Problem:
Score : 200 points

Problem Statement

Let S(n) denote the sum of the digits in the decimal notation of n.
For example, S(101) = 1 + 0 + 1 = 2.

Given an integer N, determine if S(N) divides N.

Constraints

1 \leq N \leq 10^9

Input

Input is given from Standard Input in the following format:

N

Output

If S(N) divides N, print Yes; if it does not, print No.

Sample Input 1

12

Sample Output 1

Yes

In this input, N=12.
As S(12) = 1 + 2 = 3, S(N) divides N.

Sample Input 2

101

Sample Output 2

No

As S(101) = 1 + 0 + 1 = 2, S(N) does not divide N.

Sample Input 3

999999999

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

/** author: __nishad__ **/

#include<bits/stdc++.h>
using namespace std;


typedef long long ll ;
typedef vector<ll> vll ;

#define IOS ios::sync_with_stdio(false); cin.tie(0); cout.tie(0);
#define all(v) (v).begin(),(v).end()
#define precision(k) cout<<setprecision(k)<<fixed;
#define loop(i,a) for(int i=0; i<a;i++)
#define loop2(i,a,b) for(int i=(a);i<=(b);++i)
#define minv(v) *min_element(all(v))
#define maxv(v) *max_element(all(v))
#define getpos(v,x) (lower_bound(v.begin(),v.end(),x)-v.begin())
#define unq(v) sort(all(v)),(v).erase(unique((v).begin(),(v).end()),(v).end())
#define pb push_back
#define pi 3.14159265358979323
#define endl "\n"

int main()
{
    IOS;

    ll n, sum=0;
    cin>>n;

    while(n != 0){
        sum = sum + n%10;
        n = n/10;
    }
    n = n%sum;
    cout<<(n==0? "Yes" : "No");

}