Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
int main(){
  long long int N,h,n,w;
  scanf("%lld",&N);
  w=(N*h*n)/(4*h*n-N*(n+h));
  for (h=1;h<=3500;h++){
    for (n=1;n<=3500;n++){
      if(4*h*n-N*(n+h)>0 && (N*h*n)%(4*h*n-N*(n+h))==0){
          printf("%lld %lld %lld",n,h,w);
          return 0;
        }
      }
    }
}