Problem:
Score : 200 points

Problem Statement

A string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:

S is a palindrome.

Let N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.

The string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.

Determine whether S is a strong palindrome.

Constraints

S consists of lowercase English letters.

The length of S is an odd number between 3 and 99 (inclusive).

Input

Input is given from Standard Input in the following format:

S

Output

If S is a strong palindrome, print Yes;
otherwise, print No.

Sample Input 1

akasaka

Sample Output 1

Yes

S is akasaka.

The string formed by the 1-st through the 3-rd characters is aka.

The string formed by the 5-th through the 7-th characters is aka.
All of these are palindromes, so S is a strong palindrome.

Sample Input 2

level

Sample Output 2

No

Sample Input 3

atcoder

Sample Output 3

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

/// ببِسْمِ اللَّهِ الرَّحْمَنِ الرَّحِيم
#include<bits/stdc++.h>
using namespace std;
#define ll long long
int main()
{
     ios_base::sync_with_stdio(false);cin.tie(NULL);
     ll int i,n,t,p=INT_MAX,j=0,x,a=0,b,l=0,r=0,y,k,c;
     string s,m,st,sb,sc;
     cin>>s;
     m=s.substr(0,s.size()/2);
    st=s.substr(s.size()/2+1,s.size()/2);
     sb=m.substr(0,m.size()/2);
     sc=m.substr(m.size()/2+1,m.size()/2);
     if(m==st && sb==sc){
        cout<<"Yes"<<endl;
     }
     else{
        cout<<"No"<<endl;
     }


     return EXIT_SUCCESS;
}