Problem:
Score : 200 points

Problem Statement

We have a long seat of width X centimeters.
There are many people who wants to sit here. A person sitting on the seat will always occupy an interval of length Y centimeters.

We would like to seat as many people as possible, but they are all very shy, and there must be a gap of length at least Z centimeters between two people, and between the end of the seat and a person.

At most how many people can sit on the seat?

Constraints

All input values are integers.

1 \leq X, Y, Z \leq 10^5

Y+2Z \leq X

Input

Input is given from Standard Input in the following format:

X Y Z

Output

Print the answer.

Sample Input 1

13 3 1

Sample Output 1

3

There is just enough room for three, as shown below:

Figure

Sample Input 2

12 3 1

Sample Output 2

2

Sample Input 3

100000 1 1

Sample Output 3

49999

Sample Input 4

64146 123 456

Sample Output 4

110

Sample Input 5

64145 123 456

Sample Output 5

109

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream> // {{{
#include <string>
#include <vector>
#include <stack>
#include <queue>
#include <map>
#include <algorithm>
#include <cstdio> // }}}

#define rep(i,n) for(int i=0; i<n; i++)
#define REP(i,s,n) for(int i=s; i<n; i++)

using namespace std;

int main() {
    int x,y,z;
    cin >> x >> y >> z;
    rep(i,1000000){
        if((i*(y+z)+z) > x) {
            cout << i-1 << endl;
            break;
        }
    }
    return 0;
}