Problem:
Score : 200 points

Problem Statement

The word internationalization is sometimes abbreviated to i18n.
This comes from the fact that there are 18 letters between the first i and the last n.

You are given a string s of length at least 3 consisting of lowercase English letters.
Abbreviate s in the same way.

Constraints

3 ≤ |s| ≤ 100 (|s| denotes the length of s.)

s consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s

Output

Print the abbreviation of s.

Sample Input 1

internationalization

Sample Output 1

i18n

Sample Input 2

smiles

Sample Output 2

s4s

Sample Input 3

xyz

Sample Output 3

x1z

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

/*      ex6_2
        Tarara  */
#include <stdio.h>
#include <string.h>

// 入力の最大長
#define MAX_LENGTH 110

int main(void)
{
    char word[MAX_LENGTH]; // 入力される英単語
    int length;            // wordの長さ

    // 入力
    scanf("%s", word);
    length = strlen(word);

    // 出力
    printf("%c%d%c\n", word[0], length - 2, word[length - 1]);
    return 0;
}