Problem:
Score : 200 points

Problem Statement

A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.

How many times will the ball make a bounce where the coordinate is at most X?

Constraints

1 \leq N \leq 100

1 \leq L_i \leq 100

1 \leq X \leq 10000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N X
L_1 L_2 ... L_{N-1} L_N

Output

Print the number of times the ball will make a bounce where the coordinate is at most X.

Sample Input 1

3 6
3 4 5

Sample Output 1

2

The ball will make a bounce at the coordinates 0, 3, 7 and 12, among which two are less than or equal to 6.

Sample Input 2

4 9
3 3 3 3

Sample Output 2

4

The ball will make a bounce at the coordinates 0, 3, 6, 9 and 12, among which four are less than or equal to 9.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <vector>
#include <cmath>
#include <queue>

#define endl '\n'
#define fi first
#define se second
#define pb push_back
#define debug(x) cout << "[debug] " << #x << ": " << x << endl
using namespace std;
typedef long long ll;
typedef pair<int, int> PII;
const int MOD = 1e9 + 7;
const int maxn = 1e6 + 5;
const int inf = 0x3f3f3f3f;
const ll INF = 0x3f3f3f3f3f3f3f3f;
const double eps = 1e-8;

int main() {
    int n, x; cin >> n >> x;
    vector<int> nums;
    nums.push_back(0);
    for(int i = 1; i <= n; ++i){
        int x; cin >> x;
        nums.push_back(nums[i - 1] + x);
    }
    int ans = 0;
    for(int i = 0; i <= n; ++i){
        if(nums[i] > x) {ans = i; break;}
    }
    if(ans == 0) cout << n + 1 << endl;
    else cout << ans << endl;
	return 0;
}