Problem:
Score : 200 points

Problem Statement

Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Constraints

1 \leq N \leq 10^4

1 \leq A \leq B \leq 36

All input values are integers.

Input

Input is given from Standard Input in the following format:

N A B

Output

Print the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Sample Input 1

20 2 5

Sample Output 1

84

Among the integers not greater than 20, the ones whose sums of digits are between 2 and 5, are: 2,3,4,5,11,12,13,14 and 20. We should print the sum of these, 84.

Sample Input 2

10 1 2

Sample Output 2

13

Sample Input 3

100 4 16

Sample Output 3

4554

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include <stdio.h>

int DigitSum(int x){
	return x%10 + (x/10)%10 + (x/100)%10 + (x/1000)%10 + (x/10000)%10;
}

int main(){
	int N,A,B,K,i;
	scanf("%d %d %d",&N,&A,&B);

	for(i = 1; i <= N; i++){
		if(A <= DigitSum(i) && DigitSum(i) <= B){
			K += i;
		}
	}

	printf("%d\n",K);

	return 0;
}