Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include<bits/stdc++.h>
using namespace std;
string s[100000],m;
void mm (long long &d,long long &e)
{
	if(d<e)
	{
		d++;
		e--;
	}
	else
	{
		e++;
		d--;
	}
}
int main()
{
	long long n,a,b,c;
	cin>>n>>a>>b>>c;
	for(int t=0;t<n;t++)
	{
		cin>>s[t];
	}
	for(int t=0;t<n;t++)
	{
		//cout<<"t="<<t<<" ";
		if(s[t]=="AB")
		{
			if(a<b)
			{
				m+='A';
			}
			else
			{
				m+='B';
			}
			mm(a,b);
		}
		else if(s[t]=="AC")
		{
			if(a<c)
			{
				m+='A';
			}
			else
			{
				m+='C';
			}
			mm(a,c);
		}
		else
		{
			if(c<b)
			{
				m+='C';
			}
			else
			{
				m+='B';
			}
			mm(b,c);
			//cout<<"a="<<a<<" b="<<b<<" c="<<c<<" ";
		}
		if(a<0||b<0||c<0)
		{
			cout<<"No";
			return 0;
		}
	}
	cout<<"Yes"<<endl;
	for(int t=0;t<n;t++)
	{
		cout<<m[t]<<endl;
	}
	return 0;
}