Problem:
Score : 400 points

Problem Statement

Takahashi has a string S consisting of lowercase English letters.

Starting with this string, he will produce a new one in the procedure given as follows.

The procedure consists of Q operations. In Operation i (1 \leq i \leq Q), an integer T_i is provided, which means the following:

If T_i = 1: reverse the string S.

If T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.

If F_i = 1 : Add C_i to the beginning of the string S.

If F_i = 2 : Add C_i to the end of the string S.

Help Takahashi by finding the final string that results from the procedure.

Constraints

1 \leq |S| \leq 10^5

S consists of lowercase English letters.

1 \leq Q \leq 2 \times 10^5

T_i = 1 or 2.

F_i = 1 or 2, if provided.

C_i is a lowercase English letter, if provided.

Input

Input is given from Standard Input in the following format:

S
Q
Query_1
:
Query_Q

In the 3-rd through the (Q+2)-th lines, Query_i is one of the following:

1

which means T_i = 1, and:

2 F_i C_i

which means T_i = 2.

Output

Print the resulting string.

Sample Input 1

a
4
2 1 p
1
2 2 c
1

Sample Output 1

cpa

There will be Q = 4 operations. Initially, S is a.

Operation 1: Add p at the beginning of S. S becomes pa.

Operation 2: Reverse S. S becomes ap.

Operation 3: Add c at the end of S. S becomes apc.

Operation 4: Reverse S. S becomes cpa.

Thus, the resulting string is cpa.

Sample Input 2

a
6
2 2 a
2 1 b
1
2 2 c
1
1

Sample Output 2

aabc

There will be Q = 6 operations. Initially, S is a.

Operation 1: S becomes aa.

Operation 2: S becomes baa.

Operation 3: S becomes aab.

Operation 4: S becomes aabc.

Operation 5: S becomes cbaa.

Operation 6: S becomes aabc.

Thus, the resulting string is aabc.

Sample Input 3

y
1
2 1 x

Sample Output 3

xy

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

using System;
using System.Collections;
using System.Collections.Generic;
using System.IO;
using System.Linq;
using System.Text;

namespace D
{
    public class Program
    {
        static void Main(string[] args)
        {
            var sw = new StreamWriter(Console.OpenStandardOutput()) { AutoFlush = false };
            Console.SetOut(sw);
            Solve();
            Console.Out.Flush();
        }

        public static void Solve()
        {
            var s = Console.ReadLine();
            var q = int.Parse(Console.ReadLine());
            var rightBuilder = new StringBuilder(s, q);
            var leftBuilder = new StringBuilder(q);
            var isReverse = false;

            for (var i = 0; i < q; i++)
            {
                var query = Console.ReadLine().Trim().Split(' ');
                if (query[0] == "1")
                {
                    isReverse = !isReverse;
                }
                else if (query[0] == "2")
                {
                    if (query[1] == "1")
                    {
                        if (isReverse) rightBuilder.Append(query[2]);
                        else leftBuilder.Append(query[2]);

                    }
                    else if (query[1] == "2")
                    {
                        if (isReverse) leftBuilder.Append(query[2]);
                        else rightBuilder.Append(query[2]);
                    }
                }
            }
            var right = rightBuilder.ToString();
            var left = leftBuilder.ToString();
            var result = isReverse ? Reverse(right) + left : Reverse(left) + right;
            Console.WriteLine(result);
        }

        static string Reverse(string str)
        {
            var chars = str.ToCharArray();
            var length = chars.Length;
            for (var i = 0; i < length / 2; i++)
            {
                var tmp = chars[i];
                chars[i] = chars[length - i - 1];
                chars[length - i - 1] = tmp;
            }
            return new string(chars);
        }

    }
}