Problem:
Score : 200 points

Problem Statement

A shop sells N kinds of fruits, Fruit 1, \ldots, N, at prices of p_1, \ldots, p_N yen per item, respectively. (Yen is the currency of Japan.)

Here, we will choose K kinds of fruits and buy one of each chosen kind. Find the minimum possible total price of those fruits.

Constraints

1 \leq K \leq N \leq 1000

1 \leq p_i \leq 1000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
p_1 p_2 \ldots p_N

Output

Print an integer representing the minimum possible total price of fruits.

Sample Input 1

5 3
50 100 80 120 80

Sample Output 1

210

This shop sells Fruit 1, 2, 3, 4, and 5 for 50 yen, 100 yen, 80 yen, 120 yen, and 80 yen, respectively.

The minimum total price for three kinds of fruits is 50 + 80 + 80 = 210 yen when choosing Fruit 1, 3, and 5.

Sample Input 2

1 1
1000

Sample Output 2

1000

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
 
using namespace std;

void input()
{
    #ifndef ONLINE_JUDGE
    freopen("input.txt","r",stdin);freopen("output.txt","w",stdout);
    #endif
}
#define endl "\n"
#define ll long long int
#define vll vector<ll>
#define pb push_back
#define pll pair<ll,ll>
#define mp(a,b) make_pair(a,b)
#define ff first
#define ss second
#define tll tuple<ll,ll,ll>
#define mt make_tuple
#define INF LONG_LONG_MAX
#define mod 1000000007
#define rep(i,a,b) for(ll i=a;i<b;i++)
#define rrep(i,a,b) for(ll i=a;i>=b;i--)
#define cases ll t; cin>>t; while(t--)
#define array(a,n) vll a(n); rep(i,0,n) cin>>a[i];
#define sortall(a) sort(a.begin(),a.end())
#define printall(a) rep(i,0,a.size()) cout<<a[i]<<" "; cout<<endl;

// --------------- My Template End --------------- //
bool isprime(ll n)
{
    if(n%2==0)return false;
    for(int i=3;i<=sqrt(n);i+=2)
    {
        if(n%i==0)return false;
    }
    return true;
}

int main()
{
    ios_base::sync_with_stdio(0);
    cin.tie(0); cout.tie(0);
//    input();
    ll n,ans=0,k;
    cin>>n>>k;
    array(a,n);
    sortall(a);
    rep(i,0,k)
    {
    	ans+=a[i];
    }
    cout<<ans<<endl;
}