Problem:
Score : 100 points

Problem Statement

Takahashi has a strong stomach. He never gets a stomachache from eating something whose "best-by" date is at most X days earlier.
He gets a stomachache if the "best-by" date of the food is X+1 or more days earlier, though.

Other than that, he finds the food delicious if he eats it not later than the "best-by" date. Otherwise, he does not find it delicious.

Takahashi bought some food A days before the "best-by" date, and ate it B days after he bought it.

Write a program that outputs delicious if he found it delicious, safe if he did not found it delicious but did not get a stomachache either, and dangerous if he got a stomachache.

Constraints

1 ≤ X,A,B ≤ 10^9

Input

Input is given from Standard Input in the following format:

X A B

Output

Print delicious if Takahashi found the food delicious; print safe if he neither found it delicious nor got a stomachache; print dangerous if he got a stomachache.

Sample Input 1

4 3 6

Sample Output 1

safe

He ate the food three days after the "best-by" date. It was not delicious or harmful for him.

Sample Input 2

6 5 1

Sample Output 2

delicious

He ate the food by the "best-by" date. It was delicious for him.

Sample Input 3

3 7 12

Sample Output 3

dangerous

He ate the food five days after the "best-by" date. It was harmful for him.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
#include<stdlib.h>
#include<math.h>
#include<string.h>
typedef long long int ll;
void swap(ll *x,ll *y){ll temp;temp=*x;*x=*y;*y=temp;}
ll compare_asc(const void *a,const void *b){return *(ll*)a-*(ll*)b;}
ll compare_desc(const void *a,const void *b){return *(ll*)b-*(ll*)a;}
ll max(ll x,ll y){return x>y?x:y;}
ll min(ll x,ll y){return x>y?y:x;}
/*void qsort(配列のアドレス,配列のサイズ,sizeof(配列の型),比較関数(昇順or降順)) */

int main(){
    ll a,b,x;
    scanf("%lld %lld %lld",&x,&a,&b);

    ll day=b-a;
    if(a>=b)printf("delicious\n");
    else if(day<=x)printf("safe\n");
    else printf("dangerous\n");

    return 0;
}