Problem:
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Matrix Multiplication

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\[
c_{ij} = \sum_{k=1}^m a_{ik}b_{kj}
\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Constraints

$1 \leq n, m, l \leq 100$

$0 \leq a_{ij}, b_{ij} \leq 10000$

Sample Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2

Sample Output

1 8 5
0 9 6
4 23 14

Note

      解説

Solution in C# (judge verdict: Wrong Answer)

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace ConsoleApplication11
{
    class Program
    {
       
        static int[,] GetMatrix(int a, int b)
        {
            int[,] m = new int[a,b];

            for (int i = 0; i < a; ++i)
            {
                string[] sArray = Console.ReadLine().Split(' ');

                for (int j = 0; j < b; ++j)
                {
                    m[i, j] = int.Parse(sArray[j]);
                }
            }
            return m;
        }
        

        static void Main(string[] args)
        {

            string[] str = Console.ReadLine().Split(' ');
            int n = int.Parse(str[0]);
            int m = int.Parse(str[1]);
            int l = int.Parse(str[2]);

            int[,] A = GetMatrix(n,m);
            int[,] B = GetMatrix(m,l);


            for (int i = 0; i < n; ++i)
            {
              
                for (int j = 0; j < l; ++j)
                {
                    int sum = 0;

                    for (int k = 0; k < m; ++k)
                    {
                        sum += A[i, k] * B[k, j];
                    }
                    if (j == (l-1))
                    {
                        Console.WriteLine(sum);
                    }
                    else
                    {
                        Console.Write("{0} ", sum);
                    }
                    

                }
                
            }
        }
    }
}