Problem:
Score : 100 points

Problem Statement

There are a total of A + B cats and dogs.
Among them, A are known to be cats, but the remaining B are not known to be either cats or dogs.

Determine if it is possible that there are exactly X cats among these A + B animals.

Constraints

1 \leq A \leq 100

1 \leq B \leq 100

1 \leq X \leq 200

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B X

Output

If it is possible that there are exactly X cats, print YES; if it is impossible, print NO.

Sample Input 1

3 5 4

Sample Output 1

YES

If there are one cat and four dogs among the B = 5 animals, there are X = 4 cats in total.

Sample Input 2

2 2 6

Sample Output 2

NO

Even if all of the B = 2 animals are cats, there are less than X = 6 cats in total.

Sample Input 3

5 3 2

Sample Output 3

NO

Even if all of the B = 3 animals are dogs, there are more than X = 2 cats in total.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;
#define pb push_back
#define mp make_pair
#define F first
#define S second
#define sz(x) (int)x.size()
#define all(x) (x).begin(), (x).end()
#define Red ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0)
#define rep(i, n) for(int i =0 ; i < n; ++i)
#define Rep(i,a,b) for(int i=a;i<=b;i++)
#define pii pair < int, int >
typedef vector<int> vi;
typedef  long long ll;
const int mod =1e9+7;
const int N = (int)2e5 + 5;

void solve(){
    int a,b,c;
    cin>>a>>b>>c;
    if(a+b>=c && a<c)cout<<"YES";
    else cout<<"NO";

}

int main(){
	Red;
	int t=1;
	//cin>>t;
	while(t--)
	solve();
	return 0;
}