Problem:
Score : 500 points

Problem Statement

There are N points on the 2D plane, i-th of which is located on (x_i, y_i).
There can be multiple points that share the same coordinate.
What is the maximum possible Manhattan distance between two distinct points?

Here, the Manhattan distance between two points (x_i, y_i) and (x_j, y_j) is defined by |x_i-x_j| + |y_i-y_j|.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq x_i,y_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
x_1 y_1
x_2 y_2
:
x_N y_N

Output

Print the answer.

Sample Input 1

3
1 1
2 4
3 2

Sample Output 1

4

The Manhattan distance between the first point and the second point is |1-2|+|1-4|=4, which is maximum possible.

Sample Input 2

2
1 1
1 1

Sample Output 2

0

Solution in C (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <stdio.h>
#include <stdlib.h>

int main (void) {
    int n;
    scanf("%d", &n);
    long int x, y, minz = 2000000000, maxz = 0, minw = 1000000000, maxw = 0;
    for (int i = 0; i < n; i++) {
        scanf("%ld %ld", &x, &y);
        if (x + y < minz) {
            minz = x + y;
        }
        if (x + y > maxz) {
            maxz = x + y;
        }
        if (x - y < minw) {
            minw = x - y;
        }
        if (x - y > maxw) {
            maxw = x - y;
        }
    }

    if (maxz - minz > maxw - minw) {
        printf("%ld\n", maxz - minz);
    } else {
        printf("%ld\n", maxw - minw);
    }
    return 0;
}