Problem:
Score: 100 points

Problem Statement

E869120 has A 1-yen coins and infinitely many 500-yen coins.

Determine if he can pay exactly N yen using only these coins.

Constraints

N is an integer between 1 and 10000 (inclusive).

A is an integer between 0 and 1000 (inclusive).

Input

Input is given from Standard Input in the following format:

N
A

Output

If E869120 can pay exactly N yen using only his 1-yen and 500-yen coins, print Yes; otherwise, print No.

Sample Input 1

2018
218

Sample Output 1

Yes

We can pay 2018 yen with four 500-yen coins and 18 1-yen coins, so the answer is Yes.

Sample Input 2

2763
0

Sample Output 2

No

When we have no 1-yen coins, we can only pay a multiple of 500 yen using only 500-yen coins. Since 2763 is not a multiple of 500, we cannot pay this amount.

Sample Input 3

37
514

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <bitset>
#include <vector>
#include <string>
#include <algorithm>
#include <set>
#include <map>
#include <cmath>
#include <regex>
using namespace std;
using ll = long long int;
using dd = long double;
const ll MOD = 1e9 + 7;

vector<string> dfs(string s, ll depth, vector<char> symbol)
{
    vector<string> ret;
    if (depth == 0)
    {
        ret.push_back(s);
        return ret;
    }

    for (ll i = 0; i < symbol.size(); i++)
    {
        auto vec = dfs(s + symbol[i], depth - 1, symbol);
        for (auto &&e : vec)
        {
            ret.push_back(e);
        }
    }
    return ret;
}

ll gcd(ll a, ll b)
{
    if (a % b == 0)
    {
        return b;
    }
    return gcd(b, a % b);
}

int main()
{
    ll N, A;
    cin >> N >> A;

    cout << (N % 500 <= A ? "Yes" : "No") << endl;
}