Problem:
Score : 200 points

Problem Statement

A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.

How many times will the ball make a bounce where the coordinate is at most X?

Constraints

1 \leq N \leq 100

1 \leq L_i \leq 100

1 \leq X \leq 10000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N X
L_1 L_2 ... L_{N-1} L_N

Output

Print the number of times the ball will make a bounce where the coordinate is at most X.

Sample Input 1

3 6
3 4 5

Sample Output 1

2

The ball will make a bounce at the coordinates 0, 3, 7 and 12, among which two are less than or equal to 6.

Sample Input 2

4 9
3 3 3 3

Sample Output 2

4

The ball will make a bounce at the coordinates 0, 3, 6, 9 and 12, among which four are less than or equal to 9.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

/*
  Vivek Rathi
  CSE 2nd Year
  MNNIT
*/
#include<bits/stdc++.h>
using namespace std;
#define M 1000000007
#define ll long long int
#define pb push_back
#define pf push_front
#define pob pop_back
#define pof pop_front
#define debug1(x) cout<<#x<<" "<<x<<endl;
#define debug2(x,y) cout<<#x<<" "<<x<<" "<<#y<<" "<<y<<endl;
#define debug3(x,y,z) cout<<#x<<" "<<x<<" "<<#y<<" "<<y<<" "<<#z<<" "<<z<<endl;
#define present(c,x) ((c).find(x) != (c).end())
#define null NULL
#define mp make_pair
#define fi first
#define se second
#define boost ios_base::sync_with_stdio(false);cin.tie(NULL);
#define inf 1e18
#define flush fflush(stdout);
#include <ext/pb_ds/assoc_container.hpp> 
#include <ext/pb_ds/tree_policy.hpp> 
using namespace __gnu_pbds; 
#define ordered_set tree<ll, null_type,less<ll>,rb_tree_tag,tree_order_statistics_node_update>
ll modpower(ll a,ll b,ll c)
{
	ll res=1;
	while(b)
	{
		if(b&1LL)
			res=(res*a)%c;
		a=(a*a)%c;
		b>>=1;
	}
	return res;
}
//-------------------------------Template--Above------------------------------------------------


int main()
{
	boost
	ll n,x;
	cin>>n>>x;
	ll l[n+1];
	for(ll i=1;i<=n;i++)
	{
		cin>>l[i];
	}
	vector<ll> dp;
	dp.pb(0);
	for(ll i=1;i<=n;i++)
	{
		dp.pb(dp[dp.size()-1]+l[i]);
	}
	cout<<upper_bound(dp.begin(),dp.end(),x)-dp.begin()<<endl;
	return 0;
}