Problem:
Binary Search Tree II

Write a program which performs the following operations to a binary search tree $T$ by adding the find operation to A: Binary Search Tree I.

insert $k$: Insert a node containing $k$ as key into $T$.

find $k$: Report whether $T$ has a node containing $k$.

print: Print the keys of the binary search tree by inorder tree walk and preorder tree walk respectively.

Input

In the first line, the number of operations $m$ is given. In the following $m$ lines, operations represented by insert $k$, find $k$ or print are given.

Output

For each find $k$ operation, print "yes" if $T$ has a node containing $k$, "no" if not.

In addition, for each print operation, print a list of keys obtained by inorder tree walk and preorder tree walk in a line respectively. Put a space character before each key.

Constraints

The number of operations $\leq 500,000$

The number of print operations $\leq 10$.

$-2,000,000,000 \leq key \leq 2,000,000,000$

The height of the binary tree does not exceed 100 if you employ the above pseudo code.

The keys in the binary search tree are all different.

Sample Input 1

10
insert 30
insert 88
insert 12
insert 1
insert 20
find 12
insert 17
insert 25
find 16
print

Sample Output 1

yes
no
1 12 17 20 25 30 88
30 12 1 20 17 25 88

Reference

Introduction to Algorithms, Thomas H. Cormen, Charles E. Leiserson, Ronald L. Rivest, and Clifford Stein. The MIT Press.

Solution in C (judge verdict: Accepted)

#include <stdio.h>
#include <stdlib.h>

struct node{
  struct node *right;
  struct node *left;
  struct node *parent;
  int key;
};
typedef struct node * Node;
#define NIL NULL

Node root;

void insert(int k){
  Node y = NIL;
  Node x = root;
  Node z;

  z = malloc(sizeof(struct node));
  z->key = k;
  z->left = NIL;
  z->right = NIL;

  while(x!=NIL){
    y=x;
    if(z->key<x->key){x=x->left;}
    else{x=x->right;}
  }
  
  z->parent=y;

  if(y==NIL){root=z;}
  else if(z->key<y->key){y->left=z;}
  else {y->right=z;}
  
}

Node treeSearch(Node u, int k){
  if(u==NIL||k==u->key){return u;}
  
  if(k<u->key){return treeSearch(u->left,k);}
  else {return treeSearch(u->right,k);}
}

void inorder(Node u){
  if(u!=NIL){
    inorder(u->left);
    printf(" %d",u->key);
    inorder(u->right);   
  }
}
void preorder(Node u){
  if(u!=NIL){
    printf(" %d",u->key);
    preorder(u->left);
    preorder(u->right); 
  }
}

int main(){
  int n, i, x;
  char com[20];
  scanf("%d",&n);

  for ( i = 0; i < n; i++ )
    {
      scanf("%s",com);

      if ( com[0] == 'i' )
	{
	  scanf("%d",&x);
	  insert(x);
	}
      else if ( com[0] == 'p' )
	{
	  inorder(root);
	  printf("\n");
	  preorder(root);
	  printf("\n");
	} 
      else if ( com[0] == 'f' ){
	scanf("%d",&x);
	Node t = treeSearch(root, x);
	if ( t != NIL ) printf("yes\n");
	else printf("no\n");
      }
    }

  return 0;
}