Problem:
Score : 300 points

Problem Statement

Sitting in a station waiting room, Joisino is gazing at her train ticket.

The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).

In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.

The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Constraints

0≤A,B,C,D≤9

All input values are integers.

It is guaranteed that there is a solution.

Input

Input is given from Standard Input in the following format:

ABCD

Output

Print the formula you made, including the part =7.

Use the signs + and -.

Do not print a space between a digit and a sign.

Sample Input 1

1222

Sample Output 1

1+2+2+2=7

This is the only valid solution.

Sample Input 2

0290

Sample Output 2

0-2+9+0=7

0 - 2 + 9 - 0 = 7 is also a valid solution.

Sample Input 3

3242

Sample Output 3

3+2+4-2=7

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
#define MAX_N 10000
#define INF 1e9

using namespace std;

typedef int long long ll;
typedef int long l;
typedef pair<int, int> Pii;
const ll MOD = 1000000007;

void ii(int x){
    x>=0?printf("+%d",x):printf("%d",x);
}

int main() {
    cin.tie(0);
    ios::sync_with_stdio(false);
    char a[4];
    cin>>a;
    int x[4];
    for (int i = 0; i < 4; i++){
        x[i]=int(a[i])-int('0');
    }
    for (int i = -1; i < 2; i+=2){
        int ans=x[0];
        ans+=i*x[1];
        for (int j = -1; j < 2; j+=2){
            ans+=j*x[2];
            for (int k = -1; k < 2; k+=2){
                ans+=k*x[3];
                if(ans==7){
                    printf("%d",x[0]);
                    ii(x[1]*i);
                    ii(x[2]*j);
                    ii(x[3]*k);
                    printf("=%d\n",7);
                    return 0;
                }
                ans-=k*x[2];
            }
            ans-=j*x[1];
        }
    }

    
    return 0;
}