Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>

int main()
{
    long long n,a,b,c;

    scanf("%lld",&n);

    for (int i = 1; i <= 3500; i++)
    {
        for (int j = 1; j <= 3500; j++)
        {
            if((4 * i * j - i * n - j * n) == 0)continue;
            if((n * i * j) % (4 * i * j - i * n - j * n) == 0)
            {
                a = i;
                b = j;
                c = (n * i * j) / (4 * i * j - i * n - j * n);
                break;
            }
        }
    }
    printf("%lld %lld %lld",a,b,c);
    
}