Problem:
Score : 300 points

Problem Statement

You are given an integer sequence of length n, a_1, ..., a_n.
Let us consider performing the following n operations on an empty sequence b.

The i-th operation is as follows:

Append a_i to the end of b.

Reverse the order of the elements in b.

Find the sequence b obtained after these n operations.

Constraints

1 \leq n \leq 2\times 10^5

0 \leq a_i \leq 10^9

n and a_i are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print n integers in a line with spaces in between.
The i-th integer should be b_i.

Sample Input 1

4
1 2 3 4

Sample Output 1

4 2 1 3

After step 1 of the first operation, b becomes: 1.

After step 2 of the first operation, b becomes: 1.

After step 1 of the second operation, b becomes: 1, 2.

After step 2 of the second operation, b becomes: 2, 1.

After step 1 of the third operation, b becomes: 2, 1, 3.

After step 2 of the third operation, b becomes: 3, 1, 2.

After step 1 of the fourth operation, b becomes: 3, 1, 2, 4.

After step 2 of the fourth operation, b becomes: 4, 2, 1, 3.

Thus, the answer is 4 2 1 3.

Sample Input 2

3
1 2 3

Sample Output 2

3 1 2

As shown above in Sample Output 1, b becomes 3, 1, 2 after step 2 of the third operation. Thus, the answer is 3 1 2.

Sample Input 3

1
1000000000

Sample Output 3

1000000000

Sample Input 4

6
0 6 7 6 7 0

Sample Output 4

0 6 6 0 7 7

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#define _GLIBCXX_DEBUG
#include <bits/stdc++.h>
using namespace std;
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define rep2(i, s, n) for (int i = (s); i < (int)(n); i++)
#define ALL(v) v.begin(),v.end()
using ll = long long;
using pii = pair<int,int>;
using vi = vector<int>;
using vs = vector<string>;
using vb = vector<bool>;
using vll = vector<long long>;
using vpii = vector<pair<int,int>>;
using vivi = vector<vector<int>>;
using vbvb = vector<vector<bool>>;
const int dx[4] = {1,0,-1,0};
const int dy[4] = {0,1,0,-1};
const int mod = 1000000007;
const int inf = 1001001001;



int main(void) {
  int n;
  cin >> n;
  vi a(n);
  rep(i,n) cin >> a[i];
  deque<int> b;
  rep(i,n){
    if(i%2)b.push_back(a[i]);
    else b.push_front(a[i]);
  }
  while(!b.empty()){
    if(n%2){
      cout << b.front() << endl;
      b.pop_front();
    }
    else{
      cout << b.back() << endl;
      b.pop_back();
    }
  }
  
      
}