Problem:
Score : 200 points

Problem Statement

The word internationalization is sometimes abbreviated to i18n.
This comes from the fact that there are 18 letters between the first i and the last n.

You are given a string s of length at least 3 consisting of lowercase English letters.
Abbreviate s in the same way.

Constraints

3 ≤ |s| ≤ 100 (|s| denotes the length of s.)

s consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s

Output

Print the abbreviation of s.

Sample Input 1

internationalization

Sample Output 1

i18n

Sample Input 2

smiles

Sample Output 2

s4s

Sample Input 3

xyz

Sample Output 3

x1z

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

/*  ex6_2
    Rikuta  */

#include <stdio.h>
#include <string.h>
#define LIM 101
int main(void){
    char word[LIM];
    fgets(word,LIM,stdin);
    for (int i = 0; i < LIM; i++)
    {
        if (word[i]=='\n')
        {
            word[i]='\0';
        }
        
    }
    
    printf("%c%d%c\n",word[0],(int)strlen(word)-2,word[strlen(word)-1]);
    return 0;
}