Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<bits/stdc++.h>
#define ll long long
#define rep(i,a,b) for(i=a;i<b;i++)
#define all(v) v.begin(),v.end()
#define F first
#define S second
#define pb push_back
#define hell 1000000007

using namespace std;
void solve()
{

ll int  m,i,j,k,d=1,b,c=0,sum=0,z=0,q,x=0,y=0,n;
cin>>n;
m=n%100;
n/=100;
if(!m and n>12) {cout<<"NA"; return;}
if(!n and m>12) {cout<<"NA"; return;}
if((m>12 and n>12)) {cout<<"NA"; return;}
//if( m>12 and n>12 ) {cout<<"NA"; return;}
if(m>12 and n<=12) {cout<<"MMYY"; return;}
 if(n>12 and m<=12) {cout<<"YYMM"; return;}
if(n<=12 and m<=12) cout<<"AMBIGOUS";
}



int main()
{
ios::sync_with_stdio(false);
cin.tie(0); cout.tie(0);

 int t=1;
//cin>>t;
 while(t--)
  solve();
}