Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

/*
      author  : nishi5451
      created : 15.08.2020 00:36:19
*/

#include <bits/stdc++.h>
using namespace std;
#define rep(i,n) for(int i=0; i<n; i++)
typedef long long ll;


int main(){
    string s;
    cin >> s;
    int l = 10*(s[0]-'0')+(s[1]-'0');
    int r = 10*(s[2]-'0')+(s[3]-'0');
    if(1<=r && r<=12 && 1<=l && l<=12){
        cout << "AMBIGUOUS" << endl;
    }
    else if(1<=r && r<=12){
        cout << "MMYY" << endl;
    }
    else if(1<=l && l<=12){
        cout << "YYMM" << endl;
    }
    else {
        cout << "NA" << endl;
    }
    return 0;
}