Problem:
Score : 200 points

Problem Statement

Tak performed the following action N times: rolling two dice.
The result of the i-th roll is D_{i,1} and D_{i,2}.

Check if doublets occurred at least three times in a row.
Specifically, check if there exists at lease one i such that D_{i,1}=D_{i,2}, D_{i+1,1}=D_{i+1,2} and D_{i+2,1}=D_{i+2,2} hold.

Constraints

3 \leq N \leq 100

1\leq D_{i,j} \leq 6

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
D_{1,1} D_{1,2}
\vdots
D_{N,1} D_{N,2}

Output

Print Yes if doublets occurred at least three times in a row. Print No otherwise.

Sample Input 1

5
1 2
6 6
4 4
3 3
3 2

Sample Output 1

Yes

From the second roll to the fourth roll, three doublets occurred in a row.

Sample Input 2

5
1 1
2 2
3 4
5 5
6 6

Sample Output 2

No

Sample Input 3

6
1 1
2 2
3 3
4 4
5 5
6 6

Sample Output 3

Yes

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

// lcmとか__builtin_popcountとかはg++ -std=c++17 default.cppみたいなかんじで
// g++ hoge.cpp -std=c++17 -I . でコンパイルできる
// -fsanitize=undefinedでオーバーフロー検出
#include <bits/stdc++.h>
//#include <atcoder/all>
#define mod 1000000007
#define INF LLONG_MAX
#define ll long long
#define ln cout<<endl
#define Yes cout<<"Yes"<<endl
#define NO cout<<"NO"<<endl
#define YES cout<<"YES"<<endl
#define No cout<<"No"<<endl
#define REP(i,m,n) for(ll i=(ll)(m);i<(ll)(n);i++)
#define rep(i,n) REP(i,0,n)
#define all(x) (x).begin(),(x).end()
#define rall(x) (x).rbegin(),(x).rend()
using namespace std;
//using namespace atcoder;
typedef pair<ll,ll> P;
ll dx[4]={1,0,-1,0};
ll dy[4]={0,1,0,-1};

int main() {
    cin.tie(0);
   	ios::sync_with_stdio(false);

    ll a,b,c,d,m,n,k,x,y,maxi=0,f=0,mini=INF,sum=0;
    string str;
    cin>>n;
    rep(i,n)
    {
        cin>>a>>b;
        if(a==b){
            sum++;
        }else{
            sum=0;
        }
        if(sum>=3) f=1;
    }
    if(f) Yes;
    else No;

    return 0;
}