Problem:
Score : 600 points

Problem Statement

A tetromino is a figure formed by joining four squares edge to edge.
We will refer to the following seven kinds of tetromino as I-, O-, T-, J-, L-, S- and Z-tetrominos, respectively:

Snuke has many tetrominos. The number of I-, O-, T-, J-, L-, S- and Z-tetrominos in his possession are a_I, a_O, a_T, a_J, a_L, a_S and a_Z, respectively.
Snuke will join K of his tetrominos to form a rectangle that is two squares tall and 2K squares wide.
Here, the following rules must be followed:

When placing each tetromino, rotation is allowed, but reflection is not.

Each square in the rectangle must be covered by exactly one tetromino.

No part of each tetromino may be outside the rectangle.

Snuke wants to form as large a rectangle as possible.
Find the maximum possible value of K.

Constraints

0≤a_I,a_O,a_T,a_J,a_L,a_S,a_Z≤10^9

a_I+a_O+a_T+a_J+a_L+a_S+a_Z≥1

Input

The input is given from Standard Input in the following format:

a_I a_O a_T a_J a_L a_S a_Z

Output

Print the maximum possible value of K. If no rectangle can be formed, print 0.

Sample Input 1

2 1 1 0 0 0 0

Sample Output 1

3

One possible way to form the largest rectangle is shown in the following figure:

Sample Input 2

0 0 10 0 0 0 0

Sample Output 2

0

No rectangle can be formed.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

/* be name khoda */

// #define stream_enable
#define long_enable
#include <iostream>
#include <algorithm>
#include <cstring>
#include <numeric>
#include <iomanip>
#include <sstream>
#include <vector>
#include <queue>
#include <set>
#include <map>
using namespace std;

#ifdef stream_enable
#define cin sss
#endif
#ifdef long_enable
typedef long long int ll;
#else
typedef int ll;
#endif

typedef pair<ll, ll> pii;
typedef pair<pii, ll> ppi;
typedef pair<ll, pii> pip;
typedef vector<ll> vi;
typedef vector<pii> vpii;

const ll MOD = 1000000007;
const long long BIG = 1446803456761533460;
const int Big = 336860180;

#define F first
#define S second
#define pb push_back
#define eb emplace_back
#define all(x) (x).begin(), (x).end()

#define debug(x) cout << #x << " -> " << (x) << endl
#define debug2(x, y) cout << #x << ' ' << #y << " -> " << (x) << ' ' << (y) << endl
#define debug3(x, y, z) cout << #x << ' ' << #y << ' ' << #z << " -> " << (x) << ' ' << (y) << ' ' << (z) << endl
#define debug4(x, y, z, t) cout << #x << ' ' << #y << ' ' << #z << ' ' << #t << " -> " << (x) << ' ' << (y) << ' ' << (z) << ' ' << (t) << endl
#define debugp(x) cout << #x << " -> " << "(" << (x).F << ", " << (x).S << ")" << endl
#define debuga(x, n) cout << #x << " -> "; fori (i1_da, n) { cout << (x)[i1_da] << ' '; } cout << endl
#define debugap(x, n) cout << #x << " ->\n"; fori (i1_dap, n) { cout << "(" << (x)[i1_dap].F << ", " << (x)[i1_dap].S << ")\n"; } cout << endl
#define debugaa(x, n, m) cout << #x << " ->\n"; fori (i1_daa, n) { fori (i2_daa, m) { cout << (x)[i1_daa][i2_daa] << ' '; } cout << '\n'; } cout << endl
#define debugav(x, n) cout << #x << " ->\n"; fori (i1_dav, n) { fori (i2_dav, (x)[i1_dav].size()) { cout << (x)[i1_dav][i2_dav] << ' '; } cout << '\n'; } cout << endl
#define debugia(x, n) cout << #x << " ->\n"; fori (i1_dia, n) { cout << i1_dia << " : " << (x)[i1_dia] << '\n'; } cout << endl

#define forifrom(i, s, n) for(ll i = (s); i < (n); ++i)
#define forirto(i, n, e) for(ll i = (n) - 1; i >= (e); --i)
#define fori(i, n) forifrom (i, 0, n)
#define forir(i, n) forirto (i, n, 0)

#define smin(a, b) a = min(a, (b))
#define smax(a, b) a = max(a, (b))

#define Add(a, b) a = ((a) + (b)) % MOD
#define Mul(a, b) a = (1LL * (a) * (b)) % MOD

stringstream sss;

// -----------------------------------------------------------------------

const ll maxn = 100010;

ll I, O, T, J, L, S, Z;

void MAIN() {

    cin >> I >> O >> T >> J >> L >> S >> Z;
    ll s = 0;
    if (I && J && L && I % 2 + J % 2 + L % 2 >= 2) {
        --I, --J, --L;
        s += 3;
    }
    s += I / 2 * 2 + O + J / 2 * 2 + L / 2 * 2;
    cout << s << '\n';

}

// -----------------------------------------------------------------------

int main() {
    ios_base::sync_with_stdio(false), cin.tie(0), cout.tie(0);
    cout << fixed << setprecision(10);
    sss << R"(
2 1 1 0 0 0 0

    )";
    MAIN();
    return 0;
}