Problem:
Binary Search Tree II

Write a program which performs the following operations to a binary search tree $T$ by adding the find operation to A: Binary Search Tree I.

insert $k$: Insert a node containing $k$ as key into $T$.

find $k$: Report whether $T$ has a node containing $k$.

print: Print the keys of the binary search tree by inorder tree walk and preorder tree walk respectively.

Input

In the first line, the number of operations $m$ is given. In the following $m$ lines, operations represented by insert $k$, find $k$ or print are given.

Output

For each find $k$ operation, print "yes" if $T$ has a node containing $k$, "no" if not.

In addition, for each print operation, print a list of keys obtained by inorder tree walk and preorder tree walk in a line respectively. Put a space character before each key.

Constraints

The number of operations $\leq 500,000$

The number of print operations $\leq 10$.

$-2,000,000,000 \leq key \leq 2,000,000,000$

The height of the binary tree does not exceed 100 if you employ the above pseudo code.

The keys in the binary search tree are all different.

Sample Input 1

10
insert 30
insert 88
insert 12
insert 1
insert 20
find 12
insert 17
insert 25
find 16
print

Sample Output 1

yes
no
1 12 17 20 25 30 88
30 12 1 20 17 25 88

Reference

Introduction to Algorithms, Thomas H. Cormen, Charles E. Leiserson, Ronald L. Rivest, and Clifford Stein. The MIT Press.

Solution in C (judge verdict: Accepted)

#include<stdio.h>
#include<stdlib.h>
#include<string.h>

typedef struct Node{
  int key;
  struct Node *right,*left,*parent;
}Node;

Node *root,*NIL;

Node *find(Node *,int);
void insert(int);
void inorder(Node *);
void preorder(Node *);

int main() {

  int n,i,x;
  char com[10];

  scanf("%d",&n);
  for(i=0;i<n;i++) {
    scanf("%s",com);
    if(com[0] == 'f') {
      scanf("%d",&x);
      Node *t = find(root,x);
      if(t != NIL ) printf("yes\n");
      else printf("no\n");
    } else if(com[0] == 'i') {
      scanf("%d",&x);
      insert(x);
    } else if(com[0] == 'p') {
      inorder(root);
      printf("\n");
      preorder(root);
      printf("\n");
    }
  }

  return 0;

}

void insert(int k) {
  Node *y = NIL;
  Node *x = root;
  Node *z;

  z = malloc(sizeof(Node));
  z->key = k;
  z->left = NIL;
  z->right = NIL;

  while(x != NIL ) {
    y = x;
    if(z->key < x->key) {
      x = x->left;
    } else {
      x = x->right;
    }
  }

  z->parent = y;
  if(y == NIL) {
    root = z;
  } else {
    if(z->key < y->key) {
      y->left = z;
    } else {
      y->right = z;
    }
  }
}

void inorder(Node *u) {
  if(u == NIL) return;
  inorder(u->left);
  printf(" %d",u->key);
  inorder(u->right);
}

void preorder(Node *u) {
  if(u == NIL) return;
  printf(" %d",u->key);
  preorder(u->left);
  preorder(u->right);
}

Node *find(Node *u,int k) {
  while( u != NIL && k != u->key) {
    if(k < u->key) u = u->left;
    else u = u->right;
  }

  return u;
}