Problem:
Score : 300 points

Problem Statement

Takahashi is organizing a party.

At the party, each guest will receive one or more snack pieces.

Takahashi predicts that the number of guests at this party will be A or B.

Find the minimum number of pieces that can be evenly distributed to the guests in both of the cases predicted.

We assume that a piece cannot be divided and distributed to multiple guests.

Constraints

1 \leq A, B \leq 10^5

A \neq B

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the minimum number of pieces that can be evenly distributed to the guests in both of the cases with A guests and B guests.

Sample Input 1

2 3

Sample Output 1

6

When we have six snack pieces, each guest can take three pieces if we have two guests, and each guest can take two if we have three guests.

Sample Input 2

123 456

Sample Output 2

18696

Sample Input 3

100000 99999

Sample Output 3

9999900000

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>

int gcd(int a, int b) {
	if (b == 0) return a;
	return gcd(b, a%b);
}

int main(void) {

	unsigned long long int a, b, r, tmp;
	unsigned long long int gd;
	unsigned long long int  res;
	
	scanf("%lld %lld", &a, &b);

	/* 自然数 a > b を確認・入替 */
	if (a < b) {
		tmp = a;
		a = b;
		b = tmp;
	}

	

	gd = gcd(a, b);

	res = a*b/gd;

	printf("%lld", res);

	return 0;
}