Problem:
Score : 500 points

Problem Statement

There are N points on the 2D plane, i-th of which is located on (x_i, y_i).
There can be multiple points that share the same coordinate.
What is the maximum possible Manhattan distance between two distinct points?

Here, the Manhattan distance between two points (x_i, y_i) and (x_j, y_j) is defined by |x_i-x_j| + |y_i-y_j|.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq x_i,y_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
x_1 y_1
x_2 y_2
:
x_N y_N

Output

Print the answer.

Sample Input 1

3
1 1
2 4
3 2

Sample Output 1

4

The Manhattan distance between the first point and the second point is |1-2|+|1-4|=4, which is maximum possible.

Sample Input 2

2
1 1
1 1

Sample Output 2

0

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include<bits/stdc++.h>
#define int long long
#define REP(i,a,n) for(int i=a;i<(n);i++)
#define REP_sz(i,s) for(int i=0;i<s.size();i++)
#define RE return
#define FILL(a,b) memset(a,b,sizeof(a))
#define SO(a) sort(all(a))
#define pb push_back
#define sz(a) a.size()
#define V vector
#define ld long double
#define viit(a) vector<int>::iterator a
#define msit1(a) map<string,int>::iterator a
#define miit(a) map<int,int>::iterator a
#define msit2(a) map<int,string>::iterator a
#define IT iterator
#define FOR(i,a,n) for(int i=a;i<=(n);i++)
#define B(s) s.back()
#define all(a) a.begin(),a.end()
#define ER1(a) a.erase(a.begin())
#define ER0(a) a.erase(a.end())
#define pii pair<int,int>
#define pause system("PAUSE")
#define cls system("CLS")
using namespace std;
signed main()
{
	ios::sync_with_stdio(0);
    cin.tie(0);cout.tie(0);
	int n;
    cin>>n;
    V<pii>a(n);
    REP(i,0,n){
    	int x,y;
    	cin>>x>>y;
    	a[i].first=x+y;
    	a[i].second=x-y;
	}
	SO(a);
	cout<<max(a[n-1].first-a[0].first,a[n-1].second-a[0].second);
    return 0;
}