Problem:
Score : 500 points

Problem Statement

There are N points on the 2D plane, i-th of which is located on (x_i, y_i).
There can be multiple points that share the same coordinate.
What is the maximum possible Manhattan distance between two distinct points?

Here, the Manhattan distance between two points (x_i, y_i) and (x_j, y_j) is defined by |x_i-x_j| + |y_i-y_j|.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq x_i,y_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
x_1 y_1
x_2 y_2
:
x_N y_N

Output

Print the answer.

Sample Input 1

3
1 1
2 4
3 2

Sample Output 1

4

The Manhattan distance between the first point and the second point is |1-2|+|1-4|=4, which is maximum possible.

Sample Input 2

2
1 1
1 1

Sample Output 2

0

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

 
//It doesn't matter how slow you go, Unless you don't stop.
#include<iostream>
#include<algorithm>
#include<bitset>
 
#include<cmath>
#include<cstring>
#include<climits>
 
#include<deque>
#include<queue>
#include<vector>
#include<set>
#include<map>
#include<unordered_set>
#include<unordered_map>
 
#include<fstream>
#include<chrono>
using namespace std;
 
typedef long long LL;
typedef pair<LL,LL> p64;
typedef vector<LL> v64;
typedef map<LL,LL> mp64;
 
#define pb push_back
#define mp make_pair
#define ff first
#define ss second
#define rep(i,s,e) for(long long i=s;i<=e;i++)
#define brep(i,s,e) for(long long i=s;i>=e;i--)
#define all(x) x.begin(),x.end()
#define mem(x,y) memset(x,y,sizeof(x))
#define DANGER std::ios::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL)

void solve()
{
     int n;cin>>n;
     vector<LL> a(n);
     vector<LL> b(n);
     vector<LL> add(n);
     vector<LL> sub(n);
     for(int i=0;i<n;i++){
         cin>>a[i]>>b[i];
         add[i] = {a[i]+b[i]};
         sub[i] = {a[i]-b[i]};
     }
     sort(all(add));
     sort(all(sub));
     LL mx_add = add[n-1];
     LL mn_add = add[0];
     LL mx_sub = sub[n-1];
     LL mn_sub = sub[0];
     cout<<max(mx_add-mn_add,mx_sub-mn_sub);

     
     
}
 
int main()
{
    DANGER;
    ofstream out("output.txt");
 
    auto start = chrono::high_resolution_clock::now();
    
    LL t = 1;
    // cin>>t;
    rep(test,1,t)
    {
        solve();
    }
    
    auto stop = chrono::high_resolution_clock::now();
    // auto duration = chrono::duration_cast<chrono::milliseconds>(stop - start); 
    // cout << "Time taken by function: " << duration.count() << " milliseconds" << endl;
}