Problem:
Score : 200 points

Problem Statement

Let us define the FizzBuzz sequence a_1,a_2,... as follows:

If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.

If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.

If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.

If none of the above holds, a_i=i.

Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Constraints

1 \leq N \leq 10^6

Input

Input is given from Standard Input in the following format:

N

Output

Print the sum of all numbers among the first N terms of the FizzBuzz sequence.

Sample Input 1

15

Sample Output 1

60

The first 15 terms of the FizzBuzz sequence are:

1,2,\mbox{Fizz},4,\mbox{Buzz},\mbox{Fizz},7,8,\mbox{Fizz},\mbox{Buzz},11,\mbox{Fizz},13,14,\mbox{FizzBuzz}

Among them, numbers are 1,2,4,7,8,11,13,14, and the sum of them is 60.

Sample Input 2

1000000

Sample Output 2

266666333332

Watch out for overflow.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

//Catchharsh
#include<bits/stdc++.h>
#define ll long long int 
#define ld long double
#define IOS ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL)
#define F first
#define S second
#define sz(x) x.size()
#define all(x) x.begin(),x.end()
#define pb push_back
#define endl '\n'
#define see(x) cout<<#x<<" = "<<x<<endl
const ll MOD = 1e9+7;
const ll INF = 1011111111;
const ll LLINF = 1000111000111000111LL;
const ld EPS = 1e-10;
const ld PI = 3.14159265358979323;
using namespace std;
ll power (ll base,ll exponent)
{
    ll ans=1;
    //base%=MOD;
    //exponent%=(MOD-1);
    while(exponent!=0)
    {
      if(exponent&1) ans=(1LL*ans*base);
      base=(1LL*base*base);
      exponent>>=1;
    }
    return ans;
}

int32_t main()
{   
     IOS;
     
    ll n,m,i,j,k;
    cin>>n;
    // vector<ll> v;
    // ll sz=0;
    ll sum=0;
    for(i=1;i<=n;i++)
    {
      if(i%3!=0&&i%5!=0) sum+=i;
    }
    cout<<sum;
    
     
     cerr <<endl<< "Time elapsed : " << clock() * 1000.0 / CLOCKS_PER_SEC << " ms" << '\n';             
}