Problem:
﻿Score: 100 points

Problem Statement

In AtCoder city, there are five antennas standing in a straight line. They are called Antenna A, B, C, D and E from west to east, and their coordinates are a, b, c, d and e, respectively.

Two antennas can communicate directly if the distance between them is k or less, and they cannot if the distance is greater than k.

Determine if there exists a pair of antennas that cannot communicate directly.

Here, assume that the distance between two antennas at coordinates p and q (p < q) is q - p.

Constraints

a, b, c, d, e and k are integers between 0 and 123 (inclusive).

a < b < c < d < e

Input

Input is given from Standard Input in the following format:

a
b
c
d
e
k

Output

Print :( if there exists a pair of antennas that cannot communicate directly, and print Yay! if there is no such pair.

Sample Input 1

1
2
4
8
9
15

Sample Output 1

Yay!

In this case, there is no pair of antennas that cannot communicate directly, because:

the distance between A and B is 2 - 1 = 1

the distance between A and C is 4 - 1 = 3

the distance between A and D is 8 - 1 = 7

the distance between A and E is 9 - 1 = 8

the distance between B and C is 4 - 2 = 2

the distance between B and D is 8 - 2 = 6

the distance between B and E is 9 - 2 = 7

the distance between C and D is 8 - 4 = 4

the distance between C and E is 9 - 4 = 5

the distance between D and E is 9 - 8 = 1

and none of them is greater than 15. Thus, the correct output is Yay!.

Sample Input 2

15
18
26
35
36
18

Sample Output 2

:(

In this case, the distance between antennas A and D is 35 - 15 = 20 and exceeds 18, so they cannot communicate directly.
Thus, the correct output is :(.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>

#define int long long
#define uint unsigned int
#define pii pair<int, int>

#define FOR(i,a,b) for(int i=(a);i<(b);++i)
#define FORR(i,a,b) for(int i=(a);i>=(b);--i)
#define REP(i,n) FOR(i,0,n)
#define REPR(i,n) FORR(i,n,0)
#define ALL(c) ((c).begin()), ((c).end())

#define PB(a) push_back(a)
#define EMPB(...) emplace_back(__VA_ARGS__)
#define EMP(...) emplace(__VA_ARGS__)
#define MP(a,b) make_pair(a,b)
#define MT(...) make_tuple(__VA_ARGS__)

#define ZERO(a) memset(a,0,sizeof(a))
#define MINUS(a) memset(a,0xff,sizeof(a))
#define MINF(a) memset(a,0x3f,sizeof(a))

#define PW(n) (1LL << (n))

using namespace std;

template <class T> inline bool CHMIN(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }
template <class T> inline bool CHMAX(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
template <class T> inline void SORT(T &a) { sort(a.begin(), a.end()); }
template <class T> inline void REV(T &a) { reverse(a.begin(), a.end()); }
template <class T> inline void UNI(T &a) { sort(a.begin(), a.end()); a.erase(unique(a.begin(), a.end()), a.end()); }

template <class S, class T> ostream& operator << (ostream& os, const pair<S, T> v) {
  os << "(" << v.first << ", " << v.second << ")"; return os;
}

const int MOD = 1000000007;
const int INF = 0x3f3f3f3f3f3f3f3f;
const double EPS = 1e-10;

/* ---------------------------------------------------------------------------------------------------- */

int a[5];
int k;

signed main() {
  cin.tie(0);
  ios_base::sync_with_stdio(false);
  cout << fixed << setprecision(10);
  
  REP(i, 5) cin >> a[i];
  cin >> k;
  sort(a, a+5);
  cout << (a[4]-a[0] <= k ? "Yay!" : ":(") << endl;

  return 0;
}