Problem:
Score : 300 points

Problem Statement

There are N integers written on a blackboard. The i-th integer is A_i.

Takahashi will repeatedly perform the following operation on these numbers:

Select a pair of integers, A_i and A_j, that have the same parity (that is, both are even or both are odd) and erase them.

Then, write a new integer on the blackboard that is equal to the sum of those integers, A_i+A_j.

Determine whether it is possible to have only one integer on the blackboard.

Constraints

2 ≦ N ≦ 10^5

1 ≦ A_i ≦ 10^9

A_i is an integer.

Input

The input is given from Standard Input in the following format:

N
A_1 A_2 … A_N

Output

If it is possible to have only one integer on the blackboard, print YES. Otherwise, print NO.

Sample Input 1

3
1 2 3

Sample Output 1

YES

It is possible to have only one integer on the blackboard, as follows:

Erase 1 and 3 from the blackboard, then write 4. Now, there are two integers on the blackboard: 2 and 4.

Erase 2 and 4 from the blackboard, then write 6. Now, there is only one integer on the blackboard: 6.

Sample Input 2

5
1 2 3 4 5

Sample Output 2

NO

Solution in C# (.NET Core 3.1.201) (judge verdict: Accepted)

using System;
using System.Linq;

namespace AtCoder
{
    public class Solver
    {
        private readonly IInputReader _inputReader;
        private readonly IOutputWriter _outputWriter;

        public Solver(IInputReader inputReader, IOutputWriter outputWriter)
        {
            _inputReader = inputReader;
            _outputWriter = outputWriter;
        }

        public void Solve()
        {
            var N = _inputReader.ReadLine().ToInt();
            var numbers = _inputReader.ReadLine().ToLongArray();

            var oddCount = numbers.Count(n => n % 2 == 1);
            var evenCount = numbers.Count(n => n % 2 == 0);

            while (true)
            {
                if (oddCount >= 2)
                {
                    oddCount -= 2;
                    evenCount += 1;
                }
                else if (evenCount >= 2)
                {
                    evenCount -= 2;
                    evenCount += 1;
                }
                else
                {
                    break;
                }
            }

            var result = (oddCount + evenCount) == 1;

            _outputWriter.WriteLine(result ? "YES" : "NO");
        }
    }


    internal class Program
    {
        static void Main(string[] args)
        {
            var reader = new ConsoleInputReader();
            var writer = new ConsoleOutputWriter();
            new Solver(reader, writer).Solve();
        }
    }

    public interface IInputReader
    {
        string ReadLine();
    }

    public interface IOutputWriter
    {
        void WriteLine(string output);
    }

    internal class ConsoleInputReader : IInputReader
    {
        public string ReadLine() => Console.ReadLine();
    }

    internal class ConsoleOutputWriter : IOutputWriter
    {
        public void WriteLine(string output) => Console.WriteLine(output);
    }

    public static class StringExtensions
    {
        public static char ToChar(this string text) => text[0];
        public static long ToInt(this string text) => int.Parse(text);
        public static long ToLong(this string text) => long.Parse(text);
        public static long[] ToLongArray(this string text) => text.Split(' ').Select(txt => txt.ToLong()).ToArray();
    }
}