Problem:
Score : 100 points

Problem Statement

There are a total of A + B cats and dogs.
Among them, A are known to be cats, but the remaining B are not known to be either cats or dogs.

Determine if it is possible that there are exactly X cats among these A + B animals.

Constraints

1 \leq A \leq 100

1 \leq B \leq 100

1 \leq X \leq 200

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B X

Output

If it is possible that there are exactly X cats, print YES; if it is impossible, print NO.

Sample Input 1

3 5 4

Sample Output 1

YES

If there are one cat and four dogs among the B = 5 animals, there are X = 4 cats in total.

Sample Input 2

2 2 6

Sample Output 2

NO

Even if all of the B = 2 animals are cats, there are less than X = 6 cats in total.

Sample Input 3

5 3 2

Sample Output 3

NO

Even if all of the B = 3 animals are dogs, there are more than X = 2 cats in total.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define rep(i,n) for(int i=0; i<(int)n; i++)
#define rep2(i,a,n) for(int i=(a); i<(int)(n); i++)
#define all(vec) vec.begin(),vec.end()
using ll = long long;
using vi = vector<int>;
using vs = vector<string>;
using vvi = vector<vi>;
using vll = vector<ll>;
using pii = pair<int, int>;
using psi = pair<string, int>;
const int dx[4] = {1, 0,-1, 0};
const int dy[4] = {0, 1, 0,-1};
//const ll mod = 1e9+7;
int gcd(int a, int b){if(a%b == 0){return(b);}else{return(gcd(b, a%b));}}
int lcm(int a, int b){return a * b / gcd(a, b);}

ll N, M, K, H, W, L, R;
string S, T;

int main(){
  int A, B, X; cin >> A >> B >> X;
  if(X>=A && X<= A+B) cout << "YES" << endl;
  else cout << "NO" << endl;
  
  return 0;
}