Problem:
Score : 200 points

Problem Statement

You are given string S and T consisting of lowercase English letters.

Determine if S equals T after rotation.

That is, determine if S equals T after the following operation is performed some number of times:

Operation: Let S = S_1 S_2 ... S_{|S|}. Change S to S_{|S|} S_1 S_2 ... S_{|S|-1}.

Here, |X| denotes the length of the string X.

Constraints

2 \leq |S| \leq 100

|S| = |T|

S and T consist of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S equals T after rotation, print Yes; if it does not, print No.

Sample Input 1

kyoto
tokyo

Sample Output 1

Yes

In the first operation, kyoto becomes okyot.

In the second operation, okyot becomes tokyo.

Sample Input 2

abc
arc

Sample Output 2

No

abc does not equal arc after any number of operations.

Sample Input 3

aaaaaaaaaaaaaaab
aaaaaaaaaaaaaaab

Sample Output 3

Yes

Solution in C (GCC 9.2.1) (judge verdict: Wrong Answer)

#include<stdio.h>
#include<string.h>
int main(void)
{
	int i,j,c;
	char s[100],t[100],a[1];
	scanf("%s %s",s,t);
	  c=0;
  		 for(j=0;j<strlen(s);j++){
				if(s[j] == t[j]) c++;
		 }
  		 if(c == strlen(s)) printf("Yes\n");
  	  c=0;  
  		for(i=0;i<strlen(s);i++){
			for(j=0;j<strlen(s+1*i);j++){
				a[1]=s[j];
				s[j]=s[j+1];
          		s[j+1]=a[1];
			}
          	printf("%s\n",s);
      	  		for(j=0;j<strlen(s);j++){
				if(s[j] == t[j]) c++;
				}
   			if(i == strlen(s) && c != strlen(s)) printf("No\n");
       	 }
  		if(c == strlen(s)) printf("Yes\n");
	return 0;
}