Problem:
Score : 300 points

Problem Statement

You are given a string S of length N and another string T of length M.
These strings consist of lowercase English letters.

A string X is called a good string when the following conditions are all met:

Let L be the length of X. L is divisible by both N and M.

Concatenating the 1-st, (\frac{L}{N}+1)-th, (2 \times \frac{L}{N}+1)-th, ..., ((N-1)\times\frac{L}{N}+1)-th characters of X, without changing the order, results in S.

Concatenating the 1-st, (\frac{L}{M}+1)-th, (2 \times \frac{L}{M}+1)-th, ..., ((M-1)\times\frac{L}{M}+1)-th characters of X, without changing the order, results in T.

Determine if there exists a good string. If it exists, find the length of the shortest such string.

Constraints

1 \leq N,M \leq 10^5

S and T consist of lowercase English letters.

|S|=N

|T|=M

Input

Input is given from Standard Input in the following format:

N M
S
T

Output

If a good string does not exist, print -1; if it exists, print the length of the shortest such string.

Sample Input 1

3 2
acp
ae

Sample Output 1

6

For example, the string accept is a good string.
There is no good string shorter than this, so the answer is 6.

Sample Input 2

6 3
abcdef
abc

Sample Output 2

-1

Sample Input 3

15 9
dnsusrayukuaiia
dujrunuma

Sample Output 3

45

Solution in C# (Mono 4.6.2.0) (judge verdict: Runtime Error)

using System;
using System.Collections.Generic;
using System.Linq;

namespace test
{
    class Program
    {
        static void Main(string[] args)
        {
            var input = ReadArrayInt();
            var N = input[0];
            var M = input[1];
            var S = Read();
            var T = Read();
            long L = Lcm(N, M);
            var posS = new Queue<long[]>();
            if (S[0] != T[0])
            {
                Console.WriteLine(-1);
                return;
            }
            for (int i = 1; i < N; i++)
            {
                posS.Enqueue(new long[] { L / N * i + 1, i });
            }
            for (int i = 1; i < M; i++)
            {
                var idxM = L / M * i + 1;
                while (posS.Peek()[0] < idxM)
                {
                    posS.Dequeue();
                }
                if (posS.Count == 0) break;
                else if(posS.Peek()[0] == idxM)
                {
                    var idxN = posS.Dequeue()[1];
                    if (S[(int)idxN] != T[i])
                    {
                        Console.WriteLine(-1);
                        return;
                    }
                }
            }

            Console.WriteLine(L);
            Console.ReadLine();
        }

        static long Gcd(long a, long b) { if (b == 0) return a; return Gcd(b, a % b); }
        static long Lcm(long a, long b) { return a / Gcd(a, b) * b; }

        static string Read() { return Console.ReadLine(); }
        static int ReadInt() { return int.Parse(Read()); }
        static long ReadLong() { return long.Parse(Read()); }
        static int[] ReadArrayInt() { return Read().Split(' ').Select(s => int.Parse(s)).ToArray(); }
        static long[] ReadArrayLong() { return Read().Split(' ').Select(s => long.Parse(s)).ToArray(); }
    }
}