Problem:
Score : 400 points

Problem Statement

Mr. Takahashi has a string s consisting of lowercase English letters.
He repeats the following operation on s exactly K times.

Choose an arbitrary letter on s and change that letter to the next alphabet. Note that the next letter of z is a.

For example, if you perform an operation for the second letter on aaz, aaz becomes abz.
If you then perform an operation for the third letter on abz, abz becomes aba.

Mr. Takahashi wants to have the lexicographically smallest string after performing exactly K operations on s.
Find the such string.

Constraints

1≤|s|≤10^5

All letters in s are lowercase English letters.

1≤K≤10^9

Input

The input is given from Standard Input in the following format:

s
K

Output

Print the lexicographically smallest string after performing exactly K operations on s.

Sample Input 1

xyz
4

Sample Output 1

aya

For example, you can perform the following operations: xyz, yyz, zyz, ayz, aya.

Sample Input 2

a
25

Sample Output 2

z

You have to perform exactly K operations.

Sample Input 3

codefestival
100

Sample Output 3

aaaafeaaivap

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

// #define _CRT_SECURE_NO_WARNINGS
// #define _USE_MATH_DEFINES
#include <iostream>
#include <cstdio>
#include <algorithm>
#include <string>
#include <vector>
#include <map>
#include <set>
#include <stack>
#include <cmath>
#include <cstdlib>
#include <functional>
#include <locale>
#include <cctype>
#include <sstream>
#include <iomanip>	// 10桁出力 cout << setprecision(10) << double;
#include <queue>
using namespace std;

typedef long long LL;
typedef vector<int> VI;
typedef vector<VI> VVI;
typedef map<int, int> MAPII;
typedef multimap<int, char, greater<int> > MuMAPIC;
typedef vector<pair<int, int> > VPII;
typedef multimap<int, string, greater<int> > MuMIS;
typedef pair<int, int> P;
typedef pair<int, pair<P, P> > PP;

#define MP make_pair
#define FAST_IO  cin.tie(0); ios::sync_with_stdio(false);
#define FOR(i,a,b) for(int i=(a);i<(b);i++)
//for gcc (未test)
// #define FOREACH_IT(it,c) for(typeof(c)::iterator it=(c).begin(); it!=(c).end(); ++it)
//for Visual Studio
#define foreach_it(type,it,c) for(type::iterator it=c.begin(),c_end=c.end();it!=c_end;++it)
// for Debug.
#define DUMP_VVI(b) FOR(i,0,b.size()){FOR(j,0,b[i].size())printf("%d ",b[i][j]);puts("");}
#define D_OUT(str,value) if(dbgF){cout<<str<<" : "<<value<<endl;}
// 入力をpush_back(d)やarray[d]に使う時に1行で書ける
// int INPUT_INT() {int d;cin>>d;return d;}
template<class T>T IN() { T d; cin >> d; return d; }
// 最大公約数（Greatest Common Divisor）
LL gcd(LL a, LL b) { return (b > 0) ? gcd(b, a%b) : a; }
// 最小公倍数（Least Common Multiple）
LL lcm(LL a, LL b) { return a / gcd(a, b) * b; }
// Y年はうるう年か否か
bool uruu(LL Y) { return (((Y % 4 == 0 && Y % 100 != 0) || Y % 400 == 0) ? true : false); }

// vector注意
// vec[i][j]の形に入力を入れるとき、vecは初期化してある必要がある.

// ------------------- include, typedef, define END. -------------------

int main() {
	FAST_IO;
	// for D_OUT(str, value)  ... cout<< str <<" : "<< value <<endl;
	bool dbgF = true;

	//コードはここから書く.
	string s;
	LL k;
	cin >> s >> k;
	FOR(i, 0, s.length()) {
		int t = s[i];
		if ((122-t + 1) <= k && s[i]!='a') {
			//cout << "NN"<<endl;
			s[i] = 'a';
			k -= (122-t + 1);
			//cout << "s=" << s << " , k=" << k << endl;
		}
	}

	// 残りのz消化
	//cout << "zan k = " << k << endl;
	if(k>=26)	k = k % 26;
	s[s.length() - 1] += k;
	int e = s[s.length() - 1];
	if (e > 122) {
		s[s.length() - 1] = 97 + (e - 123);
	}

	cout << s << endl;

	return 0;
}