Problem:
Score : 200 points

Problem Statement

There are some animals in a garden. Each of them is a crane with two legs or a turtle with four legs.

Takahashi says: "there are X animals in total in the garden, and they have Y legs in total." Determine whether there is a combination of numbers of cranes and turtles in which this statement is correct.

Constraints

1 \leq X \leq 100

1 \leq Y \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

If there is a combination of numbers of cranes and turtles in which the statement is correct, print Yes; otherwise, print No.

Sample Input 1

3 8

Sample Output 1

Yes

The statement "there are 3 animals in total in the garden, and they have 8 legs in total" is correct if there are two cranes and one turtle. Thus, there is a combination of numbers of cranes and turtles in which the statement is correct.

Sample Input 2

2 100

Sample Output 2

No

There is no combination of numbers of cranes and turtles in which this statement is correct.

Sample Input 3

1 2

Sample Output 3

Yes

We also consider the case in which there are only cranes or only turtles.

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cmath>
#include <queue>
#include <algorithm>
#include <vector>
#include <cstring>
#include <stack>
#include <cctype>
#include <utility>
#include <map>
#include <string>
#include <climits>
#include <set>
#include <sstream>
#include <utility>
#include <ctime>
#include <cassert>
#include <fstream>
using namespace std;
typedef long long LL;
#define MS(A) memset(A, 0, sizeof(A))
#define MSV(A,a) memset(A, a, sizeof(A))
#define MP make_pair
#define PB push_back
#define getcx getchar_unlocked
#define INF (int(1e9))
#define INFL (LL(1e18))
#define EPS 1e-12
#define chkbit(s, b) (s & (1<<b))
#define setbit(s, b) (s |= (1<<b))
#define chk(a) cerr << endl << #a << " : " << a << endl
#define chk2(a,b) cerr << endl << #a << " : " << a << "\t" << #b << " : " << b << endl
#define chk3(a,b,c) cerr << endl << #a << " : " << a << "\t" << #b << " : " << b << "\t" << #c << " : " << c << endl
#define chk4(a,b,c,d) cerr << endl << #a << " : " << a << "\t" << #b << " : " << b << "\t" << #c << " : " << c << "\t" << #d << " : " << d << endl
#define rep(i, a, n) for(i=a;i<n;i++)
#define rev(i, a, n) for(i=a;i>=n;i--)
#define rep_itr(itr, c) for(itr = (c).begin(); itr != (c).end(); itr++)
#define MOD 1000000007
#define MAX 1000000

int main() {

	int x, y, ans =0;

	cin>>x>>y;


	//only cranes

	if(y % 2 == 0 && 2*x == y) {
		cout<<"Yes"<<endl;
		return 0;
	}

	if(y % 4 == 0 && 4 * x == y) {
		cout<<"Yes"<<endl;
		return 0;
	}

	if((y - (2*x)) % 2 == 0) {
		int b = y - 2*x;
		b = b/2;

		if(x - b >=0 && (x-b) * 2  == (y-4*b)) {
			cout<<"Yes"<<endl;
		} else cout<<"No"<<endl;
	} else {


		if((4*x - y) % 2 == 0) {
			int a = 4*x - y;
			a = a/2;


			if(x - a >=0 && (x-a)*4 == (y-2*a)) {
				cout<<"No"<<endl;
		} else {
			cout<<"No"<<endl;
		}
	}
}

	return 0;
}