Problem:
Score : 200 points

Problem Statement

We have N squares assigned the numbers 1,2,3,\ldots,N. Each square has an integer written on it, and the integer written on Square i is a_i.

How many squares i satisfy both of the following conditions?

The assigned number, i, is odd.

The written integer is odd.

Constraints

All values in input are integers.

1 \leq N, a_i \leq 100

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 \cdots a_N

Output

Print the number of squares that satisfy both of the conditions.

Sample Input 1

5
1 3 4 5 7

Sample Output 1

2

Two squares, Square 1 and 5, satisfy both of the conditions.

For Square 2 and 4, the assigned numbers are not odd.

For Square 3, the written integer is not odd.

Sample Input 2

15
13 76 46 15 50 98 93 77 31 43 84 90 6 24 14

Sample Output 2

3

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#define ll long long
#define pb push_back
#define mp make_pair
#define mt make_tuple
#define min_3(a,b,c) min(a,min(b,c))
#define max_3(a,b,c) max(a,max(b,c))
#define nout(ans) cout << (ans) << "\n"
#define sout(ans) cout << (ans) << " "
using namespace std;

const double pi = 3.14159265359;
const ll INF = 1e12;
const ll MOD = 1e9 + 7;
const ll N = 1e5 + 5; 
/*
Decimal Places: cout << fixed << setprecision(n) << ans << endl
*/

bool compare(const pair<int, int>&i, const pair<int, int>&j)
{
    return i.second < j.second;
}

ll raise(ll a, ll b) {
    ll res = 1;
    while (b > 0) {
        if (b & 1)
            res = res * a;
        a = a * a;
        b >>= 1;
    }
    return res;
}


int n, a[102], ans=0;

void solve()
{
    cin >> n;
    for (int i=0; i<n; i++) cin >> a[i];
    for (int i=0; i<n; i+=2) if (a[i]%2) ans++;
    nout(ans);
}

int main()
{
    ios_base::sync_with_stdio(false);
    cin.tie(NULL); cout.tie(NULL);
    int t = 1;
    //cin >> t;
    for (int i=1; i<=t; i++)
    {
        solve();
    }
    return 0;
}