Problem:
Score : 200 points

Problem Statement

You are given strings s and t, consisting of lowercase English letters.
You will create a string s' by freely rearranging the characters in s.
You will also create a string t' by freely rearranging the characters in t.
Determine whether it is possible to satisfy s' < t' for the lexicographic order.

Notes

For a string a = a_1 a_2 ... a_N of length N and a string b = b_1 b_2 ... b_M of length M, we say a < b for the lexicographic order if either one of the following two conditions holds true:

N < M and a_1 = b_1, a_2 = b_2, ..., a_N = b_N.

There exists i (1 \leq i \leq N, M) such that a_1 = b_1, a_2 = b_2, ..., a_{i - 1} = b_{i - 1} and a_i < b_i. Here, letters are compared using alphabetical order.

For example, xy < xya and atcoder < atlas.

Constraints

The lengths of s and t are between 1 and 100 (inclusive).

s and t consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s
t

Output

If it is possible to satisfy s' < t', print Yes; if it is not, print No.

Sample Input 1

yx
axy

Sample Output 1

Yes

We can, for example, rearrange yx into xy and axy into yxa. Then, xy < yxa.

Sample Input 2

ratcode
atlas

Sample Output 2

Yes

We can, for example, rearrange ratcode into acdeort and atlas into tslaa. Then, acdeort < tslaa.

Sample Input 3

cd
abc

Sample Output 3

No

No matter how we rearrange cd and abc, we cannot achieve our objective.

Sample Input 4

w
ww

Sample Output 4

Yes

Sample Input 5

zzz
zzz

Sample Output 5

No

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <string.h>
#include <stdio.h>
#define REP(a) for(i = 0; i < a; i++)

int main(void) {
    int i,j;
    char a[105],b[105],tmp;
    scanf("%s",a);
    scanf("%s",b);
    REP(strlen(a)) {
        for (j = i + 1; j < strlen(a); j++) {
            if (a[i] > a[j]) {
                tmp = a[i];
                a[i] = a[j];
                a[j] = tmp;
            }
        }
    }
    REP(strlen(b)) {
        for (j = i + 1; j < strlen(b); j++) {
            if (b[i] < b[j]) {
                tmp = b[i];
                b[i] = b[j];
                b[j] = tmp;
            }
        }
    }
    if (strcmp(a, b) < 0) {
        printf("Yes\n");
    } else {
        printf("No\n");
    }
    return 0;
}