Problem:
Score : 300 points

Problem Statement

Takahashi is a teacher responsible for a class of N students.

The students are given distinct student numbers from 1 to N.

Today, all the students entered the classroom at different times.

According to Takahashi's record, there were A_i students in the classroom when student number i entered the classroom (including student number i).

From these records, reconstruct the order in which the students entered the classroom.

Constraints

1 \le N \le 10^5

1 \le A_i \le N

A_i \neq A_j (i \neq j)

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 \ldots A_N

Output

Print the student numbers of the students in the order the students entered the classroom.

Sample Input 1

3
2 3 1

Sample Output 1

3 1 2

First, student number 3 entered the classroom.

Then, student number 1 entered the classroom.

Finally, student number 2 entered the classroom.

Sample Input 2

5
1 2 3 4 5

Sample Output 2

1 2 3 4 5

Sample Input 3

8
8 2 7 3 4 5 6 1

Sample Output 3

8 2 4 5 6 7 3 1

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <iomanip>
#include <cassert>
#include <cmath>
#include <cstdio>
#include <cstring>
#include <cstdlib>
#include <map>
#include<unordered_map>
#include <set>
#include <queue>
#include <stack>
#include <vector>
#include<bitset>
#include<deque>
#include<string>
#include<list>
#include<iterator>
#include<sstream>
#include <algorithm>
#define lli long long int
#define lower(a) transform(a.begin(),a.end(),a.begin(),::tolower);

using namespace std;

const int N = 3e5 + 500;
const long long mod = 1e9 + 7;
const long long cmod = 998244353 ;
const long long inf = 1LL << 57;
const int M = 1e6 + 500;
const lli ths = 1LL << 40;

vector<pair<lli, lli> > v;

void solve()
{
    lli n;
    cin>>n;
    lli a[n];
    for(int i = 0; i < n; i ++)
    {
        cin>>a[i];
        v.push_back({a[i], i + 1});
    }
    sort(v.begin(), v.end());
    for(auto it : v){
        cout<<it.second<<' ';
    }
    cout<<endl;
    return ;
}
/*
7
6 7 4 1 2 11 6
5
1 2 10 4 5
*/

int main()
{
    ios_base::sync_with_stdio(false);
    cin.tie(0);
    cout.tie(0);

    lli t;
    t = 1;
//    cin>>t;
    while(t --)
    {
        solve();
    }
    return 0;
}