Problem:
Score: 300 points

Problem Statement

Find the minimum prime number greater than or equal to X.

Notes

A prime number is an integer greater than 1 that cannot be evenly divided by any positive integer except 1 and itself.

For example, 2, 3, and 5 are prime numbers, while 4 and 6 are not.

Constraints

2 \le X \le 10^5

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X

Output

Print the minimum prime number greater than or equal to X.

Sample Input 1

20

Sample Output 1

23

The minimum prime number greater than or equal to 20 is 23.

Sample Input 2

2

Sample Output 2

2

X itself can be a prime number.

Sample Input 3

99992

Sample Output 3

100003

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

  long long A,B,C,D,E,F,    I,J,K,  M,N,O,P,Q,R,S,T,U,V,  X,Y,Z;
//long long A,B,C,D,E,F,  H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z;
double dA,dB,dC,dD,dE,dF,   dI,dJ,dK,  dM,dN,dO,dP,dQ,dR,dS,dT,dU,dV,  dX,dY,dZ;
#include <string>
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
#include <iostream>
#include <algorithm>
#include <vector>
#include <queue>
#include <string>
#include <iomanip>
#include <cmath>

//typedef pair<long long,long long> P;
//typedef pair<long long,P> P1;
//typedef pair<P,P> P2;
#define pu push
#define pb push_back
#define mp make_pair
#define eps 1e-7
//#define INF 100000000000000000//19桁
#define INF 1e18+5//19桁
#define mod 1000000007
#define fi first
#define se second
#define rep(i,x) for(long long i=0;i<x;i++)
#define repn(i,x) for(long long i=1;i<=x;i++)
#define REP(i,n,x) for(long long i=n;i<x;i++)
#define REPN(i,n,x) for(long long i=n+1;i<x;i++)
#define repn(i,x) for(long long i=1;i<=x;i++)
#define rrep(i,x) for(long long i=x-1;i>=0;i--)
#define rrepn(i,x) for(long long i=x;i>1;i--)
#define SORT(x) sort(x.begin(),x.end())
#define ERASE(x) x.erase(unique(x.begin(),x.end()),x.end())
#define POSL(x,v) (lower_bound(x.begin(),x.end(),v)-x.begin())
#define POSU(x,v) (upper_bound(x.begin(),x.end(),v)-x.begin())
#define All(x) (x).begin(),(x).end()
#define rAll(x) (x).rbegin(),(x).rend()

#define ALL(v)  (v).begin(),(v).end()
//#define MAX(a,b) if(a>b)
#define MAX(a,b) (((a)>(b))?(a):(b))
#define MIN(a,b) (((a)<(b))?(a):(b))
#define popcount __builtin_popcount

const string MINUSINF = "-";

template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
void chmax(string &a, string b) {
    if (a == MINUSINF) a = b;
    else if (a.size() < b.size()) a = b;
    else if (a.size() == b.size()) {
        if (a < b) a = b;
    }
}


template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }

#define pr printf
#define re return
#define CASET int ___T, case_n = 1; scanf("%d ", &___T); while (___T-- > 0)


int GCD(int a, int b) { return b ? GCD(b, a%b) : a; }

stack<long long> sta;   
queue<long long> que;
deque<long long> dque;

set <string> s_set;








long long sum,sum1,sum2,sum3,sum4;
long long flg,flg1,flg2,flg3,cnt,cnt1,cnt2,cnt3,cnt4;
long long wk,wk1,wk2,wk3,wk4;
long long ans;

double dsum,dsum1,dsum2,dsum3,dsum4;
double dcnt,dcnt1,dcnt2,dcnt3,dcnt4;
double dwk,dwk1,dwk2,dwk3,dwk4;
double dans;
double dmax,dmax1;
double dmin,dmin1;



bool f;

long long weight[110], value[110]; // 品物の個数は 100 個なので少し余裕持たせてサイズ 110 に
ll a[100010][3]; // a[i], b[i], c[i] をそれぞれまとめて a[i][0], a[i][1], a[i][2] にしてしまう
long long n,h[100005];
vector<long long> p, c;
int vis[200001];

vector<string> fi;
int Left[2100][2100], Right[2100][2100], Up[2100][2100], Down[2100][2100];

long long match[10] = {2,5,5,4,5,6,3,7,6};
vector<long long> box;



int main(){
	
	cin.tie(nullptr);
	ios::sync_with_stdio(false);

	long long max,max1;
	long long min,min1;
	

	sum=sum1=sum2=sum3=sum4=0;
	flg=flg1=flg2=flg3=cnt=cnt1=cnt2=cnt3=cnt4=0;
	max=max1=0;
	wk=wk1=wk2=wk3=wk4=0;
	ans=0;
	min=min1=INF;

	dsum=dsum1=dsum2=dsum3=dsum4=0;
	dcnt=dcnt1=dcnt2=dcnt3=dcnt4=0;
	dmax=dmax1=0;
	dwk=dwk1=dwk2=dwk3=dwk4=0;
	dans=0;
	dmin=dmin1=INF;
	
	

	//**************************こどふぉ用******************************************
	/*
	char c[3]={'R', 'G', 'B'};
	//for(int i=0,j=1;i<n;i+=j,j++)
	cin >> T;
	while(T--){
		cin >> N >> K;
		//std::vector<long long> v(N);	
		//vector<ll> v(N, 0);
		//set<long long> st;
		//map<std::string, int> freq;
		//map<int,int> M;
		//M.clear();
		
		//if(st.find(v[i])==st.end()){
		//	st.insert(v[i]);
		//}
		//else{
		//	st.erase(v[i]);
		//}
		
		//vector<pair<long long, long long> > p(M);
		//for(long long i=0; i<M; i++){
		//long long a, b;
		//cin >> a >> b;
		//p[i] = make_pair(a, b);
		//}
		//int ret=1<<20;
		
		for(int i=1;i<=N;i++){
			
		}
		cout << N << "\n";
	}
	*/
	
	//**************************ここからスタート******************************************
	std::cin >> N;
	//std::cin >> N >> M;
	//std::cin >> N >> M >> K;
	//std::cin >> N >> K;
	//std::cin >> A >> B;
	//std::cin >> A >> B >> C;
    
	//std::vector<long long> v(N);
	//std::vector<long long> w(N);
	//std::vector<long long> x(N);
	//std::vector<int> v(100, 0);
	//int a[26]={0};
	//vector<long long> flagment(N, 0);
	
	//v.push_back(i);
	//accumulate(vec.begin(), vec.end(), 0)
    //v.resize
    
	// 配列入力1
	
	for(long long i=N; i<=100003; i++){
		flg=0;
		for(ll j=2;j*j<=i;j++){
			if(i%j==0){
				flg=1;
				//break;
			}
		}
		if(flg==0){
			pr("%lld",i);
			re 0;
		}

	}
	re 0;
	
	
	//std::sort(v.begin(),v.end());//昇順ソート
	//std::sort(v.begin(),v.end(),std::greater<long long>());//降順ソート
	
	//通常
	/*
	for(long long i=0; i<N; i++){
		
		
		
	}
	*/

	//文字列入力
	/*
	string s,t;
	std::cin >> s;
	//sort(s.begin(), s.end());
	//s=to_string(i);
	for(long long i=0; i<s.length(); i++){
		
		//wk=(s[i+2]-'0')+10*(s[i+1]-'0')+100*(s[i]-'0');
		if(s[i]!='1'){
		}	
	}
	*/

	
	if(1){
    	printf("%lld",N);
    	//printf("%lld",N);
    	//puts("Yes");
    	//printf("%d",st.size());
    	//文字列の出力
    	//std::cout << s << std::endl;
    	//printf("%.12f\n",ret);
    	//cout << sum << endl;
	}
	else{
		//puts("No");
	}
	return 0;
	

	
	
	return 0;
}