Problem:
Score : 300 points

Problem Statement

Takahashi is organizing a party.

At the party, each guest will receive one or more snack pieces.

Takahashi predicts that the number of guests at this party will be A or B.

Find the minimum number of pieces that can be evenly distributed to the guests in both of the cases predicted.

We assume that a piece cannot be divided and distributed to multiple guests.

Constraints

1 \leq A, B \leq 10^5

A \neq B

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the minimum number of pieces that can be evenly distributed to the guests in both of the cases with A guests and B guests.

Sample Input 1

2 3

Sample Output 1

6

When we have six snack pieces, each guest can take three pieces if we have two guests, and each guest can take two if we have three guests.

Sample Input 2

123 456

Sample Output 2

18696

Sample Input 3

100000 99999

Sample Output 3

9999900000

Solution in C (Clang 3.8.0) (judge verdict: Accepted)

#include <stdio.h>

int main(void) {
	long long a, b, temp, r,x;
	scanf("%d %d", &a, &b);
	x = a * b;
	if(b>a){
		temp = a;
		a = b;
		b = temp;
	}
	while((r=a%b)!=0){
    	a=b;
    	b=r;
    }
	printf("%ld\n", x / b);

	return 0;    
}