Problem:
Score : 300 points

Problem Statement

There are N people living on a number line.

The i-th person lives at coordinate X_i.

You are going to hold a meeting that all N people have to attend.

The meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.

Find the minimum total points of stamina the N people have to spend.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq X_i \leq 100

Input

Input is given from Standard Input in the following format:

N
X_1 X_2 ... X_N

Output

Print the minimum total stamina the N people have to spend.

Sample Input 1

2
1 4

Sample Output 1

5

Assume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.

Note that you can hold the meeting only at an integer coordinate.

Sample Input 2

7
14 14 2 13 56 2 37

Sample Output 2

2354

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
#include<stdlib.h>

int int_sort( const void * a , const void * b ) {
  if( *( int  * )a < *( int * )b ) {
    return -1;
  }
  else
  if( *( int * )a == *( int * )b ) {
    return 0;
  }
  return 1;
}

int main(void){
 
  int N;
  int X[100];
  int i,j;
  
  size_t data_cnt;
  
   scanf("%d\n",&N);
  
  for(i=0;i<N;i++){
  	
    scanf("%d ",&X[i]);
  
  }
  
  data_cnt =N;
  
  int hoko=10000;
  
  qsort((void*)X, data_cnt , sizeof(X[0]), int_sort );
  
  int sum=0;
 
  for(i=1;i<=100;i++){
	
    sum=0;
    
    for(j=0;j<N;j++){
    	sum=sum+(X[j]-i)*(X[j]-i);
      	//printf("%d %d\n",X[i],sum);
      
      	
    }
    
    if(hoko>sum){
          
    		hoko=sum;
    	
        }
    
  
    
    
    //printf("%d\n",hoko);
    
  }
  
  printf("%d\n",hoko);
  return 0;
  
}