Problem:
Score : 200 points

Problem Statement

There are N positive integers written on a blackboard: A_1, ..., A_N.

Snuke can perform the following operation when all integers on the blackboard are even:

Replace each integer X on the blackboard by X divided by 2.

Find the maximum possible number of operations that Snuke can perform.

Constraints

1 \leq N \leq 200

1 \leq A_i \leq 10^9

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

Print the maximum possible number of operations that Snuke can perform.

Sample Input 1

3
8 12 40

Sample Output 1

2

Initially, [8, 12, 40] are written on the blackboard.
Since all those integers are even, Snuke can perform the operation.

After the operation is performed once, [4, 6, 20] are written on the blackboard.
Since all those integers are again even, he can perform the operation.

After the operation is performed twice, [2, 3, 10] are written on the blackboard.
Now, there is an odd number 3 on the blackboard, so he cannot perform the operation any more.

Thus, Snuke can perform the operation at most twice.

Sample Input 2

4
5 6 8 10

Sample Output 2

0

Since there is an odd number 5 on the blackboard already in the beginning, Snuke cannot perform the operation at all.

Sample Input 3

6
382253568 723152896 37802240 379425024 404894720 471526144

Sample Output 3

8

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>
 
 
int main()
{
    int N;
    long int A[201];
    int min=1000000000;
    int temp=0;
    int i;
  
 // 整数の入力
    scanf("%d", &N);
 // printf("%d\n",N);
  for(i=0;i<N;i++){
    scanf("%ld", &A[i]);
//     printf("%ld\n",A[i]);
    temp = 0;
    while(1){
      if(A[i]%2 == 0){
        A[i]=A[i]/2;
        temp = temp +1;
//        printf("temp %d\n",temp);
      } else {
        break;
      }
    }
    if(min>temp)
    {
//      printf("temp %d ,%d\n",temp,min);
      min = temp;
    }
  }
  
    printf("%d\n",min);
/*
  for(i=0;i < 3 ;i++ ){
//    printf("%c\n",s[i]);
    if(49 == s[i]){ 
     cnt = cnt + 1;
//     printf("%d\n",cnt);
              }
  }
     printf("%d\n", cnt);
*/ 
    return 0;
}