Problem:
Score : 100 points

Problem Statement

This contest, AtCoder Beginner Contest, is abbreviated as ABC.

When we refer to a specific round of ABC, a three-digit number is appended after ABC. For example, ABC680 is the 680th round of ABC.

What is the abbreviation for the N-th round of ABC? Write a program to output the answer.

Constraints

100 ≤ N ≤ 999

Input

Input is given from Standard Input in the following format:

N

Output

Print the abbreviation for the N-th round of ABC.

Sample Input 1

100

Sample Output 1

ABC100

The 100th round of ABC is ABC100.

Sample Input 2

425

Sample Output 2

ABC425

Sample Input 3

999

Sample Output 3

ABC999

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

//If you are reading this then you are at wrong place.
#include<bits/stdc++.h>
#define mod 1000000007
#define lli long long int
using namespace std;
bool prime [1000001];
void debug(lli a){cout<<a<<endl;}
lli sieve(lli a){memset(prime,true,sizeof(prime));lli p,i;for(p=2;p*p<=a;p++){if(prime[p]==true){for(i=p*2;i<=a;i+=p)prime[i]=false;}}return 0;}
lli powermod(lli _a,lli _b,lli _m){lli _r=1;while(_b){if(_b%2==1)_r=(_r*_a)%_m;_b/=2;_a=(_a*_a)%_m;}return _r;}
lli find_max(lli __a,lli __b){return __a^((__a^__b) & -(__a<__b));}
lli add(lli __a,lli __b,lli MOD){lli x = (__a+__b)%MOD; return x; }
lli mul(lli a,lli b,lli MOD){lli x = (a*b)%MOD; return x; }
lli sub(lli a,lli b,lli MOD){lli x = (a-b+MOD)%MOD; return x; }
lli div(lli a,lli b,lli MOD){lli x = a;lli y = powermod(b,MOD-2,MOD);lli res = (x*y)%MOD;return res;}
//97->a 122->z
//65-A
int main()
{
	//freopen("testcase.txt", "r", stdin);
 	//freopen("output.txt", "w", stdout);
	
	ios_base::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);	
	cout.precision(20);
	lli t,i,j;
	//cin>>t;
	//memset(dp, -1, sizeof dp);
	t=1;
	lli counter1=0;
	while(t--)
	{
		counter1++;
		string a;
		cin>>a;
		cout<<"ABC";
		cout<<a<<endl;
		
		//cout<<"Case #"<<counter1<<" ";
		//cout<<endl;	
	}	
}