Problem:
Score : 100 points

Problem Statement

There are N items, numbered 1, 2, \ldots, N.
For each i (1 \leq i \leq N), Item i has a weight of w_i and a value of v_i.

Taro has decided to choose some of the N items and carry them home in a knapsack.
The capacity of the knapsack is W, which means that the sum of the weights of items taken must be at most W.

Find the maximum possible sum of the values of items that Taro takes home.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq W \leq 10^9

1 \leq w_i \leq W

1 \leq v_i \leq 10^3

Input

Input is given from Standard Input in the following format:

N W
w_1 v_1
w_2 v_2
:
w_N v_N

Output

Print the maximum possible sum of the values of items that Taro takes home.

Sample Input 1

3 8
3 30
4 50
5 60

Sample Output 1

90

Items 1 and 3 should be taken.
Then, the sum of the weights is 3 + 5 = 8, and the sum of the values is 30 + 60 = 90.

Sample Input 2

1 1000000000
1000000000 10

Sample Output 2

10

Sample Input 3

6 15
6 5
5 6
6 4
6 6
3 5
7 2

Sample Output 3

17

Items 2, 4 and 5 should be taken.
Then, the sum of the weights is 5 + 6 + 3 = 14, and the sum of the values is 6 + 6 + 5 = 17.

Solution in C++14 (GCC 5.4.1) (judge verdict: Time Limit Exceeded)

/*input
 
*/
/*
Contest: 
Problem: 
*/
#include<bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
 
using namespace __gnu_pbds;
using namespace std;
 
#pragma comment(linker, "/stack:200000000")
#pragma GCC optimize("Ofast")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
#pragma GCC optimize("unroll-loops")
 
#define F first
#define S second
#define mp make_pair
#define append push_back
#define vi vector<ll>
#define pii pair<ll,ll>
#define qi queue<ll>
#define mem(a,b) memset(a,b,sizeof(a))
#define ll long long int
#define print(a) cout<<a<<endl
#define sorted(a) sort(arr.begin(), arr.end())
#define gcd(a,b) __gcd((a),(b))
#define lcm(a,b) ((a)*(b))/gcd((a),(b))
#define read(a) scanf("%d", &a)
#define int long long int
 
const int MOD = 1e9 + 7, MAXN = 1e2 + 10, MAXW = 1e5 + 10;
 
int N, W;
vector<int> value, weight;
map<pair<int, int>, int> dp;
 
int solve(int i, int we){
    if(i < 0)
        return 0;
    if(dp.find(mp(i, we)) != dp.end())
        return dp[mp(i, we)];
    if(weight[i] > we)
        return dp[mp(i, we)] = solve(i - 1, we);
    else
        return dp[mp(i, we)] = max(solve(i - 1, we), value[i] + solve(i - 1, we - weight[i]));
}
 
signed main(){
    
    cin>> N >> W;
 
    value.resize(N);
    weight.resize(N);
 
    for(int i = 0; i < N; i++)
        cin>> weight[i] >> value[i];
 
    dp.clear();
 
    print(solve(N-1, W));
 
    cerr << "\nTime elapsed: " << 1000 * clock() / CLOCKS_PER_SEC << "ms\n";
    return 0;
}