Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>

using namespace std;
int main(int argc, char *argv[]) {
	int n,sum;
	cin >> n;
	int res = 0;
	for (int i = 1; i <= n; i += 2){
		sum = 0;
		for(int j = 1; j <= i; j++){
			if(i%j == 0) sum++;
		}
		if (sum == 8) res++;
	}
	cout << res << endl;
	return 0;
}