Problem:
Score : 100 points

Problem Statement

In the Kingdom of AtCoder, people use a language called Taknese, which uses lowercase English letters.

In Taknese, the plural form of a noun is spelled based on the following rules:

If a noun's singular form does not end with s, append s to the end of the singular form.

If a noun's singular form ends with s, append es to the end of the singular form.

You are given the singular form S of a Taknese noun. Output its plural form.

Constraints

S is a string of length 1 between 1000, inclusive.

S contains only lowercase English letters.

Input

Input is given from Standard Input in the following format:

S

Output

Print the plural form of the given Taknese word.

Sample Input 1

apple

Sample Output 1

apples

apple ends with e, so its plural form is apples.

Sample Input 2

bus

Sample Output 2

buses

bus ends with s, so its plural form is buses.

Sample Input 3

box

Sample Output 3

boxs

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)


// Problem : A - Plural Form
// Contest : AtCoder - AtCoder Beginner Contest 179
// URL : https://atcoder.jp/contests/abc179/tasks/abc179_a
// Memory Limit : 1024 MB
// Time Limit : 2000 ms
// Powered by CP Editor (https://github.com/cpeditor/cpeditor)

#include<bits/stdc++.h>
using namespace std;
const long long int  modu=1e9+7;
#define endl '\n'
#define ll long long int
#define vi vector<int>
#define vl vector<ll>
#define inp(x)  for(auto &t:x) cin>>t;
#define itr     vector<int>::iterator
#define debug(a) cout << #a << "=" << a << ' '<<endl;
#define out(x)  for(auto &t:x) cout<<t<<" "; cout<<endl;
#define ff first
#define ss second
#define pb push_back
#define initialize(a,v)  for(int i=0;i<a.size();++i) a[i]=v;
#define all(x) x.begin(),x.end()
#define mpt(mp) for(auto it=mp.begin();it!=mp.end();it++)
#define trav(x) for(int i=0;i<(int)x.size();++i)
#define mkp(a,b) make_pair(a,b)
#define sz(x)  (int)x.size()

int noofdig(int N)
{
	return floor(log10(N))+1;
}


ll f(ll a)
{

return 0;

}



void pre()
{

}



void solve()
{
  
  string s;
  cin>>s;
  if(s[s.length()-1]=='s')
  s+="es";
  else
  s+="s";
  
  cout<<s<<endl;
  





}



int main()
{
	ios_base::sync_with_stdio(false);
	cin.tie(NULL);

	int t=1;
//	cin>>t;
	while(t--)
	{
		solve();
	}
}