Problem:
Score : 200 points

Problem Statement

There is a square in the xy-plane. The coordinates of its four vertices are (x_1,y_1),(x_2,y_2),(x_3,y_3) and (x_4,y_4) in counter-clockwise order.
(Assume that the positive x-axis points right, and the positive y-axis points up.)

Takahashi remembers (x_1,y_1) and (x_2,y_2), but he has forgot (x_3,y_3) and (x_4,y_4).

Given x_1,x_2,y_1,y_2, restore x_3,y_3,x_4,y_4. It can be shown that x_3,y_3,x_4 and y_4 uniquely exist and have integer values.

Constraints

|x_1|,|y_1|,|x_2|,|y_2| \leq 100

(x_1,y_1) ≠ (x_2,y_2)

All values in input are integers.

Input

Input is given from Standard Input in the following format:

x_1 y_1 x_2 y_2

Output

Print x_3,y_3,x_4 and y_4 as integers, in this order.

Sample Input 1

0 0 0 1

Sample Output 1

-1 1 -1 0

(0,0),(0,1),(-1,1),(-1,0) is the four vertices of a square in counter-clockwise order.
Note that (x_3,y_3)=(1,1),(x_4,y_4)=(1,0) is not accepted, as the vertices are in clockwise order.

Sample Input 2

2 3 6 6

Sample Output 2

3 10 -1 7

Sample Input 3

31 -41 -59 26

Sample Output 3

-126 -64 -36 -131

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

/* ex 7_1
   riverstone */

#include <stdio.h>

//頂点を表す構造体
typedef struct point{
    int x_elem;
    int y_elem;
}point;

//関数shift_pointの定義
//ある基点point_baseから指定された移動方向に移動させたポイントを返す
point shift_point(point point_base,point point_shift){
    point point_ret;
    point_ret.x_elem = point_base.x_elem + point_shift.y_elem;
    point_ret.y_elem = point_base.y_elem + point_shift.x_elem; 
    return point_ret;
}

int main(void){
    point point1, point2, point3, point4,point_dif;
    //入力を受け取る
    scanf("%d %d %d %d", &point1.x_elem, &point1.y_elem, &point2.x_elem, &point2.y_elem);

    //残り2点の座標を求める
    //頂点1から頂点4へのベクトル(=頂点2から頂点3へのベクトル)を定義
    point_dif.x_elem = point2.x_elem - point1.x_elem;
    point_dif.y_elem = -point2.y_elem + point1.y_elem;
 
    //頂点2を基点にして頂点3を求める
    point3 = shift_point(point2,point_dif);
    //頂点1を基点にして頂点4を求める
    point4 = shift_point(point1,point_dif);

    //出力
    printf("%d %d %d %d\n", point3.x_elem, point3.y_elem, point4.x_elem, point4.y_elem);
    return 0;
}