Problem:
Score : 200 points

Problem Statement

Takahashi's house has only one socket.

Takahashi wants to extend it with some number of power strips, each with A sockets, into B or more empty sockets.

One power strip with A sockets can extend one empty socket into A empty sockets.

Find the minimum number of power strips required.

Constraints

All values in input are integers.

2 \leq A \leq 20

1 \leq B \leq 20

Input

Input is given from Standard Input in the following format:

A B

Output

Print the minimum number of power strips required.

Sample Input 1

4 10

Sample Output 1

3

3 power strips, each with 4 sockets, extend the socket into 10 empty sockets.

Sample Input 2

8 9

Sample Output 2

2

2 power strips, each with 8 sockets, extend the socket into 15 empty sockets.

Sample Input 3

8 8

Sample Output 3

1

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <vector>
#include <string>
#include <algorithm>
#include <stdio.h>
#include <map>
#include <set>
#include <utility>
#include <queue>
#include <bitset>
#include <math.h>
#include <numeric>
#include <stack>

using namespace std;
 
#define rep(i,m,n) for(int i=m;i<(int)(n);i++)
#define endl '\n'
typedef long long ll;

int main(){
    ios::sync_with_stdio(false);
    cin.tie(0);
    int a,b;
    cin>>a>>b;
    int res=1;
    int t=a;
    if(b==1){
        cout<<0<<endl;
        return 0;
    }
    while(1){
        if(a >= b)break;
        res++;
        a+=t-1;
    }
    cout<<res<<endl;
}