Problem:
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Matrix Multiplication

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\[
c_{ij} = \sum_{k=1}^m a_{ik}b_{kj}
\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Constraints

$1 \leq n, m, l \leq 100$

$0 \leq a_{ij}, b_{ij} \leq 10000$

Sample Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2

Sample Output

1 8 5
0 9 6
4 23 14

Note

      解説

Solution in C (judge verdict: Wrong Answer)

#include <stdio.h>

int main(void)
{
	int n, m, l;
	int i, j, k, sum;
	int a[100][100], b[100][100];


	scanf("%d %d %d", &n, &m, &l);

	for(i=0;i<n;i++){
		for(j=0;j<m;j++)
			scanf("%d", &a[i][j]);
	}

	for(i=0;i<m;i++){
		for(j=0;j<l;j++)
			scanf("%d", &b[i][j]);
	}


	for(i=0;i<n;i++){
		for(j=0;j<l;j++){
			sum = 0;
			for(k=0;k<m;k++)
				sum += a[i][k] * b[k][j];
			if(j==l-1)
				printf("%d", sum);
			else
				printf("%d ", sum);
		}
		printf("\n");
	}

	return 0;
}