Problem:
Score : 700 points

Problem Statement

You are given four integers: H, W, h and w (1 ≤ h ≤ H, 1 ≤ w ≤ W).
Determine whether there exists a matrix such that all of the following conditions are held, and construct one such matrix if the answer is positive:

The matrix has H rows and W columns.

Each element of the matrix is an integer between -10^9 and 10^9 (inclusive).

The sum of all the elements of the matrix is positive.

The sum of all the elements within every subrectangle with h rows and w columns in the matrix is negative.

Constraints

1 ≤ h ≤ H ≤ 500

1 ≤ w ≤ W ≤ 500

Input

Input is given from Standard Input in the following format:

H W h w

Output

If there does not exist a matrix that satisfies all of the conditions, print No.

Otherwise, print Yes in the first line, and print a matrix in the subsequent lines in the following format:

a_{11} ... a_{1W}
:
a_{H1} ... a_{HW}

Here, a_{ij} represents the (i,\ j) element of the matrix.

Sample Input 1

3 3 2 2

Sample Output 1

Yes
1 1 1
1 -4 1
1 1 1

The sum of all the elements of this matrix is 4, which is positive.
Also, in this matrix, there are four subrectangles with 2 rows and 2 columns as shown below. For each of them, the sum of all the elements inside is -1, which is negative.

Sample Input 2

2 4 1 2

Sample Output 2

No

Sample Input 3

3 4 2 3

Sample Output 3

Yes
2 -5 8 7
3 -5 -4 -5
2 1 -1 7

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>

const int ms = 505;

int a[ms][ms];

int main()
{
	int n, m, h, w;
	while(std::cin >> n >> m >> h >> w)
	{
		if(h == w && h == 1)
		{
			std::cout << "No\n";
			continue;
		}
		int area = n * m;
		for(int i = 0; i < n; i++)
		{
			for(int j = 0; j < m; j++)
			{
				if(i % h == 0 && j % w == 0)
					a[i][j] = area - 1;
				else if(i % h == h - 1 && j % w == w - 1)
					a[i][j] = -area;
				else
					a[i][j] = 0;
			}
		}
		int sum = 0;
		for(int i = 0; i < n; i++)
		{
			for(int j = 0; j < m; j++)
			{
				sum += a[i][j];
			}
		}
		if(sum > 0)
		{
			std::cout << "Yes\n";
			for(int i = 0; i < n; i++)
			{
				for(int j = 0; j < m; j++)
				{
					if(j)
						std::cout << ' ';
					std::cout << a[i][j];
				}
				std::cout << '\n';
			}
		}
		else
		{
			std::cout << "No\n";
		}
	}
}