Problem:
Score : 300 points

Problem Statement

There are N observatories in AtCoder Hill, called Obs. 1, Obs. 2, ..., Obs. N. The elevation of Obs. i is H_i.
There are also M roads, each connecting two different observatories. Road j connects Obs. A_j and Obs. B_j.

Obs. i is said to be good when its elevation is higher than those of all observatories that can be reached from Obs. i using just one road.
Note that Obs. i is also good when no observatory can be reached from Obs. i using just one road.

How many good observatories are there?

Constraints

2 \leq N \leq 10^5

1 \leq M \leq 10^5

1 \leq H_i \leq 10^9

1 \leq A_i,B_i \leq N

A_i \neq B_i

Multiple roads may connect the same pair of observatories.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M
H_1 H_2 ... H_N
A_1 B_1
A_2 B_2
:
A_M B_M

Output

Print the number of good observatories.

Sample Input 1

4 3
1 2 3 4
1 3
2 3
2 4

Sample Output 1

2

From Obs. 1, you can reach Obs. 3 using just one road. The elevation of Obs. 1 is not higher than that of Obs. 3, so Obs. 1 is not good.

From Obs. 2, you can reach Obs. 3 and 4 using just one road. The elevation of Obs. 2 is not higher than that of Obs. 3, so Obs. 2 is not good.

From Obs. 3, you can reach Obs. 1 and 2 using just one road. The elevation of Obs. 3 is higher than those of Obs. 1 and 2, so Obs. 3 is good.

From Obs. 4, you can reach Obs. 2 using just one road. The elevation of Obs. 4 is higher than that of Obs. 2, so Obs. 4 is good.

Thus, the good observatories are Obs. 3 and 4, so there are two good observatories.

Sample Input 2

6 5
8 6 9 1 2 1
1 3
4 2
4 3
4 6
4 6

Sample Output 2

3

Solution in C# (.NET Core 3.1.201) (judge verdict: Accepted)

using System;
class p
{
  static void Main()
  {
    string[] ipt = Console.ReadLine().Split(' ');
    int N = int.Parse(ipt[0]);
    int M = int.Parse(ipt[1]);
    int[] arr = new int[N];
    bool[] result = new bool[N];
    ipt = Console.ReadLine().Split(' ');
    for (int i = 0; i < N; i++) {
      arr[i] = int.Parse(ipt[i]);
      result[i] = true;
    }
    for (int i = 0; i < M; i++) {
      ipt = Console.ReadLine().Split(' ');
      int A = int.Parse(ipt[0]);
      int B = int.Parse(ipt[1]);
      if (arr[A-1] <= arr[B-1]) {
        result[A-1] = false;
      }
      if (arr[B-1] <= arr[A-1]) {
        result[B-1] = false;
      }
    }
    int count = 0;
    for (int i = 0; i < N; i++) {
      if (result[i]) {
        count++;
      }
    }
    Console.WriteLine(count);
  }
}