Problem:
Score : 300 points

Problem Statement

Sitting in a station waiting room, Joisino is gazing at her train ticket.

The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).

In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.

The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Constraints

0≤A,B,C,D≤9

All input values are integers.

It is guaranteed that there is a solution.

Input

Input is given from Standard Input in the following format:

ABCD

Output

Print the formula you made, including the part =7.

Use the signs + and -.

Do not print a space between a digit and a sign.

Sample Input 1

1222

Sample Output 1

1+2+2+2=7

This is the only valid solution.

Sample Input 2

0290

Sample Output 2

0-2+9+0=7

0 - 2 + 9 - 0 = 7 is also a valid solution.

Sample Input 3

3242

Sample Output 3

3+2+4-2=7

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<iostream>
#include<string>
using namespace std;
char A[5];
int a[5];
int sum;
string str;
int main(){
  for(int i=0; i<4; ++i){
    cin >> A[i];
    a[i] = A[i] - '0';
  }
  
  for(int bit=0; bit < (1 << 3); ++bit){
    sum =a[0];
    str ="";
    str.push_back(A[0]);
    for(int i=0; i <3; ++i){
      if (bit & (1 <<i)){
        sum +=a[i+1];
        str += "+";
        str.push_back(A[i+1]);
      }
      else {
        sum -= a[i+1];
        str +="-";
        str.push_back(A[i+1]);
      }
    }
    if (sum ==7) break;
  }
  str += "=7";
  cout << str << endl;
  return 0;
}