Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
int main()
{
    int i,j,N,o=0;
    double h,w,n;
    while(~scanf("%d",&N))
    {
        for(i=1; i<=3500; i++)
        {
            for(j=1; j<=3500; j++)
            {
                h=i;
                w=j;
                n=N*h*w/(4*h*w-N*w-N*h);
                if((int)n==n&&n>0&&j>0&&i>0)
                {
                    if(4*h*w*n==N*(w*n+h*w+n*h))
                    {
                        o++;
                        printf("%.f %.f %.f\n",h,w,n);
                    }

                }
                if(o==1)
                    break;

            }
            if(o==1)
            {
                o=0;
                break;
            }
        }
    }
}