Problem:
Score : 200 points

Problem Statement

Raccoon is fighting with a monster.

The health of the monster is H.

Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i.
There is no other way to decrease the monster's health.

Raccoon wins when the monster's health becomes 0 or below.

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Constraints

1 \leq H \leq 10^9

1 \leq N \leq 10^5

1 \leq A_i \leq 10^4

All values in input are integers.

Input

Input is given from Standard Input in the following format:

H N
A_1 A_2 ... A_N

Output

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Sample Input 1

10 3
4 5 6

Sample Output 1

Yes

The monster's health will become 0 or below after, for example, using the second and third moves.

Sample Input 2

20 3
4 5 6

Sample Output 2

No

Sample Input 3

210 5
31 41 59 26 53

Sample Output 3

Yes

Sample Input 4

211 5
31 41 59 26 53

Sample Output 4

No

Solution in C (GCC 5.4.1) (judge verdict: Time Limit Exceeded)

#include <stdio.h>
int main()
{int H,N,j,i,a,flag=0;
    scanf("%d",&H);
    scanf("%d",&N);
    int arr[N];
    for (i=0;i<N;i++)
    {scanf("%d",&arr[i]);
    }
    for (i=0;i<N;i++)
    {for (j=i+1; j<N;j++)
        {if (arr[i] < arr[j])
            {a = arr[i];
                arr[i] = arr[j];
                arr[j] = a;
            }
        }
    }
    for (i=0;i<N;i++)
    {H=H-arr[i];
        if(H<=0)
        {flag=1;
            break;
    }
    }
    if (flag==1)
    {printf("Yes");
    }
    else
    {printf("No");
    }
    return 0;
}