Problem:
Score : 200 points

Problem Statement

Tak performed the following action N times: rolling two dice.
The result of the i-th roll is D_{i,1} and D_{i,2}.

Check if doublets occurred at least three times in a row.
Specifically, check if there exists at lease one i such that D_{i,1}=D_{i,2}, D_{i+1,1}=D_{i+1,2} and D_{i+2,1}=D_{i+2,2} hold.

Constraints

3 \leq N \leq 100

1\leq D_{i,j} \leq 6

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
D_{1,1} D_{1,2}
\vdots
D_{N,1} D_{N,2}

Output

Print Yes if doublets occurred at least three times in a row. Print No otherwise.

Sample Input 1

5
1 2
6 6
4 4
3 3
3 2

Sample Output 1

Yes

From the second roll to the fourth roll, three doublets occurred in a row.

Sample Input 2

5
1 1
2 2
3 4
5 5
6 6

Sample Output 2

No

Sample Input 3

6
1 1
2 2
3 3
4 4
5 5
6 6

Sample Output 3

Yes

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;

#define ll long long int

static const auto _____ = []() {
    // fast IO code : this I understand
    ios::sync_with_stdio(false);
    cout.tie(NULL);
    cin.tie(0);
    return 0;
}();

int main(){
	int n;
	cin>>n;
	int a[n][2];
	int cnt = 0;
	int flag = 0;
	for(int i=0;i<n;i++){
		cin>>a[i][0]>>a[i][1];
		if(a[i][0]==a[i][1] ){
			cnt++;
			if(cnt == 3)
				flag = 1;
		}
		else 
			cnt = 0;
	}
	if(flag)
		cout<<"Yes"<<endl;
	else
		cout<<"No"<<endl;
	return 0;
}