Problem:
Score : 500 points

Problem Statement

There are N points on the 2D plane, i-th of which is located on (x_i, y_i).
There can be multiple points that share the same coordinate.
What is the maximum possible Manhattan distance between two distinct points?

Here, the Manhattan distance between two points (x_i, y_i) and (x_j, y_j) is defined by |x_i-x_j| + |y_i-y_j|.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq x_i,y_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
x_1 y_1
x_2 y_2
:
x_N y_N

Output

Print the answer.

Sample Input 1

3
1 1
2 4
3 2

Sample Output 1

4

The Manhattan distance between the first point and the second point is |1-2|+|1-4|=4, which is maximum possible.

Sample Input 2

2
1 1
1 1

Sample Output 2

0

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#define watch5(a,b,c,d,e) cerr<<#a<<": "<<a<<" | "<<#b<<": "<<b<<" | "<<#c<<": "<<c<<" | "<<#d<<": "<<d << " | "<<#e<<": "<<e<<endl;
#define watch4(a,b,c,d) cerr<<#a<<": "<<a<<" | "<<#b<<": "<<b<<" | "<<#c<<": "<<c<<" | "<<#d<<": "<<d<<endl;
#define watch3(a,b,c) cerr <<#a<<": "<<a<<" | "<<#b<<": "<<b<<" | "<<#c<<": "<<c<<endl;
#define printclock cerr<<"Time : "<<1000*(ld)clock()/(ld)CLOCKS_PER_SEC<<"ms\n";
#define sharingan cerr << "\n-------------------------------------------\n\n";
#define watch2(a,b) cerr <<#a<<": "<<a<<" | "<<#b<<": "<<b<< endl;
#define Yup ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);
#define watch(a) cerr <<#a<<": "<<a<<endl;
#define __gcd(a, b) __algo_gcd(a, b)
#define PI 3.14159265358979323846
#define mod 1000000007
#include "bits/stdc++.h"
using namespace std;
#define int long long

int32_t main(){
    int n;
    cin >> n;
    int x[n], y[n];
    int pp[n], nn[n]; 
    for( int i = 0; i < n; i++ ){
        cin >> x[i] >> y[i];
        pp[i] = x[i]+y[i];
        nn[i] = x[i]-y[i];
    }
    sort(pp, pp+n);
    sort(nn, nn+n);
    cout << max(pp[n-1]-pp[0], nn[n-1]-nn[0]); 
}