Problem:
Score : 200 points

Problem Statement

The word internationalization is sometimes abbreviated to i18n.
This comes from the fact that there are 18 letters between the first i and the last n.

You are given a string s of length at least 3 consisting of lowercase English letters.
Abbreviate s in the same way.

Constraints

3 ≤ |s| ≤ 100 (|s| denotes the length of s.)

s consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s

Output

Print the abbreviation of s.

Sample Input 1

internationalization

Sample Output 1

i18n

Sample Input 2

smiles

Sample Output 2

s4s

Sample Input 3

xyz

Sample Output 3

x1z

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int main(void){
    int count;
    int win=0;
    char s[200];
    scanf("%s",s);
    printf("%c%d%c\n",s[0],strlen(s)-2,s[strlen(s)-1]);
    return 0;
}

int min(int a,int b){
    int ans;
    if(a>b){return b;}
    else {return a;}
}

int max(int a,int b){
    int ans;
    if(a>b){return a;}
    else {return b;}
}