Problem:
Score : 200 points

Problem Statement

Alice and Bob are controlling a robot. They each have one switch that controls the robot.

Alice started holding down her button A second after the start-up of the robot, and released her button B second after the start-up.

Bob started holding down his button C second after the start-up, and released his button D second after the start-up.

For how many seconds both Alice and Bob were holding down their buttons?

Constraints

0≤A<B≤100

0≤C<D≤100

All input values are integers.

Input

Input is given from Standard Input in the following format:

A B C D

Output

Print the length of the duration (in seconds) in which both Alice and Bob were holding down their buttons.

Sample Input 1

0 75 25 100

Sample Output 1

50

Alice started holding down her button 0 second after the start-up of the robot, and released her button 75 second after the start-up.

Bob started holding down his button 25 second after the start-up, and released his button 100 second after the start-up.

Therefore, the time when both of them were holding down their buttons, is the 50 seconds from 25 seconds after the start-up to 75 seconds after the start-up.

Sample Input 2

0 33 66 99

Sample Output 2

0

Alice and Bob were not holding their buttons at the same time, so the answer is zero seconds.

Sample Input 3

10 90 20 80

Sample Output 3

60

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
int main()
{
	int a,b,c,d,h;
	while(scanf("%d %d %d %d",&a,&b,&c,&d)!=EOF)
	{
		if(b<a)
		{
			h=a;
			a=b;
			b=h;
		}
		if(d<c)
		{
			h=c;
			c=b;
			b=h;
		}
		if(a>d||c>b)
		h=0;
		else if(a==d||c==b)
		h=1;
		else if(b>c&&c>a&&b<d)
		h=b-c;
		else if(a<d&&a>c&&d<b)
		h=d-a;
		else if(b>c&&a>c&&a<d&&b<d)
		h=b-a;
		else if(c>a&&d>a&&c<b&&d<b)
		h=d-c;
		printf("%d\n",h);
	}
	return 0;
}