Problem:
﻿Score: 100 points

Problem Statement

In AtCoder city, there are five antennas standing in a straight line. They are called Antenna A, B, C, D and E from west to east, and their coordinates are a, b, c, d and e, respectively.

Two antennas can communicate directly if the distance between them is k or less, and they cannot if the distance is greater than k.

Determine if there exists a pair of antennas that cannot communicate directly.

Here, assume that the distance between two antennas at coordinates p and q (p < q) is q - p.

Constraints

a, b, c, d, e and k are integers between 0 and 123 (inclusive).

a < b < c < d < e

Input

Input is given from Standard Input in the following format:

a
b
c
d
e
k

Output

Print :( if there exists a pair of antennas that cannot communicate directly, and print Yay! if there is no such pair.

Sample Input 1

1
2
4
8
9
15

Sample Output 1

Yay!

In this case, there is no pair of antennas that cannot communicate directly, because:

the distance between A and B is 2 - 1 = 1

the distance between A and C is 4 - 1 = 3

the distance between A and D is 8 - 1 = 7

the distance between A and E is 9 - 1 = 8

the distance between B and C is 4 - 2 = 2

the distance between B and D is 8 - 2 = 6

the distance between B and E is 9 - 2 = 7

the distance between C and D is 8 - 4 = 4

the distance between C and E is 9 - 4 = 5

the distance between D and E is 9 - 8 = 1

and none of them is greater than 15. Thus, the correct output is Yay!.

Sample Input 2

15
18
26
35
36
18

Sample Output 2

:(

In this case, the distance between antennas A and D is 35 - 15 = 20 and exceeds 18, so they cannot communicate directly.
Thus, the correct output is :(.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>

int main(void){

int name[5];
  int k;
  int i;
  
  for(i=0;i<5;i++){
  	scanf("%d", &name[i]);
  }
  scanf("%d", &k);
int ans[12];
  
  ans[0] = name[1] - name[0];
  ans[1] = name[2] - name[0];
  ans[2] = name[3] - name[0];
  ans[3] = name[4] - name[0];
  ans[4] = name[2] - name[1];
  ans[5] = name[3] - name[1];
  ans[6] = name[4] - name[1];
  ans[7] = name[3] - name[2];
  ans[8] = name[4] - name[2];
  ans[9] = name[4] - name[3];
  int t =0;
for(t-0;t<10;t++){
  if(ans[t] > k){
	printf(":(");
    return 0;
  }
}
printf("Yay!");
return 0;

}