Problem:
Score : 100 points

Problem Statement

The door of Snuke's laboratory is locked with a security code.

The security code is a 4-digit number. We say the security code is hard to enter when it contains two consecutive digits that are the same.

You are given the current security code S. If S is hard to enter, print Bad; otherwise, print Good.

Constraints

S is a 4-character string consisting of digits.

Input

Input is given from Standard Input in the following format:

S

Output

If S is hard to enter, print Bad; otherwise, print Good.

Sample Input 1

3776

Sample Output 1

Bad

The second and third digits are the same, so 3776 is hard to enter.

Sample Input 2

8080

Sample Output 2

Good

There are no two consecutive digits that are the same, so 8080 is not hard to enter.

Sample Input 3

1333

Sample Output 3

Bad

Sample Input 4

0024

Sample Output 4

Bad

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <iomanip>
#include <vector>
#include <set>
#include <map>
#include <queue>
#include <deque>
#include <algorithm>
#include <cmath>
#include <cstring>

using namespace std;

#define REP(i,n) for(int i = 0; i < n; i++)
#define RREP(i,n) for(int i = n - 1; i >= 0; i--)

#define ALL(v) v.begin(),v.end()
#define pb push_back
#define mp make_pair
#define F first
#define S second

#define UNIQUE(v) do{sort(v.begin(), v.end()); v.erase( unique(v.begin(), v.end()), v.end() );} while(0)


#define y0 y3487465
#define y1 y8687969

#define m0(x) memset(x,0,sizeof(x))
#define m1(x) memset(x,63,sizeof(x))

typedef long long ll;
typedef pair<int,int> pi;
typedef pair<ll,ll> pll;
typedef vector<int> vi;
typedef vector<vi> vvi;
typedef vector<pi> vpi;
typedef vector<ll> vll;
typedef vector<vll> vvll;

double EPS = 1e-9;
int INFi = 1000000005;
long long INFll = 1000000000000000005ll;
double PI = acos(-1);
int dirx[8] = {-1,0,0,1,-1,-1,1,1};
int diry[8] = {0,1,-1,0,-1,1,-1,1};
ll MOD = 1000000007;

string S;

int main(){
  cin >> S;
  REP(i, 3) {
    if(S[i] == S[i + 1]) {
      cout << "Bad" << endl;
      return 0;
    }
  }
  cout << "Good" << endl;


  return 0;
}