Problem:
Score : 200 points

Problem Statement

Raccoon is fighting with a monster.

The health of the monster is H.

Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i.
There is no other way to decrease the monster's health.

Raccoon wins when the monster's health becomes 0 or below.

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Constraints

1 \leq H \leq 10^9

1 \leq N \leq 10^5

1 \leq A_i \leq 10^4

All values in input are integers.

Input

Input is given from Standard Input in the following format:

H N
A_1 A_2 ... A_N

Output

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Sample Input 1

10 3
4 5 6

Sample Output 1

Yes

The monster's health will become 0 or below after, for example, using the second and third moves.

Sample Input 2

20 3
4 5 6

Sample Output 2

No

Sample Input 3

210 5
31 41 59 26 53

Sample Output 3

Yes

Sample Input 4

211 5
31 41 59 26 53

Sample Output 4

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
using namespace std;

int main(){
    // H is monster health, N is how many moves Raccoon can make
int H, N;
    cin >> H >> N;
   
    // initialize an array
    int moves[N];
   
    // user input numbers, effectiveness of attack
    int i;
    for (i=0; i<N; i++){
      cin >> moves[i];
    }
    // add up all of the numbers in the arary
  	int sum = 0;
    for (i=0; i<N; i++){
		sum += moves[i];
    }
  	if(H > sum){
      cout << "No" << endl;
    }
  	else{
      cout << "Yes" << endl;
    }
   
   
}