Problem:
Score : 200 points

Problem Statement

Find the number of palindromic numbers among the integers between A and B (inclusive).
Here, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.

Constraints

10000 \leq A \leq B \leq 99999

All input values are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the number of palindromic numbers among the integers between A and B (inclusive).

Sample Input 1

11009 11332

Sample Output 1

4

There are four integers that satisfy the conditions: 11011, 11111, 11211 and 11311.

Sample Input 2

31415 92653

Sample Output 2

612

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <string.h>

int eh_pali(int x){

    char str[10];
    sprintf(str, "%d", x);

    return ((str[0] == str[4]) && (str[1]== str[3]));

}

int main(){

    int a, b, total = 0;
    scanf("%d%d", &a, &b );
    for (int i = a; i < b; i++) {
        if (eh_pali(i)) {
            ++total;
        }
    }

    printf("%d\n", total );
    return 0;
}