Problem:
Score : 400 points

Problem Statement

Takahashi has a string S consisting of lowercase English letters.

Starting with this string, he will produce a new one in the procedure given as follows.

The procedure consists of Q operations. In Operation i (1 \leq i \leq Q), an integer T_i is provided, which means the following:

If T_i = 1: reverse the string S.

If T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.

If F_i = 1 : Add C_i to the beginning of the string S.

If F_i = 2 : Add C_i to the end of the string S.

Help Takahashi by finding the final string that results from the procedure.

Constraints

1 \leq |S| \leq 10^5

S consists of lowercase English letters.

1 \leq Q \leq 2 \times 10^5

T_i = 1 or 2.

F_i = 1 or 2, if provided.

C_i is a lowercase English letter, if provided.

Input

Input is given from Standard Input in the following format:

S
Q
Query_1
:
Query_Q

In the 3-rd through the (Q+2)-th lines, Query_i is one of the following:

1

which means T_i = 1, and:

2 F_i C_i

which means T_i = 2.

Output

Print the resulting string.

Sample Input 1

a
4
2 1 p
1
2 2 c
1

Sample Output 1

cpa

There will be Q = 4 operations. Initially, S is a.

Operation 1: Add p at the beginning of S. S becomes pa.

Operation 2: Reverse S. S becomes ap.

Operation 3: Add c at the end of S. S becomes apc.

Operation 4: Reverse S. S becomes cpa.

Thus, the resulting string is cpa.

Sample Input 2

a
6
2 2 a
2 1 b
1
2 2 c
1
1

Sample Output 2

aabc

There will be Q = 6 operations. Initially, S is a.

Operation 1: S becomes aa.

Operation 2: S becomes baa.

Operation 3: S becomes aab.

Operation 4: S becomes aabc.

Operation 5: S becomes cbaa.

Operation 6: S becomes aabc.

Thus, the resulting string is aabc.

Sample Input 3

y
1
2 1 x

Sample Output 3

xy

Solution in C++14 (GCC 5.4.1) (judge verdict: Time Limit Exceeded)

#include<bits/stdc++.h>
using namespace std;
#define ll long long int
#define pb push_back
#define mp make_pair
#define vi vector<int>
#define vl vaector<long>
#define vll vector<long long int>
#define vC  vector<char>
#define FastIO ios::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);
#define db(...) ZZ(#__VA_ARGS__, __VA_ARGS__)
ll pow(ll x, ll y,ll m) { ll res = 1;x=x%m; while (y > 0) { if (y & 1) res = ((res%m) * (x%m))%m; y = y >> 1; x = ((x%m) * (x%m))%m; } return res%m; }
template <typename Arg1> void ZZ(const char* name, Arg1&& arg1){std::cerr << name << " = " << arg1 << endl;}
template <typename Arg1, typename... Args>void ZZ(const char* names, Arg1&& arg1, Args&&... args)
{
    const char* comma = strchr(names + 1, ',');
    std::cerr.write(names, comma - names) << " = " << arg1;
    ZZ(comma, args...);
}
const ll INF = 0xFFFFFFFFFFFFFFFL;
clock_t time_p=clock();
void abhigyan10()
{time_p=clock()-time_p;cerr<<"Time Taken : "<<(float)(time_p)/CLOCKS_PER_SEC<<"\n";}
ll seed;
mt19937 rng(seed=chrono::steady_clock::now().time_since_epoch().count());
inline ll rnd(ll l=0,ll r=INF){return uniform_int_distribution<ll>(l,r)(rng);}
#define clrbuf cin.ignore(numeric_limits<streamsize>::max(),'\n');
#define preciset(x) cout<<setprecision(x)<<fixed;
const ll mod =1000000007;
int main()
{
   
        FastIO
        string s,temp="";
        int q,i,flag=1,f,z;
        cin>>s;
        cin>>q;
        char c;
        while(q--)
        {
            cin>>z;
            if(z==1)
            {
                flag*=-1;
            }
            else
            {
                cin>>f>>c;
                if(f==1)
                {
                    if(flag==1)
                        {
                            temp=c;
                            temp+=s;
                            swap(s,temp);


                        }
                        else
                        {
                            s+=c;
                        }
                }
                else
                {
                    if(flag==1)
                    s+=c;
                else
                {
                            temp=c;
                            temp+=s;
                            swap(s,temp);                }

                }
        }
       }
       if(flag==1)
        cout<<s;
        else
        {
            reverse(s.begin(),s.end());
            cout<<s;
        }
        return 0;
    }