Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
using namespace std;
 
int main() {
    int N,cnt=0;
    cin >> N;
 
    for (int i=1; i<=N;  i++) {
        if (i % 2 == 1) {
            int c=0;
            for (int j=1; j<=i; j++) {
                if (i % j == 0) {
                    c++;
                }
            }
            if (c == 8) {
                cnt++;
            }
        }
    }
 
    cout << cnt << endl;
    return 0;
}