Problem:
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Maximum Profit

You can obtain profits from foreign exchange margin transactions. For example, if you buy 1000 dollar at a rate of 100 yen per dollar, and sell them at a rate of 108 yen per dollar, you can obtain (108 - 100) × 1000 = 8000 yen.

Write a program which reads values of a currency $R_t$ at a certain time $t$ ($t = 0, 1, 2, ... n-1$), and reports the maximum value of $R_j - R_i$ where $j > i$ .

Input

The first line contains an integer $n$. In the following $n$ lines, $R_t$ ($t = 0, 1, 2, ... n-1$) are given in order.

Output

Print the maximum value in a line.

Constraints

$2 \leq n \leq 200,000$

$1 \leq R_t \leq 10^9$

Sample Input 1

6
5
3
1
3
4
3

Sample Output 1

3

Sample Input 2

3
4
3
2

Sample Output 2

-1

Solution in C (judge verdict: Accepted)

#include<stdio.h>

int main(){
  int j,i,n,min,max;
  int a[200000];
  
  scanf("%d",&n);

  for(i=0;i<n;i++) scanf("%d",&a[i]); //配列に入力

  min = a[0]; 
  max = a[1] - min;
  
  for(j=1;j<n;j++){ // 利益の算出
    if(a[j-1]<min)
      min = a[j-1];
    if(max < a[j] - min)
      max = a[j] - min;
  }
  
  printf("%d\n",max);

  

  return 0;
}