Problem:
Score : 300 points

Problem Statement

You are given an undirected unweighted graph with N vertices and M edges that contains neither self-loops nor double edges.

Here, a self-loop is an edge where a_i = b_i (1≤i≤M), and double edges are two edges where (a_i,b_i)=(a_j,b_j) or (a_i,b_i)=(b_j,a_j) (1≤i<j≤M).

How many different paths start from vertex 1 and visit all the vertices exactly once?

Here, the endpoints of a path are considered visited.

For example, let us assume that the following undirected graph shown in Figure 1 is given.

Figure 1: an example of an undirected graph

The following path shown in Figure 2 satisfies the condition.

Figure 2: an example of a path that satisfies the condition

However, the following path shown in Figure 3 does not satisfy the condition, because it does not visit all the vertices.

Figure 3: an example of a path that does not satisfy the condition

Neither the following path shown in Figure 4, because it does not start from vertex 1.

Figure 4: another example of a path that does not satisfy the condition

Constraints

2≦N≦8

0≦M≦N(N-1)/2

1≦a_i<b_i≦N

The given graph contains neither self-loops nor double edges.

Input

The input is given from Standard Input in the following format:

N M
a_1 b_1
a_2 b_2
:
a_M b_M

Output

Print the number of the different paths that start from vertex 1 and visit all the vertices exactly once.

Sample Input 1

3 3
1 2
1 3
2 3

Sample Output 1

2

The given graph is shown in the following figure:

The following two paths satisfy the condition:

Sample Input 2

7 7
1 3
2 7
3 4
4 5
4 6
5 6
6 7

Sample Output 2

1

This test case is the same as the one described in the problem statement.

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

using System;
using System.Collections;
using System.Collections.Generic;
using System.Linq;
using System.IO;
using System.Text;

class Prog
{
    public Prog() { }
    public static int Main()
    {
        new Prog().calc();
        return 0;
    }

    const int nmax =  8;
    bool[,] graph = new bool[nmax, nmax];

    Scanner cin;
    

    public void calc()
    {
        cin = new Scanner();
        int N = cin.nextInt();
        int M = cin.nextInt();

        for(int i = 0;i<M;i++)
        {
            int A = cin.nextInt();
            int B = cin.nextInt();
            graph[A - 1, B - 1] = true;
            graph[B - 1, A - 1] = true;
        }

        bool[] visited = new bool[nmax];

        visited[0] = true;
        Console.WriteLine(dfs(0, N, visited));
    }

    int dfs(int v, int N, bool[] visited)
    {
        bool all_visited = true;
        for(int i = 0;i<N;i++)
        {
            if (!visited[i]) all_visited = false;
        }
        if (all_visited) return 1;

        int ret = 0;
        for (int i = 0; i < N; i++)
        {
            if (!graph[v, i]) continue;
            if (visited[i]) continue;

            visited[i] = true;
            ret += dfs(i, N, visited);
            visited[i] = false;
        }

        return ret;
    }   
}


class Scanner
{
    string[] s;
    int i;

    char[] cs = new char[] { ' ' };

    public Scanner()
    {
        s = new string[0];
        i = 0;
    }

    public string next()
    {
        if (i < s.Length) return s[i++];
        string st = Console.ReadLine();
        while (st == "") st = Console.ReadLine();
        s = st.Split(cs, StringSplitOptions.RemoveEmptyEntries);
        i = 0;
        return s[i++];
    }

    public int nextInt()
    {
        return int.Parse(next());
    }

    public long nextLong()
    {
        return long.Parse(next());
    }

    public double nextDouble()
    {
        return double.Parse(next());
    }

}