Problem:
Score : 200 points

Problem Statement

Raccoon is fighting with a monster.

The health of the monster is H.

Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i.
There is no other way to decrease the monster's health.

Raccoon wins when the monster's health becomes 0 or below.

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Constraints

1 \leq H \leq 10^9

1 \leq N \leq 10^5

1 \leq A_i \leq 10^4

All values in input are integers.

Input

Input is given from Standard Input in the following format:

H N
A_1 A_2 ... A_N

Output

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Sample Input 1

10 3
4 5 6

Sample Output 1

Yes

The monster's health will become 0 or below after, for example, using the second and third moves.

Sample Input 2

20 3
4 5 6

Sample Output 2

No

Sample Input 3

210 5
31 41 59 26 53

Sample Output 3

Yes

Sample Input 4

211 5
31 41 59 26 53

Sample Output 4

No

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<iostream>
#include<math.h>
#include<bits/stdc++.h>
#define ll long long int
#define hell 1000000007LL
using namespace std;
ll power(ll x, ll y){ 
    if(y==0)
     return 1;
    else
    {
        ll p=power(x,y/2);
        if(y%2==0)
         return (p*p)%hell;
        else
        return (x*((p*p)%hell))%hell;
    }}
ll gcd(ll x,ll y)
{
    if(y==0)
     return x;
    else
    return gcd(y,x%y);
}
int main()
{
    ios_base::sync_with_stdio(false);
    cin.tie(0);
    cout.precision(20);
    ll h,n;
    cin>>h>>n;
    for(int i=0;i<n;i++)
    {
        ll x;
        cin>>x;
        h=h-x;
    }
    if(h<=0)
    cout<<"Yes";
    else
    cout<<"No";}