Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define PI 3.14159265358979323846
#define int long long
constexpr int INF = numeric_limits<int>::max() / 2;
constexpr long long INFL = numeric_limits<long long>::max() / 2;
constexpr int MOD = 1000000007;
using Graph = vector<vector<int>>;



signed main() {
    cin.tie(nullptr);
    ios::sync_with_stdio(false);

    int N,A,B,C;
    cin>>N>>A>>B>>C;
    string s[N];
    rep(i,N) {
        cin >> s[i];
    }
    string ans="Yes";
    char v[N]={};
    rep(i,N){
        if(s[i]=="AB"){
            if(i+1<N &&A==1&&B==1){
                if(s[i+1]=="AC"){
                    v[i]='A';
                A++;
                B--;
                }else if(i+1<N &&s[i+1]=="BC"){
                    v[i]='B';
                A--;
                B++;
                }else {
                    v[i]='A';
                    i++;
                    v[i]='B';
                }
            }
            else if(A>=B) {
                v[i]='B';
                A--;
                B++;
            }else{
                v[i]='A';
                A++;
                B--;
            }
        }
        if(s[i]=="AC"){
            if(i+1<N &&A==1&&C==1){
                if(s[i+1]=="AB"){
                    v[i]='A';
                A++;
                C--;
                }else if(s[i+1]=="BC"){
                    v[i]='C';
                A--;
                C++;
                }else {
                    v[i]='A';
                    i++;
                    v[i]='C';
                }
            }
            else if(A>=C) {
                v[i]='C';
                A--;
                C++;
            }else{
                v[i]='A';
                A++;
                C--;
            }
        }
        if(s[i]=="BC"){
            if(i+1<N &&C==1&&B==1){
                if(i+1<N &&s[i+1]=="AC"){
                    v[i]='C';
                C++;
                B--;
                }else if(i+1<N &&s[i+1]=="AB"){
                    v[i]='B';
                C--;
                B++;
                }else {
                    v[i]='B';
                    i++;
                    if(i==N) break;
                    v[i]='C';
                }
            }
            else if(B>=C) {
                v[i]='C';
                B--;
                C++;
            }else{
                v[i]='B';
                B++;
                C--;
            }
        }
            if(A<0||B<0||C<0) {
                ans="No";
                break;
            }
    }
    if(ans=="No") cout << ans << endl;
    else{
        cout << ans << endl;
        rep(i,N){
            cout << v[i] << endl;
        }
    }





}