Problem:
Disjoint Set

Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.

same(x, y): determine whether x and y are in the same set.

Input

n q
com1 x1 y1
com2 x2 y2
...
comq xq yq

In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Constraints

1 ≤ n ≤ 10000

1 ≤ q ≤ 100000

x ≠ y

Sample Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0

Sample Output

0
0
1
1
1
0
1
1

Solution in C# (judge verdict: Accepted)

using System;
using System.Collections.Generic;
using System.Linq;
using static System.Console;
using static System.Math;

class Program
{
    static void Main()
    {
        SetOut(new System.IO.StreamWriter(OpenStandardOutput()) { AutoFlush = false });

        var nq = ReadLine().Split().Select(int.Parse).ToArray();
        var uf = new UnionFind(nq[0]);
        for (int i = 0; i < nq[1]; i++)
        {
            var line = ReadLine().Split(' ');
            if (line[0] == "0") uf.Unite(int.Parse(line[1]), int.Parse(line[2]));
            else WriteLine(uf.Same(int.Parse(line[1]), int.Parse(line[2])) ? "1" : "0");
        }
        Out.Flush();
    }
}

public class UnionFind
{
    int[] parent;
    int count;
    public int Count => count;

    public UnionFind(int length)
    {
        parent = new int[length];
        for (int i = 0; i < parent.Length; i++)
        {
            parent[i] = -1;
        }
        count = length;
    }

    public int Root(int x) => parent[x] < 0 ? x : parent[x] = Root(parent[x]);

    public bool Same(int x, int y) => Root(x) == Root(y);

    public void Unite(int x, int y)
    {
        x = Root(x);
        y = Root(y);
        if (x == y) return;
        count--;
        if (parent[x] < parent[y])
        {
            parent[x] += parent[y];
            parent[y] = x;
        }
        else
        {
            parent[y] += parent[x];
            parent[x] = y;
        }
    }

    public int Size(int x) => -parent[Root(x)];
}