Problem:
Score : 200 points

Problem Statement

Let w be a string consisting of lowercase letters.
We will call w beautiful if the following condition is satisfied:

Each lowercase letter of the English alphabet occurs even number of times in w.

You are given the string w. Determine if w is beautiful.

Constraints

1 \leq |w| \leq 100

w consists of lowercase letters (a-z).

Input

The input is given from Standard Input in the following format:

w

Output

Print Yes if w is beautiful. Print No otherwise.

Sample Input 1

abaccaba

Sample Output 1

Yes

a occurs four times, b occurs twice, c occurs twice and the other letters occur zero times.

Sample Input 2

hthth

Sample Output 2

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <cstdio>
#include <cstdlib>
#include <cmath>
#include <iostream>
#include <vector>
#include <map>
#include <stack>
#include <queue>
#include <string>
#include <algorithm>
#include <functional>
#include <utility>
#include <numeric>
#include <set>

using namespace std;
using ll = long long;

typedef pair<ll, ll> P;

const int MOD = 1000000007;
const ll INF = 1LL << 60;


// LRUD
const int dx[4] = {-1, 1, 0, 0};
const int dy[4] = {0, 0, -1, 1};
// const int dx[8] = {1, 0, -1, 0, 1, -1, -1, 1};
// const int dy[8] = {0, 1, 0, -1, 1, 1, -1, -1};

vector<vector<int> > vvi;
vector<vector<vector<int> > > vvvi;

template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }

int GCD(int a, int b) { return b ? GCD(b, a%b) : a; }

int main(int argc, char**argv){
    string w;
    cin >> w;

    map<char, int> c;
    for (auto ch : w){
        c[ch] = 0;
    }

    for (auto ch : w){
        c[ch]++;
    }

    string ans = "Yes";
    for (auto ch : w){
        if (c[ch] % 2 != 0) ans = "No";
    }

    cout << ans << endl;

    return 0;
}