Problem:
Score : 100 points

Problem Statement

Given an integer a as input, print the value a + a^2 + a^3.

Constraints

1 \leq a \leq 10

a is an integer.

Input

Input is given from Standard Input in the following format:

a

Output

Print the value a + a^2 + a^3 as an integer.

Sample Input 1

2

Sample Output 1

14

When a = 2, we have a + a^2 + a^3 = 2 + 2^2 + 2^3 = 2 + 4 + 8 = 14.

Print the answer as an input. Outputs such as 14.0 will be judged as incorrect.

Sample Input 2

10

Sample Output 2

1110

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <iostream>
#include <cmath>
#include <string>
#include <vector>
#include <map>
#include <algorithm>
#include <queue>
#include <stack>
#include <list>
#include <deque>
#include <set>
using namespace std;
using ll = long long;
using ld = long double;

const ll MOD = 1000000000 + 7;
const ll INF = 1e+9;
const ld PI = acos((long double)(-1));

#define no "no"
#define No "No"
#define NO "NO"
#define yes "yes"
#define Yes "Yes"
#define YES "YES"
#define next '\n'
#define sp " "
#define print(x) cout << (x) << endl;
#define rep(i, n) for(int (i) = (0); (i) < (n); (++i))
#define FOR(i, start, end) for(int (i) = (start); (i) < (end); (++i))
#define foreach(elem, _list) for(auto& (elem) : (_list))
#define view(_list) foreach(e, _list){ cout << e << sp; } cout << next
#define FAST ios::sync_with_stdio(false); cin.tie(nullptr)
#define size(s) (s).size()
#define ALL(vec) (vec).begin(), (vec).end()
#define pb(e) push_back(e)
#define eb(e) emplace_back(e)
#define EPS 0.00000001

int main() {
    FAST;

    int a;
    cin >> a;
    print(a + a * a + a * a * a);
}