Problem:
Score : 400 points

Problem Statement

Takahashi has a string S consisting of lowercase English letters.

Starting with this string, he will produce a new one in the procedure given as follows.

The procedure consists of Q operations. In Operation i (1 \leq i \leq Q), an integer T_i is provided, which means the following:

If T_i = 1: reverse the string S.

If T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.

If F_i = 1 : Add C_i to the beginning of the string S.

If F_i = 2 : Add C_i to the end of the string S.

Help Takahashi by finding the final string that results from the procedure.

Constraints

1 \leq |S| \leq 10^5

S consists of lowercase English letters.

1 \leq Q \leq 2 \times 10^5

T_i = 1 or 2.

F_i = 1 or 2, if provided.

C_i is a lowercase English letter, if provided.

Input

Input is given from Standard Input in the following format:

S
Q
Query_1
:
Query_Q

In the 3-rd through the (Q+2)-th lines, Query_i is one of the following:

1

which means T_i = 1, and:

2 F_i C_i

which means T_i = 2.

Output

Print the resulting string.

Sample Input 1

a
4
2 1 p
1
2 2 c
1

Sample Output 1

cpa

There will be Q = 4 operations. Initially, S is a.

Operation 1: Add p at the beginning of S. S becomes pa.

Operation 2: Reverse S. S becomes ap.

Operation 3: Add c at the end of S. S becomes apc.

Operation 4: Reverse S. S becomes cpa.

Thus, the resulting string is cpa.

Sample Input 2

a
6
2 2 a
2 1 b
1
2 2 c
1
1

Sample Output 2

aabc

There will be Q = 6 operations. Initially, S is a.

Operation 1: S becomes aa.

Operation 2: S becomes baa.

Operation 3: S becomes aab.

Operation 4: S becomes aabc.

Operation 5: S becomes cbaa.

Operation 6: S becomes aabc.

Thus, the resulting string is aabc.

Sample Input 3

y
1
2 1 x

Sample Output 3

xy

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

//いちいちreverseすると時間がかかりまくるので、どっちの向きで読めばよいかを記録する
//また普通の構造だと先頭追加はO(s.length)で末尾追加はO(1)
//先頭に追加--->H stack|M stack<=======末尾に追加
//reverseの時はstackを入れ替えるだけ
using System;
using System.Collections.Generic;
using System.Linq;
class Program
{
    static void Main()
    {
        string s = Console.ReadLine();
        var M = new Stack<string>();//main
        var H = new Stack<string>();//head
        var C = new Stack<string>();//Copy用
        for (int i = 0; i < s.Length; i++)
        {
            M.Push(s[i].ToString());
        }
        int q = int.Parse(Console.ReadLine());
        string[] In;
        for (int i = 0; i < q; i++)
        {
            In = Console.ReadLine().Split(' ');
            if (In[0] == "1")
            {
                C = M;
                M = H;
                H = C;
            }
            if (In[0] == "2")
            {
                if (In[1] == "1")
                {
                    H.Push(In[2]);
                }
                else if (In[1] == "2")
                {
                    M.Push(In[2]);
                }
            }
        }
        var HA = H.ToArray();
        var MA = M.ToArray().Reverse();
        foreach (var ha in HA) Console.Write(ha);
        foreach (var ma in MA) Console.Write(ma);
    }
}
//計算は合っているがこれだと終わらない
//O(Q^2)
//class Program
//{
//    static void Main()
//    {
//        string s = Console.ReadLine();
//        var L = new List<string>();
//        for (int i = 0; i < s.Length; i++)
//        {
//            L.Add(s[i].ToString());
//        }
//        int q = int.Parse(Console.ReadLine());
//        string[] In;
//        for (int i=0; i < q; i++)
//        {
//            In = Console.ReadLine().Split(' ');
//            if (In[0] == "1")
//            {
//                L.Reverse();
//            }
//            if (In[0] == "2")
//            {
//                if(In[1] == "1")
//                {
//                    L.Insert(0, In[2]);
//                }else if (In[1] == "2")
//                {
//                    L.Add(In[2]);
//                }
//            }
//        }
//        L.ForEach(Console.Write);
//    }
//}