Problem:
Score : 100 points

Problem Statement

AtCoDeer has three cards, one red, one green and one blue.

An integer between 1 and 9 (inclusive) is written on each card: r on the red card, g on the green card and b on the blue card.

We will arrange the cards in the order red, green and blue from left to right, and read them as a three-digit integer.

Is this integer a multiple of 4?

Constraints

1 ≤ r, g, b ≤ 9

Input

Input is given from Standard Input in the following format:

r g b

Output

If the three-digit integer is a multiple of 4, print YES (case-sensitive); otherwise, print NO.

Sample Input 1

4 3 2

Sample Output 1

YES

432 is a multiple of 4, and thus YES should be printed.

Sample Input 2

2 3 4

Sample Output 2

NO

234 is not a multiple of 4, and thus NO should be printed.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <stack>
#include <deque>
#include <queue>
#include <algorithm>
#include <cmath>
#include <vector>
#include <cstdio>
#include <map>
#include <set>
using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
typedef pair<long long, long long> pll;
#define mp make_pair
#define fname ""
#define fi first
#define se second
#define sz(a) (int)a.size()
#define pb push_back
#define fo(i,k,n) for(int i=k; (int)i<n; ++i)
#define rep(i,n,k) for(int i=n; (int)i>=k; --i)
#define all(v) v.begin(), v.end()
#define it ::iterator
#define forit(it,v) for(__typeof(v.begin()) it = v.begin(); it != v.end(); ++it)


const int inf = (int)1e9;
const ll INF = (ll)1e18;
const double eps = 1e-9;
const double pi = acos(-1.0);
const int N = 100100;

int a,b,c;

int main(){
    
//freopen(fname"in", "r", stdin);
//freopen(fname"out", "w", stdout);

	cin>>a>>b>>c;

	int k = a*100 + b*10 + c;

	if(k%4 == 0)
		printf("YES");
	else
		printf("NO");
    
    return 0;
}