Problem:
Score : 500 points

Problem Statement

On a two-dimensional plane, there are m lines drawn parallel to the x axis, and n lines drawn parallel to the y axis.
Among the lines parallel to the x axis, the i-th from the bottom is represented by y = y_i.
Similarly, among the lines parallel to the y axis, the i-th from the left is represented by x = x_i.

For every rectangle that is formed by these lines, find its area, and print the total area modulo 10^9+7.

That is, for every quadruple (i,j,k,l) satisfying 1\leq i < j\leq n and 1\leq k < l\leq m, find the area of the rectangle formed by the lines x=x_i, x=x_j, y=y_k and y=y_l, and print the sum of these areas modulo 10^9+7.

Constraints

2 \leq n,m \leq 10^5

-10^9 \leq x_1 < ... < x_n \leq 10^9

-10^9 \leq y_1 < ... < y_m \leq 10^9

x_i and y_i are integers.

Input

Input is given from Standard Input in the following format:

n m
x_1 x_2 ... x_n
y_1 y_2 ... y_m

Output

Print the total area of the rectangles, modulo 10^9+7.

Sample Input 1

3 3
1 3 4
1 3 6

Sample Output 1

60

The following figure illustrates this input:

The total area of the nine rectangles A, B, ..., I shown in the following figure, is 60.

Sample Input 2

6 5
-790013317 -192321079 95834122 418379342 586260100 802780784
-253230108 193944314 363756450 712662868 735867677

Sample Output 2

835067060

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
#define mod (int)(1e9 + 7)

long long int MOD(long long int a){
	if(a < 0){
		mod + a % mod;
	}
	else{
		return a % mod;
	}
}

int main(){
	int m, n, i;
	long long int x, y, sumn = 0, summ = 0;
	scanf("%d%d", &n, &m);
	for(i = 1; i <= n; i++){
		scanf("%lld", &x);
		sumn = MOD(sumn + ((2 * i - 1 - n) * x)); 
	}
	for(i = 1; i <= m; i++){
		scanf("%lld", &y);
		summ = MOD(summ + ((2 * i - 1 - m) * y));
	}
	printf("%d\n", (sumn * summ) % mod);
	return 0;
}