Problem:
Score : 300 points

Problem Statement

There are N people living on a number line.

The i-th person lives at coordinate X_i.

You are going to hold a meeting that all N people have to attend.

The meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.

Find the minimum total points of stamina the N people have to spend.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq X_i \leq 100

Input

Input is given from Standard Input in the following format:

N
X_1 X_2 ... X_N

Output

Print the minimum total stamina the N people have to spend.

Sample Input 1

2
1 4

Sample Output 1

5

Assume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.

Note that you can hold the meeting only at an integer coordinate.

Sample Input 2

7
14 14 2 13 56 2 37

Sample Output 2

2354

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

    #include<stdio.h>
    int main()
    {
    	int n,i,j,a=0,s=0;
    	scanf("%d",&n);
    	int x[n];

    	for(i=0;i<n;i++)
        {
            scanf("%d",&x[i]);
           a=a+x[i]*x[i];
        }
        for(i=0;i<100;i++)
        {
            for(j=0;j<n;j++)
            {
                s=s+(i-x[j])*(i-x[j]);
            }
            if(a>s)
                a=s;
        }
        printf("%d\n",a);

    return 0;

    }