Problem:
Score : 200 points

Problem Statement

Given are strings s and t of length N each, both consisting of lowercase English letters.

Let us form a new string by alternating the characters of S and the characters of T, as follows: the first character of S, the first character of T, the second character of S, the second character of T, ..., the N-th character of S, the N-th character of T. Print this new string.

Constraints

1 \leq N \leq 100

|S| = |T| = N

S and T are strings consisting of lowercase English letters.

Input

Input is given from Standard Input in the following format:

N
S T

Output

Print the string formed.

Sample Input 1

2
ip cc

Sample Output 1

icpc

Sample Input 2

8
hmhmnknk uuuuuuuu

Sample Output 2

humuhumunukunuku

Sample Input 3

5
aaaaa aaaaa

Sample Output 3

aaaaaaaaaa

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
typedef long long int64;
typedef vector<int> vec;
typedef vector<int64> vec64;
#define db(x) cout << "> " << #x << ": " << x << "\n";
#define ss cout << " ";
#define ct(x) cout << x;
#define nn cout << "\n";
#define cts(x) cout << x << " ";
#define ctn(x) cout << x << "\n";
#define qr queries();
void solve();
void YN(bool b){if (b){ctn("YES");}else{ctn ("NO");}};
void yn(bool b){if (b){ctn("Yes");}else{ctn ("No");}};
void queries(){int n;cin >> n;while (n--)solve();}
// // // // // // // // // // // // // // // // // // // // // // 
/*                  TEMPLATE - VANILLA                         */
// // // // // // // // // // // // // // // // // // // // // //
int64 q, n;

void solve(){

    return;
}


int main(){
    ios_base::sync_with_stdio(0);cin.tie(0);
    int n;
    cin >> n;
    string s,t;
    cin >> s >> t;
    string rs = "";
    for (int i = 0; i < n; i++){
        rs += s[i];
        rs+=t[i];
    }
    ctn(rs);
    return 0;
}