Problem:
Score : 300 points

Problem Statement

Given is a permutation P_1, \ldots, P_N of 1, \ldots, N.
Find the number of integers i (1 \leq i \leq N) that satisfy the following condition:

For any integer j (1 \leq j \leq i), P_i \leq P_j.

Constraints

1 \leq N \leq 2 \times 10^5

P_1, \ldots, P_N is a permutation of 1, \ldots, N.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
P_1 ... P_N

Output

Print the number of integers i that satisfy the condition.

Sample Input 1

5
4 2 5 1 3

Sample Output 1

3

i=1, 2, and 4 satisfy the condition, but i=3 does not - for example, P_i > P_j holds for j = 1.

Similarly, i=5 does not satisfy the condition, either. Thus, there are three integers that satisfy the condition.

Sample Input 2

4
4 3 2 1

Sample Output 2

4

All integers i (1 \leq i \leq N) satisfy the condition.

Sample Input 3

6
1 2 3 4 5 6

Sample Output 3

1

Only i=1 satisfies the condition.

Sample Input 4

8
5 7 4 2 6 8 1 3

Sample Output 4

4

Sample Input 5

1
1

Sample Output 5

1

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

//
//  main.cpp
//  CoderWork
//
//  Created by Minoru Hayashi on 2020/02/29.
//  Copyright © 2020 Minoru Hayashi. All rights reserved.
//

#include <bits/stdc++.h>
using namespace std;

#define REP(i,n) for (int i=0; i<(n); i++)
#define REP2(i,x,n) for (int i=x; i<(n); i++)
#define ALL(n) begin(n), end(n)



void solve(void){

  int N;
  
  cin >> N;
  
  vector<int> A(N,0);
  
  REP(i,N){
    cin >> A.at(i);
  }
  
  int T = 1;
  int MN[N];
  MN[0] = A[0];
  REP2(i,1,N){
    if(MN[i-1] >= A.at(i)){
      T++;
    }
    else
    {
      MN[i] = A.at(i);
    }
  }
  
  cout << T << endl;

  return;
}

int main(int argc, const char * argv[]) {



    // cinを高速にするためのおまじない
    cin.tie(0);
    ios::sync_with_stdio(false);
  
    solve();
 
    return 0;
}