Problem:
Score : 300 points

Problem Statement

Does \sqrt{a} + \sqrt{b} < \sqrt{c} hold?

Constraints

1 \leq a, b, c \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

a \ b \ c

Output

If \sqrt{a} + \sqrt{b} < \sqrt{c}, print Yes; otherwise, print No.

Sample Input 1

2 3 9

Sample Output 1

No

\sqrt{2} + \sqrt{3} < \sqrt{9} does not hold.

Sample Input 2

2 3 10

Sample Output 2

Yes

\sqrt{2} + \sqrt{3} < \sqrt{10} holds.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
#define rep( i, n ) for (long long i = 0; i < ( long long )(n); i++)

using namespace std;
typedef long long ll;
typedef pair< int , int > P;

int main(){
  ll a,b,c;
  long double aa,bb,cc;
  cin>>a>>b>>c;
  aa= (long double) sqrt((long double)a);
  bb= (long double) sqrt((long double)b);
  cc= (long double) sqrt((long double)c);
  if(aa+bb<cc) cout<<"Yes";
  else "No";
}