Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>

int main(){
int S,i,j,k;
int a,b;
a = b = 0;
scanf("%d",&S);
      
for(i=1;i<=S;i++){
  b = 0;
  for(j=1;j<=i;j++){
    if((i%j) == 0){
      b++;
    }
  }
  if(b == 8 && i%2 ==1)
    a++;
}

printf("%d\n",a);

return 0;
}