Problem:
Score : 100 points

Problem Statement

An elementary school student Takahashi has come to a variety store.

He has two coins, A-yen and B-yen coins (yen is the currency of Japan), and wants to buy a toy that costs C yen. Can he buy it?

Note that he lives in Takahashi Kingdom, and may have coins that do not exist in Japan.

Constraints

All input values are integers.

1 \leq A, B \leq 500

1 \leq C \leq 1000

Input

Input is given from Standard Input in the following format:

A B C

Output

If Takahashi can buy the toy, print Yes; if he cannot, print No.

Sample Input 1

50 100 120

Sample Output 1

Yes

He has 50 + 100 = 150 yen, so he can buy the 120-yen toy.

Sample Input 2

500 100 1000

Sample Output 2

No

He has 500 + 100 = 600 yen, but he cannot buy the 1000-yen toy.

Sample Input 3

19 123 143

Sample Output 3

No

There are 19-yen and 123-yen coins in Takahashi Kingdom, which are rather hard to use.

Sample Input 4

19 123 142

Sample Output 4

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define vsort(vec) sort(vec.begin(), vec.end())
#define vreverse(vec) reverse(vec.begin(), vec.end())
using ll =long long;
const ll INF =999999999;

//最大公約数
ll gcd(ll a, ll b){
   if (a%b==0){
       return(b);
   }else{
       return(gcd(b,a%b));
   }
}
//最小公倍数
ll lcm(ll a, ll b){
   return a*b/gcd(a,b);
}

//素数判定
ll isprime(ll n){
  bool prime=true;
  for(int i=2;i<n;i++){
    if(n%i==0){
      prime=false; break;
    }
  }
if(prime){cout<<n<<" is prime"<<endl;
         }else{cout<<n<<" is not prime"<<endl;}

}
//階乗　20くらいが限界
ll factorial(ll n){
  ll a=1;ll b=n;
  for(int i=0;i<n;i++){
    a*=b;
    b--;
  }
  return a;
}

//組み合わせ　nCr
ll comb(ll a,ll b){
  ll c;
  c=factorial(a)/(factorial(a-b)*factorial(b));
  return c; 
}




//10億7。　　　100000007
//2*2行列 H*W
//vector<vector<int>> vec(H,vector<int>(W));
//for(int i=0;i<H;i++){
//for(int j=0;j<W;j++){
//cin>>vec[i][j];
//  }
//}

//文字列→数列
//string S;int A=atoi(S.c_str());
//数列→文字列
//int A;string S=to_string(A);
//数字判定　isdigit(a)
//pair宣言　pair<int,int> p(5,7);
//ソート　sort(vec.begin(),vec.end());



int main(){
cout<<fixed<<setprecision(10);

int A,B,C;
  cin>>A>>B>>C;
  if(A+B>=C){
    cout<<"Yes"<<endl;
  }else{cout<<"No"<<endl;
       }
  
  
  
  
  
  
  
  
}