Problem:
Score: 400 points

Problem Statement

In Takahashi Kingdom, there is a east-west railroad and N cities along it, numbered 1, 2, 3, ..., N from west to east.
A company called AtCoder Express possesses M trains, and the train i runs from City L_i to City R_i (it is possible that L_i = R_i).
Takahashi the king is interested in the following Q matters:

The number of the trains that runs strictly within the section from City p_i to City q_i, that is, the number of trains j such that p_i \leq L_j and R_j \leq q_i.

Although he is genius, this is too much data to process by himself. Find the answer for each of these Q queries to help him.

Constraints

N is an integer between 1 and 500 (inclusive).

M is an integer between 1 and 200 \ 000 (inclusive).

Q is an integer between 1 and 100 \ 000 (inclusive).

1 \leq L_i \leq R_i \leq N (1 \leq i \leq M)

1 \leq p_i \leq q_i \leq N (1 \leq i \leq Q)

Input

Input is given from Standard Input in the following format:

N M Q
L_1 R_1
L_2 R_2
:
L_M R_M
p_1 q_1
p_2 q_2
:
p_Q q_Q

Output

Print Q lines. The i-th line should contain the number of the trains that runs strictly within the section from City p_i to City q_i.

Sample Input 1

2 3 1
1 1
1 2
2 2
1 2

Sample Output 1

3

As all the trains runs within the section from City 1 to City 2, the answer to the only query is 3.

Sample Input 2

10 3 2
1 5
2 8
7 10
1 7
3 10

Sample Output 2

1
1

The first query is on the section from City 1 to 7. There is only one train that runs strictly within that section: Train 1.
The second query is on the section from City 3 to 10. There is only one train that runs strictly within that section: Train 3.

Sample Input 3

10 10 10
1 6
2 9
4 5
4 7
4 7
5 8
6 6
6 7
7 9
10 10
1 8
1 9
1 10
2 8
2 9
2 10
3 8
3 9
3 10
1 10

Sample Output 3

7
9
10
6
8
9
6
7
8
10

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <iostream>
#include <iomanip>
#include <utility>
#include <cmath>
#include <random>
#include <vector>
#include <map>
#include <set>
#include <deque>
#include <queue>
#include <stack>
#include <string>
#include <algorithm>
using namespace std;

#define rep(i,n) for(int i = 0; i<n; ++i)
#define REP(i,n) for(int i = 1; i<=n; ++i)
#define all(x) begin(x),end(x)
#define show(obj) {for(auto x:obj)cout<<x<<' ';cout<<endl;}
#define line "----------"
typedef long long ll;
typedef pair<int,int> P;
typedef pair<ll,ll> LP;
const int inf = 1001001000;
const ll INF = 1LL<<60;
const int MOD = (int)1e9 + 7;

vector<vector<int>> G(600, vector<int>());

bool isOK(int st_num, int index, int key){
	if(G[st_num][index] <= key) return true;
	else return false;
}

int binary_search(int st_num, int nax, int key){
	int ng = nax;
	int ok = -1;
	while(abs(ok-ng) > 1){
		int mid = (ok + ng)/2;
		if(isOK(st_num,mid,key))ok = mid;
		else ng = mid;
	}
	return ok;
}

int main(){
	int N, M, Q, l, r, p, q;
	cin >> N >> M >> Q;
	G.resize(N);
	rep(i,M){
		cin >> l >> r;
		--l; --r;
		G[l].push_back(r);
	}
	rep(i,N)sort(all(G[i]));
	rep(_,Q){
		cin >> p >> q;
		--p; --q;
		int res = 0;
		int key = q;
		for(int i = p; i <= q; ++i){
			int siz = G[i].size();
			res += binary_search(i, siz, key) + 1;
		}
		cout << res << endl;
	}
	return 0;
}