Problem:
Search III

Your task is to write a program of a simple dictionary which implements the following instructions:

insert str: insert a string str in to the dictionary

find str: if the distionary contains str, then print 'yes', otherwise print 'no'

Input

In the first line n, the number of instructions is given. In the following n lines, n instructions are given in the above mentioned format.

Output

Print yes or no for each find instruction in a line.

Constraints

A string consists of 'A', 'C', 'G', or 'T'

1 ≤ length of a string ≤ 12

n ≤ 1000000

Sample Input 1

5
insert A
insert T
insert C
find G
find A

Sample Output 1

no
yes

Sample Input 2

13
insert AAA
insert AAC
insert AGA
insert AGG
insert TTT
find AAA
find CCC
find CCC
insert CCC
find CCC
insert T
find TTT
find T

Sample Output 2

yes
no
no
yes
yes
yes

Notes

Template in C

Solution in C (judge verdict: Wrong Answer)

#define M 8000
#define L 14

char H[M][L]; /* Hash Table */
int getChar(char ch){
  if ( ch == 'A') return 1;
  else if ( ch == 'C') return 2;
  else if ( ch == 'G') return 3;
  else if ( ch == 'T') return 4;
}

/* convert a string into an integer value */
long long getKey(char str[]){
  long long sum = 0, p = 1, i;
  for ( i = 0; i < strlen(str); i++ ){
    sum += p*(getChar(str[i]));
    p *= 5;
  }
  return sum;
}

int h1(int key){ return key % M; }
int h2(int key){ return 1+ (key % M); }

int find(char str[]){
  int i;
  for(i=0;i<M;i++){
    if(strcmp(str,H[i])==0)  return 1;
  }
    return 0;
}
void insert(char str[]){
  long long key = 0;
  int h_1,h_2,i=0;
  key = getKey(str);
  h_1 = h1(key);
  h_2 = h2(key);
  if(find(str) == 0) strcpy(H[h_1],str);
  else {
    i++;
    h_1 = (h_1+ i * h_2) % M;
    strcpy(H[h_1],str);
  } 
}

int main(){
  int i,h,n;
    char str[L], com[9];
    for ( i = 0; i < M; i++ ) H[i][0] = '\0';
    
    scanf("%d", &n);
    
    for ( i = 0; i < n; i++ ){
	scanf("%s %s", com, str);
	
	if ( com[0] == 'i' ){
	    insert(str);
	}
	else {
	    if (find(str)==1){
		printf("yes\n");
	    } else {
		printf("no\n");
	    }
	}
    }

    return 0;
}