Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<iostream>
#include<cstdlib>
#include<string>
#include<vector>
#include<map>
#include<unordered_map>
#include<queue>
#include<algorithm>
#include<iomanip>
#include<typeinfo>
#include<complex>
using namespace std;
using ll = long long int;
const int mod = 1e9 + 7;
#define rep(i, a, b) for(ll i = a;i < b; i++)

int main() {

	int s;
	cin >> s;

	int ans = 0;

	int l, r;
	l = s / 100;
	r = s % 100;

	if (l > 13) ans += 1;
	if (r > 13) ans += 2;
	if (l == 0 || r == 0) ans = -1;

	if (ans == -1 || ans == 3) cout << "NA" << endl;
	else if (ans == 2) cout << "MMYY" << endl;
	else if (ans == 1) cout << "YYMM" << endl;
	else cout << "AMBIGUOUS" << endl;

	return 0;
}