Problem:
Score : 200 points

Problem Statement

There is a square in the xy-plane. The coordinates of its four vertices are (x_1,y_1),(x_2,y_2),(x_3,y_3) and (x_4,y_4) in counter-clockwise order.
(Assume that the positive x-axis points right, and the positive y-axis points up.)

Takahashi remembers (x_1,y_1) and (x_2,y_2), but he has forgot (x_3,y_3) and (x_4,y_4).

Given x_1,x_2,y_1,y_2, restore x_3,y_3,x_4,y_4. It can be shown that x_3,y_3,x_4 and y_4 uniquely exist and have integer values.

Constraints

|x_1|,|y_1|,|x_2|,|y_2| \leq 100

(x_1,y_1) ≠ (x_2,y_2)

All values in input are integers.

Input

Input is given from Standard Input in the following format:

x_1 y_1 x_2 y_2

Output

Print x_3,y_3,x_4 and y_4 as integers, in this order.

Sample Input 1

0 0 0 1

Sample Output 1

-1 1 -1 0

(0,0),(0,1),(-1,1),(-1,0) is the four vertices of a square in counter-clockwise order.
Note that (x_3,y_3)=(1,1),(x_4,y_4)=(1,0) is not accepted, as the vertices are in clockwise order.

Sample Input 2

2 3 6 6

Sample Output 2

3 10 -1 7

Sample Input 3

31 -41 -59 26

Sample Output 3

-126 -64 -36 -131

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

/* ex 7_1
   hangan2020 */

#include <stdio.h>

// Structure type for square's point
typedef struct point{
    int x_elem;
    int y_elem;
}point;

// Solve by creating perpendicular vectors
/*!! Created parallel vector should have head at the tail of original vector
     in order to follow anti-clockwise */

/*Shifting point in order to create the head of a
perpendicular vector with the same length*/
void shift_point(point or_point, point* sh_point, int dif_x, int dif_y){
    sh_point -> x_elem = or_point.x_elem - dif_y;
    sh_point -> y_elem = or_point.y_elem + dif_x;
}

int main(void){
    int x1, y1, x2, y2;
    int dif_x, dif_y;
    point a, b, c, d;
    point *pc, *pd; // Pointer to the other two points
    pc = &c; pd = &d;

    scanf("%d %d %d %d", &x1, &y1, &x2, &y2);

    // point a and b'coordinate
    a.x_elem = x1; a.y_elem = y1;
    b.x_elem = x2; b.y_elem = y2;

    // Values will be use for point shifting calculation
    dif_x = x2 - x1; // x element of ab vector
    dif_y = y2 - y1; // y element of ab vector

    /*Shifting point b in order to create a perpendicular
     vector from vector ab's head (same length)*/ 
    shift_point(b, pc, dif_x, dif_y); 
    /*Shifting point b in order to create a perpendicular
     vector from vector ba's head (same length)*/ 
    shift_point(a, pd, dif_x, dif_y);

    //Print c and d's coordinates
    printf("%d %d ", c.x_elem, c.y_elem);
    printf("%d %d\n", d.x_elem, d.y_elem);

    return 0;

}