Problem:
Score : 200 points

Problem Statement

You are given strings s and t, consisting of lowercase English letters.
You will create a string s' by freely rearranging the characters in s.
You will also create a string t' by freely rearranging the characters in t.
Determine whether it is possible to satisfy s' < t' for the lexicographic order.

Notes

For a string a = a_1 a_2 ... a_N of length N and a string b = b_1 b_2 ... b_M of length M, we say a < b for the lexicographic order if either one of the following two conditions holds true:

N < M and a_1 = b_1, a_2 = b_2, ..., a_N = b_N.

There exists i (1 \leq i \leq N, M) such that a_1 = b_1, a_2 = b_2, ..., a_{i - 1} = b_{i - 1} and a_i < b_i. Here, letters are compared using alphabetical order.

For example, xy < xya and atcoder < atlas.

Constraints

The lengths of s and t are between 1 and 100 (inclusive).

s and t consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s
t

Output

If it is possible to satisfy s' < t', print Yes; if it is not, print No.

Sample Input 1

yx
axy

Sample Output 1

Yes

We can, for example, rearrange yx into xy and axy into yxa. Then, xy < yxa.

Sample Input 2

ratcode
atlas

Sample Output 2

Yes

We can, for example, rearrange ratcode into acdeort and atlas into tslaa. Then, acdeort < tslaa.

Sample Input 3

cd
abc

Sample Output 3

No

No matter how we rearrange cd and abc, we cannot achieve our objective.

Sample Input 4

w
ww

Sample Output 4

Yes

Sample Input 5

zzz
zzz

Sample Output 5

No

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main(){
  char s[101];
  char t[101];
  char tmp;
  int i, j;
 
  scanf("%s",s);
  scanf("%s",t);
  
  for(i=0;i<(int)strlen(s)-1;i++){
    for(j=i+1;j<(int)strlen(s);j++){
      if(s[i] > s[j]){
        tmp = s[i];
        s[i] = s[j];
        s[j] = tmp;
      }
    }
  }
  for(i=0;i<(int)strlen(t)-1;i++){
    for(j=i+1;j<(int)strlen(t);j++){
      if(t[i] < t[j]){
        tmp = t[i];
        t[i] = t[j];
        t[j] = tmp;
      }
    }
  }
  if(strcmp(s,t)<0)
    printf("Yes\n");
  else
    printf("No\n");
  
  return 0;
}