Problem:
Score : 100 points

Problem Statement

You are given a string S of length 3 consisting of a, b and c. Determine if S can be obtained by permuting abc.

Constraints

|S|=3

S consists of a, b and c.

Input

Input is given from Standard Input in the following format:

S

Output

If S can be obtained by permuting abc, print Yes; otherwise, print No.

Sample Input 1

bac

Sample Output 1

Yes

Swapping the first and second characters in bac results in abc.

Sample Input 2

bab

Sample Output 2

No

Sample Input 3

abc

Sample Output 3

Yes

Sample Input 4

aaa

Sample Output 4

No

Solution in C++14 (Clang 3.8.0) (judge verdict: Accepted)

#include <iostream>
#include <string.h>
#include <stdio.h>
#include <map>
#include <vector>
#include <math.h>
#include <algorithm>
using namespace std;

#define rep(i,a) for(int i=0; i<a; i++)
#define rrep(i,a) for(int i=a; i>=0; i--)
#define loop3(i,j,k,a) for(int i=0; i<a; i++)for(int j=0; j<a; j++)if(i!=j)for(int k=0; k<a; k++)if(i!=k&&j!=k)
#define loop4(i,j,k,l,a) for(int i=0; i<a; i++)for(int j=0; j<a; j++)if(i!=j)for(int k=0; k<a; k++)if(i!=k&&j!=k)for(int l=0; l<a; l++)if(i!=l&&j!=l&&k!=l)
#define rep1(i,a) for(int i=1; i<=a; i++)

#define scnd1(a) scanf("%d", &a)
#define scnd2(a,b) scanf("%d%d", &a,&b)
#define scnd3(a,b,c) scanf("%d%d%d", &a,&b,&c)
#define scnd4(a,b,c,d) scanf("%d%d%d%d", &a,&b,&c,&d)

#define cin1(a) cin >> a;
#define cin2(a,b) cin >> a >> b;
#define cin3(a,b,c) cin >> a >> b >> c;
#define cin4(a,b,c,d) cin >> a >> b >> c >> d;
#define cout1(a) cout << a << endl;
#define cout2(a,b) cout << a << " " << b << endl;
#define cout3(a,b,c) cout << a << " " << b << " " << c << endl;
#define cout4(a,b,c,d) cout << a << " " << b << " " << c << " " << d << endl;
#define prtd1(a) printf("%d\n", a)
#define prtd2(a,b) printf("%d %d\n", a,b)
#define prtd3(a,b,c) printf("%d %d %d\n", a,b,c)
#define prtd4(a,b,c,d) printf("%d %d %d %d\n", a,b,c,d)

#define mem(a,n) memset( a, n, sizeof(a))

typedef long long ll;

int main() {
    string s;
    cin >> s;
    
    if ( s=="abc" || s=="acb" || s=="bac" || s=="bca" || s=="cab" || s=="cba") {
        cout1("Yes");
    } else {
        cout1("No");
    }
}