Problem:
How many ways?

Write a program which identifies the number of combinations of three integers which satisfy the following conditions:

You should select three distinct integers from 1 to n.

A total sum of the three integers is x.

For example, there are two combinations for n = 5 and x = 9.

1 + 3 + 5 = 9

2 + 3 + 4 = 9

Input

The input consists of multiple datasets. For each dataset, two integers n and x are given in a line.

The input ends with two zeros for n and x respectively. Your program should not process for these terminal symbols.

Constraints

3 ≤ n ≤ 100

0 ≤ x ≤ 300

Output

For each dataset, print the number of combinations in a line.

Sample Input

5 9
0 0

Sample Output

2

Note

      解説

Solution in C++14 (judge verdict: Accepted)

#include<bits/stdc++.h>
#define lint long long int
#define rep(i,n) for(int i=0;i<int(n);i++)
#define per(i,n) for(int i=n-1;i>=0;i--)
#define arep(i,a,n) for(int i=a;i<n;i++)
#define sort(a) sort(a.begin(),a.end())
#define reverse(a) reverse(a.begin(),a.end())
#define fill(a,x) fill(a.begin(),a.end(),x)
#define eb(data) emplace_back(data)
#define pb(data) emplace_back(data)
#define mp make_pair
#define ALNUM 26
#define vint vector<int>
#define F first
#define S second
#define ALL(data) data.begin(),data.end()
#define GEts(s) getline(cin,s);
using namespace std;
template<typename Rast>inline void out(Rast rast){cout<<rast<<"\n";return;}
template<typename Rast>inline void in(Rast& rast){cin>>rast;return;}
template<typename T>istream& operator >> (istream& is, vector<T>& vec){for(T& x: vec) is >> x;return is;}
template<typename First, typename... Rest>void in(First& first, Rest&... rest){cin >> first;in(rest...);return;}
template<typename First, typename... Rest>void out(First first, Rest... rest){cout << first<<" ";out(rest...);return;}
template<typename T>T gcd(T a,T b){if(b==0)return a;return gcd(b,a%b);}
template<typename T1,typename T2>bool chmax(T1& a,T2 b){if(a<b){a=b;return true;}else{return false;}}
template<typename T1,typename T2>bool chmin(T1& a,T2 b){if(a>b){a=b;return true;}else{return false;}}
template<typename T>T lcm(T a, T b){return a * b / gcd(a, b);}
static const double pi = 3.141592653589793;
lint modpow(lint a,lint n,lint p){if(n==1)return a%p;if(n%2==1)return (a*modpow(a,n-1,p))%p;lint t=modpow(a,n/2,p);return (t*t)%p;}//a^n%p
lint MOD=pow(10,9)+7;
//lint MOD=998244353;
lint inf=pow(2,50);
int intinf=pow(2,30);
/**int dirx[]={1,0};int diry[]={0,1};//*///右、下
/**int dirx[]={0,1,0,-1};int diry[]={-1,0,1,0};//*///四方位
/**int dirx[]={-1,0,1,1,1,0,-1,-1};int diry[]={-1,-1,-1,0,1,1,1,0};//*///八方位

class unionfind{
public:
	vector<int> table;
	vector<int> wod;
	void init(int size){
		table.resize(size);
		wod.resize(size);
		rep(i,size)table[i]=i,wod[i]=i;
	};
	int root(int index){
		if(table[index]==index)return index;
		else{
			int hoge=root(table[index]);
			table[index]=hoge;
			return hoge;
		}
	};
	bool same(int x,int y){
		return(root(x)==root(y));
	};
	int marge(int x,int y){
		int yroot=root(y);
		int xroot=root(x);
		if(xroot==yroot)return 0;
		table[yroot]=xroot;
		return 0;
	}
};

int main(){
	cin.tie(0);ios::sync_with_stdio(false);cout<<std::fixed<<std::setprecision(12);
	while(1){
		int n,x;
		in(n,x);
		if(n==0&&x==0)return 0;
		set<vector<int>> table;
		arep(i,1,n+1){
			arep(j,1,n+1){
				if(i==j)continue;
				arep(k,1,n+1){
					if(i==k||j==k)continue;
					if(i+j+k==x){
						vector<int> hoge;
						hoge.pb(i);
						hoge.pb(j);
						hoge.pb(k);
						sort(hoge);
						table.insert(hoge);
					}
				}
			}
		}
		out(table.size());
	}
	return 0;
}