Problem:
Score : 200 points

Problem Statement

Tak performed the following action N times: rolling two dice.
The result of the i-th roll is D_{i,1} and D_{i,2}.

Check if doublets occurred at least three times in a row.
Specifically, check if there exists at lease one i such that D_{i,1}=D_{i,2}, D_{i+1,1}=D_{i+1,2} and D_{i+2,1}=D_{i+2,2} hold.

Constraints

3 \leq N \leq 100

1\leq D_{i,j} \leq 6

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
D_{1,1} D_{1,2}
\vdots
D_{N,1} D_{N,2}

Output

Print Yes if doublets occurred at least three times in a row. Print No otherwise.

Sample Input 1

5
1 2
6 6
4 4
3 3
3 2

Sample Output 1

Yes

From the second roll to the fourth roll, three doublets occurred in a row.

Sample Input 2

5
1 1
2 2
3 4
5 5
6 6

Sample Output 2

No

Sample Input 3

6
1 1
2 2
3 3
4 4
5 5
6 6

Sample Output 3

Yes

Solution in C (Clang 10.0.0) (judge verdict: Wrong Answer)

#include<stdio.h>
#include<string.h>
int main()
{
int i;
int N;
int D1;
int D2;
int count=0;
int clear=0;
int flag=0;

scanf("%d",&N);
for(i=1;i<N;i++){
scanf("%d %d",&D1,&D2);
if(D1==D2 && count == 0 && clear==0 ){count=1; clear=1;}
else if(D1==D2 && count == 1 && clear==1 ){count=2;}  
else if(D1==D2 && count == 2 && clear==1 ){count=3;flag=1;}
else{ clear=0;}
}

if(flag==1){printf("Yes");}
else{printf("No");}
return 0;
}