Problem:
Score : 600 points

Problem Statement

Given is an integer N. Snuke will choose integers s_1, s_2, n_1, n_2, u_1, u_2, k_1, k_2, e_1, and e_2 so that all of the following six conditions will be satisfied:

0 \leq s_1 < s_2

0 \leq n_1 < n_2

0 \leq u_1 < u_2

0 \leq k_1 < k_2

0 \leq e_1 < e_2

s_1 + s_2 + n_1 + n_2 + u_1 + u_2 + k_1 + k_2 + e_1 + e_2 \leq N

For every possible choice (s_1,s_2,n_1,n_2,u_1,u_2,k_1,k_2,e_1,e_2), compute (s_2 − s_1)(n_2 − n_1)(u_2 − u_1)(k_2 - k_1)(e_2 - e_1), and find the sum of all computed values, modulo (10^{9} +7).

Solve this problem for each of the T test cases given.

Constraints

All values in input are integers.

1 \leq T \leq 100

1 \leq N \leq 10^{9}

Input

Input is given from Standard Input in the following format:

T
\mathrm{case}_1
\vdots
\mathrm{case}_T

Each case is given in the following format:

N

Output

Print T lines. The i-th line should contain the answer to the i-th test case.

Sample Input 1

4
4
6
10
1000000000

Sample Output 1

0
11
4598
257255556

When N=4, there is no possible choice (s_1,s_2,n_1,n_2,u_1,u_2,k_1,k_2,e_1,e_2). Thus, the answer is 0.

When N=6, there are six possible choices (s_1,s_2,n_1,n_2,u_1,u_2,k_1,k_2,e_1,e_2) as follows:

(0,1,0,1,0,1,0,1,0,1)

(0,2,0,1,0,1,0,1,0,1)

(0,1,0,2,0,1,0,1,0,1)

(0,1,0,1,0,2,0,1,0,1)

(0,1,0,1,0,1,0,2,0,1)

(0,1,0,1,0,1,0,1,0,2)

We have one choice where (s_2 − s_1)(n_2 − n_1)(u_2 − u_1)(k_2 - k_1)(e_2 - e_1) is 1 and five choices where (s_2 − s_1)(n_2 − n_1)(u_2 − u_1)(k_2 - k_1)(e_2 - e_1) is 2, so the answer is 11.

Be sure to find the sum modulo (10^{9} +7).

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define int long long int
const int MOD=1000000007;


int add(int x, int y)
{
	return (x + y) % MOD;
}

int sub(int x, int y)
{
	return add(x, MOD - y);
}

int mul(int x, int y)
{
	return (x * 1ll * y) % MOD;
}

int binpow(int x, int y)
{
	int z = 1;
	while(y > 0)
	{
		if(y % 2 == 1)
			z = mul(z, x);
		x = mul(x, x);
		y /= 2;
	}
	return z;
}

int inv(int x)
{
	return binpow(x, MOD - 2);
}

int C(int n, int r){
	if(n==r || r==0){
		return 1;
	}
	int ans=1;
	for(int i=n; i>n-r; i--){
		ans=mul(ans, i);
	}
	for(int i=1; i<=r; i++){
		ans=mul(ans, inv(i));
	}
	return ans;
}


main() {
	int t;
	cin>>t;
	while(t--){
		int n;
		cin>>n;
		int val=n-5;
		if(val<0){
			cout<<0<<endl;
			continue;
		}
		int ans=0;
		for(int i=0; i<=11; i++){
			int rem=val-(i);
			if(rem<0 || rem%2==1){
				continue;
			}
			int po2=rem/2;
			int ad=1;
			ad=mul(ad, C(11, i));
			ad=mul(ad, C(15+po2, 15));
			ans=add(ans, ad);
		}
		cout<<ans<<endl;
	}
	return 0;
}