Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;

int main() {
    int N, A, B, C;
    cin >> N >> A >> B >> C;
    vector<string> S(N);
    for(auto &e : S) cin >> e;
    vector<char> ans;

    auto solve = [&]() -> bool {
        for(int i = 0; i < N; ++i) {
            if(S[i] == "AB") {
                if(A == 0) {
                    A++, B--, ans.push_back('A');
                } else if(B == 0) {
                    A--, B++, ans.push_back('B');
                } else if(C == 0) {
                    if(i < N - 1 and S[i + 1] == "BC") {
                        A--, B++, ans.push_back('B');
                    } else if(i < N - 1 and S[i + 1] == "AC") {
                        A++, B--, ans.push_back('A');
                    } else {
                        A++, B--, ans.push_back('A');
                    }
                } else {
                    A++, B--, ans.push_back('A');
                }
            }
            if(S[i] == "BC") {
                if(B == 0) {
                    B++, C--, ans.push_back('B');
                } else if(C == 0) {
                    B--, C++, ans.push_back('C');
                } else if(A == 0) {
                    if(i < N - 1 and S[i + 1] == "AC") {
                        B--, C++, ans.push_back('C');
                    } else if(i < N - 1 and S[i + 1] == "AB") {
                        B++, C--, ans.push_back('B');
                    } else {
                        B++, C--, ans.push_back('B');
                    }
                } else {
                    B++, C--, ans.push_back('B');
                }
            }
            if(S[i] == "AC") {
                if(A == 0) {
                    A++, C--, ans.push_back('A');
                } else if(C == 0) {
                    A--, C++, ans.push_back('C');
                } else if(B == 0) {
                    if(i < N - 1 and S[i + 1] == "BC") {
                        A--, C++, ans.push_back('C');
                    } else if(i < N - 1 and S[i + 1] == "AB") {
                        A++, C--, ans.push_back('A');
                    } else {
                        C++, A--, ans.push_back('C');
                    }
                } else {
                    C++, A--, ans.push_back('C');
                }
            }
            if(A < 0 or B < 0 or C < 0) return false;
        }
        return true;
    };

    if(solve()) {
        cout << "Yes" << '\n';
        for(auto &e : ans) cout << e << '\n';
    } else {
        cout << "No" << '\n';
    }
    return 0;
}