Problem:
Score : 400 points

Problem Statement

We have a grid with H rows and W columns of squares.
Snuke is painting these squares in colors 1, 2, ..., N.
Here, the following conditions should be satisfied:

For each i (1 ≤ i ≤ N), there are exactly a_i squares painted in Color i. Here, a_1 + a_2 + ... + a_N = H W.

For each i (1 ≤ i ≤ N), the squares painted in Color i are 4-connected. That is, every square painted in Color i can be reached from every square painted in Color i by repeatedly traveling to a horizontally or vertically adjacent square painted in Color i.

Find a way to paint the squares so that the conditions are satisfied.
It can be shown that a solution always exists.

Constraints

1 ≤ H, W ≤ 100

1 ≤ N ≤ H W

a_i ≥ 1

a_1 + a_2 + ... + a_N = H W

Input

Input is given from Standard Input in the following format:

H W
N
a_1 a_2 ... a_N

Output

Print one way to paint the squares that satisfies the conditions.
Output in the following format:

c_{1 1} ... c_{1 W}
:
c_{H 1} ... c_{H W}

Here, c_{i j} is the color of the square at the i-th row from the top and j-th column from the left.

Sample Input 1

2 2
3
2 1 1

Sample Output 1

1 1
2 3

Below is an example of an invalid solution:

1 2
3 1

This is because the squares painted in Color 1 are not 4-connected.

Sample Input 2

3 5
5
1 2 3 4 5

Sample Output 2

1 4 4 4 3
2 5 4 5 3
2 5 5 5 3

Sample Input 3

1 1
1
1

Sample Output 3

1

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<bits/stdc++.h>
using namespace std;
inline int rd(){int x;scanf("%d",&x);return x;}
int a[100*100+11];
int b[111][111];
int main(){
	int H=rd(),W=rd();
	int n=rd();
	if(!n){
		for(int i=1;i<=H;i++)
			for(int j=1;j<=W;j++)
				printf("%d%c"," \n"[j==W]);
	}
	for(int i=1;i<=n;i++)a[i]=rd();
	int t=H*W/n,cnt=1,cur=0,tmp=1;
	for(int i=1;i<=H;i++){
		if(cnt&1){
			for(int j=1;j<=W;j++){
				if(cur==t)cur=0,tmp++;
				b[i][j]=a[tmp];
				cur++;
			}
		}else{
			for(int j=W;j>0;j--){
				if(cur>=t)cur=0,tmp++;
				b[i][j]=a[tmp];
				cur++;
			}
		}
		cnt++;
	}
	for(int i=1;i<=H;i++)
		for(int j=1;j<=W;j++)
			if(!b[i][j])printf("%d%c",a[n]," \n"[j==W]);
			else printf("%d%c",b[i][j]," \n"[j==W]);
}