Problem:
Score : 400 points

Problem Statement

An altar enshrines N stones arranged in a row from left to right. The color of the i-th stone from the left (1 \leq i \leq N) is given to you as a character c_i; R stands for red and W stands for white.

You can do the following two kinds of operations any number of times in any order:

Choose two stones (not necessarily adjacent) and swap them.

Choose one stone and change its color (from red to white and vice versa).

According to a fortune-teller, a white stone placed to the immediate left of a red stone will bring a disaster. At least how many operations are needed to reach a situation without such a white stone?

Constraints

2 \leq N \leq 200000

c_i is R or W.

Input

Input is given from Standard Input in the following format:

N
c_{1}c_{2}...c_{N}

Output

Print an integer representing the minimum number of operations needed.

Sample Input 1

4
WWRR

Sample Output 1

2

For example, the two operations below will achieve the objective.

Swap the 1-st and 3-rd stones from the left, resulting in RWWR.

Change the color of the 4-th stone from the left, resulting in RWWW.

Sample Input 2

2
RR

Sample Output 2

0

It can be the case that no operation is needed.

Sample Input 3

8
WRWWRWRR

Sample Output 3

3

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define fi first
#define endl "\n"
#define se second
#define ll long long
#define inf 0x3f3f3f3f
#define fast    ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
const int N = 2e5+5;
const ll mod =   1e9+7;
int n;string s;
int x=0;int y=0;
int main()
{  fast
cin>>n>>s;
y=n-1;int ans=0;
while(x<y){
	while(x<y&&s[x]=='R')x++;
	while(y>x&&s[y]=='W')y--;
	if(x<y)
	ans++;
	x++;y--;
}

cout<<ans;
}