Problem:
Score : 400 points

Problem Statement

Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.

You are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.

Constraints

2 ≦ |s| ≦ 10^5

s consists of lowercase letters.

Partial Score

200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.

Input

The input is given from Standard Input in the following format:

s

Output

If there exists no unbalanced substring of s, print -1 -1.

If there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.

Sample Input 1

needed

Sample Output 1

2 5

The string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.

Sample Input 2

atcoder

Sample Output 2

-1 -1

The string atcoder contains no unbalanced substring.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <algorithm>
#include <numeric>
#include <cmath>
#include <string>
#include <vector>
#include <queue>
#include <deque>
#include <stack>
#include <map>
#include <set>
#include <unordered_map>
#include <unordered_set>
#include <iomanip>
#include <functional> // std::function<void(int)>
using namespace std;
#define int long long
#define All(v) (v).begin(),(v).end()
int dy[4] = {-1,0,1,0};
int dx[4] = {0,1,0,-1};
int Dy[8] = {-1,-1,0,1,1,1,0,-1};
int Dx[8] = {0,1,1,1,0,-1,-1,-1};
const int mod = 1000000007;
const int inf = mod*mod;
const int d5 = 111111;
signed main(){
    ios::sync_with_stdio(false);
    cin.tie(0);
    string s;
    cin>>s;
    int l=s.size();
    if(l==2){
        if(s[0]==s[1]){
            cout<<"1 2"<<endl;
            return 0;
        }
        else{
            cout<<"-1 -1"<<endl;
            return 0;
        }
    }
    for(int i=0;i<l-2;i++){
        string t=s.substr(i,3);
        sort(All(t));
        if(t[0]==t[1]){
            cout<<i+1<<' '<<i+3<<endl;
            return 0;
        }
    }
    cout<<"-1 -1"<<endl;
    return 0;
}