Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C (GCC 5.4.1) (judge verdict: Time Limit Exceeded)

#include <stdio.h>

int main (){
	
	int i,j,a,b,N;
	
	scanf("%d", &N);
	for (i = 1; i <= N; i+2){
		a = 0;
		for (j = 1; j <= N; j+2){
			if (j >= i)
				break;
			if (i%j == 0)
				a++;
		}
		if (a == 8)
			b++; 
		
	}
	printf("%d", b);
	
	return 0;
	
}