Problem:
Score: 200 points

Problem Statement

A country decides to build a palace.

In this country, the average temperature of a point at an elevation of x meters is T-x \times 0.006 degrees Celsius.

There are N places proposed for the place. The elevation of Place i is H_i meters.

Among them, Princess Joisino orders you to select the place whose average temperature is the closest to A degrees Celsius, and build the palace there.

Print the index of the place where the palace should be built.

It is guaranteed that the solution is unique.

Constraints

1 \leq N \leq 1000

0 \leq T \leq 50

-60 \leq A \leq T

0 \leq H_i \leq 10^5

All values in input are integers.

The solution is unique.

Input

Input is given from Standard Input in the following format:

N
T A
H_1 H_2 ... H_N

Output

Print the index of the place where the palace should be built.

Sample Input 1

2
12 5
1000 2000

Sample Output 1

1

The average temperature of Place 1 is 12-1000 \times 0.006=6 degrees Celsius.

The average temperature of Place 2 is 12-2000 \times 0.006=0 degrees Celsius.

Thus, the palace should be built at Place 1.

Sample Input 2

3
21 -11
81234 94124 52141

Sample Output 2

3

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
int main(void){
    // Your code here!
    int n,t,a,h[1000];
    scanf("%d %d\n%d\n",&n,&t,&a);
    for(int i=0;i<n;i++){
        int b;
        scanf("%d",&b);
        h[i]=b;
    }
    /*printf("%d\n%d\n%d\n",n,t,a);
    for(int i=0;i<n;i++){
        printf("%d ",h[i]);
    }*/
    
    
    long int x,z;
    x=h[0]*6;
    z=(t-a)*1000;
    int j=0;
    for(int i=0;i<n;i++){
        long int y=h[i]*6;
        int f=0;
        if(-h[j]<h[i]&&h[i]<h[j]) f=1;
        else if(h[j]<h[i]&&h[i]<-h[j]) f=1;
        else{
            if(z<=y&&y<=x) f=1;
            else if(x>=y&&y>=z) f=1;
        }
        
        if(f==1) x=y,j=i;
    }
    
    
    printf("%d\n",j+1);
}