Problem:
Score : 200 points

Problem Statement

There are N + 1 squares arranged in a row, numbered 0, 1, ..., N from left to right.

Initially, you are in Square X.
You can freely travel between adjacent squares. Your goal is to reach Square 0 or Square N.
However, for each i = 1, 2, ..., M, there is a toll gate in Square A_i, and traveling to Square A_i incurs a cost of 1.
It is guaranteed that there is no toll gate in Square 0, Square X and Square N.

Find the minimum cost incurred before reaching the goal.

Constraints

1 \leq N \leq 100

1 \leq M \leq 100

1 \leq X \leq N - 1

1 \leq A_1 < A_2 < ... < A_M \leq N

A_i \neq X

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M X
A_1 A_2 ... A_M

Output

Print the minimum cost incurred before reaching the goal.

Sample Input 1

5 3 3
1 2 4

Sample Output 1

1

The optimal solution is as follows:

First, travel from Square 3 to Square 4. Here, there is a toll gate in Square 4, so the cost of 1 is incurred.

Then, travel from Square 4 to Square 5. This time, no cost is incurred.

Now, we are in Square 5 and we have reached the goal.

In this case, the total cost incurred is 1.

Sample Input 2

7 3 2
4 5 6

Sample Output 2

0

We may be able to reach the goal at no cost.

Sample Input 3

10 7 5
1 2 3 4 6 8 9

Sample Output 3

3

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

 #include<stdio.h>
 int main(void)
 {
     int N,M,X,A[100];
     int i,j=0,k=0,l=0;

     scanf("%d%d%d",&N,&M,&X);

     for(i=0;i<M;i++)
       scanf("%d",&A[i]);

     for(i=0;i<M;i++){
       if(X<N-X){
         if((A[i]>0)&&(A[i]<X)) j++;
       }
       else if(X>N-X){
         if((A[i]>X)&&(A[i]<N)) j++;
       }
       else if(X==N-X){
         if((A[i]>0)&&(A[i]<X)) k++;
         if((A[i]>X)&&(A[i]<N)) l++;
       }
     }

     if(k<l) printf("%d\n",k);
     else if(k>l) printf("%d\n",l);
     else printf("%d\n",j);

     return 0;
 }