Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#define eps 0.00000000001

int main()
{
    int N;
    int h,n,w;
    scanf("%d",&N);
    for(h=1; h<=3500; h++)
    {
        for(n=1; n<=3500; n++)
        {
            w=1/((double)4/N-(double)1/h-(double)1/n);
            if(w>0&&w<3500&&fabs((double)4/N-(double)1/h-(double)1/n-(double)1/w)<=eps)
                printf("%d %d %d\n",h,n,w);
        }
    }

    return 0;
}