Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
int main()
{
    int a, S;
    scanf("%d",&S);
    a = S%100;
    if(S==0){
        printf("NA");
    }else if(a==0 ){
        if(99 <S && S<1201){
        printf("MMYY");
        }else{
            printf("NA");
        }
    }else if(0<a && a< 13){
        if(0<S && S<13){
            printf("YYMM");
        }else if(0101<=S && S<=1212){
            printf("AMBIGUOUS");
        }else
        {
            printf("YYMM");
        }
    }else{
        if(1313<S){
            printf("NA");
        }else if(S<0012 && 0100<S){
            printf("NA");
        }else if(S<0112 && 1300<S){
            printf("MMYY");
        }else{
            printf("YYMM");
        }
    }
   
        return 0;
}