Problem:
Score : 200 points

Problem Statement

An integer X is called a Harshad number if X is divisible by f(X), where f(X) is the sum of the digits in X when written in base 10.

Given an integer N, determine whether it is a Harshad number.

Constraints

1?N?10^8

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

Print Yes if N is a Harshad number; print No otherwise.

Sample Input 1

12

Sample Output 1

Yes

f(12)=1+2=3. Since 12 is divisible by 3, 12 is a Harshad number.

Sample Input 2

57

Sample Output 2

No

f(57)=5+7=12. Since 57 is not divisible by 12, 12 is not a Harshad number.

Sample Input 3

148

Sample Output 3

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
#define For(i,n,k) for(int i=(n);i<(k);i++)
#define ALL(a)  (a).begin(),(a).end()
ll ans=0;
void Main(){
    int x;
    cin >> x;
    int f=0,y=x;
    while(x){
        f+=x%10;
        x/=10;
    }
    if(y%f==0) cout << "Yes" << endl;
    else cout << "No" << endl;
}
int main(){
    Main();
    /*
    東方風神録は神が出てくるので当然神ゲー
    */
    return 0;
}