Problem:
Score : 100 points

Problem Statement

ButCoder Inc. runs a programming competition site called ButCoder. In this site, a user is given an integer value called rating that represents his/her skill, which changes each time he/she participates in a contest. The initial value of a new user's rating is 0, and a user whose rating reaches K or higher is called Kaiden ("total transmission"). Note that a user's rating may become negative.

Hikuhashi is a new user in ButCoder. It is estimated that, his rating increases by A in each of his odd-numbered contests (first, third, fifth, ...), and decreases by B in each of his even-numbered contests (second, fourth, sixth, ...).

According to this estimate, after how many contests will he become Kaiden for the first time, or will he never become Kaiden?

Constraints

1 ≤ K, A, B ≤ 10^{18}

All input values are integers.

Input

Input is given from Standard Input in the following format:

K A B

Output

If it is estimated that Hikuhashi will never become Kaiden, print -1. Otherwise, print the estimated number of contests before he become Kaiden for the first time.

Sample Input 1

4000 2000 500

Sample Output 1

5

Each time Hikuhashi participates in a contest, his rating is estimated to change as 0 → 2000 → 1500 → 3500 → 3000 → 5000 → … After his fifth contest, his rating will reach 4000 or higher for the first time.

Sample Input 2

4000 500 2000

Sample Output 2

-1

Each time Hikuhashi participates in a contest, his rating is estimated to change as 0 → 500 → -1500 → -1000 → -3000 → -2500 → … He will never become Kaiden.

Sample Input 3

1000000000000000000 2 1

Sample Output 3

1999999999999999997

The input and output values may not fit into 32-bit integers.

Solution in C++14 (GCC 5.4.1) (judge verdict: Runtime Error)

/*~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=
*$* WRITER:kakitamasziru/OxOmisosiru *$*
~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=*/
#ifdef LOCAL_JUDGE
#define _GLIBCXX_DEBUG //FOR THE DEBUG! COMMENT OUT THIS WHEN SUBMITTING!
#endif
/* I REALLY HOPE MY WISH REACH YOU , ATCODER'S ONLINE JUDGE */
#define WOULD
#define YOU
#define PLEASE
#define ACCEPT
#define MY
#define SUBMISSION
/* I REALLY HOPE MY WISH REACH YOU , ATCODER'S ONLINE JUDGE */
#include <iostream> // cout, endl, cin
#include <string> // string, to_string, stoi
#include <vector> // vector
#include <algorithm> // min, max, swap, sort, reverse, lower_bound, upper_bound
#include <utility> // pair, make_pair
#include <tuple> // tuple, make_tuple
#include <cstdint> // int64_t, int*_t
#include <iomanip>
#include <limits>//setprecision
//#include <cstdio> // printf
#include <map> // map
#include <queue> // queue, priority_queue
#include <set> // set
#include <stack> // stack
#include <deque> // deque
#include <math.h>//pow,,,
#include <cmath>//abs,,,
#include <bitset> // bitset
//It is so troublesome that I include bits/stdc++.h !
using namespace std;

template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return true; } return false; }
template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return true; } return false; }
const long long INF = 100100100100;
const long long MOD = 1000000007;
typedef pair<int,int> P;
//NのM乗を求める(繰り返し二乗法)
long long mod_pow(long long N, long long M) {
    if (M == 0) return 1;
    long long res = mod_pow((N * N) % MOD, M / 2);
    //最下位ビット(*N)が1の時は単独でNをかける
    if (M & 1) res = (res * N) % MOD;

    return res %= MOD;
}
long long nCr(long long n, long long r) {
    long long A = 1, B = 1;
    //Aが分子Bが1/r!
    for (long long i = n - r + 1; i <= n; i++) {
        A = A * i % MOD;
    }
    for (long long i = 1; i <= r; i++) {
        B = B * i % MOD;
    }
    B = mod_pow(B, MOD - 2);
    B %= MOD;
    //Bは割るのではなく掛ける
    return (A * B) % MOD;
}

long long gcd(long long a, long long b) {
    if (b == 0) return a;
    else return gcd(b, a % b);
}

long long lcm(long long a, long long b) {
    return a * b / gcd(a, b);
}

//long long A,B;
bool ok(long long key,long long index){
    if(index > key) return true;
    else if(index <= key) return false;
}
long long binary_search(long long key,long long size){
    //left,right,midはいずれもindex
    long long left = -1,right = size;
    while(right - left > 1){
        long long mid = left + (right-left)/2;
        long long hantei = ok(key,mid);
        if(hantei) right = mid;
        else left = mid;
    }
    if(left == -1)return 0;
    return left;
}

int main() {
    long long K,A,B;cin >> K >> A >> B;
    if(A < B && K > A){
        cout << -1 << endl;
        return 0;
    }
    if(A >= K){
        cout << 1 << endl;
        return 0;
    }
    long long times = A - B;
    K -= A;
    //K += B;
    if(K%times == 0) cout << (K/times)*2+1 << endl;
    else cout << (K/times)*2+3 << endl;

}