Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in C (Clang 3.8.0) (judge verdict: Wrong Answer)

#include <stdio.h>
#include <string.h>
#include <limits.h>
#include <stdlib.h>
#include <math.h>

int main(void)
{
	int n, a, b, c, d;
	int i, j;
	int sum;
	int work;
	int flg;
	char str[300000];
	
	scanf("%d%d%d%d%d", &n, &a, &b, &c, &d);
	
	scanf("%s", str);
	
	flg = 1;
	
	if(c > d) {
		for(i = b; i < d; i++) {
			if( (str[i] == '.') && (str[i + 1] == '.') && (str[i + 2] == '.') ) {
				flg = 0;
			}
		}
		if(flg) {
			if( (str[d - 2] == '#') || (str[d] == '#') ) {
				printf("No\n");
				return 0;
			}
		} else {
			for(i = a; i < c; i++) {
				if( (str[i] == '#') && (str[i + 1] == '#') ) {
					printf("No\n");
					return 0;
				}
			}
			for(i = b; i < d; i++) {
				if( (str[i] == '#') && (str[i + 1] == '#') ) {
					printf("No\n");
					return 0;
				}
			}
		}
	} else {
		for(i = a; i < c; i++) {
			if( (str[i] == '#') && (str[i + 1] == '#') ) {
				printf("No\n");
				return 0;
			}
		}
		
		for(i = b; i < d; i++) {
			if( (str[i] == '#') && (str[i + 1] == '#') ) {
				printf("No\n");
				return 0;
			}
		}
	}
	
	printf("Yes\n");
	
	return 0;
}