Problem:
Score : 200 points

Problem Statement

Given are integers a,b,c and d.
If x and y are integers and a \leq x \leq b and c\leq y \leq d hold, what is the maximum possible value of x \times y?

Constraints

-10^9 \leq a \leq b \leq 10^9

-10^9 \leq c \leq d \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

a b c d

Output

Print the answer.

Sample Input 1

1 2 1 1

Sample Output 1

2

If x = 1 and y = 1 then x \times y = 1.
If x = 2 and y = 1 then x \times y = 2.
Therefore, the answer is 2.

Sample Input 2

3 5 -4 -2

Sample Output 2

-6

The answer can be negative.

Sample Input 3

-1000000000 0 -1000000000 0

Sample Output 3

1000000000000000000

Solution in C (GCC 9.2.1) (judge verdict: Wrong Answer)

#include <stdio.h>

int main(){
    long long int a,b,c,d,ans1,ans2,ans3,ans4;
    scanf("%lld %lld %lld %lld", &a,&b,&c,&d);
    ans1 = a * c;
    ans2 = b * d;
    ans3 = a * d;
    ans4 = b * c;
    if(ans1 > ans2 && ans1 > ans3 && ans1 > ans4){
        printf("%lld", ans1);
    }
    if(ans2 > ans1 && ans2 > ans3 && ans2 > ans4){
        printf("%lld", ans2);
    }
    if(ans3 > ans2 && ans3 > ans1 && ans3 > ans4){
        printf("%lld", ans3);
    }
    if(ans4 > ans2 && ans4 > ans3 && ans4 > ans1){
        printf("%lld", ans4);
    }
    if(ans1 == ans2 && ans1 == ans3 && ans1 == ans4 && ans2 == ans3){
        printf("%lld", ans1);
    }
}