Problem:
Score : 300 points

Problem Statement

Sitting in a station waiting room, Joisino is gazing at her train ticket.

The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).

In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.

The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Constraints

0≤A,B,C,D≤9

All input values are integers.

It is guaranteed that there is a solution.

Input

Input is given from Standard Input in the following format:

ABCD

Output

Print the formula you made, including the part =7.

Use the signs + and -.

Do not print a space between a digit and a sign.

Sample Input 1

1222

Sample Output 1

1+2+2+2=7

This is the only valid solution.

Sample Input 2

0290

Sample Output 2

0-2+9+0=7

0 - 2 + 9 - 0 = 7 is also a valid solution.

Sample Input 3

3242

Sample Output 3

3+2+4-2=7

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include"bits/stdc++.h"
using namespace std;
#define rep(i, n) for (int i = 0; i < (int)(n); i++)

int main() {
	string numbers;
	cin >> numbers;
	int a = numbers[0] - 48;
	int b = numbers[1] - 48;
	int c = numbers[2] - 48;
	int d = numbers[3] - 48;
	if (a - b - c - d == 7) printf("%d-%d-%d-%d=7\n", a, b, c, d);
	else if (a - b - c + d == 7) printf("%d-%d-%d+%d=7\n", a, b, c, d);
	else if (a - b + c - d == 7) printf("%d-%d+%d-%d=7\n", a, b, c, d);
	else if (a - b + c + d == 7) printf("%d-%d+%d+%d=7\n", a, b, c, d);
	else if (a + b - c - d == 7) printf("%d+%d-%d-%d=7\n", a, b, c, d);
	else if (a + b - c + d == 7) printf("%d+%d-%d+%d=7\n", a, b, c, d);
	else if (a + b + c - d == 7) printf("%d+%d+%d-%d=7\n", a, b, c, d);
	else if (a + b + c + d == 7) printf("%d+%d+%d+%d=7\n", a, b, c, d);
	return 0;
}