Problem:
Score : 200 points

Problem Statement

An integer N is a multiple of 9 if and only if the sum of the digits in the decimal representation of N is a multiple of 9.

Determine whether N is a multiple of 9.

Constraints

0 \leq N < 10^{200000}

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a multiple of 9, print Yes; otherwise, print No.

Sample Input 1

123456789

Sample Output 1

Yes

The sum of these digits is 1+2+3+4+5+6+7+8+9=45, which is a multiple of 9, so 123456789 is a multiple of 9.

Sample Input 2

0

Sample Output 2

Yes

Sample Input 3

31415926535897932384626433832795028841971693993751058209749445923078164062862089986280

Sample Output 3

No

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;
#define pb 		push_back
#define mp 		make_pair
#define pii 	pair<int,int>
#define vi 		vector<int>
#define vii 	vector<vector<int>>;
#define vpii 	vector<pii>
#define ar 		array
#define SZ(x) 	((int)(x.size()))
#define fi 		first
#define se 		second


#define TRvi(a,it)   for(auto (it)=(a).begin(),it!=(a).end();it++) 	
#define FORV (a,x)   for(auto (x):(a))
#define FOR(i,n)	 for(int (i)=0;(i)<(n);++(i))
#define FORI(i,n) 	for(int (i)=1;(i)<=(n);++(i))
#define REP(i,a,b) for(int (i)=(a);(i)<=(b);++i)
#define REPD(i,a,b) for(int (i)=(a); (i)>=(b);--i)

#define IN(x,y) 	((y).find((x))!=(y).end())
#define ALL(t) 		t.begin(),t.end()

#define REMAX(a,b) (a)=max((a),(b));
#define REMIN(a,b) (a)=min((a),(b));
#define DBG cerr << "debug here" << endl;
#define DBGV(vari) cerr << #vari<< " = "<< (vari) <<endl;
#define all(x) (x).begin(), (x).end()
#define str(s) to_string(s);

typedef long long ll;

const int INF = 1e9;

const int MINV = 1;
const int MAXV = 10;



void a_m(){
	ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
	#ifndef ONLINE_JUDGE
		freopen("input.txt","r",stdin);
		freopen("output.txt","w",stdout);
	#endif
}
//type the code here






int32_t main()
{
	//type your code here
	a_m();
	string  T;
	cin>>T;
    if(T=="0"){
        cout<<"Yes"<<endl;
        return 0;
    }
	long long int sum=0;
    for(auto &x:T){

        sum += int(x);
    }
    if(sum%9!=0){
        cout<<"No"<<endl;
    }else{
        cout<<"Yes"<<endl;
    }
    return 0;
    
}