Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
int main()
{
    int arr[3][3], row, col, n, i, b, j=0;
    for(row=0; row<3; row++){
        scanf("%d %d %d", &arr[row][0], &arr[row][1], &arr[row][2]);
    }
    scanf("%d", &n);
    int r0=0, r2=0, r1=0, c0=0, c2=0, c1=0, d1=0, d2=0;
    for(i=0; i<n; i++){
        scanf("%d", &b);
        for(row=0; row<3; row++){
            for(col=0; col<3; col++){
                if(arr[row][col]==b){
                    if(row==0) r0++; 
                    else if(row==1) r1++;
                    else if(row==2) r2++;
                    if(col==0) c0++;
                    else if(col==1) c1++;
                    else if(col==2) c2++;
                    if(row==col) d1++;
                    if((row==2 && col == 0) || (row==0 && col==2) || (row==col)) d2++;
                }
                if(r0==3 || r2==3 || r1==3 || c0==3 || c2==3 || c1==3 || d1==3 || d2==3){
                    printf("Yes");
                    return 0;
                }
            }
        }
    }
    printf("No");
    return 0;
}