Problem:
Score : 200 points

Problem Statement

An integer N is a multiple of 9 if and only if the sum of the digits in the decimal representation of N is a multiple of 9.

Determine whether N is a multiple of 9.

Constraints

0 \leq N < 10^{200000}

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a multiple of 9, print Yes; otherwise, print No.

Sample Input 1

123456789

Sample Output 1

Yes

The sum of these digits is 1+2+3+4+5+6+7+8+9=45, which is a multiple of 9, so 123456789 is a multiple of 9.

Sample Input 2

0

Sample Output 2

Yes

Sample Input 3

31415926535897932384626433832795028841971693993751058209749445923078164062862089986280

Sample Output 3

No

Solution in C (Clang 10.0.0) (judge verdict: Wrong Answer)

#include <stdio.h>
#include <math.h>


int main(void){
    int nine;
    (void)scanf("%d",&nine);
    int a= 0;
    double out =0;
    /*
    while(nine){
        a = nine % 10;
        out += a;
        nine = nine/10;
    }*/
  
    double b = fmod(nine,9.0);
    if(b == 0.0){
        printf("Yes\n");
    }else{
        printf("No\n");
    }
    return 0;
    
}