Problem:
Score : 400 points

Problem Statement

Given is an integer S.
Find a combination of six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfies all of the following conditions:

0 \leq X_1,Y_1,X_2,Y_2,X_3,Y_3 \leq 10^9

The area of the triangle in a two-dimensional plane whose vertices are (X_1,Y_1),(X_2,Y_2), and (X_3,Y_3) is S/2.

We can prove that there always exist six integers that satisfy the conditions under the constraints of this problem.

Constraints

1 \leq S \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

S

Output

Print six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfy the conditions, in this order, with spaces in between.
If multiple solutions exist, any of them will be accepted.

Sample Input 1

3

Sample Output 1

1 0 2 2 0 1

The area of the triangle in a two-dimensional plane whose vertices are (1,0),(2,2), and (0,1) is 3/2.
Printing 3 0 3 1 0 1 or 1 0 0 1 2 2 will also be accepted.

Sample Input 2

100

Sample Output 2

0 0 10 0 0 10

Sample Input 3

311114770564041497

Sample Output 3

314159265 358979323 846264338 327950288 419716939 937510582

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#define DEBUG
// #define FASTIO

#include <cstring>
#include <cassert>
#include <utility>
#include <iostream>
#include <cstdio>
#include <iomanip>
#include <bitset>
#include <chrono>
#include <cstdlib>
#include <functional>
#include <tuple>
#include <climits>
#include <limits>
#include <deque>
#include <list>
#include <array>
#include <stack>
#include <queue>
#include <random>
#include <complex>
#include <string>
#include <vector>
#include <set>
#include <map>
#include <unordered_map>
#include <unordered_set>
#include <algorithm>

#define F first
#define S second 
#define pb push_back
#define endl "\n"

#ifdef FASTIO

#define pr(x) printf("%d", x)
#define ps    printf(" ")
#define endc  printf("\n")
#define pl(x) printf("%lld", x)
#define pf(x) printf("%lf", x)
#define sc(x) scanf("%d", &x)
#define sl(x) scanf("%lld", &x)
#define sf(x) scanf("%lf", &x)
#define IOS 

#endif

#ifndef FASTIO
    #define IOS { ios :: sync_with_stdio(false); cin.tie(0); }
#endif

#ifdef DEBUG
    #define dbg(s) {s;}
#endif

#ifndef DEBUG
    #define dbg(s)
#endif

using namespace std;

mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
int grand(int x) { // from [0, n-1]
    return uniform_int_distribution<int>(0, x - 1)(rng);
}

#define int ll
#define i32 int32_t

#define all(v) (v).begin(),(v).end()

typedef long long ll;
typedef long double ld;
typedef pair< int, int > pii;
typedef pair< ll, ll > pll;

ll gcd(ll x, ll y) {
    if (x < y) return gcd(y, x);
    if (y == 0) return x;
    return gcd(y, x % y);
} 

const ll mod = 1e9 + 7;

ll modexp(ll x, ll ex) {
    ll ans = 1ll;
    while (ex > 0) {
        if (ex & 1ll) ans = (ans * x) % mod;
        ex >>= 1ll;
        x = (x * x) % mod;
    }
    return ans;
}

const int maxn = 1e6 + 7;

const ll inf = 1e9;



i32 main() {
    //freopen("<file>.in", "r", stdin);
    //freopen("<file>.out", "w", stdout);

    IOS;
    
    int S; cin >> S;
    cout << 0 << " " << 0 << endl;
    int p = inf - (S % inf);
    cout << inf << " " << p << endl;
    cout << 1 << " " << (S + p) / inf << endl;
}