Problem:
Score : 100 points

Problem Statement

An elementary school student Takahashi has come to a variety store.

He has two coins, A-yen and B-yen coins (yen is the currency of Japan), and wants to buy a toy that costs C yen. Can he buy it?

Note that he lives in Takahashi Kingdom, and may have coins that do not exist in Japan.

Constraints

All input values are integers.

1 \leq A, B \leq 500

1 \leq C \leq 1000

Input

Input is given from Standard Input in the following format:

A B C

Output

If Takahashi can buy the toy, print Yes; if he cannot, print No.

Sample Input 1

50 100 120

Sample Output 1

Yes

He has 50 + 100 = 150 yen, so he can buy the 120-yen toy.

Sample Input 2

500 100 1000

Sample Output 2

No

He has 500 + 100 = 600 yen, but he cannot buy the 1000-yen toy.

Sample Input 3

19 123 143

Sample Output 3

No

There are 19-yen and 123-yen coins in Takahashi Kingdom, which are rather hard to use.

Sample Input 4

19 123 142

Sample Output 4

Yes

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
int main(){
    int A,B,C;
    scanf("%d %d %d", &A, &B, &C);
    if(A+B>=C){
        if((A!=1)&&(A!=5)&&(A!=10)&&(A!=50)&&(A!=100)&&(A!=500)&&(B!=1)&&(B!=5)&&(B!=10)&&(B!=50)&&(B!=100)&&(B!=500)){
            printf("No\n");
        }
        else if((A!=1)&&(A!=5)&&(A!=10)&&(A!=50)&&(A!=100)&&(A!=500)&&(B==1)||(B==5)||(B==10)||(B==50)||(B==100)||(B==500)){
            printf("Yes\n");
        }
        else if((B!=1)&&(B!=5)&&(B!=10)&&(B!=50)&&(B!=100)&&(B!=500)&&(A==1)||(A==5)||(A==10)||(A==50)||(A==100)||(A==500)){
            printf("Yes\n");
        }
        else{
                printf("Yes\n");
        }
    }
    else{
        printf("No\n");
    }
    return 0;
}