Problem:
Score: 300 points

Problem Statement

In Republic of Atcoder, there are N prefectures, and a total of M cities that belong to those prefectures.

City i is established in year Y_i and belongs to Prefecture P_i.

You can assume that there are no multiple cities that are established in the same year.

It is decided to allocate a 12-digit ID number to each city.

If City i is the x-th established city among the cities that belong to Prefecture i, the first six digits of the ID number of City i is P_i, and the last six digits of the ID number is x.

Here, if P_i or x (or both) has less than six digits, zeros are added to the left until it has six digits.

Find the ID numbers for all the cities.

Note that there can be a prefecture with no cities.

Constraints

1 \leq N \leq 10^5

1 \leq M \leq 10^5

1 \leq P_i \leq N

1 \leq Y_i \leq 10^9

Y_i are all different.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M
P_1 Y_1
:
P_M Y_M

Output

Print the ID numbers for all the cities, in ascending order of indices (City 1, City 2, ...).

Sample Input 1

2 3
1 32
2 63
1 12

Sample Output 1

000001000002
000002000001
000001000001

As City 1 is the second established city among the cities that belong to Prefecture 1, its ID number is 000001000002.

As City 2 is the first established city among the cities that belong to Prefecture 2, its ID number is 000002000001.

As City 3 is the first established city among the cities that belong to Prefecture 1, its ID number is 000001000001.

Sample Input 2

2 3
2 55
2 77
2 99

Sample Output 2

000002000001
000002000002
000002000003

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>

int main(){
  int n,m,
      list[100000][3],
      i,j,k,
      t[100000],
      count,ind,tmp,
      sum;
  
  scanf("%d%d", &n, &m);
  
  for(i=0;i<m;i++){
    scanf("%d%d", &list[i][0], &list[i][1]);
    list[i][2] = 0;
  }
  
  for(i=0;i<m;i++){
    if(list[i][2] == 0){
      count = 0;
      for(j=0;j<m;j++){
        if(list[j][0] == list[i][0]){
          t[count] = j;
          count++;
        }
      }
      for(j=0;j<count;j++){
        ind = j;
        for(k=j+1;k<count;k++){
          if(list[t[k]][1] < list[t[ind]][1]){
            ind = k;
          }
        }
        tmp = j;
        j = ind;
        ind = tmp;
      }
      for(j=0;j<count;j++){
        list[t[j]][2] = j+1;
      }
    }
  }
  
  for(i=0;i<m;i++){
    printf("%06d%06d\n", list[i][0], list[i][2]);
  }
  return 0;
}