Problem:
Score : 400 points

Problem Statement

Given is an integer S.
Find a combination of six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfies all of the following conditions:

0 \leq X_1,Y_1,X_2,Y_2,X_3,Y_3 \leq 10^9

The area of the triangle in a two-dimensional plane whose vertices are (X_1,Y_1),(X_2,Y_2), and (X_3,Y_3) is S/2.

We can prove that there always exist six integers that satisfy the conditions under the constraints of this problem.

Constraints

1 \leq S \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

S

Output

Print six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfy the conditions, in this order, with spaces in between.
If multiple solutions exist, any of them will be accepted.

Sample Input 1

3

Sample Output 1

1 0 2 2 0 1

The area of the triangle in a two-dimensional plane whose vertices are (1,0),(2,2), and (0,1) is 3/2.
Printing 3 0 3 1 0 1 or 1 0 0 1 2 2 will also be accepted.

Sample Input 2

100

Sample Output 2

0 0 10 0 0 10

Sample Input 3

311114770564041497

Sample Output 3

314159265 358979323 846264338 327950288 419716939 937510582

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;

#define ll long long
#define ld long double
#define pb push_back
#define mp make_pair
#define forn(i,n) for(ll i=0;i<n;i++)
#define fore(i,a,b) for(ll i=a;i<=b;i++)
#define ford(i,n) for(ll i=n-1;i>=0;i--)
#define fi first
#define se second
#define endl "\n"
#define all(a) a.begin(),a.end()
#define sync ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0);
#define PI 3.14159265

/*************************************************************************************/
void file(){
    #ifndef ONLINE_JUDGE
    // for getting input from input.txt
    freopen("input.txt", "r", stdin);
    // for writing output to output.txt
    freopen("output.txt", "w", stdout);
    #endif
}
/*************************************************************************************/

const ll maxn=2e5+1,mod=1e9+7;




int main(){

    sync
   // file();
    
    ll s;
    cin>>s;

    ll ah = sqrt(s);
    if(ah*ah!=s) ah+=1;
    ll oh = ah*ah;
    
    cout<<ah<<" "<<1<<" "<<-s+oh<<" "<<ah<<" "<<0<<" "<<0;


  return 0;
}