Problem:
Score : 200 points

Problem Statement

Let w be a string consisting of lowercase letters.
We will call w beautiful if the following condition is satisfied:

Each lowercase letter of the English alphabet occurs even number of times in w.

You are given the string w. Determine if w is beautiful.

Constraints

1 \leq |w| \leq 100

w consists of lowercase letters (a-z).

Input

The input is given from Standard Input in the following format:

w

Output

Print Yes if w is beautiful. Print No otherwise.

Sample Input 1

abaccaba

Sample Output 1

Yes

a occurs four times, b occurs twice, c occurs twice and the other letters occur zero times.

Sample Input 2

hthth

Sample Output 2

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Runtime Error)

#include<iostream>
#include<algorithm>
#include<vector>
#include<string.h>
#include<cstdlib>
#include<map>
#include<fstream>
#include<string>
#include<sstream>
#include<iomanip>
#include<cmath>

using namespace std;

long long dp[3][100100] = {};
const long long INF = 1LL << 60;
#define MOD 1000000007

template<class T> inline bool chmin(T & a, T b) { if (a > b) { a = b; return true; } return false; }
template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return true; } return false; }

/**
* @fn
* 最大値を取ります.Vector<int>を渡すこと.
*/
long long int imax(vector<int> a) {
	int MAX = -10000000;
	for (int i = 0; i < a.size(); i++) {
		if (MAX < a.at(i)) MAX = a.at(i);
	}
	return MAX;
}

/**
* @fn
* 最小値を取ります.Vector<int>を渡すこと.
*/
long long int imin(vector<int> a) {
	int MIN = 1000000000;
	for (int i = 0; i < a.size(); i++) {
		if (MIN > a.at(i)) MIN = a.at(i);
	}
	return MIN;
}


long long int absmin(vector<int> a, long long int b) {
	int mini = 100000000;
	int d = 0;
	for (int i = 0; i < a.size(); i++) {
		if (mini > abs(a.at(i) - b)) {
			mini = abs(a.at(i) - b);
			d = i;
		}
	}
	return d;
}

int gcd(int a, int b)
{
	if (a < b) swap(a, b);
	if (b < 1) return -1;
	if (a % b == 0) return b;
	return gcd(b, a % b);
}

//ここまでライブラリ
//ここから本文

long long int tpimin(vector<int> a) {
	int MIN = 1000000000;
	int number = 0;
	for (int i = 0; i < a.size(); i++) {
		if (MIN > a.at(i)) MIN = a.at(i);
		number = i;
	}
	return number;
}


int main() {
	string s;
	vector<int> a(120);
	cin >> s;
	for (int i = 0; i < s.length(); i++) {
		a.at(s.at(i))++;
	}
	for (int i = 0; i < 120; i++) {
		if (a.at(i) % 2 != 0) {
			cout << "No" << endl;
			return 0;
		}
	}
	cout << "Yes" << endl;
}