Problem:
Score : 400 points

Problem Statement

Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.

You are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.

Constraints

2 ≦ |s| ≦ 10^5

s consists of lowercase letters.

Partial Score

200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.

Input

The input is given from Standard Input in the following format:

s

Output

If there exists no unbalanced substring of s, print -1 -1.

If there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.

Sample Input 1

needed

Sample Output 1

2 5

The string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.

Sample Input 2

atcoder

Sample Output 2

-1 -1

The string atcoder contains no unbalanced substring.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#ifdef _DEBUG
#include "MyLib.h"
#else
#define main_D main
#include "bits/stdc++.h" 
#include <regex>
#define _USE_MATH_DEFINES
#include <math.h>
#define FOR(i,s,e) for (int i = int(s); i < int(e); ++i)
#define REP(i,e) FOR(i,0,e)
#define INF (INT_MAX/2)
#define EPS (1.0e-8)
#define LINF (LONG_MAX/2)
const int MGN = 8;
const int ARY_SZ_MAX = 10000000;
using namespace std;
using ll = long long; using ull = unsigned long long;
using vi = vector<int>; using vvi = vector<vi>; using vvvi = vector<vvi>;
using vb = vector<bool>; using vvb = vector<vb>; using vvvb = vector<vvb>;
using vl = vector<ll>; using vvl = vector<vl>;
using vd = vector<double>; using vs = vector<string>;
using pii = pair<int, int>; using pll = pair<ll, ll>;
// functions

#endif


int main_D() {
    cin.tie(0);
    ios::sync_with_stdio(false);

    string S;  cin >> S;
    int N = S.size();

    REP(i,N-1) {
        if (S[i] == S[i+1]) {
            cout << i + 1 << ' ' << i + 2 << endl;
            return 0;
        }
    }
    REP(i,N-2) {
        if (S[i] == S[i+2]) {
            cout << i + 1 << ' ' << i + 3 << endl;
            return 0;
        }
    }

    cout << -1 << ' ' << -1 << endl;

    return 0;
}