Problem:
Score : 200 points

Problem Statement

A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.

How many times will the ball make a bounce where the coordinate is at most X?

Constraints

1 \leq N \leq 100

1 \leq L_i \leq 100

1 \leq X \leq 10000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N X
L_1 L_2 ... L_{N-1} L_N

Output

Print the number of times the ball will make a bounce where the coordinate is at most X.

Sample Input 1

3 6
3 4 5

Sample Output 1

2

The ball will make a bounce at the coordinates 0, 3, 7 and 12, among which two are less than or equal to 6.

Sample Input 2

4 9
3 3 3 3

Sample Output 2

4

The ball will make a bounce at the coordinates 0, 3, 6, 9 and 12, among which four are less than or equal to 9.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>

using namespace std;

#define LL long long
#define Re register
#define U unsigned
#define forn(i,a,b) for(Re int i = a;i <= b;++i)
#define nfor(i,a,b) for(Re int i = a;i >= b;--i)
#define CLR(i,a) memset(i,a,sizeof(i))
#define BR printf("--------------------\n")
#define pb push_back
#define Rep(i,a,b) for(int i=a;i<=b;i++)
#define DEBUG(x) std::cerr << #x << '=' << x << std::endl
const double PI=atan(1.)*4.;
const int maxn=1e6+5;
const int inf = 0x3f3f3f3f;
const int mod=1e9+7;
const double e=2.71828182845904523536;
int dir[4][2]={1,0,0,1,-1,0,0,-1};
int a[maxn];
int main()
{
	ios::sync_with_stdio(false);
    cin.tie(0);
   	cout.tie(0);
    int n,x;
    int ans=1;
    cin>>n>>x;
    a[0]=0;
    for(int i=1;i<=n;i++)
    {
        cin>>a[i];
        a[i]=a[i]+a[i-1];
        if(a[i]<=x)
            ans++;
    }
    cout<<ans;
	return 0;
}