Problem:
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Matrix Multiplication

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\[
c_{ij} = \sum_{k=1}^m a_{ik}b_{kj}
\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Constraints

$1 \leq n, m, l \leq 100$

$0 \leq a_{ij}, b_{ij} \leq 10000$

Sample Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2

Sample Output

1 8 5
0 9 6
4 23 14

Note

      解説

Solution in C (judge verdict: Wrong Answer)

#include <stdio.h>

int main(int argc, const char * argv[]) {
    int n,m,l;
    scanf("%d %d %d",&n,&m,&l);
    
    int aMat[n][m];
    int bMat[m][l];
    int i,j,k;
    for(i=0;i<n;i++){
        for(j=0;j<m;j++){
            scanf("%d",&aMat[i][j]);
        }
    }

    for(j=0;j<m;j++){
        for(k=0;k<l;k++){
            scanf("%d",&bMat[j][k]);
        }
    }
    
    int cMat[100][100] = {0};
    for(i=0;i<n;i++){
        for(j=0;j<l;j++){
            for(k=0;k<m;k++){
                cMat[i][j] += aMat[i][k] * bMat[k][j];
            }
        }
    }
    
    for(i=0;i<n;i++){
        for(k=0;k<l;k++){
            printf("%d",cMat[i][k]);
            if(k==l-1){
                printf("\n");
            }
            else{
                printf(" ");
            }
        }
    }
    
    return 0;
}