Problem:
Score : 300 points

Problem Statement

Given is a permutation P_1, \ldots, P_N of 1, \ldots, N.
Find the number of integers i (1 \leq i \leq N) that satisfy the following condition:

For any integer j (1 \leq j \leq i), P_i \leq P_j.

Constraints

1 \leq N \leq 2 \times 10^5

P_1, \ldots, P_N is a permutation of 1, \ldots, N.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
P_1 ... P_N

Output

Print the number of integers i that satisfy the condition.

Sample Input 1

5
4 2 5 1 3

Sample Output 1

3

i=1, 2, and 4 satisfy the condition, but i=3 does not - for example, P_i > P_j holds for j = 1.

Similarly, i=5 does not satisfy the condition, either. Thus, there are three integers that satisfy the condition.

Sample Input 2

4
4 3 2 1

Sample Output 2

4

All integers i (1 \leq i \leq N) satisfy the condition.

Sample Input 3

6
1 2 3 4 5 6

Sample Output 3

1

Only i=1 satisfies the condition.

Sample Input 4

8
5 7 4 2 6 8 1 3

Sample Output 4

4

Sample Input 5

1
1

Sample Output 5

1

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#ifdef ConanYu
#include "local.hpp"
#else
#pragma GCC optimize("-O3")
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
void Main();
#define debug(...) do { } while(0)
int main() {
  ios::sync_with_stdio(false), cin.tie(0), cout.tie(0);
  Main();
}
#endif

int a[200005];

void Main() {
  int n; cin >> n;
  for(int i = 0; i < n; i++) {
    cin >> a[i];
  }
  int mn = INT_MAX;
  int ans = 0;
  for(int i = 0; i < n; i++) {
    if(a[i] < mn) {
      ans++;
    }
    mn = min(mn, a[i]);
  }
  cout << ans << "\n";
}