Problem:
Score : 200 points

Problem Statement

La Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each.
Determine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.

Constraints

N is an integer between 1 and 100, inclusive.

Input

Input is given from Standard Input in the following format:

N

Output

If there is a way to buy some cakes and some doughnuts for exactly N dollars, print Yes; otherwise, print No.

Sample Input 1

11

Sample Output 1

Yes

If you buy one cake and one doughnut, the total will be 4 + 7 = 11 dollars.

Sample Input 2

40

Sample Output 2

Yes

If you buy ten cakes, the total will be 4 \times 10 = 40 dollars.

Sample Input 3

3

Sample Output 3

No

The prices of cakes (4 dollars) and doughnuts (7 dollars) are both higher than 3 dollars, so there is no such way.

Solution in C (GCC 5.4.1) (judge verdict: Runtime Error)

#include <stdio.h>

int main(void)
{
	int N,x;
	scanf("%d", &N);

	if (N < 4) {
		printf("No");
	}
	else {
		for (int i = 0; i < 100; i++)
		{
			if (N % (11 * i) == 0)
			{
				printf("Yes");
			}
			else if ((N - (4 * i)) % 7 == 0)
			{
				printf("Yes");
			}
			else if ((N - (7 * i)) % 4 == 0)
			{
				printf("Yes");
			}
			else {
				printf("No");
			}
		}
	}
	return 0;
}