Problem:
Score : 200 points

Problem Statement

The word internationalization is sometimes abbreviated to i18n.
This comes from the fact that there are 18 letters between the first i and the last n.

You are given a string s of length at least 3 consisting of lowercase English letters.
Abbreviate s in the same way.

Constraints

3 ≤ |s| ≤ 100 (|s| denotes the length of s.)

s consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s

Output

Print the abbreviation of s.

Sample Input 1

internationalization

Sample Output 1

i18n

Sample Input 2

smiles

Sample Output 2

s4s

Sample Input 3

xyz

Sample Output 3

x1z

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

/* ex6_2 KitamoriFumiya */
#include <stdio.h>
#include <string.h>

int main(void){
	char word[100]; // word(英単語)を文字列として宣言
	int length; // length(wordの長さ)をint型の変数として宣言
	scanf("%s", word); // wordを入力
	length = strlen(word); // 単語の長さを求める
	printf("%c", word[0]); // 単語の先頭文字を出力
	printf("%d", length-2); // 単語の文字数から先頭文字と末尾文字の2文字を抜いた文字数を出力
	printf("%c\n", word[length-1]); // 単語の末尾文字を出力
	return 0;
}