Problem:
Score : 300 points

Problem Statement

You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

1 \leq |S| \leq 2 \times 10^5

|S| = |T|

S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S and T can be made equal, print Yes; otherwise, print No.

Sample Input 1

azzel
apple

Sample Output 1

Yes

azzel can be changed to apple, as follows:

Choose e as c_1 and l as c_2. azzel becomes azzle.

Choose z as c_1 and p as c_2. azzle becomes apple.

Sample Input 2

chokudai
redcoder

Sample Output 2

No

No sequences of operation can change chokudai to redcoder.

Sample Input 3

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
#define debug(x) cerr << "\n" \
                      << #x << ": " << x << "\n"
#define rep(i, n) for (int i = 0; i < (int)(n); ++i)
#define FOR(i, a, b) for (int i = (a); i < (b); ++i)
//#define int long long
#define print(x) cout << (x) << endl
using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
const int INF = (1LL << 30);
const ll MOD = 1000000007;

//=============================================================
string S, T;

void solve()
{
  bool isOK = true;

  set<pair<char, char>> s2t;
  rep(i, S.size())
  {
    s2t.insert(make_pair(S[i], T[i]));
  }

  bool exs[26] = {};

  for (auto x : s2t)
  {
    if (exs[x.second - 'a'])
    {
      isOK = false;
      break;
    }
    else
      exs[x.second - 'a'] = true;
  }
  cout << (isOK ? "Yes" : "No") << endl;
}
signed main()
{
  cin >> S;
  cin >> T;
  if (S.size() != T.size())
    return -1;
  solve();
  return 0;
}