Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>

int main(){

  int n;
  scanf("%d",&n);

  int count = 0;

  for(int i=1; i<=n; i++){
    int tmp = 0;
    if(i % 2 != 0 ){
    for(int j=1; j<=n; j++){
      if( i % j == 0 ) tmp++;
    }
    }
    if(tmp == 8) count ++;
  }

  printf("%d",count);

  return 0;
}