Problem:
Score : 200 points

Problem Statement

Given are two strings S and T.

Let us change some of the characters in S so that T will be a substring of S.

At least how many characters do we need to change?

Here, a substring is a consecutive subsequence. For example, xxx is a substring of yxxxy, but not a substring of xxyxx.

Constraints

The lengths of S and T are each at least 1 and at most 1000.

The length of T is at most that of S.

S and T consist of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

Print the minimum number of characters in S that need to be changed.

Sample Input 1

cabacc
abc

Sample Output 1

1

For example, changing the fourth character a in S to c will match the second through fourth characters in S to T.

Since S itself does not have T as its substring, this number of changes - one - is the minimum needed.

Sample Input 2

codeforces
atcoder

Sample Output 2

6

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include<bits/stdc++.h>
using namespace std;
typedef long long int ll;
int main()
{
    string a,b;
    cin>>a>>b;
    ll s1,s2;
    s1=a.size();
    s2=b.size();
    ll c=-1;
    for(ll i=0;i<s1;i++)
    {
        if(a[i]==b[0])
        {
            c=i;
            break;
        }
    }
    ll k;
    k=s1-c;
    if(c==-1 || k<0)
    {
        ll h=0;
        for(ll i=0;i<s2;i++)
        {
            if(a[i]!=b[i])
            {
                h++;
            }
        }
        cout<<h;
    }
    else
    {
        int flag=1;
        ll s=0;
        for(ll i=0;i<s2;i++)
        {
            for(ll j=c;j<s1;j++)
            {
                if(b[i]==a[j])
                {
                    s++;
                    break;
                }
                else
                {
                    flag=0;
                    break;
                }
            }
            c++;
            if(flag==0)
            {
                break;
            }
        }
        cout<<s2-s;
    }
}