Problem:
Score : 500 points

Problem Statement

Given are two strings s and t consisting of lowercase English letters. Determine if there exists an integer i satisfying the following condition, and find the minimum such i if it exists.

Let s' be the concatenation of 10^{100} copies of s. t is a subsequence of the string {s'}_1{s'}_2\ldots{s'}_i (the first i characters in s').

Notes

A subsequence of a string a is a string obtained by deleting zero or more characters from a and concatenating the remaining characters without changing the relative order. For example, the subsequences of contest include net, c, and contest.

Constraints

1 \leq |s| \leq 10^5

1 \leq |t| \leq 10^5

s and t consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s
t

Output

If there exists an integer i satisfying the following condition, print the minimum such i; otherwise, print -1.

Sample Input 1

contest
son

Sample Output 1

10

t = son is a subsequence of the string contestcon (the first 10 characters in s' = contestcontestcontest...), so i = 10 satisfies the condition.

On the other hand, t is not a subsequence of the string contestco (the first 9 characters in s'), so i = 9 does not satisfy the condition.

Similarly, any integer less than 9 does not satisfy the condition, either. Thus, the minimum integer i satisfying the condition is 10.

Sample Input 2

contest
programming

Sample Output 2

-1

t = programming is not a substring of s' = contestcontestcontest.... Thus, there is no integer i satisfying the condition.

Sample Input 3

contest
sentence

Sample Output 3

33

Note that the answer may not fit into a 32-bit integer type, though we cannot put such a case here.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;


//TEMPLATE
#define pb                push_back
#define mp                make_pair
#define ll                long long
#define ld                long double
#define pii               pair <ll, ll>
#define piii              pair <ll, pii>
#define F                 first
#define S                 second

#define newline           printf("\n")
#define minusone          printf("-1\n")
#define zeroo             printf("0\n")
#define scl1(a)           scanf("%lld", &a)
#define scl2(a, b)        scanf("%lld %lld", &a, &b)
#define scl3(a, b, c)     scanf("%lld %lld %lld", &a, &b, &c)
#define prl1(a)           printf("%lld\n", a)
#define prl2(a, b)        printf("%lld %lld\n", a, b)
#define ssl1(s)           scanf(" %[^\n]", s)
#define scd1(a)           scanf("%lf", &a)
#define scd2(a, b)        scanf("%lf %lf", &a, &b)
#define prd(a)            printf("%lf\n", a)
#define prld(a)           printf("%Lf\n", a)
#define prcase(cs)        printf("Case %lld: ", cs)
#define cin1(a)           cin >> a
#define cin2(a, b)        cin >> a >> b
#define cin3(a, b, c)     cin >> a >> b >> c
#define cin4(a, b, c, d)  cin >> a >> b >> c >> d
#define cot1(a)           cout << a << "\n"
#define cot2(a, b)        cout << a << " " << b << "\n"
#define cot3(a, b, c)     cout << a << " " << b << " " << c << "\n"
#define cot4(a, b, c, d)  cout << a << " " << b << " " << c << " " << d << "\n"
#define cotline           cout << "\n"
#define cotminus          cout << "-1\n"
#define cot0              cout << "0\n"
#define cotyes            cout << "YES\n"
#define cotno             cout << "NO\n"
#define cotcase(cs)       cout << "Case " << cs << ": "

#define reversed(s)       reverse(s.begin(), s.end())
#define asort(s)          sort(s.begin(), s.end())
#define dsort(s)          sort(s.rbegin(), s.rend())
#define all(s)            s.begin(), s.end()
#define uniq(s)           s.resize(distance(s.begin(),unique(s.begin(), s.end())))
#define found(s, x)       (s.find(x) != s.end())

#define for0(i, n)        for (i = 0; i < n; i++)
#define for1(i, n)        for (i = 1; i <= n; i++)
#define fora(i, a, b)     for (i = a; i <= b; i++)
#define forb(i, b, a)     for (i = b; i >= a; i--)
#define fori(it, s)       for(auto it = s.begin(); it != s.end(); it++)

#define FR                ios_base::sync_with_stdio(false);cin.tie(NULL)
#define ms(a, x)          memset(a, x, sizeof a)
#define bitcount(n)       __builtin_popcountll(n)

//#define pi              3.1415926536
#define pi                acos(-1)

const ll INF = LLONG_MAX;
const ll SZ = 4e5+5;
const ll mod = 1e9+7;


ll n;
//ll a[SZ];
//ll b[SZ];

bool f[30], f1[30];
vector <ll> in[30];

int main() {
    ll cs = 0, tc = 1, x, y, z, i, j, k, g, p, q, ans = 0, sum = 0, c = 0, t = 0;
//    ll a, b, d;
    string s, s1, s2;

    cin2(s, s1);

    for0(i, s.size()) {
        x = s[i] - 'a';
        f[x] = 1;
        in[x].pb(i+1);
    }
    for(auto ch: s1) {
        x = ch - 'a';
        f1[x] = 1;
    }

    for0(i, 26) {
        if(f1[i] && !f[i]) {
            cotminus;
            return 0;
        }
    }

    k = 0;
    for0(i, s1.size()) {
        x = s1[i] - 'a';
        p = lower_bound(all(in[x]), k) - in[x].begin();
        if(p == in[x].size()) {
            ans += s.size();
            p = lower_bound(all(in[x]), 0) - in[x].begin();
        }
        k = in[x][p] + 1;
    }
    ans += (k-1);

    cot1(ans);

    return 0;
}