Problem:
Score : 200 points

Problem Statement

There are some animals in a garden. Each of them is a crane with two legs or a turtle with four legs.

Takahashi says: "there are X animals in total in the garden, and they have Y legs in total." Determine whether there is a combination of numbers of cranes and turtles in which this statement is correct.

Constraints

1 \leq X \leq 100

1 \leq Y \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

If there is a combination of numbers of cranes and turtles in which the statement is correct, print Yes; otherwise, print No.

Sample Input 1

3 8

Sample Output 1

Yes

The statement "there are 3 animals in total in the garden, and they have 8 legs in total" is correct if there are two cranes and one turtle. Thus, there is a combination of numbers of cranes and turtles in which the statement is correct.

Sample Input 2

2 100

Sample Output 2

No

There is no combination of numbers of cranes and turtles in which this statement is correct.

Sample Input 3

1 2

Sample Output 3

Yes

We also consider the case in which there are only cranes or only turtles.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair<ll, ll> pll;

#define INX(x) (cin >> x)
#define INXV(vec, cnt) for(ll i; i < cnt; i++) INX(vec[i])
#define OUTX(x) (cout << x << endl)
#define OUTXV(vec) for(ll i; i < (ll)vec.size(); i++) OUTX(vec[i])

#define ADD emplace_back
#define MP make_pair
#define VVEC(type) vector<vector<type>>


int main()
{
    ll X, Y;
    cin >> X >> Y;

    if((Y - 2 * X >= 0)
    && ((Y - 2 * X) % 2 == 0)
    && (4 * X - Y >= 0)
    && ((4 * X - Y) % 2 == 0))
    {
        OUTX("Yes");
    }
    else
    {
        OUTX("No");
    }
    

    return 0;
}