Problem:
Score : 300 points

Problem Statement

In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0.
You are given a sequence h=\{h_1,h_2,h_3,......\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:

Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.

Find the minimum number of watering operations required to satisfy the condition.

Constraints

1 \leq N \leq 100

0 \leq h_i \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
h_1 h_2 h_3 ...... h_N

Output

Print the minimum number of watering operations required to satisfy the condition.

Sample Input 1

4
1 2 2 1

Sample Output 1

2

The minimum number of watering operations required is 2.
One way to achieve it is:

Perform the operation with (l,r)=(1,3).

Perform the operation with (l,r)=(2,4).

Sample Input 2

5
3 1 2 3 1

Sample Output 2

5

Sample Input 3

8
4 23 75 0 23 96 50 100

Sample Output 3

221

Solution in C (GCC 9.2.1) (judge verdict: Runtime Error)

#include<stdio.h>
int main()
{
  int N;
  int ans=0;
  int h[100]={};
  scanf("%d",&N);
        for(int i=0;i<N;i++) scanf("%d",&h[i]);
  for(int c=0;c<=100000;c++)
  {
  {
    for(int i=0;i<N;i++)
    {
      if(h[i]>0)
      {
        for(int j=1;j<N-j;j++)
        {
          if(h[i+j]==0)
          {
            for(int k=i;k<=i+j-1;k++)
            {
              h[k]--;
            }
            ans++;
          }
        }
      }
    }
             
  }
  }
        printf("%d",ans);
      return 0;
}