Problem:
Score : 400 points

Problem Statement

Let {\rm comb}(n,r) be the number of ways to choose r objects from among n objects, disregarding order.
From n non-negative integers a_1, a_2, ..., a_n, select two numbers a_i > a_j so that {\rm comb}(a_i,a_j) is maximized.
If there are multiple pairs that maximize the value, any of them is accepted.

Constraints

2 \leq n \leq 10^5

0 \leq a_i \leq 10^9

a_1,a_2,...,a_n are pairwise distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print a_i and a_j that you selected, with a space in between.

Sample Input 1

5
6 9 4 2 11

Sample Output 1

11 6

\rm{comb}(a_i,a_j) for each possible selection is as follows:

\rm{comb}(4,2)=6

\rm{comb}(6,2)=15

\rm{comb}(6,4)=15

\rm{comb}(9,2)=36

\rm{comb}(9,4)=126

\rm{comb}(9,6)=84

\rm{comb}(11,2)=55

\rm{comb}(11,4)=330

\rm{comb}(11,6)=462

\rm{comb}(11,9)=55

Thus, we should print 11 and 6.

Sample Input 2

2
100 0

Sample Output 2

100 0

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
#define rep(i,a,b) for(int i=a;i<b;i++)
#define per(i,b,a) for(int i=b;i>=a;i--)
#define For(i,a,b) for(int i=a;i<=b;i++)
#define Forenska(it,c) for(__typeof((c).begin()) it=(c).begin();it!=(c).end();it++)
#define pb push_back
#define mp make_pair
#define mt make_tuple
#define fi first
#define se second
#define all(x) x.begin(),x.end()
#define sqr(x) ((x)*(x))
#define lowbit(x) ((x)&(-x))
#define GREATER(x) x,vector<x>,greater<x>
#define randIn(L,R) (((LL)rand()*rand())%(R-L)+L)
#define __lcm(a,b) ((a)/__gcd(a,b)*(b))
using namespace std;
typedef long long LL;
typedef pair<int,int> pii;
typedef pair<LL,LL> pLL;
typedef vector<int> vec;
typedef vector<LL> vecL;
typedef vector<pii> vecP;
typedef vector<pLL> vecPL;
typedef vector<string> vecS;
typedef vector<vec> mat;
typedef complex<double> point;
const long double PI=3.14159265358979323846264338327950288419716939937510582097;
const LL INFLL=0x3f3f3f3f3f3f3f3f;
const int INF=0x3f3f3f3f;
const long double EPS=1e-10;
int read()
{
    int x=0;
    char ch=' ';
    bool flag=false;
    while(ch<'0' || ch>'9')
    {
        if(ch=='-')flag=true;
        ch=getchar();
    }
    while(ch>='0' && ch<='9')
    {
        x=(x<<3)+(x<<1)+ch-'0';
        ch=getchar();
    }
    return flag?-x:x;
}
#define int LL
signed main()
{
	int n;
	cin>>n;
	vec a(n);
	rep(i,0,n)cin>>a[i];
	sort(all(a));
	int pos=lower_bound(all(a),a.back()/2)-a.begin();
	if(abs(a.back()-a[pos])<abs(a.back()-a[pos-1]) && pos<a.size()-1)cout<<a.back()<<" "<<a[pos]<<endl;
	else cout<<a.back()<<" "<<a[pos-1]<<endl;
	return 0;
}