Problem:
Score : 200 points

Problem Statement

There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is R, and a blue hat if s_i is B.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

1 \leq N \leq 100

|s| = N

s_i is R or B.

Input

Input is given from Standard Input in the following format:

N
s

Output

If there are more people wearing a red hat than there are people wearing a blue hat, print Yes; otherwise, print No.

Sample Input 1

4
RRBR

Sample Output 1

Yes

There are three people wearing a red hat, and one person wearing a blue hat.

Since there are more people wearing a red hat than people wearing a blue hat, the answer is Yes.

Sample Input 2

4
BRBR

Sample Output 2

No

There are two people wearing a red hat, and two people wearing a blue hat.

Since there are as many people wearing a red hat as people wearing a blue hat, the answer is No.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>

void Red_or_Blue(int N) {
  char s[N+1];
  int red, blue;
  for (scanf("%s",s), red = 0, blue = 0; red+blue < N; red++, blue++) {
    if (s[red+blue] == 'R') {
      blue -= 1;
    } else {
      red -= 1;
    }
  }
  if (red > blue) {
    printf("Yes");
  } else {
    printf("No");
  }
}

int main(void) {
  int N;
  scanf("%d",&N);
  Red_or_Blue(N);
  return 0;
}