Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
 
int main(){
	int n;
	scanf("%d",&n);
	if(0 < n && n < 105)
		printf("0");
	else if(104 < n && n < 135)
		printf("1");
  	else if(134 < n && n < 165)
      	printf("2");
	else if(164 < n && n < 195)
		printf("3");
	else if(194 < n && n <  200)
		printf("4");
	return 0;
}