Problem:
Score : 200 points

Problem Statement

There are N children, numbered 1, 2, ..., N.

Snuke has decided to distribute x sweets among them.
He needs to give out all the x sweets, but some of the children may get zero sweets.

For each i (1 \leq i \leq N), Child i will be happy if he/she gets exactly a_i sweets.
Snuke is trying to maximize the number of happy children by optimally distributing the sweets.
Find the maximum possible number of happy children.

Constraints

All values in input are integers.

2 \leq N \leq 100

1 \leq x \leq 10^9

1 \leq a_i \leq 10^9

Input

Input is given from Standard Input in the following format:

N x
a_1 a_2 ... a_N

Output

Print the maximum possible number of happy children.

Sample Input 1

3 70
20 30 10

Sample Output 1

2

One optimal way to distribute sweets is (20, 30, 20).

Sample Input 2

3 10
20 30 10

Sample Output 2

1

The optimal way to distribute sweets is (0, 0, 10).

Sample Input 3

4 1111
1 10 100 1000

Sample Output 3

4

The optimal way to distribute sweets is (1, 10, 100, 1000).

Sample Input 4

2 10
20 20

Sample Output 4

0

No children will be happy, no matter how the sweets are distributed.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

//#include <ext/pb_ds/assoc_container.hpp> // Common file
//#include <ext/pb_ds/tree_policy.hpp> // Including tree_order_statistics_node_update
//#include <ext/pb_ds/detail/standard_policies.hpp>
#include<set>
#include<map>
#include <unordered_map>
#include <unordered_set>
#include<list>
#include<iomanip>
#include<cmath>
#include<string>
#include<vector>
#include<queue>
#include<stack>
#include<complex>
#include<sstream>
#include<iostream>
#include<fstream>
#include<algorithm>
#include<numeric>
#include<utility>
#include<functional>
#include<stdio.h>
#include<assert.h>
#include<memory.h>
#include<bitset>
#include<math.h>
#include <strings.h>
#include <fstream>
#include <random>


#define f first
#define s second
#define pb push_back
#define lp(i,a,n) for(int (i)=(a);(i)<=(int)(n);(i)++)
#define lpd(i,n,a) for(int (i)=(n);(i)>=(a);--(i))
#define mp make_pair
#define clr(a, b) memset(a,b,sizeof a)
#define all(v) v.begin(),v.end()
#define mod 1000000007ll
#define eps 1e-10
#define infi 1000000107
#define infll 1000000000000000000ll
#define MX 1000000
#define X real()
#define Y imag()
#define left(i) i<<1
#define right(i) (i<<1)|1
#define polar(r,t) ((r)* exp(point(0,(t))))
#define length(a) hypot( (a).X , (a).Y )
#define angle(a) atan2( (a).Y , (a).X )
#define vec(a,b) ( (b) - (a) )
#define dot(a,b) (conj(a)*(b)).X
#define cross(a,b) (conj(a)*(b)).Y
#define lengthsqr(a) dot(a,a)
#define reflect(V,M) (conj((V)/(M)) * (M))
//#define rotate(a, theta) (a) * (polar(1.0, (theta) ))
#define normalize(a)   ((a)/length(a))
#define ccw(a,b,c) cross(vec(a,b) , vec(a,c)) > eps
#define cosRule(a,b,c) (acos(((a)*(a)+(b)*(b)-(c)*(c))/(2*(a)*(b))))
#define cosDot(a,b) (acos(dot(a,b)/length(a)/length(b)))
#define EQ(a,b) (fabs((a) - (b)) <= eps) /* equal to */
#define NE(a,b) (fabs((a) - (b)) > eps)  /* not equal to */
#define LT(a,b) ((a) < (b) - eps)        /* less than */
#define GT(a,b) ((a) > (b) + eps)        /* greater than */
#define LE(a,b) ((a) <= (b) + eps)       /* less than or equal to */
#define GE(a,b) ((a) >= (b) - eps)       /* greater than or equal to */
#define mod1 1000500001ll
#define mod2 1000300001ll
#define base1 137ll
#define base2 31ll
#define PI acos(-1.0l)
#define sz(a) (int) (a).size()
#define isbit(x,k)  ((x) & (1<<(k))) > 0


using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef unsigned int ui;
typedef pair<int, int> pii;
typedef pair<double,double> pdd;
typedef pair<ll, ll> pll;
typedef vector<int> vi;
typedef vector<ll> vll;
typedef vector<vi> vvi;
typedef set<int> si;
typedef map<int, int> mii;
typedef map<ll, ll> mll;
typedef long double ld;
typedef pair<ld, ld> pld;
typedef complex<ld> point;
typedef pair<point, point> line;
typedef pair<ld , point> Circle;
typedef pair<point, int> Point;

const int N = 100002;

int n,x,a[N];


int main(){
    
    scanf("%d",&n);
    scanf("%d",&x);
    
    lp(i, 1, n) scanf("%d",&a[i]);
    
    sort(a+1, a+n+1);
    

    lp(i, 1, n) {
        if(a[i] <= x) x -= a[i];
        else {
            printf("%d\n", i-1);
            return 0;
        }
    }

    printf("%d\n",n-(x>0));
    return 0;
}

/*
 
 3
 5
 2 7
 3
 -1 0 -8
 0 -3
 -2
 
 
 
 3
 5
 -2 -7
 -3
 1 0 8
 0 3
 2
 
 
 
 
 */