Problem:
Score : 200 points

Problem Statement

Given are 1-digit positive integers a and b. Consider these two strings: the concatenation of b copies of the digit a, and the concatenation of a copies of the digit b. Which of these is lexicographically smaller?

Constraints

1 \leq a \leq 9

1 \leq b \leq 9

a and b are integers.

Input

Input is given from Standard Input in the following format:

a b

Output

Print the lexicographically smaller of the two strings. (If the two strings are equal, print one of them.)

Sample Input 1

4 3

Sample Output 1

3333

We have two strings 444 and 3333. Between them, 3333 is the lexicographically smaller.

Sample Input 2

7 7

Sample Output 2

7777777

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#define FASTIO ios::sync_with_stdio(false);cin.tie(0);
#define ADD +
#define SUBTRACT -
#define MULTIPLY *
#define DIVIDE /
#define MOD %
#define INCREMENT(x) ++x
#define DECREMENT(x) --x
#define in(a,b) cin>>a>>b;
#define out(a,b) cout<<a<<endl<<b<<endl;
#define scan(a) scanf("%d",&a);
#define print(a) printf("%d\n",a);
#define scanii(a,b) scanf("%d %d",&a,&b);
#define printii(a,b) printf("%d\n%d\n",a,b);
#define scaniii(a,b,c) scanf("%d %d %d",&a,&b,&c);
#define pub push_back
#define pob pop_back
#define puf push_front
#define pof pop_front
#define ll long long
#define ull unsigned long long
#define sll signed long long
#define pi acos(-1)
#define mod 1000000007
#define TRUE 1
#define FALSE 0
#define ZERO 0
#define MP make_pair
#define F first
#define S second
#define f1(i,a) for(int i=0;i<a;++i)
#define f2(i,a) for(int i=a-1;i>=0;--i)
#define en puts("");
#define elif else if
typedef ll int lli;
typedef sll int slli;
typedef ull int ulli;
const int sz=10000;
using namespace std;

int clue();
int result();
void show();
bool check();


// bool cmp(pair<int,int>p,pair<int,int>q) {
//     // return p.first>q.first;//descending by first
//     // return p.first<q.first;//ascending by first
//     // return p.second>q.second;//descending by second
//     return p.second<q.second;//ascending by second
// }

bool cmp(int p,int q) {
    return p>q;//descending
    // return p<q;//ascending
}


int main() {

    int t;
    // cin>>t;
    t=1;
    while(t-->0) {
        clue();
    }

    return 0;
}
int clue() {

    int a,b;
    cin>>a>>b;
    int n=max(a,b);
    int m=min(a,b);
    f1(i,n) {
        cout<<m;
    }
    en
    // ()?cout<<"Yes"<<endl:cout<<"No"<<endl;
    
    return 0;
}