Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include<bits/stdc++.h>
using namespace std;
int main()
{
  long long n,a,b,c,found=0;cin>>n>>a>>b>>c;
  string s;
  vector<char>v;
  while(n--)
  {
  cin>>s;
    if(s=="AB"){if(a>=b){a--;b++;v.emplace_back('B');
               if(a==-1){found++;break;}}
               else{b--;a++;v.emplace_back('A');
                   if(b==-1){found++;break;}
                   }
               }
    else if(s=="AC")
    {
    if(a>=c){a--;c++;v.emplace_back('C');
               if(a==-1){found++;break;}}
               else{c--;a++;v.emplace_back('A');
                   if(c==-1){found++;break;}
                   }
    }
    else
    {
    if(c>=b){c--;b++;v.emplace_back('B');
               if(c==-1){found++;break;}}
               else{b--;c++;v.emplace_back('C');
                   if(b==-1){found++;break;}
                   }
    }
  }
  if(found!=0)return cout<<"No",0;
  else
  {
  cout<<"Yes"<<"\n";
    for(auto p:v)cout<<p<<"\n";
  }
}