Problem:
Score : 100 points

Problem Statement

You have three tasks, all of which need to be completed.

First, you can complete any one task at cost 0.

Then, just after completing the i-th task, you can complete the j-th task at cost |A_j - A_i|.

Here, |x| denotes the absolute value of x.

Find the minimum total cost required to complete all the task.

Constraints

All values in input are integers.

1 \leq A_1, A_2, A_3 \leq 100

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

Print the minimum total cost required to complete all the task.

Sample Input 1

1 6 3

Sample Output 1

5

When the tasks are completed in the following order, the total cost will be 5, which is the minimum:

Complete the first task at cost 0.

Complete the third task at cost 2.

Complete the second task at cost 3.

Sample Input 2

11 5 5

Sample Output 2

6

Sample Input 3

100 100 100

Sample Output 3

0

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <cstdio>
#include <cstring>
#include <cctype>
#include <cassert>
#include <iostream>
using std::cin; using std::cout; using std::endl;
#include <algorithm>
using std::sort; using std::min; using std::max;
#include <vector>
using std::vector;
#include <set>
using std::set;
#include <queue>
using std::queue; using std::priority_queue;
#include <utility>
using std::pair;
typedef pair<int, int> pii;
typedef long long LL;
typedef long double LD;
#define pass printf("%s : Line.%d\n", __FUNCTION__, __LINE__);
int a[3];
int main() {
	cin >> a[0] >> a[1] >> a[2];
	std::sort(a, a+3);
	int ans = 0;
	ans += a[2] - a[0];
	printf("%d\n", ans);
	return 0;
}