Problem:
Score : 200 points

Problem Statement

In the beginning, Takahashi has A cookies, and Aoki has B cookies.
They will perform the following operation alternately, starting from Takahashi:

If the number of cookies in his hand is odd, eat one of those cookies; if the number is even, do nothing. Then, give one-half of the cookies in his hand to the other person.

Find the numbers of cookies Takahashi and Aoki respectively have after performing K operations in total.

Constraints

1 \leq A,B \leq 10^9

1 \leq K \leq 100

A,B and K are integers.

Input

Input is given from Standard Input in the following format:

A B K

Output

Print the number of cookies Takahashi has, and the number of cookies Aoki has, in this order, after performing K operations in total.

Sample Input 1

5 4 2

Sample Output 1

5 3

The process will go as follows:

In the beginning, Takahashi and Aoki have 5 and 4 cookies, respectively.

Takahashi eats one cookie and gives two cookies to Aoki. They now have 2 and 6 cookies, respectively.

Aoki gives three cookies to Takahashi. They now have 5 and 3 cookies, respectively.

Sample Input 2

3 3 3

Sample Output 2

1 3

Sample Input 3

314159265 358979323 84

Sample Output 3

448759046 224379523

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<bits/stdc++.h>
#define mins(a,b) a=min(a,b)
#define maxs(a,b) a=max(a,b)
using namespace std;
int main(){
  long long int a,b,n,c;
  cin>>a>>b>>n;
  for(int i=0;i<n;i++){
    if(i%2==0){
      if(a%2==0){
        c=a;
        a/=2;b+=c/2;
      }
      else{
        a=(c-1)/2;b+=(c-1)/2;
      }
    }
    else{
      if(b%2==0){
        c=b;
        b/=2;a+=c/2;
      }
      else{
        b=(b-1)/2;a+=(c-1)/2;
      }
    }
  }
  cout<<a<<" "<<b<<endl;
}