Problem:
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Maximum Profit

You can obtain profits from foreign exchange margin transactions. For example, if you buy 1000 dollar at a rate of 100 yen per dollar, and sell them at a rate of 108 yen per dollar, you can obtain (108 - 100) × 1000 = 8000 yen.

Write a program which reads values of a currency $R_t$ at a certain time $t$ ($t = 0, 1, 2, ... n-1$), and reports the maximum value of $R_j - R_i$ where $j > i$ .

Input

The first line contains an integer $n$. In the following $n$ lines, $R_t$ ($t = 0, 1, 2, ... n-1$) are given in order.

Output

Print the maximum value in a line.

Constraints

$2 \leq n \leq 200,000$

$1 \leq R_t \leq 10^9$

Sample Input 1

6
5
3
1
3
4
3

Sample Output 1

3

Sample Input 2

3
4
3
2

Sample Output 2

-1

Solution in C++ (judge verdict: Accepted)

#include<cstdio>
#include<iostream>
#include<cstdlib>
#include<cmath>
#include<vector>
#include<list>
#include<map>
#include<algorithm>

using namespace std;

int main()
{
    int n;
    cin >> n;

    vector<int> r;
    for (int i = 0; i < n; i++) {
        int ri;
        cin >> ri;
        r.push_back(ri);
    }

    int diffmax = r[1] - r[0];
    int rmin = r[0];
    for (int i = 1; i < n; i++) {
        diffmax = max(diffmax, r[i] - rmin);
        rmin = min(rmin, r[i]);
    }

    cout << diffmax << endl;

    return 0;
}