Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
#include<math.h>
int main(void){
  double n;
  int i,j,count=0,ans=0;

  scanf("%lf",&n);

  for(j=1;j<n;j++){
    count=0;
    ans=0;
    for(i=1;i<sqrt(n);i++){
      if(j%i==0){
	count++;
      }
    }
    if(count==4){
      ans++;
    }
  }

  printf("%d\n",ans);

  return 0;
}