Problem:
Score : 100 points

Problem Statement

The door of Snuke's laboratory is locked with a security code.

The security code is a 4-digit number. We say the security code is hard to enter when it contains two consecutive digits that are the same.

You are given the current security code S. If S is hard to enter, print Bad; otherwise, print Good.

Constraints

S is a 4-character string consisting of digits.

Input

Input is given from Standard Input in the following format:

S

Output

If S is hard to enter, print Bad; otherwise, print Good.

Sample Input 1

3776

Sample Output 1

Bad

The second and third digits are the same, so 3776 is hard to enter.

Sample Input 2

8080

Sample Output 2

Good

There are no two consecutive digits that are the same, so 8080 is not hard to enter.

Sample Input 3

1333

Sample Output 3

Bad

Sample Input 4

0024

Sample Output 4

Bad

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
using namespace std;
#define fastio ios_base::sync_with_stdio(false);cin.tie(NULL);

typedef tree<int,null_type,less<int>,rb_tree_tag, tree_order_statistics_node_update> indexed_set;
typedef long long int lli;
typedef long double ld;
typedef long long ll;
typedef pair<int, int> pii;
typedef pair<long long, long long> pll;
typedef vector<int> vi;
typedef vector<long long> vll;
typedef vector<pair<int,int>> vp;
typedef pair<int,pair<int,int>> ddp;
typedef pair<long long,pll> ldp;

#define mp make_pair
#define eb emplace_back
#define pb push_back
#define all(v) v.begin(), v.end()
#define fi(n) for(int i=0;i<(n);i++)
#define fj(n) for(int j=0;j<(n);j++)
#define fk(n) for(int k=0;k<(n);k++)
#define mod 1000000007
#define MAX 100000+5;

int main()
    {
        fastio
        int n,j=0,i,a[4];
        cin >> n;
        for(i=4;i>=1;i--)
        {
            a[j] = n%10;
            n/=10;
            j++;
        }
        if(a[0]==a[1] || a[1]==a[2] || a[2]==a[3])
        cout << "BAD";
        else
        cout << "GOOD";
        return 0;
    }