Problem:
Score : 200 points

Problem Statement

In the beginning, Takahashi has A cookies, and Aoki has B cookies.
They will perform the following operation alternately, starting from Takahashi:

If the number of cookies in his hand is odd, eat one of those cookies; if the number is even, do nothing. Then, give one-half of the cookies in his hand to the other person.

Find the numbers of cookies Takahashi and Aoki respectively have after performing K operations in total.

Constraints

1 \leq A,B \leq 10^9

1 \leq K \leq 100

A,B and K are integers.

Input

Input is given from Standard Input in the following format:

A B K

Output

Print the number of cookies Takahashi has, and the number of cookies Aoki has, in this order, after performing K operations in total.

Sample Input 1

5 4 2

Sample Output 1

5 3

The process will go as follows:

In the beginning, Takahashi and Aoki have 5 and 4 cookies, respectively.

Takahashi eats one cookie and gives two cookies to Aoki. They now have 2 and 6 cookies, respectively.

Aoki gives three cookies to Takahashi. They now have 5 and 3 cookies, respectively.

Sample Input 2

3 3 3

Sample Output 2

1 3

Sample Input 3

314159265 358979323 84

Sample Output 3

448759046 224379523

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <string>
#include <vector>
#include <algorithm>
using namespace std;
int main(){
    int a,b,k;
    cin >> a >> b >> k;
    bool flag = true;
    for(int i=1;i<=k;i++){
        if(flag == true){
        if(a%2 != 0){
            b = b +(a-1)/2;
            a = (a-1)/2;
        }else{
            b =  b +a/2;
            a = a/2;
        }
        flag = false;
        }else{
        if(b%2 != 0){
            a = a +(b-1)/2;
            b = (b-1)/2;
        }else{
            a =  a +b/2;
            b = b/2;
        }  
        flag = true;
        }
    }
    cout << a << " " << b << endl;
    return 0;
}