Problem:
Score : 200 points

Problem Statement

Given are 1-digit positive integers a and b. Consider these two strings: the concatenation of b copies of the digit a, and the concatenation of a copies of the digit b. Which of these is lexicographically smaller?

Constraints

1 \leq a \leq 9

1 \leq b \leq 9

a and b are integers.

Input

Input is given from Standard Input in the following format:

a b

Output

Print the lexicographically smaller of the two strings. (If the two strings are equal, print one of them.)

Sample Input 1

4 3

Sample Output 1

3333

We have two strings 444 and 3333. Between them, 3333 is the lexicographically smaller.

Sample Input 2

7 7

Sample Output 2

7777777

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#define _USE_MATH_DEFINES
#include<iostream>
#include<fstream>
#include<string>
#include<vector>
#include<utility>
#include<algorithm>
#include<climits>
#include<set>
#include<map>
#include<cmath>
#include<iomanip>
#include<iterator>
#include<queue>
#include<stack>
#include<cctype>
#include<deque>
#include<time.h>
#include<bitset>
#include<random>
#include<unordered_set>
#include<unordered_map>
#include<sstream>
#include<random>

//by Skeef79

typedef long long ll;
typedef long double ld;
typedef unsigned long long ull;

#pragma warning(disable : 4996)
#pragma comment(linker, "/STACK:16777216")
#define pb push_back
#define en '\n'
#define for0(i,n) for(int i = 0;i<n;i++)
#define all(x) (x).begin(),(x).end()
#define rall(x) (x).rbegin(),(x).rend()
#define vec vector
#define pii pair<int,int>
#define pll pair<ll,ll>

using namespace std;

const int INF = 2000000000;
const ll LINF = 2000000000000000000;

template<typename T> void print(vector<T>& a)
{
	for (int i = 0; i < a.size(); i++)
		cout << a[i] << ' ';
	cout << en;
}

template<typename T> void print(deque<T>& a)
{
	for (int i = 0; i < a.size(); i++)
		cout << a[i] << ' ';
	cout << en;
}

template<typename T> void print(vector<vector<T>>& a)
{
	for (int i = 0; i < a.size(); i++)
	{
		for (int j = 0; j < a[i].size(); j++)
			cout << a[i][j] << ' ';
		cout << en;
	}
}

template <typename T> void input(vector<T>& a)
{
	for (int i = 0; i < a.size(); i++)
		cin >> a[i];
}

template<typename T> void input(deque<T>& a)
{
	for (int i = 0; i < a.size(); i++)
		cin >> a[i];
}

template<typename T> void input(vector<vector<T>>& a)
{
	for (int i = 0; i < a.size(); i++)
		for (int j = 0; j < a[i].size(); j++)
			cin >> a[i][j];
}

void solve()
{
	int a, b;
	cin >> a >> b;
	string s1, s2;
	for (int i = 0; i < a; i++)
		s1 += char(b + '0');
	for (int i = 0; i < b; i ++)
		s2 += char(a + '0');
	cout << (s1 < s2 ? s1 : s2);

}

int main()
{
	ios::sync_with_stdio(false);
	cin.tie(0);
	cout.tie(0);

#ifdef _DEBUG
	freopen("input.txt", "r", stdin);
#endif

	int tst = 1;
	//cin >> tst;
	while (tst--)
	{
		solve();
	}
}