Problem:
Score : 300 points

Problem Statement

AtCoDeer the deer is going on a trip in a two-dimensional plane.
In his plan, he will depart from point (0, 0) at time 0, then for each i between 1 and N (inclusive), he will visit point (x_i,y_i) at time t_i.

If AtCoDeer is at point (x, y) at time t, he can be at one of the following points at time t+1: (x+1,y), (x-1,y), (x,y+1) and (x,y-1).
Note that he cannot stay at his place.
Determine whether he can carry out his plan.

Constraints

1 ≤ N ≤ 10^5

0 ≤ x_i ≤ 10^5

0 ≤ y_i ≤ 10^5

1 ≤ t_i ≤ 10^5

t_i < t_{i+1} (1 ≤ i ≤ N-1)

All input values are integers.

Input

Input is given from Standard Input in the following format:

N
t_1 x_1 y_1
t_2 x_2 y_2
:
t_N x_N y_N

Output

If AtCoDeer can carry out his plan, print Yes; if he cannot, print No.

Sample Input 1

2
3 1 2
6 1 1

Sample Output 1

Yes

For example, he can travel as follows: (0,0), (0,1), (1,1), (1,2), (1,1), (1,0), then (1,1).

Sample Input 2

1
2 100 100

Sample Output 2

No

It is impossible to be at (100,100) two seconds after being at (0,0).

Sample Input 3

2
5 1 1
100 1 1

Sample Output 3

No

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
#include <stdlib.h>


int main (void){
        int N;
        int x[100001],y[100001],t[100001];
        int dif_x,dif_y,dif_time,dif;
        x[0]=0,y[0]=0,t[0]=0;
        scanf("%d",&N);
        for (int i = 1; i <= N; i++) {
                scanf("%d %d %d",&t[i],&x[i],&y[i]);
        }

        for (int i = 1; i <= N; i++) {
                dif_x=x[i]-x[i-1];
                dif_y=y[i]-y[i-1];
                dif_time=y[i]-y[i-1];
                if (dif_x<0) {
                        dif_x*=-1;
                }
                if (dif_y<0) {
                        dif_y*=-1;
                }
                dif=dif_x+dif_y;
                if (dif>dif_time) {
                        printf("No");
                        return 0;
                }
                if ((dif_time-dif)%2==1) {
                        printf("No");
                        return 0;
                }
        }
        printf("yes");
        return 0;
}