Problem:
Score : 200 points

Problem Statement

There are some animals in a garden. Each of them is a crane with two legs or a turtle with four legs.

Takahashi says: "there are X animals in total in the garden, and they have Y legs in total." Determine whether there is a combination of numbers of cranes and turtles in which this statement is correct.

Constraints

1 \leq X \leq 100

1 \leq Y \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

If there is a combination of numbers of cranes and turtles in which the statement is correct, print Yes; otherwise, print No.

Sample Input 1

3 8

Sample Output 1

Yes

The statement "there are 3 animals in total in the garden, and they have 8 legs in total" is correct if there are two cranes and one turtle. Thus, there is a combination of numbers of cranes and turtles in which the statement is correct.

Sample Input 2

2 100

Sample Output 2

No

There is no combination of numbers of cranes and turtles in which this statement is correct.

Sample Input 3

1 2

Sample Output 3

Yes

We also consider the case in which there are only cranes or only turtles.

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
#define rep(i,n) for(int (i)=0;(i)<(int)(n);(i)++)
#define REP(i,n) for(int (i)=0;(i)<=(int)(n);(i)++)
#define rep1(i,x,n) for(int (i)=(x);(i)<(int)(n);(i)++)
#define REP1(i,x,n) for(int (i)=(x);(i)<=(int)(n);(i)++)
#define rrep(i,x) for(int i=((int)(x)-1);i>=0;i--)
using namespace std;
using ll = long long;
using ull = unsigned long long;
using Int = long long;

//INT_MAX = 2147483647;
//LLONG_MAX = 9223372036854775807;
//ULLONG_MAX = 18446744073709551615;
const int MOD = 1000000007;
const ll INF = numeric_limits<ll>::max();
const int inf = 1e8;
typedef pair<int,int> P;
typedef std::priority_queue<int> IntPrioQueue;
typedef std::priority_queue<int, std::vector<int>, std::greater<int> > IntReversePrioQueue;

//少数点表示
//cout << std::fixed << std::setprecision(14) << 値

int main(){
    cin.tie( 0 ); ios::sync_with_stdio( false );
    int x,y;
    cin >> x >> y;
    bool flag = false;
    REP1(i,1,x){
        if(2*i+4*(x-i)==y) flag = true;
    }

    if(flag) cout << "Yes";
    else cout << "No";
    
    
    
    return 0;
}