Problem:
Score : 200 points

Problem Statement

When Mr. X is away from home, he has decided to use his smartwatch to search the best route to go back home, to participate in ABC.

You, the smartwatch, has found N routes to his home.

If Mr. X uses the i-th of these routes, he will get home in time t_i at cost c_i.

Find the smallest cost of a route that takes not longer than time T.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq T \leq 1000

1 \leq c_i \leq 1000

1 \leq t_i \leq 1000

The pairs (c_i, t_i) are distinct.

Input

Input is given from Standard Input in the following format:

N T
c_1 t_1
c_2 t_2
:
c_N t_N

Output

Print the smallest cost of a route that takes not longer than time T.

If there is no route that takes not longer than time T, print TLE instead.

Sample Input 1

3 70
7 60
1 80
4 50

Sample Output 1

4

The first route gets him home at cost 7.

The second route takes longer than time T = 70.

The third route gets him home at cost 4.

Thus, the cost 4 of the third route is the minimum.

Sample Input 2

4 3
1 1000
2 4
3 1000
4 500

Sample Output 2

TLE

There is no route that takes not longer than time T = 3.

Sample Input 3

5 9
25 8
5 9
4 10
1000 1000
6 1

Sample Output 3

5

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <string>
#include <vector>
#include <list>
#include <algorithm>
#include <numeric>
#include <cmath>
#include <set>
#include <map>
#include <queue>
#include <stack>
#include <functional>
#include <utility>
#include <cctype>
#include <fstream>

using namespace std;

#define ll long long
#define INF 2000000000
#define LINF 9000000000000000000
#define rep(i,n) for(int i=0;i<(int)n;i++)
#define du(x) cout<<#x<<'='<<x<<endl
#define du2(x,y) cout<<#x<<'='<<x<<' '<<#y<<'='<<y<<'\n'<<endl
#define du3(x,y,z) cout<<#x<<'='<<x<<' '<<#y<<'='<<y<<' '<<#z<<'='<<z<<'\n'<<endl
#define darr(arr,n) rep(i,(n-arr)){cout<<*(arr+i)<<' ';}cout<<endl
#define ddarr(arr,a,b) rep(i,a){rep(j,b){cout<<*(arr+i*b+j)<<' ';}cout<<endl;}
#define ddd ifstream in("Text.txt");cin.rdbuf(in.rdbuf());

int c[1000], t[1000];

int main() {
    int N, T;
    cin >> N >> T;
    rep(i, N)cin >> c[i] >> t[i];

    int mi = INF;
    rep(i, N) {
        if (t[i] <= T) {
            mi = min(c[i], mi);
        }
    }
    if (mi == INF) {
        cout << "TLE" << endl;
    }
    else cout << mi << endl;

}