Problem:
Score : 100 points

Problem Statement

You have three tasks, all of which need to be completed.

First, you can complete any one task at cost 0.

Then, just after completing the i-th task, you can complete the j-th task at cost |A_j - A_i|.

Here, |x| denotes the absolute value of x.

Find the minimum total cost required to complete all the task.

Constraints

All values in input are integers.

1 \leq A_1, A_2, A_3 \leq 100

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

Print the minimum total cost required to complete all the task.

Sample Input 1

1 6 3

Sample Output 1

5

When the tasks are completed in the following order, the total cost will be 5, which is the minimum:

Complete the first task at cost 0.

Complete the third task at cost 2.

Complete the second task at cost 3.

Sample Input 2

11 5 5

Sample Output 2

6

Sample Input 3

100 100 100

Sample Output 3

0

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include"stdio.h"
#include"stdlib.h"

int min(int a,int b)
{
	if(a>b)
	return b;
	if(a==b)
	return a;
}
main()
{
	int A1,A2,A3;
	while(scanf("%d%d%d",&A1,&A2,&A3)!=EOF)
	{  
	    int mina,sum=0;
		mina=min(A1,min(A2,A3));
		if(mina==A1)
		sum=abs(A1-A2)+abs(A1-A3);
		else if(mina==A2)
		sum=abs(A2-A1)+abs(A2-A3);
		else if(mina==A3)
		sum=abs(A3-A2)+abs(A3-A1);
		printf("%d\n",sum);	
	}
}