Problem:
Score : 200 points

Problem Statement

There are N gems. The value of the i-th gem is V_i.

You will choose some of these gems, possibly all or none, and get them.

However, you need to pay a cost of C_i to get the i-th gem.

Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid.

Find the maximum possible value of X-Y.

Constraints

All values in input are integers.

1 \leq N \leq 20

1 \leq C_i, V_i \leq 50

Input

Input is given from Standard Input in the following format:

N
V_1 V_2 ... V_N
C_1 C_2 ... C_N

Output

Print the maximum possible value of X-Y.

Sample Input 1

3
10 2 5
6 3 4

Sample Output 1

5

If we choose the first and third gems, X = 10 + 5 = 15 and Y = 6 + 4 = 10.
We have X-Y = 5 here, which is the maximum possible value.

Sample Input 2

4
13 21 6 19
11 30 6 15

Sample Output 2

6

Sample Input 3

1
1
50

Sample Output 3

0

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;
#include <ext/pb_ds/assoc_container.hpp>
using namespace __gnu_pbds;
#define lli long long int
#define ulli unsigned long long int
#define ld long double
#define fi first
#define se second
#define pb push_back
#define mp make_pair
#define loop(i,a,b) for(lli i=a;i<b;i++)
#define initialize(array,size,value) for(lli i=0;i<size;i++) array[i]=value
#define couta(array,size) for(lli i=0;i<size;i++) cout<<array[i]<<" "
#define vl vector<lli>
#define vp vector< pair <lli,lli> >
#define sl set<lli>
#define msp multiset < pair < long long , long long > > S;
#define pll pair<lli, lli>
#define mll map<lli, lli>            //for( map<lli, lli>::iterator i=temp.begin();i!=temp.end();i++)cout<<i->fi<<" "<<i->se<<endl;
#define mvl map<lli, vl>
#define umll unordered_map<lli, lli>
#define vt vector<pair<lli, pll >  >
#define vf vector<pair<pll,pll > >
#define qu queue<lli>
#define pq priority_queue<lli>
#define dq deque <lli>
#define ptr vector<lli>::iterator
#define bs(array,x) binary_search(array.begin(),array.end(),x) // also valid for set and multiset
#define lb(array,x) lower_bound(array.begin(),array.end(),x)
#define ub(array,x) upper_bound(array.begin(),array.end(),x)
#define nobw(array,i,j) upper_bound(array.begin(), array.end(), j)-lower_bound(array.begin(), array.end(), i) //number of numbers between i & j
#define vc clear()
#define endl '\n'
#define sp system("pause");
#define INF 9223372036854775807
#define MINF -9223372036854775808
typedef tree<pll,null_type,less<pll>,rb_tree_tag,
tree_order_statistics_node_update> indexed_set;
int main()
{
 	ios::sync_with_stdio(0);
    cin.tie(0);
    lli n;
    cin>>n;
    lli a[n],b[n];
    for(lli i=0;i<n;i++)cin>>a[i];
    for(lli i=0;i<n;i++)cin>>b[i];
    lli sum=0;
	for(lli i=0;i<n;i++)
	{
		if(a[i]>b[i])sum+=a[i]-b[i];
	}
	cout<<sum;
   	return 0;
 }