Problem:
Score : 200 points

Problem Statement

The word internationalization is sometimes abbreviated to i18n.
This comes from the fact that there are 18 letters between the first i and the last n.

You are given a string s of length at least 3 consisting of lowercase English letters.
Abbreviate s in the same way.

Constraints

3 ≤ |s| ≤ 100 (|s| denotes the length of s.)

s consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s

Output

Print the abbreviation of s.

Sample Input 1

internationalization

Sample Output 1

i18n

Sample Input 2

smiles

Sample Output 2

s4s

Sample Input 3

xyz

Sample Output 3

x1z

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
#include<string.h>
int main()
{
    int i,j,k,l;
    char s[102],p,m;



    printf("enter a string \n");
    gets(s);
    l=strlen(s);
    for(i=0;i<=l;i++)
    {
        if(i==0)
        {


        p=s[i];
        l--;
        }
        else if(i==l)

            {
                m=s[i];
              l--;
            }

    }
    if(l>=3&&l<=100)
    printf("%c%d%c",p,l,m);
}