Problem:
Score : 100 points

Problem Statement

A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.

Given a string S, determine whether it is coffee-like.

Constraints

S is a string of length 6 consisting of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S

Output

If S is coffee-like, print Yes; otherwise, print No.

Sample Input 1

sippuu

Sample Output 1

Yes

In sippuu, the 3-rd and 4-th characters are equal, and the 5-th and 6-th characters are also equal.

Sample Input 2

iphone

Sample Output 2

No

Sample Input 3

coffee

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define ll long long int 
#define ull unsigned long long int
#define IOS ios_base::sync_with_stdio(false);cin.tie(NULL);
#define pb push_back
#define mp make_pair
#define fi first
#define se second
#define mx *max_element
#define mn *min_element
#define fo(i,n) for(ll i=0;i<n;i++)
#define of(i,p,n) for(ll i=n-1;i>=p;i--)
#define all(x) x.begin(),x.end()
#define sortall(x) sort(all(x))
#define mem(x,p) memset(x,p,sizeof(x))
#define trav(it,a) for(auto it=a.begin();it!=a.end();++it)
#define kk "\n"
const ll mod=1e9+7;
int main()
{
  IOS
    string s;
    cin>>s;
    if(s[2]==s[3])
    {
      if(s[4]==s[5])
        cout<<"Yes";
      else
        cout<<"No";
    }
    else
      cout<<"No";
  return 0;
}