Problem:
Score : 200 points

Problem Statement

Find the largest square number not exceeding N. Here, a square number is an integer that can be represented as the square of an integer.

Constraints

1 \leq N \leq 10^9

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

Print the largest square number not exceeding N.

Sample Input 1

10

Sample Output 1

9

10 is not square, but 9 = 3 × 3 is. Thus, we print 9.

Sample Input 2

81

Sample Output 2

81

Sample Input 3

271828182

Sample Output 3

271821169

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <utility> // pair make_pair
using std::swap; // c++11
using std::pair;
using std::make_pair;
#include <tuple> // tuple(c++11) make_tuple(c++11)
using std::tuple; // get<address>(variable)
using std::make_tuple;
#include <string> // string stoi(c++11) stoll(c++11) to_string(c++11)
using std::string;
using std::stoi;
using std::stoll;
using std::to_string;
#include <queue> // queue priority_queue
using std::queue;
using std::priority_queue;
#include <stack> // stack
using std::stack;
#include <vector> // vector
using std::vector;
#include <map> // map
using std::map;
#include <set> // set
using std::set; // insert erase find count
#include <algorithm> // min max
using std::sort;
using std::lower_bound; // iterator,  >=
using std::upper_bound; // iterator,  >
using std::min;
using std::max;
using std::min_element; // iterator
using std::max_element; // iterator
#include <complex> // complex
using std::complex; // real imag
#include <iostream> // cin cout
using std::cin;
using std::cout;
using std::endl;
#include <iomanip> // setprecision fixed(manipulator)
using std::setprecision;
using std::fixed;
#include <cmath>
#include <cstdio>

#define lli long long int
#define INF (int)1e09
#define FOR(i, m, n) for (int i = m; i < n; i++)
#define EFOR(i, m, n) for (int i = m; i <= n; i++)
#define RFOR(i, m, n) for (int i = m; i > n; i--)
#define REFOR(i, m, n) for (int i = m; i >= n; i--)
#define VSORT(v) sort((v).begin(), (v).end()) // sort vector
typedef pair<int, int> PI;
typedef tuple<int, int, int> TI;
template <typename T> using Vec = vector<T>; // c++11

int main(void) {
    int n;
    cin >> n;
    int ans = (int)sqrt(n);
    cout << ans * ans << endl;
    return 0;
}