Problem:
Score : 300 points

Problem Statement

Does \sqrt{a} + \sqrt{b} < \sqrt{c} hold?

Constraints

1 \leq a, b, c \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

a \ b \ c

Output

If \sqrt{a} + \sqrt{b} < \sqrt{c}, print Yes; otherwise, print No.

Sample Input 1

2 3 9

Sample Output 1

No

\sqrt{2} + \sqrt{3} < \sqrt{9} does not hold.

Sample Input 2

2 3 10

Sample Output 2

Yes

\sqrt{2} + \sqrt{3} < \sqrt{10} holds.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;
const long long inf = 1e18;
typedef long long ll;
typedef vector<ll> vl;
#define rp(i, f, t) for (int i = f; i < t; i++)
#define pr(i, f, t) for (int i = t - 1; i >= f; i--)
#define ca(n, a) rp(ca_i, 0, n) cout << a[ca_i] << ((ca_i == n - 1) ? "\n" : " ")
#define za(n, a) rp(za_i, 0, n) a[za_i] = 0
#define be(a) a.begin(), a.end()
int main()
{
    ll a, b, c;
    cin >> a >> b >> c;
    if (4 * a * b < (c - a - b) * (c - a - b))
        cout << "Yes";
    else
        cout << "No";
    cout << endl;
}