Problem:
Score : 300 points

Problem Statement

A company has N members, who are assigned ID numbers 1, ..., N.

Every member, except the member numbered 1, has exactly one immediate boss with a smaller ID number.

When a person X is the immediate boss of a person Y, the person Y is said to be an immediate subordinate of the person X.

You are given the information that the immediate boss of the member numbered i is the member numbered A_i. For each member, find how many immediate subordinates it has.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq A_i < i

Input

Input is given from Standard Input in the following format:

N
A_2 ... A_N

Output

For each of the members numbered 1, 2, ..., N, print the number of immediate subordinates it has, in its own line.

Sample Input 1

5
1 1 2 2

Sample Output 1

2
2
0
0
0

The member numbered 1 has two immediate subordinates: the members numbered 2 and 3.

The member numbered 2 has two immediate subordinates: the members numbered 4 and 5.

The members numbered 3, 4, and 5 do not have immediate subordinates.

Sample Input 2

10
1 1 1 1 1 1 1 1 1

Sample Output 2

9
0
0
0
0
0
0
0
0
0

Sample Input 3

7
1 2 3 4 5 6

Sample Output 3

1
1
1
1
1
1
0

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#define INF 2e9
using namespace std;
typedef long long llong;
typedef long double ldouble;

using Graph = vector<vector<int>>;

// int ctoi(const char c){
//   if('0' <= c && c <= '9') return (c-'0');
//   return -1;
// }

// int gcd(int a, int b){
//   int ma = max(a,b);
//   int mi = min(a,b);
//   if(mi == 0) return ma;

//   return gcd(mi, ma%mi);
// }
int main(){
  int N;
  cin >> N;
  vector<int> buka(N);
  for(int i=1; i<N; ++i){
    int A;
    cin >> A;
    ++buka[A-1];
  }
  for(int i=0; i<N; ++i) cout << buka[i] << endl;
}