Problem:
Score : 200 points

Problem Statement

Tak performed the following action N times: rolling two dice.
The result of the i-th roll is D_{i,1} and D_{i,2}.

Check if doublets occurred at least three times in a row.
Specifically, check if there exists at lease one i such that D_{i,1}=D_{i,2}, D_{i+1,1}=D_{i+1,2} and D_{i+2,1}=D_{i+2,2} hold.

Constraints

3 \leq N \leq 100

1\leq D_{i,j} \leq 6

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
D_{1,1} D_{1,2}
\vdots
D_{N,1} D_{N,2}

Output

Print Yes if doublets occurred at least three times in a row. Print No otherwise.

Sample Input 1

5
1 2
6 6
4 4
3 3
3 2

Sample Output 1

Yes

From the second roll to the fourth roll, three doublets occurred in a row.

Sample Input 2

5
1 1
2 2
3 4
5 5
6 6

Sample Output 2

No

Sample Input 3

6
1 1
2 2
3 3
4 4
5 5
6 6

Sample Output 3

Yes

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <iostream>
#include <vector>
#include <string>
#include <cstdio>
#include <map>
#include <algorithm>
#include <cmath>
using namespace std;

#define ll long long

#define si(x) scanf("%d", &x)
#define sll(x) scanf("%lld", &x)

#define pi(x) printf("%d", x)

int main()
{
    ll t, n, count = 0, m;
    sll(t);

    while (t--)
    {
        sll(n), sll(m);
        bool prev = true;

        if (n == m && prev)
        {
            count++;
            prev = true;
        }
        else
        {
            if (count < 3)
            {
                count = 0;
            }
            prev = false;
        }
    }

    if (count >= 3)
    {
        cout << "Yes\n";
    }
    else
    {
        cout << "No\n";
    }

    return 0;
}