Problem:
Score: 300 points

Problem Statement

As AtCoder Beginner Contest 100 is taking place, the office of AtCoder, Inc. is decorated with a sequence of length N, a = {a_1, a_2, a_3, ..., a_N}.

Snuke, an employee, would like to play with this sequence.

Specifically, he would like to repeat the following operation as many times as possible:

For every i satisfying 1 \leq i \leq N, perform one of the following: "divide a_i by 2" and "multiply a_i by 3".
Here, choosing "multiply a_i by 3" for every i is not allowed, and the value of a_i after the operation must be an integer.

At most how many operations can be performed?

Constraints

N is an integer between 1 and 10 \ 000 (inclusive).

a_i is an integer between 1 and 1 \ 000 \ 000 \ 000 (inclusive).

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 a_3 ... a_N

Output

Print the maximum number of operations that Snuke can perform.

Sample Input 1

3
5 2 4

Sample Output 1

3

The sequence is initially {5, 2, 4}. Three operations can be performed as follows:

First, multiply a_1 by 3, multiply a_2 by 3 and divide a_3 by 2. The sequence is now {15, 6, 2}.

Next, multiply a_1 by 3, divide a_2 by 2 and multiply a_3 by 3. The sequence is now {45, 3, 6}.

Finally, multiply a_1 by 3, multiply a_2 by 3 and divide a_3 by 2. The sequence is now {135, 9, 3}.

Sample Input 2

4
631 577 243 199

Sample Output 2

0

No operation can be performed since all the elements are odd. Thus, the answer is 0.

Sample Input 3

10
2184 2126 1721 1800 1024 2528 3360 1945 1280 1776

Sample Output 3

39

Solution in C++14 (Clang 3.8.0) (judge verdict: Accepted)

//#include "bits/stdc++.h"
#include <iostream>
#include <vector>
#include <map>
#include <utility>
#include <algorithm>
#include <cmath>
#include <cstdio>
#include <cstring>
#include <stack>
#include <queue>
#include <set>
#include <unordered_map>
#include <unordered_set>
#include <numeric>
#include <complex>
#include <bitset>
#include <functional>
#include <stack>
#include <regex>
#include <tuple>
#include <iomanip>

#define int long long
#define REP(i,a,n) for(int i=a;i<n;++i)
#define rep(i,n) REP(i,0,n)
#define REV(i,a,n) for(int i=n;i>=a;--i)
#define all(e) e.begin(),e.end()
#define rall(e) e.rbegin(),e.rend()
#define pb push_back
#define mp make_pair
#define fs first
#define sc second
#define show(n) cerr<<#n<<" = "<<n<<endl
#define showp(n) cerr<<n.fs<<", "<<n.sc<<endl
#define shows(n) for(auto z:n){cerr<<z<<", ";}cerr<<endl
#define showsp(n) for(auto z:n){cerr<<z.fs<<" "<<z.sc<<", "}cerr<<endl

#define yes puts("Yes")
#define no puts("No")
#define case(i) printf("Case #%lld: ",i)

using namespace std;

using vi=vector<int>;
using pint=pair<int,int>;

inline void io(){cin.tie(0);ios::sync_with_stdio(false);cout.tie(0);cout<<fixed<<setprecision(20);}
inline int  in(){int n;scanf("%lld",&n);return n;}
inline void out(int n){printf("%lld\n",n);}

const int INF=1LL<<55;
const int MOD=1000000007;
const double EPS=1e-8;

int n;
int a(int a){
    int cnt=0;
    while(true){
        if(a&1) return cnt;
        a/=2;
        cnt++;
    }
}

signed main(){
    io();
    cin>>n;
    vi vec(n);
    int sum=0;
    rep(i,n) {
        cin>>vec[i];
        sum+=a(vec[i]);
    }
    cout<<sum<<endl;

    return 0;
}