Problem:
Score : 200 points

Problem Statement

In the beginning, Takahashi has A cookies, and Aoki has B cookies.
They will perform the following operation alternately, starting from Takahashi:

If the number of cookies in his hand is odd, eat one of those cookies; if the number is even, do nothing. Then, give one-half of the cookies in his hand to the other person.

Find the numbers of cookies Takahashi and Aoki respectively have after performing K operations in total.

Constraints

1 \leq A,B \leq 10^9

1 \leq K \leq 100

A,B and K are integers.

Input

Input is given from Standard Input in the following format:

A B K

Output

Print the number of cookies Takahashi has, and the number of cookies Aoki has, in this order, after performing K operations in total.

Sample Input 1

5 4 2

Sample Output 1

5 3

The process will go as follows:

In the beginning, Takahashi and Aoki have 5 and 4 cookies, respectively.

Takahashi eats one cookie and gives two cookies to Aoki. They now have 2 and 6 cookies, respectively.

Aoki gives three cookies to Takahashi. They now have 5 and 3 cookies, respectively.

Sample Input 2

3 3 3

Sample Output 2

1 3

Sample Input 3

314159265 358979323 84

Sample Output 3

448759046 224379523

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#define sp ' '
#define mkp make_pair
#define intmax 2147483647
#define llmax 9223372036854775807
#define lP pair<ll,ll>
#define iP pair<int,int>
typedef long long ll;
using namespace std;
const int mod = 1000000007;
const int mod998 = 998244353;

int A, B, K;

int main() {
	cin >> A >> B >> K;
	for (int i = 0; i < K; ++i) {
		if (i % 2 == 0) {
			A -= A % 2;
			B += A / 2;
			A /= 2;
		}
		else {
			B -= B % 2;
			A += B / 2;
			B /= 2;
		}
	}
	cout << A << sp << B << endl;
	return 0;
}