Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
int main(void){

  int N=0,count=0,num=0;
  scanf("%d",&N);
  
  for(int i=1;i<=N;i++){
    if(i%2==1){
    	for(int j=1;j<=N;j++){
        	if(i/j > 0){
            	count++;
            }
        }
      if(count == 8){
      	num++;
      }
      count=0;
    }
  }
  
  printf("%d",num);

 return 0;
}