Problem:
Score : 400 points

Problem Statement

An altar enshrines N stones arranged in a row from left to right. The color of the i-th stone from the left (1 \leq i \leq N) is given to you as a character c_i; R stands for red and W stands for white.

You can do the following two kinds of operations any number of times in any order:

Choose two stones (not necessarily adjacent) and swap them.

Choose one stone and change its color (from red to white and vice versa).

According to a fortune-teller, a white stone placed to the immediate left of a red stone will bring a disaster. At least how many operations are needed to reach a situation without such a white stone?

Constraints

2 \leq N \leq 200000

c_i is R or W.

Input

Input is given from Standard Input in the following format:

N
c_{1}c_{2}...c_{N}

Output

Print an integer representing the minimum number of operations needed.

Sample Input 1

4
WWRR

Sample Output 1

2

For example, the two operations below will achieve the objective.

Swap the 1-st and 3-rd stones from the left, resulting in RWWR.

Change the color of the 4-th stone from the left, resulting in RWWW.

Sample Input 2

2
RR

Sample Output 2

0

It can be the case that no operation is needed.

Sample Input 3

8
WRWWRWRR

Sample Output 3

3

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<iostream>
#include<vector>
using namespace std;
#define rep(i,n) for(int i=0;i<(n);++i)
using ll = long long;
using P = pair<int, int>;
#include<algorithm>
#include<math.h>
#include<map>
#include<queue>

int main() {
	ll n;
	cin >> n;
	string a;
	cin >> a;
	ll cnt(0);
	ll cntw(0);
	rep(i, n) {
		if (a[i] == 'R') {
			++cnt;
		}
		else {
			++cntw;
		}
	}
	ll cntr(0);
	if (cntw == 0) {
		cout << 0;
		return 0;
	}
	rep(i, cnt) {
		if (a[i] == 'R') {
			cntr++;
		}
	}
	ll ans = cnt - cntr ;
	cout << ans;
	return 0;
}