Problem:
Score : 200 points

Problem Statement

A shop sells N kinds of fruits, Fruit 1, \ldots, N, at prices of p_1, \ldots, p_N yen per item, respectively. (Yen is the currency of Japan.)

Here, we will choose K kinds of fruits and buy one of each chosen kind. Find the minimum possible total price of those fruits.

Constraints

1 \leq K \leq N \leq 1000

1 \leq p_i \leq 1000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
p_1 p_2 \ldots p_N

Output

Print an integer representing the minimum possible total price of fruits.

Sample Input 1

5 3
50 100 80 120 80

Sample Output 1

210

This shop sells Fruit 1, 2, 3, 4, and 5 for 50 yen, 100 yen, 80 yen, 120 yen, and 80 yen, respectively.

The minimum total price for three kinds of fruits is 50 + 80 + 80 = 210 yen when choosing Fruit 1, 3, and 5.

Sample Input 2

1 1
1000

Sample Output 2

1000

Solution in C (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <stdio.h>

int main(void) {
	int n = 0;
	int k = 0;

	int p[1005] = { 0 };

	scanf("%d", &n);
	scanf("%d", &k);

	for (int i = 0; i < n; i++) {
		int tmp = 0;
		scanf("%d", &tmp);
		for (int j = 0; j <= i; j++) {
			if (p[j] > tmp) {
				int tmpp = p[j];
				p[j] = tmp;
				p[j + 1] = tmpp;
			}
			else if (p[j] == 0) {
				p[j] = tmp;
			}

		}
	}

	int result = 0;
	for (int i = 0; i < k; i++) {
		result += p[i];
	}

	printf("%d", result);

	return 0;
}