Problem:
Score : 100 points

Problem Statement

You have three tasks, all of which need to be completed.

First, you can complete any one task at cost 0.

Then, just after completing the i-th task, you can complete the j-th task at cost |A_j - A_i|.

Here, |x| denotes the absolute value of x.

Find the minimum total cost required to complete all the task.

Constraints

All values in input are integers.

1 \leq A_1, A_2, A_3 \leq 100

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

Print the minimum total cost required to complete all the task.

Sample Input 1

1 6 3

Sample Output 1

5

When the tasks are completed in the following order, the total cost will be 5, which is the minimum:

Complete the first task at cost 0.

Complete the third task at cost 2.

Complete the second task at cost 3.

Sample Input 2

11 5 5

Sample Output 2

6

Sample Input 3

100 100 100

Sample Output 3

0

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

#include<stdio.h>

int main(void){
  int number[3];
  scanf("%d %d %d",&number[0],&number[1],&number[2]);
  int tmp;
  for (int i=0; i<3; ++i) {
    for (int j=i+1; j<3; ++j) {
      if (number[i] > number[j]) {
        tmp =  number[i];
        number[i] = number[j];
        number[j] = tmp;
      }
    }
  }
  
  printf("%d\n",number[2]-number[0]);
  return 0;
}