Problem:
Score : 300 points

Problem Statement

You are given N positive integers a_1, a_2, ..., a_N.

For a non-negative integer m, let f(m) = (m\ mod\ a_1) + (m\ mod\ a_2) + ... + (m\ mod\ a_N).

Here, X\ mod\ Y denotes the remainder of the division of X by Y.

Find the maximum value of f.

Constraints

All values in input are integers.

2 \leq N \leq 3000

2 \leq a_i \leq 10^5

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 ... a_N

Output

Print the maximum value of f.

Sample Input 1

3
3 4 6

Sample Output 1

10

f(11) = (11\ mod\ 3) + (11\ mod\ 4) + (11\ mod\ 6) = 10 is the maximum value of f.

Sample Input 2

5
7 46 11 20 11

Sample Output 2

90

Sample Input 3

7
994 518 941 851 647 2 581

Sample Output 3

4527

Solution in C++14 (Clang 3.8.0) (judge verdict: Accepted)

#include <iostream>
#include <fstream>
#include <cmath>
#include <algorithm>
#include <vector>
#include <set>
#include <map>
#include <stack>
#include <queue>
#include <cstdlib>
#include <cstdio>
#include <string>
#include <cstring>
#include <cassert>
#include <utility>
#include <iomanip>
#include <chrono>
#include <random>
#include <bitset>

using namespace std;

#define sz(x) (int) x.size()
#define unique(x) x.erase(unique(x.begin(), x.end()), x.end())
#define all(a) a.begin(), a.end()
#define sqr(x) ((x) * (x)) 
#define y1 aksjdaskdjksjfksdjf
#define left kdnvldvoiwejifejg
#define right lkdsjflksdjfdjfk
#define prev asdasfsadjkjsdfjs
#define tm aklsjdasjdasjdkdjjf
#define lcm hddalkwjeidjjhasda
#define random_shuffle asdasdd

int n;
long long ans;

int main() { 

  cin >> n;
  for (int i = 0; i < n; i++) {
    int x;
    scanf("%d", &x);
    ans += x - 1;
  }

  cout << ans << endl;

  return 0;
}