Problem:
Score : 200 points

Problem Statement

Given are two strings S and T.

Let us change some of the characters in S so that T will be a substring of S.

At least how many characters do we need to change?

Here, a substring is a consecutive subsequence. For example, xxx is a substring of yxxxy, but not a substring of xxyxx.

Constraints

The lengths of S and T are each at least 1 and at most 1000.

The length of T is at most that of S.

S and T consist of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

Print the minimum number of characters in S that need to be changed.

Sample Input 1

cabacc
abc

Sample Output 1

1

For example, changing the fourth character a in S to c will match the second through fourth characters in S to T.

Since S itself does not have T as its substring, this number of changes - one - is the minimum needed.

Sample Input 2

codeforces
atcoder

Sample Output 2

6

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include<bits/stdc++.h>
using namespace std;
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
#define ordered_set tree<int, null_type,less<int>, rb_tree_tag,tree_order_statistics_node_update>
#define ll long long
#define si(n) scanf("%d",&n);
#define PI acos(-1.0)
#define sl(n) scanf("%lld",&n);
#define sf(n) scanf("%lf",&n);
#define ss(n) scanf("%s",n);
#define for0(i,n) for(ll i=0;i<n;i++)
#define for1(i,n) for(ll i=1;i<=n;i++)
#define forc(i,j,n) for(ll i=j;i<n;i++)
#define pb push_back
#define sor(n) sort(n.begin(),n.end())
#define sorcmp(n) sort(n.begin(),n.end(),cmp)
#define rev(n) reverse(n.begin(),n.end())
#define pi(x)  printf("%d",x);
#define pl(x)  printf("%lld",x);
#define pf(x)  printf("%.10lf",x);
#define ps(x)  printf("%s",x);
#define en() printf("\n");
#define random_shuffle(r...)random_shuffle(r,[](int _){return rand()%_;})
#define SQR(a) (a)*(a)
#define sp(x) fixed<<setprecision(x)
#define mod 1000000007
#define endl '\n'
#define pii pair<int,int>
#define pll pair<ll,ll>
#define bug cout<<"Here"<<endl
void fastio(){ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);}
template <typename T> T POW(T B,T P){ if(P==0) return 1; if(P&1) return B*POW(B,P-1);  else return SQR(POW(B,P/2));}
ll powmod(ll a, ll b){ll ans = 1;while(b){if(b&1) ans = ans*a%mod;a = a*a%mod;b >>= 1;}return ans;}


int main()
{
	string str,ptr;
	cin>>str>>ptr;
	int mn=INT_MAX;
	for(int i=0;i<str.size();i++)
    {
        int k=i;
        int cnt=0;
        for(int j=0;j<ptr.size() && k<str.size();j++)
        {
            if(str[k]==ptr[j]) cnt++;
            k++;
        }

        int need=ptr.size()-cnt;
        mn=min(mn,need);

        }

    cout<<mn<<endl;



	return 0;
}