Problem:
Score : 200 points

Problem Statement

There are N + 1 squares arranged in a row, numbered 0, 1, ..., N from left to right.

Initially, you are in Square X.
You can freely travel between adjacent squares. Your goal is to reach Square 0 or Square N.
However, for each i = 1, 2, ..., M, there is a toll gate in Square A_i, and traveling to Square A_i incurs a cost of 1.
It is guaranteed that there is no toll gate in Square 0, Square X and Square N.

Find the minimum cost incurred before reaching the goal.

Constraints

1 \leq N \leq 100

1 \leq M \leq 100

1 \leq X \leq N - 1

1 \leq A_1 < A_2 < ... < A_M \leq N

A_i \neq X

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M X
A_1 A_2 ... A_M

Output

Print the minimum cost incurred before reaching the goal.

Sample Input 1

5 3 3
1 2 4

Sample Output 1

1

The optimal solution is as follows:

First, travel from Square 3 to Square 4. Here, there is a toll gate in Square 4, so the cost of 1 is incurred.

Then, travel from Square 4 to Square 5. This time, no cost is incurred.

Now, we are in Square 5 and we have reached the goal.

In this case, the total cost incurred is 1.

Sample Input 2

7 3 2
4 5 6

Sample Output 2

0

We may be able to reach the goal at no cost.

Sample Input 3

10 7 5
1 2 3 4 6 8 9

Sample Output 3

3

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<iostream>
#include<string>
#include<string.h>
#include<map>
#include<set>
#include<vector>
#include<stdio.h>
#include<math.h>
#include<algorithm>
#include<queue> 
using namespace std;
int n,m,x,ans;
int main() 
{cin>>n>>m>>x;
 int k[2*m];
 for (int i=0;i<m;i++)
 cin>>k[i]; 
 if (x>=n-x){{
 for (int i=0;i<m;i++){
 if (k[i]>=n)
 k[i]=0;
 if (k[i]>x)
 ans++;}}}
 if (x<n-x){
 for (int i=0;i<m;i++){
 if (k[i]<x)
 ans--;}}
 if (x>=n)
 ans=0;
 cout<<ans;
 
  
 system("pause");
 return 0;
}