Problem:
Score : 200 points

Problem Statement

Given are two strings S and T.

Let us change some of the characters in S so that T will be a substring of S.

At least how many characters do we need to change?

Here, a substring is a consecutive subsequence. For example, xxx is a substring of yxxxy, but not a substring of xxyxx.

Constraints

The lengths of S and T are each at least 1 and at most 1000.

The length of T is at most that of S.

S and T consist of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

Print the minimum number of characters in S that need to be changed.

Sample Input 1

cabacc
abc

Sample Output 1

1

For example, changing the fourth character a in S to c will match the second through fourth characters in S to T.

Since S itself does not have T as its substring, this number of changes - one - is the minimum needed.

Sample Input 2

codeforces
atcoder

Sample Output 2

6

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>

using namespace std;

typedef unsigned long long ull;
typedef long long ll;
typedef pair<int, int> ii;
typedef vector<ii> vii;
typedef vector<int> vi;
typedef vector<ll> vll;

#define PI (2*acos(0.0))
#define eps 1e-9
#define pb push_back
#define endl "\n"
#define watch(x) cout << (#x) << " is " << (x) << endl;
#define show(v) for(int fi = 0; fi < v.size(); fi++) cout << v[fi] << " "; cout << endl;
#define showpair(v) for(int fi = 0; fi < v.size(); fi++) cout << v[fi].first << " " << v[fi].second << endl;
#define ff first
#define ss second
#define fu cout << "lol" << endl;
#define precision(n) cout << fixed << setprecision(n);
#define lb lower_bound
#define up upper_bound
#define vscan for(i = 0;i<n;i++){cin>>in; v.pb(in);}
#define all(a) a.begin(), a.end()
#define min3(a,b,c) min(a,min(b,c))
#define max3(a,b,c) max(a,max(b,c))
#define mem(a,val) memset(a,val,sizeof(a))
#define loop(i,n) for(i = 0; i < n; i++)
#define TC ull T; cin>>T; while(T--)
#define IN(x) {scanf("%d",&x);}
#define LL(x) {scanf("%lld",&x);}
#define CC(x) {scanf("%c",&x);}
#define pfl(x) printf("%d\n",x)
#define pfll(x) printf("%lld\n",x)
#define newl puts("")
#define space printf(" ")
#define MOD 1000000007
#define speed ios_base::sync_with_stdio(false); cin.tie(NULL);


int main()
{
    int i = 0, j = 0, cs = 0, in;
    string s, t; cin>>s>>t;
    int ans = INT_MAX;
    for(i = 0; i < s.size() - t.size() + 1; i++){
        int cnt = 0;
        for(j = 0; j < t.size(); j++){
            if(t[j] != s[i+j]) cnt++;
        }
        ans = min(ans, cnt);
    }
    cout << ans << endl;
    return 0;
}