Problem:
Score : 400 points

Problem Statement

Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.

You are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.

Constraints

2 ≦ |s| ≦ 10^5

s consists of lowercase letters.

Partial Score

200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.

Input

The input is given from Standard Input in the following format:

s

Output

If there exists no unbalanced substring of s, print -1 -1.

If there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.

Sample Input 1

needed

Sample Output 1

2 5

The string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.

Sample Input 2

atcoder

Sample Output 2

-1 -1

The string atcoder contains no unbalanced substring.

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include<iostream>
#include<map>
#include<algorithm>
using namespace std;

int main(){
    string s;
    cin >> s;
    map<char,int> mp;
    int n = (int)s.size();
    for(int i = 0; i < n; i++) mp[s[i]]++;

    for(int i = n - 1; 0 < i; i--){
        int tmp = 0;
        for(auto v:mp){
            tmp = max(tmp,v.second);
        }
        if(tmp > (i + 1) / 2){
            cout << 1 << " " << i + 1 << endl;
            return 0;
        }else{
            mp[s[i]]--;
        }
    }
    for(int i = 1; i < n; i++)mp[s[i]]++;
    for(int i = 1; i < n; i++){
        int tmp = 0;
        for(auto v:mp){
            tmp = max(tmp,v.second);
        }
        if(tmp > (i + 1) / 2){
            cout << i + 1 << " " << n << endl;
            return 0;
        }else{
            mp[s[i]]--;
        }
    }
    cout << -1 << " " << -1 << endl;
}