Problem:
Score : 200 points

Problem Statement

You are given strings s and t, consisting of lowercase English letters.
You will create a string s' by freely rearranging the characters in s.
You will also create a string t' by freely rearranging the characters in t.
Determine whether it is possible to satisfy s' < t' for the lexicographic order.

Notes

For a string a = a_1 a_2 ... a_N of length N and a string b = b_1 b_2 ... b_M of length M, we say a < b for the lexicographic order if either one of the following two conditions holds true:

N < M and a_1 = b_1, a_2 = b_2, ..., a_N = b_N.

There exists i (1 \leq i \leq N, M) such that a_1 = b_1, a_2 = b_2, ..., a_{i - 1} = b_{i - 1} and a_i < b_i. Here, letters are compared using alphabetical order.

For example, xy < xya and atcoder < atlas.

Constraints

The lengths of s and t are between 1 and 100 (inclusive).

s and t consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s
t

Output

If it is possible to satisfy s' < t', print Yes; if it is not, print No.

Sample Input 1

yx
axy

Sample Output 1

Yes

We can, for example, rearrange yx into xy and axy into yxa. Then, xy < yxa.

Sample Input 2

ratcode
atlas

Sample Output 2

Yes

We can, for example, rearrange ratcode into acdeort and atlas into tslaa. Then, acdeort < tslaa.

Sample Input 3

cd
abc

Sample Output 3

No

No matter how we rearrange cd and abc, we cannot achieve our objective.

Sample Input 4

w
ww

Sample Output 4

Yes

Sample Input 5

zzz
zzz

Sample Output 5

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <cstdio>
#include <bitset>
#include <queue>
#include <stack>
#include <vector>
#include <list>
#include <set>
#include <map>
#include <utility>
#include <string>
#include <algorithm>
#include <cmath>

using namespace std;
using ll=long long;
using vint=vector<int>;
using pint=pair<int,int>;

const double EPS = 1e-9;

#define rep(i,n) for(int i=0;i<int(n);++i)
#define REP(i,a,b) for(int i=int(a);i<int(b);++i)
#define SHOW(a) cout << #a << " = " << a << endl;

void solve(){
	string a, b;
	cin >> a >> b;
	sort(a.begin(), a.end());
	sort(b.rbegin(), b.rend());
	cout << a << " " << b << endl;
	if(a < b){
		cout << "Yes";
	}else{
		cout << "No";
	}
	cout << endl;
}

int main(){
	solve();
	return 0;
}