Problem:
Score : 200 points

Problem Statement

An integer X is called a Harshad number if X is divisible by f(X), where f(X) is the sum of the digits in X when written in base 10.

Given an integer N, determine whether it is a Harshad number.

Constraints

1?N?10^8

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

Print Yes if N is a Harshad number; print No otherwise.

Sample Input 1

12

Sample Output 1

Yes

f(12)=1+2=3. Since 12 is divisible by 3, 12 is a Harshad number.

Sample Input 2

57

Sample Output 2

No

f(57)=5+7=12. Since 57 is not divisible by 12, 12 is not a Harshad number.

Sample Input 3

148

Sample Output 3

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include "bits/stdc++.h"

#define rep(a,b) for(int a = 0;a < b;a++)
#define REP(i, x, n) for(int i = x; i < n; i++)
#define P(a) cout << a << endl
#define pb(a) push_back(a)
#define mp(a,b) make_pair(a,b)
#define ssort(v) sort(v.begin(),v.end())
#define rev(v) reverse(v.begin(),v.end())
#define vP(v) for(int i = 0;i < v.size();i++){cout << v[i];if(i != v.size()-1)cout << endl;}
#define vcin(v,n) rep(i,n){int a;cin >> a;v.pb(a);}

using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef vector<int> vi;
int dx[] = { 1, -1 , 0 , 0 };
int dy[] = { 0,  0,  1, -1 };
//int dx[] = { 1, 0 };
//int dy[] = { 0, 1 };
#define mod7 1e9+7;
#define mod9 1e9+9;
const ll INFLL = 999999999999999;

//int nextInt(){
//	int a;	cin >> a;return a;
//}
//string next(){
//	string s;cin >> s;return s;
//}
//char nextChar(){
//	char c;cin >> c;return c;
//}
int s2i(string str) {int ret;stringstream ss; ss << str;ss >> ret;return ret;}

void solve(){
	string s;
	cin >> s;
	int num = s2i(s);
	int sum = 0;
	rep(i,s.length()){
		sum += (int)(s[i]-'0');
	}
	if(num % sum == 0){
		P("Yes");
	}else{
		P("No");
	}
}

int main() {
	solve();
	return 0;
}