Problem:
Score : 200 points

Problem Statement

Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Constraints

1 \leq N \leq 10^4

1 \leq A \leq B \leq 36

All input values are integers.

Input

Input is given from Standard Input in the following format:

N A B

Output

Print the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Sample Input 1

20 2 5

Sample Output 1

84

Among the integers not greater than 20, the ones whose sums of digits are between 2 and 5, are: 2,3,4,5,11,12,13,14 and 20. We should print the sum of these, 84.

Sample Input 2

10 1 2

Sample Output 2

13

Sample Input 3

100 4 16

Sample Output 3

4554

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

#include <stdio.h>
int main(void){
  int N,A,B,i,sum1,sum2,a,b,c,d,e;
  sum1=0;
  sum2=0;
  scanf("%d %d %d",&N,&A,&B);
  for(i=0;i<N+1;i++){
    a=i/10000;
    b=(i-a*10000)/1000;
    c=(i-a*10000-b*1000)/100;
    d=(i-a*10000-b*1000-c*100)/10;
    e=i-a*10000-b*1000-c*100-d*10;
    sum1=a+b+c+d+e;
   if(A<=sum1&&sum1<=B)
     sum2+=i;
  }
  printf("%d\n",sum2);
  
 return 0; 
}