Problem:
Score : 100 points

Problem Statement

Given is a string S representing the day of the week today.

S is SUN, MON, TUE, WED, THU, FRI, or SAT, for Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, and Saturday, respectively.

After how many days is the next Sunday (tomorrow or later)?

Constraints

S is SUN, MON, TUE, WED, THU, FRI, or SAT.

Input

Input is given from Standard Input in the following format:

S

Output

Print the number of days before the next Sunday.

Sample Input 1

SAT

Sample Output 1

1

It is Saturday today, and tomorrow will be Sunday.

Sample Input 2

SUN

Sample Output 2

7

It is Sunday today, and seven days later, it will be Sunday again.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#if defined(LOCAL)
#include "C:\includes.hpp"
#include "C:\debug.hpp"
#define deb(x...) cerr << "[" << #x << "] = ["; _print(x)
#else
#include <bits/stdc++.h>
#define deb(x...)
#endif
#define mp make_pair
#define mt make_tuple
#define fi first
#define se second
#define pb push_back
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define forn(i, n) for (int i = 0; i < (int)(n); ++i)
#define for1(i, n) for (int i = 1; i <= (int)(n); ++i)
#define ford(i, n) for (int i = (int)(n) - 1; i >= 0; --i)
#define fore(i, a, b) for (int i = (int)(a); i <= (int)(b); ++i)

using namespace std;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());

typedef pair<int, int> pii;
typedef vector<int> vi;
typedef vector<pii> vpi;
typedef vector<vi> vvi;
typedef long long lint;
typedef vector<lint> vlint;
typedef vector<vlint> vvlint;
typedef pair<lint, lint> plint;
typedef double ld;

template<class T> bool uin(T &a, T b) { return a > b ? (a = b, true) : false; }
template<class T> bool uax(T &a, T b) { return a < b ? (a = b, true) : false; }

int main() {
    ios::sync_with_stdio(false);
  	cin.tie(0);
	string s;
	cin >> s;
	if(s[0] == 'S' && s[1] == 'U')cout << 7 << '\n';
	else if(s[0] == 'S' && s[1] == 'A')cout << 1 << '\n';
	else if(s[0] == 'M')cout << 6 << '\n';
	else if(s[0] == 'T' && s[1] == 'U')cout << 5 << '\n';
	else if(s[0] == 'W')cout << 4 << '\n';
	else if(s[0] == 'F')cout << 2 << '\n';
	else cout << 3 << '\n';
	return 0;
}