Problem:
Score : 200 points

Problem Statement

You are given string S and T consisting of lowercase English letters.

Determine if S equals T after rotation.

That is, determine if S equals T after the following operation is performed some number of times:

Operation: Let S = S_1 S_2 ... S_{|S|}. Change S to S_{|S|} S_1 S_2 ... S_{|S|-1}.

Here, |X| denotes the length of the string X.

Constraints

2 \leq |S| \leq 100

|S| = |T|

S and T consist of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S equals T after rotation, print Yes; if it does not, print No.

Sample Input 1

kyoto
tokyo

Sample Output 1

Yes

In the first operation, kyoto becomes okyot.

In the second operation, okyot becomes tokyo.

Sample Input 2

abc
arc

Sample Output 2

No

abc does not equal arc after any number of operations.

Sample Input 3

aaaaaaaaaaaaaaab
aaaaaaaaaaaaaaab

Sample Output 3

Yes

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
#include <string.h>

int main(void) {
	char s[101] = {0}, t[101] = {0};
	int cnt = 0;
	
	scanf("%s", &s[0]);
	scanf("%s", &t[0]);
	
	for (int i = 0; i < strlen(s); i++) {
		if (s[0] == t[i]) {
			cnt++;
			for (int j = 1; j < strlen(t); j++) {
				if (s[j] == t[(i+j)%strlen(t)])
					cnt++;
			}
			if (cnt == strlen(s))
				goto end;
			else
				cnt = 0;
		}
	}
	
	end:
	printf(cnt == strlen(s) ? "Yes" : "No");
	
	return 0;
}