Problem:
Score : 300 points

Problem Statement

Given is a permutation P_1, \ldots, P_N of 1, \ldots, N.
Find the number of integers i (1 \leq i \leq N) that satisfy the following condition:

For any integer j (1 \leq j \leq i), P_i \leq P_j.

Constraints

1 \leq N \leq 2 \times 10^5

P_1, \ldots, P_N is a permutation of 1, \ldots, N.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
P_1 ... P_N

Output

Print the number of integers i that satisfy the condition.

Sample Input 1

5
4 2 5 1 3

Sample Output 1

3

i=1, 2, and 4 satisfy the condition, but i=3 does not - for example, P_i > P_j holds for j = 1.

Similarly, i=5 does not satisfy the condition, either. Thus, there are three integers that satisfy the condition.

Sample Input 2

4
4 3 2 1

Sample Output 2

4

All integers i (1 \leq i \leq N) satisfy the condition.

Sample Input 3

6
1 2 3 4 5 6

Sample Output 3

1

Only i=1 satisfies the condition.

Sample Input 4

8
5 7 4 2 6 8 1 3

Sample Output 4

4

Sample Input 5

1
1

Sample Output 5

1

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

//#include <bits/stdc++.h>
#include <iostream>
#include <vector>
#include <algorithm>

#include <climits>
#include <cmath>
#include <cstring>

#include <iomanip>

using namespace std;

#define FAST       			ios_base :: sync_with_stdio(false); cin.tie(NULL); 
#define endl "\n"

typedef long long int  ll;
typedef unsigned long long int ull;


int main()
{
	FAST;
	int arr[200001];
	int n;

	cin >> n;
	for(int i=0 ; i<n ; i++)
		cin >> arr[i];

	int maxx = arr[0];
	int count = 0;
	for(int i=0 ; i<n ; i++)
	{
		if(maxx >= arr[i])
			count++;
		maxx = min(maxx , arr[i]);
	}

	cout << count;
	return 0;
}