Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <algorithm>
#include <string> 
#include <vector>
#include <iomanip>
#include <queue>
#include <math.h>
using namespace std;
#define lol long long



int main()
{
	int N;
	cin >> N;
	int A = N / 100;
	int B = N % 100;
	if (1 <= A && A <= 12 && 1 <= B && B <= 12) {
		cout << "AMBIGUOUS" << endl;
	}
	else if ((1 <= A && A <= 18 && 1 <= B && B <= 12) || (A == 19 && 1 <= B && B <= 5)) {
		cout << "YYMM" << endl;
 	}
	else if ((1 <= A && A <= 12 && 1 <= B && B <= 18) || (B == 19 && 1 <= A && A <= 5)) {
		cout << "MMYY" << endl;
	}
	else {
		cout << "NA" << endl;
	}
}