Problem:
Score : 300 points

Problem Statement

Given is a permutation P_1, \ldots, P_N of 1, \ldots, N.
Find the number of integers i (1 \leq i \leq N) that satisfy the following condition:

For any integer j (1 \leq j \leq i), P_i \leq P_j.

Constraints

1 \leq N \leq 2 \times 10^5

P_1, \ldots, P_N is a permutation of 1, \ldots, N.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
P_1 ... P_N

Output

Print the number of integers i that satisfy the condition.

Sample Input 1

5
4 2 5 1 3

Sample Output 1

3

i=1, 2, and 4 satisfy the condition, but i=3 does not - for example, P_i > P_j holds for j = 1.

Similarly, i=5 does not satisfy the condition, either. Thus, there are three integers that satisfy the condition.

Sample Input 2

4
4 3 2 1

Sample Output 2

4

All integers i (1 \leq i \leq N) satisfy the condition.

Sample Input 3

6
1 2 3 4 5 6

Sample Output 3

1

Only i=1 satisfies the condition.

Sample Input 4

8
5 7 4 2 6 8 1 3

Sample Output 4

4

Sample Input 5

1
1

Sample Output 5

1

Solution in C# (Mono 4.6.2.0) (judge verdict: Time Limit Exceeded)

using System;
class Program
{
	static void Main(string[] args)
	{
        string input1 = Console.ReadLine();
        string[] input2 = Console.ReadLine().Split(' ');
        int n = int.Parse(input1);
        int[] Ps = new int[n];

        for (int i = 0; i < n; i++)
        {
            Ps[i] = int.Parse(input2[i]);
        }

        int count = 0;
        bool judge = true;
        for (int i = 0; i < n; i++)
        {
            for (int j = 0; j < i; j++)
            {
                if(Ps[i] > Ps[j])
                {
                    judge = false;
                }
            }
            if(judge)
            {
                count++;
            }
            judge = true;
        }
		//出力
		Console.WriteLine(count);
	}
}