Problem:
Score : 300 points

Problem Statement

There are N people living on a number line.

The i-th person lives at coordinate X_i.

You are going to hold a meeting that all N people have to attend.

The meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.

Find the minimum total points of stamina the N people have to spend.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq X_i \leq 100

Input

Input is given from Standard Input in the following format:

N
X_1 X_2 ... X_N

Output

Print the minimum total stamina the N people have to spend.

Sample Input 1

2
1 4

Sample Output 1

5

Assume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.

Note that you can hold the meeting only at an integer coordinate.

Sample Input 2

7
14 14 2 13 56 2 37

Sample Output 2

2354

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>

int main() {
	int N, X[100], P = 0, ave, ans[100], an = 0,a=0;

	scanf("%d",&N);
	for (int i = 0; i < N;i++) {
		scanf("%d",&X[i]);
		P = P + X[i];
		ans[i]=0;
	}
	ave = P / N;

	for (int i = 1; i <= 100;i++) {
		for (int j = 0; j < N; j++) {
			a = a + (X[j] - i) * (X[j] - i);
		}
		if (i==1|| an > a) {
			an = a;
		}
		a = 0;
	}
	printf("%d",an);

	return 0;
}