Problem:
Score : 100 points

Problem Statement

The door of Snuke's laboratory is locked with a security code.

The security code is a 4-digit number. We say the security code is hard to enter when it contains two consecutive digits that are the same.

You are given the current security code S. If S is hard to enter, print Bad; otherwise, print Good.

Constraints

S is a 4-character string consisting of digits.

Input

Input is given from Standard Input in the following format:

S

Output

If S is hard to enter, print Bad; otherwise, print Good.

Sample Input 1

3776

Sample Output 1

Bad

The second and third digits are the same, so 3776 is hard to enter.

Sample Input 2

8080

Sample Output 2

Good

There are no two consecutive digits that are the same, so 8080 is not hard to enter.

Sample Input 3

1333

Sample Output 3

Bad

Sample Input 4

0024

Sample Output 4

Bad

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#include <unistd.h>
#include <random>

using namespace std;
typedef long long int LL;
typedef long long int LLint;
typedef pair<int,int> intpair;
typedef pair<bool,bool> boolpair;
typedef pair<string,string> strpair;
typedef pair<LL,LL> LLpair;
typedef pair<double,double> doublepair;
typedef pair<float,float> floatpair;
typedef vector<int> intvector;
typedef vector<bool> boolvector;
typedef vector<string> strvector;
typedef vector<LL> LLvector;
typedef vector<double> doublevector;
typedef vector<float> floatvector;
#define wait(sec) usleep((sec) * 1000000)
#define ED return 0;
#define TEST cout << "OK" << endl;
#define UP(a,b) ((a+(b-1))/b)
#define SORT(vec) sort(vec.begin(),vec.end())
#define DOUBLECHANGE(count) cout << setprecision(count)
#define REV(vec) reverse(vec.begin(),vec.end())
#define ipow(x,y) LL(pow(x,y))
#define INF 999999999
const long long mod = 1000000007;

int main(){
//    random_device rnd;
//    mt19937 mt(rnd());
      cin.tie(0);
      ios::sync_with_stdio(false);
      string s;
      cin >> s;
      if(s[0]==s[1] || s[1]==s[2] || s[2]==s[3]){
          cout << "Bad" << endl;
      }
      else{
          cout << "Good" << endl;
      }
}