Problem:
Score : 300 points

Problem Statement

Hearing that energy drinks increase rating in those sites, Takahashi decides to buy up M cans of energy drinks.

There are N stores that sell energy drinks. In the i-th store, he can buy at most B_i cans of energy drinks for A_i yen (the currency of Japan) each.

What is the minimum amount of money with which he can buy M cans of energy drinks?

It is guaranteed that, in the given inputs, a sufficient amount of money can always buy M cans of energy drinks.

Constraints

All values in input are integers.

1 \leq N, M \leq 10^5

1 \leq A_i \leq 10^9

1 \leq B_i \leq 10^5

B_1 + ... + B_N \geq M

Input

Input is given from Standard Input in the following format:

N M
A_1 B_1
A_2 B_2
\vdots
A_N B_N

Output

Print the minimum amount of money with which Takahashi can buy M cans of energy drinks.

Sample Input 1

2 5
4 9
2 4

Sample Output 1

12

With 12 yen, we can buy one drink at the first store and four drinks at the second store, for the total of five drinks. However, we cannot buy 5 drinks with 11 yen or less.

Sample Input 2

4 30
6 18
2 5
3 10
7 9

Sample Output 2

130

Sample Input 3

1 100000
1000000000 100000

Sample Output 3

100000000000000

The output may not fit into a 32-bit integer type.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
#include <stdlib.h>
typedef struct data{
  long int a;
  long int b;
}Data;
long int cmpb(const void *c,const void *d){
return ((Data *)c)->a-((Data *)d)->a;
}
int main(){
  int n,m,i,j;
  scanf("%d%d",&n,&m);
  long long int ans=0,rem=m;
  Data ene[n];
  for(i=0;i<n;i++)scanf("%ld%ld",&ene[i].a,&ene[i].b);
  qsort(ene,n,sizeof(Data),cmpb);
  for(i=0;i<n&&rem>0;i++){
    if(rem>ene[i].b){
      ans+=(ene[i].a)*(ene[i].b);
      rem-=ene[i].b;
    }
    else {
      ans+=(ene[i].a)*(rem);
      break;
    }
  }
  printf("%lld",ans);
}