Problem:
Score : 200 points

Problem Statement

There are N cities and M roads.
The i-th road (1≤i≤M) connects two cities a_i and b_i (1≤a_i,b_i≤N) bidirectionally.
There may be more than one road that connects the same pair of two cities.
For each city, how many roads are connected to the city?

Constraints

2≤N,M≤50

1≤a_i,b_i≤N

a_i ≠ b_i

All input values are integers.

Input

Input is given from Standard Input in the following format:

N M
a_1 b_1
:
a_M b_M

Output

Print the answer in N lines.
In the i-th line (1≤i≤N), print the number of roads connected to city i.

Sample Input 1

4 3
1 2
2 3
1 4

Sample Output 1

2
2
1
1

City 1 is connected to the 1-st and 3-rd roads.

City 2 is connected to the 1-st and 2-nd roads.

City 3 is connected to the 2-nd road.

City 4 is connected to the 3-rd road.

Sample Input 2

2 5
1 2
2 1
1 2
2 1
1 2

Sample Output 2

5
5

Sample Input 3

8 8
1 2
3 4
1 5
2 8
3 7
5 2
4 1
6 8

Sample Output 3

3
3
2
2
2
1
1
2

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

//#include<bits/stdc++.h>
#include<iostream>
#include<cmath>
#include<cstdio>
#include<vector>
#include<set>
#include<map>
#include<stack>
#include<queue>
#include<utility>
#include<algorithm>
#include<cstring>
#include<sstream>
#include <iomanip>

using namespace std;

typedef long long ll ;
typedef double db;
typedef vector<int> vi;
typedef pair<int,int> pii;
typedef vector< pair<int,int> > vii;
const double pi = 2*acos(0) ;

#define pf		  	printf
#define sf			  scanf
#define pb(a)         push_back(a)
#define mp			make_pair
#define fi			 first
#define se			 second
#define for0(i,n)        for(int i=0;i<n;i++)
#define for1(i,n)        for(int i=1;i<=n;i++)
#define forab(i,a,b)       for(int i=a;i<=b;i++)
#define lcm(a, b)     ((a)*((b)/gcd(a,b)))
#define sq(a)		   (a)*(a)
#define nw				"\n"
#define abs(x)		fabs(x)
#define pcase(z,x)    cout<<"Case "<<z<<": "<<x<<"\n"
int main()
{
	int n,m;
	cin>>n>>m;
	vi d(n+1,0);
	int x,y;
	for0(i,m){
		cin>>x>>y;
		d[x]++;
		d[y]++;
		}
	for1(i,n)cout<<d[i]<<nw;
	
	return 0;
}