Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
int main(void){
	int input1[9],i,j,N;
	for(i = 0; i < 9; i++){
		scanf("%d",&input1[i]);
	}
	scanf("%d",&N);
	int input2;
	int a[9];
	for(i = 0; i < N; i++){
		scanf("%d",&input2);
		for(j = 0;j < 9;j++){
			if(input2 == input1[j]){
				a[j] = 1;
				printf("a[%d] = %d\n",j,a[j]);
			}
		}
	} 
	
	if( (a[0] == a[1] && a[0] == a[2] && a[0] != 0) || (a[0] == a[4] && a[0] == a[8] && a[0] != 0) || (a[0] == a[3] && a[0] == a[6]  && a[0] != 0) || (a[1] == a[4] && a[1] == a[7] && a[1] != 0) || (a[2] == a[5] && a[2] == a[8] && a[2] != 0) || (a[3] == a[4] && a[3] == a[5] && a[3] != 0) ||(a[6] == a[7] && a[6] == a[8] && a[6] != 0) || a[2] == a[4] && a[2] == a[6] && a[2] != 0){
		puts("Yes");
	}else{
		puts("No");
	}
	
	
	return 0;
}