Problem:
Score : 200 points

Problem Statement

N Snukes called Snuke 1, Snuke 2, ..., Snuke N live in a town.

There are K kinds of snacks sold in this town, called Snack 1, Snack 2, ..., Snack K. The following d_i Snukes have Snack i: Snuke A_{i, 1}, A_{i, 2}, \cdots, A_{i, {d_i}}.

Takahashi will walk around this town and make mischief on the Snukes who have no snacks. How many Snukes will fall victim to Takahashi's mischief?

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq K \leq 100

1 \leq d_i \leq N

1 \leq A_{i, 1} < \cdots < A_{i, d_i} \leq N

Input

Input is given from Standard Input in the following format:

N K
d_1
A_{1, 1} \cdots A_{1, d_1}
\vdots
d_K
A_{K, 1} \cdots A_{K, d_K}

Output

Print the answer.

Sample Input 1

3 2
2
1 3
1
3

Sample Output 1

1

Snuke 1 has Snack 1.

Snuke 2 has no snacks.

Snuke 3 has Snack 1 and 2.

Thus, there will be one victim: Snuke 2.

Sample Input 2

3 3
1
3
1
3
1
3

Sample Output 2

2

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;

#define rep(i, n) for(int (i) = 0; (i) < (n); (i)++)
#define repp(i, n, m) for(int (i) = (n); (i) < (m); (i)++)
#define repn(i, n) for(int (i) = 1; (i) <= (n); (i)++)
#define repr(i, n) for(int (i) = (n-1); (i) >= 0; (i)--)
#define all(x) (x).begin(), (x).end()
#define lint long long
#define ulint unsigned long long
#define ldou long double
#define fi first
#define se second
#define setpre(x) std::cout << fixed << setprecision(x)
#define ii(x) int x; cin >> (x)
#define ii2(x, y) int x, y; cin >> (x) >> (y)
#define ii3(x, y, z) int x, y, z; cin >> (x) >> (y) >> (z)
#define out(x) cout << (x) << endl
#define outs(x) cout << (x) << " "
#define yn(x) cout << ((x)?("Yes"):("No")) << endl
#define YN(x) cout << ((x)?("YES"):("NO")) << endl
#define bit_c(x) __builtin_popcountll(x)

inline void logger(){ std::cout << " [LOGGER] " << endl; }
template<typename A, typename... B>
void logger(const A& a, const B&... b){
    cout << a << " , "; logger(b...);
}

typedef pair<lint, lint> P;
const lint MOD = 1000000007;
const lint MOD9 = 998244353;
const lint INF = MOD * MOD;
const int MAX = 200005;

/* ...o(^-^)o... */

int main(){
    int n,k; cin>>n>>k;
    vector<int> v(n);
    rep(i, k){
        int d; cin >> d;
        rep(j, d){
            int a; cin >> a; a--;
            v[a]++;
        }
    }
    int ans=0;
    rep(i, n){
        if(v[i]==0) ans++;
    }
    out(ans);
}