Problem:
Score : 300 points

Problem Statement

You are given three integers A, B and C. Find the minimum number of operations required to make A, B and C all equal by repeatedly performing the following two kinds of operations in any order:

Choose two among A, B and C, then increase both by 1.

Choose one among A, B and C, then increase it by 2.

It can be proved that we can always make A, B and C all equal by repeatedly performing these operations.

Constraints

0 \leq A,B,C \leq 50

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B C

Output

Print the minimum number of operations required to make A, B and C all equal.

Sample Input 1

2 5 4

Sample Output 1

2

We can make A, B and C all equal by the following operations:

Increase A and C by 1. Now, A, B, C are 3, 5, 5, respectively.

Increase A by 2. Now, A, B, C are 5, 5, 5, respectively.

Sample Input 2

2 6 3

Sample Output 2

5

Sample Input 3

31 41 5

Sample Output 3

23

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#define rep(i,a,b) for(int i=a;i<b;i++)
#define rrep(i,b,a) for(int i=b;i>=a;i--)
#define fori(a) for(auto i : a )
#define all(a) begin(a), end(a)
#define set(a,b) memset(a,b,sizeof(a))
#define sz(a) a.size()
#define pi 3.14159
#define ll long long
#define ull unsigned long long
#define pb push_back
#define PF push_front //deque
#define mp make_pair
#define pq priority_queue
#define mod 1000000007
#define f first
#define s second
#define pii pair< int, int >
#define vi vector<int>
#define vpii vector<pii>
#define debug(v) for(auto i:v) cout<<i<<" ";
#define tc int t; cin >> t; while(t--)

using namespace std;
string repeat(string s, int n) {
    string s1 = "";
    for (int i=0; i<n;i++)
        s1+=s;
    return s1;
}
string getString(char x) {
    string s(1, x);
    return s;
}

void optimizeIO(){
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    cout.tie(NULL);
}
int gcd(int a, int b){
    if (a == 0)  return b;
    return gcd(b % a, a);
}
void solve(){
  int a,b,c;
  cin>>a>>b>>c;
  vector<int> v1={a,b,c};
  sort(all(v1));
  if(a==b && b==c){
    cout<<0<<endl;return ;
  }
  int  ans=0;
  int x= (v1[1]-v1[0])/2;
  v1[0]=v1[0]+ x*2;
  ans+=x;
  if(v1[0]==v1[1]){
    cout<<ans+(v1[2]-v1[1])<<endl;
  }
  else{
    cout<<ans+(v1[2]-v1[1])+2<<endl;
  }
}
int main(){
    optimizeIO();
    // tc
    { solve();
    }
}