Problem:
Score : 200 points

Problem Statement

For a string S consisting of the uppercase English letters P and D, let the doctoral and postdoctoral quotient of S be the total number of occurrences of D and PD in S as contiguous substrings. For example, if S = PPDDP, it contains two occurrences of D and one occurrence of PD as contiguous substrings, so the doctoral and postdoctoral quotient of S is 3.

We have a string T consisting of P, D, and ?.

Among the strings that can be obtained by replacing each ? in T with P or D, find one with the maximum possible doctoral and postdoctoral quotient.

Constraints

1 \leq |T| \leq 2 \times 10^5

T consists of P, D, and ?.

Input

Input is given from Standard Input in the following format:

T

Output

Print one string with the maximum possible doctoral and postdoctoral quotient among the strings that can be obtained by replacing each ? in T with P or D.
If there are multiple such strings, you may print any of them.

Sample Input 1

PD?D??P

Sample Output 1

PDPDPDP

This string contains three occurrences of D and three occurrences of PD as contiguous substrings, so its doctoral and postdoctoral quotient is 6, which is the maximum doctoral and postdoctoral quotient of a string obtained by replacing each ? in T with P or D.

Sample Input 2

P?P?

Sample Output 2

PDPD

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
//#include <ext/pb_ds/assoc_container.hpp>
#define F first
#define S second
#define pb push_back
#define mp make_pair 
#define rep(i,n) for(int i = 0; i < (n); i++)
#define rrep(i,n) for(int i = n - 1; i>= 0; i--)
#define debug(x) cout << '>' << #x << ':' << x << endl;
#define sq(a) (a)*(a)
#define nl "\n"
using namespace std;
//using namespace __gnu_pbds;
//typedef tree<int,null_type,less<int>,rb_tree_tag,
//tree_order_statistics_node_update> indexed_set;
typedef long long ll;
typedef vector<int> vi;
typedef pair<int,int> ii;
typedef vector<ii> vii;
typedef vector<ll> vll;


const double pi = 3.14159265359;
const int MAXN = 100005;
ll mod=1000000007;

int main()
{
	ios_base::sync_with_stdio(false);
	cin.tie(0);
	cout.tie(0);
	string s;
	cin>>s;
	for(int i = 0; i < s.size(); i++){
		if(s[i]=='?')s[i] = 'D';
	}
	cout<<s;
	return 0;
}