Problem:
Score : 200 points

Problem Statement

There is a square in the xy-plane. The coordinates of its four vertices are (x_1,y_1),(x_2,y_2),(x_3,y_3) and (x_4,y_4) in counter-clockwise order.
(Assume that the positive x-axis points right, and the positive y-axis points up.)

Takahashi remembers (x_1,y_1) and (x_2,y_2), but he has forgot (x_3,y_3) and (x_4,y_4).

Given x_1,x_2,y_1,y_2, restore x_3,y_3,x_4,y_4. It can be shown that x_3,y_3,x_4 and y_4 uniquely exist and have integer values.

Constraints

|x_1|,|y_1|,|x_2|,|y_2| \leq 100

(x_1,y_1) ≠ (x_2,y_2)

All values in input are integers.

Input

Input is given from Standard Input in the following format:

x_1 y_1 x_2 y_2

Output

Print x_3,y_3,x_4 and y_4 as integers, in this order.

Sample Input 1

0 0 0 1

Sample Output 1

-1 1 -1 0

(0,0),(0,1),(-1,1),(-1,0) is the four vertices of a square in counter-clockwise order.
Note that (x_3,y_3)=(1,1),(x_4,y_4)=(1,0) is not accepted, as the vertices are in clockwise order.

Sample Input 2

2 3 6 6

Sample Output 2

3 10 -1 7

Sample Input 3

31 -41 -59 26

Sample Output 3

-126 -64 -36 -131

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

/* ex 7_1 AtCoder Beginner Contest 108 B
   nk777 */

// ↑y
// →x

#include <stdio.h>
// 頂点を返す構造体point
typedef struct point{
    int x_elem;
    int y_elem;
}point;
// ある頂点についてx軸、y軸について移動させた頂点を返す関数
// 求めたい点の2個前の点point_2before, 1個前の点point_1before
point shift_point(point point_2before, point point_1before){
    // 求めたい頂点point_next
    point point_next;
    // 符号付きの差lenX, lenY
    int lenX, lenY;
    lenX = point_1before.x_elem - point_2before.x_elem;
    lenY = point_1before.y_elem - point_2before.y_elem;
    // 1個前の点にxとyの差を入れ替えて足す。ただしyの差は符号を変える
    point_next.x_elem = point_1before.x_elem - lenY;
    point_next.y_elem = point_1before.y_elem + lenX;
    return point_next;
}

int main(void){
    // 点point1(x1,y1), 点point2(x2,y2), 点point3, 点point4
    point point1, point2, point3, point4;
    int x1, y1, x2, y2;
    scanf("%d %d %d %d", &x1, &y1, &x2, &y2);

    // 点point1(x1,y1), 点point2(x2,y2)を構造体に入れる
    point1.x_elem = x1;
    point1.y_elem = y1;
    point2.x_elem = x2;
    point2.y_elem = y2;
    // 移動した値を代入
    point3 = shift_point(point1, point2);
    point4 = shift_point(point2, point3);

    // 出力
    printf("%d %d %d %d\n", point3.x_elem, point3.y_elem, point4.x_elem, point4.y_elem);

    return 0;
}