Problem:
Score : 500 points

Problem Statement

N players will participate in a tennis tournament. We will call them Player 1, Player 2, \ldots, Player N.

The tournament is round-robin format, and there will be N(N-1)/2 matches in total.
Is it possible to schedule these matches so that all of the following conditions are satisfied? If the answer is yes, also find the minimum number of days required.

Each player plays at most one matches in a day.

Each player i (1 \leq i \leq N) plays one match against Player A_{i, 1}, A_{i, 2}, \ldots, A_{i, N-1} in this order.

Constraints

3 \leq N \leq 1000

1 \leq A_{i, j} \leq N

A_{i, j} \neq i

A_{i, 1}, A_{i, 2}, \ldots, A_{i, N-1} are all different.

Input

Input is given from Standard Input in the following format:

N
A_{1, 1} A_{1, 2} \ldots A_{1, N-1}
A_{2, 1} A_{2, 2} \ldots A_{2, N-1}
:
A_{N, 1} A_{N, 2} \ldots A_{N, N-1}

Output

If it is possible to schedule all the matches so that all of the conditions are satisfied, print the minimum number of days required; if it is impossible, print -1.

Sample Input 1

3
2 3
1 3
1 2

Sample Output 1

3

All the conditions can be satisfied if the matches are scheduled for three days as follows:

Day 1: Player 1 vs Player 2

Day 2: Player 1 vs Player 3

Day 3: Player 2 vs Player 3

This is the minimum number of days required.

Sample Input 2

4
2 3 4
1 3 4
4 1 2
3 1 2

Sample Output 2

4

All the conditions can be satisfied if the matches are scheduled for four days as follows:

Day 1: Player 1 vs Player 2, Player 3 vs Player 4

Day 2: Player 1 vs Player 3

Day 3: Player 1 vs Player 4, Player 2 vs Player 3

Day 4: Player 2 vs Player 4

This is the minimum number of days required.

Sample Input 3

3
2 3
3 1
1 2

Sample Output 3

-1

Any scheduling of the matches violates some condition.

Solution in C++14 (GCC 5.4.1) (judge verdict: Time Limit Exceeded)

#define _USE_MATH_DEFINES
#include<iostream>
#include<cstring>
#include<string>
#include<cmath>
#include<vector>
#include<algorithm>
#include<iterator>
#include<sstream>
#include<iomanip>
#include<map>
#include<queue>
#include<deque>
#include<fstream>
#include<random>

#define rep(i, n) for (ll i = 0; i < n; i++) 
#define rrep(i, n) for(ll i = n-1; i>=0; i--)
#define range(i, n, m) for (ll i = n; i < m; i++) 
#define rrange(i, n, m) for (ll i = n - 1; i => m; i--) 
#define MOD 1000000007
#define pb push_back
#define mp make_pair
#define vl vector<ll>
#define vvl vector<vector<ll> >
#define vp vector<pair<ll, ll> >
#define vvp vector<vector<pair<ll, ll> > >
#define First first
#define Second second.first
#define Third second.second
#define Sort(X) sort(X.begin(), X.end())
#define RSort(X, T) sort(X.begin(), X.end(), greater<T>())
//#define MOD 998244353
#define MAX 100000

typedef long long int ll;
typedef unsigned long long int ull;

using namespace std;

template<class T> inline bool chmax(T & a, T b) { if (a < b) { a = b; return true; } return false; }
template<class T> inline bool chmin(T & a, T b) { if (a > b) { a = b; return true; } return false; }

int main() {
	cin.tie(0);
	ios::sync_with_stdio(false);

	ll N;
	cin >> N;

	vvl A(N, vl(N-1));
	rep(i, N) {
		rep(k, N-1) {
			cin >> A[i][k];
		}
	}

	vl C(N);
	vector<bool> INIT(N, false);
	vector<bool> end(N, false);
	bool flg = false;
	ll cnt = 0;
	ll cend = 0;
	while(true){
		flg = false;
		vector<bool> S(INIT);
		rep(k, N) {
			if (end[k]) continue;
			if (S[k]) continue;
			ll r = A[k][C[k]] - 1;
			if (S[r]) continue;
			if (A[r][C[r]] - 1 != k) continue;
			flg = true;
			S[k] = S[r] = true;
			C[r]++;
			C[k]++;
			if (C[k] >= (N - 1)) {
				end[k] = true;
				cend++;
			}
			if (C[r] >= (N - 1)) {
				end[r] = true;
				cend++;
			}
		}
		if (!flg) {
			cout << -1 << endl;
			return 0;
		}
		cnt++;
		if (cend == N)break;
	}

	cout << cnt << endl;

	return 0;
}