Problem:
Score : 400 points

Problem Statement

Snuke lives in another world, where slimes are real creatures and kept by some people.
Slimes come in N colors. Those colors are conveniently numbered 1 through N.
Snuke currently has no slime. His objective is to have slimes of all the colors together.

Snuke can perform the following two actions:

Select a color i (1≤i≤N), such that he does not currently have a slime in color i, and catch a slime in color i. This action takes him a_i seconds.

Cast a spell, which changes the color of all the slimes that he currently has. The color of a slime in color i (1≤i≤N-1) will become color i+1, and the color of a slime in color N will become color 1. This action takes him x seconds.

Find the minimum time that Snuke needs to have slimes in all N colors.

Constraints

2≤N≤2,000

a_i are integers.

1≤a_i≤10^9

x is an integer.

1≤x≤10^9

Input

The input is given from Standard Input in the following format:

N x
a_1 a_2 ... a_N

Output

Find the minimum time that Snuke needs to have slimes in all N colors.

Sample Input 1

2 10
1 100

Sample Output 1

12

Snuke can act as follows:

Catch a slime in color 1. This takes 1 second.

Cast the spell. The color of the slime changes: 1 → 2. This takes 10 seconds.

Catch a slime in color 1. This takes 1 second.

Sample Input 2

3 10
100 1 100

Sample Output 2

23

Snuke can act as follows:

Catch a slime in color 2. This takes 1 second.

Cast the spell. The color of the slime changes: 2 → 3. This takes 10 seconds.

Catch a slime in color 2. This takes 1 second.

Cast the soell. The color of each slime changes: 3 → 1, 2 → 3. This takes 10 seconds.

Catch a slime in color 2. This takes 1 second.

Sample Input 3

4 10
1 2 3 4

Sample Output 3

10

Snuke can act as follows:

Catch a slime in color 1. This takes 1 second.

Catch a slime in color 2. This takes 2 seconds.

Catch a slime in color 3. This takes 3 seconds.

Catch a slime in color 4. This takes 4 seconds.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <vector>
using namespace std;
int main(int argc, char* argv[])
{
	int N;
	long long x;
	cin>>N>>x;
	vector<long long> A(N,0);
	vector<int>has(N,0);
	int i;
	for (i=0;i<N;i++){
		cin>>A[i];
	}
	long long sec=0;
	bool bFirst=true;
	long long minA=1e10;
	int minI=0;
	bFirst=true;
	for (i=0;i<N;i++){
		if (minA>A[i]){
			minA=A[i];
			minI=i;
		}
	}
	int hasN;
	hasN=0;
	for (;;){
		for (i=0;i<N;i++){
			if (has[i]==0){
				if (A[i]<=x+minA){
					sec += A[i];
					has[i]=1;
					hasN++;
				}
			}
		}
		if (has[minI]==0){
			sec+=A[minI];
			has[minI]=1;
			hasN++;
		}
		if (hasN==N){
			cout<<sec<<endl;
			return 0;
		}
		//魔法を唱える
		sec+=x;
		int tmpHas = has[N-1];
		for (i=N-1;i>=1;i--){
			has[i]=has[i-1];
		}
		has[0]=tmpHas;
	}
	return 0;
}