Problem:
Score : 300 points

Problem Statement

There are N+1 towns. The i-th town is being attacked by A_i monsters.

We have N heroes. The i-th hero can defeat monsters attacking the i-th or (i+1)-th town, for a total of at most B_i monsters.

What is the maximum total number of monsters the heroes can cooperate to defeat?

Constraints

All values in input are integers.

1 \leq N \leq 10^5

1 \leq A_i \leq 10^9

1 \leq B_i \leq 10^9

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_{N+1}
B_1 B_2 ... B_N

Output

Print the maximum total number of monsters the heroes can defeat.

Sample Input 1

2
3 5 2
4 5

Sample Output 1

9

If the heroes choose the monsters to defeat as follows, they can defeat nine monsters in total, which is the maximum result.

The first hero defeats two monsters attacking the first town and two monsters attacking the second town.

The second hero defeats three monsters attacking the second town and two monsters attacking the third town.

Sample Input 2

3
5 6 3 8
5 100 8

Sample Output 2

22

Sample Input 3

2
100 1 1
1 100

Sample Output 3

3

Solution in C# (Mono 4.6.2.0) (judge verdict: Runtime Error)

using System;
using System.Text;
using System.Linq;
using System.Collections;
using System.Collections.Generic;
using static System.Console;
using static System.Math;

namespace AtCoder
{
    public class Program
    {
        public static void Main(string[] args)
        {
            new Program().Solve(new ConsoleInput(Console.In, ' '));

            return;
        }

        public void Solve(ConsoleInput cin)
        {

            var N = cin.ReadInt;
            var A = cin.ReadIntArray(N + 1);
            var B = cin.ReadIntArray(N);

            int[,] Beat = new int[N + 1, N + 1];
            for (int i = 0; i < N + 1; i++){
                for (int j = 0; j < N + 1; j++){
                    Beat[i, j] = 0;
                }
            }

            // N = 2のとき

            Beat[0, 0] = Min(A[0], B[0]);

            // Beat[1, 0] = Min(A[1], B[0] - Beat[0, 0]);
            // Beat[1, 1] = Min(A[1] - Beat[1, 0], B[1]);

            // Beat[2, 1] = Min(A[2], B[1] - Beat[1, 1]);
            // Beat[2, 2] = Min(A[2] - Beat[2, 1], B[2]);

            // Beat[3, 2] = Min(A[3], B[2] - Beat[2, 2])
            for (int i = 0; i < N - 1; i++){
                Beat[i + 1, i] = Min(A[i + 1], B[i] - Beat[i, i]);
                Beat[i + 1, i + 1] = Min(A[i + 1] - Beat[i + 1, i], B[i + 1]);
            }

            Beat[N, N - 1] = Min(A[N], B[N - 1] - Beat[N - 1, N - 1]);

            int SumBeat = 0;
            for (int i = 0; i < N + 1; i++){
                for (int j = 0; j < N + 1; j++){
                    SumBeat += Beat[i, j];
                }
            }

            Console.WriteLine(SumBeat);
            return;
        }
    }

    public static class Extensions
    {
        public static string Reverse(this string sourse)
        {
            char[] chrAry = sourse.ToCharArray();
            Array.Reverse(chrAry);
            return new string(chrAry);
        }
    }

    public class ConsoleInput
    {
        private readonly System.IO.TextReader _stream;
        private char _separator = ' ';
        private Queue<string> inputStream;
        public ConsoleInput(System.IO.TextReader stream, char separator = ' ')
        {
            this._separator = separator;
            this._stream = stream;
            inputStream = new Queue<string>();
        }
        public string Read
        {
            get
            {
                if (inputStream.Count != 0) return inputStream.Dequeue();
                string[] tmp = _stream.ReadLine().Split(_separator);
                for (int i = 0; i < tmp.Length; ++i)
                    inputStream.Enqueue(tmp[i]);
                return inputStream.Dequeue();
            }
        }
        public string ReadLine { get { return _stream.ReadLine(); } }
        public int ReadInt { get { return int.Parse(Read); } }
        public long ReadLong { get { return long.Parse(Read); } }
        public double ReadDouble { get { return double.Parse(Read); } }
        public string[] ReadStrArray(long N) { var ret = new string[N]; for (long i = 0; i < N; ++i) ret[i] = Read; return ret; }
        public int[] ReadIntArray(long N) { var ret = new int[N]; for (long i = 0; i < N; ++i) ret[i] = ReadInt; return ret; }
        public long[] ReadLongArray(long N) { var ret = new long[N]; for (long i = 0; i < N; ++i) ret[i] = ReadLong; return ret; }
    }
}