Problem:
Score : 300 points

Problem Statement

Takahashi is a teacher responsible for a class of N students.

The students are given distinct student numbers from 1 to N.

Today, all the students entered the classroom at different times.

According to Takahashi's record, there were A_i students in the classroom when student number i entered the classroom (including student number i).

From these records, reconstruct the order in which the students entered the classroom.

Constraints

1 \le N \le 10^5

1 \le A_i \le N

A_i \neq A_j (i \neq j)

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 \ldots A_N

Output

Print the student numbers of the students in the order the students entered the classroom.

Sample Input 1

3
2 3 1

Sample Output 1

3 1 2

First, student number 3 entered the classroom.

Then, student number 1 entered the classroom.

Finally, student number 2 entered the classroom.

Sample Input 2

5
1 2 3 4 5

Sample Output 2

1 2 3 4 5

Sample Input 3

8
8 2 7 3 4 5 6 1

Sample Output 3

8 2 4 5 6 7 3 1

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;
#define rep(i,n) for(int i=0; i<n ; ++i)
#define REP(i,a,b) for(int i=a; i<b; ++i)
using ll = long long;
using vi = vector<int>;
using vl = vector<ll>;
using vvi = vector<vector<int>>;
using vvl = vector<vector<ll>>;
//プロトタイプ宣言
int gcd(int , int);
void often(void);
int get_digent(int);


int main(){
  often();
  int n;
  cin >> n;
  vi a(n);
  int num;
  rep(i,n){
    cin >> num;
    a[num - 1] = i+1;
  }
  rep(i,n) cout << a[i] << endl;
}








































//以下、ライブラリ

int gcd(auto a, auto b) {
  return b ? gcd(b, a%b) : a;
}  //ユークリッドの互除法

void often(void){
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
}

int get_digent(int x){
  string s;
  s = to_string(x);
  int digent = s.size();
  return digent;
}