Problem:
Score : 200 points

Problem Statement

We have N squares assigned the numbers 1,2,3,\ldots,N. Each square has an integer written on it, and the integer written on Square i is a_i.

How many squares i satisfy both of the following conditions?

The assigned number, i, is odd.

The written integer is odd.

Constraints

All values in input are integers.

1 \leq N, a_i \leq 100

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 \cdots a_N

Output

Print the number of squares that satisfy both of the conditions.

Sample Input 1

5
1 3 4 5 7

Sample Output 1

2

Two squares, Square 1 and 5, satisfy both of the conditions.

For Square 2 and 4, the assigned numbers are not odd.

For Square 3, the written integer is not odd.

Sample Input 2

15
13 76 46 15 50 98 93 77 31 43 84 90 6 24 14

Sample Output 2

3

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;

#define int long long
using ll = long long;
using ld = long double;
using intpair = pair<int, int>;
using intmap = map<int, int>;
using vi = vector<int>;
using vvi = vector<vector<int>>;
const int MOD = 1e9 + 7;
inline int mod (ll a, int m = MOD) { return (a % m + m) % m; }
inline bool bit (ll b, ll i) { return b & (1 << i); }
inline ll ceiv (ll a, ll b) { return (a + b - 1) / b; }
//struct Fast {Fast(){cin.tie(0);ios::sync_with_stdio(0);}} fast;

#define debug(x) cerr << #x << ": " << x << '\n'
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define reps(i, n, m) for (int i = (int)(n); i <= (int)(m); i++)
#define ALL(obj) (obj).begin(), (obj).end()
#define rALL(obj) (obj).rbegin(), (obj).rend()

signed main(){
    int n; cin >> n;
    vi a(n);
    rep(i,n) cin >> a[i];
    int ans = 0;
    rep(i,n){
        if((i+1) % 2 == 1 && a[i] % 2 == 1){
            ans++;
        }
    }
    cout << ans << endl;
}