Problem:
Score : 200 points

Problem Statement

Find the number of palindromic numbers among the integers between A and B (inclusive).
Here, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.

Constraints

10000 \leq A \leq B \leq 99999

All input values are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the number of palindromic numbers among the integers between A and B (inclusive).

Sample Input 1

11009 11332

Sample Output 1

4

There are four integers that satisfy the conditions: 11011, 11111, 11211 and 11311.

Sample Input 2

31415 92653

Sample Output 2

612

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>

int main(void)
{
  int a,b;
  int a_345=0;
  int b_345=0;
  scanf("%d %d",&a,&b);

  int temp=0;
  int temp1=0;
  int temp2=0;
  int count =0;
//  printf("%d %d %d %d ",a/1000,a-a_345*100,b/1000,b-b_345*100);

  for(int i=a; i<=b; i++){
    temp = i;
    temp1 = temp%10; temp/10;
    temp2 = temp%10;
    if(i/1000 == temp2*10+temp1){
      count ++;
    }
  }

  printf("%d",count);

    return 0;

}