Problem:
Score : 700 points

Problem Statement

You are given four integers: H, W, h and w (1 ≤ h ≤ H, 1 ≤ w ≤ W).
Determine whether there exists a matrix such that all of the following conditions are held, and construct one such matrix if the answer is positive:

The matrix has H rows and W columns.

Each element of the matrix is an integer between -10^9 and 10^9 (inclusive).

The sum of all the elements of the matrix is positive.

The sum of all the elements within every subrectangle with h rows and w columns in the matrix is negative.

Constraints

1 ≤ h ≤ H ≤ 500

1 ≤ w ≤ W ≤ 500

Input

Input is given from Standard Input in the following format:

H W h w

Output

If there does not exist a matrix that satisfies all of the conditions, print No.

Otherwise, print Yes in the first line, and print a matrix in the subsequent lines in the following format:

a_{11} ... a_{1W}
:
a_{H1} ... a_{HW}

Here, a_{ij} represents the (i,\ j) element of the matrix.

Sample Input 1

3 3 2 2

Sample Output 1

Yes
1 1 1
1 -4 1
1 1 1

The sum of all the elements of this matrix is 4, which is positive.
Also, in this matrix, there are four subrectangles with 2 rows and 2 columns as shown below. For each of them, the sum of all the elements inside is -1, which is negative.

Sample Input 2

2 4 1 2

Sample Output 2

No

Sample Input 3

3 4 2 3

Sample Output 3

Yes
2 -5 8 7
3 -5 -4 -5
2 1 -1 7

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

#include <stdio.h>

int main()
{
	int H, W, h, w;
	scanf("%d %d %d %d", &H, &W, &h, &w);
	if (H % h == 0 && W % w == 0) {
		printf("No\n");
		fflush(stdout);
		return 0;
	}
	
	int i, j, a[502][502], pos = 1 << 20, neg;
	if (H % h != 0) {
		neg = -((h - 1) * pos + 1);
		for (i = 1; i <= H; i++) {
			if (i % h == 0) for (j = 1; j <= W; j++) a[i][j] = neg;
			else for (j = 1; j <= W; j++) a[i][j] = pos;
		}
	} else {
		neg = -((w - 1) * pos + 1);
		for (j = 1; j <= W; j++) {
			if (j % w == 0) for (i = 1; i <= H; i++) a[i][j] = neg;
			else for (i = 1; i <= H; i++) a[i][j] = pos;
		}
	}
	
	printf("Yes\n");
	for (i = 1; i <= H; i++) {
		for (j = 1; j < W; j++) printf("%d ", a[i][j]);
		printf("%d\n", a[i][W]);
	}
	fflush(stdout);
	return 0;
}