Problem:
Score : 300 points

Problem Statement

Snuke loves puzzles.

Today, he is working on a puzzle using S- and c-shaped pieces.
In this puzzle, you can combine two c-shaped pieces into one S-shaped piece, as shown in the figure below:

Snuke decided to create as many Scc groups as possible by putting together one S-shaped piece and two c-shaped pieces.

Find the maximum number of Scc groups that can be created when Snuke has N S-shaped pieces and M c-shaped pieces.

Constraints

1 ≤ N,M ≤ 10^{12}

Input

The input is given from Standard Input in the following format:

N M

Output

Print the answer.

Sample Input 1

1 6

Sample Output 1

2

Two Scc groups can be created as follows:

Combine two c-shaped pieces into one S-shaped piece

Create two Scc groups, each from one S-shaped piece and two c-shaped pieces

Sample Input 2

12345 678901

Sample Output 2

175897

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <iostream>
#include <vector>
#include <string>
#include <algorithm>
#include <cmath>
#include <queue>
#include <climits>
#include <set>
#include <map>
#include <stack>
#include <iomanip>
#include <tuple>
#define ll long long
using namespace std;
ll factorial(ll n){
    if(n==0){
        return 1;
    }
    else{
        return n*factorial(n-1);
    }
}

double dist(pair<double,double> a,pair<double,double> b){
	return sqrt(pow((a.first - b.first) ,2) + pow((a.second - b.second),2));
}
//繰り返し自乗法
double ism(double aa,ll p){
    double ap=aa;
    double ans=1;
    while(p>0){
        //cout<<"p="<<p<<",ap="<<ap<<endl;
        if(p&1){//奇数が真
            ans*=ap;
        }
        p/=2;
        ap=ap*ap;
    }
    return ans;

}
//繰り返し自乗法(アマリトリバージョン)
ll ismm(ll aa,ll p,ll m){
    ll ap=aa;
    ll ans=1;
    while(p>0){
        //cout<<"p="<<p<<",ap="<<ap<<endl;
        if(p&1){//奇数が真
            ans=(ans*ap)%m;    
        }
        p/=2;              
        ap=(ap*ap)%m;
    }
    return ans;

}

struct all_init
{
    all_init()
    {
        cout << fixed << setprecision(9);
    }
} All_init;


int main()
{
    ll n,m,ans=0;
    cin>>n>>m;
    ans=min(n,m/2);
    m-=ans*2;
    ans+=m/4;
    cout<<ans<<endl;

    
}