Problem:
Score : 200 points

Problem Statement

Find the number of palindromic numbers among the integers between A and B (inclusive).
Here, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.

Constraints

10000 \leq A \leq B \leq 99999

All input values are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the number of palindromic numbers among the integers between A and B (inclusive).

Sample Input 1

11009 11332

Sample Output 1

4

There are four integers that satisfy the conditions: 11011, 11111, 11211 and 11311.

Sample Input 2

31415 92653

Sample Output 2

612

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
int main()
{
    int i,x,y,j,a[100];
    scanf("%d%d",&x,&y);


        for(i=x,j=0;i<=y;i++)
        {
           a[0] = i/10000;
           a[1] = i/1000%10;
           a[2] = i/100%10;
           a[3] = i/10%10;
           a[4] = i%10;

           if(a[0] == a[4]&&a[1] == a[3])
           {
              j++;
           }
        }
          printf("%d\n",j);

     return 0;
}