Problem:
Score : 200 points

Problem Statement

An integer N is a multiple of 9 if and only if the sum of the digits in the decimal representation of N is a multiple of 9.

Determine whether N is a multiple of 9.

Constraints

0 \leq N < 10^{200000}

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a multiple of 9, print Yes; otherwise, print No.

Sample Input 1

123456789

Sample Output 1

Yes

The sum of these digits is 1+2+3+4+5+6+7+8+9=45, which is a multiple of 9, so 123456789 is a multiple of 9.

Sample Input 2

0

Sample Output 2

Yes

Sample Input 3

31415926535897932384626433832795028841971693993751058209749445923078164062862089986280

Sample Output 3

No

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <iostream>
#include <iomanip>
#include <algorithm>
#include <bitset>
#include <string>
#include <cmath>
#include <complex>
#include <numeric>
#include <cassert>

#include <vector>
#include <array>
#include <map>
#include <set>
#include <stack>
#include <queue>
#include <deque>
#include <utility>

#define PI 3.14159265358979323846
#define int64 long long
#define uint64 unsigned long long
#define coutfix(i) cout << fixed << setprecision(i)		//coutの浮動小数出力の桁数設定
using namespace std;

int main()
{
	string ss;
	cin >> ss;
	int64 ans = 0;
	for(int64 ii = 0;ii < ss.length();ii++)
	{
		ans += (ss[ii] - '0');
	}
	if(ans % 9 == 0)
	{
		puts("Yes");
	}
	else
	{
		puts("No");
	}
	return 0;
}