Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<bits/stdc++.h>
using namespace std;

int main()
{

  vector<vector<int>> arr(3,vector<int>(3)),mark(3,vector<int>(3,0));
  
  for(int p=0;p<3;p++)
      {
          for(int q=0;q<3;q++)
          {
            cin>>arr[p][q];  
          }
      }
  
  int n,flag=0;
  cin>>n;
  vector<int> a(n);
  for(int i=0;i<n;i++) cin>>a[i];
  int sum=0;
  for(int i=0;i<n;i++)
  {
      for(int p=0;p<3;p++)
      {
          for(int q=0;q<3;q++)
          {
              if(arr[p][q]==a[i]) mark[p][q]=1,sum+=1;
          }
      }
  }
  if(sum<3) cout<<"No"<<endl;
  else
  {
      if(mark[0][0] && mark[1][1] && mark[2][2]) flag=1;
      else if ((mark[0][0] && mark[0][1] && mark[0][2])||(mark[1][0] && mark[1][1] && mark[1][2])||(mark[2][0] && mark[2][1] && mark[2][2])) flag=1;
      else if ((mark[0][0] && mark[1][0] && mark[2][0])||(mark[0][1] && mark[1][1] && mark[2][1])||(mark[0][2] && mark[1][2] && mark[2][2])) flag=1;
      else flag=0;
      
      if(flag) cout<<"Yes"<<endl;
      else cout<<"No"<<endl;
      
  }
return 0;
}