Problem:
Score : 100 points

Problem Statement

N of us are going on a trip, by train or taxi.

The train will cost each of us A yen (the currency of Japan).

The taxi will cost us a total of B yen.

How much is our minimum total travel expense?

Constraints

All values in input are integers.

1 \leq N \leq 20

1 \leq A \leq 50

1 \leq B \leq 50

Input

Input is given from Standard Input in the following format:

N A B

Output

Print an integer representing the minimum total travel expense.

Sample Input 1

4 2 9

Sample Output 1

8

The train will cost us 4 \times 2 = 8 yen, and the taxi will cost us 9 yen, so the minimum total travel expense is 8 yen.

Sample Input 2

4 2 7

Sample Output 2

7

Sample Input 3

4 2 8

Sample Output 3

8

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
#include <ctype.h>
#define MOD 1000000007
#define MAX(a,b) (a>b?a:b)
#define MAX3(a,b,c) MAX(a,MAX(b,c))
#define MIN(a,b) (a<b?a:b)
#define MIN3(a,b,c) MIN(a, MIN(b,c))
typedef long long lli;
int cmp(const void *a, const void *b) {
    return *(int*)a - *(int*)b;
}

lli nCr(int n, int r, lli *mem) {
    if(n < r) return 0;
    if(mem[n*2010 + r]!=0) {
        return mem[n*2010 + r];
    } else {
        if(n==r || r==0) {
            mem[n*2010 + r] = 1;
            return 1;
        }
        lli a = nCr(n-1, r-1, mem);
        lli b = nCr(n-1, r, mem);
        mem[n*2010 + r] = (a+b)%MOD;
        return mem[n*2010 + r];
    }
}

int main()
{
    int n, a,b;
    scanf("%d%d%d",&n,&a,&b);
    printf("%d",MIN(n*a, b));

    return 0;
}