Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
int main()
{
    int N,i,b=0;
    scanf("%d",&N);
    for(i=105; i<=N; i+=2)
    {
        if(factor(i)>=8)
            b++;
    }
    printf("%d\n",b);
    return 0;
}

int factor(int num)
{
    int j=0,i;
    for(i=1; i<=num; i++)
    {
        if(num%i==0)
            j++;
    }

    return j;
}