Problem:
Score : 300 points

Problem Statement

You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

1 \leq |S| \leq 2 \times 10^5

|S| = |T|

S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S and T can be made equal, print Yes; otherwise, print No.

Sample Input 1

azzel
apple

Sample Output 1

Yes

azzel can be changed to apple, as follows:

Choose e as c_1 and l as c_2. azzel becomes azzle.

Choose z as c_1 and p as c_2. azzle becomes apple.

Sample Input 2

chokudai
redcoder

Sample Output 2

No

No sequences of operation can change chokudai to redcoder.

Sample Input 3

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu

Sample Output 3

Yes

Solution in C (Clang 3.8.0) (judge verdict: Time Limit Exceeded)

#include <stdio.h>
#include <string.h>

int main(void){
    char S[200001];
    char T[200001];
    memset(&S,'\0',sizeof(S));
    memset(&T,'\0',sizeof(T));
    scanf("%s",S);
    scanf("%s",T);
    
    int size = strlen(S);

    char tmp;
    char tmpT;

    for(int i = 0;i<size;i++){
        if(S[i] != T[i]){
            tmp = S[i];
            // tmpT = T[i];
            // printf("%c\n",tmpS);
            // printf("%c\n",tmpT);
            for(int j = 0;j<size;j++){
                // printf("S %s\n",S);
                if(S[j] == tmp){
                    S[j] = T[i];
                    // printf("S[j] %c j %d\n",S[j],j);
                    continue;
                }
                if(S[j] == T[i]){
                    S[j] = tmp;
                    // printf("S[j] %c j %d\n",S[j],j);
                }
            }
        }
    }
    if(strcmp(S,T) == 0){
        printf("Yes\n");
        return 0;
    }
    printf("No\n");
    // printf("S %s\n",S);
    // printf("T %s\n",T);
    return 0;
}