Problem:
Score : 100 points

Problem Statement

Given are three integers A_1, A_2, and A_3.

If A_1+A_2+A_3 is greater than or equal to 22, print bust; otherwise, print win.

Constraints

1 \leq A_i \leq 13 \ \ (i=1,2,3)

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

If A_1+A_2+A_3 is greater than or equal to 22, print bust; otherwise, print win.

Sample Input 1

5 7 9

Sample Output 1

win

5+7+9=21, so print win.

Sample Input 2

13 7 2

Sample Output 2

bust

13+7+2=22, so print bust.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define int long long
using P = pair<int, int>;
constexpr array<int, 4> dx = {1, 0, -1, 0};
constexpr array<int, 4> dy = {0, 1, 0, -1};
constexpr int INF = 1234567890;
constexpr int MOD = 1000000000 + 7;
// constexpr int MOD = 998244353;
template <class T>
bool chmax(T &a, const T &b)
{
    if (a < b)
    {
        a = b;
        return 1;
    }
    return 0;
}
template <class T>
bool chmin(T &a, const T &b)
{
    if (b < a)
    {
        a = b;
        return 1;
    }
    return 0;
}
constexpr int gcd(int a, int b) { return b ? gcd(b, a % b) : a; }
constexpr int fact(int n) { return n > 1 ? n * fact(n - 1) % MOD : 1; }
int modinv(int a)
{
    int b = MOD, u = 1, v = 0;
    while (b)
    {
        int t = a / b;
        a -= t * b;
        swap(a, b);
        u -= t * v;
        swap(u, v);
    }
    u %= MOD;
    if (u < 0)
        u += MOD;
    return u;
}
constexpr int modpow(int a, int n)
{
    int rtn = 1;
    while (n > 0)
    {
        if (n & 1)
            rtn = rtn * a % MOD;
        a = a * a % MOD;
        n >>= 1;
    }
    return rtn;
}

signed main()
{
    cin.tie(0);
    ios::sync_with_stdio(0);
    cout << setprecision(10);

    int a,b,c;
    cin>>a>>b>>c;
    cout << (a + b + c >= 22 ? "bust" : "win") << endl;
}