Problem:
Score : 200 points

Problem Statement

Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print -1 instead.

Constraints

2 \leq N \leq 10^5

0 \leq A_i \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the value A_1 \times ... \times A_N as an integer, or -1 if the value exceeds 10^{18}.

Sample Input 1

2
1000000000 1000000000

Sample Output 1

1000000000000000000

We have 1000000000 \times 1000000000 = 1000000000000000000.

Sample Input 2

3
101 9901 999999000001

Sample Output 2

-1

We have 101 \times 9901 \times 999999000001 = 1000000000000000001, which exceeds 10^{18}, so we should print -1 instead.

Sample Input 3

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0

Sample Output 3

0

Solution in C++ (GCC 9.2.1) (judge verdict: Accepted)

// #include <bits/stdc++.h>
#include <algorithm>
#include <cmath>
#include <deque>
#include <iostream>
#include <iterator>
#include <list>
#include <map>
#include <queue>
#include <set>
#include <stack>
#include <string>
#include <unordered_map>
#include <unordered_set>
#include <utility>
#include <vector>

using namespace std;
typedef long long ll;

#define all(x) begin(x), end(x)
#define rep(i,n) for(int i=0; i<n; i++)

int main() {
    int n;
    cin >> n;

    ll a;
    ll ans = 1;
    ll MAX = 1e18;
    bool flag = 0;
    bool zero = 0;

    rep(i, n) {
        cin >> a;
        if (a==0) zero = 1;
        else if (ans > MAX/a) flag = 1;
        ans *= a;
    }

    if (zero) cout << 0 << endl;
    else if (flag) cout << -1 << endl;
    else cout << ans << endl;

    return 0;
}