Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>

int main(){
  int f_half,l_half;
  char s[4];
  
  scanf("%s",s);
  
  f_half=(s[0]-'0')*10+(s[1]-'0');
  l_half=(s[2]-'0')*10+(s[3]-'0');
  
  if((f_half==0 && l_half==0)||(f_half>12 && l_half>12)){
    printf("NA");
  } else if(f_half<=12 && l_half<=12){
    printf("AMBIGUOUS");
  } else if(f_half<=12 && l_half>12){
    printf("MMYY");
  } else if(f_half>12 && l_half<=12){
    printf("YYMM");
  }
}