Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in C++ (Clang 10.0.0) (judge verdict: Accepted)

#include "vector"
#include "set"
#include "map"
#include "unordered_set"
#include "unordered_map"
#include "string"
#include "iostream"
#include "algorithm"
#include "queue"

using namespace std;

#define ll long long
#define INF 2e9
#define INF2 4611686018427387904
//#define MOD 1000000007
#define MOD 998244353
#define MAX_SIZE 1000000000

typedef vector<int> vi;
typedef vector<ll> vll;
typedef pair<int, int> pii;

template<typename T>
ostream& operator<<(ostream& os, const vector<T>& v) { bool first = true; for (const auto& j: v) { if (!first) { os << " "; } first = false; os <<j; } os << "\n"; return os; }
template<typename T>
istream& operator>>(istream& is, vector<T>& v) { for (auto& elem : v) { is >> elem; } return is; }

vector<ll> f;
void set_f(int n) { f.resize(n+1); f[0] = 1; for (int i=1; i<= n; i++) { f[i] = (f[i-1] * i) % MOD;} }
ll nod(ll a, ll b) { if (b == 0) { return a; } else { return nod(b, a % b); } }
ll pw(ll x, ll n, ll m=MOD) { if (n == 0) { return 1;} if (n%2 == 0) { return pw((x*x) % m, n/2, m); } return (pw(x, n-1, m) * x) % m; }
ll dv(ll a, ll b) { return (a * pw(b, MOD - 2)) % MOD; }
ll c_n_k(int n, int k) { if (k > n) { return 0; } if (k < 0) { return 0; } return dv(dv(f[n], f[k]), f[n-k]); }

void solve() {
    int n, a, b, c;
    cin >> n >> a >> b >> c;

    vector<string> s(n);
    cin >> s;
    vector<char> ans;

    for (int i=0; i<n; i++) {
        if (i == n-1) {
            if (s[i]== "AB") {
                if (a > b) {
                    a--;
                    b++;
                    ans.push_back('B');
                } else {
                    a++;
                    b--;
                    ans.push_back('A');
                }
            }
            if (s[i] == "AC") {
                if (a > c) {
                    a--;
                    c++;
                    ans.push_back('C');
                } else {
                    a++;
                    c--;
                    ans.push_back('A');
                }
            }
            if (s[i] == "BC") {
                if (b > c) {
                    b--;
                    c++;
                    ans.push_back('C');
                } else {
                    b++;
                    c--;
                    ans.push_back('B');
                }
            }
        } else {
            if (s[i]== "AB") {
                if (a > b || (a == b && s[i+1] == "BC")) {
                    a--;
                    b++;
                    ans.push_back('B');
                } else {
                    a++;
                    b--;
                    ans.push_back('A');
                }
            }
            if (s[i] == "AC") {
                if (a > c || (a == c && s[i+1] == "BC")) {
                    a--;
                    c++;
                    ans.push_back('C');
                } else {
                    a++;
                    c--;
                    ans.push_back('A');
                }
            }
            if (s[i] == "BC") {
                if (b > c || (b == c && s[i+1] == "AC")) {
                    b--;
                    c++;
                    ans.push_back('C');
                } else {
                    b++;
                    c--;
                    ans.push_back('B');
                }
            }
        }

        if (a < 0 || b < 0 || c < 0) {
            cout << "No" << endl;
            return;
        }
    }

    cout << "Yes" << endl;
    for (char c : ans) {
        cout << c << "\n";
    }
}

int main() {
    ios::sync_with_stdio(false), cin.tie(nullptr), cout.tie(nullptr);

    if (0) {
        int tests;
        cin >> tests;
        for (int t = 1; t <= tests; t++) {
            //cout << "Case #" << t << ": ";
            solve();
            //cout << "\n";
        }
    } else {
        solve();
        //cout << endl;
    }

    return 0;
}