Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
#include<stdlib.h>
#include<string.h>

#define MAX(p,q) (p>q)?p:q
#define MIN(p,q) (p<q)?p:q

#define REP(i,n) for(i=0;i<n;i++)

int main(void)
{
  int l;
  scanf("%d",&l);
  int yy,mm;
  yy = l/100;
  mm = l%100;
  if(yy>12||yy==0)
  {
    if(mm>12||mm==0)
    {
      printf("NA");
    }
    else
    {
      printf("YYMM");
    }
  }
  else
  {
    if(mm>12||mm==0)
    {
      printf("MMYY");
    }
    else
    {
      printf("AMBIGUOUS");
    }
  }

  return 0;
}