Problem:
Score : 300 points

Problem Statement

You are given two integer sequences of length N: a_1,a_2,..,a_N and b_1,b_2,..,b_N.
Determine if we can repeat the following operation zero or more times so that the sequences a and b become equal.

Operation: Choose two integers i and j (possibly the same) between 1 and N (inclusive), then perform the following two actions simultaneously:

Add 2 to a_i.

Add 1 to b_j.

Constraints

1 ≤ N ≤ 10 000

0 ≤ a_i,b_i ≤ 10^9 (1 ≤ i ≤ N)

All input values are integers.

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 .. a_N
b_1 b_2 .. b_N

Output

If we can repeat the operation zero or more times so that the sequences a and b become equal, print Yes; otherwise, print No.

Sample Input 1

3
1 2 3
5 2 2

Sample Output 1

Yes

For example, we can perform three operations as follows to do our job:

First operation: i=1 and j=2. Now we have a = \{3,2,3\}, b = \{5,3,2\}.

Second operation: i=1 and j=2. Now we have a = \{5,2,3\}, b = \{5,4,2\}.

Third operation: i=2 and j=3. Now we have a = \{5,4,3\}, b = \{5,4,3\}.

Sample Input 2

5
3 1 4 1 5
2 7 1 8 2

Sample Output 2

No

Sample Input 3

5
2 7 1 8 2
3 1 4 1 5

Sample Output 3

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
 
#define mp make_pair
#define pb push_back
#define f first
#define s second
#define ll long long
#define forn(i, a, b) for(int i = (a); i <= (b); ++i)
#define forev(i, b, a) for(int i = (b); i >= (a); --i)
#define VAR(v, i) __typeof( i) v=(i)
#define forit(i, c) for(VAR(i, (c).begin()); i != (c).end(); ++i)
#define all(x) (x).begin(), (x).end()
#define sz(x) ((int)(x).size())
#define file(s) freopen(s".in","r",stdin); freopen(s".out","w",stdout);
 
using namespace std;
 
const int maxn = (int)3e5 + 100;
const int mod = (int)1e9 + 7;
const int P = (int) 1e6 + 7; 
const double pi = acos(-1.0);
 
#define inf mod
 
typedef long double ld;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef vector<int> vi;   
typedef vector<ll> vll;               
typedef vector<pair<int, int> > vpii;
typedef vector<pair<ll, ll> > vpll;                        

int n, b[maxn], a[maxn];
ll s1, s2;
main () {
	scanf("%d", &n);;
	forn(i, 1, n) scanf("%d", &a[i]), s1 += a[i];
	forn(i, 1, n) scanf("%d", &b[i]), s2 += b[i];
	ll dif = s2 - s1, step = 0;
	forn(i, 1, n){
		if(a[i] < b[i]) step += (b[i] - a[i] + 1) / 2;	
	}
	if(step <= dif) puts("Yes");
	else puts("No");
}