Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;
const long double PI = acos(-1);
typedef long long ll;
typedef pair<int64_t,int64_t> pll;
int dx[]={1,-1,0,0,1,-1,1,-1};
int dy[]={0,0,1,-1,1,-1,-1,1};
#define INF (2147483647)
#define mod (1000000007)
#define limit (7368791)
#define rep(i,a,b) for (int64_t i = (a); i < (b); i++)
#define REP(i,n) rep(i,0,n)
#define ALL(a) begin(a),end(a)
#define sz(s) (s).size()
#define pb push_back
#define mp make_pair
#define fi first
#define se second


void solve(){
    ll w,N;cin>>N;
    rep(i,1,3510)rep(j,1,3510){
        if((4*i*j-N*i-N*j)==0)continue;
        w=(N*i*j)/(4*i*j-N*i-N*j);
        if(4*i*j*w==N*(i*j+w*j+w*i)){cout<<i<<" "<<j<<" "<<w<<endl;return;}
    }
}
int main()
{
    cin.tie(0);
	ios::sync_with_stdio(false);
    solve();
    return 0;
}