Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>

int main(void) {
	int a,x,y;
	
	x = y = 0;
	
	scanf("%d",&a);
    if(a >= 99)x = a / 100;
if(a != 0000 || x != 0){	
	
	if(x == 1){
	    y = a % (x*10);
	}else{
	    y = a % x;
	}
	
//	printf("%d %d",x,y);
	if(x == 0 || y == 0){
	    printf("NA");
	}else if(x >= 13 && y >= 13){
	    printf("NA");
	}else if(x <= 12 && y <=12){
	    printf("AMBIGUOUS");
	}else if(x <=12 && y >=13){
	    printf("MMYY");
	}else{
	    printf("YYMM");
	}
}else{
    printf("NA");
}
	return 0;
}