Problem:
Score: 200 points

Problem Statement

A country decides to build a palace.

In this country, the average temperature of a point at an elevation of x meters is T-x \times 0.006 degrees Celsius.

There are N places proposed for the place. The elevation of Place i is H_i meters.

Among them, Princess Joisino orders you to select the place whose average temperature is the closest to A degrees Celsius, and build the palace there.

Print the index of the place where the palace should be built.

It is guaranteed that the solution is unique.

Constraints

1 \leq N \leq 1000

0 \leq T \leq 50

-60 \leq A \leq T

0 \leq H_i \leq 10^5

All values in input are integers.

The solution is unique.

Input

Input is given from Standard Input in the following format:

N
T A
H_1 H_2 ... H_N

Output

Print the index of the place where the palace should be built.

Sample Input 1

2
12 5
1000 2000

Sample Output 1

1

The average temperature of Place 1 is 12-1000 \times 0.006=6 degrees Celsius.

The average temperature of Place 2 is 12-2000 \times 0.006=0 degrees Celsius.

Thus, the palace should be built at Place 1.

Sample Input 2

3
21 -11
81234 94124 52141

Sample Output 2

3

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
#include<cstdio>
#include<iostream>
#include<string>
#include<algorithm>
#include<complex>
#include<vector>

using namespace std;

int nx[]={0,1,0,-1};
int ny[]={0,1,0,-1};
//*****************************************

int N,T,A;

double mse=100000;
int min_i;
double abs_mse;

int main(void){
    cin >> N;
    cin >> T >> A;

    vector<int> height(N+100,0);
    vector<double> temperture(N+100,0);

    for(int i=0;i<N;i++) cin >> height[i] ;

    for(int i=0;i<N;i++){
        temperture[i]=(T-height[i]*0.006);
        //cout << temperture[i] << endl;

    }

    for(int i=0;i<N;i++){
        abs_mse=abs(temperture[i]-A);
        if(mse>=abs_mse){
            
            mse=abs_mse;
            min_i=i+1;
        }
        //cout << abs_mse << endl;
    }

    cout << min_i<< endl;

    return 0;
}