Problem:
Score: 100 points

Problem Statement

M-kun is a competitor in AtCoder, whose highest rating is X.

In this site, a competitor is given a kyu (class) according to his/her highest rating. For ratings from 400 through 1999, the following kyus are given:

From 400 through 599: 8-kyu

From 600 through 799: 7-kyu

From 800 through 999: 6-kyu

From 1000 through 1199: 5-kyu

From 1200 through 1399: 4-kyu

From 1400 through 1599: 3-kyu

From 1600 through 1799: 2-kyu

From 1800 through 1999: 1-kyu

What kyu does M-kun have?

Constraints

400 \leq X \leq 1999

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print the kyu M-kun has, as an integer.
For example, if he has 8-kyu, print 8.

Sample Input 1

725

Sample Output 1

7

M-kun's highest rating is 725, which corresponds to 7-kyu.

Thus, 7 is the correct output.

Sample Input 2

1600

Sample Output 2

2

M-kun's highest rating is 1600, which corresponds to 2-kyu.

Thus, 2 is the correct output.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

//                             ¯\_(ツ)_/¯   
//#pragma GCC optimize("Ofast")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mma,ava,tune=native")
//#pragma GCC optimize("unroll-loops")
#include <bits/stdc++.h>
using namespace std;

#define pb push_back
#define sz(a) ((int)(a).size())
#define all(a) (a).begin(),(a).end()
#define ll long long
 
 
void file(){
	#ifndef ONLINE_JUDGE
    	freopen("in.txt", "r", stdin);
	#endif
}
 
const int N=2e5+5,M=2e6+5,MOD=1e9+7,OO=1e9;

int main(){
	ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);
	//file();

	int x;

	cin>>x;

	if(x>=400 && x<=599)cout<<"8";
	else if(x>=600 && x<=799)cout<<"7";
	else if(x>=800 && x<=999)cout<<"6";
	else if(x>=1000 && x<=1199)cout<<"5";
	else if(x>=1200 && x<=1399)cout<<"4";
	else if(x>=1400 && x<=1599)cout<<"3";
	else if(x>=1600 && x<=1799)cout<<"2";
	else cout<<"1";
	
	
}