Problem:
Score : 200 points

Problem Statement

There is a rectangle in the xy-plane, with its lower left corner at (0, 0) and its upper right corner at (W, H). Each of its sides is parallel to the x-axis or y-axis. Initially, the whole region within the rectangle is painted white.

Snuke plotted N points into the rectangle. The coordinate of the i-th (1 ≦ i ≦ N) point was (x_i, y_i).

Then, he created an integer sequence a of length N, and for each 1 ≦ i ≦ N, he painted some region within the rectangle black, as follows:

If a_i = 1, he painted the region satisfying x < x_i within the rectangle.

If a_i = 2, he painted the region satisfying x > x_i within the rectangle.

If a_i = 3, he painted the region satisfying y < y_i within the rectangle.

If a_i = 4, he painted the region satisfying y > y_i within the rectangle.

Find the area of the white region within the rectangle after he finished painting.

Constraints

1 ≦ W, H ≦ 100

1 ≦ N ≦ 100

0 ≦ x_i ≦ W (1 ≦ i ≦ N)

0 ≦ y_i ≦ H (1 ≦ i ≦ N)

W, H (21:32, added), x_i and y_i are integers.

a_i (1 ≦ i ≦ N) is 1, 2, 3 or 4.

Input

The input is given from Standard Input in the following format:

W H N
x_1 y_1 a_1
x_2 y_2 a_2
:
x_N y_N a_N

Output

Print the area of the white region within the rectangle after Snuke finished painting.

Sample Input 1

5 4 2
2 1 1
3 3 4

Sample Output 1

9

The figure below shows the rectangle before Snuke starts painting.

First, as (x_1, y_1) = (2, 1) and a_1 = 1, he paints the region satisfying x < 2 within the rectangle:

Then, as (x_2, y_2) = (3, 3) and a_2 = 4, he paints the region satisfying y > 3 within the rectangle:

Now, the area of the white region within the rectangle is 9.

Sample Input 2

5 4 3
2 1 1
3 3 4
1 4 2

Sample Output 2

0

It is possible that the whole region within the rectangle is painted black.

Sample Input 3

10 10 5
1 6 1
4 1 3
6 9 4
9 4 2
3 1 3

Sample Output 3

64

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>

int main () {

  int W, H, N;

  scanf("%d %d %d", &W, &H, &N);

  int map[100][100] = {};

  int i, j;
  
  for (i=0; i<H; i++) {
    for (j=0; j<W; j++) {
      map[i][j] = 1;
    }
  }


  int w, h, a;

  int x, y;
  
  for (i=0; i<N; i++) {

    scanf("%d %d %d", &w, &h, &a);

    switch (a) {
    case 1:
      for (y=0; y<H; y++) {
	for (x=0; x<w; x++) {
	  map[y][x] = 0;
	}
      }
      break;

    case 2:
      for (y=0; y<H; y++) {
	for (x=W; x>=w; x--) {
	  map[y][x] = 0;
	}
      }
      break;
      
    case 3:
      for (y=0; y<h; y++) {
	for (x=0; x<W; x++) {
	  map[y][x] = 0;
	}
      }
      break;
      
    case 4:
      for (y=H; y>h; y--) {
	for (x=0; x<=W; x++) {
	  map[y][x] = 0;
	}
      }
      break;
    }

  }

  int result = 0;

  for(y=0; y<H; y++) {
    for(x=0; x<W; x++) {
      if (map[x][y] == 1) result++;
    }
  }

  printf("%d\n", result);

  return 0;
}