Problem:
Score : 300 points

Problem Statement

You are given a sequence of length N: A_1, A_2, ..., A_N.
For each integer i between 1 and N (inclusive), answer the following question:

Find the maximum value among the N-1 elements other than A_i in the sequence.

Constraints

2 \leq N \leq 200000

1 \leq A_i \leq 200000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1
:
A_N

Output

Print N lines. The i-th line (1 \leq i \leq N) should contain the maximum value among the N-1 elements other than A_i in the sequence.

Sample Input 1

3
1
4
3

Sample Output 1

4
3
4

The maximum value among the two elements other than A_1, that is, A_2 = 4 and A_3 = 3, is 4.

The maximum value among the two elements other than A_2, that is, A_1 = 1 and A_3 = 3, is 3.

The maximum value among the two elements other than A_3, that is, A_1 = 1 and A_2 = 4, is 4.

Sample Input 2

2
5
5

Sample Output 2

5
5

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

// C - Exception Handling

#include <bits/stdc++.h>
using namespace std;
#define lli long long int
#define uli unsigned long long int
#define rep(i, m, n) for (lli i = m; i < (n); i++)
#define repe(i, m, n) for (lli i = m; i <= (n); i++)
#define ALL(x) (x).begin(), (x).end()
#define SIZE(x) ((lli)(x).size())
#define MAX(x) *max_element(ALL(x))
#define _GLIBCXX_DEBUG
const lli INF = 2147483647;
const lli MINF = -2147483648;
const lli LINF = 9223372036854775807;
const lli MOD = 1000000007; //10^9+7
const long double PI = acos(-1);
#define SORT(n) sort(n.begin(), n.end())
#define SORTR(n) sort(n.begin(), n.end(), greater<int>())
#define REV(n) reverse(n.begin(), n.end())
#define Vec(K, L, N, S) vector<L> K(N, S)
#define rt sqrt
#define pb push_back
#define ppb pop_back
#define eb emplace_back
#pragma GCC optimize("Ofast")
using vi = vector<int>;
using vvi = vector<vi>;
using vvvi = vector<vvi>;
using vlli = vector<lli>;
using P = pair<lli, lli>;
// vector<P> vp;
// vp.emplace_back(a[i], b[i]);
using vs = vector<string>;
using ll = long long;
// vector入力
template <typename T>
istream &operator>>(istream &is, vector<T> &vec)
{
  for (T &x : vec)
    is >> x;
  return is;
}
// vector出力
template <typename T>
ostream &operator<<(ostream &os, vector<T> &vec)
{
  // os << '{';
  for (int i = 0; i < vec.size(); i++)
  {
    os << vec[i] << (i + 1 == vec.size() ? "" : "");
  }
  // os << '}';
  return os;
}
// aよりもbが大きいならばaをbで更新する(更新されたならばtrueを返す)
template <typename T>
bool chmax(T &a, const T &b)
{
  if (a < b)
  {
    a = b; // aをbで更新
    return true;
  }
  return false;
}
// aよりもbが小さいならばaをbで更新する(更新されたならばtrueを返す)
template <typename T>
bool chmin(T &a, const T &b)
{
  if (a > b)
  {
    a = b; // aをbで更新
    return true;
  }
  return false;
}

int main()
{
  ios::sync_with_stdio(false);
  cin.tie(0);
  lli a, b, c, h, k, n, w, ans = 0, count = 0;
  string s, t;
  cin >> n;
  vlli d(n), e;
  rep(i, 0, n)
  {
    cin >> d[i];
    e.pb(d[i]);
    // ans = max(ans, d[i]);
  }
  SORTR(e);
  rep(i, 0, n)
  {

    if (e[0] == d[i])
    {
      cout << e[1] << endl;
    }
    else
    {
      cout << e[0] << endl;
    }
    // cout << d << endl;
  }
}