Problem:
Score : 500 points

Problem Statement

Given are two strings s and t consisting of lowercase English letters. Determine if there exists an integer i satisfying the following condition, and find the minimum such i if it exists.

Let s' be the concatenation of 10^{100} copies of s. t is a subsequence of the string {s'}_1{s'}_2\ldots{s'}_i (the first i characters in s').

Notes

A subsequence of a string a is a string obtained by deleting zero or more characters from a and concatenating the remaining characters without changing the relative order. For example, the subsequences of contest include net, c, and contest.

Constraints

1 \leq |s| \leq 10^5

1 \leq |t| \leq 10^5

s and t consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s
t

Output

If there exists an integer i satisfying the following condition, print the minimum such i; otherwise, print -1.

Sample Input 1

contest
son

Sample Output 1

10

t = son is a subsequence of the string contestcon (the first 10 characters in s' = contestcontestcontest...), so i = 10 satisfies the condition.

On the other hand, t is not a subsequence of the string contestco (the first 9 characters in s'), so i = 9 does not satisfy the condition.

Similarly, any integer less than 9 does not satisfy the condition, either. Thus, the minimum integer i satisfying the condition is 10.

Sample Input 2

contest
programming

Sample Output 2

-1

t = programming is not a substring of s' = contestcontestcontest.... Thus, there is no integer i satisfying the condition.

Sample Input 3

contest
sentence

Sample Output 3

33

Note that the answer may not fit into a 32-bit integer type, though we cannot put such a case here.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;
#define _GLIBCXX_DEBUG //これつけるとA[N]でもいいらしい
//for文のマクロ
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define big 1000000007
#define all(a) sort((a).begin(),(a).end()) //ソートのマクロ
#define Re(a) reverse((a).begin(),(a).end())
#define YN(a) if(a){cout<<"Yes"<<endl;}else cout<<"No"<<endl;//条件によってYes、Noを出力する


int main(){
    string s,t;
    cin>>s;
    cin>>t;
    set<char> S,T;
    int sn = s.length();
    int tn = t.length();
    vector<int> appear(tn);
    rep(i,sn){
        S.insert(s[i]);
    }
    rep(i,tn){
        T.insert(t[i]);
    }
    int64_t ans=0;
    for(auto c:T){
        if(!S.count(c)){
            //ans=-1;
            cout<<-1<<endl;
            return 0;
        }
    }
    
    cout<<ans<<endl;
}