Problem:
Score : 300 points

Problem Statement

There are N people living on a number line.

The i-th person lives at coordinate X_i.

You are going to hold a meeting that all N people have to attend.

The meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.

Find the minimum total points of stamina the N people have to spend.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq X_i \leq 100

Input

Input is given from Standard Input in the following format:

N
X_1 X_2 ... X_N

Output

Print the minimum total stamina the N people have to spend.

Sample Input 1

2
1 4

Sample Output 1

5

Assume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.

Note that you can hold the meeting only at an integer coordinate.

Sample Input 2

7
14 14 2 13 56 2 37

Sample Output 2

2354

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
int main()
{
    int n,k,a[100],sum=0,sum1=0,i,b,min,max,min1;
    scanf("%d",&n);
    for(i=0;i<n;i++)
    {
        scanf("%d",&a[i]);
        sum+=a[i];
    }
    for(i=1,min=max=0;i<n;i++)
    {
        if(a[i]<a[min])
            min=i;
        if(a[i]>a[max])
            max=i;
    }
    for(i=a[min];i<=a[max];i++)
    {
        if(i==a[min])
            min1=n*i*i-2*i*sum;
        b=n*i*i-2*i*sum;
        if(b<min1)
            min1=b;
    }
    for(i=0;i<n;i++)
    {
        sum1+=a[i]*a[i];
    }
    printf("%d",sum1+min1);
}