Problem:
Score: 300 points

Problem Statement

M-kun is a student in Aoki High School, where a year is divided into N terms.

There is an exam at the end of each term. According to the scores in those exams, a student is given a grade for each term, as follows:

For the first through (K-1)-th terms: not given.

For each of the K-th through N-th terms: the multiplication of the scores in the last K exams, including the exam in the graded term.

M-kun scored A_i in the exam at the end of the i-th term.

For each i such that K+1 \leq i \leq N, determine whether his grade for the i-th term is strictly greater than the grade for the (i-1)-th term.

Constraints

2 \leq N \leq 200000

1 \leq K \leq N-1

1 \leq A_i \leq 10^{9}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
A_1 A_2 A_3 \ldots A_N

Output

Print the answer in N-K lines.

The i-th line should contain Yes if the grade for the (K+i)-th term is greater than the grade for the (K+i-1)-th term, and No otherwise.

Sample Input 1

5 3
96 98 95 100 20

Sample Output 1

Yes
No

His grade for each term is computed as follows:

3-rd term: (96 \times 98 \times 95) = 893760

4-th term: (98 \times 95 \times 100) = 931000

5-th term: (95 \times 100 \times 20) = 190000

Sample Input 2

3 2
1001 869120 1001

Sample Output 2

No

Note that the output should be No if the grade for the 3-rd term is equal to the grade for the 2-nd term.

Sample Input 3

15 7
3 1 4 1 5 9 2 6 5 3 5 8 9 7 9

Sample Output 3

Yes
Yes
No
Yes
Yes
No
Yes
Yes

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <string>
using namespace std;

int main(){
	int n,kk;
	cin  >> n >> kk ;
	
	int k = n - kk+1;

	int a[n];	
	for (int i = 0; i < n; i++){
		cin >> a[i];
	}
	long b[k];
	
	for (int i = 0; i < k; i++){
		b[i] = 1;
		for (int j = 0; j < kk; j++){
			b[i] = b[i] * a[n-j-i-1];
		}
	}
	string ans[k];
	for (int i = 0; i<k-1; i++) {
		if ( b[i] - b[i+1] >= 0 ) {ans[i] = "Yes";} 
		else {ans[i]="No";}
	}
	
	for (int i = 0; i<k;i++){
		cout << ans[k-i-1] <<endl;
	}	
	
//	if (count <= k) {cout << "Yes" << endl;} 
//	else  {cout << "No" << endl;}
//	cout << y << endl;
return 0;
}