Problem:
Score : 200 points

Problem Statement

A string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:

S is a palindrome.

Let N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.

The string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.

Determine whether S is a strong palindrome.

Constraints

S consists of lowercase English letters.

The length of S is an odd number between 3 and 99 (inclusive).

Input

Input is given from Standard Input in the following format:

S

Output

If S is a strong palindrome, print Yes;
otherwise, print No.

Sample Input 1

akasaka

Sample Output 1

Yes

S is akasaka.

The string formed by the 1-st through the 3-rd characters is aka.

The string formed by the 5-th through the 7-th characters is aka.
All of these are palindromes, so S is a strong palindrome.

Sample Input 2

level

Sample Output 2

No

Sample Input 3

atcoder

Sample Output 3

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

/*
#include <iostream>
#include <vector>
#include <algorithm>
#include <cmath>
*/
#include <bits/stdc++.h>

#define rep(i,n)  for(int i=0; i<(n); i++)
using ll = long long;
using namespace std;

int main()
{
    string s;
    cin >> s;
    bool a = true;
    int n = s.length();
    rep(i,n/2){
        if(s[i] != s[(n/2)-1-i]){
            a = false;
        }
        if(s[(n/2)+1+i] != s[n-i-1]){
            a = false;
        }
    }
    if(a){
        cout << "Yes";
    }else{
        cout << "No";
    }
    return 0;
}