Problem:
Score : 300 points

Problem Statement

You are given a string S consisting of digits between 1 and 9, inclusive.
You can insert the letter + into some of the positions (possibly none) between two letters in this string.
Here, + must not occur consecutively after insertion.

All strings that can be obtained in this way can be evaluated as formulas.

Evaluate all possible formulas, and print the sum of the results.

Constraints

1 \leq |S| \leq 10

All letters in S are digits between 1 and 9, inclusive.

Input

The input is given from Standard Input in the following format:

S

Output

Print the sum of the evaluated value over all possible formulas.

Sample Input 1

125

Sample Output 1

176

There are 4 formulas that can be obtained: 125, 1+25, 12+5 and 1+2+5. When each formula is evaluated,

125

1+25=26

12+5=17

1+2+5=8

Thus, the sum is 125+26+17+8=176.

Sample Input 2

9999999999

Sample Output 2

12656242944

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

/*--------------------------------
  Author: The Ace Bee
  Blog: www.cnblogs.com/zsbzsb
  This code is made by The Ace Bee
--------------------------------*/
#include <algorithm>
#include <iostream>
#include <cstring>
#include <cstdlib>
#include <cstdio>
#include <cctype>
#include <cmath>
#include <ctime>
#define rg register
using namespace std;
template < typename T > inline void read(T& s) {
	s = 0; int f = 0; char c = getchar();
	while (!isdigit(c)) f |= (c == '-'), c = getchar();
	while (isdigit(c)) s = s * 10 + (c ^ 48), c = getchar();
	s = f ? -s : s;
}
typedef long long LL;
short n; char S[15];
inline LL calc(int s) {
	LL res = 0, fi = 0;
	for (rg int i = 1; i <= n; ++i) {
		fi = fi * 10 + S[i] - 48;
		if (s & (1 << (i - 1))) res += fi, fi = 0;
	}
	return res + fi;
}
int main() {
#ifndef ONLINE_JUDGE
	freopen("in.in", "r", stdin);
#endif
	scanf("%s", S + 1), n = strlen(S + 1);
	LL res = 0;
	for (rg int s = 0; s < 1 << (n - 1); ++s) res += calc(s);
	printf("%lld\n", res);
	return 0;
}