Problem:
Score : 400 points

Problem Statement

Let {\rm comb}(n,r) be the number of ways to choose r objects from among n objects, disregarding order.
From n non-negative integers a_1, a_2, ..., a_n, select two numbers a_i > a_j so that {\rm comb}(a_i,a_j) is maximized.
If there are multiple pairs that maximize the value, any of them is accepted.

Constraints

2 \leq n \leq 10^5

0 \leq a_i \leq 10^9

a_1,a_2,...,a_n are pairwise distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print a_i and a_j that you selected, with a space in between.

Sample Input 1

5
6 9 4 2 11

Sample Output 1

11 6

\rm{comb}(a_i,a_j) for each possible selection is as follows:

\rm{comb}(4,2)=6

\rm{comb}(6,2)=15

\rm{comb}(6,4)=15

\rm{comb}(9,2)=36

\rm{comb}(9,4)=126

\rm{comb}(9,6)=84

\rm{comb}(11,2)=55

\rm{comb}(11,4)=330

\rm{comb}(11,6)=462

\rm{comb}(11,9)=55

Thus, we should print 11 and 6.

Sample Input 2

2
100 0

Sample Output 2

100 0

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char** argv)
{
	int n, i;
	int a[100000] = {0}, max = 0;
	int k = 0;
	
	scanf("%d", &n);
	for(i=0;i<n;++i){
		scanf("%d", a+i);
		a[i] = a[i] * 2;
		if( a[i] > max ) max = a[i];
	}
	for(i=0; i<n; ++i){
		int d1, d2;
		d1 = (max/2) < k ? (k-max/2) : (max/2-k);
		d2 = (max/2) < a[i] ? (a[i] - max/2) : (max/2 - a[i]);
		if( d2 < d1 ) k = a[i];
	}
	
	printf("%d %d\n", max/2, k/2);
	return 0;
}