Problem:
Score : 200 points

Problem Statement

Tak performed the following action N times: rolling two dice.
The result of the i-th roll is D_{i,1} and D_{i,2}.

Check if doublets occurred at least three times in a row.
Specifically, check if there exists at lease one i such that D_{i,1}=D_{i,2}, D_{i+1,1}=D_{i+1,2} and D_{i+2,1}=D_{i+2,2} hold.

Constraints

3 \leq N \leq 100

1\leq D_{i,j} \leq 6

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
D_{1,1} D_{1,2}
\vdots
D_{N,1} D_{N,2}

Output

Print Yes if doublets occurred at least three times in a row. Print No otherwise.

Sample Input 1

5
1 2
6 6
4 4
3 3
3 2

Sample Output 1

Yes

From the second roll to the fourth roll, three doublets occurred in a row.

Sample Input 2

5
1 1
2 2
3 4
5 5
6 6

Sample Output 2

No

Sample Input 3

6
1 1
2 2
3 3
4 4
5 5
6 6

Sample Output 3

Yes

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
int main(){
   ll n,i,c=0,c1=0;
  cin>>n;
  vector<pair<int,int>> v(n);
  for(i=0;i<n;i++) {
  cin>>v[i].first>>v[i].second;
  }
  for(i=0;i<n;i++) {
  if(v[i].first==v[i].second) c++;
   else{
     if(c>=3){
       c=0;c1=1;
     break;
     }
     c=0;}
  }
  if(c!=0){
      if(c>=3){
          c1=1;c=0;
      }
  }
  if(c1==1) cout<<"Yes";
  else cout<<"No";
    return 0;
}