Problem:
Score : 700 points

Problem Statement

10^{10^{10}} participants, including Takahashi, competed in two programming contests.
In each contest, all participants had distinct ranks from first through 10^{10^{10}}-th.

The score of a participant is the product of his/her ranks in the two contests.

Process the following Q queries:

In the i-th query, you are given two positive integers A_i and B_i. Assuming that Takahashi was ranked A_i-th in the first contest and B_i-th in the second contest, find the maximum possible number of participants whose scores are smaller than Takahashi's.

Constraints

1 \leq Q \leq 100

1\leq A_i,B_i\leq 10^9(1\leq i\leq Q)

All values in input are integers.

Input

Input is given from Standard Input in the following format:

Q
A_1 B_1
:
A_Q B_Q

Output

For each query, print the maximum possible number of participants whose scores are smaller than Takahashi's.

Sample Input 1

8
1 4
10 5
3 3
4 11
8 9
22 40
8 36
314159265 358979323

Sample Output 1

1
12
4
11
14
57
31
671644785

Let us denote a participant who was ranked x-th in the first contest and y-th in the second contest as (x,y).

In the first query, (2,1) is a possible candidate of a participant whose score is smaller than Takahashi's. There are never two or more participants whose scores are smaller than Takahashi's, so we should print 1.

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
#define mod 1000000007
#define pb push_back
#define ll long long
#define mp make_pair
using namespace std;
int main(){
	ll q;
	cin>>q;
	for(int i=0;i<q;i++){
		ll a,b;
		cin>>a>>b;
		if(a==b){
			cout<<a+b-2<<endl;
		}
		else{
			if(a>b){
				ll x = a;
				a = b;
				b = x;
			}
			if(b-a==1){
				cout<<a+b-2<<endl;
			}
			double tag = (a*b-1.0)*4.0;
			tag = sqrt(tag);
			ll itag = (ll)floor(tag);
			cout<<itag-2<<endl;
		}
	}
	return 0;
}