Problem:
Score : 300 points

Problem Statement

Sitting in a station waiting room, Joisino is gazing at her train ticket.

The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).

In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.

The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Constraints

0≤A,B,C,D≤9

All input values are integers.

It is guaranteed that there is a solution.

Input

Input is given from Standard Input in the following format:

ABCD

Output

Print the formula you made, including the part =7.

Use the signs + and -.

Do not print a space between a digit and a sign.

Sample Input 1

1222

Sample Output 1

1+2+2+2=7

This is the only valid solution.

Sample Input 2

0290

Sample Output 2

0-2+9+0=7

0 - 2 + 9 - 0 = 7 is also a valid solution.

Sample Input 3

3242

Sample Output 3

3+2+4-2=7

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <map>
#include <set>
#include <unordered_set>
#include <list>
#include <cmath>
#include <stack>
#include <queue>
#include <bitset>
#include <cstdio>
#include <climits>
#include <vector>
#include <cstdlib>
#include <numeric>
#include <iostream>
#include <iomanip>
#include <string>
#include <cstring>
#include <algorithm>
#include <array>
#include <assert.h>
#include <functional>
#define _USE_MATH_DEFINES
#include <math.h>
#include <complex>
#include <atomic>
#include <thread>

using namespace std;
typedef long long ll;
#define ln '\n'
#define rep(i,n) for(int i=0;i<(n);++i)
#define drep(i,n) int i = 0;for(;i<(n);++i)
#define FOR(i,s,e) for(int i=s;i<=(e);++i)
#define DFOR(i,s,e) int i = s;for(;i<=(e);++i)
#define FORR(i,s,e) for(int i=s;i>=(e);--i)
#define DFORR(i,s,e) int i = s;for(;i>=(e);--i)
#define fore(a, x) for(auto& a : x)
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
#define ft first
#define sd second
#define pb push_back
#define eb emplace_back
#define all(a) a.begin(),a.end()
#define Fill(a,b) memset(a,b,sizeof(a))
template<typename T1, typename T2> bool Max(T1& a, T2 b) { return a<b ? a = b, 1 : 0; }
template<typename T1, typename T2> bool Min(T1& a, T2 b) { return a>b ? a = b, 1 : 0; }



const int N = 200001, inf = 10000;


void solve() {
  char a;
  char bcd[3];
  cin >> a;
  rep(i, 3)cin >> bcd[i];
  rep(sub, 8) {
    string str;
    str += a;
    int v = a - '0';

    rep(i, 3) {
      int sign = 1;
      if ((sub >> i) & 1) {
        str += '+';
        sign = 1;
      }
      else {
        str += '-';
        sign = -1;
      }
      str += bcd[i];
      v += sign * (bcd[i] - '0');
    }
    if (v == 7) {
      str += "=7";
      cout << str << ln;
      return;
    }
  }
    
}


void init() {
  
}

int main(void) {
  ios::sync_with_stdio(false); cin.tie(0); cout.setf(ios::fixed); cout.precision(20);
  //freopen("C:\\Users\\LENOVO\\Documents\\Visual Studio 2015\\Projects\\Test\\Input\\in.in", "r", stdin);

  init();
  int TC = 1;
#if 0
  cin >> TC; cin.get();
#endif
  FOR(TI, 1, TC) {
    //cout << "Case #" << TI << ": ";
    solve();
  }
  
  
  return 0;
}