Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <algorithm>
#include <vector>
#include <unordered_map>
#include <unordered_set>
#include <cmath>
#include <cstdio>
#include <map>
#include <set>
#include <utility>
#include <string>
#include <functional>
#include <queue>
#include <stack>

using namespace std;

typedef long long ll;
typedef long double ld;

int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    int n, x, y, z;
    cin >> n;
    z = n;
    ll i;
    for(i = 1; i <= 1e7; i++) {
        ll num = i * n;
        ll den = n - 3 * i;
        if(den > 0 && num % den == 0) {
            x = i;
            y = num / den;
            break;
        }
    }
    cout << x << " " << y << " " << z;

    return 0;
}