Problem:
Score : 200 points

Problem Statement

Let S(n) denote the sum of the digits in the decimal notation of n.
For example, S(101) = 1 + 0 + 1 = 2.

Given an integer N, determine if S(N) divides N.

Constraints

1 \leq N \leq 10^9

Input

Input is given from Standard Input in the following format:

N

Output

If S(N) divides N, print Yes; if it does not, print No.

Sample Input 1

12

Sample Output 1

Yes

In this input, N=12.
As S(12) = 1 + 2 = 3, S(N) divides N.

Sample Input 2

101

Sample Output 2

No

As S(101) = 1 + 0 + 1 = 2, S(N) does not divide N.

Sample Input 3

999999999

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cmath>
#include <string>
#include <algorithm>
#include <vector>
#include <set>
#include <map>
#include <list>
using namespace std;

typedef long long ll;
typedef vector<int> vi;
typedef vector<ll> vll;

#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define p(x) cout << x << endl;

#define MOD 1000000007
#define PI 3.14159265359

int main()
{
    cin.tie(0);
    ios::sync_with_stdio(false);

    int n;
    cin >> n;
    int x = n;

    int num = 0;
    while(x != 0){
        num += x % 10;
        x /= 10;
    }

    if(n % num == 0){
        p("Yes");
    }else{
        p("No");
    }
}