Problem:
Score : 100 points

Problem Statement

You have three tasks, all of which need to be completed.

First, you can complete any one task at cost 0.

Then, just after completing the i-th task, you can complete the j-th task at cost |A_j - A_i|.

Here, |x| denotes the absolute value of x.

Find the minimum total cost required to complete all the task.

Constraints

All values in input are integers.

1 \leq A_1, A_2, A_3 \leq 100

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

Print the minimum total cost required to complete all the task.

Sample Input 1

1 6 3

Sample Output 1

5

When the tasks are completed in the following order, the total cost will be 5, which is the minimum:

Complete the first task at cost 0.

Complete the third task at cost 2.

Complete the second task at cost 3.

Sample Input 2

11 5 5

Sample Output 2

6

Sample Input 3

100 100 100

Sample Output 3

0

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{int a1,a2,a3,cost[6],ans=100000,i;
    scanf("%d %d %d",&a1,&a2,&a3);
   
        cost[0]=abs(a1-a2)+abs(a2-a3);
        cost[1]=abs(a1-a3)+abs(a2-a3);
        cost[2]=abs(a2-a1)+abs(a1-a3);
        cost[3]=abs(a2-a3)+abs(a1-a3);
        cost[4]=abs(a3-a1)+abs(a1-a2);
        cost[5]=abs(a3-a2)+abs(a1-a2);
        for(i=0;i<6;i++){
            if(cost[i]<ans){
                ans=cost[i];
            }
        }
        printf("%d",ans);

    return 0;
}