Problem:
Score : 100 points

Problem Statement

You are given positive integers A and B.

If A is a divisor of B, print A + B; otherwise, print B - A.

Constraints

All values in input are integers.

1 \leq A \leq B \leq 20

Input

Input is given from Standard Input in the following format:

A B

Output

If A is a divisor of B, print A + B; otherwise, print B - A.

Sample Input 1

4 12

Sample Output 1

16

As 4 is a divisor of 12, 4 + 12 = 16 should be printed.

Sample Input 2

8 20

Sample Output 2

12

Sample Input 3

1 1

Sample Output 3

2

1 is a divisor of 1.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;

#define rep(i,n) for(long long i=0; i<(long long)(n);i++)
#define rep2(i,s,n) for(long long i=(s); i<(long long)(n);i++)
#define mod 1000000007
typedef long long ll;

int main() {
    int a,b;cin>>a>>b;

    if(b%a==0){
        cout<<a+b<<endl;
    }
    else {
        cout<<b-a<<endl;
    }
}