Problem:
Score : 200 points

Problem Statement

A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.

How many times will the ball make a bounce where the coordinate is at most X?

Constraints

1 \leq N \leq 100

1 \leq L_i \leq 100

1 \leq X \leq 10000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N X
L_1 L_2 ... L_{N-1} L_N

Output

Print the number of times the ball will make a bounce where the coordinate is at most X.

Sample Input 1

3 6
3 4 5

Sample Output 1

2

The ball will make a bounce at the coordinates 0, 3, 7 and 12, among which two are less than or equal to 6.

Sample Input 2

4 9
3 3 3 3

Sample Output 2

4

The ball will make a bounce at the coordinates 0, 3, 6, 9 and 12, among which four are less than or equal to 9.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
struct ios_accelerate { ios_accelerate() { ios::sync_with_stdio(false); cin.tie(nullptr); } } CALL;

#define REP(i, n) for(auto (i) = (n)*0; (i) < (n); (i)++)
#define RNG(i, a, b) for(auto (i) = (a); (i) < (b); (i)++)
#define RBF(i, v) for(auto& (i) : (v))
#define ALL(x) (x).begin(), (x).end()

using LL = long long;
using UL = unsigned;
using ULL = unsigned long long;
template<typename T> using V = vector<T>;
template<typename T> using VV = vector<vector<T>>;
template<typename T> using P = pair<T, T>;

const double PI = 3.141592653589793;
const int MOD = 1000000007;
const LL INF64 = static_cast<LL>(1e18) + 2;
const int INF = static_cast<int>(1e9) + 2;

template<typename T> inline void upsort(vector<T>& x) { sort(x.begin(), x.end()); }
template<typename T> inline void downsort(vector<T>& x) { sort(x.begin(), x.end(), greater<T>()); }
template<typename T> inline void col(T x) { cout << x << '\n'; }
template<> inline void col(double x) { cout << fixed << setprecision(12) << x << '\n'; }


signed main() {
	int n, x;
	cin >> n >> x;
	V<int> L(n);
	RBF(l, L) {
		cin >> l;
	}

	int cnt = 1, p = 0;
	RBF(l, L) {
		p += l;
		if (p <= x) {
			cnt++;
		}
	}

	col(cnt);
	return 0;
}