Problem:
Partition

Quick sort is based on the Divide-and-conquer approach. In QuickSort(A, p, r), first, a procedure Partition(A, p, r) divides an array A[p..r] into two subarrays A[p..q-1] and A[q+1..r] such that each element of A[p..q-1] is less than or equal to A[q], which is, inturn, less than or equal to each element of A[q+1..r]. It also computes the index q.

In the conquer processes, the two subarrays A[p..q-1] and A[q+1..r] are sorted by recursive calls of QuickSort(A, p, q-1) and QuickSort(A, q+1, r).

Your task is to read a sequence A and perform the Partition based on the following pseudocode:

Partition(A, p, r)
1 x = A[r]
2 i = p-1
3 for j = p to r-1
4 do if A[j] <= x
5 then i = i+1
6 exchange A[i] and A[j]
7 exchange A[i+1] and A[r]
8 return i+1

Note that, in this algorithm, Partition always selects an element A[r] as a pivot element around which to partition the array A[p..r].

Input

The first line of the input includes an integer n, the number of elements in the sequence A.

In the second line, Ai (i = 1,2,...,n), elements of the sequence are given separated by space characters.

Output

Print the sorted sequence. Two contiguous elements of the sequence should be separated by a space character. The element which is selected as the pivot of the partition should be indicated by [  ].

Constraints

1 ≤ n ≤ 100,000

0 ≤ Ai ≤ 100,000

Sample Input 1

12
13 19 9 5 12 8 7 4 21 2 6 11

Sample Output 1

9 5 8 7 4 2 6 [11] 21 13 19 12

Solution in C (judge verdict: Accepted)

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>

int partition(int *A,int p,int r){
	int x=A[r-1];
	int i=(p-1);
	int tmp;

	for(int j=0;j<(r-1);j++){
		if(A[j]<=x){
			i++;
			tmp=A[i];
			A[i]=A[j];
			A[j]=tmp;
		}

	}

	tmp=A[i+1];
	A[i+1]=A[r-1];
	A[r-1]=tmp;

	return i+1;
}

int main(){
	int N;
	int *A;

	scanf("%d",&N);
	A=(int*)malloc(sizeof(int)*N);
	for(int i=0;i<N;i++){
		scanf("%d",&A[i]);
	}
	int x=A[N-1];

	int I=partition(A,0,N);

	for(int i=0;i<N;i++){
		if(i==I){
			printf("[%d]",A[i]);
		}else{
			printf("%d",A[i]);
		}
		if(i==(N-1)){
			printf("\n");
		}else{
			printf(" ");
		}
	}
	
	return 0;
}