Problem:
Score : 100 points

Problem Statement

You have three tasks, all of which need to be completed.

First, you can complete any one task at cost 0.

Then, just after completing the i-th task, you can complete the j-th task at cost |A_j - A_i|.

Here, |x| denotes the absolute value of x.

Find the minimum total cost required to complete all the task.

Constraints

All values in input are integers.

1 \leq A_1, A_2, A_3 \leq 100

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

Print the minimum total cost required to complete all the task.

Sample Input 1

1 6 3

Sample Output 1

5

When the tasks are completed in the following order, the total cost will be 5, which is the minimum:

Complete the first task at cost 0.

Complete the third task at cost 2.

Complete the second task at cost 3.

Sample Input 2

11 5 5

Sample Output 2

6

Sample Input 3

100 100 100

Sample Output 3

0

Solution in C# (Mono 4.6.2.0) (judge verdict: Wrong Answer)

using System;
using static System.Console;
using static System.Math;
using System.Collections.Generic;
using System.Linq;
 
class Program
{
    public static void Main()
    {
        int[] A = new int[3];
        var input = ReadLine().Split();
        foreach (int i in EnumerableCommon.Range(3)) A[i] = int.Parse(input[i]);
 
        List<int> costArray = new List<int>();
        foreach (int i in EnumerableCommon.Range(3))
        {
            foreach (int j in EnumerableCommon.Range(3))
            {
              if(i == j)break;
                List<int> idx = new List<int>(3) { 0, 1, 2 };
                int cost = 0;
                cost += Abs(A[j] - A[i]);
                idx.Remove(i); idx.Remove(j);
                cost += Abs(A[idx[0]] - A[j]);
                costArray.Add(cost);
            }
        }
 
        WriteLine(costArray.Min());
    }
 
 
    public static partial class EnumerableCommon
    {
        public static IEnumerable<int> Range(int count)
        {
            return Enumerable.Range(0, count);
        }
    }
}