Problem:
Score : 200 points

Problem Statement

It is only six months until Christmas, and AtCoDeer the reindeer is now planning his travel to deliver gifts.

There are N houses along TopCoDeer street. The i-th house is located at coordinate a_i. He has decided to deliver gifts to all these houses.

Find the minimum distance to be traveled when AtCoDeer can start and end his travel at any positions.

Constraints

1 ≤ N ≤ 100

0 ≤ a_i ≤ 1000

a_i is an integer.

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 ... a_N

Output

Print the minimum distance to be traveled.

Sample Input 1

4
2 3 7 9

Sample Output 1

7

The travel distance of 7 can be achieved by starting at coordinate 9 and traveling straight to coordinate 2.

It is not possible to do with a travel distance of less than 7, and thus 7 is the minimum distance to be traveled.

Sample Input 2

8
3 1 4 1 5 9 2 6

Sample Output 2

8

There may be more than one house at a position.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
#include<stdlib.h>
#include<math.h>
#include<string.h>
typedef long long int ll;
void swap(ll *x,ll *y){ll temp;temp=*x;*x=*y;*y=temp;}
ll compare_asc(const void *a,const void *b){return *(ll*)a-*(ll*)b;}
ll compare_desc(const void *a,const void *b){return *(ll*)b-*(ll*)a;}
ll max(ll x,ll y){return x>y?x:y;}
ll min(ll x,ll y){return x>y?y:x;}
/*void qsort(配列のアドレス,配列のサイズ,sizeof(配列の型),比較関数(昇順or降順)) */

int main(){
    int n,a[200];
    int min=9999,max=-1;
    
    scanf("%d",&n);
    for(int i=0;i<n;i++){
        scanf("%d",&a[i]);
        if(min>a[i])min=a[i];
        if(max<a[i])max=a[i];
    }
    printf("%d\n",max-min);
    return 0;
    
}