Problem:
Score : 100 points

Problem Statement

Takahashi has K 500-yen coins. (Yen is the currency of Japan.)
If these coins add up to X yen or more, print Yes; otherwise, print No.

Constraints

1 \leq K \leq 100

1 \leq X \leq 10^5

Input

Input is given from Standard Input in the following format:

K X

Output

If the coins add up to X yen or more, print Yes; otherwise, print No.

Sample Input 1

2 900

Sample Output 1

Yes

Two 500-yen coins add up to 1000 yen, which is not less than X = 900 yen.

Sample Input 2

1 501

Sample Output 2

No

One 500-yen coin is worth 500 yen, which is less than X = 501 yen.

Sample Input 3

4 2000

Sample Output 3

Yes

Four 500-yen coins add up to 2000 yen, which is not less than X = 2000 yen.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <string.h>
#define yes "Yes\n"
#define no "No\n"
//int m,n;
//int i,j,k,l;
//int a,b,c,d,e,f,g;
//int sum,total;
//long long int ;
//float ;
//double ;
//char a[101],b[101],s[101],t[101],u[101];
int k,x;
int main(void){
    scanf("%d %d",&k,&x);
    if (k*500>=x)
    {
        printf(yes);
    }else
    {
        printf(no);
    }
    
    
    return 0;
}