Problem:
Score : 200 points

Problem Statement

Alice and Bob are controlling a robot. They each have one switch that controls the robot.

Alice started holding down her button A second after the start-up of the robot, and released her button B second after the start-up.

Bob started holding down his button C second after the start-up, and released his button D second after the start-up.

For how many seconds both Alice and Bob were holding down their buttons?

Constraints

0≤A<B≤100

0≤C<D≤100

All input values are integers.

Input

Input is given from Standard Input in the following format:

A B C D

Output

Print the length of the duration (in seconds) in which both Alice and Bob were holding down their buttons.

Sample Input 1

0 75 25 100

Sample Output 1

50

Alice started holding down her button 0 second after the start-up of the robot, and released her button 75 second after the start-up.

Bob started holding down his button 25 second after the start-up, and released his button 100 second after the start-up.

Therefore, the time when both of them were holding down their buttons, is the 50 seconds from 25 seconds after the start-up to 75 seconds after the start-up.

Sample Input 2

0 33 66 99

Sample Output 2

0

Alice and Bob were not holding their buttons at the same time, so the answer is zero seconds.

Sample Input 3

10 90 20 80

Sample Output 3

60

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#define _USE_MATH_DEFINES // for C++  
#include "bits/stdc++.h"
#define LL long long
#define NUM 1000000007

using namespace std;

int main() {
    int a, b, c, d;
    cin >> a >> b >> c >> d;
    if (b < c || d < a)
    {
        cout << 0 << endl;
    }
    else if (a < c && c < d && d < b)
    {
        cout << d - c << endl;
    }
    else if (c < a && a < b && b < d)
    {
        cout << b - a << endl;
    }
    else if (a < c && c < b && b < d)
    {
        cout << b - c << endl;
    }
    else if (c < a && a < d && d < b)
    {
        cout << d - a << endl;
    }
}