Problem:
Score : 200 points

Problem Statement

There are N students and M checkpoints on the xy-plane.

The coordinates of the i-th student (1 \leq i \leq N) is (a_i,b_i), and the coordinates of the checkpoint numbered j (1 \leq j \leq M) is (c_j,d_j).

When the teacher gives a signal, each student has to go to the nearest checkpoint measured in Manhattan distance.

The Manhattan distance between two points (x_1,y_1) and (x_2,y_2) is |x_1-x_2|+|y_1-y_2|.

Here, |x| denotes the absolute value of x.

If there are multiple nearest checkpoints for a student, he/she will select the checkpoint with the smallest index.

Which checkpoint will each student go to?

Constraints

1 \leq N,M \leq 50

-10^8 \leq a_i,b_i,c_j,d_j \leq 10^8

All input values are integers.

Input

The input is given from Standard Input in the following format:

N M
a_1 b_1
:
a_N b_N
c_1 d_1
:
c_M d_M

Output

Print N lines.

The i-th line (1 \leq i \leq N) should contain the index of the checkpoint for the i-th student to go.

Sample Input 1

2 2
2 0
0 0
-1 0
1 0

Sample Output 1

2
1

The Manhattan distance between the first student and each checkpoint is:

For checkpoint 1: |2-(-1)|+|0-0|=3

For checkpoint 2: |2-1|+|0-0|=1

The nearest checkpoint is checkpoint 2. Thus, the first line in the output should contain 2.

The Manhattan distance between the second student and each checkpoint is:

For checkpoint 1: |0-(-1)|+|0-0|=1

For checkpoint 2: |0-1|+|0-0|=1

When there are multiple nearest checkpoints, the student will go to the checkpoint with the smallest index. Thus, the second line in the output should contain 1.

Sample Input 2

3 4
10 10
-10 -10
3 3
1 2
2 3
3 5
3 5

Sample Output 2

3
1
2

There can be multiple checkpoints at the same coordinates.

Sample Input 3

5 5
-100000000 -100000000
-100000000 100000000
100000000 -100000000
100000000 100000000
0 0
0 0
100000000 100000000
100000000 -100000000
-100000000 100000000
-100000000 -100000000

Sample Output 3

5
4
3
2
1

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<limits.h>
#include<math.h>

int main(void){
    int N, M;
    scanf("%d %d", &N, &M);
    int *a = (int*)malloc(N * sizeof(int));
    int *b = (int*)malloc(N * sizeof(int));
    int *c = (int*)malloc(M * sizeof(int));
    int *d = (int*)malloc(M * sizeof(int));

    int i, j;
    for(i=0; i<N; i++) {
        scanf("%d %d", &a[i], &b[i]);
    }
    for(i=0; i<M; i++) {
        scanf("%d %d", &c[i], &d[i]);
    }

    for(i=0; i<N; i++) {
        int min = INT_MAX;
        int index = 0;
        for(j=0; j<M; j++) {
            if(c[j] != INT_MAX) {
                if(abs(a[i]-c[j]) + abs(b[i]-d[j]) < min) {
                    min = abs(a[i]-c[j]) + abs(b[i]-d[j]);
                    index = j;
                }
            }
        }
        printf("%d\n", index+1);
        c[index] = INT_MAX;
    }

    free(a);
    free(b);
    free(c);
    free(d);
    return 0;
}