Problem:
Score : 300 points

Problem Statement

Given are an integer X and an integer sequence of length N: p_1, \ldots, p_N.

Among the integers not contained in the sequence p_1, \ldots, p_N (not necessarily positive), find the integer nearest to X, that is, find the integer whose absolute difference with X is the minimum. If there are multiple such integers, report the smallest such integer.

Constraints

1 \leq X \leq 100

0 \leq N \leq 100

1 \leq p_i \leq 100

p_1, \ldots, p_N are all distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X N
p_1 ... p_N

Output

Print the answer.

Sample Input 1

6 5
4 7 10 6 5

Sample Output 1

8

Among the integers not contained in the sequence 4, 7, 10, 6, 5, the one nearest to 6 is 8.

Sample Input 2

10 5
4 7 10 6 5

Sample Output 2

9

Among the integers not contained in the sequence 4, 7, 10, 6, 5, the ones nearest to 10 are 9 and 11. We should print the smaller one, 9.

Sample Input 3

100 0

Sample Output 3

100

When N = 0, the second line in the input will be empty. Also, as seen here, X itself can be the answer.

Solution in C++ (Clang 10.0.0) (judge verdict: Runtime Error)

#include<iostream>
#include<stdio.h>
using namespace std;
using ll=long long;
#include<algorithm>
#include<set>
#include<vector>
#define rep(i,n) for(int i=0;i<(n);i++)
using P=pair<int,int>;


int main(){
int n,x;
cin>>n>>x;
int a;
vector<int>p(n);
rep(i,n){
  cin>>a;
  p[a]=1;
}
P ans(100000,-1);
rep(i,n){
  if(p[i])continue;
  int dif=abs(x-i);
  ans=min(ans,P(dif,i));
}
cout<<ans.second<<endl;
return 0;
}