Problem:
Score : 100 points

Problem Statement

You are given four digits N_1, N_2, N_3 and N_4. Determine if these can be arranged into the sequence of digits "1974".

Constraints

0 \leq N_1, N_2, N_3, N_4 \leq 9

N_1, N_2, N_3 and N_4 are integers.

Input

Input is given from Standard Input in the following format:

N_1 N_2 N_3 N_4

Output

If N_1, N_2, N_3 and N_4 can be arranged into the sequence of digits "1974", print YES; if they cannot, print NO.

Sample Input 1

1 7 9 4

Sample Output 1

YES

We can get 1974 by swapping N_2 and N_3.

Sample Input 2

1 9 7 4

Sample Output 2

YES

We already have 1974 before doing anything.

Sample Input 3

1 2 9 1

Sample Output 3

NO

Sample Input 4

4 9 0 8

Sample Output 4

NO

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>

int main(void){
  int a[4];
  int temp;
  for(int i = 0; i < 4; i++) scanf("%d", &a[i]);
  for(int i = 0; i < 4; i++){
    for(int j = i + 1; j < 4; j++){
      if(a[i] < a[j]){
	temp = a[i];
	a[i] = a[j];
	a[j] = temp;
      }
    }
  }
  if(a[0] == 9 && a[1] == 7 && a[2] == 4 && a[3] == 1) printf("YES\n");
  else printf("NO\n");
  return 0;
}