Problem:
Score : 300 points

Problem Statement

There are N people living on a number line.

The i-th person lives at coordinate X_i.

You are going to hold a meeting that all N people have to attend.

The meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.

Find the minimum total points of stamina the N people have to spend.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq X_i \leq 100

Input

Input is given from Standard Input in the following format:

N
X_1 X_2 ... X_N

Output

Print the minimum total stamina the N people have to spend.

Sample Input 1

2
1 4

Sample Output 1

5

Assume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.

Note that you can hold the meeting only at an integer coordinate.

Sample Input 2

7
14 14 2 13 56 2 37

Sample Output 2

2354

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <algorithm>
#include <iomanip>
#include <string>
#include <vector>
#include <math.h>
#include <queue>
#include <map>
#define ll long long
const int MOD = 1e9+7;
using namespace std;


int main(){
	int n;
	cin >> n;
	vector<int> x(n);
	for (int i = 0; i < n; i++){
		cin >> x[i];
	}
	int ans = MOD;
	for (int now = 1; now <= 100; now++){
		int power = 0;
		for (int i = 0; i < n; i++){
			power += (now - x[i])*(now - x[i]);
		}
		ans = min(ans, power);

	}
	cout << ans << endl;
	return 0;
}