Problem:
Score : 100 points

Problem Statement

Takahashi is a member of a programming competition site, ButCoder.

Each member of ButCoder is assigned two values: Inner Rating and Displayed Rating.

The Displayed Rating of a member is equal to their Inner Rating if the member has participated in 10 or more contests. Otherwise, the Displayed Rating will be their Inner Rating minus 100 \times (10 - K) when the member has participated in K contests.

Takahashi has participated in N contests, and his Displayed Rating is R. Find his Inner Rating.

Constraints

All values in input are integers.

1 \leq N \leq 100

0 \leq R \leq 4111

Input

Input is given from Standard Input in the following format:

N R

Output

Print his Inner Rating.

Sample Input 1

2 2919

Sample Output 1

3719

Takahashi has participated in 2 contests, which is less than 10, so his Displayed Rating is his Inner Rating minus 100 \times (10 - 2) = 800.

Thus, Takahashi's Inner Rating is 2919 + 800 = 3719.

Sample Input 2

22 3051

Sample Output 2

3051

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
#define int long long
#define ld long double
#define endl '\n'
#define vi vector<int>
#define vvi vector<vi>
#define pii pair<int, int>
#define vpii vector<pii>
#define gr vector<vpii>
#define fi first
#define se second
#define sz(x) (int)((x).size())
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define YES cout << "YES" << endl
#define NO cout << "NO" << endl
#define GAME_OVER return 0
using namespace std;
signed main()
{
    ios_base::sync_with_stdio(false);
    cin.tie(0); cout.tie(0);
    int n, r;
    cin >> n >> r;
    if (n >= 10)
        cout << r << endl;
    else
        cout << r + (10 - n) << endl;
    GAME_OVER;
}