Problem:
Score: 100 points

Problem Statement

E869120 has A 1-yen coins and infinitely many 500-yen coins.

Determine if he can pay exactly N yen using only these coins.

Constraints

N is an integer between 1 and 10000 (inclusive).

A is an integer between 0 and 1000 (inclusive).

Input

Input is given from Standard Input in the following format:

N
A

Output

If E869120 can pay exactly N yen using only his 1-yen and 500-yen coins, print Yes; otherwise, print No.

Sample Input 1

2018
218

Sample Output 1

Yes

We can pay 2018 yen with four 500-yen coins and 18 1-yen coins, so the answer is Yes.

Sample Input 2

2763
0

Sample Output 2

No

When we have no 1-yen coins, we can only pay a multiple of 500 yen using only 500-yen coins. Since 2763 is not a multiple of 500, we cannot pay this amount.

Sample Input 3

37
514

Sample Output 3

Yes

Solution in C (GCC 9.2.1) (judge verdict: Wrong Answer)

#include<stdio.h>
int main()
{
	int N,A;
	scanf("%d",&N);
	scanf("%d",&A);
	if(N<500 && A>=N)
	{
		printf("YES");
	}
	else if(N>=500 && A==0)
	{
		if(N%500==0)
		{
			printf("YES");
		}
		else
		{
			printf("NO");
		}
	}
	else if(N>=500 && A>0)
	{
		int r = N/500;
		int d = r*500;
		int s = N-d;
		if(A>=s)
		{
			printf("YES");
		}
		else
		{
			printf("NO");
		}
	}
	else
	{
		printf("NO");
	}
	
	
	
  
	
	return 0;
}