Problem:
Score : 100 points

Problem Statement

We have A balls with the string S written on each of them and B balls with the string T written on each of them.

From these balls, Takahashi chooses one with the string U written on it and throws it away.

Find the number of balls with the string S and balls with the string T that we have now.

Constraints

S, T, and U are strings consisting of lowercase English letters.

The lengths of S and T are each between 1 and 10 (inclusive).

S \not= T

S=U or T=U.

1 \leq A,B \leq 10

A and B are integers.

Input

Input is given from Standard Input in the following format:

S T
A B
U

Output

Print the answer, with space in between.

Sample Input 1

red blue
3 4
red

Sample Output 1

2 4

Takahashi chose a ball with red written on it and threw it away.
Now we have two balls with the string S and four balls with the string T.

Sample Input 2

red blue
5 5
blue

Sample Output 2

5 4

Takahashi chose a ball with blue written on it and threw it away.
Now we have five balls with the string S and four balls with the string T.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <vector>
#include <algorithm>
#include <string>
#include <deque>
#include <list>
#include <map>
#include <queue>
#include <set>
#include <stack>
#include <cstring>
#include <iomanip>
#include <utility>
 
#define rep(i,n) for(int i=0;i<(n);i++)
#define reps(i,n) for(int i=1;i<=(n);i++)
#define lol long long
const int INF = 0x3f3f3f3f;
const long long LINF = 0x3f3f3f3f3f3f3f3fLL;
 
using namespace std;
 
int h,w,sx,sy,gx,gy,tx,ty;
char house[505][505];   
bool isvisited[505][505]={false};
 
void search(int x,int y){
    if(isvisited[x][y]){
        return;
    }
    isvisited[x][y]=true;
 
    if(x<=0 || x>h || y<=0 || y>w){
        return;
    }
 
    if(house[x][y]=='#'){
        return;
    }
 
    search(x-1,y-1);
    search(x-1,y);
    search(x-1,y+1);
    search(x,y-1);
    search(x,y);
    search(x,y+1);
    search(x+1,y-1);
    search(x+1,y);
    search(x+1,y+1);
}
 
int main(){
  cin.tie(0);
  ios::sync_with_stdio(false);

  string s,t,u;
  int a,b;
  cin>>s>>t>>a>>b>>u;
  if(s==u){
    a--;
  }
  else{
    b--;
  }
  cout<<a<<" "<<b<<'\n';
  return 0;
}