Problem:
Score : 200 points

Problem Statement

An integer N is a multiple of 9 if and only if the sum of the digits in the decimal representation of N is a multiple of 9.

Determine whether N is a multiple of 9.

Constraints

0 \leq N < 10^{200000}

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a multiple of 9, print Yes; otherwise, print No.

Sample Input 1

123456789

Sample Output 1

Yes

The sum of these digits is 1+2+3+4+5+6+7+8+9=45, which is a multiple of 9, so 123456789 is a multiple of 9.

Sample Input 2

0

Sample Output 2

Yes

Sample Input 3

31415926535897932384626433832795028841971693993751058209749445923078164062862089986280

Sample Output 3

No

Solution in C (Clang 10.0.0) (judge verdict: Wrong Answer)

#include <stdio.h>
#include<stdlib.h>

int main()
{
    char* a = (char*)malloc(sizeof(char));
    scanf("%c",&a[0]);
    int i = 0,sum = 0;
    while((int)a[i]!=10)
    {
        sum += atoi(&a[i]);
        i++;
        a = (char*)realloc(a,(i + 1)*sizeof(char));
        scanf("%c",&a[i]);
    }
    if(sum % 9 == 0) printf("\nYes ");
    else printf("No ");
    return 0;
}