Problem:
Score : 300 points

Problem Statement

You are playing the following game with Joisino.

Initially, you have a blank sheet of paper.

Joisino announces a number. If that number is written on the sheet, erase the number from the sheet; if not, write the number on the sheet. This process is repeated N times.

Then, you are asked a question: How many numbers are written on the sheet now?

The numbers announced by Joisino are given as A_1, ... ,A_N in the order she announces them. How many numbers will be written on the sheet at the end of the game?

Constraints

1≤N≤100000

1≤A_i≤1000000000(=10^9)

All input values are integers.

Input

Input is given from Standard Input in the following format:

N
A_1
:
A_N

Output

Print how many numbers will be written on the sheet at the end of the game.

Sample Input 1

3
6
2
6

Sample Output 1

1

The game proceeds as follows:

6 is not written on the sheet, so write 6.

2 is not written on the sheet, so write 2.

6 is written on the sheet, so erase 6.

Thus, the sheet contains only 2 in the end. The answer is 1.

Sample Input 2

4
2
5
5
2

Sample Output 2

0

It is possible that no number is written on the sheet in the end.

Sample Input 3

6
12
22
16
22
18
12

Sample Output 3

2

Solution in C (GCC 5.4.1) (judge verdict: Time Limit Exceeded)

#include <stdio.h>
#include <stdlib.h>
#include <math.h>

#define MAX 100001

int a[MAX]= {0};

int find(int n)
{
    int c=n%100000;
    while(1)
    {
        if(c>100000)
            c=0;
        if(a[c]==n)
        {
            a[c]=0;
            return 1;
        }
        else if(a[c]==0)
        {
            a[c]=n;
            return 0;
        }
        else c++;
    }
}

int main()
{
    int N,i,j,count=0,n;
    scanf("%d",&N);

    for(i=0; i<N; i++)
    {
        scanf("%d",&n);
        for(j=0; j<i; j++)
        {
            if(n==a[j])
            {
                a[j]=0;
                count--;
                break;
            }
        }
        if(j==i)
        {
            a[j]=n;
            count++;
        }
        /* if(find(n)==1)
         {
             count--;
         }else
         {
             count++;
         }*/

    }
    printf("%d\n",count);
    return 0;
}