Problem:
Score: 100 points

Problem Statement

In this problem, a date is written as Y-M-D. For example, 2019-11-30 means November 30, 2019.

Integers M_1, D_1, M_2, and D_2 will be given as input.

It is known that the date 2019-M_2-D_2 follows 2019-M_1-D_1.

Determine whether the date 2019-M_1-D_1 is the last day of a month.

Constraints

Both 2019-M_1-D_1 and 2019-M_2-D_2 are valid dates in the Gregorian calendar.

The date 2019-M_2-D_2 follows 2019-M_1-D_1.

Input

Input is given from Standard Input in the following format:

M_1 D_1
M_2 D_2

Output

If the date 2019-M_1-D_1 is the last day of a month, print 1; otherwise, print 0.

Sample Input 1

11 16
11 17

Sample Output 1

0

November 16 is not the last day of a month.

Sample Input 2

11 30
12 1

Sample Output 2

1

November 30 is the last day of November.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
 
int main(void){
  
  int m1,d1,m2,d2;
  
  scanf("%d %d",&m1,&d1);
  scanf("%d %d",&m2,&d2);
  
  if(m1<m2){}
  else if((m1==m2) && (d1<d2)){}
  else{
    m1=m2;
    d1=d2;
  }
      
  
  switch(m1){
    case 1:
    case 3:
    case 5:
    case 7:
    case 8:
    case 10:
    case 12:
      if(d1==31){
        printf("1\n");
      }else{printf("0\n");}
      break;
    case 2:
      if(d1==28){
        printf("1\n");
      }else{printf("0\n");}
      break;
    case 4:
    case 6:
    case 9:
    case 11:
      if(d1==30){
        printf("1\n");
      }else{printf("0\n");}
      break;
    default:
      printf("0\n");
      
  }
  return 0;
}