Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;
int main()
{
	int i=3,s,sum=0,sum1=0;
	cin>>s;
	sum1=s/100;
	sum=s%100;
	if (sum<=12&&sum>0&&sum1<=12&&sum1>0)
	{
		cout<<"AMBIGUOUS";
		return 0;
	}
	if (sum>12||sum<=0||sum1>12||sum1<=0)
	{
		cout<<"NA";
		return 0;
	}
	if (sum<=12&&sum>0)
	{
		cout<<"YYMM";
		return 0;
	}
	if (sum1<=12&&sum1>0)
	{
		cout<<"MMYY";
		return 0;
	}
    return 0;
}