Problem:
Score : 300 points

Problem Statement

Given are N integers A_1,\ldots,A_N.

Find the sum of A_i \times A_j over all pairs (i,j) such that 1\leq i < j \leq N, modulo (10^9+7).

Constraints

2 \leq N \leq 2\times 10^5

0 \leq A_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 \ldots A_N

Output

Print \sum_{i=1}^{N-1}\sum_{j=i+1}^{N} A_i A_j, modulo (10^9+7).

Sample Input 1

3
1 2 3

Sample Output 1

11

We have 1 \times 2 + 1 \times 3 + 2 \times 3 = 11.

Sample Input 2

4
141421356 17320508 22360679 244949

Sample Output 2

437235829

Solution in C (GCC 9.2.1) (judge verdict: Runtime Error)

#include<stdio.h>
#include<stdlib.h>

int main()
{
    long long int *N ;
    N= (int*)malloc(1000000007 * sizeof(int)) ;
    int  i, j, sum, n, m;
    sum=0 ;
    scanf("%d",&n) ;
    for(i=0 ; i<n ; i++)
    {
        scanf("%lld",&N[i]) ;
    }
    for(i=0 ; i<n-1 ; i++)
    {
        for(j=i+1 ; j<n ; j++)
        {
                m= N[i]*N[j]  ;
                sum= sum+ m ;
        }
    }
    printf("%lld", sum ) ;
}