Problem:
Score : 400 points

Problem Statement

There is a knight - the chess piece - at the origin (0, 0) of a two-dimensional grid.

When the knight is at the square (i, j), it can be moved to either (i+1,j+2) or (i+2, j+1).

In how many ways can the knight reach the square (X, Y)?

Find the number of ways modulo 10^9 + 7.

Constraints

1 \leq X \leq 10^6

1 \leq Y \leq 10^6

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

Print the number of ways for the knight to reach (X, Y) from (0, 0), modulo 10^9 + 7.

Sample Input 1

3 3

Sample Output 1

2

There are two ways: (0,0) \to (1,2) \to (3,3) and (0,0) \to (2,1) \to (3,3).

Sample Input 2

2 2

Sample Output 2

0

The knight cannot reach (2,2).

Sample Input 3

999999 999999

Sample Output 3

151840682

Print the number of ways modulo 10^9 + 7.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
#define rep(i, a, b) for (int i = a; i < (int)b; i++)
#define all(v) v.begin(), v.end()
const int MOD = 1e9 + 7;
const int INF = 1e9;
//'A' = 65, 'Z' = 90, 'a' = 97, 'z' = 122

const ll MAX = 1000000;
ll fac[MAX], finv[MAX], inv[MAX];

void cominit() {
    fac[0] = fac[1] = 1;
    finv[0] = finv[1] = 1;
    inv[1] = 1;
    for (ll i = 2; i < MAX; i++){
        fac[i] = fac[i - 1] * i % MOD;
        inv[i] = MOD - inv[MOD%i] * (MOD / i) % MOD;
        finv[i] = finv[i - 1] * inv[i] % MOD;
    }
}

ll com(ll n, ll k){
    if (n < k) return 0;
    if (n < 0 || k < 0) return 0;
    return fac[n] * (finv[k] * finv[n - k] % MOD) % MOD;
}

int main() {
    ll x, y;
    cin >> x >> y;
    if ((x + y) % 3 != 0) {
        cout << 0 << endl;
        return 0;
    }
    ll mx = max(x, y);
    ll mn = min(x, y);
    if (mx / 2 > mn) {
        cout << 0 << endl;
        return 0;
    }
    if (mx / 2 == mn) {
        cout << 1 << endl;
        return 0;
    }
    ll x2 = 0;
    ll y2 = 0;
    while (x2 - x != -(y2 - y)) {
        x2 += 2;
        y2 += 1;
    }
    cominit();
    cout << com(y2, x2 - x) << endl;
    return 0;
}