Problem:
Score : 100 points

Problem Statement

A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.

Given a string S, determine whether it is coffee-like.

Constraints

S is a string of length 6 consisting of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S

Output

If S is coffee-like, print Yes; otherwise, print No.

Sample Input 1

sippuu

Sample Output 1

Yes

In sippuu, the 3-rd and 4-th characters are equal, and the 5-th and 6-th characters are also equal.

Sample Input 2

iphone

Sample Output 2

No

Sample Input 3

coffee

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;
#define int long long
#define FOR(i,a,b) for(int i=(a); i<=(b); i++) 
#define rep(i,n); for(int i = 0; i < (n); i++)
#define chmin(a,b) if((a)>(b)) (a)=(b); 
#define chmax(a,b) if((a)<(b)) (a)=(b);
#define vi vector<int>
#define all(v) (v).begin(),(v).end()
#define pb push_back
int gcd(int a,int b){/*a>=0,b>=0,￢(a=b=0)*/
  while(min(a,b)>0){if(a<b)swap(a,b);a%=b;}return max(a,b);
}
int dx[]={0,1,0,-1,1,-1,-1,1};
int dy[]={1,0,-1,0,1,1,-1,-1};
const int MOD = 1e9+7;
const int INF = 1e18+10;

/*----------------------------------------------*/
signed main(){
  int n,x,y;
  cin>>n>>x>>y;
  x--;y--;
  vector<vi> d(n,vi (n,0));
  rep(i,n){
    rep(j,n) d[i][j]=abs(i-j);
  }
  rep(i,n){
    rep(j,n){
      chmin(d[i][j],abs(x-i)+abs(j-y)+1);
      chmin(d[i][j],abs(y-i)+abs(j-x)+1);
    }
  }
  vi ans(n+1);
  rep(i,n){
    rep(j,n){
      ans[d[i][j]]++;
    }
  }
  FOR(i,1,n-1) cout<<ans[i]/2<<endl;
  return 0;
}