Problem:
Score : 100 points

Problem Statement

In programming, hexadecimal notation is often used.

In hexadecimal notation, besides the ten digits 0, 1, ..., 9, the six letters A, B, C, D, E and F are used to represent the values 10, 11, 12, 13, 14 and 15, respectively.

In this problem, you are given two letters X and Y. Each X and Y is A, B, C, D, E or F.

When X and Y are seen as hexadecimal numbers, which is larger?

Constraints

Each X and Y is A, B, C, D, E or F.

Input

Input is given from Standard Input in the following format:

X Y

Output

If X is smaller, print <; if Y is smaller, print >; if they are equal, print =.

Sample Input 1

A B

Sample Output 1

<

10 < 11.

Sample Input 2

E C

Sample Output 2

>

14 > 12.

Sample Input 3

F F

Sample Output 3

=

15 = 15.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#include <stdio.h>
#include <math.h>
using namespace std;

#define INF 1.1e9
#define LINF 1.1e18
#define FOR(i,a,b) for (int i = (a); i < (b); ++i)
#define REP(i,n) FOR(i,0,n)
#define ALL(v) (v).begin(), (v).end()
#define pb push_back
#define pf push_front
#define fi first
#define se second
#define BIT(x,n) bitset<n>(x)

typedef long long ll;
typedef pair<ll,ll> P;
typedef pair<int,P> PP;

struct edge {
	int to,cost;
	edge(int t,ll c):to(t),cost(c) {}
};

int dx[]={1,-1,0,0},dy[]={0,0,1,-1};
int ddx[]={1,1,1,0,-1,-1,-1,0},ddy[]={1,0,-1,-1,-1,0,1,1};

//-----------------------------------------------------------------------------

char x,y;

int f(char x) {
	switch (x) {
		case 'A': return 10;
		case 'B': return 11;
		case 'C': return 12;
		case 'D': return 13;
		case 'E': return 14;
		case 'F': return 15;
	}
}

int main() {
	cin.tie(0);
	ios::sync_with_stdio(false);

	cin>>x>>y;
	int xx=f(x),yy=f(y);
	if(xx<yy) cout<<'<'<<endl;
	else if(xx>yy) cout<<'>'<<endl;
	else cout<<'='<<endl;

	return 0;
}