Problem:
Score : 200 points

Problem Statement

There are some animals in a garden. Each of them is a crane with two legs or a turtle with four legs.

Takahashi says: "there are X animals in total in the garden, and they have Y legs in total." Determine whether there is a combination of numbers of cranes and turtles in which this statement is correct.

Constraints

1 \leq X \leq 100

1 \leq Y \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

If there is a combination of numbers of cranes and turtles in which the statement is correct, print Yes; otherwise, print No.

Sample Input 1

3 8

Sample Output 1

Yes

The statement "there are 3 animals in total in the garden, and they have 8 legs in total" is correct if there are two cranes and one turtle. Thus, there is a combination of numbers of cranes and turtles in which the statement is correct.

Sample Input 2

2 100

Sample Output 2

No

There is no combination of numbers of cranes and turtles in which this statement is correct.

Sample Input 3

1 2

Sample Output 3

Yes

We also consider the case in which there are only cranes or only turtles.

Solution in C (GCC 9.2.1) (judge verdict: Wrong Answer)

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>

int main(void){
  int x[]={0,0},y[]={0,0},z[]={0,0},i,j;
  
  scanf("%d",&x[0]);
  scanf("%d",&x[1]);
  
  y[0]=x[1]/4;
  z[0]=x[1]/2;
  
  i=(x[1]%4)%2;
  //printf("%d",i);
  j=(x[1]%2)%4;
  //printf("%d",j);
  
  if(i != 0 || x[1] == 2 ){
    z[1]=(x[1]%2)/4;
    if(x[0] == (z[0]+z[1])){
    	printf("YES");
    }
    else{
      printf("NO");
    }
  }
  else if(j != 0 || x[1] == 4){
    y[1]=(x[1]%4)/2;
    if(x[0] == (y[0]+y[1])){
    	printf("YES");
    }
    else{
      printf("NO");
    }
  }
  else{
        printf("NO");
  }
  
 return 0;
  
}