Problem:
Score : 200 points

Problem Statement

Given are a positive integer N and a string S of length N consisting of lowercase English letters.

Determine whether the string is a concatenation of two copies of some string.
That is, determine whether there is a string T such that S = T + T.

Constraints

1 \leq N \leq 100

S consists of lowercase English letters.

|S| = N

Input

Input is given from Standard Input in the following format:

N
S

Output

If S is a concatenation of two copies of some string, print Yes; otherwise, print No.

Sample Input 1

6
abcabc

Sample Output 1

Yes

Let T = abc, and S = T + T.

Sample Input 2

6
abcadc

Sample Output 2

No

Sample Input 3

1
z

Sample Output 3

No

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>

int main(void)
{
	int n;
	char str[100], t;
	scanf("%d%*c", &n);
	if(n < 2 || n%2 == 1) {
		printf("No");
		return 0;
	}

	for(int i=0;i<n/2;i++) {
		scanf("%c", &str[i]);
	}
	for(int i=0;i<n/2;i++) {
		scanf("%c", &t);
		if(str[i] != t) {
			printf("No");
			return 0;
		}
	}

	printf("Yes");

	return 0;
}