Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in C (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define STR_EQ(s1,s2)       strcmp(s1,s2)==0

typedef long long ll;

int main(){
    ll N,A,B,C;
    scanf("%lld %lld %lld %lld",&N,&A,&B,&C);
    char S[N][3];
    char ans[N];
    for(ll i = 0;i<N;i++) scanf("%s",S[i]);
    for(ll i = 0;i<N;i++){
        if(i==0&&(STR_EQ(S[i],"BC"))&&B==0&&C==0) {printf("No\n");return 0;}
        if(i==0&&(STR_EQ(S[i],"AB"))&&A==0&&B==0) {printf("No\n");return 0;}
        if(i==0&&(STR_EQ(S[i],"AC"))&&A==0&&C==0) {printf("No\n");return 0;}
        if(A+B+C == 0) {printf("No\n");return 0;}
        else if(A+B+C==1){
            if(A==1&&(STR_EQ(S[i],"BC"))) {printf("No\n");return 0;}
            else if(A==1){
                A--;
                if(S[i][1]=='B'){
                    B++;ans[i]='B';
                }else{
                    C++;ans[i]='C';
                }
            }else if(B==1&&(STR_EQ(S[i],"AC"))) {printf("No\n");return 0;}
            else if(B==1){
                B--;
                if(S[i][0]=='A'){
                    A++;ans[i]='A';
                }else{
                    C++;ans[i]='C';
                }
            }else if(C==1&&(STR_EQ(S[i],"AB"))) {printf("No\n");return 0;}
            else if(C==1){
                C--;
                if(S[i][0]=='A'){
                    A++;ans[i]='A';
                }else{
                    B++;ans[i]='B';
                }
            }
        }else if(A+B+C>=2){
            if(A==0){
                if((STR_EQ(S[i],"AB"))){B--;A++;ans[i]='A';continue;}
                else if((STR_EQ(S[i],"AC"))){C--;A++;ans[i]='A';continue;}
            }else if(B==0){
                if((STR_EQ(S[i],"AB"))) {A--;B++;ans[i]='B';continue;}
                else if((STR_EQ(S[i],"BC"))){C--;B++;ans[i]='B';continue;}
            }else if(C==0){
                if((STR_EQ(S[i],"AC"))){A--;C++;ans[i]='C';continue;}
                else if((STR_EQ(S[i],"BC"))){B--;C++;ans[i]='C';continue;}
            }
            if(A==1&&B==1&&i!=N-1){
                if(STR_EQ(S[i+1],"BC")){
                    B++;A--;ans[i]='B';continue;
                }else if(STR_EQ(S[i+1],"AC")){
                    B--;A++;ans[i]='A';continue;
                }
            }else if(B==1&&C==1&&i!=N-1){
                if(STR_EQ(S[i+1],"AB")){
                    B++;C--;ans[i]='B';continue;
                }else if(STR_EQ(S[i+1],"AC")){
                    B--;C++;ans[i]='C';continue;
                }
            }else if(A==1&&C==1&&i!=N-1){
                if(STR_EQ(S[i+1],"AB")){
                    A++;C--;ans[i]='A';continue;
                }else if(STR_EQ(S[i+1],"BC")){
                    A--;C++;ans[i]='C';continue;
                }
            }
            if((STR_EQ(S[i],"AB"))){
                if(A<B){A++;B--;ans[i]='A';}
                else{A--;B++;ans[i]='B';}
            }else if((STR_EQ(S[i],"BC"))){
                if(B<C){B++;C--;ans[i]='B';}
                else{B--;C++;ans[i]='C';}
            }else if((STR_EQ(S[i],"AC"))){
                if(C<A){C++;A--;ans[i]='C';}
                else{C--;A++;ans[i]='A';}
            }
        }
    }
    printf("Yes\n");
    for(ll i = 0;i<N;i++) printf("%c\n",ans[i]);
    return 0;
}