Problem:
Score : 300 points

Problem Statement

Given is a permutation P_1, \ldots, P_N of 1, \ldots, N.
Find the number of integers i (1 \leq i \leq N) that satisfy the following condition:

For any integer j (1 \leq j \leq i), P_i \leq P_j.

Constraints

1 \leq N \leq 2 \times 10^5

P_1, \ldots, P_N is a permutation of 1, \ldots, N.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
P_1 ... P_N

Output

Print the number of integers i that satisfy the condition.

Sample Input 1

5
4 2 5 1 3

Sample Output 1

3

i=1, 2, and 4 satisfy the condition, but i=3 does not - for example, P_i > P_j holds for j = 1.

Similarly, i=5 does not satisfy the condition, either. Thus, there are three integers that satisfy the condition.

Sample Input 2

4
4 3 2 1

Sample Output 2

4

All integers i (1 \leq i \leq N) satisfy the condition.

Sample Input 3

6
1 2 3 4 5 6

Sample Output 3

1

Only i=1 satisfies the condition.

Sample Input 4

8
5 7 4 2 6 8 1 3

Sample Output 4

4

Sample Input 5

1
1

Sample Output 5

1

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <iostream>
#include <iomanip>
#include <vector>
#include <string>
#include <cmath>
#include <map>
#include <climits>
#include <cassert>
#include <algorithm>
#include <utility>

using namespace std;
using Int = long long int;
using UInt = unsigned long long int;
using VI = vector<long long int>;
using VVI = vector<vector<long long int> >;

int main(void) {
    Int n;
    cin >> n;
    VI p(n);
    for (Int i = 0; i < n; ++i) {
        cin >> p[i];
    }

    Int result = 0;
    Int min_left = LLONG_MAX;
    for (Int i = 0; i < n; ++i) {
        if (p[i] <= min_left) {
            ++result;
            min_left = p[i];
        }
    }
    cout << result << endl;
    return 0;
}