Problem:
Partition

Quick sort is based on the Divide-and-conquer approach. In QuickSort(A, p, r), first, a procedure Partition(A, p, r) divides an array A[p..r] into two subarrays A[p..q-1] and A[q+1..r] such that each element of A[p..q-1] is less than or equal to A[q], which is, inturn, less than or equal to each element of A[q+1..r]. It also computes the index q.

In the conquer processes, the two subarrays A[p..q-1] and A[q+1..r] are sorted by recursive calls of QuickSort(A, p, q-1) and QuickSort(A, q+1, r).

Your task is to read a sequence A and perform the Partition based on the following pseudocode:

Partition(A, p, r)
1 x = A[r]
2 i = p-1
3 for j = p to r-1
4 do if A[j] <= x
5 then i = i+1
6 exchange A[i] and A[j]
7 exchange A[i+1] and A[r]
8 return i+1

Note that, in this algorithm, Partition always selects an element A[r] as a pivot element around which to partition the array A[p..r].

Input

The first line of the input includes an integer n, the number of elements in the sequence A.

In the second line, Ai (i = 1,2,...,n), elements of the sequence are given separated by space characters.

Output

Print the sorted sequence. Two contiguous elements of the sequence should be separated by a space character. The element which is selected as the pivot of the partition should be indicated by [  ].

Constraints

1 ≤ n ≤ 100,000

0 ≤ Ai ≤ 100,000

Sample Input 1

12
13 19 9 5 12 8 7 4 21 2 6 11

Sample Output 1

9 5 8 7 4 2 6 [11] 21 13 19 12

Solution in C (judge verdict: Accepted)

#include<stdio.h>
 
int main(){
 
  int A[100000],n,i,j,r,p,q,x,stac;
   
 scanf("%d",&n);
 for(i=1;i<=n;i++){
   scanf("%d",&A[i]);
 }
 p=1;
 r=n;
 x=A[r];
 i=p-1;
 for(j=p;j<=r-1;j++){
   if(A[j]<=x){
     i=i+1;
   stac=A[i];
   A[i]=A[j];
   A[j]=stac;
   }
 }
 stac=A[i+1];
 A[i+1]=A[r];
 A[r]=stac;
 q=i+1;
 for(i=1;i<=n;i++){
   if(i>1){
     printf(" ");
   }
   if(q==i)
     printf("[%d]",A[i]);
   else
   printf("%d",A[i]);
 }
 printf("\n");
 return 0;
}