Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>

int main()
{
    int N,sub;
    int i,k=0,l=0;
    scanf("%d",&N);
    if(N%2==0){
        N=N-1;
    }

    for(sub=N;sub>1;sub-=2){
        for(i=1;i<=sub;i++){
            if(sub%i==0){
                k++;
            }
        }

        if(k==8){
            l++;
        }
        
        k = 0;
    }

    printf("%d",l);
    return 0;
}