Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
#include<string.h>
int main()
{
int a,i=0,m=0,n=0,d=1,c=0,S=0;
scanf("%d",&a);
if(a<105)
{printf("0\n");
return 0;}


for(m=105;m<=a;)
{d=1;
c=0;
for(d;d<=m;d++)
{
if(m%d==0)
{
c++;
}

}

if(c==8)
{
S++;
}
m=m+2;
}
printf("%d\n",S);
return 0;
}