Problem:
Score : 100 points

Problem Statement

A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.

Given a string S, determine whether it is coffee-like.

Constraints

S is a string of length 6 consisting of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S

Output

If S is coffee-like, print Yes; otherwise, print No.

Sample Input 1

sippuu

Sample Output 1

Yes

In sippuu, the 3-rd and 4-th characters are equal, and the 5-th and 6-th characters are also equal.

Sample Input 2

iphone

Sample Output 2

No

Sample Input 3

coffee

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)


#include<iostream>
#include<algorithm>
#include<string>
#include<vector>
#include<queue>
#include<map>
#include<math.h>
#include<numeric>
#include<utility>
#include<unordered_map> //hash map
#include<cmath>

#define rep(i,a,n) for(int (i)=(a);(i)<(n);(i)++)
#define rrep(i,a,n) for(int (i)=(a);(i)>=(n);(i)--)

#define INF 10000007

typedef  long long ll;

using namespace std;

ll gcd(ll a,ll b){
    if (b==0)return a;
    return gcd(b,a%b);
}

ll deg(int i){
  ll ret = 1;
  while(i != 0){
    if(i/10 == 0){
      break;
    }
    i/=10;
  }
  
  return i;
}

void solve(){
  string s;
  cin >> s;
  if(s[2]==s[3]&&s[4]==s[5]) cout << "Yes"<<endl;
  else cout <<"No" << endl;


}


int main(){
    cin.tie(0);
    ios::sync_with_stdio(false);
    solve();
}