Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
#define fast ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);
#define watch(x); cout<<#x<<"="<<x<<endl;
#define watch2(x,y); cout<<#x<<"="<<x<<" "<<#y<<"="<<y<<endl;
#define endl "\n"
#define int long long
using namespace std;    

int n,a,b,c;
string s[100005];
char ans[100005];
void print(){
    cout<<"Yes"<<endl;
    for(int i=1;i<=n;i++) cout<<ans[i]<<endl;
}
void check(){
    for(int i=1;i<=n;i++){
        if(s[i]=="AB"){
            if(a==1&&b==1&&i!=n&&s[i+1]=="AC"){
                ans[i]='A';
                a++;
                b--;
                continue;
            }
            if(a==1&&b==1&&i!=n&&s[i+1]=="BC"){
                ans[i]='B';
                b++;
                a--;
                continue;
            }
            if(a>b){
                ans[i]='B';
                b++;
                a--;
            }else{
                ans[i]='A';
                a++;
                b--;
            }
        }
        if(s[i]=="AC"){
            if(a==1&&c==1&&i!=n&&s[i+1]=="AB"){
                ans[i]='A';
                a++;
                c--;
                continue;
            }
            if(a==1&&c==1&&i!=n&&s[i+1]=="BC"){
                ans[i]='C';
                c++;
                a--;
                continue;
            }
            if(a>c){
                ans[i]='C';
                c++;
                a--;
            }else{
                ans[i]='A';
                a++;
                c--;
            }
        }
        if(s[i]=="BC"){
            if(b==1&&c==1&&i!=n&&s[i+1]=="AB"){
                ans[i]='B';
                b++;
                c--;
                continue;
            }
            if(b==1&&c==1&&i!=n&&s[i+1]=="AC"){
                ans[i]='C';
                c++;
                b--;
                continue;
            }
            if(b>c){
                ans[i]='C';
                c++;
                b--;
            }else{
                ans[i]='B';
                b++;
                c--;
            }
        }
        if(a<0 || b<0 || c<0){
            cout<<"No"<<endl;
            return ;
        }
    }
    print();
}
int32_t main(){
    cin>>n>>a>>b>>c;
    for(int i=1;i<=n;i++) cin>>s[i];
    check();
    return 0;
}