Problem:
Score : 200 points

Problem Statement

There are some animals in a garden. Each of them is a crane with two legs or a turtle with four legs.

Takahashi says: "there are X animals in total in the garden, and they have Y legs in total." Determine whether there is a combination of numbers of cranes and turtles in which this statement is correct.

Constraints

1 \leq X \leq 100

1 \leq Y \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

If there is a combination of numbers of cranes and turtles in which the statement is correct, print Yes; otherwise, print No.

Sample Input 1

3 8

Sample Output 1

Yes

The statement "there are 3 animals in total in the garden, and they have 8 legs in total" is correct if there are two cranes and one turtle. Thus, there is a combination of numbers of cranes and turtles in which the statement is correct.

Sample Input 2

2 100

Sample Output 2

No

There is no combination of numbers of cranes and turtles in which this statement is correct.

Sample Input 3

1 2

Sample Output 3

Yes

We also consider the case in which there are only cranes or only turtles.

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>

#define pb push_back
#define ff first
#define ss second
#define all(x) (x).begin(), (x).end()
#define ll long long
#define ii pair<int,int>
#define vi vector<int>
#define vll vector<ll>
#define vii vector<ii>

using namespace std;

int32_t main(){
	ios_base::sync_with_stdio(false);
	cin.tie(0);
	cout.tie(0);
	int x,y;
	cin>>x>>y;
	if(y&1)
		cout<<"No\n";
	else if(y%4==0 && y/4 == x)
		cout<<"Yes\n";
	else if(y%2==0 && y/2==x)
		cout<<"Yes\n";
	else if((y%2)%4==0 && (y/2+(y%2)/4)==x)
		cout<<"Yes\n";
	else if((y%4)%2==0 && (y/4+(y%4)/2)==x)
		cout<<"Yes\n";
	else
		cout<<"No\n";
	return 0;
}