Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in C++14 (Clang 3.8.0) (judge verdict: Wrong Answer)

#include <cstdio>
#include <vector>
#include <queue>
#include <algorithm>
#include <functional>
using namespace std;

int main()
{
	int n, a, b, c, d;
	int okay = 1;
	int flag;
	char arr[200001];

	scanf("%d%d%d%d%d", &n, &a, &b, &c, &d);
	scanf("%s", arr);

	flag = 0;
	for (int i = a; i <= c; i++)
	{
		if (arr[i] == '#')
			flag++;
		else
			flag = 0;
		if (flag == 2)
			okay = 0;
	}
	flag = 0;
	for (int i = b; i <= d; i++)
	{
		if (arr[i] == '#')
			flag++;
		else
			flag = 0;
		if (flag == 2)
			okay = 0;
	}

	if (c > d && okay == 1)
	{
		flag = 0;
		for (int i = b; i <= d; i++)
		{
			if (arr[i - 1] == arr[i] && arr[i] == arr[i + 1] && arr[i] == '.')
			{
				printf("YES");
				return 0;
			}
		}
		printf("NO");
	}
	else
		printf("YES");	

	return 0;
}