Problem:
Score : 100 points

Problem Statement

You are given three strings A, B and C. Check whether they form a word chain.

More formally, determine whether both of the following are true:

The last character in A and the initial character in B are the same.

The last character in B and the initial character in C are the same.

If both are true, print YES. Otherwise, print NO.

Constraints

A, B and C are all composed of lowercase English letters (a - z).

1 ≤ |A|, |B|, |C| ≤ 10, where |A|, |B| and |C| are the lengths of A, B and C, respectively.

Input

Input is given from Standard Input in the following format:

A B C

Output

Print YES or NO.

Sample Input 1

rng gorilla apple

Sample Output 1

YES

They form a word chain.

Sample Input 2

yakiniku unagi sushi

Sample Output 2

NO

A and B form a word chain, but B and C do not.

Sample Input 3

a a a

Sample Output 3

YES

Sample Input 4

aaaaaaaaab aaaaaaaaaa aaaaaaaaab

Sample Output 4

NO

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
#include<stdio.h>
#include<stdlib.h>

int main(){
    char *a;
    char *b;
    char *c;
    a = (char *)malloc(10);
    b = (char *)malloc(10);
    c = (char *)malloc(10);

    scanf("%s %s %s",a,b,c);
    //printf("%s\n%s\n%s\n",a,b,c);

    int l,m,n;
    l = strlen(a);
    m = strlen(b);
    n = strlen(c);

    for(int i=0;i<l;i++){
        if(a[i]<'a' || a[i]>'z'){
                printf("NO");
            return 0;
        }
    }

    for(int i=0;i<m;i++){
        if(b[i]<'a' || b[i]>'z'){
                printf("NO");
            return 0;
        }
    }

    for(int i=0;i<n;i++){
        if(c[i]<'a' || c[i]>'z'){
                printf("NO");
            return 0;
        }
    }



        if((a[l-1]==b[0]) && (b[m-1]==c[0])){
            printf("YES");
            //printf("A and B form a word chain, but B and C do not.\n");
            return 0;
        }
       else {
            printf("No");
            //printf("B and C form a word chain, but A and B do not.\n");
            return 0;

        }

}