Problem:
Score : 200 points

Problem Statement

You are given a string S of length N consisting of lowercase English letters.
We will cut this string at one position into two strings X and Y.
Here, we would like to maximize the number of different letters contained in both X and Y.
Find the largest possible number of different letters contained in both X and Y when we cut the string at the optimal position.

Constraints

2 \leq N \leq 100

|S| = N

S consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

N
S

Output

Print the largest possible number of different letters contained in both X and Y.

Sample Input 1

6
aabbca

Sample Output 1

2

If we cut the string between the third and fourth letters into X = aab and Y = bca, the letters contained in both X and Y are a and b.
There will never be three or more different letters contained in both X and Y, so the answer is 2.

Sample Input 2

10
aaaaaaaaaa

Sample Output 2

1

However we divide S, only a will be contained in both X and Y.

Sample Input 3

45
tgxgdqkyjzhyputjjtllptdfxocrylqfqjynmfbfucbir

Sample Output 3

9

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

using namespace std;
#include <iostream>/*{{{*/
struct Fast {Fast(){std::cin.tie(0);ios::sync_with_stdio(false);}} fast;

#include <bits/stdc++.h>

#define rep(i, x) for(int i = 0; i < (int)(x); i++)
#define reps(i,x) for(int i = 1; i <= (int)(x); i++)
#define rrep(i,x) for(int i=((int)(x)-1);i>=0;i--)
#define rreps(i,x) for(int i=((int)(x));i>0;i--)
#define FOR(i, m, n) for(int i = m;i < n;i++)
#define RFOR(i, m, n) for(int i = m;i >= n;i--)
#define foreach(x,a) for(auto& (x) : (a) )
#define all(x) (x).begin(),(x).end()
#define sum(v) accumulate(all(v), 0)
#define sz(x) ((int)(x).size())
#define fill(x,y) memset(x,y,sizeof(x))
#define pb(a) push_back(a)
// dump macro{{{
// http://www.creativ.xyz/dump-cpp-652
#define DUMPOUT cerr // 変数ダンプ先。coutかcerr

#define DEBUG_ // 提出時はコメントアウト
#ifdef DEBUG_
#define DEB
#else
// DEB と打つとデバッグ時以外はコメントアウトになる
#define DEB /##/
#endif

// 変数ダンプ用マクロ。デバッグ時以外は消滅する
// 引数はいくつでもどんな型でも可（ストリーム出力演算子があればOK）
#define dump(...) DEB DUMPOUT<<"  "; \
DUMPOUT<<#__VA_ARGS__; \
DUMPOUT<<":=> "; \
dump_func(__VA_ARGS__); DUMPOUT<<"in ["<<__LINE__<<":"<<__FUNCTION__<<"]"<<endl;

// デバッグ用変数ダンプ関数
void dump_func() {
}
template <class Head, class... Tail>
void dump_func(Head&& head, Tail&&... tail)
{
    DUMPOUT << head;
    if (sizeof...(Tail) == 0) {
        DUMPOUT << " ";
    }
    else {
        DUMPOUT << ", ";
    }
    dump_func(std::move(tail)...);
}

// vector出力
template<typename T>
ostream& operator << (ostream& os, vector<T>& vec) {
    os << "{";
    for (int i = 0; i<vec.size(); i++) {
        os << vec[i] << (i + 1 == vec.size() ? "" : ", ");
    }
    os << "}";
    return os;
}/*}}}*/
#define debug(x)                 cerr << __LINE__ << ": " << #x << " -> " << x << '\n'/*{{{*/
#define debug2(x, y)             cerr << __LINE__ << #x<<": "<<x<<" | "<<#y<<": "<<y<<endl
#define debug3(x, y, z)          cerr << __LINE__ << #x<<":" <<x<<" | "<<#y<<": "<<y<<" | "<<#z<<": "<<z<<endl
#define debug4(a, b, c, d)       cerr << __LINE__ << #a<<": "<<a<<" | "<<#b<<": "<<b<<" | "<<#c<<": "<<c<<" | "<<#d<<": "<<d<<endl
#define debug5(a, b, c, d, e)    cerr << __LINE__ << #a<<": "<<a<<" | "<<#b<<": "<<b<<" | "<<#c<<": "<<c<<" | "<<#d<<": "<<d<<" | "<<#e<< ": "<<e<<endl
#define debug6(a, b, c, d, e, f) cerr << __LINE__ << #a<<": "<<a<<" | "<<#b<<": "<<b<<" | "<<#c<<": "<<c<<" | "<<#d<<": "<<d<<" | "<<#e<< ": "<<e<<" | "<<#f<<": "<<f<<endl
#define db_2d(d,n,m) rep(i,n){rep(j,m){ cerr << (d)[i][j] << (((j)==(m-1))?"\n":" "); }}
#define db_1d(d,n) rep(i,n){cout << d[i] << (((i)==(n-1))?"\n":" ") << __LINE__}/*}}}*/
#define INF 2147483647
#define INFLL 1000000000000000000LL
#define MOD 1000000007
typedef long long ll;
typedef vector<int> vi;
typedef vector<vi> vvi;
typedef long long ll;
typedef vector<long long> vll;
typedef vector<vll> vvll;
typedef long double ld;
typedef pair<int,int> pii;
typedef vector<pii> vii;
typedef vector<vii> vvii;
typedef tuple<int,int,int> iii;
typedef set<int> si;
typedef complex<double> pnt;
typedef vector<pnt> vpnt;
typedef priority_queue<pii,vii,greater<pii> > spq;
int dy[]={0, 0, 1, -1, 0};
int dx[]={1, -1, 0, 0, 0};/*}}}*/

int main() {
  int n;cin>>n;
  string s;cin>>s;

  int res = 0;
  int a[26] = {};
  FOR(l,1,n){
    int count = 0;
    rep(i, l){
      a[s[i]-'a'] = 1;
    }
    FOR(j, l, n){
      if (a[s[j]-'a'] == 1){
        count += 1;
        a[s[j]-'a'] = 2;
      }
    }
    res = max(res, count);
  }

  cout << res << endl;

  return 0;
}