Problem:
Score: 100 points

Problem Statement

In this problem, a date is written as Y-M-D. For example, 2019-11-30 means November 30, 2019.

Integers M_1, D_1, M_2, and D_2 will be given as input.

It is known that the date 2019-M_2-D_2 follows 2019-M_1-D_1.

Determine whether the date 2019-M_1-D_1 is the last day of a month.

Constraints

Both 2019-M_1-D_1 and 2019-M_2-D_2 are valid dates in the Gregorian calendar.

The date 2019-M_2-D_2 follows 2019-M_1-D_1.

Input

Input is given from Standard Input in the following format:

M_1 D_1
M_2 D_2

Output

If the date 2019-M_1-D_1 is the last day of a month, print 1; otherwise, print 0.

Sample Input 1

11 16
11 17

Sample Output 1

0

November 16 is not the last day of a month.

Sample Input 2

11 30
12 1

Sample Output 2

1

November 30 is the last day of November.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)


#include "bits/stdc++.h"
#include <cmath>
#include <iomanip>
using namespace std;
 
#define f first
#define s second
 
#define pb push_back
#define pp pop_back
#define mp make_pair
 
#define sz(x) (int)x.size()
#define sqr(x) ((x) * 1ll * (x))
#define all(x) x.begin(), x.end()
#define clr(a,v) memset(a, v, sizeof(a))
 
#define rep(i, l, r) for (int i = (l); i <= (r); i++)
#define per(i, l, r) for (int i = (l); i >= (r); i--)
#define reflex ios_base::sync_with_stdio(false)
 
#define nl '\n'
#define ioi exit(0);
 

#define PI 3.14159265

typedef long long ll;
typedef long double ld;
typedef unsigned long long ull;
 
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;
const int N= (int)2e5 + 7;
const int inf = (int)1e9 + 7;
//const int mod = (int)1e9 + 7;
//const int mod = 1000000007;
const ll linf = (ll)1e18 + 7;
 
const int dx[] = {-1, 0, 1, 0, 1, -1, -1, 1};
const int dy[] = {0, 1, 0, -1, 1, -1, 1, -1};
const int kx[] = {-1,1,2,2,1,-1,-2,-2};
const int ky[] = {2,2,1,-1,-2,-2,-1,1};

const int mod = 998244353;

struct dsu{
	int parent[N];
	int cont;
	void make_set(int n){
		for(int i = 1; i <= n; i++)
			parent[i] = i;
		cont = n;
	}
	
	int find_set(int v){
		if(v == parent[v])
			return v;
		return find_set(parent[v]);
	}
	
	void union_sets(int a, int b){
		a = find_set(a);
		b = find_set(b);
		if(a != b){
			parent[b] = a;
			cont--;
		}
	}
};

int m[13] ={0, 31,28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };

int main(){
	int m1, d1; cin>> m1>> d1;
	int m2, d2; cin>> m2 >> d2;
	
	if(m[11] == d1)
		cout<< 1;
	else
		cout<<0;
	
	return 0;
}