Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
#include<math.h>
#include<algorithm>
#include<vector>
#include<iostream>
#include<string>
#include<cstdlib>
using namespace std;
int main(void)
{
	string num;
	int i;
	cin >> num;
	if (num[0] == '0' && num[1] == '0')
	{
		cout << "NA" << endl;
	}
	else if (num[2] == '0' && num[3] == '0')
	{
		cout << "NA" << endl;
	}
	else if (num[0] >= '1'&&num[1] > '2'&&num[2] >= '1'&&num[3] > '2')
	{
		cout << "NA" << endl;
	}
	else if (num[0] <= '1'&&num[1]<'3' && num[2] <= '1'&&num[3]<'3')
	{
		cout << "AMBIGUOUS" << endl;
	}
	else if (num[0] >= '1' && num[1] > '2')
	{
		cout << "YYMM" << endl;
	}

	else if ( num[2] >= '1' && num[3] > '2')
	{
		cout << "MMYY" << endl;
	}



	return 0;
}