Problem:
Score : 200 points

Problem Statement

Takahashi has many red balls and blue balls. Now, he will place them in a row.

Initially, there is no ball placed.

Takahashi, who is very patient, will do the following operation 10^{100} times:

Place A blue balls at the end of the row of balls already placed. Then, place B red balls at the end of the row.

How many blue balls will be there among the first N balls in the row of balls made this way?

Constraints

1 \leq N \leq 10^{18}

A, B \geq 0

0 < A + B \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N A B

Output

Print the number of blue balls that will be there among the first N balls in the row of balls.

Sample Input 1

8 3 4

Sample Output 1

4

Let b denote a blue ball, and r denote a red ball. The first eight balls in the row will be bbbrrrrb, among which there are four blue balls.

Sample Input 2

8 0 4

Sample Output 2

0

He placed only red balls from the beginning.

Sample Input 3

6 2 4

Sample Output 3

2

Among bbrrrr, there are two blue balls.

Solution in C# (Mono 4.6.2.0) (judge verdict: Wrong Answer)

using System;
using System.Collections.Generic;
using System.Linq;

namespace ConsoleApp1
{
    class Program
    {
        /*static void Main(string[] args)
        {
            var taxp = Console.ReadLine().Split(' ');
            var t8 = int.Parse(taxp[0]);
            var t10 = int.Parse(taxp[1]);

            var t8ans = (t8 / 0.08);
            var t10ans = (t10 / 0.1);

            if ((int)t8ans == (int)t10ans)
            {
                Console.WriteLine(t8ans);
            }
            else
            {
                var t = (int)t8ans - 10;
                for (var i = 0; 20 > i; i++)
                {
                    if (((int)((t + i) * 0.08) == t8) && ((int)((t + i) * 0.1) == t10))
                    {
                        Console.WriteLine(t + i);
                    }
                }

                Console.WriteLine(-1);
            }
        }*/

        static void Main()
        {
            var line1 = Console.ReadLine().Split(' ');
            long n = long.Parse(line1[0]);
            long a = long.Parse(line1[1]);
            long b = long.Parse(line1[2]);

            var f = n % (a + b);
            var s = n / (a + b);
            var q = a * s;
            if (f > b) q += f - s * (a + b);
            else q += f;
            Console.WriteLine(q);
        }
    }
}