Problem:
Score : 500 points

Problem Statement

Let N be a positive integer.

There is a numerical sequence of length 3N, a = (a_1, a_2, ..., a_{3N}).
Snuke is constructing a new sequence of length 2N, a', by removing exactly N elements from a without changing the order of the remaining elements.
Here, the score of a' is defined as follows: (the sum of the elements in the first half of a') - (the sum of the elements in the second half of a').

Find the maximum possible score of a'.

Constraints

1 ≤ N ≤ 10^5

a_i is an integer.

1 ≤ a_i ≤ 10^9

Partial Score

In the test set worth 300 points, N ≤ 1000.

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 ... a_{3N}

Output

Print the maximum possible score of a'.

Sample Input 1

2
3 1 4 1 5 9

Sample Output 1

1

When a_2 and a_6 are removed, a' will be (3, 4, 1, 5), which has a score of (3 + 4) - (1 + 5) = 1.

Sample Input 2

1
1 2 3

Sample Output 2

-1

For example, when a_1 are removed, a' will be (2, 3), which has a score of 2 - 3 = -1.

Sample Input 3

3
8 2 2 7 4 6 5 3 8

Sample Output 3

5

For example, when a_2, a_3 and a_9 are removed, a' will be (8, 7, 4, 6, 5, 3), which has a score of (8 + 7 + 4) - (6 + 5 + 3) = 5.

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
#include <stdlib.h>

int assort(const void *a, const void *b){return *(long long*)a-*(long long*)b;}
int dessort(const void *a, const void *b){return *(long long*)b-*(long long*)a;}

int main(void){
    int n;
    scanf("%d",&n);
    long long a[300030],ar[n+2],al[n+2],tmp,R[100005]={},L[100005]={};
    ar[0]=-10e10;
    al[0]=10e10;
    ar[n+1]=10e10;
    al[n+1]=-10e10;
    for (int i=0; i<n*3; i++){
        scanf("%lld",&a[i]);
    }
    
    for (int i=0; i<n; i++){
        ar[i+1]=a[i];
        R[0]+=ar[i+1];
    }
    qsort (ar,n+2,sizeof(long long),assort);
    for (int i=0; i<n; i++){
        tmp=a[i+n];
        if (tmp>ar[1]){
            R[i+1]=R[i]-ar[1]+tmp;
            ar[1]=tmp;
            long long bf=1;
            while(1){
                if (bf*2>n){
                    break;
                }
                if (ar[bf*2]<=ar[bf*2+1]){
                    if (ar[bf]>ar[bf*2]){
                        tmp=ar[bf];
                        ar[bf]=ar[bf*2];
                        ar[bf*2]=tmp;
                        bf=bf*2;
                    } else {
                        break;
                    }
                } else {
                    if (ar[bf]>ar[bf*2+1]){
                        tmp=ar[bf];
                        ar[bf]=ar[bf*2+1];
                        ar[bf*2+1]=tmp;
                        bf=bf*2+1;
                    } else {
                        break;
                    }
                }
            }
        } else {
            R[i+1]=R[i];
        }
    }
    
    for (int i=0; i<n; i++){
        al[i+1]=a[n*3-i-1];
        L[0]+=al[i+1];
    }
    qsort (al,n+2,sizeof(long long),dessort);
    for (int i=0; i<n; i++){
        tmp=a[2*n-i-1];
        if (tmp<al[1]){
            L[i+1]=L[i]-al[1]+tmp;
            al[1]=tmp;
            long long bf=1;
            while(1){
                if (bf*2>n){
                    break;
                }
                if (al[bf*2]>=al[bf*2+1]){
                    if (al[bf]<al[bf*2]){
                        tmp=al[bf];
                        al[bf]=al[bf*2];
                        al[bf*2]=tmp;
                        bf=bf*2;
                    } else {
                        break;
                    }
                } else {
                    if (al[bf]<al[bf*2+1]){
                        tmp=al[bf];
                        al[bf]=al[bf*2+1];
                        al[bf*2+1]=tmp;
                        bf=bf*2+1;
                    } else {
                        break;
                    }
                }
            }
        } else {
            L[i+1]=L[i];
        }
    }
    tmp=R[0]-L[n];
    for (int i=0; i<=n; i++){
        tmp=tmp>(R[i]-L[n-i])?tmp:(R[i]-L[n-i]);
    }
    printf("%lld\n",tmp);
    return 0;
}