Problem:
Score : 200 points

Problem Statement

Raccoon is fighting with a monster.

The health of the monster is H.

Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i.
There is no other way to decrease the monster's health.

Raccoon wins when the monster's health becomes 0 or below.

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Constraints

1 \leq H \leq 10^9

1 \leq N \leq 10^5

1 \leq A_i \leq 10^4

All values in input are integers.

Input

Input is given from Standard Input in the following format:

H N
A_1 A_2 ... A_N

Output

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Sample Input 1

10 3
4 5 6

Sample Output 1

Yes

The monster's health will become 0 or below after, for example, using the second and third moves.

Sample Input 2

20 3
4 5 6

Sample Output 2

No

Sample Input 3

210 5
31 41 59 26 53

Sample Output 3

Yes

Sample Input 4

211 5
31 41 59 26 53

Sample Output 4

No

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <iostream>
#include <vector>
#include <string>
#include <cstring>
#include <utility>
#include <queue>
#include <algorithm>
#include <map>
#include <set>
#include <cmath>
#include <ctime>
#include <cstdlib>
#include <climits>
using namespace std;

#define MOD1097 1000000007

#define ll long long
#define pint pair<int, int>
#define pll pair<ll, ll>
#define pb push_back
#define mpair make_pair
#define pm(first, second) pb(mpair(first, second))
#define fpf first.first
#define fps first.second
#define spf second.first
#define sps second.second

#define all(X) (X).begin(), (X).end()
#define rall(X) (X).rbegin(), (X).rend()
#define divcel(a, b) (((a) + ((b) - 1)) / (b))

int main(){

	int H, N;
	cin >> H >> N;
	int a;
	for(int i = 0; i < N; i++){
		cin >> a;
		H -= a;
		if(H <= 0){
			cout << "Yes" << endl;
			return 0;
		}
	}
	cout << "No" << endl;

	return 0;
}