Problem:
Score : 100 points

Problem Statement

A balance scale tips to the left if L>R, where L is the total weight of the masses on the left pan and R is the total weight of the masses on the right pan. Similarly, it balances if L=R, and tips to the right if L<R.

Takahashi placed a mass of weight A and a mass of weight B on the left pan of a balance scale, and placed a mass of weight C and a mass of weight D on the right pan.

Print Left if the balance scale tips to the left; print Balanced if it balances; print Right if it tips to the right.

Constraints

1\leq A,B,C,D \leq 10

All input values are integers.

Input

Input is given from Standard Input in the following format:

A B C D

Output

Print Left if the balance scale tips to the left; print Balanced if it balances; print Right if it tips to the right.

Sample Input 1

3 8 7 1

Sample Output 1

Left

The total weight of the masses on the left pan is 11, and the total weight of the masses on the right pan is 8. Since 11>8, we should print Left.

Sample Input 2

3 4 5 2

Sample Output 2

Balanced

The total weight of the masses on the left pan is 7, and the total weight of the masses on the right pan is 7. Since 7=7, we should print Balanced.

Sample Input 3

1 7 6 4

Sample Output 3

Right

The total weight of the masses on the left pan is 8, and the total weight of the masses on the right pan is 10. Since 8<10, we should print Right.

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
int main(void){

	int a, b, c, sum=0, i;
	int num;
	scanf("%d%d%d", &a, &b, &c);
	
	for(i=1; i<=a; i++){
		num = 0;
		if(i < 10)
			num = i;
		else if(i >= 10 && i < 100)
			num = (i/10) + (i%10);
		else if(i >=100 && i < 1000)
			num = i/100 + (i%100)/10  + ((i%100)%10);
		else if(i >= 1000 && i < 10000)
			num = i/1000 + (i%1000)/100 + ((i%1000)%100)/10 + ((i%1000)%100)%10;
		if(num >= b && num <= c){
			sum += i;
		}
	}
	printf("%d", sum);
	return 0;
}