Problem:
Score : 100 points

Problem Statement

You are given positive integers X and Y.
If there exists a positive integer not greater than 10^{18} that is a multiple of X but not a multiple of Y, choose one such integer and print it.
If it does not exist, print -1.

Constraints

1 ≤ X,Y ≤ 10^9

X and Y are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

Print a positive integer not greater than 10^{18} that is a multiple of X but not a multiple of Y, or print -1 if it does not exist.

Sample Input 1

8 6

Sample Output 1

16

For example, 16 is a multiple of 8 but not a multiple of 6.

Sample Input 2

3 3

Sample Output 2

-1

A multiple of 3 is a multiple of 3.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#define INF 1e9
using namespace std;

#define REPR(i,n) for(int i=(n); i >= 0; --i)
#define FOR(i, m, n) for(int i = (m); i < (n); ++i)
#define REP(i, n) for(int i=0, i##_len=(n); i<i##_len; ++i)
#define ALL(a)  (a).begin(),(a).end()

template<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return true; } return false; }
template<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return true; } return false; }
int gcd(int a,int b){return b?gcd(b,a%b):a;}
typedef long long ll;
ll gcd(ll a,ll b){return b?gcd(b,a%b):a;}


int main() {
    ll X,Y;
    cin >> X >> Y;

    if (X%Y == 0) {
        cout << -1 << endl;
        return 0;
    }
    cout << X * (Y+1) << endl;
    return 0;

}