Problem:
Score : 400 points

Problem Statement

Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.

You are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.

Constraints

2 ≦ |s| ≦ 10^5

s consists of lowercase letters.

Partial Score

200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.

Input

The input is given from Standard Input in the following format:

s

Output

If there exists no unbalanced substring of s, print -1 -1.

If there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.

Sample Input 1

needed

Sample Output 1

2 5

The string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.

Sample Input 2

atcoder

Sample Output 2

-1 -1

The string atcoder contains no unbalanced substring.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
#define MAX_S 100000

char s[MAX_S+1];

int main(){
    int n;
    scanf("%s", s);
    if (s[0]==s[1]) {
        printf("1 2\n");
        return 0;
    }
    for (n=0; s[n+2]!='\0'; n++){
        if (s[n]==s[n+1]){
            printf("%d %d\n", n+1, n+2);
            return 0;
        }
        if (s[n+1]==s[n+2]){
            printf("%d %d\n", n+2, n+3);
            return 0;
        }
        if (s[n]==s[n+2]){
            printf("%d %d\n", n+1, n+3);
            return 0;
        }
    }
    printf("-1 -1\n");
    return 0;
}