Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>

using namespace std;

int main()
{
	ios_base::sync_with_stdio(false);
	cin.tie(nullptr);
	cout.tie(nullptr);

	vector<vector<int32_t>> A(3, vector<int32_t>(3));
	vector<vector<bool>> M(3, vector<bool>(3, false));

	for(int32_t i = 0; i < 3; ++i)
	{
		for(int32_t j = 0; j < 3; ++j)
		{
			cin >> A[i][j];
		}
	}

	int32_t N;
	cin >> N;

	vector<int32_t> B(N);
	for(auto& b : B)
	{
		cin >> b;
	}

	for(const auto& b : B)
	{
		for(int32_t i = 0; i < 3; ++i)
		{
			for(int32_t j = 0; j < 3; ++j)
			{
				if(A[i][j] == b)
				{
					M[i][j] = true;
				}
			}
		}
	}

	bool status = false;

	if(M[0][0] and M[0][1] and M[0][2])		status = true;
	else if(M[1][0] and M[1][1] and M[1][2])status = true;
	else if(M[2][0] and M[2][1] and M[2][2])status = true;
	else if(M[0][0] and M[1][0] and M[2][0])status = true;
	else if(M[0][1] and M[1][1] and M[2][1])status = true;
	else if(M[0][2] and M[1][2] and M[2][2])status = true;
	else if(M[0][0] and M[1][1] and M[2][2])status = true;
	else if(M[0][2] and M[1][1] and M[2][0])status = true;

	cout << (status ? "Yes" : "No") << "\n";

	return 0;
}