Problem:
Score : 200 points

Problem Statement

There are N cities and M roads.
The i-th road (1≤i≤M) connects two cities a_i and b_i (1≤a_i,b_i≤N) bidirectionally.
There may be more than one road that connects the same pair of two cities.
For each city, how many roads are connected to the city?

Constraints

2≤N,M≤50

1≤a_i,b_i≤N

a_i ≠ b_i

All input values are integers.

Input

Input is given from Standard Input in the following format:

N M
a_1 b_1
:
a_M b_M

Output

Print the answer in N lines.
In the i-th line (1≤i≤N), print the number of roads connected to city i.

Sample Input 1

4 3
1 2
2 3
1 4

Sample Output 1

2
2
1
1

City 1 is connected to the 1-st and 3-rd roads.

City 2 is connected to the 1-st and 2-nd roads.

City 3 is connected to the 2-nd road.

City 4 is connected to the 3-rd road.

Sample Input 2

2 5
1 2
2 1
1 2
2 1
1 2

Sample Output 2

5
5

Sample Input 3

8 8
1 2
3 4
1 5
2 8
3 7
5 2
4 1
6 8

Sample Output 3

3
3
2
2
2
1
1
2

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;
using ll = long long;
using pii = pair<int,int>;
#define rep(i,n) for(int i=0; i<n; i++)
#define UNIQUE(v) v.erase(unique(v.begin(), v.end()), v.end()) //sortしてから使う
#define INF 2147483647
#define LLINF 9223372036854775807LL

int main(){
  int n,m; cin>>n>>m;
  vector<int>Ans(n+1,0); //Ans[0]は使わない
  rep(i,m){
    int a,b; cin>>a>>b;
    for (int j=1; j<=n; j++){
      if (a==j) Ans[j]++;
      if (b==j) Ans[j]++;
    }
  }
  for (int i=1; i<=n; i++) cout << Ans[i] << endl;
}