Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<bits/stdtr1c++.h>
using namespace std;
int main()
{
    int n;
    while(scanf("%d",&n)==1)
    {
        if(n%2==0)
        {
            printf("%d %d %d\n",n,n,n*2);
        }
        else
        {
            int mark=0;
            for(int i=1;i<=3500;i++)
            {
                if(mark)break;
                for(int j=1;j<=3500;j++)
                {
                    if(mark)break;

                    int s1=4*i*j-(i+j)*n;
                    int s2=n*i*j;
                    if(s1>0)
                    {
                        if(s2%s1==0)
                        printf("%d %d %d\n",i,j,s2/s1);
                        mark++;
                    }
                }
            }
        }
    }
return 0;
}