Problem:
Score: 400 points

Problem Statement

In Takahashi Kingdom, there is a east-west railroad and N cities along it, numbered 1, 2, 3, ..., N from west to east.
A company called AtCoder Express possesses M trains, and the train i runs from City L_i to City R_i (it is possible that L_i = R_i).
Takahashi the king is interested in the following Q matters:

The number of the trains that runs strictly within the section from City p_i to City q_i, that is, the number of trains j such that p_i \leq L_j and R_j \leq q_i.

Although he is genius, this is too much data to process by himself. Find the answer for each of these Q queries to help him.

Constraints

N is an integer between 1 and 500 (inclusive).

M is an integer between 1 and 200 \ 000 (inclusive).

Q is an integer between 1 and 100 \ 000 (inclusive).

1 \leq L_i \leq R_i \leq N (1 \leq i \leq M)

1 \leq p_i \leq q_i \leq N (1 \leq i \leq Q)

Input

Input is given from Standard Input in the following format:

N M Q
L_1 R_1
L_2 R_2
:
L_M R_M
p_1 q_1
p_2 q_2
:
p_Q q_Q

Output

Print Q lines. The i-th line should contain the number of the trains that runs strictly within the section from City p_i to City q_i.

Sample Input 1

2 3 1
1 1
1 2
2 2
1 2

Sample Output 1

3

As all the trains runs within the section from City 1 to City 2, the answer to the only query is 3.

Sample Input 2

10 3 2
1 5
2 8
7 10
1 7
3 10

Sample Output 2

1
1

The first query is on the section from City 1 to 7. There is only one train that runs strictly within that section: Train 1.
The second query is on the section from City 3 to 10. There is only one train that runs strictly within that section: Train 3.

Sample Input 3

10 10 10
1 6
2 9
4 5
4 7
4 7
5 8
6 6
6 7
7 9
10 10
1 8
1 9
1 10
2 8
2 9
2 10
3 8
3 9
3 10
1 10

Sample Output 3

7
9
10
6
8
9
6
7
8
10

Solution in C++14 (GCC 5.4.1) (judge verdict: Time Limit Exceeded)

#include<iostream>
#include<vector>
#include<algorithm>
#include<queue>
#include<deque>
#include<cmath>
#include<map>
#include<cstring>

using namespace std;
typedef long long ll;
const int INF = 1e9;
const ll MOD = 1e9 + 7;
const ll LLINF = 1LL<<60;
#define P pair<int, int>
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define pb push_back
#define mp make_pair
#define all(x) (x).begin(),(x).end()
#define print(x) cout << (x) << endl

/*-- template --*/

int main() {
    int N, M, Q;
    cin >> N >> M >> Q;
    vector<vector<int>> G(500);
    rep(i, M) {
        int l, r; cin >> l >> r;
        --l, --r;
        G[l].pb(r);
    }
    int p[Q], q[Q];
    rep(i, Q) {
        cin >> p[i] >> q[i];
        --p[i];
    }
    int answer[Q];
    rep(i, Q) {
        int ans = 0;
        for(int j = p[i]; j < q[i]; ++j) {
            for(int k : G[j]) {
                if(k < q[i]) ++ans;
            }
        }
        answer[i] = ans;
    }
    rep(i, Q)
        cout << answer[i] << endl;
}