Problem:
Score : 200 points

Problem Statement

Let us define the FizzBuzz sequence a_1,a_2,... as follows:

If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.

If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.

If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.

If none of the above holds, a_i=i.

Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Constraints

1 \leq N \leq 10^6

Input

Input is given from Standard Input in the following format:

N

Output

Print the sum of all numbers among the first N terms of the FizzBuzz sequence.

Sample Input 1

15

Sample Output 1

60

The first 15 terms of the FizzBuzz sequence are:

1,2,\mbox{Fizz},4,\mbox{Buzz},\mbox{Fizz},7,8,\mbox{Fizz},\mbox{Buzz},11,\mbox{Fizz},13,14,\mbox{FizzBuzz}

Among them, numbers are 1,2,4,7,8,11,13,14, and the sum of them is 60.

Sample Input 2

1000000

Sample Output 2

266666333332

Watch out for overflow.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define SELECTER(_1, _2, _3, SELECT, ...) SELECT
#define REP1(i, n) for(int (i)=0; (i)<(n); (i)++)
#define REP2(i, a, b) for(int (i)=(a); (i)<(b); (i)++)
#define REP(...) SELECTER(__VA_ARGS__, REP2, REP1,) (__VA_ARGS__)
#define MOD 1'000'000'007

template <class T> ostream& operator<<(ostream& os, const vector<T>& v){ os << "{"; for(size_t i=0; i<v.size(); i++) os << v[i] << (i+1==v.size() ? "" : ", "); os << "}"; return os; }
template <class T, class U> ostream& operator<<(ostream& os, const pair<T, U>& p){ return os << "{" << p.first << ", " << p.second << "}"; }

int main(){
    int N;
    cin >> N;
    long long ans = 0;
    for(int i=1; i<=N; i++){
        if(i%3&&i%5) ans += i;
    }
    cout << ans << endl;
    return 0;
}