Problem:
Score : 400 points

Problem Statement

Snuke has N strings. The i-th string is s_i.

Let us concatenate these strings into one string after arranging them in some order.
Find the maximum possible number of occurrences of AB in the resulting string.

Constraints

1 \leq N \leq 10^{4}

2 \leq |s_i| \leq 10

s_i consists of uppercase English letters.

Input

Input is given from Standard Input in the following format:

N
s_1
\vdots
s_N

Output

Print the answer.

Sample Input 1

3
ABCA
XBAZ
BAD

Sample Output 1

2

For example, if we concatenate ABCA, BAD and XBAZ in this order, the resulting string ABCABADXBAZ has two occurrences of AB.

Sample Input 2

9
BEWPVCRWH
ZZNQYIJX
BAVREA
PA
HJMYITEOX
BCJHMRMNK
BP
QVFABZ
PRGKSPUNA

Sample Output 2

4

Sample Input 3

7
RABYBBE
JOZ
BMHQUVA
BPA
ISU
MCMABAOBHZ
SZMEHMA

Sample Output 3

4

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
#include<string.h>

int main()
{
    int N;
    long int count = 0;
    int count_A = 0;
    int count_B = 0;
    int count_AB = 0;
    
    char str[16];
    // 整数の入力
    scanf("%d", &N);

    for (int i = 0; i < N; i++) {
        int len;
        int a_flag = 0;
        scanf("%s",str);
        len = (int)strlen(str);
        //printf("len = %d\n", len);
        for (int k = 0; k < len; k++) {
            if (a_flag == 1) {
                if (str[k] == 'B') count++;
                a_flag = 0;
            }
            if (a_flag == 0) {
                if (str[k] == 'A') a_flag = 1;
            }
        }
        
        if (str[0] == 'B' && str[len - 1] == 'A') {
            count_AB++;
        }
        else if (str[0] == 'B') {
            count_B++;
        }
        else if(str[len - 1] == 'A') {
            count_A++;
        }
    }
    
    if (count_A > 0) {
        count_A--;
    }
    else if(count_AB > 0) {
        count_AB--;
    }
    else {
    }

    while (count_AB--) {
        count++;
    }
    if (count_B > 0) {
        count++;
        count_B--;
    }
    
    if (count_B > count_A) {
        count += count_A;
    }
    else {
        count += count_B;
    }

    printf("%ld\n", count);
/*
    // スペース区切りの整数の入力
    scanf("%d %d",&b,&c);
    // 文字列の入力
    scanf("%s",s);
    // 出力
    printf("%d %s\n",a+b+c,s);
*/
    return 0;
}