Problem:
Score : 200 points

Problem Statement

You are given a positive integer X.
Find the largest perfect power that is at most X.
Here, a perfect power is an integer that can be represented as b^p, where b is an integer not less than 1 and p is an integer not less than 2.

Constraints

1 ≤ X ≤ 1000

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print the largest perfect power that is at most X.

Sample Input 1

10

Sample Output 1

9

There are four perfect powers that are at most 10: 1, 4, 8 and 9.
We should print the largest among them, 9.

Sample Input 2

1

Sample Output 2

1

Sample Input 3

999

Sample Output 3

961

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
#define forr(i, a, b) for(int i = (a); i < (b); i++)
#define rep(i,n) for(int i = 0; i < (n); i++)
#define rrep(i,n) for(int i = 1; i <= (n); i++)
#define ALL(a) (a.begin()),(a.end())
using namespace std;
typedef long long ll;
typedef pair<int,int> P;
typedef pair<ll, ll> LP;
const ll LINF = 1LL<<60;
const int INF = 1001001001;
const int MOD = 1000000007;

/* --------------------------------------------------- */

int main() {
    int x;
    cin >> x;
    int ans = 1;
    rrep(i, x) {
        forr(j, 2, x + 1) {
            if((int)pow(i, j) <= x) {
                int value = pow(i, j);
                ans = max(value, ans);
            } else break;
        }
    }
    cout << ans << endl;

    return 0;
}