Problem:
Score : 100 points

Problem Statement

It has been decided that a programming contest sponsored by company A will be held, so we will post the notice on a bulletin board.

The bulletin board is in the form of a grid with N rows and N columns, and the notice will occupy a rectangular region with H rows and W columns.

How many ways are there to choose where to put the notice so that it completely covers exactly HW squares?

Constraints

1 \leq H, W \leq N \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
H
W

Output

Print the answer.

Sample Input 1

3
2
3

Sample Output 1

2

There are two ways to put the notice, as follows:

### ...
### ###
... ###

Here, # represents a square covered by the notice, and . represents a square not covered.

Sample Input 2

100
1
1

Sample Output 2

10000

Sample Input 3

5
4
2

Sample Output 3

8

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

//inlclude before define 
#define _USE_MATH_DEFINES

//include
#include<iostream>
#include<string>
#include<algorithm>
#include<vector>
#include<cmath>
#include<type_traits>
#include<numeric>
#include<assert.h>
#include<deque>
#include<iomanip>
#include<set>
#include<tuple>
#include<map>

using namespace std;

//typedef
typedef vector<int> VI;
typedef vector<string> VS;
typedef vector<char> VC;
typedef pair<int, int> P1;
typedef long long int ll;

//define
#define INF 1e9
#define NUM 1000000007
#define all(x) begin(x),end(x)
#define rep(i,n) for(int i=0;i<(int)(n);i++)
#define REP(i,a,b) for(int i=int(a);i<int(b);i++)
#define chmin(a,b) a=min((a),(b))
#define chmax(a,b) a=max((a),(b))

//function

/*ll gcd(ll a, ll b) {
	if (b == 0) return a;
	else return gcd(b, a%b);
}*/

/*ll lcm(ll a,ll b) {
	ll g = gcd(a, b);
	return a * (b / g);
}*/

/*int dig(int a) {
	int sum = 0;
	while (a) {
		sum += a % 10;
		a /= 10;
	}
	return sum;
}*/


int main () {
	int n,h,w;
	cin >>n>> h >> w;
	if (h == w && h == 1) {
		cout << n * n << endl;
	} else if(h==n || w==n){
		cout << min (h, w) << endl;
	} else {
		cout << h * w << endl;
	}
	
}