Problem:
Score : 400 points

Problem Statement

Snuke has a large collection of cards. Each card has an integer between 1 and N, inclusive, written on it.
He has A_i cards with an integer i.

Two cards can form a pair if the absolute value of the difference of the integers written on them is at most 1.

Snuke wants to create the maximum number of pairs from his cards, on the condition that no card should be used in multiple pairs. Find the maximum number of pairs that he can create.

Constraints

1 ≦ N ≦ 10^5

0 ≦ A_i ≦ 10^9 (1 ≦ i ≦ N)

All input values are integers.

Input

The input is given from Standard Input in the following format:

N
A_1
:
A_N

Output

Print the maximum number of pairs that Snuke can create.

Sample Input 1

4
4
0
3
2

Sample Output 1

4

For example, Snuke can create the following four pairs: (1,1),(1,1),(3,4),(3,4).

Sample Input 2

8
2
0
1
6
0
8
2
1

Sample Output 2

9

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#define _CRT_SECURE_NO_WARNINGS
#include <cstdio>
#include <vector>
#include <string>
#include <iostream>
#include <algorithm>
#include <map>
#include <iterator>
#include <functional>
#include <set>
#include <stack>
#include <queue>
#include <deque>
#include <fstream>
#include <iomanip>
#include <unordered_map>
#include <unordered_set>
#include <numeric>
#include <cmath>
#include <list>
#include <sstream>
#include <tuple>
#include <complex>
#include <stdio.h>
using namespace std;
#pragma GCC optimize("O3")
#pragma GCC target("sse4")

typedef long double LD;
typedef long long LL;
typedef pair<int, int> PII;
typedef pair<LD, LD> PDD;
typedef pair<LL, LL> PLL;
typedef vector<int> VI;
typedef vector<LL> VLL;
typedef vector<char> VCH;
typedef vector<LD> VLD;
typedef vector<string> VS;
typedef vector<VS> VSS;
typedef vector<VI> VVI;
typedef vector<VLL> VVLL;
typedef vector<VCH> VVCH;
typedef vector<PII> VPII;
typedef vector<PLL> VPLL;
typedef vector<PDD> VPDD;
#define MP make_pair
#define PB push_back
#define X first
#define Y second
#define next fake_next
#define prev fake_prev
#define left fake_left
#define right fake_right

#define FOR(i,a,b) for(int i = (a); i < (b); ++i)
#define RFOR(i,b,a) for(int i = (b) - 1; i >= (a); --i)
#define REP(i, t) FOR(i,0,t)
#define ALL(a) a.begin(), a.end()
#define SZ(a) (int)((a).size())

const LD PI = acos(-1.0);
const LL mod = 1000000007;
const LL INF = 1e9;
const LL LINF = 1e18;
const LL MAXQ = 1007;
const int MAXN = 10007;

int main()
{
	ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);
	//freopen("In.txt", "r", stdin);

	int n;
	cin >> n;
	VLL a(n);
	FOR(i, 0, n)
		cin >> a[i];

	LL ans = 0;

	LL x;
	FOR(i, 0, n - 1)
	{
		x = min(a[i], a[i + 1]);
		ans += x;
		a[i] -= x;
		a[i + 1] -= x;
	}

	FOR(i, 0, n)
		ans += (a[i]) / 2;

	cout << ans;
//	cin >> n;
	return 0;
}