Problem:
Score : 100 points

Problem Statement

Given an integer a as input, print the value a + a^2 + a^3.

Constraints

1 \leq a \leq 10

a is an integer.

Input

Input is given from Standard Input in the following format:

a

Output

Print the value a + a^2 + a^3 as an integer.

Sample Input 1

2

Sample Output 1

14

When a = 2, we have a + a^2 + a^3 = 2 + 2^2 + 2^3 = 2 + 4 + 8 = 14.

Print the answer as an input. Outputs such as 14.0 will be judged as incorrect.

Sample Input 2

10

Sample Output 2

1110

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;
#define FOR(i,a,b)  for(int i=(a),i##formax=(b);i< i##formax;i++)
#define FORR(i,a,b) for(int i=(a),i##formin=(b);i>=i##formin;i--)
#define pb push_back
#define eb emplace_back
#define mp make_pair
#define fi first
#define se second
#define pcnt __builtin_popcount
#define sz(x) (int)(x).size()
#define maxs(x,y) x=max((x),(y))
#define mins(x,y) x=min((x),(y))
#define show(x) cout<<#x<<" = "<<(x)<<endl;
#define all(a) ((a).begin()),((a).end())
#define each(i,c) for(__typeof((c).begin()) i=(c).begin();i!=(c).end();i++)
#define bit(n) (1LL<<(n))
typedef long long ll;
typedef __int128_t lll;
template<class T>using V=vector<T>;
template<class T>using VV=V<V<T>>;
template<class T,class Y>using P=pair<T,Y>;
template<class T,class Y>ostream& operator<<(ostream&o,P<T,Y>&p){return o<<"("<<p.fi<<","<<p.se<<")";}
template<class T>ostream& operator<<(ostream&o,V<T>&v){for(T&t:v)o<<t<<",";return o;}
template<class T>void uniq(V<T>&v){sort(all(v));v.erase(unique(all(v)), v.end());}
template<class A,size_t N,class T>void Fill(A(&a)[N],const T&v){fill((T*)a,(T*)(a+N),v);}

const int MOD = 1e9+7; //998244353;

lll gcd(lll a,lll b,lll&x,lll&y){if(!b){x=1;y=0;return a;}lll d=gcd(b,a%b,y,x);y-=a/b*x;return d;}
ll modInv(ll a,ll m=MOD){lll x,y;gcd(a,m,x,y);return(x%m+m)%m;}
ll modPow(lll a,lll n,ll m=MOD){lll p=1;for(;n;n>>=1,a=a*a%m)if(n&1)p=p*a%m;return p;}
//V<ll>Fac,Rac;void setF(int n,int m=MOD){Fac=Rac=V<ll>(++n);Fac[0]=1;FOR(i,1,n)Fac[i]=Fac[i-1]*i%m;Rac[n-1]=modInv(Fac[n-1],m);FORR(i,n-1,1)Rac[i-1]=Rac[i]*i%m;}
//ll comb(int a,int b,int m=MOD){return a<b||b<0?0:Fac[a]*Rac[b]%m*Rac[a-b]%m;}

const int IINF = 1e9+6;
const ll LINF = 1e18;
int a;
main(){
  cin.tie(0);
  ios::sync_with_stdio(false);
  cin >> a;
  cout << a*(1+a*(1+a)) << endl;
}