Problem:
Score : 100 points

Problem Statement

We have two integers: A and B.

Print the largest number among A + B, A - B, and A \times B.

Constraints

All values in input are integers.

-100 \leq A,\ B \leq 100

Input

Input is given from Standard Input in the following format:

A B

Output

Print the largest number among A + B, A - B, and A \times B.

Sample Input 1

-13 3

Sample Output 1

-10

The largest number among A + B = -10, A - B = -16, and A \times B = -39 is -10.

Sample Input 2

1 -33

Sample Output 2

34

The largest number among A + B = -32, A - B = 34, and A \times B = -33 is 34.

Sample Input 3

13 3

Sample Output 3

39

The largest number among A + B = 16, A - B = 10, and A \times B = 39 is 39.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

/*
RAone00
Rohit sharma
*/

#include <bits/stdc++.h>
using namespace std;

typedef long long ll;
typedef long double ld;
typedef pair < ll, ll > pll;
typedef vector < vector < ll > > matrix;
typedef vector < ll > vll;

#define pb push_back
#define debug(x) cout << (#x) << " is " << (x) << endl
#define fast_io() ios_base :: sync_with_stdio(0); cin.tie(0); cout.tie(0)

const ll mod = 1e9 + 7;
const ll inf = LLONG_MAX;
const ll N = 1e5 + 10;

int main() {
    fast_io();
    int a, s;
    cin >> a >> s;
    int n1 = (a + s);
    int n2 = (a - s);
    int n3 = (a * s);
        if(n1 >= n2 && n1 >= n3)
    {
        cout << n1 << "\n";
    }
    if(n2 >= n1 && n2 >= n3)
    {
        cout << n2 << "\n";
    }
    if(n3 >= n1 && n3 >= n2) {
        cout << n3 << "\n";
    }
    return 0;
}