Problem:
Score : 400 points

Problem Statement

Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.

You are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.

Constraints

2 ≦ |s| ≦ 10^5

s consists of lowercase letters.

Partial Score

200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.

Input

The input is given from Standard Input in the following format:

s

Output

If there exists no unbalanced substring of s, print -1 -1.

If there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.

Sample Input 1

needed

Sample Output 1

2 5

The string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.

Sample Input 2

atcoder

Sample Output 2

-1 -1

The string atcoder contains no unbalanced substring.

Solution in C (GCC 5.4.1) (judge verdict: Runtime Error)

#include<stdio.h>
#include<string.h>

int main(void){
  
  int i;
  int a = -1, b = -1;
  int len;
  char str[256];
  scanf("%s", str);

  len = strlen(str);
  for(i = 0; i < len-2; i++){
    if(str[i] == str[i+1]){
      a = i;
      b = i+1;
      break;
    }
    if(str[i] == str[i+2]){
      a = i;
      b = i+2;
    }
  }
  if(str[len-1] == str[len-2]){
    a = len - 1;
    b = len - 2;
  }

  if(a != -1 && b != -1){
    a++;
    b++;
  }
  printf("%d %d\n", a, b);


  return 0;
}