Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in C (GCC 5.4.1) (judge verdict: Runtime Error)


#include <stdio.h>

int main()
{   long long n;
    scanf("%lld",&n);
    if(n%2==0){
        printf("%lld %lld %lld",n,n,n/2);
        return 0;
    }
    for(long long i=1;i<=3500;i++){
        for(long long j=1;j<=3500;j++){
            if(n*i*j%(4*i*j-n*i-n*j)==0&&n*i*j/(4*i*j-n*i-n*j)>0&&(4*i*j-n*i-n*j)>0){
                printf("%lld %lld %lld",i,j,n*i*j/(4*i*j-n*i-n*j));
                return 0;
            }
        }
    }

    return 0;
}