Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
#include<stdlib.h>
long long N,n1,n2;
int main()
{
	int h, n;
	scanf("%lld", &N);
	for (h = 1; h <= 3500; h++)
	{
		for ( n = 1; n <= 3500; n++)
		{
			n1 = N*h*n;
			n2 = 4 * h*n - n*N - h*N;
			if (n1%n2 == 0&&n1>0&&n2>0)
			{
				printf("%d %d %lld\n", n, h, n1/n2);
				exit(0);
			}
		}
		
	}
	return 0;
}