Problem:
Score : 200 points

Problem Statement

You are given strings s and t, consisting of lowercase English letters.
You will create a string s' by freely rearranging the characters in s.
You will also create a string t' by freely rearranging the characters in t.
Determine whether it is possible to satisfy s' < t' for the lexicographic order.

Notes

For a string a = a_1 a_2 ... a_N of length N and a string b = b_1 b_2 ... b_M of length M, we say a < b for the lexicographic order if either one of the following two conditions holds true:

N < M and a_1 = b_1, a_2 = b_2, ..., a_N = b_N.

There exists i (1 \leq i \leq N, M) such that a_1 = b_1, a_2 = b_2, ..., a_{i - 1} = b_{i - 1} and a_i < b_i. Here, letters are compared using alphabetical order.

For example, xy < xya and atcoder < atlas.

Constraints

The lengths of s and t are between 1 and 100 (inclusive).

s and t consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s
t

Output

If it is possible to satisfy s' < t', print Yes; if it is not, print No.

Sample Input 1

yx
axy

Sample Output 1

Yes

We can, for example, rearrange yx into xy and axy into yxa. Then, xy < yxa.

Sample Input 2

ratcode
atlas

Sample Output 2

Yes

We can, for example, rearrange ratcode into acdeort and atlas into tslaa. Then, acdeort < tslaa.

Sample Input 3

cd
abc

Sample Output 3

No

No matter how we rearrange cd and abc, we cannot achieve our objective.

Sample Input 4

w
ww

Sample Output 4

Yes

Sample Input 5

zzz
zzz

Sample Output 5

No

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
#define dhoom ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);  
typedef long long ll;
typedef long double ld;
const ll inf = 1e18;
const int nax = 2e6 + 7;
const ll mod = 1e9 + 7;
//ll tree[4 * nax];
//9uS-22RSwk7gQqh
ll gcd(ll a , ll b){
	if(b == 0) return a;
	return gcd(b , a % b);	
}
ll lcm(ll a , ll b){
	ll g = gcd(a , b);
	ll lc = (a/g) * b;
	return lc;
}
//char a[55][55];
int dx[] = {1,0,-1,0,1,1,-1,-1};
int dy[] = {0,1,0,-1,1,-1,-1,1};
ll a[100];
int main()
{
	dhoom;
	string s , t;
	cin >> s >> t;
	sort(s.begin() , s.end());
	sort(t.rbegin() , t.rend());
	if(s < t)
		cout << "Yes" << endl;
	else 
		cout << "No" << endl;
	return 0;
}