Problem:
Score : 300 points

Problem Statement

Takahashi, Nakahashi and Hikuhashi have integers A, B and C, respectively.
After repeating the following operation K times, find the integer Takahashi will get minus the integer Nakahashi will get:

Each of them simultaneously calculate the sum of the integers that the other two people have, then replace his own integer with the result.

However, if the absolute value of the answer exceeds 10^{18}, print Unfair instead.

Constraints

1 \leq A,B,C \leq 10^9

0 \leq K \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B C K

Output

Print the integer Takahashi will get minus the integer Nakahashi will get, after repeating the following operation K times.
If the absolute value of the answer exceeds 10^{18}, print Unfair instead.

Sample Input 1

1 2 3 1

Sample Output 1

1

After one operation, Takahashi, Nakahashi and Hikuhashi have 5, 4 and 3, respectively. We should print 5-4=1.

Sample Input 2

2 3 2 0

Sample Output 2

-1

Sample Input 3

1000000000 1000000000 1000000000 1000000000000000000

Sample Output 3

0

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;

typedef long long ll;
typedef pair<int, int> pi;

#define rep(i, n) for (int i = 0; i < n; i++)
#define rep_op(i, a, n) for (int i = a; i < n; i++)
#define rep_d(j, n) for (int j = n; j >= 0; j--)
#define rep_d_op(j, n, a) for (int j = n; j >= a; j--)

template <class T>
inline bool chmax(T &a, T b)
{
    if (a < b)
    {
        a = b;
        return 1;
    }
    return 0;
}
template <class T>
inline bool chmin(T &a, T b)
{
    if (a > b)
    {
        a = b;
        return 1;
    }
    return 0;
}

const int MOD = 1000000007;

const vector<int> dx = {1, 0};
const vector<int> dy = {0, 1};
const ll INF = 1LL << 60;

// int max = *std::max_element(vec.begin(), vec.end());
// int sum = accumulate(list, list + size, 0);

int GCD(int a, int b) { return b ? GCD(b, a % b) : a; }

using Graph = vector<vector<int>>;

Graph G;

vector<bool> seen;
void dfs(const Graph &G, int v)
{
    seen[v] = true;

    for (auto next_v : G[v])
    {
        if (seen[next_v])
            continue;
        dfs(G, next_v);
    }
}

int main()
{

    long long a, b;
    cin >> a >> b;
    if (abs(b - a) > 1000000000000000000)
    {
        cout << "Unfair" << endl;
    }
    cout << a - b << endl;
}