Problem:
Score : 200 points

Problem Statement

Takahashi loves palindromes. Non-palindromic strings are unacceptable to him. Each time he hugs a string, he can change one of its characters to any character of his choice.

Given is a string S. Find the minimum number of hugs needed to make S palindromic.

Constraints

S is a string consisting of lowercase English letters.

The length of S is between 1 and 100 (inclusive).

Input

Input is given from Standard Input in the following format:

S

Output

Print the minimum number of hugs needed to make S palindromic.

Sample Input 1

redcoder

Sample Output 1

1

For example, we can change the fourth character to o and get a palindrome redooder.

Sample Input 2

vvvvvv

Sample Output 2

0

We might need no hugs at all.

Sample Input 3

abcdabc

Sample Output 3

2

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h> 
using namespace std;
typedef long long ll; const ll MM = 1000000000;ll mod = MM + 7;
#define rep(i, n) for(ll i=0; i<n; i++)
#define Rep(i, j, n) for(ll i=j; i<n; i++)
#define all(vec) vec.begin(), vec.end()
template<class T> inline bool chmin(T& a, T b) {if(a > b) {a = b; return true;} return false;}
template<class T> inline bool chmax(T& a, T b) {if(a < b) {a = b; return true;} return false;}
const ll INF = 1LL << 60;

int main() {
    string s; cin >> s;
    int cnt = 0;
    rep(i, s.size()/2) {
        if(s[i] != s[s.size()-i-1]) cnt++;
    }
    cout << cnt << endl;
}