Problem:
Score : 400 points

Problem Statement

Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.

You are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.

Constraints

2 ≦ |s| ≦ 10^5

s consists of lowercase letters.

Partial Score

200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.

Input

The input is given from Standard Input in the following format:

s

Output

If there exists no unbalanced substring of s, print -1 -1.

If there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.

Sample Input 1

needed

Sample Output 1

2 5

The string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.

Sample Input 2

atcoder

Sample Output 2

-1 -1

The string atcoder contains no unbalanced substring.

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

#include <stdio.h>

char s[100001];

int main(void)
{
	int n;
	char a, b, c;

	a = 0;
	b = 1;
	c = 2;

	scanf("%s", s);
	for (n = 0; s[n]; ++n)
	{
		a = s[n];
		if (a == b || a == c || b == c)
		{
			if (n < 2)
			{
				printf("1 2\n");
			}
			else
			{
				printf("%d %d\n", n - 1, n + 1);
			}
			return 0;
		}
		c = b;
		b = a;
	}

	printf("-1 -1\n");

	return 0;
}