Problem:
Score : 200 points

Problem Statement

The word internationalization is sometimes abbreviated to i18n.
This comes from the fact that there are 18 letters between the first i and the last n.

You are given a string s of length at least 3 consisting of lowercase English letters.
Abbreviate s in the same way.

Constraints

3 ≤ |s| ≤ 100 (|s| denotes the length of s.)

s consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s

Output

Print the abbreviation of s.

Sample Input 1

internationalization

Sample Output 1

i18n

Sample Input 2

smiles

Sample Output 2

s4s

Sample Input 3

xyz

Sample Output 3

x1z

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <string>
#include <cstring>
#include <queue>
#include <functional>

using namespace std;

#define ERROR_ID		0

#define PROCESS_ERROR(Condition)    \
{                                   \
		if (!(Condition))           \
		{                           \
			goto Exit0;             \
		}                           \
}

typedef unsigned char       BYTE;
typedef int                 BOOL;
typedef unsigned long       DWORD;
typedef long long			LLONG;

int main(int argc, char* argv[])
{
	string			szTargetStr;
	int				nLength;

	cin >> szTargetStr;

	nLength = szTargetStr.size() - 2;

	cout << szTargetStr[0] << nLength << szTargetStr[nLength + 1] << endl;
	return 0;
}