Problem:
Score : 400 points

Problem Statement

There are N one-off jobs available. If you take the i-th job and complete it, you will earn the reward of B_i after A_i days from the day you do it.

You can take and complete at most one of these jobs in a day.

However, you cannot retake a job that you have already done.

Find the maximum total reward that you can earn no later than M days from today.

You can already start working today.

Constraints

All values in input are integers.

1 \leq N \leq 10^5

1 \leq M \leq 10^5

1 \leq A_i \leq 10^5

1 \leq B_i \leq 10^4

Input

Input is given from Standard Input in the following format:

N M
A_1 B_1
A_2 B_2
\vdots
A_N B_N

Output

Print the maximum total reward that you can earn no later than M days from today.

Sample Input 1

3 4
4 3
4 1
2 2

Sample Output 1

5

You can earn the total reward of 5 by taking the jobs as follows:

Take and complete the first job today. You will earn the reward of 3 after four days from today.

Take and complete the third job tomorrow. You will earn the reward of 2 after two days from tomorrow, that is, after three days from today.

Sample Input 2

5 3
1 2
1 3
1 4
2 1
2 3

Sample Output 2

10

Sample Input 3

1 1
2 1

Sample Output 3

0

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

//#include "SaveFuncs.cpp"

#include <iostream>
#include <array>
#include <vector>
#include <algorithm>
#include <string>
#include <cmath>
#include <queue>
#include <stack>
#include <map>
#include <iomanip>	//cout << fixed << setprecision(桁数);
#include <stdexcept>

using namespace std;
using ll = long long;

#define rep(i, n) for(int i=0, i##_len=(n); i<i##_len; i++)
#define rep1(i, n) for(int i=1, i##_len=(n); i<i##_len; i++)
#define rrep(i, n) for(int i=(n)-1; i >= 0; i--)
#define rrep1(i, n) for(int i=(n); i > 0; i--)
#define all(x) (x).begin(), (x).end()
#define pair(a, b) make_pair(a, b);
//#define int long long
constexpr int INF = 2000000100;
constexpr int DIV = 1000000007;	// 10e9+7
template<class T> bool chmax(T& a, T b) { if (a < b) { a = b; return true; } return false; }
template<class T> bool chmin(T& a, T b) { if (a > b) { a = b; return true; } return false; }
template<class T> T divUp(T a, T b) { if (a % b == 0) { return a / b; } return a / b + 1; }
std::string strMulti(std::string t, int n) { std::string out = ""; for (int i = 0; i < n; i++) { out += t; } return out; }
template<class T> T math_P(T m, T n) { T ret = 1; for (T i = m; i > m - n; i--) { ret *= i; } return ret; }
template<class T> T math_C(T m, T n) { T ret = mathP(m, n); for (T i = 2; i <= n; i++) { ret /= i; } return ret; }
bool compare_by_b(pair<int, int> a, pair<int, int> b) { if (a.second != b.second) { return a.second < b.second; } return a.first < b.first; }

/*****/

int Main()
{
	int N, M;
	cin >> N >> M;
	vector<pair<int, int>> A(N);
	rep(i, N)
	{
		int a, b;
		cin >> a >> b;
		A.at(i) = pair(a, b);
	}

	sort(all(A), compare_by_b);
	reverse(all(A));

	int ret = 0;
	int today = 0;
	for (int i = 0; i < N; i++)
	{
		if (today + A.at(i).first <= M)
		{
			ret += A.at(i).second;
			today++;
		}
	}

	cout << ret << endl;

	return 0;
}

/*****/

int main()
{
	std::ios::sync_with_stdio(false);
	std::cin.tie(0);

	Main();

	return 0;
}