Problem:
Score : 400 points

Problem Statement

Given are three integers N, K, and S.

Find a sequence A_1, A_2, ..., A_N of N integers between 1 and 10^9 (inclusive) that satisfies the condition below.
We can prove that, under the conditions in Constraints, such a sequence always exists.

There are exactly K pairs (l, r) of integers such that 1 \leq l \leq r \leq N and A_l + A_{l + 1} + \cdots + A_r = S.

Constraints

1 \leq N \leq 10^5

0 \leq K \leq N

1 \leq S \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K S

Output

Print a sequence satisfying the condition, in the following format:

A_1 A_2 ... A_N

Sample Input 1

4 2 3

Sample Output 1

1 2 3 4

Two pairs (l, r) = (1, 2) and (3, 3) satisfy the condition in the statement.

Sample Input 2

5 3 100

Sample Output 2

50 50 50 30 70

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <algorithm>
#include <string.h>
#include <stdio.h>
#include <queue>
#include <math.h>
using namespace std;
typedef long long ll;
int main()
{
    ll m,n,k,s,i,H,W,ans=0;
    scanf("%lld%lld%lld",&n,&k,&s);
    if(s!=1000000000)
    {
        for(i=1; i<=k; i++)
            printf("%lld ",s);
        for(i=1; i<=n-k; i++)
        {
            printf("1000000000");
            if(i!=n-k)
                printf(" ");
        }
    }
    else
    {
         for(i=1; i<=k; i++)
            printf("%lld ",s);
        for(i=1; i<=n-k; i++)
        {
            printf("1");
            if(i!=n-k)
                printf(" ");
        }
    }


}