Problem:
﻿Score: 100 points

Problem Statement

In AtCoder city, there are five antennas standing in a straight line. They are called Antenna A, B, C, D and E from west to east, and their coordinates are a, b, c, d and e, respectively.

Two antennas can communicate directly if the distance between them is k or less, and they cannot if the distance is greater than k.

Determine if there exists a pair of antennas that cannot communicate directly.

Here, assume that the distance between two antennas at coordinates p and q (p < q) is q - p.

Constraints

a, b, c, d, e and k are integers between 0 and 123 (inclusive).

a < b < c < d < e

Input

Input is given from Standard Input in the following format:

a
b
c
d
e
k

Output

Print :( if there exists a pair of antennas that cannot communicate directly, and print Yay! if there is no such pair.

Sample Input 1

1
2
4
8
9
15

Sample Output 1

Yay!

In this case, there is no pair of antennas that cannot communicate directly, because:

the distance between A and B is 2 - 1 = 1

the distance between A and C is 4 - 1 = 3

the distance between A and D is 8 - 1 = 7

the distance between A and E is 9 - 1 = 8

the distance between B and C is 4 - 2 = 2

the distance between B and D is 8 - 2 = 6

the distance between B and E is 9 - 2 = 7

the distance between C and D is 8 - 4 = 4

the distance between C and E is 9 - 4 = 5

the distance between D and E is 9 - 8 = 1

and none of them is greater than 15. Thus, the correct output is Yay!.

Sample Input 2

15
18
26
35
36
18

Sample Output 2

:(

In this case, the distance between antennas A and D is 35 - 15 = 20 and exceeds 18, so they cannot communicate directly.
Thus, the correct output is :(.

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
#include<stdlib.h>

int main()
{
	int a, b, c, d, e, i, j, temp, k;
	int array[5];
	scanf("%d", &a);
	scanf("%d", &b);
	scanf("%d", &c);
	scanf("%d", &d);
	scanf("%d", &e);
	array[0] = a % 10;
	array[1] = b % 10;
	array[2] = c % 10;
	array[3] = d % 10;
	array[4] = e % 10;
	for (i = 0; i < 5; i++)
		for (j = 0; j < 4; j++) {
			if (array[j + 1] < array[j]) {
				temp = array[j]; array[j] = array[j + 1]; array[j + 1] = temp;
			}
		}
	for (k = 1; k < 5; k++) {
		if (array[k]%10 == 0) {
			array[k] = array[k] + 10;
		}
	}
	
printf("%d", a + b + c + d + e + 40 - array[1] - array[2] - array[3] - array[4]);


	return 0;
}