Problem:
Score : 200 points

Problem Statement

Two children are playing tag on a number line. (In the game of tag, the child called "it" tries to catch the other child.) The child who is "it" is now at coordinate A, and he can travel the distance of V per second.
The other child is now at coordinate B, and she can travel the distance of W per second.

He can catch her when his coordinate is the same as hers.
Determine whether he can catch her within T seconds (including exactly T seconds later).
We assume that both children move optimally.

Constraints

-10^9 \leq A,B \leq 10^9

1 \leq V,W \leq 10^9

1 \leq T \leq 10^9

A \neq B

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A V
B W
T

Output

If "it" can catch the other child, print YES; otherwise, print NO.

Sample Input 1

1 2
3 1
3

Sample Output 1

YES

Sample Input 2

1 2
3 2
3

Sample Output 2

NO

Sample Input 3

1 2
3 3
3

Sample Output 3

NO

Solution in C++ (Clang 10.0.0) (judge verdict: Wrong Answer)

#include <iostream>
#include <cmath>
#include <algorithm>
#include <string>
#include <vector>
#include <list>
#include <set>
#include <map>
#include <iostream>
#include <queue>

using namespace std;

typedef unsigned int u32;
typedef int i32;
typedef unsigned long long int u64;
typedef long long int i64; // 9e18
typedef uint16_t u16;
typedef int16_t i16;
typedef uint8_t u8;
typedef int8_t i8;

const double PI = 3.141592653589793238463;
const int MAXN = 1000500;
const int MAXVALUE = 1000000500;
const long double EPS = 1e-7;
const i64 INF = 1e18;
i64 mod = 1e9 + 7;


i64 T, n, m, k;
//vector <vector<i64>> a;
//vector <i64> a;
//vector <i64> b;
vector <i64> dp;


int main() {
    ios_base::sync_with_stdio(0);
    cin.tie(0);
    cout.precision(16);

    i64 a, b, v, w, t;

    cin >> a >> v >> b >> w >> t;

    bool fl = false;

    if (v > w) {
        i64 dv = v - w;
        i64 s = abs(a - b);
        i64 dt = s / dv + (i64)(bool)(s % dv);
        if (dt <= t) {
            fl = true;
        }
    }

    if (fl) {
        cout << "Yes" << endl;
    }
    else {
        cout << "No" << endl;
    }


    return 0;
}