Problem:
Score : 200 points

Problem Statement

There are N cities and M roads.
The i-th road (1≤i≤M) connects two cities a_i and b_i (1≤a_i,b_i≤N) bidirectionally.
There may be more than one road that connects the same pair of two cities.
For each city, how many roads are connected to the city?

Constraints

2≤N,M≤50

1≤a_i,b_i≤N

a_i ≠ b_i

All input values are integers.

Input

Input is given from Standard Input in the following format:

N M
a_1 b_1
:
a_M b_M

Output

Print the answer in N lines.
In the i-th line (1≤i≤N), print the number of roads connected to city i.

Sample Input 1

4 3
1 2
2 3
1 4

Sample Output 1

2
2
1
1

City 1 is connected to the 1-st and 3-rd roads.

City 2 is connected to the 1-st and 2-nd roads.

City 3 is connected to the 2-nd road.

City 4 is connected to the 3-rd road.

Sample Input 2

2 5
1 2
2 1
1 2
2 1
1 2

Sample Output 2

5
5

Sample Input 3

8 8
1 2
3 4
1 5
2 8
3 7
5 2
4 1
6 8

Sample Output 3

3
3
2
2
2
1
1
2

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <string>
#include <vector>
#include <algorithm>
#include <cstdio>
#include <numeric>
#include <cmath>
#include <map>
#define ull unsigned long long
#define ll long long
using namespace std;

int main(){
    cin.tie(0);
    ios::sync_with_stdio(false);
    int n,m,a,b;
    cin >> n >> m;
    vector<pair<int,int>> w;
    for(int i=0;i<m;i++){
        cin >> a >> b;
        w.push_back(make_pair(a,b));
    }
    vector<int> p(n,0);
    for(int i=0;i<m;i++){
        p[w[i].first-1]++;
        p[w[i].second-1]++;
    }
    for(int i=0;i<n;i++){
        cout << p[i] << endl;
    }

    return 0;
}