Problem:
Score : 400 points

Problem Statement

Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.

You are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.

Constraints

2 ≦ |s| ≦ 10^5

s consists of lowercase letters.

Partial Score

200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.

Input

The input is given from Standard Input in the following format:

s

Output

If there exists no unbalanced substring of s, print -1 -1.

If there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.

Sample Input 1

needed

Sample Output 1

2 5

The string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.

Sample Input 2

atcoder

Sample Output 2

-1 -1

The string atcoder contains no unbalanced substring.

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include<bits/stdc++.h>
using namespace std;
#define arep(i,x,n) for(int i=int(x);i<(int)(n);i++)
#define rep(i,n) for(long long i = 0;i < n;++i)
#define pi 3.141592653589793
#define eps 0.00000001
#define INF 1e9+7  
using ll = long long; 
using P=pair<int,int>;
using lP=pair<ll,ll>;
using fP=pair<double,double>;
ll const mod=998244353;
const ll MAX=300000;
using vi=vector<int>;
using vc=vector<char>;
using vs=vector<string>;
using vvi =vector<vector<int>>;
using vvc=vector<vector<char>>;
using vvp =vector<vector<P>>;


int main(){
    string s;
    cin>>s;
    int n=s.size();
    rep(i,n-1){
        if(i+2<n&&s[i]==s[i+2]){
            cout<<i+1<<" "<<i+3<<endl;
            return 0;
        }
        if(s[i]==s[i+1]){
            cout<<i+1<<" "<<i+2<<endl;
            return 0;
        }
    }
    cout<<-1<<" "<<-1<<endl;
    return 0;
}