Problem:
Score : 200 points

Problem Statement

Find the number of palindromic numbers among the integers between A and B (inclusive).
Here, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.

Constraints

10000 \leq A \leq B \leq 99999

All input values are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the number of palindromic numbers among the integers between A and B (inclusive).

Sample Input 1

11009 11332

Sample Output 1

4

There are four integers that satisfy the conditions: 11011, 11111, 11211 and 11311.

Sample Input 2

31415 92653

Sample Output 2

612

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>

using namespace std;

#define REP(i, n) for(int i = 0; i < (n); i++)
#define SORT(v, n) sort(v, v+n);
#define SSORT(v, n) sort(v, v+n, greater<int>())

int main(){
	int a,b;
	int ans = 0;
	string s;
	cin >> a >> b;

	for(int i=a; i<=b; i++){
		s=to_string(i);
		for(int j=0; j<s.length(); j++){
			for(int k=s.length()-1; k>=0; k--){
				if(s[j] == s[k]) ans++;
			}
		}
	}
	cout << ans << endl;
}