Problem:
Score : 200 points

Problem Statement

We have N squares assigned the numbers 1,2,3,\ldots,N. Each square has an integer written on it, and the integer written on Square i is a_i.

How many squares i satisfy both of the following conditions?

The assigned number, i, is odd.

The written integer is odd.

Constraints

All values in input are integers.

1 \leq N, a_i \leq 100

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 \cdots a_N

Output

Print the number of squares that satisfy both of the conditions.

Sample Input 1

5
1 3 4 5 7

Sample Output 1

2

Two squares, Square 1 and 5, satisfy both of the conditions.

For Square 2 and 4, the assigned numbers are not odd.

For Square 3, the written integer is not odd.

Sample Input 2

15
13 76 46 15 50 98 93 77 31 43 84 90 6 24 14

Sample Output 2

3

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#define F first
#define S second
#define pi acos(-1)
using ll = long long;
using namespace std;
using namespace __gnu_pbds;
using vl = vector<ll>;
using pll =  pair<ll,ll>;
const ll mod = 1000000007;
const ll infi = 1000000000000000;
const ll md = 998244353;
typedef tree<int,null_type,less<int>,rb_tree_tag,tree_order_statistics_node_update>ordered_set;


ll power(ll x,ll y){
    ll res = 1;
    while(y){
        if(y&1)
            res = (res*x)%md;
        x = (x*x)%md;
        y = y/2;
    }
    return res;
}

void solve(){
    int n,cnt = 0;
    cin>>n;
    for(int i=1;i<=n;i++){
        int x;
        cin>>x;
        if(x % 2 == 1&& i%2 == 1 ){
            cnt++;
        }
    }
    cout<<cnt<<endl;
}
 
int main()
{
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    cout.tie(NULL);
  //  int n; cin>>n; for (int i = 0; i < n; ++i)
    solve();
    return 0;
}