Problem:
Score : 400 points

Problem Statement

Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.

You are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.

Constraints

2 ≦ |s| ≦ 10^5

s consists of lowercase letters.

Partial Score

200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.

Input

The input is given from Standard Input in the following format:

s

Output

If there exists no unbalanced substring of s, print -1 -1.

If there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.

Sample Input 1

needed

Sample Output 1

2 5

The string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.

Sample Input 2

atcoder

Sample Output 2

-1 -1

The string atcoder contains no unbalanced substring.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <string>
using namespace std;

int main(){
	string str;
	cin >> str;
	long** cnt=(long**)malloc(sizeof(long*)*100000);
	for(int i=0;i<100000;i++){
		cnt[i] = (long*)malloc(sizeof(long)*26);
		for(int j=0;j<26;j++){
			cnt[i][j] = 0;
		}
	}
	// cout << "OK" << endl;
	long long total_cnt[26]={};
	char res_word='0';
	int start_index,fin_index;
	int length=str.length();
	long thr;

	if(length < 2){
		cout << "-1 -1" <<endl;
	}else{
		for(int i=0;i<length;i++){
			total_cnt[str[i]-'a']++;
			for(int a=0;a<26;a++){
				cnt[i][a]=total_cnt[a];
			}
		}
		// cout << "OK" << endl;
		for(int a=0;a<26;a++){
			for(int i=length-1;i>=1;i--){
				thr = (i+1)/2;
				if(cnt[i][a] > thr){
					cout << 1 << " " << i+1 << endl;
					return 0;
				}
			}
		}
		// cout << "OK" << endl;
		for(int a=0;a<26;a++){
			for(int i=length-1;i>=2;i--){
				for(int j=0;j<=i-2;j++){
					thr = (i-j+1)/2;
					if(cnt[i][a]-cnt[j][a]>thr){
						// cout << (char)('a'+a)<<endl;
						// cout << thr << endl;
						cout << j+1 << " " << i+1 << endl;
						return 0;
					}
				}
			}
		}
		cout << "-1 -1" << endl;
	}
}