Problem:
Score : 200 points

Problem Statement

Let w be a string consisting of lowercase letters.
We will call w beautiful if the following condition is satisfied:

Each lowercase letter of the English alphabet occurs even number of times in w.

You are given the string w. Determine if w is beautiful.

Constraints

1 \leq |w| \leq 100

w consists of lowercase letters (a-z).

Input

The input is given from Standard Input in the following format:

w

Output

Print Yes if w is beautiful. Print No otherwise.

Sample Input 1

abaccaba

Sample Output 1

Yes

a occurs four times, b occurs twice, c occurs twice and the other letters occur zero times.

Sample Input 2

hthth

Sample Output 2

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

/*
ID: learnin7
TASK: test
LANG: C++                 
*/
/* LANG can be C++11 or C++14 for those more recent releases */
#include<bits/stdc++.h>

/*  Macros from Endagorion */
#define mp make_pair
#define mt make_tuple
#define fi first
#define se second
#define pb push_back
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define forn(i, n) for (int i = 0; i < (int)(n); ++i)
#define for1(i, n) for (int i = 1; i <= (int)(n); ++i)
#define ford(i, n) for (int i = (int)(n) - 1; i >= 0; --i)
#define fore(i, a, b) for (int i = (int)(a); i <= (int)(b); ++i)

using namespace std;

typedef pair<int, int> pii;
typedef vector<int> vi;
typedef vector<pii> vpi;
typedef vector<vi> vvi;
typedef long long i64;
typedef vector<i64> vi64;
typedef vector<vi64> vvi64;
typedef pair<i64, i64> pi64;
typedef double ld;


int main(){
        
    ios_base::sync_with_stdio(0);
    
    //ofstream fout ("test.out");
    //ifstream fin ("test.in");
    //fin >> a >> b;
    //fout << a+b << endl;
    string w;
    cin>>w;
    int n = w.length();
    int x[26]={0};
    for(int i=0;i<n;i++)    x[w[i]-'a']++;
    for(int i=0;i<26;i++){
        if(x[i]%2==1){
            cout<<"No\n";
            return 0;
        }
    }
    cout<<"Yes\n";
    return 0;
}