Problem:
Score : 300 points

Problem Statement

Given is a permutation P_1, \ldots, P_N of 1, \ldots, N.
Find the number of integers i (1 \leq i \leq N) that satisfy the following condition:

For any integer j (1 \leq j \leq i), P_i \leq P_j.

Constraints

1 \leq N \leq 2 \times 10^5

P_1, \ldots, P_N is a permutation of 1, \ldots, N.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
P_1 ... P_N

Output

Print the number of integers i that satisfy the condition.

Sample Input 1

5
4 2 5 1 3

Sample Output 1

3

i=1, 2, and 4 satisfy the condition, but i=3 does not - for example, P_i > P_j holds for j = 1.

Similarly, i=5 does not satisfy the condition, either. Thus, there are three integers that satisfy the condition.

Sample Input 2

4
4 3 2 1

Sample Output 2

4

All integers i (1 \leq i \leq N) satisfy the condition.

Sample Input 3

6
1 2 3 4 5 6

Sample Output 3

1

Only i=1 satisfies the condition.

Sample Input 4

8
5 7 4 2 6 8 1 3

Sample Output 4

4

Sample Input 5

1
1

Sample Output 5

1

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

/*input
*/
#define debug 0
#include <bits/stdc++.h>
using namespace std;
typedef long long ll; typedef double db;
const int N = 1e7 + 5, M = 1e9 + 7; const db eps = 1e-8;
typedef vector<ll> vi; typedef vector<vi> vii;
void solve();
void print(){cout<<'\n';}template<class T,class ...U>void print(T x, U ...y){cout<<x<<' ';print(y...);}
int main() {
  ios::sync_with_stdio(0); cin.tie(0);
  cout << setprecision(2) << fixed;
  if(debug){freopen("main.cpp","r",stdin);string x;cin>>x;}
  solve();
}
//

void solve() {
  int n, x, mi = 1e9; cin >> n;
  int ans = 0;
  while (n--) {
    cin >> x;
    if (x < mi) ans++;
    mi = min(x, mi);
  }
  cout << ans;
}