Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <stdio.h>

int main(){
    int matrix[3][3];
    char x='b';
    for(int i=0;i<3;i++){
        for(int j=0;j<3;j++){
            scanf("%d", &matrix[i][j]);
        }
    }
    int n;
    scanf("%d",&n);
    int input[n];
    for(int k=0;k<n;k++){
        scanf("%d", &input[k]);
        for(int i=0;i<3;i++){
            for(int j=0;j<3;j++){
                if(input[k] == matrix[i][j]){
                    matrix[i][j] = x;
                }
            }
        }
    }
    int ctr[6] = {0};
    int last=2;
    for(int i=0;i<3;i++){
        if(matrix[i][0]==x){
            ++ctr[0];
        }
        if(matrix[i][2]==x){
            ++ctr[1];
        }
        if(matrix[0][i]==x){
            ++ctr[2];
        }
        if(matrix[2][i]==x){
            ++ctr[3];
        }
        if(matrix[i][i]==x){
            ++ctr[4];
        } 
        if(matrix[i][last--]==x){
            ++ctr[5];
        }
    }
    int flag = 0;
    for(int i=0;i<6;i++){
        if(ctr[i]>=3){
            flag = 1;
        }
    }
    printf("%s\n", (flag == 1) ? "Yes" : "No");

    return 0;
}