Problem:
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Matrix Multiplication

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\[
c_{ij} = \sum_{k=1}^m a_{ik}b_{kj}
\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Constraints

$1 \leq n, m, l \leq 100$

$0 \leq a_{ij}, b_{ij} \leq 10000$

Sample Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2

Sample Output

1 8 5
0 9 6
4 23 14

Note

      解説

Solution in C (judge verdict: Accepted)

#include <stdio.h>

int main(void) {
	int n, m, l;
	int i, j, k;
	int a[100][100], b[100][100];
	
	scanf("%d %d %d", &n, &m, &l);
	
	for (i = 0; i < n; i++) {
		for (j = 0; j < m; j++) {
			scanf("%d", &a[i][j]);
		}
	}
	
	for (i = 0; i < m; i++) {
		for (j = 0; j < l; j++) {
			scanf("%d", &b[i][j]);
		}
	}
	
	for (i = 0; i < n; i++) {
		for (j = 0; j < l; j++) {
			long long sum = 0;
			
			for (k = 0; k < m; k++) sum += a[i][k] * b[k][j];
			
			printf("%s%lld", j ? " " : "", sum);
		}
		puts("");
	}
	
	return 0;
}