Problem:
Score : 300 points

Problem Statement

Given are an integer X and an integer sequence of length N: p_1, \ldots, p_N.

Among the integers not contained in the sequence p_1, \ldots, p_N (not necessarily positive), find the integer nearest to X, that is, find the integer whose absolute difference with X is the minimum. If there are multiple such integers, report the smallest such integer.

Constraints

1 \leq X \leq 100

0 \leq N \leq 100

1 \leq p_i \leq 100

p_1, \ldots, p_N are all distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X N
p_1 ... p_N

Output

Print the answer.

Sample Input 1

6 5
4 7 10 6 5

Sample Output 1

8

Among the integers not contained in the sequence 4, 7, 10, 6, 5, the one nearest to 6 is 8.

Sample Input 2

10 5
4 7 10 6 5

Sample Output 2

9

Among the integers not contained in the sequence 4, 7, 10, 6, 5, the ones nearest to 10 are 9 and 11. We should print the smaller one, 9.

Sample Input 3

100 0

Sample Output 3

100

When N = 0, the second line in the input will be empty. Also, as seen here, X itself can be the answer.

Solution in C# (.NET Core 3.1.201) (judge verdict: Accepted)

using System;

namespace AtCoder
{
    class Program
    {
        static void Main(string[] args)
        {
            string[] input = Console.ReadLine().Split(' ');
            string[] inputP = Console.ReadLine().Split(' ');

            int X = int.Parse(input[0]);
            int N = int.Parse(input[1]);
            int count = 0;

            if (N == 0)
            {
                Console.WriteLine(X);
                return;
            }

            int[] p = new int[N];
            for (int i = 0; i < N; i++)
            {
                p[i] = int.Parse(inputP[i]);
            }

            for (int i = 0; i < 100; i++)
            {
                for (int j = 0; j < N; j++)
                {
                    if (X - i != p[j])
                    {
                        count++;
                    }
                }

                if (count == N)
                {
                    Console.WriteLine(X - i);
                    return;
                }

                count = 0;
                for (int j = 0; j < N; j++)
                {
                    if (X + i != p[j])
                    {
                        count++;
                    }
                }

                if (count == N)
                {
                    Console.WriteLine(X + i);
                    return;
                }

                count = 0;
            }
        }
    }
}