Problem:
Score : 200 points

Problem Statement

Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Constraints

1 \leq N \leq 10^4

1 \leq A \leq B \leq 36

All input values are integers.

Input

Input is given from Standard Input in the following format:

N A B

Output

Print the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Sample Input 1

20 2 5

Sample Output 1

84

Among the integers not greater than 20, the ones whose sums of digits are between 2 and 5, are: 2,3,4,5,11,12,13,14 and 20. We should print the sum of these, 84.

Sample Input 2

10 1 2

Sample Output 2

13

Sample Input 3

100 4 16

Sample Output 3

4554

Solution in C++14 (GCC 5.4.1) (judge verdict: Runtime Error)

#include <iostream>
#include <vector>
#include <algorithm>
#include <cmath>
#include <string>
using namespace std;



int main(void)
{
    int A, B, N, cnt = 0;
    
    cin >> N >> A >> B;

    for(int i = 1; i <= N; i++)
    {
        string s = to_string(i);
        int sum = 0;
        for(int j = 0; j < s.size(); j++) sum += s.at(i) - '0';
        
        if(sum >= A && sum <= B) cnt++;
    }

    cout << cnt << endl;

    return 0;
}