Problem:
Score : 200 points

Problem Statement

You are given strings s and t, consisting of lowercase English letters.
You will create a string s' by freely rearranging the characters in s.
You will also create a string t' by freely rearranging the characters in t.
Determine whether it is possible to satisfy s' < t' for the lexicographic order.

Notes

For a string a = a_1 a_2 ... a_N of length N and a string b = b_1 b_2 ... b_M of length M, we say a < b for the lexicographic order if either one of the following two conditions holds true:

N < M and a_1 = b_1, a_2 = b_2, ..., a_N = b_N.

There exists i (1 \leq i \leq N, M) such that a_1 = b_1, a_2 = b_2, ..., a_{i - 1} = b_{i - 1} and a_i < b_i. Here, letters are compared using alphabetical order.

For example, xy < xya and atcoder < atlas.

Constraints

The lengths of s and t are between 1 and 100 (inclusive).

s and t consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s
t

Output

If it is possible to satisfy s' < t', print Yes; if it is not, print No.

Sample Input 1

yx
axy

Sample Output 1

Yes

We can, for example, rearrange yx into xy and axy into yxa. Then, xy < yxa.

Sample Input 2

ratcode
atlas

Sample Output 2

Yes

We can, for example, rearrange ratcode into acdeort and atlas into tslaa. Then, acdeort < tslaa.

Sample Input 3

cd
abc

Sample Output 3

No

No matter how we rearrange cd and abc, we cannot achieve our objective.

Sample Input 4

w
ww

Sample Output 4

Yes

Sample Input 5

zzz
zzz

Sample Output 5

No

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

int main(){
  char h[100],w[100];
  scanf("%s",h);
  scanf("%s",w);
  int a[strlen(h)],b[strlen(w)];
  for(int i=0;i<strlen(h);i++)a[i]=h[i];
  for(int i=0;i<strlen(w);i++)b[i]=w[i];
  for(int i=0;i<strlen(h);i++){
    int min=i;
    for(int j=0;j<strlen(h)-i;j++){
      if(a[min]>a[i+j])min=i+j;
    }
    int temp=a[i];
    a[i]=a[min];
    a[min]=temp;
  }
  for(int i=0;i<strlen(w);i++){
    int min=i;
    for(int j=0;j<strlen(w)-i;j++){
      if(b[min]<b[i+j])min=i+j;
    }
    int temp=b[i];
    b[i]=b[min];
    b[min]=temp;
  }
  //for(int i=0;i<strlen(h);i++)printf("%d ",a[i]);
  //for(int i=0;i<strlen(w);i++)printf("%d ",b[i]);

  int ab;
  if(strlen(h)>=strlen(w)){
    ab=strlen(w);
    for(int i=0;i<ab;i++){
      if(a[i]<b[i]){
        printf("Yes");
        return 0;
      }else if(a[i]>b[i]){
        printf("No");
        return 0;
      }
    }
    //if(strcmp(h,w)<0){printf("Yes\n");return 0;}
    printf("No");
    return 0;
  }
  else{
    ab=strlen(h);
  for(int i=0;i<ab;i++){
    if(a[i]<b[i]){
      printf("Yes");
      return 0;
    }
    else if(a[i]>b[i]){
      printf("No");
      return 0;
    }
  }
  if(strcmp(h,w)==0){printf("No");return 0;}
  printf("Yes");
}
}