Problem:
Score : 400 points

Problem Statement

Let {\rm comb}(n,r) be the number of ways to choose r objects from among n objects, disregarding order.
From n non-negative integers a_1, a_2, ..., a_n, select two numbers a_i > a_j so that {\rm comb}(a_i,a_j) is maximized.
If there are multiple pairs that maximize the value, any of them is accepted.

Constraints

2 \leq n \leq 10^5

0 \leq a_i \leq 10^9

a_1,a_2,...,a_n are pairwise distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print a_i and a_j that you selected, with a space in between.

Sample Input 1

5
6 9 4 2 11

Sample Output 1

11 6

\rm{comb}(a_i,a_j) for each possible selection is as follows:

\rm{comb}(4,2)=6

\rm{comb}(6,2)=15

\rm{comb}(6,4)=15

\rm{comb}(9,2)=36

\rm{comb}(9,4)=126

\rm{comb}(9,6)=84

\rm{comb}(11,2)=55

\rm{comb}(11,4)=330

\rm{comb}(11,6)=462

\rm{comb}(11,9)=55

Thus, we should print 11 and 6.

Sample Input 2

2
100 0

Sample Output 2

100 0

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define rep(i,n) for (int i=0; i<(int)(n); ++i)
#define all(a) (a).begin(), (a).end()
#define rall(a) (a).rbegin(), (a).rend()
using ll = long long;
using vi = vector<int>;
using vl = vector<ll>;
using Graph = vector<vi>;  // vi <=> vl
using vb = vector<bool>;
using boolGraph = vector<vb>;
using P = pair<int, int>;  // int <=> ll
const int MOD = 1e9+7;
const double EPS = 1e-9;

int main() {
  int n; cin >> n;
  vi arr(n+1);
  rep(i,n) cin >> arr[i];
  arr[n] = -1;

  sort(all(arr));

  int i = arr.back();

  auto iter = lower_bound(all(arr), i/2);
  int r1 = *iter;
  --iter;
  int r2 = *iter;

  int j;
  if (abs(i - 2*r1) < abs(i - 2*r2)) j = r1;
  else j = r2;

  cout << i << ' ' << j << endl;
  return 0;
}