Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>

int main(void){
    int n;
    scanf("%d\n",&n);
    for(int a=1;a<=3500;a++){
        for(int b=1;b<=3500;b++){
            if(4*a*b-n*b-n*a==0){
                goto nop;
            }
            int c=(n*a*b)/(4*a*b-n*b-n*a);
            int c2=(n*a*b)%(4*a*b-n*b-n*a);
            if(c>=1 && c2==0){
                printf("%d %d %d\n",a,b,c);
                return 0;
            }
nop:;
        }
    }
}