Problem:
Score : 200 points

Problem Statement

A shop sells N kinds of fruits, Fruit 1, \ldots, N, at prices of p_1, \ldots, p_N yen per item, respectively. (Yen is the currency of Japan.)

Here, we will choose K kinds of fruits and buy one of each chosen kind. Find the minimum possible total price of those fruits.

Constraints

1 \leq K \leq N \leq 1000

1 \leq p_i \leq 1000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
p_1 p_2 \ldots p_N

Output

Print an integer representing the minimum possible total price of fruits.

Sample Input 1

5 3
50 100 80 120 80

Sample Output 1

210

This shop sells Fruit 1, 2, 3, 4, and 5 for 50 yen, 100 yen, 80 yen, 120 yen, and 80 yen, respectively.

The minimum total price for three kinds of fruits is 50 + 80 + 80 = 210 yen when choosing Fruit 1, 3, and 5.

Sample Input 2

1 1
1000

Sample Output 2

1000

Solution in C (GCC 9.2.1) (judge verdict: Runtime Error)

    #include <stdio.h>
    void main()
    {
 
        int i, j, a,v, n,sum=0, number[30];
        scanf("%d", &n);//total numbes
 
        scanf("%d",&v);
        //enter array element
        for (i = 0; i < n; ++i)
            scanf("%d", &number[i]);
 
        for (i = 0; i < n; ++i) 
        {
 
            for (j = i + 1; j < n; ++j)
            {
 
                if (number[i] > number[j]) 
                {
 
                    a =  number[i];
                    number[i] = number[j];
                    number[j] = a;
 
                }
 
            }
 
        }
 
       for (i = 0; i<=v; ++i)
            sum=number[i];
        printf("%d",sum);
 
    }