Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

int main()
{
    int N,C,A,i;
    scanf("%d",&N);
    C=0;
    A=0;
for(i=1;N>=i;i++)
{
    if(N%2!=0)
    {
        for(i=1;N>=i;i++)
        {
            if(N%i==0)
            {
                C++;
            }
        }
        if(C==8)
        {
            A++;
        }
        C=0;
    }
}

printf("%d",A);
    return 0;
}