Problem:
Score : 100 points

Problem Statement

Given is a three-digit integer N. Does N contain the digit 7?

If so, print Yes; otherwise, print No.

Constraints

100 \leq N \leq 999

Input

Input is given from Standard Input in the following format:

N

Output

If N contains the digit 7, print Yes; otherwise, print No.

Sample Input 1

117

Sample Output 1

Yes

117 contains 7 as its last digit.

Sample Input 2

123

Sample Output 2

No

123 does not contain the digit 7.

Sample Input 3

777

Sample Output 3

Yes

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;
using ll = long long;
#define rep(i,n) for(int i = 0; i < (n); i++)

int main(){
    int N;
    cin >> N;
    int A = N % 10;
    int B = (N - A) % 100;
    int C = N - B - A;
    if (A == 7 || B == 70 || C == 700){
        cout << "Yes" << endl;
    }
    else {
        cout << "No" << endl;
    }
}