Problem:
Score : 200 points

Problem Statement

Raccoon is fighting with a monster.

The health of the monster is H.

Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i.
There is no other way to decrease the monster's health.

Raccoon wins when the monster's health becomes 0 or below.

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Constraints

1 \leq H \leq 10^9

1 \leq N \leq 10^5

1 \leq A_i \leq 10^4

All values in input are integers.

Input

Input is given from Standard Input in the following format:

H N
A_1 A_2 ... A_N

Output

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Sample Input 1

10 3
4 5 6

Sample Output 1

Yes

The monster's health will become 0 or below after, for example, using the second and third moves.

Sample Input 2

20 3
4 5 6

Sample Output 2

No

Sample Input 3

210 5
31 41 59 26 53

Sample Output 3

Yes

Sample Input 4

211 5
31 41 59 26 53

Sample Output 4

No

Solution in C (GCC 5.4.1) (judge verdict: Runtime Error)

#include <stdio.h>
int main()
{
    while(1)
    {
        int h, n, i, err;
        scanf("%d %d", &h, &n);
        int a[n];
        if (h>=1 && h<=1000000000 && n>=1 && n<=100000)
        {
            for (i=0; i<n; i++)
            {
                scanf("%d", &a[i]);
            }
            for (i=0; i<n; i++)
            {
                if (a[i]<1 || a[i]>10000)
                {
                    goto skip;
                }
            }
            for (i=0; i<n; i++)
            {
                n-=a[i];
            }
            if (n<=0)
            {
                printf("Yes\n");
            }
            else
            {
                printf("No\n");
            }
        }
        else
        {
skip:
            printf("Error\n");
        }
    }
    return 0;
}