Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

    #include <bits/stdc++.h>
    using namespace std;

    int main(){
      long n, a , b, c , d;
      string str;
      cin >> n >> a >> b >> c >> d >> str;
      if(c < d || c < b ){
          for(long i = a - 1 ; i < c - 1 ; i++ ){
              if(str[i] == '#' && str[i+1] == '#'){
                  cout << "No" << endl;
                  return 0;
              }
          }
          for(long i = b - 1 ; i < d - 1 ; i++ ){
              if(str[i] == '#' && str[i+1] == '#'){
                  cout << "No" << endl;                  
                  return 0;
              }
          }
          cout << "Yes" << endl;
          return 0;
      }
      bool ans = false;
      for(long i = a - 1 ; i < c - 1 ; i++ ){
          if(str[i] == '#' && str[i+1] == '#'){
              cout << "No" << endl;
              return 0;
          }
          if(i >= b - 1 && i < n - 2){
              if(str[i] == '.' && str[i+1] == '.' && str[i+2] == '.')
              ans = true;
          }
      }
      
      if(b == a + 1 && str[b] == '.'){
          ans = true;
      }
      if(str[d-2] == '.' && str[d] == '.' ){
          ans = true;
      }
      if(ans){
          cout << "Yes" << endl;
      }else{
          cout << "No" << endl;
      }
      return 0;
    }