Problem:
Score : 300 points

Problem Statement

A company has N members, who are assigned ID numbers 1, ..., N.

Every member, except the member numbered 1, has exactly one immediate boss with a smaller ID number.

When a person X is the immediate boss of a person Y, the person Y is said to be an immediate subordinate of the person X.

You are given the information that the immediate boss of the member numbered i is the member numbered A_i. For each member, find how many immediate subordinates it has.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq A_i < i

Input

Input is given from Standard Input in the following format:

N
A_2 ... A_N

Output

For each of the members numbered 1, 2, ..., N, print the number of immediate subordinates it has, in its own line.

Sample Input 1

5
1 1 2 2

Sample Output 1

2
2
0
0
0

The member numbered 1 has two immediate subordinates: the members numbered 2 and 3.

The member numbered 2 has two immediate subordinates: the members numbered 4 and 5.

The members numbered 3, 4, and 5 do not have immediate subordinates.

Sample Input 2

10
1 1 1 1 1 1 1 1 1

Sample Output 2

9
0
0
0
0
0
0
0
0
0

Sample Input 3

7
1 2 3 4 5 6

Sample Output 3

1
1
1
1
1
1
0

Solution in C++ (GCC 9.2.1) (judge verdict: Runtime Error)

#include<bits/stdc++.h>
#define FasterIO     ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
using namespace std;
int main()
{
     FasterIO
    int n,a[9999],b[9999];
    vector<int>vec;
    cin>>n;
    for(int i=0; i<n-1; i++)
    {
        cin>>a[i];
    }
    int cnt=1,j=0;
    for(int i=0; i<n-1; i++)
    {
        if(a[i]==a[i+1])
        {
            cnt++;
            if(i+1==n-2)
            {
                b[j]=cnt;
                cnt=1;
                j++;
                break;
            }
            continue;
        }
        else
        {
            b[j]=cnt;
            cnt=1;
            j++;
        }
        if(i+1==n-2)
            {
                b[j]=cnt;
                cnt=1;
                j++;
                break;
            }
    }
    for(int i=j;i<n;i++)
    {
        b[i]=0;
        //cout<<i<<" ";
    }
   // cout<<endl;
    for(int i=0; i<n; i++)
    {
        cout<<b[i]<<endl;
    }
    return 0;
}