Problem:
Score : 200 points

Problem Statement

There are N balls placed in a row.
AtCoDeer the deer is painting each of these in one of the K colors of his paint cans.
For aesthetic reasons, any two adjacent balls must be painted in different colors.

Find the number of the possible ways to paint the balls.

Constraints

1≦N≦1000

2≦K≦1000

The correct answer is at most 2^{31}-1.

Input

The input is given from Standard Input in the following format:

N K

Output

Print the number of the possible ways to paint the balls.

Sample Input 1

2 2

Sample Output 1

2

We will denote the colors by 0 and 1. There are two possible ways: we can either paint the left ball in color 0 and the right ball in color 1, or paint the left in color 1 and the right in color 0.

Sample Input 2

1 10

Sample Output 2

10

Since there is only one ball, we can use any of the ten colors to paint it. Thus, the answer is ten.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
int ruizyou(int x,int n){
	int i,sum=1;
	for(i=1;i<=n;i++){
		sum*=x;}
		return sum;}
int main(void)
{int i,h,a,b,c,k,l,m,N,K,j,v,g,flag,sum;
scanf("%d%d",&N,&K);
printf("%d",K*ruizyou(K-1,N-1));

	return 0;
}