Problem:
Score : 300 points

Problem Statement

We have two desks: A and B. Desk A has a vertical stack of N books on it, and Desk B similarly has M books on it.

It takes us A_i minutes to read the i-th book from the top on Desk A (1 \leq i \leq N), and B_i minutes to read the i-th book from the top on Desk B (1 \leq i \leq M).

Consider the following action:

Choose a desk with a book remaining, read the topmost book on that desk, and remove it from the desk.

How many books can we read at most by repeating this action so that it takes us at most K minutes in total? We ignore the time it takes to do anything other than reading.

Constraints

1 \leq N, M \leq 200000

1 \leq K \leq 10^9

1 \leq A_i, B_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M K
A_1 A_2 \ldots A_N
B_1 B_2 \ldots B_M

Output

Print an integer representing the maximum number of books that can be read.

Sample Input 1

3 4 240
60 90 120
80 150 80 150

Sample Output 1

3

In this case, it takes us 60, 90, 120 minutes to read the 1-st, 2-nd, 3-rd books from the top on Desk A, and 80, 150, 80, 150 minutes to read the 1-st, 2-nd, 3-rd, 4-th books from the top on Desk B, respectively.

We can read three books in 230 minutes, as shown below, and this is the maximum number of books we can read within 240 minutes.

Read the topmost book on Desk A in 60 minutes, and remove that book from the desk.

Read the topmost book on Desk B in 80 minutes, and remove that book from the desk.

Read the topmost book on Desk A in 90 minutes, and remove that book from the desk.

Sample Input 2

3 4 730
60 90 120
80 150 80 150

Sample Output 2

7

Sample Input 3

5 4 1
1000000000 1000000000 1000000000 1000000000 1000000000
1000000000 1000000000 1000000000 1000000000

Sample Output 3

0

Watch out for integer overflows.

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#define _GLIBCXX_DEBUG

#include"bits/stdc++.h"
using namespace std;

//loops
#define REP(i,n) for(ll i=0;i<(ll)(n);i++)
#define REPD(i,n) for(ll i=(ll)(n)-1;i>=0;i--)
#define OneToN(i,n) for(ll i=1;i<(ll)(n+1);i++)
#define ZeroToN(i,n) for(ll i=0;i<(ll)(n+1);i++)
#define AToB(i,a,b) for(ll i=a;i<(ll)(b+1);i++)
#define FOR(i,a,b) for(ll i=(a);i<=(b);i++)
#define FORD(i,a,b) for(ll i=(a);i>=(b);i--)

//bitsearch
#define BITSEARCH(bit, n) for (int bit = 0; bit < (1<<n); ++bit)
#define isOne(bit, i) bit & (1<<i)


//arrays
#define ALL(x) (x).begin(),(x).end() //sortなどの引数を省略したい
#define SIZE(x) ((ll)(x).size()) //sizeをsize_tからllに直しておく
#define add push_back

template<typename T>
std::vector<T> slice(std::vector<T> const &v, int m, int n)
{
    auto first = v.cbegin() + m;
    auto last = v.cbegin() + n + 1;

    std::vector<T> vec(first, last);
    return vec;
}

//v need to be sorted
#define remove_unique(v) v.erase(unique(ALL(v)), v.end())

//comparision
template<class T> bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }
template<class T> bool chmin(T &a, const T &b) { if (a>b) { a=b; return 1; } return 0; }

//pair
#define fir first
#define sec second
#define mp make_pair

//types
#define ll long long
#define vec vector
#define cord2d pair<int,int>
#define intP pair<int, int>

//UNCOMMENT WHEN NEEDED
//#define int ll

//input
template <class T> T get(){ T s; cin >> s; return(s);}
#define gi get<int>()
#define gs get<string>()
#define gll get<ll>()

template <class T> vector<T> getv(int n) { vec<T> v(n); REP(i, n) cin >> v[i]; return v; }
#define gim(n) getv<int>(n)
#define gsm(n) getv<string>(n)
#define gllm(n) getv<ll>(n)

//output
void print(int a){ cout << a << endl; }
void print(long long a){ cout << std::fixed << a << endl; }
void print(string a){ cout << a << endl; }
void print(char a){ cout << a << endl; }
void print(double a){ cout << a << endl; }
void print(double a, int dig){ cout << std::setprecision(dig) << a << endl; }

template <class T>ostream &operator<<(ostream &o,const vector<T>&v)
{o<<"{";for(int i=0;i<(int)v.size();i++)o<<(i>0?", ":"")<<v[i];o<<"}";return o;}

template <class T = int>
void print(vec<T> v){ cout << v << endl; }

template <class T = int>
void print2dVec(vec<vec<T>> v2d){for(vec<T> v: v2d) {print(v);}}

void YesNo1(bool i = true){ return print(i?"Yes":"No"); }
void YESNO2(bool i = true){ return print(i?"YES":"NO"); }

//debug output
#define var_name(var) #var
template <class T> void debug(T &var, int nest = 0, string before = "") { cout << string("          ", nest) << before; print(var); }

//name replacement
#define y0 y0__
#define y1 y1__
#define j0 j0__
#define j1 j1__

//bool lambdas
#define lamb(exp) [](auto i){return exp;}
#define isEven [](int i){return i % 2 == 0;}
#define isOdd [](int i){return i % 2 != 0;}

//constants
const ll INF = 1e18;
const int MOD = 1000000007;
const vec<string> alphabets = { "a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z" };

//maths
int factorial(int k){ int sum = 1; for (int i = 1; i <= k; ++i) { sum *= i; } return sum; }

ll gcd(ll a, ll b) { if (b == 0) { return a; } return gcd(b, a % b); }
ll lcm(ll a, ll b) { ll temp = gcd(a, b); return temp ? (a / temp * b) : 0; }

////////////////////

vector<pair<long long, long long> > prime_factorize(long long N) {
    vector<pair<long long, long long> > res;
    for (long long a = 2; a * a <= N; ++a) {
        if (N % a != 0) continue;
        long long ex = 0; // 指数

        // 割れる限り割り続ける
        while (N % a == 0) {
            ++ex;
            N /= a;
        }

        // その結果を push
        res.push_back({a, ex});
    }

    // 最後に残った数について
    if (N != 1) res.push_back({N, 1});
    return res;
}

string capitalize(string s){ // function prototype
    string newS = "";
    for (char c: s) {
        newS += toupper(c);
    }
    return newS;
}


void Main() {
    //code here

    int n = gi, m = gi, k = gi;
    vec<int> as = gim(n);
    vec<int> bs = gim(m);

    reverse(ALL(as));
    reverse(ALL(bs));

    int count = 0;
    while(true) {
         if(as.size() == 0 && bs.size() == 0) {
             break;
         } else if (as.size() == 0) {
             if (k - *bs.rbegin() >= 0) {
                 k -= *bs.rbegin();
                 bs.pop_back();
             } else {
                 break;
             }
         } else if (bs.size() == 0) {
             if (k - *as.rbegin() >= 0) {
                 k -= *as.rbegin();
                 as.pop_back();
             } else {
                 break;
             }
         } else if (*as.rbegin() < *bs.rbegin()) {
             if (k - *as.rbegin() >= 0) {
                 k -= *as.rbegin();
                 as.pop_back();
             } else {
                 break;
             }
        } else {
             if (k - *bs.rbegin() >= 0) {
                 k -= *bs.rbegin();
                 bs.pop_back();
             } else {
                 break;
             }
        }
         //print(as);
         //print(bs);
        count++;
    }

    print(count);


}


signed main() {
    cin.tie(0);
    ios::sync_with_stdio(false);
    Main();
}