Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>

int main()
{
    int n;
    int ans = 0;
    int i, j;

    scanf("%d", &n);

    for ( i = 8; i <= n; i++) {
        int cnt = 0;

        for ( j = 1; j <= i; j++) {
            if (i % j == 0) {
                cnt++;
            }
        }

        if (cnt == 8 && (i & 1)) {
            ans++;
        }
    }

    printf("%d\n", ans);

    return 0;
}