Problem:
Score: 300 points

Problem Statement

M-kun is a student in Aoki High School, where a year is divided into N terms.

There is an exam at the end of each term. According to the scores in those exams, a student is given a grade for each term, as follows:

For the first through (K-1)-th terms: not given.

For each of the K-th through N-th terms: the multiplication of the scores in the last K exams, including the exam in the graded term.

M-kun scored A_i in the exam at the end of the i-th term.

For each i such that K+1 \leq i \leq N, determine whether his grade for the i-th term is strictly greater than the grade for the (i-1)-th term.

Constraints

2 \leq N \leq 200000

1 \leq K \leq N-1

1 \leq A_i \leq 10^{9}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
A_1 A_2 A_3 \ldots A_N

Output

Print the answer in N-K lines.

The i-th line should contain Yes if the grade for the (K+i)-th term is greater than the grade for the (K+i-1)-th term, and No otherwise.

Sample Input 1

5 3
96 98 95 100 20

Sample Output 1

Yes
No

His grade for each term is computed as follows:

3-rd term: (96 \times 98 \times 95) = 893760

4-th term: (98 \times 95 \times 100) = 931000

5-th term: (95 \times 100 \times 20) = 190000

Sample Input 2

3 2
1001 869120 1001

Sample Output 2

No

Note that the output should be No if the grade for the 3-rd term is equal to the grade for the 2-nd term.

Sample Input 3

15 7
3 1 4 1 5 9 2 6 5 3 5 8 9 7 9

Sample Output 3

Yes
Yes
No
Yes
Yes
No
Yes
Yes

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

// https://atcoder.jp/contests/m-solutions2020
#include <iostream>
#include <iomanip>
#include <cstdio>
#include <cstdlib>
#include <vector>
#include <string>
#include <algorithm>
#include <numeric>
#include <map>
#include <unordered_map>
#include <stack>
#include <queue>
#include <set>
#include <unordered_set>
#include <bitset>
using namespace std;
using ll = long long;
using P = pair<ll, ll>;
#define REP(i, n) for(size_t i = 0; i < (n); ++i)

int main()
{
    int N, K;
    cin >> N >> K;
    vector<ll> A(N+1);
    A[0] = 1LL;
    for (int i = 1; i <= N; ++i) cin >> A[i];
    ll p = 1LL;
    for (int i = 1; i <= K; ++i)
    {
        p *= A[i];
    }
    for (int i = K + 1; i <= N; ++i)
    {
        ll cur = (p / A[i - K]) * A[i];
        if (p < cur)
        {
            cout << "Yes" << endl;
        }
        else
        {
            cout << "No" << endl;
        }
        p = cur;
    }
    return 0;
}