Problem:
Score : 100 points

Problem Statement

You are given three integers A, B and C.
Determine whether C is not less than A and not greater than B.

Constraints

-100≤A,B,C≤100

A, B and C are all integers.

Input

Input is given from Standard Input in the following format:

A B C

Output

If the condition is satisfied, print Yes; otherwise, print No.

Sample Input 1

1 3 2

Sample Output 1

Yes

C=2 is not less than A=1 and not greater than B=3, and thus the output should be Yes.

Sample Input 2

6 5 4

Sample Output 2

No

C=4 is less than A=6, and thus the output should be No.

Sample Input 3

2 2 2

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <iomanip>
#include <stdio.h>
#include <set>
#include <queue>
#include <vector>
#include <map>
#include <cmath>
#include <algorithm>
#include <memory.h>
#include <string>
#include <sstream>
#include <cstdlib>
#include <ctime>
#include <cassert>

using namespace std;

typedef long long LL;
typedef pair<int,int> PII;

#define MP make_pair
#define PB push_back
#define FF first
#define SS second

#define FORN(i, n) for (int i = 0; i <  (int)(n); i++)
#define FOR1(i, n) for (int i = 1; i <= (int)(n); i++)
#define FORD(i, n) for (int i = (int)(n) - 1; i >= 0; i--)

#define DEBUG(X) { cout << #X << " = " << (X) << endl; }
#define PR0(A,n) { cout << #A << " = "; FORN(_,n) cout << A[_] << ' '; cout << endl; }

// #define FL fflush(stdout)

#define MOD 1000000007
#define INF 2000000000

int GLL(LL& x) {
  return scanf("%lld", &x);
}

int GI(int& x) {
  return scanf("%d", &x);
}

int a, b, c;
int main() {
  cin >> a >> b >> c;
  if (c >= a && c <= b) printf("Yes\n");
  else printf("No\n");
    
  return 0;
}