Problem:
Score : 200 points

Problem Statement

A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.

How many times will the ball make a bounce where the coordinate is at most X?

Constraints

1 \leq N \leq 100

1 \leq L_i \leq 100

1 \leq X \leq 10000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N X
L_1 L_2 ... L_{N-1} L_N

Output

Print the number of times the ball will make a bounce where the coordinate is at most X.

Sample Input 1

3 6
3 4 5

Sample Output 1

2

The ball will make a bounce at the coordinates 0, 3, 7 and 12, among which two are less than or equal to 6.

Sample Input 2

4 9
3 3 3 3

Sample Output 2

4

The ball will make a bounce at the coordinates 0, 3, 6, 9 and 12, among which four are less than or equal to 9.

Solution in C (Clang 3.8.0) (judge verdict: Accepted)

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main(void){
  int N,X,i,l[105],count,dis,k;
  char str[1000],*p;
  
  fgets(str,sizeof(str),stdin);
  p=strtok(str," \n");
  N=atoi(p);
  p=strtok(NULL," \n");
  X=atoi(p);
  
  l[0]=0;
  fgets(str,sizeof(str),stdin);
  p=strtok(str," \n");
  l[1]=atoi(p);
  
  for(i=2;i<N+1;i++){
    p=strtok(NULL," \n");
  	l[i]=atoi(p);
  }
  dis=l[0],count=0,k=0;
  
  while(dis<=X && k<N){
    count++,k++;
    dis+=l[k];
    if(k==N && dis<=X){
      count++;
    }
  }
  
  printf("%d\n",count);
  
  return 0;
}