Problem:
Score : 400 points

Problem Statement

Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.

You are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.

Constraints

2 ≦ |s| ≦ 10^5

s consists of lowercase letters.

Partial Score

200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.

Input

The input is given from Standard Input in the following format:

s

Output

If there exists no unbalanced substring of s, print -1 -1.

If there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.

Sample Input 1

needed

Sample Output 1

2 5

The string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.

Sample Input 2

atcoder

Sample Output 2

-1 -1

The string atcoder contains no unbalanced substring.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
#define REP(i,n) for (int i = 0; i < (n); i++)
#define RREP(i, s, n) for (int i = s; i < (n); i++)
#define ALL(a) a.begin(), a.end()
#define RALL(a) a.rbegin(), a.rend()
using namespace std;
using ll = long long;
typedef pair<int, int> pint;
typedef pair<ll, ll> pll;
const ll MOD = 1000000007;
const ll INF = MOD * MOD;
const int inf = (1<<29);

int main() {

    string S;
    cin >> S;
    
    for(int i = 1; i < S.size(); i++) {
        if (S[i-1] == S[i]) {
            cout << i << " " << i+1 << endl;
            return 0;
        }
    }

    cout << -1 << " " << -1 << endl;
    return 0;

    return 0;
}