Problem:
Score : 300 points

Problem Statement

There are N people living on a number line.

The i-th person lives at coordinate X_i.

You are going to hold a meeting that all N people have to attend.

The meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.

Find the minimum total points of stamina the N people have to spend.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq X_i \leq 100

Input

Input is given from Standard Input in the following format:

N
X_1 X_2 ... X_N

Output

Print the minimum total stamina the N people have to spend.

Sample Input 1

2
1 4

Sample Output 1

5

Assume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.

Note that you can hold the meeting only at an integer coordinate.

Sample Input 2

7
14 14 2 13 56 2 37

Sample Output 2

2354

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
//型に気を付けよう

#define rep(i,n) for(int i=0;i<n;i++)
typedef long long  ll;
typedef long double  ld;
const double pi=3.1415926535;
const ll  mod=1000000007;

long long substract(long long a,long long b){//差の絶対値　3項演算
  long long num=(a-b);
  return (num > 0) ? num : -num;}
//桁数指定　cout << fixed << setprecision(2)
int main() {
  int n;
  cin>>n;
  vector<int> v(n);
  rep(i,n)cin>>v[i];
  int Min=INT_MAX;
  rep(j,100){
    int sum=0;
    rep(k,n){
      sum+=pow(substract(j,v[k]),2);
    }
    Min=min(Min,sum);
  }
  cout<<Min;
}