Problem:
Score : 300 points

Problem Statement

You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

1 \leq |S| \leq 2 \times 10^5

|S| = |T|

S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S and T can be made equal, print Yes; otherwise, print No.

Sample Input 1

azzel
apple

Sample Output 1

Yes

azzel can be changed to apple, as follows:

Choose e as c_1 and l as c_2. azzel becomes azzle.

Choose z as c_1 and p as c_2. azzle becomes apple.

Sample Input 2

chokudai
redcoder

Sample Output 2

No

No sequences of operation can change chokudai to redcoder.

Sample Input 3

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<iostream>
#include<vector>
using namespace std;

int main(){
    string s,t;
    cin >> s >> t;
    /**/
    vector<int> c1[26],c2[26];
    bool moji[26] = {0};
    for(int i = 0;i < s.size();i++){
        int x = s.at(i) - 'a';
        int y = t.at(i) - 'a';
        if(s[i] != t[i]){
            c1[x].push_back(i);
            c2[y].push_back(i);
        }
        moji[x] = 1;
        moji[y] = 1;
    }
    /**/
    /**/

    int ans[26] = {0};

    for(int i = 0;i < 26;i++){
        if((c1[i].empty())||(ans[i] == -1)) ans[i] = -1;
        else{
            for(int j = 0;j < 26;j++){
                if(c1[i] == c2[j]){
                    ans[i] = -1;
                    ans[j] = -1;
                    break;
                }
            }
        }
    }

    bool a = 1;

    for(int i = 0;i < 26;i++){
       if(ans[i] != -1){
           a = 0;
           break;
       }
    }

    if(a){
        cout << "Yes" << endl;
    }
    else{
        cout << "No" << endl;
    }

    return 0;
}