Problem:
Score : 200 points

Problem Statement

You are given string S and T consisting of lowercase English letters.

Determine if S equals T after rotation.

That is, determine if S equals T after the following operation is performed some number of times:

Operation: Let S = S_1 S_2 ... S_{|S|}. Change S to S_{|S|} S_1 S_2 ... S_{|S|-1}.

Here, |X| denotes the length of the string X.

Constraints

2 \leq |S| \leq 100

|S| = |T|

S and T consist of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S equals T after rotation, print Yes; if it does not, print No.

Sample Input 1

kyoto
tokyo

Sample Output 1

Yes

In the first operation, kyoto becomes okyot.

In the second operation, okyot becomes tokyo.

Sample Input 2

abc
arc

Sample Output 2

No

abc does not equal arc after any number of operations.

Sample Input 3

aaaaaaaaaaaaaaab
aaaaaaaaaaaaaaab

Sample Output 3

Yes

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <iostream>
#include <vector>
#include<algorithm>
#include<string>
#include<stdio.h>
#include<map>
#include<math.h>
#include<queue>
using namespace std;
using ll = long long;
using ld = long double;
using pii = pair<int, int>;
using pll = pair<ll, ll>;
const int MOD = 1000000007;
const int mod = 1000000007;
const int INF = 1000000001;
const long long LINF = 1e18;
const int MAX = 510000;

int main(){
	string s, t;
	bool f = 0;
	cin >> s >> t;
	for (int i = 0; i < s.size(); i++) {
		s = s[s.size() - 1] + s;
		s.erase(s.end()-1);
		if (s == t)f = 1;
	}
	
	if (f == 1)cout << "Yes" << endl;
	else cout << "No" << endl;
	
	return 0;
}