Problem:
Score : 200 points

Problem Statement

We have A cards, each of which has an integer 1 written on it. Similarly, we also have B cards with 0s and C cards with -1s.

We will pick up K among these cards. What is the maximum possible sum of the numbers written on the cards chosen?

Constraints

All values in input are integers.

0 \leq A, B, C

1 \leq K \leq A + B + C \leq 2 \times 10^9

Input

Input is given from Standard Input in the following format:

A B C K

Output

Print the maximum possible sum of the numbers written on the cards chosen.

Sample Input 1

2 1 1 3

Sample Output 1

2

Consider picking up two cards with 1s and one card with a 0.
In this case, the sum of the numbers written on the cards is 2, which is the maximum possible value.

Sample Input 2

1 2 3 4

Sample Output 2

0

Sample Input 3

2000000000 0 0 2000000000

Sample Output 3

2000000000

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#include <iostream>
#include <queue>
#include <stack>
#include <vector>
#include <string>
#include <set>
#include <map>
#include <random>
#define rep(i,n) for (int i = 0; i < (n); ++i)
#define repp(i,n,m) for (int i = m; i < (n); ++i)
#define repl(i,n) for (long long i = 0; i < (n); ++i)
#define reppl(i,n,m) for (long long i = m; i < (n); ++i)
using namespace std;
using ll = long long;
using ld = long double;
using P = pair<int, int>;
using PL = pair<long long, long long>;
using Pxy = pair<long double, long double>;
using T = tuple<int, int, bool>;
const int INF = 1001001007;
const int MOD = 1000000007;
const ll inf = 1e18;
template <typename AT>
void printvec(vector<AT> &ar){
    rep(i,ar.size()-1) cout << ar[i] << " ";
    cout << ar[ar.size()-1] << endl;
}
template <typename Q>
void printvvec(vector<vector<Q>> &ar){
    rep(i,ar.size()){
        rep(j,ar[0].size()-1) cout << ar[i][j] << " ";
        cout << ar[i][ar[0].size()-1] << endl;
    }
}
template <typename S>
bool range(S a, S b, S x){
    return (a <= x && x < b);
}

int main() {
    int a, b, c, k; cin >> a >> b >> c >> k;
    if (a >= k) cout << k << endl;
    else if (a + b >= k){
        cout << a << endl;
    }
    else cout << a - (k-a-b) << endl;
}