Problem:
Score : 100 points

Problem Statement

Snuke has a favorite restaurant.

The price of any meal served at the restaurant is 800 yen (the currency of Japan), and each time a customer orders 15 meals, the restaurant pays 200 yen back to the customer.

So far, Snuke has ordered N meals at the restaurant.
Let the amount of money Snuke has paid to the restaurant be x yen, and let the amount of money the restaurant has paid back to Snuke be y yen.
Find x-y.

Constraints

1 ≤ N ≤ 100

Input

The input is given from Standard Input in the following format:

N

Output

Print the answer.

Sample Input 1

20

Sample Output 1

15800

So far, Snuke has paid 16000 yen, and the restaurant has paid back 200 yen. Thus, the answer is 15800.

Sample Input 2

60

Sample Output 2

47200

Snuke has paid 48000 yen for 60 meals, and the restaurant has paid back 800 yen.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <string>
#include <algorithm>
#include <iomanip>
#include <vector>
#include <map>
#include <cmath>
#include <queue>
#include <utility>
#include <functional>
#include <deque>
#include <cctype>
#include <stack>
#include <bitset>

using ll = long long;
typedef unsigned long long ull;
typedef std::pair<ll, ll>P;

ll gcd(ll a, ll b) {
	if (b == 0) return a;
	return gcd(b, a%b);
}
ll lcm(ll a, ll b) {
	ll g = gcd(a, b);
	return a / g * b;
}

const ll mod = 1000000007;
const ll INF = 1 << 30;
const ll INF2 = 9000000000000000000LL;
bool fl = true;
int dx[4] = { 1,0,-1,0 }, dy[4] = { 0,1,0,-1 };
std::string abc = "abcdefghijklmnopqrstuvwxyz";
struct edge { ll to, cost; };
struct edge1 { ll from, to, cost; };
double pai = 3.141592653589793;
std::vector<P>v[100010];

int main() {
	int n;
	std::cin >> n;
	std::cout << n * 800 - 200 * n / 15 << std::endl;
}