Problem:
Score : 100 points

Problem Statement

We have two bottles for holding water.

Bottle 1 can hold up to A milliliters of water, and now it contains B milliliters of water.

Bottle 2 contains C milliliters of water.

We will transfer water from Bottle 2 to Bottle 1 as much as possible.

How much amount of water will remain in Bottle 2?

Constraints

All values in input are integers.

1 \leq B \leq A \leq 20

1 \leq C \leq 20

Input

Input is given from Standard Input in the following format:

A B C

Output

Print the integer representing the amount of water, in milliliters, that will remain in Bottle 2.

Sample Input 1

6 4 3

Sample Output 1

1

We will transfer two milliliters of water from Bottle 2 to Bottle 1, and one milliliter of water will remain in Bottle 2.

Sample Input 2

8 3 9

Sample Output 2

4

Sample Input 3

12 3 7

Sample Output 3

0

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;

#define ll long long

#define all(a) (a).begin(),(a).end()
#define rep(i,n) for(int i=0;i<(int)(n);i++)
#define Rep(i,n,m) for(int i=(int)(n);i<(int)(m);i++)
#define RepS(i,n,m) for(int i=(int)(n);i<=(int)(m);i++)
#define output_s(a) printf("%s\n",(a).c_str())

//library----------------------------------------------


int main(){
    int a,b,c; cin>>a>>b>>c;
    if(a>b) c=c-(a-b);
  	if(c<0) c=0;
    printf("%d\n",c);
    return 0;  
}