Problem:
Score : 200 points

Problem Statement

There are N gems. The value of the i-th gem is V_i.

You will choose some of these gems, possibly all or none, and get them.

However, you need to pay a cost of C_i to get the i-th gem.

Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid.

Find the maximum possible value of X-Y.

Constraints

All values in input are integers.

1 \leq N \leq 20

1 \leq C_i, V_i \leq 50

Input

Input is given from Standard Input in the following format:

N
V_1 V_2 ... V_N
C_1 C_2 ... C_N

Output

Print the maximum possible value of X-Y.

Sample Input 1

3
10 2 5
6 3 4

Sample Output 1

5

If we choose the first and third gems, X = 10 + 5 = 15 and Y = 6 + 4 = 10.
We have X-Y = 5 here, which is the maximum possible value.

Sample Input 2

4
13 21 6 19
11 30 6 15

Sample Output 2

6

Sample Input 3

1
1
50

Sample Output 3

0

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

/*
Author: Sagar Gupta
E mail: sagar.june97p@gmail.com
*/

#pragma comment(linker, "/STACK:268435456")
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
using namespace std;
#define endl ("\n")
#define deb(n) cerr << #n << " = " << (n) << '\n'
#define FOR(i, n) for (int(i) = 0; (i) < n; (i)++)
#define PI (3.141592653589)
#define ordered_set tree<int, null_type, std::less<int>, rb_tree_tag, tree_order_statistics_node_update>

#define MOD 1000000007

int main()
{
    ios_base::sync_with_stdio(false);
    cin.tie(nullptr);
    cout << fixed;
    cout.precision(10);
    // Those who cannot acknowledge themselves, will invariably fail

    int n;
    cin >> n;
    vector<pair<int, int>> arr(n);
    for (int i = 0; i < n; i++)
    {
        cin >> arr[i].first;
    }
    for (int i = 0; i < n; i++)
    {
        cin >> arr[i].second;
    }
    int sol = 0;
    for(int i= 0;i<n;i++)
    {
        if(arr[i].first > arr[i].second)
        sol += arr[i].first - arr[i].second;
    }
    cout << sol;
    return 0;
}