Problem:
Score : 200 points

Problem Statement

The word internationalization is sometimes abbreviated to i18n.
This comes from the fact that there are 18 letters between the first i and the last n.

You are given a string s of length at least 3 consisting of lowercase English letters.
Abbreviate s in the same way.

Constraints

3 ≤ |s| ≤ 100 (|s| denotes the length of s.)

s consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s

Output

Print the abbreviation of s.

Sample Input 1

internationalization

Sample Output 1

i18n

Sample Input 2

smiles

Sample Output 2

s4s

Sample Input 3

xyz

Sample Output 3

x1z

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

/* ex 6-2
    kas056 */

#include <stdio.h>
#include <string.h>

#define SIZE 1000

int main(void){
    int mid; //間の数は入力した文字の長さ－2
    char omission[SIZE];

    scanf("%s", omission);
    int length = strlen(omission);//入力の読込後、長さ測定

    mid = length - 2;//midの大きさは(長さ-2)

    if(mid < 1){//midが0以下ならエラー
        fprintf(stderr, "unexpected characters: %s", omission);
    }

    else{//ヌル文字でない最後の文字は、omission[length - 1]に入っている。
        printf("%c%d%c\n",omission[0], mid, omission[length - 1]);
        
    }

    return 0;

}