Problem:
Score : 200 points

Problem Statement

Raccoon is fighting with a monster.

The health of the monster is H.

Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i.
There is no other way to decrease the monster's health.

Raccoon wins when the monster's health becomes 0 or below.

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Constraints

1 \leq H \leq 10^9

1 \leq N \leq 10^5

1 \leq A_i \leq 10^4

All values in input are integers.

Input

Input is given from Standard Input in the following format:

H N
A_1 A_2 ... A_N

Output

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Sample Input 1

10 3
4 5 6

Sample Output 1

Yes

The monster's health will become 0 or below after, for example, using the second and third moves.

Sample Input 2

20 3
4 5 6

Sample Output 2

No

Sample Input 3

210 5
31 41 59 26 53

Sample Output 3

Yes

Sample Input 4

211 5
31 41 59 26 53

Sample Output 4

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)


#include<bits/stdc++.h>
#define ll          long long
#define pb          push_back
#define c(P)        cout<<P<<"\n"
#define pii         pair<ll,ll>
#define mi          map<ll,ll>
#define mii         map<pii,ll>
#define F           first
#define S           second
#define mem(a,val)  memset(a,val,sizeof(a))
#define fr(i,x,n)   for(ll i=x;i<n;i++)
#define frr(i,x,n)  for(ll i=n-1;i>=x;i--)
using namespace std;


const ll N   =  500005;
const ll mod = 1e9 + 7;



void solve(){

  ll x=0,y=0,c=0,ans=0;
  ll n,m,k;
  cin>>k>>n;
 ll a[n];
 for (int i = 0; i < n; ++i)
 {
 	cin>>a[i];
 c+=a[i];
 }
 if(c>=k)
{
	c("Yes");
}
else c("No");
  
}

signed main(){
     
  ios_base::sync_with_stdio(false);   
  cin.tie(NULL);
  ll T=1;
  //cin>>T;
  while(T--){
  solve();
  }
  return 0;
}