Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define BUFMAX 200000

int main(){
  int n,a,b,c,d; 
  int i,flag;
  //n:number of grid
  //a:initial pos of A
  //b:initial pos of B
  //c:goal pos of A
  //d:goal pos of B
  char str[BUFMAX];
  scanf("%d %d %d %d %d",&n,&a,&b,&c,&d);
  scanf("%s",str);
  //printf("%d %d %d %d %d\n",n,a,b,c,d);
  //printf("%s\n",str);
  flag = 0;
  if(a<b && c>d){
    str[d-1] = '#';
  }else if(a>b && c<d){
    str[c-1] = '#';
  }
  for(i=1;i<n;++i){
    if(str[i-1] == '#' && str[i] == '#'){
      flag = 1;
      break;
    }
  }
  if(a<b){
    i=b;
  }else{
    i=a;
  }
  for(i=2;i<n;++i){
    if(str[i-2] == '.' && str[i-1] == '.' &&str[i] == '.'){
      flag = 0;
      break;
    }
  }
  flag == 0 ? printf("Yes\n") : printf("No\n");
  return 0;
}