Problem:
Score : 100 points

Problem Statement

Snuke lives at position x on a number line.
On this line, there are two stores A and B, respectively at position a and b, that offer food for delivery.

Snuke decided to get food delivery from the closer of stores A and B.
Find out which store is closer to Snuke's residence.

Here, the distance between two points s and t on a number line is represented by |s-t|.

Constraints

1 \leq x \leq 1000

1 \leq a \leq 1000

1 \leq b \leq 1000

x, a and b are pairwise distinct.

The distances between Snuke's residence and stores A and B are different.

Input

Input is given from Standard Input in the following format:

x a b

Output

If store A is closer, print A; if store B is closer, print B.

Sample Input 1

5 2 7

Sample Output 1

B

The distances between Snuke's residence and stores A and B are 3 and 2, respectively.
Since store B is closer, print B.

Sample Input 2

1 999 1000

Sample Output 2

A

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<iostream>
#include<vector>
#include<map>
#include<algorithm>
#include<math.h>
#include<string>
#include <iomanip>
#include<deque>

typedef long long ll;
typedef unsigned long long ull;
typedef int itn;
const ll LINF = 1e18;
const int INF = 1e8;

using namespace std;


//マクロ定義
#define vvint(vec,n,m,l) vector<vector<int>> vec(n, vector<int>(m,l));	// lで初期化
#define vvll(vec,n,m,l) vector<vector<ll>> vec(n,vector<ll>(m,l));
#define vint vector<int>
#define pint pair<int,int>
#define rep(i,a) for(int i=0;i<(a);i++)
#define all(x) (x).begin(),(x).end()
#define debug system("pause")				//デバッグ用


int main(void)
{
	cin.tie(0);
	ios::sync_with_stdio(false);
	
	int x, a, b;
	cin >> x >> a >> b;
	if (abs(x - a) > abs(x - b))
	{
		cout << "B";
	}
	else
	{
		cout << "A";
	}
	cout << endl;


}