Problem:
Score : 500 points

Problem Statement

Takahashi has decided to work on K days of his choice from the N days starting with tomorrow.

You are given an integer C and a string S. Takahashi will choose his workdays as follows:

After working for a day, he will refrain from working on the subsequent C days.

If the i-th character of S is x, he will not work on Day i, where Day 1 is tomorrow, Day 2 is the day after tomorrow, and so on.

Find all days on which Takahashi is bound to work.

Constraints

1 \leq N \leq 2 \times 10^5

1 \leq K \leq N

0 \leq C \leq N

The length of S is N.

Each character of S is o or x.

Takahashi can choose his workdays so that the conditions in Problem Statement are satisfied.

Input

Input is given from Standard Input in the following format:

N K C
S

Output

Print all days on which Takahashi is bound to work in ascending order, one per line.

Sample Input 1

11 3 2
ooxxxoxxxoo

Sample Output 1

6

Takahashi is going to work on 3 days out of the 11 days. After working for a day, he will refrain from working on the subsequent 2 days.

There are four possible choices for his workdays: Day 1,6,10, Day 1,6,11, Day 2,6,10, and Day 2,6,11.

Thus, he is bound to work on Day 6.

Sample Input 2

5 2 3
ooxoo

Sample Output 2

1
5

There is only one possible choice for his workdays: Day 1,5.

Sample Input 3

5 1 0
ooooo

Sample Output 3

There may be no days on which he is bound to work.

Sample Input 4

16 4 3
ooxxoxoxxxoxoxxo

Sample Output 4

11
16

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <iomanip>
#include <algorithm>
#include <string>
#include <vector>
#include <queue>
#include <stack>
#include <map>
#include <unordered_map>
#include <set>

typedef long long ll;
typedef long double ld;
#define FASTIO ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);
#define PRECISION std::cout << std::fixed << std::setprecision(20);
  
using namespace std;
 
const ll inf = 1e18;
const ll N = 3e5;
const ll bits = 20;
const ld pi = 3.14159265358979323846;
const ll mod = 1e9+7;
const ll p = 29;


int main(){

    FASTIO;
    PRECISION; 

    int n,k,c;
    cin>>n>>k>>c;
    string s;
    cin>>s;
    vector<int>l(k),r(k);
    int i = 0;
    int ptr = 0;
    while(i<n){
        while(i<n && s[i]=='x')i++;
        l[ptr] = i;
        i+=c+1;
        ptr++;
        if(ptr==k) break;
    }
    i = n-1;
    ptr = k-1;
    while(i>=0){
        while(i && s[i]=='x')i--;
        r[ptr] = i;
        i-=c+1;
        ptr--;
        if(ptr==-1) break;
    }

    for(int i=0;i<k;i++){
        if(l[i]==r[i]) cout<<l[i]+1<<"\n";
    }


}