Problem:
Score : 200 points

Problem Statement

Let us define the FizzBuzz sequence a_1,a_2,... as follows:

If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.

If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.

If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.

If none of the above holds, a_i=i.

Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Constraints

1 \leq N \leq 10^6

Input

Input is given from Standard Input in the following format:

N

Output

Print the sum of all numbers among the first N terms of the FizzBuzz sequence.

Sample Input 1

15

Sample Output 1

60

The first 15 terms of the FizzBuzz sequence are:

1,2,\mbox{Fizz},4,\mbox{Buzz},\mbox{Fizz},7,8,\mbox{Fizz},\mbox{Buzz},11,\mbox{Fizz},13,14,\mbox{FizzBuzz}

Among them, numbers are 1,2,4,7,8,11,13,14, and the sum of them is 60.

Sample Input 2

1000000

Sample Output 2

266666333332

Watch out for overflow.

Solution in C# (.NET Core 3.1.201) (judge verdict: Wrong Answer)

using System;
using System.Linq;

namespace ABC
{
    class Program
    {
        static void Main(string[] args)
        {
            //string line = Console.ReadLine();
            //Console.WriteLine(line.IndexOf('7') >= 0 ? "Yes" : "No");

            int num = int.Parse(Console.ReadLine());

            Enumerable.Range(1, num)
                .Select(n => (n, new[] { (3, "Fizz"), (5, "Buzz") }
                    .Where(t => n % t.Item1 == 0).Select(t => t.Item2))
                ).Select(t => t.Item2.Any() ? string.Join("", t.Item2) : t.Item1.ToString())
                .ToList().ForEach(Console.WriteLine);
        }
    }
}