Problem:
Simultaneous Equation

Write a program which solve a simultaneous equation:

ax + by = c

dx + ey = f

The program should print x and y for given a, b, c, d, e and f (-1,000 ≤ a, b, c, d, e, f ≤ 1,000). You can suppose that given equation has a unique solution.

Input

The input consists of several data sets, 1 line for each data set. In a data set, there will be a, b, c, d, e, f separated by a single space. The input terminates with EOF.

Output

For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.

Sample Input 1

1 2 3 4 5 6
2 -1 -2 -1 -1 -5

Output for the Sample Input 1

-1.000 2.000
1.000 4.000

Sample Input 2

2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27

Output for the Sample Input 2

0.000 3.000
0.000 3.000

Solution in C# (judge verdict: Wrong Answer)

using System;

namespace Prob0004
{
    class Program
    {
        static void Main(string[] args)
        {

            const int COLUMN = 2;
            const int ROW = 3;

            string line;
            while((line = Console.ReadLine()) != null)
            {
                // a[0][0]x + a[0][1]y = a[0][2]
                // a[1][0]x + a[1][1]y = a[1][2]
                string[] tokens = line.Split(' ');
                double[,] a = new double[COLUMN, ROW];
                for(int y = 0; y < COLUMN; y++)
                {
                    for (int x = 0; x < ROW; x++)
                    {
                        a[y, x] = double.Parse(tokens[y * ROW + x]);
                    }
                }


                for(int y = 0; y < COLUMN; y++)
                {
                    for (int x = 0; x < ROW; x++)
                    {
                        Console.Write("{0} ", a[y, x]);
                    }
                    Console.WriteLine("");
                }


                // pivot = (p, p)
                double coef;
                for (int p = 0; p < ROW - 1; p++)
                {

                    // ピボットのある行要素への処理
                    coef = a[p, p];
                    for (int x = p; x < ROW; x++)
                    { 
                        a[p, x] /= coef;
                    }

                    // ピボット以外の行要素への処理
                    for (int y = 0; y < COLUMN; y++)
                    {
                        if(p == y)
                        {
                            continue;
                        }

                        coef = a[y, p];
                        for (int x = p; x < ROW; x++)
                        {
                            a[y, x] -= a[p, x] * coef;
                        }
                    }
                }

                // outputs
                for (int y = 0; y < COLUMN; y++)
                {
                    Console.Write("{0} ", a[y, ROW - 1].ToString("F3"));
                }
                Console.WriteLine();
            }

        }



    }
}