Problem:
GCD and LCM

Write a program which computes the greatest common divisor (GCD) and the least common multiple (LCM) of given a and b.

Input

Input consists of several data sets. Each data set contains a and b separated by a single space in a line. The input terminates with EOF.

Constraints

0 < a, b ≤ 2,000,000,000

LCM(a, b) ≤ 2,000,000,000

The number of data sets ≤ 50

Output

For each data set, print GCD and LCM separated by a single space in a line.

Sample Input

8 6
50000000 30000000

Output for the Sample Input

2 24
10000000 150000000

Solution in C++ (judge verdict: Time Limit Exceeded)

#include <stdio.h>

int main(){
    float a[20],b[20];
    int nCount = 0;
    while( scanf( "%f %f",&a[nCount],&b[nCount] ) != EOF ){
        nCount++;
    }

    for( int k = 0;k < nCount;k++ ){
         float buf_a = a[k],buf_b = b[k];

        while( buf_a != buf_b ){
            if( buf_a < buf_b ) buf_a += a[k];
            else                      buf_b += b[k];
        }
        printf( "%d ",( int )buf_a );
        int m,n;
        if( a[k] < b[k] ) m = b[k],n = a[k];
        else if( a[k] > b[k] ) n = b[k],m = a[k];
        else {
            printf( "%d\n",a[k] );
            continue;
        }
        while( true ){
            int buf = n;
            n = m % n;
            m = buf;
            if( n == 0 ) {
                printf( "%d\n",m );
                break;
            }
        }
    }
    return 0;
}