Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#pragma region Macros
#include <bits/stdc++.h>
using namespace std;
#define REP(i, n) for(int i=0, i##_len=(n); i<i##_len; ++i)
#define REPR(i, n) for(int i=(n); i>=0; --i)
#define FOR(i, n, m) for(int i=(m), i##_len=(n); i<i##_len; ++i)
#define EACH(i, v) for(const auto& i : v)
#define ALL(x) (x).begin(),(x).end()
#define ALLR(x) (x).rbegin(),(x).rend()
template<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }
template<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }
template<class Value>using vec = vector< Value >;
using ll = long long;
using P = pair< long long, long long >;
#define fi first
#define se second
#define el endl
#pragma endregion


void Main();

int main(){
    std::cin.tie(nullptr);
    std::cout << std::fixed << std::setprecision(15);
    Main();
    return 0;
}

void Main(){
    vec<vec<int> > bng(3, vec<int>(3));
    vec<int> mp(101, -1);
    REP(i, 3){
        REP(j, 3){
            cin >> bng[i][j];
            mp[bng[i][j]] = i*3+j;
        }
    }
    ll N;
    cin >> N;
    
    int bits = 0;
    REP(i, N){
        int b;
        cin >> b;
        if(mp[b] != -1){
            bits |= 1<<mp[b];
        }
    }
    vec<int> tmp{
        0b000000111,
        0b000111000,
        0b111000000,
        0b100100100,
        0b010010010,
        0b001001001,
        0b100010001,
        0b001010100
    };
    //cout << std::bitset<9>(bits) << el;
    REP(i, tmp.size()){
        if(__builtin_popcount(bits&tmp[i]) == 3){
            cout << "Yes\n";
            return;
        }
    }
    cout << "No\n";
}