Problem:
Score : 200 points

Problem Statement

There are N cities and M roads.
The i-th road (1≤i≤M) connects two cities a_i and b_i (1≤a_i,b_i≤N) bidirectionally.
There may be more than one road that connects the same pair of two cities.
For each city, how many roads are connected to the city?

Constraints

2≤N,M≤50

1≤a_i,b_i≤N

a_i ≠ b_i

All input values are integers.

Input

Input is given from Standard Input in the following format:

N M
a_1 b_1
:
a_M b_M

Output

Print the answer in N lines.
In the i-th line (1≤i≤N), print the number of roads connected to city i.

Sample Input 1

4 3
1 2
2 3
1 4

Sample Output 1

2
2
1
1

City 1 is connected to the 1-st and 3-rd roads.

City 2 is connected to the 1-st and 2-nd roads.

City 3 is connected to the 2-nd road.

City 4 is connected to the 3-rd road.

Sample Input 2

2 5
1 2
2 1
1 2
2 1
1 2

Sample Output 2

5
5

Sample Input 3

8 8
1 2
3 4
1 5
2 8
3 7
5 2
4 1
6 8

Sample Output 3

3
3
2
2
2
1
1
2

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<bits/stdc++.h>

#define fi first
#define se second
#define FO(x, n) for (int x = 0; x < n; ++x)
#define FOR(x, a, b) for (int x = a; x < b; ++x)
#define RFO(x, n) for (int x = n - 1; x >= 0; --x)
#define RFOR(x, a, b) for (int x = b - 1; x >= a; --x)
#define FOR_ITER(x, a) for(auto x = a.begin(); x != a.end(); ++x)

using namespace std;

typedef unsigned char byte;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<int, int> pii;
typedef pair<double, double> pdd;
typedef pair<string, string> pss;
typedef pair<ll, ll> pll;
inline bool feq(const double& a, const double& b) { return fabs(a - b) < 1e-10; }



int n, m;

int main(){
//    int n, l;
//    cin >> n >> k;
//    vector<bool> dislike(10, false);
//
//    FOR(i, 0, k) {
//        int t;
//        cin >> t;
//        dislike[t] = true;
//    }


    int n, m;

    cin >> n >> m;

    vector<int> nums(n, 0);

    FO(i, m) {
        int a, b;
        cin >>a>>b;
        nums.at(a - 1)++;
        nums.at(b - 1)++;
    }
    FO(i, n) {
        cout << nums.at(i) << endl;
    }

    return 0;
}