Problem:
Score : 100 points

Problem Statement

Takahashi is going to set a 3-character password.

How many possible passwords are there if each of its characters must be a digit between 1 and N (inclusive)?

Constraints

1 \leq N \leq 9

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

Print the number of possible passwords.

Sample Input 1

2

Sample Output 1

8

There are eight possible passwords: 111, 112, 121, 122, 211, 212, 221, and 222.

Sample Input 2

1

Sample Output 2

1

There is only one possible password if you can only use one kind of character.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

/*{{{*/
#include<bits/stdc++.h>
using namespace std;

#define ll long long
#define vi vector<int>
#define vl vector<ll>
#define pii pair<int,int>
#define pll pair<ll,ll>
// pll pp; -> (pp.first,pp.second)
// vector<vl> pp(n,vl(2)); sort(pp.begin(),pp.end(),[](vl a,vl b){return a[0]<b[0];});

#define REP(i,n) for(ll (i)=0;(i)<(n);(i)++)
#define RREP(i,n) for(ll (i)=(n)-1;(i)>=0;(i)--)
#define FOR(i,a,b) for(ll (i)=(a);(i)<(b);(i)++)
#define FORR(i,a,b) for(ll (i)=(b)-1;(i)>=(a);(i)--)
#define DEBUG(x) cout << #x << ": " << x << endl
#define CHMAX(a,b) a=max((a),(b))
#define CHMIN(a,b) a=min((a),(b))
/*}}}*/
int main() {
  ll n;
  cin >> n;
  ll ans = n* n*n;
  cout << ans<< endl;
  return 0;
}