Problem:
Score : 100 points

Problem Statement

A Hitachi string is a concatenation of one or more copies of the string hi.

For example, hi and hihi are Hitachi strings, while ha and hii are not.

Given a string S, determine whether S is a Hitachi string.

Constraints

The length of S is between 1 and 10 (inclusive).

S is a string consisting of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S

Output

If S is a Hitachi string, print Yes; otherwise, print No.

Sample Input 1

hihi

Sample Output 1

Yes

hihi is the concatenation of two copies of hi, so it is a Hitachi string.

Sample Input 2

hi

Sample Output 2

Yes

Sample Input 3

ha

Sample Output 3

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <iostream>      // cout, endl, cin
#include <string>        // string, to_string, stoi
#include <vector>        // vector
#include <algorithm>     // min, max, swap, sort, reverse, lower_bound, upper_bound
#include <utility>       // pair, make_pair
#include <tuple>         // tuple, make_tuple
#include <cstdint>       // int64_t, int*_t
#include <cstdio>        // printf
#include <map>           // map
#include <queue>         // queue, priority_queue
#include <set>           // set
#include <stack>         // stack
#include <deque>         // deque
#include <unordered_map> // unordered_map
#include <unordered_set> // unordered_set
#include <bitset>        // bitset
#include <cctype>        // isupper, islower, isdigit, toupper, tolower
#define rep(i, n) for (int i = 0; i < (n); i++)
using namespace std;
typedef long long ll;
typedef pair<ll, ll> Pl;
typedef pair<int, int> P;

int main()
{
  string S;
  cin >> S;

  if (S == "hitachi")
  {
    cout << "Yes" << endl;
  }
  else
  {
    cout << "No" << endl;
  }

  return 0;
}