Problem:
Score : 300 points

Problem Statement

You are given four integers A, B, C, and D. Find the number of integers between A and B (inclusive) that can be evenly divided by neither C nor D.

Constraints

1\leq A\leq B\leq 10^{18}

1\leq C,D\leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B C D

Output

Print the number of integers between A and B (inclusive) that can be evenly divided by neither C nor D.

Sample Input 1

4 9 2 3

Sample Output 1

2

5 and 7 satisfy the condition.

Sample Input 2

10 40 6 8

Sample Output 2

23

Sample Input 3

314159265358979323 846264338327950288 419716939 937510582

Sample Output 3

532105071133627368

Solution in C (Clang 3.8.0) (judge verdict: Wrong Answer)

#include <stdio.h>
int main(void)
{
    int a, b, c, d, i, c1=0, c2=0, c3=0;

    scanf("%d%d%d%d", &a, &b, &c, &d);

 int u = b - a + 1;
 int e;

 if(c>d){
    for(i=1;i=e;i++){
        if(d*i%c==0){
         int  e = d*i;
         i=e;
        }
    }
 }else{
    for(i=1;i=e;i++){
        if(c*i%d==0){
         int  e = c*i;
         i=e;
         }
    }
 }

 for(i=a; i<=b; i++){
    if(i%c==0){
        c1++;
    }
    if(i%d==0){
        c2++;
    }
    if(i%e==0){
        c3++;
    }
 }

 int sum = u - c1 - c2 + c3;
 printf("%d\n", sum);

 return 0;

}