Problem:
Score: 200 points

Problem Statement

We have a string S consisting of lowercase English letters.

If the length of S is at most K, print S without change.

If the length of S exceeds K, extract the first K characters in S, append ... to the end of them, and print the result.

Constraints

K is an integer between 1 and 100 (inclusive).

S is a string consisting of lowercase English letters.

The length of S is between 1 and 100 (inclusive).

Input

Input is given from Standard Input in the following format:

K
S

Output

Print a string as stated in Problem Statement.

Sample Input 1

7
nikoandsolstice

Sample Output 1

nikoand...

nikoandsolstice has a length of 15, which exceeds K=7.

We should extract the first 7 characters in this string, append ... to the end of them, and print the result nikoand....

Sample Input 2

40
ferelibenterhominesidquodvoluntcredunt

Sample Output 2

ferelibenterhominesidquodvoluntcredunt

The famous quote from Gaius Julius Caesar.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#define __USE_MINGW_ANSI_STDIO
#define _CRT_SECURE_NO_WARNINGS
#include <bits/stdc++.h>
#include <unordered_set>
#include <unordered_map>

using namespace std;

typedef long long ll;
typedef long long ull;
typedef pair<ll, ll> ii;

#define all(v)		((v).begin()), ((v).end())
#define sz(v)		((int)((v).size()))
#define endl		"\n"
#define fx(n)		fixed<<setprecision(n)
#define mk			make_pair	

void File()
{
#ifndef ONLINE_JUDGE
	freopen("output.txt", "w", stdout);
	freopen("input.txt", "r", stdin);
#endif
#ifdef ONLINE_JUDGE
	/*freopen("output.txt", "w", stdout);
	freopen("commandos.in", "r", stdin);*/
#endif
}
void fast()
{
	ios::sync_with_stdio(NULL);
	cout.tie(NULL);
	cin.tie(NULL);
	//File();
}
const double pi = acos(-1.0);
const ll oo = 0x3f3f3f3f;
const int MOD = 1e9 + 7;
const int nn = 2e5 + 15;
int dx[8] = { 1, 0, -1, 0, 1, -1, 1, -1 };
int dy[8] = { 0, 1, 0, -1, 1, -1, -1, 1 };

int main()
{
	fast();
	int n;
	cin >> n;
	string s;
	cin >> s;
	for (int i = 0; i < min(sz(s), n); i++)
		cout << s[i];
	for (int i = n, k = 0; i < sz(s) && k < 1; i++,k++)
		cout << "...";
	cout << endl;
	return 0;
}