Problem:
Score : 100 points

Problem Statement

A balance scale tips to the left if L>R, where L is the total weight of the masses on the left pan and R is the total weight of the masses on the right pan. Similarly, it balances if L=R, and tips to the right if L<R.

Takahashi placed a mass of weight A and a mass of weight B on the left pan of a balance scale, and placed a mass of weight C and a mass of weight D on the right pan.

Print Left if the balance scale tips to the left; print Balanced if it balances; print Right if it tips to the right.

Constraints

1\leq A,B,C,D \leq 10

All input values are integers.

Input

Input is given from Standard Input in the following format:

A B C D

Output

Print Left if the balance scale tips to the left; print Balanced if it balances; print Right if it tips to the right.

Sample Input 1

3 8 7 1

Sample Output 1

Left

The total weight of the masses on the left pan is 11, and the total weight of the masses on the right pan is 8. Since 11>8, we should print Left.

Sample Input 2

3 4 5 2

Sample Output 2

Balanced

The total weight of the masses on the left pan is 7, and the total weight of the masses on the right pan is 7. Since 7=7, we should print Balanced.

Sample Input 3

1 7 6 4

Sample Output 3

Right

The total weight of the masses on the left pan is 8, and the total weight of the masses on the right pan is 10. Since 8<10, we should print Right.

Solution in C# (Mono 4.6.2.0) (judge verdict: Wrong Answer)

using System;
using System.Linq;
public class Hello{
    public static void Main(){
        // Your code here!
        int[] n=System.Console.ReadLine().Trim().Split(' ').Select(x=>int.Parse(x)).ToArray();
        int count=0,r;
        for(int i=1;i<=n[0];i++){
            r=_func(i);
            if(n[1]<=r&&r<=n[2]) {
                count+=i;
            }
        }
        System.Console.WriteLine(count);
    }
    public static int _func(int n){
        int r=n/1000;
        n-=(n/1000)*1000;
        r+=n/100;
        n-=(n/100)*100;
        r+=n/10;
        n-=(n/10)*10;
        r+=n;
        return r;
    }
}