Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#define _USE_MATH_DEFINES
#define _CRT_SECURE_NO_WARNINGS

#include <iostream>
#include <string>
#include <sstream>
#include <iomanip>
#include <cmath>
#include <cstring>
#include <cstdlib>
#include <algorithm>
#include <stack>
#include <queue>
#include <vector>
#include <list>
#include <set>
#include <map>
#include <bitset>
#include <utility>
#include <numeric>

using namespace std;

using ll = long long;
using ull = unsigned long long;

const ll inf = (ll)1e9;
const ll mod = (ll)1e9 + 7;

#define all(v) v.begin(), v.end()
#define rall(v) v.rbegin(), v.rend()

#define print(s) cout << s;
#define println(s) cout << s << endl;
#define printd(s, f) cout << fixed << setprecision(f) << s << endl;


int main()
{
	vector<pair<int, bool>> p(9);
	for (int i = 0; i < 9; i++)
	{
		int x;
		cin >> x;

		p[i].first = x;
		p[i].second = false;
	}

	int n;
	cin >> n;

	for (int i = 0; i < n; i++)
	{
		int x;
		cin >> x;
		for (int j = 0; j < 9; j++)
		{
			if (p[j].first == x)
			{
				p[j].second = true;
				break;
			}
		}
	}

	string res = "No";

	for (int i = 0; i < 3; i++)
	{
		int j = 3 * i;
		if (p[j].second && p[j + 1].second && p[j + 2].second)
		{
			res = "Yes";
		}

		if (p[i].second && p[i + 3].second && p[i + 6].second)
		{
			res = "Yes";
		}
	}

	if (p[0].second && p[4].second && p[8].second)
	{
		res = "Yes";
	}

	if (p[2].second && p[4].second && p[6].second)
	{
		res = "Yes";
	}

	println(res);
}