Problem:
Score : 700 points

Problem Statement

You are given four integers: H, W, h and w (1 ≤ h ≤ H, 1 ≤ w ≤ W).
Determine whether there exists a matrix such that all of the following conditions are held, and construct one such matrix if the answer is positive:

The matrix has H rows and W columns.

Each element of the matrix is an integer between -10^9 and 10^9 (inclusive).

The sum of all the elements of the matrix is positive.

The sum of all the elements within every subrectangle with h rows and w columns in the matrix is negative.

Constraints

1 ≤ h ≤ H ≤ 500

1 ≤ w ≤ W ≤ 500

Input

Input is given from Standard Input in the following format:

H W h w

Output

If there does not exist a matrix that satisfies all of the conditions, print No.

Otherwise, print Yes in the first line, and print a matrix in the subsequent lines in the following format:

a_{11} ... a_{1W}
:
a_{H1} ... a_{HW}

Here, a_{ij} represents the (i,\ j) element of the matrix.

Sample Input 1

3 3 2 2

Sample Output 1

Yes
1 1 1
1 -4 1
1 1 1

The sum of all the elements of this matrix is 4, which is positive.
Also, in this matrix, there are four subrectangles with 2 rows and 2 columns as shown below. For each of them, the sum of all the elements inside is -1, which is negative.

Sample Input 2

2 4 1 2

Sample Output 2

No

Sample Input 3

3 4 2 3

Sample Output 3

Yes
2 -5 8 7
3 -5 -4 -5
2 1 -1 7

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
#define mc 999999999
#define pc -1000000000

int main(){
  long long i,j,h,w,sh,sw,v,t=0,p,q;
  long long arr[512][512]={0};
  scanf("%lld%lld%lld%lld",&h,&w,&sh,&sw);
  if(h==sh && w==sw){
    printf("No\n");return 0;
  }
  v=-(sh*sw);
  for(i=1;i<=h;i++){
    for(j=1;j<=w;j++){
      p=i%sh;
      if(p==0){p=sh;}
      q=j%sw;
      if(q==0){q=sw;}
      if(p==1 && q==1){
        arr[i][j]=mc;
        t+=mc;
      }
      else if(p==sh && q==sw){
        arr[i][j]=pc;
        t+=pc;
      }
      else{arr[i][j]=0;}
    }
  }
  if(t<=0){printf("No\n");return 0;}
  printf("Yes\n");
  for(i=1;i<=h;i++){
    for(j=1;j<=w;j++){
      if(j!=1){printf(" ");}
      printf("%lld",arr[i][j]);
    }
    printf("\n");
  }
  return 0;
}