Problem:
Score: 200 points

Problem Statement

A country decides to build a palace.

In this country, the average temperature of a point at an elevation of x meters is T-x \times 0.006 degrees Celsius.

There are N places proposed for the place. The elevation of Place i is H_i meters.

Among them, Princess Joisino orders you to select the place whose average temperature is the closest to A degrees Celsius, and build the palace there.

Print the index of the place where the palace should be built.

It is guaranteed that the solution is unique.

Constraints

1 \leq N \leq 1000

0 \leq T \leq 50

-60 \leq A \leq T

0 \leq H_i \leq 10^5

All values in input are integers.

The solution is unique.

Input

Input is given from Standard Input in the following format:

N
T A
H_1 H_2 ... H_N

Output

Print the index of the place where the palace should be built.

Sample Input 1

2
12 5
1000 2000

Sample Output 1

1

The average temperature of Place 1 is 12-1000 \times 0.006=6 degrees Celsius.

The average temperature of Place 2 is 12-2000 \times 0.006=0 degrees Celsius.

Thus, the palace should be built at Place 1.

Sample Input 2

3
21 -11
81234 94124 52141

Sample Output 2

3

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)


//auto 関数名 = [(&:ラムダ外の引数をとる時))](引数の型1 引数名1, 引数の型2, 引数名2, ...) { 関数の処理 }; //inside main() define function. take care of };
// for (int tmp = 0; tmp < (1 << ビット数); tmp++) {
//   bitset<ビット数> s(tmp);
//   // (ビット列sに対する処理)
// }
// sort(配列変数.begin(), 配列変数.end());
// do {
//   // 順列に対する処理
// } while (next_permutation(配列変数.begin(), 配列変数.end()));
//const double PI = acos(-1); M_PI
// cout << fixed << setprecision(10);
// set<int>st{ 3,1,4,1,5,9,2,6,5,3,5 };
//     for (auto itr = st.begin(); itr != st.end(); ++itr) {
//         cout << *itr;
//     }
#include <bits/stdc++.h>
#include <regex>
using namespace std;
using ll = long long;
using P = pair<int,int>;
#define _GLIBCXX_DEBUG 
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define all(v) v.begin(), v.end() //sort(all(vec)); ,reverse(all(vec));etc
int main(){
    int n;
    cin>>n;
    int t;
    cin>>t;
    int a;
    cin>>a;
   int point=0;
   double d=1000;
   double h;
    rep(i,n){
        cin>>h;
        h=t-h*0.006;
        if(d>abs(a-h)){
            point=i;
            d=abs(a-h);
        }
    }
    cout<<point+1<<endl;
}