Problem:
Score : 200 points

Problem Statement

You have written N problems to hold programming contests.
The i-th problem will have a score of P_i points if used in a contest.

With these problems, you would like to hold as many contests as possible under the following condition:

A contest has three problems. The first problem has a score not greater than A points, the second has a score between A + 1 and B points (inclusive), and the third has a score not less than B + 1 points.

The same problem should not be used in multiple contests.
At most how many contests can be held?

Constraints

3 \leq N \leq 100

1 \leq P_i \leq 20 (1 \leq i \leq N)

1 \leq A < B < 20

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A B
P_1 P_2 ... P_N

Output

Print the answer.

Sample Input 1

7
5 15
1 10 16 2 7 20 12

Sample Output 1

2

Two contests can be held by putting the first, second, third problems and the fourth, fifth, sixth problems together.

Sample Input 2

8
3 8
5 5 5 10 10 10 15 20

Sample Output 2

0

No contest can be held, because there is no problem with a score of A = 3 or less.

Sample Input 3

3
5 6
5 6 10

Sample Output 3

1

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
#include<math.h>
int main(){
	int n;
	int a;
	int b;
	scanf("%d\n%d %d\n", &n, &a, &b);
	int p[100];
	for(int i=0;i<100;i++){
		p[i]=20;
	}
	for(int i=0;i<n;i++){
		scanf("%d\n", &p[i]);
	}
	int fir=0;
	int sec=0;
	int thi=0;
	int ans=0;
	for(int i=0;i<n;i++){
		if(p[i]<=a){
			fir++;
		}else if(p[i]<=b){
			sec++;
		}else{
			thi++;
		}
	}
	ans=fir;
	if(sec<ans){
		ans=sec;
	}
	if(thi<ans){
		ans=thi;
	}
	printf("%d\n",ans);
}