Problem:
Score : 200 points

Problem Statement

Takahashi has A cookies, and Aoki has B cookies.
Takahashi will do the following action K times:

If Takahashi has one or more cookies, eat one of his cookies.

Otherwise, if Aoki has one or more cookies, eat one of Aoki's cookies.

If they both have no cookies, do nothing.

In the end, how many cookies will Takahashi and Aoki have, respectively?

Constraints

0 \leq A \leq 10^{12}

0 \leq B \leq 10^{12}

0 \leq K \leq 10^{12}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B K

Output

Print the numbers of Takahashi's and Aoki's cookies after K actions.

Sample Input 1

2 3 3

Sample Output 1

0 2

Takahashi will do the following:

He has two cookies, so he eats one of them.

Now he has one cookie left, and he eats it.

Now he has no cookies left, but Aoki has three, so Takahashi eats one of them.

Thus, in the end, Takahashi will have 0 cookies, and Aoki will have 2.

Sample Input 2

500000000000 500000000000 1000000000000

Sample Output 2

0 0

Watch out for overflows.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define ll                      long long int
#define pb                      push_back
#define rep(i,a,b,c)            for(ll i=(a);i<=(b);i+=(c))
#define repb(i,a,b,c)           for(ll i=(a);i>=(b);i-=(c))
#define MOD                     1000000007
#define inf                     3e18
#define ld                      long double
//#define mp                      make_pair
#define vpll                    vector<pair<ll,ll>>
#define sll                     set<ll>
#define vll                     vector<ll>
#define vld                     vector<ld>
#define vvll                    vector<vector<ll>>
#define vvld                    vector<vector<ld>>
#define pll                     pair<ll,ll>
#define vvpll                   vector<vector<pair<ll,ll>>>
#define pqll                    priority_queue<ll>
#define mll                     map<ll,ll>
#define mlc                     map<ll,char>
#define um                      unordered_map
#define umll                    um<ll,ll>
#define umlc                    um<ll,char>
#define all(x)                  x.begin(),x.end()
#define fi                      first
#define se                      second
#define ln                      cout<<"\n";
#define endl                    "\n"
#define test                    ll Testcases;cin>>Testcases;while(Testcases--)
#define isvowel(a)              (a == 'a' || a == 'e' || a == 'i' || a == 'o' || a == 'u')
#define fastIO                  ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define show(w,size)            for(ll i=0;i<size;i++) cout<<w[i]<<" ";
#define print(a)                cout<<a<<"\n";
#define mset(dp,no)             memset(dp,no,sizeof(dp))
#define input(a,n)              rep(i,0,n-1,1) cin>>a[i];
#define countbit                __builtin_popcount                                           //Number of setbits in decimal notation
#define lb(v,val)               lower_bound(all(v),val)-v.begin()
#define ub(v,val)               upper_bound(all(v),val)-v.begin()
#define SS                      stringstream
#define db(...)                 __f(#__VA_ARGS__, __VA_ARGS__)
template <typename Arg1>
void __f(const char* name, Arg1&& arg1) { cerr << name << " : " << arg1 <<'\n'; }
template <typename Arg1, typename... Args>
void __f(const char* names, Arg1&& arg1, Args&&... args) {
    const char* comma = strchr(names + 1, ',');
    cerr.write(names, comma - names) << " : " << arg1 << " | "; __f(comma + 1, args...);
}

ll poww(ll b,ll e){if(e==0)return 1;else if(e%2==0){ll a=pow(b,e/2);return a*a;}else {ll a=pow(b,e/2);return b*a*a;}}
ll powm(ll x,ll y,ll m=MOD){x=x%m;ll res=1;while(y){if(y&1)res=res*x;res%=m;y=y>>1;x=x*x;x%=m;}return res;}
ll modInverse(ll a, ll m=MOD) { return powm(a, m-2, m);}

int main()
{
	fastIO
	ll a,b,k;
	cin>>a>>b>>k;
	ll fa=max(a-k,0ll);
	k-=(a-fa);
	b=max(b-k,0ll);
	cout<<fa<<" "<<b;
	return 0;
}