Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include"bits/stdc++.h"
using namespace std;

//typedef
//------------------------------------------
typedef long long LL;
typedef unsigned long long ULL;
typedef vector<LL> VLL;
typedef vector<VLL> VVLL;
typedef vector<string> VS;
typedef pair<LL, LL> PLL;

//container util
//------------------------------------------
#define ALL(a)  (a).begin(),(a).end()
#define PB push_back
#define MP make_pair
#define SORT(c) sort((c).begin(),(c).end())
#define COUT(x) cout<<x<<endl

//repetition
//------------------------------------------
#define FOR(i,a,b) for(int i=(a);i<(b);++i)
#define REP(i,n)  FOR(i,0,n)

//constant
//--------------------------------------------
const double PI = acos(-1.0);
const LL MOD = 1e9 + 7;
const ULL INF= 1e20;

//function
//--------------------------------------------
LL gcd(LL, LL);
bool isEven(LL);
void coutY();
void coutN();

int main() {
	LL n;
	cin >> n;
	LL a, b, c, d;
	cin >> a >> b >> c >> d;
	string s;
	cin >> s;
	FOR(i, a, max(c,d)) {
		if (s[i - 1] == '#' && s[i] == '#') {
			coutN();
			return 0;
		}
	}
	if (c > d) {
		FOR(i, b-1, d) {
			string tmp = s.substr(i-1, 3);
			if (tmp == "...") {
				coutY();
				return 0;
			}
		}
		coutN();
		return 0;
	}
	coutY();
	return 0;
}

LL gcd(LL a, LL b) {
	if (a == 0 || b == 0)return 0;
	if (a < b)swap(a, b);
	if (a % b == 0)return b;
	else gcd(b, a % b);
}
bool isEven(LL a) {
	return !((bool)(a % 2));
}
void coutY() {
	cout << "Yes" << endl;
	return;
}
void coutN() {
	cout << "No" << endl;
	return;
}