Problem:
Score : 200 points

Problem Statement

A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.

How many times will the ball make a bounce where the coordinate is at most X?

Constraints

1 \leq N \leq 100

1 \leq L_i \leq 100

1 \leq X \leq 10000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N X
L_1 L_2 ... L_{N-1} L_N

Output

Print the number of times the ball will make a bounce where the coordinate is at most X.

Sample Input 1

3 6
3 4 5

Sample Output 1

2

The ball will make a bounce at the coordinates 0, 3, 7 and 12, among which two are less than or equal to 6.

Sample Input 2

4 9
3 3 3 3

Sample Output 2

4

The ball will make a bounce at the coordinates 0, 3, 6, 9 and 12, among which four are less than or equal to 9.

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
int main()
{
  int n=0;
  int x=0;
  int i=0;
  int j=0;
  int k=0;
  int bound=0;
  scanf("%d%d",&n,&x);
  int array[n];
  int point[n+1];
  for(i;i<n;i++){
  scanf("%d",&array[i]);
  }
  for(j;j<n;j++)
  {
    point[j]=point[j-1]+array[j-1];
    if(j==0)
    {
      point[j]=0;
    }
  }
  for(k;k<n+1;k++)
  {
    if(point[k]<x||point[k]==x)
    {
      bound+=1;
    }
  }
  printf("%d",bound);
  return 0;
}