Problem:
Score : 100 points

Problem Statement

You have three tasks, all of which need to be completed.

First, you can complete any one task at cost 0.

Then, just after completing the i-th task, you can complete the j-th task at cost |A_j - A_i|.

Here, |x| denotes the absolute value of x.

Find the minimum total cost required to complete all the task.

Constraints

All values in input are integers.

1 \leq A_1, A_2, A_3 \leq 100

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

Print the minimum total cost required to complete all the task.

Sample Input 1

1 6 3

Sample Output 1

5

When the tasks are completed in the following order, the total cost will be 5, which is the minimum:

Complete the first task at cost 0.

Complete the third task at cost 2.

Complete the second task at cost 3.

Sample Input 2

11 5 5

Sample Output 2

6

Sample Input 3

100 100 100

Sample Output 3

0

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
int main(){

    int a[3],b,c,t,d,s,p,tmp,i,j;
    scanf("%d%d%d",&a[0],&a[1],&a[2]);
    for(i=0;i<3;i++){
        for(j=i+1;j<3;j++){
                if(a[i]<a[j]){
                    tmp=a[i];
                    a[i]=a[j];
                    a[j]=tmp;
                }

        }
    }
    s=a[0]-a[1];
    p=a[1]-a[2];
    t=s+p;
    printf("%d\n",t);
    return 0;

}