Problem:
Binary Search Tree II

Write a program which performs the following operations to a binary search tree $T$ by adding the find operation to A: Binary Search Tree I.

insert $k$: Insert a node containing $k$ as key into $T$.

find $k$: Report whether $T$ has a node containing $k$.

print: Print the keys of the binary search tree by inorder tree walk and preorder tree walk respectively.

Input

In the first line, the number of operations $m$ is given. In the following $m$ lines, operations represented by insert $k$, find $k$ or print are given.

Output

For each find $k$ operation, print "yes" if $T$ has a node containing $k$, "no" if not.

In addition, for each print operation, print a list of keys obtained by inorder tree walk and preorder tree walk in a line respectively. Put a space character before each key.

Constraints

The number of operations $\leq 500,000$

The number of print operations $\leq 10$.

$-2,000,000,000 \leq key \leq 2,000,000,000$

The height of the binary tree does not exceed 100 if you employ the above pseudo code.

The keys in the binary search tree are all different.

Sample Input 1

10
insert 30
insert 88
insert 12
insert 1
insert 20
find 12
insert 17
insert 25
find 16
print

Sample Output 1

yes
no
1 12 17 20 25 30 88
30 12 1 20 17 25 88

Reference

Introduction to Algorithms, Thomas H. Cormen, Charles E. Leiserson, Ronald L. Rivest, and Clifford Stein. The MIT Press.

Solution in C (judge verdict: Accepted)

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
struct Node{
    int key;
    struct Node *right;
    struct Node *left;
    struct Node *parent;
};
void insert(int);
int  find(struct Node *,int);
void inorder(struct Node *);
void preorder(struct Node *);

struct Node *root,*NIL;
int y_or_n[500000];
int t=0,g=0;

int main(){
    int n,i,j,x;
    char St[10];

    scanf("%d",&n);
    for(j=0;j<n;j++){
        scanf("%s%d",St,&x);//プリントしたいときはxに任意の数を入力
        if(strcmp(St,"print")==0){
            if(t==0) g=1;
            else{
                for(i=0;i<t;i++){
                if(y_or_n[i]==1) printf("yes\n");
                else printf("no\n");
            }
            }
            inorder(root);
            printf("\n");
            preorder(root);
            printf("\n");
            t=0;
        }
        else if(strcmp(St,"insert")==0) {
            insert(x);
        }
        else{
            find(root,x);
        }   
    }
    if(g==1){
         for(i=0;i<t;i++){
            if(y_or_n[i]==1) printf("yes\n");
            else printf("no\n");
            }
    }
    return 0;
}

void insert(int k){
    struct Node *x=root;
    struct Node *y=NIL;
    struct Node *z;

    z=(struct Node *)malloc(sizeof(struct Node));
    z->key=k;
    z->left=NIL;
    z->right=NIL;

    while(x!=NIL){
        y=x;
        if(z->key < x->key){
            x=x->left;
        }
        else{
            x=x->right;
        }
    }
    z->parent=y;
    if(y==NIL){
        root=z;
    }
    else{
        if(z->key < y->key){
            y->left=z;
        }
        else{
            y->right=z;
        }
    }
}
  int find(struct Node *u,int k){
    while(u!=NIL){
        if(k==u->key){
            y_or_n[t]=1;
            t++;
            return 0;
        }
        else if(k<=u->key){
            u=u->left;
        }
        else{
            u=u->right;
        }
    }
    t++;
    y_or_n[t]=2;
    return 0;
}

void inorder(struct Node *u){
    if(u==NIL) return;
    inorder(u->left);
    printf(" %d",u->key);
    inorder(u->right);
}
void preorder(struct Node *u){
    if(u==NIL) return;
    printf(" %d",u->key);
    preorder(u->left);
    preorder(u->right);
}