Problem:
Score : 200 points

Problem Statement

You are given string S and T consisting of lowercase English letters.

Determine if S equals T after rotation.

That is, determine if S equals T after the following operation is performed some number of times:

Operation: Let S = S_1 S_2 ... S_{|S|}. Change S to S_{|S|} S_1 S_2 ... S_{|S|-1}.

Here, |X| denotes the length of the string X.

Constraints

2 \leq |S| \leq 100

|S| = |T|

S and T consist of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S equals T after rotation, print Yes; if it does not, print No.

Sample Input 1

kyoto
tokyo

Sample Output 1

Yes

In the first operation, kyoto becomes okyot.

In the second operation, okyot becomes tokyo.

Sample Input 2

abc
arc

Sample Output 2

No

abc does not equal arc after any number of operations.

Sample Input 3

aaaaaaaaaaaaaaab
aaaaaaaaaaaaaaab

Sample Output 3

Yes

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
#include<string.h>
int main(void)
{
	char change[101],hikaku[101],take[101];
	int N;
	int i,j,k;
	scanf("%s",change);
	scanf("%s",hikaku);
	N=strlen(change);
	for(i=0;i<N;i++)
	{
		for(j=i,k=0;j<N;j++,k++)take[k]=change[j];
		for(j=0;j<i;j++,k++)take[k]=change[j];
		take[k]='\0';
		if(strcmp(take,hikaku)==0){puts("Yes");return 0;}
	}
	puts("No");
}