Problem:
Score : 200 points

Problem Statement

You are given a image with a height of H pixels and a width of W pixels.
Each pixel is represented by a lowercase English letter.
The pixel at the i-th row from the top and j-th column from the left is a_{ij}.

Put a box around this image and output the result. The box should consist of # and have a thickness of 1.

Constraints

1 ≤ H, W ≤ 100

a_{ij} is a lowercase English letter.

Input

Input is given from Standard Input in the following format:

H W
a_{11} ... a_{1W}
:
a_{H1} ... a_{HW}

Output

Print the image surrounded by a box that consists of # and has a thickness of 1.

Sample Input 1

2 3
abc
arc

Sample Output 1

#####
#abc#
#arc#
#####

Sample Input 2

1 1
z

Sample Output 2

###
#z#
###

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <string>
#include <array>
#include <algorithm>
#include <vector>
#include <string>
#include <set>
#include <cctype>
#include <map>
#include <stdio.h>
#include <string.h>


#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")

#define int long long
#define FOR(i,l,r) for(size_t i=(l);i<(r);++i)
#define REP(i,n) FOR(i,0,n)

using namespace std;

signed main() {
    ios::sync_with_stdio(false);
    std::cin.tie(nullptr);

    int h,w;
    char a[101][101];
    cin >> h >> w;
    for(int i = 1; i <= h; i ++){
        for(int j = 1; j <= w; j ++){
            cin >> a[i][j]; 
        }
    }
    for(int i = 0; i <= h+1; i ++){
        for(int j = 0; j <= w+1; j ++){
            if(i == 0 || j == 0 || i == h+1 || j == w+1){
                cout << "#";
            }else{
                cout <<a[i][j];
            }
        }
    }
    return 0;
}