Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in C++ (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <bits/stdc++.h>
using namespace std;
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
using ll = long long;
ll m = 1e9 + 7;

int main() {
  int N;
  cin >> N;

  for (int h = 1; h <= 3500; h++) {
    for (int n = 1; n <= 3500; n++){
      if ((4*h*n-N*n-N*h) == 0) continue;
      if ((N*h*n) % (4*h*n-N*n-N*h) == 0){
        if ((N*h*n) / (4*h*n-N*n-N*h) >= 1){
          cout << h << endl;
          cout << n << endl;
          cout << (N*h*n) / (4*h*n-N*n-N*h) << endl;
          return 0;
        }
      }
    }
  }

  return 0;

}