Problem:
Score : 300 points

Problem Statement

Snuke loves puzzles.

Today, he is working on a puzzle using S- and c-shaped pieces.
In this puzzle, you can combine two c-shaped pieces into one S-shaped piece, as shown in the figure below:

Snuke decided to create as many Scc groups as possible by putting together one S-shaped piece and two c-shaped pieces.

Find the maximum number of Scc groups that can be created when Snuke has N S-shaped pieces and M c-shaped pieces.

Constraints

1 ≤ N,M ≤ 10^{12}

Input

The input is given from Standard Input in the following format:

N M

Output

Print the answer.

Sample Input 1

1 6

Sample Output 1

2

Two Scc groups can be created as follows:

Combine two c-shaped pieces into one S-shaped piece

Create two Scc groups, each from one S-shaped piece and two c-shaped pieces

Sample Input 2

12345 678901

Sample Output 2

175897

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <vector> 
#include <list> 
#include <map>
#include <set>//2分探索木
#include <deque>
#include <stack>
#include <bitset>
#include <algorithm>
#include <functional>
#include <numeric>
#include <utility>
#include <sstream>
#include <iostream>
#include <iomanip>
#include <cstdio>
#include <cmath>
#include <cstdlib>
#include <cctype>
#include <string>
#include <cstring>
#include <ctime>
#include <queue>// キュー　優先度付きキュー
#include <stack>
#include <complex>
#include <memory>
#include <assert.h>
#ifdef LOCAL
#include "UnionFind.h"//同じグループに属するか
#include "Prime.h"//素数判定
#include "RMQ.h"//区間最小値
#include "BIT.h"//累積和
#include "Dijkstra.h"//単一始点最短経路(負の辺があるときは動作しない)　O(ElogV)
#include "Kruskal.h"//最小全域木 O(ElogV)
#endif

using namespace std;

//conversion
//------------------------------------------
inline long long toInt(string s) { long long v; istringstream sin(s); sin >> v; return v; }
template<class T> inline string toString(T x) { ostringstream sout; sout << x; return sout.str(); }

//math
//-------------------------------------------
template<class T> inline T sqr(T x) { return x * x; }

//typedef
//------------------------------------------
typedef vector<int> VI;
typedef vector<VI> VVI;
typedef vector<string> VS;
typedef pair<int, int> PII;
typedef long long LL;
typedef vector<LL> VLL;
typedef vector<PII> VPII;

//container util
//------------------------------------------
#define ALL(a)  (a).begin(),(a).end()
#define RALL(a) (a).rbegin(), (a).rend()
#define PB push_back
#define MP make_pair
#define SZ(a) int((a).size())
#define EACH(t,c) for(typeof((c).begin()) t=(c).begin(); t!=(c).end(); ++t)
#define EXIST(s,e) ((s).find(e)!=(s).end())
#define SORT(c) sort((c).begin(),(c).end())

//repetition
//------------------------------------------
#define FOR(t,a,b) for(int t=(a);t<(b);++t)
#define REP(t,n)  FOR(t,0,n)

//constant
//------------------------------------------
const double EPS = 1e-10;
const double PI = acos(-1.0);

//clear memory
//------------------------------------------
#define CLR(a) memset((a), 0 ,sizeof(a))

//debug
//------------------------------------------
#if defined(__GNUC__) 
#include <assert.h>
#define ASSERT_(x) assert(x)
#else
#include <assert.h>
#define ASSERT_(x) assert(x)
#endif
#ifdef _DEBUG
#define dump(x)  cerr << #x << '=' << (x) << endl;
#define debug(x) cerr << #x << '=' << (x) << '('<<'L' << __LINE__ << ')' << ' ' << __FILE__ << endl;
#define ASSERT(x) {if (!(x)){std::cerr << "\nError!!\n" << "info string file:" << __FILE__ << " line:" << __LINE__ <<" "<< #x<< std::endl;ASSERT_(x);}}
#else
#define ASSERT(x) ((void)0)
#define debug(x) ((void)0)
#define dump(x)  ((void)0)
#endif // _DEBUG
template<class T> void showVector(vector<T>& v) {
	for (int i = 0; i < v.size(); ++i)
		cerr << v[i] << " ";
	cerr << endl;
}


//mod
//-------------------------------------------
const LL mod = (1e+9) + 7;
LL mod_pow(LL x, LL n, LL mod) {
	if (n == 0) { return 1; }
	LL res = mod_pow(x * x % mod, n / 2, mod);
	if (n & 1) { res = res * x % mod; }
	return res;
}

//bitop
//-------------------------------------------
#if defined(__GNUC__)
#include <immintrin.h>
int popcount(int a) {
	return __builtin_popcount(a);
}
#elif defined(_MSC_VER)
#include <intrin.h>
int popcount(int a) {
	return __popcnt(a);
}
#endif 

//gcd lcm
//-------------------------------------------
LL gcd(LL a, LL b) { if (a % b == 0) { return b; } else return gcd(b, a % b); }
LL lcm(LL a, LL b) { return a / gcd(a, b) * b; }


//YES_NO
//------------------------------------------
#define Yes_ cout<<"Yes"<<endl; return 0;
#define No_ cout<<"No"<<endl; return 0;

#define YES_ cout<<"YES"<<endl; return 0;
#define NO_ cout<<"NO"<<endl; return 0;

#define POSSIBLE cout<<"POSSIBLE"<<endl; return 0;
#define IMPOSSIBLE cout<<"IMPOSSIBLE"<<endl; return 0;

//matrix
//------------------------------------------
template <class T> class matrix : public vector< vector<T> > {
private:
	int tate_, yoko_;
public:
	matrix(const int tate__, const int yoko__) {
		ASSERT(tate__ > 0); ASSERT(yoko__ > 0);
		this->resize(tate__); for (size_t i = 0; i < this->size(); i++) { (*this)[i].resize(yoko__); }tate_ = tate__; yoko_ = yoko__;
	}
	matrix() {};
	int tate() const { return tate_; } int yoko() const { return yoko_; }
	void resizematrix(const int tate__, const int yoko__) {
		ASSERT(tate__ > 0); ASSERT(yoko__ > 0);
		this->resize(tate__); for (size_t i = 0; i < this->size(); i++) { (*this)[i].resize(yoko__); }tate_ = tate__; yoko_ = yoko__;
	}
	void setzero() { for (int i = 0; i < tate(); i++) for (int j = 0; j < yoko(); j++) { (*this)[i][j] = 0; } }
};

template<class T> std::ostream& operator<<(std::ostream & os, const matrix<T> & m)
{
	for (int j = 0; j < m.tate(); j++) { for (int i = 0; i < m.yoko(); i++) { os << (int)m[j][i]; }os << endl; }
	return os;
}
#if 1
//time
//------------------------------------------
#if defined(__GNUC__) 
#include <sys/time.h>
#include <immintrin.h>
#include <string.h>
LL starttime;
inline LL now() {
	struct timeval tv;
	gettimeofday(&tv, NULL);
	LL t = tv.tv_sec * 1000LL + tv.tv_usec / 1000LL;
	return t;
}
inline LL elapsed() { return now() - starttime; }
#else
#include <chrono>
#include <intrin.h>
typedef std::chrono::milliseconds::rep TimePoint;
inline TimePoint now() { return std::chrono::duration_cast<std::chrono::milliseconds>(std::chrono::steady_clock::now().time_since_epoch()).count(); }
TimePoint starttime;
inline TimePoint elapsed() { return now() - starttime; }
#endif
#endif

//=====================================================
int main() {
	LL S, C;
	cin >> S >> C;

	int ans = 0;
	int m = min(S, C / 2LL);
	C -= m * 2LL;
	ans += m;
	ans += (C / 4);

	cout << ans << endl;
}