Problem:
Score : 400 points

Problem Statement

Given is an integer S.
Find a combination of six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfies all of the following conditions:

0 \leq X_1,Y_1,X_2,Y_2,X_3,Y_3 \leq 10^9

The area of the triangle in a two-dimensional plane whose vertices are (X_1,Y_1),(X_2,Y_2), and (X_3,Y_3) is S/2.

We can prove that there always exist six integers that satisfy the conditions under the constraints of this problem.

Constraints

1 \leq S \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

S

Output

Print six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfy the conditions, in this order, with spaces in between.
If multiple solutions exist, any of them will be accepted.

Sample Input 1

3

Sample Output 1

1 0 2 2 0 1

The area of the triangle in a two-dimensional plane whose vertices are (1,0),(2,2), and (0,1) is 3/2.
Printing 3 0 3 1 0 1 or 1 0 0 1 2 2 will also be accepted.

Sample Input 2

100

Sample Output 2

0 0 10 0 0 10

Sample Input 3

311114770564041497

Sample Output 3

314159265 358979323 846264338 327950288 419716939 937510582

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

//code by PARTH_4399 for competitive programming
#include<bits/stdc++.h>
using namespace std;
#define l long // -2^31 to +2^31-1 (upper limit ~ 2*(10^9))
#define ul unsigned long // 0 to +2^32-1
#define ll long long // -2^63 to +2^63-1 (upper limit ~ 9*(10^18))
#define ull unsigned long long // 0 to +2^64-1
#define mod(x, m) ((((x)%(m))+(m))%(m))
#define vi vector<int>
#define pi pair<int,int>
#define F first
#define S second
#define PB push_back
#define MP make_pair
//const double pi=acos(-1.0); // cout<<fixed<<setprecision(n)<<pi; - for n decimal digits, use <iomanip.h>
int main()
{
	ios_base::sync_with_stdio(false);
	cin.tie(NULL);
	cout.tie(NULL);
	//code
	ull int t,a=1;
	cin>>t;
	while(t%2==0)
	{
		t/=2;
		a*=2;
	}
	ll int i=3;
	while(t>pow(10,9))
	{
		while(t%i==0)
		{
			t/=i;
			a*=i;
		}
		i+=2;
	}
	cout<<"0 0 0 "<<a<<" "<<t<<" 0";
	return 0;
}