Problem:
Score: 100 points

Problem Statement

A triple of numbers is said to be poor when two of those numbers are equal but the other number is different from those two numbers.

You will be given three integers A, B, and C. If this triple is poor, print Yes; otherwise, print No.

Constraints

A, B, and C are all integers between 1 and 9 (inclusive).

Input

Input is given from Standard Input in the following format:

A B C

Output

If the given triple is poor, print Yes; otherwise, print No.

Sample Input 1

5 7 5

Sample Output 1

Yes

A and C are equal, but B is different from those two numbers, so this triple is poor.

Sample Input 2

4 4 4

Sample Output 2

No

A, B, and C are all equal, so this triple is not poor.

Sample Input 3

4 9 6

Sample Output 3

No

Sample Input 4

3 3 4

Sample Output 4

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

    #include <bits/stdc++.h>
    using namespace std;
    typedef long long ll;
    typedef long double ld;
    typedef pair<ll, ll> l_l;
    typedef pair<int , int> i_i;
    typedef vector<ll> vl;
    typedef vector<int> vi;
    typedef vector<char> vec;
    typedef vector<bool> veb;
    typedef vector<string> ves;
    typedef vector<vector<ll>> vvl;
    typedef vector<vector<int>> vvi;
    typedef vector<vector<char>> vvec;
    typedef vector<vector<bool>> vveb;
    typedef vector<vector<string>> vves;
    #define rep(i,n) for(int i=0;i<(int)(n);i++)
    #define rep1(i,n) for(int i=1;i<(int)(n);i++)
    #define rep2(i,n) for(int i=2;i<(int)(n);i++)
    #define repk(i,k,n) for(int i=k;i<(int)(n);i++)
    #define fs first
    #define sc second
    #define pb push_back
    #define pp pop_back
    #define all(a) a.begin(),a.end()
    #define rall(a) a.rbegin(),a.rend()
    #define maxel(a) *max_element(all(a))
    #define minel(a) *min_element(all(a))
    #define acc accumulate
    #define EPS (1e-7)
    #define INF (1e9)
    #define PI (acos(-1))
    #define mod (1000000007)
    typedef long long int64;
    //const int64 INF = 1LL << 58;
    #define dame { puts("-1"); return 0;}
    #define YES { cout << "YES" << endl; return 0; }
    #define NO { cout << "NO" << endl; return 0; }
    #define Yes { cout << "Yes" << endl; return 0; }
    #define No { cout << "No" << endl; return 0; }
    template<class T> bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }
    template<class T> bool chmin(T &a, const T &b) { if (a>b) { a=b; return 1; } return 0; }
    int dx[] = {0, 0, -1, 1};
    int dy[] = {1, -1, 0, 0};
     
    int main(){
    	cin.tie(0);
    	ios::sync_with_stdio(false);
     
      	int n;
      	cin >> n;
      	vi a(n);
  
      	rep(i,n){cin >> a.at(i);}
      	rep(i,n){
                if(a.at(i)%2 == 0){
                	if(a.at(i)%3 != 0 && a.at(i)%5 == 0){cout << "DENIED" << endl;return 0;} 
                }      
        }
      cout << "APRROVED" << endl;
      return 0;  
    }