Problem:
Score : 300 points

Problem Statement

You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

1 \leq |S| \leq 2 \times 10^5

|S| = |T|

S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S and T can be made equal, print Yes; otherwise, print No.

Sample Input 1

azzel
apple

Sample Output 1

Yes

azzel can be changed to apple, as follows:

Choose e as c_1 and l as c_2. azzel becomes azzle.

Choose z as c_1 and p as c_2. azzle becomes apple.

Sample Input 2

chokudai
redcoder

Sample Output 2

No

No sequences of operation can change chokudai to redcoder.

Sample Input 3

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu

Sample Output 3

Yes

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

using System;
using System.Linq;
using System.Collections.Generic;
using System.Numerics;
using static System.Console;

class Solver {
    Scanner sc = new Scanner();

    public void Solve() {
        var S = ReadLine();
        var T = ReadLine();

        var same = new Dictionary<char, char>();
        for (int i = 0; i < S.Length; i++) {
            if (S[i] == T[i]) {
                if (!same.ContainsKey(S[i])) {
                    same.Add(S[i], T[i]);
                }
            }
        }


        var diff = new Dictionary<char, char>();
        var diff2 = new Dictionary<char, char>();
        for (int i = 0; i < S.Length; i++) {
            if (S[i] != T[i]) {
                if (diff.ContainsKey(T[i])) {
                    if (diff[T[i]] != S[i]) {
                        WriteLine("No");
                        return;
                    }
                } else {
                    diff.Add(T[i], S[i]);
                }

                if (diff2.ContainsKey(S[i])) {
                    if (diff2[S[i]] != T[i]) {
                        WriteLine("No");
                        return;
                    }
                } else {
                    diff2.Add(S[i], T[i]);
                }

                if (same.ContainsKey(S[i]) || same.ContainsKey(T[i])) {
                    WriteLine("No");
                    return;
                }
            }
        }



        WriteLine("Yes");
    }
}



class Scanner {
    string[] s;
    int i;

    char[] cs = new char[] { ' ' };

    public Scanner() {
        s = new string[0];
        i = 0;
    }

    public string next() {
        if (i < s.Length) return s[i++];
        string st = Console.ReadLine();
        while (st == "") st = Console.ReadLine();
        s = st.Split(cs, StringSplitOptions.RemoveEmptyEntries);
        if (s.Length == 0) return next();
        i = 0;
        return s[i++];
    }

    public int nextInt() {
        return int.Parse(next());
    }
    public int[] ArrayInt(int N, int add = 0) {
        int[] Array = new int[N];
        for (int i = 0; i < N; i++) {
            Array[i] = nextInt() + add;
        }
        return Array;
    }

    public long nextLong() {
        return long.Parse(next());
    }

    public long[] ArrayLong(int N, long add = 0) {
        long[] Array = new long[N];
        for (int i = 0; i < N; i++) {
            Array[i] = nextLong() + add;
        }
        return Array;
    }

    public double nextDouble() {
        return double.Parse(next());
    }

    public double[] ArrayDouble(int N, double add = 0) {
        double[] Array = new double[N];
        for (int i = 0; i < N; i++) {
            Array[i] = nextDouble() + add;
        }
        return Array;
    }
}

class Program {
    static void Main(string[] args) {
        Solver s = new Solver();
        s.Solve();
    }
}