Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>

int main(void)
{
        int n,a,i,j,s=0;

        scanf("%d",&n);

        //if (n>200)    return 1;

        for(i=1;i<=n;i++){
                a=0;
                for (j=1; j<=i;j++){
                        if ((i%2==1)&&(i%j==0))
                                a++;
                }
                if(a==8)
                        s++;
        }

        printf("%d\n",s);

        return 0;
}