Problem:
Score : 300 points

Problem Statement

There are N people living on a number line.

The i-th person lives at coordinate X_i.

You are going to hold a meeting that all N people have to attend.

The meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.

Find the minimum total points of stamina the N people have to spend.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq X_i \leq 100

Input

Input is given from Standard Input in the following format:

N
X_1 X_2 ... X_N

Output

Print the minimum total stamina the N people have to spend.

Sample Input 1

2
1 4

Sample Output 1

5

Assume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.

Note that you can hold the meeting only at an integer coordinate.

Sample Input 2

7
14 14 2 13 56 2 37

Sample Output 2

2354

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <string>
#include <map>
#include <queue>
#include <math.h>
#include <bitset>
#include <cmath>
#include <set>
#include <queue>
#include <stack>
#include <algorithm>
#include <vector>
using namespace std;
typedef long long ll;
#define rep(i,s,n)for(ll i = s;i<n;i++)
#define repe(i,s,n)for(ll i = s;i<=n;i++)
#define rep_r(i,s,n)for(ll i = n-1;i>s;i--)
#define rep_re(i,s,n)for(ll i = n-1;i>=s;i--)
ll MOD = 1e9+7;

int main() {
	ll n; cin >> n;
	ll x[100] = {};
	rep(i, 0, n) cin >> x[i];

	ll ans = MOD;
	rep(i, 0, n) {
		ll dis = 0;
		rep(j, 0, n) {
			dis += (x[i] - x[j]) * (x[i] - x[j]);
		}

		ans = min(ans, dis);
	}
	cout << ans << endl;

	return 0;
}