Problem:
Score : 400 points

Problem Statement

Takahashi has a string S consisting of lowercase English letters.

Starting with this string, he will produce a new one in the procedure given as follows.

The procedure consists of Q operations. In Operation i (1 \leq i \leq Q), an integer T_i is provided, which means the following:

If T_i = 1: reverse the string S.

If T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.

If F_i = 1 : Add C_i to the beginning of the string S.

If F_i = 2 : Add C_i to the end of the string S.

Help Takahashi by finding the final string that results from the procedure.

Constraints

1 \leq |S| \leq 10^5

S consists of lowercase English letters.

1 \leq Q \leq 2 \times 10^5

T_i = 1 or 2.

F_i = 1 or 2, if provided.

C_i is a lowercase English letter, if provided.

Input

Input is given from Standard Input in the following format:

S
Q
Query_1
:
Query_Q

In the 3-rd through the (Q+2)-th lines, Query_i is one of the following:

1

which means T_i = 1, and:

2 F_i C_i

which means T_i = 2.

Output

Print the resulting string.

Sample Input 1

a
4
2 1 p
1
2 2 c
1

Sample Output 1

cpa

There will be Q = 4 operations. Initially, S is a.

Operation 1: Add p at the beginning of S. S becomes pa.

Operation 2: Reverse S. S becomes ap.

Operation 3: Add c at the end of S. S becomes apc.

Operation 4: Reverse S. S becomes cpa.

Thus, the resulting string is cpa.

Sample Input 2

a
6
2 2 a
2 1 b
1
2 2 c
1
1

Sample Output 2

aabc

There will be Q = 6 operations. Initially, S is a.

Operation 1: S becomes aa.

Operation 2: S becomes baa.

Operation 3: S becomes aab.

Operation 4: S becomes aabc.

Operation 5: S becomes cbaa.

Operation 6: S becomes aabc.

Thus, the resulting string is aabc.

Sample Input 3

y
1
2 1 x

Sample Output 3

xy

Solution in C++14 (GCC 5.4.1) (judge verdict: Runtime Error)

#include <bits/stdc++.h>
using namespace std;
int main(void){
  string a;
  long long int b,tmp,tmp_num;
  char tmp_char;
  vector<long long int> v;
  vector<long long int> v_num;
  vector<char> v_char;
  cin>>a;
  cin>>b;
  for(int i=0;i<b;i++){
  	cin>>tmp;
  	if(tmp==2){
  	  cin>>tmp_num>>tmp_char;
  	  v.push_back(tmp);
  	  v_num.push_back(tmp_num);
  	  v_char.push_back(tmp_char);
  	}else{
  	  v.push_back(tmp);
  	  v_num.push_back(0);
  	  v_char.push_back('0');  	  
  	}
  }
  for(int i=0;i<b-1;i++){
  	if(v[i]==v[i+1]&&v[i]==1){
  	  v.erase(v.begin() + i);
  	  v_num.erase(v_num.begin() + i);
  	  v_char.erase(v_char.begin() + i);
  	  v.erase(v.begin() + i+1);
  	  v_num.erase(v_num.begin() + i+1);
  	  v_char.erase(v_char.begin() + i+1);  	  
  	}
  }
  for(int i=0;i<b;i++){
  	if(v[i]==1){
  	  reverse(a.begin(),a.end());
  	}else{
  	  if(v_num[i]==1){
  	  	a.insert(a.begin(),v_char[i]);
  	  }else{
  	  	a.push_back(v_char[i]);
  	  }
  	}
  }
  cout<<a<<endl;
}