Problem:
Score : 200 points

Problem Statement

There are some animals in a garden. Each of them is a crane with two legs or a turtle with four legs.

Takahashi says: "there are X animals in total in the garden, and they have Y legs in total." Determine whether there is a combination of numbers of cranes and turtles in which this statement is correct.

Constraints

1 \leq X \leq 100

1 \leq Y \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

If there is a combination of numbers of cranes and turtles in which the statement is correct, print Yes; otherwise, print No.

Sample Input 1

3 8

Sample Output 1

Yes

The statement "there are 3 animals in total in the garden, and they have 8 legs in total" is correct if there are two cranes and one turtle. Thus, there is a combination of numbers of cranes and turtles in which the statement is correct.

Sample Input 2

2 100

Sample Output 2

No

There is no combination of numbers of cranes and turtles in which this statement is correct.

Sample Input 3

1 2

Sample Output 3

Yes

We also consider the case in which there are only cranes or only turtles.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
#define maxn 0x3f3f3f3f
using namespace std;
typedef long long ll;
int main()
{
	std::ios::sync_with_stdio(false);
	int a;
	int b;
	cin>>a>>b;
	int s1=2*a;
	int s2=4*a;
	if(b<s1||b>s2)
	{
		cout<<"No";
		return 0;
	}
	if(b%2!=0)
	{
		cout<<"No";
		return 0; 
	} 
	int c=b/2;
	if(c<a) 
	{
		cout<<"No";
		return 0;
	}
	int y=c-a;
	int x=2*a-c;
	if(x+y==a&&2*x+4*y==b) cout<<"Yes";
	else cout<<"No";
	return 0; 
}