Problem:
Score : 300 points

Problem Statement

There is an empty array.
The following N operations will be performed to insert integers into the array.
In the i-th operation (1≤i≤N), b_i copies of an integer a_i are inserted into the array.
Find the K-th smallest integer in the array after the N operations.
For example, the 4-th smallest integer in the array \{1,2,2,3,3,3\} is 3.

Constraints

1≤N≤10^5

1≤a_i,b_i≤10^5

1≤K≤b_1…+…b_n

All input values are integers.

Input

Input is given from Standard Input in the following format:

N K
a_1 b_1
:
a_N b_N

Output

Print the K-th smallest integer in the array after the N operations.

Sample Input 1

3 4
1 1
2 2
3 3

Sample Output 1

3

The resulting array is the same as the one in the problem statement.

Sample Input 2

10 500000
1 100000
1 100000
1 100000
1 100000
1 100000
100000 100000
100000 100000
100000 100000
100000 100000
100000 100000

Sample Output 2

1

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

/*2019/08/25 */
#include<stdio.h>
#include<stdlib.h>
#include<math.h>
#include<string.h>
#define MOD 1000000007
#define MIN 999999999
#define MAX -999999999
typedef long long int ll;
typedef unsigned long long int ull;
void llswap(ll *x,ll *y){ll temp;temp=*x;*x=*y;*y=temp;}
void swap(int *x,int *y){int tmp;tmp=*x;*x=*y;*y=tmp;}
int rmax(int x,int y){return x>y?x:y;}
int rmin(int x,int y){return x>y?y:x;}
ll llrmax(ll x,ll y){return x>y?x:y;}
ll llrmin(ll x,ll y){return x>y?y:x;}
int asc(const void *a,const void *b){return *(int*)a-*(int*)b;}
int desc(const void *a,const void *b){return *(int*)b-*(int*)a;}
int llasc(const void *a,const void *b){return *(ll*)a-*(ll*)b;}
int lldesc(const void *a,const void *b){return *(ll*)b-*(ll*)a;}
/*
int asc_t(const void *a,const void *b){return ((struct_t*)a)->member - ((struct_t*)b)->member;}
int desc_t(const void *a,const void *b){return ((struct_t*)b)->member - ((struct_t*)a)->member;}
*/

int main(){
    ll n,k;
    static ll a[200000],b[200000];
    static ll num[200000]={};

    scanf("%lld %lld",&n,&k);
    for(int i=0;i<n;i++){
        scanf("%lld %lld",&a[i],&b[i]);
        num[a[i]-1]+=b[i];
    }

    ll cnt=0;
    for(int i=0;i<100000;i++){
        cnt+=num[i];
        if(cnt>=k){
            printf("%d\n",i+1);
            return 0;
        }
    }
    return 0;
}