Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

//YYMM or MMYY
#include<stdio.h>
int main(){
    int s,a,b;

    //4桁の入力
    scanf("%d",&s);

    //先頭2桁
    a=s/100;

    //後2桁
    b=s%100;

    if((a<=12&&a>0)&&b>0){
        if(b<=12){
            //12以下 AND 12以下
            printf("AMBIGUOUS\n");
        }else{
            //12以下 AND 0以上
            printf("MMYY\n");
        }
    }else if(a>0&&b>0){
        if(b<=12){
            //0以上 AND 12以下
            printf("YYMM\n");
        }else{
            //0以上 AND 0以上
            printf("NA\n");
        }
    }else{
        //0以下
        printf("NA\n");
    }

    return 0;
}