Problem:
Score: 200 points

Problem Statement

A country decides to build a palace.

In this country, the average temperature of a point at an elevation of x meters is T-x \times 0.006 degrees Celsius.

There are N places proposed for the place. The elevation of Place i is H_i meters.

Among them, Princess Joisino orders you to select the place whose average temperature is the closest to A degrees Celsius, and build the palace there.

Print the index of the place where the palace should be built.

It is guaranteed that the solution is unique.

Constraints

1 \leq N \leq 1000

0 \leq T \leq 50

-60 \leq A \leq T

0 \leq H_i \leq 10^5

All values in input are integers.

The solution is unique.

Input

Input is given from Standard Input in the following format:

N
T A
H_1 H_2 ... H_N

Output

Print the index of the place where the palace should be built.

Sample Input 1

2
12 5
1000 2000

Sample Output 1

1

The average temperature of Place 1 is 12-1000 \times 0.006=6 degrees Celsius.

The average temperature of Place 2 is 12-2000 \times 0.006=0 degrees Celsius.

Thus, the palace should be built at Place 1.

Sample Input 2

3
21 -11
81234 94124 52141

Sample Output 2

3

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <iostream>
#include <string>
#include <vector>
#include <cmath>
#include <deque>
#include <queue>//for queue and priority_queue
#include <fstream>
#include <iomanip>
#include <stack>
#include <algorithm>
#include <set>
#include <map>
#include <list>
#define endl "\n"
typedef long long ll;
using namespace std;
void Lancer() { ios::sync_with_stdio(0); cin.tie(0); cout.tie(0); }
bool isPrime(ll n){
	if (n == 2 || n == 3 || n == 5)
		return true;
	else if (n % 2 == 0 || n % 3 == 0 || n % 5 == 0 || n == 1)
		return false;
	else {
		for (int i = 5; i <= sqrt(n); i += 2){
			if (n%i == 0)
				return false;
		}
		return true;
	}
}

//char arr[107][107];
int main(){
	Lancer();
	double n, t, a,h, ind=1,res = 1000000000000000000,d;
	cin >> n >> t >> a;
	for (int i = 0; i < n; i++){
		cin >> h;
		d = t- (h*0.006);
		d = abs(d-a);
		//cout << d << endl;
		if (d < res){
			res = d;
			ind = i+1;
		}
	}
	cout << ind;
	cout << endl;
	return 0;
}