Problem:
Score : 100 points

Problem Statement

Given is an integer N.

Takahashi chooses an integer a from the positive integers not greater than N with equal probability.

Find the probability that a is odd.

Constraints

1 \leq N \leq 100

Input

Input is given from Standard Input in the following format:

N

Output

Print the probability that a is odd.
Your output will be considered correct when its absolute or relative error from the judge's output is at most 10^{-6}.

Sample Input 1

4

Sample Output 1

0.5000000000

There are four positive integers not greater than 4: 1, 2, 3, and 4. Among them, we have two odd numbers: 1 and 3. Thus, the answer is \frac{2}{4} = 0.5.

Sample Input 2

5

Sample Output 2

0.6000000000

Sample Input 3

1

Sample Output 3

1.0000000000

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <cstdio>
#include <iostream>
#include <string>
#include <vector>
#include <array>
#include <algorithm>
#include <utility>
#include <numeric>
#include <deque>
#include <stack>
#include <queue>
#include <map>
#include <unordered_map>
#include <set>
#include <unordered_set>
#include <cmath>
#include <limits>
#include <cassert>

#define for0(i, N)    for (int i = 0  ; i <  (N); ++i)
#define for1n(i, N)   for (int i = 1  ; i <= (N); ++i)
#define for1(i, N)    for (int i = 1  ; i <  (N); ++i)
#define forn(i, N)    for (int i = 0  ; i <= (N); ++i)
#define forx(i, N, x) for (int i = (x); i <  (N); ++i)
#define forl(i, N, x, a) for (int i = (x), a = 0; a < (N);  \
                              i = (i + 1) % (N), ++a)

using namespace std;

typedef long long ll;
typedef long double ld;
typedef priority_queue<ll> pq;
typedef priority_queue<ll,vector<ll>, greater<ll>> pql;
typedef stack<ll> stk;
typedef queue<ll> qu;


int main(void){
    cin.tie(0); ios::sync_with_stdio(false);

    int n;

    cin >> n;

    printf("%.10f", n % 2 == 1 ? (double)(n / 2 + 1) / n : 0.5);

    return 0;
}