Problem:
Score : 300 points

Problem Statement

Sitting in a station waiting room, Joisino is gazing at her train ticket.

The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).

In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.

The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Constraints

0≤A,B,C,D≤9

All input values are integers.

It is guaranteed that there is a solution.

Input

Input is given from Standard Input in the following format:

ABCD

Output

Print the formula you made, including the part =7.

Use the signs + and -.

Do not print a space between a digit and a sign.

Sample Input 1

1222

Sample Output 1

1+2+2+2=7

This is the only valid solution.

Sample Input 2

0290

Sample Output 2

0-2+9+0=7

0 - 2 + 9 - 0 = 7 is also a valid solution.

Sample Input 3

3242

Sample Output 3

3+2+4-2=7

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

//前置き
#pragma region

#include<iostream>
#include<cstdio>
#include<cmath>
#include<string>
#include<vector>
#include<list>
#include<algorithm>
#include<set>
#include<map>
#include<stack>
#include<queue>

using namespace std;

typedef  long long ll;

#define pb(a) push_back(a)
#define all(x) (x).begin(),(x).end()

#define FOR(i, a, n) for(ll i = (ll)(a); i < (ll)(n); ++i)
#define REP(i, n) FOR(i, 0, n)
#define SORT(a) sort(all(a))
#define REVERSE(a) reverse(all(a))

#define PRINT(str) printf(#str "\n")
#define yOUT PRINT(Yes)
#define nOUT PRINT(No)
#define YOUT PRINT(YES)
#define NOUT PRINT(NO)

#pragma endregion

//関数定義
#pragma region 
//偶数 ->　true :: 奇数　-> false
bool EVEN(ll a){
    return a%2-1;
}

//最大公約数
ll gcd(ll a, ll b) {  
    if (!b)  
        return a;  
    return gcd(b, a%b);  
}  

//最小公倍数
ll lcm(ll a, ll b) {  
    return a*b/gcd(a,b);  
} 

#pragma endregion

int main(){
    int a[4], b;
    cin >> b;
    REP(i , 4){
        a[3-i] = b % 10;
        b /= 10;
    }
    string op = "+-";

    int ans;
    REP(i, 8){
        ans = a[0];
        REP(j, 3){
            if(i & (1 << j)) ans -= a[j+1];
            else ans += a[j+1];
        }
        if(ans == 7){
            REP(j ,4){
                cout << a[j];
                if(j < 3){
                    if(i & (1 << j)) cout << "-";
                    else cout << "+";
                }
            }
            cout << "=7" << endl;
            return 0;
        }
    }
 }