Problem:
Score : 100 points

Problem Statement

Takahashi is a member of a programming competition site, ButCoder.

Each member of ButCoder is assigned two values: Inner Rating and Displayed Rating.

The Displayed Rating of a member is equal to their Inner Rating if the member has participated in 10 or more contests. Otherwise, the Displayed Rating will be their Inner Rating minus 100 \times (10 - K) when the member has participated in K contests.

Takahashi has participated in N contests, and his Displayed Rating is R. Find his Inner Rating.

Constraints

All values in input are integers.

1 \leq N \leq 100

0 \leq R \leq 4111

Input

Input is given from Standard Input in the following format:

N R

Output

Print his Inner Rating.

Sample Input 1

2 2919

Sample Output 1

3719

Takahashi has participated in 2 contests, which is less than 10, so his Displayed Rating is his Inner Rating minus 100 \times (10 - 2) = 800.

Thus, Takahashi's Inner Rating is 2919 + 800 = 3719.

Sample Input 2

22 3051

Sample Output 2

3051

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <string>
#include <vector>
#include <algorithm>
#include <cmath>
#include <iomanip>
#include <cctype>
#define len length()
#define sz size()
#define rng(i, a, b) for(int i = a; i < b; i++)
#define rep(i, n) rng(i, 0, n)
#define srt(v) sort(v.begin(), v.end())
#define rev(s) reverse(s.begin(), s.end())
#define vi(a, n) vector<int> a(n)
#define vs(a, n) vector<string> a(n)
#define vc(a, n) vector<char> a(n)
#define psb(a) push_back(a)
#define ppb pop_back()
#define erc(S, i) S.erase(S.begin() + i)
#define ers(S, i, j) S.erase(S.begin() + i, S.begin() + j)
#define sp(n) cout << setprecision(n) << fixed
#define fst(s) s.at(0)
#define lst(s) s.at(s.len - 1)
typedef long long ll;
using namespace std;
int mod = 1000000007;

int main(){
    int n, r;
    cin >> n >> r;
    if(n>9) cout << r << endl;
    else{
        cout << r + (100*(10-n)) << endl;
    }
    return 0;
}