Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;

int		sign(int num, int *arr, int size)
{
	int		i;

	i = 0;
	while (i < size)
		if (num == arr[i++])
			return (1);
	return (0);
}
	
int		main(void)
{
	int		bingo[3][3];
	int		n;
	int		i;
	int		j;
	int		flag = 0;

	i = 0;
	while (i < 3)
	{
		j = 0;
		while (j < 3)
			cin >> bingo[i][j++];
		i++;
	}
	cin >> n;
	int		arr[n];
	i = 0;
	while (i < n)
		cin >> arr[i++];

	i = 0;
	while (i < 3)
	{
		j = 0;
		while (j < 3)
		{
			if (sign(bingo[i][j], arr, n))
				bingo[i][j] = 0;
			j++;
		}
		i++;
	}
	i = 0;
	while (i < 3)
	{
		if (!(bingo[i][0] + bingo[i][1] + bingo[i][2]))
			flag = 1;
		i++;
	}
	i = 0;
	while (i < 3)
	{
		if (!(bingo[0][i] + bingo[1][i] + bingo[2][i]))
			flag = 1;
		i++;
	}
	if (!(bingo[0][0] + bingo[1][1] + bingo[2][2]))
		flag = 1;
	if (!(bingo[0][2] + bingo[1][1] + bingo[2][0]))
		flag = 1;
	if (flag)
		cout << "Yes";
	else
		cout << "No";
}