Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <stdio.h>
int aa, bb, cc;
int n, a, b, c, f, t;
char s[3];
int x[100000];
int main() {
	scanf("%d%d%d%d", &n, &a, &b, &c);
	aa = a; bb = b; cc = c;
	for (int i = 0; i < n; i++) {
		scanf(" %s", s);
		if (s[0] == 'A' && s[1] == 'B')x[i] = 2;
		if (s[0] == 'A' && s[1] == 'C')x[i] = 1;
		if (s[0] == 'B' && s[1] == 'C')x[i] = 0;
	}
	for (int i = 0; i < n; i++) {
		t = 1;
		if (x[i] == 0) {
			if (b == 0 && c == 0)f = 1;
			if (a == 0 && b == 1 && c == 1 && i != n - 1) {
				t = 0;
				if (x[i + 1] == 0) {
					//printf("B\nC\n");
					i++;
				}
				if (x[i + 1] == 1) {
					//printf("C\nA\n");
					i++;
					a++;
					b--;
				}
				if (x[i + 1] == 2) {
					//printf("B\nA\n");
					i++;
					a++;
					c--;
				}
			}
			else {
				if (b < c) {
					//printf("B\n");
					b++;
					c--;
				}
				else {
					//printf("C\n");
					c++;
					b--;
				}
			}
		}
		if (x[i] == 1 && t) {
			if (a == 0 && c == 0)f = 1;
			if (a == 1 && b == 0 && c == 1 && i != n - 1) {
				t = 0;
				if (x[i + 1] == 1) {
					//printf("C\nA\n");
					i++;
				}
				if (x[i + 1] == 2) {
					//printf("A\nB\n");
					i++;
					b++;
					c--;
				}
				if (x[i + 1] == 0) {
					//printf("C\nB\n");
					i++;
					b++;
					a--;
				}
			}
			else {
				if (c < a) {
					//printf("C\n");
					c++;
					a--;
				}
				else {
					//printf("A\n");
					a++;
					c--;
				}
			}
		}
		if (x[i] == 2 && t) {
			if (a == 0 && b == 0)f = 1;
			if (a == 1 && b == 1 && c == 0 && i != n - 1) {
				if (x[i + 1] == 2) {
					//printf("A\nB\n");
					i++;
				}
				if (x[i + 1] == 0) {
					//printf("B\nC\n");
					i++;
					c++;
					a--;
				}
				if (x[i + 1] == 1) {
					//printf("A\nC\n");
					i++;
					c++;
					b--;
				}
			}
			else {
				if (a < b) {
					//printf("A\n");
					a++;
					b--;
				}
				else {
					//printf("B\n");
					b++;
					a--;
				}
			}
		}
	}
	if (f) {
		printf("No\n");
		return 0;
	}
	printf("Yes\n");
	a = aa; b = bb; c = cc;
	for (int i = 0; i < n; i++) {
		t = 1;
		if (x[i] == 0) {
			if (b == 0 && c == 0)f = 1;
			if (a == 0 && b == 1 && c == 1 && i != n - 1) {
				t = 0;
				if (x[i + 1] == 0) {
					printf("B\nC\n");
					i++;
				}
				if (x[i + 1] == 1) {
					printf("C\nA\n");
					i++;
					a++;
					b--;
				}
				if (x[i + 1] == 2) {
					printf("B\nA\n");
					i++;
					a++;
					c--;
				}
			}
			else {
				if (b < c) {
					printf("B\n");
					b++;
					c--;
				}
				else {
					printf("C\n");
					c++;
					b--;
				}
			}
		}
		if (x[i] == 1 && t) {
			if (a == 0 && c == 0)f = 1;
			if (a == 1 && b == 0 && c == 1 && i != n - 1) {
				t = 0;
				if (x[i + 1] == 1) {
					printf("C\nA\n");
					i++;
				}
				if (x[i + 1] == 2) {
					printf("A\nB\n");
					i++;
					b++;
					c--;
				}
				if (x[i + 1] == 0) {
					printf("C\nB\n");
					i++;
					b++;
					a--;
				}
			}
			else {
				if (c < a) {
					printf("C\n");
					c++;
					a--;
				}
				else {
					printf("A\n");
					a++;
					c--;
				}
			}
		}
		else if (x[i] == 2 && t) {
			if (a == 0 && b == 0)f = 1;
			if (a == 1 && b == 1 && c == 0 && i != n - 1) {
				if (x[i + 1] == 2) {
					printf("A\nB\n");
					i++;
				}
				if (x[i + 1] == 0) {
					printf("B\nC\n");
					i++;
					c++;
					a--;
				}
				if (x[i + 1] == 1) {
					printf("A\nC\n");
					i++;
					c++;
					b--;
				}
			}
			else {
				if (a < b) {
					printf("A\n");
					a++;
					b--;
				}
				else {
					printf("B\n");
					b++;
					a--;
				}
			}
		}
	}
}