Problem:
Score : 200 points

Problem Statement

Find the number of palindromic numbers among the integers between A and B (inclusive).
Here, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.

Constraints

10000 \leq A \leq B \leq 99999

All input values are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the number of palindromic numbers among the integers between A and B (inclusive).

Sample Input 1

11009 11332

Sample Output 1

4

There are four integers that satisfy the conditions: 11011, 11111, 11211 and 11311.

Sample Input 2

31415 92653

Sample Output 2

612

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>

int main(int argc, char *argv[]) {
    int a, b;
    int cnt = 0;

    scanf("%d%d", &a, &b);

    for (int i = a; i <= b; i++) {
        if ((i / 10000 % 10 == i % 10) && (i / 1000 % 10 == i / 10 % 10)) cnt++; 
    }

    printf("%d\n", cnt);

    return 0;
}