Problem:
Score : 200 points

Problem Statement

There are N cities and M roads.
The i-th road (1≤i≤M) connects two cities a_i and b_i (1≤a_i,b_i≤N) bidirectionally.
There may be more than one road that connects the same pair of two cities.
For each city, how many roads are connected to the city?

Constraints

2≤N,M≤50

1≤a_i,b_i≤N

a_i ≠ b_i

All input values are integers.

Input

Input is given from Standard Input in the following format:

N M
a_1 b_1
:
a_M b_M

Output

Print the answer in N lines.
In the i-th line (1≤i≤N), print the number of roads connected to city i.

Sample Input 1

4 3
1 2
2 3
1 4

Sample Output 1

2
2
1
1

City 1 is connected to the 1-st and 3-rd roads.

City 2 is connected to the 1-st and 2-nd roads.

City 3 is connected to the 2-nd road.

City 4 is connected to the 3-rd road.

Sample Input 2

2 5
1 2
2 1
1 2
2 1
1 2

Sample Output 2

5
5

Sample Input 3

8 8
1 2
3 4
1 5
2 8
3 7
5 2
4 1
6 8

Sample Output 3

3
3
2
2
2
1
1
2

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

//-------------
//include
//-------------
#include <map>
#include <list>
#include <cmath>
#include <vector>
#include <string>
#include <cctype>
#include <random>
#include <cstdlib>
#include <iostream>
#include <algorithm>
using namespace std;
//-------------
//typedef
//-------------
typedef long long LL;
typedef  vector<int> VI;
typedef  pair<int, int> PII;
typedef  vector<int, int> VII;
typedef  map<string, int> MSI;
//-------------
//utillty
//-------------
#define ALL(a)  (a).begin(),(a).end()
#define RALL(a) (a).rbegin(), (a).rend()
#define MK make_pair
#define PB push_back
#define SZ(a) int((a).size())
#define EACH(i,c) for(typeof((c).begin()) i=(c).begin(); i!=(c).end(); ++i)
#define EXIST(s,e) ((s).find(e)!=(s).end())
#define SORT(c) sort((c).begin(),(c).end())
//-------------
//repetition
//-------------
#define FOR(i,a,b) for(int i=(a);i<(b);++i)
#define REP(i,n)  FOR(i,0,n)
//-------------
//debug
//-------------
#define dump(x)  cerr << #x << " = " << (x) << endl;
#define debug(x) cerr << #x << " = " << (x) << " (L" << __LINE__ << ")" << " " << __FILE__ << endl;
#define W1 while(1);
const int MOD = 1000000007;
int main()
{
	int n, m;
	VI v;
	cin >> n >> m;
	v.resize(n);
	REP(i, m)
	{
		int a, b;
		cin >> a >> b;
		v[a-1]++;
		v[b-1]++;
	}
	REP(i,n)
	{
		cout << v[i] << endl;
	}
	return 0;
}