Problem:
Finding Missing Cards

Taro is going to play a card game. However, now he has only n cards, even though there should be 52 cards (he has no Jokers).

The 52 cards include 13 ranks of each of the four suits: spade, heart, club and diamond.

Input

In the first line, the number of cards n (n ≤ 52) is given.

In the following n lines, data of the n cards are given. Each card is given by a pair of a character and an integer which represent its suit and rank respectively. A suit is represented by 'S', 'H', 'C' and 'D' for spades, hearts, clubs and diamonds respectively. A rank is represented by an integer from 1 to 13.

Output

Print the missing cards. The same as the input format, each card should be printed with a character and an integer separated by a space character in a line.
Arrange the missing cards in the following priorities:

Print cards of spades, hearts, clubs and diamonds in this order.

If the suits are equal, print cards with lower ranks first.

Sample Input

47
S 10
S 11
S 12
S 13
H 1
H 2
S 6
S 7
S 8
S 9
H 6
H 8
H 9
H 10
H 11
H 4
H 5
S 2
S 3
S 4
S 5
H 12
H 13
C 1
C 2
D 1
D 2
D 3
D 4
D 5
D 6
D 7
C 3
C 4
C 5
C 6
C 7
C 8
C 9
C 10
C 11
C 13
D 9
D 10
D 11
D 12
D 13

Sample Output

S 1
H 3
H 7
C 12
D 8

Note

      解説

Solution in C (judge verdict: Time Limit Exceeded)

#include <stdio.h>

int main(void)          
{
	char ctype;
	int cnumber;
	int have[4][13];
	int n;
	int i, j;

	for (i = 0; i < 4; i++) 
	{
		for (j = 0;j < 13; j++)
		{
			have[i][j] = 0;
		}
	}

	scanf("%d", &n);
	for (i = 0; i < n; i++)
	{
		scanf("%c %d", &ctype, &cnumber);

		if (ctype == 'S')
		{
			have[0][cnumber] = 1;
		}
		if (ctype == 'H')
		{
			have[1][cnumber] = 1;
		}
		if (ctype == 'C')
		{
			have[2][cnumber] =1;
		}
		if (ctype == 'D')
		{
			have[3][cnumber] = 1;
		}
	
		for (i = 0; i < 4; i++)
		{
			for (j = 0; j < 13; j++)
			{
				if (have[i][j] == 0 && i == 0) printf("S %d\n", j);
				if (have[i][j] == 0 && i == 1) printf("H %d\n", j);
				if (have[i][j] == 0 && i == 2) printf("C %d\n", j);
				if (have[i][j] == 0 && i == 3) printf("D %d\n", j);
			
			
			}
		}
	
	}

	return 0;
}