Problem:
Score : 300 points

Problem Statement

You are given N positive integers a_1, a_2, ..., a_N.

For a non-negative integer m, let f(m) = (m\ mod\ a_1) + (m\ mod\ a_2) + ... + (m\ mod\ a_N).

Here, X\ mod\ Y denotes the remainder of the division of X by Y.

Find the maximum value of f.

Constraints

All values in input are integers.

2 \leq N \leq 3000

2 \leq a_i \leq 10^5

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 ... a_N

Output

Print the maximum value of f.

Sample Input 1

3
3 4 6

Sample Output 1

10

f(11) = (11\ mod\ 3) + (11\ mod\ 4) + (11\ mod\ 6) = 10 is the maximum value of f.

Sample Input 2

5
7 46 11 20 11

Sample Output 2

90

Sample Input 3

7
994 518 941 851 647 2 581

Sample Output 3

4527

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef long double ld;

int gcd(int x, int y) { return (x % y)? gcd(y, x % y): y; }
int lcm(int x, int y) { return x / gcd(x, y) * y; }

int modi(int m,int a){
    return m%a;
}

int func(vector<int> v,int lcm){
    int n = v.size();
    int sum = 0;
    for(int i=0;i<n;i++){
        sum += modi(lcm,v[i]);
    }
    return sum;
}

int main(){
    int n;
    cin >> n;
    vector<int> a(n);
    for(int i=0;i<n;i++){
        cin >> a[i];
    }
    int ans = 0;
    for(int i=0;i<n;i++){
        ans += a[i];
    }
    cout << ans - n << endl;

}