Problem:
Score : 100 points

Problem Statement

You have three tasks, all of which need to be completed.

First, you can complete any one task at cost 0.

Then, just after completing the i-th task, you can complete the j-th task at cost |A_j - A_i|.

Here, |x| denotes the absolute value of x.

Find the minimum total cost required to complete all the task.

Constraints

All values in input are integers.

1 \leq A_1, A_2, A_3 \leq 100

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

Print the minimum total cost required to complete all the task.

Sample Input 1

1 6 3

Sample Output 1

5

When the tasks are completed in the following order, the total cost will be 5, which is the minimum:

Complete the first task at cost 0.

Complete the third task at cost 2.

Complete the second task at cost 3.

Sample Input 2

11 5 5

Sample Output 2

6

Sample Input 3

100 100 100

Sample Output 3

0

Solution in C (Clang 3.8.0) (judge verdict: Accepted)

#include <stdio.h>
#include <stdlib.h>

int main(void){
    int a[3],i,j,w;
    
    for(i=0; i<3; i++)
        scanf("%d",&a[i]);

    for(i=0; i<3; i++){
        for(j=2; j>0; j--){
            if(a[j-1]<a[j]){
                w=a[j];
                a[j]=a[j-1];
                a[j-1]=w;
            }
        }
    }
    printf("%d\n",abs(a[1]-a[0])+abs(a[2]-a[1]));
        
    return 0;
}