Problem:
Simultaneous Equation

Write a program which solve a simultaneous equation:

ax + by = c

dx + ey = f

The program should print x and y for given a, b, c, d, e and f (-1,000 ≤ a, b, c, d, e, f ≤ 1,000). You can suppose that given equation has a unique solution.

Input

The input consists of several data sets, 1 line for each data set. In a data set, there will be a, b, c, d, e, f separated by a single space. The input terminates with EOF.

Output

For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.

Sample Input 1

1 2 3 4 5 6
2 -1 -2 -1 -1 -5

Output for the Sample Input 1

-1.000 2.000
1.000 4.000

Sample Input 2

2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27

Output for the Sample Input 2

0.000 3.000
0.000 3.000

Solution in C (judge verdict: Wrong Answer)

#include <stdio.h>

int main(void)
{
	int a, b, c, d, e, f;
	float x, y;
	
	while(scanf("%d %d %d %d %d %d", &a, &b, &c, &d, &e, &f) != EOF){
		for(x = -1000; x < 1000; x++){
			for(y = -1000; y < 1000; y++){
				if((a * x) + (b * y) == c && (d * x) + (e * y) == f){
					printf("%.3f %.3f\n", x, y);
				}
			}
		}
	}
	
	return (0);
}