Problem:
Score : 200 points

Problem Statement

Print all the integers that satisfies the following in ascending order:

Among the integers between A and B (inclusive), it is either within the K smallest integers or within the K largest integers.

Constraints

1 \leq A \leq B \leq 10^9

1 \leq K \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B K

Output

Print all the integers that satisfies the condition above in ascending order.

Sample Input 1

3 8 2

Sample Output 1

3
4
7
8

3 is the first smallest integer among the integers between 3 and 8.

4 is the second smallest integer among the integers between 3 and 8.

7 is the second largest integer among the integers between 3 and 8.

8 is the first largest integer among the integers between 3 and 8.

Sample Input 2

4 8 3

Sample Output 2

4
5
6
7
8

Sample Input 3

2 9 100

Sample Output 3

2
3
4
5
6
7
8
9

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;

//container util
//------------------------------------------
#define ALL(a)  (a).begin(),(a).end()
#define RALL(a) (a).rbegin(), (a).rend()
#define PB push_back
#define MP make_pair
#define SZ(a) int((a).size())
#define EACH(i,c) for(typeof((c).begin()) i=(c).begin(); i!=(c).end(); ++i)
#define EXIST(s,e) ((s).find(e)!=(s).end())
#define SORT(c) sort((c).begin(),(c).end())
//repetition
//------------------------------------------
#define FOR(i,a,b) for(int i=(a);i<(b);++i)
#define REP(i,n)  FOR(i,0,n)
//conversion
//------------------------------------------
inline int toInt(string s) {int v; istringstream sin(s);sin>>v;return v;}
template<class T> inline string toString(T x) {ostringstream sout;sout<<x;return sout.str();}

//debug
#define dump(x)  cerr << #x << " = " << (x) << endl;
#define debug(x) cerr << #x << " = " << (x) << " (L" << __LINE__ << ")" << " " << __FILE__ << endl;
//math
//-------------------------------------------
template<class T> inline T sqr(T x) {return x*x;}

typedef long long LL;
const LL mod=1000000007;
#define MAX 10000
#define NIL -1
const double PI  = acos(-1.0);
const int INF = 1e9 + 7;
//-------------------------------------------


int main(){

    cin.tie(0);
    ios::sync_with_stdio(false);

    LL a, b, k;
    cin >> a >> b >> k;

    bool flag = true;

    //even
    if( ( b - a + 1) % 2 == 0){

        if( k > ( b - a + 1) / 2){
            flag = false;
        }
    }
    else{
        if( k >= 1 + ( b - a + 1) / 2 ){
            flag = false;
        }
    }

    if( flag){

        for ( int i = a; i < a + k; i++){
            cout << i << endl;
        }
        for( int i = b - k + 1; i <= b; i++){
            cout  << i << endl;
        }
    }
    else{

        for( int i = a;  i <= b ;i++){
            cout << i << endl;
        }
    }

    return 0;
}