Problem:
Score : 400 points

Problem Statement

Given is an integer S.
Find a combination of six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfies all of the following conditions:

0 \leq X_1,Y_1,X_2,Y_2,X_3,Y_3 \leq 10^9

The area of the triangle in a two-dimensional plane whose vertices are (X_1,Y_1),(X_2,Y_2), and (X_3,Y_3) is S/2.

We can prove that there always exist six integers that satisfy the conditions under the constraints of this problem.

Constraints

1 \leq S \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

S

Output

Print six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfy the conditions, in this order, with spaces in between.
If multiple solutions exist, any of them will be accepted.

Sample Input 1

3

Sample Output 1

1 0 2 2 0 1

The area of the triangle in a two-dimensional plane whose vertices are (1,0),(2,2), and (0,1) is 3/2.
Printing 3 0 3 1 0 1 or 1 0 0 1 2 2 will also be accepted.

Sample Input 2

100

Sample Output 2

0 0 10 0 0 10

Sample Input 3

311114770564041497

Sample Output 3

314159265 358979323 846264338 327950288 419716939 937510582

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<int,int> P;

#define all(v) v.begin(), v.end()

const ll mod=1000000007;

ll countBits(ll in){
  int res=0;
  for(;in>0;in>>=1){
    if((in&0x01)!=0){
      res++;
    }
  }
  return res;
}

template<typename T>
void show2dVector(vector<vector<T>>& v){
  for(int i=0;i<v.size();i++){
    int m=v[i].size();
    cout<<i<<" : ";
    for(int j=0;i<m;i++){
      cout<<v[i][j]<<" ";
    }
    cout<<endl;
  }
}

void bfs(const vector<vector<int>>&g, int v, vector<bool>& seen){
  seen[v]=true;
  cout<<v<<" ";
  for(auto next: g[v]){
    if(seen[next]){
      continue;
    }
    bfs(g,next,seen);
  }
}

bool dfs(vector<vector<int>> &g,int start,int goal,vector<bool>&seen){
  bool res=false;
  seen[start]=true;
  if(start==goal){
    return true;
  }
  for(auto next: g[start]){
    if(seen[next]){
      continue;
    }
    res=dfs(g,next,goal,seen);
    if(res){
      break;
    }
  }
  return res;
}

ll gcd(ll a,ll b) {
  return b? gcd(b,a%b): a;  
}
ll lcm(ll a,ll b) {
  return a*b/gcd(a,b);
}
bool isLowerCase(char c){
  return (c>='a'&&c<='z');
}

ll powm(ll a,ll n, ll m){
  ll ret=1;
  while(n>0){
    if(n%2==1){
      ret=(ret*a)%m;
    }
    n>>=1;
    a=(a*a)%m;
  }
  return ret;
}

const string yesno(bool ans){
  return (ans?"Yes":"No");
}
int main() {
  ll s;cin>>s;
  ll x,y;
  x=1000000000-s%1000000000;
  y=(1000000000+x)/1000000000;
  cout<<0<<' '<<0<<' '<<1000000000<<' '<<1<<' '<<x<<' '<<y<<endl;
  return 0;
}