Problem:
Score : 300 points

Problem Statement

Fennec is fighting with N monsters.

The health of the i-th monster is H_i.

Fennec can do the following two actions:

Attack: Fennec chooses one monster. That monster's health will decrease by 1.

Special Move: Fennec chooses one monster. That monster's health will become 0.

There is no way other than Attack and Special Move to decrease the monsters' health.

Fennec wins when all the monsters' healths become 0 or below.

Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.

Constraints

1 \leq N \leq 2 \times 10^5

0 \leq K \leq 2 \times 10^5

1 \leq H_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
H_1 ... H_N

Output

Print the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning.

Sample Input 1

3 1
4 1 5

Sample Output 1

5

By using Special Move on the third monster, and doing Attack four times on the first monster and once on the second monster, Fennec can win with five Attacks.

Sample Input 2

8 9
7 9 3 2 3 8 4 6

Sample Output 2

0

She can use Special Move on all the monsters.

Sample Input 3

3 0
1000000000 1000000000 1000000000

Sample Output 3

3000000000

Watch out for overflow.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

// START OF TEMPLATE CODE
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

using namespace __gnu_pbds;
using namespace std;

#define TRACE(x) x
#define WATCH(x) TRACE( cout << #x" = " << x << endl)
#define PRINT(x) TRACE(printf(x))
#define WATCHR(a, b) TRACE( for(auto c = a; c != b;) cout << *(c++) << " "; cout << endl)
#define WATCHC(V) TRACE({cout << #V" = "; WATCHR(V.begin(), V.end()); } )
#define all(v) (v).begin(), (v).end()
#define rall(v) (v).rbegin(), (v).rend()
#define sz(v) (int) (v).size()
#define rep(i,a,b) for(int (i) = (a); (i) < (b); ++(i))
#define pb push_back
#define eb emplace_back
#define mp make_pair
#define fi first
#define se second
#define funoredered_map __fast_unordered_map

template<class Key, class Value, class Hash = std::hash<Key>>
using funordered_map = __gnu_pbds::gp_hash_table<Key, Value, Hash>;

using ll = long long;
using ld = long double;
using pii = pair<int, int>;
using pll = pair<ll, ll>;
using pdb = pair< double, double >;
using vi = vector<int>;
using vll = vector<ll>;
using vpii = vector<pii>;
using vpll = vector<pll>;
using vvi = vector<vi>;

constexpr int inf = 0x3f3f3f3f;
constexpr double eps = 1e-8;
constexpr ll MOD = 1000000007LL;

template <typename T>
using ordered_set = 
    tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;

inline ll powmod( ll a, ll b, ll mod = MOD) {
    ll res = 1; a %= mod; assert(b >= 0);
    for(;b;b>>=1) {
        if(b&1) res = (res * a) % mod;
        a = (a * a) % mod;
    }
    return res;
}

void buff() { ios::sync_with_stdio(false); cin.tie(nullptr); }

mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
// END OF TEMPLATE CODE

int main()
{
    buff(); 
    int n, k;
    cin >> n >> k;
    long long cost = 0;
    vector<int> v(n);
    for(int& x : v) cin >> x;
    sort( all(v) );
    reverse(all(v));
    for(int i = k; i < n; ++i) cost += v[i];
    cout << cost << endl;
    return 0;
}