Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<math.h>
#define MaxN 3500
typedef long long LL;
LL f(LL h,LL n,LL w)
{
	double sum=h*w*n*4.0/(n*w+h*w+n*h);
	LL truee=sum;
	if(sum!=truee)
		return -1;
	else
		return truee; 
}
int main() 
{
	LL h,n,w;
	LL N;
	int flag=0;
	scanf("%lld",&N);
	for( h=1;h<=MaxN;h++)
	{
		for(n=1;n<=MaxN;n++)
		{
			for(w=0;w<=MaxN;w+=n)
			{
				LL sum=f(h,n,w);
		//		printf("%d %d %d %d\n",h,n,w,sum);
				if(sum>N)
					break;
				if(sum==N)
				{
					flag=1;
					break;
				}
			 } 
			if(flag)
				break;
		}
		if(flag)
			break;
	}
	printf("%lld %lld %lld\n",h,n,w);
	return 0;
}