Problem:
Score : 300 points

Problem Statement

Sitting in a station waiting room, Joisino is gazing at her train ticket.

The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).

In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.

The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Constraints

0≤A,B,C,D≤9

All input values are integers.

It is guaranteed that there is a solution.

Input

Input is given from Standard Input in the following format:

ABCD

Output

Print the formula you made, including the part =7.

Use the signs + and -.

Do not print a space between a digit and a sign.

Sample Input 1

1222

Sample Output 1

1+2+2+2=7

This is the only valid solution.

Sample Input 2

0290

Sample Output 2

0-2+9+0=7

0 - 2 + 9 - 0 = 7 is also a valid solution.

Sample Input 3

3242

Sample Output 3

3+2+4-2=7

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
#include <iostream>
#include <algorithm>
#include <sstream>
#include <complex>
#include <vector>
#include <list>
#include <queue>
#include <deque>
#include <stack>
#include <set>
#include <map>
#include <cstdio>
#include <string>
#include <cstdlib>
#include <cstring>
#include <bits/stdc++.h>

using namespace std;
typedef long long ll;
const long double EPS = 1e-9;
const ll mod = 1e9 + 7;
const ll INF = 1e9;

#define rep(i, n) for(ll i = 0; i < n ; i++ )
#define For(i, a, b) for(ll i = (a); i < (b) ; i++ )
#define all(a) (a).begin(), (a).end()
#define rall(a) (a).rbegin(), (a).rend()

const ll MAX_N = 100000;

int main(void){
    string S;
    ll a[4];

    cin >> S;
    rep(i, 4) a[i] = ll(S[i]) - ll('0');

    rep(i, 8){
        ll tmp = i;
        ll answer = a[0];
        rep(j, 3){
            if (tmp % 2 == 0) answer += a[j + 1];
            else answer -= a[j + 1];
            tmp /= 2;
        }

        if (answer == 7){
            tmp = i;
            cout << a[0];
            rep(j, 3){
                if (tmp % 2 == 0) cout << "+" << a[j + 1];
                else cout << "-" << a[j + 1];
                tmp /= 2;
            }
            cout << "=" << 7 << endl;
            return 0;
        }
    }

    return 0;
}