Problem:
Score : 200 points

Problem Statement

Find the number of palindromic numbers among the integers between A and B (inclusive).
Here, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.

Constraints

10000 \leq A \leq B \leq 99999

All input values are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the number of palindromic numbers among the integers between A and B (inclusive).

Sample Input 1

11009 11332

Sample Output 1

4

There are four integers that satisfy the conditions: 11011, 11111, 11211 and 11311.

Sample Input 2

31415 92653

Sample Output 2

612

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
int main()
{
    long a, b;
    scanf("%ld %ld", &a, &b);
    long ans = 0;
    long i;
    int x, y;
    for (i = a; i <= b; i++)
    {
        x = i / 1000;
        y = i % 100;
        if ((x / 10) == (y % 10))
        {
            if ((x % 10) == (y / 10))
                ans++;
        }
    }
    printf("%ld\n", ans);
    return 0;
}