Problem:
Score : 100 points

Problem Statement

Given are three integers A_1, A_2, and A_3.

If A_1+A_2+A_3 is greater than or equal to 22, print bust; otherwise, print win.

Constraints

1 \leq A_i \leq 13 \ \ (i=1,2,3)

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

If A_1+A_2+A_3 is greater than or equal to 22, print bust; otherwise, print win.

Sample Input 1

5 7 9

Sample Output 1

win

5+7+9=21, so print win.

Sample Input 2

13 7 2

Sample Output 2

bust

13+7+2=22, so print bust.

Solution in C# (.NET Core 3.1.201) (judge verdict: Accepted)

using System;
using System.Collections.Generic;
using System.Dynamic;
using System.Linq;

namespace atcorder
{
    class Program
    {
        static void Main(string[] args)
        {
            int[] intArray = Console.ReadLine().Split(' ').Select(i => int.Parse(i)).ToArray();
            int A1 = intArray[0];
            int A2 = intArray[1];
            int A3 = intArray[2];
            if(A1 + A2 + A3 <= 21)
            {
                Console.WriteLine("win");
            }
            else
            {
                Console.WriteLine("bust");
            }
        }
    }
}

//文字配列の取得
//string[] strArray = Console.ReadLine().Split(' ').ToArray();
//string S = strArray[0];
//string T = strArray[1];

//文字列の取得
//string s = Console.ReadLine();

//数字配列の取得
//int[] intArray = Console.ReadLine().Split(' ').Select(i => int.Parse(i)).ToArray();
//int H = intArray[0];
//int W = intArray[1];

//数字の取得
//int N = int.Parse(Console.ReadLine());

//リスト型(int)の取得
//List<int> A = new List<int>(Console.ReadLine().Split(' ').Select(i => int.Parse(i)).ToArray());

//出力
//Console.WriteLine(ans);
//Console.WriteLine("Yes");
//Console.WriteLine("No");
//Console.WriteLine(cnt);