Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in C (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <stdio.h>
#define min(x, y) ((x)>(y) ? (y) : (x))

int main(){
  int n, a, b, c, d;
  scanf("%d %d %d %d %d", &n, &a, &b, &c, &d);

  char s[200005];  scanf("%s", s);
  int ans = 1;

  if(c > d){
    int flag = 0;
    for(int i=2; i<d; i++)
      if(s[i-2]=='.' && s[i-1]=='.' && s[i]=='.'){
	flag = 1;
	break;
      }
    if(!flag){
      printf("No\n");
      return 0;
    }
  }

  for(int i=1; i<min(c, d); i++)
    if(s[i-1]=='#' && s[i]=='#'){
      ans = 0;
      break;
    }

  printf("%s\n", (ans ? "Yes" : "No"));
  return 0;
}