Problem:
Score : 200 points

Problem Statement

Let S(n) denote the sum of the digits in the decimal notation of n.
For example, S(101) = 1 + 0 + 1 = 2.

Given an integer N, determine if S(N) divides N.

Constraints

1 \leq N \leq 10^9

Input

Input is given from Standard Input in the following format:

N

Output

If S(N) divides N, print Yes; if it does not, print No.

Sample Input 1

12

Sample Output 1

Yes

In this input, N=12.
As S(12) = 1 + 2 = 3, S(N) divides N.

Sample Input 2

101

Sample Output 2

No

As S(101) = 1 + 0 + 1 = 2, S(N) does not divide N.

Sample Input 3

999999999

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

//=template==================================================================//
// include
#include <vector>
#include <list>
#include <algorithm>
#include <sstream>
#include <iostream>
#include <cstdio>
#include <cmath>
#include <string>

// namespace
using namespace std;

// define
#define FOR(i,a,b) for(int (i)=(a); (i)<(b); (i)++)
#define REP(i,n) FOR(i,0,n)
#define MIN_V(v) *min_element(v.begin(), v.end())
#define MAX_V(v) *max_element(v.begin(), v.end())

// typedef
typedef vector<int> VI;
typedef vector<VI> VVI;
typedef vector<long> VL;
typedef vector<VL> VVL;
typedef vector<string> VS;
typedef long long LL;
typedef unsigned long long ULL;

// conversion
inline int toInt(string s) {int v; istringstream sin(s); sin>>v; return v;}
inline int countChar(string s, char c) {int cnt,i; cnt=0; REP (i,s.size()) {if (s[i]==c) cnt++;} return cnt;}
template<class T> inline string toString(T x) {ostringstream sout; sout<<x; return sout.str();}
//===========================================================================//

//=function prototype========================================================//
int getSum(LL n);
//===========================================================================//

//=variables=================================================================//

//===========================================================================//
int main(void)
{
  // Scan begin.
  LL n;
  cin >> n;
  // Scan done.

  // Code begin.
  int sum = getSum(n);
  if (n%sum==0) {
    cout << "Yes" << endl;
  }
  else {
    cout << "No" << endl;
  }
  // Code done.

  return 0;
}

//=functions=================================================================//
int getSum(LL n) {
  int sum = 0;
  while (n>0) {
      sum += n%10;
      n /= 10;
  }
  return sum;
}
//===========================================================================//