Problem:
Score : 300 points

Problem Statement

Takahashi has N balls. Initially, an integer A_i is written on the i-th ball.

He would like to rewrite the integer on some balls so that there are at most K different integers written on the N balls.

Find the minimum number of balls that Takahashi needs to rewrite the integers on them.

Constraints

1 \leq K \leq N \leq 200000

1 \leq A_i \leq N

All input values are integers.

Input

Input is given from Standard Input in the following format:

N K
A_1 A_2 ... A_N

Output

Print the minimum number of balls that Takahashi needs to rewrite the integers on them.

Sample Input 1

5 2
1 1 2 2 5

Sample Output 1

1

For example, if we rewrite the integer on the fifth ball to 2, there are two different integers written on the balls: 1 and 2.
On the other hand, it is not possible to rewrite the integers on zero balls so that there are at most two different integers written on the balls, so we should print 1.

Sample Input 2

4 4
1 1 2 2

Sample Output 2

0

Already in the beginning, there are two different integers written on the balls, so we do not need to rewrite anything.

Sample Input 3

10 3
5 1 3 2 4 1 1 2 3 4

Sample Output 3

3

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <limits.h>
#include <math.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>

// 内部定数
#define D_BALL_MAX		200000									// 最大ボール数

// 内部変数
static int si1Ball[D_BALL_MAX + 5];								// ボール
static int siBCnt;												// ボール数
static int si1Kind[D_BALL_MAX + 5];								// 同一種類(個数)
static int siCCnt;												// 同一種類(個数)数

// 内部変数 - テスト用
#ifdef D_TEST
	static int siRes;
	static FILE *szpFpT, *szpFpA;
#endif

// ソート関数 - int昇順
int
fSortFnc(
	const void *pzpVal1			// <I> 値１
	, const void *pzpVal2		// <I> 値２
)
{
	int *lipVal1 = (int *)pzpVal1;
	int *lipVal2 = (int *)pzpVal2;

	// 昇順
	if (*lipVal1 >  *lipVal2) {
		return(1);
	}
	else if (*lipVal1 < *lipVal2) {
		return(-1);
	}

	return 0;
}

// 実行メイン
int
fMain(
	int piTNo					// <I> テスト番号 1～
)
{
	int i;
	char lc1Buf[1024], lc1Out[1024];

	// テストファイルオープン
#ifdef D_TEST
	sprintf(lc1Buf, ".\\Test\\T%d.txt", piTNo);
	szpFpT = fopen(lc1Buf, "r");
	sprintf(lc1Buf, ".\\Test\\A%d.txt", piTNo);
	szpFpA = fopen(lc1Buf, "r");
	siRes = 0;
#endif

	// ボール数・種類数取得
	int liKCnt;
#ifdef D_TEST
	fgets(lc1Buf, sizeof(lc1Buf), szpFpT);
#else
	fgets(lc1Buf, sizeof(lc1Buf), stdin);
#endif
	sscanf(lc1Buf, "%d%d", &siBCnt, &liKCnt);

	// ボール取得
	for (i = 0; i < siBCnt; i++) {
#ifdef D_TEST
		fscanf(szpFpT, "%d", &si1Ball[i]);
#else
		fscanf(stdin, "%d", &si1Ball[i]);
#endif
	}
#ifdef D_TEST
	fgets(lc1Buf, sizeof(lc1Buf), szpFpT);
#else
	fgets(lc1Buf, sizeof(lc1Buf), stdin);
#endif

	// ソート
	qsort(si1Ball, siBCnt, sizeof(int), fSortFnc);

	// 同一種類(個数)セット
	si1Kind[0] = 1;
	siCCnt = 1;
	for (i = 1; i < siBCnt; i++) {

		// １個前と比較
		if (si1Ball[i] == si1Ball[i - 1]) {		// 一致
			si1Kind[siCCnt - 1]++;
		}
		else {									// 不一致
			si1Kind[siCCnt] = 1;
			siCCnt++;
		}
	}

	// ソート
	qsort(si1Kind, siCCnt, sizeof(int), fSortFnc);

	// 不要な種類数
	liKCnt = siCCnt - liKCnt;

	// 不要なボール数
	int liBCnt = 0;
	for (i = 0; i < liKCnt; i++) {
		liBCnt += si1Kind[i];
	}

	// 結果セット
	sprintf(lc1Out, "%d\n", liBCnt);

	// 結果表示
#ifdef D_TEST
	fgets(lc1Buf, sizeof(lc1Buf), szpFpA);
	if (strcmp(lc1Buf, lc1Out)) {
		siRes = -1;
	}
#else
	printf("%s", lc1Out);
#endif

	// テストファイルクローズ
#ifdef D_TEST
	fclose(szpFpT);
	fclose(szpFpA);
#endif

	// テスト結果
#ifdef D_TEST
	if (siRes == 0) {
		printf("OK %d\n", piTNo);
	}
	else {
		printf("NG %d\n", piTNo);
	}
#endif

	return 0;
}

int
main()
{

#ifdef D_TEST
	int i;
	for (i = D_TEST_SNO; i <= D_TEST_ENO; i++) {
		fMain(i);
	}
#else
	fMain(0);
#endif

	return 0;
}