Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C# (Mono-mcs 6.8.0.105) (judge verdict: Accepted)

public class Hello{
    public static void Main(){
        int N = int.Parse(System.Console.ReadLine());
        int count = 0;
        int ans = 0;
        
        for(int i=1; i<=N; i+=2){
            //if(i%2 != 0){
            //System.Console.WriteLine(i);
            for(int j=1; j<=i; j++){
                if(i%j==0){
                    count++;
                }
            }
            if(count==8){
                ans++;
            }
            count = 0;
            //}
        }
        System.Console.WriteLine(ans);
    }
}