Problem:
Score : 200 points

Problem Statement

You are given string S and T consisting of lowercase English letters.

Determine if S equals T after rotation.

That is, determine if S equals T after the following operation is performed some number of times:

Operation: Let S = S_1 S_2 ... S_{|S|}. Change S to S_{|S|} S_1 S_2 ... S_{|S|-1}.

Here, |X| denotes the length of the string X.

Constraints

2 \leq |S| \leq 100

|S| = |T|

S and T consist of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S equals T after rotation, print Yes; if it does not, print No.

Sample Input 1

kyoto
tokyo

Sample Output 1

Yes

In the first operation, kyoto becomes okyot.

In the second operation, okyot becomes tokyo.

Sample Input 2

abc
arc

Sample Output 2

No

abc does not equal arc after any number of operations.

Sample Input 3

aaaaaaaaaaaaaaab
aaaaaaaaaaaaaaab

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <algorithm>
#include <string>
#include <cmath>
#include <ctype.h>
#include <map>
#include <vector>
#include <stdlib.h>
#include <stdio.h>
#include <cctype>
#include <queue>
#define REP(i,n) for(int i=0;i<(int)n;++i)
#define REP1(j,n) for(int j=0;j<(int)n;++j)
#define REPD(i,n) for(int i=n;i>=0;--i)
#define REPD1(j,n) for(int j=n;j=>0;--j)
#define REPS(i,n) for(int i=1;i<=(int)n;++i)
#define REPS1(j,n) for(int j=1;j<=(int)n;++j)
#define rep(i,a,n) for(int i=a;i<=(int)n;++i)
#define SZ(x) ((int)(x).size())	//size() unsigned -> int
#define DescSort(a) sort(a.begin(),a.end(),std::greater<int>())

using namespace std;
typedef long long ll;
const ll INF=1e9+7;
int main(void) {
	string s, t;
	cin >> s >> t;
	for(int i=0;i<s.size();++i) {
		rotate(s.rbegin(), s.rbegin() + 1, s.rend());
		if (s == t) {
			cout << "Yes" << endl;
			return 0;
		}
	}
	cout << "No" << endl;
	return 0;
}