Problem:
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Transformation

Write a program which performs a sequence of commands to a given string $str$. The command is one of:

print a b: print from the a-th character to the b-th character of $str$

reverse a b: reverse from the a-th character to the b-th character of $str$

replace a b p: replace from the a-th character to the b-th character of $str$ with p

Note that the indices of $str$ start with 0.

Input

In the first line, a string $str$ is given. $str$ consists of lowercase letters. In the second line, the number of commands q is given. In the next q lines, each command is given in the above mentioned format.

Output

For each print command, print a string in a line.

Constraints

$1 \leq $ length of $str \leq 1000$

$1 \leq q \leq 100$

$0 \leq a \leq b < $ length of $str$

for replace command, $b - a + 1 = $ length of $p$

Sample Input 1

abcde
3
replace 1 3 xyz
reverse 0 2
print 1 4

Sample Output 1

xaze

Sample Input 2

xyz
3
print 0 2
replace 0 2 abc
print 0 2

Sample Output 2

xyz
abc

Solution in C (judge verdict: Time Limit Exceeded)

#include<stdio.h>
#include<string.h>

int main()
{
 int a,i,b,c,k;
 char j;
 char moji[1000],shiji[100],rep[100];
 scanf("%s",&moji);
 scanf("%d",&a);
 for(i=0;i<a;i++){
                     scanf("%s",&shiji);
                     if(strcmp(shiji,"replace")==0){
                                                     scanf("%d%d%s",&b,&c,&rep);
                                                     for(j=0;j<c-b+1;j++){
                                                                          moji[b+j]=rep[j];
                                                                          }
                                                    }
                     if(strcmp(shiji,"reverse")==0){
                                                   scanf("%d%d",&b,&c);
                                                   for(;b<c;){
                                                              j=moji[b];
                                                              moji[b]=moji[c];
                                                              moji[c]=j;
                                                              b++;
                                                              c--;
                                                              }    
                                                     }         
                           
                     if(strcmp(shiji,"print")==0){         
                                                  scanf("%d%d",&b,&c);
                                                  for(k=b;k<=c;k++){
                                                  printf("%c",moji[k]);
                                                                    }
                                                  printf("\n");
                                                  }

                     }
   return 0;

}