Problem:
Score: 300 points

Problem Statement

M-kun is a student in Aoki High School, where a year is divided into N terms.

There is an exam at the end of each term. According to the scores in those exams, a student is given a grade for each term, as follows:

For the first through (K-1)-th terms: not given.

For each of the K-th through N-th terms: the multiplication of the scores in the last K exams, including the exam in the graded term.

M-kun scored A_i in the exam at the end of the i-th term.

For each i such that K+1 \leq i \leq N, determine whether his grade for the i-th term is strictly greater than the grade for the (i-1)-th term.

Constraints

2 \leq N \leq 200000

1 \leq K \leq N-1

1 \leq A_i \leq 10^{9}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
A_1 A_2 A_3 \ldots A_N

Output

Print the answer in N-K lines.

The i-th line should contain Yes if the grade for the (K+i)-th term is greater than the grade for the (K+i-1)-th term, and No otherwise.

Sample Input 1

5 3
96 98 95 100 20

Sample Output 1

Yes
No

His grade for each term is computed as follows:

3-rd term: (96 \times 98 \times 95) = 893760

4-th term: (98 \times 95 \times 100) = 931000

5-th term: (95 \times 100 \times 20) = 190000

Sample Input 2

3 2
1001 869120 1001

Sample Output 2

No

Note that the output should be No if the grade for the 3-rd term is equal to the grade for the 2-nd term.

Sample Input 3

15 7
3 1 4 1 5 9 2 6 5 3 5 8 9 7 9

Sample Output 3

Yes
Yes
No
Yes
Yes
No
Yes
Yes

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <cstdio>
#include <cstring>
#include <cstdlib>
#include <cctype>
#include <cmath>
#include <algorithm>
#include <queue>
#include <map>
#include <vector>
#include <stack>
#include <set>
#define fi first
#define se second
#define mp make_pair

using namespace std;
typedef long long ll;
typedef pair<int,int> pii;
const double eps = 1e-8;
const int INF = 0x3f3f3f3f;
const ll mod  = 1e9 + 7;
const ll N = 1e6 + 5;

int n,k;
double a[N];

int main(){
	ios::sync_with_stdio(0);
	cin.tie(0);
 	cin>>n>>k;
 	a[0]=1.0;
 	for(int i=1;i<=n;i++) cin>>a[i],a[i]=log(a[i]);
 	double x=1;
 	vector<double> V;
 	for(int i=1;i<=n;i++){
 		// cout<<a[i]<<" \n"[i==n];
 		if(i<k) x*=a[i];
 		else{
 			x=x/a[i-k]*a[i];
 			V.push_back(x);
 		}
 	}
 	// for(auto c:V){
 	// 	cout<<c<<'\n';
 	// }
 	for(int i=1;i<V.size();i++){
 		if(V[i]>V[i-1]) cout<<"Yes\n";
 		else cout<<"No\n";
 	}
	return 0;
}