Problem:
Score : 100 points

Problem Statement

Takahashi has K 500-yen coins. (Yen is the currency of Japan.)
If these coins add up to X yen or more, print Yes; otherwise, print No.

Constraints

1 \leq K \leq 100

1 \leq X \leq 10^5

Input

Input is given from Standard Input in the following format:

K X

Output

If the coins add up to X yen or more, print Yes; otherwise, print No.

Sample Input 1

2 900

Sample Output 1

Yes

Two 500-yen coins add up to 1000 yen, which is not less than X = 900 yen.

Sample Input 2

1 501

Sample Output 2

No

One 500-yen coin is worth 500 yen, which is less than X = 501 yen.

Sample Input 3

4 2000

Sample Output 3

Yes

Four 500-yen coins add up to 2000 yen, which is not less than X = 2000 yen.

Solution in C (Clang 10.0.0) (judge verdict: Accepted)

#include <stdio.h>
int main(){
	
	int K,X;
	int yen = 500;
	
	scanf("%d %d", &K,&X);
	
	if(K*yen>=X)
	{
		printf("Yes\n");
	}
	
	if(K*yen<X)
	{
		printf("No\n");
	}
	return 0;
	
}