Problem:
Score : 600 points

Problem Statement

Snuke is introducing a robot arm with the following properties to his factory:

The robot arm consists of m sections and m+1 joints. The sections are numbered 1, 2, ..., m, and the joints are numbered 0, 1, ..., m. Section i connects Joint i-1 and Joint i. The length of Section i is d_i.

For each section, its mode can be specified individually. There are four modes: L, R, D and U. The mode of a section decides the direction of that section. If we consider the factory as a coordinate plane, the position of Joint i will be determined as follows (we denote its coordinates as (x_i, y_i)):

(x_0, y_0) = (0, 0).

If the mode of Section i is L, (x_{i}, y_{i}) = (x_{i-1} - d_{i}, y_{i-1}).

If the mode of Section i is R, (x_{i}, y_{i}) = (x_{i-1} + d_{i}, y_{i-1}).

If the mode of Section i is D, (x_{i}, y_{i}) = (x_{i-1}, y_{i-1} - d_{i}).

If the mode of Section i is U, (x_{i}, y_{i}) = (x_{i-1}, y_{i-1} + d_{i}).

Snuke would like to introduce a robot arm so that the position of Joint m can be matched with all of the N points (X_1, Y_1), (X_2, Y_2), ..., (X_N, Y_N) by properly specifying the modes of the sections.
Is this possible?
If so, find such a robot arm and how to bring Joint m to each point (X_j, Y_j).

Constraints

All values in input are integers.

1 \leq N \leq 1000

-10^9 \leq X_i \leq 10^9

-10^9 \leq Y_i \leq 10^9

Partial Score

In the test cases worth 300 points, -10 \leq X_i \leq 10 and -10 \leq Y_i \leq 10 hold.

Input

Input is given from Standard Input in the following format:

N
X_1 Y_1
X_2 Y_2
:
X_N Y_N

Output

If the condition can be satisfied, follow the following format. If the condition cannot be satisfied, print -1.

m
d_1 d_2 ... d_m
w_1
w_2
:
w_N

m and d_i are the configurations of the robot arm. Refer to the problem statement for what each of them means.
Here, 1 \leq m \leq 40 and 1 \leq d_i \leq 10^{12} must hold. Also, m and d_i must all be integers.

w_j is a string of length m that represents the way to bring Joint m of the robot arm to point (X_j, Y_j).
The i-th character of w_j should be one of the letters L, R, D and U, representing the mode of Section i.

Sample Input 1

3
-1 0
0 3
2 -1

Sample Output 1

2
1 2
RL
UU
DR

In the given way to bring Joint m of the robot arm to each (X_j, Y_j), the positions of the joints will be as follows:

To (X_1, Y_1) = (-1, 0): First, the position of Joint 0 is (x_0, y_0) = (0, 0). As the mode of Section 1 is R, the position of Joint 1 is (x_1, y_1) = (1, 0). Then, as the mode of Section 2 is L, the position of Joint 2 is (x_2, y_2) = (-1, 0).

To (X_2, Y_2) = (0, 3): (x_0, y_0) = (0, 0), (x_1, y_1) = (0, 1), (x_2, y_2) = (0, 3).

To (X_3, Y_3) = (2, -1): (x_0, y_0) = (0, 0), (x_1, y_1) = (0, -1), (x_2, y_2) = (2, -1).

Sample Input 2

5
0 0
1 0
2 0
3 0
4 0

Sample Output 2

-1

Sample Input 3

2
1 1
1 1

Sample Output 3

2
1 1
RU
UR

There may be duplicated points among (X_j, Y_j).

Sample Input 4

3
-7 -3
7 3
-3 -7

Sample Output 4

5
3 1 4 1 5
LRDUL
RDULR
DULRD

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<map>
#include<iostream>
#include<deque>
#include<algorithm>
#include<string>
#include<cctype>
#include<iomanip>
#include<vector>
#include<queue>
 
using namespace std;
#define REP(i,b,e) for(ll i=(ll)b;i<(ll)e;i++)
#define rep0(i,n) REP(i,0ll,n)
#define rep1(i,n) REP(i,1ll,n+1)
 
#define shosu setprecision(10)
 
typedef long long ll;
typedef pair<int,int> P;
ll longinf=1ll<<60;
int inf=1<<29;
int dx[4]={1,-1,0,0};
int dy[4]={0,0,1,-1};

int n;
int x[1000],y[1000];
int main (){
      cin>>n;
      rep0(i,n){
            cin>>x[i]>>y[i];
      }
      int hoge=(abs(x[0])+abs(y[0]))%2;
      bool ok =true;
      rep0(i,n){
            int huga = (abs(x[i])+abs(y[i]))%2;
            if(hoge != huga) ok=false;
      }
      if(ok){
            cout<<30+hoge<<endl;
            rep0(i,30+hoge){
                  cout<<1<<" ";
                  if(i == 29+hoge) cout<<1<<endl;
            }
            rep0(i,n){
                  int foo=0;
                  rep0(j,30+hoge){
                        if(x[i]>0){
                              cout<<"U";
                              x[i]--;
                        }
                        else if(x[i]<0){
                              cout<<"D";
                              x[i]++;
                        }
                        else if(y[i]>0){
                              cout<<"R";
                              y[i]--;
                        }
                        else if(y[i]<0){
                              cout<<"L";
                              y[i]++;
                        }
                        else{
                              if(foo==0){
                                    cout<<"U";
                                    foo++;
                              }
                              else{
                                    cout<<"D";
                                    foo--;
                              }
                        }
                  }
                  cout<<endl;
            }
      }
      else{
            cout<<-1<<endl;
      }

      return 0;
}