Problem:
Score : 100 points

Problem Statement

You have three tasks, all of which need to be completed.

First, you can complete any one task at cost 0.

Then, just after completing the i-th task, you can complete the j-th task at cost |A_j - A_i|.

Here, |x| denotes the absolute value of x.

Find the minimum total cost required to complete all the task.

Constraints

All values in input are integers.

1 \leq A_1, A_2, A_3 \leq 100

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

Print the minimum total cost required to complete all the task.

Sample Input 1

1 6 3

Sample Output 1

5

When the tasks are completed in the following order, the total cost will be 5, which is the minimum:

Complete the first task at cost 0.

Complete the third task at cost 2.

Complete the second task at cost 3.

Sample Input 2

11 5 5

Sample Output 2

6

Sample Input 3

100 100 100

Sample Output 3

0

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>

int main(void){
    int A[3]={};
    for(int i=0;i<3;i++){
        scanf("%d",&A[i]);
    }
    int a = A[0]-A[1];
    int b = A[1]-A[2];
    int c = A[0]-A[2];
    if(a<0){
        a = -a;
    }
    if(b<0){
        b = -b;
    }
    if(c<0){
        c = -c;
    }

    int max = 0;
    if(a>max){
        max = a;
    }
    if(b>max){
        max = b;
    }
    if(c>max){
        max = c;
    }
    printf("%d",a+b+c-max);
    return 0;
}