Problem:
Score: 200 points

Problem Statement

A country decides to build a palace.

In this country, the average temperature of a point at an elevation of x meters is T-x \times 0.006 degrees Celsius.

There are N places proposed for the place. The elevation of Place i is H_i meters.

Among them, Princess Joisino orders you to select the place whose average temperature is the closest to A degrees Celsius, and build the palace there.

Print the index of the place where the palace should be built.

It is guaranteed that the solution is unique.

Constraints

1 \leq N \leq 1000

0 \leq T \leq 50

-60 \leq A \leq T

0 \leq H_i \leq 10^5

All values in input are integers.

The solution is unique.

Input

Input is given from Standard Input in the following format:

N
T A
H_1 H_2 ... H_N

Output

Print the index of the place where the palace should be built.

Sample Input 1

2
12 5
1000 2000

Sample Output 1

1

The average temperature of Place 1 is 12-1000 \times 0.006=6 degrees Celsius.

The average temperature of Place 2 is 12-2000 \times 0.006=0 degrees Celsius.

Thus, the palace should be built at Place 1.

Sample Input 2

3
21 -11
81234 94124 52141

Sample Output 2

3

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;
#include <stdio.h>
#include <stdlib.h>

int main(){
    int N,T,A;
    cin >> N >> T >> A;
    vector<int> H(N);
    vector<double> TH(N);
    vector<double> THM(N);
    vector<double> P(N);
    double minT=0;
    for(int i = 0;i < N;i++){
        cin >> H.at(i);
        
            TH.at(i) = T - (H.at(i)*0.006);

        TH.at(i) = T-(H.at(i)*(0.006));
    }

    for(int i = 0;i < N;i++){
        if(A <= 0){
            THM.at(i) == abs(A+TH.at(i));
        }else{
            THM.at(i) = abs(A-TH.at(i));
        }
    }
    P = THM;
    sort(THM.begin(),THM.end());

    for(int i = 0;i < N;i++){
        if(THM.at(0) == P.at(i)){
            cout << i+1 << endl;
            break;
        }
    }
    cout << TH.at(0)*0.006;
    

    
}