Problem:
Score : 200 points

Problem Statement

Raccoon is fighting with a monster.

The health of the monster is H.

Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i.
There is no other way to decrease the monster's health.

Raccoon wins when the monster's health becomes 0 or below.

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Constraints

1 \leq H \leq 10^9

1 \leq N \leq 10^5

1 \leq A_i \leq 10^4

All values in input are integers.

Input

Input is given from Standard Input in the following format:

H N
A_1 A_2 ... A_N

Output

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Sample Input 1

10 3
4 5 6

Sample Output 1

Yes

The monster's health will become 0 or below after, for example, using the second and third moves.

Sample Input 2

20 3
4 5 6

Sample Output 2

No

Sample Input 3

210 5
31 41 59 26 53

Sample Output 3

Yes

Sample Input 4

211 5
31 41 59 26 53

Sample Output 4

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;
//define
typedef pair<int,int>pi;
#define int long long
#define elif else if
#define rep(x,y) for(int i=x;i<y;i++)
#define REP(x,y) for(int j=x;j<y;j++)
#define Rep(x,y) for(int k=x;k<y;k++)
#define all(x) x.begin(),x.end()
#define pb push_back
#define vint vector<int>
#define vvint vector<vector<int>>
#define vtr vector<string>
#define vvtr vector<vector<string>>
#define vhar vector<char>
#define vvhar vector<vector<char>>
#define mod 100000007
#define elif else if
#define str string
int digitsum(int a){
  int b=0;
  while(a){
    b+=a%10;
    a/=10;
  }
  return b;
}
signed main(){
  int N,M,O,P=0,c=0,co=0,cou=0,minN=mod;
  double D,Do;
  char C,Ca;
  str S,T;
  cin>>N>>M;
  vint A(M);
  rep(0,M){
    cin>>A[i];
    c+=A[i];
  }
  c>=N?cout<<"Yes"<<endl:cout<<"No"<<endl;
}