Problem:
Score : 100 points

Problem Statement

You are given four digits N_1, N_2, N_3 and N_4. Determine if these can be arranged into the sequence of digits "1974".

Constraints

0 \leq N_1, N_2, N_3, N_4 \leq 9

N_1, N_2, N_3 and N_4 are integers.

Input

Input is given from Standard Input in the following format:

N_1 N_2 N_3 N_4

Output

If N_1, N_2, N_3 and N_4 can be arranged into the sequence of digits "1974", print YES; if they cannot, print NO.

Sample Input 1

1 7 9 4

Sample Output 1

YES

We can get 1974 by swapping N_2 and N_3.

Sample Input 2

1 9 7 4

Sample Output 2

YES

We already have 1974 before doing anything.

Sample Input 3

1 2 9 1

Sample Output 3

NO

Sample Input 4

4 9 0 8

Sample Output 4

NO

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
#include<stdlib.h>

int compare(const int *val1,const int* val2);

int main(void){
	int ary[4],ans[4]={1,4,7,9};
	int n=sizeof(ary)/sizeof(ary[0]);
	int i,count=0;

	for(i=0;i<n;i++){
		scanf("%d",&ary[i]);
	}

	qsort(ary,n,sizeof(int),(int(*)(const void *,const void *))compare);

	for(int j=0;j<n;j++){
		if(*(ary+j)!=*(ans+j)){
			printf("No");
			break;
		}
		else {
            count++;
		}
	}
	if(count==4)printf("Yes");

	return EXIT_SUCCESS;
}

int compare(const int* val1,const int* val2){
	if(*val1<*val2){
		return -1;
	}else if(*val1==*val2){
		return 0;
	}else{
		return 1;
	}
}