Problem:
Score : 300 points

Problem Statement

You are given three integers A, B and C. Find the minimum number of operations required to make A, B and C all equal by repeatedly performing the following two kinds of operations in any order:

Choose two among A, B and C, then increase both by 1.

Choose one among A, B and C, then increase it by 2.

It can be proved that we can always make A, B and C all equal by repeatedly performing these operations.

Constraints

0 \leq A,B,C \leq 50

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B C

Output

Print the minimum number of operations required to make A, B and C all equal.

Sample Input 1

2 5 4

Sample Output 1

2

We can make A, B and C all equal by the following operations:

Increase A and C by 1. Now, A, B, C are 3, 5, 5, respectively.

Increase A by 2. Now, A, B, C are 5, 5, 5, respectively.

Sample Input 2

2 6 3

Sample Output 2

5

Sample Input 3

31 41 5

Sample Output 3

23

Solution in C++14 (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
int main (void){
  int a,b,c,i,j,count;
  scanf("%d %d %d",&a,&b,&c);
  count = 0;
  if (a == b && b == c)
    printf("%d\n",count);
  if (a > b && b > c){
    for (i = 0; i < a - b; i++)
      count++;
  }
  else if (a > b && a > c && c > b){
    j = a - c;
    for (i = 0; i < j; i++){
      count++;
      c++;
      b++;
    }
  }
  else if (b > c && c > a){
    j = b - c;
    for (i = 0; i < j; i++){
      count++;
      c++;
      a++;
    }
  }
  else if (b > c && b > a && a > c){
    j = b - a;
    for (i = 0; i < j; i++){
      count++;
      a++;
      c++;
    }
  }
  else if (c > a && a > b){
    j = c - a;
    for (i = 0; i < j; i++){
      count++;
      a++;
      b++;
    }
  }
  else if (c > a && c > b && b > a){
    j = c - b;
    for (i = 0; i < j; i++){
      count++;
      b++;
      a++;
    }
  }
  if (a == b && b > c){
    j = b - c;
    for (i = 0; i < j; i++){
      count++;
      c += 2;
      if (b == c){
	printf("%d\n",count);
	break;
      }
      else if (b < c){
	count++;
	printf("%d\n",count);
	break;
      }
    }
  }
  else if (a == b && b < c){
    for (i = 0; i < c - b; i++){
      count++;
      printf("%d\n",count);
    }
  }
  else if (b == c && a < b){
    j = b - a;
    for (i = 0; i < j; i++){
      count++;
      a += 2;
      if (a == b){
	printf("%d\n",count);
	break;
      }
      else if (a > b){
	count++;
	printf("%d\n",count);
	break;
      }
    }
  }
  else if (b == c && a > b){
    for (i = 0; i < b - a; i++){
      count++;
      printf("%d\n",count);
      break;
    }
  }
  else if (a == c && c > b){
    j = b - c;
    for (i = 0; i < j; i++){
      count++;
      b += 2;
      if (c == b){
	printf("%d\n",count);
	break;
      }
      else if (c < b){
	count++;
	printf("%d\n",count);
	break;
      }
    }
  }
  else if (a == c && b > c){
    for (i = 0; i < b - c; i++){
      count++;
      printf("%d\n",count);
      break;
    }
  }
  return (0);
}