Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
int main(void){
	int S[4];
	int a,n,dig;
	scanf("%d",&n);
	for(a=3;a>=0;a--){
		dig=n%10;
		S[a]=dig;
		n=n/10;
	}
	if(((S[0]==0)&&(S[1]==0))||((S[2]==0)&&(S[3]==0))){
		printf("NA");
	}else{
	if(S[0]*10+S[1]<=12){
		if(S[2]*10+S[3]<=12){
			printf("AMBIGUOUS");
		}else{
			printf("MMYY");
		}
	}else{
		if(S[2]*10+S[3]<=12){
			printf("YYMM");
		}else{
			printf("NA");
		}
	}
	}
return 0;
}