Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>

int main()
{
    long int N,h,n,t1,t2;
    bool flag;
    scanf("%ld",&N);
    for(h=1;h<=3500;h++){
        for(n=1;n<=3500;n++){
            t1=N*h*n;
            t2=4*h*n-n*N-h*N;
            if(t1>0&&t2>0&&t1%t2==0)
                {
                    printf("%ld %ld %ld\n",h,n,t1/t2);
                    flag=true;
                    break;
                }
            }
            if(flag) break;
    }

    return 0;
}