Problem:
Score : 100 points

Problem Statement

N of us are going on a trip, by train or taxi.

The train will cost each of us A yen (the currency of Japan).

The taxi will cost us a total of B yen.

How much is our minimum total travel expense?

Constraints

All values in input are integers.

1 \leq N \leq 20

1 \leq A \leq 50

1 \leq B \leq 50

Input

Input is given from Standard Input in the following format:

N A B

Output

Print an integer representing the minimum total travel expense.

Sample Input 1

4 2 9

Sample Output 1

8

The train will cost us 4 \times 2 = 8 yen, and the taxi will cost us 9 yen, so the minimum total travel expense is 8 yen.

Sample Input 2

4 2 7

Sample Output 2

7

Sample Input 3

4 2 8

Sample Output 3

8

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#define rep(i, n) for(int i = 0; i < n; i++)
#define reps(i, n , m) for(int i = n; i <= m; i++)
#define FDS(i, n) for(ll i = 0; i < n; ++i)
using namespace std;
using ll = long long;
using pii = pair<int,int>;
using pll = pair<ll,ll>;
using vi = vector<int>;
using vl = vector<ll>;
const int mod = 1000000007; 
long long inv[200000],fact[200000],ifact[200000];
long long comb(ll n, ll k){
	if(n<k)return 0;
	else if (n<0||k<0) return 0;
	else return fact[n] * ifact[k] % mod * ifact[n-k] % mod;
}
 
 
int main(){
	ios::sync_with_stdio(false);cin.tie(0);
	/*inv[1] = fact[0] = fact[1] = ifact[0] = ifact[1] = 1; for (int i=2;i<200000;i++){ inv[i] = (mod - mod / i) * inv[mod % i] % mod; fact[i] = fact[i-1] * i % mod;ifact[i] = ifact[i-1] * inv[i] % mod;
	}*/ //nCr
	int N,A,B;
	cin>>N>>A>>B;
	cout<<min(B,A*N)<<endl;
}