Problem:
Score : 200 points

Problem Statement

Given is an integer N. Find the number of digits that N has in base K.

Notes

For information on base-K representation, see Positional notation - Wikipedia.

Constraints

All values in input are integers.

1 \leq N \leq 10^9

2 \leq K \leq 10

Input

Input is given from Standard Input in the following format:

N K

Output

Print the number of digits that N has in base K.

Sample Input 1

11 2

Sample Output 1

4

In binary, 11 is represented as 1011.

Sample Input 2

1010101 10

Sample Output 2

7

Sample Input 3

314159265 3

Sample Output 3

18

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

/*  ex3_3
    L40S38  */
#include<stdio.h>
int main(void){
    int n, k, r, digit;
    scanf("%d %d",&n, &k);
    //整数nをk進法で表す
    r=n;
    digit=0;
    while(r>0){
        //rはnをkでdigit回割ったときの商
        digit ++;
        r=r/k;
    }
    printf("%d",digit);
    return 0;
}