Problem:
Score : 700 points

Problem Statement

You are given four integers: H, W, h and w (1 ≤ h ≤ H, 1 ≤ w ≤ W).
Determine whether there exists a matrix such that all of the following conditions are held, and construct one such matrix if the answer is positive:

The matrix has H rows and W columns.

Each element of the matrix is an integer between -10^9 and 10^9 (inclusive).

The sum of all the elements of the matrix is positive.

The sum of all the elements within every subrectangle with h rows and w columns in the matrix is negative.

Constraints

1 ≤ h ≤ H ≤ 500

1 ≤ w ≤ W ≤ 500

Input

Input is given from Standard Input in the following format:

H W h w

Output

If there does not exist a matrix that satisfies all of the conditions, print No.

Otherwise, print Yes in the first line, and print a matrix in the subsequent lines in the following format:

a_{11} ... a_{1W}
:
a_{H1} ... a_{HW}

Here, a_{ij} represents the (i,\ j) element of the matrix.

Sample Input 1

3 3 2 2

Sample Output 1

Yes
1 1 1
1 -4 1
1 1 1

The sum of all the elements of this matrix is 4, which is positive.
Also, in this matrix, there are four subrectangles with 2 rows and 2 columns as shown below. For each of them, the sum of all the elements inside is -1, which is negative.

Sample Input 2

2 4 1 2

Sample Output 2

No

Sample Input 3

3 4 2 3

Sample Output 3

Yes
2 -5 8 7
3 -5 -4 -5
2 1 -1 7

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<iostream>
#include<algorithm>
using namespace std;
int h,w,a,b;
bool m[510][501];
int main(){
	cin>>h>>w>>a>>b;
	int c=1,cnta=a;
	while(true){
		if(cnta+a+1>h)break;
		c++,cnta+=2*a-1;
	}
	int d=1,cntb=b;
	while(true){
		if(cntb+b+1>w)break;
		d++,cntb+=2*b-1;
	}
	if(h*w-(c*d)*(a*b+1)>0){
		cout<<"Yes"<<endl;
		for(int i=0;i<=h;i++){
			for(int j=0;j<=w;j++){
				m[i][j]=false;
			}
		}
		cnta=a;
		for(int i=0;i<c;i++){
			cntb=b;
			for(int j=0;j<d;j++){
				m[cnta][cntb]=true;
				cntb+=2*b-1;
				if(cntb>w)cntb=w;
			}
			cnta+=2*a-1;
			if(cnta>h)cnta=h;
		}
		for(int i=1;i<=h;i++){
			for(int j=1;j<=w;j++){
				int p=1;
				if(m[i][j]==true)p=-a*b;
				cout<<p;
				if(j<w)cout<<" ";
			}
			cout<<endl;
		}
	}
	else cout<<"No"<<endl;
	return 0;
}