Problem:
Score : 200 points

Problem Statement

Takahashi has two positive integers A and B.

It is known that A plus B equals N.
Find the minimum possible value of "the sum of the digits of A" plus "the sum of the digits of B" (in base 10).

Constraints

2 ≤ N ≤ 10^5

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

Print the minimum possible value of "the sum of the digits of A" plus "the sum of the digits of B".

Sample Input 1

15

Sample Output 1

6

When A=2 and B=13, the sums of their digits are 2 and 4, which minimizes the value in question.

Sample Input 2

100000

Sample Output 2

10

Solution in C (Clang 3.8.0) (judge verdict: Wrong Answer)

#include <stdio.h>

int main(){
    int e;//入力記録
    int x;//i格納
    int er;//合計-i格納
    int is;//合計
    int es;//合計２
    int data;//最小値
    is=0;
    es=0;
    data=100000;
    while(e<=100000&&e>=2){
        scanf("%d",&e);
    }
        for(int i=2;i<e-1;i++){
            is=0;
            es=0;
            x=i;
            er=e-i;
            while(x>0){
                is=is+x%10;
                x=x/10;
            }
            while(er>0){
                es=es+er%10;
                er=er/10;
            }
            if(is+es<data){
                data=is+es;
            }
        }
    printf("%d\n",data);
    return 0;
}