Problem:
Score : 400 points

Problem Statement

Give a pair of integers (A, B) such that A^5-B^5 = X.
It is guaranteed that there exists such a pair for the given integer X.

Constraints

1 \leq X \leq 10^9

X is an integer.

There exists a pair of integers (A, B) satisfying the condition in Problem Statement.

Input

Input is given from Standard Input in the following format:

X

Output

Print A and B, with space in between.
If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.

A B

Sample Input 1

33

Sample Output 1

2 -1

For A=2 and B=-1, A^5-B^5 = 33.

Sample Input 2

1

Sample Output 2

0 -1

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#define _ ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);
#define int long long
const int inf = 0x3f3f3f3f3f3f3f3LL;
const int mod = (int)1e9 + 7;
using namespace std;
#if LOCAL
#include "../../tr.h"
#else
#define tr(...)
#define endl '\n'
#endif
template<class T, class T2> void smin(T& a, T2 val) {if (a > val) a = val;}template<class T, class T2> void smax(T& a, T2 val) {if (a < val) a = val;}
const int N = 5*(int)1e5 + 10;

int n, x;

int32_t main(){_
   
   cin >> x;

   for (int a = -5000; a <= 5000; ++a)
   {
      for (int b = -5000; b <= 5000; ++b)
      {
         int pro1 = a * a * a * a * a;   
         int pro2 = b * b * b * b * b;
         if (pro1 - pro2 == x){
               cout<<a<<" "<<b;
               exit(0);
            }   
      }
   }
   

   return 0;
}