Problem:
Score : 200 points

Problem Statement

A shop sells N kinds of fruits, Fruit 1, \ldots, N, at prices of p_1, \ldots, p_N yen per item, respectively. (Yen is the currency of Japan.)

Here, we will choose K kinds of fruits and buy one of each chosen kind. Find the minimum possible total price of those fruits.

Constraints

1 \leq K \leq N \leq 1000

1 \leq p_i \leq 1000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
p_1 p_2 \ldots p_N

Output

Print an integer representing the minimum possible total price of fruits.

Sample Input 1

5 3
50 100 80 120 80

Sample Output 1

210

This shop sells Fruit 1, 2, 3, 4, and 5 for 50 yen, 100 yen, 80 yen, 120 yen, and 80 yen, respectively.

The minimum total price for three kinds of fruits is 50 + 80 + 80 = 210 yen when choosing Fruit 1, 3, and 5.

Sample Input 2

1 1
1000

Sample Output 2

1000

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <iostream>
#include <iomanip>
#include <cassert>
#include <cmath>
#include <cstdio>
#include <cstring>
#include <cstdlib>
#include <map>
#include <set>
#include <queue>
#include <stack>
#include <vector>
#include <algorithm>
#include <sstream>
 
using namespace std;

vector<string> vec_splitter(string s) {
  s += ',';
  vector<string> res;
  while(!s.empty()) {
    res.push_back(s.substr(0, s.find(',')));
    s = s.substr(s.find(',') + 1);
  }
  return res;
}
void debug_out(
vector<string> __attribute__ ((unused)) args,
__attribute__ ((unused)) int idx,
__attribute__ ((unused)) int LINE_NUM) { cerr << endl; }
template <typename Head, typename... Tail>
void debug_out(vector<string> args, int idx, int LINE_NUM, Head H, Tail... T) {
  if(idx > 0) cerr << ", "; else cerr << "Line(" << LINE_NUM << ") ";
  stringstream ss; ss << H;
  cerr << args[idx] << " = " << ss.str();
  debug_out(args, idx + 1, LINE_NUM, T...);
}

#ifndef ONLINE_JUDGE
#define debug(...) debug_out(vec_splitter(#__VA_ARGS__), 0, __LINE__, __VA_ARGS__)
#else
#define debug(...) 42
#endif
 
#define MOD 1000000007
#define A first
#define B second
#define all(x) (x).begin(), (x).end

typedef long long ll;
 
inline int mulmd(ll a, ll b){
  ll ret = (a * b) % MOD;
  return (int) ret;
}
 
inline int power(ll x, ll y, int m){
  ll res = 1;
  x = x % m;
  while(y > 0){
    if(y & 1){
      res = mulmd(res, x);
    }
    y = y >> 1;
    x = mulmd(x, x);
  }
  return (int) res;
}
 
inline int submd(ll a, ll b){
  ll ret = (a - b);
  if(ret < 0) ret += MOD;
  return (int) ret;
}
 
inline int addmd(ll a, ll b){
  ll ret = (a + b) % MOD;
  return (int) ret;
}
 
inline int invPow(ll a){
  return power(a, MOD - 2, MOD);
}
 
inline int divmd(ll a, ll b){
  ll ret = mulmd(a, invPow(b));
  return (int) ret;
}
 
const int N = 1e5 + 5;

int arr[N];

void solve(){
  int n, k;
  cin >> n >> k;
  for(int i = 0; i < n; i++) cin >> arr[i];
  sort(arr, arr + n);
  int s = 0;
  for(int i = 0; i < k; i++){
    s += arr[i];
  }
  cout << s;
}

int main(){
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  int t;
  t = 1;
  //cin >> t;
  while(t--){
    solve();
  }
}