Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;

using ll = long long;
using ull = unsigned long long;
using st = string;
using ch = char;
using db = double;
using bl = bool;
using vll = vector<long long>;
using vdb = vector<db>;
using vvll = vector<vll>;
using vst = vector<st>;
using vch = vector<char>;
using pll = pair<ll, ll>;
using vpll = vector<pll>;
using vvpll = vector<vpll>;
#define rep(i, m, n) for (ll i = (ll)(m); i < (ll)(n); i++)
#define vrep(i, vec) for(auto& i : vec)
#define vin(vec) for(auto& i : vec) cin >> i
#define all(v) v.begin(), v.end()
template<class T> inline bool chmin(T& a, T b){if(a > b){a = b;return true;} return false;}
template<class T> inline bool chmax(T& a, T b){if(a < b){a = b;return true;} return false;}
const ll mod = 1000000007;
const ll inf = 1LL << 60;
const db pi = acos(-1.0L);

int main(){
  ll n, a, b, c;
  cin >> n >> a >> b >> c;
  vst s(n);
  vin(s);

  vst ans(n);
  bl check = true;
  rep(i, 0, n){
    if(s.at(i) == "AB"){
      if(a == 0 && b == 0){
        check = false;
        break;
      }
      else if(a == 1 && b == 1){
        if(i == n - 1){
          a++;
          b--;
          ans.at(i) = "A";
        }
        else{
          if(s.at(i + 1) == "AC"){
            a++;
            b--;
            ans.at(i) = "A";
          }
          else{
            a--;
            b++;
            ans.at(i) = "B";
          }
        }
      }
      else if(a > b){
        a--;
        b++;
        ans.at(i) = "B";
      }
      else{
        a++;
        b--;
        ans.at(i) = "A";
      }
    }

    if(s.at(i) == "AC"){
      if(a == 0 && c == 0){
        check = false;
        break;
      }
      else if(a == 1 && c == 1){
        if(i == n - 1){
          a++;
          c--;
          ans.at(i) = "A";
        }
        else{
          if(s.at(i + 1) == "AB"){
            a++;
            c--;
            ans.at(i) = "A";
          }
          else{
            a--;
            c++;
            ans.at(i) = "C";
          }
        }
      }
      else if(a > c){
        a--;
        c++;
        ans.at(i) = "C";
      }
      else{
        a++;
        c--;
        ans.at(i) = "A";
      }
    }

    if(s.at(i) == "BC"){
      if(b == 0 && c == 0){
        check = false;
        break;
      }
      else if(b == 1 && c == 1){
        if(i == n - 1){
          b++;
          c--;
          ans.at(i) = "B";
        }
        else{
          if(s.at(i + 1) == "AB"){
            b++;
            c--;
            ans.at(i) = "B";
          }
          else{
            b--;
            c++;
            ans.at(i) = "C";
          }
        }
      }
      else if(b > c){
        b--;
        c++;
        ans.at(i) = "C";
      }
      else{
        b++;
        c--;
        ans.at(i) = "B";
      }
    }
  }
  if(check){
    cout << "Yes" << endl;
    vrep(i, ans) cout << i << endl;
    cout << a << b << c << endl;
  }
  else cout << "No" << endl;
}