Problem:
Score : 200 points

Problem Statement

Determine if an N-sided polygon (not necessarily convex) with sides of length L_1, L_2, ..., L_N can be drawn in a two-dimensional plane.

You can use the following theorem:

Theorem: an N-sided polygon satisfying the condition can be drawn if and only if the longest side is strictly shorter than the sum of the lengths of the other N-1 sides.

Constraints

All values in input are integers.

3 \leq N \leq 10

1 \leq L_i \leq 100

Input

Input is given from Standard Input in the following format:

N
L_1 L_2 ... L_N

Output

If an N-sided polygon satisfying the condition can be drawn, print Yes; otherwise, print No.

Sample Input 1

4
3 8 5 1

Sample Output 1

Yes

Since 8 < 9 = 3 + 5 + 1, it follows from the theorem that such a polygon can be drawn on a plane.

Sample Input 2

4
3 8 4 1

Sample Output 2

No

Since 8 \geq 8 = 3 + 4 + 1, it follows from the theorem that such a polygon cannot be drawn on a plane.

Sample Input 3

10
1 8 10 5 8 12 34 100 11 3

Sample Output 3

No

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

#include<stdio.h>
int main()
{
  int n,i,m,s=0;        
  scanf("%d",&n);        
    int ar[n];
   for(i=0;i<n;i++)
   {
    scanf("%d",&ar[i]);       
   } 
   m=ar[0];
   for(i=0;i<n;i++)
   {
   if(ar[i]>m) 
    {
      m=ar[i];            
    }  
   }
   for(i=0;i<n;i++)        
    {        
     s=s+ar[i];   
    } 
   if(s-m>m)         
   { 
            printf("Yes\n");
            
   } 
 
    else         
        {
               printf("No\n");
       }
    
  return 0;        
}