Problem:
Score : 500 points

Problem Statement

There are N blocks arranged in a row. Let us paint these blocks.

We will consider two ways to paint the blocks different if and only if there is a block painted in different colors in those two ways.

Find the number of ways to paint the blocks under the following conditions:

For each block, use one of the M colors, Color 1 through Color M, to paint it. It is not mandatory to use all the colors.

There may be at most K pairs of adjacent blocks that are painted in the same color.

Since the count may be enormous, print it modulo 998244353.

Constraints

All values in input are integers.

1 \leq N, M \leq 2 \times 10^5

0 \leq K \leq N - 1

Input

Input is given from Standard Input in the following format:

N M K

Output

Print the answer.

Sample Input 1

3 2 1

Sample Output 1

6

The following ways to paint the blocks satisfy the conditions: 112, 121, 122, 211, 212, and 221. Here, digits represent the colors of the blocks.

Sample Input 2

100 100 0

Sample Output 2

73074801

Sample Input 3

60522 114575 7559

Sample Output 3

479519525

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#line 1 "/mnt/c/Users/leafc/dev/compro/lib/math/modint.hpp"
#include <cstdint>
#include <iostream>
#include <vector>
#ifndef MOD_INT
#define MOD_INT

template <std::uint_fast64_t MOD> class ModInt {
  using u64 = std::uint_fast64_t;

public:
  ModInt(const u64 val = 0) { value = val % MOD; }

  ModInt operator+(const ModInt rhs) const { return ModInt(*this) += rhs; }
  ModInt operator-(const ModInt rhs) const { return ModInt(*this) -= rhs; }
  ModInt operator*(const ModInt rhs) const { return ModInt(*this) *= rhs; }
  ModInt operator/(const ModInt rhs) const { return ModInt(*this) /= rhs; }

  ModInt &operator+=(const ModInt rhs) {
    value += rhs.value;
    if (value >= MOD) {
      value -= MOD;
    }
    return *this;
  }

  ModInt &operator-=(const ModInt rhs) {
    if (value < rhs.value) {
      value += MOD;
    }
    value -= rhs.value;
    return *this;
  }

  ModInt &operator*=(const ModInt rhs) {
    value = value * rhs.value % MOD;
    return *this;
  }

  ModInt &operator/=(ModInt rhs) {
    *this *= rhs.inv();
    return *this;
  }

  ModInt &operator++(int n) {
    value++;
    if (value >= MOD) {
      value -= MOD;
    }
    return *this;
  }

  ModInt &operator--(int n) {
    if (value == 0) {
      value += MOD;
    }
    value--;
    return *this;
  }

  ModInt inv() { return ModInt::pow(*this, MOD - 2); }

  static ModInt pow(ModInt base, long long int n) {
    ModInt res = ModInt(1);
    while (n) {
      if (n & 1) {
        res *= base;
      }
      base *= base;
      n /= 2;
    }
    return res;
  }

  static ModInt comb(ModInt n, ModInt r) { return comb(n.value, r.value); }

  static ModInt comb(int n, int r) {
    if (n < r)
      return ModInt(0);
    ModInt res = ModInt(1);
    for (int i = 0; i < r; i++) {
      res *= ModInt(n - i);
    }

    ModInt inv = ModInt(1);
    for (int i = 0; i < r; i++) {
      inv *= ModInt(r - i);
    }
    return res / inv;
  }

  u64 getValue() const { return value; }

private:
  u64 value;

  friend std::ostream &operator<<(std::ostream &out, const ModInt<MOD> &m) {
    out << m.value;
    return out;
  }

  friend std::istream &operator>>(std::istream &in, ModInt &m) {
    uint_fast64_t i;
    in >> i;
    m = ModInt(i);
    return in;
  }
};

#endif
#line 1 "/mnt/c/Users/leafc/dev/compro/lib/template.hpp"


#include <bits/stdc++.h>
#define REP(i, n) for (int i = 0; i < n; i++)
#define FOR(i, m, n) for (int i = m; i < n; i++)
#define ALL(v) (v).begin(), (v).end()
#define coutd(n) cout << fixed << setprecision(n)
#define ll long long int
#define vl vector<ll>
#define vi vector<int>
#define MM << " " <<

using namespace std;

template <class T> void say(bool val, T yes = "Yes", T no = "No") { cout << (val ? yes : no) << endl; }

template <class T> void chmin(T &a, T b) {
  if (a > b)
    a = b;
}

template <class T> void chmax(T &a, T b) {
  if (a < b)
    a = b;
}


#line 3 "tmp.cpp"

using mint = ModInt<998244353>;

template <class T> std::vector<T> combination_table(int n) {
  std::vector<T> vec(n + 1);
  vec[0] = T(1);
  for (int r = 1; r < n + 1; r++) {
    vec[r] = vec[r - 1] * T(n - r + 1) / T(r);
  }
  return vec;
}

int main() {
  cin.tie(0);
  ios::sync_with_stdio(false);

  int n, m, k;
  cin >> n >> m >> k;
  auto ctable = combination_table<mint>(n - 1);
  vector<mint> ftable(n);
  ftable[0] = mint(1);
  ftable[1] = mint(m - 1);
  FOR(i, 2, n) { ftable[i] = mint(m - 1) * ftable[i - 1]; }
  mint ans(0);
  REP(i, k + 1) { ans += ctable[i] * m * ftable[n - 1 - i]; }
  cout << ans << endl;

  return 0;
}