Problem:
Score : 100 points

Problem Statement

The door of Snuke's laboratory is locked with a security code.

The security code is a 4-digit number. We say the security code is hard to enter when it contains two consecutive digits that are the same.

You are given the current security code S. If S is hard to enter, print Bad; otherwise, print Good.

Constraints

S is a 4-character string consisting of digits.

Input

Input is given from Standard Input in the following format:

S

Output

If S is hard to enter, print Bad; otherwise, print Good.

Sample Input 1

3776

Sample Output 1

Bad

The second and third digits are the same, so 3776 is hard to enter.

Sample Input 2

8080

Sample Output 2

Good

There are no two consecutive digits that are the same, so 8080 is not hard to enter.

Sample Input 3

1333

Sample Output 3

Bad

Sample Input 4

0024

Sample Output 4

Bad

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

//
//  main.cpp
//  A - Security
//
//  Created by Hashizo on 2019/06/22.
//  Copyright © 2019 Hashizo. All rights reserved.
//

#include <iostream>
#include <vector>
#include <algorithm>
#include <string>
#include <regex>

using namespace std;

#undef INT_MAX
#undef INT_MIN

#define INT_MAX	2147483647
#define INT_MIN	(-INT_MAX  -1)

#define FOR(i, a, b) for (int i = (a); i < (b); i++)
#define REP(i, n) FOR(i, 0, n)
#define SORT(c) sort((c).begin(), (c).end())
#define REPLACE(s, f, t) regex_replace(s, regex(f), t)

int main(int argc, const char * argv[]) {
	char s[4];
	cin >> s;

	
	if(s[0] == s[1]) {
		cout << "Bad" << endl;
		return 0;
	}
	else if (s[1] == s[2]){
		cout << "Bad" << endl;
		return 0;
	}
	else if (s[2] == s[3]){
		cout << "Bad" << endl;
		return 0;
	}

	cout << "Good" << endl;
	return 0;
}