Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C# (Mono 4.6.2.0) (judge verdict: Wrong Answer)

using System;


namespace ConsoleApp1
{
    class Program
    {
        static void Main(string[] args)
        {
            int N = int.Parse(Console.ReadLine());
            int Answer = 1;
            int SquareRoot = 0;
            int Count = 0;

            if (N<105)
            {
                Console.WriteLine("0");
                return;
            }
            else
            {
                for (int i = 107; i < N; i=i+2)
                {
                    SquareRoot = (int)System.Math.Sqrt(N);
                    for (int j = 1; j < N; j=j+2)
                    {
                        if (i % j == 0)
                        {
                            Count = Count + 1;
                        }


                    }
                    if (Count == 8)
                    {
                        Answer = Answer + 1;
                    }

                }
            }

            Console.WriteLine(Answer);

        }
    }
}