Problem:
Score : 100 points

Problem Statement

How many ways are there to choose two distinct positive integers totaling N, disregarding the order?

Constraints

1 \leq N \leq 10^6

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

Print the answer.

Sample Input 1

4

Sample Output 1

1

There is only one way to choose two distinct integers totaling 4: to choose 1 and 3. (Choosing 3 and 1 is not considered different from this.)

Sample Input 2

999999

Sample Output 2

499999

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

//
//  atcoder.cpp
//
//
///
#include <bits/stdc++.h>
#include <boost/optional.hpp>
#include <boost/range/irange.hpp>
#include <boost/range/algorithm.hpp>
#include <boost/range/numeric.hpp>
#include <boost/bimap/bimap.hpp>
#include <boost/bimap/multiset_of.hpp>
#include <boost/multi_array.hpp>
#include <boost/math/common_factor.hpp>
#include <boost/icl/interval_map.hpp>
#include <boost/algorithm/string.hpp>
#include <boost/pending/disjoint_sets.hpp>
#include <boost/graph/graph_traits.hpp>
#include <boost/graph/adjacency_list.hpp>
#include <boost/graph/dijkstra_shortest_paths.hpp>
#include <boost/graph/kruskal_min_spanning_tree.hpp>
#include <boost/graph/graph_utility.hpp>
#include <boost/numeric/ublas/vector.hpp>
// ↓これいる？
#include <boost/graph/strong_components.hpp>

#define REP(i, N) for(int i=0; i<(N); i++)
#define REC(f, ...) (void)0; const auto f = [&](const auto f, __VA_ARGS__)
using namespace std;
using namespace boost::math;
using namespace boost::numeric;
using ll = long long;
namespace bst = boost;
template<class T> void fill(T& v) { for (auto&& i : v) cin >> i; }

//#include "atcoder.hpp"

int main() {
    int A, B;
    
    cin >> A;
    
    cout << (A-1)/2 << endl;
    
    return 0;
}