Problem:
Score : 300 points

Problem Statement

There are N slimes lining up from left to right. The colors of these slimes will be given as a string S of length N consisting of lowercase English letters. The i-th slime from the left has the color that corresponds to the i-th character of S.

Adjacent slimes with the same color will fuse into one larger slime without changing the color. If there were a slime adjacent to this group of slimes before fusion, that slime is now adjacent to the new larger slime.

Ultimately, how many slimes will be there?

Constraints

1 \leq N \leq 10^5

|S| = N

S consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

N
S

Output

Print the final number of slimes.

Sample Input 1

10
aabbbbaaca

Sample Output 1

5

Ultimately, these slimes will fuse into abaca.

Sample Input 2

5
aaaaa

Sample Output 2

1

All the slimes will fuse into one.

Sample Input 3

20
xxzaffeeeeddfkkkkllq

Sample Output 3

10

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <vector>
#include <queue>
#include <set>
#include <map>
#include <algorithm>
#include <numeric>
#include <cmath>
#include <limits>
#include <string>
#include <bitset>
#include <functional>
#include <iomanip>

using namespace std;
using lint = long long;
using vb = vector<bool>;
using vi = vector<int>;
using vl = vector<int>;
using pii = pair<int, int>;
using pll = pair<lint, lint>;
using pqi = priority_queue<int>;
using pql = priority_queue<lint>;
#define mii = map<int, int>
#define rep(i, n) for (int i = 0; i < (n); i++)
#define repr(i, n) for (int i = (n); i > 0; i--)
#define rep1(i, n) for (int i = 1; i <= (n); i++)
#define repf(i, f, n) for (int i = (f); i < (n); i++)
#define mp(x, y) make_pair((x), (y))
#define pb(x) push_back((x))
#define all(x) (x).begin(), (x).end()
#define allr(x) (x).rbegin(), (x).rend()
#define foreach(it, x) for (auto it = (x).begin(); it != (x).end(); it++)
#define space (char)0x20

constexpr lint MOD = 1e9 + 7;
int A, B, C, D, E, F, G, H, I, J, K, L, M, N;
int O, P, Q, R, S, T, U, V, W, X, Y, Z;
string s;
int ans = 1;

int main() {
	ios::sync_with_stdio(false);
	cin.tie(0);
 
	cin >> N >> s;
    rep1(i, N-1) {
        if (s[i-1] != s[i]) ans++;
    }

    cout << ans << endl;
    return 0;
}