Problem:
Score : 100 points

Problem Statement

You have three tasks, all of which need to be completed.

First, you can complete any one task at cost 0.

Then, just after completing the i-th task, you can complete the j-th task at cost |A_j - A_i|.

Here, |x| denotes the absolute value of x.

Find the minimum total cost required to complete all the task.

Constraints

All values in input are integers.

1 \leq A_1, A_2, A_3 \leq 100

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

Print the minimum total cost required to complete all the task.

Sample Input 1

1 6 3

Sample Output 1

5

When the tasks are completed in the following order, the total cost will be 5, which is the minimum:

Complete the first task at cost 0.

Complete the third task at cost 2.

Complete the second task at cost 3.

Sample Input 2

11 5 5

Sample Output 2

6

Sample Input 3

100 100 100

Sample Output 3

0

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
#include<math.h>

int main(void){
    int a, b, c;
    int dif1, dif2, dif3;
    int min, min2;
    scanf("%d %d %d", &a, &b, &c);
    dif1 = abs(a-b);
    dif2 = abs(a-c);
    dif3 = abs(b-c);
    min = dif1;
    if ( min >= dif2 ) {
        min2 = min;
        min = dif2;
    } else {
        min2 = dif2;
    }
    if ( min >= dif3 ) {
        min2 = min;
        min = dif3;
    } else if ( min2 >= dif3 ) {
        min2 = dif3;
    }
    printf("%d\n", min+min2);
    return 0;

}