Problem:
Score: 300 points

Problem Statement

We have N voting papers. The i-th vote (1 \leq i \leq N) has the string S_i written on it.

Print all strings that are written on the most number of votes, in lexicographical order.

Constraints

1 \leq N \leq 2 \times 10^5

S_i (1 \leq i \leq N) are strings consisting of lowercase English letters.

The length of S_i (1 \leq i \leq N) is between 1 and 10 (inclusive).

Input

Input is given from Standard Input in the following format:

N
S_1
:
S_N

Output

Print all strings in question in lexicographical order.

Sample Input 1

7
beat
vet
beet
bed
vet
bet
beet

Sample Output 1

beet
vet

beet and vet are written on two sheets each, while beat, bed, and bet are written on one vote each. Thus, we should print the strings beet and vet.

Sample Input 2

8
buffalo
buffalo
buffalo
buffalo
buffalo
buffalo
buffalo
buffalo

Sample Output 2

buffalo

Sample Input 3

7
bass
bass
kick
kick
bass
kick
kick

Sample Output 3

kick

Sample Input 4

4
ushi
tapu
nichia
kun

Sample Output 4

kun
nichia
tapu
ushi

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define pb push_back
#define mp make_pair
#define fi first
#define se second
#define si size()
#define bk back()
#define popb pop_back()
#define fastio ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL)
#define endl "\n"
#define lb lower_bound
#define ub upper_bound
#define emp empty()
#define beg begin()
#define en end()
#define ump unordered_map
#define forl(i,a,n) for(int i=a;i<n;i++)
#define rfor(i,n,a) for(int i=n;i>=a;i--)
#define fore(i,a,n) for(int i=a;i<=n;i++)
#define len length()
double doINF = 1.0/0.0 ;
ostream_iterator <int> outp(cout," ");
inline ll modadd(ll n,ll m,ll mod){
    ll sum = ((n+m)%mod+mod)%mod;
    return sum;
} 
inline ll modsub(ll n,ll m, ll mod){
    ll diff = ((n-m+mod)%mod+mod)%mod;
    return diff;
}
inline ll modpro(ll n,ll m,ll mod){
    ll pro = ((n*m)%mod+mod)%mod;
    return pro;
}
inline ll pow(int x,int y){
    ll res = 1;
    while (y > 0) {
        if (y & 1)
            res = res * x;
        y = y >> 1;
        x = x * x;
    }
    return res;
}
inline ll powmod(ll x,ll y,ll mod){
    ll res = 1;
    while (y > 0) {
        if (y & 1)
            res = modpro(res , x,mod);
        y = y >> 1;
        x = modpro(x , x,mod);
    }
    return res;
}
//ll min(ll a, ll b){
//    if(a>b){
//        return b;
//    }
//    return a;
//}
// 
//ll max(ll a, ll b){
//    if(a>b){
//        return a;
//    }
//    return b;
//}
bool pairdec(const pair<int,int> &a,  
               const pair<int,int> &b) 
{ 		if(a.fi!=b.fi)
       	return (a.fi> b.fi);
		else return a.se>b.se;  
} 

ll power(ll x, ll y, ll mod) 
{ 
    ll res = 1; 
    x = x%mod; 
    while (y > 0) { 
        if (y & 1) 
            res = (res * x) % mod; 
  
        y = y >> 1;
        x = (x * x) % mod; 
    } 
    return res; 
} 
ll modInverse(ll a, ll mod) 
{ 
    return  powmod(a, mod - 2, mod); 
} 
ll modFact(ll n, ll mod) 
{ 
    if (n >=mod) 
        return 0; 
  
    ll result = 1; 
    for (ll i = 1; i <= n; i++) 
        result = (result * i) %mod; 
  
    return result; 
} 

set<ll> primeFactors(ll n)  
{  
    set<ll>s;
    while (n % 2 == 0)  
    {  
       s.insert(2);
        n = n/2;  
    }  
  
    for (int i = 3; i <= sqrt(n); i = i + 2)  
    {  
    
        while (n % i == 0)  
        {  
           s.insert(i); 
            n = n/i;  
        }  
    }  
    if (n > 2) s.insert(n);
    return s;
}  
//cout<<setprecision(9)<<fixed<<sum<<endl; --- precision for double numbers
//copy(v.beg,v.en,outp);
ll N=1e9+7;
int main()
{
	int n;
	cin>>n;
	map<string,int>mp;
	forl(i,0,n)
	{
		string s;
		cin>>s;
		if(mp.find(s)!=mp.en) mp[s]++;
		else mp[s]=1;
	}
	int x=(--mp.en)->se;
	//cout<<x<<endl;
	vector<string>st;
	for(auto val:mp)
	{
		if(val.se==x) st.pb(val.fi);
	}
	sort(st.beg,st.en);
	for(auto str:st)
	{
		cout<<str<<endl;
	}
}