Problem:
Score : 100 points

Problem Statement

We have A balls with the string S written on each of them and B balls with the string T written on each of them.

From these balls, Takahashi chooses one with the string U written on it and throws it away.

Find the number of balls with the string S and balls with the string T that we have now.

Constraints

S, T, and U are strings consisting of lowercase English letters.

The lengths of S and T are each between 1 and 10 (inclusive).

S \not= T

S=U or T=U.

1 \leq A,B \leq 10

A and B are integers.

Input

Input is given from Standard Input in the following format:

S T
A B
U

Output

Print the answer, with space in between.

Sample Input 1

red blue
3 4
red

Sample Output 1

2 4

Takahashi chose a ball with red written on it and threw it away.
Now we have two balls with the string S and four balls with the string T.

Sample Input 2

red blue
5 5
blue

Sample Output 2

5 4

Takahashi chose a ball with blue written on it and threw it away.
Now we have five balls with the string S and four balls with the string T.

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>
#include <limits.h>

#define REP(i,n) for(i=0;i<n;i++)

#define MAX 1000000
#define MOD 1000000007

long long fac[MAX], finv[MAX], inv[MAX];

//prototype declaration
int i_in();
long long ll_in();
double d_in();
char c_in();
void s_in(char *s);
void i_out(int i);
void ll_out(long long i);
void d_out(double i);
void c_out(char c);
void s_out(char *s);
int gcd(int a, int b);
int lcm(int a, int b);
long long ll_gcd(long long a, long long b);
long long ll_lcm(long long a, long long b);
void sort_asc(int *a);
void sort_desc(int *a);
int asc(const void *a, const void *b);
int desc(const void *a, const void *b);
void ll_sort_asc(long long *a);
void ll_sort_desc(long long *a);
int ll_asc(const void *a, const void *b);
int ll_desc(const void *a, const void *b);
double to_deg(double rad);
double distance(int xi, int yi, int xj, int yj);
void initComb();
long long comb(int n, int k);

//main function
int main() {
    int a, b;
    char s[11], t[11], u[11];
    s_in(s);
    s_in(t);
    a = i_in();
    b = i_in();
    if (strcmp(s, u) == 0) printf("%d %d\n", a - 1, b);
    else printf("%d %d\n", a, b - 1);
    return 0;
}

//body function
int i_in() {
    int i;
    scanf("%d", &i);
    return i;
}

long long ll_in() {
    long long i;
    scanf("%lld", &i);
    return i;
}

double d_in() {
    double i;
    scanf("%lf", &i);
    return i;
}

char c_in() {
    char c;
    scanf("%c", &c);
    return c;
}

void s_in(char *s) {
    scanf("%s", s);
}

void i_out(int i) {
    printf("%d\n", i);
}

void ll_out(long long i) {
    printf("%lld\n", i);
}

void d_out(double i) {
    printf("%lf\n", i);
}

void c_out(char c) {
    printf("%c\n", c);
}

void s_out(char *s) {
    printf("%s\n", s);
}

/*
    int型の最大公約数
*/

int gcd(int a, int b) {
    int r;

    if (a < b) {
        r = a;
        a = b;
        b = r;
    }

    r = a % b;
    while (r != 0) {
        a = b;
        b = r;
        r = a % b;
    }

    return b;
}

/*
    int型の最小公倍数
*/

int lcm(int a, int b) {
    int r = ll_gcd(a, b);
    a /= r;
    return a * b;
}

/*
    long long型の最大公約数
*/

long long ll_gcd(long long a, long long b) {
    long long r;

    if (a < b) {
        r = a;
        a = b;
        b = r;
    }

    r = a % b;
    while (r != 0) {
        a = b;
        b = r;
        r = a % b;
    }

    return b;
}

/*
    long long型の最小公倍数
*/

long long ll_lcm(long long a, long long b) {
    long long r = ll_gcd(a, b);
    a /= r;
    return a * b;
}

/*
    int型の昇順ソート
*/

void sort_asc(int *a) {
    qsort(a, sizeof(a)/sizeof(int), sizeof(int), asc);
}

/*
    int型の降順ソート
*/

void sort_desc(int *a) {
    qsort(a, sizeof(a)/sizeof(int), sizeof(int), desc);
}

/*
    int型の昇順用比較関数
*/

int asc(const void *a, const void *b) {
    return *(int *)a - *(int *)b;
}

/*
    int型の降順用比較関数
*/

int desc(const void *a, const void *b) {
    return *(int *)b - *(int *)a;
}

/*
    long long型の昇順ソート
*/

void ll_sort_asc(long long *a) {
    qsort(a, sizeof(a)/sizeof(long long), sizeof(long long), ll_asc);
}

/*
    long long型の降順ソート
*/

void ll_sort_desc(long long *a) {
    qsort(a, sizeof(a)/sizeof(long long), sizeof(long long), ll_desc);
}

/*
    long long型の昇順用比較関数
*/

int ll_asc(const void *a, const void *b) {
    long long *A = (long long *)a;
    long long *B = (long long *)b;
    if (*A > *B) return 1;
    else if (*A < *B) return -1;
    else return 0;
}

/*
    long long型の降順用比較関数
*/

int ll_desc(const void *a, const void *b) {
    long long *A = (long long *)a;
    long long *B = (long long *)b;
    if (*A < *B) return 1;
    else if (*A > *B) return -1;
    else return 0;
}

/*
    弧度法を度数法に
*/

double to_deg(double rad) {
    return rad * 180.0 / (atan(1.0) * 4.0);
}

/*
    二点間の距離
*/

double distance(int xi, int yi, int xj, int yj) {
    return hypot(xj - xi, yj - yi);
}

/*
    組み合わせ用配列の初期化
*/

void initComb() {
    fac[0] = fac[1] = 1;
    finv[0] = finv[1] = 1;
    inv[1] = 1;
    for (int i = 2; i < MAX; i++){
        fac[i] = fac[i - 1] * i % MOD;
        inv[i] = MOD - inv[MOD%i] * (MOD / i) % MOD;
        finv[i] = finv[i - 1] * inv[i] % MOD;
    }
}

/*
    nCkの組み合わせ計算
*/

long long comb(int n, int k){
    if (n < k) return 0;
    if (n < 0 || k < 0) return 0;
    return fac[n] * (finv[k] * finv[n - k] % MOD) % MOD;
}