Problem:
Score : 200 points

Problem Statement

Takahashi loves gold coins. He gains 1000 happiness points for each 500-yen coin he has and gains 5 happiness points for each 5-yen coin he has. (Yen is the currency of Japan.)

Takahashi has X yen. If he exchanges his money so that he will gain the most happiness points, how many happiness points will he earn?

(We assume that there are six kinds of coins available: 500-yen, 100-yen, 50-yen, 10-yen, 5-yen, and 1-yen coins.)

Constraints

0 \leq X \leq 10^9

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print the maximum number of happiness points that can be earned.

Sample Input 1

1024

Sample Output 1

2020

By exchanging his money so that he gets two 500-yen coins and four 5-yen coins, he gains 2020 happiness points, which is the maximum number of happiness points that can be earned.

Sample Input 2

0

Sample Output 2

0

He is penniless - or yenless.

Sample Input 3

1000000000

Sample Output 3

2000000000

He is a billionaire - in yen.

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
 
int main(void){
  int x;
  scanf("%d",&x);
  int fiveHundred;
  int oneHundred;
  int fifty;
  int ten;
  int five;
  int one;
  fiveHundred = x/500;
  x%=500;
  oneHundred = x/100;
  x%=100;
  fifty = x/50;
  x%=50;
  ten = x/10;
  x%=10;
  five = x/5;
  x%=5;
  one = x;
  printf("%d",fiveHundred*1000+oneHundred*100+fifty*50+ten*10+five*10+one);
  return 0;
}