Problem:
Score : 200 points

Problem Statement

Let us define the FizzBuzz sequence a_1,a_2,... as follows:

If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.

If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.

If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.

If none of the above holds, a_i=i.

Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Constraints

1 \leq N \leq 10^6

Input

Input is given from Standard Input in the following format:

N

Output

Print the sum of all numbers among the first N terms of the FizzBuzz sequence.

Sample Input 1

15

Sample Output 1

60

The first 15 terms of the FizzBuzz sequence are:

1,2,\mbox{Fizz},4,\mbox{Buzz},\mbox{Fizz},7,8,\mbox{Fizz},\mbox{Buzz},11,\mbox{Fizz},13,14,\mbox{FizzBuzz}

Among them, numbers are 1,2,4,7,8,11,13,14, and the sum of them is 60.

Sample Input 2

1000000

Sample Output 2

266666333332

Watch out for overflow.

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <array>
#include <cmath>
#include <functional>
#include <iomanip>
#include <iostream>
#include <list>
#include <map>
#include <set>
#include <string>
#include <tuple>
#include <utility>
#include <vector>

#define rep(i, n) for (int i = 0; i < (int)(n); i++)
using namespace std;

int main() {
    int N;
    cin >> N;
    long long ret = 0;
    for(int i=0; i<N; ++i) {
        if(i %3 == 0 || i % 5 == 0) 
            continue;
//        cout << i << endl;
        ret += i;
    }
    cout << ret << endl;

    return 0;
}