Problem:
Score : 400 points

Problem Statement

Snuke has N strings. The i-th string is s_i.

Let us concatenate these strings into one string after arranging them in some order.
Find the maximum possible number of occurrences of AB in the resulting string.

Constraints

1 \leq N \leq 10^{4}

2 \leq |s_i| \leq 10

s_i consists of uppercase English letters.

Input

Input is given from Standard Input in the following format:

N
s_1
\vdots
s_N

Output

Print the answer.

Sample Input 1

3
ABCA
XBAZ
BAD

Sample Output 1

2

For example, if we concatenate ABCA, BAD and XBAZ in this order, the resulting string ABCABADXBAZ has two occurrences of AB.

Sample Input 2

9
BEWPVCRWH
ZZNQYIJX
BAVREA
PA
HJMYITEOX
BCJHMRMNK
BP
QVFABZ
PRGKSPUNA

Sample Output 2

4

Sample Input 3

7
RABYBBE
JOZ
BMHQUVA
BPA
ISU
MCMABAOBHZ
SZMEHMA

Sample Output 3

4

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <iomanip>
#include <cstring>
#include <algorithm> 
#include <math.h>
#include <queue>
#include <functional>
#include <map>
#include <vector>
#include <string>
using namespace std;

typedef long long ll;
typedef pair<int, int> P;
typedef pair<pair<int, int>, int> PP;

const ll INF = 1e15;
int dx[4] = { 1,0,-1,0 };
int dy[4] = { 0,1,0,-1 };




int main(void) {
	int N; cin >> N;
	int A, B;
	A = B = 0;
	int ans = 0;
	for (int i = 0; i < N; i++) {
		string s; cin >> s;
		for (int j = 0; j < s.size() - 1; j++) {
			if (s[j] == 'A'&&s[j + 1] == 'B') ans++;
		}
		if (s[s.size()-1] == 'A') {
			A++;
		}
		if (s[0] == 'B') {
			B++;
		}
	}
	ans += min(A, B);
	cout << ans << endl;


}