Problem:
Score : 200 points

Problem Statement

An integer N is a multiple of 9 if and only if the sum of the digits in the decimal representation of N is a multiple of 9.

Determine whether N is a multiple of 9.

Constraints

0 \leq N < 10^{200000}

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a multiple of 9, print Yes; otherwise, print No.

Sample Input 1

123456789

Sample Output 1

Yes

The sum of these digits is 1+2+3+4+5+6+7+8+9=45, which is a multiple of 9, so 123456789 is a multiple of 9.

Sample Input 2

0

Sample Output 2

Yes

Sample Input 3

31415926535897932384626433832795028841971693993751058209749445923078164062862089986280

Sample Output 3

No

Solution in C (GCC 9.2.1) (judge verdict: Wrong Answer)

#include<stdio.h>
#include<string.h>
int main(void)
{
    char s[200002];
    long int i,j,a,sum = 0;
    scanf("%s",s);
    a = strlen(s);
    for(i = 0 ; i < a ; i++)
    {
        for(j = 0 ; j <= 9 ; j++)
        {
            if(s[i] == j)
            {
                sum += 1;
                sum = sum % 9 ;
                break;
            }
        }
        
    }
    sum = sum % 9;
    if(sum == 0)
    {
        printf("Yes\n");
    }
    else
    {
        printf("No");
    }
    
    return 0;
}