Problem:
Disjoint Set

Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.

same(x, y): determine whether x and y are in the same set.

Input

n q
com1 x1 y1
com2 x2 y2
...
comq xq yq

In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Constraints

1 ≤ n ≤ 10000

1 ≤ q ≤ 100000

x ≠ y

Sample Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0

Sample Output

0
0
1
1
1
0
1
1

Solution in C++14 (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;

typedef long long ll;

#define p_ary(ary,a,b,i) do { cout << "["; for (int (i) = (a);(i) < (b);++(i)) cout << ary[(i)] << ((b)-1 == (i) ? "" : ", "); cout << "]\n"; } while(0)
#define p_map(map,it) do {cout << "{";for (auto (it) = map.begin();;++(it)) {if ((it) == map.end()) {cout << "}\n";break;}else cout << "" << (it)->first << "=>" << (it)->second << ", ";}}while(0)

struct UnionFind {
private:
    vector<int> par,depth;
public:
    UnionFind (int n) {
        par.resize(n);
        depth = vector<int>(n,0);
        for (int i = 0;i < n;++i) par[i] = i;
    }

    int find(int x) {
        if (par[x] == x) return x;
        else return par[x] = find(par[x]);
    }

    void unite(int x,int y) {
        x = find(x);
        y = find(y);
        if (x == y) return;
        if (depth[x] < depth[y]) par[x] = y;
        else {
            par[y] = x;
            if (depth[x] == depth[y]) depth[x]++;
        }
    }

    bool same(int x,int y) {
        return find(x) == find(y);
    }
};

int main() {
    int n,q;
    cin >> n >> q;
    UnionFind a(n);
    for (int i = 0;i < q;++i) {
        int c,x,y;
        cin >> c >> x >> y;
        if (c) cout << a.same(x,y) << endl;
        else a.unite(x,y);
    }
    return 0;
}