Problem:
Score : 100 points

Problem Statement

You have three tasks, all of which need to be completed.

First, you can complete any one task at cost 0.

Then, just after completing the i-th task, you can complete the j-th task at cost |A_j - A_i|.

Here, |x| denotes the absolute value of x.

Find the minimum total cost required to complete all the task.

Constraints

All values in input are integers.

1 \leq A_1, A_2, A_3 \leq 100

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

Print the minimum total cost required to complete all the task.

Sample Input 1

1 6 3

Sample Output 1

5

When the tasks are completed in the following order, the total cost will be 5, which is the minimum:

Complete the first task at cost 0.

Complete the third task at cost 2.

Complete the second task at cost 3.

Sample Input 2

11 5 5

Sample Output 2

6

Sample Input 3

100 100 100

Sample Output 3

0

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
using namespace std;

void insertionSort(int A[], int N){
  for ( int i = 1; i < N; i++) {
    int v = A[i];
    int j = i - 1;
    while (j >= 0 && A[j] > v) {
      A[j+1] = A[j];
      j--;
    }
    A[j+1] = v;
  }
}

int main(void){

  int A[3];

  for ( int i = 0; i < 3; i++){
    cin >> A[i];
  }

  insertionSort(A, 3);

  int cost = 0;
  for ( int i = 1; i < 3; i++) {
    cost += abs(A[i-1] - A[i]);
  }

  cout << cost;

  return 0;
}