Problem:
Score : 200 points

Problem Statement

An integer X is called a Harshad number if X is divisible by f(X), where f(X) is the sum of the digits in X when written in base 10.

Given an integer N, determine whether it is a Harshad number.

Constraints

1?N?10^8

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

Print Yes if N is a Harshad number; print No otherwise.

Sample Input 1

12

Sample Output 1

Yes

f(12)=1+2=3. Since 12 is divisible by 3, 12 is a Harshad number.

Sample Input 2

57

Sample Output 2

No

f(57)=5+7=12. Since 57 is not divisible by 12, 12 is not a Harshad number.

Sample Input 3

148

Sample Output 3

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

//  main.cpp
//  CppTest

#include <iostream>
#include <fstream>
#include <vector>
#include <algorithm>
using namespace std;

int main(int argc, const char * argv[]) {
   
    
    // cinを高速にするためのおまじない
    cin.tie(0);
    ios::sync_with_stdio(false);
    
    /////////////////////
    // Write code below /
    /////////////////////
    int N;
    cin >> N;
    int s=N%10;
    for(int i=1;i<9;i++){
        int n=1;
        for(int j=0;j<i;j++){
            n*=10;
        }
        s+=N%(n*10)/n;
    }
    if(N%s==0){
        cout<<"Yes"<<endl;
    }
    else{
        cout<<"No"<<endl;
    }

    
    
    return 0;
}