Problem:
Score : 200 points

Problem Statement

Today is August 24, one of the five Product Days in a year.

A date m-d (m is the month, d is the date) is called a Product Day when d is a two-digit number, and all of the following conditions are satisfied (here d_{10} is the tens digit of the day and d_1 is the ones digit of the day):

d_1 \geq 2

d_{10} \geq 2

d_1 \times d_{10} = m

Takahashi wants more Product Days, and he made a new calendar called Takahashi Calendar where a year consists of M month from Month 1 to Month M, and each month consists of D days from Day 1 to Day D.

In Takahashi Calendar, how many Product Days does a year have?

Constraints

All values in input are integers.

1 \leq M \leq 100

1 \leq D \leq 99

Input

Input is given from Standard Input in the following format:

M D

Output

Print the number of Product Days in a year in Takahashi Calender.

Sample Input 1

15 40

Sample Output 1

10

There are 10 Product Days in a year, as follows (m-d denotes Month m, Day d):

4-22

6-23

6-32

8-24

9-33

10-25

12-26

12-34

14-27

15-35

Sample Input 2

12 31

Sample Output 2

5

Sample Input 3

1 1

Sample Output 3

0

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <algorithm> //STLͨ���㷨
#include <cmath> //������ѧ����
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#include <string> //�ַ�����
#include <ctime> //�������ʱ��ĺ���
#define itn int
#define fro for
#define ll long long
#define reg register
#define inf 1234567890
#define rep(i,a,b,c) for (int i=a;i<=b;i+=c)
/*#include <bitset> //STLλ������
#include <cstype> //�ַ�����
#include <cerrno> //���������
#include <complex> //������
#include <clocale> //���屾�ػ�����
#include <cstdlib> //������������ڴ���亯��
#include <deque> //STL˫�˶�������
#include <exception> //�쳣������
#include <fstream> //�ļ�����/���
#include <functional> //STL�������㺯��(���������)
#include <limits> //�����������������ֵ����
#include <list> //STL�����б�����
#include <map> //STLӳ������
#include <iomanip> //����������/���
#include <ios> //��������/���֧��
#include <iosfwd> //����/���ϵͳʹ�õ�ǰ������
#include <istream> //����������
#include <ostream> //���������
#include <queue> //STL��������
#include <set> //STL��������
#include <sstream> //�����ַ�������
#include <stack> //STL��ջ����
#include <stdexcept> //��׼�쳣��
#include <streambuf> //�ײ�����/���֧��
#include <utility> //STLͨ��ģ����
#include <vector> //STL��̬��������
#include <cwchar.h>//���ַ�����������/���
#include <cwctype.h> //���ַ�����*/

using namespace std;

int ans;

int max(int x,int y){return x>y?x:y;}

int min(int x,int y){return x<y?x:y;}

int abs(int x){return x>0?x:-x;}

int gcd(int x,int y){return (!y)?x:gcd(y,x%y);}

void exgcd(int a,int b,int &d,int &x,int &y){if (!b){d=a,x=1,y=0;}else{exgcd(b,a%b,d,y,x);y-=x*(a/b);}}

int quick_power(ll a,int b){ll r=1;for (;b;b>>=1,a=a*a)if (b&1) r=r*a;return r;}

inline char read() {
	static const int IN_LEN = 1000000;
	static char buf[IN_LEN], *s, *t;
	return (s == t ? t = (s = buf) + fread(buf, 1, IN_LEN, stdin), (s == t ? -1 : *s++) : *s++);
}
template<class T>
inline void read(T &x) {
	static bool iosig;
	static char c;
	for (iosig = false, c = read(); !isdigit(c); c = read()) {
		if (c == '-') iosig = true;
		if (c == -1) return;
	}
	for (x = 0; isdigit(c); c = read()) x = x * 10 + (c ^ '0');
	if (iosig) x = -x;
}

char sr[10000000],z[20];int C=-1,Z=0;
void Ot(){fwrite(sr,1,C+1,stdout),C=-1;}
void print(int x){
	if (x<0) sr[++C]='-',x=-x;
    while(z[++Z]=x%10+48,x/=10);
    while(sr[++C]=z[Z],--Z);sr[++C]='\n';
}
//int find(int x){return fa[x]=fa[x]==x?x:find(fa[x]);}

//void add(int x,int y,int z){to[++cnt]=y;v[cnt]=z;Next[cnt]=head[x];head[x]=cnt;}
int main()
{
	int m,k;
	read(m);read(k);
	for (int i=1;i<=m;i++)
		for (int j=1;j<=k;j++)
			if ((j%10>=2)&(j/10>=2)) ans+=(i==((j%10)*(j/10)));
	cout<<ans;
	return 0;
}