Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>

int main()
{
   int N, n, i, count, a;

   if(scanf("%d", &N)!=1) return 0;
   if(N<1||N>200) return 0;
   
   for(n=1;n<=N;n+=2){
      count=0;
      for(i=1;i<=N;++i){
         if(N%i==0) ++count;
      }
      if(count==8) ++a;
   }
   printf("%d", a);

   return 0;
}