Problem:
Score : 100 points

Problem Statement

Takahashi is meeting up with Aoki.

They have planned to meet at a place that is D meters away from Takahashi's house in T minutes from now.

Takahashi will leave his house now and go straight to the place at a speed of S meters per minute.

Will he arrive in time?

Constraints

1 \leq D \leq 10000

1 \leq T \leq 10000

1 \leq S \leq 10000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

D T S

Output

If Takahashi will reach the place in time, print Yes; otherwise, print No.

Sample Input 1

1000 15 80

Sample Output 1

Yes

It takes 12.5 minutes to go 1000 meters to the place at a speed of 80 meters per minute. They have planned to meet in 15 minutes so he will arrive in time.

Sample Input 2

2000 20 100

Sample Output 2

Yes

It takes 20 minutes to go 2000 meters to the place at a speed of 100 meters per minute. They have planned to meet in 20 minutes so he will arrive just on time.

Sample Input 3

10000 1 1

Sample Output 3

No

He will be late.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

// #pragma comment(linker, "/stack:200000000")
// #pragma GCC target ("avx2")
// #pragma GCC optimization ("O3")
// #pragma GCC optimization ("unroll-loops")
// #pragma GCC optimize("Ofast")
// #pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")

#include "bits/stdc++.h"

#define fastio  	ios_base::sync_with_stdio(NULL); cin.tie(NULL); cout.tie(NULL);
#define TC      	int t; cin >> t; for(int tc = 1; tc <= t; tc++)
#define read    	freopen("input.txt", "r", stdin);
#define write   	freopen("output.txt", "w", stdout);
#define nl      	'\n'
#define pii			pair<int, int>
#define ll 			long long
#define pb			push_back
#define eb			emplace_back
#define all(v)		v.begin(), v.end()
#define rall(v)		v.rbegin(), v.rend()
#define d(x)		cerr << #x << " = " << x << nl


using namespace std;


int main() {
	/*
	#ifndef ONLINE_JUDGE
        freopen("input.txt", "r", stdin);
    #endif
    */
		int d, t, s;
		cin >> d >> t >> s;
		if(t*s >= d) cout << "Yes";
		else cout << "No";
	return 0;
}