Problem:
Score : 200 points

Problem Statement

There are N cities and M roads.
The i-th road (1≤i≤M) connects two cities a_i and b_i (1≤a_i,b_i≤N) bidirectionally.
There may be more than one road that connects the same pair of two cities.
For each city, how many roads are connected to the city?

Constraints

2≤N,M≤50

1≤a_i,b_i≤N

a_i ≠ b_i

All input values are integers.

Input

Input is given from Standard Input in the following format:

N M
a_1 b_1
:
a_M b_M

Output

Print the answer in N lines.
In the i-th line (1≤i≤N), print the number of roads connected to city i.

Sample Input 1

4 3
1 2
2 3
1 4

Sample Output 1

2
2
1
1

City 1 is connected to the 1-st and 3-rd roads.

City 2 is connected to the 1-st and 2-nd roads.

City 3 is connected to the 2-nd road.

City 4 is connected to the 3-rd road.

Sample Input 2

2 5
1 2
2 1
1 2
2 1
1 2

Sample Output 2

5
5

Sample Input 3

8 8
1 2
3 4
1 5
2 8
3 7
5 2
4 1
6 8

Sample Output 3

3
3
2
2
2
1
1
2

Solution in C (Clang 3.8.0) (judge verdict: Accepted)

#include <stdio.h>

int main(void)
{
	int n,m;
	int a[51];
	int b[51];
	int i;
	int x=0;;
	int j=0;
	scanf("%d%d",&n,&m);
	for(i=0;i<m;i++){
		
		
		scanf("%d%d",&a[i],&b[i]);
		
		
		
		
		
		
	}

	for(j=1;j<=n;j++){
	for(i=0;i<m;i++){
		if(a[i]==j){
			
			
			x++;
			
			//printf("!%d %d\n",a[i],j);
			
			
			
			
			
		}
		if(b[i]==j){
			
			x++;
			
			
			
			
		}
		
		//printf("%d\n!",a[i]);
		
		
		
		
		
		
	}
	printf("%d\n",x);
	x=0;
	}
	return 0;
}