Problem:
Score : 100 points

Problem Statement

You are given positive integers A and B.

If A is a divisor of B, print A + B; otherwise, print B - A.

Constraints

All values in input are integers.

1 \leq A \leq B \leq 20

Input

Input is given from Standard Input in the following format:

A B

Output

If A is a divisor of B, print A + B; otherwise, print B - A.

Sample Input 1

4 12

Sample Output 1

16

As 4 is a divisor of 12, 4 + 12 = 16 should be printed.

Sample Input 2

8 20

Sample Output 2

12

Sample Input 3

1 1

Sample Output 3

2

1 is a divisor of 1.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include "bits/stdc++.h"
using namespace std;
#define Would
#define you
const long long INF = 9999999999;
const long long MOD = 1e9 + 7;
const double pi = 3.1415926535897932384626;
const int SIZE = 1 << 17;

int main() {
	int a, b;
	cin >> a >> b;
	if (b%a == 0) { cout << a + b; }
	else { cout << b - a; }
	cout << endl;
}