Problem:
Score : 200 points

Problem Statement

You are given a string S of length N consisting of lowercase English letters.
We will cut this string at one position into two strings X and Y.
Here, we would like to maximize the number of different letters contained in both X and Y.
Find the largest possible number of different letters contained in both X and Y when we cut the string at the optimal position.

Constraints

2 \leq N \leq 100

|S| = N

S consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

N
S

Output

Print the largest possible number of different letters contained in both X and Y.

Sample Input 1

6
aabbca

Sample Output 1

2

If we cut the string between the third and fourth letters into X = aab and Y = bca, the letters contained in both X and Y are a and b.
There will never be three or more different letters contained in both X and Y, so the answer is 2.

Sample Input 2

10
aaaaaaaaaa

Sample Output 2

1

However we divide S, only a will be contained in both X and Y.

Sample Input 3

45
tgxgdqkyjzhyputjjtllptdfxocrylqfqjynmfbfucbir

Sample Output 3

9

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
#define MAX 100
#define ALP 26
int main(void) {
    int N, cut, i, j, p, tmp, max=0;
    char S[MAX];
    int alp1[ALP+97]={0};
    int alp2[ALP+97]={0};
    scanf("%d %s", &N, S);
    
    for(cut=0; cut<N-1; cut++) {
        tmp = 0;
        for(i=0; i<=cut; i++) {
            for(p=97; p<=122; p++) {
                if(S[i]==p)
                    alp1[p]++;
            }
        }
        
        for(j=cut+1; j<=N-1; j++) {
            for(p=97; p<=122; p++) {
                if(S[j]==p)
                    alp2[p]++;
            }
        }
        
        for(p=97; p<=122; p++) {
            if(alp1[p]>=1 && alp2[p]>=1)
                tmp++;
        }
        
        if(tmp>=max)
            max = tmp;
    }
    printf("%d\n", max);
    return 0;
}