Problem:
Score : 400 points

Problem Statement

Snuke has one biscuit and zero Japanese yen (the currency) in his pocket.
He will perform the following operations exactly K times in total, in the order he likes:

Hit his pocket, which magically increases the number of biscuits by one.

Exchange A biscuits to 1 yen.

Exchange 1 yen to B biscuits.

Find the maximum possible number of biscuits in Snuke's pocket after K operations.

Constraints

1 \leq K,A,B \leq 10^9

K,A and B are integers.

Input

Input is given from Standard Input in the following format:

K A B

Output

Print the maximum possible number of biscuits in Snuke's pocket after K operations.

Sample Input 1

4 2 6

Sample Output 1

7

The number of biscuits in Snuke's pocket after K operations is maximized as follows:

Hit his pocket. Now he has 2 biscuits and 0 yen.

Exchange 2 biscuits to 1 yen. his pocket. Now he has 0 biscuits and 1 yen.

Hit his pocket. Now he has 1 biscuits and 1 yen.

Exchange 1 yen to 6 biscuits. his pocket. Now he has 7 biscuits and 0 yen.

Sample Input 2

7 3 4

Sample Output 2

8

Sample Input 3

314159265 35897932 384626433

Sample Output 3

48518828981938099

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>

int main(){
  int operation,bisket=1;
  int bis_a,bis_b,money=0;
  int tmp=0;
  scanf("%d %d %d",&operation,&bis_a,&bis_b);

  if(bis_b-bis_a<=2){
   bisket = bisket + operation;
   printf("%d",bisket);
  }
  else{
    while(operation>0){
        tmp = operation-1;
        if(tmp==0){
          if(money>0){
            bisket += bis_b;
            money--;
          }
          else bisket++;
          operation--;
        }
        else if(bisket>=bis_a){
          bisket -= bis_a;
          money++;
          operation--;
        }
        else{
          bisket++;
          operation--;
        }
        if(money>0){
          bisket += bis_b;
          money--;
          operation--;
        }	
    }
    printf("%d",bisket);
  }
  
  return 0;
}