Problem:
Score : 100 points

Problem Statement

Smeke has decided to participate in AtCoder Beginner Contest (ABC) if his current rating is less than 1200, and participate in AtCoder Regular Contest (ARC) otherwise.

You are given Smeke's current rating, x. Print ABC if Smeke will participate in ABC, and print ARC otherwise.

Constraints

1 ≦ x ≦ 3{,}000

x is an integer.

Input

The input is given from Standard Input in the following format:

x

Output

Print the answer.

Sample Input 1

1000

Sample Output 1

ABC

Smeke's current rating is less than 1200, thus the output should be ABC.

Sample Input 2

2000

Sample Output 2

ARC

Smeke's current rating is not less than 1200, thus the output should be ARC.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>

using namespace std;

#define vit vector<int>::iterator
#define pb push_back
#define ppb pop_back
#define mp make_pair
#define all(x) (x).begin(), (x).end()
#define forn(i, n) for(int i = 0; i < int(n); i++)
#define fr first
#define sc second
#define skip continue
#define PI 3.14159265

typedef unsigned long long ull;
typedef long long ll;
typedef unsigned int ui;
typedef long double ld;
typedef vector<int> vi;
typedef vector<long long> vll;
typedef vector<bool> vb;

const ll INF = 1e18;
const ll MOD = 1e9 + 7;
const ll MAXN = 3e5 + 3;
const int  M   =   1e9+7;

void faster(){
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    cout.tie(NULL);
}

bool cmp(const string& a, const string& b) {
    return (a + b) < (b + a);
}

void solve(){
    int a;
    cin >> a;
    if(a >= 1200) cout << "ARC";
    else cout << "ABC";
}


int main(){
    //freopen("slalom.in","r",stdin);
    //freopen("slalom.out","w",stdout);
    //faster();
    int n = 1;
    //cin >> n;
    while(n--){
        solve();
        cout << endl;
    }
    //fclose(stdout);
}