Problem:
Score : 100 points

Problem Statement

You are given two positive integers a and b.
Let x be the average of a and b.
Print x rounded up to the nearest integer.

Constraints

a and b are integers.

1 \leq a, b \leq 100

Input

Input is given from Standard Input in the following format:

a b

Output

Print x rounded up to the nearest integer.

Sample Input 1

1 3

Sample Output 1

2

The average of 1 and 3 is 2.0, and it will be rounded up to the nearest integer, 2.

Sample Input 2

7 4

Sample Output 2

6

The average of 7 and 4 is 5.5, and it will be rounded up to the nearest integer, 6.

Sample Input 3

5 5

Sample Output 3

5

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
#define rep(i,x) for(int i=0;i<x;i++)
#define put(ans)    cout << ans << endl;
#define sort(s) sort(s.begin(),s.end())
#define reverse(s) reverse(s.begin(),s.end())

//最大公約数
ll gcd(ll a, ll b) {
    return b ? gcd(b, a%b) : a;
}
//最小公倍数
ll lcm(ll a, ll b) {
    return a / gcd(a, b) * b;
}

int main(){
    double a,b;
    cin >> a >> b;
    cout  << ceil((a+b)/2) << endl;

    return 0;
}