Problem:
Score : 200 points

Problem Statement

In the beginning, Takahashi has A cookies, and Aoki has B cookies.
They will perform the following operation alternately, starting from Takahashi:

If the number of cookies in his hand is odd, eat one of those cookies; if the number is even, do nothing. Then, give one-half of the cookies in his hand to the other person.

Find the numbers of cookies Takahashi and Aoki respectively have after performing K operations in total.

Constraints

1 \leq A,B \leq 10^9

1 \leq K \leq 100

A,B and K are integers.

Input

Input is given from Standard Input in the following format:

A B K

Output

Print the number of cookies Takahashi has, and the number of cookies Aoki has, in this order, after performing K operations in total.

Sample Input 1

5 4 2

Sample Output 1

5 3

The process will go as follows:

In the beginning, Takahashi and Aoki have 5 and 4 cookies, respectively.

Takahashi eats one cookie and gives two cookies to Aoki. They now have 2 and 6 cookies, respectively.

Aoki gives three cookies to Takahashi. They now have 5 and 3 cookies, respectively.

Sample Input 2

3 3 3

Sample Output 2

1 3

Sample Input 3

314159265 358979323 84

Sample Output 3

448759046 224379523

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>


void sharea (long long *a, long long *b)
{
    if(*a % 2 == 0)  {
        *b += *a/2;
        *a = *a/2;
    }
    else{
        *b += (*a-1)/2;
        *a = (*a-1)/2;
    }
}
void shareb (long long *a, long long *b)
{
    if(*b % 2 == 0)  {
        *a += *b/2;
        *b = *b/2;
    }
    else{
        *a += (*b-1)/2;
        *b = (*b-1)/2;
    }
}

int main (void) {
    long long a,b,k;
    scanf("%lld %lld %lld",&a,&b,&k);
    for(int i= 0; i < k; i ++)  {
        if(i % 2 ==0 )    sharea(&a,&b);
        else    shareb(&a,&b);
    }
    printf("%lld %lld",a,b);
    return 0;
}