Problem:
Score: 200 points

Problem Statement

A country decides to build a palace.

In this country, the average temperature of a point at an elevation of x meters is T-x \times 0.006 degrees Celsius.

There are N places proposed for the place. The elevation of Place i is H_i meters.

Among them, Princess Joisino orders you to select the place whose average temperature is the closest to A degrees Celsius, and build the palace there.

Print the index of the place where the palace should be built.

It is guaranteed that the solution is unique.

Constraints

1 \leq N \leq 1000

0 \leq T \leq 50

-60 \leq A \leq T

0 \leq H_i \leq 10^5

All values in input are integers.

The solution is unique.

Input

Input is given from Standard Input in the following format:

N
T A
H_1 H_2 ... H_N

Output

Print the index of the place where the palace should be built.

Sample Input 1

2
12 5
1000 2000

Sample Output 1

1

The average temperature of Place 1 is 12-1000 \times 0.006=6 degrees Celsius.

The average temperature of Place 2 is 12-2000 \times 0.006=0 degrees Celsius.

Thus, the palace should be built at Place 1.

Sample Input 2

3
21 -11
81234 94124 52141

Sample Output 2

3

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#define rep(i,N) for (int i = 0; i < (N); ++i)
#define all(v) v.begin(), v.end()
using namespace std;
using ll = long long;
using P = pair<int, int>;
int main(void){
  int N, T, A;
  cin >> N >> T >> A;
  vector <int> H(N);
  rep(i,N) cin >> H[i];

  int ans = 0;
  double tmp = 100000.0;  //温度差の最小値を格納
  rep(i,N){
    double diff = abs(T - H[i] * 0.006 - A);  //A度との差
    if (diff == min(diff, tmp)) ans = i;  //温度差の最小値を更新したときansにiを代入
    tmp = min(diff, tmp);
  }
  cout << ans + 1 << endl;
}