Problem:
Score : 200 points

Problem Statement

Given are integers a,b,c and d.
If x and y are integers and a \leq x \leq b and c\leq y \leq d hold, what is the maximum possible value of x \times y?

Constraints

-10^9 \leq a \leq b \leq 10^9

-10^9 \leq c \leq d \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

a b c d

Output

Print the answer.

Sample Input 1

1 2 1 1

Sample Output 1

2

If x = 1 and y = 1 then x \times y = 1.
If x = 2 and y = 1 then x \times y = 2.
Therefore, the answer is 2.

Sample Input 2

3 5 -4 -2

Sample Output 2

-6

The answer can be negative.

Sample Input 3

-1000000000 0 -1000000000 0

Sample Output 3

1000000000000000000

Solution in C (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <stdio.h>
#include <string.h>
int main(void){
  long long int a,b,c,d;
  scanf("%iid %lld %lld %lld",&a,&b,&c,&d);

long long int ans;

if(a>=0&&b>=0&&c>=0&&d>=0)  ans=b*d;

if(a<=0&&b<=0&&c<=0&&d<=0)  ans=a*c;

if(a<=0&&b>=0&&c>=0&&d>=0)  ans=b*d;

if(a>=0&&b>=0&&c<=0&&d>=0)  ans=b*d;

if(a<=0&&b>=0&&c<=0&&d>=0){
  if(a*c>b*d){
    ans=a*c;
  }else{
    ans=b*d;
  } 
}
if(a<=0&&b<=0&&c>=0&&d>=0)  ans=b*c;

if(a>=0&&b>=0&&c<=0&&d<=0)  ans=a*d;

if(a<=0&&b<=0&&c<=0&&d>=0)  ans=a*c;

if(a<=0&&b>=0&&c<=0&&d<=0)  ans=a*c;


printf("%lld",ans);

return 0;


}