Problem:
Score : 100 points

Problem Statement

We conducted a survey on newspaper subscriptions.
More specifically, we asked each of the N respondents the following two questions:

Question 1: Are you subscribing to Newspaper X?

Question 2: Are you subscribing to Newspaper Y?

As the result, A respondents answered "yes" to Question 1, and B respondents answered "yes" to Question 2.

What are the maximum possible number and the minimum possible number of respondents subscribing to both newspapers X and Y?

Write a program to answer this question.

Constraints

1 \leq N \leq 100

0 \leq A \leq N

0 \leq B \leq N

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N A B

Output

Print the maximum possible number and the minimum possible number of respondents subscribing to both newspapers, in this order, with a space in between.

Sample Input 1

10 3 5

Sample Output 1

3 0

In this sample, out of the 10 respondents, 3 answered they are subscribing to Newspaper X, and 5 answered they are subscribing to Newspaper Y.

Here, the number of respondents subscribing to both newspapers is at most 3 and at least 0.

Sample Input 2

10 7 5

Sample Output 2

5 2

In this sample, out of the 10 respondents, 7 answered they are subscribing to Newspaper X, and 5 answered they are subscribing to Newspaper Y.

Here, the number of respondents subscribing to both newspapers is at most 5 and at least 2.

Sample Input 3

100 100 100

Sample Output 3

100 100

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
    #include <stdlib.h>
 
    int main(void){
     int a,b,n,p,q;
     
     scanf("%d %d %d",&n,&a,&b);
     
     if(a<b) {
                 if(a+b < n){
                 q=0;
                 }
                 else{       
                 q=b+a-n;
                }            
                 p=a;             
         } 
     else if(b<a){
                 if(a+b < n){
                 q = 0;
                 }
                 else{
                 q=a+b-n;
              }
                 p=b;
         }
     else if(a==b){
                if(b==n){
                        q=a;
                        p=b;
                  }
      }
     
     printf("%d %d\n",p,abs(q));
     
     return 0;
    }