Problem:
Score : 300 points

Problem Statement

You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

1 \leq |S| \leq 2 \times 10^5

|S| = |T|

S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S and T can be made equal, print Yes; otherwise, print No.

Sample Input 1

azzel
apple

Sample Output 1

Yes

azzel can be changed to apple, as follows:

Choose e as c_1 and l as c_2. azzel becomes azzle.

Choose z as c_1 and p as c_2. azzle becomes apple.

Sample Input 2

chokudai
redcoder

Sample Output 2

No

No sequences of operation can change chokudai to redcoder.

Sample Input 3

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <string>
#include <map>

using namespace std;

int main(){
    string s,t;
    cin >> s;
    cin >> t;
    map<char,int> m1,m2;
    bool ans = true;
    
    for(int i = 0; i < s.size(); i++){
        if(m1[s[i]] == 0){
            m1[s[i]] = t[i];
        }else{
            if(m1[s[i]] != t[i]){
                ans = false;
                break;
            }
        } 
    }

    if(!ans){
        cout << "No" << endl;
    }else{
        for(int i = 0; i < s.size(); i++){
                if(m2[t[i]] == 0){
            m2[t[i]] = s[i];
            }else{
                if(m2[t[i]] != s[i]){
                    ans = false;
                    break;
                }
            } 
        }

        if(ans){
            cout << "Yes" << endl;
        }else cout << "No" << endl;
    }

    return 0;
}