Problem:
Score : 200 points

Problem Statement

There are N positive integers written on a blackboard: A_1, ..., A_N.

Snuke can perform the following operation when all integers on the blackboard are even:

Replace each integer X on the blackboard by X divided by 2.

Find the maximum possible number of operations that Snuke can perform.

Constraints

1 \leq N \leq 200

1 \leq A_i \leq 10^9

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

Print the maximum possible number of operations that Snuke can perform.

Sample Input 1

3
8 12 40

Sample Output 1

2

Initially, [8, 12, 40] are written on the blackboard.
Since all those integers are even, Snuke can perform the operation.

After the operation is performed once, [4, 6, 20] are written on the blackboard.
Since all those integers are again even, he can perform the operation.

After the operation is performed twice, [2, 3, 10] are written on the blackboard.
Now, there is an odd number 3 on the blackboard, so he cannot perform the operation any more.

Thus, Snuke can perform the operation at most twice.

Sample Input 2

4
5 6 8 10

Sample Output 2

0

Since there is an odd number 5 on the blackboard already in the beginning, Snuke cannot perform the operation at all.

Sample Input 3

6
382253568 723152896 37802240 379425024 404894720 471526144

Sample Output 3

8

Solution in C# (.NET Core 3.1.201) (judge verdict: Accepted)

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace atcoder_081B
{
    class Program
    {
        static void Main(string[] args)
        {
            
            int n =int.Parse( Console.ReadLine());
            string[] array = new string[n];
            string s = Console.ReadLine();
            array = s.Split();
           
            int[] data = new int[n];
            for(int i = 0;i<array.Length;i++)
            {
                data[i] = int.Parse(array[i]);
            }
            int sum = 0;
            while (true)
            {
                bool a = false;
                for (int i = 0; i < array.Length; i++)
                {
                    if(data[i]%2 != 0)
                    {
                        a = true;
                        break;
                    }
                }
                if(a == true)
                {
                    break;
                }
                else
                {
                    sum++;
                }
               
                for (int i = 0; i < array.Length; i++)
                {
                    data[i] = data[i] / 2;
                }

            }

            Console.WriteLine(sum);

            Console.ReadLine();

        }
    }
}