Problem:
Score : 200 points

Problem Statement

La Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each.
Determine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.

Constraints

N is an integer between 1 and 100, inclusive.

Input

Input is given from Standard Input in the following format:

N

Output

If there is a way to buy some cakes and some doughnuts for exactly N dollars, print Yes; otherwise, print No.

Sample Input 1

11

Sample Output 1

Yes

If you buy one cake and one doughnut, the total will be 4 + 7 = 11 dollars.

Sample Input 2

40

Sample Output 2

Yes

If you buy ten cakes, the total will be 4 \times 10 = 40 dollars.

Sample Input 3

3

Sample Output 3

No

The prices of cakes (4 dollars) and doughnuts (7 dollars) are both higher than 3 dollars, so there is no such way.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<bits/stdc++.h>
using namespace std;
#define ll            long long
#define nl            "\n"
#define PB            push_back
#define _SAD()        ios::sync_with_stdio(0),cin.tie(0), cout.tie(0);
#define SZ(s)         s.size()
#define SRT(x,y)      sort(x,x+y)
#define REV(a,b)      reverse(a,a+b)
#define VSRT(x)       sort(x.begin(),x.end())
#define VREV(x)       reverse(x.begin(),x.end())
int main()
{
    _SAD()
    int n;
    cin>>n;
    if(n%4==0||n%11==0||n%7==0)
    {
        cout<<"Yes"<<nl;
        return 0;
    }
    else
    {
        int j=n,k=n,l=n;
        while(j>0)
        {
            j-=4;
        if(j%7==0||j%11==0)
        {
            cout<<"Yes"<<nl;
            return 0;
        }
        }
        while(k>0)
        {
            k-=7;
        if(k%4==0||k%11==0)
        {
            cout<<"Yes"<<nl;
            return 0;
        }
        }
        while(l>0)
        {
            k-=11;
        if(l%4==0||l%7==0)
        {
            cout<<"Yes"<<nl;
            return 0;
        }
        }
        cout<<"No"<<nl;
    }
    return 0;
}