Problem:
Score : 200 points

Problem Statement

Takahashi has two positive integers A and B.

It is known that A plus B equals N.
Find the minimum possible value of "the sum of the digits of A" plus "the sum of the digits of B" (in base 10).

Constraints

2 ≤ N ≤ 10^5

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

Print the minimum possible value of "the sum of the digits of A" plus "the sum of the digits of B".

Sample Input 1

15

Sample Output 1

6

When A=2 and B=13, the sums of their digits are 2 and 4, which minimizes the value in question.

Sample Input 2

100000

Sample Output 2

10

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#include <unistd.h>
#define ll long long
#define inf 1000000007
#define inf16 0x3f3f3f3f
#define INF 1000000000000000007LL
#define VI vector<int>
#define VPII vector<pair<int, int> >
#define VLL vector<ll>
#define PII pair<int, int>
#define st first
#define nd second
#define pb push_back
#define mp make_pair
#define eb emplace_back
#define endl '\n'
#define ALL(c) (c).begin(), (c).end()
using namespace std;

int n, res = inf;

int dig(int a)
{
	int res = 0;

	while(a)
	{
		res += a%10;
		a /= 10;
	}

	return res;
}

int32_t main()
{
	ios_base::sync_with_stdio(0);
	cin.tie(NULL);

	cin >> n;

	for(int i = 1; i < n; ++i)
	{
		res = min(res, dig(i)+dig(n-i));
	}

	cout << res << endl;
}