Problem:
Score : 100 points

Problem Statement

You are given three integers, A, B and C.

Among them, two are the same, but the remaining one is different from the rest.

For example, when A=5,B=7,C=5, A and C are the same, but B is different.

Find the one that is different from the rest among the given three integers.

Constraints

-100 \leq A,B,C \leq 100

A, B and C are integers.

The input satisfies the condition in the statement.

Input

Input is given from Standard Input in the following format:

A B C

Output

Among A, B and C, print the integer that is different from the rest.

Sample Input 1

5 7 5

Sample Output 1

7

This is the same case as the one in the statement.

Sample Input 2

1 1 7

Sample Output 2

7

In this case, C is the one we seek.

Sample Input 3

-100 100 100

Sample Output 3

-100

Solution in C (Clang 3.8.0) (judge verdict: Wrong Answer)

#include <stdio.h>
#include <string.h>

int main(void){
    char O[50];
    char E[50];
    scanf("%s",&O);
    scanf("%s",&E);
    char ans[strlen(O)+strlen(E)];
  	int j= strlen(O)-strlen(E);
    for(int i=0;i<strlen(O)+strlen(E)-j;i++){
        if(i%2==0){
            ans[i]=O[i/2];
        }else{
            ans[i]=E[i/2];
        }
    }
  	if(j>0){
      	for(int i=strlen(O)+strlen(E)-j-1;j<strlen(O)+strlen(E)+1;j++)ans[j]=O[j];
    }else if(j>0){
        for(int i=strlen(O)+strlen(E)-j-1;j<strlen(O)+strlen(E)+1;j++)ans[j]=E[j];
    }
  
    printf("%s",ans);
    return 0;
}