Problem:
Score: 200 points

Problem Statement

Today, the memorable AtCoder Beginner Contest 100 takes place. On this occasion, Takahashi would like to give an integer to Ringo.

As the name of the contest is AtCoder Beginner Contest 100, Ringo would be happy if he is given a positive integer that can be divided by 100 exactly D times.

Find the N-th smallest integer that would make Ringo happy.

Constraints

D is 0, 1 or 2.

N is an integer between 1 and 100 (inclusive).

Input

Input is given from Standard Input in the following format:

D N

Output

Print the N-th smallest integer that can be divided by 100 exactly D times.

Sample Input 1

0 5

Sample Output 1

5

The integers that can be divided by 100 exactly 0 times (that is, not divisible by 100) are as follows: 1, 2, 3, 4, 5, 6, 7, ...

Thus, the 5-th smallest integer that would make Ringo happy is 5.

Sample Input 2

1 11

Sample Output 2

1100

The integers that can be divided by 100 exactly once are as follows: 100, 200, 300, 400, 500, 600, 700, 800, 900, 1 \ 000, 1 \ 100, ...

Thus, the integer we are seeking is 1 \ 100.

Sample Input 3

2 85

Sample Output 3

850000

The integers that can be divided by 100 exactly twice are as follows: 10 \ 000, 20 \ 000, 30 \ 000, ...

Thus, the integer we are seeking is 850 \ 000.

Solution in C# (Mono 4.6.2.0) (judge verdict: Wrong Answer)

using System;
using System.Collections.Generic;
using System.Linq;

namespace AtCoderConsole
{
    class Program
    {
        static void Main(string[] args)
        {
            // 標準入力から1行取得
            string input = Console.ReadLine();

            // DとNを取得
            int d = int.Parse(input.Split(' ')[0]);
            int n = int.Parse(input.Split(' ')[1]);

            // 要素数100の配列を宣言
            int[] array = new int[100];

            // 配列に値を格納
            for(int i = 0; i < 100; i++)
            {
                if (d == 0)
                {
                    array[i] = (i + 1);
                }
                else if (d == 1)
                {
                    array[i] = 100 * (i + 1);
                }
                else
                {
                    array[i] = 10000 * (i + 1);
                }
            }
            if (d == 0)
            {
                // 100で0回割り切れる（1回も割り切れない）100番目の数は101
                array[99] = 101;
            }

            // 標準出力に出力
            Console.WriteLine(array[n - 1]);
        }
    }
}