Problem:
Score : 300 points

Problem Statement

A company has N members, who are assigned ID numbers 1, ..., N.

Every member, except the member numbered 1, has exactly one immediate boss with a smaller ID number.

When a person X is the immediate boss of a person Y, the person Y is said to be an immediate subordinate of the person X.

You are given the information that the immediate boss of the member numbered i is the member numbered A_i. For each member, find how many immediate subordinates it has.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq A_i < i

Input

Input is given from Standard Input in the following format:

N
A_2 ... A_N

Output

For each of the members numbered 1, 2, ..., N, print the number of immediate subordinates it has, in its own line.

Sample Input 1

5
1 1 2 2

Sample Output 1

2
2
0
0
0

The member numbered 1 has two immediate subordinates: the members numbered 2 and 3.

The member numbered 2 has two immediate subordinates: the members numbered 4 and 5.

The members numbered 3, 4, and 5 do not have immediate subordinates.

Sample Input 2

10
1 1 1 1 1 1 1 1 1

Sample Output 2

9
0
0
0
0
0
0
0
0
0

Sample Input 3

7
1 2 3 4 5 6

Sample Output 3

1
1
1
1
1
1
0

Solution in C (GCC 9.2.1) (judge verdict: Time Limit Exceeded)

#include<stdio.h>
 
int main() {
    int i,j,n;
    int array[200000];
    int array2[200000];
    scanf("%d",&n);
    array[0] = 0;
    array2[0] = 0;
    for(i = 1;i < n;i++) {
        scanf("%d",&array[i]); //添字＝社員番号、中身＝上司の社員番号
        array2[i] = 0;
    }
    for(i = 0;i < n;i++) {
        for(j = 0;j < n;j++) {
            if(array[i] == j) {
                array2[j-1]++;
            }
        }
    }
    for(i = 0;i < n;i++) {
        printf("%d\n",array2[i]);
    }

    return 0;
}