Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C# (Mono 4.6.2.0) (judge verdict: Wrong Answer)

using System;

namespace ABC106B
{
    class Program
    {
        static void Main(string[] args)
        {
            int N = int.Parse(Console.ReadLine());
            int[] prime = new int[] { 3, 5, 7, 11, 13, 17, 19 };
            int res = 0;

            if (N >= 105)
            {
                for (int num = 105; num <= N; num += 2)
                {
                    int cnt = 0;
                    int i = 0;
                    while (i < prime.Length)
                    {
                        if(num % prime[i] == 0) { cnt++; }
                        i++;
                    }

                    if (cnt == 3) { res++; }
                }
            }

            Console.WriteLine(res);
        }
    }
}