Problem:
Score : 100 points

Problem Statement

Takahashi is a member of a programming competition site, ButCoder.

Each member of ButCoder is assigned two values: Inner Rating and Displayed Rating.

The Displayed Rating of a member is equal to their Inner Rating if the member has participated in 10 or more contests. Otherwise, the Displayed Rating will be their Inner Rating minus 100 \times (10 - K) when the member has participated in K contests.

Takahashi has participated in N contests, and his Displayed Rating is R. Find his Inner Rating.

Constraints

All values in input are integers.

1 \leq N \leq 100

0 \leq R \leq 4111

Input

Input is given from Standard Input in the following format:

N R

Output

Print his Inner Rating.

Sample Input 1

2 2919

Sample Output 1

3719

Takahashi has participated in 2 contests, which is less than 10, so his Displayed Rating is his Inner Rating minus 100 \times (10 - 2) = 800.

Thus, Takahashi's Inner Rating is 2919 + 800 = 3719.

Sample Input 2

22 3051

Sample Output 2

3051

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#define _DEBUG 1
#define _GLIBCXX_DEBUG

#include <bits/stdc++.h>
using namespace std;

using ll = long long;

#ifdef _DEBUG
#define dump(x) cerr << #x << "=" << x << endl
#define dump2(x, y) cerr << #x << "=" << x << "," << #y << "=" << y << endl
#define dump3(x, y, z)                                                     \
  cerr << #x << "=" << x << "," << #y << "=" << y << "," << #z << "=" << z \
       << endl
#define check(s) cerr << s << endl
#else
#define dump(x)
#define dump2(x, y)
#define dump3(x, y, z)
#define check(s)
#endif

#define rep(i, n) for (int i = 0; i < n; i++)
#define repr(i, n) for (int i = n; i >= 0; i--)
#define FOR(i, m, n) for (int i = m; i < n; i++)
#define all(x) (x).begin(), (x).end()
#define sz(x) ((int)(x).size())
#define unique(v) v.erase(unique(v.begin(), v.end()), v.end());

const ll LINF = 2e18;
const int INF = 1e9;

void solve(ll N, ll R) {
  if (N >= 10) {
    cout << R << endl;
  } else {
    cout << R + 100 * (10 - N) << endl;
  }
}

int main() {
  cin.tie(0);
  ios::sync_with_stdio(false);
  cout << fixed << setprecision(15);
  ll N;
  scanf("%lld", &N);
  ll R;
  scanf("%lld", &R);
  solve(N, R);
  return 0;
}