Problem:
Score: 200 points

Problem Statement

A country decides to build a palace.

In this country, the average temperature of a point at an elevation of x meters is T-x \times 0.006 degrees Celsius.

There are N places proposed for the place. The elevation of Place i is H_i meters.

Among them, Princess Joisino orders you to select the place whose average temperature is the closest to A degrees Celsius, and build the palace there.

Print the index of the place where the palace should be built.

It is guaranteed that the solution is unique.

Constraints

1 \leq N \leq 1000

0 \leq T \leq 50

-60 \leq A \leq T

0 \leq H_i \leq 10^5

All values in input are integers.

The solution is unique.

Input

Input is given from Standard Input in the following format:

N
T A
H_1 H_2 ... H_N

Output

Print the index of the place where the palace should be built.

Sample Input 1

2
12 5
1000 2000

Sample Output 1

1

The average temperature of Place 1 is 12-1000 \times 0.006=6 degrees Celsius.

The average temperature of Place 2 is 12-2000 \times 0.006=0 degrees Celsius.

Thus, the palace should be built at Place 1.

Sample Input 2

3
21 -11
81234 94124 52141

Sample Output 2

3

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
#include <math.h>


int main(){
  int N,T,A;
  scanf("%d%d%d",&N ,&T ,&A);

  int H[1010];
  int i;

  for (i = 1; i <= N; i++) {
    scanf("%d", &H[i]);
  }

  //地点iの平均気温
  double temp[1010];
  for (i = 1; i <= N; i++) {
    temp[i] = T - H[i] * 0.006;
  }

  //地点iの平均気温とA度との差
  double sa[1010];
  for (i = 1; i <= N; i++) {
    if (temp[i] >= A) {
      sa[i] = temp[i] - A;
    }else{
      sa[i] = A - temp[i];
    }
  }

  //sa[i]が最小となるようなiを求める
  double min = sa[1];
  int answer = 1;
  for (i = 1; i <= N ; i++) {
    if (sa[i] < min) {
      min = sa[i];
      answer = i;
    }
  }
  printf("%d\n", answer);

  return 0;
}