Problem:
Score : 300 points

Problem Statement

You are given an integer sequence of length n, a_1, ..., a_n.
Let us consider performing the following n operations on an empty sequence b.

The i-th operation is as follows:

Append a_i to the end of b.

Reverse the order of the elements in b.

Find the sequence b obtained after these n operations.

Constraints

1 \leq n \leq 2\times 10^5

0 \leq a_i \leq 10^9

n and a_i are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print n integers in a line with spaces in between.
The i-th integer should be b_i.

Sample Input 1

4
1 2 3 4

Sample Output 1

4 2 1 3

After step 1 of the first operation, b becomes: 1.

After step 2 of the first operation, b becomes: 1.

After step 1 of the second operation, b becomes: 1, 2.

After step 2 of the second operation, b becomes: 2, 1.

After step 1 of the third operation, b becomes: 2, 1, 3.

After step 2 of the third operation, b becomes: 3, 1, 2.

After step 1 of the fourth operation, b becomes: 3, 1, 2, 4.

After step 2 of the fourth operation, b becomes: 4, 2, 1, 3.

Thus, the answer is 4 2 1 3.

Sample Input 2

3
1 2 3

Sample Output 2

3 1 2

As shown above in Sample Output 1, b becomes 3, 1, 2 after step 2 of the third operation. Thus, the answer is 3 1 2.

Sample Input 3

1
1000000000

Sample Output 3

1000000000

Sample Input 4

6
0 6 7 6 7 0

Sample Output 4

0 6 6 0 7 7

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)


#include <bits/stdc++.h>

#define FOR(i,b,e) for(int i=(b); i <= (e); ++i)
#define FORD(i,b,e) for(int i=(b); i >= (e); --i)
#define SIZE(c) (int) (c).size()
#define FORE(i,c) FOR(i,0,SIZE(c)-1)
#define FORDE(i,c) FORD(i,SIZE(c)-1,0)

#define pb push_back
#define mp make_pair
#define st first
#define nd second


using namespace std;

typedef long long ll;
typedef pair <int,int> pii;
typedef pair <ll,ll> pll;

typedef vector <int> VI;
typedef vector <bool> VB;
typedef vector <pii> VP;
typedef vector <ll> VL;
typedef vector <pll> VPL;

typedef vector <VI> VVI;
typedef vector <VL> VVL;
typedef vector <VB> VVB;
typedef vector <VP> VVP;

const int MOD = 1000000007;
const int INF = 1000000001;
const ll LINF = 1000000000000000001LL;


/*************************************************************************/

int main() {
    ios_base::sync_with_stdio(0);
    
    int n;
    cin >> n;
    
    deque <int> q;
    FOR(i,1,n) {
        int a;
        cin >> a;
        
        if (i % 2) q.push_back(a);
        else q.push_front(a);
    }
    
    VI vec(q.begin(), q.end());
    
    if (n % 2) {
        reverse(vec.begin(), vec.end());
    }
    
    for (int x : vec) {
        cout << x << ' ';
    }

    return 0;
}

/*************************************************************************/