Problem:
Search III

Your task is to write a program of a simple dictionary which implements the following instructions:

insert str: insert a string str in to the dictionary

find str: if the distionary contains str, then print 'yes', otherwise print 'no'

Input

In the first line n, the number of instructions is given. In the following n lines, n instructions are given in the above mentioned format.

Output

Print yes or no for each find instruction in a line.

Constraints

A string consists of 'A', 'C', 'G', or 'T'

1 ≤ length of a string ≤ 12

n ≤ 1000000

Sample Input 1

5
insert A
insert T
insert C
find G
find A

Sample Output 1

no
yes

Sample Input 2

13
insert AAA
insert AAC
insert AGA
insert AGG
insert TTT
find AAA
find CCC
find CCC
insert CCC
find CCC
insert T
find TTT
find T

Sample Output 2

yes
no
no
yes
yes
yes

Notes

Template in C

Solution in C (judge verdict: Accepted)

#include <stdio.h>
#include<string.h>
#define M 1046527
#define L 14

char H[M][L];

int get(char *c){
    int sum=0,p=1;
    for(int i=0;i<strlen(c);i++){
        if(c[i]=='A') sum+=1*p;
        else if(c[i]=='C') sum+=2*p;
        else if(c[i]=='G') sum+=3*p;
        else               sum+=4*p;
        p*=5;
    }
    return sum;
}

int h1(int key){ return key%M;}
int h2(int key){ return 1+(key%(M-1));}

void insert(char *c){
    long long i,h,key=get(c);
    i=0;
    while(1){
        h=(h1(key)+i*h2(key))%M;
        if(!strcmp(H[h],c)) return;
        else if(H[h][0]=='\0'){
            strcpy(H[h],c);
            return;
        }
        i++;
    }
    return;
}

int find(char *c){
    long long i,h,key=get(c);
    i=0;
    while(1){
        h=(h1(key)+i*h2(key))%M;
        if(!strcmp(H[h],c)) return 1;
        else if(H[h][0]=='\0') return 0; 
        i++;
    }
    return 0;
}


int main(void){
    int n,i;
    char op[8],arr[4];
    
    for(i=0;i<M;i++){
        H[i][0]='\0';
    }
    
    scanf("%d",&n);
    for(i=0;i<n;i++){
        scanf("%s %s",op,arr);
        if(op[0]=='i'){
            insert(arr);
        }
        else {
            if(find(arr)) printf("yes\n");
            else printf("no\n");
        }
    }
    return 0;
}