Problem:
Score : 200 points

Problem Statement

Find the number of palindromic numbers among the integers between A and B (inclusive).
Here, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.

Constraints

10000 \leq A \leq B \leq 99999

All input values are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the number of palindromic numbers among the integers between A and B (inclusive).

Sample Input 1

11009 11332

Sample Output 1

4

There are four integers that satisfy the conditions: 11011, 11111, 11211 and 11311.

Sample Input 2

31415 92653

Sample Output 2

612

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>
#include <math.h>
#include <string.h>

int main(void){

	int in[2]={0};
	
	char tmp;
	int i,j;
	int count=0;
	int rev=0,num=0;
	scanf("%d %d",&in[0],&in[1]);
	//printf("%d %d\n",in[0],in[1]);
	
	for(i=in[0];i<in[1];i++){
		
		num=i;
		rev=0;
		while(num>0){
			rev=rev*10+num%10;
			num/=10;
		}
		
		if(i==rev){
			count++;
		}
	}
	
	printf("%d",count);	
	
	return 0;
}