Problem:
Score : 100 points

Problem Statement

A Hitachi string is a concatenation of one or more copies of the string hi.

For example, hi and hihi are Hitachi strings, while ha and hii are not.

Given a string S, determine whether S is a Hitachi string.

Constraints

The length of S is between 1 and 10 (inclusive).

S is a string consisting of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S

Output

If S is a Hitachi string, print Yes; otherwise, print No.

Sample Input 1

hihi

Sample Output 1

Yes

hihi is the concatenation of two copies of hi, so it is a Hitachi string.

Sample Input 2

hi

Sample Output 2

Yes

Sample Input 3

ha

Sample Output 3

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define pb push_back
#define mp make_pair
#define f(i,a,n) for(int i=a;i<n;i++)
#define ve vector
#define ss second 
#define ff first
#define pf pop_front
#define pob pop_back
#define psf push_front
#define res(x) cout<<x<<'\n'
#define read(t) ll t;cin>>t

int main(){

    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
	cout.tie(NULL);
    string s;
    cin>>s;
    int n=s.length();
    bool ans=true;
    f(i,0,n){
        if(i%2==0){
            if(s[i]!='h'){
                ans=false;
            }
        }
        else {
            if(s[i]!='i'){
                ans=false;
            }
        }
    }
    if(ans){
        cout<<"Yes"<<endl;
    }
    else{
        cout<<"No"<<endl;
    }
    
    


   

}