Problem:
Score : 200 points

Problem Statement

An integer N is a multiple of 9 if and only if the sum of the digits in the decimal representation of N is a multiple of 9.

Determine whether N is a multiple of 9.

Constraints

0 \leq N < 10^{200000}

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a multiple of 9, print Yes; otherwise, print No.

Sample Input 1

123456789

Sample Output 1

Yes

The sum of these digits is 1+2+3+4+5+6+7+8+9=45, which is a multiple of 9, so 123456789 is a multiple of 9.

Sample Input 2

0

Sample Output 2

Yes

Sample Input 3

31415926535897932384626433832795028841971693993751058209749445923078164062862089986280

Sample Output 3

No

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
//cervello|Phoenix
using namespace std;
#define ll long long int
#define eb emplace_back
#define mk make_pair
#define all(x) x.begin(),x.end()
#define mod 1000000007

int main(){
    ios_base::sync_with_stdio(false);
    cin.tie(0);
    string s; cin>>s;
    ll sum=0;
    int n=s.length();
    for(int i=0;i<n;i++){
        sum+=s[i]-'0';
    }
    if(sum%9)
        cout<<"No\n";
    else
        cout<<"Yes\n";
    return 0;
}