Problem:
Score : 200 points

Problem Statement

Let S(n) denote the sum of the digits in the decimal notation of n.
For example, S(101) = 1 + 0 + 1 = 2.

Given an integer N, determine if S(N) divides N.

Constraints

1 \leq N \leq 10^9

Input

Input is given from Standard Input in the following format:

N

Output

If S(N) divides N, print Yes; if it does not, print No.

Sample Input 1

12

Sample Output 1

Yes

In this input, N=12.
As S(12) = 1 + 2 = 3, S(N) divides N.

Sample Input 2

101

Sample Output 2

No

As S(101) = 1 + 0 + 1 = 2, S(N) does not divide N.

Sample Input 3

999999999

Sample Output 3

Yes

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <algorithm>
#include <cstdlib>
#include <iostream>
#include <string>
#include <vector>
using namespace std;
typedef long long LL;

int main() {
  int N; cin >> N;
  int i = N;
  int sum = 0;
  while (i > 0) {
    sum += (i % 10);
    i /= 10;
  }
  if (N % sum == 0) cout << "Yes" << endl;
  else              cout << "No" << endl;
}