Problem:
Score : 400 points

Problem Statement

Takahashi has a string S consisting of lowercase English letters.

Starting with this string, he will produce a new one in the procedure given as follows.

The procedure consists of Q operations. In Operation i (1 \leq i \leq Q), an integer T_i is provided, which means the following:

If T_i = 1: reverse the string S.

If T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.

If F_i = 1 : Add C_i to the beginning of the string S.

If F_i = 2 : Add C_i to the end of the string S.

Help Takahashi by finding the final string that results from the procedure.

Constraints

1 \leq |S| \leq 10^5

S consists of lowercase English letters.

1 \leq Q \leq 2 \times 10^5

T_i = 1 or 2.

F_i = 1 or 2, if provided.

C_i is a lowercase English letter, if provided.

Input

Input is given from Standard Input in the following format:

S
Q
Query_1
:
Query_Q

In the 3-rd through the (Q+2)-th lines, Query_i is one of the following:

1

which means T_i = 1, and:

2 F_i C_i

which means T_i = 2.

Output

Print the resulting string.

Sample Input 1

a
4
2 1 p
1
2 2 c
1

Sample Output 1

cpa

There will be Q = 4 operations. Initially, S is a.

Operation 1: Add p at the beginning of S. S becomes pa.

Operation 2: Reverse S. S becomes ap.

Operation 3: Add c at the end of S. S becomes apc.

Operation 4: Reverse S. S becomes cpa.

Thus, the resulting string is cpa.

Sample Input 2

a
6
2 2 a
2 1 b
1
2 2 c
1
1

Sample Output 2

aabc

There will be Q = 6 operations. Initially, S is a.

Operation 1: S becomes aa.

Operation 2: S becomes baa.

Operation 3: S becomes aab.

Operation 4: S becomes aabc.

Operation 5: S becomes cbaa.

Operation 6: S becomes aabc.

Thus, the resulting string is aabc.

Sample Input 3

y
1
2 1 x

Sample Output 3

xy

Solution in C# (Mono 4.6.2.0) (judge verdict: Time Limit Exceeded)

using System;
using System.Globalization;
using System.Linq;

class Program
{
    static void solve()
    {
        double op_limit = Math.Round(Math.Pow(10, 5) * 2);

        string text = Console.ReadLine();
        if (String.IsNullOrEmpty(text) ||
                text.Length >= 1 &&
                text.Length > (op_limit / 2))
            return;

        text = text.ToLower(culture: CultureInfo.CurrentCulture);

        int opNumber = int.Parse(Console.ReadLine());
        if (opNumber >= 1 && opNumber <= op_limit)
        {
            for (int i = 0; i < opNumber; i++)
            {
                string line = Console.ReadLine();
                if (String.IsNullOrEmpty(line)) return;

                string[] opArr = line.Split(' ');
                int op = int.Parse(opArr[0]);
                if (op == 1)
                    text = new string(text.Reverse().ToArray());                 
                else if (op == 2)
                {
                    int op2 = int.Parse(opArr[1]);
                    char c = opArr[2][0];
                    if (op2 == 1)
                        text = string.Concat(c, text);
                    else if (op2 == 2)
                        text = string.Concat(text, c);
                }
            }
            Console.WriteLine(text);
        }
    }

    static void Main(string[] args)
    {
        solve();
    }
}