Problem:
Score : 100 points

Problem Statement

You have three tasks, all of which need to be completed.

First, you can complete any one task at cost 0.

Then, just after completing the i-th task, you can complete the j-th task at cost |A_j - A_i|.

Here, |x| denotes the absolute value of x.

Find the minimum total cost required to complete all the task.

Constraints

All values in input are integers.

1 \leq A_1, A_2, A_3 \leq 100

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

Print the minimum total cost required to complete all the task.

Sample Input 1

1 6 3

Sample Output 1

5

When the tasks are completed in the following order, the total cost will be 5, which is the minimum:

Complete the first task at cost 0.

Complete the third task at cost 2.

Complete the second task at cost 3.

Sample Input 2

11 5 5

Sample Output 2

6

Sample Input 3

100 100 100

Sample Output 3

0

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <vector>
#include <math.h>
#include <cmath>
#include <algorithm>
#include <string>
#include <cstring>

using namespace std;

using ull = unsigned long long;
using vi = vector<int>;
using vs = vector<string>;
using vull = vector<ull>;

#define FOR(i,a,b) for(int i=(a);i<=(b);i++)
#define rFOR(i,a,b) for(int i=(b);i>=(a);i--)
#define SORT(a) sort((a).begin(),(a).end());
#define rSORT(a) sort((a).rbegin(),(a).rend());
#define yn(a) cout <<((a)?"Yes":"No")<<endl;

//sankou
//vvi = vector<vector<int>>(20, vector<int>(10, 0));

int isP(int n) {
    if(n<=1) return 0;
    FOR(i,2,(int)sqrt(n)) {
        if(n%i==0) return 0;
    }
    return 1;
}

int main() {
    
    vector<int> a(3,0);
    cin >>a[0]>>a[1]>>a[2];
    SORT(a);
    cout <<abs(a[2]-a[0]);
    
    return 0;
}