Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in C (GCC 9.2.1) (judge verdict: Wrong Answer)

#include<stdio.h>

int main(){
  long n,a,b,c;
  scanf("%ld%ld%ld%ld",&n,&a,&b,&c);
  char s[n+1][3];
  for(long i=1;i<=n;i++)scanf("%s",s[i]);
  char ans[n+1];
  
  for(long i=1;i<=n;i++){
    if(s[i][0]=='A'&&s[i][1]=='B'){
      if(a>=b){a-=1;b+=1;ans[i]='B';}else{b-=1;a+=1;ans[i]='A';}
    }
    if(s[i][0]=='A'&&s[i][1]=='C'){
      if(c>=a){c-=1;a+=1;ans[i]='A';}else{a-=1;c+=1;ans[i]='C';}
    }
    if(s[i][0]=='B'&&s[i][1]=='C'){
      if(b>=c){b-=1;c+=1;ans[i]='C';}else{c-=1;b+=1;ans[i]='B';}
    }
    if(a<0||b<0||c<0){printf("No");return 0;}
  }
  printf("Yes\n");
  for(long i=1;i<=n;i++){
    printf("%c\n",ans[i]);
  }
  return 0;
}