Problem:
Score : 100 points

Problem Statement

Takahashi is a member of a programming competition site, ButCoder.

Each member of ButCoder is assigned two values: Inner Rating and Displayed Rating.

The Displayed Rating of a member is equal to their Inner Rating if the member has participated in 10 or more contests. Otherwise, the Displayed Rating will be their Inner Rating minus 100 \times (10 - K) when the member has participated in K contests.

Takahashi has participated in N contests, and his Displayed Rating is R. Find his Inner Rating.

Constraints

All values in input are integers.

1 \leq N \leq 100

0 \leq R \leq 4111

Input

Input is given from Standard Input in the following format:

N R

Output

Print his Inner Rating.

Sample Input 1

2 2919

Sample Output 1

3719

Takahashi has participated in 2 contests, which is less than 10, so his Displayed Rating is his Inner Rating minus 100 \times (10 - 2) = 800.

Thus, Takahashi's Inner Rating is 2919 + 800 = 3719.

Sample Input 2

22 3051

Sample Output 2

3051

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

    /*
                    Author: Ankit Kaul
    **********************Code Belongs to Respective Author Only************************************
    */
    /*#pragma GCC optimize("O3")
    #pragma GCC optimize("Ofast")
    #pragma GCC optimize("unroll-loops")
    #pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")*/
    #include <bits/stdc++.h>
    #define endl       '\n'
    #define PI          3.141592653589
    #define jaldi       ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0);
    #define M           1000000007
    #define int         long long int
    #define inf         INT_MAX
    #define pb          emplace_back
    #define pf          emplace_front
    #define pii         pair<int,int>
    #define vi          vector<int>
    #define vii         vector<pii>
    #define mi          map<int,int>
    #define mii         map<pii,int>
    #define all(a)      (a).begin(),(a).end()
    #define rall(a)     (a).rbegin(),(a).rend()
    using namespace std;
    int gcd(int a,int b) { return b == 0 ? a : gcd(b, a % b); }
    int power(int x,int n){
        int result=1;
        while(n>0)
        {   if(n % 2 ==1)
            result=(result * x) % M;
            x=(x*x)% M;
            n=n/2;
        }
    return result % M;
    }      
    bool isPrime(int n) 
    { 
    if (n <= 1) 
        return false; 
    if (n <= 3) 
        return true; 
    if (n % 2 == 0 || n % 3 == 0) 
        return false; 
    for (int i = 5; i * i <= n; i = i + 6) 
        if (n % i == 0 || n % (i + 2) == 0) 
            return false; 
    return true; 
    } 
    signed main()
    {   jaldi
        int n,x;
        cin>>n>>x;
        if(n>=10)
        cout<<x;
        else
        cout<<x+((10-n)*100);        
    }