Problem:
Score : 200 points

Problem Statement

Let S(n) denote the sum of the digits in the decimal notation of n.
For example, S(101) = 1 + 0 + 1 = 2.

Given an integer N, determine if S(N) divides N.

Constraints

1 \leq N \leq 10^9

Input

Input is given from Standard Input in the following format:

N

Output

If S(N) divides N, print Yes; if it does not, print No.

Sample Input 1

12

Sample Output 1

Yes

In this input, N=12.
As S(12) = 1 + 2 = 3, S(N) divides N.

Sample Input 2

101

Sample Output 2

No

As S(101) = 1 + 0 + 1 = 2, S(N) does not divide N.

Sample Input 3

999999999

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include "bits/stdc++.h"
using namespace std;
#define MOD 1000000007
#define Nmax 200010
#define FOR(i,a,b) for(long long i=(a);i<(b);i++)
#define REP(i,n)  FOR(i,0,n)
#define ITR(itr,mp) for(auto itr = (mp).begin(); itr != (mp).end(); ++itr)
#define dump(x)  cout << #x << " = " << (x) << endl;
#define debug(x) cout << #x << " = " << (x) << " (L" << __LINE__ << ")" << " " << __FILE__ << endl;
typedef long long ll;
 
int main() {
	string S;
	cin >> S;
	ll sum=0,N=0;
	REP(i,S.length()){
		sum+=S[i]-'0';
		N+=(S[i]-'0')*pow(10, S.length()-i-1);
	}
	if(N%sum==0) cout <<"Yes"<<endl;
	else cout << "No" << endl;
	return 0;
}