Problem:
Score : 200 points

Problem Statement

Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Constraints

1 \leq N \leq 10^4

1 \leq A \leq B \leq 36

All input values are integers.

Input

Input is given from Standard Input in the following format:

N A B

Output

Print the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Sample Input 1

20 2 5

Sample Output 1

84

Among the integers not greater than 20, the ones whose sums of digits are between 2 and 5, are: 2,3,4,5,11,12,13,14 and 20. We should print the sum of these, 84.

Sample Input 2

10 1 2

Sample Output 2

13

Sample Input 3

100 4 16

Sample Output 3

4554

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>

int Sum(int N);

int main(){
    int N, A, B, sum = 0;
    scanf("%d %d %d", &N, &A, &B);

    for(int i = 1; i <= N; i++){
        if(A <= Sum(i) && Sum(i) <= B){
            sum += i;
        }
    }
  
    printf("%d\n", sum);
    return 0;
}

int Sum(int N){
    int sum = 0;

    for(int i = N; i > 0; i /= 10){
        sum += i % 10;
    }

    return sum;
}