Problem:
Score : 100 points

Problem Statement

A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.

Given a string S, determine whether it is coffee-like.

Constraints

S is a string of length 6 consisting of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S

Output

If S is coffee-like, print Yes; otherwise, print No.

Sample Input 1

sippuu

Sample Output 1

Yes

In sippuu, the 3-rd and 4-th characters are equal, and the 5-th and 6-th characters are also equal.

Sample Input 2

iphone

Sample Output 2

No

Sample Input 3

coffee

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>

using namespace std;

#define INF 1000007
#define MOD 1000000007
#define maxn 100
#define FOR(i, a, b) for (int i = (a); i < (b); i++)
#define rep(i, n) FOR(i, 0, n)

typedef std::pair<int, int> P;

vector<bool> prime(maxn + 1, true); //素数テーブル
void prime_table(void) {
    prime[0] = false;
    prime[1] = false;
    for (int i = 2; i * i <= maxn; i++) {
        if (!prime[i]) {
            continue;
        }
        for (int j = i + i; j <= maxn; j += j + i) {
            prime[j] = false;
        }
    }
}

bool IsPrime(int num) //素数判定
{
    if (num < 2)
        return false;
    else if (num == 2)
        return true;
    else if (num % 2 == 0)
        return false;

    double sqrtNum = sqrt(num);
    for (int i = 3; i <= sqrtNum; i += 2) {
        if (num % i == 0) {
            return false;
        }
    }

    return true;
}

vector<int> divisor(int n) //約数列挙
{
    vector<int> ret;
    for (int i = 1; i * i <= n; i++) {
        if (n % i == 0) {
            ret.push_back(i - 1);
            if (i * i != n) {
                ret.push_back((n / i) - 1);
            }
        }
    }
    sort(ret.begin(), ret.end());
    return (ret);
}

int a, b;

void f(int x) {
    a = x % 10;
    b = 0;
    while (x) {
        b = x;
        x /= 10;
    }
}

signed main() {
    string S;
    cin >> S;
    if (S[2] == S[3] && S[4] == S[5]) {
        cout << "Yes" << endl;
    } else {
        cout << "No" << endl;
    }
}