Problem:
Score : 200 points

Problem Statement

The postal code in Atcoder Kingdom is A+B+1 characters long, its (A+1)-th character is a hyphen -, and the other characters are digits from 0 through 9.

You are given a string S. Determine whether it follows the postal code format in Atcoder Kingdom.

Constraints

1≤A,B≤5

|S|=A+B+1

S consists of - and digits from 0 through 9.

Input

Input is given from Standard Input in the following format:

A B
S

Output

Print Yes if S follows the postal code format in AtCoder Kingdom; print No otherwise.

Sample Input 1

3 4
269-6650

Sample Output 1

Yes

The (A+1)-th character of S is -, and the other characters are digits from 0 through 9, so it follows the format.

Sample Input 2

1 1
---

Sample Output 2

No

S contains unnecessary -s other than the (A+1)-th character, so it does not follow the format.

Sample Input 3

1 2
7444

Sample Output 3

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#define _CRT_SECURE_NO_WARNINGS
#include<bits/stdc++.h>
using namespace std;
#define int long long
#ifndef FAST_IO
 #define IOS ios_base::sync_with_stdio(false),cin.tie(nullptr);
#endif
#define ff first
#define ss second
#define endl '\n'
#define all(c) c.begin(),c.end()
template<typename T>void print(T t){for(auto &it:t)cout<<it<<" "; cout<<endl;}
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
void solve(){
  int a,b;
  string s;
  cin>>a>>b>>s;
  bool ok=true;
  if(s[a]!='-'){cout<<"No"<<endl;return;}
  for(int i=0;i<(int)s.size();i++){
	     if(i==3)continue;
	     int val=(s[i]-'0');
	     if(val<0 or val>9){
			  ok=false;
			  break; 
			}
	 }
	cout<<(ok?"Yes":"No")<<endl;
}
int32_t main(){
  IOS;
  solve();
  //debug();
 #ifdef LOCAL_DEFINE
 cerr<<"time elapsed "<<(double)clock()/CLOCKS_PER_SEC<<endl;
 #endif	
}