Problem:
Score : 100 points

Problem Statement

Takahashi is a member of a programming competition site, ButCoder.

Each member of ButCoder is assigned two values: Inner Rating and Displayed Rating.

The Displayed Rating of a member is equal to their Inner Rating if the member has participated in 10 or more contests. Otherwise, the Displayed Rating will be their Inner Rating minus 100 \times (10 - K) when the member has participated in K contests.

Takahashi has participated in N contests, and his Displayed Rating is R. Find his Inner Rating.

Constraints

All values in input are integers.

1 \leq N \leq 100

0 \leq R \leq 4111

Input

Input is given from Standard Input in the following format:

N R

Output

Print his Inner Rating.

Sample Input 1

2 2919

Sample Output 1

3719

Takahashi has participated in 2 contests, which is less than 10, so his Displayed Rating is his Inner Rating minus 100 \times (10 - 2) = 800.

Thus, Takahashi's Inner Rating is 2919 + 800 = 3719.

Sample Input 2

22 3051

Sample Output 2

3051

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
#define MOD 1e9 + 7
#define PI 3.141592653589793238
#define pb push_back
#define ALL(V) (V).begin(), (V).end()
#define FOR(i, a, b) for(int i = (a); i < (b); ++i)
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef long long int lint;
typedef vector<ll> VL;
typedef vector<VL> VVL;
typedef vector<int> VI;
typedef pair<ll, ll> P;
ll gcd(ll a, ll b) { return (a % b == 0 ? b : gcd(b, a % b)); }
ll lcm(ll a, ll b) { return a * b / gcd(a, b); }
ll char_to_ll(char c) { return (int)(c - '0'); }
ll string_to_ll(string s) { return char_to_ll(atoi(s.c_str())); }
bool is_prime(ll x){ if(x <= 1) return false; for(ll i = 2; sqrt(i) <= x; i++) if(x % i == 0) return false; return true; }


int main() {
    int n,r;
    cin >> n >> r;
    int l;
    l = 100*(10-n);
    if(n >= 10){
        cout << r << endl;
    }else{
        cout << r - l << endl;
}
  

    return 0;
}