Problem:
Score : 200 points

Problem Statement

Tak performed the following action N times: rolling two dice.
The result of the i-th roll is D_{i,1} and D_{i,2}.

Check if doublets occurred at least three times in a row.
Specifically, check if there exists at lease one i such that D_{i,1}=D_{i,2}, D_{i+1,1}=D_{i+1,2} and D_{i+2,1}=D_{i+2,2} hold.

Constraints

3 \leq N \leq 100

1\leq D_{i,j} \leq 6

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
D_{1,1} D_{1,2}
\vdots
D_{N,1} D_{N,2}

Output

Print Yes if doublets occurred at least three times in a row. Print No otherwise.

Sample Input 1

5
1 2
6 6
4 4
3 3
3 2

Sample Output 1

Yes

From the second roll to the fourth roll, three doublets occurred in a row.

Sample Input 2

5
1 1
2 2
3 4
5 5
6 6

Sample Output 2

No

Sample Input 3

6
1 1
2 2
3 3
4 4
5 5
6 6

Sample Output 3

Yes

Solution in C (Clang 10.0.0) (judge verdict: Wrong Answer)

#include <stdio.h>
int main(void){
int gyo;
int a[100], b[100];

scanf("%d", &gyo);

int count = 0;
   
for(int i = 0; i < gyo; i++) {
    scanf("%d %d", &a[i], &b[i]);
  //  printf("%d %d\n", a[i], b[i]);
    
    if(a[i] == b[i]) {
    count = count + 1;
    }
    
    if(count >= 3)
    break;
    
    if(a[i] != b[i])
    count = 0;
   }

//printf("%d\n", count);

if(count >= 3)
printf("YES");

else
printf("NO");
   
   
}