Problem:
Score : 400 points

Problem Statement

Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.

You are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.

Constraints

2 ≦ |s| ≦ 10^5

s consists of lowercase letters.

Partial Score

200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.

Input

The input is given from Standard Input in the following format:

s

Output

If there exists no unbalanced substring of s, print -1 -1.

If there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.

Sample Input 1

needed

Sample Output 1

2 5

The string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.

Sample Input 2

atcoder

Sample Output 2

-1 -1

The string atcoder contains no unbalanced substring.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <vector>
#include <string>
#include <algorithm>
#include <numeric>
#include <cmath>
#include <unordered_map>

using namespace std;
using ll = long long;

void _cin(){} template <class Head, class... Tail> void _cin(Head&& head, Tail&&... tail){ cin >> head; _cin(forward<Tail>(tail)...); }
void _cout(){ cout << "\n"; } template <class Head, class... Tail> void _cout(Head&& head, Tail&&... tail){ cout << head; _cout(forward<Tail>(tail)...); }
int gcd(int a, int b){ return (b == 0) ? a : gcd(b, a % b); }

#define For(i, n) for(int i = 0; i < (n); i ++)
#define Rep(n) For(_, n)
#define Range(c) c.begin(), c.end()
#define RevRange(c) c.rbegin(), c.rend()
#define Contains(c, x) (find(Range(c), x) != c.end())
#define Search(rb, re, x) distance(rb, find(rb, re, x))
#define Sort(a) sort(Range(a))
#define DeSort(a) sort(RevRange(a))
#define Reverse(c) reverse(Range(c))
#define Vec2(T, n, m, xs, x0) vector<vector<T>> xs(n, vector<T>(m, x0))
#define Sum(a) accumulate(Range(a), 0)
#define Cusum(T, xs, sxs) vector<T> sxs(xs.size()+1); For(i, (int)xs.size()) sxs[i+1] = sxs[i] + xs[i]
#define Cin(T, ...) T __VA_ARGS__; _cin(__VA_ARGS__)
#define Cins(T, n, xs) vector<T> xs(n); For(i, n) cin >> xs[i]
#define Cins2(T, n, xs, ys) vector<T> xs(n), ys(n); For(i, n) cin >> xs[i] >> ys[i]
#define Cins3(T, n, xs, ys, zs) vector<T> xs(n), ys(n), zs(n); For(i, n) cin >> xs[i] >> ys[i] >> zs[i]
#define Cinss(T, n, m, xs) Vec2(T, n, m, xs); For(i, n) For(j, m) cin >> xs[i][j]
#define Cinm(T, n, map) unordered_map<T, int> map; Rep(n){ Cin(T, x); map[x] ++; }
#define Cout(...) _cout(__VA_ARGS__)
#define Couts(xs) for(const auto &e : xs) cout << e << " "; cout << "\n"
#define Coutyn(cond) Cout((cond) ? "yes" : "no")
#define CoutYn(cond) Cout((cond) ? "Yes" : "No")
#define CoutYN(cond) Cout((cond) ? "YES" : "NO")

// constexpr int MOD = 1e9+7;

int main(void){
    Cin(string, s);
    int n = (int)s.size();
    For(i, n-1){
        if(s[i] == s[i+1]){
            Cout(i+1, " ", i+2); return 0;
        }
    }
    For(i, n-2){
        if(s[i] == s[i+2]){
            Cout(i+1, " ", i+3); return 0;
        }
    }
    Cout("-1 -1");
}