Problem:
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Matrix Multiplication

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\[
c_{ij} = \sum_{k=1}^m a_{ik}b_{kj}
\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Constraints

$1 \leq n, m, l \leq 100$

$0 \leq a_{ij}, b_{ij} \leq 10000$

Sample Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2

Sample Output

1 8 5
0 9 6
4 23 14

Note

      解説

Solution in C (judge verdict: Wrong Answer)

#include<stdio.h>

int mata[100][100],matb[100][100];

int main(void){
    int n,m,l,i,j,k,sum;

    scanf("%d %d %d",&n,&m,&l);

    for(i = 0;i < n;i++)
        for(j = 0;j < m;j++)
            scanf("%d",&mata[i][j]);

    for(i = 0;i < m;i++)
        for(j = 0;j < l;j++)
            scanf("%d",&matb[i][j]);

    for(i = 0;i < n;i++){
        for(j = 0;j < l;j++){
            sum = 0;
            for(k = 0;k < m;k++){
                sum += mata[i][k] * matb[k][j];
            }
            printf("%d",sum);
            if(j < l - 1)
                printf(" ");
        }
        printf("\n");
    }
    return 0;
}