Problem:
Score : 400 points

Problem Statement

Given is an integer S.
Find a combination of six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfies all of the following conditions:

0 \leq X_1,Y_1,X_2,Y_2,X_3,Y_3 \leq 10^9

The area of the triangle in a two-dimensional plane whose vertices are (X_1,Y_1),(X_2,Y_2), and (X_3,Y_3) is S/2.

We can prove that there always exist six integers that satisfy the conditions under the constraints of this problem.

Constraints

1 \leq S \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

S

Output

Print six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfy the conditions, in this order, with spaces in between.
If multiple solutions exist, any of them will be accepted.

Sample Input 1

3

Sample Output 1

1 0 2 2 0 1

The area of the triangle in a two-dimensional plane whose vertices are (1,0),(2,2), and (0,1) is 3/2.
Printing 3 0 3 1 0 1 or 1 0 0 1 2 2 will also be accepted.

Sample Input 2

100

Sample Output 2

0 0 10 0 0 10

Sample Input 3

311114770564041497

Sample Output 3

314159265 358979323 846264338 327950288 419716939 937510582

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <iomanip>
#include <cmath>
#include <algorithm>
#include <map>
#include <set>
#include <cstring>
#include <queue>
#include <unordered_map>
#include <vector>
#include <bitset>
#include <cstdio>
#include <climits>

#define eps 1e-6

#define MAXN 3010
#define INF 0x3f3f3f3f

#define MOD1 1000000009
#define MOD2 1000000007
#define MOD3 998244353
#define BASE1 304933
#define BASE2 4395853
const double PI = acos(-1);

using namespace std;
typedef long long ll;

ll S;

int main() {
    ios::sync_with_stdio(false);
    cin.tie(0);
    cin >> S;
    for(ll i = sqrt(S); i > 0; --i)
    {
        if(S % i == 0)
        {
            cout << 0 << " " << 0 << " " << 0 << " " << i << " " << S / i << " " << 0 << endl;
            return 0;
        }
    }
    cout << 0 << " " << 0 << " " << 0 << " " << 1 << " " << S << " " << 0 << endl;
    return 0;
}