Problem:
Score : 300 points

Problem Statement

Snuke has an integer sequence A of length N.

He will freely choose an integer b.
Here, he will get sad if A_i and b+i are far from each other.
More specifically, the sadness of Snuke is calculated as follows:

abs(A_1 - (b+1)) + abs(A_2 - (b+2)) + ... + abs(A_N - (b+N))

Here, abs(x) is a function that returns the absolute value of x.

Find the minimum possible sadness of Snuke.

Constraints

1 \leq N \leq 2 \times 10^5

1 \leq A_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

Print the minimum possible sadness of Snuke.

Sample Input 1

5
2 2 3 5 5

Sample Output 1

2

If we choose b=0, the sadness of Snuke would be abs(2-(0+1))+abs(2-(0+2))+abs(3-(0+3))+abs(5-(0+4))+abs(5-(0+5))=2.
Any choice of b does not make the sadness of Snuke less than 2, so the answer is 2.

Sample Input 2

9
1 2 3 4 5 6 7 8 9

Sample Output 2

0

Sample Input 3

6
6 5 4 3 2 1

Sample Output 3

18

Sample Input 4

7
1 1 1 1 2 3 4

Sample Output 4

6

Solution in C# (Mono 4.6.2.0) (judge verdict: Wrong Answer)

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Diagnostics;

namespace AtCoder
{
    class Program
    {
        private static string Read() { return Console.ReadLine(); }
        private static int ReadInt() { return int.Parse(Read()); }
        private static long ReadLong() { return long.Parse(Read()); }
        private static double ReadDouble() { return double.Parse(Read()); }
        private static int[] ReadInts() { return Array.ConvertAll(Read().Split(), int.Parse); }
        private static long[] ReadLongs() { return Array.ConvertAll(Read().Split(), long.Parse); }
        private static double[] ReadDoubles() { return Array.ConvertAll(Read().Split(), double.Parse); }

        static long Solve(int N, int[] A)
        {
            for (int i = 0; i < N; ++i) { A[i] -= i + 1; }
            Array.Sort(A);
            int min = A[0];
            int max = A[N - 1];
            int[] x = new int[N];
            int[] y = new int[N];
            for (int i = 1; i < N; ++i)
            {
                int j = N - 1 - i;
                x[i] = x[i - 1] + A[i] - min;
                y[j] = y[j + 1] + max - A[j];
            }
            long ans = long.MaxValue;
            for (int i = 0; i < N; ++i)
            {
                long L = Math.BigMul(A[i] - min, i + 1) - x[i];
                long R = (i + 1 < N) ? Math.BigMul(max - A[i], N - (i + 1)) - y[i + 1] : 0;
                ans = Math.Min(L + R, ans);
            }
            return ans;
        }
        static void Main(string[] args)
        {
            int N = ReadInt();
            int[] A = ReadInts();
            Console.WriteLine(Solve(N, A));
        }
    }
}