Problem:
Score : 100 points

Problem Statement

We have weather records at AtCoder Town for some consecutive three days. A string of length 3, S, represents the records - if the i-th character is S, it means it was sunny on the i-th day; if that character is R, it means it was rainy on that day.

Find the maximum number of consecutive rainy days in this period.

Constraints

|S| = 3

Each character of S is S or R.

Input

Input is given from Standard Input in the following format:

S

Output

Print the maximum number of consecutive rainy days in the period.

Sample Input 1

RRS

Sample Output 1

2

We had rain on the 1-st and 2-nd days in the period. Here, the maximum number of consecutive rainy days is 2, so we should print 2.

Sample Input 2

SSS

Sample Output 2

0

It was sunny throughout the period. We had no rainy days, so we should print 0.

Sample Input 3

RSR

Sample Output 3

1

We had rain on the 1-st and 3-rd days - two "streaks" of one rainy day, so we should print 1.

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
#define ll long long
#define IOS ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);
#define deb(x) cout<<#x<<"="<<x<<endl;
#define endl '\n'
#define M 1000000007
#define int long long
#define INF 1e18
#define max_n 1000000

using namespace std;

void solve()
{
	string s;
	cin >> s;
	ll c = 0;
	ll ans = 0;
	for (int i = 0; i < s.length(); ++i)
	{
		if (s[i] == 'R')c++;
		else {c = 0;}
		ans = max(ans, c);
	}
	ans = max(ans, c);
	cout << ans << endl;
}

int32_t main()
{
	IOS
	ll T = 1;
	// cin >> T;
	for (ll i = 1; i <= T; ++i)
	{
		// cout<<"Case #"<<i<<": ";
		solve();
	}
	return 0;
}