Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in C (GCC 9.2.1) (judge verdict: Wrong Answer)

#include<stdio.h>
#include<string.h>

int main(void){
    register int i,j;
    int in;
    long n[3];
    scanf("%d%ld%ld%ld",&in,&n[0],&n[1],&n[2]);
    char s[in][3];
    char ans[in];
    for(i = 0;i < in;i++)scanf("%s",s[i]);
    for(i = 0;i < in;i++){
        int i0,i1;
        if(!strcmp("AB",s[i])){i0 = 0;i1 = 1;}
        else if(!strcmp("AC",s[i])){i0 = 0;i1= 2;}
        else {i0 = 1;i1 = 2;}
        if(n[i0] < n[i1]){
            n[i0]++; n[i1]--;
            ans[i] = 'A' + i0;
        }else{
            n[i0]--; n[i1]++;
            ans[i] = 'A' + i1;
        }
        for(j = 0;j < 3;j++)if(n[j] < 0){
            puts("No");
            return 0;
        }
    }
    puts("Yes");
    for(i = 0;i < in;i++)printf("%c\n",ans[i]);
}