Problem:
Score : 100 points

Problem Statement

We have three boxes A, B, and C, each of which contains an integer.

Currently, the boxes A, B, and C contain the integers X, Y, and Z, respectively.

We will now do the operations below in order. Find the content of each box afterward.

Swap the contents of the boxes A and B

Swap the contents of the boxes A and C

Constraints

1 \leq X,Y,Z \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X Y Z

Output

Print the integers contained in the boxes A, B, and C, in this order, with space in between.

Sample Input 1

1 2 3

Sample Output 1

3 1 2

After the contents of the boxes A and B are swapped, A, B, and C contain 2, 1, and 3, respectively.

Then, after the contents of A and C are swapped, A, B, and C contain 3, 1, and 2, respectively.

Sample Input 2

100 100 100

Sample Output 2

100 100 100

Sample Input 3

41 59 31

Sample Output 3

31 41 59

Solution in C (Clang 3.8.0) (judge verdict: Wrong Answer)

#include <stdio.h>

void swap(int *a,int *b){
  int temp;
  temp=*a;
  *a=*b;
  *b=temp;
}

int main(){
  	int x,y,z;
  	if(scanf("%d %d %d",&x,&y,&z)==1);
  
  	swap(&x,&y);
    printf("箱Aと箱Bの中身を入れ替えた後、箱A,B,Cに入っている整数はそれぞれ%d,%d,%dです。\n",x,y,z);
  	swap(&x,&z);
  	printf("箱Aと箱Bの中身を入れ替えた後、箱A,B,Cに入っている整数はそれぞれ%d,%d,%dです。\n",x,y,z);
    
  	return 0;
}