Problem:
MathJax.Hub.Config({ tex2jax: { inlineMath: [["$","$"], ["\\(","\\)"]], processEscapes: true }});

Matrix Multiplication

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\[
c_{ij} = \sum_{k=1}^m a_{ik}b_{kj}
\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Constraints

$1 \leq n, m, l \leq 100$

$0 \leq a_{ij}, b_{ij} \leq 10000$

Sample Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2

Sample Output

1 8 5
0 9 6
4 23 14

Note

      解説

Solution in C (judge verdict: Wrong Answer)

#include <stdio.h>
int main(){
	int a[100][100], b[100][100];
	int n, m, l, x, y, z, ans;
	ans = 0;
	scanf("%d %d %d", &n, &m, &l);
	for(x = 0; x < n; x++){
		for(y = 0; y < m; y++){
			scanf("%d", &a[x][y]);
		}
	}
	for( x = 0; x < m; x++){
		for( y = 0; y < l; y++){
			scanf("%d", &b[x][y]);
		}
	}
	for(x = 0; x < n; x++){
		for(z = 0; z < l; z++){
			for(y = 0; y < m; y++){
				ans += a[x][y] * b[y][z];
			}
			printf("%d", ans);
			if(z != l-1){
				printf(" ");
			}
			ans = 0;
		}
		printf("\n");
	}
	
	return 0;
}