Problem:
Score : 300 points

Problem Statement

There are N slimes lining up from left to right. The colors of these slimes will be given as a string S of length N consisting of lowercase English letters. The i-th slime from the left has the color that corresponds to the i-th character of S.

Adjacent slimes with the same color will fuse into one larger slime without changing the color. If there were a slime adjacent to this group of slimes before fusion, that slime is now adjacent to the new larger slime.

Ultimately, how many slimes will be there?

Constraints

1 \leq N \leq 10^5

|S| = N

S consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

N
S

Output

Print the final number of slimes.

Sample Input 1

10
aabbbbaaca

Sample Output 1

5

Ultimately, these slimes will fuse into abaca.

Sample Input 2

5
aaaaa

Sample Output 2

1

All the slimes will fuse into one.

Sample Input 3

20
xxzaffeeeeddfkkkkllq

Sample Output 3

10

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

// " --- IN THE NAME OF ALLAH --- " // ;)
// ------------sphr_agz------------ // ;)
 
#include <bits/stdc++.h>
#include <iostream>
#include <algorithm>
#include <iomanip>
#include <string>
#include <vector>
#include <queue>
#include <deque>
#include <set>
#include <map>
#include <math.h>
#include <cmath>
#include <list>
#include <stack>
#include <bitset>
#include <ctime>
using namespace std;
 
typedef long double ld;
typedef long long int lli;
#define pb(x) push_back(x)
#define fr first
#define sc second
#define fast ios::sync_with_stdio(false), cin.tie(0), cout.tie(0)
#define stp(x) cout << setprecision(x) << fixed
#define mk make_pair
const lli N = 1e6, N2 = 5e3, delta = 46639, mod = 1e9 + 7, oo = 1e16;
const ld PI = 3.141592653589793;

lli a[N];

int main(){
	lli n, ans = 0;
	string s;
	cin >> n >> s;
	for (lli i = 1; i < n; i++) {
		if (s[i] != s[i - 1])
			ans++;
	}
	cout << ++ans;
}