Problem:
Score : 200 points

Problem Statement

The word internationalization is sometimes abbreviated to i18n.
This comes from the fact that there are 18 letters between the first i and the last n.

You are given a string s of length at least 3 consisting of lowercase English letters.
Abbreviate s in the same way.

Constraints

3 ≤ |s| ≤ 100 (|s| denotes the length of s.)

s consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s

Output

Print the abbreviation of s.

Sample Input 1

internationalization

Sample Output 1

i18n

Sample Input 2

smiles

Sample Output 2

s4s

Sample Input 3

xyz

Sample Output 3

x1z

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#include <algorithm>
using namespace std;
typedef long long ll;
template<class T> inline bool chmax(T& a, T b){if(a < b){ a = b; return 1;} return 0;}
template<class T> inline bool chmin(T& a, T b){if(a > b){ a = b; return 1;} return 0;}

const int INF = 100000; 

int main(){
    string s;
    cin >> s;

    int cnt = s.size() - 2;

    cout << s[0] << cnt << s[s.size()-1] << endl;

    return 0;
}