Problem:
Score : 400 points

Problem Statement

You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

In the i-th operation, you replace every element whose value is B_{i} with C_{i}.

For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

All values in input are integers.

1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}

B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:

N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}

Output

Print Q integers S_{i} to Standard Output in the following format:

S_{1}
S_{2}
\vdots
S_{Q}

Note that S_{i} may not fit into a 32-bit integer.

Sample Input 1

4
1 2 3 4
3
1 2
3 4
2 4

Sample Output 1

11
12
16

Initially, the sequence A is 1,2,3,4.

After each operation, it becomes the following:

2, 2, 3, 4

2, 2, 4, 4

4, 4, 4, 4

Sample Input 2

4
1 1 1 1
3
1 2
2 1
3 5

Sample Output 2

8
4
4

Note that the sequence A may not contain an element whose value is B_{i}.

Sample Input 3

2
1 2
3
1 100
2 100
100 1000

Sample Output 3

102
200
2000

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>

#define mod 1000000007
#define fastio ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);
#define rep(var,start,end) for(int var=start; var<end; var++)
#define repr(var,start,end) for(int var=start; var>=end; var--)
#define repi(var,start,end) for(int var=start; var<=end; var++)
#define debg(var) cerr<<#var<<" : "<<var<<" "
#define pb push_back
#define mp make_pair

using namespace std;

typedef unsigned long long ull;
typedef long long ll;

void solve() {
    int n;
    cin>>n;
    int a[n];
    rep(i,0,n)
        cin>>a[i];
    map<int,int> m;
    rep(i,0,n) {
        m[a[i]]++;
    }
    int q;
    cin>>q;
    while(q--) {
        int b,c;
        cin>>b>>c;
        int k = m[b];
        m.erase(b);
        m[c] += k;
        ull sum = 0;
        for(auto i = m.begin(); i!=m.end(); ++i) {
            sum += i->first*i->second;
        }
        cout<<sum<<'\n';
    }    
}


int main() {
    fastio
    int t = 1;
    //cin>>t;
    while(t--) {
        solve();
    }
    return 0;
}