Problem:
Score : 200 points

Problem Statement

Rng is preparing a problem set for a qualification round of CODEFESTIVAL.

He has N candidates of problems. The difficulty of the i-th candidate is D_i.

There must be M problems in the problem set, and the difficulty of the i-th problem must be T_i. Here, one candidate of a problem cannot be used as multiple problems.

Determine whether Rng can complete the problem set without creating new candidates of problems.

Constraints

1 \leq N \leq 200,000

1 \leq D_i \leq 10^9

1 \leq M \leq 200,000

1 \leq T_i \leq 10^9

All numbers in the input are integers.

Partial Score

100 points will be awarded for passing the test set satisfying N \leq 100 and M \leq 100.

Input

Input is given from Standard Input in the following format:

N
D_1 D_2 ... D_N
M
T_1 T_2 ... T_M

Output

Print YES if Rng can complete the problem set without creating new candidates of problems; print NO if he cannot.

Sample Input 1

5
3 1 4 1 5
3
5 4 3

Sample Output 1

YES

Sample Input 2

7
100 200 500 700 1200 1600 2000
6
100 200 500 700 1600 1600

Sample Output 2

NO

Not enough 1600s.

Sample Input 3

1
800
5
100 100 100 100 100

Sample Output 3

NO

Sample Input 4

15
1 2 2 3 3 3 4 4 4 4 5 5 5 5 5
9
5 4 3 2 1 2 3 4 5

Sample Output 4

YES

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define rep(i, n) for(int i = 0; i < (int)(n); i++)

int n, m, d[500000], t[500000];

int main(){
  cin >> n;
  rep(i, n){
    cin >> d[i];
  }
  cin >> m;
  rep(i, n){
    cin >> t[i];
  }
  sort(d, d + n);
  sort(t, t + m);
  //rep(i, n) cerr << d[i] << endl; cerr << endl; rep(i, m) cerr << t[i] << endl;
  int itr = 0;
  bool flag = true;
  rep(i, m){
    while(true){
      cerr << t[i] <<" "<< d[itr] << endl;
      if(t[i] < d[itr] || itr >= n){
        flag = false;
        break;
      }
      if(t[i] == d[itr]){
        itr++;
        break;
      }
      itr++;
    }
    if(!flag){
      break;
    }
  }
  if(flag){
    cout << "YES" << endl;
  }else{
    cout << "NO" << endl;
  }
  return 0;
}