Problem:
Score : 1000 points

Problem Statement

We will call a string x good if it satisfies the following condition:

Condition: x can be represented as a concatenation of two copies of another string y of length at least 1.

For example, aa and bubobubo are good; an empty string, a, abcabcabc and abba are not good.

Eagle and Owl created a puzzle on good strings.
Find one string s that satisfies the following conditions. It can be proved that such a string always exists under the constraints in this problem.

1 ≤ |s| ≤ 200

Each character of s is one of the 100 characters represented by the integers 1 through 100.

Among the 2^{|s|} subsequences of s, exactly N are good strings.

Constraints

1 ≤ N ≤ 10^{12}

Input

Input is given from Standard Input in the following format:

N

Output

In the first line, print |s|, the length of s.
In the second line, print the elements in s in order, with spaces in between. Any string that satisfies the above conditions will be accepted.

Sample Input 1

7

Sample Output 1

4
1 1 1 1

There are two good strings that appear as subsequences of s: (1,1) and (1,1,1,1). There are six occurrences of (1,1) and one occurrence of (1,1,1,1), for a total of seven.

Sample Input 2

299

Sample Output 2

23
32 11 11 73 45 8 11 83 83 8 45 32 32 10 100 73 32 83 45 73 32 11 10

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
#define pb push_back
using namespace std;
#define int ll


typedef long long ll;
const int maxn = 1e5 + 10;
const int maxf = 1e4 + 20;
typedef pair<int,int> pii;

int32_t main(){
    int n;
    cin >> n;
    vector<int> v;
    for (int i= 1;i <= 50;i++){
        v.pb(i);
    }
    vector<int> b,c;
    for (int i = 50;i >= -1;i--){
        if (n & (1ll << i)){
            b.pb(i + 1);
        //    cout << i  +1 << endl;
        }else c.pb(i + 1);
    }
    reverse(b.begin(),b.end());
    for (int a : c) v.pb(a);
    for (int a : b) v.pb(a);
    cout << v.size() << endl;
    for (int a : v) cout << a << ' ';
    cout << endl;
    return 0;
}