Problem:
Disjoint Set

Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.

same(x, y): determine whether x and y are in the same set.

Input

n q
com1 x1 y1
com2 x2 y2
...
comq xq yq

In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Constraints

1 ≤ n ≤ 10000

1 ≤ q ≤ 100000

x ≠ y

Sample Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0

Sample Output

0
0
1
1
1
0
1
1

Solution in C (judge verdict: Accepted)

#include <stdio.h>
#define MAX_N 10000

int par[MAX_N], rank[MAX_N];

void init(int n);
int find(int x);
void unite(int x, int y);
int same(int x, int y);

void init(int n)
{
    int i;
    for (i = 0; i < n; i++) {
        par[i] = i;
        rank[i] = 0;
    }
}

int find(int x)
{
    if (par[x] == x) {
        return x;
    } else {
        return par[x] = find(par[x]);
    }
}

void unite(int x, int y)
{
    x = find(x);
    y = find(y);
    if (x == y) {
        return ;
    }
    if (rank[x] < rank[y]) {
        par[x] = y;
    } else {
        par[y] = x;
        if (rank[x] == rank[y]) {
            rank[x]++;
        }
    }
}

int same(int x, int y)
{
    //同じなら0, 違うならそれ以外
    return find(x) - find(y);
}

int main(void)
{
    int n, q, i, j, com, x, y;
    scanf("%d %d", &n, &q);
    init(n);
    for (i = 0; i < q; i++) {
        scanf("%d %d %d", &com, &x, &y);
        if (com) {
            if (same(x, y)) {
                puts("0");
            } else {
                puts("1");
            }
        } else {
            unite(x, y);
        }
    }
    return 0;
}