Problem:
Score : 200 points

Problem Statement

Find the number of palindromic numbers among the integers between A and B (inclusive).
Here, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.

Constraints

10000 \leq A \leq B \leq 99999

All input values are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the number of palindromic numbers among the integers between A and B (inclusive).

Sample Input 1

11009 11332

Sample Output 1

4

There are four integers that satisfy the conditions: 11011, 11111, 11211 and 11311.

Sample Input 2

31415 92653

Sample Output 2

612

Solution in C (GCC 5.4.1) (judge verdict: Time Limit Exceeded)

#include <stdio.h>
int main(){
	int N, K,num;
	int ans = 0;
	scanf("%d %d", &N, &K);
	if(K>N){
		num = K;
		K = N;
		N = num;  //大小の調整
	}
	for (int a = 0; a < (N - K) / 2;a--){
		for (int b = 0; b < (N - K) / 2;b++){
			if(K+b == N-a)
				ans++;
		}
	}
	printf("%d", ans);
	return 0;
}