Problem:
Score : 400 points

Problem Statement

Takahashi has a string S consisting of lowercase English letters.

Starting with this string, he will produce a new one in the procedure given as follows.

The procedure consists of Q operations. In Operation i (1 \leq i \leq Q), an integer T_i is provided, which means the following:

If T_i = 1: reverse the string S.

If T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.

If F_i = 1 : Add C_i to the beginning of the string S.

If F_i = 2 : Add C_i to the end of the string S.

Help Takahashi by finding the final string that results from the procedure.

Constraints

1 \leq |S| \leq 10^5

S consists of lowercase English letters.

1 \leq Q \leq 2 \times 10^5

T_i = 1 or 2.

F_i = 1 or 2, if provided.

C_i is a lowercase English letter, if provided.

Input

Input is given from Standard Input in the following format:

S
Q
Query_1
:
Query_Q

In the 3-rd through the (Q+2)-th lines, Query_i is one of the following:

1

which means T_i = 1, and:

2 F_i C_i

which means T_i = 2.

Output

Print the resulting string.

Sample Input 1

a
4
2 1 p
1
2 2 c
1

Sample Output 1

cpa

There will be Q = 4 operations. Initially, S is a.

Operation 1: Add p at the beginning of S. S becomes pa.

Operation 2: Reverse S. S becomes ap.

Operation 3: Add c at the end of S. S becomes apc.

Operation 4: Reverse S. S becomes cpa.

Thus, the resulting string is cpa.

Sample Input 2

a
6
2 2 a
2 1 b
1
2 2 c
1
1

Sample Output 2

aabc

There will be Q = 6 operations. Initially, S is a.

Operation 1: S becomes aa.

Operation 2: S becomes baa.

Operation 3: S becomes aab.

Operation 4: S becomes aabc.

Operation 5: S becomes cbaa.

Operation 6: S becomes aabc.

Thus, the resulting string is aabc.

Sample Input 3

y
1
2 1 x

Sample Output 3

xy

Solution in C# (Mono 4.6.2.0) (judge verdict: Wrong Answer)

using System;
using System.Numerics;
using System.Linq;
using System.Collections.Generic;
using System.Text;
class ProgramD
    {
        static void Main(string[] args)
        {
            
            //入力
            string s = Console.ReadLine();
            StringBuilder f = new StringBuilder();
            StringBuilder l = new StringBuilder();
            int n = int.Parse(Console.ReadLine());
            int flag = 0;

            for(int i = 0;i < n;i++)
            {
                string[] temp = Console.ReadLine().Split(' ');

                if(int.Parse(temp[0]) == 1)
                {
                    if(flag == 1)
                        flag = 0;
                    else
                        flag = 1;
                }
                else
                {
                    if(flag == 1)
                    {
                        if(int.Parse(temp[1]) == 2)
                            f.Append(temp[2]);
                        else
                            l.Append(temp[2]);

                    }
                    else
                    {
                        if(int.Parse(temp[1]) == 1)
                            f.Insert(0, temp[2]);
                        else
                            l.Append(temp[2]);
                    }
                }

            }


            string s2 =  new string(f.ToString().Reverse().ToArray())+ s + l.ToString();
            if(flag == 1)
            {
                var t = s2.Reverse();
                s2 = string.Join("",t);
            }
            
            
            Console.WriteLine(s2);
            
        }
    }