Problem:
﻿Score: 100 points

Problem Statement

In AtCoder city, there are five antennas standing in a straight line. They are called Antenna A, B, C, D and E from west to east, and their coordinates are a, b, c, d and e, respectively.

Two antennas can communicate directly if the distance between them is k or less, and they cannot if the distance is greater than k.

Determine if there exists a pair of antennas that cannot communicate directly.

Here, assume that the distance between two antennas at coordinates p and q (p < q) is q - p.

Constraints

a, b, c, d, e and k are integers between 0 and 123 (inclusive).

a < b < c < d < e

Input

Input is given from Standard Input in the following format:

a
b
c
d
e
k

Output

Print :( if there exists a pair of antennas that cannot communicate directly, and print Yay! if there is no such pair.

Sample Input 1

1
2
4
8
9
15

Sample Output 1

Yay!

In this case, there is no pair of antennas that cannot communicate directly, because:

the distance between A and B is 2 - 1 = 1

the distance between A and C is 4 - 1 = 3

the distance between A and D is 8 - 1 = 7

the distance between A and E is 9 - 1 = 8

the distance between B and C is 4 - 2 = 2

the distance between B and D is 8 - 2 = 6

the distance between B and E is 9 - 2 = 7

the distance between C and D is 8 - 4 = 4

the distance between C and E is 9 - 4 = 5

the distance between D and E is 9 - 8 = 1

and none of them is greater than 15. Thus, the correct output is Yay!.

Sample Input 2

15
18
26
35
36
18

Sample Output 2

:(

In this case, the distance between antennas A and D is 35 - 15 = 20 and exceeds 18, so they cannot communicate directly.
Thus, the correct output is :(.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<bits/stdc++.h>

using namespace std;

typedef long long int llint;
typedef pair<int, int> pii;
typedef pair<llint, llint> pll;
typedef vector<int> vi;
typedef vector<llint> vl;
typedef vector<pii> vii;
typedef vector<pll> vll;

#define ci cin
#define co cout
#define en endl
#define ln cout<< '\n'
#define rep(i, n) for(int i = 0; i < n; i++)
#define outl(x) cout<< (x) << '\n'
#define pb push_back
#define fi first
#define se second
#define MOD 1000000007

template<typename Tn> Tn gcd(Tn a, Tn b)
{
    return (b ? gcd(b, a % b) : a);
}

template<typename Tn> Tn lcm(Tn a, Tn b)
{
    return a / gcd(a, b) * b;
}

string IntToString(int number)
{
    stringstream ss;
    ss << number;
    return ss.str();
}

int main()
{
    int a[10];
    int k;
    rep(i, 5) ci >> a[i];
    ci >> k;

    bool ans = true;
    rep(i, 5) rep(j, 5)
	if(abs(a[i] - a[j]) > k) ans = false;

    if(ans) co << "Yay!" << en;
    else    co << ":(" << en;
    
    return 0;
}