Problem:
Disjoint Set

Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.

same(x, y): determine whether x and y are in the same set.

Input

n q
com1 x1 y1
com2 x2 y2
...
comq xq yq

In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Constraints

1 ≤ n ≤ 10000

1 ≤ q ≤ 100000

x ≠ y

Sample Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0

Sample Output

0
0
1
1
1
0
1
1

Solution in C++14 (judge verdict: Accepted)

#include<bits/stdc++.h>
#define rep(i,n) for(int i=0;i<n;i++)
#define loop(i,x,n) for(int i=x;i<n;i++)
#define pb push_back
//#define int long long
using namespace std;
const int MOD=1000000007;
const int INF=1000000009;
int dx[4]={1,0,-1,0};
int dy[4]={0,1,0,-1};

int par[10004];
int rnk[10004];

void init(int n){
  rep(i,n){
    par[i]=i;
    rnk[i]=0;
  }
}

int find(int x){
  if(par[x]==x)return x;
  else return par[x]=find(par[x]);
}

void unite(int x,int y){
  x=find(x);
  y=find(y);
  if(x==y)return;
  if(rnk[x]<rnk[y])par[x]=y;
  else{
    par[y]=x;
    if(rnk[x]==rnk[y])rnk[x]++;
  }
}

bool same(int x,int y){
  return find(x)==find(y);
}

signed main(){
  int n,q;
  cin>>n>>q;
  init(n);
  rep(i,q){
    int com,x,y;
    cin>>com>>x>>y;
    if(com){
      cout<<same(x,y)<<endl;
    }else{
      unite(x,y);
    }
  }
  return 0;
}