Problem:
Score: 300 points

Problem Statement

We have N voting papers. The i-th vote (1 \leq i \leq N) has the string S_i written on it.

Print all strings that are written on the most number of votes, in lexicographical order.

Constraints

1 \leq N \leq 2 \times 10^5

S_i (1 \leq i \leq N) are strings consisting of lowercase English letters.

The length of S_i (1 \leq i \leq N) is between 1 and 10 (inclusive).

Input

Input is given from Standard Input in the following format:

N
S_1
:
S_N

Output

Print all strings in question in lexicographical order.

Sample Input 1

7
beat
vet
beet
bed
vet
bet
beet

Sample Output 1

beet
vet

beet and vet are written on two sheets each, while beat, bed, and bet are written on one vote each. Thus, we should print the strings beet and vet.

Sample Input 2

8
buffalo
buffalo
buffalo
buffalo
buffalo
buffalo
buffalo
buffalo

Sample Output 2

buffalo

Sample Input 3

7
bass
bass
kick
kick
bass
kick
kick

Sample Output 3

kick

Sample Input 4

4
ushi
tapu
nichia
kun

Sample Output 4

kun
nichia
tapu
ushi

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

/* 実行時間1s制限の場合
  10^6 1,000,000   : 余裕をもって間に合う
  10^7 10,000,000  : おそらく間に合う
  10^8 100,000,000 : 非常にシンプルな処理でないと厳しい
 */
#define rep(i, n) for(int i = 0; i < (int)n; i++)
#define repi(i,a,b) for(int i=int(a);i<int(b);++i)
#include <bits/stdc++.h>
using namespace std;

typedef long long ll; // long longはデータモデル(LLP64, LP64, ...)によらず64bit.
ll gcd(ll a, ll b) {return b ? gcd(b, a%b) : a;}  // Greatest Common Divisor ユークリッドの互除法（aが長辺）
vector<pair<ll,int>> factorize(ll n) {            // a,bの公約数 = GCD(a, b)の約数
    vector<pair<ll,int>> res;
    for (ll i = 2; i*i <= n; i++) { // √nまで探せばよい
        if (n%i) continue;
        res.emplace_back(i, 0);     // 割り切れたら
        while (n%i == 0) {
            n /= i;
            res.back().second++;
        }
    }
    if (n != 1) res.emplace_back(n, 1); // この時点で1でなかったら、残りは素数.
    return res;
}
ll lcm(ll a, ll b) {return a/gcd(a,b)*b;}         // Least Commont Multiple オーバーフローしないように先に割る
ll ceil(ll a, ll b) {return (a+b-1)/b;}

const ll INF = LONG_MAX;
template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }

int main(int argc, char* argv[])
{
#ifdef LOCAL
    // 以降 cin の入力元が 'xxx.txt' になる
    // std::ifstream in(argv[1]);
    //std::cin.rdbuf(in.rdbuf());
    std::ifstream in(string(argv[0]) + ".txt");
    std::cin.rdbuf(in.rdbuf());
#endif

    int n;
    cin >> n;

    map<string, int> poll;

    rep(i, n) {
        string s;
        cin >> s;
        poll[s]++;
    }

    int m = 0;
    for (auto i = poll.begin(); i != poll.end(); i++) {
        m = max(m, i->second);
    }
    for (auto i = poll.begin(); i != poll.end(); i++) {
        if (m == i->second) cout << i->first << endl;
    }

    return 0;
}

/*
  - 1e9 : 10^9
  - container一般
    - 合計
      accumulate(a.begin(), a.end(), 0LL)  0LLはオーバーフロー用
  - vector
    vector<int> A(N, 0); // 0で初期化(省略可)
    - loop
      for  (int i = 0; i < A.size(); i++) {}
      for  (int elem : A) {}
    - sort
      std::sort(v.begin(), v.end());  // 昇順
      std::sort(v.begin(), v.end(), std::greater<int>()); //降順
      - vector<vector<int>> cnt(h, vector<int>(w))
    - sort(struct)
        struct st_t {
            string name;
            int p;
            bool operator<(const st_t& another) const {
                if (name == another.name)
                {
                    return p > another.p;
                }
                return name < another.name;
            }
        };
        vector<st_t> st(n);
        sort(st.begin(), st.end());
  - pair
    - pairのソートの定義 : firstが優先的に比較。同じだったらsecond。
    - pair<pair<string,int>,int> p[110];
      std::sort(p,p+a);
        こうすると、first.first -> first.second -> secondの順にソートされる
    - sort
      - sort(a.begin(), cb.end(), greater<pair<int, int>>());
  - map
    - for (auto x : map) {}  // x.first:key  x.second:value.
  - priority_queue<int> q;
    - q.top()に最大値が入っている
  - string
    - loop
      for (char& c : s) {}
 */