Problem:
Score : 200 points

Problem Statement

You have written N problems to hold programming contests.
The i-th problem will have a score of P_i points if used in a contest.

With these problems, you would like to hold as many contests as possible under the following condition:

A contest has three problems. The first problem has a score not greater than A points, the second has a score between A + 1 and B points (inclusive), and the third has a score not less than B + 1 points.

The same problem should not be used in multiple contests.
At most how many contests can be held?

Constraints

3 \leq N \leq 100

1 \leq P_i \leq 20 (1 \leq i \leq N)

1 \leq A < B < 20

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A B
P_1 P_2 ... P_N

Output

Print the answer.

Sample Input 1

7
5 15
1 10 16 2 7 20 12

Sample Output 1

2

Two contests can be held by putting the first, second, third problems and the fourth, fifth, sixth problems together.

Sample Input 2

8
3 8
5 5 5 10 10 10 15 20

Sample Output 2

0

No contest can be held, because there is no problem with a score of A = 3 or less.

Sample Input 3

3
5 6
5 6 10

Sample Output 3

1

Solution in C (GCC 5.4.1) (judge verdict: Runtime Error)

#include <stdio.h>
int main(void){
    int N, A, B, q = 0, q1 = 0, q2 = 0, q3 = 0;
    int P[20] = {};
    int i;
    
    scanf("%d", &N);
    scanf("%d %d", &A, &B );
    for( i=0 ; i<N ; i++ ) scanf("%d", &P[i]);
    
    for( i=0 ; i<N ; i++ ){
        
        if(P[i] <= A) q1++;
        
    }
    for( i=0 ; i<N ; i++ ){
        
        if(P[i] >= A+1 && P[i] <= B) q2++;
        
    }
    
    for( i=0 ; i<N ; i++ ){
        
        if(P[i] >= B+1) q3++;
        
    }
    
    q = 0;
    if( q1 < q2 ){
        q = q1;
    }else{
        q = q2;
    } 
    if(q > q3) q = q3;
    
    printf("%d",q);
    
    return(0);
    
}