Problem:
Score : 200 points

Problem Statement

Find the number of palindromic numbers among the integers between A and B (inclusive).
Here, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.

Constraints

10000 \leq A \leq B \leq 99999

All input values are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the number of palindromic numbers among the integers between A and B (inclusive).

Sample Input 1

11009 11332

Sample Output 1

4

There are four integers that satisfy the conditions: 11011, 11111, 11211 and 11311.

Sample Input 2

31415 92653

Sample Output 2

612

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
int main(void)
{
    int a,b,c,d,s=0,i,j;
    scanf("%d%d",&a,&b);
    for(i=a;i<=b;i++){
        d=i;
        c=0;
        while(d/10!=0){
            c+=d%10;
            c=c*10;
            d=d/10;
        }
        c+=d;
        if(i-c==0)
            s++;
    }
    printf("%d\n",s);
    return 0;
}