Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

//Sani buyuk Osman Pasa Plevneden cikmam diyor.
//FatihSultanMehmedHan
//Abdulhamid Han
//Bismillahirrahmanirrahim

#pragma GCC optimize ("O3")
#pragma GCC target ("sse4")

#include <bits/stdc++.h>

using namespace std;

typedef long long int lo;
typedef pair< int,int > PII;

#define fi first
#define se second
#define mp make_pair
#define pb push_back
#define fio() ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL)
#define FOR for(lo i=1;i<=n;i++)
#define mid ((start+end)/2)
#define ort ((bas+son)/2)

const lo MAX = -1000000000000000000; 
const lo MIN = 1000000000000000000; 
const lo inf = 1000000000; 
const lo KOK = 100000; 
const lo LOG = 30; 
const lo li = 100005; 
const lo mod = 1000000007; 

lo n,m,cev,b,a[li],k,cev1;
string s;
vector<int> v;

int main(void){
	cin>>n;
	cev+=n%10;n/=10;
	cev+=10*(n%10);n/=10;
	cev1+=n%10;n/=10;
	cev1+=10*(n%10);n/=10;
	if(cev==0 && cev1==0){cout<<"NA\n";return 0;}
	if((cev>12 && cev1>12) || (cev>12 && cev1==0) || (cev1>12 && cev==0)){cout<<"NA\n";return 0;}
	if((cev<=12 && cev1<=12 && cev>0 && cev1>0) ){cout<<"AMBIGUOUS\n";return 0;}
	if(cev==0){
		cout<<"MMYY\n";
		return 0;
	}
	if(cev1==0){
		cout<<"YYMM\n";
		return 0;
	}
	if(cev1<=12){
		//~ cout<<cev<<endl;
		cout<<"MMYY\n";return 0;
	}
	else cout<<"YYMM\n";
	return 0;
}