Problem:
Score : 200 points

Problem Statement

Given are strings S and T. Consider changing S to T by repeating the operation below. Find the minimum number of operations required to do so.

Operation: Choose one character of S and replace it with a different character.

Constraints

S and T have lengths between 1 and 2\times 10^5 (inclusive).

S and T consists of lowercase English letters.

S and T have equal lengths.

Input

Input is given from Standard Input in the following format:

S
T

Output

Print the answer.

Sample Input 1

cupofcoffee
cupofhottea

Sample Output 1

4

We can achieve the objective in four operations, such as the following:

First, replace the sixth character c with h.

Second, replace the eighth character f with t.

Third, replace the ninth character f with t.

Fourth, replace the eleventh character e with a.

Sample Input 2

abcde
bcdea

Sample Output 2

5

Sample Input 3

apple
apple

Sample Output 3

0

No operations may be needed to achieve the objective.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

/*   _/                _/                 _/_/_/   _/
  _/_/_/_/   _/_/   _/_/_/_/   _/_/    _/       _/_/
   _/     _/    _/   _/     _/    _/  _/_/_/     _/
  _/     _/    _/   _/     _/    _/  _/    _/   _/
   _/_/   _/_/       _/_/   _/_/      _/_/     _/ */
#include<iostream>
#include<algorithm>
#include<cmath>
#include<iomanip>
#include<set>
#include<map>
#include<queue>
#include<vector>
using namespace std;
using ll=long long;
const int MOD=1e9+7;
const double pi=3.14159265358979323846;
const int inf=1e9+5;
const ll INF=1e18;
using P=pair<int,int>;
int dx[4]={1,0,-1,0},dy[4]={0,1,0,-1};
int main() {
  cin.tie(0),cout.tie(0);
  ios::sync_with_stdio(false);
  string s,t;
  int ans=0;
  cin >> s >> t;
  for(int i=0; i<s.size(); i++) {
    if(s[i]!=t[i]) {
      ans++;
    }
  }
  cout << ans << endl;
}