Problem:
Score : 400 points

Problem Statement

Given are three integers N, K, and S.

Find a sequence A_1, A_2, ..., A_N of N integers between 1 and 10^9 (inclusive) that satisfies the condition below.
We can prove that, under the conditions in Constraints, such a sequence always exists.

There are exactly K pairs (l, r) of integers such that 1 \leq l \leq r \leq N and A_l + A_{l + 1} + \cdots + A_r = S.

Constraints

1 \leq N \leq 10^5

0 \leq K \leq N

1 \leq S \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K S

Output

Print a sequence satisfying the condition, in the following format:

A_1 A_2 ... A_N

Sample Input 1

4 2 3

Sample Output 1

1 2 3 4

Two pairs (l, r) = (1, 2) and (3, 3) satisfy the condition in the statement.

Sample Input 2

5 3 100

Sample Output 2

50 50 50 30 70

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<iostream>
#include<algorithm>
#include<utility>
#include<vector>
#include<cmath>
using namespace std;

typedef pair<int, int> P;
typedef long long ll;
const int INF = 100000000;

ll gcd( ll a, ll b ){//最大公約数
    ll tmp;
    if( a < b ) { tmp = a; a = b; b = tmp; }
    if( b < 1 ) return -1;

    if( a % b == 0 ) return b;
    return gcd( b, a % b );
}

ll lcm(ll a, ll b){//最小公倍数
    return a * b / gcd(a, b);
}

ll sosuu(ll x){
    for(int i = 2; i < x; i++){
        if(x % i == 0) return false;
    }

    return true;
}


//入力
int n, k, s;

int main(){

    cin >> n >> k >> s;
    int tmp = -1;

    if(s == 1) tmp = 1;

    int ans[n+1];
    for(int i = 1; i <= n; i++){
        if(i <= k){
            ans[i] = s;
        }
        else{
            ans[i] = s + tmp;
        }
    }

    for(int i = 1; i < n; i++){
        cout << ans[i] << " ";
    }
    cout << ans[n] << endl;

    return 0;
}