Problem:
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Maximum Profit

You can obtain profits from foreign exchange margin transactions. For example, if you buy 1000 dollar at a rate of 100 yen per dollar, and sell them at a rate of 108 yen per dollar, you can obtain (108 - 100) × 1000 = 8000 yen.

Write a program which reads values of a currency $R_t$ at a certain time $t$ ($t = 0, 1, 2, ... n-1$), and reports the maximum value of $R_j - R_i$ where $j > i$ .

Input

The first line contains an integer $n$. In the following $n$ lines, $R_t$ ($t = 0, 1, 2, ... n-1$) are given in order.

Output

Print the maximum value in a line.

Constraints

$2 \leq n \leq 200,000$

$1 \leq R_t \leq 10^9$

Sample Input 1

6
5
3
1
3
4
3

Sample Output 1

3

Sample Input 2

3
4
3
2

Sample Output 2

-1

Solution in C (judge verdict: Time Limit Exceeded)

#include <stdio.h>

#define NMAX 200000
int main(){
   int i, j, n, max, R[NMAX];
   scanf("%d",&n);
   for(i=0;i<n;i++) scanf("%d",R+i);
   max=R[1]-R[0];
   for(i=0;i<n;i++){
      for(j=i+1;j<n;j++){
         if(R[j]-R[i]>max) max=R[j]-R[i];
      }
   }
   printf("%d\n",max);
   return 0;
}