Problem:
Score : 400 points

Problem Statement

Give a pair of integers (A, B) such that A^5-B^5 = X.
It is guaranteed that there exists such a pair for the given integer X.

Constraints

1 \leq X \leq 10^9

X is an integer.

There exists a pair of integers (A, B) satisfying the condition in Problem Statement.

Input

Input is given from Standard Input in the following format:

X

Output

Print A and B, with space in between.
If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.

A B

Sample Input 1

33

Sample Output 1

2 -1

For A=2 and B=-1, A^5-B^5 = 33.

Sample Input 2

1

Sample Output 2

0 -1

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
#define pb push_back
#define ef(i,u) for(int i=b[u];i;i=nxt[i])
#define rep(i,a,b) for(int i=a;i<=b;++i)
#define per(i,b,a) for(int i=b;i>=a;--i)
#define gcd(a,b) __gcd(a,b)
#define MEM(a,x) memset(a,x,sizeof(a))
#define VI vector<int>
#define PII pair<int,int>
#define ull unsigned long long
#define ll long long
#define fi first
#define se second
#define INF 0x3f3f3f3f
using namespace std;
const int N=2e5+5;
template<class T>inline void read(T &res)
{
char c;T flag=1;
while((c=getchar())<'0'||c>'9')if(c=='-')flag=-1;res=c-'0';
while((c=getchar())>='0'&&c<='9')res=res*10+c-'0';res*=flag;
}
ll x;
map<ll,ll>mp;
int main(){
    read(x);
    ll b=1;
    while(b*b*b*b*b<=1e11){
        mp[b*b*b*b*b]=b;
        b++;
    }
    for(ll i=1;i<=1e5;++i){
        ll t=i*i*i*i*i;
        if(x>t&&mp[x-t]){
            printf("%lld %lld\n",i,-mp[x-t]);
            break;
        }else if(x<t&&mp[t-x]){
            printf("%lld %lld\n",i,mp[t-x]);
            break;
        }else if(x==t){
            printf("%lld 0\n",i);
            break;
        }
    }
	return 0;
}