Problem:
Score : 200 points

Problem Statement

It is only six months until Christmas, and AtCoDeer the reindeer is now planning his travel to deliver gifts.

There are N houses along TopCoDeer street. The i-th house is located at coordinate a_i. He has decided to deliver gifts to all these houses.

Find the minimum distance to be traveled when AtCoDeer can start and end his travel at any positions.

Constraints

1 ≤ N ≤ 100

0 ≤ a_i ≤ 1000

a_i is an integer.

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 ... a_N

Output

Print the minimum distance to be traveled.

Sample Input 1

4
2 3 7 9

Sample Output 1

7

The travel distance of 7 can be achieved by starting at coordinate 9 and traveling straight to coordinate 2.

It is not possible to do with a travel distance of less than 7, and thus 7 is the minimum distance to be traveled.

Sample Input 2

8
3 1 4 1 5 9 2 6

Sample Output 2

8

There may be more than one house at a position.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
int minx(int v[],int n){
	int i,j,k,tmp;
	tmp=v[0];
	for(i=1;i<=n-1;i++){
		if(tmp>v[i])
		tmp=v[i];}
		return tmp;}
int maxx(int v[],int n){
	int i,j,k,tmp;
	tmp=v[0];
	for(i=1;i<=n-1;i++){
		if(tmp<v[i])
		tmp=v[i];}
		return tmp;}
int abs(int n){
		if(n<0){
		return -1*n;}else
		return n;}
int max(int n1,int n2,int n3){
	int tmp;
	tmp=n1;
	if(n2>tmp)
	tmp=n2;
	if(n3>tmp)
	tmp=n3;
	return tmp;}
int min3(int n1,int n2,int n3){
	int tmp;
	tmp=n1;
	if(n2<tmp)
	tmp=n2;
	if(n3<tmp)
	tmp=n3;
	return tmp;}
int main(void)
{int N,A,M,B,j,x,i,k,H,W,l,sum,m,mint,flag;
	scanf("%d",&N);
	int a[100];
	int t[100];
	flag=0;
	sum=0;
	for(i=0;i<=N-1;i++){
		scanf("%d",&a[i]);}
	printf("%d",maxx(a,N)-minx(a,N));



	return 0;
}