Problem:
Score : 100 points

Problem Statement

Cat Snuke is learning to write characters.
Today, he practiced writing digits 1 and 9, but he did it the other way around.

You are given a three-digit integer n written by Snuke.
Print the integer obtained by replacing each digit 1 with 9 and each digit 9 with 1 in n.

Constraints

111 \leq n \leq 999

n is an integer consisting of digits 1 and 9.

Input

Input is given from Standard Input in the following format:

n

Output

Print the integer obtained by replacing each occurrence of 1 with 9 and each occurrence of 9 with 1 in n.

Sample Input 1

119

Sample Output 1

991

Replace the 9 in the ones place with 1, the 1 in the tens place with 9 and the 1 in the hundreds place with 9. The answer is 991.

Sample Input 2

999

Sample Output 2

111

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
int main(void){
    // Your code here!
    
    int n;
    scanf("%d",&n);
    
    int i,p[4],r;
    
    for(i=0;i<3;++i){
        
        r = n%10;
        n = n/10;
        p[i] = r;
        
    }
    
    
    for(i=0; i<3;++i){
        
        if(p[i] == 1)  p[i] = 9;
        else if (p[i] == 9) p[i] = 1;
        
    }
    
    printf("%d%d%d",p[2],p[1],p[0]);
    
    
    return 0;
}