Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>

int main(){
    int a, b=0, c=0;
    scanf("%d", &a);
    
    if (a<105){
        b = 0;
    } else {
        for(int i=1; i<=a;i++){        
            if(i%2 == 0)
                continue;
            
            c = 0;
        
            for(int j=1;j<=i;j++){
                if(i%j==0)
                    c++;
                if (c>8)
                    break;
            }
        
            if (c==8)
                b++;
        }
    }
    
    printf("%d\n", b);
    
    return 0;
    
}