Problem:
Score : 100 points

Problem Statement

Takahashi is meeting up with Aoki.

They have planned to meet at a place that is D meters away from Takahashi's house in T minutes from now.

Takahashi will leave his house now and go straight to the place at a speed of S meters per minute.

Will he arrive in time?

Constraints

1 \leq D \leq 10000

1 \leq T \leq 10000

1 \leq S \leq 10000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

D T S

Output

If Takahashi will reach the place in time, print Yes; otherwise, print No.

Sample Input 1

1000 15 80

Sample Output 1

Yes

It takes 12.5 minutes to go 1000 meters to the place at a speed of 80 meters per minute. They have planned to meet in 15 minutes so he will arrive in time.

Sample Input 2

2000 20 100

Sample Output 2

Yes

It takes 20 minutes to go 2000 meters to the place at a speed of 100 meters per minute. They have planned to meet in 20 minutes so he will arrive just on time.

Sample Input 3

10000 1 1

Sample Output 3

No

He will be late.

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
#include <string>
#include <cstring>
#include <algorithm>
#include <math.h>
#include <map>
#include <bitset>
#include <cmath>
#include <set>
#include <utility>
#include <sstream>

#define INF 1000000000000
#define MOD 1000000007 //10^9+7:合同式の法

using namespace std;
typedef long long ll;

/*
0のアスキー　"48"
*/

//マクロ
#define REP(i,n) for(ll i=0;i<(ll)(n);i++)
#define REPD(i,n) for(ll i=n-1;i>=0;i--)
#define FOR(i,a,b) for(ll i=a;i<=(ll)(b);i++)
#define FORD(i,a,b) for(ll i=a;i>=(ll)(b);i--)
#define ALL(x) x.begin(),x.end()
#define chmax(x,y) (x = max(x,y))
#define chmin(x,y) (x = min(x,y))


int main(){
    ll D,T,S;
    cin >> D >> T >> S;

    double d = D / S;

    if(d <= S)
        cout << "Yes" << endl;
    else
        cout << "No" <<endl;

    return 0;
}