Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>

int main(){
  int n,ans;
  scanf("%d", &n);
  if(n<105){ans=0;}
  if(105<=n && n<135){ans=1;}
  if(135<=n && n<165){ans=2;}
  if(165<=n && n<189){ans=3;}
  if(189<=n && n<195){ans=4;}
  if(195<=n && n<201){ans=5;}
  printf("%d",ans);
  return 0;
}