Problem:
Score: 100 points

Problem Statement

E869120 has A 1-yen coins and infinitely many 500-yen coins.

Determine if he can pay exactly N yen using only these coins.

Constraints

N is an integer between 1 and 10000 (inclusive).

A is an integer between 0 and 1000 (inclusive).

Input

Input is given from Standard Input in the following format:

N
A

Output

If E869120 can pay exactly N yen using only his 1-yen and 500-yen coins, print Yes; otherwise, print No.

Sample Input 1

2018
218

Sample Output 1

Yes

We can pay 2018 yen with four 500-yen coins and 18 1-yen coins, so the answer is Yes.

Sample Input 2

2763
0

Sample Output 2

No

When we have no 1-yen coins, we can only pay a multiple of 500 yen using only 500-yen coins. Since 2763 is not a multiple of 500, we cannot pay this amount.

Sample Input 3

37
514

Sample Output 3

Yes

Solution in C# (Mono 4.6.2.0) (judge verdict: Runtime Error)

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace ABC088_C
{
    class Program
    {
        static void Main(string[] args)
        {
            var num = new double[3][];
            var input = "";
            var arrayTemp = new string[3];
            for (int i = 0; i < 3; i++)
            {
                num[i] = new double[3];
                input = Console.ReadLine();
                arrayTemp = input.Split(' ');
                num[i] = arrayTemp.Select(double.Parse).ToArray();
            }

            double a1 = 0;
            double b1 = num[0][0] - a1;
            double a2 = num[1][0] - b1;
            double a3 = num[2][0] - b1;
            double b2 = num[0][1] - a1;
            double b3 = num[0][2] - a1;
            if (num[1][1] == a2 + b2 && num[1][2] == a2 + b3 && num[2][1] == a3 + b2 && num[2][2] == a3 + b3)
            {
                Console.WriteLine("Yes");
                return;
            }

            for (a1 = 1; a1 <= Math.Ceiling(num[0][0] / 2); a1++)
            {
                if (num[1][1] == a2 + b2 && num[1][2] == a2 + b3 && num[2][1] == a3 + b2 && num[2][2] == a3 + b3)
                {
                    Console.WriteLine("Yes");
                    return;
                }
                b1 = num[0][0] - a1;
                a2 = num[1][0] - b1;
                a3 = num[2][0] - b1;
                b2 = num[0][1] - a1;
                b3 = num[0][2] - a2;
            }
            Console.WriteLine("No");
        }
    }
}