Problem:
Score : 300 points

Problem Statement

Sitting in a station waiting room, Joisino is gazing at her train ticket.

The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).

In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.

The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Constraints

0≤A,B,C,D≤9

All input values are integers.

It is guaranteed that there is a solution.

Input

Input is given from Standard Input in the following format:

ABCD

Output

Print the formula you made, including the part =7.

Use the signs + and -.

Do not print a space between a digit and a sign.

Sample Input 1

1222

Sample Output 1

1+2+2+2=7

This is the only valid solution.

Sample Input 2

0290

Sample Output 2

0-2+9+0=7

0 - 2 + 9 - 0 = 7 is also a valid solution.

Sample Input 3

3242

Sample Output 3

3+2+4-2=7

Solution in C++14 (GCC 5.4.1) (judge verdict: Accepted)

#include <bits/stdc++.h>
using namespace std;

int main() {
  int s;
  cin>>s;
  int a=s/1000;
  s -= 1000*a;
  int b=s/100;
  s -= 100*b;
  int c=s/10;
  s -= 10*c;
  int d=s;
  char op1,op2,op3;
 // cout<<a<<b<<c<<d;
  for(int i=0;i<2;i++){
    if(i%2==0) op1='+';
    else op1 ='-';
    for(int j=0;j<2;j++){
      if(j%2==0) op2='+';
      else op2 ='-';
      for(int k=0;k<2;k++){
        int sum=a;
            if(k%2==0) op3='+';
            else op3 ='-';

            if(op1=='+') sum+=b;
            if(op1=='-') sum-=b;
            if(op2=='+') sum+=c;
            if(op2=='-') sum-=c;
            if(op3=='+') sum+=d;
            if(op3=='-') sum-=d;
            if(sum==7){
              cout<<a<<op1<<b<<op2<<c<<op3<<d<<"=7"<<endl;
              return 0;
            }
      }
    }
  }

}