Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;
#define rep(i,n) for( int  i = 0 ; i < n ; i++ ) 
typedef long long ll ;

int main(){
    int N ;
    cin >> N ;
    for(int i = 1 ; i < 3501 ; i++ ){
        for(int j = 1 ; j < 3501 ; j++ ){
        if( (4*i*j-N*i-N*j) > 0 ){
            if( (N*i*j)%(4*i*j-N*i-N*j) == 0 )
        {
            cout << (ll) i << ' ' << (ll) j << ' ' << (ll) (N*i*j)/(4*i*j-N*i-N*j) ;
            return 0 ;
        }
    }
        }
    }
        
}