Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
int main(void){
    // Your code here!
    int N,A,B,C,D;
    char S[200001];
    int twocount = 0, threecount = 0, twoflag = 0, threeflag = 0;
    scanf("%d %d %d %d %d",&N,&A,&B,&C,&D);
    scanf("%s",S);
    
    for(int i = A-1; i < B-1 && twoflag == 0; i++)
    {
        if(S[i] == '#')
        {
            twocount++;
            if(twocount >= 2)
                twoflag = 1;
        }
        else
        {
            twocount = 0;
        }
    }
    
    for(int i = B-1; i <= D-1 && twoflag == 0; i++)
    {
        if(S[i] == '#')
        {
            threecount = 0;
            twocount++;
            if(twocount >= 2)
                twoflag = 1;
        }
        else
        {
            twocount = 0;
            threecount++;
            if(threecount >= 3)
                threeflag = 1;
        }
    }
    
    if(C>D)
        printf("%s\n",(threeflag == 1 && twoflag == 0)? "Yes":"No");
    else
        printf("%s\n",(twoflag == 0)? "Yes":"No");
}