Problem:
Score : 200 points

Problem Statement

An integer N is a multiple of 9 if and only if the sum of the digits in the decimal representation of N is a multiple of 9.

Determine whether N is a multiple of 9.

Constraints

0 \leq N < 10^{200000}

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a multiple of 9, print Yes; otherwise, print No.

Sample Input 1

123456789

Sample Output 1

Yes

The sum of these digits is 1+2+3+4+5+6+7+8+9=45, which is a multiple of 9, so 123456789 is a multiple of 9.

Sample Input 2

0

Sample Output 2

Yes

Sample Input 3

31415926535897932384626433832795028841971693993751058209749445923078164062862089986280

Sample Output 3

No

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#define rep(i,n) for(int i = 0;i<n;i++)
#define rep2(i,a,n) for(int i=a;i<n;i++)
#define been(ix) (ix).begin(),(ix).end()
using namespace std;
typedef long long ll; 
typedef vector<int> vi;
typedef vector<long long> vl;
const ll INFL = 1e18;
const int INF = 1001001001; 
typedef pair<int,int> P;
#define foreach(ix,i) for(auto& (ix) : (i))
typedef long double ld;
int mod =1000000007;
const double PI = acos(-1);
int main(){
    string s;cin>>s;
    int n =s.length();
    ll a =0;
    rep(i,n){
        a+=s[i]-'0';
    }
    if(a%9==0){cout<<"Yes"<<endl;}
    else
    {
        cout<<"No"<<endl;
    }
    
}