Problem:
Score : 300 points

Problem Statement

There are N people living on a number line.

The i-th person lives at coordinate X_i.

You are going to hold a meeting that all N people have to attend.

The meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.

Find the minimum total points of stamina the N people have to spend.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq X_i \leq 100

Input

Input is given from Standard Input in the following format:

N
X_1 X_2 ... X_N

Output

Print the minimum total stamina the N people have to spend.

Sample Input 1

2
1 4

Sample Output 1

5

Assume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.

Note that you can hold the meeting only at an integer coordinate.

Sample Input 2

7
14 14 2 13 56 2 37

Sample Output 2

2354

Solution in C (Clang 3.8.0) (judge verdict: Wrong Answer)

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <stdbool.h>
#include <math.h>
#pragma warning(disable : 4996) //_CRT_SECURE_NO_WARNINGS

int comp(const void* a, const void* b) {
	return *(int*)a - *(int*)b;
}


int main(void) {
	int n,center=0;
	int cnt = 0;
	int* data;
	int list[10000];
	for (int i = 0;i < 10000;i++) {
		list[i] = 0;
	}
	scanf("%d", &n);
	data = (int*)malloc(sizeof(int) * n);
	for (int i = 0;i < n;i++) {
		scanf("%d", &data[i]);
	}
	for (int i = data[n - 1] / 2;i < data[n - 1];i++) {
		for (int j = 0;j < n;j++) {
			list[cnt] += (data[j] - i) * (data[j] - i);
		}
		cnt += 1;
	}
	qsort(list,n, sizeof(int), comp);
	printf("%d\n", list[0]);
	free(data);
	data = NULL;
	return 0;
}