Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;
#define rep(i,k,n) for(int i = (k); i < n;i++)

long double calc (int N,int h,int n){
	long double temp = n * h * N;
	long double timp = 4*h*n - n*N - h*N;
	return temp / timp;
}

int main(){
	int N;
	cin >> N;
	int h,n,w;
	rep(i,1,3500){
		rep(j,1,3500){

			long double temp = calc(N,i,j);
			if(((temp - int(temp)) == 0) && (temp > 0)){
				h = i;
				n = j;
				w = temp;
				cout << h << " " << n << " " << w << endl;
				return 0;
			}
		}
	}
}