Problem:
Score : 300 points

Problem Statement

Takahashi has N balls. Initially, an integer A_i is written on the i-th ball.

He would like to rewrite the integer on some balls so that there are at most K different integers written on the N balls.

Find the minimum number of balls that Takahashi needs to rewrite the integers on them.

Constraints

1 \leq K \leq N \leq 200000

1 \leq A_i \leq N

All input values are integers.

Input

Input is given from Standard Input in the following format:

N K
A_1 A_2 ... A_N

Output

Print the minimum number of balls that Takahashi needs to rewrite the integers on them.

Sample Input 1

5 2
1 1 2 2 5

Sample Output 1

1

For example, if we rewrite the integer on the fifth ball to 2, there are two different integers written on the balls: 1 and 2.
On the other hand, it is not possible to rewrite the integers on zero balls so that there are at most two different integers written on the balls, so we should print 1.

Sample Input 2

4 4
1 1 2 2

Sample Output 2

0

Already in the beginning, there are two different integers written on the balls, so we do not need to rewrite anything.

Sample Input 3

10 3
5 1 3 2 4 1 1 2 3 4

Sample Output 3

3

Solution in C# (Mono 4.6.2.0) (judge verdict: Time Limit Exceeded)

using System;
using System.IO;
using System.Linq;
using System.Diagnostics;
using System.Threading.Tasks;
using System.Collections.Generic;

//

namespace Kyoupro
{
    class Program
    {
        
        static void Main(string[] args)
        {    

            //整数の数を取得
            var input = Console.ReadLine().Split(' ').Select(x => int.Parse(x));
            int N = input.ElementAt(0);//ボール個数
            int K = input.ElementAt(1);//あるべき種類

            //空白区切り一行
            var balls = Console.ReadLine().Split(' ').Select(x => int.Parse(x));
            
            //カウント数だけの配列？
            var qqqq = balls.GroupBy(x => x).Select(x =>x.Count());
            qqqq = qqqq.OrderBy(x => x);//昇順ソート
            
            //現在の種類数を取得
            int now = qqqq.ToArray().Length;

            //リスト化
            var qlist = qqqq.ToList();

            int count = 0;
            

            while(K<now)//nowが大きいうちは処理し続ける//減らすことはあっても足すことはない
            {
                //少ない重複数を足す
                //Console.WriteLine("書き換える回数は{0}",qlist.First());
                count +=qlist.First();

                //要素を削除する
                qlist.RemoveAt(0);
                now--;

            }

            
            Console.WriteLine(count);
                       


        }
    }
}