Problem:
Score : 200 points

Problem Statement

Raccoon is fighting with a monster.

The health of the monster is H.

Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i.
There is no other way to decrease the monster's health.

Raccoon wins when the monster's health becomes 0 or below.

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Constraints

1 \leq H \leq 10^9

1 \leq N \leq 10^5

1 \leq A_i \leq 10^4

All values in input are integers.

Input

Input is given from Standard Input in the following format:

H N
A_1 A_2 ... A_N

Output

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Sample Input 1

10 3
4 5 6

Sample Output 1

Yes

The monster's health will become 0 or below after, for example, using the second and third moves.

Sample Input 2

20 3
4 5 6

Sample Output 2

No

Sample Input 3

210 5
31 41 59 26 53

Sample Output 3

Yes

Sample Input 4

211 5
31 41 59 26 53

Sample Output 4

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
#include<algorithm>
using namespace std;
#define ll long long 
int ctoi(char c) {return c-'0';}/*char to int*/
int gcd(ll a,ll b){return b?gcd(b,a%b):a;}/*MAX*/
int lcm(ll a,ll b){return a*b/gcd(a,b);}/*MIN*/
bool primecheck(ll n){/*sosuu*/if(n < 2) return false;else{for(int i = 2; i * i <= n; i++){if(n % i == 0) return false;}return true;}}
string  reverserange(string s,ll a,ll b){reverse(s.begin()+a-1,s.begin()+b); return s;}
int  main(){
ll h,n;
cin >> h >> n; 
ll che = 0;
for(int i=0;i<n;i++){
    int z;
    cin >> z;
    che+=z;
}
if(che>=h){
    cout<<"Yes"<<endl;
}
else{
    cout<<"No"<<endl;
}
}