Problem:
Score : 100 points

Problem Statement

Given is an integer N.

Takahashi chooses an integer a from the positive integers not greater than N with equal probability.

Find the probability that a is odd.

Constraints

1 \leq N \leq 100

Input

Input is given from Standard Input in the following format:

N

Output

Print the probability that a is odd.
Your output will be considered correct when its absolute or relative error from the judge's output is at most 10^{-6}.

Sample Input 1

4

Sample Output 1

0.5000000000

There are four positive integers not greater than 4: 1, 2, 3, and 4. Among them, we have two odd numbers: 1 and 3. Thus, the answer is \frac{2}{4} = 0.5.

Sample Input 2

5

Sample Output 2

0.6000000000

Sample Input 3

1

Sample Output 3

1.0000000000

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>

int main(void){

  int i;
  int N;
  int K;
  int count;

  scanf("%d %d", &N, &K);
  int h[N];

  for(i = 1; i <= N; i++){

    scanf("%d", &h[i - 1]);
  }

  count = 0;

  for(i = 1; i <= N; i++){

    if(h[i - 1] >= K){
      count = count + 1;
    }
  }

  printf("%d", count);

  return 0;
}