Problem:
Score : 300 points

Problem Statement

Sitting in a station waiting room, Joisino is gazing at her train ticket.

The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).

In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.

The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Constraints

0≤A,B,C,D≤9

All input values are integers.

It is guaranteed that there is a solution.

Input

Input is given from Standard Input in the following format:

ABCD

Output

Print the formula you made, including the part =7.

Use the signs + and -.

Do not print a space between a digit and a sign.

Sample Input 1

1222

Sample Output 1

1+2+2+2=7

This is the only valid solution.

Sample Input 2

0290

Sample Output 2

0-2+9+0=7

0 - 2 + 9 - 0 = 7 is also a valid solution.

Sample Input 3

3242

Sample Output 3

3+2+4-2=7

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
int main() {
  int n,a,b,c,d,e;
  scanf("%d",&n);
  a=n/1000;
  b=n/100-a*10;
  c=n/10-a*100-b*10;
  d=n-a*1000-b*100-c*10;
  e=b+c+d;
  if (a+e==7) {
    printf("%d+%d+%d+%d=7\n",a,b,c,d);
  } else if (a-e==7) {
    printf("%d-%d-%d-%d=7\n",a,b,c,d);
  } else if (a+e-2*d==7) {
    printf("%d+%d+%d-%d=7\n",a,b,c,d);
  } else if (a+e-2*c==7) {
    printf("%d+%d-%d+%d=7\n",a,b,c,d);
  } else if (a+e-2*b==7) {
    printf("%d-%d+%d+%d=7\n",a,b,c,d);
  } else if (a-e+2*d==7) {
    printf("%d-%d-%d+%d=7\n",a,b,c,d);
  } else if (a-e+2*c==7) {
    printf("%d-%d+%d-%d=7\n",a,b,c,d);
  } else {
    printf("%d+%d-%d-%d=7\n",a,b,c,d);
  }
  return 0;
}