Problem:
Score : 500 points

Problem Statement

There are N points on the 2D plane, i-th of which is located on (x_i, y_i).
There can be multiple points that share the same coordinate.
What is the maximum possible Manhattan distance between two distinct points?

Here, the Manhattan distance between two points (x_i, y_i) and (x_j, y_j) is defined by |x_i-x_j| + |y_i-y_j|.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq x_i,y_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
x_1 y_1
x_2 y_2
:
x_N y_N

Output

Print the answer.

Sample Input 1

3
1 1
2 4
3 2

Sample Output 1

4

The Manhattan distance between the first point and the second point is |1-2|+|1-4|=4, which is maximum possible.

Sample Input 2

2
1 1
1 1

Sample Output 2

0

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>

using namespace std;

#define FOR(i, n) for(int i = 0; i < (int) n; i++)
#define PB push_back
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()
#define F first
#define S second

typedef long long ll;
typedef vector<int> vi;
typedef pair<int,int> pii;

const int MOD = 1e9+7;
const int MAX = 1e5+7;

int main(){
	ios::sync_with_stdio(false); cin.tie(0);

	int n; cin >> n;
	
	vi v1(n), v2(n);

	FOR(i, n){
		int a, b; cin >> a >> b;
		v1[i] = a+b;
		v2[i] = a-b;
	}

	sort(all(v1));
	sort(all(v2));

	cout << max(v1.back()-v1[0], v2.back()-v2[0]) << '\n';

	return 0;
}