Problem:
Score: 100 points

Problem Statement

We have two distinct integers A and B.

Print the integer K such that |A - K| = |B - K|.

If such an integer does not exist, print IMPOSSIBLE instead.

Constraints

All values in input are integers.

0 \leq A,\ B \leq 10^9

A and B are distinct.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the integer K satisfying the condition.

If such an integer does not exist, print IMPOSSIBLE instead.

Sample Input 1

2 16

Sample Output 1

9

|2 - 9| = 7 and |16 - 9| = 7, so 9 satisfies the condition.

Sample Input 2

0 3

Sample Output 2

IMPOSSIBLE

No integer satisfies the condition.

Sample Input 3

998244353 99824435

Sample Output 3

549034394

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;
 
#define REP(i, a, b) for(int i = (a); i <= (b); i++)
#define PER(i, a, b) for(int i = (a); i >= (b); i--)
#define rep(i, a, b) for(int i = (a); i < (b); i++)
#define all(S) (S).begin(), (S).end()
#define pf push_front
#define pb push_back
#define mk make_pair
#define S second
#define F first
typedef long long ll;
typedef long double lf;
typedef pair<int, int> ii;
int A, B;

int main(int argc, char ** argv) {
	scanf("%d%d", &A, &B);
	int x = (A+B)/2;
	if(abs(A-x)==abs(B-x)) printf("%d\n", x);
	else puts("-1");
	return 0;
}