Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

/**
 *  “Experience is the name everyone gives to their mistakes.” – Oscar Wilde
 *
 *  author  :   prodipdatta7
 *  created :   Sunday 03-May, 2020  07:01:23 PM
**/

//#include <bits/stdc++.h>
#include <iostream>
#include <algorithm>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <string>
#include <cmath>
#include <vector>
#include <set>
#include <map>
#include <unordered_set>
#include <unordered_map>
#include <stack>
#include <queue>
#include <deque>
#include <iterator>
#include <bitset>
#include <assert.h>
#include <new>
#include <sstream>
#include <time.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

// #pragma GCC optimize("Ofast")
// #pragma GCC target("avx,avx2,fma")
// #pragma GCC optimize("unroll-loops")

using namespace std ;
using namespace __gnu_pbds ;

#define     ll          long long
#define     ld          long double
#define     ull         unsigned long long
#define     pii         pair<int,int>
#define     pll         pair<ll,ll>
#define     vi          vector<int>
#define     vll         vector<ll>
#define     vvi         vector<vector<int>>
#define     debug(x)    cerr << #x << " = " << x << '\n' ;
#define     rep(i,b,e)  for(__typeof(e) i = (b) ; i != (e + 1) - 2 * ((b) > (e))  ; i += 1 - 2 * ((b) > (e)))
#define     all(x)      x.begin() , x.end()
#define     rall(x)     x.rbegin() , x.rend()
#define     sz(x)       (int)x.size()
#define     ff          first
#define     ss          second
#define     pb          push_back
#define     eb          emplace_back
#define     mem(a)      memset(a , 0 ,sizeof a)
#define     memn(a)     memset(a , -1 ,sizeof a)
#define     fread       freopen("input.txt","r",stdin)
#define     fwrite      freopen("output.txt","w",stdout)
#define     TN          typename
#define     FastIO      ios_base::sync_with_stdio(false) ; cin.tie(NULL) ; cout.tie(NULL) ;

typedef tree <int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update > ordered_set;
typedef tree <int, null_type, less_equal<int>, rb_tree_tag, tree_order_statistics_node_update > ordered_multiset;

/*
Note :  There is a problem with erase() function in ordered_multiset (for less_equal<int> tag).
        lower_bound() works as upper_bound() and vice-versa.
        Be careful to use.
        i) find_by_order(k) : kth smallest element counting from 0 .
        ii) order_of_key(k) : number of elements strictly smaller than k.
*/

/*###############-> Input Section <-###############*/

template <TN T> inline void Int(T &a) {
    bool minus = false; a = 0; char ch = getchar();
    while (true) { if (ch == '-' or (ch >= '0' && ch <= '9')) break; ch = getchar(); }
    if (ch == '-') minus = true; else a = ch - '0';
    while (true) { ch = getchar(); if (ch < '0' || ch > '9') break; a = a * 10 + (ch - '0'); }
    if (minus)a *= -1 ;
}
template < TN T, TN T1 > inline void Int(T &a, T1 &b) {Int(a), Int(b) ;}
template < TN T, TN T1, TN T2 > inline void Int(T &a, T1 &b, T2 &c) {Int(a, b), Int(c) ;}
template < TN T, TN T1, TN T2, TN T3 > inline void Int(T &a, T1 &b, T2 &c, T3 &d) {Int(a, b), Int(c, d) ;}
template < TN T, TN T1, TN T2, TN T3, TN T4> inline void Int(T &a, T1 &b, T2 &c, T3 &d, T4 &e) {Int(a, b), Int(c, d, e) ;}

/*###############-> Debugger <-###############*/

#ifndef ONLINE_JUDGE
#define error(args...) { string _s = #args; replace(_s.begin(), _s.end(), ',', ' '); stringstream _ss(_s); istream_iterator<string> _it(_ss); err(_it, args); }
void err(istream_iterator<string> it) {cout << endl ;}
template<TN T, TN... Args>
void err(istream_iterator<string> it, T a, Args... args) {
    cerr << *it << " = " << a << ' ' ;
    err(++it, args...);
}
#else
#define error(args...)
#endif

template<class ValueType>
bool unstable_remove(
    typename std::vector<ValueType>& container,
    typename std::vector<ValueType>::iterator it
) {
    auto lastEl = container.end() - 1;
    if (it != lastEl) {
        *it = std::move(*lastEl);
    }
    container.pop_back();
}

/******************************************
#Rows are numbered from top to bottom.
#Columns are numbered from left to right.
Moves : L, U, R, D, LU, RU, RD, LD.
******************************************/
int dx[8] = {0, -1, 0, 1, -1, -1, 1, 1} ;
int dy[8] = { -1, 0, 1, 0, -1, 1, 1, -1} ;

/*###############-> Constraints <-###############*/

const int N          = (int)2e5 + 5 ;
const int maxN       = (int)1e6 + 6 ;
const ll  Mod        = (ll)1e9 + 7 ;
const int inf        = (int)2e9 ;
const ll  Inf        = (ll)1e18 ;
const int mod        = (int)1e9 + 7 ;


inline int add(int a, int b, int mod) {a += b ; return a >= mod ? a - mod : a ;}
inline int sub(int a, int b, int mod) {a -= b ; return a < 0 ? a + mod : a ;}
inline int mul(int a, int b, int mod) {return (ll)a * b % mod ;}

/*...... ! Code starts from here ! ......*/

int main() {
#ifndef ONLINE_JUDGE
    clock_t tStart = clock();
    freopen("input.txt", "r", stdin) ;
    freopen("output.txt", "w", stdout) ;
#endif

    int test = 1 , tc = 0 ;
    //Int(test) ;
    while (test--) {
        int n, a[3] ; Int(n, a[0], a[1], a[2]) ;
        vector < int > res ; 
        string s ;
        bool noresult = 0 ; 
        for(int i = 1 ; i <= n ; ++i){
            cin >> s ; 
            int x = s[0] - 'A', y = s[1] - 'A' ; 
            if(a[x] >= a[y] and a[x] > 1){
                --a[x] ; 
                ++a[y] ; 
                res.pb(y) ;
            }
            else if(a[x] < a[y] and a[y] > 1){
                --a[y] ; 
                ++a[x] ; 
                res.pb(x) ;
            }
            else {
                noresult = 1 ; 
                break ; 
            }
        }
        if(noresult)puts("No") ;
        else {
            puts("Yes") ;
            for(int i : res){
                printf("%c\n",i + 'A');
            }
        }
    }

#ifndef ONLINE_JUDGE
    fprintf(stderr, "\nRuntime: %.10fs\n", (double) (clock() - tStart) / CLOCKS_PER_SEC);
#endif
    return 0 ;
}