Problem:
Score : 200 points

Problem Statement

Given are integers a,b,c and d.
If x and y are integers and a \leq x \leq b and c\leq y \leq d hold, what is the maximum possible value of x \times y?

Constraints

-10^9 \leq a \leq b \leq 10^9

-10^9 \leq c \leq d \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

a b c d

Output

Print the answer.

Sample Input 1

1 2 1 1

Sample Output 1

2

If x = 1 and y = 1 then x \times y = 1.
If x = 2 and y = 1 then x \times y = 2.
Therefore, the answer is 2.

Sample Input 2

3 5 -4 -2

Sample Output 2

-6

The answer can be negative.

Sample Input 3

-1000000000 0 -1000000000 0

Sample Output 3

1000000000000000000

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include<stdio.h>
int main()
{
    long long  a,b,c,d;
    long long x,y,z,p;
    scanf("%lld %lld %lld %lld",&a,&b,&c,&d);
    if(a>b && c>d){
        a=a*c;
        printf("%d",a);
    }
    else if(a>b && c<d){
        a=a*d;
        printf("%d",a);
    }
    else if(a<b && c>d){
        a=b*c;
        printf("%d",a);
    }
    else if(a<b && c<d){
        a=b*d;
        printf("%d",a);
    }
    else{
        printf("%d",x);
    }
    return 0;
}