Problem:
Score : 200 points

Problem Statement

Let us define the FizzBuzz sequence a_1,a_2,... as follows:

If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.

If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.

If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.

If none of the above holds, a_i=i.

Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Constraints

1 \leq N \leq 10^6

Input

Input is given from Standard Input in the following format:

N

Output

Print the sum of all numbers among the first N terms of the FizzBuzz sequence.

Sample Input 1

15

Sample Output 1

60

The first 15 terms of the FizzBuzz sequence are:

1,2,\mbox{Fizz},4,\mbox{Buzz},\mbox{Fizz},7,8,\mbox{Fizz},\mbox{Buzz},11,\mbox{Fizz},13,14,\mbox{FizzBuzz}

Among them, numbers are 1,2,4,7,8,11,13,14, and the sum of them is 60.

Sample Input 2

1000000

Sample Output 2

266666333332

Watch out for overflow.

Solution in C++ (Clang 10.0.0) (judge verdict: Accepted)

#include<iostream>
#include<cstring>
#include<algorithm>
#include<cmath>
#define mm(a,x) memset(a,x,sizeof(a))
#define sync std::ios::sync_with_stdio(false);std::cin.tie(0)
#define ll long long
using namespace std;
int main(void)
{
    sync;
    int n;
    cin>>n;
    ll sum=0;
    for(int i=1;i<=n;++i)
        if(i%3!=0&&i%5!=0)
            sum+=i;
    cout<<sum<<endl;
    return 0;
}