Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in C (judge verdict: Time Limit Exceeded)

#include<stdio.h>
#include<string.h>

int main (void){
	int s=0,i,n=0;
	char c[1010];
	while(1){
		scanf("%s",&c);
		if(c[0]=='0'){
			break;
		}
		n=strlen(c);
		for(i=0;i<n;i++){
			s+=c[i]-'0';
		}
		printf("%d\n",s);
		s=0;
		n=0;
	}
	return 0;
}