Problem:
Score : 200 points

Problem Statement

Niwango-kun is an employee of Dwango Co., Ltd.

One day, he is asked to generate a thumbnail from a video a user submitted.

To generate a thumbnail, he needs to select a frame of the video according to the following procedure:

Get an integer N and N integers a_0, a_1, ..., a_{N-1} as inputs. N denotes the number of the frames of the video, and each a_i denotes the representation of the i-th frame of the video.

Select t-th frame whose representation a_t is nearest to the average of all frame representations.

If there are multiple such frames, select the frame with the smallest index.

Find the index t of the frame he should select to generate a thumbnail.

Constraints

1 \leq N \leq 100

1 \leq a_i \leq 100

All numbers given in input are integers

Input

Input is given from Standard Input in the following format:

N
a_{0} a_{1} ... a_{N-1}

Output

Print the answer.

Sample Input 1

3
1 2 3

Sample Output 1

1

Since the average of frame representations is 2, Niwango-kun needs to select the index 1, whose representation is 2, that is, the nearest value to the average.

Sample Input 2

4
2 5 2 5

Sample Output 2

0

The average of frame representations is 3.5.

In this case, every frame has the same distance from its representation to the average.

Therefore, Niwango-kun should select index 0, the smallest index among them.

Solution in C (GCC 5.4.1) (judge verdict: Runtime Error)

#include <stdio.h>

float ave(int a[],int n);

int main()
{
	int size,number;
	scanf("%d",&size);
	int array[size];
	float average,min;
	for (int i = 0; i < size; ++i)
	{
		scanf("%d",&array[i]);
	}

	average = ave(array,size);
	min = (average - array[0])*(average - array[0]);
	number = 0;

	for (int i = 1; i < size; ++i)
	{
		float dis = (average - array[i])*(average - array[i]);
		if (min>dis){
			number = i;
		}
	}
	return number;


}

float ave(int a[],int n)
{
	int sum = 0;
	for (int i = 0; i < n; ++i)
	{
		sum += a[i];
	}

	return sum/n;

}