Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in C (judge verdict: Time Limit Exceeded)

#include <stdio.h>
#include <string.h>

int main(void)
{	
	char s[1201];
	int moji[128]={0};
	int i;
	int flag =0;
	

	while(!flag){
		scanf("%s", s);
		i=0;
		while(1){
			if(s[i] == '.'){
				flag = 1;
				break;
			}
			if(s[i] == '\0')
				break;
			if(s[i]>='A' && s[i] <='Z')
				moji[s[i]-'A'] ++;
			else if(s[i]>='a' && s[i] <='z')
				moji[s[i]-'a'] ++;
			i++;
		}
	}
	for(i=0; i<26; i++){
		printf("%c : %d\n", i+'a', moji[i]);
	}
	return 0;
}