Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in C (Clang 3.8.0) (judge verdict: Wrong Answer)

#include <stdio.h>
int main(void) {
  int N, A, B, C, D, a, p, i;
  p=1;
  char str[200005];
  scanf("%d %d %d %d %d", &N, &A, &B, &C, &D);
  scanf("%s", str);
  if (C<D) {
    a=0;
    for (i=B-1; i<=D-1; i++) {
      if (str[i] == '#') a++;
      else a=0;
      if(a>=2) {
        p=0;
        break;
      }
    }
    a=0;
    for (i=A-1; i<=C-1; i++) {
      if (str[i] == '#') a++;
      else a=0;
      if(a>=2 || p==0) {
        p=0;
        break;
      }
    }
  }
  else {
    a=0;
    for (i=B-1; i<=D-1; i++) {
      if (str[i] == '.') a++;
      else a=0;
      if(a>=3) {
        break;
      }
    }
    if (a<=1) {
        p=0;
    }
    a=0;
    for (i=B-1; i<=D-1; i++) {
      if (str[i] == '#') a++;
      else a=0;
      if(a>=2 || p==0) {
        p=0;
        break;
      }
    }
    a=0;
    for (i=A-1; i<=C-1; i++) {
      if (str[i] == '#') a++;
      else a=0;
      if(a>=2 || p==0) {
        p=0;
        break;
      }
    }
  }
  if (p==1) printf("Yes");
  else printf("No");
  return 0;
}