Problem:
Score : 700 points

Problem Statement

N problems are proposed for an upcoming contest. Problem i has an initial integer score of A_i points.

M judges are about to vote for problems they like. Each judge will choose exactly V problems, independently from the other judges,
and increase the score of each chosen problem by 1.

After all M judges cast their vote, the problems will be sorted in non-increasing order of score, and the first P problems will be chosen for the problemset.
Problems with the same score can be ordered arbitrarily, this order is decided by the chief judge.

How many problems out of the given N have a chance to be chosen for the problemset?

Constraints

2 \le N \le 10^5

1 \le M \le 10^9

1 \le V \le N - 1

1 \le P \le N - 1

0 \le A_i \le 10^9

Input

Input is given from Standard Input in the following format:

N M V P
A_1 A_2 ... A_N

Output

Print the number of problems that have a chance to be chosen for the problemset.

Sample Input 1

6 1 2 2
2 1 1 3 0 2

Sample Output 1

5

If the only judge votes for problems 2 and 5, the scores will be 2 2 1 3 1 2.
The problemset will consist of problem 4 and one of problems 1, 2, or 6.

If the only judge votes for problems 3 and 4, the scores will be 2 1 2 4 0 2.
The problemset will consist of problem 4 and one of problems 1, 3, or 6.

Thus, problems 1, 2, 3, 4, and 6 have a chance to be chosen for the problemset. On the contrary, there is no way for problem 5 to be chosen.

Sample Input 2

6 1 5 2
2 1 1 3 0 2

Sample Output 2

3

Only problems 1, 4, and 6 have a chance to be chosen.

Sample Input 3

10 4 8 5
7 2 3 6 1 6 5 4 6 5

Sample Output 3

8

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
#include<stdlib.h>
int asc(const void* a, const void* b)
{
	if (*(long long int*)a < * (long long int*)b)return 1;
	if (*(long long int*)a > * (long long int*)b)return -1;
	return 0;
}
long long int h[100005], l;
long long int d[100005];
void swap_h(long long int a, long long int b)
{
	long long int f = h[a];
	h[a] = h[b];
	h[b] = f;
	return;
}
int comp_h(long long int a, long long int b)
{
	a = h[a];
	b = h[b];
	if (d[a] > d[b])return 1;
	if (d[a] < d[b])return -1;
	return 0;
}
void f1(long long int n)
{
	h[l] = n;
	long long int now = l;
	l++;
	while (now > 0)
	{
		if (comp_h((now - 1) / 2, now) > 0)
			swap_h((now - 1) / 2, now);
		now = (now - 1) / 2;
	}
	return;
}
long long int f2()
{
	long long int res = h[0];
	l--;
	h[0] = h[l];
	long long int now = 0;
	for (;;)
	{
		if (2 * now + 2 < l)
		{
			if (comp_h(2 * now + 1, 2 * now + 2) > 0)
			{
				if (comp_h(now, 2 * now + 2) > 0)
					swap_h(now, 2 * now + 2);
				now = 2 * now + 2;
			}
			else
			{
				if (comp_h(now, 2 * now + 1) > 0)
					swap_h(now, 2 * now + 1);
				now = 2 * now + 1;
			}
		}
		else if (2 * now + 1 < l)
		{
			if (comp_h(now, 2 * now + 1) > 0)
				swap_h(now, 2 * now + 1);
			now = 2 * now + 1;
		}
		else
			break;
	}
	return res;
}
int main()
{
	long long int n, m, v, p;
	scanf("%lld %lld %lld %lld", &n, &m, &v, &p);
	long long int i;
	long long int a[100005];
	for (i = 0; i < n; i++)
		scanf("%lld", &a[i]);
	qsort(a, n, sizeof(long long int), asc);
	long long int min, mid, max;
	if (v <= p)
	{
		min = 0;
		max = n;
		while (max - min > 1)
		{
			mid = (max + min) / 2;
			if (a[mid] + m < a[p - 1])
				max = mid;
			else
				min = mid;
		}
		printf("%lld\n", max);
		return 0;
	}
	min = p;
	max = n;
	long long int c, q;
	while (max - min > 1)
	{
		mid = (max + min) / 2;
		if (a[mid] + m < a[p - 1])
		{
			max = mid;
			continue;
		}
		if (mid + v <= n)
		{
			min = mid;
			continue;
		}
		if (v - n + mid < p)
		{
			min = mid;
			continue;
		}
		c = v - n + mid - p + 1;
		l = 0;
		for (i = 0; i < c; i++)
			d[i] = 0;
		for (i = 0; i < c; i++)
			f1(i);
		for (i = mid - 1; i >= p && a[i] < a[mid] + m; i--)
		{
			q = f2();
			d[q] += a[mid] + m - a[i];
			f1(q);
		}
		q = 0;
		for (i = 0; i < c; i++)
			if (d[i] < m)
				q++;
		if (q > 0)
			max = mid;
		else
			min = mid;
	}
	printf("%lld\n", max);
	return 0;
}