Problem:
Score : 200 points

Problem Statement

There are N positive integers written on a blackboard: A_1, ..., A_N.

Snuke can perform the following operation when all integers on the blackboard are even:

Replace each integer X on the blackboard by X divided by 2.

Find the maximum possible number of operations that Snuke can perform.

Constraints

1 \leq N \leq 200

1 \leq A_i \leq 10^9

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

Print the maximum possible number of operations that Snuke can perform.

Sample Input 1

3
8 12 40

Sample Output 1

2

Initially, [8, 12, 40] are written on the blackboard.
Since all those integers are even, Snuke can perform the operation.

After the operation is performed once, [4, 6, 20] are written on the blackboard.
Since all those integers are again even, he can perform the operation.

After the operation is performed twice, [2, 3, 10] are written on the blackboard.
Now, there is an odd number 3 on the blackboard, so he cannot perform the operation any more.

Thus, Snuke can perform the operation at most twice.

Sample Input 2

4
5 6 8 10

Sample Output 2

0

Since there is an odd number 5 on the blackboard already in the beginning, Snuke cannot perform the operation at all.

Sample Input 3

6
382253568 723152896 37802240 379425024 404894720 471526144

Sample Output 3

8

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

using System;

namespace Sample101
{
    class Program
    {
        static void Main(string[] args)
        {
            int N;
            int[] A = new int[210];

            N = int.Parse(Console.ReadLine());

            // N個分のAを手に入れる
            string str = Console.ReadLine();
            string[] strA = str.Split(' ');
            for (int i = 0; i < strA.Length; ++i)
            {
                A[i] = int.Parse(strA[i]);
            }

            // すべて偶数ならば、すべて2で割った答えで置き換える
            // 何回割り切れたか出力する
            int res = 0;
            while (true)
            {
                // すべて偶数かチェック
                bool existOdd = false;
                for (int i = 0; i < N; ++i)
                {
                    if (A[i] % 2 != 0) existOdd = true;
                }
                if (existOdd) break;

                // 2で割って置き換える
                for (int i = 0; i < N; ++i)
                {
                    A[i] /= 2;
                }

                ++res;
            }

            Console.WriteLine(res);
        }
    }
}