Problem:
Score : 100 points

Problem Statement

We have weather records at AtCoder Town for some consecutive three days. A string of length 3, S, represents the records - if the i-th character is S, it means it was sunny on the i-th day; if that character is R, it means it was rainy on that day.

Find the maximum number of consecutive rainy days in this period.

Constraints

|S| = 3

Each character of S is S or R.

Input

Input is given from Standard Input in the following format:

S

Output

Print the maximum number of consecutive rainy days in the period.

Sample Input 1

RRS

Sample Output 1

2

We had rain on the 1-st and 2-nd days in the period. Here, the maximum number of consecutive rainy days is 2, so we should print 2.

Sample Input 2

SSS

Sample Output 2

0

It was sunny throughout the period. We had no rainy days, so we should print 0.

Sample Input 3

RSR

Sample Output 3

1

We had rain on the 1-st and 3-rd days - two "streaks" of one rainy day, so we should print 1.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include "bits/stdc++.h"
#include "ext/pb_ds/assoc_container.hpp"
using namespace __gnu_pbds;
using namespace std;

#define pb                push_back
#define all(x)            (x).begin(),(x).end()
#define int               long long
#define INF               1e18
#define ff                first
#define ss                second
#define vi                vector<int>
#define pii               pair<int,int>
#define mii               map<int,int>
#define endl              "\n"
#define GCD(x,y)          (__gcd((x), (y)))
#define LCM(x,y)          (((x)/__gcd((x), (y)))*(y))
#define debug(x)          cout<<#x<<" is "<<(x)<<endl
#define mem(a,x)          memset(a,x,sizeof(a))
#define rep(i,a,b)        for(long long i=a;i<b;i++)
#define sp(ans,p)         fixed <<setprecision(p)<<ans;
#define IOS ios::sync_with_stdio(0);cin.tie(0); cout.tie(0);

typedef tree<pii, null_type, less<pii>, rb_tree_tag, tree_order_statistics_node_update> ordered_set;

// constexpr int N=;
void solve()
{
    int ans = 0;
    string s;
    cin >> s;
    rep(i, 0, s.length())
    {

        if (s[i] == 'S') continue;
        int ct = 0;
        while (s[i] == 'R' and i < s.length())
        {
            i++;
            ct++;
        }
        ans = max(ct, ans);
    }
    cout << ans << endl;


    return;
}

signed main()
{
    IOS;
#ifndef ONLINE_JUDGE
    freopen("input.txt", "r", stdin);
    freopen("output.txt", "w", stdout);
#endif
    // sieve();
    int t = 1;
    //cin >> t;
    while (t--)   solve();
    return 0;
}