Problem:
Score : 200 points

Problem Statement

Given is an integer N. Find the number of digits that N has in base K.

Notes

For information on base-K representation, see Positional notation - Wikipedia.

Constraints

All values in input are integers.

1 \leq N \leq 10^9

2 \leq K \leq 10

Input

Input is given from Standard Input in the following format:

N K

Output

Print the number of digits that N has in base K.

Sample Input 1

11 2

Sample Output 1

4

In binary, 11 is represented as 1011.

Sample Input 2

1010101 10

Sample Output 2

7

Sample Input 3

314159265 3

Sample Output 3

18

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
#include<math.h>
int main()
{
    long long N,b,i,sum=0,r;
    scanf("%lld %lld",&N,&b);
    for(i=0;N!=0;i++)
    {
        r=N % b;
        //printf("%lld\n",r);
        //sum=sum+r*pow(i,10);
        //printf("%lld\n",sum);
        N=N/b;
    }
    printf("%lld",i);
    return 0;
}