Problem:
Score : 200 points

Problem Statement

We have a long seat of width X centimeters.
There are many people who wants to sit here. A person sitting on the seat will always occupy an interval of length Y centimeters.

We would like to seat as many people as possible, but they are all very shy, and there must be a gap of length at least Z centimeters between two people, and between the end of the seat and a person.

At most how many people can sit on the seat?

Constraints

All input values are integers.

1 \leq X, Y, Z \leq 10^5

Y+2Z \leq X

Input

Input is given from Standard Input in the following format:

X Y Z

Output

Print the answer.

Sample Input 1

13 3 1

Sample Output 1

3

There is just enough room for three, as shown below:

Figure

Sample Input 2

12 3 1

Sample Output 2

2

Sample Input 3

100000 1 1

Sample Output 3

49999

Sample Input 4

64146 123 456

Sample Output 4

110

Sample Input 5

64145 123 456

Sample Output 5

109

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define rep(i,n) for(int i = 0; i < (n); i++)
using ll = long long;
using P = pair<int,int>;
using PP = pair<int,pair<int,int>>;
using T = tuple<string,int,int>;
const ll INF = 1LL<<60;
const int ny[4] = {-1,1,0,0}, nx[4] = {0,0,-1,1};
int sy,sx,gy,gx;

int main(){
  int x,y,z; cin >> x >> y >> z;
  x -= z;
  int ans = 0;
  while(x >= y+z){
    ans++;
    x -= y+z;
  }
  cout << ans << endl;
  return 0;
}