Problem:
Score : 300 points

Problem Statement

You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

1 \leq |S| \leq 2 \times 10^5

|S| = |T|

S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S and T can be made equal, print Yes; otherwise, print No.

Sample Input 1

azzel
apple

Sample Output 1

Yes

azzel can be changed to apple, as follows:

Choose e as c_1 and l as c_2. azzel becomes azzle.

Choose z as c_1 and p as c_2. azzle becomes apple.

Sample Input 2

chokudai
redcoder

Sample Output 2

No

No sequences of operation can change chokudai to redcoder.

Sample Input 3

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <sstream>
#include <string>
#include <vector>
#include <stack>
#include <queue>
#include <set>
#include <map>
#include <numeric>
#include <algorithm>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <cctype>
#include <cmath>
#include <cassert>
#include <cstdarg>
#include <sys/time.h>
#include <fstream>
//#include "cout.h"

using namespace std;

#define SZ(x) ((int)x.size())
#define MSET(x,a) memset(x, a, (int)sizeof(x))
#define PB push_back
#define VI vector < int >
#define PII pair < int, int >
#define LL long long
#define FOR(i,a,b) for (int i = (a); i < (b); i++)
#define REP(i,n) FOR(i,0,n)
#define ALL(v) (v).begin(), (v).end()
#define FIT(it,v) for (__typeof((v).begin()) it = (v).begin(); it != (v).end(); it++)
#define OUT(A) cout << #A << " = "<< (A) << endl
#define OUT2(A, B) cout << "(" << #A << ", " << #B << ") = (" << (A) << ", "<< (B) << ")" << endl
template<class T> void chmin(T &t, T f) { if (t > f) t = f; }
template<class T> void chmax(T &t, T f) { if (t < f) t = f; }

#define present(c, e) ((c).find((e)) != (c).end())
#define cpresent(c, e) (find(ALL(c), (e)) != (c).end())



void init() {

}

void input() {

}

bool chk(string s, string t) {
  char c[26];
  REP(i, 26) c[i] = ' ';
  REP(i, SZ(s)) {
    int a = s[i]-'a';
    if (c[a] == ' ') c[a] = t[i];
    else {
      if (c[a] != t[i]) return false;
    }
  }
  return true;
}

void solve() {
  string s, t;
  cin >> s >> t;
  bool res = chk(s, t) && chk(t,s);
  if (res) cout << "Yes" <<endl;
  else cout << "No" << endl;
}

int main() {
	init();
	input();
	solve();
	return 0;
}