Problem:
Score : 200 points

Problem Statement

We have a string S consisting of uppercase English letters. Additionally, an integer N will be given.

Shift each character of S by N in alphabetical order (see below), and print the resulting string.

We assume that A follows Z. For example, shifting A by 2 results in C (A \to B \to C), and shifting Y by 3 results in B (Y \to Z \to A \to B).

Constraints

0 \leq N \leq 26

1 \leq |S| \leq 10^4

S consists of uppercase English letters.

Input

Input is given from Standard Input in the following format:

N
S

Output

Print the string resulting from shifting each character of S by N in alphabetical order.

Sample Input 1

2
ABCXYZ

Sample Output 1

CDEZAB

Note that A follows Z.

Sample Input 2

0
ABCXYZ

Sample Output 2

ABCXYZ

Sample Input 3

13
ABCDEFGHIJKLMNOPQRSTUVWXYZ

Sample Output 3

NOPQRSTUVWXYZABCDEFGHIJKLM

Solution in C (GCC 5.4.1) (judge verdict: Runtime Error)

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main(void){
 
  int N;

  char str[1000];
 
  /* 英数字を入力 */
  scanf("%d", &N);
  scanf("%s", str);
 
  /* アルファベットの小文字を大文字に変換 */
  for(int i=0;i<=strlen(str);i++){
    /* アルファベットの小文字なら変換 */
    if(str[i]>=65 && str[i]<=90)
      str[i] = str[i] + N;
      if (str[i] >= 91) {
        str[i] -= 26;
      }
  }
  /* 変換した文字列を出力 */
  printf("%s\n", str);
 
  return 0;
}