Problem:
Score : 200 points

Problem Statement

Having learned the multiplication table, Takahashi can multiply two integers between 1 and 9 (inclusive) together.

Given an integer N, determine whether N can be represented as the product of two integers between 1 and 9. If it can, print Yes; if it cannot, print No.

Constraints

1 \leq N \leq 100

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N can be represented as the product of two integers between 1 and 9 (inclusive), print Yes; if it cannot, print No.

Sample Input 1

10

Sample Output 1

Yes

10 can be represented as, for example, 2 \times 5.

Sample Input 2

50

Sample Output 2

No

50 cannot be represented as the product of two integers between 1 and 9.

Sample Input 3

81

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>

using namespace std;
using ll = long long;

#define REP(i,m,n) for(ll (i)=(m),i##_len=(n);(i)<(i##_len);++(i))
#define FORR(i,v) for(auto (i):v)
#define ALL(x) (x).begin(), (x).end()
#define _PR(x) cout << (x) << endl
#define _PS(x) cout << (x) << " "
#define SZ(x) ((int)(x).size())
#define MAX(a,b) (((a)>(b))?(a):(b))
#define MIN(a,b) (((a)<(b))?(a):(b))
#define pb push_back

int main()
{
    ll N;
    cin >> N;

    ll q, r;
    bool f = false;

    REP(i,1,10){
        q = N / i;
        r = N % i;
        if((r == 0) && (q < 10)){
            f = true;
        }
    }

    if(f){_PR("Yes");}
    else{_PR("No");}

    return 0;
}

/*



*/