Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#define reps(i,a,b) for(int i=a;i<b;i++)
#define rep(i,a) for(int i=0;i<a;i++)
typedef long long int ll;
using namespace std;


struct aaa{
    aaa(){
        cin.tie(0); ios::sync_with_stdio(0); cout<<fixed<<setprecision(20);
    };
}aaaaaaa;

int main(){
    string S;
    cin>>S;
    int s = (S[0]-48)*10 + (S[1]-48);
    int ss = (S[2]-48)*10 + (S[3]-48);
    if(s>12 || s==0){
        if(ss>12||ss==0){
            cout<<"NA";
        }

        else{
            cout<<"YYMM";
        }    

    }
    else{
        if(ss>12||ss==0){
            cout<<"MMYY";
        }
        else{
            cout<<"AMBIGUOUS";
        }
    }
    return 0;
}