Problem:
Score : 200 points

Problem Statement

Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Constraints

1 \leq N \leq 10^4

1 \leq A \leq B \leq 36

All input values are integers.

Input

Input is given from Standard Input in the following format:

N A B

Output

Print the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Sample Input 1

20 2 5

Sample Output 1

84

Among the integers not greater than 20, the ones whose sums of digits are between 2 and 5, are: 2,3,4,5,11,12,13,14 and 20. We should print the sum of these, 84.

Sample Input 2

10 1 2

Sample Output 2

13

Sample Input 3

100 4 16

Sample Output 3

4554

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<iostream>
#include<algorithm>
#define rep(i,n) for(int i=0;i<n;i++)
#define rep1(i,n) for(int i=1;i<=n;i++)
#define NMAX 100000
#define INF 1e+6
#define scan(arg) cin>>arg
#define prin(arg) cout<<arg<<"\n"
#define prin2(arg1,arg2) cout<<arg1<<" "<<arg2<<"\n"
using namespace std;
typedef long long ll;
int n,a,b;
int main(){
  scan(n);scan(a);scan(b);
  int ans=0;
  rep1(i,n){
    int sum=0,j=i;
    sum+=j%10;
    while(j>=10){
      j/=10;
      sum+=j%10;
    }
    if(a<=sum&&sum<=b){
      ans+=i;
    }
  }
  prin(ans);
  
  return 0;
}