Problem:
Score : 300 points

Problem Statement

A company has N members, who are assigned ID numbers 1, ..., N.

Every member, except the member numbered 1, has exactly one immediate boss with a smaller ID number.

When a person X is the immediate boss of a person Y, the person Y is said to be an immediate subordinate of the person X.

You are given the information that the immediate boss of the member numbered i is the member numbered A_i. For each member, find how many immediate subordinates it has.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq A_i < i

Input

Input is given from Standard Input in the following format:

N
A_2 ... A_N

Output

For each of the members numbered 1, 2, ..., N, print the number of immediate subordinates it has, in its own line.

Sample Input 1

5
1 1 2 2

Sample Output 1

2
2
0
0
0

The member numbered 1 has two immediate subordinates: the members numbered 2 and 3.

The member numbered 2 has two immediate subordinates: the members numbered 4 and 5.

The members numbered 3, 4, and 5 do not have immediate subordinates.

Sample Input 2

10
1 1 1 1 1 1 1 1 1

Sample Output 2

9
0
0
0
0
0
0
0
0
0

Sample Input 3

7
1 2 3 4 5 6

Sample Output 3

1
1
1
1
1
1
0

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <iostream>//cout<<right で右揃え
#include <iomanip>//cout<<setw(数字) で空白による桁揃え
#include <string>
#include <vector>
#include <queue>
#include <algorithm>
#include <cstdlib>//abs()で整数絶対値
#include <cmath>//abs()かfabs()で少数絶対値
#include <functional>//sort第三引数greater<型名>()で降順

using namespace std;
using ll = long long int;

int main(){
    int N;cin>>N;
    vector<int> A(N);
    for(int i=1;i<N;i++){
        int a;cin>>a;
        A[a]++;
    }
    for(int i=0;i<N;i++){
        cout << A[i] << endl;
    }
    return 0;
}