Problem:
Score : 300 points

Problem Statement

Snuke has an integer sequence A of length N.

He will freely choose an integer b.
Here, he will get sad if A_i and b+i are far from each other.
More specifically, the sadness of Snuke is calculated as follows:

abs(A_1 - (b+1)) + abs(A_2 - (b+2)) + ... + abs(A_N - (b+N))

Here, abs(x) is a function that returns the absolute value of x.

Find the minimum possible sadness of Snuke.

Constraints

1 \leq N \leq 2 \times 10^5

1 \leq A_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

Print the minimum possible sadness of Snuke.

Sample Input 1

5
2 2 3 5 5

Sample Output 1

2

If we choose b=0, the sadness of Snuke would be abs(2-(0+1))+abs(2-(0+2))+abs(3-(0+3))+abs(5-(0+4))+abs(5-(0+5))=2.
Any choice of b does not make the sadness of Snuke less than 2, so the answer is 2.

Sample Input 2

9
1 2 3 4 5 6 7 8 9

Sample Output 2

0

Sample Input 3

6
6 5 4 3 2 1

Sample Output 3

18

Sample Input 4

7
1 1 1 1 2 3 4

Sample Output 4

6

Solution in C (GCC 5.4.1) (judge verdict: Time Limit Exceeded)

#define _USE_MATH_DEFINES
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>
#include <ctype.h>
#include <limits.h>
#define EPS 1e-10
#define sq(n) ((n)*(n))
#define rep(i,n) for(i=0;i<n;i++)
#define rev(i,n) for(i=n-1;i>=0;i--)
#define sort(a,n) qsort(a,n,sizeof(TYPE),cmp)
#define sort_r(a,n) qsort(a,n,sizeof(TYPE),cmp_r);
#define chsort(s,n) qsort(s,n,sizeof(char),cmp)
#define chsort_r(s,n) qsort(s,n,sizeof(char),char_cmp_r);
#define TYPE int
#define MEMSET(a) memset(a,0,sizeof(a))
long long mod=(long long)1e09+7;
int inf=1<<29;
long long llinf=1ll<<60;

int in(void){
    int i;scanf("%d",&i);
    return i;
}
long long llin(void){
    long long i;scanf("%lld",&i);
    return i;
}
double din(void){
    double i;scanf("%lf",&i);
    return i;
}
void chin(char s[]){
    scanf("%s",s);
}
void print(int a){
    printf("%d\n",a);
}
void llprint(long long a){
    printf("%lld\n",a);
}
void dprint(double a){
    printf("%.10f\n",a);
}
void print2(int a,int b){
    printf("%d %d\n",a,b);
}
long long max(long long a,long long b){
    return a>b?a:b;
}
long long min(long long a,long long b){
    return a<b?a:b;
}
int cmp(const void *a,const void *b){
    return *(TYPE *)a-*(TYPE *)b;
}
int cmp_r(const void *a,const void *b){
    return *(TYPE *)b-*(TYPE *)a;
}
int char_cmp(const void *a,const void *b){
    return strcmp(*(char **)a,*(char **)b);
}
int char_cmp_r(const void *a,const void *b){
    return strcmp(*(char **)b,*(char **)a);
}
void swap(int *a,int *b){
    int t=*a;
    *a=*b;
    *b=t;
}
long long gcd(long long x,long long y){
    return x%y?gcd(y,x%y):y;
}
long long lcm(long long x,long long y){
    return x/gcd(x,y)*y;
}

// write codes below this
// when you use 'sort',
// make sure TYPE macro is correct

int main(void){
    int n=in(),i;
    long long a[200000],j,l=llinf,r=-llinf,s=0,ans=llinf;
    rep(i,n){
        a[i]=in();
        l=min(l,a[i]-i-1);
        r=max(r,a[i]-i-1);
    }
    for(j=l;j<=r;j++){
        s=0;
        rep(i,n)s+=abs(a[i]-(j+i+1));
        ans=min(ans,s);
    }
    llprint(ans);
    return 0;
}