Problem:
Score : 200 points

Problem Statement

Given are integers a,b,c and d.
If x and y are integers and a \leq x \leq b and c\leq y \leq d hold, what is the maximum possible value of x \times y?

Constraints

-10^9 \leq a \leq b \leq 10^9

-10^9 \leq c \leq d \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

a b c d

Output

Print the answer.

Sample Input 1

1 2 1 1

Sample Output 1

2

If x = 1 and y = 1 then x \times y = 1.
If x = 2 and y = 1 then x \times y = 2.
Therefore, the answer is 2.

Sample Input 2

3 5 -4 -2

Sample Output 2

-6

The answer can be negative.

Sample Input 3

-1000000000 0 -1000000000 0

Sample Output 3

1000000000000000000

Solution in C (GCC 9.2.1) (judge verdict: Output Limit Exceeded)

#include <stdio.h>
int main(void){

    int a,b,c,d,max,i,j;
   
    scanf("%d %d %d %d", &a, &b, &c, &d);
   
    if(a<0 && c<0){
        max=a*c;
        if(max<b*d){
            max=b*d;
        }
        printf("%d",max);
    }else{
    if(a>=0 || c>=0){
        max=-10000;
    for(i=a;i<=b;i++){
        for(j=c;j<=d;j++){
        if(max<i*j){
            max=i*j; 
        }
        printf("%d",max);
        }
    }
    }
    }

    return 0;
}