Problem:
Score : 200 points

Problem Statement

Takahashi's house has only one socket.

Takahashi wants to extend it with some number of power strips, each with A sockets, into B or more empty sockets.

One power strip with A sockets can extend one empty socket into A empty sockets.

Find the minimum number of power strips required.

Constraints

All values in input are integers.

2 \leq A \leq 20

1 \leq B \leq 20

Input

Input is given from Standard Input in the following format:

A B

Output

Print the minimum number of power strips required.

Sample Input 1

4 10

Sample Output 1

3

3 power strips, each with 4 sockets, extend the socket into 10 empty sockets.

Sample Input 2

8 9

Sample Output 2

2

2 power strips, each with 8 sockets, extend the socket into 15 empty sockets.

Sample Input 3

8 8

Sample Output 3

1

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
#define f first
#define s second
#define MOD 1000000007
#define PMOD 998244353
#define pb(x) push_back(x)
using namespace std;

typedef long long int ll;
typedef pair<int,int> pii;
typedef pair<ll,ll> plii;
typedef pair<int, pii> piii;
const int INF = 1e9+10;
const ll LINF = 1LL*INF*INF;
const int MAXN = 2e5+10;
const int MAXM = 5e3+10;

priority_queue<int> pq;
vector<vector<int> > graph;
queue<int> que;

int A[MAXN];
char S[MAXN];

int main()
{
    int n,m,k,a,b,x,y,q;
    int sum = 0;
    int cnt = 0;
    int mx = 0;
    int mn = INF;
    int cur = 0, idx = -1;
    int tc;

    ios_base::sync_with_stdio(false);
    cin.tie(NULL);

    cin>>a>>b;

    int res = (b+a-1)/a;

    cout<<res<<"\n";

    return 0;
}