Problem:
Score : 200 points

Problem Statement

There are N + 1 squares arranged in a row, numbered 0, 1, ..., N from left to right.

Initially, you are in Square X.
You can freely travel between adjacent squares. Your goal is to reach Square 0 or Square N.
However, for each i = 1, 2, ..., M, there is a toll gate in Square A_i, and traveling to Square A_i incurs a cost of 1.
It is guaranteed that there is no toll gate in Square 0, Square X and Square N.

Find the minimum cost incurred before reaching the goal.

Constraints

1 \leq N \leq 100

1 \leq M \leq 100

1 \leq X \leq N - 1

1 \leq A_1 < A_2 < ... < A_M \leq N

A_i \neq X

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M X
A_1 A_2 ... A_M

Output

Print the minimum cost incurred before reaching the goal.

Sample Input 1

5 3 3
1 2 4

Sample Output 1

1

The optimal solution is as follows:

First, travel from Square 3 to Square 4. Here, there is a toll gate in Square 4, so the cost of 1 is incurred.

Then, travel from Square 4 to Square 5. This time, no cost is incurred.

Now, we are in Square 5 and we have reached the goal.

In this case, the total cost incurred is 1.

Sample Input 2

7 3 2
4 5 6

Sample Output 2

0

We may be able to reach the goal at no cost.

Sample Input 3

10 7 5
1 2 3 4 6 8 9

Sample Output 3

3

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

using System;
using System.Collections;
using System.Linq;
class Program
{
    static int Main()
    {
        //int n = int.Parse(Console.ReadLine());
        string[] s = Console.ReadLine().Split(' ');
        int n, m, x;
        n = int.Parse(s[0]);
        m = int.Parse(s[1]);
        x = int.Parse(s[2]);
        int[] a = Console.ReadLine().Split(' ').Select(p => int.Parse(p)).ToArray();
        int ans1 = 0;
        for (int i = x + 1; i < n; i++)
            ans1 += a.Count(p => p == i);
        int ans2 = 0;
        for (int i = 1; i < x; i++)
            ans2 += a.Count(p => p == i);
        Console.WriteLine(Math.Min(ans1, ans2));

        return 0;
    }
}