Problem:
Score : 200 points

Problem Statement

Given is an integer N. Find the number of digits that N has in base K.

Notes

For information on base-K representation, see Positional notation - Wikipedia.

Constraints

All values in input are integers.

1 \leq N \leq 10^9

2 \leq K \leq 10

Input

Input is given from Standard Input in the following format:

N K

Output

Print the number of digits that N has in base K.

Sample Input 1

11 2

Sample Output 1

4

In binary, 11 is represented as 1011.

Sample Input 2

1010101 10

Sample Output 2

7

Sample Input 3

314159265 3

Sample Output 3

18

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<algorithm>
#include<bitset>
#include<cmath>
#include<cstdio>
#include<cstdlib>
#include<cstring>
#include<ctime>
#include<iostream>
#include<map>
#include<queue>
#include<set>
#include<stack>
#include<string>
#include<vector>
using namespace std;
namespace Solve
{
	int N,K;
	void work()
	{
		scanf("%d%d",&N,&K);
		int fig=0;
		while(N)
		{
			fig++;
			N/=K;
		}
		if(!fig) fig++;
		printf("%d\n",fig);
		return;
	}
}
int main()
{
	#ifdef LOCAL
	freopen("00test.in","r",stdin);
	freopen("00test.out","w",stdout);
	#endif
	Solve::work(); 
	return 0;
}