Problem:
Score : 400 points

Problem Statement

Give a pair of integers (A, B) such that A^5-B^5 = X.
It is guaranteed that there exists such a pair for the given integer X.

Constraints

1 \leq X \leq 10^9

X is an integer.

There exists a pair of integers (A, B) satisfying the condition in Problem Statement.

Input

Input is given from Standard Input in the following format:

X

Output

Print A and B, with space in between.
If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.

A B

Sample Input 1

33

Sample Output 1

2 -1

For A=2 and B=-1, A^5-B^5 = 33.

Sample Input 2

1

Sample Output 2

0 -1

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

/*#pragma GCC optimize("Ofast")
#pragma GCC optimize("unroll-loops")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")*/
#include<bits/stdc++.h>

using namespace std;
# define ll long long
# define int long long  //comment it out when MLE
//# define endl "\n"
#define gok ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
//# define m 163577857
//# define MOD 163577857
# define pi acos(-1)
# define fi first
# define se second
#define REP(i,n) for (int i = 1; i <= n; i++)

const ll mod = 1000000007;
const int K = 2;
//typedef vector<vector<int> > matrix;
int add(int a, int b,int mod) {
    a%=mod;
    b%=mod;
	a += b;
	if (a >= mod) a -= mod;
	if(a<0)
    {
        a += mod;
        a %= mod;
    }
	return a;
}

int mul(ll a, int b,int mod) {
    a%=mod;
    b%=mod;
	a *= b;
	return a % mod;
}
int po(int a,int b,int mod)
{
    if(b==0)
        return 1;
    if(b%2==0)
        return po(mul(a,a,mod),b/2,mod);
    return mul(a,po(mul(a,a,mod),(b-1)/2,mod),mod);
}


ll fact[1000003];
ll inv[1000003];

void fact0()
{
	int i,j;
	fact[0]=1;
	for(i=1;i<=200000;i++)
	{
		fact[i]=i*fact[i-1]%mod;
	}
	inv[0]=1;
	inv[1]=1;
	ll p=mod;
	for (i=2; i<=200000; i++)
		inv[i] = (p - (p/i) * inv[p%i] % p) % p;

	for(i=2;i<=200000;i++)
	{
		inv[i]*=inv[i-1];
		inv[i]%=mod;
	}
}
set<int> v[100005];
signed main()
{
    gok
   //fact0();
   int x;
   cin>>x;
   //cout<<pow(201,5)-pow(200,5)<<endl<<endl;
/*   set<pair<int,int>> ss;
   for(int i=-100;i<=100;i++)
   {
       int tt = i*i*i*i*i;
       ss.insert({tt,i});
   }*/
  int a,b;
  for(int i=-200;i<=200;i++)
  {
      int t1 = i*i*i*i*i;
      //cout<<t1<<" ";
      int ss = t1+x;
      int t2=-101;
     // cout<<t2<<" ";
      for(int j=-200;j<=200;j++)
      {
          int tm = j*j*j*j*j;
          if(tm==ss)
          {
            //  cout<<"jgg"<<endl;
              t2=j;
              break;
          }
      }
     // cout<<t2<<endl;
      if(t2!=-101)
      {
          b=t2,a=i;
         //cout<<i<<endl;
          break;
      }
  }
  cout<<b<<" "<<a;













    return 0;
    }