Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define ll long long int
int main() {
	// your code goes here
	string s;
	cin>>s;
	ll a[4];
	for(ll i=0;i<4;i++)
	{
		a[i]=s[i]-'0';
	}
	ll x=a[0]*10+a[1];
	ll y=a[2]*10+a[3];
	if(x==0 && y>12)
	{
		cout<<"NA";
		exit(0);
	}
	if(y==0 && x>12)
	{
		cout<<"NA";
		exit(0);
	}
	if(x==0 && y==0)
	{
		cout<<"NA";
		exit(0);
	}
	if(x>12 && y>12)
	{
		cout<<"NA";
		exit(0);
	}
	if(x==0 && y<13)
	{
		cout<<"YYMM";
		exit(0);
	}
	if(x<13 && y==0)
	{
		cout<<"MMYY";
		exit(0);
	}
	if(x<13 && y<13)
	{
		cout<<"AMBIGUOUS";
		exit(0);
	}
	if(x<13 && y>12)
	{
		cout<<"MMYY";
		exit(0);
	}
	if(x>12 && y<13)
	{
		cout<<"YYMM";
		exit(0);
	}
	
}