Problem:
Score : 200 points

Problem Statement

Snuke loves working out. He is now exercising N times.

Before he starts exercising, his power is 1. After he exercises for the i-th time, his power gets multiplied by i.

Find Snuke's power after he exercises N times. Since the answer can be extremely large, print the answer modulo 10^{9}+7.

Constraints

1 ≤ N ≤ 10^{5}

Input

The input is given from Standard Input in the following format:

N

Output

Print the answer modulo 10^{9}+7.

Sample Input 1

3

Sample Output 1

6

After Snuke exercises for the first time, his power gets multiplied by 1 and becomes 1.

After Snuke exercises for the second time, his power gets multiplied by 2 and becomes 2.

After Snuke exercises for the third time, his power gets multiplied by 3 and becomes 6.

Sample Input 2

10

Sample Output 2

3628800

Sample Input 3

100000

Sample Output 3

457992974

Print the answer modulo 10^{9}+7.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define rep(i,n) for(int (i) = 0; (i) < (n); ++(i))
#define rrep(i,n) for(int (i) = (n) - 1; (i) >= 0; --(i)) //Reversi rep
#define nfor(i,a,b) for(int (i) = (a); (i) < (b); ++(i)) //Natural for
#define rfor(i,a,b) for(int (i) = (b); (i) >= (a); --(i)) //Reversi for
#define ll long long
#define mod (1000000007)
#define YES cout << "YES" << endl;
#define Yes cout << "Yes" << endl;
#define NO cout << "NO" << endl;
#define No cout << "No" << endl;

int asc(const void *a, const void *b) {
    return *(int *)a - *(int *)b;
}

int desc(const void *a, const void *b) {
    return *(int *)b - *(int *)a;
}

int main()
{
    ll n,ans = 1;
    cin >> n;
    rep(i, n)ans = ans * (i + 1) % mod;
    cout << ans << endl;
    return 0;
}