Problem:
Score : 200 points

Problem Statement

There are N rabbits, numbered 1 through N.

The i-th (1≤i≤N) rabbit likes rabbit a_i.
Note that no rabbit can like itself, that is, a_i≠i.

For a pair of rabbits i and j (i＜j), we call the pair (i，j) a friendly pair if the following condition is met.

Rabbit i likes rabbit j and rabbit j likes rabbit i.

Calculate the number of the friendly pairs.

Constraints

2≤N≤10^5

1≤a_i≤N

a_i≠i

Input

The input is given from Standard Input in the following format:

N
a_1 a_2 ... a_N

Output

Print the number of the friendly pairs.

Sample Input 1

4
2 1 4 3

Sample Output 1

2

There are two friendly pairs: (1，2) and (3，4).

Sample Input 2

3
2 3 1

Sample Output 2

0

There are no friendly pairs.

Sample Input 3

5
5 5 5 5 1

Sample Output 3

1

There is one friendly pair: (1，5).

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>

int main(){

	int i;
	int n;
	scanf("%d",&n);
	int a[n];
	int b[n];
	int count =0;
	for(i=0;i<n;i++){
		scanf("%d",&a[i]);
		b[i] = 0;
	}
	for(i=0;i<n-1;i++){
		if(b[i]!=0){
			continue;
		}
		if(a[a[i]-1]==i+1){
			count++;
			b[a[i]-1]++;
		}
	}
	printf("%d\n",count);

	return 0;
}