Problem:
Score : 400 points

Problem Statement

There are N one-off jobs available. If you take the i-th job and complete it, you will earn the reward of B_i after A_i days from the day you do it.

You can take and complete at most one of these jobs in a day.

However, you cannot retake a job that you have already done.

Find the maximum total reward that you can earn no later than M days from today.

You can already start working today.

Constraints

All values in input are integers.

1 \leq N \leq 10^5

1 \leq M \leq 10^5

1 \leq A_i \leq 10^5

1 \leq B_i \leq 10^4

Input

Input is given from Standard Input in the following format:

N M
A_1 B_1
A_2 B_2
\vdots
A_N B_N

Output

Print the maximum total reward that you can earn no later than M days from today.

Sample Input 1

3 4
4 3
4 1
2 2

Sample Output 1

5

You can earn the total reward of 5 by taking the jobs as follows:

Take and complete the first job today. You will earn the reward of 3 after four days from today.

Take and complete the third job tomorrow. You will earn the reward of 2 after two days from tomorrow, that is, after three days from today.

Sample Input 2

5 3
1 2
1 3
1 4
2 1
2 3

Sample Output 2

10

Sample Input 3

1 1
2 1

Sample Output 3

0

Solution in C# (Mono 4.6.2.0) (judge verdict: Time Limit Exceeded)

using System;
using System.Text;
using System.Linq;
using System.Collections;
using System.Collections.Generic;


class Program {

	static long mod = 1000000007;
	static int[] ans;
	static void Main(string[] args) {

		char[] cs = new char[] { ' ' };
		//char[] cs = new char[] { ' ', ',' };

		//int n = int.Parse(Console.ReadLine());
		//int val = int.Parse(Console.ReadLine());
		//int[] vals = parseAry(Console.ReadLine().Split(cs));
		//string str = Console.ReadLine();
		//string[] strs = Console.ReadLine().Split(cs);

		string res = "";
		int p = 0;

		int[] vals = parseAry(Console.ReadLine().Split(cs));
		int n = vals[0];
		int m = vals[1];
		Dictionary<int, List<int>> dic = new Dictionary<int, List<int>>();
		
		long[] days=new long[m+1];
		for ( int i = 0; i < n; i++ ) {
			vals = parseAry(Console.ReadLine().Split(cs));
			if ( !dic.ContainsKey(vals[0]) ) { dic.Add(vals[0], new List<int>()); }
			

			dic[vals[0]].Add(vals[1]);

		}

		for ( int i = 0; i <=m; i++ ) {

			if ( !dic.ContainsKey(i) ) { continue; }
			List<int> li=dic[i];
			if ( li.Count == 1 ) { days[i] = li[0]; }
			if ( li.Count > 1 ) {
				li.Sort();
				li.Reverse();
				days[i] = li[0];
				li.RemoveAt(0);

				if ( i + 1 <= m ) {
					if ( !dic.ContainsKey(i + 1) ) { dic.Add(i + 1, new List<int>()); }
					dic[i + 1].AddRange(li);
				}
			}
		}


			Console.WriteLine((long)days.Sum());

			return;

	}


	//	int配列をスペース区切りの文字列に変換
	static string stringBuilderArrayInt(int[] a) {
		StringBuilder sb = new StringBuilder();

		for ( int i = 0; i < a.Length; i++ ) {
			if ( a[i] == 1 ) { sb.Append(i + " "); }
		}
		if ( sb.Length > 1 ) {
			sb = sb.Remove(sb.Length - 1, 1);
		}
		return sb.ToString(); ;
	}


	//	文字列strをindex番目からdで上書き
	static string strOverWrite(string str, int i, string s) {
		return str.Remove(i, s.Length).Insert(i, s);
	}

	//　String[]  ----->  int[]
	static int[] parseAry(string[] str) {
		int[] nums = new int[str.Length];
		for ( int i = 0; i < str.Length; i++ ) { nums[i] = int.Parse(str[i]); }
		return nums;
	}
	//　String[]  ----->  long[]
	static long[] parseAryL(string[] str) {
		long[] nums = new long[str.Length];
		for ( int i = 0; i < str.Length; i++ ) { nums[i] = long.Parse(str[i]); }
		return nums;
	}

	//文字列を1文字ずつString[]に入れる
	static string[] strAry(String str) {
		string[] re = new string[str.Length];
		for ( int i = 0; i < str.Length; i++ ) { re[i] = str[i].ToString(); }
		return re;
	}


}