Problem:
Score : 300 points

Problem Statement

There are N slimes lining up from left to right. The colors of these slimes will be given as a string S of length N consisting of lowercase English letters. The i-th slime from the left has the color that corresponds to the i-th character of S.

Adjacent slimes with the same color will fuse into one larger slime without changing the color. If there were a slime adjacent to this group of slimes before fusion, that slime is now adjacent to the new larger slime.

Ultimately, how many slimes will be there?

Constraints

1 \leq N \leq 10^5

|S| = N

S consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

N
S

Output

Print the final number of slimes.

Sample Input 1

10
aabbbbaaca

Sample Output 1

5

Ultimately, these slimes will fuse into abaca.

Sample Input 2

5
aaaaa

Sample Output 2

1

All the slimes will fuse into one.

Sample Input 3

20
xxzaffeeeeddfkkkkllq

Sample Output 3

10

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <cstdio>
#include <iostream>
#include <cstring>
#include <algorithm>
#include <cmath>
#include <vector>
#include <string>
using namespace std;
typedef long long ll;
const int maxn=2e5+10;
ll n,m,k,d,q;

int b[maxn],a[maxn];

int main()
{
    string s;
    int n;
    cin>>n;
    cin>>s;
    char last;
    int sum=0;
    for(int i=0;i<n;i++)
    {
        if(i==0)
        {
            last=s[i];
            sum++;
        }
        else{
            if(s[i]!=last)
                last=s[i],sum++;
        }

    }
    cout<<sum<<endl;
    return 0;
}