Problem:
Score : 300 points

Problem Statement

Find the price of a product before tax such that, when the consumption tax rate is 8 percent and 10 percent, the amount of consumption tax levied on it is A yen and B yen, respectively. (Yen is the currency of Japan.)

Here, the price before tax must be a positive integer, and the amount of consumption tax is rounded down to the nearest integer.

If multiple prices satisfy the condition, print the lowest such price; if no price satisfies the condition, print -1.

Constraints

1 \leq A \leq B \leq 100

A and B are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

If there is a price that satisfies the condition, print an integer representing the lowest such price; otherwise, print -1.

Sample Input 1

2 2

Sample Output 1

25

If the price of a product before tax is 25 yen, the amount of consumption tax levied on it is:

When the consumption tax rate is 8 percent: \lfloor 25 \times 0.08 \rfloor = \lfloor 2 \rfloor = 2 yen.

When the consumption tax rate is 10 percent: \lfloor 25 \times 0.1 \rfloor = \lfloor 2.5 \rfloor = 2 yen.

Thus, the price of 25 yen satisfies the condition. There are other possible prices, such as 26 yen, but print the minimum such price, 25.

Sample Input 2

8 10

Sample Output 2

100

If the price of a product before tax is 100 yen, the amount of consumption tax levied on it is:

When the consumption tax rate is 8 percent: \lfloor 100 \times 0.08 \rfloor = 8 yen.

When the consumption tax rate is 10 percent: \lfloor 100 \times 0.1 \rfloor = 10 yen.

Sample Input 3

19 99

Sample Output 3

-1

There is no price before tax satisfying this condition, so print -1.

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>

int main(int argc, char *argv[])
{
    int a, b;
    int out_8, out_10;
    int tmp;
    unsigned long count = 0;
    scanf("%i %i",&a, &b);

    double x_max, x_min, y_max, y_min;
    x_max = ( (double)a + 0.9999999999999999 ) * 100.0 / 8.0;
    x_min = ( (double)a ) * 100.0 / 8.0;
    y_max = ( (double)b + 0.9999999999999999 ) * 100.0 / 10.0;
    y_min = ( (double)b ) * 100.0 / 10.0;

    if (x_max < y_min){
        printf("-1");
        return 0;
    }
    else{
       out_8 = (int)x_min;
       tmp = out_8;
       while (tmp < y_min)
       {
           tmp++;
       }
       
    }
    printf("%d", tmp);

    return 0;
}