Problem:
Score : 200 points

Problem Statement

Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Constraints

1 \leq N \leq 10^5

Input

Input is given from Standard Input in the following format:

N

Output

Print the number of positive integers less than or equal to N that have an odd number of digits.

Sample Input 1

11

Sample Output 1

9

Among the positive integers less than or equal to 11, nine integers have an odd number of digits: 1, 2, \ldots, 9.

Sample Input 2

136

Sample Output 2

46

In addition to 1, 2, \ldots, 9, another 37 integers also have an odd number of digits: 100, 101, \ldots, 136.

Sample Input 3

100000

Sample Output 3

90909

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#pragma comment(linker, "/stack:200000000")
#pragma GCC optimize ("Ofast")
#pragma GCC target ("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
 
 
#include <iostream>
#include <iomanip>
#include <sstream>
#include <cstring>
#include <vector>
#include <deque>
#include <queue>
#include <set>
#include <map>
#include <valarray>
#include <iterator>
#include <functional>
#include <limits>
#include <algorithm>
#include <numeric>
#include <cmath>
#include <cassert>
#include <unordered_map>
#include <unordered_set>
#include <stack>
using namespace std;
#define IOS ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);
 
typedef int64_t ll;
 
#define endl '\n'
#define int ll
ll mod=1e9+7;
ll mod1=1e9+5;
ll power(ll a,ll b)
{
    if(b==0) return 1;
    else if(b%2==0)
        return power((((a%mod)*(a%mod))%mod),b/2)%mod;
    else return ((a%mod)*(power((((a%mod)*(a%mod))%mod),b/2)%mod))%mod;
}
int d(int n)
{
    int count=0;
    while(n)
    {
        n=n/10;
        count++;
    }
    return count;
}
int32_t main()
{
    IOS
    
    
    
    int n;
    cin>>n;
    int ans=0;

    for(int i=1;i<=n;++i)
    {
        int x=d(i);
        if(x%2!=0)
            ans++;
    }
    cout<<ans;
}