Problem:
Score : 100 points

Problem Statement

A Hitachi string is a concatenation of one or more copies of the string hi.

For example, hi and hihi are Hitachi strings, while ha and hii are not.

Given a string S, determine whether S is a Hitachi string.

Constraints

The length of S is between 1 and 10 (inclusive).

S is a string consisting of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S

Output

If S is a Hitachi string, print Yes; otherwise, print No.

Sample Input 1

hihi

Sample Output 1

Yes

hihi is the concatenation of two copies of hi, so it is a Hitachi string.

Sample Input 2

hi

Sample Output 2

Yes

Sample Input 3

ha

Sample Output 3

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include "bits/stdc++.h"
using namespace std;

#define ll long long int
#define str string
#define ALL(a)  (a).begin(),(a).end()
#define P pair<ll,ll>

using Graph = vector<vector<int>>;

const int dy[] = { 0, 0, 1, -1 }, dx[] = { 1, -1, 0, 0 };
ll INFL = 1ll << 60, INF = 1 << 30, mod = 1e9 + 7, Min = INFL, Max = -1;
ll a, b, c ,n, sum, A[500010], B[500000],rui[500000],  dp[5000];
str S,T,U;bool check = true;	vector<ll> v;



int main() {
	//Code Line
cin >> S;
for(int i = 0;i < S.size();i+= 2){
if(S[i] == 'h' && S[i+1] == 'i');
else check = 0;

}
if(check)cout << "Yes" << endl;
else cout << "No" << endl;



	return 0;
}