Problem:
Binary Search Tree III

Write a program which performs the following operations to a binary search tree $T$ by adding delete operation to B: Binary Search Tree II.

insert $k$: Insert a node containing $k$ as key into $T$.

find $k$: Report whether $T$ has a node containing $k$.

delete $k$: Delete a node containing $k$.

print: Print the keys of the binary search tree by inorder tree walk and preorder tree walk respectively.

The operation delete $k$ for deleting a given node $z$ containing key $k$ from $T$ can be implemented by an algorithm which considers the following cases:

If $z$ has no children, we modify its parent $z.p$ to replace $z$ with NIL as its child (delete $z$).

If $z$ has only a single child, we "splice out" $z$ by making a new link between its child and its parent.

If $z$ has two children, we splice out $z$'s successor $y$ and replace $z$'s key with $y$'s key.

Input

In the first line, the number of operations $m$ is given. In the following $m$ lines, operations represented by insert $k$, find $k$, delete $k$ or print are given.

Output

For each find $k$ operation, print "yes" if $T$ has a node containing $k$, "no" if not.

In addition, for each print operation, print a list of keys obtained by inorder tree walk and preorder tree walk in a line respectively. Put a space character before each key

Constraints

The number of operations $\leq 500,000$

The number of print operations $\leq 10$.

$-2,000,000,000 \leq key \leq 2,000,000,000$

The height of the binary tree does not exceed 100 if you employ the above pseudo code.

The keys in the binary search tree are all different.

Sample Input 1

18
insert 8
insert 2
insert 3
insert 7
insert 22
insert 1
find 1
find 2
find 3
find 4
find 5
find 6
find 7
find 8
print
delete 3
delete 7
print

Sample Output 1

yes
yes
yes
no
no
no
yes
yes
1 2 3 7 8 22
8 2 1 3 7 22
1 2 8 22
8 2 1 22

Reference

Introduction to Algorithms, Thomas H. Cormen, Charles E. Leiserson, Ronald L. Rivest, and Clifford Stein. The MIT Press.

Solution in C (judge verdict: Accepted)

#include<stdio.h>
#include<stdlib.h>

#define NIL NULL
#define N 500000

struct node{
  struct node *parent;
  struct node *right;
  struct node *left;
  int key;
};

typedef struct node * Node;

Node root;

void insert(int);
void inorder(Node);
void preorder(Node);
Node find(Node,int);
Node getMinimum(Node);
Node getSuccessor(Node);
void deleteNode(Node);

int main(void){
  int n,x;
  int i;
  char com[20];
  Node t;

  scanf("%d",&n);

  for(i = 0; i < n; i++){
    scanf(" %s",com);
    if(com[0] == 'i'){
      scanf(" %d",&x);
      insert(x);
    }
    else if(com[0] == 'f'){
      scanf(" %d",&x);
      t = find(root,x);
      if(t != NIL)printf("yes\n");
      else printf("no\n");
    }
    else if(com[0] == 'd'){
      scanf(" %d",&x);
      deleteNode(find(root,x));
    }
    else if(com[0] == 'p'){
      inorder(root);
      printf("\n");
      preorder(root);
      printf("\n");
    }
  }
  
  return 0;
}

void insert(int k){
  Node y = NIL;
  Node x = root;
  Node z;

  z = (Node)malloc(sizeof(struct node));
  z->key = k;
  z->left = NIL;
  z->right = NIL;

  while(x != NIL){
    y = x;
    if(z->key < x->key){
      x = x->left;
    }
    else{
      x = x->right;
    }
  }
  z->parent = y;
  if(y == NIL){
    root = z;
  }
  else{
    if(z->key < y->key){
      y->left = z;
    }
    else{
      y->right = z;
    }
  }
}

void inorder(Node u){
  if(u == NIL)return;
  inorder(u->left);
  printf(" %d",u->key);
  inorder(u->right);
}

void preorder(Node u){
  if(u == NIL)return;
  printf(" %d",u->key);
  preorder(u->left);
  preorder(u->right);
}

Node find(Node u, int k){
  while(u != NIL && u->key != k){
    if(k < u->key){
      u = u->left;
    }
    else{
      u = u->right;
    }
  }
  return u;
}

Node getMinimum(Node u){
  while(u->left != NIL) u = u->left;
  return u;
}

Node getSuccessor(Node u){
  Node y;
  
  if(u->right != NIL) return getMinimum(u->right);

  y = u->parent;
  while(y != NIL && u == y->right){
    u = y;
    y = y->parent;
  }
  return y;
}

void deleteNode(Node u){
  Node x,y;
  
  if(u->left == NIL || u->right == NIL){
    y = u;
  }
  else{
    y = getSuccessor(u);
  }

  if(y->left != NIL){
    x = y->left;
  }
  else{
    x = y->right;
  }

  if(x != NIL){
    x->parent = y->parent;
  }

  if(y->parent == NIL){
    root = x;
  }
  else if(y == y->parent->left){
    y->parent->left = x;
  }
  else{
    y->parent->right = x;
  }

  if(y != u){
    u->key = y->key;
  }
}