Problem:
Score : 100 points

Problem Statement

Takahashi has K 500-yen coins. (Yen is the currency of Japan.)
If these coins add up to X yen or more, print Yes; otherwise, print No.

Constraints

1 \leq K \leq 100

1 \leq X \leq 10^5

Input

Input is given from Standard Input in the following format:

K X

Output

If the coins add up to X yen or more, print Yes; otherwise, print No.

Sample Input 1

2 900

Sample Output 1

Yes

Two 500-yen coins add up to 1000 yen, which is not less than X = 900 yen.

Sample Input 2

1 501

Sample Output 2

No

One 500-yen coin is worth 500 yen, which is less than X = 501 yen.

Sample Input 3

4 2000

Sample Output 3

Yes

Four 500-yen coins add up to 2000 yen, which is not less than X = 2000 yen.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using vi = vector<ll>;
using vs = vector<string>;
#define  rep(i,n) for(ll i = 0; i < (n); ++i)
#define  red(i,n) for(ll i = (n)-1; i >= 0; --i)
#define  all(a)   begin(a),end(a)
#define  pb(a)    push_back(a)
#define  yn(a)    cout << ( (a)?"Yes\n":"No\n" )
inline ll gcd(ll a,ll b) { return b?gcd(b,a%b):a; }

int main()
{
    int a,x;
    cin>>a>>x;
    yn(a*500>=x);
}