Problem:
Disjoint Set

Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.

same(x, y): determine whether x and y are in the same set.

Input

n q
com1 x1 y1
com2 x2 y2
...
comq xq yq

In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Constraints

1 ≤ n ≤ 10000

1 ≤ q ≤ 100000

x ≠ y

Sample Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0

Sample Output

0
0
1
1
1
0
1
1

Solution in C++14 (judge verdict: Accepted)

#include <bits/stdc++.h>
#define REP(i, n) for(int i = 0; i < n; ++i)
#define REPP(i, n) for(int i = 1; i <= n; ++i)
#define REPR(i, n) for(int i = n-1; i >= 0; --i)
#define FOR(i, m, n) for(int i = m; i < n; ++i)
#define ALL(v) v.begin(), v.end()
#define UNIQUE(v) v.erase(unique(v.begin(), v.end()), v.end());
using namespace std;
typedef long long ll;
typedef pair<ll, ll> P;
const ll MOD = 1000000007;
const ll INF = 1000000000;

template<typename T1,typename T2> inline void chmin(T1 &a,T2 b) {if(a>b) a=b;}
template<typename T1,typename T2> inline void chmax(T1 &a,T2 b) {if(a<b) a=b;}

struct UnionFind {
    vector<int> par, size;
    UnionFind(int n) : par(n), size(n,1) {
        for(int i = 0; i < n; ++i) par[i] = i;
    }
    void Union(int x, int y) {
        x = Find(x), y = Find(y);
        if(x == y) return;
        if(size[x] < size[y]) swap(x,y);
        size[x] += size[y];
        par[y] = x;
    }
    int Find(int x) {
        if(par[x]==x) return x;
        else return par[x] = Find(par[x]);
    }
    bool Same(int x, int y) {
        return Find(x) == Find(y);
    }
    int Size(int x) {
        return size[Find(x)];
    }
};

int main() {
    cin.tie(0);
    ios::sync_with_stdio(false);
    int n,q; cin >> n >> q;
    UnionFind uf(n);
    REP(i,q) {
        bool query; cin >> query;
        int x,y; cin >> x >> y;
        if(query) {
            cout << (uf.Same(x,y) ? 1 : 0) << endl;
        }
        else uf.Union(x,y);
    }
    return 0;
}