Problem:
Score : 300 points

Problem Statement

"Pizza At", a fast food chain, offers three kinds of pizza: "A-pizza", "B-pizza" and "AB-pizza". A-pizza and B-pizza are completely different pizzas, and AB-pizza is one half of A-pizza and one half of B-pizza combined together. The prices of one A-pizza, B-pizza and AB-pizza are A yen, B yen and C yen (yen is the currency of Japan), respectively.

Nakahashi needs to prepare X A-pizzas and Y B-pizzas for a party tonight. He can only obtain these pizzas by directly buying A-pizzas and B-pizzas, or buying two AB-pizzas and then rearrange them into one A-pizza and one B-pizza. At least how much money does he need for this? It is fine to have more pizzas than necessary by rearranging pizzas.

Constraints

1 ≤ A, B, C ≤ 5000

1 ≤ X, Y ≤ 10^5

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B C X Y

Output

Print the minimum amount of money required to prepare X A-pizzas and Y B-pizzas.

Sample Input 1

1500 2000 1600 3 2

Sample Output 1

7900

It is optimal to buy four AB-pizzas and rearrange them into two A-pizzas and two B-pizzas, then buy additional one A-pizza.

Sample Input 2

1500 2000 1900 3 2

Sample Output 2

8500

It is optimal to directly buy three A-pizzas and two B-pizzas.

Sample Input 3

1500 2000 500 90000 100000

Sample Output 3

100000000

It is optimal to buy 200000 AB-pizzas and rearrange them into 100000 A-pizzas and 100000 B-pizzas. We will have 10000 more A-pizzas than necessary, but that is fine.

Solution in C# (Mono 4.6.2.0) (judge verdict: Wrong Answer)

using System;
using System.Linq;
using System.Collections;
using System.Collections.Generic;
using System.Text;

class Program
{
    static void Main(string[] args)
    {
        // 入力
        int[] abcxy = Console.ReadLine().Split().Select(int.Parse).ToArray();
        var a = abcxy[0];
        var b = abcxy[1];
        var c = abcxy[2];
        var d = abcxy[3];
        var e = abcxy[4];

        // ABピザを使わない場合
        var ans = a * d + b * e;

        // ABピザを使う場合
        if (a > c)
        {
            var tmp = c * d * 2;
            if (e > d)
            {
                tmp += b * (e - d);
            }
            ans = Math.Min(ans, tmp);
        }

        if (b > c)
        {
            var tmp = c * e * 2;
            if (d > e)
            {
                tmp += a * (d - e);
            }
            ans = Math.Min(ans, tmp);

        }

        if (a > c && b > c)
        {
            if (d > e)
            {
                ans = Math.Min(ans, c * d * 2);
            }
            else
            {
                ans = Math.Min(ans, c * e * 2);
            }

        }


        Console.WriteLine(ans);
    }
}