Problem:
Score : 300 points

Problem Statement

Given is a permutation P_1, \ldots, P_N of 1, \ldots, N.
Find the number of integers i (1 \leq i \leq N) that satisfy the following condition:

For any integer j (1 \leq j \leq i), P_i \leq P_j.

Constraints

1 \leq N \leq 2 \times 10^5

P_1, \ldots, P_N is a permutation of 1, \ldots, N.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
P_1 ... P_N

Output

Print the number of integers i that satisfy the condition.

Sample Input 1

5
4 2 5 1 3

Sample Output 1

3

i=1, 2, and 4 satisfy the condition, but i=3 does not - for example, P_i > P_j holds for j = 1.

Similarly, i=5 does not satisfy the condition, either. Thus, there are three integers that satisfy the condition.

Sample Input 2

4
4 3 2 1

Sample Output 2

4

All integers i (1 \leq i \leq N) satisfy the condition.

Sample Input 3

6
1 2 3 4 5 6

Sample Output 3

1

Only i=1 satisfies the condition.

Sample Input 4

8
5 7 4 2 6 8 1 3

Sample Output 4

4

Sample Input 5

1
1

Sample Output 5

1

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace app152
{
    class Program
    {
        static void Main(string[] args)
        {
            decimal N = decimal.Parse(Console.ReadLine());
            string[] str = Console.ReadLine().Split(' ');
            decimal[] p = new decimal[(int)N];
            for(int i = 0; i<N; i++)
            {
                p[i] = decimal.Parse(str[i]);
            }


            decimal[] min = new decimal[(int)N];
            decimal curmin = p[0];
            for(int i = 0; i<N; i++)
            {
                if(curmin > p[i])
                {
                    curmin = p[i];
                }
                min[i] = curmin;
            }

            int ans = 1;
            for(int i =1; i<N; i++)
            {
                if(p[i] <= min[i-1])
                {
                    ans += 1;
                }
            }

            Console.Write(ans);
        }
    }
}