Problem:
Score : 200 points

Problem Statement

N Snukes called Snuke 1, Snuke 2, ..., Snuke N live in a town.

There are K kinds of snacks sold in this town, called Snack 1, Snack 2, ..., Snack K. The following d_i Snukes have Snack i: Snuke A_{i, 1}, A_{i, 2}, \cdots, A_{i, {d_i}}.

Takahashi will walk around this town and make mischief on the Snukes who have no snacks. How many Snukes will fall victim to Takahashi's mischief?

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq K \leq 100

1 \leq d_i \leq N

1 \leq A_{i, 1} < \cdots < A_{i, d_i} \leq N

Input

Input is given from Standard Input in the following format:

N K
d_1
A_{1, 1} \cdots A_{1, d_1}
\vdots
d_K
A_{K, 1} \cdots A_{K, d_K}

Output

Print the answer.

Sample Input 1

3 2
2
1 3
1
3

Sample Output 1

1

Snuke 1 has Snack 1.

Snuke 2 has no snacks.

Snuke 3 has Snack 1 and 2.

Thus, there will be one victim: Snuke 2.

Sample Input 2

3 3
1
3
1
3
1
3

Sample Output 2

2

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

/*
 ABC-166
 */
#pragma warning(disable:4996)
#pragma comment(linker, "/STACK:336777216")
#pragma GCC optimize("Ofast")

#include<bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <functional>

using namespace std;
using namespace __gnu_pbds;

typedef long long ll;
#define int long long int
typedef complex<long double> cd;
const long double pi=acos(-1);
typedef double db;
typedef long double ldb;
typedef pair <int, int> pii;
typedef pair <db, db> pdd;
typedef vector<int> vi;
typedef vector<vector<int> > matrix;

#define m1 make_pair
#define pb push_back
#define flush fflush(stdout)
#define IOS std::ios::sync_with_stdio(false); cin.tie(NULL);cout.tie(NULL);
#define reset(x,v) memset(x,v,sizeof(x))

#define fi first
#define se second
#define endl "\n"
#define debug(x) (cerr << #x << ": " << x << "\n")
#define setbits(x) __builtin_popcount(x)
#define setbitsll(x) __builtin_popcountll(x)
#define all(x) x.begin(),x.end()
#define pii pair<int,int>

inline ll gcd(ll a,ll b){if(a==0) return b;return gcd(b%a,a);}
inline ll power(ll a,ll n,ll m){if(n==0)return 1;ll p=power(a,n/2,m);p=(p%m*p%m)%m;if(n%2) return (p%m*a%m)%m;else return p;}
const ll MOD =998244353;
const ll hell=1000000007;
const int INF = 1e17;
const ll LL_INF = 0x3f3f3f3f3f3f3f3f;
typedef tree<int, null_type, less<int>, rb_tree_tag,
tree_order_statistics_node_update>
ordered_set;

double startTime;
double getCurrentTime() {
    return ((double)clock() - startTime) / CLOCKS_PER_SEC;
}

const int N=300005;


void solve()
{
    int n,k;
    cin>>n>>k;
    int cnt[n+1]={0};int d,x;
    for(int i=0;i<k;i++)
    {
        cin>>d;
        for(int j=0;j<d;j++)
        {
            cin>>x;
            cnt[x]=1;
        }
    }
    int ans=0;
    for(int i=1;i<=n;i++)
        if(!cnt[i])
            ans++;
    cout<<ans<<endl;

}

int32_t main()
{
    IOS;
    // startTime=clock();
    int t;
    t=1;
    //cin>>t;
    while(t--)
    {
        solve();
    }
    // cout<<getCurrentTime()<<endl;
    return 0;
}