Problem:
Score : 200 points

Problem Statement

There are N balls placed in a row.
AtCoDeer the deer is painting each of these in one of the K colors of his paint cans.
For aesthetic reasons, any two adjacent balls must be painted in different colors.

Find the number of the possible ways to paint the balls.

Constraints

1≦N≦1000

2≦K≦1000

The correct answer is at most 2^{31}-1.

Input

The input is given from Standard Input in the following format:

N K

Output

Print the number of the possible ways to paint the balls.

Sample Input 1

2 2

Sample Output 1

2

We will denote the colors by 0 and 1. There are two possible ways: we can either paint the left ball in color 0 and the right ball in color 1, or paint the left in color 1 and the right in color 0.

Sample Input 2

1 10

Sample Output 2

10

Since there is only one ball, we can use any of the ten colors to paint it. Thus, the answer is ten.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define MOD 1000000007
#define rep(i, n) for(int i = 0; i < (int)(n); i++)
#define rep1(i, n) for(int i = 1; i <= (int)(n); i++)
#define show(x) {for(auto i: x){cout << i << " ";} cout<<endl;}
#define showm(m) {for(auto i: m){cout << m.x << " ";} cout<<endl;}
typedef long long ll;
typedef pair<int, int> P;
ll gcd(int x, int y){ return y?gcd(y, x%y):x;}
ll lcm(ll x, ll y){ return (x*y)/gcd(x,y);}


int main()
{
    int n, k;
    cin >> n >> k;

    ll ans = k;
    rep(i, n-1){
        ans *= k-1;
    }
    cout << ans << endl;
}