Problem:
Score : 300 points

Problem Statement

"Pizza At", a fast food chain, offers three kinds of pizza: "A-pizza", "B-pizza" and "AB-pizza". A-pizza and B-pizza are completely different pizzas, and AB-pizza is one half of A-pizza and one half of B-pizza combined together. The prices of one A-pizza, B-pizza and AB-pizza are A yen, B yen and C yen (yen is the currency of Japan), respectively.

Nakahashi needs to prepare X A-pizzas and Y B-pizzas for a party tonight. He can only obtain these pizzas by directly buying A-pizzas and B-pizzas, or buying two AB-pizzas and then rearrange them into one A-pizza and one B-pizza. At least how much money does he need for this? It is fine to have more pizzas than necessary by rearranging pizzas.

Constraints

1 ≤ A, B, C ≤ 5000

1 ≤ X, Y ≤ 10^5

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B C X Y

Output

Print the minimum amount of money required to prepare X A-pizzas and Y B-pizzas.

Sample Input 1

1500 2000 1600 3 2

Sample Output 1

7900

It is optimal to buy four AB-pizzas and rearrange them into two A-pizzas and two B-pizzas, then buy additional one A-pizza.

Sample Input 2

1500 2000 1900 3 2

Sample Output 2

8500

It is optimal to directly buy three A-pizzas and two B-pizzas.

Sample Input 3

1500 2000 500 90000 100000

Sample Output 3

100000000

It is optimal to buy 200000 AB-pizzas and rearrange them into 100000 A-pizzas and 100000 B-pizzas. We will have 10000 more A-pizzas than necessary, but that is fine.

Solution in C# (Mono 4.6.2.0) (judge verdict: Wrong Answer)

using System;
class Program
{
	static void Main()
	{
	string[] input = Console.ReadLine().Split(' ');//Splitで区切り文字を指定して複数個受け取る。
	int a = int.Parse(input[0]);
	int b = int.Parse(input[1]);
    int c = int.Parse(input[2]);
    int x = int.Parse(input[3]);
    int y = int.Parse(input[4]);
    
	if(a<=c*2 && b<=c*2)//cが高い
     	 Console.WriteLine(a*x + b*y);
    if(a>c*2 && b>c*2)//cが安い
    	{
      	if(x>y)Console.WriteLine(c*x);
      	else Console.WriteLine(c*y);
    	}
    if(a>c*2 && b<=c*2)//aだけ高い
    	{
      	if(y <= 2*x)Console.WriteLine(2*c*x);
      	else Console.WriteLine(2*c*x + b*(y - 2*x));
    	}
    if(a<=c*2 && b>c*2)//bだけ高い
    	{
      	if(x <= 2*y)Console.WriteLine(2*c*y);
      	else Console.WriteLine(2*c*y + b*(x - 2*y));
    	}
	}
}