Problem:
Score : 200 points

Problem Statement

Tak performed the following action N times: rolling two dice.
The result of the i-th roll is D_{i,1} and D_{i,2}.

Check if doublets occurred at least three times in a row.
Specifically, check if there exists at lease one i such that D_{i,1}=D_{i,2}, D_{i+1,1}=D_{i+1,2} and D_{i+2,1}=D_{i+2,2} hold.

Constraints

3 \leq N \leq 100

1\leq D_{i,j} \leq 6

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
D_{1,1} D_{1,2}
\vdots
D_{N,1} D_{N,2}

Output

Print Yes if doublets occurred at least three times in a row. Print No otherwise.

Sample Input 1

5
1 2
6 6
4 4
3 3
3 2

Sample Output 1

Yes

From the second roll to the fourth roll, three doublets occurred in a row.

Sample Input 2

5
1 1
2 2
3 4
5 5
6 6

Sample Output 2

No

Sample Input 3

6
1 1
2 2
3 3
4 4
5 5
6 6

Sample Output 3

Yes

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)


#include<bits/stdc++.h>
using namespace std;

#define ff              first
#define fo(i,n)         for(i=0;i<n;i++)
#define Fo(i,k,n)       for(i=k;k<n?i<n:i>n;k<n?i+=1:i-=1)
#define deb(x)          cout << #x << "=" << x << endl
#define deb2(x, y)      cout << #x << "=" << x << "," << #y << "=" << y << endl
#define ss              second
#define int             long long
#define pb              push_back
#define mp              make_pair
#define pii             pair<int,int>
#define vi              vector<int>
#define mii             map<int,int>
#define pqb             priority_queue<int>
#define pqs             priority_queue<int,vi,greater<int> >
#define setbits(x)      __builtin_popcountll(x)
#define zrobits(x)      __builtin_ctzll(x)
#define mod             1000000007
#define inf             1e18
#define ps(x,y)         fixed<<setprecision(y)<<x
#define w(x)            int x; cin>>x; while(x--)
#define FIO             ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0)
mt19937                 rng(chrono::steady_clock::now().time_since_epoch().count());


const int N = 3e5, M = N;
//=======================


void solve() {
  int i, j, n, m;
  cin>>n;
  vector<pair<int,int>> d(n);
  int count=0;
  int flag=0;
  fo(i,n){
    cin>>d[i].first>>d[i].second;
    if(d[i].first==d[i].second){
        count++;
        if(count>=3){
            flag=1;
        }
    }
    else{
        count=0;
    }
    
  }
  if(flag){
        cout<<"Yes";
    }
    else{
        cout<<"No";
    }
}

int32_t main()
{
  FIO;
#ifndef ONLINE_JUDGE
  freopen("input.txt", "r", stdin);
  freopen("output.txt", "w", stdout);
#endif
  
  solve();
  return 0;
}