Problem:
Score : 200 points

Problem Statement

A shop sells N kinds of fruits, Fruit 1, \ldots, N, at prices of p_1, \ldots, p_N yen per item, respectively. (Yen is the currency of Japan.)

Here, we will choose K kinds of fruits and buy one of each chosen kind. Find the minimum possible total price of those fruits.

Constraints

1 \leq K \leq N \leq 1000

1 \leq p_i \leq 1000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
p_1 p_2 \ldots p_N

Output

Print an integer representing the minimum possible total price of fruits.

Sample Input 1

5 3
50 100 80 120 80

Sample Output 1

210

This shop sells Fruit 1, 2, 3, 4, and 5 for 50 yen, 100 yen, 80 yen, 120 yen, and 80 yen, respectively.

The minimum total price for three kinds of fruits is 50 + 80 + 80 = 210 yen when choosing Fruit 1, 3, and 5.

Sample Input 2

1 1
1000

Sample Output 2

1000

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
#define ll long long int
#define ss second
#define ff first
#define Mem(x,val) memset(x,val,sizeof x)
#define pb push_back
#define all(v) v.begin(),v.end()
#define unik(v)  v.erase(unique(v.begin(),v.end()),v.end())
#define cerr(x) cerr << __LINE__ << " th Line : " << #x << " = " << x << "\n"
#define debug(a,b) cerr << #a<<" = "<<a<<"   |   "<<#b<<" = "<<b<<'\n'
#define endl '\n'
#define SZ(a) ((int)a.size())
using namespace std;
typedef pair<int, int> pi32;
typedef pair<ll, ll> pi64;
typedef vector<int> vi32;
typedef vector<ll> vi64;
typedef vector<pi32> vp32;
typedef vector<pi64> vp64;
const ll mod = 1e9 + 7;
const int MX = 2e5+7;

int main()
{
	ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
	
	int n,k;cin>>n>>k;
	vi32 p(n);
	for(int &x:p)cin>>x;
	sort(all(p));
	int sum=0;
	for(int i=0;i<k;i++)sum+=p[i];
	cout<<sum<<endl;
	
	return 0;
}