Problem:
Score : 200 points

Problem Statement

Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.

The problem has N test cases.

For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is AC, WA, TLE, and RE, respectively.

See the Output section for the output format.

Constraints

1 \leq N \leq 10^5

S_i is AC, WA, TLE, or RE.

Input

Input is given from Standard Input in the following format:

N
S_1
\vdots
S_N

Output

Let C_0, C_1, C_2, and C_3 be the numbers of test cases for which the verdict is AC, WA, TLE, and RE, respectively. Print the following:

AC x C_0
WA x C_1
TLE x C_2
RE x C_3

Sample Input 1

6
AC
TLE
AC
AC
WA
TLE

Sample Output 1

AC x 3
WA x 1
TLE x 2
RE x 0

We have 3, 1, 2, and 0 test case(s) for which the verdict is AC, WA, TLE, and RE, respectively.

Sample Input 2

10
AC
AC
AC
AC
AC
AC
AC
AC
AC
AC

Sample Output 2

AC x 10
WA x 0
TLE x 0
RE x 0

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <queue>
#include <map>
#include <cmath>
#include <algorithm>
#include <queue>
#include <cstdarg>
#include <set>
#include <limits>
#include <iomanip>

using namespace std;
#define INF 2e9 + 9
#define MOD 1000000007
#define ALL(v) v.begin() , v.end()
#define Int int64_t
#define pll pair<Int,Int>
template<class T> using pql = priority_queue<T, vector<T>>;
template<class T> using pq = priority_queue<T, vector<T>, greater<T>>;
#define ll(n) Int n; cin >> n;
#define LL(...) Int __VA_ARGS___; cin >> __VA_ARGS___;
#define OUT(...) cout << __VA_ARGS___;
#define RP(n, i, s) for(Int i = s ;i < n ;i++)
#define REP(n, i) for (Int i = 0; i < n; i++)
#define REPe(n, i) for (Int i = 1; i <= n; i++)
#define RPe(n, i, s) for (Int i = s; i <= n; i++)
#define upd_max(maxer, updater) if (maxer < updater) maxer = updater;
#define upd_min(miner, updater) if (miner > updater) miner = updater;
#ifdef DEBUG

#else

#    pragma GCC optimize("O3,no-stack-protector")
#    pragma GCC optimize("unroll-loops")

#    if __cplusplus < 201703L
#        pragma GCC target("avx")
#    else
#        pragma GCC target("avx2")
#    endif

#endif
// 実数の場合
// #pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")

void ansYes(bool flag){
    if (flag) cout << "Yes" << endl; else  cout << "No" << endl;
}

void ansYES(bool flag){
    if (flag) cout << "YES" << endl; else  cout << "NO" << endl;
}

struct node {
    Int to;
    Int length;
};


vector<Int> divisor(Int n) {
    vector<Int> ret;
    for (Int i = 1; i * i <= n; i++) {
        if (n % i == 0) {
            ret.push_back(i);
            if (i * i != n) ret.push_back(n / i);
        }
    }
    return (ret);
}

int dx8[8] = {0, -1, -1, -1, 0, 1, 1, 1};
int dy8[8] = {-1, -1, 0, 1, 1, 1, 0, -1};

int nanko(string s,Int n,Int i){
    Int length = min(n - i - 1,i);
    Int ans = 0;
    for (int k = i-length;k < i;k++){
        if (s.at(k) == 'R' && s.at(i +  (i - k) == 'B')) ans++;
    }
    return ans;
}

struct datas{
    Int x;

};

//UnionFind群
/*
class UnionFind {
protected:
    vector<int> par;
    vector<int> data;
    int cnt;
public:
    UnionFind() : par(1), data(1), cnt(1) {};
    UnionFind(int N);
    int root(int x);
    int marge(int x, int y);
    bool same(int x, int y);
    int add();
    int add(int x);
    int solve();
    inline int getSize(int x) { return data.at(root(x)); };
};

UnionFind::UnionFind(int N) : par(N), data(N), cnt(N) {
    for (int i = 0; i < N; i++) {
        par.at(i) = -1;
        data.at(i) = 1;
    }
}


int UnionFind::root(int x) {
    if (par.at(x) == -1) return x;
    return par.at(x) = root(par.at(x)); // 経路圧縮
}

int UnionFind::marge(int x, int y) {
    int rx = root(x);
    int ry = root(y);
    if (rx == ry) return rx;
    else { // ノード数の少ない方に接続
        if (data.at(rx) < data.at(ry)) swap(rx, ry);
        par.at(ry) = rx;
        data.at(rx) += data.at(ry);
        return rx;
    }
    return rx;
}

bool UnionFind::same(int x, int y) {
    return root(x) == root(y);
}

int UnionFind::add() {
    par.push_back(cnt);
    cnt++;
    return cnt - 1;
}

int UnionFind::add(int x) {
    par.push_back(cnt);
    cnt++;
    return marge(x, cnt);
}

int UnionFind::solve() {
    for (int i = 0; i < cnt;i++) {
        if (par.at(i) == -1) {

        }
    }
}*/

/*
int dfs(Int par, Int maxs, bool ans) {
    if (mita.at(par) == 1) return 0;
    if (maxs > h.at(par)) {
        maxs = h.at(par);
        ans = true;
    }else if (maxs == h.at(par)){
        ans = false;
    }

    Int maxer = 0;
    for (auto z : to[par]){
        mita.at(par) = 1;
        maxer = dfs(z,maxs,ans);
    }
}*/
int main() {
    Int a;
    cin >> a;
    Int ac = 0 , wa = 0, tle = 0, re = 0;
    REP(a,i){
        string s;
        cin >> s;
        if (s == "AC") ac++;
        if (s == "WA") wa++;
        if (s == "TLE") tle++;
        if (s == "RE") re++;
    }
    cout << "AC × " << ac << endl;
    cout << "WA × " << wa << endl;
    cout << "TLE × " << tle << endl;
    cout << "RE × " << re << endl;
}