Problem:
Score : 200 points

Problem Statement

We have a long seat of width X centimeters.
There are many people who wants to sit here. A person sitting on the seat will always occupy an interval of length Y centimeters.

We would like to seat as many people as possible, but they are all very shy, and there must be a gap of length at least Z centimeters between two people, and between the end of the seat and a person.

At most how many people can sit on the seat?

Constraints

All input values are integers.

1 \leq X, Y, Z \leq 10^5

Y+2Z \leq X

Input

Input is given from Standard Input in the following format:

X Y Z

Output

Print the answer.

Sample Input 1

13 3 1

Sample Output 1

3

There is just enough room for three, as shown below:

Figure

Sample Input 2

12 3 1

Sample Output 2

2

Sample Input 3

100000 1 1

Sample Output 3

49999

Sample Input 4

64146 123 456

Sample Output 4

110

Sample Input 5

64145 123 456

Sample Output 5

109

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<iostream>

int main(int argc, char const *argv[]) {

    int chair_space;
    int space_between_man;
    int man_space;

    std::cin >> chair_space >> space_between_man >> man_space;

    /** 初めのスペースは確定 **/
    chair_space -= space_between_man;

    /** 1人分の幅を算出 **/
    man_space = man_space + space_between_man;

    /** 残りスペースから座れる人数を算出 **/
    int answer = chair_space / man_space;
    std::cout << answer << '\n';

    return 0;
}