Problem:
Score : 100 points

Problem Statement

There are a total of A + B cats and dogs.
Among them, A are known to be cats, but the remaining B are not known to be either cats or dogs.

Determine if it is possible that there are exactly X cats among these A + B animals.

Constraints

1 \leq A \leq 100

1 \leq B \leq 100

1 \leq X \leq 200

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B X

Output

If it is possible that there are exactly X cats, print YES; if it is impossible, print NO.

Sample Input 1

3 5 4

Sample Output 1

YES

If there are one cat and four dogs among the B = 5 animals, there are X = 4 cats in total.

Sample Input 2

2 2 6

Sample Output 2

NO

Even if all of the B = 2 animals are cats, there are less than X = 6 cats in total.

Sample Input 3

5 3 2

Sample Output 3

NO

Even if all of the B = 3 animals are dogs, there are more than X = 2 cats in total.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<iostream>
#include<math.h>
#include <algorithm>
#include<float.h>
#include <limits>
#include <vector> 
#include <numeric>
#include <string.h>

#define rep(i,a,n) for(ll int (i) = (a);(i) < (n);(i)++)
#define urep(i,a,n) for(ll int (i) = (a);(i) > (n);(i)--)
#define MOD 1000000007
#define ll long long

using namespace::std;

int jo(ll int jxo, ll int jyo){
	ll int jhogeo = 1;
	rep(jinto,0,jyo) jhogeo=jhogeo*jxo;
	return jhogeo;
}
char tobig(char toxbig){
  return (toxbig-0x20);
}
char tolow(char toxlow){
  return (toxlow+0x20);
}
  


int main(){
  int a,b,c;
  cin>>a>>b>>c;
  if((a<=c)&&(c<=a+b)) cout<<"YES";
  else cout<<"NO";


}
// int *p = new int[N];

//  vector<int> 変数名(要素数);
//  sort(変数名.begin(),変数名.end());//昇順ソート

// vector<vector<int>> 変数名(左の個数, vector<int>(右の個数));

//