Problem:
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Matrix Multiplication

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\[
c_{ij} = \sum_{k=1}^m a_{ik}b_{kj}
\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Constraints

$1 \leq n, m, l \leq 100$

$0 \leq a_{ij}, b_{ij} \leq 10000$

Sample Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2

Sample Output

1 8 5
0 9 6
4 23 14

Note

      解説

Solution in C (judge verdict: Wrong Answer)

#include<stdio.h>
#include <stdlib.h>
int main(){
  
  int x,y,z,q,i,m,flg;
  unsigned long long int box1[101][101]={0};
  unsigned long long int box2[101][101]={0};
  unsigned long long int box3[101][101]={0};
  scanf("%d%d%d",&x,&y,&z);
  flg=0;
for(i=0;i<x;i++){
	for(q=0;q<y;q++){
		scanf("%d",&box1[i][q]);
		if(box1[i][q]>10000){flg=1;}
	}
}  
for(i=0;i<y;i++){
	for(q=0;q<z;q++){
		scanf("%d",&box2[i][q]);
		for(m=0;m<x;m++){
			box3[m][q] += box2[i][q]*box1[m][i];
			if(box2[i][q]>10000){flg=1;}
		}
		
	}
}
if(flg != 0){printf("Too Large\n");return 0;}
for(i=0;i<x;i++){
	for(q=0;q<z;q++){
		if(q==0){printf("%d",box3[i][q]);}
		else{printf(" %d",box3[i][q]);}
	}printf("\n");
}

  return 0;
}