Problem:
Score: 300 points

Problem Statement

As AtCoder Beginner Contest 100 is taking place, the office of AtCoder, Inc. is decorated with a sequence of length N, a = {a_1, a_2, a_3, ..., a_N}.

Snuke, an employee, would like to play with this sequence.

Specifically, he would like to repeat the following operation as many times as possible:

For every i satisfying 1 \leq i \leq N, perform one of the following: "divide a_i by 2" and "multiply a_i by 3".
Here, choosing "multiply a_i by 3" for every i is not allowed, and the value of a_i after the operation must be an integer.

At most how many operations can be performed?

Constraints

N is an integer between 1 and 10 \ 000 (inclusive).

a_i is an integer between 1 and 1 \ 000 \ 000 \ 000 (inclusive).

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 a_3 ... a_N

Output

Print the maximum number of operations that Snuke can perform.

Sample Input 1

3
5 2 4

Sample Output 1

3

The sequence is initially {5, 2, 4}. Three operations can be performed as follows:

First, multiply a_1 by 3, multiply a_2 by 3 and divide a_3 by 2. The sequence is now {15, 6, 2}.

Next, multiply a_1 by 3, divide a_2 by 2 and multiply a_3 by 3. The sequence is now {45, 3, 6}.

Finally, multiply a_1 by 3, multiply a_2 by 3 and divide a_3 by 2. The sequence is now {135, 9, 3}.

Sample Input 2

4
631 577 243 199

Sample Output 2

0

No operation can be performed since all the elements are odd. Thus, the answer is 0.

Sample Input 3

10
2184 2126 1721 1800 1024 2528 3360 1945 1280 1776

Sample Output 3

39

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

// vvvvvvvvvvvv TEMPLATE vvvvvvvvvvvv
#include <bits/stdc++.h>
using namespace std; using ll = long long; using P = pair<ll, ll>;
const ll linf = 1e18; const double eps = 1e-12, pi = acos(-1);
#define FOR(i,a,b) for (ll i=(a),__last_##i=(b);i<__last_##i;i++)
#define RFOR(i,a,b) for (ll i=(b)-1,__last_##i=(a);i>=__last_##i;i--)
#define REP(i,n) FOR(i,0,n)
#define RREP(i,n) RFOR(i,0,n)
#define __GET_MACRO3(_1, _2, _3, NAME, ...) NAME
#define each(i,a) for (auto&& i : a)
#define rep(...) __GET_MACRO3(__VA_ARGS__, FOR, REP)(__VA_ARGS__)
#define rrep(...) __GET_MACRO3(__VA_ARGS__, RFOR, RREP)(__VA_ARGS__)
#define pb push_back
#define eb emplace_back
#define all(a) begin(a),end(a)
#define chmin(x,v) x = min(x, v)
#define chmax(x,v) x = max(x, v)
#define min(x,y) (x < y ? x : y)
#define max(x,y) (x < y ? y : x)
template<typename Head> void out(Head h) { cout << h << endl; } template<typename Head, typename... Tail>void out(Head h, Tail... t) { cout << h << " "; out(t...); }
template<typename T> istream& operator>>(istream& is, vector<T>& v) { each(x,v) is >> x; return is; }
template<typename T> ostream& operator<<(ostream& os, const vector<T>& v) { rep(i,v.size()) { if (i) os << " "; os << v[i]; } return os; }
template<typename T> ostream& operator<<(ostream& os, const vector<string>& v) { rep(i,v.size()) { if (i) os << endl; os << v[i]; } return os; }
template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v) { rep(i,v.size()) { if (i) os << endl; os << v[i]; } return os; }
struct yes_no : std::numpunct<char> { string_type do_truename() const { return "Yes"; } string_type do_falsename() const { return "No"; } };
void solve(); int main() {
  ios::sync_with_stdio(false); cin.tie(0); locale loc(locale(), new yes_no); cout.imbue(loc); cout << fixed << setprecision(10) << boolalpha;
  solve();
}
// ^^^^^^^^^^^^ TEMPLATE ^^^^^^^^^^^^

constexpr ll mod = 1e9+7;
constexpr ll mul(ll a, ll b) { return a * b % mod; }
ll mul(initializer_list<ll> t) { ll res = 1; each(v, t) res = mul(res, v); return res; }
ll add(ll a, ll b) { return (a + b) % mod; }
ll add(initializer_list<ll> t) { ll res = 0; each(v, t) res = add(res, v); return res; }
ll sub(ll a, ll b) { return (a - b + mod) % mod; }
ll sub(initializer_list<ll> t) { auto it = t.begin(); ll res = *(it++); while (it != t.end()) res = sub(res, *(it++)); return res; }
ll inv(ll n); ll power(ll x, ll n) { if (n < 0) return inv(power(x, -n)); ll res = 1; for (ll i = 1; i <= n; i <<= 1) { if (i & n) res = mul(res, x); x = mul(x, x); } return res; }
ll inv(ll n) { return power(n, mod-2); }
ll divi(ll a, ll b) { return mul(a, inv(b)); }
ll divi(initializer_list<ll> t) { auto it = t.begin(); ll res = *(it++); while (it != t.end()) res = divi(res, *(it++)); return res; }
template<size_t n> struct Fact { ll fact[n+1]; public: constexpr Fact() : fact() { fact[0] = 1; rep(i, 1, n+1) fact[i] = fact[i-1] * i % mod; } ll operator[](size_t idx) const { return fact[idx]; } };
constexpr auto fact = Fact<size_t(300000)>();
ll comb(ll n, ll r) { if (r < 0) return 0; if (r > n) return 0; return divi(fact[n], mul(fact[r], fact[n-r])); }

using Row = vector<ll>;
using Matrix = vector<Row>;
Matrix E(ll n) { Matrix res(n, Row(n, 0)); rep(i, n) res[i][i] = 1; return res; }
Matrix mul(const Matrix& A, const Matrix& B) { const ll n = A.size(), m = A[0].size(), l = B[0].size(); assert(m == B.size()); Matrix res(n, Row(l, 0)); rep(i, n) rep(j, m) rep(k, l) res[i][k] = add(res[i][k], mul(A[i][j], B[j][k])); return res; }
Row mul(const Matrix& A, const Row& x) { Matrix tx(x.size()); rep(i, x.size()) tx[i] = Row(1, x[i]); tx = mul(A, tx); Row res(x.size()); rep(i, x.size()) res[i] = tx[i][0]; return res; }
Matrix power(Matrix A, ll n) { assert(A.size() == A[0].size()); Matrix res = E(A.size()); for (ll i = 1; i <= n; i <<= 1) { if (i & n) res = mul(res, A); A = mul(A, A); } return res; }

void solve() {
  ll n; cin >> n;
  vector<ll> a(n); cin >> a;
  vector<ll> cnt(n, 0);
  rep(i, n) {
    ll x = a[i];
    while (x % 2 == 0) {
      x /= 2;
      ++cnt[i];
    }
  }
  ll ans = 0;
  each(x, cnt) ans += x;
  cout << ans << endl;
}