Problem:
Score : 100 points

Problem Statement

There is a set A = \{ a_1, a_2, \ldots, a_N \} consisting of N positive integers.
Taro and Jiro will play the following game against each other.

Initially, we have a pile consisting of K stones.
The two players perform the following operation alternately, starting from Taro:

Choose an element x in A, and remove exactly x stones from the pile.

A player loses when he becomes unable to play.
Assuming that both players play optimally, determine the winner.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq K \leq 10^5

1 \leq a_1 < a_2 < \cdots < a_N \leq K

Input

Input is given from Standard Input in the following format:

N K
a_1 a_2 \ldots a_N

Output

If Taro will win, print First; if Jiro will win, print Second.

Sample Input 1

2 4
2 3

Sample Output 1

First

If Taro removes three stones, Jiro cannot make a move.
Thus, Taro wins.

Sample Input 2

2 5
2 3

Sample Output 2

Second

Whatever Taro does in his operation, Jiro wins, as follows:

If Taro removes two stones, Jiro can remove three stones to make Taro unable to make a move.

If Taro removes three stones, Jiro can remove two stones to make Taro unable to make a move.

Sample Input 3

2 7
2 3

Sample Output 3

First

Taro should remove two stones. Then, whatever Jiro does in his operation, Taro wins, as follows:

If Jiro removes two stones, Taro can remove three stones to make Jiro unable to make a move.

If Jiro removes three stones, Taro can remove two stones to make Jiro unable to make a move.

Sample Input 4

3 20
1 2 3

Sample Output 4

Second

Sample Input 5

3 21
1 2 3

Sample Output 5

First

Sample Input 6

1 100000
1

Sample Output 6

Second

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;

#define fio ios::sync_with_stdio(0);cin.tie(0);cout.tie(0)
#define per(i,n) for (int i=(int)(n)-1;i>=0;i--)
#define For(i,n) for (int i=1;i<=(int)(n);i++)
#define rep(i,n) for (int i=0;i<(int)(n);i++)
#define all(x) (x).begin(),(x).end()
#define Max(a,b,c) max(a,max(b,c))
#define Min(a,b,c) min(a,min(b,c))
#define pii pair<int,int>
#define vi vector <int>
#define lb lower_bound
#define ub upper_bound
#define ll long long
#define pb push_back
#define re return
#define se second
#define fi first
const int INF=0x7fffffff;
const int MAXN=100+3;

int n,k,a[MAXN];
bool f[100003];

int main(){
	cin>>n>>k;
	rep(i,n){
		cin>>a[i];
	}
	for (int i=a[0];i<=k;i++){
		rep(j,n){
			if (i-a[j]<0) break;
			f[i]|=(!f[i-a[j]]);
		}
	}
	cout<<(f[k]?"First":"Second")<<endl;
	re 0;
}