Problem:
Score : 400 points

Problem Statement

We have N balls. The i-th ball has an integer A_i written on it.

For each k=1, 2, ..., N, solve the following problem and print the answer.

Find the number of ways to choose two distinct balls (disregarding order) from the N-1 balls other than the k-th ball so that the integers written on them are equal.

Constraints

3 \leq N \leq 2 \times 10^5

1 \leq A_i \leq N

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

For each k=1,2,...,N, print a line containing the answer.

Sample Input 1

5
1 1 2 1 2

Sample Output 1

2
2
3
2
3

Consider the case k=1 for example. The numbers written on the remaining balls are 1,2,1,2.

From these balls, there are two ways to choose two distinct balls so that the integers written on them are equal.

Thus, the answer for k=1 is 2.

Sample Input 2

4
1 2 3 4

Sample Output 2

0
0
0
0

No two balls have equal numbers written on them.

Sample Input 3

5
3 3 3 3 3

Sample Output 3

6
6
6
6
6

Any two balls have equal numbers written on them.

Sample Input 4

8
1 2 1 4 2 1 4 1

Sample Output 4

5
7
5
7
7
5
7
5

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;
#define LL long long int
#define DL double
#define MLL map<LL,LL>::iterator
#define MSL map<string,L>::iterator
#define MLS map<LL,string>::iterator
#define MSS map<string,string>::iterator
#define MCL map<char,LL>::iterator
#define SL set<LL>::iterator
#define SS set<string>::iterator sl
#define G getline
#define SZ size()
#define IN insert
#define C clear()
#define B begin()
#define F front()
#define T top()
#define E end()
#define EM empty()
#define V vector
#define Q queue
#define DQ deque
#define PQ priority_queue
#define ST stack
#define FI first
#define SE second
#define PI acos(-1)
#define PS push
#define PP pop()
#define PSF push_front
#define PSB push_back
#define PPF pop_front()
#define PPB pop_back()
#define endl "\n"
#define FAST ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL)
V<LL>v,w;
map<LL,LL>u;
int main()
{
    FAST;
    LL n,m,i,j,k,p,q,o,l,s,t,z;
    cin>>n;
    k=0;
    for(i=0; i<n; i++)
    {
        cin>>o;
        v.PSB(o);
        u[o]++;
    }
    k=0;
    for(MLL it=u.B; it!=u.E; it++)
    {
        k+=(it->SE*(it->SE-1))/2;
    }
    for(i=0; i<n; i++)
    {
      cout<<k-(u[v[i]]-1)<<endl;
    }

    return 0;
}