Problem:
Score : 100 points

Problem Statement

We have weather records at AtCoder Town for some consecutive three days. A string of length 3, S, represents the records - if the i-th character is S, it means it was sunny on the i-th day; if that character is R, it means it was rainy on that day.

Find the maximum number of consecutive rainy days in this period.

Constraints

|S| = 3

Each character of S is S or R.

Input

Input is given from Standard Input in the following format:

S

Output

Print the maximum number of consecutive rainy days in the period.

Sample Input 1

RRS

Sample Output 1

2

We had rain on the 1-st and 2-nd days in the period. Here, the maximum number of consecutive rainy days is 2, so we should print 2.

Sample Input 2

SSS

Sample Output 2

0

It was sunny throughout the period. We had no rainy days, so we should print 0.

Sample Input 3

RSR

Sample Output 3

1

We had rain on the 1-st and 3-rd days - two "streaks" of one rainy day, so we should print 1.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#if __has_include("D:/dhiraj/Programming/debug.h")
    #include "D:/dhiraj/Programming/debug.h"
#else
    #include <bits/stdc++.h>
    using namespace std;
    #define d(...) 11
    #define cerr if(0) cerr
#endif

// Macro --------------------------------------------------------------------

#define ll                  int64_t
#define FOR(i, a, b, s)     for(ll i = (a); ((s) > 0 ? i < (b) : i > (b)); i += (s))
#define FOR1(b)             FOR(i, 0, b, 1)
#define FOR2(i, b)          FOR(i, 0, b, 1)
#define FOR3(i, a, b)       FOR(i, a, b, (a) <= (b) ? 1 :-1)
#define FOR4(i, a, b, s)    FOR(i, a, b, s)
#define GET5(a, b, c, d, e, ...) e
#define FORC(...)           GET5(__VA_ARGS__, FOR4, FOR3, FOR2, FOR1)
#define loop(...)           FORC(__VA_ARGS__)(__VA_ARGS__)
#define all(x)              x.begin(),x.end()
#define rall(x)             x.rbegin(),x.rend()
#define endl                '\n'

// Template -----------------------------------------------------------------

// multiple input
template <typename... T> 
inline void inp(T&... args) {
    ((cin>>args), ...);
}
// scan vector
template <typename T> 
inline istream &operator >>(istream &in, vector<T> &a) {
    for(auto &x : a) in >> x;
    return in;
}
// scan pair
template <typename T, typename U> 
inline istream &operator >>(istream &in, pair<T, U> &a) {
    in >> a.first >> a.second; 
    return in;
}

// Solve --------------------------------------------------------------------

void solve(int &T)
{
    string s;
    cin >> s;

    ll ans = 0;
    if(s[0] == 'R' or s[1] == 'R' or s[2] == 'R') ans = 1;
    if(s[0] == 'R' and s[1] == 'R') ans = 2;
    if(s[2] == 'R' and s[1] == 'R') ans = 2;
    if(s[0] == 'R' and s[2] == 'R' and s[1] == 'R') ans = 3;

    // loop(i,3) {
    //     ll x = 0;
    //     loop(j,i,3) {
    //         if(s[j] == 'S') {
    //             ans = max(ans, x);
    //             break;
    //         }
    //         x++;
    //     }
    // }
    cout << ans << endl;
}

// Main ---------------------------------------------------------------------

int main()
{
    #ifdef Dhiraj
        freopen("D:/dhiraj/Programming/i1.txt", "r", stdin);
        freopen("D:/dhiraj/Programming/o1.txt", "w", stdout);
        // freopen("D:/dhiraj/Programming/e1.txt", "w", stderr);
    #endif

    ios::sync_with_stdio(false);
    cin.tie(0);

    int t = 1;
    for(int i = 1; i <= t; i++) {
        cerr << "Case #" << i << "\n";
        solve(i);
    }
    return 0;
}