Problem:
Score : 100 points

Problem Statement

There is a directed graph G with N vertices and M edges.
The vertices are numbered 1, 2, \ldots, N, and for each i (1 \leq i \leq M), the i-th directed edge goes from Vertex x_i to y_i.
G does not contain directed cycles.

Find the length of the longest directed path in G.
Here, the length of a directed path is the number of edges in it.

Constraints

All values in input are integers.

2 \leq N \leq 10^5

1 \leq M \leq 10^5

1 \leq x_i, y_i \leq N

All pairs (x_i, y_i) are distinct.

G does not contain directed cycles.

Input

Input is given from Standard Input in the following format:

N M
x_1 y_1
x_2 y_2
:
x_M y_M

Output

Print the length of the longest directed path in G.

Sample Input 1

4 5
1 2
1 3
3 2
2 4
3 4

Sample Output 1

3

The red directed path in the following figure is the longest:

Sample Input 2

6 3
2 3
4 5
5 6

Sample Output 2

2

The red directed path in the following figure is the longest:

Sample Input 3

5 8
5 3
2 3
2 4
5 2
5 1
1 4
4 3
1 3

Sample Output 3

3

The red directed path in the following figure is one of the longest:

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#define __mode_debug__
/*   ξ
     ll
   ＿ll＿
 ／  ∞  ＼
│*  Ａ  *│
│*  Ｃ  *│
│*  祈  *│
│*  願  *│
│*      *│
 ￣￣￣￣￣    */
//C++14 (GCC 5.4.1)
#include <bits/stdc++.h>
using namespace std;
#ifdef __mode_debug__
    #define DBG
#else
    #define DBG if(false)
#endif

#define LLINF (1LL<<60)
using ll = long long;
#define mod (1e9+7)

#define whole(a) (a).begin(),(a).end()
#define rwhole(a) (a).rbegin(),(a).rend()

#define repd(i,a,b) for (int i=(a);i<(b);i++)
#define rep(i,n) repd(i,0,n)
#define rrepd(i,a,b) for(int i=(a);i>=(b);i--)
#define each(itr,ds) for(auto itr=(ds).begin();itr!=(ds).end();itr++)

template<typename T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
template<typename T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }

template < typename T > inline string toString( const T &a ) { ostringstream oss; oss << a; return oss.str(); }

//DUMP
//  ostream vector<T> , vector<vector<T>> , set<T> ,queue<T> , priority_queue<T> , pair<T,U> , map<T,U>
template<class T> ostream& operator<<(ostream&os,vector<T>&vec){os<<"{ ";rep(i,vec.size()) os<<((i==0)?"":", ")<<i<<":"<<vec[i];os<<" }";return os;}
template<class T> ostream& operator<<(ostream&os,vector<vector<T>>&vec){os<<"{"<<endl;rep(i,vec.size())os<<"\t   "<<i<<":"<<vec[i]<<((i==vec.size()-1)? "":",")<<endl;os<<"\t }";return os;}
template<class T> ostream& operator<<(ostream&os,set<T>&p){os<<"{ ";each(itr,p)  os<<((itr==p.begin())?"":", ")<<*itr;os<<" }";return os;}
template<class T> ostream& operator<<(ostream&os,queue<T>&p){queue<T> q(p);os<<"[< "<<(q.empty()?" <]":"");while(!q.empty()){os<<q.front();q.pop();os<< (q.empty() ? " <]" : ", ");}return os;}
template<class T> ostream& operator<<(ostream&os,priority_queue<T>&p){priority_queue<T> q(p);os<<"[< "<<(q.empty()?" <]":"");while(!q.empty()){os<<q.top();q.pop();os<< (q.empty() ? " <]" : ", ");}return os;}
template<class T,class U> ostream& operator<<(ostream&os,pair<T,U>&p){os<<"("<<p.first<<","<<p.second<<")";return os;}
template<class T,class U> ostream& operator<<(ostream&os,map<T,U>&p){os<<"{ ";each(itr,p)os<<((itr==p.begin())?"":", ")<<itr->first<<":"<<itr->second;os<<" }";return os;}
void dump_f(string &nm,char t){cerr<<endl;}
template<class T,class... Ts> void dump_f(string &nm,char t,T &&x,Ts&&... ts){int l=nm.find_first_of(',');string name(nm,0,l),nx(nm,l+1,-1);if(t=='\n') cerr<<"  "<<name<<"\t: "<<x<<t;else cerr << name<<": "<<x<<","<<t;dump_f(nx,t,forward<Ts>(ts)...);}
template<class... Ts> void dump_m(int &&ln,string &&nm,char t,Ts&&... ts){cerr<<"[ln: "<<ln<<"]"<<t;dump_f(nm,t,forward<Ts>(ts)...);}
#define dump(...) DBG dump_m(__LINE__,#__VA_ARGS__,'\n',__VA_ARGS__)
#define dl(...) DBG dump_m(__LINE__,#__VA_ARGS__,'\t',__VA_ARGS__)

#define lower_bound_idx(V,c) distance(V.begin(),lower_bound(whole(V),c))

int main() {
    ios::sync_with_stdio(false);//stdout<=>cout
    cin.tie(nullptr);//cin<=>cout

    int N,M,from,to;
    cin >>N>>M;
    vector<vector<int>> D(N);
    vector<int> in(N);
    rep(i,M){
        cin >> from>>to;
        from--;to--;
        D[from].push_back(to);
        in[to]++;
    }
    queue<int> inzero;
    vector<int> dp(N,0);
    rep(i,N)if(in[i]==0)inzero.push(i);
    while(!inzero.empty()){
        int from=inzero.front();inzero.pop();
        for(auto to : D[from]){
            in[to]--;
            if(in[to]==0){
                inzero.push(to);
                chmax(dp[to],dp[from]+1);
            }
        }
    }
    int ans=0;
    rep(i,N)chmax(ans,dp[i]);

    //-----------------------------------

    cout << ans <<endl;

    return (0);
}