Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in C (judge verdict: Time Limit Exceeded)

#include <stdio.h>


int main(void)
{
	char word[1201];
	int alphabet[26] = {0};
	int i;

	while(scanf("%[^\n]", word)!=EOF){

		for(i=0;word[i]!='\0';i++){
			if('A'<=word[i] && word[i]<='Z')
				alphabet[word[i]-'A']++;
			if('a'<=word[i] && word[i]<='z')
				alphabet[word[i]-'a']++;
		}
	}

	for(i=0;i<26;i++)
		printf("%c : %d\n", 'a'+i, alphabet[i]);

	return 0;
}