Problem:
Score : 300 points

Problem Statement

Takahashi is organizing a party.

At the party, each guest will receive one or more snack pieces.

Takahashi predicts that the number of guests at this party will be A or B.

Find the minimum number of pieces that can be evenly distributed to the guests in both of the cases predicted.

We assume that a piece cannot be divided and distributed to multiple guests.

Constraints

1 \leq A, B \leq 10^5

A \neq B

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the minimum number of pieces that can be evenly distributed to the guests in both of the cases with A guests and B guests.

Sample Input 1

2 3

Sample Output 1

6

When we have six snack pieces, each guest can take three pieces if we have two guests, and each guest can take two if we have three guests.

Sample Input 2

123 456

Sample Output 2

18696

Sample Input 3

100000 99999

Sample Output 3

9999900000

Solution in C (Clang 3.8.0) (judge verdict: Runtime Error)

#include<stdio.h>
int yaku(int,int);
int main(void){
int A,B;
  scanf("%d %d",&A,&B);
  int s=yaku(A,B);
  int a=A/s;
  int b=B/s;
  printf("%d",a*b*s);
  return 0;
}
  
  int yaku(int C,int D){
    if(C<=D){
      for(int i=C/2;i>0;i--){
        if(C%i==0&&D%i==0)return i;
      }
    }
    else {
      for(int i=D/2;i>0;i--){
        if(C%i==0&&D%i==0)return i;
      }
    }
    }