Problem:
Score : 200 points

Problem Statement

You are given a string S of length N consisting of lowercase English letters, and an integer K.
Print the string obtained by replacing every character in S that differs from the K-th character of S, with *.

Constraints

1 \leq K \leq N\leq 10

S is a string of length N consisting of lowercase English letters.

N and K are integers.

Input

Input is given from Standard Input in the following format:

N
S
K

Output

Print the string obtained by replacing every character in S that differs from the K-th character of S, with *.

Sample Input 1

5
error
2

Sample Output 1

*rr*r

The second character of S is r. When we replace every character in error that differs from r with *, we get the string *rr*r.

Sample Input 2

6
eleven
5

Sample Output 2

e*e*e*

Sample Input 3

9
education
7

Sample Output 3

******i**

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>

#define ipair pair<int,int>
#define rep(i,n) for(i=0;i<n;i++)
#define repj(i,j,n) for(i=j;i<n;i++)

#define PB(a,i) (a).push_back(i)
#define ALL(a) (a).begin(),(a).end()
#define SIZE(a,n) (a).resize(n)

#define OK(i) cout<<"OK "<<i<<endl
#define Yes cout<<"Yes"<<endl
#define YES cout<<"YES"<<endl
#define No cout<<"No"<<endl
#define NO cout<<"NO"<<endl

using namespace std;

typedef long long int lli;
typedef long long ll;
typedef vector<int> vi;
typedef vector< vector<int> > Matrix;



int main() {
	string s;
	int n, k, i;
	char t;

	cin >> n;
	cin >> s;
	cin >> k;

	t = s[k - 1];

	rep(i, n) {
		if (s[i] != t)s[i] = '*';
	}

	cout << s;

	return 0;
}