Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in C (judge verdict: Time Limit Exceeded)

#include <stdio.h>
#include <ctype.h>
        
int main(void)
{
int i,j,sum[26];
char ABC;
scanf("%c",&ABC);
while(ABC != EOF)
        
/*EOF(ファイル終了[End Of File])でないかどうか確認*/
        
{
if (isalpha(ABC) != 0)
        
/*入力されたものがアルファベットかどうか確認*/
        
{
j = (tolower(ABC) - 'a');
sum[j] += 1;
        
/*入力されたアルファベットを小文字に変換&0~25の数値に変換*/
        
}
scanf("%c",&ABC);
}
for(i = 'a';i <= 'z';i++)
{
printf("%c : %d\n",i,sum[(i -'a')]);
}
return 0;
}