Problem:
Score : 100 points

Problem Statement

There is a set A = \{ a_1, a_2, \ldots, a_N \} consisting of N positive integers.
Taro and Jiro will play the following game against each other.

Initially, we have a pile consisting of K stones.
The two players perform the following operation alternately, starting from Taro:

Choose an element x in A, and remove exactly x stones from the pile.

A player loses when he becomes unable to play.
Assuming that both players play optimally, determine the winner.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq K \leq 10^5

1 \leq a_1 < a_2 < \cdots < a_N \leq K

Input

Input is given from Standard Input in the following format:

N K
a_1 a_2 \ldots a_N

Output

If Taro will win, print First; if Jiro will win, print Second.

Sample Input 1

2 4
2 3

Sample Output 1

First

If Taro removes three stones, Jiro cannot make a move.
Thus, Taro wins.

Sample Input 2

2 5
2 3

Sample Output 2

Second

Whatever Taro does in his operation, Jiro wins, as follows:

If Taro removes two stones, Jiro can remove three stones to make Taro unable to make a move.

If Taro removes three stones, Jiro can remove two stones to make Taro unable to make a move.

Sample Input 3

2 7
2 3

Sample Output 3

First

Taro should remove two stones. Then, whatever Jiro does in his operation, Taro wins, as follows:

If Jiro removes two stones, Taro can remove three stones to make Jiro unable to make a move.

If Jiro removes three stones, Taro can remove two stones to make Jiro unable to make a move.

Sample Input 4

3 20
1 2 3

Sample Output 4

Second

Sample Input 5

3 21
1 2 3

Sample Output 5

First

Sample Input 6

1 100000
1

Sample Output 6

Second

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>

using namespace std;
typedef long long int ll;
#define debug(val) "[ " << #val " : " << (val) << " ]\n"
#define space " "
#define space " "
#define vi vector<int>
#define PI atan(1)*4
#define pb push_back
#define ff first
#define ss second
#define PI atan(1)*4


void solve() {
    int n , k ;
    cin >> n >> k ;
    vi a(n) ;
    for(int i=0;i<n;i++){
        cin >> a[i] ;
    }
    vector<bool> dp(k+1) ;
    for(int i=0;i<=k;i++){
        bool lose = true;
        for(auto val : a ) {
            if(i - val >= 0 ) {
                lose = lose &&   dp[i-val] ;
            }
        }
        dp[i] = !lose ;
    }
//    for(int i=0;i<k;i++){
//        cerr << dp[i] << space ;
//    }
    cout << (dp[k] ? "First" : "Second") << endl;

}
int main() {
#ifdef _DEBUG // place in cmake-build-debug folder
    freopen("in.txt", "r", stdin);
    freopen("out.txt", "w", stdout);
#endif
    ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
    int q = 1;
    //cin >> q;
    for (int i = 1; i <= q; i++) {
        // cout << "Case #" << i << ": ";
        solve();
    }
}