Problem:
Score : 100 points

Problem Statement

You have three tasks, all of which need to be completed.

First, you can complete any one task at cost 0.

Then, just after completing the i-th task, you can complete the j-th task at cost |A_j - A_i|.

Here, |x| denotes the absolute value of x.

Find the minimum total cost required to complete all the task.

Constraints

All values in input are integers.

1 \leq A_1, A_2, A_3 \leq 100

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

Print the minimum total cost required to complete all the task.

Sample Input 1

1 6 3

Sample Output 1

5

When the tasks are completed in the following order, the total cost will be 5, which is the minimum:

Complete the first task at cost 0.

Complete the third task at cost 2.

Complete the second task at cost 3.

Sample Input 2

11 5 5

Sample Output 2

6

Sample Input 3

100 100 100

Sample Output 3

0

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
#define len(array) (sizeof(array) / sizeof(int))

void sort(int *array, int len) {
	int i, j, temp;
	for (i = 0; i < len; i++) {
		for (j = 0; j < len - 1 - i; j++) {
			if (array[j] > array[j + 1]) {
				temp = array[j];
				array[j] = array[j + 1];
				array[j + 1] = temp;
			}
		}
	}
}

int main(void) {
	int array[3];
	scanf("%d%d%d", &array[0], &array[1], &array[2]);
	sort(array, len(array));
	printf("%d", array[2] - array[0]);
}