Problem:
Score : 200 points

Problem Statement

Tak performed the following action N times: rolling two dice.
The result of the i-th roll is D_{i,1} and D_{i,2}.

Check if doublets occurred at least three times in a row.
Specifically, check if there exists at lease one i such that D_{i,1}=D_{i,2}, D_{i+1,1}=D_{i+1,2} and D_{i+2,1}=D_{i+2,2} hold.

Constraints

3 \leq N \leq 100

1\leq D_{i,j} \leq 6

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
D_{1,1} D_{1,2}
\vdots
D_{N,1} D_{N,2}

Output

Print Yes if doublets occurred at least three times in a row. Print No otherwise.

Sample Input 1

5
1 2
6 6
4 4
3 3
3 2

Sample Output 1

Yes

From the second roll to the fourth roll, three doublets occurred in a row.

Sample Input 2

5
1 1
2 2
3 4
5 5
6 6

Sample Output 2

No

Sample Input 3

6
1 1
2 2
3 3
4 4
5 5
6 6

Sample Output 3

Yes

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
#define ll             long long int
#define lb             lower_bound
#define fi             first
#define ub             upper_bound
#define se              second
#define mp             make_pair
#define vll            vector<ll>
#define mod            1000003
#define endl            "\n"
#define fast           ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
#define pb             push_back
#define sz               size()
#define all(v)         v.begin(),v.end()
#define allr(v)        v.rbegin(),v.rend()
#define inp(V,n)       for(int i=0;i<n;i++){cin >> V[i];}
#define oup(V,n)       {for(int i=0;i<n;i++){cout <<  V[i] << " "  ;} cout << endl;}
using namespace std;
ll factorial(ll n)
{
    return (n == 1 || n == 0) ? 1 : n * factorial(n - 1);
}
ll gcd(ll a, ll b)
{
    if (a == 0)
      return b;
    return gcd(b % a, a);
}
ll lcm(ll a, ll b)
{
   return (a*b)/gcd(a, b);
}
bool sortByVal(const pair<double,double> &a,
               const pair<double,double> &b)
{
    if(a.fi==b.fi)
    {
    return (a.second >b.second);
    }
    else
        return (a.fi<b.fi);
}
int main()
{
   ll i,j,k,l,m,n,c=0;
     string str;
    cin>>n;
    ll a,b;
    vll v(n),v1;
    for(i=0;i<n;i++)
    { cin>>a>>b;
      if(a==b)
      {c++;
      }
       else
        {v1.pb(c);
       c=0;
       }


    } v1.pb(c);ll flag=0;
    for(i=0;i<v1.size();i++)
    {

     if(v1[i]>=3)
        flag=1;
    }
    if(flag==1)cout<<"Yes"<<endl;
    else cout<<"No"<<endl;


return 0;
}