Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
int main(){
	int a,b,n;
	long long x,c;
	scanf("%d",&n);
	for(a=(n/4+1);a<=3500;a++){
		for(b=a*n/(4*a-n)+1;b<=50000;b++){
			x=a*b*n%(4*a*b-n*(a+b));
			c=a*b*n/(4*a*b-n*(a+b));
			if(x==0&&c>0){
				printf("%d %d %lld\n",a,b,c);
				return 0;
			}
		}
	}
	return 0;
}