Problem:
Score : 200 points

Problem Statement

We have a string S consisting of uppercase English letters. Additionally, an integer N will be given.

Shift each character of S by N in alphabetical order (see below), and print the resulting string.

We assume that A follows Z. For example, shifting A by 2 results in C (A \to B \to C), and shifting Y by 3 results in B (Y \to Z \to A \to B).

Constraints

0 \leq N \leq 26

1 \leq |S| \leq 10^4

S consists of uppercase English letters.

Input

Input is given from Standard Input in the following format:

N
S

Output

Print the string resulting from shifting each character of S by N in alphabetical order.

Sample Input 1

2
ABCXYZ

Sample Output 1

CDEZAB

Note that A follows Z.

Sample Input 2

0
ABCXYZ

Sample Output 2

ABCXYZ

Sample Input 3

13
ABCDEFGHIJKLMNOPQRSTUVWXYZ

Sample Output 3

NOPQRSTUVWXYZABCDEFGHIJKLM

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<iostream>
#include<string>
#include<stack>/*** LIFO *** stack<type> var;
push(), top():to get data, pop():to remove, size(), empty() ***/
using namespace std;

#define Fp(I, STAT, END) for(int I = STAT; I < END; I++)
#define Fm(I, STAT, END) for(int I = STAT; I > END; I--)

int main(){
    int N;
    string S;
    cin >> N >> S;
    int length = S.length();
    Fp(i, 0, length){
        if((int)S[i] + N > 'Z'){
            S[i] = 'A' - 1 + (int)S[i] + N - 'Z';
        }else{
            S[i] = (int)S[i] + N;
        }
    }
    cout << S << endl;
    return 0;
}