Problem:
Score : 200 points

Problem Statement

Tak performed the following action N times: rolling two dice.
The result of the i-th roll is D_{i,1} and D_{i,2}.

Check if doublets occurred at least three times in a row.
Specifically, check if there exists at lease one i such that D_{i,1}=D_{i,2}, D_{i+1,1}=D_{i+1,2} and D_{i+2,1}=D_{i+2,2} hold.

Constraints

3 \leq N \leq 100

1\leq D_{i,j} \leq 6

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
D_{1,1} D_{1,2}
\vdots
D_{N,1} D_{N,2}

Output

Print Yes if doublets occurred at least three times in a row. Print No otherwise.

Sample Input 1

5
1 2
6 6
4 4
3 3
3 2

Sample Output 1

Yes

From the second roll to the fourth roll, three doublets occurred in a row.

Sample Input 2

5
1 1
2 2
3 4
5 5
6 6

Sample Output 2

No

Sample Input 3

6
1 1
2 2
3 3
4 4
5 5
6 6

Sample Output 3

Yes

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

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#include <stdio.h>

int main()
{
    int N;
    int D1[100];
    int D2[100];
    int i;
    int count = 0;
    int flag = 0;
    
    scanf("%d", &N);
    
    for(i=0;i<N;i++){
        scanf("%d %d", &D1[i],&D2[i]);
    }


    for(i=0;i<N;i++){
        if(D1[i] == D2[i]){
            count++;
            if(count>=3){
                flag =1;   
            }
        }
        if(D1[i] != D2[i]){
            count = 0;
        } 
    }

 
    if(flag==1){
        printf("Yes");
    }
    else{
        printf("No");
    }

    return 0;
}