Problem:
Score : 200 points

Problem Statement

An integer N is a multiple of 9 if and only if the sum of the digits in the decimal representation of N is a multiple of 9.

Determine whether N is a multiple of 9.

Constraints

0 \leq N < 10^{200000}

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a multiple of 9, print Yes; otherwise, print No.

Sample Input 1

123456789

Sample Output 1

Yes

The sum of these digits is 1+2+3+4+5+6+7+8+9=45, which is a multiple of 9, so 123456789 is a multiple of 9.

Sample Input 2

0

Sample Output 2

Yes

Sample Input 3

31415926535897932384626433832795028841971693993751058209749445923078164062862089986280

Sample Output 3

No

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;
typedef long long int ll;

int main()
{
    ll n,t,a,b,c,d,e,p,q,cnt=0;
    map<ll,ll>mp;
    vector<ll>vec;
    string s,s1,s2;
    ll ac=0,tle=0,wa=0,re=0;
   cin>>s;
   ll sum=0;
    for(ll i=0;i<s.length();i++){
        sum+=s[i]-'0';
    }

    if(sum%9==0){
        cout<<"Yes"<<endl;
    }
    else cout<<"No"<<endl;






}