Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
int main(void){
	int N;
	scanf("%d",&N);
	int a,b;
	int c=0;
	int d=0;
	for(a=1;a<=N;a++){
		if((a%2)==1){
			for(b=1;b<=a;b++){
				if((a%b)==0){
					c++;
				}
			}
		}
		if(c==8){
			d++;
		}
		c=0;
	}
	printf("%d",d);
return 0;
}