Problem:
Score : 100 points

Problem Statement

A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.

Given a string S, determine whether it is coffee-like.

Constraints

S is a string of length 6 consisting of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S

Output

If S is coffee-like, print Yes; otherwise, print No.

Sample Input 1

sippuu

Sample Output 1

Yes

In sippuu, the 3-rd and 4-th characters are equal, and the 5-th and 6-th characters are also equal.

Sample Input 2

iphone

Sample Output 2

No

Sample Input 3

coffee

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

/*
	Name:
	Author: xiaruize
	Date:
*/

#include<bits/stdc++.h>
using namespace std;
#define ull unsigned long long
#define MOD 1000000007
#define ALL(a) (a).begin(), (a).end()
#define forn(i, n) for (int i = 0; i < int(n); i++)
#define ll long long
#define form(i,j,n) for(int i=int(j);i<=int(n);i++)
#define pb push_back
#define mk make_pair
#define pii pair<int,int>
#define pis pair<int,string>
#define sec second

inline int read()
{
    char ch=getchar();
    int x=0,f=1;
    while(ch<'0'||ch>'9'){if(ch=='-') f=-1;ch=getchar();}
    while(ch>='0'&&ch<='9') x=x*10+(ch^48),ch=getchar();
    return x*f;
}

int main()
{
 	ios::sync_with_stdio(false);
	cin.tie(0);
 	//freopen(".in","r",stdin);
	//freopen(".out","w",stdout);
	string s;
	cin>>s;
	if(s[5]==s[4]&&s[2]==s[3])
	{
		cout<<"Yes"<<endl;
	}
	else
	{
		cout<<"No"<<endl;
	}
	return 0;
}