Problem:
Score : 300 points

Problem Statement

You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

1 \leq |S| \leq 2 \times 10^5

|S| = |T|

S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S and T can be made equal, print Yes; otherwise, print No.

Sample Input 1

azzel
apple

Sample Output 1

Yes

azzel can be changed to apple, as follows:

Choose e as c_1 and l as c_2. azzel becomes azzle.

Choose z as c_1 and p as c_2. azzle becomes apple.

Sample Input 2

chokudai
redcoder

Sample Output 2

No

No sequences of operation can change chokudai to redcoder.

Sample Input 3

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu

Sample Output 3

Yes

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
#include <stdbool.h>
#include <string.h>

int main(void){
	char s[200000],t[200000];
	scanf("%s",s);
	scanf("%s",t);
	int i,j,flag=0;
	int len=strlen(s);
	for(i=0;i<len;i++){
		for(j=0;j<len;j++){
			if(t[i] == t[j]){
				if(s[i] != s[j]){
					flag++;
					goto end;
				}
			}
			if(s[i] == s[j]){
				if(t[i] != t[j]){
					flag++;
					goto end;
				}
			}
		}
	}
end:
	if(flag != 0) printf("No");
	else printf("Yes");
	return 0;
}