Problem:
Score : 100 points

Problem Statement

On some day in January 2018, Takaki is writing a document. The document has a column where the current date is written in yyyy/mm/dd format. For example, January 23, 2018 should be written as 2018/01/23.

After finishing the document, she noticed that she had mistakenly wrote 2017 at the beginning of the date column. Write a program that, when the string that Takaki wrote in the date column, S, is given as input, modifies the first four characters in S to 2018 and prints it.

Constraints

S is a string of length 10.

The first eight characters in S are 2017/01/.

The last two characters in S are digits and represent an integer between 1 and 31 (inclusive).

Input

Input is given from Standard Input in the following format:

S

Output

Replace the first four characters in S with 2018 and print it.

Sample Input 1

2017/01/07

Sample Output 1

2018/01/07

Sample Input 2

2017/01/31

Sample Output 2

2018/01/31

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <string>
#include <vector>
#include <algorithm>
#include <numeric>
using namespace std;
#define ll long long
int main() {
    cin.tie(0);
    ios::sync_with_stdio(false);
    ll n,h,a,b,ans=0,cnt=0;
    cin >> n >> h;
    vector<ll> a_1,b_1;
    for(ll i=0;i<n;i++){
        cin >> a >> b;
        a_1.push_back(a);
        b_1.push_back(b);
    }
    sort(b_1.begin(),b_1.end(),greater<ll>());
    ll max = *max_element(a_1.begin(),a_1.end());
    for(ll i=0;i<h;i++){
        if(b_1[i]>=max){
            cnt+=b_1[i];
            ans++;
        }
        if(b_1[i]<max){break;}
        if(cnt>=h){
            cout << ans << endl;
            return 0;
        }
    }
    if((h-cnt)%max!=0){cout << ans+(h-cnt)/max+1 <<endl;}
    else cout << ans+(h-cnt)/max << endl;

    return 0;
}