Problem:
Score : 200 points

Problem Statement

A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.

How many times will the ball make a bounce where the coordinate is at most X?

Constraints

1 \leq N \leq 100

1 \leq L_i \leq 100

1 \leq X \leq 10000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N X
L_1 L_2 ... L_{N-1} L_N

Output

Print the number of times the ball will make a bounce where the coordinate is at most X.

Sample Input 1

3 6
3 4 5

Sample Output 1

2

The ball will make a bounce at the coordinates 0, 3, 7 and 12, among which two are less than or equal to 6.

Sample Input 2

4 9
3 3 3 3

Sample Output 2

4

The ball will make a bounce at the coordinates 0, 3, 6, 9 and 12, among which four are less than or equal to 9.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define ALL(obj) obj.begin(),obj.end()
#define pb(obj) push_back(obj)
#define REP(i,N) for(ll i=0;i<N;i++)
typedef long long ll;
int main(){
    cin.tie(0);
    ios::sync_with_stdio(false);
    int N,X;
    cin>>N>>X;
    vector<int>L(N);
    for(int i=0;i<N;i++){
        cin>>L[i];
    }
    int count=0;
    int now=0;
    if(0<=X){count++;}
    for(int i=0;i<N;i++){
        now+=L[i];
        if(now<=X){count++;}
    }
    cout<<count<<endl;
}