Problem:
Score : 100 points

Problem Statement

Takahashi is a member of a programming competition site, ButCoder.

Each member of ButCoder is assigned two values: Inner Rating and Displayed Rating.

The Displayed Rating of a member is equal to their Inner Rating if the member has participated in 10 or more contests. Otherwise, the Displayed Rating will be their Inner Rating minus 100 \times (10 - K) when the member has participated in K contests.

Takahashi has participated in N contests, and his Displayed Rating is R. Find his Inner Rating.

Constraints

All values in input are integers.

1 \leq N \leq 100

0 \leq R \leq 4111

Input

Input is given from Standard Input in the following format:

N R

Output

Print his Inner Rating.

Sample Input 1

2 2919

Sample Output 1

3719

Takahashi has participated in 2 contests, which is less than 10, so his Displayed Rating is his Inner Rating minus 100 \times (10 - 2) = 800.

Thus, Takahashi's Inner Rating is 2919 + 800 = 3719.

Sample Input 2

22 3051

Sample Output 2

3051

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
#define FIO ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);
#define PI 3.141592653589793238462643383279502884L
#define make_unique(vec) vec.resize(distance(vec.begin(),unique(vec.begin(),vec.end())))
#define Sort(vec) sort(vec.begin(),vec.end())
#define RSort(vec) sort(vec.rbegin(),vec.rend())
#define endl "\n"
#define tr1(i) cout<<i<<endl;
#define tr2(i,j) cout<<i<<" "<<j<<endl;
#define tr3(i,j,k) cout<<i<<" "<<j<<" "<<k<<endl;
#define vvi vector<vector<int> > 
#define vvl vector<vector<ll> >
#define all(st) st.begin(),st.end()
#define vpl vector<pair<ll,ll> >
#define vpi vector<pair<int,int> >
#define pi pair<int,int>
#define pl pair<ll,ll>
#define al vector<list<int> >
#define vs vector<string>
#define vi vector<int>
#define vb vector<bool>
#define vl vector<ll>
#define vc vector<char>
#define rep(i,l,r) for(int i=l;i<r;i++)
#define repit(st) for(auto it=st.begin();it!=st.end();it++)
#define ull unsigned long long int
#define eb emplace_back
#define pb push_back
#define ll long long int
#define minf -(1e18)
#define inf 1e18
#define f first
#define se second
#define mod 1000000007
using namespace std;
ll mi(ll n,ll m){ll pw=n%m;ll ex=m-2;ll ans=1;while(ex){if(ex&1) ans = ans*pw%m;pw = pw*pw%m;ex>>=1;}return ans%mod;}
ll pw(ll a,ll n){ll pw=a%mod;ll ex=n;ll ans=1;while(ex){if(ex&1) ans = ans*pw%mod;pw = pw*pw%mod;ex>>=1;}return ans%mod;}
template<typename T>istream &operator>>(istream &is, vector<T> &v) { for (T &t : v) is >> t; return is; }
template<typename T>ostream &operator<<(ostream &os, const vector<T> &v) { for (const T &t : v) {os << t <<" ";} os << '\n'; return os; }
void show(ll x){cout<<x<<" ";}
ll gcd(ll a,ll b){return b==0?a:gcd(b,a%b);}
ll lcm(ll a,ll b){return a/gcd(a,b)*b;}
ll max(ll a,ll b){return a>b?a:b;}
ll min(ll a,ll b){return a<b?a:b;}
ll Abs(ll x){return x>0?x:(-x);}
ll Ceil(ll a,ll b){return a/b+(a%b!=0);}
#define bs binary_search
//#define int long long 
#define lb lower_bound
#define mkp make_pair
//#define d double
void solve(){
 
 
	ll n,r;
	cin>>n>>r;
	if(n>=10){
		cout<<r<<endl;
	}
	else{
		cout<<r+(100*(10-n))<<endl;
	}
 
 
 
 
 
 
}
int32_t main(){
int t=1;
//cin>>t;
while(t--){
	solve();
}
}