Problem:
Score : 200 points

Problem Statement

You are given string S and T consisting of lowercase English letters.

Determine if S equals T after rotation.

That is, determine if S equals T after the following operation is performed some number of times:

Operation: Let S = S_1 S_2 ... S_{|S|}. Change S to S_{|S|} S_1 S_2 ... S_{|S|-1}.

Here, |X| denotes the length of the string X.

Constraints

2 \leq |S| \leq 100

|S| = |T|

S and T consist of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S equals T after rotation, print Yes; if it does not, print No.

Sample Input 1

kyoto
tokyo

Sample Output 1

Yes

In the first operation, kyoto becomes okyot.

In the second operation, okyot becomes tokyo.

Sample Input 2

abc
arc

Sample Output 2

No

abc does not equal arc after any number of operations.

Sample Input 3

aaaaaaaaaaaaaaab
aaaaaaaaaaaaaaab

Sample Output 3

Yes

Solution in C (GCC 5.4.1) (judge verdict: Runtime Error)

#include<stdio.h>
int main()
{
	int i,j,S,T,count;
	char s[10],t[10];
	scanf("%s %s",&s,&t);
	S = strlen(s);
	T = strlen(t);
	if(2<=S && S<=10 && S==T){
		for(i=0;i<=S;i++){
			count=0;
			s[i]=s[i+1];
			s[0]=s[S];
			for(j=0;j<=S-1;j++){
				if(s[j]==t[j])count++;
			}
		if(count==S)break;
		}
	}
	printf(count==S?"Yes":"No");
	return 0;
}