Problem:
Score : 100 points

Problem Statement

We have weather records at AtCoder Town for some consecutive three days. A string of length 3, S, represents the records - if the i-th character is S, it means it was sunny on the i-th day; if that character is R, it means it was rainy on that day.

Find the maximum number of consecutive rainy days in this period.

Constraints

|S| = 3

Each character of S is S or R.

Input

Input is given from Standard Input in the following format:

S

Output

Print the maximum number of consecutive rainy days in the period.

Sample Input 1

RRS

Sample Output 1

2

We had rain on the 1-st and 2-nd days in the period. Here, the maximum number of consecutive rainy days is 2, so we should print 2.

Sample Input 2

SSS

Sample Output 2

0

It was sunny throughout the period. We had no rainy days, so we should print 0.

Sample Input 3

RSR

Sample Output 3

1

We had rain on the 1-st and 3-rd days - two "streaks" of one rainy day, so we should print 1.

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include<bits/stdc++.h>
#define LOCAL
using namespace std;

#ifdef LOCAL
#define trace(...) __f(#__VA_ARGS__, __VA_ARGS__)
#else
#define trace(...) 42
#endif

template <typename Arg1>
void __f(const char* name, Arg1&& arg1){
  cerr << name << ": " << arg1 << endl;
}
template <typename Arg1, typename... Args>
void __f(const char* names, Arg1&& arg1, Args&&... args){
  const char* comma = strchr(names + 1, ',');
  cerr.write(names, comma - names) << ": " << arg1 << " |";
  __f(comma + 1, args...);
}

typedef long long ll;
#define fi first
#define se second
const int N=2e6+1;
int n,k;
ll a[N];
int main(){
	ios::sync_with_stdio(false);
	cin.tie(0), cout.tie(0);
	
	string s;
	cin >> s;
//	ll len = 0;
//	for(int i = 0; s[i] != '\0'; ++i )
//		len++;
	
	ll cnt = 0;
//	for(int i = 0; i < len; ++i)
//	{
		if(s[0] == 'R' && s[1] == 'R' && s[2] == 'R')
		{
			cnt = 3;
		}
		else if( (s[0] == 'R' && s[1] == 'R' && s[2] == 'S') || (s[0] == 'S' && s[1] == 'R' && s[2] == 'R') )
		{
			cnt = 2;
		}
		else if((s[0] == 'R' && s[1] == 'S' && s[2] == 'R') )
		 cnt = 1;
//	}
	cout << cnt << "\n";
}