Problem:
Score : 300 points

Problem Statement

You are given three integers A, B and C. Find the minimum number of operations required to make A, B and C all equal by repeatedly performing the following two kinds of operations in any order:

Choose two among A, B and C, then increase both by 1.

Choose one among A, B and C, then increase it by 2.

It can be proved that we can always make A, B and C all equal by repeatedly performing these operations.

Constraints

0 \leq A,B,C \leq 50

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B C

Output

Print the minimum number of operations required to make A, B and C all equal.

Sample Input 1

2 5 4

Sample Output 1

2

We can make A, B and C all equal by the following operations:

Increase A and C by 1. Now, A, B, C are 3, 5, 5, respectively.

Increase A by 2. Now, A, B, C are 5, 5, 5, respectively.

Sample Input 2

2 6 3

Sample Output 2

5

Sample Input 3

31 41 5

Sample Output 3

23

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;

int main() {
    int A, B, C; 
    cin >> A >> B >> C; 
    int M = max((A, B), C); 
  if(A % 2 == B % 2 && B % 2 == C % 2)
    cout << (M * 3 - A - B - C)/ 2 << endl;
  else if(A % 2 == 1 && B % 2 == 0 && C % 2 == 0)
    {int M = max((A, B+1), C+1); 
    cout << (M * 3 - A - B - C)/ 2 << endl;
  }
  else if(A % 2 == 0 && B % 2 == 1 && C % 2 == 0)
    {int M = max((A+1, B), C+1); 
    cout << (M * 3 - A - B - C)/ 2 << endl;
  }
  else if(A % 2 == 0 && B % 2 == 0 && C % 2 == 1)
    {int M = max((A+1, B+1), C); 
    cout << (M * 3 - A - B - C)/ 2 << endl;
  }
  else if(A % 2 == 1 && B % 2 == 1 && C % 2 == 0)
    {int M = max((A+1, B+1), C); 
    cout << (M * 3 - A - B - C)/ 2 << endl;
  }
  else if(A % 2 == 1 && B % 2 == 0 && C % 2 == 1)
    {int M = max((A+1, B), C+1); 
    cout << (M * 3 - A - B - C)/ 2 << endl;
  }
  else if(A % 2 == 0 && B % 2 == 1 && C % 2 == 1)
    {int M = max((A, B+1), C+1); 
    cout << (M * 3 - A - B - C)/ 2 << endl;
  }
}