Problem:
Score : 1000 points

Problem Statement

You are given a string S consisting of digits between 1 and 9, inclusive.
You will insert at most K commas (,) into this string to separate it into multiple numbers.

Your task is to minimize the maximum number among those produced by inserting commas. Find minimum possible such value.

Constraints

0 ≦ K < |S| ≦ 100,000

S consists of digits between 1 and 9, inclusive.

Partial Scores

In the test set worth 100 points, |S| ≦ 2.

In the test set worth another 100 points, |S| ≦ 16.

In the test set worth another 200 points, |S| ≦ 100.

In the test set worth another 200 points, |S| ≦ 2,000.

Input

The input is given from Standard Input in the following format:

K
S

Output

Print the minimum possible value.

Sample Input 1

2
15267315

Sample Output 1

315

When the string is separated into 152, 67 and 315, the maximum among these is 315, which is the minimum possible value.

Sample Input 2

0
12456174517653111

Sample Output 2

12456174517653111

12456174517653111 itself is the answer.

Sample Input 3

8
127356176351764127645176543176531763517635176531278461856198765816581726586715987216581

Sample Output 3

5317635176

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <cstdio>
#include <iostream>
#include <vector>
#include <map>
#include <unordered_map>
#include <set>
#include <unordered_set>
#include <string>
#include <cstring>
#include <sstream>
#include <algorithm>
#include <functional>
#include <queue>
#include <stack>
#include <cmath>
#include <iomanip>
#include <list>
#include <tuple>
#include <bitset>
#include <ciso646>
#include <cassert>

using namespace std;

typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
typedef pair<ll, ll> P;
typedef tuple<ll, ll, ll> T;
typedef vector<ll> vec;

inline bool check(ll x, ll y, ll xMax, ll yMax) { return x >= 0 && y >= 0 && xMax > x && yMax > y; }
inline ll toint(string s) { ll v; istringstream sin(s); sin >> v; return v; }
template<class T> inline string tostring(T x) { ostringstream sout; sout << x; return sout.str(); }
template<class T> inline T sqr(T x) { return x*x; }
template<class T> inline T mypow(T x, ll n) { T res = 1; while (n > 0) { if (n & 1)res = res * x;	x = x * x;	n >>= 1; }return res; }
inline ll gcd(ll a, ll b) { return b ? gcd(b, a%b) : a; }
inline ll lcm(ll a, ll b) { return a / gcd(a, b) * b; }

#define For(i,a,b)	for(ll (i) = (a);i < (b);(i)++)
#define rep(i,n)	For(i,0,n)
#define rFor(i,a,b)	for(ll (i) = (a-1);i >= (b);(i)--)
#define rrep(i,n)	rFor(i,n,0)
#define each(i,n)	for(auto &i : n)
#define clr(a)		memset((a), 0 ,sizeof(a))
#define mclr(a)		memset((a), -1 ,sizeof(a))
#define all(a)		(a).begin(),(a).end()
#define sz(a)		(sizeof(a))
#define tostr(a)	tostring(a)
#define dump(val) 	cerr << #val " = " << val << endl;
#define Fill(a,v)	fill((int*)a,(int*)(a+(sz(a)/sz(*(a)))),v)

const ll dx[8] = { 1, 0, -1, 0, 1, 1, -1, -1 }, dy[8] = { 0, -1, 0, 1, -1, 1, -1, 1 };

const ll mod = 1e9 + 7;
const ll INF = 1e17 + 9;

#define int ll
#define double ld

/*
                   _ooOoo_
                  o8888888o
                  88" . "88
                  (| -_- |)
                  O\  =  /O
               ____/`---'\____
             .'  \\|     |//  `.
            /  \\|||  :  |||//  \
           /  _||||| -:- |||||-  \
           |   | \\\  -  /// |   |
           | \_|  ''\---/''  |   |
           \  .-\__  `-`  ___/-. /
         ___`. .'  /--.--\  `. . __
      ."" '<  `.___\_<|>_/___.'  >'"".
     | | :  `- \`.;`\ _ /`;.`/ - ` : | |
     \  \ `-.   \_ __\ /__ _/   .-` /  /
======`-.____`-.___\_____/___.-`____.-'======
                   `=---='
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
*/

int dp[101][101][101];
string s;

int dfs(int i, int k, int pre) {
	if (dp[i][k][pre] != -1)return dp[i][k][pre];
	if (s.size() == i)return INF;
	if (k == 0)return toint(s.substr(pre));

	int r0 = max(dfs(i + 1, k - 1, i + 1), ll(toint(s.substr(pre, i - pre + 1))));
	int r1 = dfs(i + 1, k, pre);

	return dp[i][k][pre] = min(r0, r1);
}

signed main() {
	cin.tie(0);
	ios_base::sync_with_stdio(false);

	mclr(dp);
	int k;
	cin >> k >> s;

	if (s.size() > 100)return 0;

	cout << dfs(0, k, 0) << endl;

	return 0;
}