Problem:
Score : 400 points

Problem Statement

You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

In the i-th operation, you replace every element whose value is B_{i} with C_{i}.

For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

All values in input are integers.

1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}

B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:

N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}

Output

Print Q integers S_{i} to Standard Output in the following format:

S_{1}
S_{2}
\vdots
S_{Q}

Note that S_{i} may not fit into a 32-bit integer.

Sample Input 1

4
1 2 3 4
3
1 2
3 4
2 4

Sample Output 1

11
12
16

Initially, the sequence A is 1,2,3,4.

After each operation, it becomes the following:

2, 2, 3, 4

2, 2, 4, 4

4, 4, 4, 4

Sample Input 2

4
1 1 1 1
3
1 2
2 1
3 5

Sample Output 2

8
4
4

Note that the sequence A may not contain an element whose value is B_{i}.

Sample Input 3

2
1 2
3
1 100
2 100
100 1000

Sample Output 3

102
200
2000

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include<bits/stdc++.h>
// #include <boost/lexical_cast.hpp>
using namespace std;

#define ll long long int
#define vll vector<ll>
#define vllv vector<vector<ll>> 
#define vpii vector<pair<ll,ll>>
#define sz size()
#define pb push_back
#define ff first
#define ss second
#define all(v) v.begin(),v.end()
#define allr(v) v.rbegin(),v.rend()
#define fast ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0)

ll ceil1(ll n,ll m){if(n%m==0){return n/m;}return n/m +1;}
vll factor(ll n){
    vll ans;
	if(n==2)ans.pb(2);
	else
    {for(ll i=2;i*i<=n;i++){if(n%i==0 && n%i!=i){ans.pb(i);if(n/i!=i)ans.pb(n/i);}}ans.pb(n);}
    return ans;
}
ll fact(ll n){ll res = 1;for (ll i = 2; i <= n; i++)res = res * i; 
    return res; } 
  
ll nCr(ll n, ll r){ return fact(n) / (fact(r) * fact(n - r)); } 
  
void dfs(vllv &v,ll k,vll &par,vll &dis,ll p)
{
    par[k]=p;
    dis[k]=dis[p]+1;
    for(ll i=0;i<v[k].sz;i++){
        if(v[k][i]!=p){
            dfs(v,v[k][i],par,dis,k);
        }
    }
}
bool sortbysec(const pair<string,int> &a,const pair<string,int> &b){return (a.second<b.second);} 

ll pow2(ll n,ll k){ll ans=1;
    while(k>0){
        if(k%2==1)ans=ans*n;n=n*n;k/=2;
    }return ans;}
bool prime(int n){
    int i,j;
    for(i=2;i<=sqrt(n);i++){
        if(n%i==0){
            return false;
        }
    }
    return true;
}
bool bserch(vector<string> a, string s){
	ll l=0,r=a.sz-1,mid;
	while(l<=r){
		mid=(l+r)/2;
		if(a[mid]==s)return true;
		if(a[mid]<s){
			l=mid+1;
		}else{
			r=mid-1;
		}
	}
	return false;
}

bool sortcol(const vector<int>& v1, 
               const vector<int>& v2){ 
 return v1[0] < v2[0]; } 

 ll degit(ll n)
 {
 	ll t=0;
 	while(n>0)
 	{
 		t++;
 		n/=10; 	}
 		return t;
 }
void ff() {
	cout << "FastestFinger" << endl;
}
 
void aa() {
	cout << "Ashishgup" << endl;
}
 
void solve()
{
	ll n,sum=0;
	cin>>n;
	vll a(n+1),cnt(100001);
	for(ll i=1;i<=n;i++)
		cin>>a[i],sum+=a[i],cnt[a[i]]++;
	ll q;
	cin>>q;
	for(ll i=0;i<q;i++)
	{
		ll x,y;
		cin>>x>>y;
		sum-=(cnt[x]*x);
		sum+=cnt[x]*y;
		cnt[y]+=cnt[x];
		cout<<sum<<endl;
	}
}
int main()
{
	fast;
    ll q;
    q=1;
    // cin>>q;
    while(q--)
    {
        solve();
    }
    return 0;
}