Problem:
Problem Statement

You are given two integers a and b (a≤b). Determine if the product of the integers a, a+1, …, b is positive, negative or zero.

Constraints

a and b are integers.

-10^9≤a≤b≤10^9

Partial Score

In test cases worth 100 points, -10≤a≤b≤10.

Input

The input is given from Standard Input in the following format:

a b

Output

If the product is positive, print Positive. If it is negative, print Negative. If it is zero, print Zero.

Sample Input 1

1 3

Sample Output 1

Positive

1×2×3=6 is positive.

Sample Input 2

-3 -1

Sample Output 2

Negative

(-3)×(-2)×(-1)=-6 is negative.

Sample Input 3

-1 1

Sample Output 3

Zero

(-1)×0×1=0.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair<ll, ll> lpair;
const ll MOD = 1e9 + 7;
const ll INF = 1e18;
#define REP(i,m,n) for(int i=(int)(m) ; i < (int) (n) ; ++i )
#define rep(i,n) REP(i,0,n)
#define rREP(i,m,n) for(ll i = (m); i >= (n); i--)
#define ALL(c) (c).begin(), (c).end()
#define print(x) cout << (x) << endl;
#define printa(x,n) for(ll i = 0; i < n; i++){ cout << (x[i]) << " ";} cout<<endl;
int main(){
    cin.tie(0);
    ios::sync_with_stdio(false);

    ll a,b;
    cin >> a >> b;

    if (0<a)
    {
        cout << "Positive" << endl;
    }
    else if (a<=0 && 0<=b)
    {
        cout << "Zero" << endl;
    }
    else
    {
        if ((b-a)%2==0)
        {
            cout << "Negative" << endl;
        }
        else
        {
            cout << "Positive" << endl;
        }
        
    }
    
    
}