Problem:
Score : 400 points

Problem Statement

Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.

You are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.

Constraints

2 ≦ |s| ≦ 10^5

s consists of lowercase letters.

Partial Score

200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.

Input

The input is given from Standard Input in the following format:

s

Output

If there exists no unbalanced substring of s, print -1 -1.

If there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.

Sample Input 1

needed

Sample Output 1

2 5

The string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.

Sample Input 2

atcoder

Sample Output 2

-1 -1

The string atcoder contains no unbalanced substring.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <algorithm>
#include <climits>
#include <iostream>
#include <string>
#include <utility>
#include <vector>
#include <set>
#include <map>
#include <queue>
#include <iomanip>
#include <cmath>
#include <stack>

using namespace std;
using ll = long long int;

template <class T> ostream &operator<<(ostream &os, vector<T> &v) {
  for (auto i = v.begin(); i != v.end(); i++) {
    os << *i << " ";
  }
  return os;
}


void solve(std::string s){
  char x = s[0];
  char y = s[1];
  if(x==y) {
    std::cout << 1 << " "<<2 << std::endl;
    return;
  }
  for(ll i=2; i<s.size(); i++) {
    if(s[i]==x) {
      std::cout << (i-2)+1 <<" "<<i+1 << std::endl;
      return;
    } else if(s[i]==y) {
      std::cout << (i-1)+1 <<" "<<i+1<< std::endl;
      return;
    }
    x = s[i-1];
    y = s[i];
  }
  std::cout << -1 << " " << -1 << std::endl;
}

int main(){
  std::string s;
  std::cin >> s;
  solve(s);
  return 0;
}