Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>

int main(void) {
	int A[3][3];
	int _A[3][3] = { {0,0,0}, {0,0,0} };
	for (int i = 0; i < 3; ++i) {// make bingo sheet
		scanf("%d %d %d", &A[i][0], &A[i][1], &A[i][2]);
	}

	// let's bingo
	int n, b;
	scanf("%d", &n);
	for (int i = 0; i < n; ++i) {
		scanf("%d", &b);

		for (int j = 0; j < 3; ++j) {
			for (int k = 0; k < 3; ++k) {
				if (A[j][k] == b) {
					_A[j][k] = 1;
				}
			}
		}

	}
	//judge
	//line and low
	int jg = 0;
	for (int i = 0; i < 3;  ++i) {
		if ((_A[1][i] && _A[1][i] && _A[1][i])|| (_A[i][1] && _A[i][1] && _A[i][1])) {
			jg = 1;
			break;
		}
	}
	//cross
	if (jg &&(_A[0][0] && _A[1][1] && _A[2][2]) || (_A[0][2] && _A[1][1] && _A[2][0])) {
		jg = 1;

	}
	printf(jg == 1 ? "Yes" : "No");


	return 0;
}