Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in C (judge verdict: Time Limit Exceeded)

#include<stdio.h>

int main( void ) 
{
	char str[1201];
	int alphs[27]={0};
	int i;
	
	while( 1 ) {
		fgets( str, 1201, stdin);
	
		for( i=0; '\0'!=str[i]; i++ ) {
			if( 'A'<=str[i] && str[i]<='Z' ) {
				alphs[ str[i]-'A' ]++;
			} else if(  'a'<=str[i] && str[i]<='z'  ) {
				alphs[ str[i]-'a' ]++;
			} else {
				;
			}
		}
	}

	for( i=0; i<26; i++ ) {
		printf( "%c : %d\n", 'a'+i, alphs[i] );	
	}
	return 0;
}