Problem:
Score : 100 points

Problem Statement

There are two buttons, one of size A and one of size B.

When you press a button of size X, you get X coins and the size of that button decreases by 1.

You will press a button twice. Here, you can press the same button twice, or press both buttons once.

At most how many coins can you get?

Constraints

All values in input are integers.

3 \leq A, B \leq 20

Input

Input is given from Standard Input in the following format:

A B

Output

Print the maximum number of coins you can get.

Sample Input 1

5 3

Sample Output 1

9

You can get 5 + 4 = 9 coins by pressing the button of size 5 twice, and this is the maximum result.

Sample Input 2

3 4

Sample Output 2

7

Sample Input 3

6 6

Sample Output 3

12

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <iomanip>
#include <string>
#include <map>
#include <math.h>
#include <vector>
#include <algorithm>
#include <cstdio>
#include <set>
#include <queue>
#include <sstream>
#include <stack>
#include <deque>
#include <memory.h>
#include <cassert>
#include <ctime>
#include <climits>
#include <list>
#include <time.h>
#include <unordered_map>
#include <bitset>
#include <exception>

using namespace std;


int main(){
  int n;
  cin >> n;
  int arr[n];
  int count = 1;
  int currMax;
  cin >> currMax;
  int temp;
  
  for(int i = 0; i < n-1; i++){
    cin >> temp;
    if (temp >= currMax){
      count++;
      currMax = temp;
    }
  }
  cout << count << endl;
  
  
  
}