Problem:
Score : 100 points

Problem Statement

We have A balls with the string S written on each of them and B balls with the string T written on each of them.

From these balls, Takahashi chooses one with the string U written on it and throws it away.

Find the number of balls with the string S and balls with the string T that we have now.

Constraints

S, T, and U are strings consisting of lowercase English letters.

The lengths of S and T are each between 1 and 10 (inclusive).

S \not= T

S=U or T=U.

1 \leq A,B \leq 10

A and B are integers.

Input

Input is given from Standard Input in the following format:

S T
A B
U

Output

Print the answer, with space in between.

Sample Input 1

red blue
3 4
red

Sample Output 1

2 4

Takahashi chose a ball with red written on it and threw it away.
Now we have two balls with the string S and four balls with the string T.

Sample Input 2

red blue
5 5
blue

Sample Output 2

5 4

Takahashi chose a ball with blue written on it and threw it away.
Now we have five balls with the string S and four balls with the string T.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <set>
#include <queue>
#include <vector>
#include <algorithm>
#include <cmath>
#include <string>
#include <cstring>
#include <climits>
#include <sstream>
#include <iomanip>
#include <map>
#include <stack>
#include <numeric>

using namespace std;

/*-----------------------------------------------------------------------------
　定義
 -------------------------------------------------------------------------------*/
#define ALL(x)					(x).begin(),(x).end()
#define REP(i, n)				for (int (i) = 0 ; (i) < (ll)(n) ; ++(i))
#define REPN(i, m, n)			for (int (i) = m ; (i) < (ll)(n) ; ++(i))
#define INF						(int)2e9
#define MOD						(1000 * 1000 * 1000 + 7)
#define Ceil(x, n)				(((((x))+((n)-1))/n))		/* Nの倍数に切り上げ割り算 */
#define CeilN(x, n)				(((((x))+((n)-1))/n)*n)		/* Nの倍数に切り上げ */
#define FloorN(x, n)			((x)-(x)%(n))				/* Nの倍数に切り下げ */
#define IsOdd(x)				(((x)&0x01UL) == 0x01UL)			
#define IsEven(x)				(!IsOdd((x)))						
#define M_PI					3.14159265358979323846
typedef long long				ll;
typedef pair<ll, ll>			P;

/*-----------------------------------------------------------------------------
　処理
 -------------------------------------------------------------------------------*/
int main()
{
	string S, T, U;
    int A, B;
	cin >> S >> T >> A >> B >> U;

	if (S == U) {
		A--;
	} else {
		B--;
	}

    cout << A << " " <<B <<  endl;
    return 0;
}