Problem:
Score : 200 points

Problem Statement

N Snukes called Snuke 1, Snuke 2, ..., Snuke N live in a town.

There are K kinds of snacks sold in this town, called Snack 1, Snack 2, ..., Snack K. The following d_i Snukes have Snack i: Snuke A_{i, 1}, A_{i, 2}, \cdots, A_{i, {d_i}}.

Takahashi will walk around this town and make mischief on the Snukes who have no snacks. How many Snukes will fall victim to Takahashi's mischief?

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq K \leq 100

1 \leq d_i \leq N

1 \leq A_{i, 1} < \cdots < A_{i, d_i} \leq N

Input

Input is given from Standard Input in the following format:

N K
d_1
A_{1, 1} \cdots A_{1, d_1}
\vdots
d_K
A_{K, 1} \cdots A_{K, d_K}

Output

Print the answer.

Sample Input 1

3 2
2
1 3
1
3

Sample Output 1

1

Snuke 1 has Snack 1.

Snuke 2 has no snacks.

Snuke 3 has Snack 1 and 2.

Thus, there will be one victim: Snuke 2.

Sample Input 2

3 3
1
3
1
3
1
3

Sample Output 2

2

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>

using namespace std;
#define sqr(x) ((x)*(x))
#define cube(x) ((x)*(x)*(x))
#define GCD(a, b) __gcd(a, b)
#define LCM(a, b) ((a)*(b)/GCD(a,b))
#define PI (3.141592653589793238462643383279502884197169399375105820974944)
#define MP make_pair
#define n1 first
#define n2 second
#define PII pair<int,int>
#define PLL pair<ll,ll>
#define PDB pair<db,db>
#define SI set<int>
#define SL set<ll>
#define MS multiset
#define MSI multiset<int>
#define MSLL multiset<ll>
#define PB push_back
#define PF push_front
#define VI vector<int>
#define VPI vector<pair<int,int>>
#define VLL vector<ll>
#define VS vector<string>
#define SZ(x) ((int)x.size())

typedef long long ll;

typedef unsigned long long ull;
typedef long double ld;
typedef double db;
const db eps = 0.00000000001;
const int INF = 1000000007;
const ll LINF = 1000000000000000555;
const int N = 550555;
const int L = 21;
const int M = 2155;

bool used[N];
void solve() {
    int n, k;
    cin >> n >> k;

    for (int i = 1; i <= k; i++){
        int d;
        cin >> d;
        while (d--){
            int x;
            cin >> x;
            used[x] = true;
        }
    }

    int cnt = 0;
    for (int i = 1; i <= n; i++){
        if (!used[i]) cnt++;
    }

    cout << cnt;

}

int main() {
    ios_base::sync_with_stdio(false);
#ifdef dxz05
    freopen("input.txt", "r", stdin);
    freopen("output.txt", "w", stdout);
#else

#endif

    int T = 1;
    //cin >> T;

    while (T--) {
        solve();
    }

    return 0;
}