Problem:
Score : 100 points

Problem Statement

Compute A \times B.

Constraints

1 \leq A \leq 100

1 \leq B \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the value A \times B as an integer.

Sample Input 1

2 5

Sample Output 1

10

We have 2 \times 5 = 10.

Sample Input 2

100 100

Sample Output 2

10000

Solution in C (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <stdio.h>
#include <stdlib.h>

int main(void){
    int a,b,c;
    //printf("1以上100以下の数字を入力A:");
    scanf("%d",&a);
    if(1>a || a>100){
        while(1>a || a>100){
            //printf("1以上100以下の数字を入力A:");
            scanf("%d",&a);
        }
    }
    //printf("1以上100以下の数字を入力B:");
    scanf("%d",&b);
    if(1>b || b>100){
        while(1>b || b>100){
            //printf("1以上100以下の数字を入力B:");
            scanf("%d",&b);
        }
    }
    c=a*b;
    //printf("A*B=%d\n",c);
}