Problem:
Score : 100 points

Problem Statement

Given are three integers A_1, A_2, and A_3.

If A_1+A_2+A_3 is greater than or equal to 22, print bust; otherwise, print win.

Constraints

1 \leq A_i \leq 13 \ \ (i=1,2,3)

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

If A_1+A_2+A_3 is greater than or equal to 22, print bust; otherwise, print win.

Sample Input 1

5 7 9

Sample Output 1

win

5+7+9=21, so print win.

Sample Input 2

13 7 2

Sample Output 2

bust

13+7+2=22, so print bust.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

/*
  ∧,,∧
( 'ω' )つ ＜WA,またお前か！！　
（m9 ＼ 　　
　 ＼　 ＼
　 　 ) ) ＼
　 ／／ ＼ ＼
　 (＿） 　 (＿)
*/

#include <bits/stdc++.h>
using namespace std;

#define all(x) (x).begin(),(x).end()
#define rep(x, y) for (int x = 0; x < y; x++)
#define MOD 1000000007

typedef long long LL;
typedef long double LD;

bool compare_by_b(pair<int, int> a, pair<int, int> b)
{
    if (a.second != b.second) {
        return a.second < b.second;
    } else {
        return a.first < b.first;
    }
}

ostringstream oss_global;
string s_global = oss_global.str();

int main()
{
    vector<int> a(3, 0);
    for (int i = 0; i < 3; i++)
        cin >> a[i];

    int sum = accumulate(all(a), 0);
    if (sum >= 22) cout << "bust" << endl;
    else cout << "win" << endl;

    return 0;
}