Problem:
Score : 200 points

Problem Statement

Find the number of palindromic numbers among the integers between A and B (inclusive).
Here, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.

Constraints

10000 \leq A \leq B \leq 99999

All input values are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the number of palindromic numbers among the integers between A and B (inclusive).

Sample Input 1

11009 11332

Sample Output 1

4

There are four integers that satisfy the conditions: 11011, 11111, 11211 and 11311.

Sample Input 2

31415 92653

Sample Output 2

612

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;

#define ll long long
#define INF_LL 1LL << 60
#define INF 99999999
#define MOD (ll)1000000007
#define rep(i, n) for(int i = 0; i < (int)(n); i++)
#define REP(i, a, n) for(int i = a; i < (int)(n); i++)
#define all(x) (x).begin(),(x).end()

void put_double(double obj){printf("%.12f\n",obj);};

template < typename T > std::string to_string( const T& n )
{
    std::ostringstream stm ;
    stm << n ;
    return stm.str() ;
}

template<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }
template<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }


int main()
{
    int A,B;
    cin >> A >> B;
    int ans = 0;

    REP(i, A, B+1)
    {
        string tmp = to_string(i);
        string tmp2 = tmp;
        reverse(all(tmp2));
        if( tmp == tmp2 )ans++;
    }
    cout << ans << endl;
}