Problem:
Score : 200 points

Problem Statement

Takahashi's house has only one socket.

Takahashi wants to extend it with some number of power strips, each with A sockets, into B or more empty sockets.

One power strip with A sockets can extend one empty socket into A empty sockets.

Find the minimum number of power strips required.

Constraints

All values in input are integers.

2 \leq A \leq 20

1 \leq B \leq 20

Input

Input is given from Standard Input in the following format:

A B

Output

Print the minimum number of power strips required.

Sample Input 1

4 10

Sample Output 1

3

3 power strips, each with 4 sockets, extend the socket into 10 empty sockets.

Sample Input 2

8 9

Sample Output 2

2

2 power strips, each with 8 sockets, extend the socket into 15 empty sockets.

Sample Input 3

8 8

Sample Output 3

1

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
#include <stdlib.h>
int main()
{
    int x,y,min,n=1;//存储两个整数
    scanf("%d%d",&x,&y);
//采取穷举的办法 n*x-n+1>=y那么穷举成功 另min=n
    while(n)
    {
        if(x==y){
            min=n;
            break;
        }
        else if(n*x-(n-1)<y)
        {
            min=n;
            break;
        }
        n++;
    }
    printf("%d\n",min);
    return 0;
}