Problem:
Score : 200 points

Problem Statement

There are N positive integers written on a blackboard: A_1, ..., A_N.

Snuke can perform the following operation when all integers on the blackboard are even:

Replace each integer X on the blackboard by X divided by 2.

Find the maximum possible number of operations that Snuke can perform.

Constraints

1 \leq N \leq 200

1 \leq A_i \leq 10^9

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

Print the maximum possible number of operations that Snuke can perform.

Sample Input 1

3
8 12 40

Sample Output 1

2

Initially, [8, 12, 40] are written on the blackboard.
Since all those integers are even, Snuke can perform the operation.

After the operation is performed once, [4, 6, 20] are written on the blackboard.
Since all those integers are again even, he can perform the operation.

After the operation is performed twice, [2, 3, 10] are written on the blackboard.
Now, there is an odd number 3 on the blackboard, so he cannot perform the operation any more.

Thus, Snuke can perform the operation at most twice.

Sample Input 2

4
5 6 8 10

Sample Output 2

0

Since there is an odd number 5 on the blackboard already in the beginning, Snuke cannot perform the operation at all.

Sample Input 3

6
382253568 723152896 37802240 379425024 404894720 471526144

Sample Output 3

8

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<cstdio>
#include<cstring>
#include<cmath>
#include<bitset>
#include<iostream>
#include<algorithm>
#include<string>
#include<utility>
#include<tuple>
#include<vector>
#include<list>
#include<map>
#include<set>
#include<queue>
#include<stack>
#include<numeric>
#include<functional>
#include<iomanip>
#include<random>

#define IOS ios::sync_with_stdio(false),cin.tie(0)
#define REP(i,n) for(int i = 0;i < n;i++)
#define FOR(i,a,b) for(int i = a;i < b;i++)
#define MEM(a,b) memset(a,b,sizeof(a))
#define ALL(x) (x).begin(),(x).end()
#define LMAX 9223372036854775807
#define LMIN -9223372036854775808

using namespace std;

typedef long long ll;
typedef unsigned long long ull;
typedef pair<ll, ll> P;
typedef pair<ull, ull> UP;
typedef tuple<int, int, int> T;

struct UnionFind {
	vector<int> data;
	UnionFind(int size) : data(size, -1) {}
	void unionSet(int x, int y) {
		x = root(x), y = root(y);
		if (x != y) {
			if (data[y] < data[x])swap(x, y);
			data[x] += data[y]; data[y] = x;
		}
	}
	bool findSet(int x, int y) {
		return root(x) == root(y);
	}
	int root(int x) {
		return data[x] < 0 ? x : data[x] = root(data[x]);
	}
	int size(int x) {
		return -data[root(x)];
	}
};

ll gcd(ll a, ll b) {
	if (a < b)swap(a, b);
	int k = a % b;
	if (k == 1)return 1;
	if (k == 0)return b;
	int ans = gcd(b, k);
	return ans;
}
ll digisum(ll a) {
	int sum = 0;
	while (a) {
		sum += a % 10;
		a /= 10;
	}
	return sum;
}
ll countpow(ll a, ll b) {
	int ans = 0;
	if (b == 0)return -1;
	while (1) {
		if (a % b == 0) {
			a /= b;
			ans++;
		}
		else break;
	}
	return ans;
}


int main() {
	IOS;
	int n;
	cin >> n;
	ll ans = 1145148101919;
	REP(i, n) {
		ll a;
		cin >> a;
		a = countpow(a, 2);
		if (a < ans)ans = a;
	}
	cout << ans << endl;
}