Problem:
Score : 500 points

Problem Statement

There are N points on the 2D plane, i-th of which is located on (x_i, y_i).
There can be multiple points that share the same coordinate.
What is the maximum possible Manhattan distance between two distinct points?

Here, the Manhattan distance between two points (x_i, y_i) and (x_j, y_j) is defined by |x_i-x_j| + |y_i-y_j|.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq x_i,y_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
x_1 y_1
x_2 y_2
:
x_N y_N

Output

Print the answer.

Sample Input 1

3
1 1
2 4
3 2

Sample Output 1

4

The Manhattan distance between the first point and the second point is |1-2|+|1-4|=4, which is maximum possible.

Sample Input 2

2
1 1
1 1

Sample Output 2

0

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
#define ll long long int
#define db double
#define pb push_back
#define mpr make_pair
#define andl "\n"
#define f first
#define s second
#define mset(x,y) memset(x,y,sizeof(x))
#define fr(i,n) for(long long int i=0;i<n;i++)
#define trace(it,x) for(auto it = (x).begin(); it != (x).end(); it++)
#define mod 1000000007
#define fastio ios::sync_with_stdio (false); cin.tie (0); cout.tie (0);
#define runtime cerr<< '\n' << "Time elapsed :" << clock() * 1000.0 / CLOCKS_PER_SEC << " ms\n" ;
using namespace std;
 
// convert number to string to_string(x);
// convert string to number stoi();
 
// ll mulmod(ll x,ll y)
// {
//     return ((x%mod)*(y%mod))%mod;
// }
 
// ll binpow(ll x, ll y)
// {
//     ll z = 1;
//     while(y > 0)
//     {
//         if(y % 2 == 1)
//             z = mulmod(z, x);
//         x = mulmod(x, x);
//         y /= 2;
//     }
//     return z;
// }
 
// ll ncr(ll n,ll r)
// {
//     return mulmod(fact[n],binpow(mulmod(fact[n-r],fact[r]),mod-2));
// }
 
// ll pwr(ll n,ll m)
// {
//   if(n==1 || m==0)
//     return 1;
 
//   ll x=pwr(n,m/2);
//   if(m%2==0)
//     return x*x;
//   else
//     return n*x*x;
// }
 
// ll pwr(ll n,ll m,ll b)
// {
//   if(n==1 || m==0)
//     return 1;
 
//   ll x=pwr(n,m/2,b);
//   if(m%2==0)
//     return ((x%b)*(x%b))%b;
//   else
//     return ((n%b)*(((x%b)*(x%b))%b))%b;
// }
 
void solve()
{
  return ;
}
 
int main()
{
  fastio
  
  ll n,x,y;
  cin >> n;
  
  ll mn=1e10,mx=-1e10;
  fr(i,n)
  {
  	cin >> x >> y;
  	mn=min(mn,x+y);
  	mx=max(mx,x+y);
  }
  cout << mx-mn;
 
  runtime
}