Problem:
Score : 100 points

Problem Statement

Given an integer a as input, print the value a + a^2 + a^3.

Constraints

1 \leq a \leq 10

a is an integer.

Input

Input is given from Standard Input in the following format:

a

Output

Print the value a + a^2 + a^3 as an integer.

Sample Input 1

2

Sample Output 1

14

When a = 2, we have a + a^2 + a^3 = 2 + 2^2 + 2^3 = 2 + 4 + 8 = 14.

Print the answer as an input. Outputs such as 14.0 will be judged as incorrect.

Sample Input 2

10

Sample Output 2

1110

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define ll unsigned long long int
#define mod 1000000007
bool isPrime[1000001];
ll power(ll a,ll b)
{
    ll result = 1;
    while(b>0)
    {
        if(b%2)
        {
            result = (a*result)%mod;
        }
        a = (a*a)%mod;
        b = b/2;
    }
    return result;
}
int gcd(int a,int b)
{
    if(b==0)
    {
        return a;
    }
    return gcd(b,a%b);
}
void sieve()
{
    memset(isPrime,1,sizeof(isPrime));
    isPrime[0] = isPrime[1] = 0;
    for(int i=2;i*i<=1000000;i++)
    {
        if(isPrime[i])
        {
            for(int j=i*i;j<=1000000;j+=i)
            {
                isPrime[j] = 0;
            }
        }
    }
}
int main()
{
    int x;
    cin>>x;
    cout<<x+x*x+x*x*x;
    return 0;
}