Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>

int main(){
  char S[4];
  int i[4];
  scanf("%s",S);
  i[0] = S[0] - '0';
  i[1] = S[1] - '0';
  i[2] = S[2] - '0';
  i[3] = S[3] - '0';
  
  int i1,i2;
  i1 = i[0] * 10 + i[1];
  i2 = i[2] * 10 + i[3];
  
  //最初の文字を調べる
  if(i1 > 12 && i1 <= 19){	//YYMM可能性
    if(i2 > 0 && i2 <= 12){
      printf("YYMM\n");
    }else{
      printf("NA\n");
    }
  }else if(i1 > 0 && i1 <= 12){	//MMYY可能性
    if(i2 > 0 && i2 <= 12){
      printf("AMBIGUOUS\n");
    }else if(i2 > 12 && i2 <= 19){
      printf("MMYY\n");
    }
  }else{
    printf("NA\n");
  }
  
  
  return 0;
}