Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in C (judge verdict: Time Limit Exceeded)

#include<stdio.h>

int chAlpha(char);

int main(){
	
	char ch[1201],al=0,a;
	int alpha[26],i,b;
	
	for(i=0;i<26;i++){
	alpha[i]=0;
	}
	
	al+='a';
	
	while(1){
		for(i=0;;i++){
		scanf("%c",&ch[i]);
		if(ch[i]=='\n')break;
		b=chAlpha(ch[i]);
		alpha[b]++;
	}

	for(i=0;i<26;i++)
		printf("%c : %d\n",al+i,alpha[i]);
	}
return 0;
}

int chAlpha(char ch){
	int diff='a'-'A';
	if(ch>='a'&&ch<='z')ch-=diff;
	ch-='A';
	return ch;
}