Problem:
Score : 300 points

Problem Statement

Takahashi is organizing a party.

At the party, each guest will receive one or more snack pieces.

Takahashi predicts that the number of guests at this party will be A or B.

Find the minimum number of pieces that can be evenly distributed to the guests in both of the cases predicted.

We assume that a piece cannot be divided and distributed to multiple guests.

Constraints

1 \leq A, B \leq 10^5

A \neq B

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the minimum number of pieces that can be evenly distributed to the guests in both of the cases with A guests and B guests.

Sample Input 1

2 3

Sample Output 1

6

When we have six snack pieces, each guest can take three pieces if we have two guests, and each guest can take two if we have three guests.

Sample Input 2

123 456

Sample Output 2

18696

Sample Input 3

100000 99999

Sample Output 3

9999900000

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
#define rep(i, n) for (int i = 0; i < (int)(n); ++i)
#define repk(i,k, n) for (ll i = k; i < (ll)(n); ++i)
#define MAX 500001
#define MOD 1000000007
typedef long long  ll;

using namespace std;

// 最大公約数のll版
ll gcd(ll a, ll b) {
	if (a < b) swap(a, b);
	return b == 0 ? a : gcd(b, a%b);
}

// 最小公倍数のll版
ll lcm(ll a, ll b) {
	return a * b / gcd(a, b);
}

int max;
int cnt[MAX];

int main() {
	ll a,b;
	cin >>a >> b;


	
	
	cout << lcm(a,b) << endl;

	return 0;
}