Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

/* ***********************************************
Author        :yang12138
Created Time  :2018年08月18日 星期六 20时15分29秒
File Name     :B.cpp
************************************************ */
#include <iostream>
#include <stdio.h>
#include <cstring>
#include <algorithm>
#include <string>
#include <math.h>
#include <cstdlib>
#include <vector>
#include <queue>
#include <set>
#include <map>
using namespace std;
#define mem(a,b) memset(a,b,sizeof(a))
typedef long long ll;
typedef pair<int,int>pii;
#define lson (root<<1)
#define rson (root<<1|1)



int main(){
    //freopen("in.txt","r",stdin);
    //freopen("out.txt","w",stdout);
    
	int n;
	scanf("%d",&n);
	int ans=0;
	for(int i=1;i<=n;i+=2){
		int cnt=0;
		for(int j=1;j<=i;j++) cnt+=(i%j==0);
		if(cnt==8) ans++;
	}

	cout<<ans<<endl;
    return 0;
}