Problem:
Score : 200 points

Problem Statement

You are given two positive integers A and B. Compare the magnitudes of these numbers.

Constraints

1 ≤ A, B ≤ 10^{100}

Neither A nor B begins with a 0.

Input

Input is given from Standard Input in the following format:

A
B

Output

Print GREATER if A>B, LESS if A<B and EQUAL if A=B.

Sample Input 1

36
24

Sample Output 1

GREATER

Since 36>24, print GREATER.

Sample Input 2

850
3777

Sample Output 2

LESS

Sample Input 3

9720246
22516266

Sample Output 3

LESS

Sample Input 4

123456789012345678901234567890
234567890123456789012345678901

Sample Output 4

LESS

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<iostream>
using namespace std;
int main(){
  string a,b; cin >> a >> b;
  // 桁数が異なる場合を排除
  if(a.size()>b.size()){
    cout << "GREATER" << endl;
    return 0;
  }else if(a.size()<b.size()){
    cout << "LESS" << endl;
    return 0;
  }else{ // 以下桁数が同じ時
    int count=0;
    for(int i=0;i<a.size();i++){
      if(a[i]>b[i]){
        cout << "GREATER" << endl;
        return 0;
      }else if(a[i]<b[i]){
        cout << "LESS" << endl;
        return 0;
      }else{
        count++;
      }
    }
    if(count==a.size()){
      cout << "EQUAL" << endl;
      return 0;
    }
  }
}