Problem:
Score : 400 points

Problem Statement

Given are three integers N, K, and S.

Find a sequence A_1, A_2, ..., A_N of N integers between 1 and 10^9 (inclusive) that satisfies the condition below.
We can prove that, under the conditions in Constraints, such a sequence always exists.

There are exactly K pairs (l, r) of integers such that 1 \leq l \leq r \leq N and A_l + A_{l + 1} + \cdots + A_r = S.

Constraints

1 \leq N \leq 10^5

0 \leq K \leq N

1 \leq S \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K S

Output

Print a sequence satisfying the condition, in the following format:

A_1 A_2 ... A_N

Sample Input 1

4 2 3

Sample Output 1

1 2 3 4

Two pairs (l, r) = (1, 2) and (3, 3) satisfy the condition in the statement.

Sample Input 2

5 3 100

Sample Output 2

50 50 50 30 70

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
#define rep(i,n) for (int i = 0; i < (n); ++i)
using namespace std;
using ll = long long;
using vi=vector<int>;
using P = pair<int,int>;
using Graph = vector<vector<int>>;

int main(){
    cin.tie(0);
    ios::sync_with_stdio(false);
    
    int n,k,s;
    cin >> n >> k >> s;
    vector<int> ans(n,0);
    if(k==0){
        rep(i,n) cout << ans[i]+1000000001 << "\n";
        return 0;
    }
    int t=n-k+1;
    int x=s/t;
    int y=s-x*t;
    rep(i,n){
        ans[i]+=x;
        if(i%t==0) ans[i]+=y;
    }
    rep(i,n) cout << ans[i] << "\n";
    return 0;
}