Problem:
Score : 400 points

Problem Statement

We have N balls. The i-th ball has an integer A_i written on it.

For each k=1, 2, ..., N, solve the following problem and print the answer.

Find the number of ways to choose two distinct balls (disregarding order) from the N-1 balls other than the k-th ball so that the integers written on them are equal.

Constraints

3 \leq N \leq 2 \times 10^5

1 \leq A_i \leq N

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

For each k=1,2,...,N, print a line containing the answer.

Sample Input 1

5
1 1 2 1 2

Sample Output 1

2
2
3
2
3

Consider the case k=1 for example. The numbers written on the remaining balls are 1,2,1,2.

From these balls, there are two ways to choose two distinct balls so that the integers written on them are equal.

Thus, the answer for k=1 is 2.

Sample Input 2

4
1 2 3 4

Sample Output 2

0
0
0
0

No two balls have equal numbers written on them.

Sample Input 3

5
3 3 3 3 3

Sample Output 3

6
6
6
6
6

Any two balls have equal numbers written on them.

Sample Input 4

8
1 2 1 4 2 1 4 1

Sample Output 4

5
7
5
7
7
5
7
5

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#pragma region RegionDefs
#pragma GCC optimize("Ofast")
#include <bits/stdc++.h>
#define rep(i,n) for(int i=0,i##_len=(n);i<i##_len;++i)
#define reps(i,l,r) for(int i=(l),i##_len=(r);i<i##_len;++i)
#define repr(i,n) for(int i=(n);i>=0;--i)
#define all(x) begin(x),end(x)
using namespace std;
const int INF = 1e9;
template<class T=int> using P  = pair<T, T>;
template<class T=int> using V  = vector<T>;
template<class T=int> using PQ = priority_queue<T>;
template<class T=int> using PQG = priority_queue<T, V<T>, greater<T>>;
typedef long long ll;
const ll MOD = 1000000007LL;
void in() {}
template<class Head, class... Tail>
void in(Head&& head, Tail&&... tail)
{
    cin >> head;
    in(move(tail)...);
}
#define IN(...) ll __VA_ARGS__; in(__VA_ARGS__)
//時間が厳しいとき使う
#define INI(...) int __VA_ARGS__; in(__VA_ARGS__)
#define INS(T, ...) T __VA_ARGS__; in(__VA_ARGS__)
#define VIN(T, v, n) V<T> v(n); for(auto& _elem:v)cin>>_elem
template<class T>bool chmax(T &a, const T &b) {if (a<b) {a=b; return 1;} return 0;}
template<class T>bool chmin(T &a, const T &b) {if (a>b) {a=b; return 1;} return 0;}
#define y0 y__0
#define y1 y__1
#define j0 j__0
#define j1 j__1
#define YN(e) cout << ((e) ? "YES" : "NO") << endl
#define yn(e) cout << ((e) ? "Yes" : "No") << endl
#pragma endregion RegionDefs

const int MAX = 510000;
long long fac[MAX], finv[MAX], inv[MAX];

// テーブルを作る前処理
void COMinit() {
    fac[0] = fac[1] = 1;
    finv[0] = finv[1] = 1;
    inv[1] = 1;
    for (int i = 2; i < MAX; i++){
        fac[i] = fac[i - 1] * i % MOD;
        inv[i] = MOD - inv[MOD%i] * (MOD / i) % MOD;
        finv[i] = finv[i - 1] * inv[i] % MOD;
    }
}

// 二項係数計算
long long COM(int n, int k){
    if (n < k) return 0;
    if (n < 0 || k < 0) return 0;
    return fac[n] * (finv[k] * finv[n - k] % MOD) % MOD;
}



void solve()
{
    COMinit();
    IN(n);
    vector<ll> v(n);
    rep(i, n)
    {
        cin >> v[i]; --v[i];
    }
    vector<ll> t(n);
    rep(i, n)
    {
        ++t[v[i]];
    }
    ll s = 0;
    rep(i, n)
    {
        s += COM(t[i], 2);
    }
    rep(i, n)
    {
        cout << s - COM(t[v[i]], 2) + COM(t[v[i]]-1, 2) << endl;
    }
}

int main()
{
    cin.tie(0); cout.tie(0);
    ios::sync_with_stdio(false);
    cout << setprecision(numeric_limits<double>::max_digits10);

    solve();

    return 0;
}