Problem:
Score : 100 points

Problem Statement

Given are three integers A_1, A_2, and A_3.

If A_1+A_2+A_3 is greater than or equal to 22, print bust; otherwise, print win.

Constraints

1 \leq A_i \leq 13 \ \ (i=1,2,3)

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

If A_1+A_2+A_3 is greater than or equal to 22, print bust; otherwise, print win.

Sample Input 1

5 7 9

Sample Output 1

win

5+7+9=21, so print win.

Sample Input 2

13 7 2

Sample Output 2

bust

13+7+2=22, so print bust.

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

#include<stdio.h>

int AddA(int* a_aiA);

int main(void) {
	int aiA[3];
	int i;
	//3個の整数を入力
	for (i = 0;i < 3;i++) {
		scanf("%d", &aiA[i]);
	}
	//3個の整数を合計し、合計値によって結果を出力
	if (AddA(aiA) <= 21) {
		printf("win\n");
	}
	else {
		printf("bust\n");
	}
	return 0;
}

/********
*	3個の整数の和を求める関数
*	*a_aiA	入力された3個の整数
*/
int AddA(int* a_aiA) {
	return(a_aiA[0] + a_aiA[1] + a_aiA[2]);
}