Problem:
Score: 100 points

Problem Statement

M-kun is a competitor in AtCoder, whose highest rating is X.

In this site, a competitor is given a kyu (class) according to his/her highest rating. For ratings from 400 through 1999, the following kyus are given:

From 400 through 599: 8-kyu

From 600 through 799: 7-kyu

From 800 through 999: 6-kyu

From 1000 through 1199: 5-kyu

From 1200 through 1399: 4-kyu

From 1400 through 1599: 3-kyu

From 1600 through 1799: 2-kyu

From 1800 through 1999: 1-kyu

What kyu does M-kun have?

Constraints

400 \leq X \leq 1999

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print the kyu M-kun has, as an integer.
For example, if he has 8-kyu, print 8.

Sample Input 1

725

Sample Output 1

7

M-kun's highest rating is 725, which corresponds to 7-kyu.

Thus, 7 is the correct output.

Sample Input 2

1600

Sample Output 2

2

M-kun's highest rating is 1600, which corresponds to 2-kyu.

Thus, 2 is the correct output.

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>
#include <ctype.h>
#include <inttypes.h>

int compare_int(const void *a, const void *b){//qsort 整数比較<
	return *(int*)a - *(int*)b;
}
int compare_int2(const void *a, const void *b){//qsort 整数比較>
	return *(int*)b - *(int*)a;
}

//void func(int k,char *s,int i){
//	char *b={"A"};
//	if(i==k){
//		strcat(b,s);
//		strcpy(s,b);
//		strcat(s,"B");
//		strcat(s,"C");
//	}else{
//		strcat(b,s);
//		strcpy(s,b);
//		strcat(s,"B");
//		strcat(s,"C");
//		func(k,s,i+1);
//	}
//}

int main(void){
	int N;

	scanf("%d",&N);
	if(N<600){
		printf("8");
	}else if(N<800){
		printf("7");
	}else if(N<1000){
		printf("6");
	}else if(N<1200){
		printf("5");
	}else if(N<1400){
		printf("4");
	}else if(N<1600){
		printf("3");
	}else if(N<1800){
		printf("2");
	}else{
		printf("1");
	}

	return 0;
}