Problem:
Score : 200 points

Problem Statement

There are some animals in a garden. Each of them is a crane with two legs or a turtle with four legs.

Takahashi says: "there are X animals in total in the garden, and they have Y legs in total." Determine whether there is a combination of numbers of cranes and turtles in which this statement is correct.

Constraints

1 \leq X \leq 100

1 \leq Y \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

If there is a combination of numbers of cranes and turtles in which the statement is correct, print Yes; otherwise, print No.

Sample Input 1

3 8

Sample Output 1

Yes

The statement "there are 3 animals in total in the garden, and they have 8 legs in total" is correct if there are two cranes and one turtle. Thus, there is a combination of numbers of cranes and turtles in which the statement is correct.

Sample Input 2

2 100

Sample Output 2

No

There is no combination of numbers of cranes and turtles in which this statement is correct.

Sample Input 3

1 2

Sample Output 3

Yes

We also consider the case in which there are only cranes or only turtles.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>

#define int int64_t
#define loop(i,s,e) for(int i=s;i<e;++i)
#define vi vector<int>
#define pb push_back
#define max(x,y) ((x>y)?x:y)
#define min(x,y) ((x>y)?y:x)

using namespace std;

int32_t main(){
	ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);

	int x, y; cin >> x >> y;
	if(y%2 == 1) {
		cout << "No" << endl;
	}else{
		int k = 2*x - (y/2);
		if(k < 0 || k > x){
			cout << "No" << endl;
		}else{
			cout << "Yes" << endl;
		}
	}

	return 0;
}