Problem:
Search III

Your task is to write a program of a simple dictionary which implements the following instructions:

insert str: insert a string str in to the dictionary

find str: if the distionary contains str, then print 'yes', otherwise print 'no'

Input

In the first line n, the number of instructions is given. In the following n lines, n instructions are given in the above mentioned format.

Output

Print yes or no for each find instruction in a line.

Constraints

A string consists of 'A', 'C', 'G', or 'T'

1 ≤ length of a string ≤ 12

n ≤ 1000000

Sample Input 1

5
insert A
insert T
insert C
find G
find A

Sample Output 1

no
yes

Sample Input 2

13
insert AAA
insert AAC
insert AGA
insert AGG
insert TTT
find AAA
find CCC
find CCC
insert CCC
find CCC
insert T
find TTT
find T

Sample Output 2

yes
no
no
yes
yes
yes

Notes

Template in C

Solution in C (judge verdict: Accepted)

#include<stdio.h>
#include<string.h>

#define M 1046527/* your task*/
#define L 14

char H[M][L]; /* Hash Table */

int getChar(char ch){
  if ( ch == 'A') return 1;
  else if ( ch == 'C') return 2;
  else if ( ch == 'G') return 3;
  else if ( ch == 'T') return 4;
  return 0;
}

/* convert a string into an integer value */
long long getKey(char str[]){
  long long sum = 0, p = 1;
  int i;
  for ( i = 0; i < (int)strlen(str); i++ ){
    sum += p*(getChar(str[i]));
    p *= 5;
  }
  return sum;
}

int h1(int key){ return key % M; }
int h2(int key){ return 1 + (key % (M - 1));}

int find(char str[]){
  int i,hash,key;
  key = getKey(str);
  i = 0;
  while(1){
    hash = (h1(key) + i * h2(key))%M;
    if(strcmp(H[hash],str) == 0)return 1;
    else if(strlen(H[hash]) == 0)return 0;
    i++;
  }
  return 0;
}

int insert(char str[]){
  int i,hash,key;
  key = getKey(str);
  i = 0;
  while(1){
    hash = (h1(key) + i * h2(key))%M;
    if(strcmp(H[hash],str) == 0)return 1;
    else if(strlen(H[hash]) == 0){
      strcpy(H[hash],str);
      return 0;
    }
    i++;
  }
  return 0;
  /* your task */

}

int main(){
  int i, n;
  char str[L], com[9];
  for ( i = 0; i < M; i++ ) H[i][0] = '\0';

  scanf("%d", &n);

  for ( i = 0; i < n; i++ ){
    scanf("%s %s", com, str);

    if ( com[0] == 'i' ){
      insert(str);
    } else {
      if (find(str)){
        printf("yes\n");
      } else {
        printf("no\n");
      }
    }
  }

  return 0;
}