Problem:
Score : 300 points

Problem Statement

Sitting in a station waiting room, Joisino is gazing at her train ticket.

The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).

In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.

The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Constraints

0≤A,B,C,D≤9

All input values are integers.

It is guaranteed that there is a solution.

Input

Input is given from Standard Input in the following format:

ABCD

Output

Print the formula you made, including the part =7.

Use the signs + and -.

Do not print a space between a digit and a sign.

Sample Input 1

1222

Sample Output 1

1+2+2+2=7

This is the only valid solution.

Sample Input 2

0290

Sample Output 2

0-2+9+0=7

0 - 2 + 9 - 0 = 7 is also a valid solution.

Sample Input 3

3242

Sample Output 3

3+2+4-2=7

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#define REP(i,n) for(ll i = 0; i < (ll)n; i++)
#define FOR(i,a,b) for (ll i=(a);i<(ll)b; i++)
#define ALL(obj) (obj).begin(),(obj).end()
#define INF 1LL << 60
using namespace std;
typedef long long ll;
typedef double db;
typedef string str;
typedef pair<ll,ll> p;
const long long MOD=1000000007;

// vector<p> cut(M);
// cut[i].second
// cut[i].first;
// REP(i,M){
//     int a,b;cin>>a>>b;
//     cut[i] = make_pair(b,a);//last first の順番
// }
// for(int i=0; i<N;i++){
// }
// sort(cut.begin(),cut.end()); //sort
// char '' str ""
int main(void)
{
    int N[4];
    int aa;
    char res[3];
    cin>>aa;

    for(int i=0;i<=3;i++){
      N[3-i] = aa % 10;
      aa /= 10;
    }

    for(int bit=0; bit<(1<<3); bit++){
      int sum = N[0];

      for(int i=0;i<3;i++){
        if(bit & (1<<i)){
          sum += N[i+1]; res[i]='+';
        }else{
          sum -= N[i+1]; res[i]='-';
        }
      }

      if(sum==7){
        cout<<N[0];
        for(int i=0;i<3;i++){
          cout<<res[i]<<N[i+1];
        }
        cout<<"=7"<<endl;
        return 0;
      }

    }

    return 0;
}