Problem:
Score : 200 points

Problem Statement

A shop sells N kinds of fruits, Fruit 1, \ldots, N, at prices of p_1, \ldots, p_N yen per item, respectively. (Yen is the currency of Japan.)

Here, we will choose K kinds of fruits and buy one of each chosen kind. Find the minimum possible total price of those fruits.

Constraints

1 \leq K \leq N \leq 1000

1 \leq p_i \leq 1000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
p_1 p_2 \ldots p_N

Output

Print an integer representing the minimum possible total price of fruits.

Sample Input 1

5 3
50 100 80 120 80

Sample Output 1

210

This shop sells Fruit 1, 2, 3, 4, and 5 for 50 yen, 100 yen, 80 yen, 120 yen, and 80 yen, respectively.

The minimum total price for three kinds of fruits is 50 + 80 + 80 = 210 yen when choosing Fruit 1, 3, and 5.

Sample Input 2

1 1
1000

Sample Output 2

1000

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

/*
*         ****FOX****
*/
#include <iostream>
#include <string>
#include <algorithm>
#include <stack>
#include <vector>
#include <map>
#include <set>
#include <sstream>
#include <iomanip>
#include <cmath>
#include <limits>
//freopen("input.txt", "r", stdin); freopen("output.txt", "w", stdout);
#include <utility>
#include <list>
#include <cstdio>
#include<forward_list>
#include<algorithm>
#include<string>
#define Omar_Hafez ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define pi 3.1415926536
#define ll long long
#define ull unsigned long long
#define lli long long int
using namespace std;
int main()
{
    Omar_Hafez
    int n, k,x,sum=0; cin >> n >> k;
    vector<int> v;
    for (int i = 0; i < n; i++) { cin >> x; v.push_back(x); }
    sort(v.begin(), v.end());
    for (int i = 0; i < k; i++)  sum += v[i];
    return cout<<sum,0;
}