Problem:
Hit and Blow

Let's play Hit and Blow game. A imagines four numbers and B guesses the numbers. After B picks out four numbers, A answers:

The number of numbers which have the same place with numbers A imagined (Hit)

The number of numbers included (but different place) in the numbers A imagined (Blow)

For example, if A imagined numbers:

9 1 8 2

and B chose:

4 1 5 9

A should say 1 Hit and 1 Blow.

Write a program which reads four numbers A imagined and four numbers B chose and prints the number of Hit and Blow respectively. You may assume that the four numbers are all different and within from 0 to 9.

Input

The input consists of multiple datasets. Each dataset set consists of:

a1 a2 a3 a4
b1 b2 b3 b4

, where ai (0 ≤ ai ≤ 9) is i-th number A imagined and bi (0 ≤ bi ≤ 9) is i-th number B chose.

The input ends with EOF. The number of datasets is less than or equal to 50.

Output

For each dataset, print the number of Hit and Blow in a line. These two numbers should be separated by a space.

Sample Input

9 1 8 2
4 1 5 9
4 6 8 2
4 6 3 2

Output for the Sample Input

1 1
3 0

Solution in C (judge verdict: Time Limit Exceeded)

#include<stdio.h>

int main(){
	int i,j,a,b;
	while(1){
	int A[4]={},B[4]={},hit=0,brow=0,x[4]={};
	for(i=0;i<4;i++){
	scanf("%d",&a);
	A[i]=a;
	}
	for(i=0;i<4;i++){
	scanf("%d",&b);
	B[i]=b;
	}
	hit=0;
		for(i=0;i<4;i++){
			if(A[i]==B[i]){
		hit=hit+1;
		x[i]=1;
	}
	}
	brow=0;
		for(i=0;i<4;i++){
		for(j=0;j<4;j++){
			if(A[i]==B[j] && x[i]!=1){
			brow=brow+1;
	}
	}
	}
	printf("%d %d\n",hit,brow);
	}
	return 0;
}