Problem:
Score : 200 points

Problem Statement

An integer N is a multiple of 9 if and only if the sum of the digits in the decimal representation of N is a multiple of 9.

Determine whether N is a multiple of 9.

Constraints

0 \leq N < 10^{200000}

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a multiple of 9, print Yes; otherwise, print No.

Sample Input 1

123456789

Sample Output 1

Yes

The sum of these digits is 1+2+3+4+5+6+7+8+9=45, which is a multiple of 9, so 123456789 is a multiple of 9.

Sample Input 2

0

Sample Output 2

Yes

Sample Input 3

31415926535897932384626433832795028841971693993751058209749445923078164062862089986280

Sample Output 3

No

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <bits/stdc++.h>
#define ull unsigned long long int
#define scanUll(n) scanf("%llu", &n)
using namespace std;

int main() {
	ull n;
	scanUll(n);
	
	int sumOfDigits = 0;
	
	while(n != 0) {
		ull r = n % 10;
		sumOfDigits += r;
		n = n / 10;
	}
	
	if(sumOfDigits % 9 == 0)
		cout << "Yes" << endl;
	else
		cout << "No" << endl;
	
	return 0;
}