Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in C++14 (GCC 5.4.1) (judge verdict: Runtime Error)

#include <bits/stdc++.h>
using namespace std;
#define IOS ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);
#define ll long long
#define vll vector<ll>
#define vi vector<int>
#define sll(x) scanf("%lld",&x)
#define prll(x) printf("%lld ",x)
#define pri(x) printf("%d ",x)
#define si(x) scanf("%d",&x)
#define el cout << "\n"
#define pb push_back
#define f first
#define s second
#define arrondi(a) (long long)floor(a+0.5);
#define NIL -1
ll N=500005;
ll MAX=9223372036854775807;
ll MOD=1000000007;
long double PI =4*atan(1);
ll n , m ,k;
ll nbr;

int main()
{
	IOS;
	 std::cout << std::setprecision(30);
    ll n,k;
    cin >> n >> k;
    vector<ll> dp(n,0);
    string ch="";
    for(int i=0;i<n;i++)
    {
        ch+='0';
    }
    ch[0]='1';

    for(int i=0;i<k;i++)
    {
        ll x,y;
        cin >> x >> y;
        if(dp[x-1]==0 || dp[x-1]==y)
            {dp[x-1]=y; ch[x-1]=(y+'0');}
        else
            return cout << -1,0;


    }
    if(ch[0]=='0' && n!=0)
        cout << -1;
    else
        cout << ch;
    return 0;
}