Problem:
Score : 200 points

Problem Statement

A shop sells N kinds of fruits, Fruit 1, \ldots, N, at prices of p_1, \ldots, p_N yen per item, respectively. (Yen is the currency of Japan.)

Here, we will choose K kinds of fruits and buy one of each chosen kind. Find the minimum possible total price of those fruits.

Constraints

1 \leq K \leq N \leq 1000

1 \leq p_i \leq 1000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
p_1 p_2 \ldots p_N

Output

Print an integer representing the minimum possible total price of fruits.

Sample Input 1

5 3
50 100 80 120 80

Sample Output 1

210

This shop sells Fruit 1, 2, 3, 4, and 5 for 50 yen, 100 yen, 80 yen, 120 yen, and 80 yen, respectively.

The minimum total price for three kinds of fruits is 50 + 80 + 80 = 210 yen when choosing Fruit 1, 3, and 5.

Sample Input 2

1 1
1000

Sample Output 2

1000

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;

#define ll long long
#define pb push_back
#define debug1(x) cerr << #x << " = " << x << '\n';
#define debug2(x, y) cerr << #x << " = " << x << "   " << #y << " = " << y << "\n";
#define _ ios_base::sync_with_stdio(0);cin.tie(NULL);

void solve() {
    int n, k;
    cin >> n >> k;
    int a[n];
    for(int i = 0; i<n; i++) cin >> a[i];
    int sum = 0;
    sort(a, a+n);
    for(int i = 0; i<k; i++) sum += a[i];
    cout << sum;
}

int main() {
    int t = 1;
    //cin >> t;
    // Please remember to uncomment for taking test cases
    for(int i = 1; i<=t; i++) {
        solve();
    }
    return 0;
}