Problem:
Score : 100 points

Problem Statement

Takahashi is meeting up with Aoki.

They have planned to meet at a place that is D meters away from Takahashi's house in T minutes from now.

Takahashi will leave his house now and go straight to the place at a speed of S meters per minute.

Will he arrive in time?

Constraints

1 \leq D \leq 10000

1 \leq T \leq 10000

1 \leq S \leq 10000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

D T S

Output

If Takahashi will reach the place in time, print Yes; otherwise, print No.

Sample Input 1

1000 15 80

Sample Output 1

Yes

It takes 12.5 minutes to go 1000 meters to the place at a speed of 80 meters per minute. They have planned to meet in 15 minutes so he will arrive in time.

Sample Input 2

2000 20 100

Sample Output 2

Yes

It takes 20 minutes to go 2000 meters to the place at a speed of 100 meters per minute. They have planned to meet in 20 minutes so he will arrive just on time.

Sample Input 3

10000 1 1

Sample Output 3

No

He will be late.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#define REP(i, n) for(ll i = 0; i < n; i++)
#define REPR(i, n) for(ll i = n - 1; i >= 0; i--)
#define FOR(i, m, n) for(ll i = m; i <= n; i++)
#define FORR(i, m, n) for(ll i = m; i >= n; i--)
#define SORT(v, n) sort(v, v+n)
#define MAX 100000
#define inf 1000000007
using namespace std;
using ll = long long;
using vll = vector<ll>;
using vvll = vector<vector<ll>>;
using P = pair<ll, ll>;
using graph = vector<vector<int>>;

int main() {
    //cin高速化
    cin.tie(0);
    ios::sync_with_stdio(false);
    ll a, b, c;
    cin >> a >> b >> c;
    if(a <= b * c){
        cout << "Yes" <<"\n";
    }else{
        cout << "No" <<"\n";
    }
	return 0;
}