Problem:
Score : 200 points

Problem Statement

There is a kangaroo at coordinate 0 on an infinite number line that runs from left to right, at time 0.
During the period between time i-1 and time i, the kangaroo can either stay at his position, or perform a jump of length exactly i to the left or to the right.
That is, if his coordinate at time i-1 is x, he can be at coordinate x-i, x or x+i at time i.
The kangaroo's nest is at coordinate X, and he wants to travel to coordinate X as fast as possible.
Find the earliest possible time to reach coordinate X.

Constraints

X is an integer.

1≤X≤10^9

Input

The input is given from Standard Input in the following format:

X

Output

Print the earliest possible time for the kangaroo to reach coordinate X.

Sample Input 1

6

Sample Output 1

3

The kangaroo can reach his nest at time 3 by jumping to the right three times, which is the earliest possible time.

Sample Input 2

2

Sample Output 2

2

He can reach his nest at time 2 by staying at his position during the first second, and jumping to the right at the next second.

Sample Input 3

11

Sample Output 3

5

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>

int main(){

    int i,j,x,count,sum,temp = 0;
    int k = 0,space,min = 999;
    scanf("%d",&x);
    if(x == 1)
        printf("1");
    else{
        for(i = 1;i < x/2;i++){
            temp = i;
            while(temp <= x){
                sum = temp;
                count = temp;
                space = 0;
                for(j = temp+1;space < 2;j++){
                    for(k = j + space;sum < x;k++){
                        sum += k;
                        count++;
                    }
                    space++;
                    if(min > count)
                        min = count;
                }
                temp++;
            }
            if(sum == x)break;
        }
        //printf("%d\n",sum);
        printf("%d",min);
    }
    return 0;
}