Problem:
Score : 200 points

Problem Statement

There are some animals in a garden. Each of them is a crane with two legs or a turtle with four legs.

Takahashi says: "there are X animals in total in the garden, and they have Y legs in total." Determine whether there is a combination of numbers of cranes and turtles in which this statement is correct.

Constraints

1 \leq X \leq 100

1 \leq Y \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

If there is a combination of numbers of cranes and turtles in which the statement is correct, print Yes; otherwise, print No.

Sample Input 1

3 8

Sample Output 1

Yes

The statement "there are 3 animals in total in the garden, and they have 8 legs in total" is correct if there are two cranes and one turtle. Thus, there is a combination of numbers of cranes and turtles in which the statement is correct.

Sample Input 2

2 100

Sample Output 2

No

There is no combination of numbers of cranes and turtles in which this statement is correct.

Sample Input 3

1 2

Sample Output 3

Yes

We also consider the case in which there are only cranes or only turtles.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;
#define ll long long int
#define ld long double
#define pb push_back
#define mp make_pair
#define f(i,a,n) for(int i=a ; i<n ; i++)
#define F first
#define S second
#define vll vector<ll>
#define fast ios:: sync_with_stdio(false),cin.tie(0);
#define COUT cout<<fixed<<setprecision(12)
#define SET set<ll,greater<ll>>gquiz
#define ITERATOR set<ll,greater<ll>> :: iterator itr
#define V vector<ll>vector
#define sz size()
//#define A vector<pair<ll,ll>>vect
ll N=100000,M=100000;
#define B vect.push_back(make_pair(N,M));
ll MOD=1000000007;
 
bool isprime(ll n){if(n==1 || (n!=2 && n%2==0))return false; if(n==2)return true; 
		for(ll i=3;i<=sqrt(n);i+=2)if(n%i==0)return false; return true; }
ll gcd(ll a,ll b) 
{ 
    if (a == 0) 
        return b; 
    return gcd(b % a, a); 
} 

void solve()
{
	ll x,y;
	cin>>x>>y;
	for(ll i=1;i<=y;i++)
	{
		ll h=y-i;
		if(h%4==0 && i%2==0)
		{
			ll k=h/4;
			ll g=i/2;
			if((k+g)==x)
			{
				cout<<"Yes";
				return;
			}
		}
		if(h%2==0 && i%4==0)
		{
			ll k=h/2;
			ll g=i/4;
			if((k+g)==x)
			{
				cout<<"Yes";
				return;
			}
		}
	}
	cout<<"No";
}
int main()
{
	fast;
	ll t=1;
//	cin>>t;
	while(t--)
	{
		solve();
	}
}