Problem:
Score : 300 points

Problem Statement

You are given an integer sequence of length n, a_1, ..., a_n.
Let us consider performing the following n operations on an empty sequence b.

The i-th operation is as follows:

Append a_i to the end of b.

Reverse the order of the elements in b.

Find the sequence b obtained after these n operations.

Constraints

1 \leq n \leq 2\times 10^5

0 \leq a_i \leq 10^9

n and a_i are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print n integers in a line with spaces in between.
The i-th integer should be b_i.

Sample Input 1

4
1 2 3 4

Sample Output 1

4 2 1 3

After step 1 of the first operation, b becomes: 1.

After step 2 of the first operation, b becomes: 1.

After step 1 of the second operation, b becomes: 1, 2.

After step 2 of the second operation, b becomes: 2, 1.

After step 1 of the third operation, b becomes: 2, 1, 3.

After step 2 of the third operation, b becomes: 3, 1, 2.

After step 1 of the fourth operation, b becomes: 3, 1, 2, 4.

After step 2 of the fourth operation, b becomes: 4, 2, 1, 3.

Thus, the answer is 4 2 1 3.

Sample Input 2

3
1 2 3

Sample Output 2

3 1 2

As shown above in Sample Output 1, b becomes 3, 1, 2 after step 2 of the third operation. Thus, the answer is 3 1 2.

Sample Input 3

1
1000000000

Sample Output 3

1000000000

Sample Input 4

6
0 6 7 6 7 0

Sample Output 4

0 6 6 0 7 7

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<iostream>
#include<vector>
#include<string>
#include<algorithm>
#include<map>
#include<utility>
#include<set>
#include<stack>
#include<queue>
#include<deque>
#include<cmath>
#include<cstdio>
#include<cstring>
#include<cstdlib>
#include<bitset>
#include<sstream>
#include<list>
#include<climits>

using namespace std;
#define rep(i,n) for(int i=0;i<(int)(n);++i)
#define nrep(i,i0,n) for(int i=(i0);i<(int)(n);++i)
typedef vector<int> vi; typedef pair<int,int> pii; typedef vector<pair<int,int> > vpii;
typedef vector<vector<int> > vii;
typedef long long ll;


int main(){
	vi od,ev;
	int n;
	cin>>n;
	rep(i,n){
		int a;cin>>a;
		if(i%2==0)od.push_back(a);
		else ev.push_back(a);
	}
	if(n%2==0)reverse(ev.begin(),ev.end());
	else reverse(od.begin(),od.end());
	if(n%2==0){
		rep(i,ev.size())cout<<ev[i]<<" ";
		rep(i,od.size())cout<<od[i]<<" ";
		cout<<endl;
	}else{
		rep(i,od.size())cout<<od[i]<<" ";
		rep(i,ev.size())cout<<ev[i]<<" ";
		cout<<endl;
	}
	return 0;
}