Problem:
Score : 300 points

Problem Statement

There are N slimes lining up from left to right. The colors of these slimes will be given as a string S of length N consisting of lowercase English letters. The i-th slime from the left has the color that corresponds to the i-th character of S.

Adjacent slimes with the same color will fuse into one larger slime without changing the color. If there were a slime adjacent to this group of slimes before fusion, that slime is now adjacent to the new larger slime.

Ultimately, how many slimes will be there?

Constraints

1 \leq N \leq 10^5

|S| = N

S consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

N
S

Output

Print the final number of slimes.

Sample Input 1

10
aabbbbaaca

Sample Output 1

5

Ultimately, these slimes will fuse into abaca.

Sample Input 2

5
aaaaa

Sample Output 2

1

All the slimes will fuse into one.

Sample Input 3

20
xxzaffeeeeddfkkkkllq

Sample Output 3

10

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows;

namespace AtCoder
{
    class Program
    {
        static void Main()
        {
            //ここから

            var N = IO.ReadLineToInt();
            var S = IO.ReadLineToString();

            var sum = 1;
            for(int i = 0; i < N-1; i++)
            {
                if (S[i] != S[i + 1])
                {
                    sum++;
                }
            }

            //ここまで
            Console.WriteLine(sum);
            Console.ReadKey();
        }
    }

    static class Func
    {
        static long mod = 1000000007;
        static public void Swap<T>(ref T a, ref T b) { T temp = a; a = b; b = temp; }
        static public long GCD(long a, long b) { return b != 0 ? GCD(b, a % b) : a; }
        static public long LCM(long a, long b) { return (long)a * b / GCD(a, b); }
        static public int Factorial(int a) { return a == 1 ? a : a * Factorial(a - 1); }
        static public int Conbin(int n, int m) { return Factorial(n) / (Factorial(n - m) * Factorial(m)); }

        static public void Factoring(long num, ref long[] vs)
        {
            if (num == 1)
            {
                vs[1]++;
            }
            for (long i = 2; i < (long)Math.Sqrt(num); i++)
            {
                if (num % i == 0)
                {
                    vs[i]++;
                    Factoring(num / i, ref vs);
                }
            }
            vs[1]++;
        }
    }

    static class IO
    {
        static public string ReadLineToString() { return Console.ReadLine(); }
        static public int ReadLineToInt() { return int.Parse(Console.ReadLine()); }
        static public long ReadLineToLong() { return long.Parse(Console.ReadLine()); }
        static public List<string> ReadLineToStringArray() { return Console.ReadLine().Split(' ').ToList(); }
        static public int[] ReadLineToIntArray() { return Console.ReadLine().Split(' ').Select(int.Parse).ToArray(); }
        static public long[] ReadLineToLongArray() { return Console.ReadLine().Split(' ').Select(long.Parse).ToArray(); }
        static public List<string> ReadLineToStringList() { return Console.ReadLine().Split(' ').ToList(); }
        static public List<int> ReadLineToIntList() { return Console.ReadLine().Split(' ').Select(int.Parse).ToList(); }
        static public List<long> ReadLineToLongList() { return Console.ReadLine().Split(' ').Select(long.Parse).ToList(); }
    }
}