Problem:
Score : 200 points

Problem Statement

There is a square in the xy-plane. The coordinates of its four vertices are (x_1,y_1),(x_2,y_2),(x_3,y_3) and (x_4,y_4) in counter-clockwise order.
(Assume that the positive x-axis points right, and the positive y-axis points up.)

Takahashi remembers (x_1,y_1) and (x_2,y_2), but he has forgot (x_3,y_3) and (x_4,y_4).

Given x_1,x_2,y_1,y_2, restore x_3,y_3,x_4,y_4. It can be shown that x_3,y_3,x_4 and y_4 uniquely exist and have integer values.

Constraints

|x_1|,|y_1|,|x_2|,|y_2| \leq 100

(x_1,y_1) ≠ (x_2,y_2)

All values in input are integers.

Input

Input is given from Standard Input in the following format:

x_1 y_1 x_2 y_2

Output

Print x_3,y_3,x_4 and y_4 as integers, in this order.

Sample Input 1

0 0 0 1

Sample Output 1

-1 1 -1 0

(0,0),(0,1),(-1,1),(-1,0) is the four vertices of a square in counter-clockwise order.
Note that (x_3,y_3)=(1,1),(x_4,y_4)=(1,0) is not accepted, as the vertices are in clockwise order.

Sample Input 2

2 3 6 6

Sample Output 2

3 10 -1 7

Sample Input 3

31 -41 -59 26

Sample Output 3

-126 -64 -36 -131

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

/* ex3-1
    kas056 */

#include<stdio.h>
#include<math.h>

//構造体生成
typedef struct{
    int x_elem;
    int y_elem;
}point;

point shift_point(point p1, point p2){
    point p;
    int lenx, leny;

    /*正方形なので、二点間の距離のx成分、
    y成分で次の点を計算できる。*/

    //差分を符号付きで求める。
    lenx = p2.x_elem - p1.x_elem;
    leny = p2.y_elem - p1.y_elem;

    //直近の点からy軸、x軸成分の差分を加えて求める
    p.x_elem = p2.x_elem + (-leny);
    p.y_elem = p2.y_elem + lenx;
    return p;
}

int main(void){
    int x1, y1,x2,y2, x3,y3,x4,y4;
    point point1, point2, point3, point4;


    //入力読み込み
    scanf("%d %d %d %d", &x1,&y1,&x2,&y2);

    //点1、2に代入
    point1.x_elem = x1;
    point1.y_elem = y1;
    point2.x_elem = x2;
    point2.y_elem = y2;

    
    //point3,4を計算、代入。
    point3 = shift_point(point1, point2);
    point4 = shift_point(point2, point3);

    //各値代入。
    x3 = point3.x_elem;
    y3 = point3.y_elem;
    x4 = point4.x_elem;
    y4 = point4.y_elem;

    //出力
    printf("%d %d %d %d\n", x3,y3,x4,y4);
    return 0;
}