Problem:
Score : 200 points

Problem Statement

You have written N problems to hold programming contests.
The i-th problem will have a score of P_i points if used in a contest.

With these problems, you would like to hold as many contests as possible under the following condition:

A contest has three problems. The first problem has a score not greater than A points, the second has a score between A + 1 and B points (inclusive), and the third has a score not less than B + 1 points.

The same problem should not be used in multiple contests.
At most how many contests can be held?

Constraints

3 \leq N \leq 100

1 \leq P_i \leq 20 (1 \leq i \leq N)

1 \leq A < B < 20

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A B
P_1 P_2 ... P_N

Output

Print the answer.

Sample Input 1

7
5 15
1 10 16 2 7 20 12

Sample Output 1

2

Two contests can be held by putting the first, second, third problems and the fourth, fifth, sixth problems together.

Sample Input 2

8
3 8
5 5 5 10 10 10 15 20

Sample Output 2

0

No contest can be held, because there is no problem with a score of A = 3 or less.

Sample Input 3

3
5 6
5 6 10

Sample Output 3

1

Solution in C (GCC 5.4.1) (judge verdict: Runtime Error)

#include <stdio.h>
int main(void){
int i, j, tmp, n, a, b, c=0;
int p[n];
scanf("%d",&n);
scanf("%d",&a);
scanf("%d",&b);
for(i=1;i<=n;i++){
    scanf("%d",&p[i]);
}
for(i=2;i<=n;i++){
    j = i;
    while((j>0)&&(p[j-1]>p[j])){
        tmp = p[j-1];
        p[j-1] = p[j];
        p[j] = tmp;
    }
}
for(i=1;i<=n-2;i++){
    if((p[i]<=a)&&((p[i+1]>=a+1)&&(p[i+1]<=b))&&(p[i+2]>=b+1)){
            c++;
            i = i + 2;
    }
}
printf("%d", c);
return 0;
}