Problem:
Score : 200 points

Problem Statement

The word internationalization is sometimes abbreviated to i18n.
This comes from the fact that there are 18 letters between the first i and the last n.

You are given a string s of length at least 3 consisting of lowercase English letters.
Abbreviate s in the same way.

Constraints

3 ≤ |s| ≤ 100 (|s| denotes the length of s.)

s consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s

Output

Print the abbreviation of s.

Sample Input 1

internationalization

Sample Output 1

i18n

Sample Input 2

smiles

Sample Output 2

s4s

Sample Input 3

xyz

Sample Output 3

x1z

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

/* ex6_2
   KKOO  */

#include <stdio.h>
#include <string.h>

#define SIZE 256

int main(void){
    int length;
    char word[SIZE];

    //英単語を入力
    fgets(word, SIZE, stdin);

    //文字列の長さ
    length = strlen(word);

    if(length > 3){
        //”lengthー３”・・・単語の前後の文字とnull文字を引いた長さ
        //”word[lengthー2]”・・・word[lengthー1]はnull文字なので-2にする
        printf("%c%d%c\n", word[0], length-3, word[length-2]);
    }
    else{
        //2文字以下の単語はそのまま出力
        printf("%s",word);
    }

    return 0;
}