Problem:
Score : 200 points

Problem Statement

A shop sells N kinds of fruits, Fruit 1, \ldots, N, at prices of p_1, \ldots, p_N yen per item, respectively. (Yen is the currency of Japan.)

Here, we will choose K kinds of fruits and buy one of each chosen kind. Find the minimum possible total price of those fruits.

Constraints

1 \leq K \leq N \leq 1000

1 \leq p_i \leq 1000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
p_1 p_2 \ldots p_N

Output

Print an integer representing the minimum possible total price of fruits.

Sample Input 1

5 3
50 100 80 120 80

Sample Output 1

210

This shop sells Fruit 1, 2, 3, 4, and 5 for 50 yen, 100 yen, 80 yen, 120 yen, and 80 yen, respectively.

The minimum total price for three kinds of fruits is 50 + 80 + 80 = 210 yen when choosing Fruit 1, 3, and 5.

Sample Input 2

1 1
1000

Sample Output 2

1000

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
typedef long long ll;

#define pll pair<ll,ll>
#define ff first
#define snd second
#define pb push_back
#define vll vector<ll>
#define vpll vector<pll>
#define endl "\n"
#define MOD 1000000007
using namespace std;

ll const N = 1e5+1;


void solve()
{
  ll n,k;
  cin>>n>>k;
  ll a[n];
  for(int i=0;i<n;i++)
  {
        cin>>a[i];  
  }
  
  sort(a,a+n);
  ll sum = 0;
  for(int i=0;i<k;i++)
  {
          sum+=a[i];
  }
  cout<<sum;
}
 
int main() {
            ios_base::sync_with_stdio(false);
            cin.tie(NULL);
	    int t=1;
	    //cin>>t;
	    while(t--)
	    {
	            solve();
	    }
	    return 0;
}