Problem:
Score : 400 points

Problem Statement

Takahashi will play a game using a piece on an array of squares numbered 1, 2, \cdots, N. Square i has an integer C_i written on it. Also, he is given a permutation of 1, 2, \cdots, N: P_1, P_2, \cdots, P_N.

Now, he will choose one square and place the piece on that square. Then, he will make the following move some number of times between 1 and K (inclusive):

In one move, if the piece is now on Square i (1 \leq i \leq N), move it to Square P_i. Here, his score increases by C_{P_i}.

Help him by finding the maximum possible score at the end of the game. (The score is 0 at the beginning of the game.)

Constraints

2 \leq N \leq 5000

1 \leq K \leq 10^9

1 \leq P_i \leq N

P_i \neq i

P_1, P_2, \cdots, P_N are all different.

-10^9 \leq C_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
P_1 P_2 \cdots P_N
C_1 C_2 \cdots C_N

Output

Print the maximum possible score at the end of the game.

Sample Input 1

5 2
2 4 5 1 3
3 4 -10 -8 8

Sample Output 1

8

When we start at some square of our choice and make at most two moves, we have the following options:

If we start at Square 1, making one move sends the piece to Square 2, after which the score is 4. Making another move sends the piece to Square 4, after which the score is 4 + (-8) = -4.

If we start at Square 2, making one move sends the piece to Square 4, after which the score is -8. Making another move sends the piece to Square 1, after which the score is -8 + 3 = -5.

If we start at Square 3, making one move sends the piece to Square 5, after which the score is 8. Making another move sends the piece to Square 3, after which the score is 8 + (-10) = -2.

If we start at Square 4, making one move sends the piece to Square 1, after which the score is 3. Making another move sends the piece to Square 2, after which the score is 3 + 4 = 7.

If we start at Square 5, making one move sends the piece to Square 3, after which the score is -10. Making another move sends the piece to Square 5, after which the score is -10 + 8 = -2.

The maximum score achieved is 8.

Sample Input 2

2 3
2 1
10 -7

Sample Output 2

13

Sample Input 3

3 3
3 1 2
-1000 -2000 -3000

Sample Output 3

-1000

We have to make at least one move.

Sample Input 4

10 58
9 1 6 7 8 4 3 2 10 5
695279662 988782657 -119067776 382975538 -151885171 -177220596 -169777795 37619092 389386780 980092719

Sample Output 4

29507023469

The absolute value of the answer may be enormous.

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define rep2(i, s, n) for (int i = (s); i < (int)(n); i++)
using ll = long long;
const long long INF = 1LL << 60;
const int MOD = 1e9 + 7;

template <class T>
inline bool chmax(T &a, T b)
{
    if (a < b)
    {
        a = b;
        return 1;
    }
    return 0;
}
template <class T>
inline bool chmin(T &a, T b)
{
    if (a > b)
    {
        a = b;
        return 1;
    }
    return 0;
}

/* ACL */

#ifndef ATCODER_INTERNAL_SCC_HPP
#define ATCODER_INTERNAL_SCC_HPP 1

#include <algorithm>
#include <utility>
#include <vector>
#include <cassert>


namespace atcoder
{
    namespace internal
    {

        template <class E>
        struct csr
        {
            std::vector<int> start;
            std::vector<E> elist;
            csr(int n, const std::vector<std::pair<int, E>> &edges)
                : start(n + 1), elist(edges.size())
            {
                for (auto e : edges)
                {
                    start[e.first + 1]++;
                }
                for (int i = 1; i <= n; i++)
                {
                    start[i] += start[i - 1];
                }
                auto counter = start;
                for (auto e : edges)
                {
                    elist[counter[e.first]++] = e.second;
                }
            }
        };

        // Reference:
        // R. Tarjan,
        // Depth-First Search and Linear Graph Algorithms
        struct scc_graph
        {
        public:
            scc_graph(int n) : _n(n) {}

            int num_vertices() { return _n; }

            void add_edge(int from, int to) { edges.push_back({from, {to}}); }

            // @return pair of (# of scc, scc id)
            std::pair<int, std::vector<int>> scc_ids()
            {
                auto g = csr<edge>(_n, edges);
                int now_ord = 0, group_num = 0;
                std::vector<int> visited, low(_n), ord(_n, -1), ids(_n);
                visited.reserve(_n);
                auto dfs = [&](auto self, int v) -> void {
                    low[v] = ord[v] = now_ord++;
                    visited.push_back(v);
                    for (int i = g.start[v]; i < g.start[v + 1]; i++)
                    {
                        auto to = g.elist[i].to;
                        if (ord[to] == -1)
                        {
                            self(self, to);
                            low[v] = std::min(low[v], low[to]);
                        }
                        else
                        {
                            low[v] = std::min(low[v], ord[to]);
                        }
                    }
                    if (low[v] == ord[v])
                    {
                        while (true)
                        {
                            int u = visited.back();
                            visited.pop_back();
                            ord[u] = _n;
                            ids[u] = group_num;
                            if (u == v)
                                break;
                        }
                        group_num++;
                    }
                };
                for (int i = 0; i < _n; i++)
                {
                    if (ord[i] == -1)
                        dfs(dfs, i);
                }
                for (auto &x : ids)
                {
                    x = group_num - 1 - x;
                }
                return {group_num, ids};
            }

            std::vector<std::vector<int>> scc()
            {
                auto ids = scc_ids();
                int group_num = ids.first;
                std::vector<int> counts(group_num);
                for (auto x : ids.second)
                    counts[x]++;
                std::vector<std::vector<int>> groups(ids.first);
                for (int i = 0; i < group_num; i++)
                {
                    groups[i].reserve(counts[i]);
                }
                for (int i = 0; i < _n; i++)
                {
                    groups[ids.second[i]].push_back(i);
                }
                return groups;
            }

        private:
            int _n;
            struct edge
            {
                int to;
            };
            std::vector<std::pair<int, edge>> edges;
        };

    } // namespace internal


    struct scc_graph
    {
    public:
        scc_graph() : internal(0) {}
        scc_graph(int n) : internal(n) {}

        void add_edge(int from, int to)
        {
            int n = internal.num_vertices();
            assert(0 <= from && from < n);
            assert(0 <= to && to < n);
            internal.add_edge(from, to);
        }

        std::vector<std::vector<int>> scc() { return internal.scc(); }

    private:
        internal::scc_graph internal;
    };
}
using namespace atcoder;

#endif // ATCODER_SCC_HPP

//using namespace atcoder;

ll SUM(int index,int num,vector<ll> summation){
    ll rtn = 0;
    if(index + num >= summation.size()){
        rtn += SUM(0,index + num - summation.size()+1,summation);
        num = summation.size()-1 - index;
    }
    return rtn + summation[index+num] - summation[index];
}

int main()
{
    ll N,K;
    cin >> N >> K;
    
    scc_graph g(N);
    rep(i,N){
        int p;
        cin >> p;
        g.add_edge(i,p-1);
    }
    auto roop = g.scc();

    vector<ll> C(N);
    rep(i,N){
        cin >> C.at(i);
    }

    rep(i,roop.size()){
        rep(j,roop.at(i).size()){
            roop.at(i).at(j) = C.at(roop.at(i).at(j));
        }
    }

    ll maxScore = -INF;
    for(auto r : roop){
        ll score = 0;
        vector<ll> summer(r.size()+1,0);
        summer[0] = 0;
        rep(i,r.size()){
            summer[i+1] = summer[i] + r[i];
        }
        
        if(summer[summer.size()-1]>0){
            score += summer[summer.size()-1] * (K/r.size());
            K = K % r.size();
        }

        if(K==0){
            chmax(maxScore,score);
            continue;
        }

        ll miniScore = (K==0)?0:-INF;
        ll cnt = (r.size() > K) ? K : r.size();
        rep(i,r.size()){
            rep(j,(int)cnt+1){
                if(j == 0){
                    continue;
                }
                chmax(miniScore,SUM(i,j,summer));
            }
        }
        chmax(maxScore,miniScore+score);
    }
    cout << maxScore << endl;
    return 0;
}