Problem:
Score : 200 points

Problem Statement

Let S(n) denote the sum of the digits in the decimal notation of n.
For example, S(101) = 1 + 0 + 1 = 2.

Given an integer N, determine if S(N) divides N.

Constraints

1 \leq N \leq 10^9

Input

Input is given from Standard Input in the following format:

N

Output

If S(N) divides N, print Yes; if it does not, print No.

Sample Input 1

12

Sample Output 1

Yes

In this input, N=12.
As S(12) = 1 + 2 = 3, S(N) divides N.

Sample Input 2

101

Sample Output 2

No

As S(101) = 1 + 0 + 1 = 2, S(N) does not divide N.

Sample Input 3

999999999

Sample Output 3

Yes

Solution in C (GCC 5.4.1) (judge verdict: Runtime Error)

#include <stdio.h>
 
int tenzyou(int x){
  int j,ten = 1;
  for(j = 1; j <= x; j++)
    ten = ten * 10;
  return ten;
}
 
int main(void){
	int s,n,ten;
  	scanf("%d",&n);
  	int i = 1;
  	while(i < 10){
      ten = tenzyou(i);
      if(n % ten != n){
      	s = s + n % ten;
        n = n - s;
      }
      i++;
    }
  	if(n % s == 0)
      printf("Yes\n");
  	else
      printf("No\n");
  	return 0;
}