Problem:
Score : 400 points

Problem Statement

Takahashi has a string S consisting of lowercase English letters.

Starting with this string, he will produce a new one in the procedure given as follows.

The procedure consists of Q operations. In Operation i (1 \leq i \leq Q), an integer T_i is provided, which means the following:

If T_i = 1: reverse the string S.

If T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.

If F_i = 1 : Add C_i to the beginning of the string S.

If F_i = 2 : Add C_i to the end of the string S.

Help Takahashi by finding the final string that results from the procedure.

Constraints

1 \leq |S| \leq 10^5

S consists of lowercase English letters.

1 \leq Q \leq 2 \times 10^5

T_i = 1 or 2.

F_i = 1 or 2, if provided.

C_i is a lowercase English letter, if provided.

Input

Input is given from Standard Input in the following format:

S
Q
Query_1
:
Query_Q

In the 3-rd through the (Q+2)-th lines, Query_i is one of the following:

1

which means T_i = 1, and:

2 F_i C_i

which means T_i = 2.

Output

Print the resulting string.

Sample Input 1

a
4
2 1 p
1
2 2 c
1

Sample Output 1

cpa

There will be Q = 4 operations. Initially, S is a.

Operation 1: Add p at the beginning of S. S becomes pa.

Operation 2: Reverse S. S becomes ap.

Operation 3: Add c at the end of S. S becomes apc.

Operation 4: Reverse S. S becomes cpa.

Thus, the resulting string is cpa.

Sample Input 2

a
6
2 2 a
2 1 b
1
2 2 c
1
1

Sample Output 2

aabc

There will be Q = 6 operations. Initially, S is a.

Operation 1: S becomes aa.

Operation 2: S becomes baa.

Operation 3: S becomes aab.

Operation 4: S becomes aabc.

Operation 5: S becomes cbaa.

Operation 6: S becomes aabc.

Thus, the resulting string is aabc.

Sample Input 3

y
1
2 1 x

Sample Output 3

xy

Solution in C# (Mono 4.6.2.0) (judge verdict: Time Limit Exceeded)

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace AtCoders {
	class Program {
		static void Main(string[] args) {

				var S = Console.ReadLine();
			var Q = int.Parse(Console.ReadLine());
			
			//反転フラグ
			Boolean hantenFlag = false;
			for (int i = 0; i < Q; i++) {
				var inputArray = Console.ReadLine().Split(' ');

				
				// 最初に与えられるのは1か2のみ
				if (int.Parse(inputArray[0]) == 1) {
					//1が与えられたときは反転フラグを逆にする
					hantenFlag = !hantenFlag;
				}
				else {
					//要素が足りない場合はエラーメッセージ
					if (inputArray.Length < 3) {
						Console.WriteLine("不正な入力");
						//return;
					}
					S = pattern2Process(S, inputArray,hantenFlag);
				}

			}

			if (hantenFlag) {
				S = new string(S.Reverse().ToArray());
			}
			Console.WriteLine(S);

		}

		/// <summary>
		/// 最初の文字が2の時の処理
		/// </summary>
		/// <param name="S"></param>
		/// <param name="inputArray"></param>
		/// <returns></returns>
		private static string pattern2Process(string S, string[] inputArray, bool hantenFlag) {
			//反転フラグがFlaseのときは、1の時に前にたす　trueのときは2の時まえにたす
			if ((int.Parse(inputArray[1]) == 1 & hantenFlag  == false) | (int.Parse(inputArray[1]) == 2 & hantenFlag == true)) {
				S = String.Concat(inputArray[2], S);
			}
			else {
				S = String.Concat(S, inputArray[2]);
			}

			return S;
		}
	}
}