Problem:
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Matrix Multiplication

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\[
c_{ij} = \sum_{k=1}^m a_{ik}b_{kj}
\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Constraints

$1 \leq n, m, l \leq 100$

$0 \leq a_{ij}, b_{ij} \leq 10000$

Sample Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2

Sample Output

1 8 5
0 9 6
4 23 14

Note

      解説

Solution in C (judge verdict: Time Limit Exceeded)

#include<stdio.h>

main(){


int a,b,c,d,e,f,g,n,m,j;
int nm[100][100],mj[100][100],C[100][100];
scanf("%d %d %d",&n,&m,&j);
for(a=0;a<n;a++){
for(b=0;b<m;b++){
scanf("%d",&nm[a][b]);
}
}
for(a=0;a<m;a++){
for(b=0;b<j;j++){
scanf("%d",&mj[a][b]);
}
}
for(a=0;a<n;a++){
for(b=0;b<j;b++){
for(c=0;c<m;c++){
C[a][b]+=nm[a][c]*mj[c][b];
}
printf("%d",C[a][b]);
}
printf("\n");
}
return 0;
}