Problem:
Score : 300 points

Problem Statement

Sitting in a station waiting room, Joisino is gazing at her train ticket.

The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).

In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.

The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Constraints

0≤A,B,C,D≤9

All input values are integers.

It is guaranteed that there is a solution.

Input

Input is given from Standard Input in the following format:

ABCD

Output

Print the formula you made, including the part =7.

Use the signs + and -.

Do not print a space between a digit and a sign.

Sample Input 1

1222

Sample Output 1

1+2+2+2=7

This is the only valid solution.

Sample Input 2

0290

Sample Output 2

0-2+9+0=7

0 - 2 + 9 - 0 = 7 is also a valid solution.

Sample Input 3

3242

Sample Output 3

3+2+4-2=7

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
#include<stdlib.h>
#include<iostream>
#include<string>
#include<algorithm>
#include<vector> 
#include<limits>
#include<numeric>
#include<type_traits>
#include<math.h>
using namespace std;

#define rep(i, n) for(int i = 0; i < (int)(n); i++)
#define repi(i,a,b) for(int i = (int)(a); i < (int)(b); i++)
#define in(x) cin >> x
#define out(str) cout << str << endl

template<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }
template<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }

string S;

int main(){
    cin>>S;
    int A,B,C,D;
    A=(int)S[0];
    B=(int)S[1];
    C=(int)S[2];
    D=(int)S[3];
    if(A+B+C+D==7){printf("%d+%d+%d+%d\n",A,B,C,D);}
    else if(A+B+C-D==7){printf("%d+%d+%d-%d\n",A,B,C,D);}
    else if(A+B-C+D==7){printf("%d+%d-%d+%d\n",A,B,C,D);}
    else if(A+B-C-D==7){printf("%d+%d-%d-%d\n",A,B,C,D);}
    else if(A-B+C+D==7){printf("%d-%d+%d+%d\n",A,B,C,D);}
    else if(A-B+C-D==7){printf("%d-%d+%d-%d\n",A,B,C,D);}
    else if(A-B-C+D==7){printf("%d-%d-%d+%d\n",A,B,C,D);}
    else if(A-B-C-D==7){printf("%d-%d-%d-%d\n",A,B,C,D);}
}