Problem:
Score : 100 points

Problem Statement

We conducted a survey on newspaper subscriptions.
More specifically, we asked each of the N respondents the following two questions:

Question 1: Are you subscribing to Newspaper X?

Question 2: Are you subscribing to Newspaper Y?

As the result, A respondents answered "yes" to Question 1, and B respondents answered "yes" to Question 2.

What are the maximum possible number and the minimum possible number of respondents subscribing to both newspapers X and Y?

Write a program to answer this question.

Constraints

1 \leq N \leq 100

0 \leq A \leq N

0 \leq B \leq N

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N A B

Output

Print the maximum possible number and the minimum possible number of respondents subscribing to both newspapers, in this order, with a space in between.

Sample Input 1

10 3 5

Sample Output 1

3 0

In this sample, out of the 10 respondents, 3 answered they are subscribing to Newspaper X, and 5 answered they are subscribing to Newspaper Y.

Here, the number of respondents subscribing to both newspapers is at most 3 and at least 0.

Sample Input 2

10 7 5

Sample Output 2

5 2

In this sample, out of the 10 respondents, 7 answered they are subscribing to Newspaper X, and 5 answered they are subscribing to Newspaper Y.

Here, the number of respondents subscribing to both newspapers is at most 5 and at least 2.

Sample Input 3

100 100 100

Sample Output 3

100 100

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

using System;

class Program
	{
		static void Main(string[] args)
		{
			string[] input = Console.ReadLine().Split(' ');
			int	x=int.Parse(input[1]);
			int y=int.Parse(input[2]);
			int c=0;
			int n=int.Parse(input[0]);
			int d=0;
			if(x>=y)
			{
				c=y;
				if(n-c-x >0)
				{
				d=0;
				}
				else
				{
					d=(n-c-x)*-1;
				}
			}
			else
			{
				c=x;
				if(n-c-y >0)
				{
					d=0;
				}
				else
				{
					d=(n-c-y)*-1;
				}
			}
 
			Console.WriteLine(c + " " + d);
			
		}
	}