Problem:
Score : 100 points

Problem Statement

The door of Snuke's laboratory is locked with a security code.

The security code is a 4-digit number. We say the security code is hard to enter when it contains two consecutive digits that are the same.

You are given the current security code S. If S is hard to enter, print Bad; otherwise, print Good.

Constraints

S is a 4-character string consisting of digits.

Input

Input is given from Standard Input in the following format:

S

Output

If S is hard to enter, print Bad; otherwise, print Good.

Sample Input 1

3776

Sample Output 1

Bad

The second and third digits are the same, so 3776 is hard to enter.

Sample Input 2

8080

Sample Output 2

Good

There are no two consecutive digits that are the same, so 8080 is not hard to enter.

Sample Input 3

1333

Sample Output 3

Bad

Sample Input 4

0024

Sample Output 4

Bad

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
 
typedef long long ll;
typedef vector<int> vi;
typedef vector<ll> vl;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
 
#define REP(i, n) for (int i = 0; i < (int)(n); i++)
#define FOR(i, a, b) for (int i = (int)(a); i < (int)(b); i++)
#define FORR(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)
 
#define CHMIN(a, b) (a) = min((a), (b))
#define CHMAX(a, b) (a) = max((a), (b))
 
#define DEBUG(x) cout << #x << ": " << (x) << endl
#define PRINT(x) cout << x << endl
#define all(x) x.begin(),x.end()
 
 
int main() {
 
    string s;
    cin >> s;
 
    char prev = 'A'; 
    for(int i=0;i<4;i++){
        if(prev==s[i]){
            cout << "Bad" << endl;
            return 0;
        }
        prev = s[i];
    }
 
    cout<< "Good" << endl;
    return 0;
 
}