Problem:
Score : 300 points

Problem Statement

There are N people living on a number line.

The i-th person lives at coordinate X_i.

You are going to hold a meeting that all N people have to attend.

The meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.

Find the minimum total points of stamina the N people have to spend.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq X_i \leq 100

Input

Input is given from Standard Input in the following format:

N
X_1 X_2 ... X_N

Output

Print the minimum total stamina the N people have to spend.

Sample Input 1

2
1 4

Sample Output 1

5

Assume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.

Note that you can hold the meeting only at an integer coordinate.

Sample Input 2

7
14 14 2 13 56 2 37

Sample Output 2

2354

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

/************************************/
/* NoobM							*/
/* File Name : chaa.cpp				*/
/* Date : 13.07.2020 02:37:00 +06	*/
/************************************/

#include <bits/stdc++.h>

#define rr(i, b)    for (int i = 0; i < int(b); i++)
#define vi(n, a) vector <int> a(n); rr(i, n) cin >> a[i]
#define pvec(a) rr(i, a.size()) cout << a[i] << " "; cout << endl
#define bug(x) cout << #x << " " << x << endl
#define ll long long
#define vii vector <int>

using namespace std;

void solve() {
	int n;
	cin >> n;
	
	vi(n, a);
	
	sort(a.begin(), a.end());
	
	int mid = (a[n - 1] - a[0])/2;
	
	ll dist = 0;
	
	for(int x : a) {
		dist += pow((mid - x), 2);
	}
	
	cout << dist << endl;
}
 
int main(){
    cin.tie(0);
    ios_base::sync_with_stdio(false);
	
	int t = 1;
	//cin >> t;
	
	while (t--) {
		solve();
	}
    return 0;
}