Problem:
Score : 200 points

Problem Statement

Niwango-kun is an employee of Dwango Co., Ltd.

One day, he is asked to generate a thumbnail from a video a user submitted.

To generate a thumbnail, he needs to select a frame of the video according to the following procedure:

Get an integer N and N integers a_0, a_1, ..., a_{N-1} as inputs. N denotes the number of the frames of the video, and each a_i denotes the representation of the i-th frame of the video.

Select t-th frame whose representation a_t is nearest to the average of all frame representations.

If there are multiple such frames, select the frame with the smallest index.

Find the index t of the frame he should select to generate a thumbnail.

Constraints

1 \leq N \leq 100

1 \leq a_i \leq 100

All numbers given in input are integers

Input

Input is given from Standard Input in the following format:

N
a_{0} a_{1} ... a_{N-1}

Output

Print the answer.

Sample Input 1

3
1 2 3

Sample Output 1

1

Since the average of frame representations is 2, Niwango-kun needs to select the index 1, whose representation is 2, that is, the nearest value to the average.

Sample Input 2

4
2 5 2 5

Sample Output 2

0

The average of frame representations is 3.5.

In this case, every frame has the same distance from its representation to the average.

Therefore, Niwango-kun should select index 0, the smallest index among them.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <queue>
#include <iomanip>
#include <map>
#include <bitset>
#include <string>
#include <algorithm>
#include <numeric>
#include <vector>
#define REP(i, n) for(int i = 0; i < (n); i++)
#define ALL(c) c.begin(),c.end()
#define PB push_back
#define INF 1100000000
#define LLINF 1100000000000000000
#define MOD 1000000007
#define FI first
#define SE second
#define MP make_pair

using namespace std;
typedef long long ll;
typedef pair<int, int> P;

int main()
{
  int N; cin >> N;
  int sum = 0;
  vector<ll> A(N);
  REP(i, N) {
    cin >> A[i];
    sum += A[i];
  }

  int ans, mindist = INF;
  REP(i, N) {
    if (mindist > abs(sum - N*A[i])) {
      mindist = abs(sum - N*A[i]);
      ans = i;
    }
  }
  cout << ans << endl;

  return 0;
}