Problem:
Score : 100 points

Problem Statement

An elementary school student Takahashi has come to a variety store.

He has two coins, A-yen and B-yen coins (yen is the currency of Japan), and wants to buy a toy that costs C yen. Can he buy it?

Note that he lives in Takahashi Kingdom, and may have coins that do not exist in Japan.

Constraints

All input values are integers.

1 \leq A, B \leq 500

1 \leq C \leq 1000

Input

Input is given from Standard Input in the following format:

A B C

Output

If Takahashi can buy the toy, print Yes; if he cannot, print No.

Sample Input 1

50 100 120

Sample Output 1

Yes

He has 50 + 100 = 150 yen, so he can buy the 120-yen toy.

Sample Input 2

500 100 1000

Sample Output 2

No

He has 500 + 100 = 600 yen, but he cannot buy the 1000-yen toy.

Sample Input 3

19 123 143

Sample Output 3

No

There are 19-yen and 123-yen coins in Takahashi Kingdom, which are rather hard to use.

Sample Input 4

19 123 142

Sample Output 4

Yes

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
#include<math.h>
int main()
{
    int n;
    scanf("%d", &n);
    int a[200000], b;
    int i;
    for (i = 0; i < n; i++)
        scanf("%d", &a[i]);
    int c[28];
    for (i = 0; i < 28; i++)
        c[i] = 0;
    int j;
    int x;
    int k;
    for (i = 0; i < n; i++)
    {
        scanf("%d", &b);
        for (j = 0; j < n; j++)
        {
            x = a[j] + b;
            k = 0;
            while (x != 0)
            {
                c[k] += (x % 2);
                k++;
                x /= 2;
            }
        }
    }
    int ans = 0;
    for (i = 0; i < 28; i++)
    {
        if (c[i] % 2 == 1)
        {
            ans += pow(2, i);
        }
    }
    printf("%d\n", ans);
    return 0;
}