Problem:
Score : 200 points

Problem Statement

Determine if an N-sided polygon (not necessarily convex) with sides of length L_1, L_2, ..., L_N can be drawn in a two-dimensional plane.

You can use the following theorem:

Theorem: an N-sided polygon satisfying the condition can be drawn if and only if the longest side is strictly shorter than the sum of the lengths of the other N-1 sides.

Constraints

All values in input are integers.

3 \leq N \leq 10

1 \leq L_i \leq 100

Input

Input is given from Standard Input in the following format:

N
L_1 L_2 ... L_N

Output

If an N-sided polygon satisfying the condition can be drawn, print Yes; otherwise, print No.

Sample Input 1

4
3 8 5 1

Sample Output 1

Yes

Since 8 < 9 = 3 + 5 + 1, it follows from the theorem that such a polygon can be drawn on a plane.

Sample Input 2

4
3 8 4 1

Sample Output 2

No

Since 8 \geq 8 = 3 + 4 + 1, it follows from the theorem that such a polygon cannot be drawn on a plane.

Sample Input 3

10
1 8 10 5 8 12 34 100 11 3

Sample Output 3

No

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
int main() {
  int N;
  scanf("%d", &N);
  int L[10];
  int i,j; /* インデックス */
  for (i = 0; i < N; ++i) {
    scanf("%d",&L[i]);
  }

  int temp;
  for (i = 0; i < N ; ++i) {
    for	(j = i + 1; j < N; ++j) {
      if (L[i] < L[j]) {
        temp = L[i];
        L[i] = L[j];
        L[j] = temp;
      }
    }
  }

  int sum = 0;
  for (i = 1; i < N; ++i) {
    sum += L[i];
  }

  if (L[0] >= sum) {
    printf("No\n");
  } else {
    printf("Yes\n");
  }

  return 0;
}