Problem:
Score : 200 points

Problem Statement

The word internationalization is sometimes abbreviated to i18n.
This comes from the fact that there are 18 letters between the first i and the last n.

You are given a string s of length at least 3 consisting of lowercase English letters.
Abbreviate s in the same way.

Constraints

3 ≤ |s| ≤ 100 (|s| denotes the length of s.)

s consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s

Output

Print the abbreviation of s.

Sample Input 1

internationalization

Sample Output 1

i18n

Sample Input 2

smiles

Sample Output 2

s4s

Sample Input 3

xyz

Sample Output 3

x1z

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
#include <string.h>

int main(void)
{
	char s[101] = {0};
	char n[256] = {0};
	char r[256] = {0};
	int len = 0;
	int sum = 0;

	scanf("%s", s);

	len = strlen(s);

	if (3 <= len && len <= 100) {
		int len_tmp = 0;
		sum = len - 2;
		sprintf(n, "%d", sum);
		r[0] = s[0];
		strncpy(&r[1], &n[0], strlen(n));
		len_tmp = strlen(r);
		r[len_tmp] = s[len - 1];
	}

	printf("%s\n", r);

	return 0;
}