Problem:
Score : 400 points

Problem Statement

Let {\rm comb}(n,r) be the number of ways to choose r objects from among n objects, disregarding order.
From n non-negative integers a_1, a_2, ..., a_n, select two numbers a_i > a_j so that {\rm comb}(a_i,a_j) is maximized.
If there are multiple pairs that maximize the value, any of them is accepted.

Constraints

2 \leq n \leq 10^5

0 \leq a_i \leq 10^9

a_1,a_2,...,a_n are pairwise distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print a_i and a_j that you selected, with a space in between.

Sample Input 1

5
6 9 4 2 11

Sample Output 1

11 6

\rm{comb}(a_i,a_j) for each possible selection is as follows:

\rm{comb}(4,2)=6

\rm{comb}(6,2)=15

\rm{comb}(6,4)=15

\rm{comb}(9,2)=36

\rm{comb}(9,4)=126

\rm{comb}(9,6)=84

\rm{comb}(11,2)=55

\rm{comb}(11,4)=330

\rm{comb}(11,6)=462

\rm{comb}(11,9)=55

Thus, we should print 11 and 6.

Sample Input 2

2
100 0

Sample Output 2

100 0

Solution in C++14 (GCC 5.4.1) (judge verdict: Time Limit Exceeded)


/*
	@・ω・@
*/

/*****/

# include <iostream>
# include <vector>
# include <algorithm>
# include <string>
# include <sstream>
# include <cmath>
# include <queue>
# include <stack>
# include <map>
# include <iomanip>	//cout << fixed << setprecision(桁数);
# include <stdexcept>
# include <functional>

//#define int long long

using namespace std;
using ll = long long;
using ld = long double;
using pll = pair<long long, long long>;
template<class T> using vec = vector<T>;

#define debug(x) (std::cerr << x)
#define debugln(x) (std::cerr << x << "\n")
#define debug_tab(n, x) (std::cerr << strMulti("\t",n) << (x) << "\n")
#define debug_cout(x) (std::cerr << #x << " : " <<  (x) << "\n")
#define debug_coutvec(x) std::cerr << #x << " : "; _debug_coutvec(x)
#define debug_tabcout(n, x) (std::cerr << strMulti("\t",n) << #x << " : " <<  (x) << "\n")
#define debug_headcout(h, x) (std::cerr << h << " : " <<  (x) << "\n")
#define debug_tabheadcout(n, h, x) (std::cerr << strMulti("\t",n) << h << " : " <<  (x) << "\n")

#define rep(i, n) for(int i=0, i##_len=(n); i<i##_len; ++i)
#define rep1(i, n) for(int i=1, i##_len=(n); i<=i##_len; ++i)
#define rrep(i, n) for(int i=(n)-1; i >= 0; --i)
#define rrep1(i, n) for(int i=(n); i > 0; --i)
#define step(i, a, n) for(int i=(a), i##_len=(a)+(n); i<i##_len; ++i)
#define rstep(i, a, n) for(int i=(a)+(n)-1, i##_len=(a); i>=i##_len; --i)
#define range(i, a, b) for(int i=(a), i##_len=(b); i<i##_len; ++i)
#define rrange(i, a, b) for(int i=(b)-1, i##_len=(a); i>=i##_len; --i)
#define repll(i, n) for(ll i=0, i##_len=(n); i<i##_len; ++i)
#define rep1ll(i, n) for(ll i=1, i##_len=(n); i<=i##_len; ++i)
#define rrepll(i, n) for(ll i=(n)-1; i >= 0; --i)
#define rrep1ll(i, n) for(ll i=(n); i > 0; --i)
#define stepll(i, a, n) for(ll i=(a), i##_len=(a)+(n); i<i##_len; ++i)
#define rstepll(i, a, n) for(ll i=(a)+(n)-1, i##_len=(a); i>=i##_len; --i)
#define rangell(i, a, b) for(ll i=(a), i##_len=(b); i<i##_len; ++i)
#define rrangell(i, a, b) for(ll i=(b)-1, i##_len=(a); i>=i##_len; --i)
#define all(x) (x).begin(), (x).end()
#define pair(a, b) make_pair(a, b)
std::string strMulti(std::string t, int n) { std::string out = ""; for (int i = 0; i < n; i++) { out += t; } return out; }
template<class T> void _debug_coutvec(vector<T> ar, string space = " ") { rep(i, ar.size()) { debug(ar[i] << space); } debugln(""); }
constexpr int INF = 2000000000;	// 2*10^9
constexpr ll INFL = 1ll << 60ll;

template<class T> bool chmax(T& a, T b) { if (a < b) { a = b; return true; } return false; }
template<class T> bool chmin(T& a, T b) { if (a > b) { a = b; return true; } return false; }
template<class T> T divup(T a, T b) { if (a % b == 0) { return a / b; } return a / b + 1; }
template<class T> bool cmp_2nd(pair<T, T> a, pair<T, T> b) { if (a.second != b.second) { return a.second < b.second; } return a.first < b.first; }
template<class T> T mod_pow(T x, T n, const T& p) { T ret = 1; while (n > 0) { if (n & 1) { (ret *= x) %= p; } (x *= x) %= p; n >>= 1; } return ret; }
template<class T> T math_P(T m, T n) { T ret = 1; for (T i = m; i > m - n; i--) { ret *= i; } return ret; }
template<class T> T math_C(T m, T n) { T ret = math_P(m, n); for (T i = 2; i <= n; i++) { ret /= i; } return ret; }
template<class T> T math_gcd(T a, T b) { if (b == 0) { return a; } else { return math_gcd(b, a % b); } }

//constexpr ll MOD = 1000000007;	// 10^9+7
constexpr ll MOD = 998244353;

/*****/


// index が条件を満たすかどうか
template<class T>
bool isOK(vector<T>& list, int index, T key) {
	if (list[index] >= key) { return true; }
	else { return false; }
}

// 汎用的な二分探索のテンプレ
template<class T>
int binary_search(vector<T>& list, T key) {
	int ng = -1; //「index = 0」が条件を満たすこともあるので、初期値は -1
	int ok = (int)list.size(); // 「index = a.size()-1」が条件を満たさないこともあるので、初期値は a.size()

	// ok と ng のどちらが大きいかわからないことを考慮
	while (abs(ok - ng) > 1) {
		int mid = (ok + ng) / 2;

		if (isOK(list, mid, key)) ok = mid;
		else ng = mid;
	}
	return ok;
}

void Main()
{
	int N;
	cin >> N;
	vec<int> A(N);
	rep(i, N)
	{
		cin >> A[i];
	}

	sort(all(A));

	/**
	rep(i, N)
	{
		rep(j, i)
		{
			debugln(A[i] << "," << A[j] << " = " << math_C(A[i], A[j]));
		}
	}
	/**/

	int i = N - 1;
	int begin = binary_search(A, A[i / 2]);
	debug_cout(begin);
	int maxC_j = -1;
	int maxC = -1;// math_C(A[i], A[maxC_j]);

	range(j, max(0, begin - 1), min(begin + 2, i))
	{
		int c = math_C(A[i], A[j]);

		if (maxC < c)
		{
			maxC = c;
			maxC_j = j;
		}
	}

	cout << A[i] << " " << A[maxC_j];
}

/*****/

int main()
{
	std::ios::sync_with_stdio(false);
	std::cin.tie(0);

	//std::cout << std::fixed << std::setprecision(10);

	/**
	while (true)
	{
		Main();
		std::cerr << flush;
		cout << endl;
	}
	/*/
	Main();
	std::cerr << flush;
	cout << endl;
	/**/

	return 0;
}