Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
using namespace std;
int main()
{
    int n,a=0;
    cin>> n;
    if(n>=105)a++;
    if(n>=135)a++;
    if(n>=165)a++;
    if(n>=189)a++;
    if(n>=195)a++;
    //for(int i=1;i<=n;i+=2){
    //int d=0;
    //for(int j=1;j<=i;j+=2)
    //if(i%j==0)d++;
    // if(d==8)a++;
    //}
    cout<<a;
    return 0;
}