Problem:
Score : 100 points

Problem Statement

You have three tasks, all of which need to be completed.

First, you can complete any one task at cost 0.

Then, just after completing the i-th task, you can complete the j-th task at cost |A_j - A_i|.

Here, |x| denotes the absolute value of x.

Find the minimum total cost required to complete all the task.

Constraints

All values in input are integers.

1 \leq A_1, A_2, A_3 \leq 100

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

Print the minimum total cost required to complete all the task.

Sample Input 1

1 6 3

Sample Output 1

5

When the tasks are completed in the following order, the total cost will be 5, which is the minimum:

Complete the first task at cost 0.

Complete the third task at cost 2.

Complete the second task at cost 3.

Sample Input 2

11 5 5

Sample Output 2

6

Sample Input 3

100 100 100

Sample Output 3

0

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
int main()
{
int A1, A2, A3, chan;
scanf("%d %d %d", &A1, &A2, &A3);

if (A2 == A3)
{
  if (A1 > A2)
  {
    chan = A1;
    A1 = A3;
    A3 = chan;
  }
}
else if (A1 == A3)
{
  if (A1 > A2)
  {
    chan = A1;
    A1 = A2;
    A2 = chan;
  }
}

  else
  {
    if(A2 > A3)
    {
      chan = A2;
      A2 = A3;
      A3 = chan;
    }
    if(A1 > A2)
    {
      chan = A1;
      A1 = A2;
      A2 = chan;
    }
  }
  
  
printf("%d", A3-A1);

return 0;
}