Problem:
Score : 100 points

Problem Statement

It is September 9 in Japan now.

You are given a two-digit integer N. Answer the question: Is 9 contained in the decimal notation of N?

Constraints

10≤N≤99

Input

Input is given from Standard Input in the following format:

N

Output

If 9 is contained in the decimal notation of N, print Yes; if not, print No.

Sample Input 1

29

Sample Output 1

Yes

The one's digit of 29 is 9.

Sample Input 2

72

Sample Output 2

No

72 does not contain 9.

Sample Input 3

91

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define all(x) (x).begin(),(x).end()
#define rep(i, n) for(ll i = 0; i < n; i++)
const ll INF = 100100100100;


ll combination(ll n, ll r){
    if(n < r) return 0;
    if(r == 0||r == n) return 1;
    else if(r == 1) return n;
    return (combination(n - 1, r - 1) + combination(n - 1, r));
}

bool checkKaibun(string str){
    string checkStr = str;
    reverse(checkStr.begin(), checkStr.end());
    if(str == checkStr) return true;
    else return false;
}

int keta(ll num){
    int digits = 0;
    while(num > 0){
        num /= 10;
        digits++;
    }
    return digits;
}


int main(){
    int N;
    cin >> N;
    if(N % 10 == 9 || N / 10 == 9) cout<< "Yes" << endl;
    else cout << "No" << endl;
}