Problem:
Score : 300 points

Problem Statement

A company has N members, who are assigned ID numbers 1, ..., N.

Every member, except the member numbered 1, has exactly one immediate boss with a smaller ID number.

When a person X is the immediate boss of a person Y, the person Y is said to be an immediate subordinate of the person X.

You are given the information that the immediate boss of the member numbered i is the member numbered A_i. For each member, find how many immediate subordinates it has.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq A_i < i

Input

Input is given from Standard Input in the following format:

N
A_2 ... A_N

Output

For each of the members numbered 1, 2, ..., N, print the number of immediate subordinates it has, in its own line.

Sample Input 1

5
1 1 2 2

Sample Output 1

2
2
0
0
0

The member numbered 1 has two immediate subordinates: the members numbered 2 and 3.

The member numbered 2 has two immediate subordinates: the members numbered 4 and 5.

The members numbered 3, 4, and 5 do not have immediate subordinates.

Sample Input 2

10
1 1 1 1 1 1 1 1 1

Sample Output 2

9
0
0
0
0
0
0
0
0
0

Sample Input 3

7
1 2 3 4 5 6

Sample Output 3

1
1
1
1
1
1
0

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

#include<stdio.h>
int main()
{
  int n,i;
  scanf("%d", &n);
 
  int a[n],b[n];
  
  for(i=0;i<=n;i++)
  {b[i]=0;a[i]=0;}
  
  for(i=1;i<n;i++)
  {
   scanf("%d",&a[i]); 
  }
  
  //for(i=0;i<=n;i++)
  //{printf("%d ",a[i]);}
  //printf("\n");

  for(i=1;i<=n;i++)
  {
  	b[a[i]-1]=b[a[i]-1]+1;
  }
  
  for(i=0;i<n;i++)
  {
  	printf("%d\n",b[i]);
  }
  return 0;
}