Problem:
Score : 1100 points

Problem Statement

There is a set consisting of N distinct integers. The i-th smallest element in this set is S_i. We want to divide this set into two sets, X and Y, such that:

The absolute difference of any two distinct elements in X is A or greater.

The absolute difference of any two distinct elements in Y is B or greater.

How many ways are there to perform such division, modulo 10^9 + 7? Note that one of X and Y may be empty.

Constraints

All input values are integers.

1 ≦ N ≦ 10^5

1 ≦ A , B ≦ 10^{18}

0 ≦ S_i ≦ 10^{18}(1 ≦ i ≦ N)

S_i < S_{i+1}(1 ≦ i ≦ N - 1)

Input

The input is given from Standard Input in the following format:

N A B
S_1
:
S_N

Output

Print the number of the different divisions under the conditions, modulo 10^9 + 7.

Sample Input 1

5 3 7
1
3
6
9
12

Sample Output 1

5

There are five ways to perform division:

X={1,6,9,12}, Y={3}

X={1,6,9}, Y={3,12}

X={3,6,9,12}, Y={1}

X={3,6,9}, Y={1,12}

X={3,6,12}, Y={1,9}

Sample Input 2

7 5 3
0
2
4
7
8
11
15

Sample Output 2

4

Sample Input 3

8 2 9
3
4
5
13
15
22
26
32

Sample Output 3

13

Sample Input 4

3 3 4
5
6
7

Sample Output 4

0

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>

using namespace std;
typedef long long ll;
typedef pair<ll, ll> p_ll;

template<class T>
void debug(T itr1, T itr2) { auto now = itr1; while(now<itr2) { cout << *now << " "; now++; } cout << endl; }
#define repr(i,from,to) for (int i=(int)from; i<(int)to; i++)
#define all(vec) vec.begin(), vec.end()
#define rep(i,N) repr(i,0,N)
#define per(i,N) for (int i=(int)N-1; i>=0; i--)

const ll MOD = pow(10,9)+7;
const ll LLINF = pow(2,61)-1;
const int INF = pow(2,30)-1;

vector<ll> fac;
void c_fac(int x=pow(10,6)+10) { fac.resize(x,true); rep(i,x) fac[i] = i ? (fac[i-1]*i)%MOD : 1; }
ll inv(ll a, ll m=MOD) { ll b = m, x = 1, y = 0; while (b!=0) { int d = a/b; a -= b*d; swap(a,b); x -= y*d; swap(x,y); } return (x+m)%m; }
ll nck(ll n, ll k) { return fac[n]*inv(fac[k]*fac[n-k]%MOD)%MOD; }
ll gcd(ll a, ll b) { if (a<b) swap(a,b); return b==0 ? a : gcd(b, a%b); }
ll lcm(ll a, ll b) { return a/gcd(a,b)*b; }

// ----------------------------------------------------------------------
// ----------------------------------------------------------------------

struct SegTree {
  int size;
  vector<ll> pos;
  SegTree(ll N) { size = 1; while(size<N) size<<=1; pos.resize(2*size,0); }
  ll operator[](const ll &x) const { return pos[x+size]; }

  void build() { per(i,size) operate(i); }
  void set(ll x, const ll v) { pos[x+size] = v; }
  void update(ll x, const ll v) { set(x,v); x+=size; while (x>>=1) operate(x); }
  ll query(ll a, ll b) {
    ll L = 0, R = 0;
    for (a+=size, b+=size; a<b; a>>=1, b>>=1) {
      if (a&1) { L = q(L,pos[a]); a++; }
      if (b&1) { b--; R = q(R,pos[b]); }
    }
    return q(L,R);
  }
  void operate(ll i) { pos[i] = pos[i*2] + pos[i*2+1]; }
  ll q(ll x, ll y) { return x + y; }
};

// ----------------------------------------------------------------------
// ----------------------------------------------------------------------

int main() {
  ll N, A, B; cin >> N >> A >> B; if (A>B) swap(A,B);
  ll S[N+1] = {}; rep(i,N) cin >> S[i+1]; S[0] = -1*LLINF;

  rep(i,N-1) {
    if (S[i+2]-S[i]<A) {
      cout << 0 <<endl;
      return 0;
    }
  }

  SegTree st(N+1); st.update(0,1);
  ll pz = -1;
  rep(i,N) {
    ll p = upper_bound(S,S+(N+1),S[i+1]-B) - S;
    st.update(i+1,st.query(pz+1,p));
    if (S[i+1]-S[i]<A) pz = i-1;
    // cout << pz+1 << "~" << p << endl;
    // rep(j,i+2) cout << st[j] << " "; cout << endl;
  }
  ll result = st.query(pz+1,N+1);
  cout << result << endl;
  return 0;
}