Problem:
Score: 300 points

Problem Statement

M-kun is a student in Aoki High School, where a year is divided into N terms.

There is an exam at the end of each term. According to the scores in those exams, a student is given a grade for each term, as follows:

For the first through (K-1)-th terms: not given.

For each of the K-th through N-th terms: the multiplication of the scores in the last K exams, including the exam in the graded term.

M-kun scored A_i in the exam at the end of the i-th term.

For each i such that K+1 \leq i \leq N, determine whether his grade for the i-th term is strictly greater than the grade for the (i-1)-th term.

Constraints

2 \leq N \leq 200000

1 \leq K \leq N-1

1 \leq A_i \leq 10^{9}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
A_1 A_2 A_3 \ldots A_N

Output

Print the answer in N-K lines.

The i-th line should contain Yes if the grade for the (K+i)-th term is greater than the grade for the (K+i-1)-th term, and No otherwise.

Sample Input 1

5 3
96 98 95 100 20

Sample Output 1

Yes
No

His grade for each term is computed as follows:

3-rd term: (96 \times 98 \times 95) = 893760

4-th term: (98 \times 95 \times 100) = 931000

5-th term: (95 \times 100 \times 20) = 190000

Sample Input 2

3 2
1001 869120 1001

Sample Output 2

No

Note that the output should be No if the grade for the 3-rd term is equal to the grade for the 2-nd term.

Sample Input 3

15 7
3 1 4 1 5 9 2 6 5 3 5 8 9 7 9

Sample Output 3

Yes
Yes
No
Yes
Yes
No
Yes
Yes

Solution in C++ (GCC 9.2.1) (judge verdict: Runtime Error)

#include<iostream>
#include<stdio.h>
#include<vector>
#include<ctype.h>
#include<string>
#include<cmath>
#include<string.h>
#include<sstream>
#include<limits.h>
#define rep(i,n) for(int i=0;i<(n);++i)
using namespace std;
typedef long long int ll;
typedef vector<int> vi;

//最大公約数
int gcd(int a,int b){
    return b ? gcd(b,a%b):a;
}

//最小公倍数
int lcm(int a,int b){
    return a/gcd(a,b)*b;
}

//素数判定
bool isPrime(int x){
    if(x<2)return 0;
    else if(x==2)return 1;
    if(x%2==0)return 0;
    for(int i=3;i*i<=x;i+=2){
        if(x%i==0)return 0;
    }
    return 1;
}

//桁ごとの足し算
int digsum(int n){
    int res=0;
    while(n>0){
        res+=n%10;
        n/=10;
    }
    return res;
}

//約数列挙
vector<int> enum_div(int n){
    vector<int> ret;
    for(int i=1;i*i<=n;++i){
        if(n%i==0){
            ret.push_back(i);
            if(i*i !=n){
                ret.push_back(n/i);
            }
        }
    }
    return ret;
}

//累乗の計算とあまり,0で累乗そのまま出力
long long modpow(long long a,long long n,long long mod){
    if(mod==0)mod=__LONG_LONG_MAX__;
    long long res=1;
    while(n>0){
        if(n & 1)res=res*a%mod;
        a=a*a%mod;
        n>>=1;
    }
    return res;
}

long N,K;
vector<ll> A;
vector<ll> B;
int main(){
    cin>>N>>K;
    A.resize(N);
    B.assign(N+1,1);
    for(int i=0;i<N;++i){
        cin>>A[i];
        if(i==0){
            B[i+1]=A[i];
        }
        else {
            B[i+1]=B[i]*A[i];
        }
    }
    ll pre=B[K];
    for(int i=K;i<N;++i){
        ll now=B[i+1]/B[i+1-K];
        if(now>pre){
            cout<<"Yes"<<endl;
        }
        else{
            cout<<"No"<<endl;
        }
        pre=now;
    }
}