Problem:
Score : 200 points

Problem Statement

In Japan, people make offerings called hina arare, colorful crackers, on March 3.

We have a bag that contains N hina arare. (From here, we call them arare.)

It is known that the bag either contains arare in three colors: pink, white and green, or contains arare in four colors: pink, white, green and yellow.

We have taken out the arare in the bag one by one, and the color of the i-th arare was S_i, where colors are represented as follows - pink: P, white: W, green: G, yellow: Y.

If the number of colors of the arare in the bag was three, print Three; if the number of colors was four, print Four.

Constraints

1 \leq N \leq 100

S_i is P, W, G or Y.

There always exist i, j and k such that S_i=P, S_j=W and S_k=G.

Input

Input is given from Standard Input in the following format:

N
S_1 S_2 ... S_N

Output

If the number of colors of the arare in the bag was three, print Three; if the number of colors was four, print Four.

Sample Input 1

6
G W Y P Y W

Sample Output 1

Four

The bag contained arare in four colors, so you should print Four.

Sample Input 2

9
G W W G P W P G G

Sample Output 2

Three

The bag contained arare in three colors, so you should print Three.

Sample Input 3

8
P Y W G Y W Y Y

Sample Output 3

Four

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
int main(void){
    int num;
    int p = 0;
    int g = 0;
    int w = 0;
    int y= 0;
    int counter = 0;
    char c[100];
    scanf("%d", &num);
    int i;
    for(i = 0; i < num; i++){
        scanf("%c", &c[i]);
        if(c[i] == 'P') p++;
else if(c[i] == 'G') g++;
else if(c[i] == 'W') w++;
else if(c[i] == 'Y') y++;
    } 
    if(p != 0) counter++;
    if(g != 0) counter++;
    if(w != 0) counter++;
    if(y != 0) counter++;
    if(counter == 3) printf("Three");
else if(counter == 4) printf("Four"); 
    return 0;
}