Problem:
Score : 200 points

Problem Statement

Let S(n) denote the sum of the digits in the decimal notation of n.
For example, S(101) = 1 + 0 + 1 = 2.

Given an integer N, determine if S(N) divides N.

Constraints

1 \leq N \leq 10^9

Input

Input is given from Standard Input in the following format:

N

Output

If S(N) divides N, print Yes; if it does not, print No.

Sample Input 1

12

Sample Output 1

Yes

In this input, N=12.
As S(12) = 1 + 2 = 3, S(N) divides N.

Sample Input 2

101

Sample Output 2

No

As S(101) = 1 + 0 + 1 = 2, S(N) does not divide N.

Sample Input 3

999999999

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<iostream>
#include<string>
#include<algorithm>
#include<vector>
#include<cmath>
#include<climits>
#include<cstdlib>
#define ll long long
using namespace std;
int main() {
	ll sum=0,n;
	string s;
	cin >> s;
	n = stoi(s);//文字列から数値に変換
	for (ll i = 0; i < s.size(); i++) {
		sum += s[i]-'0';
	}
	if (n%sum == 0) {
		cout << "Yes" << endl;
	}
	else {
		cout << "No" << endl;
	}
}