Problem:
Score : 300 points

Problem Statement

Takahashi made N problems for competitive programming.
The problems are numbered 1 to N, and the difficulty of Problem i is represented as an integer d_i (the higher, the harder).

He is dividing the problems into two categories by choosing an integer K, as follows:

A problem with difficulty K or higher will be for ARCs.

A problem with difficulty lower than K will be for ABCs.

How many choices of the integer K make the number of problems for ARCs and the number of problems for ABCs the same?

Problem Statement

2 \leq N \leq 10^5

N is an even number.

1 \leq d_i \leq 10^5

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
d_1 d_2 ... d_N

Output

Print the number of choices of the integer K that make the number of problems for ARCs and the number of problems for ABCs the same.

Sample Input 1

6
9 1 4 4 6 7

Sample Output 1

2

If we choose K=5 or 6, Problem 1, 5, and 6 will be for ARCs, Problem 2, 3, and 4 will be for ABCs, and the objective is achieved.
Thus, the answer is 2.

Sample Input 2

8
9 1 14 5 5 4 4 14

Sample Output 2

0

There may be no choice of the integer K that make the number of problems for ARCs and the number of problems for ABCs the same.

Sample Input 3

14
99592 10342 29105 78532 83018 11639 92015 77204 30914 21912 34519 80835 100000 1

Sample Output 3

42685

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

/*
lakshaygpt28
Lakshay Gupta
*/

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;

using ll = long long;
using db = double;
using pii = pair < int, int >;
using pll = pair < ll, ll >;
using vll = vector < ll >;

template < typename T > using OrderedSet = tree < T, null_type, less < T >, rb_tree_tag, tree_order_statistics_node_update >;
template < typename T > using MinPriorityQueue = priority_queue < T, vector < T >, greater < T > >;


#ifndef ONLINE_JUDGE
#define debug(...) __f(#__VA_ARGS__, __VA_ARGS__)
template < typename Arg1 >
void __f(const char* name, Arg1&& arg1) {
    cerr << name << " : " << arg1 << std :: endl;
}
template < typename Arg1, typename... Args >
void __f(const char* names, Arg1&& arg1, Args&&... args) {
    const char* comma = strchr(names + 1, ',');
    cerr.write(names, comma - names) << " : " << arg1 << " | ";
    __f(comma + 1, args...);
}
#else
#define debug(...)
#endif

#define fast_io() ios_base :: sync_with_stdio(0); cin.tie(0); cout.tie(0)
#define eb emplace_back
#define mp make_pair
#define pb push_back
#define mt make_tuple
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()

const db PI = acos(-1);
const ll LINF = LLONG_MAX;
const int INF = INT_MAX, MOD = 1e9 + 7, N = 1e5 + 10;

ll a[N];

int main() {
    fast_io();
    ll n;
    cin >> n;
    for (ll i = 1; i <= n; i++) {
        cin >> a[i];
    }
    ll ans = 0;
    sort(a + 1, a + n + 1);
    cout << a[n / 2 + 1] - a[n / 2] << "\n";
    return 0;
}