Problem:
Score : 300 points

Problem Statement

You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

1 \leq |S| \leq 2 \times 10^5

|S| = |T|

S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S and T can be made equal, print Yes; otherwise, print No.

Sample Input 1

azzel
apple

Sample Output 1

Yes

azzel can be changed to apple, as follows:

Choose e as c_1 and l as c_2. azzel becomes azzle.

Choose z as c_1 and p as c_2. azzle becomes apple.

Sample Input 2

chokudai
redcoder

Sample Output 2

No

No sequences of operation can change chokudai to redcoder.

Sample Input 3

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu

Sample Output 3

Yes

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace AtCoder.Abc
{
    class QuestionD
    {
        public static void Main(string[] args)
        {
            var sw = new System.IO.StreamWriter(Console.OpenStandardOutput()) { AutoFlush = false };
            Console.SetOut(sw);

            // 文字列の入力
            var a = Console.ReadLine();
            var b = Console.ReadLine();

            var flag = false;
            var aa = new Dictionary<char, char>();
            var bb = new Dictionary<char, char>();

            for (int i = 0; i < a.Length; i++) {
                if (aa.ContainsKey(a[i])) {
                    if (aa[a[i]] != b[i]) {
                        flag = true;
                    }
                } else {
                    aa.Add(a[i], b[i]);
                }

                if (bb.ContainsKey(b[i])) {
                    if (bb[b[i]] != a[i]) {
                        flag = true;
                    }
                } else {
                    bb.Add(b[i], a[i]);
                }
            }

            Console.WriteLine(flag ? "No" : "Yes");

            Console.Out.Flush();
        }
    }
}