Problem:
Score : 200 points

Problem Statement

Takahashi's house has only one socket.

Takahashi wants to extend it with some number of power strips, each with A sockets, into B or more empty sockets.

One power strip with A sockets can extend one empty socket into A empty sockets.

Find the minimum number of power strips required.

Constraints

All values in input are integers.

2 \leq A \leq 20

1 \leq B \leq 20

Input

Input is given from Standard Input in the following format:

A B

Output

Print the minimum number of power strips required.

Sample Input 1

4 10

Sample Output 1

3

3 power strips, each with 4 sockets, extend the socket into 10 empty sockets.

Sample Input 2

8 9

Sample Output 2

2

2 power strips, each with 8 sockets, extend the socket into 15 empty sockets.

Sample Input 3

8 8

Sample Output 3

1

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <string>
#include <cstdio>
#include <cstring>
#include <cmath>
#include <vector>
#include <algorithm>
#include <cstdio>
#include <queue>
#define rep(i, n) for (int i = 0; i < (n); i++)
#define int long long
#define INF 1e9 + 7
#define cae cout << ans << endl;
#define cye cout << "Yes" << endl;
#define cne cout << "No" << endl;
#define r0 return 0;
using namespace std;
typedef pair<int,int>P;
typedef long long ll;
signed main() {
    int a, b;
    cin >> a >> b;
    if (b%a==0) {
        cout << b / a << endl;
    } else {
        cout << b / a + 1 << endl;
    }
}