Problem:
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Matrix Multiplication

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\[
c_{ij} = \sum_{k=1}^m a_{ik}b_{kj}
\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Constraints

$1 \leq n, m, l \leq 100$

$0 \leq a_{ij}, b_{ij} \leq 10000$

Sample Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2

Sample Output

1 8 5
0 9 6
4 23 14

Note

      解説

Solution in C (judge verdict: Wrong Answer)

#include<stdio.h>
int main(void){
int n,m,l,i,j,k;
int A[100][100],B[100][100],C[100][100];
for(i=0;i < 100;i++){
for(j=0;j < 100;j++){
A[i][j]=0;
B[i][j]=0;
C[i][j]=0;
}
}
scanf("%d %d %d",&n ,&m ,&l);
for(i=0;i < n;i++){
for(j=0;j < m;j++){
if (j == m-1){
scanf("%d\n",&A[i][j]);
}else{
scanf("%d ",&A[i][j]);
}
}
}
for(i=0;i < m;i++){
for(j=0;j < l;j++){
if (j == l){
scanf("%d\n",&B[i][j]);
}else{
scanf("%d ",&B[i][j]);
}
}
}
for(i=0;i < n;i++){
for(j=0;j < l;j++){
for(k=0;k < m;k++){
C[i][j] += A[i][k]*B[k][j];
}
if (j == l-1){
printf("%d\n",C[i][j]);
}else{
printf("%d ",C[i][j]);
}
}
}
return 0;
}