Problem:
Score : 300 points

Problem Statement

You are given an integer sequence of length n, a_1, ..., a_n.
Let us consider performing the following n operations on an empty sequence b.

The i-th operation is as follows:

Append a_i to the end of b.

Reverse the order of the elements in b.

Find the sequence b obtained after these n operations.

Constraints

1 \leq n \leq 2\times 10^5

0 \leq a_i \leq 10^9

n and a_i are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print n integers in a line with spaces in between.
The i-th integer should be b_i.

Sample Input 1

4
1 2 3 4

Sample Output 1

4 2 1 3

After step 1 of the first operation, b becomes: 1.

After step 2 of the first operation, b becomes: 1.

After step 1 of the second operation, b becomes: 1, 2.

After step 2 of the second operation, b becomes: 2, 1.

After step 1 of the third operation, b becomes: 2, 1, 3.

After step 2 of the third operation, b becomes: 3, 1, 2.

After step 1 of the fourth operation, b becomes: 3, 1, 2, 4.

After step 2 of the fourth operation, b becomes: 4, 2, 1, 3.

Thus, the answer is 4 2 1 3.

Sample Input 2

3
1 2 3

Sample Output 2

3 1 2

As shown above in Sample Output 1, b becomes 3, 1, 2 after step 2 of the third operation. Thus, the answer is 3 1 2.

Sample Input 3

1
1000000000

Sample Output 3

1000000000

Sample Input 4

6
0 6 7 6 7 0

Sample Output 4

0 6 6 0 7 7

Solution in C++14 (GCC 5.4.1) (judge verdict: Time Limit Exceeded)

#include <iostream>
#include <vector> 
#include <cmath>
#include <algorithm>
#include <set>
#include <string>
#include <map>
#include <cerrno>
#include <stdio.h>
#include <stdlib.h>
#include <cfenv>
#include <stack>
#include <math.h>
#include <iomanip>
#include <limits>
#include <queue>
#define ll long long int
#define pb push_back
#define mp make_pair

using namespace std;

int main(){

    int n;
    cin >> n;

    vector<string> a(n);

    for(int i=0;i<n;i++){
        cin >> a[i];
    }

    vector<int> vec;

    vec.pb(0);

    for(int i=1;i<n;i++){
        vec.pb(i);
        reverse(vec.begin(),vec.end());
    }

    for(int i=0;i<n;i++){
        cout << a[vec[i]] << " ";
    }

    cout << endl;
    return 0;
}