Problem:
Score : 200 points

Problem Statement

A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.

How many times will the ball make a bounce where the coordinate is at most X?

Constraints

1 \leq N \leq 100

1 \leq L_i \leq 100

1 \leq X \leq 10000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N X
L_1 L_2 ... L_{N-1} L_N

Output

Print the number of times the ball will make a bounce where the coordinate is at most X.

Sample Input 1

3 6
3 4 5

Sample Output 1

2

The ball will make a bounce at the coordinates 0, 3, 7 and 12, among which two are less than or equal to 6.

Sample Input 2

4 9
3 3 3 3

Sample Output 2

4

The ball will make a bounce at the coordinates 0, 3, 6, 9 and 12, among which four are less than or equal to 9.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
#include <stdbool.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>
typedef long long int ll;
#define mod 1000000007
#define rep(i, n) for(int i = 0; i < (int)(n); i++)
#define rep1(i, n) for(int i = 1; i < (int)(n); i++)
#define m0(x) memset(x,0,sizeof(x))

//qsort用(昇順，降順)
int cmp_asc( const void *p, const void *q ) {
    return *(int*)p - *(int*)q;
}
int cmp_desc( const void *p, const void *q ) {
    return *(int*)q - *(int*)p;
}

int main(void){
	int n,x;
	scanf("%d%d",&n,&x);
	int l[n];
	rep(i,n) scanf("%d",&l[i]);
	int count=1,now=0;
	rep(i,n){
		now+=l[i];
		if(now>x) break;
		else count++;
	}
	printf("%d\n",count);
	return 0;
}