Problem:
Score : 300 points

Problem Statement

There are N slimes lining up from left to right. The colors of these slimes will be given as a string S of length N consisting of lowercase English letters. The i-th slime from the left has the color that corresponds to the i-th character of S.

Adjacent slimes with the same color will fuse into one larger slime without changing the color. If there were a slime adjacent to this group of slimes before fusion, that slime is now adjacent to the new larger slime.

Ultimately, how many slimes will be there?

Constraints

1 \leq N \leq 10^5

|S| = N

S consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

N
S

Output

Print the final number of slimes.

Sample Input 1

10
aabbbbaaca

Sample Output 1

5

Ultimately, these slimes will fuse into abaca.

Sample Input 2

5
aaaaa

Sample Output 2

1

All the slimes will fuse into one.

Sample Input 3

20
xxzaffeeeeddfkkkkllq

Sample Output 3

10

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define F first
#define S second
#define pb push_back
#define f(i,x,n) for(int i=x;i<n;i++)
#define all(c) c.begin(),c.end()
#define int ll
using ll = long long;
using pii = pair<int,int>;
const int MOD = 1e9+7, N = 1e5 + 10; 

int32_t main(){
   ios::sync_with_stdio(false);
   cin.tie(NULL);
   int n;
   cin >> n;
   string s;
   cin >> s;
   int ans = 1;
   f(i,1,n){
      if(s[i]!=s[i-1]){
         ans++;
      }
   }
   cout << ans << '\n';
   return 0;
}