Problem:
Score : 200 points

Problem Statement

Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Constraints

1 \leq N \leq 10^4

1 \leq A \leq B \leq 36

All input values are integers.

Input

Input is given from Standard Input in the following format:

N A B

Output

Print the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Sample Input 1

20 2 5

Sample Output 1

84

Among the integers not greater than 20, the ones whose sums of digits are between 2 and 5, are: 2,3,4,5,11,12,13,14 and 20. We should print the sum of these, 84.

Sample Input 2

10 1 2

Sample Output 2

13

Sample Input 3

100 4 16

Sample Output 3

4554

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;
int main(){
	int N,A,B;
	cin >> N >> A >> B;

	int n[10];

	int rec = 0;
	for(int i=1;i<=N;++i){
		n[5] = i / 10000;
		n[4] = (i - n[5] * 10000) / 1000;
		n[3] = (i - n[5] * 10000 - n[4] * 1000) / 100;
		n[2] = (i - n[5] * 10000 - n[4] * 1000 - n[3] * 100) / 10;
		n[1] =  i - n[5] * 10000 - n[4] * 1000 - n[3] * 100 - n[2] * 10;
		int souwa = n[5] + n[4] + n[3] + n[2] + n[1];
		for(int j=A;j<=B;++j){
			if(souwa == j) rec += i;
		}
	}

	cout << rec << endl;
//	cout << n[4] << n[3] << n[2] << n[1] << endl;
}