Problem:
Score : 200 points

Problem Statement

A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.

How many times will the ball make a bounce where the coordinate is at most X?

Constraints

1 \leq N \leq 100

1 \leq L_i \leq 100

1 \leq X \leq 10000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N X
L_1 L_2 ... L_{N-1} L_N

Output

Print the number of times the ball will make a bounce where the coordinate is at most X.

Sample Input 1

3 6
3 4 5

Sample Output 1

2

The ball will make a bounce at the coordinates 0, 3, 7 and 12, among which two are less than or equal to 6.

Sample Input 2

4 9
3 3 3 3

Sample Output 2

4

The ball will make a bounce at the coordinates 0, 3, 6, 9 and 12, among which four are less than or equal to 9.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
#include <boost/multiprecision/cpp_int.hpp>
using namespace std;
typedef long long ll;
namespace mp = boost::multiprecision;
using Mint = mp::cpp_int;
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define repi(i,a,b) for(int i = int(a); i < int(b); i++)
#define all(v) v.begin(), v.end()
#define uni(v) v.erase(unique(all(v)), v.end())
#define sort_g(v) sort(all(v), greater<int>())
#define dump(x) cerr << #x << ' ' << '=' << ' ' << x << endl

int main() {
    int N, L;
    cin >> N >> L;
    vector<int> vec(N);
    rep(i, N) cin >> vec.at(i);

    int d = 0;
    int cnt = 0;
    rep(i, N) {
        if(i > 0) {
            d += vec.at(i - 1);
        }
        dump(d);
        if(d <= L) {
            cnt++;
        } else {
            break;
        }
    }

    cout << cnt << endl;
}