Problem:
Score : 300 points

Problem Statement

Takahashi is organizing a party.

At the party, each guest will receive one or more snack pieces.

Takahashi predicts that the number of guests at this party will be A or B.

Find the minimum number of pieces that can be evenly distributed to the guests in both of the cases predicted.

We assume that a piece cannot be divided and distributed to multiple guests.

Constraints

1 \leq A, B \leq 10^5

A \neq B

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the minimum number of pieces that can be evenly distributed to the guests in both of the cases with A guests and B guests.

Sample Input 1

2 3

Sample Output 1

6

When we have six snack pieces, each guest can take three pieces if we have two guests, and each guest can take two if we have three guests.

Sample Input 2

123 456

Sample Output 2

18696

Sample Input 3

100000 99999

Sample Output 3

9999900000

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>

int min(int a, int b){
  if(a > b)return b;
  else return a;
}
int max(int a, int b){
  if(a > b)return a;
  else return b;
}
int gcd(int a, int b){
  int c = max(a,b);
  int d = min(a,b);
  if(c % d == 0)return d;
  else return gcd(d,c % d);
}
int lcm(int a, int b){
  return (a * b) / gcd(a,b);
}
int main(void){
  int a,b;
  scanf("%d%d",&a,&b);
  int ans = lcm(a,b);
  printf("%d",ans);
  
}