Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>

int main(){
  int n, nDivisor=0, cnt=0;
  scanf("%d", &n);
  
  for(int i=1; i<=n; i=i+2){
    for(int j=1; j<=i; j=j+2){
      if(i%j==0){
        nDivisor++;
      }
    }
    if(nDivisor==8){
      cnt++;
    }
    nDivisor=0;
  }
  
  printf("%d",cnt);
  return 0;
}