Problem:
Score : 400 points

Problem Statement

Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.

You are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.

Constraints

2 ≦ |s| ≦ 10^5

s consists of lowercase letters.

Partial Score

200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.

Input

The input is given from Standard Input in the following format:

s

Output

If there exists no unbalanced substring of s, print -1 -1.

If there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.

Sample Input 1

needed

Sample Output 1

2 5

The string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.

Sample Input 2

atcoder

Sample Output 2

-1 -1

The string atcoder contains no unbalanced substring.

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

// lcmとか__builtin_popcountとかはg++ -std=c++17 default.cppみたいなかんじで

#include <bits/stdc++.h>
#define mod 1000000007
#define INF LLONG_MAX
#define ll long long
#define ln cout<<endl
#define Yes cout<<"Yes"<<endl
#define No cout<<"No"<<endl
#define REP(i,m,n) for(ll i=(ll)(m);i<(ll)(n);i++)
#define rep(i,n) REP(i,0,n)
using namespace std;

int main() {
    cin.tie(0);
   	ios::sync_with_stdio(false);

    ll a,b,c,d,n,maxi=0,f=0,mini=INF,sum=0;
    string str;
    cin>>str;
    if(str.length()==2&&str[0]==str[1]) {
      cout<<0<<" "<<1<<endl;
      return 0;
    }
    rep(i,str.length()-2){
      if(str[i]==str[i+1]){
        cout<<i+1<<" "<<i+3<<endl;
        return 0;
      }if(str[i]==str[i+2]){
        cout<<i+1<<" "<<i+3<<endl;
        return 0;
      }
    }
    if(str[str.length()-2]==str[str.length()-1]) {
      cout<<str.length()-2<<" "<<str.length()<<endl;
      return 0;
    }
    cout<<-1<<" "<<-1<<endl;
    
}