Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>

int main(void)
{
	int n,a,b,c,d,i,flag=0;
	char s[200000];
	scanf("%d %d %d %d %d",&n,&a,&b,&c,&d);
	scanf("%s",s);
	
	for(i=0;i<n;i++){
		if(s[i] == '#' && s[i+1] == '#'){
			//printf("NO test1\n");
			flag=0;
			break;
		}
		if(c>d){
			if(s[i] == '#' && s[i+1] == '.' && s[i+2] == '.' && s[i+3] == '#'){
				//printf("NO test2\n");
				flag=0;
				break;
			}else{
				//printf("YES test3\n");
				flag=1;
			}
		}else{
			//printf("YES test4\n");
			flag=1;
		}
	}
	if(flag == 0){
		printf("NO\n");
	}else{
		printf("YES\n");
	}
	
	
	return 0;
}