Problem:
Score : 300 points

Problem Statement

You are given a string S of length N consisting of A, C, G and T. Answer the following Q queries:

Query i (1 \leq i \leq Q): You will be given integers l_i and r_i (1 \leq l_i < r_i \leq N). Consider the substring of S starting at index l_i and ending at index r_i (both inclusive). In this string, how many times does AC occurs as a substring?

Notes

A substring of a string T is a string obtained by removing zero or more characters from the beginning and the end of T.

For example, the substrings of ATCODER include TCO, AT, CODER, ATCODER and (the empty string), but not AC.

Constraints

2 \leq N \leq 10^5

1 \leq Q \leq 10^5

S is a string of length N.

Each character in S is A, C, G or T.

1 \leq l_i < r_i \leq N

Input

Input is given from Standard Input in the following format:

N Q
S
l_1 r_1
:
l_Q r_Q

Output

Print Q lines. The i-th line should contain the answer to the i-th query.

Sample Input 1

8 3
ACACTACG
3 7
2 3
1 8

Sample Output 1

2
0
3

Query 1: the substring of S starting at index 3 and ending at index 7 is ACTAC. In this string, AC occurs twice as a substring.

Query 2: the substring of S starting at index 2 and ending at index 3 is CA. In this string, AC occurs zero times as a substring.

Query 3: the substring of S starting at index 1 and ending at index 8 is ACACTACG. In this string, AC occurs three times as a substring.

Solution in C++14 (GCC 5.4.1) (judge verdict: Time Limit Exceeded)

#include <bits/stdc++.h>
using namespace std;
using ll = long long;
#define rep(i,n) for (int i = 0; i< (n); ++i)
const long long INF = 1LL<<58;

// aを常に小さい値にする
template<class T> void chmin(T &a, T b){ if(a>b) a = b; }
template<class T> void chmax(T &a, T b){ if(a<b) a = b; }

// 二分探索 前方のindexを返すもの（自分自身を含む） 前方: -INF側のこと
template<class T> int former(const vector<T> &v, T x){
    return upper_bound(v.begin(), v.end(), x) - v.begin() -1; // upper_bound : keyより大きい要素の内の一番左側のイテレータを返す
}
// 二分探索 後方のindexを返すもの（自分自身を含む）後方: INF側のこと
template<class T> int latter(const vector<T> &v, T x){
    return lower_bound(v.begin(), v.end(), x) - v.begin(); // lower_bound : key以上の要素の内の一番左側のイテレータを返す
}

/*
 * */

bool check(char c1, char c2){
    return (c1 == 'A' && c2 == 'C');
}

int main() {
    int N, Q;
    cin >> N >> Q;

    string S;
    cin >> S;

    rep(i,Q) {
        unsigned l, r;
        cin >> l >> r;
        string sub = S.substr(l-1, r-l+1);

        int max = 0;
        int count = 0;
        rep(j,sub.size()){
            if(check(sub[j], sub[j+1])){
                count++;
                chmax(max, count);
                j++;
            }
        }

        cout << max << endl;
    }
}