Problem:
Score: 200 points

Problem Statement

We have a string S consisting of lowercase English letters.

If the length of S is at most K, print S without change.

If the length of S exceeds K, extract the first K characters in S, append ... to the end of them, and print the result.

Constraints

K is an integer between 1 and 100 (inclusive).

S is a string consisting of lowercase English letters.

The length of S is between 1 and 100 (inclusive).

Input

Input is given from Standard Input in the following format:

K
S

Output

Print a string as stated in Problem Statement.

Sample Input 1

7
nikoandsolstice

Sample Output 1

nikoand...

nikoandsolstice has a length of 15, which exceeds K=7.

We should extract the first 7 characters in this string, append ... to the end of them, and print the result nikoand....

Sample Input 2

40
ferelibenterhominesidquodvoluntcredunt

Sample Output 2

ferelibenterhominesidquodvoluntcredunt

The famous quote from Gaius Julius Caesar.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
#include<unistd.h>
using namespace std;
#define pb(x) push_back(x);
typedef long long  int ll;
ll mod = 998244353;
ll hmaxii=0;
vector<ll>values[2*100000+1];
ll MAXN = 2*100000+1;
ll spf[2*100000+1];
//vector<ll>values[];
ll diff,x,y,z;
ll flag=1;ll price[1001][1001];

ll gcd(ll a,ll b) { return b?gcd(b,a%b):a; }



void solution(){
    int n;
    cin>>n;
    int temp = n%10;
    string ans;
    cin>>ans;
    if(n>=ans.length()){
        cout<<ans<<endl;
    }
    else{
        ans = ans.substr(0,n);
        ans+="...";
        cout<<ans<<endl;
    }
}


int main()
{
	ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    //sieve();
    /*ll powe[64];
    powe[0]=1;
    ll i=1;
    while(i<64){
        powe[i] = powe[i-1]*2;
        i++;
    }*/
    ll t;
    //cin>>t;
    t=1;
    while(t--){
        solution();
    }
    return 0;
}