Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

#include <stdio.h>
#include <stdlib.h>
int A[4][4], S[4][4];
int N;
int B[11], check[8];

void checkup(int a, int b){
	if(a == 0 && b == 0){
		check[0]++;
		check[3]++;
		check[6]++;
	}
	if(a == 0 && b == 1){
			check[0]++;
			check[4]++;
			//check[6]++;
	}
	if(a == 0 && b == 2){
			check[0]++;
			check[5]++;
			check[7]++;
	}

	if(a ==1 && b == 0){
			check[1]++;
			check[3]++;
			//check[6]++;
	}
	if(a == 1 && b == 1){
			check[1]++;
			check[4]++;
			check[6]++;
			check[7]++;
	}
	if(a == 1 && b == 2){
			check[1]++;
			check[5]++;
			//check[7]++;
	}

	if(a == 2 && b == 0){
			check[2]++;
			check[3]++;
			check[7]++;
	}
	if(a == 2 && b == 1){
			check[2]++;
			check[4]++;
			//check[6]++;
		}
	if(a == 2 && b == 2){
			check[2]++;
			check[5]++;
			check[6]++;
	}


}

int main(void) {

	for(int a = 0; a < 3; a++){
		for(int b = 0; b < 3; b++){
			scanf("%d", &A[a][b]);
		}
	}
	scanf("%d", &N);
	for(int a = 0; a < N; a++){
		scanf("%d", &B[a]);
	}

	for(int k = 0; k < N; k++){
		for(int a = 0; a < 3; a++){
				for(int b = 0; b < 3; b++){
					if(B[k] == A[a][b]){
						checkup(a, b);
					}
				}
			}

	}
	int i = 0;
	while(i < 8){
		if(check[i] >= 3){
			printf("Yes");
			break;
		}
		i++;
	}

	if(i == 8)printf("No");

	return 0;
}