Problem:
Score : 400 points

Problem Statement

Let {\rm comb}(n,r) be the number of ways to choose r objects from among n objects, disregarding order.
From n non-negative integers a_1, a_2, ..., a_n, select two numbers a_i > a_j so that {\rm comb}(a_i,a_j) is maximized.
If there are multiple pairs that maximize the value, any of them is accepted.

Constraints

2 \leq n \leq 10^5

0 \leq a_i \leq 10^9

a_1,a_2,...,a_n are pairwise distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print a_i and a_j that you selected, with a space in between.

Sample Input 1

5
6 9 4 2 11

Sample Output 1

11 6

\rm{comb}(a_i,a_j) for each possible selection is as follows:

\rm{comb}(4,2)=6

\rm{comb}(6,2)=15

\rm{comb}(6,4)=15

\rm{comb}(9,2)=36

\rm{comb}(9,4)=126

\rm{comb}(9,6)=84

\rm{comb}(11,2)=55

\rm{comb}(11,4)=330

\rm{comb}(11,6)=462

\rm{comb}(11,9)=55

Thus, we should print 11 and 6.

Sample Input 2

2
100 0

Sample Output 2

100 0

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<bits/stdc++.h>

#define FOR(i,a,b) for(int i=(a);i<(b);++i)
#define REP(i,n)   FOR(i,0,n)
#define ll long long
#define PINT pair<int,int>
#define f1 first
#define s2 second
const int INF = 1e9 + 7;

using namespace std;

int main(){
    cin.tie(0), ios::sync_with_stdio(false);
    int n;
    cin >> n;
    int a[n];
    REP(i,n) cin >> a[i];

    sort(a,a+n,greater<int>());
    if(n==2){
        cout << a[0] << " " << a[1] << endl;
        return 0;
    }
    int b = a[0], c=a[0];
    REP(i,n){
        if(abs(a[i]-a[0]/2)<b){
            b = abs(a[i]-a[0]/2);
            c = a[i];
        }
    }

    cout << a[0] << " " << c << endl;

    return 0;
}