Problem:
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Distance II

Your task is to calculate the distance between two $n$ dimensional vectors $x = \{x_1, x_2, ..., x_n\}$ and $y = \{y_1, y_2, ..., y_n\}$.

The Minkowski's distance defined below is a metric which is a generalization of both the Manhattan distance and the Euclidean distance.

\[
D_{xy} = (\sum_{i=1}^n |x_i - y_i|^p)^{\frac{1}{p}}
\]

It can be the Manhattan distance

\[
D_{xy} = |x_1 - y_1| + |x_2 - y_2| + ... + |x_n - y_n|
\]

where $p = 1 $.

It can be the Euclidean distance

\[
D_{xy} = \sqrt{(|x_1 - y_1|)^{2} + (|x_2 - y_2|)^{2} + ... + (|x_n - y_n|)^{2}}
\]

where $p = 2 $.

Also, it can be the Chebyshev distance

\[
D_{xy} = max_{i=1}^n (|x_i - y_i|)
\]

where $p = \infty$

Write a program which reads two $n$ dimensional vectors $x$ and $y$, and calculates Minkowski's distance where $p = 1, 2, 3, \infty$ respectively.

Input

In the first line, an integer $n$ is given. In the second and third line, $x = \{x_1, x_2, ... x_n\}$ and $y = \{y_1, y_2, ... y_n\}$ are given respectively. The elements in $x$ and $y$ are given in integers.

Output

Print the distance where $p = 1, 2, 3$ and $\infty$ in a line respectively.
The output should not contain an absolute error greater than 10-5.

Constraints

$1 \leq n \leq 100$

$0 \leq x_i, y_i \leq 1000$

Sample Input

3
1 2 3
2 0 4

Sample Output

4.000000
2.449490
2.154435
2.000000

Solution in C# (judge verdict: Wrong Answer)

using System;
using System.Linq;

namespace ITP1_10_D
{
    class Program
    {
        static void Main(string[] args)
        {
            int member = int.Parse(Console.ReadLine());

            double[] x = Console.ReadLine().Split(' ').Select(a => Convert.ToDouble(a)).ToArray();
            double[] y = Console.ReadLine().Split(' ').Select(a => Convert.ToDouble(a)).ToArray();
            double[] p = { 0.0, 0.0, 0.0, double.MinValue };

            for (int i = 0; i < member; i++)
            {
                double abs = Math.Abs(x[i] - y[i]);
                p[0] += abs;
                p[1] += Math.Pow(abs, 2);
                p[2] += Math.Pow(abs, 3);
                if (p[3] < abs) p[3] = abs;
            }
            p[1] = Math.Sqrt(p[1]);
            p[2] = Math.Pow(p[2], (double)(1 / 3));

            foreach (var i in p)
                Console.WriteLine(i.ToString("f6"));    
        }
    }
}