Problem:
Score : 200 points

Problem Statement

There are some animals in a garden. Each of them is a crane with two legs or a turtle with four legs.

Takahashi says: "there are X animals in total in the garden, and they have Y legs in total." Determine whether there is a combination of numbers of cranes and turtles in which this statement is correct.

Constraints

1 \leq X \leq 100

1 \leq Y \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

If there is a combination of numbers of cranes and turtles in which the statement is correct, print Yes; otherwise, print No.

Sample Input 1

3 8

Sample Output 1

Yes

The statement "there are 3 animals in total in the garden, and they have 8 legs in total" is correct if there are two cranes and one turtle. Thus, there is a combination of numbers of cranes and turtles in which the statement is correct.

Sample Input 2

2 100

Sample Output 2

No

There is no combination of numbers of cranes and turtles in which this statement is correct.

Sample Input 3

1 2

Sample Output 3

Yes

We also consider the case in which there are only cranes or only turtles.

Solution in C++ (Clang 10.0.0) (judge verdict: Accepted)

#include <iostream>
#include <algorithm>
#include <cmath>
#include <queue>
#include <set>
#include <map>
#include <vector>
#include <string>
#include <iomanip>
#define faster       ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);
#define f(i,a,b) for(ll i=a;i<b;i++)
#define r(i,a,b) for(ll i=a;i>b;i--)
using namespace std;
typedef long long ll;
typedef long double ld;


int main(){

ll x,y; cin>>x>>y;

if(y%2!=0){
  cout << "No" << endl;
}else{
  if(y<=4*x && y>=2*x){
    cout << "Yes" << endl;
  }else{
    cout << "No" << endl;
  }
}

}