Problem:
Score : 200 points

Problem Statement

There are N gems. The value of the i-th gem is V_i.

You will choose some of these gems, possibly all or none, and get them.

However, you need to pay a cost of C_i to get the i-th gem.

Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid.

Find the maximum possible value of X-Y.

Constraints

All values in input are integers.

1 \leq N \leq 20

1 \leq C_i, V_i \leq 50

Input

Input is given from Standard Input in the following format:

N
V_1 V_2 ... V_N
C_1 C_2 ... C_N

Output

Print the maximum possible value of X-Y.

Sample Input 1

3
10 2 5
6 3 4

Sample Output 1

5

If we choose the first and third gems, X = 10 + 5 = 15 and Y = 6 + 4 = 10.
We have X-Y = 5 here, which is the maximum possible value.

Sample Input 2

4
13 21 6 19
11 30 6 15

Sample Output 2

6

Sample Input 3

1
1
50

Sample Output 3

0

Solution in C# (Mono 4.6.2.0) (judge verdict: Wrong Answer)

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
class Program
{
    static void Main(string[] args)
    {
        // 整数の入力
        int a = int.Parse(Console.ReadLine());
        // スペース区切りの整数の入力
        string[] inputv = Console.ReadLine().Split(' ');
        string[] inputc = Console.ReadLine().Split(' ');
        var vlist = new List<int>();
        var clist = new List<int>();       
        for (int i = 0; i < inputv.Length; i++)
        {
            int v = int.Parse(inputv[i]);
            vlist.Add(v);
            int c = int.Parse(inputc[i]);
            clist.Add(c);
        }
        int z = 0,sum = 0;
        for (int i = 0; i < inputc.Length; i++)
        {
            z = vlist[i] - clist[i];
            if (z > 0) sum += z;
        }
        //出力
        Console.WriteLine((z));
    }
}