Problem:
Score : 100 points

Problem Statement

There is a set A = \{ a_1, a_2, \ldots, a_N \} consisting of N positive integers.
Taro and Jiro will play the following game against each other.

Initially, we have a pile consisting of K stones.
The two players perform the following operation alternately, starting from Taro:

Choose an element x in A, and remove exactly x stones from the pile.

A player loses when he becomes unable to play.
Assuming that both players play optimally, determine the winner.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq K \leq 10^5

1 \leq a_1 < a_2 < \cdots < a_N \leq K

Input

Input is given from Standard Input in the following format:

N K
a_1 a_2 \ldots a_N

Output

If Taro will win, print First; if Jiro will win, print Second.

Sample Input 1

2 4
2 3

Sample Output 1

First

If Taro removes three stones, Jiro cannot make a move.
Thus, Taro wins.

Sample Input 2

2 5
2 3

Sample Output 2

Second

Whatever Taro does in his operation, Jiro wins, as follows:

If Taro removes two stones, Jiro can remove three stones to make Taro unable to make a move.

If Taro removes three stones, Jiro can remove two stones to make Taro unable to make a move.

Sample Input 3

2 7
2 3

Sample Output 3

First

Taro should remove two stones. Then, whatever Jiro does in his operation, Taro wins, as follows:

If Jiro removes two stones, Taro can remove three stones to make Jiro unable to make a move.

If Jiro removes three stones, Taro can remove two stones to make Jiro unable to make a move.

Sample Input 4

3 20
1 2 3

Sample Output 4

Second

Sample Input 5

3 21
1 2 3

Sample Output 5

First

Sample Input 6

1 100000
1

Sample Output 6

Second

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

/**************************************************************************
Coded by: Saba Karimi(_VINTAGE)
Institution: AIT PUNE
***************************************************************************/
#include<bits/stdc++.h>
using namespace std;
#define fast ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define pb push_back 
#define all(a) a.begin(),a.end()
#define lb lower_bound
#define ub upper_bound
#define pii pair<int,int>
#define ld long double
#define int long long int 
#define F first 
#define S second
/**************************************************************************/
const int N = 1e5+2;
int n,k;
int a[101];
int dp[N];
int solve(int rem)
{
    if(dp[rem]!=-1)
        return dp[rem];
    int res = 0;
    for(int i=0;i<n;i++)
    {
        if(rem-a[i]<0)
            break;
        res = res|(solve(rem-a[i])==0);
    }
    dp[rem] = res;
    return res;
}
signed main()
{
    fast;
    cin>>n>>k;
    for(int i=0;i<n;i++)
        cin>>a[i];
    memset(dp,-1,sizeof(dp));
    int res = solve(k);
    if(res)
        cout<<"First";
    else cout<<"Second";
}