Problem:
Score : 200 points

Problem Statement

Takahashi went to an all-you-can-eat buffet with N kinds of dishes and ate all of them (Dish 1, Dish 2, \ldots, Dish N) once.

The i-th dish (1 \leq i \leq N) he ate was Dish A_i.

When he eats Dish i (1 \leq i \leq N), he gains B_i satisfaction points.

Additionally, when he eats Dish i+1 just after eating Dish i (1 \leq i \leq N - 1), he gains C_i more satisfaction points.

Find the sum of the satisfaction points he gained.

Constraints

All values in input are integers.

2 \leq N \leq 20

1 \leq A_i \leq N

A_1, A_2, ..., A_N are all different.

1 \leq B_i \leq 50

1 \leq C_i \leq 50

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N
B_1 B_2 ... B_N
C_1 C_2 ... C_{N-1}

Output

Print the sum of the satisfaction points Takahashi gained, as an integer.

Sample Input 1

3
3 1 2
2 5 4
3 6

Sample Output 1

14

Takahashi gained 14 satisfaction points in total, as follows:

First, he ate Dish 3 and gained 4 satisfaction points.

Next, he ate Dish 1 and gained 2 satisfaction points.

Lastly, he ate Dish 2 and gained 5 + 3 = 8 satisfaction points.

Sample Input 2

4
2 3 4 1
13 5 8 24
45 9 15

Sample Output 2

74

Sample Input 3

2
1 2
50 50
50

Sample Output 3

150

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
 
using namespace std;
 
#define repr(i,a,b) for (int i=a; i<b; i++)
#define rep(i,n) for (int i=0; i<  n; i++)
 
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return true; } return false; }
template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return true; } return false; }
 
const long long INF = 1LL << 60;
#define PI 3.14159265359 
 
template<typename T>
void remove(std::vector<T>& vector, unsigned int index)
{
    vector.erase(vector.begin() + index);
}
 
int gcd(int a, int b){
    if(b == 0) return a;
    else return gcd(b, a%b);
}
 
long long lcm (int a, int b){
    return  (long long) a*b /gcd(a,b);
}

int main(){
    int N;
    cin >> N;

    int a[N+1],b[N+1],c[N];

    for(int i = 1; i< N+1; i++) cin >> a[i];
    for(int i = 1; i< N+1; i++) cin >> b[i];
    for(int i = 1; i< N; i++) cin >> c[i];

    int sum = 0;
    repr(i,1,N+1){
        sum += b[a[i]];
    }

    repr(i,1,N){
        if(a[i]+1 == a[i+1]){
        sum += c[a[i]];
        }
    }
    cout << sum << endl;

}