Problem:
Score: 100 points

Problem Statement

In this problem, a date is written as Y-M-D. For example, 2019-11-30 means November 30, 2019.

Integers M_1, D_1, M_2, and D_2 will be given as input.

It is known that the date 2019-M_2-D_2 follows 2019-M_1-D_1.

Determine whether the date 2019-M_1-D_1 is the last day of a month.

Constraints

Both 2019-M_1-D_1 and 2019-M_2-D_2 are valid dates in the Gregorian calendar.

The date 2019-M_2-D_2 follows 2019-M_1-D_1.

Input

Input is given from Standard Input in the following format:

M_1 D_1
M_2 D_2

Output

If the date 2019-M_1-D_1 is the last day of a month, print 1; otherwise, print 0.

Sample Input 1

11 16
11 17

Sample Output 1

0

November 16 is not the last day of a month.

Sample Input 2

11 30
12 1

Sample Output 2

1

November 30 is the last day of November.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
int main(void)
{
    int d1,d2,m1,m2;
    scanf("%d%d",&m1,&d1);
    scanf("%d%d",&m2,&d2);

    if(m1 == 1 || m1 == 3 || m1 == 5 || m1 == 7 || m1 == 8 || m1 == 10 || m1 == 12)
    {
        if(d1 == 31)
        printf("1");
        else 
        printf("0");
    }
    else if(m1 == 2)
    {
        if(d1 == 28)
        printf("1");
        else 
        printf("0");
    }
    else
    {
        if(d1 == 30)
        printf("1");
        else
        printf("0");
    }
return 0;
}