Problem:
Score : 200 points

Problem Statement

There are N balls placed in a row.
AtCoDeer the deer is painting each of these in one of the K colors of his paint cans.
For aesthetic reasons, any two adjacent balls must be painted in different colors.

Find the number of the possible ways to paint the balls.

Constraints

1≦N≦1000

2≦K≦1000

The correct answer is at most 2^{31}-1.

Input

The input is given from Standard Input in the following format:

N K

Output

Print the number of the possible ways to paint the balls.

Sample Input 1

2 2

Sample Output 1

2

We will denote the colors by 0 and 1. There are two possible ways: we can either paint the left ball in color 0 and the right ball in color 1, or paint the left in color 1 and the right in color 0.

Sample Input 2

1 10

Sample Output 2

10

Since there is only one ball, we can use any of the ten colors to paint it. Thus, the answer is ten.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;

#define rp(i,n) for(int i=0;i<n;i++)
#define rep(i,m,n) for(int i=m;i<=n;i++)
#define lrp(i,n) for(long long i=0;i<n;i++)
#define lrep(i,m,n) for(long long i=m;i<=n;i++)
#define all(a) a.begin(),a.end()
#define pb push_back

typedef vector<int> vi;
typedef vector<long long> vl;
typedef vector<string> vs;
typedef vector<char> vc;
typedef long long ll;
typedef string S;

int main(){
    int n,k;
    cin >> n >> k;
    int ans=k;
    rp(i,n-1){
        ans *= (k-1);
    }
    cout << ans << endl;
    return 0;
}