Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<bits/stdc++.h>
using namespace std;
void solve()
{
    set <int>r[3],c[3],d[2];
    int i,j,n,b,k;
    for(i=0;i<3;++i)
        {
            for(j=0;j<3;j++)
            {
                cin>>k;
                r[i].insert(k);
                c[j].insert(k);
                if(i==j)
                    d[0].insert(k);
                if(i+j==2)
                    d[1].insert(k);
            }
        }
    cin>>n;
    while(n--)
    {
        cin>>b;
        for(i=0;i<3;++i)
            {
                r[i].erase(b);
                if(r[i].empty())
                    {
                        cout<<"YES\n";
                        return ;
                    }
            }
        for(j=0;i<3;++j)
            {
                c[j].erase(b);
                if(c[j].empty())
                    {
                        cout<<"YES\n";
                        return ;
                    }
            }
        for(i=0;i<2;++i)
            {
                d[i].erase(b);
                if(d[i].empty())
                    {
                        cout<<"YES\n";
                        return ;
                    }
            }
    }
    cout<<"NO\n";
    return;
}
signed main()
{
    ios_base::sync_with_stdio(0);
    cin.tie(0);cout.tie(0);
    // int _t;cin>>_t;while(_t--)
    solve();
}