Problem:
Score : 300 points

Problem Statement

You are given N positive integers a_1, a_2, ..., a_N.

For a non-negative integer m, let f(m) = (m\ mod\ a_1) + (m\ mod\ a_2) + ... + (m\ mod\ a_N).

Here, X\ mod\ Y denotes the remainder of the division of X by Y.

Find the maximum value of f.

Constraints

All values in input are integers.

2 \leq N \leq 3000

2 \leq a_i \leq 10^5

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 ... a_N

Output

Print the maximum value of f.

Sample Input 1

3
3 4 6

Sample Output 1

10

f(11) = (11\ mod\ 3) + (11\ mod\ 4) + (11\ mod\ 6) = 10 is the maximum value of f.

Sample Input 2

5
7 46 11 20 11

Sample Output 2

90

Sample Input 3

7
994 518 941 851 647 2 581

Sample Output 3

4527

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)


// Problem : C - Modulo Summation
// Contest : AtCoder - AtCoder Beginner Contest 103
// URL : https://atcoder.jp/contests/abc103/tasks/abc103_c?lang=en
// Memory Limit : 1024 MB
// Time Limit : 2000 ms
#include<bits/stdc++.h>
using namespace std;
#define rep(i,n) for(int i=1;i<=(int)n;i++)
#define REP(i,n) for(int i=0;i<(int)n;i++)
#define ll long long
int main(){
	int n;
	cin>>n;
	vector<int>v(n);
	REP(i,n){
		cin>>v[i];
	}
	ll sum=0;
	REP(i,n){
		sum+=v[i];
	}
	cout<<(sum-n)<<endl;
	return 0;
}