Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in C# (judge verdict: Wrong Answer)

using System;

public class Program
{
	public static void Main(string[] args)
	{
		//var ss = new StreamScanner();
		//---------------------------------
		//????????????int, double, string?????????????????£????????????
		int[] intArray = new int[26];

		string abc = "abcdefghijklmnopqrstuvwxyz";
		char[] abcArray = abc.ToCharArray();


		for (int k = 0; k < 1200; k++)
		{
			int sentence = Console.Read();
			string ss = sentence.ToString();
			string s = ss.ToLower();


			char[] charArray = new char[s.Length];
			charArray = s.ToCharArray();
			for (int i = 0; i < s.Length; i++)
			{
				for (int j = 0; j < abcArray.Length; j++)
				{
					if (charArray[i] == abcArray[j])
					{
						intArray[j] += 1;
					}
				}
			}
		}

		for (int i = 0; i < abcArray.Length; i++)
		{
			Console.WriteLine(abcArray[i]+" : "+intArray[i]);
		}

		//int x = ss.Next<int>();
		//double d = ss.Next<double>();
		//string s = ss.Next<string>();

		//?????°???????????????????????¨?????????????????????????????????????????????????´???????
		//int[] array = ss.Next<int>(10);
		//---------------------------------

	}
}
public class StreamScanner
{
	private readonly char[] _c = { ' ' };
	private int _index = -1;
	private string[] _input = new string[0];
	private readonly System.IO.StreamReader _sr = new System.IO.StreamReader(Console.OpenStandardInput());

	public T Next<T>()
	{
		if (_index == _input.Length - 1)
		{
			_index = -1;
			while (true)
			{
				string rl = _sr.ReadLine();
				if (rl == null)
				{
					if (typeof(T).IsClass) return default(T);
					return (T)typeof(T).GetField("MinValue").GetValue(null);
				}
				if (rl != "")
				{
					_input = rl.Split(_c, StringSplitOptions.RemoveEmptyEntries);
					break;
				}
			}
		}
		return (T)Convert.ChangeType(_input[++_index], typeof(T), System.Globalization.CultureInfo.InvariantCulture);
	}

	public T[] Next<T>(int x)
	{
		var ret = new T[x];
		for (var i = 0; i < x; ++i) ret[i] = Next<T>();
		return ret;
	}

	public T[][] Next<T>(int x, int y)
	{
		var ret = new T[y][];
		for (var i = 0; i < y; ++i) ret[i] = Next<T>(x);
		return ret;
	}
}