Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
const int N = 1e5+5;
vector<int>v[N];
char cal[N];
int main()
{
	int a[5],n;
	cin>>n;
	for(int i=1;i<=3;i++)
	cin>>a[i];
	for(int i=1;i<=n;i++)
	{
		string b;cin>>b;
		int t1,t2;
		t1=b[0]-'A'+1;
		t2=b[1]-'A'+1;
		if(a[t1]>a[t2])swap(t1,t2);
		a[t1]++;a[t2]--;
		cal[i]=t1+'A'-1;
	}
	int f=0;
	for(int i=1;i<=3;i++)
	if(a[i]<=0)f=1;
	if(f)cout<<"No";
	else
	{
		cout<<"Yes"<<endl;
		for(int i=1;i<=n;i++)
		cout<<cal[i]<<endl;
	}
	return 0;
}