Problem:
Score : 100 points

Problem Statement

Takahashi is participating in a programming contest, AXC001. He has just submitted his code to Problem A.

The problem has N test cases, all of which must be passed to get an AC verdict.

Takahashi's submission has passed M cases out of the N test cases.

Determine whether Takahashi's submission gets an AC.

Constraints

1 \leq N \leq 100

0 \leq M \leq N

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M

Output

If Takahashi's submission gets an AC, print Yes; otherwise, print No.

Sample Input 1

3 3

Sample Output 1

Yes

All three test cases have been passed, so his submission gets an AC.

Sample Input 2

3 2

Sample Output 2

No

Only two out of the three test cases have been passed, so his submission does not get an AC.

Sample Input 3

1 1

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <algorithm>
#include <deque>
#include <iomanip>
#include <iostream>
#include <map>
#include <numeric>
#include <queue>
#include <set>
#include <stack>
#include <string>
#include <tuple>
#include <vector>

using namespace std;

typedef long long ll;
// constexpr ll MOD = 998244353;
constexpr ll MOD = 1000000007;

// struct UnionFind {
//     vector<int> par;
    
//     UnionFind(int N): par(N) {
//         for (int i=0;i<N;i++) par[i] = i;
//     }

//     int root(int x) {
//         if (par[x] == x) return x;
//         else return par[x] = root(par[x]);
//     }

//     void unite(int x, int y) {
//         int rx = root(x);
//         int ry = root(y);
//         if (rx == ry) return;
//         par[rx] = ry;
//     }

//     bool same(int x, int y) {
//         int rx = root(x);
//         int ry = root(y);
//         return rx == ry;
//     }
// };

int main(void) {
    int N, M;
    cin >> N >> M;
    if (N == M) cout << "Yes" << endl;
    else cout << "No" << endl;

    return 0;
}