Problem:
Score : 200 points

Problem Statement

You are given a string S. Each character of S is uppercase or lowercase English letter.
Determine if S satisfies all of the following conditions:

The initial character of S is an uppercase A.

There is exactly one occurrence of C between the third character from the beginning and the second to last character (inclusive).

All letters except the A and C mentioned above are lowercase.

Constraints

4 ≤ |S| ≤ 10 (|S| is the length of the string S.)

Each character of S is uppercase or lowercase English letter.

Input

Input is given from Standard Input in the following format:

S

Output

If S satisfies all of the conditions in the problem statement, print AC; otherwise, print WA.

Sample Input 1

AtCoder

Sample Output 1

AC

The first letter is A, the third letter is C and the remaining letters are all lowercase, so all the conditions are satisfied.

Sample Input 2

ACoder

Sample Output 2

WA

The second letter should not be C.

Sample Input 3

AcycliC

Sample Output 3

WA

The last letter should not be C, either.

Sample Input 4

AtCoCo

Sample Output 4

WA

There should not be two or more occurrences of C.

Sample Input 5

Atcoder

Sample Output 5

WA

The number of C should not be zero, either.

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

/* ABC104: B
Sの先頭の文字は大文字の A である。
Sの先頭から 3 文字目と末尾から 2 文字目の間（両端含む）に大文字の C がちょうど 1
個含まれる。
以上の A, C を除く Sのすべての文字は小文字である。
	*/

#include <stdio.h>
#include <string.h>

void wa(void){
	printf("WA\n");
	exit(0);
}

int main(void){
	char str[12];
	int sl;
	int i;
	int count=0;
	
	scanf("%s", str);
	
	sl = strlen(str)-1; // abcde\n => 6 - 1 => 5
	///  cd を調べる　2- (sl-1)
	
	if (str[0] != 'A') wa();
	for(i=2; i<sl-1; i++) {
		if (str[i] == 'C') count++;
	}
	if (count!=1) wa();
	count=0;
	for(i=0; i<sl; i++){
		if (i==0 && str[i] == 'A' || 2<=i && i<=sl-2 && str[i] == 'C' || 'a' <= str[i] && str[i] <= 'z') {
			count++;
		}
	}
	if (count != sl) wa();
	printf("AC\n");
	
	return 0;
}