Problem:
Score : 100 points

Problem Statement

Takahashi is meeting up with Aoki.

They have planned to meet at a place that is D meters away from Takahashi's house in T minutes from now.

Takahashi will leave his house now and go straight to the place at a speed of S meters per minute.

Will he arrive in time?

Constraints

1 \leq D \leq 10000

1 \leq T \leq 10000

1 \leq S \leq 10000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

D T S

Output

If Takahashi will reach the place in time, print Yes; otherwise, print No.

Sample Input 1

1000 15 80

Sample Output 1

Yes

It takes 12.5 minutes to go 1000 meters to the place at a speed of 80 meters per minute. They have planned to meet in 15 minutes so he will arrive in time.

Sample Input 2

2000 20 100

Sample Output 2

Yes

It takes 20 minutes to go 2000 meters to the place at a speed of 100 meters per minute. They have planned to meet in 20 minutes so he will arrive just on time.

Sample Input 3

10000 1 1

Sample Output 3

No

He will be late.

Solution in C++ (Clang 10.0.0) (judge verdict: Accepted)

//////////////////////////
//      _        ____   //
//  U  /"\  u U /"___|  //
//   \/ _ \/  \| | u    //
//   / ___ \   | |/__   //
//  /_/   \_\   \____|  //
//   \\    >>  _// \\   //
//  (__)  (__)(__)(__)  //
//  Compro by NULL_CT©  //
//////////////////////////
// STL libs
#include <algorithm>
#include <array>
#include <bitset>
#include <cctype>
#include <chrono>
#include <climits>
#include <cmath>
#include <complex>
#include <cstdint>
#include <cstdio>
#include <cstdlib>
#include <deque>
#include <functional>
#include <iomanip>
#include <ios>
#include <iostream>
#include <iterator>
#include <map>
#include <numeric>
#include <queue>
#include <set>
#include <stack>
#include <string>
#include <thread>
#include <tuple>
#include <unordered_map>
#include <unordered_set>
#include <utility>
#include <vector>

#define REP(I, LIM) for (int I = 0; I < (LIM); I++)
#define ALL(LIST) (LIST.begin()), (LIST.end())

using namespace std;

constexpr int MOD = 10000007;

vector<long> divisor(long &_n) {
  vector<long> head, tail;
  for (long i = 1; i * i <= _n; i++) {
    if (_n % i == 0) {
      head.push_back(i);
      if (i * i != _n) tail.push_back(_n / i);
    }
  }
  head.insert(head.end(), tail.rbegin(), tail.rend());
  return head;
}

long kadanes(vector<long> &_ls) {
  long highestMax = 0, currentMax = 0, length = _ls.size();
  for (long i = 0; i < length; i++) {
    currentMax = max(_ls[i], currentMax + _ls[i]);
    highestMax = max(highestMax, currentMax);
  }
  return highestMax;
}

struct init {
  init() {
    cin.tie(0);
    ios::sync_with_stdio(0);
    // cout<<fixed<<setprecision(20);
  }
} init;

/*----------------------------*/

int main() {
  int d,t,s;
  cin >> d >> t >> s;
  if(d <= t*s){
    cout << "Yes\n";
  }else{
    cout << "No\n";
  }
}