Problem:
Score : 100 points

Problem Statement

Cat Snuke is learning to write characters.
Today, he practiced writing digits 1 and 9, but he did it the other way around.

You are given a three-digit integer n written by Snuke.
Print the integer obtained by replacing each digit 1 with 9 and each digit 9 with 1 in n.

Constraints

111 \leq n \leq 999

n is an integer consisting of digits 1 and 9.

Input

Input is given from Standard Input in the following format:

n

Output

Print the integer obtained by replacing each occurrence of 1 with 9 and each occurrence of 9 with 1 in n.

Sample Input 1

119

Sample Output 1

991

Replace the 9 in the ones place with 1, the 1 in the tens place with 9 and the 1 in the hundreds place with 9. The answer is 991.

Sample Input 2

999

Sample Output 2

111

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
#include<math.h>

int main(void)
{
	int box[7] = {100,900,10,90,1,9};
	int n,temp=0;

	scanf("%d",&n);

	if (n / box[0] == 1)
	{
		temp += box[1];
		n -= box[0];
	}
	else
	{
		temp += box[0];
		n -= box[1];
	}
	if (n / box[2] == 1)
	{
		temp += box[3];
		n -= box[2];
	}
	else
	{
		temp += box[2];
		n -= box[3];
	}
	if (n / box[4] == 1)
	{
		temp += box[5];
		n -= box[4];
	}
	else
	{
		temp += box[4];
		n -= box[5];
	}

	printf("%d\n",temp);

	return 0;
}