Problem:
Score : 100 points

Problem Statement

A biscuit making machine produces B biscuits at the following moments: A seconds, 2A seconds, 3A seconds and each subsequent multiple of A seconds after activation.

Find the total number of biscuits produced within T + 0.5 seconds after activation.

Constraints

All values in input are integers.

1 \leq A, B, T \leq 20

Input

Input is given from Standard Input in the following format:

A B T

Output

Print the total number of biscuits produced within T + 0.5 seconds after activation.

Sample Input 1

3 5 7

Sample Output 1

10

Five biscuits will be produced three seconds after activation.

Another five biscuits will be produced six seconds after activation.

Thus, a total of ten biscuits will be produced within 7.5 seconds after activation.

Sample Input 2

3 2 9

Sample Output 2

6

Sample Input 3

20 20 19

Sample Output 3

0

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;
using ll = long long;
using ull = unsigned long long;
using V = vector<int>;
using VV = vector<V>;
using VVV = vector<VV>;
using VL = vector<ll>;
using VVL = vector<VL>;
using VVVL = vector<VVL>;
template<class T> using VE = vector<T>;
template<class T> using P = pair<T, T>;
#define rep(i,n) for(int i=0;i<(n);i++)
#define rep1(i,n) for(int i=1;i<=(n);i++)
#define REP(i,k,n) for(int i=(k);i<(n);i++)
#define all(a) (a).begin(),(a).end()
#define output(x,y) cout << fixed << setprecision(y) << x << endl;
template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return true; } return false; }
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return true; } return false; }
ll gcd(ll a, ll b) { return b ? gcd(b, a % b) : a; }
ll lcm(ll a, ll b) { return a / gcd(a, b) * b; }
const ll MOD = 1e9 + 7;
// const ll MOD = 998244353;
ll upper = MOD + MOD;
ll under = -upper;
ll UPPER = MOD * MOD;
ll UNDER = -UPPER;
const ll m = 1234567;
const long double pi = 3.141592653589793;
int main() {
	int a, b, t;
	cin >> a >> b >> t;
	cout << t / a * b << endl;
	return 0;
}