Problem:
Score : 200 points

Problem Statement

You are given string S and T consisting of lowercase English letters.

Determine if S equals T after rotation.

That is, determine if S equals T after the following operation is performed some number of times:

Operation: Let S = S_1 S_2 ... S_{|S|}. Change S to S_{|S|} S_1 S_2 ... S_{|S|-1}.

Here, |X| denotes the length of the string X.

Constraints

2 \leq |S| \leq 100

|S| = |T|

S and T consist of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S equals T after rotation, print Yes; if it does not, print No.

Sample Input 1

kyoto
tokyo

Sample Output 1

Yes

In the first operation, kyoto becomes okyot.

In the second operation, okyot becomes tokyo.

Sample Input 2

abc
arc

Sample Output 2

No

abc does not equal arc after any number of operations.

Sample Input 3

aaaaaaaaaaaaaaab
aaaaaaaaaaaaaaab

Sample Output 3

Yes

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>                                                                                                                           
#include<string.h>

int main()
{
   char s[101];
   char t[101];
   char stmp;
   int slen;
   int i ,j;
   int yn = 0;

   scanf("%s", s);
   scanf("%s", t);

   slen = strlen(s);

   for(i=0;i<slen;i++){
      stmp = s[slen-1];
      for(j=slen-1;j>0;j--){
         s[j] = s[j-1];
      }
      s[0] = stmp;

      if(strcmp(s,t)==0){
         yn = 1;
         break;
      }
   }

   if(yn==1){
      printf("Yes\n");
   }
   else {
      printf("No\n");
   }

   return 0;
}