Problem:
Score : 700 points

Problem Statement

10^{10^{10}} participants, including Takahashi, competed in two programming contests.
In each contest, all participants had distinct ranks from first through 10^{10^{10}}-th.

The score of a participant is the product of his/her ranks in the two contests.

Process the following Q queries:

In the i-th query, you are given two positive integers A_i and B_i. Assuming that Takahashi was ranked A_i-th in the first contest and B_i-th in the second contest, find the maximum possible number of participants whose scores are smaller than Takahashi's.

Constraints

1 \leq Q \leq 100

1\leq A_i,B_i\leq 10^9(1\leq i\leq Q)

All values in input are integers.

Input

Input is given from Standard Input in the following format:

Q
A_1 B_1
:
A_Q B_Q

Output

For each query, print the maximum possible number of participants whose scores are smaller than Takahashi's.

Sample Input 1

8
1 4
10 5
3 3
4 11
8 9
22 40
8 36
314159265 358979323

Sample Output 1

1
12
4
11
14
57
31
671644785

Let us denote a participant who was ranked x-th in the first contest and y-th in the second contest as (x,y).

In the first query, (2,1) is a possible candidate of a participant whose score is smaller than Takahashi's. There are never two or more participants whose scores are smaller than Takahashi's, so we should print 1.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
#include <iomanip>
 
using namespace std;
 
typedef long long LL;
typedef long double LD;
typedef pair<int, int> PII;
typedef pair<LL, LL> PLL;
typedef pair<LD, LD> PLDLD;
typedef vector<int> VI;
typedef vector<LL> VLL;
typedef vector<char> VB;
 
#define FOR(i,a,b) for(int i=(a);i<(int)(b);++i)
#define REP(i,n) FOR(i,0,n)
#define CLR(a) memset((a), 0 ,sizeof(a))
#define ALL(a) a.begin(),a.end()
 
const LD eps=1e-10;
const long long INFLL=(LL)(1e9)*(LL)(1e9);
const int INF=1e9;
 
template<class T>
void chmin(T& a, const T b)
{
	if(a>b)
		a=b;
}
template<class T>
void chmax(T& a, const T b)
{
	if(a<b)
		a=b;
}
 
const LL pow(const LL p, const LL q)
{
	LL t=1;
	for(int i=0;i<q;i++)
		t*=p;
	return t;
}

template <typename T>
struct has_iter
{
	private:
		template <typename U>
		static constexpr true_type check(typename U::iterator*);
		template <typename U>
		static constexpr false_type check(...);

	public:
		static constexpr bool value = decltype(check<T>(nullptr))::value;
};


template<typename T, typename U = typename T::iterator>
void print(const T& container)
{
		auto&& first=begin(container), last=end(container);
		auto&& back=prev(last);
		for(auto e=first; e!=last; e=next(e))
			cout<<*e<<" \n"[e==back];
}


extern void* enabler;
template<typename Head, typename enable_if<!has_iter<Head>::value>::type*& = enabler>
void print(const Head& head)
{
	cout<<head<<endl;
}

template<> void print<string>(const string& container)
{
	cout<<container<<endl;
}

template<typename Head, typename... Tail>
void print(const Head& head, const Tail&... tail)
{
	cout<<head<<" ";
	print(tail...);
}

void io_speedup()
{
	cin.tie(0);
	ios::sync_with_stdio(false);
}

template<typename T>
istream& operator >> (istream& is, vector<T>& vec)
{
	for(T& x: vec) is >> x;
	return is;
}

template<typename T>
vector<T> read(int n)
{
	vector<T> t(n);
	cin>>t;
	return t;
}

template<typename T>
T read()
{
	T t;
	cin>>t;
	return t;
}



int main()
{
	int q;
	cin>>q;
	REP(tt,q)
	{
		LL a,b;
		cin>>a>>b;
		if(a>b) swap(a,b);
		if(a==b&&a==1)
		{
			print(0);
			continue;
		}
		LL s=a*b;
		s--;
		LL sq=(LL)(sqrt(s)+eps);
		while((sq+1)*(sq+1)<s) sq++;
		LL ans=sq*2;
		if(a==b)
		{
			if(s/sq==a)
			{
				ans=sq*2-2;
				print(ans);
				continue;
			}
		}
		if(s/sq==sq) ans--;
		if(a<=sq) ans--;
		//print(s,sq,ans);


		print(ans);
	}

}