Problem:
Score : 300 points

Problem Statement

To make it difficult to withdraw money, a certain bank allows its customers to withdraw only one of the following amounts in one operation:

1 yen (the currency of Japan)

6 yen, 6^2(=36) yen, 6^3(=216) yen, ...

9 yen, 9^2(=81) yen, 9^3(=729) yen, ...

At least how many operations are required to withdraw exactly N yen in total?

It is not allowed to re-deposit the money you withdrew.

Constraints

1 \leq N \leq 100000

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If at least x operations are required to withdraw exactly N yen in total, print x.

Sample Input 1

127

Sample Output 1

4

By withdrawing 1 yen, 9 yen, 36(=6^2) yen and 81(=9^2) yen, we can withdraw 127 yen in four operations.

Sample Input 2

3

Sample Output 2

3

By withdrawing 1 yen three times, we can withdraw 3 yen in three operations.

Sample Input 3

44852

Sample Output 3

16

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
using ll = long long;
#define rep(i,n) for(int (i)=0;(i)<(n);(i)++)
#define rep_1(i,n) for(int (i)=0;(i)<=(n);(i)++)
#define rep_2(i,a,b) for(int (i)=(a);(i)<(b);(i)++)
#define all(x) (x).begin(),(x).end()
#define rall(x) (x).rbegin(),(x).rend()
const int INF = 1e9;
const int MOD = 1e9+7;
const ll LINF = 1e18;

int main(){
    int n;cin>>n;

    vector<ll> dp(n+1,LINF);

    dp[0] = 0;
    for(int i = 1;i<=n;i++){
        for(int pow6 = 1;pow6 <= i;pow6 *= 6){
            dp[i] = min(dp[i], dp[i - pow6] + 1);
        }
        for(int pow9 = 1;pow9 <= i;pow9 *= 9){
            dp[i] = min(dp[i], dp[i - pow9] + 1);
        }
    }
    cout << dp[n]<<endl;


    return 0;
}