Problem:
Score : 400 points

Problem Statement

Let {\rm comb}(n,r) be the number of ways to choose r objects from among n objects, disregarding order.
From n non-negative integers a_1, a_2, ..., a_n, select two numbers a_i > a_j so that {\rm comb}(a_i,a_j) is maximized.
If there are multiple pairs that maximize the value, any of them is accepted.

Constraints

2 \leq n \leq 10^5

0 \leq a_i \leq 10^9

a_1,a_2,...,a_n are pairwise distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print a_i and a_j that you selected, with a space in between.

Sample Input 1

5
6 9 4 2 11

Sample Output 1

11 6

\rm{comb}(a_i,a_j) for each possible selection is as follows:

\rm{comb}(4,2)=6

\rm{comb}(6,2)=15

\rm{comb}(6,4)=15

\rm{comb}(9,2)=36

\rm{comb}(9,4)=126

\rm{comb}(9,6)=84

\rm{comb}(11,2)=55

\rm{comb}(11,4)=330

\rm{comb}(11,6)=462

\rm{comb}(11,9)=55

Thus, we should print 11 and 6.

Sample Input 2

2
100 0

Sample Output 2

100 0

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<bits/stdc++.h>
#define pi 3.141592653897932384626
//freopen("in.txt","r",stdin);freopen("out.txt","w",stdout);
using namespace std;
#define abs(a) ((a)<0?(-(a)):(a))
long a[200005];
pair<long,long>b[200005];
long c[200005];
int main()
{
    long n,m=0;
    cin>>n;
    for(long i=0;i<n;i++){
        scanf("%ld",&a[i]);
        if(a[i]>a[m])m=i;
    }
    cout<<a[m]<<' ';
    double f=(a[m]+1)/2.0;
    long k=LONG_MAX;
    for(long i=0;i<n;i++){
        if(abs(a[i]-f)<abs(k-f)&&i!=m)
            k=a[i];
    }
    cout<<k<<endl;
	return 0;
}