Problem:
Score : 200 points

Problem Statement

There are some animals in a garden. Each of them is a crane with two legs or a turtle with four legs.

Takahashi says: "there are X animals in total in the garden, and they have Y legs in total." Determine whether there is a combination of numbers of cranes and turtles in which this statement is correct.

Constraints

1 \leq X \leq 100

1 \leq Y \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

If there is a combination of numbers of cranes and turtles in which the statement is correct, print Yes; otherwise, print No.

Sample Input 1

3 8

Sample Output 1

Yes

The statement "there are 3 animals in total in the garden, and they have 8 legs in total" is correct if there are two cranes and one turtle. Thus, there is a combination of numbers of cranes and turtles in which the statement is correct.

Sample Input 2

2 100

Sample Output 2

No

There is no combination of numbers of cranes and turtles in which this statement is correct.

Sample Input 3

1 2

Sample Output 3

Yes

We also consider the case in which there are only cranes or only turtles.

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h> //全てのヘッダファイルをインクルード

//ループ
#define REP(i, n) for(int i = 0; i < n; i++) //普通のループ
#define REPR(i, n) for(int i = n; i >= 0; i--) //逆ループ
#define FOR(i, m, n) for(int i = m; i < n; i++) //最初の数値を指定したループ

//型名省略
typedef long long ll;
//配列要素数
static const int MAX = 200000;
//値
static const ll MX = 1e18;

using namespace std;

//#include "./lib/generic/search.h"

#define M 1064527

int main(){
    ll X, Y;
    cin >> X >> Y;
   
    if(Y%2==1) cout << "No" << endl;
    else if(X*4<Y) cout << "No" << endl;
    else if(X*4>Y) cout << "Yes" << endl;
    
    return 0;
}