Problem:
Score : 300 points

Problem Statement

You are given an integer N.

For two positive integers A and B, we will define F(A,B) as the larger of the following: the number of digits in the decimal notation of A, and the number of digits in the decimal notation of B.

For example, F(3,11) = 2 since 3 has one digit and 11 has two digits.

Find the minimum value of F(A,B) as (A,B) ranges over all pairs of positive integers such that N = A \times B.

Constraints

1 \leq N \leq 10^{10}

N is an integer.

Input

The input is given from Standard Input in the following format:

N

Output

Print the minimum value of F(A,B) as (A,B) ranges over all pairs of positive integers such that N = A \times B.

Sample Input 1

10000

Sample Output 1

3

F(A,B) has a minimum value of 3 at (A,B)=(100,100).

Sample Input 2

1000003

Sample Output 2

7

There are two pairs (A,B) that satisfy the condition: (1,1000003) and (1000003,1). For these pairs, F(1,1000003)=F(1000003,1)=7.

Sample Input 3

9876543210

Sample Output 3

6

Solution in C# (.NET Core 3.1.201) (judge verdict: Time Limit Exceeded)

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Text.RegularExpressions;
using System.Threading.Tasks;

namespace AtCoder
{
    class Program
    {
        static void Main(string[] args)
        {
            long N = long.Parse(Console.ReadLine());

            long ans = Digit(N);

            for (var i = 1; i * i <= N ; i++)
            {
                if(N % i == 0)
                {
                    ans = Math.Min(Math.Max(Digit(i), Digit(N / i)), ans);
                }
            }

            Console.WriteLine(ans);
        }

        public static long Digit(long num)
        {
            long digit = 1;
            for (long i = num; i >= 10; i /= 10)
            {
                digit++;
            }
            return digit;
            //// Mathf.Log10(0)はNegativeInfinityを返すため、別途処理する。
            //return (num == 0) ? 1 : ((long)Math.Log10(num) + 1);
        }
    }
}