Problem:
Score : 700 points

Problem Statement

You are given four integers: H, W, h and w (1 ≤ h ≤ H, 1 ≤ w ≤ W).
Determine whether there exists a matrix such that all of the following conditions are held, and construct one such matrix if the answer is positive:

The matrix has H rows and W columns.

Each element of the matrix is an integer between -10^9 and 10^9 (inclusive).

The sum of all the elements of the matrix is positive.

The sum of all the elements within every subrectangle with h rows and w columns in the matrix is negative.

Constraints

1 ≤ h ≤ H ≤ 500

1 ≤ w ≤ W ≤ 500

Input

Input is given from Standard Input in the following format:

H W h w

Output

If there does not exist a matrix that satisfies all of the conditions, print No.

Otherwise, print Yes in the first line, and print a matrix in the subsequent lines in the following format:

a_{11} ... a_{1W}
:
a_{H1} ... a_{HW}

Here, a_{ij} represents the (i,\ j) element of the matrix.

Sample Input 1

3 3 2 2

Sample Output 1

Yes
1 1 1
1 -4 1
1 1 1

The sum of all the elements of this matrix is 4, which is positive.
Also, in this matrix, there are four subrectangles with 2 rows and 2 columns as shown below. For each of them, the sum of all the elements inside is -1, which is negative.

Sample Input 2

2 4 1 2

Sample Output 2

No

Sample Input 3

3 4 2 3

Sample Output 3

Yes
2 -5 8 7
3 -5 -4 -5
2 1 -1 7

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

    #include <iostream>
    #include <cstdio>
    using namespace std;
    const int N=5e2+5;

    int n,m;
    int w,h;

    int tab[N][N];


    int main()
    {
        int i,j;
        int sum=0;

        cin>>n>>m>>h>>w;

        if(n%h==0 && m%w==0)
        {
            cout<<"No"<<endl;
            return 0;
        }

        for(i=1;i<=n;i++)
            for(j=1;j<=m;j++)
            {
                if(i%h==0 && j%w==0)
                    tab[i][j]=-(h*w-1)*10000-1;
                else
                    tab[i][j]=10000;

                sum+=tab[i][j];
            }


        if(sum<=0)
        {
            cout<<"No"<<endl;;
            return 0;
        }

        cout<<"Yes"<<endl;
        for(i=1;i<=n;i++)
        {
            for(j=1;j<=m;j++)
                printf("%d ",tab[i][j]);
            printf("\n");
        }


        return 0;
    }