Problem:
Score : 200 points

Problem Statement

There are some animals in a garden. Each of them is a crane with two legs or a turtle with four legs.

Takahashi says: "there are X animals in total in the garden, and they have Y legs in total." Determine whether there is a combination of numbers of cranes and turtles in which this statement is correct.

Constraints

1 \leq X \leq 100

1 \leq Y \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

If there is a combination of numbers of cranes and turtles in which the statement is correct, print Yes; otherwise, print No.

Sample Input 1

3 8

Sample Output 1

Yes

The statement "there are 3 animals in total in the garden, and they have 8 legs in total" is correct if there are two cranes and one turtle. Thus, there is a combination of numbers of cranes and turtles in which the statement is correct.

Sample Input 2

2 100

Sample Output 2

No

There is no combination of numbers of cranes and turtles in which this statement is correct.

Sample Input 3

1 2

Sample Output 3

Yes

We also consider the case in which there are only cranes or only turtles.

Solution in C (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <stdlib.h>
#include <stdio.h>


int main(){
    int x,y;
    int turtle =4;
    int crane = 2;
    scanf("%d",&x);
    scanf("%d",&y);
    if(x == 0 && y == 0){
        printf("Yes");
        return 0;
    } 
    if(x ==y || x == 0|| y == 0 ){
        printf("No");
        return 0;
    }
    if(crane * x == y || turtle * x ==y){
        printf("yes");
        return 0 ;
    }
    
    while(x != 0){
       if(y == 0){
        break;
       } 
       if(y > turtle){
            y -= turtle;
       }else if(2 <= y <= crane){

            y -=crane;
       } 
        x-=1;
    }    
    if(y == 0){
        printf("Yes");
    }else{
        printf("No");
    }

    return 0;
}