Problem:
Score : 300 points

Problem Statement

A railroad running from west to east in Atcoder Kingdom is now complete.

There are N stations on the railroad, numbered 1 through N from west to east.

Tomorrow, the opening ceremony of the railroad will take place.

On this railroad, for each integer i such that 1≤i≤N-1, there will be trains that run from Station i to Station i+1 in C_i seconds. No other trains will be operated.

The first train from Station i to Station i+1 will depart Station i S_i seconds after the ceremony begins. Thereafter, there will be a train that departs Station i every F_i seconds.

Here, it is guaranteed that F_i divides S_i.

That is, for each Time t satisfying S_i≤t and t％F_i=0, there will be a train that departs Station i t seconds after the ceremony begins and arrives at Station i+1 t+C_i seconds after the ceremony begins, where A％B denotes A modulo B, and there will be no other trains.

For each i, find the earliest possible time we can reach Station N if we are at Station i when the ceremony begins, ignoring the time needed to change trains.

Constraints

1≤N≤500

1≤C_i≤100

1≤S_i≤10^5

1≤F_i≤10

S_i％F_i=0

All input values are integers.

Input

Input is given from Standard Input in the following format:

N
C_1 S_1 F_1
:
C_{N-1} S_{N-1} F_{N-1}

Output

Print N lines. Assuming that we are at Station i (1≤i≤N) when the ceremony begins, if the earliest possible time we can reach Station N is x seconds after the ceremony begins, the i-th line should contain x.

Sample Input 1

3
6 5 1
1 10 1

Sample Output 1

12
11
0

We will travel from Station 1 as follows:

5 seconds after the beginning: take the train to Station 2.

11 seconds: arrive at Station 2.

11 seconds: take the train to Station 3.

12 seconds: arrive at Station 3.

We will travel from Station 2 as follows:

10 seconds: take the train to Station 3.

11 seconds: arrive at Station 3.

Note that we should print 0 for Station 3.

Sample Input 2

4
12 24 6
52 16 4
99 2 2

Sample Output 2

187
167
101
0

Sample Input 3

4
12 13 1
44 17 17
66 4096 64

Sample Output 3

4162
4162
4162
0

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct stations
{
    int c;
    int s;
    int f;
} station;
int main()
{
    station stat[501];
    long time[501],t;
    long n,i,j,k;
    while(scanf("%ld",&n)!=EOF)
    {
        for(i=0; i<n-1; i++)
        {
            scanf("%d%d%d",&stat[i].c,&stat[i].s,&stat[i].f);
            time[i]=0;
        }
        time[n-1]=0;
        for(i=0; i<n-1; i++)
        {
            time[i]+=stat[i].s;
            for(j=0; j<=i; j++)
            {
                if(i!=j)
                {
                    t=time[j]-stat[i].s;
                    if(t<0)
                    {
                        time[j]=stat[i].s;
                    }else if(t%stat[i].f!=0)
                    {
                        t=(t/stat[i].s+1)*stat[i].s;
                        time[j]=time[j]-stat[i].s+t;
                    }
                }
                //t=time[j]-stat[i].c-stat[i].f;
                time[j]+=stat[i].c;
            }
        }
        for(i=0; i<n; i++)
        {
            printf("%ld\n",time[i]);
        }
    }
    return 0;
}