Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
#include<string.h>
int main(void)
{
   int s, smt34, smt12;

   scanf("%d", &s);

   smt34 = s % 100;
   smt12 = s / 100;
   char cs[][10]= {"YYMM", "MMYY", "AMBIGUOUS", "NA"};

   if((smt34 <= 12 && smt34 >0)&& smt12 > 12)
      printf("%s", cs[0]);

   else if(smt34 > 12 && (smt12 <= 12 && smt12 > 0))
      printf("%s", cs[1]);

   else if((smt34 <=12 && smt34 > 0) || (smt12 <= 12 && smt12 > 0))
      printf("%s",cs[2]);

   else printf("%s", cs[3]);

   return 0;
   
}