Problem:
Score : 200 points

Problem Statement

The word internationalization is sometimes abbreviated to i18n.
This comes from the fact that there are 18 letters between the first i and the last n.

You are given a string s of length at least 3 consisting of lowercase English letters.
Abbreviate s in the same way.

Constraints

3 ≤ |s| ≤ 100 (|s| denotes the length of s.)

s consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s

Output

Print the abbreviation of s.

Sample Input 1

internationalization

Sample Output 1

i18n

Sample Input 2

smiles

Sample Output 2

s4s

Sample Input 3

xyz

Sample Output 3

x1z

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

/* ex_6-2. nknm */

#include <stdio.h>
#include <string.h>

int main(void){
    
    int word_num, i;
    char imput[100];

    scanf("%s", imput);     //文字列を入力

    word_num = strlen(imput);       //文字数を計算

    printf("%c%d%c\n", imput[0], word_num - 2, imput[word_num - 1]);        //頭文字、(文字数-2)、最後の文字を出力

    return 0;
}