Problem:
Score : 100 points

Problem Statement

You went shopping to buy cakes and donuts with X yen (the currency of Japan).

First, you bought one cake for A yen at a cake shop.
Then, you bought as many donuts as possible for B yen each, at a donut shop.

How much do you have left after shopping?

Constraints

1 \leq A, B \leq 1 000

A + B \leq X \leq 10 000

X, A and B are integers.

Input

Input is given from Standard Input in the following format:

X
A
B

Output

Print the amount you have left after shopping.

Sample Input 1

1234
150
100

Sample Output 1

84

You have 1234 - 150 = 1084 yen left after buying a cake.
With this amount, you can buy 10 donuts, after which you have 84 yen left.

Sample Input 2

1000
108
108

Sample Output 2

28

Sample Input 3

579
123
456

Sample Output 3

0

Sample Input 4

7477
549
593

Sample Output 4

405

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<iostream>

using namespace std;

int main(){
	int A, B, C, X;
	cin >> A >> B >> C >> X;
	int res = 0;
	for (int a = 0; a <= A; ++a) {
		for (int b = 0; b <= B; ++b) {
			for (int c = 0; c <= C; ++c){
				int total = 500 * a + 100 * b + 50 * c; //合計金額
				if (total == X) ++res; //合計金額がXに一致したらカウント
				}
			}
		}
	cout << res <<endl;
	return 0;
	}