Problem:
Score : 200 points

Problem Statement

When Mr. X is away from home, he has decided to use his smartwatch to search the best route to go back home, to participate in ABC.

You, the smartwatch, has found N routes to his home.

If Mr. X uses the i-th of these routes, he will get home in time t_i at cost c_i.

Find the smallest cost of a route that takes not longer than time T.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq T \leq 1000

1 \leq c_i \leq 1000

1 \leq t_i \leq 1000

The pairs (c_i, t_i) are distinct.

Input

Input is given from Standard Input in the following format:

N T
c_1 t_1
c_2 t_2
:
c_N t_N

Output

Print the smallest cost of a route that takes not longer than time T.

If there is no route that takes not longer than time T, print TLE instead.

Sample Input 1

3 70
7 60
1 80
4 50

Sample Output 1

4

The first route gets him home at cost 7.

The second route takes longer than time T = 70.

The third route gets him home at cost 4.

Thus, the cost 4 of the third route is the minimum.

Sample Input 2

4 3
1 1000
2 4
3 1000
4 500

Sample Output 2

TLE

There is no route that takes not longer than time T = 3.

Sample Input 3

5 9
25 8
5 9
4 10
1000 1000
6 1

Sample Output 3

5

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#define rep(i,n) for(ll i=0, i##_len=(n); i<i##_len; ++i)
#define rrep(i,n) for(ll i##_len=(n) ,i=i##_len-1;i>=0;--i)
#define repi(i,a,b) for(ll i=ll(a);i<=ll(b);++i)
#define ALL(f,x,...) ([&](decltype((x)) xxxx) { return (f)(begin(xxxx), end(xxxx), ## __VA_ARGS__); })(x)
#define lim 1000000007ll
#define Yes(flag) cout<<((flag)? "Yes":"No");
#define YES(flag) cout<<((flag)? "YES":"NO");
#define MSG(msg1,msg2,flag) cout<<((flag)? msg1:msg2);

#include<bits/stdc++.h>
using ll = long long;
using ull = unsigned long long;
using ld = long double;
using pii = std::pair<ll,ll>;
using namespace std;
template<class T>T 
chmin(T& a,T b){if(a>b){a=b;return true;}return false;}
template<class T>T 
chmax(T& a,T b){if(a<b){a=b;return true;}return false;}
template <class T> T 
gcd(T a, T b){if (a < b) {a ^= b;b ^= a;a ^= b;} return b ? gcd(b, a % b) : a;}
template <class T> T 
lcm(T a, T b){return a * b / gcd(a, b);}
vector<char> 
string_to_vector_char(const string& input){vector<char> out(input.length());rep(i,input.length()){out[i]=input[i];}return out;}
template <class T> map<T,int> 
count_same_elements(const vector<T>& v){map<T,int>cmap; for_each(v.begin(),v.end(),[&cmap](auto x){cmap[x]++;}); return cmap; }
template<class A,class B> vector<B> 
mapf(const vector<A>& v,const function<B(A)>& func){vector<B> v_(v.size());rep(i,v.size()){ v_[i]=func(v[i]); }return v_;}
template<class A,class B> vector<B> 
adjacent_map(const vector<A>& v,const function<B(A,A)>& func){vector<B> v_(v.size()-1);rep(i,v.size()-1){ v_[i]=func(v[i+1],v[i]); }return v_;}
template<class A> bool
all_of(const vector<A>& v){bool flag=true;rep(i,v.size()){ if(v[i]<1){flag=false;}; }return flag;}
template<class A> bool
any_of(const vector<A>& v){bool flag=false;rep(i,v.size()){ if(v[i]>0){flag=true; break;}; }return flag;}
template<class A> bool
none_of(const vector<A>& v){bool flag=true;rep(i,v.size()){ if(v[i]>0){flag=false;}; }return flag;}
template<class T>
void scan_vector(long long size,vector<T>& vector){
    vector.resize(size);
    for(long long i=0;i<size;++i){
        cin>>vector[i];
    }
}
int n,T;
vector<pii> c;
void input(){
    cin>>n>>T;
    c.resize(n);
    rep(i,n){
        cin>>c[i].first>>c[i].second;
        if(c[i].second>T){c[i].first=1e8;}
    }
}
void src(){
    if((*min_element(c.begin(),c.end())).first==1e8){
        cout<<"TLE";
    }else{
        cout<<(*min_element(c.begin(),c.end())).first;
    };
}   

int main(int argc,char* argv[]){
    ios::sync_with_stdio(false);
 //   ifstream in( argv[1] ); cin.rdbuf(in.rdbuf());
    input();
    src();    
    return 0;
}