Problem:
Score : 200 points

Problem Statement

A shop sells N kinds of fruits, Fruit 1, \ldots, N, at prices of p_1, \ldots, p_N yen per item, respectively. (Yen is the currency of Japan.)

Here, we will choose K kinds of fruits and buy one of each chosen kind. Find the minimum possible total price of those fruits.

Constraints

1 \leq K \leq N \leq 1000

1 \leq p_i \leq 1000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
p_1 p_2 \ldots p_N

Output

Print an integer representing the minimum possible total price of fruits.

Sample Input 1

5 3
50 100 80 120 80

Sample Output 1

210

This shop sells Fruit 1, 2, 3, 4, and 5 for 50 yen, 100 yen, 80 yen, 120 yen, and 80 yen, respectively.

The minimum total price for three kinds of fruits is 50 + 80 + 80 = 210 yen when choosing Fruit 1, 3, and 5.

Sample Input 2

1 1
1000

Sample Output 2

1000

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)


#include <bits/stdc++.h>

using namespace std;

#ifdef Adrian
#include "debug.h"
#else
#define debug(...) 9999
#endif

typedef long long ll;
typedef long double ld;
typedef complex<ld> point;
#define F first
#define S second
#define ii pair<ll,ll>
template <typename G>
struct triple{G F, S, T;
    bool operator < (triple<G> o)
    { return F < o.F; }
};
#define iii triple<int>



int main()
{

#ifdef Adrian
    //freopen("test.txt", "r", stdin);
#else
    ios_base::sync_with_stdio(0); cin.tie(0);cout.tie(0);
#endif


    int n, k;
    cin>>n>>k;
    vector<int> v(n);
    for(auto &i:v)
        cin>>i;

    sort(v.begin(), v.end());
    int ans = 0;
    for(int i=0; i<k; i++)
        ans += v[i];

    cout<<ans<<'\n';


    return 0;
}