Problem:
Score : 200 points

Problem Statement

Find the number of palindromic numbers among the integers between A and B (inclusive).
Here, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.

Constraints

10000 \leq A \leq B \leq 99999

All input values are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the number of palindromic numbers among the integers between A and B (inclusive).

Sample Input 1

11009 11332

Sample Output 1

4

There are four integers that satisfy the conditions: 11011, 11111, 11211 and 11311.

Sample Input 2

31415 92653

Sample Output 2

612

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
#define rep(i,n) for(int i=0;i<(n);i++)
using namespace std;
typedef long long ll;
typedef long double ld;
const double pi=acos(-1.0);
const ll mod=pow(10,9)+7;
const ll INF=pow(2,31)-1;
typedef pair<int,int> P;
typedef vector<int> vi;

template<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }
template<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }

ll gcd(ll a , ll b){
	if(b == 0) return a;
	return gcd(b , a % b);	
}
ll lcm(ll a , ll b){
	ll g = gcd(a , b);
	ll lc = (a/g) * b;
	return lc;
}

int main(){
    ios::sync_with_stdio(false);
    int a,b;
    cin >> a >> b;
    int ans=0;
    for(int i=a;i<=b;i++){
        int s=i%10, t=(i/10000)%10;
        int u=(i/10)%10, v=(i/1000)%10;
        if(s==t && u==v) ans++;
    }
    cout << ans << endl;
    return 0;
}