Problem:
Score : 200 points

Problem Statement

The word internationalization is sometimes abbreviated to i18n.
This comes from the fact that there are 18 letters between the first i and the last n.

You are given a string s of length at least 3 consisting of lowercase English letters.
Abbreviate s in the same way.

Constraints

3 ≤ |s| ≤ 100 (|s| denotes the length of s.)

s consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s

Output

Print the abbreviation of s.

Sample Input 1

internationalization

Sample Output 1

i18n

Sample Input 2

smiles

Sample Output 2

s4s

Sample Input 3

xyz

Sample Output 3

x1z

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>

int main()
{
 char st[105];
 int i, midchar;
 int charcount=0;

 for(i=0; i<100; i++)
 {
  scanf("%c",&st[i]);
  if((st[i]<'a')|(st[i]>'z')) break;
  charcount++;
 }

 midchar=charcount-2;
 printf("%c%d%c\n",st[0],midchar,st[charcount-1]);
return 0;
}