Problem:
Score : 400 points

Problem Statement

We have a sequence of length N, a = (a_1, a_2, ..., a_N).
Each a_i is a positive integer.

Snuke's objective is to permute the element in a so that the following condition is satisfied:

For each 1 ≤ i ≤ N - 1, the product of a_i and a_{i + 1} is a multiple of 4.

Determine whether Snuke can achieve his objective.

Constraints

2 ≤ N ≤ 10^5

a_i is an integer.

1 ≤ a_i ≤ 10^9

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 ... a_N

Output

If Snuke can achieve his objective, print Yes; otherwise, print No.

Sample Input 1

3
1 10 100

Sample Output 1

Yes

One solution is (1, 100, 10).

Sample Input 2

4
1 2 3 4

Sample Output 2

No

It is impossible to permute a so that the condition is satisfied.

Sample Input 3

3
1 4 1

Sample Output 3

Yes

The condition is already satisfied initially.

Sample Input 4

2
1 1

Sample Output 4

No

Sample Input 5

6
2 7 1 8 2 8

Sample Output 5

Yes

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int a[100001];

void judge(int *a, int n)
{
    int i, t = 0, k = 0;
    for(i = 0; i < n; i++)
    {
        if(a[i] % 4 == 0)
            t++;
        else if(a[i] % 2 == 0)
            k++;
    }
    if(k % 2 == 1)
        k--;
    if(3*t + k >= n)
        printf("Yes\n");
    else
        printf("No\n");
}



int main()
{
    int n;
    int i;
    while(scanf("%d",&n) != EOF)
    {
         for(i = 0; i < n; i++)
         scanf("%d",&a[i]);
         if(n == 0)
            printf("No\n");
         else
            judge(a,n);
    }
    return 0;
}