Problem:
Score : 400 points

Problem Statement

Snuke has a large collection of cards. Each card has an integer between 1 and N, inclusive, written on it.
He has A_i cards with an integer i.

Two cards can form a pair if the absolute value of the difference of the integers written on them is at most 1.

Snuke wants to create the maximum number of pairs from his cards, on the condition that no card should be used in multiple pairs. Find the maximum number of pairs that he can create.

Constraints

1 ≦ N ≦ 10^5

0 ≦ A_i ≦ 10^9 (1 ≦ i ≦ N)

All input values are integers.

Input

The input is given from Standard Input in the following format:

N
A_1
:
A_N

Output

Print the maximum number of pairs that Snuke can create.

Sample Input 1

4
4
0
3
2

Sample Output 1

4

For example, Snuke can create the following four pairs: (1,1),(1,1),(3,4),(3,4).

Sample Input 2

8
2
0
1
6
0
8
2
1

Sample Output 2

9

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
typedef long long ll;
using namespace __gnu_pbds;
typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> pbds;
#define ios ios_base::sync_with_stdio(0) ; cin.tie(0) ; cout.tie(0)
#define so sizeof
#define pb push_back
#define vl vector<ll>
#define el endl;cout.flush()
#define be begin()
#define fi first
#define se second
#define br break
#define sz size()
#define en end()
#define ro return 0
#define br break
#define con continue;
#define um unordered_map<ll,ll>
#define ms(x) memset(x , 0 , so x)
#define all(x) (x).be , (x).en
#define rall(x) (x).rbegin() , (x).rend()
#define acc(x) accumulate((x).be , (x).en , 0)
#define forn(i,a,b) for(ll i=a;i<=b;++i)
#define forr(i,a,b) for(ll i=a;i<b;++i)
#define rng_58 mt19937 rng(chrono::steady_clock::now().time_since_epoch().count())
#define vll vector<pair<ll,ll> >
#define pll pair<ll,ll>
#define plll pair<ll,pair<ll,ll>>
#define plvl pair<pair<ll,ll> ,ll>
#define mp make_pair
int main()
{
    ios;
    ll n ;
    ll ans=  0 ;
    vl v;
    cin >> n ;
    forn(i , 1 , n ){
       ll x ;
       cin >> x ;
       v.pb(x);
    }
    for(ll i = 0 ; i < n ; ++ i ){
        ans = ans + v[i]/ 2 ;
        v[i] = v[i] % 2 ;
        if(v[i] == 1 and v[i+1] >=1 ){
            ans++ ;
            v[i+1]--;
        }
    }
    cout << ans << el ;

}