Problem:
Score : 200 points

Problem Statement

Takahashi has many red balls and blue balls. Now, he will place them in a row.

Initially, there is no ball placed.

Takahashi, who is very patient, will do the following operation 10^{100} times:

Place A blue balls at the end of the row of balls already placed. Then, place B red balls at the end of the row.

How many blue balls will be there among the first N balls in the row of balls made this way?

Constraints

1 \leq N \leq 10^{18}

A, B \geq 0

0 < A + B \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N A B

Output

Print the number of blue balls that will be there among the first N balls in the row of balls.

Sample Input 1

8 3 4

Sample Output 1

4

Let b denote a blue ball, and r denote a red ball. The first eight balls in the row will be bbbrrrrb, among which there are four blue balls.

Sample Input 2

8 0 4

Sample Output 2

0

He placed only red balls from the beginning.

Sample Input 3

6 2 4

Sample Output 3

2

Among bbrrrr, there are two blue balls.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>

using namespace std;

#define endl "\n"
//a#define ll unsigned long long
#define int long long int
#define vi vector <int >
#define vvi vector < vector < int >  >
#define vii vector < pii >
#define vll vector <ll >
#define pii pair <int, int>
#define pdd pair< double, double>
#define piii pair < pii, int > 
#define pll pair<ll, ll >
#define umap unordered_map
#define pb push_back
#define pq priority_queue
#define forn(i, n) for(int i = 0; i < (int)n; i++)
#define fore(i,c) for(int i = 1; i <= (int)c; i++)
#define rep(i,b,c) for(int i = (int)b; i < (int)c; i++)
//#define double long double
#define a first
#define b second


int32_t main(){
    ios::sync_with_stdio(0),cin.tie(0);

   int n, a, b;
   cin >> n >> a >> b;
   cout << a*(n/(a + b)) + min(a, n%(a + b)) << endl;

    return 0;
}