Problem:
Score : 200 points

Problem Statement

A string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:

S is a palindrome.

Let N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.

The string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.

Determine whether S is a strong palindrome.

Constraints

S consists of lowercase English letters.

The length of S is an odd number between 3 and 99 (inclusive).

Input

Input is given from Standard Input in the following format:

S

Output

If S is a strong palindrome, print Yes;
otherwise, print No.

Sample Input 1

akasaka

Sample Output 1

Yes

S is akasaka.

The string formed by the 1-st through the 3-rd characters is aka.

The string formed by the 5-th through the 7-th characters is aka.
All of these are palindromes, so S is a strong palindrome.

Sample Input 2

level

Sample Output 2

No

Sample Input 3

atcoder

Sample Output 3

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
bool isPalindrome(string s,int p,int r){
    string rev=s;
    for(int i=p;i<r;i++){
        rev[i]=s[r-i-1];
    }
    if(rev==s){
        return true;
    }else{
        return false;
    }
}
int main(){
    string s;
    cin>>s;
    int n=s.length();  
    //cout<<(n-1)/2;
    if(isPalindrome(s,0,n)){
        if(isPalindrome(s,0,(n-1)/2) && isPalindrome(s,(n+1)/2,n)){
            cout<<"Yes";
        }else{
            cout<<"No";
        }
    }else{
        cout<<"No";
    }
    return 0;
}