Problem:
Score : 100 points

Problem Statement

There is a set A = \{ a_1, a_2, \ldots, a_N \} consisting of N positive integers.
Taro and Jiro will play the following game against each other.

Initially, we have a pile consisting of K stones.
The two players perform the following operation alternately, starting from Taro:

Choose an element x in A, and remove exactly x stones from the pile.

A player loses when he becomes unable to play.
Assuming that both players play optimally, determine the winner.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq K \leq 10^5

1 \leq a_1 < a_2 < \cdots < a_N \leq K

Input

Input is given from Standard Input in the following format:

N K
a_1 a_2 \ldots a_N

Output

If Taro will win, print First; if Jiro will win, print Second.

Sample Input 1

2 4
2 3

Sample Output 1

First

If Taro removes three stones, Jiro cannot make a move.
Thus, Taro wins.

Sample Input 2

2 5
2 3

Sample Output 2

Second

Whatever Taro does in his operation, Jiro wins, as follows:

If Taro removes two stones, Jiro can remove three stones to make Taro unable to make a move.

If Taro removes three stones, Jiro can remove two stones to make Taro unable to make a move.

Sample Input 3

2 7
2 3

Sample Output 3

First

Taro should remove two stones. Then, whatever Jiro does in his operation, Taro wins, as follows:

If Jiro removes two stones, Taro can remove three stones to make Jiro unable to make a move.

If Jiro removes three stones, Taro can remove two stones to make Jiro unable to make a move.

Sample Input 4

3 20
1 2 3

Sample Output 4

Second

Sample Input 5

3 21
1 2 3

Sample Output 5

First

Sample Input 6

1 100000
1

Sample Output 6

Second

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;
#include <ext/pb_ds/assoc_container.hpp> 
#include <ext/pb_ds/tree_policy.hpp> 
using namespace __gnu_pbds;   

typedef long long int ll;
typedef long double ld;
typedef pair<ll,ll> isPair;
using vvll = vector< vector<ll> >;
using vll = vector<ll> ;
#define Pll pair<ll,ll>
#define vpll vector<pll>
#define sll set<ll>
#define mll map<ll,ll>

const ll inf=1e18;
const ll maxs = 100005;
const ll mod = 1e9+7;

#define mp make_pair
#define pb push_back
#define pf push_front
#define pob pop_back
#define pof pop_front
#define ff first
#define ss second
#define LB lower_bound
#define UB upper_bound
#define line cout<<endl;
#define fr(i,a,b) for(int i=a;i<=b;++i)
#define all(n) n.begin(),n.end()
#define present(s,x) (s.find(x) != s.end()) 
#define cpresent(s,x) (find(all(s),x) != s.end()) 
#define tr(container, it) for(__typeof(container.begin()) it = container.begin(); it != container.end(); it++) 
#define fastio(); ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);
#define mst(x,a) memset(x,a,sizeof(x))

ll a[maxs];
ll dp[maxs];
ll n,k;

void solve()
{
    for(ll i=0;i<n;i++)
        cin>>a[i];
    
    for(ll i=1;i<=k;i++)
        for(ll j=0;j<n;j++)
            if(i>=a[j])
                dp[i] = dp[i]|(!dp[i-a[j]]);
    if(dp[k])
        cout<<"first";
    else    
        cout<<"second";
        
}

int main(){
    cin>>n>>k;
	solve();
	return 0;
}