Problem:
Score : 300 points

Problem Statement

You are given an integer sequence of length n, a_1, ..., a_n.
Let us consider performing the following n operations on an empty sequence b.

The i-th operation is as follows:

Append a_i to the end of b.

Reverse the order of the elements in b.

Find the sequence b obtained after these n operations.

Constraints

1 \leq n \leq 2\times 10^5

0 \leq a_i \leq 10^9

n and a_i are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print n integers in a line with spaces in between.
The i-th integer should be b_i.

Sample Input 1

4
1 2 3 4

Sample Output 1

4 2 1 3

After step 1 of the first operation, b becomes: 1.

After step 2 of the first operation, b becomes: 1.

After step 1 of the second operation, b becomes: 1, 2.

After step 2 of the second operation, b becomes: 2, 1.

After step 1 of the third operation, b becomes: 2, 1, 3.

After step 2 of the third operation, b becomes: 3, 1, 2.

After step 1 of the fourth operation, b becomes: 3, 1, 2, 4.

After step 2 of the fourth operation, b becomes: 4, 2, 1, 3.

Thus, the answer is 4 2 1 3.

Sample Input 2

3
1 2 3

Sample Output 2

3 1 2

As shown above in Sample Output 1, b becomes 3, 1, 2 after step 2 of the third operation. Thus, the answer is 3 1 2.

Sample Input 3

1
1000000000

Sample Output 3

1000000000

Sample Input 4

6
0 6 7 6 7 0

Sample Output 4

0 6 6 0 7 7

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
using namespace std;

int main() {
	int n;
	cin>>n;
	int a[n];
	int b[n];
	for(int i=0;i<n;i++){
	    cin>>a[i];
	}
	for(int i=0;i<n;i++){
	    b[i]=0;
	}
	if(n!=1){
	    for(int i=0;i<n;i++){
	        if(i%2==0){
	            b[n/2+i/2]=a[i];
	        }
	        else{
	            b[n/2-(i+1)/2]=a[i];
	        }
	    }
	    if(n%2==0){
	        for(int i=0;i<n-1;i++){
	            cout<<b[i]<<" ";
	        }
	        cout<<b[n-1]<<endl;
	    }
	    else{
	        cout<<b[n-1];
	        for(int i=n-2;i>=0;i--){
	            cout<<" "<<b[i];
	        }
	        cout<<endl;
	    }
	}
	else{
	    cout<<a[0]<<endl;
	}
	return 0;
}