Problem:
Score : 200 points

Problem Statement

Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Constraints

1 \leq N \leq 10^4

1 \leq A \leq B \leq 36

All input values are integers.

Input

Input is given from Standard Input in the following format:

N A B

Output

Print the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Sample Input 1

20 2 5

Sample Output 1

84

Among the integers not greater than 20, the ones whose sums of digits are between 2 and 5, are: 2,3,4,5,11,12,13,14 and 20. We should print the sum of these, 84.

Sample Input 2

10 1 2

Sample Output 2

13

Sample Input 3

100 4 16

Sample Output 3

4554

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
int digit(long long int a)
{
    int i,j,b,s=0;
    for( ;a>0;)
    {
        b=a%10;
        s=s+b;
        a=a/10;
    }
    return s;
}
int main()
{
    long long int a,b,c,d,i,j,s=0;
    scanf("%lld%lld%lld",&a,&b,&c);
    for(i=1;i<=a;i++)
    {
        d=digit(i);
        if(d>=b && d<=c)s=s+i;
    }
    printf("%lld\n",s);
    return 0;
}