Problem:
Score : 200 points

Problem Statement

A shop sells N kinds of fruits, Fruit 1, \ldots, N, at prices of p_1, \ldots, p_N yen per item, respectively. (Yen is the currency of Japan.)

Here, we will choose K kinds of fruits and buy one of each chosen kind. Find the minimum possible total price of those fruits.

Constraints

1 \leq K \leq N \leq 1000

1 \leq p_i \leq 1000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
p_1 p_2 \ldots p_N

Output

Print an integer representing the minimum possible total price of fruits.

Sample Input 1

5 3
50 100 80 120 80

Sample Output 1

210

This shop sells Fruit 1, 2, 3, 4, and 5 for 50 yen, 100 yen, 80 yen, 120 yen, and 80 yen, respectively.

The minimum total price for three kinds of fruits is 50 + 80 + 80 = 210 yen when choosing Fruit 1, 3, and 5.

Sample Input 2

1 1
1000

Sample Output 2

1000

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#define ll long long int
#define mod 1000000007
#define f(i,a,b) for(ll i=a;i<b;i++)
#define rf(i,a,b) for(ll i=a;i>=b;i--)
#define rep(i,n) f(i,0,n)
#define rrep(i,n) rf(i,n-1,0)
#define w(t) ll t; cin>>t; while(t--)
#define vi vector<ll>
#define mp make_pair
#define pb push_back
#define ff first
#define ss second
#define mii map<ll,ll>
#define mci map<char,ll>
using namespace std;

void fast_IO_file()
{
	ios_base::sync_with_stdio(false);
	cin.tie(NULL);
#ifndef ONLINE_JUDGE
	freopen("input.txt", "r", stdin);
	freopen("output.txt", "w", stdout);
#endif
}

int main()
{
	fast_IO_file();

	int n, m, sum = 0;
	cin >> n >> m;

	int a[n + 1];

	rep(i, n)
	cin >> a[i];


	sort(a, a + n);

	rep(i, m)
	sum += a[i];


	cout << sum << endl;



	return 0;
}