Problem:
Score : 200 points

Problem Statement

There are N cities and M roads.
The i-th road (1≤i≤M) connects two cities a_i and b_i (1≤a_i,b_i≤N) bidirectionally.
There may be more than one road that connects the same pair of two cities.
For each city, how many roads are connected to the city?

Constraints

2≤N,M≤50

1≤a_i,b_i≤N

a_i ≠ b_i

All input values are integers.

Input

Input is given from Standard Input in the following format:

N M
a_1 b_1
:
a_M b_M

Output

Print the answer in N lines.
In the i-th line (1≤i≤N), print the number of roads connected to city i.

Sample Input 1

4 3
1 2
2 3
1 4

Sample Output 1

2
2
1
1

City 1 is connected to the 1-st and 3-rd roads.

City 2 is connected to the 1-st and 2-nd roads.

City 3 is connected to the 2-nd road.

City 4 is connected to the 3-rd road.

Sample Input 2

2 5
1 2
2 1
1 2
2 1
1 2

Sample Output 2

5
5

Sample Input 3

8 8
1 2
3 4
1 5
2 8
3 7
5 2
4 1
6 8

Sample Output 3

3
3
2
2
2
1
1
2

Solution in C (GCC 5.4.1) (judge verdict: Runtime Error)

#include <stdio.h>
int main(){

  int n,m,a[50]={0},h=0,result,i,j,blank;

  scanf("%d %d",&n,&m);
  m *= 2;

  for(i	= 0; i < m; i++) scanf("%d",&a[i]);

  for(i	= 0; i < m-1; i++){

    for(j = 0; j < m-1; j++){

      if(a[j] > a[j+1]){

        blank=a[j];
        a[j]=a[j+1];
        a[j+1]=blank;

      }

    }

  }

  //for(i = 0; i < m; i++) printf("%d ",a[i]);                                                                                 

  for(i = 0; i < n; i++){

    result=0;
    for(j = h; a[j] == a[h]; j++) result++;
    h=j;
    printf("%d\n",result);

  }

  return 0;

}