Problem:
Score: 300 points

Problem Statement

We have a 3 \times 3 grid. A number c_{i, j} is written in the square (i, j), where (i, j) denotes the square at the i-th row from the top and the j-th column from the left.

According to Takahashi, there are six integers a_1, a_2, a_3, b_1, b_2, b_3 whose values are fixed, and the number written in the square (i, j) is equal to a_i + b_j.

Determine if he is correct.

Constraints

c_{i, j} \ (1 \leq i \leq 3, 1 \leq j \leq 3) is an integer between 0 and 100 (inclusive).

Input

Input is given from Standard Input in the following format:

c_{1,1} c_{1,2} c_{1,3}
c_{2,1} c_{2,2} c_{2,3}
c_{3,1} c_{3,2} c_{3,3}

Output

If Takahashi's statement is correct, print Yes; otherwise, print No.

Sample Input 1

1 0 1
2 1 2
1 0 1

Sample Output 1

Yes

Takahashi is correct, since there are possible sets of integers such as: a_1=0,a_2=1,a_3=0,b_1=1,b_2=0,b_3=1.

Sample Input 2

2 2 2
2 1 2
2 2 2

Sample Output 2

No

Takahashi is incorrect in this case.

Sample Input 3

0 8 8
0 8 8
0 8 8

Sample Output 3

Yes

Sample Input 4

1 8 6
2 9 7
0 7 7

Sample Output 4

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)


#include <iostream>
using namespace std;
int a[9],ans;
int main()
{
	int n=1,c[75],b=0;
	for (int i=0;i<9;i++)
	{
		cin>>a[i];
	}
	for (int i=0;i<9;i++)
	{
		for (int j=n;j<9;j++)
		{
			c[b]=a[i]+a[j];
			b++;
			n++;
		}
	}
	for (int i=0;i<9;i++)
	{
		bool f=false;
		for (int l=0;l<72;l++)
		{
			if (c[l]==a[i])
			{
				f=true;
    			break;
			}
		}
		if (f) ans++;
	}
	if (ans==9)
		cout<<"Yes"<<endl;
	else
		cout<<"No"<<endl;
	system("pause");
    return 0;
}