Problem:
Score : 100 points

Problem Statement

In the Kingdom of AtCoder, people use a language called Taknese, which uses lowercase English letters.

In Taknese, the plural form of a noun is spelled based on the following rules:

If a noun's singular form does not end with s, append s to the end of the singular form.

If a noun's singular form ends with s, append es to the end of the singular form.

You are given the singular form S of a Taknese noun. Output its plural form.

Constraints

S is a string of length 1 between 1000, inclusive.

S contains only lowercase English letters.

Input

Input is given from Standard Input in the following format:

S

Output

Print the plural form of the given Taknese word.

Sample Input 1

apple

Sample Output 1

apples

apple ends with e, so its plural form is apples.

Sample Input 2

bus

Sample Output 2

buses

bus ends with s, so its plural form is buses.

Sample Input 3

box

Sample Output 3

boxs

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;

#define IOS ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);
#define ll long long
#define pb push_back
#define fi first
#define se second
#define all(x) (x).begin(),(x).end()
#define S(x) (int)(x).size()
#define L(x) (int)(x).length()
#define ld long double
#define mem(x,y) memset(x,y,sizeof x)

#include<ext/pb_ds/assoc_container.hpp>
#include<ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
typedef tree<int , null_type , less<int> , rb_tree_tag , tree_order_statistics_node_update> ordered_set;

const int mod = 1e9+7;
const ll infl = 0x3f3f3f3f3f3f3f3fLL;
const int infi = 0x3f3f3f3f;

void solve()
{
	string s;
	cin>>s;
	cout<<s;
	if(s.back()!='s') cout<<'s';
	else cout<<"es";
}

int main()
{
	IOS
	int t=1;
	//cin>>t;
	while(t--)
	{
		solve();
	}
}