Problem:
Score : 100 points

Problem Statement

You will turn on the air conditioner if, and only if, the temperature of the room is 30 degrees Celsius or above.

The current temperature of the room is X degrees Celsius. Will you turn on the air conditioner?

Constraints

-40 \leq X \leq 40

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print Yes if you will turn on the air conditioner; print No otherwise.

Sample Input 1

25

Sample Output 1

No

Sample Input 2

30

Sample Output 2

Yes

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

// Template //
#include<bits/stdc++.h>
using namespace std;

// マクロ //
#define rep(v,times) for(int v = 0; v < (int)(times); v++)
#define req(v,first,endplus1) for(int v = first; v < (int)(endplus1); v++)
#define all(x) x.begin(), x.end()
#define sort(x) sort(all(x))
#define uniq(x) x.erase(unique(all(x)), x.end())
#define vsum(x) accumulate(all(x), 0)
#define cou(x) cout << x << endl
#define y() cout << "Yes" << endl
#define n() cout << "No" << endl
#define Y() cout << "YES" << endl
#define N() cout << "NO" << endl
#define x2(x) (x) * (x)

// 型エイリアス //
using lint = long long;
using pii = pair<int, int>;
using vpii = vector<pii>;
using plili = pair<lint, lint>;
using vplili = vector<plili>;
using vi = vector<int>;
using vli = vector<lint>;
using vc = vector<char>;
using vs = vector<string>;
using vb = vector<bool>;
using vvi = vector<vi>;
using vvli = vector<vli>;
using vvb = vector<vb>;
using vvc = vector<vc>;
using vvs = vector<vs>;
using mii = map<int, int>;
using mili = map<int, lint>;
using mci = map<char, int>;
using mcli = map<char, lint>;
using msi = map<string, int>;
using msli = map<string, lint>;


// 関数 //
template<class T, class Q> lint gcd_(T a, Q b) {
    int t;
    while (b != 0) {
        t = a % b;
        a = b;
        b = t;
    }
    return a;
}

template<class T, class Q> lint lcm_(T a, Q b) {
    return a * b / gcd_(a, b);
}

template<class T, class Q> double distance(T a, Q b) {
    double dist;
    dist = sqrt(x2(a.first - b.first) + x2(a.second - b.second));
    return dist;
}

lint perm(int a) {
    lint perm = 1;
    for (int i = a; i >= 1; i--) {
        perm *= i;
    }
    return perm;
}

lint combination(int n, int m) {
    long double c = 1;
    for (int i = n, k = 1; i > m; i--, k++) {
        c *= i;
        c /= k;
    }
    return (lint)c;
}

template<class T, class Q> inline bool chmin(T& a, Q b) {
    if (a > b) { 
        a = b;
        return true; 
    }
    return false;
}

template<class T, class Q> inline bool chmax(T& a, Q b) {
    if (a < b) { 
        a = b; 
        return true; 
    }
    return false;
}

// 定数 //
const double pi = acos(-1);
const int mod = 1000000007;
const int inf = 1045141919;
const lint linf = ((1LL << 62) - 1);
const int dx4[4] = { 1,0,-1,0 };
const int dy4[4] = { 0,1,0,-1 };
const int dx8[8] = { 1,1,0,-1,-1,-1,0,1 };
const int dy8[8] = { 0,1,1,1,0,-1,-1,-1 };

// End of Template //



int main() {

    cin.tie(0);
    ios::sync_with_stdio(false);
    cout << fixed << setprecision(15);
        
    int N;
    cin >> N;

    N >= 30 ? y() : n();


}