Problem:
Score : 200 points

Problem Statement

You are given a string S of length N.
Among its subsequences, count the ones such that all characters are different, modulo 10^9+7. Two subsequences are considered different if their characters come from different positions in the string, even if they are the same as strings.

Here, a subsequence of a string is a concatenation of one or more characters from the string without changing the order.

Constraints

1 \leq N \leq 100000

S consists of lowercase English letters.

|S|=N

Input

Input is given from Standard Input in the following format:

N
S

Output

Print the number of the subsequences such that all characters are different, modulo 10^9+7.

Sample Input 1

4
abcd

Sample Output 1

15

Since all characters in S itself are different, all its subsequences satisfy the condition.

Sample Input 2

3
baa

Sample Output 2

5

The answer is five: b, two occurrences of a, two occurrences of ba. Note that we do not count baa, since it contains two as.

Sample Input 3

5
abcab

Sample Output 3

17

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>

using namespace std;

typedef long long ll;

const int MOD = 1e9 + 7; // change if needed

struct Modint {
  ll val;
  
  Modint (ll _val = 0)
    : val(_val % MOD) {}

  Modint operator+ (Modint other) const {
    return Modint(val + other.val);
  }

  void operator+= (Modint other) {
    val += other.val;
    val %= MOD;
  }

  Modint operator- () const {
    return Modint(MOD - val);
  }

  Modint operator- (Modint other) const {
    return Modint(val + MOD - other.val);
  }

  void operator-= (Modint other) {
    val += MOD - other.val;
    val %= MOD;
  }

  Modint operator* (Modint other) const {
    return Modint(val * other.val);
  }

  void operator*= (Modint other) {
    val *= other.val;
    val %= MOD;
  }

  bool operator== (Modint other) const {
    return val == other.val;
  }

  bool operator!= (Modint other) const {
    return val != other.val;
  }
};

Modint exp (Modint a, int k) {
  if (k == 0) {
    return Modint(1);
  } else if (k % 2 == 0) {
    Modint half = exp(a, k / 2);
    return half * half;
  } else {
    return a * exp(a, k - 1);
  }
}

Modint inv (Modint a) {
  return exp(a, MOD - 2);
}

ostream& operator<< (ostream& out, Modint p) {
  out << p.val;
  return out;
}

int cnt [200];

int main () {
  ios::sync_with_stdio(false);

  int n;
  cin >> n;

  string s;
  cin >> s;

  for (char c : s) {
    cnt[c]++;
  }

  Modint ans (1);
  for (int i = 'a'; i <= 'z'; i++) {
    ans *= Modint(cnt[i] + 1);
  }
  ans -= Modint(1);

  cout << ans << endl;
}