Problem:
Score : 600 points

Problem Statement

Silver Fox is fighting with N monsters.

The monsters are standing in a row, and we can assume them to be standing on a number line. The i-th monster, standing at the coordinate X_i, has the health of H_i.

Silver Fox can use bombs to attack the monsters.
Using a bomb at the coordinate x decreases the healths of all monsters between the coordinates x-D and x+D (inclusive) by A.
There is no way other than bombs to decrease the monster's health.

Silver Fox wins when all the monsters' healths become 0 or below.

Find the minimum number of bombs needed to win.

Constraints

1 \leq N \leq 2 \times 10^5

0 \leq D \leq 10^9

1 \leq A \leq 10^9

0 \leq X_i \leq 10^9

1 \leq H_i \leq 10^9

X_i are distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N D A
X_1 H_1
:
X_N H_N

Output

Print the minimum number of bombs needed to win.

Sample Input 1

3 3 2
1 2
5 4
9 2

Sample Output 1

2

First, let us use a bomb at the coordinate 4 to decrease the first and second monsters' health by 2.

Then, use a bomb at the coordinate 6 to decrease the second and third monsters' health by 2.

Now, all the monsters' healths are 0.
We cannot make all the monsters' health drop to 0 or below with just one bomb.

Sample Input 2

9 4 1
1 5
2 4
3 3
4 2
5 1
6 2
7 3
8 4
9 5

Sample Output 2

5

We should use five bombs at the coordinate 5.

Sample Input 3

3 0 1
300000000 1000000000
100000000 1000000000
200000000 1000000000

Sample Output 3

3000000000

Watch out for overflow.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>

using namespace std;

typedef pair<int,int> P;
typedef long long ll;
typedef vector<int> vi;
typedef vector<ll> vll;
// #define int long long
#define pb push_back
#define mp make_pair
#define eps 1e-9
#define INF 2000000000 //2e9
#define LLINF 1000000000000000ll // 1e15
#define fi first
#define sec second
#define all(x) (x).begin(),(x).end()
#define sq(x) ((x)*(x))
#define dmp(x) cerr << #x << ": " << x << endl;

template<class T> void chmin(T& a,const T& b){if(a>b)a=b;}
template<class T> void chmax(T& a,const T& b){if(a<b)a=b;}

template<class T> using MaxHeap = priority_queue<T>;
template<class T> using MinHeap = priority_queue<T,vector<T>,greater<T>>;
template<class T> vector<T> vect(int len,T elem){ return vector<T>(len,elem); }

template<class T,class U>
ostream& operator << (ostream& os,const pair<T,U>& p){
  os << p.fi << ',' << p.sec; return os;
}
template<class T,class U>
istream& operator >> (istream& is,pair<T,U>& p){
  is >> p.fi >> p.sec; return is;
}
template<class T>
ostream& operator << (ostream &os,const vector<T> &vec){
  for(int i=0;i<vec.size();i++){
    os << vec[i];
    if(i+1<vec.size())os << ' ';
  }
  return os;
}
template<class T>
istream& operator >> (istream &is,vector<T>& vec){
  for(int i=0;i<vec.size();i++)is >> vec[i];
  return is;
}
void fastio(){
  cin.tie(0);
  ios::sync_with_stdio(0);
  cout<<fixed<<setprecision(20);
}

namespace Math{
  template<int MOD> // if inv is needed, this shold be prime.
  struct ModInt{
    ll val;
    ModInt():val(0ll){}
    ModInt(const ll& v):val(((v%MOD)+MOD)%MOD){}
    bool operator==(const ModInt& x)const{return val==x.val;}
    bool operator!=(const ModInt& x)const{return !(*this==x);}
    bool operator<(const ModInt& x)const{return val<x.val;}
    bool operator>(const ModInt& x)const{return val>x.val;}
    bool operator>=(const ModInt& x)const{return !(*this<x);}
    bool operator<=(const ModInt& x)const{return !(*this>x);}
    ModInt& operator+=(const ModInt& x){if((val+=x.val)>=MOD)val-=MOD;return *this;}
    ModInt& operator-=(const ModInt& x){if((val+=MOD-x.val)>=MOD)val-=MOD;return *this;}
    ModInt& operator*=(const ModInt& x){(val*=x.val)%=MOD;return *this;}
    ModInt operator+(const ModInt& x)const{return ModInt(*this)+=x;}
    ModInt operator-(const ModInt& x)const{return ModInt(*this)-=x;}
    ModInt operator*(const ModInt& x)const{return ModInt(*this)*=x;}
    friend istream& operator>>(istream&i,ModInt& x){ll v;i>>v;x=v;return i;}
    friend ostream& operator<<(ostream&o,const ModInt& x){o<<x.val;return o;}
  };

  template<int MOD>
  ModInt<MOD> pow(ModInt<MOD> a,ll x){
    ModInt<MOD> res = ModInt<MOD>(1ll);
    while(x){
      if(x&1)res *= a;
      x >>= 1;
      a = a*a;
    }
    return res;
  }

  constexpr int MOD = 1e9+7;
  using mint = ModInt<MOD>;

  vector<mint> inv,fac,facinv;
  // notice: 0C0 = 1 
  ModInt<MOD> nCr(int n,int r){
    assert(!(n<r));
    assert(!(n<0||r<0));
    return fac[n]*facinv[r]*facinv[n-r];
  }
  void init(int SIZE){
    fac.resize(SIZE+1);
    inv.resize(SIZE+1);
    facinv.resize(SIZE+1);
    fac[0] = inv[1] = facinv[0] = mint(1ll);
    for(int i=1;i<=SIZE;i++)fac[i]=fac[i-1]*mint(i);
    for(int i=2;i<=SIZE;i++)inv[i]=mint(0ll)-mint(MOD/i)*inv[MOD%i];
    for(int i=1;i<=SIZE;i++)facinv[i]=facinv[i-1]*inv[i];
    return;
  }
  template<class T>
  int digit(T x){
    int res = 0;
    while(x){
      x /= T(10);
      res++;
    }
    return res;
  }
}

namespace DS{
  template<class T>
  struct RangeSum{
    vector<T> vec;
    RangeSum(){}
    RangeSum(vector<T> elems):vec(elems){
      for(int i=1;i<vec.size();i++){
        vec[i] += vec[i-1];
      }
    }
    T sum(int l,int r){
      if(l>r)return T(0);
      if(l==0)return vec[r];
      else return vec[r]-vec[l-1];
    }
  };
  template<class T>
  struct BIT{
    int N;
    vector<T> bit;
    BIT(int N):N(N){
      bit = vector<T>(N+1,T(0));
    }
    void add(int i,T x){
      i++;
      while(i<=N){
        bit[i]+=x;
        i+=i&-i;
      }
      return;
    }
    T sum(int i){
      i++;
      T res = T(0);
      while(i>0){
        res+=bit[i];
        i-=i&-i;
      }
      return res;
    }
    T sum(int l,int r){// [l,r]
      assert(l<=r);
      if(l==0)return sum(r);
      else return sum(r)-sum(l-1);
    }
  };
  template<class T>
  struct SlideMin{
    vector<T> v;
    deque<int> deq;
    SlideMin(vector<T> &v):v(v){}
    void add(int id){
      while(!deq.empty()&&v[deq.back()]>=v[id])deq.pop_back();
      deq.push_back(id);
    }
    T get(int id){ // [id,added]
      while(!deq.empty()&&deq.front()<id)deq.pop_front();
      assert(!deq.empty());
      return v[deq.front()];
    }
  };
  template<class T>
  struct SlideMax{
    vector<T> v;
    deque<int> deq;
    SlideMax(vector<T> &v):v(v){}
    void add(int id){
      while(!deq.empty()&&v[deq.back()]<=v[id])deq.pop_back();
      deq.push_back(id);
    }
    T get(int id){ // [id,added]
      while(!deq.empty()&&deq.front()<id)deq.pop_front();
      assert(!deq.empty());
      return v[deq.front()];
    }
  };
}

namespace Util{
  template<class T>
  vector<pair<T,int>> runLength(vector<T> v){
    vector<pair<T,int>> res;
    for(int i=0;i<v.size();i++){
      if(res.empty()||res.back().first!=v[i])res.push_back(make_pair(v[i],1));
      else res.back().second++;
    }
    return res;
  }
  template<class T>
  void compress(vector<T> &v){
    sort(v.begin(),v.end());
    v.erase(unique(v.begin(),v.end()),v.end());
  }
}

template<class D,class O>
struct LazySegmentTree{
  using DMerger = function<D(D,D)>;
  using OMerger = function<O(O,O)>;
  using Applier = function<D(D,O,int)>;

  int length;

  D d_unit;
  O o_unit;

	vector<D> seg;
  vector<O> lazy;

  DMerger dm;
  OMerger om;
  Applier app;

	void lazy_evaluate(int k,int len){
    if(lazy[k] == o_unit) return;
		if(len>1){
			lazy[2*k+1] = om(lazy[2*k+1],lazy[k]);
			lazy[2*k+2] = om(lazy[2*k+2],lazy[k]);
		}
		seg[k] = app(seg[k],lazy[k],len);
		lazy[k] = o_unit;
	}
	void update(int a,int b,int k,int l,int r,O x){
		lazy_evaluate(k,r-l);
		if(r<=a||b<=l)return;
    else if(a<=l&&r<=b){
			lazy[k] = om(lazy[k],x);
			lazy_evaluate(k,r-l);
		}else{
			update(a,b,k*2+1,l,(l+r)/2,x);
			update(a,b,k*2+2,(l+r)/2,r,x);
			seg[k] = seg[k*2+1]+seg[k*2+2];
		}
	}
  void update(int a,int b,O x){
    update(a,b,0,0,length,x);
  }
	D query(int a,int b,int k,int l,int r){
		lazy_evaluate(k,r-l);
		if(r<=a||b<=l)return 0ll; 
    else if(a<=l&&r<=b)return seg[k];
		else{
			D lch = query(a,b,k*2+1,l,(l+r)/2);
			D rch = query(a,b,k*2+2,(l+r)/2,r);
			return dm(lch,rch);
		}
	}
  D query(int a,int b){
    return query(a,b,0,0,length);
  }
  LazySegmentTree(int n,D d_unit,O o_unit,DMerger dm,OMerger om,Applier app)
    :length(1),d_unit(d_unit),o_unit(o_unit),dm(dm),om(om),app(app) {
    while(length<n){ length <<= 1; }
    seg.assign(length * 2, d_unit);
    lazy.assign(length * 2, o_unit);
  }
  LazySegmentTree(vector<D> vec,D d_unit,O o_unit,DMerger dm,OMerger om,Applier app)
    :length(1),seg(vec),d_unit(d_unit),o_unit(o_unit),dm(dm),om(om),app(app) {
    while(length<vec.size()){ length <<= 1; }
    seg.resize(length * 2, d_unit);
    lazy.assign(length * 2, o_unit);
  }
};

int N,D;
ll A;
vector<pair<ll,ll>> H;


signed main(){
  fastio();
  auto dm = [](ll a,ll b){return a+b;};
  auto om = [](ll a,ll b){return a+b;};
  auto app = [](ll dat,ll lz,int len){return dat+lz*len;};
  LazySegmentTree<ll,ll> seg(1<<18,0ll,0ll,dm,om,app);
  cin >> N >> D >> A;
  H.resize(N);
  vector<ll> zip;
  for(int i=0;i<N;i++){
    cin >> H[i].fi >> H[i].sec;
    H[i].sec = (H[i].sec-1ll)/A+1ll;
    zip.pb(H[i].fi);
  }
  sort(all(zip));
  sort(all(H));
  ll ans = 0;
  for(int i=0;i<N;i++){
    seg.update(i,i+1,H[i].sec);
  }
  for(int i=0;i<N;i++){
    ll c = seg.query(i,i+1);
    if(c<=0ll)continue;
    int idx = upper_bound(all(zip),H[i].fi+2*D)-zip.begin();
    ans += c;
    seg.update(i,idx,-c);
  }
  cout << ans << endl;
  return 0;
}