Problem:
Score : 200 points

Problem Statement

Having learned the multiplication table, Takahashi can multiply two integers between 1 and 9 (inclusive) together.

Given an integer N, determine whether N can be represented as the product of two integers between 1 and 9. If it can, print Yes; if it cannot, print No.

Constraints

1 \leq N \leq 100

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N can be represented as the product of two integers between 1 and 9 (inclusive), print Yes; if it cannot, print No.

Sample Input 1

10

Sample Output 1

Yes

10 can be represented as, for example, 2 \times 5.

Sample Input 2

50

Sample Output 2

No

50 cannot be represented as the product of two integers between 1 and 9.

Sample Input 3

81

Sample Output 3

Yes

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

/* ex3-3
   Sagzar1993  */


#include <stdio.h>

int main(void) {
    //表す整数と基数を定義
    int num;

    //入力を受け取る
    scanf("%d", &num);

    //numが各数字で割り切れ、かつその商が１から９の間であるとき、Yesを表示
    if(num % 1 == 0 && num / 1 <= 9){
        printf("Yes\n");
    }else if(num % 2 == 0 && num / 2 <= 9){
        printf("Yes\n");
    }else if(num % 3 == 0 && num / 3 <= 9){
        printf("Yes\n");
    }else if(num % 4 == 0 && num / 4 <= 9){
        printf("Yes\n");
    }else if(num % 5 == 0 && num / 5 <= 9){
        printf("Yes\n");
    }else if(num % 6 == 0 && num / 6 <= 9){
        printf("Yes\n");
    }else if(num % 7 == 0 && num / 7 <= 9){
        printf("Yes\n");
    }else if(num % 8 == 0 && num / 8 <= 9){
        printf("Yes\n");
    }else if(num % 9 == 0 && num / 9 <= 9){
        printf("Yes\n");
    }else{
        printf("No\n"); //どれにも当てはまらなかった場合はNoを表示
    }
    return 0;
}