Problem:
Score : 200 points

Problem Statement

There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is R, and a blue hat if s_i is B.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

1 \leq N \leq 100

|s| = N

s_i is R or B.

Input

Input is given from Standard Input in the following format:

N
s

Output

If there are more people wearing a red hat than there are people wearing a blue hat, print Yes; otherwise, print No.

Sample Input 1

4
RRBR

Sample Output 1

Yes

There are three people wearing a red hat, and one person wearing a blue hat.

Since there are more people wearing a red hat than people wearing a blue hat, the answer is Yes.

Sample Input 2

4
BRBR

Sample Output 2

No

There are two people wearing a red hat, and two people wearing a blue hat.

Since there are as many people wearing a red hat as people wearing a blue hat, the answer is No.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <string>
#include <vector>
#include <climits>
#include <set>
#include <algorithm>
#include <unordered_map>
#include <queue>
#include <iomanip>
#include <map>
#include <utility>
#include <numeric>
#include <chrono>
#include <ctime>
#include <bitset>
#include <iterator>
#include <cmath>
#include <stack>
#include <random>

#define rep(i,n) for(int i=0; i<(int)(n); i++)
#define debug(x) cerr << #x << ": " << x << ", "
#define debugln(x) cerr << #x << ": " << x << '\n'

template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }

using namespace std;
using ll = long long;
using P = pair<ll, ll>;

constexpr ll mod = 1e9+7;
const double PI = acos(-1.0);
mt19937_64 engine(chrono::steady_clock::now().time_since_epoch().count());

signed main() {

  int n; cin >> n;
  string s; cin >> s;
  int cnt = 0;
  int cntb = 0;
  for(auto e: s) {
    if (e == 'R') {
      cnt++;
    } else {
      cntb++;
    }
  }
  if (cnt > cntb) {
    cout << "Yes" << endl;
  } else {
    cout << "No" << endl;
  }

}