Problem:
Score : 400 points

Problem Statement

Let {\rm comb}(n,r) be the number of ways to choose r objects from among n objects, disregarding order.
From n non-negative integers a_1, a_2, ..., a_n, select two numbers a_i > a_j so that {\rm comb}(a_i,a_j) is maximized.
If there are multiple pairs that maximize the value, any of them is accepted.

Constraints

2 \leq n \leq 10^5

0 \leq a_i \leq 10^9

a_1,a_2,...,a_n are pairwise distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print a_i and a_j that you selected, with a space in between.

Sample Input 1

5
6 9 4 2 11

Sample Output 1

11 6

\rm{comb}(a_i,a_j) for each possible selection is as follows:

\rm{comb}(4,2)=6

\rm{comb}(6,2)=15

\rm{comb}(6,4)=15

\rm{comb}(9,2)=36

\rm{comb}(9,4)=126

\rm{comb}(9,6)=84

\rm{comb}(11,2)=55

\rm{comb}(11,4)=330

\rm{comb}(11,6)=462

\rm{comb}(11,9)=55

Thus, we should print 11 and 6.

Sample Input 2

2
100 0

Sample Output 2

100 0

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <algorithm>
#include <string>
#include <vector>
#include <iomanip>
#include <cmath>
#include <cstdlib>
#include <map>
#define ll long long
#define REP(i, x) for(int (i) = 0; (i) < (x); (i) ++)
#define pi 3.1415926535
const int MOD = 1000000007;
using namespace std;

int main() {
	int n, k;
	ll ans1, ans2;
	ll m = 10000000, num;
	cin >> n;
	vector<ll>a(n);
	REP(i, n) {
		cin >> a[i];
	}
	sort(a.begin(), a.end());
	ans1 = a[n - 1];
	num = (a[n - 1] + 1) / 2;
	REP(i, n) {
		ll l = abs(num - a[i]);
		if (l < m) {
			m = l;
			k = i;
		}
	}
	ans2 = a[k];
	cout << ans1 << " " << ans2 << endl;
	return 0;
}