Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
#include <string.h>

int main() {
  char s[4];
  scanf("%s", s);
  int a = 0, b = 0;
  for (int i = 0; i < 2; i++) {
    a = a*10;
    a += (s[i] - '0');
  }
  for (int i = 0; i < 2; i++) {
    b = b*10;
    b += (s[2+i] - '0');
  }
  if (0 < a && a < 13) {
    if (0 < b && b < 13) {
      printf("%s\n", "AMBIGUOUS");
    }else{
      printf("%s\n", "MMYY");
    }
  }else{
    if (0 < b && b < 13) {
      printf("%s\n", "YYMM");
    }else{
      printf("%s\n", "NA");
    }
  }
  return 0;
}