Problem:
Score : 700 points

Problem Statement

There is a tree with N vertices, numbered 1 through N.
The i-th of the N-1 edges connects vertices a_i and b_i.

Currently, there are A_i stones placed on vertex i.
Determine whether it is possible to remove all the stones from the vertices by repeatedly performing the following operation:

Select a pair of different leaves. Then, remove exactly one stone from every vertex on the path between those two vertices.
Here, a leaf is a vertex of the tree whose degree is 1, and the selected leaves themselves are also considered as vertices on the path connecting them.

Note that the operation cannot be performed if there is a vertex with no stone on the path.

Constraints

2 ≦ N ≦ 10^5

1 ≦ a_i,b_i ≦ N

0 ≦ A_i ≦ 10^9

The given graph is a tree.

Input

The input is given from Standard Input in the following format:

N
A_1 A_2 … A_N
a_1 b_1
:
a_{N-1} b_{N-1}

Output

If it is possible to remove all the stones from the vertices, print YES. Otherwise, print NO.

Sample Input 1

5
1 2 1 1 2
2 4
5 2
3 2
1 3

Sample Output 1

YES

All the stones can be removed, as follows:

Select vertices 4 and 5. Then, there is one stone remaining on each vertex except 4.

Select vertices 1 and 5. Then, there is no stone on any vertex.

Sample Input 2

3
1 2 1
1 2
2 3

Sample Output 2

NO

Sample Input 3

6
3 2 2 2 2 2
1 2
2 3
1 4
1 5
4 6

Sample Output 3

YES

Solution in C# (Mono 4.6.2.0) (judge verdict: Wrong Answer)

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using static System.Console;
using static System.Math;

namespace AtTest.AGC_Challenge
{
    class _010_C
    {
        static void Main(string[] args)
        {
            Method(args);
            ReadLine();
        }

        static void Method(string[] args)
        {
            int n = ReadInt();
            long[] cnts = ReadLongs();
            List<int>[] graph = new List<int>[n];
            for (int i = 0; i < n; i++) graph[i] = new List<int>();
            for(int i = 0; i < n - 1; i++)
            {
                int[] ab = ReadInts();
                int a = ab[0] - 1;
                int b = ab[1] - 1;
                graph[a].Add(b);
                graph[b].Add(a);
            }
            bool[] visited = new bool[n];
            Stack<int> stack = new Stack<int>();
            bool ok = true;
            DFS(graph, cnts, ref visited, ref ok, 0);
            WriteLine(ok ? "YES" : "NO");
        }

        static long DFS(List<int>[] graph,long[] cnts,
            ref bool[] visited, ref bool ok, int now)
        {
            if (!ok) return 0;

            visited[now] = true;
            long cnt = 0;
            int nodes = 0;
            for(int i = 0; i < graph[now].Count; i++)
            {
                if (visited[graph[now][i]]) continue;
                nodes++;
                long tmp = DFS(graph, cnts,
                    ref visited, ref ok, graph[now][i]);
                if (cnts[now] < tmp)
                {
                    ok = false;
                    return 0;
                }
                cnt += tmp;
            }
            if (nodes == 0) return cnts[now];
            if (cnt < cnts[now] || cnt > cnts[now] * 2)
            {
                ok = false;
                return 0;
            }
            return cnts[now] * 2 - cnt;
        }

        private static string Read() { return ReadLine(); }
        private static int ReadInt() { return int.Parse(Read()); }
        private static long ReadLong() { return long.Parse(Read()); }
        private static double ReadDouble() { return double.Parse(Read()); }
        private static int[] ReadInts() { return Array.ConvertAll(Read().Split(), int.Parse); }
        private static long[] ReadLongs() { return Array.ConvertAll(Read().Split(), long.Parse); }
        private static double[] ReadDoubles() { return Array.ConvertAll(Read().Split(), double.Parse); }
    }
}