Problem:
Score : 100 points

Problem Statement

Serval is fighting with a monster.

The health of the monster is H.

In one attack, Serval can decrease the monster's health by A.
There is no other way to decrease the monster's health.

Serval wins when the monster's health becomes 0 or below.

Find the number of attacks Serval needs to make before winning.

Constraints

1 \leq H \leq 10^4

1 \leq A \leq 10^4

All values in input are integers.

Input

Input is given from Standard Input in the following format:

H A

Output

Print the number of attacks Serval needs to make before winning.

Sample Input 1

10 4

Sample Output 1

3

After one attack, the monster's health will be 6.

After two attacks, the monster's health will be 2.

After three attacks, the monster's health will be -2.

Thus, Serval needs to make three attacks to win.

Sample Input 2

1 10000

Sample Output 2

1

Sample Input 3

10000 1

Sample Output 3

10000

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
typedef unsigned long long ull;
typedef long long ll;
#define LONGMAX 1e18
#define ll long long
#define dd double
#define MOD 1000000007
#define nl cout<<endl
#define rt ll Q[100005]={0}
#define mp make_pair
#define endl "\n"
#define test() ull t;cin>>t;while(t--)
#define pb push_back
#define ff first	
#define ss second
#define all(v) v.begin(),v.end()
#define s(ar,n) sort(ar,ar+n)
#define rs(ar,n) sort(ar, ar+n, greater<ll>()) 
#define oa(a,n) for(ll i=0;i<n;i++)cout<<a[i]<<" ";nl
#define cn(a,n) for(ll i=0;i<n;i++)cin>>a[i];
#define ov(a,n) for(ll i=n-1;i>=0;i--)cout<<a[i]<<" ";nl
#define maxa(ar,N) *max_element(ar,ar+N)
#define mina(ar,N) *min_element(ar,ar+N)
#define INF 1e9
#define fastio() ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0)
ll powe(ll x,ll y){ll res=1;while(y>0){if(y&1)res=res*x;y=y>>1;x=x*x;}return res;}
ll mpowe(ll n,ll m){if(m==0)return 1;ll t=powe(n,m/2);t%=MOD;if(m%2==0)return (t*t)%MOD;return (((t*t)%MOD)*n)%MOD;}
ll logtwo(ll n){if(n==1)return 0;return logtwo(n/2)+1;}
void ceilsearch(ll ar[],ll low,ll high,ll x,ll &y){ll mid=(low+high)/2;if(low>high)return;if(ar[mid]>x){y=mid;ceilsearch(ar,low,mid-1,x,y);}else{ceilsearch(ar,mid+1,high,x,y);}}
int main()
{
	fastio();
	ll N,M;
	cin>>N>>M;
	cout<<(N+M-1)/M<<endl;
}