Problem:
Score : 100 points

Problem Statement

Takahashi is going to set a 3-character password.

How many possible passwords are there if each of its characters must be a digit between 1 and N (inclusive)?

Constraints

1 \leq N \leq 9

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

Print the number of possible passwords.

Sample Input 1

2

Sample Output 1

8

There are eight possible passwords: 111, 112, 121, 122, 211, 212, 221, and 222.

Sample Input 2

1

Sample Output 2

1

There is only one possible password if you can only use one kind of character.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <utility>
#include <algorithm>
#include <vector>
#include <map>
#include <set>
#include <list>
#include <unordered_map>
#include <unordered_set>
#include <iterator>
#include <cmath>
#include <string>

using namespace std;

typedef long long ll;
typedef pair<int,int> pii;
typedef vector<int> vi;
typedef vector<pii> vpii;

#define pb push_back
#define fi first
#define se second
#define mp make_pair
#define ins insert
#define iter ::iterator
#define upb upper_bound
#define lwb lower_bound

#define sz(v) v.size()
#define aloc(i, a, n) i *a = new i[n]

#define for0(i,a) for(ll i = 0; i < a; i++)
#define fori(i,a,b) for(ll i = a; i < b; ++i)
#define rfor0(i,a) for(ll i = a; i >= 0; --i)
#define rfor(i,a,b) for(ll i = a; i >= b; --i)
//##############################################################################

int main(){
	int N;
	cin >> N;
	cout << N * N * N << endl;
  return 0;
}