Problem:
Score: 100 points

Problem Statement

In AtCoder Kingdom, Gregorian calendar is used, and dates are written in the "year-month-day" order, or the "month-day" order without the year.

For example, May 3, 2018 is written as 2018-5-3, or 5-3 without the year.

In this country, a date is called Takahashi when the month and the day are equal as numbers. For example, 5-5 is Takahashi.

How many days from 2018-1-1 through 2018-a-b are Takahashi?

Constraints

a is an integer between 1 and 12 (inclusive).

b is an integer between 1 and 31 (inclusive).

2018-a-b is a valid date in Gregorian calendar.

Input

Input is given from Standard Input in the following format:

a b

Output

Print the number of days from 2018-1-1 through 2018-a-b that are Takahashi.

Sample Input 1

5 5

Sample Output 1

5

There are five days that are Takahashi: 1-1, 2-2, 3-3, 4-4 and 5-5.

Sample Input 2

2 1

Sample Output 2

1

There is only one day that is Takahashi: 1-1.

Sample Input 3

11 30

Sample Output 3

11

There are eleven days that are Takahashi: 1-1, 2-2, 3-3, 4-4, 5-5, 6-6, 7-7, 8-8, 9-9, 10-10 and 11-11.

Solution in C# (Mono 4.6.2.0) (judge verdict: Runtime Error)

using System;
using System.Linq;

namespace atcoder_Beginner_Contest096_Question3
{
    class Program
    {
        static void Main(string[] args)
        {
            bool possible = true;
            var input1 = Console.ReadLine().Split().Select(int.Parse).ToArray();
            char[][] paint = new char[input1[0]][];
            for (int i = 0; i < input1[0]; i++)
            {
                paint[i] = Console.ReadLine().ToCharArray();
            }

            for (int i = 0; i < input1[0]; i++)
            {
                for (int j = 0; j < input1[1]; j++)
                {
                    if (paint[i][j] == '.') continue;

                    if (j + 1 < input1[1] && paint[i][j + 1] != '#')
                        if (j - 1 >= 0 && paint[i][j - 1] != '#')
                            if (i + 1 < input1[0] && paint[i + 1][j] != '#')
                                if (i - 1 >=0 && paint[i - 1][j] != '#')
                                    possible = false;
                    //if (!possible) break;
                }
                //if (!possible) break;
            }

            Console.WriteLine(possible ? "Yes" : "No");
        }
    }
}