Problem:
Score : 100 points

Problem Statement

Dolphin loves programming contests. Today, he will take part in a contest in AtCoder.

In this country, 24-hour clock is used. For example, 9:00 p.m. is referred to as "21 o'clock".

The current time is A o'clock, and a contest will begin in exactly B hours.
When will the contest begin? Answer in 24-hour time.

Constraints

0 \leq A,B \leq 23

A and B are integers.

Input

The input is given from Standard Input in the following format:

A B

Output

Print the hour of the starting time of the contest in 24-hour time.

Sample Input 1

9 12

Sample Output 1

21

In this input, the current time is 9 o'clock, and 12 hours later it will be 21 o'clock in 24-hour time.

Sample Input 2

19 0

Sample Output 2

19

The contest has just started.

Sample Input 3

23 2

Sample Output 3

1

The contest will begin at 1 o'clock the next day.

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
#include<math.h>
int main(void) {
	// your code goes here
	int n,m,count,l;
	long a1[50],b1[50],sum,min = 200000000;
	scanf("%d%d",&n,&m);
	for(int i = 0;i<2*n;i++)
	scanf("%ld",&a1[i]);
	for(int i = 0;i<2*m;i++)
	scanf("%ld",&b1[i]);
	for(int i = 0;i<=2*n-2;i+=2)
	{	count = 0;
min =200000000;
		for(int j = 0;j<=2*m-2;j+=2)
		{      sum = a1[i]-b1[j];
			if(a1[i]-b1[j]<0)
			sum = -sum;
			
			if(a1[i+1]-b1[j+1]>=0)
			sum += a1[i+1]-b1[j+1];
			else
			sum += -a1[i+1]+b1[j+1];
			if(sum<min)
			{min = sum;
			l  =count+1;}
			count++;
			
		}
		printf("%d\n",l);
	}
	return 0;
}