Problem:
Score : 200 points

Problem Statement

Given are strings s and t of length N each, both consisting of lowercase English letters.

Let us form a new string by alternating the characters of S and the characters of T, as follows: the first character of S, the first character of T, the second character of S, the second character of T, ..., the N-th character of S, the N-th character of T. Print this new string.

Constraints

1 \leq N \leq 100

|S| = |T| = N

S and T are strings consisting of lowercase English letters.

Input

Input is given from Standard Input in the following format:

N
S T

Output

Print the string formed.

Sample Input 1

2
ip cc

Sample Output 1

icpc

Sample Input 2

8
hmhmnknk uuuuuuuu

Sample Output 2

humuhumunukunuku

Sample Input 3

5
aaaaa aaaaa

Sample Output 3

aaaaaaaaaa

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
#include<string.h>
#include<math.h>
#include<stdlib.h>
int main()
{
    int n,i,j=0,k=0;
    char op[100],ch[100],sh[200];
    scanf("%d",&n);
    scanf("\n");
    for(i=0;i<n;i++)
    scanf("%c",&op[i]);
    op[i]='\0';
    getchar( );
    for(i=0;i<n;i++)
    scanf("%c",&ch[i]);
    ch[i]='\0';
    for(i=0;i<2*n;i++){
        if(i%2==0)
        {
            sh[i]=op[k];
            k++;
        }
        else
        {
            sh[i]=ch[j];
            j++;
        }
    }
    sh[i]='\0';
    printf("%s",sh);
    return 0;
}