Problem:
Score : 200 points

Problem Statement

In the beginning, Takahashi has A cookies, and Aoki has B cookies.
They will perform the following operation alternately, starting from Takahashi:

If the number of cookies in his hand is odd, eat one of those cookies; if the number is even, do nothing. Then, give one-half of the cookies in his hand to the other person.

Find the numbers of cookies Takahashi and Aoki respectively have after performing K operations in total.

Constraints

1 \leq A,B \leq 10^9

1 \leq K \leq 100

A,B and K are integers.

Input

Input is given from Standard Input in the following format:

A B K

Output

Print the number of cookies Takahashi has, and the number of cookies Aoki has, in this order, after performing K operations in total.

Sample Input 1

5 4 2

Sample Output 1

5 3

The process will go as follows:

In the beginning, Takahashi and Aoki have 5 and 4 cookies, respectively.

Takahashi eats one cookie and gives two cookies to Aoki. They now have 2 and 6 cookies, respectively.

Aoki gives three cookies to Takahashi. They now have 5 and 3 cookies, respectively.

Sample Input 2

3 3 3

Sample Output 2

1 3

Sample Input 3

314159265 358979323 84

Sample Output 3

448759046 224379523

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<bits/stdc++.h>

using namespace std;

int main(){
	
	ios_base::sync_with_stdio(false);
	cin.tie(0);
	/*
	#ifndef ONLINE_JUDGE
    	freopen("input.txt", "r", stdin);
    	freopen("output.txt", "w", stdout);
	#endif
	*/
	int a,b,k;
	cin >> a >> b >> k;
	for(int i = 0; i < k; i++){
		if(i & 1){
			if(b & 1) b--;
			a += (b/2);
			b /= 2;
		}
		else{
			if(a & 1) a--;
			b += (a/2);
			a /= 2;
		}
	}
	cout << a << " " << b;
}