Problem:
Score : 300 points

Problem Statement

You are given an integer N. Among the integers between 1 and N (inclusive), how many Shichi-Go-San numbers (literally "Seven-Five-Three numbers") are there?

Here, a Shichi-Go-San number is a positive integer that satisfies the following condition:

When the number is written in base ten, each of the digits 7, 5 and 3 appears at least once, and the other digits never appear.

Constraints

1 \leq N < 10^9

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

Print the number of the Shichi-Go-San numbers between 1 and N (inclusive).

Sample Input 1

575

Sample Output 1

4

There are four Shichi-Go-San numbers not greater than 575: 357, 375, 537 and 573.

Sample Input 2

3600

Sample Output 2

13

There are 13 Shichi-Go-San numbers not greater than 3600: the above four numbers, 735, 753, 3357, 3375, 3537, 3557, 3573, 3575 and 3577.

Sample Input 3

999999999

Sample Output 3

26484

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <cstdio>
int s[110],l;
void qiu(int n)
{
	l=0;
	while(n)
	{
		s[l++]=n%10;
		n/=10;
		//printf("%d///...",s[l-1]);
	}
}
int main()
{
	int n,j,ans=0,a,b,c,i;
	scanf("%d",&n);
	if(n<350)
	{
		printf("0\n");
		return 0;
	}
	for(i=355;i<n;i++)
	{
		a=0,b=0,c=0;
        if(i>760&&i<3040) i*=4;
        if(i>7600&&i<30400) i*=4;
        if(i>76000&&i<304000) i*=4;
        if(i>760000&&i<3040000) i*=4;
        if(i>7600000&&i<30400000) i*=4;
		qiu(i);
		for(j=0;j<l;j++)
		{
			if(s[j]==7)
				a++;
			if(s[j]==3)
				b++;
			if(s[j]==5)
				c++;
			if((a+b+c)==l&&a&&b&&c)
			{
				ans++;
				break;
			}
		}
	}
	printf("%d\n",ans);
	return 0;
}