Problem:
Score : 400 points

Problem Statement

Snuke has N strings. The i-th string is s_i.

Let us concatenate these strings into one string after arranging them in some order.
Find the maximum possible number of occurrences of AB in the resulting string.

Constraints

1 \leq N \leq 10^{4}

2 \leq |s_i| \leq 10

s_i consists of uppercase English letters.

Input

Input is given from Standard Input in the following format:

N
s_1
\vdots
s_N

Output

Print the answer.

Sample Input 1

3
ABCA
XBAZ
BAD

Sample Output 1

2

For example, if we concatenate ABCA, BAD and XBAZ in this order, the resulting string ABCABADXBAZ has two occurrences of AB.

Sample Input 2

9
BEWPVCRWH
ZZNQYIJX
BAVREA
PA
HJMYITEOX
BCJHMRMNK
BP
QVFABZ
PRGKSPUNA

Sample Output 2

4

Sample Input 3

7
RABYBBE
JOZ
BMHQUVA
BPA
ISU
MCMABAOBHZ
SZMEHMA

Sample Output 3

4

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include<stdio.h>
#include<string.h>
int main(){
  int i,j,n,cnt=0;
  int a=0,b=0;
  char s[10000][10];
  scanf("%d",&n);
  for(i=0;i<n;i++){
    scanf("%s",s[i]);
      if(s[i][0]=='B')
        b++;
      if(s[i][strlen(s[i])-1]=='A')
        a++;
      for(j=1;j<strlen(s[i]);j++){
        if(s[i][j-1]=='A' && s[i][j]=='B')
          cnt++;
      }
  }
  cnt += a>b ? b : a;
  cnt = a==b ? cnt-1 : cnt;
  printf("%d\n",cnt);
  return 0;
}