Problem:
Score : 200 points

Problem Statement

The word internationalization is sometimes abbreviated to i18n.
This comes from the fact that there are 18 letters between the first i and the last n.

You are given a string s of length at least 3 consisting of lowercase English letters.
Abbreviate s in the same way.

Constraints

3 ≤ |s| ≤ 100 (|s| denotes the length of s.)

s consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s

Output

Print the abbreviation of s.

Sample Input 1

internationalization

Sample Output 1

i18n

Sample Input 2

smiles

Sample Output 2

s4s

Sample Input 3

xyz

Sample Output 3

x1z

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

#include<stdio.h>

int main()
{
  char s[100],t,u[10];
  int a;
  int i;
  a=0;
  scanf("%s",s);
  for(i=1;i<=100;i++){
    if(s[i+1]>0){
      a++;
    } else{
      t=s[i];
      break;
    }
  }
  
  printf("%c",s[0]);
  printf("%d",a);
  printf("%c",t);
  return 0;     
}