Problem:
Score : 400 points

Problem Statement

#nck {
width: 30px;
height: auto;
}

You are given a permutation p of the set {1, 2, ..., N}. Please construct two sequences of positive integers a_1, a_2, ..., a_N and b_1, b_2, ..., b_N satisfying the following conditions:

1 \leq a_i, b_i \leq 10^9 for all i

a_1 < a_2 < ... < a_N

b_1 > b_2 > ... > b_N

a_{p_1}+b_{p_1} < a_{p_2}+b_{p_2} < ... < a_{p_N}+b_{p_N}

Constraints

2 \leq N \leq 20,000

p is a permutation of the set {1, 2, ..., N}

Input

The input is given from Standard Input in the following format:

N
p_1 p_2 ... p_N

Output

The output consists of two lines. The first line contains a_1, a_2, ..., a_N seperated by a space. The second line contains b_1, b_2, ..., b_N seperated by a space.

It can be shown that there always exists a solution for any input satisfying the constraints.

Sample Input 1

2
1 2

Sample Output 1

1 4
5 4

a_1 + b_1 = 6 and a_2 + b_2 = 8. So this output satisfies all conditions.

Sample Input 2

3
3 2 1

Sample Output 2

1 2 3
5 3 1

Sample Input 3

3
2 3 1

Sample Output 3

5 10 100
100 10 1

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <stdbool.h>
#include <limits.h>

#define lli long long int
#define min(a,b) ((a)<(b)?(a):(b))
#define max(a,b) ((a)>(b)?(a):(b))
#define abs(a) ((a)<0?-(a):(a))




int main(void){
	lli n;
	int *p;
	lli *a,*b;

	lli bigint = 1000000000;

	lli i;

	scanf("%lld",&n);

	p = calloc(sizeof(int),n);
	a = calloc(sizeof(lli),n);
	b = calloc(sizeof(lli),n);
	for(i=0;i<n;i++){
		scanf("%d",&p[i]);
		p[i]--;
	}
	for(i=0;i<n;i++){
		a[i] = b[n-i-1] = bigint * i / n  + 1;
	}
	for(i=0;i<n;i++){
		a[p[i]] += (i+1)*10;
	}
	for(i=0;i<n;i++){
		printf("%lld ", a[i]);
	}
	printf("\n");
	for(i=0;i<n;i++){
		printf("%lld ", b[i]);
	}
	printf("\n");
    return 0;
}