Problem:
Score : 300 points

Problem Statement

1000000000000001 dogs suddenly appeared under the roof of Roger's house, all of which he decided to keep. The dogs had been numbered 1 through 1000000000000001, but he gave them new names, as follows:

the dogs numbered 1,2,\cdots,26 were respectively given the names a, b, ..., z;

the dogs numbered 27,28,29,\cdots,701,702 were respectively given the names aa, ab, ac, ..., zy, zz;

the dogs numbered 703,704,705,\cdots,18277,18278 were respectively given the names aaa, aab, aac, ..., zzy, zzz;

the dogs numbered 18279,18280,18281,\cdots,475253,475254 were respectively given the names aaaa, aaab, aaac, ..., zzzy, zzzz;

the dogs numbered 475255,475256,\cdots were respectively given the names aaaaa, aaaab, ...;

and so on.

To sum it up, the dogs numbered 1, 2, \cdots were respectively given the following names:

a, b, ..., z, aa, ab, ..., az, ba, bb, ..., bz, ..., za, zb, ..., zz, aaa, aab, ..., aaz, aba, abb, ..., abz, ..., zzz, aaaa, ...

Now, Roger asks you:

"What is the name for the dog numbered N?"

Constraints

N is an integer.

1 \leq N \leq 1000000000000001

Input

Input is given from Standard Input in the following format:

N

Output

Print the answer to Roger's question as a string consisting of lowercase English letters.

Sample Input 1

2

Sample Output 1

b

Sample Input 2

27

Sample Output 2

aa

Sample Input 3

123456789

Sample Output 3

jjddja

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>

#ifdef DEBUG
#define PRINT(x)\
    cout<<"func "<<__func__<<": line "<<__LINE__<<": "<<#x<<" = "<<(x)<<endl;
#define PRINTA(a,first,last)\
    cout<<"func "<<__func__<<": line "<<__LINE__<<": "<<#a<<"["<<(first)<<", "<<(last)<<")"<<endl;\
    for (int _i=(first);_i<(last);++_i){cout<<#a<<"["<<_i<<"] = "<<(a)[_i]<<endl;}
#define PRINTP(p)\
    cout<<"func "<<__func__<<": line "<<__LINE__<<": "<<#p<<" = ("<<(p.first)<<", "<<(p.second)<<")"<<endl;
#define PRINTI(a,i)\
    cout<<"func "<<__func__<<": line "<<__LINE__<<": "<<#a<<"["<<#i<<"] = "<<#a<<"["<<(i)<<"] = "<<(a)[i]<<endl;
#else
#define PRINT(x)
#define PRINTA(a,first,last)
#define PRINTP(p)
#define PRINTI(a,i)
#endif

#define FOR(i,a,b) for (int i=(a);i<(b);++i)
#define RFOR(i,a,b) for (int i=(b)-1;i>=(a);--i)
#define REP(i,n) for (int i=0;i<(n);++i)
#define RREP(i,n) for (int i=(n)-1;i>=0;--i)
#define pb push_back
#define mp make_pair
#define all(a) (a).begin(),(a).end()
#define rall(a) (a).rbegin(),(a).rend()
#define MOD 1000000007
//#define MOD 998244353

using namespace std;

using ll = long long;
using ull = unsigned long long;
using pii = pair<int, int>;

template <class T, class U> void amax(T& x, U y) {if (x < y) x = y;}
template <class T, class U> void amin(T& x, U y) {if (x > y) x = y;}

template <class T>
using vec2 = vector<vector<T>>;

template <class T>
using vec3 = vector<vector<vector<T>>>;

const int dx[] = {1, 0, -1, 0, 1, -1, -1, 1};
const int dy[] = {0, 1, 0, -1, 1, 1, -1, -1};

int main() {
    cin.tie(0);
    ios::sync_with_stdio(false);

    ll N;
    cin >> N;
    ll N_ = N;
    int L = 0;
    ll p = 1;
    while (N > 0) {
        p *= 26;
        N -= p;
        ++L;
    }
    vector<int> res(L);
    N = N_;
    p = 1;
    REP(_, L - 1) {
        p *= 26;
        N -= p;
    }
    --N;
    RREP(i, L) {
        res[i] = N % 26;
        N /= 26;
    }
    REP(i, L) {
        cout << char('a' + res[i]);
    }
    cout << endl;
    return 0;
}