Problem:
Score : 200 points

Problem Statement

You are given string S and T consisting of lowercase English letters.

Determine if S equals T after rotation.

That is, determine if S equals T after the following operation is performed some number of times:

Operation: Let S = S_1 S_2 ... S_{|S|}. Change S to S_{|S|} S_1 S_2 ... S_{|S|-1}.

Here, |X| denotes the length of the string X.

Constraints

2 \leq |S| \leq 100

|S| = |T|

S and T consist of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S equals T after rotation, print Yes; if it does not, print No.

Sample Input 1

kyoto
tokyo

Sample Output 1

Yes

In the first operation, kyoto becomes okyot.

In the second operation, okyot becomes tokyo.

Sample Input 2

abc
arc

Sample Output 2

No

abc does not equal arc after any number of operations.

Sample Input 3

aaaaaaaaaaaaaaab
aaaaaaaaaaaaaaab

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
    

int main(){
    int flag=0;
    int n=0,p;
    string s,t;
    int ans=0;

    cin >>s>>t;

    for (int i = 0; i < s.length(); i++){
        n=0;
        for (int j = 0; j < s.length(); j++){
            
            p=(i+j)%s.length();
            
            if(s[p]==t[j])n++;
        }
        if(n==s.length())flag=1;
        
    }
    
    
    //cout << ans <<endl;
    //cout <<fixed<<setprecision(16)<< ans <<endl;

    if(flag==1)cout << "Yes" <<endl;
    else cout << "No" <<endl;
    
    return 0;
}