Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#define _GLIBCXX_DEBUG
#include<algorithm>
#include<cmath>
#include<cstring>
#include<cstdio>
#include<iostream>
#include<vector>
#include<queue>
#include<deque>
#include<stack>
#include<set>
#include<map>
#include<string>
#include <bits/stdc++.h>
#define rep(i, n) for(int i = 0; i < (int)n; i++)
#define rep2(i,s,n) for(int i=s;i< (int)n; i++)
#define ll long long 
#define all(v) v.begin(),v.end()
using namespace std;
const ll inf = 1000000007;
int main() {
  ll n,a,b,c,d; cin >>n>>a>>b>>c>>d;
  string s; cin >>s;
  if(c==d){
    cout <<"No"<<endl;
  }else if(c<d){
    rep2(i,b,d-2){
      if(s[i]=='#'&&s[i+1]=='#'){
        cout <<"No"<<endl;
        return 0;
      }
    }
    rep2(i,a,a-2){
      if(s[i]=='#'&&s[i+1]=='#'){
        cout <<"No"<<endl;
        return 0;
      }
    }
    cout <<"Yes"<<endl;
  }else{
   /* rep2(i,b,d-2){
      if(s[i]=='#'&&s[i+1]=='#'){
        cout <<"No"<<endl;
        return 0;
      }
    }
    rep2(i,a,a-2){
      if(s[i]=='#'&&s[i+1]=='#'){
        cout <<"No"<<endl;
        return 0;
      }
    }
    rep2(i,b-2,d-1){
      if(s[i]=='.'&&s[i+1]=='.'&&s[i+2]=='.'){
        cout <<"Yes"<<endl;
        return 0;
      }
    }*/
    cout <<"No"<<endl;
  }
}