Problem:
Score : 300 points

Problem Statement

As a token of his gratitude, Takahashi has decided to give his mother an integer sequence.
The sequence A needs to satisfy the conditions below:

A consists of integers between X and Y (inclusive).

For each 1\leq i \leq |A|-1, A_{i+1} is a multiple of A_i and strictly greater than A_i.

Find the maximum possible length of the sequence.

Constraints

1 \leq X \leq Y \leq 10^{18}

All input values are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

Print the maximum possible length of the sequence.

Sample Input 1

3 20

Sample Output 1

3

The sequence 3,6,18 satisfies the conditions.

Sample Input 2

25 100

Sample Output 2

3

Sample Input 3

314159265 358979323846264338

Sample Output 3

31

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>

#define fi first
#define se second
#define pb push_back
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()

using namespace std;

typedef long long ll;
typedef vector<ll> vll;
typedef pair<ll, ll> pll;
typedef long double ld;

const ll mod = (ll)1e9 + 7;
const ll mxN = 200200;



void solve(){
	ll a,b,ans=0;
	cin>>a>>b;
	while(a<=b){
		ans++;
		a*=2;
	}
	cout<<ans<<'\n';

}

int main() {
	ios::sync_with_stdio(false);
	cin.tie(nullptr);
	cout.precision(20);
	cout << fixed;

	//ll t;cin>>t;while(t--)
	solve();

}