Problem:
Score : 200 points

Problem Statement

Tak performed the following action N times: rolling two dice.
The result of the i-th roll is D_{i,1} and D_{i,2}.

Check if doublets occurred at least three times in a row.
Specifically, check if there exists at lease one i such that D_{i,1}=D_{i,2}, D_{i+1,1}=D_{i+1,2} and D_{i+2,1}=D_{i+2,2} hold.

Constraints

3 \leq N \leq 100

1\leq D_{i,j} \leq 6

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
D_{1,1} D_{1,2}
\vdots
D_{N,1} D_{N,2}

Output

Print Yes if doublets occurred at least three times in a row. Print No otherwise.

Sample Input 1

5
1 2
6 6
4 4
3 3
3 2

Sample Output 1

Yes

From the second roll to the fourth roll, three doublets occurred in a row.

Sample Input 2

5
1 1
2 2
3 4
5 5
6 6

Sample Output 2

No

Sample Input 3

6
1 1
2 2
3 3
4 4
5 5
6 6

Sample Output 3

Yes

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <iostream>
#include<iomanip>
#include <string>
#include<vector>
#include<algorithm>
#include<utility>
#include<queue>
#include<math.h>
#include<stack>
#include<set>
#include<map>
#include<ctime>
#include<cstdlib>
#define INF long long (int)1e18+1
#define MAX 200001
#define rep(i,n,m) for(int i=n;i<m;i++)

using namespace std;
	
int main() {
	int n;
	cin >> n;
	int ans = 0;
	bool flag = false;
	rep(i, 0, n) {
		int x, y;
		cin >> x >> y;
		if (x == y)ans++;
		else ans = 0;
		if (ans == 3)flag = true;
	}
	if (flag)cout << "Yes" << endl;
	else cout << "No" << endl;
}