Problem:
Score : 100 points

Problem Statement

You are given a three-digit positive integer N.

Determine whether N is a palindromic number.

Here, a palindromic number is an integer that reads the same backward as forward in decimal notation.

Constraints

100≤N≤999

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a palindromic number, print Yes; otherwise, print No.

Sample Input 1

575

Sample Output 1

Yes

N=575 is also 575 when read backward, so it is a palindromic number. You should print Yes.

Sample Input 2

123

Sample Output 2

No

N=123 becomes 321 when read backward, so it is not a palindromic number. You should print No.

Sample Input 3

812

Sample Output 3

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#define rep(i,n) for (int i = 0; i < (n); ++i)
#define pa(x,n) for(ll i=0;i<n;i++){cout<<(x[i])<<" \n"[i==n-1];};

using ll = long long;
using namespace std;
using P = pair<int,int>;
ll mod=1e9+7;

ll gcd(ll a, ll b) { return b?gcd(b,a%b):a; } //最大公約数
ll lcm(ll a, ll b) { return a/gcd(a,b)*b; } //最大公倍数

int main(){
  string s;
  cin>>s;
  if (s[0] == s[2]) cout << "Yes" << endl;
  else cout << "No" << endl;
  return 0;
}