Problem:
Score : 100 points

Problem Statement

A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.

Given a string S, determine whether it is coffee-like.

Constraints

S is a string of length 6 consisting of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S

Output

If S is coffee-like, print Yes; otherwise, print No.

Sample Input 1

sippuu

Sample Output 1

Yes

In sippuu, the 3-rd and 4-th characters are equal, and the 5-th and 6-th characters are also equal.

Sample Input 2

iphone

Sample Output 2

No

Sample Input 3

coffee

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#include <ext/numeric>

using namespace std;
using namespace __gnu_cxx;

#define all(v)   v.begin(), v.end()
#define endl "\n"
#define pb push_back
#define F first
#define S second
#define THINK_TWICE_CODE_ONCE cin.tie(0); cout.tie(0); ios_base::sync_with_stdio(0);
#define to_str to_string
#define isOdd(n)    (n&1)
#define LLMAX LLONG_MAX
#define LLMIN LLONG_MIN
#define IMN INT_MIN
#define IMX INT_MAX
#define pow(n, m) power((ll)n, (ll)m)
#define numOfDigits(n)  ((n)? (ll)(log10(n)+1) : 1)

typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
typedef double dd;
typedef string str;
typedef vector<int> vecint;
typedef vector<ll> vecll;
typedef pair<int, int> pii;

int main()
{
    THINK_TWICE_CODE_ONCE
    //freopen("test cases\\.txt", "r", stdin) ;
    str s; cin>>s;
    if(s[2]==s[3] && s[4]==s[5])cout<<"Yes";
    else cout<<"No";
    return 0;
}