Problem:
Score : 200 points

Problem Statement

Given are integers a,b,c and d.
If x and y are integers and a \leq x \leq b and c\leq y \leq d hold, what is the maximum possible value of x \times y?

Constraints

-10^9 \leq a \leq b \leq 10^9

-10^9 \leq c \leq d \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

a b c d

Output

Print the answer.

Sample Input 1

1 2 1 1

Sample Output 1

2

If x = 1 and y = 1 then x \times y = 1.
If x = 2 and y = 1 then x \times y = 2.
Therefore, the answer is 2.

Sample Input 2

3 5 -4 -2

Sample Output 2

-6

The answer can be negative.

Sample Input 3

-1000000000 0 -1000000000 0

Sample Output 3

1000000000000000000

Solution in C (GCC 9.2.1) (judge verdict: Accepted)


#include <stdio.h>

long long max(long long a, long long b){
    return a > b ? a :b;
}

int main(void){
    long long a, b, c, d;
    //入力
    scanf("%lld %lld %lld %lld", &a, &b ,&c ,&d);
    long long ans;
    ans = max(max(a*c, b*d), max(a*d, b*c));
    printf("%lld", ans);
    return 0; 
}
// long long は　64bit 9.22e+18
// long long lld