Problem:
Score : 300 points

Problem Statement

There are N integers written on a blackboard. The i-th integer is A_i.

Takahashi will repeatedly perform the following operation on these numbers:

Select a pair of integers, A_i and A_j, that have the same parity (that is, both are even or both are odd) and erase them.

Then, write a new integer on the blackboard that is equal to the sum of those integers, A_i+A_j.

Determine whether it is possible to have only one integer on the blackboard.

Constraints

2 ≦ N ≦ 10^5

1 ≦ A_i ≦ 10^9

A_i is an integer.

Input

The input is given from Standard Input in the following format:

N
A_1 A_2 … A_N

Output

If it is possible to have only one integer on the blackboard, print YES. Otherwise, print NO.

Sample Input 1

3
1 2 3

Sample Output 1

YES

It is possible to have only one integer on the blackboard, as follows:

Erase 1 and 3 from the blackboard, then write 4. Now, there are two integers on the blackboard: 2 and 4.

Erase 2 and 4 from the blackboard, then write 6. Now, there is only one integer on the blackboard: 6.

Sample Input 2

5
1 2 3 4 5

Sample Output 2

NO

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<iostream>
#include<algorithm>
#include<math.h>
#include<cstdio>
#include<ctype.h>
#include<stdio.h>
#include<set>
#include<vector>
#include<map>
#include<functional>
#include<iomanip>
#include<queue>
#include<ciso646>
#include<random>
#include<numeric>
#include<string>
using namespace std;
typedef long long ll;
ll prime(ll x) {
	ll i;
	if (x < 2)return 0;
	else if (x == 2) return 1;
	if (x % 2 == 0) return 0;
	for (i = 3; i*i <= x; i += 2) {
		if (x%i == 0) return 0;
	}
	return 1;
}
ll gcd(ll a, ll b) {
	if (a<b) { return gcd(b, a); }
	else if (a%b) { return gcd(b, a%b); }
	else { return b; }
}

ll MOD = 1000000007;
int main() {
	ll N;
	cin >> N;
	ll A[N + 100];
	ll cnt = 0;
	for (ll i = 0; i < N; i++) {
		cin >> A[i];
		if (A[i] % 2 == 1) {
			cnt++;
		}
	}
	if (cnt % 2 == 0)
		cout << "YES" << endl;
	else
		cout << "NO" << endl;
	}