Problem:
Score : 100 points

Problem Statement

We have five variables x_1, x_2, x_3, x_4, and x_5.

The variable x_i was initially assigned a value of i.

Snuke chose one of these variables and assigned it 0.

You are given the values of the five variables after this assignment.

Find out which variable Snuke assigned 0.

Constraints

The values of x_1, x_2, x_3, x_4, and x_5 given as input are a possible outcome of the assignment by Snuke.

Input

Input is given from Standard Input in the following format:

x_1 x_2 x_3 x_4 x_5

Output

If the variable Snuke assigned 0 was x_i, print the integer i.

Sample Input 1

0 2 3 4 5

Sample Output 1

1

In this case, Snuke assigned 0 to x_1, so we should print 1.

Sample Input 2

1 2 0 4 5

Sample Output 2

3

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;

#define INF 2147483647
#define LINF 9223372036854775807
#define MOD 1000000007
#define MOD2 998244353

template<class T,class U>bool chmax(T &a, const U &b){if(a<b){a=b;return 1;}return 0;}
template<class T,class U>bool chmin(T &a, const U &b){if(b<a){a=b;return 1;}return 0;}

#define rep(i,n) for(int i=0,_i=(n);i<_i;++i)
#define rep1(i,a,b) for(int a_=(a),b_=(b),i=a_;i<b_;++i)
#define repr(i,n) for(int _i=(n),i=_i;i>0;--i)

#define db(x) cerr<<#x<<" = "<<x<<" ";
#define db2(x,y) cerr<<"("<<#x<<", "<<#y<<") = ("<<x<<", "<<y<<") ";
#define db3(x,y,z) cerr<<"("<<#x<<", "<<#y<<", "<<#z<<") = ("<<x<<", "<<y<<", "<<z<<") ";
#define ln cout<<endl;

#define all(a)  (a).begin(),(a).end()
#define dig(n)  to_string(n).length()

#define pb push_back
#define eb emplace_back
#define mp make_pair
#define se second
#define fi first

typedef long long ll;
typedef long double ld;

typedef pair<int,int> P;
typedef pair<int,P> iP;
typedef pair<P,P> PP;

ll gcd(ll a,ll b){return b?gcd(b,a%b):a;}
ll lcm(ll a,ll b){return (a*b)/gcd(a,b);}

int dx[4]={1,0,-1,0};
int dy[4]={0,1,0,-1};





int main(){

    bool flag=false;
    ll ans=0,sum=0;

    int a[5]={};
    
    rep(i,5){
        int xi;
        cin>>xi;

        if(xi!=0)a[xi-1] = 1;
    }

    rep(i,5){
        if(a[i] == 0)ans = i+1;
    }


    cout<<ans<<endl;

    //cout <<fixed<<setprecision(16)<< << endl;

    //if(flag)cout << "Yes" <<endl;
    //else cout << "No" <<endl;

    return 0;
}