Problem:
Score : 300 points

Problem Statement

You are given a sequence of length N: A_1, A_2, ..., A_N.
For each integer i between 1 and N (inclusive), answer the following question:

Find the maximum value among the N-1 elements other than A_i in the sequence.

Constraints

2 \leq N \leq 200000

1 \leq A_i \leq 200000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1
:
A_N

Output

Print N lines. The i-th line (1 \leq i \leq N) should contain the maximum value among the N-1 elements other than A_i in the sequence.

Sample Input 1

3
1
4
3

Sample Output 1

4
3
4

The maximum value among the two elements other than A_1, that is, A_2 = 4 and A_3 = 3, is 4.

The maximum value among the two elements other than A_2, that is, A_1 = 1 and A_3 = 3, is 3.

The maximum value among the two elements other than A_3, that is, A_1 = 1 and A_2 = 4, is 4.

Sample Input 2

2
5
5

Sample Output 2

5
5

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
#include <stdlib.h>

int sift(int l, int r);

int main(){
	
	int n, a, i, j, ret, max, m_id, max2;
	int *A;
	
	max=m_id=max2=0;
		
	ret=scanf("%d", &n);
	
	if( ret == EOF ) {
    
    return 1;
		
  	}
	
	A=(int *)malloc(sizeof(int)*n);
	
	if(A == NULL){return 1;}
	
	for(i=0; i < n; i++){
		
		ret=scanf("%d", A+i);
		
		if( ret == EOF ) {
    
	    return 1;
			
	  	}
		
	}
	
	for(i=0; i < n; i++){
		if(max < *(A+i)){
			
			max=*(A+i);
			m_id=i;
			
		}
		
	}
	
	for(i=0; i < n; i++){
		
		if(max2 < *(A+i) && m_id != i){
			
			max2=*(A+i);
			
		}
		
	}
	
	
	for(i=0; i < n; i++){
		
		if(m_id != i){printf("%d\n", max);}
		else{printf("%d\n", max2);}

	}
	
	free(A);
	
	return 0; 
	
}