Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
int main()
{
    int N;
    scanf("%d", &N);
    int h, n, w;
    for (h = (N + 3) / 4; h < 3501; h++)
    {
        for (n = h; n < 3501; n++)
        {
            if (4 * h*n - N * n - N * h > 0)
            {
                if ((N*h*n) % (4 * h*n - N * n - N * h) == 0)
                {
                    w = (N*h*n) / (4 * h*n - N * n - N * h);
                    printf("%d %d %d\n", h, n, w);
                    return 0;
                }
            }
        }
    }
    return 0;
}