Problem:
Score : 200 points

Problem Statement

Find the number of palindromic numbers among the integers between A and B (inclusive).
Here, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.

Constraints

10000 \leq A \leq B \leq 99999

All input values are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the number of palindromic numbers among the integers between A and B (inclusive).

Sample Input 1

11009 11332

Sample Output 1

4

There are four integers that satisfy the conditions: 11011, 11111, 11211 and 11311.

Sample Input 2

31415 92653

Sample Output 2

612

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>

int main(void){
    int A,B,ans,da45,da21,db45,db21;
    scanf("%d %d",&A,&B);
    ans = (B - A) / 100;
    db45 = B /10000 + ((B%10000)/1000)*10;
    db21 = B %100;
    da45 = A / 10000 + ((A%10000)/1000)*10;
    da21 = A % 100;
    if(db45 - db21 < 0 && da21 > db21){
        ans++;
    }else if(da45 - da21 >= 0){
        ans++;
    }
    printf("%d\n",ans);
    return 0;
}