Problem:
Score: 300 points

Problem Statement

M-kun is a student in Aoki High School, where a year is divided into N terms.

There is an exam at the end of each term. According to the scores in those exams, a student is given a grade for each term, as follows:

For the first through (K-1)-th terms: not given.

For each of the K-th through N-th terms: the multiplication of the scores in the last K exams, including the exam in the graded term.

M-kun scored A_i in the exam at the end of the i-th term.

For each i such that K+1 \leq i \leq N, determine whether his grade for the i-th term is strictly greater than the grade for the (i-1)-th term.

Constraints

2 \leq N \leq 200000

1 \leq K \leq N-1

1 \leq A_i \leq 10^{9}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
A_1 A_2 A_3 \ldots A_N

Output

Print the answer in N-K lines.

The i-th line should contain Yes if the grade for the (K+i)-th term is greater than the grade for the (K+i-1)-th term, and No otherwise.

Sample Input 1

5 3
96 98 95 100 20

Sample Output 1

Yes
No

His grade for each term is computed as follows:

3-rd term: (96 \times 98 \times 95) = 893760

4-th term: (98 \times 95 \times 100) = 931000

5-th term: (95 \times 100 \times 20) = 190000

Sample Input 2

3 2
1001 869120 1001

Sample Output 2

No

Note that the output should be No if the grade for the 3-rd term is equal to the grade for the 2-nd term.

Sample Input 3

15 7
3 1 4 1 5 9 2 6 5 3 5 8 9 7 9

Sample Output 3

Yes
Yes
No
Yes
Yes
No
Yes
Yes

Solution in C++ (Clang 10.0.0) (judge verdict: Runtime Error)

/* 
 * Project: M-SOLUTIONS プロコンオープン 2020 C - Marks
 * Author: toms74209200 <https://github.com/toms74209200>
 *
 * Created on 2020/07/25
 * Copyright (c) 2020 toms74209200
 * 
 * This software is released under the MIT License.
 * http://opensource.org/licenses/mit-license.php
 */
#include <cstdio>
#include <cmath>
#include <vector>
#include <algorithm>
using namespace std;

int n;
int k;
int a[20000];

void solve() {

    for (int i=k;i<n;i++) {
        if (a[i-k] < a[i])
            printf("Yes\n");
        else
            printf("No\n");
    }
}

int main() {

    scanf("%d", &n);
    scanf("%d", &k);
    for (int i=0;i<n;i++) {
        scanf("%d", &a[i]);
    }

    solve();
}