Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in C (Clang 10.0.0) (judge verdict: Wrong Answer)

#include<stdio.h>
int main(){
int A[3][3]={};
int B[101]={};
int i,j,N,num,BOOL=0;
for(i=1;i<=3;i++){
  for(j=1;j<=3;j++){
scanf("%d",&A[i][j]);    
  }
}
scanf("%d",&N);
   for(i=1;i<=N;i++){
scanf("%d",&B[i]);    
  }
 for(num=1;num<=N;num++) 
 {for(i=1;i<=3;i++)
  {for(j=1;j<=3;j++)
   {
    if(A[i][j]==B[num]){A[i][j]=0;}
   }
  }
 }
 
  if(A[1][1]==0&&A[2][1]==0&&A[3][1]==0){BOOL=1;}
  if(A[1][2]==0&&A[2][2]==0&&A[3][2]==0){BOOL=1;}
  if(A[1][3]==0&&A[2][3]==0&&A[3][3]==0){BOOL=1;}
  if(A[1][1]==0&&A[1][2]==0&&A[1][3]==0){BOOL=1;}
  if(A[2][1]==0&&A[2][2]==0&&A[2][3]==0){BOOL=1;}
  if(A[3][1]==0&&A[3][2]==0&&A[3][3]==0){BOOL=1;}
  if(A[1][1]==0&&A[2][2]==0&&A[3][3]==0){BOOL=1;}
  if(A[1][3]==0&&A[2][2]==0&&A[3][1]==0){BOOL=1;}
  if(BOOL==1){printf("Yes");}
  else printf("No");
return 0;
}