Problem:
Score : 200 points

Problem Statement

Given are a positive integer N and a string S of length N consisting of lowercase English letters.

Determine whether the string is a concatenation of two copies of some string.
That is, determine whether there is a string T such that S = T + T.

Constraints

1 \leq N \leq 100

S consists of lowercase English letters.

|S| = N

Input

Input is given from Standard Input in the following format:

N
S

Output

If S is a concatenation of two copies of some string, print Yes; otherwise, print No.

Sample Input 1

6
abcabc

Sample Output 1

Yes

Let T = abc, and S = T + T.

Sample Input 2

6
abcadc

Sample Output 2

No

Sample Input 3

1
z

Sample Output 3

No

Solution in C (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <stdio.h>
int main(){
	
	int n;
	scanf("%d\n", &n);
	
	char str[n];
	scanf("%s", &str);
	int count = 0;
	
	for (int i=0; i<n/2; i++){
	if (str[i] == str[i+(n/2)]){
		count++; 
		}
	}
	if (count == n/2 && n != 1){
		printf("Yes");
	}
	else {
		printf("No");
	}
	
	return 0;
}