Problem:
Score : 200 points

Problem Statement

Takahashi's house has only one socket.

Takahashi wants to extend it with some number of power strips, each with A sockets, into B or more empty sockets.

One power strip with A sockets can extend one empty socket into A empty sockets.

Find the minimum number of power strips required.

Constraints

All values in input are integers.

2 \leq A \leq 20

1 \leq B \leq 20

Input

Input is given from Standard Input in the following format:

A B

Output

Print the minimum number of power strips required.

Sample Input 1

4 10

Sample Output 1

3

3 power strips, each with 4 sockets, extend the socket into 10 empty sockets.

Sample Input 2

8 9

Sample Output 2

2

2 power strips, each with 8 sockets, extend the socket into 15 empty sockets.

Sample Input 3

8 8

Sample Output 3

1

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<bits/stdc++.h>
using namespace std;
const int maxn=4e5+10;
const double inf=1e9;
typedef long long ll;
typedef pair<int,int>pr;
const ll mod=1e9+7;
ll _pow(ll  a,ll b) {
    ll ans=1;
    while(b) {
        if(b&1)
            ans=ans*a;
        a=a*a;
        b>>=1;
    }
    return ans;
}
ll gcd(ll a,ll b){
    if(!b) return a;
    else return gcd(b,a%b);
}

int vis[30];
int main(){
  ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);
  int a,b;
  cin>>a>>b;
  int num=b/a+1;
  if(b%a==0){
     num--;
  }
  cout<<num<<endl;
  return 0;
}