Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define fi first
#define se second
#define all(a) a.begin(), a.end()
#define pb push_back
#define mp make_pair
typedef long long ll;
typedef pair<ll,ll> P;
#define rep(i,a,b) for(ll i=a ; i<b ; i++)
const int max_n = 1e5;
const ll mod = 1e9+7;
const ll INF = 1LL<<60;
typedef long double ld;
template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }
int dx[4] = {0,0,1,-1};
int dy[4] = {1,-1,0,0};
ll gcd(ll a, ll b) { return a ? gcd(b%a, a) : b; }
int main(){
  int N,A,B,C,D;  cin>>N>>A>>B>>C>>D;
  --A;  --B;  --C;  --D;
  string s; cin>>s;
  bool ok=true;
  char str='#';
  if(C<D){
    rep(i,B,D-1) if(s[i]==str && s[i+1]==str) ok=false;
    rep(i,A,C-1) if(s[i]==str && s[i+1]==str) ok=false;
  }else{
      rep(i,A,C-1) if(s[i]==str && s[i+1]==str) ok=false;
      rep(i,B,D-1) if(s[i]==str && s[i+1]==str) ok=false;
      if(ok){
        bool isok=false;
        rep(i,B,D+1) if(i-1>=0 && s[i-1]=='.' && s[i]=='.' && s[i+1]=='.' && i+1<=N-1){
          isok=true;
          break;
        }
        if(!isok) ok=false;
      }
  }
  if(ok){
    cout << "Yes" << endl;
  }else{
    cout << "No" << endl;
  }
  return 0;
}