Problem:
Score: 200 points

Problem Statement

We have a string S consisting of lowercase English letters.

If the length of S is at most K, print S without change.

If the length of S exceeds K, extract the first K characters in S, append ... to the end of them, and print the result.

Constraints

K is an integer between 1 and 100 (inclusive).

S is a string consisting of lowercase English letters.

The length of S is between 1 and 100 (inclusive).

Input

Input is given from Standard Input in the following format:

K
S

Output

Print a string as stated in Problem Statement.

Sample Input 1

7
nikoandsolstice

Sample Output 1

nikoand...

nikoandsolstice has a length of 15, which exceeds K=7.

We should extract the first 7 characters in this string, append ... to the end of them, and print the result nikoand....

Sample Input 2

40
ferelibenterhominesidquodvoluntcredunt

Sample Output 2

ferelibenterhominesidquodvoluntcredunt

The famous quote from Gaius Julius Caesar.

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

		#include<bits/stdc++.h>
        #define ll long long int
        using namespace std;
        #define mod 1000000007
        #define pb push_back
        #define fi first
        #define si second
        #define mp make_pair
        #define f(n) for(ll i=0;i<n;i++)
        #define ff(m) for(ll j=0;j<m;j++)
        #define fr(i,p,n) for(ll i=p;i<n;i++)
        #define in insert
        ll exp(ll a,ll b,ll m);
        #define vl vector<ll> 
        #define pll pair <ll,ll>

    
        void solve(){

        	int n;
        	cin>>n;
        	string s;
        	cin>>s;
        	int k;
        	k=s.size();
        	if(k<=n)
        		cout<<s<<endl;
        	else{
        		f(k){
        			cout<<s[i];
        		}
        		cout<<"..."<<endl;
        	}



        }
 
       int main(){
 
            int t=1;
 			//cin>>t;
            while(t--)
               solve();
    
    		return 0;
		}
 
		ll exp(ll a,ll b,ll m)
		{
			if(b==0)
			{
				return 1;
			}
			ll temp =exp(a,b/2,m);
			temp=(temp*temp)%m;
			if(b&1)
			{
				return (temp*(a%m))%m;
			}
			return temp;
		}