Problem:
Score : 200 points

Problem Statement

Tak performed the following action N times: rolling two dice.
The result of the i-th roll is D_{i,1} and D_{i,2}.

Check if doublets occurred at least three times in a row.
Specifically, check if there exists at lease one i such that D_{i,1}=D_{i,2}, D_{i+1,1}=D_{i+1,2} and D_{i+2,1}=D_{i+2,2} hold.

Constraints

3 \leq N \leq 100

1\leq D_{i,j} \leq 6

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
D_{1,1} D_{1,2}
\vdots
D_{N,1} D_{N,2}

Output

Print Yes if doublets occurred at least three times in a row. Print No otherwise.

Sample Input 1

5
1 2
6 6
4 4
3 3
3 2

Sample Output 1

Yes

From the second roll to the fourth roll, three doublets occurred in a row.

Sample Input 2

5
1 1
2 2
3 4
5 5
6 6

Sample Output 2

No

Sample Input 3

6
1 1
2 2
3 3
4 4
5 5
6 6

Sample Output 3

Yes

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <algorithm>
#include <bits/stdc++.h>
#define FAST ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0);
#define ll long long
#define mm(arr) memset(arr, 0, sizeof(arr))
#define scanArray(a,n) for(int i = 0; i < n; i++){cin >> a[i];}
#define pb push_back
#define PI 3.141592653589793
#define MOD 1000000007

using namespace std;
int main(){
    FAST
    int n; cin >> n;
    int a[n],b[n];
    int cnt=0;
    for(int i=0; i<n; i++){
        cin >> a[i] >> b[i];
        if(a[i] == b[i]){
            cnt++;
        }
    }
    if(cnt>=3){
        cout << "Yes" << endl;
    }
    else{
        cout << "No" << endl;
    }
    return 0;
}