Problem:
Score : 200 points

Problem Statement

Let S(n) denote the sum of the digits in the decimal notation of n.
For example, S(101) = 1 + 0 + 1 = 2.

Given an integer N, determine if S(N) divides N.

Constraints

1 \leq N \leq 10^9

Input

Input is given from Standard Input in the following format:

N

Output

If S(N) divides N, print Yes; if it does not, print No.

Sample Input 1

12

Sample Output 1

Yes

In this input, N=12.
As S(12) = 1 + 2 = 3, S(N) divides N.

Sample Input 2

101

Sample Output 2

No

As S(101) = 1 + 0 + 1 = 2, S(N) does not divide N.

Sample Input 3

999999999

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;

#define lli long long int
#define REP(i,s,l) for(lli i=s;i<l;i++)
#define DEBUG 0
#define INF (1LL<<50)
#define MOD 1000000007

int main(){
    string n;
    cin >> n;
    int sum = 0;
    for(int i=0; i<n.length(); i++){
        sum = sum + (n[i]-'0');
    }
    if(stoi(n)%sum==0) cout << "Yes";
    else cout << "No";
    cout << endl;
    return 0;
}