Problem:
Score : 200 points

Problem Statement

Find the number of palindromic numbers among the integers between A and B (inclusive).
Here, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.

Constraints

10000 \leq A \leq B \leq 99999

All input values are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the number of palindromic numbers among the integers between A and B (inclusive).

Sample Input 1

11009 11332

Sample Output 1

4

There are four integers that satisfy the conditions: 11011, 11111, 11211 and 11311.

Sample Input 2

31415 92653

Sample Output 2

612

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
int main(void){
    int A, B, i, j, c[5], d, ans;
    ans = 0;
    scanf("%d %d", &A, &B);
    for(i = A; i <= B; i++){
        d = i;
        for(j = 0; j < 5; j++){
            c[j] = d % 10;
            d /= 10;
        }
        if(c[0] == c[4] && c[1] == c[3]) ans++;
    }
    printf("%d\n", ans);
    return 0;
}