Problem:
Score : 100 points

Problem Statement

You are given a three-digit positive integer N.

Determine whether N is a palindromic number.

Here, a palindromic number is an integer that reads the same backward as forward in decimal notation.

Constraints

100≤N≤999

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a palindromic number, print Yes; otherwise, print No.

Sample Input 1

575

Sample Output 1

Yes

N=575 is also 575 when read backward, so it is a palindromic number. You should print Yes.

Sample Input 2

123

Sample Output 2

No

N=123 becomes 321 when read backward, so it is not a palindromic number. You should print No.

Sample Input 3

812

Sample Output 3

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>

#define REP(i, n) for(decltype(n) i = 0; i < n; i++)

#define ALL(c)   c.begin(), c.end()
#define SORT(c)  std::sort(ALL(c))
#define RSORT(c) std::sort(ALL(c), std::greater<decltype(c)::value_type>())

using namespace std;
using ll = long long;

const int MOD  = (int)1e9 + 7;
const int INF  = (int)1e9 + 1;
const ll  LINF = (ll)1e18 + 1;

int main() {
    cin.tie(0);
    ios::sync_with_stdio(false);

    string N;
    std::cin >> N;

    if(N[0] == N[2]) {
        std::cout << "Yes" << std::endl;
    }
    else {
        std::cout << "No" << std::endl;
    }

    return 0;
}