Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

using System;
class Program{
    static void Main(string[]args){
        int N=int.Parse(Console.ReadLine());
        int div=0;
        int count=0;
        for(int i=1;i<=N;i++){
            div=divisor(i);
            if(i%2==1 && div==8){
                count++;
            }
        }
        Console.WriteLine(count);
    }
    static int divisor(int N){
        int count=0;
        for(int i=1;i<Math.Sqrt(N);i++){
            if(N%i==0)count=count+2;
        }
        if(N%(Math.Sqrt(N))==0)count++;
        return count;
    }
}