Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<math.h>


int main(){
	int i, j;
	int m, h, w, n;

	scanf("%d", &m);

	int min = (int)(3.0 * (double)m / 4.0);

	for (h = min; h <= 3500; h++) {
		for (w = h; w <= 3500; w++) {
			for (n = w; n <= 3500; n++) {
				long long int x, y;
				x = (long long int)m * (long long int)(h*w+w*n+n*h);
				y = (long long int)h * (long long int)(w*n);
				if (x%4 != 0) continue;
				if (x / 4 == y) {
					printf("%d %d %d\n", h, n, w);
					return 0;
				}
			}
		}
	}
	//printf("min:%d\n", min);

	return 0;
}