Problem:
Score : 200 points

Problem Statement

Takahashi is standing on a two-dimensional plane, facing north. Find the minimum positive integer K such that Takahashi will be at the starting position again after he does the following action K times:

Go one meter in the direction he is facing. Then, turn X degrees counter-clockwise.

Constraints

1 \leq X \leq 179

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print the number of times Takahashi will do the action before he is at the starting position again.

Sample Input 1

90

Sample Output 1

4

Takahashi's path is a square.

Sample Input 2

1

Sample Output 2

360

Solution in C (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <stdio.h>

int cal(int comp, int input)
{
  int ret = 0;
  
  if ((comp % input) != 0) {
    ret = cal(2 * comp, input);
  } else {
    ret = comp;
  }
  
  return ret;
}

int main(void)
{
  int input;
  
  scanf("%d", &input);
  printf("%d\n", cal(360, input) / input);
  
  return 0;
}