Problem:
Score : 400 points

Problem Statement

Takahashi has a string S consisting of lowercase English letters.

Starting with this string, he will produce a new one in the procedure given as follows.

The procedure consists of Q operations. In Operation i (1 \leq i \leq Q), an integer T_i is provided, which means the following:

If T_i = 1: reverse the string S.

If T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.

If F_i = 1 : Add C_i to the beginning of the string S.

If F_i = 2 : Add C_i to the end of the string S.

Help Takahashi by finding the final string that results from the procedure.

Constraints

1 \leq |S| \leq 10^5

S consists of lowercase English letters.

1 \leq Q \leq 2 \times 10^5

T_i = 1 or 2.

F_i = 1 or 2, if provided.

C_i is a lowercase English letter, if provided.

Input

Input is given from Standard Input in the following format:

S
Q
Query_1
:
Query_Q

In the 3-rd through the (Q+2)-th lines, Query_i is one of the following:

1

which means T_i = 1, and:

2 F_i C_i

which means T_i = 2.

Output

Print the resulting string.

Sample Input 1

a
4
2 1 p
1
2 2 c
1

Sample Output 1

cpa

There will be Q = 4 operations. Initially, S is a.

Operation 1: Add p at the beginning of S. S becomes pa.

Operation 2: Reverse S. S becomes ap.

Operation 3: Add c at the end of S. S becomes apc.

Operation 4: Reverse S. S becomes cpa.

Thus, the resulting string is cpa.

Sample Input 2

a
6
2 2 a
2 1 b
1
2 2 c
1
1

Sample Output 2

aabc

There will be Q = 6 operations. Initially, S is a.

Operation 1: S becomes aa.

Operation 2: S becomes baa.

Operation 3: S becomes aab.

Operation 4: S becomes aabc.

Operation 5: S becomes cbaa.

Operation 6: S becomes aabc.

Thus, the resulting string is aabc.

Sample Input 3

y
1
2 1 x

Sample Output 3

xy

Solution in C# (Mono 4.6.2.0) (judge verdict: Time Limit Exceeded)

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace AtCoder
{
    class Program
    {
        static int turn;

        static void Main(string[] args)
        {
            //[summary]D - String Formation
            var S = new StringBuilder(Console.ReadLine());
            int Q = int.Parse(Console.ReadLine());
            
            int turn = 0;

            var forward = new StringBuilder("");
            var back = new StringBuilder("");

            for (int i = 0; i < Q; i++)
            {
                var q = Console.ReadLine().Split(' ');

                if (q[0] == "1")
                {
                    turn++;
                }
                else
                {
                    var F = q[1];
                    var C = q[2];

                    //if (IsForward(F))
                    //{
                    //    //先頭に挿入
                    //    forward.Insert(0, C);
                    //}
                    //else
                    //{
                    //    //末尾に追加
                    //    back.Append(C);
                    //}

                    if (F == "1" && turn % 2 == 0)
                    {
                        forward.Insert(0, C);
                    }
                    else if (F == "2" && turn % 2 == 1)
                    {
                        forward.Insert(0, C);
                    }
                    else
                    {
                        back.Append(C);
                    }
                }
            }

            string ans = "";

            if (turn % 2 == 0)
            {
                ans = forward.Append(S.Append(back)).ToString();
            }
            else
            {
                ans = Reverse(back) + Reverse(S) + Reverse(forward);
            }

            Console.WriteLine(ans);
        }

        static bool IsForward(string F)
        {
            if (F == "1" && turn % 2 == 0)
            {
                return true;
            }
            else if (F == "2" && turn % 2 == 1)
            {
                return true;
            }
            else
            {
                return false;
            }
        }

        static string Reverse(StringBuilder sb)
        {
            return String.Join("", sb.ToString().Reverse());
        }

        static List<int> ReadLine()
        {
            var line = Console.ReadLine();
            var arr = line.Split(' ');

            return arr.Select(x => int.Parse(x)).ToList();
        }
    }
}