Problem:
Score: 300 points

Problem Statement

M-kun is a student in Aoki High School, where a year is divided into N terms.

There is an exam at the end of each term. According to the scores in those exams, a student is given a grade for each term, as follows:

For the first through (K-1)-th terms: not given.

For each of the K-th through N-th terms: the multiplication of the scores in the last K exams, including the exam in the graded term.

M-kun scored A_i in the exam at the end of the i-th term.

For each i such that K+1 \leq i \leq N, determine whether his grade for the i-th term is strictly greater than the grade for the (i-1)-th term.

Constraints

2 \leq N \leq 200000

1 \leq K \leq N-1

1 \leq A_i \leq 10^{9}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
A_1 A_2 A_3 \ldots A_N

Output

Print the answer in N-K lines.

The i-th line should contain Yes if the grade for the (K+i)-th term is greater than the grade for the (K+i-1)-th term, and No otherwise.

Sample Input 1

5 3
96 98 95 100 20

Sample Output 1

Yes
No

His grade for each term is computed as follows:

3-rd term: (96 \times 98 \times 95) = 893760

4-th term: (98 \times 95 \times 100) = 931000

5-th term: (95 \times 100 \times 20) = 190000

Sample Input 2

3 2
1001 869120 1001

Sample Output 2

No

Note that the output should be No if the grade for the 3-rd term is equal to the grade for the 2-nd term.

Sample Input 3

15 7
3 1 4 1 5 9 2 6 5 3 5 8 9 7 9

Sample Output 3

Yes
Yes
No
Yes
Yes
No
Yes
Yes

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define gcd(a,b) __gcd(a,b)
#define lcm(a,b) (a*b)/gcd(a,b)
#define ff first
#define ss second
#define p pair<int,int>
#define pb push_back
#define endl '\n'
#define w(t) ll test;cin>>test;while(test--)
#define fast ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(0);
#define pi acos(-1)

int main()
{
    fast;
    ll n,k;
    cin>>n>>k;
    vector<ll>vec(n,0LL),ans;
    for(auto &i:vec)cin>>i;
    ll i,sum=1LL;
    for( i=0;i<k;i++)
    {
        sum*=vec[i]*1LL;
    }
    ans.pb(1LL*sum);
    for(ll j=0;i<n;j++,i++)
    {
        sum/=vec[j]*1LL;
        sum*=vec[i]*1LL;
        ans.pb(1LL*sum);
    }
   /* for(auto i:ans)cout<<i<<" ";
    cout<<endl;*/
    for(ll i=1;i<0LL+ans.size();i++)
    {
       if(ans[i]>ans[i-1])cout<<"Yes"<<endl;
       else cout<<"No"<<endl;
    }
}