Problem:
Score : 400 points

Problem Statement

We have N balls. The i-th ball has an integer A_i written on it.

For each k=1, 2, ..., N, solve the following problem and print the answer.

Find the number of ways to choose two distinct balls (disregarding order) from the N-1 balls other than the k-th ball so that the integers written on them are equal.

Constraints

3 \leq N \leq 2 \times 10^5

1 \leq A_i \leq N

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

For each k=1,2,...,N, print a line containing the answer.

Sample Input 1

5
1 1 2 1 2

Sample Output 1

2
2
3
2
3

Consider the case k=1 for example. The numbers written on the remaining balls are 1,2,1,2.

From these balls, there are two ways to choose two distinct balls so that the integers written on them are equal.

Thus, the answer for k=1 is 2.

Sample Input 2

4
1 2 3 4

Sample Output 2

0
0
0
0

No two balls have equal numbers written on them.

Sample Input 3

5
3 3 3 3 3

Sample Output 3

6
6
6
6
6

Any two balls have equal numbers written on them.

Sample Input 4

8
1 2 1 4 2 1 4 1

Sample Output 4

5
7
5
7
7
5
7
5

Solution in C# (Mono 4.6.2.0) (judge verdict: Wrong Answer)

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using static System.Console;
using static System.Math;

namespace Atcoder
{
    class Program
    {
        static void Main(string[] args)
        {
            try
            {
                Solve.Answer();
            }
            catch (Exception ex)
            {
                WriteLine(ex.ToString());
            }
        }
    }

    public class Solve
    {
        public static void Answer()
        {
            var N = IO_ShortCut.ReadInt;
            var A = IO_ShortCut.ReadSplitInt;

            var sameNumCount = Enumerable.Repeat(0, 200010).ToList();
            foreach (var num in A)
            {
                sameNumCount[num]++;
            }
            var totalCombination = 0;
            foreach (var cnt in sameNumCount)
            {
                if (cnt == 0 || cnt == 1) continue;
                totalCombination += MathLib.Cmb(cnt, 2);
            }
            for (int i = 0; i < N; i++)
            {
                WriteLine(totalCombination - (sameNumCount[A[i]] - 1));
            }
        }
    }

    public class IO_ShortCut
    {
        #region Input
        public static string ReadString => ReadLine();
        public static int ReadInt => int.Parse(ReadLine());
        public static long ReadLong => long.Parse(ReadLine());
        public static double ReadDouble => double.Parse(ReadLine());

        public static List<string> ReadSplitString => ReadLine().Split().ToList();
        public static List<int> ReadSplitInt => ReadLine().Split().Select(s => int.Parse(s)).ToList();
        public static List<long> ReadSplitLong => ReadLine().Split().Select(s => long.Parse(s)).ToList();
        public static List<double> ReadSplitdouble => ReadLine().Split().Select(s => double.Parse(s)).ToList();
        #endregion

        #region Output
        public static void OutJoinSpace<T>(IEnumerable<T> list) => WriteLine(string.Join(" ", list));
        public static void WriteLineYes_or_No(bool flag) => WriteLine(flag ? "Yes" : "No");

        #endregion
    }

    /// <summary>
    /// 正の数の四則演算のみ対応
    /// </summary>
    public class Mod
    {
        // 割る数の定義
        private readonly static long M = 1000000007;

        // 足し算
        public static long Add(long a, long b) => (a * b) % M;
        // 引き算
        public static long Sub(long a, long b) => (a - b) % M >= 0 ? (a - b) % M : (a - b) % M + M;
        // 掛け算
        public static long Multi(long a, long b) => (a * b) % M;
    }

    public class MathLib
    {
        public static int Cmb(int n, int k)
        {
            var a = 1;
            for (int i = 0; i < k; i++)
            {
                a *= n;
                n--;
            }
            return k == 0 ? 1 : a / k;
        }

        public static int Cmb2(int n, int k)
        {
            if (k == 0) return 1;
            if (k == 1) return n;
            if (n == k) return 1;
            return Cmb2(n - 1, k) + Cmb2(n - 1, k - 1);
        }
    }
}