Problem:
Score : 1600 points

Problem Statement

A balancing network is an abstract device built up of N wires, thought of as running from left to right,
and M balancers that connect pairs of wires. The wires are numbered from 1 to N from top to bottom,
and the balancers are numbered from 1 to M from left to right.
Balancer i connects wires x_i and y_i (x_i < y_i).

Each balancer must be in one of two states: up or down.

Consider a token that starts moving to the right along some wire at a point to the left of all balancers.
During the process, the token passes through each balancer exactly once.
Whenever the token encounters balancer i, the following happens:

If the token is moving along wire x_i and balancer i is in the down state, the token moves down to wire y_i and continues moving to the right.

If the token is moving along wire y_i and balancer i is in the up state, the token moves up to wire x_i and continues moving to the right.

Otherwise, the token doesn't change the wire it's moving along.

Let a state of the balancing network be a string of length M, describing the states of all balancers.
The i-th character is ^ if balancer i is in the up state, and v if balancer i is in the down state.

A state of the balancing network is called uniforming if a wire w exists such that, regardless of the starting wire,
the token will always end up at wire w and run to infinity along it. Any other state is called non-uniforming.

You are given an integer T (1 \le T \le 2). Answer the following question:

If T = 1, find any uniforming state of the network or determine that it doesn't exist.

If T = 2, find any non-uniforming state of the network or determine that it doesn't exist.

Note that if you answer just one kind of questions correctly, you can get partial score.

Constraints

2 \leq N \leq 50000

1 \leq M \leq 100000

1 \leq T \leq 2

1 \leq x_i < y_i \leq N

All input values are integers.

Partial Score

800 points will be awarded for passing the testset satisfying T = 1.

800 points will be awarded for passing the testset satisfying T = 2.

Input

Input is given from Standard Input in the following format:

N M T
x_1 y_1
x_2 y_2
:
x_M y_M

Output

Print any uniforming state of the given network if T = 1, or any non-uniforming state if T = 2. If the required state doesn't exist, output -1.

Sample Input 1

4 5 1
1 3
2 4
1 2
3 4
2 3

Sample Output 1

^^^^^

This state is uniforming: regardless of the starting wire, the token ends up at wire 1.

Sample Input 2

4 5 2
1 3
2 4
1 2
3 4
2 3

Sample Output 2

v^^^^

This state is non-uniforming: depending on the starting wire, the token might end up at wire 1 or wire 2.

Sample Input 3

3 1 1
1 2

Sample Output 3

-1

A uniforming state doesn't exist.

Sample Input 4

2 1 2
1 2

Sample Output 4

-1

A non-uniforming state doesn't exist.

Solution in C++14 (GCC 5.4.1) (judge verdict: Runtime Error)

// https://atcoder.jp/contests/agc041/tasks/agc041_e
#define CIN_ONLY
#define DECIMAL_DIGITS 10
#define STATIC_MOD 1e9 + 7

#ifdef BTK
/*<head>*/
#    include "Template.hpp"
/*</head>*/
#else
/*<body>*/
/* #region auto includes */
/* #region stl */
/*<stl>*/
#    include <bits/stdc++.h>
#    include <sys/types.h>
#    include <unistd.h>
using namespace std;
/*</stl>*/
/* #endregion */
/* #region template/IncludeSTL.hpp*/
/**
 * @file IncludeSTL.hpp
 * @author btk
 * @brief 標準ライブラリをincludeするだけ
 * @version 0.1
 * @date 2019-07-21
 * @todo 何故か2回includeされる（展開scriptに
 * @copyright Copyright (c) 2019
 *
 */


/* #endregion */
/* #region template/Macro.hpp*/
/**
 * @file Macro.hpp
 * @author btk
 * @brief マクロとか，LLとか
 * @version 0.1
 * @date 2019-07-13
 *
 * @copyright Copyright (c) 2019
 *
 */


//! LL
using LL = long long;

/**
 * @def DEBUG
 * @brief デバッグ用のif文 提出時はif(0)で実行されない
 */

/*</head>*/
#    ifdef BTK
#        define DEBUG if (1)
#    else
#        ifdef CIN_ONLY
#            define FAST_IO
#        endif
#        define DEBUG if (0)
#    endif
/**
 * @def ALL(v)
 * @brief
 * ALLマクロ
 */
#    define ALL(v) (v).begin(), (v).end()

/**
 * @def REC(ret, ...)
 * @brief
 * 再帰ラムダをするためのマクロ
 */
#    define REC(ret, ...) std::function<ret(__VA_ARGS__)>

/**
 * @def VAR_NAME(var)
 * @brief 変数名を取得する
 */
#    define VAR_NAME(var) #    var

/**
 * @brief
 * rangeで生まれる使わない変数を消す用（警告消し）
 */
template <typename T>
inline T& unused_var(T& v) {
    return v;
}
/* #endregion */
/* #region template/IO.hpp*/
/**
 * @file IO.hpp
 * @author btk
 * @brief cin高速化とか，出力の小数桁固定とか
 * @version 0.1
 * @date 2019-07-13
 *
 * @copyright Copyright (c) 2019
 */


/**
 * @brief 入出力の設定を行うための構造体
 */
struct cww {
    /**
     * @brief Construct a new cww::cww object
     * @details
     * CIN_ONLYを定義すると，submit時にcinとscanfの同期を切る設定が走る
     * DECIMAL_DIGITSを定義すると，doubleの出力時指定した桁数分小数部を吐くようになる
     */
    cww() {
#    ifdef FAST_IO
        ios::sync_with_stdio(false);
        cin.tie(0);
#    endif
#    ifdef DECIMAL_DIGITS
        cout << fixed;
        cout << setprecision(DECIMAL_DIGITS);
#    endif
    }
};

//! 入出力設定構造体を実体化
cww star;

/**
 * @brief
 * vectorに直接cin流すためのやつ
 * @tparam T
 * @param is
 * @param v
 * @return istream&
 */
template <typename T>
std::istream& operator>>(std::istream& is, std::vector<T>& v) {
    for (auto& it : v) is >> it;
    return is;
}
/* #endregion */
/* #region template/Loop.hpp*/
/**
 * @file Loop.hpp
 * @author btk
 * @brief rangeとかループ系のクラス
 * @version 0.1
 * @date 2019-07-13
 *
 * @copyright Copyright (c) 2019
 *
 */


/**
 * @brief
 * rangeを逆向きに操作したいとき用
 * @details
 * ループの範囲は[bg,ed)なので注意
 * @see range
 */
class reverse_range {
  private:
    struct I {
        int x;
        int operator*() { return x - 1; }
        bool operator!=(I& lhs) { return x > lhs.x; }
        void operator++() { --x; }
    };
    I i, n;

  public:
    /**
     * @brief Construct a new reverse range object
     *
     * @param n
     */
    reverse_range(int n) : i({0}), n({n}) {}
    /**
     * @brief Construct a new reverse range object
     *
     * @param i
     * @param n
     */
    reverse_range(int i, int n) : i({i}), n({n}) {}
    /**
     * @brief
     * begin iterator
     * @return I&
     */
    I& begin() { return n; }
    /**
     * @brief
     * end iterator
     * @return I&
     */
    I& end() { return i; }
};
/**
 * @brief
 * python みたいな range-based for を実現
 * @details
 * ループの範囲は[bg,ed)なので注意
 * !つけると逆向きにループが回る (reverse_range)
 * 空間計算量はO(1)
 * 使わない変数ができて警告が出がちなので，unused_varとかを使って警告消しするとよい
 */
class range {
  private:
    struct I {
        int x;
        int operator*() { return x; }
        bool operator!=(I& lhs) { return x < lhs.x; }
        void operator++() { ++x; }
    };
    I i, n;

  public:
    /**
     * @brief Construct a new range object
     *
     * @param n
     */
    range(int n) : i({0}), n({n}) {}
    /**
     * @brief Construct a new range object
     *
     * @param i
     * @param n
     */
    range(int i, int n) : i({i}), n({n}) {}
    /**
     * @brief
     * begin iterator
     * @return I&
     */
    I& begin() { return i; }
    /**
     * @brief
     * end iterator
     * @return I&
     */
    I& end() { return n; }
    /**
     * @brief
     * 逆向きに参照するrange(reverse_rangeを取得できるs)
     * @return reverse_range
     */
    reverse_range operator!() { return reverse_range(*i, *n); }
};
/* #endregion */
/* #region template/MinMaxOperation.hpp*/
/**
 * @file MinMaxOperation.hpp
 * @author btk
 * @brief 最大値とか最小値を求める
 * @version 0.1
 * @date 2019-07-04
 *
 * @copyright Copyright (c) 2019
 *
 */

/**
 * @brief 2項の最小値求める
 *
 * @tparam T
 */
template <typename T>
struct min_op {
    /**
     * @brief 本体
     *
     * @param l
     * @param r
     * @return T
     */
    static T exec(const T l, const T r) { return l < r ? l : r; }
};

/**
 * @brief 2項の最大値求める
 *
 * @tparam T
 */
template <typename T>
struct max_op {
    /**
     * @brief 本体
     *
     * @param l
     * @param r
     * @return T
     */
    static T exec(const T l, const T r) { return l > r ? l : r; }
};

/**
 * @brief テンプレート再帰の末尾
 *
 * @tparam F 二項演算
 * @tparam T
 * @param v
 * @return T
 */
template <typename F, typename T>
inline T multi_op(T&& v) {
    return v;
}

/**
 * @brief 複数項における演算の結果を返す
 *
 * @tparam F
 * @tparam T
 * @tparam Ts
 * @param head
 * @param tail
 * @return T
 */
template <typename F, typename T, typename... Ts>
inline T multi_op(const T head, Ts&&... tail) {
    return F::exec(head, multi_op<F>(tail...));
}

/**
 * @brief 複数項の最小値
 * @see multi_op
 * @tparam T
 * @tparam Ts
 * @param head
 * @param tail
 * @return T
 */
template <typename T, typename... Ts>
inline T multi_min(T&& head, Ts&&... tail) {
    return multi_op<min_op<T>>(head, tail...);
}

/**
 * @brief 複数項の最大値
 * @see multi_op
 * @tparam T
 * @tparam Ts
 * @param head
 * @param tail
 * @return T
 */
template <typename T, typename... Ts>
inline T multi_max(T&& head, Ts&&... tail) {
    return multi_op<max_op<T>>(head, tail...);
}

/**
 * @brief
 * 先頭の値をFで参照する関数に基づいて変更できたらする
 * @tparam F
 * @tparam T
 * @tparam Ts
 * @param target
 * @param candidates
 * @return true
 * @return false
 */
template <typename F, typename T, typename... Ts>
inline bool ch_op(T& target, Ts&&... candidates) {
    const T old = target;
    target      = multi_op<F>(target, candidates...);
    return old != target;
}

/**
 * @brief change min
 * @tparam T 型
 * @param target 変更する値
 * @param candidates
 * @return 更新があればtrue
 */
template <typename T, typename... Ts>
inline bool chmin(T& target, Ts&&... candidates) {
    return ch_op<min_op<T>>(target, candidates...);
}

/**
 * @brief chminのmax版
 * @see chmin
 *  @tparam T 型
 * @param target 変更する値
 * @param candidates
 * @return 更新があればtrue
 */
template <typename T, typename... Ts>
inline bool chmax(T& target, Ts&&... candidates) {
    return ch_op<max_op<T>>(target, candidates...);
}
/* #endregion */
/* #region template/Random.hpp*/
/**
 * @file Random.hpp
 * @author btk
 * @brief 乱数生成系
 * @version 0.1
 * @date 2019-07-13
 * @copyright Copyright (c) 2019
 */


//! 乱数のシード値をプロセスIDとして取得
const pid_t pid = getpid();

/**
 * @brief XorShift32の実装
 */
class XorShift32 {
  private:
    //! XorShiftの現在の値
    unsigned value;

    /**
     * @brief XorShift32のアルゴリズムに基づいて value を更新
     */
    inline void update() {
        value = value ^ (value << 13);
        value = value ^ (value >> 17);
        value = value ^ (value << 5);
    }

    /**
     * @brief 値を更新し，更新前の値を返却
     * @return unsigned 呼び出し時の value を用いる
     */
    inline unsigned get() {
        unsigned v = value;
        update();
        return v;
    }

  public:
    /**
     * @brief [0, 2^bit) の範囲の乱数値を取り出す
     * @tparam デフォルトは31
     * @return int
     */
    template <int bit = 31>
    inline int next_int() {
        return (int)(get() >> (32 - bit));
    }

    /**
     * @brief [-2^bit,2^bit)の範囲の乱数値を取り出す
     * @tparam デフォルトは31
     * @return int
     */
    template <int bit = 31>
    inline int next_signed() {
        unsigned v = get();
        return (int)((v >> (31 - bit)) - (1 << (bit)));
    }

    /**
     * @brief next_int呼び出し時の最大値を取得
     * @tparam 31
     * @return int
     */
    template <int bit = 31>
    inline int range_max() {
        return (int)((1u << bit) - 1);
    };

    /**
     * @brief Construct a new XorShift32 object
     * @param seed
     * @details 初期シードをvalueとするXorShift32のインスタンスを生成
     */
    XorShift32(const unsigned seed) {
        value = seed;
        update();
    }

    /**
     * @brief Construct a new XorShift 32 object
     * @details 初期シードをプロセスIDとするXorShift32のインスタンスを生成
     */
    XorShift32() : XorShift32(pid) {}
};
/* #endregion */
/* #region Template.hpp*/
/**
 * @file Template.hpp
 * @brief 競技プログラミング用テンプレート
 * @author btk15049
 * @date 2019/05/02
 */


/* #endregion */
/* #endregion */
/*</body>*/
#endif

using V  = vector<int>;
using VV = vector<V>;


int N, M, T;
using Z = array<int, 4>;
// i, j, size, pos
vector<Z> e[400][400];
int x[112345];
int y[112345];

void solve1() {
    int p = -1, q = -1;
    vector<vector<int>> es(N);
    for (int i : range(M)) {
        es[y[i]].push_back(x[i]);
    }
    for (int i : range(N)) {
        es[i].push_back(i);
        sort(ALL(es[i]));
        es[i].erase(unique(ALL(es[i])), end(es[i]));
        for (int j : range(i)) {
            if (es[i][j] != j) {
                p = j;
                q = i;
                break;
            }
        }
    }
    cerr << p << " " << q << endl;
    string ret(M, '^');
    for (int i : range(M)) {
        if (x[i] == p || x[i] == q) {
            ret[i] = '^';
        }
        if (y[i] == p || y[i] == q) {
            ret[i] = 'v';
        }
    }
    cout << ret << endl;
}

void solve2() {
    for (int i : range(N)) {
        for (int j : range(N)) {
            if (i != j) {
                e[i][j].push_back(Z{-1, -1, -1, -1});
            }
            else {
                e[i][j].push_back({Z{-2, -2, -2, -2}});
            }
        }
    }
    for (int i : range(M)) {
        e[x[i]][y[i]].push_back(Z{-2, -2, -2, -2});
        e[y[i]][x[i]].push_back({Z{-2, -2, -2, -2}});
        vector<pair<pair<int, int>, Z>> lazy;
        for (int p : range(N)) {
            // x[i] -> y[i]
            int from = x[p];
            int to   = y[p];
            for (int i : range(N)) {
                if (e[from][i].back()[0] != -2) {
                    lazy.push_back(
                        make_pair(make_pair(to, i),
                                  Z{from, i, e[from][i].size() - 1, p}));
                }
                if (e[i][from].back()[0] != -2) {
                    lazy.push_back(
                        make_pair(make_pair(i, to),
                                  Z{i, from, e[i][from].size() - 1, p}));
                }
            }
            swap(from, to);
            for (int i : range(N)) {
                if (e[from][i].back()[0] != -2) {
                    lazy.push_back(
                        make_pair(make_pair(to, i),
                                  Z{from, i, e[from][i].size() - 1, p}));
                }
                if (e[i][from].back()[0] != -2) {
                    lazy.push_back(
                        make_pair(make_pair(i, to),
                                  Z{i, from, e[i][from].size() - 1, p}));
                }
            }
            for (auto &it : lazy) {
                e[it.first.first][it.first.second].push_back(it.second);
            }
        }
    }
    int a = -5, b = -1;
    int h = -1;
    for (int i : range(N)) {
        for (int j : range(N)) {
            if (e[i][j].back()[0] != -2) {
                a = i;
                b = j;
                h = e[i][j].size() - 1;
            }
        }
    }
    if (a == -5) {
        cout << -1 << endl;
    }
    else {
        string ret(M, '^');
        while (true) {
            int pos = e[a][b][h][3];
            int _a  = e[a][b][h][0];
            int _b  = e[a][b][h][1];
            int _h  = e[a][b][h][2];
            // cerr << a << " " << b << " " << h << " " << pos << endl;
            if (pos == -1) break;

            if (a > b) {
                swap(a, b);
            }
            if (a == x[pos] || b == x[pos]) {
                ret[pos] = '^';
            }
            else {
                ret[pos] = 'v';
            }

            a = _a;
            b = _b;
            h = _h;
        }
        cout << ret << endl;
    }
}
int main() {
    /* write here */
    cin >> N >> M >> T;
    for (int i : range(M)) {
        cin >> x[i] >> y[i];
        x[i]--;
        y[i]--;
    }
    if (T == 2) {
        if (M < (N * 1ll * (N - 1)) / 2) {
            solve1();
        }
        else {
            solve2();
        }
    }
    else {
        return -1;
    }
    return 0;
}