Problem:
Score : 100 points

Problem Statement

There are N items, numbered 1, 2, \ldots, N.
For each i (1 \leq i \leq N), Item i has a weight of w_i and a value of v_i.

Taro has decided to choose some of the N items and carry them home in a knapsack.
The capacity of the knapsack is W, which means that the sum of the weights of items taken must be at most W.

Find the maximum possible sum of the values of items that Taro takes home.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq W \leq 10^9

1 \leq w_i \leq W

1 \leq v_i \leq 10^3

Input

Input is given from Standard Input in the following format:

N W
w_1 v_1
w_2 v_2
:
w_N v_N

Output

Print the maximum possible sum of the values of items that Taro takes home.

Sample Input 1

3 8
3 30
4 50
5 60

Sample Output 1

90

Items 1 and 3 should be taken.
Then, the sum of the weights is 3 + 5 = 8, and the sum of the values is 30 + 60 = 90.

Sample Input 2

1 1000000000
1000000000 10

Sample Output 2

10

Sample Input 3

6 15
6 5
5 6
6 4
6 6
3 5
7 2

Sample Output 3

17

Items 2, 4 and 5 should be taken.
Then, the sum of the weights is 5 + 6 + 3 = 14, and the sum of the values is 6 + 6 + 5 = 17.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)


//please refer from line no. 207
/////*31022618*/////
//_MONU KUMAR
#include <bits/stdc++.h>
using namespace std;
#define fast ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);
#define tc ll t=1; cin>>t; while(t--)
#define ll long long int
#define ld long double
#define ull unsigned long long
#define p1(x) cout <<x<<"\n";
#define p2(x,y) cout <<x<<" "<<y<<"\n";
#define p3(x,y,z) cout <<x<<" "<<y<<" "<<z<<"\n";
#define p4(x,y,z,w) cout <<x<<" "<<y<<" "<<z<<" "<<w<<"\n";
#define trace(x) cout<<#x<<": "<<x<<" "<<"\n";
#define trace2(x,y) cout<<#x<<": "<<x<<" | "<<#y<<": "<<y<<"\n";
#define trace3(x,y,z) cout<<#x<<":" <<x<<" | "<<#y<<": "<<y<<" | "<<#z<<": "<<z<<"\n";
#define trace4(a,b,c,d) cout<<#a<<": "<<a<<" | "<<#b<<": "<<b<<" | "<<#c<<": "<<c<<" | "<<#d<<": "<<d<<"\n";
#define nL cout<<"\n";
#define lp(i,l,r) for (long long int i = l; i < r; i++)
#define lpr(i,r,l) for (long long int i = r-1; i >=l ; i--)
#define mem(a,x) memset(a,x,sizeof(a))              //set elements of array to some value
#define pi 3.1415926535897932384626
#define mod 1000000007
#define big 1e18
#define small -big
#define mp(a, b) make_pair(a, b)
#define pb(x) push_back(x)
#define ff first
#define ss second
#define siz 256
#define leadzero(a) __builtin_clz(a)        // count leading zeroes
#define trailzero(a) __builtin_ctz(a)       // count trailing zeroes
#define bitcount(a) __builtin_popcount(a)   // count set bits
#define all(v) v.begin(),v.end()
#define lps(v,x) (lower_bound(all(v),x)-v.begin())
#define ups(v,x) (upper_bound(all(v),x)-v.begin())
#define ina(a,n) ll a[n]; lp(i,0,n) cin>>a[i];
#define ona(a,n) lp(i,0,n) cout<<a[i]<<" ";

ll dp[110][110000], we[110], v[110];

int main() {
    fast
    ll n, w;
    cin >> n >> w;
    lp(i,1,n+1) {
        cin >> we[i] >> v[i];
    }

    lp(i,1,110000) {
        dp[0][i] = big;
    }

    lp(i,1,n+1)
     {
        lp(j,1,110000)
        {
            dp[i][j] = dp[i - 1][j];
            if (j - v[i] >= 0)
            {
                dp[i][j] = min(dp[i][j], dp[i - 1][j - v[i]] + we[i]);
            }
        }
    }
    ll ans = 0;
    lp(i,0,110000) {
        if (dp[n][i] <= w) {
            ans = max(ans, i);
        }
    }
    p1(ans)



  //clog<<((long double)(clock()-launch)/CLOCKS_PER_SEC)<<"\n";
  return 0;
}
//////////*********************end of program*********************//////////