Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

#include<stdio.h>

int main(void){
    int n, i, j, x, a;

    scanf("%d", &n);

    a = 0;
    for(i=1; i<=n; i=i+2){
        x = 0;
        for(j=1; j<=i; j++){
            if(i%j == 0){
                x++;
            }
        }
        if(x == 8){
            a++;
        }
    }
    printf("%d\n", a);
}