Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>

using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
#define en '\n'
#define fs first
#define sd second

bool f(ll& a, ll& b, char& ch, string& ss){
    if(a <=0 and b <= 0){
        return false;
    }else{
        if(a > b){
            ++b;
            --a;
            ch = ss[1];
        }else{
            ch = ss[0];
            --b;
            ++a;
        }
        return true;
    }
}

bool f1(ll& a, ll& b, char& ch, string& ss){
    if(a <=0 and b <= 0){
        return false;
    }else{
        if(a >= b){
            ++b;
            --a;
            ch = ss[1];
        }else{
            ch = ss[0];
            --b;
            ++a;
        }
        return true;
    }
}

int main() {
    ios::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);
    ll n, a, b, c;
    cin >> n >> a >> b >> c;
    bool have_res = true;
    vector<char> res(n);
    vector<string> ss(n);
    for(int i = 0; i < n; ++i){
        cin >> ss[i];
        if(have_res) {
            if (ss[i][0] == 'A' and ss[i][1] == 'B') {
                have_res = f(a, b, res[i], ss[i]);
            } else if (ss[i][0] == 'A' and ss[i][1] == 'C') {
                have_res = f(a, c, res[i], ss[i]);
            } else {
                have_res = f(b, c, res[i], ss[i]);
            }
        }
    }
    if(!have_res){
        have_res = true;
        for(int i = 0; i < n; ++i){
            if(ss[i][0] == 'A' and ss[i][1] == 'B'){
                have_res = f(a, b, res[i], ss[i]);
            }else if(ss[i][0] == 'A' and ss[i][1] == 'C'){
                have_res = f(a, c, res[i], ss[i]);
            }else{
                have_res = f(b, c, res[i], ss[i]);
            }
            if(!have_res){
                break;
            }
        }
        if(!have_res) {
            cout << "No" << en;
        } else {
            cout << "Yes" << en;
            for(auto& el : res){
                cout << el << en;
            }
        }
    }else{
        cout << "Yes" << en;
        for(auto& el : res){
            cout << el << en;
        }
    }

}