Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<bits/stdc++.h>
using namespace std;
#define forr(x,n) for(int x = 0; x < n; ++x)
#define pr pair<int,int>
#define ll long long int
const int mod=998244353;

int main()
{
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    cout.tie(NULL);
    int a[3][3],c[3][3];
    forr(i,3)
    forr(j,3)
    cin>>a[i][j];
    int n;
    cin>>n;
    int b[n];
    forr(i,n)
    cin>>b[i];
    forr(i,n)
    {
        forr(j,n)
        {
            c[i][j]=0;
            forr(k,n)
            if(a[i][j]==b[k])
            c[i][j]=1;
        }
    }
    string ans="No";
    forr(j,3)
    if(a[0][j]+a[1][j]+a[2][j]==3)
    ans="Yes";
    forr(i,3)
    if(a[i][0]+a[i][1]+a[i][2]==3)
    ans="Yes";
    if(a[0][0]+a[1][1]+a[2][2]==3)
    ans="Yes";
    if(a[0][2]+a[1][1]+a[2][0]==3)
    ans="Yes";
    cout<<ans;

}