Problem:
Score : 200 points

Problem Statement

There are N balls placed in a row.
AtCoDeer the deer is painting each of these in one of the K colors of his paint cans.
For aesthetic reasons, any two adjacent balls must be painted in different colors.

Find the number of the possible ways to paint the balls.

Constraints

1≦N≦1000

2≦K≦1000

The correct answer is at most 2^{31}-1.

Input

The input is given from Standard Input in the following format:

N K

Output

Print the number of the possible ways to paint the balls.

Sample Input 1

2 2

Sample Output 1

2

We will denote the colors by 0 and 1. There are two possible ways: we can either paint the left ball in color 0 and the right ball in color 1, or paint the left in color 1 and the right in color 0.

Sample Input 2

1 10

Sample Output 2

10

Since there is only one ball, we can use any of the ten colors to paint it. Thus, the answer is ten.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#define _GLIBCXX_DEBUG
#include <bits/stdc++.h>
using namespace std;
#define rep(i,c) for (int i = 0; i < (int)c; i++)
#define all(v) v.begin(), v.end()
const int inf = 1000000000; //10^9
using ll = long long;
using P = pair<int,int>;
//加算代入演算子は+=！！！！！

int main() {
    ll n, k, sum;
    //n個のボールをk色で塗る。隣り合ったボールは別の色で塗ること。
    cin >> n >> k;
    sum = k * pow((k - 1),(n - 1));
    cout << sum << endl;
}