Problem:
Score : 200 points

Problem Statement

Given are a positive integer N and a string S of length N consisting of lowercase English letters.

Determine whether the string is a concatenation of two copies of some string.
That is, determine whether there is a string T such that S = T + T.

Constraints

1 \leq N \leq 100

S consists of lowercase English letters.

|S| = N

Input

Input is given from Standard Input in the following format:

N
S

Output

If S is a concatenation of two copies of some string, print Yes; otherwise, print No.

Sample Input 1

6
abcabc

Sample Output 1

Yes

Let T = abc, and S = T + T.

Sample Input 2

6
abcadc

Sample Output 2

No

Sample Input 3

1
z

Sample Output 3

No

Solution in C (GCC 5.4.1) (judge verdict: Accepted)

#include<stdio.h>
#include<string.h>

int main(){
  int n,i;
  
  scanf("%d\n",&n);
  if(n%2==1){
  printf("No");
    return 0;
  }
  char str1[n/2];
  char str2[n/2];
  for(i=0;i<n/2;i++){
  scanf("%c",&str1[i]);
  }
  for(i=0;i<n/2;i++){
  scanf("%c",&str2[i]);
  }
  
  if(strncmp(str1,str2,n/2)==0){
  printf("Yes");
  return 0;
  }else{
  printf("No\n");
  }
  
  return 0;
}