Problem:
Score : 200 points

Problem Statement

Today is August 24, one of the five Product Days in a year.

A date m-d (m is the month, d is the date) is called a Product Day when d is a two-digit number, and all of the following conditions are satisfied (here d_{10} is the tens digit of the day and d_1 is the ones digit of the day):

d_1 \geq 2

d_{10} \geq 2

d_1 \times d_{10} = m

Takahashi wants more Product Days, and he made a new calendar called Takahashi Calendar where a year consists of M month from Month 1 to Month M, and each month consists of D days from Day 1 to Day D.

In Takahashi Calendar, how many Product Days does a year have?

Constraints

All values in input are integers.

1 \leq M \leq 100

1 \leq D \leq 99

Input

Input is given from Standard Input in the following format:

M D

Output

Print the number of Product Days in a year in Takahashi Calender.

Sample Input 1

15 40

Sample Output 1

10

There are 10 Product Days in a year, as follows (m-d denotes Month m, Day d):

4-22

6-23

6-32

8-24

9-33

10-25

12-26

12-34

14-27

15-35

Sample Input 2

12 31

Sample Output 2

5

Sample Input 3

1 1

Sample Output 3

0

Solution in C# (Mono 4.6.2.0) (judge verdict: Wrong Answer)

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace jsc2019_A
{
    class Program
    {
        static void Main(string[] args)
        {
            var MD = Console.ReadLine().Split().Select(int.Parse).ToArray();
            var M = MD[0];
            var D = MD[1];

            var ans = 0;
            for (int i = 1; i <= M; i++)
            {
                var f = Factorial(i);
                foreach (var item in f)
                {
                    var v = 10 * item.Item1 + item.Item2;
                    if (v <= D)
                    {
                        ans++;
                    }
                }
            }

            Console.WriteLine(ans);
        }

        public static List<Tuple<int, int>> Factorial(int i)
        {
            var ret = new List<Tuple<int, int>>();
            for (int n = 2; n < i; n++)
            {
                if (i % n == 0 && i / 2 >= 2)
                {
                    ret.Add(new Tuple<int, int>(n, i / n));
                }
            }

            return ret;
        }
    }
}