Problem:
Score : 100 points

Problem Statement

In the Kingdom of AtCoder, people use a language called Taknese, which uses lowercase English letters.

In Taknese, the plural form of a noun is spelled based on the following rules:

If a noun's singular form does not end with s, append s to the end of the singular form.

If a noun's singular form ends with s, append es to the end of the singular form.

You are given the singular form S of a Taknese noun. Output its plural form.

Constraints

S is a string of length 1 between 1000, inclusive.

S contains only lowercase English letters.

Input

Input is given from Standard Input in the following format:

S

Output

Print the plural form of the given Taknese word.

Sample Input 1

apple

Sample Output 1

apples

apple ends with e, so its plural form is apples.

Sample Input 2

bus

Sample Output 2

buses

bus ends with s, so its plural form is buses.

Sample Input 3

box

Sample Output 3

boxs

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

                  /**Bismillahir Rahmanir Rahim.**/
#include<bits/stdc++.h>
#include<stdlib.h>
#include<iostream>
#include<vector>
#include<math.h>
#include<cstring>
#include<cstdio>
using namespace std;
typedef long long int            ll;
typedef long double              ld;
#define Faster  ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define pi                 acos(-1);
#define test        int t; cin>>t; while(t--)
//scanf("%[^\n]%*c", str);
//sort(s,s+n,greater<int>());
//cin.getline(array,size);
int main()
{
    #ifndef ONLINE_JUDGE
        clock_t tStart = clock();
        freopen("input.txt", "r", stdin);
        freopen("output.txt", "w", stdout);
    #endif
    string a;
    cin>>a;
    if(a[a.size()-1]=='s')
    {
    	cout<<a<<"es"<<endl;
    }
    else
    	cout<<a<<"s"<<endl;
    
    #ifndef ONLINE_JUDGE
        fprintf(stderr, "\n>> Runtime: %.10fs\n", (double) (clock() - tStart) / CLOCKS_PER_SEC);
    #endif
}