Problem:
﻿Score: 100 points

Problem Statement

In AtCoder city, there are five antennas standing in a straight line. They are called Antenna A, B, C, D and E from west to east, and their coordinates are a, b, c, d and e, respectively.

Two antennas can communicate directly if the distance between them is k or less, and they cannot if the distance is greater than k.

Determine if there exists a pair of antennas that cannot communicate directly.

Here, assume that the distance between two antennas at coordinates p and q (p < q) is q - p.

Constraints

a, b, c, d, e and k are integers between 0 and 123 (inclusive).

a < b < c < d < e

Input

Input is given from Standard Input in the following format:

a
b
c
d
e
k

Output

Print :( if there exists a pair of antennas that cannot communicate directly, and print Yay! if there is no such pair.

Sample Input 1

1
2
4
8
9
15

Sample Output 1

Yay!

In this case, there is no pair of antennas that cannot communicate directly, because:

the distance between A and B is 2 - 1 = 1

the distance between A and C is 4 - 1 = 3

the distance between A and D is 8 - 1 = 7

the distance between A and E is 9 - 1 = 8

the distance between B and C is 4 - 2 = 2

the distance between B and D is 8 - 2 = 6

the distance between B and E is 9 - 2 = 7

the distance between C and D is 8 - 4 = 4

the distance between C and E is 9 - 4 = 5

the distance between D and E is 9 - 8 = 1

and none of them is greater than 15. Thus, the correct output is Yay!.

Sample Input 2

15
18
26
35
36
18

Sample Output 2

:(

In this case, the distance between antennas A and D is 35 - 15 = 20 and exceeds 18, so they cannot communicate directly.
Thus, the correct output is :(.

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace ABC123 {
	class ABC123_A {
		static void Main(string[] args) {
			// a-eの入力を配列に格納する - list intの配列にする int[5]で良いか
			// kの入力を受け付ける int
			// 正攻法の場合
			// a-b a-c の順に比較して、最後までたどり着いたら、Yay!と出力する
			// a-b a-c の順に比較して、途中で値を超えたら、:(と出力する
			var AE = new int[5];
			for (int i=0; i<5; i++) {
				AE[i] = int.Parse(Console.ReadLine());
			}
			var k = int.Parse(Console.ReadLine());
			CombinateAtoE(AE, k);
		}

		private static void CombinateAtoE(int[] AE, int k) {
			for(int i=0; i<AE.Length; i++) {
				for(int j=i+1; j<AE.Length; j++) {
					if((AE[j] - AE[i]) > k) {
						Console.WriteLine(":(");
						return;
					}
				}
			}
			Console.WriteLine("Yay!");
		}
	}
}