Problem:
Score : 300 points

Problem Statement

You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

1 \leq |S| \leq 2 \times 10^5

|S| = |T|

S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S and T can be made equal, print Yes; otherwise, print No.

Sample Input 1

azzel
apple

Sample Output 1

Yes

azzel can be changed to apple, as follows:

Choose e as c_1 and l as c_2. azzel becomes azzle.

Choose z as c_1 and p as c_2. azzle becomes apple.

Sample Input 2

chokudai
redcoder

Sample Output 2

No

No sequences of operation can change chokudai to redcoder.

Sample Input 3

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>

#define INF 100100100
#define MOD 1000000007

using namespace std;

int main(int argc, char const* argv[])
{
   string S,T;
   cin >> S >> T;
   string diff_S="",diff_T="";
   set<pair<char,char> >memo;
   for(int i=0;i<S.size();i++){
      if(S[i] != T[i]){
         set<pair<char,char> >::iterator it1,it2;
         pair<char,char> a = make_pair(S[i],T[i]);
         pair<char,char> a_ = make_pair(T[i],T[i]);
         it1 = memo.find(a);
         it2 = memo.find(a_);
         if(it1 != memo.end() || it2 != memo.end())continue;
         diff_S += S[i];
         diff_T += T[i];
         memo.insert(a);
      }
   }
   for(int i=0;i<diff_S.size();i++){
      char s = diff_S[i];
      char t = diff_T[i];
      for(int j=0;j<diff_S.size();j++){
         if(diff_S[j] == s)diff_S[j] = t;
         else if(diff_S[j] == t)diff_S[j] = s;
      }
   }
   if(diff_S == diff_T)cout <<"Yes";
   else cout << "No";
   return 0;
}