Problem:
Score : 200 points

Problem Statement

An integer N is a multiple of 9 if and only if the sum of the digits in the decimal representation of N is a multiple of 9.

Determine whether N is a multiple of 9.

Constraints

0 \leq N < 10^{200000}

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a multiple of 9, print Yes; otherwise, print No.

Sample Input 1

123456789

Sample Output 1

Yes

The sum of these digits is 1+2+3+4+5+6+7+8+9=45, which is a multiple of 9, so 123456789 is a multiple of 9.

Sample Input 2

0

Sample Output 2

Yes

Sample Input 3

31415926535897932384626433832795028841971693993751058209749445923078164062862089986280

Sample Output 3

No

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

# include <bits/stdc++.h>
# define sz(x) (int)((x).size())
# define F first
# define S second
# define pb push_back
# define ub upper_bound
# define lb lower_bound
# define end(x) prev(x.end());
# define all(x) x.begin(), x.end()
# define rall(x) x.rbegin(), x.rend()
# define pqueue priority_queue
# define mset multiset
# define umap unordered_map
# define Speed() ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0)
# define rep(i,n) for(int i=0;i<n;++i)
# define forn(i,n) for(int i=1;i<=n;++i)
# define lr(i,l,r) for(int i=l;(l>r?i>=r:i<=r);(l>r?--i:++i))

using namespace std;

typedef long long ll;
typedef pair<int, int> pii;

const int MOD = 1e9+7;
const int N = 2e5+5;

void solve(){
	string s;
	cin>>s;
	ll sum=0;
	rep(i,sz(s)){
		sum+=(int)(s[i]-'0');
	}
	if(sum%9==0)cout<<"Yes";
	else cout<<"No";
}

int main(){
	Speed();
	int T=1; 
	//cin>>T;	
	while(T--)
		solve();
	return 0;
}