Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
int main()
{
    long long w1,w2,h,N,n,count;
    count=0;
    scanf("%lld",&N);
    for (h=1; h<=3500; h++)
    {
        for (n=1; n<=3500; n++)
        {
            w1=N*h*n;
            w2=4*n*h-h*N-N*n;
            if(w1>0&&w2>0&&w1%w2==0)
            {
                printf("%lld %lld %lld",h,n,w1/w2);
                count++;
                break;
            }
        }
        if (count!=0)
            break;
    }
}