Problem:
Score : 500 points

Problem Statement

Takahashi and Aoki will play a game. They will repeatedly play it until one of them have N wins in total.

When they play the game once, Takahashi wins with probability A %, Aoki wins with probability B %, and the game ends in a draw (that is, nobody wins) with probability C %.
Find the expected number of games that will be played, and print it as follows.

We can represent the expected value as P/Q with coprime integers P and Q.
Print the integer R between 0 and 10^9+6 (inclusive) such that R \times Q \equiv P\pmod {10^9+7}.
(Such an integer R always uniquely exists under the constraints of this problem.)

Constraints

1 \leq N \leq 100000

0 \leq A,B,C \leq 100

1 \leq A+B

A+B+C=100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N A B C

Output

Print the expected number of games that will be played, in the manner specified in the statement.

Sample Input 1

1 25 25 50

Sample Output 1

2

Since N=1, they will repeat the game until one of them wins.
The expected number of games played is 2.

Sample Input 2

4 50 50 0

Sample Output 2

312500008

C may be 0.

Sample Input 3

1 100 0 0

Sample Output 3

1

B may also be 0.

Sample Input 4

100000 31 41 28

Sample Output 4

104136146

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
#include<stdlib.h>
#include<stdint.h>
#include<inttypes.h>

typedef int32_t i32;
typedef int64_t i64;

const i32 mod = 1000000007;

i32 mod_pow (i32 r, i32 n) {
  i32 t = 1;
  i32 s = r;
  while (n > 0) {
    if (n & 1) t = (i64) t * s % mod;
    s = (i64) s * s % mod;
    n >>= 1;
  }
  return t;
}

i32 inv (i32 a) {
  return mod_pow (a, mod - 2);
}

i32 *fact = NULL;
i32 *iFact = NULL;
void init_fact (const i32 n) {
  fact = (i32 *) calloc (n + 1, sizeof (i32));
  fact[0] = 1;
  for (i32 i = 1; i <= n; ++i) {
    fact[i] = (i64) i * fact[i - 1] % mod;
  }
  iFact = (i32 *) calloc (n + 1, sizeof (i32));
  iFact[n] = inv (fact[n]);
  for (i32 i = n - 1; i >= 0; --i) {
    iFact[i] = (i64) (i + 1) * iFact[i + 1] % mod;
  }
}

i32 comb (i32 n, i32 k) {
  if (!(0 <= k && k <= n)) return 0;
  return (i64) fact[n] * iFact[k] % mod * iFact[n - k] % mod;
}

void run (void) {
  i32 n, a, b, c;
  scanf ("%" SCNi32 "%" SCNi32 "%" SCNi32 "%" SCNi32, &n, &a, &b, &c);
  i32 p = (i64) a * inv (a + b) % mod;
  i32 q = (1 + mod - p) % mod;
  init_fact (2 * n);
  i64 ans = 0;
  for (i32 i = 0, t = 1, x = mod_pow (p, n), y = mod_pow (q, n); i < n; ++i, x = (i64) x * q % mod, y = (i64) y * p % mod) {
    i64 prob = (i64) comb (n + i - 1, i) * (x + y);
    t = (t + (i64) mod * mod - prob) % mod;
    ans += t;
  }
  ans = (ans + n) % mod * 100 % mod * inv (100 - c) % mod;
  printf ("%" PRIi64 "\n", ans);
}

int main (void) {
  run();
  return 0;
}