Problem:
Score : 400 points

Problem Statement

We have a sequence of length N, a = (a_1, a_2, ..., a_N).
Each a_i is a positive integer.

Snuke's objective is to permute the element in a so that the following condition is satisfied:

For each 1 ≤ i ≤ N - 1, the product of a_i and a_{i + 1} is a multiple of 4.

Determine whether Snuke can achieve his objective.

Constraints

2 ≤ N ≤ 10^5

a_i is an integer.

1 ≤ a_i ≤ 10^9

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 ... a_N

Output

If Snuke can achieve his objective, print Yes; otherwise, print No.

Sample Input 1

3
1 10 100

Sample Output 1

Yes

One solution is (1, 100, 10).

Sample Input 2

4
1 2 3 4

Sample Output 2

No

It is impossible to permute a so that the condition is satisfied.

Sample Input 3

3
1 4 1

Sample Output 3

Yes

The condition is already satisfied initially.

Sample Input 4

2
1 1

Sample Output 4

No

Sample Input 5

6
2 7 1 8 2 8

Sample Output 5

Yes

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>

int main(void) {
	// your code goes here
	int n,i,count=0,odd=0,two=0;
	scanf("%d",&n);
	int *a = (int*)malloc(sizeof(int)*n);
	for(i =0;i<n;i++)
	{
		scanf("%d",&a[i]);
		if(a[i]%4==0)
			count++;
		else if(a[i]%2==0)
			two++;
		else
			odd++;
	}
//	printf("%d %d %d\n",count,two,odd);
	if(two==0&&odd<=count+1)
		printf("Yes");
	else if(two!=0)
	{
		two = two/2 +two%2;
		odd+=two;
//			printf("%d %d %d",count,two,odd);
		if(odd<=count)
			printf("Yes");
		else 
		printf("No");
			
	}
	else
		printf("No");
		
	
	return 0;
}