Problem:
Score : 100 points

Problem Statement

Takahashi is a member of a programming competition site, ButCoder.

Each member of ButCoder is assigned two values: Inner Rating and Displayed Rating.

The Displayed Rating of a member is equal to their Inner Rating if the member has participated in 10 or more contests. Otherwise, the Displayed Rating will be their Inner Rating minus 100 \times (10 - K) when the member has participated in K contests.

Takahashi has participated in N contests, and his Displayed Rating is R. Find his Inner Rating.

Constraints

All values in input are integers.

1 \leq N \leq 100

0 \leq R \leq 4111

Input

Input is given from Standard Input in the following format:

N R

Output

Print his Inner Rating.

Sample Input 1

2 2919

Sample Output 1

3719

Takahashi has participated in 2 contests, which is less than 10, so his Displayed Rating is his Inner Rating minus 100 \times (10 - 2) = 800.

Thus, Takahashi's Inner Rating is 2919 + 800 = 3719.

Sample Input 2

22 3051

Sample Output 2

3051

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
#define bug(x) cerr<<#x<<"="<<x<<endl;
#define el printf("\n");
const ll mod = 1e7;




inline ll nxt() {
	ll x;
	scanf("%lld\n",&x);
	return x;
}

ll nCr(ll n ,ll k){
    if( k==n || k==0 )return 1;
    return (nCr(n-1,k-1)%mod+nCr(n-1,k)%mod)%mod;
}

int main(){
    //ios_base::sync_with_stdio(0);
    int n,k;
    scanf("%d %d",&n,&k);
    if(n<10){
        printf("%d\n",(k+(100*(10-n))));
    }
    else{
        printf("%d\n",k);
    }


}