Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in C (judge verdict: Time Limit Exceeded)

#include <stdio.h>
#include <string.h>
#include <ctype.h>

int main(void)
{
	char dat[1200];
	int abc[123]={0};
	int i,j;
	
	while (scanf("%[^\n]",&dat) != EOF) {
		
		for(i=0 ; i<strlen(dat) ; i++){
			if (isalpha(dat[i])) { //
				if (isupper(dat[i])) {
					abc[tolower(dat[i])]++;
				}
				else {
					abc[dat[i]]++;
				}
			}
		}
	}
	for(i='a' ; i<= 'z' ; i++){
		printf("%c : %d\n",i,abc[i]);
	}
	
	return 0;
}