Problem:
Score : 700 points

Problem Statement

You are given four integers: H, W, h and w (1 ≤ h ≤ H, 1 ≤ w ≤ W).
Determine whether there exists a matrix such that all of the following conditions are held, and construct one such matrix if the answer is positive:

The matrix has H rows and W columns.

Each element of the matrix is an integer between -10^9 and 10^9 (inclusive).

The sum of all the elements of the matrix is positive.

The sum of all the elements within every subrectangle with h rows and w columns in the matrix is negative.

Constraints

1 ≤ h ≤ H ≤ 500

1 ≤ w ≤ W ≤ 500

Input

Input is given from Standard Input in the following format:

H W h w

Output

If there does not exist a matrix that satisfies all of the conditions, print No.

Otherwise, print Yes in the first line, and print a matrix in the subsequent lines in the following format:

a_{11} ... a_{1W}
:
a_{H1} ... a_{HW}

Here, a_{ij} represents the (i,\ j) element of the matrix.

Sample Input 1

3 3 2 2

Sample Output 1

Yes
1 1 1
1 -4 1
1 1 1

The sum of all the elements of this matrix is 4, which is positive.
Also, in this matrix, there are four subrectangles with 2 rows and 2 columns as shown below. For each of them, the sum of all the elements inside is -1, which is negative.

Sample Input 2

2 4 1 2

Sample Output 2

No

Sample Input 3

3 4 2 3

Sample Output 3

Yes
2 -5 8 7
3 -5 -4 -5
2 1 -1 7

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
#include<stdlib.h>

typedef long long int int64;

#define POS(i,j) ((i)*W+(j))

void run(void){
  int H,W,h,w;
  scanf("%d%d%d%d",&H,&W,&h,&w);
  if(H%h==0 && W%w==0){
    printf("No\n");
    return;
  }
  int *b=(int *)calloc(H*W,sizeof(int));
  const int m=(1000000000-1)/(h*w-1);
  int64 sum=0;
  int i,j;
  for(i=0;i<H;i++){
    for(j=0;j<W;j++){
      b[POS(i,j)]=(i%h==h-1 && j%w==w-1?-m*(h*w-1)-1:m);
      sum+=b[POS(i,j)];
    }
  }
  if(sum<=0){
    printf("No\n");
    return;
  }
  printf("Yes\n");
  for(i=0;i<H;i++){
    for(j=0;j<W;j++){
      printf("%d ",b[POS(i,j)]);
    }
    printf("\n");
  }
}

int main(void){
  run();
  return 0;
}