Problem:
Score : 200 points

Problem Statement

Given are integers a,b,c and d.
If x and y are integers and a \leq x \leq b and c\leq y \leq d hold, what is the maximum possible value of x \times y?

Constraints

-10^9 \leq a \leq b \leq 10^9

-10^9 \leq c \leq d \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

a b c d

Output

Print the answer.

Sample Input 1

1 2 1 1

Sample Output 1

2

If x = 1 and y = 1 then x \times y = 1.
If x = 2 and y = 1 then x \times y = 2.
Therefore, the answer is 2.

Sample Input 2

3 5 -4 -2

Sample Output 2

-6

The answer can be negative.

Sample Input 3

-1000000000 0 -1000000000 0

Sample Output 3

1000000000000000000

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include<iostream>
#include<vector>
#include <iomanip>
int main()
{
    long long int a,b,c,d;
    std::vector<long long int> vc;
    std::cin>>a>>b>>c>>d;
    vc.push_back(a*d);vc.push_back(a*c);vc.push_back(b*d);vc.push_back(b*c);
   double max=vc[0];
   for(int i;i<4;i++)
   {
       if(max<vc[i]) max=vc[i];
   }

    std::cout <<std::fixed<< std::setprecision(0)<< max ;

}