Problem:
Score : 300 points

Problem Statement

Snuke has an integer sequence A of length N.

He will freely choose an integer b.
Here, he will get sad if A_i and b+i are far from each other.
More specifically, the sadness of Snuke is calculated as follows:

abs(A_1 - (b+1)) + abs(A_2 - (b+2)) + ... + abs(A_N - (b+N))

Here, abs(x) is a function that returns the absolute value of x.

Find the minimum possible sadness of Snuke.

Constraints

1 \leq N \leq 2 \times 10^5

1 \leq A_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

Print the minimum possible sadness of Snuke.

Sample Input 1

5
2 2 3 5 5

Sample Output 1

2

If we choose b=0, the sadness of Snuke would be abs(2-(0+1))+abs(2-(0+2))+abs(3-(0+3))+abs(5-(0+4))+abs(5-(0+5))=2.
Any choice of b does not make the sadness of Snuke less than 2, so the answer is 2.

Sample Input 2

9
1 2 3 4 5 6 7 8 9

Sample Output 2

0

Sample Input 3

6
6 5 4 3 2 1

Sample Output 3

18

Sample Input 4

7
1 1 1 1 2 3 4

Sample Output 4

6

Solution in C (GCC 5.4.1) (judge verdict: Runtime Error)

#include <stdio.h>

int main()
{
	int n, a[100], abs=0, ans;
	
	scanf("%d", &n);
	
	int i;
	for(i=0; i<n; i++) {
		scanf("%d", &a[i]);
		abs += a[i]-i-1;
	}
	
	ans = abs%n;	
	int b;
	if(ans<0) {
		if(ans+n <= -ans) b = abs/n;
		else b = (abs)/n -1;
	} else {
		if(-ans+n >= ans) b = abs/n;
		else b= (abs+1)/n ;
	}
	
  
	ans =0;
	for(i=0; i<n; i++) {
		abs = a[i]-(b+(i+1));
		if(abs<0) ans-=abs;
		else ans+=abs;
	}
	
	printf("%d", ans);
	
	return 0;
	
}