Problem:
Score : 400 points

Problem Statement

Mr. Takahashi has a string s consisting of lowercase English letters.
He repeats the following operation on s exactly K times.

Choose an arbitrary letter on s and change that letter to the next alphabet. Note that the next letter of z is a.

For example, if you perform an operation for the second letter on aaz, aaz becomes abz.
If you then perform an operation for the third letter on abz, abz becomes aba.

Mr. Takahashi wants to have the lexicographically smallest string after performing exactly K operations on s.
Find the such string.

Constraints

1≤|s|≤10^5

All letters in s are lowercase English letters.

1≤K≤10^9

Input

The input is given from Standard Input in the following format:

s
K

Output

Print the lexicographically smallest string after performing exactly K operations on s.

Sample Input 1

xyz
4

Sample Output 1

aya

For example, you can perform the following operations: xyz, yyz, zyz, ayz, aya.

Sample Input 2

a
25

Sample Output 2

z

You have to perform exactly K operations.

Sample Input 3

codefestival
100

Sample Output 3

aaaafeaaivap

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <cstdio>
#include <iostream>
#include <cstring>
#include <algorithm>
#include <sstream>
#include <vector>
#include <map>
#include <set>
#include <deque>
#include <list>
#include <stack>
#include <queue>
#include <complex>
#include <ctime>
#include<cstdlib>
#define _USE_MATH_DEFINES
#include <math.h>
#include<cmath>
#include <cstdarg> 
#include <iomanip>

#include<unordered_map>
#include<unordered_set>
//#include <arra.y>

//#define  NDEBUG
#include <assert.h>

using namespace std;

#define dprint(Exp,...) if(Exp){fprintf(stderr, __VA_ARGS__);}
#define printe(...) fprintf(stderr, __VA_ARGS__);
#define PrtExp(_Exp)  cerr<< #_Exp <<" = "<< (_Exp)
#define PrtExpN(_Exp)  cerr<< #_Exp <<" = "<< (_Exp) <<"\n"

#define SINT(n) scanf("%d",&n);
#define SINT2(n,m) scanf("%d %d",&n,&m);
#define SINT3(n,m,o) scanf("%d %d %d",&n,&m,&o);
#define SINT4(n,m,o,p) scanf("%d %d %d %d",&n,&m,&o,&p);
#define SINT5(n,m,o,p,q) scanf("%d %d %d %d %d",&n,&m,&o,&p,&q);
//#define SLL(n) scanf("%I64d",&n);
#define SLL(n) scanf("%lld",&n);
#define SLL2(n,m) scanf("%lld %lld",&n,&m);
#define SLL3(n,m,o) scanf("%lld %lld %lld",&n,&m,&o);
#define SST(s) scanf("%s",s);
#define SCH(c) scanf("%c",&c);

#define GC() getchar();

#define PINT(n) printf("%d",(int)(n));
#define PINT2(n,m) printf("%d %d",(int)(n),(int)(m));
#define PINT3(n,m,l) printf("%d %d %d",(int)(n),(int)(m),(int)(l));
//#define PLL(n) printf("%I64d",(long long)(n));
#define PLL(n) printf("%lld",(long long)(n));
#define PST(s) printf("%s",(s));
#define PCH(s) printf("%c",(s));

#define PINTN(n) printf("%d\n",(int)(n));
#define PINT2N(n,m) printf("%d %d\n",(int)(n),(int)(m));
#define PINT3N(n,m,l) printf("%d %d %d\n",(int)(n),(int)(m),(int)(l));
//#define PLLN(n) printf("%I64d\n",(long long)(n));
#define PLLN(n) printf("%lld\n",(long long)(n));
#define PSTN(s) printf("%s\n",(s));
#define PCHN(s) printf("%c\n",(s));

#define PSP() printf(" ");
#define PN() printf("\n");

#define PC(c) putchar(c);
#define CSP (' ')
#define SN ("\n")

#define rep(i,a) for(i=0;i<a;i++)
#define reP(i,a) for(i=0;i<=a;i++)
#define Rep(i,a) for(i=a-1;i>=0;i--)
#define ReP(i,a) for(i=a;i>=0;i--)

#define rEp(i,a) for(int i=0;i<a;i++)
#define rEP(i,a) for(int i=0;i<=a;i++)
#define REp(i,a) for(int i=a-1;i>=0;i--)
#define REP(i,a) for(int i=a;i>=0;i--)

#define repft(i,a,b) for(i=a;i<b;i++)
#define repfT(i,a,b) for(i=a;i<=b;i++)
#define Repft(i,a,b) for(i=a-1;i>=b;i--)
#define RepfT(i,a,b) for(i=a;i>=b;i--)

#define foreach(a,it) for(auto it = a.begin(); it != a.end(); ++it)

#define FILL(a,v) fill(begin(a),end(a), v)
#define FILL0(a) memset(a,0,sizeof(a))
#define FILL1(a) memset(a,-1,sizeof(a))

typedef long long ll;
typedef unsigned long ul;
typedef pair<int, int> Pi;
typedef pair<ll, ll>   Pl;


const int INF = 0x1f1f1f1f;//522,133,279
const ll INFLL = 0x1f1f1f1f1f1f1f1fLL;//2,242,545,357,980,376,863

template <class A, class B> inline ostream& operator<<(ostream& st, const pair<A, B>& P) { return st << "(" << P.first << "," << P.second << ")"; };
template <class A, class B> inline pair<A, B> operator+(const pair<A, B>& P, const pair<A, B>& Q) { return pair<A, B>(P.first + Q.first, P.second + Q.second); };
template <class A, class B> inline pair<A, B> operator-(const pair<A, B>& P, const pair<A, B>& Q) { return pair<A, B>(P.first - Q.first, P.second - Q.second); };

ll bitcount(ll bits) {
	bits = (bits & 0x5555555555555555) + (bits >>  1 & 0x5555555555555555);
	bits = (bits & 0x3333333333333333) + (bits >>  2 & 0x3333333333333333);
	bits = (bits & 0x0f0f0f0f0f0f0f0f) + (bits >>  4 & 0x0f0f0f0f0f0f0f0f);
	bits = (bits & 0x00ff00ff00ff00ff) + (bits >>  8 & 0x00ff00ff00ff00ff);
	bits = (bits & 0x0000ffff0000ffff) + (bits >> 16 & 0x0000ffff0000ffff);
	return (bits & 0x00000000ffffffff) + (bits >> 32 & 0x00000000ffffffff);
}



int main() {
	string s;
	int i,k;

	cin >> s;
	cin >> k;

	rep(i, s.length()-1) {
		if ('z' - s[i] < k) {
			k -= ('z' - s[i]) + 1;
			s[i] = 'a';
		}
	}
	k %= 26;

	s[s.length() - 1] += k;
	if (s[s.length() - 1] > 'z') s[s.length() - 1] -= 26;

	cout << s <<endl;

	return 0;
}