Problem:
Score : 300 points

Problem Statement

Fennec is fighting with N monsters.

The health of the i-th monster is H_i.

Fennec can do the following two actions:

Attack: Fennec chooses one monster. That monster's health will decrease by 1.

Special Move: Fennec chooses one monster. That monster's health will become 0.

There is no way other than Attack and Special Move to decrease the monsters' health.

Fennec wins when all the monsters' healths become 0 or below.

Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.

Constraints

1 \leq N \leq 2 \times 10^5

0 \leq K \leq 2 \times 10^5

1 \leq H_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
H_1 ... H_N

Output

Print the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning.

Sample Input 1

3 1
4 1 5

Sample Output 1

5

By using Special Move on the third monster, and doing Attack four times on the first monster and once on the second monster, Fennec can win with five Attacks.

Sample Input 2

8 9
7 9 3 2 3 8 4 6

Sample Output 2

0

She can use Special Move on all the monsters.

Sample Input 3

3 0
1000000000 1000000000 1000000000

Sample Output 3

3000000000

Watch out for overflow.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#define _USE_MATH_DEFINES

#include <iostream>
#include <cstdio>
#include <string>
#include <cstdlib>
#include <set>
#include <utility>
#include <vector>
#include <list>
#include <algorithm>
#include <regex>
#include <cmath>
#include <map>
#include <iterator>
#include <climits>
#include <numeric>
#include <bitset>
#include <unordered_map>
#include <unordered_set>
#include <iomanip>
#include <queue>
#include <deque>
#include <stack>
#include <array>
#include <valarray>
#include <complex>
#include <random>
#include <functional>
#include <cassert>
#include <chrono>
#include <memory>

using namespace std;

#define int long long
//region TEMPLATE
////@formatter:off
#define double long double
typedef long long ll;
typedef unsigned long long ull;
template<typename T>void __read(T &a) { cin >> a; }
template<typename T, typename ... Args> void __read(T &a, Args &... args) { cin >> a;__read(args...);}
#define make(t, ...) t __VA_ARGS__; __read(__VA_ARGS__)
#define makev(a, n) VI a(n); FOR(n) cin >> a[i];
#define ALL(x) (x).begin(), (x).end()
#define RALL(x) (x).rbegin(), (x).rend()
#define FORIT(p) for(auto it = p.begin(); it != p.end(); it++)
#define FOR(b) for(signed i = 0; i <(b); i++)
#define FORE(i, l, r) for(int i = (l); i < (r); i++)
#define NFOR(i, n) for(int i = (((int) n)-1); i >= 0; i--)
typedef vector<int> VI;
typedef vector<vector<int>> VVI;
typedef pair<int, int> PII;
typedef pair<pair<int, int>, int> PPII;
constexpr ll M7 = 1000000007ll;
constexpr ll M9 = 1000000009ll;
constexpr ll MFFT = 998244353ll;
template<class T> void outv(T &a) { for (auto &x : a) cout << x << ' '; }
static mt19937 rnd(static_cast<unsigned>(chrono::steady_clock::now().time_since_epoch().count())); // NOLINT(cert-err58-cpp)
////@formatter:on
//endregion


int32_t main() {
    ios_base::sync_with_stdio(false), cin.tie(nullptr);
    make(int, n, k);
    makev(a, n);
    sort(ALL(a));
    int sm = 0;
    for(int i = 0; i + k < n; ++i){
        sm += a[i];
    }
    cout << sm;

    return 0;
}