Problem:
Score: 100 points

Problem Statement

In this problem, a date is written as Y-M-D. For example, 2019-11-30 means November 30, 2019.

Integers M_1, D_1, M_2, and D_2 will be given as input.

It is known that the date 2019-M_2-D_2 follows 2019-M_1-D_1.

Determine whether the date 2019-M_1-D_1 is the last day of a month.

Constraints

Both 2019-M_1-D_1 and 2019-M_2-D_2 are valid dates in the Gregorian calendar.

The date 2019-M_2-D_2 follows 2019-M_1-D_1.

Input

Input is given from Standard Input in the following format:

M_1 D_1
M_2 D_2

Output

If the date 2019-M_1-D_1 is the last day of a month, print 1; otherwise, print 0.

Sample Input 1

11 16
11 17

Sample Output 1

0

November 16 is not the last day of a month.

Sample Input 2

11 30
12 1

Sample Output 2

1

November 30 is the last day of November.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>

int main(void)
{
    int M1, D1, M2, D2;
    char c;
    
    
    scanf("%d%c%d%c", &M1, &c, &D1, &c);
    scanf("%d%c%d%c", &M2, &c, &D2, &c);
    
    
    if(M1 < M2)
    {
        switch(M1)
        {
            case 1:
            case 3:
            case 5:
            case 7:
            case 8:
            case 10:
                if(D1 == 31)
                    printf("1\n");
                else
                    printf("0\n");
                
                break;
            case 2:
                if(D1 == 28)
                    printf("1\n");
                else
                    printf("0\n");
                    
                break;
            case 4:
            case 6:
            case 9:
            case 11:
                if(D1 == 30)
                    printf("1\n");
                else
                    printf("0\n");
        }
    }
    else
        printf("0\n");
    
    
    //system("pause");
    
    return 0;
}