Problem:
Simultaneous Equation

Write a program which solve a simultaneous equation:

ax + by = c

dx + ey = f

The program should print x and y for given a, b, c, d, e and f (-1,000 ≤ a, b, c, d, e, f ≤ 1,000). You can suppose that given equation has a unique solution.

Input

The input consists of several data sets, 1 line for each data set. In a data set, there will be a, b, c, d, e, f separated by a single space. The input terminates with EOF.

Output

For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.

Sample Input 1

1 2 3 4 5 6
2 -1 -2 -1 -1 -5

Output for the Sample Input 1

-1.000 2.000
1.000 4.000

Sample Input 2

2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27

Output for the Sample Input 2

0.000 3.000
0.000 3.000

Solution in C (judge verdict: Time Limit Exceeded)

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <math.h>

int main(void)
{
	double a, b, c, d, e, f, x, y;
	double b2, c2, e2, f2;

	while (1){
		scanf("%lf %lf %lf %lf %lf %lf", &a, &b, &c, &d, &e, &f);

		b2 = b * d;
		c2 = c * d;
		e2 = e * a;
		f2 = f * a;

		y = ((c2 - f2) / (b2 - e2));
		x = (c - b * y) / a;

		/*if (x > 0){
			x += 0.0005;
		}
		else{
			x -= 0.0005;
		}

		if (y > 0){
			y += 0.0005;
		}
		else{
			y -= 0.0005;
		}*/

		printf("%.3lf %.3lf\n", x, y);
	}

	return 0;
}