Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<bits/stdc++.h>
#include<iostream>
#include<string>
#include<cmath>
#include<cstdio>
#include<cctype>
#include<cstring>
#include<iomanip>
#include<cstdlib>
#include<ctime>
#include<set>
#include<map>
#include<utility>
#include<queue>
#include<vector>
#include<stack>
#include<sstream>
#include<algorithm>
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<ll,ll> pii;
typedef pair<pii,pii> piiii;
typedef vector<pii> vii;
typedef vector<ll> vi;
typedef queue<ll> qi;
typedef queue<char> qc;
typedef queue<string> qs;
typedef vector<char> vc;
typedef vector<string> vs;
typedef map<char,ll> mpci;
typedef map<ll,ll> mpii;
typedef map<string,ll> mpsi;
typedef set<ll> sei;
typedef set<char> sec;
typedef set<string> ses;
typedef stack<ll> si;
typedef stack<char> sc;
typedef vector<ll> vll;
typedef vector<vi> vvi;
typedef vector<double> vd;
typedef pair<ll,ll> pll;
typedef pair<double,double> pdd;
typedef vector<pll> vpll;
typedef vector<pdd> vdd;
typedef unsigned int uint;
typedef long double ld;
typedef vector<bool> vb;
typedef vector<double> vd;
typedef vector<vi> vvi;
typedef vector<vvi> vvvi;
typedef vector<vii> vvii;
/*=====================================================================*/
#define pb push_back
#define rep(i,n) for(int i=0;i<(int)(n);i++)
#define sz(a) (int)(a.size())
#define len(a) (int)(a.length())
#define all(s) (s).begin(),(s).end()
#define fi first
#define se second
#define be begin
#define en end
#define m_p make_pair
#define repd(i,n) for(int i=n-1;i>=0;i--)
#define forn(i,p,n) for(int i=p;i<=n;i++)
#define ford(i,p,n) for(int i=n-1;i>=p;i--)
#define foreach(i,c) for(__typeof(c.begin())i=(c.begin());i!=(c).end();++i)
#define zero(a) memset(a,0,sizeof(a))
#define number(a,num) memeset(a,num,sizeof(a))

/*=====================================================================*/

inline void read(int &x)
{
	short negative=1;
    x=0;
    char c=getchar();
    while(c<'0' || c>'9')
    {
		if(c=='-')
			negative=-1;
		c=getchar();
	}
    while(c>='0' && c<='9')
        x=(x<<3)+(x<<1)+(c^48),c=getchar();
    x*=negative;
}
inline void write(long long x) {
  static long long sta[35];
  long long top = 0;
  do {
    sta[top++] = x % 10, x /= 10;
  } while (x);
  while (top) putchar(sta[--top] + 48);
  puts("");
}
/*======================================================================*/
bool prime(int n)
{
	if(n==0||n==1)
	  return false;
	for(int i=2;i*i<=n;i++)
	  if(n%i==0)
	    return false;
	return true;
}
/*
void merge(int a[],int left,int mid,int right)
{
	int n1=mid-left;
	int n2=right-mid;
	for(int i=0;i<n1;i++)
	{
	  l[i]=a[i+left];
    }
	for(int i=0;i<n2;i++)
	{
	  r[i]=a[mid+i];
	}
	r[n2]=l[n1]=INF;
	int i=0;
	int j=0;
	for(int k=left;k<right;k++)
	{
		if(l[i]<=r[j])
		{
			a[k]=l[i++];
		}
		else
		{
			a[k]=r[j++];
		}
	}
}
void mergesort(int a[],int left,int right)
{
	if(left+1<right)
	{
		int mid=(left+right)/2;
		mergesort(a,left,mid);
		mergesort(a,mid,right);
		merge(a,left,mid,right);
	}
}
int binsearch(int x,int v[],int n)
{
	int low=0,high=n-1;
	int mid;
	while(low<=high)
	{
		mid=(low+high)/2;
		if(x<v[mid])
		  high=mid-1;
		else
		  if(x>v[mid])
		    low=mid+1;
		  else
		    return mid+1;
	}
	return -1;
}
int partition(int a[],int left,int right)
{
	int p=a[left];
	int i=left;
	int j=right+1;
	for(;;)
	{
		while(a[++i]<p)
		  if(i>=right)
		    break;
		while(a[j--]>p)
		  if(j<=left)
		    break;
		if(i>=j)
		  break;
		else
		  swap(a[i],a[j]);
	}
	if(j>=left)
	  return j;
	swap(a[left],a[j]);
	return j;
}
void quicksort(int a[],int left,int right)
{
	int q;
	while(right>left)
	{
		q=partition(a,left,right);
	    if(n-q+1==k)
	    {
	        cout<<a[q];
	  		exit(0);
		}
		quicksort(a,left,q-1);
		quicksort(a,q+1,right);
	}
}*/
/*======================================================================*/
const int dx[]={-1,0,1,0};
const int dy[]={0,-1,0,1};
int a,b,c,d,n;
string s;
bool check(string s)
{
  for(int i=max(a,b);i<=min(c,d);i++)
  {
  	if(s[i]=='#'&&s[i+1]=='#')
  	  return false;
  }
  return true;
}
int main()
{
	cin>>n>>a>>b>>c>>d;
	cin>>s;
	if(c<d)
	{
		if(check(s))
		  cout<<"Yes"<<endl;
		else
		  cout<<"No"<<endl;
	}
	else
	{
		if(check(s))
		{
			for(int i=b;i<=d;i++)
			{
				if(s[i]=='.'&&s[i+1]=='.'&&s[i+2]=='.')
				{
				  cout<<"Yes"<<endl;
				  return 0;
			    }
			}
			cout<<"No"<<endl;
		}
		else
		  cout<<"No"<<endl;
	}
	return 0;
}