Problem:
Score: 100 points

Problem Statement

A triple of numbers is said to be poor when two of those numbers are equal but the other number is different from those two numbers.

You will be given three integers A, B, and C. If this triple is poor, print Yes; otherwise, print No.

Constraints

A, B, and C are all integers between 1 and 9 (inclusive).

Input

Input is given from Standard Input in the following format:

A B C

Output

If the given triple is poor, print Yes; otherwise, print No.

Sample Input 1

5 7 5

Sample Output 1

Yes

A and C are equal, but B is different from those two numbers, so this triple is poor.

Sample Input 2

4 4 4

Sample Output 2

No

A, B, and C are all equal, so this triple is not poor.

Sample Input 3

4 9 6

Sample Output 3

No

Sample Input 4

3 3 4

Sample Output 4

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cmath>
#include <string>
#include <vector>
#include <list>
#include <set>
#include <map>
#include <queue>
#include <stack>
#include <cctype>
#include <climits>
#include <bitset>
#include <utility>
#include <cstring>
#include <numeric>
using namespace std;
typedef long double ld;
typedef long long int ll;
typedef unsigned long long int ull;
typedef vector<int> vi;
typedef vector<char> vc;
typedef vector<string> vs;
typedef vector<pair<int,int>> vpii;
typedef vector<vector<int>> vvi;
typedef vector<vector<char>> vvc;
typedef vector<vector<string>> vvs;
#define rep(i,n) for(int i=0;i<n;i++)
#define repll(i,n) for(long long int i=0;i<n;i++)
#define fin(ans) cout<<(ans)<<endl
#define P 1000000007
#define STI(s) atoi(s.c_str())//string to int
#define mp(p,q) make_pair(p,q)
#define Sort(a) sort(a.begin(),a.end())
template<class T> inline bool chmax(T& a,T b){if(a<b){a=b;return 1;}return 0;}
template<class T> inline bool chmin(T& a,T b){if(a>b){a=b;return 1;}return 0;}
const int INF = INT_MAX;
const long long LLINF = 1LL<<60;
template <typename T_char>
char ToUpper (char cX) { return toupper(cX); }
//g++ -std=c++1z temp.cpp
//./a.exe
ll digit(ll a){
    ll count = 0;
    for (ll i = 0; i < a; i++)
    {   if (a == 0)
        {
            break;
        }else
        {
            a = a/10;
            count++;
        }
    }
    return count;
}
//桁数のカウント
//pow(x,n) == x^n
//sum = accumulate(v.begin(),v.end(),0);
ll gcd(ll a, ll b) { return b ? gcd(b, a%b) : a;}
ll lcm(ll a, ll b) { return a / gcd(a,   b) * b;}



int main(void){ios::sync_with_stdio(false);cin.tie(0);
//////////////////////////////////////////////////////

int a,b,c;
cin >> a >> b >> c;
if((a == b && b != c)||(a == c && b != c)||(c == b && a != c)) cout << "Yes" << endl;
else cout << "No" << endl;





//////////////////////////////////////////////////////
return 0;}