Problem:
Score : 200 points

Problem Statement

Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Constraints

1 \leq N \leq 10^4

1 \leq A \leq B \leq 36

All input values are integers.

Input

Input is given from Standard Input in the following format:

N A B

Output

Print the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Sample Input 1

20 2 5

Sample Output 1

84

Among the integers not greater than 20, the ones whose sums of digits are between 2 and 5, are: 2,3,4,5,11,12,13,14 and 20. We should print the sum of these, 84.

Sample Input 2

10 1 2

Sample Output 2

13

Sample Input 3

100 4 16

Sample Output 3

4554

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
int main(void){
    int n,a,b;
    scanf("%d %d %d",&n,&a,&b);

    int i;
    int j;
    int ans=0;
    int wa=0;
    for(i=a;i<=n;i++){
        j=i;

        wa+=j%10;
        j=j/10;
        wa+=j%10;
        j=j/10;
        wa+=j%10;
        j=j/10;
        wa+=j%10;
        j=j/10;
        wa+=j%10;

        if(a<=wa && wa<=b){
            ans+=i;      
        }
        wa =0;
    }
    printf("%d",ans);
        
    
    return 0;
}