Problem:
Score : 100 points

Problem Statement

Based on some criterion, Snuke divided the integers from 1 through 12 into three groups as shown in the figure below.
Given two integers x and y (1 ≤ x < y ≤ 12), determine whether they belong to the same group.

Constraints

x and y are integers.

1 ≤ x < y ≤ 12

Input

Input is given from Standard Input in the following format:

x y

Output

If x and y belong to the same group, print Yes; otherwise, print No.

Sample Input 1

1 3

Sample Output 1

Yes

Sample Input 2

2 4

Sample Output 2

No

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
main()
{
    int a[7] = {1,3,5,7,8,10,12},b[4] = {4,6,9,11};
    int c[2] = {2},x,y,j,count = 0,i;
    scanf("%d %d",&x,&y);
   
    for(i=0;i<8;i++)
    {
        if(x==a[i])
        {
            for(j=0;j<8;j++)
            {
                if(y==a[j])
                {
                    count = 2;
                    break;
                }
            }
            break;
        }
        else if(y==a[i])
        {
            for(j=0;j<8;j++)
            {
                if(x==a[j])
                {
                    count = 2;
                    break;
                }
            }
            break;
        }
    }
   
    for(i=0;i<4;i++)
    {
        if(x==b[i])
        {
           
            for(j=0;j<4;j++)
            {
                if(y==b[j])
                {
                   
                    count = 2;
                    break;
                }
            }
            break;
        }
        else if(y==b[i])
        {
            for(j=0;j<4;j++)
            {
                if(x==b[j])
                {
                    count = 2;
                    break;
                }
            }
            break;
        }
    }
    if(x==2 && y==2)
    {
        count=2;
    }
    if(count == 2) printf("Yes\n");
    else printf("No\n");
    return 0;
}