Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;

#define ll long long
#define mod 1000000007
#define pb push_back
#define pi pair<int,int>
#define vi vector<int>
#define vpi vector< pi > 
#define IOS ios_base::sync_with_stdio(false),cin.tie(NULL)
const int N=200002,M=11;
int a[N],b[N],c[N],h[N];
string s[N];
int r[3];
int main()
{
	ll n,A,B,C;
	cin>>n>>A>>B>>C;
	r[0]=A;r[1]=B;r[2]=C;
	if(A==0&&B==0&&C==0)
	{
		if(n) cout<<"No";
		else cout<<"Yes";
		return 0;
	}
	for(int i=1;i<=n;i++)
	cin>>s[i];
	// a[n+1]=n+1;
	// b[n+1]=n+1;
	// c[n+1]=n+1;
	// for(int i=n;i>=1;i--)
	// {
	// 	a[i]=a[i+1];
	// 	b[i]=b[i+1];
	// 	c[i]=c[i+1];
	// 	if(s[i][0]=='A'||s[i][1]=='A')
	// 		a[i]=i;
	// 	if(s[i][0]=='B'||s[i][1]=='B')
	// 		b[i]=i;
	// 	if(s[i][0]=='C'||s[i][1]=='C')
	// 		c[i]=i;
	// }
	vector<char> v;
	for(int i=1;i<=n;i++)
	{
		int x=s[i][0]-'A';
		int y=s[i][1]-'A';
		if(r[x]+r[y]==0)
		{
			return cout<<"No",0;
		}
		if(r[x]<r[y])
		{
			v.pb(x+'A');r[x]++;r[y]--;
		}
		else if(r[y]<r[x])
		{
			v.pb(y+'A');r[y]++;r[x]--;
		}
		else
		{
			if(i==n)
			{
				v.pb(x+'A');
				break;
			}
			if(s[i+1][0]==s[i][0]||s[i+1][1]==s[i][0])
			{
				v.pb(x+'A');
				r[x]++;
				r[y]--;
			}
			else
			{
				v.pb(y+'A');r[y]++;r[x]--;
			}
		}
	}
	cout<<"Yes\n";
	for(char c:v) cout<<c<<"\n";

	
	return 0;
}