Problem:
Score : 600 points

Problem Statement

Given are two sequences A and B, both of length N.
A and B are each sorted in the ascending order.
Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderings that achieve it.

Constraints

1\leq N \leq 2 \times 10^5

1\leq A_i,B_i \leq N

A and B are each sorted in the ascending order.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 \cdots A_N
B_1 B_2 \cdots B_N

Output

If there exist no reorderings that satisfy the condition, print No.

If there exists a reordering that satisfies the condition, print Yes on the first line.
After that, print a reordering of B on the second line, separating terms with a whitespace.

If there are multiple reorderings that satisfy the condition, you can print any of them.

Sample Input 1

6
1 1 1 2 2 3
1 1 1 2 2 3

Sample Output 1

Yes
2 2 3 1 1 1

Sample Input 2

3
1 1 2
1 1 3

Sample Output 2

No

Sample Input 3

4
1 1 2 3
1 2 3 3

Sample Output 3

Yes
3 3 1 2

Solution in C++ (GCC 9.2.1) (judge verdict: Time Limit Exceeded)

#include<bits/stdc++.h>
using namespace std; 
typedef long long ll;
typedef long double ld;
#define pb push_back
#define fi first
#define se second
const ll mod = 1e9+7;
const int N = 1e6+5;
ll a[N];
ll b[N];
ll c[N];
ll ca[N];
bool vis[N];
void solve(){
	int n; 
	cin>>n; 
	for(int i=1;i<=n;i++){
		cin>>a[i];
	}
	for(int i=1;i<=n;i++){
		cin>>b[i];
	}
	for(int tc = 1;tc<=1000;tc++){
		random_shuffle(b+1,b+1+n);
		bool can = true;
		for(int i=1;i<=n;i++){
			if(a[i]==b[i])can = false;
		}
		if(can){
			cout<<"Yes"<<endl;
			for(int i=1;i<=n;i++)cout<<b[i]<<" ";
			cout<<endl;
			return ;
		}
	}
	cout<<"No"<<endl;
}
int main(){
	ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
	int t=1; 
//	cin>>t; 
	while(t--){
		solve();
	}
	return 0;
}