Problem:
Score : 200 points

Problem Statement

Let us define the FizzBuzz sequence a_1,a_2,... as follows:

If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.

If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.

If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.

If none of the above holds, a_i=i.

Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Constraints

1 \leq N \leq 10^6

Input

Input is given from Standard Input in the following format:

N

Output

Print the sum of all numbers among the first N terms of the FizzBuzz sequence.

Sample Input 1

15

Sample Output 1

60

The first 15 terms of the FizzBuzz sequence are:

1,2,\mbox{Fizz},4,\mbox{Buzz},\mbox{Fizz},7,8,\mbox{Fizz},\mbox{Buzz},11,\mbox{Fizz},13,14,\mbox{FizzBuzz}

Among them, numbers are 1,2,4,7,8,11,13,14, and the sum of them is 60.

Sample Input 2

1000000

Sample Output 2

266666333332

Watch out for overflow.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
#include<stdio.h>
#include<string.h>
#include<math.h>
#include<algorithm>
#include<queue>
#include<vector>
#include<set>
#include<iostream>
#define pb push_back
#define fi first
#define se second
#define sz(x)  x.size()
#define cl(x)  x.clear()
#define all(x)  x.begin() , x.end()
#define r(x)  scanf("%d", &x)
#define rr(x , y)  scanf("%d%d" , &x , &y)
#define rst(s)  scanf("%s" , s)
#define rl(x)  scanf("%lld" , &x)
#define rrl(x , y)  scanf("%lld%lld" , &x , &y)
#define w(x)  printf("%d" , x)
#define ww(x , y)  printf("%d %d" , x , y)
#define wl(x)  printf("%lld" , x)
#define wwl(x , y)  printf("%lld %lld" , x , y)
#define sp()  printf(" ")
#define en()  puts("")
#define rep(i , x , n)  for(int i = x ; i <= n ; i ++) 
#define per(i , n , x)  for(int i = n ; i >= x ; i --) 
#define mem0(x)  memset(x , 0 , sizeof(x))
#define mem_1(x)  memset(x , -1 , sizeof(x))
#define mem_inf(x)  memset(x , inf , sizeof(x))
#define mem__inf(x)  memset(x , -inf , sizeof(x))
#define p_queue priority_queue
#define debug(x)  printf("%d\n" , x)
#define ddebug(x , y)  printf("%d %d\n" , x , y)
using namespace std ;
//mt19937  rnd(chrono::high_resolution_clock::now().time_since_epoch().count()) ;
typedef long long ll ;
typedef unsigned long long ull ;
typedef pair<int , int> pii ;
typedef pair<ll , ll> pll ;
typedef pair<int , ll> pil ;
typedef pair<ll , int> pli ;
const int inf = 0x3f3f3f3f ;
const int maxn = 3e5 + 5 ;
const int maxm = 2e6 + 5 ;
const ll mod = 998244353 ;
int main()
{
	int n ;
	r(n) ;
    ll ans = 0 ;
    rep(i , 1 , n)  if(i % 3 != 0 && i % 5 != 0)  ans += i ;
    wl(ans) , en() ;
	return 0 ;
}