ｎ）
    {
        string[] tmp = Console.ReadLine().Split(' ');
        for (int i = 0; i < N; i++) { s.Add(int.Parse(tmp[i])); }
    }
    static void Read3()//1行複数項
    {
        string[] tmp = Console.ReadLine().Split(' ');
        for (int i = 0; i < tmp.Length; i++) { s.Add(int.Parse(tmp[i])); }
    }
    static void Read4()//NK１行
    {
        string[] tmp = Console.ReadLine().Split(' ');
        N = int.Parse(tmp[0]);
        K = int.Parse(tmp[1]);
    }
    static void Read5()//N行K項
    {
        sl = new List<int>[N];
        for (int i = 0; i < N; i++) {
            sl[i] = new List<int>();
            string[] tmp = Console.ReadLine().Split(' ');
            for (int j = 0; j < K; j++) {
                sl[i].Add(int.Parse(tmp[j]));
            }
        }

    }
}



class PriorityQueue<TKey, TValue>
{
    SortedDictionary<TKey, Queue<TValue>> dict = new SortedDictionary<TKey, Queue<TValue>>();
    int count = 0;

    public int Count
    {
        get
        {
            return count;
        }
    }

    public void Add(TKey key, TValue value)
    {
        if (!dict.ContainsKey(key))
        {
            dict[key] = new Queue<TValue>();
        }

        dict[key].Enqueue(value);
        count++;
    }

    public KeyValuePair<TKey, TValue> Dequeue()
    {
        var queue = dict.First();
        if (queue.Value.Count <= 1)
        {
            dict.Remove(queue.Key);
        }
        count--;
        return new KeyValuePair<TKey, TValue>(queue.Key, queue.Value.Dequeue());
    }
}