Problem:
Score : 400 points

Problem Statement

Let {\rm comb}(n,r) be the number of ways to choose r objects from among n objects, disregarding order.
From n non-negative integers a_1, a_2, ..., a_n, select two numbers a_i > a_j so that {\rm comb}(a_i,a_j) is maximized.
If there are multiple pairs that maximize the value, any of them is accepted.

Constraints

2 \leq n \leq 10^5

0 \leq a_i \leq 10^9

a_1,a_2,...,a_n are pairwise distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print a_i and a_j that you selected, with a space in between.

Sample Input 1

5
6 9 4 2 11

Sample Output 1

11 6

\rm{comb}(a_i,a_j) for each possible selection is as follows:

\rm{comb}(4,2)=6

\rm{comb}(6,2)=15

\rm{comb}(6,4)=15

\rm{comb}(9,2)=36

\rm{comb}(9,4)=126

\rm{comb}(9,6)=84

\rm{comb}(11,2)=55

\rm{comb}(11,4)=330

\rm{comb}(11,6)=462

\rm{comb}(11,9)=55

Thus, we should print 11 and 6.

Sample Input 2

2
100 0

Sample Output 2

100 0

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<iostream>
#include<algorithm>
#include<vector>
#include<string>
#include<map>
#include<set>
#include<queue>
#include<stack>
#include<limits>
#include<iomanip>
#include<cmath>
#include<climits>
using namespace std;

typedef long long ll;
typedef string S;
typedef pair<int,int> P;
typedef vector<int> vi;
const int mod=1e9+7;

int main(){
    cin.tie(0);
    ios::sync_with_stdio(false);
    int n;
    cin >> n;
    vector<double> a(n);
    for(int i=0;i<n;i++){
        cin >> a[i];
    }
    sort(a.begin(),a.end());
    int dp[n];
    dp[0]=0;
    for(int i=1;i<n;i++){
        if(fabs(a[i]/2-a[dp[i-1]])>=fabs(a[i]/2-a[dp[i-1]+1])){
            dp[i]=dp[i-1]+1;
        }else{
            dp[i]=dp[i-1];
        }
    }
    cout << static_cast<int>(a[n-1]) << " " << static_cast<int>(a[(dp[n-1]==n-1?n-2:dp[n-1])]) << endl;
    return 0;
}