Problem:
Score : 200 points

Problem Statement

There are some animals in a garden. Each of them is a crane with two legs or a turtle with four legs.

Takahashi says: "there are X animals in total in the garden, and they have Y legs in total." Determine whether there is a combination of numbers of cranes and turtles in which this statement is correct.

Constraints

1 \leq X \leq 100

1 \leq Y \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

If there is a combination of numbers of cranes and turtles in which the statement is correct, print Yes; otherwise, print No.

Sample Input 1

3 8

Sample Output 1

Yes

The statement "there are 3 animals in total in the garden, and they have 8 legs in total" is correct if there are two cranes and one turtle. Thus, there is a combination of numbers of cranes and turtles in which the statement is correct.

Sample Input 2

2 100

Sample Output 2

No

There is no combination of numbers of cranes and turtles in which this statement is correct.

Sample Input 3

1 2

Sample Output 3

Yes

We also consider the case in which there are only cranes or only turtles.

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef long double ld;
typedef pair<int, int> P;
typedef pair<ll, ll> Pll;
using Graph = vector<vector<int>>;
using Graphl = vector<vector<ll>>;
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define Rep(i, k, n) for (int i = k; i < (int)(n); i++)
#define RRep(i, k, n) for (int i = k; i > (int)(n); i--)
#define FOR(itr, v) for (auto itr = (v).begin(); itr != (v).end(); ++itr)
#define COUT(x) cout << #x << " = " << (x) << " (L" << __LINE__ << ")" << endl
#define ALL(a)  (a).begin(),(a).end()
#define rALL(a)  (a).rbegin(),(a).rend()
template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }
template<class T> void PrintVector(const vector<T> &vec) {for (auto val : vec) cout << val << " "; cout << endl;}
const long long INF = 1LL << 60;
const long long minusINF = -(1LL << 40);
const int MOD = 1000000007;
const double PI = acos(-1); //3.14~
const int dx[4] = {1, 0, -1, 0};
const int dy[4] = {0, 1, 0, -1};

int main()
{
    int x, y; cin >> x >> y;
    int div1 = y / 2;
    int div2 = y / 4;
    if (y % 2 == 1) {
        puts("No");
        return 0;
    }
    if (div1 >= x && div2 <= x) puts("Yes");
    else puts("No");
}