Problem:
Score : 300 points

Problem Statement

There are N people living on a number line.

The i-th person lives at coordinate X_i.

You are going to hold a meeting that all N people have to attend.

The meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.

Find the minimum total points of stamina the N people have to spend.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq X_i \leq 100

Input

Input is given from Standard Input in the following format:

N
X_1 X_2 ... X_N

Output

Print the minimum total stamina the N people have to spend.

Sample Input 1

2
1 4

Sample Output 1

5

Assume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.

Note that you can hold the meeting only at an integer coordinate.

Sample Input 2

7
14 14 2 13 56 2 37

Sample Output 2

2354

Solution in C# (.NET Core 3.1.201) (judge verdict: Accepted)

using System;
using System.Collections.Generic;
using System.Linq;

namespace test
{
    class MainClass
    {
        public static void Main(string[] args)
        {

            //問題156

            int n = int.Parse(Console.ReadLine());

            string[] line = Console.ReadLine().Split(' ');

            int[] x = new int[n];

            int min = 100;
            int max = 1;
            for (int i = 0; i < n; i++)
            {
                x[i] = int.Parse(line[i]);

                min = Math.Min(min, x[i]);
                max = Math.Max(max, x[i]);
            }

            long ans = 0;

            for (int i = min; i <= max; i++)
            {
                long count = 0;

                for (int j = 0; j < n; j++)
                {

                    count += (x[j] - i) * (x[j] - i);
                }

                if (i == min)
                {
                    ans = count;
                }

                ans = Math.Min(ans, count);
                
            }

            Console.WriteLine(ans);

        }

    }





    
}