Problem:
Score : 200 points

Problem Statement

The word internationalization is sometimes abbreviated to i18n.
This comes from the fact that there are 18 letters between the first i and the last n.

You are given a string s of length at least 3 consisting of lowercase English letters.
Abbreviate s in the same way.

Constraints

3 ≤ |s| ≤ 100 (|s| denotes the length of s.)

s consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s

Output

Print the abbreviation of s.

Sample Input 1

internationalization

Sample Output 1

i18n

Sample Input 2

smiles

Sample Output 2

s4s

Sample Input 3

xyz

Sample Output 3

x1z

Solution in C (GCC 9.2.1) (judge verdict: Wrong Answer)

#include<stdio.h>
int main(void){
  int i;
  char s[101];
  int ct=0;
  
  for(i=0;i<101;i++){
    s[i]=0;
  }
  
  for(i=0;i<101;i++){
    scanf("%c",&s[i]);
  }
  
  for(i=0;i<101;i++){
    if(s[i] != '0')ct++;
    else break;
  }
  
  printf("%c%d%c\n",s[0],ct-2,s[ct-1]);
  
  return 0;
}