Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C++14 (Clang 3.8.0) (judge verdict: Wrong Answer)

#include <iostream>
using namespace std;
int main()
{
    int N;
    cin >> N;
    int ans = 0;
    int counter = 0;

    for (int i = 1; i < N; i++) {
        for (int j = 1; j < N; j+=2) {
            if(i%j == 0) {
                counter++;
            }
            if (counter == 8) {
                ans++;
                counter = 0;
            }
        }
    }

    cout << ans << endl;
    return 0;
}