Problem:
Score : 200 points

Problem Statement

There are N gems. The value of the i-th gem is V_i.

You will choose some of these gems, possibly all or none, and get them.

However, you need to pay a cost of C_i to get the i-th gem.

Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid.

Find the maximum possible value of X-Y.

Constraints

All values in input are integers.

1 \leq N \leq 20

1 \leq C_i, V_i \leq 50

Input

Input is given from Standard Input in the following format:

N
V_1 V_2 ... V_N
C_1 C_2 ... C_N

Output

Print the maximum possible value of X-Y.

Sample Input 1

3
10 2 5
6 3 4

Sample Output 1

5

If we choose the first and third gems, X = 10 + 5 = 15 and Y = 6 + 4 = 10.
We have X-Y = 5 here, which is the maximum possible value.

Sample Input 2

4
13 21 6 19
11 30 6 15

Sample Output 2

6

Sample Input 3

1
1
50

Sample Output 3

0

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
typedef unsigned long long ull;
typedef long long ll;
typedef int Int;
typedef pair<Int,Int> pii;
typedef pair<Int,double> pid;
typedef pair<double,double> pdd;
typedef pair<Int,pii> pip;
typedef pair<double,Int> pdp;
#define A first
#define B second
#define pb(x) push_back(x)
#define ALL(x) x.begin(),x.end()
#define SZ(x) (x).size()
#define CLR(x) memset(x,0,sizeof x)
#define pdebug() printf("%d\n",__LINE__)
#define Itype(a) typeof(a.begin()) 
#define REP(i,a,b) for(int i = (a);i <= (b);i++)
#define FORO(i,n) REP(i,0,(int)n-1)
#define FORI(i,n) REP(i,1,(int)n)
#define FORIT(i,t) for(Itype(t) i = t.begin();i != t.end();i++)
#define eps 1e-6
#define sqr(x) ((x)*(x))
#define dist(_a,_b) sqrt(sqr(_a.A-_b.A)+sqr(_a.B-_b.B))
#define abs(x) (x < 0 ? -x : x) 
#define norm(_a) sqrt(sqr(_a.A)+sqr(_a.B))
template<typename T>void getMin(T &a,T b) { if(a > b) a = b; }
template<typename T>void getMax(T &a,T b) { if(a < b) a = b; }
const int MOD = 1000000007;


int main() {
    ios::sync_with_stdio(false);
    cin.tie(0);
    
    int N;
    cin >> N;
    vector<int> V(N);
    vector<int> C(N);

    FORO(i, N) {
        cin >> V[i];
    }
    FORO(i, N) {
        cin >> C[i];
    }

    int ans = 0;
    FORO(i, N) {
        if(V[i] - C[i] > 0) ans += V[i] - C[i];
    }

    cout << ans << endl;

    return 0;
}