Problem:
Score : 100 points

Problem Statement

We have A balls with the string S written on each of them and B balls with the string T written on each of them.

From these balls, Takahashi chooses one with the string U written on it and throws it away.

Find the number of balls with the string S and balls with the string T that we have now.

Constraints

S, T, and U are strings consisting of lowercase English letters.

The lengths of S and T are each between 1 and 10 (inclusive).

S \not= T

S=U or T=U.

1 \leq A,B \leq 10

A and B are integers.

Input

Input is given from Standard Input in the following format:

S T
A B
U

Output

Print the answer, with space in between.

Sample Input 1

red blue
3 4
red

Sample Output 1

2 4

Takahashi chose a ball with red written on it and threw it away.
Now we have two balls with the string S and four balls with the string T.

Sample Input 2

red blue
5 5
blue

Sample Output 2

5 4

Takahashi chose a ball with blue written on it and threw it away.
Now we have five balls with the string S and four balls with the string T.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#pragma comment(linker, "/STACK:33554432")
#define _CRT_SECURE_NO_WARNINGS
#include <iostream>
#include <vector>
#include <algorithm>
#include <map>
#include <set>
#include <string>
#include <queue>
#include <unordered_map>
#include <iterator>
#include <stack>
#include <unordered_set>
#include <iomanip>
#include <ctime>
#include <cmath>
#include <cstring>
#include <bitset>

using namespace std;
void dout() { cerr << endl; }

template <typename Head, typename... Tail>
void dout(Head H, Tail... T) {
    cerr << H << ' ';
    dout(T...);
}

using ll = long long;
using ld = long double;


void precalc() {}

void solve() {

    string a;
    string b;
    ll a_cnt;
    ll b_cnt;
    string u;

    cin >> a >> b >>a_cnt >> b_cnt >> u;


    if (a == u)
        cout << a_cnt - 1 << " " << b_cnt;
    else
        cout << a_cnt << " " << b_cnt - 1;
}

int main()
{
    ios_base::sync_with_stdio(false);
    cin.tie(0), cout.tie(0);
    cout << fixed << setprecision(20);
    precalc();
    solve();

}