Problem:
Score : 200 points

Problem Statement

We have a string S consisting of uppercase English letters. Additionally, an integer N will be given.

Shift each character of S by N in alphabetical order (see below), and print the resulting string.

We assume that A follows Z. For example, shifting A by 2 results in C (A \to B \to C), and shifting Y by 3 results in B (Y \to Z \to A \to B).

Constraints

0 \leq N \leq 26

1 \leq |S| \leq 10^4

S consists of uppercase English letters.

Input

Input is given from Standard Input in the following format:

N
S

Output

Print the string resulting from shifting each character of S by N in alphabetical order.

Sample Input 1

2
ABCXYZ

Sample Output 1

CDEZAB

Note that A follows Z.

Sample Input 2

0
ABCXYZ

Sample Output 2

ABCXYZ

Sample Input 3

13
ABCDEFGHIJKLMNOPQRSTUVWXYZ

Sample Output 3

NOPQRSTUVWXYZABCDEFGHIJKLM

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <vector>
#include <math.h>
#include <iostream>
#include <string>
using namespace std;
using uint = unsigned int;
using ll = long long;
using ull = unsigned long long;
template <class T> using V = vector<T>;
template <class T> using VV = V<V<T>>;
#define rep(i, n) for(int i = 0; i<n; i++)
#define rep_s(i, start, n) for(int i= start; i<n; i++)

int main(void){
  string alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
 string s;
  int N;
  cin >> N;
  cin >> s;
  int count[(int)s.size()];
  int amari;
  rep(i, s.size()){
   	rep(j, 26){
      if (s[i] == alphabet[j]) {
        amari = (j+N)%26;
        cout << alphabet[amari];
      }
    }
  }
}