Problem:
Score : 300 points

Problem Statement

In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0.
You are given a sequence h=\{h_1,h_2,h_3,......\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:

Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.

Find the minimum number of watering operations required to satisfy the condition.

Constraints

1 \leq N \leq 100

0 \leq h_i \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
h_1 h_2 h_3 ...... h_N

Output

Print the minimum number of watering operations required to satisfy the condition.

Sample Input 1

4
1 2 2 1

Sample Output 1

2

The minimum number of watering operations required is 2.
One way to achieve it is:

Perform the operation with (l,r)=(1,3).

Perform the operation with (l,r)=(2,4).

Sample Input 2

5
3 1 2 3 1

Sample Output 2

5

Sample Input 3

8
4 23 75 0 23 96 50 100

Sample Output 3

221

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#define rep(i,n) for(int i=0;i<(n);i++)
#define all(v) v.begin(),v.end()
#define len(x) (ll)(x).length()
using namespace std;
typedef long long ll;
typedef pair<int,int> P;
const int INF=1e9;
const int di[] = {-1,0,1,0};
const int dj[] = {0,-1,0,1};

int main(){
  int n;
  cin>>n;
  vector<int> h(n);
  rep(i,n) cin>>h[i];
  int ans=0;
  int mx=0;
  int cnt=0;
  while(true){
    if(cnt==n){
      break;
    }
    cnt=0;
    rep(j,n){
      if(h[j]==0){
        cnt++;
        continue;
      }
      ans++;
      if(h[j]!=0){
        while(h[j]!=0){
          h[j]--;
          j++;
        }
      }
    }
  }
  cout<<ans<<endl;
}