Problem:
Problem Statement

You are given two integers a and b (a≤b). Determine if the product of the integers a, a+1, …, b is positive, negative or zero.

Constraints

a and b are integers.

-10^9≤a≤b≤10^9

Partial Score

In test cases worth 100 points, -10≤a≤b≤10.

Input

The input is given from Standard Input in the following format:

a b

Output

If the product is positive, print Positive. If it is negative, print Negative. If it is zero, print Zero.

Sample Input 1

1 3

Sample Output 1

Positive

1×2×3=6 is positive.

Sample Input 2

-3 -1

Sample Output 2

Negative

(-3)×(-2)×(-1)=-6 is negative.

Sample Input 3

-1 1

Sample Output 3

Zero

(-1)×0×1=0.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
#include <iostream>
#include <algorithm>
#include <cmath>
#include <vector>
#include <set>
#include <map>
#include <queue>
#include <string>
using namespace std;
const int INF = 1001001001;
typedef long long int ll;
#define rep(i, n) for (int(i) = 0; (i) < (n); (i)++)
#define re0 return 0

int npr(int n , int r){//nPr
    r = n - r;
    int sum = 1;
    int i;
    for (i=n;i>=r+1;i--)sum*=i;
    return sum;
}
int gcd(int a, int b) {//最大公約数
    if (b==0) return a;
    else return gcd(b, a%b);
}
int lcm(int a, int b) {//最小公倍数
    return a * b / gcd(a, b);
}
int digsum(int n) {//桁和
    int res = 0;
    while(n > 0) {
        //res += n%10;
        //　↑をres++;にすれば桁数
         res++;
        n /= 10;
    }
    return res;
}
bool isPrime(int x){//素数
    if(x==1)return 0;
    if(x==2)return 1;
    if(x%2==0)return 0;
    for(int i=3;i*i<=x;i++)if(x%i==0)return 0;
    return 1;
}
/*bit全探索
for (int bit = 0; bit < (1<<N); ++bit) {
}
if (bit & (1 << i)) {
}
*/


signed main(){ 
    ll a,b;
    cin >> a >> b;
    if(a<0 && b<0){
        if(abs(a)%2!=0){
            cout << "Negative" <<endl;    
        }else{
            cout << "Positive" <<endl;
        }
    }else if(a>0 && b>0){
        cout << "Positive" <<endl;
    }else if(a==0 || b==0){
        cout << "Zero" <<endl;
    }else if(a<0 && b>0){
        cout << "Zero" <<endl;
    }else{
        cout << "Positive" <<endl;
    }
    return 0;
}