Problem:
Bubble Sort

Write a program of the Bubble Sort algorithm which sorts a sequence A in ascending order. The algorithm should be based on the following pseudocode:

BubbleSort(A)
1 for i = 0 to A.length-1
2 for j = A.length-1 downto i+1
3 if A[j] < A[j-1]
4 swap A[j] and A[j-1]

Note that, indices for array elements are based on 0-origin.

Your program should also print the number of swap operations defined in line 4 of the pseudocode.

Input

The first line of the input includes an integer N, the number of elements in the sequence.

In the second line, N elements of the sequence are given separated by spaces characters.

Output

The output consists of 2 lines.

In the first line, please print the sorted sequence. Two contiguous elements of the sequence should be separated by a space character.

In the second line, please print the number of swap operations.

Constraints

1 ≤ N ≤ 100

Sample Input 1

5
5 3 2 4 1

Sample Output 1

1 2 3 4 5
8

Sample Input 2

6
5 2 4 6 1 3

Sample Output 2

1 2 3 4 5 6
9

Solution in C (judge verdict: Time Limit Exceeded)

#include<stdio.h>
#define MAX 100
int number[MAX] = {0};
void bubbleSort(int *, int);

int main(){
    int n, i;

    scanf("%d\n", &n);

    scanf("%d", number);
    for(i = 1; i < n ; i++) {
        scanf(" %d", number + i);  
    }
    bubbleSort(number, n);

}

void bubbleSort(int *a, int n){
    int flag = 1;
    int t;    
    int i;
    int temp = 0;
    while(flag){
        flag = 0;
        for(i = n - 1; i > 0; i--) {
            if(*(a + i - 1) > *(a + i)){
                t = *(a + i);
                *(a + i) = *(a + i + 1);
                *(a + i + 1) = t;
                flag = 1;
                temp++;
            }
        }
    }
    for(i = 0; i < n - 1; i++){
        printf("%d ", *(a + i));
    }
    printf("%d\n", *(a + n - 1));
    printf("%d\n", temp);
}