Problem:
Score : 400 points

Problem Statement

Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.

You are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.

Constraints

2 ≦ |s| ≦ 10^5

s consists of lowercase letters.

Partial Score

200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.

Input

The input is given from Standard Input in the following format:

s

Output

If there exists no unbalanced substring of s, print -1 -1.

If there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.

Sample Input 1

needed

Sample Output 1

2 5

The string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.

Sample Input 2

atcoder

Sample Output 2

-1 -1

The string atcoder contains no unbalanced substring.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include "bits/stdc++.h"
using namespace std;

#define Rep(i,n) for(int i=0;i<(n);i++)
#define For(i,n1,n2) for(int i=(n1);i<(n2);i++)
#define REP(i,n) for(ll i=0;i<(n);i++)
#define RREP(i,n) for(ll i=(n-1);i>=0;i--)
#define FOR(i,n1,n2) for(ll i=(n1);i<(n2);i++)
#define put(a) cout<<(a)<<"\n";
#define all(a)  (a).begin(),(a).end()
#define SORT(a) sort((a).begin(),(a).end())
#define TDARRAY(int,a,n,m) vector<vector<int>> a(n,vector<int>(m,0));
#define oorret 0
#define oor(x) [&](){try{x;} catch(const out_of_range& oor){return oorret;} return x;}()

typedef long long ll;
typedef pair<int, int> P;
template<typename T1,typename T2> inline bool chmin(T1 &a,T2 b){if(a>b){a=b;return 1;}return 0;}
template<typename T1,typename T2> inline bool chmax(T1 &a,T2 b){if(a<b){a=b;return 1;}return 0;}

int n;
string s;

int main(){
    cin >> s;
    n = s.size();
    if(n==2){
        if(s[0]==s[1]){
            cout << 1 << " " << 2 << endl;
            return 0;
        }else{
            cout << -1 << " " << -1 << endl;
            return 0;
        }
    }
    REP(i,n-2){
        int m=0;
        if(s[i]==s[i+1]){
            m++;
        }
        if(s[i]==s[i+2]){
            m++;
        }
        if(s[i+1]==s[i+2]){
            m++;
        }
        if(m>=1){
            cout << i+1 << " " << i+3 << endl;
            return 0;
        }
    }
    cout << -1 << " " << -1 << endl;
    return 0;
}