Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>

int main(){
   int n ; 
   scanf("%d",&n);
   int i , j ;
   int count = 0 , count2 =0 ;
   for(i = 1 ; i <= n ; i=i+2){
       for(j = 1 ; j<= i ; j++)
       {
           if(i%j==0){
               count++ ;
           }
       }
       if(count==8){
           count2++ ;
       }
       //printf("%d",count);
       count=0 ;
       
   }
    printf("%d",count2) ;
   
   

    return 0;
}