Problem:
Score : 200 points

Problem Statement

Find the number of palindromic numbers among the integers between A and B (inclusive).
Here, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.

Constraints

10000 \leq A \leq B \leq 99999

All input values are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the number of palindromic numbers among the integers between A and B (inclusive).

Sample Input 1

11009 11332

Sample Output 1

4

There are four integers that satisfy the conditions: 11011, 11111, 11211 and 11311.

Sample Input 2

31415 92653

Sample Output 2

612

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<cstdlib>
#include<iostream>
#include<algorithm>
#include<vector>
#include<stack>
#include<queue>
#include<string>
#include<cstring>
using namespace std;
typedef long long lng;
typedef unsigned long long ulng;

#define pb push_back
#define SZ(a) int((a).size())
#define ALL(aA) (a).begin(), (a).end()
#define FOR(i,a,b) for(int i=(a); i<=(b); ++i)
#define FORD(i,b,a) for(int i=(b); i>=(a); --i)
#define REP(i,n) FOR(i,0,n-1)
#define UNIQUE(a) a.erase(unique(ALL(a)), a.end())

lng power(lng b, lng e) {lng sol=1; while(e>0) {if(e&1) {sol=sol*b;} e>>=1; b*= b;} return sol;}

int main() {
    cin.tie(0);
    ios::sync_with_stdio(false);

    int a, b;
    cin >> a >> b;

    int ans = 0;
    FOR(i, a, b) {
        int ni = i;
        int num = 10000;
        if(ni%10 == ni/num) {
            ni -= num * (ni/num);
            ni /= 10;
            num /= 100;
            if(ni%10 == ni/num) ans++;
        }
    }

    cout << ans << endl;
}