Problem:
Score : 300 points

Problem Statement

You are given an array A of length N.
Your task is to divide it into several contiguous subarrays.
Here, all subarrays obtained must be sorted in either non-decreasing or non-increasing order.
At least how many subarrays do you need to divide A into?

Constraints

1 \leq N \leq 10^5

1 \leq A_i \leq 10^9

Each A_i is an integer.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

Print the minimum possible number of subarrays after division of A.

Sample Input 1

6
1 2 3 2 2 1

Sample Output 1

2

One optimal solution is to divide the array into [1,2,3] and [2,2,1].

Sample Input 2

9
1 2 1 2 1 2 1 2 1

Sample Output 2

5

Sample Input 3

7
1 2 3 2 1 999999999 1000000000

Sample Output 3

3

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
#define _GLIBCXX_DEBUG
#define rep(i,n) for(int i=0;i<(n);++i)
#define repi(i,a,b) for(int i=int(a);i<int(b);++i)
#define all(x) (x).begin(), (x).end()
#define PI 3.14159265358979323846264338327950L
using namespace std;
typedef long long ll;
typedef long double ld;
int main() {
    int n;
    cin>>n;
    vector<long> a(n);
    rep(i,n) cin>>a[i];
    int ans=0;
    rep(i,n){
        while(i<n-1&&a[i-1]==a[i]) i++;
        if(a[i-1]<a[i]) while(i<n-1&&a[i-1]<=a[i]) i++;
        else if(a[i-1]>a[i]) while(i<n-1&&a[i-1]>=a[i]) i++;
        ans++;
    }
    cout<<ans;
}