Problem:
Score : 200 points

Problem Statement

Given are a positive integer N and a string S of length N consisting of lowercase English letters.

Determine whether the string is a concatenation of two copies of some string.
That is, determine whether there is a string T such that S = T + T.

Constraints

1 \leq N \leq 100

S consists of lowercase English letters.

|S| = N

Input

Input is given from Standard Input in the following format:

N
S

Output

If S is a concatenation of two copies of some string, print Yes; otherwise, print No.

Sample Input 1

6
abcabc

Sample Output 1

Yes

Let T = abc, and S = T + T.

Sample Input 2

6
abcadc

Sample Output 2

No

Sample Input 3

1
z

Sample Output 3

No

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
int main(void){
  int n;
  scanf("%d",&n);
  char s[101];
  scanf("%s",s);
  int half=n/2;
  int flg=1;
  
  for(int i=0;i<half;i++){
    if(s[i]!=s[i+half])flg=0;
  }
  if(flg && n!=1 && n%2==0){
    printf("Yes\n");
  }else{
    printf("No\n");
  }
  return(0);
  
}