Problem:
Search II

You are given a sequence of n integers S and a sequence of different q integers T. Write a program which outputs C, the number of integers in T which are also in the set S.

Input

In the first line n is given. In the second line, n integers are given. In the third line q is given. Then, in the fourth line, q integers are given.

Output

Print C in a line.

Constraints

Elements in S is sorted in ascending order

n ≤ 100000

q ≤ 50000

0 ≤ an element in S ≤ 109

0 ≤ an element in T ≤ 109

Sample Input 1

5
1 2 3 4 5
3
3 4 1

Sample Output 1

3

Sample Input 2

3
1 2 3
1
5

Sample Output 2

0

Sample Input 3

5
1 1 2 2 3
2
1 2

Sample Output 3

2

Notes

Solution in C (judge verdict: Accepted)

#include<stdio.h>
int A[1000000], n;

int binarySearch(int key){
  int left = 0;
  int right =  n;
  int mid;

  while(left<right){
    mid = (left +right)/ 2;
    if(key == A[mid]) return 1;
    if(key > A[mid]) left = mid +1;//右半分を操作
    else if(key<A[mid])right = mid;//左半分を操作
  }
  return 0;
}

int main(){
  int i ,q,key, sum =0;

  scanf("%d",&n);//要素数を入力
  for(i=0; i<n; i++){
    scanf("%d", &A[i]);
  }
  scanf("%d", &q);
  for(i=0;i<q;i++){
    scanf("%d", &key);
    if(binarySearch(key)) sum++;
  }
  printf("%d\n",sum);

  return 0;

  }