Problem:
Finding Missing Cards

Taro is going to play a card game. However, now he has only n cards, even though there should be 52 cards (he has no Jokers).

The 52 cards include 13 ranks of each of the four suits: spade, heart, club and diamond.

Input

In the first line, the number of cards n (n ≤ 52) is given.

In the following n lines, data of the n cards are given. Each card is given by a pair of a character and an integer which represent its suit and rank respectively. A suit is represented by 'S', 'H', 'C' and 'D' for spades, hearts, clubs and diamonds respectively. A rank is represented by an integer from 1 to 13.

Output

Print the missing cards. The same as the input format, each card should be printed with a character and an integer separated by a space character in a line.
Arrange the missing cards in the following priorities:

Print cards of spades, hearts, clubs and diamonds in this order.

If the suits are equal, print cards with lower ranks first.

Sample Input

47
S 10
S 11
S 12
S 13
H 1
H 2
S 6
S 7
S 8
S 9
H 6
H 8
H 9
H 10
H 11
H 4
H 5
S 2
S 3
S 4
S 5
H 12
H 13
C 1
C 2
D 1
D 2
D 3
D 4
D 5
D 6
D 7
C 3
C 4
C 5
C 6
C 7
C 8
C 9
C 10
C 11
C 13
D 9
D 10
D 11
D 12
D 13

Sample Output

S 1
H 3
H 7
C 12
D 8

Note

      解説

Solution in C (judge verdict: Time Limit Exceeded)

#include <stdio.h>

int main(){
    int a[13][4];
    int i,j,card,d=0;
    for(i=0;i<13;i++)
    for(j=0;j<4;j++)
    a[i][j]=0;
    char e;
    int number;
    scanf("%d",&card);
    while(d<card){
        scanf("%s %d",&e,&number);
        if(e=='S')
        a[number-1][0]=1;
        else if(e=='H')
        a[number-1][1]=1;
        else if(e=='C')
        a[number-1][2]=1;
        else
        a[number-1][3]=1;
     d--;
    }
    for(j=0;j<4;j++)
    for(i=0;i<13;i++){
        if(a[i][j]==0){
    if(j==0){
        printf("S %d\n",i+1);}
    else if(j==1){
        printf("H %d\n",i+1);}
    else if(j==2){
        printf("C %d\n",i+1);}
else{
        printf("D %d\n",i+1);}
    }
}
return 0;
    
}