Problem:
Score : 200 points

Problem Statement

An integer N is a multiple of 9 if and only if the sum of the digits in the decimal representation of N is a multiple of 9.

Determine whether N is a multiple of 9.

Constraints

0 \leq N < 10^{200000}

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a multiple of 9, print Yes; otherwise, print No.

Sample Input 1

123456789

Sample Output 1

Yes

The sum of these digits is 1+2+3+4+5+6+7+8+9=45, which is a multiple of 9, so 123456789 is a multiple of 9.

Sample Input 2

0

Sample Output 2

Yes

Sample Input 3

31415926535897932384626433832795028841971693993751058209749445923078164062862089986280

Sample Output 3

No

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;

typedef long long ll;
typedef unsigned long long ull;
typedef double dd;
typedef vector<int> vi;
typedef vector<ll> vl;
typedef pair<int,int> pii;

const int mx=1e6+11;
const double PI = acos(-1);
#define MOD 1000000007


#define nl '\n'
#define pb push_back
#define F first
#define S second
#define I insert
#define mp make_pair

#define sz(x) x.size()
#define tt int t; cin>>t; while(t--)
#define lo(i,a,b) for(int i=a;i<b;i++)
#define rlo(i,n) for(int i=n-1;i>=0;i--)
#define be(a) (a).begin(),(a).end()
#define rbe(a) (a).rbegin(),(a).rend()
#define mem(a,b) memset(a,b,sizeof(a))
#define pr(a) {for(auto x:a)cout<<x<<" ";cout<<nl;}
#define yes cout<<"Yes"<<nl
#define no cout<<"No"<<nl
#define su ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define file freopen("input.txt","r",stdin);freopen("output.txt","w",stdout);
#define frac cout.unsetf(ios::floatfield); cout.precision(10); cout.setf(ios::fixed,ios::floatfield);

#define dbg(args...) do {cerr << #args << " : "; faltu(args); } while(0)
void faltu () {            cerr << endl;}
template < typename T, typename ... hello>void faltu( T arg, const hello &... rest) {cerr << arg << ' ';faltu(rest...);}

void f()
{
  string s;
  int r=0;
  cin>>s;
  for(int i=0;i<sz(s);i++)
  {
    r+=(s[i]-'0')%9;
  }
  if(r%9==0)
    yes;
  else
    no;
}

int main()
{
    su;
    f();
    return 0;
}