Problem:
Score : 400 points

Problem Statement

You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

In the i-th operation, you replace every element whose value is B_{i} with C_{i}.

For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

All values in input are integers.

1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}

B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:

N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}

Output

Print Q integers S_{i} to Standard Output in the following format:

S_{1}
S_{2}
\vdots
S_{Q}

Note that S_{i} may not fit into a 32-bit integer.

Sample Input 1

4
1 2 3 4
3
1 2
3 4
2 4

Sample Output 1

11
12
16

Initially, the sequence A is 1,2,3,4.

After each operation, it becomes the following:

2, 2, 3, 4

2, 2, 4, 4

4, 4, 4, 4

Sample Input 2

4
1 1 1 1
3
1 2
2 1
3 5

Sample Output 2

8
4
4

Note that the sequence A may not contain an element whose value is B_{i}.

Sample Input 3

2
1 2
3
1 100
2 100
100 1000

Sample Output 3

102
200
2000

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;

#define ll     long long
#define fr     first
#define sec    second
#define rep(i,n)  for(i=0;i<n;i++)
#define vi     vector <int>
#define vc     vector <char>
#define vl     vector <ll>
#define vb     vector <bool>
#define pb     push_back
#define M      1000000007
#define ios    ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
#define open   freopen("input.txt","r",stdin);
#define close  freopen("output.txt","w",stdout);
#define M_PI   3.14159265358979323846
#define pp     pair<int,int>
#define nn 100003

int main()
{
    ios;
    ll n,i,q,b,c,sum=0;
    map <ll,ll> mp;
    cin>>n;
    ll a[n];
    rep(i,n)
    {
        cin>>a[i];
        sum+=a[i];
        mp[a[i]]++;
    }
    cin>>q;
    rep(i,q)
    {
        ll currsum;
        cin>>b>>c;
        if(mp.find(b)!=mp.end())
        {
            ll x=mp[b];
            currsum=sum-x*b+x*c;
            sum=currsum;
            mp.erase(b);
            if(mp.find(c)!=mp.end())
                mp[c]+=x;
            else
                mp[c]=x;
        }
        else
            currsum=sum;
        cout<<currsum<<"\n";
    }
    return 0;
}