Problem:
Score : 300 points

Problem Statement

A company has N members, who are assigned ID numbers 1, ..., N.

Every member, except the member numbered 1, has exactly one immediate boss with a smaller ID number.

When a person X is the immediate boss of a person Y, the person Y is said to be an immediate subordinate of the person X.

You are given the information that the immediate boss of the member numbered i is the member numbered A_i. For each member, find how many immediate subordinates it has.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq A_i < i

Input

Input is given from Standard Input in the following format:

N
A_2 ... A_N

Output

For each of the members numbered 1, 2, ..., N, print the number of immediate subordinates it has, in its own line.

Sample Input 1

5
1 1 2 2

Sample Output 1

2
2
0
0
0

The member numbered 1 has two immediate subordinates: the members numbered 2 and 3.

The member numbered 2 has two immediate subordinates: the members numbered 4 and 5.

The members numbered 3, 4, and 5 do not have immediate subordinates.

Sample Input 2

10
1 1 1 1 1 1 1 1 1

Sample Output 2

9
0
0
0
0
0
0
0
0
0

Sample Input 3

7
1 2 3 4 5 6

Sample Output 3

1
1
1
1
1
1
0

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <iostream>
#include <algorithm>
#include <string>
#include <vector>
#include <set>
#include <cmath>
#include <queue>
#include <map>
#include <stack>
#include <bitset>
#include <numeric> //lcm
#include <iomanip> //double精度 setprecision

using namespace std;

#define rep(i,n) for(int i = 0; i < (n); ++i)
#define rrep(i,n) for(int i = n-1; i >= 0; --i)
#define rep1(i,n) for(int i = 1; i <= (n); ++i)
#define rrep1(i,n) for(int i = (n); i >= 1; --i)
#define REP(i,n,m) for(int i = (n); i < (m); ++i)
#define all(vec) (vec).begin(),(vec).end()

#define debug(vec) for(auto v : vec) cerr << v << " "; cerr << endl;
#define debug2D(vec2D) for(auto vec : vec2D) { for (auto v : vec) cerr << v << " "; cerr << endl; } 
#define debugP(vec) for(auto v : vec) cerr << "(" << v.first << "," << v.second << ") "; cerr << endl;
#define debug2DP(vec2D) for(auto vec : vec2D) { for (auto v : vec) cerr << "(" << v.first << "," << v.second << ") "; cerr << endl; } 

typedef long long ll;

constexpr ll INF = 1000000000; //10^10
//const ll MOD = 998244353;
constexpr ll MOD = 1000000007;

template<class T> inline bool chmax(T& a, T b) { if (a <= b) { a = b; return true; } else return false; }
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return true; } else return false; }

int main() {
	ios::sync_with_stdio(false); cin.tie(nullptr); cout.tie(nullptr);

	int n; cin >> n;
	vector<int> a(n,0);
	rep(i, n-1) { int b; cin >> b; a[b - 1]++; }
	rep(i, n) cout << a[i] << endl;
}