Problem:
Score: 100 points

Problem Statement

E869120 has A 1-yen coins and infinitely many 500-yen coins.

Determine if he can pay exactly N yen using only these coins.

Constraints

N is an integer between 1 and 10000 (inclusive).

A is an integer between 0 and 1000 (inclusive).

Input

Input is given from Standard Input in the following format:

N
A

Output

If E869120 can pay exactly N yen using only his 1-yen and 500-yen coins, print Yes; otherwise, print No.

Sample Input 1

2018
218

Sample Output 1

Yes

We can pay 2018 yen with four 500-yen coins and 18 1-yen coins, so the answer is Yes.

Sample Input 2

2763
0

Sample Output 2

No

When we have no 1-yen coins, we can only pay a multiple of 500 yen using only 500-yen coins. Since 2763 is not a multiple of 500, we cannot pay this amount.

Sample Input 3

37
514

Sample Output 3

Yes

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

//Date: 17 - 02 - 18	//Author : Rishabh Paul

#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#include<stdbool.h>
#include<float.h>
#include<math.h>
#include<inttypes.h>
#include<assert.h>
#include<ctype.h>
#include<limits.h>
#include<time.h>
#define ll long long
#define For(i,n)	for(int i=0;i<n;i++)
#define rep(i ,a ,b)	for(int i=(a);i<=(b);i++)
#define mset(a ,value)	memset(a ,value ,sizeof(a))
#define s(a)	scanf("%d" ,&a);
#define ls(a)	scanf("%ld" ,&a)
#define reg(i)	register int i
#define infinite INT_MAX
#define MAX 100005
#define NIL -1
ll min(ll a,ll b){	return (a<b?a:b);	}
ll max(ll a,ll b){	return (a>b?a:b);	}
int main(){
	int n ,a;
	s(n);	s(a);
	int r = n % 500;
	puts(a == 0 || r > a ? "No" : "Yes");
	return 0;
}