Problem:
Score : 200 points

Problem Statement

Given is an integer N. Find the number of digits that N has in base K.

Notes

For information on base-K representation, see Positional notation - Wikipedia.

Constraints

All values in input are integers.

1 \leq N \leq 10^9

2 \leq K \leq 10

Input

Input is given from Standard Input in the following format:

N K

Output

Print the number of digits that N has in base K.

Sample Input 1

11 2

Sample Output 1

4

In binary, 11 is represented as 1011.

Sample Input 2

1010101 10

Sample Output 2

7

Sample Input 3

314159265 3

Sample Output 3

18

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

//RohitKaushal
#include <bits/stdc++.h>
using namespace std;

#define endl "\n"
#define ll long long int
#define vi vector<int>
#define vll vector<ll>
#define vvi vector < vi >
#define pii pair<int,int>
#define pll pair<long long, long long>
#define MOD 1000000007
#define INF 1000000000000000001;
#define all(c) c.begin(),c.end()
#define mp(x,y) make_pair(x,y) 
#define mem(a,val) memset(a,val,sizeof(a))
#define f first
#define s second
 
int main(){
	ios::sync_with_stdio(false);
	cin.tie(NULL);

	ll n,k;
	cin>>n>>k;

	int ct=0;
	while(n){
		ct++;
		n/=k;
	}

	cout<<ct;

	return 0;
}