Problem:
Score : 300 points

Problem Statement

AtCoDeer the deer is going on a trip in a two-dimensional plane.
In his plan, he will depart from point (0, 0) at time 0, then for each i between 1 and N (inclusive), he will visit point (x_i,y_i) at time t_i.

If AtCoDeer is at point (x, y) at time t, he can be at one of the following points at time t+1: (x+1,y), (x-1,y), (x,y+1) and (x,y-1).
Note that he cannot stay at his place.
Determine whether he can carry out his plan.

Constraints

1 ≤ N ≤ 10^5

0 ≤ x_i ≤ 10^5

0 ≤ y_i ≤ 10^5

1 ≤ t_i ≤ 10^5

t_i < t_{i+1} (1 ≤ i ≤ N-1)

All input values are integers.

Input

Input is given from Standard Input in the following format:

N
t_1 x_1 y_1
t_2 x_2 y_2
:
t_N x_N y_N

Output

If AtCoDeer can carry out his plan, print Yes; if he cannot, print No.

Sample Input 1

2
3 1 2
6 1 1

Sample Output 1

Yes

For example, he can travel as follows: (0,0), (0,1), (1,1), (1,2), (1,1), (1,0), then (1,1).

Sample Input 2

1
2 100 100

Sample Output 2

No

It is impossible to be at (100,100) two seconds after being at (0,0).

Sample Input 3

2
5 1 1
100 1 1

Sample Output 3

No

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>

#define num_points_max 100000

typedef struct
{
	int num_points;
	int time[num_points_max + 1];
	int rcdx[num_points_max + 1];
	int rcdy[num_points_max + 1];
} abc086c_t;

bool IsPossible (const abc086c_t * given_data)
{
	// local variables for this function
	int available_time;
	int displacement_rcdx;
	int displacement_rcdy;
	int displacement_sum;

	for (int iter = 1; iter <= (*given_data).num_points; ++iter)
	{
		available_time    = (*given_data).time[iter] - (*given_data).time[iter - 1];
		displacement_rcdx = (*given_data).rcdx[iter] - (*given_data).rcdx[iter - 1];
		displacement_rcdy = (*given_data).rcdy[iter] - (*given_data).rcdy[iter - 1];

		displacement_sum = abs(displacement_rcdx) + abs(displacement_rcdy);

		if (displacement_sum > available_time)
		{
			return false;
		}
		else if (displacement_sum % 2 != available_time % 2)
		{
			return false;
		}
		else
		{
			continue;
		}
	}

	return true;
}

void ABC086C (const abc086c_t * given_data)
{
	if   ( IsPossible(given_data) ) printf( "Yes\n" );
	else                            printf(  "No\n" );
}

int main (void)
{
	// variables for `main`
	abc086c_t given_data;
	int       retval_scanf;

	// STEP.01
	// read out the given data
	retval_scanf = scanf("%d", &given_data.num_points);

	given_data.time[0] = 0;
	given_data.rcdx[0] = 0;
	given_data.rcdy[0] = 0;

	for (int iter = 1; iter <= num_points_max; ++iter)
	{
		retval_scanf =
			scanf(
				"%d %d %d",
				&given_data.time[iter],
				&given_data.rcdx[iter],
				&given_data.rcdy[iter]
			);
	}

	// STEP.02
	// calculate & output the answer
	ABC086C(& given_data);

	// STEP.END
	return EXIT_SUCCESS;
}