Problem:
Score : 200 points

Problem Statement

Given is an integer N. Find the number of digits that N has in base K.

Notes

For information on base-K representation, see Positional notation - Wikipedia.

Constraints

All values in input are integers.

1 \leq N \leq 10^9

2 \leq K \leq 10

Input

Input is given from Standard Input in the following format:

N K

Output

Print the number of digits that N has in base K.

Sample Input 1

11 2

Sample Output 1

4

In binary, 11 is represented as 1011.

Sample Input 2

1010101 10

Sample Output 2

7

Sample Input 3

314159265 3

Sample Output 3

18

Solution in C (GCC 5.4.1) (judge verdict: Accepted)


/*
 * kadai3_3
 * kamecha
 */
#include<stdio.h>

int main(void){
    int num, kurai;
    scanf("%d %d", &num, &kurai);
    /*
     * 何桁かを求めれば良いので何回割れるかを求めればOK
     */
    int ans = 0;
    while(num > 0){
        num /= kurai;
        ans++;
    }
    printf("%d\n", ans);
    return 0;
}