Problem:
Score : 300 points

Problem Statement

There are N people living on a number line.

The i-th person lives at coordinate X_i.

You are going to hold a meeting that all N people have to attend.

The meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.

Find the minimum total points of stamina the N people have to spend.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq X_i \leq 100

Input

Input is given from Standard Input in the following format:

N
X_1 X_2 ... X_N

Output

Print the minimum total stamina the N people have to spend.

Sample Input 1

2
1 4

Sample Output 1

5

Assume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.

Note that you can hold the meeting only at an integer coordinate.

Sample Input 2

7
14 14 2 13 56 2 37

Sample Output 2

2354

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<iostream>
using namespace std;
int main(){
	int n,i;
	int a[100];
	cin>>n;
	for(i=0;i<n;i++)
		cin>>a[i];
	int sum=0;
	for(i=0;i<n;i++){
		sum=sum+a[i];
	}
	int all=0,all1=0;
	int b,c;
	if(sum%n==0){
		b=sum/n;
		for(i=0;i<n;i++){
			all=(b-a[i])*(b-a[i])+all;
		}
	}
	else{
		b=sum/n;
		c=b+1;
		for(i=0;i<n;i++){
			all=(b-a[i])*(b-a[i])+all;
		}
		for(i=0;i<n;i++){
			all1=(c-a[i])*(c-a[i])+all1;
		}
		if(all>all1)
		all=all1;
		else
		all=all;
	}	
	cout<<all;
	return 0;
}