Problem:
Score : 200 points

Problem Statement

A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.

How many times will the ball make a bounce where the coordinate is at most X?

Constraints

1 \leq N \leq 100

1 \leq L_i \leq 100

1 \leq X \leq 10000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N X
L_1 L_2 ... L_{N-1} L_N

Output

Print the number of times the ball will make a bounce where the coordinate is at most X.

Sample Input 1

3 6
3 4 5

Sample Output 1

2

The ball will make a bounce at the coordinates 0, 3, 7 and 12, among which two are less than or equal to 6.

Sample Input 2

4 9
3 3 3 3

Sample Output 2

4

The ball will make a bounce at the coordinates 0, 3, 6, 9 and 12, among which four are less than or equal to 9.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
//#define int long long

using namespace std;
using LL = long long;
using P = pair<int, int>;

#define FOR(i, a, n) for(int i = (int)(a); i < (int)(n); ++i)
#define REP(i, n) FOR(i, 0, n)

#define pb(a) push_back(a)
#define all(x) (x).begin(),(x).end()

template<typename T>
vector<T> make_v(size_t a){return vector<T>(a);}
template<typename T,typename... Ts>
auto make_v(size_t a, Ts... ts) {return vector<decltype(make_v<T>(ts...))>(a, make_v<T>(ts...)); }

template<typename T,typename V>
typename enable_if<is_class<T>::value == 0>::type
fill_v(T &t, const V &v){ t = v; }

template<typename T,typename V>
typename enable_if<is_class<T>::value != 0>::type
fill_v(T &t, const V &v){ for(auto &e : t) fill_v(e, v); }

const int INF = (int)1e9;
const LL INFL = (LL)1e18;
const int MOD = 1e9 + 7;

signed main()
{
    cin.tie(0);
    ios::sync_with_stdio(false);
    
    int n, x;
    cin >> n >> x;
    vector<int> l(n);
    REP(i, n) cin >> l[i];

    int ans = 1;
    int cur = 0;
    REP(i, n)
    {
        cur += l[i];
        if(cur <= x) ans++;
    }
    cout << ans << endl;
}