Problem:
Score: 200 points

Problem Statement

A country decides to build a palace.

In this country, the average temperature of a point at an elevation of x meters is T-x \times 0.006 degrees Celsius.

There are N places proposed for the place. The elevation of Place i is H_i meters.

Among them, Princess Joisino orders you to select the place whose average temperature is the closest to A degrees Celsius, and build the palace there.

Print the index of the place where the palace should be built.

It is guaranteed that the solution is unique.

Constraints

1 \leq N \leq 1000

0 \leq T \leq 50

-60 \leq A \leq T

0 \leq H_i \leq 10^5

All values in input are integers.

The solution is unique.

Input

Input is given from Standard Input in the following format:

N
T A
H_1 H_2 ... H_N

Output

Print the index of the place where the palace should be built.

Sample Input 1

2
12 5
1000 2000

Sample Output 1

1

The average temperature of Place 1 is 12-1000 \times 0.006=6 degrees Celsius.

The average temperature of Place 2 is 12-2000 \times 0.006=0 degrees Celsius.

Thus, the palace should be built at Place 1.

Sample Input 2

3
21 -11
81234 94124 52141

Sample Output 2

3

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <bitset>
#include <vector>
#include <string>
#include <algorithm>
#include <set>
#include <map>
#include <cmath>
#include <regex>
#include <iomanip>
#include <climits>
#include <utility>
#include <queue>
using namespace std;
using ll = long long int;
using dd = long double;
const ll MOD = 1e9 + 7;

ll gcd(ll a, ll b)
{
    if (a % b == 0)
    {
        return b;
    }
    return gcd(b, a % b);
}

struct Fish
{
    ll beauty;
    ll taste;
};

ll fact(ll n)
{
    if (n == 0)
    {
        return 1;
    }
    if (n == 1)
    {
        return 1;
    }
    return n * fact(n - 1) % MOD;
}

int main()
{
    dd N, T, A;
    cin >> N >> T >> A;

    ll ans = 0;
    ll mn = INT_MAX;
    for (ll i = 0; i < N; i++)
    {
        dd h;
        cin >> h;
        dd t = 1000 * T - h * 6;
        if (mn > abs(A - t)) {
            mn = abs(A - t);
            ans = i + 1;
        }
    }
    cout << ans << endl;
}