Problem:
Score : 300 points

Problem Statement

You are given an integer sequence of length n, a_1, ..., a_n.
Let us consider performing the following n operations on an empty sequence b.

The i-th operation is as follows:

Append a_i to the end of b.

Reverse the order of the elements in b.

Find the sequence b obtained after these n operations.

Constraints

1 \leq n \leq 2\times 10^5

0 \leq a_i \leq 10^9

n and a_i are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print n integers in a line with spaces in between.
The i-th integer should be b_i.

Sample Input 1

4
1 2 3 4

Sample Output 1

4 2 1 3

After step 1 of the first operation, b becomes: 1.

After step 2 of the first operation, b becomes: 1.

After step 1 of the second operation, b becomes: 1, 2.

After step 2 of the second operation, b becomes: 2, 1.

After step 1 of the third operation, b becomes: 2, 1, 3.

After step 2 of the third operation, b becomes: 3, 1, 2.

After step 1 of the fourth operation, b becomes: 3, 1, 2, 4.

After step 2 of the fourth operation, b becomes: 4, 2, 1, 3.

Thus, the answer is 4 2 1 3.

Sample Input 2

3
1 2 3

Sample Output 2

3 1 2

As shown above in Sample Output 1, b becomes 3, 1, 2 after step 2 of the third operation. Thus, the answer is 3 1 2.

Sample Input 3

1
1000000000

Sample Output 3

1000000000

Sample Input 4

6
0 6 7 6 7 0

Sample Output 4

0 6 6 0 7 7

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)



#include <bits/stdc++.h>
using namespace std;
 
#define fill(a,val) memset(a, (val), sizeof a)
#define pb push_back
#define lli long long int
#define scantype int
#define endl "\n"
#define unique(x) x.erase(unique(x.begin(),x.end()), x.end())
#define debug(x) cerr << #x " = " << (x) << '\n'
#define what_is(x) cerr << #x << " is " << x << endl;
 
lli MOD  = 1000000007;
lli inf = 1e15;
 
void scan(scantype &x);

lli powermod(lli _a,lli _b,lli _m){lli _r=1;while(_b){if(_b%2==1)_r=(_r*_a)%_m;_b/=2;_a=(_a*_a)%_m;}return _r;}
lli string_to_number(string s){lli x=0; stringstream convert(s); convert>>x; return x;}
lli add(lli a,lli b){lli x = (a+b)%MOD; return x; }
lli mul(lli a,lli b){lli x = (a*b)%MOD; return x; }
lli sub(lli a,lli b){lli x = (a-b+MOD)%MOD; return x; }
lli div(lli a,lli b){lli x = a;lli y = powermod(b,MOD-2,MOD);lli res = (x*y)%MOD;return res;}

bool isprime(long long int n)
{
    if(n ==1 )
        return false;
    if(n == 2)
        return true;
    for(long long int i =2;i<=n/i;i++)
    {
        if(n%i == 0)
            return false;
    }
    return true;
}
int main(void)
{
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);   
    int t;
    t = 1;
    while(t--)
    {

        int n;
        cin>>n;
        int a[n];
        for(int i = 0;i<n;i++)
            cin>>a[i];
        for(int i = n-1;i>=0;i-=2)
        {
            cout<<a[i]<<" ";
        }
        if(n%2)
        {
            for(int i = 1;i<n;i+=2)
                cout<<a[i]<<" ";
        }
        else
            for(int i = 0;i<n;i+=2)
                cout<<a[i]<<" ";
    }    


    
    return 0;    
}
 

void scan(scantype &x)
{
    register int c = getchar(); //for negative/positive
    x = 0;
    int neg = 0;
    for(;((c<48 || c>57) && c != '-');c = getchar());
    if(c=='-') {neg=1;c=getchar();}
    for(;c>47 && c<58;c = getchar()) {x = (x<<1) + (x<<3) + c - 48;}
    if(neg) x=-x;
}