Problem:
Score : 400 points

Problem Statement

We have a grid with H rows and W columns of squares.
Snuke is painting these squares in colors 1, 2, ..., N.
Here, the following conditions should be satisfied:

For each i (1 ≤ i ≤ N), there are exactly a_i squares painted in Color i. Here, a_1 + a_2 + ... + a_N = H W.

For each i (1 ≤ i ≤ N), the squares painted in Color i are 4-connected. That is, every square painted in Color i can be reached from every square painted in Color i by repeatedly traveling to a horizontally or vertically adjacent square painted in Color i.

Find a way to paint the squares so that the conditions are satisfied.
It can be shown that a solution always exists.

Constraints

1 ≤ H, W ≤ 100

1 ≤ N ≤ H W

a_i ≥ 1

a_1 + a_2 + ... + a_N = H W

Input

Input is given from Standard Input in the following format:

H W
N
a_1 a_2 ... a_N

Output

Print one way to paint the squares that satisfies the conditions.
Output in the following format:

c_{1 1} ... c_{1 W}
:
c_{H 1} ... c_{H W}

Here, c_{i j} is the color of the square at the i-th row from the top and j-th column from the left.

Sample Input 1

2 2
3
2 1 1

Sample Output 1

1 1
2 3

Below is an example of an invalid solution:

1 2
3 1

This is because the squares painted in Color 1 are not 4-connected.

Sample Input 2

3 5
5
1 2 3 4 5

Sample Output 2

1 4 4 4 3
2 5 4 5 3
2 5 5 5 3

Sample Input 3

1 1
1
1

Sample Output 3

1

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

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// C++ Conpetitive Programming Template 
// Ver 1.1 (codename: Hinata)
// Last Modified : 2019-05-28
// Created       : 2019-05-25
// Auther        : shirataki3
#include <bits/stdc++.h>
using namespace std;
// typename alias
template <class T> using vec = vector<T>;
template <class T, class U> using vep = vec<pair<T,U> >;
template <class T> using PQ = priority_queue<T>;
using ll = long long;
using vll = vec<ll>;
using pll = pair<ll, ll>;
using vpll = vec<pll>;
using str = string;
// あくまのちから
//#define int ll

// const
static const long long INF = 1LL<<59;
static const long long MOD = (ll)1e9+7;
static const double PI = 3.14159265358979323846;

// accelerate stdin, stdout
#define endl "\n"
#define fast_io ios_base::sync_with_stdio(false);cin.tie(NULL)
// repeat macro
#define FOR(i, a, b) for(ll (i)=(a);(i)<=(b);i++)
#define rFOR(i, a, b) for(ll (i)=(b);(i)>=(a);i--)
#define REP(i, n) for(ll i=0;i<n;i++)
// vector macro
#define WHOLE(v) (v).begin(), (v).end()
#define ASC(v) sort(WHOLE(v))
#define DESC(v) sort((v).rbegin(), (v).rend())
#define INV(v) reverse(WHOLE(v))
#define FOLDL(src, dst, lambda) partial_sum(WHOLE(src), (dst).begin(), lambda)
#define FOLDR(src, dst, lambda) INV(src);partial_sum(WHOLE(src), (dst).begin(), lambda);INV(dst)
#define CUMSUML(src, dst) FOLDL(src, dst, [](auto a, auto b) {return a+b;})
#define CUMSUMR(src, dst) FOLDR(src, dst, [](auto a, auto b) {return a+b;})
#define ACCUM(v, d0, lambda) accumulate(WHOLE(v), d0, lambda)
#define SUM(v, d0) ACCUM(v, d0, [](auto a, auto b) {return a+b;})
#define ERASE(v, i) v.erase(v.begin() + i)
#define UNIQ(v) ASC(v);v.erase(unique(v.begin(), v.end()), v.end())

// io helper
template <typename T>void debug(T t) {cerr << t << endl;}
template <typename T, typename ...Args>void debug(T t, Args ...args) {cerr << t << " ";debug(args...);}
template <typename T>void out(T t) {cout << t << endl;}
template <typename T, typename ...Args>void out(T t, Args ...args) {cout << t << " ";out(args...);}
template <typename T>istream& operator>>(istream &is, vec<T> &v) {for(auto &a:v) is >> a; return is;}
template <typename T>ostream& operator<<(ostream &os, vec<T> &v) {os << "[";REP(i, v.size() - 1) os << v[i] <<", "; os << v[v.size()-1]<<"]";return os;}
template <typename T, typename U>ostream& operator<<(ostream &os, pair<T, U> &p) {os << "(" << p.first << ", " << p.second << ")";return os;}
template <typename T, typename U>ostream& operator<<(ostream &os, map<T, U> &mp) {os << "{ ";for(auto &p:mp) os << p.first << ": " << p.second << ", "; os << "}";return os;}

void solve() {
    ll H, W, N;
    cin >> H >> W >> N;
    vll a(N);
    vec<vll> mp;
    mp.assign(H, vec<ll>(W));
    cin >> a;
    ll i = 0, ctr = 0;
    REP(y, H) {
        if(y % 2 == 0) {
            FOR(x, 0, W - 1) {
                ll c = (i + 1);
                mp[y][x] = c;
                ctr++;
                if(ctr == a[i]) {
                    i++;
                    ctr = 0;
                }
            }
        }else {
            rFOR(x, 0, W - 1) {
                ll c = (i + 1);
                mp[y][x] = c;
                ctr++;
                if(ctr == a[i]) {
                    i++;
                    ctr = 0;
                }
            }
        }
    }
    REP(y, H) {
        REP(x, W) {
            cout << mp[y][x];
            if(x != W - 1) cout << " ";
        }
        cout << endl;
    }
}

signed main() {
    fast_io;
    cout << setprecision(20) << fixed;
    solve();
    return 0;
}