Problem:
Score : 400 points

Problem Statement

Takahashi has a string S consisting of lowercase English letters.

Starting with this string, he will produce a new one in the procedure given as follows.

The procedure consists of Q operations. In Operation i (1 \leq i \leq Q), an integer T_i is provided, which means the following:

If T_i = 1: reverse the string S.

If T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.

If F_i = 1 : Add C_i to the beginning of the string S.

If F_i = 2 : Add C_i to the end of the string S.

Help Takahashi by finding the final string that results from the procedure.

Constraints

1 \leq |S| \leq 10^5

S consists of lowercase English letters.

1 \leq Q \leq 2 \times 10^5

T_i = 1 or 2.

F_i = 1 or 2, if provided.

C_i is a lowercase English letter, if provided.

Input

Input is given from Standard Input in the following format:

S
Q
Query_1
:
Query_Q

In the 3-rd through the (Q+2)-th lines, Query_i is one of the following:

1

which means T_i = 1, and:

2 F_i C_i

which means T_i = 2.

Output

Print the resulting string.

Sample Input 1

a
4
2 1 p
1
2 2 c
1

Sample Output 1

cpa

There will be Q = 4 operations. Initially, S is a.

Operation 1: Add p at the beginning of S. S becomes pa.

Operation 2: Reverse S. S becomes ap.

Operation 3: Add c at the end of S. S becomes apc.

Operation 4: Reverse S. S becomes cpa.

Thus, the resulting string is cpa.

Sample Input 2

a
6
2 2 a
2 1 b
1
2 2 c
1
1

Sample Output 2

aabc

There will be Q = 6 operations. Initially, S is a.

Operation 1: S becomes aa.

Operation 2: S becomes baa.

Operation 3: S becomes aab.

Operation 4: S becomes aabc.

Operation 5: S becomes cbaa.

Operation 6: S becomes aabc.

Thus, the resulting string is aabc.

Sample Input 3

y
1
2 1 x

Sample Output 3

xy

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

using System;
using System.Collections.Generic;
using System.Linq;

namespace ConsoleTest
{
    class Program
    {
        static void Main(string[] args)
        {
            List<char> ca = Console.ReadLine().ToCharArray().ToList();
            var appendFront = new List<char>();
            var appendEnd = new List<char>();
            var num = int.Parse(Console.ReadLine());
            bool isReverse = false;
            for(int i =0; i<num; ++i)
            {
                char[] ma = Console.ReadLine().Split(' ')
                    .Select(ss => ss[0])
                    .ToArray();
                if(ma[0]=='1')
                {
                    isReverse = !isReverse;
                }
                else
                {
                    bool isAppendFront = isReverse ? ma[1] == '2' : ma[1] == '1';
                    if (isAppendFront)
                    {
                        appendFront.Add(ma[2]);
                    }
                    else
                    {
                        appendEnd.Add(ma[2]);
                    }
                }
                //Console.WriteLine(string.Format("step[{0}] : {1}", i, s));
            }
            appendFront.Reverse();
            string j = new string(appendFront.ToArray()) + new string(ca.ToArray()) + new string(appendEnd.ToArray());
            if (isReverse)
            {
                j = new string(j.Reverse().ToArray());
            }
            Console.WriteLine(j.ToArray());

        }
    }
}