Problem:
Score : 100 points

Problem Statement

In programming, hexadecimal notation is often used.

In hexadecimal notation, besides the ten digits 0, 1, ..., 9, the six letters A, B, C, D, E and F are used to represent the values 10, 11, 12, 13, 14 and 15, respectively.

In this problem, you are given two letters X and Y. Each X and Y is A, B, C, D, E or F.

When X and Y are seen as hexadecimal numbers, which is larger?

Constraints

Each X and Y is A, B, C, D, E or F.

Input

Input is given from Standard Input in the following format:

X Y

Output

If X is smaller, print <; if Y is smaller, print >; if they are equal, print =.

Sample Input 1

A B

Sample Output 1

<

10 < 11.

Sample Input 2

E C

Sample Output 2

>

14 > 12.

Sample Input 3

F F

Sample Output 3

=

15 = 15.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#include <string>
#include <vector>
#include <cmath>
using namespace std;

int triple_max(int x, int y, int z){
    int ans = x;
    if (y > x && y > z) ans = y;
    else if (z > x && z > y) ans = z;

    return ans;
}

int main(){
    char a, b;
    cin >> a >> b;
    if (a < b) cout << '<' << endl;
    else if (a == b) cout << '=' << endl;
    else cout << '>' << endl;
    return 0;
}