Problem:
Score : 300 points

Problem Statement

A railroad running from west to east in Atcoder Kingdom is now complete.

There are N stations on the railroad, numbered 1 through N from west to east.

Tomorrow, the opening ceremony of the railroad will take place.

On this railroad, for each integer i such that 1≤i≤N-1, there will be trains that run from Station i to Station i+1 in C_i seconds. No other trains will be operated.

The first train from Station i to Station i+1 will depart Station i S_i seconds after the ceremony begins. Thereafter, there will be a train that departs Station i every F_i seconds.

Here, it is guaranteed that F_i divides S_i.

That is, for each Time t satisfying S_i≤t and t％F_i=0, there will be a train that departs Station i t seconds after the ceremony begins and arrives at Station i+1 t+C_i seconds after the ceremony begins, where A％B denotes A modulo B, and there will be no other trains.

For each i, find the earliest possible time we can reach Station N if we are at Station i when the ceremony begins, ignoring the time needed to change trains.

Constraints

1≤N≤500

1≤C_i≤100

1≤S_i≤10^5

1≤F_i≤10

S_i％F_i=0

All input values are integers.

Input

Input is given from Standard Input in the following format:

N
C_1 S_1 F_1
:
C_{N-1} S_{N-1} F_{N-1}

Output

Print N lines. Assuming that we are at Station i (1≤i≤N) when the ceremony begins, if the earliest possible time we can reach Station N is x seconds after the ceremony begins, the i-th line should contain x.

Sample Input 1

3
6 5 1
1 10 1

Sample Output 1

12
11
0

We will travel from Station 1 as follows:

5 seconds after the beginning: take the train to Station 2.

11 seconds: arrive at Station 2.

11 seconds: take the train to Station 3.

12 seconds: arrive at Station 3.

We will travel from Station 2 as follows:

10 seconds: take the train to Station 3.

11 seconds: arrive at Station 3.

Note that we should print 0 for Station 3.

Sample Input 2

4
12 24 6
52 16 4
99 2 2

Sample Output 2

187
167
101
0

Sample Input 3

4
12 13 1
44 17 17
66 4096 64

Sample Output 3

4162
4162
4162
0

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#define int long long
using namespace std;
const int MOD = pow(10, 9) + 7;
//const int MOD = 998244353;
//const int MOD = ;
int mod(int A, int M) {return (A % M + M) % M;}
const int INF = 1LL << 60;
template <class T> bool chmin(T& a, T b) {if (a > b) {a = b; return true;} return false;}
template <class T> bool chmax(T& a, T b) {if (a < b) {a = b; return true;} return false;}
int divCeil(int A, int B) {return (A + (B - 1)) / B;}
int myctoi(char C) {return C - 48;}
char myitoc(int N) {return '0' + N;}

signed main()
{
  int N;
  cin >> N;

  vector<int> C(N - 1), S(N - 1), F(N - 1);
  for (int i = 0; i < N - 1; i++)
  {
    cin >> C.at(i) >> S.at(i) >> F.at(i);
  }
  
  for (int i = 0; i < N; i++)
  {
    int t = 0;
    for (int j = i; j < N - 1; j++)
    {
      if (t < S.at(j)) t = S.at(j);
      else if (t % F.at(j) != 0) t += F.at(j) - t % F.at(j);
      
      t += C.at(j);
    }
    
    cout << t << endl;
  }
}