Problem:
Score : 500 points

Problem Statement

On a two-dimensional plane, there are m lines drawn parallel to the x axis, and n lines drawn parallel to the y axis.
Among the lines parallel to the x axis, the i-th from the bottom is represented by y = y_i.
Similarly, among the lines parallel to the y axis, the i-th from the left is represented by x = x_i.

For every rectangle that is formed by these lines, find its area, and print the total area modulo 10^9+7.

That is, for every quadruple (i,j,k,l) satisfying 1\leq i < j\leq n and 1\leq k < l\leq m, find the area of the rectangle formed by the lines x=x_i, x=x_j, y=y_k and y=y_l, and print the sum of these areas modulo 10^9+7.

Constraints

2 \leq n,m \leq 10^5

-10^9 \leq x_1 < ... < x_n \leq 10^9

-10^9 \leq y_1 < ... < y_m \leq 10^9

x_i and y_i are integers.

Input

Input is given from Standard Input in the following format:

n m
x_1 x_2 ... x_n
y_1 y_2 ... y_m

Output

Print the total area of the rectangles, modulo 10^9+7.

Sample Input 1

3 3
1 3 4
1 3 6

Sample Output 1

60

The following figure illustrates this input:

The total area of the nine rectangles A, B, ..., I shown in the following figure, is 60.

Sample Input 2

6 5
-790013317 -192321079 95834122 418379342 586260100 802780784
-253230108 193944314 363756450 712662868 735867677

Sample Output 2

835067060

Solution in C (GCC 5.4.1) (judge verdict: Runtime Error)

#include<stdio.h>
#include<stdlib.h>

#define DIV 1000000007

int main()
{
  int n,m,i,j,count;
  scanf("%d %d", &n, &m);
  long x[n];
  long y[m];
  for(i = 0; i < n; i++){
    scanf("%ld", &x[i]);
  }
  for(i = 0; i < m; i++){
    scanf("%ld", &y[i]);
  }
  count = 0;
  int x_num = n * (n-1) / 2;
  int y_num = m * (m-1) / 2;
  long x_sides[x_num];
  long y_sides[y_num];
  for(i = 0; i < n; i++){
    for(j = i+1; j < n; j++){
      x_sides[count] = labs(x[i] - x[j]);
      count++;
    }
  }
  count = 0;
  for(i = 0; i < n; i++){
    for(j = i+1; j < n; j++){
      y_sides[count] = labs(y[i] - y[j]);
      count++;
    }
  }
  long s = 0;
  for(i = 0; i < x_num; i++){
    for(j = 0; j < y_num; j++){
      s += x_sides[i] * y_sides[j];
    }
  }
  printf("%ld\n", (s % DIV));
  return 0;
}