Problem:
Score: 100 points

Problem Statement

M-kun is a competitor in AtCoder, whose highest rating is X.

In this site, a competitor is given a kyu (class) according to his/her highest rating. For ratings from 400 through 1999, the following kyus are given:

From 400 through 599: 8-kyu

From 600 through 799: 7-kyu

From 800 through 999: 6-kyu

From 1000 through 1199: 5-kyu

From 1200 through 1399: 4-kyu

From 1400 through 1599: 3-kyu

From 1600 through 1799: 2-kyu

From 1800 through 1999: 1-kyu

What kyu does M-kun have?

Constraints

400 \leq X \leq 1999

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print the kyu M-kun has, as an integer.
For example, if he has 8-kyu, print 8.

Sample Input 1

725

Sample Output 1

7

M-kun's highest rating is 725, which corresponds to 7-kyu.

Thus, 7 is the correct output.

Sample Input 2

1600

Sample Output 2

2

M-kun's highest rating is 1600, which corresponds to 2-kyu.

Thus, 2 is the correct output.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;
#define ll long long int
#define endl "\n"
ll fun(ll m,ll arr[],ll k,ll n)
{
	ll sum=0;
	for(int i=0;i<n;i++)
	{
		sum+=pow(abs(m-arr[i]),k);
	}
	return sum;
}
int main(){
	ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    int t;
    t=1;
    while(t--)
    {
    	int x;
    	cin>>x;
    	if(x>=400 && x<=599)
    	{
    		cout<<8<<endl;
		}
		else if(x>=600 && x<=799)
		{
			cout<<7<<endl;
		}
		else if(x>=800 && x<=999)
		{
			cout<<6<<endl;
		}
		else if(x>=1000 && x<=1199)
		{
			cout<<5<<endl;
			
		}
		else if(x>=1200 && x<=1399)
		{
			cout<<4<<endl;
		}
		else if(x>=1400 && x<=1599)
		{
			cout<<3<<endl;
		}
		else if(x>=1600 && x<=1799)
		{
			cout<<2<<endl;
		}
		else
		{
			cout<<1<<endl;
		}
	}
}