Problem:
Score : 200 points

Problem Statement

Let us define the FizzBuzz sequence a_1,a_2,... as follows:

If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.

If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.

If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.

If none of the above holds, a_i=i.

Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Constraints

1 \leq N \leq 10^6

Input

Input is given from Standard Input in the following format:

N

Output

Print the sum of all numbers among the first N terms of the FizzBuzz sequence.

Sample Input 1

15

Sample Output 1

60

The first 15 terms of the FizzBuzz sequence are:

1,2,\mbox{Fizz},4,\mbox{Buzz},\mbox{Fizz},7,8,\mbox{Fizz},\mbox{Buzz},11,\mbox{Fizz},13,14,\mbox{FizzBuzz}

Among them, numbers are 1,2,4,7,8,11,13,14, and the sum of them is 60.

Sample Input 2

1000000

Sample Output 2

266666333332

Watch out for overflow.

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include<bits/stdc++.h>
#include<stdio.h>
#define debug(x) cout << '>' << #x << ':' << x << endl;

#define nitro ios_base::sync_with_stdio(false),cin.tie(NULL),cout.tie(NULL);
const int INF = 1e9+5;
using namespace std;
using ll = unsigned long long int;
const ll mod = 998244353; 
int main() {
	// your code goes here
	
	//freopen("input.txt","r",stdin);freopen("output.txt","w",stdout);
	int n;cin>>n;
	ll total = 0 ;
	ll temp = 0;
	for(int i = 1; i <= n ; i++)
	{
		if(i%3==0 && i%5==0)
		{
			total+=temp;
			temp = 0;
		}
		if((i%3)!=0 && (i%5)!=0)
		{
			temp+=i;
		}
	}
	cout<<total;
	
}