Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;

int main() {
  double N;
  cin >> N;
  bool next=true;
  double i=0;
  double j=0;
  int an;
  while(i<3501 && next){
    j=0;
    i++;
    while(j<3501 && next){
      j++;
      double ans=1/(4/N-1/i-1/j);
      an=ans;
      if(abs(an-ans)<0.000001 && an>0){
        next=false;
        break;
      }
    }
  }
  cout << i << ' ' << j << ' ' << an;
}