Problem:
Score: 400 points

Problem Statement

Amidakuji is a traditional method of lottery in Japan.

To make an amidakuji, we first draw W parallel vertical lines, and then draw horizontal lines that connect them. The length of each vertical line is H+1 [cm], and the endpoints of the horizontal lines must be at 1, 2, 3, ..., or H [cm] from the top of a vertical line.

A valid amidakuji is an amidakuji that satisfies the following conditions:

No two horizontal lines share an endpoint.

The two endpoints of each horizontal lines must be at the same height.

A horizontal line must connect adjacent vertical lines.

Find the number of the valid amidakuji that satisfy the following condition, modulo 1\ 000\ 000\ 007: if we trace the path from the top of the leftmost vertical line to the bottom, always following horizontal lines when we encounter them, we reach the bottom of the K-th vertical line from the left.

For example, in the following amidakuji, we will reach the bottom of the fourth vertical line from the left.

Constraints

H is an integer between 1 and 100 (inclusive).

W is an integer between 1 and 8 (inclusive).

K is an integer between 1 and W (inclusive).

Input

Input is given from Standard Input in the following format:

H W K

Output

Print the number of the amidakuji that satisfy the condition, modulo 1\ 000\ 000\ 007.

Sample Input 1

1 3 2

Sample Output 1

1

Only the following one amidakuji satisfies the condition:

Sample Input 2

1 3 1

Sample Output 2

2

Only the following two amidakuji satisfy the condition:

Sample Input 3

2 3 3

Sample Output 3

1

Only the following one amidakuji satisfies the condition:

Sample Input 4

2 3 1

Sample Output 4

5

Only the following five amidakuji satisfy the condition:

Sample Input 5

7 1 1

Sample Output 5

1

As there is only one vertical line, we cannot draw any horizontal lines. Thus, there is only one amidakuji that satisfies the condition: the amidakuji with no horizontal lines.

Sample Input 6

15 8 5

Sample Output 6

437760187

Be sure to print the answer modulo 1\ 000\ 000\ 007.

Solution in C# (Mono 4.6.2.0) (judge verdict: Time Limit Exceeded)

using System;
using System.Collections.Generic;
using System.Linq;
using System.IO;
using SB = System.Text.StringBuilder;
//using System.Text.RegularExpressions;
//using System.Globalization;
//using System.Diagnostics;
using static System.Console;
using System.Numerics;
using static System.Math;
using pair = Pair<long, long>;

class Program
{
    static void Main()
    {
        //SetOut(new StreamWriter(OpenStandardOutput()) { AutoFlush = false });
        new Program().solve();
        Out.Flush();
    }
    readonly Scanner cin = new Scanner();
    readonly int[] dd = { 0, 1, 0, -1, 0 }; //→↓←↑
    readonly int mod = 1000000007;
    readonly int dom = 998244353;
    bool chmax<T>(ref T a, T b) where T : IComparable<T> { if (a.CompareTo(b) < 0) { a = b; return true; } return false; }
    bool chmin<T>(ref T a, T b) where T : IComparable<T> { if (b.CompareTo(a) < 0) { a = b; return true; } return false; }

    void solve()
    {
        int H = cin.nextint;
        int W = cin.nextint;
        int K = cin.nextint - 1;
        var C = new int[W];
        var fact = 1;
        for (int i = 0; i < W; i++)
        {
            C[i] = i;
            fact *= i + 1;
        }
        var memo = new int[int.Parse(C.Reverse().concat()) + 1];
        var list = new List<int>[fact];

        for (int j = 0; j < fact; j++)
        {
            memo[int.Parse(C.concat())] = j;
            list[j] = new List<int>();
            next_permutation(C);
        }
        for (int j = 0; j < fact; j++)
        {
            for (int s = 0; s < 1 << (W - 1); s++)
            {
                bool before = false;
                var S = new int[W];
                C.CopyTo(S, 0);
                var ok = true;
                var first = true;
                for (int k = 0; k < W - 1; k++)
                {
                    var mode = (s >> k & 1) == 1;
                    if (mode)
                    {
                        if (before || (first && S[k] > S[k + 1]))
                        {
                            ok = false;
                            continue;
                        }
                        swap(ref S[k], ref S[k + 1]);
                        first = false;
                    }

                    before = mode;
                }
                if (ok)
                {
                    var to = memo[int.Parse(S.concat())];
                    list[j].Add(to);
                    if (j != to) list[to].Add(j);
                }
            }
            next_permutation(C);
        }

        var dp = new int[H + 1][];
        for (int i = 0; i < H + 1; i++)
        {
            dp[i] = new int[fact];
        }
        dp[0][0] = 1;
        for (int i = 0; i < H; i++)
        {
            for (int j = 0; j < fact; j++)
            {
                long sum = 0;
                foreach (var v in list[j])
                {
                    sum += dp[i][v];
                }
                dp[i + 1][j] = (int)(sum % mod);
                next_permutation(C);
            }
        }
        long ans = 0;
        for (int j = 0; j < fact; j++)
        {
            if (C[0] == K)
            {
                ans += dp[H][j];
            }
            next_permutation(C);
        }

        WriteLine(ans % mod);
    }

    void swap<T>(ref T a, ref T b)
    {
        var t = a;
        a = b;
        b = t;
    }
    bool next_permutation<T>(T[] array) where T : IComparable<T>
    {
        return next_permutation(array, 0, array.Length);
    }
    bool next_permutation<T>(T[] array, int start, int length) where T : IComparable<T>
    {
        int end = start + length - 1;
        if (end <= start) return false;
        int last = end;
        while (true)
        {
            int pos = last--;
            if (array[last].CompareTo(array[pos]) < 0)
            {
                int i;
                for (i = end + 1; array[last].CompareTo(array[--i]) >= 0;) { }
                T tmp = array[last]; array[last] = array[i]; array[i] = tmp;
                Array.Reverse(array, pos, end - pos + 1);
                return true;
            }
            if (last == start)
            {
                Array.Reverse(array, start, end - start + 1);
                return false;
            }
        }
    }
}

static class Ex
{
    public static void join<T>(this IEnumerable<T> values, string sep = " ") => WriteLine(string.Join(sep, values));
    public static string concat<T>(this IEnumerable<T> values) => string.Concat(values);
    public static string reverse(this string s) => s.Reverse().concat();
    public static void ForEach<T>(this T[] array, Action<T> action) { Array.ForEach(array, action); }

    public static int lower_bound<T>(this IList<T> arr, T val) where T : IComparable<T>
    {
        int low = 0, high = arr.Count();
        int mid;
        while (low < high)
        {
            mid = ((high - low) >> 1) + low;
            if (arr[mid].CompareTo(val) < 0) low = mid + 1;
            else high = mid;
        }
        return low;
    }
    public static int upper_bound<T>(this IList<T> arr, T val) where T : IComparable<T>
    {
        int low = 0, high = arr.Count();
        int mid;
        while (low < high)
        {
            mid = ((high - low) >> 1) + low;
            if (arr[mid].CompareTo(val) <= 0) low = mid + 1;
            else high = mid;
        }
        return low;
    }
}

class Pair<T, U> : IComparable<Pair<T, U>> where T : IComparable<T> where U : IComparable<U>
{
    public T f; public U s;
    public Pair(T f, U s) { this.f = f; this.s = s; }
    public int CompareTo(Pair<T, U> a) => f.CompareTo(a.f) != 0 ? f.CompareTo(a.f) : s.CompareTo(a.s);
    public override string ToString() => $"{f} {s}";
}

class Scanner
{
    string[] s; int i;
    readonly char[] cs = new char[] { ' ' };
    public Scanner() { s = new string[0]; i = 0; }
    public string[] scan => ReadLine().Split();
    public int[] scanint => Array.ConvertAll(scan, int.Parse);
    public long[] scanlong => Array.ConvertAll(scan, long.Parse);
    public double[] scandouble => Array.ConvertAll(scan, double.Parse);
    public string next
    {
        get
        {
            if (i < s.Length) return s[i++];
            string st = ReadLine();
            while (st == "") st = ReadLine();
            s = st.Split(cs, StringSplitOptions.RemoveEmptyEntries);
            i = 0;
            return next;
        }
    }
    public int nextint => int.Parse(next);
    public long nextlong => long.Parse(next);
    public double nextdouble => double.Parse(next);
}