Problem:
Score : 100 points

Problem Statement

There is a grid with H rows and W columns.

The square at the i-th row and j-th column contains a string S_{i,j} of length 5.

The rows are labeled with the numbers from 1 through H, and the columns are labeled with the uppercase English letters from A through the W-th letter of the alphabet.

Exactly one of the squares in the grid contains the string snuke. Find this square and report its location.

For example, the square at the 6-th row and 8-th column should be reported as H6.

Constraints

1≦H, W≦26

The length of S_{i,j} is 5.

S_{i,j} consists of lowercase English letters (a-z).

Exactly one of the given strings is equal to snuke.

Input

The input is given from Standard Input in the following format:

H W
S_{1,1} S_{1,2} ... S_{1,W}
S_{2,1} S_{2,2} ... S_{2,W}
:
S_{H,1} S_{H,2} ... S_{H,W}

Output

Print the labels of the row and the column of the square containing the string snuke, with no space inbetween.

Sample Input 1

15 10
snake snake snake snake snake snake snake snake snake snake
snake snake snake snake snake snake snake snake snake snake
snake snake snake snake snake snake snake snake snake snake
snake snake snake snake snake snake snake snake snake snake
snake snake snake snake snake snake snake snake snake snake
snake snake snake snake snake snake snake snuke snake snake
snake snake snake snake snake snake snake snake snake snake
snake snake snake snake snake snake snake snake snake snake
snake snake snake snake snake snake snake snake snake snake
snake snake snake snake snake snake snake snake snake snake
snake snake snake snake snake snake snake snake snake snake
snake snake snake snake snake snake snake snake snake snake
snake snake snake snake snake snake snake snake snake snake
snake snake snake snake snake snake snake snake snake snake
snake snake snake snake snake snake snake snake snake snake

Sample Output 1

H6

Sample Input 2

1 1
snuke

Sample Output 2

A1

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#include <regex>
using namespace std;

//type
typedef long long int ll;
typedef pair<int, int> P;
//定数
#define INF 1000000000000 //10^12:∞
#define MOD 1000000007    //10^9+7:合同式の法
#define MAXR 100000       //10^5:配列の最大のrange
#define PI 3.14159265358979323846264338327950L
//略記
#define PB push_back //挿入
#define MP make_pair //pairのコンストラクタ
#define F first      //pairの一つ目の要素
#define S second     //pairの二つ目の要素
#define Z class

// input
#define INIT                          \
    std::ios::sync_with_stdio(false); \
    std::cin.tie(0);
#define VAR(type, ...) \
    type __VA_ARGS__;  \
    MACRO_VAR_Scan(__VA_ARGS__);
template <typename T>
void MACRO_VAR_Scan(T &t)
{
    std::cin >> t;
}
template <typename First, typename... Rest>
void MACRO_VAR_Scan(First &first, Rest &... rest)
{
    std::cin >> first;
    MACRO_VAR_Scan(rest...);
}
#define VEC_ROW(type, n, ...)                \
    std::vector<type> __VA_ARGS__;           \
    MACRO_VEC_ROW_Init(n, __VA_ARGS__);      \
    for (int w_ = 0; w_ < n; ++w_)           \
    {                                        \
        MACRO_VEC_ROW_Scan(w_, __VA_ARGS__); \
    }
template <typename T>
void MACRO_VEC_ROW_Init(int n, T &t)
{
    t.resize(n);
}
template <typename First, typename... Rest>
void MACRO_VEC_ROW_Init(int n, First &first, Rest &... rest)
{
    first.resize(n);
    MACRO_VEC_ROW_Init(n, rest...);
}
template <typename T>
void MACRO_VEC_ROW_Scan(int p, T &t) { std::cin >> t[p]; }
template <typename First, typename... Rest>
void MACRO_VEC_ROW_Scan(int p, First &first, Rest &... rest)
{
    std::cin >> first[p];
    MACRO_VEC_ROW_Scan(p, rest...);
}
#define VEC(type, c, n)     \
    std::vector<type> c(n); \
    for (auto &i : c)       \
        std::cin >> i;
// 2d vector:  MAT(type, v, size, size);
#define MAT(type, c, m, n)                                     \
    std::vector<std::vector<type>> c(m, std::vector<type>(n)); \
    for (auto &R : c)                                          \
        for (auto &w : R)                                      \
            std::cin >> w;

// output
template <typename T>
void MACRO_OUT(const T t) { std::cout << t; }

#define OUT(...) MACRO_OUT(__VA_ARGS__);
#define SP std::cout << " ";
#define TAB std::cout << "\t";
#define BR std::cout << "\n";
#define ENDL std::cout << std::endl;

#define YES() printf("YES\n")
#define NO() printf("NO\n")
#define isYES(x) printf("%s\n", (x) ? "YES" : "NO")
#define Yes() printf("Yes\n")
#define No() printf("No\n")
#define yes() printf("yes\n")
#define no() printf("no\n")
#define ln cout << '\n'
template <Z A>
void pr(A a)
{
    cout << a;
    ln;
}
template <Z A, Z B>
void pr(A a, B b)
{
    cout << a << ' ' << b << endl;
}

// OTHER
// xの二乗を返す (関数テンプレート版)
template <typename T>
T square(T x) { return x * x; }
ll gcd(ll a, ll b)
{
    while (b)
    {
        ll c = b;
        b = a % b;
        a = c;
    }
    return a;
}
ll lcm(ll a, ll b)
{
    if (!a || !b)
        return 0;
    return a * b / gcd(a, b);
}

#define chmax(x, y) (x = max(x, y))
#define chmin(x, y) (x = min(x, y))
// loop
#define rep(i, n) for (ll i = 0; i < (n); i++)
#define repe(i, n) for (ll i = 0; i <= (n); i++)
#define repd(i, n) for (ll i = n; i > 0; i--)
#define repde(i, n) for (ll i = n; i >= 0; i--)
#define FOR(i, a, b) for (ll i = a; i < (b); i++)
#define FORE(i, a, b) for (ll i = a; i <= (b); i++)
#define FORD(i, a, b) for (ll i = a; i >= (b); i--)
#define FORA(i, I) for (const auto &i : I)

// vector
#define ALL(x) x.begin(), x.end()
#define ALLR(x) x.end(), x.begin()
typedef vector<int> vi;
typedef vector<string> vs;
typedef vector<bool> vb;
typedef vector<vi> vvi;
typedef vector<ll> vl;
#define ERASE(x) x.erase(unique(ALL(x)), x.end()); // erase same elements
#define sz(x) (int)(x).size()
bool yes = 0;
bool boo = 0;
double mx = -100000;
int mn = 1001001001;
int sum = 0;
ll ans = 0;
int co = 0;
int abc[26];
bool OK = false;

// * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *
// * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *
// cout << (conditon ? (result:  == 1 ): (==0)) << endl; <- output result of if
// long long 型が表せる値の上限はおよそ 9 × 10＾18 です．

// vector
// sum: accumulate(ALl(x),0)
// return last element: v.back();
//  i & 1 は偶数なら 0に 奇数なら1に

// sort (descending order) :  sort(arr, arr+n, greater<int>());
// sort indescending order: sort(ALL())-> reverse(ALL())
// (string): sort(all(t),greater<char>()); (string t )

// string
// strncmp: ompare characters of two string *長さ指定 strcmp(s1,s2,length)
// <0:s1<s2  （s１が辞書早い） | 0:s1==s2 | >0:s1>s2

// 三角形 ABC について，a^2 = b^2+c^2−2bc cos ∠A
int main()
{

    VAR(int, h, w);
    string s[h][w];
    rep(i, h)
    {
        rep(j, w)
        {
            cin >> s[i][j];
            if (s[i][j] == "snuke")
            {
                cout << (char)('A' + j) << i + 1 << endl;
                return 0;
            }
        }
    }
}