Problem:
Score : 200 points

Problem Statement

The postal code in Atcoder Kingdom is A+B+1 characters long, its (A+1)-th character is a hyphen -, and the other characters are digits from 0 through 9.

You are given a string S. Determine whether it follows the postal code format in Atcoder Kingdom.

Constraints

1≤A,B≤5

|S|=A+B+1

S consists of - and digits from 0 through 9.

Input

Input is given from Standard Input in the following format:

A B
S

Output

Print Yes if S follows the postal code format in AtCoder Kingdom; print No otherwise.

Sample Input 1

3 4
269-6650

Sample Output 1

Yes

The (A+1)-th character of S is -, and the other characters are digits from 0 through 9, so it follows the format.

Sample Input 2

1 1
---

Sample Output 2

No

S contains unnecessary -s other than the (A+1)-th character, so it does not follow the format.

Sample Input 3

1 2
7444

Sample Output 3

No

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>

int main(){
	int a,b,i;
	char s[11];
	scanf("%d%d",&a,&b);
	scanf("%s",s);
	for(i=0;i<a;i++){
		if(s[i]!='0' || s[i]!='1' || s[i]!='2' || s[i]!='3' || s[i]!='4' || s[i]!='5' || s[i]!='6' || s[i]!='7' || s[i]!='8' || s[i]!='9'){
			printf("No/n");
			return 0;
		}
	}
	if(s[i]!='-'){
		printf("No/n");
			return 0;
	}
	for(i=1;i<=b;i++){
		if(s[a+i]!='0' || s[a+i]!='1' || s[a+i]!='2' || s[a+i]!='3' || s[a+i]!='4' || s[a+i]!='5' || s[a+i]!='6' || s[a+i]!='7' || s[a+i]!='8' || s[a+i]!='9'){
			printf("No/n");
			return 0;
		}
	}
	if(s[a+b+1]!='\0'){
		printf("No/n");
			return 0;
	}
	printf("Yes\n");
	return 0;
}