Problem:
Score : 300 points

Problem Statement

Takahashi is organizing a party.

At the party, each guest will receive one or more snack pieces.

Takahashi predicts that the number of guests at this party will be A or B.

Find the minimum number of pieces that can be evenly distributed to the guests in both of the cases predicted.

We assume that a piece cannot be divided and distributed to multiple guests.

Constraints

1 \leq A, B \leq 10^5

A \neq B

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the minimum number of pieces that can be evenly distributed to the guests in both of the cases with A guests and B guests.

Sample Input 1

2 3

Sample Output 1

6

When we have six snack pieces, each guest can take three pieces if we have two guests, and each guest can take two if we have three guests.

Sample Input 2

123 456

Sample Output 2

18696

Sample Input 3

100000 99999

Sample Output 3

9999900000

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h> 
using namespace std;
typedef long long ll; const ll MM = 1000000000;ll mod = MM + 7;
#define rep(i, n) for(ll i=0; i<n; i++)
#define Rep(i, j, n) for(ll i=j; i<n; i++)
#define all(vec) vec.begin(), vec.end()
template<class T> inline bool chmin(T& a, T b) {if(a > b) {a = b; return true;} return false;}
template<class T> inline bool chmax(T& a, T b) {if(a < b) {a = b; return true;} return false;}
const ll INF = 1LL << 60;


ll GCD(ll x, ll y) {
    if (y == 0) return x;
    else return GCD(y, x % y);
}

ll LCM(ll x, ll y) {
    return x / GCD(x, y) * y;
}

int main() {
    int a, b; cin >> a >> b;
    cout << LCM(a, b) << endl;
}