Problem:
Score : 100 points

Problem Statement

You are given two positive integers a and b.
Let x be the average of a and b.
Print x rounded up to the nearest integer.

Constraints

a and b are integers.

1 \leq a, b \leq 100

Input

Input is given from Standard Input in the following format:

a b

Output

Print x rounded up to the nearest integer.

Sample Input 1

1 3

Sample Output 1

2

The average of 1 and 3 is 2.0, and it will be rounded up to the nearest integer, 2.

Sample Input 2

7 4

Sample Output 2

6

The average of 7 and 4 is 5.5, and it will be rounded up to the nearest integer, 6.

Sample Input 3

5 5

Sample Output 3

5

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#pragma region header
#pragma GCC optimize("Ofast")
#include <bits/stdc++.h>
using namespace std;

int ceil_div(int X, int Y) { return (X - 1) / Y + 1; }

void solve(int a, int b) {
  cout<<ceil_div(a+b, 2)<<endl;
}

#pragma region main
signed main() {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  cout << fixed << setprecision(15);

  int a;
  cin >> a;
  int b;
  cin >> b;
  solve(a, b);
}
#pragma endregion main