Problem:
Score : 100 points

Problem Statement

Takahashi has K 500-yen coins. (Yen is the currency of Japan.)
If these coins add up to X yen or more, print Yes; otherwise, print No.

Constraints

1 \leq K \leq 100

1 \leq X \leq 10^5

Input

Input is given from Standard Input in the following format:

K X

Output

If the coins add up to X yen or more, print Yes; otherwise, print No.

Sample Input 1

2 900

Sample Output 1

Yes

Two 500-yen coins add up to 1000 yen, which is not less than X = 900 yen.

Sample Input 2

1 501

Sample Output 2

No

One 500-yen coin is worth 500 yen, which is less than X = 501 yen.

Sample Input 3

4 2000

Sample Output 3

Yes

Four 500-yen coins add up to 2000 yen, which is not less than X = 2000 yen.

Solution in C (Clang 3.8.0) (judge verdict: Wrong Answer)

#include <stdio.h>

int main(void){

    int n, count=0;

    scanf("%d", &n);

    char s[n+2];

    scanf("%s", &s);

    for(int i=0;i<n+1;i++){
        if(s[i]=='A'){
            i++;
            if(s[i]=='B'){
                i++;
                if(s[i]=='C'){
                    count++;
                    i++;
                }else{
                    i++;
                }
            }else{
                i++;
            }
        }
    }

    printf("%d", count);
}