Problem:
Score : 200 points

Problem Statement

There are N rabbits, numbered 1 through N.

The i-th (1≤i≤N) rabbit likes rabbit a_i.
Note that no rabbit can like itself, that is, a_i≠i.

For a pair of rabbits i and j (i＜j), we call the pair (i，j) a friendly pair if the following condition is met.

Rabbit i likes rabbit j and rabbit j likes rabbit i.

Calculate the number of the friendly pairs.

Constraints

2≤N≤10^5

1≤a_i≤N

a_i≠i

Input

The input is given from Standard Input in the following format:

N
a_1 a_2 ... a_N

Output

Print the number of the friendly pairs.

Sample Input 1

4
2 1 4 3

Sample Output 1

2

There are two friendly pairs: (1，2) and (3，4).

Sample Input 2

3
2 3 1

Sample Output 2

0

There are no friendly pairs.

Sample Input 3

5
5 5 5 5 1

Sample Output 3

1

There is one friendly pair: (1，5).

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>

int main (){
	int i;
		int tab [10];
		int N;
		int buf;
		int count;
		
		scanf("%d",&N);
		count=0;
			for ( i=0 ; i<N ; i++)
			{
				scanf("%d",&buf);
				tab[i]=buf;
			};
			
			for ( i=1 ; i<N ; i++)
			{
				if ((tab[i]!=tab[i+1]) && (tab[i]>tab[i+1]))
				{
					count=count+1;
					i=i+1;
				}
				else
				{
					count= count + 0;
				}
			};
			printf("%d \n",count);
return 0;
}