Problem:
Score : 100 points

Problem Statement

You have three tasks, all of which need to be completed.

First, you can complete any one task at cost 0.

Then, just after completing the i-th task, you can complete the j-th task at cost |A_j - A_i|.

Here, |x| denotes the absolute value of x.

Find the minimum total cost required to complete all the task.

Constraints

All values in input are integers.

1 \leq A_1, A_2, A_3 \leq 100

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

Print the minimum total cost required to complete all the task.

Sample Input 1

1 6 3

Sample Output 1

5

When the tasks are completed in the following order, the total cost will be 5, which is the minimum:

Complete the first task at cost 0.

Complete the third task at cost 2.

Complete the second task at cost 3.

Sample Input 2

11 5 5

Sample Output 2

6

Sample Input 3

100 100 100

Sample Output 3

0

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
#include<stdlib.h>

int main(void){
	
	int A;
	int B;
	int C;
	int D;

	scanf("%d %d %d",&A,&B,&C);
	
	D = abs(A - B) + abs(C - A);
	if (D > abs(B - A) + abs(C - B))
		D = abs(B - A) + abs(C - B);
	if (D > abs(A - C) + abs(B - A))
		D = abs(A - C) + abs(B - A);
	if (D > abs(B - C) + abs(A - B))
		D = abs(B - C) + abs(A - B);
	if (D > abs(C - A) + abs(B - C))
		D = abs(C - A) + abs(B - C);
	if (D > abs(C - B) + abs(A - C))
	D = abs(C - B) + abs(A - C);
	
	printf("%d", D);

	return 0;
}