Problem:
Score : 600 points

Problem Statement

AtCoDeer the deer has N cards with positive integers written on them. The number on the i-th card (1≤i≤N) is a_i.
Because he loves big numbers, he calls a subset of the cards good when the sum of the numbers written on the cards in the subset, is K or greater.

Then, for each card i, he judges whether it is unnecessary or not, as follows:

If, for any good subset of the cards containing card i, the set that can be obtained by eliminating card i from the subset is also good, card i is unnecessary.

Otherwise, card i is NOT unnecessary.

Find the number of the unnecessary cards. Here, he judges each card independently, and he does not throw away cards that turn out to be unnecessary.

Constraints

All input values are integers.

1≤N≤5000

1≤K≤5000

1≤a_i≤10^9 (1≤i≤N)

Partial Score

300 points will be awarded for passing the test set satisfying N,K≤400.

Input

The input is given from Standard Input in the following format:

N K
a_1 a_2 ... a_N

Output

Print the number of the unnecessary cards.

Sample Input 1

3 6
1 4 3

Sample Output 1

1

There are two good sets: {2,3} and {1,2,3}.

Card 1 is only contained in {1,2,3}, and this set without card 1, {2,3}, is also good. Thus, card 1 is unnecessary.

For card 2, a good set {2,3} without card 2, {3}, is not good. Thus, card 2 is NOT unnecessary.

Neither is card 3 for a similar reason, hence the answer is 1.

Sample Input 2

5 400
3 1 4 1 5

Sample Output 2

5

In this case, there is no good set. Therefore, all the cards are unnecessary.

Sample Input 3

6 20
10 4 3 10 25 2

Sample Output 3

3

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#define _CRT_SECURE_NO_WARNINGS
#pragma comment(linker, "/STACK:256000000")
#define _USE_MATH_DEFINES
#include<iostream>
#include<vector>
#include<string>
#include<stack>
#include<algorithm>
#include<cmath>
#include<set>
#include<queue>
#include<sstream>
#include<utility>
#include<map>
#include<ctime>
#include<cstdio>
#include<cassert>
#include<functional>
#include<unordered_map>
#include<deque>
#include<cmath>





using namespace std;

typedef long long ll;
typedef long double ld;
typedef unsigned int uint;
typedef unsigned long long ull;
typedef pair<ll, ll> pll;
typedef pair<int, int> pii;
typedef pair<char, char> pcc;
typedef pair<double, double> pdd;

#define show(x) cerr << x
#define debug(x) show(#x << ": " << (x) << endl)

const long double PI = 3.14159265358979323846;
const long double eps = 1e-5;
const ll INF = numeric_limits<int>::max();
const ll LINF = numeric_limits<ll>::max();
const ll mod = 1000 * 1000 * 1000 + 7;


void solve() {
    int n, k;
    cin >> n >> k;
    vector<int> d(k, 0);
    d[0] = 1;
    vector<int> a(n);
    for (int i = 0; i < n; ++i) {
        cin >> a[i];
    }
    sort(a.rbegin(), a.rend());
    vector<ll> s(n);
    s[n - 1] = a[n - 1];
    for (int i = n - 2; i >= 0; --i) {
        s[i] = a[i] + s[i + 1];
    }
    int mx = 0;
    for (int i = 0; i < n; ++i) {
        int st = max(0ll, k - s[i]);
        //cerr << st << endl;
        if (mx < st) {
            cout << n - i << endl;
            return;
        }
        for (int j = k - 1; j >= 0; --j) {
            if (d[j] == 0)
                continue;
            int id = j + a[i];
            if (id < k) {
                d[id] = 1;
                mx = max(mx, id);
            }
        }
    }
    cout << 0 << endl;


}


//#define LOCAL

int main() {
    ios_base::sync_with_stdio(0);cin.tie(nullptr);cout.tie(nullptr);
#ifdef LOCAL
    freopen("input.txt", "r", stdin);
    //freopen("output.txt", "w", stdout);
#endif
    solve();



#ifdef LOCAL
    cerr << "Time elapsed: " << 1.0 * clock() / CLOCKS_PER_SEC << " s.\n";
#endif	
    return 0;
}