Problem:
Score : 400 points

Problem Statement

You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

In the i-th operation, you replace every element whose value is B_{i} with C_{i}.

For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

All values in input are integers.

1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}

B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:

N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}

Output

Print Q integers S_{i} to Standard Output in the following format:

S_{1}
S_{2}
\vdots
S_{Q}

Note that S_{i} may not fit into a 32-bit integer.

Sample Input 1

4
1 2 3 4
3
1 2
3 4
2 4

Sample Output 1

11
12
16

Initially, the sequence A is 1,2,3,4.

After each operation, it becomes the following:

2, 2, 3, 4

2, 2, 4, 4

4, 4, 4, 4

Sample Input 2

4
1 1 1 1
3
1 2
2 1
3 5

Sample Output 2

8
4
4

Note that the sequence A may not contain an element whose value is B_{i}.

Sample Input 3

2
1 2
3
1 100
2 100
100 1000

Sample Output 3

102
200
2000

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;
#define int long long
#define pb push_back
#define all(a) a.begin(),a.end()
#define fi first
#define se second
#define deb(x) cout << #x << "=" << x << endl
#define clr(x) memset(x, 0, sizeof(x))
#define rep(i,k,n) for(i=k;k<n?i<n:i>n;k<n?i+=1:i-=1)
int M=1e9+7,N=205001;

int mm(int x,int y){x%=M,y%=M;return (x*y)%M;}//Modular Multiply
int po(int x,int y){ if(!y)return 1;int a=po(x,y/2)%M;if(y%2)return mm(a,mm(a,x));return mm(a,a);}//(x**y)%M



void solve() {
	int n,m,i,k,s=0,x,y;
	cin>>n;
	int a[n];
	map<int,int> mp;
	rep(i,0,n) {
		cin>>a[i];
		s+=a[i];
		mp[a[i]]++;
	}
	cin>>m;
	while(m--){
		cin>>x>>y;
		int f=mp[x];
		mp[y]+=f;
		mp[x]-=f;
		s+=f*(y-x);
		cout<<s<<"\n";
	}
	

	
}


signed main(){
ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
	int t=1;
	//cin>>t;
	while(t--) solve();
	return 0;
}