Problem:
Score : 500 points

Problem Statement

Snuke, who loves animals, built a zoo.

There are N animals in this zoo. They are conveniently numbered 1 through N, and arranged in a circle.
The animal numbered i (2≤i≤N-1) is adjacent to the animals numbered i-1 and i+1. Also, the animal numbered 1 is adjacent to the animals numbered 2 and N, and the animal numbered N is adjacent to the animals numbered N-1 and 1.

There are two kinds of animals in this zoo: honest sheep that only speak the truth, and lying wolves that only tell lies.

Snuke cannot tell the difference between these two species, and asked each animal the following question: "Are your neighbors of the same species?" The animal numbered i answered s_i. Here, if s_i is o, the animal said that the two neighboring animals are of the same species, and if s_i is x, the animal said that the two neighboring animals are of different species.

More formally, a sheep answered o if the two neighboring animals are both sheep or both wolves, and answered x otherwise.
Similarly, a wolf answered x if the two neighboring animals are both sheep or both wolves, and answered o otherwise.

Snuke is wondering whether there is a valid assignment of species to the animals that is consistent with these responses. If there is such an assignment, show one such assignment. Otherwise, print -1.

Constraints

3 ≤ N ≤ 10^{5}

s is a string of length N consisting of o and x.

Input

The input is given from Standard Input in the following format:

N
s

Output

If there does not exist an valid assignment that is consistent with s, print -1.
Otherwise, print an string t in the following format. The output is considered correct if the assignment described by t is consistent with s.

t is a string of length N consisting of S and W.

If t_i is S, it indicates that the animal numbered i is a sheep. If t_i is W, it indicates that the animal numbered i is a wolf.

Sample Input 1

6
ooxoox

Sample Output 1

SSSWWS

For example, if the animals numbered 1, 2, 3, 4, 5 and 6 are respectively a sheep, sheep, sheep, wolf, wolf, and sheep, it is consistent with their responses. Besides, there is another valid assignment of species: a wolf, sheep, wolf, sheep, wolf and wolf.

Let us remind you: if the neiboring animals are of the same species, a sheep answers o and a wolf answers x. If the neiboring animals are of different species, a sheep answers x and a wolf answers o.

Sample Input 2

3
oox

Sample Output 2

-1

Print -1 if there is no valid assignment of species.

Sample Input 3

10
oxooxoxoox

Sample Output 3

SSWWSSSWWS

Solution in C (Clang 3.8.0) (judge verdict: Runtime Error)

#include <stdio.h>
int main () {
long int N;
int a[10000],b[10000],c,i,j;
c=0;
scanf("%ld", &N);
char S[N+1],T[N+1];
scanf("%s", S);
for(i=1;i<=N;i++){
if (S[i-1]=='o') a[i]=1;
if (S[i-1]=='x') a[i]=-1;
}
 
b[1]=1, b[2]=1;
for(i=1;i<=N-2;i++){
if(b[i+1]*a[i+1]==1) b[i+2]=b[i];
if(b[i+1]*a[i+1]==-1) b[i+2]=-b[i];
}
if(a[N]*b[N]==b[N-1]*b[1] && a[1]*b[1]==b[N]*b[2]) {
for(i=1;i<=N;i++){
if(b[i]==1) T[i-1]='S';
if(b[i]==-1) T[i-1]='W';
}
printf("%s\n",T);
c=c+1;
}
 
b[1]=1, b[2]=-1;
for(i=1;i<=N-2;i++){
if(b[i+1]*a[i+1]==1) b[i+2]=b[i];
if(b[i+1]*a[i+1]==-1) b[i+2]=-b[i];
}
if(a[N]*b[N]==b[N-1]*b[1] && a[1]*b[1]==b[N]*b[2]&&c==0) {
for(i=1;i<=N;i++){
if(b[i]==1) T[i-1]='S';
if(b[i]==-1) T[i-1]='W';
}
printf("%s\n",T);
c=c+1;
}
 
b[1]=-1, b[2]=1;
for(i=1;i<=N-2;i++){
if(b[i+1]*a[i+1]==1) b[i+2]=b[i];
if(b[i+1]*a[i+1]==-1) b[i+2]=-b[i];
}
if(a[N]*b[N]==b[N-1]*b[1] && a[1]*b[1]==b[N]*b[2]&&c==0) {
for(i=1;i<=N;i++){
if(b[i]==1) T[i-1]='S';
if(b[i]==-1) T[i-1]='W';
}
printf("%s\n",T);
c=c+1;
}
 
b[1]=-1, b[2]=-1;
for(i=1;i<=N-2;i++){
if(b[i+1]*a[i+1]==1) b[i+2]=b[i];
if(b[i+1]*a[i+1]==-1) b[i+2]=-b[i];
}
if(a[N]*b[N]==b[N-1]*b[1] && a[1]*b[1]==b[N]*b[2]&&c==0) {
for(i=1;i<=N;i++){
if(b[i]==1) T[i-1]='S';
if(b[i]==-1) T[i-1]='W';
}
printf("%s\n",T);
c=c+1;
}
if (c==0) printf("%d\n",c-1);
return 0;
}