Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair<ll,ll> P;
const ll INF=1LL<<60;
const double EPS = 1e-10;
const ll mod=1000000007;

int main(void){
    int n,a,b,c,d;
    string s;
    cin>>n>>a>>b>>c>>d>>s;
    bool ans=true;
    for(int i=a;i<c-1;i++){
        if(s[i]=='#'&&s[i+1]=='#') ans=false;
    }
    for(int i=b;i<d-1;i++){
        if(s[i]=='#'&&s[i+1]=='#') ans=false;
    }
    if(c>d){
        bool kari=false;
        for(int i=b;i<=d-2&&i<=c-3;i++){
            if(s[i]=='.'&&s[i+1]=='.'&&s[i+2]=='.') kari=true;
        }
        if(kari==false) ans=false;
    }
    if(ans) cout<<"Yes"<<endl;
    else cout<<"No"<<endl;
}