Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<bits/stdc++.h>
using namespace std;
 
void __print(int x) {cerr << x;}
void __print(long x) {cerr << x;}
void __print(long long x) {cerr << x;}
void __print(unsigned x) {cerr << x;}
void __print(unsigned long x) {cerr << x;}
void __print(unsigned long long x) {cerr << x;}
void __print(float x) {cerr << x;}
void __print(double x) {cerr << x;}
void __print(long double x) {cerr << x;}
void __print(char x) {cerr << '\'' << x << '\'';}
void __print(const char *x) {cerr << '\"' << x << '\"';}
void __print(const string &x) {cerr << '\"' << x << '\"';}
void __print(bool x) {cerr << (x ? "true" : "false");}

template<typename T, typename V>
void __print(const pair<T, V> &x) {cerr << '{'; __print(x.first); cerr << ','; __print(x.second); cerr << '}';}
template<typename T>
void __print(const T &x) {int f = 0; cerr << '{'; for (auto &i: x) cerr << (f++ ? "," : ""), __print(i); cerr << "}";}
void _print() {cerr << "]\n";}
template <typename T, typename... V>
void _print(T t, V... v) {__print(t); if (sizeof...(v)) cerr << ", "; _print(v...);}
#ifndef ONLINE_JUDGE
#define debug(x...) cerr << "[" << #x << "] = ["; _print(x)
#else
#define debug(x...)
#endif
 
#define fi first
#define se second
#define FIO {ios::sync_with_stdio(0);cin.tie(nullptr);cout.tie(nullptr);}
#define pb push_back
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define forn(i, n) for (int i = 0; i < (int)(n); ++i)
#define for1(i, n) for (int i = 1; i <= (int)(n); ++i)
#define ford(i, n) for (int i = (int)(n) - 1; i >= 0; --i)
 
typedef pair<int, int> pii;
typedef vector<int> vi;
typedef vector<pii> vpi;
typedef vector<vi> vvi;
typedef long long ll;
typedef vector<ll> vll;
typedef vector<vll> vvll;
typedef long double ld;

int main(){
  FIO
  int a[3][3];
  for(int i=0;i<3;i++)
  {
    for(int j=0;j<3;j++)
    {
    cin>>a[i][j];
    }
  }
   int n;
   cin>>n;
   map<int,int> m;
   int h;
    for(int i=0;i<n;i++)
   {
    cin>>h;
    m[h]=i;
    }
    for(int i=0;i<3;i++)
    {
      int fl=1;
      for(int j=0;j<3;j++)
      {
        if(m.find(a[i][j])!=m.end())fl*=1;
        else fl*=0;
      }
      if(fl){cout<<"Yes";return 0;}
    }int i,j;
    for(i=0;i<3;i++)
    {
      int fl=1;
      for(j=0;j<3;j++)
      {
        if(m.find(a[j][i])!=m.end())fl*=1;
        else fl*=0;
      }
      if(fl){cout<<"Yes";return 0;}
    }
    int fl=1;
    if(m.find(a[0][0])!=m.end())fl*=1;
    else fl*=0;
    if(m.find(a[1][1])!=m.end())fl*=1;
    else fl*=0;
    if(m.find(a[2][2])!=m.end())fl*=1;
    else fl*=0;
     fl=1;
    if(m.find(a[0][2])!=m.end())fl*=1;
    else fl*=0;
    if(m.find(a[1][1])!=m.end())fl*=1;
    else fl*=0;
    if(m.find(a[2][0])!=m.end())fl*=1;
    else fl*=0;

    if(fl){cout<<"Yes";return 0;}
    cout<<"No";
  return 0;
}