Problem:
Score : 100 points

Problem Statement

You are given a string S of length 3 consisting of a, b and c. Determine if S can be obtained by permuting abc.

Constraints

|S|=3

S consists of a, b and c.

Input

Input is given from Standard Input in the following format:

S

Output

If S can be obtained by permuting abc, print Yes; otherwise, print No.

Sample Input 1

bac

Sample Output 1

Yes

Swapping the first and second characters in bac results in abc.

Sample Input 2

bab

Sample Output 2

No

Sample Input 3

abc

Sample Output 3

Yes

Sample Input 4

aaa

Sample Output 4

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <string>
#include <vector>
#include <numeric>
#include <queue>
#include <unordered_map>
#include <algorithm>
#include <cmath>
#include <iomanip>
#include <sstream>
#include <stack>
#include <map>
#include <set>

#define REP(i,a) for(int i = 0;i < (a);++i)
#define FOR(i,a,b) for(int i = (a);i < (b); ++i)
#define ALL(obj) (obj).begin(),(obj).end()
#define SIZE(obj) (int)(obj).size()
#define MAX(list) std::max(list)
#define MIN(list) std::min(list)
#define YESNO(cond,yes,no){cout <<((cond)?(yes):(no))<<endl; }

template<typename T>
T round_up(const T& a, const T& b) {
    return (a + (b - 1)) / b;
}

using ll = long long;
using namespace std;
ll mod = 1'000'000'007;

const int INF = 1'050'000'000;

int main() {
    string S;
    cin >> S;
    int a = 0, b = 0, c = 0;
    REP(i, 3) {
        if (S[i] == 'a')a++;
        else if (S[i] == 'b')b++;
        else c++;
    }
    YESNO(a == 1 && b == 1 && c == 1, "Yes", "No");
    return 0;
}