Problem:
Score: 100 points

Problem Statement

A triple of numbers is said to be poor when two of those numbers are equal but the other number is different from those two numbers.

You will be given three integers A, B, and C. If this triple is poor, print Yes; otherwise, print No.

Constraints

A, B, and C are all integers between 1 and 9 (inclusive).

Input

Input is given from Standard Input in the following format:

A B C

Output

If the given triple is poor, print Yes; otherwise, print No.

Sample Input 1

5 7 5

Sample Output 1

Yes

A and C are equal, but B is different from those two numbers, so this triple is poor.

Sample Input 2

4 4 4

Sample Output 2

No

A, B, and C are all equal, so this triple is not poor.

Sample Input 3

4 9 6

Sample Output 3

No

Sample Input 4

3 3 4

Sample Output 4

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

/*its_Rashid*/
#include <bits/stdc++.h>
using namespace std ;

typedef double du ;
typedef string st ;
typedef long long ll ;
typedef long double ld ;
typedef long long int lli ;

#define vi vector <lli>
#define loop(num) for (lli i = 0 ; i < num ; i ++ )
#define loop2(num) for (lli j = 0 ; j < num ; j ++ )
#define loopcin(num , ar ) for (lli i = 0 ; i < num ; i ++ ) {cin >> ar [i] ;}
#define loopcout(num , ar) for (lli i = 0 ; i < num ; i ++ ) {cout << ar [i] << ' '; }
#define looppu(num , ar) for (lli i = 0 ; i < num ;  i++) {lli x ; cin >> x ; ar . push_back (x) ;}
#define loopin(num , ar) for (lli i = 0 ; i < num ;  i++) {lli x ; cin >> x ; ar . insert (x) ;}

#define forr(num1 , num2) for (lli i = num1 ; i < num2 ; i ++ )
#define forrcin(num1 , num2 , ar ) for (lli i = num1 ; i < num2 ; i ++ ) {cin >> ar [i] ;}
#define forrcout(num1 , num2 , ar) for (lli i = num1 ; i < num2 ; i ++ ) {cout << ar [i] << ' '; }

#define D2forrcin(num1_1 , num1_2 , num2_1 , num2_2 , A ) for (lli i = num1_1 ; i < num1_2 ; i ++){ for (lli j = num2_1 ; j < num2_2 ; j++){cin >> A[i][j] ;}}
#define D2forrcout(num1_1 , num1_2 , num2_1 , num2_2 , A ) for (lli i = num1_1 ; i < num1_2 ; i ++){ for (lli j = num2_1 ; j < num2_2 ; j++){cout << A[i][j] << ' ' ;}cout << endl ;}

#define YES cout << "YES" << endl
#define Yes cout << "Yes" << endl
#define NO cout << "NO" << endl
#define No cout << "No" << endl

#define F first
#define S second
#define pb push_back
#define pf push_front
#define pob pop_back ()
#define pof pop_front ()

#define fastio ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);

signed main ()
{
    fastio
    //while (true){
    ll a , b , c ;
    cin >> a >> b >> c ;

    if  (a == b) {
        if (a == c)
            No ;
        else
            Yes ;
    }
    else if (b == c){
        if (b == c)
            No ;
        else
            Yes ;
    }
    else if (c == a){
        if (c == b)
            No ;
        else
            Yes ;
    }
    /*if (a == b && b == c)
        cout << "No" << endl ;
    else if (a != b && b != c)
        cout << "No" << endl ;
    else
        cout << "Yes" << endl ;}*/

    /*ll n ; cin >> n ;
    /*if (n >= 11 && (n != 13 && n != 17 )) Yes ;
    else if (n < 11){
        if (n % 4 == 0 || n % 7 == 0 )
            Yes ;
        else No ;
    }
    else
        No ;
    (n < 11 ? (n % 7 == 0 || n % 4 == 0 ? Yes : No) : (n == 13 || n == 17 ? No : Yes)) ;*/
    return 0 ;
}

/*___________________________________________________________________functions___________________________________________________________________________*/