Problem:
Score : 200 points

Problem Statement

Find the number of palindromic numbers among the integers between A and B (inclusive).
Here, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.

Constraints

10000 \leq A \leq B \leq 99999

All input values are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the number of palindromic numbers among the integers between A and B (inclusive).

Sample Input 1

11009 11332

Sample Output 1

4

There are four integers that satisfy the conditions: 11011, 11111, 11211 and 11311.

Sample Input 2

31415 92653

Sample Output 2

612

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>

int main()
{
    int a, b, i, count;
    char str[6];
    scanf("%d%d", &a, &b);
    count = 0;
    for (i=a; i<=b; i++)
    {
        snprintf(str, 6, "%d", i);
        if (str[0] == str[4] && str[1] == str[3]) {
            count++;
        }
    }
    printf("%d\n", count);
    return 0;
}