Problem:
Score : 200 points

Problem Statement

The word internationalization is sometimes abbreviated to i18n.
This comes from the fact that there are 18 letters between the first i and the last n.

You are given a string s of length at least 3 consisting of lowercase English letters.
Abbreviate s in the same way.

Constraints

3 ≤ |s| ≤ 100 (|s| denotes the length of s.)

s consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s

Output

Print the abbreviation of s.

Sample Input 1

internationalization

Sample Output 1

i18n

Sample Input 2

smiles

Sample Output 2

s4s

Sample Input 3

xyz

Sample Output 3

x1z

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

/* ex6_2
    sak_Citrus*/

#include <stdio.h>

int main(void){
    //|S|の最大値は100なのでnull文字を考慮して101枠確保
    char string[101];
    char *pointer = string;
    //挟まれた文字数をカウント
    int counter = 0;
    scanf("%s",pointer);

    //1文字目を出力してポインタをズラす
    putchar(*pointer++);
    //ポインタをずらしてもnull文字じゃなければカウントを増やす（2文字目を数えずに最後の文字をカウントすることにする）
    while(*(++pointer) != '\0')counter++;

    printf("%d",counter);
    //ポインタがnull文字の所を指しているので1文字分戻してから出力
    putchar(*(--pointer));
    printf("\n");

    return 0;
}