Problem:
Score : 400 points

Problem Statement

Given are three integers N, K, and S.

Find a sequence A_1, A_2, ..., A_N of N integers between 1 and 10^9 (inclusive) that satisfies the condition below.
We can prove that, under the conditions in Constraints, such a sequence always exists.

There are exactly K pairs (l, r) of integers such that 1 \leq l \leq r \leq N and A_l + A_{l + 1} + \cdots + A_r = S.

Constraints

1 \leq N \leq 10^5

0 \leq K \leq N

1 \leq S \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K S

Output

Print a sequence satisfying the condition, in the following format:

A_1 A_2 ... A_N

Sample Input 1

4 2 3

Sample Output 1

1 2 3 4

Two pairs (l, r) = (1, 2) and (3, 3) satisfy the condition in the statement.

Sample Input 2

5 3 100

Sample Output 2

50 50 50 30 70

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
#define rep(i,n) for(int64_t i=0;i < (int64_t)(n);i++)
using namespace std;

//////全探索したいときに開けよ////////
/*
vector<vector<int>> fspattern;
vector<int> fspattern_draft;
int fspcnt = 0;

void setfspattern_core(int floor,int number,int degree){
  if(floor==degree){
    fspattern.at(fspcnt) = fspattern_draft;
    fspcnt++;
  }else{
    rep(i,number){
      fspattern_draft.at(floor) = i;
      setfspattern_core(floor+1,number,degree);
    }
  }
}

void setfspattern(int number,int degree){
  int64_t array_num = 1;
  rep(i,degree){
    array_num *= number;
  }
  fspattern = vector<vector<int>>(array_num,vector<int>(degree));
  fspattern_draft = vector<int>(degree);
  setfspattern_core(0,number,degree);
}
*/

//////nCrのmodを求めたいときに開けよ/////////
//int64_t univMod = 1000000007;
//int64_t factnum = 100000
//vector<int64_t> modfact(factnum);
//vector<int64_t> modinvfact(factnum);

/*void setmodfact(){
  for(int i=0;i<factnum;i++){
    if(i == 0){
      modfact.at(i) = 1;
    }else{
      modfact.at(i) = (modfact.at(i-1)*i)%univMod;
    }
  }
}

int64_t calcmodpower(int64_t a,int64_t n){
  int64_t res = 1;
  while(n != 0){
    if(n & 1){
      res = (res * a) % univMod;
    }
    a = (a*a) % univMod;
    n = n >> 1;
  }
  return res;
}

int64_t calcinverse(int64_t n){
	return calcmodpower(n,univMod-2);
}

void setmodinvfact(){
  for(int i=0;i<factnum;i++){
    if(i==0){
      modinvfact.at(i) = 1;
    }else{
      modinvfact.at(i) = calcmodpower(modfact.at(i),univMod-2);
    }
  }
}*/


/*
int64_t calcGCD(int64_t a,int64_t b){
	int64_t p = a;
	int64_t q = b;
	int64_t c = a%b;
	while(c != 0){
		p = q;
		q = c;
		c = p%q;
	}
	return q;
}
*/

int main(){
  int n,k,s;
  cin >> n >> k >> s;
  if(k <= n - 1){
    if(s >= 3){
      rep(i,k){
        cout << 1 << " ";
      }
      cout << s-1 << " ";
      rep(i,n-k-1){
        if(s != 1000000000){
          cout << 1000000000 << " ";
        }else{
          cout << 999999999 << " ";
        }
      }
    }else if (s == 2){
      rep(i,k+1){
        cout << 1 << " ";
      }
      rep(i,n-k-1){
        cout << 3 << " ";
      }
    }else{
      rep(i,k){
        cout << 1 << " ";
      }
      rep(i,n-k){
        cout << 2 << " ";
      }
    }
  }else{
    rep(i,n){
      cout << s << ' ';
    }
  }   
}