Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <fstream>
#include <cstdio>
#include <cassert>
#include <complex>
#include <cmath>
#include <algorithm>
#include <vector>
#include <string>
#include <cstdlib>
#include <cstring>
#include <iomanip>
#include <numeric>
#include <sstream>
#include <ctime>
#include <cctype>
#include <set>
#include <map>
#include <queue>
#include <bitset>
#include <deque>
#include <stack>
#include <memory.h>
using namespace std;
#define ll long long 
int n;
int main()
{
	cin>>n;
	if(n%4==0){
		cout<<n/4*3<<" "<<n/4*3<<" "<<n/4*3;
	}
	else{
		if(n%2==0){
			cout<<n/2<<' '<<n<<" "<<n;
		}
		else{
			if(n%3==0){
				cout<<n+n/3<<" "<<n+n/3<<" "<<n+n/3;
			}
			else{
				double n=n;
				for(double i=1;i<=3500;i++){
					for(double j=1;j<=3500;j++){
						double k=1/(4/n-1/i-1/j);
						if(k<1){
							continue;
						}
						if(k==(int)k){
							cout<<i<<" "<<j<<" "<<k;
							return 0;
						}
					}
				}
			}
		}
	}
    return 0;
}