Problem:
Score : 300 points

Problem Statement

When l is an odd number, the median of l numbers a_1, a_2, ..., a_l is the (\frac{l+1}{2})-th largest value among a_1, a_2, ..., a_l.

You are given N numbers X_1, X_2, ..., X_N, where N is an even number.
For each i = 1, 2, ..., N, let the median of X_1, X_2, ..., X_N excluding X_i, that is, the median of X_1, X_2, ..., X_{i-1}, X_{i+1}, ..., X_N be B_i.

Find B_i for each i = 1, 2, ..., N.

Constraints

2 \leq N \leq 200000

N is even.

1 \leq X_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
X_1 X_2 ... X_N

Output

Print N lines.
The i-th line should contain B_i.

Sample Input 1

4
2 4 4 3

Sample Output 1

4
3
3
4

Since the median of X_2, X_3, X_4 is 4, B_1 = 4.

Since the median of X_1, X_3, X_4 is 3, B_2 = 3.

Since the median of X_1, X_2, X_4 is 3, B_3 = 3.

Since the median of X_1, X_2, X_3 is 4, B_4 = 4.

Sample Input 2

2
1 2

Sample Output 2

2
1

Sample Input 3

6
5 5 4 4 3 3

Sample Output 3

4
4
4
4
4
4

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)


#include<iostream>
#include<algorithm>
#include<vector>
#include<map>

void Funca() {
	int a, b, x;
	std::cin >> a >> b >> x;
	if (a <= x && a + b >= x) {
		std::cout << "YES" << std::endl;
	}
	else
	{
		std::cout << "NO" << std::endl;

	}
}

void Funcb() {
	int n, m, x;
	int cost0 = 0;
	int cost1 = 0;
	std::map<int, int> mp;
	std::vector<int> vec;
	std::cin >> n >> m >> x;
	for (int i = 0; i < m; ++i) {
		int t;
		std::cin >> t;
		vec.push_back(t);
	}
	for (auto it : vec) {
		if (0 < it&&it < x) {
			++cost0;
		}
		else {
			++cost1;
		}
	}
	std::cout << std::min(cost0, cost1) << std::endl;

}
int main()
{
	int n;
	std::map<int, int> mp;
	std::vector<int> vec;
	std::cin >> n;
	for (int i = 0; i < n; ++i) {
		int t;
		std::cin >> t;
		vec.push_back(t);
		mp.insert(std::make_pair(i, t));
	}
	int anum = n / 2;
	std::sort(vec.begin(), vec.end(), [](int i, int j) {return i < j; });
	for (int i = 0; i < n; ++i) {
		if (mp[i] < vec[anum]) {
			std::cout << vec[anum] << std::endl;
		}
		else
		{
			std::cout << vec[anum-1] << std::endl;

		}
	}
	return 0;
}