Problem:
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Distance II

Your task is to calculate the distance between two $n$ dimensional vectors $x = \{x_1, x_2, ..., x_n\}$ and $y = \{y_1, y_2, ..., y_n\}$.

The Minkowski's distance defined below is a metric which is a generalization of both the Manhattan distance and the Euclidean distance.

\[
D_{xy} = (\sum_{i=1}^n |x_i - y_i|^p)^{\frac{1}{p}}
\]

It can be the Manhattan distance

\[
D_{xy} = |x_1 - y_1| + |x_2 - y_2| + ... + |x_n - y_n|
\]

where $p = 1 $.

It can be the Euclidean distance

\[
D_{xy} = \sqrt{(|x_1 - y_1|)^{2} + (|x_2 - y_2|)^{2} + ... + (|x_n - y_n|)^{2}}
\]

where $p = 2 $.

Also, it can be the Chebyshev distance

\[
D_{xy} = max_{i=1}^n (|x_i - y_i|)
\]

where $p = \infty$

Write a program which reads two $n$ dimensional vectors $x$ and $y$, and calculates Minkowski's distance where $p = 1, 2, 3, \infty$ respectively.

Input

In the first line, an integer $n$ is given. In the second and third line, $x = \{x_1, x_2, ... x_n\}$ and $y = \{y_1, y_2, ... y_n\}$ are given respectively. The elements in $x$ and $y$ are given in integers.

Output

Print the distance where $p = 1, 2, 3$ and $\infty$ in a line respectively.
The output should not contain an absolute error greater than 10-5.

Constraints

$1 \leq n \leq 100$

$0 \leq x_i, y_i \leq 1000$

Sample Input

3
1 2 3
2 0 4

Sample Output

4.000000
2.449490
2.154435
2.000000

Solution in C# (judge verdict: Accepted)

using System;
using System.Linq;
public class Hello{
    public static void Main(){
        
        int kosu=int.Parse(Console.ReadLine());
        string [] a=Console.ReadLine().Split(' ');
        string [] b=Console.ReadLine().Split(' ');
        
        int [] x=a.Select(int.Parse).ToArray();
        int [] y=b.Select(int.Parse).ToArray();
        
        double sum1=0;
        double sum2=0;
        double sum3=0;
        double max=0;
        for(int i=0;i<kosu;i++)
        {
            sum1+=Math.Abs(x[i]-y[i]);
            sum2+=Math.Pow(Math.Abs(x[i]-y[i]),2);
            sum3+=Math.Pow(Math.Abs(x[i]-y[i]),3);
            if(Math.Abs(x[i]-y[i])>max)max=Math.Abs(x[i]-y[i]);
        }
        Console.WriteLine(sum1);
        Console.WriteLine(Math.Sqrt(sum2));
        Console.WriteLine(Math.Pow(sum3,1.0/3.0));
        Console.WriteLine(max);
    }
}