Problem:
Score : 300 points

Problem Statement

Given is a permutation P_1, \ldots, P_N of 1, \ldots, N.
Find the number of integers i (1 \leq i \leq N) that satisfy the following condition:

For any integer j (1 \leq j \leq i), P_i \leq P_j.

Constraints

1 \leq N \leq 2 \times 10^5

P_1, \ldots, P_N is a permutation of 1, \ldots, N.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
P_1 ... P_N

Output

Print the number of integers i that satisfy the condition.

Sample Input 1

5
4 2 5 1 3

Sample Output 1

3

i=1, 2, and 4 satisfy the condition, but i=3 does not - for example, P_i > P_j holds for j = 1.

Similarly, i=5 does not satisfy the condition, either. Thus, there are three integers that satisfy the condition.

Sample Input 2

4
4 3 2 1

Sample Output 2

4

All integers i (1 \leq i \leq N) satisfy the condition.

Sample Input 3

6
1 2 3 4 5 6

Sample Output 3

1

Only i=1 satisfies the condition.

Sample Input 4

8
5 7 4 2 6 8 1 3

Sample Output 4

4

Sample Input 5

1
1

Sample Output 5

1

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <utility>
#include <vector>
#include <iostream>
#include <algorithm>
#include <set>
#include <climits>
#include <cmath>
#include <limits.h>
#include <ios>
#include <iomanip>
#include <map> // pair
#define REP(i,n) for(int i=0;i<n;i++)
typedef unsigned long ul;
typedef unsigned long long ull;
typedef long long ll;
using namespace std;
ll gcd(ll a, ll b){return b? gcd(b, a%b):a;}
 
int main() {
	cin.tie(0);
  ios::sync_with_stdio(false);
  int N;
  cin >> N;
  int P[N-1];
  for(int i = 0; i < N; i++){
    cin >> P[i];
  }

  int ans = 0;
  int min = P[0];
  for(int i = 0; i < N; i++){
    if(i==0){
      ans++;
    }else if(P[i] < min){
      ans++;
      min = P[i];
    }
  }

  cout << ans << endl;

  return 0;
}