Problem:
Score : 100 points

Problem Statement

Given is a three-digit integer N. Does N contain the digit 7?

If so, print Yes; otherwise, print No.

Constraints

100 \leq N \leq 999

Input

Input is given from Standard Input in the following format:

N

Output

If N contains the digit 7, print Yes; otherwise, print No.

Sample Input 1

117

Sample Output 1

Yes

117 contains 7 as its last digit.

Sample Input 2

123

Sample Output 2

No

123 does not contain the digit 7.

Sample Input 3

777

Sample Output 3

Yes

Solution in C (GCC 9.2.1) (judge verdict: Accepted)

#include <stdio.h>

int main(){
	int n,x,x1,x2,x3,flag=0;
	
	scanf("%d",&n);
	
	//10で割った余りがx桁目
	x1 = n % 10;
	if(x1 == 7)	flag =1;
	
		x = n / 10;
//		printf("%d\t",x);

	
	x2 = x % 10;
	if(x2 == 7)	flag =1;
	
		x = x / 10;
//		printf("%d\t",x);

	
	x3 = x %10;
	if(x3 == 7)	flag =1;
	
	if(flag==1){
		printf("Yes");
	}
	else printf("No");
	
	return 0;
}