Problem:
Score: 300 points

Problem Statement

M-kun is a student in Aoki High School, where a year is divided into N terms.

There is an exam at the end of each term. According to the scores in those exams, a student is given a grade for each term, as follows:

For the first through (K-1)-th terms: not given.

For each of the K-th through N-th terms: the multiplication of the scores in the last K exams, including the exam in the graded term.

M-kun scored A_i in the exam at the end of the i-th term.

For each i such that K+1 \leq i \leq N, determine whether his grade for the i-th term is strictly greater than the grade for the (i-1)-th term.

Constraints

2 \leq N \leq 200000

1 \leq K \leq N-1

1 \leq A_i \leq 10^{9}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
A_1 A_2 A_3 \ldots A_N

Output

Print the answer in N-K lines.

The i-th line should contain Yes if the grade for the (K+i)-th term is greater than the grade for the (K+i-1)-th term, and No otherwise.

Sample Input 1

5 3
96 98 95 100 20

Sample Output 1

Yes
No

His grade for each term is computed as follows:

3-rd term: (96 \times 98 \times 95) = 893760

4-th term: (98 \times 95 \times 100) = 931000

5-th term: (95 \times 100 \times 20) = 190000

Sample Input 2

3 2
1001 869120 1001

Sample Output 2

No

Note that the output should be No if the grade for the 3-rd term is equal to the grade for the 2-nd term.

Sample Input 3

15 7
3 1 4 1 5 9 2 6 5 3 5 8 9 7 9

Sample Output 3

Yes
Yes
No
Yes
Yes
No
Yes
Yes

Solution in C (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <stdio.h>

int main(int argc, char const *argv[]) {
  int n,k;
  scanf("%d %d",&n,&k);
  long long int  a[n+10];
  for (int i = 0; i < n+10; i++) {
    a[i] = 0;
  }
  for (size_t i = 0; i < n; i++) {
    scanf("%d",&a[i]);
  }
  long long v[n+10];
  for (int i = 0; i < n+10; i++) {
    v[i] = 0;
  }
  long long vk = 1;
  for (int i = 0; i < k; i++) {
    vk *= a[i];
  }
  v[k] = vk;
  for (int i = k+1; i <= n ; i++) {

    v[i] = (v[i-1] / a[i-k-1]) * a[i-1];
    if (v[i-1] < v[i]) {
      printf("Yes\n");
    }else{
      printf("No\n");
    }
  
  }
  return 0;
}