Problem:
Score : 200 points

Problem Statement

An integer N is a multiple of 9 if and only if the sum of the digits in the decimal representation of N is a multiple of 9.

Determine whether N is a multiple of 9.

Constraints

0 \leq N < 10^{200000}

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a multiple of 9, print Yes; otherwise, print No.

Sample Input 1

123456789

Sample Output 1

Yes

The sum of these digits is 1+2+3+4+5+6+7+8+9=45, which is a multiple of 9, so 123456789 is a multiple of 9.

Sample Input 2

0

Sample Output 2

Yes

Sample Input 3

31415926535897932384626433832795028841971693993751058209749445923078164062862089986280

Sample Output 3

No

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <stdio.h>
#include <vector>
#include <algorithm>
#include <string>
#include <iomanip>
#define _USE_MATH_DEFINES
#include <math.h>
using namespace std;
#define rep(i,n) for(i=0;i<n;i++)
#define repl(k,n) for(k=0;k<n;++k)

int main() {
	long long int N;
	cin >> N;
	int i;
	int all=0;
	for (i = 0; i < 200000; i++) {
		all = all+N % 10;
		N = N / 10;
	}
	if (all % 9 == 0) {
		cout << "Yes";
	}
	else {
		cout << "No";
	}
	return 0;
}