Problem:
Score : 200 points

Problem Statement

A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.

How many times will the ball make a bounce where the coordinate is at most X?

Constraints

1 \leq N \leq 100

1 \leq L_i \leq 100

1 \leq X \leq 10000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N X
L_1 L_2 ... L_{N-1} L_N

Output

Print the number of times the ball will make a bounce where the coordinate is at most X.

Sample Input 1

3 6
3 4 5

Sample Output 1

2

The ball will make a bounce at the coordinates 0, 3, 7 and 12, among which two are less than or equal to 6.

Sample Input 2

4 9
3 3 3 3

Sample Output 2

4

The ball will make a bounce at the coordinates 0, 3, 6, 9 and 12, among which four are less than or equal to 9.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;

typedef long long ll;
const ll INF = 1LL<<60, MOD = 1e9 + 7;
const double EPS = 1e-9, PI = 3.141592653589793;
#define REP(i,a,b) for(ll i=a;i<b;i++)
#define rep(i,n) REP(i,0,n)
#define all(v) (v).begin(), (v).end()
#define first fi
#define second se

int main(){
  cin.tie(0);
  ios::sync_with_stdio(false);
  
  ll n,x,ans=1;
  cin >> n >> x;
  vector<ll> l(n);
  rep(i,n) cin >> l[i];
  ll d[150];
  d[0] = 0;
  REP(i,1,n){
    d[i] = d[i-1] + l[i-1];
    if(d[i]>x) break;
    ans++;
  }
  cout << ans << endl;
  return 0;
}