Problem:
Score : 500 points

Problem Statement

A robot is put at the origin in a two-dimensional plane.
Initially, the robot is facing in the positive x-axis direction.

This robot will be given an instruction sequence s.
s consists of the following two kinds of letters, and will be executed in order from front to back.

F : Move in the current direction by distance 1.

T : Turn 90 degrees, either clockwise or counterclockwise.

The objective of the robot is to be at coordinates (x, y) after all the instructions are executed.
Determine whether this objective is achievable.

Constraints

s consists of F and T.

1 \leq |s| \leq 8 000

x and y are integers.

|x|, |y| \leq |s|

Input

Input is given from Standard Input in the following format:

s
x y

Output

If the objective is achievable, print Yes; if it is not, print No.

Sample Input 1

FTFFTFFF
4 2

Sample Output 1

Yes

The objective can be achieved by, for example, turning counterclockwise in the first T and turning clockwise in the second T.

Sample Input 2

FTFFTFFF
-2 -2

Sample Output 2

Yes

The objective can be achieved by, for example, turning clockwise in the first T and turning clockwise in the second T.

Sample Input 3

FF
1 0

Sample Output 3

No

Sample Input 4

TF
1 0

Sample Output 4

No

Sample Input 5

FFTTFF
0 0

Sample Output 5

Yes

The objective can be achieved by, for example, turning counterclockwise in the first T and turning counterclockwise in the second T.

Sample Input 6

TTTT
1 0

Sample Output 6

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Runtime Error)

/*****************
 *   I<3   C++   *
 *  IWANT ANYAC  *
 * ILOVEPROGRAM! *
 *IT'SINTERESTING*
 * ILOVEPROGRAM! *
 *  INCONTESTS   *
 *   GETSCORE    *
 *    ACCODE     *
 *     LETS      *
 *      GO       *
 *Written by:    *
 *    charlieyan *
 *****************/
#include <assert.h>
#include <ctype.h>
#include <errno.h>
#include <float.h>
#include <fstream>
#include <iomanip>
#include <iostream>
#include <limits>
#include <locale>
#include <math.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>
#include <wchar.h>
#include <wctype.h>
#include <algorithm>
#include <bitset>
#include <cctype>
#include <cerrno>
#include <clocale>
#include <cmath>
#include <complex>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <ctime>
#include <deque>
#include <exception>
#include <fstream>
#include <functional>
#include <limits>
#include <map>
#include <iomanip>
#include <ios>
#include <iosfwd>
#include <istream>
#include <ostream>
#include <queue>
#include <set>
#include <sstream>
#include <stack>
#include <stdexcept>
#include <streambuf>
#include <string>
#include <utility>
#include <vector>
#include <cwchar>
#include <cwctype>
#include <complex.h>
#include <fenv.h>
#include <inttypes.h>
#include <stdbool.h>
#include <stdint.h>
#include <tgmath.h>
#include <numeric>
#include <list>
#define LL long long
#define pb push_back
#define pob pop_back
#define mp make_pair
#define FILL(a,v) memset((void*)a,v,sizeof(a))
#define FILL0(a) FILL(a,0)
#define FILL1(a) FILL(a,-1)
#define FILLBIG(a) FILL(a,0x7f)
#define ALL(a) (a).begin(),(a).end()
#define Inf ((int)0x7f7f7f7f)
#define INF ((long long)0x7f7f7f7f7f7f7f7f)
#define Mod 1000000007
#define foreach(it,x) for(__typeof(x.begin()) it=x.begin();it!=x.end();it++)
#define FOR(i,x) for(int i=0;i<x;i++)
#define RFOR(i,x) for(int i=x-1;i>=0;i--)
#define FFOR(i,a,b) for(int i=a;i<b;i++)
#define FRFOR(i,a,b) for(int i=a-1;i>=b;i--)
#define SZ(a) ((int)(a).size())
#define FI first
#define SE second
#define OVER(a) return puts(a),0
#define fastio ios::sync_with_stdio(0)
#define filei(f) freopen(f,"r",stdin)
#define fileo(f) freopen(f,"w",stdout)
#define eprintf(...) fprintf(stderr,__VA_ARGS__)
#define MASK(a) (1<<(a))
#define MASKX(x,a) ((x)<<(a))
#define BIT(a,b) ((a>>b)&1)
#define cddx(a) priority_queue<a >
#define cxdd(a) priority_queue<a,vector<a >,greater<a > >
#define deval(a) {cerr<<#a<<" = "<<a<<endl;}
#define dearr(be,en) {cerr<<#be;cerr<<" = {";for(auto i=be;i!=en;i++)cerr<<' '<<*i;cerr<<" }\n";}
#define reg register
#define prtime eprintf("\n\nTime used: %dms",clock());
using namespace std;
typedef pair<int,int> pii;
typedef unsigned long long UINT;
typedef unsigned int uint;
typedef long long INT;
typedef long double ldouble;
typedef pair<INT,INT> PII;
typedef stringstream sst;
typedef istringstream iss;
typedef vector<int> vint;
typedef vector<INT> VINT;
typedef vector<pii> vpii;
typedef vector<PII> VPII;
typedef priority_queue<int> pqi;
typedef priority_queue<INT> PQI;
typedef priority_queue<pii> pqp;
typedef priority_queue<PII> PQP;
typedef priority_queue<int,vint,greater<int> > xqi;
typedef priority_queue<INT,VINT,greater<INT> > XQI;
typedef priority_queue<pii,vpii,greater<pii> > xqp;
typedef priority_queue<PII,VPII,greater<PII> > XQP;

int dpz[4007][8007],dpf[4007][8007];
inline int& dp(int a,int b)
{
	if(b>=0)return dpz[a][b];
	else return dpf[a][-b];
}
string s;
int x,y;
vector<int> jilu[2];

int main()
{
	cin>>s>>x>>y;
	int ii=0,mode=0;
	while(s[ii]!='T')x--,ii++;
	for(;ii<SZ(s);ii++)
	{
		if(s[ii]=='T')
		{
			mode=1-mode;
			jilu[mode].push_back(0);
		}
		else jilu[mode][SZ(jilu[mode])-1]++;
	}
	dp(0,0)=1;
	for(int i=1;i<=SZ(jilu[0]);i++)
		for(int j=-8006;j<=8006;j++)
		{
			if(j-jilu[0][i-1]>=-8006)dp(i,j)|=dp(i-1,j-jilu[0][i-1]);
			if(j+jilu[0][i-1]<=8006)dp(i,j)|=dp(i-1,j+jilu[0][i-1]);
		}
	if(!dp(SZ(jilu[0]),x))OVER("No");
	for(int i=1;i<=SZ(jilu[0]);i++)
		for(int j=-8006;j<=8006;j++)
			dp(i,j)=0;
	dp(0,0)=1;
	for(int i=1;i<=SZ(jilu[1]);i++)
		for(int j=-8006;j<=8006;j++)
		{
			if(j-jilu[1][i-1]>=-8006)dp(i,j)|=dp(i-1,j-jilu[1][i-1]);
			if(j+jilu[1][i-1]<=8006)dp(i,j)|=dp(i-1,j+jilu[1][i-1]);
		}
	if(!dp(SZ(jilu[1]),y))OVER("No");
	OVER("Yes");
}