Problem:
Score : 200 points

Problem Statement

A shop sells N kinds of fruits, Fruit 1, \ldots, N, at prices of p_1, \ldots, p_N yen per item, respectively. (Yen is the currency of Japan.)

Here, we will choose K kinds of fruits and buy one of each chosen kind. Find the minimum possible total price of those fruits.

Constraints

1 \leq K \leq N \leq 1000

1 \leq p_i \leq 1000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
p_1 p_2 \ldots p_N

Output

Print an integer representing the minimum possible total price of fruits.

Sample Input 1

5 3
50 100 80 120 80

Sample Output 1

210

This shop sells Fruit 1, 2, 3, 4, and 5 for 50 yen, 100 yen, 80 yen, 120 yen, and 80 yen, respectively.

The minimum total price for three kinds of fruits is 50 + 80 + 80 = 210 yen when choosing Fruit 1, 3, and 5.

Sample Input 2

1 1
1000

Sample Output 2

1000

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define fastIO ios::sync_with_stdio(0), cin.tie(0)
#define endl '\n'
#define ft first
#define sd second
#define pb push_back
#define pob pop_back()
#define pf push_front
#define pof pop_front()
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin, (x).rend()
typedef long long ll;
typedef pair<int,int> pii;
typedef pair<char,char> pcc;
typedef pair<long long,long long> pll;

int main(){
    int n,rta=0,k;
    cin >> n >> k;
    int arr[n];
    for(int i=0;i<n;i++){
        cin >> arr[i];
    }
    sort(arr,arr+n);
    for(int i=0;i<k;i++){
        rta+=arr[i];
    }
    cout << rta << endl;
  }