Problem:
Score : 200 points

Problem Statement

Alice and Bob are controlling a robot. They each have one switch that controls the robot.

Alice started holding down her button A second after the start-up of the robot, and released her button B second after the start-up.

Bob started holding down his button C second after the start-up, and released his button D second after the start-up.

For how many seconds both Alice and Bob were holding down their buttons?

Constraints

0≤A<B≤100

0≤C<D≤100

All input values are integers.

Input

Input is given from Standard Input in the following format:

A B C D

Output

Print the length of the duration (in seconds) in which both Alice and Bob were holding down their buttons.

Sample Input 1

0 75 25 100

Sample Output 1

50

Alice started holding down her button 0 second after the start-up of the robot, and released her button 75 second after the start-up.

Bob started holding down his button 25 second after the start-up, and released his button 100 second after the start-up.

Therefore, the time when both of them were holding down their buttons, is the 50 seconds from 25 seconds after the start-up to 75 seconds after the start-up.

Sample Input 2

0 33 66 99

Sample Output 2

0

Alice and Bob were not holding their buttons at the same time, so the answer is zero seconds.

Sample Input 3

10 90 20 80

Sample Output 3

60

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;

int main() {
    int A, B, C, D;
    cin >> A >> B >> C >> D;
    int answer = 0;
    if (A < C) {
        if (B < C) {
            answer = 0;
        }
        else if (B > C && D > B) {
            answer = B - C;
        }
        else if (B > C && D < B) {
            answer = D - C;
        }
        else if (B == C) {
            answer = 0;
        }
        else if (B > C && D == B) {
            answer = D - C;
        }
    }
    else if (C < A) {
        if (D > A && B > D) {
            answer = D - A;
        }
        else if (D < A) {
            answer = 0;
        }
        else if (D == A) {
            answer = 0;
        }
        else if (D > A && D > B) {
            answer = B - A;
        }
        else if (D > A && D == B) {
            answer = B -A;
        }
    }
    cout << answer << endl;
    return 0;
}