Problem:
Score : 300 points

Problem Statement

A company has N members, who are assigned ID numbers 1, ..., N.

Every member, except the member numbered 1, has exactly one immediate boss with a smaller ID number.

When a person X is the immediate boss of a person Y, the person Y is said to be an immediate subordinate of the person X.

You are given the information that the immediate boss of the member numbered i is the member numbered A_i. For each member, find how many immediate subordinates it has.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq A_i < i

Input

Input is given from Standard Input in the following format:

N
A_2 ... A_N

Output

For each of the members numbered 1, 2, ..., N, print the number of immediate subordinates it has, in its own line.

Sample Input 1

5
1 1 2 2

Sample Output 1

2
2
0
0
0

The member numbered 1 has two immediate subordinates: the members numbered 2 and 3.

The member numbered 2 has two immediate subordinates: the members numbered 4 and 5.

The members numbered 3, 4, and 5 do not have immediate subordinates.

Sample Input 2

10
1 1 1 1 1 1 1 1 1

Sample Output 2

9
0
0
0
0
0
0
0
0
0

Sample Input 3

7
1 2 3 4 5 6

Sample Output 3

1
1
1
1
1
1
0

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

#include <stdio.h>  /*入出力*/
#include <stdlib.h> /*標準ライブラリ*/
#include <string.h> /*文字列*/
#include <math.h>   /*計算*/
#include <assert.h> /*確認*/
#include <ctype.h>  /*文字操作*/
#include <stdbool.h>/*bool型*/
#include <limits.h>/*限界*/
//---------------------------------------------------
#define rep(i, n) for(int  i = 0; i < (n); i++)
#define max(a,b) ((a>b)?a:b)
#define ABS(a) (((a)>(0))?a:-(a))
#define LL long long
#define MOD 1000000007//10^9+7(素数)
//---------------------------------------------------
void swap(int *a, int *b)
{
  int temp;
  temp = *a;*a = *b;*b = temp;
}
//---------------------------------------------------

int main(void)
{
  LL n;
  LL c;
  LL a[200001]={0};
  scanf("%lld",&n);
  for (LL i = 0; i < n-1; i++) {
    scanf("%lld",&c );
    a[c]++;
  }
  for (LL i = 1; i <= n; i++) {
    printf("%lld\n", a[i]);
  }
  return 0;
}