Problem:
Score : 100 points

Problem Statement

Cat Snuke is learning to write characters.
Today, he practiced writing digits 1 and 9, but he did it the other way around.

You are given a three-digit integer n written by Snuke.
Print the integer obtained by replacing each digit 1 with 9 and each digit 9 with 1 in n.

Constraints

111 \leq n \leq 999

n is an integer consisting of digits 1 and 9.

Input

Input is given from Standard Input in the following format:

n

Output

Print the integer obtained by replacing each occurrence of 1 with 9 and each occurrence of 9 with 1 in n.

Sample Input 1

119

Sample Output 1

991

Replace the 9 in the ones place with 1, the 1 in the tens place with 9 and the 1 in the hundreds place with 9. The answer is 991.

Sample Input 2

999

Sample Output 2

111

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>

using namespace std;

typedef long long ll;

#define MOD (int)1e9+7
#define rep(i,a,b) for(int i=a;i<b;++i)
#define rrep(i,a,b) for(int i=a;i>b;--i)
#define vi vector<int>
#define vl vector<ll>
#define ld long double
#define vvi vector<vector<int>>
#define vvl vector<vector<long long>>
#define pii pair<int,int>
#define pll pair<long,long>
#define vpii vector<pii>
#define vpll vector<pll>
#define ff first
#define ss second
#define pb push_back
#define mp make_pair
#define PI 3.1415926535897932384626433832795
#define fix(f,n) fixed<<setprecision(n)<<f
#define all(x) x.begin(),x.end()

ll powM(ll a,ll b,ll m )
{ 
  a%=m;
  ll ans=1;
  while(b>0)
  {
    if(b&1)ans=ans*a%m;
    a=a*a%m;
    b>>=1;
  }

return ans;
}



int main()
{
   ios_base::sync_with_stdio(false);
    cin.tie(NULL);

int n;
cin>>n;

ll a=n%10;

if(a==1)a=9;
else if(a==9)a=1;

ll b=(n/10)%10;
if(b==1)b=9;
else if(b==9)b=1;
ll c=(n/100)%10;
if(c==1)c=9;
else if(c==9)c=1;

cout<<100*c+10*b+a<<"\n";

return 0;

}