Problem:
Score : 200 points

Problem Statement

Let us define the FizzBuzz sequence a_1,a_2,... as follows:

If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.

If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.

If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.

If none of the above holds, a_i=i.

Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Constraints

1 \leq N \leq 10^6

Input

Input is given from Standard Input in the following format:

N

Output

Print the sum of all numbers among the first N terms of the FizzBuzz sequence.

Sample Input 1

15

Sample Output 1

60

The first 15 terms of the FizzBuzz sequence are:

1,2,\mbox{Fizz},4,\mbox{Buzz},\mbox{Fizz},7,8,\mbox{Fizz},\mbox{Buzz},11,\mbox{Fizz},13,14,\mbox{FizzBuzz}

Among them, numbers are 1,2,4,7,8,11,13,14, and the sum of them is 60.

Sample Input 2

1000000

Sample Output 2

266666333332

Watch out for overflow.

Solution in C++ (Clang 10.0.0) (judge verdict: Accepted)

#include <algorithm>
#include <bitset>
#include <cmath>
#include <ctime>
#include <iostream>
#include <list>
#include <map>
#include <math.h>
#include <numeric>
#include <queue>
#include <set>
#include <stack>
#include <stdio.h>
#include <string>
#include <vector>
#define rep(i,n) for(int i = 0; i < (n); i++)
#define all(a) a.begin(),a.end()
using namespace std;
using ll = long long;
using P = pair<int,int>;
using vi = vector<int>;
using vvi = vector<vi>;

template <typename T>
bool chmax(T &a, T &b) {
  if(a < b) {
    a = b;
    return true;
  }
  return false;
}

template <typename T>
bool chmin(T &a, T &b) {
  if(a > b) {
    a = b;
    return true;
  }
  return false;
}

int cans(bool f){
  if(f) cout << "Yes" << endl;
  else cout << "No" << endl;
  return 0;
}

int main(){
  int N;
  cin >> N;
  ll sum=0;
  for(int i=1; i<=N; i++) {
    if(i % 3 == 0 || i % 5 == 0) continue;
    sum += i;
  }
  cout << sum << endl;
}