Problem:
Score : 200 points

Problem Statement

Find the number of palindromic numbers among the integers between A and B (inclusive).
Here, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.

Constraints

10000 \leq A \leq B \leq 99999

All input values are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the number of palindromic numbers among the integers between A and B (inclusive).

Sample Input 1

11009 11332

Sample Output 1

4

There are four integers that satisfy the conditions: 11011, 11111, 11211 and 11311.

Sample Input 2

31415 92653

Sample Output 2

612

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>

int check(int n){
  if(n/10000%10 == n%10  &&  n/1000%10 == n/10%10)
    return 1;
  else
    return 0;
}

int main(){
  int a, b;  scanf("%d %d", &a, &b);

  int ans = 0;
  for(int i=a; i<=b; i++)
    ans = ans + check(i);

  printf("%d\n", ans);
  return 0;
}