Problem:
Score : 200 points

Problem Statement

Raccoon is fighting with a monster.

The health of the monster is H.

Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i.
There is no other way to decrease the monster's health.

Raccoon wins when the monster's health becomes 0 or below.

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Constraints

1 \leq H \leq 10^9

1 \leq N \leq 10^5

1 \leq A_i \leq 10^4

All values in input are integers.

Input

Input is given from Standard Input in the following format:

H N
A_1 A_2 ... A_N

Output

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Sample Input 1

10 3
4 5 6

Sample Output 1

Yes

The monster's health will become 0 or below after, for example, using the second and third moves.

Sample Input 2

20 3
4 5 6

Sample Output 2

No

Sample Input 3

210 5
31 41 59 26 53

Sample Output 3

Yes

Sample Input 4

211 5
31 41 59 26 53

Sample Output 4

No

Solution in C (GCC 5.4.1) (judge verdict: Time Limit Exceeded)

#include <stdio.h>
int main(void){
    // Your code here!
    int h,a[100000],n;
    int g;
    scanf("%d%d",&h,&n);
    for(int i=0;i<n;i++)scanf("%d",&a[i]);
    for(int i=0;i<n-1;i++){
        for(int j=i+1;j<n;j++){
            if(a[i]<a[j]){
                g=a[i];
                a[i]=a[j];
                a[j]=g;
            }
        }
    }
    for(int i=0;i<n;i++)h-=a[i];
    if(h<=0)printf("Yes\n");
    else printf("No\n");
    return 0;
}