Problem:
Score : 200 points

Problem Statement

Takahashi's house has only one socket.

Takahashi wants to extend it with some number of power strips, each with A sockets, into B or more empty sockets.

One power strip with A sockets can extend one empty socket into A empty sockets.

Find the minimum number of power strips required.

Constraints

All values in input are integers.

2 \leq A \leq 20

1 \leq B \leq 20

Input

Input is given from Standard Input in the following format:

A B

Output

Print the minimum number of power strips required.

Sample Input 1

4 10

Sample Output 1

3

3 power strips, each with 4 sockets, extend the socket into 10 empty sockets.

Sample Input 2

8 9

Sample Output 2

2

2 power strips, each with 8 sockets, extend the socket into 15 empty sockets.

Sample Input 3

8 8

Sample Output 3

1

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <algorithm>
#include <numeric>
#include <cmath>
#include <string>
#include <vector>
#include <queue>
#include <deque>
#include <stack>
#include <map>
#include <set>
#include <unordered_map>
#include <unordered_set>
#include <iomanip>
#include <functional> // std::function<void(int)>
using namespace std;
#define int long long
#define All(v) (v).begin(),(v).end()
int dy[4] = {-1,0,1,0};
int dx[4] = {0,1,0,-1};
int Dy[8] = {-1,-1,0,1,1,1,0,-1};
int Dx[8] = {0,1,1,1,0,-1,-1,-1};
const int mod = 1000000007;
const int inf = mod*mod;
const int d5 = 111111;
signed main(){
    ios::sync_with_stdio(false);
    cin.tie(0);
    int a,b;
    cin>>a>>b;
    a--;
    int cnt=1;
    int res=0;
    while(true){
        if(cnt>=b){
            cout<<res<<endl;
            return 0;
        }
        res++;
        cnt+=a;  
    }
}