Problem:
Score : 200 points

Problem Statement

There are N gems. The value of the i-th gem is V_i.

You will choose some of these gems, possibly all or none, and get them.

However, you need to pay a cost of C_i to get the i-th gem.

Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid.

Find the maximum possible value of X-Y.

Constraints

All values in input are integers.

1 \leq N \leq 20

1 \leq C_i, V_i \leq 50

Input

Input is given from Standard Input in the following format:

N
V_1 V_2 ... V_N
C_1 C_2 ... C_N

Output

Print the maximum possible value of X-Y.

Sample Input 1

3
10 2 5
6 3 4

Sample Output 1

5

If we choose the first and third gems, X = 10 + 5 = 15 and Y = 6 + 4 = 10.
We have X-Y = 5 here, which is the maximum possible value.

Sample Input 2

4
13 21 6 19
11 30 6 15

Sample Output 2

6

Sample Input 3

1
1
50

Sample Output 3

0

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

using System;

namespace ABC125_b
{
    class Program
    {
        static void Main(string[] args)
        {
            string[] array1 = Console.ReadLine().Split(' ');
            int a = int.Parse(array1[0]);
            string[] array2 = Console.ReadLine().Split(' ');
            int[] intAry2 = Array.ConvertAll<string, int>(array2, delegate (string value)
            {
                return int.Parse(value);
            });
            string[] array3 = Console.ReadLine().Split(' ');
            int[] intAry3 = Array.ConvertAll<string, int>(array3, delegate (string value)
            {
                return int.Parse(value);
            });
            int[] minus = new int[a];
            int max = 0;
            for(int i = 0; i < a; i++)
            {
                if(intAry2[i] > intAry3[i])
                {
                    minus[i] = intAry2[i] - intAry3[i];
                }
                max = max + minus[i];
            }

            Console.WriteLine(max);

        }
    }
}