Problem:
Score : 400 points

Problem Statement

We have N balls. The i-th ball has an integer A_i written on it.

For each k=1, 2, ..., N, solve the following problem and print the answer.

Find the number of ways to choose two distinct balls (disregarding order) from the N-1 balls other than the k-th ball so that the integers written on them are equal.

Constraints

3 \leq N \leq 2 \times 10^5

1 \leq A_i \leq N

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

For each k=1,2,...,N, print a line containing the answer.

Sample Input 1

5
1 1 2 1 2

Sample Output 1

2
2
3
2
3

Consider the case k=1 for example. The numbers written on the remaining balls are 1,2,1,2.

From these balls, there are two ways to choose two distinct balls so that the integers written on them are equal.

Thus, the answer for k=1 is 2.

Sample Input 2

4
1 2 3 4

Sample Output 2

0
0
0
0

No two balls have equal numbers written on them.

Sample Input 3

5
3 3 3 3 3

Sample Output 3

6
6
6
6
6

Any two balls have equal numbers written on them.

Sample Input 4

8
1 2 1 4 2 1 4 1

Sample Output 4

5
7
5
7
7
5
7
5

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

using System;
using System.Collections.Generic;
using System.Diagnostics;
using System.IO;
using System.Linq;

namespace MyProject
{
    class Program
    {
        static void Main(string[] args)
        {
#if Local
            var sw = new Stopwatch();
            sw.Start();
            Console.SetIn(new StreamReader("input.in"));
#endif

            var solver = new Solver();
            solver.Solve();
#if Local
            Console.WriteLine($"{sw.ElapsedMilliseconds}ms");
#endif
        }
    }

    class Solver
    {
        public void Solve()
        {
            var N = int.Parse(Console.ReadLine());
            var A = Console.ReadLine().Split().Select(elem => int.Parse(elem)).ToArray();

            // 整数Aiの数を数える
            var countTable = new Dictionary<int, long>();
            foreach (var i in Enumerable.Range(0, N))
            {
                countTable[A[i]] = countTable.ContainsKey(A[i]) ? countTable[A[i]] + 1 : 1;
            }

            // 全体の2つのボールを選び出す組み合わせ数を数える
            var allCount = 0L;
            foreach (var count in countTable.Values)
            {
                allCount += (count * (count - 1)) / 2;
            }

            // 各kに対して、全体の組み合わせ数 - (kの整数の個数 - 1)が答えとなる
            foreach (var k in Enumerable.Range(0, N))
            {
                var count = countTable[A[k]] - 1;
                Console.WriteLine(allCount - count);
            }
        }
    }
}