Problem:
﻿Score: 100 points

Problem Statement

In AtCoder city, there are five antennas standing in a straight line. They are called Antenna A, B, C, D and E from west to east, and their coordinates are a, b, c, d and e, respectively.

Two antennas can communicate directly if the distance between them is k or less, and they cannot if the distance is greater than k.

Determine if there exists a pair of antennas that cannot communicate directly.

Here, assume that the distance between two antennas at coordinates p and q (p < q) is q - p.

Constraints

a, b, c, d, e and k are integers between 0 and 123 (inclusive).

a < b < c < d < e

Input

Input is given from Standard Input in the following format:

a
b
c
d
e
k

Output

Print :( if there exists a pair of antennas that cannot communicate directly, and print Yay! if there is no such pair.

Sample Input 1

1
2
4
8
9
15

Sample Output 1

Yay!

In this case, there is no pair of antennas that cannot communicate directly, because:

the distance between A and B is 2 - 1 = 1

the distance between A and C is 4 - 1 = 3

the distance between A and D is 8 - 1 = 7

the distance between A and E is 9 - 1 = 8

the distance between B and C is 4 - 2 = 2

the distance between B and D is 8 - 2 = 6

the distance between B and E is 9 - 2 = 7

the distance between C and D is 8 - 4 = 4

the distance between C and E is 9 - 4 = 5

the distance between D and E is 9 - 8 = 1

and none of them is greater than 15. Thus, the correct output is Yay!.

Sample Input 2

15
18
26
35
36
18

Sample Output 2

:(

In this case, the distance between antennas A and D is 35 - 15 = 20 and exceeds 18, so they cannot communicate directly.
Thus, the correct output is :(.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#define rep(i,n) for(int i=0;i<n;++i)
#define int long long
using namespace std;
typedef pair<int,int> P;
int gcd(int a,int b){
    if(a%b==0)return b;
    else return gcd(b,a%b);
}
int lcm(int a,int b){
    return a*b/gcd(a,b);
}
bool prime(int a){
    if(a==1)return false;
    for(int i=2;i*i<=a;i++){
        if(a%i==0)return false;
    }
    return true;
}
struct edge{
    int to,cost;
};
class dijkstra{
    int V;
    int d[100002];
    priority_queue<P,vector<P>,greater<P>>que;
    void update(int s,vector<edge> G[]){
        fill(d,d+V+1,100000000000ll);
        d[s]=0;
        que.push(make_pair(0,s));
        while(!que.empty()){
            P p=que.top();
            que.pop();
            int v=p.second;
            if(d[v]<p.first)continue;
            rep(i,G[v].size()){
                edge e=G[v][i];
                if(d[e.to]>d[v]+e.cost){
                    d[e.to]=d[v]+e.cost;
                    que.push(make_pair(d[e.to],e.to));
                }
            }
        }
    }
public:
    dijkstra(int v,int s,vector<edge> G[]){
        V=v;
        update(s,G);
    }
    int find(int e){
        return d[e];
;    }
};
signed main(){
    int a,b,c,d,e,k;
    cin>>a>>b>>c>>d>>e>>k;
    if(e-a>k)cout<<":("<<endl;
    else cout<<"Yay!"<<endl;
}