Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
int main()
{
    int arr[3][3];
    
    for(int i=0;i<3;i++)
    {
        for(int j=0;j<3;j++)
        {
            cin>>arr[i][j];
        }
    }
    
    
    int n;
    cin>>n;
    
    while(n--)
    {
        int x;
        cin>>x;
       
       for(int i=0;i<3;i++)
      {
        for(int j=0;j<3;j++)
        {
            if(x==arr[i][j])
            arr[i][j]=0;
        }
      }    
    }
    
    int flag=0;
    
    for(int i=0;i<3;i++)
    {
        int cnt=1;
       
       if(arr[i][0]==0)
       {
           for(int j=1;j<3;j++)
           {
               if(arr[i][j]==0)
               cnt++;
           }
       }
       
       if(cnt==3)
       {
           flag=1;
           break;
       }
    }
    
    if(flag==0)
    {
        for(int j=0;j<3;j++)
       {
            int cnt1=1;
          if(arr[0][j]==0)
          {
          
           for(int i=1;i<3;i++)
           {
               if(arr[i][j]==0)
               cnt1++;
           }
         }
       
         if(cnt1==3)
         {
           flag=1;
           break;
         }
        }
        
    }
    
    if(flag==0)
    {
        if((arr[0][0]==0 && arr[1][1]==0 && arr[2][2]==0) || (arr[0][2]==0 && arr[1][1]==0 && arr[2][0]==0))
        flag=1;
    }
    
    
    if(flag==1)
    cout<<"Yes"<<endl;
    else
    cout<<"No"<<endl;

    return 0;
}