Problem:
Score : 200 points

Problem Statement

Given is an integer N. Find the number of digits that N has in base K.

Notes

For information on base-K representation, see Positional notation - Wikipedia.

Constraints

All values in input are integers.

1 \leq N \leq 10^9

2 \leq K \leq 10

Input

Input is given from Standard Input in the following format:

N K

Output

Print the number of digits that N has in base K.

Sample Input 1

11 2

Sample Output 1

4

In binary, 11 is represented as 1011.

Sample Input 2

1010101 10

Sample Output 2

7

Sample Input 3

314159265 3

Sample Output 3

18

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)


#include<iostream>
#include<vector>
#include <cmath>
#include <map>
#include <algorithm>
#include <string>
using namespace std;
int main(void){
    int n , k ;
    cin >> n >> k ;
    int count = 0;
    int ans = 1 ;
    if(k>n){
        cout << 1 << endl;
    }else{
    while(n>=ans){
        ans = ans * k;
        count++;
    }
    

    cout << count << endl;
    }
    return 0;
}