Problem:
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Matrix Multiplication

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\[
c_{ij} = \sum_{k=1}^m a_{ik}b_{kj}
\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Constraints

$1 \leq n, m, l \leq 100$

$0 \leq a_{ij}, b_{ij} \leq 10000$

Sample Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2

Sample Output

1 8 5
0 9 6
4 23 14

Note

      解説

Solution in C (judge verdict: Accepted)

#include<stdio.h>

int main()
{
  int n,m,l,i,j,k;
  double sum;
  scanf("%d %d %d",&n,&m,&l);
  int a[n][m],b[m][l];
  double out[n][l];
  for(i=0;i<n;i++)
    for(j=0;j<m;j++)
      scanf("%d",&a[i][j]);

  for(i=0;i<m;i++)
    for(j=0;j<l;j++)
      scanf("%d",&b[i][j]);

  sum=0;

  for(i=0;i<n;i++){
    for(j=0;j<l;j++){
        for(k=0;k<m;k++)  sum+=(double)a[i][k]*b[k][j];

        out[i][j]=sum;
        sum=0;
    }
  }
  for(i=0;i<n;i++){
    for(j=0;j<l;j++) {
      printf("%.0lf",out[i][j]);
      if(j<l-1) printf(" ");
    }
    printf("\n");
  }

  return 0;

}