Problem:
Score : 300 points

Problem Statement

AtCoDeer the deer is going on a trip in a two-dimensional plane.
In his plan, he will depart from point (0, 0) at time 0, then for each i between 1 and N (inclusive), he will visit point (x_i,y_i) at time t_i.

If AtCoDeer is at point (x, y) at time t, he can be at one of the following points at time t+1: (x+1,y), (x-1,y), (x,y+1) and (x,y-1).
Note that he cannot stay at his place.
Determine whether he can carry out his plan.

Constraints

1 ≤ N ≤ 10^5

0 ≤ x_i ≤ 10^5

0 ≤ y_i ≤ 10^5

1 ≤ t_i ≤ 10^5

t_i < t_{i+1} (1 ≤ i ≤ N-1)

All input values are integers.

Input

Input is given from Standard Input in the following format:

N
t_1 x_1 y_1
t_2 x_2 y_2
:
t_N x_N y_N

Output

If AtCoDeer can carry out his plan, print Yes; if he cannot, print No.

Sample Input 1

2
3 1 2
6 1 1

Sample Output 1

Yes

For example, he can travel as follows: (0,0), (0,1), (1,1), (1,2), (1,1), (1,0), then (1,1).

Sample Input 2

1
2 100 100

Sample Output 2

No

It is impossible to be at (100,100) two seconds after being at (0,0).

Sample Input 3

2
5 1 1
100 1 1

Sample Output 3

No

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>

int main(void)
{
    int N;
    int t[100000],x[100000],y[100000];
    scanf("%d",&N);
    for(int i=0;i<N;i++){
        scanf("%d%d%d",&t[i],&x[i],&y[i]);
    }
    int can=1;
    for(int i=0;i<N;i++){
        int can2=0;
        for(int n=0;x[i]+y[i]+2*n<=t[i];n++){
            if(x[i]+y[i]+2*n==t[i]){
                can2=1;
                //printf("n=%d ok\n",n);
            }
        }
        //printf("can2=%d\n",can2);
        if(can2==0){
            can=0;
            break;
        }
    }
    if(can==1)
        printf("Yes\n");
    else
        printf("No\n");
    
    return 0;
}