Problem:
Score : 300 points

Problem Statement

Sitting in a station waiting room, Joisino is gazing at her train ticket.

The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).

In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.

The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Constraints

0≤A,B,C,D≤9

All input values are integers.

It is guaranteed that there is a solution.

Input

Input is given from Standard Input in the following format:

ABCD

Output

Print the formula you made, including the part =7.

Use the signs + and -.

Do not print a space between a digit and a sign.

Sample Input 1

1222

Sample Output 1

1+2+2+2=7

This is the only valid solution.

Sample Input 2

0290

Sample Output 2

0-2+9+0=7

0 - 2 + 9 - 0 = 7 is also a valid solution.

Sample Input 3

3242

Sample Output 3

3+2+4-2=7

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
#include <stdlib.h>
#include <string.h>
 
 
 
int main()
{
 
    int  N;
    int  N0, N1,N2,N3;
   int f0=0,f1=0,f2=0;
   int ans[8];
   char op0,op1,op2;
   int flag;
  int i;
  // 整数の入力
    scanf("%d", &N);
     N0 = N % 10;
     N1 = (N/10 % 10);
     N2 = (N/100)% 10;
     N3 = N/1000;
 
   ans[0]=N3+N2+N1+N0;
   ans[1]=N3+N2+N1-N0;
   ans[2]=N3+N2-N1+N0;
   ans[3]=N3-N2+N1+N0;
   ans[4]=N3+N2-N1-N0;
   ans[5]=N3-N2-N1+N0;
   ans[6]=N3-N2+N1-N0;
   ans[7]=N3-N2-N1-N0;
  
   for(i=0;i<7;i++)
   {
     if(7 == ans[i]){
       flag = i;
       break;
     }
   }
        printf("%d\n",flag);
  switch (flag) {
	case 0:
		op0='+';
		op1='+';
		op2='+';
        break;
	case 1:
		op0='+';
		op1='+';
		op2='-';
        break;
	case 2:
		op0='+';
		op1='-';
		op2='+';
        break;
	case 3:
		op0='-';
		op1='+';
		op2='+';
        break;
	case 4:
		op0='+';
		op1='-';
		op2='-';
        break;
	case 5:
		op0='-';
		op1='-';
		op2='+';
        break;
	case 6:
		op0='-';
		op1='+';
		op2='-';
        break;
    case 7:
		op0='-';
		op1='-';
		op2='-';
        break;
	default:
		//printf("others\n");
		break;
}
  
     printf("%d%c%d%c%d%c%d=7\n",N3,op0,N2,op1,N1,op2,N0);
//   if ((f0&f1)||(f1&f2)){
//     printf("Yes\n");
//  }else {
//printf("No\n");
//}
    return 0;
}