Problem:
Score : 300 points

Problem Statement

There is a rectangle in a coordinate plane. The coordinates of the four vertices are (0,0), (W,0), (W,H), and (0,H).
You are given a point (x,y) which is within the rectangle or on its border. We will draw a straight line passing through (x,y) to cut the rectangle into two parts. Find the maximum possible area of the part whose area is not larger than that of the other. Additionally, determine if there are multiple ways to cut the rectangle and achieve that maximum.

Constraints

1 \leq W,H \leq 10^9

0\leq x\leq W

0\leq y\leq H

All values in input are integers.

Input

Input is given from Standard Input in the following format:

W H x y

Output

Print the maximum possible area of the part whose area is not larger than that of the other, followed by 1 if there are multiple ways to cut the rectangle and achieve that maximum, and 0 otherwise.

The area printed will be judged correct when its absolute or relative error is at most 10^{-9}.

Sample Input 1

2 3 1 2

Sample Output 1

3.000000 0

The line x=1 gives the optimal cut, and no other line does.

Sample Input 2

2 2 1 1

Sample Output 2

2.000000 1

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>

using namespace std;

#define REP1(i,n) for(int i=1, i##_len=(n); i<i##_len; ++i)
#define REP(i,n) for(int i=0, i##_len=(n); i<i##_len; ++i)
#define pow(x) x*x
#define ll long long
static const ll MAX = 1000000;
static const ll INFTY = 1e12;

template < typename T > inline string toString( const T &a ) { ostringstream oss; oss << a; return oss.str(); };

struct edge {
    ll to, cost;
};

using Graph = vector<vector<int>>;
using _Graph = vector<vector<edge>>;


const int dx[4] = {1, 0, -1, 0};
const int dy[4] = {0, 1, 0, -1};

// 深さ優先探索
vector<bool> seen;
vector<int> colors;

int H, W, N;
int sx, sy, gx, gy; 
vector<vector<char>> field;
vector<vector<int>> dist;
//vector<pair<int, int>> gx, gy;
deque<pair<int, int>> que;

typedef vector<vector<int> > Matrix;

const int INF = 100000000;


int main() {

   ll W, H, x, y;
   cin >> W >> H >> x >> y;

   double n1 = (H-y)*W;
   double n4 = (W)*(y);
   double n2 = (H)*(W-x);
   double n3 = (x)*H;

   double min1 = min(n1, n4);
   double min2 = min(n2, n3);

   int count = 0;

   if(min1 == min2)count++;

   printf("%.6f %d", max(min1, min2), count);

//    cout << max(min1, min2) << " " << count << endl;


    // cout << n1 << n2 << n3 << n4;
}
/*
                   _ooOoo_
                  o8888888o
                  88" . "88
                  (| -_- |)
                  O\  =  /O
               ____/`---'\____
             .'  \\|     |//  `.
            /  \\|||  :  |||//  \
           /  _||||| -:- |||||-  \
           |   | \\\  -  /// |   |
           | \_|  ''\---/''  |   |
           \  .-\__  `-`  ___/-. /
         ___`. .'  /--.--\  `. . __
      ."" '<  `.___\_<|>_/___.'  >'"".
     | | :  `- \`.;`\ _ /`;.`/ - ` : | |
     \  \ `-.   \_ __\ /__ _/   .-` /  /
======`-.____`-.___\_____/___.-`____.-'======
                   `=---='
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
         pass System Test!
*/