Problem:
Score : 100 points

Problem Statement

In AtCoder City, there are three stations numbered 1, 2, and 3.

Each of these stations is operated by one of the two railway companies, A and B. A string S of length 3 represents which company operates each station. If S_i is A, Company A operates Station i; if S_i is B, Company B operates Station i.

To improve the transportation condition, for each pair of a station operated by Company A and one operated by Company B, there will be a bus service connecting them.

Determine if there is a pair of stations that will be connected by a bus service.

Constraints

Each character of S is A or B.

|S| = 3

Input

Input is given from Standard Input in the following format:

S

Output

If there is a pair of stations that will be connected by a bus service, print Yes; otherwise, print No.

Sample Input 1

ABA

Sample Output 1

Yes

Company A operates Station 1 and 3, while Company B operates Station 2.

There will be a bus service between Station 1 and 2, and between Station 2 and 3, so print Yes.

Sample Input 2

BBA

Sample Output 2

Yes

Company B operates Station 1 and 2, while Company A operates Station 3.

There will be a bus service between Station 1 and 3, and between Station 2 and 3, so print Yes.

Sample Input 3

BBB

Sample Output 3

No

Company B operates all the stations. Thus, there will be no bus service, so print No.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <iostream>
#include <iomanip>
#include <vector>
#include <unordered_map>
#include <map>
#include <set>
#include <queue>
#include <stack>
#include <array>
#include <tuple>
#include <string>
#include <algorithm>
#include <functional>
#include <cmath>
#include <numeric>
#include <bitset>
#include <cstdint>
using namespace std;

#ifdef DEBUG
#include <cassert>
#else
#define assert(x)
#endif

#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define FOR(i, a, b) for (int i = (a); i < (int)(b); i++)
using ll = long long;

//////////////// //////////////// //////////////// //////////////// ////////////////
//////////////// //////////////// //////////////// //////////////// ////////////////

int main()
{
    // 高速な入出力
    ios_base::sync_with_stdio(false);
    cin.tie(nullptr);
    // 浮動小数の表示の精度
    cout << setprecision(15);

    vector<char> v(3);
    rep(i, 3) { cin >> v[i]; }
    if (v[0] == v[1] && v[1] == v[2])
    {
        cout << "No\n";
    }
    else
    {
        cout << "Yes\n";
    }

    return 0;
}