Problem:
Score : 300 points

Problem Statement

Given is a permutation P_1, \ldots, P_N of 1, \ldots, N.
Find the number of integers i (1 \leq i \leq N) that satisfy the following condition:

For any integer j (1 \leq j \leq i), P_i \leq P_j.

Constraints

1 \leq N \leq 2 \times 10^5

P_1, \ldots, P_N is a permutation of 1, \ldots, N.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
P_1 ... P_N

Output

Print the number of integers i that satisfy the condition.

Sample Input 1

5
4 2 5 1 3

Sample Output 1

3

i=1, 2, and 4 satisfy the condition, but i=3 does not - for example, P_i > P_j holds for j = 1.

Similarly, i=5 does not satisfy the condition, either. Thus, there are three integers that satisfy the condition.

Sample Input 2

4
4 3 2 1

Sample Output 2

4

All integers i (1 \leq i \leq N) satisfy the condition.

Sample Input 3

6
1 2 3 4 5 6

Sample Output 3

1

Only i=1 satisfies the condition.

Sample Input 4

8
5 7 4 2 6 8 1 3

Sample Output 4

4

Sample Input 5

1
1

Sample Output 5

1

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#define repz(i, z, n) for (decltype(n) i = (z); i < (n); i++)
#define rep(i, n) for (decltype(n) i = 0; i < (n); i++)

#define REPZ(i, z, n) for (decltype(n) i = (z); i <= (n); i++)
#define REP(i, n) for (decltype(n) i = 0; i <= (n); i++)
#define ALL(v) v.begin(), v.end()
#define SIZE(v) ((ll)(v).size())
#define MAX(v) (*max_element(ALL(v)))
#define MIN(v) (*min_element(ALL(v)))
#define INF 1000000000000  // 1E+12

// 略
#define PB push_back
#define F first
#define S second
#define MP make_pair
#define READ cin >>
#define PRINT cout <<
#define PYES cout << "Yes" << endl;
#define POK cout << "OK" << endl;
#define PNO cout << "No" << endl;
#define PNG cout << "NG" << endl;

using namespace std;

// デバッグ用
void debug_out() { cout << endl; }
template <typename Head, typename... Tail>
void debug_out(Head H, Tail... T) {
  cout << H << " ";
  debug_out(T...);
}

template <class T>
bool chmax(T &a, const T &b) {
  if (a < b) {
    a = b;
    return true;
  }
  return false;
}
template <class T>
bool chmin(T &a, const T &b) {
  if (a > b) {
    a = b;
    return true;
  }
  return false;
}

#ifdef _DEBUG
#define debug(...) debug_out(__VA_ARGS__)
#else
#define debug(...)
#endif

// typedef
typedef long long ll;
typedef unsigned long long ul;
typedef long double ld;
typedef pair<ll, ll> pl;

// const
// 円周率
const ld pi = acos(-1);
// mod用
// 1E+9 +7
const ll mod = (int)1e+9 + 7;
// 1s間で可能なループ回数2E+8回
// int        最大値2147483647         〜2E+9
// long long  最大値9223372036854775807〜9E+18
// 総和accumulate
// 単純リストvector<type> push_back
// 連想配列map<key,value> insert,
// 集合set<type>
// pair キーとバリューを格納 firstとsecondでアクセス
// 小数点指定 cout << fixed << setprecision(15) << endl;
// to_string<->stoi
// stoll(longlong)
// stod(double)
// deep copy v1->v2 copy(v1.begin(), v1.end(), back_inserter(v2) );
// 大文字65-90(-32)
// 小文字97-122(+32)
//  priority_queue<pair<ll, ll>, vector<pair<ll, ll>>, greater<pair<ll, ll>>>
//  ba;
signed main() {
  // faster
  // C言語流の入出力は使用できない
  ios::sync_with_stdio(false);
  std::cin.tie(nullptr);
  int n;
  cin >> n;
  int mintemp = 0;
  int res = 0;
  cin >> mintemp;
  res++;
  rep(i, n - 1) {
    int a;
    cin >> a;
    res += chmin(mintemp, a);
  }
  cout <<res << endl;
  return 0;
}