Problem:
Score : 400 points

Problem Statement

Given are positive integers A and B.

Let us choose some number of positive common divisors of A and B.

Here, any two of the chosen divisors must be coprime.

At most, how many divisors can we choose?

Definition of common divisor

An integer d is said to be a common divisor of integers x and y when d divides both x and y.

Definition of being coprime

Integers x and y are said to be coprime when x and y have no positive common divisors other than 1.

Definition of dividing

An integer x is said to divide another integer y when there exists an integer \alpha such that y = \alpha x.

Constraints

All values in input are integers.

1 \leq A, B \leq 10^{12}

Input

Input is given from Standard Input in the following format:

A B

Output

Print the maximum number of divisors that can be chosen to satisfy the condition.

Sample Input 1

12 18

Sample Output 1

3

12 and 18 have the following positive common divisors: 1, 2, 3, and 6.

1 and 2 are coprime, 2 and 3 are coprime, and 3 and 1 are coprime, so we can choose 1, 2, and 3, which achieve the maximum result.

Sample Input 2

420 660

Sample Output 2

4

Sample Input 3

1 2019

Sample Output 3

1

1 and 2019 have no positive common divisors other than 1.

Solution in C# (Mono 4.6.2.0) (judge verdict: Runtime Error)

using System;
using System.Linq;
using System.Collections.Generic;
namespace mytest
{
    class Program
    {
        static void Main(string[] args)
        {
            var input = Console.ReadLine();
            var A = int.Parse(input.Split(' ')[0]);
            var B = int.Parse(input.Split(' ')[0]);

            var a = Gcd(A,B);
          　var la = new List<int>();
            int total = 0;
            if(a == 1)
            {
              total = 1;
            }
            else
            {
              for (int i = 1; i < a; i++)
              {
                  if (a % i == 0) la.Add(i);
              }
              for(int i = 0; i<la.Count()-1;i++)
              {
                  for(int k = i+1; k<la.Count();k++)
                  {
                      if (Gcd(la[i], la[k]) == 1) total++;
                  }
              }
            }
            Console.WriteLine(total);
        }
      
      　public static int Gcd(int a, int b)
        {
            Func<int, int, int> gcd = null;
            gcd = (x, y) => y == 0 ? x : gcd(y, x % y);
            return a > b ? gcd(a, b) : gcd(b, a);
        }
    }
}