Problem:
Score : 300 points

Problem Statement

Given is a sequence of integers A_1, A_2, ..., A_N.
If its elements are pairwise distinct, print YES; otherwise, print NO.

Constraints

2 ≤ N ≤ 200000

1 ≤ A_i ≤ 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

If the elements of the sequence are pairwise distinct, print YES; otherwise, print NO.

Sample Input 1

5
2 6 1 4 5

Sample Output 1

YES

The elements are pairwise distinct.

Sample Input 2

6
4 1 3 1 6 2

Sample Output 2

NO

The second and fourth elements are identical.

Sample Input 3

2
10000000 10000000

Sample Output 3

NO

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<bits/stdc++.h>				//Written by ThiDaiLoc
using namespace std;				//Team Three Wolves
typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
typedef pair<ll,ll> pll;
typedef pair<ll,pll> trp;
typedef vector<ll> vi;
typedef vector<pll> vp;

#define fu(i,a,b)   for(ll i=a;i<=b;i++)
#define f1(i,n)     for(ll i=1;i<=n;i++)
#define fs(i,s)     for(ll i=0;i+1<=s.length();i++)
#define fd(i,b,a)   for(ll i=b;i>=a;i--)
#define fuv(i,a)    for(ll i=0;i<a.size();i++)
#define fdv(i,a)    for(ll i=(ll)a.size()-1;i>=0;i--)
#define ms(a,x)     memset(a, x, sizeof a)
#define prec(n)     fixed<<setprecision(n)
#define uni(a)      (a).erase(unique(all(a)), (a).end())
#define pb(i)       push_back(i)
#define pob         pop_back()
#define sc(a)       cin>>a
#define sc2(a,b)    cin>>a>>b
#define sc3(a,b,c)  cin>>a>>b>>c
#define pr(a)       cout<<a<<endl
#define pr2(a,b)    cout<<a<<" "<<b<<endl
#define rpr(a)      return cout<<a<<endl,0
#define prY         cout<<"YES"<<endl
#define prN         cout<<"NO"<<endl
#define bit(n,i)    (((n)>>(i))&1)
#define lowb(a,n,x) lower_bound(a,a+n,x) -a
#define lowb2(a,x)  lower_bound(all(a),x) -a.begin()
#define all(x)      (x).begin(), (x).end()
#define sz(a)       (ll)a.size()
#define le(s)       (ll)s.length()		
#define re          return 	
#define	mp(a,b)     make_pair(a,b)
#define	mp3(a,b,c)  make_pair(a,make_pair(b,c))
#define se          second
#define fi          first 
#define sse         second.second
#define sfi         second.first
#define soA         sort(A+1,A+1+n)
#define so(A,n)     sort(A+1,A+1+n)
#define sov(v)      sort(all(v))
#define sovr(v)     sort(all(v),greater<ll>())
#define debug(x)    cerr << #x << " = " << x << endl
#define INPUT       freopen("locin.txt", "r", stdin)
#define OUTPUT      freopen("locout.txt", "w", stdout)
inline ll isqrt(ll k) {ll r = sqrt(k) + 1; while (r * r > k) r--; return r;}
inline ll icbrt(ll k) {ll r = cbrt(k) + 1; while (r * r * r > k) r--; return r;}
inline ll mnz(ll& a,ll b){return a=(a>b?b:a);}
inline ll mxz(ll& a,ll b){return a=(a<b?b:a);}
inline string toString(ll n) {stringstream ss; ss << n;return ss.str();}
double const eps = 1e-6;
ll const Base=1e9+7,oo=1e17,MAXN=1e6;


ll A[MAXN+5];

ll Solves(){
	
	ll n,m,k,cnt=0,ans=0,x,y,q,c,sum=0,v,t;
	// PROCESS IN HERE
	sc(n);
	f1(i,n){
		sc(A[i]);
		
	}
	soA;
	f1(i,n){
		if(i>=2 and A[i]==A[i-1])sum=1;
	}
	if(sum)prN;
	else prY;
	
	
	
	
	re 0;
	// Hack it if you can :)
}

int main(){
	//INPUT;
	if(fopen("locin.txt", "r"))INPUT;
	ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
	ll test=1;
//	sc(test);
	fu(T,1,test){
//		cout<<"Case #"<<T<<": ";
		Solves();
	} 		
}