Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

# include <stdio.h>
#include <math.h>

int main(){
    int mat[3][3];
    int n;

    for(int i=0; i<3; ++i){
        for(int j=0; j< 3; ++j)
            scanf("%d", &mat[i][j]);
    }
    scanf("%d", &n);
    int sortidos=0;

    for(int h = 0; h <n; ++h){
        int bixin;
        scanf("%d", &bixin);
        for(int i=0; i< 3; ++i){
            for(int j=0; j<3; ++j){
                if(bixin== mat[i][j])
                    mat[i][j]=-1;

            }
        }
    }

    int vdd = 0;

    //linha
    for(int i=0; i<3; ++i){
    int linha = 0;
        for(int j=0; j<3; ++j){
            if (mat[i][j]==-1)
                linha += 1;
        }
        if (linha == 3){
            vdd = 1;
        //   printf("###\n");
        }
    }
    // COLUNA
    for(int j=0; j <3; ++j){
        int coluna =0;
        for(int i =0; i<3; ++i){
            if(mat[i][j]==-1)
                coluna+=1;
        }
        if(coluna == 3){
            vdd=1;
            //printf("###\n");
        }
    }


    if (mat[0][0]==-1 && mat[1][1]==-1 && mat[2][2]== -1){
        vdd = 1;
        //printf("--###\n");
    }
    if (mat[0][2] == -1 && mat[1][1] == -1 && mat[2][0] == -1){
        vdd = 1;
        //printf("---------###\n");
    }


    if(vdd==1)
        printf("Yes\n");
    else
        printf("No\n");
    return 0;
}