Problem:
Score : 300 points

Problem Statement

In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0.
You are given a sequence h=\{h_1,h_2,h_3,......\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:

Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.

Find the minimum number of watering operations required to satisfy the condition.

Constraints

1 \leq N \leq 100

0 \leq h_i \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
h_1 h_2 h_3 ...... h_N

Output

Print the minimum number of watering operations required to satisfy the condition.

Sample Input 1

4
1 2 2 1

Sample Output 1

2

The minimum number of watering operations required is 2.
One way to achieve it is:

Perform the operation with (l,r)=(1,3).

Perform the operation with (l,r)=(2,4).

Sample Input 2

5
3 1 2 3 1

Sample Output 2

5

Sample Input 3

8
4 23 75 0 23 96 50 100

Sample Output 3

221

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <algorithm>
#include <numeric>
#include <queue>
#include <vector>
#include <cmath>
#include <cctype>
#include <cstring>
#include <cstdio>

using namespace std;

typedef long long LL;
typedef pair<int, int> PII;

int main(void){
  int n;
  cin >> n;

  int h[n];
  for (int i = 0; i < n; i++) {
    cin >> h[i];
  }

  int cnt = 0;
  int height = 0;

  for (int i = 0; i < n; i++) {
    if (height < h[i]) {
      cnt += h[i] - height;
      height = h[i];
    } else {
      height = h[i];
    }
  }

  cout << cnt << endl;

  return 0;
}