Problem:
Score : 200 points

Problem Statement

Given are integers a,b,c and d.
If x and y are integers and a \leq x \leq b and c\leq y \leq d hold, what is the maximum possible value of x \times y?

Constraints

-10^9 \leq a \leq b \leq 10^9

-10^9 \leq c \leq d \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

a b c d

Output

Print the answer.

Sample Input 1

1 2 1 1

Sample Output 1

2

If x = 1 and y = 1 then x \times y = 1.
If x = 2 and y = 1 then x \times y = 2.
Therefore, the answer is 2.

Sample Input 2

3 5 -4 -2

Sample Output 2

-6

The answer can be negative.

Sample Input 3

-1000000000 0 -1000000000 0

Sample Output 3

1000000000000000000

Solution in C (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <stdio.h>
int main(){
    long long a, b, c, d;
    long long resp;

    scanf("%lld%lld%lld%lld", &a, &b, &c, &d);
    if(a >= 0 && b >= 0 && c >= 0 && d >= 0){
        if(a == b && c == d){
            resp = a * c;
        }else{
            resp = b * d;
        }
    }else if(a >= 0 && b >= 0 && c <= 0 && d <= 0){
            resp = a * d;
    }else if((a <= 0 && b <= 0)&&(c <= 0 && d <= 0)){
            resp = a * c;
    }else if((a <= 0 && b <= 0)&&(c >= 0 && d >= 0))
            resp = b * c;

    printf("%lld", resp);
    return 0;
}