Problem:
Score : 200 points

Problem Statement

Find the number of palindromic numbers among the integers between A and B (inclusive).
Here, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.

Constraints

10000 \leq A \leq B \leq 99999

All input values are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the number of palindromic numbers among the integers between A and B (inclusive).

Sample Input 1

11009 11332

Sample Output 1

4

There are four integers that satisfy the conditions: 11011, 11111, 11211 and 11311.

Sample Input 2

31415 92653

Sample Output 2

612

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
int main() {
	int a, b, ans = 0, n;
	int num[5];
	scanf("%d%d", &a, &b);
	for (int i = a; i <= b; i++) {
		n = i;
		for (int j = 0; j < 5; j++) {
			num[j] = n % 10;
			n /= 10;
		}
		if (num[0] == num[4] && num[1] == num[3]) {
			ans++;
		}
	}
	printf("%d\n", ans);
	return 0;
}