Problem:
Score : 100 points

Problem Statement

You have three tasks, all of which need to be completed.

First, you can complete any one task at cost 0.

Then, just after completing the i-th task, you can complete the j-th task at cost |A_j - A_i|.

Here, |x| denotes the absolute value of x.

Find the minimum total cost required to complete all the task.

Constraints

All values in input are integers.

1 \leq A_1, A_2, A_3 \leq 100

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

Print the minimum total cost required to complete all the task.

Sample Input 1

1 6 3

Sample Output 1

5

When the tasks are completed in the following order, the total cost will be 5, which is the minimum:

Complete the first task at cost 0.

Complete the third task at cost 2.

Complete the second task at cost 3.

Sample Input 2

11 5 5

Sample Output 2

6

Sample Input 3

100 100 100

Sample Output 3

0

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>


int main(){
	int a,b,c;
	scanf("%d %d %d",&a,&b,&c);
	if(a>=b&&b>=c){printf("%d",a-c);}
	else if(a>=c&&c>=b){printf("%d",a-b);}
	else if(b>=c&&c>=a){printf("%d",b-a);}
	else if(b>=a&&a>=c){printf("%d",b-c);}
	else if(c>=b&&b>=a){printf("%d",c-a);}
	else if(c>=a&&a>=b){printf("%d",c-b);}
	else 
	
	return 0;
}