Problem:
Score : 400 points

Problem Statement

Snuke has N strings. The i-th string is s_i.

Let us concatenate these strings into one string after arranging them in some order.
Find the maximum possible number of occurrences of AB in the resulting string.

Constraints

1 \leq N \leq 10^{4}

2 \leq |s_i| \leq 10

s_i consists of uppercase English letters.

Input

Input is given from Standard Input in the following format:

N
s_1
\vdots
s_N

Output

Print the answer.

Sample Input 1

3
ABCA
XBAZ
BAD

Sample Output 1

2

For example, if we concatenate ABCA, BAD and XBAZ in this order, the resulting string ABCABADXBAZ has two occurrences of AB.

Sample Input 2

9
BEWPVCRWH
ZZNQYIJX
BAVREA
PA
HJMYITEOX
BCJHMRMNK
BP
QVFABZ
PRGKSPUNA

Sample Output 2

4

Sample Input 3

7
RABYBBE
JOZ
BMHQUVA
BPA
ISU
MCMABAOBHZ
SZMEHMA

Sample Output 3

4

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<iostream>
#include<algorithm>
using namespace std;
typedef long long ll;
ll n,a,b,c;
int main(){
    cin>>n;
    ll ans=0; a=b=c=0;
    for(int i=0;i<n;i++){
	string s;cin>>s;
	if(s[0]=='B'&&s[s.size()-1]=='A')a++;
	else if(s[0]=='B')b++;
	else if(s[s.size()-1]=='A')c++;
	for(int j=0;j<s.size()-1;j++){
	    if(s[j]=='A'&&s[j+1]=='B')ans++;
	}
    }//cout<<a<<" "<<b<<" "<<c<<endl;
    if(a==0){
	ans+=min(b,c);
    }
    else{
	ans+=a-1;
	if(b>0)ans++,b--;
	if(c>0)ans++,c--;
	ans+=min(b,c);
    }
    cout<<ans<<endl;
    return 0;
}