Problem:
Score : 300 points

Problem Statement

There are N integers written on a blackboard. The i-th integer is A_i.

Takahashi will repeatedly perform the following operation on these numbers:

Select a pair of integers, A_i and A_j, that have the same parity (that is, both are even or both are odd) and erase them.

Then, write a new integer on the blackboard that is equal to the sum of those integers, A_i+A_j.

Determine whether it is possible to have only one integer on the blackboard.

Constraints

2 ≦ N ≦ 10^5

1 ≦ A_i ≦ 10^9

A_i is an integer.

Input

The input is given from Standard Input in the following format:

N
A_1 A_2 … A_N

Output

If it is possible to have only one integer on the blackboard, print YES. Otherwise, print NO.

Sample Input 1

3
1 2 3

Sample Output 1

YES

It is possible to have only one integer on the blackboard, as follows:

Erase 1 and 3 from the blackboard, then write 4. Now, there are two integers on the blackboard: 2 and 4.

Erase 2 and 4 from the blackboard, then write 6. Now, there is only one integer on the blackboard: 6.

Sample Input 2

5
1 2 3 4 5

Sample Output 2

NO

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace AtCoder
{
	class Program
	{
		static void Main(string[] args)
		{
			Question.Exec();
		}
	}

	public static class Question
	{
		public static bool IsOdd(long n)
		{
			bool isOdd = n % 2 == 1;
			return isOdd;
		}

		public static void Exec()
		{
			var n = long.Parse(Console.ReadLine());
			var array = Console.ReadLine().Split(' ').Select(i => long.Parse(i)).ToArray();
			var list = array.ToList();

			var oddList = list.Where(x => IsOdd(x)).ToList();
			var noOddList = list.Where(x => IsOdd(x) == false).ToList();

			bool isOK = IsOdd(oddList.Count) == false;
			if (isOK) {
				Console.WriteLine($"YES");
			} else {
				Console.WriteLine($"NO");
			}

			Console.ReadKey();
		}
	}
}