Problem:
Score : 100 points

Problem Statement

You are given positive integers A and B.

If A is a divisor of B, print A + B; otherwise, print B - A.

Constraints

All values in input are integers.

1 \leq A \leq B \leq 20

Input

Input is given from Standard Input in the following format:

A B

Output

If A is a divisor of B, print A + B; otherwise, print B - A.

Sample Input 1

4 12

Sample Output 1

16

As 4 is a divisor of 12, 4 + 12 = 16 should be printed.

Sample Input 2

8 20

Sample Output 2

12

Sample Input 3

1 1

Sample Output 3

2

1 is a divisor of 1.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
// statics
using namespace std;
using int64 = int_fast64_t;
using PAIR = pair<int64, int64>;
constexpr int INF = 1 << 30;
constexpr int64 LINF = 1LL << 60;
constexpr int MOD = 1e9 + 7;
constexpr int MAX_N = 3e5 + 1;

// init/input
#define int int64
#define INIT ios::sync_with_stdio(false);cin.tie(0);
#define VAR(type, ...) type __VA_ARGS__;MACRO_VAR_Scan(__VA_ARGS__);
template<typename T> void MACRO_VAR_Scan(T &t) {cin>>t;}
template<typename First, typename...Rest> void MACRO_VAR_Scan(First &first, Rest&...rest) {cin>>first;MACRO_VAR_Scan(rest...);}
#define VEC(type, c, n) vector<type> c(n);for(auto &&i:c)cin>>i;

// out
#define OUT(dist) cout<<(dist);
#define FOUT(n, dist) cout<<fixed<<setprecision(n)<<(dist);
#define SP cout<<" ";
#define BR cout<<endl;
#define zero(n) cout<<setfill('0')<<right<<setw(n)
#define debug(x) cerr<<#x<<":"<< (x);BR;

// utility
#define ALL(a) (a).begin(), (a).end()
#define EACH(i, a) for(auto &&i:(a))
#define FOR(i, a, b) for(int i=(a);i<(b);++i)
#define RFOR(i, a, b) for(int i=(b)-1;i>=0;--i)
#define REP(i, n) for(int i=0;i<(n);++i)
#define RREP(i, n) for(int i=(n)-1;i>=0;--i)

signed main() {
  INIT;
	
  
  return 0;
}