Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>

int main (void)
{
	int N;
	int intans,minVal2;
	float minVal;

	int h,n,w;

	scanf("%d",&N);

	intans = (int)N/4;

	if (intans < 1) 
		intans = 1;

	minVal = (3 * N) / 4;
	minVal2 = (int)minVal + 2;



	for(h = intans;h < minVal2;h++){
		for (n = h;n < minVal2;n ++){
			for (w = n;w < minVal2;w ++){
				if (1/h + 1/n + 1/w == 4/N){
					printf("%d %d %d",h,n,w);
				    return 0;
				}
			}
	}
}
}