Problem:
Score : 200 points

Problem Statement

You have written N problems to hold programming contests.
The i-th problem will have a score of P_i points if used in a contest.

With these problems, you would like to hold as many contests as possible under the following condition:

A contest has three problems. The first problem has a score not greater than A points, the second has a score between A + 1 and B points (inclusive), and the third has a score not less than B + 1 points.

The same problem should not be used in multiple contests.
At most how many contests can be held?

Constraints

3 \leq N \leq 100

1 \leq P_i \leq 20 (1 \leq i \leq N)

1 \leq A < B < 20

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A B
P_1 P_2 ... P_N

Output

Print the answer.

Sample Input 1

7
5 15
1 10 16 2 7 20 12

Sample Output 1

2

Two contests can be held by putting the first, second, third problems and the fourth, fifth, sixth problems together.

Sample Input 2

8
3 8
5 5 5 10 10 10 15 20

Sample Output 2

0

No contest can be held, because there is no problem with a score of A = 3 or less.

Sample Input 3

3
5 6
5 6 10

Sample Output 3

1

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

/*
	submission # - User: herp_sy
	https://atcoder.jp/contests/

	coding: utf-8
	lang: C (GCC 5.4.1)
*/

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>
#include <stdbool.h>

#define _CRT_SECURE_NO_WARNINGS

int min3(int a, int b, int c){
	int ary[3] = {a, b, c};
	int min = 0x7F;
	for (int i = 0; i < 3; ++i)	min = (min < ary[i] ? min : ary[i]);
	return min;
}

int main(int argc, char const *argv[])
{
	int n,a,b;
	int p[103];
	int ia = 0,ib = 0,ic = 0;

	scanf("%d %d%d",&n,&a,&b);
	for (int i = 0; i < n; ++i){
		scanf("%d", &p[i]);
		if(p[i] <= a)	++ia;
		else if((a + 1) <= p[i] && p[i] <= b)	++ib;
		else ++ic;
	}
	printf("%d\n", min3(ia, ib, ic));
	return 0;
}