Problem:
Score : 200 points

Problem Statement

Find the number of palindromic numbers among the integers between A and B (inclusive).
Here, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.

Constraints

10000 \leq A \leq B \leq 99999

All input values are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the number of palindromic numbers among the integers between A and B (inclusive).

Sample Input 1

11009 11332

Sample Output 1

4

There are four integers that satisfy the conditions: 11011, 11111, 11211 and 11311.

Sample Input 2

31415 92653

Sample Output 2

612

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define sz(x) (int)(x).size()
#define F first
#define S second
#define forn(i, n) for (int i = 0; i < (int)n; i++)
#define pb push_back
#define fastIO ios::sync_with_stdio(0), cin.tie(0);
#define endl '\n'
typedef long long ll;
typedef long double ld;
typedef unsigned long long ull;
typedef pair<int, int> pii;
int main() {
#ifdef LOCAL
    // freopen("in.txt", "r", stdin);
    // freopen("out.txt", "w", stdout);
#else
    fastIO;
#endif
    int a, b;
    cin >> a >> b;
    int cnt = 0;
    for (int i = a; i <= b; i++) {
        string cur = to_string(i);
        bool ok = 1;
        forn(i, sz(cur) / 2) {
            if (cur[i] != cur[sz(cur) - i - 1]) {
                ok = 0;
                break;
            }
        }
        if (ok) cnt++;
    }
    cout << cnt << endl;
    return 0;
}