Problem:
Score : 100 points

Problem Statement

Given are three integers A_1, A_2, and A_3.

If A_1+A_2+A_3 is greater than or equal to 22, print bust; otherwise, print win.

Constraints

1 \leq A_i \leq 13 \ \ (i=1,2,3)

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

If A_1+A_2+A_3 is greater than or equal to 22, print bust; otherwise, print win.

Sample Input 1

5 7 9

Sample Output 1

win

5+7+9=21, so print win.

Sample Input 2

13 7 2

Sample Output 2

bust

13+7+2=22, so print bust.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

/*dismint|jjc*/
#include <bits/stdc++.h>
using namespace std;
#define forl(V, S, E) for(int V = S; V < E; V++)
#define ford(V, S, E) for(int V = S; V >= E; V--)
#define fore(E, X) for(auto &E:X)
#define println(X) cout << X << endl
#define printe(X) for(auto &E:X) cout << E << " "; cout << endl
typedef unordered_map<int, unordered_set<int>> graph;
typedef long long ll;

int main() {
	ios_base::sync_with_stdio(false); cin.tie(NULL);
	int a, b, c; cin >> a >> b >> c;
	if(a+b+c >= 22) println("bust");
	else println("win");
}