Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <string>
#include <vector>
#include <algorithm>
#include <cmath>
#include <set>
#include <map>
#include <queue>
#include<limits.h>
#include<iomanip>
#define rep(i, n) for(int i = 0; i < n; i++)
#define REP(i, m, n) for(int i = m; i < n; i++)
#define ALL(v) v.begin(),v.end()
#define RALL(v) v.rbegin(),v.rend()
#define check(v) rep(i,v.size()) cout << v[i] << " ";\
cout << endl
#define INF 1e8
typedef long long ll;
using namespace std;
//オーバーフローに気をつけろよおおおおおお
//確認忘れるなよおおおおおお

int main() {
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    int n, a, b, c, d; cin >> n >> a >> b >> c >> d;
    string s; cin >> s;

    bool flag1 = true;
    bool flag2 = true;

    if(c<d) {
        for(int i = b+1; i <= d; i++) {
            if(s[i]=='#' && s[i-1]=='#') flag1 = false;
        }
        for(int i = a+1; i <= c; i++) {
            if(s[i]=='#' && s[i-1]=='#') flag2 = false;
        }
        if(flag1 && flag2) cout << "Yes" << endl;
        else cout << "No" << endl;
    }else {
        bool flag3 = false;
        for(int i = b; i <= d; i++) {
            if(s[i]=='#' && s[i-1]=='#' && i > b) flag2 = false;
            if(s[i]=='.' && s[i-1]=='.' && s[i+1]=='.') flag3 = true;
        }
        for(int i = a+1; i <= c; i++) {
            if(s[i]=='#' && s[i-1]=='#') flag1 = false;
        }
        if(flag1 && flag2 && flag3) cout << "Yes" << endl;
        else cout << "No" << endl;
    }

    return 0;
}