Problem:
Score : 200 points

Problem Statement

Rng is preparing a problem set for a qualification round of CODEFESTIVAL.

He has N candidates of problems. The difficulty of the i-th candidate is D_i.

There must be M problems in the problem set, and the difficulty of the i-th problem must be T_i. Here, one candidate of a problem cannot be used as multiple problems.

Determine whether Rng can complete the problem set without creating new candidates of problems.

Constraints

1 \leq N \leq 200,000

1 \leq D_i \leq 10^9

1 \leq M \leq 200,000

1 \leq T_i \leq 10^9

All numbers in the input are integers.

Partial Score

100 points will be awarded for passing the test set satisfying N \leq 100 and M \leq 100.

Input

Input is given from Standard Input in the following format:

N
D_1 D_2 ... D_N
M
T_1 T_2 ... T_M

Output

Print YES if Rng can complete the problem set without creating new candidates of problems; print NO if he cannot.

Sample Input 1

5
3 1 4 1 5
3
5 4 3

Sample Output 1

YES

Sample Input 2

7
100 200 500 700 1200 1600 2000
6
100 200 500 700 1600 1600

Sample Output 2

NO

Not enough 1600s.

Sample Input 3

1
800
5
100 100 100 100 100

Sample Output 3

NO

Sample Input 4

15
1 2 2 3 3 3 4 4 4 4 5 5 5 5 5
9
5 4 3 2 1 2 3 4 5

Sample Output 4

YES

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;
struct Fast { Fast() { cin.tie(0); ios::sync_with_stdio(false); cout << fixed << setprecision(20);} } fast;

long long mod = 1000000007;

long long div(long long a, long long b, long long c){
    return b / c - (a - 1) / c;
}

void print_binary(long long a) {
    for (int i = 31; i >= 0; i--) {
        cout << (a >> i & 1);
    }
    cout << endl;
}


int main() {
    long long n, m, a, b;
    cin >> n;
    //set<long long> s;
    set<long long> ss;
    for (int i = 0; i < n; i++){
        cin >> a;
        ss.insert(a);
    }
    cin >> m;
    if (m > n){
        cout << "NO" << endl;
        return 0;
    }
    for (int i = 0; i < m; i++){
        cin >> b;
        if (ss.count(b)) {
            ss.erase(ss.find(b));
            continue;
        }else{
            cout << "NO" << endl;
            return 0;
        }
    }
    cout << "YES" << endl;
}