Problem:
Score : 100 points

Problem Statement

Takahashi is a member of a programming competition site, ButCoder.

Each member of ButCoder is assigned two values: Inner Rating and Displayed Rating.

The Displayed Rating of a member is equal to their Inner Rating if the member has participated in 10 or more contests. Otherwise, the Displayed Rating will be their Inner Rating minus 100 \times (10 - K) when the member has participated in K contests.

Takahashi has participated in N contests, and his Displayed Rating is R. Find his Inner Rating.

Constraints

All values in input are integers.

1 \leq N \leq 100

0 \leq R \leq 4111

Input

Input is given from Standard Input in the following format:

N R

Output

Print his Inner Rating.

Sample Input 1

2 2919

Sample Output 1

3719

Takahashi has participated in 2 contests, which is less than 10, so his Displayed Rating is his Inner Rating minus 100 \times (10 - 2) = 800.

Thus, Takahashi's Inner Rating is 2919 + 800 = 3719.

Sample Input 2

22 3051

Sample Output 2

3051

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

/*dismint|jjc*/
#include <bits/stdc++.h>
using namespace std;
#define forl(V, S, E) for(int V = S; V < E; V++)
#define ford(V, S, E) for(int V = S; V >= E; V--)
#define fore(E, X) for(auto &E:X)
#define println(X) cout << X << endl
#define printe(X) for(auto &E:X) cout << E << " "; cout << endl
typedef unordered_map<int, unordered_set<int>> graph;
typedef long long ll;

int main() {
	ios_base::sync_with_stdio(false); cin.tie(NULL);
	int n, r; cin >> n >> r;
	if(n < 10) {
		println(n+100*(10-r));
	}
	else {
		println(n);
	}
}