Problem:
Score : 400 points

Problem Statement

Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.

You are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.

Constraints

2 ≦ |s| ≦ 10^5

s consists of lowercase letters.

Partial Score

200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.

Input

The input is given from Standard Input in the following format:

s

Output

If there exists no unbalanced substring of s, print -1 -1.

If there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.

Sample Input 1

needed

Sample Output 1

2 5

The string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.

Sample Input 2

atcoder

Sample Output 2

-1 -1

The string atcoder contains no unbalanced substring.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#define _USE_MAT_DEFINES
#include<iostream>
#include <iomanip>
#include<stdio.h>
#include<string>
#include<vector>
#include<algorithm>
#include<cmath>
#include <queue>
#include <utility>
#include <map>
#include <set>
#include <deque>
#include <numeric>
#include <functional>
using namespace std;

bool isUnbalance(string s) {
    map<char, int>mp;
    for (int i = 0; i < s.size(); i++) {
        mp[s[i]]++;
    }
    for (int i = 0; i < mp.size(); i++) {
        if (mp[i] * 2 > s.size())return true;
    }
    return false;
}

int main() {
    string s;
    cin >> s;

    for (int i = 0; i < s.size(); i++) {
        for (int j = 2; i+j < s.size(); j++) {
            if (isUnbalance(s.substr(i, j))) {
                cout << i + 1 << " " << i + j + 1 << endl;
                return 0;
            }
        }
    }
    cout << -1 << " " << -1 << endl;
    
    return 0;
}