Problem:
Score : 800 points

Problem Statement

Mr. Takahashi has in his room an art object with H rows and W columns, made up of H \times W blocks.
Each block has a color represented by a lowercase English letter (a-z).
The color of the block at the i-th row and j-th column is c_{i,j}.

Mr. Takahashi would like to dismantle the object, finding it a bit kitschy for his tastes.
The dismantling is processed by repeating the following operation:

Choose one of the W columns and push down that column one row.
The block at the bottom of that column disappears.

Each time the operation is performed, a cost is incurred.
Since blocks of the same color have a property to draw each other together, the cost of the operation is the number of the pairs of blocks (p, q) such that:

The block p is in the selected column.

The two blocks p and q are horizontally adjacent (before pushing down the column).

The two blocks p and q have the same color.

Mr. Takahashi dismantles the object by repeating the operation H \times W times to get rid of all the blocks.
Compute the minimum total cost to dismantle the object.

Constraints

1 ≤ H ≤ 300

2 ≤ W ≤ 300

All characters c_{i,j} are lowercase English letters (a-z).

Partial Score

In test cases worth 300 points, W = 3.

Input

The input is given from Standard Input in the following format:

H W
c_{1,1}c_{1,2}..c_{1,W}
c_{2,1}c_{2,2}..c_{2,W}
:
c_{H,1}c_{H,2}..c_{H,W}

Output

Print the minimum total cost to dismantle the object.

Sample Input 1

2 3
rrr
brg

Sample Output 1

2

For example, the total cost of 2 can be achieved by performing the operation as follows and this is the minimum value.

Sample Input 2

6 3
xya
xya
ayz
ayz
xaz
xaz

Sample Output 2

0

The total cost of 0 can be achieved by first pushing down all blocks of the middle column, then all of the left column, and all of the right column.

Sample Input 3

4 2
ay
xa
xy
ay

Sample Output 3

0

The total cost of 0 can be achieved by the following operations:

pushing down the right column one row;

pushing down the left column one row;

pushing down all of the right column;

and pushing down all of the left column.

Sample Input 4

5 5
aaaaa
abbba
ababa
abbba
aaaaa

Sample Output 4

24

Sample Input 5

7 10
xxxxxxxxxx
ccccxxffff
cxxcxxfxxx
cxxxxxffff
cxxcxxfxxx
ccccxxfxxx
xxxxxxxxxx

Sample Output 5

130

Solution in C# (.NET Core 3.1.201) (judge verdict: Time Limit Exceeded)

using System;
using System.Collections;
using System.Collections.Generic;
using System.Linq;
using CompLib.Collections;
using CompLib.Util;

public class Program
{
    int H, W;
    char[][] C;

    List<int>[][] ls;
    public void Solve()
    {
        var sc = new Scanner();
        // 1個の列
        // コスト0
        H = sc.NextInt();
        W = sc.NextInt();

        C = new char[H][];
        for (int i = 0; i < H; i++)
        {
            C[i] = sc.NextCharArray();
        }

        ls = new List<int>[W][];
        for (int i = 0; i < W; i++)
        {
            ls[i] = new List<int>['z' + 1];
            for (char c = 'a'; c <= 'z'; c++)
            {
                ls[i][c] = new List<int>();
            }
            for (int j = 0; j < H; j++)
            {
                ls[i][C[j][i]].Add(j);
            }
        }


        Console.WriteLine(Calc(0, W));
    }

    long Calc(int l, int r)
    {
        if (r - l <= 1) return 0;

        int m = (l + r) / 2;
        long left = Calc(l, m);
        long right = Calc(m, r);

        // mの2つ
        // m-1,m

        long[,] cost = new long[H + 1, H + 1];
        for (int ll = 0; ll <= H; ll++)
        {
            // 一致
            int cnt = 0;
            for (int i = 0; i + ll < H; i++)
            {
                if (C[i][m - 1] == C[i + ll][m]) cnt++;
            }
            for (int i = 0; i + ll < H; i++)
            {
                cost[i + ll, i] = cnt;
                // 一番下
                if (C[H - 1 - i - ll][m - 1] == C[H - i - 1][m]) cnt--;
            }
        }

        for (int rr = 0; rr <= H; rr++)
        {
            int cnt = 0;
            for (int i = 0; i + rr < H; i++)
            {
                if (C[i + rr][m - 1] == C[i][m]) cnt++;
            }

            for (int i = 0; i + rr < H; i++)
            {
                cost[i, i + rr] = cnt;
                if (C[H - i - 1][m - 1] == C[H - 1 - i - rr][m]) cnt--;
            }
        }

        long[,] dp = new long[H + 1, H + 1];
        for (int i = 0; i <= H; i++)
        {
            for (int j = 0; j <= H; j++)
            {
                dp[i, j] = long.MaxValue;
            }
        }

        dp[0, 0] = 0;
        var q = new PriorityQueue<(int left, int right, long c)>((l, r) => l.c.CompareTo(r.c));
        q.Enqueue((0, 0, 0));
        while (q.Count > 0)
        {
            var d = q.Dequeue();
            long cur = dp[d.left, d.right];
            if (cur < d.c) continue;
            long c = cost[d.left, d.right];
            if (d.left + 1 <= H && dp[d.left + 1, d.right] > cur + c)
            {
                dp[d.left + 1, d.right] = cur + c;
                q.Enqueue((d.left + 1, d.right, cur + c));
            }

            if (d.right + 1 <= H && dp[d.left, d.right + 1] > cur + c)
            {
                dp[d.left, d.right + 1] = cur + c;
                q.Enqueue((d.left, d.right + 1, cur + c));
            }
        }

        long min = dp[H, H];

        return left + min + right;
    }

    public static void Main(string[] args) => new Program().Solve();
}

// https://bitbucket.org/camypaper/complib
namespace CompLib.Collections
{
    using System;
    using System.Collections.Generic;

    #region PriorityQueue

    /// <summary>
    /// 指定した型のインスタンスを最も価値が低い順に取り出すことが可能な可変サイズのコレクションを表します．
    /// </summary>
    /// <typeparam name="T">優先度付きキュー内の要素の型を指定します．</typeparam>
    /// <remarks>内部的にはバイナリヒープによって実装されています．</remarks>
    public class PriorityQueue<T>
    {
        readonly List<T> heap = new List<T>();
        readonly Comparison<T> cmp;

        /// <summary>
        /// デフォルトの比較子を使用してインスタンスを初期化します．
        /// </summary>
        /// <remarks>この操作は O(1) で実行されます．</remarks>
        public PriorityQueue()
        {
            cmp = Comparer<T>.Default.Compare;
        }

        /// <summary>
        /// デリゲートで表されるような比較関数を使用してインスタンスを初期化します．
        /// </summary>
        /// <param name="comparison"></param>
        /// <remarks>この操作は O(1) で実行されます．</remarks>
        public PriorityQueue(Comparison<T> comparison)
        {
            cmp = comparison;
        }

        /// <summary>
        /// 指定された比較子を使用してインスタンスを初期化します．
        /// </summary>
        /// <param name="comparer"></param>
        /// <remarks>この操作は O(1) で実行されます．</remarks>
        public PriorityQueue(IComparer<T> comparer)
        {
            cmp = comparer.Compare;
        }

        /// <summary>
        /// 優先度付きキューに要素を追加します．
        /// </summary>
        /// <param name="item">優先度付きキューに追加される要素</param>
        /// <remarks>最悪計算量 O(log N) で実行されます．</remarks>
        public void Enqueue(T item)
        {
            var pos = heap.Count;
            heap.Add(item);
            while (pos > 0)
            {
                var par = (pos - 1) / 2;
                if (cmp(heap[par], item) <= 0)
                    break;
                heap[pos] = heap[par];
                pos = par;
            }

            heap[pos] = item;
        }

        /// <summary>
        /// 優先度付きキューから最も価値が低い要素を削除し，返します．
        /// </summary>
        /// <returns>優先度付きキューから削除された要素．</returns>
        /// <remarks>最悪計算量 O(log N) で実行されます．</remarks>
        public T Dequeue()
        {
            var ret = heap[0];
            var pos = 0;
            var x = heap[heap.Count - 1];

            while (pos * 2 + 1 < heap.Count - 1)
            {
                var lch = pos * 2 + 1;
                var rch = pos * 2 + 2;
                if (rch < heap.Count - 1 && cmp(heap[rch], heap[lch]) < 0) lch = rch;
                if (cmp(heap[lch], x) >= 0)
                    break;
                heap[pos] = heap[lch];
                pos = lch;
            }

            heap[pos] = x;
            heap.RemoveAt(heap.Count - 1);
            return ret;
        }

        /// <summary>
        ///  優先度付きキューに含まれる最も価値が低い要素を削除せずに返します．
        /// </summary>
        /// <returns>優先度付きキューに含まれる最も価値が低い要素．</returns>
        /// <remarks>この操作は O(1) で実行されます．</remarks>
        public T Peek()
        {
            return heap[0];
        }

        /// <summary>
        /// 優先度付きキュー内の要素の数を取得します．
        /// </summary>
        /// <returns>優先度付キュー内にある要素の数</returns>
        /// <remarks>最悪計算量 O(1) で実行されます．</remarks>
        public int Count
        {
            get { return heap.Count; }
        }

        /// <summary>
        /// 優先度付きキュー内に要素が存在するかどうかを O(1) で判定します．
        /// </summary>
        /// <returns>優先度付キュー内にある要素が存在するならば true，そうでなければ　false．</returns>
        /// <remarks>この操作は O(1) で実行されます．</remarks>
        public bool Any()
        {
            return heap.Count > 0;
        }

        /// <summary>
        /// 優先度付きキューに含まれる要素を昇順に並べて返します．
        /// </summary>
        /// <remarks>この操作は計算量 O(N log N)で実行されます．</remarks>
        public T[] Items
        {
            get
            {
                var ret = heap.ToArray();
                Array.Sort(ret, cmp);
                return ret;
            }
        }
    }

    #endregion
}

namespace CompLib.Util
{
    using System;
    using System.Linq;

    class Scanner
    {
        private string[] _line;
        private int _index;
        private const char Separator = ' ';

        public Scanner()
        {
            _line = new string[0];
            _index = 0;
        }

        public string Next()
        {
            if (_index >= _line.Length)
            {
                string s;
                do
                {
                    s = Console.ReadLine();
                } while (s.Length == 0);

                _line = s.Split(Separator);
                _index = 0;
            }

            return _line[_index++];
        }

        public string ReadLine()
        {
            _index = _line.Length;
            return Console.ReadLine();
        }

        public int NextInt() => int.Parse(Next());
        public long NextLong() => long.Parse(Next());
        public double NextDouble() => double.Parse(Next());
        public decimal NextDecimal() => decimal.Parse(Next());
        public char NextChar() => Next()[0];
        public char[] NextCharArray() => Next().ToCharArray();

        public string[] Array()
        {
            string s = Console.ReadLine();
            _line = s.Length == 0 ? new string[0] : s.Split(Separator);
            _index = _line.Length;
            return _line;
        }

        public int[] IntArray() => Array().Select(int.Parse).ToArray();
        public long[] LongArray() => Array().Select(long.Parse).ToArray();
        public double[] DoubleArray() => Array().Select(double.Parse).ToArray();
        public decimal[] DecimalArray() => Array().Select(decimal.Parse).ToArray();
    }
}