Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<math.h>

#define MAX(p,q) ((p>q)?(p):(q))
#define MIN(p,q) ((p<q)?(p):(q))

#define INF 1000000000;
#define REP(i,n) for(i=0;i<n;i++)

int gcd(int a,int b);
/*比較函数の実装
int -32768 to 32767 (2**15-1)
long -2147483648 to 2147483648 (2**31-1)
*/
int intcmp(const void *a,const void *b){
  return *(int *)a - *(int *)b;
}
//qsort(a,sizeof(a)/sizeof(int),sizeof(int),intcmp);
int longcmp(const void *a,const void *b){
  return *(long *)a - *(long *)b;
}
//qsort(a,sizeof(a)/sizeof(long),sizeof(long),longcmp);
int doublecmp(const void *a, const void *b){
  return *(double *)a - *(double *)b;
}
//qsort(a,sizeof(a)/sizeof(double),sizeof(double),doublecmp);
int main(void)
{
  int n,a,b,c,d;
  scanf("%d%d%d%d%d",&n,&a,&b,&c,&d);
  char s[200001];
  int i,flag1=0,flag2=0,max1=0,max2=0,fc1=0,fc2=0,mc1=0,mc2=0;
  REP(i,n+1)
  {
    scanf("%c",&s[i]);
    if(s[i]=='#') {
      if(i>a&&i<d)
      flag1++;
      if(i<c) {
        fc1++;
      //  printf("%dのfc1は%d\n",i,fc1);
      }
      if(i>=b) {
        fc2++;
        //printf("%dのfc2は%d\n",i,fc2);
      }
    }
    else{
      if(max1<flag1) max1 = flag1;
      flag1 = 0;
      if(mc1<fc1) mc1 = fc1;
      fc1 = 0;
      if(mc2<fc2) mc2 = fc2;
      fc2 = 0;
    }
    if(s[i]=='.') flag2++;
    else{
      if(max2<flag2) max2 = flag2;
      flag2 = 0;
    }
    //printf("s[%d]は%c\n",i,s[i]);


  }
  //printf("%d\t%d",mc1,mc2);
  //if(c<b&&mc1<2&&mc2<2) printf("Yes\n");
   if (max1 >= 2) printf("No\n");
  else if(c < d) printf("Yes\n");
  else if(max2 >= 3) printf("Yes\n");
  else printf("No\n");
  return 0;
}

int gcd(int a,int b)
{
  int max,min,tmp;
  max = MAX(a,b);
  min = MIN(a,b);
  if(max%min==0) return min;
  else
  {
    tmp = min;
    min = max%min;
    max = tmp;
    return gcd(max,min);
  }
}