Problem:
Score : 100 points

Problem Statement

Takahashi is meeting up with Aoki.

They have planned to meet at a place that is D meters away from Takahashi's house in T minutes from now.

Takahashi will leave his house now and go straight to the place at a speed of S meters per minute.

Will he arrive in time?

Constraints

1 \leq D \leq 10000

1 \leq T \leq 10000

1 \leq S \leq 10000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

D T S

Output

If Takahashi will reach the place in time, print Yes; otherwise, print No.

Sample Input 1

1000 15 80

Sample Output 1

Yes

It takes 12.5 minutes to go 1000 meters to the place at a speed of 80 meters per minute. They have planned to meet in 15 minutes so he will arrive in time.

Sample Input 2

2000 20 100

Sample Output 2

Yes

It takes 20 minutes to go 2000 meters to the place at a speed of 100 meters per minute. They have planned to meet in 20 minutes so he will arrive just on time.

Sample Input 3

10000 1 1

Sample Output 3

No

He will be late.

Solution in C++ (Clang 10.0.0) (judge verdict: Accepted)

#define _USE_MATH_DEFINES
#include <iostream>
#include <sstream>
#include <string>
#include <list>
#include <vector>
#include <queue>
#include <algorithm>
#include <climits>
#include <cstring>
#include <cmath>
#include <stack>
#include <iomanip>
#include <tuple>
#include <functional>
#include <cfloat>
#include <map>
#include <set>
#include <array>
#include <stdio.h>
#include <string.h>
#include <random>
using ll = long long;
using ull = unsigned long long;
using namespace std;
#define int long long
#define CONTAINS_VEC(v,n) (find((v).begin(), (v).end(), (n)) != (v).end())
#define SORT(v) sort((v).begin(), (v).end())
#define RSORT(v) sort((v).rbegin(), (v).rend())
#define ARY_SORT(a, size) sort((a), (a)+(size))
#define REMOVE(v,a) (v.erase(remove((v).begin(), (v).end(), (a)), (v).end()))
#define REVERSE(v) (reverse((v).begin(), (v).end()))
#define ARY_REVERSE(v,a) (reverse((v), (v)+(a)))
#define REP(i, n) for (int (i)=0; (i) < (n); (i)++)
#define CONTAINS_MAP(m, a) (m).find((a)) != m.end()
#define CONTAINS_SET(m, a) (m).find((a)) != m.end()
void YesNo(bool b) { cout << (b ? "Yes" : "No") << endl; }
void YESNO(bool b) { cout << (b ? "YES" : "NO") << endl; }


signed main()
{
	int d, t, s;
	cin >> d >> t >> s;
	YesNo(d <= s * t);
}