Problem:
Score : 200 points

Problem Statement

The word internationalization is sometimes abbreviated to i18n.
This comes from the fact that there are 18 letters between the first i and the last n.

You are given a string s of length at least 3 consisting of lowercase English letters.
Abbreviate s in the same way.

Constraints

3 ≤ |s| ≤ 100 (|s| denotes the length of s.)

s consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s

Output

Print the abbreviation of s.

Sample Input 1

internationalization

Sample Output 1

i18n

Sample Input 2

smiles

Sample Output 2

s4s

Sample Input 3

xyz

Sample Output 3

x1z

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

/*  ex6_2 i18n
    pandacodeb  */

#include <stdio.h>
#include <string.h>

#define SIZE 101

int main(void){
    int length;
    char text[SIZE];

    //input text
    fgets(text, SIZE, stdin);

    //find text's length (include \n)
    length = strlen(text);

    //change \n into null (\0) at the end of the text
    if (length >= 3 && text[length-1] == '\n'){
        text[--length] = '\0';
    }

    //print out corresponding characters
    //print: first char, length - 2, last char
    putchar(text[0]);
    printf("%d", length - 2);
    putchar(text[length-1]);
    putchar('\n');
    return 0;
}