Problem:
Score : 200 points

Problem Statement

Given are integers a,b,c and d.
If x and y are integers and a \leq x \leq b and c\leq y \leq d hold, what is the maximum possible value of x \times y?

Constraints

-10^9 \leq a \leq b \leq 10^9

-10^9 \leq c \leq d \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

a b c d

Output

Print the answer.

Sample Input 1

1 2 1 1

Sample Output 1

2

If x = 1 and y = 1 then x \times y = 1.
If x = 2 and y = 1 then x \times y = 2.
Therefore, the answer is 2.

Sample Input 2

3 5 -4 -2

Sample Output 2

-6

The answer can be negative.

Sample Input 3

-1000000000 0 -1000000000 0

Sample Output 3

1000000000000000000

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;

inline long long read(){
    long long s = 0, w = 1;
    char ch = getchar();
    while (ch < '0' || ch > '9'){
        if (ch == '-') w = -1;
        ch = getchar();
    }
    while (ch >= '0' && ch <= '9'){
        s = s * 10 + ch - '0';
        ch = getchar();
    }
    return s * w;
}

long long a, b, c, d, ans;

int main(){
    a = read(), b = read(), c = read(), d = read();
    ans = -0x7f7f7f7f;
    ans = max(ans, a * c);
    ans = max(ans, a * d);
    ans = max(ans, b * c);
    ans = max(ans, b * d);
    printf("%lld\n", ans);
    return 0;
}