Problem:
Score : 200 points

Problem Statement

There are N apple trees in a row. People say that one of them will bear golden apples.

We want to deploy some number of inspectors so that each of these trees will be inspected.

Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector deployed under the i-th tree (1 \leq i \leq N) will inspect the trees with numbers between i-D and i+D (inclusive).

Find the minimum number of inspectors that we need to deploy to achieve the objective.

Constraints

All values in input are integers.

1 \leq N \leq 20

1 \leq D \leq 20

Input

Input is given from Standard Input in the following format:

N D

Output

Print the minimum number of inspectors that we need to deploy to achieve the objective.

Sample Input 1

6 2

Sample Output 1

2

We can achieve the objective by, for example, placing an inspector under Tree 3 and Tree 4.

Sample Input 2

14 3

Sample Output 2

2

Sample Input 3

20 4

Sample Output 3

3

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

/* ex4_1
   kento_titech*/
#include<stdio.h>
int main(void){
    int n,d,num_people;
    scanf("%d %d",&n,&d);
    if(n%(2*d+1)==0){//1人の監視できる最大本数は2d+1本
        num_people=n/(2*d+1);//nが2d+1で割り切れるとき
    }else{
        num_people=n/(2*d+1)+1;//割り切れないときは余りをさらにひとりが監視
    }
    printf("%d\n",num_people);
    return 0;
}