Problem:
Score : 300 points

Problem Statement

You are given an integer sequence of length n, a_1, ..., a_n.
Let us consider performing the following n operations on an empty sequence b.

The i-th operation is as follows:

Append a_i to the end of b.

Reverse the order of the elements in b.

Find the sequence b obtained after these n operations.

Constraints

1 \leq n \leq 2\times 10^5

0 \leq a_i \leq 10^9

n and a_i are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print n integers in a line with spaces in between.
The i-th integer should be b_i.

Sample Input 1

4
1 2 3 4

Sample Output 1

4 2 1 3

After step 1 of the first operation, b becomes: 1.

After step 2 of the first operation, b becomes: 1.

After step 1 of the second operation, b becomes: 1, 2.

After step 2 of the second operation, b becomes: 2, 1.

After step 1 of the third operation, b becomes: 2, 1, 3.

After step 2 of the third operation, b becomes: 3, 1, 2.

After step 1 of the fourth operation, b becomes: 3, 1, 2, 4.

After step 2 of the fourth operation, b becomes: 4, 2, 1, 3.

Thus, the answer is 4 2 1 3.

Sample Input 2

3
1 2 3

Sample Output 2

3 1 2

As shown above in Sample Output 1, b becomes 3, 1, 2 after step 2 of the third operation. Thus, the answer is 3 1 2.

Sample Input 3

1
1000000000

Sample Output 3

1000000000

Sample Input 4

6
0 6 7 6 7 0

Sample Output 4

0 6 6 0 7 7

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#include<algorithm>
#define int long long
using namespace std;
typedef pair<int,int> P;
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define INF 1000000000000

int MOD=1000000007;
struct edge {
    int to, cost;
};

int modpow(int a,int x){
  if(a<0)a+=MOD;
  int ans=1;
  while(x>0){
    if(x&1) ans=ans*a%MOD;
      a=a*a%MOD;
      x>>=1;
  }
  return ans;
}

int gyaku(int n){
    return modpow(n,MOD-2);
}

auto factor(int n){
  map<int,int>res;
  for(int i=2;i*i<=n;i++){
      for(; n%i==0;n/=i) res[i]++;
  }
  if(n>1)res[n]++;
  return res;
}
////////////////////////////////////////////////////////////
signed main() {
  int n;
  cin>>n;
  vector<int>a(n);
  rep(i,n)cin>>a[i];
  vector<int>mae(0),usiro(0);
  rep(i,n){
    if(i%2!=n%2){
      //mae
      mae.push_back(a[i]);
    }
    else{
      //usiro
      usiro.push_back(a[i]);
    }
  }
  rep(i,mae.size()) cout<<mae[mae.size()-1-i]<<' ';
  rep(i,usiro.size()) cout<<usiro[i]<<' ';
}