Problem:
Score : 300 points

Problem Statement

Given any integer x, Aoki can do the operation below.

Operation: Replace x with the absolute difference of x and K.

You are given the initial value of an integer N. Find the minimum possible value taken by N after Aoki does the operation zero or more times.

Constraints

0 ≤ N ≤ 10^{18}

1 ≤ K ≤ 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K

Output

Print the minimum possible value taken by N after Aoki does the operation zero or more times.

Sample Input 1

7 4

Sample Output 1

1

Initially, N=7.

After one operation, N becomes |7-4| = 3.

After two operations, N becomes |3-4| = 1, which is the minimum value taken by N.

Sample Input 2

2 6

Sample Output 2

2

N=2 after zero operations is the minimum.

Sample Input 3

1000000000000000000 1

Sample Output 3

0

Solution in C (GCC 9.2.1) (judge verdict: Wrong Answer)

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<math.h>
#define rep(i,n) for(int i=0;i<n;i++)
int gcd(int a, int b){
    int r=1;
    while(r!=0){
        r=a%b;
        a=b;
        b=r;
    }
    return a;
}
void revStr(char* str){
    int size = strlen(str);
    int i,j;
    char tmp = {0};
    for(i = 0, j = size - 1; i < size / 2; i++, j--){
        tmp = str[i];
        str[i] = str[j];
        str[j] = tmp;
    }return;
}
struct data{
    int a,b,c;
};

//降順
int compare_int(const void *a, const void *b)
{
    return *(int*)b - *(int*)a;
}
#define MAXSIZE 200000
int list[MAXSIZE];
int tail;

void Init(void){
    tail=0;
}
int Top(void){
    return 0;
}

int Next(int pos){
    if(pos<tail-1){
        return pos+1;
    }else{
        return -1;
    }
}
int Count(void){
    return tail;
}

int Item(int pos){
    if((pos>=0)&&(pos<tail)){
        return list[pos];
    }else{
        return 0;
    }
}
void Add(int value){
    if(tail<MAXSIZE){
        list[tail]=value;
        tail++;
    }
}
void Delete(int pos){
    if((pos>=0)&&(pos<tail)){
        int i;
        for(i=pos;i<tail-1;i++){
            list[i]=list[i+1];
        }
        tail--;
    }
}

int main(){
    long long N,K;
    scanf("%lld%lld",&N,&K);
    
    long long min=0;
    long long minn=0;
    min=N%K;
    minn=abs(K-min);
    (min<minn)?printf("%lld",min):printf("%lld",minn);
}