Problem:
Score : 500 points

Problem Statement

Count the pairs of length-N sequences consisting of integers between 1 and M (inclusive), A_1, A_2, \cdots, A_{N} and B_1, B_2, \cdots, B_{N}, that satisfy all of the following conditions:

A_i \neq B_i, for every i such that 1\leq i\leq N.

A_i \neq A_j and B_i \neq B_j, for every (i, j) such that 1\leq i < j\leq N.

Since the count can be enormous, print it modulo (10^9+7).

Constraints

1\leq N \leq M \leq 5\times10^5

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M

Output

Print the count modulo (10^9+7).

Sample Input 1

2 2

Sample Output 1

2

A_1=1,A_2=2,B_1=2,B_2=1 and A_1=2,A_2=1,B_1=1,B_2=2 satisfy the conditions.

Sample Input 2

2 3

Sample Output 2

18

Sample Input 3

141421 356237

Sample Output 3

881613484

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

// #include "pch.h"
#include <iostream>
#include <algorithm>
#include <map>
#include <set>
#include <queue>
#include <bitset>
#include <climits>
#include <string>
#include <cmath>
#include <bitset>
#include <complex>
#include <functional>
#include <ctime>
#include <cassert>
#include <fstream>
#include <stack>
#include <random>

typedef long long ll;
typedef std::pair<int, int> Pii;
typedef std::pair<long long, long long> Pll;
typedef std::pair<double, double> Pdd;

#define rip(i, n, s) for (int i = (s);i < (int)( n ); i++)
#define all(a) a.begin(), a.end()
#define MM << " " <<

template<typename T>
using MaxHeap = std::priority_queue<T>;
template<typename T>
using MinHeap = std::priority_queue<T, std::vector<T>, std::greater<T>>;

template<typename T>
inline bool chmax(T &a, T b) {
    if (a < b) {
        a = b;
        return true;
    }
    return false;
}
template<typename T>
inline bool chmin(T &a, T b) {
    if (a > b) {
        a = b;
        return true;
    }
    return false;
}

template<typename T>
void vdeb(std::vector<T> &da) {
    for (int i = 0;i < da.size();i++) {
        if (i == da.size() - 1) std::cout << da[i];
        else std::cout << da[i] << ' ';
    }
    std::cout << '\n';
}
template<typename T>
void vdeb(std::vector<std::vector<T>> &da) {
    for (int i = 0;i < da.size();i++) {
        std::cout << i << ' ';
        vdeb(da[i]);
    }
    std::cout << '\n';
}

long long pow(long long n, long long p, long long k) {//n^k(mod p)
    if (!k) return 1;
    long long a = pow(n,p, k>>1);
    a = a * a%p;
    if (k & 1) a = a * n%p;
    return a;
}
void euclid(long long &a, long long &b, long long p) { // a>=b A*b+B*(a-a/b*b)=1
    if (a == 1) {
        a = 1;
    }
    else {
        long long A = b, B = a % b;
        euclid(A, B, p);
        b = (A - (p + a / b) % p * B % p + p) % p;
        a = B;
    }
}
long long rev(long long n, long long p) {// n*x-p*y=1
    //long long q = p;
    //euclid(p, n, p);
    //return n % q;
    return pow(n,p,p-2);
}
long long bino(long long n, long long m, long long p) {//nCm(mod p)
    long long ans = 1, div = 1;
    for(int i = 0;i < m; i++){
        ans = (n - i) * ans % p;
        div = div * (i +1) % p;
    }
    return ans * rev(div, p) % p;
}
struct modint {
    long long num;
    long long p;
    modint() {
        num = 0;
        p = 1000000007;
    }
    modint(long long x) {
        p = 1000000007;
        num = x % p;
    }
    modint inv()const{return rev(num, p);}
    modint operator-() const{return modint(p-num);}
    modint& operator+=(const modint &other){
        num = (num + other.num) % p;
        return *this;
    }
    modint& operator-=(const modint &other){
        num = (num - other.num + p) % p;
        return *this;
    }
    modint& operator*=(const modint &other){
        num = (num * other.num) % p;
        return *this;
    }
    modint& operator/=(const modint &other){
        (*this) *= other.inv();
        return *this;
    }
    modint& operator+=(const long long &other){
        num = (num + other) % p;
        return *this;
    }
    modint& operator-=(const long long &other){
        num = (num - other + p) % p;
        return *this;
    }
    modint& operator*=(const long long &other){
        num = (num * other) % p;
        return *this;
    }
    modint& operator/=(const long long &other){
        (*this) *= rev(other, p);
        return *this;
    }
    modint& operator++(){return *this += 1;}
    modint& operator--(){return *this -= 1;}
    modint& operator=(const long long &other){return (*this) = modint(other);}
    modint operator+(const modint &other) const{return modint(*this) += other;}
    modint operator-(const modint &other) const{return modint(*this) -= other;}
    modint operator*(const modint &other) const{return modint(*this) *= other;}
    modint operator/(const modint &other) const{return modint(*this) /= other;}
    modint operator+(const long long &other) const{return modint(*this) += other;}
    modint operator-(const long long &other) const{return modint(*this) -= other;}
    modint operator*(const long long &other) const{return modint(*this) *= other;}
    modint operator/(const long long &other) const{return modint(*this) /= other;}
    bool operator==(const modint &other) const{return num == other.num;}
};
std::istream& operator>>(std::istream &is, const modint x) {
    std::cin >> x.num;
    return is;
}
std::ostream& operator<<(std::ostream &os, const modint &x){
    std::cout << x.num;
    return os;
}

using namespace std;

int main() {
    ll n,m; cin >> n >> m;;
    modint x(1);
    rip(i,n,0) x *= m-i;
    auto y = x;
    modint c(1),p(1);
    rip(i,n,0) {
        if((n-i)&1) y -= c*p;
        else y += c*p;
        // cout << c MM p << endl;
        c *= n-i;
        c /= i+1;
        p *= m-n+i+1;
    }
    cout << x*y << endl;
}