Problem:
Score : 200 points

Problem Statement

There are N cities and M roads.
The i-th road (1≤i≤M) connects two cities a_i and b_i (1≤a_i,b_i≤N) bidirectionally.
There may be more than one road that connects the same pair of two cities.
For each city, how many roads are connected to the city?

Constraints

2≤N,M≤50

1≤a_i,b_i≤N

a_i ≠ b_i

All input values are integers.

Input

Input is given from Standard Input in the following format:

N M
a_1 b_1
:
a_M b_M

Output

Print the answer in N lines.
In the i-th line (1≤i≤N), print the number of roads connected to city i.

Sample Input 1

4 3
1 2
2 3
1 4

Sample Output 1

2
2
1
1

City 1 is connected to the 1-st and 3-rd roads.

City 2 is connected to the 1-st and 2-nd roads.

City 3 is connected to the 2-nd road.

City 4 is connected to the 3-rd road.

Sample Input 2

2 5
1 2
2 1
1 2
2 1
1 2

Sample Output 2

5
5

Sample Input 3

8 8
1 2
3 4
1 5
2 8
3 7
5 2
4 1
6 8

Sample Output 3

3
3
2
2
2
1
1
2

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;

void fnInput(map<int, int>& rmpCity)
{
  int nCitySiz, nRoadSiz;
  cin >> nCitySiz >> nRoadSiz;

  for (int i = 0; i < nCitySiz; i++)
    rmpCity[i] = 0;

  for (int i = 0; i < nRoadSiz; i++)
  {
    int nFromCity, nToCity;
    cin >> nFromCity >> nToCity;
    rmpCity[nFromCity]++;
    rmpCity[nToCity]++;
  }
}

int fnRoadNumOut(const map<int, int>& cnrmpCity)
{
  for (pair<const int, int> PCity : cnrmpCity)
    cout << PCity.second << endl;
}

int main()
{
  map<int, int> mpCity;

  fnInput(mpCity);
  fnRoadNumOut(mpCity);

  return 0;
}