Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in C (judge verdict: Time Limit Exceeded)

#include<stdio.h>

int count[26];
char a;

int main(void){
    int i,j;
    while(1){
        a = getc(stdin);
        if(a >= 'a' && a <= 'z')
            count[a - 'a']++;
        else if(a >= 'A' && a <= 'Z')
            count[a - 'A']++;
        else if(a == '.' || a == '!' || a == '?')
            break;
    }
    for(i = 0;i < 26;i++){
        printf("%c : %d\n",'a' + i,count[i]);
    }
    return 0;
}