Problem:
Score : 300 points

Problem Statement

Sitting in a station waiting room, Joisino is gazing at her train ticket.

The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).

In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.

The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Constraints

0≤A,B,C,D≤9

All input values are integers.

It is guaranteed that there is a solution.

Input

Input is given from Standard Input in the following format:

ABCD

Output

Print the formula you made, including the part =7.

Use the signs + and -.

Do not print a space between a digit and a sign.

Sample Input 1

1222

Sample Output 1

1+2+2+2=7

This is the only valid solution.

Sample Input 2

0290

Sample Output 2

0-2+9+0=7

0 - 2 + 9 - 0 = 7 is also a valid solution.

Sample Input 3

3242

Sample Output 3

3+2+4-2=7

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

  int main()
{
   char b[4];
   scanf("%s",b);

   int i,a[4];
   for(i=0;i<4;i++)
    {
            if(b[i]=='0') a[i]=0;
            else if(b[i]=='1') a[i]=1;
            else if(b[i]=='2') a[i]=2;
            else if(b[i]=='3') a[i]=3;
            else if(b[i]=='4') a[i]=4;
            else if(b[i]=='5') a[i]=5;
            else if(b[i]=='6') a[i]=6;
            else if(b[i]=='7') a[i]=7;
            else if(b[i]=='8') a[i]=8;
            else if(b[i]=='9') a[i]=9;
    }
    if(a[0]+a[1]+a[2]+a[3]==7) {printf("%d+%d+%d+%d=7",a[0],a[1],a[2],a[3]);return 0;}
    if(a[0]+a[1]+a[2]-a[3]==7) {printf("%d+%d+%d-%d=7",a[0],a[1],a[2],a[3]);return 0;}
    if(a[0]+a[1]-a[2]+a[3]==7) {printf("%d+%d-%d+%d=7",a[0],a[1],a[2],a[3]);return 0;}
    if(a[0]+a[1]-a[2]-a[3]==7) {printf("%d+%d-%d-%d=7",a[0],a[1],a[2],a[3]);return 0;}
    if(a[0]-a[1]+a[2]+a[3]==7) {printf("%d-%d+%d+%d=7",a[0],a[1],a[2],a[3]);return 0;}
    if(a[0]-a[1]+a[2]-a[3]==7) {printf("%d-%d+%d-%d=7",a[0],a[1],a[2],a[3]);return 0;}
    if(a[0]-a[1]-a[2]+a[3]==7) {printf("%d-%d-%d+%d=7",a[0],a[1],a[2],a[3]);return 0;}
    if(a[0]-a[1]-a[2]-a[3]==7) {printf("%d-%d-%d-%d=7",a[0],a[1],a[2],a[3]);return 0;}
    return 0;
}