Problem:
Score : 200 points

Problem Statement

AtCoDeer the deer found two rectangles lying on the table, each with height 1 and width W.
If we consider the surface of the desk as a two-dimensional plane, the first rectangle covers the vertical range of [0,1] and the horizontal range of [a,a+W], and the second rectangle covers the vertical range of [1,2] and the horizontal range of [b,b+W], as shown in the following figure:

AtCoDeer will move the second rectangle horizontally so that it connects with the first rectangle.
Find the minimum distance it needs to be moved.

Constraints

All input values are integers.

1≤W≤10^5

1≤a,b≤10^5

Input

The input is given from Standard Input in the following format:

W a b

Output

Print the minimum distance the second rectangle needs to be moved.

Sample Input 1

3 2 6

Sample Output 1

1

This input corresponds to the figure in the statement. In this case, the second rectangle should be moved to the left by a distance of 1.

Sample Input 2

3 1 3

Sample Output 2

0

The rectangles are already connected, and thus no move is needed.

Sample Input 3

5 10 1

Sample Output 3

4

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using ll = long long;
#define FOR(i, k, n) for(ll i = (k); i < (n); i++)
#define FORe(i, k, n) for(ll i = (k); i <= (n); i++)
#define FORr(i, k, n) for(ll i = (k)-1; i > (n); i--)
#define FORre(i, k, n) for(ll i = (k)-1; i >= (n); i--)
#define REP(i, n) FOR(i, 0, n)
#define REPr(i, n) FORre(i, n, 0)
#define ALL(x) (x).begin(), (x).end()
#define ALLr(x) (x).rbegin(), (x).rend()
#define chmin(x, y) x = min(x, y)
#define chmax(x, y) x = max(x, y)
#define IN(p, a, b) a <= p && p <= b
using namespace std;

const int INF = 1001001001;

int main(void){
  int w, a, b;
  cin >> w >> a >> b;
  if(IN(b, a, a+w) || IN(b+w, a, a+w)){
    cout << 0 << endl;
    return 0;
  }
  cout << min(abs(a+w-b), abs(b+w-a)) << endl;
  return 0;
}