Problem:
Score : 100 points

Problem Statement

In programming, hexadecimal notation is often used.

In hexadecimal notation, besides the ten digits 0, 1, ..., 9, the six letters A, B, C, D, E and F are used to represent the values 10, 11, 12, 13, 14 and 15, respectively.

In this problem, you are given two letters X and Y. Each X and Y is A, B, C, D, E or F.

When X and Y are seen as hexadecimal numbers, which is larger?

Constraints

Each X and Y is A, B, C, D, E or F.

Input

Input is given from Standard Input in the following format:

X Y

Output

If X is smaller, print <; if Y is smaller, print >; if they are equal, print =.

Sample Input 1

A B

Sample Output 1

<

10 < 11.

Sample Input 2

E C

Sample Output 2

>

14 > 12.

Sample Input 3

F F

Sample Output 3

=

15 = 15.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;

typedef long long int ll;
typedef long double ld;
typedef vector<ll> vi;
typedef vector<string> vs;
typedef pair<ll,ll> P;
typedef vector<P> vp;

#define REP(i,n) for(int i=0;i<n;i++)
#define FOR(i,m,n) for(int i=m;i<n;i++)
#define REPR(i,n) for(int i=n-1;i>=0;i--)
#define FORR(i,n,m) for(int i=n-1;i>=m;i--)
#define ARR(array) for(int i=0;i<array.size();i++)
#define all(in) in.begin(),in.end()
#define ALL(in,K) (in),(in)+(K)

#define INF 1e18
#define MOD 1000000007
#define SIZE 10005
#define PI 	3.14159265358979323846

ll gcd(ll a, ll b) { return b ? gcd(b, a%b) : a; } //最大公約数
ll lcm(ll a, ll b) { return a/gcd(a, b)*b; } //最小公倍数

ll input(){
ll a;
  cin >> a;
  return a;
}

vi sub(vector<bool> fin,ll n) {
  vi ret;
  REP(i,n) {
    if(fin.at(i))continue;
    vector<bool> cp = fin;
    cp.at(i) = true;
    vi result = sub(cp,n);
    ret.insert(ret.end(),result.begin(),result.end());
  }
  return ret;
}

int main() {
  char a,b;
  cin >> a >> b;
  if(a==b)cout << "=" << endl;
  if(a<b)cout << "<" << endl;
  if(a>b)cout << ">" << endl;
}