Problem:
Score : 200 points

Problem Statement

A shop sells N kinds of fruits, Fruit 1, \ldots, N, at prices of p_1, \ldots, p_N yen per item, respectively. (Yen is the currency of Japan.)

Here, we will choose K kinds of fruits and buy one of each chosen kind. Find the minimum possible total price of those fruits.

Constraints

1 \leq K \leq N \leq 1000

1 \leq p_i \leq 1000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
p_1 p_2 \ldots p_N

Output

Print an integer representing the minimum possible total price of fruits.

Sample Input 1

5 3
50 100 80 120 80

Sample Output 1

210

This shop sells Fruit 1, 2, 3, 4, and 5 for 50 yen, 100 yen, 80 yen, 120 yen, and 80 yen, respectively.

The minimum total price for three kinds of fruits is 50 + 80 + 80 = 210 yen when choosing Fruit 1, 3, and 5.

Sample Input 2

1 1
1000

Sample Output 2

1000

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

#include<stdio.h>

int main(){
  int k;//number of buy
  int n;//number of fruit
  scanf("%d %d",&n,&k);
  int p[n];
  for(int i = 0;i < n;i++){
    scanf("%d",&p[i]);
  }
  int tmp;
  for(int i = 0;i < n;i++){
    for(int j = 0;j < n - 1;j++){
      if(p[j] > p[j + 1]){
        tmp = p[j];
        p[j] = p[j + 1];
        p[j + 1] = tmp;
      }
    }
  }
  int sum = 0;
  for(int i = 0;i < k;i++){
    sum = sum + p[i];
  }
  printf("%d\n",sum);
  return 0;
}