Problem:
Score : 300 points

Problem Statement

Given is a permutation P_1, \ldots, P_N of 1, \ldots, N.
Find the number of integers i (1 \leq i \leq N) that satisfy the following condition:

For any integer j (1 \leq j \leq i), P_i \leq P_j.

Constraints

1 \leq N \leq 2 \times 10^5

P_1, \ldots, P_N is a permutation of 1, \ldots, N.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
P_1 ... P_N

Output

Print the number of integers i that satisfy the condition.

Sample Input 1

5
4 2 5 1 3

Sample Output 1

3

i=1, 2, and 4 satisfy the condition, but i=3 does not - for example, P_i > P_j holds for j = 1.

Similarly, i=5 does not satisfy the condition, either. Thus, there are three integers that satisfy the condition.

Sample Input 2

4
4 3 2 1

Sample Output 2

4

All integers i (1 \leq i \leq N) satisfy the condition.

Sample Input 3

6
1 2 3 4 5 6

Sample Output 3

1

Only i=1 satisfies the condition.

Sample Input 4

8
5 7 4 2 6 8 1 3

Sample Output 4

4

Sample Input 5

1
1

Sample Output 5

1

Solution in C++14 (Clang 3.8.0) (judge verdict: Time Limit Exceeded)

/* C++14 (Clang 3.8.0) for AtCoder */

#include <iostream>
#include <vector>
#include <string>
// #include <cmath>
// #include <math.h>
// #include <map>
// #include <algorithm>

namespace AtCoder {
	using Str = std::vector<std::string>;
	using Num = std::vector<int>;
	using BigNum = std::vector<double>;

	class InputData {
	public:
		void getInput(void);
		void skipInput(void);
		Str getStr(void);
		Num getNum(void);
		BigNum getBigNum(void);
	private:
		Str str;
		Num num;
		BigNum bNum;
	};
	Str AtCoder::InputData::getStr(void) {
		return this->str;
	}
	Num AtCoder::InputData::getNum(void) {
		return this->num;
	}
	BigNum AtCoder::InputData::getBigNum(void) {
		return this->bNum;
	}
	void AtCoder::InputData::skipInput(void) {
		std::string buf = "";
		std::getline(std::cin, buf);
	}
	void AtCoder::InputData::getInput(void) {
		this->str.clear();
		this->num.clear();
		this->bNum.clear();

		std::string buf = "", row = "";
		std::getline(std::cin, buf);
		for (unsigned int i = 0; i < buf.size(); i++) {
			if (' ' == buf[i]) {
				this->str.push_back(row);
				this->num.push_back(std::atoi(row.c_str()));
				this->bNum.push_back(std::atof(row.c_str()));
				row = "";
			} else {
				row += buf[i];
			}
		}
		this->str.push_back(row);
		this->num.push_back(std::atoi(row.c_str()));
		this->bNum.push_back(std::atof(row.c_str()));
	}

	class Ans {
	public:
		void showResult(void);
		void increment(void);
		void increment(double);
		void decrement(void);
		void decrement(double);
		double getResult(void);
	private:
		double result;
	};
	void Ans::showResult(void) {
		printf("%.0lf\n", this->result);
	}
	void AtCoder::Ans::increment(void) {
		this->result++;
	}
	void AtCoder::Ans::increment(double value) {
		this->result += value;
	}
	void AtCoder::Ans::decrement(void) {
		this->result--;
	}
	void AtCoder::Ans::decrement(double value) {
		this->result -= value;
	}
	double AtCoder::Ans::getResult(void) {
		return this->result;
	}

	void exp(std::string* str,  Str* newStr) {
		std::string pre = *str;
		newStr->clear();
		for (unsigned int i = 0; i < pre.length(); i++) {
			newStr->push_back(pre.substr(i, 1));
		}
	}
	void reverse(std::vector<int>* vec) {
		std::reverse(vec->begin(), vec->end());
	}
}

int main(void) {

	AtCoder::InputData* data = new AtCoder::InputData();
	data->skipInput();
	data->getInput();

	AtCoder::Num num = data->getNum();
	AtCoder::reverse(&num);

	AtCoder::Ans* ans = new AtCoder::Ans();

	const int max = num.size();
	for (int i = 0; i < (max - 1); i++) {
		bool ansf = true;
		for (int j = (i + 1); j < max; j++) {
			if (num[i] > num[j]) {
				ansf = false;
				break;
			}
		}
		if (ansf) {
			ans->increment();
		}
	}
	ans->increment();

	ans->showResult();

	delete(ans);
	delete(data);

	return 0;
}