Problem:
Score : 300 points

Problem Statement

There are N people living on a number line.

The i-th person lives at coordinate X_i.

You are going to hold a meeting that all N people have to attend.

The meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.

Find the minimum total points of stamina the N people have to spend.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq X_i \leq 100

Input

Input is given from Standard Input in the following format:

N
X_1 X_2 ... X_N

Output

Print the minimum total stamina the N people have to spend.

Sample Input 1

2
1 4

Sample Output 1

5

Assume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.

Note that you can hold the meeting only at an integer coordinate.

Sample Input 2

7
14 14 2 13 56 2 37

Sample Output 2

2354

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
int main()
{
    int b[100],i,e=0,f=0,c;
    float avg,d,s=0,a;
    scanf("%f",&a);
    for(i=0;i<a;i++)
    {
        scanf("%d",&b[i]);
        s=s+b[i];
    }
    avg=s/a;
    c=s/a;
    d=(avg-c);
    if(d>.5)
    {
        for(i=0;i<a;i++)
        {
            e=e+abs(b[i]-(c+1))*abs(b[i]-(c+1));
        }
        printf("%d",e);
    }
    if(d<.5)
    {
        for(i=0;i<a;i++)
        {
           f=f+abs(b[i]-c)*abs(b[i]-c);
        }
        printf("%d",f);
    }
}