Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>
int main(void){
    int i,swi1=0,swi2=0;
    char S[4];
    for(i=0;i<4;i++)
    scanf("%s",S);
    
    if( (S[0]=='0'&&S[1]!='0' )|| (S[0]=='1'&&(S[1]=='1')||S[1]=='2') )
    swi1=1;
    if( (S[2]=='0'&&S[3]!='0' )|| (S[2]=='1'&&(S[3]=='1')||S[3]=='2') )
    swi2=1;
  
   
    if(swi1==1&&swi2==1)
    printf("AMBIGUOUS");
     if(swi1==1&&swi2==0)
    printf("MMYY");
     if(swi1==0&&swi2==1)
    printf("YYMM");
     if(swi1==0&&swi2==0)
    printf("NA");
    
    return(0);
}