Problem:
Score : 300 points

Problem Statement

A company has N members, who are assigned ID numbers 1, ..., N.

Every member, except the member numbered 1, has exactly one immediate boss with a smaller ID number.

When a person X is the immediate boss of a person Y, the person Y is said to be an immediate subordinate of the person X.

You are given the information that the immediate boss of the member numbered i is the member numbered A_i. For each member, find how many immediate subordinates it has.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq A_i < i

Input

Input is given from Standard Input in the following format:

N
A_2 ... A_N

Output

For each of the members numbered 1, 2, ..., N, print the number of immediate subordinates it has, in its own line.

Sample Input 1

5
1 1 2 2

Sample Output 1

2
2
0
0
0

The member numbered 1 has two immediate subordinates: the members numbered 2 and 3.

The member numbered 2 has two immediate subordinates: the members numbered 4 and 5.

The members numbered 3, 4, and 5 do not have immediate subordinates.

Sample Input 2

10
1 1 1 1 1 1 1 1 1

Sample Output 2

9
0
0
0
0
0
0
0
0
0

Sample Input 3

7
1 2 3 4 5 6

Sample Output 3

1
1
1
1
1
1
0

Solution in C# (Mono-mcs 6.8.0.105) (judge verdict: Accepted)

using System;
using System.Collections;
using System.Collections.Generic;
using System.Linq;

namespace cysharp_test
{
    class Program
    {
        static void Main (string[] args)
        {
            new Program ().solve ();
        }

        void solve ()
        {
            int N = int.Parse(Console.ReadLine());
            int[] As = Console.ReadLine().Split(' ').Select(int.Parse).ToArray();

            int[] nums = new int[N];

            for (int i = 0; i < N - 1;i++){
                nums[As[i] - 1]++;
            }

            for (int i = 0; i < N;i++)Console.WriteLine(nums[i]);
        }

    }

    class Vector2
    {
        public Vector2 (long x, long y)
        {
            this.x = x;
            this.y = y;
        }

        long x, y;

        public static Vector2 operator + (Vector2 a, Vector2 b)
        {
            return new Vector2 (a.x + b.x, a.y + b.y);
        }

        public static Vector2 operator - (Vector2 a, Vector2 b)
        {
            return new Vector2 (a.x - b.x, a.y - b.y);
        }

        public static Vector2 operator * (Vector2 a, long scala)
        {
            return new Vector2 (a.x * scala, a.y + scala);
        }
    }
}