Problem:
Score : 200 points

Problem Statement

Sig has built his own keyboard. Designed for ultimate simplicity, this keyboard only has 3 keys on it: the 0 key, the 1 key and the backspace key.

To begin with, he is using a plain text editor with this keyboard. This editor always displays one string (possibly empty). Just after the editor is launched, this string is empty. When each key on the keyboard is pressed, the following changes occur to the string:

The 0 key: a letter 0 will be inserted to the right of the string.

The 1 key: a letter 1 will be inserted to the right of the string.

The backspace key: if the string is empty, nothing happens. Otherwise, the rightmost letter of the string is deleted.

Sig has launched the editor, and pressed these keys several times. You are given a string s, which is a record of his keystrokes in order. In this string, the letter 0 stands for the 0 key, the letter 1 stands for the 1 key and the letter B stands for the backspace key. What string is displayed in the editor now?

Constraints

1 ≦ |s| ≦ 10 (|s| denotes the length of s)

s consists of the letters 0, 1 and B.

The correct answer is not an empty string.

Input

The input is given from Standard Input in the following format:

s

Output

Print the string displayed in the editor in the end.

Sample Input 1

01B0

Sample Output 1

00

Each time the key is pressed, the string in the editor will change as follows: 0, 01, 0, 00.

Sample Input 2

0BB1

Sample Output 2

1

Each time the key is pressed, the string in the editor will change as follows: 0, (empty), (empty), 1.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;

using ll = long long;
#define int long long

#define LOG(variable) cout << #variable":\t" << (variable) << endl
#define LOGCON(i, container) for(int (i) = 0; (i) < (container).size(); ++(i)) cout << (i) << ":\t" << (container)[(i)] << endl
#define REP(i, n) for (int i = 0; i < (n); ++i)
#define REPS(i, r, n) for (int i = (r); i < (n); ++i)
#define REPR(i, n) for(int i = (n); i >= 0; --i) // from n to 0
#define REPRS(i, r, n) for(int i = (n); i >= (r); --i) // from n to r
#define REPOBJ(itr, obj) for(auto itr = (obj).begin(); itr != (obj).end() ; ++itr)
#define REPROBJ(itr, obj) for(auto itr = (obj).rbegin(), e = (obj).rend(); itr != e; ++itr)
#define COUTB(x) cout << (x) << "\n"
#define COUTS(x) cout << (x) << " "
#define PB push_back
#define SORT(obj) sort((obj).begin(), (obj).end())
#define SORTR(obj) sort((obj).begin(), (obj).end(), greater<>())
#define ALL(obj) (obj).begin(), (obj).end()
#define MOD 1000000007
#define PI (acos(-1))
struct mint {
  ll x; // typedef long long ll;
  mint(ll x=0):x((x%MOD+MOD)%MOD){}
  mint operator-() const { return mint(-x);}
  mint& operator+=(const mint a) {
    if ((x += a.x) >= MOD) x -= MOD;
    return *this;
  }
  mint& operator-=(const mint a) {
    if ((x += MOD-a.x) >= MOD) x -= MOD;
    return *this;
  }
  mint& operator*=(const mint a) { (x *= a.x) %= MOD; return *this;}
  mint operator+(const mint a) const { return mint(*this) += a;}
  mint operator-(const mint a) const { return mint(*this) -= a;}
  mint operator*(const mint a) const { return mint(*this) *= a;}
  mint pow(ll t) const {
    if (!t) return 1;
    mint a = pow(t>>1);
    a *= a;
    if (t&1) a *= *this;
    return a;
  }

  // for prime MOD
  mint inv() const { return pow(MOD-2);}
  mint& operator/=(const mint a) { return *this *= a.inv();}
  mint operator/(const mint a) const { return mint(*this) /= a;}
};
istream& operator>>(istream& is, const mint& a) { return is >> a.x;}
ostream& operator<<(ostream& os, const mint& a) { return os << a.x;}
int in() {int x; cin>>x; return x;}
string stin() {string s; cin>>s; return s;}
/***** MAIN *****/
signed main() {
  string s = stin();
  deque<char> que;
  for(int i = 0; i < s.size(); ++i) {
    if(s[i] == 'B') {
      if(que.empty()) continue;
      que.pop_back();
    } else {
      que.push_back(s[i]);
    }
  }
  while(!que.empty()) {
    cout << que.front();
    que.pop_front();
  }
  cout << "\n";
  return 0;
}
/***** MAIN *****/