Problem:
Score : 200 points

Problem Statement

Today is August 24, one of the five Product Days in a year.

A date m-d (m is the month, d is the date) is called a Product Day when d is a two-digit number, and all of the following conditions are satisfied (here d_{10} is the tens digit of the day and d_1 is the ones digit of the day):

d_1 \geq 2

d_{10} \geq 2

d_1 \times d_{10} = m

Takahashi wants more Product Days, and he made a new calendar called Takahashi Calendar where a year consists of M month from Month 1 to Month M, and each month consists of D days from Day 1 to Day D.

In Takahashi Calendar, how many Product Days does a year have?

Constraints

All values in input are integers.

1 \leq M \leq 100

1 \leq D \leq 99

Input

Input is given from Standard Input in the following format:

M D

Output

Print the number of Product Days in a year in Takahashi Calender.

Sample Input 1

15 40

Sample Output 1

10

There are 10 Product Days in a year, as follows (m-d denotes Month m, Day d):

4-22

6-23

6-32

8-24

9-33

10-25

12-26

12-34

14-27

15-35

Sample Input 2

12 31

Sample Output 2

5

Sample Input 3

1 1

Sample Output 3

0

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace TakahashiCalender
{
	class Program
	{
		static void Main(string[] args)
		{
			int d1 = 0;
			int d10 = 0;

			int month = 0;
			int day = 0;

			string[] dataList = Console.ReadLine().Split(' ');

			month = int.Parse(dataList[0]);

			day = int.Parse(dataList[1]);

			int count = 0;
			string dd = null;

			for (int i = 22; i <= day; i++)
			{
				dd = i.ToString();

				d1 = int.Parse(dd[1].ToString());
				d10 = int.Parse(dd[0].ToString());

				if (d1 >= 2 && d10 >= 2)
				{
					for (int j = 4; j <= month; j++)
					{
						if (j == d1 * d10)
						{
							count++;
						}
					}
				}
			}
			Console.WriteLine(count);
			Console.ReadKey();

		}
	}
}