Problem:
Score : 200 points

Problem Statement

There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is R, and a blue hat if s_i is B.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

1 \leq N \leq 100

|s| = N

s_i is R or B.

Input

Input is given from Standard Input in the following format:

N
s

Output

If there are more people wearing a red hat than there are people wearing a blue hat, print Yes; otherwise, print No.

Sample Input 1

4
RRBR

Sample Output 1

Yes

There are three people wearing a red hat, and one person wearing a blue hat.

Since there are more people wearing a red hat than people wearing a blue hat, the answer is Yes.

Sample Input 2

4
BRBR

Sample Output 2

No

There are two people wearing a red hat, and two people wearing a blue hat.

Since there are as many people wearing a red hat as people wearing a blue hat, the answer is No.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>

int main(void)
{
	int n,i,cntR=0,cntB=0;
	char s[100];
	
	scanf("%d",&n);
	scanf("%s",s);
	
	i=0;
	while(s[i] != '\0'){
		//printf("%c\n",s[i]);
		if(s[i] == 'R'){
			cntR++;
		}else if(s[i] == 'B'){
			cntB++;
		}
		i++;
	}
	if(cntR > cntB){
		printf("Yes\n");
	}else{
		printf("No\n");
	}
		
	return 0;
}