Problem:
Score : 400 points

Problem Statement

Give a pair of integers (A, B) such that A^5-B^5 = X.
It is guaranteed that there exists such a pair for the given integer X.

Constraints

1 \leq X \leq 10^9

X is an integer.

There exists a pair of integers (A, B) satisfying the condition in Problem Statement.

Input

Input is given from Standard Input in the following format:

X

Output

Print A and B, with space in between.
If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.

A B

Sample Input 1

33

Sample Output 1

2 -1

For A=2 and B=-1, A^5-B^5 = 33.

Sample Input 2

1

Sample Output 2

0 -1

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
#define int long long
#define mod 1000000007
#define trace(x) cerr<<#x<<": "<<x<<" "<<endl
#define tarce(x) cerr<<#x<<": "<<x<<" "<<endl
#define trace2(x, y) cerr<<#x<<": "<<x<<" | "<<#y<<": "<<y<<endl
#define trace3(x, y, z) cerr<<#x<<":" <<x<<" | "<<#y<<": "<<y<<" | "<<#z<<": "<<z<<endl
#define trace4(a, b, c, d) cerr<<#a<<": "<<a<<" | "<<#b<<": "<<b<<" | "<<#c<<": "<<c<<" | "<<#d<<": "<<d<<endl
#define sa(a,n) for(int i =0 ; i<n ; i++) cin>>a[i]
#define max3(a,b,c) max(a,max(b,c))
#define min3(a,b,c) min(a,min(b,c))
#define pb push_back
#define inf 2e18
#define scan() int n; cin>>n ; int a[n+1]; for(int i = 1 ; i<=n ; i++) cin>>a[i]
#define scan2() int n,k; cin>>n>>k ; int a[n+1]; for(int i = 1 ; i<=n ; i++) cin>>a[i]
#define print(a,n) for(int i = 0 ; i < n ; i++) cout<<a[i]<<' '
#define mem(a,v) memset(a,v,sizeof(a))
#define pii pair<int,int>
#define mkp make_pair
using namespace std;
#define N 200005


int check(int a){
    int l=-1000;
    int h=1000;
    while(l<=h){
        int mid=(l+h)/2;
        int x=pow(mid,5);
        if(x==a){
            return mid;
        }
        else if(x>a){
            h=mid-1;
        }
        else{
            l=mid+1;
        }
    }
    return inf;
}

int32_t main(){
        ios_base::sync_with_stdio(false);
        cin.tie(NULL);
        cout.tie(NULL);
        
        int x;
        cin >> x;
        for(int i=-1000; i<=1000; i++){
            int b=pow(i,5);
            int a=x+b;
            if(check(a)!=inf){
                cout << check(a) << ' ' << i << '\n';
                return 0; 
            }
        }
        

}