Problem:
Score : 400 points

Problem Statement

Give a pair of integers (A, B) such that A^5-B^5 = X.
It is guaranteed that there exists such a pair for the given integer X.

Constraints

1 \leq X \leq 10^9

X is an integer.

There exists a pair of integers (A, B) satisfying the condition in Problem Statement.

Input

Input is given from Standard Input in the following format:

X

Output

Print A and B, with space in between.
If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.

A B

Sample Input 1

33

Sample Output 1

2 -1

For A=2 and B=-1, A^5-B^5 = 33.

Sample Input 2

1

Sample Output 2

0 -1

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>

using namespace std;

typedef long long ll;

#define sz(x) ((int)(x).size())
#define in(x) int x;cin>>x
#define inn(x, y) int x,y;cin>>x>>y
#define innn(x, y, z) int x,y,z;cin>>x>>y>>z
#define bit(n) (1<<(n))

#define out(x) cout<<(x)<<endl;
#define outt(x,y) cout<<(x)<<" "<<(y)<<endl;
#define err(x) cerr<<(x)<<endl;
#define errr(x,y) cerr<<(x)<<" "<<(y)<<endl;
#define errrr(x,y,z) cerr<<(x)<<" "<<(y)<<" "<<(z)<<endl;

#define rep(i,n) for (int i=0;i<(n);i++)
#define repp(i,n) for (int i=1;i<=(n);i++)
#define reppp(j, i, n) for (int j=i+1; j<n; j++)

#define lim5 200010
#define lim9 1000000010

#define deg(rad) (((rad)/2/M_PI)*360)
#define mid(min, max) ((min + max) / 2)

int main() {
	ll x;
	cin >> x;

	for(int a = -1000; a <= 1000; a++) {
		for(int b = -1000; b <= 1000; b++) {
			if (pow(a, 5) - pow(b, 5) == x) {
				outt(a, b);
				return 0;
			}
		}
	}
    return 0;
}