Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C# (Mono 4.6.2.0) (judge verdict: Accepted)

using System;
using System.Collections.Generic;
using System.Linq;
using static Atcoder;
using System.Threading.Tasks;
using System.ComponentModel;

public class Hello
{

    public static void Main()
    {
        int N = intRead();
        int ans = 0;
        int count = 0;
        for (int i = 1; i <= N; i += 2)
        {
            count = 0;
            for (int j = 1; j <= i; j++)
            {
                if (i % j == 0)
                {
                    count++;
                }
            }
            if (count == 8) ans++;
        }
        Console.WriteLine(ans);
    }

}


public class Atcoder
{
    static void Swap<T>(ref T a, ref T b)
    {
        var t = a;
        a = b;
        b = t;
    }
    public static long LCM(long a, long b)
    {
        long c = a * b;
        if (a < b) Swap(ref a, ref b);
        long d = a % b;
        while (d != 0)
        {
            a = b;
            b = d;
            d = a % b;
        }
        return c / b;
    }
    public static string strReverce(string s)
    {
        return new string(s.Reverse().ToArray());
    }
    public static int intRead()
    {
        return int.Parse(Console.ReadLine());
    }
    public static bool IsPrime(int n)
    {
        if (n < 2) return false;
        if (n == 2) return true;
        if (n % 2 == 0) return false;

        //double sqrtNum = Math.Sqrt(n);
        for (int i = 3; i < n; i += 2)
        {
            if (n % i == 0) return false;
        }
        return true;
    }
    public static string[] SpRead(char c)
    {
        return Console.ReadLine().Split(c);
    }
    public static int[] SpIntRead(char c)
    {
        return Console.ReadLine().Split(' ').Select(a => int.Parse(a)).ToArray();
    }
    public static string ToConvertBit(int N, int e)
    {
        string ret = "";
        int r = 0;
        while (N != 0)
        {
            r = N % e;
            ret += r.ToString();
            N -= r;
            N /= e;
        }
        ret = strReverce(ret);
        return ret;
    }

}