Problem:
Score : 400 points

Problem Statement

You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

In the i-th operation, you replace every element whose value is B_{i} with C_{i}.

For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

All values in input are integers.

1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}

B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:

N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}

Output

Print Q integers S_{i} to Standard Output in the following format:

S_{1}
S_{2}
\vdots
S_{Q}

Note that S_{i} may not fit into a 32-bit integer.

Sample Input 1

4
1 2 3 4
3
1 2
3 4
2 4

Sample Output 1

11
12
16

Initially, the sequence A is 1,2,3,4.

After each operation, it becomes the following:

2, 2, 3, 4

2, 2, 4, 4

4, 4, 4, 4

Sample Input 2

4
1 1 1 1
3
1 2
2 1
3 5

Sample Output 2

8
4
4

Note that the sequence A may not contain an element whose value is B_{i}.

Sample Input 3

2
1 2
3
1 100
2 100
100 1000

Sample Output 3

102
200
2000

Solution in C++ (GCC 9.2.1) (judge verdict: Time Limit Exceeded)

#include <bits/stdc++.h> 
using namespace std;
typedef long long ll;
int main() 
{ 
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  cout.tie(NULL);
//	freopen("input.txt","r",stdin);
  // freopen("output.txt","w",stdout);
ll n;
cin>>n;
map<ll,ll> m;
for(int i=0;i<n;i++){
  ll x;
  cin>>x;
  m[x]++;
}
ll q;
cin>>q;
while(q--){
  ll b,c;
  cin>>b>>c;
  ll sum = 0;
  if(m[b]!=0){ 
      m[c] += m[b];
      m[b] = 0;
  }
  for(auto x:m){
    sum += (x.first)*(x.second);
  }
  cout<<sum<<"\n";
}
	return 0; 
}