Problem:
Score : 200 points

Problem Statement

A string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:

S is a palindrome.

Let N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.

The string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.

Determine whether S is a strong palindrome.

Constraints

S consists of lowercase English letters.

The length of S is an odd number between 3 and 99 (inclusive).

Input

Input is given from Standard Input in the following format:

S

Output

If S is a strong palindrome, print Yes;
otherwise, print No.

Sample Input 1

akasaka

Sample Output 1

Yes

S is akasaka.

The string formed by the 1-st through the 3-rd characters is aka.

The string formed by the 5-th through the 7-th characters is aka.
All of these are palindromes, so S is a strong palindrome.

Sample Input 2

level

Sample Output 2

No

Sample Input 3

atcoder

Sample Output 3

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#include <math.h>
#define rep(i,n) for (int i=0;i < (n); ++i)
#define ALL(x) (x).begin(), (x).end()
using namespace std;
using ll = long long;
 
bool pa(string s){
    string L(s.rbegin(),s.rend());
    return s == L;
}
int main() {
    string S;
    cin >> S;
    int n = S.size();
    if(pa(S)&&pa(S.substr(0,(n-1)/2))&&pa(S.substr((n+1)/2))){
        cout << "Yes" << endl;
    } else {
        cout << "No" << endl;
    }
}