Problem:
Score : 200 points

Problem Statement

Takahashi is standing on a two-dimensional plane, facing north. Find the minimum positive integer K such that Takahashi will be at the starting position again after he does the following action K times:

Go one meter in the direction he is facing. Then, turn X degrees counter-clockwise.

Constraints

1 \leq X \leq 179

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print the number of times Takahashi will do the action before he is at the starting position again.

Sample Input 1

90

Sample Output 1

4

Takahashi's path is a square.

Sample Input 2

1

Sample Output 2

360

Solution in C# (.NET Core 3.1.201) (judge verdict: Accepted)

using System;

namespace A
{
    class Program
    {
        static void Main(string[] args)
        {
            int X = int.Parse(Console.ReadLine());

            int currentDig = 0;
            int cnt = 0;
            do {
                currentDig += X;
                cnt++;
            } while(currentDig % 360 != 0);

            Console.WriteLine(cnt);
            Console.ReadLine();
        }
    }
}