Problem:
Score : 200 points

Problem Statement

There is a square in the xy-plane. The coordinates of its four vertices are (x_1,y_1),(x_2,y_2),(x_3,y_3) and (x_4,y_4) in counter-clockwise order.
(Assume that the positive x-axis points right, and the positive y-axis points up.)

Takahashi remembers (x_1,y_1) and (x_2,y_2), but he has forgot (x_3,y_3) and (x_4,y_4).

Given x_1,x_2,y_1,y_2, restore x_3,y_3,x_4,y_4. It can be shown that x_3,y_3,x_4 and y_4 uniquely exist and have integer values.

Constraints

|x_1|,|y_1|,|x_2|,|y_2| \leq 100

(x_1,y_1) ≠ (x_2,y_2)

All values in input are integers.

Input

Input is given from Standard Input in the following format:

x_1 y_1 x_2 y_2

Output

Print x_3,y_3,x_4 and y_4 as integers, in this order.

Sample Input 1

0 0 0 1

Sample Output 1

-1 1 -1 0

(0,0),(0,1),(-1,1),(-1,0) is the four vertices of a square in counter-clockwise order.
Note that (x_3,y_3)=(1,1),(x_4,y_4)=(1,0) is not accepted, as the vertices are in clockwise order.

Sample Input 2

2 3 6 6

Sample Output 2

3 10 -1 7

Sample Input 3

31 -41 -59 26

Sample Output 3

-126 -64 -36 -131

Solution in C (GCC 9.2.1) (judge verdict: Wrong Answer)

/*
    ex7_1
    takaoga
 */

#include<stdio.h>

typedef struct point{
    int x_elem;
    int y_elem;
}point;

point shift_point(point p){
    point p_rest;
    p_rest = p;
    p.x_elem = -(p_rest.y_elem);
    p.y_elem = p_rest.x_elem; //反時計周りに90度回転をしている。なお、この場合では行列による回転の表現を採用した。
    return p;
}

int main(void){
    point p1,p2,p3,p4,p_temp; 
    scanf("%d %d %d %d",&(p1.x_elem) , &(p1.y_elem) ,&(p2.x_elem) ,&(p2.y_elem));
    if(p1.x_elem < 101 || p1.y_elem < 101 || p2.x_elem < 101 || p2.y_elem < 101 || (p1.x_elem == p2.x_elem && p1.y_elem == p2.y_elem)){
        printf("条件通りに設定してください。\n");
        return 0;
    }else{
        p_temp = p2;
        p_temp.x_elem = p_temp.x_elem - p1.x_elem;
        p_temp.y_elem = p_temp.y_elem - p1.y_elem;
        p_temp = shift_point(p_temp);
        p4.x_elem = p_temp.x_elem + p1.x_elem;
        p4.y_elem = p_temp.y_elem + p1.y_elem; //p2を、p1を基準に反時計90度回転させることで、p4を求めている。
        p_temp = p1;
        p_temp.x_elem = p_temp.x_elem - p4.x_elem;
        p_temp.y_elem = p_temp.y_elem - p4.y_elem;
        p_temp = shift_point(p_temp);
        p3.x_elem = p_temp.x_elem + p4.x_elem;
        p3.y_elem = p_temp.y_elem + p4.y_elem; //p1を、p4を基準に反時計90度回転させることで、p3を求めている。
        printf("%d %d %d %d\n", p3.x_elem ,p3.y_elem ,p4.x_elem ,p4.y_elem);
        return 0;
    }
}