Problem:
Score : 300 points

Problem Statement

There are 3N participants in AtCoder Group Contest.
The strength of the i-th participant is represented by an integer a_i.
They will form N teams, each consisting of three participants.
No participant may belong to multiple teams.

The strength of a team is defined as the second largest strength among its members.
For example, a team of participants of strength 1, 5, 2 has a strength 2, and a team of three participants of strength 3, 2, 3 has a strength 3.

Find the maximum possible sum of the strengths of N teams.

Constraints

1 ≤ N ≤ 10^5

1 ≤ a_i ≤ 10^{9}

a_i are integers.

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 ... a_{3N}

Output

Print the answer.

Sample Input 1

2
5 2 8 5 1 5

Sample Output 1

10

The following is one formation of teams that maximizes the sum of the strengths of teams:

Team 1: consists of the first, fourth and fifth participants.

Team 2: consists of the second, third and sixth participants.

Sample Input 2

10
1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000

Sample Output 2

10000000000

The sum of the strengths can be quite large.

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

#pragma warning disable

using System;
using System.Collections.Generic;
using System.IO;
using System.Linq;
using System.Runtime.Serialization.Formatters.Binary;
using System.Text;
using System.Text.RegularExpressions;
using System.Diagnostics;
using System.Numerics;
using System.Collections;
using System.Timers;
using System.Threading;
// using System.Threading.Tasks;

static class MainClass
{
    public static void Main(string[] args)
    {
        var N = Console.ReadLine().ToInt32();
        var a3n = Console.ReadLine().SplittedStringToInt32List();
        var value = 0l;
        a3n.Sort();
        for (int i = 0; i < N; i++)
        {
            value += a3n[3 * N - 2 * i -2];
        }
        Console.WriteLine(value);
        Console.ReadLine();
    }


        #region ライブラリ

        #region 文字列処理
        public static long ToInt64(this string str) => long.Parse(str);
    public static int ToInt32(this string str) => int.Parse(str);
    public static BigInteger ToBigInteger(this string str) => BigInteger.Parse(str);
    public static List<string> SplittedStringToList(this string str) => str.Split(new[] { ' ' }, StringSplitOptions.RemoveEmptyEntries).ToList();
    public static List<int> SplittedStringToInt32List(this string str) => str.Split(new[] { ' ' }, StringSplitOptions.RemoveEmptyEntries).Select(x => int.Parse(x)).ToList();

    public static List<BigInteger> SplittedStringToBigInteger(this string str) => str.Split(new[] { ' ' }, StringSplitOptions.RemoveEmptyEntries).Select(x => BigInteger.Parse(x)).ToList();
    #endregion
    #region DeepClone
    public static T DeepClone<T>(this T src)
    {
        using (var memoryStream = new MemoryStream())
        {
            var binaryFormatter
              = new BinaryFormatter();
            binaryFormatter.Serialize(memoryStream, src);
            memoryStream.Seek(0, SeekOrigin.Begin);
            return (T)binaryFormatter.Deserialize(memoryStream);
        }
    }
    #endregion

    public static int Gcd(int a, int b)
    {
        if (b == 0)
            return a;
        return Gcd(b, a % b);
    }
    public static BigInteger Gcd(BigInteger a, BigInteger b)
    {
        if (b == 0)
            return a;
        return Gcd(b, a % b);
    }

    public static BigInteger Lcm(BigInteger a, BigInteger b)
    {
        return (a * b) / Gcd(a, b);
    }

    public static BigInteger Factorial(int n)
    {
        var dp = new BigInteger[n];
        dp[0] = 1;
        for (int i = 1; i < n; i++)
        {
            dp[i] = dp[i - 1] * (i + 1);
        }
        return dp[n - 1];
    }

    public static List<long> PrimeFactorize(long n)
    {
        var bases = n;
        var num = (long)Math.Pow(n, 0.5);
        var ls = new List<long>();
        for (int i = 2; i <= num; i++)
        {
            if (n % i == 0)
            {
                n = n / i;
                ls.Add(i);
                i--;
                continue;
            }
        }
        long nnn = 1;
        foreach (var item in ls)
        {
            nnn = nnn * item;
        }
        if (nnn != bases)
            ls.Add(n);
        return ls;
    }
    public static class PrimeNumber
    {

        static long[] seedPrimes = {
        2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,79,83,89,97
    };

        public static bool IsPrime(long num)
        {
            if (num == 1)
                return false;
            if (seedPrimes.Contains(num))
                return true;
            if (seedPrimes.Any(x => num % x == 0))
                return false;

            return (num < 2000000) ? IsPrimeBruteforce(num) : IsPrimeMillarRrabin(num);
        }

        private static bool IsPrimeBruteforce(long num)
        {
            if (num == 1)
                return false;
            if (num != 2 && num % 2 == 0)
                return false;
            if (num != 3 && num % 3 == 0)
                return false;
            if (num != 5 && num % 5 == 0)
                return false;
            long i = 0;
            while (true)
            {
                foreach (var p in seedPrimes.Skip(3).Take(8))
                {
                    var primeCandidte = p + i;
                    if (primeCandidte > Math.Sqrt(num))
                        return true;
                    if (num % (primeCandidte) == 0)
                        return false;
                }
                i += 30;
            }
        }

        private static bool IsPrimeMillarRrabin(long num)
        {
            if (num <= 1)
                return false;
            if ((num & 1) == 0)
                return num == 2;

            if (num < 100 && seedPrimes.Contains((int)num))
                return true;

            var WitnessMax = GetWitnessMax(num);

            long d = num - 1;
            long s = 0;
            while ((d & 1) == 0)
            {
                s++;
                d >>= 1;
            }
            foreach (var w in seedPrimes.Take(WitnessMax))
            {
                if (!MillarRrabin(num, s, d, w))
                    return false;
            }
            return true;
        }


        private static int GetWitnessMax(long num)
        {
            if (num < 2047)
                return 1;
            if (num < 1373653)
                return 2;
            if (num < 25326001)
                return 3;
            if (num < 3215031751)
                return 4;
            if (num < 2152302898747)
                return 5;
            if (num < 3474749660383)
                return 6;
            if (num < 341550071728321)
                return 7;
            if (num < 3825123056546413051)
                return 9;
            return 12;
        }


        private static bool MillarRrabin(long num, long s, long d, long witness)
        {
            long x = ModPow(witness, d, num);
            if (x == 1)
                return true;
            for (long r = 0; r < s; r++)
            {
                if (x == num - 1)
                    return true;
                BigInteger rem;
                BigInteger.DivRem(BigInteger.Multiply(x, x), num, out rem);
                x = (long)(rem);
            }
            return false;
        }

        private static long ModPow(long baseValue, long exponent, long modulus)
        {
            return (long)BigInteger.ModPow(baseValue, exponent, modulus);
        }

    }

    // 多分約数つくるやつ
    public static List<long> Make(long n)
    {
        var ls = new List<long>();
        // ls.Add(1);
        for (int i = 1; i*i <= n; i++)
        {
            if (n % i == 0)
            {
                ls.Add(i);
                if (i != 1 && i * i != n)
                {
                    ls.Add(n / i);
                }
            }
        }
        return ls;
    }
    #region 二分探索
    public static int LowerBound<T>(this IEnumerable<T> ar, int start, int end, T value, IComparer<T> comparer)
    {
        var arr = ar.ToArray();
        int low = start;
        int high = end;
        int mid;
        while (low < high)
        {
            mid = ((high - low) >> 1) + low;
            if (comparer.Compare(arr[mid], value) < 0)
                low = mid + 1;
            else
                high = mid;
        }
        return low;
    }

    public static int LowerBound<T>(this IEnumerable<T> arr, T value) where T : IComparable
    {
        return LowerBound(arr, 0, arr.Count(), value, Comparer<T>.Default);
    }

    public static int UpperBound<T>(this IEnumerable<T> ar, int start, int end, T value, IComparer<T> comparer)
    {
        var arr = ar.ToArray();
        int low = start;
        int high = end;
        int mid;
        while (low < high)
        {
            mid = ((high - low) >> 1) + low;
            if (comparer.Compare(arr[mid], value) <= 0)
                low = mid + 1;
            else
                high = mid;
        }
        return low;
    }

    public static int UpperBound<T>(this IEnumerable<T> arr, T value)
    {
        return UpperBound(arr, 0, arr.Count(), value, Comparer<T>.Default);
    }
    #endregion
    // AOJ - Power
    public static BigInteger Power(BigInteger m,BigInteger n,int p)
    {
        BigInteger amari = 1;
        while (true)
        {
            if (n / 2 >= 1)
            {
                BigInteger b = m;
                m *= m;
                if (n % 2 == 1)
                {
                    amari *= b;
                    amari %= p;
                }
                n /= 2;
            }
            m %= p;
            if (n / 2== 0)
            {
                break;
            }
        }
        return (m * amari) % p;
    }

    public static BigInteger Combination(int n, int k)
    {
        if (n < k || n == 0)
            return 0;
        if (n == k)
            return 1;
        try
        {
            return Factorial(n) / (Factorial(n - k) * Factorial(k));
        }
        catch
        {
            return 0;
        }
    }
    #endregion

}