Problem:
Score : 200 points

Problem Statement

There are some animals in a garden. Each of them is a crane with two legs or a turtle with four legs.

Takahashi says: "there are X animals in total in the garden, and they have Y legs in total." Determine whether there is a combination of numbers of cranes and turtles in which this statement is correct.

Constraints

1 \leq X \leq 100

1 \leq Y \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

If there is a combination of numbers of cranes and turtles in which the statement is correct, print Yes; otherwise, print No.

Sample Input 1

3 8

Sample Output 1

Yes

The statement "there are 3 animals in total in the garden, and they have 8 legs in total" is correct if there are two cranes and one turtle. Thus, there is a combination of numbers of cranes and turtles in which the statement is correct.

Sample Input 2

2 100

Sample Output 2

No

There is no combination of numbers of cranes and turtles in which this statement is correct.

Sample Input 3

1 2

Sample Output 3

Yes

We also consider the case in which there are only cranes or only turtles.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#pragma comment(linker, "/stack:20000000")
#pragma GCC optimize("Ofast")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx")

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp> 
  
#define mp make_pair
#define f first
#define s second
#define ll long long
#define pb push_back
#define popb pop_back
#define popf pop_front

using namespace std;

using namespace __gnu_pbds;
template <typename T> using ordered_set = tree<T, null_type, std::less<T>, rb_tree_tag, tree_order_statistics_node_update>;

const int inf = 2e9+7, mod=1e9+7;
const int N = 1e6+321, E=14e5;

ll xx[8]={1, 1, -1, -1, 1, -1, 0, 0};
ll yy[8]={1, -1, 1, -1, 0, 0, 1, -1};

string s[10];

int main(){
	ios_base::sync_with_stdio(0); cin.tie(0);cout.tie(0);
	int n, m;
	cin >> n >> m;
	if(n*2<=m && n*4>=m && m%2==0)
		cout << "Yes";
	else
		cout << "No";
    return 0;
}