Problem:
Score : 200 points

Problem Statement

Two children are playing tag on a number line. (In the game of tag, the child called "it" tries to catch the other child.) The child who is "it" is now at coordinate A, and he can travel the distance of V per second.
The other child is now at coordinate B, and she can travel the distance of W per second.

He can catch her when his coordinate is the same as hers.
Determine whether he can catch her within T seconds (including exactly T seconds later).
We assume that both children move optimally.

Constraints

-10^9 \leq A,B \leq 10^9

1 \leq V,W \leq 10^9

1 \leq T \leq 10^9

A \neq B

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A V
B W
T

Output

If "it" can catch the other child, print YES; otherwise, print NO.

Sample Input 1

1 2
3 1
3

Sample Output 1

YES

Sample Input 2

1 2
3 2
3

Sample Output 2

NO

Sample Input 3

1 2
3 3
3

Sample Output 3

NO

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>

using namespace std;
typedef long long ll;
typedef vector<ll> vl;
typedef vector<string> vs;
using pll = pair<ll, ll>;
using vl = vector<ll>;
using vll = vector<vl>;
using vpll = vector<pll>;
struct Edge {
	ll to;
	ll cost;
};
using Graph = vector<vector<Edge>>;

#define FOR(i, a, b) for (ll i = (a); i < (b); i++)
#define REP(i, n) FOR(i, 0, n)
#define ALL(a) (a).begin(), (a).end()
/***** define constant start *******/
const ll MOD = 1000000007;
const double PI = 2.0 * asin(1.0);
const ll INF = 1L<<60;
string abc = "abcdefghijklmnopqrstuvwxyz";
string ABC = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
const ll MAX = 10000000;
/****** define constant end ********/
/****** define variable start ******/
long double a, v, b, w, t;
/******* define variable end *******/
int solve() {
	cin >> a >> v >> b >> w >> t;
	long double ok = (b-a)/(v-w);
	if(ceil(ok) == floor(ok) && t >= ok && ok >= 0){
		cout << "YES" << endl;
	}else{
		cout << "NO" << endl;
	}
	return 0;
}

int main() {
	//clock_t start = clock();
	cout << std::fixed << std::setprecision(10);
	ios::sync_with_stdio(false);
	cin.tie(nullptr);
	int end_solve = solve();
	/*
	clock_t end = clock();
	const double time = static_cast<double>(end - start) / CLOCKS_PER_SEC *
	1000.0; printf("time %lf[ms]\n", time);
	*/

	return end_solve;
}