Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

// Shift-JIS（シフトジス）

#include <bits/stdc++.h>
using namespace std;

int main()
{
    string S, str;
    cin >> S;
    int former = stoi(S.substr(0, 2));
    int latter = stoi(S.substr(2, 2));
    bool flag = false;
    if (0 <= former && former <= 99 && 1 <= latter && latter <= 12)
    {
        str = "YYMM";
        flag = true;
    }
    if (1 <= former && former <= 12 && 0 <= latter && latter <= 99)
    {
        str = "MMYY";
        flag = true;
    }
    if (1 <= former && former <= 12 && 1 <= latter && latter <= 12)
    {
        str = "AMBIGUOUS";
        flag = true;
    }
    if (!flag)
    {
        str = "NA";
    }

    cout << str << endl;
}