Problem:
Score : 200 points

Problem Statement

Takahashi loves gold coins. He gains 1000 happiness points for each 500-yen coin he has and gains 5 happiness points for each 5-yen coin he has. (Yen is the currency of Japan.)

Takahashi has X yen. If he exchanges his money so that he will gain the most happiness points, how many happiness points will he earn?

(We assume that there are six kinds of coins available: 500-yen, 100-yen, 50-yen, 10-yen, 5-yen, and 1-yen coins.)

Constraints

0 \leq X \leq 10^9

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print the maximum number of happiness points that can be earned.

Sample Input 1

1024

Sample Output 1

2020

By exchanging his money so that he gets two 500-yen coins and four 5-yen coins, he gains 2020 happiness points, which is the maximum number of happiness points that can be earned.

Sample Input 2

0

Sample Output 2

0

He is penniless - or yenless.

Sample Input 3

1000000000

Sample Output 3

2000000000

He is a billionaire - in yen.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)


#include<assert.h>
#include<complex.h>
#include<ctype.h>
#include<errno.h>
#include<fenv.h>
#include<float.h>
#include<inttypes.h>
#include<iso646.h>
#include<limits.h>
#include<locale.h>
#include<math.h>
#include<setjmp.h>
#include<signal.h>
#include<stdalign.h>
#include<stdarg.h>
#include<stdatomic.h>
#include<stdbool.h>
#include<stddef.h>
#include<stdint.h>
#include<stdio.h>
#include<stdlib.h>
#include<stdnoreturn.h>
#include<string.h>
#include<tgmath.h>
#include<time.h>


int main(){
    int X;
    int Vhund,V;
    scanf("%d",&X);
    Vhund = (int)X / 500;
    X -= Vhund * 500;
    V = (int)X / 5;
    printf("%d",Vhund*1000+V*5);
    return 0;
}