Problem:
Score : 100 points

Problem Statement

You have three tasks, all of which need to be completed.

First, you can complete any one task at cost 0.

Then, just after completing the i-th task, you can complete the j-th task at cost |A_j - A_i|.

Here, |x| denotes the absolute value of x.

Find the minimum total cost required to complete all the task.

Constraints

All values in input are integers.

1 \leq A_1, A_2, A_3 \leq 100

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

Print the minimum total cost required to complete all the task.

Sample Input 1

1 6 3

Sample Output 1

5

When the tasks are completed in the following order, the total cost will be 5, which is the minimum:

Complete the first task at cost 0.

Complete the third task at cost 2.

Complete the second task at cost 3.

Sample Input 2

11 5 5

Sample Output 2

6

Sample Input 3

100 100 100

Sample Output 3

0

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>

#define each(i, c) for (auto& i : c)
#define unless(cond) if (!(cond))

using namespace std;

typedef long long int lli;
typedef unsigned long long ull;
typedef complex<double> point;

template <typename P, typename Q>
ostream& operator<<(ostream& os, pair<P, Q> p)
{
  os << "(" << p.first << "," << p.second << ")";
  return os;
}

template <typename T>
ostream& operator<<(ostream& os, vector<T> v)
{
  os << "(";
  each (i, v)
    os << i << ",";
  os << ")";
  return os;
}

int main(int argc, char* argv[])
{
  ios_base::sync_with_stdio(0);
  cin.tie(0);

  vector<int> a(3);
  while (cin >> a[0] >> a[1] >> a[2]) {
    sort(a.begin(), a.end());
    cout << (a[2] - a[1]) + (a[1] - a[0]) << endl;
  }

  return 0;
}