Problem:
Score : 100 points

Problem Statement

You are given two positive integers a and b.
Let x be the average of a and b.
Print x rounded up to the nearest integer.

Constraints

a and b are integers.

1 \leq a, b \leq 100

Input

Input is given from Standard Input in the following format:

a b

Output

Print x rounded up to the nearest integer.

Sample Input 1

1 3

Sample Output 1

2

The average of 1 and 3 is 2.0, and it will be rounded up to the nearest integer, 2.

Sample Input 2

7 4

Sample Output 2

6

The average of 7 and 4 is 5.5, and it will be rounded up to the nearest integer, 6.

Sample Input 3

5 5

Sample Output 3

5

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
#include <math.h>
// 入力a,bの平均値の小数点以下を切上げた値を出力
int main(void) {
  int a, b, c;
  // scanfで入力を読み込み
  scanf("%d%d", &a, &b);
  // 平均値の計算 ceil:小数点を切上げる関数
  c = ceil((a+b) / 2.0);
  // 答えの出力
  printf("%d\n", c);
  return 0;
}