Problem:
Score : 200 points

Problem Statement

An integer N is a multiple of 9 if and only if the sum of the digits in the decimal representation of N is a multiple of 9.

Determine whether N is a multiple of 9.

Constraints

0 \leq N < 10^{200000}

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a multiple of 9, print Yes; otherwise, print No.

Sample Input 1

123456789

Sample Output 1

Yes

The sum of these digits is 1+2+3+4+5+6+7+8+9=45, which is a multiple of 9, so 123456789 is a multiple of 9.

Sample Input 2

0

Sample Output 2

Yes

Sample Input 3

31415926535897932384626433832795028841971693993751058209749445923078164062862089986280

Sample Output 3

No

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>

using namespace std;

#define lli long long
#define ld long double
#define mod 1000000007 
#define set(n) cout << fixed << setprecision(n)    
#define fi first
#define se second
#define mp make_pair
#define pll pair<lli, lli>
#define endl '\n'

const double PI = acos(-1);
const double epsilon = 1e-7;  // floating point precision

signed main(void) {
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    string s;
    cin >> s;
    int md = 0;
    for(int i = 0; i < s.length(); i++) {
        md = (md * 10 + ((int)(s[i] - '0')) % 9) % 9;
    }
    if(md == 0) {
        cout << "Yes" << endl;
    }
    else {
        cout << "No" << endl;
    }
    return 0;
}