Problem:
Score : 200 points

Problem Statement

You are given string S and T consisting of lowercase English letters.

Determine if S equals T after rotation.

That is, determine if S equals T after the following operation is performed some number of times:

Operation: Let S = S_1 S_2 ... S_{|S|}. Change S to S_{|S|} S_1 S_2 ... S_{|S|-1}.

Here, |X| denotes the length of the string X.

Constraints

2 \leq |S| \leq 100

|S| = |T|

S and T consist of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S equals T after rotation, print Yes; if it does not, print No.

Sample Input 1

kyoto
tokyo

Sample Output 1

Yes

In the first operation, kyoto becomes okyot.

In the second operation, okyot becomes tokyo.

Sample Input 2

abc
arc

Sample Output 2

No

abc does not equal arc after any number of operations.

Sample Input 3

aaaaaaaaaaaaaaab
aaaaaaaaaaaaaaab

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <utility>
#include <vector>
#include <iostream>
#include <algorithm>
#include <set>
#define REP(i,n) for(int i=0;i<n;i++)
typedef unsigned long ul;
typedef unsigned long long ull;
typedef long long ll;
using namespace std;
int gcd(int a,int b){return b?gcd(b,a%b):a;}
int dx[4]={1,0,-1,0};
int dy[4]={0,1,0,-1};

int main() {
	cin.tie(0);
   	ios::sync_with_stdio(false);
    string S, T;
    cin >> S >> T;
    bool ans = false;
    for(int i = 0; i < T.length(); i++){
        bool result = true;
        for(int j = 0; j < S.length(); j++){
            if(S.at(j) != T.at((j+i)%T.length())){
                result = false;
                break;
            }
        }
        if(result){
            ans = true;
            break;
        }
    }
    if(ans){
        cout << "Yes" << endl;
    }else{
        cout << "No" << endl;
    }

    return 0;
}