Problem:
Score : 200 points

Problem Statement

Takahashi's house has only one socket.

Takahashi wants to extend it with some number of power strips, each with A sockets, into B or more empty sockets.

One power strip with A sockets can extend one empty socket into A empty sockets.

Find the minimum number of power strips required.

Constraints

All values in input are integers.

2 \leq A \leq 20

1 \leq B \leq 20

Input

Input is given from Standard Input in the following format:

A B

Output

Print the minimum number of power strips required.

Sample Input 1

4 10

Sample Output 1

3

3 power strips, each with 4 sockets, extend the socket into 10 empty sockets.

Sample Input 2

8 9

Sample Output 2

2

2 power strips, each with 8 sockets, extend the socket into 15 empty sockets.

Sample Input 3

8 8

Sample Output 3

1

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>

using namespace std;

typedef long long ll;

#define sz(x) ((int)(x).size())
#define in(x) int x;cin>>x
#define bit(n) (1<<(n))

#define out(x) cout<<(x)<<endl;
#define err(x) cerr<<(x)<<endl;
#define errr(x,y) cerr<<(x)<<" "<<(y)<<endl;

#define rep(i,n) for (int i=0;i<(n);i++)
#define repp(i,n) for (int i=1;i<=(n);i++)

#define inf5 100002
#define inf9 1000000002

int main(){
	int a, b;
	cin >> a >> b;

	--a;--b;
	cout << (b + (a - 1)) / a << endl;

	return 0;
}