Problem:
Score : 200 points

Problem Statement

There are N gems. The value of the i-th gem is V_i.

You will choose some of these gems, possibly all or none, and get them.

However, you need to pay a cost of C_i to get the i-th gem.

Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid.

Find the maximum possible value of X-Y.

Constraints

All values in input are integers.

1 \leq N \leq 20

1 \leq C_i, V_i \leq 50

Input

Input is given from Standard Input in the following format:

N
V_1 V_2 ... V_N
C_1 C_2 ... C_N

Output

Print the maximum possible value of X-Y.

Sample Input 1

3
10 2 5
6 3 4

Sample Output 1

5

If we choose the first and third gems, X = 10 + 5 = 15 and Y = 6 + 4 = 10.
We have X-Y = 5 here, which is the maximum possible value.

Sample Input 2

4
13 21 6 19
11 30 6 15

Sample Output 2

6

Sample Input 3

1
1
50

Sample Output 3

0

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#define _USE_MATH_DEFINES
#include<bits/stdc++.h>
using namespace std;

typedef long long ll;
const int INF = 1e9;
const ll MOD = 1e9 + 7;
const ll MOD2 = 998244353;
const ll LINF = 1e18;
#define y0 y3487465
#define y1 y8687969
#define j0 j1347829
#define j1 j234892
#define next asdnext
#define prev asdprev
#define MP make_pair
#define MT make_tuple
#define F first
#define S second
#define PB push_back
#define dump(x)  cout << #x << " = " << (x) << endl;	//debug
#define SZ(x) ((ll)(x).size())
#define FOR(i, a, b) for (ll i = (a); i <= (b); i++)
#define RFOR(i, a, b) for (ll i = (a); i >= (b); i--)
#define ps(s) cout << #s << endl;
#define pv(v) cout << (v) << endl;
#define pvd(v) cout << setprecision(16) << (v) << endl;
#define ALL(a)  (a).begin(),(a).end()
#define RANGE(a, start_index, num)  (a).begin()+(start_index),(a).begin()+(num)

int main() {
	int n;
	cin >> n;
	int res = 0;
	vector<int> v(n+1);
	vector<int>c(n+1);
	FOR(i, 1, n) {
		cin >> v[i];
	}
	FOR(i, 1, n) {
		cin >> c[i];
	}
	FOR(i, 1, n) {
		if (v[i] > c[i]) {
			res += (v[i] - c[i]);
		}
	}
	pv(res)
	return 0;
}