Problem:
Score : 300 points

Problem Statement

You are given an integer sequence of length n, a_1, ..., a_n.
Let us consider performing the following n operations on an empty sequence b.

The i-th operation is as follows:

Append a_i to the end of b.

Reverse the order of the elements in b.

Find the sequence b obtained after these n operations.

Constraints

1 \leq n \leq 2\times 10^5

0 \leq a_i \leq 10^9

n and a_i are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print n integers in a line with spaces in between.
The i-th integer should be b_i.

Sample Input 1

4
1 2 3 4

Sample Output 1

4 2 1 3

After step 1 of the first operation, b becomes: 1.

After step 2 of the first operation, b becomes: 1.

After step 1 of the second operation, b becomes: 1, 2.

After step 2 of the second operation, b becomes: 2, 1.

After step 1 of the third operation, b becomes: 2, 1, 3.

After step 2 of the third operation, b becomes: 3, 1, 2.

After step 1 of the fourth operation, b becomes: 3, 1, 2, 4.

After step 2 of the fourth operation, b becomes: 4, 2, 1, 3.

Thus, the answer is 4 2 1 3.

Sample Input 2

3
1 2 3

Sample Output 2

3 1 2

As shown above in Sample Output 1, b becomes 3, 1, 2 after step 2 of the third operation. Thus, the answer is 3 1 2.

Sample Input 3

1
1000000000

Sample Output 3

1000000000

Sample Input 4

6
0 6 7 6 7 0

Sample Output 4

0 6 6 0 7 7

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;
 
#define cinsc ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(0);
#define all(cont) cont.begin(), cont.end()
#define rall(cont) cont.end(), cont.begin()
#define FOR(i,k,n)  for(int64 i=k;i<(int64)n;i++)
#define FOREACH(it, l) for (auto it = l.begin(); it != l.end(); it++)
#define FOREACHr(it, l) for (auto it = l.rbegin(); it != l.rend(); it++)
#define IN(A, B, C) assert( B <= A && A <= C)
#define MP make_pair
#define PB push_back
#define INF (int)1e9
#define EPS 1e-9
#define PI 3.1415926535897932384626433832795
#define MOD 1000000007
#define read(type) readInt<type>()
#define SQ(x) ((x)*(x))
const double pi=acos(-1.0);
typedef pair<int, int> PII;
typedef vector<int> VI;
typedef vector<string> VS;
typedef vector<PII> VII;
typedef vector<VI> VVI;
typedef map<int,int> MPII;
typedef set<int> SETI;
typedef multiset<int> MSETI;
typedef long int int32;
typedef unsigned long int uint32;
typedef long long int int64;
typedef unsigned long long int  uint64;
 
//ONLINE_JUDGE   LOCAL
 
int64 powr(int64 x,int64 y,int64 p)  
{  
    int res = 1;    
    x = x % p; 
    if (x == 0) return 0;
    while (y > 0){   
        if (y & 1)  
            res = (res*x) % p;   
        y = y>>1; 
        x = (x*x) % p;  
    }  
    return res;  
} 
 
void  in_o(){
#ifndef LOCAL
	freopen("input.txt","r",stdin);
	freopen("output.txt","w",stdout);
#endif
	cinsc;
}


int main(){
//	in_o();
	int n;
	cin>>n;
	deque <int> q;

	FOR(i,0,n){
		int x;
		cin>>x;
		if(i%2)
			q.push_front(x);
		else
			q.push_back(x);
	}
	if(!(n%2))
		FOREACH(it,q){
			cout<<*it<<" ";
		}
	else
		FOREACHr(it,q){
			cout<<*it<<" ";
		}
	return 0;
}