Problem:
Score: 100 points

Problem Statement

M-kun is a competitor in AtCoder, whose highest rating is X.

In this site, a competitor is given a kyu (class) according to his/her highest rating. For ratings from 400 through 1999, the following kyus are given:

From 400 through 599: 8-kyu

From 600 through 799: 7-kyu

From 800 through 999: 6-kyu

From 1000 through 1199: 5-kyu

From 1200 through 1399: 4-kyu

From 1400 through 1599: 3-kyu

From 1600 through 1799: 2-kyu

From 1800 through 1999: 1-kyu

What kyu does M-kun have?

Constraints

400 \leq X \leq 1999

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print the kyu M-kun has, as an integer.
For example, if he has 8-kyu, print 8.

Sample Input 1

725

Sample Output 1

7

M-kun's highest rating is 725, which corresponds to 7-kyu.

Thus, 7 is the correct output.

Sample Input 2

1600

Sample Output 2

2

M-kun's highest rating is 1600, which corresponds to 2-kyu.

Thus, 2 is the correct output.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define rep(i, n) for (int i = 0; i < (int)(n); ++i)
#define rrep(i,n) for (int i = (int)(n)-1; i>=0; --i)
#define For(i,a,b) for(auto i=(a);i<=(b);++i)
#define rFor(i,a,b) for(auto i=(b);i>=(a);--i)
#define call(var) cerr<<#var<<"="<<var<<"\n";
#define dup(x,y) (((x)+(y)-1)/(y))
#define all(x) (x).begin(),(x).end()
using ll=long long;
using vi = vector<int>;
using vl = vector<ll>;
using vb = vector<bool>;
using Graph = vector<vi>;
using P = pair<int,int>;
const int MOD=(int)1e9+7;
const int INF=(int)1e9;
const ll LINF=(ll)1e18;
const double pi = acos(-1);
template<class t,class u> inline bool chmax(t&a,u b){if(a<b){a=b;return true;}return false;}
template<class t,class u> inline bool chmin(t&a,u b){if(b<a){a=b;return true;}return false;}
template<class T> istream& operator>>(istream& is, vector<T>& a){rep(i,a.size()) is >> a[i]; return is;}
template<class T> ostream& operator<<(ostream& os, vector<T>& a){rep(i,a.size()) os << a[i] << " "; return os;}
template<class T, class U> istream& operator>>(istream& is, pair<T,U>& p){is >> p.first >> p.second; return is;}
template<class T, class U> ostream& operator<<(ostream& os, const pair<T,U>& p){os << "("<< p.first << "," << p.second << ")"; return os;}
template<class T, class U> ostream& operator<<(ostream& os, const map<T,U>& mp){for(auto& t : mp) os << t.first << " " << t.second << "\n"; return os;}

int main(){
    int x;cin >> x;
    cout << 10 - x/200 << endl;
}