Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>

int main() {
   int i,j,k,l,m,n;

   scanf("%d",&n);
   m=0;
   for (i=2;i<=n;i++) {
       l=0;
       for (j=i,k=2,l=0;j>1;)
           if (j%k==0) {
              l++;
              j/=k;
           } else k++;
      if (l==8) m++;
    }
    printf("%d\n",m);
    return 0;
}