Problem:
Score : 200 points

Problem Statement

Given are strings s and t of length N each, both consisting of lowercase English letters.

Let us form a new string by alternating the characters of S and the characters of T, as follows: the first character of S, the first character of T, the second character of S, the second character of T, ..., the N-th character of S, the N-th character of T. Print this new string.

Constraints

1 \leq N \leq 100

|S| = |T| = N

S and T are strings consisting of lowercase English letters.

Input

Input is given from Standard Input in the following format:

N
S T

Output

Print the string formed.

Sample Input 1

2
ip cc

Sample Output 1

icpc

Sample Input 2

8
hmhmnknk uuuuuuuu

Sample Output 2

humuhumunukunuku

Sample Input 3

5
aaaaa aaaaa

Sample Output 3

aaaaaaaaaa

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
 
//LIFE IS NOT A PROBLEM TO BE SOLVED
 
#define rep(i,a,b) for( int i = (int) a; i < (int) b; i++ )
#define F first
#define S second
#define pb push_back
#define debug(a) cout << #a << " = " << a << endl;
#define debug2(a,b) cout << #a << " = " << a << " --- " << #b << " = " << b << endl;
#define debugP(a) cout << a.F << " " << a.S << endl;
#define debugV(v, n) { rep( i, 0, n ) { if(i) printf(" "); printf("%d", v[i]); } printf("\n"); }
#define debugM(mat,n,m) rep( i, 0, n ){ rep( j, 0, m ) { if(j) printf(" "); printf("%d", mat[i][j]); } printf("\n"); }
 
using namespace std;
 
typedef long long int ll;
typedef pair<int,int> ii;
	

bool isPrime(int n){
	if(n<=1) return false;
	if(n==2) return true;
	int f = sqrt(n);
	rep(i, 2, f+1) if(n%i==0) return false;
	return true;
}

int main(){
	
	int n; string s, t;
	cin >> n >> s >> t;
	rep(i, 0, n){
		cout << s[i];
		cout << t[i];
	}	cout << '\n';
	
	

	
	return 0;
}