Problem:
Score : 300 points

Problem Statement

You are given an integer sequence of length n, a_1, ..., a_n.
Let us consider performing the following n operations on an empty sequence b.

The i-th operation is as follows:

Append a_i to the end of b.

Reverse the order of the elements in b.

Find the sequence b obtained after these n operations.

Constraints

1 \leq n \leq 2\times 10^5

0 \leq a_i \leq 10^9

n and a_i are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print n integers in a line with spaces in between.
The i-th integer should be b_i.

Sample Input 1

4
1 2 3 4

Sample Output 1

4 2 1 3

After step 1 of the first operation, b becomes: 1.

After step 2 of the first operation, b becomes: 1.

After step 1 of the second operation, b becomes: 1, 2.

After step 2 of the second operation, b becomes: 2, 1.

After step 1 of the third operation, b becomes: 2, 1, 3.

After step 2 of the third operation, b becomes: 3, 1, 2.

After step 1 of the fourth operation, b becomes: 3, 1, 2, 4.

After step 2 of the fourth operation, b becomes: 4, 2, 1, 3.

Thus, the answer is 4 2 1 3.

Sample Input 2

3
1 2 3

Sample Output 2

3 1 2

As shown above in Sample Output 1, b becomes 3, 1, 2 after step 2 of the third operation. Thus, the answer is 3 1 2.

Sample Input 3

1
1000000000

Sample Output 3

1000000000

Sample Input 4

6
0 6 7 6 7 0

Sample Output 4

0 6 6 0 7 7

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <iomanip>
#include <string>
#include <vector>
#include <algorithm>
#include <numeric>
#include <utility>
#include <cmath>
#include <tuple>
#include <queue>
#include <bitset>
#include <set>
#include <map>
#include <list>

using ll = long long;
using ld = long double;
using namespace std;
const int INF = 1e9+100;
const ll INF64 = 7e18l;
const int mod = 1000000007;
#define rep(i,a,b) for(int i=(a);i<(b);i++)
#define ALL(a) (a).begin(), (a).end()
#define FIN ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);


int main(){
    FIN;
    ll n; cin >> n;
    vector<ll> a(n+1);
    a[0] = 0;
    for(ll i=1;i<n+1;i++){
        cin >> a[i];
    }

    vector<ll> ans(n+1);
    ans[0] = 0;

    if(n%2 == 0){
        ll idx = n;
        for(ll i=1;i<=n/2;i++){
            ans[i] = a[idx];
            idx -= 2;
        }
        idx = 1;
        for(ll i=n/2+1;i<=n;i++){
            ans[i] = a[idx];
            idx += 2;
        }
    }

    if(n%2 == 1){
        ll idx = n;
        for(ll i=1;i<=n/2+1;i++){
            ans[i] = a[idx];
            idx -= 2;
        }
        idx = 2;
        for(ll i=n/2+2;i<=n;i++){
            ans[i] = a[idx];
            idx += 2;
        }
    }


    for(ll i=1;i<=n;i++) cout << ans[i] << " ";
    cout << endl;
    return 0;
}