Problem:
Vector

For a dynamic array $A = \{a_0, a_1, ...\}$ of integers, perform a sequence of the following operations:

pushBack($x$): add element $x$ at the end of $A$

randomAccess($p$):print element $a_p$

popBack(): delete the last element of $A$

$A$ is a 0-origin array and it is empty in the initial state.

Input

The input is given in the following format.

$q$
$query_1$
$query_2$
:
$query_q$

Each query $query_i$ is given by

0 $x$

or

1 $p$

or

2

where the first digits 0, 1 and 2 represent pushBack, randomAccess and popBack operations respectively.

randomAccess and popBack operations will not be given for an empty array.

Output

For each randomAccess, print $a_p$ in a line.

Constraints

$1 \leq q \leq 200,000$

$0 \leq p < $ the size of $A$

$-1,000,000,000 \leq x \leq 1,000,000,000$

Sample Input 1

8
0 1
0 2
0 3
2
0 4
1 0
1 1
1 2

Sample Output 1

1
2
4

Solution in C++14 (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
//#include <boost/multiprecision/cpp_int.hpp>
//using multiInt = boost::multiprecision::cpp_int;

using ll = long long int;
using ld = long double;
using pii = pair<int, int>;
using pll = pair<ll, ll>;
template <typename Q_type>
using smaller_queue = priority_queue<Q_type, vector<Q_type>, greater<Q_type>>;

const int MOD_TYPE = 1;
const ll MOD = (MOD_TYPE == 1 ? (ll)(1e9 + 7) : 998244353);
const int INF = (int)1e9;
const ll LINF = (ll)4e18;
const double PI = acos(-1.0);

#define REP(i, m, n) for (ll i = m; i < (ll)(n); ++i)
#define rep(i, n) REP(i, 0, n)
#define MP make_pair
#define MT make_tuple
#define YES(n) cout << ((n) ? "YES" : "NO") << endl
#define Yes(n) cout << ((n) ? "Yes" : "No") << endl
#define Possible(n) cout << ((n) ? "Possible" : "Impossible") << endl
#define possible(n) cout << ((n) ? "possible" : "impossible") << endl
#define Yay(n) cout << ((n) ? "Yay!" : ":(") << endl
#define all(v) v.begin(), v.end()
#define NP(v) next_permutation(all(v))
#define dbg(x) cerr << #x << ":" << x << endl;

vector<int> Dx = {0, 0, -1, 1, -1, 1, -1, 1, 0};
vector<int> Dy = {1, -1, 0, 0, -1, -1, 1, 1, 0};

int main()
{
  cin.tie(0);
  ios::sync_with_stdio(false);
  cout << setprecision(50) << setiosflags(ios::fixed);
  vector<int> v;
  int q;
  cin >> q;
  rep(qi, q)
  {
    int type;
    cin >> type;
    if (type == 0)
    {
      int x;
      cin >> x;
      v.push_back(x);
    }
    else if (type == 1)
    {
      int p;
      cin >> p;
      cout << v[p] << endl;
    }
    else
    {
      v.pop_back();
    }
  }
  return 0;
}