Problem:
Score : 200 points

Problem Statement

A shop sells N kinds of fruits, Fruit 1, \ldots, N, at prices of p_1, \ldots, p_N yen per item, respectively. (Yen is the currency of Japan.)

Here, we will choose K kinds of fruits and buy one of each chosen kind. Find the minimum possible total price of those fruits.

Constraints

1 \leq K \leq N \leq 1000

1 \leq p_i \leq 1000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
p_1 p_2 \ldots p_N

Output

Print an integer representing the minimum possible total price of fruits.

Sample Input 1

5 3
50 100 80 120 80

Sample Output 1

210

This shop sells Fruit 1, 2, 3, 4, and 5 for 50 yen, 100 yen, 80 yen, 120 yen, and 80 yen, respectively.

The minimum total price for three kinds of fruits is 50 + 80 + 80 = 210 yen when choosing Fruit 1, 3, and 5.

Sample Input 2

1 1
1000

Sample Output 2

1000

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
#define arep(a,i,n) for(int i=(a);i<(n);i++)
#define rep(i,n) for(int i=0;i<(n);i++)
#define cinf(x,n) for(int i=0;i<(n);i++)cin>>x[i];
#define coutf(x,n) for(int i=0;i<(n);i++)cout<<x[i]<<endl;
typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;

using namespace std;

int main(){
	ll n,k;
	ull sum;
	cin >> n >> k;
	ll p[n];
	cinf(p,n);
	sort(p,p+n);
	rep(i,k){
		sum+=p[i];
	}
	cout << sum << endl;
}