Problem:
Score : 200 points

Problem Statement

A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.

How many times will the ball make a bounce where the coordinate is at most X?

Constraints

1 \leq N \leq 100

1 \leq L_i \leq 100

1 \leq X \leq 10000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N X
L_1 L_2 ... L_{N-1} L_N

Output

Print the number of times the ball will make a bounce where the coordinate is at most X.

Sample Input 1

3 6
3 4 5

Sample Output 1

2

The ball will make a bounce at the coordinates 0, 3, 7 and 12, among which two are less than or equal to 6.

Sample Input 2

4 9
3 3 3 3

Sample Output 2

4

The ball will make a bounce at the coordinates 0, 3, 6, 9 and 12, among which four are less than or equal to 9.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;

using ll = long long;
using ull = unsigned long long;
using st = string;
using ch = char;
using db = double;
using bl = bool;
using vll = vector<long long>;
using vdb = vector<db>;
using vvll = vector<vll>;
using vst = vector<st>;
using vch = vector<char>;
using pll = pair<ll, ll>;
using vpll = vector<pll>;
using vvpll = vector<vpll>;
#define rep(i, m, n) for (ll i = (ll)(m); i < (ll)(n); i++)
#define vrep(i, vec) for(auto& i : vec)
#define vin(vec) for(auto& i : vec) cin >> i
#define all(v) v.begin(), v.end()
template<class T> inline bool chmin(T& a, T b){if(a > b){a = b;return true;} return false;}
template<class T> inline bool chmax(T& a, T b){if(a < b){a = b;return true;} return false;}
const ll mod = 1000000007;
const ll inf = 1LL << 60;

int main(){
	ll n, x;
	cin >> n >> x;
	vll l(n);
	vin(l);
	ll ans = 1;
	while(ans <= n){
		x -= l.at(ans - 1);
		if(x < 0) break;
		ans++;
	}
	cout << ans << endl;
}