Problem:
Score : 200 points

Problem Statement

You are given strings s and t, consisting of lowercase English letters.
You will create a string s' by freely rearranging the characters in s.
You will also create a string t' by freely rearranging the characters in t.
Determine whether it is possible to satisfy s' < t' for the lexicographic order.

Notes

For a string a = a_1 a_2 ... a_N of length N and a string b = b_1 b_2 ... b_M of length M, we say a < b for the lexicographic order if either one of the following two conditions holds true:

N < M and a_1 = b_1, a_2 = b_2, ..., a_N = b_N.

There exists i (1 \leq i \leq N, M) such that a_1 = b_1, a_2 = b_2, ..., a_{i - 1} = b_{i - 1} and a_i < b_i. Here, letters are compared using alphabetical order.

For example, xy < xya and atcoder < atlas.

Constraints

The lengths of s and t are between 1 and 100 (inclusive).

s and t consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s
t

Output

If it is possible to satisfy s' < t', print Yes; if it is not, print No.

Sample Input 1

yx
axy

Sample Output 1

Yes

We can, for example, rearrange yx into xy and axy into yxa. Then, xy < yxa.

Sample Input 2

ratcode
atlas

Sample Output 2

Yes

We can, for example, rearrange ratcode into acdeort and atlas into tslaa. Then, acdeort < tslaa.

Sample Input 3

cd
abc

Sample Output 3

No

No matter how we rearrange cd and abc, we cannot achieve our objective.

Sample Input 4

w
ww

Sample Output 4

Yes

Sample Input 5

zzz
zzz

Sample Output 5

No

Solution in C (GCC 5.4.1) (judge verdict: Runtime Error)

#include<stdio.h>

int main(){
int i,j;
char s[51],t[51];
scanf("%s %s",s,t);
for(i=0;s[i]!=0;i++){
for(j=0;j<i;j++){
if(s[i]<s[j]){
char tmp=s[i];
s[i]=s[j];
s[j]=tmp;
}
}
}

for(i=0;t[i]!=0;i++){
for(j=0;j<i;j++){
if(t[i]>t[j]){
char tmp=t[i];
t[i]=t[j];
t[j]=tmp;
}
}
}
i=0;
while(s[i]!=0&&t[i]!=0){
if(s[i]<t[i]){
puts("Yes");
return 0;
}
if(s[i]>t[i]){
puts("No");
return 0;
}i++;
}
for(i=0;s[i]!=0;i++);
for(j=0;t[j]!=0;j++);
if(i<j)puts("Yes");
else puts("No");
return 0;
}