Problem:
Score : 300 points

Problem Statement

There are N people living on a number line.

The i-th person lives at coordinate X_i.

You are going to hold a meeting that all N people have to attend.

The meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.

Find the minimum total points of stamina the N people have to spend.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq X_i \leq 100

Input

Input is given from Standard Input in the following format:

N
X_1 X_2 ... X_N

Output

Print the minimum total stamina the N people have to spend.

Sample Input 1

2
1 4

Sample Output 1

5

Assume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.

Note that you can hold the meeting only at an integer coordinate.

Sample Input 2

7
14 14 2 13 56 2 37

Sample Output 2

2354

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

using System;

namespace atcorder
{
    class Program
    {
        public static void Main()
        {
            int n = int.Parse(Console.ReadLine());
            string[] In = Console.ReadLine().Split(' ');
            int[] X = new int[n];
            int max = 0;
            int min = Int32.MaxValue;
            for(int i=0; i<n; i++)
            {
                X[i] = int.Parse(In[i]);
                if (X[i] >= max) max = X[i];
                if (X[i] <= min) min = X[i];
            }
            int sum = Int32.MaxValue;
            for(int i=min; i<=max; i++)
            {
                int val = 0; 
                foreach(int x in X)
                {
                    val += (int)Math.Pow(x - i, 2);
                }
                if (val <= sum) sum = val;
            }
            Console.WriteLine(sum);
        }
    }
}