Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>

int main(){
  int n;
  int a;
  int b;
  int c;
  int d;
  char str[300000] = {};
  int i = 0;
  int flag = 1;
  int three = 0;
  scanf("%d %d %d %d %d",&n,&a,&b,&c,&d);
  scanf(" %s",str);
  if(c < d){
    three = 1;
    for(i=a-1;i<d;i++){
      if(str[i] == '#' && str[i+1] == '#'){
        flag = 0;
      }
    }
  }else{
    for(i=a-1;i<c;i++){
      if(str[i] == '#' && str[i+1] == '#'){
        flag = 0;
      }
    }
    for(i=b-1;i<c;i++){
      if(str[i] == '.' && str[i+1] == '.' && str[i+2] == '.'){
        three = 1;
      }
    }
    if(b-2>=0){
      if(str[b-2] == '.' && str[b] == '.'){
        three = 1;
      }
    }
   
  }
  
  if(three && flag){
    printf("Yes");
  }else{
    printf("No");
  }
  return 0;
}