Problem:
Score : 200 points

Problem Statement

An integer N is a multiple of 9 if and only if the sum of the digits in the decimal representation of N is a multiple of 9.

Determine whether N is a multiple of 9.

Constraints

0 \leq N < 10^{200000}

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a multiple of 9, print Yes; otherwise, print No.

Sample Input 1

123456789

Sample Output 1

Yes

The sum of these digits is 1+2+3+4+5+6+7+8+9=45, which is a multiple of 9, so 123456789 is a multiple of 9.

Sample Input 2

0

Sample Output 2

Yes

Sample Input 3

31415926535897932384626433832795028841971693993751058209749445923078164062862089986280

Sample Output 3

No

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>

using namespace std;

#define mod 1000000007
#define int int64_t
#define fio ios_base::sync_with_stdio(0); cin.tie(NULL); cout.tie(NULL)


void solve()
{
    string s;
    cin>>s;
    int n=s.size(),sum=0;
    for(int i=0;i<n;i++)
        sum+=s[i]-'0';
    cout<<(sum%9==0 ? "Yes":"No")<<endl;
}

int32_t main()
{
    fio;
    int t;
    // cin>>t;
    t=1;
    while(t--)
        solve();
}