Problem:
Score : 200 points

Problem Statement

Let S(n) denote the sum of the digits in the decimal notation of n.
For example, S(101) = 1 + 0 + 1 = 2.

Given an integer N, determine if S(N) divides N.

Constraints

1 \leq N \leq 10^9

Input

Input is given from Standard Input in the following format:

N

Output

If S(N) divides N, print Yes; if it does not, print No.

Sample Input 1

12

Sample Output 1

Yes

In this input, N=12.
As S(12) = 1 + 2 = 3, S(N) divides N.

Sample Input 2

101

Sample Output 2

No

As S(101) = 1 + 0 + 1 = 2, S(N) does not divide N.

Sample Input 3

999999999

Sample Output 3

Yes

Solution in C (GCC 5.4.1) (judge verdict: Runtime Error)

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>
 
int main()

{
  //int A, B, C, X, Y;
  char s[101]={};
  long long min=0;
  long long A, B, C, K;
//  int sosu[20000]={};
  int i,j,k;
  int flag=0;
  int tmp=0;
  int cnt =0;
  int next_cnt = 0;
  int tmp_cnt =0;
  int tmp_next_cnt = 0;
  long long A_temp;
//    int k=0;

  scanf("%lld", &A);
  A_temp = A;
//  printf("%s\n", s);

  for(i=0;i<9;i++){
    cnt = cnt + A%10;
    A = A/10;
//    printf("%lld\n", cnt);

  }
  
/*  while (1){
    for(i=5;i>0;i--){
      printf("cnt%d\n",cnt);
      tmp=pow(9,i);
      if(A>tmp){
        while(1){
        A = A -pow(9,i);
        cnt++;
        if(A<=tmp) break;
       }
      }
    if(A==0) break;
//      printf("%d\n",A);
    }
    for(i=6;i>0;i--){
      printf("%d\n",A);
      tmp=pow(6,i);
      printf("cnt %d\n",cnt);
      if(A>tmp){
        while(1){
        A = A -pow(6,i);
        cnt++;
      printf("cnt %d\n",cnt);
        if(A<=tmp) break;
       }
      }
    if(A==0) break;
//      printf("%d\n",A);
    }
    for(i=0;i<A;i++){
      printf("%d\n",A);
        A--;
        cnt++;
      if(A==0) break;
//      printf("%d\n",A);
    }
  break;
  }
*/
//  printf("%d\n",A_temp/cnt);  
if( A_temp%cnt == 0 )printf("Yes\n");   
else printf("No\n");  
  
return 0;
}