Problem:
Score : 300 points

Problem Statement

There are N people living on a number line.

The i-th person lives at coordinate X_i.

You are going to hold a meeting that all N people have to attend.

The meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.

Find the minimum total points of stamina the N people have to spend.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq X_i \leq 100

Input

Input is given from Standard Input in the following format:

N
X_1 X_2 ... X_N

Output

Print the minimum total stamina the N people have to spend.

Sample Input 1

2
1 4

Sample Output 1

5

Assume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.

Note that you can hold the meeting only at an integer coordinate.

Sample Input 2

7
14 14 2 13 56 2 37

Sample Output 2

2354

Solution in C++ (Clang 3.8.0) (judge verdict: Accepted)

#include <string>
#include <stdio.h>
#include <algorithm>
#include <iostream>
#include <vector>
#include <cmath>
#define rep(i,n) for(int i = 0; i < (n); i++)
using namespace std;

int main()
{
    int n;
    cin >> n;
    vector<int> x(n);
    rep(i, n){
        cin >> x[i];
    }
    long long tot, minCoord = pow(10, 7);
    for(int xi = 1; xi <= 100; xi++){
        tot = 0;
        rep(i,n){
            tot += (x[i] - xi) * (x[i] - xi);
        }
        //cout << tot << endl;
        minCoord = min(minCoord, tot);
        //cout << minCoord << endl;
    }
    cout << minCoord << endl;
    return 0;
}