Problem:
Score : 300 points

Problem Statement

Hearing that energy drinks increase rating in those sites, Takahashi decides to buy up M cans of energy drinks.

There are N stores that sell energy drinks. In the i-th store, he can buy at most B_i cans of energy drinks for A_i yen (the currency of Japan) each.

What is the minimum amount of money with which he can buy M cans of energy drinks?

It is guaranteed that, in the given inputs, a sufficient amount of money can always buy M cans of energy drinks.

Constraints

All values in input are integers.

1 \leq N, M \leq 10^5

1 \leq A_i \leq 10^9

1 \leq B_i \leq 10^5

B_1 + ... + B_N \geq M

Input

Input is given from Standard Input in the following format:

N M
A_1 B_1
A_2 B_2
\vdots
A_N B_N

Output

Print the minimum amount of money with which Takahashi can buy M cans of energy drinks.

Sample Input 1

2 5
4 9
2 4

Sample Output 1

12

With 12 yen, we can buy one drink at the first store and four drinks at the second store, for the total of five drinks. However, we cannot buy 5 drinks with 11 yen or less.

Sample Input 2

4 30
6 18
2 5
3 10
7 9

Sample Output 2

130

Sample Input 3

1 100000
1000000000 100000

Sample Output 3

100000000000000

The output may not fit into a 32-bit integer type.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
#include <stdlib.h>

typedef struct pair{
  int x,y;
}point;

int compare_int(const void *a,const void *b){
  return (*(point*)a).x > (*(point*)b).x;
}

int main(void){
  int N,M;
  scanf("%d%d",&N,&M);

  point A[N];
  for(int i = 0;i < N;i++) scanf("%d%d",&A[i].x,&A[i].y);

  qsort(A,N,sizeof(point),compare_int);

  int cnt = 0;
  long long money = 0;  
  for(int i = 0;;i++){
    if(cnt+A[i].y < M){
      cnt += A[i].y;
      money += (long long)A[i].y*A[i].x;
    }else{
      money += (long long )(M-cnt)*A[i].x;
      break;
    }
  }

  printf("%lld\n",money);

  return 0;
}