Problem:
Score : 300 points

Problem Statement

You are given three integers A, B and C. Find the minimum number of operations required to make A, B and C all equal by repeatedly performing the following two kinds of operations in any order:

Choose two among A, B and C, then increase both by 1.

Choose one among A, B and C, then increase it by 2.

It can be proved that we can always make A, B and C all equal by repeatedly performing these operations.

Constraints

0 \leq A,B,C \leq 50

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B C

Output

Print the minimum number of operations required to make A, B and C all equal.

Sample Input 1

2 5 4

Sample Output 1

2

We can make A, B and C all equal by the following operations:

Increase A and C by 1. Now, A, B, C are 3, 5, 5, respectively.

Increase A by 2. Now, A, B, C are 5, 5, 5, respectively.

Sample Input 2

2 6 3

Sample Output 2

5

Sample Input 3

31 41 5

Sample Output 3

23

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;
#define REP(i, n) for(int i = 0; i < n; i++)

int main(){
    cin.tie(0);
    ios::sync_with_stdio(false);

    vector<int> A(3);
    REP(i, 3) cin >> A[i];

    sort(A.begin(), A.end());

    int d1 = A[2] - A[1];
    int d2 = A[2] - A[0];

    int ans = 0;
    ans += d1 / 2;
    ans += d2 / 2;
    ans += d1 % 2;
    if(d1 % 2 != d2 % 2){
        ans += 1;
    }

    cout << ans << endl;    

    return 0;
}