Problem:
Score : 100 points

Problem Statement

Given is an integer x that is greater than or equal to 0, and less than or equal to 1.
Output 1 if x is equal to 0, or 0 if x is equal to 1.

Constraints

0 \leq x \leq 1

x is an integer

Input

Input is given from Standard Input in the following format:

x

Output

Print 1 if x is equal to 0, or 0 if x is equal to 1.

Sample Input 1

1

Sample Output 1

0

Sample Input 2

0

Sample Output 2

1

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

//God's Grace
#include <iostream>
#include <map>
#include <algorithm>
#include <queue>
#include <list>
#include <string>
#include <cmath>
#include <stack>
#include <cstdio>
#include <fstream>
#include <climits>
#include <set>
#include <vector>
#include <tuple>
#include <cstring>
#include <functional>
#include <utility>
#include <iomanip>
//#pragma g++ optimize("O2")
//#pragma GCC target("avx,avx2,fma")
using namespace std;

#define endl '\n'
#define f(k,a,b) for(int k=(a);k<(b);++k)
#define vi vector <int>
#define vvi vector <vector <int> >
#define vii vector <pair <int, int > >
#define int long long
#define lli long long
#define pii pair <int,int>
#define piii pair< pair<lli,lli>, lli >
#define fsd fflush(stdout);
#define pb(x) push_back(x)
#define fast_io ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL)
//#define tdef typedef
#define all(x) x.begin(),x.end()
#define ret return
const int fix = (int)1e9 + 7;

int po2(lli a){double temp = a;if(log2(temp)==(int)log2(temp))return log2(temp);return -1;}
void tc(int i){cout<<"Case #"<<i+1<<": ";}
void yes(){cout<<"YES"<<endl;}
void no(){cout<<"NO"<<endl;}
void impb(){cout<<"IMPOSSIBLE"<<endl;}
int ct(){int t;scanf("%lld",&t);return t;}
int gcd(int a, int b) {if (b == 0)return a;return gcd(b, a % b);}
int pwr(int a, int b){ int x=1, y=a; while(b>0){if(b%2) x = (x*y)%fix; y=(y*y)%fix; b/=2;} return x;}
int power(int a, int b){ int x=1, y=a; while(b>0){if(b%2) x = (x*y); y=(y*y); b/=2;} return x;}
int pmodinv(int a){return pwr(a,fix-2);}
void error(){cerr<<"Here!"<<endl;}

vvi adj;


const int N = 3e5+5;
bool visited[N]= {};
queue <int> q;

int comanc(int u, int v,int parent[]){
	while(u^v){
		if(u==1||v==1)
			return 1;
		u = parent[u];
		v = parent[v];
	}

	return u;
}
int x;


int min(int a,int b){if(a<b)ret a;ret b;}
int max(int a, int b){if (a>b) ret a;ret b;}

vector <int> factorial((int)4002);

int nCr(int n, int k){
	return (factorial[n]*((pmodinv(factorial[k])*pmodinv(factorial[n-k]))%fix))%fix;
}


/******************* -- DSU -- *******************/
int dsu_par[N];
int sze[N];
//int cost[N];
void make_set(int n){
	f(j,1,n+1){
		dsu_par[j]=j;
		sze[j]=1;

	}
}

int find_set(int a){
	if(dsu_par[a]==a)
		return a;
	 dsu_par[a] = find_set(dsu_par[a]);
	// cost[a]+=dsu_par[a];
	return dsu_par[a];
}

void union_set(int a, int b){
	a = find_set(a);
	    b = find_set(b);
	    if (a^b) {
	        if (sze[a] < sze[b])
	            swap(a, b);
	        dsu_par[b] = a;
	       sze[a] += sze[b];
	    }
}

/******************** LCA *********************/
map <pii, int> mp;
vvi up;
vi tin, tout;
int dfs_timer=0;
int lim;
int dist[N]={};
void _dfs(int v, int par){
	tin[v] = ++dfs_timer;
	up[v][0] = par;
	f(j,1,lim+1)
	up[v][j] = up[up[v][j-1]][j-1];

	for(int u:adj[v]){
		if(u^par){
			dist[u] = dist[v] + mp.find(pii(u,v))->second;
			//parent[u]=v;
			_dfs(u,v);
		}
	}

	tout[v] = ++dfs_timer;
}

bool is_anc(int u, int v){ return tin[u] <= tin[v] && tout[u] >= tout[v];}
int lca(int u, int v){
	if(is_anc(u,v))
		return u;
	if(is_anc(v,u))
		return v;
	for(int i=lim;i>=0;i--)
		if(is_anc(up[u][i],v)^1)
			u = up[u][i];

	return up[u][0];
}



int32_t main() {

	int t=1;
	t = ct();


	f(ii,0,t){

		int x =ct();
		cout<<(x^1)<<endl;




		}
ret 0;
}