Problem:
Score : 400 points

Problem Statement

Let {\rm comb}(n,r) be the number of ways to choose r objects from among n objects, disregarding order.
From n non-negative integers a_1, a_2, ..., a_n, select two numbers a_i > a_j so that {\rm comb}(a_i,a_j) is maximized.
If there are multiple pairs that maximize the value, any of them is accepted.

Constraints

2 \leq n \leq 10^5

0 \leq a_i \leq 10^9

a_1,a_2,...,a_n are pairwise distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print a_i and a_j that you selected, with a space in between.

Sample Input 1

5
6 9 4 2 11

Sample Output 1

11 6

\rm{comb}(a_i,a_j) for each possible selection is as follows:

\rm{comb}(4,2)=6

\rm{comb}(6,2)=15

\rm{comb}(6,4)=15

\rm{comb}(9,2)=36

\rm{comb}(9,4)=126

\rm{comb}(9,6)=84

\rm{comb}(11,2)=55

\rm{comb}(11,4)=330

\rm{comb}(11,6)=462

\rm{comb}(11,9)=55

Thus, we should print 11 and 6.

Sample Input 2

2
100 0

Sample Output 2

100 0

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <vector>
#include <algorithm>
#include <set>
#include <map>
#include <queue>
#include <stack>
#include <iostream>
#include <cstdio>
#include <cmath>
#include <cstring>
//#include <chrono> //1e+9で割る auto end= chrono::system_clock::now()-st;  cout<<end.count()%1e+9<<endl;
using namespace std;
typedef long long ll;
typedef pair<int,int> P;
typedef pair<ll,ll> LP;
typedef long double db;

#define fr first
#define sc second
#define pb push_back
#define rep(i,x) for(int i=0;i<x;i++)
#define rep1(i,x) for(int i=1;i<=x;i++)
#define rrep(i,x) for(int i=x-1;i>=0;i--)
#define rrep1(i,x) for(int i=x;i>0;i--)

ll N;
ll A[300000];

int main()
{
	cin>>N;
	ll v=-1;
	ll b;
	rep(i,N){
		cin>>A[i];
		if(v<A[i]){
			b=i;
			v=A[i];
		}
	}
	ll ans=-1;
	ll x,id;
	rep(i,N){
		if(i==b) continue; 
		x=A[i];
		if(x*2LL>v) x=v-x;
		if(ans<x){
			id=i;
			ans=x;
		}
	}
	cout<<v<<" "<<A[id]<<endl;
}