Problem:
Search III

Your task is to write a program of a simple dictionary which implements the following instructions:

insert str: insert a string str in to the dictionary

find str: if the distionary contains str, then print 'yes', otherwise print 'no'

Input

In the first line n, the number of instructions is given. In the following n lines, n instructions are given in the above mentioned format.

Output

Print yes or no for each find instruction in a line.

Constraints

A string consists of 'A', 'C', 'G', or 'T'

1 ≤ length of a string ≤ 12

n ≤ 1000000

Sample Input 1

5
insert A
insert T
insert C
find G
find A

Sample Output 1

no
yes

Sample Input 2

13
insert AAA
insert AAC
insert AGA
insert AGG
insert TTT
find AAA
find CCC
find CCC
insert CCC
find CCC
insert T
find TTT
find T

Sample Output 2

yes
no
no
yes
yes
yes

Notes

Template in C

Solution in C (judge verdict: Accepted)

#include <stdio.h>
#include <string.h>
 
#define N 1000000
#define L 14
 
char A[N][L];
 
int getChar(char c);
long long getKey(char str[]);
int h1(int key){ return key%N; }
int h2(int key){ return 1+(key%(N-1)); }
int find(char str[]);
int insert(char str[]);

int main(){
  int i, n;
  char str[L], cmp[9];

  for(i = 0; i < N; i++){
    A[i][0] = '\0';
  }
  scanf("%d", &n); 
  for(i = 0; i < n; i++){
    scanf("%s %s", cmp, str);
    if(cmp[0] == 'i'){
      insert(str);
    } else {
      if(find(str)){
        printf("yes\n");
      } else {
        printf("no\n");
      }
    }
  }
  return 0;
}

int getChar(char c){
  if( c == 'A') return 1;
  else if( c == 'C') return 2;
  else if( c == 'G') return 3;
  else if( c == 'T') return 4;
  else return 0;
}

long long getKey(char str[]){
  long long sum = 0, p = 1, i;
  for (i = 0; i < strlen(str); i++){
    sum += p*(getChar(str[i]));
    p *= 5;
  }
  return sum;
}

int find(char str[]){
  int i, h;
 
  h = (h1(getKey(str)) + i * h2(getKey(str))) % N;
  for(i = 0; i < 14; i++){
    h = (h1(getKey(str)) + i * h2(getKey(str))) % N;
    if(strcmp(A[h], str) == 0) return 1;
  }
  return 0; 
}

int insert(char str[]){
  int i;
  if(find(str)) return 0;
  for(i = 0; i < 14; i++){
    if(A[ (h1(getKey(str)) + i * h2(getKey(str))) % N ][0] == '\0'){
      strcpy(A[ (h1(getKey(str)) + i * h2(getKey(str))) % N ], str);
      return 1;
    }
  }
  return 0;
}