Problem:
Score : 100 points

Problem Statement

You are given a three-digit positive integer N.

Determine whether N is a palindromic number.

Here, a palindromic number is an integer that reads the same backward as forward in decimal notation.

Constraints

100≤N≤999

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a palindromic number, print Yes; otherwise, print No.

Sample Input 1

575

Sample Output 1

Yes

N=575 is also 575 when read backward, so it is a palindromic number. You should print Yes.

Sample Input 2

123

Sample Output 2

No

N=123 becomes 321 when read backward, so it is not a palindromic number. You should print No.

Sample Input 3

812

Sample Output 3

No

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#define fi first
#define se second
#define rep(i, s, n) for (int i = (s); i < (n); ++i)
#define rrep(i, n, g) for (int i = (n)-1; i >= (g); --i)
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
#define len(x) (int)(x).size()
#define dup(x, y) (((x) + (y)-1) / (y))
#define pb push_back
#define Field(T) vector<vector<T>>
using namespace std;
using ll = long long;
using P = pair<int, int>;

int main() {
  string a;
  cin >> a;
  string b = a;
  reverse(all(a));
  if (a == b)
    cout << "Yes" << endl;
  else
    cout << "No" << endl;
}