Problem:
Score : 100 points

Problem Statement

You are given three words s_1, s_2 and s_3, each composed of lowercase English letters, with spaces in between.
Print the acronym formed from the uppercased initial letters of the words.

Constraints

s_1, s_2 and s_3 are composed of lowercase English letters.

1 ≤ |s_i| ≤ 10 (1≤i≤3)

Input

Input is given from Standard Input in the following format:

s_1 s_2 s_3

Output

Print the answer.

Sample Input 1

atcoder beginner contest

Sample Output 1

ABC

The initial letters of atcoder, beginner and contest are a, b and c. Uppercase and concatenate them to obtain ABC.

Sample Input 2

resident register number

Sample Output 2

RRN

Sample Input 3

k nearest neighbor

Sample Output 3

KNN

Sample Input 4

async layered coding

Sample Output 4

ALC

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
#include <boost/multiprecision/cpp_int.hpp>
#define rep(i,n) for(int i=0;i<n;++i)
#define int long long
namespace mp=boost::multiprecision;
using namespace std;
typedef mp::cpp_int bint;
typedef pair<int,int> P;
int gcd(int a,int b){
    if(a%b==0)return b;
    else return gcd(b,a%b);
}
int lcm(int a,int b){
    return a*b/gcd(a,b);
}
bool prime(int a){
    if(a==1)return false;
    for(int i=2;i*i<=a;i++){
        if(a%i==0)return false;
    }
    return true;
}
struct edge{
    int to,cost;
};
class dijkstra{
    int V;
    int d[100002];
    priority_queue<P,vector<P>,greater<P>>que;
    void update(int s,vector<edge> G[]){
        fill(d,d+V+1,100000000000ll);
        d[s]=0;
        que.push(make_pair(0,s));
        while(!que.empty()){
            P p=que.top();
            que.pop();
            int v=p.second;
            if(d[v]<p.first)continue;
            rep(i,G[v].size()){
                edge e=G[v][i];
                if(d[e.to]>d[v]+e.cost){
                    d[e.to]=d[v]+e.cost;
                    que.push(make_pair(d[e.to],e.to));
                }
            }
        }
    }
public:
    dijkstra(int v,int s,vector<edge> G[]){
        V=v;
        update(s,G);
    }
    int find(int e){
        return d[e];
;    }
};
int dp[111][4][4][4];
signed main(){
    ios::sync_with_stdio(0);
    cin.tie(0);
    string ans,a,b,c;
    cin>>a>>b>>c;
    ans=a[0]+b[0]+c[0];
    transform(ans.begin(),ans.end(),ans.begin(),[](char c){return (char)toupper((int)c);});
    cout<<ans<<endl;
    return 0;
}