Problem:
Score : 400 points

Problem Statement

Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.

You are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.

Constraints

2 ≦ |s| ≦ 10^5

s consists of lowercase letters.

Partial Score

200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.

Input

The input is given from Standard Input in the following format:

s

Output

If there exists no unbalanced substring of s, print -1 -1.

If there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.

Sample Input 1

needed

Sample Output 1

2 5

The string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.

Sample Input 2

atcoder

Sample Output 2

-1 -1

The string atcoder contains no unbalanced substring.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;
//#include<ext/rope>
//using namespace __gnu_cxx
//#include<ext/pb_ds/priority_queue.hpp>
//using namespace __gnu_pbds;
#define lowbit(x) (x&-x)
#define pb push_back
#define empb emplace_back
#define all(x) (x).begin(),(x).end()
#define clr(a,b) memset(a,b,sizeof(a))
#define caze(T) for(cin>>T;T;T--)
#define inf (1<<29)
#define Endl ('\n')
#define fi first
#define se second
#define db double
#define ldb long double
#define ll long long
#define pii pair<int,int>
#define pil pair<int,ll>
#define pli pair<ll,int>
#define pll pair<ll,ll>
#define ull unsigned long long
#define IOS ios::sync_with_stdio(0),cin.tie(0),cout.tie(0)
inline char nc() {
	#define SZ 1000000
	static char buf[SZ], *p1, *p2;
	return p1==p2&&(p2=(p1=buf)+fread(buf,1,SZ,stdin),p1==p2)?EOF:*p1++;
}
template<typename T>
inline int scan(T &x) {
	char c, sign=1; 
	while(!isdigit(c=nc())&&c!=EOF)if(c=='-')sign*=-1;
	if(c==EOF) return EOF;
	for(x = 0; isdigit(c); c = nc())
		x = (x<<1) + (x<<3) + (c&15);
	return x *= sign, 1;
}
template<typename T, typename...Args>
inline int scan(T &x, Args&...args) {
	return scan(x), scan(args...);
}
string s;
int main()
{
	cin>>s;
	int n=s.length();
	bool f=1;
	int a1=-1,a2=-1;
	for(int i=1;f&&i<n;++i)
		if(s[i]==s[i-1])
			a1=i,a2=i+1,f=0;
	for(int i=2;f&&i<n;++i)
		if(s[i]==s[i-2])
			a1=i-1,a2=i+1,f=0;
	cout<<a1<<' '<<a2<<Endl;
}