Problem:
Score : 200 points

Problem Statement

An integer N is a multiple of 9 if and only if the sum of the digits in the decimal representation of N is a multiple of 9.

Determine whether N is a multiple of 9.

Constraints

0 \leq N < 10^{200000}

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a multiple of 9, print Yes; otherwise, print No.

Sample Input 1

123456789

Sample Output 1

Yes

The sum of these digits is 1+2+3+4+5+6+7+8+9=45, which is a multiple of 9, so 123456789 is a multiple of 9.

Sample Input 2

0

Sample Output 2

Yes

Sample Input 3

31415926535897932384626433832795028841971693993751058209749445923078164062862089986280

Sample Output 3

No

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define pb push_back
#define speed ios_base::sync_with_stdio(0); cin.tie(0);
#define FL(i,a,n) for(ll i=a;i<n;i++)
#define even(x) (((x)%(2))==(0))
#define odd(x) (((x)%(2))==(1))
#define meme(x) memset(x, 0, sizeof(x))

#define pb push_back
#define mp make_pair
#define ff first
#define ss second
	
int main()
{
    speed;
    string s;
    cin>>s;
    ll ans=0;
    for(char c:s)
    {
	    ans=ans+(c-'0');
    }
    if(ans%9==0)
    cout<<"Yes\n";
    else
    {
	    cout<<"No\n";
    }
    


}