Problem:
Score : 300 points

Problem Statement

Sitting in a station waiting room, Joisino is gazing at her train ticket.

The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).

In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.

The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Constraints

0≤A,B,C,D≤9

All input values are integers.

It is guaranteed that there is a solution.

Input

Input is given from Standard Input in the following format:

ABCD

Output

Print the formula you made, including the part =7.

Use the signs + and -.

Do not print a space between a digit and a sign.

Sample Input 1

1222

Sample Output 1

1+2+2+2=7

This is the only valid solution.

Sample Input 2

0290

Sample Output 2

0-2+9+0=7

0 - 2 + 9 - 0 = 7 is also a valid solution.

Sample Input 3

3242

Sample Output 3

3+2+4-2=7

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <iostream> // cout, endl, cin
#include <string> // string, to_string, stoi
#include <vector> // vector


using namespace std;
 
int main(){
    vector<int>a(4);
    for(int i=0;i<4;i++)cin>>a.at(i);
    string op="";
 
    for(int bit=0;bit<(1<<4);++bit){
     int x=0;
        for(int i=0;i<4;i++){
            if(bit&(1<<3)){
       x+=a.at(i);
              if(i!=0)op+="+";
            }
            else { x-=a.at(i); if(i!=0)op+="-";}
if(x==7) {cout<<a.at(0)<<op.at(0)<<a.at(1)<<op.at(1)<<a.at(2)<<op.at(2)<<a.at(3)<<"=7"; return 0;}

    }}


}