Problem:
Score : 100 points

Problem Statement

A Hitachi string is a concatenation of one or more copies of the string hi.

For example, hi and hihi are Hitachi strings, while ha and hii are not.

Given a string S, determine whether S is a Hitachi string.

Constraints

The length of S is between 1 and 10 (inclusive).

S is a string consisting of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S

Output

If S is a Hitachi string, print Yes; otherwise, print No.

Sample Input 1

hihi

Sample Output 1

Yes

hihi is the concatenation of two copies of hi, so it is a Hitachi string.

Sample Input 2

hi

Sample Output 2

Yes

Sample Input 3

ha

Sample Output 3

No

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
#include<string.h>
int main(void){
    char str1[] = "hi";
    char str3[] = "hihi";
    char str4[] = "hihihi";
    char str5[] = "hihihihi";
    char str6[] = "hihihihihi";
    char str2[10];
    int n;
     
    scanf("%s",str2);
    
    n=strlen(str2);
  
    if(n==2){  
     //2
     if(strstr(str2,str1)==0)
     {
         printf("No\n");
     }
     else
     {
         printf("Yes\n");
     }
    }else if(n==4){  
     //4
     if(strstr(str2,str3)==0)
     {
         printf("No\n");
     }
     else
     {
         printf("Yes\n");
     }
    }else if(n==6){  
     //6
     if(strstr(str2,str4)==0)
     {
         printf("No\n");
     }
     else
     {
         printf("Yes\n");
     }
    }else if(n==8){  
     //8
     if(strstr(str2,str5)==0)
     {
         printf("No\n");
     }
     else
     {
         printf("Yes\n");
     }
    }else if(n==10){  
     //10
     if(strstr(str2,str6)==0)
     {
         printf("No\n");
     }
     else
     {
         printf("Yes\n");
     }
    }else{
       printf("No\n");
    }
  
  

    return 0;
};