Problem:
Score: 100 points

Problem Statement

A triple of numbers is said to be poor when two of those numbers are equal but the other number is different from those two numbers.

You will be given three integers A, B, and C. If this triple is poor, print Yes; otherwise, print No.

Constraints

A, B, and C are all integers between 1 and 9 (inclusive).

Input

Input is given from Standard Input in the following format:

A B C

Output

If the given triple is poor, print Yes; otherwise, print No.

Sample Input 1

5 7 5

Sample Output 1

Yes

A and C are equal, but B is different from those two numbers, so this triple is poor.

Sample Input 2

4 4 4

Sample Output 2

No

A, B, and C are all equal, so this triple is not poor.

Sample Input 3

4 9 6

Sample Output 3

No

Sample Input 4

3 3 4

Sample Output 4

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#define fast ios_base::sync_with_stdio(0),cin.tie(0),cout.tie(0)
#define all(x) begin(x),end(x)
#define msi map<string,int>
#define pii pair<int,int>
#include <bits/stdc++.h>
#define pll pair<ll,ll>
#define vll vector<ll>
#define vi vector<int>
#define ld long double
#define ll long long
#define sh short int
#define pb push_back
#define mid (l+r)/2
#define S second
#define F first
using namespace std;
const int inf = 1e9+9;
const int mod = 1e9+7;
const int shift = 2e6;
int a[9];
int main(){
    cin>>a[0]>>a[1]>>a[2];
    sort(a,a+3);
    if(a[0] == a[1] && a[0] != a[2]){
        cout<<"YES"<<endl;
    }
    else cout<<"NO"<<endl;
}