Problem:
Score : 100 points

Problem Statement

Given is an integer N.

Takahashi chooses an integer a from the positive integers not greater than N with equal probability.

Find the probability that a is odd.

Constraints

1 \leq N \leq 100

Input

Input is given from Standard Input in the following format:

N

Output

Print the probability that a is odd.
Your output will be considered correct when its absolute or relative error from the judge's output is at most 10^{-6}.

Sample Input 1

4

Sample Output 1

0.5000000000

There are four positive integers not greater than 4: 1, 2, 3, and 4. Among them, we have two odd numbers: 1 and 3. Thus, the answer is \frac{2}{4} = 0.5.

Sample Input 2

5

Sample Output 2

0.6000000000

Sample Input 3

1

Sample Output 3

1.0000000000

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>

int main(){

    int N=0;
    int A[100001]={};
    int B[100001]={};
    int sarch=1;
    int tmp=1;
    scanf("%d",&N);
    
    for(int i=0;i<N;i++){
        scanf("%d",&A[i]);
    }
    for(int i=0;i<N;i++){
        B[i]=tmp;
        tmp++;
    }

    tmp=0;

    for (int i=0;i<N;++i) {
        for (int j=i+1;j<N;++j) {
            if (A[i]>A[j]) {
                tmp=A[i];
                A[i]=A[j];
                A[j]=tmp;
                tmp=B[i];
                B[i]=B[j];
                B[j]=tmp;
      }
    }
  }


  for(int i=0;i<N;i++){
        printf("%d ",B[i]);
    }

    return 0;
}