Problem:
Score : 200 points

Problem Statement

An integer N is a multiple of 9 if and only if the sum of the digits in the decimal representation of N is a multiple of 9.

Determine whether N is a multiple of 9.

Constraints

0 \leq N < 10^{200000}

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a multiple of 9, print Yes; otherwise, print No.

Sample Input 1

123456789

Sample Output 1

Yes

The sum of these digits is 1+2+3+4+5+6+7+8+9=45, which is a multiple of 9, so 123456789 is a multiple of 9.

Sample Input 2

0

Sample Output 2

Yes

Sample Input 3

31415926535897932384626433832795028841971693993751058209749445923078164062862089986280

Sample Output 3

No

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include<bits/stdc++.h>
using namespace std;
using ll = long long;
int main(){
    ll N=0,size=0,sum=0;
    cin >> N;

    if(N == 0){
        cout << "Yes" << endl;
        return 0;
    }

    string s = to_string(N); 
    size = s.length();
    for(int i=0;i<size;i++){
        sum += s[i];
    }
    cout << sum << endl;
    if(sum % 9 == 0){
        cout << "Yes" << endl;
    }
    else cout << "No" << endl;

    return 0;

}