Problem:
Score : 200 points

Problem Statement

The word internationalization is sometimes abbreviated to i18n.
This comes from the fact that there are 18 letters between the first i and the last n.

You are given a string s of length at least 3 consisting of lowercase English letters.
Abbreviate s in the same way.

Constraints

3 ≤ |s| ≤ 100 (|s| denotes the length of s.)

s consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s

Output

Print the abbreviation of s.

Sample Input 1

internationalization

Sample Output 1

i18n

Sample Input 2

smiles

Sample Output 2

s4s

Sample Input 3

xyz

Sample Output 3

x1z

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <string>
#include <algorithm>
#include <vector>
#include <utility>
#include <cstring>
#include <cmath>
#include <queue>
#include <stack>
#include <map>
#define INF (long)1e9
const int MOD = 1e9 + 7;
const int dx[] = {1, -1, 0, 0};
const int dy[] = {0, 0, 1, -1};
using namespace std;
typedef long long ll;
int main()
{
	cin.tie(0);
	ios::sync_with_stdio(false);
	string s;
	cin >> s;
	string ans = "";
	ans += s[0];
	ans += to_string(s.size() - 2);
	ans += s[s.size() - 1];
	cout << ans << endl;
	return 0;
}