Problem:
Score : 300 points

Problem Statement

There are N people living on a number line.

The i-th person lives at coordinate X_i.

You are going to hold a meeting that all N people have to attend.

The meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.

Find the minimum total points of stamina the N people have to spend.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq X_i \leq 100

Input

Input is given from Standard Input in the following format:

N
X_1 X_2 ... X_N

Output

Print the minimum total stamina the N people have to spend.

Sample Input 1

2
1 4

Sample Output 1

5

Assume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.

Note that you can hold the meeting only at an integer coordinate.

Sample Input 2

7
14 14 2 13 56 2 37

Sample Output 2

2354

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

int main(void) {
	int  i, n, x[101], p;
	long t = 0;

	scanf("%d", &n);
	for (i = 0; i < n; i++) {
		scanf("%d", &x[i]);
		t += x[i];
	}
	
	int min=1000000,j;
	for (i = 1; i <= 100; i++) {
		t = 0;
		for (j = 0; j < n; j++)
			t += pow(x[j] - i, 2);
		if (t < min) 
			min = t;

	}
	//p = (t%n t/2)?t/n-1:t/n;

//	t = 0;
//	for (i = 0; i < n; i++) 
//		t += pow(x[i] - p, 2);
	printf("%ld", min);
	return 0;
}