Problem:
Score : 200 points

Problem Statement

An integer N is a multiple of 9 if and only if the sum of the digits in the decimal representation of N is a multiple of 9.

Determine whether N is a multiple of 9.

Constraints

0 \leq N < 10^{200000}

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a multiple of 9, print Yes; otherwise, print No.

Sample Input 1

123456789

Sample Output 1

Yes

The sum of these digits is 1+2+3+4+5+6+7+8+9=45, which is a multiple of 9, so 123456789 is a multiple of 9.

Sample Input 2

0

Sample Output 2

Yes

Sample Input 3

31415926535897932384626433832795028841971693993751058209749445923078164062862089986280

Sample Output 3

No

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)


#include <bits/stdc++.h>
/*#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>*/
 
#define pll              pair <long long,long long>
#define pb               push_back
#define ll               long long
#define ff               first
#define ss               second
#define D(x)             cerr<<#x " = "<<(x)<<endl
#define vll              vector <ll>
#define IOS              ios_base::sync_with_stdio(0); cin.tie(NULL);
#define endl             '\n'   
using namespace std;
int main()
{
    IOS
 	// freopen("input.txt","r",stdin);
 	// freopen("output.txt","w",stdout);
 	// freopen("error.txt","w",stderr);
    string s;
    cin>>s;
    ll sum=0;
    for(char c:s)
    	sum+=c-'0';
    if(sum%9==0)
    {
    	cout<<"Yes"<<endl;
    }
    else
    {
    	cout<<"No"<<endl;
    }
    return 0;
}