Problem:
Score : 200 points

Problem Statement

Given are a positive integer N and a string S of length N consisting of lowercase English letters.

Determine whether the string is a concatenation of two copies of some string.
That is, determine whether there is a string T such that S = T + T.

Constraints

1 \leq N \leq 100

S consists of lowercase English letters.

|S| = N

Input

Input is given from Standard Input in the following format:

N
S

Output

If S is a concatenation of two copies of some string, print Yes; otherwise, print No.

Sample Input 1

6
abcabc

Sample Output 1

Yes

Let T = abc, and S = T + T.

Sample Input 2

6
abcadc

Sample Output 2

No

Sample Input 3

1
z

Sample Output 3

No

Solution in C (GCC 9.2.1) (judge verdict: Runtime Error)

#include <stdio.h>
#include <string.h>

int main() {
	
	int n;
	char s[n];
	char t1[n];
	char t2[n];
	
	scanf("%d", &n);
	
	scanf("%s", s);
	
	int length = strlen(s);
	
	if(n==1){
		printf("No\n");
	}
	
	else if(n>1){
		for(int i=0; i<n/2; i++){
		t1[i] = s[i];
		t2[i] = s[i+(n/2)];
	}
			
		if(length==n && strcmp(t1, t2)==0){
			printf("Yes\n");
		}
		
		else if(length!=n && strcmp(t1, t2)!=1){
			printf("No\n");
		}
	}
	
	
	return 0;
}