Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C (Clang 3.8.0) (judge verdict: Time Limit Exceeded)

//Atcoder-Begginer-Contest
//2018/8/18
//B

#include<stdio.h>

int main(void)
{
  int i;
  int N;
  int res;

  scanf("%d",&N);
  res = 1;
  for(i=3;i<=N;i+2){
    if(N%i==0){
      res++;
    }
  }
  printf("%d\n",res);
  return 0;
}