Problem:
Score : 200 points

Problem Statement

We have held a popularity poll for N items on sale. Item i received A_i votes.

From these N items, we will select M as popular items. However, we cannot select an item with less than \dfrac{1}{4M} of the total number of votes.

If M popular items can be selected, print Yes; otherwise, print No.

Constraints

1 \leq M \leq N \leq 100

1 \leq A_i \leq 1000

A_i are distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M
A_1 ... A_N

Output

If M popular items can be selected, print Yes; otherwise, print No.

Sample Input 1

4 1
5 4 2 1

Sample Output 1

Yes

There were 12 votes in total. The most popular item received 5 votes, and we can select it.

Sample Input 2

3 2
380 19 1

Sample Output 2

No

There were 400 votes in total. The second and third most popular items received less than \dfrac{1}{4\times 2} of the total number of votes, so we cannot select them. Thus, we cannot select two popular items.

Sample Input 3

12 3
4 56 78 901 2 345 67 890 123 45 6 789

Sample Output 3

Yes

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <string>
#include <algorithm>

using namespace std;

int main(){
  int i,N,M,sum,all; 
  bool can;
  int A[100];
  can=false;
  //  string S,A;
  
  cin>>N>>M;
  for(i=0;i<N;i++){
    cin>>A[i];
  }
  all=0;
  sum=0;
  for(i=0;i<N;i++){
    all+=A[i];
  }
  for(i=0;i<N;i++){
    if(A[i]>=(all/(4.0*M)))sum+=1;
  }
  if(sum>=M){
  cout<<"Yes"<<endl;
  }
  else{
    cout<<"No"<<endl;
  }
   return 0;
}