Problem:
Score : 200 points

Problem Statement

A shop sells N kinds of fruits, Fruit 1, \ldots, N, at prices of p_1, \ldots, p_N yen per item, respectively. (Yen is the currency of Japan.)

Here, we will choose K kinds of fruits and buy one of each chosen kind. Find the minimum possible total price of those fruits.

Constraints

1 \leq K \leq N \leq 1000

1 \leq p_i \leq 1000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
p_1 p_2 \ldots p_N

Output

Print an integer representing the minimum possible total price of fruits.

Sample Input 1

5 3
50 100 80 120 80

Sample Output 1

210

This shop sells Fruit 1, 2, 3, 4, and 5 for 50 yen, 100 yen, 80 yen, 120 yen, and 80 yen, respectively.

The minimum total price for three kinds of fruits is 50 + 80 + 80 = 210 yen when choosing Fruit 1, 3, and 5.

Sample Input 2

1 1
1000

Sample Output 2

1000

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

#include<stdio.h>
int main(){
  int n,k,i,j,p[1000],x[1000],sum=0;
  scanf("%d %d",&n,&k);
  for(i=0;i<n;i++){
    scanf("%d",&p[i]);
    x[i]=1000;
  }
  for(i=0;i<n;i++){
    for(j=0;j<k;j++){
      if(p[i]>x[j]){
        if(j>0){x[j-1]=p[i];}
        break;
      }else{
         if(j>0){x[j-1]=x[j];}
      }
      if(j==k-1){x[j]=p[i];}
    }
  }
  for(j=0;j<k;j++){
    sum+=x[j];
  }
  printf("%d\n",sum);
}