Problem:
Score : 100 points

Problem Statement

There are a total of A + B cats and dogs.
Among them, A are known to be cats, but the remaining B are not known to be either cats or dogs.

Determine if it is possible that there are exactly X cats among these A + B animals.

Constraints

1 \leq A \leq 100

1 \leq B \leq 100

1 \leq X \leq 200

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B X

Output

If it is possible that there are exactly X cats, print YES; if it is impossible, print NO.

Sample Input 1

3 5 4

Sample Output 1

YES

If there are one cat and four dogs among the B = 5 animals, there are X = 4 cats in total.

Sample Input 2

2 2 6

Sample Output 2

NO

Even if all of the B = 2 animals are cats, there are less than X = 6 cats in total.

Sample Input 3

5 3 2

Sample Output 3

NO

Even if all of the B = 3 animals are dogs, there are more than X = 2 cats in total.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#pragma GCC optimize "-O3"
#pragma GCC target ("avx")
#define _USE_MATH_DEFINES
#include<bits/stdc++.h>
#define int long long
#define rep(i,n) for(int i=0;i<n;++i)
#define vi vector<int>
#define vvi vector<vi>
#define pb push_back
#define pi pair<int,int>
#define vp vector<pair<int,int>>
#define mp make_pair
#define all(v) (v).begin(),(v).end()
#define fi first
#define se second
#define MEMSET(a) memset(a,0,sizeof(a))
#define inf (1ll<<60)
#define SORT(v) sort(all(v))
#define RSORT(v) sort(all(v),greater<int>())
#define SPEED ios::sync_with_stdio(false);cin.tie(0);cout<<fixed<<setprecision(12)
signed gcd(int a, int b){return b?gcd(b,a%b):a;}
signed lcm(int a, int b){return a*b/gcd(a,b);}
//priority_queue<int, vi, greater<int> > que;//昇順

using namespace std;

const int mod=1e9+7;

signed main(){
    SPEED;
    int a, b, x;
    cin >> a >> b >> x;
    if(a<=x&&a+b>=x)
    {
        cout << "YES" << endl;
    }
    else
    {
        cout << "NO" << endl;
    }
}