Problem:
Score : 100 points

Problem Statement

You have three tasks, all of which need to be completed.

First, you can complete any one task at cost 0.

Then, just after completing the i-th task, you can complete the j-th task at cost |A_j - A_i|.

Here, |x| denotes the absolute value of x.

Find the minimum total cost required to complete all the task.

Constraints

All values in input are integers.

1 \leq A_1, A_2, A_3 \leq 100

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

Print the minimum total cost required to complete all the task.

Sample Input 1

1 6 3

Sample Output 1

5

When the tasks are completed in the following order, the total cost will be 5, which is the minimum:

Complete the first task at cost 0.

Complete the third task at cost 2.

Complete the second task at cost 3.

Sample Input 2

11 5 5

Sample Output 2

6

Sample Input 3

100 100 100

Sample Output 3

0

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>

int diffabs(int a,int b){
    if(a<b){
        return b-a;
    }else{
        return a-b;
    }
}

int main(void){
    int A[3]={};
    for(int i=0;i<3;i++){
        scanf("%d",&A[i]);
    }
    int small;
    small = diffabs(A[0],A[1])+diffabs(A[1],A[2]);
    if(diffabs(A[0],A[2])+diffabs(A[2],A[1])<small){
        small = diffabs(A[0],A[2])+diffabs(A[1],A[2]);
    }
    if(diffabs(A[2],A[1])+diffabs(A[0],A[2])){
        small = diffabs(A[2],A[1])+diffabs(A[0],A[2]);
    }

    printf("%d",small);
    return 0;
}