Problem:
Score : 400 points

Problem Statement

You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

In the i-th operation, you replace every element whose value is B_{i} with C_{i}.

For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

All values in input are integers.

1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}

B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:

N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}

Output

Print Q integers S_{i} to Standard Output in the following format:

S_{1}
S_{2}
\vdots
S_{Q}

Note that S_{i} may not fit into a 32-bit integer.

Sample Input 1

4
1 2 3 4
3
1 2
3 4
2 4

Sample Output 1

11
12
16

Initially, the sequence A is 1,2,3,4.

After each operation, it becomes the following:

2, 2, 3, 4

2, 2, 4, 4

4, 4, 4, 4

Sample Input 2

4
1 1 1 1
3
1 2
2 1
3 5

Sample Output 2

8
4
4

Note that the sequence A may not contain an element whose value is B_{i}.

Sample Input 3

2
1 2
3
1 100
2 100
100 1000

Sample Output 3

102
200
2000

Solution in C (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <stdio.h>
#include <stdlib.h>

typedef long long int ll;

int compare_ints(const void* a, const void* b)
{
    int arg1 = *(const int*)a;
    int arg2 = *(const int*)b;
 
    if (arg1 < arg2) return -1;
    if (arg1 > arg2) return 1;
    return 0;
}

int	main(void)
{
  	int	n;
  	int	a[100001];
  	int	q;
  	int	b[100001];
  	int	c[100001];
  	int	i;
  	int	j;
  	ll	s;
  
  	s = 0;
  	scanf("%d\n", &n);
  	for(i=0; i<n; i++)
    {
      	scanf("%d", &a[i]);
      	s += a[i];
    }
    
    qsort(a, n, sizeof(int), compare_ints);
    
  	scanf("%d\n", &q);
  	for(j=0; j<q; j++)
    {
      	scanf("%d %d\n", &b[j], &c[j]);
    }
  
  	for(j=0; j<q; j++)
    {
        for(i=0; i<n; i++)
        {
		  	if (a[i] == b[j])
    	    {
        	  	s = s + c[j] - a[i];
    	        a[i] = c[j];
        	}
        	else if (a[i+1] > b[j])
        	{
        	    break ;
        	}
        }
      	printf("%lld\n", s);
    }
    return (0);
}