Problem:
Score : 200 points

Problem Statement

There are some animals in a garden. Each of them is a crane with two legs or a turtle with four legs.

Takahashi says: "there are X animals in total in the garden, and they have Y legs in total." Determine whether there is a combination of numbers of cranes and turtles in which this statement is correct.

Constraints

1 \leq X \leq 100

1 \leq Y \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

If there is a combination of numbers of cranes and turtles in which the statement is correct, print Yes; otherwise, print No.

Sample Input 1

3 8

Sample Output 1

Yes

The statement "there are 3 animals in total in the garden, and they have 8 legs in total" is correct if there are two cranes and one turtle. Thus, there is a combination of numbers of cranes and turtles in which the statement is correct.

Sample Input 2

2 100

Sample Output 2

No

There is no combination of numbers of cranes and turtles in which this statement is correct.

Sample Input 3

1 2

Sample Output 3

Yes

We also consider the case in which there are only cranes or only turtles.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include "bits/stdc++.h"
#define ll long long
#define lld long double
#define MOD 1000000007LL
#define inf 1000000000000000000ll
#define pii pair<int,int>
#define f first
#define s second
#define pb push_back
#define mp make_pair
#define all(v) v.begin(),v.end()
#define fast ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);
ll power(ll x,ll y, ll md=MOD){ll res = 1;x%=md;while(y){if(y&1)res = (res*x)%md;x *= x; if(x>=md) x %= md; y >>= 1;}return res;}
 
using namespace std;

#define endl '\n'
#define int ll

struct node {
	vector<int> v,w;
};



signed main() {
	fast;

	int x,y;
	cin>>x>>y;

	if(y%2==1) {cout<<"No";return 0;}

	int a = 2*x - y/2;
	int b = y/2 - x;

	if(a<0||b<0) {cout<<"No";return 0;}
	cout<<"Yes";

}