Problem:
Score : 100 points

Problem Statement

Given an integer a as input, print the value a + a^2 + a^3.

Constraints

1 \leq a \leq 10

a is an integer.

Input

Input is given from Standard Input in the following format:

a

Output

Print the value a + a^2 + a^3 as an integer.

Sample Input 1

2

Sample Output 1

14

When a = 2, we have a + a^2 + a^3 = 2 + 2^2 + 2^3 = 2 + 4 + 8 = 14.

Print the answer as an input. Outputs such as 14.0 will be judged as incorrect.

Sample Input 2

10

Sample Output 2

1110

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <string.h>
#include <ctype.h>
#include <time.h>
#define findmax(a,b) (a)>(b)?(a):(b)
#define findmin(a,b) (a)<(b)?(a):(b)
#define inout freopen("in.txt","r",stdin);freopen("out.txt","w",stdout)
#define swap(a,b) (a)+=(b);(b)=(a)-(b);(a)-=(b)
#define quicksort(a,n) qsort(a,n,sizeof(a[0]),cmp)
#define inputarr(a,n) for(int i=0;i<n;i++){scanf("%d",&a[i]);}
#define printarr(a,n) for(int i=0;i<n;i++){printf("%d ",a[i]);}puts("");
int cmp(const void *a,const void *b){return *(int *)a - *(int *)b;}

int main() {
    //inout;

    int n;

    scanf("%d", &n);

    printf("%d", n + n * n + n * n* n);

    

}