Problem:
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Maximum Profit

You can obtain profits from foreign exchange margin transactions. For example, if you buy 1000 dollar at a rate of 100 yen per dollar, and sell them at a rate of 108 yen per dollar, you can obtain (108 - 100) × 1000 = 8000 yen.

Write a program which reads values of a currency $R_t$ at a certain time $t$ ($t = 0, 1, 2, ... n-1$), and reports the maximum value of $R_j - R_i$ where $j > i$ .

Input

The first line contains an integer $n$. In the following $n$ lines, $R_t$ ($t = 0, 1, 2, ... n-1$) are given in order.

Output

Print the maximum value in a line.

Constraints

$2 \leq n \leq 200,000$

$1 \leq R_t \leq 10^9$

Sample Input 1

6
5
3
1
3
4
3

Sample Output 1

3

Sample Input 2

3
4
3
2

Sample Output 2

-1

Solution in C++ (judge verdict: Accepted)

#include <stdio.h>

int main(){
	int n;
	int R[200000];
	int cur_min;
	int res;
	
	scanf("%d\n", &n);
	for (int i = 0;i<n;i++){
		scanf("%d\n", &R[i]);
	}
	
	cur_min = R[0];
	res = R[1] - R[0];
	
	for (int i = 1; i < n; i++){
		if (R[i] - cur_min > res){
			res = R[i] - cur_min;
		}
		if (R[i] < cur_min){
			cur_min = R[i]; 
		}
	}
	printf("%d\n", res);
	return 0;
}