Problem:
Score : 200 points

Problem Statement

The postal code in Atcoder Kingdom is A+B+1 characters long, its (A+1)-th character is a hyphen -, and the other characters are digits from 0 through 9.

You are given a string S. Determine whether it follows the postal code format in Atcoder Kingdom.

Constraints

1≤A,B≤5

|S|=A+B+1

S consists of - and digits from 0 through 9.

Input

Input is given from Standard Input in the following format:

A B
S

Output

Print Yes if S follows the postal code format in AtCoder Kingdom; print No otherwise.

Sample Input 1

3 4
269-6650

Sample Output 1

Yes

The (A+1)-th character of S is -, and the other characters are digits from 0 through 9, so it follows the format.

Sample Input 2

1 1
---

Sample Output 2

No

S contains unnecessary -s other than the (A+1)-th character, so it does not follow the format.

Sample Input 3

1 2
7444

Sample Output 3

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;
 
int main() {
  int A,B,i,x=0;
  string S;
  
  cin >> A >> B >> S;
  
  for(i=0; i <= A+B; i++){
  	if(i == A){
    	if(S[i] == '-'){
          x++;
        }
    }else{
    	if(S[i] == '1' || S[i] == '2' || S[i] == '3' || S[i] == '4' || S[i] == '5' || S[i] == '6' || S[i] == '7' || S[i] == '8' || S[i] == '9'){

        }else{
        	x = -100;
        }
    }
  }
  if(S.size() == A+B+1){
  	x++;
  }
  
  if(A >= 0 && A <= 5){
    if(B >= 0 && B <= 5){
 	 if(x == 2){
  		cout << "Yes" << endl;
     }else{
     	cout << "No" << endl;
     }
    }else{
    	cout << "No" << endl;
    }
  }else{
  	cout << "No" << endl;
  }
}