Problem:
Score : 100 points

Problem Statement

You have three tasks, all of which need to be completed.

First, you can complete any one task at cost 0.

Then, just after completing the i-th task, you can complete the j-th task at cost |A_j - A_i|.

Here, |x| denotes the absolute value of x.

Find the minimum total cost required to complete all the task.

Constraints

All values in input are integers.

1 \leq A_1, A_2, A_3 \leq 100

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

Print the minimum total cost required to complete all the task.

Sample Input 1

1 6 3

Sample Output 1

5

When the tasks are completed in the following order, the total cost will be 5, which is the minimum:

Complete the first task at cost 0.

Complete the third task at cost 2.

Complete the second task at cost 3.

Sample Input 2

11 5 5

Sample Output 2

6

Sample Input 3

100 100 100

Sample Output 3

0

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
int main()
{
    int A1,A2,A3,x,y,z;
    scanf("%d%d%d",&A1,&A2,&A3);
    if(A1>A2&&A1>A3)
    {
        z=A1;
        if(A2>A3){
            y=A2;
            x=A3;
        }
        else
        {
            y=A3;
            x=A2;
        }
    }
       else if(A2>A1&&A2>A3)
    {
        z=A2;
        if(A1>A3){
            y=A1;
            x=A3;
        }
        else
        {
            y=A3;
            x=A1;
        }
    }
    else
    {
        z=A3;
        if(A1>A2){
            y=A1;
            x=A2;
        }
        else
        {
            y=A2;
            x=A1;
        }
    }

    printf("%d\n",z-x);
    return 0;
}