Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef vector<int> vi;
typedef vector<string> vs;
typedef vector<bool> vb;
typedef vector<char> vc;
typedef vector<ll> vll;
typedef vector<vector<int>> vvi;
typedef vector<vector<string>> vvs;
typedef vector<vector<char>> vvc;
typedef vector<vector<bool>> vvb;
typedef pair<int,int> P;
#define vrep(v,n) for(int i=0;i<n;i++){cin >> v.at(i);} //配列vにn個の要素を入力する
#define rep(i, l, n) for (int i = l; i < (int)(n); i++)
#define repn(i, l, n) for (int i = l; i <= (int)(n); i++)
#define pb push_back 

const int mod = 1000000007;
const int inf = 1e9;

int main(){
    int a[9];
    rep(i,0,9){cin >> a[i];}
    int n;int b[n];
    cin >> n;
    rep(i,0,n){cin >> b[i];}
    rep(i,0,9){
        rep(j,0,n){
            if(a[i]==b[j]){a[i] = 0;}
        }
    }
    bool flag = false;
    if(a[0] == a[1] && a[0] == a[2]){flag = true;}
    if(a[3] == a[4] && a[3] == a[5]){flag = true;}
    if(a[6] == a[7] && a[7] == a[8]){flag = true;}
    if(a[0] == a[3] && a[0] == a[6]){flag = true;}
    if(a[1] == a[4] && a[1] == a[7]){flag = true;}
    if(a[2] == a[5] && a[2] == a[8]){flag = true;}
    if(a[0] == a[4] && a[0] == a[8]){flag = true;}
    if(a[2] == a[4] && a[2] == a[6]){flag = true;}
    if(flag){cout << "Yes";}else{cout << "No";}

}