Problem:
Score : 300 points

Problem Statement

There is a rectangle in a coordinate plane. The coordinates of the four vertices are (0,0), (W,0), (W,H), and (0,H).
You are given a point (x,y) which is within the rectangle or on its border. We will draw a straight line passing through (x,y) to cut the rectangle into two parts. Find the maximum possible area of the part whose area is not larger than that of the other. Additionally, determine if there are multiple ways to cut the rectangle and achieve that maximum.

Constraints

1 \leq W,H \leq 10^9

0\leq x\leq W

0\leq y\leq H

All values in input are integers.

Input

Input is given from Standard Input in the following format:

W H x y

Output

Print the maximum possible area of the part whose area is not larger than that of the other, followed by 1 if there are multiple ways to cut the rectangle and achieve that maximum, and 0 otherwise.

The area printed will be judged correct when its absolute or relative error is at most 10^{-9}.

Sample Input 1

2 3 1 2

Sample Output 1

3.000000 0

The line x=1 gives the optimal cut, and no other line does.

Sample Input 2

2 2 1 1

Sample Output 2

2.000000 1

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
#include <iomanip>      // std::setprecision
using namespace std;
#define what_is(x) cerr << #x << " is " << x << endl;
#define bit(x,i) (x&(1<<i))  //select the bit of position i of x
#define lowbit(x) ((x)&((x)^((x)-1))) //get the lowest bit of x
#define hBit(msb,n) asm("bsrl %1,%0" : "=r"(msb) : "r"(n)) //get the highest bit of x, maybe the fastest
#define IN(i,l,r) (l<i&&i<r) //the next for are for checking bound
#define LINR(i,l,r) (l<=i&&i<=r)
#define LIN(i,l,r) (l<=i&&i<r)
#define INR(i,l,r) (l<i&&i<=r)
#define F(i,L,R) for (int i = L; i < R; i++) //next four are for "for loops"
#define FE(i,L,R) for (int i = L; i <= R; i++)
#define FF(i,L,R) for (int i = L; i > R; i--)
#define FFE(i,L,R) for (int i = L; i >= R; i--)
#define char2Int(c) (c-'0')
#define lastEle(vec) vec[vec.size()-1] 
#define SZ(x) ((int)((x).size()))
#define REMAX(a,b) (a)=max((a),(b)) // set a to the maximum of a and b
#define REMIN(a,b) (a)=min((a),(b));
#define FENWICK(k) (k&-k)
#define FOREACH(i,t) for (auto i=t.begin(); i!=t.end(); i++) // traverse an STL data structure
#define ALL(c) (c).begin(),(c).end() //handy for function like "sort()"
#define PRESENT(c,x) ((c).find(x) != (c).end()) 
#define CPRESENT(c,x) (find(ALL(c),x) != (c).end()) 
#define LL long long //data types used often, but you don't want to type them time by time
#define ull unsigned long long
#define ui unsigned int
#define us unsigned short
#define IOS ios_base::sync_with_stdio(0); //to synchronize the input of cin and scanf
#define INF 1001001001
#define PI 3.1415926535897932384626
//for map, pair
#define mp make_pair
#define fi first
#define se second
//for vectors
#define pb push_back
typedef int elem_t;
typedef vector<int> vi; 
typedef vector<vi> vvi; 
typedef pair<int,int> ii; 
// directions
const int fx[4][2] = {{0,1}, {0,-1}, {1,0}, {-1,0}};
const int fxx[8][2] = {{0,1}, {0,-1}, {1,0}, {-1,0}, {1,1}, {1,-1}, {-1,1}, {-1,-1}};
const int rogi[4][2] = { {1,1}, {1,-1}, {-1,1}, {-1,-1} };

LL W,H,x,y;

void dane() {
	cin>>W>>H>>x>>y;

	LL a1 = x*H;
	LL a2 = (W-x)*H;
	LL roz1 = abs(a2 - a1);

	LL b1 = y*W;
	LL b2 = (H-y)*W;
	LL roz2 = abs(b2-b1);

	if(roz1 == roz2) {
		cout<<std::fixed<< std::setprecision(10)<<min(a1,a2)<<" 1\n";
	} else if(roz1 < roz2) {
		cout<<std::fixed<< std::setprecision(10)<<min(a1,a2)<<" 0\n";
	} else {
		cout<<std::fixed<< std::setprecision(10)<<min(b1,b2)<<" 0\n";
	}

}   


int main() {
	IOS
	// int t;
	// cin>>t;
	// F(i,0,t)
	    dane();
    return 0;
}