Problem:
Score : 200 points

Problem Statement

The word internationalization is sometimes abbreviated to i18n.
This comes from the fact that there are 18 letters between the first i and the last n.

You are given a string s of length at least 3 consisting of lowercase English letters.
Abbreviate s in the same way.

Constraints

3 ≤ |s| ≤ 100 (|s| denotes the length of s.)

s consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s

Output

Print the abbreviation of s.

Sample Input 1

internationalization

Sample Output 1

i18n

Sample Input 2

smiles

Sample Output 2

s4s

Sample Input 3

xyz

Sample Output 3

x1z

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
#include <string.h>

#define LEN_WORD 100

int main (void)
{
	/* variables for main process */
	char buffer_word[LEN_WORD];

	// STEP.01
	// read out the targe word
	fgets( buffer_word, LEN_WORD, stdin );

	// STEP.02
	// output the shortened word
	printf( "%c%d%c\n", buffer_word[0], strlen( buffer_word )-2, buffer_word[ strlen( buffer_word )-1 ] );

	// STEP.TRUE_END
	return 0;
}