Problem:
Score : 300 points

Problem Statement

Sitting in a station waiting room, Joisino is gazing at her train ticket.

The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).

In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.

The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Constraints

0≤A,B,C,D≤9

All input values are integers.

It is guaranteed that there is a solution.

Input

Input is given from Standard Input in the following format:

ABCD

Output

Print the formula you made, including the part =7.

Use the signs + and -.

Do not print a space between a digit and a sign.

Sample Input 1

1222

Sample Output 1

1+2+2+2=7

This is the only valid solution.

Sample Input 2

0290

Sample Output 2

0-2+9+0=7

0 - 2 + 9 - 0 = 7 is also a valid solution.

Sample Input 3

3242

Sample Output 3

3+2+4-2=7

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
int main()
{
    char a[10];
    while(~scanf("%s",a))
    {
        if((a[0]-'0')+(a[1]-'0')+(a[2]-'0')+(a[3]-'0')==7)
        {
            printf("%c+%c+%c+%c=7\n",a[0],a[1],a[2],a[3]);
        }
        else if((a[0]-'0')+(a[1]-'0')+(a[2]-'0')-(a[3]-'0')==7)
        {
            printf("%c+%c+%c-%c=7\n",a[0],a[1],a[2],a[3]);
        }
        else if((a[0]-'0')+(a[1]-'0')-(a[2]-'0')-(a[3]-'0')==7)
        {
            printf("%c+%c-%c-%c=7\n",a[0],a[1],a[2],a[3]);
        }
        else if((a[0]-'0')-(a[1]-'0')-(a[2]-'0')-(a[3]-'0')==7)
        {
            printf("%c-%c-%c-%c=7\n",a[0],a[1],a[2],a[3]);
        }
        else if((a[0]-'0')+(a[1]-'0')-(a[2]-'0')+(a[3]-'0')==7)
        {
            printf("%c+%c-%c+%c=7\n",a[0],a[1],a[2],a[3]);
        }
        else if((a[0]-'0')-(a[1]-'0')-(a[2]-'0')+(a[3]-'0')==7)
        {
            printf("%c-%c-%c+%c=7\n",a[0],a[1],a[2],a[3]);
        }
        else if((a[0]-'0')-(a[1]-'0')+(a[2]-'0')-(a[3]-'0')==7)
        {
            printf("%c-%c+%c-%c=7\n",a[0],a[1],a[2],a[3]);
        }
        else if((a[0]-'0')-(a[1]-'0')+(a[2]-'0')+(a[3]-'0')==7)
        {
            printf("%c-%c+%c+%c=7\n",a[0],a[1],a[2],a[3]);
        }
        else{break;}
    }
    return 0;
}