Problem:
Score : 300 points

Problem Statement

Does \sqrt{a} + \sqrt{b} < \sqrt{c} hold?

Constraints

1 \leq a, b, c \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

a \ b \ c

Output

If \sqrt{a} + \sqrt{b} < \sqrt{c}, print Yes; otherwise, print No.

Sample Input 1

2 3 9

Sample Output 1

No

\sqrt{2} + \sqrt{3} < \sqrt{9} does not hold.

Sample Input 2

2 3 10

Sample Output 2

Yes

\sqrt{2} + \sqrt{3} < \sqrt{10} holds.

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
#include <math.h>
#include <tgmath.h>



int main(void){

  double a,b,c;
  scanf("%lf",&a);
  scanf("%lf",&b);
  scanf("%lf",&c);

  // double pi = 100.123456789101112;
  // double ii = 83.435614514613452346;
  // printf("%.17lf",pi+ii);

  if(sqrtl(c)-sqrtl(a)-sqrtl(b)>0){
    printf("Yes");
  }
  else{
    printf("No");
  }

}