Problem:
Score : 100 points

Problem Statement

You have three tasks, all of which need to be completed.

First, you can complete any one task at cost 0.

Then, just after completing the i-th task, you can complete the j-th task at cost |A_j - A_i|.

Here, |x| denotes the absolute value of x.

Find the minimum total cost required to complete all the task.

Constraints

All values in input are integers.

1 \leq A_1, A_2, A_3 \leq 100

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

Print the minimum total cost required to complete all the task.

Sample Input 1

1 6 3

Sample Output 1

5

When the tasks are completed in the following order, the total cost will be 5, which is the minimum:

Complete the first task at cost 0.

Complete the third task at cost 2.

Complete the second task at cost 3.

Sample Input 2

11 5 5

Sample Output 2

6

Sample Input 3

100 100 100

Sample Output 3

0

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <cstdlib>
#include <iostream>
#include <string>
#include <time.h>
#include <cstdio>
#include <algorithm>
#include <cmath>
#include <sstream>
#include <iomanip>
#include <vector>
//#include "bits/stdc++.h"
using namespace std;
//using namespace std::vector;
#define rep(i,a,b) for(int i=(a);i<(b);++i)


#define huge 1000000007
typedef long long ll;

int main(void) {

	ll N = 0;
	ll A = 0;
	ll B = 0;
	ll C = 0;
	ll K = 0;
	ll W = 0;
	ll X = 0;
	//ll m[100000] = {};
	ll w[3] = {};
	ll v[100] = {};
	ll *x, *c, *d;
	//string S,T,U;
	ll count = 0;
	ll sum = 0;
	ll min = 1;
	ll max = 0;
	int flag = 0;
	//char p;
	cin >> w[0] >> w[1] >> w[2];
	
	sort(w,w+3);

	//x = (ll *)malloc(N * sizeof(ll));

	sum += abs(w[0] - w[1]);
	sum += abs(w[1] - w[2]);


		cout << sum << endl;


	return 0;

}