Problem:
Score : 200 points

Problem Statement

You are given string S and T consisting of lowercase English letters.

Determine if S equals T after rotation.

That is, determine if S equals T after the following operation is performed some number of times:

Operation: Let S = S_1 S_2 ... S_{|S|}. Change S to S_{|S|} S_1 S_2 ... S_{|S|-1}.

Here, |X| denotes the length of the string X.

Constraints

2 \leq |S| \leq 100

|S| = |T|

S and T consist of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S equals T after rotation, print Yes; if it does not, print No.

Sample Input 1

kyoto
tokyo

Sample Output 1

Yes

In the first operation, kyoto becomes okyot.

In the second operation, okyot becomes tokyo.

Sample Input 2

abc
arc

Sample Output 2

No

abc does not equal arc after any number of operations.

Sample Input 3

aaaaaaaaaaaaaaab
aaaaaaaaaaaaaaab

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <vector>
#include <algorithm>
#include <cmath>
#include <numeric>  // min, max
#include <fstream>  // ifstream
#include <iomanip>  // setprecision
using namespace std;
typedef long long ll;

int main(void)
{
#ifdef FILE_DEBUG
    ifstream inputFile("data/input.txt");
    cin.rdbuf(inputFile.rdbuf());
#endif
    // これより下にコードを書く

    string S, T;
    cin >> S >> T;

    for (int i = 0; (i < S.size()); ++i) {
        char init = S[0];
        for (int j = 1; (j < S.size()); ++j) {
            S[j-1] = S[j];
        }
        S[S.size()-1] = init;
        if (S == T) {
            cout << "Yes" << endl;
            return 0;
        }
    }

    cout << "No" << endl;
    return 0;
}