Problem:
Score : 300 points

Problem Statement

There are N people living on a number line.

The i-th person lives at coordinate X_i.

You are going to hold a meeting that all N people have to attend.

The meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.

Find the minimum total points of stamina the N people have to spend.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq X_i \leq 100

Input

Input is given from Standard Input in the following format:

N
X_1 X_2 ... X_N

Output

Print the minimum total stamina the N people have to spend.

Sample Input 1

2
1 4

Sample Output 1

5

Assume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.

Note that you can hold the meeting only at an integer coordinate.

Sample Input 2

7
14 14 2 13 56 2 37

Sample Output 2

2354

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
int main()
{
    int i,j,n,max=0,summin=100000000,min=101,sum;
    scanf("%d",&n);
    int a[n];
    for(i=0; i<n; i++)
    {
        scanf("%d",&a[i]);
        if(max<a[i])
            max=a[i];
        if(min>a[i])
            min=a[i];
    }
    for(i=min; i<=max; i++)
    {
        sum=0;
        for(j=0; j<n; j++)
        {
            sum=sum+(i-a[j])*(i-a[j]);
        }
        if(summin>sum)
            summin=sum;
    }
    printf("%d",summin);
    return 0;
}