Problem:
Score : 100 points

Problem Statement

A Hitachi string is a concatenation of one or more copies of the string hi.

For example, hi and hihi are Hitachi strings, while ha and hii are not.

Given a string S, determine whether S is a Hitachi string.

Constraints

The length of S is between 1 and 10 (inclusive).

S is a string consisting of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S

Output

If S is a Hitachi string, print Yes; otherwise, print No.

Sample Input 1

hihi

Sample Output 1

Yes

hihi is the concatenation of two copies of hi, so it is a Hitachi string.

Sample Input 2

hi

Sample Output 2

Yes

Sample Input 3

ha

Sample Output 3

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
#include<vector>
#include<string>
#include<algorithm>
#include<cmath>
 
#define fast ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
#define int long long int
#define mod 1000000007

#define out1(a) cout<<#a<<" "<<a<<endl
#define out2(a,b) cout<<#a<<" "<<a<<" "<<#b<<" "<<b<<endl
#define out3(a,b,c) cout<<#a<<" "<<a<<" "<<#b<<" "<<b<<" "<<#c<<" "<<c<<endl
 
using namespace std;

signed main()
{
    fast;
    string s;
    cin>>s;

    if ( s == "hi" )
    {
        cout<<"Yes"<<endl;
    }
    else if ( s == "hihi" )
    {
        cout<<"Yes"<<endl;
    }
    else if ( s == "hihihi" )
    {
        cout<<"Yes"<<endl;
    }
    else if ( s == "hihihihi" )
    {
        cout<<"Yes"<<endl;
    }
    else if ( s == "hihihihihi" )
    {
        cout<<"Yes"<<endl;
    }
    else
    {
        cout<<"No"<<endl;
    }
    return 0;
}