Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
main()
{
	int n, i, j, s, x;
	scanf("%d", &n);
	if (n<105)
	{
		x=0;
	}
	else
	{
		for (i=105, x=0; i<=n; i=i+2)
		{
			for (j=1, s=0; j<=i; j++)
			{
				if (i%j==0)
				{
					s++;
					if (j==i && s==8)
					{
						x++;
					}
				}
			}
		}
	}
	printf("%d\n", x);
	return 0;
}