Problem:
Score : 100 points

Problem Statement

We have two bottles for holding water.

Bottle 1 can hold up to A milliliters of water, and now it contains B milliliters of water.

Bottle 2 contains C milliliters of water.

We will transfer water from Bottle 2 to Bottle 1 as much as possible.

How much amount of water will remain in Bottle 2?

Constraints

All values in input are integers.

1 \leq B \leq A \leq 20

1 \leq C \leq 20

Input

Input is given from Standard Input in the following format:

A B C

Output

Print the integer representing the amount of water, in milliliters, that will remain in Bottle 2.

Sample Input 1

6 4 3

Sample Output 1

1

We will transfer two milliliters of water from Bottle 2 to Bottle 1, and one milliliter of water will remain in Bottle 2.

Sample Input 2

8 3 9

Sample Output 2

4

Sample Input 3

12 3 7

Sample Output 3

0

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <vector>
#include <algorithm>
#include <set>
#include <map>
#include <deque>
#include <queue>
#include <string>
#include <string.h>
#include <math.h>
#include <iomanip>
using namespace std;

#define int64 long long
#define pii pair <int64, int64>
#define fr first
#define sc second
#define heap priority_queue
struct piii{
    int64 fr, sc, th;
    bool operator < (const piii &b){
        if (fr != b.fr) return fr < b.fr;
        if (sc != b.sc) return sc < b.sc;
        return th < b.th;
    }
};
///////////////////////////////////////////////
///////////////////////////////////////////////

int main(){
    cout << setprecision(2) << fixed;
    ios::sync_with_stdio(false), cin.tie(0);
    //freopen("input.txt", "r", stdin);
    int a, b, c;
    cin >> a >> b >> c;
    cout << c - (a - b);
    return 0;
}