Problem:
Score : 300 points

Problem Statement

1000000000000001 dogs suddenly appeared under the roof of Roger's house, all of which he decided to keep. The dogs had been numbered 1 through 1000000000000001, but he gave them new names, as follows:

the dogs numbered 1,2,\cdots,26 were respectively given the names a, b, ..., z;

the dogs numbered 27,28,29,\cdots,701,702 were respectively given the names aa, ab, ac, ..., zy, zz;

the dogs numbered 703,704,705,\cdots,18277,18278 were respectively given the names aaa, aab, aac, ..., zzy, zzz;

the dogs numbered 18279,18280,18281,\cdots,475253,475254 were respectively given the names aaaa, aaab, aaac, ..., zzzy, zzzz;

the dogs numbered 475255,475256,\cdots were respectively given the names aaaaa, aaaab, ...;

and so on.

To sum it up, the dogs numbered 1, 2, \cdots were respectively given the following names:

a, b, ..., z, aa, ab, ..., az, ba, bb, ..., bz, ..., za, zb, ..., zz, aaa, aab, ..., aaz, aba, abb, ..., abz, ..., zzz, aaaa, ...

Now, Roger asks you:

"What is the name for the dog numbered N?"

Constraints

N is an integer.

1 \leq N \leq 1000000000000001

Input

Input is given from Standard Input in the following format:

N

Output

Print the answer to Roger's question as a string consisting of lowercase English letters.

Sample Input 1

2

Sample Output 1

b

Sample Input 2

27

Sample Output 2

aa

Sample Input 3

123456789

Sample Output 3

jjddja

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

// C++ program to find Excel 
// column name from a given 
// column number 
#include <bits/stdc++.h> 
#define MAX 50 
using namespace std; 

// Function to print Excel column name for a given column number 
void printString(int n) 
{ 
	char str[MAX]; // To store result (Excel column name) 
	int i = 0; // To store current index in str which is result 

	while (n > 0) { 
		// Find remainder 
		int rem = n % 26; 

		// If remainder is 0, then a 'Z' must be there in output 
		if (rem == 0) { 
			str[i++] = 'z'; 
			n = (n / 26) - 1; 
		} 
		else // If remainder is non-zero 
		{ 
			str[i++] = (rem - 1) + 'a'; 
			n = n / 26; 
		} 
	} 
	str[i] = '\0'; 

	// Reverse the string and print result 
	reverse(str, str + strlen(str)); 
	cout << str << endl; 

	return; 
} 

// Driver program to test above function 
int main() 
{ 
	int n;
  	cin>>n;
	printString(n); 
	return 0; 
}