Problem:
Score : 300 points

Problem Statement

There are N observatories in AtCoder Hill, called Obs. 1, Obs. 2, ..., Obs. N. The elevation of Obs. i is H_i.
There are also M roads, each connecting two different observatories. Road j connects Obs. A_j and Obs. B_j.

Obs. i is said to be good when its elevation is higher than those of all observatories that can be reached from Obs. i using just one road.
Note that Obs. i is also good when no observatory can be reached from Obs. i using just one road.

How many good observatories are there?

Constraints

2 \leq N \leq 10^5

1 \leq M \leq 10^5

1 \leq H_i \leq 10^9

1 \leq A_i,B_i \leq N

A_i \neq B_i

Multiple roads may connect the same pair of observatories.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M
H_1 H_2 ... H_N
A_1 B_1
A_2 B_2
:
A_M B_M

Output

Print the number of good observatories.

Sample Input 1

4 3
1 2 3 4
1 3
2 3
2 4

Sample Output 1

2

From Obs. 1, you can reach Obs. 3 using just one road. The elevation of Obs. 1 is not higher than that of Obs. 3, so Obs. 1 is not good.

From Obs. 2, you can reach Obs. 3 and 4 using just one road. The elevation of Obs. 2 is not higher than that of Obs. 3, so Obs. 2 is not good.

From Obs. 3, you can reach Obs. 1 and 2 using just one road. The elevation of Obs. 3 is higher than those of Obs. 1 and 2, so Obs. 3 is good.

From Obs. 4, you can reach Obs. 2 using just one road. The elevation of Obs. 4 is higher than that of Obs. 2, so Obs. 4 is good.

Thus, the good observatories are Obs. 3 and 4, so there are two good observatories.

Sample Input 2

6 5
8 6 9 1 2 1
1 3
4 2
4 3
4 6
4 6

Sample Output 2

3

Solution in C# (.NET Core 3.1.201) (judge verdict: Wrong Answer)

using System;
using System.Text;
using System.Linq;
using System.Collections;
using System.Collections.Generic;
using static System.Math;
using static System.Console;
using static exMath;
using static exReadLine;


class Program
{
    static void Main(string[] args)
    {
        int N, M;
        intReadLine(out N, out M);
        int[] H = intArrayReadLine();
        bool[] hasRoad = new bool[N];
        bool[] isGood = new bool[N];
        for (int i = 0; i < M; i++)
        {
            int A, B;
            intReadLine(out A, out B);
            hasRoad[A - 1] = true;
            hasRoad[B - 1] = true;
            if (H[A - 1] > H[B - 1])
            {
                isGood[A - 1] = true;
                isGood[B - 1] = false;
            }
            else if(H[A - 1] == H[B - 1])
            {
                isGood[A - 1] = false;
                isGood[B - 1] = false;
            }
            else
            {
                isGood[A - 1] = false;
                isGood[B - 1] = true;
            }
        }

        int ans = 0;
        for (int i = 0; i < N; i++)
        {
            if (isGood[i])
            {
                ans++;
            }
            else
            {
                if (!hasRoad[i])
                {
                    ans++;
                }
            }
        }
        WriteLine(ans);
        //ReadLine();
    }
}

static class exReadLine
{
    public static void intReadLine(out int a)
    {
        a = int.Parse(ReadLine());
    }
    public static void intReadLine(out int a, out int b)
    {
        int[] input = ReadLine().Split().Select(int.Parse).ToArray();
        a = input[0];
        b = input[1];
    }
    public static void intReadLine(out int a, out int b, out int c)
    {
        int[] input = ReadLine().Split().Select(int.Parse).ToArray();
        a = input[0];
        b = input[1];
        c = input[2];
    }
    public static void intReadLine(out int a, out int b, out int c, out int d)
    {
        int[] input = ReadLine().Split().Select(int.Parse).ToArray();
        a = input[0];
        b = input[1];
        c = input[2];
        d = input[3];
    }

    public static void longReadLine(out long a)
    {
        a = long.Parse(ReadLine());
    }
    public static void longReadLine(out long a, out long b)
    {
        long[] input = ReadLine().Split().Select(long.Parse).ToArray();
        a = input[0];
        b = input[1];
    }
    public static void longReadLine(out long a, out long b, out long c)
    {
        long[] input = ReadLine().Split().Select(long.Parse).ToArray();
        a = input[0];
        b = input[1];
        c = input[2];
    }
    public static void longReadLine(out long a, out long b, out long c, out long d)
    {
        long[] input = ReadLine().Split().Select(long.Parse).ToArray();
        a = input[0];
        b = input[1];
        c = input[2];
        d = input[3];
    }
    
    public static int[] intArrayReadLine()
    {
        return ReadLine().Split().Select(int.Parse).ToArray();
    }

    public static long[] longArrayReadLine()
    {
        return ReadLine().Split().Select(long.Parse).ToArray();
    }

    public static List<int> intListReadLine()
    {
        return ReadLine().Split().Select(int.Parse).ToList();
    }

    public static List<long> longListReadLine()
    {
        return ReadLine().Split().Select(long.Parse).ToList();
    }
}

static class exMath
{
    // 最大公約数
    public static int Gcd(int a, int b)
    {
        if (a < b) return Gcd(b, a);
        while (b != 0)
        {
            var r = a % b;
            a = b;
            b = r;
        }
        return a;
    }
    public static long Gcd(long a, long b)
    {
        if (a < b) return Gcd(b, a);
        while (b != 0)
        {
            var r = a % b;
            a = b;
            b = r;
        }
        return a;
    }

    // 最小公倍数
    public static long Lcm(int a, int b)
    {
        return BigMul(a, b) / Gcd(a, b);
    }
    public static long Lcm(long a, long b)
    {
        return a * b / Gcd(a, b);
    }
}