Problem:
Score : 400 points

Problem Statement

Given are integers A, B, and N.

Find the maximum possible value of floor(Ax/B) - A × floor(x/B) for a non-negative integer x not greater than N.

Here floor(t) denotes the greatest integer not greater than the real number t.

Constraints

1 ≤ A ≤ 10^{6}

1 ≤ B ≤ 10^{12}

1 ≤ N ≤ 10^{12}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B N

Output

Print the maximum possible value of floor(Ax/B) - A × floor(x/B) for a non-negative integer x not greater than N, as an integer.

Sample Input 1

5 7 4

Sample Output 1

2

When x=3, floor(Ax/B)-A×floor(x/B) = floor(15/7) - 5×floor(3/7) = 2. This is the maximum value possible.

Sample Input 2

11 10 9

Sample Output 2

9

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

#include<stdio.h>

int main(void){
    long int A,B,N;
    scanf("%ld %ld %ld",&A,&B,&N);
    double width=(double)B/A;    
    if(width<1){
        if(N<B){
            long int ans=N*A/B;
            printf("%ld\n",ans);
        }else{
            long int ans=(B-1)*A/B;
            printf("%ld\n",ans);
        }
    }else{
        if(N<B){
            long int ans=N*A/B;
            printf("%ld\n",ans);
        }else{
            printf("%ld\n",A-1);
        }
    }
    return 0;
}