Problem:
Score : 300 points

Problem Statement

There are N integers written on a blackboard. The i-th integer is A_i.

Takahashi will repeatedly perform the following operation on these numbers:

Select a pair of integers, A_i and A_j, that have the same parity (that is, both are even or both are odd) and erase them.

Then, write a new integer on the blackboard that is equal to the sum of those integers, A_i+A_j.

Determine whether it is possible to have only one integer on the blackboard.

Constraints

2 ≦ N ≦ 10^5

1 ≦ A_i ≦ 10^9

A_i is an integer.

Input

The input is given from Standard Input in the following format:

N
A_1 A_2 … A_N

Output

If it is possible to have only one integer on the blackboard, print YES. Otherwise, print NO.

Sample Input 1

3
1 2 3

Sample Output 1

YES

It is possible to have only one integer on the blackboard, as follows:

Erase 1 and 3 from the blackboard, then write 4. Now, there are two integers on the blackboard: 2 and 4.

Erase 2 and 4 from the blackboard, then write 6. Now, there is only one integer on the blackboard: 6.

Sample Input 2

5
1 2 3 4 5

Sample Output 2

NO

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <algorithm>
#include <cstdio>
#include <deque>
#include <iomanip>
#include <iostream>
#include <queue>
#include <stack>
#include <utility>
#include <vector>
using std::cerr;
using std::cin;
using std::cout;
using std::endl;

void OutputError(std::string s) {
  cerr << "\033[93m" << s << "\033[m" << endl;
  return;
}

void Yes(void) {
  cout << "YES" << endl;
  exit(0);
}
void No(void) {
  cout << "NO" << endl;
  exit(0);
}

int main(void) {
  cout << std::fixed << std::setprecision(10);
  cin.tie(0);
  std::ios::sync_with_stdio(false);

  int n;
  cin>>n;
  int even = 0, odd = 0;
  for (int i = 0; i < n; i++) {
    int a;
    cin >> a;
    if (a % 2 == 0) {
      even++;
    } else {
      odd++;
    }
  }
  if (odd % 2 == 1) {
    No();
  } else {
    even += odd / 2;
    if (even % 2 == 0) {
      Yes();
    } else {
      No();
    }
  }

  return 0;
}