Problem:
Score : 200 points

Problem Statement

For a string S consisting of the uppercase English letters P and D, let the doctoral and postdoctoral quotient of S be the total number of occurrences of D and PD in S as contiguous substrings. For example, if S = PPDDP, it contains two occurrences of D and one occurrence of PD as contiguous substrings, so the doctoral and postdoctoral quotient of S is 3.

We have a string T consisting of P, D, and ?.

Among the strings that can be obtained by replacing each ? in T with P or D, find one with the maximum possible doctoral and postdoctoral quotient.

Constraints

1 \leq |T| \leq 2 \times 10^5

T consists of P, D, and ?.

Input

Input is given from Standard Input in the following format:

T

Output

Print one string with the maximum possible doctoral and postdoctoral quotient among the strings that can be obtained by replacing each ? in T with P or D.
If there are multiple such strings, you may print any of them.

Sample Input 1

PD?D??P

Sample Output 1

PDPDPDP

This string contains three occurrences of D and three occurrences of PD as contiguous substrings, so its doctoral and postdoctoral quotient is 6, which is the maximum doctoral and postdoctoral quotient of a string obtained by replacing each ? in T with P or D.

Sample Input 2

P?P?

Sample Output 2

PDPD

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;
#define ll long long 
// memo  fixed  setprecision(20);
using vvll = vector<vector<ll>>;
ll mod =1e9+7;
/*"itob" int to "N"base */           template<typename TypeInt> string itob(const TypeInt v, int base){static const char table[] = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ";string ret;static numeric_limits<TypeInt> t;TypeInt n = v;if (t.is_signed) {if (v < 0) n *= -1;}while (n >= base) {ret += table[n%base];n /= base;}ret += table[n];if (t.is_signed) {if (v < 0 && base == 10) ret += '-';}reverse(ret.begin(), ret.end());return ret;}
/*"chmin" a = MAX*/                  template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return true; } return false; }
/*"chmax" a = MIN*/                  template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return true; } return false; }
/*"ctoi"  char to int*/              int ctoi(char c) {return c-'0';}
/*"gcd"   MAX Euclidean */           ll gcd(ll a,ll b){if(b==0)return a; return gcd(b,a%b);}
    /*"lcm"   MIN*/                      ll lcm(ll a,ll b){ll g = gcd(a,b);return a/g*b;}
/*"primecheck"If prime,return true.*/bool primecheck(ll n){if(n < 2) return false;else{for(int i = 2; i * i <= n; i++){if(n % i == 0) return false;}return true;}}
string  reverserange(string s,ll a,ll b){reverse(s.begin()+a-1,s.begin()+b); return s;}
ll modpow(ll a,ll n, ll mod){ll res = 1;while(n>0){if (n%2==1){res = res * a % mod;}a = a * a % mod;n/=2;}return res;}
int main() {
    string t;
    cin >> t;
    for(int i=0;i<t.size();i++){
        if(t.at(i)=='?'){
            t.at(i)='D';
        }
    }
    cout<<t<<endl;
}