Problem:
Score : 900 points

Problem Statement

Takahashi has decided to make a Christmas Tree for the Christmas party in AtCoder, Inc.

A Christmas Tree is a tree with N vertices numbered 1 through N and N-1 edges, whose i-th edge (1\leq i\leq N-1) connects Vertex a_i and b_i.

He would like to make one as follows:

Specify two non-negative integers A and B.

Prepare A Christmas Paths whose lengths are at most B. Here, a Christmas Path of length X is a graph with X+1 vertices and X edges such that, if we properly number the vertices 1 through X+1, the i-th edge (1\leq i\leq X) will connect Vertex i and i+1.

Repeat the following operation until he has one connected tree:

Select two vertices x and y that belong to different connected components. Combine x and y into one vertex. More precisely, for each edge (p,y) incident to the vertex y, add the edge (p,x). Then, delete the vertex y and all the edges incident to y.

Properly number the vertices in the tree.

Takahashi would like to find the lexicographically smallest pair (A,B) such that he can make a Christmas Tree, that is, find the smallest A, and find the smallest B under the condition that A is minimized.

Solve this problem for him.

Constraints

2 \leq N \leq 10^5

1 \leq a_i,b_i \leq N

The given graph is a tree.

Input

Input is given from Standard Input in the following format:

N
a_1 b_1
:
a_{N-1} b_{N-1}

Output

For the lexicographically smallest (A,B), print A and B with a space in between.

Sample Input 1

7
1 2
2 3
2 4
4 5
4 6
6 7

Sample Output 1

3 2

We can make a Christmas Tree as shown in the figure below:

Sample Input 2

8
1 2
2 3
3 4
4 5
5 6
5 7
5 8

Sample Output 2

2 5

Sample Input 3

10
1 2
2 3
3 4
2 5
6 5
6 7
7 8
5 9
10 5

Sample Output 3

3 4

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

// IO
#include <cstdio>
#include <iomanip>
#include <ios>
#include <iostream>

// algorithm
#include <algorithm>
#include <cmath>
#include <numeric>

// container
#include <vector>
#include <string>
#include <tuple>
#include <set>
#include <map>
#include <unordered_map>
#include <stack>
#include <queue>
#include <deque>

// others
#include <random>
#include <limits>
#include <functional>
#include <ctime>
#include <cassert>

// type alias
using lint = long long;
using ldouble = long double;
template <class T>
using greater_priority_queue = std::priority_queue<T, std::vector<T>, std::greater<T>>;

/* ----- class ----- */

template <class Cost = int>
struct Edge {
    int from, to;
    Cost cost;
    Edge(int from = -1, int to = -1, Cost cost = 1)
        : from(from), to(to), cost(cost){};

    bool operator<(const Edge<Cost>& e) const { return this->cost < e.cost; }
    bool operator>(const Edge<Cost>& e) const { return this->cost > e.cost; }
};

template <class Cost = int>
using Edges = std::vector<Edge<Cost>>;

template <class Cost = int>
class Graph {
public:
    int size;
    std::vector<std::vector<Edge<Cost>>> path;

    explicit Graph(int N = 0) : size(N), path(size) {}
    void span(int from, int to, Cost cost = 1) {
        path[from].push_back(Edge<Cost>(from, to, cost));
    }
    std::vector<Edge<Cost>>& operator[](int v) { return path[v]; }
};

/* ----- Output Functions for Debugging ----- */

template <class T>
std::ostream& operator<<(std::ostream& os, std::vector<T> v);
template <class T>
std::ostream& operator<<(std::ostream& os, std::set<T> v);
template <class L, class R>
std::ostream& operator<<(std::ostream& os, std::pair<L, R> p);
template <class K, class T>
std::ostream& operator<<(std::ostream& os, std::map<K, T> v);
template <class T>
std::ostream& operator<<(std::ostream& os, std::stack<T> s);
template <class T>
std::ostream& operator<<(std::ostream& os, std::queue<T> q);
template <class T>
std::ostream& operator<<(std::ostream& os, std::priority_queue<T> q);
template <class T>
std::ostream& operator<<(std::ostream& os, std::priority_queue<T, std::vector<T>, std::greater<T>> q);
template <class T>
std::ostream& operator<<(std::ostream& os, Edge<T> e);

template <class T>
std::ostream& operator<<(std::ostream& os, std::vector<T> v) {
    os << "[";
    for (auto vv : v) os << vv << ",";
    return os << "]";
}
template <class T>
std::ostream& operator<<(std::ostream& os, std::set<T> v) {
    os << "{";
    for (auto vv : v) os << vv << ",";
    return os << "}";
}
template <class L, class R>
std::ostream& operator<<(std::ostream& os, std::pair<L, R> p) {
    return os << "(" << p.first << "," << p.second << ")";
}
template <class K, class T>
std::ostream& operator<<(std::ostream& os, std::map<K, T> v) {
    os << "{";
    for (auto vv : v) os << vv << ",";
    return os << "}";
}
template <class T>
std::ostream& operator<<(std::ostream& os, std::stack<T> s) {
    os << "[";
    while (!s.empty()) {
        os << s.top() << ",";
        s.pop();
    }
    return os << "]";
}
template <class T>
std::ostream& operator<<(std::ostream& os, std::queue<T> q) {
    os << "[";
    while (!q.empty()) {
        os << q.front() << ",";
        q.pop();
    }
    return os << "]";
}
template <class T>
std::ostream& operator<<(std::ostream& os, std::priority_queue<T> q) {
    os << "{";
    while (!q.empty()) {
        os << q.top() << ",";
        q.pop();
    }
    return os << "}";
}
template <class T>
std::ostream& operator<<(std::ostream& os, std::priority_queue<T, std::vector<T>, std::greater<T>> q) {
    os << "{";
    while (!q.empty()) {
        os << q.top() << ",";
        q.pop();
    }
    return os << "}";
}
template <class T>
std::ostream& operator<<(std::ostream& os, Edge<T> e) {
    return os << "(" << e.from << "->" << e.to << ":" << e.cost << ")";
}

/* ----- Short Functions ----- */

template <class T>
inline T sq(T a) { return a * a; }

template <class T>
inline T iceil(T n, T d) { return (n + d - 1) / d; }

template <class T>
T gcd(T a, T b) {
    while (b > 0) {
        a %= b;
        std::swap(a, b);
    }
    return a;
}

template <class T, class U>
T ipow(T b, U n) {
    T ret = 1;
    while (n > 0) {
        if (n & 1) ret *= b;
        n >>= 1;
        b *= b;
    }
    return ret;
}

// 0-indexed
template <class T, class U>
inline T kthbit(T a, U k) { return (a >> k) & 1; }

template <class T, class U>
inline T mask(T a, U k) { return a & ((1 << k) - 1); }

template <class T>
std::map<T, int> compress(std::vector<T>& v) {
    std::sort(v.begin(), v.end());
    v.erase(std::unique(v.begin(), v.end()), v.end());

    std::map<T, int> rev;
    for (int i = 0; i < v.size(); ++i) rev[v[i]] = i;
    return rev;
}

template <class T>
T Vec(T v) { return v; }

template <class T, class... Ts>
auto Vec(size_t l, Ts... ts) {
    return std::vector<decltype(Vec<T>(ts...))>(l, Vec<T>(ts...));
}

/* ----- Constants ----- */

const int INF = std::numeric_limits<int>::max() / 3;
// const lint INF = std::numeric_limits<lint>::max() / 3;
// const ldouble PI = acos(-1);
// const ldouble EPS = 1e-10;
// std::mt19937 mt(int(std::time(nullptr)));

using namespace std;

Graph<> tree;

int A;

int dfs1(int v, int r) {
    int ch = 0;
    for (auto e : tree[v]) {
        if (e.to == r) continue;
        ++ch;
        dfs1(e.to, v);
    }
    A += ch / 2;
    return ch % 2;
}

int B;

int dfs2(int v, int r) {
    vector<int> ch;
    for (auto e : tree[v]) {
        if (e.to == r) continue;
        ch.push_back(dfs2(e.to, v) + 1);
    }

    if (ch.size() % 2 == 0) ch.push_back(0);
    sort(ch.begin(), ch.end());

    int ok = ch.size(), ng = -1;
    // ok番目抜きで、和の最大値がB以下になるようマッチングできる
    while (ok - ng > 1) {
        int mid = (ok + ng) / 2;

        bool judge = true;
        for (int l = 0, r = ch.size() - 1; l < r; ++l, --r) {
            if (l == mid) ++l;
            if (r == mid) --r;
            if (ch[l] + ch[r] > B) judge = false;
        }

        (judge ? ok : ng) = mid;
    }

    return (ok == ch.size() ? INF : ch[ok]);
}

int main() {
    int N;
    cin >> N;

    tree = Graph<>(N);
    for (int i = 0; i < N - 1; ++i) {
        int u, v;
        cin >> u >> v;
        --u, --v;
        tree.span(u, v);
        tree.span(v, u);
    }

    A = 0;
    int res = dfs1(0, -1);
    A += res;

    int ok = N, ng = 0;
    while (ok - ng > 1) {
        int mid = (ok + ng) / 2;
        B = mid;
        (dfs2(0, -1) <= mid ? ok : ng) = mid;
    }

    cout << A << " " << ok << endl;
    return 0;
}