Problem:
Score : 200 points

Problem Statement

Tak performed the following action N times: rolling two dice.
The result of the i-th roll is D_{i,1} and D_{i,2}.

Check if doublets occurred at least three times in a row.
Specifically, check if there exists at lease one i such that D_{i,1}=D_{i,2}, D_{i+1,1}=D_{i+1,2} and D_{i+2,1}=D_{i+2,2} hold.

Constraints

3 \leq N \leq 100

1\leq D_{i,j} \leq 6

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
D_{1,1} D_{1,2}
\vdots
D_{N,1} D_{N,2}

Output

Print Yes if doublets occurred at least three times in a row. Print No otherwise.

Sample Input 1

5
1 2
6 6
4 4
3 3
3 2

Sample Output 1

Yes

From the second roll to the fourth roll, three doublets occurred in a row.

Sample Input 2

5
1 1
2 2
3 4
5 5
6 6

Sample Output 2

No

Sample Input 3

6
1 1
2 2
3 3
4 4
5 5
6 6

Sample Output 3

Yes

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<stdbool.h>
#include<math.h>
#include<limits.h>

typedef long long ll;

int max(int a,int b){
    if(a>b) return a;
    else return b;
}

int min(int a,int b){
    if(a<b) return a;
    else return b;
}

/*qsort(array,num_of_index,sizeof(int),compare_int); */
 int compare_int(const void *a,const void *b){
     return *(int*) a - *(int *) b; 
 } 
 
int main(){
    int N;
    scanf("%d",&N);
    int Di[102],Dj[102];
    int f[102];
    for(int i=1;i<=N;i++){
        scanf("%d %d",Di+i,Dj+i);
        if(Di[i] == Dj[i])
            f[i] = 1;
        else
            f[i] = 0;
    }
    int len = 0,ans = 0;
    for(int i=1;i<=N;i++){
        if(f[i])
            len++;
        else
            len = 0;
        if(len >= 3)
            ans = 1;
    }
    if(ans)
        printf("Yes");
    else
        printf("No");
}