Problem:
Score : 100 points

Problem Statement

You are given two positive integers a and b.
Let x be the average of a and b.
Print x rounded up to the nearest integer.

Constraints

a and b are integers.

1 \leq a, b \leq 100

Input

Input is given from Standard Input in the following format:

a b

Output

Print x rounded up to the nearest integer.

Sample Input 1

1 3

Sample Output 1

2

The average of 1 and 3 is 2.0, and it will be rounded up to the nearest integer, 2.

Sample Input 2

7 4

Sample Output 2

6

The average of 7 and 4 is 5.5, and it will be rounded up to the nearest integer, 6.

Sample Input 3

5 5

Sample Output 3

5

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
int main()
{
	int i,j, jud; // jud =1 yes, =0 no
	char s[102], t[102], letter;
	jud = 0;
	// I scan and rearrange s:
	scanf("%s",s);
	for (j=0;j<=100;j++){
	for (i=0;s[i+1]!=0;i++){
		if (s[i]>s[i+1]){ letter=s[i]; s[i]=s[i+1]; s[i+1]=letter;}
		else ;
	} }
	// next, I do the same for t:
		scanf("%s",t);
	for (j=0;j<=100;j++){
	for (i=0;t[i+1]!=0;i++){
		if (t[i]<t[i+1]){ letter=t[i]; t[i]=t[i+1]; t[i+1]=letter;}
		else ;
	} }
	// printf("%s\n",s); printf("%s\n",t);
	// Lastly, I compare s and t:
	j=0;
	for (i=0;j==0&&s[i]!=0;i++){
		if (s[i]>t[i]) j=1; 
			else{ 	if(s[i]<t[i]){ jud = 1; j=1;} 
					else ; }
	}
	if (jud==0) printf("No"); else printf("Yes");
	return 0;
}