Problem:
Score : 200 points

Problem Statement

An integer N is a multiple of 9 if and only if the sum of the digits in the decimal representation of N is a multiple of 9.

Determine whether N is a multiple of 9.

Constraints

0 \leq N < 10^{200000}

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a multiple of 9, print Yes; otherwise, print No.

Sample Input 1

123456789

Sample Output 1

Yes

The sum of these digits is 1+2+3+4+5+6+7+8+9=45, which is a multiple of 9, so 123456789 is a multiple of 9.

Sample Input 2

0

Sample Output 2

Yes

Sample Input 3

31415926535897932384626433832795028841971693993751058209749445923078164062862089986280

Sample Output 3

No

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <iostream>
#include <string.h>
#include <algorithm>
#include <cstring>
#include <math.h>
#define ll long long
ll gcd(ll a,ll b){
    ll s=1,c;
    while(a&&b){
        if((~a&1)&&(~b&1))
            a>>=1,b>>=1,s<<=1;
        else if(~a&1)a>>=1;
        else if(~b&1)b>>=1;
        else if(a>b)a=a-b;
        else c=b-a,b=a,a=c;
    }
    if(!a)return b*s;
    if(!b)return a*s;
}
using namespace std;
int main(){
	char n;ll cnt=0;
	while(cin>>n){
		cnt+=n-'0';
	}
	if(cnt%9==0)
		cout<<"Yes"<<endl;
	else
		cout<<"No"<<endl;
}