Problem:
Score : 200 points

Problem Statement

You are given string S and T consisting of lowercase English letters.

Determine if S equals T after rotation.

That is, determine if S equals T after the following operation is performed some number of times:

Operation: Let S = S_1 S_2 ... S_{|S|}. Change S to S_{|S|} S_1 S_2 ... S_{|S|-1}.

Here, |X| denotes the length of the string X.

Constraints

2 \leq |S| \leq 100

|S| = |T|

S and T consist of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S equals T after rotation, print Yes; if it does not, print No.

Sample Input 1

kyoto
tokyo

Sample Output 1

Yes

In the first operation, kyoto becomes okyot.

In the second operation, okyot becomes tokyo.

Sample Input 2

abc
arc

Sample Output 2

No

abc does not equal arc after any number of operations.

Sample Input 3

aaaaaaaaaaaaaaab
aaaaaaaaaaaaaaab

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;

#define rep(i,n) for(int i=0 ; i<(n) ; i++)
#define repr(i,n) for(int i=(n) ; i>=0 ; i--)
#define FOR(i,m,n) for(int i=(m) ; i<(n) ; i++)
#define FORR(i,m,n) for(int i=(m) ; i>=(n) ; i--)

typedef long long ll;
typedef unsigned long long ull;

const int INF = 1000000000;

int main(){
   string s,t;
   cin >> s >> t;
   for(int i=0;i<(int)s.size();i++){
      if(s == t){
         cout << "Yes" << endl;
         return 0;
      }else{
         s = s.back() + s.substr(0,s.size()-1);
      }
   }
   cout << "No" << endl;
   return 0;
}