Problem:
Score : 200 points

Problem Statement

The word internationalization is sometimes abbreviated to i18n.
This comes from the fact that there are 18 letters between the first i and the last n.

You are given a string s of length at least 3 consisting of lowercase English letters.
Abbreviate s in the same way.

Constraints

3 ≤ |s| ≤ 100 (|s| denotes the length of s.)

s consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s

Output

Print the abbreviation of s.

Sample Input 1

internationalization

Sample Output 1

i18n

Sample Input 2

smiles

Sample Output 2

s4s

Sample Input 3

xyz

Sample Output 3

x1z

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

/* ex6_1.12
   tamayama */

#include<stdio.h>
#define SIZE 100

int main(void){
    char str1[SIZE];    /*文字列の配列を用意*/
    int i;
    int count=0;
    char first;
    char last;

    for(i=0;i<SIZE;i++){    /*ヌル文字を挿入*/
        str1[i] = '\0';
    }

    scanf("%s",str1);    /*入力された文字数をカウントする*/
    for(i=0;i<SIZE;i++){
        if(str1[i] != '\0'){
            count++;
        }
    }
    first = str1[0];    /*最初の文字*/
    last = str1[count-1];    /*最後の文字*/
    printf("%c%d%c\n",first,count-2,last);    /*真ん中の文字数は、（全体の文字数）-2*/
    return 0;
}