Problem:
Score : 300 points

Problem Statement

Takahashi is organizing a party.

At the party, each guest will receive one or more snack pieces.

Takahashi predicts that the number of guests at this party will be A or B.

Find the minimum number of pieces that can be evenly distributed to the guests in both of the cases predicted.

We assume that a piece cannot be divided and distributed to multiple guests.

Constraints

1 \leq A, B \leq 10^5

A \neq B

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the minimum number of pieces that can be evenly distributed to the guests in both of the cases with A guests and B guests.

Sample Input 1

2 3

Sample Output 1

6

When we have six snack pieces, each guest can take three pieces if we have two guests, and each guest can take two if we have three guests.

Sample Input 2

123 456

Sample Output 2

18696

Sample Input 3

100000 99999

Sample Output 3

9999900000

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

/*
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 ║║░║║╔══╝║║║║
 ║╚═╝║╚══╦╝╚╝║
 ╚══╗╠═══╩═══╝
 ░░░╚╝░░░░░░░░
 */

#include <bits/stdc++.h>
#define ll					long long
#define debug(x)			{ cerr << #x << " = " << x << endl; }
#define MOD					1000000007
#define MAX					1e9
#define MIN                 -1e9
#define vi					vector<int>
#define vii					vector<vi>
#define max(x,y)			(x>y)?x:y
#define min(x,y)			(x<y)?x:y
#define mid(s,e)			(s+(e-s)/2)

using namespace std;
ll gcd(ll a, ll b){ 
    if (a == 0) 
        return b;  
    return gcd(b % a, a);  
}
ll lcm(ll a, ll b) {
	return (a*b) / gcd(a,b);
}
int main() {
	ios::sync_with_stdio(false);
 	cin.tie(0);
	ll a,b;
	cin>>a>>b;
	cout<<lcm(a,b);

	return 0;
}