Problem:
Score : 400 points

Problem Statement

You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

In the i-th operation, you replace every element whose value is B_{i} with C_{i}.

For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

All values in input are integers.

1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}

B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:

N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}

Output

Print Q integers S_{i} to Standard Output in the following format:

S_{1}
S_{2}
\vdots
S_{Q}

Note that S_{i} may not fit into a 32-bit integer.

Sample Input 1

4
1 2 3 4
3
1 2
3 4
2 4

Sample Output 1

11
12
16

Initially, the sequence A is 1,2,3,4.

After each operation, it becomes the following:

2, 2, 3, 4

2, 2, 4, 4

4, 4, 4, 4

Sample Input 2

4
1 1 1 1
3
1 2
2 1
3 5

Sample Output 2

8
4
4

Note that the sequence A may not contain an element whose value is B_{i}.

Sample Input 3

2
1 2
3
1 100
2 100
100 1000

Sample Output 3

102
200
2000

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>

using namespace std;

#define  CLR(a)  memset(a,0,sizeof(a))
#define  SET(a)  memset(a,-1,sizeof(a))
#define  nl "\n";
#define FIO ios_base::sync_with_stdio(false);cout.setf(ios::fixed);cout.precision(10);cout.tie(nullptr);cin.tie(nullptr);

int dx[] = { 0,0,1,-1,-1,-1,1,1 };
int dy[] = { 1,-1,0,0,-1,1,1,-1 };

template < class T> inline T biton(T n, T pos) { return n | ((T)1 << pos); }
template < class T> inline T bitoff(T n, T pos) { return n & ~((T)1 << pos); }
template < class T> inline T ison(T n, T pos) { return (bool)(n & ((T)1 << pos)); }
template < class T> inline T gcd(T a, T b) { while (b) { a %= b; swap(a, b); }return a; }

template <class T> inline T bigmod(T p, T e, T m) {
	T ret = 1;
	for (; e > 0; e >>= 1) {
		if (e & 1) ret = (ret * p) % m; p = (p * p) % m;
	} return (T)ret;
}

#define DEBUG

#ifdef DEBUG
#define debug(...) __f(#__VA_ARGS__, __VA_ARGS__)
template < typename Arg1 >
void __f(const char* name, Arg1&& arg1)
{
	cerr << name << " is " << arg1 << std::endl;
}
template < typename Arg1, typename... Args>
void __f(const char* names, Arg1&& arg1, Args&&... args)
{
	const char* comma = strchr(names + 1, ',');
	cerr.write(names, comma - names) << " is " << arg1 << " | ";
	__f(comma + 1, args...);
}
#else
#define debug(...)
#endif

void solve()
{
	int n;
	cin>>n;

	long long sum=0;
    map<long long,long long> mp;

	for(int i=0;i<n;i++){
       int it;
	   cin>>it;
	   sum+=it;
	   mp[it]++;
	}

	int q;
	cin>>q;

	while(q--){

		long long u,v;
		cin>>u>>v;

		if(mp.count(u)){

			long long cnt=mp[u];
			long long par=(v-u)*cnt;
			sum+=par;
			mp.erase(u);
			mp[v]+=cnt;
		}
		cout<<sum<<nl;
	}
}

int main()
{
	FIO;

	int t = 1;

	while (t--)
	{
		solve();
	}

	return 0;
}