Problem:
Score : 400 points

Problem Statement

Given is an integer S.
Find a combination of six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfies all of the following conditions:

0 \leq X_1,Y_1,X_2,Y_2,X_3,Y_3 \leq 10^9

The area of the triangle in a two-dimensional plane whose vertices are (X_1,Y_1),(X_2,Y_2), and (X_3,Y_3) is S/2.

We can prove that there always exist six integers that satisfy the conditions under the constraints of this problem.

Constraints

1 \leq S \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

S

Output

Print six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfy the conditions, in this order, with spaces in between.
If multiple solutions exist, any of them will be accepted.

Sample Input 1

3

Sample Output 1

1 0 2 2 0 1

The area of the triangle in a two-dimensional plane whose vertices are (1,0),(2,2), and (0,1) is 3/2.
Printing 3 0 3 1 0 1 or 1 0 0 1 2 2 will also be accepted.

Sample Input 2

100

Sample Output 2

0 0 10 0 0 10

Sample Input 3

311114770564041497

Sample Output 3

314159265 358979323 846264338 327950288 419716939 937510582

Solution in C (GCC 5.4.1) (judge verdict: Time Limit Exceeded)

#include<stdio.h>
#include <stdlib.h>

int main(void) {
	int a;
	scanf("%d", &a);
	int x1, x2, x3, y1, y2, y3;
	while (1) {
		for (x1 = 0; x1 < a; x1++) {
			for (x2 = 0; x2 < a; x2++) {
				for (x3 = 0; x3 < a; x3++) {
					for (y1 = 0; y1 < a; y1++) {
						for (y2 = 0; y2 < a; y2++) {
							for (y3 = 0; y3 < a; y3++) {
								if (abs((x1 - x3)*(y2 - y3) - (x2 - x3)*(y1 - y3)) == a) {
									printf("%d %d %d %d %d %d\n", x1, y1, x2, y2, x3, y3);
									goto owata;
								}
							}
						}
					}
				}
			}
		}
	}
owata:
	return 0;
}