Problem:
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Depth First Search

Depth-first search (DFS) follows the strategy to search ”deeper” in the graph whenever possible. In DFS, edges are recursively explored out of the most recently discovered vertex $v$ that still has unexplored edges leaving it. When all of $v$'s edges have been explored, the search ”backtracks” to explore edges leaving the vertex from which $v$ was discovered.

This process continues until all the vertices that are reachable from the original source vertex have been discovered. If any undiscovered vertices remain, then one of them is selected as a new source and the search is repeated from that source.

DFS timestamps each vertex as follows:

$d[v]$ records when $v$ is first discovered.

$f[v]$ records when the search finishes examining $v$’s adjacency list.

Write a program which reads a directed graph $G = (V, E)$ and demonstrates DFS on the graph based on the following rules:

$G$ is given in an adjacency-list. Vertices are identified by IDs $1, 2,... n$ respectively.

IDs in the adjacency list are arranged in ascending order.

The program should report the discover time and the finish time for each vertex.

When there are several candidates to visit during DFS, the algorithm should select the vertex with the smallest ID.

The timestamp starts with 1.

Input

In the first line, an integer $n$ denoting the number of vertices of $G$ is given. In the next $n$ lines, adjacency lists of $u$ are given in the following format:

$u$ $k$ $v_1$ $v_2$ ... $v_k$

$u$ is ID of the vertex and $k$ denotes its degree. $v_i$ are IDs of vertices adjacent to $u$.

Output

For each vertex, print $id$, $d$ and $f$ separated by a space character in a line. $id$ is ID of the vertex, $d$ and $f$ is the discover time and the finish time respectively. Print in order of vertex IDs.

Constraints

$1 \leq n \leq 100$

Sample Input 1

4
1 1 2
2 1 4
3 0
4 1 3

Sample Output 1

1 1 8
2 2 7
3 4 5
4 3 6

Sample Input 2

6
1 2 2 3
2 2 3 4
3 1 5
4 1 6
5 1 6
6 0

Sample Output 2

1 1 12
2 2 11
3 3 8
4 9 10
5 4 7
6 5 6

This is example for Sample Input 2 (discover/finish)

Reference

Introduction to Algorithms, Thomas H. Cormen, Charles E. Leiserson, Ronald L. Rivest, and Clifford Stein. The MIT Press.

Solution in C# (judge verdict: WA: Presentation Error)

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace ALDS1_11_B_Depth_First_Search
{
	class Program
	{
		static void Main ( string[] args )
		{
			int vertexCount = int.Parse (Console.ReadLine ());
			Graph graph = new Graph (vertexCount);

			for (int lp = 0; lp < vertexCount; lp++)
			{
				int[] inputNum = Array.ConvertAll (Console.ReadLine ().Split (' '), int.Parse);

				for (int lp2 = 0; lp2 < inputNum[1]; lp2++)
				{
					graph.GetPath (inputNum[0], inputNum[2 + lp2]);
				}
			}

			Console.WriteLine (graph);
		}
	}

	class Graph
	{
		public Graph ( int size )
		{
			this.Map = new int[size, size];
			this.Timestamp = new int[size, 2];
			this.UsedIndex = new int[size];
			this.StateArray = new int[size];
		}

		private int[,] Map { set; get; }
		private	int[,] Timestamp { set; get; }
		private int[] UsedIndex { set; get; }
		private int[] StateArray { set; get; }
		private int Time = 1;

		public const int Exist = 1;
		private const int OutOfRange = -1;

		const int NotVisited = 0;
		const int Stay = 1;
		const int Visited = 2;

		public void GetPath ( int beginPoint, int adjacencyPoint )
		{
			Map[beginPoint - 1, adjacencyPoint - 1] = Exist;
		}

		public int[,] DepthFirstSearch ()
		{
			for (int lp = 0; lp < Map.GetLength(0); lp++)
			{
				if (StateArray[lp] == NotVisited)
				{
					Search (lp);
				}
			}

			return Timestamp;
		}

		private void Search ( int lp )
		{
			const int First = 0;
			const int Last = 1;

			UsedIndex.Initialize ();

			Stack<int> stack = new Stack<int> (Timestamp.Length / 2);
			stack.Push (lp);
			StateArray[lp] = Stay;
			Timestamp[lp, First] = Time;
			Time++;

			while (stack.Count != 0)
			{
				int point = stack.Peek ();
				int index = NextIndex (point);

				if (index != OutOfRange)
				{
					if (StateArray[index] == NotVisited)
					{
						StateArray[index] = Stay;
						Timestamp[index, First] = Time;
						Time++;
						stack.Push (index);
					}
				}
				else
				{
					stack.Pop ();
					StateArray[point] = Visited;
					Timestamp[point, Last] = Time;
					Time++;
				}
			}
		}

		private int NextIndex ( int index )
		{
			for (int lp = UsedIndex[index]; lp < UsedIndex.Length; lp++)
			{
				if (Map[index, lp] == Exist)
				{
					UsedIndex[index] = lp + 1;
					return lp;
				}
			}

			UsedIndex[index] = UsedIndex.Length + 1;

			return OutOfRange;
		}

		public override string ToString ()
		{
			int[,] result = DepthFirstSearch ();
			StringBuilder output = new StringBuilder (result.Length * 2);

			for (int row = 0; row < result.GetLength (0); row++)
			{
				output.Append (row + 1);
				output.Append (" ");
				output.Append (result[row, 0]);
				output.Append (" ");
				output.Append (result[row, 1]);
				output.AppendLine ();
			}

			return output.ToString ();
		}
	}
}