Problem:
Score : 200 points

Problem Statement

There is a square in the xy-plane. The coordinates of its four vertices are (x_1,y_1),(x_2,y_2),(x_3,y_3) and (x_4,y_4) in counter-clockwise order.
(Assume that the positive x-axis points right, and the positive y-axis points up.)

Takahashi remembers (x_1,y_1) and (x_2,y_2), but he has forgot (x_3,y_3) and (x_4,y_4).

Given x_1,x_2,y_1,y_2, restore x_3,y_3,x_4,y_4. It can be shown that x_3,y_3,x_4 and y_4 uniquely exist and have integer values.

Constraints

|x_1|,|y_1|,|x_2|,|y_2| \leq 100

(x_1,y_1) ≠ (x_2,y_2)

All values in input are integers.

Input

Input is given from Standard Input in the following format:

x_1 y_1 x_2 y_2

Output

Print x_3,y_3,x_4 and y_4 as integers, in this order.

Sample Input 1

0 0 0 1

Sample Output 1

-1 1 -1 0

(0,0),(0,1),(-1,1),(-1,0) is the four vertices of a square in counter-clockwise order.
Note that (x_3,y_3)=(1,1),(x_4,y_4)=(1,0) is not accepted, as the vertices are in clockwise order.

Sample Input 2

2 3 6 6

Sample Output 2

3 10 -1 7

Sample Input 3

31 -41 -59 26

Sample Output 3

-126 -64 -36 -131

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

/*  ex7_1
    Acro   */
#include <stdio.h> 

typedef struct point
{
    int x_elem;
    int y_elem;
}point;
/* vec1を支点としてvec2を反時計回り90°回転させた点を返す*/
point shift_point(point vec1, point vec2)
{
    point new_vec;
    /* 支点の移動 */
    new_vec.x_elem = vec2.x_elem - vec1.x_elem;
    new_vec.y_elem = vec2.y_elem - vec1.y_elem;
    /* 回転 */
    new_vec.x_elem = new_vec.y_elem*(-1);
    /* new_vec.y_elem = new_vec.x_elem */
    new_vec.y_elem = vec2.x_elem - vec1.x_elem;
    /* 支点を戻す */
    new_vec.x_elem += vec1.x_elem;
    new_vec.y_elem += vec1.y_elem;

    return new_vec;
}

int main(void){
    point vec1,vec2,vec3,vec4;
    /* 入力 */
    scanf("%d %d %d %d",&vec1.x_elem,&vec1.y_elem,&vec2.x_elem,&vec2.y_elem);
    /* 順番に注意 */
    vec4 = shift_point(vec1,vec2);
    vec3 = shift_point(vec4,vec1);
    /* 出力 */
    printf("%d %d %d %d\n",vec3.x_elem, vec3.y_elem, vec4.x_elem, vec4.y_elem);
    return 0;
}