Problem:
Score : 200 points

Problem Statement

Takahashi's house has only one socket.

Takahashi wants to extend it with some number of power strips, each with A sockets, into B or more empty sockets.

One power strip with A sockets can extend one empty socket into A empty sockets.

Find the minimum number of power strips required.

Constraints

All values in input are integers.

2 \leq A \leq 20

1 \leq B \leq 20

Input

Input is given from Standard Input in the following format:

A B

Output

Print the minimum number of power strips required.

Sample Input 1

4 10

Sample Output 1

3

3 power strips, each with 4 sockets, extend the socket into 10 empty sockets.

Sample Input 2

8 9

Sample Output 2

2

2 power strips, each with 8 sockets, extend the socket into 15 empty sockets.

Sample Input 3

8 8

Sample Output 3

1

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#define _GLIBCXX_DEBUG
#include <bits/stdc++.h>
using namespace std;
#define rep(i,N) for(int i = 0; i < (N); i++)
#define repo(i,N) for(int i = 1; i < (N); i++)
#define pb push_back
#define mp make_pair
#define ll long long
#define fi first
#define se second
#define all(x) (x).begin(),(x).end()
//#define num 1000000007
#define pi acos(-1.0)
//cout << fixed << setprecision (20);   小数点以下2０桁まで
//intの最大値2147483647 ≒ 2×10^9
//long longの最大値9223372036854775807 ≒ 9×10^18
//'大文字'+=32;    で小文字に
//string s = to_string(int数);
//int n = stoi(string文字列);

int main() {
  int a,b;
  cin >>a>>b;
 
  cout << (b+a-3)/(a-1) << endl;
  
}