Problem:
Score : 200 points

Problem Statement

The postal code in Atcoder Kingdom is A+B+1 characters long, its (A+1)-th character is a hyphen -, and the other characters are digits from 0 through 9.

You are given a string S. Determine whether it follows the postal code format in Atcoder Kingdom.

Constraints

1≤A,B≤5

|S|=A+B+1

S consists of - and digits from 0 through 9.

Input

Input is given from Standard Input in the following format:

A B
S

Output

Print Yes if S follows the postal code format in AtCoder Kingdom; print No otherwise.

Sample Input 1

3 4
269-6650

Sample Output 1

Yes

The (A+1)-th character of S is -, and the other characters are digits from 0 through 9, so it follows the format.

Sample Input 2

1 1
---

Sample Output 2

No

S contains unnecessary -s other than the (A+1)-th character, so it does not follow the format.

Sample Input 3

1 2
7444

Sample Output 3

No

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
#include<stdlib.h>
#include<limits.h>
#include<math.h>

int main(){
	int A,B,i,j,k,n;
	char addr[20];
	char c;
	int boo = 1;
	int endflag = 0;
	
	scanf("%d",&A);
	scanf("%d",&B);
	
	if(A >=6 || B >= 6){endflag = 1;boo = -1;}
	
	scanf("%s",&addr);
	
	for(i=0;i<A;i++){
		if(endflag == 1)break;
		if(addr[i]=='\0'){endflag = 1;boo = -1;break;}
		if( !(addr[i] >= '0' && addr[i] <= '9')){endflag = 1;boo =-1;break;}
	}
	
	if(endflag!= 1){
		if(addr[A] == '-');
		else{endflag = 1;boo = -1;}
	}
	
	for(i=A+1;i<A+B+1;i++){
		if(endflag == 1)break;
		if(addr[i]=='\0'){endflag = 1;boo = -1;break;}
		if( !(addr[i] >= '0' && addr[i] <= '9')){endflag = 1;boo =-1;break;}
	}
	
	if(addr[A+B+1] != '\0'){endflag = 1;boo = -1;}
	
	if(boo == 1)printf("Yes\n");
	else printf("No\n");
	
	
	return 0;
}