Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in C (GCC 9.2.1) (judge verdict: Runtime Error)

#include <stdio.h>
int main(void)
{
    char c[3];
    char a[100003];
    int tmp;
    long long int A, B, C, N, i, ii;
    scanf("%lld %lld %lld %lld", &N, &A, &B, &C);
    
    for (i = 0; i < N; i++)
    {
        scanf("%s", c);
        if (c[0] == 'A')
        {
            if (c[1] == 'B')
            {
                if(A > B)
                {
                    A--;
                    B++;
                    a[i] = 'B';
                }
                else
                {
                    A++;
                    B--;
                    a[i] = 'A';
                }       
            }
            else 
            {
                if(A > C)
                {
                    A--;
                    C++;
                    a[i] = 'C';
                }
                else
                {
                    C--;
                    A++;
                    a[i] = 'A';
                }    
            }
                
        }
        else 
        {
            if(B > C)
            {
                B--;
                C++;
                a[i] = 'C';
            }
            else
            {
                C--;
                B++;
                a[i] = 'B';
            }
        }
        
        if (A * B * C < 0)
        {
            printf("No");
            return (0);
        }

        
    }
    
    printf("Yes\n");
    for (i = 0; i < N; i++)
        printf("%c\n", c[i]);
    return (0);
}