Problem:
Score : 200 points

Problem Statement

There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is R, and a blue hat if s_i is B.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

1 \leq N \leq 100

|s| = N

s_i is R or B.

Input

Input is given from Standard Input in the following format:

N
s

Output

If there are more people wearing a red hat than there are people wearing a blue hat, print Yes; otherwise, print No.

Sample Input 1

4
RRBR

Sample Output 1

Yes

There are three people wearing a red hat, and one person wearing a blue hat.

Since there are more people wearing a red hat than people wearing a blue hat, the answer is Yes.

Sample Input 2

4
BRBR

Sample Output 2

No

There are two people wearing a red hat, and two people wearing a blue hat.

Since there are as many people wearing a red hat as people wearing a blue hat, the answer is No.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <algorithm>
#include <bitset>
#include <tuple>
#include <cstdint>
#include <cstdio>
#include <cctype>
#include <assert.h>
#include <stdlib.h>
#include <stdio.h>
#include <cassert>
#include <cfloat>
#include <climits>
#include <cmath>
#include <complex>
#include <ctime>
#include <deque>
#include <fstream>
#include <functional>
#include <iomanip>
#include <iostream>
#include <iterator>
#include <list>
#include <limits>
#include <map>
#include <memory>
#include <queue>
#include <random>
#include <set>
#include <stack>
#include <string>
#include <unordered_map>
#include <unordered_set>
#include <utility>
#include <vector>
#define ArraySizeOf(array)     (sizeof(array) / sizeof(array[0]))
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define REP(i,n) for(int i=1;i<n;i++)
#define rev(i,n) for(int i=n-1;i>=0;i--)
#define REV(i,n) for(int i=n-1;i>0;i--)
#define req(i,n,m) for(int i=n;i<m;i++)
#define REQ(i,n,m,l) for(int i=n;i<m;i+=l) 
#define _GLIBCXX_DEBUG
int INF = 1e9 + 7;
unsigned NthDayOfWeekToDay(unsigned n, unsigned dow, unsigned dow1)
{
    unsigned day;
    if (dow < dow1) dow += 7;
    day = dow - dow1;
    day += 7 * n - 6;
    return day;
}
signed gcd(int x, int y) {
    if (y == 0)return x;
    return gcd(y, x % y);
}
signed lcm(int x, int y) {
    return x / gcd(x, y) * y;
}
unsigned DayToWeekNumber(unsigned day)
{
    return (day - 1) / 7 + 1;
}
unsigned AnotherDayOfWeek(unsigned day, unsigned day0, unsigned dow0)
{
    return (dow0 + 35 + day - day0) % 7;
}
using namespace std;
pair<string, int>A[101];
signed main() {
  int N; cin>>N;
  string S; cin>>S;
  int count=0;
  rep(i,N){
    if(S.at(i)=='R')count++;
    else count--;
  }
  cout<<(count>0? "Yes":"No")<<endl;
}