Problem:
Score : 300 points

Problem Statement

You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

1 \leq |S| \leq 2 \times 10^5

|S| = |T|

S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S and T can be made equal, print Yes; otherwise, print No.

Sample Input 1

azzel
apple

Sample Output 1

Yes

azzel can be changed to apple, as follows:

Choose e as c_1 and l as c_2. azzel becomes azzle.

Choose z as c_1 and p as c_2. azzle becomes apple.

Sample Input 2

chokudai
redcoder

Sample Output 2

No

No sequences of operation can change chokudai to redcoder.

Sample Input 3

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu

Sample Output 3

Yes

Solution in C (GCC 5.4.1) (judge verdict: Runtime Error)

#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <string.h>

int main(){
int i, j, n;
int len;
int wrong = 0;
char a[200000];
char b[200000];
int c[200000] = {};
int d[200000] = {};
int seno[128] = {};
int tno[128] = {};

scanf("%s", &a);
scanf("%s", &b);

len = strlen(a);
//len = 200000;
for(i = 0; i<len;i++){
  seno[(a[i])-'a']++;
  tno[(b[i])-'a']++;
}

for(i = 0;i < 128; i++){
  c[seno[i]]++;
  d[tno[i]]++;
}

for(i = 0; i < len; i++){
  if(c[i] != d[i]) wrong++;
}
if(wrong == 0){
  printf("Yes\n");
}else{
  printf("No\n");
}


  return 0;
}