Problem:
Score : 300 points

Problem Statement

As a token of his gratitude, Takahashi has decided to give his mother an integer sequence.
The sequence A needs to satisfy the conditions below:

A consists of integers between X and Y (inclusive).

For each 1\leq i \leq |A|-1, A_{i+1} is a multiple of A_i and strictly greater than A_i.

Find the maximum possible length of the sequence.

Constraints

1 \leq X \leq Y \leq 10^{18}

All input values are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

Print the maximum possible length of the sequence.

Sample Input 1

3 20

Sample Output 1

3

The sequence 3,6,18 satisfies the conditions.

Sample Input 2

25 100

Sample Output 2

3

Sample Input 3

314159265 358979323846264338

Sample Output 3

31

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#if defined(__GNUC__)
#include <bits/stdc++.h>
// __GNUC__
#else
#include "bits/stdc++.h"
#endif
using namespace std;

#define int long long

#if defined(__GNUC__)
#define __int32 __int32_t
#endif // __GNUC__

#define itn __int32
#define REP(i, n) for(itn (i) = 0; (i) < (n); (i)++)
#define REP2(i, x, n) for(itn (i) = x; (i) < (n); (i)++)
#define ALL(x) (x).begin(), (x).end()
#define RALL(x) (x).rbegin(), (x).rend()
#define SORT(x) std::sort(ALL(x))
#define RSORT(x, T) std::sort(ALL(x), greater<T>())
#define REVERCE(x) std::reverce(ALL(x))

#define INT_POW(x, y) [](int a, int b) -> int {int c = a; REP(i, b - 1){c *= a;} return c;}(x, y)
#define INT_POWM(x, y, m) [](int a, int b, int m) -> int {int c = a; REP(i, b - 1){c *= a; c %= m;} return c;}(x, y, m)

itn main() {
	std::ios::sync_with_stdio(false);

	int x, y;

	cin >> x >> y;

	long double a = (long double)y / x;

	int br = log2l(a);

	cout << br + 1;

	return 0;
}