Problem:
Score : 200 points

Problem Statement

An integer X is called a Harshad number if X is divisible by f(X), where f(X) is the sum of the digits in X when written in base 10.

Given an integer N, determine whether it is a Harshad number.

Constraints

1?N?10^8

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

Print Yes if N is a Harshad number; print No otherwise.

Sample Input 1

12

Sample Output 1

Yes

f(12)=1+2=3. Since 12 is divisible by 3, 12 is a Harshad number.

Sample Input 2

57

Sample Output 2

No

f(57)=5+7=12. Since 57 is not divisible by 12, 12 is not a Harshad number.

Sample Input 3

148

Sample Output 3

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;

int main(){ //11-b-Harshad_Namber
  string a;
  int f,n,x,y;
  n=0;
  f=0;
  x=1;
  y=0;
  cin >> a;
  for(int i=1;i<a.size();i++){
    x*=10;
  }  
  //cout<<x<<endl;
  for(int i=0;i<a.size();i++){
    
    if(a.at(i) =='1'){
      y=1;
    }
    else if(a.at(i) =='2'){
      y=2;
    }
    else if(a.at(i) =='3'){
      y=3;
    }
    else if(a.at(i) =='4'){
      y=4;
    }
    else if(a.at(i) =='5'){
      y=5;
    }
    else if(a.at(i) =='6'){
      y=6;
    }
    else if(a.at(i) =='7'){
      y=7;
    }
    else if(a.at(i) =='8'){
      y=8;
    }
    else if(a.at(i) =='9'){
      y=9;
    }
    else {
    }
    n+=y*x;
    f+=y;
    x/=10;
   // cout<<a.at(i)<<","<<n<<","<<f<<","<<endl;
  }
  if(n==0){
    cout <<"Yes"<<endl;
  }
  else if(n%f == 0){
    cout << "Yes" << endl;
  }
  else{
    cout <<"No"<< endl;
  }
}