Problem:
Score : 200 points

Problem Statement

Raccoon is fighting with a monster.

The health of the monster is H.

Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i.
There is no other way to decrease the monster's health.

Raccoon wins when the monster's health becomes 0 or below.

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Constraints

1 \leq H \leq 10^9

1 \leq N \leq 10^5

1 \leq A_i \leq 10^4

All values in input are integers.

Input

Input is given from Standard Input in the following format:

H N
A_1 A_2 ... A_N

Output

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Sample Input 1

10 3
4 5 6

Sample Output 1

Yes

The monster's health will become 0 or below after, for example, using the second and third moves.

Sample Input 2

20 3
4 5 6

Sample Output 2

No

Sample Input 3

210 5
31 41 59 26 53

Sample Output 3

Yes

Sample Input 4

211 5
31 41 59 26 53

Sample Output 4

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;

typedef long long ll;

#define F first 
#define S second 
#define PB push_back
#define MP make_pair 
#define rep(i,a,b) for (ll i=a;i<b;i++)

typedef vector<int> vi;
typedef pair<int,int> pi;


int main()
{
    int h,n;
    cin>>h>>n;
    vi a(n);
    rep(i,0,n) cin>>a[i];

    int sum =0;
    rep(i,0,n)  sum +=a[i];

    if(sum>=h) {
        cout<<"Yes"<<endl;
        return 0;
    } 


    cout<<"No"<<endl;
    return 0; 
}