Problem:
Score : 300 points

Problem Statement

You are given four integers A, B, C, and D. Find the number of integers between A and B (inclusive) that can be evenly divided by neither C nor D.

Constraints

1\leq A\leq B\leq 10^{18}

1\leq C,D\leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B C D

Output

Print the number of integers between A and B (inclusive) that can be evenly divided by neither C nor D.

Sample Input 1

4 9 2 3

Sample Output 1

2

5 and 7 satisfy the condition.

Sample Input 2

10 40 6 8

Sample Output 2

23

Sample Input 3

314159265358979323 846264338327950288 419716939 937510582

Sample Output 3

532105071133627368

Solution in C (GCC 5.4.1) (judge verdict: Runtime Error)

#include<stdio.h>
#include<math.h>
double x;
int N,M,i,sum,num,A[1001];
int main()
{

    scanf("%d %d",&N ,&M);
    for(i=1;i<=N;i++)
    {
        scanf("%d",& A[i]);
        sum=sum+A[i];
    }
    x=sum/(4.0*M);
    for(i=1;i<=N;i++)
    {
        if(A[i]>=x)
            num++;
    }
    if(num>=M)
    {
        printf("Yes\n");
    }
    else {
        printf("No\n");
    }
    return 0;
}