Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C (GCC 5.4.1) (judge verdict: Time Limit Exceeded)

#include<stdio.h>
#include<string.h>
int main()
{
	int n,i,j,count[14],yaku[201],k,ans=0,temp;
	scanf("%d",&n);
	for(j=2;j<=n;j++){
		temp = j;
		for(i=2;i<14;i++){
			while(j%i==0){
				count[i]++;
				j = j/i;
			}
		}
		yaku[temp]=yaku[temp]*(count[i]+1);
		k = k + yaku[temp];
	}
	if (k==8)ans++;
	printf("%d",ans);
	return 0;
}