Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in C (Clang 10.0.0) (judge verdict: Accepted)

#include <stdio.h>

int main(){
  int arr[101][101];
  int flag[101][101];
  for(int i=0;i<3;i++){
    for(int j=0;j<3;j++){
      flag[i][j]=0;
    }
  }
  for(int i=0;i<3;i++){
    for(int j=0;j<3;j++){
      scanf("%d",&arr[i][j]);
    }
  }
  int a;
  scanf("%d",&a);
  for(int i=0;i<a;i++){
    int x;
    scanf("%d",&x);
    for(int j=0;j<3;j++){
      for(int k=0;k<3;k++){
        if(x==arr[j][k])
          flag[j][k]=1;
    }
  }
}
int flg=0;
for(int i=0;i<3;i++){
  if(flag[0][i]&&flag[1][i]&&flag[2][i]){
    flg=1;
  }
}
for(int i=0;i<3;i++){
  if(flag[i][0]&&flag[i][1]&&flag[i][2]){
    flg=1;
  }
}
if(flag[0][0]&&flag[1][1]&&flag[2][2]){
  flg=1;

}if(flag[0][2]&&flag[1][1]&&flag[2][0]){
  flg=1;
}
(flg)?puts("Yes"):puts("No");
  return 0;
}