Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

// https://atcoder.jp/contests/abc106/tasks/abc106_b
#include <bits/stdc++.h>
using namespace std;
#define int long long
#define REP(i, n) FOR(i, 0, n)
#define REPR(i, n) for (int_fast32_t i = n - 1; i >= 0; i--)
#define FOR(i, s, n) for (int_fast32_t i = (s), i##_len = (n); i < i##_len; ++i)
#define ALL(obj) (obj).begin(), (obj).end()
#define ALLR(obj) (obj).rbegin(), (obj).rend()
#define DIV(a, b) ((a - 1) / b + 1)

vector<int> a = {105, 135, 165, 189, 195};

signed main() {
    ios::sync_with_stdio(false);
    cin.tie(0);
    int N;
    cin >> N;
    auto it = lower_bound(ALL(a), N + 1);
    cout << distance(a.begin(), it) << endl;
    return 0;
}