Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<iostream>

using namespace std;

int main(){
	
	int A[3][3];
	
	for(int i = 0; i < 3; i++){
		for(int j = 0; j < 3; j++){
			cin>>A[i][j];
		}
	}
	
	int N;
	cin>>N;
	int b[N];
	
	for(int i = 0; i < N; i++){
		cin>>b[i];
	}
	
	int Yes1[4],Yes2[4],Yes3[4],Yes4[4],Yes5[4];
	
	Yes1[4] = 0,Yes2[4] = 0,Yes3[4] = 0,Yes4[4] = 0,Yes5[4] = 0;
	for(int i = 0; i < 3; i++){
		
		for(int j = 0 ; j < N; j++){
			
		
		if(A[i][i] == b[j]) Yes1[i] = 1;
		
		if(A[i][0] == b[j]) Yes2[i] = 1;
		
		if(A[i][1] == b[j]) Yes3[i] = 1;
		
		if(A[i][2] == b[j]) Yes4[i] = 1;
		
		if(A[i][2-i] == b[j]) Yes5[i] = 1;
		
		}
		if(Yes1[i] == 1)Yes1[4]++;
		if(Yes2[i] == 1)Yes2[4]++;
		if(Yes3[i] == 1)Yes3[4]++;
		if(Yes4[i] == 1)Yes4[4]++;
		if(Yes5[i] == 1)Yes5[4]++;
	}
	
	if(Yes1[4] == 3 ||Yes2[4] == 3 ||Yes3[4] == 3 ||Yes4[4] == 3 ||Yes5[4] == 3){
		cout<<"Yes";
	}
	else cout<<"No";
	
	
	
	
	return 0;
}