Problem:
Score : 300 points

Problem Statement

You are given two integer sequences of length N: a_1,a_2,..,a_N and b_1,b_2,..,b_N.
Determine if we can repeat the following operation zero or more times so that the sequences a and b become equal.

Operation: Choose two integers i and j (possibly the same) between 1 and N (inclusive), then perform the following two actions simultaneously:

Add 2 to a_i.

Add 1 to b_j.

Constraints

1 ≤ N ≤ 10 000

0 ≤ a_i,b_i ≤ 10^9 (1 ≤ i ≤ N)

All input values are integers.

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 .. a_N
b_1 b_2 .. b_N

Output

If we can repeat the operation zero or more times so that the sequences a and b become equal, print Yes; otherwise, print No.

Sample Input 1

3
1 2 3
5 2 2

Sample Output 1

Yes

For example, we can perform three operations as follows to do our job:

First operation: i=1 and j=2. Now we have a = \{3,2,3\}, b = \{5,3,2\}.

Second operation: i=1 and j=2. Now we have a = \{5,2,3\}, b = \{5,4,2\}.

Third operation: i=2 and j=3. Now we have a = \{5,4,3\}, b = \{5,4,3\}.

Sample Input 2

5
3 1 4 1 5
2 7 1 8 2

Sample Output 2

No

Sample Input 3

5
2 7 1 8 2
3 1 4 1 5

Sample Output 3

No

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)


#include <stdio.h>
#include <stdlib.h>
int compare(const void *a,const void *b){
    if(*(int *)a>*(int* )b )return 1;
    return -1;
}
int main()
{   int n;
    scanf("%d",&n);
    int a[n],b[n];
    long long asum=0,bsum=0;
    for(int i=0;i<n;i++){
        scanf("%d",&a[i]);
        asum+=a[i];
    }
    for(int i=0;i<n;i++){
        scanf("%d",&b[i]);
        bsum+=b[i];
    }
    long long stocka=0,stockb=0;
    for(int i=0;i<n;i++){
        if(a[i]==b[i])continue;
        if(a[i]>b[i]){
            stocka+=(a[i]-b[i]);
            //printf("@%d stocka %d\n",i,stocka);
        }else{
            stockb+=((b[i]-a[i]+1)/2);
            //printf("@%d stockb %d\n",i,stockb);
        }
    }
    //printf("stocka=%lld,stockb=%lld\n",stocka,stockb);
    if(bsum-asum>=stockb+stocka){
        printf("Yes");
        return 0;
    }else{
        printf("No");
        return 0;
    }
    

    return 0;
}