Problem:
Score : 100 points

Problem Statement

You have three tasks, all of which need to be completed.

First, you can complete any one task at cost 0.

Then, just after completing the i-th task, you can complete the j-th task at cost |A_j - A_i|.

Here, |x| denotes the absolute value of x.

Find the minimum total cost required to complete all the task.

Constraints

All values in input are integers.

1 \leq A_1, A_2, A_3 \leq 100

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

Print the minimum total cost required to complete all the task.

Sample Input 1

1 6 3

Sample Output 1

5

When the tasks are completed in the following order, the total cost will be 5, which is the minimum:

Complete the first task at cost 0.

Complete the third task at cost 2.

Complete the second task at cost 3.

Sample Input 2

11 5 5

Sample Output 2

6

Sample Input 3

100 100 100

Sample Output 3

0

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
int main()
{
    int a,b,c,ans1,ans2,max;
    scanf("%d%d%d",&a,&b,&c);
    if(a>=b && a>=c) {
    ans1=abs(a-b)+abs(b-c);
    ans2=abs(a-c)+abs(c-b);
    }
    else if(b>=a && b>=c) {
    ans1=abs(b-a)+abs(a-c);
    ans2=abs(b-c)+abs(c-a);
    }
    else if(c>=b && c>=a) {
    ans1=abs(c-a)+abs(a-b);
    ans2=abs(c-b)+abs(b-a);
    }
    if(ans1>ans2) {
        printf("%d\n",ans2);
    }
    else {
        printf("%d\n",ans1);
    }
    return 0;
}