Problem:
Score : 200 points

Problem Statement

You are given a string S of length N consisting of lowercase English letters, and an integer K.
Print the string obtained by replacing every character in S that differs from the K-th character of S, with *.

Constraints

1 \leq K \leq N\leq 10

S is a string of length N consisting of lowercase English letters.

N and K are integers.

Input

Input is given from Standard Input in the following format:

N
S
K

Output

Print the string obtained by replacing every character in S that differs from the K-th character of S, with *.

Sample Input 1

5
error
2

Sample Output 1

*rr*r

The second character of S is r. When we replace every character in error that differs from r with *, we get the string *rr*r.

Sample Input 2

6
eleven
5

Sample Output 2

e*e*e*

Sample Input 3

9
education
7

Sample Output 3

******i**

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
#include <stdint.h>

int getNumsInt32(int32_t *buf, int32_t num)
{
  int32_t i;

  for (i = 0; i < num; i++) {
    if (scanf("%d", &buf[i]) == EOF) {
      return -1;
    }
  }
  return 0;
}

int main()
{
  int32_t K, N, i;
  char s[10 + 1];

  if (getNumsInt32((int32_t *)&N, (int32_t)1) == -1) {
    return -1;
  }

  if (scanf("%s", s) == EOF) {
    return -1;
  }

  if (getNumsInt32((int32_t *)&K, (int32_t)1) == -1) {
    return -1;
  }
  
  for (i = 0; i < N; i++) {
    if (s[i] != s[K - 1]) {
      s[i] = '*';
    }
  }

  printf("%s\n", s);

  return 0;
}