Problem:
Score : 300 points

Problem Statement

There are N slimes lining up from left to right. The colors of these slimes will be given as a string S of length N consisting of lowercase English letters. The i-th slime from the left has the color that corresponds to the i-th character of S.

Adjacent slimes with the same color will fuse into one larger slime without changing the color. If there were a slime adjacent to this group of slimes before fusion, that slime is now adjacent to the new larger slime.

Ultimately, how many slimes will be there?

Constraints

1 \leq N \leq 10^5

|S| = N

S consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

N
S

Output

Print the final number of slimes.

Sample Input 1

10
aabbbbaaca

Sample Output 1

5

Ultimately, these slimes will fuse into abaca.

Sample Input 2

5
aaaaa

Sample Output 2

1

All the slimes will fuse into one.

Sample Input 3

20
xxzaffeeeeddfkkkkllq

Sample Output 3

10

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;

void fnInput(string& rsColor)
{
  int nColorSiz;
  cin >> nColorSiz >> rsColor;
}

int fnColorCount(string sColor)
{
  int nColorCnt = 0;
  int nBgn = 0;
  while (nBgn < sColor.size())
  {
    nColorCnt++;
    int nFoward = nBgn + 1;

    while (nFoward < sColor.size() &&
           sColor[nBgn] == sColor[nFoward])
      nFoward++;

    nBgn = nFoward;
  }
  return nColorCnt;
}

int main()
{
  string sColor;

  fnInput(sColor);
  cout << fnColorCount(sColor) << endl;

  return 0;
}