Problem:
Score : 300 points

Problem Statement

Given is a permutation P_1, \ldots, P_N of 1, \ldots, N.
Find the number of integers i (1 \leq i \leq N) that satisfy the following condition:

For any integer j (1 \leq j \leq i), P_i \leq P_j.

Constraints

1 \leq N \leq 2 \times 10^5

P_1, \ldots, P_N is a permutation of 1, \ldots, N.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
P_1 ... P_N

Output

Print the number of integers i that satisfy the condition.

Sample Input 1

5
4 2 5 1 3

Sample Output 1

3

i=1, 2, and 4 satisfy the condition, but i=3 does not - for example, P_i > P_j holds for j = 1.

Similarly, i=5 does not satisfy the condition, either. Thus, there are three integers that satisfy the condition.

Sample Input 2

4
4 3 2 1

Sample Output 2

4

All integers i (1 \leq i \leq N) satisfy the condition.

Sample Input 3

6
1 2 3 4 5 6

Sample Output 3

1

Only i=1 satisfies the condition.

Sample Input 4

8
5 7 4 2 6 8 1 3

Sample Output 4

4

Sample Input 5

1
1

Sample Output 5

1

Solution in C# (Mono 4.6.2.0) (judge verdict: Time Limit Exceeded)

using System;
using System.Collections;
using System.Collections.Generic;

namespace ABC152
{
	class Program
	{
		static void Main(string[] args)
		{
			int n = int.Parse(Console.ReadLine());
			string[] ps = Console.ReadLine().Split(' ');
			int[] p = new int[n];

			for(int i = 0; i < n; i++)
			{
				p[i] = int.Parse(ps[i]);
			}

			int count = 0;
			int pi;
			int pj;
			bool flag = false;

			//iのループ
			for(int i = 0; i < n; i++)
			{
				pi = p[i];
				//jのループ
				for(int j = 0; j < i; j++)
				{
					pj = p[j];

					if(pi > pj)
					{
						flag = true;
						break;
					}
				}

				if (!flag)
				{
					count++;
				}

				flag = false;
			}

			Console.WriteLine(count);
		}
	}
}