Problem:
Score : 200 points

Problem Statement

In Japan, people make offerings called hina arare, colorful crackers, on March 3.

We have a bag that contains N hina arare. (From here, we call them arare.)

It is known that the bag either contains arare in three colors: pink, white and green, or contains arare in four colors: pink, white, green and yellow.

We have taken out the arare in the bag one by one, and the color of the i-th arare was S_i, where colors are represented as follows - pink: P, white: W, green: G, yellow: Y.

If the number of colors of the arare in the bag was three, print Three; if the number of colors was four, print Four.

Constraints

1 \leq N \leq 100

S_i is P, W, G or Y.

There always exist i, j and k such that S_i=P, S_j=W and S_k=G.

Input

Input is given from Standard Input in the following format:

N
S_1 S_2 ... S_N

Output

If the number of colors of the arare in the bag was three, print Three; if the number of colors was four, print Four.

Sample Input 1

6
G W Y P Y W

Sample Output 1

Four

The bag contained arare in four colors, so you should print Four.

Sample Input 2

9
G W W G P W P G G

Sample Output 2

Three

The bag contained arare in three colors, so you should print Three.

Sample Input 3

8
P Y W G Y W Y Y

Sample Output 3

Four

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<iostream>
#include<string>
#include<vector>
#include<math.h>
#include<algorithm>
#include<cstdio>
#include<stdio.h>
#include<stack>
#include<sstream>
typedef long long ll;

#define pi 3.14159265358979323846
#define VI vector<int>
#define VLL vector<long long>
#define MAX max_element
#define MIN min_element
#define all(v) v.begin(), v.end()

using namespace std;

template<typename T>
T gcd(T a, T b) {
	return b ? gcd(b, a % b) : a;
}
template<typename T>
T lcm(T a, T b) {
	return a * b / gcd(a, b);
}

template<typename T>
T finder(vector<T> vec, T number) {
	auto itr = find(vec.begin(), vec.end(), number);
	size_t index = distance(vec.begin(), itr);
	if (index != vec.size()) { // 発見できたとき
		return 1;
	}
	else { // 発見できなかったとき
		return 0;
	}
}

/*char r[4];
int yaju[4];
char op[3];
int sum = 0;
scanf("%s", r);
for (int i = 0;i < 4;i++) {
	yaju[i] = r[i] - '0';
}
*/
int main() {
	ll N; cin >> N;
	ll a = 0, b = 0, c = 0, d = 0;
	ll ans = 0;
	vector<string> S(N);
	for (int i = 0;i < N;i++) cin >> S[i];
	for(int i=0;i<N;i++){
	if (S[i] == "G")a++;
	if (S[i] == "P")b++;
	if (S[i] == "W")c++;
	if (S[i] == "Y")d++;
	}
	if (a > 0) ans++;
	if (b > 0) ans++;
	if (c > 0) ans++;
	if (d > 0) ans++;
	if (ans == 4) cout << "Four" << endl;
	else cout << "Three" << endl;
}