Problem:
Score : 400 points

Problem Statement

Fennec and Snuke are playing a board game.

On the board, there are N cells numbered 1 through N, and N-1 roads, each connecting two cells. Cell a_i is adjacent to Cell b_i through the i-th road. Every cell can be reached from every other cell by repeatedly traveling to an adjacent cell. In terms of graph theory, the graph formed by the cells and the roads is a tree.

Initially, Cell 1 is painted black, and Cell N is painted white. The other cells are not yet colored.
Fennec (who goes first) and Snuke (who goes second) alternately paint an uncolored cell.
More specifically, each player performs the following action in her/his turn:

Fennec: selects an uncolored cell that is adjacent to a black cell, and paints it black.

Snuke: selects an uncolored cell that is adjacent to a white cell, and paints it white.

A player loses when she/he cannot paint a cell. Determine the winner of the game when Fennec and Snuke play optimally.

Constraints

2 \leq N \leq 10^5

1 \leq a_i, b_i \leq N

The given graph is a tree.

Input

Input is given from Standard Input in the following format:

N
a_1 b_1
:
a_{N-1} b_{N-1}

Output

If Fennec wins, print Fennec; if Snuke wins, print Snuke.

Sample Input 1

7
3 6
1 2
3 1
7 4
5 7
1 4

Sample Output 1

Fennec

For example, if Fennec first paints Cell 2 black, she will win regardless of Snuke's moves.

Sample Input 2

4
1 4
4 2
2 3

Sample Output 2

Snuke

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<iostream>
#include<string>
#include<cmath>
#include<cstdio>
#include<cctype>
#include<cstring>
#include<iomanip>
#include<cstdlib>
#include<ctime>
#include<set>
#include<map>
#include<utility>
#include<queue>
#include<vector>
#include<stack>
#include<sstream>
#include<algorithm>
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<ll,ll> pii;
typedef vector<pii> vii;
typedef vector<ll> vi;
typedef queue<ll> qi;
typedef queue<char> qc;
typedef queue<string> qs;
typedef vector<char> vc;
typedef vector<string> vs;
typedef map<char,ll> mpci;
typedef map<ll,ll> mpii;
typedef map<string,ll> mpsi;
typedef set<ll> sei;
typedef set<char> sec;
typedef set<string> ses;
typedef stack<ll> si;
typedef stack<char> sc;
typedef vector<ll> vll;
typedef vector<vi> vvi;
typedef vector<double> vd;
typedef pair<ll,ll> pll;
typedef pair<double,double> pdd;
typedef vector<pll> vpll;
typedef vector<pdd> vdd;
typedef unsigned int uint;
typedef long double ld;
typedef vector<bool> vb;
typedef vector<double> vd;
typedef vector<vi> vvi;
typedef vector<vvi> vvvi;
typedef vector<vii> vvii;
/*=====================================================================*/
#define mp make_pair
#define pb push_back
#define rep(i,n) for(int i=0;i<(int)(n);i++)
#define sz(a) (int)(a.size())
#define len(a) (int)(a.length())
#define all(s) (s).begin(),(s).end()
#define fi first
#define se second
#define be begin
#define en end
#define repd(i,n) for(int i=n-1;i>=0;i--)
#define forn(i,p,n) for(int i=p;i<n;i++)
#define ford(i,p,n) for(int i=n-1;i>=p;i--)
#define foreach(i,c) for(__typeof(c.begin())i=(c.begin());i!=(c).end();++i)
#define zero(a) memset(a,0,sizeof(a))
#define number(a,num) memeset(a,num,sizeof(a))

/*=====================================================================*/

inline void read(int &x)
{
	short negative=1;
    x=0;
    char c=getchar();
    while(c<'0' || c>'9')
    {
		if(c=='-')
			negative=-1;
		c=getchar();
	}
    while(c>='0' && c<='9')
        x=(x<<3)+(x<<1)+(c^48),c=getchar();
    x*=negative;
}
inline void write(long long x) {
  static long long sta[35];
  long long top = 0;
  do {
    sta[top++] = x % 10, x /= 10;
  } while (x);
  while (top) putchar(sta[--top] + 48);
  puts("");
}
/*======================================================================*/
bool prime(int n)
{
	if(n==0||n==1)
	  return false;
	for(int i=2;i*i<=n;i++)
	  if(n%i==0)
	    return false;
	return true;
}
/*======================================================================*/
const int dx[]={-1,0,1,0};
const int dy[]={0,-1,0,1};
vector<int> v[111111];
int dist[2][111111];
int n;
/*======================================================================*/
void dfs(int m,int p,int c)
{
	dist[c][m]=dist[c][p]+1;
  	rep(i,v[m].size())
  	{
  	  if(v[m][i]!=p)
	  {
		dfs(v[m][i],m,c);
	  }	
	}
}
int main()
{
  /*
	ios_base::sync_with_stdio(0);
	cin(tie);
	freopen("input.txt","r",stdin);
	freopen("output.txt","w",stdout);
  */
  /*====================================================================*/
  read(n);
  rep(i,n-1)
  {
  	int a,b;
  	read(a);
  	read(b);
  	v[a].pb(b);
  	v[b].pb(a);
  }
  dist[0][0]=-1;
  dist[1][0]=-1;
  dfs(1,0,0);
  dfs(n,0,1);
  int cnt1=0,cnt2=0;
  for(int i=1;i<=n;i++)
  {
  	if(dist[0][i]<=dist[1][i])
  	  cnt1++;
  	else
  	  cnt2++;
  }
  if(cnt1>cnt2)
    cout<<"Fennec";
  else
    cout<<"Snuke";
  return 0;
}