Problem:
Score : 300 points

Problem Statement

There are N people living on a number line.

The i-th person lives at coordinate X_i.

You are going to hold a meeting that all N people have to attend.

The meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.

Find the minimum total points of stamina the N people have to spend.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq X_i \leq 100

Input

Input is given from Standard Input in the following format:

N
X_1 X_2 ... X_N

Output

Print the minimum total stamina the N people have to spend.

Sample Input 1

2
1 4

Sample Output 1

5

Assume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.

Note that you can hold the meeting only at an integer coordinate.

Sample Input 2

7
14 14 2 13 56 2 37

Sample Output 2

2354

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

using System;
using System.Linq;
using System.Collections;
using System.Collections.Generic;
using static System.Math;
using static System.Console;
using static exMath;
using static exReadLine;


class Program
{
    static void Main(string[] args)
    {
        int N;
        intReadLine(out N);
        int[] X = intArrayReadLine();
        int ans = int.MaxValue;
        for(int i = 1; i <= X.Max(); i++)
        {
            int count = 0;
            for(int j = 0; j < N; j++)
            {
                count += (X[j] - i) * (X[j] - i);
            }
            if(count < ans)
            {
                ans = count;
            }
        }
        WriteLine(ans);
        //ReadLine();
    }
}

static class exReadLine
{
    public static void intReadLine(out int a)
    {
        a = int.Parse(ReadLine());
    }
    public static void intReadLine(out int a, out int b)
    {
        int[] input = ReadLine().Split().Select(int.Parse).ToArray();
        a = input[0];
        b = input[1];
    }
    public static void intReadLine(out int a, out int b, out int c)
    {
        int[] input = ReadLine().Split().Select(int.Parse).ToArray();
        a = input[0];
        b = input[1];
        c = input[2];
    }
    public static void intReadLine(out int a, out int b, out int c, out int d)
    {
        int[] input = ReadLine().Split().Select(int.Parse).ToArray();
        a = input[0];
        b = input[1];
        c = input[2];
        d = input[3];
    }

    public static void longReadLine(out long a)
    {
        a = long.Parse(ReadLine());
    }
    public static void longReadLine(out long a, out long b)
    {
        long[] input = ReadLine().Split().Select(long.Parse).ToArray();
        a = input[0];
        b = input[1];
    }
    public static void longReadLine(out long a, out long b, out long c)
    {
        long[] input = ReadLine().Split().Select(long.Parse).ToArray();
        a = input[0];
        b = input[1];
        c = input[2];
    }
    public static void longReadLine(out long a, out long b, out long c, out long d)
    {
        long[] input = ReadLine().Split().Select(long.Parse).ToArray();
        a = input[0];
        b = input[1];
        c = input[2];
        d = input[3];
    }
    
    public static int[] intArrayReadLine()
    {
        return ReadLine().Split().Select(int.Parse).ToArray();
    }

    public static long[] longArrayReadLine()
    {
        return ReadLine().Split().Select(long.Parse).ToArray();
    }

    public static List<int> intListReadLine()
    {
        return ReadLine().Split().Select(int.Parse).ToList();
    }

    public static List<long> longListReadLine()
    {
        return ReadLine().Split().Select(long.Parse).ToList();
    }
}

static class exMath
{
    // 最大公約数
    public static int Gcd(int a, int b)
    {
        if (a < b) return Gcd(b, a);
        while (b != 0)
        {
            var r = a % b;
            a = b;
            b = r;
        }
        return a;
    }
    public static long Gcd(long a, long b)
    {
        if (a < b) return Gcd(b, a);
        while (b != 0)
        {
            var r = a % b;
            a = b;
            b = r;
        }
        return a;
    }

    // 最小公倍数
    public static long Lcm(int a, int b)
    {
        return BigMul(a, b) / Gcd(a, b);
    }
    public static long Lcm(long a, long b)
    {
        return a * b / Gcd(a, b);
    }
}