Problem:
Score : 200 points

Problem Statement

Find the number of palindromic numbers among the integers between A and B (inclusive).
Here, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.

Constraints

10000 \leq A \leq B \leq 99999

All input values are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the number of palindromic numbers among the integers between A and B (inclusive).

Sample Input 1

11009 11332

Sample Output 1

4

There are four integers that satisfy the conditions: 11011, 11111, 11211 and 11311.

Sample Input 2

31415 92653

Sample Output 2

612

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
int main (){
int a,b,ans=0,i;
scanf ("%d%d",&a,&b);
  for (i=a;i<b+1;i++){
  if (a/10000 == a%10){
    if ((a-((a/10000)*10000))/1000 == (a-((a/1000)*1000))/10){
    ans++;
    }
  }
  }
  printf ("%d",ans);
return 0;
}