Problem:
Score : 300 points

Problem Statement

You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

1 \leq |S| \leq 2 \times 10^5

|S| = |T|

S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S and T can be made equal, print Yes; otherwise, print No.

Sample Input 1

azzel
apple

Sample Output 1

Yes

azzel can be changed to apple, as follows:

Choose e as c_1 and l as c_2. azzel becomes azzle.

Choose z as c_1 and p as c_2. azzle becomes apple.

Sample Input 2

chokudai
redcoder

Sample Output 2

No

No sequences of operation can change chokudai to redcoder.

Sample Input 3

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu

Sample Output 3

Yes

Solution in C# (Mono 4.6.2.0) (judge verdict: Wrong Answer)

using System;
using System.Linq;
using System.Collections;
using System.Collections.Generic;

namespace AtCoderABC086
{
    class Program
    {
        public static void Main(string[] args)
        {
            string S = Console.ReadLine();
            string T = Console.ReadLine();
            bool flag = true;
            Dictionary<char, int> dictS =  new Dictionary<char, int>();
            Dictionary<char, int> dictT =  new Dictionary<char, int>();
            for (int i = 0; i < S.Length; i++)
            {
                if (dictS.ContainsKey(S[i]))
                {
                    if (T[i] != T[dictS[S[i]]])
                    flag = false;
                    break;
                }
                if (dictT.ContainsKey(T[i]))
                {
                    if (S[i] != S[dictT[T[i]]])
                    flag = false;
                    break;
                }
                if (S[i] != T[i])
                {
                    dictS[S[i]] = i;
                    dictT[T[i]] = i;
                }
            }
            Console.WriteLine((flag)? "Yes": "No");
        }
    }
}