Problem:
Score : 200 points

Problem Statement

Let S(n) denote the sum of the digits in the decimal notation of n.
For example, S(101) = 1 + 0 + 1 = 2.

Given an integer N, determine if S(N) divides N.

Constraints

1 \leq N \leq 10^9

Input

Input is given from Standard Input in the following format:

N

Output

If S(N) divides N, print Yes; if it does not, print No.

Sample Input 1

12

Sample Output 1

Yes

In this input, N=12.
As S(12) = 1 + 2 = 3, S(N) divides N.

Sample Input 2

101

Sample Output 2

No

As S(101) = 1 + 0 + 1 = 2, S(N) does not divide N.

Sample Input 3

999999999

Sample Output 3

Yes

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>

int main() {
    int n, N, S, tmp;
    scanf("%d", &n);
    
    N = (int)log10((double)n) + 1;
    S = 0;
    tmp = n;
    for (int i = 0; i < N; i++) {
        S += tmp;
        tmp /= 10;
        S -= tmp * 10;
    }
    
    if (n % S == 0) {
        printf("Yes");
    } else {
        printf("No");
    }
    
    return 0;
}