Problem:
Score : 200 points

Problem Statement

Takahashi is standing on a two-dimensional plane, facing north. Find the minimum positive integer K such that Takahashi will be at the starting position again after he does the following action K times:

Go one meter in the direction he is facing. Then, turn X degrees counter-clockwise.

Constraints

1 \leq X \leq 179

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print the number of times Takahashi will do the action before he is at the starting position again.

Sample Input 1

90

Sample Output 1

4

Takahashi's path is a square.

Sample Input 2

1

Sample Output 2

360

Solution in C# (.NET Core 3.1.201) (judge verdict: Accepted)

using System;

public class Hello
{
    public static void Main()
    {
        var x = int.Parse(Console.ReadLine().Trim());
        var t = Gcd(360, x);
        Console.WriteLine(360 / t);
    }
    public static int Gcd(int a, int b)
    {
        if (a < b) return Gcd(b, a);
        while (b != 0)
        {
            var w = a % b;
            a = b;
            b = w;
        }
        return a;
    }
}