Problem:
Score : 100 points

Problem Statement

You are given three strings A, B and C. Check whether they form a word chain.

More formally, determine whether both of the following are true:

The last character in A and the initial character in B are the same.

The last character in B and the initial character in C are the same.

If both are true, print YES. Otherwise, print NO.

Constraints

A, B and C are all composed of lowercase English letters (a - z).

1 ≤ |A|, |B|, |C| ≤ 10, where |A|, |B| and |C| are the lengths of A, B and C, respectively.

Input

Input is given from Standard Input in the following format:

A B C

Output

Print YES or NO.

Sample Input 1

rng gorilla apple

Sample Output 1

YES

They form a word chain.

Sample Input 2

yakiniku unagi sushi

Sample Output 2

NO

A and B form a word chain, but B and C do not.

Sample Input 3

a a a

Sample Output 3

YES

Sample Input 4

aaaaaaaaab aaaaaaaaaa aaaaaaaaab

Sample Output 4

NO

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define rep(i,n) for(int (i) = 0; (i) < (n); ++(i))
#define rrep(i,n) for(int (i) = (n) - 1; (i) >= 0; --(i)) //Reversi rep
#define nfor(i,a,b) for(int (i) = (a); (i) < (b); ++(i)) //Natural for
#define rfor(i,a,b) for(int (i) = (b); (i) >= (a); --(i)) //Reversi for

int main()
{
    string a,b,c,ans;
    cin >> a >> b >> c;
    if(a[a.size() - 1] == b[0] && b[b.size() - 1] == c[0]){
        cout << "YES" << endl;
    }else{
        cout << "NO" << endl;
    }
    return 0;
}