Problem:
Score : 300 points

Problem Statement

There are N people living on a number line.

The i-th person lives at coordinate X_i.

You are going to hold a meeting that all N people have to attend.

The meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.

Find the minimum total points of stamina the N people have to spend.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq X_i \leq 100

Input

Input is given from Standard Input in the following format:

N
X_1 X_2 ... X_N

Output

Print the minimum total stamina the N people have to spend.

Sample Input 1

2
1 4

Sample Output 1

5

Assume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.

Note that you can hold the meeting only at an integer coordinate.

Sample Input 2

7
14 14 2 13 56 2 37

Sample Output 2

2354

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;

long long sum(vector<int> X, int x,int N){
    long long s=0;
    for(int i=0;i<N;i++){
        s=s+((X.at(i)-x)*(X.at(i)-x));
    }
    return s;
}

int main() {
	int N;
	cin >> N;
	vector<int> X(N);
	for(int i=0;i<N;i++){
	    cin >> X.at(i);
	}
	long long dist=1000000000000000000;
	for(int x=0;x<=100;x++){
	    long long s=sum(X,x,N);
	    if(dist>s) dist=s;
	}
	cout << dist << endl;
}