Problem:
Score : 200 points

Problem Statement

Takahashi is standing on a two-dimensional plane, facing north. Find the minimum positive integer K such that Takahashi will be at the starting position again after he does the following action K times:

Go one meter in the direction he is facing. Then, turn X degrees counter-clockwise.

Constraints

1 \leq X \leq 179

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print the number of times Takahashi will do the action before he is at the starting position again.

Sample Input 1

90

Sample Output 1

4

Takahashi's path is a square.

Sample Input 2

1

Sample Output 2

360

Solution in C# (.NET Core 3.1.201) (judge verdict: Accepted)

using System;
using System.Linq;
namespace Sample
{
  class Sample
  {
    static void Main(string[] args)
    {
    int N=int.Parse(Console.ReadLine());
     int kaiten=N;
      int ans=0;
      bool flg=false;
      while(!flg){
       if (kaiten%360==0){
         flg=true;
       }
        kaiten+=N;
        ans++;
      }
      Console.WriteLine(ans);
    }
    
  }

}