Problem:
Score : 200 points

Problem Statement

Let us define the FizzBuzz sequence a_1,a_2,... as follows:

If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.

If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.

If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.

If none of the above holds, a_i=i.

Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Constraints

1 \leq N \leq 10^6

Input

Input is given from Standard Input in the following format:

N

Output

Print the sum of all numbers among the first N terms of the FizzBuzz sequence.

Sample Input 1

15

Sample Output 1

60

The first 15 terms of the FizzBuzz sequence are:

1,2,\mbox{Fizz},4,\mbox{Buzz},\mbox{Fizz},7,8,\mbox{Fizz},\mbox{Buzz},11,\mbox{Fizz},13,14,\mbox{FizzBuzz}

Among them, numbers are 1,2,4,7,8,11,13,14, and the sum of them is 60.

Sample Input 2

1000000

Sample Output 2

266666333332

Watch out for overflow.

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include<bits/stdc++.h>
#define eps 1e-6
#define ll long long
#define IOS cin.sync_with_stdio(false);cin.tie(0);cout.tie(0);
//#define int long long
#define MEM(x,y) memset(x,y,sizeof(x))
#define rep(i,a,n) for (int i=a;i<n;i++)
#define fi first
#define se second
#define endl "\n"
const ll mod=1000000007;
const int inf=0x3f3f3f3f;
const ll INF=0x3f3f3f3f3f3f3f3f;
ll qpow(ll a,ll b){ll s=1;while(b>0){if(b%2==1){s=s*a;}a=a*a;b=b>>1;}return s;}
ll qpowmod(ll a, ll b, ll c){ll res, t;res=1;t=a%c;while(b){if(b & 1){res=res*t%c;}t=t*t%c;b>>=1;}return res;}
ll gcd(ll a,ll b){return b?gcd(b,a%b):a;}
ll lcm(ll a,ll b){return a/gcd(a,b)*b;}
inline long long read(){long long k=0,f=1;char ch=getchar();while(ch<'0'||ch>'9'){if(ch=='-')f=-1;ch=getchar();}while(ch>='0'&&ch<='9'){k=k*10+ch-'0';ch=getchar();}return k*f;}
inline void write(long long x){if(x<0)x=-x,putchar('-');if(x>9)write(x/10);putchar(x%10+'0');}
using namespace std;
int main()
{
    int n;
    cin>>n;
    ll sum=0;
    rep(i,1,n)
    {
        if(i%5==0||i%3==0)
        continue;
        else sum+=i;
    }
    cout<<sum;
    return 0;
}