Problem:
Score : 100 points

Problem Statement

ButCoder Inc. runs a programming competition site called ButCoder. In this site, a user is given an integer value called rating that represents his/her skill, which changes each time he/she participates in a contest. The initial value of a new user's rating is 0, and a user whose rating reaches K or higher is called Kaiden ("total transmission"). Note that a user's rating may become negative.

Hikuhashi is a new user in ButCoder. It is estimated that, his rating increases by A in each of his odd-numbered contests (first, third, fifth, ...), and decreases by B in each of his even-numbered contests (second, fourth, sixth, ...).

According to this estimate, after how many contests will he become Kaiden for the first time, or will he never become Kaiden?

Constraints

1 ≤ K, A, B ≤ 10^{18}

All input values are integers.

Input

Input is given from Standard Input in the following format:

K A B

Output

If it is estimated that Hikuhashi will never become Kaiden, print -1. Otherwise, print the estimated number of contests before he become Kaiden for the first time.

Sample Input 1

4000 2000 500

Sample Output 1

5

Each time Hikuhashi participates in a contest, his rating is estimated to change as 0 → 2000 → 1500 → 3500 → 3000 → 5000 → … After his fifth contest, his rating will reach 4000 or higher for the first time.

Sample Input 2

4000 500 2000

Sample Output 2

-1

Each time Hikuhashi participates in a contest, his rating is estimated to change as 0 → 500 → -1500 → -1000 → -3000 → -2500 → … He will never become Kaiden.

Sample Input 3

1000000000000000000 2 1

Sample Output 3

1999999999999999997

The input and output values may not fit into 32-bit integers.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <vector>
#include <string>
#include <cmath>
#include <algorithm>
#include <map>
#include <iomanip>
#include <stdlib.h>
#include <queue>

using namespace std;

const int nmax = 1e9 + 7;
typedef long long ll;

int main(){
  ll K, A, B; cin >> K >> A >> B;
  if (A <= B){
    if (A >= K){
      cout << 1 << endl;
    }else{
      cout << -1 << endl;
    }
  }else{
    ll N = (K - A) / (A - B);
    cout << 2 * N + 1 << endl;
  }
  
  

  return 0;
}