Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
int main()
{
    int n,h,N,sum=0;
    double w;
    while(scanf("%d",&N)!=EOF)
    {
        sum=0;
        for(h=1 ; h<=3500 ; h++)
        {
            for(n=1 ; n<=3500 ; n++)
            {
                if(4*h*n-N*n-N*h==0)
                    continue;
                w=1.0*(N*h*n)/(4*h*n-N*n-N*h);
                if(w-(int)w==0&&w>0)
                {
                    printf("%d %d %d\n",h,n,(int)w);
                    sum++;
                }
                if(sum==1)
                    break;
            }
            if(sum==1)
                break;
        }
    }
    return 0;

}