Problem:
Score : 200 points

Problem Statement

There is a square in the xy-plane. The coordinates of its four vertices are (x_1,y_1),(x_2,y_2),(x_3,y_3) and (x_4,y_4) in counter-clockwise order.
(Assume that the positive x-axis points right, and the positive y-axis points up.)

Takahashi remembers (x_1,y_1) and (x_2,y_2), but he has forgot (x_3,y_3) and (x_4,y_4).

Given x_1,x_2,y_1,y_2, restore x_3,y_3,x_4,y_4. It can be shown that x_3,y_3,x_4 and y_4 uniquely exist and have integer values.

Constraints

|x_1|,|y_1|,|x_2|,|y_2| \leq 100

(x_1,y_1) ≠ (x_2,y_2)

All values in input are integers.

Input

Input is given from Standard Input in the following format:

x_1 y_1 x_2 y_2

Output

Print x_3,y_3,x_4 and y_4 as integers, in this order.

Sample Input 1

0 0 0 1

Sample Output 1

-1 1 -1 0

(0,0),(0,1),(-1,1),(-1,0) is the four vertices of a square in counter-clockwise order.
Note that (x_3,y_3)=(1,1),(x_4,y_4)=(1,0) is not accepted, as the vertices are in clockwise order.

Sample Input 2

2 3 6 6

Sample Output 2

3 10 -1 7

Sample Input 3

31 -41 -59 26

Sample Output 3

-126 -64 -36 -131

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

/* ex7_1 
melo */
#include <stdio.h>
#include <math.h>
typedef struct{//構造体"point"
    double x_elem;//x座標
    double y_elem;//y座標
}point;
point square_point(point top1,point top2){//top2の隣の正方形の頂点を求める関数
    point top3;//もうひとつの頂点
    point deg45 ={cos(M_PI/4),sin(M_PI/4)};//半径１の円の45度の座標
    //45度回してsqrt(2)をかけた座標を求める
    top3.x_elem=sqrt(2)*(deg45.x_elem*(top2.x_elem-top1.x_elem)-deg45.y_elem*(top2.y_elem-top1.y_elem))+top1.x_elem;
    top3.y_elem=sqrt(2)*(deg45.x_elem*(top2.y_elem-top1.y_elem)+deg45.y_elem*(top2.x_elem-top1.x_elem))+top1.y_elem;
    return top3;//もうひとつの頂点を返す
}
int main(void){
    point top1,top2,top3,top4;//4頂点
    scanf("%lf %lf %lf %lf",&top1.x_elem,&top1.y_elem,&top2.x_elem,&top2.y_elem);//頂点1,2を入力する
    top3=square_point(top1,top2);//２の隣の頂点を求める
    top4=square_point(top2,top3);//3の隣の頂点を求める
    printf("%.0lf %.0lf %.0lf %.0lf\n",top3.x_elem,top3.y_elem,top4.x_elem,top4.y_elem);//頂点3,4の整数部を出力する
    return 0;//正常終了
}