Problem:
Score : 200 points

Problem Statement

Print all the integers that satisfies the following in ascending order:

Among the integers between A and B (inclusive), it is either within the K smallest integers or within the K largest integers.

Constraints

1 \leq A \leq B \leq 10^9

1 \leq K \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B K

Output

Print all the integers that satisfies the condition above in ascending order.

Sample Input 1

3 8 2

Sample Output 1

3
4
7
8

3 is the first smallest integer among the integers between 3 and 8.

4 is the second smallest integer among the integers between 3 and 8.

7 is the second largest integer among the integers between 3 and 8.

8 is the first largest integer among the integers between 3 and 8.

Sample Input 2

4 8 3

Sample Output 2

4
5
6
7
8

Sample Input 3

2 9 100

Sample Output 3

2
3
4
5
6
7
8
9

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#include <iostream>
#include <vector>
#include <algorithm>
#include <cmath>
#include <string>
#include <queue>
#include <stack>
#include <set>
#include <map>
#include <iomanip>
#include <utility>
#include <tuple>
#include <functional>
#include <bitset>
#include <cassert>
#include <complex>
#include <stdio.h>
#include <time.h>
#include <numeric>
#include <unordered_map>
#include <unordered_set>

using namespace std;

#define vv vector< vector< int > >
#define ll long long
#define ALL(a) (a).begin(), (a).end()
const long long mod = 1000000000 + 7;
const long long INF = 9e18;
const double PI = 3.14159265358979323846;

ll gcd(ll a, ll b){if (b == 0) return a;return gcd(b, a % b);}
ll lcm(ll a, ll b) { return a / gcd(a, b) * b; }

int dx[4] = {1, -1, 0, 0};
int dy[4] = {0, 0, 1, -1};


int main(){
    int A, B, K;
    cin >> A >> B >> K;
    int r = B - A + 1;
    if(r <= K * 2) {
        for(int i = A; i <= B; i++) {
            cout << i << endl;
        }
    }
    else {
        for(int i = A; i < A+K; ++i){
            cout << i << endl;
        }
        for(int i = B-K+1; i <= B; i++) {
            cout << i << endl;
        }
    }
    return 0;
}