Problem:
Score : 200 points

Problem Statement

There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is R, and a blue hat if s_i is B.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

1 \leq N \leq 100

|s| = N

s_i is R or B.

Input

Input is given from Standard Input in the following format:

N
s

Output

If there are more people wearing a red hat than there are people wearing a blue hat, print Yes; otherwise, print No.

Sample Input 1

4
RRBR

Sample Output 1

Yes

There are three people wearing a red hat, and one person wearing a blue hat.

Since there are more people wearing a red hat than people wearing a blue hat, the answer is Yes.

Sample Input 2

4
BRBR

Sample Output 2

No

There are two people wearing a red hat, and two people wearing a blue hat.

Since there are as many people wearing a red hat as people wearing a blue hat, the answer is No.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<bits/stdc++.h>

using namespace std;
#define INF (1<<28)
#define DEKAI 1000000007
#define lp(i,n) for(int i=0;i<n;i++)
#define int long long
int dp[2011][2021];

signed main(){
  int n;
  cin>>n;
  string s;
  cin>>s;
  int cntr=0,cntb=0;
  lp(i,s.size()){
    if(s[i]=='R') cntr++;
    else cntb++;
  }
  if(cntr>cntb) cout<<"Yes"<<endl;
  else cout<<"No"<<endl;
  return 0;
}