Problem:
Score: 300 points

Problem Statement

M-kun is a student in Aoki High School, where a year is divided into N terms.

There is an exam at the end of each term. According to the scores in those exams, a student is given a grade for each term, as follows:

For the first through (K-1)-th terms: not given.

For each of the K-th through N-th terms: the multiplication of the scores in the last K exams, including the exam in the graded term.

M-kun scored A_i in the exam at the end of the i-th term.

For each i such that K+1 \leq i \leq N, determine whether his grade for the i-th term is strictly greater than the grade for the (i-1)-th term.

Constraints

2 \leq N \leq 200000

1 \leq K \leq N-1

1 \leq A_i \leq 10^{9}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
A_1 A_2 A_3 \ldots A_N

Output

Print the answer in N-K lines.

The i-th line should contain Yes if the grade for the (K+i)-th term is greater than the grade for the (K+i-1)-th term, and No otherwise.

Sample Input 1

5 3
96 98 95 100 20

Sample Output 1

Yes
No

His grade for each term is computed as follows:

3-rd term: (96 \times 98 \times 95) = 893760

4-th term: (98 \times 95 \times 100) = 931000

5-th term: (95 \times 100 \times 20) = 190000

Sample Input 2

3 2
1001 869120 1001

Sample Output 2

No

Note that the output should be No if the grade for the 3-rd term is equal to the grade for the 2-nd term.

Sample Input 3

15 7
3 1 4 1 5 9 2 6 5 3 5 8 9 7 9

Sample Output 3

Yes
Yes
No
Yes
Yes
No
Yes
Yes

Solution in C (GCC 9.2.1) (judge verdict: Runtime Error)

#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#include <math.h>
#include <stdbool.h>

int ASC( void *a,  void *b) {
	return strcmp(*(const char **)a, *(const char **)b);//降順
}
int GCD(int a, int b) {	//最大公約数
	if (b == 0) return a;
	else return GCD(b, a % b);
}
int min(int a, int b ) {
	if (a < b) {
		return a;
	}
	else
		return b;
}
int max(int a, int b) {
	if (a < b)
		return b;
	else
		return a;
}
int main(void)
{
	int n, k, a[2010];
	scanf("%d%d",&n,&k);
	for (int i = 0; i < n; i++) {
		scanf("%d",&a[i]);
	}
	int ans = 1, ans2 = 1;
	for (int i = 0; i <= n - k; i++) {
		for (int j = 0; j < k; j++) {
			ans *= a[j+i];
		}
		if (i != 0) {
			if (ans > ans2)
				printf("Yes\n");
			else
				printf("No\n");
		}
		ans2 = ans;
		ans = 1;
	}
	
	return 0;
}//pd pdp