Problem:
Score : 100 points

Problem Statement

In AtCoder City, there are three stations numbered 1, 2, and 3.

Each of these stations is operated by one of the two railway companies, A and B. A string S of length 3 represents which company operates each station. If S_i is A, Company A operates Station i; if S_i is B, Company B operates Station i.

To improve the transportation condition, for each pair of a station operated by Company A and one operated by Company B, there will be a bus service connecting them.

Determine if there is a pair of stations that will be connected by a bus service.

Constraints

Each character of S is A or B.

|S| = 3

Input

Input is given from Standard Input in the following format:

S

Output

If there is a pair of stations that will be connected by a bus service, print Yes; otherwise, print No.

Sample Input 1

ABA

Sample Output 1

Yes

Company A operates Station 1 and 3, while Company B operates Station 2.

There will be a bus service between Station 1 and 2, and between Station 2 and 3, so print Yes.

Sample Input 2

BBA

Sample Output 2

Yes

Company B operates Station 1 and 2, while Company A operates Station 3.

There will be a bus service between Station 1 and 3, and between Station 2 and 3, so print Yes.

Sample Input 3

BBB

Sample Output 3

No

Company B operates all the stations. Thus, there will be no bus service, so print No.

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>

int main(){
    char s[5];



    scanf("%s",s);

    if((s[0]=='A') && (s[1]=='B') && (s[2]!='A'))
        printf("Yes\n");
    else if((s[0]=='B') && (s[1]=='A') && (s[2]=='A'))
        printf("Yes\n");
    else if((s[0]=='A') && (s[1]=='A') && (s[2]=='B'))
        printf("Yes\n");
    else if((s[0]=='B') && (s[1]=='A') && (s[2]=='B'))
        printf("Yes\n");
    else if((s[0]=='A') && (s[1]=='B') && (s[2]=='B'))
        printf("Yes\n");
    else if((s[0]=='B') && (s[1]=='B') && (s[2]=='A'))
        printf("Yes\n");



    else if(((s[0]=='B')&& (s[1]=='B') && (s[2]=='B'))||((s[0]=='A') && (s[1]=='A') && (s[2]=='A')))
            printf("No\n");

    return 0;
}