Problem:
Score : 300 points

Problem Statement

Sitting in a station waiting room, Joisino is gazing at her train ticket.

The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).

In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.

The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Constraints

0≤A,B,C,D≤9

All input values are integers.

It is guaranteed that there is a solution.

Input

Input is given from Standard Input in the following format:

ABCD

Output

Print the formula you made, including the part =7.

Use the signs + and -.

Do not print a space between a digit and a sign.

Sample Input 1

1222

Sample Output 1

1+2+2+2=7

This is the only valid solution.

Sample Input 2

0290

Sample Output 2

0-2+9+0=7

0 - 2 + 9 - 0 = 7 is also a valid solution.

Sample Input 3

3242

Sample Output 3

3+2+4-2=7

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
#include <math.h>

int main() {
    char A, B, C, D;
    int a, b, c, d;
    scanf("%c%c%c%c", &A, &B, &C, &D);
    a = A - '0';
    b = B - '0';
    c = C - '0';
    d = D - '0';
    int ans;
    ans = a+b+c+d;
    if (ans == 7) {
        printf("%d+%d+%d+%d=7\n", a, b, c, d);
        return 0;
    }
    ans = a+b+c-d;
    if (ans == 7) {
        printf("%d+%d+%d-%d=7\n", a, b, c, d);
        return 0;
    }
    ans = a+b-c+d;
    if (ans == 7) {
        printf("%d+%d-%d+%d=7\n", a, b, c, d);
        return 0;
    }
    ans = a+b-c-d;
    if (ans == 7) {
        printf("%d+%d-%d-%d=7\n", a, b, c, d);
        return 0;
    }
    ans = a-b+c+d;
    if (ans == 7) {
        printf("%d-%d+%d+%d=7\n", a, b, c, d);
        return 0;
    }
    ans = a-b+c-d;
    if (ans == 7) {
        printf("%d-%d+%d-%d=7\n", a, b, c, d);
        return 0;
    }
    ans = a-b-c-d;
    if (ans == 7) {
        printf("%d-%d-%d-%d=7\n", a, b, c, d);
        return 0;
    }
    ans = a+b+c+d;
    if (ans == 7) {
        printf("%d+%d+%d+%d=7\n", a, b, c, d);
        return 0;
    }
    return 0;
}