Problem:
Score : 100 points

Problem Statement

Cat Snuke is learning to write characters.
Today, he practiced writing digits 1 and 9, but he did it the other way around.

You are given a three-digit integer n written by Snuke.
Print the integer obtained by replacing each digit 1 with 9 and each digit 9 with 1 in n.

Constraints

111 \leq n \leq 999

n is an integer consisting of digits 1 and 9.

Input

Input is given from Standard Input in the following format:

n

Output

Print the integer obtained by replacing each occurrence of 1 with 9 and each occurrence of 9 with 1 in n.

Sample Input 1

119

Sample Output 1

991

Replace the 9 in the ones place with 1, the 1 in the tens place with 9 and the 1 in the hundreds place with 9. The answer is 991.

Sample Input 2

999

Sample Output 2

111

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
#include <string.h>

int main(void){
    int i, n; 
    char x[10];

    scanf("%d", &n);
    sprintf(x, "%d", n);

    for(i = 0; i < 3; i++){
    if(x[i] == '0' + 9){
        x[i] = 1;
    }else if(x[i] == '0' + 1) {
        x[i] = 9;
    }
    }
    for(i = 0; i < 3; i++){
    printf("%d",x[i]);
    }

    return 0;
}