Problem:
Score: 200 points

Problem Statement

A country decides to build a palace.

In this country, the average temperature of a point at an elevation of x meters is T-x \times 0.006 degrees Celsius.

There are N places proposed for the place. The elevation of Place i is H_i meters.

Among them, Princess Joisino orders you to select the place whose average temperature is the closest to A degrees Celsius, and build the palace there.

Print the index of the place where the palace should be built.

It is guaranteed that the solution is unique.

Constraints

1 \leq N \leq 1000

0 \leq T \leq 50

-60 \leq A \leq T

0 \leq H_i \leq 10^5

All values in input are integers.

The solution is unique.

Input

Input is given from Standard Input in the following format:

N
T A
H_1 H_2 ... H_N

Output

Print the index of the place where the palace should be built.

Sample Input 1

2
12 5
1000 2000

Sample Output 1

1

The average temperature of Place 1 is 12-1000 \times 0.006=6 degrees Celsius.

The average temperature of Place 2 is 12-2000 \times 0.006=0 degrees Celsius.

Thus, the palace should be built at Place 1.

Sample Input 2

3
21 -11
81234 94124 52141

Sample Output 2

3

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

using System;
using System.Linq;

class Program
{
    static double T = 0.0;

    static void Main(string[] args)
    {
	//N
	var input = Console.ReadLine();
	int n = int.Parse(input);
	//T A
	input = Console.ReadLine();
	var inputs = input.Split();
	int t = int.Parse(inputs[0]);
	int a = int.Parse(inputs[1]);
	double tempA = (double)a;
	T = (double)t;
	// Hn
	input = Console.ReadLine();
	inputs = input.Split();
	var hs = inputs.Select(x => int.Parse(x));
	//結果の計算
	int res = 1;
	double tempRes = temperature(hs.First());
	int count = 0;
	foreach (var h in hs) {
	    count++;
	    double tempH = temperature((double)h);
	    if (Math.Abs(tempA - tempH) < Math.Abs(tempA - tempRes)) {
		tempRes = tempH;
		res = count;
	    }
	}
	//結果を出力
	Console.WriteLine($"{res}");
    }

    static double temperature(double x) {
	return T - (x * 0.006);
    }
}