Problem:
Score : 300 points

Problem Statement

There are N slimes lining up from left to right. The colors of these slimes will be given as a string S of length N consisting of lowercase English letters. The i-th slime from the left has the color that corresponds to the i-th character of S.

Adjacent slimes with the same color will fuse into one larger slime without changing the color. If there were a slime adjacent to this group of slimes before fusion, that slime is now adjacent to the new larger slime.

Ultimately, how many slimes will be there?

Constraints

1 \leq N \leq 10^5

|S| = N

S consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

N
S

Output

Print the final number of slimes.

Sample Input 1

10
aabbbbaaca

Sample Output 1

5

Ultimately, these slimes will fuse into abaca.

Sample Input 2

5
aaaaa

Sample Output 2

1

All the slimes will fuse into one.

Sample Input 3

20
xxzaffeeeeddfkkkkllq

Sample Output 3

10

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <algorithm>
#include <stdio.h>

using namespace std;

#define LL long long
#define FOR(i,l,r) for(int i = l; i <= r; ++i)
#define REP(i,l,r) for(int i = l; i < r; ++i)

int N;
string s;

int main(){
    ios_base::sync_with_stdio(false);
    cin.tie();
    cout.tie();
    //
    cin >> N;
    cin >> s;
    int r = 1;
    for(int i = 1; i < s.size(); ++i){
        if(s[i] != s[i - 1]) ++r;
    }

    cout << r;

    return 0;

}