Problem:
Score : 200 points

Problem Statement

The word internationalization is sometimes abbreviated to i18n.
This comes from the fact that there are 18 letters between the first i and the last n.

You are given a string s of length at least 3 consisting of lowercase English letters.
Abbreviate s in the same way.

Constraints

3 ≤ |s| ≤ 100 (|s| denotes the length of s.)

s consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s

Output

Print the abbreviation of s.

Sample Input 1

internationalization

Sample Output 1

i18n

Sample Input 2

smiles

Sample Output 2

s4s

Sample Input 3

xyz

Sample Output 3

x1z

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

/* ex6_2 melo */
#include <stdio.h>
#include<string.h> //文字列関数
#define SIZE 101 //文字列の大きさを定義
int main(void){
    char sente[SIZE];
    int length,i;
    for(i=0;i<SIZE;++i){
        sente[i]=getchar();
        if(sente[i]=='\n')break;
    }
    length=(int)strlen(sente)-1;
    printf("%c%d%c\n",sente[0],length-2,sente[length-1]);
    return 0;
}