Problem:
Score : 200 points

Problem Statement

Takahashi loves gold coins. He gains 1000 happiness points for each 500-yen coin he has and gains 5 happiness points for each 5-yen coin he has. (Yen is the currency of Japan.)

Takahashi has X yen. If he exchanges his money so that he will gain the most happiness points, how many happiness points will he earn?

(We assume that there are six kinds of coins available: 500-yen, 100-yen, 50-yen, 10-yen, 5-yen, and 1-yen coins.)

Constraints

0 \leq X \leq 10^9

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print the maximum number of happiness points that can be earned.

Sample Input 1

1024

Sample Output 1

2020

By exchanging his money so that he gets two 500-yen coins and four 5-yen coins, he gains 2020 happiness points, which is the maximum number of happiness points that can be earned.

Sample Input 2

0

Sample Output 2

0

He is penniless - or yenless.

Sample Input 3

1000000000

Sample Output 3

2000000000

He is a billionaire - in yen.

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

using System;
using System.Collections;
using System.Collections.Generic;
using System.Linq;
using System.IO;
using System.Text;
using System.Globalization;
using System.Diagnostics;


class Solve
{
  public Solve() { }
  public static int Main()
  {
    new Solve().calc();
    return 0;
  }


  Scanner cin;

  void calc()
  {
    cin = new Scanner();
    uint X = cin.nextUInt();
    uint count500 = X / 500;
    X -= 500 * count500;
    uint count5 = X / 5;

    uint result = count500 * 1000 + count5 * 5;

    Console.WriteLine(result.ToString());

  }
}
class Modulo
{
  private const int M = 1000000007;
  private readonly int[] m_facs;
  public int Mul(int a, int b)
  {
    return (int)(Math.BigMul(a, b) % M);
  }
  public Modulo(int n)
  {
    m_facs = new int[n + 1];
    m_facs[0] = 1;
    for (int i = 1; i <= n; ++i)
    {
      m_facs[i] = Mul(m_facs[i - 1], i);
    }
  }
  public int Fac(int n)
  {
    return m_facs[n];
  }
  public int Pow(int a, int m)
  {
    switch (m)
    {
      case 0:
        return 1;
      case 1:
        return a;
      default:
        int p1 = Pow(a, m / 2);
        int p2 = Mul(p1, p1);
        return ((m % 2) == 0) ? p2 : Mul(p2, a);
    }
  }
  public int Div(int a, int b)
  {
    return Mul(a, Pow(b, M - 2));
  }
  public int Ncr(int n, int r)
  {
    if (n < r) { return 0; }
    if (n == r) { return 1; }
    int res = Fac(n);
    res = Div(res, Fac(r));
    res = Div(res, Fac(n - r));
    return res;
  }
}

class Scanner
{
  string[] s;
  int i;

  char[] cs = new char[] { ' ' };

  public Scanner()
  {
    s = new string[0];
    i = 0;
  }

  public string next()
  {
    if (i < s.Length) return s[i++];
    string st = Console.ReadLine();
    while (st == "") st = Console.ReadLine();
    s = st.Split(cs, StringSplitOptions.RemoveEmptyEntries);
    if (s.Length == 0) return next();
    i = 0;
    return s[i++];
  }

  public int nextInt()
  {
    return int.Parse(next());
  }
  public uint nextUInt()
  {
    return uint.Parse(next());
  }
  public int[] ArrayInt(int N, int add = 0)
  {
    int[] Array = new int[N];
    for (int i = 0; i < N; i++)
    {
      Array[i] = nextInt() + add;
    }
    return Array;
  }

  public long nextLong()
  {
    return long.Parse(next());
  }

  public ulong nextULong()
  {
    return ulong.Parse(next());
  }

  public long[] ArrayLong(int N, long add = 0)
  {
    long[] Array = new long[N];
    for (int i = 0; i < N; i++)
    {
      Array[i] = nextLong() + add;
    }
    return Array;
  }

  public double nextDouble()
  {
    return double.Parse(next());
  }


  public double[] ArrayDouble(int N, double add = 0)
  {
    double[] Array = new double[N];
    for (int i = 0; i < N; i++)
    {
      Array[i] = nextDouble() + add;
    }
    return Array;
  }
}