Problem:
Score : 200 points

Problem Statement

Takahashi is standing on a two-dimensional plane, facing north. Find the minimum positive integer K such that Takahashi will be at the starting position again after he does the following action K times:

Go one meter in the direction he is facing. Then, turn X degrees counter-clockwise.

Constraints

1 \leq X \leq 179

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print the number of times Takahashi will do the action before he is at the starting position again.

Sample Input 1

90

Sample Output 1

4

Takahashi's path is a square.

Sample Input 2

1

Sample Output 2

360

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)


///-----Bismillahir Rahmanir Rahim-----///

#include<bits/stdc++.h>
using namespace std;

///---FAST I/O---///
#define Boost() ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);

///---DATA TYPE---///
typedef long long ll;
typedef long long int lli;
///vector
typedef vector<int> vi;
typedef vector<ll> vl;
///pair
typedef pair<int,int> pii;
typedef pair<double, double> pdd;
typedef pair<ll, ll> pll;

///---LOOP---///
#define rep0(i,n) for(i=0;i<n;i++)
#define rep1(i,n) for(i=1;i<=n;i++)

///---I/O---///
#define sf scanf
#define pf printf

///---OTHERS---///
#define pb push_back
#define all(c)		c.begin(),c.end()
#define MK make_pair
#define F first
#define S second
#define endl '\n'


///---INITIALIZATION---//
#define mem(a,b) memset(a, b, sizeof(a) )

///---CALCULATE---///
#define gcd(a,b) __gcd(a,b)
#define lcm(a,b) (a*(b/gcd(a,b)))
#define sqr(a) ((a) * (a))

///---BIT OPERATION---///
inline bool checkBit(ll n, int i) { return n&(1LL<<i); }
inline ll setBit(ll n, int i) { return n|(1LL<<i);; }
inline ll resetBit(ll n, int i) { return n&(~(1LL<<i)); }

///---CONSTANT---///
const double PI = acos(-1);
const double eps = 1e-9;
const int inf = 2000000000;
const ll infLL = 9000000000000000000;
#define MOD 1000000007

int main()
{
    Boost();

    int t;
    t=1;
    //cin>>t;
    while(t--)
    {
        int x;
        cin>>x;
        cout<<2*ceil(180.0/(double)x)<<endl;
    }
    return 0;
}