Problem:
Score : 200 points

Problem Statement

In Japan, people make offerings called hina arare, colorful crackers, on March 3.

We have a bag that contains N hina arare. (From here, we call them arare.)

It is known that the bag either contains arare in three colors: pink, white and green, or contains arare in four colors: pink, white, green and yellow.

We have taken out the arare in the bag one by one, and the color of the i-th arare was S_i, where colors are represented as follows - pink: P, white: W, green: G, yellow: Y.

If the number of colors of the arare in the bag was three, print Three; if the number of colors was four, print Four.

Constraints

1 \leq N \leq 100

S_i is P, W, G or Y.

There always exist i, j and k such that S_i=P, S_j=W and S_k=G.

Input

Input is given from Standard Input in the following format:

N
S_1 S_2 ... S_N

Output

If the number of colors of the arare in the bag was three, print Three; if the number of colors was four, print Four.

Sample Input 1

6
G W Y P Y W

Sample Output 1

Four

The bag contained arare in four colors, so you should print Four.

Sample Input 2

9
G W W G P W P G G

Sample Output 2

Three

The bag contained arare in three colors, so you should print Three.

Sample Input 3

8
P Y W G Y W Y Y

Sample Output 3

Four

Solution in C (Clang 3.8.0) (judge verdict: Accepted)

#include<stdio.h>
#include<string.h>

int main(){
char s[100];
int i;
int n;
int a=0,b=0,c=0,g=0;
scanf("%d",&n);

	for(i=0;i<n;i++){
	scanf("%*c%c",&s[i]);
	}
	
//printf("%s\n",s);
for(i=0;i<n;i++){
	/*if(s[i]=='P'){
		a++;
		
	}else
	if(s[i]=='W'){
		b++;
	}else
	if(s[i]=='G'){
		
		c++;
	}else*/
	if(s[i]=='Y'){
		g++;
		
	}
	
	
	
	
}
//printf("%d%d%d%d\n",a,b,c,g);
if(g>0){
	printf("Four\n");
	
}else{
	printf("Three\n");
	
}
	return 0;
}