Problem:
Score : 200 points

Problem Statement

Let w be a string consisting of lowercase letters.
We will call w beautiful if the following condition is satisfied:

Each lowercase letter of the English alphabet occurs even number of times in w.

You are given the string w. Determine if w is beautiful.

Constraints

1 \leq |w| \leq 100

w consists of lowercase letters (a-z).

Input

The input is given from Standard Input in the following format:

w

Output

Print Yes if w is beautiful. Print No otherwise.

Sample Input 1

abaccaba

Sample Output 1

Yes

a occurs four times, b occurs twice, c occurs twice and the other letters occur zero times.

Sample Input 2

hthth

Sample Output 2

No

Solution in C++ (Clang 10.0.0) (judge verdict: Accepted)

/**
 * code generated by JHelper
 * More info: https://github.com/AlexeyDmitriev/JHelper
 * @author
 */

#include <iostream>
#include <fstream>

#include <iostream>
#include <string>
#include <vector>
#include <math.h>
#include <map>
#include <set>
#include <algorithm>
#include <numeric>
#include <bitset>
#include <limits>
#include <iomanip>
using namespace std;
using ll = long long;
constexpr ll INF = 1010000000000000017LL;
#define rep(i, n) for(ll i = 0; i < (ll)(n); i++)
#define all(v) v.begin(), v.end()

ll GCD(ll a, ll b) { if(b==0) return a; else return GCD(b, a%b); }
ll LCM(ll a, ll b) { return a/GCD(a,b)*b; }

class B {
public:
	void solve(std::istream& in, std::ostream& out) {
	    string w;
	    map<char,int> m;
	    in>>w;
	    rep(i,w.size()){
	        m[w.at(i)]++;
	    }
	    bool isBeu=true;
	    for(const auto i:m){
	        if(i.second%2!=0) isBeu=false;
	    }
	    if(isBeu) out<<"Yes";
	    else out<<"No";

	}
};


int main() {
	B solver;
	std::istream& in(std::cin);
	std::ostream& out(std::cout);
	solver.solve(in, out);
	return 0;
}