Problem:
Score : 100 points

Problem Statement

There is a set A = \{ a_1, a_2, \ldots, a_N \} consisting of N positive integers.
Taro and Jiro will play the following game against each other.

Initially, we have a pile consisting of K stones.
The two players perform the following operation alternately, starting from Taro:

Choose an element x in A, and remove exactly x stones from the pile.

A player loses when he becomes unable to play.
Assuming that both players play optimally, determine the winner.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq K \leq 10^5

1 \leq a_1 < a_2 < \cdots < a_N \leq K

Input

Input is given from Standard Input in the following format:

N K
a_1 a_2 \ldots a_N

Output

If Taro will win, print First; if Jiro will win, print Second.

Sample Input 1

2 4
2 3

Sample Output 1

First

If Taro removes three stones, Jiro cannot make a move.
Thus, Taro wins.

Sample Input 2

2 5
2 3

Sample Output 2

Second

Whatever Taro does in his operation, Jiro wins, as follows:

If Taro removes two stones, Jiro can remove three stones to make Taro unable to make a move.

If Taro removes three stones, Jiro can remove two stones to make Taro unable to make a move.

Sample Input 3

2 7
2 3

Sample Output 3

First

Taro should remove two stones. Then, whatever Jiro does in his operation, Taro wins, as follows:

If Jiro removes two stones, Taro can remove three stones to make Jiro unable to make a move.

If Jiro removes three stones, Taro can remove two stones to make Jiro unable to make a move.

Sample Input 4

3 20
1 2 3

Sample Output 4

Second

Sample Input 5

3 21
1 2 3

Sample Output 5

First

Sample Input 6

1 100000
1

Sample Output 6

Second

Solution in C++ (Clang 10.0.0) (judge verdict: Accepted)

#include<iostream>
#include<fstream>
#include<math.h>
#include<vector>
#include<string>
#include<algorithm>
#include<map>
#include <chrono>
#include<math.h>

#define FIO ios_base::sync_with_stdio(0);  cin.tie(0);
#define PI 3.14159265358979323846
#define mod 998244353
#define ll long long
#define vll vector<long long>  
#define all(c) c.begin(), c.end()
// Used to traverse in any STL container with iterators
#define tr(container, it) for(typeof(container.begin()) it = container.begin(); it != container.end(); it++)
// Find whether element is present in given container or not
#define present(container, element) (container.find(element) != container.end())
// Finds whether element in present container is present in vector or not
#define cpresent(container, element) (find(all(container),element) != container.end())

using namespace std;
using namespace std::chrono; 

const ll INF = 1e13;
int n , k;
// void dfs(int v, vector<vector<int> >& adj, vector<bool> visited){
//     visited[v] = true;
//     for(int u: adj[v]){
//         if(!visited[u])
//             dfs(u, adj, visited);
//     }
// }

int solve(int val, vector<int>& dp, vector<int>& arr){
    if(dp[val] != -1)return dp[val];
    int flag = 1;
    for(int i=0;i<n;i++){
        if(arr[i] <= val){
            flag = 0;
            break;
        }
    }
    if(flag)return 0;

    for(int i=0;i<n;i++){
        if(arr[i] <= val){
            if(solve(val-arr[i], dp, arr) == 0){
                dp[val] = 1;
                return dp[val];
            }
        }
    }
    return 0;

}

int main(){
    #ifndef ONLINE_JUDGE
    freopen("input.txt", "r", stdin);
    freopen("output.txt", "w", stdout);
    freopen("error.txt", "w", stderr);
    #endif
    FIO

    cin>>n>>k;
    vector<int> dp(k+1, -1);
    dp[0] = 0;
    vector<int> arr(n);
    for(int i=0;i<n;i++){
        cin>>arr[i];
    }
    if(solve(k, dp, arr))cout<<"First"<<endl;
    else cout<<"Second"<<endl;
    

    return 0;
}