Problem:
Score : 200 points

Problem Statement

Find the number of palindromic numbers among the integers between A and B (inclusive).
Here, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.

Constraints

10000 \leq A \leq B \leq 99999

All input values are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the number of palindromic numbers among the integers between A and B (inclusive).

Sample Input 1

11009 11332

Sample Output 1

4

There are four integers that satisfy the conditions: 11011, 11111, 11211 and 11311.

Sample Input 2

31415 92653

Sample Output 2

612

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
int PN(int A,int B){
  int i;
  int a,b,c,d,f,e;
  int count=0;
  for(i=A;i<=B;i++){
    a=i/1000;
    b=i/100;
    c=i-b*100;
    d=c/10;
    f=c-10*d;
    e=10*f+d;
    if(a==e){
      count++;
    }
  }
  return count;

}
int main(){
  int A,B;
  scanf("%d%d",&A,&B);
  printf("%d",PN(A,B));
}