Problem:
Score : 200 points

Problem Statement

Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.

The problem has N test cases.

For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is AC, WA, TLE, and RE, respectively.

See the Output section for the output format.

Constraints

1 \leq N \leq 10^5

S_i is AC, WA, TLE, or RE.

Input

Input is given from Standard Input in the following format:

N
S_1
\vdots
S_N

Output

Let C_0, C_1, C_2, and C_3 be the numbers of test cases for which the verdict is AC, WA, TLE, and RE, respectively. Print the following:

AC x C_0
WA x C_1
TLE x C_2
RE x C_3

Sample Input 1

6
AC
TLE
AC
AC
WA
TLE

Sample Output 1

AC x 3
WA x 1
TLE x 2
RE x 0

We have 3, 1, 2, and 0 test case(s) for which the verdict is AC, WA, TLE, and RE, respectively.

Sample Input 2

10
AC
AC
AC
AC
AC
AC
AC
AC
AC
AC

Sample Output 2

AC x 10
WA x 0
TLE x 0
RE x 0

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)


#include<bits/stdc++.h>
#include<ext/pb_ds/assoc_container.hpp>
#include<ext/pb_ds/tree_policy.hpp>
 #define int long long

#define all(X) (X).begin(), (X).end()
#define reset(X) memset(X, 0, sizeof(X))
#define mp(a, b) make_pair(a, b)
#define pb push_back
#define endl '\n'
#define fi first
#define se second


using namespace __gnu_pbds;
using namespace std;
const int mod=1e9+7;
 // const int mod=998244353;
 // const int mod=1e9+9;
const int INF=4e18+10;
// const int INF=4e18+10;
template <typename T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
template <typename T>
using ordered_multiset = tree<T, null_type, less_equal<T>, rb_tree_tag, tree_order_statistics_node_update>;

#define read(n) int n; cin>>n;
#define readv(x, n) vector<int> x(n); for(auto &i:x) cin>>i;


typedef vector<int> vi;
typedef vector<vector<int>> vvi;
typedef pair<int, int> pii;

template<typename T1,typename T2>
void set_min(T1& a, T2 b)
{
    a=min(a, (T1)b);
}


int multiply(int a, int b, int in_mod){return (a*b)%in_mod;}
int mult_identity(int a){return 1;}


auto power(auto a, int b, int in_mod)
{
    auto prod=mult_identity(a);
    auto mult=a%in_mod;
    while(b!=0)
    {
        if(b%2)
        {
            prod=multiply(prod,mult, in_mod);

        }
        mult=multiply(mult, mult,in_mod);
        b/=2;
    }
    return prod;
}
int mod_inv(int q, int in_mod)
{

    return power(q, in_mod-2,in_mod);
}

void precomp()
{
}



void solve()
{
    map<string, int> cnt;
    int n;
    cin>>n;
    for(int i=0;i<n;i++)
    {
        string s;
        cin>>s;
        cnt[s]++;
    }
    cout<<"AC x " <<cnt["AC"]<<endl;
    cout<<"WA x " <<cnt["WA"]<<endl;
    cout<<"TLE x " <<cnt["TLE"]<<endl;
    cout<<"RE x " <<cnt["RE"]<<endl;
}


signed main()
{
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    cout.tie(NULL);
#ifndef ONLINE_JUDGE
    if (fopen("INPUT.txt", "r"))
    {
        freopen("INPUT.txt", "r", stdin);
        freopen("OUTPUT.txt", "w", stdout);
    }
#endif
    auto clk = clock();
    mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
    // -------------------------------------Code starts here---------------------------------------------------------------------
    precomp();
    int t = 1;
    // cin>>t;

    for (int test = 1; test <= t; test++)
    {
        // cout<<"Case #"<<test<<": ";
        // cout<<endl;
        solve();

        // cout<<endl;
    }

    // -------------------------------------Code ends here------------------------------------------------------------------

    clk = clock() - clk;
    // cerr << fixed << setprecision(6) << "Time: " << ((long double)clk) / CLOCKS_PER_SEC << "\n";
    return 0;
}