Problem:
Score : 200 points

Problem Statement

The word internationalization is sometimes abbreviated to i18n.
This comes from the fact that there are 18 letters between the first i and the last n.

You are given a string s of length at least 3 consisting of lowercase English letters.
Abbreviate s in the same way.

Constraints

3 ≤ |s| ≤ 100 (|s| denotes the length of s.)

s consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s

Output

Print the abbreviation of s.

Sample Input 1

internationalization

Sample Output 1

i18n

Sample Input 2

smiles

Sample Output 2

s4s

Sample Input 3

xyz

Sample Output 3

x1z

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>

#define STRING_LENGTH 100
#define ARRAY_SIZE (STRING_LENGTH + 1)

void solve(char s[ARRAY_SIZE]);


int main()
{
  char s[ARRAY_SIZE];

  scanf("%s", &s);
  solve(s);

  return 0;
}

void solve(char s[ARRAY_SIZE])
{
  int i;
  int length;

  i = 0;
  while (s[i] != '\0')
    {
      i++;
    }
  length = i;

  printf("%c%d%c\n", s[0], length - 2, s[length - 1]);
}