Problem:
Score : 100 points

Problem Statement

There are N items, numbered 1, 2, \ldots, N.
For each i (1 \leq i \leq N), Item i has a weight of w_i and a value of v_i.

Taro has decided to choose some of the N items and carry them home in a knapsack.
The capacity of the knapsack is W, which means that the sum of the weights of items taken must be at most W.

Find the maximum possible sum of the values of items that Taro takes home.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq W \leq 10^9

1 \leq w_i \leq W

1 \leq v_i \leq 10^3

Input

Input is given from Standard Input in the following format:

N W
w_1 v_1
w_2 v_2
:
w_N v_N

Output

Print the maximum possible sum of the values of items that Taro takes home.

Sample Input 1

3 8
3 30
4 50
5 60

Sample Output 1

90

Items 1 and 3 should be taken.
Then, the sum of the weights is 3 + 5 = 8, and the sum of the values is 30 + 60 = 90.

Sample Input 2

1 1000000000
1000000000 10

Sample Output 2

10

Sample Input 3

6 15
6 5
5 6
6 4
6 6
3 5
7 2

Sample Output 3

17

Items 2, 4 and 5 should be taken.
Then, the sum of the weights is 5 + 6 + 3 = 14, and the sum of the values is 6 + 6 + 5 = 17.

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

                                  //ABHISHEK AGRAWAL//                    
                      //Newbie......You have to be odd to be no. ONE :)//
#include<bits/stdc++.h>
using namespace std;
#define ll long long int
#define ld long double
#define fl float
#define lcm(a,b) (a*(b/__gcd(a,b)))
#define vs vector <string>
#define vc vector <char>
#define vll vector<ll>
#define sll set<ll>
#define pll pair<ll,ll>
#define plc pair<ll,char>
#define tlll tuple<ll,ll,ll>
#define mt make_tuple
#define vpll vector<pair<ll,ll>>
#define vtll vector<tuple<ll,ll,ll>>
#define vvll vector<vector<ll>>
#define lb lower_bound
#define pb push_back
#define pob pop_back
#define f first
#define s second
#define mll map<ll,ll>
#define mp make_pair
#define sp(n) fixed<<setprecision(n)
#define mcl map<char,ll>
#define mcc map<char,char>
#define msl map<string,ll>
#define mss map<string,string>  
#define mod (ll)1000000007
#define flash ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL); 
#define test ll t;read(t);while(t--) 
#define sortv(v) sort(v.begin(),v.end())
#define INF (ll)(1e15)
#define loop(i,n) for(ll i=0;i<n;i++)
#define loop1(i,n) for(ll i=1;i<=n;i++)
#define rloop(n,i) for(ll i=n-1;i>=0;i--)
#define loopab(i,a,b,c) for(ll i=a;i<=b;i+=c)
#define max3(a,b,c) max(max(a,b),c)
#define min3(a,b,c) min(min(a,b),c)
#define reada(a,n) loop(i,n) cin>>a[i];
#define reada1(a,n) loop1(i,n) cin>>a[i];
#define sorta(a) sort(a,a+n,greater<ll>())
#define countone(n) __builtin_popcount(n)
#define numoftrailzero(n) __builtin_ctz(n)
#define maxpowoftwo(n) __builtin_clz(n)
#define leastindexwithone(n)  __builtin_ffs(n)
#define what_is(x) cerr << #x << " is " << x << endl;
#define pfv(v) cout<<v.size()<<"\n";loop(i,v.size()) cout<<v[i]<<" ";
#define pv(v) loop(i,v.size()) cout<<v[i]<<" ";
//if we need to devide any given number in powers of term the power of max term
#define answer(n) ceil(log2(n+1))
ll n,q;
ll gcd(ll a, ll b){if (b==0){return a;} return gcd(b,a%b);}
ll powe(ll a,ll b){ll res=1;while(b>0){if(b%2 ==1){res=(res*a);}a=(a*a);b/=2;} return res;}
ll power(ll a,ll b,ll M){a%=M;ll res=1;while(b>0){if(b%2 ==1){res=(res*a)%M;}a=(a*a)%M;b/=2;} return res;}
ll extendedEuclid(ll A,ll B,ll &x,ll &y){
    if(B == 0) {
        x = 1;
        y = 0;
        return A;
    }
    else {
        ll x1 , y1;
        ll gcd = extendedEuclid(B,A%B,x1,y1);
        y = x1-(A/B)*y1; 
        x = y1;
        return gcd;
    }
}
ll mi(ll A, ll M){ll x,y;extendedEuclid(A,M,x,y);if(x<0){x+=mod;} return x;}
 
 
template <typename T>
void read(T &x) {
    cin >> x;
}
template <typename T , typename T0>
void read(T &x, T0 &y) {
    cin >> x >> y;
}
template <typename T , typename T0 , typename T1>
void read(T &x, T0 &y, T1 &z) {
    cin >> x >> y >> z;
}
template <typename T , typename T0 , typename T1 , typename T2>
void read(T &x, T0 &y, T1 &z, T2 &w) {
    cin >> x >> y >> z >> w;
}
 
//pair//
//read pair//
template <typename T , typename T0>
void read(pair< T , T0 > &p) {
    cin >> p.f >> p.s;
}
//write pair//
template <typename T , typename T0>
void write(pair< T , T0 > &p){
    write(p.f);
    write(p.s);
}
 
//vector//
//read vector//
template <typename T>
void read(vector< T > &oneD, ll n) {
    loop(i,n)
    {
        ll x;
        read(x);
        oneD.pb(x);
    }
}
//array//
//read array//
template <typename T>
void read(T oneD[] , ll n) {
    loop(i,n){
        read(oneD[i]);
    }
}
//write array//
template <typename T>
void write(T oneD[] ,int n){
    loop(i,n){
        write(oneD[i]);
    }
    cout << endl;
}

vector<bool>sieve(1000000,true);
void Sieve(){
 sieve[0]=false;
 sieve[1]=false;
 for(ll i=2;i*i<=1000000;i++){
  if(sieve[i]==true){
   for(ll j=i*i;j<1000000;j+=i)
    sieve[j]=false;
  }
 }
}
 vll sieve_spf;
void Sieve_spf(){
 const ll n = 1e6 + 5;
 sieve_spf.resize(n);
 
 loop(i,n)
  sieve_spf[i]=i;
 
 sieve_spf[0]=-1;
 sieve_spf[1]=1;
 
 loopab(i,2,n,2)
  sieve_spf[i]=2;
 
 loopab(i,3,n,2)
  if(sieve_spf[i]==i)
   loopab(j,i*i,n,i)
    if(sieve_spf[j]==j)
     sieve_spf[j]=i;
}
bool oppositeSigns(ll x,ll y) 
{ 
    return ((x^y)<0); 
} 
int mpt(ll n){
    ll c=0;
     ll n1=pow(2,c);
     while(n1<n){
         c++;
         n1=pow(2,c);
     }
     return c;
}
void the_happiest_place_on_earth()
{
    flash;
  #ifdef ENABLE_FILE_IO
    freopen("in", "r", stdin);
    freopen("out", "w", stdout);
  #endif      
} 
const int N=400023;ll wt[N],val[N],dp[100001];
/*ll knapsack(ll wt[],ll val[],ll vl,ll n){
    if(dp[n][vl]!=-1) return dp[n][vl];
    dp[n][vl]=max(wt[n-1]+knapsack(wt,val,vl-val[n-1],n-1),knapsack(wt,val,vl,n-1));
    return dp[n][vl];
}*/
/*void solve(){
    ll w;read(n,w);ll dp[n+1][w+1];
    loop(i,n) read(wt[i],val[i]);
    loop(i,n+1) loop(j,w+1) if(i==0||j==0) dp[i][j]=0;
    loop1(i,n) {
        loop1(j,w){
            if(wt[i-1]<=j) dp[i][j]=max(val[i-1]+dp[i-1][j-wt[i-1]],dp[i-1][j]);
            else dp[i][j]=dp[i-1][j];
        }
    }
    cout<<dp[n][w]<<"\n";
    return;
}*/
int main(){
    the_happiest_place_on_earth();
    //Today's thought: Push yourself, because no one else is going to do it for you.
    //Things aren’t always #000000 and #FFFFFF
    //START OF PROGRAM LOGIC
    ll w;read(n,w);ll vl=0;
    loop(i,n) {read(wt[i],val[i]);vl+=val[i];}
    loop1(i,vl) dp[i]=INT64_MAX;
    ll ma=0;
    loop(i,n) for(ll j=vl;j>=val[i];j--) dp[j]=min(dp[j],dp[j-val[i]]+wt[i]);
    for(ll i=vl;i>0;i--) if(dp[i]<=w){ma=i;break;}
    cout<<ma<<"\n";
    cerr << "Time : " << 1000 * ((double)clock()) / (double)CLOCKS_PER_SEC << "ms\n";
    //END OF PROGRAM LOGIC
	return 0;
}