Problem:
Score : 300 points

Problem Statement

To make it difficult to withdraw money, a certain bank allows its customers to withdraw only one of the following amounts in one operation:

1 yen (the currency of Japan)

6 yen, 6^2(=36) yen, 6^3(=216) yen, ...

9 yen, 9^2(=81) yen, 9^3(=729) yen, ...

At least how many operations are required to withdraw exactly N yen in total?

It is not allowed to re-deposit the money you withdrew.

Constraints

1 \leq N \leq 100000

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If at least x operations are required to withdraw exactly N yen in total, print x.

Sample Input 1

127

Sample Output 1

4

By withdrawing 1 yen, 9 yen, 36(=6^2) yen and 81(=9^2) yen, we can withdraw 127 yen in four operations.

Sample Input 2

3

Sample Output 2

3

By withdrawing 1 yen three times, we can withdraw 3 yen in three operations.

Sample Input 3

44852

Sample Output 3

16

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define rep(i,n) for(int i = 0; i < (int)(n); i++)
#define repr(i,n) for(int i = (int)(n); i >= 0; i--)
#define all(v) v.begin(),v.end()
typedef long long ll;

vector<int> binary(int i, int n, int N){
    int x = 1;
    rep(j,N){
        x *= n;
    }
    vector<int> vec(N);
    rep(j,N){
        x /= n;
        vec[j] = i / x;
        i -= x * vec[j];
    }
    return vec;
}

int main(){
    int N;
    cin >> N;
    int ans = 100000;
    for(int i = 0; i <= N; i++){
        int ans_sub = 0;
        vector<int> binary_6 = binary(i,6,7);
        rep(j,7){
            ans_sub += binary_6[j];
        }
        vector<int> binary_9 = binary(N - i, 9, 6);
        rep(j,6){
            ans_sub += binary_9[j];
        }
        ans = min(ans, ans_sub);
    }
    cout << ans << endl;
}