Problem:
Score : 200 points

Problem Statement

You are given string S and T consisting of lowercase English letters.

Determine if S equals T after rotation.

That is, determine if S equals T after the following operation is performed some number of times:

Operation: Let S = S_1 S_2 ... S_{|S|}. Change S to S_{|S|} S_1 S_2 ... S_{|S|-1}.

Here, |X| denotes the length of the string X.

Constraints

2 \leq |S| \leq 100

|S| = |T|

S and T consist of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S equals T after rotation, print Yes; if it does not, print No.

Sample Input 1

kyoto
tokyo

Sample Output 1

Yes

In the first operation, kyoto becomes okyot.

In the second operation, okyot becomes tokyo.

Sample Input 2

abc
arc

Sample Output 2

No

abc does not equal arc after any number of operations.

Sample Input 3

aaaaaaaaaaaaaaab
aaaaaaaaaaaaaaab

Sample Output 3

Yes

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
#include<string.h>

int main(void)
{
  char s[128],t[128];
  scanf("%s %s",s,t);
  int len=(int)strlen(s);

  if(strcmp(s,t)==0){
    puts("Yes");
    return 0;
  }

  int count=len-1;
  while(count>0){
    char c=s[len-1];
    for(int i=len-1;i>0;i--){
      s[i]=s[i-1];
    }
    s[0]=c;
    if(strcmp(s,t)==0){
      puts("Yes");
      return 0;
    }
    count--;
  }

  puts("No");
  return 0;
}