Problem:
Score : 500 points

Problem Statement

There are N points on the 2D plane, i-th of which is located on (x_i, y_i).
There can be multiple points that share the same coordinate.
What is the maximum possible Manhattan distance between two distinct points?

Here, the Manhattan distance between two points (x_i, y_i) and (x_j, y_j) is defined by |x_i-x_j| + |y_i-y_j|.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq x_i,y_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
x_1 y_1
x_2 y_2
:
x_N y_N

Output

Print the answer.

Sample Input 1

3
1 1
2 4
3 2

Sample Output 1

4

The Manhattan distance between the first point and the second point is |1-2|+|1-4|=4, which is maximum possible.

Sample Input 2

2
1 1
1 1

Sample Output 2

0

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
#define ll long long
#define pb push_back
#define mp make_pair
#define mt make_tuple
#define min_3(a,b,c) min(a,min(b,c))
#define max_3(a,b,c) max(a,max(b,c))
#define nout(ans) cout << (ans) << "\n"
#define sout(ans) cout << (ans) << " "
using namespace std;

const double pi = 3.14159265359;
const ll INF = 1e12;
const ll MOD = 1e9 + 7;
const ll N = 2e5+5; 
/*
Decimal Places: cout << fixed << setprecision(n) << ans << endl
*/

bool compare(const pair<int, int>&i, const pair<int, int>&j)
{
    return i.second < j.second;
}

ll raise(ll a, ll b) {
    ll res = 1;
    while (b > 0) {
        if (b & 1)
            res = res * a;
        a = a * a;
        b >>= 1;
    }
    return res;
}


ll n, x[N], y[N];

void solve()
{
    cin >> n;
    for (int i=0; i<n; ++i) cin >> x[i] >> y[i];
    ll mi1=INF, ma1=-1, mi2=INF, ma2=-1;
	for (int i=0; i<n; ++i) {
		mi1 = min(mi1, x[i]+y[i]);
		ma1 = max(ma1, x[i]+y[i]);
		mi2 = min(mi2, x[i]-y[i]);
		ma2 = max(ma2, x[i]-y[i]);
	}
	nout(max((ma1-mi1),(ma2-mi2)));
}

int main()
{
    ios_base::sync_with_stdio(false);
    cin.tie(NULL); cout.tie(NULL);
    int t = 1;
    //cin >> t;
    for (int i=1; i<=t; i++)
    {
        solve();
    }
    return 0;
}