Problem:
Score : 200 points

Problem Statement

Find the number of palindromic numbers among the integers between A and B (inclusive).
Here, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.

Constraints

10000 \leq A \leq B \leq 99999

All input values are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the number of palindromic numbers among the integers between A and B (inclusive).

Sample Input 1

11009 11332

Sample Output 1

4

There are four integers that satisfy the conditions: 11011, 11111, 11211 and 11311.

Sample Input 2

31415 92653

Sample Output 2

612

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>

int main()
{
	int A, B;
	int count = 0;
	
	scanf("%d %d",&A,&B);
	for(int i=A; i<B; i++){
		int a, b, c, d;
		
		a = i/10000;
		b = (i - a*10000)/1000;
		d = i%10;
		c = i%100/10;
		if(a == d && b == c) count++;
	}
		printf("%d",count);
		
		return 0;
	}