Problem:
Score: 500 points

Problem Statement

We have caught N sardines. The deliciousness and fragrantness of the i-th sardine is A_i and B_i, respectively.

We will choose one or more of these sardines and put them into a cooler. However, two sardines on bad terms cannot be chosen at the same time.

The i-th and j-th sardines (i \neq j) are on bad terms if and only if A_i \cdot A_j + B_i \cdot B_j = 0.

In how many ways can we choose the set of sardines to put into the cooler? Since the count can be enormous, print it modulo 1000000007.

Constraints

All values in input are integers.

1 \leq N \leq 2 \times 10^5

-10^{18} \leq A_i, B_i \leq 10^{18}

Input

Input is given from Standard Input in the following format:

N
A_1 B_1
:
A_N B_N

Output

Print the count modulo 1000000007.

Sample Input 1

3
1 2
-1 1
2 -1

Sample Output 1

5

There are five ways to choose the set of sardines, as follows:

The 1-st

The 1-st and 2-nd

The 2-nd

The 2-nd and 3-rd

The 3-rd

Sample Input 2

10
3 2
3 2
-1 1
2 -1
-3 -9
-8 12
7 7
8 1
8 2
8 4

Sample Output 2

479

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#define __mode_debug__
/*   ξ
     ll
   ＿ll＿
 ／  ∞  ＼
│*  Ａ  *│
│*  Ｃ  *│
│*  祈  *│
│*  願  *│
│*      *│
 ￣￣￣￣￣    */
//C++14 (GCC 5.4.1)
#include <bits/stdc++.h>
using namespace std;
#ifdef __mode_debug__
    #define DBG
#else
    #define DBG if(false)
#endif

#define LLINF (1LL<<60)
using ll = long long;
#define mod  1000000007

#define whole(a) (a).begin(),(a).end()
#define rwhole(a) (a).rbegin(),(a).rend()

#define repd(i,a,b) for (ll i=(a);i<(b);i++)
#define rep(i,n) repd(i,0,n)
#define rrepd(i,a,b) for(ll i=(a);i>=(b);i--)
#define each(itr,ds) for(auto itr=(ds).begin();itr!=(ds).end();itr++)

template<typename T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
template<typename T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }

template < typename T > inline string toString( const T &a ) { ostringstream oss; oss << a; return oss.str(); }

//DUMP
//  ostream vector<T> , vector<vector<T>> , set<T> ,queue<T> , priority_queue<T> , pair<T,U> , map<T,U>
template<class T> ostream& operator<<(ostream&os,vector<T>&vec){os<<"{ ";rep(i,vec.size()) os<<((i==0)?"":", ")<<i<<":"<<vec[i];os<<" }";return os;}
template<class T> ostream& operator<<(ostream&os,vector<vector<T>>&vec){os<<"{"<<endl;rep(i,vec.size())os<<"\t   "<<i<<":"<<vec[i]<<((i==vec.size()-1)? "":",")<<endl;os<<"\t }";return os;}
template<class T> ostream& operator<<(ostream&os,set<T>&p){os<<"{ ";each(itr,p)  os<<((itr==p.begin())?"":", ")<<*itr;os<<" }";return os;}
template<class T> ostream& operator<<(ostream&os,queue<T>&p){queue<T> q(p);os<<"[< "<<(q.empty()?" <]":"");while(!q.empty()){os<<q.front();q.pop();os<< (q.empty() ? " <]" : ", ");}return os;}
template<class T> ostream& operator<<(ostream&os,priority_queue<T>&p){priority_queue<T> q(p);os<<"[< "<<(q.empty()?" <]":"");while(!q.empty()){os<<q.top();q.pop();os<< (q.empty() ? " <]" : ", ");}return os;}
template<class T,class U> ostream& operator<<(ostream&os,pair<T,U>&p){os<<"("<<p.first<<","<<p.second<<")";return os;}
template<class T,class U> ostream& operator<<(ostream&os,map<T,U>&p){os<<"{ ";each(itr,p)os<<((itr==p.begin())?"":", ")<<itr->first<<":"<<itr->second;os<<" }";return os;}
void dump_f(string &nm,char t){cerr<<endl;}
template<class T,class... Ts> void dump_f(string &nm,char t,T &&x,Ts&&... ts){int l=nm.find_first_of(',');string name(nm,0,l),nx(nm,l+1,-1);if(t=='\n') cerr<<"  "<<name<<"\t: "<<x<<t;else cerr << name<<": "<<x<<","<<t;dump_f(nx,t,forward<Ts>(ts)...);}
template<class... Ts> void dump_m(int &&ln,string &&nm,char t,Ts&&... ts){cerr<<"[ln: "<<ln<<"]"<<t;dump_f(nm,t,forward<Ts>(ts)...);}
#define dump(...) DBG dump_m(__LINE__,#__VA_ARGS__,'\n',__VA_ARGS__)
#define dl(...) DBG dump_m(__LINE__,#__VA_ARGS__,'\t',__VA_ARGS__)

#define lower_bound_idx(V,c) distance(V.begin(),lower_bound(whole(V),c))

pair<ll,ll> mkr2(ll a,ll b){
    if(a==0) return make_pair(0,1);
    else if(b==0) return make_pair(1,0);
    else{
        ll t=std::gcd(a,b);
        ll c=(a>=0 && b>=0 || a<=0 && b<=0)? 1 : -1;
        return make_pair(c*abs(a)/t,abs(b)/t);
    }
}

template <class T1, class T2>
class hash<pair<T1,T2>> {
public:
    size_t operator()(const pair<T1, T2>& p) const{

        auto hash1 = hash<T1>{}(p.first);
        auto hash2 = hash<T2>{}(p.second);

        size_t seed = 0;
        seed ^= hash1 + 0x9e3779b9 + (seed << 6) + (seed >> 2);
        seed ^= hash2 + 0x9e3779b9 + (seed << 6) + (seed >> 2);
        seed ^= m_hash_pair_random + 0x9e3779b9 + (seed << 6) + (seed >> 2);
        return seed;
    }
private:
    size_t m_hash_pair_random = (size_t) random_device()();
};

ll powmod(ll x,ll n){
    ll ans=1,y=x;
    ll k=n;
    while(k){
        if(k&1) ans= (ans*y)%mod;
        y=(y*y)%mod;
        k/=2;
    }
    return ans;
}

int main() {
    ios::sync_with_stdio(false);//printf<=>cout
    cin.tie(nullptr);//cin<=>cout


    ll N;
    cin >>N;
    std::unordered_map<pair<ll,ll>,ll> hog;
    ll t,a,b;
    rep(i,N){
        cin >> a >> b;
        hog[mkr2(a,b)]++;
    }

    //-----------------------------------
    ll ans =1;
    each(itr,hog){
        const ll ai=itr->first.first,bi=itr->first.second, ci=itr->second;
        const ll cj=hog[mkr2(-bi,ai)];
        ll t=0;
        //dl(ai,bi,ci,cj);

        if(ai==0 && bi==0){
            ans*=2;
            ans%=mod;
        }else{

            t+=powmod(2,ci)-1;
            t+=powmod(2,cj)-1;
            t++;
            ans*=t;
            ans%=mod;

            itr->second=0;
            hog[mkr2(-bi,ai)]=0;

        }

    }

    ans--;
    if(ans<0)ans+=mod;

    cout << ans <<'\n';


    return (0);
}