Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C (Clang 3.8.0) (judge verdict: Wrong Answer)

#include<stdio.h>

int main()

{
	int n;

	scanf("%d", &n);

	if (n < 3 * 5 * 7) {
		printf("0\n");

	}
	else if (n < 3 * 5 * 9) {
		printf("1\n");

	}
	else if (n < 3 * 5 * 11) {
		printf("2\n");
	}
	else if (n < 3 * 7 * 9) {

		printf("3\n");

	}
	else if (n < 3 * 7 * 13) {

		printf("4\n");

	}
	else {
		printf("5\n");

	}

	return 0;



}