Problem:
Score : 200 points

Problem Statement

The word internationalization is sometimes abbreviated to i18n.
This comes from the fact that there are 18 letters between the first i and the last n.

You are given a string s of length at least 3 consisting of lowercase English letters.
Abbreviate s in the same way.

Constraints

3 ≤ |s| ≤ 100 (|s| denotes the length of s.)

s consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s

Output

Print the abbreviation of s.

Sample Input 1

internationalization

Sample Output 1

i18n

Sample Input 2

smiles

Sample Output 2

s4s

Sample Input 3

xyz

Sample Output 3

x1z

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <cstdio>
#include <cstdlib>
#include <iostream>
#include <algorithm>
#include <cstring>
#include <vector>
#include <map>
#include <cmath>
 
#define rep(i,n) for(int i = 0;i < (n);i++)
#define all(x) (x).begin(),(x).end()
#define pb(x) push_back(x)
#define mp(a,b) make_pair(a,b)

using namespace std;

typedef long long int ll;
typedef vector<int> vi;
typedef vector<vi> vvi;
typedef vector<ll> vl;
typedef vector<pair<int, int> > vpi;
typedef vector<pair<ll, ll> > vpl;

int main(){
	cin.tie(0);
	ios::sync_with_stdio(false);
  string s;
  cin >> s;
	cout << s[0] << (int)s.size()-2 << s[s.size()-1] << endl;
	return 0;
}