Problem:
Score : 100 points

Problem Statement

Takahashi, who is A years old, is riding a Ferris wheel.

It costs B yen (B is an even number) to ride the Ferris wheel if you are 13 years old or older, but children between 6 and 12 years old (inclusive) can ride it for half the cost, and children who are 5 years old or younger are free of charge. (Yen is the currency of Japan.)

Find the cost of the Ferris wheel for Takahashi.

Constraints

0 ≤ A ≤ 100

2 ≤ B ≤ 1000

B is an even number.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the cost of the Ferris wheel for Takahashi.

Sample Input 1

30 100

Sample Output 1

100

Takahashi is 30 years old now, and the cost of the Ferris wheel is 100 yen.

Sample Input 2

12 100

Sample Output 2

50

Takahashi is 12 years old, and the cost of the Ferris wheel is the half of 100 yen, that is, 50 yen.

Sample Input 3

0 100

Sample Output 3

0

Takahashi is 0 years old, and he can ride the Ferris wheel for free.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

//==========================Head files==========================
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<vector>
#include<queue>
#include<cmath>
#include<set>
#include<iostream>
#include<map>
#define LL long long
#define db double
#define mp make_pair
#define pr pair<int, int>
#define fir first
#define sec second
#define pb push_back
#define ms(i, j) memset(i, j, sizeof i)
using namespace std;
//==========================Templates==========================
inline int read() {
    int x = 0, f = 1; char c = getchar();
    while(c < '0' || c > '9'){if (c == '-') f = -1; c = getchar();}
    while(c >= '0' && c <= '9'){x = x * 10 + c - '0'; c = getchar();}
    return x * f;
}
inline LL readl() {
    LL x = 0, f = 1; char c = getchar();
    while(c < '0' || c > '9'){if (c == '-') f = -1; c = getchar();}
    while(c >= '0' && c <= '9'){x = x * 10 + c - '0'; c = getchar();}
    return x * f;
}
int power(int a, int b) {
	int ans = 1;
	while (b) {
		if(b & 1) ans = ans * a;
		b >>= 1; a = a * a;
	}
	return ans;
}
int power_mod(int a, int b, int mod) {
	a %= mod;
	int ans = 1;
	while (b) {
		if(b & 1) ans = (ans * a) % mod;
		b >>= 1, a = (a * a) % mod;
	}
	return ans;
}
LL powerl(LL a, LL b) {
	LL ans = 1ll;
	while (b) {
		if(b & 1ll) ans = ans * a;
		b >>= 1ll;a = a * a;
	}
	return ans;
}
LL power_modl(LL a, LL b, LL mod) {
	a %= mod;
	LL ans = 1ll;
	while (b) {
		if(b & 1ll) ans = (ans * a) % mod;
		b >>= 1ll, a = (a * a) % mod;
	}
	return ans;
}
LL gcdl(LL a, LL b) {return b == 0 ? a : gcdl(b, a % b);}
LL abssl(LL a) {return a > 0 ? a : -a;}
int gcd(int a, int b) {return b == 0 ? a : gcd(b, a % b);}
int abss(int a) {return a > 0 ? a : -a;}
//==========================Main body==========================
#define LD "%I64d"
#define D "%d"
#define pt printf
#define sn scanf
#define pty printf("YES\n")
#define ptn printf("NO\n")
//==========================Code here==========================
int main() {
	int A, B; cin >> A >> B;
	if (A <= 5) cout << 0;
	else if (A >= 13) cout << B;
	else cout << B / 2;
	return 0;
}