Problem:
Score : 200 points

Problem Statement

We have a string S consisting of uppercase English letters. Additionally, an integer N will be given.

Shift each character of S by N in alphabetical order (see below), and print the resulting string.

We assume that A follows Z. For example, shifting A by 2 results in C (A \to B \to C), and shifting Y by 3 results in B (Y \to Z \to A \to B).

Constraints

0 \leq N \leq 26

1 \leq |S| \leq 10^4

S consists of uppercase English letters.

Input

Input is given from Standard Input in the following format:

N
S

Output

Print the string resulting from shifting each character of S by N in alphabetical order.

Sample Input 1

2
ABCXYZ

Sample Output 1

CDEZAB

Note that A follows Z.

Sample Input 2

0
ABCXYZ

Sample Output 2

ABCXYZ

Sample Input 3

13
ABCDEFGHIJKLMNOPQRSTUVWXYZ

Sample Output 3

NOPQRSTUVWXYZABCDEFGHIJKLM

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>
int main(){
	int n;
	char a[10001];
	scanf("%d %s",&n,a);
	char b[26] = {'A','B','C','D','E','F','G','H','I','J','K','L','M','N',
	'O','P','Q','R','S','T','U','V','W','X','Y','Z'};
	for(int i=0;i<strlen(a);i++){
		for(int j=0;j<26;j++){
			if(a[i]==b[j]){
				if(j+n>=26)
					printf("%c",b[j+n-26]);
				else
					printf("%c",b[j+n]);
			}
		}
	}
	puts("");

	return 0;
}