Problem:
Score : 300 points

Problem Statement

"Pizza At", a fast food chain, offers three kinds of pizza: "A-pizza", "B-pizza" and "AB-pizza". A-pizza and B-pizza are completely different pizzas, and AB-pizza is one half of A-pizza and one half of B-pizza combined together. The prices of one A-pizza, B-pizza and AB-pizza are A yen, B yen and C yen (yen is the currency of Japan), respectively.

Nakahashi needs to prepare X A-pizzas and Y B-pizzas for a party tonight. He can only obtain these pizzas by directly buying A-pizzas and B-pizzas, or buying two AB-pizzas and then rearrange them into one A-pizza and one B-pizza. At least how much money does he need for this? It is fine to have more pizzas than necessary by rearranging pizzas.

Constraints

1 ≤ A, B, C ≤ 5000

1 ≤ X, Y ≤ 10^5

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B C X Y

Output

Print the minimum amount of money required to prepare X A-pizzas and Y B-pizzas.

Sample Input 1

1500 2000 1600 3 2

Sample Output 1

7900

It is optimal to buy four AB-pizzas and rearrange them into two A-pizzas and two B-pizzas, then buy additional one A-pizza.

Sample Input 2

1500 2000 1900 3 2

Sample Output 2

8500

It is optimal to directly buy three A-pizzas and two B-pizzas.

Sample Input 3

1500 2000 500 90000 100000

Sample Output 3

100000000

It is optimal to buy 200000 AB-pizzas and rearrange them into 100000 A-pizzas and 100000 B-pizzas. We will have 10000 more A-pizzas than necessary, but that is fine.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

////////////////////////// Author
////////////////////////// Nasim Hossain Rabbi
////////////////////////// JU-CSE28
////////////////////////// CF - imnasim3.1415
////////////////////////// UVA - imnasim3.1415
////////////////////////// Mail - imnasim3.1415@gmail.com
#include<bits/stdc++.h>
using namespace std;
#define sz size()
#define mk make_pair
#define clr clear()
#define B begin()
#define E end()
#define EM empty()
#define mem(a,b) memset(a,b,sizeof(a))
#define rep(i,n) for(i=0;i<n;i++)
#define Rep(i,n) for(i=1;i<=n;i++)
#define all(cont) cont.begin(),cont.end()
#define pb push_back
string en="\n";
string t="hello";
#define sqr(a) ((a) * (a))
#define fast ios_base::sync_with_stdio(false); cin.tie(NULL);cout.tie(NULL)
#define pi 3.1415926535897932384626433832795
#define vi vector<int>
#define vl vector<long long>
#define vs vector<string>
#define vp(vi,x) cin>>x; vi.pb(x);
#define LB(a,x) (lower_bound(aov(a),x)-a.begin())
#define UB(a,x) (upper_bound(aov(a),x)-a.begin())
typedef long long LL;
typedef unsigned long long ULL;
bool isVowel(char ch){ ch=toupper(ch); if(ch=='A'||ch=='U'||ch=='I'||ch=='O'||ch=='E') return true; return false;}
int toInt(string s){int sm;stringstream ss(s);ss>>sm;return sm;}
template<typename T>inline T gcd(T a,T b){if(a<0)return gcd(-a,b);if(b<0)return gcd(a,-b);return (b==0)?a:gcd(b,a%b);}
template<typename T>inline T lcm(T a,T b) {if(a<0)return lcm(-a,b);if(b<0)return lcm(a,-b);return a*(b/gcd(a,b));}
int main()
{
//    fast;
    LL i,j,k,n,m,l,s=0,x,y,tc=1,c=0;
    while(cin>>i>>j>>k>>x>>y)
    {
        s=0;
        c=INT_MAX;
        l=min(x,y);
        s=l*2*k;
        s+=(x-l)*i;
        s+=(y-l)*j;
        if(s<c) c=s;
        s=i*x+j*y;
        if(s<c) c=s;
        l=max(x,y);
        s=k*l*2;
        if(s<c) c=s;
        cout<<c<<en;
    }
}