Problem:
Score : 700 points

Problem Statement

10^{10^{10}} participants, including Takahashi, competed in two programming contests.
In each contest, all participants had distinct ranks from first through 10^{10^{10}}-th.

The score of a participant is the product of his/her ranks in the two contests.

Process the following Q queries:

In the i-th query, you are given two positive integers A_i and B_i. Assuming that Takahashi was ranked A_i-th in the first contest and B_i-th in the second contest, find the maximum possible number of participants whose scores are smaller than Takahashi's.

Constraints

1 \leq Q \leq 100

1\leq A_i,B_i\leq 10^9(1\leq i\leq Q)

All values in input are integers.

Input

Input is given from Standard Input in the following format:

Q
A_1 B_1
:
A_Q B_Q

Output

For each query, print the maximum possible number of participants whose scores are smaller than Takahashi's.

Sample Input 1

8
1 4
10 5
3 3
4 11
8 9
22 40
8 36
314159265 358979323

Sample Output 1

1
12
4
11
14
57
31
671644785

Let us denote a participant who was ranked x-th in the first contest and y-th in the second contest as (x,y).

In the first query, (2,1) is a possible candidate of a participant whose score is smaller than Takahashi's. There are never two or more participants whose scores are smaller than Takahashi's, so we should print 1.

Solution in C# (Mono 4.6.2.0) (judge verdict: Wrong Answer)

using System;
using System.Collections;
using System.Linq;
class Program
{
    static int Main()
    {
        int q = int.Parse(Console.ReadLine());
        for (int i = 0; i < q; i++)
        {
            string[] s = Console.ReadLine().Split(' ');
            long a, b;
            a = long.Parse(s[0]);
            b = long.Parse(s[1]);

            long temp = a * b - 1;
            long temp2 = (long)Math.Floor(Math.Pow(temp, 0.5));

            long ans = temp2 * 2;
            if (temp2 * temp2 == a * b - 1)
                ans--;
            if (temp2 >= Math.Min(a, b))
                ans--;
            if (Math.Max(a, b) - Math.Min(a, b) == 1)
                ans--;
            Console.WriteLine(Math.Max(ans, 0));
        }


        return 0;
    }
}