Problem:
Score : 400 points

Problem Statement

There are N persons called Person 1 through Person N.

You are given M facts that "Person A_i and Person B_i are friends." The same fact may be given multiple times.

If X and Y are friends, and Y and Z are friends, then X and Z are also friends. There is no friendship that cannot be derived from the M given facts.

Takahashi the evil wants to divide the N persons into some number of groups so that every person has no friend in his/her group.

At least how many groups does he need to make?

Constraints

2 \leq N \leq 2\times 10^5

0 \leq M \leq 2\times 10^5

1\leq A_i,B_i\leq N

A_i \neq B_i

Input

Input is given from Standard Input in the following format:

N M
A_1 B_1
\vdots
A_M B_M

Output

Print the answer.

Sample Input 1

5 3
1 2
3 4
5 1

Sample Output 1

3

Dividing them into three groups such as \{1,3\}, \{2,4\}, and \{5\} achieves the goal.

Sample Input 2

4 10
1 2
2 1
1 2
2 1
1 2
1 3
1 4
2 3
2 4
3 4

Sample Output 2

4

Sample Input 3

10 4
3 1
4 1
5 9
2 6

Sample Output 3

3

Solution in C++ (GCC 9.2.1) (judge verdict: Runtime Error)

#include<bits/stdc++.h>
using namespace std;

#define rep(i, n) for(int (i) = 0; (i) < (n); (i)++)
#define repp(i, n, m) for(int (i) = (n); (i) < (m); (i)++)
#define repn(i, n) for(int (i) = 1; (i) <= (n); (i)++)
#define repr(i, n) for(int (i) = (n-1); (i) >= 0; (i)--)
#define all(x) (x).begin(), (x).end()
#define lint long long
#define ulint unsigned long long
#define ldou long double
#define fi first
#define se second
#define setpre(x) std::cout << fixed << setprecision(x)
#define ii(x) int x; cin >> (x)
#define ii2(x, y) int x, y; cin >> (x) >> (y)
#define ii3(x, y, z) int x, y, z; cin >> (x) >> (y) >> (z)
#define out(x) cout << (x) << endl
#define outs(x) cout << (x) << " "
#define yn(x) cout << ((x)?("Yes"):("No")) << endl
#define YN(x) cout << ((x)?("YES"):("NO")) << endl
#define bit_c(x) __builtin_popcountll(x)

inline void logger(){ std::cout << " [LOGGER] " << endl; }
template<typename A, typename... B>
void logger(const A& a, const B&... b){
    cout << a << " , "; logger(b...);
}

typedef pair<lint, lint> P;
const lint MOD = 1000000007;
const lint MOD9 = 998244353;
const lint INF = MOD * MOD;
const int MAX = 100005;

/* ...o(^-^)o... */

vector<int> to[MAX];
bool seen[MAX];

int dfs(int s){
    seen[s] = true;
    int tmp = 1;
    for(auto t : to[s]){
        if(seen[t]) continue;
        tmp += dfs(t);
    }
    return tmp;
}

int main(){
    int n,m; cin >> n >> m;
    rep(i, m){
        int a, b; cin >> a >> b;
        a--; b--;
        to[a].push_back(b);
        to[b].push_back(a);
    }

    int ans = 0;
    rep(i, n){
        if(seen[i]) continue;
        seen[i] = true;
        int connect = dfs(i);
        ans = max(connect, ans);
    }
    out(ans);
}