Problem:
Score : 300 points

Problem Statement

There are N people living on a number line.

The i-th person lives at coordinate X_i.

You are going to hold a meeting that all N people have to attend.

The meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.

Find the minimum total points of stamina the N people have to spend.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq X_i \leq 100

Input

Input is given from Standard Input in the following format:

N
X_1 X_2 ... X_N

Output

Print the minimum total stamina the N people have to spend.

Sample Input 1

2
1 4

Sample Output 1

5

Assume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.

Note that you can hold the meeting only at an integer coordinate.

Sample Input 2

7
14 14 2 13 56 2 37

Sample Output 2

2354

Solution in C (GCC 9.2.1) (judge verdict: Runtime Error)

#include <stdio.h>

#define rep(i,n) for(int i=0;i<(int)n;++i)

int main(void) {
	int X[10];
	int N;

	scanf("%d",&N);
	int ans = 1001001001;

	rep(i, N)scanf("%d",&X[i]);

	for (int j = 1; j <= 100; ++j) {
		int now = 0;
			rep(i,N) now += (X[i] - j) * (X[i] - j);
		if(ans > now)
			ans = now;
	}

	printf("%d",ans);
}