Problem:
Score : 100 points

Problem Statement

Given is an integer N.

Takahashi chooses an integer a from the positive integers not greater than N with equal probability.

Find the probability that a is odd.

Constraints

1 \leq N \leq 100

Input

Input is given from Standard Input in the following format:

N

Output

Print the probability that a is odd.
Your output will be considered correct when its absolute or relative error from the judge's output is at most 10^{-6}.

Sample Input 1

4

Sample Output 1

0.5000000000

There are four positive integers not greater than 4: 1, 2, 3, and 4. Among them, we have two odd numbers: 1 and 3. Thus, the answer is \frac{2}{4} = 0.5.

Sample Input 2

5

Sample Output 2

0.6000000000

Sample Input 3

1

Sample Output 3

1.0000000000

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

int main()
{
	int i, j, A[100000], B[100000];
	int N;
	scanf("%d", &N);

	for (i = 0; i < N; i++) {
		scanf("%d", &A[i]);
	}
	
	for (i = 1; i <= N; i++) {
		for (j = 0; j < N; j++) {
			if (A[j] == i) {
				B[i - 1] = j;
			}
		}
	}

	for (i = 0; i < N; i++) {
		printf("%d ", B[i] + 1);
	}
}