Problem:
Score : 300 points

Problem Statement

You are given four integers A, B, C, and D. Find the number of integers between A and B (inclusive) that can be evenly divided by neither C nor D.

Constraints

1\leq A\leq B\leq 10^{18}

1\leq C,D\leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B C D

Output

Print the number of integers between A and B (inclusive) that can be evenly divided by neither C nor D.

Sample Input 1

4 9 2 3

Sample Output 1

2

5 and 7 satisfy the condition.

Sample Input 2

10 40 6 8

Sample Output 2

23

Sample Input 3

314159265358979323 846264338327950288 419716939 937510582

Sample Output 3

532105071133627368

Solution in C (GCC 5.4.1) (judge verdict: Runtime Error)

#include "stdio.h"

int main(void){
  long long A, B, C, D;

  int count = 0;

  scanf("%lld",&A);
  scanf("%lld",&B);
  scanf("%lld",&C);
  scanf("%lld",&D);

  long long number_C[B - A];

  long long number_D[B - A];

  for (long long  i = 0; i <= B - A; i++) {
    number_C[i] = (A  + i) % C;

    number_D[i] = (A + i) % D;
  }

  for(long long j = 0; j <= B - A; j++){
    if(number_C[j]  != 0 && number_D[j] != 0){
      count++;
    }
  }

  printf("%d\n", count);
}