Problem:
Score : 300 points

Problem Statement

There are N people living on a number line.

The i-th person lives at coordinate X_i.

You are going to hold a meeting that all N people have to attend.

The meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.

Find the minimum total points of stamina the N people have to spend.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq X_i \leq 100

Input

Input is given from Standard Input in the following format:

N
X_1 X_2 ... X_N

Output

Print the minimum total stamina the N people have to spend.

Sample Input 1

2
1 4

Sample Output 1

5

Assume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.

Note that you can hold the meeting only at an integer coordinate.

Sample Input 2

7
14 14 2 13 56 2 37

Sample Output 2

2354

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>

using Int = int;
using namespace std;

#define ARC(i, a, b) for(Int i = (a); i < (b); ++i)
#define RC(i, n) ARC(i, 0, n)
#define ARCH(i, a, b) for(Int i = (a) - 1; i >= (b); --i)
#define RCH(i, n) ARCH(i, n, 0)
template<class T> T ant(const T &a, const T &b){ return a > b ? a : b; };
template<class T> T ont(const T &a, const T &b){ return a < b ? a : b; };
template<class T> T th(T &a, const T &b, T (*f)(const T &, const T &)){ a = f(a, b); }
#define anth(a, b) th(a, b, ant)
#define onth(a, b) th(a, b, ont)

int main(){
	int n;
	int x[112];
	cin >> n;
	RC(i, n) cin >> x[i];
	int av = 0;
	RC(i, n) av += x[i];
	av /= n;
	int ans1 = 0;
	RC(i, n) ans1 += (x[i] - av) * (x[i] - av);
	++av;
	int ans2 = 0;
	RC(i, n) ans2 += (x[i] - av) * (x[i] - av);
	cout << ont(ans1, ans2) << endl;
}