Problem:
Score : 300 points

Problem Statement

N persons are standing in a row. The height of the i-th person from the front is A_i.

We want to have each person stand on a stool of some heights - at least zero - so that the following condition is satisfied for every person:

Condition: Nobody in front of the person is taller than the person. Here, the height of a person includes the stool.

Find the minimum total height of the stools needed to meet this goal.

Constraints

1 \leq N \leq 2\times 10^5

1 \leq A_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 \ldots A_N

Output

Print the minimum total height of the stools needed to meet the goal.

Sample Input 1

5
2 1 5 4 3

Sample Output 1

4

If the persons stand on stools of heights 0, 1, 0, 1, and 2, respectively, their heights will be 2, 2, 5, 5, and 5, satisfying the condition.

We cannot meet the goal with a smaller total height of the stools.

Sample Input 2

5
3 3 3 3 3

Sample Output 2

0

Giving a stool of height 0 to everyone will work.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

/*
Created by Rishu Sahu @ covid 20-20
*/
/*
*****************************************************************
*/

#include<bits/stdc++.h>
using namespace std;

#define IOS cin.sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define ll long long int
#define pai pair<int,int>
#define pal pair<ll,ll>
#define rep(i,n) for(int i=0;i<n;i++)
#define repn(i,a,b) for(int i=a;i<=b;i++)
#define ff first 
#define ss second
#define sz(x) (int)x.size()
#define vi vector<int>
#define vl vector<ll>
#define mpl map<ll,ll>
#define mpi map<int,int>
#define pb push_back
#define all(x) x.begin(),x.end()

const int mod = 1e9+7;
const int INF = INT_MAX;

void prime(int &temp,int fa,vi &vec){
    while(temp%fa==0){
        vec.pb(fa);
        temp=temp/fa;
        break;
    }
}

void solve(){
    int n;
    cin>>n;
    ll sum=0;
    int arr[n];
    rep(i,n) cin>>arr[i];
    int mx=arr[0];
    for(int i=1;i<n;i++){
        if(arr[i]<mx)
        sum+=(mx-arr[i]);
        mx=max(mx,arr[i]);
    }
    cout<<sum<<endl;
}


int main(){
    /*int t;
    cin>>t;
    while(t--){*/
        solve();
    //}
}