Problem:
Score : 100 points

Problem Statement

You have three tasks, all of which need to be completed.

First, you can complete any one task at cost 0.

Then, just after completing the i-th task, you can complete the j-th task at cost |A_j - A_i|.

Here, |x| denotes the absolute value of x.

Find the minimum total cost required to complete all the task.

Constraints

All values in input are integers.

1 \leq A_1, A_2, A_3 \leq 100

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

Print the minimum total cost required to complete all the task.

Sample Input 1

1 6 3

Sample Output 1

5

When the tasks are completed in the following order, the total cost will be 5, which is the minimum:

Complete the first task at cost 0.

Complete the third task at cost 2.

Complete the second task at cost 3.

Sample Input 2

11 5 5

Sample Output 2

6

Sample Input 3

100 100 100

Sample Output 3

0

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
int main()
{
int a,b,c,max,d,min,e,f;
scanf("%d %d %d",&a,&b,&c);
  if(a>b && a>c){
  max=a;
  if(b>c) {d=b;
           min=c;} 
    else {d=c;
           min=b;} 
    
  }
  
  else if(b>a && b>c){
  max=b;
  if(a>c) {d=a;
           min=c;} 
    else {d=c;
           min=a;} 
  }

 else if(c>a && c>b){
  max=c;
  if(a>b) {d=a;
           min=b;} 
    else {d=b;
           min=a;} 
  }
e=max-d;
f=d-min;
  printf("%d",e+f);
return 0;
}