Problem:
Score : 200 points

Problem Statement

A shop sells N kinds of fruits, Fruit 1, \ldots, N, at prices of p_1, \ldots, p_N yen per item, respectively. (Yen is the currency of Japan.)

Here, we will choose K kinds of fruits and buy one of each chosen kind. Find the minimum possible total price of those fruits.

Constraints

1 \leq K \leq N \leq 1000

1 \leq p_i \leq 1000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
p_1 p_2 \ldots p_N

Output

Print an integer representing the minimum possible total price of fruits.

Sample Input 1

5 3
50 100 80 120 80

Sample Output 1

210

This shop sells Fruit 1, 2, 3, 4, and 5 for 50 yen, 100 yen, 80 yen, 120 yen, and 80 yen, respectively.

The minimum total price for three kinds of fruits is 50 + 80 + 80 = 210 yen when choosing Fruit 1, 3, and 5.

Sample Input 2

1 1
1000

Sample Output 2

1000

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <algorithm>
#include <bitset>
#include <cmath>
#include <deque>
#include <iomanip>
#include <iostream>
#include <map>
#include <queue>
#include <set>
#include <stack>
#include <tuple>
#include <vector>

using namespace std;
typedef long long ll;
#define rep(i, n) for (ll i = 0; i < (n); i++)
#define reps(i, f, n) for (ll i = (f); i < (n); i++)
#define repv(v) for (auto it = (v).begin(); it != (v).end(); it++)
ll const INF = 1LL << 60;
ll const MAX_N = 510000;
ll const MOD = 1000000007;

int main() {
    ll N, K;
    cin >> N >> K;

    vector<ll> p(N);
    rep(i, N) cin >> p[i];

    // ll ans = INF;

    sort(p.begin(), p.end());
    ll ans = 0;
    rep(i, K) { ans += p[i]; }

    cout << ans << endl;

    // // bit全探索
    // bool exist = false;
    // for (ll bit = 0; bit < (1 << N); bit++) {
    //     ll sum = 0;

    //     for (ll i = 0; i < N; i++) {
    //         if (bit & (1 << i)) sum += p[i];
    //     }

    //     ans = min(sum, ans);
    // }

    // cout << ans << endl;

    return 0;
}