Problem:
Score: 100 points

Problem Statement

M-kun is a competitor in AtCoder, whose highest rating is X.

In this site, a competitor is given a kyu (class) according to his/her highest rating. For ratings from 400 through 1999, the following kyus are given:

From 400 through 599: 8-kyu

From 600 through 799: 7-kyu

From 800 through 999: 6-kyu

From 1000 through 1199: 5-kyu

From 1200 through 1399: 4-kyu

From 1400 through 1599: 3-kyu

From 1600 through 1799: 2-kyu

From 1800 through 1999: 1-kyu

What kyu does M-kun have?

Constraints

400 \leq X \leq 1999

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print the kyu M-kun has, as an integer.
For example, if he has 8-kyu, print 8.

Sample Input 1

725

Sample Output 1

7

M-kun's highest rating is 725, which corresponds to 7-kyu.

Thus, 7 is the correct output.

Sample Input 2

1600

Sample Output 2

2

M-kun's highest rating is 1600, which corresponds to 2-kyu.

Thus, 2 is the correct output.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>

using namespace std;
typedef long long ll;
typedef pair<ll, ll> P;
using pll = pair<ll, ll>;
using vl = vector<ll>;
using vll = vector<vl>;
using vpll = vector<pll>;
struct Edge {
	ll to;
	ll cost;
};
using Graph = vector<vector<Edge>>;

#define FOR(i, a, b) for (ll i = (a); i < (b); i++)
#define REP(i, n) FOR(i, 0, n)
#define ALL(a) (a).begin(), (a).end()
#define RES(a, n) (a).resize(n)
#define VLCIN(a, n) REP(i,n){cin >> a[i];}
/***** define constant start *******/
const ll MOD = 1000000007;
const double PI = 2.0 * asin(1.0);
const ll INF = 1L<<60;
string abc = "abcdefghijklmnopqrstuvwxyz";
string ABC = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
const ll MAX = (ll)pow(10,7);
/****** define constant end ********/
/****** define variable start ******/
ll x;
/******* define variable end *******/
int solve() {
	cin >> x;
	if(x <= 599) cout << 8 << endl;
	else if(x <= 799) cout << 7 << endl;
	else if(x <= 999) cout << 6 << endl;
	else if(x <= 1199) cout << 5 << endl;
	else if(x <= 1399) cout << 4 << endl;
	else if(x <= 1599) cout << 3 << endl;
	else if(x <= 1799) cout << 2 << endl;
	else cout << 1 << endl;
	return 0;
}
int main() {
	// clock_t start = clock();
	cout << std::fixed << std::setprecision(10);
	ios::sync_with_stdio(false);
	cin.tie(nullptr);
	int end_solve = solve();
	/*
	clock_t end = clock();
	const double time = static_cast<double>(end - start) / CLOCKS_PER_SEC *
	1000.0; printf("time %lf[ms]\n", time);
	*/

	return end_solve;
}