Problem:
Score : 300 points

Problem Statement

There are N people living on a number line.

The i-th person lives at coordinate X_i.

You are going to hold a meeting that all N people have to attend.

The meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.

Find the minimum total points of stamina the N people have to spend.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq X_i \leq 100

Input

Input is given from Standard Input in the following format:

N
X_1 X_2 ... X_N

Output

Print the minimum total stamina the N people have to spend.

Sample Input 1

2
1 4

Sample Output 1

5

Assume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.

Note that you can hold the meeting only at an integer coordinate.

Sample Input 2

7
14 14 2 13 56 2 37

Sample Output 2

2354

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<iostream>

using namespace std;

int main() {
    int n;
    cin >> n;
    int x[n];
    for(int i = 0; i < n; i++) {
        cin >> x[i];
    }
    for(int i = 0; i < n - 1; i++) {
        int min = i;
        for(int j = i + 1; j < n; j++) {
            if(x[j] < x[min]) {
                min = j;
            }
        }
        int tmp = x[min];
        x[min] = x[i];
        x[i] = tmp;
    }

    int p = 0;
    /*
    if(n % 2 == 0) {
        p = x[n/2 - 1] + x[n/2];
        p /= 2;
    } else {
        p = x[n/2];
    }*/
    for(int i = 0; i < n; i++) {
        p += x[i];
    }
    if(p % n != 0) {
        p /= n;
        p++;
        cout << "a" << endl;
    } else {
        p /= n;
    }
    cout << "P:" << p << endl;
    int res = 0;
    for(int i = 0; i < n; i++) {
        res += (x[i] - p) * (x[i] - p);
    }
    cout << res << endl;
    return 0;
}