Problem:
Score: 400 points

Problem statement

We have an H \times W grid whose squares are painted black or white. The square at the i-th row from the top and the j-th column from the left is denoted as (i, j).

Snuke would like to play the following game on this grid. At the beginning of the game, there is a character called Kenus at square (1, 1). The player repeatedly moves Kenus up, down, left or right by one square. The game is completed when Kenus reaches square (H, W) passing only white squares.

Before Snuke starts the game, he can change the color of some of the white squares to black. However, he cannot change the color of square (1, 1) and (H, W). Also, changes of color must all be carried out before the beginning of the game.

When the game is completed, Snuke's score will be the number of times he changed the color of a square before the beginning of the game. Find the maximum possible score that Snuke can achieve, or print -1 if the game cannot be completed, that is, Kenus can never reach square (H, W) regardless of how Snuke changes the color of the squares.

The color of the squares are given to you as characters s_{i, j}. If square (i, j) is initially painted by white, s_{i, j} is .; if square (i, j) is initially painted by black, s_{i, j} is #.

Constraints

H is an integer between 2 and 50 (inclusive).

W is an integer between 2 and 50 (inclusive).

s_{i, j} is . or # (1 \leq i \leq H, 1 \leq j \leq W).

s_{1, 1} and s_{H, W} are ..

Input

Input is given from Standard Input in the following format:

H W
s_{1, 1}s_{1, 2}s_{1, 3} ... s_{1, W}
s_{2, 1}s_{2, 2}s_{2, 3} ... s_{2, W}
: :
s_{H, 1}s_{H, 2}s_{H, 3} ... s_{H, W}

Output

Print the maximum possible score that Snuke can achieve, or print -1 if the game cannot be completed.

Sample Input 1

3 3
..#
#..
...

Sample Output 1

2

The score 2 can be achieved by changing the color of squares as follows:

Sample Input 2

10 37
.....................................
...#...####...####..###...###...###..
..#.#..#...#.##....#...#.#...#.#...#.
..#.#..#...#.#.....#...#.#...#.#...#.
.#...#.#..##.#.....#...#.#.###.#.###.
.#####.####..#.....#...#..##....##...
.#...#.#...#.#.....#...#.#...#.#...#.
.#...#.#...#.##....#...#.#...#.#...#.
.#...#.####...####..###...###...###..
.....................................

Sample Output 2

209

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using intl = long long;
using itnl = long long;//typo用
using itn = int;//typo用
using ld = long double;
using namespace std;
#define rep(i, n) for(intl i = 0; i < (intl)(n); i++)
#define rrep(i, n) for(intl i = (intl)(n) - 1; i >= 0; i--)
#define repi(i, a, b) for(intl i = (intl)(a); i < (intl)(b); i++)
#define rrepi(i, a, b) for(intl i = (intl)(a); i > (intl)(b); i--)
#define all(x) (x).begin(),(x).end()
#define rall(x) (x).rbegin(),(x).rend()
#define m0(x) memset(x,0,sizeof(x))
#define m1(x) memset(x,1,sizeof(x))
#define fill(x,y) memset(x,y,sizeof(x))
#define alength(a) (sizeof(a) / sizeof(a[0]))
#define debug(x) cout << #x << ":" << x << endl
#define rdebug(i,x) rep(i, alength(x))cout << #x << "[" << i << "]:" << x[i] << endl//1次元配列の出力
#define rrdebug(i, j, x) rep(i, alength(x))rep(j, alength(x[i]))cout << #x << "[" << i << "][" << j << "]:" << x[i][j] << endl//二次元配列の出力
#define pb push_back
#define mp make_pair
#define Pii pair<intl,intl>
const intl INF = 1e9;
const intl MOD = 1e9+7;
const ld EPS = 1.0e-14;//-9
const ld PI = acos(-1);
void fp(bool f){cout << (f ? "Yes" : "No") << endl;}
void fp(bool f, string s, string t){cout << (f ? s : t) << endl;}
template<class T> inline bool chmin(T& a, T b) { if (a > b) {a = b; return true;} return false; }
template<class T> inline bool chmax(T& a, T b) { if (a < b) {a = b; return true;} return false; }
intl kai(intl k){//k!を求める関数,
    intl a = 1;
    for(int i = 2; i <= k; i++){
        a *= i;
    }
    return a;
}
intl digit10(intl a){//aを10進数で表したときの桁数を求める関数
    intl b = 0;
    do{
        a /= 10;
        b++;
    }while(a);
    return b;
}

//--------------入力受け取る場所----------------------------------------------------
intl h,w;
char s[50][50];

void input_var(){
    cin >> h >> w;
    rep(i,h){
        rep(j,w){
            cin >> s[i][j];
        }
    }
}
//-------------------------------------------------------------------------------


signed main(){
    cout << fixed << setprecision(10);
    input_var();
    intl cnt = 0;
    queue<Pii > q;
    q.push(mp(0,0));
    bool f = false;
    while(!q.empty()){
        intl len = q.size();
        rep(i,len){
            Pii p = q.front();
            q.pop();
            if(s[p.first][p.second + 1] == '.')q.push(mp(p.first, p.second + 1));
            if(s[p.first + 1][p.second] == '.')q.push(mp(p.first + 1, p.second));
            if((p.first == h-1)&&(p.second == w-1)){
                f = true;
                break;
            }
        }
        cnt++;
        if(f)break;
    }
    if(f){
        intl ans = 0;
        rep(i,h)rep(j,w)ans += (s[i][j] == '#');
        ans = h * w - ans - cnt;
        cout << ans << endl;
    }
    else cout << -1 << endl;
    return 0;
}