Problem:
Score : 300 points

Problem Statement

You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

1 \leq |S| \leq 2 \times 10^5

|S| = |T|

S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S and T can be made equal, print Yes; otherwise, print No.

Sample Input 1

azzel
apple

Sample Output 1

Yes

azzel can be changed to apple, as follows:

Choose e as c_1 and l as c_2. azzel becomes azzle.

Choose z as c_1 and p as c_2. azzle becomes apple.

Sample Input 2

chokudai
redcoder

Sample Output 2

No

No sequences of operation can change chokudai to redcoder.

Sample Input 3

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Runtime Error)

#include <bits/stdc++.h>
using namespace std;

typedef long long ll;
typedef pair<int, int> P;

#define For(i, a, b) for(int i = (a); i < (b); i++)
#define Rep(i, n) For(i, 0, (n))
#define Rrep(i, n) for(int i = (n - 1); i >= 0; i--)
#define Itr(i, c) for(typeof(c.begin()) i = c.begin(); i != c.end(); i++)
#define pb push_back

const int inf = 999999999;
const int mod = 1000000007;
const int dx[4] = {1, 0, -1, 0}, dy[4] = {0, 1, 0, -1};

int c1[26], c2[26];

int main(){
	string s, t; cin >> s >> t;
	int l = s.size();
	Rep(i, l){
		int k = s[i] - 'a';
		c1[k] += 1;
		k = t[i] - 'a';
		c2[k] += 1;
	}
	sort(c1, c1 + l);
	sort(c2, c2 + l);
	bool flag = true;
	Rep(i, l){
		if(c1[i] == c2[i]){
			continue;
		}else{
			flag = false;
		}
	}
	if(flag){
		cout << "Yes" << endl;
	}else{
		cout << "No" << endl;
	}
	return 0;
}