Problem:
Score : 100 points

Problem Statement

A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.

Given a string S, determine whether it is coffee-like.

Constraints

S is a string of length 6 consisting of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S

Output

If S is coffee-like, print Yes; otherwise, print No.

Sample Input 1

sippuu

Sample Output 1

Yes

In sippuu, the 3-rd and 4-th characters are equal, and the 5-th and 6-th characters are also equal.

Sample Input 2

iphone

Sample Output 2

No

Sample Input 3

coffee

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Runtime Error)

#include <algorithm>
#include <iostream>
#include <string>
#include <vector>
#include <cmath>
#define DEBUG(x) std::cout << '>' << #x << ':' << x << '\n';
#define PRINTVEC(x) for (int i = 0; i < (int)x.size(); i++) std::cout << x[i] << ' '; std::cout << '\n';
#define PRINTP(x) for (int i = 0; i < (int)x.size(); i++) std::cout << x[i].first << ' ' << x[i].second << '\n'; std::cout << '\n';
#define io std::ios_base::sync_with_stdio(false);std::cin.tie(NULL);   
const int INF = 1<<29;
typedef long long ll;



int main()
{
	io;
    #ifndef ONLINE_JUDGE
    freopen("input.txt", "r", stdin); 
    freopen("output.txt", "w", stdout);  
    #endif

    std::string s;
    std::cin >> s;
    std::cout << (s[2] == s[3] && s[4] == s[5] ? "Yes" : "No");

    #ifndef ONLINE_JUDGE   
    std::cout << '\n' << "Time elapsed : " << 1.0 * clock() / CLOCKS_PER_SEC << " sec \n";
    #endif
    return 0;
}