Problem:
Score : 100 points

Problem Statement

You are given positive integers A and B.

If A is a divisor of B, print A + B; otherwise, print B - A.

Constraints

All values in input are integers.

1 \leq A \leq B \leq 20

Input

Input is given from Standard Input in the following format:

A B

Output

If A is a divisor of B, print A + B; otherwise, print B - A.

Sample Input 1

4 12

Sample Output 1

16

As 4 is a divisor of 12, 4 + 12 = 16 should be printed.

Sample Input 2

8 20

Sample Output 2

12

Sample Input 3

1 1

Sample Output 3

2

1 is a divisor of 1.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#define rep(i,n) for(int i = 0; i < (n); i++)
#define all(x) (x).begin(),(x).end()
#define dup(x,y) (((x)+(y)-1)/(y))
#define sz(x) (int)(x).size()
#define MOD 1000000007
using namespace std;
typedef long long ll;

int main(){
    int a, b;
    cin >> a >> b;
    if(b%a == 0) cout << a+b << endl;
    else cout << b-a << endl;
    return 0;
}