Problem:
Search III

Your task is to write a program of a simple dictionary which implements the following instructions:

insert str: insert a string str in to the dictionary

find str: if the distionary contains str, then print 'yes', otherwise print 'no'

Input

In the first line n, the number of instructions is given. In the following n lines, n instructions are given in the above mentioned format.

Output

Print yes or no for each find instruction in a line.

Constraints

A string consists of 'A', 'C', 'G', or 'T'

1 ≤ length of a string ≤ 12

n ≤ 1000000

Sample Input 1

5
insert A
insert T
insert C
find G
find A

Sample Output 1

no
yes

Sample Input 2

13
insert AAA
insert AAC
insert AGA
insert AGG
insert TTT
find AAA
find CCC
find CCC
insert CCC
find CCC
insert T
find TTT
find T

Sample Output 2

yes
no
no
yes
yes
yes

Notes

Template in C

Solution in C (judge verdict: Runtime Error)

/* Dictionary */
#include <stdio.h>
#include <string.h>

#define M 1046527
#define NIL (-1)
#define L 14

char H[M][L];


int getChar(char ch) {
    if(ch == 'A') return 1;
    else if(ch == 'C') return 2;
    else if(ch == 'G') return 3;
    else if(ch == 'T') return 4;
    else return 0;
}


long long getKey(char str[]) {
    long long sum=0, p=1, i;
    for(i=0; i < strlen(str); i++){
        sum += p*(getChar(str[i]));
        p *= 5;
    }
    return sum;
}

int h1(int key){ return key % M; }
int h2(int key){ return 1 + (key * (M - 1));}

int find(char str[]) {
    long long key, i, h;
    key = getKey(str);
    for(i=0;; i++){
        h = (h1(key) + i * h2(key)) % M;
        if(strcmp(H[h], str) == 0) return 1;
        else if(strlen(H[h]) == 0) return 0;
    }
    return 0;
}

int insert(char str[]) {
    long long key, i, h;
    key = getKey(str);
    for(i=0;; i++){
        h = (h1(key) + i * h2(key)) % M;
        if(strcmp(H[h], str) == 0) return 1;
        else if(strlen(H[h]) == 0) {
            strcpy(H[h], str);
            return 0;
        }
    }
    return 0;
}

int main() {
    int i, n, h;
    char str[L], com[9];
    for(i=0; i<M; i++){ H[i][0] = '\0'; }
    scanf("%d", &n);
    for(i=0; i<n; i++){
        scanf("%s %s", com, str);

        if(com[0] == 'i') {
            insert(str);
        } else {
            if(find(str)) {
                printf("yes\n");
            } else {
                printf("no\n");
            }
        }
    }
    return 0;
}