Problem:
Score : 400 points

Problem Statement

Snuke has N strings. The i-th string is s_i.

Let us concatenate these strings into one string after arranging them in some order.
Find the maximum possible number of occurrences of AB in the resulting string.

Constraints

1 \leq N \leq 10^{4}

2 \leq |s_i| \leq 10

s_i consists of uppercase English letters.

Input

Input is given from Standard Input in the following format:

N
s_1
\vdots
s_N

Output

Print the answer.

Sample Input 1

3
ABCA
XBAZ
BAD

Sample Output 1

2

For example, if we concatenate ABCA, BAD and XBAZ in this order, the resulting string ABCABADXBAZ has two occurrences of AB.

Sample Input 2

9
BEWPVCRWH
ZZNQYIJX
BAVREA
PA
HJMYITEOX
BCJHMRMNK
BP
QVFABZ
PRGKSPUNA

Sample Output 2

4

Sample Input 3

7
RABYBBE
JOZ
BMHQUVA
BPA
ISU
MCMABAOBHZ
SZMEHMA

Sample Output 3

4

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <algorithm>
using namespace std;
int main(){
  int n;
  cin >> n;
  string s[n];
  int ans = 0,a=0,b=0,w=0;
  for(int i=0;i<n;i++){
    cin >> s[i];
    for(int j=0;j<s[i].length()-1;j++){
      if(s[i][j]=='A'&&s[i][j+1]=='B'){
        ans++;
      }
    }
    if(s[i][0]=='B'&&s[i][s[i].length()-1]=='A') w++;
    else if(s[i][0]=='B') b++;
    else if(s[i][s[i].length()-1]=='A') a++;
  }
  cout << ans+min(a+w,b+w) << endl;
}