Problem:
Score : 100 points

Problem Statement

You have three tasks, all of which need to be completed.

First, you can complete any one task at cost 0.

Then, just after completing the i-th task, you can complete the j-th task at cost |A_j - A_i|.

Here, |x| denotes the absolute value of x.

Find the minimum total cost required to complete all the task.

Constraints

All values in input are integers.

1 \leq A_1, A_2, A_3 \leq 100

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

Print the minimum total cost required to complete all the task.

Sample Input 1

1 6 3

Sample Output 1

5

When the tasks are completed in the following order, the total cost will be 5, which is the minimum:

Complete the first task at cost 0.

Complete the third task at cost 2.

Complete the second task at cost 3.

Sample Input 2

11 5 5

Sample Output 2

6

Sample Input 3

100 100 100

Sample Output 3

0

Solution in C (Clang 3.8.0) (judge verdict: Wrong Answer)

// Ver19.02
#include <math.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#define INF 1 << 29
#define LLINF 4545454545454545454
#define MOD 1000000007
#define ll long long
#define MAX(a, b) ((a) > (b) ? (a) : (b))
#define MIN(a, b) ((a) < (b) ? (a) : (b))
int upll(const void *a, const void *b) { return *(ll *)a < *(ll *)b ? -1 : *(ll *)a > *(ll *)b ? 1 : 0; }
int downll(const void *a, const void *b) { return *(ll *)a < *(ll *)b ? 1 : *(ll *)a > *(ll *)b ? -1 : 0; }
void sortup(ll *a, int n) { qsort(a, n, sizeof(ll), upll); }
void sortdown(ll *a, int n) { qsort(a, n, sizeof(ll), downll); }

int main()
{
  char s[200], ss[200], t[200];
  scanf("%s%s", s, t);
  for (int j = 0; j <= strlen(s) - 1; j++)
  {
    for (int i = 0; i < strlen(s); i++)
    {
      ss[i] = s[(i + j) % strlen(s)];
    }
    if (strcmp(ss, t) == 0)
    {
      puts("Yes");
      return 0;
    }
  }
  puts("No");
  return 0;
}