Problem:
Score : 100 points

Problem Statement

Snuke built an online judge to hold a programming contest.

When a program is submitted to the judge, the judge returns a verdict, which is a two-character string that appears in the string S as a contiguous substring.
(The judge can return any two-character substring of S.)

Determine whether the judge can return the string AC as the verdict to a program.

Constraints

2 \leq |S| \leq 5

S consists of uppercase English letters.

Input

Input is given from Standard Input in the following format:

S

Output

If the judge can return the string AC as a verdict to a program, print Yes; if it cannot, print No.

Sample Input 1

BACD

Sample Output 1

Yes

The string AC appears in BACD as a contiguous substring (the second and third characters).

Sample Input 2

ABCD

Sample Output 2

No

Although the string ABCD contains both A and C (the first and third characters), the string AC does not appear in ABCD as a contiguous substring.

Sample Input 3

CABD

Sample Output 3

No

Sample Input 4

ACACA

Sample Output 4

Yes

Sample Input 5

XX

Sample Output 5

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <set>
#include <map>
#include <list>
#include <queue>
#include <stack>
#include <cmath>
#include <ctime>
#include <cstdio>
#include <vector>
#include <string>
#include <bitset>
#include <cctype>
#include <cstdlib>
#include <cstring>
#include <utility>
#include <numeric>
#include <complex>
#include <sstream>
#include <fstream>
#include <iomanip>
#include <cassert>
#include <iostream>
#include <iterator>
#include <algorithm>
using namespace std;
typedef long long ll;
typedef vector<int> vint;
typedef pair<int, int> pint;
typedef vector<long long> vlong;
#define vpush(a,x) a.push_back(x);
#define rep(i, n) REP(i, 0, n)
#define all(v) v.begin(), v.end()
#define REP(i, x, n) for(int i = x; i < n; i++)
#define INF 2e9
signed main(){
  cin.tie(0);
  ios::sync_with_stdio(false);
  string s;
  cin>>s;
  int flag=0;
  int si=s.size();
  rep(i,si){
    if(s[i]=='A'){
      if(s[i+1]=='C'){
	flag=1;
      }
    }
    if(s[i]=='C'){
      if(s[i+1]=='A'){
	flag=1;
      }
    }
  }
  if(flag==1){
    cout<<"Yes"<<'\n';
  }
  else{
    cout<<"No"<<'\n';
  }
  return(0);
}