Problem:
Score : 400 points

Problem Statement

Let {\rm comb}(n,r) be the number of ways to choose r objects from among n objects, disregarding order.
From n non-negative integers a_1, a_2, ..., a_n, select two numbers a_i > a_j so that {\rm comb}(a_i,a_j) is maximized.
If there are multiple pairs that maximize the value, any of them is accepted.

Constraints

2 \leq n \leq 10^5

0 \leq a_i \leq 10^9

a_1,a_2,...,a_n are pairwise distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print a_i and a_j that you selected, with a space in between.

Sample Input 1

5
6 9 4 2 11

Sample Output 1

11 6

\rm{comb}(a_i,a_j) for each possible selection is as follows:

\rm{comb}(4,2)=6

\rm{comb}(6,2)=15

\rm{comb}(6,4)=15

\rm{comb}(9,2)=36

\rm{comb}(9,4)=126

\rm{comb}(9,6)=84

\rm{comb}(11,2)=55

\rm{comb}(11,4)=330

\rm{comb}(11,6)=462

\rm{comb}(11,9)=55

Thus, we should print 11 and 6.

Sample Input 2

2
100 0

Sample Output 2

100 0

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;

#ifdef LOCAL
#define debug(var) cerr << (#var) << " = " << (var) << endl;
#else
#define debug(var)
#endif

void init() {
    ios_base::sync_with_stdio(0);
    cin.tie(0); cout.tie(0);
}

const int N = 1e5+23;
int a[N];

void solve() {
    int n; scanf("%d", &n);
    for (int i = 0; i < n; ++i) {
        scanf("%d", a+i);
    }
    sort(a, a+n);
    int m = a[n-1];
    printf("%d ", m);
    auto p = equal_range(a, a+n-1, m/2);
    --p.first;
    if (p.second == a+n-1 || abs(*(p.first)-m/2) <= abs(*(p.second)-m/2)) {
        printf("%d", *(p.first));
    } else {
        printf("%d", *(p.second));
    }
}

int main() {
    init();
    int t = 1; //scanf("%d", &t);
    while (t--) {
        solve();
    }
    return 0;
}