Problem:
Score : 300 points

Problem Statement

You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

1 \leq |S| \leq 2 \times 10^5

|S| = |T|

S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S and T can be made equal, print Yes; otherwise, print No.

Sample Input 1

azzel
apple

Sample Output 1

Yes

azzel can be changed to apple, as follows:

Choose e as c_1 and l as c_2. azzel becomes azzle.

Choose z as c_1 and p as c_2. azzle becomes apple.

Sample Input 2

chokudai
redcoder

Sample Output 2

No

No sequences of operation can change chokudai to redcoder.

Sample Input 3

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu

Sample Output 3

Yes

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
#include <string.h>

main(){
    int cnt;
    char a[200001],b[200001];
    scanf("%s%s",a,b);

    int flg[26];
    for (int i = 0; i < 26; ++i)flg[i]=0;
    for (int i = 0; i < strlen(a); ++i) {
        if(a[i]==b[i])flg[a[i]-97]=1;
    }
    for (int i = 0; i < strlen(a); ++i) {
        if(a[i]!=b[i] &&(flg[a[i]-97]==1 || flg[b[i]-97]==1)){
            printf("No");
            return 0;
        }
    }

    printf("Yes");
}