Problem:
Score : 200 points

Problem Statement

An integer N is a multiple of 9 if and only if the sum of the digits in the decimal representation of N is a multiple of 9.

Determine whether N is a multiple of 9.

Constraints

0 \leq N < 10^{200000}

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a multiple of 9, print Yes; otherwise, print No.

Sample Input 1

123456789

Sample Output 1

Yes

The sum of these digits is 1+2+3+4+5+6+7+8+9=45, which is a multiple of 9, so 123456789 is a multiple of 9.

Sample Input 2

0

Sample Output 2

Yes

Sample Input 3

31415926535897932384626433832795028841971693993751058209749445923078164062862089986280

Sample Output 3

No

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <iostream>
#include <algorithm>
#include <vector>
#include <cmath>
#include <string>
#include <map>
#include <queue>
#include <set>

#define ll long long
#define REP(i,n) for(int i = 0; i < n; i++)
#define PI 3.141592653589
#define MOD 1000000007

using namespace std;

template<typename T> T gcd(T a, T b){return (a % b)? gcd(b, a % b) : b;}
template<typename T> T lcm(T a, T b){return a * b / gcd(a, b);}

int main(void){
    int sum = 0;
    string s;
    cin >> s;
    int N = s.size();
    REP(i,N){
        sum = (sum + (s[i]-'0')) % 9;
    }
    if(sum == 0) cout << "Yes" << endl;
    else cout << "No" << endl;
    return 0;
}