Problem:
Score : 200 points

Problem Statement

You are given string S and T consisting of lowercase English letters.

Determine if S equals T after rotation.

That is, determine if S equals T after the following operation is performed some number of times:

Operation: Let S = S_1 S_2 ... S_{|S|}. Change S to S_{|S|} S_1 S_2 ... S_{|S|-1}.

Here, |X| denotes the length of the string X.

Constraints

2 \leq |S| \leq 100

|S| = |T|

S and T consist of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S equals T after rotation, print Yes; if it does not, print No.

Sample Input 1

kyoto
tokyo

Sample Output 1

Yes

In the first operation, kyoto becomes okyot.

In the second operation, okyot becomes tokyo.

Sample Input 2

abc
arc

Sample Output 2

No

abc does not equal arc after any number of operations.

Sample Input 3

aaaaaaaaaaaaaaab
aaaaaaaaaaaaaaab

Sample Output 3

Yes

Solution in C (GCC 9.2.1) (judge verdict: Wrong Answer)

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<math.h>
#define rep(i,n) for(int i=0;i<n;i++)
int gcd(int a, int b){
    int r=1;
    while(r!=0){
        r=a%b;
        a=b;
        b=r;
    }
    return a;
}
typedef long long ll;
void revStr(char* str){
    int size = strlen(str);
    int i,j;
    char tmp = {0};
    for(i = 0, j = size - 1; i < size / 2; i++, j--){
        tmp = str[i];
        str[i] = str[j];
        str[j] = tmp;
    }return;
}
typedef struct{
    int a,b;
}data;

//昇順
int compare_int(const void *a, const void *b)
{
    return *(int*)a - *(int*)b;
}
//構造体降順
int comp( const void *c1, const void *c2 )
{
  data test1 = *(data *)c1;
  data test2 = *(data *)c2;
  int tmp1 = test1.b;   /* b を基準とする */
  int tmp2 = test2.b;
  return tmp2 - tmp1;
}


int kai(int n){
    if(n==0){
        return 1;
    }
    int sum=1;
    for(int i=1;i<=n;i++){
        sum*=i;
    }
    return sum;
}

int main(){
    char a[110],b[110];
    scanf("%s",a);
    scanf("%s",b);
    rep(i,strlen(a)){
        a[strlen(a)]=a[0];
        rep(j,strlen(a)){
            a[j]=a[j+1];
        }
        a[strlen(a)]=0;
        if(strcmp(a,b)==0){
            printf("Yes");
            return 0;
        }
    }
    printf("No");
}