Problem:
Score : 200 points

Problem Statement

Takahashi went to an all-you-can-eat buffet with N kinds of dishes and ate all of them (Dish 1, Dish 2, \ldots, Dish N) once.

The i-th dish (1 \leq i \leq N) he ate was Dish A_i.

When he eats Dish i (1 \leq i \leq N), he gains B_i satisfaction points.

Additionally, when he eats Dish i+1 just after eating Dish i (1 \leq i \leq N - 1), he gains C_i more satisfaction points.

Find the sum of the satisfaction points he gained.

Constraints

All values in input are integers.

2 \leq N \leq 20

1 \leq A_i \leq N

A_1, A_2, ..., A_N are all different.

1 \leq B_i \leq 50

1 \leq C_i \leq 50

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N
B_1 B_2 ... B_N
C_1 C_2 ... C_{N-1}

Output

Print the sum of the satisfaction points Takahashi gained, as an integer.

Sample Input 1

3
3 1 2
2 5 4
3 6

Sample Output 1

14

Takahashi gained 14 satisfaction points in total, as follows:

First, he ate Dish 3 and gained 4 satisfaction points.

Next, he ate Dish 1 and gained 2 satisfaction points.

Lastly, he ate Dish 2 and gained 5 + 3 = 8 satisfaction points.

Sample Input 2

4
2 3 4 1
13 5 8 24
45 9 15

Sample Output 2

74

Sample Input 3

2
1 2
50 50
50

Sample Output 3

150

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)


// Problem : B - Buffet
// Contest : AtCoder Beginner Contest 140
// URL : https://atcoder.jp/contests/abc140/tasks/abc140_b
// Memory Limit : 1024,000000 MB 
// Time Limit : 2000,000000 milisec 
// Powered by CP Editor (https://github.com/coder3101/cp-editor2)

#include <algorithm>
#include <cmath>
#include <iostream>
#include <iterator>
#include <map>
#include <set>
#include <vector>

using namespace std;

int main() {
#ifdef _DEBUG
  freopen("input.txt", "r", stdin);
  freopen("output.txt", "w", stdout);
#endif

  ios_base::sync_with_stdio(false);
  cin.tie(0);

  cout.precision(16);
  cout << fixed;
  
  int n;
  cin >> n;
  
  vector<int> a(n);
  for (auto&& i : a) {
    cin >> i;
  }
  
  vector<int> b(n);
  for (auto&& i : b) {
    cin >> i;
  }
  
  vector<int> c(n - 1);
  for (auto&& i : c) {
    cin >> i;
  }
  
  bool first = true;
  
  int ans = 0;
  
  for (auto&& i : a) {
    ans += b[i - 1];
  
    if (first || i == 1) {
      first = false;
      
      continue;
    }
    
    ans += c[i - 2];
  }
  
  cout << ans;
}