Problem:
Score : 200 points

Problem Statement

An integer X is called a Harshad number if X is divisible by f(X), where f(X) is the sum of the digits in X when written in base 10.

Given an integer N, determine whether it is a Harshad number.

Constraints

1?N?10^8

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

Print Yes if N is a Harshad number; print No otherwise.

Sample Input 1

12

Sample Output 1

Yes

f(12)=1+2=3. Since 12 is divisible by 3, 12 is a Harshad number.

Sample Input 2

57

Sample Output 2

No

f(57)=5+7=12. Since 57 is not divisible by 12, 12 is not a Harshad number.

Sample Input 3

148

Sample Output 3

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define int long long
#define rep(i,n) for(int i=0;i<n;i++)
#define krep(i,k,n,m) for(int i=k;i<n;i+=m)
#define erep(i,k,n) for(int i=k;i<n;i++)
//最大公約数
int gcd(int s,int b){
    if(b==0)return s;
    return gcd(b,s%b);
}
signed main() {
    int n;
    cin>>n;
    int kai,nai,ans=0,b;
    b=n;
    for(int i=0;i<=9;i++){
        kai=n%10;
        nai=n/10;
        if(nai==0){
            ans+=kai;
            break;
        }
        ans+=kai;
        n=nai;
    }
    if(b%ans==0){
        cout<<"Yes"<<endl;
    }
    else{
        cout<<"No"<<endl;
    }
}