Problem:
Score : 200 points

Problem Statement

Takahashi loves palindromes. Non-palindromic strings are unacceptable to him. Each time he hugs a string, he can change one of its characters to any character of his choice.

Given is a string S. Find the minimum number of hugs needed to make S palindromic.

Constraints

S is a string consisting of lowercase English letters.

The length of S is between 1 and 100 (inclusive).

Input

Input is given from Standard Input in the following format:

S

Output

Print the minimum number of hugs needed to make S palindromic.

Sample Input 1

redcoder

Sample Output 1

1

For example, we can change the fourth character to o and get a palindrome redooder.

Sample Input 2

vvvvvv

Sample Output 2

0

We might need no hugs at all.

Sample Input 3

abcdabc

Sample Output 3

2

Solution in C++ (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;

//#define int long long
#define fi first
#define se second
#define rep(i, n) for (int i = 0; i < (int)(n); ++i)
#define rep1(i, n) for (int i = 1; i <= (int)(n); ++i)
#define rep11(i, n) for (int i = 1; i < (int)(n); ++i)
#define repo(i, o, n) for (int i = o; i < (int)(n); ++i)
#define repm(i, n) for (int i = (int)(n)-1; i >= 0; --i)
#define all(v) (v).begin(), (v).end()
#define rall(v) (v).rbegin(), (v).rend()
#define pb(n) push_back(n)
#define mp make_pair
#define MOD 1002000007
#define INF LONG_LONG_MAX

int main()
{
    string S;
    cin >> S;
    int co = 0;
    for (int i = 0; i < S.length(); i++){
        if (S[i] != S[S.length()-1-i]){
            S[S.length()-1-i]==S[i];
            co++;
        }
    }
    cout << co <<endl;
}