Problem:
Score : 200 points

Problem Statement

An integer N is a multiple of 9 if and only if the sum of the digits in the decimal representation of N is a multiple of 9.

Determine whether N is a multiple of 9.

Constraints

0 \leq N < 10^{200000}

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a multiple of 9, print Yes; otherwise, print No.

Sample Input 1

123456789

Sample Output 1

Yes

The sum of these digits is 1+2+3+4+5+6+7+8+9=45, which is a multiple of 9, so 123456789 is a multiple of 9.

Sample Input 2

0

Sample Output 2

Yes

Sample Input 3

31415926535897932384626433832795028841971693993751058209749445923078164062862089986280

Sample Output 3

No

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

/*

 Remember, Hope is a good thing... May be the best of things... and No Good thing ever Dies !!!

*/
#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define IOS ios::sync_with_stdio(0); cout.tie(0);
#define endl "\n"
#define MOD 1000000007
const ll inf=(1LL<<60)-1;
int dx[]= {-1,1,0,0};
int dy[]= {0,0,-1,1};
void solve()
{
    //freopen("input.txt", "r", stdin); freopen("output.txt", "w", stdout);
    string s;
    cin>>s;
    ll mul=0;
    for(ll i=0;i<s.size();i++)
    {
        mul+=s[i]-'0';
    }
    if(mul%9==0)
        cout<<"Yes"<<endl;
    else
        cout<<"No"<<endl;
}
int main()
{
    IOS;
    //ll t;
    //cin>>t;
    //while(t--)
    solve();
    return 0;
}