Problem:
Score : 200 points

Problem Statement

Given are integers a,b,c and d.
If x and y are integers and a \leq x \leq b and c\leq y \leq d hold, what is the maximum possible value of x \times y?

Constraints

-10^9 \leq a \leq b \leq 10^9

-10^9 \leq c \leq d \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

a b c d

Output

Print the answer.

Sample Input 1

1 2 1 1

Sample Output 1

2

If x = 1 and y = 1 then x \times y = 1.
If x = 2 and y = 1 then x \times y = 2.
Therefore, the answer is 2.

Sample Input 2

3 5 -4 -2

Sample Output 2

-6

The answer can be negative.

Sample Input 3

-1000000000 0 -1000000000 0

Sample Output 3

1000000000000000000

Solution in C (GCC 9.2.1) (judge verdict: Wrong Answer)

#include<stdio.h>
#include<limits.h>

int main(void){
  int a,b,c,d;
  scanf("%d%d%d%d",&a,&b,&c,&d);
    long long int ans1,ans2,ans3,ans4,ans;
    ans1=a*c;
    ans2=a*d;
    ans3=b*c;
    ans4=b*d;
    ans=LLONG_MIN;
    if(ans1>ans)ans=ans1;
    if(ans2>ans)ans=ans2;
    if(ans3>ans)ans=ans3;
    if(ans4>ans)ans=ans4;

    printf("%lld",ans);



  return 0;
}