Problem:
Score : 300 points

Problem Statement

You are given an integer sequence of length n, a_1, ..., a_n.
Let us consider performing the following n operations on an empty sequence b.

The i-th operation is as follows:

Append a_i to the end of b.

Reverse the order of the elements in b.

Find the sequence b obtained after these n operations.

Constraints

1 \leq n \leq 2\times 10^5

0 \leq a_i \leq 10^9

n and a_i are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print n integers in a line with spaces in between.
The i-th integer should be b_i.

Sample Input 1

4
1 2 3 4

Sample Output 1

4 2 1 3

After step 1 of the first operation, b becomes: 1.

After step 2 of the first operation, b becomes: 1.

After step 1 of the second operation, b becomes: 1, 2.

After step 2 of the second operation, b becomes: 2, 1.

After step 1 of the third operation, b becomes: 2, 1, 3.

After step 2 of the third operation, b becomes: 3, 1, 2.

After step 1 of the fourth operation, b becomes: 3, 1, 2, 4.

After step 2 of the fourth operation, b becomes: 4, 2, 1, 3.

Thus, the answer is 4 2 1 3.

Sample Input 2

3
1 2 3

Sample Output 2

3 1 2

As shown above in Sample Output 1, b becomes 3, 1, 2 after step 2 of the third operation. Thus, the answer is 3 1 2.

Sample Input 3

1
1000000000

Sample Output 3

1000000000

Sample Input 4

6
0 6 7 6 7 0

Sample Output 4

0 6 6 0 7 7

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

using System;
using System.Collections.Generic;

namespace MyProgram{
    class AtCoder{
        static void Main(){
            int n = int.Parse(Console.ReadLine());
            long[] a = Array.ConvertAll(Console.ReadLine().Split(' '),long.Parse);
            var b_index = 2*n;
            var b = new long[b_index];
            for(var i=0;i<b_index;i++)b[i] = -1;
            for(var i=0;i<n;i++){
                if(i%2==1){
                    b[b_index/2+(i+1)/2] = a[i];
                }else{
                    b[b_index/2-i/2] = a[i];
                }
            }
            if(n%2==1){
                for(var i=0;i<b_index;i++){
                    if(b[i]!=-1)Console.Write("{0} ",b[i]);
                }
            }else{
                for(var i=b_index-1;i>=0;i--){
                    if(b[i]!=-1)Console.Write("{0} ",b[i]);
                }
            }
        }
    } 
}