Problem:
Score : 100 points

Problem Statement

You are given positive integers A and B.

If A is a divisor of B, print A + B; otherwise, print B - A.

Constraints

All values in input are integers.

1 \leq A \leq B \leq 20

Input

Input is given from Standard Input in the following format:

A B

Output

If A is a divisor of B, print A + B; otherwise, print B - A.

Sample Input 1

4 12

Sample Output 1

16

As 4 is a divisor of 12, 4 + 12 = 16 should be printed.

Sample Input 2

8 20

Sample Output 2

12

Sample Input 3

1 1

Sample Output 3

2

1 is a divisor of 1.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include "bits/stdc++.h"
using namespace std;
typedef long long ll;
typedef pair<ll,ll> P;
typedef pair<P,ll> Pll;
typedef pair<P,P> PP;
#define rep(i,a,n) for(int i = a;i < n;i++)
#define LINF (ll)1e17
#define INF 1e9
#define MOD 1e9+7
#define sMOD 1e5
#define fs first
#define sc second


signed main(){
	
	ll a,b,c,d,e,f;
	string s,t;
	ll A[10000],B[10000],C[10000];
	
	
	cin >> a >> b;
	
	if(b % a == 0) cout <<  a+b << endl;
	else cout << b-a << endl;
	
	return 0;

}