Problem:
Score : 300 points

Problem Statement

There are N slimes lining up from left to right. The colors of these slimes will be given as a string S of length N consisting of lowercase English letters. The i-th slime from the left has the color that corresponds to the i-th character of S.

Adjacent slimes with the same color will fuse into one larger slime without changing the color. If there were a slime adjacent to this group of slimes before fusion, that slime is now adjacent to the new larger slime.

Ultimately, how many slimes will be there?

Constraints

1 \leq N \leq 10^5

|S| = N

S consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

N
S

Output

Print the final number of slimes.

Sample Input 1

10
aabbbbaaca

Sample Output 1

5

Ultimately, these slimes will fuse into abaca.

Sample Input 2

5
aaaaa

Sample Output 2

1

All the slimes will fuse into one.

Sample Input 3

20
xxzaffeeeeddfkkkkllq

Sample Output 3

10

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

/*
the top of the losers
*/
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#define sz(v)   ((int)(v).size())
#define  all(v)    ((v).begin()),((v).end())
#define  allr(v)    ((v).rbegin()),((v).rend())
#define   pb         push_back
#define   mp         make_pair
#define    Lcm(a,b)  ((a*b)/(__gcd(a,b)))
#define    X            real()
#define    Y            imag()
#define    clr(v,d)      memset( v, d ,sizeof(v))
#define     point        complex<ll>
#define    cp(a,b)          (((conj(a))*(b)).imag())
typedef  long long     ll ;
typedef  unsigned long long     ull ;
const double eps= (1e-9);
using namespace std;
using namespace __gnu_pbds;
int dcmp(long double a,long double b){   return fabsl(a-b)<=eps ? 0: (a>b)? 1:-1  ;}
int countNumBit1(int mask) {int ret=0; while (mask) 	{mask &= (mask-1);++ret;	}return ret;}
void GO(){ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);}
string st;
int main(){
    GO();
    int n;
    cin>>n>>st;
    ll cnt=0;
    for(int i=0;i<n;i++){
        if(i+1<n&&st[i]==st[i+1])
            ;
        else{
            cnt++;
        }
    }
    cout<<cnt<<endl;
}