Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
int main(void)
{
    int n,h,m,w;
    scanf("%d",&n);
    h=n/4+1;
    if(n*h/(4*h-n)==0)
        m=w=n*h*2/(4*h-n);
    else if((4*h-n)==2)
    m=w=n*h;
    else if(((4*h-n)==3)&&(n*h%2==0)){
        m= n*h/2;
        w=n*h;
    }
    else {
        m=(n*h)*(n*h+3)/2;
        w=(n*h)*(n*h+3);
    }
    printf("%d %d %d",h,m,w);
}