Problem:
Score : 300 points

Problem Statement

A company has N members, who are assigned ID numbers 1, ..., N.

Every member, except the member numbered 1, has exactly one immediate boss with a smaller ID number.

When a person X is the immediate boss of a person Y, the person Y is said to be an immediate subordinate of the person X.

You are given the information that the immediate boss of the member numbered i is the member numbered A_i. For each member, find how many immediate subordinates it has.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq A_i < i

Input

Input is given from Standard Input in the following format:

N
A_2 ... A_N

Output

For each of the members numbered 1, 2, ..., N, print the number of immediate subordinates it has, in its own line.

Sample Input 1

5
1 1 2 2

Sample Output 1

2
2
0
0
0

The member numbered 1 has two immediate subordinates: the members numbered 2 and 3.

The member numbered 2 has two immediate subordinates: the members numbered 4 and 5.

The members numbered 3, 4, and 5 do not have immediate subordinates.

Sample Input 2

10
1 1 1 1 1 1 1 1 1

Sample Output 2

9
0
0
0
0
0
0
0
0
0

Sample Input 3

7
1 2 3 4 5 6

Sample Output 3

1
1
1
1
1
1
0

Solution in C (GCC 9.2.1) (judge verdict: Runtime Error)

#include <stdio.h>
 
int main(void) {
 
	int N;
	int A[20000];
	int result[20000];
 
 
	// 社員数を入力
	scanf("%d", &N);
 
	// resultを初期化
	for (int i = 1; i <= N; i++) {
		result[i] = 0;
	}
 
	// Aの値を配列に入力
	for (int i = 1; i < N; i++) {
		scanf("%d", &A[i]);
	}
  
  	for(int i = 1; i < N; i++){
      result[A[i]]++;
    }
 
 
	//　直属の部下の人数を改行区切りで出力
	for (int i = 1; i <= N; i++) {
		printf("%d\n", result[i]);
	}
 
	return 0;
}