Problem:
Score : 600 points

Problem Statement

Consider the following arithmetic progression with n terms:

x, x + d, x + 2d, \ldots, x + (n-1)d

What is the product of all terms in this sequence?
Compute the answer modulo 1\ 000\ 003.

You are given Q queries of this form.
In the i-th query, compute the answer in case x = x_i, d = d_i, n = n_i.

Constraints

1 \leq Q \leq 10^5

0 \leq x_i, d_i \leq 1\ 000\ 002

1 \leq n_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

Q
x_1 d_1 n_1
:
x_Q d_Q n_Q

Output

Print Q lines.

In the i-th line, print the answer for the i-th query.

Sample Input 1

2
7 2 4
12345 67890 2019

Sample Output 1

9009
916936

For the first query, the answer is 7 \times 9 \times 11 \times 13 = 9009.
Don't forget to compute the answer modulo 1\ 000\ 003.

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>

int main(void){

    float an[100000],bn[100000],cn[100000],amari[100000];

    float x[100000],d[100000],n[1000000000];

    int q;

    int i,j;

    for(i=0;i<q;i++){
        scanf("%f %f %f",&x[i],&d[i],&n[i]);
    }

    for(i=0;i<q;i++){
        an[i]=1;
        bn[i]=1;
        for(j=0;j<n[i];j++){
            an[i]=(-x[i]/d[i]-j)*an[i];
            bn[i]=bn[i]*(-d[i]);
        }
        cn[i]=an[i]*bn[i];
        amari[i]=(int)cn[i]%1000003;
    }

    for(i=0;i<q;i++){
        printf("%d %d",cn[i],amari[i]);
    }



    return 0;
}