Problem:
Score : 300 points

Problem Statement

Snuke has an integer sequence A of length N.

He will freely choose an integer b.
Here, he will get sad if A_i and b+i are far from each other.
More specifically, the sadness of Snuke is calculated as follows:

abs(A_1 - (b+1)) + abs(A_2 - (b+2)) + ... + abs(A_N - (b+N))

Here, abs(x) is a function that returns the absolute value of x.

Find the minimum possible sadness of Snuke.

Constraints

1 \leq N \leq 2 \times 10^5

1 \leq A_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

Print the minimum possible sadness of Snuke.

Sample Input 1

5
2 2 3 5 5

Sample Output 1

2

If we choose b=0, the sadness of Snuke would be abs(2-(0+1))+abs(2-(0+2))+abs(3-(0+3))+abs(5-(0+4))+abs(5-(0+5))=2.
Any choice of b does not make the sadness of Snuke less than 2, so the answer is 2.

Sample Input 2

9
1 2 3 4 5 6 7 8 9

Sample Output 2

0

Sample Input 3

6
6 5 4 3 2 1

Sample Output 3

18

Sample Input 4

7
1 1 1 1 2 3 4

Sample Output 4

6

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <stdlib.h>

int main(void)
{
	int N, A[200000], i, b = 0, ABS = 0, MIN = 1000000;

	scanf("%d", &N);
	for (i = 0; i < N-1; i++) {
		scanf("%d ", &A[i]);
	}
	scanf("%d", &A[N-1]);

	while (1) {
		ABS = 0;

		for (i = 0; i < N; i++) {
			ABS += abs(A[i] - (b + i + 1));
		}
		if (ABS < MIN) {
			MIN = ABS;
		}
		if ((MIN==0)||(b==3000)) {
			break;
		}
		ABS = 0;

		for (i = 0; i < N; i++) {
			ABS += abs(A[i] - (-b + i + 1));
		}
		if (ABS < MIN) {
			MIN = ABS;
		}
		if (MIN == 0) {
			break;
		}
		b++;
	}

	printf("%d\n", MIN);
	return 0;
}