Problem:
Simultaneous Equation

Write a program which solve a simultaneous equation:

ax + by = c

dx + ey = f

The program should print x and y for given a, b, c, d, e and f (-1,000 ≤ a, b, c, d, e, f ≤ 1,000). You can suppose that given equation has a unique solution.

Input

The input consists of several data sets, 1 line for each data set. In a data set, there will be a, b, c, d, e, f separated by a single space. The input terminates with EOF.

Output

For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.

Sample Input 1

1 2 3 4 5 6
2 -1 -2 -1 -1 -5

Output for the Sample Input 1

-1.000 2.000
1.000 4.000

Sample Input 2

2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27

Output for the Sample Input 2

0.000 3.000
0.000 3.000

Solution in C (judge verdict: Time Limit Exceeded)

#include <stdio.h>
#include <string.h>

int main(void)
{
	int		 a,b, c,  d, e, f, ax, bx, cx, dx, ex, fx;
	int		aflag=0, dflag=0;
	int		gx, hx, ix, jx;
	float	x, y;
	scanf("%d %d %d %d %d %d",&a, &b, &c, &d, &e, &f ) ;

	if(a <0){			
		a= a*(-1);
		aflag=1;
	}
	if(d<0){			
		d= d*(-1);
		dflag=1;
	}
	ax = a;
	bx = b;
	cx = c;
	dx = d;
	ex = e;
	fx = f;	
	while(1){
		if(a > d){
			d = d+dx;
			e = e+ex;
			f = f+fx;
		}
		else if(d > a){
			a = a+ax;
			b = b+bx;
			c = c+cx;			
		}
		else{
			break;
		}	
	}

	if((aflag==1) &&(dflag==1) || (aflag==0) &&(dflag==0)){
		gx = b - e;
		hx = c - f;
	}
	else{
		gx = b + e;
		hx = c + f;	
	}
	x = hx / gx;
	y = c - a*x;
	printf("%.3f %.3f", x, y);
	return 0;
}