Problem:
Score : 100 points

Problem Statement

X and A are integers between 0 and 9 (inclusive).

If X is less than A, print 0; if X is not less than A, print 10.

Constraints

0 \leq X, A \leq 9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X A

Output

If X is less than A, print 0; if X is not less than A, print 10.

Sample Input 1

3 5

Sample Output 1

0

3 is less than 5, so we should print 0.

Sample Input 2

7 5

Sample Output 2

10

7 is not less than 5, so we should print 10.

Sample Input 3

6 6

Sample Output 3

10

6 is not less than 6, so we should print 10.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

/**
 * code generated by JHelper
 * More info: https://github.com/AlexeyDmitriev/JHelper
 * @author ExplodingFreeze
 */

#include <iostream>
#include <fstream>

#pragma comment(linker, "/stack:200000000")
#include <bits/stdc++.h>
#define int long long
#define f(i,a,b) for(int i=(a);i<(b);i++)
#define MOD 1000000007

using namespace std;

class ARounding {
public:
	void solve(std::istream& in, std::ostream& out) {
		int x,a;
		in >> x >> a;
		if(x<a)
			out << "0\n";
		else
			out << "10\n";
	}
};


int32_t main() {
	ios_base::sync_with_stdio(false);
	cin.tie(0);
	ARounding solver;
	std::istream& in(std::cin);
	std::ostream& out(std::cout);
	solver.solve(in, out);
	return 0;
}