Problem:
Score : 200 points

Problem Statement

In the beginning, Takahashi has A cookies, and Aoki has B cookies.
They will perform the following operation alternately, starting from Takahashi:

If the number of cookies in his hand is odd, eat one of those cookies; if the number is even, do nothing. Then, give one-half of the cookies in his hand to the other person.

Find the numbers of cookies Takahashi and Aoki respectively have after performing K operations in total.

Constraints

1 \leq A,B \leq 10^9

1 \leq K \leq 100

A,B and K are integers.

Input

Input is given from Standard Input in the following format:

A B K

Output

Print the number of cookies Takahashi has, and the number of cookies Aoki has, in this order, after performing K operations in total.

Sample Input 1

5 4 2

Sample Output 1

5 3

The process will go as follows:

In the beginning, Takahashi and Aoki have 5 and 4 cookies, respectively.

Takahashi eats one cookie and gives two cookies to Aoki. They now have 2 and 6 cookies, respectively.

Aoki gives three cookies to Takahashi. They now have 5 and 3 cookies, respectively.

Sample Input 2

3 3 3

Sample Output 2

1 3

Sample Input 3

314159265 358979323 84

Sample Output 3

448759046 224379523

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
int main(){
int a,b,k,d,n,j=0;

scanf("%d %d %d",&a,&b,&k);

if(k%2==1){
n=(k-1)/2;
d++;
}else{
n=k/2;
}


for(j=0;j<=n;j++){

if(a%2==1){
a=(a-1)/2;
b=b+a;
}else{
a=a/2;
b=b+a;
}

if(b%2==1){
b=(b-1)/2;
a=a+b;
}else{
b=b/2;
a=a+b;
}

}

if(d==1){
if(a%2==1){
a=(a-1)/2;
b=b+a;
}else{
a=a/2;
b=b+a;
}}
printf("%d %d",&a,&b);
return 0;
}