Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

# include <iostream>
using namespace std;

int N;
int A, B, C, D;
string S;
int consecutiverocks=0;
int consecutiveblanks=0;

int main()
{
    cin>>N>>A>>B>>C>>D;
    cin>>S;

    for (int i=0; i<S.size(); i++)
    {
        if (S[i]!='#')
        {
            consecutiverocks=0;
        }

        else if (S[i]=='#')
        {
            consecutiverocks++;
        }

        if (consecutiverocks==2)
        {
            cout<<"No"<<endl;
            return 0;
        }
    }   

    if (A<B && B<C && C<D)
    {
        cout<<"Yes"<<endl;
        return 0;
    }

    else if (A<C && C<B && B<D)
    {
        cout<<"Yes"<<endl;
        return 0;
    }

    else if (A<B && B<D && D<C)
    {
        for (int i=0; i<S.size(); i++)
        {
            if (S[i]=='.')
            {
                consecutiveblanks++;
            }

            else if (S[i]=='#')
            {
                consecutiveblanks=0;
            }

            if (consecutiveblanks==3)
            {
                cout<<"Yes"<<endl;
                return 0;
            }
        }
    }

    cout<<"No"<<endl;
}