Problem:
Score : 200 points

Problem Statement

An integer N is a multiple of 9 if and only if the sum of the digits in the decimal representation of N is a multiple of 9.

Determine whether N is a multiple of 9.

Constraints

0 \leq N < 10^{200000}

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a multiple of 9, print Yes; otherwise, print No.

Sample Input 1

123456789

Sample Output 1

Yes

The sum of these digits is 1+2+3+4+5+6+7+8+9=45, which is a multiple of 9, so 123456789 is a multiple of 9.

Sample Input 2

0

Sample Output 2

Yes

Sample Input 3

31415926535897932384626433832795028841971693993751058209749445923078164062862089986280

Sample Output 3

No

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
int ctoi(char);
#define MAX_N 200001
#define l long
#define ll long long
#define f(a, b) for (ll i = a; i < b; i++)
#define f0(a) for (ll i=0;i<a;i++)
#define input(d) cin >> d;
#define inputs(n,d) for(int i=0;i<n;i++){cin >> d[i];}
#define output(d) cout << d << endl;
#define outputs(n,d) for(int i=0;i<n;i++){cout << d[i] << endl;}

int main(void) {
	//ll n;
	//l n;
	//ll n,x,t;
	char s[MAX_N];
	ll ans=0;
	input(s);
	//vector<int> d();
	//vector<l> d();
	//vector<ll> d();

	f0(MAX_N){
		int temp=ctoi(s[i]);
		if(temp==-1){
			break;
		}
		ans+=(ll)temp;
	}
	if((ans%9)==0){
		output("Yes")
	}else{
		output("No")
	}
	//output(ans);

	return 0;
}

int ctoi(char c){
	switch(c){
		case '0': return 0;
		case '1': return 1;
		case '2': return 2;
		case '3': return 3;
		case '4': return 4;
		case '5': return 5;
		case '6': return 6;
		case '7': return 7;
		case '8': return 8;
		case '9': return 9;
		default : return -1;
	}
}