Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in C (GCC 5.4.1) (judge verdict: Time Limit Exceeded)


#include<stdio.h>
#define MAX 3500

int main()
{
        float N;
        float i, j, k;
        scanf("%f", &N);

        for(i=1; i<=MAX; i++){
                for(j=i; j<=MAX; j++){
                        for(k=j; k<=MAX; k++){
                                if(4 == N*(1/i+1/j+1/k))printf("%f %f %f\n", i, j, k);
                        }
                }
        }

        return 0;
}