Problem:
Score : 200 points

Problem Statement

The word internationalization is sometimes abbreviated to i18n.
This comes from the fact that there are 18 letters between the first i and the last n.

You are given a string s of length at least 3 consisting of lowercase English letters.
Abbreviate s in the same way.

Constraints

3 ≤ |s| ≤ 100 (|s| denotes the length of s.)

s consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s

Output

Print the abbreviation of s.

Sample Input 1

internationalization

Sample Output 1

i18n

Sample Input 2

smiles

Sample Output 2

s4s

Sample Input 3

xyz

Sample Output 3

x1z

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

/* kadai6_1
   reo012 */

#include <stdio.h>
#include <string.h>

#define SIZE 101

int main(void){
    char word[SIZE];    //単語入る配列word用意
    int length;    //単語の文字数length用意
    scanf("%s", word);    //単語入力
    length = (int)strlen(word);    //単語の文字数取得
    printf("%c%d%c\n", word[0], length-2, word[length-1]);    //最初の文字、間の文字数、最後の文字出力
    return 0;
}