Problem:
Score : 200 points

Problem Statement

The word internationalization is sometimes abbreviated to i18n.
This comes from the fact that there are 18 letters between the first i and the last n.

You are given a string s of length at least 3 consisting of lowercase English letters.
Abbreviate s in the same way.

Constraints

3 ≤ |s| ≤ 100 (|s| denotes the length of s.)

s consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s

Output

Print the abbreviation of s.

Sample Input 1

internationalization

Sample Output 1

i18n

Sample Input 2

smiles

Sample Output 2

s4s

Sample Input 3

xyz

Sample Output 3

x1z

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

/* ABC069_B
    Stuartyg */

#include <stdio.h>
#include <string.h>


int main(void){
        char str[150]; //sのこと.これだけあれば安心
        int length; //sの間に入っている文字数を求めるための変数
        scanf("%s",str);//標準入力からの受取り

        length = strlen(str)-2; //strの間に入っている文字数
        printf("%c%d%c\n",str[0],length,str[length+1]); //0始まりなので終わりの文字は(length+1)番目
        return 0;
}