Problem:
Score : 200 points

Problem Statement

Raccoon is fighting with a monster.

The health of the monster is H.

Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i.
There is no other way to decrease the monster's health.

Raccoon wins when the monster's health becomes 0 or below.

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Constraints

1 \leq H \leq 10^9

1 \leq N \leq 10^5

1 \leq A_i \leq 10^4

All values in input are integers.

Input

Input is given from Standard Input in the following format:

H N
A_1 A_2 ... A_N

Output

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Sample Input 1

10 3
4 5 6

Sample Output 1

Yes

The monster's health will become 0 or below after, for example, using the second and third moves.

Sample Input 2

20 3
4 5 6

Sample Output 2

No

Sample Input 3

210 5
31 41 59 26 53

Sample Output 3

Yes

Sample Input 4

211 5
31 41 59 26 53

Sample Output 4

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <vector>
#include <algorithm>

using namespace std;

#define FOR(i, a) for(int i = 0; i < (int) a; i++)
#define all(v) v.begin(), v.end()
#define f first
#define s second

typedef long long ll;
typedef vector<int> vi;
typedef pair<int,int> pii;



int main(){
	ios::sync_with_stdio(false); cin.tie(0);

	int h, n; cin >> h >> n;
	ll sum = 0;
	FOR(i, n){
		int x; cin >> x;
		sum += x;
	}

	if(sum >= h) cout << "Yes\n";
	else cout << "No\n";

	return 0;
}