Problem:
Score : 200 points

Problem Statement

We have held a popularity poll for N items on sale. Item i received A_i votes.

From these N items, we will select M as popular items. However, we cannot select an item with less than \dfrac{1}{4M} of the total number of votes.

If M popular items can be selected, print Yes; otherwise, print No.

Constraints

1 \leq M \leq N \leq 100

1 \leq A_i \leq 1000

A_i are distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M
A_1 ... A_N

Output

If M popular items can be selected, print Yes; otherwise, print No.

Sample Input 1

4 1
5 4 2 1

Sample Output 1

Yes

There were 12 votes in total. The most popular item received 5 votes, and we can select it.

Sample Input 2

3 2
380 19 1

Sample Output 2

No

There were 400 votes in total. The second and third most popular items received less than \dfrac{1}{4\times 2} of the total number of votes, so we cannot select them. Thus, we cannot select two popular items.

Sample Input 3

12 3
4 56 78 901 2 345 67 890 123 45 6 789

Sample Output 3

Yes

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

/* B - Popular Vote */

#include <stdio.h>

int main(void){
  int N, M, i, A[100], sum = 0, count = 0;
  scanf("%d %d", &N, &M);
  for(i = 0; i < N; i++){
    scanf("%d", &A[i]);
    sum += A[i];
  }
  for(i = 0; i < N; i++){
    if(sum % (4 * M) == 0){
      if(A[i] >= sum / (4 * M)){
        count++;
      }
    }else{
      if(A[i] >= sum / (4 * M) + 1){
        count++;
      }
    }
  }
  if(count >= M){
    printf("Yes\n");
  }else{
    printf("No\n");
  }
}