Problem:
Score : 100 points

Problem Statement

You have three tasks, all of which need to be completed.

First, you can complete any one task at cost 0.

Then, just after completing the i-th task, you can complete the j-th task at cost |A_j - A_i|.

Here, |x| denotes the absolute value of x.

Find the minimum total cost required to complete all the task.

Constraints

All values in input are integers.

1 \leq A_1, A_2, A_3 \leq 100

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

Print the minimum total cost required to complete all the task.

Sample Input 1

1 6 3

Sample Output 1

5

When the tasks are completed in the following order, the total cost will be 5, which is the minimum:

Complete the first task at cost 0.

Complete the third task at cost 2.

Complete the second task at cost 3.

Sample Input 2

11 5 5

Sample Output 2

6

Sample Input 3

100 100 100

Sample Output 3

0

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
int main(void){

	int A,B,C;
	
	scanf("%d%d%d",&A,&B,&C);
	
	if(A<=B && B<=C){
		printf("%d",(B-A)+(C-B));
	
	}else if(B<=A && A<=C){
		printf("%d",(A-B)+(C-B));
		
	}else if(A<=C && C<=B){
		printf("%d",(C-A)+(B-C));
		
	}else if(B<=C && C<=A){
		printf("%d",(C-B)+(A-C));
		
	}else if(C<=B && B<=A){
		printf("%d",(B-C)+(A-B));
	
	}else if(C<=A && A<=B){
		printf("%d",(A-C)+(B-A));
	}
	return 0;
}