Problem:
Score : 200 points

Problem Statement

You are given two positive integers A and B. Compare the magnitudes of these numbers.

Constraints

1 ≤ A, B ≤ 10^{100}

Neither A nor B begins with a 0.

Input

Input is given from Standard Input in the following format:

A
B

Output

Print GREATER if A>B, LESS if A<B and EQUAL if A=B.

Sample Input 1

36
24

Sample Output 1

GREATER

Since 36>24, print GREATER.

Sample Input 2

850
3777

Sample Output 2

LESS

Sample Input 3

9720246
22516266

Sample Output 3

LESS

Sample Input 4

123456789012345678901234567890
234567890123456789012345678901

Sample Output 4

LESS

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#define rep(i, n) for (int i = 0; i < (n); ++i)
#define repI(i, d, n) for (int i = (d); i < (n); ++i)
#define reps1(i, n) for (int i = 1; i < (n); ++i)
using namespace std;
template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }

using ll = long long;
using P = pair<int, int>;
using Pl = pair<ll, ll>;
using M = map<int, int>;
using Ml = map<ll, ll>;
ll const INF = 1ll<<61;
double pi = 3.141592653589793238;

int main() {
  string a, b;
  cin >> a >> b;

  if (a.size() > b.size()) cout << "GREATER" << endl;
  else if (a.size() < b.size()) cout << "LESS" << endl;
  else if (a > b) cout << "GREATER" << endl;
  else if (a < b) cout << "LESS" << endl;
  else cout << "EQUAL" << endl;

  return 0;
}