Problem:
Score : 200 points

Problem Statement

Tak performed the following action N times: rolling two dice.
The result of the i-th roll is D_{i,1} and D_{i,2}.

Check if doublets occurred at least three times in a row.
Specifically, check if there exists at lease one i such that D_{i,1}=D_{i,2}, D_{i+1,1}=D_{i+1,2} and D_{i+2,1}=D_{i+2,2} hold.

Constraints

3 \leq N \leq 100

1\leq D_{i,j} \leq 6

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
D_{1,1} D_{1,2}
\vdots
D_{N,1} D_{N,2}

Output

Print Yes if doublets occurred at least three times in a row. Print No otherwise.

Sample Input 1

5
1 2
6 6
4 4
3 3
3 2

Sample Output 1

Yes

From the second roll to the fourth roll, three doublets occurred in a row.

Sample Input 2

5
1 1
2 2
3 4
5 5
6 6

Sample Output 2

No

Sample Input 3

6
1 1
2 2
3 3
4 4
5 5
6 6

Sample Output 3

Yes

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>

using namespace std;

#define ll long long

void solve() {
	int n;
	cin >> n;
	int cnt = 0, temp = 0;
	for(int i = 0; i < n; i++) {
		int a, b;
		cin >> a >> b;
		if (a == b) {
			temp++;
			cnt = max(temp, cnt);
		} else {
			temp = 0;
		}
	}
	cout << (cnt > 2 ? "Yes\n" : "No\n");
}

int main() {
	ios::sync_with_stdio(0);
	cin.tie(0);

	int t = 1, i = 1;
	//cin >> t;
	while(t--) {
		//cout << "Case #" << i << ": ";
		solve();
		//i++;
	}
	return 0;
}