Problem:
Score : 100 points

Problem Statement

You have three tasks, all of which need to be completed.

First, you can complete any one task at cost 0.

Then, just after completing the i-th task, you can complete the j-th task at cost |A_j - A_i|.

Here, |x| denotes the absolute value of x.

Find the minimum total cost required to complete all the task.

Constraints

All values in input are integers.

1 \leq A_1, A_2, A_3 \leq 100

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

Print the minimum total cost required to complete all the task.

Sample Input 1

1 6 3

Sample Output 1

5

When the tasks are completed in the following order, the total cost will be 5, which is the minimum:

Complete the first task at cost 0.

Complete the third task at cost 2.

Complete the second task at cost 3.

Sample Input 2

11 5 5

Sample Output 2

6

Sample Input 3

100 100 100

Sample Output 3

0

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;

typedef long long lli;
typedef pair<lli,lli> pll;
typedef vector<lli> vcL;
typedef vector<pll> vPL;


void solve() {
	lli n = 3;
//	cin >> n;
	
	lli _min = INT_MAX, _max = 0;
	
	vcL num( n, 0 );
	
	for (int i = 0; i < n; ++i) {
		cin >> num[i];
		_min = min( _min, num[i] );
		_max = max( _max, num[i] );
	}
	
	cout << _max-_min << '\n';
}

int main() {
	int t = 1;
//	cin >> t;
	for (int i = 1; i <= t; ++i) {
		solve();
	}
	return 0;
}