Problem:
Score : 400 points

Problem Statement

Akari has n kinds of flowers, one of each kind.

She is going to choose one or more of these flowers to make a bouquet.

However, she hates two numbers a and b, so the number of flowers in the bouquet cannot be a or b.

How many different bouquets are there that Akari can make?

Find the count modulo (10^9 + 7).

Here, two bouquets are considered different when there is a flower that is used in one of the bouquets but not in the other bouquet.

Constraints

All values in input are integers.

2 \leq n \leq 10^9

1 \leq a < b \leq \textrm{min}(n, 2 \times 10^5)

Input

Input is given from Standard Input in the following format:

n a b

Output

Print the number of bouquets that Akari can make, modulo (10^9 + 7). (If there are no such bouquets, print 0.)

Sample Input 1

4 1 3

Sample Output 1

7

In this case, Akari can choose 2 or 4 flowers to make the bouquet.

There are 6 ways to choose 2 out of the 4 flowers, and 1 way to choose 4, so there are a total of 7 different bouquets that Akari can make.

Sample Input 2

1000000000 141421 173205

Sample Output 2

34076506

Print the count modulo (10^9 + 7).

Solution in C (GCC 5.4.1) (judge verdict: Runtime Error)

#include<stdio.h>
typedef long long int lli;
lli ncr(lli n,lli r){
  	if(r==0||r==n){
        return 1;
    }
    return ncr(n-1,r) + ncr(n-1,r-1);
}
int main(int argc,char* argv){
lli n,a,b;
  scanf("%lld %lld %lld",&n,&a,&b);
    lli res=0;
  for(int i=1;i<=n;i++){
  		if(ncr(n,i)!=ncr(n,a)&&ncr(n,i)!=ncr(n,b)){
    		res += ncr(n,i);
        }
  	}
    printf("%lld",res);
    return 0;
}