Problem:
Score : 200 points

Problem Statement

Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print -1 instead.

Constraints

2 \leq N \leq 10^5

0 \leq A_i \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the value A_1 \times ... \times A_N as an integer, or -1 if the value exceeds 10^{18}.

Sample Input 1

2
1000000000 1000000000

Sample Output 1

1000000000000000000

We have 1000000000 \times 1000000000 = 1000000000000000000.

Sample Input 2

3
101 9901 999999000001

Sample Output 2

-1

We have 101 \times 9901 \times 999999000001 = 1000000000000000001, which exceeds 10^{18}, so we should print -1 instead.

Sample Input 3

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0

Sample Output 3

0

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <iostream>
#include <sstream>
#include <iomanip>
#include <stdio.h>
#include <string>
#include <cstdlib>
#include <vector>
#include <cmath>
#include <math.h>
#include <stdexcept>
#include <algorithm>
#include <set>
#include <map>
#include <stdlib.h>
#include <cctype>
using namespace std;
int main(){
    long long int N,i,a;
    cin >> N;
    a = 1;
    long long int A[N];
    for(i = 0;i < N;i++){
        cin >> A[i];
    }
    sort(A,A + N);
    for(i = 0;i < N;i++){
        if (A[i] == 0){
            a = 0;
            break;
        }
        a *= A[i];
        if (a > 1000000000000000000){
            a = -1;
            break;
        }
    }
    cout << a << endl;
}