Problem:
Score : 300 points

Problem Statement

Takahashi is organizing a party.

At the party, each guest will receive one or more snack pieces.

Takahashi predicts that the number of guests at this party will be A or B.

Find the minimum number of pieces that can be evenly distributed to the guests in both of the cases predicted.

We assume that a piece cannot be divided and distributed to multiple guests.

Constraints

1 \leq A, B \leq 10^5

A \neq B

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the minimum number of pieces that can be evenly distributed to the guests in both of the cases with A guests and B guests.

Sample Input 1

2 3

Sample Output 1

6

When we have six snack pieces, each guest can take three pieces if we have two guests, and each guest can take two if we have three guests.

Sample Input 2

123 456

Sample Output 2

18696

Sample Input 3

100000 99999

Sample Output 3

9999900000

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <vector>
#include <algorithm>
#include <queue>
#include <set>
#include <map>
#include <string>
#include <cmath>
#include <climits>

using namespace std;

#define REP(i,n) for(int i=0, i##_len=(n); i<i##_len; ++i)

typedef long long LL;
typedef vector<int> VI;

int gcd(LL m, LL n) {
  LL temp;
  while (m % n != 0) {
    temp = n;
    n = m % n;
    m = temp;
  }
  return n;
}

int main() {
  LL A, B;
  cin >> A >> B;
  cout << A*B / gcd(A, B) << endl;;
  return 0;
}