Problem:
Score : 300 points

Problem Statement

To make it difficult to withdraw money, a certain bank allows its customers to withdraw only one of the following amounts in one operation:

1 yen (the currency of Japan)

6 yen, 6^2(=36) yen, 6^3(=216) yen, ...

9 yen, 9^2(=81) yen, 9^3(=729) yen, ...

At least how many operations are required to withdraw exactly N yen in total?

It is not allowed to re-deposit the money you withdrew.

Constraints

1 \leq N \leq 100000

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If at least x operations are required to withdraw exactly N yen in total, print x.

Sample Input 1

127

Sample Output 1

4

By withdrawing 1 yen, 9 yen, 36(=6^2) yen and 81(=9^2) yen, we can withdraw 127 yen in four operations.

Sample Input 2

3

Sample Output 2

3

By withdrawing 1 yen three times, we can withdraw 3 yen in three operations.

Sample Input 3

44852

Sample Output 3

16

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
#include <bits/stdc++.h>

using namespace std;
using ll=long long;
using ld=long double;
using P=pair<ll,ll>;
#define FOR(i,n,m) for(ll i=n; i<(ll)m;i++)
#define FORr(i,n,m) for(ll i=n; i>(ll)m; i--)
#define cinv(v,n,m) FOR(i,n,m) cin>>v.at(i)
#define coutv(v,n,m) FOR(i,n,m) cout<<v.at(i) <<" "
#define cout(n) cout<<fixed<<setprecision(n)
int main(){
	ll N;
	cin>>N;
	ll res=1e9;
	ll i6=0,i9=0;
	int a;
	FOR(i,0,N){
		a=i;
		i6=0;
		i9=0;
		while(a!=0){
			i6+=a%6;
			a = a/6;
		}

		a=N-i;
		while(a!=0){
			i9+=a%9;
			a = a/9;
		}
		if(i6+i9<res) res=i6+i9;
	}
	cout<<res<<endl;
}