Problem:
Score : 100 points

Problem Statement

You have three tasks, all of which need to be completed.

First, you can complete any one task at cost 0.

Then, just after completing the i-th task, you can complete the j-th task at cost |A_j - A_i|.

Here, |x| denotes the absolute value of x.

Find the minimum total cost required to complete all the task.

Constraints

All values in input are integers.

1 \leq A_1, A_2, A_3 \leq 100

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

Print the minimum total cost required to complete all the task.

Sample Input 1

1 6 3

Sample Output 1

5

When the tasks are completed in the following order, the total cost will be 5, which is the minimum:

Complete the first task at cost 0.

Complete the third task at cost 2.

Complete the second task at cost 3.

Sample Input 2

11 5 5

Sample Output 2

6

Sample Input 3

100 100 100

Sample Output 3

0

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include "iostream"
#include <stdio.h>
#include <algorithm>
#include <stdlib.h>
#include <cstring>
#include <math.h>
#include <cctype>
#include <stack>
#include <vector>
#include <list>
#include <queue>
#include <set>
#include <map>
#include <bitset>
#include <iomanip>
using namespace std;
using ll=long long;
#define MOD  1000000007


int main(int argc, char const *argv[]) {
  int A1,A2,A3;
  std::cin >> A1 >> A2 >> A3;
  int ans = max ({ A1 , A2 , A3 }) - min ({ A1 , A2 , A3 });
  std::cout << ans << '\n';

  return 0;
}