Problem:
Max Score: 250 Points

Problem Statement

Mr.X, who the handle name is T, looked at the list which written N handle names, S_1, S_2, ..., S_N.

But he couldn't see some parts of the list. Invisible part is denoted ?.

Please calculate all possible index of the handle name of Mr.X when you sort N+1 handle names (S_1, S_2, ..., S_N and T) in lexicographical order.

Note: If there are pair of people with same handle name, either one may come first.

Input

The input is given from standard input in the following format.

N
S_1
S_2
:
S_N
T

Output

Calculate the possible index and print in sorted order. The output should be separated with a space. Don't print a space after last number.

Put a line break in the end.

Constraints

1 ≤ N ≤ 10000

1 ≤ |S_i|, |T| ≤ 20 (|A| is the length of A.)

S_i consists from lower-case alphabet and ?.

T consists from lower-case alphabet.

Scoring

Subtask 1 [ 130 points ]

There are no ?'s.

Subtask 2 [ 120 points ]

There are no additional constraints.

Sample Input 1

2
tourist
petr
e

Sample Output 1

1

There are no invisible part, so there are only one possibility.
The sorted handle names are e, petr, tourist, so e comes first.

Sample Input 2

2
?o?r?s?
?et?
e

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <limits.h>
#include <algorithm>

using namespace std;

int n, same = 0, ans = 1;
char s[10000][21], t[21];

int main(){
	cin >> n;
	for (int i = 0; i < n; i++){
		cin >> s[i];
	}
	cin >> t;

	for (int i = 0; i < n; i++){
		int num = 0;
		bool flag = false;
		while (s[i][num] == t[num]){
			if (t[num] == 0){
				same++;
				flag = true;

				break;
			}

			num++;
		}
		if (!flag && s[i][num] < t[num]){
			ans++;
		}
	}

	for (int i = 0; i < same; i++){
		cout << ans + i << ' ';
	}

	cout << ans + same;

	cout << endl;

	return 0;
}