Problem:
Score : 300 points

Problem Statement

A company has N members, who are assigned ID numbers 1, ..., N.

Every member, except the member numbered 1, has exactly one immediate boss with a smaller ID number.

When a person X is the immediate boss of a person Y, the person Y is said to be an immediate subordinate of the person X.

You are given the information that the immediate boss of the member numbered i is the member numbered A_i. For each member, find how many immediate subordinates it has.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq A_i < i

Input

Input is given from Standard Input in the following format:

N
A_2 ... A_N

Output

For each of the members numbered 1, 2, ..., N, print the number of immediate subordinates it has, in its own line.

Sample Input 1

5
1 1 2 2

Sample Output 1

2
2
0
0
0

The member numbered 1 has two immediate subordinates: the members numbered 2 and 3.

The member numbered 2 has two immediate subordinates: the members numbered 4 and 5.

The members numbered 3, 4, and 5 do not have immediate subordinates.

Sample Input 2

10
1 1 1 1 1 1 1 1 1

Sample Output 2

9
0
0
0
0
0
0
0
0
0

Sample Input 3

7
1 2 3 4 5 6

Sample Output 3

1
1
1
1
1
1
0

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
 
#define MAXN (int)(2 * 1e5 + 5)
#define MAXL 20
#define F first
#define S second
#define endl "\n"
#define MOD (lli)(1e9 + 7)
#define lli long long int
#define sz(a) int(a.size())
#define DEBUG if (0) cout << "aqui" << endl;
#define PI 2 * acos(0.0)
typedef pair<int, int> ii;
int dx[] = {1, -1, 0, 0};
int dy[] = {0, 0, 1, -1};
int dddx[] = {1, -1, 0, 0, 1, 1, -1, -1};
int dddy[] = {0, 0, 1, -1, 1, -1, 1, -1};

int n;
int ans[MAXN];

int main(){
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);

  cin >> n;
  for(int i=2;i<=n;i++) {
    int a;
    cin >> a;
    ans[a]++;
  }

  for(int i=1;i<=n;i++) cout << ans[i] << endl;

  return 0;
}