Problem:
Score : 300 points

Problem Statement

1000000000000001 dogs suddenly appeared under the roof of Roger's house, all of which he decided to keep. The dogs had been numbered 1 through 1000000000000001, but he gave them new names, as follows:

the dogs numbered 1,2,\cdots,26 were respectively given the names a, b, ..., z;

the dogs numbered 27,28,29,\cdots,701,702 were respectively given the names aa, ab, ac, ..., zy, zz;

the dogs numbered 703,704,705,\cdots,18277,18278 were respectively given the names aaa, aab, aac, ..., zzy, zzz;

the dogs numbered 18279,18280,18281,\cdots,475253,475254 were respectively given the names aaaa, aaab, aaac, ..., zzzy, zzzz;

the dogs numbered 475255,475256,\cdots were respectively given the names aaaaa, aaaab, ...;

and so on.

To sum it up, the dogs numbered 1, 2, \cdots were respectively given the following names:

a, b, ..., z, aa, ab, ..., az, ba, bb, ..., bz, ..., za, zb, ..., zz, aaa, aab, ..., aaz, aba, abb, ..., abz, ..., zzz, aaaa, ...

Now, Roger asks you:

"What is the name for the dog numbered N?"

Constraints

N is an integer.

1 \leq N \leq 1000000000000001

Input

Input is given from Standard Input in the following format:

N

Output

Print the answer to Roger's question as a string consisting of lowercase English letters.

Sample Input 1

2

Sample Output 1

b

Sample Input 2

27

Sample Output 2

aa

Sample Input 3

123456789

Sample Output 3

jjddja

Solution in C (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <stdio.h>
int main(void){
    long int i, n, count = 0;
    char a[100];
    scanf("%ld", &n);
    
    for( i = 0; 0 < n; i++ ){
        if( n % 26 == 1 ){
            a[i] = 'a';
        } else if( n % 26 == 2 ){
            a[i] = 'b';
        } else if( n % 26 == 3 ){
            a[i] = 'c';
        } else if( n % 26 == 4 ){
            a[i] = 'd';
        } else if( n % 26 == 5 ){
            a[i] = 'e';
        } else if( n % 26 == 6 ){
            a[i] = 'f';
        } else if( n % 26 == 7 ){
            a[i] = 'g';
        } else if( n % 26 == 8 ){
            a[i] = 'h';
        } else if( n % 26 == 9 ){
            a[i] = 'i';
        } else if( n % 26 == 10 ){
            a[i] = 'j';
        } else if( n % 26 == 11 ){
            a[i] = 'k';
        } else if( n % 26 == 12 ){
            a[i] = 'l';
        } else if( n % 26 ==  13){
            a[i] = 'm';
        } else if( n % 26 == 14 ){
            a[i] = 'n';
        } else if( n % 26 == 15 ){
            a[i] = 'o';
        } else if( n % 26 == 16 ){
            a[i] = 'p';
        } else if( n % 26 == 17 ){
            a[i] = 'q';
        } else if( n % 26 == 18 ){
            a[i] = 'r';
        } else if( n % 26 == 19 ){
            a[i] = 's';
        } else if( n % 26 == 20 ){
            a[i] = 't';
        } else if( n % 26 == 21 ){
            a[i] = 'u';
        } else if( n % 26 == 22 ){
            a[i] = 'v';
        } else if( n % 26 == 23 ){
            a[i] = 'w';
        } else if( n % 26 == 24 ){
            a[i] = 'x';
        } else if( n % 26 == 25 ){
            a[i] = 'y';
        } else {
            a[i] = 'z';
        }
        count++;
        n = n / 26;
    }
    
    for( i = count-1; 0 <= i; i-- ){
        printf("%c", a[i]);
    }
    return 0;
}