Problem:
Score : 100 points

Problem Statement

You have three tasks, all of which need to be completed.

First, you can complete any one task at cost 0.

Then, just after completing the i-th task, you can complete the j-th task at cost |A_j - A_i|.

Here, |x| denotes the absolute value of x.

Find the minimum total cost required to complete all the task.

Constraints

All values in input are integers.

1 \leq A_1, A_2, A_3 \leq 100

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

Print the minimum total cost required to complete all the task.

Sample Input 1

1 6 3

Sample Output 1

5

When the tasks are completed in the following order, the total cost will be 5, which is the minimum:

Complete the first task at cost 0.

Complete the third task at cost 2.

Complete the second task at cost 3.

Sample Input 2

11 5 5

Sample Output 2

6

Sample Input 3

100 100 100

Sample Output 3

0

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
#include<stdlib.h>

int main(int argc, char *argv[]){
    int A,B,C;
    int ab = 0;
    int ac = 0;
    int bc = 0;

    if(scanf("%d %d %d", &A, &B, &C) < 3){
        exit(1);
    }

    ab = A - B;
    if(ab < 0){
        ab = -ab;
    }

    ac = A -C;
    if(ac < 0){
        ac = -ac;
    }

    bc = B-C;
    if(bc < 0){
        bc = -bc;
    }

    if(ab < ac){
        printf("%d\n", ab + bc);
    }else{
        printf("%d\n", ac + bc);
    }
    return 0;
}