Problem:
Score : 100 points

Problem Statement

In programming, hexadecimal notation is often used.

In hexadecimal notation, besides the ten digits 0, 1, ..., 9, the six letters A, B, C, D, E and F are used to represent the values 10, 11, 12, 13, 14 and 15, respectively.

In this problem, you are given two letters X and Y. Each X and Y is A, B, C, D, E or F.

When X and Y are seen as hexadecimal numbers, which is larger?

Constraints

Each X and Y is A, B, C, D, E or F.

Input

Input is given from Standard Input in the following format:

X Y

Output

If X is smaller, print <; if Y is smaller, print >; if they are equal, print =.

Sample Input 1

A B

Sample Output 1

<

10 < 11.

Sample Input 2

E C

Sample Output 2

>

14 > 12.

Sample Input 3

F F

Sample Output 3

=

15 = 15.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<int,int> P;

#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define repl(i, n) for (ll i = 0; i < (ll)(n); i++)
#define repr(i, n) for(int i = n; i >= 0; i--)
#define reprl(i, n) for(ll i = n; i >= 0; i--)
#define fori(i, m, n) for(int i = m; i < (int)n; i++)
#define forl(i, m, n) for(ll i = m; i < (ll)n; i++)
#define all(v) v.begin(), v.end()
ll gcd(ll a,ll b) {
  return b? gcd(b,a%b): a;  
}
ll lcm(ll a,ll b) {
  return a*b/gcd(a,b);
}
bool isLowerCase(char c){
  return (c>='a'&&c<='z');
}
const string btos(bool ans){
  return (ans?"Yes":"No");
}
int main() {
  char x,y;cin>>x>>y;
  char ans;
  if(x==y)ans='=';
  else if(x<y)ans='<';
  else ans='>';
  cout << ans<<endl;
  return 0;
}