Problem:
Problem Statement

You are given two integers a and b (a≤b). Determine if the product of the integers a, a+1, …, b is positive, negative or zero.

Constraints

a and b are integers.

-10^9≤a≤b≤10^9

Partial Score

In test cases worth 100 points, -10≤a≤b≤10.

Input

The input is given from Standard Input in the following format:

a b

Output

If the product is positive, print Positive. If it is negative, print Negative. If it is zero, print Zero.

Sample Input 1

1 3

Sample Output 1

Positive

1×2×3=6 is positive.

Sample Input 2

-3 -1

Sample Output 2

Negative

(-3)×(-2)×(-1)=-6 is negative.

Sample Input 3

-1 1

Sample Output 3

Zero

(-1)×0×1=0.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#include <set>
#define REP(i, n) for(int i = 0;i < n;i++)
#define REPR(i, n) for(int i = n;i >= 0;i--)
#define FOR(i, m, n) for(int i = m;i < n;i++)
#define FORR(i, m, n) for(int i = m;i >= n;i--)
#define SORT(v, n) sort(v, v+n);
#define VSORT(v) sort(v.begin(), v.end());
#define llong long long
#define pb(a) push_back(a)

#define INF 100000000
#define MOD 100000007

#define writeln(n) cout<<n<<endl

using namespace std;
typedef pair<int, int> P;
typedef pair<llong, llong> LP;
typedef pair<int, P> PP;
typedef pair<llong, LP> LPP;
//vector<tuple<long long, long long, long long>>vec;

template<class T>
inline bool chmax(T &a, T b) {
    if (a < b) {
        a = b;
        return true;
    }
    return false;
}

template<class T>
inline bool chmin(T &a, T b) {
    if (a > b) {
        a = b;
        return true;
    }
    return false;
}

llong pownew(llong m, llong n) {
    if (n == 0) { return 1; }
    if (n % 2 == 0) { return pow(m*m, n/2); }
    return pow(m, n-1) * m;
}

bool isprime(int p) {
    if (p == 1) return false;
    for (int i = 2; i < p; i++) {
        if (p%i == 0) return false;
    }
    return true;
}

int dx[4] = {1, 0, -1, 0};
int dy[4] = {0, 1, 0, -1};

const int inf=100000000;

long long modpow(long long a, long long n, long long mod) //a^n
{
    long long res = 1;
    while (n > 0) {
        if (n & 1) res = res * a % mod;
        a = a * a % mod;
        n >>= 1;
    }
    return res;
}

llong gcd(llong a, llong b) {
    return b != 0 ? gcd(b, a % b) : a;
}
//setprecision(10);



int main() {
    ios::sync_with_stdio(false);
    cin.tie(0);
    llong a,b; cin>>a>>b;
    string ans="Positive";
    if(a<0&&b>0) ans="Zero";
    else if(a>0) ans="Positive";
    else if(a<0&&b>0){
        if((0-a)%2!=0) ans="Negative";
        }
    else
        {
        if((b-a)%2==0) ans="Negative";
        }
    cout<<ans<<endl;
    return  0;
}