Problem:
Score : 200 points

Problem Statement

There are N rectangular plate materials made of special metal called AtCoder Alloy.
The dimensions of the i-th material are A_i \times B_i (A_i vertically and B_i horizontally).

Takahashi wants a rectangular plate made of AtCoder Alloy whose dimensions are exactly H \times W.
He is trying to obtain such a plate by choosing one of the N materials and cutting it if necessary.
When cutting a material, the cuts must be parallel to one of the sides of the material.
Also, the materials have fixed directions and cannot be rotated.
For example, a 5 \times 3 material cannot be used as a 3 \times 5 plate.

Out of the N materials, how many can produce an H \times W plate if properly cut?

Constraints

1 \leq N \leq 1000

1 \leq H \leq 10^9

1 \leq W \leq 10^9

1 \leq A_i \leq 10^9

1 \leq B_i \leq 10^9

Input

Input is given from Standard Input in the following format:

N H W
A_1 B_1
A_2 B_2
:
A_N B_N

Output

Print the answer.

Sample Input 1

3 5 2
10 3
5 2
2 5

Sample Output 1

2

Takahashi wants a 5 \times 2 plate.

The dimensions of the first material are 10 \times 3. We can obtain a 5 \times 2 plate by properly cutting it.

The dimensions of the second material are 5 \times 2. We can obtain a 5 \times 2 plate without cutting it.

The dimensions of the third material are 2 \times 5. We cannot obtain a 5 \times 2 plate, whatever cuts are made. Note that the material cannot be rotated and used as a 5 \times 2 plate.

Sample Input 2

10 587586158 185430194
894597290 708587790
680395892 306946994
590262034 785368612
922328576 106880540
847058850 326169610
936315062 193149191
702035777 223363392
11672949 146832978
779291680 334178158
615808191 701464268

Sample Output 2

8

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#pragma target("avx")
#pragma optimize("O3")
#include<bits/stdc++.h>
using ll = int_fast64_t;
using P = std::pair<ll,ll>;
using PP = std::pair<ll,P>;
using V = std::vector<ll>;
template<typename T> using pq = std::priority_queue<T>;
template<typename T> using rpq = std::priority_queue<T, std::vector<T>, std::greater<T>>;

#define REP(i,b,e) for(ll i=b; i<e; i++)
#define ALL(vec) vec.begin(),vec.end()
#define PRINT(vec) printf("[ ");for(auto &i:vec)printf("%ld ",i);puts("]");
#define SCAN(vec) for(auto &i:vec)scanf("%ld",&i)
#define fi first
#define se second

const int MOD = 1e9+7;
const ll INF = 1e18;
int dx[] = {0, 1, 0, -1, 1, 1, -1, -1}, dy[] = {1, 0, -1, 0, 1, -1, -1, 1};

int main(){
	int n, h, w;
	scanf("%d %d %d", &n, &h, &w);

	int ans = 0;
	REP(i, 0, n){
		int a, b;
		scanf("%d %d", &a, &b);
		if(a>=h && b>=w) ans++;
	}
	printf("%d\n", ans);
	return 0;
}