Problem:
Score : 500 points

Problem Statement

Takahashi has decided to work on K days of his choice from the N days starting with tomorrow.

You are given an integer C and a string S. Takahashi will choose his workdays as follows:

After working for a day, he will refrain from working on the subsequent C days.

If the i-th character of S is x, he will not work on Day i, where Day 1 is tomorrow, Day 2 is the day after tomorrow, and so on.

Find all days on which Takahashi is bound to work.

Constraints

1 \leq N \leq 2 \times 10^5

1 \leq K \leq N

0 \leq C \leq N

The length of S is N.

Each character of S is o or x.

Takahashi can choose his workdays so that the conditions in Problem Statement are satisfied.

Input

Input is given from Standard Input in the following format:

N K C
S

Output

Print all days on which Takahashi is bound to work in ascending order, one per line.

Sample Input 1

11 3 2
ooxxxoxxxoo

Sample Output 1

6

Takahashi is going to work on 3 days out of the 11 days. After working for a day, he will refrain from working on the subsequent 2 days.

There are four possible choices for his workdays: Day 1,6,10, Day 1,6,11, Day 2,6,10, and Day 2,6,11.

Thus, he is bound to work on Day 6.

Sample Input 2

5 2 3
ooxoo

Sample Output 2

1
5

There is only one possible choice for his workdays: Day 1,5.

Sample Input 3

5 1 0
ooooo

Sample Output 3

There may be no days on which he is bound to work.

Sample Input 4

16 4 3
ooxxoxoxxxoxoxxo

Sample Output 4

11
16

Solution in C# (Mono 4.6.2.0) (judge verdict: Time Limit Exceeded)

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace q5
{
    class Program
    {
        static void Main(string[] args)
        {
            var input1 = Console.ReadLine().Split(' ').Select(x => Convert.ToInt32(x)).ToArray();
            var N = input1[0];
            var K = input1[1];
            var C = input1[2];
            var S = Console.ReadLine().Trim().Select(x => x == 'o').ToArray();

            var counts = new int[N+1];
            var poss = new int[K+1];
            var pointer = 0;
            var patternCount = 0;
            while (true)
            {
                if (pointer == K)
                {
                    //Console.WriteLine("== K");
                    for (var i = 0; i < K; i++)
                    {
                        counts[poss[i]] += 1;
                    }
                    patternCount += 1;
                    pointer -= 1;
                    poss[pointer] += 1;
                    continue;
                }
                if (poss[pointer] >= N)
                {
                    //Console.WriteLine(">= N");
                    if (pointer == 0)
                        break;
                    pointer -= 1;
                    poss[pointer] += 1;
                    continue;
                }
                var p = poss[pointer];
                //Console.WriteLine($"body {pointer} {p}");
                if (S[p])
                {
                    pointer += 1;
                    poss[pointer] = p + 1 + C;
                }
                else
                {
                    poss[pointer] += 1;
                }
            }
            for (var n = 0; n < N; n++)
            {
                if (counts[n] == patternCount)
                {
                    Console.WriteLine(n + 1);
                }
            }
        }
    }
}