Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
#include<stdlib.h>

int main()
{
    char day[5];
    int first,second;
    int flag1,flag2;


    gets(day);

    second=atoi(day)%100;
    first=(atoi(day)-second)/100;


    if(0<first && first<13)
    flag1=0;      //month or year
    else flag1=1;      //year only

   
    if(0<second && second<13)
    flag2=0;      //month or year
    else flag2=1;      //year only

    if(flag1 == 0 && flag2 == 0 )
    printf("AMBIGUOUS");
    else if(flag1 == 1 && flag2 == 1)
    printf("NA");
    else if(flag1 == 0 && flag2==1)
    printf("MMYY");
    else if(flag1 == 1 && flag2 == 0)
    printf("YYMM");

 
  

    return 0;
}