Problem:
Score : 200 points

Problem Statement

There are N positive integers written on a blackboard: A_1, ..., A_N.

Snuke can perform the following operation when all integers on the blackboard are even:

Replace each integer X on the blackboard by X divided by 2.

Find the maximum possible number of operations that Snuke can perform.

Constraints

1 \leq N \leq 200

1 \leq A_i \leq 10^9

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

Print the maximum possible number of operations that Snuke can perform.

Sample Input 1

3
8 12 40

Sample Output 1

2

Initially, [8, 12, 40] are written on the blackboard.
Since all those integers are even, Snuke can perform the operation.

After the operation is performed once, [4, 6, 20] are written on the blackboard.
Since all those integers are again even, he can perform the operation.

After the operation is performed twice, [2, 3, 10] are written on the blackboard.
Now, there is an odd number 3 on the blackboard, so he cannot perform the operation any more.

Thus, Snuke can perform the operation at most twice.

Sample Input 2

4
5 6 8 10

Sample Output 2

0

Since there is an odd number 5 on the blackboard already in the beginning, Snuke cannot perform the operation at all.

Sample Input 3

6
382253568 723152896 37802240 379425024 404894720 471526144

Sample Output 3

8

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include "bits/stdc++.h"
#define PRECISION(x) cout << fixed << setprecision(x)
#define FAST_IO ios::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);
#define SZ(X) ((int)(X).size())
#define ALL(X) (X).begin(), (X).end()
#define ALLR(X) (X).rbegin(), (X).rend()
#define MP make_pair
#define PB push_back
#define EB emplace_back
#define F first
#define S second

using namespace std;
 
template<class T> void max_self(T & a, const T & b) { if(a < b) a = b; }
template<class T> void min_self(T & a, const T & b) { if(a > b) a = b; }
typedef long long LL;
const int INF = 1e9 + 7;
const double PI = acos(-1.0);
const double EPS = (1e-9);



int main(){
  FAST_IO
  int N, min = INF; cin >> N;

  for(int rep = 0; rep < N; ++rep){
    int cur = 0, x; cin >> x;
    while((x & 1) == 0){
      cur++;
      x >>= 1;
    }
    min_self(min, cur);
  }

  cout << min << "\n";
 
  return 0;
}