Problem:
Finding Missing Cards

Taro is going to play a card game. However, now he has only n cards, even though there should be 52 cards (he has no Jokers).

The 52 cards include 13 ranks of each of the four suits: spade, heart, club and diamond.

Input

In the first line, the number of cards n (n ≤ 52) is given.

In the following n lines, data of the n cards are given. Each card is given by a pair of a character and an integer which represent its suit and rank respectively. A suit is represented by 'S', 'H', 'C' and 'D' for spades, hearts, clubs and diamonds respectively. A rank is represented by an integer from 1 to 13.

Output

Print the missing cards. The same as the input format, each card should be printed with a character and an integer separated by a space character in a line.
Arrange the missing cards in the following priorities:

Print cards of spades, hearts, clubs and diamonds in this order.

If the suits are equal, print cards with lower ranks first.

Sample Input

47
S 10
S 11
S 12
S 13
H 1
H 2
S 6
S 7
S 8
S 9
H 6
H 8
H 9
H 10
H 11
H 4
H 5
S 2
S 3
S 4
S 5
H 12
H 13
C 1
C 2
D 1
D 2
D 3
D 4
D 5
D 6
D 7
C 3
C 4
C 5
C 6
C 7
C 8
C 9
C 10
C 11
C 13
D 9
D 10
D 11
D 12
D 13

Sample Output

S 1
H 3
H 7
C 12
D 8

Note

      解説

Solution in C (judge verdict: Time Limit Exceeded)

#include<stdio.h>
int main(void){
  int a[4][13];
  int n;
  scanf("%d",&n);
  int i,j;
  for (i=0;i<4;i++){
    for (j=0;j<13;i++){
      a[i][j]=0;
    }
  }
  for (i=0;i<n;i++){
    char mark;
    int j,m;
    scanf("%c %d",&mark,&j);
    if(mark=='S') m=1;
    else if (mark=='H') m=2;
    else if (mark=='C') m=3;
    else m=4;
    a[m][j-1]=1;
  }
  for (i=0;i<4;i++){
    for (j=0;j<13;i++){
      if (a[i][j]==0)
	if (i ==1) printf("S %d",j);
	else if (i==2) printf("H %d",j);
	else if (i==3) printf("C %d",j);
        else printf("D %d",j);
    }    
  }
  return 0;
}