Problem:
Score : 300 points

Problem Statement

There is a rectangle in a coordinate plane. The coordinates of the four vertices are (0,0), (W,0), (W,H), and (0,H).
You are given a point (x,y) which is within the rectangle or on its border. We will draw a straight line passing through (x,y) to cut the rectangle into two parts. Find the maximum possible area of the part whose area is not larger than that of the other. Additionally, determine if there are multiple ways to cut the rectangle and achieve that maximum.

Constraints

1 \leq W,H \leq 10^9

0\leq x\leq W

0\leq y\leq H

All values in input are integers.

Input

Input is given from Standard Input in the following format:

W H x y

Output

Print the maximum possible area of the part whose area is not larger than that of the other, followed by 1 if there are multiple ways to cut the rectangle and achieve that maximum, and 0 otherwise.

The area printed will be judged correct when its absolute or relative error is at most 10^{-9}.

Sample Input 1

2 3 1 2

Sample Output 1

3.000000 0

The line x=1 gives the optimal cut, and no other line does.

Sample Input 2

2 2 1 1

Sample Output 2

2.000000 1

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

/*
	Failure is not the reason for you to stop trying 
	   it is actually a remainder that you should 
			KEEP GOING 
*/
#include<bits/stdc++.h>
using namespace std;
#define int long long
#define IOS ios_base::sync_with_stdio(false);cin.tie(NULL);
#define pb push_back 
#define eb emplace_back
#define fn for(int i =0 ;i <n;i++)
#define fn1 for( int i =1;i<=n;i++)
#define fm for(int j =0 ;j <m;j++)
#define fm1 for(int j =1;j<=m;j++)
#define fi first
#define se second
#define E endl
#define MOD 1000000007
#define all(v) v.begin(),v.end()
#define rall(v) v.rbegin(),v.rend()
const int N = 1e6+5;
const int INF = 1e18L;
#define trace(...) __f(#__VA_ARGS__, __VA_ARGS__)
template <typename Arg1>
void __f(const char* name, Arg1&& arg1){
  cerr << name << ": " << arg1 << endl;
}
template <typename Arg1, typename... Args>
void __f(const char* names, Arg1&& arg1, Args&&... args){
  const char* comma = strchr(names + 1, ',');
  cerr.write(names, comma - names) << ": " << arg1 << " |";
  __f(comma + 1, args...);
}
double ar[N];
int dp[N];
signed main(){
	// #ifndef ONLINE_JUDGE
	// freopen("input.txt","r",stdin);
	// freopen("output.txt","w",stdout);
	// #endif
	IOS;
	int T=1;
	// cin >> T;
	while(T--){
		double h , w , x  ,y;
		cin >> h >> w >> x >> y;
		double tot = h*w;
		ar[0] = min(tot- abs(h-x)*w , abs(h-x)*w);
		ar[1]= min(tot-abs(w-y)*h,abs(w-y)*h);
		cout << setprecision(10) << fixed;
		if(ar[0]==ar[1]){
			cout << max(ar[0],ar[1]) <<" "<<1<<endl;
		}
		else{
			cout << max(ar[0],ar[1])<<" "<<0<<endl;
		}
	
	}
	
	cerr << "Time elapsed : " << 1.0 * clock() / CLOCKS_PER_SEC << " sec \n";
	return 0;
}