Problem:
Score : 300 points

Problem Statement

Compute A \times B, truncate its fractional part, and print the result as an integer.

Constraints

0 \leq A \leq 10^{15}

0 \leq B < 10

A is an integer.

B is a number with two digits after the decimal point.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the answer as an integer.

Sample Input 1

198 1.10

Sample Output 1

217

We have 198 \times 1.10 = 217.8. After truncating the fractional part, we have the answer: 217.

Sample Input 2

1 0.01

Sample Output 2

0

Sample Input 3

1000000000000000 9.99

Sample Output 3

9990000000000000

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

// Best practice

#include<bits/stdc++.h>

#define int         long long
#define pb          push_back
#define pf          emplace_front
#define all(a)      (a).begin(),(a).end()
#define rall(a)     (a).rbegin(),(a).rend()
#define pii 		pair<int,int>
#define psi 		pair<string,int>
#define vi 			vector<int>
#define vpii  		vector<pii>
#define vvi 		vector<vi>
#define sz(x)	    (int)(x).size()
#define x           first
#define y           second
#define endl        '\n'
#define tezz        ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0);
#define MOD         1000000007
#define hell        998244353
#define output(x)   cout << (x ? "YES" : "NO")<<endl;
using namespace std;


// Code from Here -------------------------------------------------------------------------------


signed main() {
	tezz

	double a,b;
	cin >> a >> b;
	a = a*b;
	int ans=a;
	cout << ans;

	return 0;
}