Problem:
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Longest Common Subsequence

For given two sequences $X$ and $Y$, a sequence $Z$ is a common subsequence of $X$ and $Y$ if $Z$ is a subsequence of both $X$ and $Y$. For example, if $X = \{a,b,c,b,d,a,b\}$ and $Y = \{b,d,c,a,b,a\}$, the sequence $\{b,c,a\}$ is a common subsequence of both $X$ and $Y$. On the other hand, the sequence $\{b,c,a\}$ is not a longest common subsequence (LCS) of $X$ and $Y$, since it has length 3 and the sequence $\{b,c,b,a\}$, which is also common to both $X$ and $Y$, has length 4. The sequence $\{b,c,b,a\}$ is an LCS of $X$ and $Y$, since there is no common subsequence of length 5 or greater.

Write a program which finds the length of LCS of given two sequences $X$ and $Y$. The sequence consists of alphabetical characters.

Input

The input consists of multiple datasets. In the first line, an integer $q$ which is the number of datasets is given. In the following $2 \times q$ lines, each dataset which consists of the two sequences $X$ and $Y$ are given.

Output

For each dataset, print the length of LCS of $X$ and $Y$ in a line.

Constraints

$1 \leq q \leq 150$

$1 \leq$ length of $X$ and $Y$ $\leq 1,000$

$q \leq 20$ if the dataset includes a sequence whose length is more than 100

Sample Input 1

3
abcbdab
bdcaba
abc
abc
abc
bc

Sample Output 1

4
3
2

Reference

Introduction to Algorithms, Thomas H. Cormen, Charles E. Leiserson, Ronald L. Rivest, and Clifford Stein. The MIT Press.

Solution in C++14 (judge verdict: Accepted)

#include <iostream>
#include <sstream>
#include <fstream>
#include <string>
#include <vector>
#include <deque>
#include <queue>
#include <stack>
#include <set>
#include <map>
#include <unordered_map>
#include <algorithm>
#include <functional>
#include <utility>
#include <bitset>
#include <cmath>
#include <cstdlib>
#include <ctime>
#include <cstdio>
#include <cstring>
using namespace std;

typedef long long ll;
#define rep(i, a, b) for (ll i=(a); i<(b); i++)
#define all(obj) (obj).begin(), (obj).end()
#define fi first
#define sc second
#define pb push_back
#define str to_string
const ll INF = 1e18;
const ll MOD = 1e9 + 7;
void chmax(ll &a, ll b) { a = max(a, b); }
void chmin(ll &a, ll b) { a = min(a, b); }

ll dp[1010][1010];

ll LCS(string a, string b) {
    int N = a.size();
    int M = b.size();
    memset(dp, 0, sizeof(dp));

    rep(i, 0, N+1) rep(j, 0, M+1) {
        if (i < N) {
            chmax(dp[i+1][j], dp[i][j]);
        }
        if (j < M) {
            chmax(dp[i][j+1], dp[i][j]);
        }
        if (i < N && j < M && a[i] == b[j]) {
            chmax(dp[i+1][j+1], dp[i][j]+1);
        }
    }
    return dp[N][M];
}

int main() {
    int Q;
    string a, b;
    cin >> Q;
    rep(i, 0, Q) {
        cin >> a;
        cin >> b;
        cout << LCS(a, b) << endl;
    }
    return 0;
}