Problem:
Score : 300 points

Problem Statement

Sitting in a station waiting room, Joisino is gazing at her train ticket.

The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).

In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.

The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Constraints

0≤A,B,C,D≤9

All input values are integers.

It is guaranteed that there is a solution.

Input

Input is given from Standard Input in the following format:

ABCD

Output

Print the formula you made, including the part =7.

Use the signs + and -.

Do not print a space between a digit and a sign.

Sample Input 1

1222

Sample Output 1

1+2+2+2=7

This is the only valid solution.

Sample Input 2

0290

Sample Output 2

0-2+9+0=7

0 - 2 + 9 - 0 = 7 is also a valid solution.

Sample Input 3

3242

Sample Output 3

3+2+4-2=7

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;

int main() {

    int n;

    cin >> n;

    int a,b,c,d;

    d = n%10;
    n /= 10;
    c = n%10;
    n /= 10;
    b = n%10;
    n /= 10;
    a = n%10;
    char op[3];

    if(a+b+c+d == 7){
        op[0] = '+';
        op[1] = '+';
        op[2] = '+';
    }
    else if(a+b+c-d == 7){
        op[0] = '+';
        op[1] = '+';
        op[2] = '-';
    }
    else if(a+b-c+d == 7){
        op[0] = '+';
        op[1] = '-';
        op[2] = '+';
    }
    else if(a+b-c-d == 7){
        op[0] = '+';
        op[1] = '-';
        op[2] = '-';
    }
    else if(a-b+c+d == 7){
        op[0] = '-';
        op[1] = '+';
        op[2] = '+';
    }
    else if(a-b+c-d == 7){
        op[0] = '-';
        op[1] = '+';
        op[2] = '-';
    }
    else if(a-b-c+d == 7){
        op[0] = '-';
        op[1] = '-';
        op[2] = '+';
    }
    else if(a-b-c-d == 7){
        op[0] = '-';
        op[1] = '-';
        op[2] = '-';
    }

    cout << a << op[0] << b << op[1] << c << op[2] << d << "=7" << endl;

    return 0;
}