Problem:
Score : 200 points

Problem Statement

A string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:

S is a palindrome.

Let N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.

The string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.

Determine whether S is a strong palindrome.

Constraints

S consists of lowercase English letters.

The length of S is an odd number between 3 and 99 (inclusive).

Input

Input is given from Standard Input in the following format:

S

Output

If S is a strong palindrome, print Yes;
otherwise, print No.

Sample Input 1

akasaka

Sample Output 1

Yes

S is akasaka.

The string formed by the 1-st through the 3-rd characters is aka.

The string formed by the 5-th through the 7-th characters is aka.
All of these are palindromes, so S is a strong palindrome.

Sample Input 2

level

Sample Output 2

No

Sample Input 3

atcoder

Sample Output 3

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Runtime Error)

#include <bits/stdc++.h>

using namespace std;
using ll = long long;

#define FOR(i,a,n) for(int i=(a); i<(n); i++)
#define REP(i,n) FOR(i, 0, n)
#define FORD(i,a,n) for(int i=(a); i>=(n); i--)
#define REPD(i,n) FOR(i, n, 0)

#define ALL(o) (o).begin(), (o).end()

template<class T> using V = vector<T>;
template<class T, class U> using P = pair<T, U>;
template<class T> using PQ = priority_queue<T>;
template<class T> using PQR = priority_queue<T, vector<T>, greater<T> >;

const ll MOD = 1000000007;

bool f(string s) {
	string ss = s;
	reverse(ALL(ss));
	if(s == ss) {
		return true;
	}
	return false;
}

int main() {
	string s;
	cin >> s;

	int n = s.size();
	if(f(s) && f(s.substr(0, n/2)) && f(s.substr((n+3)/2+1, (n-(n+3)/2+1)))) {
		cout << "Yes" << endl;
	} else {
		cout << "No" << endl;
	}

	return 0;

}