Problem:
Score : 100 points

Problem Statement

An elementary school student Takahashi has come to a variety store.

He has two coins, A-yen and B-yen coins (yen is the currency of Japan), and wants to buy a toy that costs C yen. Can he buy it?

Note that he lives in Takahashi Kingdom, and may have coins that do not exist in Japan.

Constraints

All input values are integers.

1 \leq A, B \leq 500

1 \leq C \leq 1000

Input

Input is given from Standard Input in the following format:

A B C

Output

If Takahashi can buy the toy, print Yes; if he cannot, print No.

Sample Input 1

50 100 120

Sample Output 1

Yes

He has 50 + 100 = 150 yen, so he can buy the 120-yen toy.

Sample Input 2

500 100 1000

Sample Output 2

No

He has 500 + 100 = 600 yen, but he cannot buy the 1000-yen toy.

Sample Input 3

19 123 143

Sample Output 3

No

There are 19-yen and 123-yen coins in Takahashi Kingdom, which are rather hard to use.

Sample Input 4

19 123 142

Sample Output 4

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<iostream>
#include<climits>
#include<math.h>
#include<vector>
#include<algorithm>
#include<cstdio>
#include<stdio.h>
#include <string>
#include <complex>
#include <functional>
#include <map>
using namespace std;
using ll = long long;
//typedef pair<string,string> P;
//double dat[100][100];
//int dp[6][1010];//動的計画法
//int prime[100001];
//char str[1010][1010];
//vector<pair<int,int> > pc[100001];
//int ABS(int a){return max(a,-a);}
int main(){
	int a,b,c;
	cin>>a>>b>>c;
	if(a+b>=c) cout<<"Yes"<<endl;
	else cout<<"No"<<endl;
	return 0;
}