Problem:
Score : 100 points

Problem Statement

A biscuit making machine produces B biscuits at the following moments: A seconds, 2A seconds, 3A seconds and each subsequent multiple of A seconds after activation.

Find the total number of biscuits produced within T + 0.5 seconds after activation.

Constraints

All values in input are integers.

1 \leq A, B, T \leq 20

Input

Input is given from Standard Input in the following format:

A B T

Output

Print the total number of biscuits produced within T + 0.5 seconds after activation.

Sample Input 1

3 5 7

Sample Output 1

10

Five biscuits will be produced three seconds after activation.

Another five biscuits will be produced six seconds after activation.

Thus, a total of ten biscuits will be produced within 7.5 seconds after activation.

Sample Input 2

3 2 9

Sample Output 2

6

Sample Input 3

20 20 19

Sample Output 3

0

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
#include <ctype.h>
#include <string.h>
#include <math.h>

#define SWAP(a, b) a = a ^ b; b = a ^ b; a = a ^ b

void swap(int * a, int * b)
{
    int temp = *a;
    *a = *b;
    *b = temp;
}

void print_int(int n)
{
    printf("%d\n",n);
    
}

void sort(int a[], int n)
{
    int h, i, j;

    for(h = 1; h < n / 9; h = h * 3 + 1)
        continue;

    for(; h > 0; h /= 3)
    {
        for(i = h; i < n; i++)
        {
            j = i;
            while(j >= h && a[j] < a[j-h])
            {
                swap(&a[j], &a[j-h]);
                j -= h;
            }
        }
    }
}

void print_list(int a[], int n)
{
    for(int i = 0; i < n; i++)
    {
        printf("%d ", a[i]);
    }
}

void intcpy(int a[], const int b[], int count)
{
    for(int i = 0; i < count; i++)
    {
        a[i] = b[i];
    }
}

int list_sum(int a[], int n)
{
    int sum = 0;

    for(int i = 0; i < n; i++)
    {
        sum += a[i];
    }

    return sum;
}


void permutate(int s[], int count, int n)
{
    if(n == count)
        return;

    for(int i = n; i < count; i++)
    {
        swap(&s[i], &s[n]);

        if(i != n)
        {
            //intcpy(result[j++], s, count);
        }
        
        permutate(s, count, n+1);
        swap(&s[i], &s[n]);
    }
}



int main(void)
{
    int a, b, t, result = 0;
    scanf("%d %d %d", &a, &b, &t);
    for (int i = a; i <= t; i += a)
    {
        result += b;
    }
    print_int(result);
    
    
    return 0;
}