Problem:
Score : 100 points

Problem Statement

There are three airports A, B and C, and flights between each pair of airports in both directions.

A one-way flight between airports A and B takes P hours, a one-way flight between airports B and C takes Q hours, and a one-way flight between airports C and A takes R hours.

Consider a route where we start at one of the airports, fly to another airport and then fly to the other airport.

What is the minimum possible sum of the flight times?

Constraints

1 \leq P,Q,R \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

P Q R

Output

Print the minimum possible sum of the flight times.

Sample Input 1

1 3 4

Sample Output 1

4

The sum of the flight times in the route A \rightarrow B \rightarrow C: 1 + 3 = 4 hours

The sum of the flight times in the route A \rightarrow C \rightarrow C: 4 + 3 = 7 hours

The sum of the flight times in the route B \rightarrow A \rightarrow C: 1 + 4 = 5 hours

The sum of the flight times in the route B \rightarrow C \rightarrow A: 3 + 4 = 7 hours

The sum of the flight times in the route C \rightarrow A \rightarrow B: 4 + 1 = 5 hours

The sum of the flight times in the route C \rightarrow B \rightarrow A: 3 + 1 = 4 hours

The minimum of these is 4 hours.

Sample Input 2

3 2 3

Sample Output 2

5

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

//
#include <vector>
#include <set>
#include <map>
#include <array>
#include <iostream>
#include <cstdio>
#include <cstdint>
#include <algorithm>
#include <numeric>
#include <bitset>
#include <iomanip>
//
using ll = long long;
using namespace std;
#define rep(i,n) for(ll i=0;i<(n);++i)
#define outD(fpv) cout << setprecision(20) << fpv << endl;
inline void yes(bool cond) { cond ? puts("YES") : puts("NO"); }
template<typename Type> inline void chmin(Type& a, Type b) { if (a > b) a = b; }
template<typename Type> inline void chmax(Type& a, Type b) { if (a < b) a = b; }
template<typename Arr, typename Type> inline void fill(Arr& arr, Type v) { std::fill(arr.begin(), arr.end(), v); }
template<typename Type> inline void sort(Type& arr) { std::sort(arr.begin(), arr.end()); }
template<typename Type> inline Type nth(vector<Type>& arr, size_t pos) { std::nth_element(arr.begin(), arr.begin() + pos, arr.end()); return arr[pos]; }
template<typename Type> inline void unique(Type& arr) { sort(arr); arr.erase(unique(arr.begin(), arr.end()), arr.end()); }
constexpr double BIGP = 1000000007L;
constexpr double INF_I = std::numeric_limits<ll>::max();
constexpr double INF_F = std::numeric_limits<float>::infinity();
constexpr double PI = 3.14159265358979323846L;
//
int main()
{
    cin.tie(0); ios::sync_with_stdio(false);
    ll P, Q, R;
    cin >> P >> Q >> R;
    cout << min({ P + Q,Q + R,P + R });
    //
    return 0;
}