Problem:
Score : 100 points

Problem Statement

You are given a string S of length 3 consisting of a, b and c. Determine if S can be obtained by permuting abc.

Constraints

|S|=3

S consists of a, b and c.

Input

Input is given from Standard Input in the following format:

S

Output

If S can be obtained by permuting abc, print Yes; otherwise, print No.

Sample Input 1

bac

Sample Output 1

Yes

Swapping the first and second characters in bac results in abc.

Sample Input 2

bab

Sample Output 2

No

Sample Input 3

abc

Sample Output 3

Yes

Sample Input 4

aaa

Sample Output 4

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <cmath>
#include <algorithm>
#include <string>
#include <sstream>
#include <complex>
#include <vector>
#include <list>
#include <queue>
#include <deque>
#include <stack>
#include <map>
#include <set>
#include <array>
#include <tuple>
#include <random>

using namespace std;
typedef long long int ll;

#define _overload3(_1, _2, _3, name, ...) name
#define _rep(i, n) repi(i, 0, n)
#define repi(i, a, b) for(int i = int(a); i < int(b); i++)
#define rep(...) _overload3(__VA_ARGS__, repi, _rep,)(__VA_ARGS__)
#define all(x) (x).begin(), (x).end()

#define inf 10000000000

int main(){
    cin.tie(0);
    ios::sync_with_stdio(false);

    string s;
    cin >> s;
    cout << ((s.find('a') != string::npos && s.find('b') != string::npos && s.find('c') != string::npos) ? "Yes" : "No") << endl;
}