Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in C (Clang 3.8.0) (judge verdict: Wrong Answer)

#include<stdio.h>
int main(){
    
    int a,h,n,w;
    scanf("%d",&a);
    h = 1;
    
    while(1)
    {
        if (4*h > a)break;
        h++;
    }
    
    n = 1;
    
    while (1)
    {
        if (4*h*n > a*n + a*h){
            w = a*h*n/(4*h*n - a*n - a*h);
            if(4/a == 1/h + 1/n + 1/w) break;
        }
        n++;
    }
    
    printf("%d %d %d\n",h,n,w);
    
    
    return 0;
}