Problem:
Score : 400 points

Problem Statement

You are given N integers; the i-th of them is A_i.
Find the maximum possible sum of the absolute differences between the adjacent elements after arranging these integers in a row in any order you like.

Constraints

2 \leq N \leq 10^5

1 \leq A_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1
:
A_N

Output

Print the maximum possible sum of the absolute differences between the adjacent elements after arranging the given integers in a row in any order you like.

Sample Input 1

5
6
8
1
2
3

Sample Output 1

21

When the integers are arranged as 3,8,1,6,2, the sum of the absolute differences between the adjacent elements is |3 - 8| + |8 - 1| + |1 - 6| + |6 - 2| = 21. This is the maximum possible sum.

Sample Input 2

6
3
1
4
1
5
9

Sample Output 2

25

Sample Input 3

3
5
5
1

Sample Output 3

8

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include "bits/stdc++.h"
using namespace std;

typedef long long ll;
typedef pair <int, int> ii;
typedef pair <int, ii> iii;
typedef pair<ll, ll> pll;
typedef pair<double, int> pdi;
typedef pair<ll, int> pli;
typedef pair<int, ll> pil;
#ifdef VC
#define scanf scanf_s
#endif
#define iINF (1<<30)
#define INF (1LL<<59)
#define forn(i) for(int i = 0;i < n; ++i)
#define form(i,n) for(int i = 0 ;i < n; ++i)
#define NIL -1

const ll mod = 998244353;
int n;
int m;
int ans = 0;

int main(){
	int a[100010];
	int j = 0, l,r;
	cin >> n;
	forn(i) {
		cin >> a[i];
	}
	sort(a, a+n);
	l = 0;
	r = n - 1;
	int ans = 0;
	while (r-l>2) {
		ans += 2 * a[r];
		ans -= 2 * a[l];
		l++;
		r--;
	}
	ans = abs(ans);
	if (r - l == 2) {
		ans += max(2 * a[r] - a[l] - a[l + 1], a[r]+a[r-1]-2*a[l]);
	}
	else {
		ans += a[r] - a[l];
	}
	cout << ans << endl;
	return 0;
}