Problem:
Score : 400 points

Problem Statement

We have a grid with H rows and W columns of squares.
Snuke is painting these squares in colors 1, 2, ..., N.
Here, the following conditions should be satisfied:

For each i (1 ≤ i ≤ N), there are exactly a_i squares painted in Color i. Here, a_1 + a_2 + ... + a_N = H W.

For each i (1 ≤ i ≤ N), the squares painted in Color i are 4-connected. That is, every square painted in Color i can be reached from every square painted in Color i by repeatedly traveling to a horizontally or vertically adjacent square painted in Color i.

Find a way to paint the squares so that the conditions are satisfied.
It can be shown that a solution always exists.

Constraints

1 ≤ H, W ≤ 100

1 ≤ N ≤ H W

a_i ≥ 1

a_1 + a_2 + ... + a_N = H W

Input

Input is given from Standard Input in the following format:

H W
N
a_1 a_2 ... a_N

Output

Print one way to paint the squares that satisfies the conditions.
Output in the following format:

c_{1 1} ... c_{1 W}
:
c_{H 1} ... c_{H W}

Here, c_{i j} is the color of the square at the i-th row from the top and j-th column from the left.

Sample Input 1

2 2
3
2 1 1

Sample Output 1

1 1
2 3

Below is an example of an invalid solution:

1 2
3 1

This is because the squares painted in Color 1 are not 4-connected.

Sample Input 2

3 5
5
1 2 3 4 5

Sample Output 2

1 4 4 4 3
2 5 4 5 3
2 5 5 5 3

Sample Input 3

1 1
1
1

Sample Output 3

1

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

#include <stdio.h>
int main(void){
    // Your code here!
    int h,w,n;
    scanf("%d %d\n%d",&h,&w,&n);
    
    int c[10001];
    for(int i=0;i<n;i++){
        scanf("%d",&c[i]);
    }
    
    int s[101][101]={};
    
    int now=0;
    for(int i=0;i<h;i++){
        if(i%2==0){
            for(int j=0;j<w;j++){
                if(c[now]<=0)now++;
                
                s[i][j]=now+1;
                c[now]--;
                
                if(c[now]<=0)now++;
            }
        }else{
            for(int j=w-1;j>=0;j--){
                if(c[now]<=0)now++;
                
                s[i][j]=now+1;
                c[now]--;
                
                if(c[now]<=0)now++;
            }
        }
    }
    
    for(int i=0;i<h;i++){
        for(int j=0;j<w;j++){
            printf("%d",s[i][j]);
            if(j!=w-1)printf(" ");
        }
        printf("\n");
    }
}