Problem:
Score : 400 points

Problem Statement

Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.

You are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.

Constraints

2 ≦ |s| ≦ 10^5

s consists of lowercase letters.

Partial Score

200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.

Input

The input is given from Standard Input in the following format:

s

Output

If there exists no unbalanced substring of s, print -1 -1.

If there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.

Sample Input 1

needed

Sample Output 1

2 5

The string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.

Sample Input 2

atcoder

Sample Output 2

-1 -1

The string atcoder contains no unbalanced substring.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#define rep(i,n) for(int i=0;i<n;i++)
typedef unsigned long ul;
typedef long long ll;
//typedef pair<int, int> mpair;
using namespace std;

int main() {
	cin.tie(0);
   	ios::sync_with_stdio(false);
   	string s;cin >> s;
    rep(i, s.length()-2){
        if(s[i] == s[i+2]){
            printf("%d %d",i+1,i+3);
            return 0;
        }else if(s[i] == s[i+1]){
            printf("%d %d",i+1,i+2);
            return 0;
        }
    }
    if(s.length()==2&&s[0]==s[1]){
        printf("1 2");
        return 0;
    }
	cout << "-1 -1" << endl;
	return 0;
}