Problem:
Score : 200 points

Problem Statement

Given are integers a,b,c and d.
If x and y are integers and a \leq x \leq b and c\leq y \leq d hold, what is the maximum possible value of x \times y?

Constraints

-10^9 \leq a \leq b \leq 10^9

-10^9 \leq c \leq d \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

a b c d

Output

Print the answer.

Sample Input 1

1 2 1 1

Sample Output 1

2

If x = 1 and y = 1 then x \times y = 1.
If x = 2 and y = 1 then x \times y = 2.
Therefore, the answer is 2.

Sample Input 2

3 5 -4 -2

Sample Output 2

-6

The answer can be negative.

Sample Input 3

-1000000000 0 -1000000000 0

Sample Output 3

1000000000000000000

Solution in C (Clang 10.0.0) (judge verdict: Wrong Answer)

#include <stdio.h>
int main(void){
    long long int a,b,c,d,ans;
    scanf("%lld",&a);
    scanf("%lld",&b);
    scanf("%lld",&c);
    scanf("%lld",&d);

    if(a>=0 && b>=0 && c>=0 && d>=0){
        ans=b*d;
    }else if(b<=0 && d<=0){
        ans=a*c;
    }else if(b<=0 && d>=0 && c>=0){
        ans=b*c;
    }else if(b<=0 && d>=0 && c<=0){
        ans=a*c;
    }else if(b>=0 && d<=0 && a>=0){
        ans=a*d;
    }else if(b>=0 && d<=0 && a<=0){
        ans=a*c;
    }else if(b>=0 && d>=0 && a<=0 && c<=0){
        ans=a*c;
    }else if(b>=0 && d>=0){
        ans=b*d;
    }
    printf("%lld\n",ans);
    return 0;
}