Problem:
Score : 200 points

Problem Statement

You are given a string S. Each character of S is uppercase or lowercase English letter.
Determine if S satisfies all of the following conditions:

The initial character of S is an uppercase A.

There is exactly one occurrence of C between the third character from the beginning and the second to last character (inclusive).

All letters except the A and C mentioned above are lowercase.

Constraints

4 ≤ |S| ≤ 10 (|S| is the length of the string S.)

Each character of S is uppercase or lowercase English letter.

Input

Input is given from Standard Input in the following format:

S

Output

If S satisfies all of the conditions in the problem statement, print AC; otherwise, print WA.

Sample Input 1

AtCoder

Sample Output 1

AC

The first letter is A, the third letter is C and the remaining letters are all lowercase, so all the conditions are satisfied.

Sample Input 2

ACoder

Sample Output 2

WA

The second letter should not be C.

Sample Input 3

AcycliC

Sample Output 3

WA

The last letter should not be C, either.

Sample Input 4

AtCoCo

Sample Output 4

WA

There should not be two or more occurrences of C.

Sample Input 5

Atcoder

Sample Output 5

WA

The number of C should not be zero, either.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;
#define rep(i,n) for(int i=0;i<(int)(n);++i)
#define repone(i,n) for(int i=1;i<(int)(n);++i)
#define repo(i,o,n) for(int i=o;i<(int)(n);++i)
#define Rep(j,n) for(int j=0;j<(int)(n);++j)
#define Repo(j,o,n) for(int j=o;j<(int)(n);++j)
#define Repone(j,n) for(int j=1;j<(int)(n);++j)
#define all(v) (v).begin(),(v).end()
#define rall(v) (v).rbegin(),(v).rend()
#define int long long
#define pb(a) push_back(a)
#define eraser(v,i) (v).erase(v.begin()+(i))
#define pbpair(a,b) push_back(make_pair(a,b))
#define MOD 1000000007
#define INF 9223372036854775807
#define pairint pair<int,int>
signed main()
{
int x=0,y=0,z=0,w=0,n=0,m=0,a=0,b=0;
string s="";
std::cin >> s;
rep(i,s.size()){
  if(i==0){
    if(s[i]!='A'){
      std::cout << "WA" << '\n';
      return 0;
    }
  }
  else if(i==2){
    if(s[i]!='C'){
      std::cout << "WA" << '\n';
      return 0;
    }
  }
  else if(isupper(s[i])){
    std::cout << "WA" << '\n';
    return 0;
  }
}
std::cout << "AC" << '\n';
}