Problem:
Score : 100 points

Problem Statement

You will turn on the air conditioner if, and only if, the temperature of the room is 30 degrees Celsius or above.

The current temperature of the room is X degrees Celsius. Will you turn on the air conditioner?

Constraints

-40 \leq X \leq 40

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print Yes if you will turn on the air conditioner; print No otherwise.

Sample Input 1

25

Sample Output 1

No

Sample Input 2

30

Sample Output 2

Yes

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp> // Common file
#include <ext/pb_ds/tree_policy.hpp> // Including tree_order_statistics_node_update
using namespace std;
using namespace __gnu_pbds;

#define TRACE

#ifdef TRACE
#define trace(...) __f(#__VA_ARGS__, __VA_ARGS__)
template <typename Arg1>
void __f(const char* name, Arg1&& arg1){
	cerr << name << " : " << arg1 << std::endl;
}
template <typename Arg1, typename... Args>
void __f(const char* names, Arg1&& arg1, Args&&... args){
	const char* comma = strchr(names + 1, ',');cerr.write(names, comma - names) << " : " << arg1<<" | ";__f(comma+1, args...);
}
#else
#define trace(...)
#endif

#define lsc(x)      scanf("%lld",&x)
#define sc(x)       scanf("%d",&x)
#define lpr(x)      printf("%lld ",(long long)x)
#define pr(x)       printf("%d ",x)
#define n_l         printf("\n")
#define VI          vector<int>
#define VII         vector<long long int>
#define m_p         make_pair
#define pb          push_back
#define fi           first
#define se           second
#define mset(x,y)   memset(x,y,sizeof(x))
#define sz(v)       (int)v.size()
#define all(v)      v.begin(), v.end()
#define fr(i, a, n) for(int i=a;i<=n;i++)
#define FIO ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);
mt19937 rng32(chrono::steady_clock::now().time_since_epoch().count());
const int N=(int)1e6+5;
const int mod = 1000000007;
typedef long long ll;
// order_of_key (val): returns the no. of values strictly less than val
// find_by_order (k): returns the kth largest element iterator.(0-based)
// vector<int>::iterator itr=lower_bound(v.begin(),v.end(),x);
// s.substr(pos[0-indexed], len(default=till end))
typedef tree<ll,null_type,less<ll>,rb_tree_tag,tree_order_statistics_node_update> ordered_set;

ll fmod(ll x){if (x<mod) return x;return x%mod;}
ll mul(ll a, ll b, ll c){
	ll ret=0;while(b){if (b%2) ret=(ret+a)%c;a=(a*2)%c;b>>=1;}
    return ret;
}
int modpow(ll a, ll b){
    ll ret=1;while(b){if (b%2) ret=(ret*a)%mod;a=(a*a)%mod;b>>=1;}
    return (int)ret;
}
inline int inv(int x){ return modpow(x, mod-2);}
int isprime[N];
void calc_prime(){
	isprime[1]=1;for(ll i=2;i<N;i++) if (!isprime[i]) for(ll j=i*i;j<N;j+=i) isprime[j]=1;
}
int main(){
    int n;sc(n);
    if (n>=30) cout<<"Yes\n";
    else cout<<"No\n";
    return 0;
}