Problem:
Score : 400 points

Problem Statement

Give a pair of integers (A, B) such that A^5-B^5 = X.
It is guaranteed that there exists such a pair for the given integer X.

Constraints

1 \leq X \leq 10^9

X is an integer.

There exists a pair of integers (A, B) satisfying the condition in Problem Statement.

Input

Input is given from Standard Input in the following format:

X

Output

Print A and B, with space in between.
If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.

A B

Sample Input 1

33

Sample Output 1

2 -1

For A=2 and B=-1, A^5-B^5 = 33.

Sample Input 2

1

Sample Output 2

0 -1

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

//Jai Bhole Ki
#include <bits/stdc++.h>
using namespace std;
#define fast static int fastline = []() { std::ios::sync_with_stdio(false); cin.tie(NULL); return 0; }();
#define ll long long
#define LL unsigned ll
#define pb push_back
#define pi pair<ll,ll>
#define debug(x) cout<<x<<"\n";
#define debug cout<<"debugged\n";
#define minval -2e9
#define maxval 2e9
long double PI =3.14159265358979323846;
 
const ll M=1e9+7;
const ll inf=1e18;
const ll ms=2e5+5;
fast;
bool com(pi &a,pi&b)
{
       return a.first-a.second>b.first-b.second;
}

void solve()
{
    ll n;cin>>n;
    for(ll i=-118;i<=119;i++)
    {
        ll a=pow(i,5),b;
        for(ll j=-119;j<=118;j++)
        {
            b=pow(j,5);
            if(a-b==n)
                {cout<<i<<" "<<j<<endl;return;}
            else if(b-a==n)
                {cout<<j<<" "<<i<<endl;return;}
                
        }
    }
}
int main()
{
 // freopen("input.txt","r",stdin);
//  freopen("output.txt","w",stdout);
    //int t;cin>>t;while(t--)
    {
        solve();
    }
    return 0;
}