Problem:
Score : 200 points

Problem Statement

There are N rabbits, numbered 1 through N.

The i-th (1≤i≤N) rabbit likes rabbit a_i.
Note that no rabbit can like itself, that is, a_i≠i.

For a pair of rabbits i and j (i＜j), we call the pair (i，j) a friendly pair if the following condition is met.

Rabbit i likes rabbit j and rabbit j likes rabbit i.

Calculate the number of the friendly pairs.

Constraints

2≤N≤10^5

1≤a_i≤N

a_i≠i

Input

The input is given from Standard Input in the following format:

N
a_1 a_2 ... a_N

Output

Print the number of the friendly pairs.

Sample Input 1

4
2 1 4 3

Sample Output 1

2

There are two friendly pairs: (1，2) and (3，4).

Sample Input 2

3
2 3 1

Sample Output 2

0

There are no friendly pairs.

Sample Input 3

5
5 5 5 5 1

Sample Output 3

1

There is one friendly pair: (1，5).

Solution in C (GCC 5.4.1) (judge verdict: Time Limit Exceeded)

#include <stdio.h>

int main(void) {
	int n;
	scanf("%d", &n);
	
	int a[n + 1];
	int ans = 0;
	int count = 0;
	
	for(int i = 1; i < n + 1; i++){
		scanf("%d",&a[i]);
	}
	
	for(int i = 1; i < n + 1; i++){
		for(int j = 1; j < n + 1; j++){
			if(a[i] == j && a[j] == i){
				count++;
			}
		}
	}
	ans = count/2;
	
	printf("%d\n", ans);
	
	return 0;
}