Problem:
Score : 200 points

Problem Statement

Rng is preparing a problem set for a qualification round of CODEFESTIVAL.

He has N candidates of problems. The difficulty of the i-th candidate is D_i.

There must be M problems in the problem set, and the difficulty of the i-th problem must be T_i. Here, one candidate of a problem cannot be used as multiple problems.

Determine whether Rng can complete the problem set without creating new candidates of problems.

Constraints

1 \leq N \leq 200,000

1 \leq D_i \leq 10^9

1 \leq M \leq 200,000

1 \leq T_i \leq 10^9

All numbers in the input are integers.

Partial Score

100 points will be awarded for passing the test set satisfying N \leq 100 and M \leq 100.

Input

Input is given from Standard Input in the following format:

N
D_1 D_2 ... D_N
M
T_1 T_2 ... T_M

Output

Print YES if Rng can complete the problem set without creating new candidates of problems; print NO if he cannot.

Sample Input 1

5
3 1 4 1 5
3
5 4 3

Sample Output 1

YES

Sample Input 2

7
100 200 500 700 1200 1600 2000
6
100 200 500 700 1600 1600

Sample Output 2

NO

Not enough 1600s.

Sample Input 3

1
800
5
100 100 100 100 100

Sample Output 3

NO

Sample Input 4

15
1 2 2 3 3 3 4 4 4 4 5 5 5 5 5
9
5 4 3 2 1 2 3 4 5

Sample Output 4

YES

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#define _USE_MATH_DEFINES
#include <math.h>
#include <iostream>
#include <iomanip>
#include <cstdlib>
#include <algorithm>
#include <numeric>
#include <stdio.h>
#include <vector>
#include <map>

using namespace std;
typedef long long ll;

#define rep(i, n) for(ll i = 0; i < (ll)(n); i++)

int main() {

    ll N;
    cin >> N;
    ll D;
    map<ll,ll> mp;
    mp.insert(make_pair(D,1));
    rep(i,N){
        cin >> D;
        if(mp.count(D)) mp[D]++;
        else mp.insert(make_pair(D,1));
    }
    ll M;
    cin >> M;
    ll T;
    string out = "YES";
    rep(i,M){
        cin >> T;
        if(mp.count(T)){
            mp[T]--;
            if(mp[T]<0){
                out = "NO";
                break;
            }
        }else{
            out = "NO";
            break;
        }
    }
    cout << out << endl;
    return 0;
}