Problem:
Score : 200 points

Problem Statement

It is only six months until Christmas, and AtCoDeer the reindeer is now planning his travel to deliver gifts.

There are N houses along TopCoDeer street. The i-th house is located at coordinate a_i. He has decided to deliver gifts to all these houses.

Find the minimum distance to be traveled when AtCoDeer can start and end his travel at any positions.

Constraints

1 ≤ N ≤ 100

0 ≤ a_i ≤ 1000

a_i is an integer.

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 ... a_N

Output

Print the minimum distance to be traveled.

Sample Input 1

4
2 3 7 9

Sample Output 1

7

The travel distance of 7 can be achieved by starting at coordinate 9 and traveling straight to coordinate 2.

It is not possible to do with a travel distance of less than 7, and thus 7 is the minimum distance to be traveled.

Sample Input 2

8
3 1 4 1 5 9 2 6

Sample Output 2

8

There may be more than one house at a position.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#include <algorithm>
using namespace std;
typedef long long ll;
template<class T> inline bool chmax(T& a, T b){if(a < b){ a = b; return 1;} return 0;}
template<class T> inline bool chmin(T& a, T b){if(a > b){ a = b; return 1;} return 0;}

const int INF = 100000; 

int main(){
    int n;
    cin >> n;

    vector<int> a(n, 0);
    for(int i = 0; i < n; i++) cin >> a[i];

    sort(a.begin(), a.end());

    cout << a[n-1] - a[0] << endl;

    return 0;
}