Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>

int main(void){
  int n;
  int a;
  int b;
  int c;
  int d;
  scanf("%d", &n);
  scanf("%d", &a);
  scanf("%d", &b);
  scanf("%d", &c);
  scanf("%d", &d);
  char road[n];
  scanf("%s", road);
  int i;
  if(c<d){
    int count = 0;
    int rockcount;
    for(i=0;i<n;i++){
      if(road[i]=='.'){
        rockcount = 0;
        count++;
      }else{
        rockcount++;
        count = 0;
      }
      if(rockcount==2){
        printf("No");
        return 0;
      }
    }
    printf("Yes");
    return 0;
  }else{
    int count = 0;
    int rockcount;
    int three[n];
    int threeidx = 0;
    for(i=0;i<n;i++){
      //printf("ループ:%d\n",i);
      //printf("カウント:%d\n",count);
      if(road[i]=='.'){
        rockcount = 0;
        count++;
      }else if(i==b-1){
        if(count == 1){
          count++;
        }
      }else{
        rockcount++;
        count = 0;
      }
      if(rockcount == 2){
        printf("禁止！！:%d",i);
        if(i-1<=c||i-1<=d){
          printf("No");
          return 0;
        }
      }
      if(count == 3&&i-1<d-1){
        three[threeidx] = i;
        threeidx++;
        //printf("ここは三点連続idx:%d\n",i);
        count = 0;
        rockcount = 0;
        i = i - 2;
      }
    }
    for(i=0;i<threeidx;i++){
      //printf("%d番目は%d", i, three[i]);
      if(b-1<three[i]&&three[i]<=c-1){
        printf("Yes");
        return 0;
      }
    }
    printf("No");
    return 0;
  }
}