Problem:
Score : 400 points

Problem Statement

We have a tree with N vertices numbered 1 to N.
The i-th edge in the tree connects Vertex u_i and Vertex v_i, and its length is w_i.
Your objective is to paint each vertex in the tree white or black (it is fine to paint all vertices the same color) so that the following condition is satisfied:

For any two vertices painted in the same color, the distance between them is an even number.

Find a coloring of the vertices that satisfies the condition and print it. It can be proved that at least one such coloring exists under the constraints of this problem.

Constraints

All values in input are integers.

1 \leq N \leq 10^5

1 \leq u_i < v_i \leq N

1 \leq w_i \leq 10^9

Input

Input is given from Standard Input in the following format:

N
u_1 v_1 w_1
u_2 v_2 w_2
.
.
.
u_{N - 1} v_{N - 1} w_{N - 1}

Output

Print a coloring of the vertices that satisfies the condition, in N lines.
The i-th line should contain 0 if Vertex i is painted white and 1 if it is painted black.

If there are multiple colorings that satisfy the condition, any of them will be accepted.

Sample Input 1

3
1 2 2
2 3 1

Sample Output 1

0
0
1

Sample Input 2

5
2 5 2
2 3 10
1 3 8
3 4 2

Sample Output 2

1
0
1
0
1

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
#include <unordered_map>

using namespace std;
typedef long long int ll;
typedef long double ld;
#define rep(i, n) for(ll i = 0; i < (ll)(n); i++)
#define repr(i, n) for (ll i = (ll)(n) - 1; i >= 0; i--)
#define all(x) (x).begin(),(x).end()
#define MOD 1000000007
#define INF (1LL << 62)

#define PI (acos(-1))
#define print(x) cout << x << endl
 
ll gcd(ll a, ll b) { return b ? gcd(b,a%b) : a;}
ll lcm(ll a, ll b) { return a / gcd(a, b) * b; }
ll countDigit(ll n) { return floor(log10(n) + 1); } 
typedef pair <ll,ll> P;
static const ll dy[4] = {0,1,0,-1}, dx[4] = {1,0,-1,0};

template <typename T> 
ostream& operator<<(ostream& os, const vector<T>& v) 
{ 
    for (int i = 0; i < (int)v.size(); ++i) os << v[i] << " ";  
    return os; 
}

template <typename T1, typename T2> 
ostream& operator<<(ostream& os, const map<T1, T2>& m) 
{ 
    for (auto p : m) os << "<" << p.first << ", " << p.second << "> "; 
    return os; 
}


template<int mod>
struct ModInt{
    int x;
    ModInt():x(0){}
    ModInt(long long y):x(y>=0?y%mod:(mod-(-y)%mod)%mod){}
    ModInt &operator+=(const ModInt &p){
        if((x+=p.x)>=mod)x-=mod;
        return *this;
    }
    ModInt &operator-=(const ModInt &p){
        if((x+=mod-p.x)>=mod)x-=mod;
        return *this;
    }
    ModInt &operator*=(const ModInt &p){
        x=(int)(1LL*x*p.x%mod);
        return *this;
    }
    ModInt &operator/=(const ModInt &p){
        *this*=p.inverse();
        return *this;
    }
    ModInt &operator^=(long long p){
        ModInt res = 1;
        for (; p; p >>= 1) {
            if (p & 1) res *= *this;
            *this *= *this;
        }
        return *this = res;
    }
    ModInt operator-()const{return ModInt(-x);}
    ModInt operator+(const ModInt &p)const{return ModInt(*this)+=p;}
    ModInt operator-(const ModInt &p)const{return ModInt(*this)-=p;}
    ModInt operator*(const ModInt &p)const{return ModInt(*this)*=p;}
    ModInt operator/(const ModInt &p)const{return ModInt(*this)/=p;}
    ModInt operator^(long long p)const{return ModInt(*this)^=p;}
    bool operator==(const ModInt &p)const{return x==p.x;}
    bool operator!=(const ModInt &p)const{return x!=p.x;}
    explicit operator int() const { return x; }						   // added by QCFium
    ModInt operator=(const int p) {x = p; return ModInt(*this);} // added by QCFium
    ModInt inverse()const{
        int a=x,b=mod,u=1,v=0,t;
        while(b>0){
            t=a/b;
            a-=t*b;
            std::swap(a,b);
            u-=t*v;
            std::swap(u,v);
        }
        return ModInt(u);
    }
    friend std::ostream &operator<<(std::ostream &os,const ModInt<mod> &p){
        return os<<p.x;
    }
    friend std::istream &operator>>(std::istream &is,ModInt<mod> &a){
        long long x;
        is>>x;
        a=ModInt<mod>(x);
        return (is);
    }
};
typedef ModInt<MOD> mint;
 
struct MComb {
    std::vector<mint> fact;
    std::vector<mint> inversed;
    MComb(int n) { // O(n+log(mod))
        fact = std::vector<mint>(n+1,1);
        for (int i = 1; i <= n; i++) fact[i] = fact[i-1]*mint(i);
        inversed = std::vector<mint>(n+1);
        inversed[n] = fact[n] ^ (MOD-2);
        for (int i = n - 1; i >= 0; i--) inversed[i]=inversed[i+1]*mint(i+1);
    }
    mint ncr(int n, int r) {
        return (fact[n] * inversed[r] * inversed[n-r]);
    }
    mint npr(int n, int r) {
        return (fact[n] * inversed[n-r]);
    }
    mint nhr(int n, int r) {
        assert(n+r-1 < (int)fact.size());
        return ncr(n+r-1, r);
    }
};
 
mint ncr(int n, int r) {
    mint res = 1;
    for (int i = n - r + 1; i <= n; i++) res *= i;
    for (int i = 1; i <= r; i++) res /= i;
    return res;
}

int main()
{
    ll N;
    cin >> N;
    vector<vector<P>> mat(N, vector<P>());
    rep(i, N) {
        ll u, v, w;
        cin >> u >> v >> w;
        u--; v--;
        mat[u].push_back(P(v, w));
    }
    vector<bool> visited(N, false);
    vector<bool> color(N, false);

    queue<P> que;
    que.push(P(0, 0));
    visited[0] = true;
    while(!que.empty()) {
        P p = que.front();
        que.pop();
        if (p.second % 2 == 1) color[p.first] = true;
        for(P tmp : mat[p.first]) {
            if (!visited[tmp.first]) {
                visited[tmp.first] = true;
                que.push(P(tmp.first, tmp.second + p.second));
            }
        }
    }
    rep(i, N) print(color[i]);
    return 0;
}