Problem:
Score : 100 points

Problem Statement

Given a lowercase English letter c, determine whether it is a vowel. Here, there are five vowels in the English alphabet: a, e, i, o and u.

Constraints

c is a lowercase English letter.

Input

The input is given from Standard Input in the following format:

c

Output

If c is a vowel, print vowel. Otherwise, print consonant.

Sample Input 1

a

Sample Output 1

vowel

Since a is a vowel, print vowel.

Sample Input 2

z

Sample Output 2

consonant

Sample Input 3

s

Sample Output 3

consonant

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <cstdlib>
#include <iostream>
#include <string>
#include <time.h>
#include <cstdio>
#include <algorithm>
#include <cmath>
#include <sstream>
#include <iomanip>
#include <vector>
#include <functional>
#include <numeric>
#include <cassert>
#include <algorithm>
#include <functional>
//#include "bits/stdc++.h"
using namespace std;
//using namespace std::vector;
#define rep(i,a,b) for(ll i=(a);i<(b);++i)

#define huge 1000000007
typedef long long int ll;
ll gcd(ll a, ll b);
ll bur(ll N, ll X);
bool IsPrime(int num);

int main(void) {

	ll N = 0;
	ll A = 0;
	ll B = 0;
	ll C = 0;
	ll D = 0;
	ll L = 0;
	ll P = 0;
	//ll T = 0;
	//ll M = 0;
	ll h[1000] = {};
	//ll b[100] = {};
	//ll c[100] = {};
	//ll d[100] = {};

	//ll v[3] = {};
	//ll *c, *s, *n;
	string S[50],T[50],U[52];
	ll count = 0;
	ll count2 = 0;
	float sum = 0;
	ll min = 1000000000000;
	ll max = 1;
	ll dist1 = 0;
	ll dist2 = 0;
	ll now = 0;
	int tmax = 0;
	int tmax2 = 0;
	//int flag = 0;
	char temp,head;
	//int is = 0;
	bool flag = false;
	
	//char p;

	ll all = 0;
	ll niku = 0;
	ll state = 2;
	bool down = true;
	

	//cin >> S;
	
	
	
	
	cin >>temp;
	vector<int> tr(3);
	
	
	if(temp == 'a' || temp == 'i' || temp == 'u' || temp == 'e' || temp == 'o')
	cout << "vowel" << endl;
	else
		cout << "consonant" << endl;

	//x = (ll *)malloc((N+1) * sizeof(ll));
	//c = (ll *)malloc((N) * sizeof(ll));
	//cin >> D >> G;
	//vector<pair<int,int>> tr(M);
	//vector<pair<int,int>> qes(Q);
	//sort(c.begin(), c.end());
	
	//cout << c[2] - c[1] << endl;

	
	/*A = N / 1000;
	N %= 1000;
	B = N / 100;
	N %= 100;
	C = N / 10;
	N %= 10;
	D = N;*/
	


	//cin >> N >> M;

	//vector<pair<int,int>> c(M);
	////vector<pair<int, int>> e(M);
	//vector<ll> d(M);

	//rep(i, 0, M) {
	//	cin >> c[i].first >> c[i].second;
	//	//e[i].first = c[i].first;
	//	//e[i].second = c[i].second;

	//}
	////sort(c.begin(), c.end());

	//

	//rep(i, 0, M) {

	//	
	//	
	//	rep(j, 0, M) {
	//		if (c[i].first == c[j].first && c[j].second < c[i].second) {
	//			d[i]++;
	//			//cout << j << endl;
	//		}
	//	}
	//	cout << std::setfill('0') << std::right << std::setw(6) << c[i].first;
	//	cout << std::setfill('0') << std::right << std::setw(6) << d[i]+1 << endl;
	//}

	return 0;

}

ll bur(ll N,ll X) {
	ll pan = 1;
	ll pat = 1;
	ll burg = 0;



	if (X > burg) {
		if (N == 0)
			return pat;


		burg += pan;
		burg += bur(N - 1, X);
		burg += pat;
		burg += bur(N - 1, X);
		burg += pan;


	}

	return burg;

}

ll gcd(ll a, ll b) {
	
	/* 自然数 a > b を確認・入替 */
	if (a<b) {
		ll tmp = a;
		a = b;
		b = tmp;
	}
	ll x = b;
	ll y = a;
	/* ユークリッドの互除法 */
	ll r = a % b;
	while (r != 0) {
		a = b;
		b = r;
		r = a % b;
	}


	return y/b*x;
}

bool IsPrime(int num)
{
	if (num < 2) return false;
	else if (num == 2) return true;
	else if (num % 2 == 0) return false; // 偶数はあらかじめ除く

	double sqrtNum = sqrt(num);
	for (int i = 3; i <= sqrtNum; i += 2)
	{
		if (num % i == 0)
		{
			// 素数ではない
			return false;
		}
	}

	// 素数である
	return true;
}