Problem:
Score : 600 points

Problem Statement

Snuke has an integer sequence, a, of length N. The i-th element of a (1-indexed) is a_{i}.

He can perform the following operation any number of times:

Operation: Choose integers x and y between 1 and N (inclusive), and add a_x to a_y.

He would like to perform this operation between 0 and 2N times (inclusive) so that a satisfies the condition below. Show one such sequence of operations.
It can be proved that such a sequence of operations always exists under the constraints in this problem.

Condition: a_1 \leq a_2 \leq ... \leq a_{N}

Constraints

2 \leq N \leq 50

-10^{6} \leq a_i \leq 10^{6}

All input values are integers.

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 ... a_{N}

Output

Let m be the number of operations in your solution. In the first line, print m.
In the i-th of the subsequent m lines, print the numbers x and y chosen in the i-th operation, with a space in between.
The output will be considered correct if m is between 0 and 2N (inclusive) and a satisfies the condition after the m operations.

Sample Input 1

3
-2 5 -1

Sample Output 1

2
2 3
3 3

After the first operation, a = (-2,5,4).

After the second operation, a = (-2,5,8), and the condition is now satisfied.

Sample Input 2

2
-1 -3

Sample Output 2

1
2 1

After the first operation, a = (-4,-3) and the condition is now satisfied.

Sample Input 3

5
0 0 0 0 0

Sample Output 3

0

The condition is satisfied already in the beginning.

Solution in C++14 (GCC 5.4.1) (judge verdict: Runtime Error)

#include<bits/stdc++.h>
using namespace std;
int num;
int t[220];
int main()
{
	int n;
	cin>>n;
	int a[n+1];
	int i,j,k=0;
	for(i=1;i<=n;i++)
	{
		cin>>a[i];
	}
	for(i=1;i<=n-1;i++)
	{
		for(j=i+1;j<=n;j++)
		{
			if(a[j]<a[i])
			{				
				if(num<=2*n)
				{
					if(a[i]>0)
					{
						while(a[j]<a[i])
						{
							a[j]+=a[i];
							t[++k]=i;
							t[++k]=j;
							num++;
						}
					}
					else
					{
						a[i]+=a[j];
						t[++k]=j;
						t[++k]=i;
						num++;
					}
				}
				else
				{
					break;
				}
			}
		}
	}
	if(num<=2*n)
	{
		cout<<num<<endl;
		for(i=1;i<=k;i++)
		{
			cout<<t[i]<<' ';
			if(i%2==0)
			{
				cout<<endl;
			}
		}
	}
	return 0;
}