Problem:
Score : 100 points

Problem Statement

Given is a lowercase English letter C that is not z. Print the letter that follows C in alphabetical order.

Constraints

C is a lowercase English letter that is not z.

Input

Input is given from Standard Input in the following format:

C

Output

Print the letter that follows C in alphabetical order.

Sample Input 1

a

Sample Output 1

b

a is followed by b.

Sample Input 2

y

Sample Output 2

z

y is followed by z.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>

int main(void){
	char c;
	scanf("%s",&c);
	if(c=='a'){
		printf("b");
	}else if(c=='b'){
		printf("c");
	}else if(c=='c'){
		printf("d");
	}else if(c=='d'){
		printf("e");
	}else if(c=='e'){
		printf("f");
	}else if(c=='f'){
		printf("g");
	}else if(c=='g'){
		printf("h");
	}else if(c=='h'){
		printf("i");
	}else if(c=='i'){
		printf("j");
	}else if(c=='j'){
		printf("k");
	}else if(c=='k'){
		printf("l");
	}else if(c=='l'){
		printf("m");
	}else if(c=='m'){
		printf("n");
	}else if(c=='n'){
		printf("o");
	}else if(c=='o'){
		printf("p");
	}else if(c=='p'){
		printf("q");
	}else if(c=='p'){
		printf("q");
	}else if(c=='q'){
		printf("r");
	}else if(c=='r'){
		printf("s");
	}else if(c=='s'){
		printf("t");
	}else if(c=='t'){
		printf("u");
	}else if(c=='u'){
		printf("v");
	}else if(c=='v'){
		printf("w");
	}else if(c=='w'){
		printf("x");
	}else if(c=='x'){
		printf("y");
	}else if(c=='y'){
		printf("z");
	}
	return 0;
}