Problem:
Score : 200 points

Problem Statement

Tak performed the following action N times: rolling two dice.
The result of the i-th roll is D_{i,1} and D_{i,2}.

Check if doublets occurred at least three times in a row.
Specifically, check if there exists at lease one i such that D_{i,1}=D_{i,2}, D_{i+1,1}=D_{i+1,2} and D_{i+2,1}=D_{i+2,2} hold.

Constraints

3 \leq N \leq 100

1\leq D_{i,j} \leq 6

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
D_{1,1} D_{1,2}
\vdots
D_{N,1} D_{N,2}

Output

Print Yes if doublets occurred at least three times in a row. Print No otherwise.

Sample Input 1

5
1 2
6 6
4 4
3 3
3 2

Sample Output 1

Yes

From the second roll to the fourth roll, three doublets occurred in a row.

Sample Input 2

5
1 1
2 2
3 4
5 5
6 6

Sample Output 2

No

Sample Input 3

6
1 1
2 2
3 3
4 4
5 5
6 6

Sample Output 3

Yes

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;
 #define MAX 1000000000005
 #define ll long long int
 int main()
 {    ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);
   ll t;

        long long int m,sum=0,k=0,i,j,x=0,sum1=0,l,kk,y,z,e,f,q=MAX,r=MAX,n;
           ll a,b,c=0,d,zz=1;
             cin>>n;
              for(i=0;i<n;i++)
                 { cin>>a>>b;
                   if(a==b)
                     c++;
                 }
                 if(c==3)
                    cout<<"Yes";
                 else
                    cout<<"No";
    }