Problem:
Score : 200 points

Problem Statement

In the beginning, Takahashi has A cookies, and Aoki has B cookies.
They will perform the following operation alternately, starting from Takahashi:

If the number of cookies in his hand is odd, eat one of those cookies; if the number is even, do nothing. Then, give one-half of the cookies in his hand to the other person.

Find the numbers of cookies Takahashi and Aoki respectively have after performing K operations in total.

Constraints

1 \leq A,B \leq 10^9

1 \leq K \leq 100

A,B and K are integers.

Input

Input is given from Standard Input in the following format:

A B K

Output

Print the number of cookies Takahashi has, and the number of cookies Aoki has, in this order, after performing K operations in total.

Sample Input 1

5 4 2

Sample Output 1

5 3

The process will go as follows:

In the beginning, Takahashi and Aoki have 5 and 4 cookies, respectively.

Takahashi eats one cookie and gives two cookies to Aoki. They now have 2 and 6 cookies, respectively.

Aoki gives three cookies to Takahashi. They now have 5 and 3 cookies, respectively.

Sample Input 2

3 3 3

Sample Output 2

1 3

Sample Input 3

314159265 358979323 84

Sample Output 3

448759046 224379523

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

/* 
	Author: ankrypt
*/


#include <bits/stdc++.h>

using namespace std;

#define MOD 1000000007
#define ll long long int
#define u64 unsigned long long int

ll A, B, K;

int main() {
	scanf("%lld %lld %lld", &A, &B, &K);
	for(int i = 0; i < K; i++) {
		if(i % 2 == 0) {
			if(A % 2 != 0 && A != 0) {
				A -= 1;
				A -= A / 2;
				B += A;
			}
			else if(A % 2 == 0 && A != 0){
				A -= A / 2;
				B += A;
			}
		}
		else {
			if(B % 2 != 0 && B != 0) {
				B -= 1;
				B -= B / 2;
				A += B;
			}
			else if(B % 2 == 0 && B != 0){
				B -= B / 2;
				A += B;
			}
		}
		// cout << A << " " << B;
	}
	printf("%lld %lld\n", A, B);
	return 0;
}
/*
	Powered by Buggy Plugin
*/