Problem:
Simultaneous Equation

Write a program which solve a simultaneous equation:

ax + by = c

dx + ey = f

The program should print x and y for given a, b, c, d, e and f (-1,000 ≤ a, b, c, d, e, f ≤ 1,000). You can suppose that given equation has a unique solution.

Input

The input consists of several data sets, 1 line for each data set. In a data set, there will be a, b, c, d, e, f separated by a single space. The input terminates with EOF.

Output

For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.

Sample Input 1

1 2 3 4 5 6
2 -1 -2 -1 -1 -5

Output for the Sample Input 1

-1.000 2.000
1.000 4.000

Sample Input 2

2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27

Output for the Sample Input 2

0.000 3.000
0.000 3.000

Solution in C (judge verdict: Time Limit Exceeded)

#include<stdio.h>
int main(void){
	int a,b,c,d,e,f;
	double x,y;
	while(scanf("%d%d%d%d%d%d",&a,&b,&c,&d,&e,&f)){
	if(b*d-a*e==0)y=0;
	else y=(c*d-a*f)/(b*d-a*e);
	if(c*e-b*f==0)x=0;
	else x=(a*e-b*d)/(c*e-b*f);
	
	
	printf("%.3f %.3f\n",((int) x*10000%10<5)?x:x+0.001,((int)y*10000%10<5)?y:y+0.001);
	}
	return 0;
}