Problem:
Score : 200 points

Problem Statement

In the beginning, Takahashi has A cookies, and Aoki has B cookies.
They will perform the following operation alternately, starting from Takahashi:

If the number of cookies in his hand is odd, eat one of those cookies; if the number is even, do nothing. Then, give one-half of the cookies in his hand to the other person.

Find the numbers of cookies Takahashi and Aoki respectively have after performing K operations in total.

Constraints

1 \leq A,B \leq 10^9

1 \leq K \leq 100

A,B and K are integers.

Input

Input is given from Standard Input in the following format:

A B K

Output

Print the number of cookies Takahashi has, and the number of cookies Aoki has, in this order, after performing K operations in total.

Sample Input 1

5 4 2

Sample Output 1

5 3

The process will go as follows:

In the beginning, Takahashi and Aoki have 5 and 4 cookies, respectively.

Takahashi eats one cookie and gives two cookies to Aoki. They now have 2 and 6 cookies, respectively.

Aoki gives three cookies to Takahashi. They now have 5 and 3 cookies, respectively.

Sample Input 2

3 3 3

Sample Output 2

1 3

Sample Input 3

314159265 358979323 84

Sample Output 3

448759046 224379523

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>

int main(void)
{
	int i,j,taka,aoki,times;
	int cnt = 0;
	
	scanf("%d %d %d",&taka,&aoki,&times);
	
	for(cnt = 1;cnt <= times; cnt++){
		if (cnt % 2 != 0){
			if (taka % 2 != 0){
				taka = taka--;
			}
			taka = taka / 2;
			aoki = aoki + taka;
		}
		else{
			if(aoki % 2 != 0){
				aoki = aoki--;
			}
			aoki = aoki / 2;
			taka = taka + aoki;
		}
	}
	
	printf("%d %d",taka,aoki);
	
	return 0;
}