query: SELECT T1.name FROM student AS T1 JOIN advisor AS T2 ON T1.id  =  T2.s_id GROUP BY T2.s_id HAVING count(*)  >  1
question: Find name student who have more than one advisor?
query_toks: SELECT T1.name FROM student AS T1 JOIN advisor AS T2 ON T1.id = T2.s_id GROUP BY T2.s_id HAVING count ( * ) > 1
query_toks_no_value: select t1 . name from student as t1 join advisor as t2 on t1 . id = t2 . s_id group by t2 . s_id having count ( * ) > value
question_toks: Find name student who have more than one advisor?