Problem:
Score : 300 points

Problem Statement

There are N people living on a number line.

The i-th person lives at coordinate X_i.

You are going to hold a meeting that all N people have to attend.

The meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.

Find the minimum total points of stamina the N people have to spend.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq X_i \leq 100

Input

Input is given from Standard Input in the following format:

N
X_1 X_2 ... X_N

Output

Print the minimum total stamina the N people have to spend.

Sample Input 1

2
1 4

Sample Output 1

5

Assume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.

Note that you can hold the meeting only at an integer coordinate.

Sample Input 2

7
14 14 2 13 56 2 37

Sample Output 2

2354

Solution in C (Clang 3.8.0) (judge verdict: Accepted)

#include <stdio.h>

int main(){
    int size;
    scanf("%d",&size);
    int arr[size];

    for(int i=0;i<size;i++){
        scanf("%d",&arr[i]);
    }
    int sum=0;
    for(int i=0;i<size;i++){
        sum+=arr[i];
    }
    int average;
    average=sum/size;
    //printf("%d\n",average);
    sum=0;
    for(int i=0;i<size;i++){
        sum+=(arr[i]-average)*(arr[i]-average);
    }
    int min=sum;
    sum=0;
    for(int i=0;i<size;i++){
        sum+=(arr[i]-average+1)*(arr[i]-average+1);
    }
    if(sum<min) min=sum;
    sum=0;

    for(int i=0;i<size;i++){
        sum+=(arr[i]-average-1)*(arr[i]-average-1);
    }
    if(sum<min) min=sum;


    printf("%d",min);

    return 0;
}