Problem:
Score : 200 points

Problem Statement

Raccoon is fighting with a monster.

The health of the monster is H.

Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i.
There is no other way to decrease the monster's health.

Raccoon wins when the monster's health becomes 0 or below.

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Constraints

1 \leq H \leq 10^9

1 \leq N \leq 10^5

1 \leq A_i \leq 10^4

All values in input are integers.

Input

Input is given from Standard Input in the following format:

H N
A_1 A_2 ... A_N

Output

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Sample Input 1

10 3
4 5 6

Sample Output 1

Yes

The monster's health will become 0 or below after, for example, using the second and third moves.

Sample Input 2

20 3
4 5 6

Sample Output 2

No

Sample Input 3

210 5
31 41 59 26 53

Sample Output 3

Yes

Sample Input 4

211 5
31 41 59 26 53

Sample Output 4

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#define MOD 1e9 + 7
#define PI 3.141592653589793238
#define pb push_back
#define ALL(V) (V).begin(), (V).end()
#define FOR(i, a, b) for(int i = (a); i < (b); ++i)
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef long long int lint;
typedef vector<ll> VL;
typedef vector<VL> VVL;
typedef vector<int> VI;
typedef pair<ll, ll> P;
ll gcd(ll a, ll b) { return (a % b == 0 ? b : gcd(b, a % b)); }
ll lcm(ll a, ll b) { return a * b / gcd(a, b); }
ll char_to_ll(char c) { return (int)(c - '0'); }
ll string_to_ll(string s) { return char_to_ll(atoi(s.c_str())); }
bool is_prime(ll x){ if(x <= 1) return false; for(ll i = 2; sqrt(i) <= x; i++) if(x % i == 0) return false; return true; }


int main() {
    int a,n;
    cin >> a >> n;
    VL s(n);
    FOR(i,0,n) cin >> s.at(i);

    int sum = 0;
    FOR(i,0,n) sum += s.at(i);
    bool ans = false;

    if(a <= sum){
        ans = true;
    }
    
    if(ans == true){
        cout << "Yes" << endl;
    }else{
        cout << "No" << endl;
    }
  

    return 0;
}