Problem:
Score : 400 points

Problem Statement

Given is an integer S.
Find a combination of six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfies all of the following conditions:

0 \leq X_1,Y_1,X_2,Y_2,X_3,Y_3 \leq 10^9

The area of the triangle in a two-dimensional plane whose vertices are (X_1,Y_1),(X_2,Y_2), and (X_3,Y_3) is S/2.

We can prove that there always exist six integers that satisfy the conditions under the constraints of this problem.

Constraints

1 \leq S \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

S

Output

Print six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfy the conditions, in this order, with spaces in between.
If multiple solutions exist, any of them will be accepted.

Sample Input 1

3

Sample Output 1

1 0 2 2 0 1

The area of the triangle in a two-dimensional plane whose vertices are (1,0),(2,2), and (0,1) is 3/2.
Printing 3 0 3 1 0 1 or 1 0 0 1 2 2 will also be accepted.

Sample Input 2

100

Sample Output 2

0 0 10 0 0 10

Sample Input 3

311114770564041497

Sample Output 3

314159265 358979323 846264338 327950288 419716939 937510582

Solution in C++14 (GCC 5.4.1) (judge verdict: Time Limit Exceeded)

#include<stdio.h>
#include<math.h>
typedef long long ll;
int main ()
{
    long long s,i,a,b,flag=0,j;
    scanf("%lld",&s);
    if(s<1000000000)
    {
        printf("%lld 1 %lld 0 0 0\n",s,s);
    }
    else
    {
        if((ll)(((ll)sqrt(s)) * ((ll)sqrt(s))) == s)
        {
            printf("0 %lld %lld 0 0 0\n",(ll)sqrt(s),(ll)sqrt(s));
        }
        else
        {
            for(i=(ll)sqrt(s),j=(ll)sqrt(s)-1; ; i++,j--)
            {
                if(s%i==0&&s/i<=1000000000)
                {
                    flag=1;
                    break;
                }
                if(s%j==0&&s/j<=1000000000&&j>=1)
                {
                    flag=2;
                    break;
                }
            }
            if(flag==1)
                printf("0 %lld %lld 0 0 0\n",i,s/i);
           if(flag==2)
                printf("0 %lld %lld 0 0 0\n",j,s/j);
        }
    }
    return 0;
}