Problem:
Score : 500 points

Problem Statement

Takahashi has decided to work on K days of his choice from the N days starting with tomorrow.

You are given an integer C and a string S. Takahashi will choose his workdays as follows:

After working for a day, he will refrain from working on the subsequent C days.

If the i-th character of S is x, he will not work on Day i, where Day 1 is tomorrow, Day 2 is the day after tomorrow, and so on.

Find all days on which Takahashi is bound to work.

Constraints

1 \leq N \leq 2 \times 10^5

1 \leq K \leq N

0 \leq C \leq N

The length of S is N.

Each character of S is o or x.

Takahashi can choose his workdays so that the conditions in Problem Statement are satisfied.

Input

Input is given from Standard Input in the following format:

N K C
S

Output

Print all days on which Takahashi is bound to work in ascending order, one per line.

Sample Input 1

11 3 2
ooxxxoxxxoo

Sample Output 1

6

Takahashi is going to work on 3 days out of the 11 days. After working for a day, he will refrain from working on the subsequent 2 days.

There are four possible choices for his workdays: Day 1,6,10, Day 1,6,11, Day 2,6,10, and Day 2,6,11.

Thus, he is bound to work on Day 6.

Sample Input 2

5 2 3
ooxoo

Sample Output 2

1
5

There is only one possible choice for his workdays: Day 1,5.

Sample Input 3

5 1 0
ooooo

Sample Output 3

There may be no days on which he is bound to work.

Sample Input 4

16 4 3
ooxxoxoxxxoxoxxo

Sample Output 4

11
16

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)


#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <ctime>
#include <cmath>
#include <climits>
#include <cassert>
#include <iostream>
#include <algorithm>
#include <map>
#include <set>
#include <stack>
#include <queue>
#include <string>
#include <list>
#include <bitset>
#include <vector>
using namespace std;

#define I64d_OJ

//#ifdef I64d_OJ
//#define LL __int64
//#endif // I64d_OJ
#ifdef I64d_OJ
#define LL long long
#endif // I64d_OJ

typedef unsigned LL ULL;
typedef unsigned uint;
typedef pair<int,int> pii;
typedef pair<double,double> pdd;
typedef pair<LL,LL> pLL;
typedef vector<int> vi;

inline int read(){
    int x=0,f=1;
    char ch=getchar();
    while(ch<'0'||ch>'9'){if(ch=='-') f=-f; ch=getchar();}
    while(ch>='0'&&ch<='9'){x=x*10+ch-'0'; ch=getchar();}
    return x*f;
}

#define lson l,mid,rt<<1
#define rson mid+1,r,rt<<1|1
#define ls rt<<1
#define rs rt<<1|1
#define MID(a,b) (((LL)(a)+(LL)(b))>>1)
#define absx(a) ((a)<0?-(a):(a))
#define MK(a,b) make_pair(a,b)
#define PB(a) push_back(a)
#define lowbit(x) ((x)&-(x))

#define lc c[x][0]
#define rc c[x][1]

template< typename T >
inline void Max(T &a,T &b){if(a<b) a=b;}
template< typename T>
inline void Min(T &a,T &b){if(a>b) a=b;}

const double pi=(double)acos(-1.0);
const double eps=(double)1e-8;
const int INF = (int) 0x3f3f3f3f;
const int MOD = (int) 1e9+7;
const int MAXN =(int) 2e5+10;
const int MAXM = (int) 3e6+10;

///--------------------START-------------------------
int N,K,C;
char s[MAXN];
int dp[MAXN][2];
map<int,int> mp1,mp2;

void work(){
    scanf("%d%d%d",&N,&K,&C);
    scanf("%s",s+1);
    int pre=-C;
    int mx1=0,mx2=0;
    for(int i=1;i<=N;i++){
        if(s[i]=='o'&&pre+C<i){
            pre=i;
            mp1[i]=1;
//            printf("%d ",i);
            mx1++;
        }
    }
//    printf("\n");
    int nxt=C+N+1;
    for(int i=N;i>=1;i--){
        if(s[i]=='o'&&i+C<nxt){
            nxt=i;
            mp2[i]=1;
            mx2++;
//            printf("%d ",i);
        }
    }
//    printf("\n");
    if(mx1>K||mx2>K){
        return;
    }
    for(int i=1;i<=N;i++){
        if(mp1[i]>0&&mp2[i]>0) printf("%d\n",i);
    }
}

///--------------------END-------------------------
int main(){
#ifdef NNever
//freopen("data.in","r",stdin);
///freopen("out.txt","w",stdout);
#endif // NNever
    work();
    return 0;
}