Problem:
Score : 100 points

Problem Statement

Takahashi has K 500-yen coins. (Yen is the currency of Japan.)
If these coins add up to X yen or more, print Yes; otherwise, print No.

Constraints

1 \leq K \leq 100

1 \leq X \leq 10^5

Input

Input is given from Standard Input in the following format:

K X

Output

If the coins add up to X yen or more, print Yes; otherwise, print No.

Sample Input 1

2 900

Sample Output 1

Yes

Two 500-yen coins add up to 1000 yen, which is not less than X = 900 yen.

Sample Input 2

1 501

Sample Output 2

No

One 500-yen coin is worth 500 yen, which is less than X = 501 yen.

Sample Input 3

4 2000

Sample Output 3

Yes

Four 500-yen coins add up to 2000 yen, which is not less than X = 2000 yen.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <string>
#include <map>
#include <queue>
#include <algorithm>
#include <vector>
#include <math.h>
#include <bitset>
#include <cmath>
#include <set>
#include <queue>
#include <stack>

typedef long long ll;
#define rep(i,s,n)for(ll i = s;i<n;i++)
#define rep_r(i,s,n)for(ll i = n-1;i>=s;i--)
using namespace std;
static const ll MOD = 1e9 + 7;
static const ll INF = 1e25;
static const ll MAX_N = 100001;

int main() {
	ll k, x; cin >> k >> x;

	cout << ((k * 500 >= x) ? "Yes" : "No") << endl;

	return 0;
}