Problem:
Score : 100 points

Problem Statement

Given is a three-digit integer N. Does N contain the digit 7?

If so, print Yes; otherwise, print No.

Constraints

100 \leq N \leq 999

Input

Input is given from Standard Input in the following format:

N

Output

If N contains the digit 7, print Yes; otherwise, print No.

Sample Input 1

117

Sample Output 1

Yes

117 contains 7 as its last digit.

Sample Input 2

123

Sample Output 2

No

123 does not contain the digit 7.

Sample Input 3

777

Sample Output 3

Yes

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

#include<iostream>
#include<bits/stdc++.h>
using namespace std;
using ll = long long;
/*int main()
{
    char s[4];
    cin>>s;
    if((s[0]=='7')|| (s[1]=='7') || (s[2]=='7'))
    {
         cout<<"YES";
    }
    else{
         cout<<"NO";
    }*/
int main()
{
    char s[4];
    scanf("%s",s);
    if(s[0]=='7'||s[1]=='7'||s[2]=='7')
        puts("Yes");
    else
        puts("No");
}