Problem:
Score : 300 points

Problem Statement

You are given a string S consisting of digits between 1 and 9, inclusive.
You can insert the letter + into some of the positions (possibly none) between two letters in this string.
Here, + must not occur consecutively after insertion.

All strings that can be obtained in this way can be evaluated as formulas.

Evaluate all possible formulas, and print the sum of the results.

Constraints

1 \leq |S| \leq 10

All letters in S are digits between 1 and 9, inclusive.

Input

The input is given from Standard Input in the following format:

S

Output

Print the sum of the evaluated value over all possible formulas.

Sample Input 1

125

Sample Output 1

176

There are 4 formulas that can be obtained: 125, 1+25, 12+5 and 1+2+5. When each formula is evaluated,

125

1+25=26

12+5=17

1+2+5=8

Thus, the sum is 125+26+17+8=176.

Sample Input 2

9999999999

Sample Output 2

12656242944

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

using System;
using System.Collections.Generic;
using System.Linq;
using System.IO;
using System.Text;
using static System.Math;
using static System.Array;
namespace AtCoderSolve
{
    class Solve
    {
        const int mod = 1000000007;
        const int INF = 2147483647;
        const long SINF = 9223372036854775807;

        //static int N;
        //static int[] T, A;
        static string S;


        public static void Input()
        {
            var cin = new Scanner();
            S = Console.ReadLine();
        }

        static void Main(string[] args)
        {
            Input();
            //var sw = new StreamWriter(Console.OpenStandardOutput()) { AutoFlush = false };
            //Console.SetOut(sw);

            int N = S.Length - 1;
            if (N == 0)
            {
                Console.WriteLine(S[0] - '0');
                return;
            }

            long ans = 0;
            for(var bit = 0; bit < (1 << N); bit++)
            {
                List<int> use = new List<int>();
                use.Add(0);
                for(var i = 0; i < N; i++)
                {
                    if ((bit & (1 << i)) != 0)
                    {
                        use.Add(i + 1);
                    }
                }
                use.Add(N + 1);
                
                
                for (var i = 0; i < use.Count() - 1; i++) 
                {
                    ans += long.Parse(S.Substring(use[i], use[i + 1] - use[i]));
                }
            }

            Console.WriteLine(ans);

            //Console.Out.Flush();
        }

    }

    public class Scanner
    {
        public int[] SplitReader()
        {
            int[] array = Console.ReadLine().Split().Select(int.Parse).ToArray();
            return array;
        }
        public long[] SplitReaderL()
        {
            long[] array = Console.ReadLine().Split().Select(long.Parse).ToArray();
            return array;
        }

        public int[] MultiLineReader(int N)
        {
            int[] ret = new int[N];
            for(var i = 0; i < N; i++)
            {
                ret[i] = int.Parse(Console.ReadLine());
            }

            return ret;
        }
        public long[] MultiLineReaderL(int N)
        {
            long[] ret = new long[N];
            for (var i = 0; i < N; i++)
            {
                ret[i] = long.Parse(Console.ReadLine());
            }

            return ret;
        }

    }

    public class Graph
    {
        public void Dfs(List<List<int>> graph, bool[] seen, int v)
        {
            seen[v] = true;
            //初めて訪れたタイミングでここの処理

            foreach (var next in graph[v])
            {
                if (seen[next] == true) { continue; }
                Dfs(graph, seen, next);
            }
            //行き先がない状態になったらこの部分の処理

        }

        public void Gin(List<List<int>> graph, int size)
        {
            for (var i = 0; i < size; i++)
            {
                graph.Add(new List<int>());

            }
        }

        public void InitializeFalse(bool[] seen)
        {
            for (var i = 0; i < seen.Length; i++)
            {
                seen[i] = false;
            }
        }

        public bool AllTrue(bool[] seen)
        {
            for (var i = 0; i < seen.Length; i++)
            {
                if (!seen[i])
                {
                    return false;
                }
            }
            return true;
        }
    }
}