Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <cmath>
#include <vector>
#include <cstdlib>
#include <stdio.h>


using namespace std;

int main(int argc, char *argv[]){

  /*

  4/N = 1/h + 1/n + 1/w
  */

  int N;
  if(argc == 2){
    N = atoi(argv[1]);
  }
  else{
    cin >> N;
  }
  unsigned int h, n, w;

  for(int h = 1; h < 3500; h++){
    for(int n = h; n < 3500; n++){
      long long int tmp = 4*h*n - (n+h)*N;
      if(tmp <= 0) continue;
      long long int tmp2 = N*h*n;
      w = (int)(tmp2 / tmp);
      //if(w < n) continue;

      if(N == (  4*h*n*w / (n*w + h*(n+w))  ) ){
        printf("%u %u %u\n", h, n, w);
        return 0;
      }
    }
  }

  return 0;
}