Problem:
Score : 400 points

Problem Statement

Given is a string S consisting of digits from 1 through 9.

Find the number of pairs of integers (i,j) (1 ≤ i ≤ j ≤ |S|) that satisfy the following condition:

Condition: In base ten, the i-th through j-th characters of S form an integer that is a multiple of 2019.

Constraints

1 ≤ |S| ≤ 200000

S is a string consisting of digits from 1 through 9.

Input

Input is given from Standard Input in the following format:

S

Output

Print the number of pairs of integers (i,j) (1 ≤ i ≤ j ≤ |S|) that satisfy the condition.

Sample Input 1

1817181712114

Sample Output 1

3

Three pairs - (1,5), (5,9), and (9,13) - satisfy the condition.

Sample Input 2

14282668646

Sample Output 2

2

Sample Input 3

2119

Sample Output 3

0

No pairs satisfy the condition.

Solution in C# (.NET Core 3.1.201) (judge verdict: Runtime Error)

using System;
using System.Linq;
using System.Collections.Generic;

namespace ABC164
{
    class D
    {
        static void Main(string[] args)
        {
            var input = Console.ReadLine();
            var S = new long[input.Length + 1];
            for (int i = 0; i < input.Length; i++)
            {
                S[i + 1] = long.Parse(input.Substring(input.Length - 1 - i, i + 1));
            }

            //Console.WriteLine(string.Join(",", S));

            var sum = 0;
            for (int i = 0; i < input.Length; i++)
            {
                for (int j = i - 1; 0 <= j; j--)
                {
                    //Console.WriteLine((S[i] - S[j]) / Math.Pow(10, j));
                    if (((S[i] - S[j]) / Math.Pow(10, j)) % 2019 == 0) sum++;
                }
            }
            Console.WriteLine(sum);
        }
    }
}