Problem:
Score : 300 points

Problem Statement

AtCoDeer the deer is going on a trip in a two-dimensional plane.
In his plan, he will depart from point (0, 0) at time 0, then for each i between 1 and N (inclusive), he will visit point (x_i,y_i) at time t_i.

If AtCoDeer is at point (x, y) at time t, he can be at one of the following points at time t+1: (x+1,y), (x-1,y), (x,y+1) and (x,y-1).
Note that he cannot stay at his place.
Determine whether he can carry out his plan.

Constraints

1 ≤ N ≤ 10^5

0 ≤ x_i ≤ 10^5

0 ≤ y_i ≤ 10^5

1 ≤ t_i ≤ 10^5

t_i < t_{i+1} (1 ≤ i ≤ N-1)

All input values are integers.

Input

Input is given from Standard Input in the following format:

N
t_1 x_1 y_1
t_2 x_2 y_2
:
t_N x_N y_N

Output

If AtCoDeer can carry out his plan, print Yes; if he cannot, print No.

Sample Input 1

2
3 1 2
6 1 1

Sample Output 1

Yes

For example, he can travel as follows: (0,0), (0,1), (1,1), (1,2), (1,1), (1,0), then (1,1).

Sample Input 2

1
2 100 100

Sample Output 2

No

It is impossible to be at (100,100) two seconds after being at (0,0).

Sample Input 3

2
5 1 1
100 1 1

Sample Output 3

No

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>

int kyori(int x1,int y1,int x2,int y2){
    int po1=x1-x2;
    if(po1<0)po1*=-1;
    int po2=y1-y2;
    if(po2<0)po2*=-1;
    return po1+po2;
}

int main(void){
    int N;
    scanf("%d",&N);
    int x=0;
    int y=0;
    int t=0;
    for(int i=0;i<N;i++){
        int X,Y,T;
        scanf("%d %d %d",&T,&X,&Y);
        if(kyori(x,y,X,Y)>T-t||(T-t-kyori(x,y,X,Y))%2==1){printf("No");return 0;}
        else {
            x=X;
            y=Y;
            t=T;
        }
    }
    printf("Yes");
    return 0;
}