Problem:
Score : 300 points

Problem Statement

As a token of his gratitude, Takahashi has decided to give his mother an integer sequence.
The sequence A needs to satisfy the conditions below:

A consists of integers between X and Y (inclusive).

For each 1\leq i \leq |A|-1, A_{i+1} is a multiple of A_i and strictly greater than A_i.

Find the maximum possible length of the sequence.

Constraints

1 \leq X \leq Y \leq 10^{18}

All input values are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

Print the maximum possible length of the sequence.

Sample Input 1

3 20

Sample Output 1

3

The sequence 3,6,18 satisfies the conditions.

Sample Input 2

25 100

Sample Output 2

3

Sample Input 3

314159265 358979323846264338

Sample Output 3

31

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;
#define dhoom ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);  
typedef long long ll;
typedef long double ld;
const ll inf = 1e18;
const int nax = 2e6 + 7;
const ll mod = 1e9 + 7;
//ll tree[4 * nax];
//9uS-22RSwk7gQqh
ll gcd(ll a , ll b){
	if(b == 0) return a;
	return gcd(b , a % b);	
}
ll lcm(ll a , ll b){
	ll g = gcd(a , b);
	ll lc = (a/g) * b;
	return lc;
}
//char a[55][55];
int dx[] = {1,0,-1,0,1,1,-1,-1};
int dy[] = {0,1,0,-1,1,-1,-1,1};
ll a[100];
int main()
{
	dhoom;
	ll x , y;
	cin >> x >> y;
	int cnt = 0;
	for(ll i = 0;pow(2LL,i)*x <= y && x*pow(2LL,i) > 0 ; i++){
		cnt++;
	}
	cout << cnt << endl;
	return 0;
}