Problem:
Score : 100 points

Problem Statement

AtCoDeer has three cards, one red, one green and one blue.

An integer between 1 and 9 (inclusive) is written on each card: r on the red card, g on the green card and b on the blue card.

We will arrange the cards in the order red, green and blue from left to right, and read them as a three-digit integer.

Is this integer a multiple of 4?

Constraints

1 ≤ r, g, b ≤ 9

Input

Input is given from Standard Input in the following format:

r g b

Output

If the three-digit integer is a multiple of 4, print YES (case-sensitive); otherwise, print NO.

Sample Input 1

4 3 2

Sample Output 1

YES

432 is a multiple of 4, and thus YES should be printed.

Sample Input 2

2 3 4

Sample Output 2

NO

234 is not a multiple of 4, and thus NO should be printed.

Solution in C (Clang 3.8.0) (judge verdict: Wrong Answer)

#include <stdio.h>
int main(void){
	int max = 0;
	int min = 0;
	int choose = 0;
	int color[8] = {0, 0, 0, 0, 0, 0, 0, 0};
	int n;
	scanf("%d", &n);
	int rate[n];
	for(int i = 0; i < n; i++){
		scanf("%d", rate+i);
	}
	for(int i = 0; i < n; i++){
		if(rate[i] < 400){
			color[0]++;
		}
		else if(rate[i] < 800){
			color[1]++;
		}
		else if(rate[i] < 1200){
			color[2]++;
		}
		else if(rate[i] < 1600){
			color[3]++;
		}
		else if(rate[i] < 2000){
			color[4]++;
		}
		else if(rate[i] < 2400){
			color[5]++;
		}
		else if(rate[i] < 2800){
			color[6]++;
		}
		else if(rate[i] < 3200){
			color[7]++;
		}
		else{
			choose++;
		}
	}
#ifdef DEBUG
for(int i = 0; i < 8; i++){
printf("color[%d] %d\n", i, color[i]);
}
#endif
	for(int i = 0; i < 8; i++){
		if(color[i] > 0){
			max++;
			min++;
		}
	}
	max += choose;
	printf("%d %d\n", min, max);
	return 0;
}