Problem:
Score : 200 points

Problem Statement

Determine if an N-sided polygon (not necessarily convex) with sides of length L_1, L_2, ..., L_N can be drawn in a two-dimensional plane.

You can use the following theorem:

Theorem: an N-sided polygon satisfying the condition can be drawn if and only if the longest side is strictly shorter than the sum of the lengths of the other N-1 sides.

Constraints

All values in input are integers.

3 \leq N \leq 10

1 \leq L_i \leq 100

Input

Input is given from Standard Input in the following format:

N
L_1 L_2 ... L_N

Output

If an N-sided polygon satisfying the condition can be drawn, print Yes; otherwise, print No.

Sample Input 1

4
3 8 5 1

Sample Output 1

Yes

Since 8 < 9 = 3 + 5 + 1, it follows from the theorem that such a polygon can be drawn on a plane.

Sample Input 2

4
3 8 4 1

Sample Output 2

No

Since 8 \geq 8 = 3 + 4 + 1, it follows from the theorem that such a polygon cannot be drawn on a plane.

Sample Input 3

10
1 8 10 5 8 12 34 100 11 3

Sample Output 3

No

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace AtCoder.AtCoderBeginnerContest_117
{
    public class B_Polygon
    {
        public static void Main(string[] args)
        {
            var Nstr = Console.ReadLine();
            int N = int.Parse(Nstr);

            var line = Console.ReadLine();
            var str = line.Split(' ');
            int[] L = new int[N];

            for (int i = 0; i < N; i++)
            {
                L[i] = int.Parse(str[i]);
            }

            int max = L[0];
            int tmp = 0;
            for (int i = 1; i < N; i++)
            {
                if (max < L[i])
                {
                    max = L[i];
                    tmp = i;
                }
            }

            int sum = 0;

            int tmpn = 0;

            tmpn = L[0];
            L[0] = L[tmp];
            L[tmp] = tmpn;

            for (int i = 1; i < N; i++)
            {
                sum += L[i];
            }

            if (L[0] >= sum)
            {
                Console.WriteLine("No");
            }
            else
            {
                Console.WriteLine("Yes");
            }
        }
    }
}