Problem:
Merge Sort

Write a program of a Merge Sort algorithm implemented by the following pseudocode. You should also report the number of comparisons in the Merge function.

Merge(A, left, mid, right)
n1 = mid - left;
n2 = right - mid;
create array L[0...n1], R[0...n2]
for i = 0 to n1-1
do L[i] = A[left + i]
for i = 0 to n2-1
do R[i] = A[mid + i]
L[n1] = SENTINEL
R[n2] = SENTINEL
i = 0;
j = 0;
for k = left to right-1
if L[i] <= R[j]
then A[k] = L[i]
i = i + 1
else A[k] = R[j]
j = j + 1

Merge-Sort(A, left, right){
if left+1 < right
then mid = (left + right)/2;
call Merge-Sort(A, left, mid)
call Merge-Sort(A, mid, right)
call Merge(A, left, mid, right)

Input

In the first line n is given. In the second line, n integers are given.

Output

In the first line, print the sequence S. Two consequtive elements should be separated by a space character.

In the second line, print the number of comparisons.

Constraints

n ≤ 500000

0 ≤ an element in S ≤ 109

Sample Input 1

10
8 5 9 2 6 3 7 1 10 4

Sample Output 1

1 2 3 4 5 6 7 8 9 10
34

Notes

Solution in C (judge verdict: Wrong Answer)

#include <stdio.h>
#define N 500000
#define INFTY 1000000
void mergesort(int,int);
void merge(int,int,int);

int count=0,S[N];

int main(){
  int i,n;
 
  scanf("%d",&n);
  for(i=0;i<n;i++){
    scanf("%d",&S[i]);
  }
  mergesort(0,n);
  for(i=0;i<n;i++){
    printf("%d",S[i]);
    if(i<n-1)  printf(" ");
  }
  printf("\n");
  printf("%d\n",count);
  return 0;

}
 

void merge(int left,int mid,int right){

  int x,y,L[N],R[N],i,j,k;

  x = mid - left;
  y = right - mid;

  for(i=0;i<x;i++){
    L[i]=S[left+i];
  }
  for(i=0;i<y;i++){
    R[i]=S[mid+i];
  }
  L[x]=INFTY;
  R[y]=INFTY;
  i=0;
  j=0;


  for(k=left;k<right;k++){
    if(L[i]<=R[j]){
      S[k]=L[i];
      i++;
    }
    else{
      S[k]=R[j];
      j++;
    }
    count++;
  }
}


void mergesort(int left,int right){
  int mid;
  if(left+1<right){
    mid = (left+right)/2;
    mergesort(left,mid);
    mergesort(mid,right);
    merge(left,mid,right);
  }
}