Problem:
Score : 200 points

Problem Statement

You are given a string S. Each character of S is uppercase or lowercase English letter.
Determine if S satisfies all of the following conditions:

The initial character of S is an uppercase A.

There is exactly one occurrence of C between the third character from the beginning and the second to last character (inclusive).

All letters except the A and C mentioned above are lowercase.

Constraints

4 ≤ |S| ≤ 10 (|S| is the length of the string S.)

Each character of S is uppercase or lowercase English letter.

Input

Input is given from Standard Input in the following format:

S

Output

If S satisfies all of the conditions in the problem statement, print AC; otherwise, print WA.

Sample Input 1

AtCoder

Sample Output 1

AC

The first letter is A, the third letter is C and the remaining letters are all lowercase, so all the conditions are satisfied.

Sample Input 2

ACoder

Sample Output 2

WA

The second letter should not be C.

Sample Input 3

AcycliC

Sample Output 3

WA

The last letter should not be C, either.

Sample Input 4

AtCoCo

Sample Output 4

WA

There should not be two or more occurrences of C.

Sample Input 5

Atcoder

Sample Output 5

WA

The number of C should not be zero, either.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#define _GLIBCXX_DEBUG
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
typedef vector<int> vi;
typedef vector<bool> vb;
#define pb push_back
#define mp make_pair
#define f first
#define s second
#define in insert
#define FOR(i,a,b) for (int i = a; i < b; i++)
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define speed ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
const int INF = 1e9 + 5;
int main(){
    string s;
    cin >> s;
    for(int i = 0; i < s.size(); i++) if(s[i] >= 'A' && s[i] <= 'Z'){
        if(s[i] != 'C' && s[i] != 'A') {
            cout << "WA";
        return 0;
        }
    }
    if(s[0] == 'A'){
        int cnt = 0;
        if(s[1] != 'C' && s[s.size()-1] != 'C'){
        for(int i = 2; i < s.size()-1; i++) {
            if(s[i] == 'C') cnt++;
            if(s[i] >= 'A' && s[i] <= 'Z' && s[i] != 'A' && s[i] != 'C'){
                cout << "WA";
                return 0;
            }
        }
        if(cnt == 1) cout << "AC";
        else cout << "WA";
        }
        else cout << "WA";
    }
    else cout << "WA";
}