Problem:
Score : 300 points

Problem Statement

1000000000000001 dogs suddenly appeared under the roof of Roger's house, all of which he decided to keep. The dogs had been numbered 1 through 1000000000000001, but he gave them new names, as follows:

the dogs numbered 1,2,\cdots,26 were respectively given the names a, b, ..., z;

the dogs numbered 27,28,29,\cdots,701,702 were respectively given the names aa, ab, ac, ..., zy, zz;

the dogs numbered 703,704,705,\cdots,18277,18278 were respectively given the names aaa, aab, aac, ..., zzy, zzz;

the dogs numbered 18279,18280,18281,\cdots,475253,475254 were respectively given the names aaaa, aaab, aaac, ..., zzzy, zzzz;

the dogs numbered 475255,475256,\cdots were respectively given the names aaaaa, aaaab, ...;

and so on.

To sum it up, the dogs numbered 1, 2, \cdots were respectively given the following names:

a, b, ..., z, aa, ab, ..., az, ba, bb, ..., bz, ..., za, zb, ..., zz, aaa, aab, ..., aaz, aba, abb, ..., abz, ..., zzz, aaaa, ...

Now, Roger asks you:

"What is the name for the dog numbered N?"

Constraints

N is an integer.

1 \leq N \leq 1000000000000001

Input

Input is given from Standard Input in the following format:

N

Output

Print the answer to Roger's question as a string consisting of lowercase English letters.

Sample Input 1

2

Sample Output 1

b

Sample Input 2

27

Sample Output 2

aa

Sample Input 3

123456789

Sample Output 3

jjddja

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
//#include <string>
using namespace std;


#define typeof(x) __typeof__(x)
#define bit(x,i) (x&(1<<i))  //select the bit of position i of x
#define lowbit(x) ((x)&((x)^((x)-1))) //get the lowest bit of x
#define hBit(msb,n) asm("bsrl %1,%0" : "=r"(msb) : "r"(n)) //get the highest bit of x, maybe the fastest
#define max(a,b) (a<b?b:a)
//#define abs(x) (x<0?(-x):x) // big bug here if "-x" is not surrounded by "()"
#define IN(i,l,r) (l<i&&i<r) //the next for are for checking bound
#define LINR(i,l,r) (l<=i&&i<=r)
#define LIN(i,l,r) (l<=i&&i<r)
#define INR(i,l,r) (l<i&&i<=r)
#define F(i,L,R) for (int i = L; i < R; i++) //next four are for "for loops"
#define FIN(i,L,R) for (int i = L; i <= R; i++)
#define FF(i,L,R) for (int i = L; i > R; i--)
#define FFIN(i,L,R) for (int i = L; i >= R; i--)
#define getI(a) scanf("%d", &a) //next three are handy ways to get ints, it's also force you to use '&' sign
#define getII(a,b) scanf("%d%d", &a, &b)
#define getIII(a,b,c) scanf("%d%d%d", &a, &b, &c)
#define g_s(n) int (n); scanf("%d",&(n)) //handy if the input is right after the definition of a variable
#define g_s2(n,m) int (n),(m); scanf("%d %d",&(n),&(m))
#define g_s3(n,m,k) int (n),(m),(k); scanf("%d %d %d",&(n),&(m),&(k))
#define TESTS g_s(testow);while(testow--) //for multilple cases problems
#define whileZ int T; getI(T); while(T--) // the same as above
#define getS(x) scanf("%s", x) //get a char* string
#define MEM(a,x) memset(a,x,sizeof(a)) //set elements of array to some value
#define char2Int(c) (c-'0')
#define lastEle(vec) vec[vec.size()-1]
#define SZ(x) ((int)((x).size()))
#define REMAX(a,b) (a)=max((a),(b)) // set a to the maximum of a and b
#define REMIN(a,b) (a)=min((a),(b));
#define FOREACH(i,t) for (typeof(t.begin()) i=t.begin(); i!=t.end(); i++) // traverse an STL data structure
#define ALL(c) (c).begin(),(c).end() //handy for function like "sort()"
#define PRESENT(c,x) ((c).find(x) != (c).end())
#define CPRESENT(c,x) (find(ALL(c),x) != (c).end())
#define ll long long //data types used often, but you don't want to type them time by time
#define ull unsigned long long
#define ui unsigned int
#define us unsigned short
#define IOS ios_base::sync_with_stdio(0); //to synchronize the input of cin and scanf
#define INF 1001001001
#define PI 3.1415926535897932384626
//for map, pair
#define mp make_pair
#define fi first
#define se second
// for debug
inline void pisz(int n) { printf("%d\n",n); }
#define DBG(vari) cerr<<#vari<<" = "<<(vari)<<endl;
#define printA(a,L,R) FIN(jk,L,R) cout << a[jk] << (jk==R?'\n':' ')
#define printV(a) printA(a,0,a.size()-1)
#define MAXN 10000
#define sf scanf
#define pf printf
//for vectors
#define pb push_back
typedef int elem_t;
typedef vector<int> vi;
typedef vector<string> vstr;
typedef vector<set<int> > vset;
typedef vector<vi> vvi;
typedef vector<bool> vb;
typedef vector<vector<bool> > vvb;
typedef pair<int,int> ii;
typedef vector<ii> vii;
// directions
const int dr[4] = {-1,0,1,0};
const int dc[4] = {0,-1,0,1};
const int drr[8] = {-1,-1,0,1,1,1,0,-1};
const int dcc[8] = {0,-1,-1,-1,0,1,1,1};
template<typename T,typename TT> ostream& operator<<(ostream &s,pair<T,TT> t) {return s<<"("<<t.first<<","<<t.second<<")";}
template<typename T> ostream& operator<<(ostream &s,vector<T> t){F(i,0,SZ(t))s<<t[i]<<" ";return s; }

bool ckmin(int& a, int b){ return b < a ? a = b, true : false; }
bool ckmax(int& a, int b){ return b > a ? a = b, true : false; }

class UnionFind{
    private: vi rank,p;
    public: 
        UnionFind(int n){
            F(i,0,n)p.pb(i);
            rank.assign(n,1);
        }

        int findSet(int s){
            return (p[s]==s) ? s : (p[s]=findSet(p[s]));
        }

        bool isSameSet(int i,int j){
            return findSet(i)==findSet(j);
        }

        void unionSet(int i,int j){
            if(isSameSet(i,j))return;

            int x=findSet(i),y=findSet(j);
            if(rank[x]>rank[y]){
                p[y]=x;
                rank[x]+=rank[y];
            }
            else {
                p[x]=y;
                //if(rank[x]==rank[y])rank[y]++;
                rank[y] += rank[x];
            }
            
        }

        int sz(int x){
            int px=findSet(x);
            return rank[px];
        }
};


double x_y(int x1,int y1,int x2,int y2){
    return sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2));
}



int main(){
    //ios::sync_with_stdio(false);
    //cin.tie(nullptr);
    int cn=0;
    // TESTS{
    //     g_s
    // }
    ll n;
    sf("%lld",&n);

    string ans="";
    while(n){
        //if(n>=26)ans = 'z'+ans;
        //else {
            char iv=('a'+(int)n%26-1);
            ans = iv+ans;
        //}
        n /= 26;
    }

    cout<<ans<<endl;


    return 0;
}