Problem:
Score : 400 points

Problem Statement

Snuke has N strings. The i-th string is s_i.

Let us concatenate these strings into one string after arranging them in some order.
Find the maximum possible number of occurrences of AB in the resulting string.

Constraints

1 \leq N \leq 10^{4}

2 \leq |s_i| \leq 10

s_i consists of uppercase English letters.

Input

Input is given from Standard Input in the following format:

N
s_1
\vdots
s_N

Output

Print the answer.

Sample Input 1

3
ABCA
XBAZ
BAD

Sample Output 1

2

For example, if we concatenate ABCA, BAD and XBAZ in this order, the resulting string ABCABADXBAZ has two occurrences of AB.

Sample Input 2

9
BEWPVCRWH
ZZNQYIJX
BAVREA
PA
HJMYITEOX
BCJHMRMNK
BP
QVFABZ
PRGKSPUNA

Sample Output 2

4

Sample Input 3

7
RABYBBE
JOZ
BMHQUVA
BPA
ISU
MCMABAOBHZ
SZMEHMA

Sample Output 3

4

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
#include<string.h>
int strAB(char[],int);
int main(void){
  int N,i,len,a=0,b=0,ab=0,c=0;
  char S[12];
  scanf("%d",&N);
  for(i=0;i<N;i++){
    scanf("%s",S);
    len=strlen(S);
    c+=strAB(S,len);
    if(S[0]=='B' && S[len-1]=='A'){
      ab++;
      a++;
      b++;
    }else if(S[0]=='B' && S[len-1]!='A'){
      b++;
    }else if(S[0]!='B' && S[len-1]=='A'){
      a++;
    }else{
      continue;
    }
  }
  if(ab==b && b==a && a!=0){
    printf("%d\n",c+ab-1);
  }else if(a>b){
    printf("%d\n",c+b);
  }else{
    printf("%d\n",c+a);
  }
  return 0;
}
int strAB(char x[],int y){
  int t=0,j=0;
  while(j<y-1){
    if(x[j]=='A' && x[j+1]=='B'){
      t++;
    }
    j++;
  }
  return t;
}