Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
#define rep(i,n) for(int i=0;i<n;i++)

using namespace std;
typedef unsigned long ul;
typedef pair<ul, ul> P;

int main(){
    int S, L, R;
    string ans;
    cin >> S;

    R = S % 100;
    L = S / 100;

    if(R <= 12 && L <= 12 && (L > 0 || R > 0)){
        ans = "MBIGUOUS";
    }else if((R > 12 || R == 0) && L > 0 && L <= 12){
        ans = "MMYY";
    }else if((L > 12 || L == 0) && R > 0 && R <= 12){
        ans = "YYMM";
    }else{
        ans = "NA";
    }
    cout << ans << endl;
}