Problem:
Score : 200 points

Problem Statement

There are N balls placed in a row.
AtCoDeer the deer is painting each of these in one of the K colors of his paint cans.
For aesthetic reasons, any two adjacent balls must be painted in different colors.

Find the number of the possible ways to paint the balls.

Constraints

1≦N≦1000

2≦K≦1000

The correct answer is at most 2^{31}-1.

Input

The input is given from Standard Input in the following format:

N K

Output

Print the number of the possible ways to paint the balls.

Sample Input 1

2 2

Sample Output 1

2

We will denote the colors by 0 and 1. There are two possible ways: we can either paint the left ball in color 0 and the right ball in color 1, or paint the left in color 1 and the right in color 0.

Sample Input 2

1 10

Sample Output 2

10

Since there is only one ball, we can use any of the ten colors to paint it. Thus, the answer is ten.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <cstdlib>
#include <algorithm>
#include <vector>
#include <string>
#include <cmath>
#include <cassert>
#include <functional>
#include <string>
#include <sstream>
#include <cctype>
using namespace std;

class xy{
public:
  int x, y;
  xy() {x = y = 0;}
};

int main(){
  int N, K; cin >> N >> K;
  long long res = 1;
  for(int i = 0; i < N; i++){
    if(i == 0) res *= K;
    else res *= K - 1;
  }
  cout << res << endl;
}