Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
#define FIO ios::sync_with_stdio(0), cin.tie(0), cout.tie(0)
#define FOR(a,b,c) for(int a = (b); a <= (c); a++)
#define RFOR(a,b,c) for(int a = (b); a >= (c); a--)
#define all(x) (x).begin(), (x).end()
#define vi vector <int>
#define vvi vector <vi>
#define ll long long
#define vll vector <ll>
#define vvl vector <vll>
#define pii pair<int,int>
#define pll pair<ll,ll>
#define eb emplace_back
#define ep emplace
#define fs first
#define sd second
#define mod 998244353
#define EPS 1e-9
#define tc int t; cin >> t; while(t--)
using namespace std;

int main() {
    FIO;
    int n, a, b,c; cin >> n >> a >> b >> c;
    vector <string> ss(n + 1);
    FOR(i,1,n) cin >> ss[i];
    string ans;

    FOR(i,1,n){
        if(ss[i] == "AB"){
            if(!a && !b) return cout << "NO" << '\n', 0;
            else if(i < n && a == 1 && b == 1 && !c) {
                if(ss[i] == "BC") a--, b++, ans+='B';
                else a++, b--, ans+='A';
            }
            else if(a <= 1 && b) b--, a++, ans +='A';
            else b++, a--, ans += 'B';
        }
        else if(ss[i] == "AC"){
            if(!a && !c) return cout << "NO" << '\n', 0;
            else if(i < n && a == 1 && !b && c == 1) {
                if(ss[i] == "BC") a--, c++, ans+='C';
                else a++, c--, ans+='A';
            }
            else if(a <= 1 && c) c--, a++, ans += 'A';
            else c++, a--,ans += 'C';
        }
        else{
            if(!c && !b) return cout << "NO" << '\n', 0;
            else if(i < n && !a && b == 1 && c == 1) {
                if(ss[i] == "AC") b--, c++, ans+='C';
                else b++, c--, ans+='B';
            }
            else if(c <= 1 && b) b--, c++, ans += 'C';
            else b++, c--, ans += 'B';
        }
    }

    cout << "Yes"<<'\n';
    for(auto i : ans) cout << i << '\n';
    return 0;
}