Problem:
Score : 500 points

Problem Statement

You have a string A = A_1 A_2 ... A_n consisting of lowercase English letters.

You can choose any two indices i and j such that 1 \leq i \leq j \leq n and reverse substring A_i A_{i+1} ... A_j.

You can perform this operation at most once.

How many different strings can you obtain?

Constraints

1 \leq |A| \leq 200,000

A consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

A

Output

Print the number of different strings you can obtain by reversing any substring in A at most once.

Sample Input 1

aatt

Sample Output 1

5

You can obtain aatt (don't do anything), atat (reverse A[2..3]), atta (reverse A[2..4]), ttaa (reverse A[1..4]) and taat (reverse A[1..3]).

Sample Input 2

xxxxxxxxxx

Sample Output 2

1

Whatever substring you reverse, you'll always get xxxxxxxxxx.

Sample Input 3

abracadabra

Sample Output 3

44

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;

int main(){
    string s;
    long long ans;
    int cnt[26];
    cin>>s;

    ans = s.size()*(s.size()-1)/2;
    for(int i=0; i<26; i++){
        cnt[i] = 0;
    }

    for(int i=0; i<s.size(); i++){
        int v = int(s[i]-'a');
        cnt[v]++;
    }


    for(int i=0; i<26; i++){
        if(cnt[i] > 1){
            ans -= cnt[i]*(cnt[i]-1) / 2 ;
        }
    }

    ans++;
    
    cout<<ans<<endl;

    return 0;
}