Problem:
Score : 300 points

Problem Statement

You are given a sequence of length N: A_1, A_2, ..., A_N.
For each integer i between 1 and N (inclusive), answer the following question:

Find the maximum value among the N-1 elements other than A_i in the sequence.

Constraints

2 \leq N \leq 200000

1 \leq A_i \leq 200000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1
:
A_N

Output

Print N lines. The i-th line (1 \leq i \leq N) should contain the maximum value among the N-1 elements other than A_i in the sequence.

Sample Input 1

3
1
4
3

Sample Output 1

4
3
4

The maximum value among the two elements other than A_1, that is, A_2 = 4 and A_3 = 3, is 4.

The maximum value among the two elements other than A_2, that is, A_1 = 1 and A_3 = 3, is 3.

The maximum value among the two elements other than A_3, that is, A_1 = 1 and A_2 = 4, is 4.

Sample Input 2

2
5
5

Sample Output 2

5
5

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>

int main(){
	int n;
	scanf("%d",&n);
	int a[n+1];
	a[0] = 0;
	for(int i=1; i<=n; i++){
		scanf("%d",&a[i]);
	}
	int max = -1,max_number = 1,second_max = -10, second_max_number = 1;
	max=a[1];
	for(int i=1; i<=n; i++){
		if(a[i] > max){
			max = a[i];
			max_number = i;
		}
	}
	
	if(max_number == 1){
		second_max = a[2];
		second_max_number = 2;
	}
	else{
		second_max = a[1];
		second_max_number = 1;
	}
	for(int i=1; i<=n; i++){
		if((a[i] > second_max) && (i != max_number)){
			second_max = a[i];
			second_max_number = i;
		}
	}
	
	for(int i=1; i<=n; i++){
		if(i != max_number) printf("%d\n",max);
		else printf("%d\n",second_max);
	}
	
	return 0;
}