Problem:
Score : 200 points

Problem Statement

In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.

It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.

Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.

Assume also that the depth of the snow cover is always at least 1 meter.

Constraints

1 \leq a < b < 499500(=1+2+3+...+999)

All values in input are integers.

There is no input that contradicts the assumption.

Input

Input is given from Standard Input in the following format:

a b

Output

If the depth of the snow cover is x meters, print x as an integer.

Sample Input 1

8 13

Sample Output 1

2

The heights of the two towers are 10 meters and 15 meters, respectively.
Thus, we can see that the depth of the snow cover is 2 meters.

Sample Input 2

54 65

Sample Output 2

1

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

/* ex4_3
	kanon */

#include <stdio.h>
#include <math.h>

//n番目の塔の高さを求める
int calculate_height(int height_a,int height_b);

int main(void)
{

    //与えられる値を入れる数を宣言
    int height_a,height_b;

    //変数に値を入力する
    scanf("%d %d",&height_a,&height_b);
    
    int ans=calculate_height(height_a,height_b);
    printf("%d",ans);

    return 0;
}

int calculate_height(int height_a,int height_b){
    int snow_height=0;
    //高さの差を計算する
    int diff=height_b-height_a;
    //diff-1番目の塔ーheight_a＝求める雪の高さ
    for(int i=1;i<diff;i++){
        snow_height+=i;
    }
    return snow_height-height_a;
}