Problem:
Score : 300 points

Problem Statement

Snuke has an integer sequence A of length N.

He will freely choose an integer b.
Here, he will get sad if A_i and b+i are far from each other.
More specifically, the sadness of Snuke is calculated as follows:

abs(A_1 - (b+1)) + abs(A_2 - (b+2)) + ... + abs(A_N - (b+N))

Here, abs(x) is a function that returns the absolute value of x.

Find the minimum possible sadness of Snuke.

Constraints

1 \leq N \leq 2 \times 10^5

1 \leq A_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

Print the minimum possible sadness of Snuke.

Sample Input 1

5
2 2 3 5 5

Sample Output 1

2

If we choose b=0, the sadness of Snuke would be abs(2-(0+1))+abs(2-(0+2))+abs(3-(0+3))+abs(5-(0+4))+abs(5-(0+5))=2.
Any choice of b does not make the sadness of Snuke less than 2, so the answer is 2.

Sample Input 2

9
1 2 3 4 5 6 7 8 9

Sample Output 2

0

Sample Input 3

6
6 5 4 3 2 1

Sample Output 3

18

Sample Input 4

7
1 1 1 1 2 3 4

Sample Output 4

6

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

/* Coached by rainboy */
#include <stdio.h>
#include <stdlib.h>

#define N 200000

int compare(const void *a, const void *b) {
	int ia = *(int *) a;
	int ib = *(int *) b;

	return ia - ib;
}

int main() {
	static int aa[N];
	int n, i, b, sadness;

	scanf("%d", &n);
	for (i = 0; i < n; i++) {
		scanf("%d", &aa[i]);
		aa[i] -= (i + 1);
	}
	qsort(aa, n, sizeof *aa, compare);
	b = aa[(n - 1) / 2];
	sadness = 0;
	for (i = 0; i < n; i++)
		sadness += abs(aa[i] - b);
	printf("%d\n", sadness);
	return 0;
}