Problem:
Score : 100 points

Problem Statement

Given is an integer r.

How many times is the area of a circle of radius r larger than the area of a circle of radius 1?

It can be proved that the answer is always an integer under the constraints given.

Constraints

1 \leq r \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

r

Output

Print the area of a circle of radius r, divided by the area of a circle of radius 1, as an integer.

Sample Input 1

2

Sample Output 1

4

The area of a circle of radius 2 is 4 times larger than the area of a circle of radius 1.

Note that output must be an integer - for example, 4.0 will not be accepted.

Sample Input 2

100

Sample Output 2

10000

Solution in C++14 (Clang 3.8.0) (judge verdict: Accepted)

#include <cstdio>
#include <iostream>
#include <iomanip>
#include <functional>
#include <algorithm>
#include <string>
#include <vector>
#include <limits>
#include <numeric>
#include <queue>
#include <cmath>
#include <set>
#include <map>
#include <stack>

using namespace std;

#define INFint (1<<30)
#define BOUND 27182818284
#define MAT 2

typedef long long ll;
typedef long long int lli;
typedef pair<ll, ll> P;

ll MOD = 1000000007;
const ll INF = (1ll<<60);
#define rep(i, n) for(int i = 0; i < (int)(n); i++)
#define repi(i, a, b) for(int i=int(a);i<int(b);++i)

template<class T>
bool umax(T &a, const T &b) {
    if (a < b) {
        a = b;
        return true;
    }
    return false;
}

template<class T>
bool umin(T &a, const T &b) {
    if (b < a) {
        a = b;
        return true;
    }
    return false;
}

// gcd
template<typename T>
T gcd(T a, T b) {
    if (a == 0)
        return b;
    return gcd(b % a, a);
}

int findGCD(vector<int> arr) {
    int result = arr[0];
    for (auto a: arr) {
        result = gcd(a, result);
    }
    return result;
}

template<typename T>
T lcm(T m, T n) {
    // 引数に0がある場合は0を返す
    if ((0 == m) || (0 == n))
        return 0;
    return ((m / gcd(m, n)) * n); // lcm = m * n / gcd(m,n)
}

template<typename A, size_t N, typename T>
void Fill(A (&array)[N], const T &val) {
    fill((T *) array, (T *) (array + N), val);
}


int dx[5] = {1, 0, -1, 0};
int dy[5] = {0, 1, 0, -1};

// v.front() = -BOUND;
// v.back() = BOUND;

//struct edge{
//    int cost, to;
//
//    edge(int in_cost, int in_to){
//        cost=in_cost;
//        to=in_to;
//    }
//    bool operator<(const edge &a) const
//    {
//        return cost > a.cost;
//    }
//};

struct UnionFind {
    int n, cnt;
    vector<ll> par, rank, sz;

    UnionFind(ll n) : n(n), cnt(n), par(n), rank(n), sz(n, 1) { iota(par.begin(), par.end(), 0); }

    ll find(ll x) {
        if (x == par[x]) return x;
        return par[x] = find(par[x]);
    }

    bool same(ll x, ll y) { return find(x) == find(y); }

    ll size(ll x) { return sz[find(x)]; }

    void unite(ll x, ll y) {
        x = find(x), y = find(y);
        if (x == y) return;
        if (rank[x] < rank[y]) {
            par[x] = y;
            sz[y] += sz[x];
        } else {
            par[y] = x;
            sz[x] += sz[y];
            if (rank[x] == rank[y]) {
                rank[x]++;
            }
        }
        cnt--;
    }
};

int main() {
    int N,M,A,B,C; cin >> N;
    int ans=0;

    cout << N*N << endl;
    return 0;
}