Problem:
Score : 300 points

Problem Statement

There are N slimes lining up from left to right. The colors of these slimes will be given as a string S of length N consisting of lowercase English letters. The i-th slime from the left has the color that corresponds to the i-th character of S.

Adjacent slimes with the same color will fuse into one larger slime without changing the color. If there were a slime adjacent to this group of slimes before fusion, that slime is now adjacent to the new larger slime.

Ultimately, how many slimes will be there?

Constraints

1 \leq N \leq 10^5

|S| = N

S consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

N
S

Output

Print the final number of slimes.

Sample Input 1

10
aabbbbaaca

Sample Output 1

5

Ultimately, these slimes will fuse into abaca.

Sample Input 2

5
aaaaa

Sample Output 2

1

All the slimes will fuse into one.

Sample Input 3

20
xxzaffeeeeddfkkkkllq

Sample Output 3

10

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
#define ll long long
#define int long long int
#define mkp make_pair
#define maxN 100005
#define pb push_back
#define ff first
#define ss second
#define debug1(a) cout<<a<<endl;
#define debug2(a,b) cout<<a<<' '<<b<<endl;
#define debug3(a,b,c) cout<<a<' '<<b<<' '<<c<<endl;
#define rep(i,n) for(int i=0;i<n;i++)
#define repl(i,a,b) for(int i=a;i<b;i++)
#define pi pair<int,int>
#define pii pair<int,pi>
#define mp map<int,int>
#define ump unordered_map<int,int>
#define  vi vector<int>
#define st set<int>
#define mst multiset<int>
#define pq priority_queue
#define mpq priority_queue<int,vector<int>,greater<int> >
#define fastio ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);
#define in cin>>
#define out cout<<
using namespace std;
void printArray(int arr[],int n)
{
   for(int i=0;i<n;i++)cout<<arr[i]<<' ';
}
 set<pair<int,int>> primeset;
void SieveOfEratosthenes(int n)
{
    bool prime[n+1];
    memset(prime, true, sizeof(prime));

    for (int p=2; p*p<=n; p++)
    {
        if (prime[p] == true)
        {
        for (int i=p*p; i<=n; i += p)
                prime[i] = false;
        }
    }
    for (int p=2; p<=n; p++)
       if (prime[p])
          primeset.insert(mkp(p,1));
}
int32_t main()
{
fastio;
int n;in n;
string s;in s;
bool f=false;
int c=0;
for(int i=1;i<=s.size();i++){
    if(s[i]==s[i-1]){
        if(f==true) continue;
        else {
            f=true;
            //out i<<" ";
        }
    }
    else {
    c++;
    }
}
out c;
    return 0;
}