Problem:
Score : 100 points

Problem Statement

Takahashi has K 500-yen coins. (Yen is the currency of Japan.)
If these coins add up to X yen or more, print Yes; otherwise, print No.

Constraints

1 \leq K \leq 100

1 \leq X \leq 10^5

Input

Input is given from Standard Input in the following format:

K X

Output

If the coins add up to X yen or more, print Yes; otherwise, print No.

Sample Input 1

2 900

Sample Output 1

Yes

Two 500-yen coins add up to 1000 yen, which is not less than X = 900 yen.

Sample Input 2

1 501

Sample Output 2

No

One 500-yen coin is worth 500 yen, which is less than X = 501 yen.

Sample Input 3

4 2000

Sample Output 3

Yes

Four 500-yen coins add up to 2000 yen, which is not less than X = 2000 yen.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;

#define SZ(c) int(c.size())
#define ALL(c) c.begin(), c.end()
#define pb  push_back

typedef vector<int> vi;
typedef vector<pair<int,int> > vii;
typedef long long ll;

using int_type = int64_t;

const int N = 2e5 + 3;

int main() {

    int_type k, x;
    cin >> k >> x; 
    if(500 * k >= x)
        cout << "Yes\n";
    else 
        cout << "No\n"; 

    return 0;
}