Problem:
Score : 200 points

Problem Statement

Given are strings S and T. Consider changing S to T by repeating the operation below. Find the minimum number of operations required to do so.

Operation: Choose one character of S and replace it with a different character.

Constraints

S and T have lengths between 1 and 2\times 10^5 (inclusive).

S and T consists of lowercase English letters.

S and T have equal lengths.

Input

Input is given from Standard Input in the following format:

S
T

Output

Print the answer.

Sample Input 1

cupofcoffee
cupofhottea

Sample Output 1

4

We can achieve the objective in four operations, such as the following:

First, replace the sixth character c with h.

Second, replace the eighth character f with t.

Third, replace the ninth character f with t.

Fourth, replace the eleventh character e with a.

Sample Input 2

abcde
bcdea

Sample Output 2

5

Sample Input 3

apple
apple

Sample Output 3

0

No operations may be needed to achieve the objective.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
using ll = long long int;
#define REP(i,n) for(ll i=0; i<(n); i++)
#define REP2(i,x,n) for(ll i=x; i<(n); i++)
#define REP3(i,x,n) for(ll i=x; i>(n); i--)
#define zero_pad(num) setfill('0') << std::right << setw(num)
#define space_pad(num) setfill(' ') << std::right << setw(num)
#define ALL(n) begin(n),end(n)
struct cww{cww(){ios::sync_with_stdio(false);cin.tie(0);}}star;
const long long INF = numeric_limits<long long>::max();
int main(){
    string S,T;
    int cnt=0;
    cin >> S;
    cin >> T;
    for (int i = 0; i < (int)(S.length()); i++)
    {
        if(S[i]!=T[i]){
            cnt++;
        }
    }
    cout << cnt << endl;
    return 0;
}