Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;

int main() {
  int N,A,B,C;
  cin >> N >> A >> B >> C;
  vector<string> choice(N);
  int NO = 0;
  char AB,BC,AC;
  for (int n = 0; n < N; n++) {
	cin >> choice[n];
    if( (choice[n] == "AB" && A == 0 && B == 0) || (choice[n] == "BC" && B == 0 && C == 0) || (choice[n] == "AC" && C == 0 && A == 0) ){
      NO++;
    }
    if(choice[n] == "AB" && A != 0){
       AB = 'A';
    }else if(choice[n] == "AB" && B != 0){
       AB = 'B';
    }
    if(choice[n] == "BC" && B != 0){
       BC = 'B';
    }else if(choice[n] == "BC" && C != 0){
       BC = 'C';
    }
    if(choice[n] == "AC" && A != 0){
        AC ='A';
    }else if(choice[n] == "AC" && C != 0){
        AC = 'C';
    }
  }
  if(NO > 0){
    cout << "No" << endl;
  }else {
    cout << "Yes" << endl;
    for (int n = 0; n < N; n++) {
		if(choice[n] == "AB"){
          cout << (char)AB << endl;
        } else if (choice[n] == "BC"){
          cout << (char)BC << endl;
        } else if (choice[n] == "AC"){
          cout << (char)AC << endl;
        }
    }
  }
}