Problem:
Score: 100 points

Problem Statement

In this problem, a date is written as Y-M-D. For example, 2019-11-30 means November 30, 2019.

Integers M_1, D_1, M_2, and D_2 will be given as input.

It is known that the date 2019-M_2-D_2 follows 2019-M_1-D_1.

Determine whether the date 2019-M_1-D_1 is the last day of a month.

Constraints

Both 2019-M_1-D_1 and 2019-M_2-D_2 are valid dates in the Gregorian calendar.

The date 2019-M_2-D_2 follows 2019-M_1-D_1.

Input

Input is given from Standard Input in the following format:

M_1 D_1
M_2 D_2

Output

If the date 2019-M_1-D_1 is the last day of a month, print 1; otherwise, print 0.

Sample Input 1

11 16
11 17

Sample Output 1

0

November 16 is not the last day of a month.

Sample Input 2

11 30
12 1

Sample Output 2

1

November 30 is the last day of November.

Solution in C++ (GCC 9.2.1) (judge verdict: Time Limit Exceeded)

#include <bits/stdc++.h>
using namespace std;
#define int long long
typedef pair<int, int> ii;
typedef vector<int> vi;
typedef vector<ii> vii;
#define pb push_back
#define ld long double
#define f first
#define s second
#define in insert
#define sz(x) (int)x.size()
#define all(x) (x).begin(), (x).end()
#define speed ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
const int INF = 1e18 + 5;
const int mod = 1e9 + 7;
const int  N = 2e5 + 314;
const long double pi = 3.1415926535897932384626433832795;
void solve(){
    int n;
    cin>>n;
    for(int i = 0; i < 50; i++){
        for(int j = 0; j < 50; j++){
            for(int k = 0; k < 50; k++){
                for(int l = 0; l < 50; l++){
                    for(int p = 0; p < 50; p++){
                        for(int t = 0; t < 50; t++){
                            if(100*i+101*j+102*k+103*l+104*p+105*t==n){
                                cout<<1;
                                return;
                            }
                        }
                    }
                }
            }
        }
    }
    cout<<0;
}
signed main(){
    speed;
    int t=1;
    //cin>>t;
    while(t--)solve();
}