Problem:
Score : 200 points

Problem Statement

Given are a positive integer N and a string S of length N consisting of lowercase English letters.

Determine whether the string is a concatenation of two copies of some string.
That is, determine whether there is a string T such that S = T + T.

Constraints

1 \leq N \leq 100

S consists of lowercase English letters.

|S| = N

Input

Input is given from Standard Input in the following format:

N
S

Output

If S is a concatenation of two copies of some string, print Yes; otherwise, print No.

Sample Input 1

6
abcabc

Sample Output 1

Yes

Let T = abc, and S = T + T.

Sample Input 2

6
abcadc

Sample Output 2

No

Sample Input 3

1
z

Sample Output 3

No

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>

int main()
{
	int n;
	char a[100];
	scanf("%d", &n);
	scanf("%s", a);
	if (n % 2 != 0) {
	printf("No");
	return 0;
	}		
	for (int i = 0; i < (n/2); i++) {
		if (a[i] != a[((n / 2) + i)]) {
			printf("No");
			return 0;
		}
	}
	printf("Yes");
	return 0;
	
}