Problem:
Score : 100 points

Problem Statement

Given is a string S representing the day of the week today.

S is SUN, MON, TUE, WED, THU, FRI, or SAT, for Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, and Saturday, respectively.

After how many days is the next Sunday (tomorrow or later)?

Constraints

S is SUN, MON, TUE, WED, THU, FRI, or SAT.

Input

Input is given from Standard Input in the following format:

S

Output

Print the number of days before the next Sunday.

Sample Input 1

SAT

Sample Output 1

1

It is Saturday today, and tomorrow will be Sunday.

Sample Input 2

SUN

Sample Output 2

7

It is Sunday today, and seven days later, it will be Sunday again.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
using ll=long long int;
using ld=long double;
using VI=vector<ll>;
using VD=vector<ld>;
using VVI=vector<VI>;
using VC=vector<char>;
using VVC=vector<VC>;
using VS=vector<string>;
using PLL =pair<ll,ll>;
using PLD=pair<ld,ld>;
using VPLL=vector<PLL>;
#define REP(i,n) for(ll i=0;i<(ll)(n);i++)
#define REPD(i,n) for(ll i=(ll)(n)-1;i>=0;i--)
#define FOR(i,a,b) for(ll i=(a);i<=(b);i++)
#define FORD(i,a,b) for(ll i=(a);i>=(b);i--)
#define ALL(x) (x).begin(),(x).end()
#define ALLR(x) (x).rbegin(),(x).rend()
#define SIZE(x) ((ll)(x).size())
#define MAX(x) *max_element((x).begin(),(x).end())
#define MIN(x) *min_element((x).begin(),(x).end())
#define SORTR(x) sort((x).rbegin(),(x).rend())
#define SORT(x) sort((x).begin(),(x).end())
#define SUM(x) accumulate((x).begin(),(x).end(), 0)
#define FILL(x,a) fill(x.begin(),x.end(),a)
#define EACH(i,x) for(typeof((x).begin()) i=(x).begin(); i!=(x).end(); ++i)

const int INF  = 1<<30;
const ld EPS   = 1e-10;
const int MOD  = int(1e9)+7;
template<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }
template<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }
template <class BidirectionalIterator>
bool next_partial_permutation(BidirectionalIterator first, BidirectionalIterator middle,BidirectionalIterator last){reverse(middle, last); return next_permutation(first , last);}
#define COUT(x) cout<<x<<"\n"

void Main()
{
	ll result=0;
	map<string,ll> day={
			{"SUN",7},
			{"MON",6},
			{"TUE",5},
			{"WED",4},
			{"THU",3},
			{"FRI",2},
			{"SAT",1},
	};
	string S;
	cin>>S;
	result=day[S];
	cout << result << "\n";
	return;
}

int main()
{
	std::cin.tie(0);
	std::ios_base::sync_with_stdio(false);
	std::cout << std::fixed << std::setprecision(15);
	Main();
}