Problem:
Score : 200 points

Problem Statement

Given are a positive integer N and a string S of length N consisting of lowercase English letters.

Determine whether the string is a concatenation of two copies of some string.
That is, determine whether there is a string T such that S = T + T.

Constraints

1 \leq N \leq 100

S consists of lowercase English letters.

|S| = N

Input

Input is given from Standard Input in the following format:

N
S

Output

If S is a concatenation of two copies of some string, print Yes; otherwise, print No.

Sample Input 1

6
abcabc

Sample Output 1

Yes

Let T = abc, and S = T + T.

Sample Input 2

6
abcadc

Sample Output 2

No

Sample Input 3

1
z

Sample Output 3

No

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <limits.h>
#include <string.h>



int main(void){
int N=0;
scanf("%d\n",&N);

char S[N];

scanf("%Ns",S);
if (N==1){printf("No");
return 0;}
char T1[N/2];
char T2[N/2];
for (int i=0;i<N/2;i++){
  T1[i]=S[i];
  T2[i]=S[(N/2)+i];
}
if (strcmp(T1,T2)==0) printf("Yes");
else printf("No");
return EXIT_SUCCESS;
}