Problem:
Score : 200 points

Problem Statement

Let us define the FizzBuzz sequence a_1,a_2,... as follows:

If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.

If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.

If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.

If none of the above holds, a_i=i.

Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Constraints

1 \leq N \leq 10^6

Input

Input is given from Standard Input in the following format:

N

Output

Print the sum of all numbers among the first N terms of the FizzBuzz sequence.

Sample Input 1

15

Sample Output 1

60

The first 15 terms of the FizzBuzz sequence are:

1,2,\mbox{Fizz},4,\mbox{Buzz},\mbox{Fizz},7,8,\mbox{Fizz},\mbox{Buzz},11,\mbox{Fizz},13,14,\mbox{FizzBuzz}

Among them, numbers are 1,2,4,7,8,11,13,14, and the sum of them is 60.

Sample Input 2

1000000

Sample Output 2

266666333332

Watch out for overflow.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <cstdio>
#include <iostream>
#include <cstdlib>
#include <unordered_map>
#include <map>
#include <unordered_set>
#include <set>
#include <vector>
#include <string>
#include <cstring>
#include <sstream>
#include <algorithm>
#include <cmath>
#include <queue>
#include <stack>
#include <list>
#include <array>
#include <deque>
#include <bitset>
typedef long long ll;
using namespace std;
#define trace(x) cerr << #x << " is " << x << endl;

ll f(int n) {
    ll res = 0;
    for (int i = 1; i <= n; i++) {
        if (i % 3 != 0 && i % 5 != 0) res+= i;
    }
    return res;
}
int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    int n;
    cin >> n;
    cout << f(n) <<endl;
    return 0;
}