Problem:
Score : 100 points

Problem Statement

You are given a three-digit positive integer N.

Determine whether N is a palindromic number.

Here, a palindromic number is an integer that reads the same backward as forward in decimal notation.

Constraints

100≤N≤999

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a palindromic number, print Yes; otherwise, print No.

Sample Input 1

575

Sample Output 1

Yes

N=575 is also 575 when read backward, so it is a palindromic number. You should print Yes.

Sample Input 2

123

Sample Output 2

No

N=123 becomes 321 when read backward, so it is not a palindromic number. You should print No.

Sample Input 3

812

Sample Output 3

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;
 
typedef long long ll;
typedef vector<pair<ll, ll>> pll;
 
#define mod 1000000007
#define all(x) (x).begin(), (x).end()
#define pb push_back
#define popcount(x) __builtin_popcountll(x)
 
const long double PI = acos(-1);
 
ll gcd(ll a,ll b){return b ? gcd(b,a%b) : a;}
ll lcm(ll a,ll b){return a / gcd(a,b) * b;}
ll stringcount(string s, char c){return count(s.cbegin(), s.cend(), c);}
bool isInteger(double x){return floor(x) == x;}

int main(){
  ios::sync_with_stdio(false);
  cin.tie(0);
  
  ll n;
  cin >> n;
  if(n/100 == n%10) cout << "Yes" << endl;
  else cout << "No" << endl;
  return 0;
}