Problem:
Search II

You are given a sequence of n integers S and a sequence of different q integers T. Write a program which outputs C, the number of integers in T which are also in the set S.

Input

In the first line n is given. In the second line, n integers are given. In the third line q is given. Then, in the fourth line, q integers are given.

Output

Print C in a line.

Constraints

Elements in S is sorted in ascending order

n ≤ 100000

q ≤ 50000

0 ≤ an element in S ≤ 109

0 ≤ an element in T ≤ 109

Sample Input 1

5
1 2 3 4 5
3
3 4 1

Sample Output 1

3

Sample Input 2

3
1 2 3
1
5

Sample Output 2

0

Sample Input 3

5
1 1 2 2 3
2
1 2

Sample Output 3

2

Notes

Solution in C# (judge verdict: Wrong Answer)

using System;

class A4{
  public static void Main(){
    int n,q,l = 0,count = 0;
    n = int.Parse(Console.ReadLine());
    //string[] S = new string[n];
    string[] str = Console.ReadLine().Split(' ');

    /*for(int i = 0;i < n;i++){
      S[i] = str[i];
    }*/

    q = int.Parse(Console.ReadLine());
    //string[] T = new string[q];
    string[] str2 = Console.ReadLine().Split(' ');

  /*  for(int i = 0;i < q;i++){
      T[i] = str2[i];
    }*/

    int[] memory = new int[n];
    for(int i = 0;i < q;i++){
      if(binarySearch(str,str2[i]) != -1){
        memory[l] = binarySearch(str,str2[i]);
        l++;
      }
    }
    /*for(int i = 0;i < l;i++){
      Console.Write(memory[i] + " ");
    }
    Console.WriteLine("");
    */
    for(int i = 0;i < l;i++){
      bool flag = false;
      for(int j = 0;j < l;j++){
        if(memory[i] == memory[j] && flag == false){
           count++;
           flag = true;
        }
      }
    }
    Console.WriteLine(count);

  }

  static int binarySearch(string[] S,string key){
    int left = 0;
    int right = S.Length;
    while(left < right){
      int mid = (left + right) / 2;
      if(S[mid] == key) return mid;
      else if(key.CompareTo(S[mid]) < 0) right = mid;
      else left = mid + 1;
    }
    return -1;
  }
}