Problem:
Score : 300 points

Problem Statement

You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

1 \leq |S| \leq 2 \times 10^5

|S| = |T|

S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S and T can be made equal, print Yes; otherwise, print No.

Sample Input 1

azzel
apple

Sample Output 1

Yes

azzel can be changed to apple, as follows:

Choose e as c_1 and l as c_2. azzel becomes azzle.

Choose z as c_1 and p as c_2. azzle becomes apple.

Sample Input 2

chokudai
redcoder

Sample Output 2

No

No sequences of operation can change chokudai to redcoder.

Sample Input 3

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu

Sample Output 3

Yes

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include "stdio.h"

int main(){
	char s[200001], t[200001];
	char rs[26], rt[26];
	scanf("%s\n", s);
	scanf("%s\n", t);
	for (int i = 0; i < 26; i++){
		rs[i] = -1;
		rt[i] = -1;
	}
	for (int i = 0; s[i]; i++){
		if (rs[s[i] - 'a'] < 0) {
			rs[s[i] - 'a'] = t[i];
		}
		else {
			if (rs[s[i] - 'a'] != t[i]) {
				printf("No\n");
				return 0;
			}
		}
		if (rs[t[i] - 'a'] < 0) {
			rs[t[i] - 'a'] = s[i];
		}
		else {
			if (rs[t[i] - 'a'] != s[i]) {
				printf("No\n");
				return 0;
			}
		}
	}
	printf("Yes\n");
}