Problem:
Score : 300 points

Problem Statement

You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

1 \leq |S| \leq 2 \times 10^5

|S| = |T|

S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S and T can be made equal, print Yes; otherwise, print No.

Sample Input 1

azzel
apple

Sample Output 1

Yes

azzel can be changed to apple, as follows:

Choose e as c_1 and l as c_2. azzel becomes azzle.

Choose z as c_1 and p as c_2. azzle becomes apple.

Sample Input 2

chokudai
redcoder

Sample Output 2

No

No sequences of operation can change chokudai to redcoder.

Sample Input 3

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu

Sample Output 3

Yes

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
#include<string.h>
#define MYSTRINGMAX 20000
#define SIZE 100

int main(void) {
	char s[MYSTRINGMAX + 1], t[MYSTRINGMAX + 1], c1, c2;
	int flag = 0, i, j;
	fgets(s, SIZE, stdin);
	fgets(t, SIZE, stdin);
	int length = strlen(s);
	for (i = 0; i < length; i++) {
		if (s[i] != t[i]) {
			c1 = s[i];
			c2 = t[i];
			for (j = 0; j < length; j++) {
				if (s[j] == c2 || s[j] == c1) {
					if (j < i) {
						flag = 1;
						break;
					}
					if (s[j] == c1) {
						s[j] = c2;
					}
					else {
						s[j] = c1;
					}
				}
			}
			if (flag == 1) {
				printf("No\n");
				return 0;
			}
		}
		if (flag == 1) {
			printf("No\n");
			return 0;
		}
	}
	printf("Yes\n");
	return 0;
}