query: SELECT employee_id FROM job_history GROUP BY employee_id HAVING COUNT(*)  >= 2
question: What employee id employee who everholds two or more job?
query_toks: SELECT employee_id FROM job_history GROUP BY employee_id HAVING COUNT ( * ) > = 2
query_toks_no_value: select employee_id from job_history group by employee_id having count ( * ) > = value
question_toks: What employee id employee who everholds two or more job?