Problem:
Score : 100 points

Problem Statement

You are given positive integers A and B.

If A is a divisor of B, print A + B; otherwise, print B - A.

Constraints

All values in input are integers.

1 \leq A \leq B \leq 20

Input

Input is given from Standard Input in the following format:

A B

Output

If A is a divisor of B, print A + B; otherwise, print B - A.

Sample Input 1

4 12

Sample Output 1

16

As 4 is a divisor of 12, 4 + 12 = 16 should be printed.

Sample Input 2

8 20

Sample Output 2

12

Sample Input 3

1 1

Sample Output 3

2

1 is a divisor of 1.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <algorithm>
#include <cstdio>
#include <cmath>
#include <vector>
#include <map>
#include <set>
#include <string>
#include <stack> // s.top()
#include <bitset>
#include <queue> // s.front()
using namespace std;

typedef long long Int;
typedef pair<Int,Int> P;
#define print(x) cout<<(x)<<endl

#define INF10 10000000000
#define INF5 100000
#define EPS 1e-10
#define MOD 1000000007


int main() {
	int	a, b; cin >> a >> b;
	if (b%a == 0)print(a + b);
	else print(b - a);





	return 0;
}