Problem:
Score : 200 points

Problem Statement

Takahashi has many red balls and blue balls. Now, he will place them in a row.

Initially, there is no ball placed.

Takahashi, who is very patient, will do the following operation 10^{100} times:

Place A blue balls at the end of the row of balls already placed. Then, place B red balls at the end of the row.

How many blue balls will be there among the first N balls in the row of balls made this way?

Constraints

1 \leq N \leq 10^{18}

A, B \geq 0

0 < A + B \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N A B

Output

Print the number of blue balls that will be there among the first N balls in the row of balls.

Sample Input 1

8 3 4

Sample Output 1

4

Let b denote a blue ball, and r denote a red ball. The first eight balls in the row will be bbbrrrrb, among which there are four blue balls.

Sample Input 2

8 0 4

Sample Output 2

0

He placed only red balls from the beginning.

Sample Input 3

6 2 4

Sample Output 3

2

Among bbrrrr, there are two blue balls.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#define _USE_MATH_DEFINES
#include<bits/stdc++.h>
using namespace std;

typedef long long ll;
const int INF = 1e9;
const int MOD = 1e9 + 7;
const ll LINF = 1e18;
#define y0 y3487465
#define y1 y8687969
#define j0 j1347829
#define j1 j234892
#define next asdnext
#define prev asdprev
#define dump(x)  cout << #x << " = " << (x) << endl;	//debug
#define SZ(x) ((int)(x).size())
#define REP(i, n) for(ll i = 0; i < (n); i++)
#define REPR(i, n) for (ll i = (n); i >= 0; i--)
#define FOR(i, a, b) for (ll i = (a); i <= (b); i++)
#define ps(s) cout << #s << endl;
#define pv(v) cout << (v) << endl;
#define ALL(a)  (a).begin(),(a).end()

int main() {
	ll n, a, b;
	cin >> n >> a >> b;
	ll x = n / (a + b);
	ll y = n % (a + b);
	ll res = 0;
	res += x * a;
	res += min(y, a);
	pv(res)
	return(0);
}