Problem:
Score : 100 points

Problem Statement

An elementary school student Takahashi has come to a variety store.

He has two coins, A-yen and B-yen coins (yen is the currency of Japan), and wants to buy a toy that costs C yen. Can he buy it?

Note that he lives in Takahashi Kingdom, and may have coins that do not exist in Japan.

Constraints

All input values are integers.

1 \leq A, B \leq 500

1 \leq C \leq 1000

Input

Input is given from Standard Input in the following format:

A B C

Output

If Takahashi can buy the toy, print Yes; if he cannot, print No.

Sample Input 1

50 100 120

Sample Output 1

Yes

He has 50 + 100 = 150 yen, so he can buy the 120-yen toy.

Sample Input 2

500 100 1000

Sample Output 2

No

He has 500 + 100 = 600 yen, but he cannot buy the 1000-yen toy.

Sample Input 3

19 123 143

Sample Output 3

No

There are 19-yen and 123-yen coins in Takahashi Kingdom, which are rather hard to use.

Sample Input 4

19 123 142

Sample Output 4

Yes

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
#include<stdlib.h>
#include<string.h>

typedef struct {
	char str[10];
	int counta;
} AtCoderB;

int main(void){
	int num, con = 0, i = 2, j = 0;
	char str[10];
	AtCoderB *atcoderb = (AtCoderB*)malloc(sizeof(AtCoderB));
	for(; i; i--){
		scanf("%d", &num);
		for(; num; num--){
			scanf("%s", str);
			for(j = 0; j < con; j++){
				if(!strcmp(str, atcoderb[j].str)){
					i == 2 ? atcoderb[j].counta++ : atcoderb[j].counta--;
					break;
				}
			}
			if(j == con){
				atcoderb = (AtCoderB*)realloc(atcoderb, sizeof(AtCoderB)*++con);
				strcpy(atcoderb[con-1].str, str);
				atcoderb[con-1].counta = i == 2 ? 1 : -1;
			}
		}
	}
	for(j = 0;j < con; j++){
		num = atcoderb[j].counta > num ? atcoderb[j].counta : num;
	}
	printf("%d\n", num);
	return 0;
}