Problem:
Score : 500 points

Problem Statement

There are N points on the 2D plane, i-th of which is located on (x_i, y_i).
There can be multiple points that share the same coordinate.
What is the maximum possible Manhattan distance between two distinct points?

Here, the Manhattan distance between two points (x_i, y_i) and (x_j, y_j) is defined by |x_i-x_j| + |y_i-y_j|.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq x_i,y_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
x_1 y_1
x_2 y_2
:
x_N y_N

Output

Print the answer.

Sample Input 1

3
1 1
2 4
3 2

Sample Output 1

4

The Manhattan distance between the first point and the second point is |1-2|+|1-4|=4, which is maximum possible.

Sample Input 2

2
1 1
1 1

Sample Output 2

0

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include<bits/stdc++.h>
#define pb push_back
#define sz(v) (v).size()
#define all(v) (v).begin(),(v).end()
#define fi first
#define se second
#define mp make_pair
#define inf 2000000007
#define mod 1000000007
using namespace std;
template <typename T> T Max(T x,T y){return x>y?x:y;}
template <typename T> T Min(T x,T y){return x<y?x:y;}
template <typename T> void chmax(T &x,T y){x=x>y?x:y;return;}
template <typename T> void chmin(T &x,T y){x=x<y?x:y;return;}

int n,x,y,max1,min1=inf,max2,min2=inf;

int main()
{
	scanf("%d",&n);
	for(int i=1;i<=n;i++)
	{
		scanf("%d%d",&x,&y);
		chmax(max1,x+y);
		chmin(min1,x+y);
		chmax(max2,x-y);
		chmin(min2,x-y);
	}
	printf("%d",Max(max1-min1,max2-min2));
	return 0;
}