Problem:
Score : 200 points

Problem Statement

Takahashi loves gold coins. He gains 1000 happiness points for each 500-yen coin he has and gains 5 happiness points for each 5-yen coin he has. (Yen is the currency of Japan.)

Takahashi has X yen. If he exchanges his money so that he will gain the most happiness points, how many happiness points will he earn?

(We assume that there are six kinds of coins available: 500-yen, 100-yen, 50-yen, 10-yen, 5-yen, and 1-yen coins.)

Constraints

0 \leq X \leq 10^9

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print the maximum number of happiness points that can be earned.

Sample Input 1

1024

Sample Output 1

2020

By exchanging his money so that he gets two 500-yen coins and four 5-yen coins, he gains 2020 happiness points, which is the maximum number of happiness points that can be earned.

Sample Input 2

0

Sample Output 2

0

He is penniless - or yenless.

Sample Input 3

1000000000

Sample Output 3

2000000000

He is a billionaire - in yen.

Solution in C# (.NET Core 3.1.201) (judge verdict: Wrong Answer)

using System;

namespace abc160_b
{
    class Program
    {
        static void Main(string[] args)
        {
            int x = int.Parse(Console.ReadLine());

            int coinCount500 = x / 500;
            int sum = 0;

            int x5 = 0;

            for (int i = 1; i <= coinCount500; i++)
            {
                sum += 1000;
                x5 = x % 500;
            }

            int coinCount5 = x5 / 5;

            for (int j = 1; j <= coinCount5; j++)
            {
                sum += 5;
            }
            Console.WriteLine(sum);
        }
    }
}