Problem:
Score : 200 points

Problem Statement

Two children are playing tag on a number line. (In the game of tag, the child called "it" tries to catch the other child.) The child who is "it" is now at coordinate A, and he can travel the distance of V per second.
The other child is now at coordinate B, and she can travel the distance of W per second.

He can catch her when his coordinate is the same as hers.
Determine whether he can catch her within T seconds (including exactly T seconds later).
We assume that both children move optimally.

Constraints

-10^9 \leq A,B \leq 10^9

1 \leq V,W \leq 10^9

1 \leq T \leq 10^9

A \neq B

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A V
B W
T

Output

If "it" can catch the other child, print YES; otherwise, print NO.

Sample Input 1

1 2
3 1
3

Sample Output 1

YES

Sample Input 2

1 2
3 2
3

Sample Output 2

NO

Sample Input 3

1 2
3 3
3

Sample Output 3

NO

Solution in C# (.NET Core 3.1.201) (judge verdict: Wrong Answer)

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace ConsoleApp20
{
    class Program
    {
        static void Main(string[] args)
        {

            //long[] iti = Console.ReadLine().Split(' ').Select(s => long.Parse(s)).ToArray();
            /*
             * 
             * int a,b,c;
            a = int.Parse(Console.ReadLine()); //標準入力
            string[] str = Console.ReadLine().Split(' ');//2つ以上のスペース区切り入力の取得
            b = int.Parse(str[0]);  //数値で受け取りたい場合は変換する
            c = int.Parse(str[1]);
　　　　　　　Console.Write("改行なし a = {0} b = {1} c = {2}", a, b, c)//改行なし出力
            Console.WriteLine("改行あり a = {0} b = {1} c = {2}", a, b, c);//改行付き出力
             * */
            long[] iti = Console.ReadLine().Split(' ').Select(s => long.Parse(s)).ToArray();

            long[] ni = Console.ReadLine().Split(' ').Select(s => long.Parse(s)).ToArray();

            long sann = long.Parse(Console.ReadLine()); // 制限秒数

            long ssss = iti[1] - ni[1]; // 追う速度

            long sss2 = Math.Abs(ni[0]) -Math.Abs(iti[0]); // 現在の位置関係　離れている距離

            if((ssss* sann) >= sss2)  // 速度*秒数 >= 距離 の時
            {
                Console.WriteLine("YES");
            } else
            {
                Console.WriteLine("NO");
            }

            //Console.Read();
        }
    }
}