Problem:
Score: 300 points

Problem Statement

M-kun is a student in Aoki High School, where a year is divided into N terms.

There is an exam at the end of each term. According to the scores in those exams, a student is given a grade for each term, as follows:

For the first through (K-1)-th terms: not given.

For each of the K-th through N-th terms: the multiplication of the scores in the last K exams, including the exam in the graded term.

M-kun scored A_i in the exam at the end of the i-th term.

For each i such that K+1 \leq i \leq N, determine whether his grade for the i-th term is strictly greater than the grade for the (i-1)-th term.

Constraints

2 \leq N \leq 200000

1 \leq K \leq N-1

1 \leq A_i \leq 10^{9}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
A_1 A_2 A_3 \ldots A_N

Output

Print the answer in N-K lines.

The i-th line should contain Yes if the grade for the (K+i)-th term is greater than the grade for the (K+i-1)-th term, and No otherwise.

Sample Input 1

5 3
96 98 95 100 20

Sample Output 1

Yes
No

His grade for each term is computed as follows:

3-rd term: (96 \times 98 \times 95) = 893760

4-th term: (98 \times 95 \times 100) = 931000

5-th term: (95 \times 100 \times 20) = 190000

Sample Input 2

3 2
1001 869120 1001

Sample Output 2

No

Note that the output should be No if the grade for the 3-rd term is equal to the grade for the 2-nd term.

Sample Input 3

15 7
3 1 4 1 5 9 2 6 5 3 5 8 9 7 9

Sample Output 3

Yes
Yes
No
Yes
Yes
No
Yes
Yes

Solution in C (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <stdio.h>
#include <stdlib.h>

typedef unsigned long long int ULLI;

void input(int *, int);
double first(int *, int,int );
double work(int *, int , int ,double );

int main()
{
	int n, k;
	int* data;
	double before=0, now;

	scanf("%d %d", &n, &k);

	data = (int*)malloc(n * sizeof(int));
	input(data, n);

	before = first(data, n,k);

	for (int i = k; i < n; i++) {
		now = work(data, i, k,before);
		if (now > before)
			printf("Yes\n");
		else
			printf("No\n");
		before = now;
	}

	return 0;
}

void input(int *data, int n)
{
	for (int i = 0; i < n; i++)
		scanf("%d", &data[i]);
}

double first(int *data, int n,int k)
{
	double sum = 0.00001;
	int count = 0;

	n--;

	for (int i = k-1; i >= 0; i--) {
		if (count == k)
			break;
		sum *= data[i];
		count++;
	}

	return sum;
}

double work(int* data, int i, int k,double before)
{
	double sum=before;

	sum /= data[i - k];
	sum *= data[i];

	return sum;
}