Problem:
Score : 400 points

Problem Statement

Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.

You are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.

Constraints

2 ≦ |s| ≦ 10^5

s consists of lowercase letters.

Partial Score

200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.

Input

The input is given from Standard Input in the following format:

s

Output

If there exists no unbalanced substring of s, print -1 -1.

If there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.

Sample Input 1

needed

Sample Output 1

2 5

The string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.

Sample Input 2

atcoder

Sample Output 2

-1 -1

The string atcoder contains no unbalanced substring.

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>

int main(void){
  char str[100002];
  scanf("%100001s",str);
  int array[]={-1,1};
  int i,j;

  //文字列の長さ
  for(j=0;str[j]!='\0';j++){
  }

  for(i=0;i<j;i++){
    if(str[i]==str[i+1]){
      array[0]=i+1,array[1]=i+2;
      // printf("%d %d\n",array[0],array[1]);
      break;
    }else if(str[i]==str[i+2]){
      array[0]=i+1,array[1]=i+3;
      //printf("%d %d\n",array[0],array[1]);
      break;
    }
  }

  // printf("%d\n",j);
  printf("%d %d\n",array[0],array[1]);
    return 0;
  }