Problem:
Score: 200 points

Problem Statement

A country decides to build a palace.

In this country, the average temperature of a point at an elevation of x meters is T-x \times 0.006 degrees Celsius.

There are N places proposed for the place. The elevation of Place i is H_i meters.

Among them, Princess Joisino orders you to select the place whose average temperature is the closest to A degrees Celsius, and build the palace there.

Print the index of the place where the palace should be built.

It is guaranteed that the solution is unique.

Constraints

1 \leq N \leq 1000

0 \leq T \leq 50

-60 \leq A \leq T

0 \leq H_i \leq 10^5

All values in input are integers.

The solution is unique.

Input

Input is given from Standard Input in the following format:

N
T A
H_1 H_2 ... H_N

Output

Print the index of the place where the palace should be built.

Sample Input 1

2
12 5
1000 2000

Sample Output 1

1

The average temperature of Place 1 is 12-1000 \times 0.006=6 degrees Celsius.

The average temperature of Place 2 is 12-2000 \times 0.006=0 degrees Celsius.

Thus, the palace should be built at Place 1.

Sample Input 2

3
21 -11
81234 94124 52141

Sample Output 2

3

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;
 
int main(){
 int N, T, A;
  cin >> N >> T >> A;
  
  vector<int> h(N);
  for(int i=0; i<N; i++){
    cin >> h.at(i);
  }
  vector<double> temp(N);
  for(int i=0; i<N; i++){
	temp.at(i) = T-h.at(i)*0.006;
  }
  vector<double> gap(N);
  for(int i=0; i<N; i++){
    if(temp.at(i) >= A){
      gap.at(i) = temp.at(i)-A;
    }
    else{
      gap.at(i) = A-temp.at(i);
    }
  }
    int ans = 1;
   for(int i=0; i<N-1; i++){
    if(gap.at(i) > gap.at(i+1)){
      ans = i+2;
    }
   }
    cout << ans << endl;
  }