Problem:
Score : 200 points

Problem Statement

Takahashi is standing on a two-dimensional plane, facing north. Find the minimum positive integer K such that Takahashi will be at the starting position again after he does the following action K times:

Go one meter in the direction he is facing. Then, turn X degrees counter-clockwise.

Constraints

1 \leq X \leq 179

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print the number of times Takahashi will do the action before he is at the starting position again.

Sample Input 1

90

Sample Output 1

4

Takahashi's path is a square.

Sample Input 2

1

Sample Output 2

360

Solution in C (GCC 9.2.1) (judge verdict: Wrong Answer)

#include  <stdio.h>

int main( void )
{
  	int x;
    scanf("%d",&x);
  	int a=360%x;
  	if(a!=0)
    {
      int z;
	  for(int p=1; ; p++)
      {
        if((360/p)%x==0)
        {
        	printf("%d",(360*p)/x);
  	        return 0;
        }
      }
    }
    printf("%d %d",360/x,a);
}