Problem:
Score : 200 points

Problem Statement

Let us define the FizzBuzz sequence a_1,a_2,... as follows:

If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.

If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.

If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.

If none of the above holds, a_i=i.

Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Constraints

1 \leq N \leq 10^6

Input

Input is given from Standard Input in the following format:

N

Output

Print the sum of all numbers among the first N terms of the FizzBuzz sequence.

Sample Input 1

15

Sample Output 1

60

The first 15 terms of the FizzBuzz sequence are:

1,2,\mbox{Fizz},4,\mbox{Buzz},\mbox{Fizz},7,8,\mbox{Fizz},\mbox{Buzz},11,\mbox{Fizz},13,14,\mbox{FizzBuzz}

Among them, numbers are 1,2,4,7,8,11,13,14, and the sum of them is 60.

Sample Input 2

1000000

Sample Output 2

266666333332

Watch out for overflow.

Solution in C (GCC 9.2.1) (judge verdict: Wrong Answer)

/**************************************
* AUTHOR : SHAKIL MOSHARROF 202014048 *
* NICK : xBCC [2013-2019] C/N:1819    *
* INSTITUTION : MIST CSE 20           *
***************************************/
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<ctype.h>
#include<float.h>
#define PI 3.14
int main()
{
	int n;
	scanf("%d ",&n);

	for (int i = 1; i <= n; i++)
	{
		if (i%3==0 && i%5!=0)
		{
			printf("Fizz\n");
		}
		if (i%3==0 && i%5==0)
		{
			printf("FizzBuzz\n");
		}
		if (i%3!=0 && i%5==0)
		{
			printf("Buzz\n");
		}
		if(i%3!=0 && i%5!=0)
		{
			printf("%d\n",i );
		}
	}

return 0;
}
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