Problem:
Score : 400 points

Problem Statement

The ABC number of a string T is the number of triples of integers (i, j, k) that satisfy all of the following conditions:

1 ≤ i < j < k ≤ |T| (|T| is the length of T.)

T_i = A (T_i is the i-th character of T from the beginning.)

T_j = B

T_k = C

For example, when T = ABCBC, there are three triples of integers (i, j, k) that satisfy the conditions: (1, 2, 3), (1, 2, 5), (1, 4, 5). Thus, the ABC number of T is 3.

You are given a string S. Each character of S is A, B, C or ?.

Let Q be the number of occurrences of ? in S. We can make 3^Q strings by replacing each occurrence of ? in S with A, B or C. Find the sum of the ABC numbers of all these strings.

This sum can be extremely large, so print the sum modulo 10^9 + 7.

Constraints

3 ≤ |S| ≤ 10^5

Each character of S is A, B, C or ?.

Input

Input is given from Standard Input in the following format:

S

Output

Print the sum of the ABC numbers of all the 3^Q strings, modulo 10^9 + 7.

Sample Input 1

A??C

Sample Output 1

8

In this case, Q = 2, and we can make 3^Q = 9 strings by by replacing each occurrence of ? with A, B or C. The ABC number of each of these strings is as follows:

AAAC: 0

AABC: 2

AACC: 0

ABAC: 1

ABBC: 2

ABCC: 2

ACAC: 0

ACBC: 1

ACCC: 0

The sum of these is 0 + 2 + 0 + 1 + 2 + 2 + 0 + 1 + 0 = 8, so we print 8 modulo 10^9 + 7, that is, 8.

Sample Input 2

ABCBC

Sample Output 2

3

When Q = 0, we print the ABC number of S itself, modulo 10^9 + 7. This string is the same as the one given as an example in the problem statement, and its ABC number is 3.

Sample Input 3

????C?????B??????A???????

Sample Output 3

979596887

In this case, the sum of the ABC numbers of all the 3^Q strings is 2291979612924, and we should print this number modulo 10^9 + 7, that is, 979596887.

Solution in C++14 (GCC 5.4.1) (judge verdict: Time Limit Exceeded)

#include <iostream>
#include <string>
#include <vector>
using namespace std;
int MOD = 1000000007;
int MUL(int x, int y) { return (long long)x * y % MOD; }
int ADD(int x, int y) { return (x + y) % MOD; }
int POW3(int n) {
    int ans = 1;
    for (int i = 0; i < n; i++) ans = MUL(ans, 3);
    return ans;
}
int main()
{
    string S;
    cin >> S;
    int answer = 0;
    for (int i = 1; i < S.size() - 1; i++) {
        if (!(S[i] == 'B' || S[i] == '?')) continue;
        int la = 0, lq = 0, rc = 0, rq = 0;
        for (int j = 0; j < i; j++) {
            if (S[j] == 'A') la++;
            if (S[j] == '?') lq++;
        }
        for (int j = i+1; j < S.size(); j++) {
            if (S[j] == 'C') rc++;
            if (S[j] == '?') rq++;
        }
        answer = ADD(answer, MUL(MUL(la, rc), POW3(lq+rq)));
        answer = ADD(answer, MUL(MUL(lq, rc), POW3(lq+rq-1)));
        answer = ADD(answer, MUL(MUL(la, rq), POW3(lq+rq-1)));
        answer = ADD(answer, MUL(MUL(lq, rq), POW3(lq+rq-2)));
    }
    cout << answer << endl;
    return 0;
}