Problem:
Score : 200 points

Problem Statement

Takahashi loves gold coins. He gains 1000 happiness points for each 500-yen coin he has and gains 5 happiness points for each 5-yen coin he has. (Yen is the currency of Japan.)

Takahashi has X yen. If he exchanges his money so that he will gain the most happiness points, how many happiness points will he earn?

(We assume that there are six kinds of coins available: 500-yen, 100-yen, 50-yen, 10-yen, 5-yen, and 1-yen coins.)

Constraints

0 \leq X \leq 10^9

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print the maximum number of happiness points that can be earned.

Sample Input 1

1024

Sample Output 1

2020

By exchanging his money so that he gets two 500-yen coins and four 5-yen coins, he gains 2020 happiness points, which is the maximum number of happiness points that can be earned.

Sample Input 2

0

Sample Output 2

0

He is penniless - or yenless.

Sample Input 3

1000000000

Sample Output 3

2000000000

He is a billionaire - in yen.

Solution in C (Clang 3.8.0) (judge verdict: Accepted)

#include <stdio.h>

int main(void) {

    long int X;
    long int en500;
    long int en5;
    long int result = 0;

    // input
    scanf("%ld", &X);

    en500 = X / 500; // 500円の枚数
    en5 = (X - (en500 * 500)) / 5;  // 5円の枚数

    result = en500 * 1000 + en5 * 5;

    // output
    // printf("%ld, %ld\n", en500, en5);
    printf("%ld\n", result);

    return 0;
}