Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef vector<long long> vll;
typedef vector<pair<int,int>> vp;
typedef pair<int,int> pii;
#define INF (int)(1e9)
#define MAXX 1.1529215e+18
#define inf 999999
#define EPS (1e-7)
#define rep(i,n) for(int i=0; i<(int)(n);i++)
#define REP(i,n) for(int i=1;i<=(int)(n);i++)
#define FOR(i,k,n) for(int i=(k);i<(int)(n);i++)
#define ALL(a)  a.begin(),a.end()
#define RALL(a) a.begin(),a.end(),greater<int>()
#define ROT(a) a.begin(),a.begin()+1,a.end()
#define RROT(a) a.begin(),a.end()-1,a.end()
#define PB push_back
#define MP make_pair
#define PI acos(-1.0)
#define sz(a) a.size()
const ll MOD = 1e9+7;
const int MAX = 10000000;
template<typename T1, typename T2> inline bool chmin(T1 &a, T2 b) { if (a > b) { a = b; return 1; } return 0; }
template<typename T1, typename T2> inline bool chmax(T1 &a, T2 b) { if (a < b) { a = b; return 1; } return 0; }
template<typename T> T gcd(T a, T b) { if (b == 0) return a; return gcd(b, a % b); }
//cout << 'H' << endl;
//next_permutation(ALL(p));
//typedef priority_que<int> pque;//これは大きい順
//typedef priority_que<int, vector<int>, greater<int>> pque;//これは小さい順


int main(){
	int a[3][3];
	int b[3][3];
	rep(i,3) rep(j,3){
		cin >> a[i][j];
		b[i][j] = 0;
	}
	int n;
	cin >> n;
	rep(i,n){
		int x;
		cin >> x;
		rep(j,3) rep(k,3){
			if(a[j][k] == x){
				b[j][k] = 1;
			}
		}
	}
	int flag=0;
	if((b[0][0]+b[0][1]+b[0][2])==3)flag = 1;
	else if((b[1][0]+b[1][1]+b[1][2])==3) flag = 1;
	else if((b[2][0]+b[2][1]+b[2][2])==3) flag = 1;
	else if((b[0][0]+b[1][0]+b[2][0])==3) flag = 1;
	else if((b[0][2]+b[1][2]+b[2][2])==3) flag = 1;
	else if((b[0][1]+b[1][1]+b[2][1])==3) flag = 1;
	else if((b[0][0]+b[1][1]+b[2][2])==3) flag = 1;
	else if((b[0][2]+b[1][1]+b[2][0])==3) flag = 1;

	if(flag == 1){
		cout << "Yes" << endl;
	}else{
		cout << "No" << endl;
	}

  return 0;
}