Problem:
Score : 200 points

Problem Statement

There are N gems. The value of the i-th gem is V_i.

You will choose some of these gems, possibly all or none, and get them.

However, you need to pay a cost of C_i to get the i-th gem.

Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid.

Find the maximum possible value of X-Y.

Constraints

All values in input are integers.

1 \leq N \leq 20

1 \leq C_i, V_i \leq 50

Input

Input is given from Standard Input in the following format:

N
V_1 V_2 ... V_N
C_1 C_2 ... C_N

Output

Print the maximum possible value of X-Y.

Sample Input 1

3
10 2 5
6 3 4

Sample Output 1

5

If we choose the first and third gems, X = 10 + 5 = 15 and Y = 6 + 4 = 10.
We have X-Y = 5 here, which is the maximum possible value.

Sample Input 2

4
13 21 6 19
11 30 6 15

Sample Output 2

6

Sample Input 3

1
1
50

Sample Output 3

0

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

using System;
using System.Collections.Generic;

namespace ABC125_B
{
    class Program
    {
        static void Main(string[] args) {
            int n = int.Parse(Console.ReadLine());
            List<int> vList = new List<int>();
            List<int> cList = new List<int>();
            string[] input = Console.ReadLine().Split();
            for(int i = 0; i < n; i++) {
                vList.Add(int.Parse(input[i]));
            }
            input = Console.ReadLine().Split();
            for (int i = 0; i < n; i++) {
                cList.Add(int.Parse(input[i]));
            }

            int sum = 0;
            for(int i = 0; i < n; i++) {
                if (vList[i] - cList[i] > 0)
                    sum += vList[i] - cList[i];
            }
            Console.WriteLine(sum);
        }
    }
}