Problem:
Score : 300 points

Problem Statement

You are given a sequence of length N: A_1, A_2, ..., A_N.
For each integer i between 1 and N (inclusive), answer the following question:

Find the maximum value among the N-1 elements other than A_i in the sequence.

Constraints

2 \leq N \leq 200000

1 \leq A_i \leq 200000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1
:
A_N

Output

Print N lines. The i-th line (1 \leq i \leq N) should contain the maximum value among the N-1 elements other than A_i in the sequence.

Sample Input 1

3
1
4
3

Sample Output 1

4
3
4

The maximum value among the two elements other than A_1, that is, A_2 = 4 and A_3 = 3, is 4.

The maximum value among the two elements other than A_2, that is, A_1 = 1 and A_3 = 3, is 3.

The maximum value among the two elements other than A_3, that is, A_1 = 1 and A_2 = 4, is 4.

Sample Input 2

2
5
5

Sample Output 2

5
5

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<bits/stdc++.h>
using namespace std;
 
#define cinsc ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(0);
#define all(cont) cont.begin(), cont.end()
#define rall(cont) cont.end(), cont.begin()
#define FOR(i,k,n)  for(int64 i=k;i<(int)n;i++)
#define FOREACH(it, l) for (auto it = l.begin(); it != l.end(); it++)
#define IN(A, B, C) assert( B <= A && A <= C)
#define MP make_pair
#define PB push_back
#define INF (int)1e9
#define EPS 1e-9
#define PI 3.1415926535897932384626433832795
#define MOD 1000000007
#define read(type) readInt<type>()
#define SQ(x) ((x)*(x))
const double pi=acos(-1.0);
typedef pair<int, int> PII;
typedef vector<int> VI;
typedef vector<string> VS;
typedef vector<PII> VII;
typedef vector<VI> VVI;
typedef map<int,int> MPII;
typedef set<int> SETI;
typedef multiset<int> MSETI;
typedef long int int32;
typedef unsigned long int uint32;
typedef long long int int64;
typedef unsigned long long int  uint64;
 
//ONLINE_JUDGE   LOCAL
 
int64 powr(int64 x,int64 y,int64 p)  
{  
    int res = 1;    
    x = x % p; 
    if (x == 0) return 0;
    while (y > 0){   
        if (y & 1)  
            res = (res*x) % p;   
        y = y>>1; 
        x = (x*x) % p;  
    }  
    return res;  
} 
 
void  in_o(){
#ifndef LOCAL
	freopen("input.txt","r",stdin);
	freopen("output.txt","w",stdout);
#endif
	cinsc;
}
 
int64 a[200001];
 
int main(){
	//in_o();
	int64 n;
	cin>>n;
	FOR(i,0,n){
		cin>>a[i];
	}
	int64 mx=0,second_mx=0;
	FOR(i,0,n){
		if(a[i]>mx){
			mx=a[i];
		}
	}
	FOR(i,0,n){
		if(a[i]>second_mx && a[i]!=mx){
			second_mx=a[i];
		}
	}
	if(second_mx==0)
		second_mx=a[0];
	FOR(i,0,n){
		if(a[i]==mx)
			cout<<second_mx<<endl;
		else
			cout<<mx<<endl;
	}	
	return 0;
}