Problem:
Score : 400 points

Problem Statement

We have a grid with H rows and W columns of squares.
Snuke is painting these squares in colors 1, 2, ..., N.
Here, the following conditions should be satisfied:

For each i (1 ≤ i ≤ N), there are exactly a_i squares painted in Color i. Here, a_1 + a_2 + ... + a_N = H W.

For each i (1 ≤ i ≤ N), the squares painted in Color i are 4-connected. That is, every square painted in Color i can be reached from every square painted in Color i by repeatedly traveling to a horizontally or vertically adjacent square painted in Color i.

Find a way to paint the squares so that the conditions are satisfied.
It can be shown that a solution always exists.

Constraints

1 ≤ H, W ≤ 100

1 ≤ N ≤ H W

a_i ≥ 1

a_1 + a_2 + ... + a_N = H W

Input

Input is given from Standard Input in the following format:

H W
N
a_1 a_2 ... a_N

Output

Print one way to paint the squares that satisfies the conditions.
Output in the following format:

c_{1 1} ... c_{1 W}
:
c_{H 1} ... c_{H W}

Here, c_{i j} is the color of the square at the i-th row from the top and j-th column from the left.

Sample Input 1

2 2
3
2 1 1

Sample Output 1

1 1
2 3

Below is an example of an invalid solution:

1 2
3 1

This is because the squares painted in Color 1 are not 4-connected.

Sample Input 2

3 5
5
1 2 3 4 5

Sample Output 2

1 4 4 4 3
2 5 4 5 3
2 5 5 5 3

Sample Input 3

1 1
1
1

Sample Output 3

1

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

//This is getting accepted!
// I HATE BUG
// God Of The Bugs
// 12/11/2016
#include<bits/stdc++.h>

using namespace std;

#define ms(s, n) memset(s, n, sizeof(s))
#define FI first
#define SE second
#define pb push_back
#define mp make_pair
#define ll long long
#define sz(a) ((int)(a).size())
#define __builtin_popcount __builtin_popcounll
#define ld long double

typedef pair<int, int> pii;
typedef pair<double, double> pdd;
typedef pair<int, pii> ppi;

const double PI = acos(0) * 2;
const double EPS = 1e-8;
const ll MOD = 1e9 + 7;
const int MAXN = 1e5 + 5;
const int oo = 1e9;
const double foo = 1e30;

template<class T> int getbit(T s, int i) { return (s >> i) & 1; }
template<class T> T onbit(T s, int i) { return s | (T(1) << i); }
template<class T> T offbit(T s, int i) { return s & (~(T(1) << i)); }
template<class T> int cntbit(T s) { return __builtin_popcounll(s);}
template<class T> T sqr(T x) { return x * x; }

inline void addmod(int& a, int val, int p = MOD) {if ((a = (a + val)) >= p) a -= p;}
inline void submod(int& a, int val, int p = MOD) {if ((a = (a - val)) < 0) a += p;}
inline int mult(int a, int b, int p = MOD) {return (ll) a * b % p;}

int h, w, n, a[MAXN], c[210][210];

int main() {
//#ifndef ONLINE_JUDGE
//    freopen("inp.txt", "r", stdin);
////    freopen("out.txt", "w", stdout);
//#endif

	cin >> h >> w;
	cin >> n;
	for (int i=0; i<n; i++) cin >> a[i];
	
	int cur = 1;
	for (int i=0; i<h; i++) {
		if (i % 2) {
			for (int j=0; j<w; j++) {
				while (!a[cur - 1]) cur++;
				c[i][j] = cur;
				a[cur - 1]--;
			}
		}
		else {
			for (int j=w-1; j>=0; j--) {
				while (!a[cur - 1]) cur++;
				c[i][j] = cur;
				a[cur - 1]--;
			}
		}
	}
	
	for (int i=0; i<h; i++) {
		for (int j=0; j<w; j++) cout << c[i][j] << " ";
		cout << endl;
	}


}