Problem:
Score : 200 points

Problem Statement

Snuke has come to a store that sells boxes containing balls. The store sells the following three kinds of boxes:

Red boxes, each containing R red balls

Green boxes, each containing G green balls

Blue boxes, each containing B blue balls

Snuke wants to get a total of exactly N balls by buying r red boxes, g green boxes and b blue boxes.
How many triples of non-negative integers (r,g,b) achieve this?

Constraints

All values in input are integers.

1 \leq R,G,B,N \leq 3000

Input

Input is given from Standard Input in the following format:

R G B N

Output

Print the answer.

Sample Input 1

1 2 3 4

Sample Output 1

4

Four triples achieve the objective, as follows:

(4,0,0)

(2,1,0)

(1,0,1)

(0,2,0)

Sample Input 2

13 1 4 3000

Sample Output 2

87058

Solution in C (GCC 5.4.1) (judge verdict: Time Limit Exceeded)

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>
int compare_int(const void *a, const void *b)
{
    return *(int*)a - *(int*)b;
//    return *(long long*)a - *(long long*)b;
}
//  qsort(A, b, sizeof(int), compare_int);

int main()
{
 
//  int a, b, c, d, e, X, Y;
  int a, b, c,  d, e,f,n;
  //  double  c;
//  long long  A[1000001]={};
  int  A[2001][1001]={};
  int  B[2000001]={};
  int  ans[100003]={};
  int  sum[100003]={};
  int  cnt_flag[100003]={};

  int  L[1003]={};


//  long long  a, b, c, d, X, Y;
//  long long   d, X, Y;
  long long JPY;
  double BTC;
  char s[200001][1001]={};
  char t[200001][1001]={};
  char u[200001]={};
//  int N, M;
//  int A[1000000001]={};
//  long long  C[101]={};
  int i,j,k,point;
  int point_A=0, point_B=0;
  int flag=0;
//  int flag[10000003]={};
  int tmp=0;
//  int min=1000000;
  int min=10;
  int len=0;
  int cnt=0;
  int cnt0=0;
  int cnt1=0;
  int num=0;
//  double ans=0.0;
//  long long ans=0;
  int max=0;
//  int sum=0;
//  char alp[26]={'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};

  //  a=0;
//  scanf("%lld %lld", &a, &b);
 
  scanf("%d%d%d%d", &a, &b, &c, &n);
  for(i=0;(i*a)<n+1;i++){
    for(j=0;(j*b)<n+1;j++){
      for(k=0;(k*c)<n+1;k++){
        if((i*a)+(j*b)+(k*c)==n) cnt++;
        //printf("i=%d j=%d k=%d n=%d\n",i,j,k,(i*a)+(j*b)+(k*c));
      }
    }
  }
  
  printf("%d\n",cnt);
//    else  
  
return 0;
}