Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main() {
	int i,t;
	int k;
	scanf("%d", &k);
	if (135 <= k && k < 189) {
		t = 1;
	}
	else if (189 <= k) {
		t = 2;
	}
	else {
		t = 0;
	}

	if (k <= 104) {
		printf("0");
	}
	else if (105 <= k && k < 165) {
		t = t + 1;
		printf("%d", t);
	}
	else if (165 <= k && k < 195) {
		t = t + 2;
		printf("%d", t);
	}
	else if (195 <= k) {
		t = t + 3;
		printf("%d", t);
	}
	return 0;
}