Problem:
Score : 200 points

Problem Statement

The word internationalization is sometimes abbreviated to i18n.
This comes from the fact that there are 18 letters between the first i and the last n.

You are given a string s of length at least 3 consisting of lowercase English letters.
Abbreviate s in the same way.

Constraints

3 ≤ |s| ≤ 100 (|s| denotes the length of s.)

s consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s

Output

Print the abbreviation of s.

Sample Input 1

internationalization

Sample Output 1

i18n

Sample Input 2

smiles

Sample Output 2

s4s

Sample Input 3

xyz

Sample Output 3

x1z

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

#include <stdio.h>
#include <string.h>
int main(){
  char	s[100+1]={0}, f[2]={0}, e[2]={0}, buff[8]={0};
  int	len;
  scanf("%s",s);
  
  len=strlen(s);
  strncpy(f, s, 1);
  strncpy(e, &s[len-1], 1);
  
  sprintf(buff, "%s%d%s", f, len-2, e);
  printf("%s\n", buff);
  
  return 0;
}