Problem:
Score : 100 points

Problem Statement

AtCoDeer has three cards, one red, one green and one blue.

An integer between 1 and 9 (inclusive) is written on each card: r on the red card, g on the green card and b on the blue card.

We will arrange the cards in the order red, green and blue from left to right, and read them as a three-digit integer.

Is this integer a multiple of 4?

Constraints

1 ≤ r, g, b ≤ 9

Input

Input is given from Standard Input in the following format:

r g b

Output

If the three-digit integer is a multiple of 4, print YES (case-sensitive); otherwise, print NO.

Sample Input 1

4 3 2

Sample Output 1

YES

432 is a multiple of 4, and thus YES should be printed.

Sample Input 2

2 3 4

Sample Output 2

NO

234 is not a multiple of 4, and thus NO should be printed.

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>

int main(void) {
	int N = 0;
	int a[4801];
	int hai = 0, tya = 0, midori = 0, mizu = 0, ao = 0, ki = 0, daidai = 0, aka = 0, over = 0;
	int kinds = 0, max = 0;

	scanf("%d", &N);
	for (int i = 0; i < N; i++) {
		scanf("%d", &a[i]);
		switch (a[i] / 400) {
		case 0:	hai++;
				break;

		case 1:	tya++;
				break;

		case 2:	midori++;
				break;

		case 3:	mizu++;
				break;

		case 4:	ao++;
				break;

		case 5:	ki++;
				break;

		case 6:	daidai++;
				break;

		case 7:	aka++;
				break;

		default:over++;
				break;
		}
	}

	if (hai > 0)	kinds++;
	if (tya > 0)	kinds++;
	if (midori > 0)	kinds++;
	if (mizu > 0)	kinds++;
	if (ao > 0)		kinds++;
	if (ki > 0)		kinds++;
	if (daidai > 0)	kinds++;
	if (aka > 0)	kinds++;

	max = kinds + over;
	if (max > 7)max = 7;

	printf("%d %d", kinds, max);

	return 0;
}