Problem:
Score : 200 points

Problem Statement

Takahashi's house has only one socket.

Takahashi wants to extend it with some number of power strips, each with A sockets, into B or more empty sockets.

One power strip with A sockets can extend one empty socket into A empty sockets.

Find the minimum number of power strips required.

Constraints

All values in input are integers.

2 \leq A \leq 20

1 \leq B \leq 20

Input

Input is given from Standard Input in the following format:

A B

Output

Print the minimum number of power strips required.

Sample Input 1

4 10

Sample Output 1

3

3 power strips, each with 4 sockets, extend the socket into 10 empty sockets.

Sample Input 2

8 9

Sample Output 2

2

2 power strips, each with 8 sockets, extend the socket into 15 empty sockets.

Sample Input 3

8 8

Sample Output 3

1

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <fstream>
#include <vector>
#include <algorithm>
#include <cmath>
#include <numeric>
#include <functional>
#include <map>
#include <queue>
#define REP(i,n) for(int (i)=0; (i)<(n); (i)++)
using namespace std;
using ll = long long;
ll MOD = 1e9+7;


int main(){
    cin.tie(0);
    ios::sync_with_stdio(false);
    
    
    int A, B;
    cin >> A >> B;
    int t = 1, ans = 0;
    while(true){
        t--;
        t += A;
        ans++;
        if(t >= B){
            break;
        }
    }
    cout << ans << endl;
    return 0;
}