Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include<bits/stdc++.h>
using namespace std;
int n,m,ans;
int a,b,c,ab,ac,bc;
vector<int>vab,vac,vbc;
char sol[100005];
string st[100005];
int main()
{
    scanf("%d %d %d %d",&n,&a,&b,&c);
    int ta=a,tb=b,tc=c;
    for(int i=1;i<=n;i++)
    {
        string s;
        cin>>s;
        st[i]=s;
        if(s=="AB")ab++,vab.push_back(i);
        if(s=="AC")ac++,vac.push_back(i);
        if(s=="BC")bc++,vbc.push_back(i);
    }
    ab%=2,ac%=2,bc%=2;
    for(int i=0;i<vab.size()-ab;i++)
    {
        if(i%2)sol[vab[i]]='A';
        else sol[vab[i]]='B';
    }
    for(int i=0;i<vac.size()-ac;i++)
    {
        if(i%2)sol[vac[i]]='A';
        else sol[vac[i]]='C';
    }
    for(int i=0;i<vbc.size()-bc;i++)
    {
        if(i%2)sol[vbc[i]]='B';
        else sol[vbc[i]]='C';
    }
    for(int i=0;i<2;i++)
    {
        if(ab)
        {
            if(i)a--,b++,sol[vab.back()]='B';
            else a++,b--,sol[vab.back()]='A';
        }
        for(int i1=0;i1<2;i1++)
        {
            if(ac)
            {
                if(i1)a--,c++,sol[vac.back()]='C';
                else a++,c--,sol[vac.back()]='A';
            }
            for(int i2=0;i2<2;i2++)
            {
                if(bc)
                {
                    if(i2)b--,c++,sol[vbc.back()]='C';
                    else b++,c--,sol[vbc.back()]='B';
                }
                if(a>=0&&b>=0&&c>=0)
                {
                    printf("Yes\n");
                    for(int i=1;i<=n;i++)
                    {
                        printf("%c\n",sol[i]);
                        if(st[i]=="AB")
                        {
                            if(sol[i]=='A')ta++,tb--;
                            else if(sol[i]=='B')ta--,tb++;
                            else assert(0);
                        }
                        if(st[i]=="AC")
                        {
                            if(sol[i]=='A')ta++,tc--;
                            else if(sol[i]=='C')ta--,tc++;
                            else assert(0);
                        }
                        if(st[i]=="BC")
                        {
                            if(sol[i]=='B')tb++,tc--;
                            else if(sol[i]=='C') tb--,tc++;
                            else assert(0);
                        }
                    }
                    assert(ta>=0&&tb>=0&&tc>=0);
                    return 0;
                }
                if(bc)
                {
                    if(i2)b++,c--;
                    else b--,c++;
                }
            }
            if(ac)
            {
                if(i1)a++,c--;
                else a--,c++;
            }
        }
        if(ab)
        {
            if(i)a++,b--;
            else a--,b++;
        }
    }
    printf("No\n");
    return 0;
}