Problem:
Score : 200 points

Problem Statement

Given are 1-digit positive integers a and b. Consider these two strings: the concatenation of b copies of the digit a, and the concatenation of a copies of the digit b. Which of these is lexicographically smaller?

Constraints

1 \leq a \leq 9

1 \leq b \leq 9

a and b are integers.

Input

Input is given from Standard Input in the following format:

a b

Output

Print the lexicographically smaller of the two strings. (If the two strings are equal, print one of them.)

Sample Input 1

4 3

Sample Output 1

3333

We have two strings 444 and 3333. Between them, 3333 is the lexicographically smaller.

Sample Input 2

7 7

Sample Output 2

7777777

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <regex>
#include "bits/stdc++.h"
#define FOR(i, s, e) for (int i = int(s); i < int(e); ++i)
#define REP(i, e) FOR(i, 0, e)
#define INF (INT_MAX / 2)
#define LINF (LLONG_MAX / 2)
#define EPS (1.0e-8)
#define mkpr make_pair
const int MGN = 10;
const int ARY_SZ_MAX = (int)1e7;
using namespace std;
using ll = long long; using ull = unsigned long long;
using vi = vector<int>; using vvi = vector<vi>;
using vc = vector<char>; using vvc = vector<vc>;
using vb = vector<bool>; using vvb = vector<vb>;
using vl = vector<ll>; using vvl = vector<vl>;
using vd = vector<double>; using vs = vector<string>;
using pii = pair<int, int>; using pll = pair<ll, ll>; using psl = pair<string, ll>;


int main() {
  cin.tie(0);
  ios::sync_with_stdio(false);


  int A,B; cin>>A>>B;
  string s = string(B, '0'+A);  
  string t = string(A, '0'+B);

  if (s.compare(t) <= 0) cout << s << endl;
  else cout << t << endl;

  return 0;
}