Problem:
Score : 200 points

Problem Statement

You are given strings s and t, consisting of lowercase English letters.
You will create a string s' by freely rearranging the characters in s.
You will also create a string t' by freely rearranging the characters in t.
Determine whether it is possible to satisfy s' < t' for the lexicographic order.

Notes

For a string a = a_1 a_2 ... a_N of length N and a string b = b_1 b_2 ... b_M of length M, we say a < b for the lexicographic order if either one of the following two conditions holds true:

N < M and a_1 = b_1, a_2 = b_2, ..., a_N = b_N.

There exists i (1 \leq i \leq N, M) such that a_1 = b_1, a_2 = b_2, ..., a_{i - 1} = b_{i - 1} and a_i < b_i. Here, letters are compared using alphabetical order.

For example, xy < xya and atcoder < atlas.

Constraints

The lengths of s and t are between 1 and 100 (inclusive).

s and t consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s
t

Output

If it is possible to satisfy s' < t', print Yes; if it is not, print No.

Sample Input 1

yx
axy

Sample Output 1

Yes

We can, for example, rearrange yx into xy and axy into yxa. Then, xy < yxa.

Sample Input 2

ratcode
atlas

Sample Output 2

Yes

We can, for example, rearrange ratcode into acdeort and atlas into tslaa. Then, acdeort < tslaa.

Sample Input 3

cd
abc

Sample Output 3

No

No matter how we rearrange cd and abc, we cannot achieve our objective.

Sample Input 4

w
ww

Sample Output 4

Yes

Sample Input 5

zzz
zzz

Sample Output 5

No

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>
int sort1(const void *a, const void *b){
  if(*(char *)a > *(char *)b){
    return -1;
  }else if(*(char *)a == *(char *)b){
    return 0;
  }
  return 1;
}

int sort2(const void *a, const void *b){
  if(*(char *)a < *(char *)b){
    return -1;
  }else if(*(char *)a == *(char *)b){
    return 0;
  }
  return 1;
}

int main(void){
  char s[101], t[101];
  int l, f=0, i;
  scanf("%s",s);
  scanf("%s",t);
  qsort((void *)s, strlen(s), sizeof(s[0]), sort2);
  qsort((void *)t, strlen(t), sizeof(t[0]), sort1);
  l = strlen(s);
  if(l>strlen(t)) l=strlen(t);
  for(i=0;i<l;i++){
    if(s[i]>t[i]){f=1; break;}
    else if(s[i]<t[i]){f=2; break;}
  } 
  if((f==0 && strlen(s)<strlen(t)) || f==2) printf("Yes\n");
  else printf("No\n");
  return 0;
}