Problem:
Score : 100 points

Problem Statement

You will be given a string S of length 3 representing the weather forecast for three days in the past.

The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. S, C, and R stand for sunny, cloudy, and rainy, respectively.

You will also be given a string T of length 3 representing the actual weather on those three days.

The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. S, C, and R stand for sunny, cloudy, and rainy, respectively.

Print the number of days for which the forecast was correct.

Constraints

S and T are strings of length 3 each.

S and T consist of S, C, and R.

Input

Input is given from Standard Input in the following format:

S
T

Output

Print the number of days for which the forecast was correct.

Sample Input 1

CSS
CSR

Sample Output 1

2

For the first day, it was forecast to be cloudy, and it was indeed cloudy.

For the second day, it was forecast to be sunny, and it was indeed sunny.

For the third day, it was forecast to be sunny, but it was rainy.

Thus, the forecast was correct for two days in this case.

Sample Input 2

SSR
SSR

Sample Output 2

3

Sample Input 3

RRR
SSS

Sample Output 3

0

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <algorithm>
#include <cmath>
#include <vector>
#include <set>
#include <map>
#include <unordered_set>
#include <unordered_map>
#include <queue>
#include <ctime>
#include <cassert>
#include <complex>
#include <string>
#include <cstring>
#include <chrono>
#include <random>
#include <queue>
#include <bitset>
using namespace std;

typedef long long ll;
typedef long long unsigned int llui;
typedef pair<int,int> ii;
typedef pair<ll,ll> pll;
typedef vector<ii> vii;
typedef vector<int> vi;
typedef vector<ll> vl;
typedef vector< vector<int> > vvi;
typedef set<int> si;
typedef map<string, int> msi;
typedef map<int, int> mii;

#define INF 1000000000
#define MOD 1000000007
#define EPS 1e-9
#define ALL(x) (x).begin(), (x).end()
#define RALL(x) (x).rbegin(), (x).rend()
#define SORT(x) sort((x).begin(),(x).end())
#define UNIQUE(x) SORT(x),(x).erase(unique((x).begin(),(x).end()),(x).end())
#define F first
#define S second
#define MP make_pair
#define PB push_back
#define EB emplace_back
#define LB lower_bound
#define UB upper_bound
#define SZ(a) int((a).size())
#define CLR(a) memset(a,0,sizeof(a))
#define SET(a,b) memset(a,b,sizeof(a))

#define FOR(i,a,b) for (int i = int(a); i < int(b); i++)
#define FORD(i,a,b) for(int i=int(b)-1; i>=int(a); i--)
#define REP(i, n) for (int i = 0; i < int(n); i++)
#define REP1(i,n) for (int i = 1; i <= int(n); i++)
#define REV(i, n) for (int i = int(n)-1; i >=0 ; i--)

#define sd(n) scanf("%d",&n)
#define dsd(n) int n; scanf("%d",&n)
#define sd2(a,b) scanf("%d%d",&a,&b)
#define dsd2(a,b) int a,b; scanf("%d%d",&a,&b)
#define sd3(a,b,c) scanf("%d%d%d",&a,&b,&c)
#define dsd3(a,b,c) int a,b,c; scanf("%d%d%d",&a,&b,&c)
#define pd(n) printf("%d\n",n)
#define pds(n) printf("%d ",n)
#define sl(n) scanf("%lld",&n)
#define dsl(n) ll n; scanf("%lld",&n)
#define sl2(a,b) scanf("%lld%lld",&a,&b)
#define dsl2(a,b) ll a,b; scanf("%lld%lld",&a,&b)
#define sl3(a,b,c) scanf("%lld%lld%lld",&a,&b,&c)
#define dsl3(a,b,c) ll a,b,c; scanf("%lld%lld%lld",&a,&b,&c)
#define pl(n) printf("%lld\n",n)	
#define pls(n) printf("%lld ",n)	
#define PR(a,n) { REP(_,n) cout<<a[_]<<' '; cout<<"\n"; }
#define PR1(a,n) { REP1(_,n) cout<<a[_]<<' '; cout<<"\n"; }
#define trace(x) cerr << " [" << #x << ": " << x << "]\n"

#define sim template < class c
#define ris return * this
#define dor > debug & operator <<
#define eni(x) sim > typename \
  enable_if<sizeof dud<c>(0) x 1, debug&>::type operator<<(c i) {
sim > struct rge { c b, e; };
sim > rge<c> range(c i, c j) { return rge<c>{i, j}; }
sim > auto dud(c* x) -> decltype(cerr << *x, 0);
sim > char dud(...);
struct debug {
~debug() { cerr << endl; }
eni(!=) cerr << boolalpha << i; ris; }
eni(==) ris << range(begin(i), end(i)); }
sim, class b dor(pair < b, c > d) {
  ris << "(" << d.first << ", " << d.second << ")";
}
sim dor(rge<c> d) {
  *this << "[";
  for (auto it = d.b; it != d.e; ++it)
    *this << ", " + 2 * (it == d.b) << *it;
  ris << "]";
}
};
#define imie(...) " [" << #__VA_ARGS__ ": " << (__VA_ARGS__) << "] "	  

inline int two(int n) { return 1 << n; }
inline int test(int n, int b) { return (n>>b)&1; }
inline void set_bit(int & n, int b) { n |= two(b); }
inline void unset_bit(int & n, int b) { n &= ~two(b); }
inline int last_bit(int n) { return n & (-n); }
inline int ones(int n) { int res = 0; while(n && ++res) n-=n&(-n); return res; }

#define LSOne(S) (S&(-S))

const double pi = acos(-1);
//const int oo = 0x3f3f3f3f;

int cmp(double x, double y = 0, double tol = EPS) {
    return (x <= y + tol) ? (x + tol < y) ? -1 : 0 : 1;
}

template<class T> bool uin(T &a,T b) {return a > b ? (a=b, true):false;}
template<class T> bool uax(T &a,T b) {return a < b ? (a=b, true):false;}

/////////////////////////////////////////////////////////////////////

//const int nax = 5e6+10;
//int arr[nax][nax];

int main(){
    string s,t;
    cin>>s>>t;
    int ans=0;
    REP(i,3) if(s[i]==t[i]) ans++;
    pd(ans);
    return 0;
}

// Do something instead of nothing, stay organised