Problem:
Score : 100 points

Problem Statement

Takahashi is meeting up with Aoki.

They have planned to meet at a place that is D meters away from Takahashi's house in T minutes from now.

Takahashi will leave his house now and go straight to the place at a speed of S meters per minute.

Will he arrive in time?

Constraints

1 \leq D \leq 10000

1 \leq T \leq 10000

1 \leq S \leq 10000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

D T S

Output

If Takahashi will reach the place in time, print Yes; otherwise, print No.

Sample Input 1

1000 15 80

Sample Output 1

Yes

It takes 12.5 minutes to go 1000 meters to the place at a speed of 80 meters per minute. They have planned to meet in 15 minutes so he will arrive in time.

Sample Input 2

2000 20 100

Sample Output 2

Yes

It takes 20 minutes to go 2000 meters to the place at a speed of 100 meters per minute. They have planned to meet in 20 minutes so he will arrive just on time.

Sample Input 3

10000 1 1

Sample Output 3

No

He will be late.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;
#define rep(i,n) for (int i = 0; i < (n); ++i)
#define dup(x,y) (((x)+(y)-1)/(y))
#define ALL(x) (x).begin(), (x).end()
typedef long long ll;
typedef pair<int, int> pii;
const double EPS = 1e-10;
const int INF = 1e9;
const ll LINF = 1e15;
const int MOD = 1000000007;
const double PI = acos(-1);
int dx[4] = {0,1,0,-1};
int dy[4] = {1,0,-1,0};

typedef pair<ll, ll> pll;

int main() {
	int n;
	double d, t, s;
	cin >> d >> t >> s;
	
	double a = d / s;
	if(a <= t){
	    cout << "Yes" << endl;
	}else{
	    cout << "No" << endl;
	}
}