Problem:
Score : 400 points

Problem Statement

You are given integers N and M.

Consider a sequence a of length N consisting of positive integers such that a_1 + a_2 + ... + a_N = M. Find the maximum possible value of the greatest common divisor of a_1, a_2, ..., a_N.

Constraints

All values in input are integers.

1 \leq N \leq 10^5

N \leq M \leq 10^9

Input

Input is given from Standard Input in the following format:

N M

Output

Print the maximum possible value of the greatest common divisor of a sequence a_1, a_2, ..., a_N that satisfies the condition.

Sample Input 1

3 14

Sample Output 1

2

Consider the sequence (a_1, a_2, a_3) = (2, 4, 8). Their greatest common divisor is 2, and this is the maximum value.

Sample Input 2

10 123

Sample Output 2

3

Sample Input 3

100000 1000000000

Sample Output 3

10000

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;
#define ll long long 

void chmax(ll& a, ll b) {
  if (a < b) a = b;
}

int main() {
  ll N, M;
  cin >> N >> M;
  ll ans = 1;
  
  for (int i = 2; i * i <= M; i++) {
    if (M % i == 0 &&  i * N <= M) {
      chmax(ans, i);
    }
    if ((M/i) % i == 0 && M/i * N <= M) {
      chmax(ans, M/i);
    }
  }
  
  cout << ans << endl;
}