Problem:
Score : 400 points

Problem Statement

You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

In the i-th operation, you replace every element whose value is B_{i} with C_{i}.

For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

All values in input are integers.

1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}

B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:

N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}

Output

Print Q integers S_{i} to Standard Output in the following format:

S_{1}
S_{2}
\vdots
S_{Q}

Note that S_{i} may not fit into a 32-bit integer.

Sample Input 1

4
1 2 3 4
3
1 2
3 4
2 4

Sample Output 1

11
12
16

Initially, the sequence A is 1,2,3,4.

After each operation, it becomes the following:

2, 2, 3, 4

2, 2, 4, 4

4, 4, 4, 4

Sample Input 2

4
1 1 1 1
3
1 2
2 1
3 5

Sample Output 2

8
4
4

Note that the sequence A may not contain an element whose value is B_{i}.

Sample Input 3

2
1 2
3
1 100
2 100
100 1000

Sample Output 3

102
200
2000

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

#include <stdio.h>
#include <stdlib.h>
int main(void){
	int n, q;
	int array[100001] = { 0 };
	long tmp_sum;
	scanf("%d", &n);
	for(int i=0; i<n; i++){
		int a;
		scanf("%d", &a);
		array[a]++;
		tmp_sum += a;
	}
	scanf("%d", &q);
	long *sum;
	sum = (long *)malloc(sizeof(long) * q);
	for(int j=0; j<q; j++){
		int b;
		int c;
		scanf("%d", &b);
		scanf("%d", &c);
		tmp_sum += (c-b)*array[b];
		sum[j] = tmp_sum;
		array[c] += array[b];
		array[b] = 0;
	}
	for(int k=0; k<q; k++){
		printf("%ld\n", sum[k]);
	}
	return 0;
}