Problem:
Score: 300 points

Problem Statement

M-kun is a student in Aoki High School, where a year is divided into N terms.

There is an exam at the end of each term. According to the scores in those exams, a student is given a grade for each term, as follows:

For the first through (K-1)-th terms: not given.

For each of the K-th through N-th terms: the multiplication of the scores in the last K exams, including the exam in the graded term.

M-kun scored A_i in the exam at the end of the i-th term.

For each i such that K+1 \leq i \leq N, determine whether his grade for the i-th term is strictly greater than the grade for the (i-1)-th term.

Constraints

2 \leq N \leq 200000

1 \leq K \leq N-1

1 \leq A_i \leq 10^{9}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
A_1 A_2 A_3 \ldots A_N

Output

Print the answer in N-K lines.

The i-th line should contain Yes if the grade for the (K+i)-th term is greater than the grade for the (K+i-1)-th term, and No otherwise.

Sample Input 1

5 3
96 98 95 100 20

Sample Output 1

Yes
No

His grade for each term is computed as follows:

3-rd term: (96 \times 98 \times 95) = 893760

4-th term: (98 \times 95 \times 100) = 931000

5-th term: (95 \times 100 \times 20) = 190000

Sample Input 2

3 2
1001 869120 1001

Sample Output 2

No

Note that the output should be No if the grade for the 3-rd term is equal to the grade for the 2-nd term.

Sample Input 3

15 7
3 1 4 1 5 9 2 6 5 3 5 8 9 7 9

Sample Output 3

Yes
Yes
No
Yes
Yes
No
Yes
Yes

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;
#define rep(i, N) for (long long i = 0; i < N; i++)
using ll = long long;

const string YES = "Yes";
const string NO = "No";

void solve(long long N, long long K, std::vector<long long> A) {
    vector<ll> mulvec(N);
    mulvec[0] = A[0];
    for (ll i = 1; i < N; i++) {
        if (i < K) {
            mulvec[i] = mulvec[i - 1] * A[i];
            continue;
        }
        mulvec[i] = mulvec[i - 1] * A[i];
        mulvec[i] /= A[i - K];
    }
    for (ll i = K; i < N; i++) {
        if (mulvec[i] > mulvec[i - 1]) {
            cout << YES << endl;
        } else {
            cout << NO << endl;
        }
    }
}

int main() {
    long long N;
    scanf("%lld", &N);
    long long K;
    scanf("%lld", &K);
    std::vector<long long> A(N);
    for (int i = 0; i < N; i++) {
        scanf("%lld", &A[i]);
    }
    solve(N, K, std::move(A));
    return 0;
}