Problem:
Score : 300 points

Problem Statement

Snuke has N hats. The i-th hat has an integer a_i written on it.

There are N camels standing in a circle.
Snuke will put one of his hats on each of these camels.

If there exists a way to distribute the hats to the camels such that the following condition is satisfied for every camel, print Yes; otherwise, print No.

The bitwise XOR of the numbers written on the hats on both adjacent camels is equal to the number on the hat on itself.

What is XOR?

The bitwise XOR x_1 \oplus x_2 \oplus \ldots \oplus x_n of n non-negative integers x_1, x_2, \ldots, x_n is defined as follows:

- When x_1 \oplus x_2 \oplus \ldots \oplus x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.

For example, 3 \oplus 5 = 6.

Constraints

All values in input are integers.

3 \leq N \leq 10^{5}

0 \leq a_i \leq 10^{9}

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 \ldots a_{N}

Output

Print the answer.

Sample Input 1

3
1 2 3

Sample Output 1

Yes

If we put the hats with 1, 2, and 3 in this order, clockwise, the condition will be satisfied for every camel, so the answer is Yes.

Sample Input 2

4
1 2 4 8

Sample Output 2

No

There is no such way to distribute the hats; the answer is No.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<bits/stdc++.h>
using namespace std;

#define rep(i,n) for(int i=0;i<(n);++i)
#define reps(i,n) for(int i=1;i<=(n);++i)
#define repr(i,n) for(int i=(n);i>=0;--i)
#define cinv(n,v) VL v(n);rep(i,n)cin>>v[i]
#define int long long
#define itn int
#define pb push_back
#define eb emplace_back
#define m_p make_pair
#define m_t make_tuple
#define p_p(a,b) pb(m_p(a,b))
#define all(a) a.begin(),a.end()
#define SORT(a) sort(all(a))
#define RSORT(a) sort(all(a),greater<>())
#define UNIQUE(a) a.erase(unique(all(a)),a.end())
#define SZ(a) (signed)(a.size())
#define debg(a) cout<<#a<<" "<<a<<endl;
#define debgp(a) cout<<#a<<" "<<a.fi<<" : "<<a.se<<endl
#define call(a) for(auto i:a)cout<<i<<" ";cout<<endl
#define callp(a) for(auto [k,v]:a)cout<<k<<":"<<v<<endl
#define show(a) for(cont &y:a){for(cont &x:y){cout<<x<<" ";}cout<<endl;}
#define out(a) cout<<(a)<<endl
#define ENDL cout<<endl
#define YES cout<<"YES"<<endl
#define NO cout<<"NO"<<endl
#define Yes cout<<"Yes"<<endl
#define No cout<<"No"<<endl
#define LINE puts("------------------")
#define fi first
#define se second
#define V vector
#define P pair
#define T tuple
#define PQ priority_queue
#define cont const auto
#define VV(type,name,y,x,a) vector<vector<type>> name = vector<vector<type>>(y,vector<type>(x,a))
typedef long long ll;
typedef double D;
typedef long double LD;
typedef string str;
typedef vector<ll> VL;
typedef pair<ll,ll> PL;
typedef vector<pair<ll,ll>> VP;
typedef tuple<ll,ll,ll> T3;
typedef tuple<ll,ll,ll,ll> T4;
typedef struct{ll to;ll cost;} Graphs;
typedef V<V<Graphs>> AdjList;
const signed INF = (1LL<<30);
const long long MOD = (1e9+7);
const long long LINF = (1LL<<60);
const long long LMAX = LLONG_MAX;
void YN(bool b){cout<<(b?"Yes":"No")<<endl;}

template<class T>inline T gcd(T a,T b){if(b==0)return a; return(gcd(b,a%b));}
template<class T>inline T lcm(T a,T b){return a/gcd(a,b)*b;}
template<class T>inline bool chmax(T &a,const T &b){if(a<b){a=b;return true;}return false;}
template<class T>inline bool chmin(T &a,const T &b){if(a>b){a=b;return true;}return false;}
template<class T>T center(T a,T b,T c){
  if( (a<=b&&b<=c)||(a>=b&&b>=c) )return b;
  if( (b>=a&&a>=c)||(b<=a&&a<=c) )return a;
  return c;
}
void print(){cout<<endl;}
template<class Head,class... Tail>
void print(Head&& head, Tail&&... tail){
  cout<<head<<", ";
  print(forward<Tail>(tail)...);
}
void input(){}
template<class Head,class... Tail>
void input(Head&& head, Tail&&... tail){
  cin>>head;
  input(forward<Tail>(tail)...);
}
template<typename T>
ostream &operator<<(ostream&out,const vector<T>&v){
  if(!v.empty()){
    copy(v.begin(),v.end(),ostream_iterator<T>(out,", "));
    out<<"\b\b";
  }
  return out;
}
template<typename T1, typename T2>
ostream &operator<<(ostream&out,const pair<T1,T2>&p){
  out<<p.first<<", "<<p.second;
  return out;
}

signed main(){
  cin.tie(0);
  ios::sync_with_stdio(false);
  cout<<fixed<<setprecision(10);
  
  ll n;
  cin>>n;
  map<ll,ll> x;
  vector<ll> a(n);
  rep(i,n){
    cin>>a[i];
    x[a[i]]++;
  }
  if(SZ(a)>3||n%3!=0){
    No;
    return 0;
  }
  ll res=0;
  for(auto s:a)res^=s;
  if(res==0)Yes;
  else No;




  return 0;
}