Problem:
Score : 100 points

Problem Statement

We have A balls with the string S written on each of them and B balls with the string T written on each of them.

From these balls, Takahashi chooses one with the string U written on it and throws it away.

Find the number of balls with the string S and balls with the string T that we have now.

Constraints

S, T, and U are strings consisting of lowercase English letters.

The lengths of S and T are each between 1 and 10 (inclusive).

S \not= T

S=U or T=U.

1 \leq A,B \leq 10

A and B are integers.

Input

Input is given from Standard Input in the following format:

S T
A B
U

Output

Print the answer, with space in between.

Sample Input 1

red blue
3 4
red

Sample Output 1

2 4

Takahashi chose a ball with red written on it and threw it away.
Now we have two balls with the string S and four balls with the string T.

Sample Input 2

red blue
5 5
blue

Sample Output 2

5 4

Takahashi chose a ball with blue written on it and threw it away.
Now we have five balls with the string S and four balls with the string T.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#ifdef LOCAL
#include <cstdio>
#include <vector>
#include <algorithm>
#include <iostream>
#include <cstring>
#else
#include <bits/stdc++.h>
#endif
using namespace std ;

typedef long long ll ;
#define rep(i , n ) for ( int i =0; i < n ; i++)
#define _sort(arg) sort(begin(arg), end(arg))
#define MOD 1000000007
#define pb push_back
#define DEBUG(x) cout << #x << ": " << x << endl;

/*
__attribute__((constructor))
void initial()
{
	cin.tie(NULL);
	ios::sync_with_stdio(false);
}
*/

int main()
{
	cin.tie(NULL);
	ios::sync_with_stdio(false);

	string s, t;
	int A, B;
	string c;
	cin >> s >> t;
	cin >> A >> B;
	cin >> c;

	if (c == s)
	{
		cout << A - 1 << " " << B << endl;
	}
	else
	{
		cout << A << " " << B - 1 << endl;
	}
	

	
	return 0;
}