Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
#include<stdlib.h>
int main(){
    int i,j,n;
    int a[3][3];
    for(i=0;i<3;i++){
        for(j=0;j<3;j++)
            scanf("%d",&a[i][j]);
    }
    scanf("%d",&n);
    int b[n];
    for(i=0;i<n;i++){
        scanf("%d",&b[i]);
        for(j=0;j<3;j++){
            for(int k=0;k<3;k++)
                if(a[j][k]==b[i])
                    a[j][k]=0;
        }
    }
    int p=a[0][0],q=a[1][0],r=a[2][0],ans=0;
    if(p==q&&p==r) ans=1;
    int count=0;
    for(i=1;i<3;i++){
        if(p==a[0][i])
            count++;
    }
    if(count==2) ans=1;
    count=0;
    for(i=1;i<3;i++){
        if(q==a[0][i])
            count++;
    }
    if(count==2) ans=1;
    count=0;
    for(i=1;i<3;i++){
        if(r==a[0][i])
            count++;
    }
    if(count==2) ans=1;
    count=0;
    p=a[0][1];q=a[1][1];r=a[2][1];
    if(p==q&&p==r) ans=1;
    for(i=1;i<3;i++){
        if(p==a[0][i])
            count++;
    }
    if(count==2) ans=1;
    count=0;
    for(i=1;i<3;i++){
        if(q==a[0][i])
            count++;
    }
    if(count==2) ans=1;
    count=0;
    for(i=1;i<3;i++){
        if(r==a[0][i])
            count++;
    }
    if(count==2) ans=1;
    count=0;
    p=a[0][2];q=a[1][2];r=a[2][2];
    if(p==q&&p==r) ans=1;
    for(i=1;i<3;i++){
        if(p==a[0][i])
            count++;
    }
    if(count==2) ans=1;
    count=0;
    for(i=1;i<3;i++){
        if(q==a[0][i])
            count++;
    }
    if(count==2) ans=1;
    count=0;
    for(i=1;i<3;i++){
        if(r==a[0][i])
            count++;
    }
    if(count==2) ans=1;
    count=0;
    if(r==a[0][0]&&r==a[1][1]) ans=1;
    if(a[1][1]==a[2][0]&&a[1][1]==a[0][2]) ans=1;
    if(ans==1) printf("Yes\n");
    else printf("No\n");
    return 0;
}