Problem:
Score : 400 points

Problem Statement

On a two-dimensional plane, there are N red points and N blue points.
The coordinates of the i-th red point are (a_i, b_i), and the coordinates of the i-th blue point are (c_i, d_i).

A red point and a blue point can form a friendly pair when, the x-coordinate of the red point is smaller than that of the blue point, and the y-coordinate of the red point is also smaller than that of the blue point.

At most how many friendly pairs can you form? Note that a point cannot belong to multiple pairs.

Constraints

All input values are integers.

1 \leq N \leq 100

0 \leq a_i, b_i, c_i, d_i < 2N

a_1, a_2, ..., a_N, c_1, c_2, ..., c_N are all different.

b_1, b_2, ..., b_N, d_1, d_2, ..., d_N are all different.

Input

Input is given from Standard Input in the following format:

N
a_1 b_1
a_2 b_2
:
a_N b_N
c_1 d_1
c_2 d_2
:
c_N d_N

Output

Print the maximum number of friendly pairs.

Sample Input 1

3
2 0
3 1
1 3
4 2
0 4
5 5

Sample Output 1

2

For example, you can pair (2, 0) and (4, 2), then (3, 1) and (5, 5).

Sample Input 2

3
0 0
1 1
5 2
2 3
3 4
4 5

Sample Output 2

2

For example, you can pair (0, 0) and (2, 3), then (1, 1) and (3, 4).

Sample Input 3

2
2 2
3 3
0 0
1 1

Sample Output 3

0

It is possible that no pair can be formed.

Sample Input 4

5
0 0
7 3
2 2
4 8
1 6
8 5
6 9
5 4
9 1
3 7

Sample Output 4

5

Sample Input 5

5
0 0
1 1
5 5
6 6
7 7
2 2
3 3
4 4
8 8
9 9

Sample Output 5

4

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;
const long long INF = (1LL << 32);
const long long MOD = 1000000007;
const long double PI = 3.1415926;
#define FOR(i, r, n) for (ll i = (ll)(r); i < (ll)(n); i++)
#define RFOR(i, r, n) for (ll i = (ll)(n - 1); i >= r; i--)
#define REP(i, n) FOR(i, 0, n)
#define RREP(i, n) RFOR(i, 0, n)
#define ALL(x) x.begin(), x.end()
#define RALL(x) x.rbegin(), x.rend()
typedef long long int ll;
typedef vector<ll> vi;
typedef vector<pair<ll, ll>> vp;
typedef vector<string> vs;
typedef vector<char> vc;
typedef list<ll> lst;
typedef pair<ll, ll> P;
template <class T>
T &chmin(T &a, const T &b) { return a = min(a, b); }
template <class T>
T &chmax(T &a, const T &b) { return a = max(a, b); }

ll n, m, k, ans = 0, sum = 0, cnt = 0;
string s;
char c;

#define Endl endl

/*--------------------template--------------------*/

int main()
{
    cin >> n;
    vp vx(n), vy(n);
    REP(i, n)
    {
        cin >> vx[i].first >> vx[i].second;
    }
    REP(i, n)
    {
        cin >> vy[i].first >> vy[i].second;
    }
    sort(ALL(vx));
    sort(ALL(vy));
    set<P> st;
    RREP(j, n)
    {
        RREP(i, n)
        {
            if (vx[i].first < vy[j].first && vx[i].second < vy[j].second)
            {
                if (st.count(P(vx[i].first,vx[i].second)) == 0)
                {
                    ans++;
                    st.insert(P(vx[i].first, vx[i].second));
                    break;
                }
            }
        }
    }
    cout << ans << endl;
}