Problem:
Score : 400 points

Problem Statement

There are N towns in the State of Atcoder, connected by M bidirectional roads.

The i-th road connects Town A_i and B_i and has a length of C_i.

Joisino is visiting R towns in the state, r_1,r_2,..,r_R (not necessarily in this order).

She will fly to the first town she visits, and fly back from the last town she visits, but for the rest of the trip she will have to travel by road.

If she visits the towns in the order that minimizes the distance traveled by road, what will that distance be?

Constraints

2≤N≤200

1≤M≤N×(N-1)/2

2≤R≤min(8,N) (min(8,N) is the smaller of 8 and N.)

r_i≠r_j (i≠j)

1≤A_i,B_i≤N, A_i≠B_i

(A_i,B_i)≠(A_j,B_j),(A_i,B_i)≠(B_j,A_j) (i≠j)

1≤C_i≤100000

Every town can be reached from every town by road.

All input values are integers.

Input

Input is given from Standard Input in the following format:

N M R
r_1 ... r_R
A_1 B_1 C_1
:
A_M B_M C_M

Output

Print the distance traveled by road if Joisino visits the towns in the order that minimizes it.

Sample Input 1

3 3 3
1 2 3
1 2 1
2 3 1
3 1 4

Sample Output 1

2

For example, if she visits the towns in the order of 1, 2, 3, the distance traveled will be 2, which is the minimum possible.

Sample Input 2

3 3 2
1 3
2 3 2
1 3 6
1 2 2

Sample Output 2

4

The shortest distance between Towns 1 and 3 is 4. Thus, whether she visits Town 1 or 3 first, the distance traveled will be 4.

Sample Input 3

4 6 3
2 3 4
1 2 4
2 3 3
4 3 1
1 4 1
4 2 2
3 1 6

Sample Output 3

3

Solution in C# (Mono 4.6.2.0) (judge verdict: Wrong Answer)

using System;
using System.Collections.Generic;
using System.Text;

namespace AtTest.ForBlue.ABC_073
{
    class D
    {
        static Node[] nodes;

        static void Main(string[] args)
        {
            Method(args);
            Console.ReadLine();
        }

        static void Method(string[] args)
        {
            string[] input = Console.ReadLine().Split(' ');
            int n = int.Parse(input[0]);
            int m = int.Parse(input[1]);
            int r = int.Parse(input[2]);
            nodes = new Node[n];
            var rs = new int[r];

            string[] rInput = Console.ReadLine().Split(' ');
            for (int i = 0; i < r; i++)
            {
                rs[i] = int.Parse(rInput[i]) - 1;
            }
            for (int i = 0; i < n; i++)
            {
                nodes[i] = new Node(n);
                nodes[i].distances[i] = 0;//自分を0に
                nodes[i].isMin[i] = true;
            }
            for (int i = 0; i < m; i++)
            {
                string[] mInput = Console.ReadLine().Split(' ');
                int a = int.Parse(mInput[0]) - 1;
                int b = int.Parse(mInput[1]) - 1;
                int c = int.Parse(mInput[2]);
                nodes[a].edgeTo.Add(b);
                nodes[a].edgeDistances.Add(c);
                nodes[b].edgeTo.Add(a);
                nodes[b].edgeDistances.Add(c);
            }

            for (int i = 0; i < r; i++)
            {
                Dijkstra(rs[i]);
                for (int j = 0; j < n; j++)
                {
                    //Console.WriteLine(nodes[rs[i]].distances[j]);
                }
            }

            long minDistance = 0;
            long allPat = Factorial(r);
            var route = new int[r];
            for(int i = 0; i < allPat; i++)
            {
                var rList = new List<int>();
                rList.AddRange(rs);
                long distance = 0;
                for(int j = 0; j < r; j++)
                {
                    route[j] = rList[i % (r - j)];
                    //Console.WriteLine(route[j]);
                    rList.RemoveAt(i % (r - j));
                    if (j > 0)
                    {
                        distance += nodes[route[j - 1]].distances[route[j]];
                    }
                }
                if(i==0||distance < minDistance)
                {
                    minDistance = distance;
                }
            }

            Console.WriteLine(minDistance);
        }

        static void Dijkstra(int start)
        {
            var queue = new Queue<long>();
            queue.Enqueue(start);
            var unsettledDistances = new List<long[]>();//index,distance
            Node startNode = nodes[start];

            while (queue.Count > 0)
            {
                long index = queue.Dequeue();

                for (int i = 0; i < nodes[index].edgeTo.Count; i++)
                {
                    int destIndex = nodes[index].edgeTo[i];
                    if (startNode.isMin[destIndex]) continue;//確定ノードは無視

                    long distance = startNode.distances[index]
                        + nodes[index].edgeDistances[i];
                    int unsettledIndex = unsettledDistances.FindIndex(x => x[0] == destIndex);
                    if (unsettledIndex >= 0
                        && unsettledDistances[unsettledIndex][1] > distance)
                    {
                        unsettledDistances[unsettledIndex][1] = distance;
                    }
                    else if (unsettledIndex == -1)
                    {
                        unsettledDistances.Add(new long[2] { destIndex, distance });
                    }
                }

                if (unsettledDistances.Count == 0) break;

                int settleIndex = 0;
                for (int i = 0; i < unsettledDistances.Count; i++)
                {
                    if (unsettledDistances[i][1]
                        > unsettledDistances[settleIndex][1]) continue;

                    settleIndex = i;
                }
                long minDistance = unsettledDistances[settleIndex][1];
                startNode.isMin[unsettledDistances[settleIndex][0]] = true;
                startNode.distances[unsettledDistances[settleIndex][0]] = minDistance;
                queue.Enqueue(unsettledDistances[settleIndex][0]);
                unsettledDistances.RemoveAt(settleIndex);
            }
        }

        static long Factorial(int n)
        {
            if (n == 0) return 1;

            return n * Factorial(n - 1);
        }
    }

    class Node
    {
        public long[] distances;
        public bool[] isMin;
        public List<int> edgeTo;
        public List<long> edgeDistances;
        public Node(int length)
        {
            distances = new long[length];
            isMin = new bool[length];
            for(int i = 0; i < length; i++)
            {
                distances[i] = -1;
            }
            edgeTo = new List<int>();
            edgeDistances = new List<long>();
        }
    }
}