Problem:
Score : 200 points

Problem Statement

Given is a sequence of N integers A_1, \ldots, A_N.

Find the (multiplicative) inverse of the sum of the inverses of these numbers, \frac{1}{\frac{1}{A_1} + \ldots + \frac{1}{A_N}}.

Constraints

1 \leq N \leq 100

1 \leq A_i \leq 1000

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 \ldots A_N

Output

Print a decimal number (or an integer) representing the value of \frac{1}{\frac{1}{A_1} + \ldots + \frac{1}{A_N}}.

Your output will be judged correct when its absolute or relative error from the judge's output is at most 10^{-5}.

Sample Input 1

2
10 30

Sample Output 1

7.5

\frac{1}{\frac{1}{10} + \frac{1}{30}} = \frac{1}{\frac{4}{30}} = \frac{30}{4} = 7.5.

Printing 7.50001, 7.49999, and so on will also be accepted.

Sample Input 2

3
200 200 200

Sample Output 2

66.66666666666667

\frac{1}{\frac{1}{200} + \frac{1}{200} + \frac{1}{200}} = \frac{1}{\frac{3}{200}} = \frac{200}{3} = 66.6666....

Printing 6.66666e+1 and so on will also be accepted.

Sample Input 3

1
1000

Sample Output 3

1000

\frac{1}{\frac{1}{1000}} = 1000.

Printing +1000.0 and so on will also be accepted.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <string>
#include <queue>
#include <stack>
#include <vector>
#include <sstream>
#include <algorithm>
#include <deque>
#include <set>
#include <map>
#include <unordered_set>
#include <unordered_map>
#include <list>
#include <cstdio>
#include <iostream>
#include <cmath>
#include <climits>
#include <bitset>
#include <functional>
#include <numeric>
#include <ctime>
#include <cassert>
#include <cstring>
#include <fstream>

using namespace std;

#define FOR(i, a, b) for(int (i)=(a);(i)<(b);(i)++)
#define IFOR(i, a, b) for(int (i)=(a);(i)<=(b);(i)++)
#define RFOR(i, a, b) for(int (i)=(a);(i)>=(b);(i)--)
#define REP(i, n) FOR((i), 0, (n))

using ll = long long;
using pii = pair<int, int>;
using pll = pair<ll, ll>;

template<class T>
void print_container(T &container, string delim=" ") {
    bool first = true;
    for(auto &t: container){
        if(!first){
            cout << delim;
        }
        first = false;
        cout << t;
    }
    cout << endl;
}

int main() {
    int n;
    cin >> n;
    vector<int> a(n);
    REP(i, n)
        cin >> a[i];

    double bunbo = 0.0;
    REP(i, n){
        bunbo += 1.0 / a[i];
    }
    printf("%.14f\n", 1.0 / bunbo);
    return 0;
}