Problem:
Score : 200 points

Problem Statement

N Snukes called Snuke 1, Snuke 2, ..., Snuke N live in a town.

There are K kinds of snacks sold in this town, called Snack 1, Snack 2, ..., Snack K. The following d_i Snukes have Snack i: Snuke A_{i, 1}, A_{i, 2}, \cdots, A_{i, {d_i}}.

Takahashi will walk around this town and make mischief on the Snukes who have no snacks. How many Snukes will fall victim to Takahashi's mischief?

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq K \leq 100

1 \leq d_i \leq N

1 \leq A_{i, 1} < \cdots < A_{i, d_i} \leq N

Input

Input is given from Standard Input in the following format:

N K
d_1
A_{1, 1} \cdots A_{1, d_1}
\vdots
d_K
A_{K, 1} \cdots A_{K, d_K}

Output

Print the answer.

Sample Input 1

3 2
2
1 3
1
3

Sample Output 1

1

Snuke 1 has Snack 1.

Snuke 2 has no snacks.

Snuke 3 has Snack 1 and 2.

Thus, there will be one victim: Snuke 2.

Sample Input 2

3 3
1
3
1
3
1
3

Sample Output 2

2

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
typedef long long ll;
const int INF = 1e9;
const int MOD = 1e9 + 7;
using namespace std;

//ループマクロ
#define FOR(i , a , b)  for(int i = (a) ; i < (b) ; i++)
#define REP(i , n)      for(int i = 0 ; i < n ; i++)
#define REPR(i , n)     for(int i = n ; 0 <= i ; i--)
#define ROP(i, n)       for(int i = 1 ; i <= n ; i++)

//入出力
#define SCOUT(x) cout << (x) << " "
#define VECCIN(x) for(auto& ele : (x) ) cin >> ele
#define VECOUT(x) for(auto& ele : (x) ) cout << ele << " "; cout << endl;

//その他
#define ALL(obj) (obj).begin() , (obj).end() 
#define SORT(obj) sort(ALL(obj))
#define GSORT(obj) sort(ALL(obj) , greater<int>())
#define P pair<int , int>
#define V vector<int>
#define VLL vector<long long>
#define M map<int, int>
#define S set<int>
#define PQ priority_queue<int>
#define PQG priority_queue<int , V , greater<int>>

int main(void) {

	ios::sync_with_stdio(false);	cin.tie(0);
    int N, K;  cin >> N >> K;
    vector<bool> hoge(N);  fill(ALL(hoge), false);
    REP(i, K){
      int d;  cin >> d;
      REP(j, d){  int A;  cin >> A;  hoge[A-1] = true;  }
    }

    int ans = 0;
    REP(i, N)
      if(hoge[i] == false)  ans++;
    cout << ans << endl;
	return 0;
}