Problem:
Score : 200 points

Problem Statement

An integer N is a multiple of 9 if and only if the sum of the digits in the decimal representation of N is a multiple of 9.

Determine whether N is a multiple of 9.

Constraints

0 \leq N < 10^{200000}

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a multiple of 9, print Yes; otherwise, print No.

Sample Input 1

123456789

Sample Output 1

Yes

The sum of these digits is 1+2+3+4+5+6+7+8+9=45, which is a multiple of 9, so 123456789 is a multiple of 9.

Sample Input 2

0

Sample Output 2

Yes

Sample Input 3

31415926535897932384626433832795028841971693993751058209749445923078164062862089986280

Sample Output 3

No

Solution in C (GCC 9.2.1) (judge verdict: Runtime Error)

#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#include<math.h>

int main()
{
    long long int n ;
    scanf("%lld", &n)  ;
    char Num[n] ;
    sprintf(Num, "%lld", n);
    long int k = strlen(Num) ;
    long int t= atoi(Num)  ;
    long int sum = 0 ;
    for(long int i =0 ; i<k ; i++)
    {
        int p = t % 10 ;
        sum = sum + p ;
        t = t/10 ;

    }
    if (sum % 9 != 0)
    {
        printf("NO") ;
    }
    else
    {
        printf("Yes") ;
    }


}