Problem:
Score : 100 points

Problem Statement

You are given a string S of length 2 or 3 consisting of lowercase English letters. If the length of the string is 2, print it as is; if the length is 3, print the string after reversing it.

Constraints

The length of S is 2 or 3.

S consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S

Output

If the length of S is 2, print S as is; if the length is 3, print S after reversing it.

Sample Input 1

abc

Sample Output 1

cba

As the length of S is 3, we print it after reversing it.

Sample Input 2

ac

Sample Output 2

ac

As the length of S is 2, we print it as is.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair<ll, ll> pii;
typedef pair<double,double> pdd;
#define MEM(a, b) memset(a, (b), sizeof(a))
#define SZ(i) ll(i.size())
#define FOR(i, j, k, in) for (ll i=j ; i<k ; i+=in)
#define RFOR(i, j, k, in) for (ll i=j ; i>=k ; i-=in)
#define REP(i, j) FOR(i, 0, j, 1)
#define REP1(i,j) FOR(i, 1, j+1, 1)
#define RREP(i, j) RFOR(i, j, 0, 1)
#define ALL(_a) _a.begin(),_a.end()
#define mp make_pair
#define pb push_back
#define X first
#define Y second
#ifdef tmd
#define debug(...) do{\
    fprintf(stderr,"%s - %d (%s) = ",__PRETTY_FUNCTION__,__LINE__,#__VA_ARGS__);\
    _do(__VA_ARGS__);\
}while(0)
template<typename T>void _do(T &&_x){cerr<<_x<<endl;}
template<typename T,typename ...S> void _do(T &&_x,S &&..._t){cerr<<_x<<" ,";_do(_t...);}
template<typename _a,typename _b> ostream& operator << (ostream &_s,const pair<_a,_b> &_p){return _s<<"("<<_p.X<<","<<_p.Y<<")";}
template<typename It> ostream& _OUTC(ostream &_s,It _ita,It _itb)
{
    _s<<"{";
    for(It _it=_ita;_it!=_itb;_it++)
    {
        _s<<(_it==_ita?"":",")<<*_it;
    }
    _s<<"}";
    return _s;
}
template<typename _a> ostream &operator << (ostream &_s,vector<_a> &_c){return _OUTC(_s,ALL(_c));}
template<typename _a> ostream &operator << (ostream &_s,set<_a> &_c){return _OUTC(_s,ALL(_c));}
template<typename _a,typename _b> ostream &operator << (ostream &_s,map<_a,_b> &_c){return _OUTC(_s,ALL(_c));}
template<typename _t> void pary(_t _a,_t _b){_OUTC(cerr,_a,_b);cerr<<endl;}
#define IOS()
#else
#define debug(...)
#define pary(...)
#define endl '\n'
#define IOS() ios_base::sync_with_stdio(0);cin.tie(0)
#endif

template<class T> inline bool cmax(T &a, const T &b) { return b > a ? a = b, true : false; }
template<class T> inline bool cmin(T &a, const T &b) { return b < a ? a = b, true : false; }
template<class T> using MaxHeap = priority_queue<T>;
template<class T> using MinHeap = priority_queue<T, vector<T>, greater<T>>;

const ll MOD=1000000007;
const ll INF=0x3f3f3f3f3f3f3f3f;
const ll MAXN=1e5+5;
const ll MAXLG=__lg(MAXN)+2;

ll n,sqt,ss,idx;
vector<ll> s[MAXN];
/********** Main()  function **********/
int main()
{
  IOS();

  cin>>n;
  sqt = -1;
  REP1(i,8*n+1){
    if(i*i == 8*n+1)sqt = i;
    if(i*i > 8*n+1)break;
  }

  
  if(n==4 || sqt == -1) {
    cout<<"No"<<endl;
  } else {

      cout<<"Yes"<<endl;
      ss = (sqt + 1) / 2;
      assert(ss < MAXN);
      for(ll i=0;i<ss;i++){
        for(ll j=i+1;j<ss;j++){
          s[j].pb(++idx);
          s[i].pb(idx);
        }
      }

      for(ll i=0;i<ss;i++){
        cout<<s[i].size();
        //assert(s[i].size() == ss - 1);
        REP(j,SZ(s[i]))cout<<" "<<s[i][j];
        cout<<endl;
      }
  }

  return 0;
}