Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
#include <queue>
#include <string>
#include <set>
#include <map>
#define REP(i,n) for(ll i = 0; i < (ll)n; i++)
#define INF 1000000000000000
using namespace std;
typedef long long ll;
typedef double db;
typedef string str;

ll cnt_n(ll n){
  ll cnt = 0;
  for(int i = 1; i <= n; i++){
    if(n%i==0) cnt++;
  }
  return cnt;
}

int main(){
  ll n;
  cin >> n;
  ll cnt = 0;
  for(int i = 1; i <= n; i+=2){
    if(cnt_n(i)==8){
      cnt++;
    }
  }
  cout << cnt << endl;
  return 0;
}