Problem:
Score : 400 points

Problem Statement

Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.

You are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.

Constraints

2 ≦ |s| ≦ 10^5

s consists of lowercase letters.

Partial Score

200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.

Input

The input is given from Standard Input in the following format:

s

Output

If there exists no unbalanced substring of s, print -1 -1.

If there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.

Sample Input 1

needed

Sample Output 1

2 5

The string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.

Sample Input 2

atcoder

Sample Output 2

-1 -1

The string atcoder contains no unbalanced substring.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<cstdio>
#include<cstring>

const int N = 1e5 + 10;

char s[N];
int n, x, y;

bool ok(){
    for(int i=2; i<n; i++){
		if(s[i]==s[i-1] || s[i]==s[i-2]){
			x = i-2;
			y = i;
			return 1;
		}
    }
    if(n == 2 && s[0]==s[1]){
		x = 0;
		y = 1;
		return 1;
    }
    return 0;
}

int main(){
	scanf("%s", s);
	n = strlen(s);
	if(ok()){
		printf("%d %d\n", x+1, y+1);
	} else {
		puts("-1 -1");
	}
	return 0;
}