Problem:
Score : 200 points

Problem Statement

An integer X is called a Harshad number if X is divisible by f(X), where f(X) is the sum of the digits in X when written in base 10.

Given an integer N, determine whether it is a Harshad number.

Constraints

1?N?10^8

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

Print Yes if N is a Harshad number; print No otherwise.

Sample Input 1

12

Sample Output 1

Yes

f(12)=1+2=3. Since 12 is divisible by 3, 12 is a Harshad number.

Sample Input 2

57

Sample Output 2

No

f(57)=5+7=12. Since 57 is not divisible by 12, 12 is not a Harshad number.

Sample Input 3

148

Sample Output 3

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

//#include <bits/stdc++.h>                          //include all library
#include <cstdio>
#include <iostream>
#include <algorithm>
#include <cmath>
#include <string>
#include <map>
#include <sstream>
#include <vector>
#include <stack>
#include <queue>
#include <string.h>
#include <functional> // greater<int> はfunctionalヘッダ
using namespace std;

#define REP(i, n) for(int i = 0;i < n;i++)          //REP(i, 10){...} //i=0～i=9までのループ
#define REPR(i, n) for(int i = n;i >= 0;i--)        //REPR(i, 10){...} //i=10～i=0までのループ
#define FOR(i, m, n) for(int i = m;i < n;i++)       //FOR(i, 3, 10){...} //i=3～i=9までのループ
#define FORR(i, m, n) for(int i = m;i >= n;i--)     //FORR(i, 10, 3){...} //i=10～i=3までのループ
#define VSORT(v) sort(v.begin(), v.end());
#define llong long long
#define pb(a) push_back(a)
#define INF 999999999
#define PI 3.141592653589
#define npos -1


int n;


int main()
{
	cin >> n;
	int x = n;
	int a=0, b=0;
	REP(i, 8)
	{
		a = n % 10;
		n = (n-a)/10;
		b += a;
		if(n == 0) break;
	}
	
	if(x % b ==0) cout << "Yes";
	else cout << "No";
	cout << endl;
}