Problem:
Score : 200 points

Problem Statement

Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print -1 instead.

Constraints

2 \leq N \leq 10^5

0 \leq A_i \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the value A_1 \times ... \times A_N as an integer, or -1 if the value exceeds 10^{18}.

Sample Input 1

2
1000000000 1000000000

Sample Output 1

1000000000000000000

We have 1000000000 \times 1000000000 = 1000000000000000000.

Sample Input 2

3
101 9901 999999000001

Sample Output 2

-1

We have 101 \times 9901 \times 999999000001 = 1000000000000000001, which exceeds 10^{18}, so we should print -1 instead.

Sample Input 3

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0

Sample Output 3

0

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <iostream>
using namespace std;
#define ll long long int
const ll big = 1e18;
int main() {
    // #ifndef ONLINE_JUDGE
    //     // for getting input from input.txt
    //     freopen("input.txt", "r", stdin);
    //     // for writing output to output.txt
    //     freopen("output.txt", "w", stdout);
    // #endif
    ll n, ans = 1, a;
    cin >> n;
    for(int i = 0; i < n; i++) {
        cin >> a;
        ans *= a;
        if(ans>big) {
            cout << -1;
            return 0;
        }
    }
    if(ans > big) {
        cout << -1;
    } else {
        cout << ans;
    }
    return 0;
}