Problem:
Score : 200 points

Problem Statement

Given are strings s and t of length N each, both consisting of lowercase English letters.

Let us form a new string by alternating the characters of S and the characters of T, as follows: the first character of S, the first character of T, the second character of S, the second character of T, ..., the N-th character of S, the N-th character of T. Print this new string.

Constraints

1 \leq N \leq 100

|S| = |T| = N

S and T are strings consisting of lowercase English letters.

Input

Input is given from Standard Input in the following format:

N
S T

Output

Print the string formed.

Sample Input 1

2
ip cc

Sample Output 1

icpc

Sample Input 2

8
hmhmnknk uuuuuuuu

Sample Output 2

humuhumunukunuku

Sample Input 3

5
aaaaa aaaaa

Sample Output 3

aaaaaaaaaa

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>

int main(){
	int N;
	scanf("%d",&N);
	char S[N+1],T[N+1];
    char ans[256];
    for(int i=0;i<N*2;i++){
        ans[i]='\0';
        S[i]='\0';
        T[i]='\0';
    }
    for(int i=0;i<N;i++){
        S[i]='\0';
        T[i]='\0';
    }
	scanf("%s %s",S,T);
	
	/*printf("S=%s\n",S);
	printf("T=%s\n",T);*/
	for(int i=0;i<N;i++){
		ans[i*2]=S[i];
		ans[i*2+1]=T[i];
		/*printf("%s\n",ans);*/
	}
	
	printf("%s\n",ans);
	return 0;
}