Problem:
Score : 200 points

Problem Statement

Given is an integer N. Find the number of digits that N has in base K.

Notes

For information on base-K representation, see Positional notation - Wikipedia.

Constraints

All values in input are integers.

1 \leq N \leq 10^9

2 \leq K \leq 10

Input

Input is given from Standard Input in the following format:

N K

Output

Print the number of digits that N has in base K.

Sample Input 1

11 2

Sample Output 1

4

In binary, 11 is represented as 1011.

Sample Input 2

1010101 10

Sample Output 2

7

Sample Input 3

314159265 3

Sample Output 3

18

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

/* ABC156_B
    Stuartyg */

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdbool.h>


int main(void){
        int num,base_num; /*n,kのこと*/
        double ans = 0;

        scanf("%d %d",&num,&base_num);

        ans = log(num)/log(base_num);/*logの公式より底の変換*/
        printf("%d",(int)ans+1); /*型キャスト*/

        return 0;
}