Problem:
Score: 100 points

Problem Statement

M-kun is a competitor in AtCoder, whose highest rating is X.

In this site, a competitor is given a kyu (class) according to his/her highest rating. For ratings from 400 through 1999, the following kyus are given:

From 400 through 599: 8-kyu

From 600 through 799: 7-kyu

From 800 through 999: 6-kyu

From 1000 through 1199: 5-kyu

From 1200 through 1399: 4-kyu

From 1400 through 1599: 3-kyu

From 1600 through 1799: 2-kyu

From 1800 through 1999: 1-kyu

What kyu does M-kun have?

Constraints

400 \leq X \leq 1999

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print the kyu M-kun has, as an integer.
For example, if he has 8-kyu, print 8.

Sample Input 1

725

Sample Output 1

7

M-kun's highest rating is 725, which corresponds to 7-kyu.

Thus, 7 is the correct output.

Sample Input 2

1600

Sample Output 2

2

M-kun's highest rating is 1600, which corresponds to 2-kyu.

Thus, 2 is the correct output.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#define rep(i,n) for(int i=0; i<(n); i++)
using ll = long long;
#define fast_io(); std::ios_base::sync_with_stdio(0); std::cin.tie(0); std::cout.tie(0);
#define rad2deg(a) ((a)/M_PI * 180.0)
#define deg2rad(a) ((a)/180.0 * M_PI)
const std::string yes = "Yes";
const std::string no  = "No";

int main(){
    int x;
    std::cin >> x;
    if(x<=599){std::cout << 8 << "\n";}
    else if(x<=799){std::cout << 7 << "\n";}
    else if(x<=999){std::cout << 6 << "\n";}
    else if(x<=1199){std::cout << 5 << "\n";}
    else if(x<=1399){std::cout << 4 << "\n";}
    else if(x<=1599){std::cout << 3 << "\n";}
    else if(x<=1799){std::cout << 2 << "\n";}
    else{std::cout << 1 << "\n";}
    return 0;
}