Problem:
Score : 200 points

Problem Statement

The word internationalization is sometimes abbreviated to i18n.
This comes from the fact that there are 18 letters between the first i and the last n.

You are given a string s of length at least 3 consisting of lowercase English letters.
Abbreviate s in the same way.

Constraints

3 ≤ |s| ≤ 100 (|s| denotes the length of s.)

s consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s

Output

Print the abbreviation of s.

Sample Input 1

internationalization

Sample Output 1

i18n

Sample Input 2

smiles

Sample Output 2

s4s

Sample Input 3

xyz

Sample Output 3

x1z

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
#include<string.h>


int main() {
char s[100];
scanf("%s", s);
int i;
int f;
char b;
for(i=0;i<=strlen(s);i++){
  if(s[i]>=65&&s[i]<=90)
    s[i]=s[i]+32;
    b = s[i-1];
}

char a = s[0];

i = i-3;
printf("%c%d%c\n",a,i,b);

return 0;


}