Problem:
Score : 200 points

Problem Statement

You are given strings s and t, consisting of lowercase English letters.
You will create a string s' by freely rearranging the characters in s.
You will also create a string t' by freely rearranging the characters in t.
Determine whether it is possible to satisfy s' < t' for the lexicographic order.

Notes

For a string a = a_1 a_2 ... a_N of length N and a string b = b_1 b_2 ... b_M of length M, we say a < b for the lexicographic order if either one of the following two conditions holds true:

N < M and a_1 = b_1, a_2 = b_2, ..., a_N = b_N.

There exists i (1 \leq i \leq N, M) such that a_1 = b_1, a_2 = b_2, ..., a_{i - 1} = b_{i - 1} and a_i < b_i. Here, letters are compared using alphabetical order.

For example, xy < xya and atcoder < atlas.

Constraints

The lengths of s and t are between 1 and 100 (inclusive).

s and t consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s
t

Output

If it is possible to satisfy s' < t', print Yes; if it is not, print No.

Sample Input 1

yx
axy

Sample Output 1

Yes

We can, for example, rearrange yx into xy and axy into yxa. Then, xy < yxa.

Sample Input 2

ratcode
atlas

Sample Output 2

Yes

We can, for example, rearrange ratcode into acdeort and atlas into tslaa. Then, acdeort < tslaa.

Sample Input 3

cd
abc

Sample Output 3

No

No matter how we rearrange cd and abc, we cannot achieve our objective.

Sample Input 4

w
ww

Sample Output 4

Yes

Sample Input 5

zzz
zzz

Sample Output 5

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <cmath>
#include <vector>
#include <string>
#include <map>
#include <algorithm>
#include <numeric>
#include <fstream>
#include <iomanip>

typedef long double ld;
typedef long long ll;
const ll INF = (ll)1e18 + 1;
const ll MOD = 1e9 + 7;

// Split
namespace util {

std::vector< std::string > split(std::string s, char delimiter)
{
  std::vector< std::string > vs;
  std::string sub;
  for (auto c : s) {
    if (c == delimiter) vs.push_back(sub), sub.clear();
    else sub += c;
  }
  vs.push_back(sub);
  return vs;
}

} // namespace util

// Minimum, Maximum
template<class T> T minimum(T head, T tail) { return std::min(head, tail); }
template<class H, class... T> H minimum(H head, T... tail) { return std::min(head, minimum(tail...)); }
template<class T> T maximum(T head, T tail) { return std::max(head, tail); }
template<class H, class... T> H maximum(H head, T... tail) { return std::max(head, maximum(tail...)); }

// Output
template<class T> std::ostream& operator << (std::ostream& os, std::vector< T > v)
{
  for (ll i = 0; i < (ll)v.size(); i++){ os << " [" << i << "]" << v[i]; if (i % 10 == 9) os << std::endl; }
  return os;
}

template<class T, class S> std::ostream& operator << (std::ostream& os, std::vector< std::pair<T, S> > vp)
{
  ll i = 0;
  for (auto p : vp){os << " [" << i++ << "]" << p.first << " " << p.second; if (i % 10 == 0) os << std::endl;}
  return os;
}

void print(){ std::cout << std::endl; }
template<typename H> void print(H head) { std::cout << head << std::endl; }
template<typename H, typename... T> void print(H head, T... tail){ std::cout << head << " ", print(tail...); }

int main()
{
  std::cin.tie(nullptr);
  std::ios::sync_with_stdio(false);

  std::string s, t;
  std::cin >> s >> t;

  std::sort(s.begin(), s.end());
  std::sort(t.begin(), t.end(), std::greater<>());

  bool judge = s < t;
  if (judge) print("Yes");
  else print("No");

  return 0;
}