Problem:
Score : 400 points

Problem Statement

An altar enshrines N stones arranged in a row from left to right. The color of the i-th stone from the left (1 \leq i \leq N) is given to you as a character c_i; R stands for red and W stands for white.

You can do the following two kinds of operations any number of times in any order:

Choose two stones (not necessarily adjacent) and swap them.

Choose one stone and change its color (from red to white and vice versa).

According to a fortune-teller, a white stone placed to the immediate left of a red stone will bring a disaster. At least how many operations are needed to reach a situation without such a white stone?

Constraints

2 \leq N \leq 200000

c_i is R or W.

Input

Input is given from Standard Input in the following format:

N
c_{1}c_{2}...c_{N}

Output

Print an integer representing the minimum number of operations needed.

Sample Input 1

4
WWRR

Sample Output 1

2

For example, the two operations below will achieve the objective.

Swap the 1-st and 3-rd stones from the left, resulting in RWWR.

Change the color of the 4-th stone from the left, resulting in RWWW.

Sample Input 2

2
RR

Sample Output 2

0

It can be the case that no operation is needed.

Sample Input 3

8
WRWWRWRR

Sample Output 3

3

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
typedef long long int ll;
ll mod=1000000007;


int main(){
    mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
	cout.tie(NULL);
    ll t,i,q,j,x,y,k,temp,temp2,z,l,tt,n,m,sum=0;
    cin >> n;
    string a;
    cin >> a;
    ll w=0;
    for(i=0;i<n;i++){
        if(a[i]=='W') w++;
    }
    ll ans=0;
    for(i=n-1;i>=0;i--){
        if(w==0) break;
        else if(a[i]=='R') ans++;
        w--;
    }
    cout << ans << endl;
}