Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
int main()
{
    long long n,w1,w2,j,h;
    int f;
    while(~scanf("%lld",&n))
    {
        f=0;
     for(h=1;h<=3500;h++)
       { for(j=1;j<=3500;j++)

       {

        w1=n*h*j;
        w2=4*h*j-n*h-n*j;
        if(w1>0&&w2>0&&w1%w2==0)
          {

           printf("%lld %lld %lld\n",h,j,w1/w2);
                f=1;}
       if(f)
                break;

    }
    if(f)
        break;
}
 }
return 0;
}