Problem:
Score : 100 points

Problem Statement

We have N+M balls, each of which has an integer written on it.

It is known that:

The numbers written on N of the balls are even.

The numbers written on M of the balls are odd.

Find the number of ways to choose two of the N+M balls (disregarding order) so that the sum of the numbers written on them is even.

It can be shown that this count does not depend on the actual values written on the balls.

Constraints

0 \leq N,M \leq 100

2 \leq N+M

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M

Output

Print the answer.

Sample Input 1

2 1

Sample Output 1

1

For example, let us assume that the numbers written on the three balls are 1,2,4.

If we choose the two balls with 1 and 2, the sum is odd;

If we choose the two balls with 1 and 4, the sum is odd;

If we choose the two balls with 2 and 4, the sum is even.

Thus, the answer is 1.

Sample Input 2

4 3

Sample Output 2

9

Sample Input 3

1 1

Sample Output 3

0

Sample Input 4

13 3

Sample Output 4

81

Sample Input 5

0 3

Sample Output 5

3

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

using System;
using System.Collections;
using System.Collections.Generic;
using System.Linq;
using System.IO;

namespace AtCoder
{
    public class MainClass
    {
        public static void Main(string[] args)
        {
            var sw = new StreamWriter(Console.OpenStandardOutput(), Console.Out.Encoding);
            sw.AutoFlush = false;
            Console.SetOut(sw);

            if (args.Length > 0 && args[0] == "debug")
            {
                var inputs = new[] { @"
2 1
				", @"
4 3
				", @"
1 1
				", @"
13 3
				", @"
0 3
				" };

                foreach (var str in inputs)
                {
                    var text = str.Trim();
                    if (text.Length == 0) continue;
                    var reader = new System.IO.StringReader(text);
                    Console.SetIn(reader);
                    Main2(args);
                    Console.WriteLine();
                    Console.WriteLine("----------------------------------");
                    Console.WriteLine();
                }
            }
            else
                Main2(args);

            Console.Out.Flush();
        }

        public static void Main2(string[] args)
        {
            checked
            {
                var paramsList = Console.ReadLine().Split(' ').ToList();
                // NM
                var N = long.Parse(paramsList[0]);
                var M = long.Parse(paramsList[1]);

                var res = MathPlus.Combination(N, 2) + MathPlus.Combination(M, 2);
                Console.WriteLine(res);
            }
        }
    }

    public static class EnumerablePlus
    {
        ///<summary>出力文字列に変換。</summary>
        public static string MkString<T>(this IEnumerable<T> list)
        {
            return list.Aggregate(
                new System.Text.StringBuilder(),
                (a, b) => ((a.Length > 0) ? a.Append(' ') : a).Append(b)
                ).ToString();
        }

        ///<summary>添字付きfor。</summary>
        public static void ForEach2<T>(this IEnumerable<T> list, Action<T, long> a)
        {
            long i = 0;
            foreach (var item in list)
            {
                a(item, i);
            }
        }

        ///<summary>添字付きfor。</summary>
        public static void ForEach<T>(this IEnumerable<T> list, Action<T> a)
        {
            foreach (var item in list)
            {
                a(item);
            }
        }

        ///<summary>指定回数デリゲートを呼び出す。</summary>
        public static IEnumerable<T> Repeat<T>(long n, Func<T> f)
        {
            for (long i = 0; i < n; i++)
            {
                yield return f();
            }
        }

        public static T MinBy<T, U>(this IEnumerable<T> xs, Func<T, U> key) where U : IComparable<U>
        {
            return xs.Aggregate((a, b) => key(a).CompareTo(key(b)) <= 0 ? a : b);
        }

        public static T MaxBy<T, U>(this IEnumerable<T> xs, Func<T, U> key) where U : IComparable<U>
        {
            return xs.Aggregate((a, b) => key(a).CompareTo(key(b)) >= 0 ? a : b);
        }

        public static List<T> MaxBy2<T, U>(this IEnumerable<T> xs, Func<T, U> key) where U : IComparable<U>
        {
            return xs.Aggregate(
                new List<T>(),
                (list, b) =>
                {
                    if (list.Count == 0) { list.Add(b); return list; }

                    var aa = key(list[0]);
                    var bb = key(b);

                    if (aa.CompareTo(bb) < 0) list.Clear();

                    if (aa.CompareTo(bb) <= 0) { list.Add(b); return list; }

                    return list;
                });
        }

        public static List<T> Max2<T>(this IEnumerable<T> xs) where T : IComparable<T>
        {
            return xs.MaxBy2(o => o);
        }

        public static void Move<T>(this IList<T> list, int from, int to)
        {
            var item = list[from];

            for (var idx = from; idx > to; --idx)
            {
                list[idx] = list[idx - 1];
            }

            list[to] = item;
        }

        public static void Add2<T>(this IDictionary<T, int> xs, T key)
        {
            if (xs.ContainsKey(key))
                xs[key]++;
            else
                xs.Add(key, 1);
        }
    }

    public static class MathPlus
    {
        ///<summary>約数。順番は不定。</summary>
        public static List<long> Divisor(long n)
        {
            var list = Prime(n).
                GroupBy(id => id).
                Select(pair => new { prime = pair.Key, power = pair.Count() }).
                ToList();

            var result = list.Aggregate(new List<long>(), (left, pair) =>
            {
                var list2 = Enumerable.
                    Range(0, pair.power + 1).
                    Aggregate(new List<long>(), (res, l) =>
                    {
                        var next = res.Count > 0 ? res.Last() * pair.prime : 1L;
                        res.Add(next);
                        return res;
                    });

                if (left.Count == 0) return list2.ToList();

                return list2.
                    SelectMany(l => left.Select(m => l * m)).
                    ToList();
            });

            return result;
        }

        ///<summary>順列の数。</summary>
        public static long Permutation(long n, long r)
            => Factorial(n, r);

        ///<summary>組合せの数。</summary>
        public static long Combination(long n, long r)
        {
            if (r == 0) return 1;

            return Factorial(n, r) / Factorial(r);
        }

        ///<summary>階乗。カウントも指定可能。</summary>
        public static long Factorial(long a, long count = long.MaxValue)
        {
            long res = 1;

            for (long i = 0; a > 0 && i < count; i++)
            {
                checked { res *= a; }
                --a;
            }

            return res;
        }

        ///<summary>素因数分解。昇順。</summary>
        public static List<long> Prime(long a)
        {
            var res = new List<long>();

            var a2 = Math.Ceiling(Math.Sqrt(a));
            for (long b = 2; b <= a2; ++b)
            {
                while (a % b == 0)
                {
                    res.Add(b);
                    a = a / b;
                    a2 = Math.Ceiling(Math.Sqrt(a));
                }
            }

            if (a > 1) res.Add(a);
            return res;
        }

        ///<summary>最小公倍数。</summary>
        public static long Lcm(IEnumerable<long> list)
        {
            return list.Aggregate((a, b) => Lcm(a, b));
        }

        ///<summary>最小公倍数。</summary>
        public static long Lcm(long a, long b)
        {
            return checked(a * b) / Gcd(a, b);
        }

        ///<summary>最大公約数。</summary>
        public static long Gcd(IEnumerable<long> list)
        {
            return list.Aggregate((a, b) => Gcd(a, b));
        }

        ///<summary>最大公約数。</summary>
        public static long Gcd(long a, long b)
        {
            if (a < b)
                Gcd(b, a);

            while (b != 0)
            {
                var rem = a % b;
                a = b;
                b = rem;
            }

            return a;
        }

        ///<summary>切り上げ。</summary>
        public static long Ceiling(long a, long b) => (a + (b - 1)) / b;
    }
}