Problem:
Score : 200 points

Problem Statement

The word internationalization is sometimes abbreviated to i18n.
This comes from the fact that there are 18 letters between the first i and the last n.

You are given a string s of length at least 3 consisting of lowercase English letters.
Abbreviate s in the same way.

Constraints

3 ≤ |s| ≤ 100 (|s| denotes the length of s.)

s consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s

Output

Print the abbreviation of s.

Sample Input 1

internationalization

Sample Output 1

i18n

Sample Input 2

smiles

Sample Output 2

s4s

Sample Input 3

xyz

Sample Output 3

x1z

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
#include<string.h>
void mozi_sort(char str[], int length) {
	int tmp[10000] = {};
	int memo = 0;
	for (int i = 0; i < length; i++) {
		tmp[(int)str[i]]++;
	}
	for (int i = 0; i < 256; i++) {
		while (tmp[i] > 0) {
			str[memo] = (char)i;
			memo++;
			tmp[i]--;
		}
	}
}
//大小比較(小)
long long int small(long long int a, long long int b) {
	if (a >= b) {
		return b;
	}
	else {
		return a;
	}
}
int main() {
	long long int a, b, c, d, n, m, num[2000][2] = {}, result = 0;
	char str[200005];
	scanf("%s", str);
	printf("%c%d%c", str[0], strlen(str)-2, str[strlen(str)-1]);
			
}