Problem:
Score : 400 points

Problem Statement

We have a tree with N vertices numbered 1 to N.
The i-th edge in the tree connects Vertex u_i and Vertex v_i, and its length is w_i.
Your objective is to paint each vertex in the tree white or black (it is fine to paint all vertices the same color) so that the following condition is satisfied:

For any two vertices painted in the same color, the distance between them is an even number.

Find a coloring of the vertices that satisfies the condition and print it. It can be proved that at least one such coloring exists under the constraints of this problem.

Constraints

All values in input are integers.

1 \leq N \leq 10^5

1 \leq u_i < v_i \leq N

1 \leq w_i \leq 10^9

Input

Input is given from Standard Input in the following format:

N
u_1 v_1 w_1
u_2 v_2 w_2
.
.
.
u_{N - 1} v_{N - 1} w_{N - 1}

Output

Print a coloring of the vertices that satisfies the condition, in N lines.
The i-th line should contain 0 if Vertex i is painted white and 1 if it is painted black.

If there are multiple colorings that satisfy the condition, any of them will be accepted.

Sample Input 1

3
1 2 2
2 3 1

Sample Output 1

0
0
1

Sample Input 2

5
2 5 2
2 3 10
1 3 8
3 4 2

Sample Output 2

1
0
1
0
1

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
 
#define M_PI       3.14159265358979323846
 
using namespace std;
 
 
//typedef
//-------------------------#include <bits/stdc++.h>
 
#define M_PI       3.14159265358979323846
 
using namespace std;
 
//conversion
//------------------------------------------
inline int toInt(string s) { int v; istringstream sin(s); sin >> v; return v; }
template<class T> inline string toString(T x) { ostringstream sout; sout << x; return sout.str(); }
inline int readInt() { int x; scanf("%d", &x); return x; }
 
//typedef
//------------------------------------------
typedef vector<int> VI;
typedef vector<VI> VVI;
typedef vector<string> VS;
typedef pair<int, int> PII;
typedef pair<int, PII> TIII;
typedef long long LL;
typedef unsigned long long ULL;
typedef vector<LL> VLL;
typedef vector<VLL> VVLL;
 
 
//container util
 
//------------------------------------------
#define ALL(a)  (a).begin(),(a).end()
#define RALL(a) (a).rbegin(), (a).rend()
#define PB push_back
#define MP make_pair
#define SZ(a) int((a).size())
#define SQ(a) ((a)*(a))
#define EACH(i,c) for(typeof((c).begin()) i=(c).begin(); i!=(c).end(); ++i)
#define EXIST(s,e) ((s).find(e)!=(s).end())
#define SORT(c) sort((c).begin(),(c).end())
 
//repetition
//------------------------------------------
#define FOR(i,s,n) for(int i=s;i<(int)n;++i)
#define REP(i,n) FOR(i,0,n)
#define MOD 1000000007
 
#define rep(i, a, b) for(int i = a; i < (b); ++i)
#define trav(a, x) for(auto& a : x)
#define all(x) x.begin(), x.end()
#define sz(x) (int)(x).size()
 
 
 
typedef long long ll;
typedef pair<int, int> pii;
typedef vector<int> vi;
const double EPS = 1E-8;
 
#define chmin(x,y) x=min(x,y)
#define chmax(x,y) x=max(x,y)
const int INF = 100000000;
 
struct Edge {
    int to, from;
    ll cost;
    Edge(int from, int to, ll cost): from(from), to(to), cost(cost) {}
};
 
class UnionFind {
public:
    vector <ll> par; 
    vector <ll> siz; 
    
    vector <ll> maxv;
    UnionFind(ll sz_): par(sz_), siz(sz_, 1LL) {
        for (ll i = 0; i < sz_; ++i) par[i] = i;
    }
    void init(ll sz_) {
        par.resize(sz_);
        siz.assign(sz_, 1LL);
        for (ll i = 0; i < sz_; ++i) par[i] = i;
    }
 
    ll root(ll x) { 
        while (par[x] != x) {
            x = par[x] = par[par[x]];
        }
        return x;
    }
 
    bool merge(ll x, ll y) {
        x = root(x);
        y = root(y);
        if (x == y) return false;
        if (siz[x] < siz[y]) swap(x, y);
        siz[x] += siz[y];
        par[y] = x;
        return true;
    }
 
    bool issame(ll x, ll y) { 
        return root(x) == root(y);
    }
 
    ll size(ll x) { 
        return siz[root(x)];
    }
};
 
typedef vector<vector<Edge>> AdjList;
AdjList graph;
 
ll mod_pow(ll x, ll n, ll mod){
    ll res = 1;
    bool c = false;
    while(n){
        if(n&1) res = res * x;
 
        if(res > mod){
            c = true;
            res %= mod;
        }
        x = x * x %mod;
        n >>= 1;
    }
    if(c) return mod;
    return res;
}
 
#define SIEVE_SIZE 5000000+10
bool sieve[SIEVE_SIZE];
void make_sieve(){
    for(int i=0; i<SIEVE_SIZE; ++i) sieve[i] = true;
    sieve[0] = sieve[1] = false;
    for(int i=2; i*i<SIEVE_SIZE; ++i) if(sieve[i]) for(int j=2; i*j<SIEVE_SIZE; ++j) sieve[i*j] = false;
}
 
bool isprime(ll n){
    if(n == 0 || n == 1) return false;
    for(ll i=2; i*i<=n; ++i) if(n%i==0) return false;
    return true;
}
 
template<typename T>
vector<T> gauss_jordan(const vector<vector<T>>& A, const vector<T>& b){
    int n = A.size();
    vector<vector<T>> B(n, vector<T>(n+1));
 
    for(int i=0; i<n; ++i){
        for(int j=0; j<n; ++j){
            B[i][j] = A[i][j];
        }
    }
 
    for(int i=0; i<n; ++i) B[i][n] = b[i];
 
    for(int i=0; i<n; ++i){
        int pivot = i;
        for(int j=i; j<n; ++j){
            if(abs(B[j][i]) > abs(B[pivot][i])) pivot = j;
        }
        swap(B[i], B[pivot]);
 
        if(abs(B[i][i]) < EPS) return vector<T>(); //解なし
 
        for(int j=i+1; j<=n; ++j) B[i][j] /= B[i][i];
        for(int j=0; j<n; ++j){
            if(i != j){
                for(int k=i+1; k<=n; ++k) B[j][k] -= B[i][j] * B[i][k];
            }
        }
    }
 
    vector<T> x(n);
 
    for(int i=0; i<n; ++i) x[i] = B[i][n];
    return x;
    
}
 
 
 
 
typedef vector<ll> vec;
typedef vector<vec> mat;
 
mat mul(mat &A, mat &B) {
    mat C(A.size(), vec((int)B[0].size()));
    for(int i=0; i<A.size(); ++i){
        for(int k=0; k<B.size(); ++k){
            for(int j=0; j<B[0].size(); ++j){
                C[i][j] = (C[i][j] + A[i][k] * B[k][j] %MOD) % MOD;
            }
        }
    }
    return C;
}
mat mat_pow(mat A, ll n) {
    mat B(A.size(), vec((int)A.size()));
 
    for(int i=0; i<A.size(); ++i){
        B[i][i] = 1;
    }
 
    while(n > 0) {
        if(n & 1) B = mul(B, A);
        A = mul(A, A);
        n >>= 1;
    }
    return B;
}
 
bool operator<(const pii& a, const pii& b){
    if(a.first == b.first) return a.second < b.second;
    return a.first < b.first;
}
 
const int MAX = 510000;
long long fac[MAX], finv[MAX], inv[MAX];
 
// テーブルを作る前処理
void COMinit() {
    fac[0] = fac[1] = 1;
    finv[0] = finv[1] = 1;
    inv[1] = 1;
    for (int i = 2; i < MAX; i++){
        fac[i] = fac[i - 1] * i % MOD;
        inv[i] = MOD - inv[MOD%i] * (MOD / i) % MOD;
        finv[i] = finv[i - 1] * inv[i] % MOD;
    }
}
 
// 二項係数計算
long long COM(int n, int k){
    if (n < k) return 0;
    if (n < 0 || k < 0) return 0;
    return fac[n] * (finv[k] * finv[n - k] % MOD) % MOD;
}
 
int bit[1000010];
int sums(int i){
    i++;
    int s = 0;
    while(i > 0){
        s += bit[i];
        i -= i & -i;
    }
    return s;
}
void add(int i, int x){
    i++;
    while(i <= 1000010){
        bit[i] += x;
        i += i & -i;
    }
}
long long extGCD(long long a, long long b, long long &x, long long &y) {
    if (b == 0) {
        x = 1;
        y = 0;
        return a;
    }
    long long d = extGCD(b, a%b, y, x);
    y -= a/b * x;
    return d;
}
 
ll GCD(ll a, ll b){
    
    if(b == 0) return a;
    return GCD(b, a%b);
}
 
struct BipartiteMatching {
  vector< vector< int > > graph;
  vector< int > match, alive, used;
  int timestamp;
 
  BipartiteMatching(int n) : graph(n), alive(n, 1), used(n, 0), match(n, -1), timestamp(0) {}
 
  void add_edge(int u, int v) {
    graph[u].push_back(v);
    graph[v].push_back(u);
  }
 
  bool dfs(int idx) {
    used[idx] = timestamp;
    for(auto &to : graph[idx]) {
      int to_match = match[to];
      if(alive[to] == 0) continue;
      if(to_match == -1 || (used[to_match] != timestamp && dfs(to_match))) {
        match[idx] = to;
        match[to] = idx;
        return true;
      }
    }
    return false;
  }
 
  int bipartite_matching() {
    int ret = 0;
    for(int i = 0; i < graph.size(); i++) {
      if(alive[i] == 0) continue;
      if(match[i] == -1) {
        ++timestamp;
        ret += dfs(i);
      }
    }
    return ret;
  }
 
  void output() {
    for(int i = 0; i < graph.size(); i++) {
      if(i < match[i]) {
        cout << i << "-" << match[i] << endl;
      }
    }
  }
};

struct PartiallyPersistentUnionFind {

    using pint = pair<int, int>;

    // last[i]が-1でならその頂点iは根である
    // あるtに対してt < last[i]が成り立つなら, tにおいて頂点iは根である
    // last[i]は一度しか更新されない ⇔ 縮約を行わない

    // historyはmergeが行われるたびにemplace_backされる
    // history[i].FIはtでソートされているため, 要素数をみるだけでsizeを求められる
    vector<int> par, last;
    vector<vector<pint>> history;

    PartiallyPersistentUnionFind(int n) : par(n, -1), last(n, -1), history(n) {
        for(auto &vec : history) vec.emplace_back(-1, -1);
    }

    void init(int n){
        par.assign(n, -1); last.assign(n, -1); history.assign(n, vector<pint>());
        for(auto &vec: history) vec.emplace_back(-1, -1);
    }

    int root(int t, int x){
        if(last[x] == -1 || t < last[x]) return x;
        return root(t, par[x]);
    }

    bool issame(int t, int x, int y){
        return root(t, x) == root(t, y);
    }

    bool merge(int t, int x, int y){
        x = root(t, x);
        y = root(t, y);

        if(x == y) return false;
        // xとyをmergeする
        if( par[x] > par[y]) swap(x, y);
        par[x] += par[y];
        par[y] = x;
        // yが根でなくなったのはtなので lastに記録する
        last[y] = t; 
        history[x].emplace_back(t, par[x]);
        return true;
    }

    int size(int t, int x){
        x = root(t, x);
        
        return -prev(lower_bound(history[x].begin(), history[x].end(), make_pair(t, 0)))->second;
    }
};

vector<vector<pii>> G(100010);
int ans[100010];
bool visited[100010];
void dfs(int v, int c, int prev = -1){

    if(visited[v]) return;
    visited[v] = true;

    ans[v] = c;
    for(int i=0; i<G[v].size(); i++){
        pii p = G[v][i];
        int u = p.first, cc = p.second;

        if(u != prev){

            if(cc%2 == 0){
                dfs(u, c, v);
            }else{
                dfs(u, c^1, v);
            }
        }
    }
}
int main() {
    cin.tie(0);
    ios::sync_with_stdio(false);
    cout << fixed << setprecision(15);

    int N; cin >> N;
    REP(i,N) visited[i] = false;
    REP(i,N-1){
        int u, v, w; cin >> u >> v >> w;
        u--; v--;
        G[u].PB({v, w});
        G[v].PB({u, w});
    }

    dfs(0, 1);

    for(int i=0; i<N; i++){
        cout << ans[i] << endl;
    }
    return 0;
}