Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in C (judge verdict: Time Limit Exceeded)

#include<stdio.h>
#include<ctype.h>
int main(){
    char moji;
    int num, i, count[26] = {};

    for(;/* scanf("%c", &moji) != EOF*/;){
       scanf("%c", &moji);
    if ( moji == EOF ){
            break;
        }
        if( islower( moji ) ){
        num = moji - 'a';
        count[ num ] += 1;

//        printf("%d", num);
        }else if( isupper( moji ) ){
            num = moji - 'A';
            count[ num ] += 1;
        }

    }
    for( i = 0; i < 26; i++ ){
        printf("%c : %d\n", i + 'a', count[i]);
    }
    return 0;
}