Problem:
Score : 200 points

Problem Statement

There is an image with a height of H pixels and a width of W pixels. Each of the pixels is represented by either . or *. The character representing the pixel at the i-th row from the top and the j-th column from the left, is denoted by C_{i,j}.

Extend this image vertically so that its height is doubled. That is, print a image with a height of 2H pixels and a width of W pixels where the pixel at the i-th row and j-th column is equal to C_{(i+1)/2,j} (the result of division is rounded down).

Constraints

1≦H, W≦100

C_{i,j} is either . or *.

Input

The input is given from Standard Input in the following format:

H W
C_{1,1}...C_{1,W}
:
C_{H,1}...C_{H,W}

Output

Print the extended image.

Sample Input 1

2 2
*.
.*

Sample Output 1

*.
*.
.*
.*

Sample Input 2

1 4
***.

Sample Output 2

***.
***.

Sample Input 3

9 20
.....***....***.....
....*...*..*...*....
...*.....**.....*...
...*.....*......*...
....*.....*....*....
.....**..*...**.....
.......*..*.*.......
........**.*........
.........**.........

Sample Output 3

.....***....***.....
.....***....***.....
....*...*..*...*....
....*...*..*...*....
...*.....**.....*...
...*.....**.....*...
...*.....*......*...
...*.....*......*...
....*.....*....*....
....*.....*....*....
.....**..*...**.....
.....**..*...**.....
.......*..*.*.......
.......*..*.*.......
........**.*........
........**.*........
.........**.........
.........**.........

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <iomanip>
#include <vector>
#include <utility>
#include <cmath>
#include <algorithm>
#include <numeric>
#include <functional>
#include <unordered_map>
#include <unordered_set>
#include <deque>
#include <stack>
#include <queue>
#include <array>
#include <random>
#include <chrono>

using namespace std;
#define rep(i, a, n) for (int i = a; i < n; ++i)
#define per(i, a, n) for (int i = n - 1; i >= a; --i)
#define pb push_back
#define eb emplace_back
#define mp make_pair
#define all(x) (x).begin(), (x).end()
#define sz(x) ((int)(x).size())
typedef vector<int> vi;
typedef int64_t i64;
typedef uint64_t ui64;
typedef pair<int, int> pi;

struct custom_hash {
    static ui64 splitmix64(ui64 x) {
        x += 0x9e3779b97f4a7c15;
        x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9;
        x = (x ^ (x >> 27)) * 0x94d049bb133111eb;
        return x ^ (x >> 31);
    }

    size_t operator()(ui64 x) const {
        static const ui64 FIXED_RANDOM = chrono::steady_clock::now().time_since_epoch().count();
        return splitmix64(x + FIXED_RANDOM);
    }
};

template <class T, class U>
inline ostream& operator<<(ostream& os, const pair<T, U>& p) {
    os << p.first << ' ' << p.second;
    return os;
}
template <class T, class U>
inline istream& operator>>(istream& os, pair<T, U>& p) {
    os >> p.first >> p.second;
    return os;
}
template <class T>
inline ostream& operator<<(ostream& os, const vector<T>& v) {
    if (v.empty())
        return os;
    if (v.begin() != v.end())
        os << v.front();
    for (auto it = ++v.begin(); it != v.end(); ++it)
        os << ' ' << *it;
    return os;
}
template <class T>
inline istream& operator>>(istream& is, vector<T>& v) {
    for (auto& i : v)
        is >> i;
    return is;
}

template <class T, size_t N>
inline istream& operator>>(istream& is, array<T, N>& a) {
    for (auto& i : a)
        is >> i;
    return is;
}

inline void Solve(istream& is, ostream& os) {
    int n, _;
    is >> n >> _;
    string s;
    while (n--) {
        is >> s;
        os << s << '\n' << s << '\n';
    }
}

int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(nullptr);
    cout.tie(nullptr);
    cout << setprecision(20) << fixed;
    Solve(cin, cout);
    return 0;
}