Problem:
Score : 600 points

Problem Statement

Silver Fox is fighting with N monsters.

The monsters are standing in a row, and we can assume them to be standing on a number line. The i-th monster, standing at the coordinate X_i, has the health of H_i.

Silver Fox can use bombs to attack the monsters.
Using a bomb at the coordinate x decreases the healths of all monsters between the coordinates x-D and x+D (inclusive) by A.
There is no way other than bombs to decrease the monster's health.

Silver Fox wins when all the monsters' healths become 0 or below.

Find the minimum number of bombs needed to win.

Constraints

1 \leq N \leq 2 \times 10^5

0 \leq D \leq 10^9

1 \leq A \leq 10^9

0 \leq X_i \leq 10^9

1 \leq H_i \leq 10^9

X_i are distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N D A
X_1 H_1
:
X_N H_N

Output

Print the minimum number of bombs needed to win.

Sample Input 1

3 3 2
1 2
5 4
9 2

Sample Output 1

2

First, let us use a bomb at the coordinate 4 to decrease the first and second monsters' health by 2.

Then, use a bomb at the coordinate 6 to decrease the second and third monsters' health by 2.

Now, all the monsters' healths are 0.
We cannot make all the monsters' health drop to 0 or below with just one bomb.

Sample Input 2

9 4 1
1 5
2 4
3 3
4 2
5 1
6 2
7 3
8 4
9 5

Sample Output 2

5

We should use five bombs at the coordinate 5.

Sample Input 3

3 0 1
300000000 1000000000
100000000 1000000000
200000000 1000000000

Sample Output 3

3000000000

Watch out for overflow.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;

// def
#define debug(x) cout << #x << ": " << x << endl
#define out(x) cout << x << endl
#define repeat(i, a, b) for (int i = (a); i < (b); i++)
#define revrepeat(i, a, b) for (int i = (b)-1; i >= (a); i--)
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define revrep(i, n) for (int i = (n)-1; i >= 0; i--)
#define all(x) (x).begin(), (x).end()
#define CYES cout << "Yes" << endl
#define CNO cout << "No" << endl
#define SPC(x) cout << fixed << setprecision(x)
#define ZERO(a) memset(a, 0, sizeof(a))
#define MINUS(a) memset(a, 0xff, sizeof(a))

typedef long long ll;
typedef long double ld;
typedef vector<int> vi;
typedef vector<vector<int>> vii;
typedef vector<ll> vl;
typedef vector<vector<ll>> vll;
typedef pair<int, int> P;
typedef complex<ld> Point;
const int MOD = 1e9 + 7;
const int INF = 1e9;
const int MAX_V = 1e5 + 5;
const int MAX_N = 1e5 + 5;
const double PI = acos(-1);

int main() {
    ll n, d, a;
    cin >> n >> d >> a;
    vector<pair<ll, ll>> v(n);
    vl reach(n, 0);
    vl damage(n, 0);
    ll ans = 0;
    rep(i, n) cin >> v[i].first >> v[i].second;
    auto comPair = [](const P &firstElof, const P &secondElof) {
        return firstElof.first < secondElof.first;
    };
    sort(all(v), comPair);
    // debug(v[2].first);

    int r = 0;
    rep(l, n) {
        if (l == r) r++;

        while (v[r].first - v[l].first <= 2 * d && r < n) {
            r++;
        }

        // debug(l);
        // debug(r);

        reach[l] = r;
    }

    rep(i, n) {
        auto p1 = v[i];
        ll bomb_num = (p1.second + a - 1) / a;
        ll bomb = bomb_num * a;

        ans += bomb_num;

        // debug(i);
        // debug(reach[i]);
        // debug(bomb_num);

        repeat(j, i, reach[i]) {
            damage[j] += bomb;
        }
        while (1) {
            if (damage[i] < v[i].second || i >= n) break;
            i++;
        }
    }

    out(ans);

    return 0;
}