Problem:
Score : 200 points

Problem Statement

Snuke loves working out. He is now exercising N times.

Before he starts exercising, his power is 1. After he exercises for the i-th time, his power gets multiplied by i.

Find Snuke's power after he exercises N times. Since the answer can be extremely large, print the answer modulo 10^{9}+7.

Constraints

1 ≤ N ≤ 10^{5}

Input

The input is given from Standard Input in the following format:

N

Output

Print the answer modulo 10^{9}+7.

Sample Input 1

3

Sample Output 1

6

After Snuke exercises for the first time, his power gets multiplied by 1 and becomes 1.

After Snuke exercises for the second time, his power gets multiplied by 2 and becomes 2.

After Snuke exercises for the third time, his power gets multiplied by 3 and becomes 6.

Sample Input 2

10

Sample Output 2

3628800

Sample Input 3

100000

Sample Output 3

457992974

Print the answer modulo 10^{9}+7.

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
#include <math.h>
using namespace std;
typedef long long ll;
typedef vector<int> vint;
#define rep(i,n) for (ll i = 0; i < (ll)(n); ++i)
#define rrep(i,j,n) for(ll i = (ll)(j); i < (ll)(n); i++)
#define mrep(i,n) for (ll i = (ll)(n); i > 0; i--)
#define be(v) (v).begin(), (v).end()
#define dcout cout << fixed << setprecision(20) 
ll INF = 1LL << 60;
ll mod = 1e9 + 7;

int main() {
	int n; cin >> n;
	int ans=1;
	for(int i=1;i<=n;i++) {
		ans=ans*(i%mod);
	}
	cout << ans << endl;
}