Problem:
Score: 100 points

Problem Statement

The weather in Takahashi's town changes day by day, in the following cycle: Sunny, Cloudy, Rainy, Sunny, Cloudy, Rainy, ...

Given is a string S representing the weather in the town today. Predict the weather tomorrow.

Constraints

S is Sunny, Cloudy, or Rainy.

Input

Input is given from Standard Input in the following format:

S

Output

Print a string representing the expected weather tomorrow, in the same format in which input is given.

Sample Input 1

Sunny

Sample Output 1

Cloudy

In Takahashi's town, a sunny day is followed by a cloudy day.

Sample Input 2

Rainy

Sample Output 2

Sunny

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include "bits/stdc++.h"
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
//#define int ll
typedef vector<vector<pair<int, int> > > vvp;
typedef vector<pair<int, int> > vp;
typedef vector<vector<int> > vvi;
typedef vector<int> vi;
typedef vector<vector<ll> > vvl;
typedef vector<ll> vl;
typedef vector<vector<double> > vvd;
typedef vector<double> vd;
typedef vector<vector<bool> > vvb;
typedef vector<bool> vb;
typedef vector<string> vs;
typedef pair<string, int> psi;
typedef pair<int, int> pii;
#define rep(i,s,n) for(int i = (s); i < (n); i++)
#define all(x) (x).begin(), (x).end()
#define yn(f) (f?"yes":"no")
#define YN(f) (f?"YES":"NO")
#define Yn(f) (f?"Yes":"No")
#define len(x) int(x.size())
#define inf (1000000007)
#define ll_inf (1000000000000000007)
#define nil -1

void puts() {
	cout << endl;
}
template <class Head, class... Tail>
void puts(Head&& head, Tail&& ... tail) {
	cout << head;
	if (sizeof...(tail) == 0) {
		cout << endl;
	}
	else {
		cout << " ";
		puts(forward<Tail>(tail)...);
	}

}
void puts(vector<pair<int,int> >& A) {
	for (int i = 0; i < A.size(); i++)
	{
		cout <<"("<< A[i].first<<","<<A[i].second<<")";
		if (A.size() - 1 == i) {
			cout << endl;
		}
		else {
			cout << " ";
		}
	}
}
void puts(vector<vector<pair<int,int> > >& A) {
	for (int i = 0; i < A.size(); i++)
	{
		puts(A[i]);
	}
}
template <class T>
void puts(vector<T>& A) {
	for (int i = 0; i < A.size(); i++)
	{
		cout << A[i];
		if (A.size() - 1 == i) {
			cout << endl;
		}
		else {
			cout << " ";
		}
	}
}
template<class T>
void puts(vector<vector<T> >& A) {
	for (int i = 0; i < A.size(); i++)
	{
		puts(A[i]);
	}
}
class disjoint_set {
public:
	vi p, rank;
	disjoint_set(int size) {
		p.resize(size, 0);
		rank.resize(size, 0);
		for (int i = 0; i < size; i++)makeSet(i);
	}
	void makeSet(int x) {
		p[x] = x;
		rank[x] = 0;
	}
	bool same(int x, int y) {
		return findSet(x) == findSet(y);
	}
	void unite(int x, int y) {
		link(findSet(x), findSet(y));
	}
	void link(int x, int y) {
		if (rank[x] < rank[y]) {
			p[x] = y;
		}
		else {
			p[y] = x;
			if (rank[x] == rank[y]) {
				rank[x]++;
			}
		}
	}
	int findSet(int x) {
		if (x != p[x]) {
			p[x] = findSet(p[x]);
		}
		return p[x];
	}
};
int gcd(int a, int b) {//log N
	return (b == 0) ? a : gcd(b, a % b);
}
int lcm(int a, int b) {//log N
	return (a * b) / gcd(a, b);
}
int extgcd(int a, int b, int& x, int& y) {// log N
	int d = a;
	if (b == 0) {
		x = 1;
		y = 0;
	}
	else {
		d = extgcd(b, a % b, y, x);
		y -= (a / b) * x;
	}
	return d;
}
vi get_primes(int limit) {//N log N
	vb A(limit + 1, true);
	for (int i = 2; i < A.size(); i++) {
		if (!A[i])continue;
		for (int j = i * 2; j < A.size(); j += i)A[j] = false;
	}
	vi B;
	for (int i = 2; i < A.size(); i++)
	{
		if (A[i])B.push_back(i);
	}
	return B;
}
bool is_prime(int num) {// sqrt(N)
	if (num < 2)return false;
	for (int i = 2; i <= sqrt(num); i++)
	{
		if (num % i == 0) {
			return false;
		}
	}
	return true;
}
ll merge_count(vi & A) {//N log N
	int n = A.size();
	if (n <= 1)return 0;
	long long count = 0;
	int mid = n / 2;
	vector<int> B(A.begin(), A.begin() + mid);
	vector<int> C(A.begin() + mid, A.end());
	count += merge_count(B);
	count += merge_count(C);
	B.push_back(inf);
	C.push_back(inf);
	int B_i = 0;
	int C_i = 0;
	for (int i = 0; i < n; i++) {
		if (B[B_i] <= C[C_i]) {
			A[i] = B[B_i++];
		}
		else {
			count += (n / 2) - B_i;
			A[i] = C[C_i++];
		}
	}
	return count;
}
vvi bit(int size) {//2**N
	vvi A;
	for (int i = 0; i < (1<<size); i++)
	{
		vi temp;
		for (int j = 0; j < size; j++)
		{
			if ((i & (1 << (size - j - 1))) > 0) {
				temp.push_back(1);
			}
			else {
				temp.push_back(0);
			}
		}
		A.push_back(temp);
	}
	return A;
}
vvi bit(int size,int min,int max) {//長さがsizeで、1の個数がmin以上max以下のものを全列挙して返す  2**N
	vvi A;
	for (int i = 0; i < (1 << size); i++)
	{
		vi temp;
		int count = 0;
		for (int j = 0; j < size; j++)
		{
			if ((i & (1 << (size - j - 1))) > 0) {
				temp.push_back(1);
				count++;
			}
			else {
				temp.push_back(0);
			}
		}
		if(min<=count && count<=max)A.push_back(temp);
	}
	return A;
}


int main() {
	string s; cin >> s;
	if (s == "Sunny")puts("Cloudy");
	else if (s == "Cloudy")puts("Rainy");
	else puts("Sunny");
}