Problem:
Score : 200 points

Problem Statement

La Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each.
Determine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.

Constraints

N is an integer between 1 and 100, inclusive.

Input

Input is given from Standard Input in the following format:

N

Output

If there is a way to buy some cakes and some doughnuts for exactly N dollars, print Yes; otherwise, print No.

Sample Input 1

11

Sample Output 1

Yes

If you buy one cake and one doughnut, the total will be 4 + 7 = 11 dollars.

Sample Input 2

40

Sample Output 2

Yes

If you buy ten cakes, the total will be 4 \times 10 = 40 dollars.

Sample Input 3

3

Sample Output 3

No

The prices of cakes (4 dollars) and doughnuts (7 dollars) are both higher than 3 dollars, so there is no such way.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<iostream>
#include<algorithm>
#include<vector>
#include<queue>
#include<stack>
#include<string>
#include<map>
#include<set>
#include<tuple>
#include<cmath>
#include<iomanip>


#define MOD 1000000007
#define INF 1001001001
#define MIN -1001001001
#define rep(i,k,N) for(int i=k;i<N;i++)
#define MP make_pair
#define MT make_tuple //tie,make_tuple は別物
#define PB push_back
#define PF push_front
#define all(x) (x).begin(),(x).end()


using namespace std;
typedef long long ll;
typedef vector<ll> v;
typedef vector<vector<ll>> vv;

int dx[4]={1,0,-1,0};
int dy[4]={0,1,0,-1};

void YN(bool ans){
    if(ans)cout<<"AC"<<endl;
    else cout <<"WA"<<endl;
    return;
}
int main(){
    string S;
    cin>>S;
    bool ans = true;
    if(S[0] != 'A')ans = false;
    bool ok = false;
    ll c;
    rep(i,2,S.size()-1){
        if(S[i] == 'C'){
            ok = true;
            c=i;
            break;
        }
    }
    if(!ok)ans = false;
    rep(i,1,S.size()){
        if(i!=c){
            if(S[i] <= 'Z')ans = false;
        }
    }
    YN(ans);
    return 0;
}