Problem:
Score : 200 points

Problem Statement

Given are a positive integer N and a string S of length N consisting of lowercase English letters.

Determine whether the string is a concatenation of two copies of some string.
That is, determine whether there is a string T such that S = T + T.

Constraints

1 \leq N \leq 100

S consists of lowercase English letters.

|S| = N

Input

Input is given from Standard Input in the following format:

N
S

Output

If S is a concatenation of two copies of some string, print Yes; otherwise, print No.

Sample Input 1

6
abcabc

Sample Output 1

Yes

Let T = abc, and S = T + T.

Sample Input 2

6
abcadc

Sample Output 2

No

Sample Input 3

1
z

Sample Output 3

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;

int main()
{
  int n;
  string s;
  cin>>n>>s;
  
  if(n%2!=0)
  {
    cout<<"No"<<endl;
    return 0;
  }
  
  for(int i=0;i<n/2;i++)
  {
    if(s.at(i)!=s.at(i+n/2))
    {
      cout<<"No"<<endl;
      return 0;
    }
  }
  cout<<"Yes"<<endl;
}