Problem:
Score : 200 points

Problem Statement

Rng is preparing a problem set for a qualification round of CODEFESTIVAL.

He has N candidates of problems. The difficulty of the i-th candidate is D_i.

There must be M problems in the problem set, and the difficulty of the i-th problem must be T_i. Here, one candidate of a problem cannot be used as multiple problems.

Determine whether Rng can complete the problem set without creating new candidates of problems.

Constraints

1 \leq N \leq 200,000

1 \leq D_i \leq 10^9

1 \leq M \leq 200,000

1 \leq T_i \leq 10^9

All numbers in the input are integers.

Partial Score

100 points will be awarded for passing the test set satisfying N \leq 100 and M \leq 100.

Input

Input is given from Standard Input in the following format:

N
D_1 D_2 ... D_N
M
T_1 T_2 ... T_M

Output

Print YES if Rng can complete the problem set without creating new candidates of problems; print NO if he cannot.

Sample Input 1

5
3 1 4 1 5
3
5 4 3

Sample Output 1

YES

Sample Input 2

7
100 200 500 700 1200 1600 2000
6
100 200 500 700 1600 1600

Sample Output 2

NO

Not enough 1600s.

Sample Input 3

1
800
5
100 100 100 100 100

Sample Output 3

NO

Sample Input 4

15
1 2 2 3 3 3 4 4 4 4 5 5 5 5 5
9
5 4 3 2 1 2 3 4 5

Sample Output 4

YES

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<iostream>	// 入出力
#include<stdio.h>	// printf()が使える 小数は%fで
#include<math.h>	// 数学の関数
#include<vector>	// 配列
#include<string>	// 文字列
#include<map>		// 連想配列
#include<stack>		// スタック
#include<queue>		// キュー
#include<algorithm> // ソートとか

using namespace std;

using ll = long long;


int main()
{

	int N, M;

	cin >> N;

	map<int, int> mp;

	for (int i = 0; i < N; ++i)
	{

		int D; cin >> D;

		auto itr = mp.find(D);

		if (itr != mp.end())
		{
			mp[D]++;
		}
		else
		{
			mp[D] = 1;
		}

	}

	cin >> M;

	for (int i = 0; i < M; ++i)
	{

		int T; cin >> T;

		auto itr = mp.find(T);

		if (itr != mp.end())
		{
			if (mp[T] == 0)
			{
				cout << "NO" << endl; return 0;
			}

			mp[T]--;
		}
		else
		{
			cout << "NO" << endl; return 0;
		}
		
	}


	cout << "YES" << endl;

	return 0;

}