Problem:
Score : 200 points

Problem Statement

There are some animals in a garden. Each of them is a crane with two legs or a turtle with four legs.

Takahashi says: "there are X animals in total in the garden, and they have Y legs in total." Determine whether there is a combination of numbers of cranes and turtles in which this statement is correct.

Constraints

1 \leq X \leq 100

1 \leq Y \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

If there is a combination of numbers of cranes and turtles in which the statement is correct, print Yes; otherwise, print No.

Sample Input 1

3 8

Sample Output 1

Yes

The statement "there are 3 animals in total in the garden, and they have 8 legs in total" is correct if there are two cranes and one turtle. Thus, there is a combination of numbers of cranes and turtles in which the statement is correct.

Sample Input 2

2 100

Sample Output 2

No

There is no combination of numbers of cranes and turtles in which this statement is correct.

Sample Input 3

1 2

Sample Output 3

Yes

We also consider the case in which there are only cranes or only turtles.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)


// Problem : Crane and Turtle
// Contest : Virtual Judge - AtCoder
// URL : https://vjudge.net/problem/AtCoder-abc170_b
// Memory Limit : 1048 MB
// Time Limit : 2000 ms
// Powered by CP Editor (https://github.com/cpeditor/cpeditor)

#include <bits/stdc++.h>
#pragma GCC target("avx,avx2,fma")
//#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#pragma GCC optimize("Ofast")  // disable
using namespace std;
#define ll long long
#define ull unsigned long long
#define ld long double
#define lll __int128
#define lp(i, a, b) for (int i = (int)(a); i < (int)(b); i++)
#define vec(v, type, sz) vector<type> v(sz)
#define in(v) \
    for (auto &i : v) cin >> i
#define all(v) v.begin(), v.end()
#define prv(v)                         \
    for (auto i : v) cout << i << " "; \
    cout << "\n"
#define MOD 1000000007
#define INF 1000000000
#define INFL 1000000000000000000ll
#define fast_io                       \
    ios_base::sync_with_stdio(false); \
    cin.tie(NULL);                    \
    cout.tie(NULL);
#define vi vector<int>
#define vl vector<ll>
#define vii(v, n, m, val) vector<vector<int>> v(n, vector<int>(m, val))
#define viii(v, i, j, k, val)        \
    vector<vector<vector<int>>> v(i, \
                                  vector<vector<int>>(j, vector<int>(k, val)))
#define pii pair<int, int>
#define pb push_back
#define file_io                       \
    freopen("input.txt", "r", stdin); \
    freopen("output.txt", "w", stdout);
#define testcases \
    int tcc;      \
    cin >> tcc;   \
    for (int tc = 1; tc <= tcc; tc++)
vector<string> vec_splitter(string s) {
    s += ',';
    vector<string> res;
    while (!s.empty()) {
        res.push_back(s.substr(0, s.find(',')));
        s = s.substr(s.find(',') + 1);
    }
    return res;
}
void debug_out(vector<string> __attribute__((unused)) args,
               __attribute__((unused)) int idx,
               __attribute__((unused)) int LINE_NUM) {
    cerr << endl;
}
template <typename Head, typename... Tail>
void debug_out(vector<string> args, int idx, int LINE_NUM, Head H, Tail... T) {
    if (idx > 0)
        cerr << ", ";
    else
        cerr << "Line(" << LINE_NUM << ") ";
    stringstream ss;
    ss << H;
    cerr << args[idx] << " = " << ss.str();
    debug_out(args, idx + 1, LINE_NUM, T...);
}
#ifdef DB
#define debug(...) \
    debug_out(vec_splitter(#__VA_ARGS__), 0, __LINE__, __VA_ARGS__)
#else
#define debug(...) 42
#endif

int main() {
    fast_io;
    int x,y; cin>>x>>y;
    int a=(4*x-y);
    if(a&1){
    	cout<<"No"; return 0;
    }
    a/=2;
    int b=x-a;
    if(a>=0 && b>=0) cout<<"Yes"; else cout<<"No";
}