Problem:
Score : 300 points

Problem Statement

A company has N members, who are assigned ID numbers 1, ..., N.

Every member, except the member numbered 1, has exactly one immediate boss with a smaller ID number.

When a person X is the immediate boss of a person Y, the person Y is said to be an immediate subordinate of the person X.

You are given the information that the immediate boss of the member numbered i is the member numbered A_i. For each member, find how many immediate subordinates it has.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq A_i < i

Input

Input is given from Standard Input in the following format:

N
A_2 ... A_N

Output

For each of the members numbered 1, 2, ..., N, print the number of immediate subordinates it has, in its own line.

Sample Input 1

5
1 1 2 2

Sample Output 1

2
2
0
0
0

The member numbered 1 has two immediate subordinates: the members numbered 2 and 3.

The member numbered 2 has two immediate subordinates: the members numbered 4 and 5.

The members numbered 3, 4, and 5 do not have immediate subordinates.

Sample Input 2

10
1 1 1 1 1 1 1 1 1

Sample Output 2

9
0
0
0
0
0
0
0
0
0

Sample Input 3

7
1 2 3 4 5 6

Sample Output 3

1
1
1
1
1
1
0

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#pragma GCC optimize("Ofast")
#pragma GCC target("avx,avx2,fma")
#include <bits/stdc++.h>
#define FAST_IO  ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);
#define mod 10000007
#define endl "\n"
#define PI 3.14159265358979323846264338327950288
 
using namespace std ;
using bigint = long long int ;
using vi = vector<int> ;
using vll = vector<long long int> ;




int main(){
    FAST_IO ;
    int N ; cin >> N ;
    int cnt[N+2] ;
    memset(cnt, 0, sizeof(cnt)) ;
    for( int i = 0 ; i < N - 1 ; i++ ){
        int x ; cin >> x ;
        cnt[x]++ ;
    }
    
    for( int i = 1 ; i <= N ; i++ )
        cout << cnt[i] << endl ;
    return 0 ;
}