Problem:
Score : 200 points

Problem Statement

Snuke loves working out. He is now exercising N times.

Before he starts exercising, his power is 1. After he exercises for the i-th time, his power gets multiplied by i.

Find Snuke's power after he exercises N times. Since the answer can be extremely large, print the answer modulo 10^{9}+7.

Constraints

1 ≤ N ≤ 10^{5}

Input

The input is given from Standard Input in the following format:

N

Output

Print the answer modulo 10^{9}+7.

Sample Input 1

3

Sample Output 1

6

After Snuke exercises for the first time, his power gets multiplied by 1 and becomes 1.

After Snuke exercises for the second time, his power gets multiplied by 2 and becomes 2.

After Snuke exercises for the third time, his power gets multiplied by 3 and becomes 6.

Sample Input 2

10

Sample Output 2

3628800

Sample Input 3

100000

Sample Output 3

457992974

Print the answer modulo 10^{9}+7.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
using ll=long long;
using vi=vector<int>;
using vvi=vector<vi>;
using vl=vector<ll>;
using vvl=vector<vl>;
using pii=pair<int,int>;
using pll=pair<ll,ll>;
const ll LINF=0x1fffffffffffffff;
const int INF=0x3fffffff;
const int MOD=1000000007;
#define VAR(type,...) type __VA_ARGS__;in(__VA_ARGS__)
#define VEC(type,name,size) vector<type> name(size);each(x, name)in(x)
#define rep(i,a,b) for(int i=(a);i<(b);++i)
#define rrep(i,a,b) for(int i=(a-1);i>=(b);--i)
#define each(x,v) for(auto &x:(v))
#define all(x) (x).begin(),(x).end()
#define print(x) cout<<(x)<<endl
void in(){} template<class T,class... U> void in(T &t,U &...u){cin>>t;in(u...);}
void solve();
int main(){cin.tie(0);ios::sync_with_stdio(0);solve();}

void solve() {
  VAR(int, N);
  ll ans = 1;
  rep(i, 1, N + 1) {
    ans = (ans * i) % MOD;
  }
  print(ans);
}