Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include "stdio.h"
int main(int argc, char const *argv[])
{
	long n;
	while(~scanf("%ld",&n))
	{
		int i,j;
		for(i=1;i<=3500;i++)
		{
			int f=0;
			for(j=1;j<=3500;j++)
			{
				long w1,w2;
				w1=n*i*j;
				w2=4*i*j-n*(i+j);
				if(w1>0&&w2>0&&w1%w2==0)
				{
					f=1;
					printf("%d %d %ld\n",i,j,w1/w2);
					break;
				}
			}
			if(f)
				break;
        }
    }
    return 0;
}