Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
typedef long long int ll;

int main(){
    int n;
    cin >> n;
    int cnt=0,ans=0;
    for(int i=1; i<=n; i++){
        if(i%2==0)continue;
        cnt=0;
        for(int j=1; j<=i; j++){
            int tmp=i/j;
            if(tmp*j==i)cnt++;
        }
        if(cnt==8)ans++;
    }
    cout << ans << endl;
}