Problem:
Score : 300 points

Problem Statement

You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

1 \leq |S| \leq 2 \times 10^5

|S| = |T|

S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S and T can be made equal, print Yes; otherwise, print No.

Sample Input 1

azzel
apple

Sample Output 1

Yes

azzel can be changed to apple, as follows:

Choose e as c_1 and l as c_2. azzel becomes azzle.

Choose z as c_1 and p as c_2. azzle becomes apple.

Sample Input 2

chokudai
redcoder

Sample Output 2

No

No sequences of operation can change chokudai to redcoder.

Sample Input 3

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu

Sample Output 3

Yes

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>

int main(void) {
	//i, j : カウント変数
	//len : 文字列の長さを格納
	//f : 真フラグを格納
	//c, d : 文字列sと文字列tのそれぞれのi番目の文字を格納
	//s[], t[] : 入力した文字列を格納
	int i, j, len;
	int f = 0;
	char c, d;
	char s[200001] = {}, t[200001] = {};
	
	//文字列をscanf
	scanf("%s%s", s, t);
	//lenに文字列の長さを格納
	if (strlen(s) == strlen(t)) f = 1;
	len = strlen(s);

	for (i = 0; i < len; i++) {
		//文字列sと文字列tのi番目の文字が一致するか
			//↓一致しなかった場合の処理（一致した場合は何もしない）
		if (s[i] != t[i]) {
			//c, d に文字列sと文字列tのi番目の文字を格納
			c = s[i];
			d = t[i];
			//文字列tを0からlenまで走査していき、cと一致していたらdと、dと一致していたらcと交換する
			for (j = 0; j < len; j++) {
				if (t[j] == c) {
					t[j] = d;
					//すでに交換した文字を再度交換した場合フラグを偽にする
					if (i > j) {
						f = 0;
						break;
					}
				} else if (t[j] == d) {
					t[j] = c;
					//すでに交換した文字を再度交換した場合フラグを偽にする
					if (i > j) {
						f = 0;
						break;
					}
				}
			}
		}
	}
	//結果の出力
	printf(f ? "Yes\n" : "No\n");
	return 0;
}