Problem:
Score : 300 points

Problem Statement

You are given a string S of length N and another string T of length M.
These strings consist of lowercase English letters.

A string X is called a good string when the following conditions are all met:

Let L be the length of X. L is divisible by both N and M.

Concatenating the 1-st, (\frac{L}{N}+1)-th, (2 \times \frac{L}{N}+1)-th, ..., ((N-1)\times\frac{L}{N}+1)-th characters of X, without changing the order, results in S.

Concatenating the 1-st, (\frac{L}{M}+1)-th, (2 \times \frac{L}{M}+1)-th, ..., ((M-1)\times\frac{L}{M}+1)-th characters of X, without changing the order, results in T.

Determine if there exists a good string. If it exists, find the length of the shortest such string.

Constraints

1 \leq N,M \leq 10^5

S and T consist of lowercase English letters.

|S|=N

|T|=M

Input

Input is given from Standard Input in the following format:

N M
S
T

Output

If a good string does not exist, print -1; if it exists, print the length of the shortest such string.

Sample Input 1

3 2
acp
ae

Sample Output 1

6

For example, the string accept is a good string.
There is no good string shorter than this, so the answer is 6.

Sample Input 2

6 3
abcdef
abc

Sample Output 2

-1

Sample Input 3

15 9
dnsusrayukuaiia
dujrunuma

Sample Output 3

45

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

using System;
using System.Collections.Generic;
using System.Linq;
using static System.Console;
using static System.Convert;
using static System.Math;

class Program
{
    static void Main(string[] args)
    {
        var input = Array.ConvertAll(ReadLine().Split(' '), int.Parse);
        var length1 = input[0];
        var length2 = input[1];
        var str1 = ReadLine();
        var str2 = ReadLine();
        var g = Calculation.GCD(length1, length2);
        for(var i = 0; i <g; i++)
        {
            if (str1.Substring(i*(length1/g), 1) != str2.Substring(i*(length2/g), 1)) { WriteLine(-1);return; }
        }
        WriteLine(Calculation.LCM((long)length1,(long)length2));
    }
}
public class Calculation
{
   public static int LCM(int num1, int num2)
    {
        return num1 / GCD(num1, num2) * num2;
    }

    public static long LCM(long num1, long num2)
    {
        return num1 / GCD(num1, num2) * num2;
    }
  
  public static int GCD(int num1, int num2)
    {
        return num1 < num2 ? GCD(num2, num1) :
            num2 > 0 ? GCD(num2, num1 % num2) : num1;
    }

    public static long GCD(long num1, long num2)
    {
        return num1 < num2 ? GCD(num2, num1) :
            num2 > 0 ? GCD(num2, num1 % num2) : num1;
    }
}