Problem:
Score : 500 points

Problem Statement

Takahashi has decided to work on K days of his choice from the N days starting with tomorrow.

You are given an integer C and a string S. Takahashi will choose his workdays as follows:

After working for a day, he will refrain from working on the subsequent C days.

If the i-th character of S is x, he will not work on Day i, where Day 1 is tomorrow, Day 2 is the day after tomorrow, and so on.

Find all days on which Takahashi is bound to work.

Constraints

1 \leq N \leq 2 \times 10^5

1 \leq K \leq N

0 \leq C \leq N

The length of S is N.

Each character of S is o or x.

Takahashi can choose his workdays so that the conditions in Problem Statement are satisfied.

Input

Input is given from Standard Input in the following format:

N K C
S

Output

Print all days on which Takahashi is bound to work in ascending order, one per line.

Sample Input 1

11 3 2
ooxxxoxxxoo

Sample Output 1

6

Takahashi is going to work on 3 days out of the 11 days. After working for a day, he will refrain from working on the subsequent 2 days.

There are four possible choices for his workdays: Day 1,6,10, Day 1,6,11, Day 2,6,10, and Day 2,6,11.

Thus, he is bound to work on Day 6.

Sample Input 2

5 2 3
ooxoo

Sample Output 2

1
5

There is only one possible choice for his workdays: Day 1,5.

Sample Input 3

5 1 0
ooooo

Sample Output 3

There may be no days on which he is bound to work.

Sample Input 4

16 4 3
ooxxoxoxxxoxoxxo

Sample Output 4

11
16

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<bits/stdc++.h>
using namespace std;
char s[200005];
int l[200005]={0},r[2000005]={0};
int main(void)
{
	int n,k,c;
	scanf("%d%d%d",&n,&k,&c);c++;
	scanf(" %s",s);
	int cnt=1;
	for(int i=0;i<n;)
	{
		while(s[i]=='x'&&i<n) i++;
		if(i==n) break;
		l[i]=cnt++;
		i+=c;
	}
	cnt=1;
	for(int i=n-1;i>=0;)
	{
		while(s[i]=='x'&&i>=0) i--;
		if(i==-1) break;
		r[i]=cnt++;
		i-=c;
	}
	for(int i=0;i<n;i++)
	{
		if(l[i]+r[i]==k+1) printf("%d\n",i+1);
	}
}