Problem:
Search III

Your task is to write a program of a simple dictionary which implements the following instructions:

insert str: insert a string str in to the dictionary

find str: if the distionary contains str, then print 'yes', otherwise print 'no'

Input

In the first line n, the number of instructions is given. In the following n lines, n instructions are given in the above mentioned format.

Output

Print yes or no for each find instruction in a line.

Constraints

A string consists of 'A', 'C', 'G', or 'T'

1 ≤ length of a string ≤ 12

n ≤ 1000000

Sample Input 1

5
insert A
insert T
insert C
find G
find A

Sample Output 1

no
yes

Sample Input 2

13
insert AAA
insert AAC
insert AGA
insert AGG
insert TTT
find AAA
find CCC
find CCC
insert CCC
find CCC
insert T
find TTT
find T

Sample Output 2

yes
no
no
yes
yes
yes

Notes

Template in C

Solution in C (judge verdict: Accepted)

#include <stdio.h>
#include <string.h>

char dict[30600000];

char word[26];

long encode(const char *key){
  int n=strlen(key),i;
  long sum=0;
  long keta=1;
  for(i=0;i<n;i++){
    int keyi=key[i];
    sum = sum + keta * word[keyi];
    //    if (key[i]=='A')      sum = sum + keta;
    //    else if (key[i]=='C') sum = sum + (keta << 1);
    //    else if (key[i]=='G') sum = sum + (keta << 1) + keta;
    //    else if (key[i]=='T') sum = sum + (keta << 2);
    keta=keta*5;
  }
  return (sum);
}

void insert(const char *key2) {
  long key=encode(key2);
  long keta=key/8;
  dict[keta]=(dict[keta]|(1<<(key%8)));
}

int find_h(const char *key2) {
  long key=encode(key2);
  return (dict[key/8] & 1<<(key%8));
}

int main(void) {
  long n,i;
  word['A'] = 1;
  word['C'] = 2;
  word['G'] = 3;
  word['T'] = 4;
  scanf("%ld\n",&n);
  for(i=0;i<n;i++){
    char cmd[8], str[14]; scanf("%s %s\n",cmd, str);
    if(cmd[0]=='i') {
      insert(str);
    }
    else {
      if(find_h(str)) printf("yes\n");
      else printf("no\n");
    }
  }
  return 0;
}