Problem:
Score : 200 points

Problem Statement

Given are a positive integer N and a string S of length N consisting of lowercase English letters.

Determine whether the string is a concatenation of two copies of some string.
That is, determine whether there is a string T such that S = T + T.

Constraints

1 \leq N \leq 100

S consists of lowercase English letters.

|S| = N

Input

Input is given from Standard Input in the following format:

N
S

Output

If S is a concatenation of two copies of some string, print Yes; otherwise, print No.

Sample Input 1

6
abcabc

Sample Output 1

Yes

Let T = abc, and S = T + T.

Sample Input 2

6
abcadc

Sample Output 2

No

Sample Input 3

1
z

Sample Output 3

No

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>

main()
{
    char str[101];
    int len;
    int JudgeNum;

    scanf("%d", &len);
    scanf("%s", &str);

    if(len % 2 == 0)
    {
        printf("No");
    }

    JudgeNum = len / 2;

    for(int i = 0; i < JudgeNum; i++)
    {
        if(str[i + JudgeNum] == str[i])
        {
            printf("No");
        }
    }

    printf("Yes");
}