Problem:
Score : 300 points

Problem Statement

You are given N positive integers a_1, a_2, ..., a_N.

For a non-negative integer m, let f(m) = (m\ mod\ a_1) + (m\ mod\ a_2) + ... + (m\ mod\ a_N).

Here, X\ mod\ Y denotes the remainder of the division of X by Y.

Find the maximum value of f.

Constraints

All values in input are integers.

2 \leq N \leq 3000

2 \leq a_i \leq 10^5

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 ... a_N

Output

Print the maximum value of f.

Sample Input 1

3
3 4 6

Sample Output 1

10

f(11) = (11\ mod\ 3) + (11\ mod\ 4) + (11\ mod\ 6) = 10 is the maximum value of f.

Sample Input 2

5
7 46 11 20 11

Sample Output 2

90

Sample Input 3

7
994 518 941 851 647 2 581

Sample Output 3

4527

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

/*input
7
994 518 941 851 647 2 581
*/
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
using namespace std;
using namespace __gnu_pbds;
#define REP(i,j,k)     for(int i = j ; i < k ; ++i)
#define RREP(i,j,k)    for(int i = j ; i >=k ; --i)
#define A    first
#define B    second
#define mp   make_pair
#define pb   emplace_back
#define PII pair<int , int>
#define MEM(i,j)   memset(i , j , sizeof i)
#define ALL(i)     i.begin() , i.end()
#define DBGG(i,j)     cout << i << " " << j << endl
#define DB4(i,j,k,l)  cout << i << " " << j << " " << k << " " << l << endl
#define IOS cin.tie(0) , cout.sync_with_stdio(0)
#define endl "\n"
///------------------------------------------------------------
#define int long long
#define MAX 3030
#define INF 0x3f3f3f3f

int n , x[MAX];
int32_t main(){
    IOS;
    cin >> n;
    REP(i , 1 , n + 1) cin >> x[i];
    int ans = 0;
    REP(i , 1 , n + 1) ans += x[i] - 1;
    cout << ans << endl;
    return 0;
}