Problem:
Score : 300 points

Problem Statement

A company has N members, who are assigned ID numbers 1, ..., N.

Every member, except the member numbered 1, has exactly one immediate boss with a smaller ID number.

When a person X is the immediate boss of a person Y, the person Y is said to be an immediate subordinate of the person X.

You are given the information that the immediate boss of the member numbered i is the member numbered A_i. For each member, find how many immediate subordinates it has.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq A_i < i

Input

Input is given from Standard Input in the following format:

N
A_2 ... A_N

Output

For each of the members numbered 1, 2, ..., N, print the number of immediate subordinates it has, in its own line.

Sample Input 1

5
1 1 2 2

Sample Output 1

2
2
0
0
0

The member numbered 1 has two immediate subordinates: the members numbered 2 and 3.

The member numbered 2 has two immediate subordinates: the members numbered 4 and 5.

The members numbered 3, 4, and 5 do not have immediate subordinates.

Sample Input 2

10
1 1 1 1 1 1 1 1 1

Sample Output 2

9
0
0
0
0
0
0
0
0
0

Sample Input 3

7
1 2 3 4 5 6

Sample Output 3

1
1
1
1
1
1
0

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define COUT(x) cout<<(x)<<endl
typedef long long ll;
template<class T> inline void chmax(T& a, T b) {
  if (a < b) a = b;
}

template<class T> inline void chmin(T& a, T b) {
  if (a > b) a = b;
}

const long long INF = 1LL << 60;
int main() {
  ll n;
  cin >> n;
  int a[n];
  for (int i = 0; i < n - 1; ++i) {
    cin >> a[i];
    a[i]--;
  }
  ll num[n] = {0};
  for (int i = 0; i < n - 1; ++i) {
    ++num[a[i]];
  }
  for (int i = 0; i < n; ++i) COUT(num[i]);
  return 0;
}