Problem:
Score : 200 points

Problem Statement

A shop sells N kinds of fruits, Fruit 1, \ldots, N, at prices of p_1, \ldots, p_N yen per item, respectively. (Yen is the currency of Japan.)

Here, we will choose K kinds of fruits and buy one of each chosen kind. Find the minimum possible total price of those fruits.

Constraints

1 \leq K \leq N \leq 1000

1 \leq p_i \leq 1000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
p_1 p_2 \ldots p_N

Output

Print an integer representing the minimum possible total price of fruits.

Sample Input 1

5 3
50 100 80 120 80

Sample Output 1

210

This shop sells Fruit 1, 2, 3, 4, and 5 for 50 yen, 100 yen, 80 yen, 120 yen, and 80 yen, respectively.

The minimum total price for three kinds of fruits is 50 + 80 + 80 = 210 yen when choosing Fruit 1, 3, and 5.

Sample Input 2

1 1
1000

Sample Output 2

1000

Solution in C (GCC 9.2.1) (judge verdict: Wrong Answer)

#include<stdio.h>
#pragma warning(disable:4996)

int main() {
	int p[1001] = { 0 };
	int k = 0,n = 0,tmp = 0,sum =0;

	scanf("%d %d", &n, &k);

	for (int i = 0; i < n; i++) {
		scanf("%d", &p[i]);
	}

	for (int j = 0; j < n; j++) {
		for (int m = j+1; m < n; m++) {
			if (p[j] < p[m]) {
				tmp = p[m];
				p[m] = p[j];
				p[j] = tmp;
			}
		}
	}

	for (int s = 0; s < k; s++) {
		sum += p[s];
	}
	printf("%d", sum);
}