Problem:
Score : 200 points

Problem Statement

We have a long seat of width X centimeters.
There are many people who wants to sit here. A person sitting on the seat will always occupy an interval of length Y centimeters.

We would like to seat as many people as possible, but they are all very shy, and there must be a gap of length at least Z centimeters between two people, and between the end of the seat and a person.

At most how many people can sit on the seat?

Constraints

All input values are integers.

1 \leq X, Y, Z \leq 10^5

Y+2Z \leq X

Input

Input is given from Standard Input in the following format:

X Y Z

Output

Print the answer.

Sample Input 1

13 3 1

Sample Output 1

3

There is just enough room for three, as shown below:

Figure

Sample Input 2

12 3 1

Sample Output 2

2

Sample Input 3

100000 1 1

Sample Output 3

49999

Sample Input 4

64146 123 456

Sample Output 4

110

Sample Input 5

64145 123 456

Sample Output 5

109

Solution in C++ (Clang 3.8.0) (judge verdict: Wrong Answer)

#include <iostream>
#include <cstring>
#include <stdlib.h>
#include <vector>
#include <algorithm>
#include <cmath>
#include <stack>
#include <queue>
#include <math.h>

using namespace std;

int main()
{
    int x, y, z;
    cin >> x >> y >> z;
    int sum=z;
    int ans=0;
    while(sum+y+z<=x){
        ans++;
        sum=sum+y+z;
    }
    cout << sum << endl;
    cout << ans << endl;
    
    return 0;
}