Problem:
Score : 200 points

Problem Statement

There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is R, and a blue hat if s_i is B.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

1 \leq N \leq 100

|s| = N

s_i is R or B.

Input

Input is given from Standard Input in the following format:

N
s

Output

If there are more people wearing a red hat than there are people wearing a blue hat, print Yes; otherwise, print No.

Sample Input 1

4
RRBR

Sample Output 1

Yes

There are three people wearing a red hat, and one person wearing a blue hat.

Since there are more people wearing a red hat than people wearing a blue hat, the answer is Yes.

Sample Input 2

4
BRBR

Sample Output 2

No

There are two people wearing a red hat, and two people wearing a blue hat.

Since there are as many people wearing a red hat as people wearing a blue hat, the answer is No.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define inf 999999999
#define loop(i, a, b) for (int i = (a), i##len = (b); i < i##len; ++i)
#define rep(i, n) loop(i, 0, n)
#define lin long long
#define lfl long double

int main(void)
{
    string s;
    int n;
    cin >> n >> s;
    int r = 0;
    int b = 0;

    rep(i,n)
    {
        if(s[i] == 'R')
            r++;
        else
            b++;
    }

    if(r > b)
        cout << "Yes" << endl;
    else
        cout << "No" << endl;

    return 0;
}