Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;

typedef long long ll;

int main() {
    int N;
    cin >> N;
    
    bool f=false;
    for(int n=1; n<=3500; n++){
        for(int w=1; w<=3500; w++){
            int h;
            if(4*n*w - N*w - N*n == 0) continue;
            h = N*n*w / (4*n*w - N*w - N*n);
            if(h > 0 && h <= 3500){
                printf("%d %d %d\n", h,n,w);
                f=true;
                break;
            }
        }
        if(f) break;
    }
}