Problem:
Score : 200 points

Problem Statement

A shop sells N kinds of fruits, Fruit 1, \ldots, N, at prices of p_1, \ldots, p_N yen per item, respectively. (Yen is the currency of Japan.)

Here, we will choose K kinds of fruits and buy one of each chosen kind. Find the minimum possible total price of those fruits.

Constraints

1 \leq K \leq N \leq 1000

1 \leq p_i \leq 1000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
p_1 p_2 \ldots p_N

Output

Print an integer representing the minimum possible total price of fruits.

Sample Input 1

5 3
50 100 80 120 80

Sample Output 1

210

This shop sells Fruit 1, 2, 3, 4, and 5 for 50 yen, 100 yen, 80 yen, 120 yen, and 80 yen, respectively.

The minimum total price for three kinds of fruits is 50 + 80 + 80 = 210 yen when choosing Fruit 1, 3, and 5.

Sample Input 2

1 1
1000

Sample Output 2

1000

Solution in C++ (Clang 10.0.0) (judge verdict: Accepted)

#include <iostream>
#include <vector>
#include <unordered_set>
#include <set>
#include <cstring>
#include <map>
#include <cmath>
#include <algorithm>
#include <queue>

using namespace std;

using ll = long long;
const ll INF = 1e18 + 1;


int main(){
    cin.tie(0);
    ios_base::sync_with_stdio(0);

    ll n, k;
    cin >> n >> k;

    vector<ll> p(n);
    for (int i = 0; i < n; ++i) {
        cin >> p[i];
    }

    sort(p.begin(), p.end());

    ll ans = 0;
    for (int i = 0; i < k; ++i) {
        ans += p[i];
    }

    cout << ans << endl;


}