Problem:
Score: 200 points

Problem Statement

Takahashi will do a tap dance. The dance is described by a string S where each character is L, R, U, or D. These characters indicate the positions on which Takahashi should step. He will follow these instructions one by one in order, starting with the first character.

S is said to be easily playable if and only if it satisfies both of the following conditions:

Every character in an odd position (1-st, 3-rd, 5-th, \ldots) is R, U, or D.

Every character in an even position (2-nd, 4-th, 6-th, \ldots) is L, U, or D.

Your task is to print Yes if S is easily playable, and No otherwise.

Constraints

S is a string of length between 1 and 100 (inclusive).

Each character of S is L, R, U, or D.

Input

Input is given from Standard Input in the following format:

S

Output

Print Yes if S is easily playable, and No otherwise.

Sample Input 1

RUDLUDR

Sample Output 1

Yes

Every character in an odd position (1-st, 3-rd, 5-th, 7-th) is R, U, or D.

Every character in an even position (2-nd, 4-th, 6-th) is L, U, or D.

Thus, S is easily playable.

Sample Input 2

DULL

Sample Output 2

No

The 3-rd character is not R, U, nor D, so S is not easily playable.

Sample Input 3

UUUUUUUUUUUUUUU

Sample Output 3

Yes

Sample Input 4

ULURU

Sample Output 4

No

Sample Input 5

RDULULDURURLRDULRLR

Sample Output 5

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

//IN THE NAME OF GOD;
//Test By Dev-C++5.11
#include<bits/stdc++.h>
#define ll  long long
#define isc ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);
#define ld long double
#define ss string
#define ww while
#define vl vector<ll>
#define pb push_back
#define in insert
#define itr iterator
#define gt goto
#define rep(i,n,j) for(ll i=n;i<j;i++)
#define tep(i,n,j) for(ll i=n;i>=j;i--)
#define co(n) cout << n ;
#define pll pair<ll,ll>
#define bft bool f=true
#define bff bool f=false
using namespace std;

ll bmm(ll a, ll b) {
	if (b == 0) return a;
	else return bmm(b, a%b);
}
ll kmm(ll a, ll b) {
	return(a*b) / bmm(a, b);
}


const ll mod = 1e9 + 7;
const ll MAXN = 3e5+5;

ss s;
bft;
int main() {
	isc;
	cin >> s;
	rep(i,0,s.size() && f){
		if(i%2==0){
			if(s[i]=='L')
				f=false;
		}
		else{
			if(s[i]=='R')
				f=false;
		}
	}
	if(f)
		cout << "Yes";
	else
		cout << "No";
	return 0;
}