Problem:
Score : 100 points

Problem Statement

There is a set A = \{ a_1, a_2, \ldots, a_N \} consisting of N positive integers.
Taro and Jiro will play the following game against each other.

Initially, we have a pile consisting of K stones.
The two players perform the following operation alternately, starting from Taro:

Choose an element x in A, and remove exactly x stones from the pile.

A player loses when he becomes unable to play.
Assuming that both players play optimally, determine the winner.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq K \leq 10^5

1 \leq a_1 < a_2 < \cdots < a_N \leq K

Input

Input is given from Standard Input in the following format:

N K
a_1 a_2 \ldots a_N

Output

If Taro will win, print First; if Jiro will win, print Second.

Sample Input 1

2 4
2 3

Sample Output 1

First

If Taro removes three stones, Jiro cannot make a move.
Thus, Taro wins.

Sample Input 2

2 5
2 3

Sample Output 2

Second

Whatever Taro does in his operation, Jiro wins, as follows:

If Taro removes two stones, Jiro can remove three stones to make Taro unable to make a move.

If Taro removes three stones, Jiro can remove two stones to make Taro unable to make a move.

Sample Input 3

2 7
2 3

Sample Output 3

First

Taro should remove two stones. Then, whatever Jiro does in his operation, Taro wins, as follows:

If Jiro removes two stones, Taro can remove three stones to make Jiro unable to make a move.

If Jiro removes three stones, Taro can remove two stones to make Jiro unable to make a move.

Sample Input 4

3 20
1 2 3

Sample Output 4

Second

Sample Input 5

3 21
1 2 3

Sample Output 5

First

Sample Input 6

1 100000
1

Sample Output 6

Second

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#define boost ios_base::sync_with_stdio(false), cin.tie(NULL);

using namespace std;
const int N = 1e5 + 44;
const int X[] = {1,0,-1,0,1,-1,1,-1};
const int Y[] = {0,1,0,-1,1,1,-1,-1};
const int mod = 1e9 + 7;
const long long INF = 1e18;
const int inf = 1e9;

int dp[N];

int a[111];

int main () {
	boost;
	int n, k;
	cin >> n >> k;
	for (int i = 0 ; i < n ; ++ i) {
		cin >> a[i];
	}
	dp[0] = 0;
	for (int i = 1 ; i <= k ; ++ i) {
		for (int j = 0 ; j < n ; ++ j) {
			if (i - a[j] >= 0 && !dp[i - a[j]])
				dp[i] = 1;
		}
	}
	cout << (dp[k] ? "First" : "Second");
}