Problem:
Score : 200 points

Problem Statement

Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Constraints

1 \leq N \leq 10^4

1 \leq A \leq B \leq 36

All input values are integers.

Input

Input is given from Standard Input in the following format:

N A B

Output

Print the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Sample Input 1

20 2 5

Sample Output 1

84

Among the integers not greater than 20, the ones whose sums of digits are between 2 and 5, are: 2,3,4,5,11,12,13,14 and 20. We should print the sum of these, 84.

Sample Input 2

10 1 2

Sample Output 2

13

Sample Input 3

100 4 16

Sample Output 3

4554

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
int s(int i)
{
	int t=0;

	while(i>0){
		t+=i%10;
		i/=10;
	}
	return t;
}

int main()
{
	int n,a,b,t=0,i;

	scanf("%d%d%d",&n,&a,&b);

	for(i=1;i<=n;i++)
		if(a<=s(i)&&s(i)<=b)
			t+=i;
	printf("%d",t);
	return 0;
}