Problem:
Score : 200 points

Problem Statement

Niwango-kun is an employee of Dwango Co., Ltd.

One day, he is asked to generate a thumbnail from a video a user submitted.

To generate a thumbnail, he needs to select a frame of the video according to the following procedure:

Get an integer N and N integers a_0, a_1, ..., a_{N-1} as inputs. N denotes the number of the frames of the video, and each a_i denotes the representation of the i-th frame of the video.

Select t-th frame whose representation a_t is nearest to the average of all frame representations.

If there are multiple such frames, select the frame with the smallest index.

Find the index t of the frame he should select to generate a thumbnail.

Constraints

1 \leq N \leq 100

1 \leq a_i \leq 100

All numbers given in input are integers

Input

Input is given from Standard Input in the following format:

N
a_{0} a_{1} ... a_{N-1}

Output

Print the answer.

Sample Input 1

3
1 2 3

Sample Output 1

1

Since the average of frame representations is 2, Niwango-kun needs to select the index 1, whose representation is 2, that is, the nearest value to the average.

Sample Input 2

4
2 5 2 5

Sample Output 2

0

The average of frame representations is 3.5.

In this case, every frame has the same distance from its representation to the average.

Therefore, Niwango-kun should select index 0, the smallest index among them.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include "iostream"
#include "fstream"
#include "algorithm"
#include "iomanip"
#include "stack"
#include "queue"
#include "string"
#include "vector"
#include "map"
#include "set"
#include "unordered_set"
#include "unordered_map"
#include "iterator"
#include <ctime>
#include "bitset"
#include "cmath"
#include "list"
#include "complex"
#include <cassert>
#include "deque"
#include "numeric"

using namespace std;

//#define f(i,n) for(int i=0; i<n;i++) 
//#define rf(i, n) for(int i=n-1;i>=0;i--)
//#define forn(i, j, n) for(int i=j; i<n; i++)
//#define ff(i, j, n) f(i, n)f(j, n)
#define pb push_back
#define mp make_pair
#define maxi(a,b) a = max(a, b);
#define mini(a,b) a = min(a, b);
#define endl '\n'
#define all(a) a.begin(), a.end()
#define sqr(x) ((x) * (x))
#define SZ(a) ((int)(a.size()))
#define watch(x) cout << (#x) << " = " << x << endl;
//typedef long long ll;
typedef long double ld;
#define int long long
#define double ld
typedef map<int, int> mii;
typedef pair<int, int> pii;
typedef pair<string, int> psi;
typedef pair<int, string> pis;
typedef vector<int> vi;
typedef vector<double> vd;
typedef vector<pii> vpii;
typedef vector<char> vc;

template<class T>
void show(const vector<T> &a)
{
	for (T x : a)
		cout << x << " ";
	cout << endl;
}

const int sze = 3e5 + 50, oo = 1e18 + 500, mod = 1000000007;
const double eps = 5e-10, PI = 2 * acos(0.0);
vi vertices[sze];
vc visit(sze, false);
vi arr(sze, 0);
int n, m, k;
int cnt = 0;
int x, y;


signed main()
{
	ios::sync_with_stdio(false);
	cin.tie(0);
	cout.tie(0);

	cin >> n;
	vd a(n);
	double avr = 0;
	for (int i = 0; i < n; i++)
	{
		cin >> a[i];
		avr += a[i];
	}

	avr /= n;

	vpii ind;
	for (int i = 0; i < n; i++)
	{
		ind.pb(mp(fabs(a[i] - avr), i));
	}
	sort(all(ind));

	cout << ind[0].second;
	return 0;
}