Problem:
Score : 300 points

Problem Statement

There are N people living on a number line.

The i-th person lives at coordinate X_i.

You are going to hold a meeting that all N people have to attend.

The meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.

Find the minimum total points of stamina the N people have to spend.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq X_i \leq 100

Input

Input is given from Standard Input in the following format:

N
X_1 X_2 ... X_N

Output

Print the minimum total stamina the N people have to spend.

Sample Input 1

2
1 4

Sample Output 1

5

Assume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.

Note that you can hold the meeting only at an integer coordinate.

Sample Input 2

7
14 14 2 13 56 2 37

Sample Output 2

2354

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
#include <string.h>
int main(void){
    int N,X[101];
    int max=0,min=100,Smin=10000,S;
    scanf("%d",&N);
    for (int i=0; i<N; i++) {
        scanf("%d",&X[i]);
        if(X[i]>max){
            max=X[i];
        }
        if(min>X[i]){
            min=X[i];
        }
    }
    for (int i=min; i<max; i++) {
        S=0;
        for (int j=0 ;X[j]!='\0' ; j++) {
            S+=(X[j]-i)*(X[j]-i);
        }
        if(S<Smin){
            Smin=S;
        }
    }
    printf("%d\n",Smin);
    return 0;
}