Problem:
Score : 100 points

Problem Statement

You are given positive integers A and B.

If A is a divisor of B, print A + B; otherwise, print B - A.

Constraints

All values in input are integers.

1 \leq A \leq B \leq 20

Input

Input is given from Standard Input in the following format:

A B

Output

If A is a divisor of B, print A + B; otherwise, print B - A.

Sample Input 1

4 12

Sample Output 1

16

As 4 is a divisor of 12, 4 + 12 = 16 should be printed.

Sample Input 2

8 20

Sample Output 2

12

Sample Input 3

1 1

Sample Output 3

2

1 is a divisor of 1.

Solution in C++ (GCC 5.4.1) (judge verdict: Accepted)

#include<iostream>
#include<string>
#include<algorithm>
#include<vector>
#include<map>
#include<cmath>
#include<string>
#include<bitset>
#include <sstream>
#include<queue>
#include<set>
#define rep(i,n) for(ll i=0;i<(n);++i)
using namespace std;
typedef long long ll;
typedef pair<int,ll>P;

const ll mod = 1e9+7;
const ll INF = 1e9;
const ll MAXN = 1e6;

int main()
{
    int a,b;
    cin>>a>>b;
    if(b%a==0)cout<<a+b;else cout<<b-a;
}