Problem:
Score : 200 points

Problem Statement

We have a string S consisting of uppercase English letters. Additionally, an integer N will be given.

Shift each character of S by N in alphabetical order (see below), and print the resulting string.

We assume that A follows Z. For example, shifting A by 2 results in C (A \to B \to C), and shifting Y by 3 results in B (Y \to Z \to A \to B).

Constraints

0 \leq N \leq 26

1 \leq |S| \leq 10^4

S consists of uppercase English letters.

Input

Input is given from Standard Input in the following format:

N
S

Output

Print the string resulting from shifting each character of S by N in alphabetical order.

Sample Input 1

2
ABCXYZ

Sample Output 1

CDEZAB

Note that A follows Z.

Sample Input 2

0
ABCXYZ

Sample Output 2

ABCXYZ

Sample Input 3

13
ABCDEFGHIJKLMNOPQRSTUVWXYZ

Sample Output 3

NOPQRSTUVWXYZABCDEFGHIJKLM

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <math.h>
#include <algorithm>
#include <queue>
#include <map>
#include <list>
//#include <bits/stdc++.h>


using namespace std;

#define FOR(i,a,b) for(int i=(a),i##formax=(b);i<i##formax;i++)
typedef long long ll;

int main(){
    int n;
    string s,all,ans;

    ans = "";    
    all = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
    
    cin >> n >> s;
    
    for(int i=0;i<(int) s.length();i++){
        char tmp = s[i];
         
        for(int j=0;j<26;j++){
            if(tmp == all[j]){
                int tp = (j + n) % 26;
                ans += all[tp];
            }
        }
    }

    cout << ans << endl; 

    return 0;
}