Problem:
Disjoint Set

Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.

same(x, y): determine whether x and y are in the same set.

Input

n q
com1 x1 y1
com2 x2 y2
...
comq xq yq

In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Constraints

1 ≤ n ≤ 10000

1 ≤ q ≤ 100000

x ≠ y

Sample Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0

Sample Output

0
0
1
1
1
0
1
1

Solution in C (judge verdict: Accepted)

// AOJ DSL_1 A Set - Disjoint Set: Union Find Tree
// 2017.10.31 bal4u@uu

#include <stdio.h>

#define MAX 10002
/* UNION-FIND library */
int p[MAX], rank[MAX];
void make_set(int x) { p[x] = x, rank[x] = 0; }
void link(int x, int y) {
	if (rank[x] > rank[y]) p[y] = x;
	else { p[x] = y; if (rank[x] == rank[y]) rank[y] = rank[y] + 1;	}
}
int find_set(int x) { if (x != p[x]) p[x] = find_set(p[x]);	return p[x]; }
void union_set(int x, int y) { link(find_set(x), find_set(y)); }

int main()
{
	int n, q, i;
	int cmd, x, y;

	scanf("%d%d", &n, &q);
	for (i = 1; i <= n; i++) make_set(i);
	for (i = 0; i < q; i++) {
		scanf("%d%d%d", &cmd, &x, &y);
		if (cmd == 0) union_set(x, y);
		else printf("%d\n", find_set(x) == find_set(y));
	}
	return 0;
}