Problem:
Score : 200 points

Problem Statement

Tak performed the following action N times: rolling two dice.
The result of the i-th roll is D_{i,1} and D_{i,2}.

Check if doublets occurred at least three times in a row.
Specifically, check if there exists at lease one i such that D_{i,1}=D_{i,2}, D_{i+1,1}=D_{i+1,2} and D_{i+2,1}=D_{i+2,2} hold.

Constraints

3 \leq N \leq 100

1\leq D_{i,j} \leq 6

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
D_{1,1} D_{1,2}
\vdots
D_{N,1} D_{N,2}

Output

Print Yes if doublets occurred at least three times in a row. Print No otherwise.

Sample Input 1

5
1 2
6 6
4 4
3 3
3 2

Sample Output 1

Yes

From the second roll to the fourth roll, three doublets occurred in a row.

Sample Input 2

5
1 1
2 2
3 4
5 5
6 6

Sample Output 2

No

Sample Input 3

6
1 1
2 2
3 3
4 4
5 5
6 6

Sample Output 3

Yes

Solution in C++ (Clang 10.0.0) (judge verdict: Accepted)

#define _USE_MATH_DEFINES
#include <iostream>
#include <string>
#include <queue>
#include <stack>
#include <vector>
#include <algorithm>
#include <math.h>
#include <map>
#include <list>
#include <iomanip>
#include <queue>
#include <cmath>
#include <numeric>
#define repl(i, l, r) for (ll i = l; i < r; i++)
#define rep(i, n) repl(i, 0, n)

using namespace std;
using ll = long long;
typedef pair<ll, ll> P;
template<class T>bool chmax(T& a, const T& b) { if (a < b) { a = b; return 1; } return 0; }
template<class T>bool chmin(T& a, const T& b) { if (b < a) { a = b; return 1; } return 0; }
const long long mod = 1e9 + 7;
ll gcd(ll a, ll b);
ll lcm(ll a, ll b);
ll dx[] = { 1, 0 , -1,  0 }, dy[] = { 0, 1, 0, -1 };
ll cb(ll a, ll b);

int main() {
	ll n;
	cin >> n;

	ll x, y, cnt = 0;
	string ans = "No";
	rep(i, n) {
		cin >> x >> y;
		if (x == y) cnt++;
		else cnt = 0;
		if (cnt >= 3) ans = "Yes";
	}

	cout << ans;
}


ll cb(ll a, ll b) {
	ll ans = 1;
	rep(i, b) ans *= (a - i);
	rep(i, b) ans /= (b - i);

	return ans;
}