Problem:
Score : 200 points

Problem Statement

Find the number of palindromic numbers among the integers between A and B (inclusive).
Here, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.

Constraints

10000 \leq A \leq B \leq 99999

All input values are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the number of palindromic numbers among the integers between A and B (inclusive).

Sample Input 1

11009 11332

Sample Output 1

4

There are four integers that satisfy the conditions: 11011, 11111, 11211 and 11311.

Sample Input 2

31415 92653

Sample Output 2

612

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
int main(void)
{
    int A, B;
    int c=0;
    scanf("%d%d", &A, &B);
    for(int i=A;i<=B;i++){
        int n=i;
        int ind=0;
        int x[5]={};
        while(n>0){
            x[ind]=n%10;
            n/=10;
            ind++;
        }
        int res=1;
        for(int j=0;j<(ind-1)/2;j++){
            if(x[j]!=x[ind-1-j]) res=0;
        }
        if(res) c++;
    }
    printf("%d\n",c);
    return 0;
}