Problem:
Score: 200 points

Problem Statement

A country decides to build a palace.

In this country, the average temperature of a point at an elevation of x meters is T-x \times 0.006 degrees Celsius.

There are N places proposed for the place. The elevation of Place i is H_i meters.

Among them, Princess Joisino orders you to select the place whose average temperature is the closest to A degrees Celsius, and build the palace there.

Print the index of the place where the palace should be built.

It is guaranteed that the solution is unique.

Constraints

1 \leq N \leq 1000

0 \leq T \leq 50

-60 \leq A \leq T

0 \leq H_i \leq 10^5

All values in input are integers.

The solution is unique.

Input

Input is given from Standard Input in the following format:

N
T A
H_1 H_2 ... H_N

Output

Print the index of the place where the palace should be built.

Sample Input 1

2
12 5
1000 2000

Sample Output 1

1

The average temperature of Place 1 is 12-1000 \times 0.006=6 degrees Celsius.

The average temperature of Place 2 is 12-2000 \times 0.006=0 degrees Celsius.

Thus, the palace should be built at Place 1.

Sample Input 2

3
21 -11
81234 94124 52141

Sample Output 2

3

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <vector>
#include <algorithm>
#include <functional>
#include <queue>
#include <deque>
#include <string>
#include <stack>
#include <unordered_set>
#include <cmath>
#include <climits>
#include <cstdlib>
#define endl '\n'
#define ll long long
#define mod 1000000007
#define NCONS 100001
#define PLUS 0
#define MINUS 1

using namespace std;

ll N, T, A;

ll get(ll x)
{
	return T * 1000 - x * 6;
}

int main(void)
{
	cin.tie(NULL); ios_base::sync_with_stdio(false);
	cin >> N >> T >> A;
	ll ret = 1;
	ll diff = LLONG_MAX;
	for (ll i = 1; i <= N; i++)
	{
		ll h; cin >> h;
		if (abs(1000 * A - get(h)) < diff)
		{
			ret = i;
			diff = abs(1000 * A - get(h));
		}

	}
	cout << ret << endl;
	return 0;
}