Problem:
Score : 100 points

Problem Statement

Takahashi, who is A years old, is riding a Ferris wheel.

It costs B yen (B is an even number) to ride the Ferris wheel if you are 13 years old or older, but children between 6 and 12 years old (inclusive) can ride it for half the cost, and children who are 5 years old or younger are free of charge. (Yen is the currency of Japan.)

Find the cost of the Ferris wheel for Takahashi.

Constraints

0 ≤ A ≤ 100

2 ≤ B ≤ 1000

B is an even number.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the cost of the Ferris wheel for Takahashi.

Sample Input 1

30 100

Sample Output 1

100

Takahashi is 30 years old now, and the cost of the Ferris wheel is 100 yen.

Sample Input 2

12 100

Sample Output 2

50

Takahashi is 12 years old, and the cost of the Ferris wheel is the half of 100 yen, that is, 50 yen.

Sample Input 3

0 100

Sample Output 3

0

Takahashi is 0 years old, and he can ride the Ferris wheel for free.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define pb push_back
#define all(t) t.begin(), t.end()
#define inrange(i, a, b) (((i)>= min((a), (b))) && ((i) <= max((a), (b))))
typedef vector<ll> vi;
#define fi first
#define se second
const ll inf = 9e18;
const ll mod = 1e9 + 7;

void print(ll a[], ll n){for(ll i=0;i<n;i++){cout<<a[i]<<" ";}cout<<"\n";}
ll power(ll x, ll y, ll M = inf){
    ll ans = 1;
    x %= M;
    while(y){
        if(y&1)
            ans = (x * ans) % M;

        x = (x * x) % M;
        y >>= 1;
    }
    return ans;
}
ll modInverse(ll n) {return power(n, mod-2, mod);}
inline ll mul(ll a, ll b){ return (a * b) % mod; }
inline ll sub(ll a, ll b){ ll c = a - b; if(c < 0) c += mod; return c; }
inline ll add(ll a, ll b){ ll c = a + b; if(c > mod) c -= mod; return c; }
inline ll divi(ll a, ll b){ return mul(a, modInverse(b)); }

int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(NULL); cout.tie(NULL);

	ll a, b;
	cin>>a>>b;
	ll ans=0;
	if(a <= 5){
		ans=0;
	}
	else if(a>=13){
		ans = b;
	}
	else if(a>=6 && a<=12)ans=b/2;
	
	cout<<ans<<"\n";
	return 0;
}