Problem:
Score : 300 points

Problem Statement

Given is a permutation P_1, \ldots, P_N of 1, \ldots, N.
Find the number of integers i (1 \leq i \leq N) that satisfy the following condition:

For any integer j (1 \leq j \leq i), P_i \leq P_j.

Constraints

1 \leq N \leq 2 \times 10^5

P_1, \ldots, P_N is a permutation of 1, \ldots, N.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
P_1 ... P_N

Output

Print the number of integers i that satisfy the condition.

Sample Input 1

5
4 2 5 1 3

Sample Output 1

3

i=1, 2, and 4 satisfy the condition, but i=3 does not - for example, P_i > P_j holds for j = 1.

Similarly, i=5 does not satisfy the condition, either. Thus, there are three integers that satisfy the condition.

Sample Input 2

4
4 3 2 1

Sample Output 2

4

All integers i (1 \leq i \leq N) satisfy the condition.

Sample Input 3

6
1 2 3 4 5 6

Sample Output 3

1

Only i=1 satisfies the condition.

Sample Input 4

8
5 7 4 2 6 8 1 3

Sample Output 4

4

Sample Input 5

1
1

Sample Output 5

1

Solution in C++14 (GCC 5.4.1) (judge verdict: Time Limit Exceeded)

  
#include <iostream>
#include <string>
#include <vector>
#include <utility>
#include <functional>
#include <numeric>
#include <list>
#include <set>
#include <map>
#include <algorithm>
#include <cmath>
#include <limits>
#include <iomanip>
#include <bitset>
#include <queue>
#include <unordered_set>
#include <unordered_map>
#include <stdio.h>

#define rep(i,n) repi(i,0,n)
#define repi(i,a,b) for(int i=int(a);i<int(b);++i)
#define per(i,a,n) for (int i=n-1;i>=a;i--)
#define all(x) (x).begin(),(x).end()
#define SZ(x) ((int)(x).size())
#define INPUT1(n, a) for(int i##n = 0; i##n < n; i##n++) {cin >> a[i##n]; } //n = count, a = vector 
#define OUTPUT1(n, a) cout << "---count---" << endl << n << endl << "---content---" << endl; for(const auto b : a){cout << b << endl; }
#define INPUT2(x, y, field) for(int i##x = 0; i##x < y; i##x++) { for(int j##x = 0; j##x < x; j##x++) { cin >> field[i##x][j##x]; } }
#define OUTPUT2(x, y, field) cout << "---count---" << endl << x << " " << y << endl <<"---content---" << endl; for(int i##x = 0; i##x < y; i##x++) { cout << i##x << "   "; for(int j##x = 0; j##x < x; j##x++) { cout << field[i##x][j##x] << " "; } cout << endl; }

using namespace std;
using ll = long long;

const int INF = 1001001001;

int main()
{
	int n, ans(0), num;
	bool flag=true;
	cin>>n;
	vector<int> vec(n), p_vec(0);
	rep(i, n)cin>>vec[i];
	
	rep(i, n){
	    flag=true;
	    p_vec.push_back(vec[i]);
	    rep(j, p_vec.size()){
	        if(p_vec[j]<vec[i]){
	            flag=false;
	            break;
	        }
	    }
	    if(flag)ans++;
	}
	cout<<ans<<endl;
}