Problem:
Score : 300 points

Problem Statement

Takahashi is a teacher responsible for a class of N students.

The students are given distinct student numbers from 1 to N.

Today, all the students entered the classroom at different times.

According to Takahashi's record, there were A_i students in the classroom when student number i entered the classroom (including student number i).

From these records, reconstruct the order in which the students entered the classroom.

Constraints

1 \le N \le 10^5

1 \le A_i \le N

A_i \neq A_j (i \neq j)

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 \ldots A_N

Output

Print the student numbers of the students in the order the students entered the classroom.

Sample Input 1

3
2 3 1

Sample Output 1

3 1 2

First, student number 3 entered the classroom.

Then, student number 1 entered the classroom.

Finally, student number 2 entered the classroom.

Sample Input 2

5
1 2 3 4 5

Sample Output 2

1 2 3 4 5

Sample Input 3

8
8 2 7 3 4 5 6 1

Sample Output 3

8 2 4 5 6 7 3 1

Solution in C (GCC 5.4.1) (judge verdict: Runtime Error)

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<math.h>

#define num_max(p,q)((p)>(q)?(p):(q))
#define num_min(p,q)((p)<(q)?(p):(q))
int cmp(const void *a, const void *b)
{
	return *(int*)a - *(int*)b;//昇順
	 //降順ならreturn *(int*)b - *(int*)a;
}
int main()
{
	int N,i;
	scanf("%d", &N);
	int(*A) = (int(*))malloc(N * sizeof(int));
	int(*B) = (int(*))malloc(N * sizeof(int));
	
	for (i = 1;i <= N;i++)
	{
		scanf("%d", &A[i]);
		B[A[i]] = i;
	}
	for (i = 1;i <= N;i++)printf("%d ", B[i]);
	free(A);
	free(B);
	return 0;
}