Problem:
Score : 200 points

Problem Statement

An integer N is a multiple of 9 if and only if the sum of the digits in the decimal representation of N is a multiple of 9.

Determine whether N is a multiple of 9.

Constraints

0 \leq N < 10^{200000}

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a multiple of 9, print Yes; otherwise, print No.

Sample Input 1

123456789

Sample Output 1

Yes

The sum of these digits is 1+2+3+4+5+6+7+8+9=45, which is a multiple of 9, so 123456789 is a multiple of 9.

Sample Input 2

0

Sample Output 2

Yes

Sample Input 3

31415926535897932384626433832795028841971693993751058209749445923078164062862089986280

Sample Output 3

No

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>

#ifndef M_PI
#define M_PI 3.14159265358979
#endif
#define deg_to_rad(deg) (((deg) / 360) * 2 * M_PI)
#define rad_to_deg(rad) (((rad) / 2 / M_PI) * 360)

using namespace std;

typedef long long ll;
typedef vector<ll> vll;
typedef vector<int> vi;
typedef pair<ll, ll> pll;
typedef pair<int, int> pi;
typedef long double ld;
typedef pair<long double, long double> pld;

const ll INF = 1e18;
const ll MOD = 1e9 + 7;

int main() {
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    ll i, j, k;

    string n;
    cin >> n;
    int s = 0;
    for(i = 0; i < n.length(); i++) {
        s += n[i] - '0';
    }
    if(s % 9 == 0)
        cout << "Yes" << endl;
    else {
        cout << "No" << endl;
    }

    return 0;
}