Problem:
Score : 200 points

Problem Statement

Given are two strings S and T.

Let us change some of the characters in S so that T will be a substring of S.

At least how many characters do we need to change?

Here, a substring is a consecutive subsequence. For example, xxx is a substring of yxxxy, but not a substring of xxyxx.

Constraints

The lengths of S and T are each at least 1 and at most 1000.

The length of T is at most that of S.

S and T consist of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

Print the minimum number of characters in S that need to be changed.

Sample Input 1

cabacc
abc

Sample Output 1

1

For example, changing the fourth character a in S to c will match the second through fourth characters in S to T.

Since S itself does not have T as its substring, this number of changes - one - is the minimum needed.

Sample Input 2

codeforces
atcoder

Sample Output 2

6

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#define rep(i,a,b) for(int i = (a); i <= (b); i++)
#define rng(a) a.begin(), a.end()
#define ina(n,a) cin >> n; for(int i = 1; i <= n; i++) cin >> a[i]
#define sz(x) (int)(x).size()
#define se second
#define fi first
#define prev            coyhhhhhhyoc    
#define next          sdNNNmNNNNNNNmds  
#define y0           hNNNNy_yNNNNNN_sNh
#define y1          mNNNNNdtdNNNNNNtsNNm
#define yn          mNNNNNNNNy___smNNNms
#define tm            oooooosyysooooot 
#define read               tyhyt        
#define rank              ytmNmo         
#define index              yyy
#define pb push_back
#define pcnt __builtin_popcountll
#define rrep(i,a,b) for(int i = (b); i >= (a); i--)
#define rall(x,a) for(auto x : a)
#define MOD 1000000007
#define endl "\n"
typedef long long ll;
using namespace std;

int solve() {
    string s, t;
    cin >> s >> t;
    int n = sz(s), m = sz(t);
    int ans = 1e9;
    rep(i, 0, n - m) {
        int cur = 0;
        rep(j, 0, m - 1) {
            cur += s[i + j] != t[j];
        }
        ans = min(ans, cur);
    }
    cout << ans << endl;
    return 0;
}

signed main() {
    ios_base::sync_with_stdio(false);
    cin.tie(0);
    int t = 1;
    while(t--) {
        solve();
    }
    return 0;
}