Problem:
Score : 400 points

Problem Statement

Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.

You are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.

Constraints

2 ≦ |s| ≦ 10^5

s consists of lowercase letters.

Partial Score

200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.

Input

The input is given from Standard Input in the following format:

s

Output

If there exists no unbalanced substring of s, print -1 -1.

If there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.

Sample Input 1

needed

Sample Output 1

2 5

The string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.

Sample Input 2

atcoder

Sample Output 2

-1 -1

The string atcoder contains no unbalanced substring.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <iostream>
using namespace std;
#include <vector>
#include <stdio.h>
#include <algorithm>
#define _USE_MATH_DEFINES
#include <math.h>
#include <string>
#include <cstdlib>

int dx[8] = {1, 2, 1, 2, -1, -2, -1, -2}, dy[8] = {2, 1, -2, -1, -2, -1, 2, 1};

int main() {

	string s; cin >> s;
	for(int i = 0; i < s.length()-1; i++) {
		if(s[i] == s[i+1]) {cout << i+1 << " " << i+2 <<endl; return 0;}
		if(i != s.length()-2 ) {
			if(s[i] == s[i+2]) {cout << i+1 << " " << i+3 <<endl; return 0;}
		}
	}
	cout << -1 <<endl;
	return 0;
}