Problem:
Score : 200 points

Problem Statement

Evi has N integers a_1,a_2,..,a_N. His objective is to have N equal integers by transforming some of them.

He may transform each integer at most once. Transforming an integer x into another integer y costs him (x-y)^2 dollars. Even if a_i=a_j (i≠j), he has to pay the cost separately for transforming each of them (See Sample 2).

Find the minimum total cost to achieve his objective.

Constraints

1≦N≦100

-100≦a_i≦100

Input

The input is given from Standard Input in the following format:

N
a_1 a_2 ... a_N

Output

Print the minimum total cost to achieve Evi's objective.

Sample Input 1

2
4 8

Sample Output 1

8

Transforming the both into 6s will cost (4-6)^2+(8-6)^2=8 dollars, which is the minimum.

Sample Input 2

3
1 1 3

Sample Output 2

3

Transforming the all into 2s will cost (1-2)^2+(1-2)^2+(3-2)^2=3 dollars. Note that Evi has to pay (1-2)^2 dollar separately for transforming each of the two 1s.

Sample Input 3

3
4 2 5

Sample Output 3

5

Leaving the 4 as it is and transforming the 2 and the 5 into 4s will achieve the total cost of (2-4)^2+(5-4)^2=5 dollars, which is the minimum.

Sample Input 4

4
-100 -100 -100 -100

Sample Output 4

0

Without transforming anything, Evi's objective is already achieved. Thus, the necessary cost is 0.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

//おまじない
#include <iostream>
#include <algorithm>
#include <vector>
#include <string>
#define INF 1e9+7
#define roop(i,m,n) for(int i=m;i<n;i++)
#define mroop(i,m,n) for(int i=m;i<n;i--)
#define NO cout<<"NO"<<endl;
#define YES cout << "YES"<<endl;
#define No cout << "No"<<endl;
#define Yes cout << "Yes"<<endl;
using namespace std;
typedef long long int ll;

//(int)'a'は97 (int)'A'は65
//おまじない



int main() {

	int n[100] = { 0 };
	int N = 0;
	

	cin >> N;
	roop(i, 0, N) {
		cin >> n[i];
	}

	ll ans = INF;
	ll sum = 0;

	roop(i, -1000, 1000) {
		sum = 0;
		roop(j, 0, N) {
			sum += abs(i - n[j])*abs(i - n[j]);
		}
		ans = min(ans, sum);
	}


	cout << ans << endl;

	return 0;
}