Problem:
Score : 200 points

Problem Statement

Given are a positive integer N and a string S of length N consisting of lowercase English letters.

Determine whether the string is a concatenation of two copies of some string.
That is, determine whether there is a string T such that S = T + T.

Constraints

1 \leq N \leq 100

S consists of lowercase English letters.

|S| = N

Input

Input is given from Standard Input in the following format:

N
S

Output

If S is a concatenation of two copies of some string, print Yes; otherwise, print No.

Sample Input 1

6
abcabc

Sample Output 1

Yes

Let T = abc, and S = T + T.

Sample Input 2

6
abcadc

Sample Output 2

No

Sample Input 3

1
z

Sample Output 3

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;

int main(){
  int N; string S;	
  cin >> N >> S;
  bool loop =true;
  if((N % 2) == 1){
    loop = false;
  }
  else{
    for(int i=0; i < N/2; i++){
      if(S.at(i) != S.at(i+N/2)){
        loop = false;
        break;
      }
    }
  }
  
  if(loop) cout << "Yes" << endl;
  else cout << "No" << endl;
  
}