Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;
using lint = long long;

signed main(){
	lint N, A, B, C;
	cin >> N >> A >> B >> C;
	string ans;
	vector<string> s(N);
	for(int i = 0; i < N; i++) cin >> s[i];
	bool ok = true;
	for(int i = 0; i < N; i++){
		if(s[i] == "AB"){
			if(A == 0 && B == 0) ok = false;
			else if(A == B){
				if(s[i + 1] == "AB") A++, B--;
				if(s[i + 1] == "BC") A--, B++;
				if(s[i + 1] == "AC") A++, B--;
			}
			else if(A <= B) ans.push_back('A'), A++, B--;
			else ans.push_back('B'), A--, B++;
		}
		if(s[i] == "BC"){
			if(B == 0 && C == 0) ok = false;
			else if(C == B){
				if(s[i + 1] == "AB") B++, C--;
				if(s[i + 1] == "BC") C--, B++;
				if(s[i + 1] == "AC") C++, B--;
			}
			else if(C <= B) ans.push_back('C'), C++, B--;
			else ans.push_back('B'), C--, B++;
		}
		if(s[i] == "AC"){
			if(C == 0 && A == 0) ok = false;
			else if(C == A){
				if(s[i + 1] == "AB") A++, C--;
				if(s[i + 1] == "BC") C++, A--;
				if(s[i + 1] == "AC") C++, A--;
			}
			else if(C <= A) ans.push_back('C'), C++, A--;
			else ans.push_back('A'), C--, A++;
		}
	}
	if(ok){
		cout << "Yes" << endl;
		for(int i = 0; i < ans.size(); i++) cout << ans[i] << '\n';
	}
	else cout << "No" << endl;
}