Problem:
Score : 500 points

Problem Statement

We have N bulbs arranged on a number line, numbered 1 to N from left to right.
Bulb i is at coordinate i.

Each bulb has a non-negative integer parameter called intensity.
When there is a bulb of intensity d at coordinate x, the bulb illuminates the segment from coordinate x-d-0.5 to x+d+0.5.
Initially, the intensity of Bulb i is A_i. We will now do the following operation K times in a row:

For each integer i between 1 and N (inclusive), let B_i be the number of bulbs illuminating coordinate i. Then, change the intensity of each bulb i to B_i.

Find the intensity of each bulb after the K operations.

Constraints

1 \leq N \leq 2 \times 10^5

1 \leq K \leq 2 \times 10^5

0 \leq A_i \leq N

Input

Input is given from Standard Input in the following format:

N K
A_1 A_2 \ldots A_N

Output

Print the intensity A{'}_i of each bulb i after the K operations to Standard Output in the following format:

A{'}_1 A{'}_2 \ldots A{'}_N

Sample Input 1

5 1
1 0 0 1 0

Sample Output 1

1 2 2 1 2

Initially, only Bulb 1 illuminates coordinate 1, so the intensity of Bulb 1 becomes 1 after the operation.
Similarly, the bulbs initially illuminating coordinate 2 are Bulb 1 and 2, so the intensity of Bulb 2 becomes 2.

Sample Input 2

5 2
1 0 0 1 0

Sample Output 2

3 3 4 4 3

Solution in C++ (GCC 9.2.1) (judge verdict: Runtime Error)

#include<bits/stdc++.h>
using namespace std;
int a[200005], b[200005];
bool flag;
int main()
{
	ios::sync_with_stdio(false);
	cin.tie(0);
	cout.tie(0);
	int n, k;
	cin >> n >> k;
	for (int i = 0; i < n; i++) {
		cin >> a[i];
	}
	while (k--) {
		memset(b, 0, sizeof(b));
		for (int i = 0; i < n; i++) {
			for (int j = i - a[i]; j <= min(i + a[i], n); j++) {
				b[j]++;
			}
		}
		for (int i = 0; i < n; i++) {
			a[i] = b[i];
		}
		flag = true;
		for (int i = 0; i < n; i++) {
			if (a[i] != n)
			{
				flag = false;
				break;
			}
		}
		if (flag)
		{
			cout << a[0];
			for (int i = 1; i < n; i++) {
				cout << " " << a[i];
			}
			cout << endl;
			return 0;
		}
	}
	cout << a[0];
	for (int i = 1; i < n; i++) {
		cout << " " << a[i];
	}
	cout << endl;
	return 0;
}