Problem:
Score : 200 points

Problem Statement

We have a permutation p = {p_1,\ p_2,\ ...,\ p_n} of {1,\ 2,\ ...,\ n}.

Print the number of elements p_i (1 < i < n) that satisfy the following condition:

p_i is the second smallest number among the three numbers p_{i - 1}, p_i, and p_{i + 1}.

Constraints

All values in input are integers.

3 \leq n \leq 20

p is a permutation of {1,\ 2,\ ...,\ n}.

Input

Input is given from Standard Input in the following format:

n
p_1 p_2 ... p_n

Output

Print the number of elements p_i (1 < i < n) that satisfy the condition.

Sample Input 1

5
1 3 5 4 2

Sample Output 1

2

p_2 = 3 is the second smallest number among p_1 = 1, p_2 = 3, and p_3 = 5. Also, p_4 = 4 is the second smallest number among p_3 = 5, p_4 = 4, and p_5 = 2. These two elements satisfy the condition.

Sample Input 2

9
9 6 3 2 5 8 7 4 1

Sample Output 2

5

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>

int main(void){
   int p[25],o=0,n;
   scanf("%d",&n);
   for(int i=0;i<=n-1;i++){
       scanf("%d",&p[i]);
   }
   for(int i=1;i<=n-2;i++){
       if(p[i-1]-p[i]<=0 && p[i]-p[i+1]<=0){
           o++;
       }else if(p[i-1]-p[i]>=0 && p[i]-p[i+1]>=0){
           o++;
       }
       if(p[i-1]==p[i]&&p[i]==p[i+1]){
           o--;
       }
   }
   
   printf("%d",o);
}