Problem:
Score : 200 points

Problem Statement

A shop sells N kinds of fruits, Fruit 1, \ldots, N, at prices of p_1, \ldots, p_N yen per item, respectively. (Yen is the currency of Japan.)

Here, we will choose K kinds of fruits and buy one of each chosen kind. Find the minimum possible total price of those fruits.

Constraints

1 \leq K \leq N \leq 1000

1 \leq p_i \leq 1000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
p_1 p_2 \ldots p_N

Output

Print an integer representing the minimum possible total price of fruits.

Sample Input 1

5 3
50 100 80 120 80

Sample Output 1

210

This shop sells Fruit 1, 2, 3, 4, and 5 for 50 yen, 100 yen, 80 yen, 120 yen, and 80 yen, respectively.

The minimum total price for three kinds of fruits is 50 + 80 + 80 = 210 yen when choosing Fruit 1, 3, and 5.

Sample Input 2

1 1
1000

Sample Output 2

1000

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

#include<stdio.h>
signed main(){
    int n,x[1001],k;
    int i,j,min,temp;
    scanf("%d %d",&n,&k);
    for(i=0;i<n;i++){
        scanf("%d",&x[i]);
    }
    for(i=0;i<n;i++){
        min=i;
        for(j=i+1;j<n;j++){
            if(x[j]<x[min]){
                min=j;
            }
        }
        if(min!=i){
            temp=x[i];
            x[i]=x[min];
            x[min]=temp;
        }
    }
     int sum=0;
    for(i=0;i<k;i++){
        sum+=x[i];
    }
    printf("%d\n",sum);
    return(0);
}