题目：如果 \frac{1}{97}+ \frac{3}{97}= \frac{2}{97}×2= \frac{4}{97}; \frac{1}{97}+ \frac{3}{97}+ \frac{5}{97}= \frac{3}{97}×3= \frac{9}{97}; \frac{1}{97}+ \frac{3}{97}+ \frac{5}{97}+ \frac{7}{97}= \frac{4}{97}×4= \frac{16}{97}，则 \frac{1}{97}+ \frac{3}{97}+ \frac{5}{97}+…+ \frac{49}{97}=( ) 
选项：
bullet: A
text: \frac{625}{97}
bullet: B
text: \frac{676}{97}
bullet: C
text: \frac{1225}{97}
bullet: D
text: \frac{2401}{97}
答案：A
解析：通过观察，每个算式中分数的分子都是连续的奇数，得数为分母不变，分子为分数的个数，然后乘分数的个数，据此解答.