Problem:
Score : 300 points

Problem Statement

AtCoDeer the deer and his friend TopCoDeer is playing a game.
The game consists of N turns.
In each turn, each player plays one of the two gestures, Rock and Paper, as in Rock-paper-scissors, under the following condition:

(※) After each turn, (the number of times the player has played Paper)≦(the number of times the player has played Rock).

Each player's score is calculated by (the number of turns where the player wins) - (the number of turns where the player loses), where the outcome of each turn is determined by the rules of Rock-paper-scissors.

(For those who are not familiar with Rock-paper-scissors: If one player plays Rock and the other plays Paper, the latter player will win and the former player will lose. If both players play the same gesture, the round is a tie and neither player will win nor lose.)

With his supernatural power, AtCoDeer was able to foresee the gesture that TopCoDeer will play in each of the N turns, before the game starts.
Plan AtCoDeer's gesture in each turn to maximize AtCoDeer's score.

The gesture that TopCoDeer will play in each turn is given by a string s. If the i-th (1≦i≦N) character in s is g, TopCoDeer will play Rock in the i-th turn. Similarly, if the i-th (1≦i≦N) character of s in p, TopCoDeer will play Paper in the i-th turn.

Constraints

1≦N≦10^5

N=|s|

Each character in s is g or p.

The gestures represented by s satisfy the condition (※).

Input

The input is given from Standard Input in the following format:

s

Output

Print the AtCoDeer's maximum possible score.

Sample Input 1

gpg

Sample Output 1

0

Playing the same gesture as the opponent in each turn results in the score of 0, which is the maximum possible score.

Sample Input 2

ggppgggpgg

Sample Output 2

2

For example, consider playing gestures in the following order: Rock, Paper, Rock, Paper, Rock, Rock, Paper, Paper, Rock, Paper. This strategy earns three victories and suffers one defeat, resulting in the score of 2, which is the maximum possible score.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<ctime>
#include<iostream>
#include<algorithm>
#include<cstdio>
#include<cstdlib>
#include<cmath> 
#include<cstring> 
#include<cassert>
#include<string>
#include<sstream>
#include<fstream>
#include<deque>
#include<queue>
#include<vector>
#include<map>
#include<list>
#include<stack>
#include<set>
#include<bitset>
#include<iomanip>
#include<utility>
#include<functional>
#include<cctype>
#include<cerrno>
#include<cfloat>
#include<ciso646>
#include<climits>
#include<clocale>
#include<complex>
#include<csetjmp>
#include<csignal>
#include<cstdarg>
#include<cstddef>
#include<cwchar>
#include<cwctype>
#include<exception>
#include<locale>
#include<numeric>
#include<new>
#include<stdexcept>
#include<limits>
using namespace std;

#define ll long long
#define INF 1e9
#define rep(i,n) for(int (i)=0;(i)<n;i++)
#define REP(i,n) for(int (i)=1;(i)<=n;i++)
#define mk(a,b) make_pair(a,b)
#define fi first
#define se second
#define pii pair<int,int>
#define sz(s) s.size()
#define all(s) (s.begin(),s.end())

const int maxn=100005;
string s;
char c[maxn];
int cur;

int main(){
	scanf("%s",c);
	s=c;
	rep(i,s.size()){
		if(i%2==0)if(s[i]=='p')cur--;
		if(i%2==1)if(s[i]=='g')cur++;
	}
	printf("%d",cur);
	return 0; 
}