Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in C (judge verdict: Time Limit Exceeded)

#include<stdio.h>
int main(void)
{
char ch;
int counter[26],num;
for(num=0;num<26;num++){counter[num]=0;}
while (1){
	scanf("%c", &ch);
	if(ch=='.')break;
	if(ch<91 && ch>64)num=ch-'A';
	else num = ch - 'a'; 
	if(num<26)counter[num]++;  
}
for(num=0;num<26;num++){
	ch=num+'a';
	printf("%c : %d\n",ch,counter[num]);
}
return 0;
}