Problem:
Score : 200 points

Problem Statement

The word internationalization is sometimes abbreviated to i18n.
This comes from the fact that there are 18 letters between the first i and the last n.

You are given a string s of length at least 3 consisting of lowercase English letters.
Abbreviate s in the same way.

Constraints

3 ≤ |s| ≤ 100 (|s| denotes the length of s.)

s consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s

Output

Print the abbreviation of s.

Sample Input 1

internationalization

Sample Output 1

i18n

Sample Input 2

smiles

Sample Output 2

s4s

Sample Input 3

xyz

Sample Output 3

x1z

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <string>
#include <vector>
#include <algorithm>
#include <functional>  // std::greater<T>()

using namespace std;

// macro
#define ALL(obj) (obj).begin(), (obj).end()
#define REP(i, n) for (int i=0; i < (int)(n); i++)  // 0 ~ n-1
#define DESCEND greater<int>()  // sort 降順
#define UNIQUE(vec) (vec).erase(unique(ALL((vec))), (vec).end());  // 必ずsortを行なってから

// func declaration
template <class T> void printVec(vector<T>);


int main() {
    string str;
    cin >> str;
    cout << str.at(0) << str.size() - 2 <<str.at(str.size() - 1) << endl;
    return 0;
}

// function
template <class T> void printVec(vector<T> vec) {
    // 1要素ずつ、空白・改行なしで出力
    REP(i, vec.size()) {
        cout << vec.at(i);
    }
    cout << endl;
}