Problem:
Score : 200 points

Problem Statement

We have a string S consisting of uppercase English letters. Additionally, an integer N will be given.

Shift each character of S by N in alphabetical order (see below), and print the resulting string.

We assume that A follows Z. For example, shifting A by 2 results in C (A \to B \to C), and shifting Y by 3 results in B (Y \to Z \to A \to B).

Constraints

0 \leq N \leq 26

1 \leq |S| \leq 10^4

S consists of uppercase English letters.

Input

Input is given from Standard Input in the following format:

N
S

Output

Print the string resulting from shifting each character of S by N in alphabetical order.

Sample Input 1

2
ABCXYZ

Sample Output 1

CDEZAB

Note that A follows Z.

Sample Input 2

0
ABCXYZ

Sample Output 2

ABCXYZ

Sample Input 3

13
ABCDEFGHIJKLMNOPQRSTUVWXYZ

Sample Output 3

NOPQRSTUVWXYZABCDEFGHIJKLM

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define GET_ARRAY_SIZE(a)   (sizeof(a)/sizeof(a[0]))
#define LL long long
#define VI vector<int>
#define VL vector<LL>
#define VII vector< vector<int> >
#define VLL vector< vector<LL> >
#define VS  vector<string>
#define VSS vector< vector<string> >
#define PII pair<int,int>
#define PIS pair<int,string>
#define PSI pair<string,int>
#define PLL pair<LL,LL>
const LL MOD = 1000000007;
const LL INF = 1e16;
LL facctorialMethod(int k);
int main(){
    LL n,s_len;
    string s;
    cin >> n;
    cin >> s;
    for(int i = 0; i < s.size(); i++) {
        s_len = s[i] - 'A';
        s_len = (s_len + n) % 26;
        s[i] = s_len + 'A'; 
//        cout << "s_len :" << s_len << endl;
    }
    cout << s << endl;

//    s_len = 'A';
//    cout << "s_len :" << s_len << endl;
    return 0;
}

LL facctorialMethod(int k){
    int sum = 1;
    for (int i = 1; i <= k; ++i){
        sum *= i;
    }
    return sum;
}