Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
int main(void)
{
 
    int a,b,c;
    int d=0;
    int ans=0;
    scanf("%d",&a);
//    if(a<105)
//    {
//       printf("0");return 0;
//    }

    for(b=105; b<=a; b+=2)
    {
        for(c=1;c<=b;c++)
        {
            if(b%c==0)
               { d++;}
        }

        if(d==8)
           { ans++;}
        d=0;
    }
    printf("%d",ans);
return 0;
}