Problem:
Score : 200 points

Problem Statement

You are given two positive integers A and B. Compare the magnitudes of these numbers.

Constraints

1 ≤ A, B ≤ 10^{100}

Neither A nor B begins with a 0.

Input

Input is given from Standard Input in the following format:

A
B

Output

Print GREATER if A>B, LESS if A<B and EQUAL if A=B.

Sample Input 1

36
24

Sample Output 1

GREATER

Since 36>24, print GREATER.

Sample Input 2

850
3777

Sample Output 2

LESS

Sample Input 3

9720246
22516266

Sample Output 3

LESS

Sample Input 4

123456789012345678901234567890
234567890123456789012345678901

Sample Output 4

LESS

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>

int main()
{
	int i;

	char A[101];
	char B[101];
	scanf("%s %s", A, B);

	//桁数確認
	if (getDigit(A) > getDigit(B)) {
		puts("GREATER");
	}
	else if(getDigit(A) < getDigit(B)){
		puts("LESS");
	}
	else {
		for (i = 0; i < 100; i++) {
			if (A[i] > B[i]) {
				puts("GREATER");
				break;
			}
			else if (A[i] < B[i]) {
				puts("LESS");
				break;
			}
		}
		if (i == 100) puts("EQUAL");
	}


	getchar();
	getchar();
	getchar();

	return 0;
}

int getDigit(char *str) 
{
	int i;
	for (i = 0; i < 101; i++) {
		if (str[i] == '\0') {
			return i - 1;
		}
	}
}