Problem:
Score : 300 points

Problem Statement

There are N slimes lining up from left to right. The colors of these slimes will be given as a string S of length N consisting of lowercase English letters. The i-th slime from the left has the color that corresponds to the i-th character of S.

Adjacent slimes with the same color will fuse into one larger slime without changing the color. If there were a slime adjacent to this group of slimes before fusion, that slime is now adjacent to the new larger slime.

Ultimately, how many slimes will be there?

Constraints

1 \leq N \leq 10^5

|S| = N

S consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

N
S

Output

Print the final number of slimes.

Sample Input 1

10
aabbbbaaca

Sample Output 1

5

Ultimately, these slimes will fuse into abaca.

Sample Input 2

5
aaaaa

Sample Output 2

1

All the slimes will fuse into one.

Sample Input 3

20
xxzaffeeeeddfkkkkllq

Sample Output 3

10

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<iostream>
#include<vector>
using namespace std;
#define rep(i,n) for(int i=0;i<(n);++i)
using ll = long long;
using P = pair<int, int>;
#include<algorithm>
#include<math.h>
#include<map>
#include<queue>
#include<cmath>
#include<iomanip>
#define M_PI 3.1415926535897932384626433832795

int main() {
	int n;
	string s;
	cin >> n >> s;
	int count(1);
	char buffer;
	buffer = s[0];
	rep(i, n) {
		if (buffer != s[i]) {
			++count;
			buffer = s[i];
		}
	}
	cout << count;
}