Problem:
Score : 200 points

Problem Statement

There are N cities and M roads.
The i-th road (1≤i≤M) connects two cities a_i and b_i (1≤a_i,b_i≤N) bidirectionally.
There may be more than one road that connects the same pair of two cities.
For each city, how many roads are connected to the city?

Constraints

2≤N,M≤50

1≤a_i,b_i≤N

a_i ≠ b_i

All input values are integers.

Input

Input is given from Standard Input in the following format:

N M
a_1 b_1
:
a_M b_M

Output

Print the answer in N lines.
In the i-th line (1≤i≤N), print the number of roads connected to city i.

Sample Input 1

4 3
1 2
2 3
1 4

Sample Output 1

2
2
1
1

City 1 is connected to the 1-st and 3-rd roads.

City 2 is connected to the 1-st and 2-nd roads.

City 3 is connected to the 2-nd road.

City 4 is connected to the 3-rd road.

Sample Input 2

2 5
1 2
2 1
1 2
2 1
1 2

Sample Output 2

5
5

Sample Input 3

8 8
1 2
3 4
1 5
2 8
3 7
5 2
4 1
6 8

Sample Output 3

3
3
2
2
2
1
1
2

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include "bits/stdc++.h"

using namespace std;
typedef long long ll;
#define out(ans) cout << ans << endl;
const long long mod = 1e9 + 7;

bool isMatch(string sub, string obj) {
  for (int i = 0; i < sub.size(); i++) {
    if (!(sub[i] == '?' || sub[i] == obj[i])) {
      return false;
    }
  }
  return true;
}

int main() {
  int n, m, a, b;
  cin >> n >> m;
  vector<int> roads(n, 0);
  for (int i = 0; i < m; i++) {
    cin >> a >> b;
    roads[a - 1]++;
    roads[b - 1]++;
  }

  for (int i = 0; i < n; i++) {
    cout << roads[i] << endl;
  }

  return 0;
}