Problem:
Score : 400 points

Problem Statement

Let {\rm comb}(n,r) be the number of ways to choose r objects from among n objects, disregarding order.
From n non-negative integers a_1, a_2, ..., a_n, select two numbers a_i > a_j so that {\rm comb}(a_i,a_j) is maximized.
If there are multiple pairs that maximize the value, any of them is accepted.

Constraints

2 \leq n \leq 10^5

0 \leq a_i \leq 10^9

a_1,a_2,...,a_n are pairwise distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print a_i and a_j that you selected, with a space in between.

Sample Input 1

5
6 9 4 2 11

Sample Output 1

11 6

\rm{comb}(a_i,a_j) for each possible selection is as follows:

\rm{comb}(4,2)=6

\rm{comb}(6,2)=15

\rm{comb}(6,4)=15

\rm{comb}(9,2)=36

\rm{comb}(9,4)=126

\rm{comb}(9,6)=84

\rm{comb}(11,2)=55

\rm{comb}(11,4)=330

\rm{comb}(11,6)=462

\rm{comb}(11,9)=55

Thus, we should print 11 and 6.

Sample Input 2

2
100 0

Sample Output 2

100 0

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
#define rep(i,a) for(int i=0;i<int(a);++i)
#define REP(i,a,b) for(int i=int(a);i<int(b);++i)
#define pb push_back
#define mp make_pair
#define F first
#define S second
using ll = long long;
using itn = int;
using namespace std;
static const long double GRATIO=(long double)(1+sqrt(5))/2;
ll GCD(ll a, ll b){
    return b ? GCD(b, a%b) : a;
}
ll LCM(ll a, ll b){
    return a/GCD(a,b)*b;
}
void calc_comb(vector<vector<long long>> &v){
    rep(i,v.size()){
        v[i][0]=1;
        v[i][i]=1;
    }
    for(int i=1; i<v.size(); i++){
        for(int j=1; j<i; j++){
            v[i][j]=(v[i-1][j-1]+v[i-1][j]);
        }
    }
}
int main(){
    int n;
    cin>>n;
    vector<int> a(n);
    rep(i,n) cin>>a[i];
    sort(a.begin(),a.end());
    ll ans=a[0];
    for(int i=0; i<n-1; i++){
        if(a[i]<=(a[n-1]+1)/2) ans=a[i];
    }
    //cout<<v[a[n-1]][a[2]]<<endl;
    cout<<a[n-1]<<" "<<ans<<endl;
}