Problem:
Score : 200 points

Problem Statement

There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is R, and a blue hat if s_i is B.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

1 \leq N \leq 100

|s| = N

s_i is R or B.

Input

Input is given from Standard Input in the following format:

N
s

Output

If there are more people wearing a red hat than there are people wearing a blue hat, print Yes; otherwise, print No.

Sample Input 1

4
RRBR

Sample Output 1

Yes

There are three people wearing a red hat, and one person wearing a blue hat.

Since there are more people wearing a red hat than people wearing a blue hat, the answer is Yes.

Sample Input 2

4
BRBR

Sample Output 2

No

There are two people wearing a red hat, and two people wearing a blue hat.

Since there are as many people wearing a red hat as people wearing a blue hat, the answer is No.

Solution in C (Clang 3.8.0) (judge verdict: Accepted)

/*redorblue*/
#import<stdio.h>
int main(void){
    int N, i, Rnumber = 0, Bnumber = 0;
    char s[100];

    scanf("%d", &N);
    scanf("%s", s);
    for(i = 0; i < N; i++){

    if(s[i] == 'R'){
        Rnumber += 1;
    }else{
        Bnumber += 1;
    }
    }

    if(Rnumber > Bnumber){
        printf("Yes\n");
    }else{
        printf("No\n");
    }
    return 0;
}