Problem:
Score : 300 points

Problem Statement

Let f(n) be the number of triples of integers (x,y,z) that satisfy both of the following conditions:

1 \leq x,y,z

x^2 + y^2 + z^2 + xy + yz + zx = n

Given an integer N, find each of f(1),f(2),f(3),\ldots,f(N).

Constraints

All values in input are integers.

1 \leq N \leq 10^4

Input

Input is given from Standard Input in the following format:

N

Output

Print N lines. The i-th line should contain the value f(i).

Sample Input 1

20

Sample Output 1

0
0
0
0
0
1
0
0
0
0
3
0
0
0
0
0
3
3
0
0

For n=6, only (1,1,1) satisfies both of the conditions. Thus, f(6) = 1.

For n=11, three triples, (1,1,2), (1,2,1), and (2,1,1), satisfy both of the conditions. Thus, f(6) = 3.

For n=17, three triples, (1,2,2), (2,1,2), and (2,2,1), satisfy both of the conditions. Thus, f(17) = 3.

For n=18, three triples, (1,1,3), (1,3,1), and (3,1,1), satisfy both of the conditions. Thus, f(18) = 3.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
using ll = long long;
ll GetDigit(ll num){ return log10(num)+1; } //numの桁数を求める

int main()
{
    int n;
    int x = 1,y = 1, z = 1;
    cin >> n;
    vector<int> a(n);
    for (size_t i = x; i <= 98; i++)
    {
        for (size_t j = y; j <= 98; j++)
        {
            for (size_t k = z; k <= 98; k++)
            {
                int xyz = i+j+k;
                int fn = xyz*xyz-i*j-j*k-k*i;
                if( fn <= n){
                    a[fn-1]++;
                }
            }
            
        }
        
    }
    rep(i,n){
        cout << a[i] << endl;
    }
    return 0;
}