Problem:
Score : 200 points

Problem Statement

A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.

How many times will the ball make a bounce where the coordinate is at most X?

Constraints

1 \leq N \leq 100

1 \leq L_i \leq 100

1 \leq X \leq 10000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N X
L_1 L_2 ... L_{N-1} L_N

Output

Print the number of times the ball will make a bounce where the coordinate is at most X.

Sample Input 1

3 6
3 4 5

Sample Output 1

2

The ball will make a bounce at the coordinates 0, 3, 7 and 12, among which two are less than or equal to 6.

Sample Input 2

4 9
3 3 3 3

Sample Output 2

4

The ball will make a bounce at the coordinates 0, 3, 6, 9 and 12, among which four are less than or equal to 9.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>

using namespace std;

#define loop(i, n) for(int i = 0;i < int(n);i++)
#define rloop(i, n) for(int i = int(n);i >= 0;i--)
#define range(i, a, b) for(int i = int(a);i <= int(b);i++)
#define SZ(c) int(c.size())
#define ALL(c) c.begin(), c.end()
#define RALL(c) c.rbegin(), c.rend()
#define PI acos(-1)
#define pb push_back
#define mp make_pair
#define fr first
#define sc second
#define sfi1(v) scanf("%d",&v)
#define sfi2(v1, v2) scanf("%d %d",&v1,&v2)
#define sfi3(v1, v2, v3) scanf("%d %d %d",&v1,&v2,&v3)
#define sfll1(v) scanf("%I64d",&v);
#define sfll2(v1, v2) scanf("%I64d %I64d",&v1,&v2)
#define sfll3(v1, v2, v3) scanf("%I64d %I64d %I64d",&v1,&v2,&v3)
#define endl '\n'

typedef vector<int> vi;
typedef vector<pair<int, int> > vii;
typedef long long ll;
typedef pair<int, int> pii;


int main() {

#ifndef ONLINE_JUDGE
    //freopen("in.in", "r", stdin);
    //freopen("out.in", "w", stdout);
#endif

    ios_base::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);


    int n, x;
    cin >> n >> x;
    int sum = 0, cur;
    range(i, 1, n) {
        cin >> cur;
        sum += cur;
        if (sum == x) {
            cout << i + 1 << endl;
            return 0;
        } else if (sum > x) {
            cout << i << endl;
            return 0;
        }
    }

    cout << n + 1 << endl;

    return 0;
}