Problem:
Score : 100 points

Problem Statement

Cat Snuke is learning to write characters.
Today, he practiced writing digits 1 and 9, but he did it the other way around.

You are given a three-digit integer n written by Snuke.
Print the integer obtained by replacing each digit 1 with 9 and each digit 9 with 1 in n.

Constraints

111 \leq n \leq 999

n is an integer consisting of digits 1 and 9.

Input

Input is given from Standard Input in the following format:

n

Output

Print the integer obtained by replacing each occurrence of 1 with 9 and each occurrence of 9 with 1 in n.

Sample Input 1

119

Sample Output 1

991

Replace the 9 in the ones place with 1, the 1 in the tens place with 9 and the 1 in the hundreds place with 9. The answer is 991.

Sample Input 2

999

Sample Output 2

111

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>

int main(){
    int n,a[3];
    scanf("%d",&n);
    a[0]=n/100;
    a[1]=(n-100*a[0])/10;
    a[2]=(n-100*a[0]-10*a[1]);
    
    for(int i = 0; i <3; i++)
    {
    if (a[i]==9) {a[i]=1;
    }else{
        
        if (a[i]==1) {
            a[i]=9;
        }
        
    }
    
    }
    printf("%d",100*a[0]+10*a[1]+a[2]);
    return 0;
}