Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#define REP(i, n) for(int i=0; i<(int)(n); ++i)
#define FOR(i, s, n) for(int i=(int)(s); i<(int)(n); ++i)
#define ALL(n) (n).begin(), (n).end()
#define pb push_back

using namespace std;

typedef long long ll;
typedef vector<int> vi;
typedef vector<vi> mat;

const ll MAX_V = 100000;
const ll INF = 1e9;
const ll MOD = 998244353;

int main(){
    int n; cin >> n;
    int ans = 0;
    FOR(i, 1, n+1){
        int cnt = 0;
        if (i % 2 == 0) continue;
        FOR(j, 1, n+1){
            if (i % j == 0) cnt++;
        }
        if (cnt == 8) ans++;
    }
    cout << ans << endl;
}