Problem:
Score : 200 points

Problem Statement

Given are integers a,b,c and d.
If x and y are integers and a \leq x \leq b and c\leq y \leq d hold, what is the maximum possible value of x \times y?

Constraints

-10^9 \leq a \leq b \leq 10^9

-10^9 \leq c \leq d \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

a b c d

Output

Print the answer.

Sample Input 1

1 2 1 1

Sample Output 1

2

If x = 1 and y = 1 then x \times y = 1.
If x = 2 and y = 1 then x \times y = 2.
Therefore, the answer is 2.

Sample Input 2

3 5 -4 -2

Sample Output 2

-6

The answer can be negative.

Sample Input 3

-1000000000 0 -1000000000 0

Sample Output 3

1000000000000000000

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <string.h>


int main(){
  long long int a,b,c,d,n,m;
  scanf("%lld %lld %lld %lld",&a,&b,&c,&d);
  if(b>=0 && d>=0){
    if(a<0 && c<0){
      n=a*c;
      m=b*d;
      if(n>m)	
	printf("%lld\n",n);
      else
	printf("%lld\n",m);
    }
    else
      printf("%lld\n",b*d);
  }
  else if(a>=0 && d<=0)
    printf("%lld\n",a*d);
  else if(c>=0 && b<=0)
    printf("%lld\n",b*c);
  else
    printf("%lld\n",a*c);
  return 0;
}