Problem:
Score : 100 points

Problem Statement

In programming, hexadecimal notation is often used.

In hexadecimal notation, besides the ten digits 0, 1, ..., 9, the six letters A, B, C, D, E and F are used to represent the values 10, 11, 12, 13, 14 and 15, respectively.

In this problem, you are given two letters X and Y. Each X and Y is A, B, C, D, E or F.

When X and Y are seen as hexadecimal numbers, which is larger?

Constraints

Each X and Y is A, B, C, D, E or F.

Input

Input is given from Standard Input in the following format:

X Y

Output

If X is smaller, print <; if Y is smaller, print >; if they are equal, print =.

Sample Input 1

A B

Sample Output 1

<

10 < 11.

Sample Input 2

E C

Sample Output 2

>

14 > 12.

Sample Input 3

F F

Sample Output 3

=

15 = 15.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <iostream>
#include <cmath>
#include <complex>
#include <string>
#include <sstream>
#include <limits>
#include <algorithm>
#include <functional>

#include <map>

using namespace std;

int main()
{
	ios::sync_with_stdio(false);
	cin.tie(nullptr);
	cout.tie(nullptr);

	char A, B;
	cin >> A >> B;

	map<char, int> value_pair;
	value_pair['A'] = 10;
	value_pair['B'] = 11;
	value_pair['C'] = 12;
	value_pair['D'] = 13;
	value_pair['E'] = 14;
	value_pair['F'] = 15;

	if (value_pair[A] < value_pair[B])
	{
		cout << "<";
	}
	else if (value_pair[A] > value_pair[B])
	{
		cout << ">";
	}
	else
	{
		cout << "=";
	}

	return 0;
}