Problem:
Score : 200 points

Problem Statement

There are some animals in a garden. Each of them is a crane with two legs or a turtle with four legs.

Takahashi says: "there are X animals in total in the garden, and they have Y legs in total." Determine whether there is a combination of numbers of cranes and turtles in which this statement is correct.

Constraints

1 \leq X \leq 100

1 \leq Y \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

If there is a combination of numbers of cranes and turtles in which the statement is correct, print Yes; otherwise, print No.

Sample Input 1

3 8

Sample Output 1

Yes

The statement "there are 3 animals in total in the garden, and they have 8 legs in total" is correct if there are two cranes and one turtle. Thus, there is a combination of numbers of cranes and turtles in which the statement is correct.

Sample Input 2

2 100

Sample Output 2

No

There is no combination of numbers of cranes and turtles in which this statement is correct.

Sample Input 3

1 2

Sample Output 3

Yes

We also consider the case in which there are only cranes or only turtles.

Solution in C++ (Clang 10.0.0) (judge verdict: Wrong Answer)

#include <iostream>
#include <string>
using namespace std;
int main()
{
 long long int x,y;
 cin >> x >> y;
 if (x>=1 && y>=1)
     {if(y%2==0 && y/2==x)
        cout << "Yes";
     else if(y%2==0 && y/2==x+1)
        cout<< "Yes"; 
     else if(y%4==0 && y/4==x)
        cout<< "Yes";
    else if(y%4==0 && (y/4)+1==x)
        cout<< "Yes"; 
     else if(y%4==2 && ((y/4)+1)==x)
        cout<< "Yes";
     else if(y%4==2 && ((y/4)+2)==x)
        cout<< "Yes"; 
     else if(y%4==2 && ((y/4)+3)==x)
        cout<< "Yes"; 
     else
        cout <<"No";
     }
else
    return 0;
}