Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;

int main() {
  string S, S1, S2;
  int A, B;
  cin >> S;
  S1 = S.substr(0,2);
  S2 = S.substr(2,2);
  A = stoi(S1);
  B = stoi(S2);
  
  if (A <= 12 && A != 0 && B <= 12 && B != 0){
    cout << "AMBIGUOUS" << endl;
  }
  else if ((B > 13 || B ==0) && (A > 13 || A ==0)){
    cout << "NA" << endl;
  }
  else if (A > 13 || A ==0){
    cout << "YYMM" << endl;
  }
  else {
    cout << "MMYY" << endl;
  }
}