Problem:
Score : 100 points

Problem Statement

Given is a three-digit integer N. Does N contain the digit 7?

If so, print Yes; otherwise, print No.

Constraints

100 \leq N \leq 999

Input

Input is given from Standard Input in the following format:

N

Output

If N contains the digit 7, print Yes; otherwise, print No.

Sample Input 1

117

Sample Output 1

Yes

117 contains 7 as its last digit.

Sample Input 2

123

Sample Output 2

No

123 does not contain the digit 7.

Sample Input 3

777

Sample Output 3

Yes

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include <iostream>
#include <climits>
#include <algorithm>
#include <string>
#define rep(i, n) for (int i = 0; (i) < (int)(n); i++)
using namespace std;
int main() {
	string N;
	cin >> N;
	for (int i = 0; i < 3; i++) {
		if (N[i] == '7') {
			cout << "Yes" << endl;
			return 0;
		}
	}
	cout << "No" << endl;
	return 0;
}