Problem:
Score : 200 points

Problem Statement

A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.

How many times will the ball make a bounce where the coordinate is at most X?

Constraints

1 \leq N \leq 100

1 \leq L_i \leq 100

1 \leq X \leq 10000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N X
L_1 L_2 ... L_{N-1} L_N

Output

Print the number of times the ball will make a bounce where the coordinate is at most X.

Sample Input 1

3 6
3 4 5

Sample Output 1

2

The ball will make a bounce at the coordinates 0, 3, 7 and 12, among which two are less than or equal to 6.

Sample Input 2

4 9
3 3 3 3

Sample Output 2

4

The ball will make a bounce at the coordinates 0, 3, 6, 9 and 12, among which four are less than or equal to 9.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <cstdio>
#include <string>
#include <cstdlib>
#include <vector>
#include <algorithm>
#include <functional>
#include <iomanip>
#include <stdlib.h>
#include <string.h>
#include <cmath>
#include <map>
#include <queue>
#include <deque>
#include <stack>
#include <set>
const long long MOD = 1e9 + 7;
using namespace std;
typedef long long ll;

map<ll, int> mp;
int main()
{
	cin.tie(0);
	ios::sync_with_stdio(false);
	cout << setprecision(20);
	int n, x;
	cin >> n >> x;
	vector<int> a(n);
	int sum = 0;
	int counter = 1;
	for (int i = 0; i < n; i++) {
		cin >> a[i];
		sum += a[i];
		if (sum > x) break;
		else counter++;
	}
	cout << counter << endl;
	return 0;
}