Problem:
Score : 500 points

Problem Statement

You are given two integers A and B.

Print a grid where each square is painted white or black that satisfies the following conditions, in the format specified in Output section:

Let the size of the grid be h \times w (h vertical, w horizontal). Both h and w are at most 100.

The set of the squares painted white is divided into exactly A connected components.

The set of the squares painted black is divided into exactly B connected components.

It can be proved that there always exist one or more solutions under the conditions specified in Constraints section.
If there are multiple solutions, any of them may be printed.

Notes

Two squares painted white, c_1 and c_2, are called connected when the square c_2 can be reached from the square c_1 passing only white squares by repeatedly moving up, down, left or right to an adjacent square.

A set of squares painted white, S, forms a connected component when the following conditions are met:

Any two squares in S are connected.

No pair of a square painted white that is not included in S and a square included in S is connected.

A connected component of squares painted black is defined similarly.

Constraints

1 \leq A \leq 500

1 \leq B \leq 500

Input

Input is given from Standard Input in the following format:

A B

Output

Output should be in the following format:

In the first line, print integers h and w representing the size of the grid you constructed, with a space in between.

Then, print h more lines. The i-th (1 \leq i \leq h) of these lines should contain a string s_i as follows:

If the square at the i-th row and j-th column (1 \leq j \leq w) in the grid is painted white, the j-th character in s_i should be ..

If the square at the i-th row and j-th column (1 \leq j \leq w) in the grid is painted black, the j-th character in s_i should be #.

Sample Input 1

2 3

Sample Output 1

3 3
##.
..#
#.#

This output corresponds to the grid below:

Sample Input 2

7 8

Sample Output 2

3 5
#.#.#
.#.#.
#.#.#

Sample Input 3

1 1

Sample Output 3

4 2
..
#.
##
##

Sample Input 4

3 14

Sample Output 4

8 18
..................
..................
....##.......####.
....#.#.....#.....
...#...#....#.....
..#.###.#...#.....
.#.......#..#.....
#.........#..####.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <algorithm>
#include <cmath>
#include <iomanip>
#include <vector>
#include <utility>
#include <numeric>
#include <string>
#include <set>
#include <map>
#include <tuple>
#include <queue>
#include <stack>
#include <deque>
#define rep(i, a, n) for(int (i) = (int)(a);(i) < (int)(n);++(i))
#define repe(i, a, n) for(int (i) = (int)(a);(i) <= (int)(n);++(i))
#define repif(i, a, x) for(int (i) = (int)(a);(x);++(i))
#define repr(i, a, n) for(int (i) = (int)(a);(i) > (int)(n);--(i))
#define reper(i, a, n) for(int (i) = (int)(a);(i) >= (int)(n);--(i))
#define SIZE(x) ((int)(x).size())
#define ALL(x) (x).begin(), (x).end()
#define RNG(x, n) &((x)[0]), &((x)[n])
#define ADD(a, b) ((((a)%MOD)+((b)%MOD))%MOD)
#define MUL(a, b) ((((a)%MOD)*((b)%MOD))%MOD)
#define FLOOR(x) ((int)floor(((double)x)))
#define CEIL(x) ((int)ceil(((double)x)))
#define YES cout << "YES" << endl
#define NO cout << "NO" << endl
#define Yes cout << "Yes" << endl
#define No cout << "No" << endl
#define yes cout << "yes" << endl;
#define no cout << "no" << endl;
#define fcout cout << fixed << setprecision(10)
#define pb push_back
#define pf push_front
#define mt make_tuple
#define fi first
#define se second
#define EPS (1e-20)
#define INF 2147483647
#define MOD 1000000007
using llint = long long;
using VI = std::vector<int>;
using PII = std::pair<int, int>;
using SI = std::set<int>;
using MII = std::map<int, int>;
using TIII = std::tuple<int, int, int>;
using VLL = std::vector<llint>;
using MCI = std::map<char, int>;
using namespace std;


int A, B;
char ans[100][100];


void makeAns(){
	rep(i, 0, 50)
		rep(j, 0, 100) ans[i][j] = '.';
	rep(i, 50, 100)
		rep(j, 0, 100) ans[i][j] = '#';
		A--, B--;
	for(int i = 0;i < 50;i+=2){
		for(int j = 0;j < 100;j+=2){
			if(B == 0){ i = 50; break; }
			ans[i][j] = '#';
			B--;
		}
	}
	for(int i = 99;i >= 0;i-=2){
		for(int j = 0;j < 100;j+=2){
			if(A == 0){ i = 0; break; }
			ans[i][j] = '.';
			A--;
		}
	}
}


signed main(){
	cin >> A >> B;
	
	makeAns();
	
	cout << 100 << ' ' << 100 << endl;
	rep(i, 0, 100){
		rep(j, 0, 100) cout << ans[i][j];
		cout << endl;
	}
	
	return 0;
}