Problem:
Score : 200 points

Problem Statement

There are N gems. The value of the i-th gem is V_i.

You will choose some of these gems, possibly all or none, and get them.

However, you need to pay a cost of C_i to get the i-th gem.

Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid.

Find the maximum possible value of X-Y.

Constraints

All values in input are integers.

1 \leq N \leq 20

1 \leq C_i, V_i \leq 50

Input

Input is given from Standard Input in the following format:

N
V_1 V_2 ... V_N
C_1 C_2 ... C_N

Output

Print the maximum possible value of X-Y.

Sample Input 1

3
10 2 5
6 3 4

Sample Output 1

5

If we choose the first and third gems, X = 10 + 5 = 15 and Y = 6 + 4 = 10.
We have X-Y = 5 here, which is the maximum possible value.

Sample Input 2

4
13 21 6 19
11 30 6 15

Sample Output 2

6

Sample Input 3

1
1
50

Sample Output 3

0

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

using System;
class Program
{
    static void Main(string[] args)
    {
        int N = int.Parse(Console.ReadLine());

        string[] input = Console.ReadLine().Split(' ');
        int[] V = new int[N];
        for(int i = 0; i < input.Length; i++)
        {
            V[i] = int.Parse(input[i]);
        }
        input = Console.ReadLine().Split(' ');
        int[] C = new int[N];
        for (int i = 0; i < input.Length; i++)
        {
            C[i] = int.Parse(input[i]);
        }
        int[] Ans = new int[N];
        for(int i = 0; i < N; i++)
        {
            Ans[i] = V[i] - C[i];
        }
        Array.Sort(Ans);
        int sum = 0;
        for (int i = N - 1; i >= 0; i--)
        {
            if (Ans[i] > 0)
                sum += Ans[i];
            else
                break;
        }
        Console.WriteLine(sum);
    }
}