Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in C (GCC 5.4.1) (judge verdict: Wrong Answer)

#include <stdio.h>

int main(){
  int S; scanf("%d", &S);
  if(S >= 1213){
    if((S % 100 <= 12) && (S % 100 != 0)){ // 9912, 1403, etc
      printf("YYMM"); 
    }
    else{
      printf("NA");
    }
  }
  
  else{
    if(S < 100){ // korede YYMM ka NA ga kakutei
      if((S <= 12) && (S != 0)){ // 0012 ~ 0001
	printf("YYMM");
      }
      else{ // 0099 ~ 0013, 0000
	printf("NA");
      }
    }
    else{ // 
      if((S % 100 <= 12) && (S % 100 != 0)){ // 1231 ~ 
	printf("AMBIGUOUS");
      }
      else{
	printf("YYMM");
      }
    }
  }
  return 0;
}