Problem:
Score : 400 points

Problem Statement

Given are three integers N, K, and S.

Find a sequence A_1, A_2, ..., A_N of N integers between 1 and 10^9 (inclusive) that satisfies the condition below.
We can prove that, under the conditions in Constraints, such a sequence always exists.

There are exactly K pairs (l, r) of integers such that 1 \leq l \leq r \leq N and A_l + A_{l + 1} + \cdots + A_r = S.

Constraints

1 \leq N \leq 10^5

0 \leq K \leq N

1 \leq S \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K S

Output

Print a sequence satisfying the condition, in the following format:

A_1 A_2 ... A_N

Sample Input 1

4 2 3

Sample Output 1

1 2 3 4

Two pairs (l, r) = (1, 2) and (3, 3) satisfy the condition in the statement.

Sample Input 2

5 3 100

Sample Output 2

50 50 50 30 70

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<bits/stdc++.h>
using namespace std;
#define all(a)  (a).begin(),(a).end()
typedef long long ll;
const ll mod=1000000007;
#define repi(i,a,b) for(ll i=ll(a);i<ll(b);++i)

int main() {
  int n,k,s;cin>>n>>k>>s;
  int a0 = s/(n-k+1);
  int a1 = s%(n-k+1);
  vector<int> v(n,a0);
  if(a0==0||s==1){
    for(int j=0;j<k;++j)v[j] = s;
    for(int j=k;j<n;++j)v[j] = s+1;
  } else {
  	v[n-k] += a1;
  }
  for(int i=0;i<n;++i) cout << v[i] << " ";
  return 0;
}