Problem:
Score : 1100 points

Problem Statement

There are N strings of lowercase alphabet only. The i-th string is S_i. Every string is unique.

Provide answers for the Q queries below. The i-th query has the following format:

Query: An integer k_i and a string p_{i,1}p_{i,2}...p_{i,26} that results from permuting {a,b,...,z} are given. Output the sequence of the string S_{k_i} among the N strings in lexicographical order when the literal sequence is p_{i,1}<p_{i,2}<...<p_{i,26}.

Constraints

1 ≦ N,Q ≦ 100000

1 ≦ |S_i| (1 ≦ i ≦ N)

S_i (1 ≦ i ≦ N) is a string of lowercase alphabet.

The sum of |S_i| is no more than 400000.

Every S_i is unique.

1 ≦ k_i ≦ N (1 ≦ i ≦ Q)

For all 1 ≦ i ≦ Q, p_{i,1}p_{i,2}...p_{i,26} is a permutation of abcd...z.

Input

Inputs are provided from standard inputs in the following form.

N
S_1
:
S_N
Q
k_1 p_{1,1}p_{1,2}...p_{1,26}
:
k_Q p_{Q,1}p_{Q,2}...p_{Q,26}

Output

Output Q lines.

On line i, for the i-th query, output an integer indicating the sequence of the string S_{k_i} among the N strings in lexicographical order.

Sample Input 1

5
aa
abbaa
abbba
aaab
aaaaaba
5
1 abcdefghijklmnopqrstuvwxyz
2 bacdefghijklmnopqrstuvwxyz
3 abcdefghijklmnopqrstuvwxyz
4 bacdefghijklmnopqrstuvwxyz
5 abcdefghijklmnopqrstuvwxyz

Sample Output 1

1
2
5
4
2

When the literal sequence is a < b, sorting the input strings in lexicographical order yields aa, aaaaaba, aaab, abbaa, abbba. The answers to queries 1, 3, and 5 are thus 1, 5, and 2, respectively.

When the literal sequence is b < a, sorting the input strings in lexicographical order yields abbba, abbaa, aa, aaab, aaaaaba. The answers to queries 2 and 4 are thus 2 and 4, respectively.

Sample Input 2

8
abrakatabra
abadaba
abracadabra
atcoder
grand
contest
ababa
a
6
3 abcdefghijklmnopqrstuvwxyz
6 qwertyuiopasdfghjklzxcvbnm
8 poiuytrewqlkjhgfdsamnbvcxz
2 qazwsxedcrfvtgbyhnujmikolp
1 plokmijnuhbygvtfcrdxeszwaq
4 mnbvcxzasdfghjklpoiuytrewq

Sample Output 2

4
8
2
3
4
7

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#define pb push_back
#define mp make_pair
#define inf 998244353
#define LINF 1000000000000000007LL
#define ll long long
using namespace std;
template< int char_size >
struct TrieNode {
  int nxt[char_size];

  int exist;
  vector< int > accept;

  TrieNode() : exist(0) {
    memset(nxt, -1, sizeof(nxt));
  }
};

template< int char_size, int margin >
struct Trie {
  using Node = TrieNode< char_size >;

  vector< Node > nodes;
  int root;

  Trie() : root(0) {
    nodes.push_back(Node());
  }

  void update_direct(int node, int id) {
    nodes[node].accept.push_back(id);
  }

  void update_child(int node, int child, int id) {
    ++nodes[node].exist;
  }

  void add(const string &str, int str_index, int node_index, int id) {
    if(str_index == str.size()) {
      update_direct(node_index, id);
    } else {
      const int c = str[str_index] - margin;
      if(nodes[node_index].nxt[c] == -1) {
        nodes[node_index].nxt[c] = (int) nodes.size();
        nodes.push_back(Node());
      }
      add(str, str_index + 1, nodes[node_index].nxt[c], id);
      update_child(node_index, nodes[node_index].nxt[c], id);
    }
  }

  void add(const string &str, int id) {
    add(str, 0, 0, id);
  }

  void add(const string &str) {
    add(str, nodes[0].exist);
  }

  void query(const string &str, const function< void(int) > &f, int str_index, int node_index) {
    for(auto &idx : nodes[node_index].accept) f(idx);
    if(str_index == str.size()) {
      return;
    } else {
      const int c = str[str_index] - margin;
      if(nodes[node_index].nxt[c] == -1) return;
      query(str, f, str_index + 1, nodes[node_index].nxt[c]);
    }
  }

  void query(const string &str, const function< void(int) > &f) {
    query(str, f, 0, 0);
  }

  int count() const {
    return (nodes[0].exist);
  }

  int size() const {
    return ((int) nodes.size());
  }
};
int prx[114514],cp[100009][26][26];
signed main(){
	Trie< 26, 'a' > trie;
	int n;
	cin>>n;
	vector<string> s;
	for(int i=0;i<n;i++){
		string tmp;
		cin>>tmp;
		trie.add(tmp);
		s.pb(tmp);
	}
	for(int i=0;i<n;i++){
		auto count_pref = [&](int idx){ prx[i]++; };
		trie.query(s[i],count_pref);
		prx[i]--;
	}
	for(int i=0;i<n;i++){
		int cur = 0;
		for(int j=0;j<s[i].size();j++){
			for(int k=0;k<26;k++){
				if( k == s[i][j] - 'a' )continue;
				int nx = trie.nodes[cur].nxt[k];
				if( nx != -1 ) cp[i][k][s[i][j] - 'a'] += trie.nodes[nx].exist + trie.nodes[nx].accept.size();
			}
          	cur = trie.nodes[cur].nxt[ s[i][j]-'a' ];
		}
	}
	int q; cin>>q;
	for(int p=0;p<q;p++){
		int num; string jun;
		int ans = 0;
		cin>>num;
		cin>>jun;
		num--;
		ans += prx[num];
		for(int i=0;i<26;i++){
			for(int j=i+1;j<26;j++){
				ans += cp[num][jun[i]-'a'][jun[j]-'a'];
			}
		}
		cout<<ans+1<<endl;
	}
	return 0;
}