Problem:
Score : 100 points

Problem Statement

Snuke lives at position x on a number line.
On this line, there are two stores A and B, respectively at position a and b, that offer food for delivery.

Snuke decided to get food delivery from the closer of stores A and B.
Find out which store is closer to Snuke's residence.

Here, the distance between two points s and t on a number line is represented by |s-t|.

Constraints

1 \leq x \leq 1000

1 \leq a \leq 1000

1 \leq b \leq 1000

x, a and b are pairwise distinct.

The distances between Snuke's residence and stores A and B are different.

Input

Input is given from Standard Input in the following format:

x a b

Output

If store A is closer, print A; if store B is closer, print B.

Sample Input 1

5 2 7

Sample Output 1

B

The distances between Snuke's residence and stores A and B are 3 and 2, respectively.
Since store B is closer, print B.

Sample Input 2

1 999 1000

Sample Output 2

A

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;

#define ll long long
#define pb push_back
#define mp make_pair
#define ff first
#define ss second
#define sc(x) scanf("%lld",&x)
#define pr(x) printf("%lld\n",x)
#define clr(x) memset(x, 0, sizeof(x))
#define all(x) x.begin(), x.end()
typedef pair<ll, ll> pii;
typedef vector< ll > vl;
typedef vector< pii > vpii;
const ll N= 1e5+55,mod = 1e9+7;
int main() {
// 	freopen("Task.in","r",stdin);freopen("Task.out","w",stdout);
	ll x,a,b,ans,xx,yy;
	sc(x);sc(a);sc(b);
	xx=abs(x-a);
	yy=abs(x-b);
	ans=min(xx,yy);
	if(ans==xx)printf("A\n");
	else printf("B\n");	
}