Problem:
Score : 200 points

Problem Statement

Raccoon is fighting with a monster.

The health of the monster is H.

Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i.
There is no other way to decrease the monster's health.

Raccoon wins when the monster's health becomes 0 or below.

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Constraints

1 \leq H \leq 10^9

1 \leq N \leq 10^5

1 \leq A_i \leq 10^4

All values in input are integers.

Input

Input is given from Standard Input in the following format:

H N
A_1 A_2 ... A_N

Output

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Sample Input 1

10 3
4 5 6

Sample Output 1

Yes

The monster's health will become 0 or below after, for example, using the second and third moves.

Sample Input 2

20 3
4 5 6

Sample Output 2

No

Sample Input 3

210 5
31 41 59 26 53

Sample Output 3

Yes

Sample Input 4

211 5
31 41 59 26 53

Sample Output 4

No

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>

int main(){
    int h1, n, h2 = 0, cont = 0;

    scanf("%d %d", &h1, &n);

    int v[n];

    for(int i = 0; i < n; ++i){
        scanf("%d", &v[i]);
    }
    for(int i = 0; i < n; ++i){
        for(int j = i + 1; j < n; ++j){
            if(v[i] == v[j]){
                cont += v[i];
            }
        }
    }

    for(int i = 0; i < n; ++i){
        h2 += v[i];
    }
    h2 -= cont;

    if(h2 >= h1){
        printf("Yes\n");
    }else{
        printf("No\n");
    }


    return 0;
}