Problem:
Score : 100 points

Problem Statement

There are two buttons, one of size A and one of size B.

When you press a button of size X, you get X coins and the size of that button decreases by 1.

You will press a button twice. Here, you can press the same button twice, or press both buttons once.

At most how many coins can you get?

Constraints

All values in input are integers.

3 \leq A, B \leq 20

Input

Input is given from Standard Input in the following format:

A B

Output

Print the maximum number of coins you can get.

Sample Input 1

5 3

Sample Output 1

9

You can get 5 + 4 = 9 coins by pressing the button of size 5 twice, and this is the maximum result.

Sample Input 2

3 4

Sample Output 2

7

Sample Input 3

6 6

Sample Output 3

12

Solution in C++14 (GCC 5.4.1) (judge verdict: Runtime Error)

// #include </Users/kmudda/Downloads/Karthik/stdc++.h>
#include <bits/stdc++.h>
#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
#include <climits>
#define ll long long int
#define ld long double
#define vl vector<ll>
#define vi vector<int>
#define vvl vector< vl >
#define vvi vector< vi >
#define pb push_back
#define mp make_pair
#define max_int_value 2147483647
#define max_long_value 9223372036854775807
#define min_long_value -9223372036854775806
#define ii pair<ll,ll>
#define F first
#define S second
#define fast_io ios_base::sync_with_stdio(0);cin.tie(0)
 
#define CLR(v, d)     memset(v, d, sizeof(v))
 
template<typename T> T gcd(T a, T b){return (b?__gcd(a,b):a);}
template<typename T> T lcm(T a, T b){return (a*(b/gcd(a,b)));}
template<typename T> T mod(T a, T b) {return (a<b ? a : a%b);}
template<typename T> T mod_neg(T a, T b) {return ((a%b)+b)%b;}
ll mulmod(ll a,ll b, ll m){ll q=(ll)(((ld)a*(ld)b)/(ld)m);ll r=a*b-q*m;if(r>m)r%=m;if(r<0)r+=m;return r;}
template<typename T> T expo(T e, T n){T x=1,p=e;while(n){if(n&1)x=x*p;p=p*p;n>>=1;}return x;}
template<typename T> T power(T e, T n, T m){T x=1,p=e;while(n){if(n&1)x=mod(x*p,m);p=mod(p*p,m);n>>=1;}return x;}
template<typename T> T extended_euclid(T a, T b, T &x, T &y){T xx=0,yy=1;y=0;x=1;while(b){T q=a/b,t=b;b=a%b;a=t;t=xx;xx=x-q*xx;x=t;t=yy;yy=y-q*yy;y=t;}return a;}
template<typename T> T mod_inverse(T a, T n){T x,y;T d = extended_euclid(a, n, x, y);return (d>1?-1:mod_neg(x,n));}
 
using namespace std;
 
string IntToString (int a)
{
    ostringstream temp;
    temp<<a;
    return temp.str();
}
 
int StringToInt (string str)
{
    int xx;
    stringstream ss;
    ss << str;
    ss >> xx;
    return xx;
}
 
ll powerwithmodulus(ll base, ll exponent,ll modulus){
    ll result = 1; base%=modulus;
    while (exponent > 0)
    {
        if (exponent % 2 == 1) result = (result * base) % modulus;
        exponent = exponent >> 1;
        base = (base * base) % modulus;
    }
    return result;
}

/*  NCR using DP
for(int n = 0; n <= 1000; n++)
        for(int r = 0; r <= n; r++)
            if(r == 0 || n == r) ncr[n][r] = 1;
            else ncr[n][r] = (ncr[n-1][r-1] + ncr[n-1][r]) % mod;

*/

 
ll largestPowerOf2(ll n)
{
    return (ll)pow(2, floor(log(n) / log(2)));
}

inline bool cmp1(pair<ll,ll> &p1, pair<ll,ll> &p2) {
    if(p1.F == p2.F)
        return p1.S < p2.S;
    else
        return p1.F < p2.F;
}
 
//lower case std::transform(str.begin(), str.end(), str.begin(), ::tolower);
//Ascii A-65 Z-90 a-97 z-122 0-48 9-57

int cal(int pow, int val, int MOD){
   if(pow <= 0)
      return 1;
   int v = cal(pow/2, val, MOD);
   if(pow % 2 == 0)
      return (v*v) % MOD; 
   else
      return (((v*val) % MOD) * v) % MOD;
}

ll t,n,m,sum=0,coun=0,m1,m2,m3,i,j,k,sum1,sum2,p,q,r,p1,q1;
bool flag2;

int main() {

  fast_io;
  freopen("inputf.in", "r", stdin);
  freopen("outputf.in", "w", stdout);
  cin>>n>>m;
  if(abs(n-m) >= 2) {
    cout<<max(n,m) + (max(n,m) - 1)<<endl;
  } else {
    cout<<(n+m)<<endl;
  }
}