Problem:
Score : 300 points

Problem Statement

Takahashi is a teacher responsible for a class of N students.

The students are given distinct student numbers from 1 to N.

Today, all the students entered the classroom at different times.

According to Takahashi's record, there were A_i students in the classroom when student number i entered the classroom (including student number i).

From these records, reconstruct the order in which the students entered the classroom.

Constraints

1 \le N \le 10^5

1 \le A_i \le N

A_i \neq A_j (i \neq j)

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 \ldots A_N

Output

Print the student numbers of the students in the order the students entered the classroom.

Sample Input 1

3
2 3 1

Sample Output 1

3 1 2

First, student number 3 entered the classroom.

Then, student number 1 entered the classroom.

Finally, student number 2 entered the classroom.

Sample Input 2

5
1 2 3 4 5

Sample Output 2

1 2 3 4 5

Sample Input 3

8
8 2 7 3 4 5 6 1

Sample Output 3

8 2 4 5 6 7 3 1

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using ld = long double;
using vi = vector<int>;
using vvi = vector<vi>;
using vvvi = vector<vvi>;
using vll = vector<ll>;
using vvll = vector<vll>;
using vvvll = vector<vvll>;
using vs = vector<string>;
using pll = pair<ll, ll>;
using vp = vector<pll>;
template<class T> using V = vector<T>;
template<class T> using VV = vector<vector<T> >;
#define rep(i, n) for(ll i = 0; i < (n); i++)
#define repb(i, n) for(ll i = (n)-1; i >= 0; i--)
#define repr(i, a, b) for(ll i = (a); i < (b); i++)
#define reprb(i, a, b) for(ll i = (b)-1; i >= (a); i--)
#define ALL(a) (a).begin(), (a).end()
#define SZ(x) ((ll)(x).size())
const ll MOD = 1000000007;
const ll INF = 100000000000000000LL;
inline ll GCD(ll a, ll b){ return b?GCD(b, a % b):a; }
inline ll LCM(ll a, ll b){ return a/GCD(a, b)*b; }
inline ll powint(unsigned long long x, ll y){ ll r=1; while(y){ if(y&1) r*=x; x*=x; y>>=1; } return r; }
inline ll powmod(ll x, ll y, ll m = MOD){ ll r=1; while(y){ if(y&1) r*=x; x*=x; r%=m; x%=m; y>>=1; } return r; }
template<class S, class T>bool chmax(S &a, const T &b){ if(a<b) { a=b; return 1; } return 0; }
template<class S, class T>bool chmin(S &a, const T &b){ if(b<a) { a=b; return 1; } return 0; }
#ifdef OJ_LOCAL
#include "dump.hpp"
#else
#define dump(...) ((void)0)
#endif

// 配列がソートされたときに移動するインデックスの配列を返す
// 配列自体はソートされない
// {1, 6, 2, 3, 6} -> {0, 3, 1, 2, 4}
template<typename T>
vi sortIndex(const vector<T>& vec){
    vi idx(SZ(vec));
    iota(ALL(idx), 0);
    sort(ALL(idx), [vec](int l, int r){
        return vec[l] < vec[r];
    });
    return idx;
}

int main(){
    cin.tie(0); ios::sync_with_stdio(false);
    cout << fixed << setprecision(15);
    ll n;
    cin >> n;
    /*
    vll a(n);
    rep(i, n){
        cin >> a[i];
    }
    vi ans = sortIndex(a);
    rep(i, n){
        cout << ans[i]+1 << " \n"[i==n-1];
    }
    */
    vp a(n);
    rep(i, n){
        cin >> a[i].first;
        a[i].second = i+1;
    }
    sort(ALL(a));
    rep(i, n){
        cout << a[i].second << " \n"[i==n-1];
    }
    return 0;
}