Problem:
Score : 200 points

Problem Statement

Raccoon is fighting with a monster.

The health of the monster is H.

Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i.
There is no other way to decrease the monster's health.

Raccoon wins when the monster's health becomes 0 or below.

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Constraints

1 \leq H \leq 10^9

1 \leq N \leq 10^5

1 \leq A_i \leq 10^4

All values in input are integers.

Input

Input is given from Standard Input in the following format:

H N
A_1 A_2 ... A_N

Output

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Sample Input 1

10 3
4 5 6

Sample Output 1

Yes

The monster's health will become 0 or below after, for example, using the second and third moves.

Sample Input 2

20 3
4 5 6

Sample Output 2

No

Sample Input 3

210 5
31 41 59 26 53

Sample Output 3

Yes

Sample Input 4

211 5
31 41 59 26 53

Sample Output 4

No

Solution in C (Clang 3.8.0) (judge verdict: Accepted)

//  Twitter@KonoLv1 2020年春からエンジニア見習いデビュー！
 
//  標準入出力を扱うヘッダーファイルの読み込み
#include <stdio.h>
//  "atoi" "atof"などのキャスト、"rand" 疑似乱数を発生させるヘッダーファイルの読み込み
#include <stdlib.h>
//  "strcpy" "strcat"などの文字列操作や"strlen"文字列長さ取得などを行うヘッダーファイルの読み込み
#include <string.h>
//  "sqrtl" "fmax"などの数値操作を行うヘッダーファイルの読み込み
#include <math.h>
 
int main(void){
 
    int x,y,z;
    int i,j,k;
    int count = 0;
    int flg = 0;
    char s[200000] = {};
    int box[200000] = {};
    int sum = 0;
 
    //scanf("%s %d",&s,&box[0]);
    scanf("%d %d",&x,&y);
    // HP x
    // DM y
    for (i = 0; i < y; i++){
        scanf("%d",&sum);
        count = count + sum;
    }
    if (count >= x){
        printf("Yes");
    }else{
        printf("No");
    }
    

 
}