Problem:
Hit and Blow

Let's play Hit and Blow game. A imagines four numbers and B guesses the numbers. After B picks out four numbers, A answers:

The number of numbers which have the same place with numbers A imagined (Hit)

The number of numbers included (but different place) in the numbers A imagined (Blow)

For example, if A imagined numbers:

9 1 8 2

and B chose:

4 1 5 9

A should say 1 Hit and 1 Blow.

Write a program which reads four numbers A imagined and four numbers B chose and prints the number of Hit and Blow respectively. You may assume that the four numbers are all different and within from 0 to 9.

Input

The input consists of multiple datasets. Each dataset set consists of:

a1 a2 a3 a4
b1 b2 b3 b4

, where ai (0 ≤ ai ≤ 9) is i-th number A imagined and bi (0 ≤ bi ≤ 9) is i-th number B chose.

The input ends with EOF. The number of datasets is less than or equal to 50.

Output

For each dataset, print the number of Hit and Blow in a line. These two numbers should be separated by a space.

Sample Input

9 1 8 2
4 1 5 9
4 6 8 2
4 6 3 2

Output for the Sample Input

1 1
3 0

Solution in C (judge verdict: Time Limit Exceeded)

#include <stdio.h>

int main(){
	int a[4];
	int b[4];
	int hit,blow;
	int i,j;
	char c[8];
	
	while(1){
		hit=0;
		blow=0;
		gets(c);
		if(c[0]==0){
			break;
		}
		a[0]=c[0];
		a[1]=c[2];
		a[2]=c[4];
		a[3]=c[6];
		
		gets(c);
		if(c[0]==0){
			break;
		}
		b[0]=c[0];
		b[1]=c[2];
		b[2]=c[4];
		b[3]=c[6];
		
		/*scanf("%d %d %d %d",&a[0],&a[1],&a[2],&a[3]);
		scanf("%d %d %d %d",&b[0],&b[1],&b[2],&b[3]);*/
		
		for(i=0;i<4;i++){
			for(j=0;j<4;j++){
				if(a[i]==b[j]){
					blow++;
				}
			}
			if(a[i]==b[i]){
				hit++;
			}
		}
		blow-=hit;
		printf("%d %d\n",hit,blow);
	}
	return 0;
}