Problem:
Score : 400 points

Problem Statement

You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

In the i-th operation, you replace every element whose value is B_{i} with C_{i}.

For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

All values in input are integers.

1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}

B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:

N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}

Output

Print Q integers S_{i} to Standard Output in the following format:

S_{1}
S_{2}
\vdots
S_{Q}

Note that S_{i} may not fit into a 32-bit integer.

Sample Input 1

4
1 2 3 4
3
1 2
3 4
2 4

Sample Output 1

11
12
16

Initially, the sequence A is 1,2,3,4.

After each operation, it becomes the following:

2, 2, 3, 4

2, 2, 4, 4

4, 4, 4, 4

Sample Input 2

4
1 1 1 1
3
1 2
2 1
3 5

Sample Output 2

8
4
4

Note that the sequence A may not contain an element whose value is B_{i}.

Sample Input 3

2
1 2
3
1 100
2 100
100 1000

Sample Output 3

102
200
2000

Solution in C# (Mono-mcs 6.8.0.105) (judge verdict: Accepted)

using System;
using System.Collections.Generic;
using System.Linq;
class d{
  public static void Main(){
    long n = long.Parse(Console.ReadLine());
    long[] num = Console.ReadLine().Split(' ').Select(s => long.Parse(s)).ToArray();
    long[] count = new long[(long)Math.Pow(10,5)+1];
    long sum = 0;
    for(long i=0; i<n; i++){
      count[num[i]]++;
      sum += num[i];
    }
    long q = long.Parse(Console.ReadLine());
    for(long i=0; i<q; i++){
      long[] order = Console.ReadLine().Split(' ').Select(s => long.Parse(s)).ToArray();
      if(count[order[0]] == 0){
        Console.WriteLine(sum);
        continue;
      }
      long mult = count[order[0]];
      count[order[1]] += mult;
      count[order[0]] = 0;
      sum += (order[1]-order[0])*mult;
      Console.WriteLine(sum);
    }
  }
}