Problem:
Score : 100 points

Problem Statement

There are a total of A + B cats and dogs.
Among them, A are known to be cats, but the remaining B are not known to be either cats or dogs.

Determine if it is possible that there are exactly X cats among these A + B animals.

Constraints

1 \leq A \leq 100

1 \leq B \leq 100

1 \leq X \leq 200

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B X

Output

If it is possible that there are exactly X cats, print YES; if it is impossible, print NO.

Sample Input 1

3 5 4

Sample Output 1

YES

If there are one cat and four dogs among the B = 5 animals, there are X = 4 cats in total.

Sample Input 2

2 2 6

Sample Output 2

NO

Even if all of the B = 2 animals are cats, there are less than X = 6 cats in total.

Sample Input 3

5 3 2

Sample Output 3

NO

Even if all of the B = 3 animals are dogs, there are more than X = 2 cats in total.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;

#define rep(i,l,r) for(int i=(l);i<(r);i++)
#define pb push_back
#define fi first
#define se second

using ll = long long;
using G = vector<vector<int>>;
using pii = pair<int, int>;
using pll = pair<ll, ll>;
const ll MOD = 1000000007;

ll GCD(ll x, ll y){
	return y ? GCD(y, x%y) : x;	
}
ll LCM(ll x, ll y){
	return x/GCD(x, y)*y;
}

int main() {
	int a, b, x; cin >> a >> b >> x;
	if(a>x || a+b<x){
		cout << "NO" << endl;
	}else{
		cout << "YES" << endl;
	}
	return 0;
}