Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>
int cmp(const void *a,const void *b){
    if(*(int*)a>*(int*)b){return -1;}
    else if(*(int*)a<*(int*)b){return 1;}
    else {return 0;}
}
int min(int a,int b){

    if(a>=b){return b;}
    return a;
}

int main(void){
    //0000<=a<=9999
int a;
scanf("%d",&a);
int mn,yr;
mn=(a%10)+(((a/10)%10)*10);
yr=(a/10/10%10)+(a/10/10/10%10*10);
if(1<=mn&&mn<=12&&1<=yr&&yr<=12){printf("AMBIGUOUS");}
else if(1<=mn&&mn<=12){printf("MMYY");}
else if(1<=yr&&yr<=12){printf("YYMM");}
else {printf("NA");}

}