Problem:
Score : 200 points

Problem Statement

Tak performed the following action N times: rolling two dice.
The result of the i-th roll is D_{i,1} and D_{i,2}.

Check if doublets occurred at least three times in a row.
Specifically, check if there exists at lease one i such that D_{i,1}=D_{i,2}, D_{i+1,1}=D_{i+1,2} and D_{i+2,1}=D_{i+2,2} hold.

Constraints

3 \leq N \leq 100

1\leq D_{i,j} \leq 6

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
D_{1,1} D_{1,2}
\vdots
D_{N,1} D_{N,2}

Output

Print Yes if doublets occurred at least three times in a row. Print No otherwise.

Sample Input 1

5
1 2
6 6
4 4
3 3
3 2

Sample Output 1

Yes

From the second roll to the fourth roll, three doublets occurred in a row.

Sample Input 2

5
1 1
2 2
3 4
5 5
6 6

Sample Output 2

No

Sample Input 3

6
1 1
2 2
3 3
4 4
5 5
6 6

Sample Output 3

Yes

Solution in C (GCC 9.2.1) (judge verdict: Wrong Answer)

#include<stdio.h>

int main(){
      int n ;
      scanf("%d", &n) ;
      int D1[n], D2[n] ;
      for(int i=0; i<n; i++)
            scanf("%d%d", &D1[i], &D2[i]) ;
      int ans = 0 ;
      for(int i=0; i<n-1; i++) 
      {
              if(D1[i]==D2[i]&&D1[i+1]==D2[i+1]\
              &&D1[i+2]==D2[i+2])
              {
                    ans = 1 ;
                    break ;
              }
      }
      if(ans == 0)
            printf("No\n") ;
      else 
            printf("Yes\n") ;
      return 0 ;
}