Problem:
Score : 300 points

Problem Statement

There are N people living on a number line.

The i-th person lives at coordinate X_i.

You are going to hold a meeting that all N people have to attend.

The meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.

Find the minimum total points of stamina the N people have to spend.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq X_i \leq 100

Input

Input is given from Standard Input in the following format:

N
X_1 X_2 ... X_N

Output

Print the minimum total stamina the N people have to spend.

Sample Input 1

2
1 4

Sample Output 1

5

Assume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.

Note that you can hold the meeting only at an integer coordinate.

Sample Input 2

7
14 14 2 13 56 2 37

Sample Output 2

2354

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

//inlclude前用define 
#define _USE_MATH_DEFINES

//include
#include<iostream>
#include<string>
#include<algorithm>
#include<vector>
#include<cmath>
#include<type_traits>
#include<numeric>
//#include<deque>
#include<iomanip>
#include<set>
#include<tuple>
#include<map>
#include<limits>

using namespace std;

//typedef
typedef vector<int> VI;
typedef vector<string> VS;
typedef vector<char> VC;
typedef long long int ll;

//define
#define INF 1e9 
#define NUM 1000000007
#define all(x) begin(x), end(x)
#define rep(i,n) for(int i=0;i<(int)(n);i++)

int main(){
  int n;
  cin>>n;
  int sum=0;
  VI x(n);
  rep(i,n){
    cin>>x[i];
    sum+=x[i];
  }

  int ave=floor(sum/n)+1;
  //cout<<ave<<endl;
  int ans=0;
  rep(i,n){
    ans+=abs(ave-x[i])*abs(ave-x[i]);
  }
  cout<<ans<<endl;

}