Problem:
Score : 500 points

Problem Statement

On a two-dimensional plane, there are m lines drawn parallel to the x axis, and n lines drawn parallel to the y axis.
Among the lines parallel to the x axis, the i-th from the bottom is represented by y = y_i.
Similarly, among the lines parallel to the y axis, the i-th from the left is represented by x = x_i.

For every rectangle that is formed by these lines, find its area, and print the total area modulo 10^9+7.

That is, for every quadruple (i,j,k,l) satisfying 1\leq i < j\leq n and 1\leq k < l\leq m, find the area of the rectangle formed by the lines x=x_i, x=x_j, y=y_k and y=y_l, and print the sum of these areas modulo 10^9+7.

Constraints

2 \leq n,m \leq 10^5

-10^9 \leq x_1 < ... < x_n \leq 10^9

-10^9 \leq y_1 < ... < y_m \leq 10^9

x_i and y_i are integers.

Input

Input is given from Standard Input in the following format:

n m
x_1 x_2 ... x_n
y_1 y_2 ... y_m

Output

Print the total area of the rectangles, modulo 10^9+7.

Sample Input 1

3 3
1 3 4
1 3 6

Sample Output 1

60

The following figure illustrates this input:

The total area of the nine rectangles A, B, ..., I shown in the following figure, is 60.

Sample Input 2

6 5
-790013317 -192321079 95834122 418379342 586260100 802780784
-253230108 193944314 363756450 712662868 735867677

Sample Output 2

835067060

Solution in C (GCC 5.4.1) (judge verdict: Runtime Error)

#include <stdio.h>
#define MOD 1000000007

int main(void) {
	int n,m;
	long x[50],y[50];

	scanf("%d %d",&n,&m);
	for (int i = 0;i < n;i++) {
		scanf("%lld",&x[i]);
	}
	for (int i = 0;i < m;i++) {
		scanf("%lld",&y[i]);
	}
	
	long sumx = 0L;
	long tmp;
	for (int i = 0;i < n-1;i++) {
		tmp = (x[i+1]-x[i])*(i+1);
		tmp %= MOD;
		tmp *= (n-1-i);
		tmp %= MOD;
		sumx += tmp;
	}
	long sumy = 0L;
	for (int i = 0;i < m-1;i++) {
		tmp = (y[i+1]-y[i])*(i+1);
		tmp %= MOD;
		tmp *= (m-1-i);
		tmp %= MOD;
		sumy += tmp;
	}
	printf("%lld\n", (sumx*sumy)%MOD);
	
	return 0;
}