Problem:
Score : 200 points

Problem Statement

There is a square in the xy-plane. The coordinates of its four vertices are (x_1,y_1),(x_2,y_2),(x_3,y_3) and (x_4,y_4) in counter-clockwise order.
(Assume that the positive x-axis points right, and the positive y-axis points up.)

Takahashi remembers (x_1,y_1) and (x_2,y_2), but he has forgot (x_3,y_3) and (x_4,y_4).

Given x_1,x_2,y_1,y_2, restore x_3,y_3,x_4,y_4. It can be shown that x_3,y_3,x_4 and y_4 uniquely exist and have integer values.

Constraints

|x_1|,|y_1|,|x_2|,|y_2| \leq 100

(x_1,y_1) ≠ (x_2,y_2)

All values in input are integers.

Input

Input is given from Standard Input in the following format:

x_1 y_1 x_2 y_2

Output

Print x_3,y_3,x_4 and y_4 as integers, in this order.

Sample Input 1

0 0 0 1

Sample Output 1

-1 1 -1 0

(0,0),(0,1),(-1,1),(-1,0) is the four vertices of a square in counter-clockwise order.
Note that (x_3,y_3)=(1,1),(x_4,y_4)=(1,0) is not accepted, as the vertices are in clockwise order.

Sample Input 2

2 3 6 6

Sample Output 2

3 10 -1 7

Sample Input 3

31 -41 -59 26

Sample Output 3

-126 -64 -36 -131

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

/* ex7_1
   urah   */

#include <stdio.h>

// 頂点を表す構造体
typedef struct point{
    int x_elem;
    int y_elem;
}point;

// 移動させた頂点を返す関数
point shift_point(point coord, int dx, int dy){
    point new_coord;

    new_coord.x_elem = coord.x_elem - dy;
    new_coord.y_elem = coord.y_elem + dx;
    
    return new_coord;
}


int main(void){
    // coordi(i=1,2,3,4)は(xi,yi)を表す
    point coord1, coord2, coord3, coord4;
    // dx = x2-x1, dy = y2 - y1
    int dx, dy;

    // 入力受け取り
    scanf("%d\t%d\t%d\t%d", &coord1.x_elem, &coord1.y_elem, &coord2.x_elem, &coord2.y_elem);

    dx = coord2.x_elem - coord1.x_elem;
    dy = coord2.y_elem - coord1.y_elem;

    coord3 = shift_point(coord2, dx, dy);
    coord4 = shift_point(coord1, dx, dy);

    // 出力
    printf("%d %d %d %d\n", coord3.x_elem, coord3.y_elem, coord4.x_elem, coord4.y_elem);

    return 0;
}