Problem:
Score : 100 points

Problem Statement

Takahashi has K 500-yen coins. (Yen is the currency of Japan.)
If these coins add up to X yen or more, print Yes; otherwise, print No.

Constraints

1 \leq K \leq 100

1 \leq X \leq 10^5

Input

Input is given from Standard Input in the following format:

K X

Output

If the coins add up to X yen or more, print Yes; otherwise, print No.

Sample Input 1

2 900

Sample Output 1

Yes

Two 500-yen coins add up to 1000 yen, which is not less than X = 900 yen.

Sample Input 2

1 501

Sample Output 2

No

One 500-yen coin is worth 500 yen, which is less than X = 501 yen.

Sample Input 3

4 2000

Sample Output 3

Yes

Four 500-yen coins add up to 2000 yen, which is not less than X = 2000 yen.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define rep(i,n) for(ll i=0;i<n;++i)
#define P pair<ll,ll>
#define Graph vector<vector<P>>
#define fi first
#define se second
constexpr ll mod=1000000007;
constexpr ll INF=(1ll<<60);
constexpr double pi=3.14159265358979323846;
template<typename T> inline bool chmax(T& a,T b){if(a<b){a=b;return 1;} return 0;}
template<typename T> inline bool chmin(T& a,T b){if(a>b){a=b;return 1;} return 0;}

int main(){
    ll k,x;cin>>k>>x;
    if(500*k>=x) cout<<"Yes"<<endl;
    else cout<<"No"<<endl;
    
    return 0;
}