Problem:
Score: 400 points

Problem Statement

AtCoder Inc. has decided to lock the door of its office with a 3-digit PIN code.

The company has an N-digit lucky number, S. Takahashi, the president, will erase N-3 digits from S and concatenate the remaining 3 digits without changing the order to set the PIN code.

How many different PIN codes can he set this way?

Both the lucky number and the PIN code may begin with a 0.

Constraints

4 \leq N \leq 30000

S is a string of length N consisting of digits.

Input

Input is given from Standard Input in the following format:

N
S

Output

Print the number of different PIN codes Takahashi can set.

Sample Input 1

4
0224

Sample Output 1

3

Takahashi has the following options:

Erase the first digit of S and set 224.

Erase the second digit of S and set 024.

Erase the third digit of S and set 024.

Erase the fourth digit of S and set 022.

Thus, he can set three different PIN codes: 022, 024, and 224.

Sample Input 2

6
123123

Sample Output 2

17

Sample Input 3

19
3141592653589793238

Sample Output 3

329

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
  
#define IOS ios_base::sync_with_stdio(false);cin.tie(NULL); 
  
#define ff first
#define ss second
#define pb push_back
#define pf push_front
#define mp make_pair
#define pu push
#define pp pop_back
#define in insert
#define ld long double


#define TRACE
#ifdef TRACE
#define trace(...) __f(#__VA_ARGS__, __VA_ARGS__)
template <typename Arg1>
void __f(const char* name, Arg1&& arg1){
  cerr << name << " : " << arg1 << std::endl;
}
template <typename Arg1, typename... Args>
void __f(const char* names, Arg1&& arg1, Args&&... args){
  const char* comma = strchr(names + 1, ',');cerr.write(names, comma - names) << " : " << arg1<<" | ";__f(comma+1, args...);
}
#else
#define trace(...) 1
#endif
template<class T> ostream& operator<<(ostream &os, vector<T> V) {os << "[ "; for(auto v : V) os << v << " "; return os << "]";}
template<class L, class R> ostream& operator<<(ostream &os, pair<L,R> P) {return os << "(" << P.first << "," << P.second << ")";}
  
typedef long long int ll;
  
typedef vector<int> vi;
typedef vector<ll> vl;
typedef vector<vi> vvi;
typedef vector<vl> vvl;
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;
typedef vector<pii> vpii;
typedef vector<pll> vpll;
const ll mod =998244353;
const ll maxn=1000001;
const ll LOGMAXN=30;
ll power(ll x, ll n) {
      ll res = 1;
      for (; n > 0; n >>= 1) {
        if (n & 1) res = (res * x) % mod;
        x = (x * x) % mod;
      }
      return res;
}

int main()
{
  
  IOS
  ll n;
  cin>>n;
  string s;
  cin>>s;
  set<string> s1,s2,s3;
  for(ll i=0;i<n;i++)
  { 
    string temp="";
    temp+=s[i];
    for(auto y:s2)
    {
      s3.in(y+temp);
    }
    for(auto x:s1)
    {
      s2.in(x+temp);
    }
    s1.in(temp);
  }
  cout<<s3.size();

}