Problem:
Score : 200 points

Problem Statement

In a factory, there are N robots placed on a number line.
Robot i is placed at coordinate X_i and can extend its arms of length L_i in both directions, positive and negative.

We want to remove zero or more robots so that the movable ranges of arms of no two remaining robots intersect.
Here, for each i (1 \leq i \leq N), the movable range of arms of Robot i is the part of the number line between the coordinates X_i - L_i and X_i + L_i, excluding the endpoints.

Find the maximum number of robots that we can keep.

Constraints

1 \leq N \leq 100,000

0 \leq X_i \leq 10^9 (1 \leq i \leq N)

1 \leq L_i \leq 10^9 (1 \leq i \leq N)

If i \neq j, X_i \neq X_j.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
X_1 L_1
X_2 L_2
\vdots
X_N L_N

Output

Print the maximum number of robots that we can keep.

Sample Input 1

4
2 4
4 3
9 3
100 5

Sample Output 1

3

By removing Robot 2, we can keep the other three robots.

Sample Input 2

2
8 20
1 10

Sample Output 2

1

Sample Input 3

5
10 1
2 1
4 1
6 1
8 1

Sample Output 3

5

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef long double ld;
const ll mod = 1e9 + 7;
#define pival 3.14159265358979323846264338327950L
#define pll pair<ll,ll>
#define pb push_back
#define mp make_pair
#define fi first
#define se second
#define pqq priority_queue
#define all(a) a.begin(), a.end()
#define sz(a) (ll)(a.size())
#define endl '\n'
#define DEBUG
#ifdef DEBUG
#define debug(...) __f(#__VA_ARGS__, __VA_ARGS__)
    template <typename Arg1>
    void __f(const char* name, Arg1&& arg1)
    {
        cerr << name << " = " << arg1 << endl;
    }
    template <typename Arg1, typename... Args>
    void __f(const char* names, Arg1&& arg1, Args&&... args)
    {
        const char* comma = strchr(names + 1, ','); cerr.write(names, comma - names) << " = " << arg1 << " || ";
        __f(comma+1, args...);
    }
#else
#define debug(...)
#endif
template <class Ch, class Tr, class Container>
basic_ostream <Ch, Tr> & operator << (basic_ostream <Ch, Tr> & os, Container const& x) {
    os << "{ ";
    for(auto& y : x) os << y << " ; ";
    return os << "}";
}
template <class X, class Y>
ostream & operator << (ostream & os, pair <X, Y> const& p) {
    return os << "[ " << p.first << ", " << p.second << "]" ;
}
ll power(ll x, ll y, ll p)
{ 
    ll res = 1;  
    x = x % p;
    while (y > 0) { 
        if (y & 1) res = (res * x) % p; 
        y = y >> 1;
        x = (x * x) % p;   
    } 
    return res; 
}
int main()
{
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    cout.tie(NULL);
 	ll n;
 	cin >> n;
 	set <pll> as;
 	ll a, b;	
 	while (n--) {
 		cin >> a >> b;
 		as.insert({a + b  - 1, a - b + 1});
 	}
 	ll prev = -1e18;
 	ll ans = 0;
 	while (sz(as) > 0) {
 		pll temp = *as.begin();
 		// debug(prev, temp);
 		if (temp.se >= prev) {
 			ans++;
 			prev = temp.fi;
 		}
 		as.erase(as.begin());
 	}
 	cout << ans << endl;
	return 0;
}