Problem:
Merge Sort

Write a program of a Merge Sort algorithm implemented by the following pseudocode. You should also report the number of comparisons in the Merge function.

Merge(A, left, mid, right)
n1 = mid - left;
n2 = right - mid;
create array L[0...n1], R[0...n2]
for i = 0 to n1-1
do L[i] = A[left + i]
for i = 0 to n2-1
do R[i] = A[mid + i]
L[n1] = SENTINEL
R[n2] = SENTINEL
i = 0;
j = 0;
for k = left to right-1
if L[i] <= R[j]
then A[k] = L[i]
i = i + 1
else A[k] = R[j]
j = j + 1

Merge-Sort(A, left, right){
if left+1 < right
then mid = (left + right)/2;
call Merge-Sort(A, left, mid)
call Merge-Sort(A, mid, right)
call Merge(A, left, mid, right)

Input

In the first line n is given. In the second line, n integers are given.

Output

In the first line, print the sequence S. Two consequtive elements should be separated by a space character.

In the second line, print the number of comparisons.

Constraints

n ≤ 500000

0 ≤ an element in S ≤ 109

Sample Input 1

10
8 5 9 2 6 3 7 1 10 4

Sample Output 1

1 2 3 4 5 6 7 8 9 10
34

Notes

Solution in C (judge verdict: Accepted)

#include<stdio.h>
#define MAX 500000
#define INF 1000000001
int n,count,S[MAX];

void merge(int left,int right,int mid){
  int n1,n2,i,j,k,s1[MAX/2+2],s2[MAX/2+2];
  n1=mid-left;
  n2=right-mid;
  for(i=0;i<n1;i++) s1[i]=S[left+i];
  for(i=0;i<n2;i++) s2[i]=S[mid+i];
  i=j=0;
  s1[n1]=s2[n2]=INF;
  for(k=left;k<right;k++){
    count++;
      if(s1[i]>s2[j]) S[k]=s2[j++];
      else S[k]=s1[i++];
  }
}
void mergesort(int left,int right){
  int mid;
  if(left+1<right){
    mid=(left+right)/2;
    mergesort(left,mid);
    mergesort(mid,right);
    merge(left,right,mid);
  }
}

int main(){
  int i;
  scanf("%d",&n);
  for(i=0;i<n;i++) scanf("%d",&S[i]);

  mergesort(0,n);
  for(i=0;i<n;i++){
    if(i>0) printf(" ");
    printf("%d",S[i]);
  }
  printf("\n%d\n",count);
  return 0;
}