Problem:
Score : 200 points

Problem Statement

Determine if an N-sided polygon (not necessarily convex) with sides of length L_1, L_2, ..., L_N can be drawn in a two-dimensional plane.

You can use the following theorem:

Theorem: an N-sided polygon satisfying the condition can be drawn if and only if the longest side is strictly shorter than the sum of the lengths of the other N-1 sides.

Constraints

All values in input are integers.

3 \leq N \leq 10

1 \leq L_i \leq 100

Input

Input is given from Standard Input in the following format:

N
L_1 L_2 ... L_N

Output

If an N-sided polygon satisfying the condition can be drawn, print Yes; otherwise, print No.

Sample Input 1

4
3 8 5 1

Sample Output 1

Yes

Since 8 < 9 = 3 + 5 + 1, it follows from the theorem that such a polygon can be drawn on a plane.

Sample Input 2

4
3 8 4 1

Sample Output 2

No

Since 8 \geq 8 = 3 + 4 + 1, it follows from the theorem that such a polygon cannot be drawn on a plane.

Sample Input 3

10
1 8 10 5 8 12 34 100 11 3

Sample Output 3

No

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

#include<stdio.h>
int main(void)
{   
    int N,L[10];
    int i,j,tmp,S=0;
  
    scanf("%d",&N);
    
    for(i=0;i<N;i++)
      scanf("%d",&L[i]);
  
    for(i=0;i<N;i++){
      for(j=i+1;j<N;j++){
        if(L[i]>L[j]){
          tmp=L[i];
          L[i]=L[j];
          L[j]=tmp;
        }
      }
    }
  
    for(i=0;i<N-1;i++)
      S+=L[i];
    
    if(S>L[N-1]) printf("Yes\n");
    else printf("No\n");
  
    return 0;
}