Problem:
Score : 200 points

Problem Statement

An integer N is a multiple of 9 if and only if the sum of the digits in the decimal representation of N is a multiple of 9.

Determine whether N is a multiple of 9.

Constraints

0 \leq N < 10^{200000}

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a multiple of 9, print Yes; otherwise, print No.

Sample Input 1

123456789

Sample Output 1

Yes

The sum of these digits is 1+2+3+4+5+6+7+8+9=45, which is a multiple of 9, so 123456789 is a multiple of 9.

Sample Input 2

0

Sample Output 2

Yes

Sample Input 3

31415926535897932384626433832795028841971693993751058209749445923078164062862089986280

Sample Output 3

No

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define fastio ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);
#define ll long long int
#define MP make_pair
#define ull unsigned long long int
#define F first
#define S second
#define put insert
#define pb push_back
#define rsortV(arr) sort(arr.begin(),arr.end(),greater<int>())
#define sortV(arr) sort(arr.begin(),arr.end())
#define sortA(arr,n) sort(arr,arr+n)
#define rsortA(arr,n) sort(arr,arr+n,greater<int>())
#define arrInput(arr,n) for(int i=0;i<n;i++) cin>>arr[i];
#define rev(arr) reverse(arr.begin(), arr.end())
#define all(x) (x).begin(), (x).end()
ll MOD = 1e9+7;
int main() {
    fastio
    // int t;
    // cin>>t;
    // while(t--) {
    string s;
    cin>>s;
    vector<ll> arr(10,0);
    for(char c : s) {
        arr[c-'0'] = (arr[c-'0']+1)%9;
    }
    ll sum = 0;
    for(ll i=0;i<10;i++)
        sum += (i*arr[i])%9;
    cout<<((sum%9==0)?"Yes":"No");
    // }
    return 0;
}