Problem:
Score : 400 points

Problem Statement

Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.

You are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.

Constraints

2 ≦ |s| ≦ 10^5

s consists of lowercase letters.

Partial Score

200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.

Input

The input is given from Standard Input in the following format:

s

Output

If there exists no unbalanced substring of s, print -1 -1.

If there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.

Sample Input 1

needed

Sample Output 1

2 5

The string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.

Sample Input 2

atcoder

Sample Output 2

-1 -1

The string atcoder contains no unbalanced substring.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;

//定数
const long long MOD1=1000000007;
const long long MOD2=998244353;
const long double PI=3.1415926535897932;
const long long MAXLL=9223372036854775807;
const long long INF=2305843009213693951;
const long long dx[]={0,1,0,-1,1,-1,1,-1};
const long long dy[]={1,0,-1,0,1,1,-1,-1};

//型名省略
#define ll long long
#define ull unsigned long long
#define ld long double
#define uld unsigned long double
#define pll pair<long long,long long>
#define tll(n) array<long long,(int)(n)>
#define pcc pair<char,char>
#define vl vector<long long>
#define vvl vector<vector<long long>>
#define vc vector<char>
#define vvc vector<vector<char>>
#define vb vector<bool>
#define vvb vector<vector<bool>>
#define vp vector<pair<long long,long long>>
#define vt(n) vector<array<long long,(int)(n)>>
#define umap unordered_map
#define uset unordered_set
#define Lqueue priority_queue<long long>
#define Squeue priority_queue<long long,vector<long long>,greater<long long>>
#define Fi first
#define Se second
#define mp make_pair
#define eb emplace_back

//マクロ
#define all(x) (x).begin(),(x).end()
#define rall(x) (x).rbegin(),(x).rend()
#define rbf(a,x) for(auto& a:x)
#define rep(i,n) for(long long i=0;i<(long long)(n);i++)
#define rep2(i,s,n) for(long long i=(s);i<(long long)(n);i++)
#define bitrep(i,s,n) for(long long i=(s);i<(1LL<<(n));i++)
#define Maxe(x) *max_element((x).begin(),(x).end())
#define Mine(x) *min_element((x).begin(),(x).end())
#define Size(x) ((long long)(x).size())
#define lin(s) getline(cin,(s))
#define Ssort(v) sort((v).begin(),(v).end(),[](auto &left,auto &right){return left.second<right.second;})

//Yes,No
void Yes(bool a){cout<<(a?"Yes":"No")<<endl;}
//YES.NO
void YES(bool a){cout<<(a?"YES":"NO")<<endl;}

//MAX,MIN
template<class T,class U> auto max(T a,U b){return a>b?a:b;}
template<class T,class U> auto min(T a,U b){return a<b?a:b;}

//最大公約数,最小公倍数
long long gcd(long long a,long long b){return b?gcd(b,a%b):a;}
long long lcm(long long a,long long b){return a/gcd(a,b)*b;}

//累乗
template<typename t>
constexpr t mypow(t a,long long b){
    if(b==0)return 1;
    if(a==0)return 0;
    t x=1;
    while(b>0){
        if(b&1LL)x*=a;
        a*=a;
        b>>=1LL;
        }
    return x;
}
#define pow mypow

//chmin,chmax
template<class T> inline bool chmin(T& a,T b){if(a>b){a=b;return true;}return false;}
template<class T> inline bool chmax(T& a,T b){if(a<b){a=b;return true;}return false;}

//組み合わせ O(r)
template<typename t>
constexpr t nCr(t n,long long r){
    if(r==0)return 1;
    if(n==0)return 0;
    if(n<r)return 0;
    t x=1;
    for(long long i=1;i<=r;i++){
        x*=n-i+1;
        x/=i;
    }
    return x;
}

//main関数
signed main(){
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    string s;
    cin>>s;
    ll n=Size(s);
    rep(i,n-2){
        if(s[i]==s[i+1]){
            cout<<i+1<<" "<<i+3<<endl;
            return 0;
        }
        else if(s[i]==s[i+2]){
            cout<<i+1<<" "<<i+3<<endl;
            return 0;
        }
        else if(s[i+1]==s[i+2]){
            cout<<i+1<<" "<<i+3<<endl;
            return 0;
        }
    }
    if(n==2&&s[0]==s[1]){
        cout<<1<<" "<<2<<endl;
        return 0;
    }
    cout<<-1<<" "<<-1<<endl;
}