Problem:
Score : 200 points

Problem Statement

Given are a positive integer N and a string S of length N consisting of lowercase English letters.

Determine whether the string is a concatenation of two copies of some string.
That is, determine whether there is a string T such that S = T + T.

Constraints

1 \leq N \leq 100

S consists of lowercase English letters.

|S| = N

Input

Input is given from Standard Input in the following format:

N
S

Output

If S is a concatenation of two copies of some string, print Yes; otherwise, print No.

Sample Input 1

6
abcabc

Sample Output 1

Yes

Let T = abc, and S = T + T.

Sample Input 2

6
abcadc

Sample Output 2

No

Sample Input 3

1
z

Sample Output 3

No

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

#include <stdio.h>
#include <string.h>

int main(){
  int N,c=1;
  char S[102];
  scanf("%d\n%s",&N,S);
  if(N%2==0){
    int T=N/2;
    for(int i=0;i<T;i++){
      if(S[i]!=S[i+T]) c=0;
    }
  }else{
    c=0;
  }
  if(c) printf("Yes\n");
  else printf("No\n");
  return 0;
}