Problem:
Score : 100 points

Problem Statement

Given is an integer N.

Takahashi chooses an integer a from the positive integers not greater than N with equal probability.

Find the probability that a is odd.

Constraints

1 \leq N \leq 100

Input

Input is given from Standard Input in the following format:

N

Output

Print the probability that a is odd.
Your output will be considered correct when its absolute or relative error from the judge's output is at most 10^{-6}.

Sample Input 1

4

Sample Output 1

0.5000000000

There are four positive integers not greater than 4: 1, 2, 3, and 4. Among them, we have two odd numbers: 1 and 3. Thus, the answer is \frac{2}{4} = 0.5.

Sample Input 2

5

Sample Output 2

0.6000000000

Sample Input 3

1

Sample Output 3

1.0000000000

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>

int main(void) {
    double n;
    int eve = 0;
    int odd = 0;
    double t = 0;
    
    scanf("%lf", &n);

    if (n < 0 || n > 100) {
        puts("error");
        return 0;
    }

    for (int k = 1; k <= n; k++) {
        if (k%2 == 1) {
            odd++;
        } else {
            eve++;
        }
    }
    t = odd/n;

    printf("%.10f\n", t);

}