Problem:
Score : 300 points

Problem Statement

A sequence a_1,a_2,... ,a_n is said to be /\/\/\/ when the following conditions are satisfied:

For each i = 1,2,..., n-2, a_i = a_{i+2}.

Exactly two different numbers appear in the sequence.

You are given a sequence v_1,v_2,...,v_n whose length is even.
We would like to make this sequence /\/\/\/ by replacing some of its elements.
Find the minimum number of elements that needs to be replaced.

Constraints

2 \leq n \leq 10^5

n is even.

1 \leq v_i \leq 10^5

v_i is an integer.

Input

Input is given from Standard Input in the following format:

n
v_1 v_2 ... v_n

Output

Print the minimum number of elements that needs to be replaced.

Sample Input 1

4
3 1 3 2

Sample Output 1

1

The sequence 3,1,3,2 is not /\/\/\/, but we can make it /\/\/\/ by replacing one of its elements: for example, replace the fourth element to make it 3,1,3,1.

Sample Input 2

6
105 119 105 119 105 119

Sample Output 2

0

The sequence 105,119,105,119,105,119 is /\/\/\/.

Sample Input 3

4
1 1 1 1

Sample Output 3

2

The elements of the sequence 1,1,1,1 are all the same, so it is not /\/\/\/.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <string>
#include <algorithm>
#include <cstdio>
#include <vector>
#include <queue>
#include <set>
#include <map>
#include <numeric>
#include <cmath>

using namespace std;
typedef long long int ll;
#define all(x) x.begin(),x.end()

const ll mod = 1e9+7;
const ll INF = 1e9;
const ll MAXN = 1e9;

int main()
{
	int n;
	cin >> n;
	vector<int> v(n);
	for(int i = 0; i < n; i++){
		cin >> v[i];
	}
	map<int,int> even,odd;
	for(int i = 0; i < n; i++){
		if(i%2==0) odd[v[i]]++;
		else even[v[i]]++;
	}

	int even_1=0,even_2=0,odd_1=0,odd_2=0;
	int e1=0,e2=0,o1=0,o2=0;
	int cnt = 0;
   
	for(auto itr = even.begin();  itr != even.end() ; ++itr){
		if(itr->second > 0){
			cnt = itr->second;
			even_1 = itr->first;
		}
	}
	e1 = cnt;
	cnt = 0;
	for(auto itr = even.begin();  itr != even.end() ; ++itr){
		if(itr->second > cnt && itr->first != even_1){
			cnt = itr->second;
			even_2 = itr->first;
		}
	}
	e2 = cnt;

	cnt = 0;
	for(auto itr = odd.begin();  itr != odd.end() ; ++itr){
		if(itr->second > cnt){
			cnt = itr->second;
			odd_1 = itr->first;
		}
	}
	o1= cnt;
	cnt = 0;
	for(auto itr = odd.begin();  itr != odd.end() ; ++itr){
		if(itr->second > cnt && itr->first != odd_1){
			cnt = itr->second;
			odd_2 = itr->first;
		}
	}
	o2=cnt;

	if(even_1 == odd_1){
		cout << min(n-e1-o2, n-e2-o1) << endl;
	}else{
		cout << n-e1-o1 << endl;
	}

	return 0;
}