Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in C (judge verdict: Time Limit Exceeded)

#include<stdio.h>
#include<string.h>

int main(){
	char moji[2][27]={"abcdefghijklmnopqrstuvwxyz","ABCDEFGHIJKLMNOPQRSTUVWXYZ"};
	char uketori[1201];
	int i,j,mojisuu,count[26]={0};
	
	while(scanf("%s",uketori)){
		
		mojisuu=(int)strlen(uketori);
		
		for(i=0;i<mojisuu;i++){
			for(j=0;j<26;j++){
				if(uketori[i]==moji[0][j]){
					count[j]++;
				}else if(uketori[i]==moji[1][j]){
					count[j]++;
				}
				
			}
			
		}
		
		
	}
	for(i=0;i<26;i++){
			printf("%c : %d\n",moji[0][i],count[i]);
	}
	return 0;
}