Problem:
Score : 200 points

Problem Statement

A string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:

S is a palindrome.

Let N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.

The string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.

Determine whether S is a strong palindrome.

Constraints

S consists of lowercase English letters.

The length of S is an odd number between 3 and 99 (inclusive).

Input

Input is given from Standard Input in the following format:

S

Output

If S is a strong palindrome, print Yes;
otherwise, print No.

Sample Input 1

akasaka

Sample Output 1

Yes

S is akasaka.

The string formed by the 1-st through the 3-rd characters is aka.

The string formed by the 5-th through the 7-th characters is aka.
All of these are palindromes, so S is a strong palindrome.

Sample Input 2

level

Sample Output 2

No

Sample Input 3

atcoder

Sample Output 3

No

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
 
int isKaibun(char *s, int n){
    int a = 0;

    for (int i = 0; i < n/2; i++)
    {
        if (s[i] == s[n - 1 - i])
        {
            a = 1;
        }
    }
    return a;
    
}

int main(){
  char s[100];
  int n;
  scanf("%s",&s);

  for(n=0; n++; s[n] == '\0');
  if (isKaibun(s, n) && isKaibun(s, n/2) && isKaibun(s + 1 + n/2, n/2)){
      printf("Yes\n");
  }
  else{
      printf("No\n");
  }
  return 0;
}