Problem:
Score : 300 points

Problem Statement

A company has N members, who are assigned ID numbers 1, ..., N.

Every member, except the member numbered 1, has exactly one immediate boss with a smaller ID number.

When a person X is the immediate boss of a person Y, the person Y is said to be an immediate subordinate of the person X.

You are given the information that the immediate boss of the member numbered i is the member numbered A_i. For each member, find how many immediate subordinates it has.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq A_i < i

Input

Input is given from Standard Input in the following format:

N
A_2 ... A_N

Output

For each of the members numbered 1, 2, ..., N, print the number of immediate subordinates it has, in its own line.

Sample Input 1

5
1 1 2 2

Sample Output 1

2
2
0
0
0

The member numbered 1 has two immediate subordinates: the members numbered 2 and 3.

The member numbered 2 has two immediate subordinates: the members numbered 4 and 5.

The members numbered 3, 4, and 5 do not have immediate subordinates.

Sample Input 2

10
1 1 1 1 1 1 1 1 1

Sample Output 2

9
0
0
0
0
0
0
0
0
0

Sample Input 3

7
1 2 3 4 5 6

Sample Output 3

1
1
1
1
1
1
0

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

//Nihal Mittal - nihal_47
//Strike First , Strike Hard , No Mercy !!

/**⠀⠀⠀⠀⠀⠀⣀⣤⣤⣄⣀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀⣠⣾⣿⣿⣿⣿⣿⣿⣿⣿⣿⣦⣀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⣰⣿⣿⣿⣿⠿⠿⣿⣿⣿⣿⣿⣿⣿⣧⢀⠀⠀⠀⠀
⠀⠀⠀⣿⣿⣿⠋⠀⠀⠀⠀⠀⠙⠀⠙⣿⣿⣿⣷⢳⢀⠀⠀⠀
⠀⠀⣠⣿⣿⣿⢸⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣿⣿⣿⣿⣿⢀
⠀⠀⣸⣿⣿⣿⠸⠀⠀⠀⠒⠒⠒⠐⠀⠀⢿⣿⣿⣿⣿⣿⠀⠀
⠀⣴⣿⣿⣿⡿⠀⠒⣋⣙⡒⢰⠀⠤⣖⠒⢾⣿⣿⣿⣿⣧⠀⠀
⢺⣿⣿⣿⣿⢀⠀⠀⠉⠉⠉⠸⠀⡇⠉⠉⠀⢿⣿⣿⣿⣄⠀⠀
⠀⠙⣿⣿⣧⢻⠀⠀⠀⠀⠀⠠⠀⠰⠀⠀⠀⣸⠸⣿⣿⠿⠰⠀
⠀⠀⠀⠹⣿⣿⣿⣷⠀⡠⠙⣲⣔⣅⢡⣰⣷⣿⣿⣿⣧⠀⠀⠀
⠀⠀⠀⣼⣿⣿⣿⣿⠀⡿⠭⠭⠭⠭⢿⠀⣿⢻⣿⣿⠃⠀⠀⠀
⠀⠀⠀⠙⠛⣿⢻⠹⣿⠐⠙⠛⠟⠉⢀⣴⡟⢿⣿⡏⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀⡟⠀⠀⠻⣦⣤⣶⠾⠋⠀⠀⠁⡦⢄⢀⠀⠀⠀
⠀⠀⠀⠀⡠⠁⡇⠑⢄⠀⠀⠀⠀⠀⠀⠔⠀⠀⠁⠀⠀⠀⠉⠁
⠀⠔⠊⠁⠀⠀⣇⠀⠀⠀⠑⡤⠤⢎⠁⠀⠀⡘⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀⢢⠠⠀⡠⢆⠀⠀⡠⠙⢄⠀⡸⠀
**/
#include<bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#define ll long long
#define ld long double
#define mk make_pair
#define pb push_back
#define in insert
#define se second
#define fi first
#define mod 1000000007
#define watch(x) cout << (#x) << " is " << (x) << "\n"
#define all(v) (v).begin(),(v).end()
#define fast ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(0);
#define pii pair<ll,ll>
#define vi(x) vector<x>
#define maxn 100005
#define ordered_set tree<ll, null_type,less<ll>, rb_tree_tag,tree_order_statistics_node_update> 
using namespace std;
using namespace __gnu_pbds;

signed main()
{
    fast;
   
    ll n,i,j;
    cin>>n;
    ll ma[n+2]={0};
    for(i=2;i<=n;i++)
    {
    	ll x;
    	cin>>x;
    	ma[x]++;
    }
    for(i=1;i<=n;i++) cout<<ma[i]<<"\n";
}