Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>
int compare_int(const void *a, const void *b)
{
//    return *(int*)a - *(int*)b;
    return *(long long*)a - *(long long*)b;
}
//  qsort(A, b, sizeof(int), compare_int);

int main()
{
  int a ,b, c, d, e, X, Y;
//  long long  b, c, d, e, X, Y;
  //  double  c;
  long long  A[100003]={};
  int  B[100003]={};
  int  C[100003]={};

  int  flag[103]={};

//  long long  a, b, c, d, X, Y;
  char s[101]={};
//  int N, M;
//  int A[1000000001]={};
//  long long  C[101]={};
  int i,j,k;
//  int flag=0;
  int tmp=0;
//  int min=1000000;
  long long min=100000001;
  int len=0;
  int cnt=0;
  int num=0;
  double ans=1000;
  int max=0;
//  char alp[26]={'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};

  //  a=0;
//  scanf("%lld %lld", &a, &b);
//  scanf("%d%d", &a,&c);
//  cnt = strlen(t);
// printf("%d\n",a);
    scanf("%s", &s);
/*  
  for(i=0;i<a;i++){
//    printf("%lld ",A[i]);
    if(A[i]==1) {
      printf("1\n");
      return 0;
    }
  }    
*/
  
  a=(s[0]-'0')*10+s[1]-'0';
  b=(s[2]-'0')*10+s[3]-'0';
//  printf("%d %d\n", a,b);
  
  if (((0<a)&&(a<13)) && ((0<b)&&(b<13)))printf("AMBIGUOUS\n");
  else if((0<b)&&(b<13))printf("YYMM\n");
  else if((0<a)&&(a<13)) printf("MMYY\n");
  else printf("NA\n");
  //  //  if(flag==0)   printf("TLE\n");
//    if(max < cnt - max)  printf("Yes\n");
//    else  printf("No\n");
  
return 0;
}