Problem:
Score : 200 points

Problem Statement

An integer X is called a Harshad number if X is divisible by f(X), where f(X) is the sum of the digits in X when written in base 10.

Given an integer N, determine whether it is a Harshad number.

Constraints

1?N?10^8

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

Print Yes if N is a Harshad number; print No otherwise.

Sample Input 1

12

Sample Output 1

Yes

f(12)=1+2=3. Since 12 is divisible by 3, 12 is a Harshad number.

Sample Input 2

57

Sample Output 2

No

f(57)=5+7=12. Since 57 is not divisible by 12, 12 is not a Harshad number.

Sample Input 3

148

Sample Output 3

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<iostream>
#include<string>
#include<math.h>
#include<vector>
#include<algorithm>
#include<iomanip>
#include<stack>

#define ll long long
#define vl vector<ll>
#define vvl vector< vector<ll> >
#define vb vector<bool>
#define vbb vector< vector<bool> >
#define vs vector<string>
#define vc vector<char>
#define vvc vector< vector<char> >

#define all(a) (a).begin(),(a).end()
#define rall(a) (a).rbegin(),(a).rend()

using namespace std;

ll sumdigit(ll n){
	string s = to_string(n);
	ll ret = 0;
	for (char c : s) ret += c - '0';
	return ret;
}

int main(){
	ll n; cin >> n;
	ll nd = sumdigit(n);
	if (n % nd) cout << "Yes" << endl;
	else cout << "No" << endl;
	return 0;
}