Problem:
Score : 100 points

Problem Statement

You are parking at a parking lot. You can choose from the following two fee plans:

Plan 1: The fee will be A×T yen (the currency of Japan) when you park for T hours.

Plan 2: The fee will be B yen, regardless of the duration.

Find the minimum fee when you park for N hours.

Constraints

1≤N≤20

1≤A≤100

1≤B≤2000

All input values are integers.

Input

Input is given from Standard Input in the following format:

N A B

Output

When the minimum fee is x yen, print the value of x.

Sample Input 1

7 17 120

Sample Output 1

119

If you choose Plan 1, the fee will be 7×17=119 yen.

If you choose Plan 2, the fee will be 120 yen.

Thus, the minimum fee is 119 yen.

Sample Input 2

5 20 100

Sample Output 2

100

The fee might be the same in the two plans.

Sample Input 3

6 18 100

Sample Output 3

100

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <algorithm>
#include <vector>
#include <queue>
#include <string.h>
typedef long long ll;

#define MAX(x, y)	(((x) > (y))? (x) : (y))
#define MIN(x, y)	(((x) < (y))? (x) : (y))
#define ABS(x)		(((x) < 0)? (-1*(x)) : (x))
#define REPI(x,y)	for (int i=(x);i<(y);i++)
#define REPJ(x,y)	for (int j=(x);j<(y);j++)
#define MEMCLR(X)	memset((X),0,sizeof((X)))

using namespace std;
typedef vector<vector<pair<int, int>>> G;
typedef pair<int, int> P;

int i,j,N,A,B;

int main() {
	cin >> N >> A >> B;
		
	cout << (MIN(N*A,B));
	
	return 0;
}