Problem:
Score : 200 points

Problem Statement

Find the number of palindromic numbers among the integers between A and B (inclusive).
Here, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.

Constraints

10000 \leq A \leq B \leq 99999

All input values are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the number of palindromic numbers among the integers between A and B (inclusive).

Sample Input 1

11009 11332

Sample Output 1

4

There are four integers that satisfy the conditions: 11011, 11111, 11211 and 11311.

Sample Input 2

31415 92653

Sample Output 2

612

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
int main()
{
    int a,b,i,num[4],count=0;
    scanf("%d%d",&a,&b);
    for(i=a;i<=b;i++)
    {
        num[0]=i%10;
        num[1]=i/10%10;
        num[2]=i/1000%10;
        num[3]=i/10000%10;
        if(num[0]==num[3]&&num[1]==num[2])
            count++;
    }
    printf("%d\n",count);
    return 0;
}