Problem:
Score : 400 points

Problem Statement

We have a sequence of length N, a = (a_1, a_2, ..., a_N).
Each a_i is a positive integer.

Snuke's objective is to permute the element in a so that the following condition is satisfied:

For each 1 ≤ i ≤ N - 1, the product of a_i and a_{i + 1} is a multiple of 4.

Determine whether Snuke can achieve his objective.

Constraints

2 ≤ N ≤ 10^5

a_i is an integer.

1 ≤ a_i ≤ 10^9

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 ... a_N

Output

If Snuke can achieve his objective, print Yes; otherwise, print No.

Sample Input 1

3
1 10 100

Sample Output 1

Yes

One solution is (1, 100, 10).

Sample Input 2

4
1 2 3 4

Sample Output 2

No

It is impossible to permute a so that the condition is satisfied.

Sample Input 3

3
1 4 1

Sample Output 3

Yes

The condition is already satisfied initially.

Sample Input 4

2
1 1

Sample Output 4

No

Sample Input 5

6
2 7 1 8 2 8

Sample Output 5

Yes

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>

int main()
{
	int N;
	scanf("%d", &N);
	int a[N];
	int i, j, k;
	for (i = 0; i < N; i++) {
		scanf("%d", &a[i]);
	}

	int count_2 = 0, count_4 = 0;
	for (i = 0; i < N; i++) {
		if (a[i] == 2) {
			count_2++;
		} else if (a[i] % 4 == 0) {
			count_4++;
		}
	}

/*	if ((N - count_2) / 2 <= count_4) {
		printf("Yes\n");
	} else {
		printf("No\n");
	}*/
	if (count_2 >= 2) {
		if (count_4 >= N - count_2) {
			printf("Yes\n");
		} else {
			printf("No\n");
		}
	} else if (count_2 == 1) {
		if (count_4 + count_2 >= N / 2) {
			printf("Yes\n");
		} else {
			printf("No\n");
		}
	} else if (count_2 == 0) {
		if (count_4 >= N / 2) {
			printf("Yes\n");
		} else {
			printf("No\n");
		}
	}

	return 0;
}