Problem:
Score : 200 points

Problem Statement

There are some animals in a garden. Each of them is a crane with two legs or a turtle with four legs.

Takahashi says: "there are X animals in total in the garden, and they have Y legs in total." Determine whether there is a combination of numbers of cranes and turtles in which this statement is correct.

Constraints

1 \leq X \leq 100

1 \leq Y \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

If there is a combination of numbers of cranes and turtles in which the statement is correct, print Yes; otherwise, print No.

Sample Input 1

3 8

Sample Output 1

Yes

The statement "there are 3 animals in total in the garden, and they have 8 legs in total" is correct if there are two cranes and one turtle. Thus, there is a combination of numbers of cranes and turtles in which the statement is correct.

Sample Input 2

2 100

Sample Output 2

No

There is no combination of numbers of cranes and turtles in which this statement is correct.

Sample Input 3

1 2

Sample Output 3

Yes

We also consider the case in which there are only cranes or only turtles.

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include<bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp> 
#include <ext/pb_ds/tree_policy.hpp> 
#define FIO ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);
#define PI 3.141592653589793238462643383279502884L
#define make_unique(vec) vec.resize(distance(vec.begin(),unique(vec.begin(),vec.end())))
#define Sort(vec) sort(vec.begin(),vec.end())
#define RSort(vec) sort(vec.rbegin(),vec.rend())
#define endl "\n"
#define tr1(i) cout<<i<<endl;
#define tr2(i,j) cout<<i<<" "<<j<<endl;
#define tr3(i,j,k) cout<<i<<" "<<j<<" "<<k<<endl;
#define vvi vector<vector<int> > 
#define vvl vector<vector<ll> >
#define all(st) st.begin(),st.end()
#define vpl vector<pair<ll,ll> >
#define vpi vector<pair<int,int> >
#define pi pair<int,int>
#define pl pair<ll,ll>
#define al vector<list<int> >
#define vs vector<string>
#define vb vector<bool>
#define vi vector<int>
#define vl vector<ll>
#define vc vector<char>
#define rep(i,l,r) for(int i=l;i<r;i++)
#define repit(st) for(auto it=st.begin();it!=st.end();it++)
#define cs(ans); cout<<setprecision(20)<<fixed<<ans<<endl;
#define ull unsigned long long int
#define eb emplace_back
#define pb push_back
#define ll long long int
#define minf -(1e18)
#define inf 1e18
#define f first
#define se second
#define mod 1000000007
using namespace std;
using namespace __gnu_pbds; 
ll mi(ll n,ll m){ll pw=n%m;ll ex=m-2;ll ans=1;while(ex){if(ex&1) ans = ans*pw%m;pw = pw*pw%m;ex>>=1;}return ans%mod;}
ll pw(ll a,ll n){ll pw=a;ll ex=n;ll ans=1;while(ex){if(ex&1) ans = ans*pw;pw = pw*pw;ex>>=1;}return ans;}
ll pwm(ll a,ll n){ll pw=a%mod;ll ex=n;ll ans=1;while(ex){if(ex&1) ans = ans*pw%mod;pw = pw*pw%mod;ex>>=1;}return ans%mod;}
template<typename T>istream &operator>>(istream &is, vector<T> &v) { for (T &t : v) is >> t; return is; }
template<typename T>ostream &operator<<(ostream &os, const vector<T> &v) { for (const T &t : v) {os << t <<" ";} os << '\n'; return os; }
template<typename T> using ordered_set=tree<T,null_type,less<T>,rb_tree_tag,tree_order_statistics_node_update>;
//st.order_of_key(num)->number of elements < num
//st.find_by_order(i)->iterator of ith element in sorted order starting from zero
ll gcd(ll a,ll b){return b==0?a:gcd(b,a%b);}
ll lcm(ll a,ll b){return a/gcd(a,b)*b;}
ll max(ll a,ll b){return a>b?a:b;}
ll min(ll a,ll b){return a<b?a:b;}
ll Abs(ll x){return x>0?x:(-x);}
ll Ceil(ll a,ll b){return a/b+(a%b!=0);}
#define bs binary_search
#define lb lower_bound
#define ub upper_bound
#define mkp make_pair
//#define int long long int
//Binary_Search->dp->greedy
//auto check = [&](ll x){};
int dx[]={1,0,-1,0};
int dy[]={0,1,0,-1};
int X[]={2,1,-1,-2,-2,-1,1,2}; 
int Y[]={1,2,2,1,-1,-2,-2,-1}; 
struct comp{
	bool operator()(const pair<int,int>&a,const pair<int,int>&b) const {
		if(a.first>b.first) return true;
		if(a.first<b.first) return false; 
		if(a.second<b.second) return true;
		return false;
	}
};
void solve(){
	int x,y;
	cin>>x>>y;
	int fir=y-2*x;
	if(fir%2) cout<<"No"<<endl;
	else{
		int Y=fir/2;
		int sec=2*x-Y;
		if(sec>0) cout<<"Yes"<<endl;
		else cout<<"No"<<endl;
	}
		
	
	
	
	
	
	
	
}
int32_t main(){
int t=1;
//scanf("%d",&t);
while(t--){
	solve();
}
return 0;
}