Problem:
Score : 200 points

Problem Statement

The development of algae in a pond is as follows.

Let the total weight of the algae at the beginning of the year i be x_i gram. For i≥2000, the following formula holds:

x_{i+1} = rx_i - D

You are given r, D and x_{2000}. Calculate x_{2001}, ..., x_{2010} and print them in order.

Constraints

2 ≤ r ≤ 5

1 ≤ D ≤ 100

D < x_{2000} ≤ 200

All values in input are integers.

Input

Input is given from Standard Input in the following format:

r D x_{2000}

Output

Print 10 lines. The i-th line (1 ≤ i ≤ 10) should contain x_{2000+i} as an integer.

Sample Input 1

2 10 20

Sample Output 1

30
50
90
170
330
650
1290
2570
5130
10250

For example, x_{2001} = rx_{2000} - D = 2 \times 20 - 10 = 30 and x_{2002} = rx_{2001} - D = 2 \times 30 - 10 = 50.

Sample Input 2

4 40 60

Sample Output 2

200
760
3000
11960
47800
191160
764600
3058360
12233400
48933560

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;


void __print(int x) {cerr << x;}
void __print(long x) {cerr << x;}
void __print(long long x) {cerr << x;}
void __print(unsigned x) {cerr << x;}
void __print(unsigned long x) {cerr << x;}
void __print(unsigned long long x) {cerr << x;}
void __print(float x) {cerr << x;}
void __print(double x) {cerr << x;}
void __print(long double x) {cerr << x;}
void __print(char x) {cerr << '\'' << x << '\'';}
void __print(const char *x) {cerr << '\"' << x << '\"';}
void __print(const string &x) {cerr << '\"' << x << '\"';}
void __print(bool x) {cerr << (x ? "true" : "false");}

template<typename T, typename V>
void __print(const pair<T, V> &x) {cerr << '{'; __print(x.first); cerr << ','; __print(x.second); cerr << '}';}
template<typename T>
void __print(const T &x) {int f = 0; cerr << '{'; for (auto &i : x) cerr << (f++ ? "," : ""), __print(i); cerr << "}";}
void _print() {cerr << "]\n";}
template <typename T, typename... V>
void _print(T t, V... v) {__print(t); if (sizeof...(v)) cerr << ", "; _print(v...);}

#define fo(i, n) for(int i=0; i<n; i++)
#define Fo(i, k, n) for(int i=k; i<n; i++)
#define w(x)  int x; cin>>x; while(x--)
#define watch(x) cout << (#x) << " is " << (x) << "\n"
#define watch2(x,y) cout <<(#x)<<" is "<<(x)<<" and "<<(#y)<<" is "<<(y)<<"\n"
#define watch3(x,y,z) cout <<(#x)<<" is "<<(x)<<" and "<<(#y)<<" is "<<(y)<<" and "<<(#z)<<" is "<<(z)<<"\n"
#define watch4(x,y,z,q) cout <<(#x)<<" is "<<(x)<<" and "<<(#y)<<" is "<<(y)<<" and "<<(#z)<<" is "<<(z)<<" and "<<(#q)<<" is "<<(q)<<"\n"
#define MOD 1000000007
#define INF 1000000007;
#define F first
#define S second
#define pb(x) push_back(x);


#define ll  long long
#define all(c) (c).begin(),(c).end()
#define endl "\n"

typedef vector<int> vl;
typedef vector< vl > vvl;
typedef pair< int, int> pll;
typedef map< int, int> mll;


#ifndef ONLINE_JUDGE
#define debug(x...) cerr << "[" << #x << "] = ["; _print(x)
#else
#define debug(x...)
#endif





void c_p_c()
{
#ifndef ONLINE_JUDGE
	ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
	freopen("input.txt", "r", stdin);
	freopen("output.txt", "w", stdout);
#endif
}
void parray(int a[], int n) {
	for (int i = 0; i < n; i++) {
		cout << a[i] << " ";
	}
	cout << endl;
}



int check(int n) {

	int temp = n + 9;

	temp = temp / 10;
	return temp * 10;



}

bool comp(int a, int b) {


	return a % 10 > b % 10;

}

int main() {
	int i, n, m, k, c = 0;
	c_p_c();
	ll r ,D, x200;
	cin>>r>>D>>x200;



	for (int i = 0; i < 10; ++i)
	{
		/* code */
		ll ans = r*x200-D;
		cout<<ans<<endl;
		x200=ans;
	}

	return 0;
}