Problem:
Score : 300 points

Problem Statement

Takahashi is organizing a party.

At the party, each guest will receive one or more snack pieces.

Takahashi predicts that the number of guests at this party will be A or B.

Find the minimum number of pieces that can be evenly distributed to the guests in both of the cases predicted.

We assume that a piece cannot be divided and distributed to multiple guests.

Constraints

1 \leq A, B \leq 10^5

A \neq B

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the minimum number of pieces that can be evenly distributed to the guests in both of the cases with A guests and B guests.

Sample Input 1

2 3

Sample Output 1

6

When we have six snack pieces, each guest can take three pieces if we have two guests, and each guest can take two if we have three guests.

Sample Input 2

123 456

Sample Output 2

18696

Sample Input 3

100000 99999

Sample Output 3

9999900000

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define IOS ios_base::sync_with_stdio(0); cin.tie(); cout.tie();
#define ff first
#define ss second
#define pb push_back
#define debug(val) cerr << "The value of " << #val << " is = " << val << '\n';
typedef long long ll;
typedef unsigned long long ull;
const ll mod = 1e9 + 7;
const ll inf = 922337203685477;
const ll mininf = -922337203685477;
const ll nax = 1e5 + 5;

int main(){
	IOS
	ll a, b;
	cin >> a >> b;
	ll fpb=__gcd(a, b);
	cout << a*b/fpb << '\n';
}