Problem:
Score : 100 points

Problem Statement

Takahashi has K 500-yen coins. (Yen is the currency of Japan.)
If these coins add up to X yen or more, print Yes; otherwise, print No.

Constraints

1 \leq K \leq 100

1 \leq X \leq 10^5

Input

Input is given from Standard Input in the following format:

K X

Output

If the coins add up to X yen or more, print Yes; otherwise, print No.

Sample Input 1

2 900

Sample Output 1

Yes

Two 500-yen coins add up to 1000 yen, which is not less than X = 900 yen.

Sample Input 2

1 501

Sample Output 2

No

One 500-yen coin is worth 500 yen, which is less than X = 501 yen.

Sample Input 3

4 2000

Sample Output 3

Yes

Four 500-yen coins add up to 2000 yen, which is not less than X = 2000 yen.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>

using namespace std;

int main(void){
//string S;
int K;
int X;
cin >> K >> X;
/*vector<int> P(N);

for(int i = 0; i < N; i++){
  cin >> P[i];
}

vector<int> PP;

PP.push_back(P[0]);
for(int i = 1; i < P.size(); i++){
  if(P[i] <= PP.back()){
    PP.push_back(P[i]);
  }
}*/
if(500*K >= X) cout << "Yes" << endl;
if(500*K < X) cout << "No" << endl;
return 0;
}