Problem:
Score : 200 points

Problem Statement

There are N cities and M roads.
The i-th road (1≤i≤M) connects two cities a_i and b_i (1≤a_i,b_i≤N) bidirectionally.
There may be more than one road that connects the same pair of two cities.
For each city, how many roads are connected to the city?

Constraints

2≤N,M≤50

1≤a_i,b_i≤N

a_i ≠ b_i

All input values are integers.

Input

Input is given from Standard Input in the following format:

N M
a_1 b_1
:
a_M b_M

Output

Print the answer in N lines.
In the i-th line (1≤i≤N), print the number of roads connected to city i.

Sample Input 1

4 3
1 2
2 3
1 4

Sample Output 1

2
2
1
1

City 1 is connected to the 1-st and 3-rd roads.

City 2 is connected to the 1-st and 2-nd roads.

City 3 is connected to the 2-nd road.

City 4 is connected to the 3-rd road.

Sample Input 2

2 5
1 2
2 1
1 2
2 1
1 2

Sample Output 2

5
5

Sample Input 3

8 8
1 2
3 4
1 5
2 8
3 7
5 2
4 1
6 8

Sample Output 3

3
3
2
2
2
1
1
2

Solution in C++14 (GCC 5.4.1) (judge verdict: Runtime Error)

#include <bits/stdc++.h>
using namespace std;

#define rep(i, n) for (int i = 0; i < (int)(n); i++)
//都市iから伸びる道路の数=a,bに含まれるiの数
int main(){
 int N,M;
 cin >> N >> M;
 vector<int> a(M);
 vector<int> b(M);
 rep(i,M){
   cin >> a[i];
   cin >> b[i];
 }
 vector<int> num(N);//num[i]は都市iから伸びる道路の数
 for(int i = 1;i<=N;i++){
   int c = 0;
   for(int j = 0;j<M;j++){
     if(a[j] == i) c++;
     if(b[j] == i) c++;
   }
   num[i] = c;
 }

 for(int i = 1;i<=N;i++){
   cout << num[i] << endl;
 }
}