Problem:
Score : 100 points

Problem Statement

We conducted a survey on newspaper subscriptions.
More specifically, we asked each of the N respondents the following two questions:

Question 1: Are you subscribing to Newspaper X?

Question 2: Are you subscribing to Newspaper Y?

As the result, A respondents answered "yes" to Question 1, and B respondents answered "yes" to Question 2.

What are the maximum possible number and the minimum possible number of respondents subscribing to both newspapers X and Y?

Write a program to answer this question.

Constraints

1 \leq N \leq 100

0 \leq A \leq N

0 \leq B \leq N

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N A B

Output

Print the maximum possible number and the minimum possible number of respondents subscribing to both newspapers, in this order, with a space in between.

Sample Input 1

10 3 5

Sample Output 1

3 0

In this sample, out of the 10 respondents, 3 answered they are subscribing to Newspaper X, and 5 answered they are subscribing to Newspaper Y.

Here, the number of respondents subscribing to both newspapers is at most 3 and at least 0.

Sample Input 2

10 7 5

Sample Output 2

5 2

In this sample, out of the 10 respondents, 7 answered they are subscribing to Newspaper X, and 5 answered they are subscribing to Newspaper Y.

Here, the number of respondents subscribing to both newspapers is at most 5 and at least 2.

Sample Input 3

100 100 100

Sample Output 3

100 100

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>

using namespace std;

int main() {
    int n, a, b;

    cin >> n >> a >> b;

    int min, max;

    if(n > a+b) {
        if(a > b) {
            max = b;
            min = 0;
        }else if(a < b){
            max = a;
            min = 0;
        }else if(a == b){
            max = a;
            min = 0;
        }
    }else if(n < a+b) {
        if(a > b) {
            max = b;
            min = a - b;
        }else if(a < b) {
            max = a;
            min = b - a;
        }else if(a == b) {
            max = a;
            min = a + a - n;
        }
    }else if(n == (a+b)) {
        if(a > b) {
            max = b;
            min = a-b;
        }else if(a < b) {
            max = a;
            min = b-a;
        }else if(a == b) {
            max = a;
            min = b;
        }
    }

    cout << max << " " << min;
}