Problem:
Score : 200 points

Problem Statement

There are N rabbits, numbered 1 through N.

The i-th (1≤i≤N) rabbit likes rabbit a_i.
Note that no rabbit can like itself, that is, a_i≠i.

For a pair of rabbits i and j (i＜j), we call the pair (i，j) a friendly pair if the following condition is met.

Rabbit i likes rabbit j and rabbit j likes rabbit i.

Calculate the number of the friendly pairs.

Constraints

2≤N≤10^5

1≤a_i≤N

a_i≠i

Input

The input is given from Standard Input in the following format:

N
a_1 a_2 ... a_N

Output

Print the number of the friendly pairs.

Sample Input 1

4
2 1 4 3

Sample Output 1

2

There are two friendly pairs: (1，2) and (3，4).

Sample Input 2

3
2 3 1

Sample Output 2

0

There are no friendly pairs.

Sample Input 3

5
5 5 5 5 1

Sample Output 3

1

There is one friendly pair: (1，5).

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

#pragma warning disable

using System;
using System.Collections.Generic;
using System.IO;
using System.Linq;
using System.Runtime.Serialization.Formatters.Binary;
using System.Text;
using System.Text.RegularExpressions;
using System.Diagnostics;
using System.Numerics;
using System.Collections;
using System.Timers;

static class MainClass
{
    public static void Main(string[] args)
    {
        var n = Console.ReadLine().ToInt32();
        var an = Console.ReadLine().SplittedStringToInt32List();
        var ls = new List<KeyValuePair<int, int>>();
        var dic = new Dictionary<int, int>();
        for (int i = 0; i < n; i++)
        {
            var ai = an[i];
            var ani = an[ai - 1]; //  || x.Value == Math.Max(i + 1, ai)
            if (i + 1 == ani && i + 1 != ai && !dic.ContainsKey(Math.Min(i + 1, ai)))
            {
                dic.Add(Math.Min(i+1,ai), Math.Max(i+1,ai));
            }
        }
        Console.WriteLine(dic.Count);
        Console.ReadLine();
    }

    #region ライブラリ

    #region 文字列処理

    public static int ToInt32(this string str)
    {
        
return int.Parse(str);
    }
    public static List<string> SplittedStringToList(this string str)
    {
        return str.Split(new[] { ' ' }, StringSplitOptions.RemoveEmptyEntries)
            .ToList();
    }
    public static List<int> SplittedStringToInt32List(this string str)
    {
        return str.Split(new[] { ' ' }, StringSplitOptions.RemoveEmptyEntries).Select(x => int.Parse(x)).ToList();
    }
    #endregion
    #region DeepClone
    public static T DeepClone<T>(this T src)
    {
        using (var memoryStream = new MemoryStream())
        {
            var binaryFormatter
              = new BinaryFormatter();
            binaryFormatter.Serialize(memoryStream, src);
            memoryStream.Seek(0, SeekOrigin.Begin);
            return (T)binaryFormatter.Deserialize(memoryStream);
        }
    }
    #endregion

    public static int Gcd(int a,int b)
    {
        if (b == 0)
            return a;
        return Gcd(b, a % b);
    }
    #endregion
}