Problem:
Score : 200 points

Problem Statement

A string is called a KEYENCE string when it can be changed to keyence by removing its contiguous substring (possibly empty) only once.

Given a string S consisting of lowercase English letters, determine if S is a KEYENCE string.

Constraints

The length of S is between 7 and 100 (inclusive).

S consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S

Output

If S is a KEYENCE string, print YES; otherwise, print NO.

Sample Input 1

keyofscience

Sample Output 1

YES

keyence is an abbreviation of key of science.

Sample Input 2

mpyszsbznf

Sample Output 2

NO

Sample Input 3

ashlfyha

Sample Output 3

NO

Sample Input 4

keyence

Sample Output 4

YES

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

//Ruthless Coding 
#include <bits/stdc++.h>

#define uni(x)      (x).resize(unique(all(x)) - (x).begin())
#define fprint(v)   for(auto x : v) cout << x << ' '
#define ALL(x)      (x).begin(), (x).end()
#define MP(x, y)    make_pair(x, y)
#define SZ(x)       int((x).size())
#define PB(x)       push_back(x)
#define ll          long long
#define S           second 
#define F           first
#define nl          '\n'

using namespace std;
void __print(int x) {cerr << x;}
void __print(long x) {cerr << x;}
void __print(long long x) {cerr << x;}
void __print(unsigned x) {cerr << x;}
void __print(unsigned long x) {cerr << x;}
void __print(unsigned long long x) {cerr << x;}
void __print(float x) {cerr << x;}
void __print(double x) {cerr << x;}
void __print(long double x) {cerr << x;}
void __print(char x) {cerr << '\'' << x << '\'';}
void __print(const char *x) {cerr << '\"' << x << '\"';}
void __print(const string &x) {cerr << '\"' << x << '\"';}
void __print(bool x) {cerr << (x ? "true" : "false");}

template<typename T, typename V>
void __print(const pair<T, V> &x) {cerr << '{'; __print(x.first); cerr << ','; __print(x.second); cerr << '}';}
template<typename T>
void __print(const T &x) {int f = 0; cerr << '{'; for (auto &i: x) cerr << (f++ ? "," : ""), __print(i); cerr << "}";}
void _print() {cerr << "]\n";}
template <typename T, typename... V>
void _print(T t, V... v) {__print(t); if (sizeof...(v)) cerr << ", "; _print(v...);}
#ifndef ONLINE_JUDGE
#define debug(x...) cerr << "[" << #x << "] = ["; _print(x)
#else
#define debug(x...)
#endif
mt19937_64 rnd;

const int N = 2e5 + 5;

int main() {
    ios_base::sync_with_stdio(0);cin.tie(0);
    string s;
    cin >> s;
    string p = "keyence";
    int j = 0;
    int cnt = 0;
    for(int i = 0; i < SZ(s); i++){
        if(p[j] == s[i]){
            s[i] = '#';
            j++;
        }
    }
    if(j != SZ(p)){
        cout << "NO";
        return 0;
    }
    for(int i = 0; i < SZ(s);){
        int pos = i;
        while(i < SZ(s) && s[i] != '#'){
            i++;
        }
        if(i > pos){
            cnt++;
        }
        i++;
    }
    if(cnt <= 1 && j == SZ(p)){
        cout << "YES";
    }else{
        cout << "NO";
    }
    return 0;
}
/*
    *** Most Impo.. -> check base case always
    1. Overflow Check (*, +)
    2. Index check (0 - based or 1 - based)
    3. Check for n = 1, 2, 3, 4....
    4. Corner Cases
*/