Problem:
Score : 200 points

Problem Statement

The word internationalization is sometimes abbreviated to i18n.
This comes from the fact that there are 18 letters between the first i and the last n.

You are given a string s of length at least 3 consisting of lowercase English letters.
Abbreviate s in the same way.

Constraints

3 ≤ |s| ≤ 100 (|s| denotes the length of s.)

s consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s

Output

Print the abbreviation of s.

Sample Input 1

internationalization

Sample Output 1

i18n

Sample Input 2

smiles

Sample Output 2

s4s

Sample Input 3

xyz

Sample Output 3

x1z

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

/*  6_2
    Y_Aizaki    */

#include <stdio.h>
#include <string.h>

#define SIZE 120

int main(void){
    char word[SIZE]; // 文字列
    int wordlen, mwordlen; // 文字列の長さ(null込み)、挟むべき文字列中身の長さ

    fgets(word, SIZE, stdin);
    wordlen = strlen(word);
    mwordlen = wordlen - 3;

    printf("%c", word[0]);

    while (mwordlen/10 >0)
    {
        printf("%c", '0'+ (mwordlen/10));
        mwordlen %= 10;
    }
    printf("%c", '0'+ mwordlen);
    
    printf("%c\n", word[wordlen-2]);

    return 0;
}