Problem:
Score : 200 points

Problem Statement

Takahashi has many red balls and blue balls. Now, he will place them in a row.

Initially, there is no ball placed.

Takahashi, who is very patient, will do the following operation 10^{100} times:

Place A blue balls at the end of the row of balls already placed. Then, place B red balls at the end of the row.

How many blue balls will be there among the first N balls in the row of balls made this way?

Constraints

1 \leq N \leq 10^{18}

A, B \geq 0

0 < A + B \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N A B

Output

Print the number of blue balls that will be there among the first N balls in the row of balls.

Sample Input 1

8 3 4

Sample Output 1

4

Let b denote a blue ball, and r denote a red ball. The first eight balls in the row will be bbbrrrrb, among which there are four blue balls.

Sample Input 2

8 0 4

Sample Output 2

0

He placed only red balls from the beginning.

Sample Input 3

6 2 4

Sample Output 3

2

Among bbrrrr, there are two blue balls.

Solution in C# (Mono 4.6.2.0) (judge verdict: Wrong Answer)

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace ABC158
{
    class Program
    {
        static void Main(string[] args)
        {
            b();
        }

        public static void b()
        {
            long[] nab = Console.ReadLine().Split(' ').Select(long.Parse).ToArray();
            long n = nab[0], a = nab[1], b = nab[2];
            if (n <= a)
            {
                Console.WriteLine(n);
                return;
            }
            else if (n <= a + b)
            {
                Console.WriteLine(a);
                return;
            }
            else if (a == 0 || n == 0)
            {
                Console.WriteLine(0);
                return;
            }
            else if(a == 0 && b == 00)
            {
                Console.WriteLine(0);
                return;
            }
            long sum = 0;
            long bb = n / (a + b);
            n %= a + b;
            sum = bb * a;
            for(long i = 0; i < n; i++)
            {
                sum++;
            }
            Console.WriteLine(sum);
        }

    }
}