Problem:
Score : 200 points

Problem Statement

Given are strings s and t of length N each, both consisting of lowercase English letters.

Let us form a new string by alternating the characters of S and the characters of T, as follows: the first character of S, the first character of T, the second character of S, the second character of T, ..., the N-th character of S, the N-th character of T. Print this new string.

Constraints

1 \leq N \leq 100

|S| = |T| = N

S and T are strings consisting of lowercase English letters.

Input

Input is given from Standard Input in the following format:

N
S T

Output

Print the string formed.

Sample Input 1

2
ip cc

Sample Output 1

icpc

Sample Input 2

8
hmhmnknk uuuuuuuu

Sample Output 2

humuhumunukunuku

Sample Input 3

5
aaaaa aaaaa

Sample Output 3

aaaaaaaaaa

Solution in C (GCC 5.4.1) (judge verdict: Time Limit Exceeded)

#include<stdio.h>
int main()
{int n;
scanf("%d",&n);
char i,a[n+1],b[n+1];
for(i=0;i<n+1;i++)
	{scanf("%c",&a[i]);}
for(i=0;i<n+1;i++)
	{scanf("%c",&b[i]);}
char c[2*n+1];
for(i=0;i<2*n+2;i++)
	{if(i%2==0)
    {
        if(i==0)
        {
            c[i]=a[i];
        }
        else
        c[i]=a[i/2];
    }
    else if(i%2!=0)
    {c[i]=b[(i-1)/2];}}
for(i=0;i<2*n+2;i++)
{printf("%c",c[i]);}
return 0;}