Problem:
Score : 300 points

Problem Statement

You are given three integers A, B and C. Find the minimum number of operations required to make A, B and C all equal by repeatedly performing the following two kinds of operations in any order:

Choose two among A, B and C, then increase both by 1.

Choose one among A, B and C, then increase it by 2.

It can be proved that we can always make A, B and C all equal by repeatedly performing these operations.

Constraints

0 \leq A,B,C \leq 50

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B C

Output

Print the minimum number of operations required to make A, B and C all equal.

Sample Input 1

2 5 4

Sample Output 1

2

We can make A, B and C all equal by the following operations:

Increase A and C by 1. Now, A, B, C are 3, 5, 5, respectively.

Increase A by 2. Now, A, B, C are 5, 5, 5, respectively.

Sample Input 2

2 6 3

Sample Output 2

5

Sample Input 3

31 41 5

Sample Output 3

23

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

using System;
using System.Collections;
using System.Collections.Generic;
using System.Linq;
using System.IO;
using System.Text;
using System.Globalization;
using System.Diagnostics;
 
 
 
class Solve
{
    public Solve() { }
    public static int Main()
    {
        new Solve().calc();
        return 0;
    }
 
 
    Scanner cin;
 
    void calc()
    {
        cin = new Scanner();
        var num = new int[3];
        var isEven = new bool[3];
        int evenCount = 0;

        for (int i = 0; i < 3; i++){
            num[i] = cin.nextInt();
            isEven[i] = (num[i] % 2 == 0);
            if (isEven[i])
                evenCount++;
        }

        int plusCount = 0;

        switch(evenCount){
            case 1:
                for (int i = 0; i < 3; i++){
                    if (num[i] % 2 != 0)
                    {
                        num[i]++;
                    }
                }
                plusCount++;
                break;
            case 2:
                for (int i = 0; i < 3; i++)
                {
                    if (num[i] % 2 == 0)
                    {
                        num[i]++;
                    }
                }
                plusCount++;
                break;
        }

        int highest = 0;
        for (int i = 0; i < 3; i++)
        {
            if (num[i] >= highest)
                highest = num[i];
        }

        for (int i = 0; i < 3; i++)
        {
            if (num[i] < highest){
                plusCount += (highest - num[i]) / 2;
            }
        }
        Console.WriteLine(plusCount.ToString());

    }
}
 
class Scanner
{
    string[] s;
    int i;
 
    char[] cs = new char[] { ' ' };
 
    public Scanner()
    {
        s = new string[0];
        i = 0;
    }
 
    public string next()
    {
        if (i < s.Length) return s[i++];
        string st = Console.ReadLine();
        while (st == "") st = Console.ReadLine();
        s = st.Split(cs, StringSplitOptions.RemoveEmptyEntries);
        if (s.Length == 0) return next();
        i = 0;
        return s[i++];
    }
 
    public int nextInt()
    {
        return int.Parse(next());
    }
    public int[] ArrayInt(int N, int add = 0)
    {
        int[] Array = new int[N];
        for (int i = 0; i < N; i++)
        {
            Array[i] = nextInt() + add;
        }
        return Array;
    }
 
    public long nextLong()
    {
        return long.Parse(next());
    }
 
    public long[] ArrayLong(int N, long add = 0)
    {
        long[] Array = new long[N];
        for (int i = 0; i < N; i++)
        {
            Array[i] = nextLong() + add;
        }
        return Array;
    }
 
    public double nextDouble()
    {
        return double.Parse(next());
    }
 
 
    public double[] ArrayDouble(int N, double add = 0)
    {
        double[] Array = new double[N];
        for (int i = 0; i < N; i++)
        {
            Array[i] = nextDouble() + add;
        }
        return Array;
    }
}