Problem:
Score : 500 points

Problem Statement

There are N points on the 2D plane, i-th of which is located on (x_i, y_i).
There can be multiple points that share the same coordinate.
What is the maximum possible Manhattan distance between two distinct points?

Here, the Manhattan distance between two points (x_i, y_i) and (x_j, y_j) is defined by |x_i-x_j| + |y_i-y_j|.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq x_i,y_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
x_1 y_1
x_2 y_2
:
x_N y_N

Output

Print the answer.

Sample Input 1

3
1 1
2 4
3 2

Sample Output 1

4

The Manhattan distance between the first point and the second point is |1-2|+|1-4|=4, which is maximum possible.

Sample Input 2

2
1 1
1 1

Sample Output 2

0

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
typedef long long ll;
using namespace std;
#define repr(i,a,b) for(int i=a;i<b;i++)
#define rep(i,n) for(int i=0;i<n;i++)
#define invrepr(i,a,b) for(int i=b-1;i>=a;i--)
#define invrep(i,n) invrepr(i,0,n)
#define repitr(itr,a) for(auto itr=a.begin();itr!=a.end();++itr)
#define P pair<int,int>
const ll MOD=1e9+7;
const int INF=2e9;
const double PI=acos(-1);

const int MAX=200010;


int main() {
    ios_base::sync_with_stdio(false); 

    int n;
    cin >> n;
    vector<pair<ll,ll>> pp(n),pm(n);
    rep(i,n) {
        int x,y;
        cin >> x >> y;
        pp[i]={x+y,y};
        pm[i]={x-y,y};
    }
    sort(pp.begin(),pp.end());
    sort(pm.begin(),pm.end());
    ll ansx=abs(pp[0].first-pp[n-1].first);
    ll ansy=abs(pm[0].first-pm[n-1].first);
    ll ans=(ansx>ansy)?ansx:ansy;
    cout << ans << endl;
    return 0;
}