Problem:
Score : 400 points

Problem Statement

Takahashi has a string S consisting of lowercase English letters.

Starting with this string, he will produce a new one in the procedure given as follows.

The procedure consists of Q operations. In Operation i (1 \leq i \leq Q), an integer T_i is provided, which means the following:

If T_i = 1: reverse the string S.

If T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.

If F_i = 1 : Add C_i to the beginning of the string S.

If F_i = 2 : Add C_i to the end of the string S.

Help Takahashi by finding the final string that results from the procedure.

Constraints

1 \leq |S| \leq 10^5

S consists of lowercase English letters.

1 \leq Q \leq 2 \times 10^5

T_i = 1 or 2.

F_i = 1 or 2, if provided.

C_i is a lowercase English letter, if provided.

Input

Input is given from Standard Input in the following format:

S
Q
Query_1
:
Query_Q

In the 3-rd through the (Q+2)-th lines, Query_i is one of the following:

1

which means T_i = 1, and:

2 F_i C_i

which means T_i = 2.

Output

Print the resulting string.

Sample Input 1

a
4
2 1 p
1
2 2 c
1

Sample Output 1

cpa

There will be Q = 4 operations. Initially, S is a.

Operation 1: Add p at the beginning of S. S becomes pa.

Operation 2: Reverse S. S becomes ap.

Operation 3: Add c at the end of S. S becomes apc.

Operation 4: Reverse S. S becomes cpa.

Thus, the resulting string is cpa.

Sample Input 2

a
6
2 2 a
2 1 b
1
2 2 c
1
1

Sample Output 2

aabc

There will be Q = 6 operations. Initially, S is a.

Operation 1: S becomes aa.

Operation 2: S becomes baa.

Operation 3: S becomes aab.

Operation 4: S becomes aabc.

Operation 5: S becomes cbaa.

Operation 6: S becomes aabc.

Thus, the resulting string is aabc.

Sample Input 3

y
1
2 1 x

Sample Output 3

xy

Solution in C# (Mono 4.6.2.0) (judge verdict: Wrong Answer)

using System;
using System.Text;
using System.Linq;

public class ABC158_D {
	private static void Main(string[] args) {
		var s = ReadStr();
		var q = ReadInt();

		var isReversed = false;
		var sbHead = new StringBuilder("");
		var sbTail = new StringBuilder("");
		
		for (int i = 0; i < q; i++) {
			var currentQuery = ReadStrsAsArray();
			var t = currentQuery[0];

			if (t == "1") {
				isReversed = !isReversed;

			} else {
				var f = currentQuery[1];
				var c = currentQuery[2];

				if (IsHead(f, isReversed)) sbHead.Append(c);
				else sbTail.Append(c);
			}
		}

		var head = (isReversed) ? sbTail.ToString() : sbHead.ToString();
		head = new string(head.Reverse().ToArray());
		var tail = (isReversed) ? sbHead.ToString() : sbTail.ToString();

		var answer = head + s + tail;
		Console.WriteLine(answer);
	}

	private static string ReadStr() => Console.ReadLine().Trim();
	private static string[] ReadStrsAsArray() => Console.ReadLine().Trim().Split();
	private static int ReadInt() => int.Parse(Console.ReadLine().Trim());
	private static string ReverseString (string str) => new string(str.Reverse().ToArray());
	private static bool IsHead(string f, bool isReversed) => (((f == "2") && (isReversed)) || ((f == "1") && (!isReversed)));
}