Problem:
Score : 300 points

Problem Statement

There are N people living on a number line.

The i-th person lives at coordinate X_i.

You are going to hold a meeting that all N people have to attend.

The meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.

Find the minimum total points of stamina the N people have to spend.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq X_i \leq 100

Input

Input is given from Standard Input in the following format:

N
X_1 X_2 ... X_N

Output

Print the minimum total stamina the N people have to spend.

Sample Input 1

2
1 4

Sample Output 1

5

Assume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.

Note that you can hold the meeting only at an integer coordinate.

Sample Input 2

7
14 14 2 13 56 2 37

Sample Output 2

2354

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define ff        first
#define ss        second
#define ll        long long
#define int       long long
#define inf       ((ll)1e18)
#define mod       1000000007
#define double    long double
#define ull       unsigned long long
#define vi        vector<ll>
#define ppi       pair<int,int>
#define pii       pair<pair<int,int>,int>
#define pb        push_back
#define pi        2*acos(0.0)
#define rev       greater<int>()
#define pr(a,x,y) for(int i=x;i<y;i++){cout<<a[i]<<" ";}
#define ps(s)     for(auto i:s){cout<<i<<" ";}
#define sp(x,y)   fixed<<setprecision(y)<<x
#define w(x)      ll x; cin>>x; while(x--)
#define all(v)    v.begin(), v.end()
#define rall(v)   v.rbegin(), v.rend()
#define test      cout<<"This is test"<<endl;
#define str       string
#define endl      '\n'
#define e         cout<<'\n';
void kehsihba(){
	ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
	/*#ifndef ONLINE_JUDGE
		freopen("input.txt", "r", stdin);
		freopen("output.txt", "w", stdout);
	#endif*/
}
void solve(){
	ll n;cin>>n;
	ll arr[n];
	for(int i=0;i<n;i++){cin>>arr[i];}
	int ans=INT_MAX;
	for(int i=0;i<=200;i++){
		int c=0;
		for(int j=0;j<n;j++){
			c+=((i-arr[j])*(i-arr[j]));
		}
		ans=min(ans,c);
	}
	cout<<ans;
}
int32_t main(){
	kehsihba();
	//init();
	ll t=1;
	//cin>>t;
	for(int k=1;k<=t;k++){
		//cout<<"Case "<<k<<": ";
		solve();
		//e;
	}
}