Problem:
Score : 500 points

Problem Statement

There are N points on the 2D plane, i-th of which is located on (x_i, y_i).
There can be multiple points that share the same coordinate.
What is the maximum possible Manhattan distance between two distinct points?

Here, the Manhattan distance between two points (x_i, y_i) and (x_j, y_j) is defined by |x_i-x_j| + |y_i-y_j|.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq x_i,y_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
x_1 y_1
x_2 y_2
:
x_N y_N

Output

Print the answer.

Sample Input 1

3
1 1
2 4
3 2

Sample Output 1

4

The Manhattan distance between the first point and the second point is |1-2|+|1-4|=4, which is maximum possible.

Sample Input 2

2
1 1
1 1

Sample Output 2

0

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;


int main() {

  ios::sync_with_stdio(false);
  cin.tie(0);
  int n;
  cin >> n;
  vector<int> x(n);
  vector<int> y(n);
  for(int i=0;i<n;i++) cin >> x[i] >> y[i];
  vector<int> xpy(n);
  vector<int> xmy(n);
  for(int i=0;i<n;i++) {
    xpy[i] = x[i] + y[i];
    xmy[i] = x[i] - y[i];
  }
  sort(xpy.begin(),xpy.end());
  sort(xmy.begin(),xmy.end());
  cout << max(xpy[n-1]-xpy[0],xmy[n-1]-xmy[0]) << endl;

}