Problem:
Score : 200 points

Problem Statement

Let us define the FizzBuzz sequence a_1,a_2,... as follows:

If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.

If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.

If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.

If none of the above holds, a_i=i.

Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Constraints

1 \leq N \leq 10^6

Input

Input is given from Standard Input in the following format:

N

Output

Print the sum of all numbers among the first N terms of the FizzBuzz sequence.

Sample Input 1

15

Sample Output 1

60

The first 15 terms of the FizzBuzz sequence are:

1,2,\mbox{Fizz},4,\mbox{Buzz},\mbox{Fizz},7,8,\mbox{Fizz},\mbox{Buzz},11,\mbox{Fizz},13,14,\mbox{FizzBuzz}

Among them, numbers are 1,2,4,7,8,11,13,14, and the sum of them is 60.

Sample Input 2

1000000

Sample Output 2

266666333332

Watch out for overflow.

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#define _GLIBCXX_DEBUG
#include <bits/stdc++.h>
using namespace std;
#define rep(i, c) for (int i = 0; i < (int)c; i++)
#define all(v) v.begin(), v.end()
using ll = long long;
using P = pair<int, int>;
const int inf = 1000000000; //10^9
const ll MOD = 1e9 + 7;
//加算代入演算子は+=！！！！！
//int 2^31 10^9まで
int main()
{
    ll n;
    cin >> n;
    ll sum = 0;
    rep(i, n)
    {
        if (i % 3 == 0 or i % 5 == 0 or i % 15 == 0)
        {
            sum += 0;
        }
        else
        {
            sum += i;
        }
    }
    cout << sum << endl;
}