Problem:
Score : 700 points

Problem Statement

You are given four integers: H, W, h and w (1 ≤ h ≤ H, 1 ≤ w ≤ W).
Determine whether there exists a matrix such that all of the following conditions are held, and construct one such matrix if the answer is positive:

The matrix has H rows and W columns.

Each element of the matrix is an integer between -10^9 and 10^9 (inclusive).

The sum of all the elements of the matrix is positive.

The sum of all the elements within every subrectangle with h rows and w columns in the matrix is negative.

Constraints

1 ≤ h ≤ H ≤ 500

1 ≤ w ≤ W ≤ 500

Input

Input is given from Standard Input in the following format:

H W h w

Output

If there does not exist a matrix that satisfies all of the conditions, print No.

Otherwise, print Yes in the first line, and print a matrix in the subsequent lines in the following format:

a_{11} ... a_{1W}
:
a_{H1} ... a_{HW}

Here, a_{ij} represents the (i,\ j) element of the matrix.

Sample Input 1

3 3 2 2

Sample Output 1

Yes
1 1 1
1 -4 1
1 1 1

The sum of all the elements of this matrix is 4, which is positive.
Also, in this matrix, there are four subrectangles with 2 rows and 2 columns as shown below. For each of them, the sum of all the elements inside is -1, which is negative.

Sample Input 2

2 4 1 2

Sample Output 2

No

Sample Input 3

3 4 2 3

Sample Output 3

Yes
2 -5 8 7
3 -5 -4 -5
2 1 -1 7

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
 
using namespace std;
 
const int X = 2;
 
int a[1234][1234];
 
int main() {
  int H, W, h, w;
  cin >> H >> W >> h >> w;
  for (int i = 0; i < H; i++) {
    for (int j = 0; j < W; j++) {
      if (i % h == h - 1 && j % w == w - 1) {
        a[i][j] = -X * (h * w - 1) - 1;
      } else {
        a[i][j] = X;
      }
    }
  }
  long long total = 0;
  for (int i = 0; i < H; i++) {
    for (int j = 0; j < W; j++) {
      total += a[i][j];
    }
  }
  if (total <= 0) {
    puts("No");
    return 0;
  }
  puts("Yes");
  for (int i = 0; i < H; i++) {
    for (int j = 0; j < W; j++) {
      if (j > 0) putchar(' ');
      printf("%d", a[i][j]);
    }
    printf("\n");
  }
  return 0;
}