Problem:
Score : 200 points

Problem Statement

There are N cities and M roads.
The i-th road (1≤i≤M) connects two cities a_i and b_i (1≤a_i,b_i≤N) bidirectionally.
There may be more than one road that connects the same pair of two cities.
For each city, how many roads are connected to the city?

Constraints

2≤N,M≤50

1≤a_i,b_i≤N

a_i ≠ b_i

All input values are integers.

Input

Input is given from Standard Input in the following format:

N M
a_1 b_1
:
a_M b_M

Output

Print the answer in N lines.
In the i-th line (1≤i≤N), print the number of roads connected to city i.

Sample Input 1

4 3
1 2
2 3
1 4

Sample Output 1

2
2
1
1

City 1 is connected to the 1-st and 3-rd roads.

City 2 is connected to the 1-st and 2-nd roads.

City 3 is connected to the 2-nd road.

City 4 is connected to the 3-rd road.

Sample Input 2

2 5
1 2
2 1
1 2
2 1
1 2

Sample Output 2

5
5

Sample Input 3

8 8
1 2
3 4
1 5
2 8
3 7
5 2
4 1
6 8

Sample Output 3

3
3
2
2
2
1
1
2

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#define _CRT_SECURE_NO_WARNINGS
#include"bits/stdc++.h"
#ifdef _DEBUG
#define DBG(n) n
#else
#define DBG(n)
#endif
#define INF         1e9
#define INFLL       1e18
#define EPS         1e-9
#define REP(i,n)    for(ll i=0,i##_len=(n);i<i##_len;++i)
#define REP1(i,n)   for(ll i=1,i##_len=(n);i<=i##_len;++i)
#define REPR(i,n)   for(ll i=(n)-1;i>=0;--i)
#define REPR1(i,n)  for(ll i=(n);i>0;--i)
#define REPC(i,obj) for(auto i:obj)
#define ALL(obj)    (obj).begin(),(obj).end()
#define SETP(n)     cout << fixed << setprecision(n)
using namespace std;
using ll = long long;
template<typename T = ll>inline T in() { T ret; cin >> ret; return ret; }

signed main() {
	int n = in(), m = in();
	vector<int>road(n);
	REP(i, m) {
		int a = in() - 1, b = in() - 1;
		++road[a];
		++road[b];
	}
	REPC(i, road) {
		cout << i << endl;
	}
}