Problem:
Score : 300 points

Problem Statement

Takahashi is organizing a party.

At the party, each guest will receive one or more snack pieces.

Takahashi predicts that the number of guests at this party will be A or B.

Find the minimum number of pieces that can be evenly distributed to the guests in both of the cases predicted.

We assume that a piece cannot be divided and distributed to multiple guests.

Constraints

1 \leq A, B \leq 10^5

A \neq B

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the minimum number of pieces that can be evenly distributed to the guests in both of the cases with A guests and B guests.

Sample Input 1

2 3

Sample Output 1

6

When we have six snack pieces, each guest can take three pieces if we have two guests, and each guest can take two if we have three guests.

Sample Input 2

123 456

Sample Output 2

18696

Sample Input 3

100000 99999

Sample Output 3

9999900000

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>

long long int gcd(long long int a, long long int b){
  	long long int tmp;
    if(a<b){tmp=a;a=b;b=tmp;}
    if(b == 0)return a;
    return gcd(b, a%b);
}

long long int lcm(long long int a, long long int b){
    return a * b / gcd(a, b);
}

int main(){
  long long int A,B;
  scanf("%lld %lld",&A,&B);
  printf("%lld\n",lcm(A,B));
}