Problem:
Score : 200 points

Problem Statement

A shop sells N kinds of fruits, Fruit 1, \ldots, N, at prices of p_1, \ldots, p_N yen per item, respectively. (Yen is the currency of Japan.)

Here, we will choose K kinds of fruits and buy one of each chosen kind. Find the minimum possible total price of those fruits.

Constraints

1 \leq K \leq N \leq 1000

1 \leq p_i \leq 1000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
p_1 p_2 \ldots p_N

Output

Print an integer representing the minimum possible total price of fruits.

Sample Input 1

5 3
50 100 80 120 80

Sample Output 1

210

This shop sells Fruit 1, 2, 3, 4, and 5 for 50 yen, 100 yen, 80 yen, 120 yen, and 80 yen, respectively.

The minimum total price for three kinds of fruits is 50 + 80 + 80 = 210 yen when choosing Fruit 1, 3, and 5.

Sample Input 2

1 1
1000

Sample Output 2

1000

Solution in C (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <stdio.h>
#include <stdlib.h>

int main(void){
    int n,k;
    int sum = 0;
    scanf("%d",&n);
    int a[n];
    int buf;
    scanf("%d",&k);

    for(int i= 0;i<n;i ++)scanf("%d",&a[i]);
    
    for(int i = 0;i < n;i++){
        for(int j = n-1;j >= i ;j--){
            if(a[j] < a[j-1]){
                buf = a[j];
                a[j] = a[j-1];
                a[j-1] = buf;
            }
        }
    }
    
    for(int i = 0;i<k;i++)sum += a[i];
    printf("%d",sum);

    return 0;
}