Problem:
Score : 200 points

Problem Statement

Tak performed the following action N times: rolling two dice.
The result of the i-th roll is D_{i,1} and D_{i,2}.

Check if doublets occurred at least three times in a row.
Specifically, check if there exists at lease one i such that D_{i,1}=D_{i,2}, D_{i+1,1}=D_{i+1,2} and D_{i+2,1}=D_{i+2,2} hold.

Constraints

3 \leq N \leq 100

1\leq D_{i,j} \leq 6

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
D_{1,1} D_{1,2}
\vdots
D_{N,1} D_{N,2}

Output

Print Yes if doublets occurred at least three times in a row. Print No otherwise.

Sample Input 1

5
1 2
6 6
4 4
3 3
3 2

Sample Output 1

Yes

From the second roll to the fourth roll, three doublets occurred in a row.

Sample Input 2

5
1 1
2 2
3 4
5 5
6 6

Sample Output 2

No

Sample Input 3

6
1 1
2 2
3 3
4 4
5 5
6 6

Sample Output 3

Yes

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp> 
#include <ext/pb_ds/tree_policy.hpp>  
using namespace std;
using namespace __gnu_pbds;

#define int long long int
#define float long double
#define pb push_back
#define fi first
#define se second
#define vii vector<int>
#define pii pair<int,int>
#define vpii vector<pii>
#define pq priority_queue<int>
#define test int tcase; cin>>tcase; for(int tc = 1; tc <= tcase; tc++)
#define inp(a,n,f) int a[n+f];for(int hh=f;hh<n+f;hh++)cin>>a[hh];
#define prdec(k) cout<<fixed<<setprecision(k);
#define mem(a,k) memset(a,k,sizeof(a))
#define ub upper_bound
#define lb lower_bound
#define ordered_set tree<int, null_type,less<int>, rb_tree_tag,tree_order_statistics_node_update>
#define mii map<int,int>
#define all(v) v.begin(),v.end()
#define mod (int)(1e9+7)
#define inf LLONG_MAX
int exp(int x,int y){int res=1;x=x%mod;while(y>0){if(y&1)res=(res*x)%mod;y=y>>1;x=(x*x)%mod;}return res;}
int modinv(int x){return exp(x,mod-2);}


signed main()
{
	ios_base::sync_with_stdio(false);
	cin.tie(NULL);
	cout.tie(NULL);

	int n,res=0,mx=0;
	cin>>n;
	for(int i=0;i<n;i++)
	{
		int x,y;
		cin>>x>>y;
		if(x==y)
			mx++;
		else
			res=max(res,mx),mx=0;
	}
	res=max(res,mx);
	cout<<(res>2?"Yes":"No");
	return 0;
}