Problem:
Score : 300 points

Problem Statement

Sitting in a station waiting room, Joisino is gazing at her train ticket.

The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).

In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.

The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Constraints

0≤A,B,C,D≤9

All input values are integers.

It is guaranteed that there is a solution.

Input

Input is given from Standard Input in the following format:

ABCD

Output

Print the formula you made, including the part =7.

Use the signs + and -.

Do not print a space between a digit and a sign.

Sample Input 1

1222

Sample Output 1

1+2+2+2=7

This is the only valid solution.

Sample Input 2

0290

Sample Output 2

0-2+9+0=7

0 - 2 + 9 - 0 = 7 is also a valid solution.

Sample Input 3

3242

Sample Output 3

3+2+4-2=7

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
#include<string.h>

int main()
{
	char a1,b1,c1,d1;
	int a,b,c,d;
	int t=0;
	scanf("%c%c%c%c",&a1,&b1,&c1,&d1);
	a=(int)(a1-'0');
	b=(int)(b1-'0');
	c=(int)(c1-'0');
	d=(int)(d1-'0');
	if (a+b+c+d==7) t=1;
	else if (a+b+c-d==7) t=2;
	else if (a+b-c+d==7) t=3;
	else if (a-b+c+d==7) t=4;
	else if (a+b-c-d==7) t=5;
	else if (a-b+c-d==7) t=6;
	else if (a-b-c+d==7) t=7;
	else if (a-b-c-d==7) t=8;
	
	switch(t){
	case 1:	printf("%d+%d+%d+%d=7",a,b,c,d);break;
	case 2:	printf("%d+%d+%d-%d=7",a,b,c,d);break;
	case 3:	printf("%d+%d-%d+%d=7",a,b,c,d);break;
	case 4:	printf("%d-%d+%d+%d=7",a,b,c,d);break;
	case 5:	printf("%d+%d-%d-%d=7",a,b,c,d);break;
	case 6:	printf("%d-%d+%d-%d=7",a,b,c,d);break;
	case 7:	printf("%d-%d-%d+%d=7",a,b,c,d);break;
	case 8:	printf("%d-%d-%d-%d=7",a,b,c,d);break;
	default:printf("no answer!");break;
	}
}