Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;

int main() {
	long double N;
	cin >> N; 
	N = 4.0 / N;
	for (long double i = 1; i <= 3500; i += 1) {
		for (long double j = 1; j <= 3500; j += 1) {
			long double w = N - 1.0/i - 1.0/j;
			if (w == 0) continue;
			w = 1.0 / w;
			if (w < 0.0) continue;
			if (floor(w) == w && w <= 3500) {
				cout << fixed << setprecision(0) << i << " " << j << " " << w << " \n";
				return 0;
			}
		}
	}
}