Problem:
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Maximum Profit

You can obtain profits from foreign exchange margin transactions. For example, if you buy 1000 dollar at a rate of 100 yen per dollar, and sell them at a rate of 108 yen per dollar, you can obtain (108 - 100) × 1000 = 8000 yen.

Write a program which reads values of a currency $R_t$ at a certain time $t$ ($t = 0, 1, 2, ... n-1$), and reports the maximum value of $R_j - R_i$ where $j > i$ .

Input

The first line contains an integer $n$. In the following $n$ lines, $R_t$ ($t = 0, 1, 2, ... n-1$) are given in order.

Output

Print the maximum value in a line.

Constraints

$2 \leq n \leq 200,000$

$1 \leq R_t \leq 10^9$

Sample Input 1

6
5
3
1
3
4
3

Sample Output 1

3

Sample Input 2

3
4
3
2

Sample Output 2

-1

Solution in C (judge verdict: Accepted)

#include<stdio.h>
#define MAX 200000

int main(){
  int i,n=0,r[MAX];
  int maxvalue=-2000000000;
  //int minivalue;

  scanf("%d",&n);

  for(i=0;i<n;i++){
    scanf("%d",&r[i]);
  }

  int minivalue=r[0];

  for(i=1;i<n;i++){
    if(maxvalue<r[i]-minivalue){
      maxvalue=r[i]-minivalue;
    }
    //else maxvalue=maxvalue;

    if(minivalue>r[i]){
       minivalue=r[i];
       // minivalue=minivalue;
    }
    // else minivalue=r[i];
  }

  printf("%d\n",maxvalue);

  return 0;
}