Problem:
Score : 300 points

Problem Statement

You are given a sequence of length N: A_1, A_2, ..., A_N.
For each integer i between 1 and N (inclusive), answer the following question:

Find the maximum value among the N-1 elements other than A_i in the sequence.

Constraints

2 \leq N \leq 200000

1 \leq A_i \leq 200000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1
:
A_N

Output

Print N lines. The i-th line (1 \leq i \leq N) should contain the maximum value among the N-1 elements other than A_i in the sequence.

Sample Input 1

3
1
4
3

Sample Output 1

4
3
4

The maximum value among the two elements other than A_1, that is, A_2 = 4 and A_3 = 3, is 4.

The maximum value among the two elements other than A_2, that is, A_1 = 1 and A_3 = 3, is 3.

The maximum value among the two elements other than A_3, that is, A_1 = 1 and A_2 = 4, is 4.

Sample Input 2

2
5
5

Sample Output 2

5
5

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

// ========================================================================================================
// Library
// ========================================================================================================
#define _CRT_SECURE_NO_WARNINGS

#include <bits/stdc++.h>
using namespace std;

// competitive macro
#define FOR(i, a, b) for (int i = (a); i < (b); i++)
#define RFOR(i, a, b) for (int i = (b) - 1; i >= (a); i--)
#define REP(i, n) for (int i = 0; i < (n); i++)
#define RREP(i ,n) for (int i = (n) - 1; i >= 0; i--)
#define LL long long
#define ULL unsigned long long


void fastIOS()
{
	cin.tie(0);
	ios::sync_with_stdio(false);
}
// ========================================================================================================
// ========================================================================================================

int main()
{
	fastIOS();

    int n; cin >> n;
    int indexMax = -1;
    int max1 = -1 , max2 = -1;
    
    for(int i = 0; i< n; i++)
    {
        int tmp; cin >> tmp;
        
        if(tmp > max1)
        {
            max2 = max1;
            max1 = tmp;
            indexMax = i;
        }
        
        else if(tmp > max2)
        {
            max2 = tmp;
        }
    }
    
    for(int i = 0; i< n; i++)
    {
        if(i != indexMax)
        {
            cout << max1 << endl;
        }
        else{
            cout << max2 << endl;
        }
    }
    
    return 0;
}