Problem:
Score : 100 points

Problem Statement

In the Kingdom of AtCoder, people use a language called Taknese, which uses lowercase English letters.

In Taknese, the plural form of a noun is spelled based on the following rules:

If a noun's singular form does not end with s, append s to the end of the singular form.

If a noun's singular form ends with s, append es to the end of the singular form.

You are given the singular form S of a Taknese noun. Output its plural form.

Constraints

S is a string of length 1 between 1000, inclusive.

S contains only lowercase English letters.

Input

Input is given from Standard Input in the following format:

S

Output

Print the plural form of the given Taknese word.

Sample Input 1

apple

Sample Output 1

apples

apple ends with e, so its plural form is apples.

Sample Input 2

bus

Sample Output 2

buses

bus ends with s, so its plural form is buses.

Sample Input 3

box

Sample Output 3

boxs

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
#define pint pair<int, int>
#define pll pair<ll, ll>
#define vint vector<int >
#define vll vector<ll >
#define ALL(x) (x).begin(), (x).end()
#define FOR(i, a, b) for (int i = (a); i < (b); ++i)
#define REP(i,n) for (int i = 0; i < (n); ++i)
const int INF = 100100100;
const int MOD = (int)1e9 + 7;
const double EPS = 1e-9;
int main(){
    ios::sync_with_stdio(false);
    cin.tie(0); cout.tie(0);
    string s;
    cin >> s;
    if(s[s.length()-1] == 's'){
        cout << s+"es" << "\n";
    }else{
        cout << s+"s" << "\n";
    }
    
    return 0;
}